MU-NLPC/Calc-aqua_rat huggingface dataset:
The perimeters of two squares are 40 cm and 36 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares .  Pick:  A) 17.6 cm  B) 24 cm  C) 26 cm  D) 28 cm  E) 29 cm

Solution: Explanation:   We know perimeter of square = 4(side)   So Side of first square = 40/4= 
40/4 = 10
10 cm   Side of second square= 36/4= 
36/4 = 9
9 cm   17.6 cmrea of third Square= 10*10 - 9*9= 
10*10 - 9*9 = 19
19 cm   So side of third square= 4.4 [because area of square = side*side]   Perimeter = 4*Side = 4*4.4= 
4*4.4 = 17.6
17.6 cm   17.6 cmnswer: Option 17.6 cm
Answer: A
A group of 10 representatives is to be selected out of 14 seniors and 10 juniors. In how many different ways can the group be selected, if it should have 5 seniors and 5 juniors?  Choices:
A) 14C₅ * 10  B) 14C₇ * 10  C) 14C9 * ¹⁰C₅  D) 12 * ¹⁰C₅  E) None of these

Solution: Here, five seniors out of 14 seniors can be selected in 14C₅ ways. Also, five juniors out of ten juniors can be selected ¹⁰C₅ ways. Hence the total number of different ways of selection = 1414C9 * ¹⁰C₅₅ * ¹⁰14C9 * ¹⁰C₅₅ = 1414C9 * ¹⁰C₅9 * ¹⁰14C9 * ¹⁰C₅₅   since 1414C9 * ¹⁰C₅₅ = 1414C9 * ¹⁰C₅9   ANSWER:14C9 * ¹⁰C₅
Answer: C
A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 12m/h. what is the speedof the person while he was going to his office?  Choose the correct choice from the following.
A) 8km/h
B) 9km/h
C) 10km/h
D) 12km/h
E) 14km/h

Solution: u = k , v= 3k   \inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=12   \inline \Rightarrow 1.5k = 12   \inline \Rightarrow k=8km/h   8km/h
Answer: A
In how many ways can you sit 8 people on a bench if 3 of them must sit together?  Choose the correct choice from the following.
A) 720 B) 2,160 C) 2,400 D) 4,320 E) 40,320

Solution: Say 8 people are {A, B, C, D, E, F, G, H} and A, B and C must sit together. Consider them as one unit {ABC}, so we'll have total of 6 units: {ABC}, {D}, {E}, {F}, {G}, {H}, which can be arranged in 6! ways. Now, A, B and C within their unit can be arranged in 3! ways, which gives total of 6!*3!=4,320 different arrangements.   Answer: 4,320.
Answer: D
By investing in 16 % stock at 64, one earns Rs. 1500. The investment made is? Choose the correct answer:  A) 2288  B) 2877  C) 5760  D) 7636  E) 5728

Solution: To earn Rs., investment = Rs. 64.   To earn Rs. 1500, investment = = Rs. 5760.   Answer: 5760
Answer: C
Find the area of circle whose radius is 5.5m?  Select the correct option:
A) 138  B) 95.1  C) 288  D) 280  E) 371

Solution: 22/7 * 5.5 * 5.5   = 95.1   Answer:95.1
Answer: B
How many positive integers less than 25 are prime numbers, odd multiples of 5, or the sum of a positive multiple of 2 and a positive multiple of 4? Choose the correct answer:
A) 27 B) 25 C) 24 D) 22 E) 20

Solution: 9 prime numbers less than 28: {2, 3, 5, 7, 11, 13, 17, 19, 23}   2 odd multiples of 5: {5, 15}   10 numbers which are the sum of a positive multiple of 2 and a positive multiple of 4: {6, 8, 10, 12, 14, 16, 18, 20, 22, 24}   Notice, that 5 is in two sets, thus total # of integers satisfying the given conditions is  9+2+10-1= 
 9+2+10-1 = 20
20.   Answer: 20.
Answer: E
Harkamal purchased 8kg of grapes at the rate of 70 per kg and 9 kg of mangoes at the rate of 55 per kg. How much amount did he pay to the shopkeeper? Choose the correct choice from the following answers:	A) 1055	B) 1075	C) 1065	D) 1070	E) 1080

Solution: Cost of 8 kg grapes = 70 × 8 = 560.   Cost of 9 kg of mangoes = 55 × 9 = 490.   Total cost he has to pay = 560 + 490 = 1055.   1055)
Answer: A
In a certain pond, 40 fish were caught, tagged, and returned to the pond. A few days later, 40 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? Choose one
A) 400  B) 625  C) 1250  D) 2500  E) 1000

Solution: If x is total number of fish in the pond :   4 = 40/x * 100   => x = 1000   So answer is 1000
Answer: E
Compound interest of Rs.1000 at 10% per annum for 1 1/2years will be (interest compounded half yearly).  Choose the correct option.
A) Rs.473
B) Rs.374
C) Rs.495
D) Rs.157
E) None of the above

Solution: 10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)   So compound interest=3000[1+(5/100)]^3 - 1000=1000[(21/20)^3 -1]   =1000(9261-8000)/8000   =1*1261/8   =157   ANSWER:Rs.157
Answer: D
Sripad has scored average of 67 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?  Choose the correct choice.
A) 85  B) 28  C) 38  D) 27  E) 21

Solution: Assuming Sripad has scored the least marks in subject other than science,   Then the marks he could secure in other two are 58 each.   Since the average mark of all the 3 subject is 67.   i.e (58+58+x)/3 = 67   116 + x = 201   x = 85 marks.   Therefore, the maximum marks he can score in maths is 85.   85nswer: 85
Answer: A
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Seven years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?	Options
A) Can't be determined  B) 56  C) 27  D) 24  E) None of these

Solution: Explanation:   Let the present ages of Sameer and Anand be 5x years and 4x years respectively.   Then, (5x+7)/(4x+7)=11/9   ⇒ 45x + 63 = 44x + 77⇒ 9(5x + 7) = 11(4x + 7)   ⇒ 45x - 44x = 77 - 63= 
77 - 63 = 14
14.   Anand's present age= 4x = 56 years.   Answer: 56
Answer: B
A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.4 m and its walls are 5 cm thick. The thickness of the bottom is:  Choose the correct choice from the following
A) 90 cm	B) 4 dm	C) 1 m	D) 1.1 cm	E) None of these

Solution: Explanation:   Let the thickness of the bottom be x cm.   Then , [(330 - 10) × (260 - 10) × (140 - x)] = 8000 × 1000   => 320 × 250 × (140 - x) = 8000 × 1000   => (140 - x) = 8000×1000/320=   100   => x = 40 cm = 4 dm.   Answer: 4 dm
Answer: B
If x≠5 and (x^2 - 25)/(2y) = (x - 5)/4, then in terms of y, x = ?	Choose the correct choice from the following
A) (y - 6)/2 B) (y - 10)/2 C) y - 3 D) y - 6 E) (y + 6)/2

Solution: Since (x^2 – 25)=(x-5)(x+5) the original equation can be changed into 4*(x-5)(x+5) = 2y *(x-5).   By cancelling 2(x-5) (we can do it because x≠5) we get :   2*(x+5)=y.   So x=(y-10)/2. So the answer is (y - 10)/2).
Answer: B
A, B and C started a business with a total investment of Rs. 90000. A invests Rs. 6000 more than B and B invests Rs. 3000 less than C. If the total profit at the end of a year is Rs. 8640, Find C's share.
Choose the correct choice from the following answers.
A) Rs. 3240	B) Rs. 2520	C) Rs. 2880	D) Rs. 3360	E) None of these

Solution: Explanation:   Let C's investment = Rs. x   B's investment = Rs. (x - 3000)   A's investment = Rs. (x - 3000 + 6000) = Rs. (x + 3000)   Now, (A + B + C)'s investment = Rs. 90000   => x + (x - 3000) + (x + 3000) = 90000   => 3x = 90000   => x = 30000   Hence, A's investment = Rs. 33000   B's investment = Rs. 27000   C's investment = Rs. 30000   Ratio of the capitals of A, B and C   = 33000 : 27000 : 30000   = 11 : 9 : 10   A's share = Rs. [(10/30) Ã— 8640] = Rs. 2880   Answer: Option Rs. 2880
Answer: C
How many three digit numbers that do not contain the digit 2 are there? Choose the correct answer:
A) 100
B) 200
C) 512
D) 648
E) 729

Solution: 8*9*9= 
8*9*9 = 648
648: 8 options for the first digit (no 0, no 2) and 9 options for each of the remaining digits (no 2 there).   Answer: 648
Answer: D
The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 16000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is: Choose the correct option.
A) 23 B) 19 C) 22 D) 35 E) 21

Solution: Let the total number of workers be x. Then,   8000x = (16000 * 7) + 6000(x - 7)   = 2000x = 70000   = x = 35.   ANSWER:35
Answer: D
For how many integers n is 2^x = n^x ?  Choose the correct answer
A) None	B) One	C) Three	D) Two	E) More than Three

Solution: draw a graph with x^2 and 2^x, you'll see 3 intercepts between the 2 curves, but one is in the 2nd quadrant, so it can't be an integer (for integer values of x, 2^x can be an integer only for x>0). Thus 2 are valid, and the answer is Two
Answer: D
What is the dividend. divisor 14, the quotient is 12 and the remainder is 8
Choose the correct choice from the following choices.
A) 175
B) 176
C) 177
D) 178
E) 179

Solution: 176 = d * Q + R   176 = 14 * 12 + 8   176 = 168 + 8   176 = 176
Answer: B
When n is divided by 25, the remainder is 4. What is the remainder when n + 15 is divided by 5?
Choices
A) 2 B) 3 C) 4 D) 5 E) 6

Solution: Assume n = 29   Remainder (n/24) = 4   n+15 = 44   Remainder (44/5) = 4   Option 4
Answer: C
A train 140 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is?	Choose the correct answer:
A) 13 km/hr	B) 55.4 km/hr	C) 17 km/hr	D) 18 km/hr	E) 12 km/hr

Solution: Speed of the train relative to man = (140/10) m/sec   = (14 m/sec. [(14   ) * (18/5)] km/hr   = 50.4 km/hr. Let the speed of the train be x km/hr. Then, relative speed   = (x - 5) km/hr. x - 5 = 50.4 ==> x   = 55.4 km/hr.   Answer:55.4 km/hr
Answer: B
The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Pick one:
A) 10m B) 245m C) 25m D) 18m E) 12m

Solution: Explanation:   Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (130 + x)/30 = 25/2 => 2(130 + x) = 750 => x = 245 m.   Answer: 245m) 245m
Answer: B
A train is 700 meter long is running at a speed of 21 km/hour. In what time will it pass a bridge of 130 meter length?	Choose the correct choice:
A) 142.286  B) 251.228  C) 34  D) 200  E) 150.627

Solution: Speed = 21 Km/hr = 21*(5/18) m/sec = 35/6 m/sec   Total distance = 700+130= 
700+130 = 830
830 meter   Time= Distance/speed   = 830 * (6/35) = 142.286 seconds.   142.286nswer: 142.286
Answer: A
Find large number from below question The difference of two numbers is 1000. On dividing the larger number by the smaller, we get 10 as quotient and the 10 as remainder Pick one.
A) 1234 B) 1110 C) 1456 D) 1200 E) 1600

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1000 = 10x + 10   9x = 990   x = 110   Large number = 110+1000= 
110+1000 = 1_110
1110   1110
Answer: B
Of the science books in a certain supply room, 30 are on botany, 45 are on zoology, 90 are on physics, 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same area science?	Choose the correct choice from the following options.
A) 125 B) 180 C) 236 D) 284 E) 311

Solution: The worst case scenario is to remove all the books on botany, zoology, and geology.   Also we can remove 79 books each from physics and chemistry.   The total is  30 + 45 + 50 + 79 + 79= 
 30 + 45 + 50 + 79 + 79 = 283
283.   The next book removed must either be physics or chemistry, ensuring 80 books in that subject.   The answer is 284.
Answer: D
Three friends-whose walking rates are 1 ft./sec., 3ft./sec.,and 6ft./sec. start together walking in the same direction around a circular track that is 360 feet in circumference.After how many minutes are the three of them together again?	Select the correct option
A) 6 mins	B) 10 mins	C) 15 mins	D) 3 mins	E) 7 mins

Solution: The time they take will be what the 1st friend takes to complete one circumference as he is the slowest and that is the point all 3 of them will be together at the end of =360/60= 
360/60 = 6
6 mins.   6 mins
Answer: A
A fair coin is tossed 5 times. What is the probability of getting more heads than tails in 5 tosses? Choose the correct choice from the following answers:
A) 1/2  B) 63/128  C) 4/7  D) 61/256  E) 63/64

Solution: On each toss, the probability of getting a head is 1/2 and the probability of getting a tail is 1/2.   There is no way to get the same number of heads and tails on an odd number of tosses.   There will either be more heads or more tails.   Then there must be more heads on half of the possible outcomes and more tails on half of the possible outcomes.   P(more heads) = 1/2   The answer is 1/2.
Answer: A
Gary drove from point A to point B at 60 Km/h. On his way back he took a train travelling at 110 Km/h and therefore his trip back lasted 5 hours less. What is the distance (in Km) between A and B? Choose the correct option:
A) 600.  B) 630.  C) 660.  D) 690.  E) 720.

Solution: distance=speed*time   d1=s1t1   d2=s2t2   The distance from point A to point B is the same for each trip so,   d1=d2 and   t2=t1-5   thus,   s1t1=s2t2   60t1=s2(t1-5)   t1=11   60*11= 
60*11 = 660
660   Answer: 660.
Answer: C
Points A, B, and, C have xy-coordinates (2,0), (8,12), and (14,0), respectively. Points X, Y, and Z have xy-coordinates (6,0), (8,4), and (10,0), respectively. What fraction D of the area of triangle ABC is the area of triangle XYZ? Choose the correct choice from the following options
A) 1/9  B) 1/8  C) 1/6  D) 1/5  E) 1/3

Solution: If you notice, both triangles ABC and XYZ have a side on X axis. we can take these sides as bases for each triangle, therefore   1/9rea of 1/9BC is 1/2*12*12 (Height of 1/9BC is the y coordinate of the third point (8,12))   similarly 1/9rea of XYZ is 1/2*4*4   dividing area of XYZ with that of 1/9BC gives D=1/9.1/9
Answer: A
A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?	Select the correct option.
A) 229 B) 240 C) 288 D) 277 E) 221

Solution: Speed = 54 * 5/18= 
54 * 5/18 = 15
15 m/sec.   Length of the train= 15 * 20= 
15 * 20 = 300
300 m.   Let the length of the platform be x m . Then,   (x + 300)/36= 15 => x = 240 m.   Answer: 240
Answer: B
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is?	Choose the correct choice from the following answers
A) 24 kg B) 62 kg C) 34 kg D) 31 kg E) 37 kg

Solution: Let A, B, C represent their respective weights.   Then, we have:   A + B + C = (45 * 3)= 
(45 * 3) = 135
135 --- (i)   A + B= (40 * 2)= 
(40 * 2) = 80
80 --- (ii)   B + C= (43 * 2)= 
(43 * 2) = 86
86 --- (iii)   Adding (ii) and (iii), we get: A + 2B + C= 166 --- (iv)   Subtracting (i) from (iv), we get: B = 31   B's weight = 31 kg.   Answer:31 kg
Answer: D
A jar contains only three types of objects: red, blue, and silver paper clips. The probability of selecting a red paper clip is 1/3, and the probability of selecting a blue paper clip is 3/5. What is the probability of selecting a silver paper clip?
Options
A) 1/12 B) 2/15 C) 7/15 D) 3/4 E) 11/15

Solution: Prob of Red = 1/3   Prob of 2/15lue = 3/5   Prob of Silver = ?   P(Silver) = 1 - P(Red) - P(2/15lue) ==> 1-1/3-3/5 = 1/15   Ans: 2/15
Answer: B
One hour before John started walking from P to Q, a distance of 38 miles, Ann had started walking along the same road from Q to P. Ann walked at a constant speed of 3 miles per hour and John at 2 miles per hour. How many miles had Ann walked when they met?	Options.
A) 6 miles  B) 8,4 miles  C) 19 miles  D) 19,6 miles  E) 24 miles

Solution: Ann walks from Q to P at a speed of 3 miles/hr for one hour. She covers 3 miles in 1 hour and now distance between John and Ann is   38 - 3= 
  38 - 3 = 35
35 miles.   Ann walks at 3 mph and John at 2 mph so their relative speed is   3+2= 
  3+2 = 5
5 mph.   They have to cover 35 miles so it will take them  35/5= 
 35/5 = 7
7 hours to meet.   In 7 hrs, Ann would have covered 7 hrs * 3 miles per hour= 21 miles.   Adding this to the 3 miles she covered before John, Ann covered a total of 3 + 21= 
3 + 21 = 24
24 miles.   Answer (24 miles)
Answer: E
A trained covered x km at 40 kmph and another 2x km at 20 kmph. Find the average speed of the train in covering the entire 2x km.	Answers:	A) 16kmph	B) 20kmph	C) 25kmph	D) 30kmph	E) 35kmph

Solution: Total time taken = x/40 + 2x/20 hours   = 5x/40 = x/8 hours   16kmphverage speed = 2x/(x/8)   = 16 kmph   16kmphnswer:16kmph
Answer: A
A1, A2 and A3 enter into a partnership in the ratio 7/2 : 4/3 : 6/5 . After 4 months, A1 increases his share 50%. If the total profit at the end of one year be Rs. 21,600, then A2's share in the profit is: Pick one:
A) 3000
B) 3200
C) 3450
D) 4000
E) 3570

Solution: Ratio of initial investments = 7/2 : 4/3 : 6/5   = 105 : 40 : 36.   Let the initial investments be 105x, 40x and 36x.   => A1 : A2 : A3 = 105x x 4 + 150/100 x 105x x 8 : (40x x 12) : (36x x 12)   = 1680x : 480x : 432x   = 35 : 10 : 9.   Hence, A2's share = Rs. 21600 x 10/54   = Rs. 4000. Answer : 4000
Answer: D
A lady builds 10cm length, 18cm width, and 4cm height box using 12cubic cm cubes. What is the minimum number of cubes required to build the box?
Choose the correct answer:
A) 107	B) 70	C) 78	D) 60	E) 111

Solution: Number of cubes required = Volume of box/Volume of cube   = 10*18*4/12= 
10*18*4/12 = 60
60 cubes   ANSWER:60
Answer: D
At a local supermarket, a box of cereal usually costs 18 dollars. This week, the supermarket sells the box of cereal for 12 dollars. How much money will you save if you buy this cereal at this supermarket?
Choose the correct option:	A) 5 dollars	B) 3 dollars	C) 6 dollars	D) 2 dollars	E) 4 dollar

Solution: Solution:   In this situation, there is a decrease in the price.   Saving = 18 - 12= 
18 - 12 = 6
6 dollars   Option 6 dollars
Answer: C
A person covered one-fourth of the total distance at 20 kmph and remaining distance at 24 kmph. What is the average speed for the total distance?	Select
A) 21 (6/7)kmph  B) 22 (6/7)kmph  C) 21 (7/3)kmph  D) 27 (6/7)kmph  E) 21 (1/8)kmph

Solution: Let the total distance be x km   total time taken = (x/4)/20 + (3x/4)/24 = x/80 + x/32 = 7x/160   Average speed = x/(7x/160) = 160/7kmph   = 22 (6/7)kmph.   Answer:22 (6/7)kmph
Answer: B
3 Years ago, the average age of a family of 5 members was 16 years. A baby having been born, the average age of the family is the same today. The present age of the baby is	Choose the correct choice from the following choices.
A) 1 year.	B) 1.5 Years.	C) 2 Years.	D) 3 Years.	E) 4 Years.

Solution: We're told that 3 YEARS AGO, the average age of a family of 5 members was 16 years.   This means that the SUM of their ages was (5)(16) = 80 years.   A baby was born (meaning that there are now 6 family members). We're told that the PRESENT average age of the family members is the SAME.   This means that the sum of the ages is (6)(16) = 96 years.   We're asked for the PRESENT age of the baby.   Since each of the original 5 family members has aged 3 years since the initial average was calculated, the sum of their PRESENT ages is...   80 + (5)(3) = 95.   1 year.
Answer: A
After spending 40 percent machinery, 25 percent inbuilding , 15 percent in raw material and 5 percent on furniture. John had a balance of Rs.1305. Total money with him was? Pick.
A) 7600
B) 8700
C) 9000
D) 9200
E) 9400

Solution: [100 - (40+25+5+15)] % of x = 1305   \inline \Rightarrow 15% of x =1305   \inline \Rightarrow \frac{15}{100}\times x=1305   \inline \therefore x=\frac{1305\times 100}{15}=8700   8700
Answer: B
Which of the following CAN be the least common multiple of two positive integers 4 and 6?  Choose the correct choice:
A) 4	B) 6	C) 8	D) 10	E) 12

Solution: LCM of 4,6 is 12   Answer : 12
Answer: E
Last year, sales at Company Zora were 12% greater in February than in January, 15% less in March than in Feb, 30% greater in April than in March, 10% less in May than in April, and 5% greater in June than in May. In which month were sales closest to Jan?
Choose one
A) April
B) March
C) May
D) Feb
E) June

Solution: Jan = $100   12% greater in February than in January ---> Feb = $112   15% less in March than in Feb ---> Mar = $95.2   30% greater in April than in March ---> Apr = $123.76   10% less in May than in April ---> May $111.38   5% greater in June than in May --->Jun = $116.95   Answer : March
Answer: B
A salesman's income consists of a commission and a base salary of $450 per week. Over the past 5 weeks, his weekly income totals have been $406, $413, $420, $436 and $395. What must his average (arithmetic mean) commission be per week over the next two weeks so that his average weekly income is $500 over the 7-week period?	Answers.
A) $150  B) $245  C) $365  D) $715  E) $265

Solution: Total weekly income over 5 weeks=$406+$413+$420+$436+$395=$2070   For avg weekly income to be $500 over 7 weeks, we need total weekly income over 7 weeks406+ 413+ 420+ 436+ 395= 
406+ 413+ 420+ 436+ 395 = 2_070
$2070   For avg weekly income to be $500 over 7 weeks, we need total weekly income over 7 weeks=$3500   Now, $3500-$2070=$1430   From this, we subtract base salary for 2 weeks i.e $450*2= 
450*2 = 900
$900   Therefore, commission=$1430-$900=$530 for 2 weeks   Avg weekly commission1430- 900= 
1430- 900 = 530
$530 for 2 weeks   Avg weekly commission=$265   Answer $265
Answer: E
From 6 officers and 10 clerks in how many can 5 be chosen to include exactly one officer?	Choose the correct choice from the following options:	A) 1452	B) 1562	C) 2456	D) 1260	E) 660

Solution: Required number of ways = 6C1 * 10C4 = 1260   Answer is 1260
Answer: D
Sally, Mark, Sarah, Steve and Jim are inheriting the money from their grandmother. She left them $527,500 to split equally between all of them. If the money is split equally, how much money will each person receive?  Choose the correct choice from the following options:  A) $135,875  B) $52,700  C) $127,900  D) $105,500  E) $105,000

Solution: There are 5 people inheriting the money.   We have to take the total of the inheritance and divide it by 5 for each person receiving money.   $527,500 / 5 = $105,500.   Therefore the correct answer is $105,500.
Answer: D
Every day Daniel drives 96 miles back from work. On Sunday, Daniel drove all the way back from work at a constant speed of x miles per hour. On Monday, Daniel drove the first 32 miles back from work at (2x) miles per hour, and the rest of the way at (x/2) miles per hour. The time it took Daniel to drive back from work on Monday is longer than the time it took him to drive back from work on Sunday by what percent?
Choose the correct choice from the following options.
A) 10%  B) 20%  C) 30%  D) 40%  E) 50%

Solution: Let's TEST X = 4....   On Sunday, Daniel drove 96 miles at 4 miles/hour.   D = (R)(T)   96 = (4)(T)   96/4= 
96/4 = 24
24= T   It takes 24 hours to drive home   On Monday, Daniel drove the first 32 miles at (2)(4) = 8 miles/hour and the rest of the way (64 miles) at  4/2= 
 4/2 = 2
2 miles/hour   D= (R)(T)   32 = (8)(T)   32/8= 
32/8 = 4
4= T   It takes 4 hours for the first part   D = (R)(T)   64 = (2)(T)   64/2= 
64/2 = 32
32= T   It takes 32 hours for the second part   Total time to drive home on Monday = 4+32= 
4+32 = 36
36 hours   We're asked by what percent 36 hours is greater than 32 hours.   36/32= 1.5, so it is 50% greater.   50%
Answer: E
When positive integer N is divided by positive integer D, the quotient is 16, with a remainder of 7. When N is divided by (D + 2), the quotient is 15 and the remainder is 1. What is the value of N?
Choose the correct choice from the following answers:  A) 151  B) 391  C) 511  D) 691  E) 871

Solution: N/D=16 7/D= 16D+7   N/(D+2)=15 1/(D+2)=15D+30+1   solving these two equations   we get D=24 N= 391 answer is 391.
Answer: B
R campers fished for 4 hours. If m of the campers caught 2 fish apiece and the rest caught a combined total of n fish, how many fish did the R campers catch per hour?  Choose the correct choice from the following
A) 2m + n(R-m)
B) (2m + n(R-m))/3
C) (2m + n(m-R))/3
D) (2m + n)/3
E) (2m + n)/4

Solution: m of the campers caught 2 fish apiece in 4 hours --> total fish caught by m campers = 2m;   The rest caught a combined total of n fish.   Total fish caught in 4 hours = 2m+n --> per hour (2m+n)/4.   Answer: (2m + n)/4.
Answer: E