MU-NLPC/Calc-aqua_rat huggingface dataset:
There are some 2 wheelers and 4 wheelers parked total number of wheels present is 240 then how many 4 wheelers were there Choose the correct answer:
A) 20
B) 30
C) 40
D) 50
E) 60

Solution: 2x+4x=240;   x=40;   then two whl=2*40= 
2*40 = 80
80   4 whl=4*40= 
4*40 = 160
160;   ans: 160/4= i-e 40   ANSWER:40
Answer: C
Express 50 mps in kmph?  Choose the most appropriate option:
A) 172
B) 160
C) 150
D) 180
E) 120

Solution: 25 * 18/5 = 180 kmph   Answer:180
Answer: D
(112 x 54) = ? Options
A) 60000  B) 70000  C) 80000  D) 88000  E) None

Solution: (112 x 54) = 112 x 10 4	=	112 x 104	=	1120000	= 70000   2	24	16   70000)
Answer: B
If PENCIL is coded as 45 and TRASH is coded as 36, then MEMORY is coded as Choose the correct choice from the following.
A) 33  B) 59  C) 60  D) 72  E) None

Solution: PENCIL= 16+5+14+3+9+12= 
16+5+14+3+9+12 = 59
59 i.e 5*9=45   TRASH= 20+18+1+19+8= 
20+18+1+19+8 = 66
66 i.e 6*6=36   MEMORY  13+5+13+15+18+25= 
 13+5+13+15+18+25 = 89
89 8*9=72   ANSWER:72
Answer: D
In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 36π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green?
Choose the correct choice from the following choices:
A) 100PI
B) 144PI
C) 70
D) 80
E) 90

Solution: AREA OF CIRCLE 36PI SQ FEET =PI R^2 THEREFORE R =6   NOW GREEN RADI DOU144PILED I.E R =12 AREA =144 PI   144PI
Answer: B
In a 800 m race around a stadium having the circumference of 200 m, the top runner meets the last runner on the 5th minute of the race. If the top runner runs at twice the speed of the last runner, what is the time taken by the top runner to finish the race ? Pick one:
A) 20 min
B) 15 min
C) 10 min
D) 5 min
E) None of these

Solution: After 5 minutes (before meeting), the top runner covers 2 rounds i.e., 400 m and the last runner covers 1 round   i.e., 200 m.   ∴ Top runner covers 800 m race in 10 minutes.   Answer 10 min
Answer: C
A man sells a horse for Rs.1000 and loses something, if he had sold it for Rs.1090, his gain would have been double the former loss. Find the cost price of the horse?  Choose the correct choice from the following:
A) 1080	B) 1040	C) 1070	D) 1030	E) 1060

Solution: CP = SP + 1CP = SP - g   1000 + x = 1090 - 2x   3x = 90 => x = 30   CP = 1000 + 30= 
1000 + 30 = 1_030
1030   Answer: 1030
Answer: D
The speed of a boat in still water is 50kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?  Choose the correct choice from the following choices:  A) kmph  B) kmph  C) kmph  D) kmph  E) kmph

Solution: Speed downstream = 50 + 20= 
50 + 20 = 70
70 kmph   Speed upstream= 50 - 20= 
50 - 20 = 30
30 kmph   Answer:kmph
Answer: B
In an election, candidate Smith won 52% of the total vote in Counties A and Q. He won 61% of the vote in County A. If the ratio of people who voted in County Q to County B is 3:1, what percent of the vote did candidate Smith win in County Q ?
Choose the correct choice from the following.
A) A.25%
B) B.27%
C) C.34%
D) D.43%
E) E.49%

Solution: (61%)*3x + (y%)*x = (52%)*4x   y = 25% of County Q   hence answer is A.25%.
Answer: A
Find the face value of 8 in 8213456	Answers
A) 8000  B) 80  C) 8  D) 800  E) 80000

Solution: Face value is the value of digit itself   face value of 8 = 8   Answer : 8
Answer: C
If (a – b) is 13 more than (c + d) and (a + b) is 3 less than (c – d), then (a – c) is:
Choose the correct choice from the following answers
A) 6
B) 2
C) 3
D) 4
E) 5

Solution: (a – b) – (c + d) = 13 and (c – d) – (a + b) = 3   => (a – c) – (b + d) = 13 and (c – a) – (b + d) = 3   => (b + d) = (a – c) – 13 and (b + d) = (c – a) – 3   => (a – c) – 13 = (c – a) – 3 => 2(a – c) = 10 => (a – c) = 5   ANSW5R:5
Answer: E
The price of a T.V. set worth Rs. 20000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?	Choose the most appropriate option:
A) A)19009
B) B)19074
C) C)19008
D) D)19000
E) E)19002

Solution: Explanation:   Money paid in cash = Rs. 1000   Balance payment = (20000 - 1000) = Rs. 19000   Answer: Option 19000
Answer: D
What is the remainder when the infinite sum (1!)² + (2!)² + (3!)² + ··· is divided by 1152?
Choose one
A) 12
B) 41
C) 152
D) 802
E) None

Solution: Explanation :   We have to find out the remainder when (1!)² + (2!)² + (3!)² + ··· is divided by 1152   1152 = 27 * 32   => (6!)2 is divisble by 1152   => All (n!)2 are divisible by 1152 as long as n > 5   So, our problem is now reduced to   Rem [((1!)² + (2!)² + (3!)² + (4!)² + (5!)²)/1152]   = Rem[(1 + 4 + 36 +576 + 14400) / 1152]   = Rem [15017/1152]   = 41   Answer : 41
Answer: B
A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 7% of bananas were rotten. Find the percentage of fruits in good condition? Choose one.
A) 92.5%  B) 88.2%  C) 85.2%  D) 96.8%  E) 78.9%

Solution: Total number of fruits shopkeeper bought = 600 + 400= 
600 + 400 = 1_000
1000   Number of rotten oranges= 15% of 600   = 15/100 × 600   = 9000/100= 
9000/100 = 90
90   Number of rotten bananas= 7% of 400   = 28   Therefore, total number of rotten fruits = 90 + 28= 
90 + 28 = 118
118   Therefore Number of fruits in good condition= 1000 - 118= 
1000 - 118 = 882
882   Therefore Percentage of fruits in good condition= (882/1000 × 100)%   = (88200/1000)= 
(88200/1000) = 441/5 = around 88.2
88.2%   Answer:88.2%
Answer: B
If a class of 10 students has four men, how many ways can the men and women be arranged in a circle so that no two men sit next to each other?  Choose one.
A) 5!4! B) 5!5! C) 4!3! D) 10! E) 10!/5!

Solution: for no two men to sit together, either all are in even or odd position   fix one at any one position then rest three can be fixed in 3! ways...   also rest four position of women can be fixed in 4!..   total ways 4!3!   4!3!
Answer: C
A cask initially contains pure alcohol up to the brim. The cask can be emptied by removing exactly 5 liters at a time . Each time this is done, the cask must be filled back to the brim with water. The capacity of the cask is 15 liters. When the cask is completely emptied and filled back to the brim two times, what is the ratio of alcohol to water in the cask	Choose the correct option.
A) 4/5	B) 3/5	C) 4/6	D) 3/6	E) 2/6

Solution: You are given that the initial quantity of the cask is 15 l. So for the changing of the liquids,   The first time you remove 5 l of pure alcohol---> 10 l of alcohol remaining and you add 5 l of water. Ratio of alcohol in the remaining mixture = 10/(10+5) = 10/15 =2/3, similarly water = 1/3.   The second time you remove 5 l of the mixture having alcohol = 5*2/3 = 10/3 --> remaining alcohol = 10-10/3 =20/3   Similarly, the amount of water removed = 5*1/3=5/3 ---> remaining water = 5-5/3=10/3 but you also add 5 l more of water --> total water now = 5+10/3 = 25/3   Finally, ratio asked = 20/3 / 25/3 = 20/25 = 4/5   4/5 is the correct answer.
Answer: A
The number of arrangements that can be made with the letters of the word MEADOWS so that the vowels occupy the even places?  Choose the correct choice from the following choices
A) 720	B) 144	C) 120	D) 36	E) 204

Solution: The word MEADOWS has 7 letters of which 3 are vowels.   -V-V-V-   As the vowels have to occupy even places, they can be arranged in the 3 even places in 3! i.e., 6 ways. While the consonants can be arranged among themselves in the remaining 4 places in 4! i.e., 24 ways.   Hence the total ways are  24 * 6= 
 24 * 6 = 144
144.   ANSWER:144
Answer: B
Train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds. The length of train P is three-fourths the length of train Q. What is the ratio of the speed of train P to that of train Q? Choose the correct choice from the following choices
A) 15 : 8 B) 14 : 8 C) 17 : 8 D) 13 : 8 E) 12 : 8

Solution: A   15 : 8   Given that train P crosses a pole in 30 seconds and train Q crosses the same pole in one minute and 15 seconds.   Let the length of train P be LP and that of train Q be LQ   given that LP = 3/4 LQ   15 : 8s the train P and Q crosses the pole in 30 seconds and 75 seconds respectively,   => Speed of train P = VP = LP/30   Speed of train Q = VQ = LQ/75   LP = 3/4 LQ   => VP = 3/4 LQ/(30) = LQ/40   Ratio of their speeds = VP : VQ   = LQ/40 : LQ/75 => 1/40 : 1/75 = 15 : 8
Answer: A
A man can swim in still water at 6 km/h, but takes twice as long to swim upstream than downstream. The speed of the stream is? Pick
A) 1.7
B) 1.9
C) 1.1
D) 2
E) 1.2

Solution: M = 6   S = x   2S = 6 + x   US = 6 - x   6 + x = (6 - x)2   6 + x = 12 -2x   3x = 12-6= 
12-6 = 6
6   x= 2   Answer:2
Answer: D
Convert 300 miles into km? Answers
A) 360km  B) 480km  C) 510km  D) 320km  E) 500km

Solution: 1 mile = 1.6 km approximately   300mile = 300*1.6= 
300*1.6 = 480
480km   Answer is 480km
Answer: B
What number continues the sequence?
25, 50, 27, 46, 31, 38, 39, ?  Choose the correct choice from the following choices: A) 21 B) 22 C) 23 D) 24 E) 25

Solution: 22   22   There are two alternate sequences, the first increases by 2, 4, 8 etc and the second decreases by 4, 8, 16 etc.
Answer: B
If all of the telephone extensions in a certain company must be even numbers, and if each of the extensions uses all four of the digits 1, 2, 3, and 4, what is the greatest number of four-digit extensions that the company can have?  Choose the correct choice:
A) 4 B) 6 C) 12 D) 16 E) 24

Solution: Since the phone number must be even, the unit's digit can be either 2 or 4.   When the unit's digit is 2 --> number of possibilities is 3! = 6   When the unit's digit is 4 --> number of possibilities is 3! = 6   Largest number of extensions = 6 + 6= 
6 + 6 = 12
12   Answer:12
Answer: C
A couple spent $198 in total while dining out and paid this amount using a credit card. The $198 figure included a 20 percent tip which was paid on top of the price which already included a sales tax of 10 percent on top of the price of the food. What was the actual price of the food before tax and tip?	Choose the correct choice from the following options
A) $130  B) $140  C) $150  D) $160  E) $170

Solution: Let the price of the meal be x.   After a 10% sales tax addition, the price is 1.1*x   After a 20% tip on this amount, the total is 1.2*1.1*x = 1.32x   1.32x = 198   x = $150   The correct answer is $150.
Answer: C
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream? Choose the correct choice:
A) 5 kmph  B) 7 kmph  C) 9 kmph  D) 8 kmph  E) 1 kmph

Solution: Speed downstream = d/t = 85/(2 1/2) = 34 kmph   Speed upstream = d/t = 45/(2 1/2) = 18 kmph   The speed of the stream = (34 - 18)/2= 
(34 - 18)/2 = 8
8 kmph   Answer:8 kmph
Answer: D
T is the set of all positive integers x such that x^2 is a multiple of both 27 and 375. Which of the following integers must be a divisor of every integer x in T?
I. 9
II. 15
III. 27
Pick one:
A) I only	B) II only	C) I and II only	D) I and III only	E) I, II, and III

Solution: Solution:   T->{x} where x^2 is a multiple of both 27 and 375 means 3^3 and (5^3)*3   means x must contain 3^2 and 5^2   so with these conditions we know that 9=3^2 and 15=3*5 both have required factors for the divisibility of lowest int for x which is 9*25   but 27 is not a divisor because it can't divide 9*25 fully.   so Ans : I and II only
Answer: C
Four different children have jelly beans: Aaron has 5, Bianca has 7, Callie has 8, and Dante has 19. How many jelly beans must Dante give to Aaron to ensure that no child has more than 1 fewer jelly beans than any other child?
Choose the correct option: A) 2 B) 3 C) 4 D) 5 E) 7

Solution: Since Bianca and Callie are both within 1 jelly bean of each other and Aaron has 5, Dante must provide 3 of his 19 jelly beans so each child has no more than 1 fewer jelly bean than any other child.   Dante + Aaron = 19+5= 
19+5 = 24
24/2= 
24/2 = 12
12   19-2= 7 so Dante must provide 3 jelly beans to Aaron.   Answer (7)
Answer: E
3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?  Choose the correct choice from the following:
A) 16 B) 15 C) 17 D) 18 E) 21

Solution: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days   So fodder will be available for  (60 + 8 + 12)= 
 (60 + 8 + 12) = 80
80 cows c 24x60 .0 .   for-^—=18 days.   18
Answer: D
Four bells begin to toll together respectively at the intervals of 8, 10, 12 and 16 seconds. After how many seconds will they toll together again?	Choose the correct choice from the following answers.
A) 246 seconds
B) 242 seconds
C) 240 seconds
D) 243 seconds
E) 253 seconds

Solution: L240 secondsM of 8,10,12 and 16 is   240   L240 secondsM=240   ANSWER:240 seconds
Answer: C
The hypotenuse of a right triangle is 2 centimeters more than the longer side of the triangle. The shorter side of the triangle is 7 centimeters less than the longer side. Find the length of the hypotenuse.	Options:
A) 17
B) 18
C) 19
D) 20
E) 21

Solution: Let a and b be the two sides of the triangle such that a is longer than b. The statement "the hypotenuse of a right triangle is 2 centimeters more than the longer side of the triangle" may be fomulated by   h = a + 2 or a = h - 2   The statement "the shorter side of the triangle is 7 centimeters less than the longer side" may be formulated .   b = a - 7 or b = (h - 2) - 7 = h - 9   We now use Pythagora's theorem to write a third equation   h 2 = a 2 + b 2   Substitute a by h - 2 and b by h - 9 in the above equation to obtain an equation in one variable only.   h 2 = (h - 2) 2 + (h - 9) 2   Simplify and rewrite the above equation in standard form.   h 2 -22 h + 85 = 0   Solve for h.   h = 5 and h = 17.   Only the solution h = 17 gives a and b positive and it is the length of the hypotenuse of the triangle.   17nswer 17
Answer: A
A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.800 when the rate to profit rises from 5 to 7 percent. Find the Capital of B? Choose the correct choice.
A) 3999
B) 10000
C) 2500
D) 2772
E) 2912

Solution: A:10000:C = 2/3:1/6:1/6 = 4:1:1   x * 2/100 * 2/3 = 800   10000 capital = 60000*1/6= 
60000*1/6 = 10_000
10000.Answer: 10000
Answer: B
A train 250 m long is running at a speed of 27 km/hr. In what time will it pass a bridge 200 m long?	Select:
A) 40 B) 45 C) 50 D) 55 E) 60

Solution: Speed = 27 * 5/18 = 15/2 m/sec   Total distance covered = 250 + 200= 
250 + 200 = 450
450 m   Required time= 450 * 2/15= 
450 * 2/15 = 60
60 sec   Answer: 60
Answer: E
A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?	Pick one
A) 24  B) 27  C) 20  D) 35  E) 25

Solution: 20   20   x ------- 9   (x + 10) ---- 6   x * 9 = (x + 10)6   x = 20
Answer: C
How many hours are there in 1200 minutes?  Choose one
A) 10 B) 20 C) 85 D) 86 E) 88

Solution: We know that there are 60 minutes in 1 hour.Divide the number of minutes by the number of minutes in 1 hour. We get, divide 1200 by 601200 ÷ 60 = 20   So there are 20 hours in 1200 minutes.   ANSWER IS 20
Answer: B
Of the 75 cars on a car lot, 45 have air-conditioning, 35 have power steering, and 12 have both air-conditioning and power steering. How many of the cars on the lot have neither air-conditioning nor power steering?	Answers
A) 7
B) 8
C) 10
D) 15
E) 18

Solution: Total -Neither = All Air Conditioning + All Power steering - Both   or 75 - Neither = 45 + 35 -12= 
45 + 35 -12 = 68
68.=> Neither = 7, hence A.   7nswer : 7
Answer: A
When n liters of fuel was added to a tank that was already 1/3 full, the tank was filled to 7/3 of its capacity. In terms of n, what is the capacity of the tank, in liters?
Choose the correct option
A) 1/2 n  B) 4/3 n  C) 3/2 n  D) 9/4 n  E) 7/3n

Solution: A is the answer.   To solve this problem, draw diagram or use algebra. I'm more comfortable with algebra.   Given   - tank was already 1/3 full.   - When n ltr added, it became 7/3   So 1/3 + n = 7/3   n = 7/3 - 1/3   n = 6/3   capacity of the tank is full fraction . i.e. 1 i.e. 3/3   so the question is 3/3 is how much times n   = 3/3= 
3/3 = 1
1= xn   so x = 3/6   and total = 3/6n=1/2n
Answer: A
If r < y < -1, which of the following is true? Choose the most appropriate option
A) r/y > ry	B) y/r > r+y	C) y/r > ry	D) y/r < r+y	E) y/r > r/y

Solution: Consider :   r= -3   y= -2   then put for every option. U'll get ans y/r > r+y.
Answer: B
Find the value of 72518 x 9999 = m?  Select:
A) 345434667	B) 246465757	C) 465767867	D) 725107482	E) 645354643

Solution: 72518 x 9999 = 72518 x (10000 - 1)   = 72518 x 10000 - 72518 x 1   = 725180000 - 72518= 
725180000 - 72518 = 725_107_482
725107482   725107482
Answer: D
If the sides of a triangle are 26 cm, 18 cm and 10 cm, what is its area?
Options: A) 90 B) 110 C) 130 D) 140 E) 150

Solution: The triangle with sides 26 cm, 18 cm and 10 cm is right angled, where the hypotenuse is 26 cm.   90rea of the triangle = 1/2 * 18 * 10= 
1/2 * 18 * 10 = 90
90 cm2   90nswer: Option 90
Answer: A
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Pick.
A) 7 kmph  B) 6 kmph  C) 5 kmph  D) 8 kmph  E) 2 kmph

Solution: Speed downstream = d/t = 85/(2 1/2) = 34 kmph   Speed upstream = d/t = 45/(2 1/2) = 18 kmph   The speed of the stream = (34 - 18)/2= 
(34 - 18)/2 = 8
8 kmph   Answer:8 kmph
Answer: D
Ramesh can finish a piece of work in 16 days. Rohan is twice as efficient as Ramesh.If they work together how many days will they need to finish the same amount of work?	Choose the correct choice from the following:
A) 8/3 days B) 9/3 days C) 16/3 days D) 11/3 days E) 7/3 days

Solution: Ramesh can finish a piece of work in 16 days. Rohan is twice as efficient as Ramesh.   So Rohan can finish a piece of work in 8 days.   days needed to finish the same amount of work = 1/(1/8+1/16)=16/3 days   ANSWER:16/3 days
Answer: C
A train of length 110 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?  Select
A) 10
B) 8
C) 6
D) 4
E) 2

Solution: Explanation:   Distance = 110 m   Relative speed = 60 + 6= 
60 + 6 = 66
66 kmph (Since both the train and the man are in moving in opposite direction)= m/sec = m/sec   Time taken to pass the man = = 6 s   ANSWER IS 6
Answer: C
a,b and c are positive integers less than or equal to 9 and multiple of 3. If a,b and c are assembled into the three-digit number abcabc, which of the following must be a factor of abcabc?	Pick one
A) 6	B) 4	C) 7	D) 5	E) 9

Solution: as a, b and c are multiple of 3, they can be written as a=3l, b=3m and c=3n. the sum of digits of abc is a+b+c = 3(l+m+n+l+m+n)=6(l+m+n).   Thus, 6 is always a factor.   6nswer: 6
Answer: A
y =x^2 + bx + 128 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b?
Select the correct option
A) -129	B) -132	C) 32	D) 64	E) 128

Solution: As the curve cuts the x-axis at (h,0) and (k,0). Therefore h,k are the roots of the quadratic equation.   For the quadratic equation is in the form of ax^2+bx+c=0,   The product of the roots =c/a= 128/1 = 64 and the sum of the roots =-b/a=-b/1   128 can be expressed as product of two numbers in the following ways:   1 * 128   2 * 64   4 * 32   8 * 16   The sum of the roots is maximum when the roots are 1 and 128 and the maximum sum is 1 + 128= 
1 + 128 = 129
129.   The least value possible for b is therefore -129.   a
Answer: A
Last year a certain bond yielded 12 percent of its face value in interest. If that interest was approximately 4 percent of the bonds selling price of $7,500, what is the bonds face value? Select the correct option.
A) $6,000 B) $6,750 C) $7,425 D) $2,500 E) $9,375

Solution: Interest = 0.12*face value = 0.04*7,500 --> face value = 0.04*7,500/0.12 = 2,500.   Answer: $2,500.
Answer: D
A bakery currently has 5 pies and 6 cakes in its inventory. The bakery’s owner has decided to display 5 of these items in the bakery’s front window. If the items are randomly selected, what is the probability that the display will have exactly 3 pies?  Select the correct option:
A) 3/11 B) 25/77 C) 5/11 D) 7/11 E) 50/77

Solution: We need the probability that the owner will select PPPCC: 5!/3!∗2!∗(5/11∗4/10∗3/9)∗(6/8∗5/7)=25/77, we are multiplying by 5!/3!∗2! since PPPCC scenario can occur in number of ways: PPPCC, PPCPC, PCPPC, CPPPC, ... Notice that the number of occurrences of PPPCC basically is the number of arrangements of 5 letters PPPCC out of which 3 P's and 2 C's are identical, so it's 5!/3!∗2!   Answer: 25/77.
Answer: B
A train 280 m long, running with a speed of 63 km/hr will pass a tree in? Answers:
A) 22 sec	B) 16 second	C) 77 sec	D) 55 sec	E) 17 sec

Solution: Speed = 63 * 5/18 = 35/2 m/sec   Time taken = 280 * 2/35= 
280 * 2/35 = 16
16 sec   Answer:16 second
Answer: B
You enter a weight loss challenge game and manage to lose 14% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in?	Options
A) 13%
B) 9.22%
C) 9%
D) 14%
E) 12.28%

Solution: (100%-14%)*(100%+2%) = 0.86*1.02 = 12.28%   The weigh in records your weight loss at 12.28%!   The Answer is 12.28%
Answer: E
Find the invalid no.from the following series 3, 7, 15, 27, 63, 127, 255	Choose the correct option.
A) 3	B) 7	C) 27	D) 127	E) 255

Solution: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 27 is wrong.   27
Answer: C
Two trains are running in opposite directions with the same speed. If the length of each train is 240 m and they cross each other in 12 sec, then the speed of each train is?  Answers:  A) 22  B) 77  C) 72  D) 88  E) 21

Solution: Let the speed of each train be x m/sec.   Then, relative speed of the two trains = 2x m/sec.   So, 2x = (240 + 240)/12 => x = 20   Speed of each train = 20 m/sec.   = 20 * 18/5 =- 72 km/hr.Answer: 72
Answer: C
300 gm of sugar solution has 40% sugar. How much sugar should be added to make it 50% in the solution? Choose the most appropriate option:
A) 80 gm  B) 20 gm  C) 60 gm  D) 67 gm  E) 63 gm

Solution: Explanation:   No explanation is available for this question!   ANSWER:60 gm
Answer: C
If taxi fares were $1.00 for the first 1/5 mile and $0.40 for each 1/5 mile there after, then the taxi fare for a 3-mile ride was  Choose the correct choice from the following options
A) $1.56 B) $2.40 C) $3.80 D) $4.20 E) $6.60

Solution: In 3 miles , initial 1/5 mile charge is $1   rest of the distance = 3 - (1/5) = 14/5   rest of the distance charge = 14(0.4) = $5.6 (as the charge is 0.4 for every 1/5 mile)   => total charge for 3 miles = 1+5.6= 
1+5.6 = 6.6
6.6   Answer is $6.60.
Answer: E
Set R consists of integers {3, -8, Y, 19, -6} and set B consists of integers {k, -3, 0, 16, -5, 9}. Number L represents the median of set R, number M represents mode of set B and number Z = L^M. If Y is an integer greater than 21, for what value of k will Z be a divisor of 26?  Choose the correct choice from the following choices:  A) -2  B) -1  C) 0  D) 1  E) 2

Solution: R = {3,-8,Y,19,-6}   B = {k,-3,0,16,-5,9}   Y > 21   So L = Median of R = 3   M = Mode of Set B   Z = (3)^M   If Z is a divisor of 26, (3)^M = 1 because 26 does not have 3 as a factor   => M = 0   Hence k = 0, as M is mode and 0 will be the most frequently occuring number in set B.   Answer - 0
Answer: C
A shop owner sells 30mtr of cloth and gains SP of 10 metres. Find the gain %? Answers:	A) 30%	B) 40%	C) 50%	D) 56%	E) 78%

Solution: Here, selling price of 10 m cloth is obtained as profit.   Profit of 10 m cloth = (S.P. of 30 m cloth) – (C.P. of 30 m cloth)   Selling price of 20 m cloth = Selling Price of 30 m of cloth   Let cost of each metre be Rs. 100.   Therefore, cost price of 20 m cloth = Rs. 2000 and S.P. of 20 m cloth = Rs. Rs. 3000   Profit% =	10	× 100 = 50%   20   Profit of 50 % was made by the merchant.   50%
Answer: C