MU-NLPC/Calc-aqua_rat huggingface dataset:
The schedule of G first year students was inspected. It was found that M were taking a Mathematics course, L were taking a Language course and B were taking both a Mathematics course and a Language course. Which of the following expression gives the percentage of the students whose schedule was inspected who were taking neither a mathematics course nor a language course? Choose one:  A) 100 x G/B+L+M)  B) 100 x (B+L+M)/G  C) 100 x (G-L-M)/G  D) 100 x (G-B-L-M)/G  E) 100 x (G+B-L-M)/G

Solution: Explanatory Answer   M students are taking a math course.   L students are taking a language course.   B students are taking both a math and a language course.   Number of students taking at least one of the two courses = M U L   M U L = M + L - B   Hence, number of students taking neither of the two courses = G - (M + L - B) = G + B - M - L   100 x (G+B-L-M)/Gxpressed as a percent of the total number of students, we get 100 x (G+B-L-M)/G   Answer 100 x (G+B-L-M)/G
Answer: E
Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 12 minutes earlier than usual. How much time did the man spend walking? Choose the correct choice from the following answers
A) 45 minutes B) 50 minutes C) 40 minutes D) 54 minutes E) 35 minutes

Solution: As they arrived 12 minutes earlier than usual, they saved 12 minutes on round trip from home to station (home-station-home) --> 6 minutes in each direction (home-station) --> wife meets husband 6 minutes earlier the usual meeting time --> husband arrived an hour earlier the usual meeting time, so he must have spent waking the rest of the time before their meeting, which is hour-6 minutes=54 minutes.   Answer: 54 minutes
Answer: D
There are 5 different letters and 5 letter boxes of same size shape and colors. How many method are possible to post the letters?
Answers
A) 50	B) 51	C) 52	D) 53	E) 54

Solution: 50000 ->1   41000 ->5   31100 ->10   32000 ->10   21110 ->10   22100 ->15   11111 ->1   1+5+10+10+10+30+1=52   ANSWER:52
Answer: C
A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 2:3:4. Choose the correct choice from the following answers:
A) 50p coins = 400 20p coins = 600 10p coins = 800  B) 50p coins = 480 20p coins = 600 10p coins = 800  C) 50p coins = 400 20p coins = 600 10p coins = 780  D) 50p coins = 400 20p coins = 608 10p coins = 800  E) 50p coins = 400 20p coins = 600 10p coins = 820

Solution: 50*2k + 20*3k + 10*4k = 40000   200k = 40000 => k = 200   50p coins = 2k = 2*200= 
2*200 = 400
400   20p coins= 3k = 3*200= 
3*200 = 600
600   10p coins= 4k = 4*200= 
4*200 = 800
800   50p coins= 400 20p coins = 600 10p coins = 800nswer:50p coins = 400 20p coins = 600 10p coins = 800
Answer: A
The difference of two numbers is 1360. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?	Select.
A) 240	B) 270	C) 295	D) 360	E) 269

Solution: Let the smaller number be x. Then larger number = (x + 1360).   x + 1360 = 6x + 15   5x = 1345   x = 269   Smaller number = 270.   ANSW269R 269
Answer: E
The rate of a certain chemical reaction is directly proportional to the concentration of chemical B present and inversely proportional to the concentration of chemical A present. If the concentration of chemical B present is increased by 50 percent, which of the following is closest to the percent change in the the concentration of chemical B required to keep the reaction rate unchanged.	Choose the correct answer:
A) 100 % decrease	B) 30% decrease	C) 40% decrease	D) 50% increase	E) 60% increase

Solution: Let's say here is the formula of how A and B affects the reaction speed:   rate = B/A   After the concentration A is increased by 50%, the percentage of A   become 1.5A, to keep 'rate' the same, need to have 1.5B.   Which means B increased by 50%   Answer : 50% increase
Answer: D
Ace Transport has acquired two trucks to carry different types of cargo. One costs $70,000; the other costs $52,000. The company expects that the first will last 165,000 miles, after which it can be sold for salvage for about $4,000. The other will fetch the same salvage price, but will last 200,000 miles. The two trucks convoy together, so they always show the same mileage readings. If the value of each truck declines at different constant rates for every mile driven, at what mileage reading will the residual values of the two trucks be equal?	Select the correct option:  A) 87,500 miles  B) 100,000 miles  C) 107,750 miles  D) 112,500 miles  E) The residual values will never be equal.

Solution: Truck 1 : 70,000 = m1 * 165,000 + 4,000 , where m1 is the depreciation $ per mile   Solve for m1 = 0.4   So the depreciation line for Truck 1 is y = 0.4 x + 4,000 , where y is in dollars and x is in mileage.   Similarly for Truck 2 : 52,000 = m2 * 200,000 + 4,000   and this gives m2 = 0.24   and similar line for Truck 2 is y = 0.24 x + 4,000.   The question is where values are same, and in terms of the equation, it's where the two depreciation lines meet.   so solve for x, 0.4 x + 4,000 = 72,000   0.24x + 4,000 = 52,000   gives x = 112,500,   ANSWER:112,500 miles
Answer: D
An association of mathematics teachers has 1,260 members. Only 560 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 60 percent of the votes cast?  Choose the correct choice
A) 75% B) 26.67% C) 42% D) 34% E) 25%

Solution: Total Number of members = 1260   Number of members that cast votes = 560   Since , winning candidate received 60 percent of the votes cast   Number of votes for winning candidate = (60/100)*560= 
(60/100)*560 = 336
336   Percent of total membership that voted for winning candidate= (336/1260)*100 = 26.67%   Answer 26.67%
Answer: B
Out of 450 students of a school, 325 play football, 175 play cricket and 50 neither play football nor cricket. How many students play both football and cricket ?  Choose the correct choice from the following answers
A) 75	B) 100	C) 125	D) 150	E) None of these

Solution: Explanation:   Students who play cricket, n(A) = 325   Students who play football, n(100) = 175   Total students who play either or both games,   =n(A∪100)=450−50=400Required Number,n(A∩100)=n(A)+n(100)−n(A∪100)=325+175−400=100   Option 100
Answer: B
?% of 360 = 129.6
Choices
A) 277  B) 36  C) 64  D) 72  E) None of these

Solution: ?% of 360 = 129.6   or, ? = 129.6×100/360=36   Answer 36
Answer: B
Factory X's bulbs work for over 5000 hours in 79% of cases, whereas factory Y's bulbs work for over 5000 hours in 85% of cases. It is known that factory X supplies 80% of the total bulbs available. What is the chance that a purchased bulb will work for longer than 5000 hours? Choose the correct choice from the following answers
A) 80.2%  B) 88%  C) 87.4%  D) 85%  E) 83.9%

Solution: For X, 80% of 79% will work.   For Y, 20% of 85% will work. *20% is the rest of the bulb supply in the market.   So, the probability that a purchased bulb will work is:   0.80(0.79) = .632   0.20(0.85) = 0.17   The combined probability then is 63.2 + 17= 
63.2 + 17 = 80.2
80.2%   80.2%NS 80.2%
Answer: A
The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is: Choose the correct option:
A) 4050
B) 3500
C) 4000
D) 4500
E) 5000

Solution: Let P, Q and R represent their respective monthly incomes. Then, we have:   P + Q = (5050 x 2) = 10100 .... (i)   Q + R = (6250 x 2) = 12500 .... (ii)   P + R = (5200 x 2) = 10400 .... (iii)   Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)   Subtracting (ii) from (iv), we get P = 4000.   P's monthly income = Rs. 4000.   Answer: 4000
Answer: C
If the sum of 5 consecutive integers is x, which of the following must be true?
I. x is an even number
II. x is an odd number
III. x is a multiple of 6	Choose the correct option
A) I only	B) II only	C) None	D) I and III	E) II and III

Solution: I. If you start off with an even number, the sum (x) is even, and if you start off with an odd number the sum (x) is odd. Therefore this is not always true.   II. Same as above. This need not be always true.   III. Say, the first number is p. Then the sum of the five numbers = p + (p+1) + (p+2)...... + (p+4)   = 5p + 10 = 5 (p+2) => divisible by 5.   Therefore None is the answer.
Answer: C
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
Choose one.
A) Tuesday B) Monday C) Sunday D) Friday E) Wednesday

Solution: The year 2004 is a leap year. It has 2 odd days.   The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.   Hence, this day is Sunday.   answer : Sunday
Answer: C
The points A(0, 0), B(0, 4a - 5) and C(2a + 1, 2a + 5) form a triangle. If angle ABC = 90, what is the area of triangle ABC?	Choose one:
A) 80 B) 82.5 C) 78.5 D) 75.5 E) 74

Solution: 1/2bh=1/2(2a+1)(2a+5)   Now 4a-5=2a+5   2a=10 ,a=5   Therefore,   A(0,0); 82.5(0,15); C(10,15)   1/2*11*15= 
1/2*11*15 = 165/2 = around 82.5
82.5   Answer: 82.5
Answer: B
The price of a jacket is reduced by 25%. During a special sale the price of the jacket is reduced another 15%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? Options: A) 32.5 B) 35 C) 48 D) 56.8 E) 67.5

Solution: 1) Let the price of jacket initially be $100.   2) Then it is decreased by 25% , therefore bringing down the price to $75.   3) Again it is further discounted by 10%, therefore bringing down the price to $63.75.   4) Now 63.75 has to be added byX %in order to equal the original price.   63.75 + ( X% ) 63.75 = 100.   Solving this eq for X, we get X = 56.8   Ans is 56.8.
Answer: D
A lady has fine gloves and hats in her closet- 25 blue, 7 red, and 9 yellow. The lights are
out and it is totally dark. In spite of the darkness, she can make out the difference between
a hat and a glove. She takes out an item out of the closet only if she is sure that if it is a
glove. How many gloves must she take out to make sure she has a pair of each color?  Answers: A) 36 B) 37 C) 38 D) 39 E) 40

Solution: since it is not given hw many hats so he has hance to take any so 25+7+depends on given answer if 36 is answer round off to 25+7+4= 
25+7+4 = 36
36   36NSWER:36
Answer: A
If x is the sum of six consecutive integers, then x is divisible by which of the following:
I. 3
II. 4
III. 6  Options:
A) I only	B) II only	C) III only	D) I and III	E) I, II, and III

Solution: let the six numbers be k-2, k-1, k, k+1, k+2, k+3   then, there sum will be 6k+3   3(2k+1),which is clearly a multiple of 3. Also, 2k+1 will always be odd. thus the sum will never be divisible by 2.   hence option I only
Answer: A
he average of 5 numbers is zero. Of them, at the most, how many may be greater than zero?
Select the correct option
A) 0 B) 4 C) 10 D) 19 E) 8

Solution: Average of 5 numbers = 0.   Sum of 5 numbers (0 x 5) = 0.   It is quite possible that 4 of these numbers may be positive and if their sum is a the 5th number is (-a).   Answer: Option 10
Answer: C
if a@b = a * b^(1/2) then 3@9 = ?
self made	Choose the correct choice
A) 2  B) 6  C) 3  D) 8  E) 9

Solution: a@b = a * b^(1/2)   3@9 = 3*9^(1/2) = 3*3= 
3*3 = 9
9   Correct Option: 9
Answer: E
If we want to choose out of 6 consonants and 4 vowels, how many words of 3 consonants and 3 vowels can be formed? Select the correct option.
A) 12200	B) 720	C) 9002	D) 57600	E) 12130

Solution: Required selection = select 3 consonants from 6 and 3 vowels frm 4   = 6C3 * 4C3   = 80   As we have to form 6 letter word the above combination of consonants and vowels can be done in 6! = 720 different ways   Required no. of ways = 80 * 720= 
80 * 720 = 57_600
57600   Ans - 57600
Answer: D
A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed
at which the train must run to reduce the time of journey to 40 minutes Choose the correct choice.
A) 50 km/hr B) 60 km/hr C) 65 km/hr D) 70 km/hr E) None of these

Solution: Explanation:   We are having time and speed given, so first we will calculate the distance. Then we can get new speed   for given time and distance.   Lets solve it.   Time = 50/60 hr = 5/6 hr   Speed = 48 mph   Distance = S*T = 48 * 5/6= 
48 * 5/6 = 40
40 km   New Ɵme will be 40 minutes so,   Time= 40/60 hr = 2/3 hr   Now we know,   Speed = Distance/Time   New speed = 40*3/2= 
40*3/2 = 60
60kmph   Answer: 60 km/hr
Answer: B
If A:B=4:7 AND B:C=5:9,THEN A:C=? Choices
A) 28:37	B) 18:37	C) 16:53	D) 20:63	E) 15:48

Solution: A/B=4/7 AN20:63 B/c=5/9   A/B*B/C=4/7*5/9=20/63   SO A/C=20/63   20:63   ANSWER 20:63
Answer: D
A car started running at a speed of 28 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey. Choose the correct choice:  A) 37 km  B) 76 km  C) 25 km  D) 15 km  E) 30 km

Solution: 37 km   37 km   The total distance covered by the car in the first 10 hours = 28 + 30 + 32 + 34 + 36 + 38 + 40 + 42 + 44 + 46 = sum of 10 terms in 37 kmP whose first term is 28 and last term is 46 = 10/2 [28 + 46] = 370 km.
Answer: A
A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 153, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala?
Choose one
A) 22 B) 33 C) 55 D) 27 E) 88

Solution: Let f = pure fuji , g = pure gala and c - cross pollinated.   c = 10% of x where x is total trees.   c = .1x   also 3x/4 = f and c+f = 153 => .1x + 3/4x = 153=> x = 180   180 - 153 = pure gala = 27.   27
Answer: D
Three consecutive odd integers are in increasing order such that the sum of the last two integers is 19 more than the first integer. Find the three integers?	Select the correct option.
A) 7, 9, 29 B) 7, 2, 10 C) 7, 9, 10 D) 7, 9, 11 E) 13,15,17

Solution: Explanation:   Let the three consecutive odd integers be x, x + 2 and x + 4 respectively.   x + 4 + x + 2 = x + 19 => x = 13   Hence three consecutive odd integers are 13, 15 and 17.   Answer:13,15,17
Answer: E
The standard deviation of a normal distribution of data is 2, and 3 standard deviations below the mean is greater than 46. What is a possible value for the mean of the distribution?
Choose the correct choice:
A) 46
B) 52
C) 48
D) 49
E) 50

Solution: The standard deviation ({SD}) = 2;   3 standard deviations below the mean is greater than 46:   {Mean} - 3*{SD} > 46;   {Mean} - 6 > 46;   {Mean} > 52.   Answer: 52.
Answer: B
Health insurance Plan P requires the insured person to pay $500 but then the insurance pays 80% of the cost over $500. Plan Q requires the insured to pay the initial $300, but then pays 60% of the cost over $300. Which of the following is a cost level for which both insurance plans pay out the same amount? Choose the correct choice from the following answers:  A) $1100  B) $1600  C) $2200  D) $2800  E) $3300

Solution: 0.8(x-500)=0.6(x-300)   0.2x=400-180   x=1100   The answer is $1100.
Answer: A
The contents of a certain box consist of 14 apples and 25 oranges. How many oranges must be removed from the box so that 70 percent of the pieces of fruit in the box will be apples? Choose one
A) 3	B) 6	C) 14	D) 19	E) 20

Solution: The objective here is that 70% of the fruit in the box should be apples.   Now, there are 14 apples at start and there is no talk of removing any apples, so number of apples should remain 14 and they should constitute 70% of total fruit, so total fruit = 14/0.7= 
14/0.7 = 20
20   So we should have 20-14= 
20-14 = 6
6 oranges.   Right now, there are 25 oranges, so to get to 6 oranges, we should remove 25 - 6= 
25 - 6 = 19
19 oranges.   Answer 19
Answer: D
Working together, printer A and printer B would finish the task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 6 pages a minute more than printer A ?  Select the correct option:	A) 600	B) 800	C) 1000	D) 720	E) 1500

Solution: Answer: 720.
Answer: D
The sector of a circle has radius of 20 cm and central angle 135o. Find its perimeter?	Pick
A) 91.5  B) 87.1  C) 91.7  D) 91.3  E) 91.1

Solution: Perimeter of the sector = length of the arc + 2(radius)   = (135/360 * 2 * 22/7 * 20) + 2(20)   = 47.1 + 40= 
47.1 + 40 = 87.1
87.1 cm   Answer:87.1
Answer: B
If books bought at prices ranging from Rs. 250 to Rs. 350 are sold at prices ranging from Rs. 300 to Rs. 425, what is the greatest possible profit that might be made in selling eight books ? Choose one
A) 23267
B) 1400
C) 1800
D) 2778
E) 76611

Solution: Explanation:   Least Cost Price = Rs. (250 * 8) = Rs. 2000.   Greatest Selling Price = Rs. (425 * 8) = Rs. 3400.   Required profit = Rs. (3400 - 2000) = Rs. 1400.   Answer: 1400) 1400
Answer: B
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 12% per annum then the gain of B in a period of 3 years is?  Choose the correct choice from the following answers.
A) 200 B) 210 C) 220 D) 225 E) 230

Solution: (3500*2*3)/100= 
(3500*2*3)/100 = 210
> 210   Answer: 210
Answer: B
Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages	Options:
A) 35
B) 34
C) 45
D) 25
E) 65

Solution: Explanation:   Let the present age of P and Q be 3x and 4x respectively.   Ten years ago, P was half of Q in age   => 2(3x – 10) = (4x – 10)   => 6x – 20 = 4x – 10   => 2x = 10   => x = 5   Option 35
Answer: A
There are 40 doors marked with numbers 1 to 40. And there are 40 individuals marked 1 to 40.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All doors are closed to start with.
Now one at a time one randomly picked individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For e.g. individual marked with number 5 operates the doors marked with the following numbers: 5, 10, 15,... and 40.
If every individual in the group get one turn then how many doors are open at the end?
Choose the correct choice from the following answers.
A) 0  B) 1  C) 2  D) 4  E) 6

Solution: Let us start with 1.   When 1 goes, all the doors are open since every number is a multiple of 1.   Also 1 will remain opened since 1 is not a multiple of any number.   Prime numbers can only be operated by people with prime numbers.   So 2,3,5,7,11,13,17,19,23,29,31,37 will be closed when people with respective numbers perform operations on them.   Our numbers left are 4,6,8,9,10,12,14,15,16,18,20,21,22,24,...28 and   From these numbers, only those numbers will remain opened on which even number of operations are performed including the operation performed by number 1.   This is possible only for perfect squares which are 4,9,16,25 and 36.   So our numbers are 1,4,9, 16,25 and 36.   Answer:- 6
Answer: E
A positive integer n is a perfect number provided that the sum of all the positive factors of n, including 1 and n, is equal to 2n. What is the sum of the reciprocals of all the positive factors of the perfect number 28?	Choose the correct choice from the following.
A) 1/4 B) 56/27 C) 2 D) 3 E) 4

Solution: Soln:   28 = 1*28   2*14   4*7   sum of reciprocals = 1+1/28+1/2+1/14+1/4+1/7=56/28= 
56/28 = 2
2   ANSWER:2
Answer: C
what is the least number. which should be added to 0.0282 to make it a perfect square?  Select: A) 0.0007 B) 0.0042 C) 0.0002 D) 0.0003 E) 0.0004

Solution: 0.0282+0.0007= 
0.0282+0.0007 = 0.0289
0.0289   (0.17)^2   0.0007NSWER:0.0007
Answer: A
Given that 2x + 17 > 5 and 5x - 13 < 7, all values of x must be between which of the following pairs of integers? Choices.
A) -4 and -1 B) -1 and 4 C) -4 and 1 D) -6 and 4 E) 2 and 5

Solution: 2x + 17 > 5   i.e 2x >5-17   i.e. 2x > -12   i.e. x > -6   Also, 5x - 13 < 7   i.e. 5x <7+13   i.e 5x < 20   i.e x < 4   i.e. -6 < x < 4   Answer: Option -6 and 4
Answer: D
For the positive numbers, n, n + 2, n + 4, n + 6, and n + 8, the mean is how much greater than the median?	Select:
A) n+l B) 1 C) 0 D) n+2 E) n+3

Solution: Let’s first calculate the mean (arithmetic average).   mean = sum/quantity   mean = (n + n + 2 + n + 4 + n + 6 + n + 8)/5   mean = (5n + 20)/5   mean = n + 4   Next, we determine the median. The median is the middle value when the terms are ordered from least to greatest. The terms ordered from least to greatest are as follows:   n, n + 2, n + 4, n + 6, n + 8   The median is n + 4.   Finally we are asked how much greater the mean is than the median. To determine the difference we can subtract the smaller value (the median) from the larger value (the mean) and we get:   n + 4 – (n + 4) = n + 4 – n – 4 = 0   The answer is 0
Answer: C
if 7v passes to that wire and a current of 260mA then find the resistance Options
A) 26.9  B) 27.9  C) 28.9  D) 29.9  E) 30.9

Solution: V=IR   => R=V/I = 7 V / 260 m26.9 = 7 V / 260*10^(-3) 26.9 = 26.92 ohm   26.9NSWER:26.9
Answer: A
Every digit of a number written in binary is either 0 or 1. To translate a number from binary, multiply the nth digit (reading from right to left) by 2^(n-1)
What is the largest prime number (written in binary) that is a factor of both 100010000 and 1000100000 ?  Choose the correct answer:
A) 10
B) 11
C) 101
D) 1011
E) 10001

Solution: Starting from right count the positions of 1 s   100010000=(1*2^8) + (1*2^4)=(2^8 + 2^4)   similarly,   1000100000=(1*2^9)+(1*2^5)=(2^9 + 2^5)   Lets simplify them further,   (2^8 + 2^4)=2^4(2^4 +1)=2^4(16+1)=2^4(17)   (2^9 + 2^5)=2^5(2^4 +1)=2^5(16+1)=2^5(17)   The prime numbers common in both are 2 and 17, and the largest one is 17.   from the options, (10001) 10001=1*2^4+1*2^0=16+1= 
16+1 = 17
17   Hence answer (10001).
Answer: E
An urn contains 5 red, 6 blue and 8 green balls. 4 balls are randomly selected from the urn, find the probability that the drawn ball are 1 blue and 2 red and 1 green balls ?
Answers: A) 20/323 B) 40/323 C) 60/273 D) 50/373 E) 40/373

Solution: Sample space = no. of ways 4 balls were drawn from urn = 19C4 = 3876   No. ways 1 blue and 2 red and 1 green balls were drawn from bag = 6C1 * 5C2 * 8C1 = 480   Probability = 480 / 3876 = 40/323   Ans - 40/323
Answer: B
In a garden, trees are planted in rows. In each row there are as many trees as the number of rows in the garden. If the total number of trees in that garden is n, then :
Choices
A) n is a perfect square B) n is an odd number C) n is an even number D) n is a perfect cube. E) none

Solution: If there are, for example, 4 rows of trees, each row would have 4 trees. The total would be   4*4= 
  4*4 = 16
16, which is a perfect square.   n is a perfect squarenswer: n is a perfect square
Answer: A
A glucose molecule contains 6 carbon, 12 hydrogen and 6 oxygen atoms. During photosynthesis, green plants create glucose daily. If, over a period of 15 days, an eucalyptus plant (a green plant) creates 15,000 molecules of glucose then approximately how many more atoms of hydrogen than carbon are created on average per day?
Choose the correct choice:	A) 60,000	B) 6,000	C) 2,500	D) 250	E) 0

Solution: Solution:   We know that 15,000 glucose molecules are created over a period of 15 days. Therefore 15,000/15 = 1,000 glucose molecules are created on average per day.   Each glucose molecule contains 6 carbon atoms and 12 hydrogen atoms. So 1,000 glucose molecules contain 6 × 1,000 = 6,000 carbon atoms and 12 × 1,000 = 12,000 hydrogen atoms. The difference is 12,000 – 6,000 = 6,000.   The correct answer is 6,000.
Answer: B