MU-NLPC/Calc-aqua_rat huggingface dataset:
About the number of pairs which have 12 as their HCF and 136 as their LCM, the conclusion can be Options:
A) no pair exist	B) only two such pairs exist	C) many such pairs exist	D) only one such pair exists	E) None of these

Solution: Explanation:   HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.   Correct Option: no pair exist
Answer: A
A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:	Choose the correct choice from the following choices:
A) 49 m2	B) 50 m2	C) 52 m2	D) 53.5 m2	E) 55 m2

Solution: Area of the wet surface	= [2(lb + bh + lh) - lb]   = 2(bh + lh) + lb   = [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2   = 49 m2.   answer :49 m2
Answer: A
11 persons are sitting ina row. how many ways can 11persons be arranged in a row such that 3 persons should always be together?  Choose the correct choice from the following answers:
A) 7!×3! B) 7!×2! C) 9!×3! D) 7!×1! E) 6!×2!

Solution: Given that three particular persons should always be together. Hence, just group these three persons together and consider as a single person.   Therefore we can take total number of persons as 9. These 9 persons can be arranged in 9! ways.   We had grouped three persons together. These three persons can be arranged among themselves in 3! ways.   Hence, required number of ways   =9!×3!   9!×3!
Answer: C
A man can row upstream at 29km/hr and down stream at 15km/hr find mans rate of the current ?	Select.
A) 9.8km/hr	B) 3.6km/hr	C) 8.9km/hr	D) 7km/hr	E) 5.9km/hr

Solution: given upstream(u) =29km/hr   down stream (v)= 15km/hr rate of the current =1/2(u-v) =1/2(29-15)=7km/hr   Answer is (7km/hr)
Answer: D
If the product 4864 x 9 P 2 is divisible by 12, then the value of P is: Pick one:
A) 2 B) 5 C) 6 D) 8 E) None of these

Solution: Clearly, 4864 is divisible by 4.   So, 9P2 must be divisible by 3. So, (9 + P + 2) must be divisible by 3.   P = 1.   Option None of these
Answer: E
It being given that √ 15 = 3.88, the best approximation to √5/3 is Pick:
A) 0.43	B) 1.89	C) 1.29	D) 1.63	E) 1.54

Solution: x = √(5/3) = √(5*3)/(3*3)   = √15 /√ 9   = √15/3   = 3.88/3 = 1.29   Answer is 1.29.
Answer: C
The numbers of pizza slices that are sold in Joey's Pizza are only in quantities of 4 and 9 slices per customer. How many slices cannot be bought?  Select.
A) 58.  B) 50.  C) 67.  D) 74.  E) 22.

Solution: Answer:	Let X pizzas of 4 slices and Y pizzas of 9 slices.   4X + 9Y.   Lets check options wise.   A. 58 => 4(19) + 6(32)   B. 50 => we can't write anything with 4 and 6 series..Lets try 4(1) + 9(5) = 49 , 4(6) + 9(3) = 51 , nothing works out   C. 67 => 4(10) + 9(3)   D. 74 => 4(5) + 9(6)B. 74 => 4(5) + 9(6)   E. 22 => 4(1) + 9(2)   Answer: correct option is 50.
Answer: B
What annual payment will discharge a debt of Rs. 1050 due in 2 years at the rate of 5% compound interest?  Select the correct option.
A) 993.2	B) 551.25	C) 534.33	D) 543.33	E) 564.69

Solution: Explanation:   Let each installment be Rs. x. Then,   x/(1 + 5/100) + x/(1 + 5/100)2 = 1050   820x + 1050 * 441   x = 564.69   So, value of each installment = Rs. 564.69   Answer: Option 564.69
Answer: E
A group of candidates for two analyst positions consists of six people. If one-third of the candidates are disqualified and three new candidates are recruited to replace them, the number of ways in which the two job offers can be allocated will:  Choose the correct choice.
A) Drop by 40% B) Remain unchanged C) Increase by 20% D) Increase by 40% E) Increase by 60%

Solution: Initially 6 people for 2 positions, meaning   6 - 1st position   5 - 2nd position   Total combinations- 5*6 = 30   Now 1/3rd not qualified, so reduce by 2. Hence, now we have 4+3 candidates for the position.   Same as above, 7*6 for two positions will give 42 combinations. Thus, 42-30/30 = 40% increase;   ANSWER:Increase by 40%
Answer: D
Two numbers X and Y are such that the sum of 5% of X and 4% of Y is two-third of the sum of 6% of X and 8% of Y. Find the ratio of X : Y.  Choose the correct choice from the following answers.
A) 4:3 B) 3:2 C) 1:2 D) 2:1 E) 3:5

Solution: 5% of X + 4% B = 2/3 (6% X + 8% Y)   = 5/100X+4/100Y = 2/3(6/100 X + 8/100 Y)   1/100X = 1/75 Y   X/Y = 100/75 = 4/3   Ratio 4:3   4:3NSWER 4:3
Answer: A
The ratio of red, yellow, and green jelly beans in a jar is 1:2:3. If the number of jelly beans is increased by 10%, 20%, and 30% respectively, what will be the new ratio? Choose the correct choice.
A) 11:24:39
B) 7:19:35
C) 6:18:29
D) 4:15:28
E) 2:11:25

Solution: The new ratio will be 1.1:2.4:3.9=11:24:39.   The answer is 11:24:39.
Answer: A
If x is the sum of s and t, then which one of the following must equal s – t ?
Select the correct option.
A) x-2t
B) x+2t
C) x-t
D) x+t
E) x/2t

Solution: Given x= s+t if you subtracts both side with -2t   x-2t = s-t   x-2tnswer : x-2t
Answer: A
Two pumps are connected to an empty tank. Pump X fills the tank with water at a constant rate, while pump Y drains water out of the tank at a constant rate. The two pumps finish filling the tank in two times the duration it would take pump X alone to fill the tank. If pump Y alone can empty a whole tank in 30 minutes, then how many minutes does it take pump X alone to fill the tank?
Options
A) 15	B) 16	C) 18	D) 20	E) 24

Solution: Let V be the volume of the tank.   Let R be the rate per minute that pump X fills the tank.   Let T be the time it takes pump X to fill the tank.   The rate at which pump Y empties the tank is V/30 per minute.   (R - V/30)*2T=V=RT.   (R-V/30)*2=R   R=V/15.   It takes pump X 15 minutes to fill the tank.   The answer is 15.
Answer: A
The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 60 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?
Choose the correct answer.
A) 75%  B) 80%  C) 104.8%  D) 150.5%  E) 180%

Solution: Let length of each side of square A be 10   Area of A = 10^2 = 100   Since , length of each side of square A is increased by 100 percent to make square B   length of each side of square B = 2*10= 
2*10 = 20
20   Area of B= 20^2 = 400   Since , length of the side of square B is increased by 60 percent to make square 104.8%   length of each side of square 104.8%= 1.6*20= 
1.6*20 = 32
32   Area of 104.8%= 32^2 = 1024   Difference in areas of 104.8% and cummulative areas of A and B = 1024 -(400+100)= 
1024 -(400+100) = 524
524   percent is the area of square 104.8% greater than the sum of the areas of squares A and B= (524/500) * 100= 
(524/500) * 100 = 524/5 = around 104.8
104.8%   Answer 104.8%
Answer: C
Sum of two numbers is 35. Two times of the first exceeds by 5 from the three times of the other. Then the numbers will be? Select:
A) A)5 B) B)9 C) C)11 D) D)22 E) E)15

Solution: Explanation:   x + y = 35   2x – 3y = 5   x = 22 y = 13   22)
Answer: D
What is the sum of all four digit integers formed using the digits 2, 3, 4 and 5 (repetition is allowed)  Choose the correct answer:
A) 444440 B) 610000 C) 666640 D) 995456 E) 880000

Solution: n = 4 * 4 * 4 * 4= 
4 * 4 * 4 * 4 = 256
256   <x></x>= (5555+ 2222) / 2= 
(5555+ 2222) / 2 = 7_777/2 = around 3_888.5
3888.5   Sum= number of integers x average value   n * <x> </x>= 256 * 3888.5 = 711040   answer = 995456
Answer: D
A committee of three people is to be chosen from 3 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?
Options:
A) 16 B) 24 C) 26 D) 30 E) 8

Solution: Total no of ways of choosing a committee = 6C3 = 20   No of ways to choose first couple = 3C1 = 3   No of ways to choose 1 person from remaining 4 = 4C1 = 4   Total number of ways of choosing a married couple to be in the same committee = 3*4= 
3*4 = 12
12   So, no of ways not choosing a married couple= 20-12= 
20-12 = 8
8   ANS:E. 8
Answer: E
After depositing a check into his checking account, the amount of money in Daniel's checking account increased from $9,090.00 to $9180.90. What was the percentage of the increase?  Choose the correct choice from the following options
A) 2%	B) 1.5%	C) 1%	D) 0.5%	E) None

Solution: First we need to figure out how much money Daniel deposited:   =$9180.90-$9,090.00=$90.90   Now we need to determine what percentage $90.90 is of $9,090.00:    90.9/9090*100= 
 90.9/9090*100 = 1
1%   answer is 1%.
Answer: C
In a series of six consecutive even numbers, the sum of the second and sixth numbers is 24. What is the fourth number?	Answers:
A) 22	B) 12	C) 98	D) 27	E) 14

Solution: Let the numbers be x, x + 2, x + 4, x + 6, x + 8 and x + 10.   Given (x + 2) + (x + 10) = 24   => 2x + 12 = 24 => x = 6   The fourth number = x + 6= 
+ 6 = 6
6 + 6= 
6 + 6 = 12
12.   Answer: 12
Answer: B
100 identical coins each with probability 'pp' showing up heads & tossed. If 0<p<10<p<1 and the probability of heads showing on 50 coins is equal to that ofheads on 51 coins, then the value of pp is?	Choose the correct choice.
A) 50/101	B) 51/103	C) 51/101	D) 63/111	E) 63/113

Solution: Let aa be the number of coins showing heads   Then, P(A=50)=P(A=51)P(A=50)=P(A=51)   ⇒10051/10150×P50×(1−P)50⇒10051/10151×P51×(1−P)49⇒10051/10150×P51×(1−P)50=10051/10151×P⇒51(1âˆ′P)=50P⇒P=51/101   51/101
Answer: C
The greatest number of four digits which is divisible by 20,25,30 and 70 is: Pick one
A) 8400	B) 9200	C) 9600	D) 9800	E) 9960

Solution: Greatest number of 4-digits is 9999.   L.C.M. of 20, 25, 30 and 70 is 2100.   On dividing 9999 by 2100, the remainder is 1599.   Required number  (9999 - 1599)= 
 (9999 - 1599) = 8_400
8400.   8400nswer: Option 8400
Answer: A
January 1, 2008 is Tuesday. What day of the week lies on Jan. 1, 2009 ?  Choose the correct choice.
A) Monday  B) wednesday  C) Thursday  D) Sunday  E) None of these

Solution: Solution   The year 2008 is a leap year. So, it has 2 odd day.   1st day of the year 2008 is Tuesday(Given)   so,1st day of the year 2009 is 2 days beyond Tuesday.   Hence, it will be Thursday. Answer Thursday
Answer: C
How many times are the hands of a clock at right angle in 6 hours?	Choose the correct choice from the following options:
A) 9	B) 10	C) 11	D) 12	E) 13

Solution: In 12 hours, they are at right angles 22 times.   In 6 hours, they are at right angles 11 times. Answer: Option 11
Answer: C
If Tim had lunch at $50.50 and he gave 20% tip, how much did he spend?
Options:
A) $57.45
B) $35.42
C) $60.60
D) $21.56
E) $78.45

Solution: The tip is 20% of what he paid for lunch.   tip = 20% of 50.50 = (20/100)*50.50 = 101/100 = $10.10   Total spent     50.50 + 10.10= 
  50.50 + 10.10 = 60.6
$60.60   correct answer is $60.60)$60.60
Answer: C
A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?	Pick one.
A) 118
B) 150
C) 277
D) 200
E) 191

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 12= 
50/3 * 12 = 200
200 m   Answer: 200
Answer: D
There are 100 students in a college class of which 36 are boys studying Tamil & 13 girls not studying Tamil. If there are 55 girls in all, then the probability that a boy picked up at random is not studying Tamil, is  Pick.
A) 1/5
B) 2/3
C) 3/5
D) 3/7
E) 4/9

Solution: There are 55 girls and 45 boys in the college. Out of 45 boys, 36 are studying Tamil and 9 are not studying Tamil. The probability that a boy picked up at random is not studying Tamil= 9/45 = 1/5   1/5
Answer: A
In how much time would the simple interest on a certain sum be 0.125 times the principal at 10% per annum?
Choose the correct choice from the following answers:
A) 1 1/4
B) 1 1/6
C) 1 1/0
D) 1 1/5
E) 1 5/1

Solution: Let sum = x. Then, S.I. = 0.125x = 1/8 x, R = 10%   Time = (100 * x) / (x * 8 * 10) = 5/4 = 1 1/4 years.1 1/4nswer: 1 1/4
Answer: A
David obtained 96, 95, 82, 97 and 95 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?  Choose one
A) 75	B) 95	C) 93	D) 165	E) 11

Solution: Explanation:   Average = (96+ 95+ 82+ 97 + 95 )/ 5 = 465/5= 
465/5 = 93
93.   Answer:93
Answer: C
Some of 40%-intensity red paint is replaced with 20% solution of red paint such that the new paint intensity is 20%. What fraction of the original paint was replaced?	Answers
A) 2/5
B) 2/3
C) 1/3
D) 1/2
E) 1/1

Solution: Let total paint = 1   Let amount replaced = x   40 (1-x) + 20x = 20   x = 1/1   ANSW1/1R:1/1
Answer: E
In what time will a railway train 60 m long moving at the rate of 36 kmph pass a telegraph post on its way?
Choose the correct choice from the following options
A) 6 sec B) 7 sec C) 2 sec D) 1 sec E) 5 sec

Solution: t= 60/36* 18/5= 
60/36* 18/5 = 6
6 sec   6 secNSWER 6 sec
Answer: A
If QUESTION = DOMESTIC what will b code for RESPONSE ?
Choose the correct option: A) OMESICEM B) HSDUISAH C) SSIDFUGD D) SDIFUGAU E) UIDFGWIW

Solution: Explanation:   Q U E S T I O N   D O M E S T I C   We can see in the word 'RESPONSE' only R and P are the letters whose code is not given, by having a look on options we can say code for R is O and code for P is S (because common in all options).   Now we can easily code the word 'RESPONSE'as 'OMESICEM'.   OMESICEMnswer : OMESICEM
Answer: A
A coin is tossed three times. What is the probability that there is at the least one tail?
Choose the correct choice from the following answers.
A) 7/8 B) 6/7 C) 1/7 D) 3/7 E) 1/31

Solution: Let P(T) be the probability of getting least one tail when the coin is tossed three times.   = There is not even a single tail.   i.e. all the outcomes are heads.   = 1/8 ; P(T) = 1 - 1/8   = 7/8   7/8nswer: 7/8
Answer: A
A can do a job in 16 days, B can do same job in 12 days. With the help of C they did the job in 4 days. C alone can do the same job in how many days ?  Choose the correct choice from the following answers.
A) 6 1/2days	B) 7 1/2days	C) 8 3/5days	D) 9 3/5days	E) 10 1/2 days

Solution: Explanation:   In this question we having, A's work, B's work and A+B+C work. We need to calculate C's work.   We can do it by,   (A+B+C)'s work - (A's work + B's work).   Let's solve it now:   C's 1 day work =   1/4−(1/16+1/12)=(1/4−7/48)=5/48   So C can alone finish the job in 48/5 days,   Which is =   9 3/5days   Option 9 3/5days
Answer: D
If x^3 > y^2 = z, which of the statements could be true?
I. x < y < z
II. x < z < y
III. y < x < z Choose the correct choice from the following options
A) I only B) III only C) I and II only D) II and III only E) I, II and III

Solution: Given : x^3 > y^2 = z   I. x < y < z is not true for x=3, y=2, z=4   II. x < z < y is not true for x=3, y=2, z=4   III. y < x < z is true for x=3, y=2, z=4 i.e. Answers can only be Options E   Answer: option III only
Answer: B
Two trains of equal length are running on parallel lines in the same directions at 46km/hr. and 36km/hr. The faster trains pass the slower train in 108 seconds. The length of each train is:	Choose the correct choice from the following answers:
A) 82m
B) 50m
C) 72m
D) 150m
E) None of these

Solution: Explanation:   The relative speed of train is 46-36= 
46-36 = 10
10 Km/hr= (10 X 5) / 18 = 25/9 m/s10×518=259m/s   In 108 secs the total distance traveled is 108x25/9 = 300 m.   Therefore the length of each train is = 300/2= 
300/2 = 150
150 m.   Answer 150m
Answer: D
A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more. On arriving at the third station it is found to have 248 passengers. Find the no of passengers in the beginning? Choose the correct choice from the following options:
A) 292  B) 180  C) 192  D) 144  E) 168

Solution: Let no of passengers in the beginning be X   After first station no passengers=(X-X/3)+280=2X/3 +280   After second station no passengers =1/2(2X/3+280)+12   1/2(2X/3+280)+12=248   2X/3+280=2*236= 
2*236 = 472
472 - 280= 
472 - 280 = 192
192   2X/3=192   X=288. So the answer is option 192) 192.
Answer: C
The total marks obtained by a student in Physics, Chemistry and Mathematics is 150 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics? Select.
A) 75
B) 65
C) 29
D) 26
E) 12

Solution: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.   P + C + M = 150 + P   C + M = 150   Average mark obtained by the student in Chemistry and Mathematics   = (C + M)/2 = 150/2= 
150/2 = 75
75.   75nswer:75
Answer: A
20/25 = 4/5 . which method did you use to determine whether this proportion is true or false?
Choose the correct answer:
A) true
B) neutral
C) false
D) not sure
E) none

Solution: 20/25= 4/5 cross multiplication:   20 * 5= 
  20 * 5 = 100
100, 4 * 25=100,   we see that 100 are not equal to 100. so there is proportion. corrcet answer: (true)
Answer: A
If f1(x)=f(x)=12xf1(x)=f(x)=12x and fn(x)=f(fn−1(x)fn(x)=f(fn−1(x), then find f5(x)+f10(x)f5(x)+f10(x) where x = 1 Choose the correct choice from the following answers:
A) 3/9 B) 3/2 C) 3/1 D) 3/3 E) 3/4

Solution: f(x) = 12x12x and f(f(x)) = f(12x)f(12x) = 12(12x)12(12x) = x   Similarly f3(x)=f(f2(x))=f(x)=12xf3(x)=f(f2(x))=f(x)=12x and f4(x)=f(f3(x))=f(12x)=12×12x=xf4(x)=f(f3(x))=f(12x)=12×12x=x   Hence fn(x)=12xfn(x)=12x for n = odd and fn(x)=xfn(x)=x for n = even   f5(x)+f10(x)=12x+xf5(x)+f10(x)=12x+x   If x = 1, ⇒12×1+1=3/2   Answer:3/2
Answer: B
A shopkeeper labels the price of articles 20% above the cost price. If he allows 31.20 off on a bill of 312, find his profit per cent on the article?
Choose the correct answer:  A) 8  B) 12 1⁄3  C) 11 2⁄3  D) 8 1⁄3  E) None of these

Solution: Let the CP = 100 Marked price = 120   Discount = 312⁄31.2 × 1⁄100 = 10% = 12   SP = 120 – 12 = 108 Profit% = 108 – 100 = 8%   8nswer 8
Answer: A
A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is? Select the correct option:
A) 22
B) 21
C) 77
D) 88
E) 66

Solution: 20 15 5   25 20 8   500 + 300 + 40= 
500 + 300 + 40 = 840
840/40= 
840/40 = 21
21   Answer: 21
Answer: B
3x^2-6x+3 = 0 Find the above equation find the value of x  Choose the correct choice.
A) 0  B) 1  C) 3  D) 4  E) 5

Solution: a = 3, b = -6, c = 3   x1,2 = (6 ± √( (-6)2 - 4×3×3)) / (2×3) = (6 ± √(36-36)) / 6 = (6 ± 0) / 6   x1 = x2 = 1   1
Answer: B
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?	Choose one: A) 7 kmph B) 9 kmph C) 3 kmph D) 8 kmph E) 2 kmph

Solution: Speed downstream = d/t = 85/(2 1/2) = 34 kmph   Speed upstream = d/t = 45/(2 1/2) = 18 kmph   The speed of the stream = (34 - 18)/2= 
(34 - 18)/2 = 8
8 kmph.Answer: 8 kmph
Answer: D
There are two groups of students in the sixth grade. There are 45 students in group A, and 55 students in group B. If, on a particular day, 20% of the students in group A forget their homework, and 40% of the students in group B forget their homework, then what percentage of the sixth graders forgot their homework?  Choose the most appropriate option:
A) 23%	B) 25%	C) 29%	D) 31%	E) 36%

Solution: Number of students in group A = 45   students who forget homework in group A = 20 % of 45 = 9 students   Number of students in group B = 55   students who forget homework in group B = 40 % of 55 = 22 students   Total number of students = 45 + 55= 
45 + 55 = 100
100   students who forgot homework= 9 + 22= 
9 + 22 = 31
31 students   percentage of students who forget homework= 31/100 * 100= 
31/100 * 100 = 31
31%   Answer: 31%
Answer: D
Seven men and seven women have to sit around a circular table so that no 2 women are together. In how many different ways can this be done?  Pick one.
A) 6!*7!
B) 136!*7!
C) 356!*7!
D) 366!*7!
E) 566!*7!

Solution: Yes, the solution given above is correct. Think of it this way:   There are 7 men: Mr. A, Mr. B .....   and 7 women: Ms. A, Ms. B ....   14 seats around a circular table.   You seat the 7 women such that no two of them are together so they occupy 7 non-adjacent places in 6! ways. For the first woman who sits, each seat is identical. Once she sits, each seat becomes unique and when the next woman sits, she sits in a position relative to the first woman (e.g. 1 seat away on left, 3 seats away on right etc)   The 7 men have 7 unique seats to occupy. Each of the 7 seats are unique because they have a fixed relative position (e.g. between Ms. A and Ms. B or between Ms. C and Ms. B etc...). So the men can sit in 7! ways.   Total 6!*7! ways.   6!*7!NS:6!*7!
Answer: A
Find the odd man out
4, 9,16, 36, 64, 144	Choices:
A) 144 B) 16 C) 9 D) 36 E) 4

Solution: 9 is square of 3 which is odd number where as all others are squares of even numbers.   ANSWER:9
Answer: C
3 friends A, B, C went for week end party to McDonald’s restaurant and there they measure there weights in some order In 7 rounds. A, B, C, AB, BC, AC, ABC. Final round measure is 140kg then find the average weight of all the 7 rounds? Options.
A) 98.5 kgs B) 80 kgs C) 76.5 kgs D) 67.5 kgs E) 58.2 kgs

Solution: Average weight = [(a + b + c + (a+b) + (b+c) + (c+a)+(a+b+c)] / 7 = 4 (a+b+c) /7 = 4 x 140/7 = 80 kgs   Answer:80 kgs
Answer: B
Let C be defined as the sum of all prime numbers between 0 and 30. What is C/3	Choose the correct choice.
A) 155  B) 129  C) 61  D) 47  E) 43

Solution: Prime numbers between 0 and 30 - 2 , 3 , 5 , 7, 11 , 13 , 17 , 19 , 23 , 29   Sum,C = 129   C/3 = 43   Answer 43
Answer: E
A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 950 grams. Find the profit percent.  Pick one
A) 100/18%
B) 100/17%
C) 100/16%
D) 100/19%
E) 100/13%

Solution: Explanation:   (100 + g) / (100 + x) = True measure / Faulty measure   x = 0   true measure = 1000   faulty measure = 950   100 + g / 100 + 0 = 1000 / 950   100+g = 20/19*100   g = 100/19 %   ANSWER: 100/19%
Answer: D
What distance will be covered by a bus moving at 36 kmph in 30 seconds?
Choose the correct choice from the following choices
A) 287  B) 600  C) 289  D) 300  E) 207

Solution: 36 kmph = 36 * 5/18= 
36 * 5/18 = 10
10 mps   D= Speed * time = 10 * 30= 
10 * 30 = 300
300 m.   Answer:300
Answer: D
Rs.8000 become Rs.11256 in a certain interval of time at the rate of 5% per annum of C.I. Find the time? Pick.
A) 6 YEARS	B) 7	C) 5	D) 3	E) 4

Solution: Explanation:   11256 = 8000(21/20)N   (21/20)7 = (21/20)N => N = 7   Answer: Option 7
Answer: B
In N is a positive integer less than 200, and 14N/60 is an integer, then N has how many different positive prime factors?	Choose one
A) 2
B) 3
C) 5
D) 6
E) 8

Solution: 14n/60 must be an integer. => 7n/30 must be an integer. Hence n must be a multiple of 2*3*5.   => n has 3 different prime integers and cannot have more than 3 different prime integers because  2*3*5*7= 
 2*3*5*7 = 210
210 > 200 ANSWER:3
Answer: B
The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle?  Choose the most appropriate option.
A) 432 B) 672 C) 278 D) 266 E) 261

Solution: 2(3x + x) = 96   l = 36 b = 12   lb = 36 * 12= 
36 * 12 = 432
432   432nswer: 432
Answer: A
Month	Average Price
per Dozen
April $1.26
May $1.20
June $1.08
The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a General store during three successive months. If 2/3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
Choose the correct answer:
A) 1.4  B) 1.3  C) 1.2  D) 1.1  E) 1.16

Solution: Say x dozen eggs were sold in May.   Then 2x/3 dozen eggs were sold in April and 2*2x/3=4x/3 dozen eggs were sold in May.   Total x+2x/3+4x/3=3x dozen eggs were sold in three months.   Total sales: 2x/3*1.26+x*1.2+4x/3*1.08=$3.48x. The average price per dozen 3.48x/3x=$1.16.   1.16
Answer: E
If A : B= 1 : 2 and B : C = 3 : 4, then A : B : C is: Choose the correct option: A) 9:6:4 B) 1:2:3 C) 3:6:9 D) 12:25:87 E) 3:5:7

Solution: 9:6:4:B=1:2, B:C=3:4, 9:6:4:B:C=3Ã—3:3Ã—2:1Ã—4   â‡’ 9:6:4   9:6:4nswer: 9:6:4.
Answer: A