MU-NLPC/Calc-aqua_rat huggingface dataset:
Simple interest on a certain sum at a certain annual rate of interest is 1/9 of the sum. If the numbers representing rate percent and time in years be equal, then the rate of interest is:	Choose the correct choice from the following choices
A) 5  B) 8  C) 3 1/3  D) 2 2/3  E) None

Solution: Sol.   Let sum = x. Then, S.I. = x/9   Let rate = R% and time = R years.   ∴ [x * R * R / 100] = x / 9 ↔ R’ = 100/9 ⇔ R = 10/3 = 3 1/3.   Hence, time = 3 1/3 %.   Answer 3 1/3
Answer: C
How many two digit prime numbers are there in which both digits are prime numbers? (For
example, 23 is one of these numbers but 31 is not, since 1 is not a prime number.)	Select.
A) 3 B) 4 C) 5 D) 8 E) 15

Solution: The second digit can only be 3 or 7, so the choice quickly narrows down to 23, 27,   33, 37, 53, 57, 73, and 77. Of these, 27, 33, and 57 are divisible by 3, and 77 by 7, leaving 23,   37, 53, and 73. It is easy to see that none of these is divisible by 2, 3, 5, or 7, and there is no   need to look at greater prime divisors since   root77 < 11.   correct answer 4
Answer: B
A 25 cm wide path is to be made around a circular garden having a diameter of 4 meters. Approximate area of the path is square meters is	Options:
A) 3.34 sq m B) 3.94 sq m C) 7.34 sq m D) 3.35 sq m E) 3.44 sq m

Solution: Explanation:   3.34 sq mrea of the path = 3.34 sq mrea of the outer circle - 3.34 sq mrea of the inner circle = ∏{4/2 + 25/100}2 - ∏[4/2]2   = ∏[2.252 - 22] = ∏(0.25)(4.25) { (a2 - b2 = (a - b)(a + b) }   = (3.14)(1/4)(17/4) = 53.38/16 = 3.34 sq m   3.34 sq mnswer: Option 3.34 sq m
Answer: A
Find the value of a/b + b/a, if a and b are the roots of the quadratic equation x2 + 10x +5 = 0?  Choose the correct choice from the following answers
A) 6
B) 42
C) 24
D) 18
E) 95

Solution: a/b + b/a = (a2 + b2)/ab = (a2 + b2 + a + b)/ab   = [(a + b)2 - 2ab]/ab   a + b = -10/1 = -10   ab = 5/1= 
5/1 = 5
5   Hence a/b + b/a= [(-10)2 - 2(5)]/5 = 90/5= 
90/5 = 18
18.   18)
Answer: D
Find the least number must be subtracted from 531742 so that remaining no.is divisible by 3? Choose the correct choice from the following:
A) 4  B) 5  C) 1  D) 2  E) 3

Solution: On dividing 531742 by 3 we get the remainder 1, so 1 should be subtracted   1
Answer: C
In racing over a given distance d at uniform speed, A can beat B by 10 meters, B can beat C by 6 meters, and A can beat C by 14 meters. What is the distance d in meters?	Choose the correct choice from the following answers
A) 30
B) 40
C) 50
D) 60
E) 70

Solution: When A is at the finish line, B is 10 meters back, and C is 14 meters back.   When B runs another 10 meters to the finish line, C is 6 meters back.   So B gains 2 meters every 10 meters covered.   To gain a final difference of 6 meters, B runs a total of 30 meters.   The answer is 30.
Answer: A
A,B,C can complete a piece of work in 24,6 and 12 days respectively. Working together, they will complete the same work in how many days?  Choose the correct choice from the following answers
A) 13/8	B) 26/11	C) 24/7	D) 12/13	E) 1/2

Solution: (A+B+24/7)'s 1day work = (1/24)+(1/6)+(1/12) = 7/24   A,B,24/7 together will complete the work in 24/7 days   Answer is 24/7
Answer: C
If a/b = 1/3, b/c = 2, c/d = 1/2, d/e = 3 and e/f = 1/10, then what is the value of abc/def ?
Choose the correct choice:
A) 27/4
B) 27/8
C) 3/4
D) 3/20
E) 1/4

Solution: Say a = 2. Then:   a/b = 1/3 --> b = 6;   b/c = 2 --> c = 3;   c/d = 1/2 --> d = 6;   d/e = 3 --> e = 2;   e/f = 1/10 --> f = 20.   abc/def = (2*6*3)/(6*2*20) = 3/20.   Answer: 3/20.
Answer: D
There is a group of persons each of whom can complete a piece of work in 16 days, when they are working individually. On the first day one person works, on the second day another person joins him, on the third day one more person joins them and this process continues till the work is completed. How many days are needed to complete the work?  Select the correct option.
A) 3 1⁄4 days  B) 4 1⁄3 days  C) 5 1⁄6 days  D) 6 1⁄5 days  E) 7 1⁄5 days

Solution: Explanation :   Work completed in 1st day = 1/16   Work completed in 2nd day = (1/16) + (1/16) = 2/16   Work completed in 3rd day = (1/16) + (1/16) + (1/16) = 3/16   …   An easy way to attack such problems is from the choices. You can see the choices are   very close to each other. So just see one by one.   For instance, The first choice given in 3 1⁄4   The work done in 3 days = 1/16 + 2/16 + 3/16 = (1+2+3)/16 = 6/16   The work done in 4 days = (1+2+3+4)/16 = 10/16   The work done in 5 days = (1+2+3+4+5)/16 = 15/16, almost close, isn't it?   The work done in 6 days = (1+2+3+4+5+6)/16 > 1   Hence the answer is less than 6, but greater than 5. Hence the answer is 5 1⁄6 days.   (Just for your reference, work done in 5 days = 15/16.   Pending work in 6th day = 1 – 15/16 = 1/16.   In 6th day, 6 people are working and work done = 6/16.   To complete the work 1/16, time required = (1/16) / (6/16) = 1/6 days.   Hence total time required = 5 + 1/6 = 5 1⁄6 days   Answer : Option 5 1⁄6 days
Answer: C
The temperature of a certain cup of coffee 5 minutes after it was poured was 120 degrees Fahrenheit. If the temperature F of the coffee t minutes after it was poured can be determined by the formula F = 120*2^(-at) + 60, where F is in degrees Fahrenheit and a is a constant. Then the temperature of the coffee 30 minutes after it was poured was how many degrees Fahrenheit? Choose the correct choice from the following answers.
A) 65 B) 61.875 C) 80 D) 85 E) 90

Solution: First, we have to find a.   We know that after t=5 minutes the temperature F=120 degrees.   Hence:   120 = 120*(2^-5a)+60   60 = 120*(2^-5a)   60/120 = 2^-5a   1/2 = 2^-5a   2^-1 = 2^-5a   -1 = -5a   1/5 = a   Now we need to find F after t=30 minutes:   F = 120*(2^-1/5*30)+60   F = 120* (2^-6) +60   F = 120* (1/2^6) +60   F = 120*1/64 +60   F = 1.875+60= 
1.875+60 = 61.875
61.875   Answer 61.875!
Answer: B
What is the area of a triangle with the following vertices L(1, 3), M(5, 1), and N(2, 5) ?
Pick:	A) 3	B) 4	C) 5	D) 6	E) 7

Solution: There is a direct formula to calculate the are of a triangle based on coordinates of its vertices and one could use it to solve this problem.   Though if you make a diagram minimum simple calculations will be needed:   Answer: 5.
Answer: C
A bicycle at Store P costs $200. The regular price of the same bicycle at Store Q is
15% more than it is at Store P. The bicycle is on sale at Store Q for 10% o of the
regular price. What is the sale price of the bicycle at Store Q?  Choose the correct option.
A) $230  B) $201  C) $199  D) $207  E) $210

Solution: At Store Q, the bicycle's regular price is 15% more than the price at Store P, or 15% more than   $200.   Since 15% of 200 is 15   100 200 = 0:15200 = 30, then 15% more than $200 is $200+$30 or $230.   This bicycle is on sale at Store Q for 10% o of the regular price, $230.   Since 10% of 230 is 10   100 230 = 0:10 230 = 23, then 10% o of $230 is $230 􀀀 $23 or $207.   The sale price of the bicycle at Store Q is $207.   correct answer $207
Answer: D
Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is Choose the correct choice from the following choices
A) 5/18	B) 5/12	C) 5/112	D) 5/17	E) 5/11

Solution: Using question number 11 and 12, we get the probability as   1 - (1/36 + 5/9)   = 5/12   Answer:5/12
Answer: B
Diana works 10 hours per day on Monday, Wednesday and Friday, and 15 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $1800 per week. How much does she earn in dollars per hour?
Pick:
A) 20
B) 22
C) 30
D) 24
E) 25

Solution: So, she works 30 hours in 3 days   So, she works 30 hours in 2 days   So in a week she works 60 hours ( 30 + 30 ) and earns $1800   So, Hourly wage is  1800/60= 
 1800/60 = 30
> 30   Hence answer will be (30) 30
Answer: C
Two pipes A and B can separately fill a cistern in 80 minutes and 160 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 40 minutes. In how much time, the third pipe alone can empty the cistern?	Pick one:
A) 90 min B) 160 min C) 110 min D) 120 min E) 130 min

Solution: 1/40-(1/80+1/160)=-1/160   third pipe can empty in 160 minutes   ANSWER:160 min
Answer: B
Two numbers N and 10 have LCM = 36 and GCF = 5. Find N.  Answers.
A) 35
B) 56
C) 76
D) 18
E) 24

Solution: The product of two integers is equal to the product of their LCM and GCF. Hence.   10* N = 36 * 5   N = 36*5 / 10= 
36*5 / 10 = 18
18 correct answer 18
Answer: D
Meera purchased two three items from a shop. Total price for three items is Rs.2000/- She have given Rs. 3000/- What is the balance amount meera got?
Select the correct option:
A) 650  B) 1000  C) 1500  D) 800  E) 750

Solution: Total cost of Items : 2000/-   amount Paid : 3000/-   1000alance receivable :   3000- 2000= 
  3000- 2000 = 1_000
1000/-   Answer is 1000
Answer: B
If logn48 = a and logn108 = b. What is the value of logn1296 in terms of a and b?	Choices
A) 2(2a + b)/5  B) (a + 3b)/5  C) 4(2a + b)/5  D) 2(a + 3b)/5  E) None of these

Solution: Given logn48 = 4logn2 + logn3 = a and   logn108 = 2.logn2 + 3logn3 = b   Let logn 2 = X and logn3 = Y.   => 4X + Y = a   2X +3Y = b.   2 x (ii) - (i) gives   6Y - Y = 2b - a   Y = (2b - a)/5   Similarly, X = (3a - b)/10.   logn1296 = 4(logn2 + logn3).   = 4[(2b - a)/5 + (3a - b)/10].   = 4[(a + 3b)/10] = 2(a + 3b)/5.   ANSWER:2(a + 3b)/5
Answer: D
A courtyard is 28 meter long and 13 meter board is to be paved with bricks of dimensions 22 cm by 12 cm. The total number of bricks required is :  Select the correct option
A) 16000 B) 14567 C) 13787 D) 13456 E) None of these

Solution: Explanation:   Number of bricks =13787ourtyard area /1 brick area   =(2800Ã—1300 /22Ã—12)=13787   Option 13787
Answer: C
There are two numbers. If 80% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?  Answers.
A) A)3/7 B) B)5/16 C) C)6 D) D)6/7 E) E)7

Solution: Let the two numbers be x and y.   80/100 * x + y = 5/4y   => 4/5 x = 1/4 y => x/y = 5/16   5/16)
Answer: B
The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is?  Choose the correct choice from the following answers
A) 759 B) 750 C) 278 D) 267 E) 187

Solution: Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.   Let the length of the train and that of the platform be x meters.   Then, 2x/60 = 25 è x = 25 * 60 / 2= 
25 * 60 / 2 = 750
750   Answer: 750
Answer: B
Deepak is 4 times as old as his son. four years hence the sum of their ages will be 43 years. How old is deepak's son now ?	Choose the correct answer:	A) 5 years	B) 7 years	C) 8 years	D) 9 years	E) 10 years

Solution: Let the son's present age be x years   Then, (x + 4 ) + (4x + 4) = 43   5x = 35   x = 7 years   Answer : 7 years
Answer: B
How many numbers between 0 and 1570 have a prime tens digit and a prime units digit?
Choose one.
A) 268	B) 272	C) 202	D) 112	E) 252

Solution: From 1-9 there are 4 prime numbers {2, 3, 5, 7}. The 10s and 1s of the number must be made with these numbers. The total number of combinations is  4*4= 
 4*4 = 16
16. Thus every set of 100 consecutive positive integers has 16 such numbers.   From 0 to 1500, there  16*15= 
 16*15 = 240
240 such numbers.   From 1501 to 1570, the 10s units can only use 3 numbers {2, 3, 5}. 3*4=12.   The total number is then  240+12= 
 240+12 = 252
252   The answer is 252.
Answer: E
The remainder when dividing the expression (X + Y) by 5 is 4. The remainder of X divided by 10 is 2. What is the remainder D of Y divided by 5?	Choose the most appropriate option:	A) D=1.	B) D=2.	C) D=3.	D) 4.	E) 5.

Solution: X divided by 10 gives reminder of 2. X can be 2/12/22....   X+Y divided by 5 is 4 . X+Y can be 4/ 9/ 19....   If X+Y= 4 and X is 2 then Y = 2 and Y/5 will give a reminder of 2   Similarly, if X+Y= 9 and X = 2, then y/5 will give a reminder of 2   Hence the answer must be 2 (B)   Also....   x+y=5m+4 and x=10K+2   hence 10k+2+y=5m+4 or y=5(m-2k)+2, m-2k being a constant remainder is 2 hence answer is D=2.
Answer: B
A 70 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?  Select:
A) 10	B) 20	C) 30	D) 40	E) 50

Solution: 1: 2/5 = 5: 2   2/7 * 70= 
2/7 * 70 = 20
20   ANSWER 20
Answer: B
If 50 apprentices can finish a job in 4 hours, and 30 journeymen can finish the same job in 5,5 hours, how much of the job should be completed by 10 apprentices and 15 journeymen in one hour?
Choose the correct option:
A) 1/9 B) 29/180 C) 26/143 D) 1/5 E) 31/220

Solution: 50 apprentices can finish the job in 4 hours,thus:   10 apprentices can finish the job in   4*5= 
  4*5 = 20
20 hours;   In 1 hour 10 apprentices can finish 1/20 of the job.   30 journeymen can finish the same job in 4,5 hours,thus:   15 journeymen can finish the job in  5.5*2= 
 5.5*2 = 11
11 hours;   In 1 hour 15 journeymen can finish 1/11 of the job.   Therefore, in 1 hour 10 apprentices and 15 journeymen can finish 1/20+1/11=31/220 of the job.   Answer: 31/220
Answer: E
If the cost price of 30 pens is equal to the selling price of 25 pens, the gain percent is:  Answers:
A) 9%	B) 20%	C) 50%	D) 80%	E) 34%

Solution: Solution :   Let cost price of the price be Rs.1   25 pens C.P. = 25   30 pens S.P. = 30   Gain = 5/25*100= 
5/25*100 = 20
20 %   Answer :20%
Answer: B
In how many ways can three members be selected from a group of five members?  Choose the correct choice from the following answers.
A) 5C6	B) 5C3	C) 5C4	D) 10C3	E) 10C1

Solution: three members can be selected from five members in   5C3   = 5C3 ways.   Answer: 5C3
Answer: B
A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was : Choose the correct choice from the following choices
A) 14
B) 19
C) 33
D) 38
E) 56

Solution: Explanation:   Let the son's present age be x years .Then, (38 - x) = x x= 19.   Son's age 5 years back = (19 - 5)= 
(19 - 5) = 14
14 years. 14nswer: 14
Answer: A
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is? Choose the correct choice from the following options
A) 27	B) 50	C) 22	D) 26	E) 28

Solution: Speed of the train relative to man   = 125/10   = 25/2 m/sec.   = 25/2 * 18/5= 
25/2 * 18/5 = 45
45 km/hr   Let the speed of the train be x km/hr. Then, relative speed= (x - 5) km/hr.   x - 5 = 45 => x   = 50 km/hr.   Answer:50
Answer: B
If each of 4 subsidiaries of Corporation R has been granted a line of credit of $119,000 and each of the other 3 subsidiaries of Corporation R has been granted a line of credit of $112,000, what is the average (arithmetic mean) line of credit granted to a subsidiary of Corporation R?	Choose the correct option.
A) $1,568,000  B) $448,000  C) $406,000  D) $313,600  E) $116,000

Solution: My take is E.   (119000*4 + 112000*3)/7= 
(119000*4 + 112000*3)/7 = 116_000
116000
Answer: E
The average weight of a class of 20 boys was calculated to be 58.4 kgs and it was later found that one weight was misread as 56 kg instead of 65 kg. What is the correct weight?	Pick
A) 59kg
B) 58.85kg
C) 59.75kg
D) 60kg
E) None of these

Solution: Explanation:   Actual total weight is (20X 58.4 – 56 + 65) = 1177 Kgs   Actual average weight is   1177/20= 
  1177/20 = 1_177/20 = around 58.85
58.85kgs   Answer 58.85kg
Answer: B
Two musicians, Maria and Perry, work at independent constant rates to tune a warehouse full of instruments. If both musicians start at the same time and work at their normal rates, they will complete the job in 120 minutes. However, if Perry were to work at twice Maria’s rate, they would take only 20 minutes. How long would it take Perry, working alone at his normal rate, to tune the warehouse full of instruments?	Choose the correct answer:
A) 1 hr 20 min	B) 1 hr 45 min	C) 2 hr	D) 2 hr 20 min	E) 1 hr

Solution: Sol:   Lets Perry Rate be P and Rate of Maria be M   (rate)*(time)= Work or rate = work/time   first equation=> P+M = 1/120   converting it to hrs P+M= 1/(60/120)= 
1/(60/120) = 2
> 2   second equation=> M+2M =>1/20   converting it to hrs 3M=1/(20/60) =>1/(1/3)= 
1/(1/3) = 3
>3   therefore M= 1 and P=1   Rate of Perry = 1   time= work/rate (work = 1 job)   Time= 1 hrs   Answer : 1 hr
Answer: E
Darius and Daniel each had an equal amount of money to spend. After Darius spent 360.00 and Daniel spent 150.00. Daniel had 8 times as much money as what Darius had left. How much money did each boy have to begin with
Choose the correct choice:
A) $390
B) $380
C) $370
D) $360
E) $350

Solution: Since Darius and Daniel each had an equal amount of money to spend (and because this is the amount we are wanting to find) we can let "d" denote the variable for this amount. Now it is given to us that Darius spent $360 and Daniel spent $150. So, we can let "d - 360" denote the amount of money Darius has left, and we can let "d - 150" denote the amount of money Daniel has left. Finally, we are given that the amount of money Daniel has left (d - 150) is equal to 8 times the amount of money Darius had left (d - 360). Therefore,   d - 150 = 8(d - 360)   d - 150 = 8d - 2880   -150 = 7d - 2880   7d = 2730   d = 390   So, the amount of money each boy had to begin with is $390.00.   $390nswer $390
Answer: A
The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 10092 sq. m, the cost of fencing the field @ 25 paise per metre is  Options:  A) Rs. 55.50  B) Rs. 67.50  C) Rs. 86.50  D) Rs. 101.50  E) None of these

Solution: Solution   Let length = (3x) metres and breadth = (4x) metres.   Then, 3x × 4x = 10092⇔ 12x2 = 10092 ⇔ x2 = 841 ⇔ x = 29.   So, length = 87 m and breadth = 116 m.   Perimeter = [2(87 + 116)] m = 406 m.   ∴ Cost of fencing = Rs. (0.25 × 406) = Rs. 101.50. Answer Rs. 101.50
Answer: D
If b is a positive integer and b^2 is divisible by 12, then the largest positive integer that must divide b ^3 is	Choose the correct choice from the following answers
A) 2^3  B) 2^6  C) 3^3  D) 6^3  E) 12^2

Solution: Since b is an integer so b cannot have a 2 and sqrt 3 (because squaring this will give us a 2^2 and 3 (making the product as 12, and making b^2 as a multiple of 12))   b^2 is divisible by 12 (12 = 2*2*3), So, b should have at least one 2 and one 3 so that b^2 has a 2^2 and two 3   So, b will have a 2 and a 3. Or b will be a multiple of 6   So, largest possible integer than should divide b^3 is 6^3   So, Answer will be 6^3
Answer: D
A clock store sold a certain clock to a collector for 45 percent more than the store had originally paid for the clock. When the collector tried to resell the clock to the store, the store bought it back at 25 percent of what the collector had paid. The shop then sold the clock again at a profit of 55 percent on its buy-back price. If the difference between the clock's original cost to the shop and the clock's buy-back price was $180, for how much did the shop sell the clock the second time?
Answers:  A) $149.55  B) $134.56  C) $175.43  D) $158.65  E) $255.45

Solution: Now, in the question above, lets say the original cost of the clock to store was C$ and then it sold the same to the collector at 45% profit.   This means the clocks' selling price was C (1.45) and this becomes cost price for the collector.   Now, when the collector tries to sell the same clock to the store, the store buys it for 25% the price at which the collector bought it.   Thus, you get = 1.45*0.25*C = 0.3625 C   Furthermore, the store sells the clock for the second time for 55% profit and thus the selling price of the clock becomes = cost price of the clock for the store at buy-back * 1.55 = 1.55 * 0.3625 C   Finally given that C - 0.3625 C = 180 ----> C = 282.35$   Thus, the cost of the clock the second time around = 1.55*0.3625 C = 1.55 * 0.3625 * 282.35 = 158.65$. Hence $158.65 is the correct answer.
Answer: D
Tickets to a certain concert sell for $20 each. The first 10 people to show up at the ticket booth received a 40% discount, and the next 20 received a 15% discount. If 50 people bought tickets to the concert, what was the total revenue from ticket sales?  Options:
A) $600
B) $740
C) $860
D) $980
E) $1,140

Solution: Price of 1 ticket = 20$   Revenue generated from sales of first 10 tickets = 10 * (60/100 * 20 )   = 10 * 12= 
10 * 12 = 120
120   Revenue generated from sales of next 20 tickets= 20 *(85/100 * 20 )   =20*17= 
20*17 = 340
340   Revenue generated from sales of last 20 tickets= 20 * 20= 
20 * 20 = 400
400   Revenue generated from sales of 50 tickets= 120 + 340 + 400= 
120 + 340 + 400 = 860
860 $   Answer $860
Answer: C
If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?	Choose the correct choice from the following answers
A) 40 kms	B) 70 kms	C) 80 kms	D) 50 kms	E) 10 kms

Solution: Explanation:   Let the actual distance travelled be x km.   Then x/8=(x+20)/12   => 12x = 8x + 160   => 4x = 160   => x = 40 km.   40 kmsnswer: 40 kms
Answer: A
A certain bacteria colony doubles in size every day for 21 days, a which point it reaches the limit of its habitat and can no longer grow. If two bacteria colonies start growing simultaneously, how many days will it take them to reach the habitat’s limit?	Choose the correct option:
A) 6.33
B) 7.5
C) 10
D) 20
E) 19

Solution: Case 1: Consider the bacteria num to be B. As it doubles every day, number of bacteria at the end of each day would be   Day 1 – B   Day 2 – 2B   Day 3 – 4B   Day 4 – 8B   .   .   .   Day 21 – 2^19 B   It can be implied that the capacity of the habitat is 2^19 B.   Case 2: There are 2 bacteria which keep doubling every day. So, the count would be   Day 1 – 2B   Day 2 – 4B   Day 3 – 8B   .   .   .   Day 18 – 2^18 B   Day 19 – 2^19 B --> this is the point where the habitat is filled to its capacity.   Hence, 20 is the answer   20
Answer: D
If a person walks at 20 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance traveled by him is:  Choose the correct choice from the following answers.
A) 20 km  B) 56 km  C) 60 km  D) 70 km  E) 80 km

Solution: Let the actual distance travelled be x km.   x/10 = (x+20)/14   20x = 10x + 200   10x = 200   x = 20 km.   answer :20 km
Answer: A
How much space, in cubic units, is left vacant when maximum number of 2x2x2 cubes are fitted in a rectangular box measuring 8x10x9 ?  Answers
A) 60	B) 65	C) 70	D) 75	E) 80

Solution: No of cubes that can be accommodated in box = (8*10*9)/(2*2*2)   8*10 in numerator can be perfectly divided by 2*2 in denominator.   side with length 9 can't be perfectly divided by 2 and hence is the limiting factor. Closet multiple of 2 less that 9 is 8. so vacant area in cube =   =10*8 (9-8)   =10*8*1= 
10*8*1 = 80
80   Ans - 80
Answer: E
Find the sum of prime numbers lying between 60 and 75.  Choose the correct choice from the following answers: A) 199 B) 201 C) 211 D) 272 E) NOne

Solution: Sol.   Required sum = ( 61 + 67 + 71 + 73)= 
( 61 + 67 + 71 + 73) = 272
272.   Answer 272
Answer: D
A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?	Pick:
A) 28	B) 99	C) 27	D) 26	E) 11

Solution: Explanation:   1/A + 1/B + 1/C = 1/8 (Given)   Also given that A = 2B and B = 2C   => 1/2B + 1/B + 2/B = 1/8   => (1 + 2 + 4)/2B = 1/8   => 2B/7 = 8   => B = 28 hours.   28nswer:28
Answer: A
On dividing 144 by a number, the quotient is 13 and the remainder is 1. Find the divisor.
Choose the correct option.
A) A)11
B) B)14
C) C)16
D) D)18
E) E)22

Solution: d = (D-R)/Q   = (144 - 1)/13   = 143/13= 
143/13 = 11
11   11)
Answer: A
Find large number from given question. The difference of 2 numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Choose the correct answer:
A) 1345
B) 1450
C) 1440
D) 1546
E) 1635

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1365 = 6x + 15   5x = 1350   x = 270   Large number = 270+1365= 
270+1365 = 1_635
1635   1635
Answer: E