MU-NLPC/Calc-aqua_rat huggingface dataset:
The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes? Choices.
A) 15	B) 66	C) 18	D) 16	E) 81

Solution: Explanation:   90 * 10/60= 
90 * 10/60 = 15
15 kmph   15nswer:15
Answer: A
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?  Choose the correct choice from the following choices:
A) 238
B) 480
C) 287
D) 117
E) 181

Solution: Explanation:   SP = 800   Profit = 25%   CP = (SP)*[100/(100+P)]   = 800 * [100/125]   = 640   Loss 800 *  100/125= 
800 *  100/125 = 640
640   Loss= 25% = 25% of 640 = Rs.160   SP = CP - Loss = 640 - 160 = Rs.480   Answer: 480
Answer: B
One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 300 of the attendees are neither female nor students, what is the total number of attendees at the convention? Choose the correct choice from the following choices:
A) 600  B) 300  C) 1200  D) 1500  E) 1800

Solution: Let no. of Attendee are A.   Now As per the condition of the problem stated above .   We have following population in the convention as Attendee.   Total no. of females = [2/3]*A   Total no. of females as student : [1/6]*A   Total no. of students = [1/3]*A   Total no. of male as student = [1/6]*A   Total no. of males = A - [2/3]*A = [1/3]A   No. of males which are not student = [1/3]A - [1/6]*A = 300   Hence A = 1800   Total no of males who are not student will be the answer as it states it should be neither female nor student   So Answer is 1800
Answer: E
If a boat is rowed downstream for 200 km in 10 hours and upstream for 96 km in 12 hours, what is the speed of the boat and the river?	Pick.
A) 14 , 18 B) 14 , 6 C) 14 , 14 D) 6 , 6 E) 14 , 10

Solution: Explanation:   If x: speed of boats man in still water   y: speed of the river   Downstream speed (Ds) = x + y   Upstream speed (Us) = x â€“ y   x = (Ds + Us) / 2   y = (Ds â€“ Us) / 2   In the above problem Ds = 20 ; Us = 8   x = (20 + 8) / 2 = 28/2= 
28/2 = 14
14 km/hr   y= (20 - 8) /2 = 12/2= 
12/2 = 6
6 km/hr   ANSWER: 14 , 6
Answer: B
On an order of 3 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of:
Select:	A) 20%	B) 25%	C) 30%	D) 35%	E) 40%

Solution: Clearly, the retailer gets 1 dozen out of 4 dozens free.   Equivalent discount = 1/4 * 100= 
1/4 * 100 = 25
25%.   Answer 25%) 25%
Answer: B
Ajith and Rana walk around a circular course 115 km in circumference, starting together from the same
point. If they walk at speed of 4 and 5 kmph respectively, in the same direction, when will they meet ? Select.
A) after 20 hours  B) after 115 hours  C) after 115 minutes  D) after 20 minutes  E) after 25 minutes

Solution: Rana is the faster person. He gains 1 km in 1 hour. So Rana will gain one complete round over   Ajith in 115 hours. i.e. they will meet after 115 hours.   Answer: after 115 hours
Answer: B
If a Ã— b = 2a - 3b + ab, then 4 Ã— 5 + 5 Ã— 4 is equal to :  Pick:  A) 31  B) 32  C) 43  D) 45  E) 26

Solution: Explanation:   4 Ã— 5 + 5 Ã— 4 = (2 Ã— 4 - 3 Ã— 5 + 4 Ã— 5) + ( 2 Ã— 5 - 3 Ã— 4 + 5 Ã— 4)   = (8 -15 + 20 + 10 - 12 +20)= 
(8 -15 + 20 + 10 - 12 +20) = 31
31.   31nswer: 31
Answer: A
If ab-a-b=265
bc-b-c=155
ac-c-a=150
then find a?  Select the correct option
A) 16
B) 17
C) 18
D) 19
E) 20

Solution: (A-1)(17-1)=A17-A-17+1=265+1=266..(1)   (17-1)(C-1)=17C-17-C+1=155+1=156..(2)   (C-1)(A-1)=CA-C-A+1=150+1=151..(3)   (1)/(2) gives..(A-1)/(C-1)=266/156..(4)   (3)*(4) gives..(A-1)^2=257.47...A=17.04   Solving other equations..17=17.58 and C=10.4   ANSWER:17
Answer: B
A rectangular field is to be fenced on three sides leaving a side of 10 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required?	Options
A) 144ft	B) 88ft	C) 22ft	D) 112ft	E) 146t

Solution: Given that length and area, so we can find the breadth.   Length x Breadth = Area   10 x Breadth = 680   Breadth = 68 feet   Area to be fenced = 2B + L = 2 (68) + 20 = 146 feet   Answer: 146t) 146ft
Answer: E
How many cubes of 10cm edge can be put in a cubical box of 1m edge Choose the correct choice from the following choices:
A) 10 B) 100 C) 1000 D) 10000 E) 3000

Solution: number of cubes=(100x100x100)/(10x10x10)=1000 Answer: 1000
Answer: C
A has 10000 chocolates.20% of the chocolates are Eaten.What percentage of the uneaten Chocolates must be eaten so that 3/2 of all chocolates are eaten?	Choose one:
A) 39.25  B) 37.25  C) 37.26  D) 38.21  E) 38.32

Solution: Number of chocolates=10,000   Currently Eaten=10,000*20/100=2000   Uneaten Chocolates=10000-2000= 
10000-2000 = 8_000
8000   2/3 of all chocolates=5000   The number of chocolates to be eaten to make 2/3 of all chocolates Eaten =5000-2000= 
5000-2000 = 3_000
3000   So now the question remains - 3000 is how much percentage of uneaten chocolates (8000)= 3000 * 100 /8000= 
3000 * 100 /8000 = 75/2 = around 37.5
37.5   Answer (37.25)
Answer: B
In Plutarch Enterprises, 60% of the employees are marketers, 20% are engineers, and the rest are managers. Marketers make an average salary of $50,000 a year, and engineers make an average of $80,000. What is the average salary for managers if the average for all employees is also $80,000?	Choose the correct choice from the following:
A) $80,000
B) $130,000
C) $240,000
D) $290,000
E) $340,000

Solution: For sake of ease, let's say there are 10 employees: 6 marketers, 2 engineers, and 2 manager.   Average company salary * Number of employees = Total company salary   >>> $80,000 * 10 = $800,000   Subtract the combined salaries for the marketers (6 * $50,000) and the engineers (2 * $80,000)   >>> $800,000 - $300,000 - $160,000 = $340,000.   The correct answer is $340,000.
Answer: E
A man walks from B to C, a distance of x miles, at 6 miles per hour and returns at 12 miles per hour. What is his average speed? Choose the correct choice from the following answers: A) 10 mph B) 9.6 mph C) 8.0 mph D) 8.4 mph E) 4 mph

Solution: Total distance covered = 2x   Time taken12miles / hour = x/12 hrs   Time taken @ 6 miles / hour = x/6 hrs   Avg speed = 2x / (x/6 + x/12) = 8 mph   Ans is 8.0 mph
Answer: C
A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to
contradict each other, narraƟng the same incident Answers.
A) 30%
B) 35%
C) 40%
D) 45%
E) 50%

Solution: Explanation:   Let A = Event that A speaks the truth   35% = Event that 35% speaks the truth   Then P(A) = 75/100 = 3/4   P(35%) = 80/100 = 4/5   P(A-lie) = 1-3/4 = 1/4   P(35%-lie) = 1-4/5 = 1/5   Now   A and 35% contradict each other =   [A lies and 35% true] or [35% true and 35% lies]   = P(A).P(35%-lie) + P(A-lie).P(35%)   [Please note that we are adding at the place of OR]   = (3/5*1/5) + (1/4*4/5) = 7/20   = (7/20 * 100)= 
(7/20 * 100) = 35
35%   Answer: 35%
Answer: B
♠n denotes the number obtained when n is rounded to the nearest tenth. For example ♠4.31 = 4.3
♠2.423 - ♠3.421 = Choose the correct choice from the following answers: A) 1.05 B) 1.04 C) -0.8 D) -1.0 E) -0.1

Solution: ♠2.423 - ♠3.421   2.4 - 3.2 = -0.8   Answer : -0.8
Answer: C
In digging a pond 25 m * 10 m * 5 m the volumes of the soil extracted will be?  Answers:	A) 1750	B) 1000	C) 2866	D) 2787	E) 1121

Solution: 25 * 10 * 5 = 1750   1750nswer: 1750
Answer: A
A zeebra chases a tiger 5 hours after the tiger runs. zeebra takes 6 hours to reach the tiger. If the average speed of the zeebra is 55 kmph, what s the average speed of the tiger?	Choices:
A) 35kmph
B) 32kmph
C) 30kmph
D) 31kmph
E) 20kmph

Solution: tiger take 11 hours and zeebra take 6 hours...then Distance chased by them is 55*6.so speed of tiger is (55*6)/11= 
(55*6)/11 = 30
30kmph.   ANSWER IS 30kmph
Answer: C
The speed of a boat in upstream is 45 kmph and the speed of the boat downstream is 90 kmph. Find the speed of the boat in still water and the speed of the stream?	Choices
A) 70,10 kmph
B) 67.5,22.5 kmph
C) 70.5,70.5 kmph
D) 78.6,10.25 kmph
E) 70,12 kmph

Solution: Speed of the boat in still water   = (45+90)/2= 
(45+90)/2 = 135/2 = around 67.5
67.5 kmph. Speed of the stream= (90-45)/2= 
(90-45)/2 = 45/2 = around 22.5
22.5 kmph.   Answer:67.5,22.5 kmph
Answer: B
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?	Pick one:
A) 7m
B) 6m
C) 5m
D) 2m
E) 4m

Solution: Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   => l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   => (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 => l + b = 14   12(l + b)2 = 49lb   => 12(14)2 = 49lb   => lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
8 - 6 = 2
2m.   Answer: 2m
Answer: D
From January 1, 1991, to January 1, 1993, the number of people enrolled in health maintenance organizations increased by 15 percent. The enrollment on January 1, 1993, was 45 million. How many million people, to the nearest million, were enrolled in health maintenance organizations on January 1, 1991 ?
Options
A) 38
B) 39
C) 40
D) 41
E) 42

Solution: Soln:-   15x=45 --> 23/20*x=45 --> x=45*20/23=900/23=~39.   Answer: 39.
Answer: B
A team of 11 member is to be formed from a group of 5 men and 8 women. At most 3 men are allowed. How many combination are possible.	Choose the most appropriate option
A) 9	B) 10	C) 11	D) 12	E) 13

Solution: At most 3 men means not more than 3,   Case 1 All women not possible   Case 2 10 women and 1men not possible   Case 3 9 women and 2 men not possible   Case 4 8 women and 3 men =5C3 * 8C8 = 10.   ANSWER:10
Answer: B
A trader bought a car at 20% discount on its original price. He sold it at a 45% increase on the price he bought it. What percent of profit did he make on the original price?	Choose the most appropriate option
A) A)10%	B) B)12%	C) C)16%	D) D)20%	E) E)22%

Solution: Original price = 100   16%P = 80   S = 80*(145/100)= 
80*(145/100) = 116
116   100 - 116= 16%   16%)
Answer: C
The slant height of a cone is 12 cm and radius of the base is 4cm, find the curved surface of the cone.
Pick one:
A) 33
B) 88
C) 48
D) 77
E) 27

Solution: π * 12 * 4 = 48   Answer:48
Answer: C
Two trains of length 400 m and 200 m are 200 m apart. They start moving towards each other on parallel tracks, at speeds 54 kmph and 36 kmph. After how much time will the trains meet?	Pick one:	A) 8 sec	B) 20/7 sec	C) 33/7 sec	D) 21/7 sec	E) 32/7 sec

Solution: They are moving in opposite directions, relative speed is equal to the sum of their speeds.   Relative speed = (54 + 36)*5/18= 
(54 + 36)*5/18 = 25
25 mps.   The time required= d/s = 200/25= 
200/25 = 8
8 sec.   8 secnswer : 8 sec
Answer: A
What is the greatest integer m for which the number 40!/14^m is an integer?	Choose the correct choice from the following answers.
A) 8  B) 7  C) 6  D) 5  E) 4

Solution: 14^m = 2^m*7^m.   Let's figure out how many 7's are in the prime factorization of 40!   The multiples of 7 are: 7, 14, 21, 28, 35.   Thus 7^5 will divide 40! but 7^6 will not.   Clearly 2^5 will divide 40!   So m=5 is the largest possible integer.   The answer is 5.
Answer: D
If n = (33)^43 + (23)^33 what is the units digit of n?	Pick.
A) 0	B) 2	C) 4	D) 6	E) 8

Solution: First of all, the units digit of (33)^23 is the same as that of 3^23 and the units digit of (23)^33 is the same as that of 3^33. So, we need to find the units digit of 3^23 + 3^33.   Next, the units digit of 3 in positive integer power repeats in blocks of four {3, 9, 7, 1}:   3^1=3 (the units digit is 3)   3^2=9 (the units digit is 9)   3^3=27 (the units digit is 7)   3^4=81 (the units digit is 1)   3^5=243 (the units digit is 3 again!)   ...   Thus:   The units digit of 3^23 is the same as the units digit of 3^3, so 7 (43 divided by the cyclicity of 4 gives the remainder of 3).   The units digit of 3^33 is the same as the units digit of 3^1, so 3 (33 divided by the cyclicity of 4 gives the remainder of 1).   Therefore the units digit of (33)^23 + (23)^33 is  3 + 3= 
 3 + 3 = 6
6.   Answer: 6.
Answer: D
If n = 2×3×5×7×11×13×17, then which of the following statements must be true?
I. n2 is divisible by 600
II. n + 19 is divisible by 19
III. is even n+4 / 2 = even
IV . divisible by 35 only  Answers.
A) I only B) none and IV only C) III only D) I and III only E) e None

Solution: n = 2×3×5×7×11×13×17 = 39270   I. not divisible by 600   II 39270+19= 
39270+19 = 39_289
39289 not divisible by 19   III. 39270+4/2= odd= 19637   iv. divisible by 35   none and IV only
Answer: B
The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is?  Choose the correct choice from the following choices
A) 255
B) 267
C) 235
D) 277
E) 211

Solution: Speed = [45 X 5/18] m/sec = [25/2] m/sec Time = 30 sec Let the length of bridge be x metres. Then, (140 + x)/30 = 25/2 => 2(140 + x) = 750 => x = 235 m.   Answer:235
Answer: C
Let us say that a table tennis tournament was going on with knock out terms which means the one who loses the match is out of the tournament. 101 players took part in that tournament. How many matches were played?	Options.
A) 90 matches
B) 95 matches
C) 99 matches
D) 100 matches
E) 87 matches

Solution: D100 matches. The number of matches will always sum up to one less than the number of players in a knock out tournament. You may calculate it in any manner. Thus 100 matches were played.
Answer: D
A room is 18 meters long, 15 meters wide 12 meters in height. The longest possible rod which can be placed in the room is	Choose the correct answer
A) 25.28 meters B) 24.28 meters C) 23.28 meters D) 26.28 meters E) 20.28 meters

Solution: Square root of 18^2+15^2+12^2...(Diognal) which is square root of 639 that lies 25<√639<26. Hence the answer should be 25.28 meters
Answer: A
A train running at the speed of 60 km/hr crosses a pole in 12 seconds. Find the length of the train.  Select the correct option: A) 175 m B) 145 m C) 140 m D) 200 m E) 155 m

Solution: Speed = 60*(5/18) m/sec = 50/3 m/sec   Length of Train (200 mistance) = Speed * Time     (50/3) * 12= 
  (50/3) * 12 = 200
200 meter   ANSWER: 200 m
Answer: D
A sum fetched a total simple interest of Rs. 4016.25 at the rate of 1% p.a. in 5 years. What is the sum?  Choose one:
A) 82762 B) 12877 C) 82882 D) 80925 E) 80325

Solution: Principal = (100 * 4016.25) / (1 * 5)   = Rs.80325.   Answer:80325
Answer: E
A vendor bought 6 toffees for a rupee.How many for a rupee he must sell to gain 20%.  Choices
A) 3  B) 4  C) 5  D) 6  E) 7

Solution: SP=(100+20)*1/100= 
(100+20)*1/100 = 6/5 = around 1.2
1.20   1.20 rupees=6 toffees   so for 1 rupee=6/1.2= 
6/1.2 = 5
5   ANSWER:5
Answer: C
A roofing crew can roof the house in 10 hours. Another crew can roof the house in 15 hours. How many hours will it take for both of them working together to roof the house?
Choose the correct choice from the following answers.
A) 6 B) 5 C) 8 D) 4 E) 9

Solution: Work hrs=6B/(6+B)= 150/25= 
150/25 = 6
6   6nswer is 6
Answer: A
A number is said to be prime saturated if the product of all the different positive prime factors of z is less than the square root of z. What is the greatest two digit prime saturated integer ?	Choose the correct answer
A) 99
B) 98
C) 97
D) 96
E) 95

Solution: Clearly D A number is said to be prime saturated if the product of all the different positive prime factors of z is less than the square root of z.   96 has more number of smaller prime factor thats the clue !!=96
Answer: D
The marked price of a radio is Rs 1,600. Rahul gives successive discount of 10%, r% to the Pradeep. If Pradeep pays Rs 1.224 for the radio, find the value of r.	Select the correct option:	A) 10%	B) 20%	C) 25%	D) 15%	E) 30%

Solution: Marked price of the article = Rs 1,600   Therefore, Selling price = (100 - 10)% x (100 - r%) x 1600   = (90/100) x [(100 - r) / 100] x 1600   Given, 1224 = 9/10 x (100 - r) x 16   => 1224 x 10 / (9 x 16) = (100 – r)   85 = 100 - r   r = 15%   ANSWER:15%
Answer: D
On my sister's birthday, she was 132 cm in height, having grown 10% since the year before. How tall was she the previous year?
Choose one:
A) 130 cm B) 126 cm C) 120 cm D) 116 cm E) 112 cm

Solution: Let the previous year's height be x.   1.1x = 132   x = 120   The answer is 120 cm.
Answer: C
How many different ways are possible to arrange the letters of the word “MACHINE” so that the vowels may occupy only the odd positions?	Select the correct option:
A) 800 B) 125 C) 348 D) 576 E) None

Solution: Solution   MACHINE has 4 consonants and 3 vowels.The vowels can be placed in position no. 1, 3, 5, 7   ⇒ Total number of ways possible = 4P3 = 24.   For each of these 24 ways the 4 consonants can occupy the other 4 places in 4P4 ways   ⇒ Total = 24 × 24 = 576   Answer 576
Answer: D
If an item that originally sold for z dollars was marked up by x percent and then discounted by y percent, which of the following expressions Q represents the final price of the item?
Choose the most appropriate option.
A) Q=(10,000z + 100z(x – y) – xyz)/10,000  B) Q=(10,000z + 100z(y – x) – xyz)/10,000  C) Q=(100z(x – y) – xyz)/10000  D) (100z(y – x) – xyz)/10000  E) 10000 /(x – y)

Solution: -Q=(10,000z + 100z(x – y) – xyz)/10,000-   z=Original Price   x=MU   y=MD   New price with MU:   z(x/ 100+1)   New price with MD:   z[(x/100+1)(-y/100+1)]   Solvingâ€¦   =z[((x+100)/100)((-y+100)/100)]   =z(x100-xy+10000-100y)/10000   =(zx100-xyz+10000z-100yz)/10000 --> similar to Q=(10,000z + 100z(x – y) – xyz)/10,000
Answer: A
Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them?  Select:	A) 5/8	B) 5/5	C) 5/4	D) 5/6	E) 5/1

Solution: P(at least one graduate)   = 1 - P(no graduates)   = 1 - ⁶C₃/¹⁰C₃ = 1 - (6 * 5 * 4)/(10 * 9 * 8)   = 5/6   Answer:5/6
Answer: D
If a lies in the range (-3,2) then which of the following statements must be true?  Choose the correct choice from the following choices: A) a^4 >a^3 > a^2 > a B) a > a^2 > a^3 > a^4 C) a^4 > a^2 > a^3 >a D) a^2 > a^4 > a^3 >a E) a^2 > a^4 > a > a^3

Solution: consider any number from the given range (-3,+2)..let a=-1/2   then a^2= 1/4   a^3=-1/8   a^4=1/16   so we have a^2>a^4>a^3>a   Ans a^2 > a^4 > a^3 >a
Answer: D
In a group of 2 boys and 8 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be selected?  Choose the correct choice from the following choices:
A) 120  B) 140  C) 160  D) 180  E) 200

Solution: Number of ways to select four children is 10C4 = 210   Number of ways to choose only girls is 8C4 = 70   Number of ways that at least one boy is selected is  210 - 70= 
 210 - 70 = 140
140   The answer is 140.
Answer: B
Two numbers are in the ratio of 5:7. If 25 be subtracted from each, they are in the ratio of 35:59. Find the numbers?
Choose the correct choice from the following.
A) 60,87
B) 60,86
C) 60,89
D) 60,84
E) 60,81

Solution: (5x-25):(7x-25) = 35:59   x = 12 => 60,84   Answer: 60,84
Answer: D
If 6 different numbers are to be selected from integers 0 to 6, how many 6-digit even integers greater than 300,000 can be composed?  Pick:
A) 1080	B) 1180	C) 1280	D) 1480	E) 1680

Solution: Starting with number n >= 3and last number = {0,2,4,6}   case I :   1680ven number   4 or 6 in 100 thousands digit   the units digit can be any one of {0,2,4(if 6 is considered), 6 (if 4 is considered)}   so IF 4 is considered in 100 thousands digit    1*5*4*3*2*3= 
 1*5*4*3*2*3 = 360
360   So if 6 is considered in 100 thousands digit    1*5*4*3*2*3= 
 1*5*4*3*2*3 = 360
360   Hence in Case I we have 720   Case II   3 or 5 in 100 thousands digit   So if 3 is considered in 100 thousands digit    1*5*4*3*2*4= 
 1*5*4*3*2*4 = 480
480   So if 5 is considered in 100 thousands digit    1*5*4*3*2*4= 
 1*5*4*3*2*4 = 480
480   Hence For case II we have   480+480= 
  480+480 = 960
960   Total we have   960+720= 
  960+720 = 1_680
1680 cases:   Final Answer:1680
Answer: E
If a - b = 3 and a(power 2) + b(power 2) = 29, find the value of ab.	Pick one: A) 5 B) 8 C) 4 D) 10 E) 3

Solution: 2ab = (a(power 2) + b(power 2) - (a - b)(power 2)   = 29 - 9= 
29 - 9 = 20
20   ab= 10.   Answer is 10.
Answer: D
A warehouse is labeling computer inventory with 3-digit codes. Each code is to consist of four digits between the numbers 0 and 9. The manager is debating whether to allow any 3-digit codes to have leading zero's before a non-zero number is used. If not allowed, then numbers like0025cannot be used.
The manager wants to measure the magnitude of the number of 3-digit code possibilities that are lost if he disallows the use of leading zero's. How many such codes would be lost?
Choose the correct choice from the following:	A) 981	B) 1000	C) 1011	D) 1101	E) 100

Solution: The number of codes possible if leading zero is allowed = 10*10*10=10^3   The number of codes possible if leading zero is NOT allowed = 9*10*10*10=9*10^3   The difference = 10^3 - 9*10^2 = 10^2(10-9) = 10^2.   Answer: 100   Similar questions to practice:   Hope it helps.
Answer: E
A man has Rs. 512 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?	Select
A) 33
B) 38
C) 37
D) 90
E) 96

Solution: Let number of notes of each denomination be x.   Then x + 5x + 10x = 512   ⇒ 16x = 512   ∴ x = 32.   Hence, total number of notes = 3x = 96   Answer:96
Answer: E
A certain quantity is measured on two different scales, the R scale and the S scale, that are related linearly. Measurements on the R scale of 6 and 24 correspond to the measurements on the S scale of 30 and 60 respectively. What measurement on the R scale corresponds to a measurement of 85 on the S scale?  Choose the correct choice from the following answers:
A) 39  B) 41  C) 43  D) 45  E) 47

Solution: A change of +18 on the R scale is a change of +30 on the S scale.   R = (18/30)*S + K = 3S/5 + K   6 = 3(30)/5 + K   K = -12   R = 3S/5 - 12   R = 3(85)/5 - 12 = 51-12= 
51-12 = 39
39   The answer is 39.
Answer: A
Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price of the sweater was $60, what was the final price of the sweater?  Choose the correct choice from the following choices.
A) $31.5  B) $35.75  C) $15.75  D) $ 45.75  E) $17.75

Solution: The price with 30% off   60 - 30% of 60 = 60 - (30 / 100) *60= 
60 - (30 / 100) *60 = 42
42   The price with another 25% off   42 - 25% of 42= 42 - (25/100)* 42= 
42 - (25/100)* 42 = 63/2 = around 31.5
$31.5   correct answer $31.5
Answer: A
The product of two successive numbers is 1122. Which is the smaller of the two numbers? Choose the correct choice from the following choices.
A) 34  B) 36  C) 33  D) 38  E) 31

Solution: 33   33   From the given alternatives,   33 × 34 = 1122   ∴ Smaller number = 33
Answer: C
How many integers between 1 and 1,800 are divisible by 20,30,40?
Select:
A) 14
B) 15
C) 16
D) 17
E) 18

Solution: LCM of the given numbers=120   Therefore , number of integers = 1800/120= 
1800/120 = 15
15   Option 15 is answer
Answer: B
How many different arrangements of letters are possible if three letters are chosen from the letters A through F and the letters E and A must be among the letters selected?  Select.
A) 24  B) 28  C) 32  D) 36  E) 40

Solution: Besides A and E, there are 4 letters and we can choose one of them.   4C1 = 4   Three letters can be arranged in 3! ways.   The number of arrangements is 4*3! = 24   The answer is 24.
Answer: A
At the end of a business conference the 8 people present all shake hands with each other once. How many handshakes will there be altogether ?  Choose the correct choice:  A) 20  B) 28  C) 55  D) 90  E) 95

Solution: number of handshakes = 8C2= 8*7/2= 
8*7/2 = 28
28   ANSWER:28
Answer: B