MU-NLPC/Calc-aqua_rat huggingface dataset:
In a certain random experiment, exactly one of the outcomes A, B, and M will occur. In each random experiment, the probability that outcome A will occur is 1/3 , and the probability that outcome B will occur is 1/3. What is the probability that when the random experiment is conducted 6 independent times, each of outcomes A, B, and M will occur twice?
Pick one:  A) 5/243  B) 1/12  C) 10/81  D) 1/6  E) 16/81

Solution: Number of ways in which a group of 2A,2B,2M can be formed in any order = 6!/(2!*2!*2!) [ formula for total of 6 items with 2 each of similar kind)   Total number of ways in which the die can be thrown independently = _ _ _ _ _ _ ; there are 6 places .First can be filled in 3 different ways A/B/M; Second in 3 diff ways again and so on.   So total number of ways = 3X3X3X3X3X3 = 3^6   There fore probability = 6!/(2!x2!x2!) by 3^6 = 90/3^6 = 10/81 Answer 10/81
Answer: C
A man buys a cycle for Rs. 1600 and sells it at a loss of 15%. What is the selling price of the cycle?  Select
A) s. 1090  B) s. 1360  C) s. 1190  D) s. 1202  E) s. 1256

Solution: S.P. = 85% of Rs. 1600 = Rs.85/100x 1600	= Rs. 1360   ANSWER :s. 1360
Answer: B
Which of the following data sets has the largest standard deviation? Choose the correct answer:
A) {1, 2, 3, 4, 5}
B) {2, 3, 3, 3, 4}
C) {2, 2, 2, 4, 5}
D) {0, 2, 3, 4, 6}
E) {-1, 1, 3, 5, 7}

Solution: since we are asked to compare 'standard deviation', we should look out for similarity between all the sets..   The SIMILARITY is - the SUM of all sets is equal =15..   and hence average = 15/5 = 3...   Now we have 5 different sets which have AVG as 3, so we will look for the spread of the other elements of set around the AVERAGE..   clearly E has a range of 7-(-1) or 8, and has the highest standard deviation..   ans {-1, 1, 3, 5, 7}
Answer: E
At present, the ratio between the ages of Arun and Deepak is 5:4. After 5 years, Arun's age will be 40 years. What is the age of Deepak at present?
Select.
A) 28  B) 26  C) 24  D) 22  E) 20

Solution: Let the present ages of Arun and Deepak be 5x and 4x years respectively.   Then, 5x + 5 = 40 => x = 7   Deepak's age = 4x = 28 years.   28nswer: 28
Answer: A
Twenty four men can do a work in 35 days. How many men are required to complete the work in 21 days?  Choose the correct option:	A) 11	B) 40	C) 99	D) 77	E) 21

Solution: We have M1 D1 = M2 D2   So, 24 * 35 = M2 * 21 => M2   = 40.   Answer: 40
Answer: B
An express traveled at an average speed of 100 km/hr, stopping for 3 min after every 75 kn. How long did it take to reach its destination 600 km from the starting point?	Choose the correct choice:
A) 5 hrs 21 min
B) 4 hrs 21 min
C) 6 hrs 41 min
D) 6 hrs 21 min
E) 4 hrs 34 min

Solution: D   6 hrs 21 min   Time taken to cover 600 km = 600/100= 
600/100 = 6
6 hrs.   Number of stoppages= 600/75 - 1= 
600/75 - 1 = 7
7   Total time of stoppages= 3 * 7= 
3 * 7 = 21
21 min   Hence, total time taken= 6 hrs 21 min.
Answer: D
In a kilometer race, A beats B by 20 meters or 10 seconds. What time does A take to complete the race?  Choose the correct option
A) 490 sec  B) 190 sec  C) 176 sec  D) 716 sec  E) 123 sec

Solution: Time taken by B run 1000 meters   = (1000 * 10)/20= 
(1000 * 10)/20 = 500
500 sec.   Time taken by A= 500 - 10= 
500 - 10 = 490
490 sec.   490 secnswer:490 sec
Answer: A
A group of 4 students bought movie tickets in one row next to each other. If Bob and Lisa are in this group, what is the probability that Bob and Lisa will each sit next to only one of the three other students from the group?	Pick one:
A) 5.55%
B) 16.67%
C) 15.75%
D) 20.45%
E) 25%

Solution: The question basically asks about the probability that Bob and Lisa sit at the ends.   The total # of sitting arrangements is 4!.   Desired arrangement is either BYZL or LYZB. Now, YZ can be arranged in 2! ways, therefore total # of favorable arrangements is 2*2!.   P=(favorable)/(total)=(2*2!)/4!=1/6.   Answer: 16.67%.(2*2 )/4= 
(2*2 )/4 = 1
1/6.   Answer: 16.67%.
Answer: B
AB
+BA
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141
In the addition problem above, A and B represent digits in two different two-digit numbers. What is the sum of A and B?  Choose the correct choice from the following answers.
A) 6
B) 8
C) 9
D) 11
E) 12

Solution: two ways to do it..   1) straight logic..   we can see that ones digit is 1 when units digit B and A are added..   only 12 fits in..   12
Answer: E
If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is:  Select the correct option:
A) 20:15:16 B) 20:15:11 C) 20:15:12 D) 20:15:18 E) 20:19:19

Solution: 6A = 8B = 10 20:15:12   A:B:20:15:12 = 1/6:1/8:1/10   = 20:15:12   Answer:20:15:12
Answer: C
Find the invalid no.from the following series 3, 7, 15, 27, 63, 127, 255
Choose the correct answer:
A) 3  B) 7  C) 27  D) 63  E) 127

Solution: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 27 is wrong.   27
Answer: C
(1.00001)(0.99999) - (1.00006)(0.99994) =	Choose the correct option.
A) 35(10^-10) B) 10^-10 C) 3(10^-10) D) 10^-5 E) 3(10^-5)

Solution: (1.00001*0.99999)-(1.00006*0.99994)   = (1+0.00001)(1-0.00001) - (1+0.00006)(1-0.00006)   = 1 - (0.00001)^2 - 1 + (0.00006)^2   = -(0.0000000001) + (0.0000000036)   = 0.0000000035=35(10^-10)   35(10^-10)nswer 35(10^-10)
Answer: A
Find ? x 11 = 555555 Pick one
A) 505 B) 5050 C) 50505 D) 5005 E) None of these

Solution: Answer   Let N x 11 = 555555   Then N = 555555 / 11= 
555555 / 11 = 50_505
50505.   50505orrect Option: 50505
Answer: C
In 1982 and 1983, Company B’s operating expenses were $12.0 million and $13.0 million, respectively, and its revenues were $15.6 million and $18.8 million, respectively. What was the percent increase in Company B’s profit (revenues minus operating expenses) from 1982 to 1983 ?
Choose the correct choice from the following choices.
A) 3%	B) 61 1/9%	C) 25%	D) 33 1/3%	E) 60%

Solution: Profit in 1982 = 15.6 - 12= 
15.6 - 12 = 3.6
3.6 million $   Profit in 1983= 18.8 - 13= 
18.8 - 13 = 5.8
5.8 million $   Percentage increase in profit= (5.8-3.6)/3.6 * 100 %   = 61 1/9 %   Answer 61 1/9%
Answer: B
Avg cost of 3 sharpners and 6 erasers is Rs.72. The avg cost of 6 sharpners and 8 erasers is Rs.112. Find the total cost of 20 sharpners and 20 erasers?	Select the correct option
A) 190  B) 160  C) 130  D) 200  E) 180

Solution: Avg cost of 3 sharpners and 6 erasers is Rs.72   (3 sharpner + 6 erasers) 9=72   therefore 1 sharpner cost is 72/9= 
72/9 = 8
8, so 3 sharpner cost is 3x8=24 and 6 erasers cost is 6x8=48   Again, avg cost of 6 sharpners and 8 erasers is Rs.112   (6 sharpner + 8 erasers) 14=112   therefore 1 sharpner cost is 112/14= 
112/14 = 8
8, so 6 sharpner cost is 6x8=48 and 8 erasers cost is 8x8=64   So 20 sharpner cost is (20/a)=160 and 20 erasers cost is (20x8)=160   ANSWER:160
Answer: B
Sachin is younger than Rahul by 4 years. If their ages are in the respective ratio of 7:9, how old is Sachin? Choose the correct option.
A) 24.9	B) 24.6	C) 24.2	D) 24.8	E) 24.5

Solution: Let Rahul's age be x years.   Then, Sachin's age = (x - 7) years.   (x - 7)/x = 7/9   2x = 63 => x = 31.5   Hence, Sachin's age = (x - 7) = 24.5 years.   Answer: 24.5
Answer: E
A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
Choose the correct choice from the following answers.
A) 9:1
B) 8:1
C) 9:8
D) 2:1
E) 1:1

Solution: Milk = 3/5 * 20= 
3/5 * 20 = 12
12 liters, water= 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6= 
12 - 6 = 6
6 liters   Remaining water= 8 - 4= 
8 - 4 = 4
4 liters   10 liters of pure milk are added, therefore total milk= (6 + 10)= 
(6 + 10) = 16
16 liters.   The ratio of milk and water in the new mixture= 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10= 
4/5 * 10 = 8
8 liters.   Amount of water removed= 2 liters.   Remaining milk = (16 - 8)= 
(16 - 8) = 8
8 liters.   Remaining water= (4 -2)= 
(4 -2) = 2
2 liters.   The required ratio of milk and water in the final mixture obtained= (8 + 10):2 = 18:2 = 9:1.   9:1nswer:9:1
Answer: A
In a game of 90 points, A can give B 5 points and C 15 points. then how many points B can give C in a game of 60?  Choices: A) 2.82 B) 7.82 C) 5.82 D) 12.82 E) 8.82

Solution: In a game of 90 points,A give B 5 points and c 25 points means B=85,C=65   In 85 points B give 15 since  80-65= 
 80-65 = 15
15   In 50 points B gives=50*15/85=8.82   ANSW8.82R:8.82
Answer: E
ABCD is a square where AB =âˆš6016. Let X be a point on AB and Y be a point on CD such
that AX = CY . Compute the area of trapezoid AXYD.  Answers
A) 3008 B) 2002 C) 1008 D) 2016 E) 3000

Solution: Note that trapezoids AXY D and BXY C are congruent, so the area of AXY D is   always   6016/2= 
6016/2 = 3_008
3008 .   correct answer 3008
Answer: A
12 is what % of 80?  Choose the correct answer:
A) 6
B) 6.67
C) 12
D) 13
E) 15

Solution: We assume that 80 is 100%   assume 'x' is value we looking for   here,   80 = 100% and   x% = 12   therefore,   100/x = 80/12   100/x = 6.6667   x = 15   15
Answer: E
33
a3
+4b
___
88
If a and b represent positive single digits in the correctly worked computation above, what is the value of the two digit integer ab?
Choose the correct choice from the following answers:
A) 12
B) 10
C) 13
D) 24
E) 34

Solution: 3+3+b=8   b=2   3+a+4=8   a=1   ab=12   ans=12
Answer: A
A train running at 1/4 of its own speed reached a place in 12 hours. How much time could be saved if the train would have run at its own speed? Options.
A) 9 hrs
B) 10hrs
C) 12hrs
D) 15hrs
E) 6hrs

Solution: time taken if run its own speed = 1/4*12= 
1/4*12 = 3
3 hrs   Time saved= 12 - 3= 
12 - 3 = 9
9 hrs   9 hrsnswer : 9 hrs
Answer: A
A collector collects stamps from foreign countries. In June, she gave 20 percent of her stamps to her friend. In July, she gave 35 percent of her remaining stamps to another friend. If these were the only changes in the number of stamps in the stamp collection during those two months, what percent of her collection at the beginning of June did she give to away in June and July? Choices:
A) 32%
B) 36%
C) 40%
D) 44%
E) 48%

Solution: Let x be the number of stamps in the original collection.   The percentage of the collection given away is:   0.2x + 0.35(0.8x) = 0.2x + 0.28x = 0.48x 0.2  + 0.28= 
0.2  + 0.28 = 0.48
0.48x= 48%   The answer is 48%.
Answer: E
How much pure alcohol should be added to 400ml of a 15% solution to make the strength of solution 32%? Choose the correct choice from the following options.
A) 100 ml  B) 60 ml  C) 120 ml  D) 130 ml  E) 150 ml

Solution: 400ml has 15% alcohol i.e 60ml . This means we have 340ml of water or the liquid with which alcohol is mixed   Let V be the volume of alcohol added to make the strength 32%   then V/340+V = 32/100. solving this we get V as 160ml   so we need to add   160 -60= 
  160 -60 = 100
100 ml of alcohol   100 mlNSWER:100 ml
Answer: A
The tailor has a 10 meter long piece of fabric for which to sew a ball room dress.
She has to cuts this fabric into strips of 200 centimeters each.
How long will it take the tailor to complete this tasks if each 200 centimeter took 5 minutes to cut ? Choose the correct option: A) 150 B) 200 C) 188 D) 245 E) 123

Solution: The tailors would need to cut the fabric 49 times thus the total amount spent would be 245 minutes. The answer is 245
Answer: D
Find the largest number of four digits which is exactly divisible by 26,18,12,15
Choose the most appropriate option
A) 9700  B) 9710  C) 9360  D) 9130  E) 9140

Solution: Explanation:   LCM of 26-18-12-15 is 2340.   After dividing 9999 by 2340 we get 639 remainder.   So answer will be 9999-639= 
9999-639 = 9_360
9360   Option 9360
Answer: C
Set R has a mean of 15 and a standard deviation of 1.5. We are going to add two additional numbers to Set S. Which pair of numbers would decrease the standard deviation the most?
Pick one.
A) {11,26} B) {18,19} C) {16,18} D) {16,16} E) {14,16}

Solution: The lesser the variance( values closer to mean) ,lower the standard deviation. As discussed in question the mean is 15,the values (14,16) are closer than others.   Hence Answer : {14,16}
Answer: E
Eggs are sold in packages of six or eleven only. If Doris bought 78 eggs exactly, what could be the number of large packs Doris bought?
Choose the correct choice from the following:
A) 6.  B) 2.  C) 3.  D) 5.  E) 4.

Solution: No strategy involved. Simple question demanding fast calculation.   11x6 = 66=> 78-66= 
78-66 = 12
12=> 12/6 is an integer   Ans A. 6.   Good luck
Answer: A
There 3 kinds of books in the library physics, chemistry and biology. Ratio of physics to chemistry is 3 to 2; ratio of chemistry to biology is 4 to 3, and the total of the books is more than 3000. Which one of following can be the total W of the book?
Choose the most appropriate option:
A) 3003 B) 3027 C) 3024 D) 3021 E) 3018

Solution: First, you have to find the common ratio for all 3 books. You have:   P:C:B   3:2 --> multiply by 2 (gives you row 3)   4:6   6:4:3   Hence:   P:C:B:T(Total)W   6:4:3:13 ----> This means, the Total Number must be a multiple of 13.   3003nswer 3003 is correct since 299 is divisible by 13, hence is 2990 and so is 3003 (2990+13).
Answer: A
The sum of squares of two numbers is 80 and the square of their difference is 36. The product of the two numbers is.
Choose the correct choice
A) 22	B) 44	C) 58	D) 116	E) None

Solution: Explanation :   Let the numbers be x and y . Then   x2+y2=80 and (x−y)2=36   (x−y)2=36⇒x2+y2−2xy=36   ⇒2xy=(x2+y2)−36=80−36=44   ⇒xy=22   Correct Option: 22
Answer: A
A salesperson receives a base salary of $900 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 210 items for $150 each, what will her monthly salary be?
Choose the correct choice
A) $1,500 B) $1,800 C) $2,100 D) $2,700 E) $2,800

Solution: Ans : 900+ 7.5 % * 150 * (210-50) = $ 2700   Answer $2,700
Answer: D
If both 112 and 33 are factors of the number a * 43 * 62 * 1311, then what is the smallest possible value of a? Pick one.
A) 121
B) 3267
C) 363
D) 33
E) None of the above

Solution: Explanatory Answer   Step 1: Prime factorize the given expression   a * 43 * 62 * 1311 can be expressed in terms of its prime factors as a * 28 * 32 * 1311   Step 2: Find factors missing after excluding 'a' to make the number divisible by both 112 and 33   112 is a factor of the given number.   If we do not include 'a', 11 is not a prime factor of the given number.   If 112 is a factor of the number, 112 should have been in 'a'   33 is a factor of the given number.   If we do not include 'a', the number has only 32 in it.   Therefore, if 33 has to be a factor of the given number 'a' has to contain 31 in it.   Therefore, 'a' should be at least 112 * 3 = 363 if the given number has 112 and 33 as its factors.   The smallest value that "a" can take is 363.   363hoice 363 is the correct answer.
Answer: C
Of the students at a certain high school, 90 percent took a course in algebra or geometry and 10 percent took courses in both. If the percent of students who took a course in algebra was 3 times the percent of students who took a course in geometry, what percent of the students took a course in algebra but not geometry?	Choose the correct choice:
A) 35%
B) 45%
C) 55%
D) 65%
E) 70%

Solution: You can also just use the formula   n(A or B) = n(A) + n(B) - n(A and B)   90 = 3X + X - 10   X = 25   3X = 75   This is the number of people who took algebra including those who took both. To get the number of people who took only algebra, 75 - 10 = 65%   Answer (65%)
Answer: D
If a certain sample of data has a mean of 25.0 and a standard deviation of 3.0, which of the following values is more than 2.5 standard deviations from the mean?  Pick one.
A) 12.0
B) 13.5
C) 17.5
D) 23.5
E) 26.5

Solution: The standard deviation is 3. 2.5 standard deviations, which is just 2.5 x 3.0 is 7.5. The only answer more than 7.5 away from the mean is 17.5.
Answer: C
At the time of marriage, a man was 7 years elder to his wife. 10 years after their marriage, his age is 4/3 times the age of his wife. What was wife's age at the time of marriage ? Choose one answer. Choices:
A) 36 years  B) 30 years  C) 26 years  D) 24 years  E) 11 years

Solution: let wifes age= x   husband age = x+7   now after 10 years of mrg x+10 wifes age   x+7+10 husbands age   4/3(x+10)=x+7+10   after solving x=11   ANSW11 yearsR:11 years
Answer: E
A 500 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?  Choose the most appropriate option:
A) 2 min 48 sec
B) 4 min 48 sec
C) 4 min 38 sec
D) 4 min 18 sec
E) 4 min 8 sec

Solution: S = 500/40= 
500/40 = 25/2 = around 12.5
12.5 mps   S= 3600/12.5= 
3600/12.5 = 288
288 sec= 4 min 48 sec   ANSWER:4 min 48 sec
Answer: B
If an amount of Rs 42,460 is distributed equally
amongst 22 persons, how much amount would each
person get?  Choose the correct choice from the following answers:
A) Rs 1905	B) Rs 2000	C) Rs 1930	D) Rs 765	E) None

Solution: Required amount =42460/22= 
42460/22 = 1_930
Rs 1930   Answer Rs 1930
Answer: C
What is the average of four tenths and two thousandths Choose the correct choice from the following options: A) 0.2022 B) 0.3325 C) 0.201 D) 0.2012 E) 0.2114

Solution: Explanation:   Four tenths = 0.4   two thousandths = 0.002   The average is (0.4 + 0.002)/2= 
(0.4 + 0.002)/2 = 0.201
0.201   Answer: 0.201
Answer: C
A factory has 500 workers, 18 percent of whom are women. If 50 additional workers are to be hired and all of the present workers remain, how many of the additional workers must be women in order to raise the percent of women employees to 20 percent?
Choose the correct choice from the following answers:
A) 3
B) 10
C) 20
D) 30
E) 35

Solution: Currently the factory has 0.18*500= 
0.18*500 = 90
90 women.   After 50 additional workers are hired, there will be total of 550 workers and we need 0.2*550= 
0.2*550 = 110
110 of them to be women, so we need 110-90= 
110-90 = 20
20 more women.   Answer: 20.
Answer: C
An airplane flies along the four sides of a square field at the speeds of 200, 400, 600 and 800 km/h. The average speed of the plane around the field in km/h is Choices:
A) 384 B) 400 C) 500 D) 284 E) None of these

Solution: Explanation :   Let each side of the square field be x km.   So, average speed of the plane   = 4x/((x/800)+(x/600)+(x/400)+(x/200))   = (4*2400)/(3+4+6+12) = 9600/25= 
9600/25 = 384
384   384nswer : 384
Answer: A
A can run 4 times as fast as B and gives B a start of 63 m. How long should the race course be so that A and B might reach in the same time?  Choose the correct choice from the following options.
A) 70 m  B) 60 m  C) 80 m  D) 65 m  E) 84 m

Solution: Speed of A:Speed of B=4:1   means in a race of 4m A gains 3m.   then in a race of 63m he gains 63*(4/3)   I.e 84m   ANSW84 mR:84 m
Answer: E
Find the amount on Rs.5000 in 2 years, the rate of interest being 4% per first year and 5% for the second year? Choose the correct choice from the following choices: A) 3377 B) 2678 C) 5460 D) 1976 E) 1671

Solution: 5000 * 104/100 * 105/100= 
5000 * 104/100 * 105/100 = 5_460
> 5460   Answer: 5460
Answer: C
A straight fence is to be constructed from posts 6 inches wide and separated by lengths of chain 9 feet long. If a certain fence begins and ends with a post, which of the following could not be the length of the fence in feet? (12 inches = 1 foot)	Pick one
A) 29  B) 48  C) 55  D) 67  E) 86

Solution: There is one post for each length of chain, plus one final post at the end.   The length of the fence in feet is 9.5x + 0.5, where each is the number of chain lengths.   The length of the fence is an integer when x = 1,3,5,7,...   The length of the fence could be 10, 29, 48, 67, 86,...   The answer is 55.
Answer: C
In how many ways can the letters of the word ED456 be rearranged such that the numbers always appear together? Choose the correct choice: A) 25 B) 16 C) 36 D) 9 E) 29

Solution: ED456   456 will come together as a group which can be arranged in 3!=6ways.   456,E,D can be arranged in 3!=6 ways.   total possible arrangements = 6*6= 
6*6 = 36
36 ways   ANSWER:36
Answer: C
A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?	Choose the correct choice:
A) 28
B) 29
C) 31
D) 35
E) 37

Solution: Explanation:   Clearly, we have :   A = B - 3 ...(i)   D + 5 = E ...(ii)   A+C = 2E ...(iii)   B + D = A+C = 2E ...(iv)   A+B + C + D + E=150 ...(v)   From (iii), (iv) and (v), we get: 5E = 150 or E = 30.   Putting E = 30 in (ii), we get: D = 25.   Putting E = 30 and D = 25 in (iv), we get: B = 35.   Putting B = 35 in (i), we get: A = 32.   Putting A = 32 and E = 30 in (iii), we get: C = 28.   28nswer: 28
Answer: A
Two employees X and Y are paid a total of Rs. 330 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Pick one
A) s.150  B) s.200  C) s.250  D) s.350  E) s.400

Solution: Let the amount paid to X per week = x   and the amount paid to Y per week = y   Then x + y = 330   But x = 120% of y = 120y/100 = 12y/10   âˆ´12y/10 + y = 330   â‡’ y[12/10 + 1] = 330   â‡’ 22y/10 = 330   â‡’ 22y = 3300   â‡’ y = 3300/22 = 300/2 = Rs.150   s.150)
Answer: A
A certain car increased its average speed by 4 miles per hour in each successive 5-minute interval after the first interval. If in the first 5-minute interval its average speed was 20 miles per hour, how many miles did the car travel in the third 5-minute interval?	Choose the correct choice from the following.
A) 1.0  B) 1.5  C) 2.0  D) 2.5  E) 3.0

Solution: In the third time interval the average speed of the car was 20+4+5= 
20+4+5 = 29
29 miles per hour;   In 5 minutes (1/12 hour) at that speed car would travel 29*1/12=2.5 miles.   Answer: 2.5.
Answer: D
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 24 kmph and 48 kmph. After how much time will the trains meet?  Pick:
A) 20/8 sec
B) 20/4 sec
C) 20/7 sec
D) 22/7 sec
E) 5 sec

Solution: They are moving in opposite directions, relative speed is equal to the sum of their speeds.   Relative speed = (24 + 48)*5/18 = 4*5= 
4*5 = 20
20 mps.   The time required= d/s = 100/20= 
100/20 = 5
5 sec.Answer:5 sec
Answer: E
A man sells a horse for Rs.800 and loses something, if he had sold it for Rs.980, his gain would have been double the former loss. Find the cost price of the horse?	Choose the correct choice from the following
A) 868	B) 869	C) 865	D) 860	E) 861

Solution: CP = SP + 1CP = SP - g   800 + x = 980 - 2x   3x = 180 => x = 60   CP = 800 + 60= 
800 + 60 = 860
860   Answer: 860
Answer: D
The measurement of a rectangular box with lid is 25cmx4cmx18cm. Find the volume of the largest sphere that can be inscribed in the box (in terms of πcm3). (Hint: The lowest measure of rectangular box represents the diameter of the largest sphere)
Choose the correct choice from the following:  A) 11.12  B) 10.11  C) 72  D) 10.66  E) 9.2

Solution: d=4, r=2;   Volume of the largest sphere= 4/3πr3   = 4/3 *π*2*2*2= 10.66πcm3 ANSWER:10.66
Answer: D
Length of a rectangular plot is 10 mtr more than its breadth. If the cost of fencing the plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr?	Pick one.
A) 55 m B) 60 m C) 80 m D) 82 m E) 84 m

Solution: Let breadth = x metres.   Then, length = (x + 10) metres.   Perimeter = 5300 m = 200 m.   26.50   2[(x + 10) + x] = 200   2x + 10 = 100   2x = 90   x = 45.   Hence, length = x + 10= 55 m   55 m
Answer: A