MU-NLPC/Calc-aqua_rat huggingface dataset:
Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 6 hours? Choose the correct option:
A) 60X/Y.	B) 360X/Y.	C) 60Y/X.	D) 120Y/X.	E) (X + Y)/60.

Solution: Kramer can pack X boxes per min.   Therefore in 6 hrs(360mins)he can pack 360X boxes.   If there are Y boxes in one case then then the total number of cases packed by Kramer = 360X/Y   (ANSWER 360X/Y.)
Answer: B
The positive numbers w, x, y, and z are such that x is 30 percent greater than y, y is 20 percent greater than z, and w is 20 percent less than x. What percent greater than z is w ?	Choose the correct option:
A) 15.2% B) 16.0% C) 20.0% D) 23.2% E) 24.8%

Solution: My strategy is same as theDobermanbut instead take z=100, which makes life a bit easy. As:   z=100   y=120 (20% greater than z)   z=144(20% greater than y)   Now calculate w 20% less than z = 144*80/100= 
144*80/100 = 576/5 = around 115.2
115.2   Now by just looking, relation between w and z:   w-z/z*100= 20 - Answer   20.0%
Answer: C
After three successive equal percentage rise in the salary the sum of 100 rupees turned into 140 rupees and 49 paise. Find the percentage rise in the salary. Options.
A) 12%  B) 22%  C) 66%  D) 82%  E) 77%

Solution: Solution:   We solve it through options. Choosing options for trial depends on mental thought.   100 ==12% up ==>112 ==12% up ==>125.44 ==12% Up ==> 140.49   So, answer is 12%.   12%nswer: Option 12%
Answer: A
A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit? Choose the correct choice from the following options
A) 39:40 B) 39:45 C) 39:40 D) 39:41 E) 39:42

Solution: 3: 4   39:40 = 3/7*210= 
3/7*210 = 90
90   390: 400   39:40   39:40nswer: 39:40
Answer: A
If x > 5 and y < -5, then which of the following must be true ? Choose the correct choice from the following answers: A) x/y > 1 B) x/y < -1 C) x/y < 0 D) x + y > 0 E) xy > 0

Solution: Pick x=3, y = -3   A) x/y > 1 - Incorrect as x/y = -1   B) x/y < -1 - Incorrect as x/y = -1   C) x/y < 0 -Correct. It will hold for all values x > 2 and y < -2 as x/y = -1 < 0   D) x + y > 0 - Incorrect. x + y = 0   E) xy > 0 - Incorrect. XY = -9 which is less than zero.   x/y > 1 should be the answer.
Answer: A
When Greenville State University decided to move its fine arts collection to a new library, it had to package the collection in 20-inch by 20-inch by 15-inch boxes. If the university pays $0.70 for every box, and if the university needs 3.06 million cubic inches to package the collection, what is the minimum amount the university must spend on boxes?	Choose the correct choice from the following answers:	A) $255	B) $357	C) $510	D) $1,250	E) $2,550

Solution: Total no. Of boxes = 3060000/(20×20×15) = 510   Total cost = 510×$0.7=$357   Answer $357
Answer: B
In a family 13 people eat only vegetarian, 7 people eat only non veg., 8 people eat both veg and non veg.. How many people eat veg in the family?  Pick one
A) 20	B) 11	C) 9	D) 31	E) 21

Solution: Total people eat veg = only veg + both veg and non veg   Total= 13+8= 
13+8 = 21
21   Answer= 21
Answer: E
Average weight of 10 people increased by 2.5 kg when one person of 45 kg is replaced by a new
man. Then weight of the new man is  Pick one:
A) 50 B) 55 C) 60 D) 65 E) 70

Solution: Explanation:   Total weight increased is 2.5 * 10= 
2.5 * 10 = 25
25.   So weight of new person is 45+25= 
45+25 = 70
70   Answer: Option 70
Answer: E
If 10 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?  Choose the correct choice.
A) 127  B) 237  C) 360  D) 450  E) 281

Solution: Explanation:   Let the required no of hectares be x. Then   Men --- Hectares---Days   10---------80---------24   36---------x---------30   More men, More hectares (Direct proportion)   More days, More hectares (Direct proportion)   x=36/10*30/24*80= 
36/10*30/24*80 = 360
360   Answer: 360
Answer: C
8, 27, 64, 100, 125, 216, 343  Choose the correct option:  A) 40  B) 100  C) 290  D) 102  E) 293

Solution: The pattern is 23, 33, 43, 53, 63, 73. 100ut, 100 is not a perfect cube.
Answer: B
The rate of increase of the price of sugar is observed to be two percent more than the inflation rate expressed in percentage. The price of sugar, on January 1, 1994, is Rs. 24 per kg. The inflation rate for the years 1994 and 1995 are expected to be 20% each. The expected price of sugar on January 1, 1996 would be Choose the correct choice
A) 23.6	B) 36.45	C) 35.72	D) 24.6	E) None of these

Solution: Explanation :   Increase in the price of sugar = (20+2)= 
(20+2) = 22
22%   Hence, price of the sugar on Jan 1, 1996=> (24 * 122 * 122)/( 100 * 100 ) = Rs 35.72.   Answer : 35.72
Answer: C
A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match	Answers
A) 36	B) 37	C) 38	D) 39	E) 40

Solution: Explanation:   Let the average after 17th match is x   then the average before 17th match is x-3   so 16(x-3) + 87 = 17x   => x = 87 - 48= 
87 - 48 = 39
39   Answer: Option 39
Answer: D
A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 35% lemonade syrup?  Answers:
A) 1.5	B) 1.75	C) 2.14	D) 2.34	E) 2.64

Solution: Let the total solution is 150 L with 80 L water70 L syrup.   To make 35% syrup solution, the result solution must have 97.5 L syrup and 52.5 L syrup.   Therefore we are taking 17.5 L of syrup from initial solution and replacing with water.   using urinary method:   70 L syrup in 150 L solution   17.5 L syrup in 37.5 L solution   We started by multiplying 10   Now to get to the result we need to divide by 17.5 => amount of solution to be replaced with water (37.5/17.5)=2.14.   2.14orrect option : 2.14
Answer: C
If Ajay completes a certain work in 8 days and Vijay can complete the same work in 24 days, find the time in which the work will be completed if both Ajay and Vijay work together.	Choose the correct choice from the following answers:  A) 6 days  B) 9 days  C) 2 days  D) 7 days  E) 1 days

Solution: Explanation:   On working together 6 daysjay and Vijay can complete the work in (8*24)/(8 + 24)   = 192/32= 
192/32 = 6
6 days   6 daysNSWER: 6 days
Answer: A
An accurate clock shows 8 o'clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 1 o'clock in the afternoon? Choose the correct option
A) 180°	B) 154°	C) 160°	D) 170°	E) 150°

Solution: The angle traced by the hour hand in 12 hours is 360°, which is 30° per hour.   In 5 hours, the angle traced by the hour hand is 5×30° = 150°   The answer is 150°.
Answer: E
A password of a computer used five digits where they are from 0 and 9. What is the probability that the password solely consists of prime numbers and zero?
Choose one:
A) 1/32 B) 1/16 C) 1/8 D) 2/5 E) 1/2

Solution: We have five digits can be used for password -0,2,3,5,7.   1/32ssuming that the numbers can be repeated any number of times in the password, probability of selecting any one of them is 5/10 (out of 10 digits from 0-9)   So, 5/10 * 5/10 * 5/10 * 5/10 * 5/10 =1/32 (1/32)
Answer: A
A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is Choose the correct choice from the following
A) 38	B) 40	C) 28	D) 12	E) 19

Solution: Explanation:   Let there be x pupils in the class.   Total increase in marks = (x * 1/2) = x/2.   x/2 = (83 - 63) => x/2 = 20 => x = 40.   Answer: 40
Answer: B
A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 3 a rupee. Find his net profit or loss percent?
Choices.
A) 33 1/4 %  B) 33 9/3 %  C) 33 1/3 %  D) 33 1/5 %  E) 33 1/3 %

Solution: The total number of mangoes bought by the shopkeeper be 12.   If he buys 4 a rupee, his 33 1/3 %P = 3   He selling at 3 a rupee, his SP = 4   Profit = SP - 33 1/3 %P = 4 - 3= 
4 - 3 = 1
1   Profit Percent= 1/3 * 100 = 33 1/3 %   Answer:33 1/3 %
Answer: C
A, B and C invested Rs.6300, Rs.4200 and Rs.10500 respectively, in a partnership business. Find the share of A in profit of Rs.12100 after a year?  Choose one:
A) 3630  B) 3617  C) 3187  D) 7288  E) 2661

Solution: 6300:4200:10500   3:2:5   3/10 * 12100= 
3/10 * 12100 = 3_630
3630   3630nswer: 3630
Answer: A
On my sister's birthday, she was 154 cm in height, having grown 10% since the year before. How tall was she the previous year? Choose the correct choice from the following options.
A) 150 cm B) 140 cm C) 142 cm D) 148 cm E) 146 cm

Solution: Let the previous year's height be x.   1.1x = 154   x = 140   The answer is 140 cm.
Answer: B
Triangle STV has sides ST = TV = 10, and SV = 12. What is the area?  Choose one:
A) 36
B) 40
C) 44
D) 48
E) 52

Solution: Let the base B of the triangle be SV = 12. Then we need to find the height H.   H^2 = 100^2 - 6^2 = 64 and then H = 8.   The area is (1/2)*B*H = 6*8= 
6*8 = 48
48   The answer is 48.
Answer: D
A 240 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train?	Choose the most appropriate option.
A) 260  B) 250  C) 240  D) 230  E) 220

Solution: Relative speed = 120 + 80= 
120 + 80 = 200
200 km/hr.= 200 * 5/18 = 500/9 m/sec.   Let the length of the other train be x m.   Then, (x + 240)/9 = 500/9 => x = 260.   260nswer: Option 260
Answer: A
I. a3 - 212 = 131,
II. b2 - 72 = -23 to solve both the equations to find the values of a and b?	Choose the most appropriate option:
A) a > b
B) a ≥ b
C) a < b
D) a ≤ b
E) a = b or the relationship between a and b cannot be established.

Solution: a3 = 343 => a = 7   b2 = 49 => b = ± 7   a ≥ b   ANSWER:a ≥ b
Answer: B
Jennifer had $60 to spend on herself. She spent 1/5 of the money on a sandwich, 1/6 for a ticket
to a museum, and 1/2 of it on a book. How much money does Jennifer have left over? Choose the correct choice from the following answers.
A) $8	B) $14	C) $5	D) $15	E) $0

Solution: 1/5 x $60 = $12 for sandwich   1/6 x $60 = $10 for museum   1/2 x $60 = $30 for book   $12 + $10 + $30 = $52 spent   $60 - $52  12 +  10 +  30= 
 12 +  10 +  30 = 52
$52 spent   $60 - $52 = $8 left over   correct answer $8 60 -  52= 
 60 -  52 = 8
$8 left over   correct answer $8
Answer: A
Two varieties of wheat - A and B costing Rs. 9 per kg and Rs. 15 per kg were mixed in the ratio 3 : 7. If 5 kg of the mixture is sold at 25% profit, find the profit made?	Answers.
A) 16.9	B) 16.59	C) 16.53	D) 16.5	E) 16.55

Solution: Explanation:   Let the quantities of A and B mixed be 3x kg and 7x kg.   Cost of 3x kg of A = 9(3x) = Rs. 27x   Cost of 7x kg of B = 15(7x) = Rs. 105x   Cost of 10x kg of the mixture = 27x + 105x = Rs. 132x   Cost of 5 kg of the mixture = 132x/10x (5) = Rs. 66   Profit made in selling 5 kg of the mixture = 25/100 (cost of 5 kg of the mixture) = 25/100 * 66 = Rs. 16.50   Answer: Option 16.5
Answer: D
How many five-digit numbers can be formed from the digits 0, 1, 2, 3, 4, and 5, if no digits can repeat and the number must be divisible by 4?
Select:
A) 36
B) 48
C) 72
D) 96
E) 144

Solution: Thus the last two digit must be 04, 12, 20, 24, 32, 40, or 52.   If the last two digits are 04, 20, or 40, the first three digits can take 4*3*2= 
4*3*2 = 24
24 values.   Total for this case: 24*3= 
24*3 = 72
72.   If the last two digits are 12, 24, 32, or 52, the first three digits can take 3*3*2= 
3*3*2 = 18
18 values (that's because the first digit in this case cannot be 0, thus we are left only with 3 options for it not 4, as in previous case).   Total for this case: 18*4= 
18*4 = 72
72.   Grand total 72 +72= 
72 +72 = 144
144.   Answer: 144.
Answer: E
By the how much is two-fifth of 100 greater than three -fifths of 25?
Choose one: A) 25 B) 3 C) 5 D) 30 E) None of these

Solution: Reqd no. = 2â„5 Ã— 200 - 3â„5 Ã— 25   = 40 - 15= 
40 - 15 = 25
25   25nswer 25
Answer: A
A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of colors in a pair does not matter)
Options:
A) 4  B) 5  C) 6  D) 12  E) 24

Solution: Let # of colors needed be nn, then it must be true that n+C2n≥12n+Cn2 - # of ways to choose the pair of different colors from nn colors when order doesn't matter) --> n+n(n−1)/2≥12 --> 2n+n(n−1)≥24 --> n is an integer (it represents # of colors) n≥5--> nmin=5   Answer: 5.
Answer: B
Which greatest possible length can be used to measure exactly 12 meter 15 cm, 10 meter 15 cm and 10 meter 65 cm Pick one: A) 45cm B) 25cm C) 4cm D) 5cm E) 50cm

Solution: Explanation:   Convert first all terms into cm.   i.e. 1215 cm, 1015cm, 1065cm.   Now whenever we need to calculate this type of question, we need to find the HCF. HCF of above terms is 5.   Option 5cm
Answer: D
Kramer can pack X boxes of cigarettes per minute. If there are Y boxes of cigarettes in one case, how many cases can Kramer pack in 3 hours?	Pick.
A) 60X/Y.	B) 180X/Y.	C) 60Y/X.	D) 120Y/X.	E) (X + Y)/60.

Solution: Kramer can pack X boxes per min.   Therefore in 3 hrs(180mins)he can pack 180X boxes.   If there are Y boxes in one case then then the total number of cases packed by Kramer = 180X/Y   (ANSWER 180X/Y.).
Answer: B
Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?
Choose the correct choice from the following choices:
A) Rs. 759	B) Rs. 792	C) Rs. 818	D) Rs. 828	E) Rs. 838

Solution: Let the parts be x, y and [2379 - (x + y)]   x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)   11x/10 = 23y/20 = 6z/5 = k   x = 10k/11, y = 20k/23, z = 5k/6   But x + y + z = 2379   10k/11 + 20k/23 + 5k/6 = 2379   k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5   x = [10/11 * (3 * 11 * 23 * 6)/5= 
10/11 * (3 * 11 * 23 * 6)/5 = 828
828   Hence, the first part is Rs. 828.   ANSWER:Rs. 828
Answer: D
The ratio of two natural numbers is 5:6. If a certain number is added to both the numbers, the ratio becomes 7:8. If the larger number exceeds the smaller number by 10, find the number added?
Choose the correct answer:
A) 17	B) 12	C) 20	D) 27	E) 18

Solution: Let the two numbers be 5x and 6x.   Let the number added to both so that their ratio becomes 7:8 be k.   (5x + k)/(6x + k) = 7/8   42x = 7k => k = 2x.   6x - 5x = 10 => x = 10   k = 2x = 20.   Answer:20
Answer: C
David's Bank's saving amount is decreased 10% due to loan payment and current balance is Rs.90000. Find the actual balance before deduction?  Pick one.
A) 8000	B) 8500	C) 9000	D) 9500	E) 100000

Solution: 10% decreased   90% Balance = 90000   100% = 90000/90*100= 
90000/90*100 = 100_000
100000   Answer : 100000
Answer: E
Find the odd man out. 2, 3, 7, 11, 19, 32	Choose the correct choice from the following options:
A) 32  B) 9  C) 1  D) 3  E) 19

Solution: 32 is an not prime number. 32ll other given numbers are prime   32nswer : Option 32
Answer: A
A train leaves Mumabai at 9 am at a speed of 40 kmph. After one hour, another train leaves Mumbai in the same direction as that of the first train at a speed of 50 kmph. When and at what distance from Mumbai do the two trains meet?
Choose one:
A) 276 B) 271 C) 200 D) 278 E) 268

Solution: When the second train leaves Mumbai the first train covers 40 * 1= 
40 * 1 = 40
40 km   So, the distance between first train and second train is 40 km at 10.00am   Time taken by the trains to meet= Distance / relative speed = 40 / (50 -40)= 
40 / (50 -40) = 4
4 hours   So, the two trains meet at 2 p.m. The two trains meet 4 * 50= 
4 * 50 = 200
200 km away from Mumbai.   Answer: 200
Answer: C
Find value of X: (422+404)^2−(4×422×404)=X. Select
A) 234 B) 267 C) 324 D) 356 E) 577

Solution: Given Equation is in the form (a+b)2−4ab where a=422 and b=404   Hence answer   =(a+b)2−4ab=(a−b)2=(422−404)2=182=324   324
Answer: C
A train approaches a tunnel AB. Inside the tunnel is a cat located at a point that is 3/8 of the distance AB measured from the entrance A. When the train whistles the cat runs. If the cat moves to the entrance of the tunnel A, the train catches the cat exactly at the entrance. If the cat moves to the exit B, the train catches the cat at exactly the exit. The speed of the train is greater than the speed of the cat by what order?	Answers:
A) 3 : 1
B) 4:1
C) 5:1
D) None of these
E) Cannot be determined

Solution: Explanation :   Let tunnel = 8 km and speed of the cat is 1 km/hr.   Time taken to reach entrance of tunnel by cat = 3 hr   Time taken to reach exit of tunnel by cat = 5 hr   Train will cover the sum ( length of tunnel) = 2 hr.   Therefore, ratios of speeds of train and cat = 4 : 1   => Speed of the train is greater by 3 : 1 than that of the cat.   3 : 1nswer : 3 : 1
Answer: A
The first flight out of Phoenix airport had a late departure. If the next three flights departed on-time, how many subsequent flights need to depart from Phoenix on-time, for the airport's on-time departure rate to be higher than 50%?	Choose the correct choice from the following choices
A) 3
B) 5
C) 7
D) 8
E) 6

Solution: We need on-time departure rate to be higher than 5/10, so it should be at least 6/11, which means that 6 out of 11 flights must depart on time. Since for now 3 out of 4 flights departed on time then  6-3= 
 6-3 = 3
3 subsequent flights need to depart on-time.   3nswer: 3
Answer: A
The length of a rectangualr hll is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is
Answers:
A) 15 m  B) 22.5 m  C) 25 m  D) 30 m  E) None

Solution: Solution   Let the length = xmetres.   Then length = (x +5)metres.   Then,x(x +5)= 750   = x² + 5x - 750= 0   (x+30)(x-25)= 0   x=25.   Answer 25 m
Answer: C
Find the L.C.M of 12, 8, 24 and 16.  Pick one:
A) 48  B) 96  C) 80  D) 44  E) 140

Solution: Explanation:   2x3x2x2x2 = 48   48nswer: Option 48
Answer: A
The Banker’s gain on a bill due 1 year hence at 12% per annum is Rs. 6. The true discount is: Choose the correct choice from the following
A) 30
B) 40
C) 50
D) 60
E) None

Solution: Sol.   T.D. = B.G. * 100 / R * T = Rs.[6 * 100 / 12 * 1] = Rs.50   Answer 50
Answer: C
A train covers a distance in 1 h 40 min, if it runs at a speed of 96 km/h on an average. Find the speed at which the train must run reduce the time of journey to 1 h 20 min.	Choose the correct choice:  A) 120 km/h  B) 90 km/h  C) 144 km/h  D) 150 km/h  E) 160 km/h

Solution: Distance= Speed x Time = 96 x (100/60) = 160 km   New time = 80/60 h = 4/3 h   New speed = 160 x 3/4 = 40 x 3 =120 km/h   120 km/hnswer :120 km/h
Answer: A
A tortoise is making its way to eat a piece of lettuce at a constant speed. On its way to the lettuce, it takes 10 seconds to walk past a grain of sand. It then passes a piece of wood 20 cm long in 30 seconds to get to the lettuce. What is the length of the tortoise?	Choose the correct choice from the following answers
A) 4 cm  B) 5 cm  C) 7.5 cm  D) 9 cm  E) 10 cm

Solution: Sol.Let the length of the tortoise be x centimetres and its speed be y cm/sec. Then, x / y = 10 ⇒ y = x / 10∴ (x + 20) / 30 = x / 10 ⇔ x = 10 cm. Answer 10 cm
Answer: E
Stephanie, Regine, and Brian ran a 20 mile race. Stephanie and Regine's combined times exceeded Brian's time by exactly 2 hours. If nobody ran faster than 8 miles per hour, who could have won the race?
I. Stephanie
II. Regine,Brian
III.Regine	Choose the correct choice from the following answers.
A) I only B) II only C) III only D) I or II only E) I, or III only

Solution: Given that S+R=B+2, where S, R, and B are times in which Stephanie, Regine, and Brian completed the race.   Min time one could complete the race is  20/8= 
 20/8 = 5/2 = around 2.5
2.5 hours. Let's see if Brian could have won the race: if he ran at the fastest rate, he would complete the race in 2.5 hours, so combined time needed for Stephanie and Regine would be S+R=B+2=4.5 hours, which is not possible as sum of two must be more than or equal the twice the least time: 2*2.5= 
2*2.5 = 5
5. So Brian could not have won the race.   There is no reason to distinguish Stephanie and Regine so if one could have won the race, another also could. So both could have won the race.   Answer: I, or III only.
Answer: E
Graph G has a line of symmetry of x = –1. Graph G passes through the point (3, 3). What is the x-coordinate of another point that must have a y-coordinate of 3?  Choose the correct option: A) –8 B) –7 C) –5 D) –4 E) 2

Solution: Line of symmetry is X=-1; one point is (3,3)   Right side distance =1+3(distance from origin) = 4; therefore Left side distance should be same from line of symmetry =4;   therefore left side co-ordinate=4+ 1(distance from origin) = 5; as the X coordinate is in 2nd quadrant hence -5   Therefore answer is –5
Answer: C
A certain tax rate is $.32 per $100.00. What is the rate, expressed as a percent?
Options
A) 32%	B) 3.2%	C) 0.82%	D) 0.032%	E) 0.32%

Solution: Here in question it is asking $.32 is what percent of $ 100.Suppose $ .32 is x% of 100 means   100* (x/100) = .32   Hence x = .32 %   So answer is 0.32%
Answer: E
If a is an integer greater than 2 but less than 11 and b is an integer greater than 11 but less than 21, what is the range of a/b?  Choose the correct answer.
A) 52/45
B) 23/47
C) 60/41
D) 51/42
E) 41/60

Solution: The way to approach this problem is 2<a<11 and 11<b<21   Minimum possible value of a is 3 and maximum is 10   Minimum possible value of b is 12 and maximum is 20   Range = max a/min b - min a/max b   (Highest - lowest)   10/12 - 3/20 = 41/60   Hence 41/60
Answer: E
A man swims downstream 48 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water?
Pick one:
A) 2	B) 8	C) 9	D) 11	E) 14

Solution: 48 --- 3 11S = 16   ? ---- 1   18 ---- 3 US = 6   ? ---- 1 M = ?   M = (16 + 6)/2= 
(16 + 6)/2 = 11
11   Answer: 11
Answer: D
A shopkeeper sold some articles @ 35 per article and earned a profit of 40%. At what price each article should have been sold so that 60% profit was earned?  Choices
A) 25
B) 29
C) 30
D) 40
E) 45

Solution: SP = 140% of CP; :. CP = 35 × 100/140 = 25   Then, 60% of CP = 2.5 × 6 = 15   To set a profit of 60% the SP = 25 + 15= 
25 + 15 = 40
40.   Option '40'
Answer: D
The five sides of a pentagon have lengths of 2, 3, 4, 5 and 7 inches. Two pentagons are considered different only when the positions of the side lengths are different relative to each others. What is the total number of different possible pentagons that could be drawn using these five side lengths ?	Choose the correct choice from the following choices
A) 5 B) 15 C) 24 D) 32 E) 120

Solution: CONCEPT: The number of ways to arrange n elements around a circular Manner is (n-1)!.   But the number of ways to arrange n elements in circular manner where the arrangement can be flipped around (e.g. Necklace, Garland, Bracelet) = (n-1)!/2.   The pentagon in the problem above can be flipped over (Clockwise Arrangement of Sides = Counter-clockwise arrangement), the number of distinct ways to arrange the 5 sides = (5-1)!/2 = 15.   Answer: option 15
Answer: B
The average of temperatures at noontime from Monday to Friday is 50; the lowest one is 42, what is the possible maximum range of the temperatures?  Answers: A) 20 B) 25 C) 40 D) 45 E) 86

Solution: there are 5 days so the sum of temperature can be 50*5= 
50*5 = 250
250   lowest is 42. to find the maximum range we can say the temperature was the lowest for 4 of the 5 days   so   4*42= 
  4*42 = 168
168.   on the fifth day it is 250-168=281   range is therefore  128-42= 
 128-42 = 86
86   answer 86
Answer: E
What is the place value of 7 in the numeral 55468?  Select.
A) 5  B) 50  C) 5000  D) 55  E) 500

Solution: place value of 5 = 5* 1000= 
5* 1000 = 5_000
5000   Answer is 5000
Answer: C