MU-NLPC/Calc-aqua_rat huggingface dataset:
Cars emerging from a motorway arrive at a junction that splits the road into two separate lanes. The number of cars per hour that continue in either lane is constant. If 70 cars per hour were diverted from the left lane to the right lane, the number of cars entering the right lane per hour would be twice as big as the number of cars entering the left lane per hour. Alternatively, if 70 cars per hour were diverted from the right lane to the left lane, the number of cars entering the left lane per hour would be four times as great as the number of cars entering the right lane per hour. How many cars enter the left lane per hour?	Choose the most appropriate option
A) 140  B) 170  C) 210  D) 265  E) 235

Solution: as per question 70 cars diverted from left lane to right lane. Thus we get equation R+70=2(L-70)   as per question 70 cars diverted from right lane to left lane .thus we get equation L+70=4(R-70)   by solving two equation i.e R +70 =2L-140 OR. R =2L -210 AND L+70= 4R -280 OR L= 4R -3500   170Y SOLVING WE GET L= 4( 2L -210) -350 OR L= 8L -840-350 OR 1190 =7L THUS L =170   170
Answer: B
The first three terms of a proportion are 4, 12 and 16. The fourth term is? Choose the correct answer
A) 22
B) 28
C) 27
D) 36
E) 48

Solution: (12*16)/4= 
(12*16)/4 = 48
48   Answer:48
Answer: E
When 40 per cent of a number is added to another number the second number increases to its 140 per cent. What is the ratio between the first and the second number?
Choose one
A) 1 : 1	B) 4 : 3	C) 3 : 2	D) Data inadequate	E) None of these

Solution: Let the first and the second numbers be x and y respect then   y + 40% of x = 140% of y   or, y + 0.4x = 1.4y   or, 0.4x = 0.4y   ∴ x : y = 0.4 : 0.4 = 1 : 1   1 : 1nswer 1 : 1
Answer: A
If 3x + 7 = x2 + M = 7x + 5, what is the value of 120% of M?
Select the correct option.
A) 8.9	B) 9.9	C) 9.98	D) Cannot be determined	E) None of these

Solution: If 3x + 7 = x2 + M = 7x + 5   ie, 3x + 7 = 7x + 5   or, 4x = 2 ∴ x = 1⁄2   and 3x + 7 = x2 + M   or, 1⁄4 + M = 3⁄2 + 7 ⇒ M + 1⁄4 = 8 + 1⁄2   ∴ M = 81⁄4   Answer 9.9
Answer: B
Population of a city in 20004 was 1000000. If in 2005 there isan increment of 15% , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45%, then find the population of city atthe end of the year 2007
Choose one.
A) 354354 B) 545454 C) 465785 D) 456573 E) 1083875

Solution: Required population = P (1 + R1/100)(1 - R2/100)(1 + R3/100)   = P (1 + 15/100)(1 - 35/100)(1 + 45/100)   = 1083875   1083875
Answer: E
Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 168 and for 36kgs of Apples is 186 then the cost of first 20 kgs of Apples is Answers:  A) 3.69  B) 3.66  C) 3.6  D) 100  E) 3.61

Solution: Ans: By framing equations we get   30L+3Q=168   30L+6Q=186   Eliminate Q by multiplying the first equation by 2 and subtracting second equation from the first   30 L = 150 => L = 5   Then we get L = 5   Cost of 20 kgs of apples = 20 x 5 =100   Answer:100
Answer: D
A train speeds past a pole in 15 sec and a platform 110 m long in 25 sec, its length is? Select the correct option:	A) 50 m	B) 165 m	C) 200 m	D) 300 m	E) None of these

Solution: Let the length of the train be x m and its speed be y m/sec.   Then, x/y = 15 => y = x/15   (x + 110)/25 = x/15 => x = 165 m.   ANSWER:165 m
Answer: B
Triangle A’s base is 10% greater than the base of triangle B, and A’s height is 10% less than the height of triangle B. The area of triangle A is what percent less or more than the area of triangle B?  Choose the correct choice:
A) 9 % less	B) 1 % less	C) Equal to each other	D) 1 % more	E) 9 % more

Solution: Base of A = 11/10 * Base of B   Height of A = 9/10 * Height of B   Area of A = (1/2) * Base of A * Height of A = 11/10 * 9/10 * Area of B = 99/100 * Area of B   Area of A is 1% less than the area of B.   Answer (1 % less)
Answer: B
When the integer k is divided by 7, the remainder is 1. Which of the following expressions below when divided by 7, will have a remainder of 5?
I. 4k + 1
II. 6k + 6
III. 8k + 2  Choose the correct choice from the following options:
A) I only B) II only C) III only D) I and II only E) I, II and III

Solution: k = 7j + 1   4k + 1 = 28j + 4 + 1 = 28j + 5   6k + 6 = 42j + 6 + 6 = 42j + 7 + 5   8k + 2 = 56j + 8 + 2 = 56j + 7 + 3   The answer is I and II only.
Answer: D
If “&” implies “Add”, “@” implies “multiply”, “#” implies “subtract”, “$” implies “division”,
12 & 3 @ 2 # 32 $ 4 = ?
Choose the correct choice from the following answers:
A) 12 B) 10 C) 13 D) 14 E) None of these

Solution: Explanation:   Given:   12 & 3 @ 2 # 32 $ 4 = ?   10y substituting appropriate mathematical symbols, we get,   12 + 3 * 2 – 32/4 = ?   12 + 3 * 2 – 8 = ?   12 + 6 – 8 = ?   18 – 8 = 10   ANSWER IS 10
Answer: B
what is next no. 11 23 47 83 131 ???  Select
A) 171	B) 181	C) 191	D) 201	E) 211

Solution: 11+12*1= 
11+12*1 = 23
23   23+12*2= 
23+12*2 = 47
47   47+12*3= 
47+12*3 = 83
83   83+12*4= 
83+12*4 = 131
131   131+12*5= 
131+12*5 = 191
191   ANSWER:191
Answer: C
Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/7 full and other jar 1/6 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water?	Choose the correct choice from the following options
A) 1/7 B) 7/12 C) 1/2 D) 2/7 E) 2/3

Solution: Same amount of water made bigger jar 1/7 full, then the same amount of water(stored for a while in smaller jar) were added to bigger jar, so bigger jar is 1/7+1/7=2/7 full.   Answer: 2/7.
Answer: D
A can do a work in 15 days and B in 20 days. If they work on it together for 5 days, then the fraction of the work that is left is :  Pick one.
A) 1/3	B) 7/12	C) 5/12	D) 2/3	E) 1/2

Solution: Ans is:C   A's 1 day's work =1/15   B's 1 day's work =1/20   (A + B)'s 1 day's work =(1/15+1/20)=7/60   (A + B)'s 5 day's work =(7/60*5)=7/12   Therefore, Remaining work =(1-7/12)=5/12. Answer: 5/12
Answer: C
In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got?
Choose one.
A) 2800 B) 2700 C) 2100 D) 2500 E) None of these

Solution: Explanation :   Total number of votes = 7500   Given that 20% of Percentage votes were invalid   => Valid votes = 80%   Total valid votes = 7500 × (80/100)   1st candidate got 55% of the total valid votes.   Hence the 2nd candidate should have got 45% of the total valid votes   => Valid votes that 2nd candidate got = total valid votes × (45/100)   = 7500 × (80/100) × (45/100) = 75 × 45 × 45 = 75 × 4 × 9 = 300 × 9 = 2700   Answer : Option 2700
Answer: B
In the first 10 overs of a cricket game, the run rate was only 3.8. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? Choices.
A) 6.25  B) 6.5  C) 6.75  D) 6.1  E) 8

Solution: 10 overs - run rate = 3.8   runs scored in first 10 overs = 38   remaining overs 40   total runs to be scored= 282   38 runs already scored 282-38= 
282-38 = 244
244   244 runs to be scored in 40 overs   let required runrate be x   40*x=244   x=244/40= 
244/40 = 61/10 = around 6.1
6.1   the required runrate is 6.1   ANSWER:6.1
Answer: D
A sum fetched a total simple interest of 4025.25 at the rate of 9 %.p.a. in 5 years. What is the sum?	Choices:  A) 5768  B) 8925  C) 2345  D) 8945  E) 8723

Solution: Principal = (100 x 4025.25)/(9 x 5)   = 402525/45= 
402525/45 = 8_945
8945.   ANSWER 8945
Answer: D
A man buys an article for $110. and sells it for $125. Find the gain percent?	Choose the correct choice from the following
A) 10%  B) 13.6%  C) 25%  D) 20%  E) 30%

Solution: C.P. = $110   S.P. = $125   Gain = $15   Gain% = 15/110 *100 = 13.6%   Answer is 13.6%
Answer: B
A car takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?  Choose the correct option
A) 55 Kmph  B) 60 Kmph  C) 65 Kmph  D) 70 Kmph  E) 80 Kmph

Solution: Time = 6   Distence = 540   3/2 of 6 hours = 6 * 3/2= 
6 * 3/2 = 9
9 Hours   Required speed= 540/9= 
540/9 = 60
60 Kmph   60 Kmph)
Answer: B
The operation T is defined by x T y=1/x+1/y for all nonzero numbers x and y. If z is a number greater than 1, which of the following must be true.
I. z T (-z)=0
II. z T z/z-1=0
III. 2/z T 2/z=z Choose the correct choice from the following answers:	A) a.) I	B) b.) I and II only	C) c) I and III only	D) d) II and III only	E) e) I, II and III only

Solution: Statement I is TRUE   Statement II is not TRUE   Statement III is TRUE   Answer : c) I and III only
Answer: C
A factory has three types of machines, each of which works at its own constant rate. If 7 Machine As and 11 Machine Bs can produce 525 widgets per hour, and if 8 Machine As and 22 Machine Cs can produce 600 widgets per hour, how many widgets could one machine A, one Machine B, and one Machine C produce in one 8-hour day?  Choose the correct choice from the following answers:
A) 400
B) 475
C) 550
D) 625
E) 600

Solution: Let Machine A produce A widgets per hour. B produce B widgets per hour and C produce C widgets per hour.   7A+11B=525 ---(1)   8A+22C=600 ---(2)   Dividing (2) by 2   4A+11C=300.....(3)   Adding (1)(3)   11A+11B+11C = 825   A+B+C=75 per hour   So for eight hrs = 75*8= 
75*8 = 600
600= Answer = 600
Answer: E
How many odd numbers between 10 and 1,100 are the squares of integers? Select the correct option.
A) 12	B) 13	C) 14	D) 15	E) 16

Solution: The square of an odd number is an odd number:   10 < odd < 1,000   10 < odd^2 < 1,000   3.something < odd < 31.something (by taking the square root).   So, that odd number could be any odd number from 5 to 31, inclusive: 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, and 31.   15 numbers.   Answer: 15.
Answer: D
six boys picked up 30 mangoes .In how many ways can they divide them if all mangoes be identical?
Options:
A) A)4^30
B) B)2^30
C) C)1^30
D) D)3^30
E) E)6^30

Solution: 6^30ach Mango can be given to any one of the four people or in other words..1 mango can be divided into 6 ways...so all 30 can be divided in 6^30 ways   ANS:6^30
Answer: E
Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? Choose the correct choice from the following.
A) 22
B) 98
C) 60
D) 88
E) 12

Solution: Let the speed of the slower train be x m/sec.   Then, speed of the train = 2x m/sec.   Relative speed = ( x + 2x) = 3x m/sec.   (100 + 100)/8 = 3x => x = 25/3.   So, speed of the faster train = 50/3 = 50/3 * 18/5= 
50/3 * 18/5 = 60
60 km/hr.   Answer:60
Answer: C
If the weight of 12 meters long rod is 14 kg. What is the weight of 6 meters long rod ? Choose the correct choice from the following answers.
A) 8 kg. B) 10.8 kg. C) 7 kg. D) 18.0 kg E) None

Solution: Answer   ∵Weight of 12 m long rod = 14 kg   ∴ Weight of 1 m long rod = 14 / 12 kg   ∴ Weight of 6 m long rod = 14 x 6 / 12   = 7 kg   Option: 7 kg.
Answer: C
Cost of 16 mirror and 8 comb is Rs.352 and the cost of 4 mirror and 4 comb is Rs.96. Find the cost of each mirror? Options:  A) 10  B) 12  C) 20  D) 21  E) 22

Solution: Let the cost of each pen and pencil be 'p' and 'q' respectively.   16m + 8c = 352 --- (1)   4m + 4c = 96   8m + 8c = 192 --- (2)   (1) - (2) => 8p = 160   => m = 20   20
Answer: C
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?  Choose the correct option:
A) 23/35
B) 23/39
C) 23/33
D) 23/31
E) 23/34

Solution: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.   Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green   = (⁶C₁ * ⁹C₁)/¹⁵C₂ + ⁶C₂/¹⁵C₂   = (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7   = 46/70 = 23/35   23/35nswer: 23/35
Answer: A
If a randomly selected non-negative single digit integer is added to {2, 3, 4, 7}. What is the probability that the median of the set will increase but the range still remains the same? Choose the correct choice from the following choices.
A) 0.2 B) 0.3 C) 0.4 D) 0.5 E) 0.6

Solution: We are selecting from non-negative single digit integers, so from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. These 10 digits represent the total number of outcomes.   Hence, the total number of outcomes is 10.   We need to find the probability that the median of the set will increase but the range still remains the same.   The median of the set is  (3 + 4)/2= 
 (3 + 4)/2 = 7/2 = around 3.5
3.5, thus the number selected must be 4 or greater.   For the range to remain the same, the number must be between 2 and 7 inclusive.   To satisfy both conditions, the number selected must be 4, 5, 6, or 7.   The probability is  4/10= 
 4/10 = 2/5 = around 0.4
0.4   The answer is 0.4.
Answer: C
The denominator of a fraction is 2 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?
Pick one.
A) A)2/3
B) B)3/5
C) C)4/9
D) D)5/9
E) E) None of these

Solution: Let the numerator and denominator of the fraction be 'n' and 'd' respectively.   d = 2n - 2   (n + 1)/(d + 1) = 3/5   5n + 5 = 3d + 3   5n + 5 = 3(2n - 2 ) + 3 => n = -8   d = 2n - 2 => d = -18   Hence the fraction is : 4/9   ANSWER:4/9
Answer: C
99,996^2 - 4^2 =	Choose one.
A) 10^10 - 2 B) (10^5 – 2)^2 C) 10^5(10^5 – 8) D) 10^5(10^4 – 2) E) 10^5(10^5 – 2)

Solution: (99,996)^2 - (4)^2 = (100,000 -4)^2 - (4)^2 = (100,000)^2 - 2*4*100,000 + 4^2-4^2=(10^5)^2 - 8*(10^5) = 10^10 - 8*(10^5)=10^5(10^5 - 8) Answer 10^5(10^5 – 8)
Answer: C
Cassandra invested one part of her $10,000 at 7.5% per year and the other part at 8.5% per year. Her income from the two investment was $820. How much did she invest at each rate? Answers:
A) x = $2000 and y = $7000
B) x = $4000 and y = $7000
C) x = $3000 and y = $7000
D) x = $5000 and y = $7000
E) x = $6000 and y = $7000

Solution: Let x and y be the amount invested at 7.5% and 8.5% respectively   Income = $820 = 7.5% * x + 8.5% * y   The total amount invested is also known   10,000 = x + y   Solve the system of the equations to find x and y.   x = $3000 and y = $7000   Answer x = $3000 and y = $7000
Answer: C
The ratio of the cost price and selling price is 4:5. The profit percent is?
Pick: A) 20% B) 25% C) 30% D) 50% E) 15%

Solution: Let the C.P. = $4x   Then S.P. = $5x   Then, Gain = 5x-4x = $x   Gain% = x/4x *100 = 25%   Answer is 25%
Answer: B
Reema took a loan of Rs 1100 with simple interest for as many years as the rate of interest. If she paid Rs. 704 as interest at the end of the loan period, what was the rate of interest.	Choose the correct choice from the following choices: A) 5% B) 6% C) 7% D) 8% E) 9%

Solution: Explanation:   Let rate = R% then Time = R years.   =>1100∗R∗R /100=704   =>R2=64   =>R=8%   Option 8%
Answer: D
Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
Choose the correct choice from the following answers.
A) Rs.589 B) Rs.518 C) Rs.519 D) Rs.540 E) Rs.528

Solution: A+B+C = 1170   4A = 3B = 2C = x   A:B:C = 1/4:1/3:1/2 = 3:4:6   6/13 * 1170 = Rs.540   Answer: Rs.540
Answer: D
Mrs. Anderson divided $420 evenly among her children. Later, when Mrs. Anderson was away, Daniel, the eldest, took $5 from each of his brothers and sisters. Daniel ended up with $90. If Mrs. Anderson has more than 7 children, how many children does Mrs. Anderson have?	Choices:
A) 12
B) 14
C) 16
D) 18
E) 20

Solution: Let no of children be x   Even share as per initial division = 420/x   Daniel took $5 from each of his brother & sisters = 5(x-1)   so, 420/x + 5(x-1) = 90   5x^2 -95x + 420 = 0   x^2 - 19x + 84 = 0   Solving for X, x = 12 or x =7   Since we are given that x > 7, so no of children = 12   Option 12.
Answer: A
If the sum of two integers is 6, then it must be true that
Answers: A) both integers are even B) both integers are odd C) both integers are positive D) if one integer is negative, the other is positive E) if one integer is positive, the other is negative

Solution: We're asked to find a statement that MUST be true. So, if we can find a case where a statement is false, we can ELIMINATE that answer choice.   (A) both integers are even : it could be the case that the numbers are 1 and 5. ELIMINATE A   (B) both integers are odd : it could be the case that the numbers are 2 and 4. ELIMINATE B   (C) both integers are positive : it could be the case that the numbers are -1 and 7. ELIMINATE C   (D) if one integer is negative, the other is positive : Can't think of a counterexample so KEEP D for now   (E) if one integer is positive, the other is negative : it could be the case that the numbers are 1 and 5. ELIMINATE E   By the process of elimination, the correct answer is if one integer is negative, the other is positive
Answer: D
A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6100?	Choose the correct choice from the following options.
A) Rs. 5870  B) Rs. 5991  C) Rs. 6470  D) Rs. 6850  E) None of these

Solution: Explanation:   Total sale for 5 months = Rs. (5420 + 5660 + 6200 + 6350 + 6500) = Rs. 30,130   Therefore, required sale = Rs. [(6100 * 6) – 30,130] = Rs. (36600 – 30,130) = Rs. 6470   ANSWER Rs. 6470
Answer: C
The probability that a visitor at the mall buys a pack of candy is 40%. If three visitors come to the mall today, what is the probability that exactly two will buy a pack of candy?	Choose the correct choice from the following:
A) .288	B) .147	C) .189	D) .063	E) .027

Solution: One case is: candy - candy - no candy   The probability is 4/10*4/10*6/10 = 96/1000   There are 3 such cases, so we should multiply this probability by 3.   P(exactly 2 buy candy) = 96/1000 * 3 = 288/1000= 
288/1000 = 36/125 = around 0.288
0.288   The answer is .288.
Answer: A
A bus and a truck are available to cross a jungle. The speed of the truck is thrice that of the bus. The capacity of the truck is 50 persons and that of bus is 30 persons. The average occupancy of the bus is twice that of the truck. The tickets for the bus and the truck cost Re 1 and Re 1.50 respectively. What is the ratio of the average rupee collection of the truck to that of the bus in a day? Assume there is no wastage time between trips and the occupancy of the bus/truck is defined as the ratio of the actual number of persons boarding it and its capacity.	Choose one.
A) 15:2	B) 15:4	C) 15:8	D) 15:7	E) None of these

Solution: Explanation :   Average Rupee collection = Speed × capacity × Occupancy × Ticket rate.   The ratio of average Rupee collection of truck to that of bus is :-   =>(3×50×1×1.5):(1×30×2×1)=15:4.   Answer : 15:4
Answer: B
The markup on a shirt is 50 percent of the cost. The markup is what percent of the selling price?
(markup = selling price - cost)	Choose the correct answer.
A) 18% B) 20% C) 33 1/3% D) 45% E) 56 2/3%

Solution: MP = 0.5 CP   SP = CP + 0.5 CP = 1.5 CP   hence MP = 0.5/1.5 SP = 1/3 SP. Hence MP is 33.33 % of SP   Answer 33 1/3%
Answer: C
If the day after tomorrow will be Sunday, when was Thursday?	Choose the correct choice.
A) Today  B) Tomorow  C) Yesterday  D) The day before yesterday  E) none

Solution: Explanation:   Day after tomorrow will be Sunday   =>Tomorrow will be Saturday   => Today is a Friday   => Yesterday was a Thursday   Answer: Option Yesterday
Answer: C
Median H of price of the car is 52,000. which could be the median of the other two.
35000, 44000, x, y, 57000. Pick one:
A) 38000 B) 47000 C) 48000 D) 51,000 E) 56,000

Solution: Median of the car is 52,000 therefore 52,000 is the middle number. Assuming Y >= X, X will have to be the median value i.e. 52,000. Therefore the remaining value would have to be between 52,000 and 57,000 inclusive. The only answer choice that fits H is 56,000.56,000
Answer: E
If â€˜PUNJABâ€™ is coded as â€˜GCEAABâ€™, then â€˜KERALAâ€™ is coded as
Choose the correct choice from the following answers
A) BEICCA	B) BIECAA	C) BEIACA	D) BIEACA	E) BEICAA

Solution: M=13,1+3=4=D   A=1=A   SIMILARLY,   K=11=1+1= 
1+1 = 2
2=B   E=5=E   R=18=9=I   A=1=A   L=12=3=BEIACA   A=I=A   BEIABEIACAA   ANSWER:BEIACA
Answer: C
The triplicate ratio of 2:4 is?
Choose the correct choice:
A) 1:64  B) 1:8  C) 1:34  D) 3:64  E) 5:64

Solution: 2^3: 4^3 = 8:64=1:8   ANSWER:1:8
Answer: B
A certain set of numbers has an average (arithmetic mean) of 10 and a standard deviation of 2.5. If X, a number in the set, is within 2 standard deviations from the average, then which of the following CANNOT be the value of X?
Pick one:	A) 2	B) 5.5	C) 6	D) 10	E) 14

Solution: average (arithmetic mean) of 10 and a standard deviation of 2.5   Since, X, a number in the set, is within 2 standard deviations   i.e. X, a number in the set, between 10+2*2.5 and 10-2*2.5   i.e. X, a number in the set, between 15 and 5   Option 2 (2) is not within 2 SD therefore   2nswer: Option 2
Answer: A
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 3600 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?	Choose the correct choice
A) 240  B) 250  C) 260  D) 270  E) 280

Solution: Given that the area of the square = 3600 sq.units   => Side of square = √3600 = 60 units   The radius of the circle = side of the square = 60 units   Length of the rectangle = 2/5 * 60= 
2/5 * 60 = 24
24 units   Given that breadth= 10 units   240rea of the rectangle = lb = 24 * 10= 
24 * 10 = 240
240 sq.units   240nswer: Option 240
Answer: A
The sum of two numbers is 33. Five times one number is equal to 6 times the other. The bigger of the two numbers is
Choose the correct choice from the following choices:	A) 10	B) 18	C) 15	D) 22	E) 24

Solution: Sol.   Let the numbers be x and (33 - x).   Then, 5x = 6(33 - x)   ⇔ 11x = 198⇔ x = 18.   So, the numbers are 18 and 15.   Answer 18
Answer: B
4, 12, 48, 240, 1440, (...) Pick:	A) 10080	B) 12000	C) 24000	D) 14400	E) 40000

Solution: Go on multiplying the given numbers by 3, 4, 5, 6, 7   10080nswer is 10080
Answer: A
The ratio between the radii of two spheres is 1:3. Find the ratio between their volumes?	Select the correct option:
A) 1:27	B) 27:1	C) 3:1	D) 1:3	E) 1:9

Solution: r1 : r2 = 1:3   r13 : r23 = 1:27   1:27NSWER 1:27
Answer: A
Set A = {2,3,4,5}
Set B = {4,5,6,7,8}
Two integers will be randomly selected from the sets above, one integer from Set A and one integer from Set B. What is the probability that the sum of the two integers will equal 9?
Pick one:
A) 0.20  B) 0.25  C) 0.30  D) 0.33  E) 0.39

Solution: Explanation :   Total numbers in n(S)=4×5=20.   =>n(E)=4. [(2,7), (3,6), (4,5), (5,4)].   The required probability :-   =>P(E)=n(E)/n(S).   =>4/20.   =>0.20.   0.20nswer : 0.20
Answer: A
If 80% of 90 is greater than 70% of a number by 30, what is the number?  Choose one
A) 70  B) 60  C) 10  D) 75  E) 85

Solution: Explanation:   80/100 * 90 - 70/100 * x = 30   72 - 70/100 * x = 30   72 - 30 = 70/100 *x   42 = 70/100 * x     42 * 100 / 70= 
  42 * 100 / 70 = 60
x   60= x   Answer: Option 60
Answer: B
In practical applications, battery voltage: Options
A) 22	B) 66	C) 76	D) 126	E) 81

Solution: Explanation:   No answer description available for this questio   Answer: Option 66
Answer: B
A tin of oil was 4/5 full. when 6 bottles of oil were taken out and four bottles of oil were poured into it, it was ¾ full. how many bottles of oil can the tin contain?  Choose the correct choice from the following options.
A) 20	B) 10	C) 40	D) 50	E) 20

Solution: Suppose x bottles can fill the tin completely   Then 4/5x-3/4x=6-4   X/20=2   X=40   Therefore required no of bottles =40   Answer is 40.
Answer: C