MU-NLPC/Calc-aqua_rat huggingface dataset:
A, B and C enter into a partnership with a capital in which A's contribution is Rs. 10,000. If out of a total profit of Rs. 1000, A gets Rs. 500 and B gets Rs. 300, then C's capital is?
Choose one.
A) 4002  B) 4029  C) 4129  D) 4000  E) 4019

Solution: A : B : C = 500 : 300 : 200 = 5 : 3 : 2.   Let their capitals be 5x, 3x and 2x respectively.   Then, 5x = 10000   => x = 2000.   C's capital = 2x = Rs. 4000.   Answer: 4000
Answer: D
Taps A and B can fill a bucket in 12 minutes and 15 minutes respectively. If both are opened and A is closed after 4minutes, how much further time would it take for B to fill the bucket?	Choose the correct choice from the following answers
A) 6 min.	B) 4 min.	C) 5 min.	D) 3 min.	E) 2 min.

Solution: Explanation:   Part filled in 4 minutes =   4∗(1/12+1/15)=4∗9/60=3/5   Remaining part =1−3/5=2/5   =>1/15:2/5=1:X   =>X=6   =>X=6 min.   So it will take further 6 min. to fill the bucket.   Option 6 min.
Answer: A
Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond four years. If he pays a total interest of 11,500 at the end of nine years, how much money did he borrow?	Select.
A) 10,105  B) 12,105  C) 14,105  D) 16,105  E) None of these

Solution: Let the sum borrowed be x. Then,   (x×6×21/00)+(x×9×3/100)+(x×14×4/100)= 11500   ⇒ (3⁄25x + 27⁄100x + 14⁄25x) = 11400 ⇒ 95⁄100x = 11500   ⇒ x = (11500×100/95)= 12105   Hence, sum borrowed = 12,105   Answer 12,105
Answer: B
3 women and a few men participated in a chess tournament. Each player played two matches with each of the other players. If the number of matches that men played among themselves is 78 more than those they played with the women, how many more men than women participated in the tournament?
Pick one.
A) 14  B) 13  C) 11  D) 10  E) 8

Solution: let the number of men=m..   so 3 women and m men will play= 2*3= 
2*3 = 6
6m games   m will play each other in mC2 way so number of games= 2*mC2= m(m-1)   Difference in two = m(m-1)-6m=78   m^2-7m-78=0   m^2-13m+6m-78=0   (m-13)(m+6)=0   so m = 13 or -6   cannot be -ive so m=13   difference in number of women and men= 13-3=10.. Imp that we do not choose 13 as the answer   ANS 10
Answer: D
Kamal started a business with Rs.25000 and after 4 months, Kiran joined him with Rs.60000. Kamal received Rs.58000 including 10% of profit as commission for managing the business. What amount did Kiran receive? Choose the correct option:
A) 72000 B) 720 C) 82000 D) 92000 E) 7200

Solution: Ratio of the profits = 25000*12 : 60000*8   = 25*12 : 60*8	= 5*3 : 12:2 = 5 : 4*2   = 5:8   Let the total profit = x.   Then Kamal received 10x/100 = x/10 as commission for managing the business   Remaining profit = x- x/10 = 9x/10 which is shared in the ration 5:8   Kamal's share = x/10 + (9x/10) * (5/13) = 58000   => x + 9x(5/13) = 580000   => x(1 + 45/13) = 580000   => x ( 58/13) = 580000   => x ( 1/13) = 10000   => x = 130000   Kiran's share = 130000 - 58000= 
130000 - 58000 = 72_000
72000   72000nswer is 72000
Answer: A
Rs 12200 divided among 5 women, 4 boys and 7 men , such that the share a woman, a boy and a man are in the ratio of 7:3:2. Find the share of a girl?  Choose the most appropriate option:
A) Rs 100  B) Rs200  C) Rs300  D) Rs 2000  E) Rs 600

Solution: Total amount paid = (5 x 7x) + (4 x 3x) +(7 x 2x) =61x = 12200   =>35x+12x+14x=12200   =>61x=12200 =>x=200   The share of a girl= 3x = 3 x Rs 200 = Rs 600   Answer:Rs 600
Answer: E
The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?	Choose the correct answer:
A) 10	B) 99	C) 77	D) 55	E) 22

Solution: Speed of the boat in still water = (60+80)/2= 
(60+80)/2 = 70
70 kmph. Speed of the stream= (80-60)/2= 
(80-60)/2 = 10
10 kmph.   10nswer: 10
Answer: A
find two integers, neither of which ends in a zero, and whose product is exactly 100	Select the correct option.
A) 4 and 25
B) 60 and 15,625
C) 64 and 15,620
D) 64 and 15,635
E) 64 and 16,625

Solution: 100=10^2   =10x10   =(2x5)x(2x5)   =(2^2)x(5^2)   = 4x25   so the numbers are 4 and 25   4 and 25NSWER:4 and 25
Answer: A
600 km journey it will take 8hrs, if 120 km is done by bus and the rest by car. It takes 20 minutes more, if 200 km is done by busand the rest by car. The ratio of the speed of the train to that of the cars is?  Pick.
A) 1 : 3
B) 3 : 4
C) 2 : 5
D) 1 : 4
E) 3 : 5

Solution: Let the speed of the train be x km/hr and that of the car be y km/hr.   Then, 120 + 480 = 8 1 + 4 = 1 ....(i)   x y x y 15   And, 200 + 400 = 25 1 + 2 = 1 ....(ii)   x y 3 x y 24   Solving (i) and (ii), we get: x = 60 and y = 80.   Ratio of speeds = 60 : 80 = 3 : 4.   3 : 4
Answer: B
Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $360 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996?
Choose the correct choice
A) $24 million
B) $120 million
C) $644 million
D) $540 million
E) $720 million

Solution: Convert units to millions as answer is in millions   1996 Imports = $1.44 bill = $1440 mill   i.e. 1440/12 = $120 mill/month   1997 Imports = $360 mill/2 month   i.e. $180 mill/month   Difference/month = 180-120= 
180-120 = 60
60   Difference/year= $60 mill * 12 = $720 mill   ANSW$720 millionR: $720 million
Answer: E
Two alloys A and B are composed of two basic elements. The ratios of the compositions of the two basic elements in the two alloys are 5 : 3 and 1 : 5, respectively. A new alloy X is formed by mixing the two alloys A and B in the ratio 4 : 3. What is the ratio of the composition of the two basic elements in alloy X ?
Pick one.
A) 1 : 1	B) 3 : 4	C) 5 : 2	D) 4 : 3	E) 7 : 9

Solution: Mixture A has a total of 5 + 3= 
5 + 3 = 8
8 parts. If in the final mixture this represents 4 parts, then the total number of parts in mixture B should be  (8/4)*3= 
 (8/4)*3 = 6
6.   So, we should take of mixture B a quantity with 1 and 5 parts, respectively.   This will give us in the final mixture (5 + 1) : (3 + 5), which means 6:8, or 3:4.   Answer 3 : 4.
Answer: B
A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age five years back was:
Choose one:  A) 9 years  B) 14 years  C) 25 years  D) 12 years  E) 11 years

Solution: Answer: Option B   Let the son's present age be x years.   Then, (38 - x) = x   2x = 38 => x = 19   Son's age 5 years back = (19 - 5)= 
(19 - 5) = 14
14 years.
Answer: B
You choose at random ten points inside of a circle, so that no two of them are
on any diameter. What is the probability that the circle has some diameter, so that exactly
five points are on one side and exactly five points are on the other?
Pick:
A) 63/256	B) 1/2	C) 2/3	D) 5/6	E) 1

Solution: The randomness is a red herring: There is some diameter dividing the points 5 - 5   no matter what!   Note that none of the points can be in the center of the circle. (Then any diameter going   through any of the points would contain two points.) Choose any diameter. If five points   are on either side, we're done. Otherwise, let n be the larger number of points and rotate   the diameter gradually 180 degrees. As we do this, the number of points on the side with   n changes whenever the diameter crosses a point, eventually dropping to 10 - n. Since 5 is   between n and 10-n, and this number of points changes one at a time, it must be 5 at some point   correct answer 1
Answer: E
The first train leaves the station at 7:00 am with a speed of 60 km/hr. The second train leaves at 8:30 am, in the same direction from the same station, with a speed of 80 km/hr. What time will the second train catch the first train?
Choose the correct choice from the following answers
A) 11:00 am
B) 12:00 noon
C) 1:00 pm
D) 2:00 pm
E) 3:00 pm

Solution: In ninety minutes, the first train travels 90 km.   The second train catches the first train with a relative speed of 20 km/h.   The second train will catch the first train in 4.5 hours.   The second train will catch the first train at 1:00 pm.   The answer is 1:00 pm.
Answer: C
John found that the average of 15 numbers is 40. If 13 is added to each number then the mean of number is?
Answers:  A) 53  B) 45  C) 65  D) 78  E) 64

Solution: (x+x1+...x14)/15 = 40   53   Option 53
Answer: A
Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:	Answers
A) 2:3	B) 1:2	C) 7:9	D) 5:11	E) 4:5

Solution: Explanation:   Let the third number be x.   Then, first number = 120% of x=120x/100=6x/5   Second number = 150% of x =150 x/100=3x/2   Ratio of first two numbers =(6x/5:3x/2)=12x:15x=4:5   Answer:4:5
Answer: E
When 6 is added to half of one-third of one-fifth of a number, the result is one-fifteenth of the number. Find the number? Options:
A) 32
B) 180
C) 60
D) 27
E) 11

Solution: Explanation:   Let the number be   26+ 1/2[1/3(a/5)] = a/15   => 6 = a/30 => a = 180   Answer:180
Answer: B
How many times will the digit 5 be written when listing the integers from 1 to 1000?
Choose the most appropriate option:
A) 300
B) 380
C) 180
D) 415
E) 264

Solution: Many approaches are possible. For example:   Consider numbers from 0 to 999 written as follows:   1. 000   2. 001   3. 002   4. 003   ...   ...   ...   1000. 999   We have 1000 numbers. We used 3 digits per number, hence used total of 3*1000= 
3*1000 = 3_000
3000 digits. Now, why should ANY digit have preferences over another? We used each of 10 digits equal # of times, thus we used each digit (including 5) 3000/10=300 times.   300nswer: 300.
Answer: A
Mary's income is 70 percent more than Tim's income, and Tim's income is 40 percent less than Juan's income. What percent of Juan's income is Mary's income?  Answers:	A) 124%	B) 102%	C) 96%	D) 80%	E) 64%

Solution: Juan's income = 100 (assume);   Tim's income = 60 (40 percent less than Juan's income);   Mary's income = 102 (70 percent more than Tim's income).   Thus, Mary's income (102) is 102% of Juan's income (100).   Answer: 102%.
Answer: B
In 1995 a certain store had ,2000 tools in stock that had been purchased for $30 each. If 1,000 of these tools were sold in 1995 for $40 each and the remaining 800 were sold in 1996 for $50 each, how many greater was the gross profit on the tools sold in 1996 than the gross profit on those sold in 1995?  Select the correct option:
A) $0 B) $6,000 C) $8,000 D) $32,000 E) $10,000

Solution: The keyword here isGross Profit:   Gross Profit = (Selling Price - Original Price)*(# of Items Sold)   So lets figure out what the Gross Profit for 1995:   GP1995 = (40-30)*(1000)= 
(40-30)*(1000) = 10_000
10000   And the Gross Profit for 1996:   GP1996= (50-30)*(1000)= 
(50-30)*(1000) = 20_000
20000   So the difference would be:   20000-10000= 
20000-10000 = 10_000
10000   ANSW$10,000R: $10,000.
Answer: E
In how many different ways can the letters of the word 'SCHOOL' be arranged so that the vowels always come together?  Options.
A) 120  B) 140  C) 145  D) 150  E) 160

Solution: 'SCHOOL' contains 6 different letters.   vowels OO are always together   we have to arrange the letters (OO)SCHL   Now 5 letters can be arranged in 5! = 120 ways   The vowels (OO) can be arranged 2! = 2 ways.   = (120 x 2) = 240   again you have to divided 2 common vowels so answer is 120.   120)
Answer: A
Two vessels A and B contain 62.5% and 87.5% of alcohol respectively. If 2 litres from vessel A is mixed with 4 litres from vessel B , the ratio of alcohol and water in the resulting mixture is?
Choices
A) 19:5	B) 17:2	C) 27:2	D) 21:5	E) 11:1

Solution: 19:5   19:5   Quantity of alcohol in vessel 19:5 = 62.5/100 * 2 = 5/4 litres   Quantity of alcohol in vessel B = 87.5/100 * 4 = 7/2 litres   Quantity of alcohol in the mixture formed = 5/4 + 7/2 = 19/4= 
19/4 = 19/4 = around 4.75
4.75 litres   19:5s 6 litres of mixture is formed, ratio of alcohol and water in the mixture formed= 4.75 : 1.25 = 19:5.
Answer: A
In a class of 150 students 55 speak English;85 speak Telugu and 30 speak neither English nor Telugu
How many speak both English and Telugu? Choices: A) 10 B) 20 C) 30 D) 40 E) 50

Solution: Total=150   English=55   Telugu=85   none/ neither English nor Telugu=30   No. of Students who speak only one or both=150-30= 
150-30 = 120
120   so, 120 stud's can speak english or telugu or both.   then,   No. of Stud's speak only English= 120-85(telugu)=35   " " " " " Telugu= 120-55= 
120-55 = 65
65   Remaining  120-(65+35)= 
 120-(65+35) = 20
20 stud's can speak both.   20)
Answer: B
A total of 5 liters of gasoline is to be poured into two empty containers with capacities of 2 liters and 6 liters, respectively, such that both containers will be filled to the same percent of their respective capacities. What amount of gasoline, in liters, must be poured into the 6-liter container?	Choose the correct choice from the following:
A) 4 1/2 B) 4 C) 3 3/4 D) 3 E) 1 1.4

Solution: Let x be the amount of gasoline in 2 lt container.   (x/2)*100 = ((5 - x)/6)*100   x = (5 - x)/3   3x = 5 - x   x = 1.25   Amount of gasoline in 6 lt container = 5 - 1.25= 
5 - 1.25 = 3.75
3.75   Answer: 3 3/4
Answer: C
One hour after Yolanda started walking from X to Y, a distance of 31 miles, Bob started walking along the same road from Y to X. If Yolanda's walking rate was 3 miles per hour and Bobт's was 4 miles per hour, how many miles had Bob walked when they met?	Options
A) 24  B) 23  C) 22  D) 21  E) 16

Solution: When B started walking Y already has covered 3 miles out of 31, hence the distance at that time between them was   31-3= 
  31-3 = 28
28 miles.   Combined rate of B and Y was   3+4= 
  3+4 = 7
7 miles per hour, hence they would meet each other in  28/7= 
 28/7 = 4
4 hours. In 6 hours B walked  4*4= 
 4*4 = 16
16 miles.   Answer: 16.
Answer: E
There are some passengers riding on a bus. At the first stop, half the passengers get off and nobody gets on the bus. This pattern continues as the bus goes to the next stops. If only one passenger gets off at stop number 5, how many passengers were on the bus originally?
Choose the correct option:
A) 128
B) 64
C) 32
D) 16
E) 8

Solution: Before stop 5, there were 2 passengers on the bus.   Before stop 4, there were 4 passengers on the bus.   etc...   Before stop x, there were 2^(6-x) passengers on the bus.   Before stop 1, there were 2^5 = 32 passengers on the bus.   The answer is 32.
Answer: C
A can do a work in 15 days and B in 20 days. If they work on it together for 7 days, then the fraction of the work that is left is	Answers
A) 8/17 B) 7/15 C) 3/15 D) 8/15 E) 11/60

Solution: Person ( A ) ( B ) ( A+B )   Time - ( 15 ) ( 20 ) (-)   Rate - ( 20 ) ( 15 ) ( 35 )   Work -(300) (300) (300)   therefore A+B requires (300/35) days to complete entire work   For 1st 4 days they work  35 * 7= 
 35 * 7 = 245
245   Remaining work is 300 - 245= 
300 - 245 = 55
55   Remaining fraction of work is= 55/300 = 11/60   Answer 11/60
Answer: E
On Monday, a certain animal shelter housed 70 cats and dogs. By Friday, 1/5 of the cats and 1/4 of the dogs had been adopted; no new cats or dogs were brought to the shelter during this period. What is the greatest possible number of pets that could have been adopted from the animal shelter between Monday and Friday?  Choose the correct choice from the following:
A) 13	B) 15	C) 17	D) 19	E) 21

Solution: To maximize the number of pets adopted, we should maximize the number of dogs adopted since 1/4 > 1/5.   The greatest multiple of 4 less than 70 is 60 (such that the remaining number is divisible by 5), so let's assume there were 60 dogs and 10 cats.   Then the maximum number of adopted pets is 1/4*(60) + 1/5*(10) = 15 + 2= 
15 + 2 = 17
17.   The answer is 17.
Answer: C
A circle graph shows how the budget of a certain company was spent: 60 percent for salaries, 9 percent for research and development, 5 percent for utilities, 4 percent for equipment, 2 percent for supplies, and the remainder for transportation. If the area of each sector of the graph is proportional to the percent of the budget it represents, how many degrees of the circle are used to represent transportation?
Choose the most appropriate option:
A) 18°	B) 36°	C) 54°	D) 72°	E) 90°

Solution: The percent of the budget for transportation is 100 - (60+9+5+4+2)= 
100 - (60+9+5+4+2) = 20
20%   100% of the circle is 360 degrees.   Then (20%/100%)*360 = 72 degrees   The answer is 72°.  (20 /100 )*360= 
  (20 /100 )*360 = 72
72 degrees   The answer is 72°.
Answer: D
A sum of Rs. 4000 amounts to Rs. 4600 in 5 years at a certain rate of simple interest. What would be the amount, if the rate of interest is increased by 3 %. Choices:
A) Rs. 4900 B) Rs. 5000 C) Rs. 5200 D) Rs. 5600 E) None of these

Solution: Explanation:   Principal = Rs. 4000, Amount = Principal + SI = Rs. 4600   SI = Amount – Principal = 4600 – 4000 = Rs. 600   Given : Principal = Rs. 4000, Time = T = 5 years and SI = Rs. 600   SI =PRT/100   600 = 4000 *R * 5/100   600 = 200R   R = 3 % p.a.   Now the new interest rate is = 3% + 3% = 6 % p.a.   SI 3  + 3= 
3  + 3 = 6
6 % p.a.   SI= PRT/ 100 = 4000 * 6 * 5/ 100 = Rs. 1200   Amount = Principal + SI   = 4000 + 1200= 
4000 + 1200 = 5_200
5200   ANSWER Rs. 5200
Answer: C
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1225 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units? Choose the correct choice from the following answers
A) 140 sq.units  B) 158 sq.units  C) 187 sq.units  D) 607 sq.units  E) 815 sq.units

Solution: Given that the area of the square = 1225 sq.units   => Side of square = √1225 = 35 units   The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35= 
2/5 * 35 = 14
14 units   Given that breadth= 10 units   140 sq.unitsrea of the rectangle = lb = 14 * 10= 
14 * 10 = 140
140 sq.units   140 sq.unitsnswer: 140 sq.units
Answer: A
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 176 votes. Find the total number of valid votes?
Select the correct option
A) 440	B) 570	C) 480	D) 520	E) 550

Solution: Let the total number of valid votes be x.   70% of x = 70/100 * x = 7x/10   Number of votes secured by the other candidate = x - 7x/100 = 3x/10   Given, 7x/10 - 3x/10 = 176 => 4x/10 = 176   => 4x = 1760 => x = 440.   440NSWER:440
Answer: A
With # andeach representing different digits in the problem below, the difference between #and ## is 445. What is the value of?
#
-##
____
445
E	Choose the correct choice from the following answers.
A) 7	B) 8	C) 9	D) 6	E) 5

Solution: 100x   -(10x +x)   -----------   89 x= 445   x = 5   5
Answer: E
If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.	Choose one:	A) 50 cm	B) 70 cm	C) 60 cm	D) 30 cm	E) 40 cm

Solution: Let x and y be the length and breadth of the rectangle respectively.   Then, x - 4 = y + 3 or x - y = 7 ----(i)   Area of the rectangle =xy; Area of the square = (x - 4) (y + 3)   (x - 4) (y + 3) =xy<=> 3x - 4y = 12 ----(ii)   Solving (i) and (ii), we get x = 16 and y = 9.   Perimeter of the rectangle = 2 (x + y) = [2 (16 + 9)] cm = 50 cm.   50 cmNSWER 50 cm 50 cm
Answer: A
Goldenrod and No Hope are in a horse race with 6 contestants. How many different arrangements of finishes are there if No Hope always finishes before Goldenrod and if all of the horses finish the race?
Choose the correct choice from the following options
A) 720  B) 360  C) 120  D) 24  E) 21

Solution: All 6 horses can finish the race in 6! way (assuming no tie).   If no tie is possible between No Hope and Goldenrod, then in half of these cases No Hope will be before Goldenrod and in half of these cases after (not necessarily right before or right after). How else? So, there are 6!/2=360 different arrangements of finishes where No Hope always finishes before Goldenrod.   Answer: 360.
Answer: B
If n is a positive integer and n^2 is divisible by 50, then what is the largest positive integer that must divide n?
Choose the correct option:	A) 5	B) 8	C) 10	D) 20	E) 25

Solution: 50 =   2 * 5= 
  2 * 5 = 10
10   The answer is 10.
Answer: C
Raju age after 35 years will be 5 times his age 5 years back, What is the present age of Raju	Pick:	A) 28	B) 17	C) 15	D) 77	E) 66

Solution: 15learly,   x+35 = 5(x-5)   <=> 4x = 60 => x = 15   Answer:15
Answer: C
What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?  Pick
A) 1260	B) 630	C) 2524	D) 1680	E) 2250

Solution: L.C.M. of 12, 18, 21 30 2 | 12 - 18 - 21 - 30   ----------------------------   = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15   ----------------------------   Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5   = 630. ANSWER : 630
Answer: B
In the xy-coordinate system, line k passes through points (-4m, 0) and (0, 2m). Which of the following is a possible equation of line k?	Select the correct option:
A) y = -2x + 2m  B) y = 1/2*x - 4m  C) y = 2x + 2m  D) y = 1/2*x + 2m  E) y = -1/2*x - 5m

Solution: The slope of the line is 2m/4m=1/2.   The y-intercept is 2m.   the equation of the line is: y = 1/2*x +2m   The answer is y = 1/2*x + 2m.1/2*  +2= 
1/2*  +2 = 1
1/2*x + 2m.
Answer: D
What is the units digit of 13^4*17^2*29^3?	Pick:
A) 9  B) 7  C) 5  D) 3  E) 1

Solution: 3^1=3   3^2=9   3^3=7   3^4=1, it is first digit   7^2=9, it is second digit   9^3=9, it is third digit   1*9*9=1   ANSW1R:1
Answer: E
Find the invalid no.from the following series 15, 16, 34, 105, 424, 2124, 12756	Pick
A) 1230
B) 1435
C) 1540
D) 1600
E) 2124

Solution: 2nd term = (1st term) * 1 + 1 = 15 *1 + 1= 
15 *1 + 1 = 16
16.   3rd term= (2nd term) * 2 + 2 = 16 * 2 + 2= 
16 * 2 + 2 = 34
34   4th term= (3th term) *3 + 3 = 34 * 3 + 3= 
34 * 3 + 3 = 105
105   5th term= (4th term) * 4 + 4 = 105 * 4 + 4= 
105 * 4 + 4 = 424
424   6th term= (5th term) * 5 + 5 = 424 * 5 + 5= 
424 * 5 + 5 = 2_125
2125   6th term should 2125 instead of 2124.   2124
Answer: E
A boy was asked to multiply a number by 25. He instead multiplied the next number by 52 and got the answers 324 more than the correct answer. The number to be multiplied was Pick one:  A) 10  B) 12  C) 15  D) 25  E) 14

Solution: Let the number be x.   Then, 52 x - 25 x	= 324   ‹=› 27 x = 324   x= 12.   Answer :12
Answer: B
Today is Sunday. A person wants to meet a lawyer and as that lawyer is busy he asks him to come three days after the before day of the day after tomorrow? On which day the lawyer asks the person to come?	Choose the correct choice from the following choices: A) SUNDAY B) MONDAY C) TUESDAY D) WEDNESDAY E) Thursday

Solution: Today is sunday   after three days--->wednesday   now, (wednesday)after before day--->tuesday   then, (tuesday)day after tomorrow--->thursday   ANSWThursdayR:Thursday
Answer: E
The number x yields a remainder p when divided by 13 and a remainder q when divided by 7. If p = q + 7, then which one of the following could be the value of x ?  Choose the correct choice from the following choices
A) 45  B) 36  C) 72  D) 85  E) 100

Solution: I solved this question in the following way:   Q<7 so Q can be from 0 to 4 and P<13 so P can be from 0 to 12, BUT the constraint is P=Q +7 so this will mean that P can be in the range from 7 to 12.   x=13k + P or x= 13k + 7 to 12 and look at the answer as, place different values for k, 36 will give 36 which is 13*2 + 10, the other answers are out of the range
Answer: B
The daytime telephone rate between two cities is 60 cents for the first 3 minutes and c cents for each additional minute. The total charge is reduced 60 percent on calls made after 10:00 P.M. The cost, in dollars, of a 33-minute call made at 10:30 P.M. between these two cities is:
Answers.
A) 0.4(0.60) + 35c	B) 0.4(0.60 + 9c)	C) 0.4(0.60 + 0.30c)	D) 0.6(0.60 + 30c)	E) 0.6(0.60 + 0.35c)

Solution: For first three minutes = 60 cents   Remaining minutes = 33 -3= 
33 -3 = 30
30   charge for 32 minutes= 30c   total cost (if the call was made in daytime) = 0.60 + 30c   60% chargereducedon night calls => 40% charge   =>0.4(0.60 + 30c)   Hence, Answer is 0.4(0.60 + 0.30c)
Answer: C