MU-NLPC/Calc-aqua_rat huggingface dataset:
All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 156 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? Choose the correct choice:
A) 1248  B) 1723  C) 1129  D) 2613  E) 1372

Solution: A   B has 62.5% or (5/8) of the milk in A. Therefore, let the quantity of milk in container A(initially) be 8k.   Quantity of milk in B = 8k - 5k = 3k.   Quantity of milk in container C 8  - 5= 
8  - 5 = 3
3k.   Quantity of milk in container C= 8k - 3k = 5k   Container: A B C   Quantity of milk: 8k 3k 5k   It is given that if 156 liters was transferred from container C to container B, then both the containers would have equal quantities of milk.   5k - 156 8  - 3= 
8  - 3 = 5
5k   Container: A B C   Quantity of milk: 8k 3k 5k   It is given that if 156 liters was transferred from container C to container B, then both the containers would have equal quantities of milk.   5k - 156= 3k + 156 => 2k = 312 => k = 156   The initial quantity of milk in 1248 = 8k = 8 * 156= 
8 * 156 = 1_248
1248 liters.
Answer: A
When working alone, painter W can paint a room in 2 hours, and working alone, painter X can paint the same room in a hours. When the two painters work together and independently, they can paint the room in 3/4 of an hour. What is the value of a?	Choose the correct choice from the following options
A) 3/4	B) 1[1/5]	C) 1[2/5]	D) 1[3/4]	E) 2

Solution: Rate*Time=Work   Let Painter W's rate be W and Painter X's rate be X   R*T = Work   W * 2 = 1 (If the work done is same throughout the question then the work done can be taken as 1) => W = 1/2   X * a = 1 => X = 1/a   When they both work together then their rates get added up   Combined Rate = (W+X)   R*T = Work   (W+X) * 3/4 = 1   => W+X = 4/3   => 1/2 + 1/a = 4/3   => 1/a = (8-3)/6 = 5/6   => a = 6/5 = 1[1/5]   Answer 1[1/5]
Answer: B
A case contains c cartons. Each carton contains b boxes, and each box contains 400 paper clips. How many paper clips are contained in 2 cases? Options.
A) 400bc	B) 400b/c	C) 800bc	D) 800b/c	E) 800/bc

Solution: 2 cases * c cartons/case * b boxes/carton * 400 clips/box = 800bc paper clips   The answer is 800bc.
Answer: C
Find the ratio of the surfaces of the inscribed and circumscribed spheres about a cube.	Choose the correct choice from the following options.
A) 1:2 B) 1:3 C) 1:4 D) 1:5 E) None of these

Solution: 1:2nswer: 1:2)
Answer: A
Two boys starts from the same place walking at the rate of 5.5 kmph and 7.5 kmph respectively in the same direction. What time will they take to be 20 km apart?  Answers:
A) 10 B) 11 C) 14 D) 15 E) 20

Solution: Explanation:   Relative speed = 7.5 - 5.5= 
7.5 - 5.5 = 2
2 kmph (because they walk in the same direction)   distance= 20 km   time = distance / speed=20/2= 
20/2 = 10
10 hr   10nswer :10
Answer: A
If the average of r, b, c, 14 and 15 is 12. What is the average value of r, b, c and 29 Choose the correct choice:
A) 12 B) 13 C) 14 D) 15 E) 16

Solution: r+b+c+14+15 = 12*5= 
12*5 = 60
60=>r+b+c = 60-29= 
60-29 = 31
31   r+b+c+29= 31+29= 
31+29 = 60
60   Average= 60/4= 
60/4 = 15
15   Answer 15
Answer: D
P and Q started a business investing Rs. 85,000 and Rs. 15,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? Choose the correct choice from the following options:
A) 17:6
B) 18:5
C) 17:9
D) 17:1
E) 17:3

Solution: P:Q = 85000 : 15000 = 17:3.Answer:17:3
Answer: E
A man bought some apples of which 13% of then were rotten. He sold 75% of the balance and was left with 261 apples. How many apples did he have originally? Choose the correct choice from the following answers
A) 1000  B) 1100  C) 1200  D) 1300  E) 1400

Solution: Ans.   Now take initial number of apples x.   Then x×(100−13)%×(100−75)%=261   ⇒x=261/(87)%×(25)%⇒261×100×100/87×25⇒1200   Answer 1200
Answer: C
Two isosceles Triangles have equal vertical angles and their areas are in the ratio 16:49. Find the ratio of their corresponding heights . Options
A) 4/5 B) 5/4 C) 3/2 D) 4/7 E) 2/3

Solution: We are basically given that the triangles are similar.   In two similar triangles, the ratio of their areas is the square of the ratio of their sides and also, the square of the ratio of their corresponding heights.   Therefore, area/AREA=height^2/HEIGHT^2=16/49 --> height/HEIGHT=4/7.   Answer: 4/7.
Answer: D
13 Examiners check 650 abswer books in 5 days working 4 hours daily. How many more Examiners are required to check 7200 answer books in 12 days working 3 hours daily Options: A) 48 B) 68 C) 67 D) 47 E) 57

Solution: Needed Examiners =(7200*5*4*13 )/650*12*3 =80 More Examiners needed =80-13= 
80-13 = 67
67 Answer : 67
Answer: C
Mantu starts a month with provisions expected to last for the entire month. After few days, it is discovered that the provisions will, in fact short by 12 days and it is calculated that if the stock of provisions left is immediately tripled, it will be possible to exactly make up for the shortfall. If the stock of provisions left is doubled instead of being tripled, and simultaneously the strength of the Mantu is decreased by 25, then the provisions will fall short by :-	Choose the correct choice:
A) 2 days	B) 1 days	C) 3 days	D) 4 days	E) None of these

Solution: Explanation :   At the moment the shortfall is discovered, let there be n days worth of provision left.   Now, 3n−n=2n extra days worth of provisions lasts for the 12 additional days.   Thus, 3n lasts for 18 days i.e. 18 days are left for the month to end.   But if the provisions are only doubled and the strength becomes (3/4)th then the provisions will last for :-   =>12×(4/3).   =>16 days.   i.e. short fall of 18−16= 2 days.   2 daysnswer : 2 days
Answer: A
The current of a stream at 1 kmph. A motor boat goes 35 km upstream and back to the starting point in 12 hours. The speed of the motor boat in still water is ?	Pick:  A) 8 kmph  B) 6 kmph  C) 7.5 kmph  D) 5.5 kmph  E) 6.5 kmph

Solution: Explanation:   Speed of the stream = 1   Motor boat speed in still water be = x kmph   Down Stream = x + 1 kmph   Up Stream = x - 1 kmph   [35/(x + 1)] + [35/(x - 1)] = 12   x = 6 kmph   ANSWER IS 6 kmph
Answer: B
A train passes a station platform in 46 sec and a man standing on the platform in 16 sec. If the speed of the train is 54 km/hr. What is the length of the platform?	Choose the correct choice from the following choices:
A) 227
B) 240
C) 460
D) 450
E) 455

Solution: Speed = 54 * 5/18= 
54 * 5/18 = 15
15 m/sec.   Length of the train= 15 * 16= 
15 * 16 = 240
240 m.   Let the length of the platform be x m . Then,   (x + 240 )/46= 15=> x = 450 m.   Answer:450
Answer: D
A dealer originally bought 80 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? Select the correct option.
A) 3q/160  B) 3q/2  C) 120q  D) q/80  E) 120/q

Solution: The cost of each battery was q/80.   Each battery was sold for 1.5q/80 = 3q/160.   The answer is 3q/160.
Answer: A
Two persons A and B can complete a piece of work in 15 days and 30 days respectively. If they work together, what part of the work will be completed in 5 days? Options:  A) 1/8  B) 1/3  C) 1/6  D) 1/2  E) 5/3

Solution: A's one day's work = 1/15   B's one day's work = 1/30   (A + B)'s one day's work = 1/15 + 1/30 = 1/10   The part of the work completed in 5 days = 5 (1/10) = 1/2.   Answer:1/2
Answer: D
The cost of 4 bags and 12 purses is Rs.2800, what is the cost of 10 bags and 30 purses?	Choose the correct option
A) Rs.7000	B) Rs.7500	C) Rs.3800	D) Rs.7900	E) None of these

Solution: Explanation:   Cost of 4 bags + 12 purses = Rs.2800   Multiply each term by 5/2, we get,   Cost of 10 bags + 30 purses = Rs.7000.   Rs.7000nswer: Option Rs.7000
Answer: A
Find the principle on a certain sum of money at 6% per annum for 2 2/5 years if the amount being Rs.1120?	Choose the correct choice from the following options:
A) 979	B) 1288	C) 2778	D) 2682	E) 1021

Solution: 1120 = P [1 + (6*12/5)/100]   P= 979   979nswer: 979
Answer: A
The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and David have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?
Choose the correct choice from the following answers: A) $0.32 B) $0.40 C) $0.45 D) $0.48 E) $0.54

Solution: If Steve and David submit separate orders, each would be smaller than 100 photocopies, so no discount. Each would pay (80)*($0.02) = $1.60, or together, a cost of $3.20 --- that's the combined "no discount cost".   If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer  (80)*( 0.02)= 
 (80)*( 0.02) = 1.6
$1.60, or together, a cost of $3.20 --- that's the combined "no discount cost".   If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer= ($0.40).
Answer: B
If a man crosses a 700 m long street in 5 minutes. What is his speed? Choose the correct answer:  A) 7 km/hr  B) 7.1 km/hr  C) 7.2 km/hr  D) 8 km/hr  E) 8.4 km/hr

Solution: distance = 700 meter   time = 5 minutes = 5 x 60 seconds = 300 seconds   Speed = distance/time=700/300=2.3m/s=2.3×18/5 km/hr=8.4 km/hr   8.4 km/hr
Answer: E
Population is 24000. Population increases by 10% every year, then the population after 3 years is?
Choose the correct choice from the following options:
A) 26630
B) 26640
C) 36644
D) 31944
E) 26844

Solution: population after 1st year = 24000*10/100= 
24000*10/100 = 2_400
2400===> 24000+2400= 
24000+2400 = 26_400
26400   population after 2nd year= 26400*10/100= 
26400*10/100 = 2_640
2640===> 26400+2640= 
26400+2640 = 29_040
29040   population after 3rd year= 29040*10/100= 
29040*10/100 = 2_904
2904===> 29040+2904= 
29040+2904 = 31_944
31944   ANSWER:31944
Answer: D
Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins?
Choose the correct answer.
A) 276	B) 188	C) 120	D) 982	E) 129

Solution: 4x 5x 6x   100 50 25   400x + 350x + 150x = 16000   x = 20   6x = 120   Answer: 120
Answer: C
Using all the letters of the word "THURSDAY", how many different words can be formed?  Choose the correct choice from the following.
A) 7 B) 8! C) 9 D) 3 E) 4

Solution: Total number of letters   = 8   Using these letters the number of 8 letters words formed is 8P8   = 8!.   Answer:8!
Answer: B
How many multiples of 3 are there between 15 and 246 ? Choices.
A) 128  B) 94  C) 89  D) 76  E) 60

Solution: It should be mentioned whether 15 and 246 are inclusive.   If 15 and 246 are inclusive, then the answer is   (246-15)/3+1= 
  (246-15)/3+1 = 78
78.   If 15 and 246 are NOT inclusive, then the answer is   (243-18)/3+1= 
  (243-18)/3+1 = 76
76.   Since OA is 76, then we have NOT inclusive case.
Answer: D
Tom opened a shop investing Rs.3000. Jose joined him 2 months later, investing Rs.4500. They earned a profit of Rs.6300 after completion of one year. What will be Jose's share of profit?  Choose the correct choice from the following options.
A) 3500 B) 2800 C) 3251 D) 4251 E) 3508

Solution: SoL = ~s- So 3500nju’s share = [5/9] x 6300 = 3500   3500
Answer: A
x, a, z, and b are single digit positive integers. x = 1/5 a. z = 1/5 b. (10a + b) – (10x + z) could NOT equal
Choose the correct choice from the following
A) 36 B) 33 C) 44 D) 64 E) 56

Solution: a=5x , b =5z therefore(5x*10+5z) - (10x +z) = (5-1) (10x+z) =.(10x+Z)   number should be divisible by 4   33
Answer: B
A man took loan from a bank at the rate of 12% p.a. S.I. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was? Select.
A) 3887
B) 2768
C) 15000
D) 76887
E) 16711

Solution: Principal = (100 * 5400) / (12 * 3) = Rs. 15000   Answer: 15000
Answer: C
A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A. Options:  A) 240  B) 88  C) 66  D) 528  E) 22

Solution: (3*8 + 2*4):(4*8 + 5*4)   8:13   8/21 * 630 = 240.240nswer:240
Answer: A
What is the sum of this series?
1, 3, 5, 7, 9, ...... 77.  Choices:
A) 1666	B) 1555	C) 1777	D) 1444	E) 1333

Solution: Number of odd numbers between 1 and 59 is (77+1)/2=38   Therefore Sum of odd numbers   38*38= 
  38*38 = 1_444
1444   ANSWER: 1444
Answer: D
A box has 10 black and 10 white balls. What is the probability of getting two balls of the same color?	Choose the correct choice from the following answers
A) 9/18
B) 9/19
C) 9/12
D) 9/11
E) 9/13

Solution: ANSWER:9/19
Answer: B
The G.C.D. of 1.08, 0.32 and 0.9 is:  Answers
A) 0.02 B) 0.9 C) 0.18 D) 0.108 E) None

Solution: EXPLANATION   Given numbers are 1.08, 0.32 and 0.90. H.C.F. of 108, 32 and 90 is 2,   H.C.F. of given numbers = 0.02.   0.02nswer 0.02
Answer: A
If 225/999=0.225, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? Choose the correct choice from the following answers.
A) 9	B) 8	C) 7	D) 6	E) 5

Solution: 0.[u]225[/u = 0.225225225.....   Every 3rd digit is 5 and every multiple of 3 will be the digit 5. Since 81 is multiple of 3, the 81st digit is 5.   Answer 5
Answer: E
List L: ABC, BCA, CAB
In list L above, there are 2 positive integers, where each of A, B, and C is a different nonzero digit. Which of the following is the sum of all the positive integers that MUST be factors of the sum of the integers in list L?
Pick one:
A) 47
B) 114
C) 152
D) 161
E) 488

Solution: Let's try to sum the 2 given numbers taking their place values into account:   (100A + 10B + C) + (100B + 10C + A) + (100C + 10A + B)   = 100(A + B + C) + 10(A + B + C) + (A + B + C)   = 111*(A + B + C)   We know 111 = 37 * 3 so the sum will certainly have 1, 3, 37 and 111 as factors. 1 + 3 + 37 + 111 = 152   Note: How do we know that (A + B + C) will not give us a factor that we get every time? Try and take a few cases where A, B and C have different characteristics e.g. case 1: they are all odd, case 2: they are all even with no multiple of 3 etc. We want to see if there are cases where (A+B+C) has no common factors with other cases.   Let's say A, B and C are all odd. 1+3+5 = 9. Factors 3 and 3   A, B and C are all even. 2+4+8 = 14. Factors 2 and 7   Other factors will depend on values of A, B and C. Hence there is no other factor which we MUST get.   161
Answer: D
In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.3 times as old as Robert? Choose the correct choice from the following choices:
A) 1960  B) 1965  C) 1970  D) 1975  E) 2040

Solution: In 1950: Ri = 4 Ro -------------- eq1   In 1955: Ri +5 = 3(Ro+5)---------eq2   Thus in 1950, solving eq1 and eq2   Ro= 10 , Ri =40   Now for each year we can calculate:   1960: Ri = 50 , Ro =20   1965: Ri= 55, Ro=25   2040: Ri= 100, Ro = 130   Thus Ans:2040
Answer: E
What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, 35, 38, x	Choose the most appropriate option:
A) 29 B) 31 C) 23 D) 43 E) 53

Solution: (43)   The pattern is + 3, + 5, + 3, + 5, …………   So the missing term is = 38 + 5= 
38 + 5 = 43
43.
Answer: D
How many 4-digit numbers are completely divisible by 7? Select.
A) 1354  B) 1286  C) 1178  D) 1224  E) None

Solution: Solution: 4- digit numbers divisible by 7 are: 1001, 1008, 1015….. 9996.   This is an A.P. in which a=1001, d=7, l=9996.   Let the number of terms be n.   Then Tn=9996. .'. a+(n-1)d=9996   => 1001+(n-1)7= 9996   =>(n-1)7=8995   =>(n-1)= 8995/7= 
8995/7 = 1_285
1285=> n=1286.   .'. number of terms =1286.   Answer 1286
Answer: B
A certain club has 10 members, including Rarry. One of the 10 members is chosen at random to be the president, one of the remaining 9 members is to be chosen at random to be the secretary, and one of the remaining 8 members is to be chosen at random to be the treasurer. What is the probability that Rarry will be either the member chose to be secretary or the member chose to be treasurer?	Answers:
A) 1/720 B) 1/80 C) 1/10 D) 1/9 E) 1/5

Solution: In order to become a secretary the person cannot be chosen as a president. This can be done in 9/10 ways. Then to become a secretary this person's probability is 1/9   Probability to become a secretary = (9/10 * 1/9) = 1/10   Similar concept for treasurer. Probability of not president = 9/10, Probability of not secretary = 8/9, probability of treasurer 1/8   probability to become a treasurer = (9/10 * 8/9 * 1/8) = 1/10   Since, the problem is saying Rarry secretary OR Treasurer it is addition: 1/10 + 1/10 = 1/5=1/5
Answer: E
If a and b are positive integers and (2^a)^b = 2^7, what is the value of 2^a*2^b?	Choose one.
A) 16  B) 32  C) 64  D) 256  E) 128

Solution: 2^ab =2^7 therefore ab=7 either a=1 or 7 or b=7 or 1   therefore 2^a* 2^b = 2^(a+b)= 2^8 =256   256
Answer: D
The average temperature of the first three days is 27∘C and that of the next three days is 29∘C. If the average of the whole week is 28.5∘C, the temperature of the last day of the week is :	Choose the correct choice from the following choices
A) 10.5∘C B) 21∘C C) 31.5∘C D) 42∘C E) None

Solution: Explanation:   Let the seventh day temperature be x. Then total temperature for the whole week is   3×27+3×29+1×x=7×28.5   x = 31.5   31.5∘Correct Option: 31.5∘C
Answer: C
If x and y are integer, which of the following must also be an integer?
I. xy
II. y/x
III. x
Pick one: A) I alone B) II alone C) III alone D) I and III E) None of the above

Solution: Let's take X = 4and Y = 3   XY which is an integer   Y/X = 3/4 Not an integer.   X alone is 4 which is an integer.   Hence I and III.
Answer: D
As x increases from 121 to 122, which of the following increases? I) x−1/x II) 17−1/x III) (17+x)/x Choose the correct choice from the following answers:
A) I,II only  B) I only  C) II only  D) III only  E) II,III only

Solution: On Increasing the value of x from 121 to 122   I) x−1/x will increase as 1/x will be very small and x will increase by 1 unit   II) 17−1/x Will Increase as the value of 1/x will decrease thereby increasing the value of 17-(1/x)   III) (17+x)/x = (17/x)+1 will Decrease as 1/x will decrease thereby decreasing the value of (17/x)   I,II onlynswer:I,II only
Answer: A
50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?  Choose the most appropriate option.
A) 140 days.	B) 140 days.	C) 120 days.	D) 100 days.	E) 110 days.

Solution: D   100 days.   After 5 days, the following situation prevails.   50 men can complete the work in 60 days.   30 men can complete the work in ? days.   M1 100 days.1 = M2 100 days.2   => 50 * 60 = 30 * 100 days.2   => 100 days.2 = (50 * 60)/30= 
(50 * 60)/30 = 100
100 days.
Answer: D
The odds in favour of an events are 3:5. The probability of occurrence of the event is
Pick one.
A) 3/8
B) 2/7
C) 1/3
D) 2/5
E) 6/7

Solution: Number of cases favourable to E = 3   Total number of cases = 3+5= 
3+5 = 8
8   P(E)= 3/8   3/8nswer is 3/8
Answer: A
Two pipes A and B can fill a tank in 15 min and 20 min respectively. Both the pipes are opened together but after 4 min, pipe A is turned off. What is the total time required to fill the tank?
Choose the correct choice from the following answers: A) 14 min 70 sec B) 14 min 60 sec C) 14 min 47 sec D) 14 min 40 sec E) 13 min 40 sec

Solution: Part filled in 4 minutes = 4(1/15 + 1/20) = 7/15   Remaining part = 1 - 7/15 = 8/15   Part filled by B in 1 minute = 1/20   1/20 : 8/15 :: 1 ; x   x = 8/15 * 1 * 20 = 10 2/3 min = 10 min 40 sec.   The tank will be full in (4 min. + 10 min. 40 sec)   = 14 min 40 sec.   Answer: 14 min 40 sec
Answer: D
There are two boxes,one containing 39 red balls & the other containing 26 green balls.you are allowed to move the balls b/w the boxes so that when you choose a box random & a ball at random from the chosen box,the probability of getting a red ball is maximized.this maximum probability is
Choices:
A) 0.9  B) 0.8  C) 0.5  D) 0.7  E) 0.2

Solution: Ans: Very interesting question.   As we are allowed to move the balls, we keep only one red ball in first box and move all the remaining balls to the second box   So fist box contains 1 redball, second box contains 38 red + 26 green = 64 balls   Probability of choosing any box is 1/ 2.   So probability of taking one red ball = 12×(1)+12(3864)≃0.8   Answer:0.8
Answer: B
A train of 25 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.0 km long?
Choose the correct choice from the following answers:	A) 2.5	B) 3	C) 5	D) 7	E) 9

Solution: D = 25 * 60 + 1000= 
25 * 60 + 1000 = 2_500
2500 m   T= 2500/60 * 18/5= 
2500/60 * 18/5 = 150
150 sec= 2.5 mins   2.5nswer: 2.5
Answer: A
When positive integer W is divided by 6 the remainder is 3. Which of the following CANNOT be an even integer?
Choose the correct choice from the following choices:	A) a. k + 1	B) b. k -11	C) c. 4k + 2	D) d. (k-3)/3 +2	E) e. W/3

Solution: When positive integer W is divided by 6 the remainder is 3   So, W could equal 3, 9, 15, 21, etc   let's TEST W =3   a.3+ 1 = 4 (EVEN)   b.3-11 = -8 (EVEN)   c. 4(3) + 2 = 14 (EVEN)   d. (3-3)/3 +2 = 2 (EVEN)   At this point, we can already see the answer must be E.   Let's check e. W/3 forfun   e.3/3 = 1 (ODD)   Great!   Answer: e. W/3
Answer: E
Find the amount on Rs.8000 in 9 months at 20% per annum, if the interest being compounded quarterly?	Choose the correct choice from the following choices:
A) 9287	B) 9261	C) 9229	D) 9285	E) 2788

Solution: A = 8000(21/20)3   = 9261   Answer: 9261
Answer: B
If 0 < A < Y, A is an odd number and Y is a prime number, which of the following can be the value of A + Y ?	Choose the correct choice from the following options
A) 11.	B) 13.	C) 17.	D) 10.	E) 7.

Solution: If A is odd ,implies a(odd)+y(odd/even prime)=(Even/Odd)   If Y is even, the 2 is the even prime , therefore y=2A=1 since 0<A<Y therefore A+Y =3. But 3 is not an option   which implies y is odd,   Now A(odd)+Y(odd)=Even   10 is the only option that is even=10.
Answer: D
One vessel contains a mixture of 5 parts pure wine and 3 parts soda, whereas the other vessel contains a mixture of 7 parts pure wine and 5 parts soda. Compare the strength of the wine.	Choose the correct choice from the following answers.
A) 35;36 B) 7 : 8 C) 15 : 14 D) 14 : 5 E) None of these

Solution: 5/8 : 7/12   L15 : 14M of 8,12 = 24   (5/8)*24 : (7/12)*24   15:14   Answer is 15 : 14.
Answer: C
Employees at a company will vote for an executive team of five people from eight qualified candidates. The executive team consists of a president, a treasurer, and three warrant officers. If an executive team is considered different if any of the same people hold different offices, then how many possible executive teams S could be selected from the eight candidates?
Choose the correct answer.
A) 56	B) 120	C) 210	D) 1120	E) 6720

Solution: If an executive team is considered different if any of the same people hold different offices,....   so you will not have answer as 6720..   president could be by any of 8 person..   treasurer could be any out of remaining 7 person..   remaining three order does not matter, so we have to choose 3 out of 6=6c3=20..   total ways S= 8*7*20=1120..   ans 1120...
Answer: D
Find the least number of five digits which is exactly divisible by 12, 15 and 18?  Choose the correct answer.
A) 1080	B) 10080	C) 10025	D) 11080	E) 12000

Solution: LCM = 180   180) 10000 (55   9900   ---------   100   10000 + 180 - 100= 
10000 + 180 - 100 = 10_080
10080   ANSWER:10080
Answer: B