MU-NLPC/Calc-aqua_rat huggingface dataset:
what is the compound interest on rs:40,000 for 4 months at the rate of 5% per annum	Pick one
A) 670.85	B) 671.85	C) 672.85	D) 673.85	E) 674.85

Solution: it is monthly compound   rate=5/12% per month   40000*(1+5/1200)^4-40000=670.85   670.85NSWER:670.85
Answer: A
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 9 years and that for 6 years? Choose the correct option
A) 1 : 3	B) 2 : 3	C) 1 : 2	D) 3 : 2	E) 1 : 4

Solution: Let the principal be P and rate of interest be R%.   Required ratio =   (P x R x 9)/100 DIVIDED BY	(P x R x 6)/100   =	9PR/6PR	=	9/6	= 3 : 2.   ANSWER : 3 : 2
Answer: D
If three machines working at the same rate can do 3/4 of a job in 30 minutes, how many minutes would it take two machines working at the same rate to do 3/5 of the job?	Choose the correct choice from the following answers: A) 36 B) 60 C) 75 D) 80 E) 100

Solution: using the std formula   m1d1h1/w1=m2d2h2/w2   substituting the values we have    3*1/2*4/3= 
 3*1/2*4/3 = 2
2*5/3*x (converted 30 min into hours=1/2)   2=10/3*x   x=3/5 hour   so 36 minutes   36NSWER:36
Answer: A
The number of circles that can be drawn out of 10 points of which 7 are collinear is Choose the correct choice from the following choices
A) 130
B) 85
C) 45
D) Cannot be determined
E) None of these

Solution: Solution   For drawing a circle we need 3 non collinear points.This can be done in:   3C3 + 3C2 × 7C1 + 3C1 × 7C2 = 1 + 21 + 63= 
1 + 21 + 63 = 85
85. Answer 85
Answer: B
Ravi can do a piece of work in 30 days while Prakash can do it in 40 days. In how many days will they finish it together?
Choose one
A) 17 1/7 days	B) 17 1/8 days	C) 17 1/9 days	D) 17 7/7 days	E) 18 1/7 days

Solution: 1/30 + 1/40 = 7/120   120/7   = 17 1/7 days   17 1/7 daysnswer: 17 1/7 days
Answer: A
The average of a non-zero number and its square is 5 times the number. The number is:	Pick one:
A) 5	B) 6	C) 7	D) 8	E) 9

Solution: (x+x^2)/2=5x   x^2=9x   x=9   ANSW9R:9
Answer: E
Pipes A and B can fill a cistern in 9 and 72 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full? Choose the correct choice from the following options:
A) 13
B) 12
C) 16
D) 18
E) 19

Solution: :   1/9 + 1/72 = 1/8   8 * 2= 
8 * 2 = 16
16.Answer:16
Answer: C
Look at this series: 7, 10, 8, 11, 9, 12, 10, ... What number should come next?	Pick:
A) 7	B) 10	C) 12	D) 13	E) 14

Solution: This is a simple alternating addition and subtraction series. In the first pattern, 3 is added; in the second, 2 is subtracted.   The answer is 13.
Answer: D
If a and b are the two values of t that satisfy
the equation t^2 â€“ 14t + 24 = 0, with a > b, what is the value of a â€“ b?  Answers:
A) 2	B) 4	C) 6	D) 8	E) 10

Solution: Factor the left side of the equation:   t^2 â€“ 14t + 24 = 0   (t â€“ 2)(t â€“ 12) = 0   t = 2, t = 12   Thus, a = 12 and b = 2. So a â€“ b = 12 â€“ 2 = 10.   The answer is 10.
Answer: E
At a conference table, 9 employees gather around a table. One of the employees is the manager and he sits at the head of the table. Two of the employees sit on either side of the table. How many different seating arrangements can be made with these 9 employees?
Select the correct option
A) 41000	B) 41320	C) 42320	D) 40320	E) 43320

Solution: Head's sit is fixed. Now 8 people is left with 8 seats.   8 people can sit on 8 seats in 8! ways or 40320 ways.   Ans is 40320
Answer: D
Line m lies in the xy-plane. The y-intercept of line m is -2, and line m passes through the midpoint of the line segment whose endpoints are (2, 4) and (6, -6). What is the slope of line m ?	Choose the correct choice:  A) -3  B) -1  C) -1/3  D) 0  E) Undefined

Solution: Ans:B   Solution: line m goes through midpoint of (2, 4) and (6, -8). midpoint is (4,-1)   as we can see that the y axis of intercept point is (0,-2) means line m is parallel to x axis   slope M= -1   Ans: -1
Answer: B
The sale price of a trolley bag including the sale tax is Rs. 420. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: Choose the correct option
A) Rs 625  B) Rs 300  C) Rs 350  D) Rs 375  E) None of these

Solution: Explanation :   112% of S.P. = 420   S.P. = Rs.(420x 100/112) = Rs.375.   C.P. = Rs (100/125x 375) = Rs 300   Answer : Rs 300
Answer: B
Out of 7 constants and 4 vowels how many words of 3 consonants and 2 vowels can be formed?  Select:	A) 25200	B) 32500	C) 45100	D) 15460	E) 36400

Solution: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)   = 7C3 * 4C2   = 210   Number of groups each having 3 consonants and 2 vowels = 210   Each group contains 5 letters   Number of ways of arranging 5 letters among themselves   = 5! = (5 * 4 * 3 * 2 * 1)   = 210   Required number of words = (210 * 210)   = 25200   25200ns: 25200
Answer: A
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?	Pick one
A) 157.58
B) 157.56
C) 157.5
D) 157.52
E) 157.54

Solution: (3500*1.5*3)/100= 
(3500*1.5*3)/100 = 157.5
> 157.50   Answer:157.5
Answer: C
If 20% of a number is equal to three-fifth of another number, what is the ratio of first number to the second number?  Answers.
A) 3:1 B) 2:1 C) 1:3 D) 1:2 E) 2:3

Solution: Let 20% of A = 3/5 B. Then,   20A/100 = 3B/5 => 1A/5 = 3B/5   A/B = (3/5 * 5/1)= 
(3/5 * 5/1) = 3
3/1= 
3/1 = 3
3:1.   3:1nswer: 3:1
Answer: A
A basket has 6 apples and 6 oranges. Three fruits are picked at random. What is the probability that at least 2 apples are picked?
Choose the correct choice:
A) 1/2  B) 1/3  C) 1/4  D) 2/5  E) 3/10

Solution: The total possible choices are 12C3 = 220   The ways to choose 3 apples: 6C3 = 20   The ways to choose 2 apples: 6C2 * 6C1 = 90   P(at least 2 apples) = 110/220 = 1/2   The answer is 1/2.
Answer: A
By purchasing an article at 20 % discount on the original price and then selling it at a price of 25% above the original price, a trader earns Rs. 200 as the profit. What was the original price of the article? Select.
A) Rs. 444.44
B) Rs. 255.50
C) Rs. 100.10
D) Rs. 810
E) None of these

Solution: Explanation:   Let the original price of the article be Rs. 100. Hence the purchase price for the trader would be Rs. 80 and his selling price would be Rs. 125. Thus, he would earn a profit of Rs. 45 (125 – 80). Therefore,   Profit is Rs. 45 if the original price is Rs. 100   Hence, if profit is Rs. 200, then original price will be..   = 100x 200/45   = Rs. 444.44   Rs. 444.44NSWER Rs. 444.44
Answer: A
A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is: Choose the correct choice from the following options: A) 288 B) 278 C) 267 D) 285 E) 231

Solution: Since the month begins with a Sunday, so there will be five Sundays in the month.   Required average = [(510 * 5) + (240 * 25)]/30   = 8550/30= 
8550/30 = 285
285.   Answer: 285
Answer: D
Select the non termination decimal among the following.	Answers:
A) 11/3
B) 3/4
C) 4/5
D) 7/8
E) 9/10

Solution: A. Non terminating decimal means that 11/3 = 3.66666 and so on.
Answer: A
How many paying stones, each measuring 3 * 2 m are required to pave a rectangular court yard 15 m long and 6 m board? Choose the correct choice:
A) 99  B) 18  C) 26  D) 15  E) 12

Solution: 15 * 6 = 3 * 2 * x => x   = 15   Answer: 15
Answer: D
Ten percent of Ram's monthly salary is equal to eight percent of Shyam's monthly salary. Shyam's monthly salary is twice Abhinav's monthly salary. If Abhinav's annual salary is Rs. 1.92 lakhs, find Ram's monthly salary? Choose the correct choice from the following choices.
A) 28888	B) 28892	C) 25600	D) 27772	E) 17713

Solution: Let the monthly salaries of Ram and Shyam be Rs. r and Rs. s respectively.   10/100 r = 8/100 s   r = 4/5 s   Monthly salary of Abhinav = (1.92 lakhs)/12 = Rs. 0.16 lakhs   s = 2(0.16 lakhs) = 0.32 lakhs   r = 4/5(0.32 lakhs) = Rs. 25600   Answer: 25600
Answer: C
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is: Choose the correct choice from the following answers.
A) 17 kg B) 20 kg C) 22 kg D) 26 kg E) 31 kg

Solution: Let A, B, C represent their respective weights. Then, we have:   A + B + C = (45 x 3) = 135 .... (i)   A + B = (40 x 2) = 80 .... (ii)   B + C = (43 x 2) = 86 ....(iii)   Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)   Subtracting (i) from (iv), we get : B = 31.   B's weight = 31 kg.   Answer: Option 31 kg
Answer: E
A man rows to a place 24 km distance and come back in 7 hours. He finds that he can row 2 km with the up stream in the same time as 3 km against the down stream. The rate of the stream is Choices: A) 10/3 km/hr B) 13/3 km/hr C) 20/7 km/hr D) 30/7 km/hr E) 40/7 km/hr

Solution: Explanation:   Speed down stream = distance/time = 3/x   Speed up stream = distance/time = 2/x   Time taken to row 24 km up stream and down stream is   = 48/(2/x) + 48/(3/x)   = 48x/2 + 48x/3 = 48x(5/6) = 8x+5 = 40x   40x = 7   x = 7/40 hr   Speed of down stream 3/(7/40) = 120/7   speed of up stream = 2/(7/40) = 80/7   Rate of stream = 1/2(a - b) = 1/2[(120/7)-(80/7)]   = 1/2(40/7)   = 20/7 km/hr   Answer: Option 20/7 km/hr
Answer: C
What is the remainder when 3^381 is divided by 5 ?
Pick:
A) 0
B) 1
C) 2
D) 3
E) 4

Solution: I also agree that the remainder is '3' (using the last digit of the powers of 7). Could we have the official answer please?3
Answer: D
P alone can complete a piece of work in 6 days. Work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?	Choose the correct choice from the following answers.
A) 6 (1/4) days  B) 6 (3/4) days  C) 7 (3/4) days  D) 8 (3/4) days  E) 9 (3/4) days

Solution: Work done by P alone in one day = 1/9th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/9 of the total) = 1/27 of the total.   Work done by P and Q, working together in one day = 1/9 + 1/27 = 4/27 of the total   They would take 27/4 days = 6 (3/4) days to complete the work working together.   ANSWER:6 (3/4) days
Answer: B
A runs twice as fast as B and gives B a start of 60m.How long should the racecourse be so that A and B might reach in the same time?
Choose the correct choice: A) 120 m. B) 80 m. C) 150 m. D) 100 m. E) None of the above

Solution: ratio of speeds of a and b is 2:1   b is 60m away from a but we know that a covers 1 meter(2-1) more in every second than b   the time taken for a to cover 60m is   60/1= 
  60/1 = 60
60m   so the total time taken by a and b to reach=2*60= 
2*60 = 120
120m   120 m.NSWER:120 m.
Answer: A
If 5 is added to twice a number and this sum is multiplied by 10, the result is the same as if the number is multiplied by 5 and 20 is added to the product. What is the number?	Pick
A) -5 B) -8 C) -2 D) 10 E) 11

Solution: let the number be x;   10(5+2x)=5x+20;   x=-2   ANSWER:-2
Answer: C
Laxman went 15 kms from my house, then turned left and walked 20 kms. He then turned east and walked 25 kms and finally turning left covered 20kms. How far was he from his house?	Answers:
A) 40*1.414
B) 30*1.414
C) 45*1.414
D) 20*1.414
E) 48*1.414

Solution: If we plot a graph for the given motion then we find that total distance in a direction is 40 km. and there is 40 km. in perpendicular to that direction so direct distance of Laxman from the initial position will be sqrt(40^2 + 40^2) = 40 sqrt(2) = 40*1.414   40*1.414NSWER:40*1.414
Answer: A
A sum of money invested for a certain number of years at 8% p.a. simple interest grows to Rs.180. The same sum of money invested for the same number of years at 4% p.a. simple interest grows to Rs.120. For how many years was the sum invested?  Choose the correct choice from the following choices.
A) 25 years
B) 40 years
C) 33 years and 4 months
D) Cannot be determined
E) None of these

Solution: Solution:   From the information provided we know that,   Principal + 8% p.a. interest on principal for n years = 180 …….. (1)   Principal + 4% p.a. interest on principal for n years = 120 ……… (2)   Subtracting equation (2) from equation (1), we get   4% p.a. interest on principal for n years = Rs.60.   Now, we can substitute this value in equation (2),   i.e Principal + 60 = 120   = Principal = Rs.60.   We know that SI = pnr/100, where p is the principal, n the number of years and r the rate percent of interest.   In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.   Therefore, 60 = (60 X n X 4)/100   => n = 100/4= 
100/4 = 25
25 years.   25 yearsnswer 25 years
Answer: A
Calculate the number of urns of water needed to fill a tank of dimensions of 10x10x5m to 90% full, if the volume of the urn is 0.8m3 and can only be filled to 80%.	Choose the correct choice:
A) 520  B) 650.2  C) 685.5  D) 703.1  E) 712.2

Solution: Volume of the tank that needed to be filled=10x10x5x0.9=450   Volume of the urn that can be filled=0.8x0.8=0.64   No. of urns of water needed to fill the tank=450/0.64= 703.1   Answer: 703.1
Answer: D
A clock is set right at 5 a.m. The clock loses 16 minutes in 24 hours.What will be the true time when the clock indicates 10 p.m. on 4th day?	Select the correct option:  A) 11pm  B) 12pm  C) 10pm  D) 09pm  E) 08pm

Solution: Time from 5 am. on a day to 10 pm. on 4th day = 89 hours.   Now 23 hrs 44 min. of this clock = 24 hours of correct clock.   356/15 hrs of this clock = 24 hours of correct clock   89 hrs of this clock = (24 x 31556 x 89) hrs of correct clock.   = 90 hrs of correct clock.   So, the correct time is 11 p.m.   11pmnswer:11pm
Answer: A
7 speakers gathered to deliver speeches on two topics. Even though 7 speeches were initially planned to be delivered, due to lack of time only 2 speeches were finally decided to be delivered. Topics are to be spoken in a specific order and the speeches differ with respect to speaker or topic. How many such two speeches are possible?	Choose the correct choice from the following options
A) 2	B) 49	C) 50	D) 47	E) 1024

Solution: 1)there are 7 speeches in ONE topic and 7 in OTHER..   2)there is a specific order for topics, so   a) both the topics are to be spoken on- so ONE from each   b) the order does not matter since there is ONLY one specific order..   so 7C1∗7C1=7∗7=49   ANSWER:49
Answer: B
Bill is golfing with two friends and can either buy generic golf tees that are packaged by the dozen or the higher quality Aero flight tees that come by the pair. What is the minimum number of packages of Aero flight tees Bill must purchase to ensure that he has at least 10 golf tees for each member of his foursome, if he will buy no more than 2 packages of the generic golf tees?
Choose the correct choice from the following choices.
A) 3	B) 10	C) 8	D) 4	E) 2

Solution: At least 10 golf tees for each member of his threesome = total of at least 3*10= 
3*10 = 30
30 tees.   2 packages of the generic golf tees, that are packaged by the dozen= 2*12= 
2*12 = 24
24 tees.   So, Bill must by at least 6 Aero tees. They come by the pair, hence he must by at least 6/2= 
6/2 = 3
3 packages of Aero flight tees.   3nswer: 3
Answer: A
What is the selling price of a car? cost of car is Rs 60 & profit 10% profit over selling price Select the correct option.
A) 63 B) 64 C) 65 D) 66 E) 67

Solution: sp=1.1*60= 
1.1*60 = 66
66   ANSWER:66
Answer: D
Two unbiased coins are tossed. Find the probability of getting at most one head?
Choose the correct answer
A) 1/2  B) 3/4  C) 2/5  D) 2/3  E) 1/4

Solution: S = {HH,HT,TH,TT}   E = Event of getting at most one head   E = {TT,HT,TH}   P(E) = 3/4   Answer is 3/4
Answer: B
Compound interest of Rs.5000 at 10% per annum for 1 1/2years will be (interest compounded half yearly). Choose the correct choice from the following options
A) Rs.473 B) Rs.374 C) Rs.495 D) Rs.788 E) None of the above

Solution: 10% interest per annum will be 5% interest half yearly for 3 terms( 1 1/2 years)   So compound interest=5000[1+(5/100)]^3 - 5000=5000[(21/20)^3 -1]   =5000(9261-8000)/8000   =5*1261/8   =788   ANSWER:Rs.788
Answer: D
An airplane flies against the wind from A to B in 8 hours. The same airplane returns from B to A, in the same direction as the wind, in 7 hours. Find the ratio of the speed of the airplane (in still air) to the speed of the wind. Select the correct option:
A) 5	B) 10	C) 15	D) 20	E) 25

Solution: Let x = speed of airplane in still air, y = speed of wind and D the distance between A and B. Find the ratio x / y   Against the wind: D = 8(x - y), with the wind: D = 7(x + y)   8x - 8y = 7x + 7y, hence x / y = 15   correct answer 15
Answer: C
A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time?
Choose the correct choice from the following:
A) 76 men
B) 60 men
C) 78 men
D) 87 men
E) 75 men

Solution: In 120days, only 240m of the tunnel is constructed by 60 men.   The remaining 120days, 480m of the tunnel can be constructed by 120 men.   Additional number of men required   = 120 - 60= 
120 - 60 = 60
60 men.   Answer: 60 men
Answer: B
The length of the bridge, which a train 130 metres long and travelling at 36 km/hr can cross in 45 seconds, is:
Options:	A) 320 m	B) 225 m	C) 245 m	D) 250 m	E) 240 m

Solution: Speed = [36X 5/18] m/sec = 10 m/sec   Time = 45 sec   Let the length of bridge be x metres.   Then, (130 + x)/45 = 10 => 130 + x = 450 => x = 320 m.   320 mNSWER:320 m
Answer: A
Which of the following is equal to the value of 2^7 + 2^7 + 3^7 + 3^7 + 3^7 ?  Choose the correct choice from the following answers
A) 2^8 + 3^8
B) 2^6 + 3^8
C) 2^8 + 3^6
D) 2^9 + 3^9
E) 2^5 + 3^5

Solution: 2^7 + 2^7 + 3^7 + 3^7 + 3^7   = 2 (2^7) + 3 (3^7)   = 2^1 (2^7) + 3^1 (3^7)   = 2^(1+7) + 3^(1+7)   = 2^8 + 3^8   2^8 + 3^8ns: 2^8 + 3^8
Answer: A
Fred and Sam are standing 50 miles apart and they start walking in a straight line toward each other at the same time. If Fred walks at a constant speed of 5 miles per hour and Sam walks at a constant speed of 5 miles per hour, how many miles has Sam walked when they meet?  Choose the correct choice from the following:
A) 5 B) 9 C) 25 D) 30 E) 45

Solution: relative distance =50 miles   relative speed =5+5= 
5+5 = 10
10 miles per hour   time taken=50/10= 
50/10 = 5
5 hours   distance travelled by sam=5*5= 
5*5 = 25
25 miles= 25
Answer: C
If -1 < x < 0, which of the following must be true?
I. x^7 < x^3
II. x^3 < 1 – x
III. x^5 < x^3
Choices
A) II,III only  B) I,II,III only  C) I only  D) II only  E) III only

Solution: Answer : I,II,III only
Answer: B
On a trip, a cyclist averaged 8 miles per hour for the first 12 miles and 12 miles per hour for the remaining 24 miles. If the cyclist returned immediately via the same route and took a total of 7.5 hours for the round trip, what was the average speed (in miles per hour) for the return trip?
Choose the correct choice from the following choices: A) 9 B) 10 C) 11 D) 12 E) 13

Solution: The time to go 36 miles was 12/8+24/12=1.5+2= 
1.5+2 = 3.5
3.5 hours.   The average speed for the return trip was 36 miles/4 hours= 9 mph.   The answer is 9.
Answer: A
A man can do a piece of work in 5 days, but with the help of his son he can do it in 3 days. In what time can the son do it alone ?
Choose the correct choice from the following choices:
A) 13/2  B) 19/2  C) 21/2  D) 15/2  E) None

Solution: Son's one day work = (1/3âˆ’1/5)=2/15   So son will do whole work in = 15/2 days   Answer: 21/2
Answer: C
At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 30 years. What is the age of Deepak at present? Options:
A) 77 years  B) 15 years  C) 66 years  D) 18 years  E) 55 years

Solution: Let the present ages of Arun and Deepak be 4x and 3x years respectively.   Then, 4x + 6 = 30 => x = 6   Deepak's age = 3x = 18 years.   Answer: 18 years
Answer: D
Calculate the amount that an investor needs to be invest to earn $441 in interest in 12 months if the investor plans to invest x dollars in a savings account that pays interest at an annual rate of 7% compounded semi-annually?	Choose the correct option.
A) 6209 B) 6200 C) 6799 D) 6199 E) 6685

Solution: the approach is substitution,   our interest requirement is $441 after 12 months, 2 compounding period.   calculate the compound interest on each option and find out the one that yields $441 in 12 months   6200 yielded $441   using the formula   A = P(1 + r/n)nt   hence answer is 6200
Answer: B
What least number should be added to 1052, so that the sum is completely divisible by 23
Choose the correct choice:
A) A)4 B) B)1 C) C)6 D) D)3 E) E)5

Solution: Explanation:   (1052 / 23) gives remainder 17   17 + 6= 
17 + 6 = 23
23, So we need to add 6   Answer: Option 6
Answer: C
The population of a bacteria colony doubles every day. If it was started 9 days ago with 2 bacteria and each bacteria lives for 11 days, how large is the colony today? Choices
A) 512
B) 768
C) 4096
D) 2048
E) 1024

Solution: 9 days ago- 2   8 days ago- 4   7 days ago- 8   6 days ago- 16   5 days ago- 32   4 days ago- 64   3 days ago- 128   2 days ago- 256   Yesterday- 512   Today- 1024   Ans:1024
Answer: E
A woman takes 5hr 45min in walking to certain place and riding back. She would have gained 2hrs by riding both ways. The time she would take to walk both ways is?
Answers:
A) 6 hr 45 min
B) 3 hr 45 min
C) 8 hr 55 min
D) 7 hr 45 min
E) 4 hr 60 min

Solution: 7 hr 45 min   7 hr 45 min   Let x be the speed of walked   Let y be the speed of ride   Let 7 hr 45 min be the distance   Then 7 hr 45 min/x + 7 hr 45 min/y = 23/4 hr -------------------(1)   7 hr 45 min/y + 7 hr 45 min/y = 23/4 – 2 hr   7 hr 45 min/y = 15/8 ----------------------------------(2)   substitute 2 in 1   7 hr 45 min/x + 15/8 = 23/4   7 hr 45 min/x = 23/4 -15/8 =46-15/8 =31/8   Time taken for walk one way is 31/8 hr   time taken to walk to and fro is 2*31/8 = 31/4 hr   =7 hr 45 min
Answer: D
If x > 0.7, which of the following could be the value of x?	Select the correct option: A) √0.06 B) √0.07 C) √0.7 D) √0.05 E) √0.04

Solution: Answer : √0.7
Answer: C
There is a sequence ni such, in which i is a positive integer, ni+1=2ni.
If n1=1, n2=2, n3=4, n4=8, what is the scope including n11?  Pick one
A) 10~100	B) 1,000~10,000	C) 10,000~100,000	D) 100,000~1,000,000	E) 1,000,000~

Solution: -> ni=2^(i-1) -> 2^10=1,024>1,000=10^3 -> n11=2^10=(2^10)>(10^3)=10^3   Thus, the answer is 1,000~10,000.
Answer: B
A and B can do a job in 15 days and 10 days, respectively. They began the work together but A leaves after some days and B finished the remaining job in 5 days. After how many days did A leave? Choose one.
A) 2 days	B) 3 days	C) 1 day	D) 4 days	E) None of these

Solution: A’s one day’s work = 1⁄15 th work.   B’s one day’s work = 1⁄10 th work.   (A + B)’s one day’s work = 1⁄15 + 1⁄10 = 1⁄6 th work.   Let A left after x days.   ∴ (A + B)’s x days’ work = x⁄6 th work.   Remaining work = 1 - x⁄6 = (6 - x)⁄6 th work.   Now, in 5 days, work done by B = (6 - x)⁄6 th work.   ∴ in 1 day work done by B = (6 - x)⁄30 th work.   and (6 - x)⁄30 = 1⁄10   ∴ x = 3 days   Answer 3 days
Answer: B
If Q = x% of y and B = y% of x, then which of the following is true?	Select the correct option:	A) 1) Q is smaller than B.	B) 2) A is greater than B	C) 3) Relationship between A and B cannot be determined.	D) 4) If x is smaller than y, then Q is greater than B.	E) 5) None of the above

Solution: Basically Q = B = xy/100   None of the options mentions this; hence 5) None of the above.
Answer: E
A and B undertake to do a piece of work for Rs. 600. A alone can do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. !find the share of each.
Choose one
A) 25	B) 50	C) 75	D) 80	E) None of them

Solution: C's 1 day's work = 1/3-(1/6+1/8)=24   A : B : C = Ratio of their 1 day's work = 1/6:1/8:1/24= 4 : 3 : 1.   A’s share = Rs. (600 *4/8) = Rs.300, B's share = Rs. (600 *3/8) = Rs. 225.   C's share = Rs. [600 - (300 + 225») = Rs. 75.   Answer is 75
Answer: C