MU-NLPC/Calc-aqua_rat huggingface dataset:
The volumes of two cones are in the ratio 1 : 10 and the radii of the cones are in the ratio of 1 : 2. What is the length of the wire?	Pick:
A) 2:5  B) 2:9  C) 2:4  D) 2:7  E) 2:1

Solution: The volume of the cone = (1/3)πr2h   Only radius (r) and height (h) are varying.   Hence, (1/3)π may be ignored.   V1/V2 = r12h1/r22h2 => 1/10 = (1)2h1/(2)2h2   => h1/h2 = 2/5   i.e. h1 : h2 = 2 : 5   2:5nswer: 2:5
Answer: A
Lottery balls numbered consecutively from one through one hundred are placed in a spinner. If one ball is drawn at random, what is the probability that it will have the number 4 on it exactly once?  Choose one:  A) 9/100  B) 1/10  C) 11/100  D) 18/100  E) 1/5

Solution: Probability = No of balls with exactly one 1 / total number of balls   = {4,14,24,34,40,41,42,43,45 to 49,54,64,74,84,94}/100   = 18/100   Answer is 18/100
Answer: D
Ramesh spends 40% of his monthly salary on food, 40% of the remaining on conveyance and clothes and saves 50% of the remaining amount. If his monthly salary is Rs.17,000, how much money does he save every month ?	Choose the correct choice from the following options:
A) Rs. 3,400	B) Rs. 3060	C) Rs. 2,540	D) Rs.1,880	E) None of these

Solution: Explanation:   Ramesh's monthly income = Rs.17,000   He spends 40% on food.   The total money spent on food = 40/100 * 17000 = Rs. 6800   Now, his monthly remaining income = Rs.17000 – Rs.6800 = Rs. 10200   Out of Rs. 10200, he spends 40% on conveyance and clothes.   The total money spent on conveyance and clothes = 40/100 * 10200 = Rs. 4080   Now, his monthly remaining income = Rs.10200 – Rs.4080 = Rs. 6120   Out of Rs. 6120, he saves 50%.   Amount saved = 50/100 * 6120 = Rs. 3060   ANSWER Rs. 3060
Answer: B
A and B together can complete work in 6 days. A alone starts working and leaves it after working for 4 days completing only half of the work. In how many days it can be completed if the remaining job is undertaken by B? Answers
A) 4 B) 12 C) 5 D) 6 E) 7

Solution: Explanation:   (A+12) one day work =1/6   now A does half of the work in 4 days so A can complete the whole work in 8 days   A’s one day work =1/8   12’s one day work=1/6 - 1/8= 2/48= 1/24   12 alone can complete the work in 24 days so half of the work in 12 days   Answer: Option 12
Answer: B
12 men complete a work in 9 days. After they have worked for 6 days, 6 more
men joined them. How many days will they take to complete the remaining work? Choose one
A) 5  B) 1  C) 2  D) 3  E) 7

Solution: 1 man's 1 day work = 1/108   12 men's 6 days work = 6/9 = 2/3   remaining work = 1 – 2/3 = 1/3   18 men's 1 days work = 18/108 = 1/6   1/6 work is done by them in 1 day   therefore, 1/3 work is done by them in  6/3= 
 6/3 = 2
2 days.   ANSWER 2
Answer: C
ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 3-digit numbers areSvennumbers?
Choose the correct choice from the following answers
A) 20	B) 60	C) 160	D) 220	E) 250

Solution: ASvennumber is defined as a five-digit number which goes according to the following rules: the leftmost digit is even, any digit to the right of an even digit must be an odd digit, and any digit to the right of an odd digit can only be one of the digits 1 or 7. How many different 5-digit numbers areSvennumbers?   4/9*5/10*2/10*2/10*2/10=160/9000   B. 60
Answer: B
In a hostel there were 100 students. To accommodate 20 more students the average is decreased by rupees 5. But total expenditure increased by Rs.400. Find the total expenditure of the hostel now?	Choose the most appropriate option.
A) 2299
B) 2777
C) 5400
D) 1277
E) 231

Solution: 100x + 400 = 12(x – 5)   x = 50   100 * 50 + 400= 
100 * 50 + 400 = 5_400
5400.Answer:5400
Answer: C
Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756  Options
A) 1789  B) 1890  C) 2100  D) 2300  E) 2124

Solution: 2nd term = (1st term) * 1 + 1 = 15 *1 + 1= 
15 *1 + 1 = 16
16.   3rd term= (2nd term) * 2 + 2 = 16 * 2 + 2= 
16 * 2 + 2 = 34
34   4th term= (3th term) *3 + 3 = 34 * 3 + 3= 
34 * 3 + 3 = 105
105   5th term= (4th term) * 4 + 4 = 105 * 4 + 4= 
105 * 4 + 4 = 424
424   6th term= (5th term) * 5 + 5 = 424 * 5 + 5= 
424 * 5 + 5 = 2_125
2125   6th term should 2125 instead of 2124.   2124
Answer: E
Machine A and machine B process the same work at different rates. Machine C processes work as fast as Machines A and B combined. Machine D processes work three times as fast as Machine C; Machine D’s work rate is also exactly four times Machine B’s rate. Assume all four machines work at fixed unchanging rates. If Machine A works alone on a job, it takes 6 hours and 40 minutes. If all four machines work together on the same job simultaneously, how many minutes will it take all of them to complete it? Choices: A) 18 B) 18 C) 20 D) 22 E) 24

Solution: C = A + B   D = 3C = 3(A+B) = 4B   Then B = 3A and C = 4A   The combined rate of the four machines is A + 3A + 4A + 12A = 20A   Machine A can complete the work in 400 minutes, so its rate is 1/400 of the work per minute.   The combined rate is 20/400 = 1/20 so the work will be completed in 20 minutes.   The answer is 20.
Answer: C
Three unbased coins are tossed. the probability of getting at most three head and three tails is ?	Choose the most appropriate option:
A) 1/2	B) 1/4	C) 3/4	D) 1/5	E) 2/3

Solution: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}   E be the event of getting at least two head is {TTT,HHH}   P(E)=n(E)/n(S)=2/8 = 1/4   Answer(1/4)
Answer: B
If the average (arithmetic mean) of 5 positive temperatures is q degrees Fahrenheit, then the sum of the 3 greatest of these temperatures, in degrees Fahrenheit, could be:  Pick one:
A) 6q	B) 4q	C) 5q/3	D) 3q/2	E) 3q/5

Solution: The sum of three greatest should be more than sum of two lowest.   The total sum is; 5q   A. 6q; 6q is more than 5q. Not possible.   B. 4q; 5q-4q=q(Possible)   C. 5q/3; 10q/3; 10q/3 > 5q/3. Not possible   D. 3q/2; 7q/2; 7q/2 > 3q/2. Not possible   E. 3q/5; 22q/5; 22q/5 > 3q/5. Not possible.   Ans:4q
Answer: B
A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 77.44, the number of the member is the group is:  Select the correct option:
A) 57  B) 67  C) 77  D) 88  E) 97

Solution: Money collected = (77.44 x 100) paise = 7744 paise.   Number of members =Square root of 7744 = 88.   Answer: Option 88
Answer: D
Three men " Sam, Cam and Laurie " are married to Carrie, Billy and Tina, but not necessarily in the same order. Sam's wife and Billy's Husband play Carrie and Tina's husband at bridge. No wife partners her husband and Cam does not play bridge. Who is married to Cam?  Choose the correct choice from the following answers.
A) Carrie	B) Billy	C) Tina	D) Laurie	E) none

Solution: 1 st game:   sam's wife-Tina   VS   Billy'husband-laurie   2 nd game   carrie   VS   tina's husband-sam   Cam is married to carrie   CarrieNSWER:Carrie
Answer: A
How much time will a train of length 200 m moving at a speed of 72 kmph take to cross another train of length 300 m, moving at 36 kmph in the same direction? Select the correct option.
A) 50 sec  B) 25 sec  C) 40 sec  D) 65 sec  E) 60 sec

Solution: Explanation:   The distance to be covered = Sum of their lengths = 200 + 300= 
200 + 300 = 500
500 m.   Relative speed= 72 -36= 
72 -36 = 36
36 kmph= 36 * 5/18= 
36 * 5/18 = 10
10 mps.   Time required= d/s = 500/10= 
500/10 = 50
50 sec.   50 secNSWER IS 50 sec
Answer: A
Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 11 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n?	Choose one:
A) 10
B) 11
C) 12
D) 13
E) 14

Solution: if n =12   mark sold 1 box   and Ann sold 10 boxes   total 11 < 12   Answer:12
Answer: C
One hour after Jerry started walking the 60 miles from X to Y, James started walking from X to Y as well. Jerry walks 3 miles per hour and James walks 1 mile per hour faster than Jerry . How far from X will James be when he catches up to Jerry ?
Choose the correct choice from the following choices:
A) 12 miles
B) 9 miles
C) 10 miles
D) 11 miles
E) 13 miles

Solution: One hour after Jerry started walking the 60 miles from X to Y, James started walking from X to Y as well. Jerry walks 3 miles per hour and James walks 1 mile per hour faster than Jerry . How far from X will James be when he catches up to Jerry ?   First, determine how far Jerry has walked in the one hour. he has walked three miles which means she is three miles ahead of James when he sets off. James walks at four miles/hour which means that every hour, james will get one mile closer to Jerry . If he gets one mile closer every hour, it will take him three hours to catch up to her which means he travels 3hours * 4 miles/hour = 12 miles and he travels 4 hours * 3 miles/hour = 12 miles. He will be 12 miles from X when he catches up to her.   A slightly different way to solve...   We don't know how long they will walk before they catch up to one another but we do know that A walks for one hour more than J. J = T and A = T+1. We are looking for the distance at which they meet up which means the distance will be the same. D=r*t so,   r*t (james) = r*t (Jerry )   r*(t) = r*(t+1)   4t = 3t+3   t=3   d=r*t   d=4*3= 
4*3 = 12
12   answer is 12 miles
Answer: A
A train 108 m long moving at a speed of 50 kmph crosses a train 112 m long coming from opp direction in 6 seconds.The speed of the second train is
Choose the correct choice.
A) 48 kmph B) 54 kmph C) 66 kmph D) 82 kmph E) 69 kmph

Solution: both trains are moving in opposite direction means we need to add their speeds.   i.e: 1st train speed is = 50kmph   let the 2nd train speed = x kmph   relative speed = (50+x) kmph   = (50+x)* 5/18   = (250+5x)/18 m/sec   Distance covered by two trains = 108+112= 
108+112 = 220
220m   therefore, 220/((250+5x)/18)= 6   => 250+5x=660   => x=82km/hr.   ANSWER:82 kmph
Answer: D
By selling 99 pens, a trader gains the cost of 33 pens. Find his gain percentage?  Choose the correct choice from the following options:	A) 33 1/3%	B) 33 7/3%	C) 33 1/8%	D) 32 1/3%	E) 33 1/5%

Solution: Let the CP of each pen be Rs. 1.   CP of 99 pens = Rs. 99   Profit = Cost of 33 pens   = Rs. 33   Profit% = 33/99 * 100   = 33 1/3%   33 1/3%nswer: 33 1/3%
Answer: A
If 2|2 –e| = 5, what is the sum of all the possible values for e ?	Choose the correct choice
A) 1/2
B) 2
C) 5/2
D) 4
E) 5

Solution: if e<2, then 2-e=5/2; e=-1/2   if e>2 , then e-2=5/2; e=9/2   9/2-1/2=8/2= 
8/2 = 4
4=4
Answer: D
A is the son of C; C and Q are sisters; Z is the mother of Q and P is the son of Z. Which of the following statements is true?  Pick:  A) P and A are cousins  B) P is the maternsl uncle of A  C) Q is the maternal grandfather of A  D) C and P are sisters  E) none

Solution: P is the maternsl uncle of A   ANSWER:P is the maternsl uncle of A
Answer: B
I have a huge bed-sheet of 1 meter long.
I want to cuts this role into pieces of 20 centimeter long cloth.
How long will it take me to cut the bed sheet if each 20 centimeter cut took me 5 minutes ?	Choose the correct choice from the following:
A) 200 minutes  B) 245 minutes  C) 140 minutes  D) 220 minutes  E) 324 minutes

Solution: B   245 minutes   It will take 49 cuts not 50.   so 49*5= 
49*5 = 245
> 245 minutes
Answer: B
Find large number from below question The difference of two numbers is 1325. On dividing the larger number by the smaller, we get 5 as quotient and the 5 as remainder  Choose the correct choice from the following:
A) 1650 B) 1324 C) 1245 D) 1300 E) 1635

Solution: Let the smaller number be x. Then larger number = (x + 1325).   x + 1325 = 5x + 5   4x = 1320   x = 330   Large number = 330+1320= 
330+1320 = 1_650
1650   1650nswer : 1650
Answer: A
If two-third of a bucket is filled in 2 minutes then the time taken to fill the bucket completely will be .	Choose the correct choice from the following choices:
A) 3 minutes  B) 70 seconds  C) 60 seconds  D) 100 seconds  E) 120 seconds

Solution: 2/3 filled in 2 mint   1/3 filled in 1 mint   then 2/3+1/3= 2 + 1= 
2 + 1 = 3
3 minutes   3 minutesNSWER: 3 minutes
Answer: A
A salt solution contains 15 grams of salt per 1000 cubic centimeters of solution. If 25 cubic centimeters of the solution were poured into an empty container, how many grams of salt would be in the container? Answers
A) 0.550	B) 0.350	C) 0.450	D) 0.700	E) 0.375

Solution: We are given that a salt solution contains 15 grams of salt per 1000 cubic centimeters of solution. Since we are dealing with a solution, we know that the grams of salt is proportional to the number of cubic centimeters of solution. Thus, to determine how many grams of salt would be in the container when we have 25 cubic centimeters of solution, we can set up a proportion.   We can say: “15 grams of salt is to 1000 cubic centimeters of solution as x grams of salt is to 25 cubic centimeters of solution.” Let’s now set up the proportion and solve for x.   15/1000 = x/25   When we cross multiply we obtain:   (15)(25) = 1000x   375 = 1000x   0.375 = x   There are 0.375 grams of salt in the solution in the container.   The answer is 0.375.
Answer: E
In a certain animal shelter, the ratio of the number of catsto the number of dogs is 15 to 7. If 12 additional dogs were to be taken in by the shelter, the ratio of the number of cats to the number of dogs would be 15 to 11. How many cats are in the shelter?
Choices.
A) 15	B) 45	C) 30	D) 45	E) 60

Solution: This ratio question can be solved in a couple of different ways. Here's an Algebraic approach...   We're told that the ratio of the number of cats to the number of dogs is 15:7. We're then told that 12 more dogs are added to this group and the ratio becomes 15:11. We're asked for the number of cats.   Algebraically, since the number of cats is a multiple of 15 and the number of dogs is a multiple of 7, we can write this initial relationship as...   15X/7X   When we add the 12 cats and factor in the 'ending ratio', we have an equation....   15X/(7X+12) = 15/11   Here we have 1 variable and 1 equation, so we can solve for X....   (15X)(11) = (7X+12)(15)   (X)(11) = (7X+12)(1)   11X = 7X + 12   4X = 12   X = 3   With this X, we can figure out the initial number of dogs and cats...   Initial dogs = 15X = 15(3) = 45   Final Answer: 45
Answer: B
The water level in a reservoir has been dropping at the rate of 14 inches per day. Exactly 4 days ago, the water level was at w inches. What will be the water level exactly 4 days from now if the rate at which the level is dropping remains the same?	Choose the correct choice from the following choices.
A) w − 126  B) w − 112  C) w − 14  D) w + 14  E) w + 126

Solution: Drop=14 inches/day   4 Days ago=w, means now it's equal w-56 and in 4 days = w-56-56=w-112   Answer w − 112
Answer: B
How many integers between 50 and 200 are there such that their unit digit is odd?
Choose the correct choice from the following:	A) 100	B) 120	C) 75	D) 50	E) 150

Solution: 150 numbers between - 50 and 200   Out of which half would be even, half odd.   Number of odd unit digit number = 75.   correct option is 75
Answer: C
In how many ways can 5 different candies be distributed in 4 identical baskets?	Pick one.
A) 120
B) 51
C) 24
D) 5^4
E) 4^5

Solution: 5-N-N-N : 5C5 = 1 - OK   4-1-N-N : 5C4 *1C1 = 5 - OK   3-2-N-N : 5C3*2C2 = 10 - OK   3-1-1-N : 5C3*2C1*1C1 = 20 - NO - only 10, once you decide to split the remaining two after choosing the 3 before, no factor of 2 needed   2-2-1-N : 5C2*3C2*1C1 = 30 - NO - it is 15 = 30/2; baskets being identical, doesn't matter which group of 2 you choose first   2-1-1-1 : 5C2*3*2*1 = 60 - NO - only 10, because you only choose those 2 to be placed together, all the other three you put in different baskets, no choices   Total of   1 + 5 + 10 + 10 + 15 + 10= 
  1 + 5 + 10 + 10 + 15 + 10 = 51
51.   Answer 51.
Answer: B
A wheel has a diameter of x inches and a second wheel has a diameter of y inches. The first wheel covers a distance of d feet in 75 revolutions. How many revolutions does the second wheel make in covering d feet? Choose the correct option:
A) 75x/y
B) 75x-y
C) 25x-y
D) 25x+y
E) 75y/x

Solution: A wheel covers 2πr distance in one revolution. where r= diameter/2   First wheel covers d feet in 75 rev. => d= 75* 2π * (x/2)   Second wheel covers d feet in let's say P revolutions; => d = P* 2π * (y/2)   comparing both equations:-   => p= (75∗2π∗x/2)/(2π∗y/2)   => 75x/y   75x/ynswer :- 75x/y
Answer: A
Radha remembers that her father's birthday is after 16th but before 21st of March, While her brother Mangesh remembers that his father,s birthday is before 22nd but after 19th of March. On which date is the birthday of their father?  Choose one:
A) 19th
B) 20th
C) 21st
D) Cannot be determined
E) None of these

Solution: before 21st and after 19th they mentioned clearly   so 20th march   ANSWER:20th
Answer: B
In a TV factory, an average of 60 TVs are produced per day for the fist 25days of the months. A few workers fell ill for the next five days reducing thedaily avg for the month to 58 sets/day . The average production per day for day last 5days is ?	Answers.
A) 42  B) 46  C) 48  D) 50  E) 54

Solution: Production during these 5 days = Total production in a month - production in first 25 days.   = 30 x 58 - 25 x 60   = 240   ∴ Average for last 5 days = 240 / 5= 
240 / 5 = 48
48   48
Answer: C
The sum of three consecutive even numbers is 42. Find the middle number of the three?
Choose the correct choice from the following choices:
A) 14  B) 16  C) 18  D) 24  E) 25

Solution: Explanation:   Three consecutive even numbers (2P - 2), 2P, (2P + 2).   (2P - 2) + 2P + (2P + 2) = 42   6P = 42 => P = 7.   The middle number is: 2P = 14.   14NSWER IS 14
Answer: A
In a certain game, you pick a card from a standard deck of 52 cards. If the card is a heart, you win. If the card is not a heart, the person replaces the card to the deck, reshuffles, and draws again. The person keeps repeating that process until he picks a heart, and the point is to measure how many draws did it take before the person picked a heart and won. What is the probability that there will be at least four draws involved in a win, i.e. someone picking her first heart on the fourth draw or later?
Choose the correct choice from the following:
A) 1/2  B) 9/16  C) 11/16  D) 13/16  E) 27/64

Solution: Probability of picking a heart on any draw = 1/4   Probability of NOT picking a heart on the first draw AND on the second draw And 3rd draw = [1-(1/4)] X [1-(1/4)] X [1-(1/4)]= 3/4 X 3/4 X 3/4 = 27/64   Answer : 27/64
Answer: E
Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?  Choose one.
A) Rs.200  B) Rs.250  C) Rs.350  D) Rs.370  E) Rs.400

Solution: Let the amount paid to A per week = x   and the amount paid to Rs.250 per week = y   Then x + y = 550   Rs.250ut x = 120% of y = 120y/100 = 12y/10   ∴12y/10 + y = 550   ⇒ y[12/10 + 1] = 550   ⇒ 22y/10 = 550   ⇒ 22y = 5500   ⇒ y = 5500/22 = 500/2 = Rs.250   Rs.250)
Answer: B
A certain bushel of wheat generates one-third the profit of a bushel of corn. If a bushel of corn generates five-fourths the profit of a bushel of truffles, what fraction of the profit from a bushel of wheat is the profit from a bushel of truffles?	Choose the correct choice from the following answers.
A) 5/12  B) 4/5  C) 5/4  D) 5/3  E) 12/5

Solution: Let Corn profit = 3x   Wheat profit = x   Truffle Profit = 4/5 * 3x = 12/5 * x   Wheat Profit / Truffle Profit = x / [12/5 * x] = 5/12   5/12nswer 5/12.
Answer: A
The number 642 is added to a 3-digit number 7x2 to give a 4 digit 13y4 which is exactly divisible by 11.find xy  Choose the correct choice from the following choices:  A) 12  B) 13  C) 14  D) 15  E) 16

Solution: if a number is divisible by 11,means diff b/w it's digits at odd and even place should be 0 or multiples of 11.   so 13y4 1+y=3+4 y=6 therefore no is 1364   now subtract 642 from 1364=722   therefore x=2   xy=12   12NSWER:12
Answer: A
If YWVSQ is 27 - 23 - 21 - 19 - 17, Then WKIGF
Choose the correct option:
A) 13 - 11 - 9 - 7 - 9
B) 13 - 11 - 9 - 7 - 6
C) 13 - 11 - 9 - 7 - 7
D) 13 - 11 - 9 - 7 - 5
E) 13 - 11 - 9 - 7 - 1

Solution: WKIGF = 13 - 11 - 9 - 7 - 5   Note: this is a dummy question. 13 - 11 - 9 - 7 - 5ont answer these questions   Answer:13 - 11 - 9 - 7 - 5
Answer: D
An bus covers a certain distance at a speed of 140 kmph in 5 hours. To cover the samedistance in 1hr, it must travel at a speed of? Choose the correct choice from the following:
A) 520 km/hr B) 640 km/hr C) 656 km/hr D) 731 km/hr E) 700 km/hr

Solution: Distance = (140 x 5) = 700 km.   Required speed = 700 km/hr.   700 km/hr
Answer: E
A not-so-good clockmaker has four clocks on display in the window. Clock #1 loses 17 minutes every hour. Clock #2 gains 15 minutes every hour relative to Clock #1 (i.e., as Clock #1 moves from 12:00 to 1:00, Clock #2 moves from 12:00 to 1:15). Clock #3 loses 20 minutes every hour relative to Clock #2. Finally, Clock #4 gains 20 minutes every hour relative to Clock #3. If the clockmaker resets all four clocks to the correct time at 12 noon, what time will Clock #4 display after 6 actual hours (when it is actually 6:00 pm that same day)? Choose the correct choice from the following choices
A) 5:00  B) 5:34  C) 5:42  D) 6:00  E) 6:24

Solution: C1 loses 15 minutes every hour. So after 60 minutes have passed, C1 displays that 60-15= 
60-15 = 45
45 minutes have passed.   C2 gains 15 minutes for every 60 minutes displayed on C1. Thus, the time displayed on C2 is 75/60= 5/4 the time displayed on C1. So after 60 minutes have passed, C2 displays the passing of (5/4 * 45) minutes.   C3 loses 20 minutes for every 60 minutes displayed on C2. Thus, the time displayed on C3 is 40/60 = 2/3 the time displayed on C2. So after 60 minutes have passed, C3 displays the passing of (2/3 * 5/4 * 45) minutes.   C4 gains 20 minutes for every 60 minutes displayed on C3. Thus, the time displayed on C4 is 80/60 = 4/3 the time displayed on clock 3. So after 60 minutes have passed, C4 displays the passing of  4/3 * 2/3 * 5/4 * 45= 
 4/3 * 2/3 * 5/4 * 45 = 50
50 minutes.   C4 loses 10 minutes every hour.   In 6 hours, C4 will lose   6*10= 
  6*10 = 60
60 minutes= 1 hour.   Since the correct time after 6 hours will be 6pm, C4 will show a time of 6-1= 
6-1 = 5
5:34pm.   The correct answer is 5:34.
Answer: B
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum? Choose the most appropriate option
A) 8000
B) 8925
C) 8500
D) 8700
E) 8750

Solution: P = (100*4016.25/9*5) ==>8925   ANSWER 8925
Answer: B
The price of commodity X increases by 40 cents every year, while the price of commodity Y increases by 15 cents every year. In 2001, the price of commodity X was $4.20 and the price of commodity Y was $6.30. In which year will the price of commodity X be 15 cents more than the price of commodity Y?	Choose the correct choice from the following
A) 2010  B) 2011  C) 2012  D) 2013  E) 2014

Solution: The price of commodity X increases 25 cents each year relative to commodity Y.   The price difference is $2.10 and commodity X needs to be 15 cents more than commodity Y.   $2.25 / 25 cents = 9 years   The answer is   2001 + 9= 
  2001 + 9 = 2_010
2010.   The answer is 2010.
Answer: A
Kate made a deposit in a savings account that pays 5% compound interest annually two years ago. If her current account balance is $1,323, how much did she deposit in the account?
Answers:  A) $1000  B) $1100  C) $1200  D) $1300  E) $1400

Solution: We are given the final amount at the end of two years (i.e initial amount invested + interest) = $1323   Interest rate = 5%   No of $1200ycles = 2   A = P (1 +r)^n   1323 = P (1 + .05)^2   1323 = P (1 + 1/20)^2   1323 = P*(21/20)^2   Solving for P = 1200   Option $1200
Answer: C