MU-NLPC/Calc-aqua_rat huggingface dataset:
The length of a rectangular plot is 10 meters more than its width. If the cost of fencing the plot at $15.50 per meter is $930, what is the length of the plot in meters?
Select.
A) 23 B) 20 C) 28 D) 11 E) 19

Solution: perimeter = 2L + 2W = 2L + 2(L-10) = 4L - 20   cost of fencing = (4L - 20) * 15.50 = 62L - 310 = 930   62L = 1240   L = 20 meters   The answer is 20.
Answer: B
If the area of a circle is 25pi square feet, find its circumference.  Choose the correct choice from the following choices.
A) 10 pi feet	B) 28 pi feet	C) 38 pi feet	D) 48 pi feet	E) 58 pi feet

Solution: The area is given by pi *r* r. Hence   pi * r *r = 25 pi   r * r = 25 ; hence r = 25 feet   The circumference is given by   2 * pi * r = 2 * pi * 5 = 10 pi feet   correct answer 10 pi feet
Answer: A
What is the dividend. divisor 17, the quotient is 8 and the remainder is 5  Pick one
A) A)145  B) B)141  C) C)150  D) D)153  E) E)158

Solution: D = d * Q + R   D = 17 * 8 + 5   D = 136 + 5= 
136 + 5 = 141
141   Answer : 141
Answer: B
How many two-digit integers exist such that all their digits are odd?  Select the correct option:	A) 80	B) 25	C) 120	D) 125	E) 135

Solution: so last digit can be filled in 5 ways- 1,3,5,7,9   there are 5 possibilities. The answer is 5∗5=25   The correct answer is 25
Answer: B
The true discount on Rs.1600 due to after a certain of 5% per annum is Rs.160. The time after which it is due is  Choose the correct choice from the following:
A) 27months
B) 23months
C) 20months
D) 12months
E) None of these

Solution: Explanation:   P.W. = Rs. (1600 - 160) = Rs. 1440   ∴ S.I. on Rs.1440 at 5% is Rs. 160.   ∴ Time = [100 × 160/1440 × 5] = 20/9 years = [20/9 × 12] months = 27 months.   27monthsnswer: 27months
Answer: A
A shopkeeper sold sarees at Rs. 266 each after giving 5% discout on labelled price. Had he not given the discount, he would have earned a profit of 12% on the cost price. What was the cost price of each saree? Choose one: A) 240 B) 250 C) 260 D) 270 E) None

Solution: Sol.   S.P. of 1 saree = Rs.266. Let the labelled price of each saree be Rs. x.   Then, 95/100x = 266 ⇒ x = Rs. [266*100]/95 = Rs. 280.   New, S.P. = Rs. 280, Profit = 12%.   ∴ C.P. of 1 saree = Rs. [100/112 * 280] = Rs. 250.   Answer 250
Answer: B
Pipes A and B can fill a tank in 6 and 3 hours respectively. Pipe C can empty it in 12 hours. If all the three pipes are opened together, then the tank will be filled in:	Select the correct option
A) 2 2/5 hours.	B) 3 2/5 hours.	C) 1 1/5 hours.	D) 4 2/5 hours.	E) 2 1/5 hours.

Solution: Explanation:   Pipes A and B can fill the tank in 5 and 6 hours respectively. Therefore,   part filled by pipe A in 1 hour =1/6   part filled by pipe B in 1 hour = 1/3   Pipe C can empty the tank in 11 hours. Therefore,   part emptied by pipe C in 1 hour =1/12   Net part filled by Pipes A,B,C together in 1 hour   =1/6+1/3-1/12=5/12   i.e., the tank can be filled in 12//5= 
12//5 = 2
2 2/5 hours.   2 2/5 hours.nswer: Option 2 2/5 hours.
Answer: A
Of the 13 employees in a certain department, 1 has an annual salary of 38,000, 2 have an annual salary of 45,900 each, 2 have an annual salary of 42,500 each, 3 have an annual salary of 40,000 each and 5 have an annual salary of 48,500 each. What is the median annual salary for the 13 employees? Choose the correct choice from the following answers:  A) 38,000  B) 40,000  C) 42,500  D) 45,900  E) 48,500

Solution: Median is just the value in the middle when you arrange all values in the ascending order   In this question, the 7th value would be the median (Since there are 13 employees)   38, 40, 40, 40, 42.5, 42.5,45.9   So, answer is 45,900.
Answer: D
Observe the dots on a dice (one to six dots) in the following figures. How many dots are contained on the face opposite to that containing four dots?
Choose the correct choice from the following choices
A) 2 B) 6 C) 7 D) 8 E) 9

Solution: Explanation:   We shall assume the dice in fig. (ii) to be rotated so that the 5 dots appear at the same position as in fig. (i) i.e. on RHS face (i.e. on face II as per activity 1) and 1 dot appears at the same position as in fig; (i) i.e. on Front face (i.e. on face I). Then, from the, two figures, 2 dots appear on the top face (i.e. on face V) and 4 dots appear on the Bottom face (i.e. on face VI).   Since, these two faces are opposite to each other, therefore, two dots are contained on the face opposite to that containing four dots.   2nswer: 2) 2
Answer: A
11234783131 find the next three numbers
Select the correct option: A) 145 B) 178 C) 176 D) 181 E) 191

Solution: we can write in this way   23 - 11= 
23 - 11 = 12
12= 12*1   47-23= 
47-23 = 24
24= 12*2   83-47= 
83-47 = 36
36= 12*3   131 - 83= 
131 - 83 = 48
48=12*4   x-131 = 60 = 12*5, x is the unknown   =>x= 131+60= 
131+60 = 191
191   so the answer is 191   ANSW191R:191
Answer: E
When the integer n is divided by 17, the quotient is x and the remainder is 5. When n is divided by 23, the quotient is y and the remainder is 16. Which of the following is true?  Choose the correct choice:	A) 23x + 17y =19	B) 17x –23y = 11	C) 17x +23y =19	D) 14x + 5y = 6	E) 5x – 14y = -6

Solution: From the problem it follows:   n=17x+5   n=23y+16   So, 17x+5=23y+16   17x-23y=11   The answer is 17x –23y = 11
Answer: B
The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:  Choose the correct answer
A) 152600m2
B) 153500m2
C) 153600m2
D) 153800m2
E) None of these

Solution: Explanation:   Question seems to be typical, but trust me it is too easy to solve, before solving this, lets analyse how we can solve this.   We are having speed and time so we can calculate the distance or perimeter in this question.   Then by applying the formula of perimeter of rectangle we can get value of length and breadth, So finally can get the area. Lets solve it:   Perimeter = Distance travelled in 8 minutes,   => Perimeter = 12000/60 * 8= 
12000/60 * 8 = 1_600
1600 meter. [because Distance= Speed * Time]   As per question length is 3x and width is 2x   We know perimeter of rectangle is 2(L+B)   So, 2(3x+2x) = 1600   => x = 160   So Length = 160*3= 
160*3 = 480
480 meter   and Width= 160*2= 
160*2 = 320
320 meter   Finally, Area= length * breadth   = 480 * 320= 
480 * 320 = 153_600
153600   Answer: Option 153600m2
Answer: C
A forest consists of 4 elms, 6 red woods, and 5 birches In how many ways can 2 elms, 2 red woods and 2 birches be selected from the given group?
Choose the most appropriate option.
A) 987 ways B) 346 ways C) 5400 ways D) 157 ways E) 134 ways

Solution: The number of ways of selecting two elms, two red woods and two birches is:   = ⁴C₂ * ⁶C₂ * ⁵C₂   = (4 * 3 * 2)/(2 * 1) * (6 * 5)/(2 * 1) * (5 * 4 * 3)/(2 * 1)   = 12 * 15 * 30= 
12 * 15 * 30 = 5_400
5400 ways.   Answer: 5400 ways
Answer: C
A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?  Choose the correct choice from the following answers.
A) 635 B) 700 C) 1404 D) 2620 E) 3510

Solution: The only cases possible are :   1. 2 men and 4 women : 8C2 * 5C4 = 140   2. 3 men and 3 women: 8C3*5C3 = 560   Rest of the cases will either have 1 or 0 men (not allowed) or will have 1 or 2 or 0 women (not allowed)   Total possible combinations = 140+560= 
140+560 = 700
700. Thus 700 is the correct answer.
Answer: B
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability J that the first ball picked up is odd numbered?	Choose the correct answer: A) 0 B) 1/3 C) 1/2 D) 2/3 E) 1

Solution: Answer-D   Selecting the balls either Even or Odd is having probability 50/100=1/2   We have already selected 3 balls with 2 odd numbers and 1 even number.   So we have 3 combinations OOE, OEO, EOO. We have 3 outcomes and 2 are favourable as in 2 cases 1st number is odd. So probability J is 2/3.2/3
Answer: D
A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:	Choose the correct answer:  A) 100  B) 378  C) 777  D) 299  E) 277

Solution: Explanation:   When B runs 25 m, A runs \inline \fn_jvn {\color{Black} \frac{45}{2}} m   When B runs 1000 m, A runs \inline \fn_jvn {\color{Black} \left ( \frac{45}{2}\times \frac{1}{25}\times 1000 \right )}m = 900 m.   \inline \fn_jvn {\color{Black} \therefore }B beats A by 100 m.   100nswer: 100) 100 m
Answer: A
A and B can do a work in 10 days and 15 days respectively. A starts the work and B joins him after 5 days. In how many days can they complete the remaining work?
Choose one:
A) 6 days  B) 2 days  C) 8 days  D) 4 days  E) 3 days

Solution: Work done by A in 5 days = 5/10 = 1/2   Remaining work = 1/2   Work done by both A and B in one day = 1/10 + 1/15 = 5/30 = 1/6   Remaining work = 1/2 * 6/1= 
1/2 * 6/1 = 3
3 days.   Answer: 3 days
Answer: E
The age of a father is 5/2 of his daughter. 5 years ago it was 3 times that of his daughter.what is daughter's present age?
Choose the correct choice from the following choices:
A) 20 YRS B) 25 YRS C) 15 YRS D) 10 YRS E) 18 YRS

Solution: daughter's present age is x   father's present age is (5/2)*x   5 years ago father's age is (5x/2)-5=3(x-5)   Therefore,x=20 years   20 YRSNSWER:20 YRS
Answer: A
In day before Yesterday it was Monday, What day will fall on day after tomorrow ? Choose the correct choice from the following options
A) Sunday	B) Tuesday	C) Saturday	D) Friday	E) Monday

Solution: if day before yesterday was Monday then today is Wednesday   if today is wednesday then day after tommorrow will be Friday   ANSWER:Friday
Answer: D
Pumping alone at their respective constant rates, one inlet pipe fills an empty tank to 1/2 of capacity in 9 hours and a second inlet pipe fills the same empty tank to 2/3 of capacity in 6 hours. How many hours will it take both pipes, pumping simultaneously at their respective constant rates, to fill the empty tank to capacity?  Pick one
A) 3.25  B) 3.6  C) 4.2  D) 4.4  E) 6

Solution: Time taken by First tank Fill 1/2 the tank = 9 hours   i.e. Time taken by First tank to Fill 1 complete the tank = 18 hours   Time taken by Second tank Fill 2/3 the tank = 6 hours   i.e. Time taken by First tank to Fill 1 complete the tank = (3/2)*6= 
(3/2)*6 = 9
9 hours   in 1 Hour, Both tanks together Fill the tank= (1/18)+(1/9) =1/6 tank   i.e. Time taken by Both tank to Fill 1 complete the tank =6 hours   Answer: option 6
Answer: E
At 9 am a car (A) began a journey from a point, traveling at 40 mph. At 10 am another car (B) started traveling from the same point at 60 mph in the same direction as car (A). At what time will car B pass car A?	Choose the correct choice from the following answers:  A) 12p.m.  B) 1p.m.  C) 2p.m.  D) 3p.m.  E) 11p.m.

Solution: If x hours have elapsed since 9AM:   A has traveled 40x   B has traveled 60(x - 1)   60(x - 1) = 40x   60x - 60 = 40x   60x - 40x = 60   20x = 60   x = 60/20= 
60/20 = 3
3   ans:   9+3= 
  9+3 = 12
12p.m.   12p.m.NSWER:12p.m.
Answer: A
If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 2?	Choose the correct answer:  A) 5/6  B) 7/36  C) 5/36  D) 1/36  E) 12/36

Solution: The sum of numbers appeared is 2.   Therefore, the required probability = n(E)/n(S) = 1/36.   ANSWER:1/36
Answer: D
Shekar scored 76, 65, 82, 67 and 75 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks? Choose the correct choice from the following answers.
A) 65 B) 69 C) 75 D) 85 E) 73

Solution: 73xplanation :   Average= (76+65+82+67+75)/5 = 365/5= 
365/5 = 73
73   Hence average=73   Answer : 73
Answer: E
On Monday, a certain animal shelter housed 72 cats and dogs. By Friday, 1/6 of the cats and 1/5 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?
Answers.
A) 11 B) 12 C) 13 D) 14 E) 15

Solution: To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/5 > 1/6.   The greatest multiple of 5 less than 72 is 60 (such that the remaining number is divisible by 6), so let's assume there were 60 dogs and 12 cats.   Then the maximum number of adopted pets is 1/5*(60) + 1/6*(12) = 12 + 2= 
12 + 2 = 14
14.   The answer is 14.
Answer: D
When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $110.60, what was the total value of the item?
Choose the correct choice from the following options:
A) $2160  B) $2370  C) $2580  D) $2790  E) $2950

Solution: Let x be the value of the item.   0.07*(x-1000) = 110.60   x = 2580   The answer is $2580.
Answer: C
The roots of the equation ax2 + bx + c = 0 will be reciprocal if:  Choose the correct choice from the following answers.
A) a = b,	B) a = bc,	C) c = a,	D) c = b	E) c = ab.

Solution: Solution:   Let k be one of the root of the given equation.   According to the problem,   1/k will be the other root of the given equation.   We know that, product of the roots of the equation = c/a.   Therefore, k × 1/k = c/a.   or, 1 = c/a.   or, a = c [multiplying a on both sides].   The roots of the equation ax2 + bx + c = 0 will be reciprocal if a = c.   Therefore, a = c or c = a.   Answer: c = a,
Answer: C
When positive integer t is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180? Select:  A) 0  B) 1  C) 2  D) 3  E) 4

Solution: the equation that can be formed t is 13x+2=8y+5..   13x-3=8y...   as we can see x can take only odd values as the RHS will always be even..   Also x can take values till 13 as 13*14>180..   now we have to substitue x as 1,3,5,7,9,11,13...   once we find 7 fitting in , any other value need not be checked as every 4th value will give us answer so next value will be 15..   ans 1.. 1
Answer: B
Set S contains exactly 10 numbers and has an average (arithmetic mean) of 6.2. If one of the numbers in Set S is increased by 8, while all other numbers remain the same, what is the new average of Set S?	Choices:
A) 6.6  B) 6.7  C) 6.8  D) 7.0  E) 6.9

Solution: Old set S - Total is avg * no of elements = 6.2*10= 
6.2*10 = 62
62   If one number is increased by 8 then total increased to  62+8= 
 62+8 = 70
70   New avg - 70/10= 7.0.   Hence answer is 7.0.
Answer: D
A small college reduced its faculty by approximately 20 percent to 195 professors. What was the original number of faculty members?	Choose the correct choice from the following options:
A) 182 B) 208 C) 224 D) 254 E) 244

Solution: If x is the original number of faculty members, then after 20% reduction in faculty members number is .80x   but we are given .80x = 195   x = 244   So the original number of faculty members is 244   Correct Answer - 244
Answer: E
Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 5 cm. Pick one
A) 187 cm2 B) 185 cm2 C) 85 cm2 D) 85 cm2 E) 95 cm2

Solution: 95 cm2xplanation:   Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them) = 1/2 (20 + 18) * (5) = 95 cm2   Answer: Option 95 cm2
Answer: E
0---:-|---:--|-:--:-|--:---|-:----1
On the number line above, the segment from 0 to 1 has been divided into fifths, as indicated by the large tick marks, and also into sevenths, as indicated by the small tick marks. What is the LEAST possible distance Q between any two of the tick marks?	Choose the correct choice from the following options.
A) 1/70  B) 1/35  C) 2/35  D) 1/12  E) 1/7

Solution: divisions are 0 1/7 2/7 3/7 4/7 5/7 6/7 1   1/5 2/5 3/5 4/5 5/5   expressing the same in terms of the lcm of 5,7 ,i.e 35   0 7/35 14/35 21/35 28/35 35/35   5/35 10/35 15/35 20/35 25/35 30/35   by comparing the divisions with each other we can see 1/35 is the shortest possible distance between any two selected divisions.   Q=1/35   Answer is 1/35.
Answer: B
AZ + CD = AAA, where AZ and CD are two-digit numbers and AAA is a three digit number; A, Z, C, and D are distinct positive integers. In the addition problem above, what is the value of C?
Pick one.
A) 1
B) 3
C) 7
D) 9
E) Cannot be determined

Solution: Since AZ and CD are two-digit integers, their sum can give us only one three digit integer of a kind of AAA: 111.   So, A=1 and we have 1Z+CD=111   Now, C can not be less than 9, because no two-digit integer with first digit 1 (1Z<20) can be added to two-digit integer less than 90, so that to have the sum 111 (if CD<90, so if C<9, CD+1Z<111).   Hence C=9.   Answer: 9.
Answer: D
The weights of three boys are in the ratio 4 : 5 : 6. If the sum of the weights of the heaviest and the lightest boy is 48 kg more than the weight of the third boy, what is the weight of the lightest boy?  Pick one.
A) 87 kg B) 38.4 kg C) 98.4kg D) 65.4 kg E) 87.4 kg

Solution: Let the weights of the three boys be 4k, 5k and 6k respectively.   4k + 6k = 5k + 48   => 5k = 48 => k = 9.6   Therefore the weight of the lightest boy   = 4k = 4(9.6) = 38.4 kg.   Answer:38.4 kg
Answer: B
A container holding 9 ounces of a solution that is 1 part alcohol to 2 parts water is added to a container holding 8 ounces of a solution that is 1 part alcohol to 3 parts water. What is the ratio of alcohol to water in the resulting solution? Choose the correct choice from the following
A) 2:5	B) 3:7	C) 3: 5	D) 5:12	E) 7:3

Solution: Container 1 has 9 ounces in the ratio 1:2   or,   x+2x=9 gives x(alcohol)=3 and remaining water =6   container 2 has 8 ounces in the ratio 1:3   or,   x+3x=8 gives x(alcohol)=2 and remaining water =6   mixing both we have alcohol=3+2 and water =6+6   ratio thus alcohol/water =5/12   Answer 5:12
Answer: D
A fruit seller sells mangoes at the rate of Rs.12 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 5%	Pick one:
A) Rs 8.82 B) Rs 9.82 C) Rs 10.82 D) Rs 14.82 E) None of these

Solution: Explanation:   85 : 12 = 105 : x   x= (12×105/85)   = Rs 14.82   Option Rs 14.82
Answer: D
Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?	Choose the correct choice from the following choices
A) 2500 m^2	B) 25	C) 2520 metre sq	D) 2540 m^2	E) 2590 m^2

Solution: Solving the two equations, we get: l = 63 and b = 40.   Area = (l x b) = (63 x 40) m2 = 2520 m ^2   2520 metre sq
Answer: C
How many numbers from 15 to 65 are exactly divisible by 5? Choose the correct choice from the following options.
A) 5 B) 7 C) 9 D) 10 E) 12

Solution: Option '10'    15/5= 
 15/5 = 3
3 and   65/5= 
  65/5 = 13
13==> 13-3= 
13-3 = 10
10 Numbers
Answer: D
3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
Choose the correct choice from the following answers:  A) 8  B) 10  C) 12  D) 18  E) 20

Solution: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days   So fodder will be available for  (60 + 8 + 12)= 
 (60 + 8 + 12) = 80
80 cows c 24x60 .0 .   for-^—=18 days.   18
Answer: D
A train 500m long takes 10 sec to cross a man walking at 6 kmph in a direction opposite to that of the train. Find the speed of the train?  Choose the correct answer: A) A)175kmph B) B)150kmph C) C)162kmph D) D)176kmph E) E)100kmph

Solution: Let the speed of the train be x kmph   Speed of the train relative to man = x+6 = (x+6)*5/18 m/sec   500/[(x+6)*5/18] = 10   10(x+6) = 1800   x = 176kmph   Answer is 176kmph
Answer: D
For a light that has an intensity of 60 candles at its source, the intensity in candles, S, of the light at a point d d feet from the source is given by the formula S=60k/d^2 60, where k is a constant. If the intensity of the light is 40 candles at a distance of 3 feet from the source, what is the intensity of the light at a distance of 20 feet from the source?
Options:
A) 3/10 candles  B) 9/10 candles  C) 1 1/3 candles  D) 2 candles  E) 3 candles

Solution: S= 60k/d^2   At 3 feet   40 = 60k/9 so k = 6   At 20 feet   S = 60 *6/20^2 = 9/10   9/10 candles
Answer: B
A boat goes 100 km downstream in 4 hours, and 75 Km upstream in 15 hours. The speed of the stream is?  Options
A) 10  B) 20  C) 25  D) 35  E) 15

Solution: 100 --- 10 DS = 25   ? ---- 1   75 ---- 15 US = 5   ? ----- 1 S = (25 - 5)/2= 
(25 - 5)/2 = 10
10 kmph.   10nswer:10
Answer: A
P and Q started a business investing Rs. 85,000 and Rs. 35,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively?  Choose the correct choice from the following choices
A) 17:6
B) 17:0
C) 17:7
D) 17:2
E) 17:3

Solution: P:Q = 85000 : 35000   = 17:7.   Answer: 17:7
Answer: C
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
A) 0	B) 1	C) 9	D) 10	E) 19

Solution: Average of 20 numbers = 0.   Sum of 20 numbers (0 x 20) = 0.   It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).   answer: option 19
Answer: E
A dice has one of the first 6 prime number on each its six sides ,with no two sides having the same number .the dice is rolled 10 times and the results added.the addition is most likely to be closet to  Select the correct option
A) 41  B) 48  C) 60  D) 68  E) 70

Solution: if die is rolled then avg score = (2+3+5+7+11+13 )/6 = 41/6   so, most likely sum for 10 times = 41/6 * 10 = 68   ANSWER:68
Answer: D
How much time will it take for an amount of 1800 to yield 81 as interest at 4.5% per annum of simple interest?
Choose the correct choice from the following options.
A) 3 years  B) 4 years  C) 2 years  D) 1 years  E) 7 years

Solution: Time = (100 x 81)/(1800 x 4.5) years = 1 years.   answer 1 years
Answer: D
The ratio between the number of sheep and the number of horses at the Stewart farm is 1 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm?
Choose the correct choice.
A) 18	B) 28	C) 32	D) 56	E) 8

Solution: Let the number of sheeps and horses be 1x and 7x.   Now total number of horses = total consumption of horse food/consumption per horse = 12880/230= 
12880/230 = 56
56, which is equal to 7x.=> x = 8   Sheeps = 1x = 1*8= 
1*8 = 8
8.   Hence 8
Answer: E
In how many ways can the letters of the word 'LEADER' be arranged?	Choices:
A) 360
B) 450
C) 455
D) 375
E) 480

Solution: The word 'LEADER' contains 6 letters, namely 1L, 2E, 1A, 1D and 1R.   Req = 6!/1!2!1!1!1! = 360   360NSWER 360
Answer: A
Two pipes A and B can fill a cistern in 12 and 15 minutes respectively. Both are opened together but after 1 minutes A is turned off. After how much more time will the cistern be filled?  Select:
A) 8 1/7	B) 8 1/1	C) 8 1/4	D) 8 1/2	E) 12 3/4

Solution: 1/12 + (1 + x)/15 = 1   x = 12 3/4   Answer: 12 3/4
Answer: E
A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 350. Find the total worth of the stock? Select the correct option:
A) 20029 B) 20000 C) 20289 D) 17500 E) 20026

Solution: Let the total worth of the stock be Rs. x.   The SP of 20% of the stock = 1/5 * x * 1.1 = 11x/50   The SP of 80% of the stock = 4/5 * x * 0.95 = 19x/25 = 38x/50   Total SP = 11x/50 + 38x/50 = 49x/50   Overall loss = x - 49x/50 = x/50   x/50 = 350 => x = 17500   Answer: 17500
Answer: D