MU-NLPC/Calc-aqua_rat huggingface dataset:
There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability that at least one will be orange? Answers.
A) 7/10	B) 3/5	C) 2/5	D) 3/10	E) 1/10

Solution: Probability of the first ball being orange = 2/5   The first all is not replaced, hence the total number of balls for the second pick = 1/4   Therefore the total probability is 2/5 x 1/4 = 1/10   Hence 1/10
Answer: E
The average weight of 20 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.	Choose the correct choice from the following answers: A) 48.79286 B) 42.25 C) 50.87364 D) 51.25 E) 52.25474

Solution: Explanation:   48.79286verage weight of 20 boys = 50.25   Total weight of 20 boys = 50.25 × 20   48.79286verage weight of remaining 8 boys = 45.15   Total weight of remaining 8 boys = 45.15 × 8   Total weight of all boys in the class = (50.25 × 20)+ (45.15 × 8)   Total boys = 20 + 8= 
20 + 8 = 28
28   48.79286verage weight of all the boys= (50.25×20)+(45.15×8)/28   =   48.79286nswer: Option 48.79286
Answer: A
How many factors of 880 are odd numbers greater than 1?  Choose the correct choice from the following answers
A) 3
B) 4
C) 5
D) 6
E) 7

Solution: When factorized, 880 has 6 prime factors. Of these prime factors 2 are odd and 4 are even. Hence total number of odd factors is 2*2(4), which includes 4. The total number of odd factors greater than 1 are 3.(option 3)
Answer: A
The average of six number is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. what is the average of the remaining four number ? Choose the correct answer:
A) 2.3
B) 4.6
C) 4.7
D) 4.8
E) None of these

Solution: solution:   Sum of the remaining four numbers = (3.95 × 6) - [(3.4 × 2) + (3.85 ×2)]   =23.70 -(6.8 + 7.7) = 23.70 - 14.5 = 9.20.   ∴ Required average =9.2/4= 
9.2/4 = 2.3
2.3 2.3nswer 2.3
Answer: A
The operation # is defined for all nonzero q and y by #y = q + q/y. If a>0, then 1#(1#a) =
Answers
A) a  B) a+1  C) a/(a+1)  D) (a+2)/(a+1)  E) (2a+1)/(a+1)

Solution: q#y = q + q/y. If a>0, then 1#(1#a) =   You can see that a stands for y and 1 stands for q. I like to work with numbers so I did q=1 a=2 and a=y so y=2   1#a= 1+(1/2)= 
1+(1/2) = 3/2 = around 1.5
1.5 so now a is 1.5 --> 1+(1/1.5)=1 2/3 = 5/3   So now you can check by filling in a, which is 2:   A. a --> 2   B. a+1 --> 2+1=3   C. a/(a+1)-->2/(2+1)=2/3   D. (a+2)/(a+1)-->(2+2)/(2+1)=4/3   E. (2a+1)/(a+1)-->(2*2+1)/(2+1)=5/3   So (2a+1)/(a+1) is the answer.
Answer: E
Find the value of x: x² + 4x + 4.	Choose the most appropriate option.
A) 2  B) 4  C) -2  D) -4  E) 0

Solution: That quadratic is factored as follows:x² + 4x +4 = (x+2)(x+2).Lesson 17.Now, it is easy to see that the second factor will be 0 when x = -2.The solution is:x	=	-2 -2
Answer: C
A clerk multiplied a number by ten when ten should have divided it. The answer he got was 100.what should the ans have been? Choose one
A) 3	B) 1	C) 2	D) 4	E) 5

Solution: let the number be x   actually form = x/10   but x*10=100   =>x=10   means the number the should be divided is 10   =>the answer would have been (10/10)= 
(10/10) = 1
1   ANSWER:1
Answer: B
The sale price at which a store sells an article is 25% more than its cost price. If the sale price is an integer, which of the following cannot be the cost price?	Choose the most appropriate option:  A) $12  B) $16  C) $31  D) $56  E) $92

Solution: Sale Price = (5/4)*(Cost Price)   If the sale price is an integer, then the cost price must be divisible by 4.   The answer is $31.
Answer: C
The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Pick:
A) 80,47 kmph
B) 80,80 kmph
C) 80,42 kmph
D) 80,40 kmph
E) 83,40 kmph

Solution: Speed downstream = 60 + 20= 
60 + 20 = 80
80 kmph   Speed upstream= 60 - 20= 
60 - 20 = 40
40 kmph.Answer:80,40 kmph
Answer: D
If 24 men can do a piece of work in 25 hours, in how many hours will 15 men
do it ?  Choose the correct option: A) 40 hours B) 45 hours C) 50 hours D) 55 hours E) 60 hours

Solution: Let the required number of hours be x. Then,   Less men, More hours	(Indirect Proportion)   15 : 24 : : 25 : x<=>(15 x x) =(24 x 25)<=>(24 x 25)/15 = 40   Hence, 15 men can do it in 60 hours   40 hoursnswer is 40 hours.
Answer: A
There are two sets A and B. The range of set A is 7, and the range of set B is 13. If the two sets are combined and get a new set R, which cannot be the range of the set R?	Choose the most appropriate option.
A) 8 B) B.11 C) C.14 D) D.17 E) E.21

Solution: Let Set A has 1,8 as elements   B has 1,14 as elements.. So Range for Combined set R becomes  14-1= 
 14-1 = 13
13   For range to be 14,   A= 1,8   B= 2,15 (Range=14)   For range to be 17   A=1,8   B= 5,18   For range to be 21:   A=1,8   B= 9 ,22   So we are left with A and B.   Now consider A has elements A= -1,-8 and Thus Range =-1-(-8)= 
-1-(-8) = 7
7   So for Range of combined set to be 11, B needs to have largest elementxso that x- (-8)=11 or x=3...But if x=3, the largest element in Combined Set then smallest element in the combined set will be 3-y=13 or y=-10....And the range of combined set 3-(-10)=13...   Consider Option A   A=-1,-8   B= y,x where y and x are smallest and largest element in Set B   Elements of Combined Set: -8,-1,y and x   Now x-(-8)= 
-(-8) = 8
8 or x=0, then x-y=13 or y=-13...   Range of Combined Set: 0-(-13)= 13...   I don't see how range can be 8 or 11...Can you please post the source and explanation for the OA in spoiler...=B.11
Answer: B
If the radius of the sphere is 14 m. then its total surface area is	Choose one:
A) 2644  B) 2446  C) 2464  D) 6442  E) 6424

Solution: Sphere Total surface area   = 4πr(power2) = 4 × 22/7 × 14 × 14 = 2464   Answer is 2464.
Answer: C
The average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?
Choose the correct answer:	A) 40	B) 41	C) 44	D) 42	E) 43

Solution: Total age of all students =22×21   Total age of all students + Age of the teacher =23×22   Age of the teacher   =23×22−22×21=22(23−21)=22×2=44   Answer is 44.
Answer: C
Find the value of
((0.1)3 + (0.6)3 + (0.7)3 − (0.3)(0.6)(0.7))/((0.1)2 + (0.6)2 + (0.7)2 − 0.006 − 0.42 − 0.07)
Select the correct option
A) 14/10
B) 14/23
C) 15/31
D) 13/15
E) None

Solution: ((0.1)3 + (0.6)3 + (0.7)3 − (0.3)(0.6)(0.7))/((0.1)2 + (0.6)2 + (0.7)2 − 0.006 − 0.42 − 0.07)   => (0.1 + 0.6 + 0.7)3/(0.1 + 0.6 + 0.7)2   => 0.1 + 0.6 + 0.7= 
0.1 + 0.6 + 0.7 = 1.4
> 1.4= 14/10   14/10)
Answer: A
In a clothing store, there are six different colored neckties (red, orange, yellow, green, blue, and indigo) and three different colored shirts (red, orange, yellow, green, blue, and indigo) that must be packed into boxes for gifts. If each box can only fit one necktie and one shirt, what is the probability that all of the boxes will contain a necktie and a shirt of the same color? Choices: A) 719/720 B) 1/120 C) 2/233 D) 1/6 E) 1/720

Solution: 6 ties and 6 shirts...   red tie can take any of 6 shirts..   orange can take any of the remaining 5 shirts   yellow any of remaining 4..   and so on till last indigo chooses the 1 remaining..   Total ways= 3*2*1= 
3*2*1 = 6
6   out of this 6, ONLY 1 way will have same colour tie and shirt..   prob= 1/6   1/6
Answer: D
The circulation for magazine Z in 1971 was 6 times the average (arithmetic mean) yearly circulation for magazine Z for the years 1972-1980. What is the ratio of the circulation in 1971 to the total circulation during 1971-1980 for magazine Z ?	Pick one
A) 4/7  B) 5/7  C) 3/7  D) 2/7  E) 1/7

Solution: There are 9 years from 1972-1980, inclusive. Let's say the average circulation every year between 1972-1980 inclusive is x.   So the total circulation is 9x from 1972-1980, inclusive.   In 1971, the circulation is 6x.   So total circulation for 1971-1980 is 6x + 9x = 15x.   Ratio of circulation in 1971 to total circulation during 1971-1980 is 6x to 14x or 6/14 6  + 9= 
 6  + 9 = 15
15x.   Ratio of circulation in 1971 to total circulation during 1971-1980 is 6x to 14x or 6/14=3/7   Answer : 3/7
Answer: C
A bike covers a certain distance at the speed of 64km/h in 8 hrs. If the bike was to cover the same distance in approximately 6 hrs, at what approximate speed should the bike travel? Choose the correct answer.
A) 80.34 km/h	B) 85.34 km/h	C) 90.30 km/h	D) 92.25 km/h	E) 97.74 km/h

Solution: Ans.(B)   Sol. Total distance = 64 × 8 = 512 km   Now speed = 512/6 = 85.34 km/h
Answer: B
A man can row his boat with the stream at 18 km/h and against the stream in 4 km/h. The man's rate is?  Choose the correct choice from the following choices:
A) 1 kmph B) 3 kmph C) 8 kmph D) 7 kmph E) 5 kmph

Solution: 7 kmphS = 18   US = 4   S = ?   S = (18 - 4)/2= 
(18 - 4)/2 = 7
7 kmph   Answer: 7 kmph
Answer: D
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?  Pick one.
A) 288  B) 277  C) 200  D) 150  E) 982

Solution: Let the length of the train be x meters and its speed be y m/sec.   They, x / y = 15 => y = x/15   x + 100 / 25 = x / 15   x = 150 m.   Answer:150
Answer: D
A number is greater than 3 but less than 8. Also the number is greater than 6 but less than 10. What is the number?	Choose the correct choice from the following choices.
A) 5
B) 7
C) 6
D) 8
E) 9

Solution: 7 7
Answer: B
By how much is three-fifth of 340 greater than four-seventh of 210 ?
Choose the correct answer.
A) 90	B) 100	C) 110	D) 120	E) 84

Solution: Explanation:   3/5 of 340 - 4/7 of 210 = 204 - 120= 
204 - 120 = 84
84.   Answer: 84
Answer: E
Albert invested amount of 8000 in a fixed deposit for 2 years at compound interest rate of 5 % per
annum. How much Albert will get on the maturity of the fixed deposit	Choose the correct answer.
A) Rs. 8510	B) Rs. 8620	C) Rs. 8730	D) Rs. 8820	E) None of these

Solution: Explanation:   =>(8000×(1+5100)2)=>8000×2120×2120=>8820   Answer:Rs. 8820
Answer: D
At the store, Sam bought a shirt and a toaster. There was a 7% sales tax on each item, and with tax, Sam paid a total of K. If the price of the toaster before tax was T, what, in terms of K and T, is the price of the shirt before tax? Choose the correct choice from the following answers.
A) 0.93(K – T)  B) 0.93K – T  C) 0.93(K – 1.07T)  D) (K – T)/1.07  E) (K/1.07) – T

Solution: 1.07S + 1.07T = K   1.07S = K - 1.07T   S = (K/1.07) - T   The answer is (K/1.07) – T.
Answer: E
V is the volume of a cylinder; the radius of the cylinder is 3.4. The height of the cylinder is 550% more than the radius. Which of the following is true? Choose the correct choice from the following choices:
A) 100 < V < 300
B) 300 < V < 500
C) 500 < V < 700
D) 700 < V < 900
E) 900 < V < 1100

Solution: Volume of a cylinder is pi*(r^2)*h   h>5.5r+r ---> h>6.5*3.4   So, volume is > 3.14*3.4*3.4*6.5*3.4=800 (approx)   Hence, answer will be 700 < V < 900.
Answer: D
Mr. Kramer, the losing candidate in a two-candidate election, received 942,568 votes, which was exactly 20 percent of all votes cast. Approximately what percent of the remaining votes would he need to have received in order to have won at least 50 percent of all the votes cast?  Options:	A) 10%	B) 12%	C) 15%	D) 27%	E) 37%

Solution: Lets assume that candidate got 20% votes and total votes is 100.   Candidate won = 20   Remaining = 80   To get 50%, candidate requires 30 votes from 100 which is 30% and 30 votes from 80.   30/80 = 37.5%   Which is approx 37%. Hence the answer is 37%
Answer: E
7+2=56
6+3=48
5+5=45
2+1=4
4+9=??
Solve it?	Choose the most appropriate option:
A) 92  B) 48  C) 42  D) 38  E) 72

Solution: x+y=x[y+(x-1)]=x^2+xy-x   7+2=7[2+(7-1)]=49+14-7= 
49+14-7 = 56
56   6+3=6[3+(6-1)]=36+18-6= 
36+18-6 = 48
48   5+5=5[5+(5-1)]=25+25-5= 
25+25-5 = 45
45   2+1=2[1+(2-1)]=4+2-2= 
4+2-2 = 4
4   4+9=4[9+(4-1)]=16+36-4= 
16+36-4 = 48
48   Answer :48
Answer: B
George baked a total of 175 pizzas for 7 straight days, beginning on Saturday. He baked 3/5 of the pizzas the first day, and 3/5 of the remaining pizzas the second day. If each successive day he baked fewer pizzas than the previous day, what is the maximum number of pizzas he could have baked on Wednesday?
Choose one
A) 2	B) 3	C) 4	D) 6	E) 7

Solution: 3/5 of the 175 pizzas cooked on Saturday = 105 pizzas   3/5 of the remaining pizzas on Sunday = 42 pizzas   We're left with   (175-105-42)= 
  (175-105-42) = 28
28 pizzas for the remaining 5 days. The prompt tells us that each day has FEWER pizzas than the day before it, so we can't have duplicate numbers.   M T W TH F   8 7 6 4 3=28   W=6   6
Answer: D
A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?  Choices
A) 24  B) 77  C) 66  D) 89  E) 12

Solution: 10/40 + 10/30 + 10/x = 1   x = 24 days   24nswer:24
Answer: A
Find the least number of complete years in which a sum of money put out at 25% compound interest will be more than double of itself?
Choose the most appropriate option:
A) 8 years
B) 9 years
C) 6 years
D) 4 years
E) 5 years

Solution: 4 years   Answer:4 years
Answer: D
The edges of three metal cubes are 1 cm, 2 cm, and 3 cm respectively. A new cube is made by melting these three cubes together. What is the edge of the new cube (in centimeters)?
Choose the correct answer:
A) 3.3	B) 3.5	C) 3.7	D) 3.9	E) 4.1

Solution: The total volume is 1^3+2^3+3^3=36   The edge of the new cube is the cube root of 36 which is about 3.3 cm.   The answer is 3.3.
Answer: A
Kim has 5 pairs of shoes; each pair is a different color. If Kim randomly selects 2 shoes without replacement from the 10 shoes, what is the probability that she will select 2 shoes of the same color?
Choose the correct choice from the following answers:
A) 2/5	B) 1/5	C) 1/9	D) 1/10	E) 1/25

Solution: Total pairs = 101/92 = 45; Same 1/9olor Pairs= 51/91*11/91=5; Prob = 1/9   Or 2/10 * 1/9 * 5 = 1/9   Ans 1/9
Answer: C
Four of the five parts numbered (a), (b), (c), (d) and (e) are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer. Select
A) (2x + 3y)2	B) (2y – x)2 + y(16x + 5y)	C) 4x(x + 2y) + y(4x + 9y)	D) (2x + 2y)2 + y(4x + 5y)	E) (2x – y)2 + 8y(2x + y)

Solution: Others are requal to 4x2 + 9y2 + 12xy.   Answer (2y – x)2 + y(16x + 5y)
Answer: B
In what time will a railway train 80 m long moving at the rate of 40 kmph pass a telegraph post on its way?  Choose the correct answer
A) 3  B) 5  C) 4  D) 6.4  E) 7.2

Solution: T = 80/40 * 18/5= 
80/40 * 18/5 = 36/5 = around 7.2
7.2 sec   Answer:7.2
Answer: E
Calculate the number of bricks, each measuring 25 cm * 15 cm * 8 cm required to construct a wall of dimensions 10 m * 4 m * 5 m when 10% of its volume is occupied by mortar? Select the correct option.
A) 2288 B) 2677 C) 6000 D) 2700 E) 2881

Solution: 10 * 4/100 * 5 * 90/100 = 25/100 * 15/100 * 8/100 * x   10 * 20 * 90 = 15 * 2 * x => x = 6000   Answer: 6000
Answer: C
At what rate p.a a sum of Rs. 2400 will become Rs. 3600/- in 5 years.  Choose one:
A) 10%
B) 15%
C) 20%
D) 12%
E) 23%

Solution: Explanation:   principal P = 2400/-   Rate of interest R = ?   Time T = 5 years   10%ccumulated 10%mount 10% = Rs.10400/-   10% = P + I   10% = P + PTR/100   10% = P(1+ TR/100)   2400[ 1 + (5 x R)/100] = 3600   2[(20 + R)/20] = 3   20 + R = 30   R = 10%   10%nswer: Option 10%
Answer: A
The sum of the squares of three number is 138,while the sum of their products taken two at a time is 131. their sum is :  Choose the most appropriate option.
A) 20	B) 30	C) 40	D) None of these	E) Cannot be determined

Solution: Solution   Let the numbers be a,b and c then, a 2 + b 2+ c 2 = 138 and (ab + b c + ac) = 131.   (a + b+ c)2 = a 2 + b 2 + c 2 + 2(ab + b c + ca) = 138 + 2 * 131= 
138 + 2 * 131 = 400
400 .   ⇒ (a + b + c)= 400/20= 
400/20 = 20
20   20nswer 20
Answer: A
What distance will be covered by a bus moving at 72 kmph in 30 seconds?
Pick:
A) 287
B) 600
C) 289
D) 276
E) 207

Solution: 72 kmph = 72 * 5/18= 
72 * 5/18 = 20
20 mps   D= Speed * time = 20 * 30= 
20 * 30 = 600
600 m.   Answer:600
Answer: B
Siddharth wants to borrow Rs.6000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?
Choose the correct choice from the following options:  A) Rs.21.60  B) Rs.24.00  C) Rs.25.20  D) Rs.27.80  E) None of these

Solution: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.6,000   He lend the same amount for C.I at 6% p.a. for two years.   => Siddharth's income = C.I - S.I   = p[1 + r/ 100]n - p - pnr/100   = p{ [1 + r/ 100]2 - 1 - nr/100   = 6,000{ [1 + 6/100]2 - 1 - 12/100}   = 6,000 {(1.06)2- 1 - 0.12} = 6,000(1.1236 - 1 - 0.12)   = 6,000 (0.0036) = 6 * 3.6 = Rs.21.60   Rs.21.60NSWER:Rs.21.60
Answer: A
A box contains 10 tablets of medicine A and 14 tablets of medicine B. What is the least number of tablets that should be taken from the box to ensure that at least two tablets of each kind are among the extracted.	Choose one.
A) 12 B) 16 C) 17 D) 19 E) 21

Solution: The worst case scenario will be if we remove all 14 tablets of medicine B first. The next 2 tablets we remove have to be of medicine A, so to guarantee that at least two tablets of each kind will be taken we should remove minimum of   14+2= 
  14+2 = 16
16 tablets.   Answer: 16.
Answer: B
Find the value of a/b + b/a, if a and b are the roots of the quadratic equation x2 + 8x + 4 = 0?  Choose the correct choice from the following:
A) 15  B) 14  C) 13  D) 12  E) 11

Solution: a/b + b/a = (a2]/ab   a + b = + b2)/ab = (a2 + b2 + a + b)/ab   = [(a + b)2 - 2ab -8/1 = -8   ab = 4/1= 
4/1 = 4
4   Hence a/b + b/a= [(-8)2 - 2(4)]/4 = 56/4= 
56/4 = 14
14.   ANSWER:14
Answer: B
The area of a square field is 7201 sq m. How long will a lady take to cross the field diagonally at the rate of 2.4 km/hr? Choose one.
A) 2 min B) 3 min C) 4 min D) 5 min E) 6 min

Solution: Area of a square field = 7201 sq m   Let the side of square = a   a^2 = 7201   => a = 84.86   Diagonal = (2)^(1/2) * a   = 1.414 * 84.86   =120   Speed of lady = 2.4 km / hour   = 2400 m / hour   = 40 m / min   Time taken by lady to cross the field diagonally = 120/40= 
120/40 = 3
3 min   Answer 3 min
Answer: B
The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Select:  A) 29  B) 27  C) 29  D) 64  E) 99

Solution: r = 3 πr2 = 9   r = 5 πr2 = 25   25 π – 16 π   100 ---- ? => 64% Answer: 64
Answer: D
In a shop, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, find out approximately what percentage of the selling price is the profit?
Select:
A) 20%
B) 30%
C) 40%
D) 50%
E) 70%

Solution: Let cost price =100   Then, profit =320   selling price =100+320= 
100+320 = 420
420   new cost price=125   profit =420-125= 
420-125 = 295
295   Required percentage=295*100/420 =70 %   Answer : 70%
Answer: E
We made a down payment of $50 and borrowed the balance on a new oven which cost $300. The balance with interest was paid in 23 monthly payments of $11 each and a final payment of $27. The amount of interest paid was what percent of the amount borrowed?	Pick one:
A) 10%
B) 12%
C) 14%
D) 16%
E) 18%

Solution: We borrowed $250.   To pay back this loan, we paid 23*$11 + $27=$280.   The interest was $280-$25023* 11 +  27= 
23* 11 +  27 = 280
$280.   The interest was $280-$250=$30.   The percentage was $30/$250280- 250= 
280- 250 = 30
$30.   The percentage was $30/$250=0.12  30/ 250= 
  30/ 250 = 3/25 = around 0.12
0.12=12%.   The answer is 12%.
Answer: B
The jogging track in a sports complex is 726 meters in circumference. Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively. They will meet for the first time in?
Choices:  A) 450min  B) 528min  C) 610min  D) 714min  E) 359min

Solution: Clearly, the two will meet when they are 726m apart   To be  4.5+3.75= 
 4.5+3.75 = 8.25
8.25 km apart, they take 1 hour   To be 726 m apart, they take 100/825 * 726/1000= 242/2750 * 60 = 528 min.   Answer is 528min
Answer: B
A man sitting in a train which is travelling at 50 kmph observes that a goods train travelling in a opposite direction, takes 9seconds to pass him. If the goods train is 280 m long, find its speed.
Choices:
A) 58  B) 62  C) 74  D) 81  E) 65

Solution: Relative speed = (280/9)m/s = (280/9)*(18/5)= 
(280/9)*(18/5) = 112
112 kmph   speed of goods train= 112-50= 
112-50 = 62
62 kmph   Answer is 62
Answer: B
If 12 men can reap 120 acres of land in 36 days, how many acres of land can 44 men reap in 54 days?  Select the correct option
A) 820 acres	B) 660 acres	C) 620 acres	D) 720 acres	E) 920 acres

Solution: 12 men 120 acres 36 days   44 men ? 54 days   120 * 44/12 * 54/36   10 * 44 * 3/2   44 * 15= 
44 * 15 = 660
660   ANSWER:660 acres
Answer: B
Mudit's age 18 years hence will be thrice his age four years ago. Find Mudit's present age?	Pick:  A) 12  B) 19  C) 27  D) 18  E) 15

Solution: Explanation:   Let Mudit's present age be 'm' years.   m + 18 = 3(m - 4)   => 2m = 30 => m = 15 years.   Answer:15
Answer: E
A certainno. when divided by 35leaves a remainder 25, what is the remainder if the same no.be divided by 15?
Options.
A) 4	B) 5	C) 6	D) 8	E) 9

Solution: Explanation:   35 + 25= 
35 + 25 = 60
60/15= 
60/15 = 4
4 (Remainder)   4
Answer: A
Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
Select the correct option.
A) 29.25  B) 29.29  C) 29.12  D) 29.98  E) 79.12

Solution: 29.25verage of 9 = x   9x = 8 * 3 + x * 2 x = 3.25   Total = 9 * 3.25= 
9 * 3.25 = 29.25
29.25   29.25nswer:29.25
Answer: A
If one-third of one-fourth of a number is 15, then three-tenth of that number is :  Options
A) 35  B) 36  C) 45  D) 54  E) 30

Solution: Let the number be x. Then, 1/3 of 1/4 of x=15   13of14ofx=15   <=> x = 15 * 12= 
15 * 12 = 180
180.   So, required number=   ((3/10)∗180)=54.   Answer :54
Answer: D
Three machines operating independently, simultaneously, and at the same constant rate can fill a certain production order in 48 hours. If one additional machine were used under the same operating conditions, in how manyfewerhours of simultaneous operation could the production order be fulfilled? Pick: A) 6 B) 9 C) 12 D) 27 E) 48

Solution: If 3 Machines can do the work in 48 hr then 4 Machines can do the work in   3/4*48= 
  3/4*48 = 36
36 Hrs. hence time saved will be 12hr   option 12 is the correct answer
Answer: C
Two pipes A and B can fill a tank in 24 hours and 36 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?	Options:
A) 20 hours
B) 15 hours
C) 14 2/5 hours
D) 12 hours
E) 8 hours

Solution: Part filled by A in 1 hour = 1/24   Part filled by B in 1 hour = 1/36   Part filled by (A+B) in 1 hour = 1/24 + 1/36 = 5/72   Both the pipes together fill the tank in 72/5 = 14 2/5 hours   Answer is 14 2/5 hours
Answer: C
The average waight of A,B,C is 45 Kg. The avgwgt of A & B be 40Kg & that of B,C be 43Kg. Find the wgt of B.
Choose the most appropriate option.
A) 23kg  B) 16kg  C) 29kg  D) 31kg  E) 52kg

Solution: Let A,B,c represent their individual wgts.   Then,   A+B+C=(45*3)= 
(45*3) = 135
135Kg   A+B=(40*2)= 
(40*2) = 80
80Kg & B+C=(43*2)= 
(43*2) = 86
86Kg   B=(A+B)+(B+C)-(A+B+C)   =(80+86-135)= 
(80+86-135) = 31
31Kg.   Ans: 31kg
Answer: D
A can do a work in 15 days and B in 20 days. If they work on it together for 6 days, then the fraction of the work that is left is  Choices.
A) 8/17 B) 7/15 C) 3/10 D) 8/15 E) 1/4

Solution: Person ( A ) ( B ) ( A+B )   Time - ( 15 ) ( 20 ) (-)   Rate - ( 20 ) ( 15 ) ( 35 )   Work -(300) (300) (300)   therefore A+B requires (300/35) days to complete entire work   For 1st 4 days they work  35 * 6= 
 35 * 6 = 210
210   Remaining work is 300 - 210= 
300 - 210 = 90
90   Remaining fraction of work is= 90/300 = 3/10   Answer 3/10
Answer: C