MU-NLPC/Calc-aqua_rat huggingface dataset:
The proportion of water to alcohol in Solution A is 4:1 and the proportion of water to alcohol in Solution B is 3:1. If an equal amount of each solution is mixed together, what is the concentration of alcohol in the new solution? Pick one
A) 16.5%	B) 18.5%	C) 20.5%	D) 22.5%	E) 24.5%

Solution: Let V be the total volume of the new solution.   Then a volume of V/2 was added from each solution A and B.   The amount of alcohol added to the new solution was:   (1/5)(V/2)+(1/4)(V/2)=V/10+V/8=9V/40.   The concentration of alcohol is 9/40=22.5%   The answer is 22.5%.
Answer: D
A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price? Options.
A) 62% B) 42% C) 12% D) 22% E) 82%

Solution: Explanation:   Original price = 100   12%P = 80   S = 80*(140/100)= 
80*(140/100) = 112
112   100 - 112= 12%   Answer: 12%
Answer: C
In a partnership, A invests 1⁄6 of the capital for 1⁄6 of the time, B invests 1⁄3 of the capital for 1⁄3 of the time and C, the rest of the capital for whole time. Find A’s share of the total profit of 2,300. Choose the correct choice from the following:  A) 100  B) 200  C) 300  D) 400  E) None of these

Solution: Remaining capital = 1 - (1⁄6 + 1⁄3) = 1⁄2   Ratio of their profit   = 1⁄6 × [1⁄6 × 12] : 1⁄3 × [1⁄3 × 12] : 1⁄2 × 12   = 1⁄3 : 4⁄3 : 6 = 1 : 4 : 18   ∴ 100's share = 1 /1+4+18×2300 = 100   100nswer 100
Answer: A
A and B can do a piece of work in 10 days and 10 days respectively. They work together for 10 days and B leaves. In how many days the whole work is completed? Choose the correct answer:
A) 30days B) 40days C) 50days D) 60days E) 70days

Solution: Explanation:   (30days+B)’s 10 days work = 10[1/10+1/10]=10[1+1/10]= 2   30days complete remaining work in   2*10= 
  2*10 = 20
20   Total work= 10+20= 
10+20 = 30
30days   30daysnswer: Option 30days
Answer: A
A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 40% more recliners. What is the percentage increase of the gross?	Answers:
A) 10% B) 15% C) 11.2% D) 7% E) 13%

Solution: Say a recliner is actually worth $100   If she sells 100 recliners then she earns $10000   After the discount of 20%, she will earn $80 per recliner and she sells 40% more ie.,140 recliners   Hence her sales tields 140*80= 
140*80 = 11_200
$11200   Increase in sales=11200-10000=$1120   So% increase = 1120*100/10000= 
1120*100/10000 = 56/5 = around 11.2
11.20%   11.2% is the answer
Answer: C
In a class, the number of girls is 20% more than that of the boys. The strength of the class is 66. If 4 more girls are admitted to the class, the ratio of the number of boys to that of the girls is
Choose the correct choice from the following answers:
A) 1:2
B) 3:4
C) 1:4
D) 3:5
E) None

Solution: Solution: Girls:boys = 6:5;   Hence, girls = 6*66/11= 
6*66/11 = 36
36;   Boys= 30;   New ratio, 30:(36+4) = 3:4.   Answer: Option 3:4
Answer: B
A batsman scored 150 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?	Answers
A) 50% B) 40% C) 60% D) 70% E) 80%

Solution: Number of runs made by running = 150 - (3 x 4 + 8 x 6)   = 150 - (60)= 
150 - (60) = 90
90   Now, we need to calculate 90 is what percent of 150.=> 90/150 x 100 = 60 %   ANSWER:60%
Answer: C
(1.00003)(0.99997) - (1.00002)(0.99998) =  Choose the correct option.
A) 0
B) -5(10^-10)
C) 3(10^-10)
D) 10^-5
E) 3(10^-5)

Solution: (1.00003*0.99997)-(1.00002*0.99998)   = (1+0.00003)(1-0.00003) - (1+0.00002)(1-0.00002)   = 1 - (0.00003)^2 - 1 + (0.00002)^2   = -(0.0000000009) + (0.0000000004)   = - 0.0000000005= -5(10^-10)   Answer -5(10^-10)
Answer: B
The student manager of the university theater estimated that for every 6 movie tickets sold on Valentine's Weekend, the theater will sell 3 packs of grain crackers at $2.25 each, 4 bottles of a beverage at $1.50 each, and 4 chocolate bars at $1.00 each. Find the approximate average (arithmetic mean) amount of estimated snack sales per movie ticket sold. Select.
A) $1.40 B) $1.58 C) $2.00 D) $2.64 E) $2.79

Solution: 3*2.25 + 4 *1.50+ 4 * 1 = 6.75+6+4 = 16.75.   This is the sale for 6 tickets   Avg sale per ticket: 16.75/6 = $2. 79   Answer : $2.79
Answer: E
A deck of 9 cards contains 2 red cards, 3 blue cards, and 4 green cards. 3 cards are randomly drawn with replacement from the deck. What is the probability that all three cards are the same color?  Choose one.
A) 11/81	B) 64/729	C) 5/7	D) 27/729	E) 2/5

Solution: Note that cards are drawn with replacement. So every time we draw from 9 cards and it's possible to draw 3 red cards, 3 blue cards or 3 green cards:   P=(2/9)3+(3/9)3+(4/9)3=11/81   11/81nswer: 11/81.
Answer: A
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:  Choose one:
A) 278
B) 288
C) 298
D) 308
E) 318

Solution: Other numberOther number =(11x7700)/275 =308   answer :308
Answer: D
The compound ratio of 1:3, 3:2 and 4:5? Choices
A) 1:9	B) 1:7	C) 1:2	D) 2:5	E) 1:4

Solution: 1/3 * 3/2 * 4/5   = 2/5   =2:5   Answer: 2:5
Answer: D
How many numbers are divisible by both 2 and 3 up to 300? Pick:  A) 50  B) 100  C) 150  D) 200  E) 250

Solution: Divide 300 by 6, as the numbers which are divisible by both 2 and 3 are also divisible by 6.   The quotient obtained after dividing 300 by 6 is 50, hence answer is 50.   Option 50
Answer: A
Find the least number must be subtracted from 427398 so that remaining no.is divisible by 15?	Choose the correct option.
A) 3	B) 5	C) 6	D) 9	E) 8

Solution: On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted   3
Answer: A
what is the product of first three whole no.
Answers.
A) 0
B) 1
C) 6
D) 2
E) 3

Solution: first three whole no. are 0,1,2.   remember whole no. start from 0 and natural no. from 1   so product will 0 only.   answer 0
Answer: A
The result when a number subtracted from 150 is the same as the number added to 68. what is the number?
Choices:
A) 110 B) 100 C) 109 D) 218 E) 210

Solution: Answer   Let the number be x.   Then, x - 68= 150- x   â‡’ 2x = 150+ 68= 
150+ 68 = 218
218   â‡’ 2x= 218   âˆ´ x = 109   109orrect Option: 109
Answer: C
The ratio of the incomes of Chetan and Dinesh is 3:4. The ratio of their expenditures is 5:7. If each of them saves Rs.200, find the incomes of both? Choose the correct choice from the following answers:	A) 1600	B) 2888	C) 2662	D) 9222	E) 7122

Solution: The savings of Chetan and Dinesh are 3x - 5y and 4x - 7y respectively.   3x - 5y = 200 --- (1)   4x - 7y = 200 --- (2)   Multiplying (1) by 7 and (2) by 5 and subtracting the resultant equation (2) from resultant equation (1), we get x = 400.   The incomes of Chetan and Dinesh are 3x = Rs.1200 and 4x = Rs.1600 respectively.   1600nswer: 1600
Answer: A
A sum of Rs.2200 has been divided among A, B and C such that A gets 1/4 of what B gets and B gets 1/5 of what C gets. What is B's share?	Pick:	A) Rs. 341	B) Rs. 364	C) Rs. 372	D) Rs. 352	E) Rs. 354

Solution: Let C's share =x   Then B's share =x/5   A's share =(x/5)×1/4=x/20   x+(x/5)+(x/20)=2200   ⇒x(1+(1/5)+(1/20))=2200   ⇒x(25/20)=2200   ⇒x(5/4)=2200   ⇒x/4=440   ⇒x=1760   B's share=x/5=1760/5= 
1760/5 = 352
352   Answer: Rs. 352
Answer: D
P can do the work in 10 days and Q can do the same work in 15 days. If they work together for 4 days, what is the fraction of work that is left?
Choose the correct choice from the following answers:	A) 1/5	B) 1/4	C) 1/3	D) 2/5	E) 2/3

Solution: 4/10 + 4/15 = 20/30 = 2/3 (completed work)   The work that is left is 1 - 2/3 = 1/3   The answer is 1/3.
Answer: C
On his first 3 tests, Rajeev received an average score of X points. If on his fourth test, he exceeds his previous average score by 24 points, what is his average score for his first 4 tests? Choose the correct choice from the following choices.
A) X  B) X+6  C) X+4  D) X+3  E) X+2

Solution: Total of 1st 3 tests= 3X   4th test score = X + 24   Total of all 4 tests = 4X + 24   Average = X + 6   Answer : X+6
Answer: B
Find the value of (1/(2*3))+(1/(3*4))+(1/(4*5))+(1/(5*6))+…..+ ((1/(9*10)). Select:
A) 1/5 B) 2/5 C) 4/5 D) 3/5 E) None of them

Solution: Given expression=((1/2)-(1/3))+((1/3)-(1/4))+((1/4)-(1/5))+   ((1/5)-(1/6))+….+ ((1/9)-(1/10))   =((1/2)-(1/10))=4/10 = 2/5.   Answer is 2/5.
Answer: B
If 314,314 football shoes need to be placed in boxes and each box can contain at most 6 pair of football shoes. How many pair of football shoes will be in the last unfilled box?
Options:
Pick.
A) 1football shoes
B) 3 football shoes
C) 4 football shoes
D) 7 football shoes
E) 9 football shoes

Solution: The number of football shoes that can be placed in boxes of 6 football shoes is the first number that is divisible by 6 that occurs before 314,314.   In order to divide the sum in 6 parts, the amount must be divisible by 6   Divisibility rule of 6: The sum of the digits must be divisible by 6   Sum of digits of 314,314 = 16 and 6 is divisible by 6.   Hence, we need to remove 4 to this number for it to be divisible by 6   4 football shoesorrect Option: c
Answer: C
A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 % gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain, he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse and Rs.________ for the cart.  Choose the correct choice:
A) Cost price of horse = Rs. 230 & the cost price of cart = 900.  B) Cost price of horse = Rs. 900 & the cost price of cart = 700.  C) Cost price of horse = Rs. 400 & the cost price of cart = 200.  D) Cost price of horse = Rs. 300 & the cost price of cart = 800.  E) Cost price of horse = Rs. 800 & the cost price of cart = 800.

Solution: Let x be the cost price of the horse and y be the cost price of the cart.   In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the gain.   Therefore (10/100) * x = (20/100) * y   X = 2 * y -----------------(1)   In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by Rs. 10.   Therefore (5 / 100) * x = (5 / 100) * y + 10 -------(2)   Substituting (1) in (2) we get   (10 / 100) * y = (5 / 100) * y + 10   (5 / 100) * y = 10   y = 200   From (1) 2 * 200 = x = 400   Answer:Cost price of horse = Rs. 400 & the cost price of cart = 200.
Answer: C
The average age of the district level hockey team of eleven is 22 years.The average age gets increased by 3 years when the coach age is also included.what is the age of the coach ?  Choose the correct choice.
A) 45 yrs.	B) 53 yrs.	C) 58 yrs.	D) 48 yrs.	E) 55 yrs.

Solution: Explanation:   Total age of players in team = 22 x 11 = 242   When coach is included, total members = 12, Avg age decreses by one becomes 25   Total age when coach is included = 25x12 = 300   Age of coach = 300-242= 
300-242 = 58
58 yrs.   Answer: 58 yrs.
Answer: C
When anunfaircoin is tossed twice, the probability of getting one tails and one heads is 1/2. What is the probability of getting two heads and two tails if the coin is tossed 4 times? Choose the correct choice
A) 2/3
B) 1/3
C) 1/4
D) 1/6
E) 1/9

Solution: Let the probability of heads be x and the probability of tails be 1-x.   So, we are given that P(one tails and one heads) = 2*x*(1-x) = 1/2.   P(two heads and two tails) = 4!/(2!2!)*x^2*(1-x)^2 = 6*(x*(1-x))^2. We are multiplying by 4!/(2!2!) because HHTT scenario can occur in several ways: HHTT, HTHT, THHT, ... (permutation of 4 letters HHTT where 2 T's and 2 H's are the same).   Since from 2*x*(1-x) = 1/2 it follows that x*(1-x) = 1/4, then 4*(x*(1-x))^2 = 4*(1/6)^2 = 1/9.   Answer: 1/9.
Answer: E
If 1000 microns = 1 decimeter, and 1,000,000angstroms = 1 decimeter, how many angstroms equal 1 micron? Pick one: A) 10 B) 1000 C) 100 D) 0.01 E) 0.0001

Solution: 1000 microns = 1 decimeter, and 1,000,000angstroms = 1 decimeter   1000 microns = 1,000,000angstroms   1 micron = 1,000,000/1,000 = 1,000   Answer : 1000
Answer: B
How many positive integers less than 50 have a reminder 01 when divided by 4?  Options:
A) 13
B) 14
C) 15
D) 16
E) 17

Solution: 1 also gives the remainder of 1 when divided by 4. So, there are total of 13 numbers.   13nswer: 13.
Answer: A
A factory has a fixed cost of $50,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?	Answers:
A) 9,000	B) 14,000	C) 18,000	D) 20,000	E) 27,000

Solution: selling price - Cost price = 2.5 so per unit profit =2.5   cost to recover =50000   no of items required = 50000/2.5= 
50000/2.5 = 20_000
20000   Ans 20,000
Answer: D
Three 7 faced dice are thrown together. The probability that all the three show the same number on them is ?
Select the correct option.
A) 1/38  B) 1/49  C) 1/39  D) 1/42  E) 1/29

Solution: It all 3 numbers have to be same basically we want triplets. 111, 222, 333, 444, 555, 666 and 777. Those are seven in number. Further the three dice can fall in 7 * 7* 7= 
7 * 7* 7 = 343
343 ways.   Hence the probability is 7/343= 1/49   Answer:1/49
Answer: B
A garrison of 400 men had a provision for 31 days. After 25 days 320 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?  Choose one:
A) 65 days	B) 30 days	C) 10 days	D) 16 days	E) 18 days

Solution: 400 --- 31   400 --- 6   80 --- ?   400*6 = 80*x => x =30 days.   Answer: 30 days
Answer: B
A and B are in a relay race. A runs the first leg of the course in 42 seconds. B runs the second leg of the course in 19 seconds. What was the average time they took to run a leg of the course?	Choose the correct choice from the following choices
A) 26.5
B) 27.5
C) 28.5
D) 29.5
E) 30.5

Solution: (42 seconds +19 seconds)/2= 30.5 seconds   Correct option is: 30.5
Answer: E
How many positive integers less than 260 are multiple of 4 but NOT multiples of 6?
Choose the correct choice from the following answers.
A) 20	B) 31	C) 45	D) 53	E) 64

Solution: 260/4= 
260/4 = 65
65   Multiples of 4 which are a multiple of 6 will be of the form 2*2*3= 
2*2*3 = 12
12n where n>0   240/12= 
240/12 = 20
20   65-20= 
65-20 = 45
45   Answer: 45
Answer: C
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 19 inches than that of a rectangular sheet of paper measuring 9.5 inches by 11 inches? Choose the correct choice from the following choices:
A) 50% B) 87% C) 100% D) 187% E) 200%

Solution: Let's just look at the dimensions (no calculation needed).   With dimension 11 the same, the other dimension 19 is twice 9.5   Then the area will be double which means 100% greater.   The answer is 100%.
Answer: C
n^(n/2)=2 is true when n=2 in the same way what is the value of n if n^(n/2) =4?
Choose the correct choice from the following choices
A) 2
B) 3
C) 4
D) 5
E) 6

Solution: n^(n/2)=4   Apply log   N/2logn=log4   nlogn=2log4=log4^2=log16   Logn=log16   Now apply antilog   n=16/n   Now n=4.   ANSWER:4
Answer: C
A man sold an article offering a discount of 5% and earned a profit of 23.5%. What would have been the percentage of profit earned if no discount was offered?	Choose the correct choice from the following answers
A) 20%  B) 35%  C) 30%  D) 37%  E) 39%

Solution: C   30%   Let C.P. be $100.   Then, S.P. = $123.50   Let marked price be $x. Then, 95/100 x = 123.50   x = 12350/95= 
12350/95 = 130
$130   Now, S.P.= $130, C.P. = $100   Profit % = 30%.
Answer: C
The average of 11numbers is 60. Out of 11numbers the average of first 6no. is 58, and last 6numbers is 65 then find 6th number?	Choices:
A) 78	B) 65	C) 58	D) 62	E) 48

Solution: 6th number = sum of 1st 6no.s + sum of last 6no.s - sum of 11no.s   answer = 6*58+6*65-11*60= 
6*58+6*65-11*60 = 78
78   78nswer is 78
Answer: A
John was 22 years old when he married Betty. They just celebrated their fifth wedding anniversary, and Betty's age is now 7/9 of John's. How old is Betty?	Choose the correct option
A) 24 B) 26 C) 28 D) 21 E) 32

Solution: Assume Betty's age on marriage = x years.   John's age on marriage = 22   John's age after 5 years = 27 years.   Betty's age after 5 years = x + 5   Given: x + 5 = 7/9 (27) = 21   Therefore Betty's current age = 21   Option 21
Answer: D
If a particular is never chosen, in how many ways can a cricketbe chosen out of 15 players? Select
A) 245	B) 250	C) 364	D) 389	E) 398

Solution: A particular players is never chosen, it means that 11 players are selected out of 14 players.   => Required number of ways = 1436411   = 14!/11!x3! = 364   364
Answer: C
A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 110 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?  Choose the correct choice from the following choices: A) 19 sec B) 87 sec C) 36 sec D) 16 sec E) 35 sec

Solution: Speed of train relative to jogger = 45 - 9= 
45 - 9 = 36
36 km/hr.= 36 * 5/18= 
36 * 5/18 = 10
10 m/sec.   Distance to be covered= 240 + 110= 
240 + 110 = 350
350 m.   Time taken= 350/10= 
350/10 = 35
35 sec.   Answer: 35 sec
Answer: E
Two passenger trains start at the same hour in the day from two different stations and move towards each other at the rate of 28 kmph and 21 kmph respectively. When they meet, it is found that one train has traveled 60 km more than the other one. The distance between the two stations is?  Choose the correct choice from the following
A) 457 km B) 444 km C) 547 km D) 588 km E) 653 km

Solution: 1h ----- 5   ? ------ 60   12 h   RS = 28 + 21= 
28 + 21 = 49
49   T= 12   588 km = 49 * 12= 
49 * 12 = 588
588   Answer:588 km
Answer: D
Stock / Number of shares
V ------------ 68
W ---------- 112
X ------------ 56
Y ------------ 94
Z ------------ 45
The table shows the number of shares of each of the 5 stocks owned by Mr Sami. If Mr. Sami was to sell 20 shares of Stock X and buy 26 shares of stock Y, what would be the increase in the range of the numbers of shares of the 5 stocks owned by Mr. Sami?
Choose the correct choice from the following answers:	A) 4	B) 6	C) 9	D) 17	E) 20

Solution: Based on the original number of shares, the range would be: 112 - 45= 
112 - 45 = 67
67   However, the prompt tells us that two of the values in the table are going to change. After the changes, the values will be:   V 68   W 112   X 36   Y 120   Z 45   Now the range is   120 - 36= 
  120 - 36 = 84
84   The INCREASE in the range requires us to compare thenewrange to theoldrange:   84 - 67= 
  84 - 67 = 17
17   17
Answer: D
If n is a positive integer and the product of all the integers from 1 to n, inclusive, is a multiple of 1000, what is the least possible value of n? Choose the correct choice from the following.
A) 12  B) 11  C) 14  D) 13  E) 15

Solution: 1000 = 2*2*2*5*5*5, so we need 3 factors of 2 and 3 factors of 5. Therefore, the smallest value of n is 15, so the answer is 15.
Answer: E
Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $500 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $555 as interest. What was the value of his total savings before investing in these two bonds? Choose the correct choice.
A) 2,000	B) 2,500	C) 4,000	D) 5,000	E) 6,000

Solution: So, we know that Shawn received 20% of the amount he invested in a year. We also know that in one year Shawn received $250, thus 0.2x = $250 --> x = $1,250.   Since, he invested equal sums in his 2 bonds, then his total savings before investing was 2*$1,250 = $2,500.   Answer:2,500
Answer: B
IF GO=32& SHE=49 the SOME will be equal to?
Choose the correct option.
A) 56 B) 58 C) 62 D) 64 E) 66

Solution: If we count letters till the end of the alphabet including that letter in reverse order then   G = 20 and O = 12 totaling 32   S = 8, H = 19 and E = 22 totaling 49   So   SOME = 8 + 12 + 14 + 22= 
8 + 12 + 14 + 22 = 56
56   56NSWER:56
Answer: A
If the positive integer y is divisible by 4, 8, and 12, then which of the following must y be divisible by?
I. 24
II. 36
III. 48  Pick
A) III only
B) II only
C) I only
D) II and III only
E) I, II, and III

Solution: Answer = I only   LI onlyM of 4, 8, 12 = 24   Answer = 24   Answer: I only
Answer: C
Of the books standing in a row on a shelf, an atlas is the 30th book from the left and the 33rd book from the right. If 3 books to the left of the atlas and 4 books to the right of the atlas are removed from the shelf, how many books will be left on the shelf?
Options
A) 55	B) 57	C) 58	D) 61	E) 63

Solution: 100%. There are total of   30+33-1= 
  30+33-1 = 62
62 books and   3+4= 
  3+4 = 7
7 books are removed, thus 62-7= 
62-7 = 55
55 books are left.   55nswer: 55.
Answer: A
John, James and Jim' investment ratio in a business is 4:7:9. If total total investment is 80000. Find Jim's investment?	Select: A) 35000 B) 40000 C) 16000 D) 36000 E) 60000

Solution: let the investment of John James and Jim is 4x 7x and 9x   4x+7x+9x = 80000   20x = 80000   x = 4000   Jim' investment = 9*4000= 
9*4000 = 36_000
36000   Answer : 36000
Answer: D
clay brought 4 chocolates for 4 guests. 1 of the guest arrive early and eat 3 chocolates each. How many chocolates are left over if the other guests all have the same number of chocolates? Select the correct option:
A) 0 B) 1 C) 6 D) 5 E) 2

Solution: clay made 4*4= 
4*4 = 16
16 chocolates. 1 guests eat 2 chocolates, leaving 13 remaining for 3 guests.   1+3= 
1+3 = 4
4.   4 is not divisible by 3. The 3 guests ate a cumulative number of chocolates divisible by 3, because the number is the same.   13-12= 
13-12 = 1
1.   1 is the correct answer
Answer: B
If the selling price is trippled,the profit is quadrupled, what is the percentage of profit??	Pick one:
A) 50%
B) 100%
C) 150%
D) 200%
E) 250%

Solution: we can make two equations from the given info..   let selling price be S and cost price be C..   so profit=P=S-C...   if S is doubled profit is tripled..   so 4P=3S-C..   or S=3P...   therefore C=P..   % of profit=P/P=100%   100%
Answer: B
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:	Choose the correct choice:  A) 20 days  B) 22 1/2 days  C) 25 days  D) 30 days  E) 40 days

Solution: Ratio of times taken by A and B = 1 : 3.   The time difference is (3 - 1) 2 days while B take 3 days and A takes 1 day.   If difference of time is 2 days, B takes 3 days.   If difference of time is 60 days, B takes = 3/2 x 60 = 90 days.   So, A takes 30 days to do the work.   A’s 1 day’s work = 1/30   B’s 1 day’s work = 1/90   A’s and B’s one day work = 1/30 + 1/90 = 2/45.   Therefore, A and B together can do the work in = 45/2 = 22 1/2 days.   ANSWER:22 1/2 days
Answer: B
Two cars cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower car takes 1 hour more than the faster car  Pick one.
A) 960 km B) 968 km C) 960 km D) 980 km E) 964 km

Solution: 60(x + 1) = 64x   X = 15   60 * 16= 
60 * 16 = 960
960 km   Answer: 960 km
Answer: C
4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 6 mat-weavers in 6 days?
Choose the correct option
A) 25
B) 9
C) 39
D) 61
E) 16

Solution: Let the required number of bottles be x.   More weavers, More mats (Direct Proportion)   More days, More mats (Direct Proportion)   Wavers	4	:	6 :: 4 : x   Days	4:6   4 * 4 * x = 6 * 6 * 4   x =	(6 * 6 * 4)/(4 x 4)   x = 9.   Answer is 9.
Answer: B