MU-NLPC/Calc-aqua_rat huggingface dataset:
Mohit sold an article for Rs . 18000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? Pick:	A) Rs.15000	B) 15002	C) 26879	D) 26992	E) 12681

Solution: Let the CP be Rs. x.   Had he offered 10% discount, profit = 8%   Profit = 8/100 x and hence his SP = x + 8/100 x   = Rs. 1.08x = 18000 - 10/100(18000)   = 18000 - 1800 = Rs. 16200   => 1.08x = 16200   => x = 15000   Rs.15000nswer: Rs.15000
Answer: A
Nr Books bought Nr of People
5 7
6 3
7 3
8 2
What is the median of books bought per person?	Select:  A) a) 2  B) b) 4  C) c) 6  D) d) 8  E) e) 18

Solution: 5,5,5,5,5,5,5,6,6,6,7,7,7,8,8   so you will observer that the median of the list is 6.   Ans c) 6
Answer: C
A customer bought a product at the shop. However, the shopkeeper increased the price of the product by 20% so that the customer could not buy the required amount of the product. The customer managed to buy only 80% of the required amount. What is the difference in the amount of money that the customer paid for the second purchase compared to the first purchase?
Choose the correct choice from the following answers:
A) 10%	B) 8%	C) 6%	D) 4%	E) 2%

Solution: Let x be the amount of money paid for the first purchase.   The second time, the customer paid 0.8(1.2x)=0.96x.   The difference is 4%.   The answer is 4%.
Answer: D
For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the standard deviation for the exam? Options.
A) 7  B) 6  C) 8  D) 0  E) 2

Solution: Mean-2SD=58   Mean+3SD=98   By solving above equation we get,   SD (absolute value)=8   Ans. 8
Answer: C
A committee has 5 men and 5 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Choose one:
A) 127
B) 100
C) 882
D) 272
E) 323

Solution: The number of ways to select two men and three women   = ⁵C₂ * 5C₃   = (5 *4 )/(2 * 1) * (5 * 4 * 3)/(3 * 2)= 
(5 *4 )/(2 * 1) * (5 * 4 * 3)/(3 * 2) = 100
100   Answer: 100
Answer: B
The G.C.D of 1.08, 0.36 and 1.5 is  Pick:
A) 0.06  B) 0.1  C) 0.18  D) 0.11  E) 0.12

Solution: Explanation:   Given numbers are 1.08 , 0.36 and 1.5   H.C.F of 108, 36 and 150 is 6[because G.C.D is nothing but H.C.F]   therefore H.C.F of given numbers = 0.06   0.06nswer: 0.06
Answer: A
Company X sells a selection of products at various price points. Listed below are unit sales made for one particular day. How many unit sales on that day were greater than the mean sale price but less than the median sale price?
$50, $50, $97, $97, $97, $120, $155, $155, $199, $199, $219  Choose the correct choice from the following answers: A) 0 B) 1 C) 2 D) 3 E) 4

Solution: Taking the prices of products in ascending order(already arranged)   $50, $50, $97, $97, $97, $120, $125, $155, $199, $199, $219   we see that median value is the 6th value as there in total 11 values given   Arithmetic mean = total/number of entries = 1408/11= 
1408/11 = 128
128   We are asked to find how many unit sales on that day were greater than the mean sale price but less than the median sale price   as we can clearly see that there is one value between $120 and $128, answer is 1 unit   Correct Answer - 1
Answer: B
The average of 2,7,6 and x is 5 and the average of 18,1,6,x and y is 10. What is the value of y ?	Choose the correct choice:
A) 5	B) 10	C) 20	D) 30	E) 40

Solution: Answer C   Solution   We have :(2+7+6+X/4) = 5 or 15+x = 20 or x=5   Also, (18+1+6+X+Y/5) = 10 or 25+5+y = 50 or y=20. Answer 20
Answer: C
A bookseller has two display windows. She plans to display 4 new fiction books in the left window, and 5 new non-fiction books in the right window. Assuming she can put the five fiction books in any order, and separately, the three non-fiction books in any order, how many total configurations will there be for the two display windows?
Options.
A) 2400  B) 720  C) 2880  D) 336  E) 420

Solution: Two displays books could be arranged n! # of total arrangements are combinations multiplied together,   4!*5! =24*120= 
24*120 = 2_880
2880   Answer is 2880
Answer: C
The larger of two negative consecutive even integers 2t and 2(t-1) is multiplied by 6 and then added to the smaller of the two original integers. Which of the following represents this operation?
Choose the correct choice from the following answers:
A) 6t-2	B) 8t-2	C) 14t-2	D) 3	E) -2-4t^2

Solution: larger of 2t-2, 2t (when they are negative) is 2t. the smallest of 2t and 2t-2 when they are positive is 2t-2.   therefore 6* 2t + 2t-2 = 14t-2.   option 14t-2.
Answer: C
Number of ways in which the letters of word PARTI can be arranged with vowels in alphabetical order, is Choose the correct choice from the following answers
A) 60
B) 240
C) 120
D) 480
E) None of these

Solution: Solution   Order of vowels of fixed   âˆ´ required number of ways are 5!/2!.   60nswer 60
Answer: A
Each shelf of a bookcase contained 11 books. If the librarian took out 33 books and rearranged the remaining books so that all shelves but the last one contained 7 books and that last shelf contained 2 books, how many shelves does the bookcase have?  Choose one:
A) 5
B) 6
C) 7
D) 8
E) 9

Solution: Let x be the number of shelves.   11x - 33 = 7(x-1) + 2   4x = 28   x = 7   The answer is 7.
Answer: C
If 60 percent of the members of a certain organization are women and 6/8 of the members of the organization are married men, which of the following statements concerning the membership must be true? I. The number of women in the organization is greater than the number of married men in the organization. II. The number of women in the organization is greater than the number of unmarried men in the organization. III. The number of married men in the organization is greater than the number of unmarried men in the organization.  Choose the correct choice from the following answers:
A) II
B) III
C) I, II
D) I
E) II, III

Solution: 6/10 (60%) of the members are women and 6/8 of the members are married men. Let the total numbers of members is 80 (the LCM of 10 and 8). Then there are:    6/10*80= 
 6/10*80 = 48
48 women;    80 - 48= 
 80 - 48 = 32
32 men;     6/8*32= 
  6/8*32 = 24
24 married men;    32 - 24= 
 32 - 24 = 8
8 unmarried men.   So, option I,II is true.   Answer: I, II
Answer: C
The price of pulses has fallen by 20%. How many quintals can be bought for the same amount which was sufficient to buy 18 quintals at the higher price?  Choose the correct option:
A) 20
B) 22.5
C) 25
D) 30
E) 32.5

Solution: 80% of original price can buy = 18 quintals.   Therefore, he can buy ( 18 x 100 )/ 80 = 22.5 quintals at the lower price.   ANSWER:22.5
Answer: B
There are 6 boxes numbered 1, 2,3,4,5 and 6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball & the boxes containing green balls are consecutively numbered. The total no. of ways in which this can be done is?	Choices:
A) 18  B) 19  C) 21  D) 23  E) 25

Solution: If only one of the boxes has a green ball, it can be any of the 6 boxes. So, this can be achieved in 6 ways.   If two of the boxes have green balls and then there are 5 consecutive sets of 2 boxes. 12, 23, 34, 45, 56.   Similarly, if 3 of the boxes have green balls, there will be 4 options.   If 4 boxes have green balls, there will be 3 options.   If 5 boxes have green balls, then there will be 2 options.   If all 6 boxes have green balls, then there will be just 1 options.   Total number of options = 6 + 5 + 4 + 3 + 2 + 1= 
6 + 5 + 4 + 3 + 2 + 1 = 21
21   21
Answer: C
A, B and C enter into a partnership by investing $11000, $15000 and $23000 respectively. At the end of 8 months, B receives $3315 as his share. Find the share of A.  Answers
A) $1865 B) $2087 C) $2217 D) $2431 E) $2662

Solution: The ratio of capital of A, B and C = 11000 : 15000 : 23000 = 11 : 15 : 23   A's share = (11/15)*3315= 
(11/15)*3315 = 2_431
$2431   The answer is $2431.
Answer: D
A cubical tank is filled with water to a level of 2 feet. If the water in the tank occupies 50 cubic feet, to what fraction of its capacity is the tank filled with water?  Choose the correct choice from the following
A) 1/3  B) 2/3  C) 3/4  D) 2/5  E) 5/6

Solution: The volume of water in the tank is H*L*B = 50 cubic feet.   Since H = 2, then L*B = 25 and L = B = 5.   Since the tank is cubical, the capacity of the tank is   5*5*5= 
  5*5*5 = 125
125.   The ratio of the water in the tank to the capacity is 50/125= 2/5   The answer is 2/5.
Answer: D
5 is added to a certain number, the sum is multiplied by 7, the product is divided by 5 and 5 is subtracted from the quotient. The remainder left is half of 66. What is the number?  Select the correct option.
A) 21  B) 20  C) 22  D) 30  E) 45

Solution: Let number is X.   When 5 added to it,   = (X+5)   7 multiplied to sum,   = 7 *(X +5)   Now,   = [{7 *(X +5)} /5]   And,   = [{7 *(X +5)} /5] - 5   According to question,   [{7 *(X +10)} /5] - 5 = half of 66   [(7X + 35) /5) = 33 +5   7X + 35 = 38 *5   X = 155/7   X = 22.14=22   So, required number is: 22.   ANSWER : 22
Answer: C
In the accounting branch of a commercial institute, the percentage of male and female workers is 48% and 52% respectively. In this branch, 40% of males and 20% of females are age 25 or older. If one of the workers is selected at random, what is the probability Y that the worker is under 25 years old?	Choose the correct option
A) 0.30
B) 0.25
C) 0.45
D) 0.70
E) 0.90

Solution: Percentage of male worker = 48   Percentage of female worker = 52   Let total number of workers = 1000   number of male workers= 480   number of female workers = 520   Number of male age 25 or older = (4/10)*480= 
(4/10)*480 = 192
192   Number of female age 25 or older=(2/10)*520= 
(2/10)*520 = 104
104   Total number of workers 25 or older= 192+104= 
192+104 = 296
296   Total number of workers under 25= 1000 - 296= 
1000 - 296 = 704
704   Probability that a worker randomly selected is under 25 years old= 704/1000= 
704/1000 = 88/125 = around 0.704
.704   Alternatively , since the answer options are not close , we can use estimation here .   Percentage of male worker 25 or older= (4/10)*48 = 20 % approx   Percentage of female worker 25 or older = (2/10)*52 = 10 % approx   Percentage of total worker 25 or older = 30 %   Percentage of total worker under 25 = 70 %   Probability that a worker randomly selected is under 25 years old Y= .7   Answer 0.70
Answer: D
The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:
Choose the correct choice:
A) 9000	B) 9400	C) 9600	D) 9800	E) 7500

Solution: Explanation:   Greatest number of 4-digits is 9999.   L.C.M. of 15, 25, 40 and 75 is 600.   On dividing 9999 by 600, the remainder is 399.   Required number  (9999 - 399)= 
 (9999 - 399) = 9_600
9600.   ANSWER IS 9600
Answer: C
In an xy-coordinate plane, a line is defined by y = kx + 1. If (4, b), (a, 5), and (a, b+1) are three points on the line, where a and b are unknown, then k = ?  Options.
A) 1/2	B) 1	C) 3/4	D) 2	E) 5/2

Solution: b=4k+1...(1)   b+1=ak+1...(2)   5=ak+1...(3)   Taking (2) and (3)   5=b+1   b=4   Taking (1)   4=4k+1   k=3/4   Answer :3/4
Answer: C
A and B are partners in a business. A contributes 1/4 of the capital for 15 months and B received 2/3 of the profit. For how long B’s money was used?	Choose the correct choice from the following choices:
A) 4 months  B) 6 months  C) 8 months  D) 10 months  E) None

Solution: Sol.   Let the total profit be Rs. z. Then,   B’ share = Rs. 2z/3, A’s share = Rs. [z - 2z/3] = Rs. z/3   ∴ A : B = z/3 : 2z/3 = 1 : 2.   Let the total capital be Rs. x and suppose B’s money was used for x months. Then,   [1/4 x * 15] / [3/4 x * y] = 1/2 ⇔ y = [15 * 2 / 3= 
15 * 2 / 3 = 10
10.   Thus, B’s money was used for 10 months.   Answer 10 months
Answer: D
A searchlight on top of the watchtower makes 2 revolutions per minute. What is the probability that a man appearing near the tower will stay in the dark for at least 6 seconds?
Choose the correct choice from the following answers.
A) 5/6  B) 4/5  C) 3/4  D) 2/3  E) 1/2

Solution: The searchlight completes one revolution every 30 seconds.   The probability that the man's area will be lit up is 6/30=1/5.   The probability that he will stay in the dark is 1-1/5=4/5   The answer is 4/5.
Answer: B
Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:
Choose the correct choice from the following options:
A) lost 4 cents
B) broke even
C) gained 4 cents
D) lost 10 cents
E) gained 10 cents

Solution: B   broke even   20 % profit on $ 1.20   = $ 20/100 × 1.20   = $ 0.20 × 1.20   = $ 0.24   Similarly, 20 % loss on $ 1.20   = $ 20/100 × 1.20   = $ 0.20 × 1.20   = $ 0.24   Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.   Since both profit and loss amount is same so, it’s broke even.
Answer: B
what is the probability of always having x+y>0 ,where y<0  Choose the correct choice from the following choices
A) 1/2	B) 1/8	C) 3/4	D) 1/4	E) none

Solution: total value of X can be : 1. X < 0 ; 2. X = 0 ; 3. X > 0 but less than Y in magnitude 4. X > 0 as well as |Y|   so probability of having X + Y > 0 would be 1/4   ANSWER:1/4
Answer: D
According to the 2001 census,the population growth rate of Lucknow is going to be an increasing AP with first year's rate as 5% and common difference as 5% but simultaneously the migration,rate is an increasing GP with first term as 1% and common ratio of 2.If the population on 31 december 2000 is 1 million,thn find in which year will Lucknow witness its first fall in population?
Pick one.
A) 2006 B) 2007 C) 2005 D) 2008 E) 2009

Solution: population growth rate according to the problem   year 1 = 5%   year 2 = 10%   year 3 = 15%   year 4 = 20%   year 5 = 25%   year 6 = 30%   population decrease due to migration   year 1 = 1%   year 2 = 2%   year 3 = 4%   year 4 = 8%   year 5 = 16%   year 6 = 32%   Thus, the first fall would happen in year 2006   2006NSWER:2006
Answer: A
In a game of billiards, A can give B 20 points in 60 and he can give C 30 points in 60. How many points can B give C in a game of 100? Choose the most appropriate option:	A) 43	B) 54	C) 25	D) 86	E) 23

Solution: A scores 60 while B score 40 and C scores 30.   The number of points that C scores when B scores 100   = (100 * 30)/40 = 25 * 3= 
25 * 3 = 75
75.   In a game of 100 points, B gives (100 - 75)= 
(100 - 75) = 25
25 points to C.   Answer: 25
Answer: C
For any two numbers X and Y , define X#Y=X+Y -XY . If X,Y>0.5, then X#X < Y#Y if
i. 1>X>Y
ii. 1>Y>X
iii. Y>X>1
Choose the correct option
A) i only	B) option ii only	C) i and ii only	D) ii and iii only	E) i and ii only

Solution: X#X = 2X-X^2 and Y#Y=2Y-Y^2   X#X <Y#X   => 2X - X^2 < 2Y - Y^2   => 2(X-Y) < (X-Y)(X+Y)   => X+Y>2 and X-Y>0 or X+Y<2 and X-Y<0   => X+Y>2 and X>Y or X+Y<2 and X<y (i),="" 1="" if="" using="">X>Y, then the first case applies but X+Y>2 is not satisfied. False.   Using (ii), if 1>Y>X, then the second case applies and X+Y<2 is satisfied. True.   Using (iii), if Y>X>1, then the second case applies but X+Y<2 is not satisfied. False.   Therefore only (ii) is true, and choice (option ii only) is correct.</y>
Answer: B
Car Z travels 50 miles per gallon of gasoline when driven at a constant rate of 45 miles per hour, but travels 20 percent fewer miles per gallon of gasoline when driven at a constant rate of 60 miles per hour. How many miles does car Z travel on 10 gallons of gasoline when driven at a constant rate of 60 miles per hour? Select.
A) 320
B) 375.2
C) 400
D) 408.3
E) 440

Solution: The question stem asks us for the distance possible with 10 gallons of fuel at a constant speed of 60 miles per hour. We therefore first calculate the fuel efficiency at that speed.   The stem tells us that at 50 miles/hour, the car will run 40 miles/gallon and at 60 miles/hour, that distance decreases by 20%. We can therefore conclude that the car will travel 40 miles/gallon at a constant speed of 60 miles/gallon. With 10 gallons of fuel, the car can therefore travel 40 miles/gallon * 10 gallons = 400 miles.   Answer 400.
Answer: C
How many positive integers will divide evenly into 310? Choose the correct option.
A) 4
B) 6
C) 8
D) 12
E) 16

Solution: The question is asking how many factors 310 has.   310 = 2*5*31   The number of factors is 2^3 = 8   The answer is 8.
Answer: C
Divide Rs. 1700 among A, B and C so that A receives 1/3 as much as B and C together and B receives 2/3 as A and C together. A's share is?	Choose one.
A) 346	B) 425	C) 375	D) 337	E) 639

Solution: A+425+C = 1700   A = 1/3(425+C); 425 = 2/3(A+C)   A/(425+C) = 1/3   A = 1/4 * 1700= 
1/4 * 1700 = 425
> 425   Answer:425
Answer: B
A person traveled from his house to office at 30 kmph; then he was late to his office by 5 minutes. If he increases his speed by 10 kmph he would be early by 15 minutes to his office. What should be his speed so that he reaches his office on time ?
Select the correct option:
A) 36 kmph
B) 32 kmph
C) 34 kmph
D) 35 kmph
E) 37 kmph

Solution: Let the distance between house and office be x km   (x/30) – (x/40) = 20/40; x/120 = 1/3 x = 40 km   Travlling at 40 kmph, he reaches office in 1 hour i.e. 15 minutes early   So required speed = 40/ 5/4 = 40 * 4/5   = 160/5= 
160/5 = 32
32 kmph   ANSWER:32 kmph
Answer: B
Which of the options below is the lowest interger divisible by all the numbers below: 1,2,3,4,5,6,7,8,9,10  Choose the most appropriate option
A) 234 B) 1222 C) 2520 D) 2894 E) 1430

Solution: To get the least positive integer that can be divided by each of these numbers 1,2,3,4,5,6,7,8,9,10 you calculate the lowest common denominator of all the numbers. Express each number as a product of their prime factors and multiply the set of prime numbers from each set with the highest exponent value.   L2520M=2^3*3^2*5*7   The answer is 2520)
Answer: C
If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 12, respectively, what is the probability that b/a will not be an integer? Choose the correct choice from the following choices:
A) 2/12
B) 3/12
C) 4/12
D) 1/2
E) 2/3

Solution: a is from the following set {1,2,3,4}   b is from the following set {12,14,16}   The total number of ways of choosing 2 integers, one from each set is  4*3= 
 4*3 = 12
12 ways.   The possibilities where b/a is not an integer is for the following outcomes:   {b,a}= {14,3},{14,4},{16,3} = 3 ways   Thus the probability is 3/12 = 1/4   The answer is 3/12.
Answer: B
If def < 0 and ef > 0, which of the following must be positive? Choose the correct answer:
A) xy
B) xz
C) (d^2)ef
D) d(e^2)f
E) xy(z^2)

Solution: Given that ef is positive and def is negative, you can say that a MUST be negative. As for e and f either they are both positive or both negative.   Option (C) has d^2 which is positive and ef which is positive. So ((d^2)ef) must be positive.
Answer: C
Jim bought edging to go around a circular garden with a radius of 10 feet. Later he decided to
double the diameter of the garden. How many more feet of edging must he buy?  Pick one.
A) 28.84' additional edging	B) 48.84' additional edging	C) 38.84' additional edging	D) 62.80' additional edging	E) 58.84' additional edging

Solution: circumference of small garden = 2 x 3.14 x 10 = 62.80'   double of the circumference of small garden = 2 x 62.80' = 125.60'   More feet to be buy =125.60 - 62.80= 
125.60 - 62.80 = 62.8
62.80   Answer :62.80' additional edging
Answer: D
The sum of the present ages of two persons A and B is 90. If the age of A is twice that of B, find the sum of their ages 5 years hence?
Choose the correct option
A) 50
B) 60
C) 70
D) 80
E) 100

Solution: A + B = 90, A = 2B   2B + B = 90 => B = 30 then A = 60.   5 years, their ages will be 65 and 35.   Sum of their ages = 65 + 35= 
65 + 35 = 100
100.   ANSW100R:100
Answer: E
The area of circle O is added to its diameter. If the circumference of circle O is then subtracted from this total, the result is 10. What is the radius of circle O?  Choose the correct choice from the following options
A) –2/pi
B) 2
C) 3
D) 4
E) 5

Solution: pi*r^2 + 2r -2*pi*r = 10   Simplifying the equation: pi*r(r-2)+2r=10   Without much algebraic: We can Test the answers quickly, then 5 is the only possible answer that will eliminate pi from equation.   Answer is 5
Answer: E
On a certain road 10% of the motorists exceed the posted speed limit and receive speeding tickets, but 24% of the motorists who exceed the posted speed limit do not receive speeding tickets. What percent of the motorists on the road exceed the posted speed limit?  Pick one
A) 10.5% B) 13.2% C) 15% D) 22% E) 30%

Solution: Answer is B.   This question is in the OG and thus well explained by ets.   those who exceed : X   so X = 10%+0,24X   id est X = 13.2%
Answer: B
The average age of students in section A of 124 students is 22 years and the average age of students in section B of 145 students is 32 years. Find the average age of students in both sections taken together?	Choose the correct option.
A) 27 years  B) 30years  C) 15years  D) 25years  E) 20years

Solution: The required average = (124*22+145*32)/124+145 = 27 years   27 yearsnswer is 27 years
Answer: A
How many pieces of 85 cm length can be cut from a rod of 29.75 meters long?	Pick.
A) 55  B) 45  C) 35  D) 25  E) 15

Solution: Number of pieces = 2975/85= 
2975/85 = 35
35   The answer is 35.
Answer: C
26 An uneducated retailar marks all its goods at 50% above the cost price and thinking that he will still make 25% profit,offers a discount of 25% on the marked price.what is the actual profit on the sales? Choose the correct choice
A) 5%  B) 10.50%  C) 9.50%  D) 12.50%  E) 10%

Solution: Let C.P =Rs 100.then ,marked price =Rs100   S.P=75% of Rs 150=Rs112.50   Hence,gain%=12.50%   Answer is 12.50%.
Answer: D
The length of a room is 5.5 m and width is 3.75 m. What is the cost of paying the floor by slabs at the rate of Rs. 800 per sq. meter.  Pick one.
A) Rs.12000  B) Rs.19500  C) Rs.18000  D) Rs.16500  E) Rs.17500

Solution: Explanation:   Area =5.5×3.75 sq. metre.   Cost for 11 sq. metre. = Rs.800   Hence, total cost   =5.5×3.75×800=5.5×3000   = Rs.16500   Answer: Option Rs.16500
Answer: D
In six successive games, a baseball team scored 1 runs once, 4 runs twice, and 5 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period? Choose the correct choice:	A) 8	B) 7	C) 6	D) 5	E) 4

Solution: 1 runs once (one game)   4 runs twice (two game)   5 runs three times (three games)   SO we have (1*1 + 4*2 + 5*3)/6 = 24/6= 
24/6 = 4
4.   ANS: 4.
Answer: E
Your town has a population of 1260. Every three people have a car. How many cars are in your town? Choose the correct answer
A) 400  B) 410  C) 420  D) 430  E) 450

Solution: Every three person has a car, then the number of cars in the town could be calculated by the division of number of people over the person-to-car ratio.   the number of cars in the town=1260/(3/1)=1260/3= 
1260/3 = 420
420 cars   So the correct choice is 420
Answer: C
Tough and Tricky questions: Work/Rate Problems.
A group of 4 junior lawyers require 7 hours to complete a legal research assignment. How many hours would it take a group of three legal assistants to complete the same research assignment assuming that a legal assistant works at two-thirds the rate of a junior lawyer?
Source: Chili Hot GMAT
Choose the most appropriate option:
A) 14
B) 10
C) 9
D) 6
E) 5

Solution: # of people times the # of hours:   4*7= 
4*7 = 28
28 --> 4 lawyers do 28 worksin 7 hours.   3*14/3= 
3*14/3 = 14
14 --> 3 assistants do 14worksin 4 hours   So, since the amount of work the assistants do is half the work the lawyers do, the time will be double, so14NS 14
Answer: A
The mass of 1 cubic meter of a substance is 500 kg under certain conditions. What is the volume in cubic centimeters of 1 gram of this substance under these conditions? (1 kg =1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters)
Choices:
A) 0.1	B) 0	C) 1	D) 2	E) 3

Solution: 500 kg - 1 cubic meter;   500,000 g - 1 cubic meter;   500,000 g - 1,000,000 cubic centimeters;   1 g - 1,000,000/500,000 = 10/5= 
10/5 = 2
2 cubic centimeters.   Answer: 2.
Answer: D