MU-NLPC/Calc-aqua_rat huggingface dataset:
What is the percentage increase in the area of a rectangle, if each of its sides is increased by 20%? Choose the most appropriate option:
A) 42%	B) 43%	C) 45%	D) 44%	E) 46%

Solution: Let original length =l   original breadth =b   Then original area =lb   Length is increased by 20%   ⇒ New length =l×120100=1.2l   Breadth is increased by 20%   ⇒ New breadth =b×120100=1.2b   New area =1.2l×1.2b=1.44lb   Increase in area = new area - original area   =1.44lb−lb=0.44lb   Percentage increase in area   =increase in areaoriginal area×100=0.44lblb×100=44%   Answer is 44%.
Answer: D
In a class,7 students like to play Basketball and 8 like to play Cricket. 3 students like to play on both Basketball and Cricket. How many students like to play Basketball or Cricket or both?	Choose the correct choice from the following answers.
A) 12  B) 15  C) 16  D) 18  E) 22

Solution: Draw a Venn Diagram yourself !   B + C - BC = Number of students that play either Basketball or Cricket   7 +8 - 3= 
7 +8 - 3 = 12
12   12)
Answer: A
The second of two numbers is two less than three times the first. Find the numbers if there sum is
66. Choose the correct option:
A) 7-19 B) 8-20 C) 10-16 D) 17-49 E) 19-55

Solution: We are looking for two numbers.   #1 - x   #2 - 3x â€“ 2   The sum is 66. #1 + #2 = 66   Substituting x + 3x â€“ 2 = 66   4x â€“ 2 = 66   4x = 68   x = 17   The first number is 17, the second number is two less than three times 17 or 49.   correct answer 17-49
Answer: D
If 1/2 of the air in a tank is removed with each stroke of a vacuum pump, what fraction of the original amount of air has been removed after 5 strokes ?
Choices: A) 31/32 B) 7/8 C) 1/4 D) 1/8 E) 1/16

Solution: Left 31/32fter 1st stroke = 1/2   Left 31/32fter 2nd stroke = 1/2 * 1/2 = 1/4   Left 31/32fter 3rd stroke = 1/2 * 1/4 = 1/8   Left 31/32fter 4th stroke = 1/2 * 1/8 = 1/16   Left 31/32fter 5th stroke = 1/2 * 1/16 = 1/32   So removed = 1- 1/32 = 31/32
Answer: A
John left home and drove at the rate of 55 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive?
Choose the correct choice:	A) 235 miles.	B) 245 miles.	C) 255 miles.	D) 265 miles.	E) 275 miles.

Solution: The total distance D traveled by John is given by   D = 55 * 2 + 3 * 55= 
55 * 2 + 3 * 55 = 275
275 miles.   Answer 275 miles.
Answer: E
Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 72 sec. The length of each train is?  Choose the correct choice from the following answers: A) 50 B) 26 C) 27 D) 28 E) 100

Solution: Let the length of each train be x m.   Then, distance covered = 2x m.   Relative speed = 46 - 36= 
46 - 36 = 10
10 km/hr.= 10 * 5/18 = 25/9 m/sec.   2x/72 = 25/9 => x = 100.   Answer: 100
Answer: E
The original price of a certain TV set is discounted by g percent, and the reduced price is then discounted by 2g percent. If P is the original price of the TV Set, which of the following represents the price of the television set after the two successive discounts?	Choose the correct choice from the following answers:  A) P(1 - 0.03x + 0.02x^2)  B) P(1 - 0.03g + 0.0002g^2)  C) P(1 - 0.03x + 0.002x^2)  D) P(1 - 2x^2)  E) P(1 - 3x + 2x^2)

Solution: Youcansolve this problem with number plugging.   Say the original price was $10 and g=50. Then after the first reduction the price would become $5 and after the second reduction of   2*50= 
  2*50 = 100
100% the rprice would become $0.   Now, since P is not zero, then the expression in the brackets must be zero for g=50. Only answer choice B works.   Answer: B.   On this problem - number pluggin is not giving me the answer.. I initially used g = 10, then g = 20 and P = 100. Answer should after both consecutive discounts = 72. I plug in the respective values and I keep getting 68. Can you double check my math.   100 (1-0.03(10) + 0.0002 (10)^2)   100 (1-0.3 + 0.0002 (100))   100 (0.7 + 0.02)   100 (0.68) = 68????   double check my math. Am I missing something? I also plugged in your numbers and still did not get zero as final answer with choice P(1 - 0.03g + 0.0002g^2)..
Answer: B
The sum of ages of 5 children born at the intervals of 3 years each is 55 years. What is the age of the youngest child? Choose the correct answer: A) 5 years B) 4 years C) 6 years D) 7 years E) 8 years

Solution: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.   Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 55   5x = 25   x = 5.   Age of the youngest child = x = 5 years.   5 years)
Answer: A
An alloy of copper and zinc contains copper and zinc in the ratio 5 : 4. Another alloy of copper and zinc contains copper and zinc in the ratio 3 : 6. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc? Choose the correct choice from the following: A) 4 : 1 B) 6 : 1 C) 1 : 3 D) 2 : 1 E) 4 : 1

Solution: Let Alloy_1 be x units, and let Alloy_2 be y units.   So, fraction of copper in Alloy_1 = 5x/9, and fraction of zinc in Alloy_1 = 4x/9.   Similarly, fraction of copper in Alloy_2 = 3y/9, and fraction of zinc in Alloy_2 = 6y/9.   Mixing them, we get   copper = 5x/9 +3y/9; zinc = 4x/9 + 6y/9   So, 5x+3y = 4x+6y   -> x = 3y   -> x/y =1/3   So, they must be mixed in the ratio 1 : 3   Answer : 1 : 3
Answer: C
A salesperson receives a base salary of $1000 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 290 items for $150 each, what will her monthly salary be?  Choose the correct choice from the following options
A) $1,500
B) $1,800
C) $2,100
D) $3,700
E) $2,800

Solution: Ans : 1000+ 7.5 % * 150 * (290-50) = $ 3700   ANSWER:$3,700
Answer: D
In how many years will a sum of Rs 800 and 10% per annum completed semiannually becomes Rs.926.10?  Options
A) 1 years B) 2 years C) 1 years 6 months D) 2 years 6 months E) 3 years

Solution: 800 ------------->926.10926.10-800=126.10Ist six month =40IInd 6 month=40+2= 
40+2 = 42
42IIIrd 6 month=40+4.1= 
40+4.1 = 44.1
44.140+42+44.1=126.1Answer 1 years 6 months
Answer: C
The sum of the even numbers between 1 and n is 95*96, where n is an odd number, then n=?	Select the correct option
A) 167
B) 175
C) 183
D) 191
E) 199

Solution: Let n-1 = 2a.   2+4+...+2a = 2*(1+2+...+a) = 2*(a)(a+1)/2 = (a)(a+1) = 95*96   Then a = 95 and n = 191.   The answer is 191.
Answer: D
A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is? Choose the correct choice from the following:  A) 41 sec  B) 42 sec  C) 43 sec  D) 48 sec  E) 47 sec

Solution: 48 sec   48 sec   48 sec = 540 + 180= 
540 + 180 = 720
720   S= 54 * 5/18= 
54 * 5/18 = 15
15 mps   T= 720/15= 
720/15 = 48
48 sec
Answer: D
If the average (arithmetic mean) of a list of numbers is 12 and the standard deviation of that list of numbers is 1.3, then which of the following numbers is more than two standard deviations from the mean?
I. 14.3
II. 12.3
III. 9.2
Answers
A) I only
B) I and II only
C) II only
D) III only
E) I and III only

Solution: Mean = 12   SIII only = 1.3   2 SIII only above mean = 12+2*1.3= 
12+2*1.3 = 14.6
14.6   2 SIII only below mean= 12-2*1.3= 
12-2*1.3 = 9.4
9.4   12.3 and 14.3 lies in the range of 2SIII only from mean   Answer: Option III only
Answer: D
For 2consecutive yrs, my incomes are in the ratio of 4:7 and expenses in the ratio of 3:5. If my income in the 2nd yr is Rs. 42000 & my expenses in the first yr in Rs.21000, my total savings for the two-year is  Options
A) Rs. 8000  B) Rs. 9000  C) Rs. 9900  D) Rs. 98900  E) Rs. 10000

Solution: Sol. Income in first year = * x 42000 = Rs. 24000   Expenses in second year = \ x 21000 = Rs. 35000 Total savings = Total income - Total expenses = (42000 + 24000)- (21000 + 35000)   = 66000 - S6000 = Rs. 10000   Rs. 10000
Answer: E
What is the ratio R of the surface area of a cube to the surface area of a rectangular solid identical to the cube in all ways except that its length has been doubled? Choose the correct choice.
A) 1/4 B) 3/8 C) 1/2 D) 3/5 E) 2

Solution: Let X be the side of the cube. Therefore X^2*6= surface area.   the rectangle is the same other than length is 2X. The width and height are the same as the cube. 2*W*H+2*W*L+2*H*L= 2X^2+4X^2+4X^2= 10X^2.   6X^2/10X^2 = 3/5= R.   Answer = 3/5
Answer: D
The length of the rectangular field is double its width. Inside the field there is square shaped pond 8m long. If the area of the pond is 1/8 of the area of the field. What is the length of the field?	Select the correct option.
A) 22
B) 32
C) 44
D) 66
E) 88

Solution: A/8 = 8 * 8 => A = 8 * 8 * 8   x * 2x = 8 * 8 * 8   x = 16 => 2x = 32 .Answer: 32
Answer: B
Plane leaves from Chelsea every 30 minutes from West Ham airport. Air hostess told Frank Lampard that the plane had left 25 minutes ago and the next plane for Chelsea will leave at 7:00 p.m.
At what time air hostess convey this information to Frank Lampard?	Choose the correct choice from the following choices
A) 5:35 p.m  B) 6:55 p.m  C) 7:35 p.m  D) 8:55 p.m  E) 9:35 p.m

Solution: Explanation:   Time of Frank Lampard last missed plane = 7:00 p.m - 30 min = 6:30 p.m   As this information has been given to Frank Lampard 25 minutes after the plane has already left, the air hostess gave the information at 6:30 p.m + 25 min = 6:55 p.m   Answer 6:55 p.m
Answer: B
The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the numbers is 77,find the other.  Choose the correct choice from the following answers.
A) 99
B) 88
C) 77
D) 66
E) 55

Solution: Other number = 11 X 693/77 = 99   99nswer is 99.
Answer: A
Three models (F, G, and H) of cars are distributed among three showrooms. The number of cars in each showrooms must be equal and each model must be represented by at least one car in every showroom. There are 19 cars of Model F, 17 cars of Model G, and 15 cars of Model H. What is the maximum number of cars of model F in any showroom ?
Choose the correct choice from the following answers
A) 17 B) 16 C) 15 D) 14 E) 13

Solution: The total number of cars is 51. So each showroom has 17 cars(since the number of cars in each showrooms should be equal   51/3= 
  51/3 = 17
17).   Moreover that the number of model F is maximum means that the numbers of model G and H should be minimum. Since each model must be represented by at least one car in every showroom that minimum number should be 1.   So Maximum number of model F is   17-2= 
  17-2 = 15
15.   The answer is (15)
Answer: C
In a question on division with zero remainder, a candidate took 20 as divisor instead of 10. The quotient obtained by him was 35. The correct quotient is?	Choose the correct choice from the following answers: A) A)70 B) B)24 C) C)28 D) D)29 E) E)30

Solution: Number = (35 * 20)= 
(35 * 20) = 700
700   Correct quotient= 700/10= 
700/10 = 70
70   70)
Answer: A
The 46th digit after the decimal in the decimal expansion of 11996 is
Choose the correct choice from the following choices
A) 0 B) 1 C) 4 D) 6 E) 8

Solution: Let dj denote the jth digit of 1/1996 after the decimal. In other words, we write   1/1996=0.d1d2d3....The problem is to determine d46. Observe that   (*)   10in45*1/1996=d1d2d3...d45d46d47...   We compute 1045 modulo 1996. Since 1996 5 = (2000 - 4) 5 = 104 -20, we get   that 104* 20 (mod 1996). Since 1996 4 = (2000- 4) 4 = 8000 - 16, we obtain   1012*(104)3 *203 * 8000*6 (mod 1996). Continuing in this manner, we get 1036 *   (1012)3* 16*212 * 4096 * 104 (mod 1996), 1044* 1036 104 104 *104 20 20 *   2080 20*84 20 * 1680 (mod 1996), and 1045 * 1044 10* 16800* 8 (1996 +   4) + 800 * 832 (mod 1996). This means that the remainder when we divide 1045 by 1996   is 832. If q denotes the quotient, we deduce that   1045/1996= q +832/1996= q.4168...   where the digits after the decimal are computed by long division. We are only interested   in the first of these, the digit 4 since it follows from () that this digit must be d46.   correct answer 4
Answer: C
The probability of Sam passing the exam is 1/4. The probability of Sam passing the exam and Michael passing the driving test is 1/5. What is the probability of Michael passing his driving test?	Choose the correct choice from the following options: A) 1/24. B) 1/2. C) 1/3. D) 2/3. E) 4/5

Solution: 1/4 *1/m= 1/5 , 1/m = 4/5   Answer 4/5
Answer: E
A type W machine can complete a job in 5 hours and a type B machine can complete the job in 7 hours. How many hours will it take 2 type W machines and 3 type B machines working together and independently to complete the job?
Select the correct option:
A) 1/5
B) 29/35
C) 5/6
D) 35/29
E) 35/12

Solution: now D should be the answer.   W need 5 hours to complete   and B needs 7 hours to compete   so 2W + 3B will complete 2/5 + 3/7 or 29/35 portion of the job in 1 hour   so the whole job will take 35/29 hours....=35/29
Answer: D
A and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work?	Choose the correct choice.
A) 12 days
B) 9 days
C) 6 days
D) 5 days
E) 8 days

Solution: Sol. (A + B)'s 1 day's work = (1/4). A's 1 day's work = (1/12)   B's 1 day's work =((1/4)-(1/12))=(1/6)   Hence, B alone can complete the work in 6 days.   Ans: 6 days
Answer: C
One year ago, the ratio of Gaurav' and Sachin's age was 6 : 7 respectively Four years hence , this raio would become 7 : 8. How old is Sachin ?  Options:
A) 34 years B) 36 years C) 37 years D) 38 years E) 39 years

Solution: Explanation :   Sol Let Gaurav's and Sachins ages one year ago be 6xand7x6xand7x 7ears respectively . Then   Gaurav's age 4 years hence = (6x+1) +4=(6x+5)(6x+1) +4=(6x+5) years   Sachin's age 4 years hence = (7x+1)+4=(7x+5)(7x+1)+4=(7x+5) years.   6X+5 / 7X+5 =7/8   â‡” 8(6x+5)= 7(7x+5)   â‡” 48x+40=49x+35   â‡” x=5   Hence , Schin's present age = (7x+1)(7x+1) = 36 years.   ANSWER IS 36 years
Answer: B
Marge has E candies, where E is an integer such that 20 <E< 50. If Marge divides the candies equally among 5 children, she will have 2 candies remaining. If she divides the candies among 6 children, she will have 1 candy remaining. How many candies will remain if she divides the candies among 7 children? Pick one
A) 0	B) 1	C) 2	D) 3	E) 4

Solution: If Marge divides the candies equally among 5 children, she will have 2 candies remaining.   This tells us that the candies are of 5x + 2 type and so 22, 27, 32, 37, 42, or 47   If she divides the candies among 6 children, she will have 1 candy remaining.   this tells us it is if 6x+1 type and so 25, 31, 37, 43, or 49   ONLY 37 is common, so candies are 37 in number..   if 37 is divided in 7 kids, remainder E= 2   2
Answer: C
Sound is said to travel in air at about 1100 feet per second. A man hears the axe striking the tree, 11/5seconds after he sees it strike the tree. How far is the man from the wood chopper?
Choices:	A) 2420 ft	B) 2810 ft	C) 1800 ft	D) 1820 ft	E) None of these

Solution: Explanation:   Speed of the sound = 1100 ft/s   Time = 11/5 second   Distance = Speed × Time = 1100 ×11/5 = 220 × 11= 2420 ft   2420 ftnswer: Option 2420 ft
Answer: A
Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is
Select the correct option
A) 1/7
B) 1/9
C) 1/6
D) 1/4
E) 1/2

Solution: Explanation:   One person can select one house out of 3= \inline {\color{Black}3C_{1}} ways =3.   Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.   Therefore, probability that all thre apply for the same house is 1/9   Answer: 1/9) 1/9
Answer: B
Tom planted vegetables in a rectangular garden that was 27 feet long and 15 feet wide. He used
1/3 of the area for corn and 1/5 of it for peas. How many square feet are left for other vegetables?  Answers.
A) 185 sq. ft.
B) 186 sq. ft.
C) 187 sq. ft.
D) 188 sq. ft.
E) 189 sq. ft.

Solution: area of garden is 27 x 15 = 405 sq. ft.   1/3 x 405 = 135 sq. ft. for corn   1/5 x 405 = 81 sq. ft. for peas   135 + 81= 
135 + 81 = 216
216 sq. ft. used     405 - 216= 
  405 - 216 = 189
189 sq. ft. left over   correct answer 189 sq. ft.
Answer: E
A dog breeder currently has 9 breeding dogs. 6 of the dogs have exactly 1 littermate, and 3 of the dogs have exactly 2 littermates. If 2 dogs are selected at random, what is the probability E that both selected dogs are NOT littermates?	Pick one.
A) 1/6
B) 2/9
C) 5/6
D) 7/9
E) 8/9

Solution: We have three pairs of dogs for the 6 with exactly one littermate, and one triplet, with each having exactly two littermates.   So, in fact there are two types of dogs: those with one littermate - say A, and the others with two littermates - B.   Work with probabilities:   Choosing two dogs, we can have either one dog of type B or none (we cannot have two dogs both of type B).   The probability of choosing one dog of type B and one of type A is 3/9 * 6/8 * 2 = 1/2 (the factor of 2 for the two possibilities BA and AB).   The probability E of choosing two dogs of type A which are not littermates is 6/9 * 4/8 = 1/3 (choose one A, then another A which isn't the previous one's littermate).   The required probability is 1/2 + 1/3 = 5/6.   Find the probability for the complementary event: choose AA or BB.   Probability of choosing two dogs of type A who are littermates is 6/9 * 1/8 = 1/12.   Probability of choosing two dogs of type B (who necessarily are littermates) is 3/9 * 2/8 = 1/12.   Again, we obtain 1 - (1/12 + 1/12) = 5/6.   Answer: 5/6
Answer: C
Two pipes P and Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 6 minutes the first is turned off. How many more minutes will it take for the cistern to fill after the first pipe is turned off?
Choose the correct choice from the following choices:  A) 1  B) 1.5  C) 2  D) 2.5  E) 3

Solution: Let x be the total time it takes for the cistern to fill.   6/12 + x/15 = 1   x/15 = 1/2   x = 7.5   After the first pipe is turned off, it takes 1.5 more minutes to fill the cistern.   The answer is 1.5.
Answer: B
Two friends C and D leave point C and point D simultaneously and travel towards Point D and Point C on the same route at their respective constant speeds. They meet along the route and immediately proceed to their respective destinations in 32 minutes and 50 minutes respectively. How long will D take to cover the entire journey between Point D and point C?
Choose the correct choice from the following answers:	A) 90	B) 80	C) 75	D) 60	E) 65

Solution: Let x per minute be the speed of C and y per minute be the speed of D.   After meeting at a point, C travels for 32 mins and D travels for 50 mins. So distance covered by each of them post point of crossing   C= 32x and D=50y   The distance covered by C and D before they cross each would be distance covered by D and C post crossing respectively.   Therefore distance covered by D before he meets C= 32x   Time taken by D cover 32x distance= 32x/y mins   Therefore total time taken by D= 32x/y + 50 mins ................. I   We need to find value of x in terms of y to arrive at final answer.   Total distance= 32x+50y   Combined speed of C and D= x+y   Therefore time taken before C and D meet en-route= (32x+50y)/(x+y)   Time taken by D reach destination after meeting C= 50 mins   Total travel time for D= [(32x+50y)/(x+y)]+50 mins ...................II   Equate I and II   32x/y+50= [(32x+50y)/(x+y)]+50   (32x+50y)/y=(82x+100y)/(x+y)   32x^2+50xy+32xy+50y^2=82xy+100y^2   32x^2+82xy-82xy+50y^2-100y^2=0   32x^2-50y^2=0   32x^2=50y^2   16x^2=25y^2   Taking square root.. (since x and y denote speed, square root can't be negative)   4x=5y   y=4x/5 ............ III   substitute in I   =32x/(4x/5) + 50   =32x*5/4x + 50   =40+50= 
40+50 = 90
90 mins   90
Answer: A
if there is one larger cube with volume 1000 and no. of smaller cubes with volume 8.then how many small cubes are required to make a larger cube with volume of 600?  Choose the correct choice from the following answers:	A) 5	B) 10	C) 125	D) 100	E) 4

Solution: the ratio between larger and smaller is   a13:a23=1000:8   a1:a2=10:2   then length of cube is 10 and 2   so make a cube with length 10, we have to 5 small cubes each in length, breadth and height. so total 125 cubes are required.   then the answer is 125
Answer: C
Two stations P and Q are 155 km apart on a straight track. One train starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will they meet?  Choose the correct choice:
A) 10 am
B) 12 am
C) 10.30 am
D) 12.30 am
E) 11 am

Solution: Assume both trains meet after x hours after 7 am   Distance covered by train starting from P in x hours = 20x km   Distance covered by train starting from Q in (x-1) hours = 25(x-1)   Total distance = 155   => 20x + 25(x-1) = 155   => 45x = 180   => x= 4   Means, they meet after 3 hours after 7 am, ie, they meet at 11 am   Answer is 11 am.
Answer: E
Anil purchased 30 kg of wheat at the rate of Rs. 22 per kg and 20 kg of wheat at the rate of Rs. 24 per kg. He mixed the two. Approximately at what rate per kg should he sell the mixture to make 25% profit?  Pick one:
A) Rs. 28 B) Rs. 29 C) Rs. 26 D) Rs. 282 E) Rs. 21

Solution: Explanation:   Total quantity of mixture = 30 + 20= 
30 + 20 = 50
50 kg.   By earning a profit of 25% on the total cost, the selling price of the mixture is   125/100 * (660 + 480= 1140) = Rs. 1425   Selling price per kg = Total selling price / Total of mixture   = 1425 / 50   = Rs. 28.5   Rs. 28NSWER: Rs. 28
Answer: A
A football player scores 2 goals in his fifth match thus increasing his average goals score by 0.1. The total number of goals in his 5 matches would be Select the correct option: A) 4 B) 6 C) 8 D) 10 E) 12

Solution: While this question can be solved with a rather straight-forward algebra approach (as the other posters have noted), it can also be solved by TESTing THE ANSWERS. One of those numbers MUST be the total number of goals...   From a tactical standpoint, it's best to TEST either Answer B or Answer D, so if the answer is not correct, then you would have a gauge for whether you should gohigherorlowerwith your next TEST.   Here, I'll start with Answer C = 8 goals   If....   Total goals = 8 goals   5th game = 2 goals   1st 4 games = 6 goals   Avg. for 1st 4 games = 6/4= 
6/4 = 3/2 = around 1.5
1.5 goal/game   Avg. for all 5 games= 8/5= 
8/5 = 8/5 = around 1.6
1.6 goals/game   This is an EXA8T MAT8H for what we're told in the prompt, so Answer 8 MUST be the answer.
Answer: C
Raju is 10 years elder to Sita. 10 years from now Raju would be twice as old as sita was before 10 years. How old would be Sita after 12 years.
Choose one.
A) 42 years  B) 46 years  C) 50 years  D) 52 years  E) 55 years

Solution: If R and S are their present ages, then   R=S+10   and   R+10= 2*(S-10)   solving these eqns, we get   R=50 and S=40   At present, Sita is 40 years old.   After 12 years, Sita will be 52 years old.   ANSWER:52 years
Answer: D
A part of certain sum of money is invested at 9% per annum and the rest at 12% per annum, if the interest earned in each case for the same period is equal, then ratio of the sums invested is?
Choose the correct choice from the following answers:
A) 4:6  B) 4:9  C) 4:3  D) 4:1  E) 4:2

Solution: 12:9   = 4:3   Answer: 4:3
Answer: C
Two goods trains each 625 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Choose the correct choice from the following
A) 22 sec  B) 88 sec  C) 60 sec  D) 18 sec  E) 9 sec

Solution: Relative speed = 45 + 30= 
45 + 30 = 75
75 km/hr.   75 * 5/18= 125/6 m/sec.   Distance covered = 625 + 625= 
625 + 625 = 1_250
1250 m.   Required time= 1250 * 6/125= 
1250 * 6/125 = 60
60 sec.   Answer:60 sec
Answer: C
n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2n is divided by 4 ?
Choose one:
A) 3
B) 2
C) 1
D) 0
E) 5

Solution: Explanation:   Let n = 4q + 3. Then 2n = 8q + 6 = 4(2q + 1 ) + 2.   Thus, when 2n is divided by 4, the remainder is 2.   Answer: 2
Answer: B