MU-NLPC/Calc-aqua_rat huggingface dataset:
During the months May through October, Teddy the bear doubles his weight, and during the months November through April, Teddy loses 100 pounds. If at the beginning of November 1973, Teddy's weight was m pounds, what was Teddy's weight in pounds by the end of April 1976?	Choose the most appropriate option:	A) 4m - 1300	B) 9m - 1200	C) 4m - 1200	D) 9m - 1300	E) m - 1200

Solution: Nov ' 73 = m   4m - 1300pril ' 74 = m - 100   Oct ' 74 = 2m - 300   4m - 1300pril' 75 = 2m - 400   Oct' 75 = 4m - 1200   4m - 1300pril'76 = 4m - 1300   Hence answer will be (4m - 1300) 4m - 1300
Answer: A
The radius of the wheel of a bus is 35 cms and the speed of the bus is 66 km/h, then the r.p.m. (revolutions per minutes)of the wheel is	Choose the correct option.
A) 200
B) 250
C) 300
D) 500
E) None of these

Solution: Radius of the wheel of bus = 35 cm. Then,   circumference of wheel = 2Ï€r = 70Ï€ = 220 cm   500istance covered by bus in 1 minute   = 66â„60 Ã— 1000 Ã— 100 cms   500istance covered by one revolution of wheel   = circumference of wheel   = 220 cm   âˆ´ Revolutions per minute = 6600000/60Ã—220 = 500   Answer 500
Answer: D
When the number 2y31129 is exactly divisible by 11, then what can be the smallest whole number in place of y?  Choose the correct answer:  A) 1  B) 3  C) 4  D) 7  E) 8

Solution: The given number =2y31129   Sum of the odd places =9+1+3+2= 
9+1+3+2 = 15
15   Sum of the even places= 2+1+y   (Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)   15-(3+y) = divisible by 11   12 � y = divisible by 11.   Y must be 1, to make given number divisible by 11.   1
Answer: A
A bag contains 7 white balls, 5 black balls, and 4 red balls. One by one, three balls are drawn out without replacement. What is the probability that the third ball is red? Options.
A) 1/2
B) 1/4
C) 3/8
D) 5/12
E) 2/5

Solution: The probability for each ball to be drawn third is equal.   Then the probability a red ball is drawn third is 4/16 = 1/4.   The answer is 1/4.
Answer: B
Man1 does a work in 10 days and Man2 does the same work in 15 days. In how many days they together will do the same work ?
Pick one:
A) 10 days
B) 5 days
C) 6 days
D) 7 days
E) 8 days

Solution: Man1 day work = 1/10   Man2 day work = 1/15   Both work =1/10+1/15   ===>3+2/30   ==>1/6   ANSWER 6 days
Answer: C
A man's regular pay is $3 per hour up to 40 hours. Overtime is twice the payment for regular time. If he was paid $186, how many hours overtime did he work?	Choose the correct choice from the following answers.
A) 8  B) 5  C) 9  D) 6  E) 11

Solution: At $3 per hour up to 40 hours, regular pay = $3 x 40 = $120 If total pay = $168, overtime pay = $186 - $120 = $66 Overtime rate (twice regular) 186 -  120= 
186 -  120 = 66
$66 Overtime rate (twice regular)= 2 x $3 = $6 per hour => number of overtime hours = $66/$6 = 11   Ans is 1166/ 6= 
66/ 6 = 11
11   Ans is 11
Answer: E
Coins are stacked one on top of the other to form a column. The first column has 12 coins and subsequent columns have 2 more coins than the previous one. Find the number of columns if total number of coins is 432. Choose the most appropriate option.
A) 27  B) 16  C) 15  D) 26  E) 11

Solution: Assume there are n columns. This forms an Arithmetic Progression with first term 12 and nth term (12+2*(n-1)). The average is (12+12+2n-2)/2 or (11+n) and total number of coins will be (11+n)*n = n2+11n-432=0 or (n+27)*(n-16)=0   n=16 or -27. Since n cannot be negative, n=16   Answer is 16
Answer: B
The cost per pound of green tea and coffee were the same in June. In July, the price of coffee shot up by 100% and that of green tea dropped by 70%. If in July, a mixture containing equal quantities of green tea and coffee costs $3.45 for 3lbs, how much did a pound of green tea cost in July?  Select the correct option:
A) $4 B) $0.3 C) $1 D) $3 E) $1.65

Solution: Lets assume price of Coffee in June =100x   Price of green Tea in June =100x   Price of Coffee in July = 200x (because of 100% increase in price)   Price of green Tea in July = 30x (because of 70% Decrease in price)   Price of 1.5 pound of Coffee 1.5 pound of green Tea in July will be = 300x + 45x = 345x   As per question   345x300  + 45= 
300  + 45 = 345
345x   As per question   345x= 3.45$   x = 0.01S   So the Price of Tea in July = 30x = 30 x 0.01 = 0.3$/pound   Answer $0.3
Answer: B
The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class. Choose the correct choice from the following
A) 48
B) 48.55
C) 46
D) 34.5
E) 50.0

Solution: Avg weight of 16 boys = 50.25   tot weight of 16 boys = 50.25 * 16   avg weight of remaining 8 boys = 45.15   tot weight of remaining 8 boys=45.15*8   tot weight of remaining 8 boys = 45.15 * 8   tot weight of all boys = 50.25 * 16 + 45.15*18   =24   avg weight=(50.25*16)+(45.15*8)/24=48.55   ANSWER 48.55
Answer: B
Two numbers are in the ratio of 1 : 2. If 5 be added to both, their ratio changes to 3 : 5. The greater number is Choose the correct choice from the following options: A) 20 B) 24 C) 28 D) 32 E) 36

Solution: Let the ratio be X : Y,   Given X/Y = 1/2 ,   (X + 5)/(Y + 5) = 3/5   => X = 10   20nd Y = 20   20NSWER:20
Answer: A
If R=30^65−29^65/3064+2964 then	Select:
A) 0<R≤0.10<R≤0.1	B) 0.1<R≤0.50.1<R≤0.5	C) 0.5<R≤1.00.5<R≤1.0	D) R<1.0	E) R>1.0

Solution: This question is based on your understanding of number properties. You don't have to do any calculations actually.   At higher powers, a difference of even 1 in the base creates creates a huge difference in the number. For example, 2^10=10242 but 3^10=59049.   So 30^65 will not be very different from 30^65-29^65   Similarly, 30^64 will not be very different from 30^64+29^64   So the question boils down to approx 30^65/30^64 This will be something less than 30 but certainly greater than 1.   Answer (R>1.0)
Answer: E
If the seventh day of a month is three days earlier than Friday, What day will it be on the nineteenth day of the month? Answers
A) Saturday
B) Monday
C) Sunday
D) Wednesday
E) None of these

Solution: Explanation :   Given that seventh day of a month is three days earlier than Friday   => Seventh day is Tuesday   => 14th is Tuesday   => 19th is Sunday, Answer : Option Sunday
Answer: C
The average of 6 observations is 14. A new observation is included and the new average is decreased by 1. The seventh observation is? Choices:
A) 1 B) 3 C) 5 D) 6 E) 7

Solution: Let seventh observation = X.   Then, according to the question we have   => (84 + X) / 7 = 13   => X = 7.   Hence, the seventh observation is 7.   ANSW7R:7
Answer: E
Machine A and machine E are each used to manufacture 660 sprockets. It takes machine A 10 hours longer to produce 660 sprockets than machine E. Machine E produces 10 percent more sprockets per hour than machine A. How many sprockets per hour does machine A produces?	Choose the correct choice from the following answers:	A) 6	B) 6.6	C) 60	D) 100	E) 110

Solution: [Reveal]Spoiler:   TimeE: 660/x   Time6: [660/x+10]   660/x = [660/x+10] *110/100   660/x =66*11/x+10   660x+10= 66*11*x   660x +6600 = 66*11*x   x= 100   plug in back to time6   660/100+10 => 660/110= 
660/110 = 6
6
Answer: A
A person was asked to subtract 25% of a number from the original but he subtracted 25 from the number. His answer was 25 more than correct one. What was the original number? Pick: A) 100 B) 919 C) 102 D) 200 E) 234

Solution: 25 + 25= 
25 + 25 = 50
50   25% ------ 50   100% ----- ?=> 200   Answer:200
Answer: D
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 40 as remainder. Find the no. is?  Pick one.
A) 220044
B) 145778
C) 220400
D) 220014
E) 220040

Solution: (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220040   220040
Answer: E
John distributes his pencil among his 4 friends Rose, Mary, Ranjan, and Rohit in the ratio 1/3 : 1/3 :1/4:1/5 . What is the minimum no. of pencils that the person should have? Choose the correct option:	A) 45	B) 67	C) 70	D) 77	E) 98

Solution: Rakesh : Rahul : Ranjan : Rohit = 1 / 3 : 1 / 3 : 1 / 4 : 1 / 5   Step 1: At First we need to do is LCM of 3,3,4 and 5 is 60.   Step 2: Then pencil are distributed in ratio among friends,   Rakesh = ( 1 / 3 x 60 ) = 20.   Rahul = ( 1 / 3 x 60 ) = 20.   Ranjan = ( 1 / 4 x 60 ) = 15.   Rohit = ( 1 / 5 x 60 ) = 12.   Step 3: Total number of pencils are ( 20 x + 20 x + 15 x + 12 x) = 67 x.   For minimum number of pencils x = 1 .   The person should have atleast 67 pencils.   67)
Answer: B
A large petrol tank has two inlet tubes (a large one and a small one) and one outlet tube. It takes 3 hours to fill the tank with the large inlet tube. On the other hand, it takes 6 hours to fill the tank with the small inlet tube. The outlet tube allows the full tank to be emptied in 9 hours.
What fraction of the tank (initially empty) will be filled in 0.64 hours if all three tubes are in operation? Give your answer to two decimal places (e.g., 0.25, 0.5, or 0.75).
Choose the correct choice from the following choices
A) 1 hour	B) 2 hour	C) 3 hour	D) 4 hour	E) 5 hour

Solution: In one hour,   Soln 1:   the large inlet tube fills 1 / 3 of the tank;   the small inlet tube fills 1 / 6 of the tank;   the outlet tube empties 1 / 9 of the tank; and therefore   all three tubes together fill [ (1 / 3) + (1 / 6) − (1 / 9) ] of the tank.   Fraction of the tank that will be filled in 0.64 hours =   0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.   Soln 2:   Let V be the total volume of the tank. From equation (1),   Flow Rate (large inlet tube) = V / 3   Flow Rate (small inlet tube) = V / 6   Flow Rate (outlet tube) = V / 9.   Substituting in equation (2),   Rate of Accumulation in tank = (V / 3) + (V / 6) − (V / 9).   Using the above result in equation (1),   Time required to fill the complete tank = V / [ (V / 3) + (V / 6) − (V / 9) ].   Note that V cancels out on simplifying the above expression.   Fraction of the tank that will be filled in 0.64 hours =   0.64 [ (1 / 3) + (1 / 6) − (1 / 9) ] = 0.25.
Answer: A
For which of the following values of s is (20+s)/s an integer?
Choose the correct choice
A) 3	B) 4	C) 9	D) 11	E) 20

Solution: This problem has to be solved by checking the options   (20 + s)/s   For this entity to be an integer, 50 + s should be divisible by s   Option A: 23/3 - Not an Integer   Option B: 24/4 - Not an Integer   Option C: 29/9 - Not an integer   Option D: 41/11 - Not an integer   Option 20 - 40/20 - Integer   Correct Option: 20
Answer: E
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are drawn at random, what is the probability that at least one is green?
Select:
A) 23/35	B) 23/32	C) 23/31	D) 23/30	E) 63/35

Solution: Explanation:   Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles.   Probability that at least one green marble can be picked in the random draw of two marbles = Probability that one is green + Probability that both are green   = (â¶Câ‚ * â¹Câ‚)/Â¹âµCâ‚‚ + â¶Câ‚‚/Â¹âµCâ‚‚   = (6 * 9 * 2)/(15 * 14) + (6 * 5)/(15 * 14) = 36/70 + 1/7   = 46/70 = 23/35   23/35nswer: 23/35
Answer: A
Kamal is 60 years old and Karthi is 80 years old. How many years ago was the ratio of their ages 4 : 6?	Answers
A) 20 yrs	B) 30 yrs	C) 25 yrs	D) 40 yrs	E) 15 yrs

Solution: (60-x)/(80-x) = 4/6   6(60-x)=4(80-x)   x = 20   20 yrsNSWER 20 yrs
Answer: A
The average of first 9 natural numbers is?	Answers:
A) 1.5 B) 2.5 C) 3.5 D) 4.5 E) 5.5

Solution: Sum of 10 natural no. = 90/2= 
90/2 = 45
45   Average= 45/10= 
45/10 = 9/2 = around 4.5
4.5   ANSWER:4.5
Answer: D
In a mixture of 60 liters, the ratio of milk and water is 2:1. What amount of water must be added to make the ratio of milk and water as 1:2?
Choose the correct choice from the following choices
A) 60	B) 277	C) 299	D) 66	E) 221

Solution: 2:1 --- 60   1:2   2:4   ---------------   3   3 ----------- 60   3 ----------- ? => 60 liters   60nswer:60
Answer: A
The average age of the mother and her six children is 11 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother Choose the correct choice from the following answers:
A) 40	B) 41	C) 42	D) 43	E) 44

Solution: Total age of mother and 6 children = avg x n = 11 x (6+1)= 77   If mother is excluded new average is  (11 - 5)= 
 (11 - 5) = 6
6   so for 6 children= 6 x 6 =36   so mother's age is  77 - 36= 
 77 - 36 = 41
41   Answer: Option 41
Answer: B
In a kilometer race, A beats B by 60 meters or 10 seconds. What time does A take to complete the race? Choose the correct choice from the following.
A) 199 sec  B) 156.7 sec  C) 726 sec  D) 127 sec  E) 128 sec

Solution: Time taken by B run 1000 meters   = (1000 * 10)/60 = 166.7 sec.   Time taken by A = 166.7 - 10= 
166.7 - 10 = 156.7
156.7 sec.   Answer: 156.7 sec
Answer: B
Increasing the original price of a certain item by 30 percent and then increasing the new price by 30 percent is equivalent to increasing the original price by what percent?  Choose the correct choice from the following choices:
A) 31.25
B) 37.5
C) 50.0
D) 52.5
E) 69.0

Solution: We're told that the original price of an item is increased by 30% and then THAT price is increased by 30%....   IF....   Starting value = $100   + 30% = 100 + .30(100) = 130   + 30% = 130 + .30(130) = 130 + 39= 
130 + 39 = 169
169   The question asks how the final price relates to the original price. This is essentially about Percentage Change, which means we should use the Percentage Change Formula:   Percentage Change= (New - Old)/Old = Difference/Original   Doing either calculation will yield the same result:   59/100 = 69%   Final Answer:   69.0
Answer: E
Sachin borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends money to Rahul
at 25/4% p.a. for 2 years. Find the gain of one year by Sachin.	Choose the correct choice from the following options: A) 110.5 B) 111.5 C) 112.5 D) 113.5 E) None of these

Solution: Explanation:   Two things need to give attention in this question, First we need to calculate gain for 1 year only.   Gain in 2 year = [(5000×254×2100)−(5000×4×2100)]=(625−400)=225 So gain for 1 year = 2252=112.50   Answer: 112.5
Answer: C
The average age of 36 students in a group is 14 years. When teacher's age is included to it, the average increases by one. What is the teacher's age in years?	Choose one.
A) 31
B) 41
C) 51
D) 61
E) 71

Solution: Solution   Age of the teacher	= (37 x 15 - 36 x 14)   = 51 years.   Answer 51
Answer: C
In a group of 25, 13 can speak Latin, 15 can speak French, and 6 don't speak either. How many of these speak both Latin and French? Choose the correct choice from the following options:  A) 9  B) 10  C) 11  D) 12  E) 8

Solution: let no.of persons who speeks booth latin and french = x   so, no.of persons who speeks only latin = 13-x   no.of persons who speeks only french= 15-x   no.of persons who speeks dont speek any lag = 6   therefore (13-x)+(15-x)+x+6=25   34-x=25   x=9   9NSWER:9
Answer: A
A train traveling at 72 kmph crosses a platform in 34 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters?
Select the correct option:  A) 240 meters  B) 320 meters  C) 420 meters  D) 600 meters  E) Cannot be determined

Solution: Speed of train = 72 * (5/18)= 
72 * (5/18) = 20
20 m/s   Lets consider the man as a stationery point on the platform.   Crossing the point gives us the length of the train.   Lt= 20 * 18= 
20 * 18 = 360
360 m.   Crossing the platform gives us the length of trainlength of platform.   L(t+p)= 20 * 34= 
20 * 34 = 680
680 m.   So, length of platform= 680 - 360= 
680 - 360 = 320
320 m   IMO, Answer   320 meters
Answer: B
Siddharth wants to borrow Rs.4000 at rate of interest 6% p.a. at S.I and lend the same amount at C.I at same rate of interest for two years. What would be his income in the above transaction?	Choose the correct choice from the following answers.
A) s.21.60
B) s.21.68
C) s.21.18
D) s.14.4
E) s.21.29

Solution: Amount of money Siddharth borrowed at S.I at 6% p.a. for two years = Rs.4,000   He lend the same amount for C.I at 6% p.a. for two years.   => Siddharth's income = C.I - S.I   = p[1 + r/ 100]n - p - pnr/100   = p{ [1 + r/ 100]2 - 1 - nr/100   = 4,000{ [1 + 6/100]2 - 1 - 12/100}   = 4,000 {(1.06)2- 1 - 0.12} = 4,000(1.1236 - 1 - 0.12)   = 4,000 (0.0036) = 4 * 3.6   = Rs.14.4   Answer: s.14.4
Answer: D
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/3 hours to fill the tank. The leak can drain all the water of the tank in?  Choose the correct choice from the following answers:
A) 4 1/3 hrs	B) 7 hrs	C) 8 hrs	D) 14 hrs	E) 15 hrs

Solution: Work done by the tank in 1 hour = (1/2 - 1/3) = 1/14 Leak will empty the tank in 14 hrs.   ANSWER:14 hrs
Answer: D
Find the smallest number which should be multiplied with 13225 to make it a perfect square. Pick
A) 25  B) 5  C) 1  D) 23  E) 6

Solution: 13225 = 5*5*23*23   Required smallest number = 1   1 is the smallest number which should be multiplied with 13225 to make it a perfect square.   ANSWER:1
Answer: C
If 36 men can do a piece of work in 20 hours, in how mwny hours will15 men do it? Choices: A) 22 B) 48 C) 60 D) 88 E) 72

Solution: Explanation:   Let the required no of hours be x. Then   Less men , More hours (Indirect Proportion)   \inline \fn_jvn \therefore 15:36 ::20:x \inline \fn_jvn \Leftrightarrow (15 x X)=(36 x 20) \inline \fn_jvn \Leftrightarrow \inline \fn_jvn x=\frac{36\times 20}{15}=48   Hence, 15 men can do it in 48hours.   Answer: 48)48
Answer: B
A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age five years back was? Answers:
A) 14yr B) 15yr C) 20yr D) 25yr E) 30yr

Solution: Let the son's present age be x years   Then, 38-x = x   x = 19   Son's age 5 years back = 19-5= 
19-5 = 14
14 years   14yrnswer is 14yr
Answer: A
The value of “A” varies in inverse proportion as the square of “B”. If the value of “A” is equal to 40 when “B” is equal to 12. What would be the value of “A” when “B” is equal to 24 ?  Select the correct option.
A) 10 B) 88 C) 26 D) 27 E) 28

Solution: Explanation:   We have, A α 1/B2   A * B2 = K (constant)   When B = 12, A = 40 …..Given   K = 40 * (12)2 = 5760   Now, B = 24. Hence, 10 = 5760 / 576= 
5760 / 576 = 10
10   10NSWER: 10
Answer: A
In year Y imported machine tools accounted for 25 percent of total machine-tools sales in the United States, and Japanese imports accounted for 55 percent of the sales of imported machine tools. If the total sales of machine tools imported from Japan that year was x billion dollars, then the total sales of all machine tools in the United States was how many billion dollars?
Choices:
A) 9x/80 B) 13x/20 C) 80/9x D) 20x/13 E) 80x/11

Solution: Sales of imported tools = 25% of the total sales = 0.25*{total} = {total}/4;   Sales of Japanese tools = 55% of the sales of imported tools = 0.55*{total}/4 = 11/20*{total}/4 = 11*{total}/80.   Since the sales of of Japanese tools was x, then 11*{total}/80 = x --> {total} = 80x/11.   Answer: 80x/11.
Answer: E
what is the smallest integer that is multiple of 5,7,9 Pick one:	A) A)70	B) B)315	C) C)200	D) D)280	E) E)140

Solution: It is the lcm of 5, 7 and 9 which is 315.   The answer is 315.
Answer: B
What is the difference between the compound interest on Rs.12000 at 28% p.a. for one year when compounded yearly and half yearly? Choose the correct choice from the following answers.
A) 399
B) 383
C) 235
D) 288
E) 133

Solution: When compounded annually, interest   = 12000[1 + 28/100]1 - 12000 = Rs.3360   When compounded semi-annually, interest   = 12000[1 + 14/100]2 - 12000 = Rs.3595.2   Required difference = 3595.2 - 3360 = Rs.235.2   Answer: 235
Answer: C
Nelson borrowed some money at the rate of 6 p.c.p.a. for the first three years, 9 p.c.p.a. for the next five years and 13 p.c.p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is 8,160, how much money did he borrow? Select the correct option
A) 12,000  B) 10,000  C) 8,000  D) Data inadequate  E) None of these

Solution: Let ‘x’ be the amount borrowed by Nelson   and x×6×3/100+x×9×5/100+x×13×3/100=8160   ⇒ 102⁄100x = 8,160   ∴ x = 8,160×100102=8000   Answer 8,000
Answer: C
Monica planned her birthday party. She prepared 5 muffins for each of her guests and kept aside two additional muffins in case someone will want extra. After the party, it turned out that one of the guests didn't come but every one of the guests that did come ate six muffins and 4 muffins remained. How many guests did Monica plan on?  Choose the correct answer
A) 3.  B) 4.  C) 5.  D) 6.  E) 7.

Solution: Let x be the number of guests.   Number of muffins prepared = 5x + 2   Number of muffins eaten + Number of muffins remaining = Number of muffins prepared   6(x - 1) + 4 = 5x + 2   6x - 4 = 5x + 2   x = 6   Answer: 6.
Answer: D
The present ages of A,B & C are in the ratio of 5:7:8. 7years ago, the sum oftheir ages was 59. What is the present age of eldest one?	Answers.
A) 30
B) 31
C) 32
D) 35
E) 36

Solution: Let their present ages be 5x, 7x and 8x.   7 years ago, sum of their ages was 59.   Sum of their present ages = 59 +( 3 x 7) = 80   Sum of their present ages given is 5x + 7x + 8x = 20x   20x   5  + 7  + 8= 
  5  + 7  + 8 = 20
20x   20x= 80 =>x = 80 20   =4   Age of the Eldest one= 8x = 8x 4 = 32 years.   32
Answer: C
A, B, K start from the same place and travel in the same direction at speeds of 30km/hr, 40km/hr, 60km/hr respectively. B starts six hours after A. If B and K overtake A at the same instant, how many hours after A did K start?	Select the correct option.
A) 3
B) 4.5
C) 4
D) d) 12
E) e) 5

Solution: The table you made doesn't make sense to me. All three meet at the same point means the distance they cover is the same.   We know their rates are 30, 40 and 60.   Say the time taken by B is T hrs. Then A takes 6+T hrs. And we need to find the time taken by K.   Distance covered by A = Distance covered by B   30*(6+T) = 40*T   T = 18 hrs   Distance covered by B = Distance covered by K   40*T = 60*Time taken by K   Time taken by K = 40*18/60= 
40*18/60 = 12
12 hrs   Time taken by A= 6+T = 6+18= 
6+18 = 24
24 hrs   Time taken by K= 12 hrs   So K starts  24-12= 
 24-12 = 12
12 hrs after A. (ANSWER d) 12)
Answer: D
How long does a train 110 m long traveling at 72 kmph takes to cross a bridge of 170 m in length?  Choose the correct answer:
A) 16.5  B) 16.0  C) 16.4  D) 14  E) 16.1

Solution: 14 = 110 + 170= 
110 + 170 = 280
280 m   S= 72 * 5/18= 
72 * 5/18 = 20
20   T= 280 * 1/20= 
280 * 1/20 = 14
14 sec   Answer: 14
Answer: D
As part of her MBA program, Karen applied for three different Spring Break outreach projects, each of which selects its students by a random lottery of its applicants. If the probability of her being accepted to each individual project is 30%, what is the probability that Karen will be accepted to at least one project?
Choose the most appropriate option
A) 729/1000 B) 657/1000 C) 343/500 D) 123/250 E) 17/100

Solution: Since the probability of Karen's being accepted to each individual project is 30%, the probability of her not being accepted to each project is 70%. The probability that she will be accepted to none is, therefore, (7/10)*(7/10)*(7/10)=343/1000.   P(Karen will be accepted to at least one project) = 1 - (343/1000) = 657/1000.   The answer is 657/1000.
Answer: B
For an agricultural experiment, 300 seeds were planted in one plot and 200 were planted in a second plot. If exactly 25 percent of the seeds in the first plot germinated and exactly 40 percent of the seeds in the second plot germinated, what percent of the total number of seeds germinated? Choices.
A) 12%  B) 26%  C) 29%  D) 31%  E) 60%

Solution: In the first plot 25% of 300 seeds germinated, so 0.25 x 300 = 75 seeds germinated.   In the second plot, 40% of 200 seeds germinated, so 0.4 x 200 = 80 seeds germinated.   Since 75 + 80= 
75 + 80 = 155
155 seeds germinated out of a total of 300 + 200= 
300 + 200 = 500
500 seeds, the percent of seeds that germinated is (155/500) x 100%, or 31%.   Answer: 31%.
Answer: D