MU-NLPC/Calc-aqua_rat huggingface dataset:
The county-mandated guidelines at a certain community college specify that for the introductory English class, the professor may choose one of three specified novels, and choose two from a list of 5 specified plays. Thus, the reading list for this introductory class is guaranteed to have one novel and two plays. How many different reading lists could a professor create within these parameters?  Select.
A) 15	B) 30	C) 90	D) 150	E) 360

Solution: There are three possibilities for the novel. With the plays, we are taken a combination of 2 from a set of 5 right n = 5, r = 2, n – r = 3   # of combinations = 5!/2!3! = (5)(4)(3)(2)(1)/(2)(1)(3)(2)(1) = (5)(4)/2 = 10   If the plays are P, Q, R, S, and T, then the 10 sets of two are PQ, PR, PS, PT, QR, QS, QT, RS, RT, & ST.   Any of the three novels can be grouped with any of the 10 possible pairs of plays, for a total of 30 possible reading lists.   Answer: 30.
Answer: B
Triangle ATriangle B are similar triangles with areas 2023 units square and 1792 units square respectively. The ratio of there corresponding height would be	Choose the correct choice from the following choices:	A) 9:10	B) 17:16	C) 23:27	D) 13:17	E) 15:23

Solution: Let x be the height of triangle A and y be the height of triangle of B.   since triangles are similar, ratio of area of A and 17:16 is in the ratio of x^2/y^2   Therefore, (x^2/y^2)=2023/1792   (x^2/y^2)=(17*17*7)/(16*16*7)   (x^2/y^2)=17^2/16^2   x/y=17/16   Ans=17:16   You need to take a hint from given options to find factors of 2013 and 2527.
Answer: B
7 letters have to be put into their 7 respective envelopes. If the letters are inserted randomly into the envelopes, what is the probability that all the letters go into their respective envelopes?
Select the correct option:  A) 1/30  B) 1/720  C) 1/5040  D) 1/240  E) 3/5

Solution: A-B-C-D-E (envelopes)   a-b-c-d-e (letters)   7 letters (a, b, c, d, and e) can be assigned to 7 envelopes (arranged) in 7! ways, out of which only one will be correct, thus the probability is 1/7! = 1/5040.   Answer: 1/5040.
Answer: C
If an article is sold at 18% profit instead of 11% profit, then the profit would be $63 more. What is the cost price?	Choose the correct choice from the following options
A) $600  B) $900  C) $1200  D) $1500  E) $1800

Solution: 7% * cost price = $63   1% * cost price = $63 / 7= 
63 / 7 = 9
$9   The cost price is $900.   The answer is $900.
Answer: B
36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work? Select:  A) 12  B) 18  C) 22  D) 24  E) none of these

Solution: Let the required number of days be x.   Less men, More days (Indirect Proportion)   27 : 36 :: 18 : x 27 * x = 36 * 18   x =	(36 * 18)/27= 
(36 * 18)/27 = 24
24.   Answer is 24.
Answer: D
What is the present age of Kim, given that the ratio between her age and her sisters age 7 years ago was 4:3, and her sister is presently 31 years old. Choose the correct choice from the following.
A) 23	B) 19	C) 22	D) 21	E) 24

Solution: Let the present ages of Kim's sister and Kim be 4x years and 3x years respectively   4x+7 = 35   4x = 28   x = 7   Kim's age = 3x = 21 years   Answer is 21
Answer: D
What is the smallest positive perfect square that is divisible by 4, 9, and 18?
Select the correct option
A) 36  B) 81  C) 144  D) 625  E) 900

Solution: The number needs to be divisible by 2^2, 3^2, and 2*3^2.   The smallest such perfect square is 2^2*3^2 = 36   The answer is 36.
Answer: A
In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?	Answers:
A) 48 B) 37 C) 26 D) 98 E) 27

Solution: Explanation:   3X + 4y = 240   by substitute through options 48 is correct   48nswer: 48
Answer: A
A man sold 20 articles for $40 and gained 20%. How many articles should he sell for $90 to incur a loss 20%?
Pick:
A) 45
B) 36
C) 40
D) 50
E) 67.5

Solution: Production cost per article: $40*(100%-20%) / 20 = $1.6   Required production costs for a loss of 20%: $90*(100% + 20%) = $108   Number of articles to be sold for $108 to incur a 20% loss: $108 / $1.6 = 67.5   Thus, solution 67.5 is correct.108 /  1.6= 
108 /  1.6 = 67.5
67.5   Thus, solution 67.5 is correct.
Answer: E
A dishonest milk man tops up his bucket which is only 4/5 th full of milk with water. He again removes 5 liters of this mixture from the bucket and adds an equal quantity of water. If milk is now 60% of the mixture, what is the capacity of the bucket ?	Choose the most appropriate option:
A) 15 lit B) 20 lit C) 22.5 lit D) 25 lit E) 30 lit

Solution: Solution:   Let x be the capacity of the bucket.then, initial mixture has 80% milk.   then after 5 lt replaced with water---->(80/100)∗(x−5)=(60/100)∗x(80/100)∗(x−5)=(60/100)∗x   x=20 lt.   Ans:- 20 lit.
Answer: B
How many ounces of a 60% salt solution must be added to 40 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt?	Answers.
A) 16.67  B) 40  C) 50  D) 60.33  E) 70

Solution: let x=ounces of 60% salt solution to be added   .2*40+.6x=.4(40+x)   x=40   Amswer 40
Answer: B
A and B start a business jointly. A invests Rs. 16,000 for 8 months and B remains in the business for 4 months, Out of total profit, B claims - of the profit. How much money was contributed by B ?	Answers:
A) 12822
B) 12800
C) 12819
D) 12129
E) 12811

Solution: Let the total profit be Rs. x. Then, B = 2x/7 and A = (x - 2x /7) = 5x / 7.   So, A : B = 5x/7 : 2x/7 = 5 : 2.   Let B s capital be Rs. y. Then, (16000 * 8) / ( y * 4) = 5/2 <=> (16000 * 8 * 2) / (5 * 4) = 12800..   Answer: 12800
Answer: B
Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 7 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?  Choose the correct answer
A) 8 mph	B) 5.25 mph	C) 3.5 mph	D) 4 mph	E) 0.5 mph

Solution: (1 mph +7 mph)/2 = 4 mph   Correct option is: 4 mph
Answer: D
A photography dealer ordered 60 Model X cameras to be sold for $250 each, which represents a 10 percent markup over the dealer’s initial cost for each camera. Of the cameras ordered, 6 were never sold and were returned to the manufacturer for a refund of 50 percent of the dealer's initial cost. What was the dealer's approximate profit or loss as a percent of the dealer’s initial cost for the 60 cameras? Pick.
A) 7% loss  B) 13% loss  C) 5% profit  D) 13% profit  E) 15% profit

Solution: Total cost 60*($250/1.1)=54.54*250;   # of cameras sold is  60-5= 
 60-5 = 55
55 total revenue is 55*250;   # of cameras returned is 6 total refund 6*(250/1.1)*0.5;   So, total income 55*250+ 6*(250/1.1)*0.5   The dealer's approximate profit is (55*250+ 6*(250/1.1)*0.5-54.54*250)/(54.54*250)*100=5%   Answer: 5% profit.
Answer: C
A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points T that an individual player might have scored? Select
A) 7	B) 13	C) 16	D) 21	E) 23

Solution: General rule for such kind of problems:   to maximize one quantity, minimize the others;   to minimize one quantity, maximize the others.   Thus to maximize the number of points of one particular player minimize the number of points of all other 11 players.   Minimum number of points for a player is 7, so the minimum number of points of 11 players is 7*11= 
7*11 = 77
77.   Therefore, the maximum number of points T for 12th player is  100-77= 
 100-77 = 23
23.   Answer: 23.
Answer: E
The banker's discount on Rs. 1600 at 15% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is:
Choose the correct choice from the following.
A) 7 B) 4 C) 5 D) 3 E) 2

Solution: S.I. on Rs. 1600 = T.D. on Rs. 1680.   Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.   Time = 100 x 80	year	=	1	year = 4 months.   1600 x 15	3   Answer:4
Answer: B
In an election between two candidates, one got 55% of the total valid votes. 20% of the votes were invalid. If the total number of votes was 7500, what was the number of valid votes that the other candidate got?
Choose the most appropriate option:
A) 2800
B) 2700
C) 2100
D) 2500
E) 3000

Solution: Total no of votes = 7500   20 % invalid   =>80% valid   tot valid votes = 7500*80/100   =>valid for 2nd candidate got    7500*80/100*45/100= 
 7500*80/100*45/100 = 2_700
2700   ANSWER 2700
Answer: B
Two trains of length 100 m and 200 m are 100 m apart. They start moving towards each other on parallel tracks, at speeds 72 kmph and 90 kmph. In how much time will the trains cross each other? Select
A) 80/8	B) 80/9	C) 80/5	D) 80/3	E) 80/1

Solution: Relative speed = (72 + 90)* 5/18 = 9* 5= 
9* 5 = 45
45 mps.   The time required= d/s = (100 + 100 + 200)/45   = 400/45 = 80/9 sec.   Answer: 80/9
Answer: B
The probabilities of solving a question by 3students A, B & C are 1/2,1/3 &1/4, respectively. The probability that the problem will be solved is? Choose the correct choice from the following choices:
A) 3/4
B) 3/5
C) 4/7
D) 4/9
E) 5/7

Solution: Sol. First, we find the probability of not solving the problem x PTO x = (1 — D x - D x - D   1 2 3 1 =iXiX71=4;   1 3 Required probability 3/4   3/5
Answer: B
If the mean of numbers 28, x, 42, 78 and 104 is 90, then what is the mean of 128, 255, 511, 1023 and x?
Choose the correct answer
A) 395	B) 275	C) 355	D) 415	E) 423

Solution: The mean of numbers 28, x, 42, 78 and 104 is 62: 28+x+42+78+104=90*5 --> x=198;   So, the mean of 128, 255, 511, 1023 and x is  (128+255+511+1023+198)/5= 
 (128+255+511+1023+198)/5 = 423
423.   Answer: 423.
Answer: E
42573y is exactly divisible by 72, then what is the minimum value of y? Pick:
A) 3  B) 4  C) 6  D) 8  E) 9

Solution: 72 = 9 x8, where 9 and 8 are co-prime.   The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.   Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6)= 
(4 + 2 + 5 + 7 + 3 + 6) = 27
27, which is divisible by 9.   Required value of y is 6   6
Answer: C
For a certain exam,a score of 58 was 2 standard deviations below mean and a score of 98 was 3 standard deviations above mean.What was the mean score R for the exam?
Choose the correct choice:	A) 74	B) 76	C) 78	D) 80	E) 82

Solution: A score of 58 was 2 standard deviations below the mean --> 58 = Mean - 2d   A score of 98 was 3 standard deviations above the mean --> 98 = Mean + 3d   Solving above for Mean R= 74.   74nswer: 74.
Answer: A
5 years ago, Paula was 3 times as old as Karl. In 6 years, Paula will be twice as old as Karl. What is the sum of their ages now?
Choose the correct choice from the following:
A) 42
B) 46
C) 50
D) 54
E) 58

Solution: P-5 = 3(K-5) and so P = 3K-10   P+6 = 2(K+6)   (3K-10)+6 = 2K+12   K = 16   P = 38   P+K = 54   The answer is 54.
Answer: D
A five-person team is to be formed from a pool of 6 East All Stars and 6 West All Stars. What is the probability that the team will contain at least 2 East All Stars?	Choose the most appropriate option
A) 29/33  B) 81/169  C) 57/120  D) 47/144  E) 119/720

Solution: Teams can be formed as 2E-3W , 3E-2W , 4E-W and 5E   Possible ways to make a team 2E-3W = 6c2 * 6c3 = 300   Possible ways to make a team 3E-2W = 6c3 * 6c2 = 300   Possible ways to make a team 4E-W = 6c4 * 6c1 = 90   Possible ways to make a team 5E = 6c5 = 6   Number of ways to select a team of 5 out of 12 people = 12c5   =12!/(7!*5!)   = 792   Probability that the team will contain at least 2 East All Stars   = (300+300+90+6) / 792   =696/792   = 29/33   Answer A   Alternatively we can also calculate the number of possible ways to make a team of 5W and E-4W .   Possible ways to make a team 5W = 6c5 = 6   Possible ways to make a team E-4W = 6c1 * 6c4 = 90   Probability that the team will contain at least 2 East 29/33ll Stars = 1 - (96/792)   = 29/33
Answer: A
A rectangular park is 110 m long and 65 m wide.in this park there is 2.5m wide path all four side.on this path on the rate of 7.20 per sq. m what will be cost of spreading sand?  Select
A) 6120
B) 7350
C) 6250
D) 8285
E) 6565

Solution: 6120rea of park=110*65= 
110*65 = 7_150
7150sq.m   6120rea of park without path=[(110-2.5*2)×(65-2.5*2)]sq.m   (105*60) sq.m=6300 sq.m   6120rea of path=(7150-6300)= 
(7150-6300) = 850
850 sq.m   Cost of spreading sand=[850×720/100]=6120   6120nswer 6120
Answer: A
9 men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?	Choose the correct choice: A) 29.25 B) 30 C) 31.2 D) 34 E) 35

Solution: 29.25verage of 9 = x   9x = 8 * 3 + x * 2 x = 3.25   Total = 9 * 3.25= 
9 * 3.25 = 29.25
29.25   29.25
Answer: A
There are 6 distinct letters of the English alphabet and 4 distinct digits. all possible 6 character apha-numero codes are generated using any 4 letters of the alphabet and any 2 available digits. If in any given code, the characters are all distinct, then what is the maximum number of such codes that can be generated?  Choose the correct option:
A) 4320
B) 64800
C) 8800
D) 22000
E) 6600

Solution: From the six letters, we need four distinct letters   # of combinations = 6C4 = 15   From the four numerals, we need 2 distinct digits   4C2 = 6   Once we have our unique four letter and our unique 2 digits, we can put them in any order: each new order would be a different code. The number of orders would be   6! = 720   Total number of codes equals =  15*6= 
 15*6 = 90
90. Then, 90= 100 - 10, so   720*90 = 720*(100 - 10) = 72000 - 7200= 
72000 - 7200 = 64_800
64800   Answer= (64800)
Answer: B
A certain electric-company plan offers customers reduced rates for electricity used between 8 p.m. and 8 a.m. weekdays and 24 hours a day Saturdays and Sundays. Under this plan, the reduced rates Z apply to what fraction of a week?
Choose the correct choice from the following options.
A) 1/2 B) 5/8 C) 9/14 D) 16/21 E) 9/10

Solution: Number of hours between 8 PM to 8 AM = 12   Number of hours with reduced rates = (12*5)+(24*2)   Hours with reduced rates Z/Total number of hours in a week = (12*5)+(24*2)/(24*7) = 108/(24*7) = 9/14   Answer: 9/14
Answer: C
The game of blackjack is played with a deck consisting of 13 cards (one of each of the numbers 2-10, one jack, one queen, one king, and one of ace) in each of four suits: clubs, diamonds, hearts, and spades.
In a game of blackjack, if your first card is a spade, what are the odds that it is a king? Choose the correct option:	A) 1/52	B) 1/26	C) 2/13	D) 1/4	E) 1/13

Solution: The question should ask about the probability not the odds.   There are 13 spades, the probability that the spade we already have is a king is therefore 1/13.   Answer: 1/13.
Answer: E
Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 27 kg of zinc has been consumed in it?
Pick:
A) 58 kg  B) 60 kg  C) 64 kg  D) 70 kg  E) None

Solution: Sol.   For 9 kg Zinc, mixture melted = (9+11) kg.   For 27 kg Zinc, mixture, melted = [20/9 x 27] kg   = 60 kg.   Answer 60 kg
Answer: B
A certain party consists of four different group of people 30 students, 35 politicians, 20 actors and 27 leaders. On a particular function day, the total cost spent on party members was Rs.9000. It was found that 6 students spent as much as 7 politicians, 15 politicians spent as much as 12 actors and 10 actors spent as much as 9 leaders. How much did students spent? Pick one.
A) 2191	B) 2200	C) 2291	D) 2391	E) 2491

Solution: Let S be the amount spent for all students   Let P be the amount spent for all politicians   Let A be the amount spent for all actors and   Let L be the amount spent for all leaders.   given that 6 students spent as much as 7 politicians   i.e Amount spent per student x 6 = Amount spent per politician x 7   Or (Total amount spent on students / Total Students) x 6 = (Total amount spent on politicians / Total politicians)x 7   Or., (S/30)x 6 = (P/35)x7   => S/5 = P/5   => S = P ..... eqn 1   15 politicians spent as much as 12 actors :   Therefore, (P/35)x15 = (A/20)x12   => 3P/7 = 3A/5   => 5P = 7P   => 5S = 7A (since S = P)   => A = 5S/7 ........eqn2   and 10 actors spent as much as 9 leaders :   Therefore, (A/20)x10 = (L/27)x9   => 3A = 2L   => A = 2L/3   => 5S/7 = 2L/3 (since A=5S/7)   => L = 15S/14 ......eqn3   the total amount spent for the party is Rs.9000   i.e., S+P+A+L = 9000   from eqn1, eqn2, eqn3 we have   S + S + 5S/7 + 15S/14 = 9000   53S/14 = 9000   s=9000*14 / 53   s=2290.90 ~ 2291   Hence the answer is Rs.2291   ANSWER:2291
Answer: C
Anna and Carol buy CDs and tapes at a music store that sells each of its CDs for a certain price and each of its tapes for a certain price. Anna spends twice as much as Carol spends, buying three times as many CDs and the same number of tapes. If Carol spends $70.00 on four CDs and five tapes, how much does one tape cost?	Choose the correct answer: A) $5.00 B) $6.25 C) $7.00 D) $25.00 E) $100.00

Solution: $7.00D => $7.00   Type => T   $7.00arol: 4$7.00+5T=70   Anna: 12$7.00+5T=140   12$7.00-4$7.00=70   8$7.00=70   $7.00=8.75   4$7.00+5T=70   35+5T=70   5T=35   T=7   Answer is $7.00
Answer: C
Anne, Markov, Peter line up at a ticket window. In how many ways can they arrange themselves so that Peter is first in line from the window? Select the correct option:
A) a 24
B) b 12
C) c 9
D) d 2
E) e 3

Solution: D   Peter's position is fixed. Now we need to arrange all others around Peter.   There are 2x1= 2 ways to arrange two people.
Answer: D
When a merchant imported a certain item, he paid a 9 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $76.50, what was the total value of the item?	Options
A) $1,250 B) $1,450 C) $1,650 D) $1,850 E) $2,050

Solution: Let x be the value in excess of $1,000.   0.09x = 76.5   x = $850   The total value was $850 + $1,000 = $1,850.   The answer is $1,850.
Answer: D
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 172 votes. Find the total number of valid votes?	Choose the correct choice from the following
A) 430 B) 436 C) 477 D) 439 E) 537

Solution: Let the total number of valid votes be x.   70% of x = 70/100 * x = 7x/10   Number of votes secured by the other candidate = x - 7x/100 = 3x/10   Given, 7x/10 - 3x/10 = 172 => 4x/10 = 172   => 4x = 1720 => x = 430.   430nswer:430
Answer: A
The greatest common divisor of (b-2)!,(b+1)!, and (b+4)! is 5040. what is the value of b?  Pick:
A) 8	B) 10	C) 12	D) 9	E) 6

Solution: GCD of (b-2)!,(b+1)!, and (b+4)! is 5040. Find x.   Best way to find n is substitute each of the answer and find out the correct one.   Only option D gave the correct answer.   Option D: 9 and find GCD or 7!, 10! and 13!. 7! itself is 5040 and 7! which is contained in the other two factorials. This satisfies the condition, hence answer is 9.   Answer is 9.
Answer: D
By walking at 3/4th of his usual speed, a man reaches office 18 minutes later than usual. What is his usual time?  Choose the correct choice from the following answers.
A) 43min  B) 54min  C) 65min  D) 60min  E) 70min

Solution: let T be the usual time.   time spent=4T/3   therefore, 4T/3=T+18   4T=3T+54...therefor T=54min   ANSWER:54min
Answer: B
A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train ?	Choose one
A) 230 B) 777 C) 267 D) 288 E) 277

Solution: Explanation:   Relative speed = (120 + 80) km/hr   ==   Let the length of the other train be x metres.   Then,   x + 270 = 500   x = 230.   230nswer: 230) 230 m
Answer: A
If each participant of a chess tournament plays exactly one game with each of the remaining participants, then 153 games will be played during the tournament. Find the number of participants.  Choose the most appropriate option
A) 15 B) 16 C) 17 D) 18 E) 19

Solution: If the number of participants is 3 (say A, B, C) the number of games played will be 2 (A plays against B and C) + 1 (B plays against C) = 3   Using the same logic, if the number of participants is n, the number of games played will be (n-1) + (n - 2) + (n - 3) + ... 3 + 2 + 1   Given that this sum = 153 = 1 + 2 + 3 + ... ( n - 1)   Sum of first m positive integers is given by m(m+1)/2. So sum of first (n-1) positive integers is (n-1)*n/2   153 = (n-1)*n/2   (n-1)*n = 306   17*18= 
17*18 = 306
306 (We know that 15^2= 225 so the two consecutive numbers must be greater than 15. Also, 20^2 = 400 so the two numbers must be less than 20. The pair of numbers in between 15 and 20 whose product ends with 6 is 17 and 18)   So n = 18   Answer (18)
Answer: D
A cab driver 5days income was $30, $50, $60, $65 , $70. Then his average income is?  Choose the correct choice from the following:
A) A)$55  B) B)$42  C) C)$65  D) D)$48  E) E)$62

Solution: avg = sum of observations/number of observations   avg income=(30+50+60+65+70)/5= 
(30+50+60+65+70)/5 = 55
55   $55nswer is $55
Answer: A
A wheel rotates 15 times every minute and moves 35 cm during each rotation. How many metres does the wheel move in one hour?  Answers: A) 6 metre B) 12 metre C) 120 metre D) 315 metre E) 130 metre

Solution: Number of times wheel moves in 1 hour = 15 * 60= 
15 * 60 = 900
900   :. 315 metreistance moves= (900 *35)= 
(900 *35) = 31_500
31500 cms   In metres= 315 metre   ANSWER:315 metre
Answer: D
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 8 AM, what will be the time at the end of 10 days?	Choose the correct choice from the following choices
A) 08:54:40 AM	B) 08:56:24 AM	C) 08:16:40 PM	D) 08:54:24 AM	E) 09:06:36 PM

Solution: Loses 8 minutes each day.   so total loss = 4×8 = 32min   subsequent 6 days = 6×24×60 minutes   1% gain = ( 6×24×60)/100 = 86.4 minutes   so, total gain = 86.4 - 32= 
86.4 - 32 = 54.4
54.4 min= 54 + 0.4 min = 54 minutes + 0.4 × 60 seconds = 54min + 24seconds   10 days later the clock should be 54 min and 24seconds fast.   so time , 09:54:24 am (Answer 08:54:24 AM)
Answer: D
Judges will select 6 finalists from the 7 contestants entered in a singing competition. The judges will then rank the contestants and award prizes to the 3 highest ranked contestants: a blue ribbon for first place, a red ribbon for second place, and a yellow ribbon for third place. How many different arrangements of prize-winners are possible? Choose the correct choice from the following answers:  A) 140  B) 21  C) 210  D) 420  E) 1,260

Solution: First Select 5 from 7 contestants and then select top 3 from those 5 =   7C6*6C3 = 7 * 20= 
7 * 20 = 140
140   140NS:140
Answer: A
A bicyclist's wheel has a circumference of 6 meters. if the bicyclist covers 180 meters in 5 hours at a constant speed, how many rotations does the wheel make per hour at that speed?	Answers
A) 2
B) 3
C) 4
D) 5
E) 6

Solution: The bicyclist covers y meters in t hrs. So he covers y/t meters in one hour.   To cover y/t meters, the bicycle's wheel went round and round that is, multiple times, the wheel completed one circumference on the road. How many times did it complete one full rotation. Since the circumference is x, the number of times it completes the circumference is y/xt.=180/6*5 =6   Answer (6)
Answer: E
What will come in place of the x in the following Number series? 68, 36, 20, 12, 8, x Choose one.
A) 6
B) 4
C) 2
D) 1
E) 0

Solution: 6868 / 2 + 2 = 3636 / 2 + 2 = 2020 / 2 + 2 = 1212 / 2 + 2 = 88 / 2 + 2 = 6 6
Answer: A
Today is Thursday. The day after 54 days will be?	Options
A) Monday B) Tuesday C) Saturday D) Sunday E) wednesday

Solution: Explanation:   54 days = 7 weeks 3 days = 5 odd days   Hence if today is Thursday, After 54 days, it will be = (Thursday + 5 odd days)   = Tuesday   Answer: Option Tuesday
Answer: B