MU-NLPC/Calc-aqua_rat huggingface dataset:
Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 cm x 6 m when 10% of its volume is occupied by mortar ? Choose the correct choice from the following
A) 720 B) 600 C) 660 D) 6000 E) NONE OF THESE

Solution: Explanation:   Let the number of bricks be 'N'   10 x 4/100 x 6 x 90/100 = 25/100 x 15/100 x 8/100 x N   10 x 4 x 6 x 90 = 15 x 2 x N => N = 720.   720NSWER IS 720
Answer: A
Solve below question 2x + 1 = -13
Choose one
A) -8  B) -9  C) 9  D) 8  E) -7

Solution: 2x + 1 = -13   x = -7   -7
Answer: E
Adding 25% of x to x is equivalent to multiplying x by which of the following? Choices
A) 12.5 B) 1.05 C) 1.15 D) 1.2 E) 1.25

Solution: 125x/100= 1.25*x   ANSW1.25R:1.25125 /100= 
125 /100 = 5/4 = around 1.25
1.25*x   ANSW1.25R:1.25
Answer: E
The ratio of speeds of a car, a train and a bus is 5:9:4. The average speed of the car, the bus and the train is 72 km/hr together. What is the average speed of the car and the train together ?	Choices.
A) 84 km/hr  B) 74 km/hr  C) 34 km/hr  D) 64 km/hr  E) 14 km/hr

Solution: Let the speeds of the car, train and bus be 5x, 9x and 4x km/hr respectively.   Average speed = 5x + 9x + 4x/3 = 18x /3 = 6x km/hr.   Also, 6x 18  /3= 
18  /3 = 6
6x km/hr.   Also, 6x= 72 => x = 12 km/hr   Therefore, the average speed of the car and train together is = = 7x = 7 x 12 = 84 km/hr.   84 km/hrnswer: 84 km/hr
Answer: A
A certain protective additive increases from 30 days to 45 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?  Pick one:
A) 25%
B) 33 1/3%
C) 50%
D) 66 2/3%
E) 75%

Solution: General formula for percent increase or decrease, (percent change):   percent=50%hange/Original∗100   So, the time between maintenance checks increased by 45−30/30∗100=50   Answer: 50%.
Answer: C
In digging a hole 10 m * 10 m * 100 m the volumes of the sand extracted will be? Options:  A) 100 cu.m  B) 1000 cu.m  C) 10000 cu.m  D) 2000 cu.m  E) 4000 cu.m

Solution: 10 * 10 * 100= 
10 * 10 * 100 = 10_000
10000   ANSWER:10000 cu.m
Answer: C
Suppose that f(x) is a function such that for every real number x,i)f(x)+f(1-x) = 14 and (ii) f(1+x) = 3+f(x). Then f(x)+f(-x)
must equal
Choose the correct choice from the following choices: A) 8 B) 9 C) 10 D) 11 E) 12

Solution: Since (ii) holds for every real number x, it will remain valid if we replace x with   -x. Therefore, f(1-x) = 3+f(-x). Now, from (i), 14 = f(x)+f(1-x) = f(x)+3+f(-x)   so that f(x) + f(-x) = 14-3= 
14-3 = 11
11. (Observe that f(x)= 3x + 4 satisfies the conditions   in the problem.)   correct answer 11
Answer: D
Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 6 minutes more to walk to work than to ride his bike to work, then x equals?  Choose the correct choice
A) 4 B) 7 C) 9 D) 15 E) 20

Solution: Please follow posting guidelines, link is in my signatures.   As for your question, x/60 = blocks/time/block = block^2/time . This is not what you want. You are given x blocks and 60 seconds PER BLOCK. Thus you need to put it as 60*x to give you units of seconds as you are equating this to 360 (which is TIME in seconds.).   Thus the correct equation is : 60*x-20*x=360 ----> 40x=360--> x = 9.   option 9
Answer: C
What is greatest positive integer n such that 2^n is a factor of 12^13? Select the correct option
A) a)10 B) b)12 C) c)16 D) d)26 E) e)60

Solution: The given number is 12^13   =(2*2*3)^13   =(2^26)*(3^13)   So the greatest possible value for n such that 2^n can be factor of given number is 26.   Answer d)26
Answer: D
A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did C get in a profit of Rs.2490 ?
Options
A) s. 332  B) s. 498  C) s. 822  D) s. 812  E) s. 810

Solution: Let the total amount in the partnership be 'x'.   Then A's share = x/3   B's share = x/4   C's share = x/5   D's share = x - (x/3 + x/4 +x/5) = 13x/60   A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13   C's share in the profit of Rs. 2490 = 12 (2490/60) = Rs. 498.   Answer: s. 498
Answer: B
Two same glasses are respectively 1/4th 1/5th full of milk. They are then filled with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is?	Options
A) 9:39
B) 9:31
C) 9:36
D) 9:32
E) 9:34

Solution: 1/4 : 3/4 = (1:3)5 = 5:15   1/5 : 4/5 = (1:4)4 = 4:16   ------   9:31   Answer: 9:31
Answer: B
Before January, the price of a dress was D and the price of a matching pair of shoes was H. In January, the price of the dress increased by 40% and the price of the shoes increased by 50%. In March, Roberta bought both items with a 30% discount. If D = 1H, which of the following represents the amount that Roberta paid?
Choose one:  A) D + 40  B) D + H – 1  C) D + 2H  D) 2.03H  E) 1.21D

Solution: before 2.03Hiscount price was: 1.42.03H+1.5H   After 2.03Hiscount: 1.42.03H +1.5H-.422.03H-.45H   substitute 2.03H=H   final value: 2.03H   Ans Is 2.03H :
Answer: D
Triangle XYZ is an isosceles right triangle. If side XY is longer than side YZ, and the area of the triangle is 25, what is the measure of side XY?	Choose the correct choice from the following options:
A) 10
B) 4√2
C) 8
D) 8√2
E) Cannot be determined from the information provided

Solution: ans A ..10..   xy being larger means it is the hyp..   area =(1/2)*(yz)^2=25 or yz=5*\sqrt{2}..   therefore hyp=xy=10
Answer: A
Series 3,15,35,__,99
Select.
A) 43	B) 53	C) 63	D) 73	E) 83

Solution: 1*3= 
1*3 = 3
3   3*5= 
3*5 = 15
15   5*7= 
5*7 = 35
35   7*9= 
7*9 = 63
63   9*11= 
9*11 = 99
99   ANSWER:63
Answer: C
A sum of Rs. 125000 amounts to Rs. 16500 in 4 years at the rate of simple interest. What is the rate of interest?
Choose the correct option: A) 3% B) 4% C) 5% D) 6% E) 8%

Solution: S.I. = (16500 - 12500) = Rs. 4000\   Rate = (100 * 4000) / (12500 * 4)= 
(100 * 4000) / (12500 * 4) = 8
8%   ANSW8%R:8%
Answer: E
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is: Answers.
A) 279
B) 283
C) 308
D) 318
E) 338

Solution: Other number =	(11 x 7700)/275= 308. Answer : 308
Answer: C
A is 2 times as fast as B. A alone can do the work in 20 days. If A and B work on alternative days, beginning with A, in how many days will the work be completed?	Select:
A) 23 B) 22 C) 21 D) 24 E) 26

Solution: A can finish 1 work in 20 days   B can finish 1/2 work in 20 days - since A is 2 faster than B   This means   B can finish 1 work in 20*2= 
20*2 = 40
40 days   Now using the awesome GMAT formula when two machines work together they can finish the job in= AB/ (A+B) = 20*40/(20+40) = 13 days   Since they alternate on days, it will take them double this time so total time = 13 * 2= 
13 * 2 = 26
26 days   So answer is 26
Answer: E
A committee that includes 12 members is about to be divided into 4 subcommittees with 3 members each. On what percent of the possible subcommittees that Michael is a member of is Annie also a member?  Options:
A) 34%
B) 30%
C) 26%
D) 22%
E) 18%

Solution: Michael is a member of one of the subcommittees.   P(Annie is on the same subcommittee) = 2/11 which is about 18%.   The answer is 18%.
Answer: E
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.64000?  Options.
A) 81000 B) 22887 C) 26877 D) 26771 E) 17121

Solution: 64000* 9/8 * 9/8= 
64000* 9/8 * 9/8 = 81_000
81000   81000nswer:81000
Answer: A
The average of six numbers is X and the average of three of these is Y.If the average of the remaining three is Z, then Choose the correct choice from the following answers
A) x = y + z
B) 2x = y + z
C) x = 2y + 2z
D) None of these
E) Cannot be determined

Solution: Solution   Clearly, we have	X =(3y+3z/6)   or   2x= y + z   Answer 2x = y + z
Answer: B
A certain set of numbers has an average (arithmetic mean) of 50 and a standard deviation of 50.5. If k and n, two numbers in the set, are both within 2 standard deviations from the average, then which of the following could be the sum of k and n?  Choices:
A) -200
B) -130
C) -104
D) 51
E) 305

Solution: 2 standard deviations from the average is from mean - 2*SDtomean + 2*SD, thus from 50-2*50.5=51 to  50+2*50.5= 
 50+2*50.5 = 151
151:   -51 < k < 151   -51 < n < 151   -102 < k+n < 302.   Only option D is in this range.   Answer: 51.
Answer: D
A certain car can travel 40 minutes on a gallon of gasoline at 60 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 120 miles at 60 mph? Choices
A) 15%
B) 20%
C) 25%
D) 27%
E) 40%

Solution: Total time for travelling 120 miles @ 60 mph = 120/60= 
120/60 = 2
2 hour= 120 minutes.   Given, the car uses 1 gallon for every 40 minutes of driving @ 60 mph. Thus in 120 minutes it will use = 3 gallons. Thus, full tank = 3+8= 
3+8 = 11
11 gallons --->3/11= 27% of the fuel used. 27% is the correct answer.
Answer: D
At what rate percent on simple interest will Rs.650 amount to Rs.950 in 5 years?  Choose one:
A) 3.33%
B) 5.93%
C) 4.33%
D) 5.33%
E) 9.23%

Solution: 300 = (650*5*R)/100   R = 9.23%   ANSW9.23%R:9.23%
Answer: E
The sum of the non-prime numbers between 20 and 30, non-inclusive, is  Choose the correct choice from the following choices:
A) 173
B) 185
C) 197
D) 209
E) 221

Solution: sum of consecutive integers from 21 to 29, inclusive ====> (1731 + 173n)/2 * # of terms = (21 + 29)/2 * 9 = 25 * 9= 
25 * 9 = 225
225   sum of non-prime numbers b/w 20 and 30, non inclusive===> 225 - 52 (i.e., 23 + 29, being the prime #s in the range) =173   173nswer: 173
Answer: A
Two cars are driving toward each other. The first car is traveling at a speed of 100 km/h, which is 20% slower than the second car's speed. If the distance between the cars is 1125 km, how many hours will it take until the two cars meet?  Pick.
A) 4	B) 4.5	C) 4.8	D) 5	E) 5.5

Solution: The speed of the first car is 100 km/h.   The speed of the second car is  100 / 0.8= 
 100 / 0.8 = 125
125 km/h.   The two cars complete a total of 225 km each hour.   The time it takes the cars to meet is   1125 / 225= 
  1125 / 225 = 5
5 hours.   The answer is 5.
Answer: D
In an hour a boat goes 10 Km along the stream and 4 Km against the stream. The speed of the boat in still water (in Kmph) is:
Choose the correct option.
A) 7 Kmph	B) 8 Kmph	C) 10 Kmph	D) 12 Kmph	E) None of these

Solution: Explanation:   Let the speed of stream = X Kmph   and the speed of water = 8 Kmph   X + Y = 10   X - Y = 4   X = 7, Y = 3   Speed of stream = 7 Kmph   7 Kmphnswer: Option 7 Kmph
Answer: A
Jim is now twice as old as Fred, who is eight years older than Sam. Four years ago, Jim was four times as old as Sam. How old is Jim now?
Select:
A) 36  B) 40  C) 44  D) 48  E) 52

Solution: J = 2F = 2(S+8) = 2S+16   J-4 = 4*(S-4)   (2S+16)-4 = 4S-16   S = 14 and so J = 44   The answer is 44.
Answer: C
A firm of ready made garments makes both men’s and women’s shirts. Its average profit is 6% of the sales. Its profit in men’s shirts average 8% of the sales and women’s shirts comprise 60% of the output. The average profit per sale rupee in women shirts is  Choose the correct choice from the following answers
A) 0.0466	B) 0.0666	C) 0.0166	D) 0.0366	E) None of these

Solution: Women's shirt comprise 60% of the output.   ∴ Men's shirts comprise (100 – 60) = 40% of the output.   ∴ Average profit from men's shirt = 8% of 40 = 3.2 out of 40   Overall average profit = 6 out of 100   ∴ Average profit from women's shirts = 2.8 out of 60   i.e. 0.0466 out of each shirt.   0.0466nswer 0.0466
Answer: A
In a group of ducks and cows, the total number of legs are 32 more than twice the number of heads. Find the total number of cows. Choose the correct choice from the following answers
A) 12 B) 14 C) 16 D) 18 E) 20

Solution: Let the number of ducks be d   and number of cows be c   Then, total number of legs = 2d + 4c = 2(d + 2c)   total number of heads = c + d   Given that total number of legs are 32 more than twice the number of heads   => 2(d + 2c) = 32 + 2(c + d)   => d + 2c = 16 + c + d   => 2c = 16 + c   => c = 16   i.e., total number of cows = 16   Answer is 16.
Answer: C
A man is 30 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is? Pick: A) 16 B) 19 C) 15 D) 20 E) 28

Solution: Let the son's present age be x years.   Then, man's present age = (x + 30) years.   (x + 30) + 2 = 2(x + 2)   x + 32 = 2x + 4   => x = 28 .   Answer: 28
Answer: E
A man buys a scooter for Rs. 1400 and sells it at a loss of 15%. What is the selling price of the scooter?  Choose the correct choice from the following:
A) Rs. 1240	B) Rs. 1190	C) Rs. 1090	D) Rs. 1130	E) Rs. 1330

Solution: SP=1400×85/100=14×85=1190   Answer : Option Rs. 1190
Answer: B
The area of a square field 3136 sq m, if the length of cost of drawing barbed wire 3 m around the field at the rate of Rs.1.50 per meter. Two gates of 1 m width each are to be left for entrance. What is the total cost?
Select the correct option
A) 978 B) 789 C) 999 D) 778 E) 787

Solution: a2 = 3136   => a = 56   56 * 4 * 3= 
56 * 4 * 3 = 672
672 – 6= 666 * 1.5= 
666 * 1.5 = 999
999   Answer: 999
Answer: C
Pipe A runs 10 liters of water per minute into a tank that has a total volume of 1,200 liters. Pipe B fills an half the tank in 1 hours.
Working together how long will it take both pipes to fill the tank ?	Pick
A) 2 hours and 36 minutes B) 1.5 hours C) 9 hours and 12 minutes D) 15 hours E) 1 hour and 12 minutes.

Solution: Pipe A has a rate of 10 liters per minute which equals a rate of 600 liters per hour.   Pipe B has a rate of 400 liters per hour.   400 + 600 (A+B) = Together they have a rate of 1000 liters per hour.   1200 (The tank ) / 1000 = 6/5 = 1 hour and 12 minutes   Answer -1 hour and 12 minutes.
Answer: E
Nine family members are seated around their circular dinner table. If only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, and Michael and Bobby insist on sitting next to one another, then how many distinct arrangements around the table are possible?  Answers:
A) 7080
B) 8080
C) 9080
D) 10,080
E) 11,080

Solution: Let's consider Michael and Bobby as one unit.   There are 8! possible arrangements of 8 units.   Around a table, there would be repetitions of each arrangement, so we divide by 8.   Then there are 7! arrangements around a circular table.   For each arrangement, Michael and Bobby can switch places, so we multiply by 2.   The number of arrangements is 7!*2 = 10,080.   The answer is 10,080.
Answer: D
Of the integers between 100 and 999, inclusive, how many do not have digit 3 and 5?  Select.
A) 310	B) 320	C) 448	D) 428	E) 528

Solution: Options for the first digit 9-2(2 and 5)=7;   Options for the second digit 10-2= 
10-2 = 8
8;   Options for the third digit   10-2= 
  10-2 = 8
8;   Total numbers possible 7*8*8=320.   Answer: 448.
Answer: C
If 3x=6y=z, what is x+y, in terms of z?  Options
A) z/2  B) 2z  C) z/3  D) 3z/5  E) z/9

Solution: 3x=6y=z   x = z/3   and y = z/6   x+y = z/3 + z/6 = z/2   z/2nswer is z/2
Answer: A
What are the number of ways to select 3 men and 2 women such that one man and one woman are always selected? Answers:
A) 12 ways
B) 14 ways
C) 30 ways
D) 61 ways
E) 51 ways

Solution: The number of ways to select three men and two women such that one man and one woman are always selected = Number of ways selecting two men and one woman from men and five women   = 4C2 * 5C1   = (4 * 3)/(2 * 1) * 5= 
(4 * 3)/(2 * 1) * 5 = 30
30 ways.   Answer: 30 ways
Answer: C
If the cost price of 8 articles is the same as the selling price of 10 articles. Find the gain or loss percentage?
Choose the most appropriate option:	A) 20% gain	B) 20% loss	C) 30% gain	D) 30% loss	E) 40% loss

Solution: Explanation:   Ex:-   2X = 3Y   X = 3   Y = 2   12 cp = 15 sp   Cost price CP = 15   Selling price SP = 12   Formula = (SP-CP)/CP * 100 = (12 - 15)/10 * 100 = 30 % Loss   Answer: Option 30% loss
Answer: D
If $x is invested at a constant annually compound interest rate of k percent, what is the ratio of the total amount including interest after 7n years to that after 3n years?	Select:  A) (1+k/100)^n  B) (1+k)^n  C) (1+kn/100)  D) (1+k/100)^4n  E) (1+kn)

Solution: Amount after 7n years will be = x ( 1 + k/100)^4n   Amount after 3n years will be = x ( 1 + k/100)^3n   So, required ratio will be -   { x ( 1 + k/100)^7n } / {x ( 1 + k/100)^3n } = (1+k/100)^4n   Hence answer will be a. (1+k/100)^4n   (1+k/100)^4n
Answer: D
A store reported total sales of $385 million for February of this year. If the total sales for the same month last year was $320 million, approximately what was the percent increase Q in sales?  Select the correct option:
A) 2%
B) 17%
C) 20%
D) 65%
E) 83%

Solution: Last year's sales = $320 million;   This year's sales = $385 million;   Increase Q = $65 million.   Now, 20% of $320 million is $64 million, which is very close to actual increase of $65 million.   Answer: 20%.
Answer: C
How many seconds will a train 130 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph? Options:
A) 28 sec B) 23 sec C) 24 sec D) 25 sec E) 26 sec

Solution: D = 130 + 150= 
130 + 150 = 280
280   S= 36 * 5/18= 
36 * 5/18 = 10
10 mps   T= 280/10= 
280/10 = 28
28 sec   28 sec
Answer: A
The total cost of a vacation was divided among 4 people. If the total cost of the vacation had been divided equally among 5 people, the cost per person would have been $50 less. What was the total cost cost of the vacation? Choose the correct choice:
A) $200	B) $300	C) $400	D) $500	E) $1000

Solution: C for cost.   P price per person.   C= 4*P   C=5*P-250   Substituting the value of P from the first equation onto the second we get P = 250.   Plugging in the value of P in the first equation, we get C= 1000. Which leads us to answer choice $1000
Answer: E
Find the compound interest and the amount on Rs.8000 at 5% per annum for 3 years when C.I is reckoned yearly?  Options
A) 2661
B) 1651
C) 1267
D) 1627
E) 1261

Solution: 1261xplanation:   A = 8000(21/20)3   = 9261   = 8000   ---------   1261   Answer:1261
Answer: E
Truck P and Truck Q drive on the highway in the same direction at respective rates of 72 kph and 80 kph. If Truck Q is 5 km behind Truck P, by how much does Truck P need to increase the speed to catch up with Truck P in 30 minutes?	Choose the correct choice from the following answers.
A) 2 kph
B) 4 kph
C) 6 kph
D) 8 kph
E) 10 kph

Solution: Truck Q needs to gain 5 km in 30 minutes.   The relative speed difference needs to be 5 km / 30 minutes = 10 km/hour   Truck Q needs to increase up to 82 kph, thus an increase in 2 kph.   The answer is 2 kph.
Answer: A
If A and B are positive integers, A - 4 is divisible by 4 and B - 2 is divisible by 2, all of the following could be the value of A - B Except? Choose the most appropriate option
A) 4
B) 8
C) 10
D) 14
E) 3

Solution: A-4 = 4B   => A = 4B + 4 = 4,8,12,16,20,24,28,32,36   B-2 = 2A   => B = 2A + 2 = 2,4,6,8,10,12,14,16,18,20   4 = 8 - 4   8 = 12 - 4   10 = 16 - 6   14 = 32 - 18   So , we can see that all the answer choices are possible here except 3
Answer: E
Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3?
Choose the most appropriate option:
A) 16
B) 50
C) 277
D) 92
E) 11

Solution: Let the distances between city A to B and B to C be 2x km and 3x km respectively.   Total time taken to cover from A to C   = (2x)/40 + (3x)/60 = (6x + 6x)/120 = 12x/120 = x/10 Average speed = (2x + 3x)/(x/10) = 50 kmph.   Answer:50
Answer: B
Simple interest on a certain sum is 36 over 25 of the sum. Find the rate per cent and time, if both are equal. Answers:
A) 8% and 8 years
B) 6% and 6 years
C) 10% and 10 years
D) 12 % and 12 years
E) None of these

Solution: 36â„25P = PÃ—RÃ—R/100   â‡’ R^2 = 3600â„25 â‡’144=> R = 12%   Also, time = 12 years   Answer 12 % and 12 years
Answer: D
What is the two-digit number whose first digit is a and the second digit is b?. The number is greater than 9.
The number is multiple of 51.
The sum of the digits a and b is 6.	Choose one
A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer C) Either I or II alone sufficient to answer D) Both I and II are not sufficient to answer E) Both I and II are necessary to answer

Solution: From statement I:   A two digit number, greater than 9 and multiple of 51 should be 51 itself.   Because, 2 x 51 = 102 (3 digit number). Therefore, I alone sufficient to answer.   From statement II:   A two digit number, greater than 9 and sum of the digit is 6.   It can be 15, 24, 33, 42, 51. So we cannot determine the required answer from the statement II alone.   Thus, I alone give the answer while II alone not sufficient to answer.   I alone sufficient while II alone not sufficient to answerNSWER I alone sufficient while II alone not sufficient to answer
Answer: A
A certain company had a total annual expenditure of 1.26∗10^7 on employee salaries last year. If the company employed 420 people, what was the average employee salary?  Pick one
A) $20,000  B) $25,000  C) $35,000  D) $30,000  E) $45,000

Solution: Given: Total annual expenditure of 1.26∗10^7 on employee salaries   Total employees = 420   Observe that  420*3= 
 420*3 = 1_260
1260   Therefore try to bring the numerator in terms of 1260   Average salary= (1260*10^4) /420 = 3*10^4 = 30,000   Option $30,000
Answer: D
A fruit-salad mixture consists of apples, peaches, and grapes in the ratio 9:6:5, respectively, by weight. If 40 pounds of the mixture is prepared, the mixture includes how many more pounds of apples than grapes? Options: A) 15 B) 12 C) 8 D) 6 E) 4

Solution: We can first set up our ratio using variable multipliers. We are given that a fruit-salad mixture consists of apples, peaches, and grapes, in the ratio of 6:5:2, respectively, by weight. Thus, we can say:   apples : peaches : grapes = 6x : 5x : 2x   We are given that 39 pounds of the mixture is prepared so we can set up the following question and determine a value for x:   9x + 6x + 5x = 40   20x = 40   x = 2   Now we can determine the number of pounds of apples and of grapes.   pounds of grapes = (5)(2) = 10   pounds of apples = (9)(2) = 18   Thus we know that there are 18 – 10 = 8 more pounds of apples than grapes.   Answer is 8.
Answer: C
A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?  Choose the correct choice from the following answers
A) 388898 B) 2777 C) 2928 D) 15000 E) 2882

Solution: The ratio of their profits A:B = 8:12 = 2:3   Share of A in the total profit = 2/5 * 25000 = Rs.10000 Share of A in the total profit = 3/5 * 25000 = Rs.15000.Answer: 15000
Answer: D
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Choose the correct option.
A) 40  B) 41  C) 45  D) 49  E) 46

Solution: Speed = 45 * 5/18 = 25/2 m/sec   Total distance covered = 360 + 140= 
360 + 140 = 500
500 m   Required time= 500 * 2/25= 
500 * 2/25 = 40
40 sec   40nswer: Option 40
Answer: A
Taylor works in a bakery. He made cookies that cost $2.50 and made $350. How many customer did he have?  Pick:	A) 180 customers	B) 185 customers	C) 250 customers	D) 100customers	E) 140 customers

Solution: A cookie costs $2.50 adding another one is $5. 350 divided by 5 is 70 x 2 is 140. He had 140 customers. The correct answer is 140 customers.
Answer: E
A person purchases 90 clocks and sells 40 clocks at a gain of 10% and 50 clocks at a gain of 20%. If he sold all of them at a uniform profit of 15%, then he would have got Rs. 40 less. The cost price of each clock is? Choose the correct option
A) 16
B) 26
C) 80
D) 26
E) 92

Solution: Let C.P. of clock be Rs. x.   Then, C.P. of 90 clocks = Rs. 90x.   [(110% of 40x) + (120% of 50x)] - (115% of 90x) = 40   44x + 60x - 103.5x = 40   0.5x = 40 => x = 80   Answer:80
Answer: C