MU-NLPC/Calc-aqua_rat huggingface dataset:
How many integers are between 9 and 67/5, inclusive?
Choose the correct choice from the following choices.
A) 5  B) 7  C) 9  D) 10  E) 11

Solution: 67/5 = 13.xx   We are not concerned about the exact value of 67/5 as we just need the integers.   Since the values are small, we can write down the integers.   The different integers between 9 and 67/5 would be 9, 10, 11, 12,13   Total number of integers = 5   Option 5
Answer: A
Suppose son name is 120,his brother name is 150 and his mother name is 230.find out his father's name???  Choose the correct choice from the following options.
A) 190
B) 210
C) 230
D) 240
E) 260

Solution: since difference between all name is =30   so father's name will be  230+30= 
 230+30 = 260
260.   ANSW260R:260
Answer: E
Find the average of all numbers between 3 and 86 which are divisible by 5	Pick.
A) 15  B) 20  C) 25  D) 30  E) 45

Solution: 45xplanation:   Average=(5+10+15+20+25+30+35+40+45+50+55+60+65+70+75+80+85)/17=765/17= 
765/17 = 45
45   Answer: Option 45
Answer: E
Eddy and Freddy start simultaneously from city A and they travel to City B and City C respectively. Eddy takes 3 hours and Freddy takes 4 hours to complete the journey. If the distance between City A and City B is 510 kms and City A and City C is 300 kms. What is the ratio of their average speed of travel? (Eddy: Freddy)  Choose one:
A) 8/3  B) 3/8  C) 8/5  D) 5/8  E) 34/15

Solution: Distance traveled by 34/15ddy = 510 km   Time taken by 34/15ddy = 3 hours   Average speed of 34/15ddy = 510/3= 
510/3 = 170
170 km/hour   Distance traveled by Freddy= 300 km   Time taken by Freddy = 4 hours   Average speed of Freddy = 300/4= 
300/4 = 75
75 km/hour   Ratio of average speed of 34/15ddy to Freddy= 170/75 = 34/15   Answer 34/15
Answer: E
Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A man rows to a place at a distance of 4864 km and comes back to the starting point. The total time taken by him is:  Select:	A) 600	B) 500	C) 700	D) 900	E) 800

Solution: Speed downstream = (14 + 1.2)= 
(14 + 1.2) = 15.2
15.2 kmph   Speed upstream= (14 - 1.2)= 
(14 - 1.2) = 12.8
12.8 kmph   Total time taken=4864/15.2+4864/12.8 = 320 + 380= 
320 + 380 = 700
700 hours   Answer is 700.
Answer: C
The average attendance in a school for the first 4 days of the week is 30 and for the first 5 days of the week is 32. The attendance on the fifth day is  Choose the most appropriate option
A) 32 B) 40 C) 38 D) 36 E) None of the above

Solution: Attendance on the fifth day = 32 × 5 – 30 × 4   = 160 – 120 = 40   Answer 40
Answer: B
A car is traveling 72 kilometers per hour. How many meters does the car travel in one minute? Choose the correct option
A) 1,200 meters / minute B) 1,300 meters / minute C) 1,450 meters / minute D) 1,550 meters / minute E) 1,650 meters / minute

Solution: Convert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify   72 kilometers per hour = 72 km/hr   = (72 * 1000 meters) / (60 minutes) = 1,200 meters / minute   correct answer 1,200 meters / minute
Answer: A
If X = 2 + 1/(1+1/(1-1/2))then the value of 7x+7/3?
Choose the correct answer
A) 9 2/3 B) 10 1/3 C) 11 D) 11 2/3 E) 18

Solution: X = 2 + 1/(1+1/(1-1/2))   = 2 + 1/(1+2)   = 2 + 1/3   X = 7/3 ==> 7X + 7/3 => 7(7/3) + 7/3   ==> 49/3 + 7/3   ==> 56/3   ==> 18.   18)
Answer: E
A is twice as good a workman as B and they took 6 days together to do the work B alone can do it in. Choose the correct choice from the following options:
A) 18 days
B) 12 days
C) 29 days
D) 25 days
E) 27 days

Solution: WC = 2:1   2x + x = 1/6   x = 1/18 => 18 days   18 daysNSWER:18 days
Answer: A
For an employee to qualify for early retirement at a certain company, the sum of the employee’s age and years of service must be at least 60, If Sue was K years old when she was hired by the company, what is the minimum age at which she could possibly qualify for early retirement. Choose the correct choice from the following
A) K+35	B) 2K+35	C) (60+K)/2	D) (70-K)/2	E) 2(70-K)

Solution: Say Sue was hired when she was already 60 years old (k=60), then she could retire right away, at the age of 60. Now, plug k=60 in the answer choices and see which yields 60. Only C fits.   Answer: (60+K)/2.
Answer: C
Jill is dividing her 14-person class into two teams of equal size for a basketball game. If no one will sit out, how many different match-ups between the two teams are possible?  Choose the correct answer
A) 1110  B) 1125  C) 1716  D) 2152  E) 1630

Solution: With 14 players, the process of figuring out how many groups of 7 can be formed is pretty straight-forward....   14C7 = 14!/(7!7!) = 3432 possible groups of 7   Once forming that first group of 7, the remaining 7 players would all be placed on the second team by default.   The 'twist' is that the two teams of 7 canshow upin either order:   1716
Answer: C
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.  Select
A) 125/128 B) 125/125 C) 125/126 D) 125/121 E) 125/122

Solution: Required probability = 1 - 1/126   = 125/126   Answer: 125/126
Answer: C
If a code word is defined to be a sequence of different letters chosen from the 10 letters A, B, C, D, E, F, G, H, I, and J, what is the ratio of the number of 6-letter code words to the number of 5-letter code words? Select
A) 5 to 4  B) 3 to 2  C) 2 to 1  D) 5 to 1  E) 6 to 1

Solution: Number of ways to form 6-letter code: 10!/4! = 10*9*8*7*6*5   Number of ways to form 5-letter code: 10!/5! = 10*9*8*7*6   Ratio: 5 to 1   Answer : 5 to 1
Answer: D
How many terms are in the G.P. 3, 6, 12, 24, ......., 384,768
Choose the most appropriate option:
A) 8
B) 9
C) 67
D) 5
E) 2

Solution: Explanation:   Here a = 3 and r = 6/3= 
6/3 = 2
2. Let the number of terms be n.   Then, t= 768 => a * r^(n-1) = 768   => 3 * 2^(n-1) = 768 => 2^(n-1) = 256 = 2^(8)   => n-1 = 8 => n = 9.   Answer: 9
Answer: B
If the selling price of 50 articles is equal to the cost price of 40 articles, then the loss or gain percent is? Choose the correct choice from the following answers:
A) 20
B) 98
C) 66
D) 54
E) 12

Solution: Let C.P. of each article be Re. 1.   Then, C.P. of 50 articles = Rs. 50;   S.P. of 50 articles = Rs. 40.   Loss % = 10/50 * 100= 
10/50 * 100 = 20
20%   20nswer: 20
Answer: A
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is: Choose the correct choice from the following:
A) 50 km
B) 56 km
C) 60 km
D) 70 km
E) 80 km

Solution: Let the actual distance travelled be x km.   x/10 = (x+20)/14   14x = 10x + 200   4x = 200   x = 50 km.   answer :50 km
Answer: A
Gold is 19 times as heavy as water and copper is 9 times as heavy as water. In what ratio should these be mixed to get an alloy 15 times as heavy as water?  Choose the correct choice from the following answers.
A) 1:2	B) 3:2	C) 4:1	D) 5:2	E) 6:5

Solution: G = 19W   C = 9W   Let 1gm of gold mixed with x gm of copper to get 1+x gm of the alloy   1gm gold + x gm copper = x+1 gm of alloy   19W+9Wx = x+1 * 15W   19+9x = 15(x+1)   x = 2/3   Ratio of gold with copper = 1:2/3 = 3:2   Answer is 3:2
Answer: B
The average height of 35 boys in a class was calculated as 180cm. It has later found that the height of one of the boys in the class was wrongly written as 156 cm whereas his actual height was 106 cm. Find the actual average height of the boys in the class (Round off your answer to two decimal places).	Options: A) 168.58 cm B) 158.58 cm C) 179.29 cm D) 168.58 cm E) 178.58 cm

Solution: Calculated average height of 35 boys = 180 cm.   Wrong total height of 35 boys = 180 * 35 cm. This was as a result of an actual height of 106 cm being wrongly written as 156 cm. Correct total height of 35 boys = 180 * 35 cm - 156 cm + 106 cm   = 180 * 35 cm - 156 cm + 106 cm/35 = 180 cm - 50 /35 cm   = 180 cm - 1.42 cm = 178.58 cm.   ANSW178.58 cmR:178.58 cm
Answer: E
The average of four consecutive even numbers is one-fourth of the sum of these numbers. What is the difference between the first and the last number?
Choose the correct answer:
A) 4 B) 6 C) 2 D) Cannot be determined E) None of these

Solution: Let the four consecutive even nos. be 2x, 2x + 2, 2x + 4 and 2x + 6 respectively.   Reqd difference = 2x + 6 – 2x = 6   Answer 6
Answer: B
A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is?
Choose the correct choice:
A) 3.34 B) 3.36 C) 3.39 D) 3.35 E) 3.31

Solution: 3.34rea of the path = 3.34rea of the outer circle - 3.34rea of the inner circle = ∏{4/2 + 25/100}2 - ∏[4/2]2   = ∏[2.252 - 22] = ∏(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) }   = (3.14)(1/4)(17/4) = 53.38/16   = 3.34 sq m   3.34nswer: 3.34
Answer: A
A car covers a distance of 526 km in 9 hours. Find its speed? Choose the correct choice from the following choices
A) 104 kmph B) 289 kmph C) 58 kmph D) 277 kmph E) 177 kmph

Solution: 526/9   = 58 kmph   Answer: 58 kmph
Answer: C
How many words can be formed by using all letters of the word “BIHAR”  Pick one:
A) 523	B) 190	C) 145	D) 450	E) 120

Solution: The word BIHAR contains 5 different letters.   Required number of words = 5p5 = 5! = (5x4x3x2x1) = 120   Ans: 120
Answer: E
A group of men decided to do a work in 40 days, but 5 of them became absent. If the rest of the group did the work in 60 days, Find the original number of men?	Choose the correct choice from the following answers.
A) 60	B) 15	C) 40	D) 10	E) 25

Solution: Original number of men = 5*60 / (60-40)= 
5*60 / (60-40) = 15
15   Answer is 15
Answer: B
Hari purchased 20 dozen notebook at Rs. 48 per dozen. He sold 8 dozen at 10% profit and remaining 12 dozen with 20% profit. What is his profit percentage in the transaction? Choose one:
A) 8%
B) 15%
C) 16%
D) none of the above
E) Cannot be determined

Solution: Explanation :   C.P of 20 dozen = Rs.(48 x 20) = Rs.960   C.P of 8 dozen = Rs. (48 x8) = Rs. 384.   C.P of 12 dozen =Rs. (960 384) = Rs. 576   Total S.P = Rs. (110/100 x 384 +120/100 x 576) = Rs.1113.60   Profit % = (153.60/960 x 100)% =16%   Answer : 16%
Answer: C
If a 3-member subcommittee is to be formed from a certain 4-member committee, how many different such subcommittee are possible?  Choose one.
A) 4  B) 18  C) 20  D) 108  E) 216

Solution: 4nother way:   1st member can be selected in 4 ways   2nd can be selected in 3 ways   3rd can be selected in 2 ways   So total ways : 24   But to avoid the similar scenarios 24/3!=4   4
Answer: A
Anand and Deepak started a business investing Rs. 3500 and Rs. 7000 respectively. Out of a total profit of Rs. 2000, Deepak's share is: Choose the correct choice.
A) 1333.3	B) 2687.1	C) 1200.6	D) 1580.2	E) 2671

Solution: Ratio of their shares = 3500 : 7000 = 1:2   Deepak's share = 2000* 2/3 = Rs. 1333.3.   1333.3nswer: 1333.3
Answer: A
Before lunch, a painter can paint a wall at a rate of r square feet per minute. The same painter, after lunch and a cup of coffee, can paint the same wall at a rate r + 1 square feet per minute, and the same wall would be finished in 30 seconds less time. What is the value of r? Choose one.
A) 1/3 B) 3 C) 1/2 D) 1 E) 2

Solution: Convert 30 seconds to 1/2 minute   Equation: 1/r = 1/(r + 1) + 1/2   Plug options into the equation:   1 fits:  1/1= 
 1/1 = 1
1/(1 + 1) + 1/2   Answer: 1
Answer: D
A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing. If the poles of the fence are kept 10 metres apart, how many poles will be needed ?  Choose the most appropriate option.
A) 28  B) 56  C) 57  D) 58  E) None of these

Solution: Solution   Perimeter of the plot = 2(90 + 50) = 280 m.   ∴ Number of poles = [280/10= 
280/10 = 28
28m 28nswer 28
Answer: A
The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 20,000 is made?  Pick one.
A) 328897  B) 120000  C) 877888  D) 116000  E) 188871

Solution: The value of the machine after two years = 0.8 * 0.8 * 1,50,000 = Rs. 96,000   SP such that a profit of Rs. 20,000 is made = 96,000 + 20,000 = Rs. 1,16,000   Answer: 116000
Answer: D
A truck covers a distance of 240 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 0 km more than that travelled by the truck ?
Choose the correct choice from the following choices:  A) 6 hours  B) 5 hours  C) 7 hours  D) 8 hours  E) None

Solution: Explanation :   Speed of the truck = Distance/time = 240/8= 
240/8 = 30
30 kmph   Now, speed of car= (speed of truck + 18) kmph = (30 + 18)= 
(30 + 18) = 48
48 kmph   Distance travelled by car= 240 + 0= 
240 + 0 = 240
240 km   Time taken by car= Distance/Speed = 240/48= 
240/48 = 5
5 hours.   Answer –5 hours
Answer: B
Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 150 milliliters of solution X to create a solution that is 25 percent alcohol by volume?
Pick one.
A) 250/3  B) 500/3  C) 400  D) 450  E) 600

Solution: we know that X is 10% , Y is 30% and W.Avg = 25% . what does this mean with respect to W.Avg technique ?   W.Avg is 1 portion away from Y and 3 portion away from X so for every 1 portion of X we will have to add 3 portions of Y.   If X = 150 then Y = 450   ANSWER:450
Answer: D
If the side length of Square B is three times that of Square A, the area of Square B is how many times the area of Square A?
Choose the correct choice from the following answers
A) 9 B) 8 C) 6 D) 3 E) 2

Solution: Let x be the side length of Square A.   Then the area of Square A is x^2.   The area of Square B is (3x)^2=9x^2.   The answer is 9.
Answer: A
5 cats are about to jump on 5 different mice. What is the probability that exactly one cat will jump on a single mouse?  Choose the correct answer:
A) 5*5
B) 1/5!
C) 5!/5^5
D) 5!/5^2
E) 1/5^5

Solution: Each cat out of 5 has 5 options, hence total # of outcomes is 5^5;   Favorable outcomes will be 5!, which is # of ways to assign 5 different mice to 5 cats:   1-2-3-4-5 (mice)   A-B-C-D-E (cats)   B-A-C-D-E (cats)   B-C-A-D-E (cats)   ...   So basically # of arrangements of 5 distinct objects: 5!.   P=favorable/total=5!/5^5   Answer: 5!/5^5.
Answer: C
A dishonest dealer professes to sell goods at the cost price but uses a weight of 800 grams per kg, what is his percent? Choose the correct option: A) 29% B) 25% C) 95% D) 26% E) 95%

Solution: 800 --- 200   100 --- ? => 25%   Answer: 25%
Answer: B
What is the minimum number of square marbles required to tile a floor of length 5 metres 78 cm and width 3 metres 06 cm?  Choose the correct answer:  A) 153  B) 187  C) 540  D) 748  E) 546

Solution: The marbles used to tile the floor are square marbles.   Therefore, the length of the marble=width of the marble.the length of the marble=width of the marble.   As we have to use whole number of marbles, the side of the square should a factor of both 5 m 78 cm and 3m 06. And it should be the highest factor of 5 m 78 cm and 3m 06.   5 m 78 cm = 578 cm and 3 m 06 cm = 306 cm.   The HCF of 578 and 306 = 34.   Hence, the side of the square is 34.   The number of such square marbles required,   =578×306/34×34   =153 marbles   Option(153)
Answer: A
A man rows downstream 30 km and upstream 18 km, taking 5 hours each time. What is the velocity of the stream (current)? Choose one:
A) 1.2 km/hr  B) 1.5 km/hr  C) 2.5 km/hr  D) 1.8 km/hr  E) None of these

Solution: 30/(B+5) = 18/(B-5) = 5   ? B+5 = 6 km/hr   B - 5 = 3.6 km/hr   ? 5 = 1.2 km/hr   1.2 km/hrnswer: 1.2 km/hr.
Answer: A
Boy purchased two flats for Rs.5,00,000. On one he gains 15 % while on the other he losses 15%. How much does he gain or lose?	Choose the correct option: A) 2% B) 2.12% C) 2.25% D) 2.30% E) 2.50%

Solution: Generally in such cases, there is always loss.   So always remember, when two materials are sold and if one material gets profit and the other gets a loss, then use the trick shown below to calculate the loss.   Loss% = 2.25%ommon loss and gain% 2 = x 2   10 10   Therefore, here common loss and gain % = 15%   Hence,   Loss% = 15 2 = 2.25%   2.25%
Answer: C
If a is a positive integer, and if the units' digit of a^2 is 4 and the units' digit of (a + 1)^2 is 1, what is the units' digit of (a + 2)^2 ?
Select.
A) 0  B) 2  C) 4  D) 6  E) 8

Solution: A for me.   _1² = _1   _2² = _4   _3² = _9   _4² = _6   _5² = _5   _6² = _6   _7² = _9   _8² = _4   _9² = _1   _0² = _0   On the list, the only number that squared has the units digit = 4 preceding a number that squared has the units digit = 1 is the _8.   So, a = _8, that has square 4. The next square is 1 andnext nextsquare is 0.
Answer: A
On my sister's 15th birthday, she was 159 cm in height, having grown 6% since the year before. How tall was she the previous year? Choices
A) 150 cm  B) 140 cm  C) 142 cm  D) 154 cm  E) None of these

Solution: Explanation :   Given that height on 15th birthday = 159 cm and growth = 6%   Let the previous year height = x   Then height on 15th birthday = x ×100+6/100=x×106/100   ⇒159 = x × (106/100)   ⇒�x=159×100/106=1.5×100=150;cm   150 cmnswer : Option 150 cm
Answer: A
Find the ratio in which rice at Rs. 7.20 a kg be mixed with rice at Rs. 5.70 a kg to produce a mixture worth Rs. 6.30 a kg.	Choose the correct choice from the following options:  A) 1 : 3.  B) 2 : 3.  C) 2 : 4  D) 1 : 4  E) 3 : 3.

Solution: Cost of 1 kg of 1st kind=720 p   Cost of 1 kg of 2nd kind=570 p   Mean Price=630 p   Cost of 1 kg of 1st kind - Mean Price=720-630= 
720-630 = 90
90   Cost of 1 kg of 2nd kind- Mean Price=570-630=60   Required ratio = 60 : 90 = 2 : 3.   Answer:2 : 3.
Answer: B
The last day of a century cannot be
Choose the correct answer
A) Monday	B) Wednesday	C) Tuesday	D) sunday	E) Friday

Solution: 100 years contain 5 odd days.   Last day of 1st century is Friday.   200 years contain (5 x 2) 3 odd days.   Last day of 2nd century is Wednesday.   300 years contain (5 x 3) = 15 1 odd day.   Last day of 3rd century is Monday.   400 years contain 0 odd day.   Last day of 4th century is Sunday.   This cycle is repeated.   Last day of a century cannot be Tuesday or Thursday or Saturday.   Answer: Option Tuesday
Answer: C
A train starts full of passengers at the first station it drops 1/3 of the passengers and takes 280 more at the second station it drops one half the new total and takes twelve more. On arriving at the third station it is found to have 246 passengers. Find the no of passengers in the beginning?  Choose the correct choice from the following options:
A) 292  B) 180  C) 192  D) 282  E) 168

Solution: Let no of passengers in the beginning be X   After first station no passengers=(X-X/3)+280=2X/3 +280   After second station no passengers =1/2(2X/3+280)+12   1/2(2X/3+280)+12=246   2X/3+280=2*234= 
2*234 = 468
468 - 280= 
468 - 280 = 188
188   2X/3=188   X=282. So the answer is option 282) 282.
Answer: D
A man goes downstream at 12 kmph, and upstream8 kmph. The speed of the stream is  Choose the correct choice from the following options.
A) 2kmph  B) 4kmph  C) 16kmph  D) 2.5kmph  E) 26kmph

Solution: Speed of the stream = 1/2(12-8)kmph   =2kmph.   correct option 2kmph
Answer: A
Siddharth wants to borrow Rs.9000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction? Options: A) s.21.60 B) s.32.40 C) s.21.18 D) s.21.98 E) s.21.29

Solution: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.9,000   He lend the same amount for C.I at 6% p.a. for two years.   => Siddharth's income = C.I - S.I   = p[1 + r/ 100]n - p - pnr/100   = p{ [1 + r/ 100]2 - 1 - nr/100   = 9,000{ [1 + 6/100]2 - 1 - 12/100}   = 9,000 {(1.06)2- 1 - 0.12} = 9,000(1.1236 - 1 - 0.12)   = 9,000 (0.0036) = 9 * 3.6   = Rs.32.40   Answer: s.32.40
Answer: B
How many such pairs of letters are there in the word EXPRESSION which have as many letters between them in the word as in the alphabet ?	Choose the correct choice from the following choices:
A) 4  B) 5  C) 3  D) 2  E) 1

Solution: (E,N)   (P,S)   (O.N)   (X,S)   4NSWER:4
Answer: A
What is the value of 100p2 ?	Answers:	A) 9801	B) 12000	C) 5600	D) 9900	E) None of these

Solution: Explanation :   100p2 = 100 x 99 = 9900. Answer : Option 9900
Answer: D
What is the greatest value of n such that 18^n is a factor of 17! ? Select:
A) 1 B) 2 C) 3 D) 4 E) 5

Solution: Another way to solve this question :   We know that 18 = 2 *3^2.   Hence, we need to find total number of 3s in 18! ( As out of 3 and 2 , we will have count of 3 least)   No. of 3s = 18/3= 
18/3 = 6
6/3= 
6/3 = 2
2.   Add the numbers in Bold, you will get total number of 3s= 8.   Hence, total number of 3^2 = 8/2= 
8/2 = 4
4.   Hence, answer is 3. 3
Answer: C
A rectangular box of volume V has width, depth and height in the ratio of 2:2:1 (in that order). What is the width as a function of V?	Choose the correct choice:
A) (3V/2)^(1/4)	B) (7V/6)^(1/4)	C) (9V/2)^(1/4)	D) (16V/4)^(1/4)	E) (4V/2)^(1/4)

Solution: We are given width = 2, depth = 2, height = 1.   Then Volume V = Width x Depth x Height = 2*2*1= 
2*2*1 = 4
4   i.e. V= 4   The correct option should result in 2 (the width) on substituting the value of V=4.   Checking options with V=4:   A) (3V/2)^(1/4) = (6/2)^(1/4) = 3^(1/4) INCORRECT ANSWER   B) (7V/6)^(1/4) = (28/6)^(1/4) INCORRECT ANSWER   C) (9V/2)^(1/4) = (36/2)^(1/4) = 18^(1/4) INCORRECT ANSWER   (16V/4)^(1/4)) (16V/4)^(1/4) = (64/4)^(1/4) = 16^(1/4) = 2 CORRECT ANSWER   E) (4V/2)^(1/4) = (16/2)^(1/4) = 8^(1/4) INCORRECT ANSWER   Answer: Option (16V/4)^(1/4)
Answer: D
A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1Â½ times of the previous in how many days will he cover 840 km ?
Options:
A) 25 days	B) 75 days	C) 35 days	D) 15 days	E) 05 days

Solution: Explanation:   Distance d = 1200km   let S be the speed   he walks 15 hours a day(i.e 24 - 9)   so totally he walks for 70 x 15 = 1050hrs.   S = 1200/1050 => 120/105 = 24/21 => 8/7kmph   given 1 1/2 of previous speed   so 3/2 * 8/7= 24/14 = 12/7   New speed = 12/7kmph   Now he rests 10 hrs a day that means he walks 14 hrs a day.   time = 840 x 7 /12 => 490 hrs   => 490/14= 
490/14 = 35
35 days   So he will take 35 days to cover 840 km.   Answer: 35 days
Answer: C
A boy gets some rupees from his mother and spends them on 5 stores. He spends one rupee more than half of the money. How much money he had at the time of entering the shop.  Choose the most appropriate option
A) 60	B) 61	C) 62	D) 63	E) 64

Solution: (x+2)/(2^n)=2   where n=no. of shops   so we get ,(x+2)/(2^5)=2   x=62   ANSWER:62
Answer: C
If apples cost x dollars per m dozen, how many dollars will it cost to buy n apples?	Options
A) xn/(12m)	B) xn/m	C) m/(xn)	D) 12m/(xn)	E) 12mn/x

Solution: let it 2 dollars for 2 dozens(24) and we are asked to find the value n apples...let n be 4...   In order to buy 24 apples it took 2 dollars...then for 4 apples it'll take 4*2/12*2 = 1/3.. i.e. n*x/12*m.   xn/(12m)nswer: option xn/(12m) is correct answer...
Answer: A
Interest Rate: 4% monthly Starting Balance: 124 Time Passed: 4 months How much interest has accrued if calculated as compound interest? What is the new total balance?  Choose the correct choice from the following answers:
A) 21 & 145	B) 22 & 146	C) 23 & 145	D) 20 & 140	E) None

Solution: Compound Interest: Total Balance = P(1 + R)T P = principle = starting balance = $124 R = interest rate = 4% T = time = 4 years Total balance = principle × (1 + interest rate)time = 124 × (1 + (4 / 100))4 = 145 Interest accrued = total balance - starting balance = 145 - 124= 
145 - 124 = 21
21   21 & 145nswer 21 & 145
Answer: A
Find the perimeter and area of a square of side 19 cm.
Answers:  A) 324  B) 361  C) 400  D) 441  E) 484

Solution: We know that the perimeter of square = 4 Ã— side   Side= 19 cm   Therefore, perimeter = 4 Ã— 19 cm = 76 cm   Now, area of the square = (side Ã— side) sq. units   = 19 Ã— 19 cmÂ²   = 361 cmÂ²   ANSWER : 361
Answer: B