MU-NLPC/Calc-aqua_rat huggingface dataset:
If the price of petrol increases by 25% and Benson intends to spend only an additional 15% on petrol, by how much % will he reduce the quantity of petrol purchased?
Options:
A) A)8% B) B)7% C) C)10% D) D)6% E) E)9%

Solution: Explanation:   8%ssume that the initia price of 1 Litre petrol = Rs.100 ,Benson spends Rs.100 for petrol,   such that Benson buys 1 litre of petrol   8%fter the increase by 25%, price of 1 Litre petrol = 100 × (100+25)/100 = Rs.125   Since Benson spends additional 15% on petrol,   amount spent by Benson = 100× (100+15)/100 = Rs.115   Hence Quantity of petrol that he can purchase = 115/125 Litre   Quantity of petrol reduced = (1−115/125) Litre   Percentage Quantity of reduction = (1−115125)/1 × 100 = 10/125 × 100 = 105 × 4 = 2 × 4 = 8%   8%nswer: Option 8%
Answer: A
If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 6 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?  Choose the correct option
A) 1/9	B) 29/180	C) 26/143	D) 2/15	E) 39/121

Solution: 50 apprentices can finish the job in 4 hours,thus:   10 apprentices can finish the job in   4*5= 
  4*5 = 20
20 hours;   In 1 hour 10 apprentices can finish 1/20 of the job.   30 journeymen can finish the same job in 4,5 hours,thus:   15 journeymen can finish the job in  6*2= 
 6*2 = 12
12 hours;   In 1 hour 15 journeymen can finish 1/12 of the job.   Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/12=2/15 of the job.   Answer: 2/15.
Answer: D
A taxi leaves Point A 3 hours after a bus left the same spot. The bus is traveling 30 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.  Choose the correct choice from the following
A) 60	B) 72	C) 48	D) 36	E) 64

Solution: Let the speed of bus be v - 30, speed of taxi be v   The bus travelled a total of 6 hrs and taxi a total of 3 hrs.   Hence 6 * (v-30) = 3v   6v - 180 = 3v   3v = 180   v = 60 mph   60
Answer: A
What is the 8th digit to the right of the decimal point in the decimal equivalent of 73/11?
Answers:  A) 1  B) 3  C) 4  D) 5  E) 2

Solution: 73/11 = 6.6363....   63 is non-terminating repeating decimal.   The 8th digit to the right of decimal point will be 3.   Answer 3
Answer: B
In a certain deck of cards, each card has a positive integer written on it. In a multiplication game, a child draws a card and multiples the integer on the card by the next larger integer. If each possible product is between 28 and 200, then the least and greatest integers on the card could be  Choose the correct answer:
A) 3 and 15	B) 3 and 20	C) 5 and 13	D) 4 and 14	E) 5 and 14

Solution: There child draws one number then multiplies that number by the number above it. The number must be more than 28 and less than 200.   x * (x+1)   Answer gives us choices of 3,4 and 5 (JUST ABOVE 28)   3*(3+1)= 
3*(3+1) = 12
12 <- WRONG   4*(4+1)= 
4*(4+1) = 20
20 <- WRONG   5*(5+1)= 
5*(5+1) = 30
30 <- CORRECT AS IT IS ABOVE 28   Answer gives us choices 13,14,15 and 20 (BELOW 200)   Immediately by knowing squares you should be able to rule out 15 (225) and 20 (400). And common sense dictates that as 14^2 is 196 that 14*(14+1) is above 200.   13*(13+1)= 
13*(13+1) = 182
182 <- 5 and 13ORRE5 and 13T   Answer is 5 and 13) 5 and 13
Answer: C
Marcus deposited $8,000 to open a new savings account that earned five percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Marcuss account one year after the account was opened? Choose one.
A) $8,200 B) $8,205 C) $8,400 D) $8,405 E) $8,500

Solution: Approach #1:   5 percent annual interest compounded semi-annually --> 2.5% in 6 moths.   For the first 6 moths interest was 2.5% of $8,000, so $200;   For the next 6 moths interest was 2.5% of $8,000, plus 2.5% earned on previous interest of $200, so $200+$5=$205;   Total interest for one year was $200+$205  200+ 5= 
  200+ 5 = 205
$205;   Total interest for one year was $200+$205=$405, hence balance after one year was $8,000+ $405 200+ 205= 
 200+ 205 = 405
$405, hence balance after one year was $8,000+ $405=$8,405.   Answer: $8,405.
Answer: D
If a is the interest on y and y is the interest on z, the rate and time is the same on both the cases. What is the relation between a, y and z?  Options
A) Y^2 = aZ	B) Y^3 = aZ	C) Y^3 = aY	D) Y^1 = aZ	E) Z^3 = aZ

Solution: a = (Y*NR)/100 Y = (Z*NR)/100   a/Y = NR/100 Y/Z = NR/100   a/Y = Y/Z   Y^2 = aZ   ANSWER:Y^3 = aZ
Answer: B
The table shows the number of calls received by each of five operators during each of 4 one-hour periods. For which operator was the standard deviation of the numbers of calls received during these 4 periods the least  Choose one.
A) Operator A: 3, 7, 7, 3 B) Operator B: 4, 5, 5, 6 C) Operator C: 8, 2, 5, 5 D) Operator D: 6, 4, 4, 6 E) Operator E: 3, 4, 5, 8

Solution: Operator E: 3, 4, 5, 8   it has 2 numbers right at the average, Operator E: 3, 4, 5, 8 has none.
Answer: E
On Sunday, Bill ran 4 more miles than he ran on Saturday. Julia did not run on Saturday, but she ran twice the number of miles on Sunday that Bill ran on Sunday. If Bill and Julia ran a total of 32 miles on Saturday and Sunday, how many miles did Bill run on Sunday?  Choose the correct choice from the following answers.
A) 5  B) 6  C) 7  D) 8  E) 9

Solution: Let Bill run x on saturday, so he will run x+4 on sunday..   Julia will run 2*(x+4) on sunday..   totai= x+x+4+2x+8=32..   4x+12=32..   x=5..   ans =x+4=5+4= 
5+4 = 9
9   Answer 9
Answer: E
If a > 1 and b = 2^(a −1), then 4^a =
Choose the correct option:
A) 16b^2 B) 4b^2 C) b^2 D) b^2/4 E) b^2/16

Solution: If a > 1 and b = 2^(a −1), then 4^a   Given a>1, so let's assume a=2   b=2^(a-1) = 2^(2-1) = 2, so b=2   hence, 4^a = 4^2 = 16   only 1 ans. choice can satisfy this:   A) 16b^2 --> clearly > 16   B) 4b^2 --> 4*2^2 = 16(we can stop after this as there can be only 1 right answer)   C) b^2 --> clearly < 16   D) b^2/4 --> clearly < 16   E) b^2/16 --> clearly < 16   Ans. 4b^2) 4b^2
Answer: B
A man can row a boat at 20 kmph in still water. If the speed of the stream is 8 kmph, what is the time taken to row a distance of 60 km downstream?  Choices:
A) 30/18
B) 30/29
C) 30/14
D) 30/13
E) 30/82

Solution: Speed downstream = 20 + 8= 
20 + 8 = 28
28 kmph.   Time required to cover 60 km downstream= d/s = 60/28   = 30/14 hours.   Answer:30/14
Answer: C
A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 500. How much did he have with him in the beginning? Pick one.
A) s 200 B) s 1250 C) s 300 D) s 450 E) s 550

Solution: Suppose the amount in the beginning was Rs ’x’   Money spent on clothes = Rs 1x/3 s 1250alance = Rs 2x/3   Money spent on food = 1/5 of 2x/3 = Rs 2x/15   s 1250alance = 2x/3 - 2x/15 = Rs 8x/15   Money spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5   Therefore 2x/5 = 500 = 1250   ANSWER:s 1250
Answer: B
If a store owner increases a product’s price by 20 percent and then increases this price by another 15 percent, what percent of the original price is the total price increase?  Options:	A) 20%	B) 35%	C) 38%	D) 65%	E) 135%

Solution: let the initial price be 100   1st increase =20 % the price now is 120   2nd increase of 15% on 120 =18   final price =138, total increase =38%   ANSWER:38%
Answer: C
Today is Peter's birthday. One year, from today he will be twice as old as he was 9 years ago. How old is Peter today ? Choose the correct choice from the following answers:
A) 25 years
B) 19 years
C) 17 years
D) 23 years
E) 21 years

Solution: let Peter's age=xx+1=2(x-9)x=19ANSWER:19 years
Answer: B
In a certain game, you perform three tasks. You flip a coin, and success would be tail. You roll a single die, and success would be a six. You pick a card from a full playing-card deck, and success would be picking a spades card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning? Choose the correct choice from the following choices:
A) 11/16  B) 23/48  C) 15/32  D) 14/36  E) 17/56

Solution: The answer is 23/48   Probability of just one enent will be happining   So, Probability heads=1/2   Probability number 6 =1/6   Probability picking a spades card =1/4   so, Probability win by getting tails= 1/2*5/6*3/4 = 15/48   Probability win by getting number 6 = 1/2*1/6*3/4 = 3/48   Probability win by picking a spades card =1/2*5/6*1/4=5/48   Probability wining= 15/48+3/48+5/48 =23/48
Answer: B
Kathleen can paint a room in 3 hours, and Anthony can paint an identical room in 4 hours. How many hours would it take Kathleen and Anthony to paint both rooms if they work together at their respective rates?	Choose one:
A) 8/15  B) 4/3  C) 15/8  D) 24/7  E) 15/4

Solution: (1/3 + 1/4)t=2   t=24/7   Answer: 24/7
Answer: D
The marks obtained by Vijay and Amith are in the ratio 4:4 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? Choose the correct choice from the following choices
A) 3:2  B) 6:1  C) 6:5  D) 6:2  E) 6:3

Solution: 4:4   3:2   -------   12:12:8   12:8   3:2   3:2nswer: 3:2
Answer: A
A work as fast as B. If B can complete a work in 24days independently,the number of days in which A and B can together finish the work in? Choose the correct option
A) 2days
B) 3days
C) 8days
D) 5days
E) 6days

Solution: Ratio of rates of working of A and B = 2:1   ratio of times taken = 1:2   A's 1day work = 1/12   B's 1day work = 1/24   A+B 1day work = 1/12 + 1/24  +  1= 
 +  1 = 1
1/12 + 1/24= 3/24 = 1/8   A and B can finish the work in 8days   Answer is 8days
Answer: C
one person Tharak speed with the current is 15 km/hr and the speed of the current is 6 km/hr. Tharak's speed against the current is:	Select
A) 0 km/hr
B) 1 km/hr
C) 2 km/hr
D) 3 km/hr
E) 4 km/hr

Solution: Man's speed with the current = 15 km/hr   => speed of the man + speed of the current = 15 km/hr   speed of the current is 6 km/hr   Hence, speed of the man = 15-6= 
15-6 = 9
9 km/hr   man's speed against the current= speed of the man - speed of the current   = 9-6= 
9-6 = 3
3 km/hr   ANSWER:3 km/hr
Answer: D
An investor bought 200 shares of stock in ABCD company in 1990. By 1992, the investment was worth only 2/3 of its original value. By 1995, the 200 shares were worth only 1/5 of their value in 1990. By what percent did the value of the investment drop from 1992 to 1995?
Choose the correct choice from the following choices:
A) 16 2/3%	B) 70%	C) 33 1/3%	D) 50%	E) 66 2/3%

Solution: Let price of each share in 1990 = X.   Total cost in 1990 = 200X   Now Price in 1992 = 2/3 * 200X = 400/3 * X   Now price in 1995 = 1/5 *200= 
1/5 *200 = 40
40X   %Change in 1995 from 1992= [(400/3* X -40X) / (400/3 *X) ] *100 = 70%   Answer 70%
Answer: B
Pat wants to invest at the local bank that offers a rate of 10% per annum per year. If the interest is compounded half-yearly, how much will Pat have to invest to get Rs. 20000 at the end of a year?  Choose the correct choice from the following options:
A) 18,140.59
B) 18,410.95
C) 18,590.41
D) 18,950.14
E) 18,150.49

Solution: Amount = 20000; R = 10% p.a. = 5% per half-year; T = 1 year = 2 half-year   20000 = [P * (1 + 5/100)2]   P = 20000 / (1.05)2 = 18140.59   18,140.59nswer: 18,140.59
Answer: A
The parameter of a square is equal to the perimeter of a rectangle of length 16 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)  Pick
A) 23.58 cm  B) 23.17 cm  C) 28.17 cm  D) 23.77 cm  E) 23.57 cm

Solution: Let the side of the square be a cm.   Parameter of the rectangle = 2(16 + 14) = 60 cm Parameter of the square = 60 cm   i.e. 4a = 60   A = 15   Diameter of the semicircle = 15 cm   Circimference of the semicircle   = 1/2(∏)(15)   = 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places   Answer:23.57 cm
Answer: E
A train when moves at an average speed of 40 kmph, reaches its destination on time. When its average speed becomes 35 kmph, then it reaches its destination 15 minutes late. Find the length of the journey Select the correct option.
A) 40km B) 50km C) 60km D) 70km E) 80km

Solution: Difference between timings = 15 min =0.25hr.   Let the length of journey be x km.   Then,   x/35-x/40=0.25   8x - 7x = 70   x = 70km.   ANSWER:70km
Answer: D
In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (2, 0), (7, 4), and (7, -4)?  Pick one.
A) 18	B) 19	C) 20	D) 21	E) 22

Solution: The triangle is symmetric about the x-axis.   The part above the x-axis forms a triangle with a base of 5 and a height of 4.   The area of this part is (1/2)(5)(4).   We can double this to find the area of the whole triangle.   The total area is (2)(1/2)(5)(4) = 20.   The answer is 20.
Answer: C
The area of square ABCD above is 22. The shaded region is the intersection of the square and a circular region centered at C. What is the area of the shaded region?  Select the correct option.
A) 18−9/4∗π
B) 22−11/2∗π
C) 9+9/4∗π
D) 9+9/2∗π
E) 9/2−9/4∗π

Solution: =Square - Quarter circle   =22- pi*22/4   =22- pi*11/2   ANSWER:22−11/2∗π
Answer: B
If 9 is added to twice a number and this sum is multiplied by 3, the result is the same as if the number is multiplied by 4 and 13 is added to the product. What is the number?
Choose the correct answer:	A) -7	B) -8	C) -9	D) -10	E) -11

Solution: let the number be x;   3(9+2x)=4x+13;   x=-7   -7NSWER:-7
Answer: A
A man can row with a speed of 14 kmph in still water. If the stream flows at 8 kmph, then the speed in downstream is?	Choose the correct choice from the following options.
A) 22
B) 28
C) 20
D) 82
E) 34

Solution: M = 14   S = 8   DS = 14 + 8= 
14 + 8 = 22
22. 22nswer:22
Answer: A
A shopkeeper sold an article offering a discount of 4% and earned a profit of 32%. What would have been the percentage of profit earned if no discount was offered?	Pick.
A) 24.5
B) 28.5
C) 30.5
D) 32.5
E) 37.5

Solution: Let C.P. be Rs. 100.   Then, S.P. = Rs. 132   Let marked price be Rs. x. Then, 96/100 x = 132   x = 13200/96 = Rs. 137.5   Now, S.P. = Rs. 137.5, C.P. = Rs. 100   Profit % = 37.5%.   ANSW37.5R:37.5
Answer: E
The denominator of a fraction is 1 less than twice the numerator. If the numerator and denominator are both increased by 1, the fraction becomes 3/5. Find the fraction?	Select:
A) 1/3
B) 2/3
C) 5/9
D) 5/7
E) 7/11

Solution: Explanation:   Let the numerator and denominator of the fraction be 'n' and 'd' respectively.   d = 2n - 1   (n + 1)/(d + 1) = 3/5   5n + 5 = 3d + 3   5n + 5 = 3(2n - 1) + 3 => n = 5   d = 2n - 1 => d = 9   Hence the fraction is : 5/9   5/9
Answer: C
How many different subsets of the set {0, 1, 2} do not contain 0? Choose one.
A) A.6
B) B.7
C) C.1
D) D.4
E) E.2

Solution: Number of subset   Since we have 2 digits other than 0, we can take any numbers from the set of 2 to make a subset. Also it is a matter of selection and not arrangement.So we will consider combinations.   2c1+2c2=3   And one set is the NULL set having no elements in it so    3+1= 
 3+1 = 4
4.   ANSWER D.4.
Answer: D
A, B and C completed a piece of work costing Rs.1800. A worked for 6 days, B for 4 days and C for 9 days. If their daily wages are in the ratio 5 : 6 : 4, how much amount will be received by A?  Choose the correct choice from the following
A) Rs.800	B) Rs. 600	C) Rs.900	D) Rs.750	E) Rs.850

Solution: Explanation:   The new ratio = wages ratio × No. of days   A = 5 × 6 = 30   B = 6 × 4 = 24   C = 4 × 9 = 36   Therefore, the ratio of the amount received = 30 : 24 : 36 = 5 : 4 :6   Total ratio = 15   1 unit of ratio = 1800/15 = Rs. 120   Therefore, amount received by A = 5 units = 5 × 120 = Rs.600.   Answer: Option Rs. 600
Answer: B
The number of defects in the first five cars to come through a new production line are 9, 7, 11, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12
Choose the correct choice from the following
A) I only  B) II only  C) III only  D) I and III only  E) I, II, and III

Solution: III only   for 7 we will have mean as 7.16(approx) and median as 7 but for 3 we will have mean and median = 6.5 and for 12 we will have median and mean =8
Answer: C
If x and y are numbers such that (x+6)(y-6)=0, what is the smallest possible value of x^2 + y^2	Choose the correct answer:
A) 0  B) 16  C) 25  D) 36  E) 49

Solution: From (x+6)(y-6)=0 it follows that either x=-6 or y=6. Thus either x^2=36 or y^2=36.   Now, if x^2=36, then the least value of y^2 is 0, so the least value of x^2 + y^2 = 36 + 0= 
36 + 0 = 36
36.   Similarly if y^2=36, then the least value of x^2 is 0, so the least value of x^2 + y^2 = 0 + 36= 
0 + 36 = 36
36.   Answer: 36.
Answer: D
The ratio between the sale price and the cost price of an article is 8:5. What is the ratio between the profit and the cost price of that article?  Options:
A) 23	B) 1:2	C) 2:5	D) 3:5	E) 25

Solution: C.P. = Rs. 5x and S.P. = Rs. 8x.   Then, Gain = Rs. 3x   Required ratio = 3x : 5x = 3:5   3:5
Answer: D
Which answer is closest to the √17?	Choose one:
A) a 4.1  B) b 4.2  C) c 4.4  D) d 4.5  E) e 4.6

Solution: Try filling the numbers into the y's. y x y =   4.1 x 4.1= 16.81   4.2 x 4.2 = 17.64   a 4.1nswer: a 4.1
Answer: A
Find the value of 72518 x 9999 = m?  Choices:	A) 456578972	B) 436567874	C) 653658791	D) 725117481	E) 725107482

Solution: 72518 x 9999 = 72518 x (10000 - 1)   = 72518 x 10000 - 72518 x 1   = 725180000 - 72518= 
725180000 - 72518 = 725_107_482
725107482   725107482
Answer: E
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?  Choose the most appropriate option:	A) 118	B) 150	C) 277	D) 258	E) 191

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 9= 
50/3 * 9 = 150
150 m   Answer: 150
Answer: B
A man buys 58 pens at marked price of 46 pens from a whole seller. If he sells these pens giving a discount of 1% , what is the profit percent? Choices:
A) 7.6 %
B) 7.7 %
C) 24.82 %
D) 13.6 %
E) 27.82 %

Solution: Explanation:   Let Marked price be Re. 1 each   C.P. of 58 pens = Rs. 46   S.P. of 58 pens = 99% of Rs. 58 = Rs. 57.42   Profit % = (Profit /24.82 %.P.) x 100   Profit% = (11.42/46) x 100 = 24.82 %   ANSWER: 24.82 %
Answer: C
A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 2:3 and B:C = 2:5. If the total runs scored by all of them are 100, the runs scored by C are?
Choose the correct choice.
A) 59 B) 58 C) 60 D) 61 E) 12

Solution: A:B = 2:3   B:60 = 2:5   A:B:60 = 4:6:15   15/25 * 100= 
15/25 * 100 = 60
60   Answer:60
Answer: C
If 0.75: x :: 5:11, then x is equal to:  Choose the correct choice from the following answers:  A) 1.12  B) 1.65  C) 1.2  D) 1.3  E) None of these

Solution: Explanation:   (x * 5) = (0.75 *11)= 
(0.75 *11) = 8.25
8.25/5= 
8.25/5 = 1.65
1.65   Answer: 1.65
Answer: B
The size of a flat-screen television is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 28-inch flat-screen television than a square 25 -inch flat-screen television?
Choose the correct answer
A) 79.5  B) 89.3  C) 85.5  D) 75.4  E) 72.5

Solution: If we take a square with side length x and draw a diagonal, we get two isosceles right triangles.   If we focus on one such right triangle, we see that the legs have length x.   square 28-inch flat-screen television   The diagonal (hypotenuse) = 28   So, we can apply the Pythagorean Theorem to get x² + x² = 28²   Simplify: 2x² = 28²   Divide both sides by 2 to get: x² = 28²/2   Since the area of the square = x², we can see that the area of this square is 28²/2   square 25-inch flat-screen television   The diagonal (hypotenuse) = 25   So, we can apply the Pythagorean Theorem to get x² + x² = 25²   Simplify: 2x² = 25²   Divide both sides by 2 to get: x² = 25²/2   Since the area of the square = x², we can see that the area of this square is 25²/2   DIFFERENCE IN 79.5RE79.5S =28²/2-25²/2   = (28²- 25²)/2 = (784-625)/2 =159/2= 
159/2 = 159/2 = around 79.5
79.5   79.5
Answer: A
If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is? Choose the correct choice from the following options
A) Rs. 400
B) Rs. 450
C) Rs. 460
D) Rs. 480
E) Rs. 580

Solution: Let the sum be Rs. P. Then,   [P(1 + 25/(2 * 100))2 - P] = 510   P[(9/8)2 - 1] = 510.   Sum = Rs. 1920   So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480   ANSWER:Rs. 480
Answer: D
In how many different number of ways 6 men and 4 women can sit on a shopa which can accommodate persons? Choose the correct choice from the following answers:
A) 200
B) 210
C) 90
D) 250
E) 270

Solution: 10p2 = 10 X 9 = 90   90)
Answer: C
Ayush was born two years after his father's marriage. His mother is five years younger than his father but 22 years older than Ayush who is 10 years old. At what age did the father get married ?	Options.
A) 22years	B) 23years	C) 24years	D) 25years	E) 26years

Solution: Explanation:   Ayush's present age = 10 years.   His mother's present age = (10 + 22)= 
(10 + 22) = 32
32 years.   Ayush's father's present age= (32+ 5)= 
(32+ 5) = 37
37 years.   Ayush's father's age at the time of Ayush's birth= (37 - 10)= 
(37 - 10) = 27
27 years.   Therefore Ayush's father's age at the time of marriage= (27 - 2)= 
(27 - 2) = 25
25 years.   Answer: 25years) 25 year
Answer: D
Find the odd man out. 187, 264, 326, 473, 682, 781	Choose the correct choice from the following options:
A) 187
B) 326
C) 781
D) 682
E) 473

Solution: In all numbers except 326, the middle digit is the sum of other two digits.Answer is 326
Answer: B
An old priest fell on a bottom of the well of a church.
The well is 16 inches deep.
At day time, the old priest climbs 5-inches but when at dark he slip back 4 inches.
In how many days priest will come out of the well ?	Answers:
A) 12-days
B) 14-days
C) 11-days
D) 19-days
E) 10-days

Solution: 12-days   12-days   In 11-days, he will climb 11-inch and when he climbs 5 inch more, he will be out of the well :-)
Answer: A
there is 6 letter d,f,g,h,r,t.then how many word of 2 letter can be form through these letters?  Choices:
A) 720	B) 360	C) 48	D) 30	E) 24

Solution: it will comes like 6P2   6!/4!=(1*2*3*4*5*6)/1*2*3*4=30   answer 30
Answer: D
what is 5+7 Choose the most appropriate option: A) 2 B) 4 C) 10 D) 12 E) 11

Solution: 12
Answer: D
If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?	Answers:	A) 1/6	B) 1/2	C) 1/9	D) 1/5	E) 1/1

Solution: The number of exhaustive outcomes is 36.   Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2   P(E) = 1 - 1/2 = 1/2.   Answer:1/2
Answer: B
Four car rental agencies A, B, C and D rented a plot for parking their cars during the night. A parked 15 cars for 12 days, B parked 12 cars for 20 days, C parked 18 cars for 18 days and D parked 16 cars for 15 days. If A paid Rs. 1305 as rent for parking his cars, what is the total rent paid by all the four agencies?	Choose the most appropriate option.
A) 2388
B) 2778
C) 1279
D) 6150
E) 7134

Solution: The ratio in which the four agencies will be paying the rents = 15 * 12 : 12 * 20 : 18 * 18 : 16 * 15   = 180 : 240 : 324 : 240 = 45 : 60 : 81 : 60   Let us consider the four amounts to be 45k, 60k, 81k and 60k respectively.   The total rent paid by the four agencies = 45k + 60k + 81k + 60k= 246k   It is given that A paid Rs. 1305   45k 45  + 60  + 81  + 60= 
45  + 60  + 81  + 60 = 246
246k   It is given that A paid Rs. 1305   45k= 1305 => k = 29   246k = 246(29) = Rs. 7134   Thus the total rent paid by all the four agencies is Rs. 7134.   Answer: 7134
Answer: E
Latha took a loan of Rs. 2000 with simple interest for as many years as the rate of interest. If she paid Rs.180 as interest at the end of the loan period, what was the rate of interest?	Choices:
A) 5
B) 4
C) 7
D) 3
E) 9

Solution: Let rate = R% and time = R years.   Then, (2000 * R * R) / 100 = 180   20R2 = 180   R2 = 9 => R = 3   Answer:3
Answer: D