MU-NLPC/Calc-aqua_rat huggingface dataset:
A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is Select:	A) 400 m	B) 450 m	C) 560 m	D) 600 m	E) 680 m

Solution: Length of the Ist train=2x m and the length of the other train be x m(1/2)   The relative speed of the train (48+42)= 
 (48+42) = 90
90kmph or 25m/s   Time taken to cross one another=12s   Hence, 12=2x+x/25   Solving, x=100m and 200m   Now to determine the length of the platform   45=100+length of the platform/speed of the Ist train   45=100+L/240/18( 48kmph=240/118m/s)   Solving, we get L=600M   ANSWER:600 m
Answer: D
On Sunday Mario handled 75 sales. Deshawn handled 20% more sales than Mario, Callie handled 1/5 of the sales that Deshawn handled, and Jane handled 5 less sales than Callie. How much transactions did Jane handle?	Select the correct option
A) 90
B) 13
C) 65
D) 70
E) 42

Solution: B   15   Mario handled 75 transactions   Deshawn handled 20% more transactions than Mario   Anthony = 75 + 75 × 20%   = 75+ 75 × 0.20   = 75 + 15= 
75 + 15 = 90
90   Callie handled 1/5 of the transactions than Deshawn handled   Callie= 1/5 × 90   = 18   Jane handled 5 less than Callie.   Jane = 18 - 5= 
18 - 5 = 13
13   Jane handled 13 transactions.   The correct answer is 13.
Answer: B
The H.C.F. of two numbers is 11 and their L.C.M. is 693. If one of the number is 77, find the other? Choose the correct choice
A) 88 B) 99 C) 76 D) 55 E) 66

Solution: Other number = 11*693/77= 
11*693/77 = 99
99   Answer is 99
Answer: B
A clock loses a minute every three hours for 4 days and gains 2% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?	Choose the correct choice from the following choices.
A) 11:54:40 AM B) 01:20:13 PM C) 12:16:40 PM D) 11:54:24 AM E) 12:06:36 PM

Solution: Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.   Clock gains: 1% in the subsequent 6 days = 2% in 6*24*60 minutes = 172.8 minute in 6 days;   Net gain in 10 days = 172.8 - 32= 
172.8 - 32 = 140.8
140.8 minutes.   11AM + 140.8 minutes= 01:20 and 13 seconds.   Answer: 01:20:13 PM.
Answer: B
John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 190% of John's weight. Which of these 5 people weighs the least? Choose the correct choice from the following answers:
A) John
B) Susan
C) Sam
D) Mark
E) Lynn

Solution: Let J – John’s weight   S – Susan’s weight   M – Mark’s weight   A – Sam’s weight   L – Lynn’s weight   J = 2S   S = 0.6A   M = 0.5L   L = 1.9J   Let us convert these weights to one variable   S = J/2   A = S/0.6 = J/1.2 = 5J/6   L = 1.9J   M = 0.5 * 1.9= 
0.5 * 1.9 = 0.95
0.95J   So Susan has the least weight.   Answer - Susan
Answer: B
If n is an odd integer less than 10, which of the following must also be an odd integer?  Choices:
A) 2n + n^2 + 2  B) n^3 + 2n  C) 3n + 2^n  D) n^3 + 1  E) 3n

Solution: Answer: n^3 + 1   A: 2n = even   B: 3n = even   C: 3n + n^2 + 2 = even   n^3 + 1: n^2 + 1 = odd   E: 2n + n^2 = even   Answer: n^3 + 1
Answer: D
P and Q need 8 days to complete a work. Q and R need 12 days to complete the same work. But P, Q and R together can finish it in 6 days. How many days will be needed if P and R together do it?
Choose one
A) 3
B) 8
C) 12
D) 4
E) 15

Solution: Let work done by P in 1 day = p   work done by Q in 1 day =q   Work done by R in 1 day = r   p + q = 1/8 ---(1)   q + r= 1/12	---(2)   p+ q+ r = 1/6	---(3)   (3) – (2) => p = 1/6 - 1/12 = 1/12   (3) – (1) => r = 1/6 – 1/8 = 1/24   p + r = 1/12 + 1/24 = 3/24 = 1/8   => P and R will finish the work in 8 days   Option 8
Answer: B
A Student got 78 marks in avg of 4 subjects.the avg odf 5 subjects is 80.what is the amrk he got in 5th subject.
Pick.
A) 87  B) 88  C) 89  D) 90  E) 91

Solution: avg mrk he got in 5th subject=80*5-78*4   avg mrk he got in 5th subject=400-312= 
400-312 = 88
88   ANSWER:88
Answer: B
In her backyard, Florry grows only yellow roses and white roses. Some of the rose bushes have flowers of both colors, and some have flowers of one color only. The number of rose bushes that have only yellow roses is 50% greater than the number of rose bushes that have only white roses. If there are yellow roses on 80% of Florry's rose bushes, then what percent F of her bushes have only yellow roses? Choose one
A) 20  B) 30  C) 50  D) 70  E) 80

Solution: let, the number of bushes with only yellow flowers be x   so, number of bushes with only yellow flowers will be 1.5x   if total number of bushes of flowers= T   then total number of bushes with yellow flowers= 0.8T   we can say that total number of bushes with yellow flowers+ bushes with only white flowers= total number of bushes with flowers   so, F=0.8T+x=T   x=0.2T   so, 1.5x=0.3T   30% flowers are yellow flowers   OA 30
Answer: B
A small pool filled only with water will require an additional 300 gallons of water in order to be filled to 80% of its capacity. If pumping in these additional 300 gallons of water will increase the amount of water in the pool by 40%, what is the total capacity of the pool in gallons?	Select the correct option
A) 1000
B) 1312.5
C) 1400
D) 1600
E) 1625

Solution: 300 gallons of water increases capacity by 40% that means   40% is 300 gallons, so 100% would be = 300*100/40= 
300*100/40 = 750
750 gallons   Now 750 +300 gallons is 80% capacity of tank.   so 100% capacity would be= 1050 *100/80= 
1050 *100/80 = 2_625/2 = around 1_312.5
1312.5   1312.5 is the answer
Answer: B
A circular garden is surrounded by a fence of negligible width along the boundary. If the length of the fence is 1/3 of th area of the garden. What is the radius of the circular garden? Pick
A) 6 B) 2 C) 4 D) 8 E) 16

Solution: as per the question-- width is negligible   now,   let L be the length of the fence =2pir   L=1/3(pir^2)   pir^2=6pir   r=6   6nswer : 6
Answer: A
If 60! is written out as an integer, with how many consecutive 0’s will that integer end?
Pick.
A) 6  B) 12  C) 14  D) 42  E) 56

Solution: Soln:-   60/5+60/52=12+2= 
12+2 = 14
14   Answer: 14
Answer: C
In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ?	Choose the correct option:  A) 160  B) 175  C) 180  D) 195  E) 200

Solution: Explanation:   Suppose the man works overtime for x hours.   Now, working hours in 4 weeks = (5 x 8 x 4) = 160.   160 x 2.40 + x x 3.20 = 432   3.20x = 432 - 384= 
432 - 384 = 48
48   x= 15.   Hence, total hours of work = (160 + 15)= 
(160 + 15) = 175
175.   ANSWER IS 175
Answer: B
In an arithmetic progression the difference between the any two consecutive terms is a constant. What is the arithmetic mean of all of the terms from the first to the 31st in an arithmetic progression if the sum of the 14th and 18th terms of the sequence is 122?	Choose the correct choice from the following choices.
A) 46  B) 51  C) 56  D) 61  E) 66

Solution: Let x be the difference between any two consecutive terms.   The mean of a sequence like this is the middle term, thus the 16th term in the sequence.   Then the mean of the 15th and 17th term is also equal to the overall mean, because the 15th term is (16th term - x) and the 17th term is (16th term + x).   Similarly the mean of the 14th and 18th term is also equal to the mean.   etc...   Thus the mean is   122/2= 
  122/2 = 61
61   The answer is 61.
Answer: D
Yogesh started a business investing Rs. 45000. After 3 months, Pranab joined him with a capital of Rs. 60000. After another 6 months, Atul joined them with a capital of Rs. 90000. At the end of the year, they made a profit of Rs. 20000. What would be Atuls share in it?
Pick.
A) Rs 7000  B) Rs 6000  C) Rs 5000  D) Rs 4000  E) None of these

Solution: Explanation:   Just take care of the months of investment, rest all will be simple.   Yogesh:Pranab:Atul = 45000*12:60000*9:90000*3   = 2:2:1   Atul's share = Rs. 20000 * (1/5) = Rs. 4000   Option Rs 4000
Answer: D
In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 1999 were what percent of the profits in 1998? Answers
A) 80%  B) 105%  C) 120%  D) 124.2%  E) 138%

Solution: Let's TEST:   1998   Revenues= $100   Profits = $10   Next we're told that, in 1999, revenue FELL by 20%, but profits were 15% of revenues. Using the numbers from 1998 (above), we end up with...   1999   Revenues = $80   Profits = $12   We're asked to compare the profits in 1999 to the profits in 1998 (as a percentage):   $12/$10 = 1.2   12/ 10= 
  12/ 10 = 6/5 = around 1.2
1.2= 120%   ANSWER:120%
Answer: C
If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?
Choose the most appropriate option
A) 65mtr.  B) 52mtr  C) 70mtr.  D) 78mtr.  E) 17mtr.

Solution: 20 men is 6 days can build 112 metres   25 men in 3 days can build = 112*(25/20)x(3/6)   = 70 meters   Answer: 70mtr..
Answer: C
A cyclist rides a bicycle 9 km at an average speed of 11 km/hr and again travels 11 km at an average speed of 9 km/hr. What is the average speed for the entire trip?
Choose the most appropriate option: A) 9.3 B) 9.6 C) 9.8 D) 10.1 E) 10.3

Solution: distance = 20 km   time = 9/11 + 11/9 = (81 + 121) / 99 = 202 / 99 hours   average speed = (20 * 99) / 202 = 9.8 km/h   The answer is 9.8.
Answer: C
If M and N are positive integers that have remainders of 2 and 3, respectively, when divided by 6, which of the following could NOT be a possible value of M+N?
Select the correct option
A) 89  B) 53  C) 34  D) 29  E) 11

Solution: M=6p+2   N=6q+3   We need M+N=6p+3+6q+3=6(p+q)+5   Pick numbers for pq   Since it is an addition of pq and the answer to this expression should be an integer (because all the numbers being added are integers),   we just need to choose values so that we get integer multiples of 6 so   p+q=0 ; M+n = 5   p+q=1 ; M+N = 11   P+q=2 ; M+N = 17   and so on, so basically you get something like - 5,11,17,23,29,35,41,..... all the other options were turning up.   Then I directly tried p+q=5 because it was closer to 34 , i got 35,   So Answer 34.
Answer: C
If the sum of two positive integers is 18 and the difference of their squares is 36, what is the product of the two integers?	Pick:
A) 108
B) 80
C) 128
D) 135
E) 143

Solution: Let the 2 positive numbers x and y   x+ y = 18 -- 1   x^2 - y^2 = 36   => (x+y)(x-y)=36 -- 2   Using equation 1 in 2 , we get   => x-y = 2 -- 3   Solving equation 1 and 3 , we get   x= 10   y= 8   Product = 10*8= 
10*8 = 80
80   Answer 80
Answer: B
A, B and C, each working alone can complete a job in 6, 8 and 12 days respectively. If all three of them work together to complete a job and earn $ 2340, what will be C's share of the earnings? Choose the correct choice from the following choices:
A) $1100
B) $520
C) $1080
D) $1170
E) $630

Solution: Explanatory Answer   A, B and C will share the amount of $2340 in the ratio of the amounts of work done by them.   As A takes 6 days to complete the job, if A works alone, A will be able to complete 1/6 th of the work in a day.   Similarly, B will complete 1/8th and C will complete 1/12th of the work.   So, the ratio of the work done by A : B : C when they work together will be equal to 1/6 : 1/8 : 1/12   Multiplying the numerator of all 3 fractions by 24, the LCM of 6, 8 and 12 will not change the relative values of the three values.   We get 24/6 : 24/8 : 24/12 = 4 : 3 : 2.   i.e., the ratio in which A : B : C will share $2340 will be 4 : 3 : 2.   Hence, C's share will be  2*2340/9= 
 2*2340/9 = 520
520.   correct choice is ($520)
Answer: B
A man can row three-quarters of a kilometre against the stream in 11 1/4 minutes. The speed (in km/hr) of the man in still water is:  Choose the most appropriate option
A) 4 1/4 km/hr	B) 5 km/hr	C) 6 km/hr	D) 7 km/hr	E) None

Solution: Sol.   Rate upstream = [750 / 675] m/sec = 10/9 m/sec.   Rate downstream = [750 / 450] m/sec = 5/3 m/sec.   ∴ Rate in still water = 1/2 [10/9 + 5/3] m/sec = 25/18 m/sec = [25/18 * 18/5] km/hr   = 5 km/hr   Answer 5 km/hr
Answer: B
we have 6 weights one of 2 kg one of 3 kg one of 5 kg one of 1 kg one of 0.5 kg one of 0.25 kg by using only two weight how many wight u can weight
Choose the correct option:
A) 11	B) 12	C) 13	D) 14	E) 15

Solution: select 2 weight out of 6, 6C2=15   ANSW15R:15
Answer: E
Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 14 such machines produce in 4 minutes ? Choose the correct choice from the following answers:
A) 2520  B) 1800  C) 2700  D) 10800  E) None of these

Solution: Solution   Let the required number of bottles be x.   More machines,More bottles (Direct Proportion)   More minutes,More bottles (Direct Proportion)   âˆ´ 6 Ã— 1 Ã— x = 14 Ã— 4 Ã— 270 â‡” x = 14x4x270/6= 2520 . 2520nswer 2520
Answer: A
If a 2-digit integer is selected at random from the integers 60 through 99, inclusive, what is the probability that the first digit is equal to two less than the second digit? Choose one
A) 4/40
B) 4/90
C) 60/100
D) 1/99
E) 4/60

Solution: The tens digit may be 6, 7, 8, or 9   The units digit may be 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9   The tens digit has to be 2 less than the value of the units digit so we will add 2 to possible tens digits   6+2= 
6+2 = 8
8   7+2= 
7+2 = 9
9   8+2= 
8+2 = 10
10   9+2= 
9+2 = 11
11   Of these values, 8 and 9 are possible units digits which means that 6 and 7 are possible tens digits   Possible numbers are 68, 69, 78, and 79   We have 4 possible numbers   Total numbers between 60 and 99= (99-60)+1= 
(99-60)+1 = 40
40   Probability= 4/40   4/40nswer 4/40
Answer: A
In an examination, a student scores 6 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 280 marks, the no of questions he attempts correctly is : Choose the correct choice from the following choices:  A) A)20  B) B)38  C) C)90  D) D)88  E) E)37

Solution: Let the number of correct answers be X.   Number of incorrect answers = (60 – X).   6x – (60 – x) = 280   => 7x = 340   => x = 20   20nswer:20
Answer: A
If 11 ml of water is mixed with 1 ml of a chemical, a magical perfume is manufactured. The manufacturer initially wanted to have 500 ml of one box of the magical perfume. How much extra ml is to be added with the proposed box size to comply with the formula? Select:
A) 3
B) 4
C) 5
D) 7
E) 8

Solution: The magical perfume should have 11/12 of water and 1/12 of chemical. With 500 ml, there will be a need to add 4 ml more such that the final solution is divisible by 12; that is , 42x12=504. Answer 4.
Answer: B
A book seller marks his books 50% more than the real price and allows 30% discount. His profit is: Choose the correct choice:
A) 3%
B) 4%
C) 5%
D) 6%
E) None of these

Solution: Let the CP = 100 Rs.   Mark Price = 150   Discount = 30%   Selling price 70/100 Ã— 150   Hence profit = 5%   Answer: 5%.
Answer: C
There are 20 balls of green color,20 balls of red color,20 balls of blue color,20 of balck,20 of yellow. how many u have to pick to guarantee 2pairs of same color?
Choose the correct choice.
A) 2 B) 3 C) 4 D) 5 E) 6

Solution: Here we have five different colours.(Red, Green, Black, Blue and Yellow)   Consider If we pick 1st ball as red. After that, there may be a chance to pick FOUR different colours of ball.   But, if we pick the 6th ball, it must be match any one of the colour ball.   So for guarntee the same pair of colur balls, we pick 6 balls.   ANSW6R:6
Answer: E
In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?	Select the correct option:
A) 8200
B) 7500
C) 7000
D) 8000
E) None of these

Solution: Explanation :   State A and State B had an equal number of candidates appeared.   In state A, 6% candidates got selected from the total appeared candidates   In state B, 7% candidates got selected from the total appeared candidates   But in State B, 80 more candidates got selected than State A   From these, it is clear that 1% of the total appeared candidates in State B = 80   => total appeared candidates in State B = 80 x 100 = 8000   => total appeared candidates in State A = total appeared candidates in State B = 8000   Answer : Option 8000
Answer: D
John distributes his pencil among his 4friends Rose, Mary, Ranjan, and Rohit in the ratio 1/2 : 1/3 : 1/4 : 1/5 . What is the minimum no. of pencils that the person should have?	Answers.
A) 65 B) 68 C) 70 D) 77 E) 80

Solution: Rakesh : Rahul : Ranjan : Rohit = 1 / 2 : 1 / 3 : 1 / 4 : 1 / 5   Step 1: At First we need to do is LCM of 2,3,4 and 5 is 60.   Step 2: Then pencil are distributed in ratio among friends,   Rakesh = ( 1 / 2 x 60 ) = 30.   Rahul = ( 1 / 3 x 60 ) = 20.   Ranjan = ( 1 / 4 x 60 ) = 15.   Rohit = ( 1 / 5 x 60 ) = 12.   Step 3: Total number of pencils are ( 30 x + 20 x + 15 x + 12 x) = 77 x.   For minimum number of pencils x = 1 .   The person should have atleast 77 pencils.   77)
Answer: D
Jim’s only source of income comes from his job as a question writer. In this capacity, Jim earns a flat salary of $200 per week plus a fee of $9 for every question that he writes. Every year, Jim takes exactly two weeks of unpaid vacation to visit his uncle, a monk in Tibet, and get inspired for the next year. If a regular year consists of 52 weeks and the number of questions that Jim wrote in each of the past 5 years was an odd number greater than 20, which of the following could be Jim’s median annual income over the past 5 years?	Choose the correct answer:  A) $22,474  B) $25,673  C) $27,318  D) $28,441  E) $31,227

Solution: Okay u just need less than one min to answer this question. any odd number greater than 20 means that that last digit must be 1,3,5,7, or 9. 9$ per week for every question. So (odd)(odd) will give odd digit. A and C out. (50 weeks) (200) = 10,000. subtract this amount from option B, $28,441 and E and u will find that only option $28,441 is divisible by 9 (once 10,000 is subtracted from 28441)   so its the right choice.$28,441
Answer: D
Roberto has three children: two girls and a boy. All were born on the same date in different years. The sum of the ages of the two girls today is smaller than the age of the boy today, but a year from now the sum of the ages of the girls will equal the age of the boy. one years from today, the difference between the age of the boy and the combined ages of the girls will be	Choose the correct choice from the following answers.
A) 0
B) 2
C) 3
D) –2
E) –1

Solution: Approach I (Plugin's)   Girl I ............... Girl II ................ Boy   1 ....................... 1 ........................ 3 (Assume the current ages)   1 + 1 < 3 .......... (Satisfies the given condition)   1 Year later there ages are   2 ....................... 2 ......................... 4   2 + 2= 
2 + 2 = 4
4 ............ (Satisfies the given condition)   Difference= 4 - (2+2)= 
4 - (2+2) = 0
0   0nswer= 0
Answer: A
Suppose you have access to a large vat of distilled water, several gallons large. You have two precise measuring pipettes, one to measure exactly 1/7 of an ounce and one to measure exactly 1/8 of an ounce. You can pour precisely measured amounts into a beaker, which initially is empty. You can use either pipette to remove distilled water from the vat or from the beaker and use either pipette to dispense water into either of those receptacles, but you cannot use either pipette to take any quantity of distilled water other than the amount for which it is designed. Which of the following represents, in ounces, a precise amount of distilled water you can transfer from the vat to the beaker?
I. 1/6
II. 1/7
III. 1/12	Choose the most appropriate option
A) I only	B) III only	C) I and III only	D) II and III only	E) 1/56 and 1556

Solution: Looking at the potential answer choices, 1/7 is immediately out as 7 is a prime that cannot be created from either 4 or 3.   1/7-1/8=1/56   1/7+1/8=15/56   Answer: 1/56 and 1556
Answer: E
A van takes 6 hours to cover a distance of 540 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time?
Choose one
A) 40 Kmph
B) 50 Kmph
C) 60 Kmph
D) 75 Kmph
E) 860 Kmph

Solution: Time = 6   Distence = 540   3/2 of 6 hours = 6 * 3/2= 
6 * 3/2 = 9
9 Hours   Required speed= 540/9= 
540/9 = 60
60 Kmph   60 Kmph)
Answer: C
Find the value of 3 + 3 â€¢ (8 â€“ 3)
Answers.
A) 25	B) 18	C) 17	D) 24	E) 15

Solution: 3 + 3 â€¢ (8 â€“ 3)   = 3 + 3 (5)   = 3 + 3 *5   = 3 + 15= 
3 + 15 = 18
18   correct answer 18
Answer: B
Find the smallest no divisible by 5 ,3,7 and leave a remainder of 2 in each case and is divisible by 11 ?	Pick one:
A) 737  B) 735  C) 105  D) 107  E) 108

Solution: the smallest no divisible by 5,3 and 7 and leaving reminder 2   and which is divisible by 11 is 737..   737/11= 
737/11 = 67
67   and when divided by 5,3 & 7 leave the reminder 2.....   so ans is 737   ANSWER:735
Answer: B
Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 3? Choose the correct choice
A) 70 kmph B) 50 kmph C) 57 kmph D) 54 kmph E) 70 kmph

Solution: Let the distances between city A to B and B to C be 2x km and 3x km respectively.   Total time taken to cover from A to C   = (2x)/40 + (3x)/60   = (6x + 6x)/120 = 12x/120   = x/10 Average speed   = (2x + 3x)/(x/10) = 50 kmph.   Answer: 50 kmph
Answer: B
Question: What is the remainder when W=(1!)!^3 + (2!)^3 + (3!)^3 + … + (432!)^3 is divided by 144?  Choose the correct choice from the following choices.
A) 0 B) 25 C) 49 D) 81 E) 100

Solution: 144 =12 *12   (1!)^3=1   2!=2, therefore (2!)^3=2*2*2= 
2*2*2 = 8
8   3!=6, therefore (3!)^3=6*6*6= 
6*6*6 = 216
216   4!=24 therefore (4!)^3= 24*24*24 which is completely divisible by 144   thus from 4! onwards each term will be divisible by 144 and will leave the remainder of 0   now the remainder when W=(1!)^3 + (2!)^3 + (3!)^3 + … + (432!)^3 is divided by 144 is same as, when 1+8+216= 
1+8+216 = 225
225 is divided by 144   now remainder when 225 is divided by 144 is 81. hence answer should be 81
Answer: D
Initially, the men and women in a room were in the ratio of 4 : 5. Then, 2 men entered the room and 3 women left the room. Then, the number of women doubled. Now there are 14 men in the room. How many E women are currently in the room?  Choose the most appropriate option
A) 12	B) 14	C) 15	D) 24	E) 36

Solution: the number of women doubled means that they have become 24 from 12..   and we have to tell the current strength so 24 is the answer..   let the number be 4x and 5x..   given 4x+2=14.. so x=3..   women number=5*3-3= 
5*3-3 = 12
12, then doubled=24..   ans 24
Answer: D
Find the odd man out
2880, 480, 92, 24, 8, 4, 4 Options.
A) 480 B) 92 C) 24 D) 8 E) 4

Solution: divide by 6, 5, 4, 3, 2, 1 respectively to obtain the next number.   92 is wrong.   ANSWER:92
Answer: B
The average of 9 observations was 9, that of the 1st of 5 being 10 and that of the last 5 being 8. What was the 5th observation?
Choose one.
A) 9 B) 8 C) 7 D) 6 E) 5

Solution: 1 to 9 = 9 * 9= 
9 * 9 = 81
81   1 to 5= 5 * 10= 
5 * 10 = 50
50   5 to 9= 5 * 8= 
5 * 8 = 40
40   5th= 50 + 40= 
50 + 40 = 90
90 – 81= 9   9nswer:9
Answer: A