MU-NLPC/Calc-aqua_rat huggingface dataset:
A family pays $900 per year for an insurance plan that pays 80 percent of the first $1,000 in expenses and 100 percent of all medical expenses thereafter. In any given year, the total amount paid by the family will equal the amount paid by the plan when the family's medical expenses total. Choose the correct choice from the following answers:
A) $1,000
B) $1,200
C) $1,300
D) $1,800
E) $2,200

Solution: Upfront payment for insurance plan = 900$   Family needs to pay 20 % of first 1000 $ in expense = 200$   Total amount paid by family when medical expenses are equal to or greater than 1000 $ = 900 + 200= 
900 + 200 = 1_100
1100 $   Total amount paid by insurance plan for first 1000 $= 900 $   Total amount paid by family will equal amount paid by plan when medical expense = 1300 $   (Since insurance plan will pay 100% of amount that exceeds 1100$ )   Answer $1,300
Answer: C
A number is doubled and 15 is added. If the resultant is multiplied by 5, it becomes 125. What is that number?
Choose the correct option.
A) 5
B) 10
C) 8
D) None of these
E) Cannot be determined

Solution: Solution   Let the number be x.   Then, 5(2x + 15) ‹=› 125   ‹=› 2x+15 = 25   ‹=› 2x= 10   x= 5.   Answer None of these
Answer: D
It was calculated that 100 men could complete a piece of work in 20 days. When work was scheduled to commence, it was found necessary to send 50 men to another project. How much longer will it take to complete the work? Choose the correct choice from the following choices:  A) 45 days.  B) 40 days.  C) 38 days.  D) 35 days.  E) 30 days.

Solution: One day work = 1 / 20   One man’s one day work = 1 / ( 20 * 100)   Now:   No. Of workers = 50   One day work = 50 * 1 / ( 20 * 100)   The total no. of days required to complete the work = (100 * 20) / 50= 
(100 * 20) / 50 = 40
40   Answer:40 days.
Answer: B
A can run 2 km distance in 2 min., while B can run this distance in 2 min 40 sec. By how much distance can A beat B?	Choose the most appropriate option:
A) 150 m
B) 100 m
C) 500 m
D) 180 m
E) 190 m

Solution: A takes time 2 minutes=120sec   B takes time 2.40 minutes=160sec   diffrence= 160-120= 
160-120 = 40
40sec   now we are to find distance covered in 40 sec by B   160sec=2000m   1sec=25/2 m   40sec=40 x 25/2=500m   ANSWER:500 m
Answer: C
There are 35 kids in a play school. 26 kids play with white color balls and some kids play with yellow color balls and 19 kids play with both color balls. How many kids use yellow color balls? Select:
A) 12
B) 32
C) 5
D) 28
E) 35

Solution: Explanation :   n(AuB)= n(A) + n(B) - n(AnB)....(1)   n(A) = number of kids playing with white color balls = 26   n(AUB) = total number of kids in the play school = 35   n(AnB) = number of kids playing with both white and yellow color balls = 19   we have to find,   n(B) = number of kids playing with yellow color balls   From (1), 35 = 26 + n(B) - 19   n(B) = 35 + 19 - 26= 
35 + 19 - 26 = 28
28   Hence, Answer is 28 kids play with yellow color   balls.   Answer : 28
Answer: D
If f(x)= 5x^3- 2x+4 and g(y)= 6y-4, then g(f(x)) =	Pick:
A) 11x^2+4x+4 B) 30x^3-12x+20 C) 8x^3-8x+32 D) 30x^3+4x+4 E) 30x^3-12x+44

Solution: g(f(x)) = 6(f(x)) -4 = 6(5x^3- 2x+4) - 4 = 30x^3-12x+20 =>30x^3-12x+20
Answer: B
The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8587 for a computer table, then what was the cost price of the computer table? Answers:
A) 6925	B) 6887	C) 6728	D) 6725	E) 2871

Solution: :   CP = SP * (100/(100 + profit%))   = 8587(100/124) = Rs. 6925.   6925nswer: 6925
Answer: A
Veena ranks 65rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination?	Choose the correct choice from the following
A) 96	B) 108	C) 110	D) 90	E) 93

Solution: total student=182   failed=22   paasd student=182-22= 
182-22 = 160
160   from bottom her rank is=160-65+1= 
160-65+1 = 96
96   96NSWER:96
Answer: A
A 180 meter long train crosses a man standing on the platform in 6 sec. What is the speed of the train? Choose the most appropriate option
A) 109  B) 108  C) 109  D) 106  E) 101

Solution: S = 180/6 * 18/5= 
180/6 * 18/5 = 108
108 kmph   Answer108
Answer: B
The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 resolutions? Answers:  A) 794 m  B) 704 m  C) 454 m  D) 186 m  E) 176 m

Solution: In one resolution, the distance covered by the wheel is its own circumference. Distance covered in 500 resolutions.   = 500 * 2 * 22/7 * 22.4= 
500 * 2 * 22/7 * 22.4 = 70_400
70400 cm= 704 m   Answer: 704 m
Answer: B
Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.13 of money?	Choose the correct option:
A) 1300
B) 1992
C) 9921
D) 2798
E) 2789

Solution: P = 13(100/10)2   => P = 1300   1300nswer: 1300
Answer: A
If the cost price of 12 pens is equal to the selling price of 8 pens, the gain percent is:  Answers:
A) 22  B) 77  C) 50  D) 77  E) 23

Solution: Let C.P. of each pen be Re. 1.   Then, C.P. of 8 pens = Rs. 8; S.P. of 8 pens = Rs. 12.   Gain % = 4/8 * 100= 
4/8 * 100 = 50
50%   Answer:50
Answer: C
The third proportional to 2 and 6 is?  Pick one.
A) 18  B) 17  C) 14  D) 15  E) 13

Solution: (6*6)/2= 
(6*6)/2 = 18
18   18nswer:18
Answer: A
Ratio of the ages of Mahesh and Nilesh is 5:x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x?	Choose the correct choice:
A) 14.9
B) 14.5
C) 14.3
D) 14.2
E) 14.5

Solution: Let the present ages of Mahesh, Nilesh and Ramesh be M, N and R respectively.   M/N = 5/x --- (1)   M = R - 18 --- (2)   R + 9 = 47 --- (3)   M - N = R --- (4)   (3) => R = 47 - 9= 
47 - 9 = 38
38 years   (2)=> M = 38 - 18= 
38 - 18 = 20
20 years   (1)=> 20/N = 5/x => N = 4x   (4) => 4x - 20 = 38   => 4x = 58 => x = 14.5   Answer: 14.5
Answer: E
What is the place value of 3 in the numeral 2734?
Pick.
A) 30	B) 50	C) 70	D) 80	E) 84

Solution: Option '30'    3 * 10= 
 3 * 10 = 30
30
Answer: A
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Choose the correct option:
A) 3/4
B) 1/4
C) 3/8
D) 7/8
E) None of these

Solution: Explanation:   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E) =	n(E)	/ n(S) =7/8.   ANSWER IS 7/8
Answer: D
A company produces 65000 bottles of water everyday. If a case can hold 13 bottles of water .How many cases are required by the company to hold its one day production	Pick one:  A) 2000  B) 4500  C) 5000  D) 8000  E) 9000

Solution: Number of bottles that can be held in a case = 13   Number of cases required to hold 65000 bottles = 65000/13= 
65000/13 = 5_000
5000 cases.   So the answer is 5000=5000
Answer: C
In jar X there are 3 silver coins and 5 gold coins, in jar Y there are 4 silver coins and 2 gold coins. A jar is randomly picked, what is the probability of picking up a gold coin out of jar Y? Options:
A) 2/5.  B) 3/5.  C) 1/5.  D) 3/4.  E) 1/6.

Solution: Probability of picking up one jar out of two= 1/2   probability of picking 1 gold coin from jar Y= 2/6= 1/3   Hence the desired probability= 1/2*1/3= 1/6   1/6. is the answer
Answer: E
The charge for a single room at Hotel P is 25 percent less than the charge for a single room at Hotel R and 15 percent less than the charge for a single room at Hotel G. The charge for a single room at Hotel R is what percent greater than the charge for a single room at Hotel G ? Pick:  A) 15%  B) 20%  C) 40%  D) 13%  E) 150%

Solution: Let rate in R = 100x   then P = 75x   G = 100y   P = 85y   Thus   75 x=85y   or x = 1.13 y   Ans R = 113y   so increase = 13%   Answer: 13%
Answer: D
If the perimeter of square region D and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3 then the ratio of the area of R to the area of D  Choose the correct choice from the following answers.
A) 25:16  B) 24:25  C) 5:6  D) 4:5  E) 4:9

Solution: We know Perimeter of a square (Pd) = 4*side   Perimeter of a rectangle (Pr) = 2(length+breath)   Let us assume 40 to be the perimeter of the square (since we know each side of a square is equal and the perimeter is divisible by 4, also take in to account the length and breadth of the rectangle is in the ration 2k:3k = 5k; we can assume such a number)   Therefore,   Pd = Pr = 40   Area of the square = 100 sq. units   We know 2(length+breadth) = 40   i.e. length + breadth = 20 (or 5k = 20 given that l:b (or b:l) = 2:3)   Therefore length = 8, breath = 12   Area of the rectangle = 8*12= 
8*12 = 96
96 sq. units   Question asked= Area of the rectangle : Area of the square = 96:100 ==> 24:25=24:25
Answer: B
How many natural numbers are there between 43 and 200 which are exactly divisible by 6?  Choose the correct choice from the following choices:
A) 26	B) 25	C) 24	D) 22	E) 23

Solution: 43/6 = 7, remainder = 1. Hence 5 more should be added to 43 to get the minimum   number divisible by 6 between 43 and 200.   => Minimum number divisible by 6 between 43 and 200 = 43 + 5= 
43 + 5 = 48
48   200/6= 33, remainder = 2. Hence 2 should be decreased from 200 to get the maximum   number divisible by 6 between 43 and 200.   => Maximum number divisible by 6 between 43 and 200 = 200 - 2= 
200 - 2 = 198
198   Hence, natural numbers numbers divisible by 6 between 43 and 200 are 48, 54, 60,...198   This is 26rithmetic Progression with a= 48, d = 6, l=198   Number of terms =(l−a)/d+1=(198−48)/6+1=150/6+1=25+1= 
25+1 = 26
26   26nswer is 26
Answer: A
If x and y are positive integers and 25x=10y what is the least possible value of xy?  Choose the correct choice from the following answers.
A) 14 B) 25 C) 63 D) 84 E) 252

Solution: 25x=10y   => x/y = 2/5   => 5x=2y   5(3)=2(3) => x*y=9 25ut it is not given   5(5)=2(5) => x*y=25   25
Answer: B
A person's present age is two-fifth of the age of his mother. After 10 years, he will be one - half of the age of his mother. How old is the mother at present ?	Pick:
A) A)25  B) B)40  C) C)32  D) D)50  E) E)28

Solution: Let the mother's present age be x years   Then the person's present age = 2x/5   (2x/5)+10 = 1/2(x+10)   2(2x+50) = 5 (x+10)   x = 50   Answer is 50
Answer: D
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010? Choose the correct choice from the following answers:	A) Tuesday	B) Friday	C) Monday	D) Sunday	E) MondSD

Solution: On 31st December, 2005 it was Saturday.   Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1)= 
(1 + 1 + 2 + 1) = 5
5 days.   On 31st December 2009, it was Thursday.   Thus, on 1st Jan, 2010 it is Friday   Answer: Friday
Answer: B
In covering a distance of 30 km, A takes 2 hours more than B. If Abhay doubles his speed, then he would take 1 hour less than B. A's speed is:  Choose the most appropriate option
A) 5 kmph  B) 6 kmph  C) 6.25 kmph  D) 7.5 kmph  E) 8.5 kmph

Solution: Let A's speed be x km/hr.   Then, 30/x -30/2x = 3   --> 6x = 30   --> x = 5 km/hr.   5 kmphnswer : 5 kmph.
Answer: A
In a division sum, the remainder is 0. As student mistook the divisor by 12 instead of 21 and obtained 49 as quotient. What is the correct quotient ?  Answers.
A) 0 B) 12 C) 13 D) 20 E) 28

Solution: 12*49= 
12*49 = 588
588   588%21=28   ANSW28R:28
Answer: E
Three solid metallic balls of radii, 3 cm, 4cm and 5 cm are
melted and moulded into a single solid ball. The radius of the
new ball is
Choose the correct answer:
A) 4	B) 5	C) 6	D) 7	E) 8

Solution: Total volume of three metallic balls(spheres)= (4/3)*Pi*(3^3+4^3+5^3)   =(4/3)*Pi*216= Volume of new ball with radius 'r'   so (4/3)*Pi*r^3=(4/3)*Pi*216   r^3=216 , r=6   ANSWER:5
Answer: B
The average of first six prime numbers which are between 30 and 70 is	Options.
A) 35.4	B) 42	C) 45.7	D) 57	E) 67

Solution: Explanation :   first six prime numbers which are between 30 and 70 = 31, 37, 41, 43, 47, 53   average = (31 + 37 +41 + 43 + 47 + 53)/6= 
(31 + 37 +41 + 43 + 47 + 53)/6 = 42
42   Answer : 42
Answer: B
JAK, KBL, LCM, MDN, _____ Choose the most appropriate option:
A) NEO B) SAS C) DFG D) JKL E) JHN

Solution: This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.   NEONSWER:NEO
Answer: A
If G is to be chosen at random from the set {5,8,7,1} and K is to be chosen at random from the set {14,8,3}, what is the probability that GK will be even?  Answers:
A) 1 B) 5 C) 8 D) 4 E) 3

Solution: Method-1   GK will be even when   1) G is even and K is odd, Probability of G even is (1/4) and Probability of K odd is (1/3), so Probability of Case(1) = (1/4)*(1/3) = (1/12)   2) G is Odd and K is Even, Probability of G Odd is (3/4) and Probability of K Even is (2/3), so Probability of Case(2) = (3/4)*(2/3) = (6/12)   3) G is even and K is Even, Probability of G even is (1/4) and Probability of K Even is (2/3), so Probability of Case(1) = (1/4)*(2/3) = (2/12)   Total Favorable Probability = (1/12)+(6/12)+(2/12) = (12/12)= 
(12/12) = 1
1   1nswer: option 1
Answer: A
A pump can fill a tank with water in 2 hours. Because of a leak, it took 7/3 hours to fill the tank. The leak can drain all the water of the tank in?
Choose the correct choice from the following answers.
A) 7 B) 12 C) 5 D) 14 E) 13/3

Solution: P --> Pump, L ---> Leak   Pipe----------P---------L------------(P-L)--   Time---------2---------x-------------7/3   *   Rate-------7/3---------x-------------2   Work------14/3-------14/3---------14/3   Time required to empty the tank if leakage present = (14/3)/((7/3) - 2)   = (14/3)/(1/3)= 
(14/3)/(1/3) = 14
14   Ans -14
Answer: D
Find the simple interest on Rs. 68,000 at 16 2/3% per year for 9 months.  Answers.
A) 7500 B) 6500 C) 8500 D) 9500 E) None of them

Solution: P = Rs.68000,R = 50/3% p.a and T = 9/12 years = 3/4years.   Simple Interest = (P*R*T)/100 = Rs.(68,000*(50/3)*(3/4)*(1/100))= Rs.8500   Answer is 8500.
Answer: C
The total of company C's assets in 1994 was 150% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:	Choices:	A) 7N	B) 8N	C) 9N	D) 12.5N	E) 20

Solution: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.   In 1993, the total assets were 400% GREATER, which means 1992 PLUS 400% of 1992:   $100 + 4x$100 = $100 + $400 =$500   In 1994, the total assets were 150% GREATER than they were in 1993, which means 1993 PLUS 300% of 1993:   $500 + 1.5x$500 100 +  400= 
100 +  400 = 500
$500   In 1994, the total assets were 150% GREATER than they were in 1993, which means 1993 PLUS 300% of 1993:   $500 + 1.5x$500= $500 + $750 =$1250   This is 12.5 times the 1992 number, so the correct answer is 12.5N.   12.5N500 +  750= 
500 +  750 = 1_250
$1250   This is 12.5 times the 1992 number, so the correct answer is 12.5N.   12.5N
Answer: D
Two spherical balls lie on the ground touching. If one of the balls has a radius of 9 cm, and the point of contact is 10 cm above the ground, what is the radius of the other ball (in centimeters)?
Options
A) 50/4  B) 70/6  C) 80/7  D) 90/8  E) 100/9

Solution: A straight line will join the two centers and the point of contact, thus making similar triangles.   1/9 = (r-10)/r   r = 9r - 90   r = 90/8   The answer is 90/8.
Answer: D
Peeta asks Katniss, 'It is 6 pm as per my watch right now.Do you know what will be the time 23, 999, 999 hours later?'
Katniss knows the answer. Do you ?
Choose the correct choice from the following options
A) 3pm
B) 6pm
C) 4am
D) 7am
E) 8pm

Solution: A   3pm   The time after 24, 000, 000 hours will be the same as it is now. We want the time 3 hours before that and thus you can deduct three hours from 9 pm. So the time will be 6 pm.
Answer: A
If a tap could fill entire tank in 18 hrs due to leakage, then in how much time
tank can be emptied by leakage if tap can fill entire tank in 12 hrs without leakage  Choose the correct choice from the following answers:
A) 12hrs
B) 24hrs
C) 36hrs
D) 48hrs
E) 52hrs

Solution: time take to fill[withleakage] =18hrs so workdone in 1hr=1/18   time tkae to fill[without leakage]=12hrs so workdone in 1hr=1/12   if u subtract both u'll get time taken by leakage to empty...   1/18-1/12=1/36 so 36hrs   ANSWER:36hrs
Answer: C
In a simultaneous throw of two coins, the probability of getting atleast one headis:
Choose the correct choice.
A) 1/4	B) 2/5	C) 7/9	D) 4/5	E) 3/4

Solution: n(S)=4   3/4 = even getting at least one head   N(3/4)=3   P(3/4)=3/4   Ans: 3/4
Answer: E
A circular logo is enlarged to fit the lid of a jar. The new diameter is 20 per cent larger than the original. By what percentage has the area of the logo increased?	Choose the correct choice from the following:
A) 50
B) 80
C) 100
D) 44
E) 250

Solution: Let old diameter be 4 , so radius is 2   Old area = 4π   New diameter is 4.8 , so radius is 2.4   New area = 5.76π   Increase in area is 1.76π   % increase in area = 1.76/4*100   So, % increase is 44%   Answer will be (44)
Answer: D
Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team H, but each box of Team A’s has 60% fewer booklets than each box of Team H’s. Which of the following could be the total number of booklets distributed by the two groups?
Choose the correct choice from the following answers:
A) 2,000  B) 3,200  C) 4,100  D) 4,800  E) 4,900

Solution: Let x be the no of booklets in each box that team H distributes. So, Team A has 60% fewer - 0.4x.   Let y be the no. of boxes distributed by team H. So, Team A distributes 60% more - 1.6y   Total booklets distributed by team A = xy   Total booklets distributed by team H=0.64xy   Total booklets distributed = xy+0.64xy=1.64xy   As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.   Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.   Similarly all answer choices, except choice C, fail to provide an integer value.   4,100hoice 4,100 = 4100/1.64= 
4100/1.64 = 2_500
2500 and is the correct answer.
Answer: C
Linda spent 3/4 of her savings on furniture and the rest on a TV. If the TV cost her $250, what were her original savings? Select the correct option
A) $500 B) $600 C) $700 D) $800 E) $1000

Solution: If Linda spent 3/4 of her savings on furnitute, the rest   4 / 4 - 3 / 4 = 1 / 4 on a TV   But the TV cost her $250. So 1 / 4 of her savings is $250. So her original savings are 4 times $250 = $1000   correct answer $1000
Answer: E
To produce an annual income of Rs. 1200 from a 15 % stock at 90,the amount of stock needed is :  Pick.
A) s. 10,000 B) s. 10,800 C) s. 14,400 D) s. 16,000 E) s. 46,000

Solution: Solution   For an income of Rs. 15, stock needed = Rs. 100.   For an income of Rs. 1500, stock needed = Rs. 10/12x15000=10,000   s. 10,000nswer s. 10,000
Answer: A
The boys in the class have an average height of 140 cm and the girls in the class have an average height of 150 cm. If the overall class average height is 144 cm, what is the ratio of boys to girls in the class?  Pick:  A) 1/2  B) 3/2  C) 3/4  D) 4/3  E) 4/5

Solution: (150G + 1403/2) / (G+3/2) = 144   150G + 1403/2 = 144(G+3/2)   6G=43/2   3/2/G = 3/2   The answer is 3/2.
Answer: B
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Pick one: A) 3:5 B) 4:5 C) 5:5 D) 4:3 E) 2:1

Solution: third no is x   first no - 120% of x = 6x/5   second no = 150x/100= 3x/2   ration of first nos = 6x/5:3x/2 = 12x:15x   = 4:5   ANSWER 4:5
Answer: B
One-fourth of the students at a nursery school are 5 years old or older. If 15 students have not yet reached their fourth birthday, and a total of 25 students are not between 4 years old and 5 years old, how many children are in the nursery school? Choose the correct choice:
A) 20  B) 25  C) 30  D) 35  E) 40

Solution: x/4 students are > 5 yrs   15 students are < 4 yrs   x/4+15 = 25   x/4 = 10   x = 40   Answer: 40
Answer: E
Find the HCF of
2/3,4/6,8/27  Pick one:  A) 2/27  B) 8/3  C) 2/3  D) 2/27  E) 1/7

Solution: Explanation:   Whenever we have to solve this sort of question, remember the formula.   HCF =   HCF of Numerators/LCM of Denominators   So answers will be option 1   Option 2/27
Answer: A
A can do a piece of work in 20 days. B in 15 days A and C in 12 days. In how many days can A finish the work if he is assisted by B on one day and C on the next, alternately?
Select the correct option:
A) 2 days  B) 5 days  C) 8 days  D) 7 days  E) 9 days

Solution: 8 days   8 days   A + B = 1/20 + 1/15 = 7/60   A + 8 days = 1/20 + 1/12 = 8/60   7/60 + 8/60 = 15/60 = 1/4   4 days * 2 = 8 days
Answer: C
what are the total number of divisors of 600?
Choose one.
A) 24 B) 40 C) 16 D) 20 E) 30

Solution: The prime factorization of 600   600 = (2^3)(3^1)(5^2)   The number of divisors (including 1 and the number itself) is the product of one plus the exponents.   (3+1)(1+1)(2+1) = 24   24NSWER:24
Answer: A
In Solution P, the proportion of water to alcohol is 3:1. In Solution Q, the proportion of water to alcohol is 2:1. If the two solutions are combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
Choose the correct choice from the following answers.
A) 25%
B) 29%
C) 33%
D) 37%
E) 41%

Solution: Let V be the total volume of the new solution.   The amount of alcohol added from Solution P is (1/4)*V/2=(1/8)*V   The amount of alcohol added from Solution Q is (1/3)*V/2=(1/6)*V   The total amount of alcohol in the new solution is (1/8+1/6)*V=(7/24)*V   The alcohol concentration is 7/24=29% (approximately)   The answer is 29%.
Answer: B
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 600 kms and City A and City C is 360 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)	Choose the correct option:
A) 8/3
B) 3/8
C) 8/5
D) 5/8
E) 20/9

Solution: Distance traveled by 20/9ddy = 600 km   Time taken by 20/9ddy = 3 hours   Average speed of 20/9ddy = 600/3= 
600/3 = 200
200 km/hour   Distance traveled by Freddy= 360 km   Time taken by Freddy = 4 hours   Average speed of Freddy = 360/4= 
360/4 = 90
90 km/hour   Ratio of average speed of 20/9ddy to Freddy= 200/90 = 20/9   Answer 20/9
Answer: E
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 48 years now, the son's age 4 years back was: Choose one.
A) 12 years.
B) 14 years.
C) 17 years.
D) 20 years.
E) 19 years.

Solution: Let the son's present age be x years. Then, (48 - x) = x   2x = 48.   x = 24   Son's age 4 years back (24- 4)= 
(24- 4) = 20
20 years.   ANSWER :20 years.
Answer: D
The average age of 36 students in a group is 18 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years ?  Choose the correct answer.
A) 35 years	B) 55 years	C) 51 years	D) 54 years	E) None of these

Solution: Explanation:   Age of the teacher = (37 * 19 - 36 * 18)= 
(37 * 19 - 36 * 18) = 55
55 years. Answer: 55 years
Answer: B
For which of the following values of n is (100+n)/n NOT an integer?  Choose the correct choice from the following choices:	A) 1	B) 2	C) 3	D) 4	E) 5

Solution: This problem is easiest solved by plugging in each answer choice.   A) (100 + 1)/1 = 101/1= 
101/1 = 101
101   Answer choice A yields an integer.   B) (100 + 2)/2= 102/2= 
102/2 = 51
51   Answer choice B yields an integer.   C) (100 + 3)/3= 103/3 = 34, remainder 2   Answer choice C DOES NOT yield an integer.   Although we believe answer choice C is correct, we should still test the other answer choices.   D) (100 + 4)/4 = 104/4= 
104/4 = 26
26   Answer choice D yields an integer.   E) (100 + 5)/5= 105/5= 
105/5 = 21
21   Answer choice E yields an integer.   Thus, the correct answer is answer choice 3.
Answer: C