MU-NLPC/Calc-aqua_rat huggingface dataset:
Two diagonals of a rhombus are 72 cm and 30 cm respectively. What is its perimeter?	Choose the correct answer:	A) 136 CM	B) 156 CM	C) 144 CM	D) 121 CM	E) 126 CM

Solution: ALL SIDES OF RHOM156 CMUS ARE CONGRUENT LET PR = 72 SQ = 30 CM   PO = 0R = 72/1 = 36 CM SO = 0Q = 30/2= 
30/2 = 15
15 CM   PQ= QR = RS = SP   = ROOT( 36^2 + 15^2) = RPPT(1296+225)=ROOT(1521) = 39 CM   PERIMETER = 4 * 39= 
4 * 39 = 156
156 CM   ANSWER 156 CM
Answer: B
The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.440 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office.  Select the correct option.
A) 400 B) 420 C) 480 D) 450 E) 510

Solution: Let no. of non- officers be x   15 * 440 + x * 110 = (x + 15) 120   x = 480   480
Answer: C
In how many different ways can the letters of the word "FAME" be rearrangement?	Choose the correct choice.
A) 26	B) 24	C) 28	D) 12	E) 30

Solution: Option '24'   The total number of arrangements is   4P4 = 4! = 24
Answer: B
Each night before he goes to bed, Jordan likes to pick out an outfit to wear the next day. He has 11 different shirts, 10 different pairs of jeans, and 8 pairs of sneakers. If an outfit consists of 1 shirt, 1 pair of jeans, and 1 pair of sneakers, how many different outfits does Jordan have?
Pick one:  A) 30  B) 90  C) 240  D) 880  E) 960

Solution: Total # of outfits = 11 * 10 * 8= 
11 * 10 * 8 = 880
880   Answer - 880
Answer: D
A student chose a number, multiplied it by 5, then subtracted 275 from the result and got 135. What was the number he chose?	Pick.
A) 80	B) 82	C) 84	D) 86	E) 88

Solution: Let x be the number he chose, then   5⋅x−275=135   5x=410   x=82   correct answer 82
Answer: B
Stephen likes to bike after school, and he has to get home before dark, so he only bike for five hours. His favorite route is a 45 mile loop starting from his house. In the first hour, he travels nine miles. For the next two hours, he travels at 7 miles per hour. Compute the average speed Stephen has to ride for the last three hours to get home before dark.  Answers:
A) 10	B) 11	C) 12	D) 13	E) 14

Solution: Stephen has to travel (45 - 9 - 7 * 2)= 
(45 - 9 - 7 * 2) = 22
22 miles in 2 hours   22 miles / 2 hours= 11 miles per hour   Correct answer 11
Answer: B
The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?  Select the correct option
A) 40 B) 32 C) 28 D) 30 E) 35

Solution: Explanation:   Let the present age of the husband = h   Present age of the wife = w   Present age of the child = c   3 years ago, average age of husband, wife and their child = 27   => Sum of age of husband, wife and their child before 3 years = 3 × 27 = 81   => (h-3) + (w-3) + (c-3) = 81   => h + w + c = 81 + 9= 
81 + 9 = 90
90 --- equation(1)   5 years ago, average age of wife and child= 20   => Sum of age of wife and child before 5 years = 2 × 20 = 40   => (w-5) + (c-5) = 40   => w + c = 40 + 10= 
40 + 10 = 50
50 --- equation(2)   Substituting equation(2) in equation(1)=> h + 50 = 90   => h = 90 - 50= 
90 - 50 = 40
40   i.e., Present age of the husband= 40   40nswer: Option 40
Answer: A
If a coin is tossed twice, what is the probability that on the first toss the coin lands tails and on the second toss the coin lands tails?
Choose the correct choice from the following answers.
A) 1/6
B) 1/3
C) 1/2
D) 1/4
E) 1

Solution: Since there are two options for how a coin can land (heads or tails), that means there is a 1/2 chance to land on tails and a 1/2 chance to land heads. To solve this problem you multiply each probability for each flip together. (1/2) chance to land tails the first time * (1/2) chance to land tails the second time = (1/4) chance to land tails both times.   Answer: 1/4
Answer: D
A can do a piece of work in 4 days. B can do it in 6 days. With the assistance of C they completed the work in 2 days. Find in how many days can C alone do it?	Select the correct option:	A) 87 days	B) 12 days	C) 66 days	D) 77 days	E) 44 days

Solution: C = 1/2 - 1/4 - 1/6 = 1/12   => 12 days   Answer: 12 days
Answer: B
The speed of a boat in still water is 80kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Choose the most appropriate option.
A) 60 kmph B) 40 kmph C) 16 kmph D) 15 kmph E) 18 kmph kmph

Solution: Speed downstream = 80 + 20= 
80 + 20 = 100
100 kmph   Speed upstream= 80 - 20= 
80 - 20 = 60
60 kmph   60 kmphnswer:60 kmph
Answer: A
If the letters in the word RUTHENIUM are rearranged in the alphabatical order, which letter will be
second to the right of middle letter? Pick.
A) I
B) T
C) Y
D) H
E) F

Solution: Alphabetical order of the letters of the word RUTHENIUM:   E H I M N R T U U   Middle Letter = N. will be second to the right of middle letter is T.   Answer: Option 'T'
Answer: B
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit ?	Choose the correct choice:
A) 24884  B) 10500  C) 23878  D) 29988  E) 27711

Solution: Explanation:   Simran : Nanda = (50000 * 36) : (80000 * 30) = 3 : 4.   Simran's share = Rs. ( 24500 * 3/7) = Rs. 10500.   Answer: 10500) 10500
Answer: B
If two numbers are in the ratio 5:3. If 10 is Reduced to both of the numbers then the ratio becomes 2:1 then find the smallest number?
Choose the most appropriate option:	A) 15	B) 20	C) 30	D) 34	E) 36

Solution: 5:3   5x - 10 : 3x - 10 = 2 : 1   1[5x - 10] = 2[3x - 10]   5x - 10 = 6x - 20   6x - 5x = 20 - 10= 
20 - 10 = 10
10   the small number is= 3   3x = 30 (Answer = 30)   Short cut method:   a:b = 5:3   c:d = 2:1   1.Cross multiplication with both ratios   a * d ~ b * c = 5 * 1 ~ 3 * 2 = 5 ~ 6 = 1   2. If 10 is reduced both the number means  10 * 2= 
 10 * 2 = 20
20 and   10 * 1= 
  10 * 1 = 10
10,   Then 20 ~ 10= 10   ===> 1 -----> 10   ===> 3 -----> 30 (Answer is = 30)   30
Answer: C
Hali builds a tower using only red, green, and blue toy bricks in a ratio of 4:3:1. She then removes 1/2 of the green bricks and adds 1/3 more blue bricks, reducing the size of the tower by 14 bricks. How many red bricks will she need to add in order to double the total number of bricks used to build the original tower?  Pick one: A) 82 B) 96 C) 110 D) 120 E) 192

Solution: Hali want to double the original amount of blocks, not just the red blocks   the original tower had 96 bricks, the new tower has 82 bricks and the question is asking how many extra red blocks are needed to build a tower of 192 bricks (double the original: 96*2).   192-82= 
192-82 = 110
110   so 110 bricks need to be added to the new 82 brick tower to double the original.   They worded the question ashow many red bricks need to be addedbut really it could be any colour just that 110 more bricks need to be there to equal 192=192
Answer: E
What is the sum of the prime factors of 81 and the prime factors of 144?
Choose the most appropriate option:	A) 33	B) 45	C) 30	D) 33	E) 36

Solution: The prime factors of 81 are 3*3*3*3   The prime factors of 144are 12*12   3+3+3+3+12+12= 
3+3+3+3+12+12 = 36
36 36 is the correct answer
Answer: E
A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay?
Choose the correct option
A) 20%  B) 45%  C) 44%  D) 48%  E) 50%

Solution: Explanation:   g% = 20 + 20 + (20*20)/100= 
20 + 20 + (20*20)/100 = 44
44%   ANSWER IS 44%
Answer: C
Which expression is the greatest	Choose the most appropriate option.
A) 3252/3257  B) 3456/3461  C) 3591/3596  D) 3641/3656  E) 3453/3458

Solution: Options can be re-written as (x-5)x => 1-(5/x)   A) 1- (5/3257)   B) 1- (5/3461)   C) 1- (5/3596)   D) 1- (5/3656)   E) 1- (5/3458)   To get the largest among these second half should be the least and so denominator to be largest. Hence '3641/3656'.
Answer: D
In ABC limited, 75% are using Samsung phone at the same time 70% using i phone; If in the same company 85% are using Samsung phone then, what is the percentage of i phone user?
Choose the correct choice from the following answers:	A) 55	B) 68	C) 38	D) 34	E) 69

Solution: Samsung phone user = 75%; i phone user= 80%; Total = 85*100;Percentage of Samsung phone users = 85 - 75= 
85 - 75 = 10
10;   Percentage of i phone users= 100 - 80= 
100 - 80 = 20
20; then total % of i phone users=0.70*20= 
0.70*20 = 14
14;then total % of i phone users= 20+14= 
20+14 = 34
34. Answer= 34
Answer: D
26% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair?
Choose the correct choice from the following choices
A) 25 B) 30 C) 50 D) 55 E) 65

Solution: Think of 100 people total:   From the first fact, 26 of these are women with fair hair.   From the second fact, these 20 women make up 40% of the total fair haired population.   We can then make a ratio of 60:40 fair haired men to fair haired women.   This means that (60/40)*26 equals the number of fair haired men, which is 39 men with fair hair.   Add this 39 to the 26 women and get 65 fair haired men and women out of 100 total men and women.   65%65
Answer: E
The value for D=(0.889 × 55)/9.97 to the nearest tenth is Options:
A) 0.5  B) 4.63  C) 4.9  D) 7.7  E) 49.1

Solution: if we read the Q, we can easily home on to the answer,,   the numerator is clearly between 40 and 50..   denomiator is close to 10..   so D=(0.889 × 55)/9.97 is between 4 and 5..   It may tempt us to solve it since ther are two values between 4 and 5..   but the catch is innearest tenth   4.63 can be called nearest to hundreth and no tenth, so can be eliminated..   4.9 is our answer...   4.9
Answer: C
All the stocks on the over-the-counter market are designated by either a 1 letter or 2 letter codes that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different stocks that can be designated with these codes? Choose the correct option:
A) 2(26^5)  B) 26(26^4)  C) 27(26^1)  D) 26(26^5)  E) 27(26^5)

Solution: with 1 letters: 26^1   with 2 letters: 26^2   26^1 + 26^2 = 27*(26^1)   27(26^1)
Answer: C
What is the area of rectangular field?
I.	The perimeter of the field is 110 metres.
II.	The length is 5 metres more than the width.
III.	The ratio between length and width is 6 : 5 respectively.  Choose the correct choice from the following.
A) I and II only B) Any two of the three C) All I, II and III D) I, and either II or III only E) None of these

Solution: EXPLANATION   I. 2(l + b) = 110 l + b = 55.   II. l = (b + 5) l – b = 5.   III. l/b (  + 5)= 
(  + 5) = 5
5.   III. l/b= 6/5 => 5l – 6b = 0.   These are three equations in l and b. We may solve them pairwise.   Any two of the three will give the answer.   answer is (Any two of the three).
Answer: B
If 27.5% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class?	Choose the correct choice from the following answers.
A) 638 B) 330 C) 550 D) 430 E) 880

Solution: Students enrolled in biology are 27.5% and therefore not enrolled are 72.5%. so of 880 is 880*.225 = 638   638nswer is 638 638
Answer: A
Sanoop bought 8 t-shirts at an average price (arithmetic mean) of Rs.526. If Sanoop returned 5 t-shirts to the retailer, and the average price of the remaining t-shirts was Rs.505, then what is the average price, of the three returned t-shirts?	Options.
A) 560 B) 561 C) 562 D) 538.6 E) 564

Solution: Total price of 8 t-shirts= 8*526= 
8*526 = 4_208
4208   Total price of 3 t-shirts=5*505=1515   Total price of 5 t-shirts=4208-1515= 
4208-1515 = 2_693
2693   Average price of 3 t-shirts=2693/5= 
2693/5 = 2_693/5 = around 538.6
538.6   Correct option Answer:538.6
Answer: D
A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? Choose the correct choice from the following answers:
A) 11 B) 66 C) 77 D) 80 E) 71

Solution: Given M + P + C = 80 * 3= 
80 * 3 = 240
240 --- (1)   M + P= 90 * 2= 
90 * 2 = 180
180 --- (2)   P + C= 70 * 2= 
70 * 2 = 140
140 --- (3)   Where M, P and C are marks obtained by the student in Mathematics, Physics and Chemistry.   P= (2) + (3) - (1) = 180 + 140 - 240= 
180 + 140 - 240 = 80
80   Answer:80
Answer: D
When p is divided by 9, the remainder is 4. All of the following are possible values of p, except for which of the following?	Choose the correct choice:
A) 13
B) 31
C) 49
D) 52
E) 67

Solution: If a number is divisible by 9, the sum of its digits must be divisible by 9. --> If a number leaves a remainder 4 when divided by 9 the sum of its digits must be 4.   52   Answer: 52
Answer: D
If the LCM of 2, 5, 6, and a is 210, which of the following could be a?	Choose the correct choice from the following answers:
A) 5
B) 6
C) 4
D) 7
E) 12

Solution: Using elimination method, eliminate the option to arrive at   if a is replaced by 7 and the LCM is calculated you arrive at 210   7
Answer: D
(178% of 1265) ÷ 5.96 = ?	Pick
A) 125
B) 175
C) 225
D) 375
E) 524

Solution: Explanation :   ? = (178 x 1265/100) ÷ 6 = 2250/600 = 375   Answer : Option 375
Answer: D
The C.P of 10 pens is equal to the S.P of 12 pens. Find his gain % or loss%?	Choose the correct choice
A) 16 2/8%  B) 16 8/3%  C) 16 2/3%  D) 16 4/3%  E) 16 6/3%

Solution: 10 16 2/3%P = 12 SP   12 --- 2 16 2/3%P loss   100 --- ? => 16 2/3%   Answer:16 2/3%
Answer: C
If s is an integer greater than 6, which of the following must be divisible by 3? Select:
A) s (s+3) (s-5)
B) s (s+2) (s-1)
C) s (s+1) (s-4)
D) s (s+4) (s-2)
E) s (s+5) (s-6)

Solution: anything in the form of (s-1) (s) (s+1) is divisible by 3. in other word, a product of any 3 consecutive intevers is divisible by 3.   s (s+1) (s-4) = s (s+1) ((s-1)-3) is equivalant to (s-1) (s) (s+1)   s (s+2) (s-1) is equivalant to (s+1) missing.   s (s+3) (s-5) is equivalant to (s-1) missing and s repeating.   s (s+4) (s-2) is equivalant to odd/even consqcutive integers   s (s+5) (s-6) is equivalant to (s+1) missing and s repeating.   Answer : s (s+1) (s-4)
Answer: C
If four coins are tossed, the probability of getting two heads and two tails is  Choose the correct choice:
A) 3/8  B) 3/4  C) 3/5  D) 3/3  E) 3/1

Solution: Since four coins are tossed, sample space = 24   Getting two heads and two tails can happen in six ways.   n(E) = six ways   p(E) = 6/24   = 3/8   3/8nswer:3/8
Answer: A
If −y ≥ x, and −x < −8, then which of the following must be true?	Choose the correct choice from the following answers.
A) y = −8 B) y > −8 C) −y > 8 D) y ≤ −8 E) y ≥ −8

Solution: −y ≥ x, and −x < −8   y <= -x < -8   As '-x' is less than '-8' and Y is less than or equal to '-x'   we have y < -8 which is similar to -y > 8.   −y > 8) -y > 8
Answer: C
A rectangular swimming pool is 20 feet by 18 feet. A deck that has uniform width surrounds the pool. The total area of the pool and deck is 624 square feet. What is the width of the deck?	Options
A) 2	B) 3	C) 4	D) 5	E) 6

Solution: Let the width =W   Total Area of the pool and deck= (2W+20)(2W+18)   We can Test the answer choices along with unit digit method   A) 2 feet ...........24*22 has unit digit 8..........Eliminate   3) 2.5 feet.........25*23 has unit digit 5..........Eliminate   C) 3 feet............26*24 has unit digit 4...........Hold   D) 4 feet............28*26 has unit digit 8...........Eliminate   E) 5 feet............30*38 has unit digit 0...........Eliminate   Answer: 3 w=3
Answer: B
If 3 girls can do 3 times of a particular work in 3 days, then, 7 girls can do 7 times of that work in
Answers
A) 1 1/5 days
B) 2 days
C) 2 1/5 days
D) 3 days
E) 4 days

Solution: Answer: Option 'D'   That is, 1 girl can do one time of the work in 3 days.   Therefore, 7 girls can do 7 times work in the same 3 days itself.
Answer: D
A dice is rolled 3times & sum of 3 no.'sappearing on the uppermost face is 15. The chance that the first roll was four is?  Choose one:
A) 2/113
B) 3/114
C) 1/108
D) 2/213
E) 3/111

Solution: Sol. Total number of favorable outcomes n(S) . e . 216 1/108ombinations of outcomes for getting sum of 15 on uppermost face = (4, 5, 6) (5, 4, 6) (6, 5, 4) (5, 6, 4), (4, 6, 5), (6, 4, 5), (5, 5, 5), (6, 6, 3), (6, 3, 6) (3, 6, 6) Now outcomes on which first roll was a four, n(E) = (4, 5, 6), (4, 6, 5) P(E) n(E) 2 1 Pt') = n(S) = 216 = 1/108   1/108
Answer: C
2056 x 987 = ?  Pick one.
A) 1936372  B) 2029272  C) 1896172  D) 1923472  E) None of them

Solution: =2056 x 987   =2056 x (1000 - 13)   =2056 x 1000 - 2056 x 13   =2056000 - 26728= 
2056000 - 26728 = 2_029_272
2029272   Answer is 2029272
Answer: B
Which of the following is not a composite number ?	Answers.
A) 234
B) 211
C) 525
D) 603
E) 217

Solution: Clearly 211 is not a composite number. All others are divisible by 3. 234ns : 234
Answer: A
By how much does the larger root of the equation 2b^2+5b = 12 exceed the smaller root?  Pick one:
A) 5/2 B) 10/3 C) 7/2 D) 14/3 E) 11/2

Solution: For 2b^2+5b = 12 Roots are [-5 + sqrt(25 + 96)]/4 OR [-5 - sqrt(25 + 96)]/4   = 1.5 OR -4   Hence larger root 1.5 is  1.5 - (-4)= 
 1.5 - (-4) = 5.5
5.5= 11/2 greater than smaller root (-4).   Hence option (11/2).
Answer: E
The sum of the ages of 4 children born at the intervals of 3 years each is 38 years. What is the age of the youngest child?  Choose the correct choice from the following choices: A) 2 years B) 3 years C) 4 years D) 5 years E) 6 years

Solution: Let the ages of the children be x, (x + 3), (x + 6), (x + 9) years.   Then, x + (x + 3) + (x + 6) + (x + 9) = 38   4x = 20 => x = 5.   Age of youngest child = x = 5 years.   ANSWER:5 years
Answer: D
At a certain stage of a soccer tournament, the score ratio of teams A, B and C was 3:4:5. Eventually, the score ratio of A to B has doubled while the score ratio of A to C has halved. If the final score of team C was 40, what was the final score S of team B? Select the correct option:
A) 1)8	B) 2)10	C) 3)20	D) 4)40	E) 5)80

Solution: A to B = 3 : 4   So, on doubling we get 6 : 4   A to C = 3 : 5   So, on halving we get 1.5 : 5 or 3 : 10 or 6 : 20   So final ratio = 6 : 4 : 20.   If 20x = 40   4x = 8   Hence, answer is 1)8
Answer: A
The difference between two positive integers is 3.if the sum of their squares is 369, the the sum of the numbers is:	Choose the correct option:  A) 12  B) 29  C) 71  D) 48  E) 23

Solution: x^2 +(x+3)^2=369   x^2+x^2+9+6x=369   2x^2+6x-360=0   x^2+3x-180=0   (x+15)(x-12)=0   x=12   correct answer 12
Answer: A
The length of a rectangular plot is thrice its breadth. If the area of the rectangular plot is 972 sq m, then what is the breadth of the rectangular plot?	Pick one:
A) 16	B) 17	C) 18	D) 19	E) 14

Solution: Let the breadth of the plot be b m.   Length of the plot = 3 b m   (3b)(b) = 972   3b2 = 972   b2 = 324   b = 18 m.   Answer: Option 18
Answer: C
A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?  Pick one:	A) 22	B) 23	C) 25	D) 35	E) 30

Solution: Explanation:   Clearly, we have :   B-3 = E ...(i)   B + 3 = D ...(ii)   A+B = D + E+10 ...(iii)   B = C + 2 ...(iv)   A+B + C + D + E= 133 ...(v)   From (i) and (ii), we have : 2 B = D + E ...(vi)   From (iii) and (vi), we have : A = B + 10 ...(vii)   Using (iv), (vi) and (vii) in (v), we get:   (B + 10) + B + (B - 2) + 2B = 133 => 5B = 125=> B = 25.   ANSWER IS 25
Answer: C
A discount electronics store normally sells all merchandise at a discount of 5 percent to 25 percent off the suggested retail price. If, during a special sale, an additional 25 percent were to be deducted from the discount price, what would be the lowest possible price of an item costing $300 before any discount?  Choose the most appropriate option.
A) $130.00 B) $160.75 C) $168.75 D) $182.00 E) $168.00

Solution: Original price : 300 $   Max first discount = -25%   Thus : 300âˆ—(1âˆ’25/100)=225   Second discount on the discounted price = -25%   Thus : 225âˆ—(1âˆ’25/100)=168.75   Answer $168.75
Answer: C
Alice and Bob race around a running track. Alice runs at a constant rate of one lap every 5 minutes and Bob runs at a constant rate of one lap every 6 minutes. If they both start at the same time, how many minutes will it take for Alice to get exactly one lap ahead of Bob?	Choices.
A) 30  B) 32  C) 35  D) 36  E) 40

Solution: Let x be the number of minutes it takes for Alice to get one lap ahead.   Then Alice ran x/5 laps and Bob ran x/6 laps.   x/5 = 1+x/6   6x=30+5x   x=30   The answer is 30.
Answer: A
What is the next number of the following sequence
125, 25, 175, 35, 245, 49 (...)	Select the correct option.
A) 282
B) 343
C) 393
D) 434
E) 515

Solution: The series is   125/5= 
125/5 = 25
25   25*7= 
25*7 = 175
175   175/5= 
175/5 = 35
35   35*7= 
35*7 = 245
245   245/5= 
245/5 = 49
49   49*7= 
49*7 = 343
343   ANSWER: 343
Answer: B
A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 3.5 km long?  Choose one.
A) 4  B) 3  C) 5  D) 7  E) 9

Solution: D = 25 * 60 + 3500= 
25 * 60 + 3500 = 5_000
5000 m   T= 5000/60 * 18/5= 
5000/60 * 18/5 = 300
300 sec= 5 mins   Answer: 5
Answer: C
Difference between the length &breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is?? We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103?
Answers
A) 2500 m^2
B) 2540 m^2
C) 2520 m^2
D) 2600 m^2
E) 3000 m^2

Solution: Solving the two equations, we get: l = 63 and b = 40.   Area = (l x b) = (63 x 40) m2 = 2520 m^2   2520 m^2
Answer: C
If z is a positive integer, which of the following could NOT be the square of z?
Choose the correct choice from the following: A) 5,008,644 B) 5,004,169 C) 4,999,696 D) 4,995,225 E) 4,990,752

Solution: A number ending with 2 can never be a perfect square.   Units digit of a perfect square must be:   1,4,9,6,5   Answer 4,990,752)   9*9=1   1,4,9,6,5   Ans:4,990,752
Answer: E
Kamal started a business investing Rs. 9000. After five months, Sameer joined with a capital of Rs. 8000. If at the end of the year, they earn a profit of Rs. 6970, then what will be the share of Sameer in the profit?  Choose the correct choice from the following choices
A) 2388  B) 2380  C) 2888  D) 2663  E) 2922

Solution: Kamal : Sameer = (9000 * 12) : (8000 * 7)   = 108:56 = 27:14   Sameer's share = 6970 * 14/41 = Rs. 2380.   Answer: 2380
Answer: B
A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 10 days before the completion of the work. In how many days was the work completed?  Choose the correct answer:	A) 12.5 days	B) 16 days	C) 18 days	D) 11 days	E) 38 days

Solution: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 10 days = 10*(1/24 + 1/30) = 3/4   Remaining work = 1/4   The number of days required for this initial work = 2.5 days.   The total number of days required = 10 + 2.5= 
10 + 2.5 = 12.5
12.5 days.   12.5 daysnswer: 12.5 days
Answer: A
Following the approval of crude oil production cuts by OPEC, the price of crude which has slumped by 28% in the last 3 months is expected to rally and increase by about 5% in the next one month. This will bring the price of crude oil to $60.  Choices.
A) 79.4	B) 75.1	C) 80.7	D) 68.3	E) 89.6

Solution: -28+5-(28*5)/100=-24.4% net decrease   let initial price be Y   Y(1-24.4/100)=60   Y=60/0.756 = ~79.4   79.4ns is 79.4)
Answer: A
In a simultaneous throw of pair of dice .find the probability of getting the total more than 7 Choose the correct choice
A) 5/7
B) 4/7
C) 5/12
D) 4/7
E) 1/6

Solution: Here n(S)=(6*6)= 
(6*6) = 36
36   let E=event of getting a total more than 7   ={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}   P(E)=n(E)/n(S)=15/36=5/12   Option 5/12
Answer: C