MU-NLPC/Calc-aqua_rat huggingface dataset:
A envelop weight 8.2 gm,if 800 of these envelop are sent with an advertisement mail. How much wieght?	Choose the correct answer
A) 6.56kg  B) 6.8kg  C) 6.7kg  D) 6.9kg  E) 7.8kg

Solution: 800*8.2   6560.0gm   6.56kg   6.56kgNSWER:6.56kg
Answer: A
A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work? Select: A) 7 B) 6 C) 5 D) 4 E) 3

Solution: B's 10 day's work = (10*1/15) = 2/3.   Remaining work =	(1- (2/3))=1/3   Now, 1/18 work is done by A in 1 day.   A= 18* 1/3= 
18* 1/3 = 6
6 DAYS   ANSWER:6
Answer: B
The breadth of a rectangular hall is two-thirds of its length. If the area of the hall is 2400 sq metres, what is the length in metres? Options:
A) 120 B) 80 C) 60 D) 40 E) None of these

Solution: Let the length of the rectangular hall be ‘x’ m, then the breadth of the rectangular hall = 2x⁄3 m.   Area of hall = 2x⁄3 × x = 2x2⁄3   or, 2x2⁄3 = 2400 or x = 60 m   Answer 60
Answer: C
A man can row 4 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man?	Choose the correct choice from the following:
A) 5.98	B) 3.98	C) 3.54	D) 3.87	E) 3.82

Solution: M = 4   S = 1.2   DS = 4.8   US = 2.8   x/4.8 + x/2.8 = 1   x = 1.77   D = 1.77* 2= 
1.77* 2 = 3.54
3.54   Answer:3.54
Answer: C
The standard model numbers of cell phones in a company are 1 letter followed by 6 digits. How many different model numbers are possible if letters and digits can be repeated?  Choose the most appropriate option:  A) 26 × 26 × 10 × 4  B) 26 x 100 000  C) 26 x 10  D) 26 × 25 × 24 × 10 × 9 × 8 × 7  E) 26 x 1 000 000

Solution: OFFICIAL SOLUTION:   (E) The formula for permutations of events is the product of the number of ways each event can occur. There are 26 letters and 10 digits. So there are 26 options for a letter, and 10 × 10 × 10 × 10 × 10 × 10 for the six digits. The number of different license plates is 26 × 10 × 10 × 10 × 10 × 10 × 10 = 26 × 1 000 000.   The correct answer is choice (26 x 1 000 000).
Answer: E
A,B,C can complete a piece of work in 25,5,10 days. Working together, they complete the same work in how many days? Choices:
A) 2
B) 4/5
C) 50/17
D) 10
E) 24/7

Solution: A+B+50/17 1day work = 1/25 + 1/5 + 1/10 = 17/50   A,B,50/17 together will complete the job in 50/17 days   Answer is 50/17
Answer: C
If 70 percent of 600 is 40 percent of x, then x=?	Pick one
A) 105
B) 168
C) 342
D) 660
E) 1050

Solution: Given: 0.7*600=0.4x --> 420=4/10*x --> x=1,050.   Answer: 1050.
Answer: E
Average of money that group of 4 friends pay for rent each month is $800.After one persons rent is increased by 20% the new mean is $860.What was original rent of friend whose rent is increased?	Choose the correct choice:
A) 800	B) 900	C) 1000	D) 1100	E) 1200

Solution: 0.2X = 4(860-800)   0.2X = 240   X = 1200   Answer 1200
Answer: E
In 100 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:	Choose the correct choice from the following options: A) 20 m B) 25 m C) 22.5 m D) 9 m E) 12 m

Solution: Distance covered by B in 9 sec. =	100/45 x 9	m = 20 m.   A beats B by 20 metres.   20 mnswer: Option 20 m
Answer: A
A fort of 4000 soldiers has provisions for 100 days. After 20 days some of them left and the food was now enough for the same period of 100 days as before. How many of them left?
Choose the correct answer:
A) 650	B) 700	C) 750	D) 800	E) 850

Solution: 2000 ---- 50   4000 ---- 80   x ----- 100   x*100 = 4000*80   x=3200   4000   -------   800   Answer: 800
Answer: D
Girl and Boy together can complete a piece of work in 35 days while Girl alone can complete the same work in 60 days. Boy alone will be able to complete the same working in:  Select the correct option:
A) 72	B) 75	C) 84	D) 88	E) 90

Solution: Subtraction of fraction   ab−cd=ad−cbbd   Girl   and 75oy finish one work with company = 35   days   (Girl+75oy)′   s one day’s work = 135   Girl alone finish the same work = 60   days   Girl′   s one day’s work = 160   75′   s one day’s work = (A+75)′s one day’s work - A′   s one day’s work   135−160=184   Hence 75 alone can complete the work in 84 days
Answer: B
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:  Choose the correct choice from the following answers
A) 15 hours
B) 20 hours
C) 25hours
D) 28 hours
E) 18 hours

Solution: Let the first pipe alone can fill the tank in x hours   Then the second pipe can fill the tank in (x-5) hours   and the third pipe can fill the tank in (x-5)-4 = (x-9) hours   part filled by first pipe and second pipe together in 1 hr = part filled by third pipe in 1 hr   (1/x)+1/(x−5)=1/(x−9)   (x−5)(x−9)+x(x−9)=x(x−5)   x^2−14x+45+x^2−9x=x^2−5x   −14x+45+x^2−9x=−5x   x^2−18x+45=0   (x−15)(x−3)=0   x=15 or 3   We can not take the value of x = 3 because, (x-9) becomes negative which is not possible   because the third pipe can fill the tank in (x-9) hours   Hence, x = 15   15 hoursnswer is 15 hours
Answer: A
You collect baseball cards. Suppose you start out with 15. Since her father makes baseball cards, Cindy decides to quadruple your baseball cards. Since you're nice, you give Mike 10 baseball cards. Tiffany gives you another 12 baseball cards. Pearl gives you another 23 baseball cards. How many baseball cards do you have at the end?	Choose the correct choice from the following options:
A) 55	B) 65	C) 75	D) 95	E) 85

Solution: Solution   Start with 15 baseball cards.   Cindy quadruples the number of baseball cards you have: 15 × 4 = 60 baseball cards.   Mike takes 10 baseball cards from you:   60 - 10= 
  60 - 10 = 50
50 baseball cards.   Tiffany gives you 12 baseball cards:   50 + 12= 
  50 + 12 = 62
62 baseball cards.   Pearl gives you 23 baseball cards:   62 + 23= 
  62 + 23 = 85
85 baseball cards.   So you have 85 at the end.   Correct answer : 85
Answer: E
It costs a man 75 dollars to buy the things that he needs to make hotdogs. The city allows him to sell his hotdog somewhere near the city hall. However, the city hall charges him 1 dollar for each hotdog sold
Calculate the break even point if the price he charges for 1 hotdog is $1.50 Choose the correct answer:
A) 140
B) 150
C) 160
D) 170
E) 180

Solution: Let x be the number of hotdogs sold   Let C be the cost of buying and selling x hotdogs   Let R be the revenue made for selling x hotdogs   R = selling price of 1 hotdog × number of hotdogs sold   R = 1.50x   C = fixed cost + variable cost   variable cost = fee charged for 1 hotdog × number of hotdogs sold   variable cost = 1x   C = 75 + 1x   R = C   1.50x = 75 + 1x   1.50x - 1x = 75 + 1x - 1x   0.5x = 75   x = 150 since 0.5 × 150 = 75   The break even point is to sell 150 hotdogs.   Answer 150
Answer: B
In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?  Choose the correct choice from the following.
A) 3	B) 5	C) 4	D) 6	E) 7

Solution: T = 60/36 * 18/5= 
60/36 * 18/5 = 6
6 sec   Answer:6
Answer: D
A contractor is engaged for 30days on the condition that he receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.490 in all. For how many days was he absent?	Choose the correct answer.
A) 8 B) 10 C) 15 D) 17 E) 19

Solution: 30 * 25= 
30 * 25 = 750
750   490   -----------   260   25 + 7.50= 
25 + 7.50 = 32.5
32.5   260/32.5= 
260/32.5 = 8
8   8
Answer: A
{-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number selected will be a solution of the equation (x-5)(x+8)(2x-5) = 0? Pick.
A) 1/12  B) 1/6  C) 1/4  D) 1/3  E) 1/2

Solution: Roots of the equation (x-5)(x+10)(2x-5)=0 are x=5,x=-8 and x=5/2=2.5. So, one solutions present in our set of 12 distinct numbers, therefore P=1/12   1/12nswer: 1/12.
Answer: A
The average score of a cricketer for seven matches is 56 runs. If the average for first four matches is 46, then average for last three matches is	Select:  A) 33.25  B) 32.25  C) 65  D) 67  E) 69

Solution: 69xplanation:   =(56×7)−(46×4)/3   =(392−184)/3=69   Answer: Option 69
Answer: E
Find the arithmetic mean L of all roots of the following equation- see an attachment. Answers
A) 2
B) 1
C) 0.5
D) -1/3
E) 0.3

Solution: arithmetic mean L your answer C and E are same, can you correct one of them please. thanks.0.5
Answer: C
If in a game of 80, P can give 16 points to Q and R can give 20 points to P, then in a game of 150, how many points can R give to Q? Choose the correct answer:
A) 48
B) 60
C) 54
D) 90
E) 100

Solution: Explanation:   When P scores 80, Q scores 64.   When R scores 80, P scores 60   Hence, when R scores 150, Q scores  (60 * 64 * 150) / (80 * 80)= 
 (60 * 64 * 150) / (80 * 80) = 90
90   Therefore, in a game of 150, R can give 60 points to Q.   ANSWER 60
Answer: B
Find: S.l. on Rs 3000 at 18% per annum for the period from 4th	Select
A) 118	B) 105	C) 108	D) 110	E) 111

Solution: Explanation:   (24 + 31 + 18)= 
(24 + 31 + 18) = 73
73 days= 1/5 year .   P = Rs 3000 and R = 18 % p.a.   S.I=(3000 *18 * 1/5)/100   ANSWER IS 108
Answer: C
In how much time will interest on Rs. 2300 at 4 1/2 percent p/a be Rs.310.50
Choose the correct choice from the following options.
A) 5years	B) 2years	C) 4years	D) 3 years	E) 2 1/2 years

Solution: 310 = (2300*T*9/2)/100   T = (310.50x100x2)/(300x9)= 3 years.   Answer: 3 years
Answer: D
What will be the fraction of 8%	Options.
A) 1/20	B) 1/50	C) 1/75	D) 2/25	E) None of these

Solution: Explanation:   8*1/100 = 2/25.   Option 2/25
Answer: D
Two boys picked up 30 mangoes .In how many ways can they divide them if all mangoes be identical?	Pick
A) A)4^30
B) B)2^30
C) C)1^30
D) D)3^30
E) E)6^30

Solution: Each Mango can be given to any one of the two people or in other words..30 mango can be divided into 2 ways...so all 30 can be divided in 2^30 ways   ANS:2^30
Answer: B
Compound interest earned on a sum for the second and the third years are Rs.12500 and Rs.14000 respectively. Find the rate of interest?	Options:  A) 18% p.a.  B) 22% p.a.  C) 20% p.a.  D) 12% p.a.  E) None of these.

Solution: Rs.14000 - 12500 = Rs.1500 is the interest on Rs.12500 for one year.   Rate of interest = (1500/12500) * 100= 
(1500/12500) * 100 = 12
12% p.a   ANSWER:12% p.a.
Answer: D
A bag contains six white and four red balls. Two balls are picked at random from the bag. What is the probability that they both are different color?	Choose the correct choice from the following
A) 15/8 B) 8/15 C) 5/6 D) 5/3 E) 5/1

Solution: Two balls can be picked from ten balls in 10Câ‚‚ ways.   We select one white ball and one red ball from five white balls and four red balls. This can be done âµ ways.   The required probability = (6 * 4)= 
(6 * 4) = 24
24/45= 8/15   Answer: 8/15
Answer: B
Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 1/4 of all the paint. During the second week, he uses 1/7 of the remaining paint. How many gallons of paint has Joe used?
Answers.
A) 18
B) 128
C) 175
D) 216
E) 250

Solution: Total paint initially = 360 gallons   Paint used in the first week = (1/4)*360= 
(1/4)*360 = 90
90 gallons.   Remaning paint= 270 gallons   Paint used in the second week = (1/7)*270 = 38 gallons   Total paint used = 128 gallons.   Option 128
Answer: B
Let d > c > b > q. If c is twice as far from q as it is from d, and b is twice as far from c as it is from q, then (d - b)/(d - q) = ?  Choices
A) 2/9
B) 1/3
C) 2/3
D) 7/9
E) 3/2

Solution: Draw a number line and label with x and y. You would have:   Before calculating recognize it would be more effcient to express x or y in terms of the other. here 2x = 3y so x =3/2 y.   Now you can calculate d -b and d -a   d - b= x +2y = 7/2 y   d - q = x + 2x = 3x = 9/2y   7/9ividing both you get: 7/9   Answer 7/9
Answer: D
The ratio of two numbers is 2/3, and if a 1 is subtracted from the numerator and a 1 is added to the remainder the ratio becomes 1/2, then the numbers are.	Choose one:  A) 6 and 9  B) 6 and 10  C) 6 and 8  D) 6 and 7  E) 6 and 11

Solution: a:b=2:3 b=3/2a   a-1/b+1=1/2   solving this we get a=6 and b=9   6 and 9NSWER:6 and 9
Answer: A
A jar full of whiskey contains 40% alcohol. A part of
this whiskey is replaced by another containing 19% alcohol
and now the percentage of alcohol was found to be 26%.
The quantity of whiskey replaced is?	Choose the correct choice from the following
A) 2/3 B) 1/3 C) 1/4 D) 1/2 E) 1/5

Solution: Strength of first jar 40% Strength of 2nd jar 19%   Mean Strength 26%   7 14   So,ratio of 1st and 2nd quantities =7:14 =1:2   Therefore required quantity replaced =2/3.   2/3NSWER 2/3
Answer: A
Which 2 digit number has its digits reversed when you double it and take 1?  Choose the correct choice.
A) 33	B) 34	C) 35	D) 36	E) 37

Solution: reverse it and you get 73 which is 2*37-1.   ANSW37R:37
Answer: E
The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 21 years. The ratio of their ages after 8 years will be  Choose the correct option:  A) 2 : 3  B) 20 : 17  C) 5 : 4  D) 3 : 5  E) 6 : 11

Solution: Let Mini’s age = 4x and Minakshi’s age = 3x   Then 4x + 3x = 21   x = 3   Mini’s age = 12 years   And Minakshi’s age = 9 years   Ratio of their ages after 8 years = (12 + 8) : (9 + 8) = 20 : 17   ANSWER:20 : 17
Answer: B
A goods train runs at the speed of 72 km/hr and crosses a 290 m long platform in 26 sec. What is the length of the goods train? Pick one.
A) 278 B) 166 C) 151 D) 230 E) 109

Solution: Speed = 72 * 5/18= 
72 * 5/18 = 20
20 m/sec.   Time= 26 sec.   Let the length of the train be x meters.   Then, (x + 290)/26 = 20   x = 230 m.   Answer:230
Answer: D
Find the difference between C.I and S.I on a sum of money Rs. 2000 for 2 years. at 4% p.a	Choose the correct choice from the following.
A) Rs.2.20	B) Rs.3.20	C) Rs.4.20	D) Rs.5.20	E) Rs.3.25

Solution: P9r/100)^2 =2000(4/100)^2 =Rs.3.20 Answer : Rs.3.20
Answer: B
Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $8.55 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discount rates is 22 percent, what is the discount rate on Pony jeans?	Choose the correct option.
A) 7%  B) 10%  C) 11%  D) 12%  E) 15%

Solution: Let x be the discount on Pony jeans. Then 0.22-x is the discount on Fox jeans.   3(0.22-x)(15) + 2x(18) = 8.55   9.9 - 45x + 36x = 8.55   9x = 1.35   x = 0.15   The answer is 15%.
Answer: E
(786×74) ÷ ? = 4847  Pick:  A) A)4.8  B) B)12  C) C)58  D) D)68  E) E)48

Solution: Explanation:   58164/x = 4847 => x = 58164/4847= 
58164/4847 = 12
12   Answer: Option 12
Answer: B
How many odd numbers between 10 and 2000 are the squares of integers?	Choose the correct option:	A) 12	B) 14	C) 16	D) 18	E) 20

Solution: The numbers are the squares of 5, 7, 9,...,43 which includes 20 numbers.   The answer is 20.
Answer: E
If x^2−2ax+a^2=0 get value of x/a  Options:
A) 1	B) 2	C) 3	D) 4	E) 7

Solution: a is obviously non-zero. We divide the equation by   a^2   we get (x/a-1)^2=0   x/a=1   1NSWER 1 1
Answer: A
If 75 percent of a class answered the first question on a certain test correctly, 70 percent answered the second question on the test correctly, and 20 percent answered neither of the questions correctly, what percent answered both correctly? Choices:
A) 10%  B) (8) 20%  C) 30%  D) 50%  E) 65%

Solution: {Total} = {First} + {Second} - {Both} + {Neither}   100% = 75% + 70% - {Both} + 20% --> {Both} = 65%.   Answer: 65%.
Answer: E
If (a-5)(b-2) =0, which of the following must be true ?
I. a=5 and b=2
II. if a is not 5, then b=2
III. if a=5, then b is not=2 Choose the correct choice from the following: A) I only B) II only C) III only D) I and II E) II and III

Solution: (a-5)(b-2)=0   So either a=5 or b=2 or both. It is 'or' not 'and', so it could be any of the three possibilities. Thus I and III are not necessarily true.   The answer is II only.
Answer: B
If the compound interest on a certain sum of money for 5 years at 10% per annum be Rs. 993, what would be the simple interest?
Answers:
A) Rs. 1500
B) Rs. 890
C) Rs. 895
D) Rs. 900
E) None

Solution: Let P = Principal   Rs. 1500 - Rs. 1500mount   We have a = P(1 + R/100)3 and CI = Rs. 1500 - P   Rs. 1500TQ 993 = P(1 + R/100)3 - P   ? P = 3000/-   Now SI @ 10% on 3000/- for 5 yrs = (3000 x 10 x 5)/100   = 1500/-   Rs. 1500nswer: Rs. 1500.
Answer: A
10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.150000, find the cost of a camel?  Select: A) s.9800 B) s.3800 C) s.9800 D) s.6000 E) s.6880

Solution: Cost of the camel = P   10 camels = 24 horses   16 horses = 4 oxen   6 oxen = 4 elephants   10 elephants = Rs.150000   P = Rs.[(24 * 4 * 4 * 150000)/(10 * 16 * 6 * 10)]   P = Rs.(57600000/9600) => P = Rs.6000   Answer:s.6000
Answer: D
√{(6.3)(10^9)} is closest to which of the following?	Choose the correct answer: A) 1,500 B) 6,000 C) 25,000 D) 80,000 E) 150,000

Solution: √{(6.3)(10^9)} = √{(63)(10^8)} = √(63)√(10^8) = (√63) * 10,000 which is almost 80,000.   The answer is 80,000.
Answer: D
In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 30% of the boys and 32% of the girls passed, then the total percentage of failed candidates is? Pick one:  A) 35.67%  B) 64.75%  C) 68.57%  D) 69.10%  E) none of these

Solution: Girls = 900, Boys = 1100   Passed = ( 30% of 1100 ) + ( 32% of 900)   = 330 + 288= 
330 + 288 = 618
618   Failed= 2000 - 618= 
2000 - 618 = 1_382
1382   Failed %= [(1382/2000) x 100]%   = 69.1%.   ANSWER:69.10%
Answer: D
If the average (arithmetic mean) of 5 positive temperatures is x degrees Fahrenheit, then the sum Q of the 3 greatest of these temperatures, in degrees Fahrenheit, could be Choose one: A) 6x B) 4x C) 5x/3 D) 3x/2 E) 3x/5

Solution: Note that we have 5positivetemperatures.   Next, as the average is x then the sum of the temperatures is 5x and as all the temperatures are positive then the sum of the 3 greatest must be more than (or equal to) 3x (as the average of the 3 greatest must be at least x) and less than 5x: 3x<q<5x --=""> only option B fits.   Answer: 4x.</q<5x>
Answer: B
There are 79 people that own pets. 15 people own only dogs, 10 people own only cats, 5 people own only cats and dogs, 3 people own cats, dogs and snakes. How many total snakes are there?	Choose the correct choice from the following choices.
A) 2  B) 4  C) 8  D) 49  E) 32

Solution: lets assign variables to all the areas in Venn Diagram of Three.   three different Units are 49OG, Cat, Snake= Total = 79   Only 49og= d=15   Only Cat = c=10   Only Snake = s   Exactly 49og and Cat= 5   Exactly 49og and Snake = x   Exactly Cat and Snake = y   all three= 3   so 79=15+10+5+3+x+y+s   we need to know total snakes= x+y+s+3 = 49   answer:49
Answer: D
If the average (arithmetic mean) of a and b is 45 and the average of b and c is 60, what is the value of c âˆ’ a?	Pick:
A) 25 B) 30 C) 90 D) 140 E) It cannot be determined from the information given

Solution: the arithmetic mean of a and b =(a+b)/2=45 -- a+b=90 --1   similarly for b+c=120 --2   subtracting 1 from 2 we have   c-a=30;   ANSWER:30
Answer: B
Two members of a club are to be selected to represent the club at a national meeting. if there are 190 different possible selections of the 2 members, how many members does the club have?  Select the correct option.
A) 20  B) 27  C) 40  D) 57  E) 95

Solution: Below is an answer to your question.   C2n=190Cn2=190 --> n!/2!∗(n−2)!=190. Now, notice that n!=(n−2)!∗(n−1)∗n so (n−2)!∗(n−1)∗n2!∗(n−2)!=190 --> (n−1)∗n/2=190 (n−1)n=380 --> n=20   20nswer: 20.
Answer: A
In how many ways 3 boys and 3 girls can be seated in a row so that they are alternate.	Choose the correct answer.
A) 144 B) 288 C) 36 D) 256 E) None

Solution: Solution: Let the Arrangement be,   B G B G B G B   34 boys can be seated in 3! Ways.   Girl can be seated in 3! Ways.   Required number of ways,   = 3!*3! = 36.   Answer: Option 36
Answer: C
A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 55km/hr. in return trip, he covers the same distance at an average speed of 20km/hr. the average speed of the car over the entire distance of 400 km is  Choices
A) 8.95km/hr  B) 26.7km/hr  C) 27.8km/hr  D) 29.3km/hr  E) 8.45km/hr

Solution: average speed = (2*55*20)/55+20 km/hr   =29.3 km/hr   Answer (29.3km/hr)
Answer: D
Which of the following expressions CANNOT have a negative value Answers:	A) |a + b| – |a – b|	B) |a + b| – |a|	C) a^2 + b^2	D) |2a + b| – |a + b|	E) |a^3 + b^3| – a – b

Solution: Whenever you are required to find if the equation is a perfect square or not, try to bring everything in the form of a perfect square as they are always positive.   Of the given options, only option D can be written in from of a perfect square.   a^2+b^2   This will always be positive.   a^2 + b^2orrect Option: a^2 + b^2
Answer: C
A committee of three people is to be chosen from 6 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
Select the correct option
A) 16
B) 24
C) 26
D) 30
E) 160

Solution: One of the approaches:   Each couple can send only onerepresentativeto the committee. Let's see in how many ways we can choose 3 couples (as there should be 3 members) out of 6 to send only onerepresentativesto the committee: 6C3=20.   But each of these 3 couples can send two persons (husband or wife): 2*2*2=2^3=8.   Total # of ways: 6C3*2^3=160.   Answer: 160.
Answer: E
Ramesh can finish a piece of work in 12 days. Rohan is twice as efficient as Ramesh.If they work together how many days will they need to finish the same amount of work?
Choose the correct choice from the following choices
A) 8/3 days B) 4 days C) 5 days D) 11/3 days E) 7/3 days

Solution: Ramesh can finish a piece of work in 12 days. Rohan is twice as efficient as Ramesh.   So Rohan can finish a piece of work in 6 days.   days needed to finish the same amount of work = 1/(1/6+1/12)= 
1/(1/6+1/12) = 4
4 days   ANSWER:4 days
Answer: B
An article is bought for Rs.600 and sold for Rs.500, find the loss percent?	Select:
A) 16 2/6% B) 16 8/3% C) 16 7/3% D) 16 2/3% E) 12 2/3%

Solution: 600 ---- 100   100 ---- ? => 16 2/3%   Answer:16 2/3%
Answer: D
he population of a city is 130,000. If it increases at the rate of 6% per annum, then what will be its population 2 years hence?	Choose the correct choice from the following answers.
A) 146069	B) 146067	C) 156068	D) 146068	E) 179718

Solution: Population after n years = P [1 + (R/100)]2   Population after 2 years = 130000 * [1 + 6/100]2 = (130000 x 53/50 x 53/50) = 146068   ANSWER: 146068
Answer: D
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?  Choose the correct choice from the following options:
A) 1/10
B) 2/5
C) 2/7
D) 5/7
E) None

Solution: Solution   P(getting a prize)	= 10 / (10+25)   ‹=› 10 / 35   ‹=› 2 / 7.   Answer 2/7
Answer: C
The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively  Choose the most appropriate option.
A) 11 years B) 77 years C) 88 years D) 10 years E) 66 years

Solution: Let their ages be x and (x + 20) years.   5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.   Their present ages are 30 years and 10 years   Answer: 10 years
Answer: D
A profit of Rs. 600 is divided between X and Y in the ratio of 1/2:1/3 . What is the difference between their profit shares ?	Pick one:  A) s. 220  B) s. 120  C) s. 320  D) s. 50  E) s. 90

Solution: A profit of Rs. 600 is divided between X and Y in the ratio of 1/2 : 1/3 or 3:2.   so profits are 360 and 240.   difference in profit share = 360-240= 
360-240 = 120
120   ANSWER:s. 120
Answer: B