MU-NLPC/Calc-aqua_rat huggingface dataset:
The speed of boat in still water is 20 km/hr. If it travels 26 km downstream and 14 km upstream in same time, what is the speed of the stream?	Choose the correct choice from the following answers:
A) 6  B) 7  C) 8  D) 9  E) 2

Solution: Explanation:   Let X be speed of stream   Speed of boat downstream = (20 + X )   Speed of boat upstream = (20 – X)   It is given that boat takes same time to travel 26 km downstream and 14 km upstream   [26/(20 +X)] = [14 / (20 – X)]   520 – 26 X = 280 + 14X   40X = 240   X = 6 km/hr   6NSWER: 6
Answer: A
Four barrels of water have an average capacity of 8 gallons. What is the maximum possible capacity of the smallest barrel Q if the median is 10 gallons?  Select
A) 1 B) 2 C) 3 D) 4 E) 5

Solution: Suppose 4 barrels are B1, B2, B3, B4 in ascending capacity.   (B1+B2+B3+B4)/4 = 8   B1+B2+B3+B4=32   median is 10 ....... as the no. of terms are even i.e 4, median = (22+23)/2   ==> 22+23 = 20   now we have 21+24 = 32-20= 
32-20 = 12
12   Only the following possible cases can be there :   1,9,11,11   1,10,10,11   2,10,10,10   Max value of smallest barrel Q= 2
Answer: B
Set J consists of 5 consecutive even numbers. If the smallest term in the set is -2, what is the range of the positive integers in set J?  Pick one:
A) 0  B) 2  C) 4  D) 6  E) 8

Solution: Since there are only 5 integers, another approach is the just list all 5.   We get: -2,0,2, 4, 6   Range of POSITIVE INTEGERS =6 - 2= 
6 - 2 = 4
4   Answer: 4
Answer: C
What is the measure of the acute angle between the hour and minute hands of a correctly
working clock at 4:18 ?
Select:
A) 12◦
B) 15◦
C) 18◦
D) 21◦
E) 24◦

Solution: Consider an axis through the center of the clock with direction, the direction of the hands of the   clock at 12:00. At 4:18 the angle between the axis and the hour hand is   (4+18/60)*360◦/12=129◦   The angle between the axis and the minute hand is 18/60*360◦(4+18/60)*360 /12= 
(4+18/60)*360 /12 = 129
129◦   The angle between the axis and the minute hand is 18/60*360= 
18/60*360 = 108
108◦   correct answer 21◦
Answer: D
A and B can do a piece of work in 7 days. With the help of C they finish the work in 5 days. C alone can do that piece of work in?
Choose the correct choice from the following choices.
A) 15.5 days
B) 19.5 days
C) 17.5 days
D) 16.5 days
E) 18.5 days

Solution: 17.5 days = 1/5 – 1/7 = 2/35 => 17.5 days   ANSWER:17.5 days
Answer: C
A train 300 m long is running at a speed of 99 km/hr. In what time will it pass a bridge 195 m long?
Pick:
A) 17
B) 18
C) 19
D) 20
E) 21

Solution: Speed = 99 * 5/18 = 55/2 m/sec   Total distance covered = 300 + 195= 
300 + 195 = 495
495 m   Required time= 495 * 2/55= 
495 * 2/55 = 18
18 sec   Answer: 18
Answer: B
Of the science books in a certain supply room, 50 are on botany, 75 are on zoology, 90 are on physics. 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same science?  Choose one:  A) 81  B) 59  C) 166  D) 285  E) 334

Solution: I solve it using the tough luck technique:   According to question: What is the least number of books you should pick so as to get at least 80 books of the same science subject.   80 books of the same science subjects is possible only for two subjects: Physics=90>80 OR Chemistry=110>80   Now, we need to be certain that out of the books we picked, there are either at least 80 physics books or 80 chemistry books   What if we pick the first 80 books and none of them is either Physics or Chemistry. Possible. Thus, we first count all our negatives.   We picked:   50 Botany Books   75 Zoology Books   50 Geology Books   Now, any book we pick will be either Chemistry or Physics. But unfortunately, we can't be lucky enough to pick 80 books and all of them will be Physics, right!!   Thus, in order to make sure that we have 80 books of either of these 2 subjects, we must pick   79*2+1 books   Because, we could have picked the books in following order;   1st book picked: Physics   2nd book picked: Chemistry   3rd book picked: Physics   Thus, Total= 50+75+50+79*2+1=175+1+158= 
175+1+158 = 334
334   Ans:334
Answer: E
A bag contains 12 white and 18 black balls. 2balls are drawn in succession. What is the probability that first is white and second is black? Choose the correct answer.
A) 13/213 B) 36/145 C) 25/113 D) 27/137 E) 31/128

Solution: The probability that first ball is white:   =12C130C1=12C130C1   =1230=1230   =25=25   Since, the ball is not replaced; hence the number of balls left in bag is 29.   Hence, the probability the second ball is black:   =18C129C1=18C129C1   =1829=1829   Required probability,   =(25)×(1829)=(25)×(1829)   =36/145   36/145
Answer: B
A can finish a work in 36days, B in 9days and C in 2days, B and C start the work but are forced to leave after 3 days. The remaining work was done by A in?
Choices:	A) 15days	B) 12days	C) 6days	D) 7days	E) 8days

Solution: B+C 1day work = 1/9 + 1/12 +  1= 
+  1 = 1
1/9 + 1/12= 7/36   work done by B and C in 3days = 7/36 * 3 = 7/12   Remaining work = 1 - 7/12 = 5/12   1/36 work is done by 15days in 1day   5/12 work is done by 15days in   36*5/12= 
  36*5/12 = 15
15days   15daysnswer is 15days
Answer: A
The numbers of students speaking English and Hindi are in the ratio of 4 : 5. If the number of students speaking English increased by 35% and that speaking Hindi increased by 20%, what would be the new respective ratio?	Options:
A) 19 : 20
B) 7 : 8
C) 8 : 9
D) Cannot be determined
E) None of these

Solution: Reqd ratio = 4×13/55×120=9:10   Answer None of these
Answer: E
A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 2 days. In how many days can they complete the remaining work?  Choose the correct choice from the following answers
A) 7 days
B) 2 days
C) 5 days
D) 3 days
E) 6 days

Solution: 2 days   2 days   Work done by A in 2 days = 2/5   Remaining work = 3/5   Work done by both A and 2 days in one day = 1/5 + 1/10 = 3/10   Remaining work = 3/5 * 10/3= 
3/5 * 10/3 = 2
2 days.
Answer: B
An association of mathematics teachers has 1,260 members. Only 525 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 60 percent of the votes cast? Choose the correct choice from the following answers.
A) 75%  B) 58%  C) 42%  D) 34%  E) 25%

Solution: Total Number of members = 1260   Number of members that cast votes = 525   Since , winning candidate received 60 percent of the votes cast   Number of votes for winning candidate = (60/100)*525= 
(60/100)*525 = 315
315   Percent of total membership that voted for winning candidate= (315/1260)*100= 
(315/1260)*100 = 25
25%   Answer 25%
Answer: E
A train passes a station platform in 32 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?	Choose the correct choice from the following answers
A) 180 m	B) 160 m	C) 240 m	D) 207 m	E) 202 m

Solution: Speed = [54 * 5/18] m/sec   = 15 m/sec.   Length of the train = (15 * 20)= 
(15 * 20) = 300
300 m.   Let the length of the platform be x meters.   Then, x + 300 / 32= 15   x + 300 = 480   x =180m.   180 mnswer: 180 m
Answer: A
In how many a committee of 5 members can be selected from 6men 5 ladies consisting of 3 men and 2 ladies
Pick:
A) 231
B) 150
C) 200
D) 450
E) 451

Solution: (3 men out of 6) and (2 ladies out of 5) are to be chosen   Required number of ways   =(62003 * 52002)   = 200   Ans: 200
Answer: C
Nine men went to a hotel. Eight of them spent Rs.3 each over their meals and the ninth spent Rs.2 more than the average expenditure of all the nine. Determine the total money spent by them?
Choose the correct answer
A) 29.25  B) 29.28  C) 79.28  D) 29.22  E) 29.21

Solution: 29.25verage of 9 = x   9x = 8 * 3 + x * 2 x = 3.25   Total = 9 * 3.25= 
9 * 3.25 = 29.25
29.25   29.25nswer: 29.25
Answer: A
The current of a stream runs at the rate of 4 kmph. A boat goes 6 km and back to the starting point in 2 hours, then find the speed of the boat in still water? Choose the correct choice:
A) 6  B) 7  C) 8  D) 5  E) 3

Solution: S = 4   M = x   DS = x + 4   US = x - 4   6/(x + 4) + 6/(x - 4) = 2   x = 8   Answer:8
Answer: C
A train covers a certain distance at a speed of 340kmph in 4 hours. To cover the same distance in 2 3/4 hours, it must travel at a speed of Choose the correct choice from the following answers:
A) 495km/hr	B) 420km/hr	C) 450km/hr	D) 550km/hr	E) 650km/hr

Solution: Explanation:   Distance = 340Ã—4 = 1360km   Required speed = (1360Ã— 4/11) = 495km/hr   495km/hrnswer: Option 495km/hr
Answer: A
6 people meet for a business breakfast. Each person shakes hands once with each other person present. How many handshakes take place?  Answers.
A) 30 B) 21 C) 18 D) 15 E) 10

Solution: Let's look at the logic.   Every person shakes hand with other '5'. So, 6 people shake hands with 6X5= 30 people   But in this 30 we have counted two times the total handshakes (c shakes hand with d and d shakes hand with c)   So just divide 30/2= 
30/2 = 15
15 total handshakes   Answer is 15
Answer: D
Find the odd man out?
396, 462, 572, 427, 671, 264.	Choose the correct option
A) 2378  B) 427  C) 297  D) 2678  E) 187

Solution: Explanation:   In each number except 427, the middle digit is the sum of other two.   Answer: 297) 427
Answer: C
To deliver an order on time, a company has to make 25 parts a day. After making 25 parts per day for 3 days, the company started to produce 5 more parts per day, and by the last day of work 100 more parts than planned were produced. Find how many parts the company made and how many days this took.
Select:
A) 347  B) 3667  C) 387  D) 675  E) 711

Solution: Let xx be the number of days the company worked. Then 25x is the number of parts they planned to make. At the new production rate they made:   3⋅25+(x−3)⋅30=75+30(x−3)3⋅25+(x−3)⋅30=75+30(x−3)   Therefore: 25x=75+30(x−3)−10025x=75+30(x−3)−100   25x=75+30x−90−10025x=75+30x−90−100   190−75=30x−25190−75=30x−25   115=5x115=5x   x=23x=23   So the company worked 23 days and they made 23⋅25+100=67523⋅25+100=675 pieces.   Answer:675
Answer: D
The average weight of 8 persons increases by 4 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ?	Select
A) 75 kg	B) 65 kg	C) 55 kg	D) 97 kg	E) 25 kg

Solution: Total weight increased = (8 x 4) kg = 32 kg.   Weight of new person = (65 + 32)= 
(65 + 32) = 97
97 kg.   Answer: 97 kg
Answer: D
Which of the following statements is not correct?
A.	log10 (10) = 1
B.	log (2 + 3) = log (2 x 3)
C.	log10 (1) = 0
D.	log (1 + 2 + 3) = log 1 + log 2 + log 3	Choose the correct option.
A) log10 (10) = 1 B) log (2 + 3) = log (2 x 3) C) log10 (1) = 0 D) log (1 + 2 + 3) = log 1 + log 2 + log 3 E) none of these

Solution: (a) Since loga (a) = 1, so log10 (10) = 1.   (b) log   (2 + 3)= 
  (2 + 3) = 5
log 5 and log (2 x 3)= log 6 = log 2 + log 3   log (2 + 3) log (2 x 3)   (c) Since loga (1) = 0, so log10 (1) = 0.   (d) log   (1 + 2 + 3)= 
  (1 + 2 + 3) = 6
log 6= log (1 x 2 x 3) = log 1 + log 2 + log 3.   So, (b) is incorrect.   Answer is log (2 + 3) = log (2 x 3).
Answer: B
A pipe takes a hours to fill the tank. But because of a leakage it took 7 times of its original time. Find the time taken by the leakage to empty the tank	Choose the correct choice from the following:  A) 50 min  B) 60 min  C) 90 min  D) 80 min  E) 70 min

Solution: pipe a can do a work 60 min.   lets leakage time is x;   then   1/60 -1/x=1/420   x=70 min   ANSW70 minR:70 min
Answer: E
Three positive integers a, b, and c are such that their average is 24 and a ≤ b ≤ c. If the median is (a + 11), what is the least possible value of c? Choose the correct choice.
A) 23
B) 25
C) 27
D) 29
E) 31

Solution: Solution:   We know that the average value is 24 therefore (a+b+c)/3 = 24   so a+b+c = 72   and b = a + 11   therefore a + (a + 11) + c = 72   The least value of c is when c = b   so take c = a + 11   hence, a + (a + 11) + (a + 11) = 72   i.e., a = 50/3 a non integer therefore c is not equal to b   so take c = b+1 therefore c = a+12   a + (a + 11) + (a + 12) = 72   i.e., a= 49/3 again a non integer therefore c is not equal to b+1   next take c= b+2 therefore c = a+13   a + (a + 11) + (a + 13) = 72   i.e., a=48/3= 
48/3 = 16
16   hence, a= 16, b = 27, and c = 29   Answer: 29
Answer: D
X and Y run a 100m race,where X beats Y by 20 m. To do a favor to Y, X starts 10m behind the starting line in a second 100m race. Both run at the same previous speed. Which of the following is true?	Choose the correct choice from the following answers:
A) X Beats Y by 2m B) X Beats Y by 0.5 m C) X Beats Y by 4 m D) Y Beats X by 10m E) Beats X by 11m

Solution: Let's suppose that the speed of X is 10m/s and that the speed of Y is 8m/s.   So, in the first race, the results are the following:   X crosses the finish line in 10s. In other words, X has run 100m in 10 s.   In 10s, Y has run 80 meters.   Therefore, there is the difference of 20 meters mentioned in the question.   Now, let's review the second race.   In 12 seconds, X can complete the 120 meters race. We have to remember that X is 20 meters behind the starting line.   But in 12 seconds, Y has covered (80+16)= 
(80+16) = 96
96 meters. Also, it is important to notice that in 12 seconds Y cannot arrive to the finish line.   So, 100 - 96= 4 meter   Answer: X Beats Y by 4 m
Answer: C
A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 25%. What was its profit on the items sold in February?	Pick one:
A) 12.5%
B) 30%
C) 35%
D) 37.5%
E) 40%

Solution: 12.5%ssume the total price = 100x   Price after 20% markup = 120x   Price after 25%further markup = 1.25*120= 
1.25*120 = 150
150x   Price after the discount= 0.75*150= 
0.75*150 = 112.5
112.5x   Hence total profit= 12.5%   Option 12.5%
Answer: A
Which of the following fractions terminates?	Choose the correct choice:
A) 3/160 B) 5/900 C) 7/220 D) 9/120 E) 11/550

Solution: For a fraction to have terminating decimal, it must either have only 2 and/or 5 in the denominator. All other values in the denominator leads to non terminating decimal values   Hence,   1. 160 = 2 * 2 * 2 * 2 * 2 * 5, hence is terminating   2. There is a 3 in the denominator, hence it is a non terminating decimal   3. There is an 11 in the denominator, hence it is a non terminating decimal   4. There is a 3 in the denominator, hence it is a non terminating decimal   5. There is an 11 in the denominator, hence non terminating   Option 3/160
Answer: A
A train consists of 12 boggies, each boggy 15 metres long. The train crosses a telegraph post in 9 seconds. Due to some problem, three boggies were detached. The train now crosses a telegraph post in Choose the correct choice from the following:
A) 6.75 sec
B) 12 sec
C) 15 sec
D) 20 sec
E) None of these

Solution: Length of train = 12 Ã— 15 = 180 m.   Then, speed of train = 180â„9 = 20 m/s   Now, length of train = 9Ã— 15 = 135m   âˆ´ Required time = 135â„20 = 6.75 sec.   6.75 secnswer 6.75 sec
Answer: A
Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. The length of the faster train is Choose the correct option
A) 80 m	B) 100 m	C) 120 m	D) 180 m	E) None

Solution: Solution   Relative Speed	= (36 + 45) km/hr   = (81 x 5/18) m/sec   = (45/2) m/sec   Length of the train	= (45 / 2 x 8) m   = 180 m.   Answer 180 m
Answer: D
A shopkeeper labeled the price of his articles so as to earn a profit of 40% on the cost price. He then sold the articles by offering a discount of 10% on the labeled price. What is the actual percent profit earned in the deal? Choose the most appropriate option: A) 26% B) 20% C) 17% D) 18% E) None of these

Solution: Explanation:   Let the CP of the article = Rs.100.   Then labeled price = Rs.140.   SP = Rs.140- 10% of 140 = Rs.140-14 = Rs.126.   Gain = Rs.126 â€“ Rs.100 = Rs.26   Therefore, gain/profit percent = 26%.   26%nswer: Option 26%
Answer: A
the ratio of two no. addition and subtraction be 4:3.the what is the ratio of numbers?
Choose the correct choice from the following:
A) 3:2
B) 4:3
C) 5:1
D) 6:5
E) 7:1

Solution: (x+y)/(x-y)=4/3   dividing numerator and denominator by y   (x/y)+1/(x/y)-1=4/3   let x/y be z   z+1/z-1=4/3   3z+3=4z-4   z=7   x/y=7   answer 7:1
Answer: E
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?  Select the correct option
A) 99.222 B) 223.22 C) 157.5 D) 222.88 E) 229.11

Solution: (3500*1.5*3)/100= 
(3500*1.5*3)/100 = 157.5
> 157.50   Answer: 157.5
Answer: C
Three workers have a productivity ratio of 2 to 5 to 9. All three workers are working on a job for 4 hours. At the beginning of the 5th hour, the slowest worker takes a break. The slowest worker comes back to work at the beginning of the 9th hour and begins working again. The job is done in ten hours. What was the ratio of the work performed by the fastest worker as compared to the slowest? Choices:
A) 12 to 1
B) 6 to 1
C) 15 to 2
D) 1 to 6
E) 1 to 5

Solution: The fastest worker who does 9 units of job worked for all 10 hours, so he did   9*10= 
  9*10 = 90
90 units of job;   The slowest worker who does 2 unit of job worked for only   4+2= 
  4+2 = 6
6 hours (first 4 hours and last 2 hours), so he did   2*6= 
  2*6 = 12
12 units of job;   The ratio thus is 90 to 12, or 15 to 2.   Answer: 15 to 2.
Answer: C
A committee has 4 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?	Choose the correct choice from the following answers:  A) 127  B) 120  C) 882  D) 272  E) 323

Solution: The number of ways to select two men and three women   = 4C₂ * ⁶C₃   = (4*3 )/(2 * 1) * (6 * 5 * 4)/(3 * 2)= 
(4*3 )/(2 * 1) * (6 * 5 * 4)/(3 * 2) = 120
120   Answer: 120
Answer: B
Divide 71 into 2 parts such that 1 part exceeds the other by 8. What are the 2 no.'s in that part?
Choose the correct answer:	A) 23	B) 28	C) 31	D) 36	E) 39

Solution: Let $let n$ be the smaller and 71 - n be the larger number. Now, since the larger number exceeds the smaller number by 7, we can form the equation   larger number – smaller number = 7   which is equivalent to   Simplifying, we have 71 - 2n = 7. This gives us 2n = 78 which implies that the larger number is . The smaller is 71-39=31.   31
Answer: C
As a bicycle salesperson, David earns a fixed salary of $40 per week plus $6 per bicycle for the first 6 bicycles he sells, $12 per bicycle for the next 6 bicycles he sells, and $18 per bicycle for every bicycle sold after first 12. This week, he earned more than twice as much as he did last week. If he sold x bicycles last week and y bicycles this week, which of the following statements must be true? I. y<2x II. y>x III. y>3
Choose the correct option
A) I,II only
B) I only
C) II only
D) II,III only
E) III only

Solution: II. y>x --> since this week, David earned more than he did last week and the total salary is in direct relationship with the # of bicycle sold, then y (# of bicycle sold this week) must be more than x (# of bicycle sold last week);   III. y>3 --> if David sold 3 bicycles this week then this week he earned 40+3*6= 
40+3*6 = 58
$58, which cannot be more than twice as much as he earned the last week, since the minimum salary is fixed to $40. So y must be more than 3;   I. y<2x --> is not always true.   Answer: II,III only
Answer: D
A certain university will select 3 of 7 candidates eligible to fill a position in the mathematics department and 5 of 8 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? Choose the correct choice from the following answers:
A) 42232
B) 42170
C) 14008
D) 16510
E) 41160

Solution: 7C3*8C5 = 35*56 = 41160   the answer is (41160)
Answer: E
a light flashes every 20 seconds, how many times will it flash in ? of an hour?	Pick one:
A) 550 B) 600 C) 650 D) 180 E) 750

Solution: 1flash=20sec   for 1 min=3flashes   so for 1 hour=3*60= 
3*60 = 180
180 flashes.   ANSWER:180
Answer: D
Company S produces two kinds of stereos: basic and deluxe. Of the stereos produced by Company S last month, 2/3 were basic and the rest were deluxe. If it takes 1.2 as many hours to produce a deluxe stereo as it does to produce a basic stereo, then the number of hours it took to produce the deluxe stereos last month was what fraction of the total number of hours it took to produce all the stereos?
Choose the correct choice from the following answers: A) 3/8 B) 14/31 C) 7/15 D) 17/35 E) 1/2

Solution: The easiest way for me is to plug in numbers.   Let the number of basic stereos produced be 40, and number of delux stereos produced be 20. Total of 60 stereos.   If it takes an hour to produce a basic stereo then it will take 1.2 hours to produce a deluxe stereo.   40 basic stereos = 40 hours.   20 delux stereos = 24 hours.   Total hours = 64.   Then the fraction would be 24/64 = 3/8. Therefore answer 3/8.
Answer: A
What is the CP of Rs 100 stock at 2 discount, with 1/5% brokerage? Answers.
A) 99.6  B) 96.2  C) 97.5  D) 98.2  E) None of these

Solution: Explanation:   Use the formula,   CP= 100 â€“ discount + brokerage%   CP= 100-2+1/5   98.2   Thus the CP is Rs 98.2.   ANSWER 98.2
Answer: D
The average of the marks of 10 students in a class is 40. If the marks of each student are doubled, find the new average?	Options:
A) 78	B) 56	C) 80	D) 27	E) 40

Solution: Sum of the marks for the 10 students   = 10 * 40= 
10 * 40 = 400
400. The marks of each student are doubled, the sum also will be doubled.   The new sum= 400 * 2= 
400 * 2 = 800
800. So, the new average= 800/10= 
800/10 = 80
80.   Answer: 80
Answer: C
A man can row upstream at 20 kmph and downstream at 60 kmph, and then find the speed of the man in still water?	Select the correct option:	A) 27	B) 29	C) 40	D) 20	E) 24

Solution: US = 20   DS = 60   M = (20 + 60)/2= 
(20 + 60)/2 = 40
40   Answer: 40
Answer: C
The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 92. Find the number of students who wrote the exam.	Choose the correct choice from the following choices.
A) 15  B) 25  C) 30  D) 45  E) 55

Solution: Let the number of students who wrote the exam be x.   Total marks of students = 80 x.   Total marks of (x - 5) students = 92(x - 5)   80x - (5 * 20) = 92(x - 5)   360 = 12x => x = 30   ANSWER:30
Answer: C
The ratio of the ages of Anil and his son at present is 7:3. Six years hence, the ratio of the ages of the Anil's wife and the son will be 2:1. Find the ratio of the present ages of Anil and his wife?  Choose the correct choice from the following choices:
A) 6.3	B) 4:3	C) 5:2	D) Cannot be determined	E) 7:8

Solution: Answer: Option D   Let the present ages of anil and his son be 7x and 3x years respectively.   Let the present age of the son's mother be m years.   (m + 6)/(3x + 6) = 2/1   m = 6x + 6   Ratio of the present ages of anil and his son's mother = 7x/(6x + 6).   This cannot be found uniquely.
Answer: D