MU-NLPC/Calc-aqua_rat huggingface dataset:
What is the probability of getting a sum 9 from two throws of a dice? Choose the correct choice from the following options:	A) 1/6	B) 1/8	C) 1/9	D) 1/12	E) 1/21

Solution: In two throws of a dice, n(S) = (6 x 6) = 36.   Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.   P(E) =n(E)/n(S)=4/36=1/9.   Answer:1/9
Answer: C
Pointing a photograph X said to his friend Y, "She is the only daughter of the father of my mother." How X is related to the person of photograph?
Choose the correct choice from the following answers:
A) Daughter B) Son C) Nephew D) Cannot be decided E) None

Solution: since the lady is daughter of his grandfather ...so she must be sister of his mother....that means he is the nephew.   ANSWER:Nephew
Answer: C
Sandy had $231 left after spending 30% of the money she took for shopping. How much money did Sandy take along with her?	Pick one
A) $270 B) $290 C) $310 D) $330 E) $350

Solution: Let the money Sandy took for shopping be x.   0.7x = 231   x = 330   The answer is $330.
Answer: D
In the first 5 overs of a cricket game, the run rate was only 2.1. What should be the rate in the remaining 30 overs to reach the target of 200 runs? Select:
A) 6.25  B) 6.28  C) 6.31  D) 6.19  E) 6.21

Solution: Required run rate   = [200 - (2.1 * 5)]/30   = 189.50/30   = 6.31   Answer:6.31
Answer: C
By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c? Options.
A) 38029  B) 38000  C) 38098  D) 38028  E) 27768

Solution: CP + CP/8 = 45000   CP = 40000   SP = 40000*(95/100)= 
40000*(95/100) = 38_000
38000   Answer: 38000
Answer: B
A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 6 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?	Choose the correct choice
A) 17.5 B) 7.4 C) 7.9 D) 12.0 E) 7.1

Solution: Net part filled in 1 hour = (1/4 - 1/6) = 1/12   The cistern will be filled in 12/1 hrs i.e., 12 hrs.Answer: 12.0
Answer: D
Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kgs of Apples is Choose one:
A) 3.69  B) 3.66  C) 3.6  D) 3.62  E) 3.61

Solution: Ans: By framing equations we get   30L+3Q=11.67   30L+6Q=12.48   Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first   Then we get L = 0.362   Cost of 10 kgs of apples = 0.362 x 10 = 3.62   Answer:3.62
Answer: D
The sum of the present ages of father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:	Answers.
A) 12 years	B) 11 years	C) 10years	D) 20 years	E) 9 years

Solution: Answer: Option D   Let the present ages of son and father be x and (60 - x) years respectively.   Then, (60 - x) - 6 = 5(x - 6)   6x = 84 => x = 14   Son's age after 6 years = (x + 6) = 20 years.
Answer: D
What is the remainder when 43*49 is divided by 8?
Pick.
A) 1
B) 3
C) 4
D) 5
E) 7

Solution: we can make use of the rule :   Remainder of { (a * b)/n}} = Remainder of (a/n) * Remainder of (b/n)   Here   Remainder of { 43 * 49)/8}} = Remainder of (43/8) * Remainder of (49/8) = 3 * 1= 
3 * 1 = 3
3   Answer :3
Answer: B
The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is?	Pick.
A) 12	B) 77	C) 26	D) 29	E) 24

Solution: S = 1   M = x   DS = x + 1   US = x - 1   35/(x + 1) + 35/(x - 1) = 12   x = 6.12nswer: 12
Answer: A
Mark is playing poker at a casino. Mark starts playing with 110 chips, 20% of which are $100 chips and 80% of which are $20 chips. For his first bet, Mark places chips, 10% of which are $100 chips, in the center of the table. If 70% of Mark's remaining chips are $20 chips, how much money did Mark bet?	Choose the correct choice:
A) $1,960	B) $1,740	C) $1,540	D) $3,080	E) $2,640

Solution: Total chips 110   20% of $100 chips = 22 chips * $100 = $2,200   80% of $20 chips = 88 chips * $20 = $1,760   If x is the number of chips bet and y is the amount of chips remaining:   x + y = 110   y = 110 - x ~ (1)   [First round bet] + [Second round bet] = $2,200 + $1,760   [0.1x * $100 + 0.9x * $20] + [0.3y * $100 + 0.7y * $20] = $3,960   10x + 18x + 30y + 14y = 3960   28x + 44y = 3960 ~ (2)   Substitute (1) into (2) to solve for x:   28x + 44(110 - x) = 3960   28x + 4840 - 44x = 3960   16x = 880   x = 55   Substituting x:   [First round bet] = [0.1x * $100 + 0.9x * $20] = 0.1(55)($100)+0.9(55)($20) = $550 + $990 = $1,540   Answer is $1,540
Answer: C
How many zeroes are there at the end of the number N, if N = 70! + 140! ? Choose the correct option.
A) 8	B) 12	C) 16	D) 20	E) 24

Solution: The number of zeroes at the end of 70! will be less than the number of zeroes at the end of 140!   Hence it is sufficient to calculate the number of zeroes at the end of 70!   The number of zeroes = [70/5] + [70/25] + [70/125] = 14 + 2 + 0= 
14 + 2 + 0 = 16
16   The answer is 16.
Answer: C
The area of a circular field is 17.56 hectares. Find the cost of fencing it at the rate of Rs. 7 per metre approximately  Pick.
A) 4457
B) 10400
C) 4235
D) 4547
E) 4675

Solution: Explanation:   Area = (17.56 x 10000) m2= 175600 m2.   ΠR2 = 175600 ⇔ (R)2 = (175600 x (7/22)) ⇔ R = 236.37 m.   Circumference = 2ΠR = (2 x (22/7) x 236.37) m =1485.78 m.   Cost of fencing = Rs. (1485.78 x 7) = Rs. 10400.   Answer: Option 10400
Answer: B
If the sum of two numbers is 12 and the sum of their squares is 124, then the product of the numbers is  Choose one:
A) 10	B) 44	C) 80	D) 88	E) 90

Solution: Sol.   Let the numbers be x and y.   Then, (x+y) = 12 and x2 + y2 = 124.   Now, 2xy = (x+y)2 - (x2 + y2)   = (12)2 - 124 = 144 - 124= 
144 - 124 = 20
20   xy= 10.   10nswer 10
Answer: A
The average expenditure of a labourer for 6 months was 70 and he fell into debt. In the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30. His monthly income i  Choose the correct choice:  A) 69  B) 72  C) 75  D) 78  E) 80

Solution: Income of 6 months = (6 × 70) – debt   = 420 – debt   Income of the man for next 4 months   = 4 × 60 + debt + 30   = 270 + debt   ∴ Income of 10 months = 690   69verage monthly income = 690 ÷ 10 = 69   69nswer 69
Answer: A
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
Answers:
A) 5/21
B) 5/22
C) 5/29
D) 5/27
E) 5/12

Solution: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)   As remaining person can be any one among three couples left.   Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅   = (10 * 6)/252   = 5/21   5/21nswer: 5/21
Answer: A
A's speed is 20/13 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that B beats A by 60% of the length of the race?	Options:
A) 44%
B) 48%
C) 52%
D) 42%
E) 74%

Solution: First calculate the distance, B has covered with his speed in the time, in which A reached 40% of the race.   Then Add the remaining distance as head start for B to win the race.   Its best to apply Ratios concept here.   Since A's speed is 20/13 of B, therefore, B's speed is 13/20 of A   Distance covered by B = speed x time = (13/20) x (0.4) = 0.26   (Which means B would have covered 0.26 of the race length during the time in which A has covered 0.4 of the race length.   Therefore to win, B needs a headstart of (1 - 0.26 = ) 0.74 of the race length.   So the answer is 74%
Answer: E
Laya finished 2/3 of a book. She calculated that she finished 50 more pages than she has yet to read. How long is her book?
Select.
A) A)150
B) B)180
C) C)130
D) D)90
E) E)210

Solution: Let x be the total number of pages in the book, then she finished 2/3*x pages.   Then she has x−2/3*x=1/3*x pages left.   2/3*x−1/3*x=50   1/3*x=50   x=150   So the book is 150 pages long.   150nswer is 150.
Answer: A
A dealer purchases 15 articles for Rs. 25 and sells 12 articles for Rs. 30. Find the profit percentage?
Choose the correct option
A) 59  B) 50  C) 56  D) 51  E) 52

Solution: L.C.M of 15 and 12 = 60   CP of 60 articles = Rs. 100 (25 * 4)   SP of 60 articles = Rs. 150 (30 * 5)   Profit percentage = (150 - 100)/100 * 100= 
(150 - 100)/100 * 100 = 50
50%.Answer50
Answer: B
Car A runs at the speed of 50 km/hr and reaches its destination in 8 hours. Car B runs at the speed of 70 km/h and reaches its destination in 4 hours. What is the ratio of distances covered by Car A and Car B?
Pick one
A) 3 : 7 B) 4 : 9 C) 10 : 7 D) 5 : 7 E) 6 : 11

Solution: 10 : 7ar A travels 50 × 8 = 400 km   10 : 7ar B travels 70 × 4 = 280 km   The ratio is 400 : 280 = 40 : 28 = 10 : 7   The answer is 10 : 7.
Answer: C
In a box, there are 6 red, 3 blue and 56 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green? Choices:
A) 2/3  B) 8/21  C) 6/14  D) 9/22  E) 10/21

Solution: Explanation:   Total number of balls = (6 + 3 + 5)= 
(6 + 3 + 5) = 14
14   Let E= event that the ball drawn is neither blue nor green =e vent that the ball drawn is red.   Therefore, n(E) = 6.   P(E) = 6/14.   Answer: Option 6/14
Answer: C
The length and width of a rectangle are integer values. What is the area of the smallest such rectangle that can be inscribed in a circle whose radius is also an integer  Answers:
A) 12  B) 45  C) 36  D) 48  E) 60

Solution: If we consider all pythagorean triplets with integral values, we have the following results:-   (3,4,5),(6,8,10)........   The diameter of the circle is 5 in the 1st case and 10 in the 2nd.   But the question says that radius of the circle is also an integer hence the 1st triplet will be ruled out.   We are left with the 2nd triplet where radius of the circle=5,   Hence the sides of the rectangle are 6 and 8 making the area =45.   45
Answer: B
one year before the age of pramila was four times than her daughter swati.after 6 years the age of pramila will be 24 year greater than the age of swati.then calculate the ratio of ages of pramila and swati?	Answers:
A) 5:3
B) 16:3
C) 11:3
D) 11:5
E) 9:4

Solution: let 1 year before age of swati=x years and age of pramila =4x years   swati present age=(x+1) and pramila present age=(4x+1)   after 6 year age of swati=(x+7),age of pramila=(4x+7)   so,4x+7-(x+7)=24,3x=24,x=8.   ratio=(4x+7):(x+1)=33:9=11:3   answer 11:3
Answer: C
Abhay’s age after six years will be three-seventh of his fathers age. Ten years ago the ratio of their ages was 1 : 5. What is Abhay’s father's age at present?
Choose the correct choice from the following answers.
A) 52 years
B) 48 years
C) 50 years
D) 54 years
E) 35 years

Solution: Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,   Abhay's age after 6 years = (x + 10) + 6 = (x + 16) years.   Father's age after 6 years = (5x + 10) + 6 = (5x + 16) years.   (x + 16) = 3 (5x + 16)   __   7   7(x + 16) = 3 (5x + 16)   7x + 112 = 15x + 48   8x = 64   x = 8.   hence, Abhay's father's present age = (5x + 10) = 50 years.   Answer is 50 years.
Answer: C
A 300-metre-long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?  Choose the correct option:
A) 320 metres B) 650 metres C) 350 metres D) Data inadequate E) None of these

Solution: When a train crosses a platform, it crosses a distance equal to the sum of the length of the platform and that of the train. But when a train crosses a signal pole, it crosses the distance equal to its length only.   Here, time taken by the train to cross a signal pole = 18 seconds   Hence, speed of the train = 300⁄18 m/sec   The train takes 21 = (39 – 18) seconds extra in order to cross the platform.   Hence, length of platform = 21×300/18=350m   Answer 350 metres
Answer: C
If two numbers are in the ratio 2:3. If 10 is added to both of the numbers then the ratio becomes 5:7 then find the largest number? Choose the correct choice from the following answers:
A) 20  B) 25  C) 40  D) 44  E) 46

Solution: 2:3   2x + 10 : 3x + 10 = 5 : 7   7[2x + 10] = 5[3x + 10]   14x + 70 = 15x + 50   15x - 14x = 70 - 50= 
70 - 50 = 20
20   Then the first number is= 2   2x = 40   Short cut method:   a:b = 2:3   c:d = 5:7   1.Cross multiplication with both ratios   a * d ~ b * c = 2 * 7 ~ 3 * 5 = 14 ~ 15 = 1   2. If 10 is added both the number means   10 * 5= 
  10 * 5 = 50
50 and   10 * 7= 
  10 * 7 = 70
70,   Then 50 ~ 70= 20   ===> 1 -----> 20   ===> 2 -----> 40 (Answer is = 40)   40
Answer: C
A man buys 25 shares in company which pays 9 % dividend. The
money invested is such that it gives 10 % on investment. At what price did he buy the shares? Choose the correct choice from the following options.
A) 25	B) 22.5	C) 23	D) 24	E) 25.5

Solution: Suppose he buys each share for $ x.   Then, [25*(9/100)] = [x*(10/100)] or x = $ 22.50.   Cost of each share = $ 22.50.   Answer 22.5.
Answer: B
In a survey conducted to find out the readership of three Newspapers A,B and C, it was found that the number of newspaper A is at least 20 and at most 40. The number of people who read newspaper B is at least 50 and at most 70. The number of people who read newspaper C is at least 70 and at most 83. It was also found that 6 people read all three newspapers. Find the minimum number of people who read both A and B but not C.	Pick one:
A) A)1 B) B)2 C) C)3 D) D)0 E) E)5

Solution: I wish I could draw a diagram to show you but by giving you number A and B, it might help a little.   A and B and C is 6 - that means A and B is at least 6. This seems trivial given the value intervals of A and B but definitely helps to think through how to minimize A and B but not C   A and B but not C = |A|-|B| - 6   So i would pick A=30 and B =50 to minimize the value to a 2. (ANS 2)
Answer: B
In how many ways 8 different tickets can be distributed between Jane and Bill if each is to receive any even number of tickets and all 8 tickets to be distributed. Choose the correct choice from the following answers.
A) From 2 to 6 inclusive.
B) From 98 to 102 inclusive.
C) From 122 to 126 inclusive.
D) From 128 to 132 inclusive
E) From 196 to 200 inclusive

Solution: Possibilities   J 8 6 4 2 0   B 0 2 4 6 8   # of ways 8C8 8C6 8C4 8C2 8C0   1+28+70+28+1= 
1+28+70+28+1 = 128
128 Answer is From 128 to 132 inclusive.
Answer: D
At a dinner party 2 people are to be seated around a circular table. Two sitting arrangements are considered different only when the positions of the people are different relative to each other.What is the total number of possible sitting arrangements or the group?	Choose the correct choice from the following answers
A) 1
B) 10
C) 24
D) 32
E) 120

Solution: Hi there,   You can treat this as an ordering question except thatfor a circular arrangement you need to divide by the number of spaces.So in this case:   2!/2=1   If you spin the circle to right, that doesn't count as a new arrangement. Dividing by the number of spaces takes that into consideration.   Happy Studies,   HG.   1 2 /2= 
 2 /2 = 1
1   If you spin the circle to right, that doesn't count as a new arrangement. Dividing by the number of spaces takes that into consideration.   Happy Studies,   HG.   1
Answer: A
An Olympic diver received the following scores: 5, 3, 7, 6, and 4. The standard deviation of her scores is  Choose the correct choice from the following:
A) 1.41
B) 2.41
C) 3.41
D) 4.41
E) 5.41

Solution: 5+3+7+6+4/5 = 5   | 5-5= 
 5-5 = 0
0 0^2= 0   |3-5| = 2 2^2 = 4   | 7-5= 
 7-5 = 2
2 2^2= 4   | 6-5= 
 6-5 = 1
1 1^2= 1   |4-5| = 1 1^2 = 1   SD = sqrt 10/5 =1.41   1.41nswer : 1.41
Answer: A
At a local beach, the ratio of little dogs to average dogs to enormous dogs is 1:4:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?	Choose the correct choice from the following.
A) 25% B) 40% C) 50% D) 55% E) 70% or 20%

Solution: Little Dogs(L), Average Dogs(A) and 70% or 20%normous Dogs (70% or 20%)   The initial ratio for L:A:70% or 20% :: 1:4:8   Initial Total dogs = 13X ( x assumed; 1+4+8= 
1+4+8 = 13
13), Since the total dogs are less than 30 therefore initial total value has to be 13   L= 1, A = 4 70% or 20% = 8   L:A= 1:4   This ratio doubles   Hence New Dog count is   L= 2 , A = 4 70% or 20%= X: Also 2+4+x<30   We need to Find X*100/(2+4+X)   Now it says that new percentage of little dogs and Average dogs is an integer   %L = 2*100/(6+x) %A = 4*100/(6+x); Only Value for X is 4 or 14; 6+x<30 and % integer   Therefore, 70% or 20%normus Dogs % is = 4*100/(20)= 
4*100/(20) = 20
20% or   14*100/20= 
  14*100/20 = 70
70%   20% or 70%   70% or 20%
Answer: E
You collect coins. Suppose you start out with 15. Since you're nice, you give Sharon 3 coins. Since you're nice, you give Steven 4 coins. How many coins do you have at the end?  Select:
A) 2  B) 3  C) 8  D) 5  E) 6

Solution: Solution   Start with 15 coins.   Sharon takes 3 coins from you:   15 - 3= 
  15 - 3 = 12
12 coins.   Steven takes 4 coins from you:   12 - 4= 
  12 - 4 = 8
8 coins.   So you have 8 at the end.   8orrect answer : 8
Answer: C
There is 60% increase in an amount in 6years at SI. What will be the CI of Rs. 12,000 after 3 years at the same rate?  Pick:  A) 2372  B) 2572  C) 4542  D) 2343  E) 3972

Solution: Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.   R = 100 x 60 = 10% p.a.   100 x 6   Now, P = Rs. 12000. T = 3 years and R = 10% p.a.   C.I.   = Rs. 12000 x 1 +	10 3	- 1   100   = Rs. 12000 x	331   1000   = 3972.   3972
Answer: E
Lucy invested $10,000 in a new mutual fund account exactly three years ago. The value of the account increased by 10 percent during the first year, increased by 8 percent during the second year, and decreased by 10 percent during the third year. What is the value of the account today?
Choose the correct choice from the following answers:  A) $10,350  B) $10,395  C) $10,692  D) $11,500  E) $12,705

Solution: the amount at the end of first year will become the principle for 2nd year, applying this trick and calculating we get the amount at the end of third year to be 10692. So the answer is ($10,692).
Answer: C
Worker A takes 12 hours to do a job. Worker B takes 15 hours to do the same job. How long it take both A & B, working together but independently, to do the same job?	Select.
A) 40 days	B) 40/9 days	C) 39/9 days	D) 30/9 days	E) 20/3 days

Solution: A's one hour work = 1/12.   B's one hour work = 1/15.   (A+B)'s one hour work = 1/12+1/15 = 9/60 = 3/20.   Both A & B can finish the work in 20/3 days   20/3 days
Answer: E
Find the area of a parallelogram with base 36 cm and height 18 cm?  Choose the correct choice from the following answers:  A) 287 cm2  B) 887 cm2  C) 384 cm2  D) 268 cm2  E) 648 cm2

Solution: Area of a parallelogram = base * height   = 36 * 18= 
36 * 18 = 648
648 cm2   Answer: 648 cm2
Answer: E
Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 55 players took part in that tournament. How many matches were played? Choices:  A) 90 matches  B) 95 matches  C) 99 matches  D) 85 matches  E) 87 matches

Solution: A 54 matches. The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 54 matches were played.
Answer: A
If four coins are tossed, the probability of getting two heads and two tails is -.	Pick one
A) 1/2	B) 3/5	C) 4/3	D) 3/8	E) 9/8

Solution: Explanation:   Since four coins are tossed, sample space = 24   Getting two heads and two tails can happen in six ways.   n(E) = six ways   p(E) = 6/24 = 3/8   Answer:3/8
Answer: D
Two trains 300m and 400m long run at the speeds of 40 kmph and 50kmph respectively in opposite Directions on parallel tracks. The time taken to cross each other? Choose the correct choice from the following options.
A) 28sec	B) 20sec	C) 30sec	D) 15sec	E) 25sec

Solution: Length of two Trains = 300m + 400m = 700m   Total Speed300  + 400= 
300  + 400 = 700
700m   Total Speed= 40 Kmph + 50 Kmph (Opposite Direction)   = 90 Kmph   Time = Distance/Speed   Time = 700/ 90   Time = 28Sec   28secNSWER 28sec
Answer: A
Which common no should be added or substracted to 17/24 to make it 1/2  Choose the correct choice
A) 3/24
B) 4/24
C) 5/24
D) 6/24
E) 7/24

Solution: Since 17/24>1/2..the mumber is needed to be subtracted.   let the no. subtracted be x   so..17/24-x=1/2   17/24-1/2=x   therefore..x=5/24   ANSWER:5/24
Answer: C
Townville has 100 residents, and 60 of them are females. If half of Townville’s male residents are smokers, and 1/2 of the female residents are smokers, which of the following represents the total number of Townville’s residents who are NOT smokers?  Choose the correct choice from the following choices:
A) 48	B) 50	C) 52	D) 54	E) 56

Solution: Number of people =100   Females = 60   men = 100-60= 
100-60 = 40
40   Half of the men are smoker  40/2= 
  40/2 = 20
20, that means the remaining men 40-20= 
40-20 = 20
20 are non smokers.   1/2 females are smoker. i.e 1/2*60= 30   60-30= 
60-30 = 30
30 females are non smokers   So, total number of non smokers in the town are 20+30= 
20+30 = 50
50   Answer : 50
Answer: B
0.009/x=0.025. find the value of X Choose the most appropriate option.
A) 0.0003	B) 0.36	C) 0.3	D) 36	E) 90

Solution: x=0.009/0.36=0.25   ANSWER:0.3
Answer: C
If Log 4 (x) = 12, then log 2 (x / 4) is equal to Pick one:
A) 23
B) 25
C) 21
D) 22
E) 26

Solution: If Log 4 (x) = 12, then   x = 412   x / 4 = 411   Hence   log 2 (x / 4) = log 2 (411)   = log 2 ((22)11)   = log 2 (222)   = 22   answer 22
Answer: D
A person incurs 10% loss by selling a laptop for $900. At what price should the watch be sold to earn 10% profit?  Choose the correct choice from the following choices
A) 1200  B) 1000  C) 1100  D) 1050  E) 1250

Solution: Let the new S.P. = x   then (100-loss%): (1st S.P.) = (100+gain%): (2nd S.P.)   (100-10)/900 = (100+10)/x   x=110*900/90= 
110*900/90 = 1_100
1100   new price= $1100   correct option is 1100
Answer: C
Two plates and one cup costs $27. Three plates and four cups cost $58. Find the cost of a cup. Choose the correct answer.
A) 8 B) 7 C) 10 D) 5 E) 9.5

Solution: Let cost of 1 plate = x, let cost of 1 cup = y   2x + y = 27   y = 27 - 2x   Again,   3x + 4y = 51   3x + 4(27 - 2x) = 58   3x + 108 - 8x = 58   3x + 108 = 58 + 8x   3x + 50 = 8x   50 = 5x   10 = x   Now plug x into initial equation:   2x + y = 27   2(10) + y = 27   20 + y = 27   y = 7   Answer: 7
Answer: B
Today Joelle opened an interest-bearing savings account and deposited $6,000. If the annual interest rate is 5 percent compounded interest, and she neither deposits nor withdraws money for exactly 2 years, how much money will she have in the account?
Choose one:
A) $6715  B) $5615  C) $6415  D) $6615  E) $6315

Solution: Interest for 1st year = 6000*5/100= 
6000*5/100 = 300
300   Interest for 2nd year= 6300 *5/100= 
6300 *5/100 = 315
315   Total=6000+300+315= 
6000+300+315 = 6_615
6615   Answer : $6615
Answer: D
A trader marked the price of a car 20% above the cost price and allowed the purchaser 5% discount on the marked price there by gained Rs.8400. Find the cost price of the car?	Choose the correct choice from the following options:	A) 1028	B) 1026	C) 1023	D) 1029	E) 1021

Solution: Given that, the question paper consists of five problems. For each problem, one or two or three or none of the choices can be attempted.   Hence, the required number of ways = 45 - 1.   = 210 - 1 = 1024 - 1= 
1024 - 1 = 1_023
1023   Answer: 1023
Answer: C