MU-NLPC/Calc-aqua_rat huggingface dataset:
An oratorical society consists of six members, and at an upcoming meeting, the members will present a total of four speeches. If no member presents more than two of the four speeches, in how many different orders could the members give speeches?	Pick one
A) 720	B) 1080	C) 1170	D) 1470	E) 1560

Solution: You need to remember that of the 3 people, 1 is going twice and two are going once. Since one of the 3 is going once, there are 3C1 possibilities for the double speaker.   So, to convert your work to the correct answer, you need to multiply:   240 * 3C1 = 240 * 3= 
240 * 3 = 720
720. 720NS:720
Answer: A
Andrew investe 12 percent of his March earnings. In April he earned 20 percent more than he did in March, and he invested 9 percent of his April earnings. The amount he invested in April was what percent of the amount he invested in March?  Pick one:
A) 80%	B) 90%	C) 100%	D) 110%	E) 120%

Solution: Let Andrew's March earnings be 100 --> Amount invested = 12% of 100 = 12   Andrews April earning = 1.2 * 100= 
1.2 * 100 = 120
120 --> Amount invested= 9% of 120 = 10.8   Amount invested in April = (10.8/12)*100 = (108/120)*100= 
(108/120)*100 = 90
90% of the amount invested in March   Answer: 90%
Answer: B
Kelly has had 3 pay cuts in her salary in the past 6 months. If the first pay cut was 8%, the second pay cut was 14% and the third was 18%. What will be the percentage decrease, if the salary is decreased in a single shot?
Choose the correct choice from the following
A) 35.9%	B) 34.12%	C) 32.12%	D) 35.12%	E) 31.12%

Solution: Let Rs.100 be initial salary.   Salary After 1st decrease, 8% = 92   Salary After 2nd decrease, 14% = 79.12 i.e. reduced by 14 percent of 92   Salary After 3rd decrease, 18% = 64.88 i.e. reduced by 18 percent of 79.12   So if its decreased in single shot =   i = ( ( b - a ) /b ) * 100   =35.12%   ANSWER:35.12%
Answer: D
An amount of money is to be distributed among P, Q and R in the ratio of 5 : 8 : 12 respectively. If the total share of Q and R is four times that of P, what is definitely P’s share?
Choose the correct choice from the following options
A) 3,000  B) 5,000  C) 8,000  D) Data inadequate  E) None of these

Solution: P : Q : R = 5 : 8 : 12   Total share of QandR/Share of P=8+12/5=20/5= 
20/5 = 4
4   So, we see that no new information has been given in the question and P’s share can’t be determined.   Answer Data inadequate
Answer: D
Find the 12th term of an arithmetic progression whose first term is 2 and the common difference is 8.
Choose the correct choice from the following options.
A) 45  B) 38  C) 44  D) 90  E) 96

Solution: n th term of A.P = a +(n-1) *d   = 2+(12-1)*8 , = 2 + 88= 
2 + 88 = 90
90.   ANSWER:90
Answer: D
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 2 cm when a man gets on it. The mass of man is	Select
A) 12 kg
B) 60 kg
C) 72 kg
D) 120 kg
E) None

Solution: Solution   Volume of water displaced	= (3 x 2 x 0.02)m3   = 0.12m3.   Mass of man	=Volume of water displaced ×Density of water   = (0.12×1000) kg   = 120 kg.   Answer 120 kg
Answer: D
The numerator of a certain fraction is 8 less than the denominator. If 3 is added to the numerator and 3 is subtracted from the denominator, the fraction becomes 3/4. Find the original fraction?
Choose the correct choice from the following options:
A) A)24.5
B) B)28.5
C) C)30
D) inadequate
E) of these

Solution: Explanation:   Let C.P. be Rs. 100.   Then, S.P. = Rs. 123.50   Let marked price be Rs. x. Then, 95/100 x = 123.50   x = 12350/95 = Rs. 130   Now, S.P. = Rs. 130, C.P. = Rs. 100   Profit % = 30%.   Answer: Option 30
Answer: C
At a certain university, the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:85. At this university, what is the maximum number of students possible in a course that has 5 teaching assistants?
Choose the correct option
A) 140	B) 141	C) 142	D) 143	E) 144

Solution: (5/3)*85=141 plus remainder   The answer is 141.
Answer: B
A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Answers:
A) 7.5	B) 7.4	C) 7.9	D) 7.2	E) 7.1

Solution: Net part filled in 1 hour = (1/4 - 1/9) = 5/36   The cistern will be filled in 36/5 hrs i.e., 7.2 hrs.Answer: 7.2
Answer: D
If z is a multiple of 9702, what is the remainder when z^2 is divided by 4? Select.
A) 0 B) 1 C) 2 D) 3 E) It depends on z.

Solution: 2 is a factor of 9702, so 2 is a factor of z.   Then 2^2 = 4 is a factor of z^2.   Then the remainder when z^2 is divided by 4 is 0.   The answer is 0.
Answer: A
Company P had 15 percent more employees in December than it had in January. If Company P had 460 employees in December, how many employees did it have in January?	Pick
A) 391  B) 400  C) 410  D) 423  E) 445

Solution: Given: January*1.15=December --> January*1.15=460 --> January=460/1.15= 
460/1.15 = 400
400.   Answer: 400.
Answer: B
One robot builds a robot in 1 hour, another one builds a robot in 2 hours. The 2 robots work together and when a new robot is complete, it joins the others, working at a constant rate of one robot in 2 hours. How much time will it take until there are 6 robots altogether, if the robots build only one robot at a time?  Choose the correct choice.
A) 70 min  B) 94 min  C) 109 min  D) 114 min  E) 120 min

Solution: First the 2 robots work at the rate of   1 + 1/2 = 3/2   so they complete one robot in 2/3 rd of an hour = 40 minutes - (1)   Now the 3 robots work together at the rate of   1 + 1/2 + 1/2 = 4/2= 
4/2 = 2
2/1   so they complete one robot in 1/2 an hour,i.e 30 minutes - (2)   Now the 4 robots work together at the rate of   1 + 1/2 + 1/2 + 1/2= 5/2   so they complete one robot in 2/5th of an hour, i.e. 24 minutes - (3)   Now the 4 robots work together at the rate of   1 + 1/2 + 1/2 + 1/2+1/2= 
1 + 1/2 + 1/2 + 1/2+1/2 = 3
3   so they complete one robot in 1/3th of an hour, i.e. 20 minutes - (4)   And now we have 5 robots   So Total= (1) + (2) + (3) +(4)= 114minutes   Answer - 114 min
Answer: D
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?  Choose the correct choice from the following answers:
A) 5/21  B) 5/28  C) 5/22  D) 5/25  E) 5/27

Solution: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)   As remaining person can be any one among three couples left.   Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅   = (10 * 6)/252 = 5/21   5/21nswer:5/21
Answer: A
An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 10000 people who applied for the army and 350 were finally selected, what was the value of N?
Choices
A) 4
B) 5
C) 6
D) 9
E) 8

Solution: fastly i reduce 60% till it gets closer to our required 2000 candidates   step(1) 40000 accepted.   step(2) another 40%of 40000=16000 accepted.   here it is quiet observable that if we further deduct candidate by 60% it would change our probablity of easy going 2000 candidate.   so i would get to second stage of recruitment where 50 % is accepted   step(3) 50% of 16000=8000   step(4) 50% of 8000=4000   Step(5) 50% of 4000=2000   Step(6) 50% of 2000=1000   Step(7) 50% of 1000=500   last step of accepting 70% of 500=350(our target)   total 8 steps required.   Ans 9
Answer: D
A class consists of 15 girls and 10 boys. Three students are to be randomly selected. Find the probability that one boy and two girls are picked.
Answers: A) 21/46 B) 21/49 C) 21/42 D) 26/46 E) 21/43

Solution: 21/46NSWER: 21/46
Answer: A
In a division, when a student mistook the divisor as 12 instead of 21 and obtained 35 as quotient the remainder is 0 . What is the correct quotient? Choose the correct choice from the following answers:
A) 14	B) 18	C) 20	D) 24	E) 29

Solution: Let x be the number   x÷12=35, remainder = 0   => x=35×12   correct quotient   =x21=35×1221=5×123=5×4=20   20
Answer: C
What are the next two numbers in this sequence?
7, 14, 17, 21, 27, 28, 35, 37, ?	Select the correct option
A) 40	B) 41	C) 42	D) 43	E) 44

Solution: these are digits which are either multiples of 7 or containing the digit 7.   s0 next numbers are 42   ANSWER:42
Answer: C
How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated? Pick.
A) 5  B) 10  C) 15  D) 20  E) 25

Solution: Explanation:   Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.   The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20.   Answer: 20
Answer: D
Which of the following is a possible length for side AB of triangle ABC if AC = 3 and BC = 9?
I. 6
II. 9 √3
III. 11.5  Choices.
A) I only
B) II only
C) III only
D) II and III
E) I, II, and III

Solution: (9-3) < AB < (9+3)   The answer is III only.
Answer: C
At a certain pizza parlor, the diameter of a large pizza is 40% larger than the diameter of a small pizza. What is the percent increase in total amount of pizza, from a small to a large?  Pick.
A) 20%	B) 40%	C) 64%	D) 80%	E) 96%

Solution: A real world problem —- yum! —- but again, the specifics of the shape don’t matter. Diameter increases 40%, so k = 1.4 in this case. “Amount of pizza” just means the area of the circle, so k^2 = (1.4)^2 = 1.96, which is the multiplier for a 96% increase. That’s the percent increase in area. Answer = 96%
Answer: E
In a party every person shakes hands with every other person. If there are 105 hands shakes, find the number of person in the party. Choose the correct choice from the following answers.
A) 15 B) 14 C) 21 D) 25 E) 18

Solution: Solution: Let n be the number of persons in the party. Number of hands shake = 105; Total number of hands shake is given by nC2.   Now, according to the question,   nC2 = 105;   Or, n!/[2!*(n-2)!] = 105;   Or, n*(n-1)/2 = 105;   Or, n2-n = 210;   Or, n2-n-210 = 0;   Or, n = 15, -14;   But, we cannot take negative value of n.   So, n = 15 i.e. number of persons in the party = 15.   15nswer: Option 15
Answer: A
At a certain university, 70% of the professors are women, and 70% of the professors are tenured. If 90% of the professors are women, tenured, or both, then what percent of the men are tenured? Select the correct option:
A) 25  B) 37.5  C) 50  D) 62.5  E) 75

Solution: answer is 75%   total women = 70%   total men = 40%   total tenured = 70% (both men and women)   therefore, women tenured + women professors + men tenured = 90%   men tenured = 20%   but question wants to know the percent of men that are tenured   20%/40%=50%   50
Answer: C
The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 42 kmph, find the speed of the stream?  Select:
A) 22 kmph B) 77 kmph C) 14 kmph D) 88 kmph E) 12 kmph

Solution: The ratio of the times taken is 2:1.   The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1)= 
(2+1)/(2-1) = 3
3/1= 
3/1 = 3
3:1   Speed of the stream= 42/3= 
42/3 = 14
14 kmph.   Answer:14 kmph
Answer: C
Which of these must the factor M of the product of four consecutive even integers:-
1) 48
2) 64
3) 96
4) 192
5) 80
Choose the correct answer:
A) M=1,2 only B) M=2,3 only C) M=1,2,3 only D) M=1,2,3,4 only E) All of them

Solution: Let the four variables be a< b< c< d.   Assume a worst case scenario where the a equal to a prime number (hence odd).   therefore   a = divisible by 1   b = a + 1 (divisible by 2)   c = a + 3 (divisible by 3)   d = a + 4 (divisible by 4)   therefore   each answer choice must be divisible by 2 x 3 x 4 = 24   only 80 is not divisible. Therefore answer = M=1,2,3,4 only
Answer: D
Of the 800 employees in a certain company, 70% have serviced more than 10 years. A number of y of those who have serviced more than 10 years will retire and no fresh employees join in. What is y if the 10 years employees become 60% of the total employees?  Choose the correct choice from the following options
A) 150 B) 200 C) 250 D) 450 E) 550

Solution: TOTAL 10 YRS   Original: 800 560   New: 800-y 560-y   560-y = .6 (800 -y)   560-y = 480 - .6y   80 = .4y   800/4 = y   y= 200   Answer: 200	ANSWER:200
Answer: B
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B? Pick one
A) 5  B) 6  C) 8  D) 10  E) 12

Solution: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.   (2x + 2) + 2x + x = 27   5x = 25   x = 5.   Hence, B's age = 2x = 10 years.   answer :10
Answer: D
Arun borrowed a sum of money from Jayant at the rate of 8% per annum simple interest for the first four years, 10% per annum for the next six years and 12% per annum for the period beyond ten years. If he pays a total of 12,160 as interest only at the end of 15 years, how much money did he borrow?
Choose one:
A) 8000
B) 10,000
C) 12,000
D) 9,000
E) None of these

Solution: Let the Principal = P   Then P×8×4/100+P×10×6/100+P×12×5/100   = 12160   ⇒ 152P = 12160 × 100   or 12160×100/152=8000   8000nswer 8000
Answer: A
If Q is an odd number and the median of Q consecutive integers is 130, what is the largest of these integers?	Choices
A) (Q + 130)/2	B) Q/2 + 129	C) Q/2 + 130	D) (Q + 129)/2	E) (Q - 1)/2 + 130

Solution: Consider the easiest case, say Q=3, then;   Set = {129, 130, 131};   The largest integer = 131.   Now, plug Q=3 into the answers to see which yields 131.   Answer: (Q - 1)/2 + 130.
Answer: E
An article is bought for Rs.675 and sold for Rs.1215, find the gain percent?
Choose the correct choice from the following
A) 33 1/9%  B) 33 8/3%  C) 33 1/3%  D) 33 2/3%  E) 80%

Solution: 675 ---- 540   100 ---- ? => 80%   Answer: 80%
Answer: E
A car traveled from San Diego to San Francisco at an average speed of 54 miles per hour. If the journey back took twice as long, what was the average speed of the trip?	Choices:
A) 24. B) 32. C) 36. D) 42. E) 44.

Solution: Let the time taken be = x   One way distance = 54x   Total distance traveled = 2 * 54= 
2 * 54 = 108
108x   Total time taken= x + 2x = 3x   Average speed = 108x/3x = 36   Answer: 36.108 /3= 
108 /3 = 36
36   Answer: 36.
Answer: C
In g is a positive integer smaller than 200 and (14g)/60 is an integer, then g has how many different positive prime factors?
Choose the correct choice from the following:
A) 2	B) 3	C) 5	D) 6	E) 8

Solution: 7g/30 tells us that g is a factor of 30, which has 2, 3, and 5 as its prime factors. Each of them is distinct. Moreover, all multiples of 30 less than 200 can be derived by multiplying these prime factors alone. Thus, number of different prime factors is 3.   Answer: 3
Answer: B
Calculate how many seconds it will take for 4 bells to toll together again, given that they begin to toll together respectively at the intervals of 9, 10, 14 and 18 seconds. ?	Pick.
A) 636
B) 631
C) 633
D) 610
E) 630

Solution: LCM of 9, 10, 14 and 18 is   630   LCM=630   ANSW630R:630
Answer: E
A monkey start climbing up a tree 21 ft tall.Each hour it hops 3 ft and slips back 2 ft. How much time would it take the monkey to reach the top. Select:
A) 15 hrs B) 18 hrs C) 19 hrs D) 17 hrs E) 16 hrs

Solution: if monkey hops 3ft and slips back 2ft in a hour, it means the monkey hops (3ft-2ft)= 1ft/hr.   similarly in 18hrs it wil be 18ft.   But since the height of the tree is 21 ft, so if the monkey hops up the tree in the next hr i.e 19th hr then it reaches at the top of the tree.   hence it takes 19 hrs for monkey to reach at the top   ANSWER:19 hrs  (3  -2  )= 
  (3  -2  ) = 1
1ft/hr.   similarly in 18hrs it wil be 18ft.   But since the height of the tree is 21 ft, so if the monkey hops up the tree in the next hr i.e 19th hr then it reaches at the top of the tree.   hence it takes 19 hrs for monkey to reach at the top   ANSWER:19 hrs
Answer: C
A grocery shop has a sale of Rs. 6735, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?  Choose the correct choice:	A) 4857	B) 4184	C) 4012	D) 4691	E) 5291

Solution: Let the sale in the sixth month =x   Then   (6735+6927+6855+7230+6562+x)/6 =6500   =>6735+6927+6855+7230+6562+x =6×6500   => 34309+x=39000   => x=39000−34309   =4691   ANSWER:4691
Answer: D
At a conference, the only events scheduled for the day are seminars and breaks. All seminars are the same length and are 10 times as long as each break. A break must be between two consecutive seminars. If the first seminar begins at 9:00 a.m. and the third one ends at 11:40 a.m., how long S will the conference last if there are a total of 6 seminars that day?	Choose the correct choice from the following answers.
A) 5 hours and 15 minutes B) 5 hours and 20 minutes C) 5 hours and 25 minutes D) 5 hours and 30 minutes E) 5 hours and 35 minutes

Solution: Shouldnt the answer be 5 hours 20 mins?   5 hours and 20 minutesreak = b   Seminar= 10b   9am to 11:40am= 160mins   3s+b=160   30b+b=160   b=160/31   6 seminar will take   6s+2b   =60b+2b   =62b   60 +2= 
60 +2 = 62
62b=62*160/31= 
62*160/31 = 320
320   S=5 hours 20 mins.5 hours and 20 minutes
Answer: B
If abc represents a positive three-digit number, where a, b and c are one-digit integers, which of the following CAN be true?
Options:
A) a + b + c = 9
B) a – b - c = 9
C) b – c - a = 9
D) Both A and C
E) Both A and B

Solution: The (hundreds place digit, a) cannot be zero, but (tens and ones place digits; b and c) can be zero.   A is NOT possible   B is possible   C is possible   D is possible   Both A and B is possible   Answer: Both A and B
Answer: E
Mayank Bothra purchased 20 dozens of toys at the rate of 375 Rs per dozen .He sold each one of them at the rate of Rs 33.What was his percentage profit?	Choices:
A) 5.6 %
B) 6.5 %
C) 7.5 %
D) 7.6 %
E) None

Solution: Sol.   Cost = 375 * 20= 
375 * 20 = 7_500
7500   sale price   33 * 20 * 12= 
  33 * 20 * 12 = 7_920
7920 profit= 420 profit in % = 420/7500 * 100= 
420/7500 * 100 = 28/5 = around 5.6
5.6 %   5.6 %ns: 5.6 %.
Answer: A
Nine persons went to a hotel for taking their meals. Eight of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine. What was the total money spent by them.	Choose the correct choice from the following answers:  A) Rs. 115  B) Rs. 116  C) Rs. 117  D) Rs. 118  E) None

Solution: Solution:   Let the average expenditure of all the nine be x.   Then, 12 × 8 + (x + 8) = 9x.   Therefore, x = 13.   Total money spent,   = 9x = Rs.(9 × 13) = Rs.117   Answer: Option Rs. 117
Answer: C
N and M are each 3-digit integers. Each of the numbers 3,4, 5, 6, 7, and 8 is a digit of either N or M. What is the smallest possible positive difference between N and M? Choose the correct choice from the following choices:  A) 59  B) 49  C) 58  D) 113  E) 131

Solution: You have 6 digits: 3, 4, 5, 6, 7, 8   Each digit needs to be used to make two 3 digit numbers. This means that we will use each of the digits only once and in only one of the numbers. The numbers need to be as close to each other as possible. The numbers cannot be equal so the greater number needs to be as small as possible and the smaller number needs to be as large as possible to be close to each other.   The first digit (hundreds digit) of both numbers should be consecutive integers   Now let's think about the next digit (the tens digit). To minimize the difference between the numbers, the tens digit of the greater number should be as small as possible and the tens digit of the smaller number should be as large as possible . So let's not use 3 and 8 in the hundreds places and reserve them for the tens places . Now what are the options?   Try and make a pair with (4** and 5**). Make the 4** number as large as possible and make the 5** number as small as possible.   487 and 536 (difference is 49) or   Try and make a pair with (6** and 7**). Make the 6** number as large as possible and make the 7** number as small as possible. We get 685 and 734 (difference is 49)   49
Answer: B
The ratio of investments of two partners P and Q is 7:5 and the ratio of their profits is 7:9. If P invested the money for 5 months, find for how much time did Q invest the money?
Choose the correct answer:  A) 9  B) 17  C) 13  D) 10  E) 12

Solution: 7*5: 5*x = 7:9   x = 9   9nswer: 9
Answer: A
Two persons A and B take a field on rent. A puts on it 21 horses for 3 months and 15 cows for 2 months; B puts 15 cows for 6months and 40 sheep for 7 1/2 months. If one day, 3 horses eat as much as 5 cows and 6 cows as much as 10 sheep, what part of the rent should A pay? Choose the correct choice from the following options
A) 1/3  B) 1/9  C) 1/6  D) 1/2  E) 1/5

Solution: 3h = 5c   6c = 10s   1/3 = 21h*3 + 15c*2   = 63h + 30c   = 105c + 30c = 135c   B 105  + 30= 
105  + 30 = 135
135c   B= 15c*6 + 40s*7 1/2   = 90c + 300s   = 90c + 180c = 270c   1/3:B 90  + 180= 
90  + 180 = 270
270c   1/3:B= 135:270   27:52   1/3 = 27/79 = 1/3   1/3nswer: 1/3
Answer: A
A sum of money deposited at C.I. amounts to Rs.1820 in 4 years and to Rs.2402 in 5 years. Find the rate percent?  Options
A) 30%	B) 31%	C) 34%	D) 19%	E) 50%

Solution: 1820 --- 582   100 --- ? => 31%   Answer: 31%
Answer: B
The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?  Choices.
A) 6:3	B) 6:9	C) 6:5	D) 6:1	E) 6:4

Solution: 4:5   3:2   -------   12:15:10   12:10   6:5   Answer:6:5
Answer: C
A certain characteristic in a large population has a distribution that is symmetric about the mean m. 80 percent of the distribution lies within one standard deviation d of the mean. If the shelf’s average life is 8.6 years and the standard deviation is 3.4 years, what percent of the distribution has more than 12.0 years as a shelf’s average life?	Choices:	A) 23%	B) 22%	C) 21%	D) 20%	E) 19%

Solution: Average = 8.6   SD = 3.4   8.6 - 3.4 < 80% of distribution < 8.6 + 3.4   5.2 < 80% of distribution < 12.0   40% is outside this range.   Given: Distribution is symmetric. So 20% of distribution is less than 5.2 and the other 20% of distribution is greater than 12.0.   Answer: 20%
Answer: D
The simple interest on a sum of money will be Rs. 600 after 10 years.If the principal is trebled after 5 years,what will be the total interest at the end of the tenth year ?	Answers
A) Rs. 600 B) Rs. 900 C) Rs. 1200 D) Rs. 1500 E) None

Solution: Solution   22.22   Let the sum be Rs. x. Now, S.I. = Rs. 600,T = 10 years.   Rate = % = (100x600/X x 10)% =(6000/X)%   S.I. for first 5 years = Rs.(X x 5 x 6000/X x 100) = Rs. 300.   S.I. for first 5 years = Rs. (3X x 5 x 6000/X x 100)= Rs. 900.   ∴ Total interest = Rs. 1200.   Answer Rs. 1200
Answer: C
A hall 20m long and 15m broad is surrounded by a verandah of uniform width of 2.5m. The cost of flooring the verandah at the rate of Rs.3.50 per sq. meter is Answers
A) 500	B) 600	C) 650	D) 700	E) 750

Solution: Area of verandah = [(25Ãƒâ€”20)?(20Ãƒâ€”15)]mÂ²=200 mÂ²   Cost of flooring = Rs.(200Ãƒâ€”3.50) = Rs.700   Answer :700
Answer: D
If the LCM of A and B is 72 and their HCF is 6, what is the product of A & B? Choose the correct choice from the following options
A) 432 B) 433 C) 434 D) 435 E) 436

Solution: The most important property of LCM (the least common multiple) and GCD (the greatest common divisors) is: for any positive integers x and y, x∗y=GCD(x,y)∗LCM(x,y) so AB=72*6= 
72*6 = 432
432.   432NSWER:432
Answer: A