MU-NLPC/Calc-aqua_rat huggingface dataset:
A departmental store has 9 managers and 18 associates. The 9 managers have an average salary of $1300. The 18 associates have an average salary of $12,000. What is the average salary for the departmental store?  Choose the correct choice
A) $3556.25	B) $3988.89	C) $3836.56	D) $3745.56	E) $3428.56

Solution: Number of managers is 9   Their average salary is $1300   Number of associates is 18   Their average salary is $12,000   Total salary of managers is  9*1300= 
 9*1300 = 11_700
$11700   Total salary of associates is 18*12,000=$96,000   Total salary for the departmental store is 96,000+11700=107700   Average salary for the departmental store is 107700/9+18=3988.89   Answer is $3988.89
Answer: B
The average of 11 results is 50, if the average of first six results is 49 and that of the last six is 52. Find the sixth result? Choose the correct choice from the following answers:
A) 21  B) 56  C) 18  D) 25  E) 23

Solution: 1 to 11 = 11 * 50= 
11 * 50 = 550
550   1 to 6= 6 * 49= 
6 * 49 = 294
294   6 to 11= 6 * 52= 
6 * 52 = 312
312   6th= 294 + 312 – 550 = 56   Answer:56
Answer: B
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is: Choose the correct choice:
A) 10  B) 6  C) 5  D) 4  E) 3

Solution: Explanation :   Speed of the motor boat = 15 km/hr   Let speed of the stream = v   Speed downstream = (15+v) km/hr   Speed upstream = (15-v) km/hr   Time taken downstream = 30/(15+v)   Time taken upstream = 30/(15−v)   total time = (30/(15+v)) + (30/(15−v))   It is given that total time is 4 hours 30 minutes = 4(1/2) hour = 9/2 hour   i.e.,(30/(15 + v)) + (30/(15 − v)) = 9/2   ⇒ (1/(15+v)) + (1/(15−v)) = 9/(2×30) = 3/20   ⇒ (15 − v + 15 + v)/(15+v)(15−v) = 3/20   ⇒ (30/152)− (v2) = 3/20   ⇒ (30/225−v2) = 3/20   ⇒ 10/(225−v2) = 1/20   ⇒225 − v2= 200   ⇒ v2 = 225 − 200 = 25   ⇒ v = 5 km/hr. Answer : Option 5
Answer: C
Working together, 7 identical pumps can empty a pool in 4 hours. How many hours will it take 5 pumps to empty the same pool?  Pick one:
A) 4 2/3
B) 9 1/4
C) 9 1/3
D) 9 3/4
E) 5 3/5

Solution: The answer is E   7 pumps take 4 hours. 1 Pump will take 4*7 hours . Hence 5 pumps will take (4*7)/5 = 5 6/10 = 5 3/5 hours
Answer: E
How many words can be formed by using all letters of the word ‘JUPITER’ ?
Options.
A) 3220	B) 3640	C) 4420	D) 5040	E) 5680

Solution: The word contains 7 different letters.   The number of permutations is 7! = 5040   The answer is 5040.
Answer: D
A cistern which could be filled in 5 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it?
Answers:	A) 76 hrs	B) 99 hrs	C) 55 hrs	D) 90 hrs	E) 10 hrs

Solution: 1/5 - 1/x = 1/10   => 10 hrs   Answer: 10 hrs
Answer: E
The difference between 3/5 of 2/3 of a number and 2/5 of 1/4 of the same number is 288. What is the number?  Choose the most appropriate option
A) 960	B) 850	C) 895	D) 955	E) 975

Solution: according to the given condition   x*(2/3)*(3/5) - x*(2/5)*(1/4) = 288   so 2x/5 - x/10 = 288   or 3x/10 = 288   or x = 2880/3= 
2880/3 = 960
960   960NSWER:960
Answer: A
A school having three classes only have student strength of 40, 20 and 40 respectively. The pass percentages of these classes are 20%, 30% and 100% respectively. What is the pass percentage for the entire school? Choices.
A) 54%  B) 76%  C) 34%  D) 66%  E) 46%

Solution: 20% of 40+30% of 20+100% of 40   =8+6+40= 
8+6+40 = 54
now 54 of 100= 54%   54%NSWER:54%
Answer: A
There is a total of 90 marbles in a box, each of which is red, green, blue, or white. If one marble is drawn from the box at random, the probability that it will be white is 1/6 and the probability that it will be green is 1/5. What is the probability that the marble will be either red or blue? Options:
A) 3/5
B) 7/15
C) 11/15
D) 19/30
E) 23/30

Solution: P(red or blue) = 1 - P(white) - P(green) = 30/30 - 5/30 - 6/30 = 19/30   The answer is 19/30.
Answer: D
Aarti can do a piece of work in 5 days. In how many days will she complete three time of work of same type?
Answers
A) 6 days	B) 18 days	C) 21 days	D) 3 days	E) 15 days

Solution: We have the important relation, More work, More time (days)   A piece of work can be done in 5 days.   Three times of work of same type can be done in 5 x 3   = 15 days   Answer 15 days
Answer: E
Tough and Tricky questions: Word Problems.
ABZ Car Company wants to manufacture a new car known as Model X, and it is trying to determine how many cars it needs to sell in order to make an annual profit of $30,500,000. The annual fixed costs for Model X total $50,200,000. In addition, each Model X car has an average cost of $5,000 per vehicle to manufacture. If the Company forecasts it will sell 20,000 Model X cars this year, at what price must the Company sell the car to achieve the desired annual profit? Choose the correct answer:	A) $4,035	B) $4,036	C) $9,035	D) $16,140	E) $36,140

Solution: The ABZ company plans to make a profit of $30,500,000 and it needs to earn the fixed costs of $50,200,000, so it needs to earn $80,700,000 on top of the costs for the production of the 20,000 cars.   Therefore, price of each car needs to be the unit costs plus $80,700,000/20,000. After removing the 0's, we end with the unit costs plus $8,070/2, which is $5,000 plus $4,035. Therefore, Answer $9,035 is correct.
Answer: C
The sum of the present ages of a father and his son is 47 years. Six years ago, father's age was four times the age of the son. After 6 years, son's age will be:	Pick one: A) 13 B) 15 C) 17 D) 19 E) 21

Solution: Let the present ages of son and father be x and (47 - x) years respectively.   Then, (47 - x) - 6 = 4(x - 6)   41 - x = 4x - 24   x = 13   The son's age after 6 years will be 19.   The answer is 19.
Answer: D
A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 20.00? Choose the correct choice from the following answers
A) $ 10.00	B) $ 11.20	C) $ 14.40	D) $ 16.00	E) $ 18.00

Solution: For retail price = $20   First maximum discounted price = 20 - 30% of 20 = 20-6= 
20-6 = 14
14   Price after additional discount of 20%= 14 - 20% of 14 = 14 - 2.8= 
14 - 2.8 = 11.2
11.2   Answer: Option $ 11.20
Answer: B
Population of a city decreases by 10% at the end of first year and increases by 10% at the end of second year and again decreases by 10% at the end of third year. If the population of the city at the end of third year is 4455, then what was the population of the city at the beginning of the first year?	Select.
A) 5,000  B) 4,500  C) 4,950  D) 1,000  E) 2,000

Solution: M. F = 90/100*110*100*90/100 = 81*11/1000   Population before 3Yrs = I.Q /M. F = 4455*1000/81*11   = 5000   5,000NSWER:5,000
Answer: A
If N = 2^0.15 and N^b = 8, b must equal  Select
A) 3/80
B) 3/5
C) 20
D) 5/3
E) 80/3

Solution: 15/100 = 3/20   N = 2 ^ 3/20   N^b = 2^3   (2^3/20)^b = 2^3   b = 20   Answer: 20
Answer: C
A solution of X pounds of water and sugar is boiled until 20% of the water content evaporates. Originally p% of sugar was present in the solution. After evaporation, what percentage of the solution is sugar?  Choose the most appropriate option.
A) 100p/(1-p)	B) 80p/(1-p)	C) 75p/(1-p)	D) 100p/(80-0.2p)	E) 100p/(80+0.2p)

Solution: We'll go for the ALTERNATIVE approach since there are variables in all the answers (which means that any number could work). Since the question deals with percents, the easiest number to use is X = 100. Now let's say that p = 10. Before the evaporation we had 10 pound of sugar and 90 pounds of water. Since only water evaporated, after the evaporation the 10 pounds of sugar remained the same, but the water reduced by 20% of 90 (18 pounds), so we have only 72 pounds of water. 10 out of 82 is the fraction of sugar, so if we multiply it by 100 we get the percents. The correct answer is 100p/(80+0.2p): 100p/(80+0.2p) >>> 100x10 / 82
Answer: E
An order was placed for the supply of a carper whose length and breadth were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and breadth were in the ratio 7 : 3 but were was no change in its parameter. Find the ratio of the areas of the carpets in both the cases?  Select the correct option:
A) 8:4  B) 8:7  C) 8:2  D) 8:3  E) 8:1

Solution: Let the length and breadth of the carpet in the first case be 3x units and 2x units respectively.   Let the dimensions of the carpet in the second case be 7y, 3y units respectively.   From the data,.   2(3x + 2x) = 2(7y + 3y)   => 5x = 10y   => x = 2y   Required ratio of the areas of the carpet in both the cases   = 3x * 2x : 7y : 3y   = 6x2 : 21y2   = 6 * (2y)2 : 21y2   = 6 * 4y2 : 21y2   = 8:7   Answer: 8:7
Answer: B
There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 64%  Pick: A) 18.75 B) 19.75 C) 20.75 D) 21.75 E) 22.75

Solution: 60*84/100= 
60*84/100 = 252/5 = around 50.4
50.40 lit milk that is 9.60 lit water   let x lit water will be added then   (60+x)*64/100=50.40   so x=18.75   18.75NSWER:18.75
Answer: A
270 candidates appeared for an examination, of which 252 passed. The pass percentage is :	Choose the correct choice from the following choices.
A) (93 + 1/9 )%
B) (93 + 1/3 )%
C) (93 + 9/3 )%
D) (94 + 9/3 )%
E) (43 + 1/3 )%

Solution: Answer: (93 + 1/3 )%) (93 + 1/3 )%
Answer: B
In an examination 80% pass in english, 70%pass in maths , 10%fail in both ,
144 pass in both . How many all appeared to the test?  Choose the most appropriate option.
A) 260 B) 240 C) 370 D) 120 E) 150

Solution: E : 80%, Fail in both: 10%, therefore only M pass is 10%   M: 70%, fail in both: 10%, therefore only E pass is 20%   100% = all fail + only E pass + only M pass + both E and M   pass   100%=10%+20%+10% + both E and M pass   Therefore, both E and M pass = 60%   60%=> 144   100% => 240   Answer: 240
Answer: B
A taxi charges p dollars for the first two miles and c cents per quarter mile for every mile after the first two. Which equation describes cost of a taxi ride of n miles in dollars.  Answers
A) pn – c/8(100)  B) cp + 4n-8/200  C) p + (4cn-8c)/100  D) p + 100cn/4  E) 4cp(n-2) – 100

Solution: This is about as complicated as these types of problems come, but it is essentially the same as any problem which has an initial cost which is added to a dependent additional cost. Looking at the problem, we notice that the cost p is added to the mile dependent cost, which is some combination of the other terms listed in the problem. With just that knowledge we can eliminate all but two of the answer choices! Choices (A), (B), and (E) either do some strange calculation with the initial cost p, or subtract the additional cost from p. Both of these circumstances would be next to impossible if there is an initial cost being added to another cost. Thus, we only have to choose between choice (C) and choice (D). We can easily find the right answer by plugging in real numbers and checking which choice yields a correct answer. We can also see that answer choice (D) seems to be multiplying the cost in cents by 100, which, if the trip was 6 miles and the charge per mile was 25 cents, would make the taxi cost an additional $3750! This seems impossible, and leaves only the correct answer choice, (p + (4cn-8c)/100).
Answer: C
How many words can be formed from the letters of the word ‘DIRECTOR’
So that the vowels are always together?	Answers:
A) 1240
B) 2630
C) 4702
D) 2160
E) 1205

Solution: In the given word, we treat the vowels IEO as one letter.   Thus, we have DRCTR (IEO).   This group has 6 letters of which R occurs 2 times and others are different.   Number of ways of arranging these letters = 6!/2! = 360.   Now 3 vowels can be arranged among themselves in 3! = 6 ways.   Required number of ways = (360x6) = 2160.   ANSWER 2160 2160
Answer: D
Five persons having ages in ascending order with exact difference of 5 years, decided to donate for a charity ,an amount equal to fifty times of their ages. The total donation was Rs 8750.Find the ages of five persons ? Choose the correct answer:
A) 31
B) 32
C) 33
D) 34
E) 35

Solution: 25,30,35,40,45 are the ages.   let ages be x-10,x-5,x,x+5,x+10   given 50(5x)=8750   x=35   ANSW35R:35
Answer: E
If the sides of two cubes are in the ratio 3: 1 the ratio of their total surface area is?	Choose the correct choice from the following choices:  A) 3:1  B) 8:1  C) 9:1  D) 12:1  E) 9:1

Solution: a1 : a2 = 3 : 1   6 a12 : 6 a22 = 9: 1   ANSWER:9:1
Answer: C
A bag is filled with pennies and nickels in the ratio of 2 to 1. There are 10 nickles in the bag, how many coins are there in that bag?	Pick:
A) 30
B) 50
C) 65
D) 70
E) 80

Solution: A ratio of pennies to nickels of 2 to 1 means that we can write the number of pennies and nickels in the form   number of pennies = 2x and number of nickels = x   But we know the number of nickels, 10. Hence   x = 10   The total number of coins is given by   2x + x = 3x = 3 × 10 = 30   30nswer : 30
Answer: A
On rainy mornings, Mo drinks exactly N cups of hot chocolate (assume that N is an integer). On mornings that are not rainy, Mo drinks exactly 3 cups of tea. Last week Mo drank a total of 26 cups of tea and hot chocolate together. If during that week Mo drank 10 more tea cups than hot chocolate cups, then how many rainy days were there last week?
Options:
A) 0  B) 1  C) 4  D) 5  E) 6

Solution: T= the number of cups of tea   C= the number of cups of hot chocolate   T+C = 26 T-C=10 -> T= 18. C=8.   Mo drinks 3 cups of tea a day then number of days that are not rainy = 18/3= 
18/3 = 6
6   So number of rainy days= 7-6= 
7-6 = 1
1   1 is the answer.
Answer: B
There are 5 orators A, B, C, D, E. In how many ways can the arrangements be made so that A always comes before B and B always comes before C.  Choose the most appropriate option
A) 5! / 3!  B) 8! / 6!  C) 5! x 3!  D) 8! / (5! x 3!)  E) 8! / (5! x 4!)

Solution: Select any three places for A, B and C. They need no arrangement amongst themselves as A would always come before B and B would always come before C.   The remaining 2 people have to be arranged in 2 places.   Thus, 5C3 x 2! = 5! / 3!   5! / 3!NSWER:5! / 3!
Answer: A
A sum of money amounts to Rs. 9800 after 5 years and Rs. 12015 after 8 years at the same rate of simple interest. The rate of interest per annum is?
Choose one:
A) 12.05%	B) 5%	C) 13.05%	D) 22.05%	E) 18.05%

Solution: S.I. for 3 years = (12015 - 9800) = Rs. 2215   S.I. for 5 years = Rs. 2215/3 * 5 = Rs. 3691.   Principal = (9800 - 3675) = Rs. 6108   Hence, rate = (100 * 3691) / (6125 * 5) = 12.05%   12.05%NSWER:12.05%
Answer: A
If the two hands in a clock are 11 minutes divisions apart,then the angle between them is
Choose one:
A) 66Â°
B) 18Â°
C) 24Â°
D) 60Â°
E) None of these

Solution: In a clock, each minute makes 6Â°   âˆ´ 11 minutes will make 6 Ã— 11 = 66Â°   66Â°nswer 66Â°
Answer: A
Let's say in a lottery Samuel have a 4% chance of winning the jackpot.
All lined up and 1st four people on the line lose. Samuel is 5th in the row.
What's the chance of Samuel winning now? Select:
A) 2%  B) 3%  C) 4%  D) 5%  E) 6%

Solution: Solution:   4%   Explanation:   The winning chance probability is still 4% as the outcome of Samuel winning the lottery is a separate event from the 1st four losing it.   Answer 4%
Answer: C
One out of every 3000 computer chips is defective. If 2 out of every 30 defective chips have defective processors and there are 30 defective processors in the first batch, how many computer chips are there in the first batch?  Choose the correct choice from the following answers
A) 450  B) 900  C) 90,000  D) 1350,000  E) 900,000

Solution: (D) Read the whole question to get the feel of what they are asking you to find. Then start with the smallest amount and work your way outwards. We are told that two out of every 30 defective chips have a defective processor. Let x be the total number of defective processors in the batch. Because we know 2 out of every 30 defective chips will have defective processors, and the total number of defective processors in the batch is 30, we can write out an equation: (2/30)x = 30. This can be simplified to (1/15)x = 30. Multiplying each side by 15, we arrive at x = 450. This tells us that there are 450 defective chips in the whole batch. Because we know that 1 out of every 1000 chips is defective, we can set up a proportion. If 1 out of every 3000 chips is defective, then 450 out of y chips would be defective, where y is the total number of chips in the batch. This can be set up as an equation as follows: 1/3000 = 450/y. Solve for y and you will get the total number of chips in the batch: 1350,000.   The answer is (1350,000).
Answer: D
39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?	Pick
A) 9
B) 12
C) 10
D) 13
E) 15

Solution: Explanation:   Let the required number of days be x   More persons, less days (indirect proportion)   More hours, less days (indirect proportion)   Hence we can write as   (persons)39:30   (hours) 5:6}:: x:12   ⇒39×5×12=30 × 6 × x   ⇒39×5×2=30 × x   ⇒39=3×x   ⇒x=13   Answer: Option 13
Answer: D
Bookman purchased 55 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 360, how many paperback copies were sold?
Select
A) 8
B) 10
C) 12
D) 19
E) 16

Solution: The bookman had 10 hardback ad  55-10= 
 55-10 = 45
45 paperback copies;   14 copies were sold, hence  55-14= 
 55-14 = 41
41 copies were left. Let # of paperback copies left be p then 10p+20(41-p)=560 --> 10 p=260 --> p=26   # of paperback copies sold is 45-26= 
45-26 = 19
19   Answer: 19
Answer: D
20 men can cut 30 trees in 4 hours. If 4men leave the job, how many trees will be cut in 6 hours?
Select the correct option.
A) 24  B) 36  C) 48  D) 22  E) 32

Solution: 20 men - working 4 hrs - cut 30 trees   1men - working 1hr - cuts = 30/20*4   Thus 16 men - working 6hrs - cut = 30*16*6 / 20*4 = 36 trees   Answer is 36
Answer: B
The center of a circle lies on the origin of the coordinate plane. If a point (x, y) is randomly selected inside of the circle, what is the probability that y > x or x < 0?  Pick
A) 5/8	B) 4/5	C) 3/8	D) 1/2	E) 3/4

Solution: The line y=x divides the circle into two equal areas.   All the points above the line y=x satisfy the condition that y > x.   All the points to the left of the y-axis satisfy the condition that x < 0.   The union of these two areas is 5/8 of the circle.   The answer is 5/8.
Answer: A
A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent J of the distribution is less than m +d ?  Choose the correct choice from the following answers
A) 16%  B) 32%  C) 48%  D) 84%  E) 92%

Solution: D   The prompt says that 68% of the population lies between m-d and m+d.   Thus, 32% of the population is less than m-d or greater than m+d.   Since the population is symmetric, half of this 32% is less than m-d and half is greater than m+d.   Thus,J= (68+16)% or (100-16)% of the population is less than m+d.84%
Answer: D
In Township K each property is taxed at 8 percent of its assessed value. If the assessed value of a property in Township K is increased from $180,000 to $24,000, by how much will the property tax increase?
Pick one:
A) $32	B) $50	C) $480	D) $400	E) $500

Solution: Increase in house value = $24,000 - $18,000 =$8000   So, tax increase = 8% of$6000=$480   Answer: $480
Answer: C
1904 x 1904 =?
Choices:  A) 3654316  B) 3632646  C) 3625216  D) 3623436  E) None of them

Solution: =(1904)^2   =(1900+4)^2   =(1900)^2 + 4^2 + 2 x 1900 x 4   =3610000+16+15200   =3610016+15200= 
3610016+15200 = 3_625_216
3625216   Answer is 3625216
Answer: C
Two trains travelling in the same direction at 72 and 36 kmph completely pass off another in 1 minute. If the length of the first train is 250 m, what is the length of the second train? Pick:	A) 228	B) 350	C) 175	D) 99	E) 171

Solution: RS = 72 â€“ 36 = 36 * 5/18= 
36 * 5/18 = 10
10 mps   T= 60 sec   D = 10 * 60= 
10 * 60 = 600
600 m   250   --------   350 m   Answer: 350
Answer: B
The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?  Pick
A) 1000
B) 3000
C) 2400
D) 5000
E) 7000

Solution: Explanation:   Let the price of a saree and a shirt be Rs. x and Rs. y respectively.   Then, 2x + 4y = 1600 .... (i)   and x + 6y = 1600 .... (ii)   Divide equation (i) by 2, we get the below equation.   => x + 2y = 800. --- (iii)   Now subtract (iii) from (ii)   x + 6y = 1600 (-)   x + 2y = 800   ----------------   4y = 800   ----------------   Therefore, y = 200.   Now apply value of y in (iii)   => x + 2 x 200 = 800   => x + 400 = 800   Therefore x = 400   Solving (i) and (ii) we get x = 400, y = 200.   Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.   Answer is 2400
Answer: C
Arun and Tarun can do a work in 10 days.After 4 days tarun went to his village.How many days are required to complete the remaining work by Arun alone.Arun can do the work alone in 60 days.  Options
A) 36 days. B) 17 days. C) 18 days. D) 19 days. E) 20 days.

Solution: They together completed 4/10 work in 4 days.   balance 6/10 work will be completed by Arun alone in   60*6/10= 
  60*6/10 = 36
36 days.   36 days.NSWER:36 days.
Answer: A
Rs. 700 is divided among A, B, C so that A receives half as much as B and B half as much as C. Then C's share is
Answers.
A) Rs 429 B) Rs 412 C) Rs 400 D) Rs 129 E) Rs 122

Solution: Let C = x.   Then B = x/2   and A = x/4   A:B:C = 1:2:4.   Rs 400's share Rs.[(4/7)*700) = 400   Answer: Rs 400
Answer: C
Two trains are running in opposite directions with the same speed. If the length of each train is 100 metres and they cross each other in 12 seconds, then the speed of each train (in km/hr) is:	Choose one:  A) 31 km/hr.  B) 30 km/hr.  C) 34 km/hr.  D) 35 km/hr.  E) 36 km/hr.

Solution: Let the speed of each train be x m/sec.   Then, relative speed of the two trains = 2x m/sec.   So, 2x = (100 + 100 )/12   2x = 16.6   x = 8.3.   Speed of each train = 8.3 m/sec = 8.3 x 18/5 km/hr = 30 km/hr.   answer :30 km/hr.
Answer: B
A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 52000, then the share of A is? Choose one
A) s.28028
B) s.28000
C) s.28003
D) s.28029
E) s.24029

Solution: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6   Total profit = Rs. 52000   Share of s.28000 = 7/13 (52000) = Rs.28000   Answer: s.28000
Answer: B
If -1<x<0, what is the median J of these six numbers listed below
1/x^3,1/x^2, 1/x,x, x^2,x^3  Choices:
A) 1/x	B) x^2	C) x^2(x+1)/2	D) J=x(x^2+1)/2	E) x^2/2x

Solution: My approach: Put any value between -1 and 0. you will get the answer. lets say 0.5. so the list will be as follows:   -8,-2,-0.5,-0.125 and last two numbers will be positive so need to see that.   median will be between -0.5 and -0.125.   So, (x^3+x)/2 (J=x(x^2+1)/2).
Answer: D
Two trains of length 100 meters and 200 meters are 140 meters apart. They are moving towards each other on parallel tracks, at speeds of 54 km/h and 72 km/h. After how many seconds will the trains meet?
Select
A) 2
B) 4
C) 6
D) 8
E) 10

Solution: The speeds are 54000/3600= 
54000/3600 = 15
15 m/s and 72000/3600= 
72000/3600 = 20
20 m/s   The relative speed is 35 m/s.   time= 140 / 35= 
140 / 35 = 4
4 seconds   The answer is 4.
Answer: B
A train is moving at a speed of 60km/hr and its length is 500m. Find the time taken by it to pass a man standing near the railway line?	Choose the correct answer
A) 30sec  B) 45sec  C) 36sec  D) 29sec  E) 52sec

Solution: Speed of the train = 60*5/18 = 50/3 m/sec   Distance moved in passing the standing man = 500m   Required time taken = 500/(50/3)= 
500/(50/3) = 30
30sec   30secnswer is 30sec
Answer: A