MU-NLPC/Calc-aqua_rat huggingface dataset:
In a certain village, 200 litres of water are required per household per month. At this rate, if there are 5 households in the village, how long (in months) will 2000 litres of water last? Choose one:
A) 9	B) 5	C) 6	D) 2	E) 4

Solution: I find it much easier to understand with real numbers, so choose (almost) any numbers to replace m,n and p:   In a certain village,m 200 litres of water are required per household per month. At this rate, if there aren 5 households in the village, how long (in months) willp2000litres of water last?   Water required is 200*5= 
200*5 = 1_000
1000 (m*n)   Water available is 2000 (p)   It will last 2 months (p/m*n)   Ans : 2
Answer: D
What is the place value of 3 in the numeral 3259 Pick one
A) 2000
B) 2500
C) 2600
D) 3000
E) 3100

Solution: Option '3000'    3 * 1000= 
 3 * 1000 = 3_000
3000
Answer: D
A car dealership sold two cars: the first car at a 10% profit and the second car at a 10% loss, which gave them an overall profit margin of 5% from these two sales. If the dealership's total profit was $1000, what was the sale price of each car?	Select the correct option
A) $5,000 and $1,000
B) $9,000 and $5,000
C) $11,000 and $9,000
D) $15,000 and $5,000
E) $20,000 and $10,000

Solution: lets denote cost of Car1 as c1 and cost car2 as c2 respectively.   overall sale resulted in a profit of 5%   => profit from first sale - loss from second sale still yielded in overall 5% profit   => (10/100)c1 - (10/100)c2 = (5/100)(c1+c2)   => c1 = 3c2 ----equation 1   Overall profit = 1000   =>(5/100)(c1+c2) = 1000   => c1+c2 = 20000------equation 2   from 1 and 2 we can find out values of c1 and c2.   c2=5000   c1 = 15000   Answer is $15,000 and $5,000.
Answer: D
One year ago, the ratio of Gaurav’s and Sachin’s age was 6: 7 respectively.Four years hence, this ratio would become 7: 8. How old is Sachin ?	Pick.
A) 27 years B) 36 years C) 12 years D) 41 years E) 35 years

Solution: Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively. Then, Gaurav's age   4 years hence = (6x + 1) + 4 = (6x + 5) years.   Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 5) years.   6x+5 = 7   ____ _   7x+5 8   8(6x+5) = 7 (7x + 5)   48x + 40 = 49x + 35   x = 5.   Hence, Sachin's present age = (7x + 1) = 36 years   Answer is 36 years.
Answer: B
If 2x+3y+z=55,x-y=4 and y - x + z=12,then what are the values of x , y and z?	Choose the correct choice from the following choices:	A) 11,8,	B) 8,11,7	C) 8,7,11	D) 11,7,8	E) 7,11,8

Solution: The given equations are:   2x+3y+z=55 …(i); x + z - y=4 …(ii); y -x + z =12 …(iii)   Subtracting (ii) from (i), we get: x+4y=51 …(iv)   Subtracting (iii) from (i), we get: 3x+2y=43 …(v)   Multiplying (v) by 2 and subtracting (iv) from it, we get: 5x=35 or x=7.   Putting x=7 in (iv), we get: 4y=44 or y=11.   Putting x=7,y=11 in (i), we get: z=8.   Answer is 7,11,8.
Answer: E
A man sitting in a train which is travelling at 50 kmph observes that a goods train, travelling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed?  Options.
A) 52 kmph.	B) 62 kmph.	C) 72 kmph.	D) 80 kmph.	E) None

Solution: Solution   Relative Speed	= (280 / 9)m/sec   = (280/9 x 18/5)   = 112 kmph.   Speed of the train	= (112 - 50)= 
(112 - 50) = 62
62 kmph.   Answer 62 kmph.
Answer: B
A local bank that has 8 branches uses a two-digit code to represent each of its branches. The same integer can be used for both digits of a code, and a pair of two-digit numbers that are the reverse of each other (such as 17 and 71) are considered as two separate codes. What is the fewest number of different integers required for the 8 codes?	Select
A) 4  B) 6  C) 5  D) 3  E) 7

Solution: Pick any two integer.   Integers: 12   Code: 11, 12, 21, 22 = 4 Codes   Add one more integer: 3   13, 31, 33, 23, 32 = 5 Codes   Total = 9 Codes. Enough.   Answer: 3
Answer: D
If there are 4 peanuts in a box and Mary puts 4 more peanuts inside, how many peanuts are in the box? Pick one:
A) 8
B) 9
C) 10
D) 11
E) 12

Solution: 4+4= 
4+4 = 8
8   correct answer is 8)8
Answer: A
A package contains 8 black and 14 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?	Select
A) 3/5
B) 7/11
C) 6/8
D) 7/9
E) 1/3

Solution: Let number of balls = (8+14)= 
(8+14) = 22
22.   Number of white balls= 14.   P (drawing a white ball) =	14/22=7/11   7/11
Answer: B
At what time between 5.30 and 6 will the hands of a clock be at right angles?
Choose the correct choice from the following answers:
A) (43 + 7/11) min pats 7	B) (43 + 7/11) min pats 5	C) (43 + 7/11) min pats 4	D) (43 + 7/11) min pats 2	E) (43 + 7/11) min pats 1

Solution: At 5 o'clock, the hands are 25 min. spaces apart.   To be at right angles and that too between 5.30 and 6, the minute hand has to gain   (25 + 15)= 
  (25 + 15) = 40
40 min. spaces.   55 min. spaces are gained in 60 min   40 min. spaces are gained in min   Answer: (43 + 7/11) min pats 5
Answer: B
Each customer of a networking company subscribes to one of two plans: Plan A or Plan B. Plan A costs $75 per month and Plan B costs $175 per month per customer. If the company’s average revenue per customer per month is $150, then what percent of the company's revenue comes from customers with Plan A?  Choose the most appropriate option.
A) 25% B) 30% C) 37.5% D) 56.25% E) 75%

Solution: We can show this algebraically:   If there are A customers with plan A, and B customers with plan B, then the total revenue is $75A + $175B.   Since the average customer pays $150, we know that   $150 = ($75A + $175B) / (A + B)   $150(A + B) = ($75A + $175B)   $150A + $150B = $75A + $175B   $75A = $25B   3A = B.   Since there are 1/3 times as many $75 clients as $175 clients, for every $175 received from Plan B customers, 3($75) = $75 is received from Plan A customers, and the percent of revenue from customers with Plan A is:   $75/($75 + $175)= 30%.   The correct answer is choice (30%).
Answer: B
The annual budget of a certain college is to be shown on a circle graph. If the size of each sector of the graph is to be proportional to the amount of the budget it represents, how many degrees of the circle should be used to represent an item that is 40 percent of the budget?
Answers.
A) 15 ° B) 144 ° C) 54 ° D) 90 ° E) 150 °

Solution: 100 percent = 360 degrees   40 percent = 360*40/100= 
360*40/100 = 144
144 degrees   Answer is 144 °.
Answer: B
A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?	Pick one:
A) Rs. 4991	B) Rs. 5991	C) Rs. 6001	D) Rs. 6991	E) Rs. 6992

Solution: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.   Required sale = Rs. [ (6500 x 6) - 34009 ]   = Rs. (39000 - 34009)   = Rs. 4991.   Rs. 4991nswer Rs. 4991
Answer: A
X and Y started a business with capitals Rs. 20000 and Rs. 25000. After few months Z joined them with a capital of Rs. 30000. If the share of Z in the annual profit of Rs. 50000 is Rs. 14000, then after how many months from the beginning did Z join?  Answers
A) 6  B) 7  C) 4  D) 9  E) 5

Solution: Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000   Let investment period of Z be x months.   Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)   = 240 : 300 : 30x = 8 : 10 : x   The share of Z in the annual profit of Rs. 50000 is Rs. 14000.   => [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7   => 25x = 7x + (18 * 7) => x = 7 months.   Z joined the business after (12 - 7) months. i.e., 5 months.   Answer: 5
Answer: E
If a company allocates 25 percent of its budget to advertising, 15 percent to capital improvements, and 55 percent to salaries, what fraction of its budget remains for other allocations?  Choose one
A) 4/5
B) 3/5
C) 3/10
D) 1/20
E) 1/40

Solution: 25 + 15 + 55= 
25 + 15 + 55 = 95
95% 100 - 95= 5% to all others   1/20
Answer: D
A shopkeeper sells 400 metres of cloth for Rs. 18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth?
Choose the correct choice from the following answers
A) 12  B) 27  C) 29  D) 50  E) 21

Solution: SP per metre = 18000/400 = Rs. 45 Loss per metre = Rs. 5 CP per metre = 45 + 5 = Rs. 50.Answer: 50
Answer: D
From a group of 4 boys and 4 girls, 6 children are to be randomly selected. What is the probability that 3 boys and 3 girls will be selected?  Pick one: A) 1/2 B) 2/3 C) 3/5 D) 4/7 E) 5/9

Solution: The total number of ways to choose 6 children from 8 is 8C6 = 28   The number of ways to choose 3 boys and 3 girls is 4C3*4C3 = 4*4= 
4*4 = 16
16   P(3 boys and 3 girls)= 16/28 = 4/7   The answer is 4/7.
Answer: D
A man is walking at a speed of 6 km per hour. After every km he takes rest for 6 minutes. How much time will he take to cover a distance of 12 km.	Answers:
A) 3 hr
B) 5 hr 42 min
C) 4 hrs. 10 min
D) 3 hr. 6 min
E) None of these

Solution: Explanation:   For 12 km he takes 11 times rest.   11 x 6 = 66 minutes rest   = 1 hr 6 min   For 12 km, 2 hr is required + rest   = 2 + 1 hr 6m = 3 hr. 6 min   Answer: Option 3 hr. 6 min
Answer: D
Average of all prime numbers between 20 to 50  Select the correct option
A) 37  B) 37.8  C) 39  D) 39.8  E) 35.8

Solution: 35.8xplanation:   Prime numbers between 20 and 50 are:   23, 29, 31, 37, 41, 43, 47   Average of prime numbers between 20 to 50 will be   (23+29+31+37+41+43+47 / 7)=251 / 7=35.8   Option 35.8
Answer: E
If the number 52,1n9, where n represents the tens digit, is a multiple of 3, then the value of n could be which of the following? Choose one:  A) 6  B) 5  C) 3  D) 1  E) 0

Solution: Maybe you are misreading the question but it is saying that 52,1n9 is a multiple of 3 and not necessarily n is a multiple of 3.   The sum of the digits 5 + 2 + 1 + n + 9 must be a multiple of 3   17 + n must be a multiple of 3   substituting the numbers n must = 1   ANSWER:1
Answer: D
A train 500 m long passed a pole in 50 sec. How long will it take to pass a platform 1000 m long?  Choose the correct choice from the following answers.
A) 28 sec B) 89 sec C) 85 sec D) 150 sec E) 15 sec

Solution: Speed = 500/50= 
500/50 = 10
10 m/sec.   Required time= (500 + 1000)/10= 
(500 + 1000)/10 = 150
150 sec.   Answer:150 sec
Answer: D
24 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus?
Choose the correct choice from the following options.
A) None of these  B) 552  C) 512  D) 524  E) 542

Solution: Explanation :   He can go in any bus out of the 24 buses.   Hence He can go in 24 ways.   Since he can not come back in the same bus that he used for travelling,   He can return in 23 ways.   Total number of ways = 24x 23 = 552. Answer : Option 552
Answer: B
A box contains 15 mangoes out of which 8 are spoilt. If eight mangoes are chosen at random, find the probability that A number is selected at random from first twenty natural numbers. What is the chance that it is a multiple of either 4 or 15?	Pick one
A) 17/10
B) 1/10
C) 7/10
D) 1/5
E) 3/10

Solution: The probability that the number is a multiple of 4 is 5/20. (Since 4*5= 
4*5 = 20
20).   Similarly the probability that the number is a multiple of 15 is 1/20. {Since   15*1= 
  15*1 = 15
15).   Neither 4 nor 15 has common multiple from 1 to 20. Hence these events are mutually exclusive events. Therefore chance that the selected number is a multiple of 4 or 15 is (5+1)/20= 3/10.   ANSW3/10R:3/10
Answer: E
If a is a positive integer, and if the units digit of a^2 is 9 and the units digit of (a+1)^2 is 4, what is the units digit of (a+2)^2?  Choices:  A) 1  B) 3  C) 5  D) 6  E) 14

Solution: For unit digit of a^2 to be 9...unit digit of a has to be 3 or 7...   Now for unit digit of (a+1)^2 to be 4..unit digit of a has to be 1 or 7....   From the above two conditions, unit value of a has to be 7, which will satisfy both the conditions...   Now id unit digit of a is 7, unit digit of (a+2)^2 hast to be 1.   1NSWER:1
Answer: A
Mixture A is 40 percent alcohol, and mixture B is 80 percent alcohol. If the two are poured together to create a 4-gallon mixture that contains 50 percent alcohol, approximately how many gallons of mixture A are in the mixture?
Choices.
A) 1.5  B) 1.7  C) 2.3  D) 2.5  E) 2.4

Solution: (80-50)/(50-40) = Qa/Qb   30/10 = Qa/Qb   3/1 = Qa/Qb   Qa = (3/5) * 4 = 12/5= 
12/5 = 12/5 = around 2.4
2.4 approx   Answer : 2.4
Answer: E
A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is: Choose the correct option.
A) 10	B) 100	C) 50	D) 200	E) 300

Solution: 2 kmph =	(2 x	5/18	)m/sec =	5/9	m/sec.   4 kmph =	(4 x	5/18	)m/sec =	10/9	m/sec.   Let the length of the train be x metres and its speed by y m/sec.   Then,(x/y -5/9)= 9 and(x/y -10/9)= 10.   9y - 5 = x and 10(9y - 10) = 9x   => 9y - x = 5 and 90y - 9x = 100.   On solving, we get: x = 50.   Therefore Length of the train is 50 m.   Answer: 50
Answer: C
In how many different ways can the letters of the word 'RUMOUR' be arranged ?	Choose the correct choice from the following options
A) 90	B) 270	C) 350	D) 790	E) 180

Solution: The word 'RUMOUR' contains 6 letters, namely 2R, 2U, 1M and 1U.   ∴ Required number of ways = 6!/(2!)(2!)(1!)(1!) = 180.   Answer is 180
Answer: E
Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A?	Select
A) 7  B) 6  C) 5  D) 4  E) 3

Solution: There are five letters in the given word.   Consider 5 blanks ....   The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.   The number of words = 3! = 6.   Answer: 6
Answer: B
Group A has 3 boys and 2 girls, group B has 4 boys and 4 girls and group C has 3 boys and 3 girls. One student is selected from each of the group. Find the probability that one girl and two boys are among the three selected?	Options:
A) 2/5  B) 1/18  C) 9/5  D) 2/3  E) 77/272

Solution: Group A has 3 boys and 2 girls; 5   Group B has 4 boys and 4 girls; 8   Group C has 3 boys and 3 girls. 6   Selected group should have one girl and two boys.   Girl from A, boy from B, boy from C: 2/5*4/8*3/6 = 1/10;   Boy from A, girl from B, boy from C: 3/5*4/8*3/6 = 3/20;   Boy from A, boy from B, girl from C: 3/5*4/8*3/6 = 6/40.   Sum = 1/10 + 3/20 + 6/40 = 2/5.   2/5nswer: 2/5.
Answer: A
An engineer undertakes a project to build a road 15 km long in 300 days and employs 50 men for the purpose. After 100 days, he finds only 2.5 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time. Choose the correct choice from the following options:  A) a. 43  B) b. 45  C) c. 75  D) d. 68  E) e. 60

Solution: 50 workers working already   Let x be the total men required to finish the task in next 200 days   2.5 km done hence remaining is 12.5 km   Also, work has to be completed in next 200 days (300 - 100 = 200)   We know that, proportion of men to distance is direct proportion   and, proportion of men to days is inverse proportion   Hence, X = (50 * 12.5 * 100) / (2.5 * 200)   thus, X = 125   Thus, more men needed to finish the task = 125-50= 
125-50 = 75
75   hence Answer is c. 75
Answer: C
A 300 meter long train crosses a platform in 36 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Pick.
A) 300m
B) 278m
C) 350m
D) 228m
E) 282m

Solution: Speed = [300 / 18] m/sec = 50/3 m/sec.   Let the length of the platform be x meters.   Then, x + 300 / 36   = 50/3   3(x + 300)   = 1800 è x   = 300m.   300mnswer:300m
Answer: A
A shopping cart contains only apples, oranges, and pears. If there are twice as many oranges as apples, and four times as many pears as oranges, then the apples are equivalent to what fraction of the pears? Choose the correct choice from the following answers.
A) 1/6  B) 1/8  C) 2/3  D) 1/3  E) 1/4

Solution: O = 2A   P = 4O = 8A   A = P/8   The answer is 1/8.
Answer: B
The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?	Select the correct option
A) 15√2 cm  B) 13√2 cm  C) 16√2 cm  D) 17√2 cm  E) 18√2 cm

Solution: 4a = 48 4a = 20   a = 12 a = 5   a2 = 144 a2 = 25   Combined area = a2 = 169 => a = 13   d = 13√2   ANSWER:13√2 cm
Answer: B
How many positive integers except zero that are less than 10,000 can be formed using the digits 0, 1, 2, 3, 4, 6, 78? Choices
A) 5000  B) 4096  C) 6560  D) 4095  E) 8000

Solution: According to what i have read - it is always better to assume natural numbers beginning from 01 onward (for the gmat) unless otherwise stated. Assuming that to be the case we can sub divide the problem into :   A) Four digit Numbers : _ _ _ _ , The ones place - hundreds place can be filled by any one of the 8 numbers given (the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) the thousands place can be filled by any number except0.. This gives us 7 x 8 x 8 x 8 = 3584   B) Three digit Numbers : _ _ _ , The ones place - tens Place can be filled by any one of the 8 numbers given ( the problem speaks nothing about NOT REPEATING the numbers so we have to assume that they can be repeated) , the hundreds place can be filled by only 7 of the given 8 numbers (If we use0we will end up with a two digit number ). This gives us 7 x 8 x 8 = 448   C) Two digit numbers : _ _ , The ones place can be filled up by any one of the 8 numbers given , and the tens place by any 7 of the 8 ... This gives us 7 x 8 = 56   D) Assuming that zero is not a natural number , we have seven different possibilities for the one digit numbers . 7   Add A + B + C + D , This gives us 3584 + 448 + 56 + 7= 
3584 + 448 + 56 + 7 = 4_095
4095 (D)   Now let us assume that ZERO is a NATURAL number (as some mathematicians do) ... A thru C is not effected by this assumption as the resultant would have meant that a four number digit with a zero at the beginning would have effectively made it a three digit no. , and a 0 to begin a three digit number would make it a two digit number etc ... The only difference including ZERO to be a natural number would have made for D , in that it would have given it 8 possibilities instead of 7 ... Which would have added 1 to our total making it 4096. Simply by looking at the answer choices we can determine that the test maker wanted natural numbers to begin from 1 and not from 0 ( as per the answer choices) ..
Answer: D
At a certain paint store forest green is made by mixing 4 parts blue paint with 3 parts yellow paint.Verdant green is made by mixing 4 parts yellow paint with 3 parts blue paint.How many liters of yellow paint must be added to 28 liters of forest green to change it to Verdant green?
Choose the correct choice from the following answers:
A) 28/3	B) 13/6	C) 3	D) 4	E) 14/3

Solution: 28 liter of Forset green have 16 liter of blue and 12 liter of yellow   Suppose we add x liter of yellow to make it a verdant green so the ratio of blue to yellow in verdant green is ¾ so the equation is   Blue/yellow =16/(12+x) = ¾   36+3x=64 => x =28/3   28/3nswer : 28/3
Answer: A
A man can row his boat with the stream at 12 km/h and against the stream in 4 km/h. The man's rate is?  Pick.
A) 1 kmph  B) 4 kmph  C) 98 kmph  D) 6 kmph  E) 4 kmph

Solution: DS = 12   S = ?   S = (12 - 4)/2= 
(12 - 4)/2 = 4
4 kmph   Answer: 4 kmph
Answer: E
Tanya prepared 4 different letters to 4 different addresses. For each letter, she prepared one envelope with its correct address. If the 4 letters are to be put into the four envelopes at random, what is the probability that only one letter will be put into the envelope with its correct address? Options
A) 1/24 B) 1/8 C) 1/4 D) 1 by 3 E) 3/8

Solution: The number of ways to put exactly one letter in the right envelope is not equal to 4C1. There are 4C1 ways to choose which letter goes in the right envelope, but you then need to work out how many ways the remaining letters can be placed in the wrong envelope. For the first of these three letters, there are 2 wrong envelopes you could choose. Now, you still have one letter left which has its matching envelope unused; you must put this letter in the wrong envelope, so you have only 1 choice for this letter, and finally for the last letter you have only 1 choice for where to put it. So you have  2*1*1= 
 2*1*1 = 2
2 ways to assign the remaining letters incorrectly, which is why you need to multiply your answer by 2.   I posted a slightly different solution to BTG a while ago, which I'll paste here:   One letter goes in the right envelope. It doesn't matter which envelope this is- there are three envelopes left. 2/3 chance the next letter goes in the wrong envelope, 1/2 the next one does, and 100% the last one does- its envelope must have been used already.   (2/3)(1/2)= 1/3.   Slightly old post, but very interesting explanation...   Just would like to add my 2 cents:   For 1 letter to go in right envelope - probability = 1/4   For 2nd letter to go in wrong envelope - probability = 2/3   For 3rd letter to go in wrong envelope - probability = 1/2   For 4th letter to go in wrong envelope - probability = 1   Now, in the order this arrangement can be done:   C - Letter going into correct envelope   W - Letter going into wrong envelope   No#1. C - W - W - W   No#2. W - C - W - W   No#3. W - W - C - W   No#4. W - W - W - C   There are 4 ways, it can be done   So, probability of 1 letter going in correct envelope: 4* (1/4) * (2/3) * (1/2) * 1 =1/3 1 by 3
Answer: D
a person has 12004 coins of silver. How much would he need to add so that he can distribute equally among his seven children in whole numbers? Pick one:
A) 1 coin B) 2 coins C) 3 coins D) 4 coins E) coins

Solution: He would need to add one coin more so 12005 is fully divisible by 7 and each would get 1715 coins. So the correct answer is 1 coin
Answer: A
The average weight of a group of boys is 20 kg. After a boy of weight 36 kg joins the group, the average weight of the group goes up by 1 kg. Find the number of boys in the group originally ?	Choose the correct choice from the following choices: A) 12 B) 15 C) 18 D) 24 E) 10

Solution: Let the number off boys in the group originally be x.   Total weight of the boys = 20x   After the boy weighing 36 kg joins the group, total weight of boys = 20x + 36   So 20x + 36 = 21(x + 1) = > x = 15   ANSWER:15
Answer: B
A student can select one of 7 different math book, one of 3 different chemistry book & one of 4 different science book.In how many different ways students can select book of math, chemistry & science.  Choose the correct choice from the following options
A) 22  B) 84  C) 99  D) 37  E) 01

Solution: 7C1×3C1×4C1 = 7x3x4=84 ways   Answer:84
Answer: B
Three printing presses, Q, S, and T, working together at their respective constant rates, can do a certain printing job in 4 hours. S and T, working together at their respective constant rates, can do the same job in 5 hours. How many hours would it take Q, working alone at its constant rate, to do the same job?  Pick one.
A) 8
B) 10
C) 12
D) 15
E) 20

Solution: =1/4-1/5=1/20   Q can do 1/20 job in 1 hour   Q can do the whole job in 20 hours=20
Answer: E
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?  Choose the correct choice: A) 3/8 B) 7/16 C) 2/7 D) 9/16 E) 5/7

Solution: P(getting prize)=10/(10+25)   =10/35   =2/7   Option:2/7
Answer: C
A cistern 4m long and 2 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
Choose the most appropriate option.
A) 23 m2 B) 20 m2 C) 52 m2 D) 24 m2 E) 55 m2

Solution: Area of the wet surface	= [2(lb + bh + lh) - lb]   = 2(bh + lh) + lb   = [2 (2 x 1.25 + 4 x 1.25) + 4 x 2] m2   = 23 m2.   answer :23 m2
Answer: A