MU-NLPC/Calc-aqua_rat huggingface dataset:
In western Europe, q bicycles were sold in each of the years 1990 and 1993. The bicycle producers of Western Europe had a 42 percent share of this market in 1990 and a 33 percent share in 1993. Which of the following represents the decrease in the annual number of bicycles produced and sold in Western Europe from 1990 to 1993?  Choices:
A) 9% of (x/100)
B) 14% of (x/100)
C) 75% of (x/100)
D) 9% of q
E) 14% of x

Solution: Moreover is't question actually asking the the difference between the {(Quantity Produced + Quantity Sold ) q in 1990 - (Quantity Produced + Quantity Sold ) in 1993}   Though the Quantity sold in both the years is same it actually boils down to (Quantity Produced in 1990 ) in (Quantity Produced in 1993)=9% of q
Answer: D
In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 300 more than the correct answer. Find the number.
Choose the correct choice from the following answers
A) 125  B) 280  C) 384  D) 400  E) 576

Solution: Explanation:   Let the number be x.   5*x/6 = 5*x/16 + 300   25*x/48 = 300   x = 576   ANSW576R 576
Answer: E
The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 8 years hence?
Choose the correct option:
A) 50	B) 60	C) 70	D) 76	E) 90

Solution: A + B = 60, A = 2B   2B + B = 60 => B = 20 then A = 40.   5 years, their ages will be 48 and 28.   Sum of their ages = 48 + 28= 
48 + 28 = 76
76.   ANSWER:76
Answer: D
Find the length of a rope by which a cow must be tethered in order that it may be able to graze an area of 2244 sq. metres. Pick: A) 25.4 B) 26.7 C) 24.3 D) 22.5 E) None of these

Solution: Explanation:   Clearly, the cow will graze a circular field of area 2244 sq. metres and radius   equal to the length of the rope.   Let the length of the rope be R metres.   Then, Π(R)2= 2244 => R2 = (2244 X (7/22)) = 714=> R = 26.72   Length of the rope = 26.72 m.   Answer: Option 26.7
Answer: B
In what time will a railway train 65 m long moving at the rate of 32 kmph pass a telegraph post on its way? Select.
A) 3 sec  B) 4 sec  C) 5 sec  D) 6 sec  E) 7 sec

Solution: T = 65/32 * 18/5 = 7 sec   ANSW7 secR:7 sec
Answer: E
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.  Choose the correct option
A) 4 B) 7 C) 9 D) 13 E) 8

Solution: Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)   = H.C.F. of 48, 92 and 140 = 4.   4nswer is 4
Answer: A
difference between LCM and HCF of
following number 20 30 40?
Choose the correct choice.
A) 140  B) 130  C) 100  D) 110  E) 120

Solution: LCM of 20, 30, 40 is 120   HCF of 20, 30, 40 is 10   110ifference is  120 - 10= 
 120 - 10 = 110
110   ANSWER:110
Answer: D
Carrey rented a car for Rs.20 plus Rs.0.25 per kilometer driven. Samuel rented a car for Rs.24 plus Rs.0.16 per kilometer driven. If each drove d km. and each was charged exactly the same amount for the rental, then d equals ? Answers.
A) 44.4
B) 44.8
C) 1
D) 19
E) 44.11

Solution: Explanation:   20 + 0.25 × d = 24 + 0.16d   Solving we get d = 44.4   44.4nswer:44.4
Answer: A
Three unbiased coins are tossed. What is the probability of getting 3 heads and 1 Tail? Choose the correct choice.
A) 3/4	B) 1/4	C) 3/8	D) 1/2	E) 1/8

Solution: Let, H --> Head , T --> Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting 3 heads   Then E = {HHH,HTH,THH,HHT}   P(E) = n(E)/n(S) =4/8 = 1/2   Answer is 1/2
Answer: D
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:  Choose the correct choice from the following choices
A) 9
B) 9.6
C) 10
D) 10.8
E) 7

Solution: Explanation:   Relative speed = (60 + 40) km/hr =[ 100 x ( 5 / 18 ) ]m/sec = ( 250 /9 ) m/sec.   Distance covered in crossing each other = (140 + 160)= 
(140 + 160) = 300
300 m.   Required time= [ 300 x ( 9/250 ) ] sec = ( 54/ 5 )= 
( 54/ 5 ) = 54/5 = around 10.8
10.8 sec. Answer: 10.8
Answer: D
An eccentric casino owner decides that his casino should only use chips in $5 and $9 denominations. Which of the following amount cannot be paid out using these chips? Options: A) $31 B) $37 C) $33 D) $24 E) $15

Solution: Yes, the number of 5 or/and 9 dollar chips can be zero, however both being zero mean that the casino is paying out $0, which is not realistic.   Each option but A can be represented as the sum of a multiple of 5 and a multiple of 9:   A. $33 = 5*3 + 9*2   B. $37 = 5*2 + 9*3   C. $24 = 5*3 + 9*1   E. $15 = 5*3   $31nswer: $31.
Answer: A
The diameter of a garden roller is 1.4 m and it is 2 m long. How much area will it cover in 5 revolutions ? (use π = 22⁄7) Choose the correct choice from the following options
A) 40 m2 B) 44 m2 C) 48 m2 D) 36 m2 E) None of these

Solution: Required area covered in 5 revolutions   = 5 × 2πrh = 5 × 2 × 22⁄7 × 0.7 × 2 = 44 m2   Answer 44 m2
Answer: B
The base of a triangular field is three times its altitude. If the cost of cultivating the field at Rs. 24.68 per hectare be Rs. 333.18, find its base and height.  Choices
A) 100m B) 125m C) 150m D) 278m E) 300m

Solution: Sol. Area of the field = Total cost/rate = (333.18/25.6)hectares = 13.5 hectares   (13.5 x 10000) m^2 = 135000 m^2.   Let altitude = x metres and base = 3x metres.   Then, (1/2)* 3x* x = 135000 <=>x^2= 90000 <=>x = 300.   Base = 900 m and Altitude = 300 m.   Ans: 300m
Answer: E
A chemist mixes one liter of pure water with x liters of a 75% salt solution, and the resulting mixture is a 15% salt solution. What is the value of x?  Choose the correct choice from the following choices
A) 1/4
B) 1/3
C) 1/2
D) 1
E) 3

Solution: Concentration of salt in pure solution = 0   Concentration of salt in salt solution = 75%   Concentration of salt in the mixed solution = 15%   The pure solution and the salt solution is mixed in the ratio of --> (75 - 15)/(15 - 0) = 4/1   1/x --  (75 - 15)/(15 - 0)= 
--  (75 - 15)/(15 - 0) = 4
4/1   1/x= 4/1   x = 1/4   1/4nswer: 1/4
Answer: A
Three rugs have a combined area of 200 square meters. By overlapping the rugs to cover floor area of 140 square meters, the area that is covered by exactly two layers of rug is 22 square meters. What is the area that is covered with three layers of rug ?  Choices:
A) 18 square meters	B) 20 square meters	C) 24 square meters	D) 19 square meters	E) 30 square meters

Solution: Total = Rug1 + Rug2 + Rug3 - {overlap of exactly 2 rugs} - 2*{overlap of exactly 3 rugs}   140 = 200 - 22 - 2*{overlap of exactly 2 rugs} --> {overlap of exactly 3 rugs} = 19.   Answer: 19 square meters.
Answer: D
A thief is noticed by a policeman from a distance of 450 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes ?  Choices
A) 50 meter B) 100 meter C) 220 meter D) 120 meter E) 350 meter

Solution: 350 meterxplanation:   Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr   Distance covered in 6 minutes =   1/60∗6=1/10=100meters   So distance between them after 6 minutes = 450 - 100= 
450 - 100 = 350
350 meters   Option 350 meter
Answer: E
How many bricks, each measuring 80 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?	Choose the correct choice:
A) 6400	B) 2000	C) 5500	D) 7400	E) 3000

Solution: Number of bricks = Volume Of the wall / Volume of 1 brick = (800 x 600 x 22.5) / (80 x 11.25 x 6) = 2000   ANSWER:2000
Answer: B
A scale 6 ft. 8 inches long is divided into 4 equal parts. Find the length of each part. Select the correct option.
A) 20 inches  B) 77 inches  C) 66 inches  D) 97 inches  E) 66 inches

Solution: Explanation:   Total length of scale in inches = (6*12) + 8= 
(6*12) + 8 = 80
80 inches   Length of each of the 4 parts= 80/4= 
80/4 = 20
20 inches   20 inchesNSWER:20 inches
Answer: A
A and B are two multiples of 14, and Q is the set of consecutive integers between A and B, inclusive. If Q contains 14 multiples of 14, how many multiples of 7 are there in Q? Choose the correct choice from the following options:
A) 26 B) 27 C) 28 D) 29 E) 30

Solution: Halfway between the multiples of 14, there will be another multiple of 7.   The total number of multiples of 7 is  14+13= 
 14+13 = 27
27.   The answer is 27.
Answer: B
What will be the difference in simple and compound interest on 4000 after three years at the rate of 10 percent per annum?
Choose the correct answer:
A) 160 B) 42 C) 62 D) 124 E) None of these

Solution: For 3 years:   124iff.=Sum×(rate)2(300+rate)/(100)3   = 4000×10×10×310/100×100×100 = 124   Answer 124
Answer: D
A hiker walking at a constant rate of 4 miles per hour is passed by a cyclist travelling in the same direction along the same path at a constant rate of 16 miles per hour. the cyclist stopswaits for the hiker 5 min after passing her while the hiker continues to walk at her constant rate. how many minutes must the cyclist wait until the hiker catches up	Choose the correct choice from the following.
A) 6 2/3	B) 15	C) 20	D) 25	E) 26 2/3

Solution: Here is how I did it:   The cyclist travels 16 miles in 60 mins, so in 5 mins he will travel [(16*5)/60] miles, which equals 4/3 miles in 5 mins.   Now the hiker travels 4 miles in 60 mins. To travel 4/3 miles, he will take [(60*4/3)/4= 
(60*4/3)/4 = 20
20 mins.   hence 20-5= 
20-5 = 15
15 mins   15
Answer: B
The average height of 50 pupils in a class is 150 cm. Five of them whose height is 146 cm, leave the class and five others whose average height is 156 cm, join. The new average height of the pupils of the class (in cm) is?	Choose the correct choice from the following
A) 551 cm
B) 151 cm
C) 156 cm
D) 165 cm
E) 146 cm

Solution: Total height   = 150 * 50= 
150 * 50 = 7_500
7500 cm.   New average= [7500 - 5 * 146 + 5 * 156 ] / 50   = 151 cm.   Answer: 151 cm
Answer: B
Excluding stoppages, the speed of a train is 60 kmph and including stoppages it is 40 kmph. Of how many minutes does the train stop per hour?	Choices:
A) 12
B) 14
C) 16
D) 18
E) 20

Solution: 20xplanation:   T = 20/60 * 60= 
20/60 * 60 = 20
20   Answer: Option 20
Answer: E
A man can do a piece of work in 10days, but with the help of his son, he can finish it in 5days. In what time can the son do it alone? Choose the correct choice from the following answers:
A) 5	B) 8	C) 7	D) 10	E) 15

Solution: Son's 1day work = 1/5 - 1/10 = 1/10   Son alone can do the work in 10days   Answer is 10
Answer: D
Three bells chime at intervals of 18 min., 24 min. and 32 min. respectively. At a certain time they begin together. What length Q of time will elapse before they chime together again?  Select:
A) 2 hr. and 24 min.
B) 4 hr. and 48 min.
C) 1 hr. and 36 min.
D) 5 hr.
E) 2 hr.

Solution: It should be simple. All the three bells will chime again together whenver their time intervals intersect eachother.   So the LCM of the three time intervals (18, 24,32) would be the answer.   LCM (18, 24, 32) Q= 288 => 4 hours 48 mins.4 hr. and 48 min.
Answer: B
Marks of a student were wrongly entered in computer as 83, actual marks of that student were 63. Due to this mistake average marks of whole class got increased by half (1/2). Find the total number of students in that class. Answers
A) 25  B) 30  C) 35  D) 40  E) 45

Solution: Explanation:   Suppose total number of students are = X   Totalincrease=x∗1/2=x/2   =>x/2=83−63=20   =>x=40   Answer: Option 40
Answer: D
A mathematics teacher tabulated the marks secured by 35 students of 8th class. The average of their marks was 62. If the marks secured by Reema was written as 50 instead of 85 then find the correct average marks up to two decimal places.
Choose the correct choice from the following options.
A) 63
B) 74.31
C) 72.43
D) 73.43
E) Cannot be determined

Solution: Total marks = 35 x 62 =2170   Corrected total marks = 2170 - 50 + 85= 
2170 - 50 + 85 = 2_205
2205   Correct 63verage= 2205/35= 
2205/35 = 63
63   63nswer : 63
Answer: A
Find the largest number that will divide 43,91,183 so as to leave the same reminder in each case.
Pick one:
A) 5
B) 4
C) 26
D) 35
E) 9

Solution: Explanation:   Required Number=H.C.F of(91-43),(183-91) and (183-43)   H.C.F of 48,92 and 140=4   Answer:4
Answer: B
Marla is hanging a banner diagonally across a rectangular room. The length of the room is 2 feet shorter than its width. If the total area of the room is 120 square feet, what is the length of the banner (in feet)? Choose the correct choice from the following options: A) Between 13 and 14 B) Between 14 and 15 C) Between 15 and 16 D) Between 16 and 17 E) Between 17 and 18

Solution: To solve this, we first need to set up an equation for the area of the room. If x is the width, then we have   x(x - 2) = 120. By putting the equation in standard form, we get x^2-2x-120=0. By using the quadratic formula, we get roots of -10 and 12. We know that x is the width, and x-2 is the length, so by using the roots, we get 12 as the width (x), and 10 as the length (x-2).   Once we have this, we can use the Pythagorean Theorem to solve for the diagonal. Plugging in the length and width, we will get d^2=12^2+10^2   =144+100= 
144+100 = 244
244   The square root of 244 is less than 16, since 16^2= 256. Going down a number, we can compute 15^2 = 225 < 224. Therefore, the length of the diagonal must be between 15 and 16.   The correct answer is Between 15 and 16.
Answer: C
A cyclist rides a bicycle over a route which is 1/3 uphill, 1/3 level, and 1/3 downhill. If the cyclist covers the uphill part of the route at the rate of 10 km per hour and the level part at the rate of 15 km per hour, what rate in km per hour would the cyclist have to travel the downhill part of the route in order to average 15 km per hour for the entire route?  Pick one: A) 20 B) 25 C) 30 D) 35 E) 40

Solution: Let V be the speed on the downhill section.   Let D be the distance of each of the three equal sections.   Total time T = T1+T2+T3 and 3D/T = 15 km/hour   3D / (D/10 + D/15 + D/V) = 15   1/5 = 1/10 + 1/15 + 1/V   1/V = 1/30 and so V = 30 km/h   The answer is 30.
Answer: C
On the xy-plane, each point on circle C has coordinates such
that x 0 and y 0. If the center of circle C is the point (3; 9),
what is the maximum possible area of C?	Choose one
A) 6 B) 9 C) 24 D) 32 E) 64

Solution: I think that theintentof this question is that the circle will have NO CO-ORDINATES that fit the following 2 forms: (0, Y) or (X, 0). In real basic terms, this circle will NEITHER touch (nor cross) the X-axis NOR will it touch (nor cross) the Y-axis.   With a center at (3,8), the longest possible radius would ALMOST touch the X-axis, so the radius would be a little less than 3.   If the radius WAS 3 exactly, then the area would be 9pi, which is approximately 28.26   Since the circle CAN'T touch the X-axis, the area has to be LESS than approximately 28.26   As it's written, none of the answers is clearly the correct one.   24
Answer: C
If a certain sample of data has a mean of 24.0 and a standard deviation of 3.0, which of the following values is more than 2.5 standard deviations from the mean?  Choose the correct choice from the following choices:  A) 12.0  B) 13.5  C) 17.0  D) 23.5  E) 16.5

Solution: The standard deviation is 3. 2.5 standard deviations, which is just 2.5 x 3.0 is 7.5. The only answer more than 7.5 away from the mean is 16.5.
Answer: E
A not-so-good clockmaker has four clocks on display in the window. Clock #1 loses 25 minutes every hour. Clock #2 gains 15 minutes every hour relative to Clock #1 (i.e., as Clock #1 moves from 12:00 to 1:00, Clock #2 moves from 12:00 to 1:15). Clock #3 loses 20 minutes every hour relative to Clock #2. Finally, Clock #4 gains 20 minutes every hour relative to Clock #3. If the clockmaker resets all four clocks to the correct time at 12 noon, what time will Clock #4 display after 6 actual hours (when it is actually 6:00 pm that same day)?	Pick:
A) 5:00	B) 5:34	C) 5:42	D) 6:00	E) 6:24

Solution: C1 loses 15 minutes every hour. So after 60 minutes have passed, C1 displays that 60-15= 
60-15 = 45
45 minutes have passed.   C2 gains 15 minutes for every 60 minutes displayed on C1. Thus, the time displayed on C2 is 75/60= 5/4 the time displayed on C1. So after 60 minutes have passed, C2 displays the passing of (5/4 * 45) minutes.   C3 loses 20 minutes for every 60 minutes displayed on C2. Thus, the time displayed on C3 is 40/60 = 2/3 the time displayed on C2. So after 60 minutes have passed, C3 displays the passing of (2/3 * 5/4 * 45) minutes.   C4 gains 20 minutes for every 60 minutes displayed on C3. Thus, the time displayed on C4 is 80/60 = 4/3 the time displayed on clock 3. So after 60 minutes have passed, C4 displays the passing of  4/3 * 2/3 * 5/4 * 45= 
 4/3 * 2/3 * 5/4 * 45 = 50
50 minutes.   C4 loses 10 minutes every hour.   In 6 hours, C4 will lose   6*10= 
  6*10 = 60
60 minutes= 1 hour.   Since the correct time after 6 hours will be 6pm, C4 will show a time of 6-1= 
6-1 = 5
5:42pm.   The correct answer is 5:42.
Answer: C
If HCF of two numbers is 11 and the product of these numbers is 363, what is the the greater number?
Select the correct option
A) 33	B) 36	C) 38	D) 42	E) 44

Solution: Let the numbers be 11a and 11b   11a × 11b = 363   => ab = 3   co-primes with product 3 are (1, 3)   Hence the numbers with HCF 11 and product 363   = (11 × 1, 11 × 3)   = (11, 33)   Hence, numbers are 11 and 33   The greater number =   33)
Answer: A
A man can row with a speed of 10 kmph in still water. If the stream flows at 30 kmph, then the speed in downstream is?	Answers:
A) 10 kmph  B) 5 kmph  C) 40 kmph  D) 22 kmph  E) 25 kmph

Solution: M = 10   S = 30   DS = 10 + 30= 
10 + 30 = 40
40   ANSWER:40 kmph
Answer: C
Find the ones digit of 73^356 Choose the correct option.
A) 1	B) 5	C) 6	D) 7	E) 9

Solution: The units digit of 73^356 will be the same as the units digit of 3^356.   3^1=3 --> the units digit is 3;   3^2=9 --> the units digit is 9;   3^3=27 --> the units digit is 7;   3^4=81 --> the units digit is 1;   3^5=243 --> the units digit is 3 AGAIN;   ...   So, as you can see the units digit repeats in blocks of 4: {3, 9, 7, 1}, {3, 9, 7, 1}, ... Now, since 356=356+0=(multiple of 4)+0, then the units digit of 3^356 will be thus 1.   1nswer: 1.
Answer: A
10^25 - 250 is divisible by all of the following except:  Choices.
A) A.11
B) B.15
C) C.5
D) D.6
E) E.3

Solution: The last three digits ( 1000 - 250 ) 750   750 is divisible by 15,3,6,5   750 is not evenly divisible by 11 so the answer is A.11) 11
Answer: A
If A speaks the truth 85% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time
Options:	A) 0.49	B) 0.48	C) 0.41	D) 0.482	E) 0.51

Solution: 0.51xplanation:   Probability that A speaks truth is  85/100= 
 85/100 = 17/20 = around 0.85
0.85   Probability that B speaks truth is   60/100= 
  60/100 = 3/5 = around 0.6
0.6   Since both A and B are independent of each other   So probability of A intersection B is P(A) × P(B)=0.85 × 0.6 = 0.51   Answer: 0.51
Answer: E
Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km? Choices
A) 600 m  B) 300 m  C) 400 m  D) 700 m  E) 500 m

Solution: 600 m   600 m   Distance covered by 600 mmar = 18/4.8 (1.6km) = 3/8(1600) = 600 m
Answer: A
A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years? Choose one:
A) Rs.3129 B) Rs.3120 C) Rs.3108 D) Rs.3106 E) Rs.3127

Solution: Let A be the amount received at the end of the three years.   A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]   A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)   A = Rs.7920   So the interest = 7920 - 4800 =   Rs.3120   Answer:Rs.3120
Answer: B
A person travels equal distances with speed of 3 km/hr, 4 km/hr and 5 km/hr and takes a total of 47 minutes. Find the total distane Select:
A) 3 km
B) 4 km
C) 6 km
D) 9 km
E) 5 km

Solution: Explanation:   Let the distance be 3x km,   then,   x/3+x/4+x/5=47/60   47x /60= 47 /60   x=1   So total distance = 3*1= 
3*1 = 3
3 Km   Option 3 km
Answer: A
An item is being sold for $10 each. However, if a customer will “buy at least 3” they have a promo discount of 32%. Also, if a customer will “buy at least 10” items they will deduct an additional 8% to their “buy at least 3” promo price. If Sam buys 10 pcs of that item how much should he pay?	Choose the correct choice from the following answers:  A) $92.00  B) $88.00  C) $87.04  D) $80.96  E) $70.00

Solution: Without any discount Sam should pay 10*10= 
10*10 = 100
$100. Now, the overall discount would be slightly less than 40%, thus he must pay slightly more than $60. Only answer choice E fits.   Answer: $70.00.
Answer: E
A can run 4 times as fast as B and gives B a start of 66 m. How long should the race course be so that A and B might reach in the same time? Choose the correct choice from the following choices:
A) 88 m	B) 60 m	C) 80 m	D) 65 m	E) 75 m

Solution: Speed of A:Speed of B=4:1   means in a race of 4m A gains 3m.   then in a race of 66m he gains 66*(4/3)   I.e 88m   88 mNSWER:88 m
Answer: A
The length of a side of a hexagon is 8 inches. What is the perimeter?
Choose the correct choice from the following options
A) 40	B) 44	C) 48	D) 50	E) 38

Solution: Hexagon. It means 6 equal sides.   p = 6(8) = 48 inches   Answer 48
Answer: C
Two trains are running in opposite directions with the same speed. If the length of each train is 300 m and they cross each other in 12 sec, then the speed of each train is?
Answers:	A) 22	B) 77	C) 36	D) 90	E) 21

Solution: Let the speed of each train be x m/sec.   Then, relative speed of the two trains = 2x m/sec.   So, 2x = (300 + 300)/12 => x = 25   Speed of each train = 10 m/sec.   = 25 * 18/5 =- 90 km/hr.   Answer: 90
Answer: D
Ms. Lopez deposits $ 150 in an account that pays 20% interest, compounded semiannually. How much money will there be in the account at the end of one year? Choose the correct choice from the following choices.
A) $118.00 B) $120.00 C) $181.15 D) $122.00 E) $140.00

Solution: Using Formula - A = P(1+r/n)^nt   Given   P=150   n=2   t=1   r=0.2   Substituting value in formula   A = 150(1+0.2/2)^2   A= 181.15$=$181.15
Answer: C
How many four digit numbers divisible by 4 can be made with digits 1, 2, 3, 4, 5 if the repetition of digits is not allowed?	Answers.
A) 10  B) 20  C) 30  D) 40  E) 50

Solution: A number is divisible by 4 if the last 2 numbers are divisible by 4 (divisible by 2 twice)   Ending can be   12   24   32   42   52   Case: Ending with 12,24,32,42,54   First digit - 3 choices   Second digit - 2 choices   Third digit - 1 choice   Fourth digit - 1 choice   6 possible choices for each ending (e.g. 3412,3512, 3212 ,4512 ,5312 ,5412)   Total number of 4 digit numbers divisible by 4 = 6 * 5= 
6 * 5 = 30
30   ANSWER:30
Answer: C
A candidate appearing for an examination has to secure 42% marks to pass paper I. But he secured only 60 marks and failed by 20 marks. What is the maximum mark for paper I? Choose the correct choice from the following choices.
A) 110
B) 120
C) 130
D) 140
E) 190

Solution: he secured 60 marks nd fail by 20 marks so   total marks for pass the examinatn=80   let toal marks x   x*42/100=80   x=190   ANSW190R:190
Answer: E
The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 90 kmph. Find the speed of the boat in still water and the speed of the stream? Choose the most appropriate option:
A) 10 kmph
B) 67 kmph
C) 15 kmph
D) 88 kmph
E) 12 kmph

Solution: Speed of the boat in still water   = (60+90)/2= 
(60+90)/2 = 75
75 kmph. Speed of the stream= (90-60)/2= 
(90-60)/2 = 15
15 kmph.   Answer:15 kmph
Answer: C
By selling a watch for Rs.800/-, a man loses 20% what is that watch cost price	Select:
A) s. 700/- B) s. 800/- C) s. 880/- D) s. 900/- E) s. 1000/-

Solution: 80 % ------> 800 (80 * 10 = 640)   100 % ------>1000 (100 * 10 = 1000)   Cost price = Rs. 1000/-   s. 1000/-
Answer: E