MU-NLPC/Calc-aqua_rat huggingface dataset:
A wheel has a diameter of x inches and a second wheel has a diameter of y inches. The first wheel covers a distance of d feet in 400 revolutions. How many revolutions does the second wheel make in covering d feet?
Choose the most appropriate option:
A) 400xy
B) 400y - x
C) 400x - y
D) 400x/y
E) 400y/x

Solution: First Wheel with diameter x inches ----> So the circumference = x*pi --------- (1)   Second Wheel with diameter y inches ----> So the circumference = y*pi --------- (2)   Revolutions = distance/circumference   So, from equation (1)   400 = d/(x*pi)   d = 100 * x * pi ---------- (3)   From equation (2)   Revolutions = d/(y*pi) = (400 * x * pi) / (y*pi) = 400x/y   Answer (400x/y)
Answer: D
A pupil's marks were wrongly entered as 73 instead of 45. Due to that the average marks for the class got increased by half. The number of pupils in the class is :	Choose the correct choice
A) 56
B) 80
C) 20
D) 25
E) 26

Solution: Let there be x pupils in the class.   Total increase in marks = (X*1/2) = X/2.   X/2 = (73 - 45)   => X/2 = 28   => X = 56.   56NSWER:56
Answer: A
Sixty men can stitch 200 shirts in 30 days working 8 hours a day. In how many days can 45 men stitch 300 shirts working 6 hours a day?	Choose the correct choice from the following options.
A) 20	B) 90	C) 10	D) 80	E) 70

Solution: 80   80   We have M1 801 H1 / W1 = M2 802 H2 / W2 (Variation rule)   (60 * 30 * 8)/ 200 = (45 * 802 * 6) / 300   802 = (60 * 30 * 8 * 300) / (200 * 45 * 6) => 802 = 80.
Answer: D
The cost of a one-family home was $ 120,000 in 1980. In 1988, the price had increased to $ 180,000. What was the percent increase in the cost of the home?  Choose the correct choice from the following options.
A) 60%
B) 50%
C) 55%
D) 40%
E) 33.3%

Solution: Percentage Increase = Increase in price / original price *100= (180000-120000)/120000*100= 
(180000-120000)/120000*100 = 50
50%   Answer: 50%
Answer: B
a boy average marks in five subject is 60.he score 90 in math,in physics he scores 95.in rest three in how much maximum subject he can score more than or equal to 95.  Answers.
A) 1 B) 2 C) 3 D) 0 E) 4

Solution: addition of marks of all five subject=300.   math+physics=185   sum of three subject marks=300-185= 
300-185 = 115
115   here it is clearly visible that he can only score more than 95 in one subject if he will score more than 95 in two then it will exceed 115 because marks are not in negative.   answer 1
Answer: A
In a division sum, the remainder is 6 and the divisor is 5 times the quotient and is obtained by adding 2 to the thrice of the remainder. The dividend is?	Answers:
A) 75
B) 78
C) 80
D) 82
E) 86

Solution: Divisor = (6 * 3) + 2= 
(6 * 3) + 2 = 20
20   5 * Quotient= 20   Quotient = 4.   Dividend = (Divisor * Quotient) + Remainder   Dividend = (20 * 4) + 6= 
(20 * 4) + 6 = 86
86   86)
Answer: E
A and B entered into a partnership investing Rs. 16000 and Rs. 12000 respectively. After 3 months, A withdrew Rs. 5000 while B invested Rs. 5000 more. After 3 more months C joins the business with a capital of Rs. 21000. The share of B exceeds that of C, out of a total profit of Rs. 26400 after one year by	Pick:  A) Rs. 3200  B) Rs. 3400  C) Rs. 3600  D) Rs. 3800  E) None of these

Solution: Explanation:   A:B: C = 16000*3 + 11000*9:12000*3 + 17000*9:21000*6   = 147:189:126 = 7:9:6   Difference of B and C’s shares =   Rs. [26400 * (9/22) — 26400 * (6/22))   = Rs. 3600   Option Rs. 3600
Answer: C
The “length of integer x” refers to the number of prime factors, not necessarily distinct, that x has. (If x = 60, the length of x would be 4 because 60 = 2 × 2 × 3 × 5.) What is the greatest possible length of integer z if z < 500?  Pick
A) 4 B) 6 C) 8 D) 10 E) 12

Solution: To maximize the length of z, we should minimize its prime base. The smallest prime is 2 and since 2^8 = 256 < 500, then the greatest possible length of integer z is 8.   The answer is 8.
Answer: C
X and Y are two points respectively on sides AB and AC of triangle ABC such that XY is parallel to BC. If the ratio of area of triangle ADE to that of the trapezium XYCB is 25:144 and BC=13 cm, then find the length of XY.	Choose the correct option
A) 12	B) 13	C) 14	D) 11	E) 5

Solution: ABC and AXY are similar triangles.   So (side of ABC/side of AXY)^2=169/25   side of ABC/side of AXY = 13/5   So the length of XY = 5   Answer - 5
Answer: E
Envelopes can be purchased for $1.50 per pack of 100, $1.00 per pack of 50, or $0.03 each. What is the greatest number of envelopes that can be purchased for $6.30?  Answers
A) 426	B) 430	C) 443	D) 410	E) 486

Solution: I think first we should see in what group envelopes value less, so that we can buy as many as we can with a specific amount of money:   -the 100 pack costs 1.5$, meaning 0.015$ per envelope   -the 50 pack costs 1$, meaning 0.02$ per envelope   -the single envelope costs 0.03$ per envelope   Thus, we have to buy as many 100 packs as we can, then as meny of 50 packs as we can and the remaining envelopes are single ones.   Having 6.3$, we can buy as many as 4 packs of 100 (4 x 1.5$ = 6$). We then have 0.3 $ left. so we buy 10 individual envelopes. If we add up the numbers, we get   400+10= 
  400+10 = 410
410 envelopes. Answer 410
Answer: D
A taxi leaves Point A 5 hours after a bus left the same spot. The bus is traveling 20 mph slower than the taxi. Find the speed of the taxi, if it overtakes the bus in three hours.  Options:  A) 34  B) 32  C) 36  D) 38  E) 40

Solution: Let the speed of bus be v - 20, speed of taxi be v   The bus travelled a total of 8 hrs and taxi a total of 3 hrs.   Hence 8 * (v-20) = 3v   8v - 160 = 3v   5v = 160   v = 32 mph   32
Answer: B
The average temperature from Tuesday to Friday is 48°C and from Wednesday to Saturday is 52°C. If the temperature on Tuesday is 42°C, what was it on Saturday?	Options.
A) 52°C  B) 55°C  C) 58°C  D) 51°C  E) 53°C

Solution: Temperature on Tuesday + Wednesday + Thursday + Friday = 4 x 48°58°C = 192°58°C   Temperature on Tuesday = 42°58°C   Thus, Wednesday + Thursday + Friday = (192°58°C - 42°58°C) = 150°58°C   Temperature on Wednesday + Thursday + Friday + Saturday = 4 × 52°58°C = 208°58°C   Thus, Saturday’s temperature = 208 - 150°58°C = 58°58°C   ANSWER:58°C
Answer: C
In a rectangular coordinate system, what is the area of a rhombus whose vertices have the coordinates (0, 5.5), (8, 0), (0, -5.5), (-8, 0)?	Choose the correct answer
A) 56 B) 88 C) 112 D) 116 E) 120

Solution: Ares of rhombus= 1/2* D1 *D2   Length of 1st diagonal = 8+8= 
8+8 = 16
16   Length of 2nd diagonal= 5.5+5.5= 
5.5+5.5 = 11
11   Area= 1/2*16*11= 
1/2*16*11 = 88
88   88 is the answer
Answer: B
A man engaged a servant on the condition that he would pay him Rs.600 and a uniform after one year service. He served only for 9 months and received uniform and Rs.400, find the price of the uniform?
Pick:  A) s.80  B) s.85  C) s.90  D) s.100  E) s.200

Solution: 9/12 = 3/4 * 600= 
3/4 * 600 = 450
450   400   -------------   50   1/4 -------- 50   1 --------- ?=> Rs.200   ANSWs.200R:s.200
Answer: E
If a young child was 17 months old one year ago, how old was the child, in months, x months ago? Pick one:
A) x − 29 B) x − 12 C) 17 − x D) 24 − x E) 29 − x

Solution: The child's age today is 17 months + 12 months = 29 months   x months ago, the child's age was (29 - x) months old.   The answer is 29 − x.
Answer: E
When positive integer N is divided by positive integer J, the remainder is 11. If N/J = 724.04, what is value of J?	Choose the correct choice from the following.
A) 140 B) 150 C) 260 D) 275 E) 280

Solution: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder   So, Dividend/Divisor = Quotient + Remainder/Divisor   Given that N/J = 724.04   Here 724 is the quotient.   Given that Remainder = 11   So, 724.04 = 724 + 11/J   So, J = 275
Answer: D
Find the side of the largest possible square slabs which can be paved on the floor of a room 2 m 50 cm long and 1 m 50 cm broad. Also find the number of such slabs to pave the floor.  Options.
A) 25, 20	B) 30, 15	C) 50, 15	D) None of these	E) 75,35

Solution: Explanation:   H50, 15F (250, 150) = 50 cm   The number slabs = 250 *150/ 50*50   =15   Answer: 50, 15
Answer: C
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? Choose the correct option.
A) 34 B) 40 C) 68 D) 88 E) 98

Solution: Explanation:   We have: l = 20 ft and lb = 680 sq. ft.   So, b = 34 ft.   Length of fencing = (l + 2b) = (20 + 68)= 
(20 + 68) = 88
88 ft.   Answer: 88
Answer: D
A farmer brought 76 cows, the price of each cow being the same and then sold 20 cows at a profit of 15%, 40 cows at a profit of 19% and the remainder at a profit of 25% making a total profit of Rs.26,280. What is the cost price of each cow?	Select the correct option: A) Rs.1000 B) Rs.1800 C) Rs.1500 D) Rs.1400 E) Rs.2500

Solution: Let cost price of each Cow is x.   Total Cost of 76 Cows = 76x.   SP of 20 Cows = 20x + 15% of 20x   SP of 20 Cows = 20x + 3x = 23x   SP of 40 Cows 20  + 3= 
20  + 3 = 23
23x   SP of 40 Cows= 40x + 19% of 40x = 47.6x   SP of remaining cows (16 cows) = 16x + 25% of 16x = 20x   Total selling price of 76 cows = 23x + 47.6x + 20x = 90.6x.   Total Profit 23  + 47.6  + 20= 
23  + 47.6  + 20 = 90.6
90.6x.   Total Profit= Rs. 26280   Total SP - Total CP = Total Profit   90.6x - 76x = 26280   14.6x = 26280   x = 1800.   CP of each Cow is Rs. 1800.   ANSWER :OPTION Rs.1800
Answer: B
Bus 1 and Bus 2 run between cities A and B. Bus 1 leaves city A at the same time Bus 2 leaves city B,
each at a constant rate of speed. Their first meeting is 60 miles from city A. After reaching their
respective destinations and immediately turning around, their second meeting is 30 miles from city B.
What is the distance in miles between city A and city B? Choose one
A) 90  B) 120  C) 125  D) 150  E) 180

Solution: let d=distance between cities A and B   bus 1 distance to first meeting=60 miles   bus 1 distance from first to second meeting=(d-60)+30=d-30 miles   bus 2 distance to first meeting=d-60 miles   bus 2 distance from first to second meeting=60+(d-30)=d+30 miles   because both buses take the same time for the pre-meeting leg, and   the same time for the inter-meeting leg, and their speeds remain   constant, their ratios between pre-meeting distance and inter-meeting   distance should be the same   therefore, 60/(d-30)=(d-60)/(d+30)   d^2=150d   d=150 miles   150
Answer: D
If the arithmetic mean of seventy five numbers is calculated, it is 35. If each number is increased by 5, then mean of new number is?
Choose the correct choice from the following answers:
A) 87 B) 40 C) 37 D) 28 E) 26

Solution: A.M. of 75 numbers = 35   Sum of 75 numbers = 75 * 35= 
75 * 35 = 2_625
2625   Total increase= 75 * 5= 
75 * 5 = 375
375   Increased sum= 2625 + 375= 
2625 + 375 = 3_000
3000   Increased average= 3000/75= 
3000/75 = 40
40.   Answer:40
Answer: B
A shop produces sarongs. The daily average production is given by 5n + 20, where n is the number of workers aside from the owner. In the first k days, 500 units are produced, and then 5 workers are added to the team. After another k days, the cumulative total is 1300. How many workers were part of the latter production run? Choose the correct choice from the following answers:	A) A)6	B) B)10	C) C)9	D) D)15	E) E)23.5

Solution: The daily average production is given by 5n + 20- given   In the first k days, 500 units are produced   = (5n+20)K =500   k = 500/5n+20...................................1   5 workers were added = 5(n+5)+20 = 5n +45   cumulative is 1300 .. thus for the current period = 1300 -500= 
1300 -500 = 800
800   (5n+45)K= 800   k = 800/5n+45........................................2   equate 1 and 2   500/5n+20 = 800 /5n+45   500(5n+45) = 800(5n+20)   25n + 225 = 40n + 160   -15n = -65   n = 4   thus n+5 = 9   hence 9
Answer: C
A car started running at a speed of 36 km/hr and the speed of the car was increased by 2 km/hr at the end of every hour. Find the total distance covered by the car in the first 10 hours of the journey.
Choose the correct choice
A) 45 km  B) 76 km  C) 25 km  D) 15 km  E) 30 km

Solution: 45 km   45 km   The total distance covered by the car in the first 10 hours = 36 + 38 + 40 + 42 + 44 + 46 + 48+ 50 + 52 + 54= sum of 10 terms in 45 kmP whose first term is 36 and last term is 54 = 10/2 [36 + 54] = 450 km.
Answer: A
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples?
Choose the correct choice from the following options
A) 5/26	B) 5/78	C) 5/21	D) 5/56	E) 5/12

Solution: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ * ⁶C₁)   As remaining person can be any one among three couples left.   Required probability = (⁵C₂ * ⁶C₁)/¹⁰C₅   = (10 * 6)/252   = 5/21   5/26nswer:5/26
Answer: A
Kristy, Amy, and Blair are going on a cross-country road trip from Washington to Maine. The total driving time is 48 hours. Each driver will drive 6 hours daily and in the remaining hours of the day the group will sight-see and explore. They will sleep in the car when they are not driving. They all have driver's licenses, but Amy is scared of driving in unfamiliar places and would prefer not to take the wheel. How much sooner would the group arrive in Maine, in hours, if Amy chose to drive, compared to just Kristy and Blair?	Choose the correct choice from the following answers
A) 12
B) 24.76
C) 31.92
D) 36.92
E) 24

Solution: All three girls calculation: 3 girls x 6 hours = 18 hours of driving per day, 6 nondriving hours/day   48 total trip hours divided by 18 daily driving hours = 2.67 days / driving rotations   2.67 x 24 (hours in one day) = 64.08 total hours for road trip   2 girls calculation: 2 girls x 6 hours = 12 hours of driving per day, 12 nondriving hours/day   48 total trip hours divided by 12 daily driving hours = 4 days / driving rotations   4 x 24 (hours in one day) = 96 total hours for road trip   FINAL ANSWER: 96 hours (2 girls total) minus 64.08 (3 girls total) = ANSWER 31.92: The group would arrive in Maine 31.92 hours sooner if all three drove.
Answer: C
P, Q and R can do a work in 10 , 12 and 15 days respectively. What is the share ratio of P, Q and R respectively?
Answers
A) 6 : 5 : 7 B) 6 : 5 : 4 C) 6 : 5 : 3 D) 6 : 4 : 5 E) 4 : 5 : 6

Solution: The ratio of their working rates = 1/10 : 1/12 : 1/15 = 6 : 5 : 4.   Answer: 6 : 5 : 4
Answer: B
A bookstore has a shelf that contains biographies which normally sell for $20 each and mysteries that normally sell for $12 each. During a sale, the biographies and mysteries are discounted at different rates so that a customer saves a total of $19 from the normal price by buying 5 discounted biographies and 3 discounted mysteries. If the sum of the discount rates for the two types of books is 30 percent, what is the discount rate on mysteries?  Choose the correct choice from the following choices: A) 17.18% B) 12% C) 13% D) 14% E) 15%

Solution: Let B be the discount on biographies and M be the discount on mysteries   So., B + M = 0.30 -----(1)   17.18%nd   (20*5 + 12*3) - (20*5*(1-B) + 12*3*(1-M)) = 19   --> 100(1-(1-B)) + 36(1-(1-M) = 19   100B + 36M = 19 ------(2)   Solving 12., we get M = 0.1718 = 17.18   17.18%
Answer: A
Amar started a business investing Rs. 34000/-. After 3 months, Vamsi joined him with a capital of Rs. 40000/-. At the end of the year, they make a profit of Rs. 17040/-. What will be Amar’s share in the profit?  Choose the correct choice
A) Rs. 9025/-
B) Rs. 9052.5/-
C) Rs. 9503.5/-
D) Rs. 9504.5/-
E) None of these

Solution: Explanation:   Amar : Vamsi = (34000 * 12 : 40000 * 9)   = 408000 : 360000   = 408 : 300   = 51 : 45   Amar’s share = 17040 * 51/91 = 177.5 * 51 = Rs. 9052.5/-   Answer: Option Rs. 9052.5/-
Answer: B
A bag contains ten marbles of the same size: 3 are identical green marbles, 2 are identical red marbles, and the other 5 are five distinct colors. If 5 marbles are selected at random, how many distinct combinations Q of five marbles could be drawn? Choices.
A) 41	B) 51	C) 62	D) 72	E) 82

Solution: there will be different cases, which we will take one by one..   1)case 1 when all five colours are different-7c5=21..   2)case 2 when three different colours and 2 of same type=6c3*2=30..   3)case 3 when two different colours and 3 of same type=6c2=15..   4)case 4 when one different colours and 2 of two different colors=5c1*4!/2!2!=15...   5)case 4 when 3 of one type and 2 of other colour=1...   total Q-82 ans 82
Answer: E
If the greatest common divisor of (n+2)!, (n-1)!, and (n+4)! is 120, what is the value of n?
Choose the correct choice from the following:  A) 4  B) 5  C) 6  D) 7  E) 3

Solution: Notice that:   1! = 1   2! = 2   3! = 6   4! = 24   5! = 120   So, the smallest factorial must be 5! for the GCD to be 120   The smallest of the three factorials is (n-1)!   So, we need (n-1)! to equal 5!   This means that n = 6   If n = 6, then (n+2)!, (n-1)!, and (n+4)! become 8!, 5! and 10!   Let's CONFIRM this conclusion   8! = (1)(2)(3)(4)(5)(6)(7)(8) = (120)(6)(7)(8)   5! = (1)(2)(3)(4)(5) = 120   10! = (1)(2)(3)(4)(5)(6)(7)(8)(9)(10) = (120)(6)(7)(8)(9)(10)   As you can see, 120 is a divisor of all three factorials.   In fact, 120 is the GREATEST COMMON divisor of all three factorials.   Answer: 6
Answer: C
The bus that travels from St. Louis to Chicago and back comes to St. Louis every 3 hours while the bus that travels from St. Louis to Springfield and back comes to St. Louis every 6 hours. If at 12:00 o'clock both bused arrived at St. Louis, at what time will they meet in St. Louis again?  Pick.
A) 16:00.  B) 18:00  C) 20:00  D) 22:00.  E) 24:00.

Solution: Time taken by bus to travel from St. Louis to Chicago and back comes to St. Louis = 3 hours   Time taken by bus to travel from St. Louis to Springfield and back comes to St. Louis = 6 hours   Time taken by both buses to meet again in St. Louis will be LCM of 3 and 6 = 6   If the buses start at 12:00 o'clock from St. Louis , they will meet again in St. Louis at 18:00 hours   Answer 18:00
Answer: B
A man bets on no.16 on a roulette wheel 14times and losses each time. On the 15th span he does a quick calculation and finds out that the no. 12 had appeared twice in the 14 spans and istherefore, unable to decide whether to bet on 16 or 12 in the 15th span. Which will give him the best chance and what r the odds of winning on the bet that he takes?  Answers
A) 35:1	B) Either ;35:1	C) Either 70;35:1	D) Either 55;45:1	E) Either 65;35:5

Solution: Each of the span is an independent event and the outcome of the 15th span will not depend on the outcome of the earlier spans.   Either ;35:1   Either ;35:1)
Answer: B
Let A be the event that a randomly selected two digit number is divisible by 2 and let B be the event that a randomly selected two digit number is divisible by 10. What is P(A and B)?	Choose the correct choice from the following:
A) 1/20
B) 1/15
C) 1/12
D) 1/8
E) 1/2

Solution: P(1/20 and B) = 1/2*1/10 = 1/20   The answer is 1/20.
Answer: A
A train 280 m long, running with a speed of 63 km/hr will pass a tree in? Select:
A) 65 sec  B) 16 sec  C) 18 sec  D) 13 sec  E) 76 sec

Solution: Speed = 63 * 5/18 = 35/2 m/sec   Time taken   = 280 * 2/35= 
280 * 2/35 = 16
16 sec   Answer:16 sec
Answer: B
Shaun is starting a new diet plan that offers him the choice of fruit or yogurt for breakfast, 6 different entrees for lunch, and 9 different entrees for dinner. If Shaun chooses an Italian entree for lunch, he always chooses an Italian entree for dinner. If Shaun chooses a Chinese entree for lunch, he never chooses a Chinese entree for dinner. If there are 2 Italian entrees and 2 Chinese entrees among the lunch choices, and 3 Italian entrees and 3 Chinese entrees among the dinner choices, from how many different daily menus can Shaun choose? Choose the correct choice:	A) 24	B) 36	C) 72	D) 90	E) 108

Solution: Let the Breakfast set be {F , Y}   Lunch be {I ,I , C,C , L1,L2}   Dinner be {I,I,I , C,C,C, D1,D2,D3}   There are only 2 restrictions, Italian Lunch has to go with Italian Dinner and Chinese Lunch cannot go with Chinese dinner.   So the set of Breakfast, Lunch and Dinner will   {Any BF, Italian Lunch, Italian Dinner } = 2 * 2 * 2   {Any BF, Chinese Lunch, Not Chinese Dinner} = 2 * 2 * 6   {Any BF, Not Italian or Chinese Lunch, Any Dinner} = 2 * 2 * 9   Adding all these gives 72.   Answer is 72
Answer: C
If 3/p=6 & 3/q=18 then p-q=?	Select the correct option:  A) 5/24  B) 6/24  C) 7/24  D) 8/24  E) 1/3

Solution: p=3/6 , q=3/18=>q=1/6   therefore   p-q=(1/2)-(1/6)=1/3   ANSW1/3R:1/3
Answer: E
What is the smallest no. which must be added to 532869 so as to obtain a sum which is divisible by 9?  Choose the correct choice from the following options:
A) 9  B) 2  C) 1  D) 3  E) 6

Solution: For 532869 , 5+3+2+8+6+9=33   3 must be added to 532869 to make it divisible by 9.   Now ,5+3+2+8+7+2=27=> 27 is a multiple of 9 and hence 532869 is also divisible by 9   3
Answer: D
In a division sum, the remainder is 8 and the divisor is 3 times the quotient and is obtained by adding 3 to the thrice of the remainder. The dividend is: Choose the correct choice from the following
A) 200	B) 251	C) 250	D) 262	E) 254

Solution: Diver = (8*3)+3= 
(8*3)+3 = 27
27   3* Quotient= 27   Quotient = 9   Dividend = (Divisor * Quotient) + Remainder   Dividend = (27 * 9) + 8= 
(27 * 9) + 8 = 251
251   251
Answer: B
Six bells commence tolling together and toll at intervals of 2,4,6,8,10 and 12 seconds respectively. in 30 m9nutes,how many times do they toll together ? Choices:
A) 4
B) 10
C) 15
D) 16
E) 17

Solution: Solution   L.C.M. of 2,4,6,8,10,12 is 120.   So, the bells will toll together after every 120 seconds, i.e., 2 minutes   In 30 minutes, they will toll together left [   ( 30/2 )+ 1= 
  ( 30/2 )+ 1 = 16
16 times. Answer 16
Answer: D
The difference between compound and simple interest on a certain sum of money for 3 years at 6 2/3% p.a is Rs.184. Find the sum? Choose the correct option: A) 33772 B) 26782 C) 26788 D) 13500 E) 27761

Solution: P = (184*106) / [6 2/3 * 6 2/3 *(300*6 2/3)]   P = 13500   Answer: 13500
Answer: D
What annual payment will discharge a debt of Rs. 1125 due in 2 years at the rate of 5% compound interest? Choose the correct choice from the following answers:
A) 993.2 B) 551.25 C) 534.33 D) 605.03 E) 646.33

Solution: Explanation:   Let each installment be Rs. x. Then,   x/(1 + 5/100) + x/(1 + 5/100)2 = 1125   820x + 1125 * 441   x = 605.03   So, value of each installment = Rs. 605.03   Answer: Option 605.03
Answer: D
If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 8400 ?	Choose the correct choice from the following answers
A) Rs.12  B) Rs.16  C) Rs.14  D) Rs.10  E) Rs.18

Solution: Required difference = [3 ½ % of Rs.8400] – [3 1/3 % of Rs.8400]   = [(7/20-(10/3)]% of Rs.8400 =1/6 % of Rs.8400   = Rs. [(1/6)8(1/100)*8400] = Rs. 14.   Answer is Rs.14.
Answer: C
If 0.5% of A =80 paise, then the value of A is ? Options: A) Rs. 170 B) Rs. 160 C) Rs. 1.70 D) Rs. 4.25 E) None

Solution: Answer   ∵ 0.5/100 of A = 80/100   ∴ A = Rs. (80 / 0.5) = Rs. 160   Correct Option: Rs. 160
Answer: B
In the Biotechnology class of 2000, there were X graduates. 32 of the graduates found a job, 45 continued on to their second degree and 13 did both. If only 9 people didn't do both, What is X equal to?  Pick:
A) 69.	B) 71	C) 73	D) 75	E) 76

Solution: Graduates got job = 32   Graduates continued to second degree = 45   Graduates got job and continued to second degree = 13   Graduates didn't get job and didn't continue to second degree = 9   Job	No Job	Total   Second Degree 13	32	45   No Second Degree	19	9	28   Total	32	41	X   Therefore X = 73   Answer 73
Answer: C
The original price of a car was $30,000. Because the car owner thought he could get more money for the car, he set a new price by increasing the original price of the car by 5%. After a week, the car had not sold, so the owner discounted the new price by 5%, and the car was finally sold. What price was the car sold for?
Options:
A) $29,915 B) $29,925 C) $29,935 D) $29,945 E) $29,955

Solution: The car was sold for (0.95)(1.05)($30,000)=$29,925.   The answer is $29,925.
Answer: B