MU-NLPC/Calc-aqua_rat huggingface dataset:
Shipment --- No. of Defective Chips/shipment --- Total Chips in shipment
S1 ---------------------- 3 ------------------------------------------ 8,000
S2 ---------------------- 5 ------------------- ---------------------- 12,000
S3 ---------------------- 6 ------------------------------------------ 18,000
S4 ---------------------- 4 ------------------------------------------ 16,000
A computer chip manufacturer expects the ratio of the number of defective chips to the total number of chips in all future shipments to equal the corresponding ratio for shipments S1, S2, S3, and S4 combined, as shown in the table above. What’s the expected number of defective chips in a shipment of 60,000 chips?	Choose the correct choice from the following answers
A) 14	B) 22	C) 20	D) 24	E) 25

Solution: for a total of 51000 chips (adding S1,S2,S3,S4) total number of defective chips is 17 ((adding defective chips of S1,S2,S3,S4) so ratio is 18/54000 or 1 every 3000 chips.   Keeping this ratio constant for 60000 chips number of defective chips will be   (1/3000) * 60000= 
  (1/3000) * 60000 = 20
20   20
Answer: C
I. All the offices on the 9th floor have wall-to-wall carpeting.
II. No wall-to-wall carpeting is pink.
III.None of the offices on the 9th floor has pink wall-to-wall carpeting.
If the first two statements are true, the third statement is
Choose the correct choice from the following
A) true B) false C) uncertain D) none E) 223

Solution: Explanation:   If no wall-to-wall carpeting is pink and all the offices have wall-to-wall carpeting, none of the offices has pink wall-to-wall carpeting.   truenswer: true) true
Answer: A
If d and y are positive integer and d/y is an even integer, which of the following can be an odd integer?  Pick
A) x	B) xy	C) x−y	D) x+2y	E) d/3

Solution: C d-Y   Let says d =12 Y=3 iT BECOMES d-Y =9 This is odd True   d = 12 Y = 6 THEN d-Y = 2, Which is even hence this is False.   so both Yes and NO situations are exists for this Option. C can't be the correct answer same logic goes for E. I believe this question is incomplete b'coz of Irrelevant Options.
Answer: E
The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is?  Choose the correct option:
A) Rs.4007	B) Rs.4000	C) Rs.4028	D) Rs.4050	E) Rs.4032

Solution: Let P, Q and R represent their respective monthly incomes. Then, we have:   P + Q = (5050 * 2)= 
(5050 * 2) = 10_100
10100 --- (i)   Q + R= (6250 * 2)= 
(6250 * 2) = 12_500
12500 --- (ii)   P + R= (5200 * 2)= 
(5200 * 2) = 10_400
10400 --- (iii)   Adding (i), (ii) and (iii), we get:   2(P + Q + R)= 33000 = P + Q + R = 16500 --- (iv)   Subtracting (ii) from (iv), we get, P = 4000.   P's monthly income = Rs. 4000.   Answer:Rs.4000
Answer: B
If r is even and t is odd, which of the following is odd r or t?	Choose one.
A) rt  B) 6rt  C) 6(r^2)t  D) 6r + 5t  E) 5r + 6t

Solution: Just checking options (In case you have difficulty then choose values of r=2 and t=1)   r = even   t= Odd   A. rt = Even*Odd = EvenINCORRECT   B. 5rt = Odd*Even*Odd = EvenINCORRECT   C. 6(r^2)t = 6*(Even^2)*Odd = EvenINCORRECT   E. 5r + 6t = 5*Even + 6*Odd = Even+Even = EvenINCORRECT   D. 6r + 5t = 6*5r + 6tven + 5*Odd = 5r + 6tven+Odd = OddCORR5r + 6tCT   Answer: option 5r + 6t
Answer: E
If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 54kmh, what was the average speed of the car for the entire trip?  Choose one.
A) 36 kmh	B) 40 kmh	C) 41 kmh	D) 44 kmh	E) 50 kmh

Solution: Assume D/3 = 2160 (this number is convenient because it is divisible by 80, 24 and 54)   So:   2160 = 80*T1 = 27 hrs   2160 = 24*T2 = 90 hrs   2160 = 54*T3 = 40 hrs   T = T1 + T2 + T3 = 157 hrs   D = RT   (240*3) = R*157   R = 41.27   ANSWER: 41 kmh
Answer: C
If p and n are positive integers, with p > n, what is the average of n consecutive multiples of p (starting with p), less the average of p consecutive multiples of n (starting with n)?  Choose one.
A) (p + n)/2 B) (p – n)/2 C) p + n D) p – n E) p^2 – n^2

Solution: Let, n = 2   and p = 3   i.e. Average of 2 (n) consecutive multiples of 3 (p) starting from 3 (p) = (3+6)/2 = 9/2   and Average of 3 (p) consecutive multiples of 2 (n) starting from 2 (n) = (2+4+6)/3 = 12/3= 
12/3 = 4
4   The average of n consecutive multiples of p (starting with p), less the average of p consecutive multiples of n (starting with n)= (9/2)-4 = (1/2)   A. (p + n)/2 = (3+2)/2 = 7/2 INCORRECT   B. (p – n)/2 = (3-2)/2 = 1/2 CORRECT   C. p + n = (3+2) = 7 INCORRECT   D. p – n = (3-2)= 
(3-2) = 1
1 INCORRECT   E. p^2 – n^2= 3^2 - 2^2 = 5 INCORRECT   Answer: option (p – n)/2
Answer: B
Kim bought a total of $2.95 worth of postage stamps in four denominations. If she bought an equal number of 5-cent and 25-cent stamps and twice as many 10-cent stamps as 5-cent stamps, what is the least number of 1-cent stamps she could have bought?
Select the correct option:
A) 5  B) 10  C) 15  D) 20  E) 45

Solution: Let:   # of 5 and 25 cents stamps = n   # of 10 cent stamps = 2n   # of 1 cent stamps = m   Therefore:   5n + 25n + 10(2n) + m = 295 cents   50n + m = 295   Forleastnumber of 1 cents stamps, maximize 50n. Hence,   50*5 + m = 295   m = 45 i.e. 45 stamps 1 cents each   Answer: 45
Answer: E
Sripad has scored average of 65 marks in three objects. In no subjects has he secured less than 58 marks. He has secured more marks in Maths than other two subjects. What could be his maximum score in Maths ?  Pick.
A) 79  B) 47  C) 29  D) 27  E) 19

Solution: Explanation:   Assuming Sripad has scored the least marks in subject other than science,   Then the marks he could secure in other two are 58 each.   Since the average mark of all the 3 subject is 65.   i.e (58+58+x)/3 = 65   116 + x = 195   x = 79 marks.   Therefore, the maximum marks he can score in maths is 79.   79nswer: 79
Answer: A
Awordis defined as a sequence of four dots arranged in a row. Each dot is colored either red or blue. How many distinct words can be formed? Choose the correct choice from the following.
A) 16	B) 15	C) 6	D) 18	E) 9

Solution: Each dot can be either yellow or blue, so 2 options for each dot:   2*2*2*2= 
  2*2*2*2 = 16
16.   16nswer: 16.
Answer: A
A man can row 6 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and black. What is the total distance traveled by the man? Pick:  A) 5.76  B) 5.78  C) 5.76  D) 5.75  E) 5.71

Solution: M = 6   S = 1.2   DS = 7.2   US = 4.8   x/7.2 + x/4.8 = 1   x = 2.88   D = 2.88 * 2= 
2.88 * 2 = 5.76
5.76   Answer: 5.76
Answer: C
A man purchases 2 watches for $ 520. He sells one at 15% profit and the other at a loss of 10%. He neither gains nor loses on the whole. Thus, the cost price of two watches are :	Choose the correct choice from the following answers: A) $ 208 and $ 312 B) $210 and $ 350 C) $224 and $336 D) $560 and $560 E) $224 and $ 350

Solution: x + y = 520 --- (1)   1.15x + 0.9y = 520 --- (2)   (2) - (1) --> 0.15x - 0.1y = 0   15x = 10y   x/y = 2/3 = (2*104)/(3*104) = 208/312   $ 208 and $ 312nswer: $ 208 and $ 312
Answer: A
If p and q are positive integers each greater than 1, and 17(p+1)=21(q+1), what is the least possible value of p+q?  Choose the correct choice from the following choices:
A) 36  B) 42  C) 44  D) 46  E) none

Solution: 17(p+1)=21(q+1) --> (p+1)/(q+1) = 21/17 --> the least positive value of p+1 is 21, so the least value of p is 20 and the least positive value of q+1 is 17, so the least value of q is 16 --> the least value of p+q is   20+16= 
  20+16 = 36
36.   36nswer: 36.
Answer: A
The roof of an apartment building is rectangular and its length is 3 times longer than its width. If the area of the roof is 675 feet squared, what is the difference between the length and the width of the roof? Select the correct option:
A) 38. B) 30. C) 42. D) 44. E) 46.

Solution: Let the width= x   x*3x=675   x^2= 225   x= 15   Length= 3*15= 
3*15 = 45
45   difference= 45-15= 
45-15 = 30
30   30. is the answer
Answer: B
If a, b, and c are integers and a*b^2/c is a positive even integer, which of the following must be true?
I. c is even
II. ab > 2
III. ab is even	Choose the correct choice from the following answers:
A) I only  B) III only  C) I and II  D) I and III  E) I, II, and III

Solution: Two ways this can happen: 1- Even/ Even= Even or 2- Even/Odd= Even   So Ab MUST be even, with either A or B being even, Ab does not have to be positive, as B could be negative and once it is raised to 2 it becomes positive again, and of course, C could be Odd or Even as described above.   III only.letter III only
Answer: B
X and Y are integers, X is even and negative, Y is odd and positive. Which of the following could be false?
1. (X + Y) is an odd number.
2. Y^(X + Y) is an integer.
3. X^Y is a positive number.  Select
A) 2 only B) 3 only C) 1 and 3 only D) 2 and 3 only E) 1, 2 and 3

Solution: Using the properties for even and odd numbers along with positive and negatives,   1. (X + Y) is an odd number : even + odd is always a odd number, so eliminate 1   2. Y^(X + Y) is an integer. : an odd and positive number could be raised to power of either positive or negative, so not conclusive, eliminate 2   3. X^Y is a positive number. : a negative number raised to power of odd number is always negative.   Answer : 3 only
Answer: B
A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Answers.
A) 3	B) 4	C) 5	D) 7	E) 9

Solution: Area of the park = (60 x 40) m2 = 2400 m2.   Area of the lawn = 2109 m2.   Area of the crossroads = (2400 - 2109) m2 = 291 m2.   Let the width of the road be x metres. Then,   60x + 40x - x2 = 291   x2 - 100x + 291 = 0   (x - 97)(x - 3) = 0   x = 3   3)
Answer: A
What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 57?
Pick one:  A) 3944  B) 920  C) 7290  D) 3876  E) 3729

Solution: Explanation:   Let the side of the square plot be a ft.   a2 = 289 => a = 17   Length of the fence = Perimeter of the plot = 4a = 68 ft.   Cost of building the fence = 68 * 57 = Rs. 3876.   Answer: Option 3876
Answer: D
A can do a piece of work in 10 days and B can do it in 15 days and C can do it 20 days. They started the work together and A leaves after 2 days and B leaves after 4 days from the beginning. How long will work lost?	Choose the correct choice from the following choices:
A) 10 2/9
B) 10 2/6
C) 10 2/3
D) 10 2/2
E) 10 2/1

Solution: 2/10 + 4/15 + x/20 = 1   x = 32/3 = 10 2/3   Answer:10 2/3
Answer: C
16! is equal to which of the following?  Pick one
A) 20,922,789,888,321 B) 20,922,789,888,000 C) 20,922,789,888,525 D) 20,922,789,888,416 E) 20,922,789,888,928

Solution: After 4!, the units digit of every factorial is 0.   5!=120   6!=720   etc...   The answer is 20,922,789,888,000.
Answer: B
If a 3-member subcommittee is to be formed from a certain 7-member committee, how many different such subcommittee are possible? Pick
A) 6	B) 18	C) 35	D) 108	E) 216

Solution: 1st member can be selected in 7 ways   2nd can be selected in 6 ways   3rd can be selected in 5 ways   So total ways : 210   But to avoid the similar scenarios 210/3!=35   ANS:35
Answer: C
Which of the following expressions CANNOT have a negative value	Options:
A) |a + b| – |a – b|	B) |a + b| – |a|	C) |2a + b| + |a + b|	D) a^2 - b^2 – 2|ab|	E) |a^3 + b^3| – a – b

Solution: Whenever you are required to find if the equation is a perfect square or not, try to bring everything in the form of a perfect square as they are always positive.   Of the given options, only option D can be written in from of a perfect square.   |2a + b| + |a + b|   This will always be positive.   |2a + b| + |a + b|orrect Option: |2a + b| + |a + b|
Answer: C
The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is: Pick one
A) 3500
B) 4000
C) 4050
D) 5000
E) None

Solution: EXPLANATION   Let P, Q and R represent their respective monthly incomes. Then, we have:   P + Q = (5050 x 2) = 10100 …. (i)   Q + R = (6250 x 2) = 12500 …. (ii)   P + R = (5200 x 2) = 10400 …. (iii)   Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 …. (iv)   Subtracting (ii) from (iv), we get P = 4000.   P’s monthly income = Rs. 4000.   Answer 4000
Answer: B
P can do a work in 24 days. Q can do the samework in 9 days & R can do the same work in 12 days. Q & R start the work and leave after 3 days. P finishes the remaining work in how many days.	Choices.
A) 8  B) 10  C) 14  D) 16  E) 19

Solution: Work done by P in 1 day = 1/24   Work done by Q in 1 day = 1/9   Work done by R in 1 day = 1/12   Work done by Q and R in 1 day = 1/9 + 1/12 = 7/36   Work done by Q and R in 3 days = 3×7/36 = 7/12   Remaining work = 1 – 7/12 = 5/12   Number of days in which P can finish the remaining work = (5/12) / (1/24)= 
(5/12) / (1/24) = 10
10   10
Answer: B
Two trains of length 120 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet?  Choose the correct choice from the following answers:
A) 18 sec  B) 70 sec  C) 21 sec  D) 20 sec  E) 19 sec

Solution: Relative speed = (42 + 30) * 5/18 = 4 * 5= 
4 * 5 = 20
20 mps.   Distance covered in passing each other= 120 + 280= 
120 + 280 = 400
400 m.   The time required= d/s   = 400/20= 
400/20 = 20
20 sec.   Answer: 20 sec
Answer: D
4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 10 mat-weavers in 10 days?
Choose the most appropriate option
A) 25 B) 19 C) 39 D) 61 E) 16

Solution: Let the required number of bottles be x.   More weavers, More mats (Direct Proportion)   More days, More mats (Direct Proportion)   Wavers	4	:	10 :: 4 : x   Days	4:10   4 * 4 * x = 10 * 10 * 4   x =	(10 * 10 * 4)/(4 x 4)   x = 25.   25nswer is 25.
Answer: A
A grocer wants to arrange 13 fruits in a line among which 3 are mangoes, 4 are apples, 2 are oranges, 1 pineapple and remaining are guavas. In how many different ways can he do so, if fruits of one kind are identical?	Options
A) 13!/{(2!)(3!^2)(4!)}
B) 13!/{(2!)(3!^2)}
C) 13!/{(2!)(4!)}
D) 13!
E) 13!/(3!^2)

Solution: The total number of ways in which a total N items, out of which p are identical of one type, q are identical of another type and rest are different, can be arranged in a line is N!/{p!q!}   Here we have 13 fruits out of which there are 3 alike mangoes, 4 alike apples, 2 alike oranges, 3 alike guavas and 1 pineapple.   Hence the number of ways in which he can arrange these in a line are 13!/(3!4!2!3!) = 13!/{(2!)(3!^2)(4!)}   13!/{(2!)(3!^2)(4!)}ns 13!/{(2!)(3!^2)(4!)}
Answer: A
In how many ways 6 persons can be formed from 8 men and 7 women? Choices.
A) 5005 B) 6452 C) 4516 D) 2313 E) 3564

Solution: Total number of persons = 15   Required number of ways = 15C6 = 5005   5005nswer is 5005
Answer: A
At a certain college there are twice as many Economics majors as history majors and three times as many Economics majors as mathematics majors. What is the ratio of the number of history majors to the number of mathematics majors?
Choose the correct choice from the following answers.
A) 6 to 1 B) 6 to 4 C) 2 to 3 D) 1 to 5 E) 1 to 6

Solution: This is how I translated the question:   At a certain college there are twice as many economics majors as history majors   E = 2H   and three times as many economics majors as mathematics majors.   E = 3M   What is the ratio of the number of history majors to the number of mathematics majors?   What is H:M?   Just set E equal to each other to get the ratio in terms of H and M.   2H = 3M   H/M = 3/2   The answer is 6:4   Answer : 6 to 4
Answer: B
Simplify: 6005-6000+10  Choose the correct choice.
A) 4505
B) 4509
C) 5405
D) 4508
E) None of them

Solution: 6005-6000+10   =6005-(6000/10)   =6005-600= 
6005-600 = 5_405
5405.   Answer is 5405
Answer: C
The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than A
Choose one.
A) A)11 B) B)12 C) C)13 D) D)16 E) E)15

Solution: Explanation:   Given that A+B = 16 + B + C   => A – C = 16 + B – B = 16   => C is younger than A by 16 years   Answer: Option 16
Answer: D
If selling price of 12 pens is equal to the cost price of 18 pens, find the profit percent. Choose the correct option.
A) 40%
B) 33.3%
C) 50%
D) 25%
E) None of these

Solution: Explanation:   Selling price of 12 pens = cost price of 18 pens   Therefore, the profit is 6 pens and cost price is 12 pens.   % profit = profit/cost price * 100   = 6/12 * 100= 
6/12 * 100 = 50
50%   ANSWER 50%
Answer: C
Eggs are sold in packages of six or eleven only. If Doris bought 70 eggs exactly, what could be the number of large packs Doris bought?	Choose the correct choice
A) 6. B) 2. C) 3 D) 5. E) 4

Solution: Let number of packs of six = s   let number of packs of eleven = e   6s + 11e = 70   Now , we need to test for values of e .   Since sum 70 is even and 6s will always be even , e can't be odd .   Now , we can test for values e = 2 , 4 and 6   11*2 + 6*8 = 22 + 48= 
22 + 48 = 70
70   Answer 2.
Answer: B
If p and q are positive integers each greater than 1, and 17(p+1)=25(q+1), what is the least possible value of p+q?
Choose the correct choice from the following answers:  A) 36  B) 42  C) 40  D) 46  E) none

Solution: 17(p+1)=29(q+1) --> (p+1)/(q+1) = 29/17 --> the least positive value of p+1 is 25, so the least value of p is 24 and the least positive value of q+1 is 17, so the least value of q is 16 --> the least value of p+q is   24+16= 
  24+16 = 40
40.   Answer: 40.
Answer: C
The length of a rectangular field is 7/5 its width. If the perimeter of the field is 432 meters, what is the width of the field? Choose the correct answer
A) 50
B) 60
C) 70
D) 80
E) 90

Solution: Let L be the length and W be the width. L = (7/5)W   Perimeter: 2L + 2W = 432, 2(7/5)W + 2W = 432   Solve the above equation to find: W = 90 m and L = 126 m.   correct answer 90)90
Answer: E
In case N is the only individual sewing on committee B, which among the following shouldserve on committee A?  Choose the most appropriate option:
A) V and U
B) V and T
C) U and S
D) O and P
E) T and U

Solution: O and P should serve on A   ANSWER:O and P
Answer: D
What percent is 350 gm of 1 kg?	Choices:
A) 25%	B) 40%	C) 35%	D) 8%	E) 12%

Solution: 1 kg = 1000 gm   350/1000 Ã— 100 = 35000/1000= 
35000/1000 = 35
35 %   Answer is 35%
Answer: C
If in a certain sequence of consecutive multiples of 100, the median is 650, and the greatest term is 1000, how many terms that are smaller than 650 are there in the sequence? Choose the correct choice.
A) 6
B) 4
C) 8
D) 12
E) 13

Solution: Since the median is 650 we know there must be a even number of integers   So the list around 625 must go. 600 ( 650) 700 800 900 1000   Since we know there are 4 numbers greater than 650 then there must be 4 numbers less then 650.   4
Answer: B
Three bodies D, E and F start moving around a circular track of length 240m from the same point simultaneously in the same direction at speeds of 6 m/s, 10 m/s and 18 m/s respectively. When will they meet for the first time after they started moving?  Pick one
A) 120 seconds
B) 60 seconds
C) 30 seconds
D) 20 seconds
E) 50 seconds

Solution: If they all meet after T seconds, it means they covered the distances 6T, 10T, and 18T respectively.   Since they all arrive to the same spot, it means that the differences taken pairwise between the distances must be positive integer multiples of the length of the track, which is 240m. So, 4T, 8T, and 12T must all be multiples of 240. 4T multiple of 240 means T multiple of 60. The smallest T with this property is 60 and is on the list of answers.   Answer 60 seconds.
Answer: B
If a boat goes 7 km upstream in 42 minutes and the speed of the stream is 7 kmph, then the speed of the boat in still water is :
Choose one.
A) 2.5 km/hr
B) 4.5 km/hr
C) 5 km/hr
D) 10.5 km/hr
E) None of these

Solution: Solution   Speed of stream = 1/2 (17-8) km/hr= 4.5kmph . Answer 4.5 km/hr
Answer: B
A trader sells 80 meters of cloth for Rs. 9000 at the profit of Rs. 23.5 per metre of cloth. What is the cost price of one metre of cloth?
Choose the correct option.
A) 22	B) 89	C) 90	D) 78	E) 80

Solution: SP of 1m of cloth = 9000/80 = Rs. 112.5   CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth   = Rs. 112.5 - Rs. 23.5 = Rs. 89.   Answer: 89
Answer: B
A train sets off at 2 p.m. at the speed of 70 kmph. Another train starts at 3:30 p.m. in the same direction at the rate of 85 kmph. At what time the trains will meet?  Choose the correct option:	A) 10.39	B) 10.36	C) 10.3	D) 10.33	E) 10.31

Solution: D = 70 * 1 ½ = 105 km   RS = 85 – 70 = 15   T = 105/15= 
105/15 = 7
7 h     3.30 + 7= 
  3.30 + 7 = 10.3
10.30 p.m.   Answer: 10.3
Answer: C
55 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be :  Options.
A) 84 m  B) 88 m  C) 120 m  D) 70 m  E) None

Solution: Sol.   Let the length of the wire b h.   Radius = 1/2 mm = 1/20 cm. Then,   22/7 * 1/20 * 1/20 * h = 55 ⇔ = [55 * 20 * 20 * 7 / 22= 
55 * 20 * 20 * 7 / 22 = 7_000
7000cm= 70 m.   Answer 70 m
Answer: D
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?
Options
A) 1245	B) 1683	C) 1773	D) 1650	E) 1760

Solution: Explanation:   LCM of 5, 6, 7 and 8 = 840   Hence the number can be written in the form (840k + 3) which is divisible by 9.   If k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9.   If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9.   Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.   Answer: Option 1683
Answer: B
Solve 2x – 5 = 1  Options:
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: Sol.   2x – 5 = 1   => 2x = 1 + 5   => 2x = 6   => x = 3.   Answer : 3
Answer: C
A room is 4 meters 37 cm long and 3 meters 23cm broad. It is required to pave the floor with minimum square slabs. Find the number of slabs required for this purpose?	Pick.
A) 485 B) 431 C) 391 D) 381 E) 481

Solution: H391F of 323, 437 = 19   323 * 437 = 19 * 19 * x   x = 391   ANSWER:391
Answer: C
Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 40 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped?
Choose the correct choice
A) 205 B) 220 C) 240 D) 247 E) 294

Solution: Car Y began travelling after 72 minutes or 1.2 hours.   Let t be the time for which car Y travelled before it stopped.   Both cars stop when they have travelled the same distance.   So,   35(t+1.2) = 40t   t=8.4   Distance traveled by car X from the time car Y began traveling until both cars stopped is   35 x 8.4   = 294 miles   Answer:- 294
Answer: E
The guidelines at a certain college specify that for the introductory English class, the professor may choose one of six specified novels, and choose two plays from a list of 5 specified plays. Thus, the reading list for this introductory class has one novel and two plays. How many different reading lists could a professor create within these parameters?  Select:  A) 50  B) 55  C) 60  D) 65  E) 70

Solution: 6601*5602 = 6*10= 
6*10 = 60
60   The answer is 60.
Answer: C