MU-NLPC/Calc-aqua_rat huggingface dataset:
Walking across campus, a student interviewed a group of students. 20% of the students took a finance class last semester, 45% took a marketing class last semester, and 45% took neither a finance nor a marketing class last semester. What percent of the students in the group took both a finance and a marketing class?
Choose the most appropriate option:
A) 60%
B) 50%
C) 25%
D) 15%
E) 10%

Solution: {Total} = {finance} + {marketing} - {both} + {neither}   100 = 20 + 45 - {both} + 45   {both} = 10%.   The answer is 10%.
Answer: E
Harkamal purchased 8kg of grapes at the rate of 75 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper?
Choose the correct choice from the following answers: A) A)1000 B) B)1055 C) C)1065 D) D)1075 E) E)1095

Solution: Cost of 8 kg grapes = 75 × 8 = 600.   Cost of 9 kg of mangoes = 55 × 9 = 495.   Total cost he has to pay = 600 + 495= 
600 + 495 = 1_095
1095.   1095)
Answer: E
If y = 30p, and p is prime, what is the greatest common factor of y and 10p, in terms of p?  Choose the correct option:
A) 10p	B) 2p	C) 5p	D) 7p	E) p^2

Solution: Y=30p   other number is 10p   then GCF(30p,10P)=10P; 10p is the correct answer
Answer: A
Everyone shakes hands with everyone else in a room. Total number of handshakes is 120. Number of persons=? Answers:
A) a.14 B) b.12 C) c.11 D) d.15 E) e.16

Solution: In a room of n people, the number of possible handshakes is C(n,2) or n(n-1)/2   So n(n-1)/2 = 120 OR n(n-1)=240 OR n=16   Answer is (e.16)
Answer: E
10% people of a village in Sri Lanka died by bombardment, 20% of the remainder left the village on account of fear. If now the population is reduced to 3168, how much was it in the beginning? Select.
A) A)3800	B) B)4200	C) C)4400	D) D)4500	E) E)4600

Solution: X * (90/100) * (80/100) = 3168   X = 4400   ANSWER:4400
Answer: C
A dealer originally bought 90 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?	Choose the most appropriate option:
A) q/60
B) 3q/2
C) 145q
D) q/90
E) 145/q

Solution: The cost of each battery was q/90.   Each battery was sold for 1.5q/90 = 3q/180 = q/60.   The answer is q/60.
Answer: A
The first term in a sequence is 1 and the second term is 10. From the third term on each term is the average (arithmetic mean) of all preceding terms. What is the 29th term in the sequence?
Choose the correct choice from the following:	A) 3.5	B) 5.5	C) 10	D) 10.5	E) 29

Solution: The third term is 5.5 since this is the average of 1 and 10.   Then the next terms will all be 5.5 since the average stays at 5.5   The answer is 5.5.
Answer: B
Billy makes $124 more than Kimberly in a week. Wynona makes 3 times as much as Billy and Kimberly put together in a week, which totals $2,436. How much would Billy, Kimberly, and Wynona make together in a month?
Select
A) $12,992  B) $9,744  C) $29,232  D) $11,232  E) None of the above

Solution: b-k=124   3(b+k)=2,436 or b+k=812   Solving the 2 equations you get B=$468 and K=$344   So 4(468+344+2436)=$12,992   Correct $12,992nswer: $12,992
Answer: A
The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?  Choose the correct answer
A) 13√4
B) 13√2
C) 23√2
D) 12√4
E) 13√9

Solution: 4a = 48 4a = 20   a = 12 a = 5   a2 = 144 a2 = 25   Combined area = a2 = 169 => a = 13   d = 13√2   Answer: 13√2
Answer: B
If a number between 10 and 60 (inclusive) at random. What is the probability that the tens digit is greater than ones digit?
Pick one: A) 31/41 B) 1041 C) 14/41 D) 27/41 E) 16/51

Solution: If tens digi is 6 ---> ones digit : 0   If tens digi is 5 ---> ones digit : 0, 1, 2, 3, 4   If tens digi is 4 ---> ones digit : 0, 1, 2, 3   If tens digi is 3 ---> ones digit : 0, 1, 2   If tens digi is 2 ---> ones digit : 0, 1   If tens digi is 1 ---> ones digit : 0   So the number of numbers whose tens digit is greater than ones digit is 11.   The total number is   60-10+1= 
  60-10+1 = 51
51.   So the probability is 16/51.   The answer is (16/51).
Answer: E
The average age of A and B is 50 years. If C were to replace A, the average would be 50 and if C were to replace B, the average would be 40. What are the age of A, B and C?	Choices:
A) 100,100, 80 B) 50, 50, 40 C) 40, 60, 40 D) 50, 60, 40 E) None of the above

Solution: Given A + B = 100â€¦(i)   40, 60, 40 + B = 100â€¦ (ii)   A + 40, 60, 40 = 80â€¦(iii)   (i) + (ii) + (iii) â‡’ A + B + 40, 60, 40 = 140â€¦(iv)   from (i) and (iv), we get   40, 60, 40 = 40years   âˆ´ B = 60 years and A = 40 years   Answer 40, 60, 40
Answer: C
If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 7 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?
Choose the most appropriate option.
A) 17/140  B) 29/180  C) 26/143  D) 1/5  E) 39/121

Solution: 50 apprentices can finish the job in 4 hours,thus:   10 apprentices can finish the job in   4*5= 
  4*5 = 20
20 hours;   In 1 hour 10 apprentices can finish 1/20 of the job.   30 journeymen can finish the same job in 4,5 hours,thus:   15 journeymen can finish the job in  7*2= 
 7*2 = 14
14 hours;   In 1 hour 15 journeymen can finish 1/14 of the job.   Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/14=17/140 of the job.   17/140nswer: 17/140
Answer: A
If x^4 > x^5 > x^3, which of the following could be the value of x?	Choose the most appropriate option:  A) -3  B) -2  C) -2/3  D) 2/3  E) 3

Solution: Let's break this question down into two parts. I: x4>x5x4>x5 and II: x5>x3x5>x3   Consider Part I:   x4>x5x4>x5   For this to be true, either xx is negative or it is a fraction less than 1   Consider Part II:   x5>x3x5>x3   If xx is negative, then for this to be true, xx has to be greater than -1.   If xx is a fraction less than 1, then for this part to be true, xx must also be negative.   In either case, xx can be represented by the inequality 0>x>−10>x>−1.   The only option that satisfies this condition is -2/3 (-2/3)   ANSWER:-2/3
Answer: C
A die is thrown three times. Events X and Y are defined as below:
X : 4 on the third throw
Y : 6 on the first and 5 on the second throw
What is the probability of X given that Y has already occurred.
Choices
A) 1/7  B) 1 by 6  C) 2/3  D) 2/5  E) 3/5

Solution: The sample space has 216 outcomes.   Now X =   (1,1,4) (1,2,4) ... (1,6,4) (2,1,4) (2,2,4) ... (2,6,4)   (3,1,4) (3,2,4) ... (3,6,4) (4,1,4) (4,2,4) ...(4,6,4)   (5,1,4) (5,2,4) ... (5,6,4) (6,1,4) (6,2,4) ...(6,5,4) (6,6,4)   Y = {(6,5,1), (6,5,2), (6,5,3), (6,5,4), (6,5,5), (6,5,6)}   and X n Y = {(6,5,4)}.   Now P(Y) = 6/216   and P (X n Y) = 1/216   Then P(X|Y) = (1/216)/(6/216) = 1/6.   1 by 6)
Answer: B
What is the sum of all the numbers between 1 and 16, inclusive?
Choose the most appropriate option: A) 190 B) 200 C) 185 D) 166 E) 213

Solution: All you have to do is add 1+2+3+4...+14+15+16, which is 190.   Final 190nswer:   190
Answer: A
If the median of a list of numbers is m, the first quartile of the list is the median of the numbers in the list that are less than m. What is the first quartile of the list of numbers 42, 24, 30, 34, 26, 36, 33 and 35 ? Options:
A) 33
B) 28
C) 27
D) 24
E) 23

Solution: It is given that a quartile is the middle number of all numbers less than median..   so lets arrange the number in ascending order- 42, 24, 30, 34, 26, 36, 33 and 35   24, 26, 30, 33, 34, 35, 36, 42...   numbers less than median are 24, 26, 30, 33..   the median of these numbers = center of 26 and 30 = 28   28
Answer: B
If Re.250 amounts to Rs.400 over a period of 5 years. What is the rate of simple interest?
Choose the correct choice from the following:	A) 11%	B) 12%	C) 13%	D) 10%	E) 14%

Solution: 150 = (250*5*R)/100   R = 12%   Answer:12%
Answer: B
For the given equation x9+5x8−x3+7x+2=0,x9+5x8−x3+7x+2=0, how many maximum real roots are possible?  Choose the correct choice from the following:
A) 3  B) 7  C) 4  D) 0  E) 1

Solution: f(x) = x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0   In f(x), there are 2 changes of sign. So, there are two positive roots.   f(-x) = - x9+5x8−x3+7x+2=0x9+5x8−x3+7x+2=0   In f(-x), there are 3 changes of sign. So, there are three negative roots.   So, in all there are 5 real roots possible (2 positive and 3 negative) and as degree of the given equation is 9, there are total 9 roots. So, remaining 4 roots will be imaginary.   Answer:4
Answer: C
The diagonals of two squares are in the ratio of 2 : 5. Find the ratio of their areas. Choices:
A) 5:25	B) 4:25	C) 3:15	D) 7:15	E) 6:15

Solution: Let the diagonals of the squares be 2x and 5x respectively.   Ratio of their areas = (1/2)*(2x) 2:(1/2)*(5x) 2   = 4x2: 25x2   = 4 : 25.   ANSWER 4:25 4:25
Answer: B
In how many ways R can the crew of a ten oared boat be arranged ,when of the ten persons available, 2 of whom can row only on the bow side and 3 of whom can row only on the stroke side?	Options
A) 1. 10!/(2! * 3!)	B) 2. 10!/(8! * 7!)	C) 3. 5!/(3! * 2!)	D) 4. (5!)^3/(3! * 2!)	E) 5. 5!/(8! * 7!)

Solution: Ans is D.   Going by the assumtion that both the Bow side and Stroke side will have 5 person each.   Five(3+2) of them had allready been selected(according to their preference), so from the remaining 5 we have to select 2 for the stroke side or 3 for the bow side.   and the 5 crew of each side can be arranged in 5! ways.R   Hence answer is 5C3 * 5! * 5!= (5!)^3/ 3!2!.4. (5!)^3/(3! * 2!)
Answer: D
Envelopes can be purchased for $1.50 per pack of 100, $1.00 per pack of 50, or $0.03 each. What is the greatest number of envelopes that can be purchased for $8.40? Pick one
A) 426	B) 430	C) 443	D) 530	E) 486

Solution: I think first we should see in what group envelopes value less, so that we can buy as many as we can with a specific amount of money:   -the 100 pack costs 1.5$, meaning 0.015$ per envelope   -the 50 pack costs 1$, meaning 0.02$ per envelope   -the single envelope costs 0.03$ per envelope   Thus, we have to buy as many 100 packs as we can, then as meny of 50 packs as we can and the remaining envelopes are single ones.   Having 8.4$, we can buy as many as 5 packs of 100 (5 x 1.5$ = 7.5$). We then have 0.9 $ left. so we buy 30 individual envelopes. If we add up the numbers, we get   500+30= 
  500+30 = 530
530 envelopes. Answer 530
Answer: D
A wholesaler wishes to sell 100 pounds of mixed nuts at $1.50 a pound. She mixes peanuts worth $1.50 a pound with cashews worth $4.00 a pound. How many pounds of cashews must she use?	Answers:
A) 40 B) 45 C) 50 D) 55 E) 60

Solution: From the question stem we know that we need a mixture of 100 pounds of peanuts and cashews. If we represent peanuts as x and cashews as y, we get x + y = 100. Since the wholesaler wants to sell the mixture of 100 pounds @ $2.50, we can write this as: $1.5 * (x + y) = $1.5x + $4y   From the equation x + y = 100, we can rewrite y as y = 100 - x and substitute this into our equation to get:   $2.5 * (x + 100 - x) = $1.5x + $4(100 - x)   If you solve for x, you will get x = 60, and therefore y = 40. So the wholesaler must use 40 pounds of cashews.   You can substitute into the original equation to see that: $250 = $1.5(60) + $4(40)   40nswer is 40.
Answer: A
A can finish a piece of work in 4 days. B can do it in 8 days. They work together for two days and then A goes away. In how many days will B finish the work? Select the correct option
A) 4 B) 5 C) 6 D) 2 E) 8

Solution: 2/4 + (2 + x)/8 = 1 => x = 2 days   Answer: 2
Answer: D
If each term in the sum a1+a2+a3+...+an either 2 or 22 and the sum equals 100, which of the following could be equal to n?
Choose the correct choice from the following.
A) 38	B) 39	C) 40	D) 41	E) 42

Solution: Min value of 'n' can be 10 i.e 4*22+6*12 => 22+22+22+22+2+2+2+2+2+2= 
22+22+22+22+2+2+2+2+2+2 = 100
100   Since we don't have 10 in the options proceed further, (10-1)+22/2=> 20 digits, which is again not in the options    (20-1) + 22/2= 
 (20-1) + 22/2 = 30
30 digits ( not in options)   (30-1) + 22/2= 
(30-1) + 22/2 = 40
40 digits   ANSWER:40
Answer: C
Two trains start from the same station at the same time and travel in opposite directions. One
train travels at an average rate of 40 mph, the other at 65 mph. In how many hours will they be
315 miles apart?
Choose one
A) 1 hour B) 2 hours C) 3 hours D) 4 hours E) 5 hours

Solution: First we’ll make the d=rt chart. But we won’t fill in the d.   d = r x t   Train 1 40 x   Train 2 65 x   The reason we have an x in the time column is because they left at the same time and will be 315   at the same time. In other words, their times are equal.   Now, the big question. Are there distances equal? Since they do not meet the criteria in a TYPE   A problem, the answer is no. That means the sum of the distances must be equal to a number.   D1 + D2 = #   40x + 65 = 315   105x = 315   x = 3 It will take three hours.   correct answer 3 hours
Answer: C
At a party, there were five times as many females as males and six times as many adults as children. Which of the following could be the number of people at the party? Choose the correct choice.
A) 384 B) 258 C) 216 D) 120 E) 77

Solution: Five times as many females as males --> F = 5M.   Three times as many adults as children --> (F + M) = 6C.   The number of people at the party = F + M + C = 6C + C = 7C.   The number of people at the party must be a multiple of 7. The only answer choice which is a multiple of 7 is E.   Answer: 77.
Answer: E
The average of first ten prime numbers:
Select.
A) 5.6  B) 11.2  C) 12.9  D) 6.3  E) 7.4

Solution: Explanation:   The first ten prime numbers is 2, 3, 5, 7, 11, 13, 17, 19, 23, 29   Average = 129/10= 
129/10 = 129/10 = around 12.9
12.9   Answer: Option 12.9
Answer: C
One out of every 500 light bulbs are defected. If 2 out of every 10 defected light bulbs have a broken glass and there are 12 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment? Pick
A) 2,000 B) 5,000 C) 10,000 D) 30,000 E) 52,000

Solution: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs   Now out of these 10 bulbs, 2 bulbs, have broken glass   i.e 2 broken glass out of 5000 bulbs   12 broken glass will be from 30000 bulbs   Answer is 30,000
Answer: D
The local carpenter made a beautiful table for my father. He told him that the type of wood which he used costs G dollars per kg, and that the table only weight F kilograms. If the carpenter worked for D hours on the table and makes E dollars per hour, how much profit will my father make when he sells the table for V dollars?
Options.
A) V-GF-DE  B) V+GE-DF  C) V-(GF-DE)  D) G(V-DE)+F  E) (FG+DE)+V

Solution: The wood will cost= GF dollars   The carpenter will be payed an amount= DE dollars   Hence, the cost price= GF+DE dollars   The selling price= V dollars   V-GF-DEnd the profit= V-(GF+DE)   The answer is V-GF-DE
Answer: A
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is?  Choose the correct choice from the following answers
A) 1 hr  B) 7 hr  C) 9 hr  D) 4 hr  E) 9 hr

Solution: Let the duration of the flight be x hours. Then,   600/x - 600/(x + 1/2) = 200   x(2x + 1) = 3 2x2 + x - 3  (2  + 1)= 
 (2  + 1) = 3
3 2x2 + x - 3= 0   (2x + 3)(x - 1) = 0   x = 1 hr.   1 hrnswer: 1 hr
Answer: A
In a rectangular axis system, what is the area of a parallelogram with the coordinates: (4,4), (7,4), (5,9), (8,9) ? Select the correct option: A) 21. B) 28. C) 5. D) 49. E) 52.

Solution: Delta x will give us the dimension of one side of the parallelogram = 5-4= 
5-4 = 1
1 unit   Delta y will give us the dimension of the other side of parallelogram= 9-4= 
9-4 = 5
5 unit   Area of parallelogram= 1*5= 
1*5 = 5
5   ANSWER IS 5.
Answer: C
For a certain set, the value range of its members is 84.4. A new set is created from the members of the old set as follows: 12 is subtracted from a member of the old set, and the result is divided by 4. The resulting value is a member of the new set. If this operation is done for each member of the old set, what is the range of values of the members of the new set? Choose the correct choice from the following:
A) 18.1
B) 21.1
C) 36.5
D) 42.2
E) 84.4

Solution: Let x and z be the smallest and largest of the original set, respectively.   z - x = 84.4   The smallest and largest members of the new set will be (x-12) / 4 and (z-12) / 4.   Then the range is (z-12) / 4 - (x-12) / 4 = (z-x) / 4 = 84.4 / 4= 
84.4 / 4 = 21.1
21.1   The answer is 21.1.
Answer: B
A discount of 10 percent on an order of goods followed by a discount of 30 percent amounts to
Select the correct option.
A) the same as one 45 percent discount	B) the same as one 40 percent discount	C) the same as one 37 percent discount	D) the same as one 30 percent discount	E) the same as one 25 percent discount

Solution: 0.9*0.7*x=0.63x from initial value, meaning 0.37 or 37% discount   the same as one 37 percent discount
Answer: C
The interest on a certain deposit at 4.5% p.a. is Rs. 202.50 in one year. How much will the additional interest in one year be on the same deposit at 5% p.a.?	Choose the correct choice from the following
A) Rs. 20.25
B) Rs. 22.50
C) Rs. 25
D) Rs. 42.75
E) None

Solution: Solution   S.I. = Rs. 202.50, R = 4.5% ,T = 1 year.   principal = Rs. (100x202.50/4.5x1)= Rs. 4500.   Now,P = Rs. 4500,R = 5% ,T = 1 year.   S.I. = Rs.(4500x5x1/1000 = Rs. 225.   ∴ Difference in interest = Rs. (225 - 202.50)= Rs. 22.50.   Answer Rs. 22.50
Answer: B
If an amount of Rs 42,900 is distributed equally
amongst 22 persons, how much amount would each
person get? Select.
A) Rs 1950 B) Rs 2000 C) Rs 745 D) Rs 765 E) None

Solution: Required amount =42900/22= 
42900/22 = 1_950
Rs 1950   Rs 1950nswer Rs 1950
Answer: A
When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water? Choose the correct option:
A) 1.2 kg
B) 1.5 kg
C) 1.7 kg
D) 1.9 kg
E) None of these

Solution: Explanation :   Flower-nectar contains 50% of non-water part.   In honey this non-water part constitutes 85% (100-15).   Therefore 0.5 X Amount of flower-nectar = 0.85 X Amount of honey = 0.85 X 1 kg   Therefore amount of flower-nectar needed =   (0.85/0.51)kg=1.7 kgs   Answer : 1.7 kg
Answer: C
A particular library has 300 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 244 books in the special collection at that time, how many books of the special collection were loaned out during that month?
Select the correct option
A) 120 B) 140 C) 160 D) 180 E) 200

Solution: The total number of books is 300.   Let x be the number of books which were loaned out.   65% of books that were loaned out are returned.   35% of books that were loaned out are NOT returned.   Now, there are 244 books, thus the number of un-returned books is 300-244= 
300-244 = 56
56 books.   0.35x= 56   x = 160   The answer is 160.
Answer: C
What least number should be added to 1019, so that the sum is completely divisible by 25?  Choose the correct choice from the following answers
A) 4  B) 3  C) 2  D) 0  E) 6

Solution: 1019 Ã· 25 = 40 with remainder = 19   19 + 6= 
19 + 6 = 25
25.   Hence 6 should be added to 1019 so that the sum will be divisible by 25   Answer: Option 6
Answer: E
When N is divided by T, the quotient is S and the remainder is B. Which of the following expressions is equal to N?	Answers.
A) ST
B) S + V
C) ST + B
D) T(S+V)
E) T(S – V)

Solution: Using the rule dividend = Quotient * divisor + remainder =>ST + B ST + B is correct
Answer: C
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran share in the profit?  Choose the correct choice:
A) Rs 9500
B) Rs 10,000
C) Rs 10,500
D) Rs 11,000
E) Rs 14,000

Solution: Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.   Simran's share = Rs.24500 x	3/7	= Rs. 10,500.   ANSWER :Rs 10,500
Answer: C
The positive number a is q percent greater than the positive number b, which is p percent less than a itself. If a is increased by p percent, and the result is then decreased by q percent to produce a positive number c, which of the following could be true?
I. c > a
II. c = a
III. c < a
Choose the correct choice from the following answers
A) I only	B) II only	C) III only	D) I and II only	E) II and III only

Solution: a = (1 + q%)b   b = (1-p%)a   a = (1 + q%)*(1-p%)a   So (1 + q%)(1 - p%) = 1 = No change   One easy solution to this would be q = 0 and p = 0. In that case, a = b = c. So statement II can hold.   Assuming p and q are not 0,   (1 + q%)(1 - p%) = 1 = No change   So if you increase something by q% (it becomes bigger) and then decrease it by p% (now you will need to decrease it by a lesser %), there is no change.   Such as, you increase 100 by 25% and it becomes 125. Then you decrease 125 by only 20% and it comes back to 100. (This should remind you of cost price, sale price, profit and margin). So q would be a higher percentage than p.   Now if you increase something by p% (the lower %) and then decrease by q% (the higher %), the value you will obtain will certainly be lower than original.   Say you increase a (100) by p% (20%) to get 120 and then decrease it by q% (25%), you will get c (90). Hence c < a is possible too.   Answer (II and III only)
Answer: E
what is next no. 11 23 47 83 131 191 263 347 443???	Pick:  A) 171  B) 181  C) 191  D) 551  E) 211

Solution: 11+12*1= 
11+12*1 = 23
23   23+12*2= 
23+12*2 = 47
47   47+12*3= 
47+12*3 = 83
83   83+12*4= 
83+12*4 = 131
131   131+12*5= 
131+12*5 = 191
191   191+ 12*6= 
191+ 12*6 = 263
263   263+12*7= 
263+12*7 = 347
347   347+12*8= 
347+12*8 = 443
443   443+12*9= 
443+12*9 = 551
551   ANSWER:551
Answer: D
The product of all the prime numbers less than 30 is closest to which of the following powers of 10 ?
Options:
A) 10^9	B) 10^8	C) 10^7	D) 10^6	E) 15*10^5

Solution: 2*3*5*7*11*13*17*19   2*19*3*17*5*13*7*11   38*51*65*77   By approximation   40*50*70*70   2000*4900   By approximation   3000*5000   1,500,000   15*10^5
Answer: E
After 10% of the inhabitants of a village disappeared, a panic set in during which 25% of the remaining inhabitants left the village. At that time, the population was reduced to 5130. What was the number of original inhabitants?	Choose the correct choice from the following answers:	A) 7300	B) 7600	C) 7900	D) 8200	E) 8500

Solution: Let the total number of original inhabitants be x.   (75/100) * (90/100) * x = 5130   (27/40) * x = 5130   x = 5130 * 40 / 27= 
5130 * 40 / 27 = 7_600
7600   The answer is 7600.
Answer: B
A 400 meter long train crosses a platform in 45 seconds while it crosses a signal pole in 30 seconds. What is the length of the platform?	Choose the correct choice from the following answers.
A) 200	B) 400	C) 350	D) 1800	E) 45

Solution: Speed = [400 / 30] m/sec = 40/3 m/sec.   Let the length of the platform be x meters.   Then, x + 400 / 45= 40/3   3(x + 400) = 1800 è x = 200 m. 200nswer: 200
Answer: A
Aravamudhan, Balakrishnan and Chinnan work in a developing software company in starting level positions. However their salaries are different. Aravamudhan's salary to Balakrishnan's salary and Balakrishnan's salary to Chinnan's salary are in the ratio 4:3. If the total salary of all the three employees is Rs.29230, what is the salary of Chinnan?
Pick.
A) Rs.12640
B) Rs.9480
C) Rs.7110
D) Rs.8660
E) Rs.9660

Solution: making them in equal proportion of Aravind:Bala:Rs.7110innana=16:12:9   and given total salary 37*x=29230   x=790   Rs.7110hinnana salary is 9*790= 
9*790 = 7_110
7110   ANSWER:Rs.7110
Answer: C