MU-NLPC/Calc-aqua_rat huggingface dataset:
The total price of a basic computer and printer are $2,500. If the same printer had been purchased with an enhanced computer whose price was $500 more than the price of the basic computer, then the price of the printer would have been 1/6 of that total. What was the price of the basic computer?
Choose the correct choice from the following options
A) 1500
B) 1600
C) 1750
D) 1900
E) 2000

Solution: Let the price of basic computer be C and the price of the printer be P: C+P=$2,500.   The price of the enhanced computer will be C+500 and total price for that computer and the printer will be 2,500+500=$3,000. Now, we are told that the price of the printer is 1/6 of that new total price: P=1/6*$3,000=$500.   Plug this value in the first equation: C+500=$2,500 --> C=$2000   Answer: 2000.
Answer: E
A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. The number is:	Select the correct option
A) 145
B) 253
C) 370
D) 352
E) 382

Solution: we can easily solve the ans using the result   all options are fullfill 1st condition ie the sum of digit is 10   now only 253 and D are full fill the 2nd condition ie middle digit = sum of the side digit   now finally 253 is the result bcze if we add two number the number must be increase but here if we reverse 352 then it become 253 but if we add 99 the itnever be a small number so thats why result is 253   ANSWER:253
Answer: B
A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : Choose the correct choice from the following answers.
A) 285	B) 377	C) 366	D) 288	E) 261

Solution: Since the month begins with a Sunday, there will be five Sundays in the month   Required average = (510 * 5 + 240 * 25) / 30 = 8550/30= 
8550/30 = 285
285   285nswer: 285) 285
Answer: A
There are two numbers. If 55% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number? Choose the correct choice from the following options
A) A)5/6  B) B)5/8  C) C)5/11  D) D)6/7  E) E)7

Solution: Let the two numbers be x and y.   55/100 * x + y = 5/4y   => 11/20 x = 1/4 y => x/y = 5/11   5/11)
Answer: C
In how many years Rs 100 will produce the same interest at 5% as Rs. 600 produce in 4 years at 10% Pick one.
A) 44 B) 52 C) 50 D) 46 E) 48

Solution: Explanation:   Clue:   Firstly we need to calculate the SI with prinical 600,Time 4 years and Rate 10%, it will be Rs. 240   Then we can get the Time as   Time = (100*240)/(100*5)= 
(100*240)/(100*5) = 48
48   Option 48
Answer: E
A worker's take-home pay last year was the same each month, and she saved the same fraction of her take-home pay each month. The total amount of money that she had saved at the end of the year was 4 times the amount of that portion of her monthly take-home pay that she did NOT save. If all the money that she saved last year was from her take-home pay, what fraction of her take-home pay did she save each month?	Choose the correct choice from the following answers
A) 1/3	B) 1/4	C) 1/5	D) 1/6	E) 1/7

Solution: Let x be the fraction of her take-home pay that the worker saved.   Let P be the monthly pay.   12xP = 4(1-x)P   12xP = 4P - 4xP   16xP = 4P   x = 1/4   The answer is 1/4.
Answer: B
How many digits are required to number a book containing 250 pages? Choose the correct choice from the following.
A) 756  B) 642  C) 492  D) 372  E) 250

Solution: 9 pages from 1 to 9 will require 9 digits.   90 pages from 10 to 99 will require   90*2= 
  90*2 = 180
180 digits.   250-(90+9)= 
250-(90+9) = 151
151 pages will require   151*3= 
  151*3 = 453
453 digits.   The total number of digits is 9+180+453= 
9+180+453 = 642
642.   The answer is 642.
Answer: B
In how many ways can the letters of the word ACTUAL be rearranged such that the vowels always appear together? Select.
A) 6!/2!  B) 3!*3!  C) 4!/2!  D) (4! *3!)/2!  E) 3!*3!/2

Solution: In the word ABACUS , there are 3 vowels - 2 A's and U   Number of ways the letters of word ACTUAL be rearranged such that the vowels always appear together   = (4! * 3! )/2!   We can consider the the 3 vowels as a single unit and there are 3 ways to arrange them . But since 2 elements of vowel group are identical we divide by 2! .   The entire vowel group is considered as a single group .   Answer (4! *3!)/2!
Answer: D
If x and y are both prime numbers greater than 10, which of the following CANNOT be true?
I. xy is an even number.
II. x - y = 117.
III.The sum of x and y is even.
Choose the correct choice from the following options:  A) A)I and II only  B) I only  C) I and III only  D) II and III only  E) I, II and III

Solution: MANHATTAN GMATOFFICIAL SOLUTION:   Since x and y are both prime numbers greater than 10, they must both be odd. Therefore xy must be an odd number, so Statement I cannot be true. Similarly, if x and y are both odd, then x - y cannot equal 117 (an odd number). This difference must be even. Therefore, Statement II cannot be true. Finally, since x and y are both odd, x + y must be even, so Statement III will always be true. Since Statements I and II CANNOT be true, but Statement III IS true,the correct answer is (D).   Answer : II and III only
Answer: D
There is a total of 84 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/4 and the probability that it will be green is 1/7. What is the probability that the marble will be either red or blue?  Choose the correct choice from the following choices:  A) 4/7  B) 9/14  C) 11/14  D) 17/28  E) 23/28

Solution: P(red or blue) = 1 - P(white) - P(green) = 28/28 - 7/28 - 4/28 = 17/28   The answer is 17/28.
Answer: D
A worker makes a toy in every 1h. If he works for 100h, then how many toys will he make ?
Choose the correct answer:  A) 40  B) 54  C) 45  D) 39  E) 100

Solution: No. of toys = 100/1= 
100/1 = 100
100   Answer : 100
Answer: E
A chessboard is an 8×8 array of identically sized squares. Each square has a particular designation, depending on its row and column. An L-shaped card, exactly the size of four squares on the chessboard, is laid on the chessboard as shown, covering exactly four squares. This L-shaped card can be moved around, rotated, and even picked up and turned over to give the mirror-image of an L. In how many different ways can this L-shaped card cover exactly four squares on the chessboard?
Options.
A) 256  B) 336  C) 424  D) 512  E) 672

Solution: Select 3 squares which are in a line together first. We will call them a block of 3 squares. Consider just the vertical arrangement for now (for horizontal, we will multiply everything by 2 at the end).   Consider a block of 3 squares lying vertically on the left edge (the first column of the chess board). You can place another square on the right to make an L at either extreme of the block. So for each such block, you can make an L in 2 ways. There will be 12 such blocks (6 on either edge).   You get 12*2 Ls.   Now consider the blocks of 3 squares lying vertically in columns 2 to 7. You can make an L by placing a square on left or right at either end. So for each block of 3 squares, you can make 4 Ls. There are 6 such blocks in each of the 6 columns   You get 6*6*4 Ls.   Total you get   12*2 + 6*6*4= 
  12*2 + 6*6*4 = 168
168 Ls.   Now you just multiply it by 2 to account for the Ls lying horizontally too. Since it is a square, the number of Ls found vertically will be the same as the number of Ls found horizontally.   Total= 168*2= 
168*2 = 336
336   Answer (336)
Answer: B
A dairyman pays Rs. 6.40 per liter of milk. He adds water and sells the mixture at Rs. 8per liter, thereby making 37.5% profit. The proportion of water to milk received by the customers is
Choose the most appropriate option
A) 1:10  B) 1:12  C) 1:15  D) 1:20  E) 1:25

Solution: Milk = m liters;   Water = w liters;   Cost of m+w liters = 6.4m;   Selling price of m+w liters = 8(m+w).   Given that 6.4m*1.375 = 8(m+w) --> w/m=1/10.   1:10nswer: 1:10.
Answer: A
A train speeds past a pole in 15 sec and a platform 150 m long in 25 sec, its length is?  Pick one.
A) 238  B) 150  C) 988  D) 177  E) 225

Solution: Let the length of the train be x m and its speed be y m/sec.   Then, x/y = 15 => y = x/15   (x + 150)/25 = x/15 => x = 225 m.   Answer: 225
Answer: E
The number 94 can be written as the sum of squares of 3 integers. Which of the following could be the difference between the largest and smallest integers of the 3?
Choose the correct choice.
A) 2
B) 5
C) 7
D) 8
E) 9

Solution: Notice that the question asks which of the followingcouldbe the difference between the largest and smallest integers, not must be. The 3 integers could be: +/-2, +/-3 and +/-9, so the difference could be 7, 11 or 12. Since only one of them is among the choices, then it must be the correct answer.   Answer: 7
Answer: C
The greatest common factor of two numbers is 5!. Which of the following can be the second number, if one of the numbers is 9!? Pick one:	A) 3(5!)	B) 4(5!)	C) 6(5!)	D) 5(5!)	E) 7(5!)

Solution: GCF is the product of common factors of the numbers involved.   GCF = 5!   a = 9! = 9*8*7*6*5!   b will certainly have 5! and cannot have any more common factors with a (as this will increase the GCF)   Looking at the answers only 5 (5!) and 9! will have GCF as 5!   Ans 5(5!)
Answer: D
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train catches and completely passes the slower train in 72 seconds. What is the length of each train (in meters)?
Choose the correct answer:
A) 70  B) 80  C) 90  D) 100  E) 110

Solution: The relative speed = 46 - 36= 
46 - 36 = 10
10 km/hr= 10 * 5/18 = 25/9 m/s   In 72 seconds, the relative difference in distance traveled is  72 * 25/9= 
 72 * 25/9 = 200
200 meters   This distance is twice the length of each train.   The length of each train is  200/2= 
 200/2 = 100
100 meters   The answer is 100.
Answer: D
A certain article of clothing was discounted during a special sale to 2/3 of its original retail price. When the clothing didn't sell, it was discounted even further to 1/2 of its original retail price during a second sale. By what percent did the price of this article of clothing decrease from the first sale to the second sale?
Choose the correct answer.
A) 50%	B) 22.22%	C) 25%	D) 16.66%	E) 12.5%

Solution: Say the original retail price of the item was $200.   The price after the first sale = 2/3 * $200 = $400/3.   The price after the second sale = 1/2 * $200 = $100.   The percent change from the first sale to the second 1/2 *  200= 
1/2 *  200 = 100
$100.   The percent change from the first sale to the second= (400/3 - 100) / 150 = 1/3 = 22.22%.   Answer: 22.22%.
Answer: B
In a lottery, there are 10 prizes and 20 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Choose the correct choice from the following
A) 1/10  B) 2/5  C) 1/3  D) 5/7  E) None

Solution: Solution   P(getting a prize)	= 10 / (10+20)   ‹=› 10 / 30   ‹=› 1/ 3.   Answer 1/3
Answer: C
In a 500 m race, Ravi beats Ramesh by 5 seconds or 100 m. They decide to run another race and this time Ravi gives Ramesh a head tart of 200 m. If Ravi’s speed is twice his previous speed and Ramesh’s speed is one and half times his previous speed, how far from the starting point should the winning post be so that they finish at the same time?
Choose the correct choice from the following options:
A) 500 m B) 1000 m C) 1500 m D) 2000 m E) 2500 m

Solution: Ravi beats ramesh by 5 sec or 100 mtr....means ramesh cover 100mtr in 5 sec....by this we can get ramesh speed in 20m/sec   20.............in 1 sec   500........in 500/20= 
500/20 = 25
25 sec(Ramesh's time)   so ravi take 20 sec to cover 500 mtr......by this we can get that ravis speed is 25m/sec   now assume x be the distance from staring line where we need to put the winning post.   According to question ravi’s speed will be  25*2= 
 25*2 = 50
50m/sec & ramesh’s speed will be   20*1.5= 
  20*1.5 = 30
30 m/sec   now assume x be the distance from staring line where we need to put the winning post.   they will take same time to reach the wining post.   500 ms ravi gives Ramesh a 200 m ahead start so he has to accede x meter and Ramesh has to accede (x-200) meter   Hence we may write,   x/50=(x-200)/30   x=500 meter   500 mNSWER:500 m
Answer: A
What is the Compound Interest on Rs.9500 at 6% p.a. compounded half-yearly for 1 1/2 years.	Select:	A) 810.91	B) 840.91	C) 880.91	D) 887.91	E) 980.91

Solution: Compound interest : A = P(1 + r/n)nt   A = 10,380.91   C.I. >> 10,380.91 - 9500 >> Rs. 880.91   Answer:880.91
Answer: C
Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards.last year each of them discovered that every tree in their own orchard bore exactly d same no of apples.further,if d 3rd farmer gives one apple to the 1st,& the 5th gives 3 to each of the 2nd & d 4th,they would all exactly have the same no of apples, what were d yields per tree in the orchards of d 3rd & 4th farmers?	Choose the correct choice: A) 8,9 B) 10,11 C) 11,12 D) 11,9 E) 11,8

Solution: Let a, b, c, d & e be the number of apples bored last year in each farmer's tree.   Given that 7a + 1 = 9b + 3 = 11c - 1 = 13d + 3 = 14e - 6   But the question is to find the number of apples bored per tree in 3rd nd 4th orchard.It is enough to consider 11c - 1 = 13d + 3..   Therefore 11 c - 1 = 13 d + 3   By trial and error method, we get the value for c and d as 11 and 9.   5th nd 4th   14e - 6 = 13d + 3   14e - 13d = 9   here if u put e=d=1, result ll be 1, e=d=2 difference ll be 2, .... e=d=9 ,result ll be 9   so e=9 , d=9   So 5ht tree ll give  14 * 9= 
 14 * 9 = 126
126 no. of apples   4th tree ll give  13 * 9= 
 13 * 9 = 117
117 no. of apples   for 5th nd 2nd   14 * 9 -6= 9 * b + 3   120=9b + 3   b = 13   So 2nd tree ll give  9 * 13= 
 9 * 13 = 117
117   A= 119 , per tree = 17   B= 117 , per tree = 13   C= 121, per tree = 11   D= 117, per tree = 9   E = 126 , per tree = 9   3'rd farmer have 11 apples per tree and   4'th farmer have 9 apples per tree.   ANSWER:11,9
Answer: D
Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ? Pick:
A) 17/27  B) 17/25  C) 17/76  D) 17/20  E) 17/23

Solution: n(S) = 20   n(Even no) = 10 = n(E)   n(Prime no) = 8 = n(P)   P(EᴜP) = 10/20 + 8/20 - 1/20   = 17/20   Answer: 17/20
Answer: D
Find the probability that a non leap year selected at random will have 53 Sundays	Options.
A) 6/7
B) 5/7
C) 4/7
D) 3/7
E) 1/7

Solution: There are 365 days in a leap year: 52 weeks and 1 more days. So, 52 Sundays and 1 days.   This 1 days can be {Mon, Tue, Wed, Thu, Fri, Sat,Sun} (7 cases). In order to have 53 Sundays we should have Sun case.   The probability of that is 1/7.   Answer: 1/7.
Answer: E
Of the 200 employees in a certain company, 25 percent will be relocated to City X and the remaining 75 percent will be relocated to City Y. However, 45 percent of the employees prefer City Y and 55 percent prefer City X. What is the highest possible number of employees who will be relocated to the city they prefer?  Answers:
A) 65
B) 100
C) 115
D) 130
E) 135

Solution: 110 prefer X (Group 1);   90 prefer Y (Group 2).   City Y needs 150 people: letall 90 who prefer Y (entire Group 2) be relocated there, the rest 60 will be those who prefer X from Group 1;   City X needs 40 people: 110-60=40 from Group 1 will be relocated to X, which they prefer.   So, the highest possible number of employees who will be relocated to the city they prefer is  90+40= 
 90+40 = 130
130.   Answer: 130.
Answer: D
Johnny has 4 classes. He averaged a mark of 83 in those classes. If Johnny takes night school and scores an 88 in the course, what will his new average be? Choose the correct choice from the following answers.
A) 83	B) 84	C) 85	D) 85.5	E) 86

Solution: (sum of the 4 marks)/4 = 83   sum of the 4 marks = 332   new sum = 332 + 88= 
332 + 88 = 420
420   new average= 420/5= 
420/5 = 84
84   ans: 84
Answer: B
A student chose a number, multiplied it by 7, then subtracted 150 from the result and got 130. What was the number he chose?  Pick one:	A) 40	B) 42	C) 44	D) 46	E) 48

Solution: Let x be the number he chose, then   7⋅x−150=130   7x=280   x=40   correct answer 40
Answer: A
The surface area of a cube is 1734 sq. cm. Find its volume Choose one:
A) 2334 cubic.cm
B) 3356 cubic.cm
C) 4913 cubic.cm
D) 3478 cubic.cm
E) None of these

Solution: Explanation:   Let the edge of the cube bea. Then,   6a2 = 1734   => a = 17 cm.   Volume = a3 = 173 = 4193 cm3   Answer: 4913 cubic.cm
Answer: C
A certain pilot flew 400 miles to City K at an average speed of 350 miles per hour with the wind and made the trip back at an average speed of 150 miles per hour against the wind. Which of the following is closest to the pilot’s average speed, in miles per hour, for the round-trip?	Choices.
A) 280 B) 210 C) 300 D) 310 E) 320

Solution: Avg speed = total distance/ total time   total distance = 800   total time = 400/350 + 400/150 = 80/21   => avg speed = (800*21)/80= 
(800*21)/80 = 210
210(approx)   ans is 210
Answer: B
The average of 11 numbers is 10.6. If the average of the first six numbers is 10.5 and that of the last six numbers is 11.4, then the middle number is	Answers:
A) 71.5	B) 11.5	C) 81.5	D) 14.8	E) 21.5

Solution: Explanation:   Middle numbers = [(10.5 x 6 + 11.4 x 6) - 10.6 x 11] = 14.8.   Answer: 14.8
Answer: D
A toy store regularly sells all stock at a discount of 10 percent. If an additional 10 percent were deducted from the discount price during a special sale, what would be the lowest possible price of a toy costing $10 before any discount?	Choices
A) $7.20
B) $8.00
C) $8.10
D) $8.27
E) $9.00

Solution: sale price = (original price - 10% decrease) - 10% decrease   price = [10 * (90/100)] * (90/100) = 10 * (.90) * (.90) = 9 * .90= 
9 * .90 = 8.1
8.10   The answer is $8.10.
Answer: C
A merchant gains or loses, in a bargain, a certain sum. In a second bargain, he gains 680 dollars, and, in a third, loses 80. In the end he finds he has gained 250 dollars, by the three together. How much did he gain or lose bv the first ?  Options.
A) -280  B) 300  C) -350  D) -380  E) None

Solution: In this sum, as the profit and loss are opposite in their nature, they must be distinguished by contrary signs. If the profit is marked +, the loss must be -.   Let x = the sum required.   Then according to the statement x + 680 - 80 = 250   And x = -350.   Answer -350
Answer: C
In a certain store, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?	Choose the correct choice from the following answers.
A) 30%
B) 70 percent
C) 100%
D) 120%
E) None

Solution: Solution   Let C.P. = Rs. 100.	Then, Profit = Rs.320,   S.P. = 420.   Let C.P. = Rs. 125% of Rs. 100	= Rs.125.   New S.P. = Rs.420.   Profit = Rs. (420 - 125)	= Rs.295.   ∴ Required percentage	= (295 / 420 x 100)%   = 1475 / 21%   = 70%.   Answer 70 percent
Answer: B
6+3+2 = 242116
8+9+1 = 727216
5+7+4 = 505644
2+7+5 =?	Pick:
A) 224210 B) 224220 C) 224230 D) 224240 E) 224250

Solution: 6+3+2 = 242116 = 6*(3+2-1) 3*(6+2-1) 2*(6+3-1)=6*4 3*7 2*8= 242116   8+9+1 = 727216   5+7+4 = 505644 = (5*10) (7*8) (4*11)   2+7+5 = 2*(7+5-1) 7*(2+5-1) 5*(2+7-1) = 224240   ANSWER:224240
Answer: D
The ratio 25:50 expressed as percent equals to
Choose the correct choice from the following choices:
A) 50 %
B) 85 %
C) 25 %
D) 75 %
E) None of above

Solution: Explanation:   50 %ctually it means 25 is what percent of 50, which can be calculated as,   (25/50)*100 = 25 * 2= 
25 * 2 = 50
50   50 %nswer: Option 50 %
Answer: A
Find the C.I. on a sum of Rs.10000 for 6 months at 25% per annum, interest being compounded quarterly?	Select.
A) 10290  B) 5290  C) 1289  D) 1290  E) 2290

Solution: 1289.I.= 2000(21/20)^2-1800   = 1289   Answer: 1289
Answer: C
If pqr < 0 and qr > 0, which of the following must be positive?	Choose the correct choice from the following answers:  A) xy  B) xz  C) (p^2)qr  D) p(q^2)r  E) xy(z^2)

Solution: Given that qr is positive and pqr is negative, you can say that p MUST be negative. As for q and r either they are both positive or both negative.   Option (C) has p^2 which is positive and qr which is positive. So ((p^2)qr) must be positive.
Answer: C
56 +57+58+59=230. How many such 4 consecutive numbers are there less than 500 when added gives a sum which is divisible by 10? Choose the correct choice from the following choices.
A) 100
B) 200
C) 300
D) 400
E) 500

Solution: since 1+2+3+4= 
1+2+3+4 = 10
10 & 6+7+8+9= 
6+7+8+9 = 30
30   any combination with these no be will give u desirable result...   so total no in 100 will be 20 & that's why in in 500,it will be 20x5=100.   100NSWER:100
Answer: A
Consider a quarter of a circle of radius 36. Let r be the radius of the circle inscribed in this quarter of a circle. Find r.
Choose one:  A) 16*(sqr2 -1)  B) 8*(sqr3 -1)  C) 4*(sqr7 - 1)  D) 36* (sqr2 -1)  E) None of these

Solution: I got 36/(sqr2 +1) and just forgot to multiply by (sqr2 -1).   Answer is 36* (sqr2 -1)
Answer: D
In how many ways can 8 Indians and, 4 American and 4 Englishmen can be seated in a row so that all person of the same nationality sit together?
Choose the correct choice from the following options:
A) 3!*8!*4!*4! ways B) 8!*4!*4! ways C) 3!4! ways D) 3!*5! ways E) 3!*6! ways

Solution: Taking all person of same nationality as one person, then we will have only three people.   These three person can be arranged themselves in 3! Ways.   8 Indians can be arranged themselves in 8! Way.   4 American can be arranged themselves in 4! Ways.   4 Englishman can be arranged themselves in 4! Ways.   Hence, required number of ways = 3!*8!*4!*4! Ways.   3!*8!*4!*4! waysNSWER 3!*8!*4!*4! ways
Answer: A
A woman named Ragavi started a business investing Rs. 7,000. Roja joined him after six months with an amount of Rs. 7,000 and Sachin joined them with Rs. 7,000 after another six months. The amount of profit earned should be distributed in what ratio among Ragavi, Roja and Sachin respectively, 3 years after A woman started the business ?
Options:  A) 7:6:10  B) 12:15:16  C) 42:45:56  D) 42:45:55  E) 6:5:4

Solution: 6:5:4xplanation :   Akash : Roja : Sachin = (7000 x 36) : (7000 x 30) : (7000 x 24)   = 36:30:24 => 6:5:4   Answer :6:5:4
Answer: E
Dan's age after 16 years will be 4 times his age 8 years ago. What is the present age of Dan? Select the correct option.
A) 12	B) 16	C) 20	D) 24	E) 28

Solution: Let Dan's present age be x.   x+16 = 4(x-8)   3x = 48   x = 16   The answer is 16.
Answer: B
A train covers a distance of 18 km in 10 min. If it takes 6 sec to pass a telegraph post, then the length of the train is?	Choose the correct choice:  A) 120m  B) 180m  C) 240m  D) 220m  E) 280m

Solution: Speed = (18/10 * 60) km/hr = (108 * 5/18) m/sec = 30 m/sec.   Length of the train = 30 * 6= 
30 * 6 = 180
180 m.   ANSWER:180m
Answer: B
Use distributive property to solve the problem below:
Maria bought 10 notebooks and 5 pens costing 3 dollars each.How much did Maria pay?
Answers
A) 30 dollars B) 40 dollars C) 45 dollars D) 60 dollars E) 70 dollars

Solution: Solution   3 × (10 + 5) = 3 × 10 + 3 × 5 = 30 + 15= 
30 + 15 = 45
45 dollars   Answer 45 dollars
Answer: C
The present ages of three persons in proportions 4 : 7 : 5. Eight years ago, the sum of their ages was 56. Find their present ages (in years).
Answers: A) 8, 20, 28 B) 16, 28, 36 C) 20, 35, 25 D) 16, 28, 34 E) 16, 28, 33

Solution: Let their present ages be 4x, 7x and 5x years respectively.   Then, (4x - 8) + (7x - 8) + (5x - 8) = 56   16x = 5.   Their present ages are 4x = 20 years, 7x = 35 years and 5x = 25 years respectively.   Answer:20, 35, 25
Answer: C