MU-NLPC/Calc-aqua_rat huggingface dataset:
The distance between Delhi and Mathura is 170 kms. A starts from Delhi with a speed of 20 kmph at 7 a.m. for Mathura and B starts from Mathura with a speed of 25 kmph at 8 p.m. from Delhi. When will they meet?	Choose the correct choice from the following.
A) 10.50 a.m.
B) 11.20 a.m.
C) 10.30 a.m.
D) 11.40 a.m.
E) 1.40 a.m.

Solution: D = 170 â€“ 20 = 150   RS = 20 + 25= 
20 + 25 = 45
45   T= 150/45 = 3 1/3 hours   8 a.m. + 3 hrs 20 min = 11.20 a.m.   ANSWER:11.20 a.m.
Answer: B
If f(x)= 5x^3- 2x+8 and g(y)= 6y+4, then g(f(x)) =
Answers
A) 30x^3-12x+52  B) 11x^2-12x+44  C) 8x^3-8x+32  D) 30x^3+4x+4  E) 30x^3-12x+44

Solution: g(f(x)) = 6(f(x)) +4 = 6(5x^3- 2x+8) + 4 = 30x^3-12x+52 =>30x^3-12x+52
Answer: A
A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at: Select.
A) 5.30 a.m B) 6.42 a.m C) 7.55 a.m D) 7.42 a.m E) None

Solution: Sol.   Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two   Relative speed of A and B = (6-1)= 
(6-1) = 5
5 rounds per hour.   Time taken to complete one round at this speed= 1/5 hr = 12 min.   Answer 7.42 a.m
Answer: D
If 5a + 7b = t, where a and b are positive integers, what is the largest possible value of t for which exactly one pair of integers (a, b) makes the equation true?  Choose the correct choice from the following options:	A) 35	B) 48	C) 69	D) 70	E) 74

Solution: 5*a1 + 7*b1 = t   5*a2 + 7*b2 = t   5*(a1 - a2) = 7*(b2 - b1)   since we are dealing with integers we can assume that a1 - a2 = 7*q and b2 - b1 = 5*q where q is integer, so whenever we get a pair for (a;b) we can find another one by simply adding 7 to a and subtracting 5 from b or vice versa, subtracting 7 from a and adding 5 to b.   Lets check how it works for our numbers, starting from the largest:   E)74 = 5*12 + 7*2 (a1 = 12, b1 = 2), subtract 7 fromaand add 5 tobrespectively, so a2 = 5 and b2 = 7, second pair - bad   70)70 = 5*7 + 7*5 (a1 = 7, b1 = 5), if we add 7 toawe will have to subtract 5 from b but b can't be 0, so - no pair, if we subtract 7 froma, we'll get a = 0 which also isn't allowed - no pair, thus this is the only pair for (a;b) that works,good!, thus   70 is the answer
Answer: D
A software programmer does 20% of the work in 80% of the time, and 80% of the work in the remaining 20% of the time. If the code he writes is X lines long and he was given one month (30 days) to accomplish the task, then, assuming that the programmer works at a constant rate in each of the two stages, How many lines of code were written in the last two weeks, in terms of X?  Pick:  A) 13x /15  B) 15x/15  C) 7x/15  D) 2x/30  E) 13x/30

Solution: 30 days- X lines   80% of 30   24 days; 0.2X lines   Remaining 6 days:   0.8X lines   Need to find out for last 14 days;   We know the number of lines for last 6 days: 0.8X   How about 8 days before that;   24 days- 0.2X   1 day - 0.2X/24 lines   8 days - (0.2X/24)*8 lines = (1/15)X lines   Total number of lines in last 14 days   (1/15)x + 0.8X = (1/15)x + (8/10)X = (52/60)X = (13/15)X lines of codes   13x /15NSWER:13x /15
Answer: A
In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 12 to the thrice of the remainder. The dividend is  Pick one.
A) 74
B) 78
C) 86
D) 126
E) 98

Solution: Divisor = (6 * 3) + 12= 
(6 * 3) + 12 = 30
30   5 * Quotient= 30   Quotient = 6.   Dividend = (Divisor * Quotient) + Remainder   Dividend = (20 * 6) + 6= 
(20 * 6) + 6 = 126
126.   126)
Answer: D
The length of a room is 5.5 m and width is 3.75 m. Find the cost of paving the floor by slabs at the rate of Rs. 1000 per sq. metre.  Choose the correct choice from the following answers: A) Rs. 15000 B) Rs. 15550 C) Rs. 15600 D) Rs. 20625 E) None of these

Solution: Solution   Area of the floor = (5.5 × 3.75) m2 = 20.625 m2   ∴ Cost of paving = Rs. (1000 × 20.625) = 20625. Answer Rs. 20625
Answer: D
What must be added to each term of the ratio 7:11, So as to make it equal to 3:4?  Options
A) 8  B) 7.5  C) 6.5  D) 5  E) 6

Solution: Solution: Let x be added to each term.   According to question,   (7+x)/(11+x) = 3/4;   Or, 33+3x = 28+4x;   Or, x = 5.   Answer: Option 5
Answer: D
The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?  Choose one:
A) 270
B) 250
C) 245
D) 320
E) 620

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1365 = 6x + 15   5x = 1350   x = 270   Smaller number = 270.   270NSWER 270
Answer: A
A ladder 14 feet long is leaning against a wall that is perpendicular to level ground. The bottom of the ladder is 9 feet from the base of the wall. If the top of the ladder slips down 1 feet, how many feet will the bottom of the ladder slip?
Choose the correct option.
A) 4  B) 10  C) 18  D) 19  E) 25

Solution: 14^2-9^2=115   it means that the height is equal to 10.72.   since the top of the ladder slips down 1 feet, then the height of the wall =10.72-1= 
10.72-1 = 9.72
9.72   the bottom=sqrt(14^2-9.72^2)=sqrt(196-94.47)=10.07~=10   ans is 10
Answer: B
What day of the week was 1 January 1901	Select the correct option.
A) Monday
B) Tuesday
C) Saturday
D) Friday
E) Sunday

Solution: Explanation:   1 Jan 1901 = (1900 years + 1st Jan 1901)   We know that number of odd days in 400 years = 0   Hence the number of odd days in 1600 years = 0 (Since 1600 is a perfect multiple of 400)   Number of odd days in the period 1601-1900   = Number of odd days in 300 years   = 5 x 3 = 15 = 1   (As we can reduce perfect multiples of 7 from odd days without affecting anything)   1st Jan 1901 = 1 odd day   Total number of odd days = (0 + 1 + 1)= 
(0 + 1 + 1) = 2
2   2 odd days= Tuesday   Hence 1 January 1901 is Tuesday.   Answer: Option Tuesday
Answer: B
Jayant opened a shop investing Rs. 30,000. Madhu joined him 2 months later, investing Rs. 45,000. They earned a profit of Rs. 52,000 after completion of one year. What will be Madhu's share of profit?	Select:
A) Rs. 27,000
B) Rs. 26,000
C) Rs. 30,000
D) Rs. 36,000
E) None of these

Solution: 30,000 *12=45,000*8   1:1   Madhu's share=1/2*52,000   i.e. Rs. 26,000   ANSWER:Rs. 26,000
Answer: B
In 22 minutes, the minute hand gains over the hour hand by	Choose the correct choice from the following options.
A) 56°  B) 80°  C) 88°  D) 96°  E) 121°

Solution: In one hour, the hour hand moves 30°, which is 0.5° each minute.   In one hour, the minute hand moves 360°, which is 6° each minutes.   The minute hand gains 5.5° each minute.   In 22 minutes, the minute hand gains   22 * 5.5= 
  22 * 5.5 = 121
121°.   The answer is 121°.
Answer: E
lexus car agency has 189 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?
Pick one:
A) 56	B) 37	C) 38	D) 39	E) 40

Solution: ratio of 36% profit cars to 9% profit cars = 8:19   so no. of cars sold at 36% profit = 189*8/27= 
189*8/27 = 56
56 cars   56NSWER:56
Answer: A
Tom, working alone, can paint a room in 10 hours. Peter and John, working independently, can paint the same room in 5 hours and 2 hours, respectively. Tom starts painting the room and works on his own for two hour. He is then joined by Peter and they work together for two hour. Finally, John joins them and the three of them work together to finish the room, each one working at his respective rate. What fraction of the whole job was done by Peter?
Options:
A) 1/3  B) 1/2  C) 1/4  D) 1/5  E) 1/6

Solution: Let the time when all three were working together be t hours. Then:   Tom worked for t+4 hour and has done 1/10*(t+4) part of the job;   Peter worked for t+2 hour and has done 1/5*(t+2) part of the job;   John worked for t hours and has done 1/2*t part of the job:   1/10*(t+4)+1/5*(t+2)+1/2*t=1 --> multiply by 10 --> (t+4)+(2t+2)+5t=10 --> t=1/2;   Hence Peter has done 1/5*(1/2+2)=1/5 *5/2=1/2   Answer: 1/2
Answer: B
A group consists of 5 men, 5 women and 3 children. In how many ways can 2 men , 2 women and 1 child selected from the given group?
Choices:  A) 300 ways  B) 400 ways  C) 500 ways  D) 360 ways  E) 380 ways

Solution: Two men, two women and one child can be selected in 5C₂ * 5C2 * 3C₁ ways    5*4/2*1*5*4/2*1*3= 
 5*4/2*1*5*4/2*1*3 = 300
300 ways   300 waysnswer : 300 ways
Answer: A
A butler is promised Rs. 100 and a cloak as his wages for a year. After 7 months he leaves this service, and receives the cloak and Rs.20 as his due. How much is the cloak worth?
Choose the correct option.
A) 22  B) 98  C) 92  D) 72  E) 71

Solution: Explanation:   Let be the price of cloak is = x   According to the Question he should get 7/12th of 100 and 7/12th of cloak.   712(100)+712(x)=20+x712(100)+712(x)=20+x   ⇒ x = 92.   Answer: 92
Answer: C
A barrel holds 4 litres of paint and 4 litres of turpentine. How many quarts of turpentinemust be added to the container to create a mixture that is 3 parts petrol to 5 parts turpentine by volume? Choose the correct option
A) 4/3	B) 5/3	C) 7/3	D) 8/3	E) 10/3

Solution: An alternate to the alligation method is the more direct/algebraic method:   Let x be the amount of turpentine to be added.   New total amount of turpentine = 4+x   Total amount of paint = 4   New total = 4+4+x=8+x   Final ratio required (for turpentine) = 5/(5+3)=5/8   Thus, (4+x)/(8+x) = 5/8 --> solving for x you get x = 8/3.   8/3 is thus the correct answer.
Answer: D
A car covers a certain distance at aspeed of 50 kmph in 5 hours. To cover the same distance in 2 hrs, it must travel at a speed of?
Choose the correct choice from the following answers:
A) 125 km/hr B) 678 km/hr C) 782 km/hr D) 789 km/hr E) 720 km/hr

Solution: Distance = (50 x 5) =250 km.   Speed = Distance/Time   Speed = 250/2= 
250/2 = 125
125 kmph   125 km/hrnswer : 125 km/hr
Answer: A
Jim’s Taxi Service charges an initial fee of $2.25 at the beginning of a trip and an additional charge of $0.25 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?  Choose the correct choice from the following.
A) $3.15
B) $4.5
C) $4.80
D) $5.05
E) $5.40

Solution: Let the fixed charge of Jim’s Taxi Service = 2.25 $   and charge per 2/5 mile(.4 mile) = .25$   Total charge for a trip of 3.6 miles = 2.25 + (3.6/.4) * .25   = 2.25 + 9*.25= 
2.25 + 9*.25 = 4.5
4.5 $   Answer $4.5
Answer: B
If it is 7:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)  Choose the correct option: A) 7:22 B) 7:24 C) 7:27 D) 7:30 E) 7:32

Solution: 7:27minus 2,880,717in any way must end with 0, the only answer choice which ends with 0 is D.   Answer: 7:30.
Answer: D
In covering a distance of 90 km, A takes 2 hours more than B. If A doubles his speed, then he would take 1 hour less than B. A's speed is:	Choose the correct choice from the following answers:
A) 5 km/h B) 8 km/h C) 10 km/h D) 15 km/h E) 25 km/h

Solution: Let A's speed be X km/hr.   Then, 90/x - 90/2x = 3   6x = 90   x = 15 km/hr.   Answer : 15 km/h.
Answer: D
What will come in place of the x in the following number series? 1, 4, 10, 22, 46, x  Pick.
A) 84
B) 92
C) 94
D) 98
E) 104

Solution: 11 × 2 + 2= 
2 + 2 = 4
44 × 2 + 2= 1010 × 2 + 2 = 2222 × 2 + 2 = 4646 × 2 + 2 = 94 94
Answer: C
In a certificate by mistake a candidate gave his height as 20% more than actual height. In the interview panel, he clarified that his height was 5 feet 5 nches. Find the % correction made by the candidate from his stated height to his actual height?	Choose one.
A) 13 B) 20 C) 30 D) 43 E) 50

Solution: His height was = 5 feet 5 inch = 5 + 60= 
5 + 60 = 65
65 inch. Required % correction=65*(1.20-1)= 
65*(1.20-1) = 13
13   13
Answer: A
In Township K each property is taxed at 12 percent of its assessed value. If the assessed value of a property in Township K is increased from $20,000 to $24,000, by how much will the property tax increase?	Choose the correct choice from the following choices:
A) $32 B) $50 C) $320 D) $400 E) $480

Solution: Increase in house value = $24,000 - $20,000 =$4000   So, tax increase = 12% of$4000=$480   Answer: $480
Answer: E
A person crosses a 600 metre long street in 5 minutes. What is his speed in km per hour?  Select:
A) 8.2	B) 4.2	C) 6.1	D) 7.2	E) 8.5

Solution: 7.2istance =600 metre =0.6 km   Time = 5 min = 1/12 hr   speed = dist/time = 0.6/(1/2) = 7.2 km/hr   ANSWER 7.2
Answer: D
The volume of the sphere QQ is (dfrac{37}{64}%)less than the volume of sphere PP and the volume of sphere RR is (dfrac{19}{27}%) less than that of sphere QQ. By what is the surface areaof sphere RR less than the surfacearea of sphere PP? Select the correct option:
A) 50% B) 60% C) 75% D) 80% E) 83%

Solution: Let the volume of sphere PP be 64 parts.   Therefore volume of sphere QQ   =64−3764%=64−3764% of 6464   =64−37=27=64−37=27 parts.   The volume of RR   =27−1927×27=27−1927×27   =27−19=8=27−19=8 parts.   Volume ratio:   =P:Q:R=64:27:8=P:Q:R=64:27:8   Radius ratio:   =P:Q:R=4:3:2=P:Q:R=4:3:2   The surface area will be 16:9:516:9:5   Surface area of RR is less than the surface area of sphere PP   16k−4k=12k16k−4k=12k   Now,   =12k16k×100=12k16k×100   =75%=75%   Thus surface area of sphere RR is less than the surface area of sphere P by 75%   75%
Answer: C
If f(a)=a^2, what is the value of (f(a+b)+f(a))/b ? Select the correct option:  A) a  B) b  C) 2a  D) 2a + b  E) 2a+b+2a^2

Solution: start with f(a+b) before start calculations: f(a+b)=(a+b)^2= a^2+2ab+b^2   a^2+2ab+b^2 + a^2/b = (simplify a^2)   2ab+b^2/b+2a^2 = (cancel b's)   = 2a+b+2a^2   Answer : 2a+b+2a^2
Answer: E
An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: Choose the correct option:
A) 4.04%
B) 4.14%
C) 4.16%
D) 4.20%
E) 5.04%

Solution: 100 cm is read as 102 cm.   A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.   (A2 - A1) = [(102)2 - (100)2]   = (102 + 100) x (102 - 100)   = 404 cm2.   Percentage error = 404 x 100 % = 4.04%   100 x 100   4.04%)
Answer: A
Pipe A fills a tank of capacity 700 liters at the rate of 40 liters a minute. Another pipe B fills the same tank at the rate of 30 liters a minute. A pipe at the bottom of the tank drains the tank at the rate of 20 liters a minute. If pipe A is kept open for a minute and then closed and pipe B is open for a minute and then closed and then pipe C is open for a minute and then closed and the cycle is repeated, when will the tank be full? Select the correct option.
A) 42 minutes B) 14 minutes C) 39 minutes D) 40 minutes 20 seconds E) None of these

Solution: In one cycle they fill 40+30-20= 
40+30-20 = 50
50 liters   700= 50*n => n = 14   here n = number of cycles.   total time = 14*3= 
14*3 = 42
42 as in one cycle there are 3 minutes.   thus 42 minutes   42 minutesNSWER:42 minutes
Answer: A
If x is divisible by 2 and 7, which of the following must divide evenly into x? I. 60 II. 32 III. 14
Pick:	A) I,II only	B) I,III only	C) I only	D) III only	E) II only

Solution: If x is divisible by 2,7 means it will be = or > 14, 28,42 etc...   That are not divisible by 60, 32.   So, the answer is III only
Answer: D
Ramu bought an old car for Rs. 42000. He spent Rs. 13000 on repairs and sold it for Rs. 66900. What is his profit percent?
Choose the correct choice from the following options
A) 17%
B) 19%
C) 18%
D) 21.6%
E) 16%

Solution: Total CP = Rs. 42000 + Rs. 13000   = Rs. 55000 and SP   = Rs. 66900   Profit(%) = (66900 - 55000)/55000 * 100   = 21.6%   Answer: 21.6%
Answer: D
Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 36 hours and 16 hours respectively. The ratio of their speeds is?  Choose one.
A) 4:5  B) 4:3  C) 4:6  D) 4:9  E) 4:2

Solution: Let us name the trains A and B.   Then, (A's speed) : (B's speed)   = √b : √a = √16 : √36 = 4:6   Answer:4:6
Answer: C
Betty picked a number of pears, each of which she sold, canned, or poached. If she canned 30 percent more than she poached, and she poached 10 percent less than she sold. If there were a total of 614 pears, then how many pears did she sell?	Choose the correct choice from the following options:
A) 190  B) 200  C) 210  D) 220  E) 230

Solution: Let x be the amount of pears that she sold.   Then she poached 0.9x.   Then she canned  1.3*0.9= 
 1.3*0.9 = 1.17
1.17x.   The total amount of pears is x+0.9x+1.17x=3.07x   The fraction of pears that she sold is 1/3.07=100/307.   The number of pears she sold is   (100/307)*614= 
  (100/307)*614 = 200
200.   The answer is 200.
Answer: B
The second smallest prime number is? Choices:
A) 67  B) 71  C) 73  D) 21  E) 23

Solution: The second smallest prime number is 67.   67)
Answer: A
If the length of an edge of cube M is four times the length of an edge of cube N, what is the ratio of the volume of cube N to the volume of cube M?
Answers:
A) 1/32
B) 1/16
C) 1/8
D) 1/64
E) 1/12

Solution: The length of cube N = 1;   The length of cube M = 4;   The ratio of the volume of cube N to the volume of cube M = 1^3/4^3 = 1/64   Answer : 1/64
Answer: D
The number of permutations of the letters of the word 'REMEMBER' is?	Choose one.
A) 7!/(2!)2 3!  B) 8!/(2!)2 8!  C) 8!/(8!)2 3!  D) 8!/(2!)2 3!  E) 8!/(2!)2 1!

Solution: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.   The letter pattern 'REMEMBER' consists of 8 letters of which there are 2R's, 3E's, 2M's and 1B.   Number of arrangements = 8!/(2!)2 3!   Answer: 8!/(2!)2 3!
Answer: D
The number 311311311311311311311 is:	Choose one:
A) divisible by 3 but not by 11 B) divisible by 11 but not by3 C) divisible by both 3 and 11 D) neither divisible by 3 nor by 11. E) none of these

Solution: Sum of digits= 35 and so it is not divisible by 3.   (Sum of digits at odd places)- (Sum of digits at even places)= 19-16= 
19-16 = 3
3, not divisible by 11.   So, the given number is neither divided by 3 nor by 11.   ANSWER:neither divisible by 3 nor by 11.
Answer: D
During a two-week period, the price of an ounce of silver increased by 5 percent by the end of the first week and then decreased by 10 percent of this new price by the end of the second week. If the price of silver was x dollars per ounce at the beginning of the two-week period, what was the price, in dollars per ounce, by the end of the period?	Choose the correct answer
A) 0.945x  B) 0.985x  C) 0.995x  D) 1.05x  E) 1.15x

Solution: The price at the end is 0.9(1.05x)=0.945x   The answer is 0.945x.
Answer: A
Simple interest on a certain sum is 9 over 25 of the sum. Find the rate per cent and time, if both are equal.	Choose the most appropriate option:
A) 8% and 8 years  B) 6% and 6 years  C) 10% and 10 years  D) 6 % and 6 years  E) None of these

Solution: 9â„25 P = PÃ—RÃ—R/100   â‡’ R2 = 900â„25 â‡’ R^2 = 36 R= 6   Also, time = 6 years   Answer 6 % and 6 years
Answer: D
A data set with a mean of 90 has a standard deviation of 2.5. Which of the following is the smallest number that falls within one standard deviation of the mean?	Choose the correct choice from the following choices:
A) 53 B) 56 C) 59 D) 63.5 E) 87

Solution: One standard deviation of the mean is from{mean}-{deviation}=90-2.5= 
90-2.5 = 87.5
87.5 to{mean}+{deviation}=90+2.5=92.5. The smallest number within this range from the options is 87.   Answer: E.   Hope this helps.
Answer: E
if A=2^65 AND B=2^64+2^63.....+2^0 Choose the correct choice from the following options:
A) A is larger than B by 2^64 times  B) B is larger than A by 1  C) A is larger than B by 1  D) A is equal to B  E) None

Solution: lets say A : 2^4=16 , B: 2^3+2^2+2^1+2^0 = 15 so A is larger than B by 1 always   ANSWER:A is larger than B by 1
Answer: C
X, Y and Z together invested Rs.106000, X invested Rs.4000 more than Y, and Rs.10000 more than Z. what is the share of X out of annual profit of Rs.26500 ?	Choose the correct choice: A) Rs.10000 B) Rs.10800 C) Rs.10500 D) Rs.11000 E) Rs.11500

Solution: Let Z share be ‘a’ then   Y = a + Rs.6000 [as X investment is Rs.10000 more than Z, and Rs.4000 more than Y, then Y share more than Z by Rs.10000 – Rs.4000 = Rs.6000]   X = a + Rs.10000.   X + Y + Z = 3a + 16000 = Rs.106000.   3a = 106000 – 16000 = Rs.90000.   a = 90000 / 3 = Rs.30000.   therefore Z investment = Rs.30000.   Y = Rs.30000 + Rs.6000 = Rs.36000.   X = Rs.30000 + Rs.10000 = Rs.40000.   Ratio of shares X : Y : Z = 20 : 18 : 15 = [53 units].   Investment Ratio = Profit sharing Ratio.   X = 26500 × 20 / 53 = Rs.10000   Option Rs.10000
Answer: A
A trade analyst announced 10% reduction in the unit price of bike. As a result, the sales volume went up by 25%. What was the net effect on the sales revenue? Select the correct option:  A) no change  B) decreases by 12.5%  C) increases by 12.5%  D) increases by 10%  E) None of these

Solution: Explanation :   Reduction of price = (100 -10)= 
(100 -10) = 90
90%= 0.9   Increase of sale = (100+25)= 
(100+25) = 125
125%= 1.25   Total effect = 0.90X 1.25 = 112.5%, Increases by 12.5%   Answer : increases by 12.5%
Answer: C
10, 50, 13, 45, 18, 38, ?.
What a number should replace the question mark?  Choices:
A) 34
B) 27
C) 25
D) 46
E) 51

Solution: 25   25   There are two alternate sequences: start at 10 and add 3, 5, 7;   start at 50 and deduct 5, 7, 9.
Answer: C
Two trains are running in opposite directions in the same speed. The length of each train is 120 meter. If they cross each other in 4 seconds, the speed of each train (in km/hr) is
Choose the correct answer
A) 42  B) 36  C) 108  D) 120  E) 124

Solution: Explanation:   Distance covered = 120+120= 
120+120 = 240
240 m   Time= 4 s   Let the speed of each train = v. Then relative speed = v+v = 2v   2v = distance/time = 240/4= 
240/4 = 60
60 m/s   Speed of each train= v = 60/2= 
60/2 = 30
30 m/s= 30×36/10 km/hr = 108 km/hr   Answer: Option 108
Answer: C
Calculate how much time could be saved if the train would run at its usual speed, given that it ran at 4/9 of its own speed and got to its destination in 13 hours? Choose the correct choice from the following answers.
A) 1.22 hrs B) 2.22 hrs C) 5.22 hrs D) 6.22 hrs E) 7.22 hrs

Solution: New speed = 4/9 of usual speed   New time = 4/9 of usual time   4/9 of usual time = 13 hrs   Usual time = 13*4/9 = 5.78 hrs   Time saved = 13-5.78= 
13-5.78 = 7.22
7.22 hrs   Answer is 7.22 hrs
Answer: E
In a college, 50% of total 400 Arts students are Locals. 25% of students from 100 Science students are locals and 85% of total 120 Commerce students are locals. What is the total percentage of locals from Arts, Science and Commerce.  Options.
A) 322 B) 340 C) 333 D) 327 E) 500

Solution: locals from Arts = 50% of 400 = 200   locals from Science = 25% of 100 = 25   locals from Commerce = 85% of 120 = 102   total locals = 200+25+102= 
200+25+102 = 327
327   327
Answer: D
Of 5 employees, 3 are to be assigned an office and 2 are to be assigned a cubicle. If 3 of the employees are men and 2 are women, and if those assigned an office are to be chosen at random, what is the probability that the offices will be assigned to 2 of the men and 1 of the women?	Answers:
A) 1/3
B) 2/5
C) 1/2
D) 3/5
E) 2/3

Solution: probability = Desired Outcomes/Total Outcomes   Event = Selection of 3 employees to assign office from 5 such that 2 are men and 1 is woman   Total Outcomes = Selection of any 3 employees from 5 employees = 5 C 3 = 10   Desired Outcomes = Selection of 2 Men from 3 Men AND selection of 1 woman from 2 Women. = (3 C 2) * (2 C 1) = 3*2= 
3*2 = 6
6   Probability= 6/10 --------> 3/5   ANSWER:3/5
Answer: D
What is the quotient between the place values of two 5's in the numeral 57005  Choices
A) 11401  B) 0.5  C) 49995  D) 50000  E) 10000

Solution: Required quotient = 50000 / 5= 
50000 / 5 = 10_000
10000   Answer is 10000
Answer: E
An outlet pipe can empty 2/3 rd of a cistern in 12 minutes. In 8 minutes, what part of the cistern will be emptied?
Choose the correct choice from the following options
A) 4/9  B) 2/3  C) 3/4  D) 5/6  E) 6/8

Solution: 2/3 ---- 12   ? ----- 8 ==> 4/9   4/9NSWER 4/9
Answer: A