MU-NLPC/Calc-aqua_rat huggingface dataset:
A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
Choose the correct option:
A) 78
B) 72
C) 90
D) 27
E) 23

Solution: SP of m of cloth   = 8925/85 = Rs. 105   CP of 1m of cloth   = SP of 1m of cloth - profit on 1m of cloth   = Rs. 105 - Rs. 15   = Rs. 90.   Answer: 90
Answer: C
Lorna invests $4000, with some at 6% annual interest and some at 11% annual interest. If she receives a total of $580 from these investments at the end of a year, how much was invested at the 6% interest rate?	Choices
A) $160 B) $1,600 C) $800 D) $4,400 E) $5,840

Solution: We have that 'x' invested at 6%   We also have that 4000-x' invested at 11%   Now then 580/4000 is approx 10%   Therefore, -4x+4000-x=0   5x=4000   x=800 approximately. Probably higher   Only $800 matches
Answer: C
There are 2 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women?
Choose the correct choice.
A) 10/16
B) 6/16
C) 4/16
D) 7/9
E) 4/10

Solution: w = m+2   w+m = 16   m+2+m = 16   2m = 14   m = 7   w = 9   ratio:7:9   Ans: 7/9
Answer: D
What percent of 200 is 55? Options
A) 0.25% B) 4% C) 25% D) 27.5% E) 250%

Solution: 200*x /100 = 55   x = 27.5   Ans: 27.5%
Answer: D
A number a is squared and then multiplied by negative 4. The result of this operation is equal to 4times the sum of FOURTH times a and 1. What is one possible value of a ?  Choose the correct option:	A) 1	B) 2	C) 3	D) 4	E) 5

Solution: -4*a^2=4(4a+1)   a= -1 or -1   a=-1=B   1NSWER:1
Answer: A
8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10 children can do it in 24 days. In how many days can 10 men, 4 women and 10 children together complete the piece of work? Options
A) 5 days B) 15 days C) 28 days D) 6 days E) 7 days

Solution: Explanation:   1 man’s 1 day’s work = 1/8 × 12 = 1/96   10 men’s 1 day’s work = 1 × 10/96 = 5/48   1 woman’s 1 day’s work = 1/192   4 women’s 1 day’s work = 1/192 × 4 = 1/48   1 child’s 1 day’s work = 1/240   10 children’s 1 day’s work = 1/24   Therefore, (10 men + 4 women + 10 children)’s 1 day’s work = 5/48 + 1/48 + 1/24   = 8/48 =1/6   The required No. of days = 6 days   Answer: Option 6 days
Answer: D
The rate fo simple interest in two banks is in the ratio of 4 : 5 . Amith wants to deposit his total saving in these two banks in such a way that he should receive equal half yearly interest from both. He should deposits the saving in the banks in the ratio of:
Choices.
A) 2 : 5  B) 5 : 4  C) 5 : 3  D) 4 : 5  E) 1 : 2

Solution: Let the savings be X and Y and the rates of simple interest be 4x and 5x respectively.   Then X +4x * 1/2 *1/100 = Y + 5x * 1/2 *1/100   or X/Y = 5/4   i.e. X : Y = 5 : 4   ANSWER:5 : 4
Answer: B
The retail price of a washing machine is Rs.1265. If the manufacturer gains 10%, the wholesale dealer gains 15% and the retailer gains 25%, then the cost of the product is	Select the correct option
A) Rs 800
B) Rs 900
C) Rs 700
D) Rs 600
E) Rs 500

Solution: Suppose the cost = Rs X   Therefore, S.P. of the manufacturer = X + 10% of X = 11X/10   S.P. of the wholesale dealer = 11X/10 + 15% of 11X/10 = 11X/10 + 33X/200 = (253/200) X   S.P. of the retailer = 253/200 X + 25% of 253/200X = 253/200 X + 253/800 X = (1265/800) X   Given (1265/800) X = 1265 => X = Rs. 800   Rs 800NSWER:Rs 800
Answer: A
Find the largest number which divides 62, 132 and 237 to leave the same remainder in each case.  Choose the correct answer:
A) 35
B) 25
C) 15
D) 45
E) None of them

Solution: Required number = H.C.F. of (132 - 62), (237 - 132) and (237 - 62)   = H.C.F. of 70, 105 and 175 = 35.   35nswer is 35.
Answer: A
There are 200 questions in a 3 hr examination. Among these questions there are 50 mathematics problems. It is suggested that twice as much time be spent on each maths problem as for each other question. How many minutes should be spent on mathematics problems
Choose the correct option:
A) 36 B) 60 C) 45 D) 72 E) 90

Solution: Let x = minutes spent on a non-math problem   then 2x = minutes spent on a math problem   x(200-50) + 2x(50) = 180   x(150) + 2x(50) = 180   150x + 100x = 180   250x = 180   x = 0.72 minutes   Time to spend on math problems:   2x(50)=100x = 100(0.72) = 72 minutes ANSWER :72
Answer: D
If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 9 less than n. What is y in terms of x ?  Choose the correct choice from the following:  A) 20 - x  B) 9 - x  C) x + 9  D) x - 1  E) x + 1

Solution: Original Digits=xy i.e. Number=10x+y   After reversing the digits:   Digits=yx i.e. Number=10y+x   10y+x is 9 less than 10x+y   10x+y-9=10y+x   10x-x-9=10y-y   9x-9=9y   x+1=y   OR   y=x-1   Ans:x - 1
Answer: D
The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.  Choose the correct choice from the following:
A) 30 B) 40 C) 45 D) 48 E) 54

Solution: Let the price of gift pack be 'aa'   Then number of packs bought =a+1=a+1   Hence total cost is a(a+1)a(a+1)   It is given that 380<a(a+1)380<a(a+1)   If a=19a=19, the total cost =19×20=380=19×20=380   Dexter would not have fallen short, If:   a=20a=20, a(a+1)=420a(a+1)=420   So he would have fallen short by Rs 40.   This is the minimum amount by which he may have fallen short.   40)
Answer: B
A train of 30 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
Select
A) 6
B) 3.3
C) 4
D) 9
E) 2

Solution: D = 30 * 60 + 1500= 
30 * 60 + 1500 = 3_300
3300 m   T= 3300/60 * 18/5= 
3300/60 * 18/5 = 198
198 sec= 3.3 mins   Answer:3.3
Answer: B
A person spent 1/5 of his salary last year on household and 1/4 of the remainder on clothes. What fraction of last year’s salary did the person have left after his household and clothes expenditures?  Choose the most appropriate option
A) 2/3  B) 3/5  C) 2/6  D) 5/4  E) 1/2

Solution: The person spent 1/5 of his salary on household, so remaining is 4/5   1/4 of the remaining is spent is spent on clothes, 1/4*4/5 is 2/10   To make the denominator common, we use 10, so 1/5=2/10   Total amount spent=2/10+2/10=4/10 is the total amount spent on household and clothes   Remaining salary is 6/10 of the total salary reduced to 3/5   Answer is 3/5
Answer: B
I came across this problem in the GMATprep software and got it totally wrong!
A company consists of 6 senior and 4 junior staff officers. If a committee is created with 3 senior and 2 junior staff officers, how many possible committees are there?  Pick one.
A) 12  B) 44  C) 56  D) 120  E) 200

Solution: 6C3*4C2   =120=120
Answer: D
Find 20 % of 240
Choose the correct option:
A) 96
B) 94
C) 86
D) 74
E) 48

Solution: We know that R % of m is equal to R/100 × m.   So, we have 20 % of 240   20/100 × 240   = 48   Answer:48
Answer: E
In what ratio must rice at Rs 9.30 per Kg be mixed with rice at Rs 10.80 per Kg so that the mixture be worth Rs 10 per Kg? Choose the most appropriate option:  A) 5:7  B) 8:7  C) 7:3  D) 3:8  E) 4:7

Solution: Cost of 1 kg of 1st kind=930 P   Cost of 1 kg of 2nd kind=1080 P   Mean Price=1000 P   Cost of 1 kg of 1st kind - Mean Price=1000-930= 
1000-930 = 70
70   Cost of 1 kg of 2nd kind- Mean Price=1080-1000= 
1080-1000 = 80
80   Required ratio= 80 : 70 = 8 : 7   Answer:8:7
Answer: B
The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is Select.
A) 48	B) 22	C) 56	D) 27	E) 35

Solution: Explanation:   Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.   So, the numbers 12 and 16.   L.C.M. of 12 and 16 = 48.   48nswer: Option 48
Answer: A
A dealer sells his goods 10% less at cost price uses 850gm weight for 1kg his gain or loss percentage is Options
A) 21% Gain	B) 21% Loss	C) 17 11/17% Gain	D) 17 11/17% Loss	E) None of these

Solution: Explanation:   17 11/17% Gainost price ---> 850   Selling price --->1000 - 100 = 900   = ( 900 ~ 850 )/850 * 100 = 150/850 * 100 = 17 11/17% Gain   Answer: Option 17 11/17% Gain
Answer: C
Find the circumference of radius 7 cm.	Choose the correct answer.
A) 44 B) 55 C) 66 D) 77 E) 88

Solution: Circumference of circle = 2πr   = 2 × 22/7 × 7   = 44 cm   44NSWER : 44
Answer: A
If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 3 kmph, then the speed of the boat in still water is
Choose the correct choice from the following choices.
A) 12 kmph  B) 13 kmph  C) 14 kmph  D) 15 kmph  E) None of these

Solution: Explanation:   Rate upstream = (7/42)*60= 
(7/42)*60 = 10
10 kmph.   Speed of stream= 3 kmph.   Let speed in sttil water is x km/hr   Then, speed upstream = (x —3) km/hr.   x-3 = 10 or x = 13 kmph   Option 13 kmph
Answer: B
At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $220?  Choices.
A) 1,108 B) 2,100 C) 2,108 D) 2,124 E) 2,218

Solution: I can buy 9 250-pack for Rs 22.95*9= 
22.95*9 = 206.55
$206.55   Now, I can buy 5 20-pack for 3.05*5= 
3.05*5 = 15.25
$15.25   Now, I am left with only $1.15. I cannot but anything with this.   Hence Total Hotdogs= 250*8 + 20*5 = 2218   2,218
Answer: E
Of the science books in a certain supply room, 50 are on botany, 60 are on zoology, 90 are on physics. 40 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science? Choose the correct choice from the following answers:	A) 81	B) 159	C) 309	D) 285	E) 324

Solution: First, you can take all 50 Botany books, all 60 zoology books and all 40 geology books because you're sure to never pick 80 of them.   There are still 90 on physics and 110 on chemistry   The worst case could be that we pick 79 physics and 79 chemistry. So that the next book picked will necessary complete 80 books picked, either in physics or chemistry.   Minimum number of books picked to reach 80 in the same science should be : 50 + 60 + 40 + 79 +79 + 1= 
50 + 60 + 40 + 79 +79 + 1 = 309
309   309
Answer: C
Find the average of all the numbers between 6 and 34 which are divisible by 5.	Choose the correct choice from the following answers: A) 18 B) 20 C) 24 D) 30 E) 32

Solution: Solution   Average	= (10+15+20+25+30/5)   = 100 / 5= 
100 / 5 = 20
20.   Answer 20
Answer: B
How many 5 digit no. can b formed with digits 1, 2, 3,4,5,6 which r divisible by 4 and digits not repeated?
Options:
A) 189
B) 190
C) 191
D) 192
E) 193

Solution: for a no. to be divisible by 4, last two digit should be divisible by 4   last tw0 digit can be 12,16,24,32,36,52,56,64 (8 possibilities)   remaining 3 places can be filled in 4*3*2 ways for each   total 5 digit no. formed = 8*4*3*2= 
8*4*3*2 = 192
192   ANSWER:192
Answer: D
In a school seats for Maths, Physics and Biology in a school are in the ratio 1:2:3. There is a proposal to increase these seats by 10%,20% and 30%. What will be the ratio of increased seats?  Choose the most appropriate option:
A) 1:4:9  B) 16:34:47  C) 11:24:39  D) 15:42:77  E) 5:15:26

Solution: Let the number of seats of M,P,B be x,2x,3x   Number of increased seats are 110% of x , 120% of 2x , 130% of 3x   x*110/100 , 2x*120/100 and 3x*130/100   i.e. 11x/10, 12x/5 and 39x/10   Required ratio = 11x:24x : 39x = 11:24:39   Answer is 11:24:39
Answer: C
In an election between the two candidates ,The candidates who gets 60% of votes polled is wined by 280 votes majority. What is the total number of votes polled?	Choose the correct choice from the following options:
A) 1400
B) 1500
C) 1600
D) 1700
E) 1800

Solution: Note : majority (20 %) = difference in votes polled to win (60 %) & defeated candidates (40 %)   20 % = 60 % - 40 %   20% -----> 280 (20×14 = 280 )   100% -----> 1400 (100×14 = 1400)   1400
Answer: A
The length of a rectangular hall is 5m more than its breadth. The area of the hall is 750 m. The length of the hall is?
Choose the correct choice from the following options:
A) 22
B) 25
C) 27
D) 19
E) 12

Solution: Let breadth = x m   Then, length = (x+5)m   x(x+5) = 750   x² + 5x - 750= 0   (x+30)(x-25)= 0   x = 25   Answer: 25
Answer: B
A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?  Options
A) 32:42 B) 32:41 C) 32:45 D) 32:49 E) 32:47

Solution: A : B   (8000*4)+(4000*8) : (9000*6)+(6000*6)   64000 : 90000   32 : 45   Answer: 32:45
Answer: C
A sum of Rs.4500 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.  Choose the most appropriate option.
A) Rs.2925 B) Rs.3120 C) Rs.3320 D) Rs.2760 E) None of these

Solution: Let A be the amount received at the end of the three years.   Rs.2925 = 4500[1 + 10/100][1 + 20/100][1 + 25/100]   Rs.2925 = (4500 * 11 * 6 * 5)/(10 * 5 * 4)   Rs.2925 = Rs.7425   So the interest = 7425 - 4500 = Rs.2925   Rs.2925NSWER:Rs.2925
Answer: A
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: Options.
A) 3 days B) 4 days C) 5 days D) 6 days E) 7 days

Solution: Let 1 man's 1 day's work = x and 1 boy's 1 day's work = y.   Then, (6x + 8y) = 1/10 and (26x + 48y) = 1/2.   Solving these two equations, we get : x = 1/100	and y = 1/200.   (15 men + 20 boy)'s 1 day's work = (15/100 + 20/200) = 1/4.   Therefore, 15 men and 20 boys can do the work in 4 days.   CORRECT OPTION: "4 days".
Answer: B
A train running at the speed of 180 km/hr crosses a pole in 18 seconds. What is the length of the train? Choose the correct option:  A) 800  B) 900  C) 950  D) 1000  E) 1050

Solution: Speed=(180 x(5/18)m/sec	=(50)m/sec.   Length of the train = (Speed x Time).   Length of the train =	((50)x 18)m = 900 m   900
Answer: B
If a certain number of labours can dig earth 100m deep, 25m long, and 30m broad in 12 days, then find the number of days the same number of labours will require to dig earth 75m deep, 20m long and 50m broad.
Choose the correct choice
A) 12 B) 18 C) 6 D) 1 E) 2

Solution: Explanation :   More number of days means more length, more depth and more width. Hence, its a direct proportion.   (100*25*30):(75*20*50) :: 12:x   75000:75000::12:x   x = 12   12nswer : 12
Answer: A
In a bag there are a certain number of orange balls and blue balls. The probability of picking up exactly 1 blue ball when 2 balls are randomly drawn, is 1/2. Which of the following is the ratio of the number of orange balls to blue balls in the bag Choose the correct choice:
A) 2:1 B) 1:1 C) 1:31 D) 1:3 E) 1:5

Solution: since the probability of drawing a blue ball out of two picks is 1/2.   the ratio of the blue ball to orange balls should be 1:1   Answer : 1:1
Answer: B
The simple interest on a sum of money will be Rs.400 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year?
Choose the most appropriate option
A) 2261	B) 2888	C) 1200	D) 800	E) 2771

Solution: P --- 10 ---- 400   P --- 5 ----- 200   3P --- 5 ----- 600   ------   => 800   Answer: 800
Answer: D
Club X has more than 20 but fewer than 50 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 4 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?
Choose one.
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: The number of members is 4j+3 = 5k+4.   Let's start at 4(5)+3 = 23 and keep adding 4 until we find a number in the form 5k+4.   23, 27, 31, 35, 39 = 5(7) + 4   The club has 39 members.   39/6 = 6(6) + 3   The answer is 3.
Answer: C
What is the rate percent when the simple interest on Rs.800 amount to Rs.144 in 4 Years?
Choose the most appropriate option.
A) 5% B) 8% C) 3% D) 4.5% E) 1%

Solution: 144 = (800*4*R)/100   R = 4.5%   Answer: 4.5%
Answer: D
A man can row upstream at 40 kmph and downstream at 52 kmph, and then find the speed of the man in still water?  Options.
A) 27	B) 40	C) 42	D) 46	E) 24

Solution: US = 40   46S = 52   M = (40 + 52)/2= 
(40 + 52)/2 = 46
46   Answer:46
Answer: D
Find the value of x from the below equation: x^2−7x+10=0  Choose the correct choice:
A) 5 or 2
B) 1 or 3
C) 1 or 7
D) 3 or 5
E) None

Solution: Here we need to find out a and b such that a + b = -7 and ab = +10   a = -5 and b = -2 satisfies the above condition.   Hence   x^2−7x+10=(x−5)(x−2)   x2−7x+10=(x−5)(x−2)   x^2−7x+10   =0   ⇒(x−5)(x−2)   =0   x2−7x+10=0⇒(x−5)(x−2)=0   Step 3: Equate each factor to 0 and solve the equations   (x−5)(x−2)   =0   ⇒(x−5)   =0or (x−2)=0   ⇒x= 5 or 2   5 or 2
Answer: A
In a certain store, the profit is 150% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?	Choose the correct answer
A) 30% B) 70% C) 100% D) 50% E) 120%

Solution: Let C.P. = Rs. 100. Then, profit = Rs. 150, S.P. = Rs. 250   New C.P. = 125% of Rs. 100 = Rs. 125.   New S.P. = Rs. 250   Profit = 250 - 125 = Rs. 125   Required percentage = 125/250 * 100= 
125/250 * 100 = 50
50%   ANSWER:50%
Answer: D
What percent of a day is six hours?
Choose the correct choice from the following options
A) 20.83%
B) 25%
C) 18x2/3%
D) 22x1/2%
E) None of these

Solution: Explanation :   Required percentage = (6/24100)%   = 25%.   Answer : 25%
Answer: B
Pipe A fills a tank in 6 minutes. Pipe B can fill the same tank 2 times as fast as pipe A. If both the pipes are kept open when the tank is empty, how many minutes will it take to fill the tank?
Choose the correct option: A) 0.5 B) 1.0 C) 1.5 D) 2.0 E) 2.5

Solution: A's rate is 1/6 and B's rate is 1/3.   The combined rate is 1/6 + 1/3 = 1/2   The pipes will fill the tank in 2 minutes.   The answer is 2.0.
Answer: D
For a certain cylinder, the diameter equals the height. If every length in this cylinder is decreased by 60%, then to the nearest integer, by what percent does the volume decrease?
Choose the correct choice.
A) 22%
B) 40%
C) 60%
D) 84%
E) 94%

Solution: Again, the exact dimensions of the cylinder do not matter, as long as every length increases by the same percent or same ratio. We now have a percent decrease, which means we subtract to construct our multiplier. A 60% decrease means we have a multiplier of 1 – 0.60 = 0.4, and so k = 0.4 as well. For volume we need to cube the scale factor: k^3 = (0.4)^3 = 0.064 {approx} 0.06 approximately. That would be the multiplier for a 94% decrease, because 1 – 0.94 = 0.06; therefore, the volume decreases by 94%. Answer = 94%.
Answer: E
The C.P of 20 pens is equal to the S.P of 12 pens. Find his gain % or loss%?	Select the correct option:
A) 10%  B) 20%  C) 30%  D) 40%  E) 50%

Solution: 20 CP = 12 SP   20 --- 8 CPgain   100 --- ? => 40%   Answer: 40%
Answer: D
Divide $5000 among X,Y in the ratio 2:8. How many $ that X get? Choose the correct option.
A) $1000  B) $1050  C) $1100  D) $1150  E) $1200

Solution: Sum of ratio terms = 2+8= 
2+8 = 10
10   X= 5000*2/10= 
5000*2/10 = 1_000
$1000   $1000nswer is $1000
Answer: A
There are 250 doctors and nurses at a hospital. If the ratio of doctors to nurses is 2 to 3, how many nurses are at the hospital?
Pick one
A) 134
B) 138
C) 142
D) 146
E) 150

Solution: The number of nurses at the hospital is (3/5)*250= 
(3/5)*250 = 150
150.   The answer is 150.
Answer: E
If an integer n is to be chosen at random from the integers 1 to 96, inclusive, what is the probability that n(n + 1)(n + 2) will be divisible by 8?	Choose the correct choice from the following
A) 1/4	B) 3/8	C) 1/2	D) 5/8	E) 3/4

Solution: total nos of ways in which we can choose n = 96   n(n + 1)(n + 2) will be divisible by 8?   case 1: n = odd then n+2 =odd & n+1 will be even i.e this needs get divided by 8, hence is a multiple of 8 so we have 8..96 = 12 multiples to fill the n+1 pos hence 12 ways   case 2: n is even then n+2 will be even & the product will be divisible by 24 & thus 8   so nos of values that can be used for n= 2....96 (all even nos) i.e 48 nos   total = 48+12= 
48+12 = 60
60 ways   so reqd P=60/96 =5/8;   ANSWER:5/8
Answer: D
There is 50% increase in an amount in 6 years at S.I. What will be the C.I. of Rs. 12,000 after 3 years at the same rate?
Choose the correct option:
A) 2160
B) 3120
C) 17988
D) 6240
E) 5240

Solution: Let P = Rs. 100. Then, S.I. Rs. 50 and T = 6 years.   R = (100 * 50)/(100 * 6) = 10% p.a.   Now, P = Rs. 12000, T = 3 years and R = 8.33% p.a.   C.I. = [12000 * {(1 + 8.33/100)3 - 1}]   = Rs. 17988   ANSWER:17988
Answer: C
The average marks obtained by 50 candidates in a certain examination is 40.Find the total marks.	Choose the correct option
A) 1800	B) 2000	C) 1640	D) 2200	E) 2400

Solution: Following the above formula, we have the total marks =50*40= 
50*40 = 2_000
2000   Answer is 2000
Answer: B
If 20% of (x-y) = 15% of (x+y), then what percent of x is y?	Pick:  A) 50.5%  B) 44.4%  C) 22.2%  D) 14.3%  E) 25%

Solution: 20% of (x-y) = 15% of (x+y)   20/100 (x-y) = 15/100 (x+y)   5x = 35y   Required percentage = y/x *100 = 5y/35y * 100 = 14.28%   Answer is 14.3%
Answer: D
30 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. Choose the correct choice
A) 190	B) 200	C) 210	D) 220	E) 435

Solution: or, if there are n persons then no. of shakehands = nC2 = 30C2 = 435   ANSW435R:435
Answer: E
If a - b = 3 and a2 + b2 = 29, find the value of ab.
Pick one
A) 10
B) 12
C) 13
D) 15
E) 18

Solution: 2ab = (a2 + b2) - (a - b)2   = 29 - 9= 
29 - 9 = 20
20   ab= 10.   answer :10
Answer: A
A Prototype fuel-efficient car (P-Car) is estimated to get 80% more miles per gallon of gasoline
than does a traditional fuel-efficient car (T-Car). However, the P-Car requires a special type
of gasoline that costs 20% less per gallon than does the gasoline used by a T-Car. If the two
cars are driven the same distance, what percent less than the money spent on gasoline for the
T-Car is the money spent on gasoline for the P-Car?
Choose the correct choice from the following answers:  A) 16 2/3%  B) 33 1/3 %  C) 50%  D) 55.56%  E) 66 2/3 %

Solution: Assumption   Miles/Gallon   T = 100   P = 180 ( 80% more)   $/gallon   T = 100   P = 80 (20% less)   Miles   100 for both   Cost = (Miles X $/ Gallon)/ M/gallon   T = 100   P = 44.44   Hence 100 - 44.44= 
100 - 44.44 = 55.56
55.56%   Ans 55.56%
Answer: D
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:  Choose the correct option
A) 14
B) 17
C) 19
D) 22
E) 24

Solution: Let the son's present age be x years. Then, (38 - x) = x   2x = 38.   x = 19.   Son's age 5 years back (19 - 5)= 
(19 - 5) = 14
14 years.   14nswer : 14
Answer: A
he total marks obtained by a student in Physics, Chemistry and Mathematics is 110 more than the marks obtained by him in Physics. What is the average mark obtained by him in Chemistry and Mathematics?  Choose the correct choice from the following options:  A) 55  B) 65  C) 75  D) 85  E) 95

Solution: Let the marks obtained by the student in Physics, Chemistry and Mathematics be P, C and M respectively.   P + C + M = 110 + P   C + M = 110   Average mark obtained by the student in Chemistry and Mathematics = (C + M)/2 = 110/2= 
110/2 = 55
55.   55NSWER:55
Answer: A