MU-NLPC/Calc-aqua_rat huggingface dataset:
Two trains having equal lengths, take 10 seconds and 15 seconds respectively to cross a post. If the length of each train is 120 meters, in what time (in seconds) will they cross each other when traveling in opposite direction?
Options:
A) 22
B) 38
C) 12
D) 99
E) 73

Solution: Explanation:   Speed of train 1 = = 12 m/sec   Speed of train 2 = = 8 m/sec   if they travel in opposite direction, relative speed = 12 + 8= 
12 + 8 = 20
20 m/sec   distance covered= 120 + 120= 
120 + 120 = 240
240 m   time= distance/speed = 240/20= 
240/20 = 12
12 sec   Answer: 12) 12
Answer: C
An illiterate retailer marks all its goods at 50% above the cost price and thinking that he will still make 25% profit, offers a discount of 25% on the market price. What is the actual profit on the sales?
Pick:
A) 0.125	B) 26.5%	C) 27.8%	D) None of the above	E) Cannot be determined

Solution: Explanation :   Let C.P =Rs 100.then, marked price =Rs100   S.P=75% of Rs 150= Rs 112.50   Hence, gain%=12.50%   0.125nswer : 0.125
Answer: A
If the perimeter of a rectangular garden is 680 m, its length when its breadth is 82 m is?  Choose the correct option
A) 286 m
B) 899 m
C) 200 m
D) 166 m
E) 258 m

Solution: 2(l + 82) = 680 => l   = 258 m   Answer: 258 m
Answer: E
A number when divided by 5, gives 45 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 10 Choose the most appropriate option: A) A)5 B) B)3 C) C)4 D) D)6 E) E)7

Solution: Explanation:   P ÷ 5 = 45   => P = 45 * 5= 
45 * 5 = 225
225   P / 10=225 / 10 = 22, remainder = 5   5nswer: Option 5
Answer: A
The toll T, in dollars, for a truck using a certain bridge is given by the formula T = 0.50 + 0.50( x − 2), where x is the number of axles on the truck. What is the toll for an 18-wheel truck that has 2 wheels on its front axle and 4 wheels on each of its other axles? Pick.
A) $ 2.00	B) $ 3.00	C) $ 3.50	D) $ 4.00	E) $ 5.00

Solution: Number of wheels in truck = 18   Number of wheels on its front axle =2   number of wheels remaining = 16   number of axles remaining axles = 16/4= 
16/4 = 4
4   Total number of axles= 5   T = 0.50 + 0.50( x − 2)   = 0.50 + .5*3   = 0.5 +1.5= 
0.5 +1.5 = 2
2 $   $ 2.00nswer $ 2.00
Answer: A
The circumference of the front wheel of a cart is 40 ft long and that of the back wheel is 48 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?	Choices:
A) 1200 ft
B) 800 ft
C) 900 ft
D) 1000 ft
E) 1500 ft

Solution: total distance - x   x/40 - x/48 = 5   x = 1200 ft   1200 ftNSWER 1200 ft
Answer: A
The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 11 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?  Pick.
A) 23 years  B) 24 years  C) 25 years  D) 26 years  E) 27 years

Solution: EXPLANATION   Let the average age of the whole team by x years.   11x â€“ (26 + 40) = 9(x -1)   11x â€“ 9x = 54   2x = 54   x = 27.   So, average age of the team is 27 years.   Answer 27 years
Answer: E
Difference between a two-digit number and the number obtained by interchanging the two digits is 36, what is the difference between two numbers  Answers:
A) 2
B) 4
C) 8
D) 12
E) 14

Solution: Explanation:   Let the ten digit be x, unit digit is y.   Then (10x + y) - (10y + x) = 36   => 9x - 9y = 36   => x - y = 4.   Option 4
Answer: B
By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent?
Select:
A) 42 6/8% B) 42 6/7% C) 42 4/7% D) 42 9/7% E) 42 6/7%

Solution: SP = CP + g   50 SP = 50 CP + 15 SP   35 SP = 50 CP   35 --- 15 CP gain   100 --- ? => 42 6/7%   Answer: 42 6/7%
Answer: B
In a BCCI meeting there are 14 people. All shake hands with each other once. How many handshakes will be there altogether?	Answers.
A) 28
B) 13
C) 14
D) 19
E) 18

Solution: There will be n-1 handshakes as A person will shake hands with all the other members.   =14-1= 
14-1 = 13
13   Answer:13
Answer: B
40% of Ram's marks is equal to 20% of Rahim's marks which percent is equal to 30% of Robert's marks. If Robert's marks is 80, then find the average marks of Ram and Rahim?	Choose the correct choice from the following answers:
A) 93
B) 77
C) 68
D) 90
E) 62

Solution: Given, 40% of Ram's marks = 20% of Rahim's marks = 30% of Robert's marks.   Given, marks of Robert = 80   30% of 80 = 30/100 * 8 = 24   Given, 40% of Ram's marks = 24.   => Ram's marks = (24 * 100)/40= 
(24 * 100)/40 = 60
60   Also, 20% of Rahim's marks= 24   => Rahim's marks = (24 * 100)/20= 
(24 * 100)/20 = 120
120   Average marks of Ram and Rahim= (60 + 120)/2= 
(60 + 120)/2 = 90
90.   Answer:90
Answer: D
In a shower, 4 cm of rain falls. The volume of water that falls on 1.5 hectares of ground is:  Choose the correct choice from the following
A) 75 cu. m	B) 600 cu. m	C) 750 cu. m	D) 6000 cu. m	E) 7.50 cu. m

Solution: 1 hectare = 10000 sq mtr   The volume of water that falls on 1.5 hectares of ground = 0.04*1.5*10000= 
0.04*1.5*10000 = 600
600 cub mtr .   ANSWER:600 cu. m
Answer: B
One fourth of a solution that was 10 percent sugar by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight. The second solution was what percent sugar by weight ? Choose the correct choice from the following answers
A) 34% B) 24% C) 22% D) 18% E) 8.5%

Solution: Let the original solution be 100 ml   It had 10ml of sugar   1/4 of this solution is removed   sugar remaining = 7.5 ML   25 ml of x% solution is added.   New volume of sugar = 7.5+25*x/100   Since resulting solution is 16% sugar by weight, volume of sugar = 16ml   equating the 2   x=(16-7.5)*4= 
(16-7.5)*4 = 34
34   34%NSWER:34%
Answer: A
What do you get if you add 5 to 500 five times?  Choose the correct choice from the following answers:	A) 305	B) 510	C) 320	D) 505	E) 509

Solution: 505   505 , 505 , 505 , 505 , 505
Answer: D
A man spends 10% of his income in house rent, 20% of the rest on his childrenâ€™s education, 25% of the rest miscellaneous causes. If he now posses Rs. 1944 then his income is?
Choices.
A) 3600  B) 5500  C) 5000  D) 4000  E) 2000

Solution: X * (90/100) * (80/100) * (75/100) = 1944   X * 0.9 * 0.8 * 0.75   X = 1944/0.54= 
1944/0.54 = 3_600
3600   3600NSWER 3600
Answer: A
A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years. Pick one:
A) Rs.3128
B) Rs.3120
C) Rs.3122
D) Rs.3121
E) Rs.3122

Solution: Explanation:   Let A be the amount received at the end of the three years.   A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]   A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)   A = Rs.7920   So the interest = 7920 - 4800 = Rs.3120   Answer: Rs.3120
Answer: B
P and Q began business with Rs.6000 and Rs.9000 after 4 months, P withdraws Rs.2000 and B advances Rs.3000 more.
At the end of the year, their profits amounted to Rs.1175 find the share of Q.
Options:
A) 800  B) 625  C) 825  D) 725  E) 850

Solution: (6*4 + 4*8):(9*4 + 12*8)   14 : 33   33/47 * 1175= 
33/47 * 1175 = 825
825.Answer:825
Answer: C
If C is the temperature in degrees Celsins and F is the temperature in degrees Fahrenheit, then the relationship between temperatures on the two scales is expressed by the equation 9C=5(F-32). On a day when the temperature extremes recorded at two different cities differed by 55 degrees on the Fahrenheit scale, by how many degrees did the temperature extremes differ on the Celsius scale?
Choose the correct choice from the following options
A) a) 65/9
B) b) 13
C) c) 28
D) d) 45
E) e) 81

Solution: The relationship is 9/5 - 32, so approximately half of difference in Celsius (the -32 part won't be used in this case).   Just looking at the answer choices you can pick C which is the only number near half of 55. The other answer choices are too far apart so no need to calculate.
Answer: C
If 20 ounces of a strong vinegar solution are diluted with 40 ounces of water to form a five-percent vinegar solution, what was the concentration of the original solution?  Select:
A) 8%
B) 10%
C) 12%
D) 15%
E) 18%

Solution: Let x be the concentration of the original solution.   20x = 0.05(60)   x = 0.15   The answer is 15%.
Answer: D
A basket has 6 apples and 4 oranges. Three fruits are picked at random. What is the probability that at least 2 apples are picked?	Choose one:	A) 1/2	B) 1/3	C) 2/3	D) 2/5	E) 3/5

Solution: The total possible choices are 102/33 = 120   The ways to choose 3 apples: 62/33 = 20   The ways to choose 2 apples: 62/32 * 42/31 = 60   P(at least 2 apples) = 80/120 = 2/3   The answer is 2/3.
Answer: C
In a ratio which is equal to 3:4, if the antecedent is 12, then the consequent is?	Answers:
A) 12  B) 16  C) 20  D) 22  E) 25

Solution: We have 3/4 = 12/x   3x = 48   x = 16   consequent = 16   Answer is 16
Answer: B
There are two positive numbers in the ratio 5:8. If the larger number exceeds the smaller by 27, then find the smaller number?	Choose the correct choice from the following answers
A) 25	B) 66	C) 45	D) 88	E) 44

Solution: Let the two positive numbers be 5x and 8x respectively.   8x - 5x = 27   3x = 27 => x = 9   => Smaller number = 5x = 45.   Answer: 45
Answer: C
Gordon buys 5 dolls for his 5 nieces. The gifts include two identical S beach dolls, one E, one G, one T doll. If the youngest niece doesn't want the G doll, in how many different ways can he give the gifts
Answers.
A) 24	B) 48	C) 72	D) 96	E) 120

Solution: Total # of ways to distribute SSEGT among 5 sisters (without restriction) is 5!2!=605!2!=60;   The # of ways when the youngest niece gets G is: 4!2!=124!2!=12 (give G to youngest and then distribute SSET among 4 sisters).   So, # of ways when youngest niece doesn't get G is: 60−12=4860−12=48.   Answer: 48.   ANSWER:48
Answer: B
There are two tanks a and b. A drains water with 6L/m and b drains water with 8L/m. A starts drain water at 9:00 and after 2 minute, b starts draining of water. At what time, both with have same level.
Choose the correct choice from the following answers:
A) 9:12	B) 9:10	C) 9:08	D) 9:04	E) 9:06

Solution: 9:01 --- 6 L   9:02 --- 12 L   from 9:03 onwards --------18,24,30,36,42,48,54,60   B =>   from 9:03 onwards -------- 8,16,24,32,40,48,56,64   at 9:08 both A & B have same level (48 L)   ANSWER:9:08
Answer: C
Q is the set of the first n positive odd numbers, where n is a positive integer. Given that n > k, where k is also a positive integer, x is the maximum value of the sum of k distinct members of Q, and y is the minimum value of the sum of k distinct members of Q, what is x + y?
Choose the correct choice from the following
A) kn	B) kn + k^2	C) kn + 2k^2	D) 2kn – k^2	E) 2kn

Solution: Probably the easiest way to solve this question would be to assume some values for n and k.   Say n=3, so Q, the set of the first n positive odd numbers would be: Q={1, 3, 5};   Say k=1, so X, the maximum value of the sum of K distinct members of Q would simply be 5. Similarly, Y, the minimum value of the sum of K distinct members of Q would simply be 1.   X+Y=5+1= 
5+1 = 6
6.   Now, substitute n=3 and k=1 in the options provided to see which one yields 6. Only asnwer choice E fits: 2kn=2*3*1= 
2*3*1 = 6
6.   Answer: 2kn.
Answer: E
In an examination 35% of the students passed and 481 failed. How many students appeared for the examination?
Select the correct option:
A) A)540	B) B)400	C) C)700	D) D)740	E) E)840

Solution: Let the number of students appeared be x   then, 65% of x = 481   65x/100 = 481   x = 481*100/65= 
481*100/65 = 740
740   Answer is 740
Answer: D
In right triangle ABC, AC is the hypotenuse. If AC is 35 and AB + BC = 55, what is the area of the triangle ABC?
Choose the correct choice from the following.
A) 225
B) 450
C) 25√2
D) 200
E) 200√2

Solution: Square AB + BC = 55:   (AB)^2 + 2*AB*BC + (BC)^2 = 3025. Since (AC)^2 = (AB)^2 + (BC)^2 = 35^2 = 1225, then (AB)^2 + 2*AB*BC + (BC)^2 = 1225 + 2*AB*BC = 3025.   1225 + 2*AB*BC = 3025.   AB*BC = 900.   The area = 1/2*AB*BC = 450.   Answer: 450.
Answer: B
Due to construction, the speed limit along an 6-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ?	Choose the correct choice from the following answers
A) 4	B) 8	C) 10	D) 15	E) 24

Solution: 6/35 - 6/55 = 6/5 * ( 11 - 7)/77   = 6/5 * 4/77 * 60 min   = 6 * 12 * 4/77   = 288/77 ~ 3.7   4nswer - 4
Answer: A
In how many different orders can the people Alice, Benjamin, Charlene, David, Elaine, Frederick, Gale, and Harold be standing on line if each of Alice, Benjamin, Charlene must be on the line before each of Elaine, Gale, and Harold?	Choose the correct choice.
A) 1,008
B) 2016
C) 1,512
D) 2,018
E) 2,268

Solution: Place D and F first: 8 options for D, 7 options for F   We are left with 6 empty places. A, B and C must take first 3 places and F, G, H must take the remaining three. A, B and C can be arranged in their places in 3! ways. The same for E, G, and H.   Total = 8*7*3!*3! = 2,016.   Answer: 2016
Answer: B
A room is 30 m long and 24 m broad. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, the volume of the hall is:
Answers:	A) 9.6 m3	B) 96 m3	C) 960 m3	D) 9600 m3	E) 96000 m3

Solution: Let the height be H   2(30+24) x H – 2(30-24)   H=(2(30x24))/(2(30+24)) = (30x24)/54 = 40/3 m   Volume = 30x24x40/3 = 9600 m3   answer :9600 m3
Answer: D
If the cost price of 60 articles is equal to the selling price of 40 articles, then what is the percent profit?  Choose the correct choice from the following options: A) 30% B) 40% C) 50% D) 60% E) 70%

Solution: Let x be the cost price of one article.   Let y be the selling price of one article.   40y = 60x   y = 1.5x   The answer is 50%.
Answer: C
The average of 50 numbers is 30. If two numbers, 35 and 40 are discarded, then the average of the remaining numbers is nearly Choose the correct choice from the following answers:
A) 28.32 B) 28.78 C) 29.27 D) 29.68 E) None

Solution: Solution   Sum of 50 numbers	= 30 x 50   = 1500.   Sum of remaining 48 numbers	= 1500 - (35+40)= 
1500 - (35+40) = 1_425
1425.   ∴ Required average= (1425 / 48)   = 475 / 16.   = 29.68.   Answer 29.68
Answer: D
In a partnership between A, B and C. A's capital is Rs.5000. If his share of a profit of Rs.900 is Rs.200 and C's share is Rs.130, what is B's capital? Options.
A) 19878
B) 14250
C) 26908
D) 11750
E) 22073

Solution: 200 + 130= 
200 + 130 = 330
330   900 - 330= 
900 - 330 = 570
570   200 ---- 5000   570 ---- ?=> 14250   Answer: 14250
Answer: B
The value of 5 in the number 357.21 is
Choices: A) 5 ones B) 5 twenty C) 5 tens D) 5 hundreds E) none of the above

Solution: Ans is 5 tens   The number 357.21 consists of: 3 hundreds, 5 tens, 7 ones, 2 tenths and 1 hundredth =>the value of 5 in 357.21	is 5 tens
Answer: C
A WORKS TWICE AS FAST AS B. IF B CAN COMPLETE A WORK IN 6 DAYS INDEPENDENTLY, THE NUMBER OF DAYS IN WHICH A AND B CAN TOGETHER FINISH THE WORK IS:	Choose the correct choice from the following answers
A) 3/4 DAYS  B) 2/1 DAYS  C) 4/3 DAYS  D) 3/2 DAYS  E) 1/2 DAYS

Solution: RATIO OF RATES OF WORKING OF A AND B = 2:1. SO, RATIO OF TIME TAKEN = 1:2   A'S 1 DAY'S WORK = 1/3, B'S 1 DAY'S WORK = 1/6   (A+B)'S 1 DAY'S WORK = (1/3+1/6)=1/2=1/2   SO, A AND B TOGETHER CAN FINISH THE WORK IN 1/2 DAYS.   CORR1/2 DAYSCT OPTION: 1/2 DAYS
Answer: E
Y and Z walk around a circular track. They start at 5 a.m from the same point in the opposite directions. Y and Z walk at a speed of 3 rounds per hour and 4 rounds per hour respectively. How many times shall they cross each other before 7 a.m  Options: A) 14 B) 15 C) 16 D) 17 E) 18

Solution: 18xplanation:   Relative speed = (3+4) =9 rounds per hour   So, they cross each other 9 times in an hour hence, they cross 18 times before 7 a.m   Answer: Option 18
Answer: E
If p is a positive integer and 10p/96 is an integer, then the minimum number of unique prime factors p could have is Q:
Choose the correct choice from the following choices:
A) Q=1  B) Q=2  C) Q=3  D) Q=4  E) Q=5

Solution: 10p/96 should resolve to a integer => 5p/48 should resolve to an integer.   Hence p/48 should resolve to a integer.   48 -- > 2^4 * 3.   Hence p should have atleast 2^4*3 for p/48 to resolve to a int.   The unique prime factors in 2^4 * 3 is 2, 3 and hence the answer is Q=2(2).
Answer: B
The boat moves downside 50km and upside 10km in 2 hours each. Then find the boat speed in still water?  Choose the correct option
A) 10km/hr	B) 15km/hr	C) 20km/hr	D) 25km/hr	E) 30km/hr

Solution: Down stream = 50/2= 
50/2 = 25
25km/hr   Up stream= 10/2= 
10/2 = 5
5km/hr   speed of boat in still water= 30/2= 
30/2 = 15
15km/hr   Answer is 15km/hr
Answer: B
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:  Choices
A) 12  B) 27  C) 26  D) 11  E) 99

Solution: Explanation:   Let the ten's digit be x and unit's digit be y.   Then, number 10x + y.   Number obtained by interchanging the digits = 10y + x.   (10x + y) + (10y + x) = 11(x + y)   which is divisible by 11.   Answer: 11
Answer: D
if q=0 and k = qr/2 -s, then what is r in terms of k,q,s?	Choose the correct answer.
A) 2k+s/q
B) 2sk/q
C) 2(k-s)/q
D) 2k+sq/q
E) 2(k+s)/q

Solution: k+s=qr/2   2(k+s)=qr   r=2(k+s)/q   ANSW2(k+s)/qR:2(k+s)/q
Answer: E
If k, (k+200), (k+350), and 15*K are all multiples of F, then F could equal which of the following ?
Choose the correct choice from the following answers
A) 20 B) F=25 C) 75 D) 100 E) 150

Solution: {Multiple of F} - {Multiple of F} = {Multiple of F}.   (K+200) - k = 200 = {Multiple of F}.   (K+350) - k = 350 = {Multiple of F}.   Both 200 and 350 are multiples of only option B.   Answer: F=25.
Answer: B
A sum of money is to be distributed among P, Q, and R in the ratio 6:19:7. If R gives Rs. 200 from his share to Q, the ratio of P, Q and R becomes 3:10:3, what is the total sum?	Choose the correct choice from the following answers.
A) Rs. 4800  B) Rs. 12800  C) Rs. 3200  D) Rs. 7200  E) data inadequate

Solution: Explanation:   Let the shares of P, Q and R be 6x, 19x and 7x.   By given condition, R’s new share = 7x – 200   Q’s new share = 19x + 200   New ratio = 6x :19x +200:7x-200=3:10:3   P : R = 6x :7x -200=3 :3   6x=7x-200   x=200   Total sum 6x + 19x + 7x = 32x  6  + 19  + 7= 
 6  + 19  + 7 = 32
32x= Rs. 4800   Rs. 4800nswer: Rs. 4800
Answer: A
The average weight of 25 persons sitting in a boat had some value. A new person added to them whose weight was 46 kg only. Due to his arrival, the average weight of all the persons decreased by 5 kg. Find the average weight of first 25 persons?  Pick one:
A) 288
B) 278
C) 297
D) 176
E) 267

Solution: 25x + 46 = 26(x – 5)   x = 176   Answer: 176
Answer: D
An army’s recruitment process included N rounds of selection tasks. For the first A rounds, the rejection percentage was 60 percent per round. For the next B rounds, the rejection percentage was 50 percent per round and for the remaining rounds, the selection percentage was 70 percent per round. If there were 100000 people who applied for the army and 1400 were finally selected, what was the value of N? Choose the correct choice from the following answers.
A) 4  B) 5  C) 6  D) 8  E) 10

Solution: Since 70% is accepted and figure will be 1400 therefore in last stage tested/interviewed no. candidates should be 2000   So from here i will work for those two steps of decrements of 100000 candidates.   fastly i reduce 60% till it gets closer to our required 2000 candidates   step(1) 40000 accepted.   step(2) another 40%of 40000=16000 accepted.   here it is quiet observable that if we further deduct candidate by 60% it would change our probablity of easy going 2000 candidate.   so i would get to second stage of recruitment where 50 % is accepted   step(3) 50% of 16000=8000   step(4) 50% of 8000=4000   Step(5) 50% of 4000=2000...here we are done with total 5 steps   and last step of accepting 70% of 2000=1400(our target)   total 6 steps required.   Answer: 6
Answer: C
If x=-3, which of the following is(are) true? I. x^2=-|x| II |x|=-x III x/-3 = -1  Select
A) II, III only	B) II only	C) I,II only	D) I only	E) III only

Solution: I. x^2=-|x| -3^2 = - |-3| Not true   II |x|=-x |-3| =-( -3 ) true   III x/-3 = -1 Not true   Answer : II only
Answer: B
A bag contains 4 black, 5 yellow and 6 green balls. Three balls are drawn at random from the bag. What is the probability that all of them are yellow?  Pick:
A) 2/81
B) 2/91
C) 1/81
D) 1/91
E) 1/51

Solution: Total number of balls = 4 + 5 + 6= 
4 + 5 + 6 = 15
15   n(S)= tot no of ways of drawing 3 balls out of 15 =15c3   let E = event of drawing 3 balls   n(E) = no of ways of drawing 3 balls   = no of ways of drawing 3 balls from the total 5 = 5c3   =>(5*4/2*1)/(15*14*13/3*2*1)=2/91   ANSWER 2/91
Answer: B
A trucking company plans to gradually replace their older fleet of trucks with newer more energy efficient ones. Every year it plans to retire 6 trucks and buy 8 newer ones. How many years starting from 2005 will it take to reduce its fleet of 40 old trucks to less than half its fleet?
Choose the correct answer.
A) 8	B) 2	C) 5	D) 6	E) 3

Solution: Total fleet--40   End of year 2005 -- (retires 6 and buys 8) total fleet--42(34 old 8 new).   End of year 2006 -- (retires 6 and buys 8) total fleet--44(28 old 16 new).   End of year 2007 -- (retires 6 and buys 8) total fleet--46(22 old 24 new).   Answer is 3--after 3 years the company has a total of 56 taxis (20 old 36 new), the old taxis are already less than 50% of its fleet.
Answer: E
A pack of baseball cards consists of 12 outfielder cards and 8 infielder cards. What is the lowest number of outfielder cards that would have to be removed from the pack so that no more than 35 percent of the pack would be outfielder cards?
Choose the most appropriate option:
A) 4 B) 5 C) 6 D) 7 E) 8

Solution: let the number of O card to be removed=X   then remaning cards=12-X   now this 12-X cards should count less than 35% of toatal Ocards   12-X<.35*12   X>12-4.2   X>7.8   X=8   Ans 8
Answer: E
A can do a piece of work in 4 days. B can do it in 15 days. With the assistance of C they completed the work in 24 days. Find in how many days can C alone do it?	Answers
A) 0.391 days  B) 0.491 days  C) 0.331 days  D) 1.391 days  E) 0.301 days

Solution: C = 1/2 - 1/24 - 1/15 = 0.391 days   0.391 daysNSWER:0.391 days
Answer: A
what is the compound interest on rs:70,000 for 4 months at the rate of 5% per annum	Select the correct option:  A) 1171.98  B) 1172.98  C) 1173.98  D) 1174.98  E) 1175.98

Solution: it is monthly compound   rate=5/12% per month   70000*(1+5/1200)^4-70000=1173.98   ANSWER:1173.98
Answer: C
A bus trip of 660 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?
Choose the correct choice.
A) 40	B) 45	C) 50	D) 55	E) 60

Solution: The time is the distance/speed. The time difference is 1 hour.   660/V - 660/(V+5) = 1   660(V+5) - 660V = (V)(V+5)   3300 = (V)(V+5)   55*60 = (V)(V+5)   V = 55 mph   The answer is 55.
Answer: D
A worker's daily wage is increased by 50% and the new wage is $51 per day. What was the worker's daily wage before the increase?  Select the correct option:
A) $28	B) $32	C) $34	D) $35	E) $40

Solution: Let x be the daily wage before the increase.   1.5x = $51   x = $34   The answer is $34.
Answer: C
A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its average monthly production for that year? Pick one.
A) 5578	B) 5552	C) 5550	D) 5528	E) 5598

Solution: Total production of salt by the company in that year   = 5000 + 5100 + 5200 + .... + 6100   = 66600.   Average monthly production of salt for that year   = 66600/12= 
66600/12 = 5_550
5550.   Answer:5550
Answer: C