MU-NLPC/Calc-aqua_rat huggingface dataset:
If you graph the lines 3x + 2y = –2 and
5x – y = 14 on a standard xy-graph, at
which point will the lines intersect?
Choices:
A) (1, –7)
B) (2, –4)
C) (–5, 4)
D) (–9, 3)
E) (11, 2)

Solution: Solve the two equations, 3x + 2y = –2 and 5x – y = 14, as a system of equations. To do   this, multiply the second equation by 2 and then add it to the first equation:   3x+2y=-2+10x-2y=28=>13x=26   Now solve for x:   x = 2   Replace x with 2 in either equation and solve for y:   3(2) + 2y = –2   6 + 2y = –2   2y = –8   y = –4   At the point of intersection, x = 2 and y = –4, so this point is (2, –4).   correct answer (2, –4)) (2, –4).
Answer: B
A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is :-	Pick:
A) a gain of Rs 27  B) a loss of Rs 37  C) neither gain nor a loss  D) a gain or a loss depending upon the order in which the wins and losses occur  E) None of these

Solution: Explanation :   As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply initial amount by 1.5 thrice and by 0.5 thrice (in any order).   The overall resultant will remain same.   So final amount with the person will be (in all cases):   =64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs 27   Hence the final result is:   64−27=37.   Answer : a loss of Rs 37
Answer: B
T divided by S equals 405.24 what is a possible remainder? Select the correct option.
A) 54 B) 2 C) 9 D) 40 E) 4

Solution: With the decimal being 24/100, the simplest form is 6/25. If the divisor is a multiple of 25, the remainder must be a multiple of 6. The only number that is so is 54. 54nswer 54.
Answer: A
A rectangular lawn of dimensions 110 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? Options:
A) s.3988	B) s.4800	C) s.3228	D) s.3922	E) s.3928

Solution: Area = (l + b – d) d   (110 + 60 – 10)10 => 1600 m2   1600 * 3   = Rs.4800   Answer:s.4800
Answer: B
You hold some gold in a vault as an investment. Over the past year the price of gold increases by 42%. In order to keep your gold in the vault, you must pay 4% of the total value of the gold per year. What percentage has the value of your holdings changed by over the past year.  Choose the correct choice
A) 38%	B) 46%	C) 47.68%	D) 44.32%	E) 36.32%

Solution: (100%+42%)*(100%-4%) = 1.42*0.96 = 136.32% an increase of 36.32%   Your gold holdings have increased in value by 36.32%.   The Answer is 36.32%
Answer: E
Of the 85 house in a development, 50 have a two-car garage, 40 have an in-the-ground swimming pool, and 35 have both a two-car garage and an in-the-ground swimming pool. How many houses in the development have neither a two-car garage nor an in-the-ground swimming pool? Choices:  A) 10  B) 15  C) 20  D) 25  E) 30

Solution: Neither Car nor Garage   = Total - Garage - (Swim - Common)   = 85 - 50 - (40-35) = 85-55= 
85-55 = 30
30   Answer 30
Answer: E
After his first semester in college, Thomas is applying for a scholarship that has a minimum Grade Point Average (GPA) requirement of 3.5. The point values of pertinent college grades are given in the table below. If Thomas took 7 courses, each with an equal weight for GPA calculations, and received two grades of A-, one grade of B+, and one grade of B, what is the lowest grade that Thomas could receive for his fifth class to qualify for the scholarship?
Point Values of Select Grades
Grade: A | A- | B+ | B | B- | C+ | C | C-
Value: 4 | 3.7 | 3.3 | 3 | 2.7 | 2.3 | 2 | 1.7 Choose the correct answer
A) A  B) B+  C) B  D) B-  E) C+

Solution: Grade: A | A- | B+ | B | B- | C+ | C | C-   Value: 4 |3.7|3.3|3| 2.7 | 2.3 | 2 | 1.7   7.4 + 3.3 + 3 + x = 3.5 * 5= 
3.5 * 5 = 17.5
17.5 - 13.7= 
17.5 - 13.7 = 3.8
3.8   Grade A is required to qualify   Answer= B-   B-
Answer: D
The average runs scored by a batsman in 35 matches is 36. In the next 14 matches the batsman scored an average of 15 runs. Find his average in all the 30 matches?	Choose the correct choice from the following answers.
A) 31 B) 35 C) 29 D) 25 E) 30

Solution: Total score of the batsman in 35 matches = 1260.Total score of the batsman in the next 14 matches = 210.Total score of the batsman in the 30 matches = 1470.Average score of the batsman = 1470/49= 
1470/49 = 30
30.Answer: 30
Answer: E
A man buys a cycle for Rs. 1600 and sells it at a loss of 10%. What is the selling price of the cycle?
Choose one
A) 1410
B) 1420
C) 1430
D) 1440
E) 1540

Solution: S.P. = 90% of Rs. 1600 = 90/100 x1600= Rs. 1440   answer : 1440
Answer: D
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?	Choose the correct choice:
A) 299  B) 277  C) 240  D) 88  E) 112

Solution: Speed = [54 * 5/18] m/sec = 15 m/sec.   Length of the train = (15 * 20)= 
(15 * 20) = 300
300 m.   Let the length of the platform be x meters.   Then, x + 300 / 36= 15   x + 300 = 540   x = 240 m.   Answer:240
Answer: C
A boy has fourteen trousers and 13 shirts. In how many different ways can he select a trouser and a shirt? Choose the correct choice from the following choices.
A) 182 ways
B) 287 ways
C) 266 ways
D) 108 ways
E) 121 ways

Solution: Explanation:   The boy can select one trouser in 14 ways.   The boy can select one shirt in 13 ways.   The number of ways in which he can select one trouser and one shirt is   14 * 13= 
  14 * 13 = 182
182 ways.   182 waysnswer: 182 ways
Answer: A
Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 34 kmph. Of how many minutes does the train stop per hour? Select the correct option
A) E982 B) 27 C) 12 D) 14.6 E) 28

Solution: Explanation:   T = 11/45 * 60 = 14.6   Answer: Option 14.6
Answer: D
In a certain pet shop, the ratio of dogs to cats to bunnies in stock is 3 : 7 : 13. If the shop carries 352 dogs and bunnies total in stock, how many dogs are there?  Choose the correct choice from the following options.
A) 42
B) 66
C) 98
D) 112
E) 154

Solution: Let us assume the number of dogs, cats and bunnies to be 3x, 7x and 13x   Total dogs and bunnies = 16x.   And we are given that 16x = 352.   Hence x = 22.   Dogs = 3x = 3*22= 
3*22 = 66
66 (Option 66)
Answer: B
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.30 per glass on the first day, what was the price per glass on the second day?
Choose the correct choice from the following answers.
A) $0.15  B) $0.20  C) $0.30  D) $0.40  E) $0.45

Solution: On the first day 1 unit of orange juice and 1 unit of water was used to make 2 units of orangeade;   On the second day 1 unit of orange juice and 2 units of water was used to make 3 units of orangeade;   So, the ratio of the amount of orangeade made on the first day to the amount of orangeade made on the second day is 2 to 3. Naturally the ratio of the # of glasses of orangeade made on the first day to the # of glasses of orangeade made on the second day is 2 to 3.   We are told thatthe revenue from selling the orangeade was the same for both daysso the revenue from 2 glasses on the first day equals to the revenue from 3 glasses on the second day.   Say the price of the glass of the orangeade on the second day was $x then 2*0.3=3*x --> x=$0.2.   Answer: $0.20.
Answer: B
A cylindrical water tower with radius 10 m and height 16 m is 3/4 full at noon. Every minute, .08π m3 is drawn from tank, while .03π m3 is added. Additionally, starting at 1pm and continuing each hour on the hour, there is a periodic drain of 4π m3. From noon, how many hours will drain the entire tank?	Options:
A) 170 2/7 B) 170 6/7 C) 171 D) 171 3/7 E) 172

Solution: initial volume = (3/4)×∏×10²×16 = 1200∏   Relative Drain/ min = .08∏ - .03∏ = .05∏ m³/min drain   Relative drain / hour .08  - .03= 
.08  - .03 = 0.05
.05∏ m³/min drain   Relative drain / hour= .05∏×60 = 3∏ m³/ hr   Every one hour starting from 1pm, 4∏ m³ of water is drained. It means that only at the hour the water is drained and NOT “in that 1 hour“   So after 1 hr the relative drain would be 3∏ + 4∏ = 7∏m³ of water drain   What i did initially was formed an equation 1200∏   3  + 4= 
  3  + 4 = 7
7∏m³ of water drain   What i did initially was formed an equation 1200∏= 7∏×n (n is the number of hrs) so ended up with 171.428. This wrong   Look at this way   after 171 hrs the amount of water drain will be 171×7∏ = 1197∏ m³   Left over water in the tank after 171 hrs = 3∏ m³   From above we know that it take 1 more hour to drain that 3∏ m³.   So ans is 172hrs   172
Answer: E
A train running at the speed of 60 km/hr crosses a pole in 6 sec. What is the length of the train?
Choose the correct choice from the following answers
A) 118	B) 150	C) 277	D) 258	E) 100

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 6= 
50/3 * 6 = 100
100 m   Answer: 100
Answer: E
If f(x) = 2x^2 + y, and f(2) = 30, what is the value of f(10)?
Choose the most appropriate option
A) 104  B) 60  C) 52  D) 50  E) 222

Solution: f(x) = 2x^2 + y   f(2) = 30   => 2*(2)^2 + y = 30   => 8 + y = 30   => y = 22   f(10)= 2*(10)^2 + 22   = 222   Answer 222
Answer: E
A, B and C work on a task. To complete the task alone, B takes twice the time that A would take to complete the task alone and 1/2rd the time that C would take to complete the task alone. If B actually worked for half the number of days that A worked and 3/2 times the number of days that C worked, what proportion of the total work was completed by B? Choose the correct choice from the following answers: A) 1/3 B) 2/9 C) 9/49 D) 7/19 E) 4/21

Solution: The first thing to notice is that A is faster than B and B is faster than C.   Since work is proportional to time, in 1 day lets say if A does 2 works, B does 1 work and C does 2/3rd of a work.   If A works for 2 days, B works for 1 day and C works for only 2/3 of the day.   Therefore total work done = (2*2) + (1*1) + (1/2*1/2) = 21/4   Proportion of work done by B = (1*1) / (21/4) = 4/21   Hence Answer 4/21.
Answer: E
If two numbers, a and b, are to be chosen from a set of 4 consecutive integers starting with 1 and a set of three consecutive even integers starting with 10, respectively, what is the probability that b/a will not be an integer?  Choices:
A) 1/2
B) 1/3
C) 1/4
D) 1/6
E) 1/8

Solution: a is from the following set {1,2,3,4}   b is from the following set {10,12,14}   The total number of ways of choosing 2 integers, one from each set is  4*3= 
 4*3 = 12
12 ways.   The possibilities where b/a is not an integer is for the following outcomes:   {b,a}= {10,3},{10,4},{14,3},{14,4} = 4 ways   Thus the probability is 4/12 = 1/3   The answer is 1/3.
Answer: B
Company P had 15 percent more employees in December than it had in January. If Company P had 480 employees in December, how many employees did it have in January?	Choose the correct choice from the following options
A) 391	B) 417	C) 410	D) 423	E) 445

Solution: D = number of employees in December   J = number of employees in January   J x 1.15 = D   J x 1.15 = 480   J = 480/1.15   J = 48,000/115 = 417   Thus 417 is the correct answer.
Answer: B
A jogger running at 9 km/hr along side a railway track is 360 m ahead of the engine of a 90 m long train running at 63 km/hr in the same direction. In how much time will the train pass the jogger? Choose the correct choice
A) 76 sec	B) 67 sec	C) 30 sec	D) 36 sec	E) 23 sec

Solution: Speed of train relative to jogger = 63 - 9= 
63 - 9 = 54
54 km/hr.= 54 * 5/18= 
54 * 5/18 = 15
15 m/sec.   Distance to be covered= 360 + 90= 
360 + 90 = 450
450 m.   Time taken= 450/15= 
450/15 = 30
30 sec.   Answer:30 sec
Answer: C
The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 90 metres?
Choose the correct choice from the following options:  A) 16 seconds  B) 76 seconds  C) 26 seconds  D) 12 seconds  E) 18 seconds

Solution: Speed of the boat downstream = 15 + 3= 
15 + 3 = 18
18 kmph= 18 * 5/18= 
18 * 5/18 = 5
5 m/s   Hence time taken to cover 90 m= 90/5= 
90/5 = 18
18 seconds.   Answer: 18 seconds
Answer: E
If you have 6 New Year greeting cards and you want to send them to 4 of your friends, in how many ways can this be done?	Pick one.
A) 360
B) 720
C) 920
D) 670
E) None

Solution: Solution   We have to find number of permutations of 4 objects out of 6 objects. This number is 6P4=6(6-1)(6-2)(6-3)=6*5*4*3= 
6*5*4*3 = 360
360   360nswer 360
Answer: A
What is the diffference between the place value and face value of 9 in the numeral 9184?
Choose the correct choice from the following choices
A) 8891 B) 9991 C) 8881 D) 8091 E) 8991

Solution: place value of 9 = 9 * 1000= 
9 * 1000 = 9_000
9000   face value of 9= 9   9000 - 9= 
9000 - 9 = 8_991
8991   8991
Answer: E
Train A leaves the station traveling at 30 miles per hour. Two hours later train В leaves the same station traveling in the same direction at 36 miles per hour. How many miles from the station was train A overtaken by train B?	Choose the correct option
A) 320 B) 360 C) 400 D) 440 E) 480

Solution: After two hours, Train A is ahead by 60 miles.   Train B can catch up at a rate of 6 miles per hour.   The time to catch up is 60/6= 
60/6 = 10
10 hours.   In 10 hours, train A travels another  30*10= 
 30*10 = 300
300 miles for a total of 360 miles.   The answer is 360.
Answer: B
A vessel of capacity 75 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?  Choose the correct choice from the following options:  A) 23.89  B) 72.9  C) 58.08  D) 78.3  E) 79.3

Solution: Explanation:   Let the initial quantity of milk in vessel be T litres.   Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.   Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T   For the given problem, T = 75, y = 9 and n = 2.   Hence, quantity of milk finally in the vessel   = [(75 - 9)/75]^2 (75) = 58.08 litres.   Answer: Option 58.08
Answer: C
Find the area of a cuboid of length 10cm , breadth 8 cm . and height 6cm.	Choose one.
A) 400 cm cube  B) 410 cm cube  C) 420 cm cube  D) 430 cm cube  E) 480 cm cube

Solution: Area of a cuboid = lxbxh =10cm x 8cm x 6cm = 480 cm cube   answer :480 cm cube
Answer: E
if cost of an apple is equal to cost of 4 oranges and he has 100$ with him. Cost of an orange is 1$. He want to buy same number of orange and apples. So how many apple and orange he would be able to buy in 100$? Select
A) 10 apple an 10 oranges  B) 20 apple and 20 oranges  C) 27 apples and 27 oranges  D) 30 apple and 30 oranges  E) 34 apples and 34 oranges

Solution: Since cost of an orange is 1$ and apple is 4 times costlier than orange so the cost of apple is 4$. Now if we add cost of an apple and orange it comes to be 5$ and hence if we divide 100 by 5 we get answer 20. So he will be able to buy 20 apple and 20 oranges. So option 20 apple and 20 oranges is correct.
Answer: B
Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction?  Select the correct option:	A) 7 3/8 km	B) 5 7/8 km	C) 17 7/8 km	D) 7 7/8 km	E) 2 7/8 km

Solution: RS = 6 ¾ - 4 ½ = 2 ¼   T = 3 ½ h.   7 7/8 km = 9/4 * 7/2 = 63/8 = 7 7/8 km   ANSWER:7 7/8 km
Answer: D
Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.85. How much was lent at 5%?  Choose the correct choice from the following options:  A) 228  B) 299  C) 266  D) 500  E) 188

Solution: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 85   5x/100 + 90 – 6x/100 = 85   x/100 = 5   => x = 500   Answer:500
Answer: D
A 270 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train? Choices:  A) 230  B) 387  C) 277  D) 299  E) 213

Solution: Relative speed = 120 + 80= 
120 + 80 = 200
200 km/hr.= 200 * 5/18 = 500/9 m/sec.   Let the length of the other train be x m.   Then, (x + 270)/9 = 500/9 => x = 230.230nswer:230
Answer: A
A right triangle has sides of a, b, and 15, respectively, where a and b are both integers. What is the value of (a + b)?  Choose the correct choice from the following:	A) 220	B) 221	C) 225	D) 224	E) 226

Solution: LET a= hypotenuse , b =base ,15 = perpendicular . therefore a^2 -b^2 =15^2 or (a+b)(a-b) = 225   a+b =225/a-b ' a-b cannot be zero ..therefore a+ b =225 where a-b is equal to 1   225
Answer: C
Find the area of circle whose radius is 8.2m?	Choose the correct choice from the following:	A) 138	B) 154	C) 288	D) 211.3	E) 371

Solution: 22/7 * 8.2 * 8.2   = 211.3   Answer:211.3
Answer: D
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?  Choose the correct choice from the following:
A) 10.9 sec
B) 13.8 sec
C) 53.8 sec
D) 10.8 sec
E) 10.4 sec

Solution: Relative speed = 60 + 40= 
60 + 40 = 100
100 km/hr.= 100 * 5/18 = 250/9 m/sec.   Distance covered in crossing each other = 140 + 160= 
140 + 160 = 300
300 m.   Required time= 300 * 9/250 = 54/5= 
54/5 = 54/5 = around 10.8
10.8 sec.   Answer: 10.8 sec:
Answer: D
5358 x 51 = ?
Choices
A) 273762
B) 283758
C) 273298
D) 273258
E) 277382

Solution: 273258   273258   5358 x 51 = 5358 x (50 + 1)   = 5358 x 50 + 5358 x 1   = 267900 + 5358= 
267900 + 5358 = 273_258
273258.
Answer: D
30 men take 20 days to complete a job working 9 hours a day. how many hour a day should 40 men work to complete the job? Choose the correct answer: A) 6.79 B) 6.75 C) 6.71 D) 6.74 E) 6.712

Solution: Explanation:   Let the capacity of man in hour is 1 unit. Then total work = 30 × 20 × 9   40 men in 20 days working t hours a day can complete = 40 × 20 × t   ⇒ 40 × 20 × t = 30 × 20 × 9   ⇒ t = 6.75 hours.   Answer: 6.75
Answer: B
A computer can perform c calculations in s seconds. How many minutes will it take the computer to perform A calculations?	Choose the correct choice from the following choices:
A) 60as/c  B) as/c  C) as/60c  D) 60c/as  E) a/60cs

Solution: As 'thick' as this question might look, it's actually a fairly straight-forward Rate question and can be solved by TESTing VALUES.   We're told that a computer can perform a calculations in S seconds.   Let's TEST....   a = 2   S = 3   2 calculations every 3 seconds =   40 calculations every 1 minute   We're asked how many MINUTES it will take to perform K calculations.   Since we already know that the computer can perform 40 calculations in 1 minute, let's TEST...   K = 80   So we're looking for an answer that = 2 when C = 2, S = 3 and K = 80   Answer A: 60KS/a = 60(80)(3)/2 = 7200 This is NOT a match   Answer B: KS/a = (80)(3)/2 = 120 This is NOT a match   Answer C: KS/60a = (80)(3)/(60)(2) = 2 This IS a match   Answer D: 60a/KS = 60(2)/(80)(3) = 1/2 This is NOT a match   Answer E: K/60aS = 80/(60)(2)(3) = a fraction. This is NOT a match   as/60c
Answer: C
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?  Options:
A) 12 B) 13 C) 14 D) 15 E) 16

Solution: Explanation:   (A+B) - (B-C) = 12 <=> A - C = 12. 12nswer: 12
Answer: A
How many possible integer values are there for x if |2x - 3| < 6 ?  Choose the correct option:
A) One B) Two C) Three D) Four E) Six

Solution: Solution: |2x-3| < 6   let 2x=a therefore we have |a-3| < 6 ==> read this as origin is at +3 and we have to move +6 to the right and -6 to the left   (the less than sign represents that the a must be within boundaries )   (3-6)----------3----------(3+6)   now, we have -3<a<9   but a =2x ==> -3<2x<9   dividing all values by +4 we have -1.5 <x < 4.5   Now question says Integer values (not rational ) therefore we have -1,0,1,2, 3, 4   Hence 6 Six
Answer: E
It is currently 7:05 PM. What time was it in the morning exactly 51,132 minutes ago?  Choose the correct choice from the following.
A) 6:53  B) 6:55  C) 6:59  D) 7:03  E) 7:09

Solution: Convert 51,132 minutes to hours by dividing by 60: 51,132/60 = 852 R12. That is 852 hours, 12 minutes. Convert 852 hours to days by dividing by 24: 852/24 = 35 R12. That is 35 days, 12 hours. Thus 852 hours before 7:05 PM is 12 hours before 7:05 PM which is 7:05 AM. 12 minutes before that is 6:53 AM. 6:53
Answer: A
Of the 400 math majors at a certain university, 30 percent will be assigned to advanced calculus on Monday and Wednesday and the remaining 70 percent will be assigned to advanced calculus on Tuesday and Thursday. However, 40 percent of the math majors prefer Tuesday and Thursday and 60 percent prefer Monday and Wednesday. What is the lowest possible number of math majors who will NOT be assigned to the days they prefer?
Choose the correct choice from the following options
A) 15  B) 20  C) 30  D) 45  E) 80

Solution: 30% of students are assigned to Monday and Wednesday = 0.3*400 = 60   70% of students are assigned to Tuesday and Thursday = 0.7*200= 
0.7*200 = 140
140   60% of students prefer Monday and Wednesday= 0.6*200= 
0.6*200 = 120
120   40% of students prefer Tuesday and Thursday= 0.4*200= 
0.4*200 = 80
80   Since we need theleastnumber of students who will not be assigned to their preferred days, we shall fit in themaximumpossible students as per their preference:   All of the 40% of students who prefer Tuesday and Thursday can be accommodated to their preferred days, whereas only 60 out of 120 students who prefer Monday and Wednesday can be accommodated to their preferred days.   The remaining 60 students who prefer Monday and Wednesday will be allocated to Tuesday and Thursday by default, which is not their choice.   Answer is 80.
Answer: E
If a is a positive integer then 1^(2a) + (1^a)/(1^(2a)) =  Answers.
A) 3  B) 4  C) 2  D) 5  E) 6

Solution: 1^(2a) + 1^a/ 1^(2a) = 1^a + 1^a/1^a = 1+ 1 + 1  /1= 
+ 1  /1 = 1
1+ 1= 
1+ 1 = 2
2   Answer : 2
Answer: C
A batsman makes a score of 90 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?	Choose the correct choice from the following options
A) 25  B) 31  C) 27  D) 29  E) 42

Solution: Let the average after 17 innings = x   Total runs scored in 17 innings = 17x   Average after 16 innings = (x-3)   Total runs scored in 16 innings = 16(x-3)   Total runs scored in 16 innings + 90 = Total runs scored in 17 innings   => 16(x-3) + 90 = 17x   => 16x - 48 + 90 = 17x   => x = 42   Answer is 42.
Answer: E
If the product of two positive integers is 120, which of the following could be the LCM and HCF of the two numbers? a. LCM 60 : HCF 2 b. LCM 30 : HCF 4 c. LCM 12 : HCF 10
Pick one
A) b only B) c only C) b,c only D) a only E) a,c only

Solution: The right answer is a.   Answer : a only
Answer: D
What is the lowest positive integer that is divisible by 1 through 2, inclusive?	Choose the correct choice from the following.
A) 2
B) 4
C) 8
D) 6
E) 1

Solution: The integer should be divisible by: 1 and 2. The least common multiple of these integers is LCM=1*2= 
1*2 = 2
2   2nswer: 2
Answer: A
If goods be purchased for Rs.840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction?
Choose the correct choice from the following answers
A) 33 1/8% B) 33 7/3% C) 33 1/3% D) 37 1/3% E) 32 1/3%

Solution: 1/4 33 1/3%P = 210 SP = 21*(80/100) = 168   SP = 840*(120/100)= 
840*(120/100) = 1_008
1008   1008 - 168= 
1008 - 168 = 840
840   3/4 SP= 630   Gain = 210   630 --- 210   100 --- ? => 33 1/3%   Answer:33 1/3%
Answer: C