MU-NLPC/Calc-aqua_rat huggingface dataset:
What least number must be subtracted from 42739 so that remaining no.is divisible by 15  Choose the correct choice from the following answers
A) 3  B) 4  C) 6  D) 8  E) 9

Solution: Explanation:   On dividing 42739 by 15 we get the remainder 4, so 4 should be subtracted   Option 4
Answer: B
A library branch originally contained 18360 volumes, 30% of which were fiction novels. 1/3 of the volumes were transferred to another location and 1/3 of the volumes transferred were fiction novels. What percent of the remaining collection was fiction novels?
Answers:
A) 2.5%
B) 17.67%
C) 28.3%
D) 45.2%
E) 73.6%

Solution: As everything is either fraction or percentage, the given figure 18360 is just a false alarm. We can do this by assuming that originally the branch had 100 volumes.   Originally:   Total- 100   Fiction- 30   Transferred:   Total- 33 (One third of original total)   Fiction- 11 (One third of those transferred)   Remaining:   Total- 100−33=67100−33=67   Fiction- 30−11=1930−11=19   To find:   19 is what percent of 67   28.3   Option 28.3%
Answer: C
From among the 34 students in a class, one leader and one class representative are to be appointed. In how many ways can this be done?	Choices
A) 1122
B) 1260
C) 1060
D) 1160
E) 1460

Solution: There are 34 students and every one has equal chance of being selected as a leader. Hence, the leader can be appointed in 34 ways. When one person is appointed as leader, we are left with 35 students. Out of these 33 teachers, we can select one class representative. So, a class representative can be selected in 33 ways. Hence, the number of ways in which a leader and class representative can be selected = 34 x 33= 1122   1122NSWER:1122
Answer: A
A rectangular grass field is 75 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? Choose the correct choice from the following answers:
A) 1350
B) 2987
C) 2369
D) 6989
E) 2982

Solution: 1350rea = (l + b +2d) 2d   = (75 + 55 +2.5 * 2) 2*2.5 => 675   675 * 2   = Rs.1350   1350nswer:1350
Answer: A
A store’s selling price of $2500 for a certain computer would yield a profit of 40 percent of the store’s cost for the computer. What selling price would yield a profit of 50 percent of the computer’s cost?
Choose the correct choice from the following answers:  A) $2678  B) $2464  C) $2650  D) $2732  E) $2800

Solution: 1.4x = 2500   x=2500/1.4   so, 1.5X = 2500*1.5/1.4= 2478   $2678nswer:- $2678
Answer: A
A wooden box of dimensions 8 m x 3 m x 6 m is to carry rectangularboxes of dimensions 8 cm x 3 cm x 2 cm. The maximum number ofboxes that can be carried in the wooden box, is
Choose the most appropriate option.
A) 9800000 B) 1000000 C) 7500000 D) 3000000 E) None of these

Solution: Explanation: Number = (800*300*600)/8*3*2 = 3000000 Answer: 3000000
Answer: D
What is the rate percent when the simple interest on Rs.800 amount to Rs.160 in 4 Years? Choose the correct choice from the following
A) 5%	B) 7%	C) 3%	D) 9%	E) 1%

Solution: 160   = (180*4*R)/100   R = 5%   5%nswer:5%
Answer: A
A pipe can fill a cistern in 20 minutes whereas the cistern when full can be emptied by a leak in 28 minutes. When both pipes are opened, find when the cistern will be full?	Choose the correct choice from the following answers:
A) 17 B) 16 C) 70 D) 13 E) 12

Solution: 1/20 - 1/28 = 1/70   70 minutes   Answer: 70
Answer: C
A large box contains 18 small boxes and each small box contains 28 chocolate bars. How many chocolate bars are in the large box?	Pick one:
A) A)220  B) B)490  C) C)380  D) D)450  E) E)504

Solution: the only thing you have to do is a simple multiply   we have:   18*28= 
18*28 = 504
504   correct answer is:   504) 504
Answer: E
Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ?
Choose one:
A) 91.5 B) 21.5 C) 61.5 D) 81.5 E) 11.5

Solution: Explanation:   Let the number of students in classes A, B and C be P, Q and R respectively.   Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.   Also given that,   (83P + 76Q) / (P + Q) = 79   =>4P = 3Q.   (76Q + 85R)/(Q + R) = 81   =>4R = 5Q,   =>Q = 4P/3 and R = 5P/3   Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12= 
978/12 = 163/2 = around 81.5
81.5   Answer: 81.5
Answer: D
If X = 2 + 1/(1+1/(1-1/2))then the value of 3x+7/3?  Select:
A) 9 1/3
B) 10 1/3
C) 11
D) 11 2/3
E) 12

Solution: X = 2 + 1/(1+1/(1-1/2))   = 2 + 1/(1+2)   = 2 + 1/3   X = 7/3 ==> 3X + 7/3 => 3(7/3) + 7/3   ==> 21/3 + 7/3   ==> 28/3   ==> 9 1/3.   9 1/3)
Answer: A
The relationship between quantities m and n is expressed by the equation 25m = 5(n - 42). If the difference between the two chosen values of n is 30, what is the difference in the corresponding values of m?
Choose the correct choice
A) 30/11
B) 42/11
C) 6
D) 150/11
E) 14

Solution: Another Simple way   25m=5(n-42)   Assume n = 42 to make one side equal to 0   then 25m=0   and m = 0   Repeat it by assuming n as 42+30 i.e 72   25m= 5(72-42)   25m=150   m=150/25= 
150/25 = 6
6 - 0= 
6 - 0 = 6
6   Answer : 6
Answer: C
By selling 99 pencil, a trader gains the cost of 33 Pencil. Find his gain percentage?	Select: A) 26 1/3% B) 51 1/3% C) 33 1/3% D) 53 1/3% E) 34 1/3%

Solution: C   33 1/3%   Let the CP of each pencil be Rs. 1.   CP of 99 pens = Rs. 99   Profit = Cost of 33 pencil = Rs. 33   Profit% = 33/99 * 100 = 33 1/3%
Answer: C
An anticraft gun can take a maximum of four shots at an enemy plane moving away from it. The probabilities of hitting the plane at the first, second, third and the fourth shot are 0.4, 0.3, 0.2 and 0.1 respectively. What is the probability that the gun hits the plane. Choices.
A) 0.3024  B) 0.6976  C) 0.44  D) 0.868  E) 0.839

Solution: Explanation :   Let E ≡ the gun hits the plane i.e at least one of the 4 shots hits the plane.   P(E) = 1 - P( none hits the plane)   = 1 - P( ~S1 ~S2 ~S3 ~S4).   ( S1 S2 S3 S4 are the probabilities of shots)   = 1 - P( ~S1) x P(~S2) x P(~S3) x P(~S4).   = 1 - (1-0.4)(1-0.3)(1-0.2)(1-0.1)   =1 - [0.6 x 0.7 x 0.8 x 0.9 ]   = 1 - 0.3024.   = 0.6976.   Hence, the required probabilities is 0.6976.   Answer : 0.6976
Answer: B
Evaluate: 20 - 12÷12×2 =  Choose the correct choice
A) A)4 B) B)8 C) C)12 D) D)16 E) E)20

Solution: According to order of operations, 12÷12×2 (division and multiplication) is done first from left to right   12÷12×2 = 1 × 2 = 2   Hence   20 - 12÷12×2 = 20 - 12= 
20 - 12 = 8
8   correct answer is 8) 8
Answer: B
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?	Choose the correct choice from the following answers
A) 1/2
B) 3/8
C) 3/4
D) 5/16
E) 9/16

Solution: In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.   Then, E	= {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),   (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),   (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}   n(E) = 27.   P(E) =	n(E)/n(S)	=	27/36	=	3/4	.   Answer : 3/4.
Answer: C
In how many seconds will a train 150 meters long pass an oak tree, if the speed of the train is 36 km/hr? Choices: A) 11 B) 13 C) 15 D) 17 E) 19

Solution: speed = 36 * 5/18= 
36 * 5/18 = 10
10 m/s   time= 150/10= 
150/10 = 15
15 seconds   The answer is 15.
Answer: C
If the cost price of 50 articles is equal to the selling price of 40 articles, then the gain or loss percent is?	Select the correct option:  A) 22  B) 65  C) 78  D) 33  E) 25

Solution: Given that, cost price of 50 article is equal to selling price of 40 articles.   Let cost price of one article = Rs. 1   Selling price of 40 articles = Rs. 50   But Cost price of 40 articles = Rs. 40   Therefore, the trader made profit.\Percentage of profit = 10/40 * 100= 
10/40 * 100 = 25
25%   Answer:25
Answer: E
How many plants will be there in a circular bed whose outer edge measure 32 cms, allowing 4 cm2 for each plant ?  Choose the correct choice from the following answers.
A) 18  B) 750  C) 24  D) 20  E) None of these

Solution: Circumference of circular bed = 32 cm   Area of circular bed = (32)2â„4Ï€   Space for each plant = 4 cm2   âˆ´ Required number of plants   = (32)2â„4Ï€ Ã· 4 = 20.36 = 20(approx)   Answer 20
Answer: D
On my sister's 15th birthday, she was 159 cm in height, having grown 6% since the year before. How tall was she the previous year? Choose the most appropriate option.
A) 150 cm  B) 160 cm  C) 170 cm  D) 140 cm  E) 150 cm

Solution: Explanation:   Given that height on 15th birthday = 159 cm and growth = 6%   Let the previous year height = x   Then height on 15th birthday = x × (100 + 6)/100 = x × 106/100   ⇒159 = x × 106/100   ⇒x = 159 × 100/106 = 1.5 × 100 = 150 cm   150 cmnswer: Option 150 cm
Answer: A
If in a cricket one day match, there were no wide balls, no wides, no extras and no overthrows.
What is the maximum number of runs that a batsman can score in an ideal case scenario? Choose one:
A) 2663 B) 1653 C) 3693 D) 4253 E) 2653

Solution: B   1653   For an ideal case, the batsman will hit a six on each ball. But if he hits six on the last ball of the over, the strike will change in the next over. Thus, the best he can do in the last ball is run 3 runs so that he retains the strike even in the next over. Thus the total runs that he can score in each over:    6 * 5 + 3= 
 6 * 5 + 3 = 33
33   But this will have to go like it only till the 49th over. In the last over, he can hit a six in the last ball as well as that will be the last ball of the match.   Thus runs for the last over will be 6 * 6= 
6 * 6 = 36
36.   Hence the maximum runs= 33 * 49 + 36= 
33 * 49 + 36 = 1_653
1653
Answer: B
A sum of money lent out at S.I. amounts to Rs. 780 after 2 years and to Rs. 1020 after a further period of 5 years. The sum is?
Choose one: A) s. 684 B) s. 500 C) s. 540 D) s. 740 E) s. 840

Solution: S.I for 5 years = (1020 - 780) = Rs. 240.   S.I. for 2 years = 240/5 * 2 = Rs. 96.   Principal = (780 - 96) = Rs. 684   s. 684NSWER:s. 684
Answer: A
Three numbers are in the ratio 4 : 5 : 6 and their product is 76680. the largest number is  Choose the correct option
A) 30
B) 24
C) 26
D) 28
E) 22

Solution: Explanation:   Let the number be 4x, 5x and 6x. Then,   (4x)(5x)(6x) = 2880   => 120x3 = 7680   => x3 = 64 => x = 4   So, largest number is 6x = 24   Answer: Option 24
Answer: B
A present value of a machine is $1100. Its value depletion rate is 10% per annum then find the machine value after 2 years?	Pick one
A) $900  B) $891  C) $915  D) $715  E) $795

Solution: P= $1100   R = 10%   T = 2 years   Machine value after 2 years = P[(1-R/100)^T]   =1100*9/10 * 9/10= 
1100*9/10 * 9/10 = 891
$891   Answer is $891
Answer: B
Three beakers namely A, B and C each contain 100 ml of spirit in water solution. The ratio of spirit to water in the beakers A, B and C is 1 : 3, 1 : 4 and 2 : 3 respectively. 40 ml of solution is transferred from beaker A to beaker C and than 28 ml of solution is transferred from beaker C to beaker B. Find the final ratio of spirit in the beakers A, B and C. Select:
A) 3 : 6 : 8
B) 6 : 15 : 20
C) 15 : 28 : 42
D) 25 : 28 : 42
E) None of these

Solution: Initial quantity of spirit and water in the beakers.   Beaker 3 : 6 : 8: spirit = 25 ml and Water=75 ml   Beaker B: spirit = 20 ml and Water = 80 ml   Beaker C: spirit = 40 ml and Water= 60 ml   3 : 6 : 8fter 40 ml is transferred from beaker 3 : 6 : 8 to beaker C, the quantity of spirit and water in the beakers is as follows:   Beaker 3 : 6 : 8 : spirit = 25 - 10= 
25 - 10 = 15
15 ml and   Water=75 - 30= 
75 - 30 = 45
45 ml   Beaker B : spirit= 20 ml and Water = 80 ml   Beaker C: spirit=40 + 10= 
40 + 10 = 50
50ml and   Water=60 + 30= 
60 + 30 = 90
90 ml   Now, spirit : Water in Beaker C= 5:9   3 : 6 : 8fter 28 ml is transferred form beaker C to beaker B:   Beaker 3 : 6 : 8: spirit= 15 and Water = 40mI   Beaker B: spirit = 20 + l0 = 30ml and   Water=80 + 18= 
80 + 18 = 98
98 ml   Beaker C: spirit= 50 - 10= 
50 - 10 = 40
40ml and   Water=90 - 18= 
90 - 18 = 72
72 ml   Required Ratio= 15 : 30 : 40 = 3 : 6 : 8   3 : 6 : 8NSWER:3 : 6 : 8
Answer: A
The average of 11 numbers is 10.9. If the average of first six is 10.5 and that of the last six is 11.2 the sixth number is?  Choose the correct option.
A) 10.3 B) 11.3 C) 11.8 D) 11.5 E) 11.1

Solution: 1 to 11 = 11 * 10.9= 
11 * 10.9 = 119.9
119.9   1 to 6= 6 * 10.5= 
6 * 10.5 = 63
63   6 to 11= 6 * 11.2= 
6 * 11.2 = 67.2
67.2   63 + 67.2= 
63 + 67.2 = 130.2
130.2 – 119.9= 10.3   6th number = 10.3   10.3nswer: 10.3
Answer: A
Jim drove 215 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey?	Choose the correct choice:
A) 113 miles  B) 432 miles  C) 456miles  D) 887 miles  E) 985 miles

Solution: The number of miles to drive to finish his journey is given by   1200 - 215= 
1200 - 215 = 985
985 miles   correct answer 985 miles
Answer: E
M = {-6, -5, -4, -3, -2}
T = {-2, -1, 1, 2, 3}
If an integer is to be randomly selected from set M above and an integer is to be randomly selected from set T above, what is the probability that the product of the two integers will be negative? Choose the correct choice from the following
A) 0  B) 1/3  C) 2/5  D) 1/2  E) 3/5

Solution: Answer E.   Total # of outcomes: 5*5= 
5*5 = 25
25   # of outcomes where Product is -ve : (-6,1) ,(-6,2), (-6,3)... Hence, total: 15   Probability: 15/25= 3/5
Answer: E
When positive integer x is divided by positive integer y, the result is 59.32. What is the sum T of all possible 2-digit remainders for x/y?  Options:
A) 560
B) 616
C) 672
D) 728
E) 784

Solution: ans B 616...   remainders = .32=32/100=8/25=16/50 and so on..   so two digit remainders are 16+24+32+....+96..   T=8(2+3+4....+12)=616.616
Answer: B
A tank has both an inlet pipe and an outlet pipe. Working alone, the inlet pipe can fill up the tank in 4 hours. Working alone, the outlet pipe can empty out the tank in 10 hours. If it is desired that the tank should be filled, from empty, exactly 6 hours after the inlet pipe is turned on at 9:30am, then at what time should the outlet pipe be opened ? Choose the most appropriate option
A) 8:30am	B) 9:30am	C) 10:00am	D) 10:30am	E) 11:30am

Solution: In 6 hours the inlet pipe will pump in water equal to 6*1/4 = 6/4 of the pool. So, 2/4 more than necessary, which should be compensated by the outlet pipe. To pump out 2/4 of the water the outlet pipe needs 20/4= 
20/4 = 5
5 hours.   Therefore, the outlet pipe should be opened at 9:30am + 6 hours - 5 hours= 10:30am.   Answer: 10:30am
Answer: D
In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2? Choose the correct choice from the following answers:	A) 60	B) 88	C) 77	D) 66	E) 44

Solution: 2:1 --- 60   1:2   2:4   ---------------   3   3 ----------- 60   3 ----------- ? => 60 liters   60nswer:60
Answer: A
If st > 0, which of the following must be negative? Select the correct option
A) -s/t
B) st
C) -s*-t
D) -s/-t
E) s+t

Solution: Given st> 0 So both will be the positive integers. If both are positive, then B,C,D,E also positive.   -s/tnswer :-s/t
Answer: A
If the cost price is 92% of sp then what is the profit %  Choices.
A) 8.70%  B) 8.60%  C) 8.10%  D) 8.30%  E) 8.27%

Solution: Sol. sp=Rs100 : then cp=Rs 92:profit =Rs 8.   Profit={(8/92)*100}%=8.70%   8.70%nswer is 8.70%.
Answer: A
What is the are of an equilateral triangle of side 10 cm?  Choices
A) 66âˆš3 cm2
B) 25âˆš3 cm2
C) 64âˆš3 cm2
D) 64âˆš5 cm2
E) 14âˆš3 cm2

Solution: Area of an equilateral triangle = âˆš3/4 S2   If S = 10, Area of triangle = âˆš3/4 * 10 * 10 = 25âˆš3 cm2;   Answer:25âˆš3 cm2
Answer: B
The product of HCF and LCM of 18 and 15 is	Choose the correct choice from the following options:  A) 120  B) 150  C) 175  D) 270  E) 190

Solution: HCF of 18 and 15   18 = 2 x 3 x 3   15 = 3 x 15 = 3   LCM of 18 and 15 = 2 x 3 x 3 x 5 = 90   ∴ Product of HCF and LCM of both numbers = 3 x 90 = 270   ANSWER :270
Answer: D
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If three marbles are drawn what is the probability that one is yellow and two are red?  Answers:
A) 12/455
B) 12/458
C) 12/487
D) 12/456
E) 12/4512

Solution: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.   When three marbles are drawn, the probability that one is yellow and two are red   = (2 * 4 * 3 * 3 * 2)/(1 * 2 * 15 * 14 * 13)   = 12/455   12/455nswer:12/455
Answer: A
When a student Joe, weighing 45 kg, joins a group of students whose average weight is 30 kg, the average weight goes up by 1 kg. Subsequently, if two students, excluding Joe, leave the group the average weight comes back to 30 kg. What is the difference between the average weight of the two students who left and the weight of Joe?  Choose the correct choice from the following answers:
A) 7.5 kg	B) 11 kg	C) 30 kg	D) 36.5 kg	E) 71 kg

Solution: After two persons leave the group the average remains the same. That means the weight of the two persons = 45+30= 
45+30 = 75
75   So, the average the two persons= 37.5   That gives the answer  45-37.5= 
 45-37.5 = 7.5
7.5   7.5 kgNswer 7.5 kg
Answer: A
A number when divided by a certain divisor left remainder 251, when twice the number was divided by the same divisor, the remainder was 112. Find the divisor? Choose the correct choice from the following options:
A) 370	B) 365	C) 390	D) 456	E) 460

Solution: Easy solution:   N= Dq1+251   2N = 2Dq1 + 502 - (1)   2N = Dq2 + 112 - (2)   As (1) = (2) = 2N   D*(q2-2q1) = 390   D * Some integer = 390   Checking all options only (C) syncs with it.   Answer 390
Answer: C
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $60 to incur a loss 20%?  Pick
A) 30 B) 36 C) 40 D) 50 E) 48

Solution: Production cost per article: $60*(100%-20%) / 20 = $2.40   Required production costs for a loss of 20%: $60*(100% + 20%) = $72   Number of articles to be sold for $72 to incur a 20% loss: $72 / $2.40 = 30   Thus, solution 30 is correct.72 /  2.40= 
72 /  2.40 = 30
30   Thus, solution 30 is correct.
Answer: A
How many shots of 1cm radius can be prepared from a sphere of 4cm radius?	Select:
A) 33	B) 88	C) 27	D) 64	E) 99

Solution: 4/3 Ï€ * 4 * 4 * 4 = 4/3 Ï€ * 1 * 1 * 1 * x   x = 64   Answer: 64
Answer: D
A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:
Choose the correct choice from the following answers: A) 0% B) 1% C) 2% D) 3% E) 4%

Solution: C.P. = Rs. 3000.   S.P. = Rs.	(3600 x 100)/(100 + (10 x 2))= Rs. 3000.   Gain = 0%.   answer :0%
Answer: A
Four usual dice are thrown on the ground. The total of numbers on the top faces of these four dice is 13 as the top faces showed 4, 3, 1 and 5 respectively. What is the total of the faces touching the ground? Select:
A) 22	B) 37	C) 15	D) 99	E) 26

Solution: Explanation:   In a usual dice, the sum of the numbers on any two opposite faces is always 7. Thus, 1 is opposite 6, 2 is opposite 5 and 3 is opposite 4.   Consequently, when 4, 3, 1 and 5 are the numbers on the top faces, then 3, 4, 6 and 2 respectively are the numbers on the face touching the ground. The total of these numbers = 3 + 4 + 6 + 2= 
3 + 4 + 6 + 2 = 15
15.   Answer: 15) 15
Answer: C
M is a certain set of numbers with an average (arithmetic mean) of 10 and a standard deviation of 1. Q is a subset of M consisting of 5 terms. Exactly 80% of the numbers in Q are located within 2 standard deviations from the average of M. Which of the following could Q be? Choose the correct choice.
A) {3, 4, 5, 10, 14} B) {3, 6, 7, 10, 12} C) {3, 5, 5, 10, 16} D) {1, 5, 7, 10, 12} E) {5, 8, 9, 10, 12}

Solution: Exactly 80% of the numbers in Q, so 4 out of 5 numbers are from 10 - 2*{SD} = 8 to 10 + 2*{SD} = 12.   A. {3, 4,5, 10, 14} --> only 1 number is in this range. Discard.   B. {3,6, 7, 10, 12} --> only 2 numbers are in this range. Discard.   C. {3,5, 5, 10, 16} --> only 1 number is in this range. Discard.   D. {1,5, 7, 10, 12} --> only 2 numbers are in this range. Discard.   E. {5, 8, 9, 10, 12} --> 4 numbers are in this range. OK.   Answer:{5, 8, 9, 10, 12}.
Answer: E
On increasing the number of lines in a page by 100, they become 240. What is the % of increase in the no. of lines in the page?  Choose the correct choice
A) 20%	B) 305	C) 50%	D) 71.4%	E) 60%

Solution: Explanation : Number of pages increased = 100   Now , the number of pages of book = 240   Number of pages of the books before increase = 240 – 100 = 140   % increase in the number of pages in the book = 100 /140   x 100% = 71.4%   71.4%
Answer: D
A man has $480 in the denominations of one-Dollar, five-Dollar notes and ten-Dollar. The number of Dollars of each denomination is equal. What is the total number of Dollar that he has ? Choose one
A) 50 B) 60 C) 90 D) 48 E) 67

Solution: C   $90   Let number of notes of each denomination be x.   Then x + 5x + 10x = 480   16x = 480   x = 30.   Hence, total number of notes = 3x = 90.
Answer: C
Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 72 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B?  Choices:
A) 11 : 6	B) 12 : 7	C) 13 : 7	D) 65 : 36	E) 13 : 6

Solution: Sol. 65 : 36istance travelled by Car A = 65 Ã— 8 = 520 km   65 : 36istance travelled by Car B = 72 Ã— 4 = 288 km   Ratio = 520/288 = 65 : 36   65 : 36
Answer: D
The side of a square is increased by 25% then how much % does its area increases? Choose the correct choice
A) 55.2 % B) 10 % C) 15 % D) 56.25 % E) 18 %

Solution: Explanation:   a = 100 a2 = 10000   a = 125 a2 = 15625   ----------------   10000 --------- 5625   100 -------? => 56.25 %   Answer : 56.25 %
Answer: D
When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 24, what is the remainder when k is divided by 7? Pick one
A) 2
B) 5
C) 6
D) 3
E) 8

Solution: Cant think of a straight approach but here is how I solved it:   K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)   so the possible values of K = {2, 7, 12, 17, 22} (less than 24)   Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5   so the possible value set for k = {5, 11, 17, 23} (less than 24)   17 is the only common number in both the sets. Hence k = 17   Answer : 3
Answer: D
Health insurance Plan C requires the insured to pay $1000 or 50% of total cost, whichever is lower. Plan B requires the insured to pay the initial $300, but then pays 80% of the cost over $300. Which of the following is a cost level for which both insurance plans pay out the same amount? Pick:
A) $600
B) $1000
C) $3800
D) $5300
E) $6200

Solution: 0.5 * 600= 
0.5 * 600 = 300
300 where C= $1000.
Answer: B
Which of these fractions is equivalent to 15
25?
Pick one:
A) 3/4
B) 2/3
C) 3/5
D) 1/2
E) 5/7

Solution: Both the numerator and the denominator are divisible by 5.   Dividing, we get 15/25 = 15/5/25/5 = 3/5 . Therefore, 15/25 is equivalent to 3/5 .   correct answer 3/5
Answer: C
The average of 10 numbers is calculated as 15. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is?
Choose the correct choice from the following options:	A) 16	B) 18	C) 19	D) 22	E) 24

Solution: Explanation:   10 * 15 + 36 – 26 = 160/10= 
160/10 = 16
16   16)
Answer: A
In an examination 40% failed in Hindi, 45% failed in English. If 25% students failed in both the subjects. Then the percentage of failed students is? Choose the correct choice from the following.
A) 60	B) 20	C) 25	D) 30	E) 40

Solution: 15+25+20= 
15+25+20 = 60
60   60NSWER 60
Answer: A
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 14% per annum then the gain of B in a period of 3 years is?	Answers:
A) 400
B) 410
C) 460
D) 420
E) 430

Solution: (3500*4*3)/100= 
(3500*4*3)/100 = 420
> 420   Answer: 420
Answer: D