MU-NLPC/Calc-aqua_rat huggingface dataset:
Danny is sitting on a rectangular box. The area of the front face of the box is half the area of the top face, and the area of the top face is 1.5 times the area of the side face. If the volume of the box is 3000, what is the area of the side face of the box?	Choose one.
A) 300 B) 150 C) 180 D) 109 E) 200

Solution: Lets suppose length= l, breadth= b, depth= d   Front face area= l*w = 1/2 w*d (l=1/2 d or d=2l)   top face area= w*d   side face area= w*d = 1.5 d*l (w=1.5l)   Volume = l*w*d= 3000   l*1.5l*2l= 3000   l=10   Side face area= l*d= l*2l= 10*2*10= 
10*2*10 = 200
200   200 is the answer
Answer: E
How many positive integers less than 5,000 are evenly divisible by neither 15 nor 23?  Answers
A) 4,514	B) 4,475	C) 4,521	D) 4,428	E) 4,349

Solution: integers less than 5000 divisible by 15 5000/15 =333.something , so 333   integers less than 5000 divisible by 23 5000/23 = 238.## , so 238   we have double counted some, so take LCM of 15 and 23 =105 and divide by 5000, we get 47. so all numbers divisible by 15 and 23 = 333 +238 -47= 
333 +238 -47 = 524
524   now subtract that from 4999. 4999- 524= 4521 answer 4,521.
Answer: C
Which of the following is closer to (3!+2!)+(3!-2!)? Pick one:
A) 8	B) 22	C) 10	D) 14	E) 12

Solution: (3!+2!)+(3!-12!)=6+2+6-2= 
6+2+6-2 = 12
12   Answer: 12
Answer: E
At a local beach, the ratio of little dogs to average dogs to enormous dogs is 1:4:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?	Select the correct option
A) 20% or 70%	B) 40%	C) 50%	D) 55%	E) 70%

Solution: Little Dogs(L), 20% or 70%verage Dogs(20% or 70%) and Enormous Dogs (E)   The initial ratio for L:20% or 70%:E :: 1:4:8   Initial Total dogs = 13X ( x assumed; 1+4+8= 
1+4+8 = 13
13), Since the total dogs are less than 30 therefore initial total value has to be 13   L= 1, 20% or 70% = 4 E = 8   L:20% or 70%= 1:4   This ratio doubles   Hence New Dog count is   L= 2 , 20% or 70% = 4 E= X: 20% or 70%lso 2+4+x<30   We need to Find X*100/(2+4+X)   Now it says that new percentage of little dogs and 20% or 70%verage dogs is an integer   %L = 2*100/(6+x) %20% or 70% = 4*100/(6+x); Only Value for X is 4 or 14; 6+x<30 and % integer   Therefore, Enormus Dogs % is = 4*100/(20)= 
4*100/(20) = 20
20% or   14*100/20= 
  14*100/20 = 70
70%   20% or 70%   20% or 70%
Answer: A
Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 12 inches long, how wide is Jordan's rectangle, in inches?
Choose the most appropriate option:
A) 25
B) 23
C) 22
D) 20
E) 10

Solution: Area of Carol's rectangle = 24*5= 
24*5 = 120
120   Let width of Jordan's rectangle= w   Since , the areas are equal   12w = 120   =>w = 10   Answer 10
Answer: E
What number should be added to or subtracted from each term of the ratio 17 : 24 so that it becomes equal to 1 : 2.	Choose the correct choice from the following choices:
A) 35	B) 66	C) 77	D) 88	E) 99

Solution: Ans. 35
Answer: A
Two hoses are pouring water into an empty pool. Hose 1 alone would fill up the pool in 6 hours. Hose 2 alone would fill up the pool in 7 hours. How long would it take for both hoses to fill up two-thirds of the pool?	Choices.
A) 5/12 hours B) 5/8 hours C) 28/13 hours D) 12/7 hours E) 12/5 hours

Solution: Hose 1 would fill the pool alone in 6 hours   i.e. 1 Hour work of Hose 1 = 1/6   Hose 2 would fill the pool alone in 7 hours   i.e. 1 Hour work of Hose 2 = 1/7   i.e. 1 Hour work of Hose1 and Hose2 together = (1/6)+(1/7) = (13/42)   i.e. (13/42) work can be finished by Hose1 and Hose2 together in 1 hour   i.e. (2/3) work can be finished by Hose1 and Hose2 together in 1*(42/13)*(2/3) = 28/13 hour   Answer: Option 28/13 hours
Answer: C
A man can hit a target once in 4 shots. If he fires 4 shots in succession, what is the probability that he will hit his target?  Answers:
A) 175/256	B) 256/175	C) 451/784	D) 451/864	E) 145/562

Solution: The man will hit the target if he hits it once or twice or thrice or all four times in the four shots that he takes.   So, the only possibility when the man will not hit the target is when he fails to hit the target in even one of the four shots that he takes.   The event of not hitting the target even once is the complement of the event of hitting the target at least once.   The probability that he will not hit the target in any given shot = 1 – 1/4 = ¾   Therefore, the probability that he will not hit the target in any of the four shots =3/4*3/4*3/4*3/4=81/256   The probability that he will hit the target at least in one of the four shots=1-81/256   =175/256   175/256ns: 175/256
Answer: A
The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?	Choose the correct choice from the following options:
A) 15	B) 66	C) 77	D) 88	E) 12

Solution: 90 * 10/60= 
90 * 10/60 = 15
15 kmph   15nswer:15
Answer: A
A town in California fines residents who do not pay their property taxes on time. All residents must pay their taxes before July 1st for that calendar year or face the following fine structure: For the first month the taxes are overdue (that would be any payment made on July 1st through July 31st), the total fine is 1% of the original tax bill; for each additional month that the taxes are overdue, the total fine is increased by $600 or tripled, whichever results in the lesser amount. What is the total fine for a resident of that town who originally owed $45,000 in property taxes, but did not pay until October 15th?  Pick: A) $1,400 B) $1,800 C) $2,400 D) $21,400 E) $12,150

Solution: Original amount = 20,000   Fine for July = 20,000 * 1% = 450   Fine for August = lesser of the 2 , 450+600= 1050 or  450*3= 
 450*3 = 1_350
1350 . Pick 1350   Fine for September= 1350+600= 
1350+600 = 1_950
1950 or  1350*3= 
 1350*3 = 4_050
4050. Pick 4050   Fine for October= 4050+600= 
4050+600 = 4_650
4650 or  4050*3= 
 4050*3 = 12_150
12150. Pick 12150.   The wording of the question should be have been clearer as total fines should be= 12150+4050+1350+450= 
12150+4050+1350+450 = 18_000
18000 and NOT 12150.   12150 is the fine ONLY for the month of October!   $12,150
Answer: E
34.	The side surface of a cylinder is rolled with a rectangular plate. If the perimeter of the circular base Is 9 feet, and the diagonal of the rectangular plate was 15 ft. What is height of the of the cylinder?
Choose the correct option:
A) 12
B) 15
C) 10
D) 8
E) 14

Solution: Think of a Pringles can. If you took off the bottom and top and cut a slit down the length, it would flatten to a rectangle. The dimensions of the rectangle are the height of the can and the circumference of the circle. Since you know both, one side and thehypothenuse use pythagoreans theorem or properties of 3-4-5 triangles to solve for the other side, 12. Correct answer 12
Answer: A
The cost price of an article is 56% of the marked price. Calculate the gain percent after allowing a discount of 13%. Options:
A) 23.4%
B) 44.5%
C) 55.3%
D) 57.4%
E) none

Solution: Sol.   Let marked price = Rs. 100. Then, C.P. = Rs. 56. S.P = Rs. 87.   âˆ´ Gain % = [31/56 * 100]% = 55.3%.   Answer 55.3%
Answer: C
How many three letter combinations can be formed using the letters of the word STARE? Select
A) 6 B) 25 C) 45 D) 60 E) 120

Solution: The number of letters in the given word is five.   The number of three letter combinations that can be formed using these five letters is   = 5 * 4 * 3= 
5 * 4 * 3 = 60
60.   Answer: 60
Answer: D
At what price must an article costing Rs.85.5 be marked in order that after deducting 5% from the list price. It may be sold at a profit of 25% on the cost price?	Answers.
A) 122.5	B) 142.5	C) 162.5	D) 182.5	E) 112.5

Solution: CP = 85.50   SP = 85.5*(125/100)= 
85.5*(125/100) = 106.875
106.875   MP*(95/100)= 106.875   MP = 112.5   Answer:112.5
Answer: E
A, B and C have Rs.400 between them, A and C together have Rs.300 and B and C Rs.150. How much does C have?	Answers
A) 40  B) 50  C) 60  D) 70  E) 100

Solution: A+50+C = 400   A+C = 300   50+C = 150   --------------   A+50+2C = 450   A+50+C = 400   ----------------   C = 50   Answer : 50
Answer: B
Sahil purchased a machine at Rs 10000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it.
Choose the correct answer:
A) Rs. 22000 B) Rs. 24000 C) Rs. 26000 D) Rs. 28000 E) None of these

Solution: Explanation:   Question seems a bit tricky, but it is very simple.   Just calculate all Cost price, then get 150% of CP.   C.P. = 10000 + 5000 + 1000= 
10000 + 5000 + 1000 = 16_000
16000   150% of 16000= 150/100 * 16000= 
150/100 * 16000 = 24_000
24000   Option Rs. 24000
Answer: B
If b does not equal zero, and ab = b/4, what is the value of a?
Choose the correct choice from the following:  A) 1/8  B) 1/4  C) 1/3  D) 1/2  E) None of the above

Solution: Explanation:   To solve for a, divide both sides of the equation by b: ab = b/4   (ab)/b = (b/4)/b   a = (b/4)*1/b   a = 1/4   Answer: (1/4).
Answer: B
The apartment on King-Williams street is an asset that its value is tramping about. From the year 1973 to 1983 it's value decreased by 16% and from 1983 to 1993 it's value increased by 16%. What is the value of the asset in 1993 if in 1973 it was worth $30,000? Answers:
A) $38,796.
B) $40,000.
C) $38,976.
D) $29,232.
E) $36,796.

Solution: 30,000 *1.16*.84=29,232   Answer $29,232.
Answer: D
Ron walks to a viewpoint and returns to the starting point by his car and thus takes a total time of 6 hours 45 minutes. He would have gained 2 hours by driving both ways. How long Y would it have taken for him to walk both ways. Choices.
A) 8 h 45 min B) 7 h 45 min C) 6 h 45 min D) 5 h 30 min E) None of these

Solution: 1.Walking to to a viewpoint+Driving back=6 hours 45 minutes   2.Driving to a viewpoint+Driving back=6 hours 45 minutes - 2 hours=4 hours 45 minutes, thereforeone way driving=4 hours 45 minutes/2 =2 hours 22.5 minutes.   3. From 1.one way driving=6 hours 45 minutes-2 hours 22.5 minutes=4 hours 22.5 minutes.   4.Walking to to a viewpoint+Walking back Y=4 hours 22.5 minutes+4 hours 22.5 minutes=8 hours 45 minutes.   8 h 45 minnswer: 8 h 45 min.
Answer: A
The greatest common factor of 16 and the positive integer n is 4, and the greatest common factor of n and 45 is 3. Which of the following could be the greatest common factor of n and 150?  Choose the correct choice
A) 3	B) 14	C) 30	D) 42	E) 30

Solution: Greatest common factor n and 16 is 4 = 2*2 * 2*2   Greatest common factor n and 45 is 3 = 3*3 *5   Greatest common factor n and 150 is = 2*3*5= 
2*3*5 = 30
30   Answer: 30.
Answer: E
There are 35 students in a hostel. If the no. of students increases by 2, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?  Choose the correct choice from the following answers.
A) s. 234.50	B) s. 239.50	C) s. 242.50	D) s. 248.50	E) s. 249.50

Solution: Suppose the average join the mess , total expenditure = 35x + 42   Now, the average expenditure = (35x + 42)/ (35 + 2) = x – 1   or, 35x + 42 = 37x – 37   or, x = 39.50   Thus the original expenditure of the mess = 35 x 39.5 =1382.50   Therefore x-1 = 38.5   hence 42 x 38.5 = 1617   1617-1382.50 = Rs. 234.50   s. 234.50
Answer: A
In a box, there are 4 green, 5 black and 7 red pencils. One pen is picked up randomly. What is the probability that it is neither black nor red?
Pick:
A) 2/5
B) 1/5
C) 1/2
D) 1/3
E) 1/4

Solution: Explanation :   Neither black nor red means the pencils drawn is green.   Total number of outcomes = (4+5+7)= 
(4+5+7) = 16
16.   Number of Favourable outcomes= 4 = Number of green pencils.   Hence, Probability of the event = 4/16 = 1/4.   Answer : 1/4
Answer: E
An optometrist charges $150 per pair for soft contact lenses and $85 per pair for hard contact lenses. Last week she sold 5 more pairs of soft lenses than hard lenses. If her total sales for pairs of contact lenses last week were $1,220, what was the total number of pairs of contact lenses that she sold? Pick one:
A) 9	B) 13	C) 15	D) 17	E) 19

Solution: (x+5)*150 +x*85=1220   =>x=2   total lens=2+(2+5)= 
2+(2+5) = 9
9   9nswer 9
Answer: A
The average age of three boys is 18 years and their ages are in the proportion 3 : 3 : 6. The age of the youngest boy is: Pick one:
A) 21 years B) 18 years C) 15.5 years D) 13.5 years E) None of these

Solution: Total age of 3 boys = (18 Ã— 3) years = 54 years. Ratio of their ages = 3 : 3 : 6.   Age of the youngest = (54 Ã— 3â„12) years = 13.5 years.   Answer 13.5 years
Answer: D
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 20 seconds. The ratio of their speeds is?
Choices:	A) 3/7	B) 3/2	C) 3/5	D) 3/1	E) 3/3

Solution: Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters, and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 20   ==> 27 x + 17 y = 20 x + 20 y ==> 7 x = 3 y ==> x/y   = 3/7.   3/7nswer: 3/7
Answer: A
At what price must an article costing Rs.47.50 be marked in order that after deducting 10% from the list price. It may be sold at a profit of 25% on the cost price?
Choose the correct choice from the following answers:
A) 60.5	B) 65.9	C) 67.5	D) 62.5	E) 22.5

Solution: CP = 47.50   SP = 47.50*(125/100)= 
47.50*(125/100) = 59.375
59.375   MP*(90/100)= 59.375   MP = 65.9   Answer:65.9
Answer: B
Out of 18 points in a plane, no three are in the same straight line except five points which are collinear. How many straight lines can be formed by joining them ?
Answers:
A) 124
B) 144
C) 134
D) 142
E) 143

Solution: The number of straight lines formed joining the 18 points, taking 2 at a time = 18C2=153. Number of straight lines formed by joining the 5 points, taking 2 at a time =5C2=10. But 5 collinear point, when joined pairwise give only one line. Required number of straight lines =153-10+1= 
153-10+1 = 144
144. Answer :144
Answer: B
What is the greatest value of n such that 15^n is a factor of 15! ?
Choose the correct choice from the following choices:
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: Another way to solve this question :   We know that 18 = 2 *3^2.   Hence, we need to find total number of 3s in 18! ( As out of 3 and 2 , we will have count of 3 least)   No. of 3s = 18/3= 
18/3 = 6
6/3= 
6/3 = 2
2.   Add the numbers in Bold, you will get total number of 3s= 8.   Hence, total number of 3^2 = 10/2= 
10/2 = 5
5.   Hence, answer is 5. 5
Answer: E
If Rs. 782 be divided into three parts, proportional to 1/2:1/3:3/4, then the second part is?  Pick one:
A) A)426  B) B)526  C) C)207  D) D)165  E) E)297

Solution: Given ratio   = 1/2:2/3:3/4 = 6:4:9   1st part = 782 * 4/19   = Rs. 165   Answer:165
Answer: D
Two interconnected, circular gears travel at the same circumferential rate. If Gear A has a diameter of 60 centimeters and Gear B has a diameter of 50 centimeters, what is the ratio of the number of revolutions that Gear A makes per minute to the number of revolutions that Gear B makes per minute?	Answers:
A) 6:5  B) 9:25  C) 5:6  D) 25:9  E) Cannot be determined from the information provided

Solution: Same circumferential rate means that a point on both the gears would take same time to come back to the same position again.   Hence in other words, time taken by the point to cover the circumference of gear A = time take by point to cover the circumference of gear B   Time A = 2*pi*25/Speed A   Time B = 2*pi*30/Speed B   Since the times are same,   50pi/Speed A = 60pi/Speed B   SpeedA/Speed B = 50pi/60pi = 5/6   5:6orrect Option: 5:6
Answer: C
An even and an odd integer are multiplied together. Which of the following could not be the square of their product? Choose the correct option:
A) 36 B) 100 C) 144 D) 225 E) 400

Solution: 2*3= 
2*3 = 6
6 and 6^2=36   5*2= 
5*2 = 10
10 and 10^2=100   3*4= 
3*4 = 12
12 and 12^2=144   5*4= 
5*4 = 20
20 and 20^2=400   Answer 225
Answer: D
A and B together have $ 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have? Pick one
A) $400	B) $489	C) $484	D) $365	E) $342

Solution: 4/15A = 2/5B -> A= (2/5 * 15/4) B -> A = 3/2B -> A/B = 3/2   A: B = 3:2   B'S SHARE = RS (1210 * 2/5)= 
(1210 * 2/5) = 484
$484   ANSWER $484 $464
Answer: C
A four-digit code can consist of the digits 0 ~ 9 except that it does not contain the digits 1, 3, and 4 at all. If repeated digits are allowed, what is the probability that it has at least one even digit?
Select the correct option
A) 130/201
B) 320/401
C) 820/901
D) 1320/1401
E) 2320/2401

Solution: P(no even digits) = 3/7*3/7*3/7*3/7 = 81/2401   P(at least one even digit) = 1 - 81/2401 = 2320/2401   The answer is 2320/2401.
Answer: E
An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is?
Select the correct option:
A) 4.04%
B) 5%
C) 7%
D) 9%
E) 11%

Solution: 100 cm is read as 102 cm.   A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.   (A2 - A1) = [(102)2 - (100)2]   = (102 + 100) x (102 - 100)   = 404 cm2.   Percentage error = 404	x 100	%	= 4.04%   100 x 100   4.04%)
Answer: A
The average salary of a person for the months of January, February, March and April is Rs.8000 and that for the months February, March, April and May is Rs.8500. If his salary for the month of May is Rs.6500, find his salary for the month of January?
Choices:  A) 277  B) 2667  C) 4500  D) 2688  E) 2671

Solution: Sum of the salaries of the person for the months of January, February, March and April = 4 * 8000= 
4 * 8000 = 32_000
32000 ----(1)   Sum of the salaries of the person for the months of February, March, April and May= 4 * 8500= 
4 * 8500 = 34_000
34000 ----(2)   (2)-(1) i.e. May - Jan= 2000   Salary of May is Rs.6500   Salary of January = Rs.4500   Answer: 4500
Answer: C
A’s speed is 32/27 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?  Select the correct option
A) 5/32	B) 5/27	C) 1/27	D) 1/32	E) 27/32

Solution: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.   This is what the beginning of the race will look like:   (Start) A_________B______________________________   If A covers 32 meters, B covers 27 meters in that time. So if the race is 32 meters long, when A reaches the finish line, B would be 5 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 5 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 32 meters) would be the same as the time required by B (to cover 27 meters) to reach the finish line.   So B should get a head start of 5/32 th of the race.   5/32nswer (5/32)
Answer: A
There are 4 numbers W, X, Y, and Z. If W:X = 4/5, X:Y = 5/6, Y:Z = 6/7, then W:Z will be? Choices:
A) 4 : 5  B) 2 : 3  C) 4 : 7  D) 1 : 2  E) 5 : 7

Solution: Solution   W : X = 4 : 5, X : Y = 5 : 6, Y : Z = 6 : 7   âˆ´Wâˆ¶Xâˆ¶Yâˆ¶Z= 4 : 5 : 6 : 7.   Thus, W : Z = 4 : 7   4 : 7orrect Option 4 : 7
Answer: C
The difference between compound and simple interest on a particular sum of money for 3 years at 6 and 2/3% p.a is Rs.184. What is the sum? Options:
A) 13000 B) 13500 C) 14000 D) 14500 E) 15000

Solution: P = (184*10^6) / (6 2/3 * 6 2/3*(300*6 2/3))   ==> 13500   ANSWER 13500
Answer: B
Four dice are thrown simultaneously. Find the probability that all of them show the same face. Choose the correct choice from the following answers.
A) 1/45	B) 1/35	C) 1/216	D) 4/216	E) 6/216

Solution: The total number - four dice simultaneously is:   =6×6×6×6=64=6×6×6×6=64   n(S)=64n(S)=64   Let X be the event that all dice   X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}   n(X)=6n(X)=6   Hence required probability, = 6/6^4   ==>1/216   ANSWER 1/216
Answer: C
A shopkeeper buys mangoes at the rate of 4 a rupee and sells them at 2 a rupee. Find his net profit or loss percent? Answers: A) 100 % B) 200 % C) 250% D) 300% E) 50%

Solution: The total number of mangoes bought by the shopkeeper be 12.   If he buys 4 a rupee, his CP = 3   He selling at 2 a rupee, his SP = 4   Profit = SP - CP = 4 - 2= 
4 - 2 = 2
2   Profit Percent= 2/2 * 100= 
2/2 * 100 = 100
100 %   100 %nswer:100 %
Answer: A
A carpenter makes 2 bunk beds every day. A military school needs to organize a place to sleep for 143 soldiers. If there are 5 carpenters working on the job, how many whole days in advance should they receive the order and start working in order to finish the right number of beds assuming that each bunk- bed is used by two soldiers?
Choose the correct choice from the following answers: A) 3. B) 4. C) 5. D) 6. E) 7.

Solution: I believe it is C because if 1C makes 3 beds in 1 day then:   1C's rate = 3/1   So 5c's = 3/1 * 5= 
3/1 * 5 = 15
15/1= 
15/1 = 15
15 beds in a day.   Since we have 173 soldiers who need beds and bunk beds come in pairs, 72 is the least amount of beds needed.   Time= Amount / Rate   Time = 72 / (15/1) = 72/15, simplifying we get 72/15 = 24/5 = 3.8   So, in order for the carpenters to be able to finish they need 4 whole days. At first I made the mistake of thinking how many whole days it took them to finish (as in ignore the partial day) but the prompt clarifiesdays in advance, meaning how many days would they need to finish so even if they finish early, theyusedthat day.   4.
Answer: B
If (n + 2)! = 2550 (n!); find ’n’  Select:
A) 38  B) 35  C) 49  D) 43  E) 34

Solution: (n + 2)! = 2550(n!)   (n + 2)(n + 1)(n!) = 2550(n!)   (n + 2)(n + 1) = 2550   2n + 3n + 2 - 2550 = 0   2n + 3n - 2548 = 0   2n + 52n - 49n - 2548 = 0   n(n - 49)(n + 52) = 0   n = 49 or n = - 52   ANSWER:49
Answer: C
What is the place value of 5 in the numeral 4529  Choose the correct choice
A) 200  B) 300  C) 500  D) 600  E) 700

Solution: 5*100= 
5*100 = 500
500   ANSWER 500
Answer: C
In a certain country, 60 percent of the population likes basketball, and 34 percent of the population likes both basketball and golf. What percentage of the people who like basketball also like golf?	Answers:
A) 20%	B) 33%	C) 40%	D) 57%	E) 67%

Solution: Correct Answer: (D).   Since this is a percent problem without concrete numbers, we can assign our own. If we assume that there are 100 people in the country, then 60 people like basketball, and 34 people like basketball and golf. We’re looking for people who like both divided by people who like basketball, so 34/60 = 57%, or choice 57%.
Answer: D
An auction house charges a commission of 16% on the first $50,000 of the sale price of an item, plus 10% on the amount of of the sale price in excess of $50,000. What was the price of a painting for which the house charged a total commission of $24,000?	Choose the correct choice from the following options:
A) $115,000	B) $160,000	C) $210,000	D) $240,000	E) $365,000

Solution: Say the price of the house was $x, then 0.16*50,000+0.1*(x-50,000)=24,000 --> x=$210,000 (16% of $50,000 plus 10% of the amount in excess of $50,000, which is x-50,000, should equal to total commission of $24,000).   Answer: $210,000.
Answer: C
The true discount on a bill due 9 months hence at 16% per annum is Rs. 240. The amount of the bill is	Pick one:	A) 2200	B) 2240	C) 1600	D) 1354	E) None of these

Solution: Explanation:   Let P.W. be Rs.x.   Then, S.I. on Rs. x at 16% for 9 months = Rs. 240.   x Ã— 16 Ã— (9/12) Ã— (1/100) = 240 or x = 2000.   P.W. = Rs. 2000.   Sum due = P.W. + T.D. = Rs.(2000   240) = Rs. 2240.   Answer: 2240
Answer: B
If you cut a 30ft piece of wood into two pieces making one piece 4ft longer than the other. What size is the smaller piece?  Choose one.
A) 4ft
B) 6ft
C) 8ft
D) 10ft
E) 13ft

Solution: Total length is 30ft, one piece is 4ft longer (x+4), leaving the other piece to figure out (x).   (x)+ (x+4)=30   x+x+4-4=30-4   2x=26   2x/2=26/2= 
26/2 = 13
13   The piece is 13ft) 13ft.
Answer: E