MU-NLPC/Calc-aqua_rat huggingface dataset:
A, B and C have Rs.500 between them, A and C together have Rs.200 and B and C Rs.330. How much does C have? Choose the correct choice from the following answers:
A) 50
B) 78
C) 30
D) 29
E) 27

Solution: A+B+30 = 500   A+30 = 200   B+30 = 330   --------------   A+B+230 = 530   A+B+30 = 500   ----------------   30 = 30   Answer: 30
Answer: C
Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 7 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?
Choose the correct choice from the following answers:
A) 5 : 1
B) 10 : 5
C) 15 : 2
D) 20 : 2
E) 35 : 2

Solution: U/I = 7/2   I/B = 5/1   Since I is multiple of both 2 (as per first ratio) and 5 (as per second ratio) so let's assume that I = 10   i.e. Multiplying teh first ratio by 5 and second ration by 2 in each numerator and denominator   then, U : I : B = 35 : 21 : 2   i.e. U : B = 35 : 2   Answer: Option 35 : 2
Answer: E
How many integers Z are prime numbers in the range 200 < Z < 220?	Choose the correct choice from the following choices:
A) 1
B) 2
C) 3
D) 4
E) 5

Solution: My friend, every single odd number greater than can be written either as 4Z+1 or as 4Z+3. If you divide any odd number by 4, you will get a remainder of either 1 or 3. That's not a rule unique to prime numbers at all.   The 6Z+1 or 6Z-1 rule is basically every odd number that is not divisible by three, so it narrows the search a little.   Here's how I thought about the problem. First, eliminate all the even numbers and the odd multiples of 5 in that range. That leaves us with:   {201, 203, 207, 209, 211, 213, 217, 219}   Eliminate the four multiples of 3. Notice that 21 is a multiple of 3, so 210 is also a multiple of 3. If we add or subtract 3 or 9, we get more multiples of three. When we eliminate those, we are left with.   {203, 209, 211, 217}   Now, notice that a cool thing about this range is that 210 is also a multiple 7 (again, because 21 is a multiple of 7). This means that    210 - 7= 
 210 - 7 = 203
203   210 + 7= 
210 + 7 = 217
217   Those two numbers are also multiples of 7, so eliminate them from the list. Now, we are left with   {209, 211}.   We've already checked all the prime numbers less than 10, so we know that neither of these numbers is divisible by anything less than 10. We have to check 11 now. We know that 22 is a multiple of 11, so 220 is also a multiple of 11. This means that    220 - 11= 
 220 - 11 = 209
209   is also a multiple of 11. We can eliminate this from the list also.   That leaves us with just 211. There's no zero option in the question, so this must be a prime number.   1nswer= (1)
Answer: A
A invested $150 in a business after 6 months B invested $200 in the business. End of the year if they got $100 as profit. Find A shares?	Options:
A) $100	B) $75	C) $20	D) $120	E) $60

Solution: A:B = 150*12:200*6   A:B = 3:2   A's share = 100*3/5= 
100*3/5 = 60
$60   Answer is $60
Answer: E
The average of 6 observations is 12. A new seventh observation is included and the new average is decreased by 1. The seventh observation is :  Pick one:	A) 1	B) 3	C) 5	D) 6	E) 8

Solution: Explanation:   Seventh observation = (7××11-6××12)=5   5orrect Option: 5
Answer: C
Two numbers N and 16 have LCM = 48 and GCF = 8. Find N.	Options.
A) 11	B) 32	C) 24	D) 48	E) 50

Solution: The product of two integers is equal to the product of their LCM and GCF. Hence.   16 * N = 48 * 8   N = 48 * 8 / 16= 
48 * 8 / 16 = 24
24   correct answer 24
Answer: C
A began a business with Rs. 85,000. He was joined afterwards by B with Ks. 42,500. For how much period does B join, if the profits at the end of the year are divided in the ratio of 6 : 1 ?  Pick:
A) 6 months	B) 4 months	C) 2 months	D) 8 months	E) 9 months

Solution: Suppose B joined for x months . Then, ( 85000 * 12 )/(42500 * x) = 6. or x = (85000 * 12) / (42500 * 6)= 
(85000 * 12) / (42500 * 6) = 4
4.   So, B joined for 4 months.   Answer: 4 months
Answer: B
One man adds 3 liters of water to 12 liters of milk and another 4 liters of water to 10 liters of milk. What is the ratio of the strengths of milk in 2 mixtures?  Choose the correct answer:
A) 11:21  B) 15:33  C) 28:25  D) 3:2  E) 31:33

Solution: Strength of milk in the mixture = Quantity of milk/total quantity of mixture   strength of milk in the 1st mixture = 12/15   strength of the milk 2nd mixture = 10/14   The ratio of their strengths = 12/15 : 10/14 = 28:25   Answer is 28:25
Answer: C
In how many ways the letters of the word ENGINEERING can be arranged?  Choose the correct choice from the following.
A) 200002  B) 262011  C) 277200  D) 216181  E) 280161

Solution: Total number of ways=(11!)/(3!*3!*2!*2!*1!)   =(11*10*9*8*7*6*5*4*3!)/(3!*3*2*2*2)   =277200 ways   Option 277200(11*10*9*8*7*6*5*4*3 )/(3 *3*2*2*2)= 
(11*10*9*8*7*6*5*4*3 )/(3 *3*2*2*2) = 277_200
277200 ways   Option 277200
Answer: C
Fence X is twice as long as fence Y, and fence Y is 1 feet shorter than fence Z. If 3 feet were added to each fence, which of the following must be true?
I) X is twice as long as Y.
II) Y is 1 feet shorter than Z.
III) X is longer than Z. Options:
A) I only  B) II only  C) III only  D) II and III  E) I and II

Solution: If X= 6   Y= 3   Z= 4   Then, after adding 3 feet to each:   X= 9   Y=6   Z=7   And the answer would be E, which is wrong.   II and III
Answer: D
On dividing 109 by a number, the quotient is 9 and the remainder is 1. Find the divisor.
Choose the correct choice:  A) 10  B) 11  C) 12  D) 13  E) 15

Solution: d = (D-R)/Q   = (109 - 1)/9   = 108/9= 
108/9 = 12
12   12
Answer: C
120kg of an alloy A is mixed with 180 kg of alloy B. If alloy A has lead and tin in the ratio 2:3 and alloy B has tin and copper in the ratio 3:5, then the amount of tin in the new alloy is? Choices:  A) 100.6kg  B) 120.3kg  C) 139.5kg  D) 140.8kg  E) 114.5kg

Solution: Quantity of tin in 120kg of A = 120*3/5= 
120*3/5 = 72
72kg   Quantity of tin in 180kg of B= 180*3/8= 
180*3/8 = 135/2 = around 67.5
67.5kg   Quantity of tin in the new alloy= 72+67.5= 
72+67.5 = 139.5
139.5kg   Answer is 139.5kg
Answer: C
180,131,95,70,?  Select.
A) 42  B) 43  C) 54  D) 40  E) 39

Solution: 180 - 131= 
180 - 131 = 49
49= 7^2   131 - 95= 
131 - 95 = 36
36= 6^2   95 - 70= 
95 - 70 = 25
25= 5^2   so we can write   70 - x = 16 = 4^2 , where x is the next number   x = 70 - 16= 
70 - 16 = 54
54   so the next number will be 54   ANSWER:54
Answer: C
A plant manager must assign 6 new workers to one of five shifts. She needs a first, second, and third shift, and two alternate shifts. Each of the shifts will receive 2 new workers. How many different ways can she assign the new workers?
Choose the most appropriate option
A) 24
B) 27
C) 33
D) 45
E) 54

Solution: whatever : my take selecting team of 2 out of 10 to assign to the shifts =6C2 = 15 ways.   now 2 out of 10 means total of 3 group possible.   so putting them in shifts = counting methode: first, second, third, alt , alt   = 3*2*1= 
3*2*1 = 6
6   here alt and alt are the same: so  6/2= 
 6/2 = 3
3 ways.   total ways of selecting= (selecting 2 out of 6)*arranging those teams in shifts   = 15*3= 
15*3 = 45
45   Ans: 45
Answer: D
The timing of a college is from 12 p.m to 4.20 p.m. Five lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture. Choose the correct option:
A) 52 minutes  B) 45 minutes  C) 30 minutes  D) 48 minutes  E) 44 minutes

Solution: Explanation:   Total time a student spends in college = 4 hours 20 minutes = 260 minutes   As there are 5 lectures, the number of breaks between lectures is 4. Total time of the break = 20 minutes   Hence, the duration of each lecture is = (260 – 20)/5   = 48 minutes   ANSWER 48 minutes
Answer: D
Albert invested an amount of Rs.8000 in a fixed deposit scheme for 2 years at compound interest rate 5 p.c.p.a. How much amount will Albert get on maturity of the fixed deposit ?
Choices:
A) Rs.8600 B) Rs.8620 C) Rs.8840 D) Rs.8820 E) None

Solution: Solution   Amount	=Rs.[8000x(1+5/100)²]   = Rs.   [8000 x 21/20x21/20]   = Rs.8820.   Answer Rs.8820
Answer: D
If p+q=8z, then which of the following represents the average (arithmetic mean) of p, q, and z, in terms of z? Choose one
A) 2z+1  B) 3z  C) 5z  D) z/3  E) 3z/2

Solution: Pick any number like P=12, Q=12 and Z= 3 so that P+Q=8Z, now then the arithmetic mean will be   (12+12+3)/3= 
  (12+12+3)/3 = 9
9. Now, just look at the answers and put the value of Z there.   (A) 2.3+1=7, no.   (3z) 3.3=9, it can be the answer, lets check us the other options   (C) 5.3=15, no   (D) 3/3=1 no   (E) (3.3)/2=9/2, no   so the answer will be 3z..
Answer: B
How much space, in cubic units, is left vacant when maximum number of 6x6x6 cubes are fitted in a rectangular box measuring 12x18x14 ?  Pick.
A) 428	B) 429	C) 430	D) 431	E) 432

Solution: No of cubes that can be accommodated in box = (12*18*14)/(6*6*6)   12*16 in numerator can be perfectly divided by 6*6 in denominator.   side with length 14 can't be perfectly divided by 6 and hence is the limiting factor. Closet multiple of 6 less that 14 is 12. so vacant area in cube =   =18*12*(14-12)   =18*12*2= 
18*12*2 = 432
432   Ans - 432
Answer: E
Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?	Select the correct option
A) Rs. 1(2/9)	B) Rs. 2(2/9)	C) Rs. 2(2/7)	D) Rs. 3(2/5)	E) Rs. 3(1/9)

Solution: Here r = 10 % ,x = 100 and A = 5 kg   Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)   Rs. 2(2/9)
Answer: B
A bag contain 4 red , 6 yellow, 5 green balls, 3 balls are drawn randomly . What is the probability that the balls drawn contain exactly two green balls ? Choose the correct choice from the following answers:
A) 5/11
B) 4/11
C) 6/11
D) 7/11
E) 8/11

Solution: 2 green balls can be selected from 5 green balls and the remaining one ball select from   (15-5)= 
(15-5) = 10
10 balls in 8C1 ways   n(E) 5C2 X 8C1=10 X 8 =80   So, P(E) = 80/220 =4/11   Answer is 4/11
Answer: B
A team of 6 cooks is chosen from 6 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?	Choose the correct option:  A) 140  B) 320  C) 275  D) 700  E) 840

Solution: Only possible combinations are a team of 2M, 4 W or 3M,3W.   Possible ways to make a team of 2M,4W = 62752 * 52754 =15*5= 
15*5 = 75
75   Possible ways to make a team of 3M,3W= 62753* 52753 = 20*10= 
20*10 = 200
200   Total possible ways= 75+200= 
75+200 = 275
275   Ans 275 it is.
Answer: C
What percent of the different arrangements of the letters of the word ABACUS are those in which the vowels appear together? Choose one:  A) 10%  B) 20%  C) 40%  D) 50%  E) 60%

Solution: The total number of different arrangements are 6!/2=360. We divide here by 2, since we have two same letters A.   Letters A, A, and U are vowels. Put them together and consider as one object. So, we have 4 different objects (AAU) B C S. The number of different arrangements of them are 4!=24. And we have 3 possibilities to arrange vowels: AAU, AUA, UAA. Therefore, we have 24*3= 
24*3 = 72
72 different arrangements.   Hence, 72/360*100%=20%.   The correct answer is 20%.
Answer: B
The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years	Choose the correct choice:
A) A)3:4  B) B)3:5  C) of these  D) inadequate  E) C)4:3

Solution: Let P's age and Q's age be 6x and 7x years respectively.   Then, 7x - 6x = 4 => x = 4   Required ratio = (6x + 4) : (7x + 4)   28 : 32 = 7:8   ANSWER:of these
Answer: C
Three pounds of 05 grass seed contain 3 percent herbicide. A different type of grass seed, 20, which contains 20 percent herbicide, will be mixed with three pounds of 05 grass seed. How much grass seed of type 20 should be added to the three pounds of 05 grass seed so that the mixture contains 15 percent herbicide?
Select the correct option:
A) 3	B) 7.2	C) 4.5	D) 6	E) 9

Solution: 05 grass seed contains 5% herbicide and its amount is 3 pound   20 grass seed contains 20% herbicide and its amount is x   when these two types of grass seeds are mixed, their average becomes 15%   thus we have   3(3)+x(20)/(x+3) = 15   9+20x=15x +45   5x=36   or x=7.2   7.2
Answer: B
What will be the reminder when (67^67+67) is divided by 68? Select:
A) 1	B) 63	C) 66	D) 67	E) None of these

Solution: (x^n+1) will be divisible by (x+1) only when n is odd;   (67^67+1) will be divisible by (67+1);   (67^67+1)+66 when divided by 68 will give 66 as remainder.   66orrect Option : 66
Answer: C
There are 20 poles with a constant distance between each pole. A car takes 24 second to reach the 12th pole. How much will it take to reach the last pole.  Choose the correct choice from the following answers:
A) 41.4543	B) 41.4545	C) 41.45128	D) 41.41288	E) 41.41222

Solution: Assuming the car starts at the first pole.   To reach the 12th pole, the car need to travel 11 poles (the first pole doesn't count, as the car is already there).   11 poles 24 seconds   1 pole (24/11) seconds   To reach the last (20th) pole, the car needs to travel 19 poles.   19 pole 19 x (24/11) seconds   = 41.4545 seconds   Answer:41.4545
Answer: B
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?  Pick one.
A) 3/8	B) 3/2	C) 3/5	D) 3/9	E) 4/2

Solution: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y)   = 23 ==> 27 x + 17 y = 23 x + 23 y   ==> 4 x = 6 y   ==> x/y = 3/2.   Answer:3/2
Answer: B
A person got Rs.60 more when he invested a certain sum at compound interest instead of simple interest for two years at 15% p.a. Find the sum?
Choose the correct choice from the following answers
A) 7500
B) 2666
C) 2877
D) 2667
E) 2671

Solution: P = (d * 1002) / R2   => (60 * 100 * 100) / 15 * 15 = Rs.2666   Answer:2666
Answer: B
Q's mother is sister of P and daughter of M. S is daughter of P and sister of T.How is M related to T? Select:
A) Grandfather  B) Grandmother  C) Father  D) Either Grandmother or Grandfather  E) Grandf4her

Solution: Explanation:   Q's mother is sister of P & daughter of M.[sex of P and M are not clear]   S is daughter of P and sister of T. [sex of P and T is not clear]   M's children : Q's mother and P   P's children :S[female] and T   \fn_cm \therefore M is either Grandmother or Grandfather of T   Answer: Either Grandmother or Grandfather
Answer: D
Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Fuel and Transport	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The total amount of Fuel paid by the company during the given period is approximately what percent of the total amount of salary paid during this period?	Answers.
A) A)0.5%
B) B)1%
C) C)1.25%
D) D)3%
E) E)4%

Solution: Required percentage   =	(288 + 342 + 324 + 336 + 420)   =	[	17	x 100	]	%   1710   ~= 1%.   Answer : 1%
Answer: B
he distance from town A to town B is five miles. C is six miles from B. Which of the following could be the maximum distance from A to C?
Choices:
A) 11  B) 77  C) 51  D) 16  E) 12

Solution: Explanation:   Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11   11nswer:11
Answer: A
Margaret is 13 years more than twice the age of his son. The age of son is 12. Find the age of mother and find the difference between their ages
Choose the correct answer.
A) 10yrs  B) 20yrs  C) 30yrs  D) 40yrs  E) 25yrs

Solution: Let, age of son x=12   Margaret is 13 years more than twice the age of his son, y = 13+2(x)   =13+2(12)   =13+24= 
13+24 = 37
37yrs   Difference= 37 - 12= 
37 - 12 = 25
25yrs   ANSW25yrsR:25yrs
Answer: E
The price of an item is discounted 7 percent on day 1 of a sale. On day 2, the item is discounted another 7 percent, and on day 3, it is discounted an additional 10 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
Choose one: A) 83.7% B) 85.2% C) 86.8% D) 78.8% E) 69.4%

Solution: Let initial price be 100   Price in day 1 after 7% discount = 93   Price in day 2 after 7% discount = 86.49   Price in day 3 after 10% discount = 77.84   So, Price in day 3 as percentage of the sale price on day 1 will be = 77.84/93*100 => 83.7%   83.7%nswer will definitely be (83.7%)
Answer: A
Out of the total 390 students studying in a college of Arts and Science, boys and girls are in the ratio of 7 : 6 respectively and the number of students studying Arts and Science are in the ratio of 3 : 7 respectively. The boys and girls studying Arts are in the ratio of 4 : 5 respectively. How many boys are studying science?
Options:
A) 52
B) 65
C) 115
D) 158
E) 168

Solution: Given, boys and girls are in the ratio of 7 : 6,   So, Number of boys = 7/13 x 390 = 210   Number of girls = 390 - 210= 
390 - 210 = 180
180   Students studying Arts and Science are in the ratio of 3 : 7,   Number of students studying Arts= 3/10 x 390 = 117   Number of students studying Science = 390 - 117= 
390 - 117 = 273
273   Also boys and girls studying Arts are in the ratio of 4 : 5,   Number of boys studying arts= 4/9 x 117 = 52   Number of boys studying science = 210 - 52= 
210 - 52 = 158
158   ANSWER:158
Answer: D
In 2 bags, there are to be put together 5 red and 12 white balls, neither bag being empty. How must the balls be divided so as to give a person who draws 1 ball from either bag- the greatest chance of drawing a red ball ?	Choose one:	A) 1/8	B) 2/8	C) 3/8	D) 4/8	E) 5/8

Solution: greatest chance.   1/2*1 +1/2*4/16=5/8   ANSW5/8R:5/8
Answer: E
The average of runs of a cricket player of 20 innings was 32. How many runs must he make in his next innings so as to increase his average of runs by 5 ? Choose the correct choice from the following answers:
A) 96	B) 106	C) 128	D) 137	E) 122

Solution: Average = total runs / no.of innings = 32   So, total = Average x no.of innings = 32 * 20= 
32 * 20 = 640
640   Now increase in avg= 4 runs. So, new avg = 32+5= 
32+5 = 37
37 runs   Total runs= new avg x new no. of innings = 37 * 21= 
37 * 21 = 777
777   Runs made in the 11th inning= 777-640= 
777-640 = 137
137   ANSWER:137
Answer: D
A “Sophie Germain” prime is any positive prime number p for which 2p + 1 is also prime. The product of all the possible units digits of Sophie Germain primes greater than 9 is	Choices:
A) 3
B) 7
C) 21
D) 189
E) 267

Solution: In that case, the Sophie prime numbers greater than 9 are 11,23,47,59, .. which yields units digit as 1,3,7 and 9   Product would be 1 x 3 x 7x9 =189 Answer should be 189
Answer: D
Machine–A produces 40% of the total output and Machine-B produces 60% of the total output. An average of nine units out of a thousand goods manufactured by Machine-A and one unit of 100 units produced by Machine-B prove to be defective. What is the probability that a unit chosen at random from the total daily output of the factory is defective?
Pick one
A) a. 0.96 B) b. 0.096 C) c. 0.0096 D) d. 0.00096 E) e. 0.000096

Solution: Let total Production be 10000 units....   A produces 4000 units and 36 units are defective   B produces 6000 units and 60 units are defective   So, Out of total 10,000 units 96 units are defective...   So the required probability = 96/10000= 
96/10000 = 6/625 = around 0.0096
> 0.0096   Answer will be (c. 0.0096)
Answer: C
There are 3 people and 3 chairs. In how many different ways people can occupy the chairs?
Pick:
A) 6  B) 15  C) 24  D) 36  E) 120

Solution: number of ways =3! = 6   6nswer is 6
Answer: A
If a positive integer n is divisible by both 3 and 7, then n must also be divisible by which of the following?
I. 21
II. 10
III. 63
Choose the correct choice
A) None	B) I only	C) II only	D) I and II	E) II and III

Solution: A multiple of 3 and 7 is also a multiple of 21, but not necessarily a multiple of 10 or 63.   The answer is I only.
Answer: B
A train passes a station platform in 40 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answers
A) 177 m B) 300 m C) 240 m D) 187 m E) 186 m

Solution: Speed = [54 * 5/18] m/sec = 15 m/sec.   Length of the train = (15 * 20)= 
(15 * 20) = 300
300 m.   Let the length of the platform be x meters.   Then, x + 300 / 40= 15   x + 300 = 600   x = 300 m.   Answer: 300 m
Answer: B
Each night before he goes to bed, Jordan likes to pick out an outfit to wear the next day. He has 8 different shirts, 10 different pairs of jeans, and 8 pairs of sneakers. If an outfit consists of 1 shirt, 1 pair of jeans, and 1 pair of sneakers, how many different outfits does Jordan have?
Choose the correct choice: A) 30 B) 90 C) 640 D) 480 E) 960

Solution: Total # of outfits = 8 * 10 * 8 = 960   Answer - 640
Answer: C
X can finish a work in 30 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work?  Answers:
A) 3  B) 10  C) 6  D) 8  E) 9

Solution: Work done by X in 1 day = 1/30   Work done by Y in 1 day = 1/15   Work done by Y in 10 days = 10/15 = 2/3   Remaining work = 1 – 2/3 = 1/3   Number of days in which X can finish the remaining work = (1/3) / (1/30)= 
(1/3) / (1/30) = 10
10   10
Answer: B
There are different 6 circles. What is the number of the greatest possible points with which the circles intersect?
Choose the correct choice from the following options: A) 90 B) 100 C) 110 D) 180 E) 30

Solution: Maximum points of intersection between n different circles = n*(n - 1) = 6*5= 
6*5 = 30
30   Answer: 30
Answer: E
A and B started a business in partnership investing Rs.20,000 and Rs.15,000 respectively. After 6months, C joined them with Rs.20,000. Whatwill be B's share in total profit of Rs.15,000 earned at the end of 2years from the startingof the business?  Choose one:
A) s. 5,000	B) s. 4,500	C) s. 5,700	D) s. 6,500	E) s. 7,500

Solution: A : B : C = (20,000 x 24) : (15,000 x 24) : (20,000 x 18) = 4 : 3 : 3.   B's share = Rs. 15000 x	3/10	= Rs. 4,500.   s. 4,500
Answer: B
If the weight of 10 meters long rod is 23.4 kg. What is the weight of 6 meters long rod ? Options.
A) 7.2 kg.  B) 10.8 kg.  C) 14.04 kg.  D) 18.0 kg  E) None

Solution: Answer   ∵Weight of 10 m long rod = 23.4 kg   ∴ Weight of 1 m long rod = 23.4 / 10 kg   ∴ Weight of 6 m long rod = 23.4 x 6 / 10   = 14.04 kg   Option: 14.04 kg.
Answer: C
Two trains are moving in the same direction at 54 kmph and 36 kmph. The faster train crosses a man in the slower train in 27 seconds. Find the length of the faster train?
Choose the correct choice from the following answers:
A) 135 B) 277 C) 187 D) 257 E) 271

Solution: Relative speed = (54 - 36) * 5/18= 
(54 - 36) * 5/18 = 5
5 mps.   Distance covered in 27 sec= 27 * 5= 
27 * 5 = 135
135 m.   The length of the faster train= 135 m.   135nswer: 135
Answer: A
If by selling twelve note-books, the seller earns profit equal to the selling price of two note-books, what is his percentage profit?
Choose one:
A) 20% B) 25% C) 2163% D) Data inadequate E) None of these

Solution: Percentage profit= 2/12−2×100=20%   20%nswer 20%
Answer: A
Find the odd man out. 5,7,9,12,13  Choose the correct answer:	A) 52	B) 12	C) 11	D) 14	E) 10

Solution: Explanation :   5+2= 
5+2 = 7
7   7+2= 
7+2 = 9
9   9+2= 
9+2 = 11
11   11+2= 
11+2 = 13
13   Hence, it is clear that 11 should have come instead of 12   Answer : Option 11
Answer: C