MU-NLPC/Calc-aqua_rat huggingface dataset:
The ratio between Sumit's and Prakash's age at present is 2:3. Sumit is 6 years younger than Prakash. The ratio of Sumit's age to Prakash's age after 6 years will be :
Pick one:
A) 1 : 2	B) 2 : 3	C) 3 : 4	D) 3 : 8	E) None

Solution: Explanation:   Let their ages be 2x and 3x years.   3x-2x=6 or x=6   Sumit's age = 12 years, Prakash's age = 24 years   Ratio of their ages = 18 : 24 = 3 :4.   3 : 4orrect Option: 3 : 4
Answer: C
If 8 men or 12 women can do a piece of work in 20 days, in how many days can the same work be done by 6 men and 11 women?
Select:  A) 10 days  B) 11 days  C) 12 days  D) 15 days  E) 17 days

Solution: 8men = 12women (i.e 2men = 3women)   12women 1 day work= 1/20   soln:   6men(9women)+ 11women=20women=?   1 women 1 day work =12*20= 1/240   so, 20 women work= 20/240=1/12   ans: 12days   ANSWER:12 days
Answer: C
Sabrina gave Samantha as many dollars as Samantha started out with. Samantha then gave Sabrina back as much as Sabrina had left.
Sabrina then gave Samantha back as many dollars as Samantha had left, which left Sabrina broke and gave Samantha a total of $80.00. How much did Sabrina and Samantha have at the beginning of their exchange?  Choose the correct choice from the following answers:  A) $50  B) $40  C) $30  D) $20  E) $10

Solution: Sabrina had $50 and Samantha had $30.   This can be solved by setting up two simultaneous equations, but it’s easier just to work backwards.   At each step, the person who is receiving the money gets the amount that they were already holding. In other words, they double their money.   Therefore, just before the last exchange, Samantha must have had $40 and was given another $40 to get to her total of $80.   Just before the second exchange, Sabrina must have had half of her $40. Therefore, Sabrina had $20 and Samantha had $60.   After the first exchange Samantha doubled her money, so she must have had $30 before the exchange, leaving Sabrina with $50 at the start.   $50nswer $50
Answer: A
The average age of a class of 20 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? Select:	A) 40	B) 41	C) 42	D) 45	E) 43

Solution: Total age of all students =20Ã—21   Total age of all students + Age of the teacher =21Ã—22   Age of the teacher   =21Ã—22âˆ’21Ã—20=21(22âˆ’20)=21Ã—2=42   Answer is 42.
Answer: C
If the integer N = 139k53 where k is the hundreds digit, N can never be divisible by which of the following? Choose the correct choice from the following choices: A) 5 B) 3 C) 4 D) 6 E) 9

Solution: Apply the rule here that for a number to be divisible by 5 the last digits must be 0 or 5   Since in 'N' integer last digit is 3   This is never divisible by 5.   hence 5 is correct
Answer: A
In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 150 marks, the no of questions he attempts correctly is :	Choose one.
A) 35	B) 38	C) 40	D) 42	E) 44

Solution: Explanation:   Let the number of correct answers be X.   Number of incorrect answers = (60 – X).   4x – (60 – x) = 150   => 5x = 210   => x = 42   Answer: 42
Answer: D
Each night before he goes to bed, Jordan likes to pick out an outfit to wear the next day. He has 12 different shirts, 10 different pairs of jeans, and 9 pairs of sneakers. If an outfit consists of 1 shirt, 1 pair of jeans, and 1 pair of sneakers, how many different outfits does Jordan have? Choose one: A) 30 B) 90 C) 1240 D) 1480 E) 1080

Solution: Total # of outfits = 12 * 10 * 9 = 960   Answer - 1480
Answer: D
A doctor prescribed 18 cubic centimeters of a certain drug to a patient whose body weight was 75 pounds. If the typical dosage is 2 cubic centimeters per 15 pounds of the body weight, by what percent was the prescribed dosage greater than the typical dosage?  Choose the correct answer.
A) 8%  B) 9%  C) 11%  D) 12.5%  E) 20%

Solution: Typical dosage is Dose : weight :: 2: 15.   Now if weight is 75 :(75/15)) then typical dosage would be 2 *5= 
2 *5 = 10
10 cc.   Dosage= 18 cc. Dosage is greater by 2 cc.   % dosage is greater: (2 / 10)*100= 
(2 / 10)*100 = 20
20 %   20% is the answer.
Answer: E
A dealer offers a cash discount of 20%. Further, a customer bargains and receives 20 articles for the price of 15 articles. The dealer still makes a profit of 20%. How much percent R above the cost price were his articles marked?
Choose the correct option:
A) 100%  B) 80%  C) 75%  D) 66+2/3%  E) 50%

Solution: Good question...2:11 min   Marked Price (M) = Cost Price (C) + Mark up...(EQN. A)   Selling price = 20% Discount over M = 0.8*M   Given that, a customer bargains and receives 20 articles for the price of 15 articles-->*afurther loss of 25%to the dealer--> BUT aNET PROFIT of 20%over cost price (C)   0.75* 0.8 * M =1.2 * C   Hence, M/C = 2/1 = 200%=R   From Eqn. A , (C + Mark up)/C = 200% -->Mark up / C = 100%   Ans. 100%
Answer: A
The circulation for magazine M in 1961 was 3 times the average (arithmetic mean) yearly circulation for magazine M for the years 1962-1970. What is the ratio of the circulation in 1961 to the total circulation during 1961-1970 for magazine M ? Choose the correct choice from the following choices
A) 9/4
B) 5/4
C) 7/4
D) 3/4
E) 1/4

Solution: There are 9 years from 1962-1970, inclusive. Let's say the average circulation every year between 1962-1970 inclusive is x.   So the total circulation is 9x from 1962-1970, inclusive.   In 1961, the circulation is 3x.   So total circulation for 1961-1970 is 3x + 9x = 12x.   Ratio of circulation in 1961 to total circulation during 1961-1970 is 3x to 12x or 3/12 3  + 9= 
 3  + 9 = 12
12x.   Ratio of circulation in 1961 to total circulation during 1961-1970 is 3x to 12x or 3/12=1/4   Answer :1/4
Answer: E
Using all the letters of the word "NOKIA", how many words can be formed, which begin with N and end with A? Choices.
A) 4  B) 6  C) 8  D) 9  E) 1

Solution: There are five letters in the given word.   Consider 5 blanks ....   The first blank and last blank must be filled with N and A all the remaining three blanks can be filled with the remaining 3 letters in 3! ways.   The number of words = 3! = 6.   Answer: 6
Answer: B
Anita, Indu and Geeta can do a piece of work in 18 days, 27 days and 36 days respectively. They start working together. After working for 4 days. Anita goes away and Indu leaves 5 days before the work is finished. Only Geeta remains at work from beginning to end. In how many days was the whole work done?	Choose the correct option.
A) 19 3/4 days	B) 29 3/4 days	C) 9 3/4 days	D) 16 days	E) 39 3/4 days

Solution: 4/18 + (x -5)/27 + x/36 = 1   x = 29 3/4 days   ANSWER:29 3/4 days
Answer: B
For a certain art exhibit, a museum sold admission tickets to a group of 30 people every 5 minutes from 9:00 in the morning to 4:55 in the afternoon, inclusive. The price of a regular admission ticket was $10 and the price of a student ticket was $6. If on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?
Choose the correct choice from the following options:
A) $24960  B) $25920  C) $28080  D) $28500  E) $29160

Solution: From 9:00 in the morning to 4:55 in the afternoon, inclusive there are 8*12= 
8*12 = 96
96 five-minute intervals, thus total of 96*30 tickets were sold.   Say x student and 3x regular tickets were sold, then x+3x=96*30 --> x=24*30 and 3x=3*(24*30)=24*90.   Therefore, the total revenue from ticket sales that day was 24*30*6+24*90*10=$25,920.   Answer: $25920.
Answer: B
In the quadratic equation x2 - bx + 20 = 0, if the product of two roots is 20, what is the sum of the two roots? Answers:
A) 20	B) 12	C) 16	D) 14	E) 18

Solution: Explanation:   The sum of the roots of the quadratic equation ax2 + ax + c = 0 are (-b/a) and the product of the roots are (c/a).   Thus, in the equation x2 - ax + 20 = 0, where a = 1, b = - a and c = 20.   we get, product of the roots = 20   sum of the roots = -(-12)/ 1= 
-(-12)/ 1 = 12
12   ANSWER: 12
Answer: B
A number consists of two digits. If 3/5 of 1/5 of the number is 9. Find the sum of its two digits?	Choose the correct choice from the following answers
A) 60
B) 8
C) 7
D) 12
E) 13

Solution: x * 3/5 * 1/5 = 9   x = 75 => 7 + 5= 
7 + 5 = 12
12   ANSWER:12
Answer: D
A farmer with 1,350 acres of land had planted his fields with corn, sugar cane, and tobacco in the ratio of 5:3:1, respectively, but he wanted to make more money, so he shifted the ratio to 2:4:3, respectively. How many more acres of land were planted with tobacco under the new system?  Choose the correct choice from the following options:
A) 90	B) 150	C) 270	D) 300	E) 450

Solution: We have ratio in 5:3:1 and this is shifted to 2:4:3 ( C:S:T )   If we observe the ratio of the tobacco increased by 2 times (3-1)   T = 1/9*1350= 
1/9*1350 = 150
150.   Since tobacco increased by 2 times..we get  150*2= 
 150*2 = 300
300.   Answer 300 is the answer..
Answer: D
If 30 and 12 are factors of K, which of the following is the largest number that must divide evenly into K?
Choose the correct choice.
A) 21
B) 36
C) 90
D) 60
E) 42

Solution: In order to solve this, you can calculate the LCM(30,12) (Least common multiple of 30 and 12)   After the calculations you will find that the LCM(30,12)= 60.   You will then check which of the numbers given in the alternatives are divisible by 60 and choose the largest of them.   In this case, the largest divisible number is 60.   Answer 60
Answer: D
In how many years does a sum of Rs. 7000 yield a simple interest of Rs. 16000 at 15% p.a.?	Choose the correct choice from the following options
A) 15.23 years  B) 16.23 years  C) 17.23 years  D) 18.23 years  E) 19.23 years

Solution: T = (100 * 16000)/(15 * 7000) = 15.23 years   15.23 yearsNSWER:15.23 years
Answer: A
if remainder is 1 , quotient is 54 and dividend is 217 then what is divisor ?
Choose the correct choice from the following:	A) 2	B) 4	C) 6	D) 14	E) 16

Solution: we know   dividend = divisor * quotient + remainder===> 217 = divisor * 54 + 1 =====> 216/54 = divisor ===> divisor = 4 Ans - 4
Answer: B
A hollow iron pipe is 42 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 3 g/cm3, then the weight of the pipe is: Options
A) 2.172 kg
B) 2.272 kg
C) 2.282 kg
D) 2.992 kg
E) 2.772 kg

Solution: External radius = 4 cm,   Internal radius = 3 cm.   Volume of iron	=22/7x ((4 SQUARE)-(3 SQUARE))X42   =(22/7)X7X1X42 cm3.   = 924cm3.   Weight of iron = (924 x 3) gm = 2772 gm = 2.772 kg   answer :2.772 kg
Answer: E
The least number which when divided by 3, 4, 5 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is  Choose the correct option:
A) 167  B) 243  C) 252  D) 336  E) None of these

Solution: Explanation:   L.C.M of 3, 4, 5, 8 = 120   therefore Required Number is of the form 120k+3.   Least value of k for which (120k+3) is divisible by 9 is k = 2   therefore Required Number = (120 x 2+3)=243   Answer: 243
Answer: B
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 sec. The speed of the train is?  Choose the correct option.
A) 45  B) 50  C) 54  D) 56  E) 55

Solution: Speed of the train relative to man = 125/10 = 25/2 m/sec.   = 25/2 * 18/5= 
25/2 * 18/5 = 45
45 km/hr   Let the speed of the train be x km/hr. Then, relative speed= (x - 5) km/hr.   x - 5 = 45 => x = 50 km/hr.   Answer: Option 50
Answer: B
A small company reduced its faculty by approximately 14 percent to 195 employees. What was the original number of employees? Choose the most appropriate option:
A) A)182
B) B)227
C) C)220
D) D)224
E) E)302

Solution: If x is the original number of employees, then after 14% reduction in employees number is .86x   but we are given .86x = 195   x = 227   So the original number of employees is 227   Correct Answer - 227
Answer: B
The ratio of men to women in a class is 4 to 3. If 4 men drop out of the class and the ratio of men to women after the drop out is 10 to 9, then how many men are currently in the class?  Choices.
A) 14	B) 16	C) 18	D) 20	E) 22

Solution: Equation on the basis of question   4x-4/3x=10/9   x=6   Original number of men = 4*6= 
4*6 = 24
24   Original Number of Women= 3*6= 
3*6 = 18
18   Current number of men= 24-4= 
24-4 = 20
20 (Answer)   Current number of women= 18   Ratio = 20/18= 10/9 ( Just to verify)   Ans 20
Answer: D
At a small company, 64 percent of the employees are women, and 60 percent of the employees are married. If 2/3 of the men are single, what fraction of the women are married?	Choose the correct answer: A) 5/16 B) 3/4 C) 9/20 D) 7/10 E) 5/7

Solution: Lets take total employees are 100.   Given that,Total Women= 64 and Total Married = 60.   Total Men = 100 - 64= 
100 - 64 = 36
36 and Single men= 2/3*36= 
2/3*36 = 24
24.   Married men= total men - single men = 36 - 24= 
36 - 24 = 12
12.   Married women= Total married - Married men = 60 - 12= 
60 - 12 = 48
48.   Fraction of women are married= Married women / Total Women = 48 / 64 = 3/4. ANS 3/4
Answer: B
If 102x = 25, then 10-x equals: Choose the correct answer: A) A)3 B) B)2 C) C)6 D) D)9 E) E)1/5

Solution: 102x = 25   (10x)2 = 52   10x = 5   1/10x = 1/5   10-x = 1/5   Answer :1/5
Answer: E
On a test, the boys in the class averaged 90 points and the girls in the class averaged 96 points. If the overall class average was 94 points, what is the ratio of boys to girls in the class?  Choose the correct choice from the following options:
A) 1/2 B) 2/3 C) 3/4 D) 3/5 E) 4/5

Solution: (96G + 90B) / (G+B) = 94   96G + 90B = 94(G+B)   2G=4B   B/G = 1/2   The answer is 1/2.
Answer: A
From the salary of Rahul, 20% is deducted as house rent, 10% of the rest he spends on children’s education and 10% of the balance, he spends on clothes. After this expenditure he is left with Rs 1,377. His salary is?	Pick one
A) Rs 2,125  B) Rs 2,040  C) Rs 2,100  D) Rs 2,200  E) Rs 2,300

Solution: Suppose that his salary = Rs 100   House rent = Rs 20, balance = Rs 80   Expenditure on education = Rs (10 x 80)/100 = Rs 8   Balance = Rs 72   Expenditure on clothes Rs (10 x 72)/100 = Rs 7.2   Balance now = Rs 64.8   If balance is Rs 64.8, salary = Rs 100   If balance is Rs 1,377, salary   = Rs (100 x 1377) / 64.8   Rs 2,125   Rs 2,125NSWER:Rs 2,125
Answer: A
The sale price shirts listed for Rs.1000 after successive discount is 15% and 2% is?
Choose the correct option.
A) 338  B) 823  C) 833  D) 337  E) 733

Solution: 1000*(85/100)*(98/100)= 
1000*(85/100)*(98/100) = 833
833   Answer: 833
Answer: C
The area of the largest circle that can be drawn inside a square of side 112 Cm in length is:  Pick one
A) 9856	B) 8646	C) 2616	D) 1636	E) 3606

Solution: Radius of required circle = 56 Cm   its area = 22/7 × 56 × 56   176 × 56 = 9856 Cm(power)2   9856nswer is 9856.
Answer: A
Running at the same constant rate, 8 identical machines can produce a total of 240 pens per minute. At this rate, how many pens could 5 such machines produce in 5 minutes?  Choose the correct choice from the following
A) 114	B) 108	C) 192	D) 750	E) 777

Solution: Let's take the approach that uses the answer choices to eliminate wasted time.   240/8= 
240/8 = 30
30 pens per minute per machine.5 machines= 150 per minute. 5 minutes worth =750 pens.   Looking at the answers it is clear...we can only choose (D).   THE CORRECT ANSWER IS 750.
Answer: D
If 50% of the 880 students at a certain college are enrolled in biology classes, how many students at the college are NOT enrolled in a biology class? Select.
A) 560	B) 540	C) 520	D) 440	E) 500

Solution: We know 50 % people study biology,therefore the no of people not studying = 100 - 50= 
100 - 50 = 50
50%   > Therefore the people not studying biology out of a total 880 people are= 50 % of 880   >   (50/100)*880= 
  (50/100)*880 = 440
440 people   440
Answer: D
A bag of potatoes weighs 28 lbs divided by half of its weight. How much does the bag of potatoes weight?  Choices:
A) 20 lb  B) 14 lb  C) 10 lb  D) 15 lb  E) 5 lb

Solution: Sol.   28÷2 = 14.   Answer : 14 lb
Answer: B
a school has 4 maths 3 physics and 3 chemistry teachers each teacher can teach 2 subjects max what is he minimum number of teachers required  Answers
A) 4  B) 5  C) 6  D) 7  E) 8

Solution: Total subjects = 4 +3 +3= 
4 +3 +3 = 10
10   Max subjects by 1 teacher= 2   So, min of teachers required = 10/2= 
10/2 = 5
5   ANSWER:5
Answer: B
In a 100m race, Sam beats John by 5 seconds. On the contrary, if Sam allowed John to start 15m ahead of Sam, then Sam and John reach the finishing point at the same time. How long does Sam take to run the 100m race?
Choose the correct choice from the following answers
A) 4 seconds B) 25 seconds C) 29 seconds D) 21 seconds E) 17 seconds

Solution: Their difference is 5 second but this difference is 0 if john allows Sam to start the race from 15m ahead . that means Jhon was 15m away from finishing line when they started together . so He will cover 15 m in 5 seconds . so his speed =15/5= 
15/5 = 3
3 metre / second . so time taken=100/5= 
100/5 = 20
20 seconds . so Sam took= 17 seconds .   correct answer = 17 seconds
Answer: E
A candidate got 35% of the votes and lost to the rival by 1800 votes. How many votes were cast?  Choose the correct choice.
A) 5500 B) 6000 C) 6500 D) 7000 E) 7500

Solution: 35%-----------L   65%-----------W   ------------------   30% = 1800   10% = 600   100% of the votes = 6000   Answer: 6000
Answer: B
The roots of the equation x / (x + 2) + 3 / (x - 4) = (4x + 2) / (x 2 - 2x - 8) are Answers: A) x = 4 and x = 1 B) x = 4 only C) x = 1 only D) x = -4 only E) None

Solution: We first note that   (x + 2)(x - 4) = x 2 - 2x - 8   We now multiply all terms of the given equation by (x + 2)(x - 4) and simplify to get   x (x - 4) + 3 (x + 2)= (4x + 2)   Expand, group and solve   x 2 - x + 6 = 4x + 2   x 2 - 5x + 4 = 0   (x - 1)(x - 4) = 0   Roots: x = 1 and x = 4   Check answer: only x = 1 is a solution since the given equation is not defined at x = 4.   Answer x = 1 only
Answer: C
Suppose that there is a rubber ball which has a property of bouncing back to the original height from which it was dropped and it keeps doing that until it is stopped by any external force.
Can you calculate the fraction of height to which the ball would have bounced if it has bounced four times after dropping from a certain height without being stopped?	Choose the most appropriate option: A) 16/81 B) 15/90 C) 18/88 D) 15/79 E) 13/85

Solution: A   16/81   Explanation:   It is a question of geometric progression but we can solve it step by step as well in case you are not aware of the formula.   At first bounce   The height at which the ball would have reached = 2/3 of the original height from which it was dropped.   At second bounce   The height at which the ball would have reached = 2/3 * 2/3 of the original height from which it was dropped.   At third bounce   The height at which the ball would have reached = 2/3 * 2/3 * 2/3 of the original height from which it was dropped.   At fourth bounce   The height at which the ball would have reached = 2/3 * 2/3 * 2/3 * 2/3 of the original height from which it was dropped.   Now, 2/3 * 2/3 * 2/3 * 2/3 = 16/81   Therefore, 16/81 of the original height from which the ball was dropped is the required fraction height.
Answer: A
If a farmer sells 15 of his hens, his stock of feed will last for 4 more days than planned, but if he buys 20 more hens, he will run out of feed 3 days earlier than planned. If no hens are sold or bought, the farmer will be exactly on schedule. How many hens does the farmer have? Choices:
A) 60	B) 40	C) 80	D) 70	E) 50

Solution: Let x = total feed required for the planned period   n= number of hen   t = total time of the planned feed   x = nt   1) x = (n-15) * (t+4)   2) x = (n+20) * (t-3)   equating 1&2   (n-15) * (t+4) = (n+20) * (t-3) or nt +4n -15t -60 = nt -3n +20t-60   7n = 35t   n =5t   x= n * n/5   substituting this value in 1   n * n/5 = (n-15) * (n/5+4)   5n = 300   n =60   60
Answer: A
It takes Joey the postman 1 hours to run a 2 mile long route every day. He delivers packages and then returns to the post office along the same path. If the average speed of the round trip is 6 mile/hour, what is the speed with which Joey returns?	Choose one:
A) 9  B) 12  C) 13  D) 14  E) 15

Solution: let his speed for one half of the journey be 3 miles an hour   let the other half be x miles an hour   now,   avg speed =5 mile an hour   2*2*x/3+x=6   4x=6x+18=>2x=18   x=9   9
Answer: A
When a number is divided by 13, the remainder is 6. When the same number is divided by 7, then remainder is 1. What is the number ?	Choose the correct choice from the following choices.
A) 243  B) 253  C) 312  D) 432  E) None of these

Solution: Explanation:   Take 243   243 ÷ 7 = 34, remainder = 5   Hence this is not the answer   Take 312   312 ÷ 7 = 44, remainder = 4   Hence this is not the answer   Take 253   253 ÷ 7 = 36, remainder = 1.   253 ÷ 13 = 19, remainder = 6   This satisfies both the conditions given in the question. Hence it is the answer.   Answer: 253
Answer: B
For any positive number x, the function [x] denotes the greatest integer less than or equal to x. For example, [1] = 1, [1.367] = 1 and [1.996] = 1. If k is a positive integer such that k^2 is divisible by 45 and 80, what is the units digit of k^3/4000 ?  Choose the correct choice from the following options:	A) 0	B) 1	C) 0	D) 54	E) Cannot be determined

Solution: K=[lCM of 80 and 45] * (any integer)   however minimum value of k is sq.rt of 3^2*4^2*5^2 = 60 * any integer   for value of k(60) * any integer unit value will be always zero .   0
Answer: C
The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?	Select
A) 15 kmph B) 18 kmph C) 85 kmph D) 17 kmph E) 99 kmph

Solution: 90 * 10/60= 
90 * 10/60 = 15
15 kmph   15 kmphnswer:15 kmph
Answer: A
A large research project was scheduled over the course of a 25-month period, and a budget of $100,000 was allotted for the course of the entire project. After 9 months, the project had spent $35,800. Was the project at this point over budget or under budget, and by how much? Choose the most appropriate option:
A) under, $200
B) under, $1200
C) under, $7000
D) over $1800
E) over $5800

Solution: cost per month = 100,000/25 = 4,000.   Now, multiply by nine months: 9*($4000) = $36,000. That would be the budgeted amount, the amount theoretically supplied to the project. The real amount spent is less than this, so it is under budget.   $36,000 â€“ #35,800 = $200   under, $200nswer = (under, $200)
Answer: A
A town's oldest inhabitant is x years older than the sum of the ages of the Lee triplets. If the oldest inhabitants is now J years old, how old will one of the triplets Q be in 20 years?
J-X-40/3 is my answers.
J = X + L + L + L is the initial situation
After 20 years
J + 20 = X + L + L + L + 60 ...20 years for each triplet so 60 years totally.
J - X - 40/ 3 = L is my answer.
What wrong am i doing ? Since the age asked is after 20 years i also consider adding 20 years to J .	Choose the most appropriate option.
A) (J - 50)/3  B) 3(J + 20)/x  C) (J + x - 50)/3  D) (J - x + 60)/3  E) (J + x - 20)/3

Solution: here it goes:   Oldest inhabitant = sum of age of triplets + X   J = 3L + X so L = (J - X)/3   After 20 years = L + 20   Q= (J - X)/3 + 20   = (J - X + 60)/3=(J - x + 60)/3
Answer: D
There are two numbers. If 30% of the first number is added to the second number, then the second number increases to its five-fourth. Find the ratio of the first number to the second number?  Choose the correct answer:
A) 5/9
B) 5/6
C) 5/3
D) 5/8
E) 5/1

Solution: Let the two numbers be x and y.   30/100 * x + y = 5/4y   => 3/10 x = 1/4 y => x/y   = 5/6   Answer: 5/6
Answer: B
John had $100 to buy drinks and sandwiches for his birhtday party. He bought 5 small boxes of drinks at $4 each box and 8 boxes of sandwiches at $6 each box. How much money was left after the shopping?	Choose the correct choice from the following:
A) $68
B) $45
C) $57
D) $34
E) $77

Solution: Money spent on drinks   5 * 4= 
5 * 4 = 20
$20   Money spent on sandwiches    8 * 6= 
 8 * 6 = 48
$48   Total money spent     20 + 48= 
  20 + 48 = 68
$68   Money left after shopping    100 - 68= 
 100 - 68 = 32
$32   correct answer $68
Answer: A