MU-NLPC/Calc-aqua_rat huggingface dataset:
If Rs. 782 be divided into three parts, proportional to 1/2:2/3 :3/4, then the first part is: Pick.
A) 402	B) 408	C) 48	D) 24	E) 204

Solution: Given ratio = 1/2: 2/3:3/4   = 6 : 8 : 9.   Therefore, 1st part = Rs. (782 x 6/23)= Rs. 204.   Answer is 204.
Answer: E
7% of the total quantity of rice is lost in grinding when a country has to import 6 million tonnes, but when only 7 3/4% is lost, it can import 3 million tonnes. Find the quantity of rice grown in the country.	Choose the correct answer: A) 120 B) 200 C) 400 D) 430 E) 540

Solution: Let x be the total grown quantity of wheat. According to the question   (7%of x)+ 64 31 %of x)+3 7x 31x => 100+ 6 = 400 + 3 1200 x = — 400 million tonnes rice grown   400
Answer: C
The average of first five multiples of 7 is	Choose one:  A) 21  B) 6  C) 9  D) 12  E) 15

Solution: Solution   Average	= 7(1+2+3+4+5) / 5   = 105 / 5.= 
105 / 5. = 21
21   21nswer 21
Answer: A
The daily high temperatures were recorded at an Antarctic weather station. If a temperature of -38.2 degrees Celsius is 2 units of standard deviation below the mean temperature, and a temperature of -22.6 degrees Celsius is 4 units of standard deviation above the mean, which of the following temperatures is 4 unit of standard deviation above the mean?  Choose the correct option
A) -35.6 degrees Celsius  B) -22.6 degrees Celsius  C) -30.4 degrees Celsius  D) -27.8 degrees Celsius  E) -25.2 degrees Celsius

Solution: Let us suppose mean = M and SD = d.   So, we are given M - 2d = -38.2   and M + 4d = -22.6   solving both the equations, we will get M = -33 an d = 2.6   So, we need to find out M + 4d = -33 + 4*2.6 = -22.6. Hence, -22.6 degrees Celsius
Answer: B
Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $167 million, which represented 10 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars? Select the correct option.
A) 1,650 B) 1,670 C) 1,890 D) 1,701 E) 3,210

Solution: 10% ---- 167 millions   for 100% => ( 167 * 100% )/10% = 1670.   Option 1,670.( 167 * 100  )/10= 
( 167 * 100  )/10 = 1_670
1670.   Option 1,670.
Answer: B
A cargo ship carrying four kinds of items, doohickies, geegaws, widgets, and yamyams, arrives at the port. Each item weighs 2, 11, 5, and 7 pounds, respectively, and each item is weighed as it is unloaded. If, in the middle of the unloading process, the product of the individual weights of the unloaded items equals 104,350,400 pounds, how many widgets have been unloaded? Select:
A) 2	B) 3	C) 4	D) 25	E) 20,870,080

Solution: We need to know the number of widgets (which weigh 5 pounds each). The number of times that 5 divides the number is related to the number of times that 10 divides the number.   When we divide 104,350,400 by 100, we get 104,350,400 = 1,043,504 * 5^2 *2^2.   1,043,504 is not divisible by 5, thus there are 2 widgets.   The answer is 2.
Answer: A
Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder  Choices:
A) 1345  B) 1250  C) 1540  D) 1600  E) 1635

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1365 = 6x + 15   5x = 1350   x = 270   Large number = 270+1365= 
270+1365 = 1_635
1635   1635
Answer: E
Departments A, B, and C have 10 employees each, and department D has 20 employees. Departments A, B, C, and D have no employees in common. A task force is to be formed by selecting 1 employee from each of departments A, B, and C and 2 employees from department D. How many different task forces are possible?
Select
A) 19,000  B) 40,000  C) 100,000  D) 190,000  E) 400,000

Solution: Take the task of creating the task force and break it into stages.   Stage 1: Select one person from department A   There are 10 people to choose from, so we can complete stage 1 in 10 ways   Stage 2: Select one person from department B   There are 10 people to choose from, so we can complete stage 2 in 10 ways   Stage 3: Select one person from department C   There are 10 people to choose from, so we can complete stage 3 in 10 ways   Stage 4: Select 2 people from department D   Since the order in which we select the 2 people does not matter, we can use combinations.   We can select 2 people from 20 people in 20C2 ways (190 ways)   So, we can complete stage 4 in 190 ways   By the Fundamental Counting Principle (FCP), we can complete all 4 stages (and thus create a task force) in (10)(10)(10)(190) ways (= 190,000 ways)   Answer:190,000
Answer: D
The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?	Choose the correct answer.
A) 28	B) 26	C) 265	D) 35	E) 27

Solution: Area of a triangle = r * s   Where r is the inradius and s is the semi perimeter of the triangle.   Area of triangle = 2.5 * 28/2= 
2.5 * 28/2 = 35
35 cm2   Answer: 35
Answer: D
In how many different number of ways a combination of 3 men and 2 women can be selected from 6 men and 5 women?	Choose the correct choice from the following answers
A) 18  B) 20  C) 22  D) 24  E) 26

Solution: 6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   20)
Answer: B
What will be the reminder when (13^13+13) is divided by 14?
Pick.
A) 16  B) 14  C) 12  D) 18  E) 21

Solution: (x^n+1) will be divisible by (x+1) only when n is odd;   (13^13+1) will be divisible by (13+1);   (13^13+1)+12 when divided by 14 will give 12 as remainder.   12orrect Option : 12
Answer: C
The average age of 42 students in a group is 16 years. When teacherâ€™s age is included to it, the average increases by one. What is the teacherâ€™s age in years?  Choices:
A) 31
B) 56
C) 41
D) 59
E) None

Solution: Sol.   Age of the teacher = ( 43 Ã— 17 â€“ 42 Ã— 16 ) years = 59 years.   Answer 59
Answer: D
What is the probability that the sum of two dice will yield a 6, and then when both are thrown again, their sum will again yield a 6? assume that each die has 5 sides with faces numbered 1 to 5. Choose the correct choice:
A) 1/144
B) 1/25
C) 1/12
D) 1/6
E) 1/3

Solution: Solution -   Rolling dices is an independent event.   The combinations to get 6 are (1,5), (5,1), (2,4), (4,2), (3,3) and total combinations of both dices is 25.   The probability of getting 6 in first attempt is 5/25=1/5.   Probability of getting 6 again in second attempt = (1/5)*(1/5) = 1/25. ANS 1/25
Answer: B
A fair coin is tossed 10 times. If the coin lands tails 8 out of the 10 times, what is the probability that the coin will land on heads on the next toss? Choose one:
A) 4/5
B) 2/5
C) 1/3
D) 2/10
E) 5/10

Solution: As the given coin is a fair coin, the probability of getting tail on the next toss is independent of the out comes in the previous 10 tosses. So probability = 1/2 => 5/10   Answer:5/10
Answer: E
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?  Answers
A) 1108 B) 1683 C) 2007 D) 3363 E) 1436

Solution: LCM of 5, 6, 7 and 8 = 840   Hence the number can be written in the form (840k + 3) which is divisible by 9.   If k = 1, number = (840 × 1) + 3 = 843 which is not divisible by 9.   If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9.   Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.   ANSWER:1683
Answer: B
The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.2 years, The ratio of the number of boys to the number of girls in the class is	Choose the most appropriate option.
A) 7 : 3	B) 2 : 3	C) 9 : 3	D) 6 : 3	E) 1 : 1

Solution: Explanation:   Let the ratio be k : 1. Then,   k * 16.4 + 1 * 15.2 = (k + 1) * 15.8   <=> (16.4 - 15.8) k = (15.8 - 15.2) <=> k = 0.6/0.6= 
0.6/0.6 = 1
1/1.= 
1/1. = 1
1/1 : 1= 1 : 1.   Answer: 1 : 1
Answer: E
A library has an average of 400 books on Sundays and 240 on other days. The average number of books per day in a month of 30 days beginning with a Sunday is?	Choose the correct choice.
A) 50
B) 55.5
C) 65
D) 75.5
E) 78.5

Solution: Since the month begins with a Sunday, to there will be five Sundays in the month.   Required average   = (400 x 5 + 240 x 25)/30   =	8550   30   = 75.5   75.5
Answer: D
X is a positive integer. When X + 1 is divided by 7, the remainder is 3. What is the remainder when N is divided by 7?  Choices:
A) 6
B) 5
C) 4
D) 3
E) 2

Solution: N+1 = 7a+3   i.e. N+1 = 10, 17, 24, 31, ... etc.   i.e. N = 9, 16, 23, 30, ... etc.   When N is divided by 7 Remainder is always 2   Answer: 2
Answer: E
complete the numerical series with the correct number
5+3+4=152032
9+2+9=188197
8+6+7=485698
5+4+4=202036
9+5+2= ? Select the correct option:
A) 451858
B) 454586
C) 454585
D) 454386
E) 444586

Solution: 9+5+2=451858   451858nswer : 451858
Answer: A
Chandu started a business investing Rs. 70,000. Firoz joined him after 6 months with an amount of Rs. 1,05,000 and Pavan joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Chandu, Firoz and Pavan respectively, 3 years after Chandu started the business ? Choose the correct choice from the following choices:
A) 12:15:16  B) 13:16:21  C) 16:15:12  D) 10:14:19  E) None of these

Solution: Explanation :   Chandu : Firoz : Pavan = (70000*36) : (105000*30) : (140000*24)   = 12 : 15 : 16   12:15:16nswer : 12:15:16
Answer: A
A card game called “high-low” divides a deck of 52 playing cards into 2 types, “high” cards and “low” cards. There are an equal number of “high” cards and “low” cards in the deck and “high” cards are worth 2 points, while “low” cards are worth 1 point. If you draw cards one at a time, how many ways can you draw “high” and “low” cards to earn 4 points if you must draw exactly 2 “low” cards? Choose the correct choice from the following answers:
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: Great question Ravih. This is a permutations problem (order matters) with repeating elements. Given thatlowcards are worth 1 pt andhigh cards2 pts, and you must draw 3 low cards, we know that you must also draw 1 high card. The formula for permutations problems with repeating elements isN!/A!B!...where N represents the number of elements in the group and A, B, etc. represent the number of times that repeating elements are repeated. Here there are 4 elements and thelowcard is repeated 3 times. As a result, the formula is:   3!/2! which represents (3*2*1)/(2*1) which simplifies to just 4, giving you answer 3.
Answer: C
six friends met for lunch at an expensive restaurant, and everyone decided to contribute equally to the total bill of $420. If one of the friends had a coupon for 20% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay? Answers:
A) $90	B) $70	C) $56	D) $37	E) $35

Solution: 420 * 0,20 = 84   420 - 84= 
420 - 84 = 336
336   336 /6= 
336 /6 = 56
56   Answer $56
Answer: C
The average of six number is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. what is the average of the remaining two number ?
Options
A) 4.5
B) 4.6
C) 4.7
D) 4.8
E) None of these

Solution: solution:   Sum of the remaining two numbers = (3.95 × 6) - [(3.4 × 2) + (3.85 ×2)]   =23.70 -(6.8 + 7.7) = 23.70 - 14.5 = 9.20.   ∴ Required average =9.2/2= 
9.2/2 = 4.6
4.6 Answer 4.6
Answer: B
An art gallery owner is hanging paintings for a new show. Of the six paintings she has to choose from, she can only hang three on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings?  Choose the correct choice from the following choices:
A) 18	B) 30	C) 64	D) 120	E) 216

Solution: Arrangement means permutations questions..   6P3 = 6!/3! = 120   .   ANS option 120 is correct answer..
Answer: D
Find the invalid no.from the following series 13, 18, 25, 30, 37, 40 Choose the correct option:
A) 13  B) 18  C) 40  D) 25  E) 30

Solution: The differences between two successive terms from the beginning are 7, 5, 7, 5, 7, 5. So, 40 is wrong.   40
Answer: C
What percentage of simple interest per annum did Anand pay to Deepak?
I.Anand borrowed Rs. 8000 from Deepak for four years.
II.Anand returned Rs. 8800 to Deepak at the end of two years and settled the loan. Choose the correct choice:
A) I alone sufficient while II alone not sufficient to answer
B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer
D) Both I and II are not sufficient to answer
E) Both I and II are necessary to answer

Solution: Explanation:   Let the rate be R% p.a.   I gives, P = Rs. 8000 and T = 4 years.   II gives, S.I. = Rs. (8800 – 8000) = Rs. 800.   R =( 100 x S.I / P x T ) = ( 100 x 800 / 8000 x 4 )% = 2 1/2 % p.a   Thus, I and II both are needed to get the answer.   answer is (Both I and II are necessary to answer).
Answer: E
A computer can perform y calculations in s seconds. How many minutes will it take the computer to perform k calculations?	Pick:
A) 60ks/y B) ks/y C) ks/60y D) 60y/ks E) k/60ys

Solution: As 'thick' as this question might look, it's actually a fairly straight-forward Rate question and can be solved by TESTing VALUES.   We're told that a computer can perform y calculations in S seconds.   Let's TEST....   y = 2   S = 3   2 calculations every 3 seconds =   40 calculations every 1 minute   We're asked how many MINUTES it will take to perform K calculations.   Since we already know that the computer can perform 40 calculations in 1 minute, let's TEST...   K = 80   So we're looking for an answer that = 2 when y = 2, S = 3 and K = 80   Answer A: 60KS/y = 60(80)(3)/2 = 7200 This is NOT a match   Answer B: KS/y = (80)(3)/2 = 120 This is NOT a match   Answer C: KS/60y = (80)(3)/(60)(2) = 2 This IS a match   Answer D: 60y/KS = 60(2)/(80)(3) = 1/2 This is NOT a match   Answer E: K/60yS = 80/(60)(2)(3) = a fraction. This is NOT a match   ks/60y
Answer: C
9000 + 16 2/3 % of ? = 10500	Choices
A) 2387 B) 2888 C) 9000 D) 2837 E) 2271

Solution: Explanation:   9000 + 16 2/3 % of ? = 10500 => 9000 + 50/3 % of ? = 10500   50/(3 * 100) of ? = 1500 => ? = 1500 * 6= 
1500 * 6 = 9_000
9000   Answer: 9000
Answer: C
Harold works at a resort from the beginning of March to the end of September. During the month of August this past year, he made 5 times the average (arithmetic mean) of his monthly totals in tips for the other months. His total tips for August were what fraction of his total tips for all of the months he worked?	Options.
A) 1/3 B) 2/5 C) 3/7 D) 4/7 E) 5/11

Solution: The time from beginning of March to the end of September is 7 months.   If x is the average monthly tip for all months other than August then his August month tip will be 5*x   His total tip for the 7 months = 6*(average tip for the months other than August) + 5x   =11x   August tips as a fraction of total tips = 5x/11x =5/11. So 5/11
Answer: E
In an apartment building that has 490 units, 4 out of every 7 units are currently rented, including 1/6 of the one-bedroom units. If, of the rented apartments, there is a 6:1 ratio of two-bedroom units to one-bedroom units, and the building only consists of two-bedroom and one-bedroom units, how many two-bedroom units are not rented? Choose the correct choice
A) 50 B) 70 C) 10 D) 105 E) 140

Solution: Rented = 4/7*490= 
4/7*490 = 280
280.   Rented two-bedroom= 6/7*280= 
6/7*280 = 240
240;   Rented one-bedroom= 1/7*280= 
1/7*280 = 40
40 (or 280-240= 
280-240 = 40
40).   Rented one-bedroom units are 1/5 of all one-bedroom: 1/6*{All one bedroom}= 40 --> {All one-bedroom} = 240.   {All two-bedroom} = 490 - 240= 
490 - 240 = 250
250.   Two-bedroom not rented= 250 - 240= 
250 - 240 = 10
10.   Answer: 10.
Answer: C
If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?
Choose the most appropriate option
A) 22 1/7 %
B) 22 3/2 %
C) 22 1/8 %
D) 22 1/2 %
E) 22 1/2 %

Solution: 9 = (1*40*R)/100   R = 22 1/2 %   Answer:22 1/2 %
Answer: D
What will come in place of the x in the following Number series? 6, 12, 21, x , 48
Select.
A) 33  B) 38  C) 45  D) 49  E) 52

Solution: (A)   The pattern is + 6, + 9, + 12, +15 ………..   So the missing term is = 21 + 12= 
21 + 12 = 33
33
Answer: A
What is the difference between the place value of 6 in the numeral 7669?  Choose the correct choice from the following answers
A) 150 B) 160 C) 180 D) 190 E) 540

Solution: 600 - 60= 
600 - 60 = 540
540   540
Answer: E
For what values of k will the pair of equations 4(3x + 4y) = 48 and kx + 12y = 30 does not have a unique solution?  Choose the correct choice from the following choices.
A) 12  B) 9  C) 3  D) 7.5  E) 2.5

Solution: we have 2 equations   1. 4(3x + 4y) = 48 --> 3x + 4y = 12 -- > 9x + 12y = 36   2. kx + 12y = 30   substract 1-2, we get (9-K)x = 6   i.e. x = 6/(9-k)   then, by looking at options, we get some value of x except for B. When we put k=9, x becomes 6/0 and hence answer is 9
Answer: B
If it takes a tub 3 minutes to drain 6/7 of its content, how much more time will it take for the tub to be empty?
Pick one
A) 30 seconds	B) 1 minute, 12 seconds	C) 1 minute, 50 seconds	D) 2 minutes, 14 seconds	E) 4 minutes, 12 seconds

Solution: If 6/7 of tub's content is drained 1/7 th of tub still needs to be drained.   If it takes 3 minutes to drain 6/7 th of tub it takes 3*(7/6) minutes to drain the entire tub and 3*(7/6)*(1/7) min to drain 1/7 th of the tub which is 6/5 minutes or 0.5 minutes or 30 seconds   So answer is 30 seconds
Answer: A
If a man lost 4% by selling oranges at the rate of 12 a rupee at how many a rupee must he sell them to gain 44%?	Pick
A) 6
B) 8
C) 6
D) 5
E) 4

Solution: 96% ---- 12   144% ---- ?     96/144 * 12= 
  96/144 * 12 = 8
8   Answer:8
Answer: B
In what time will a train 120 meters long completely pass an electric pole, if it travels at a speed of 60kmph.  Choose the correct choice from the following answers:
A) 6.18 B) 5.18 C) 4.18 D) 4.18 E) 7.18

Solution: Sol.   Speed = [ 60x5/18] m/sec =16.7 m / sec.   Time taken = (120/16.7)sec = 7.18 sec.   Answer 7.18
Answer: E
A house seller can deduct 5 percent from the total sales value. If he has sold 5 houses, and the price of two houses is between $150,000 and $250,000, one of them is $300,000 house, two houses are between $500,000 and 800,000, what is the range of his revenue?	Choices
A) 750
B) 800
C) 850
D) 860
E) 880

Solution: (1) 2(150)+300+2(500) = 1600   1600*0.95= 
1600*0.95 = 1_520
1520 (Revenue considering the minimum values with the discount)   (2) 2(250)+300+2(800)= 2400 (Revenue considering the maximum values without the discount)   So, the the revenue range could be = 2400 - 1520= 
2400 - 1520 = 880
880   (Answ 880)
Answer: E
In how many ways can the letters of word "EDUCATION" be arranged such that NO two vowels appear together?
Select:  A) 9!  B) 5!*4!  C) 5!*5!  D) 5!*4!*2!  E) 6!*4!

Solution: No 2 vowels together = the only arrangement possible will be V C V C V C V C V (with V=vowel, C=consonant). This is true as we have 5 vowels and 4 consonants and any other combination will force us to pair 2 vowels together.   Thus, the number of arrangements possible : 5 *4 *4 *3 *3 *2 *2*1 = 5!*4! ----> 5!*4! is the correct answer.
Answer: B
In a sequence, each term is obtained by adding 8 to the preceding one. If the sum of the first 30 terms is equal to 210, what is the result of the addition of the first 50 terms?  Pick.
A) 8400
B) 8575
C) 8650
D) 8680
E) 8700

Solution: a is first term and d = 8 since the preceding number is always greater than the previous one..   Now 30th term is a+29(2).   Sum of n terms is n/2(first term + last term)and here we have to get sum of 30 terms , we get 30/2 ( a + a+58) = 210 ( given sum of 30 terms is 210)   => 15(2a+58) = 210   => 2a+58 = 14   => a = -22   Now to get sum of first 50 terms , we need to get 50th term value i.e. -22+49(8) = 370.   Sum of first 50 terms = 50/2( -22 + 370) = 8700.   Hence option 8700 is correct answer..
Answer: E
A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?
Select the correct option.
A) 22 1/9 kmph B) 27 1/2 kmph C) 42 1/2 kmph D) 22 1/2 kmph E) 22 5/2 kmph

Solution: 100 --- 10 22 1/2 kmphS = 10   ? ---- 1   75 ---- 15 US = 5   ? ----- 1 S = (10 - 5)/2   = 22 ½ kmph   Answer: 22 1/2 kmph
Answer: D
In a primary school, 10% of students are below 11 years of age. The number of students above 11 years of age is 3/4 of the number of students of 11 years of age which is 36. What is the total number of students in the school?  Choose the correct answer:
A) 72 B) 80 C) 70 D) 150 E) None of these

Solution: Explanation :   Let the number of students be x.   Then, Number of students above 11 years of age = (100 - 10)= 
(100 - 10) = 90
90% of x.   90% of x= 36 + 3/4 of 36   90x/100 = 63   x = 70.   Answer : 70
Answer: C
Sandy is younger than Molly by 10 years. If their ages are in the respective ratio of 7:9, how old is Molly? Choices:
A) 27
B) 36
C) 45
D) 54
E) 63

Solution: S = M - 10   S / M = 7/9   9S = 7M   9(M-10) = 7M   M = 45   The answer is 45.
Answer: C
If G and H are positive integers, and the remainder obtained when G is divided by H is the same as the remainder obtained when H is divided by G, which of the following is a possible value of GH? Choose the correct choice from the following answers
A) 62  B) 55  C) 46  D) 35  E) 4

Solution: I am not too sure on this. I guess it is possible only when G and H are both same. If they are both same, GH must be a perfect square.   4 is a perfect square.   Ans:4
Answer: E
How many distinct ponts do the hour and minute hands of a clock meet on its dual between 6AM and 6PM of certain day. Choose the most appropriate option:
A) 14 times
B) 13 times
C) 12 times
D) 11 times
E) 10 times

Solution: in 12 hours min. & hr. hand meet 11 times at different times   ANSWER:11 times
Answer: D
Vinay spends 30% of his salary on house rent and 55% of the remaining money on food and clothes. He saves the remaining amount. If he saves ?59724 yearly, how much amount does he spend on food and clothes per month ?	Select:
A) Rs. 5316
B) Rs. 4792
C) Rs. 5817
D) Rs. 6080
E) Rs. 6083

Solution: Let his monthly salary be x.   House rent expenditure = 30/100 x = 3x/10   âˆ´ Remaining = 7x/10   Rs. 6083xpense of food = 7x/10 x 55/100 = 77x/200   âˆ´ Remaining = 7x/10 - 77x/200   = 140x - 77x/200 = 63x/200   Monthly saving = 59724/12= 
59724/12 = 4_977
4977   âˆ´ 63x/200= 4977 = x = 4977 x 200/63 = 15800   Rs. 6083xpenditure on food and clothes = 77x/200   = 6083
Answer: E
A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 28 minutes. When both pipes are opened, find when the cistern will be full?
Choices
A) 17 minutes
B) 87 minutes
C) 70 minutes
D) 27 minutes
E) 11 minutes

Solution: 1/20 - 1/28 = 1/70   70 minutes   Answer:70 minutes
Answer: C
A train 400 m long is running at a speed of 54 km/hr. If it crosses a tunnel in 2 minutes. Then what is the length of tunnel?  Pick.
A) 1200 m B) 1400 m C) 1600 m D) 1800 m E) 2200 m

Solution: Speed of train in m/sec = (speed of train in km/hr) x 5/18   ∴ speed of train in m/sec = 54 x 5/18 = 15 m/sec   Time taken to cross the tunnel = 2 minutes = 120 sec   Therefore, Total length covered by train in crossing the tunnel = Speed of train x Time taken to cross the tunnel   = 15 m/sec x 120 sec = 1800 m   Total length covered by train in crossing the tunnel = Length of train + Length of tunnel   Given, Length of train =400m and   Calculated above, Length covered by train in crossing the tunnel = 1800 m   Therefore, Length of tunnel = 1800m- 400m = 1400m   CORRECT ANSWER : Option: 1400 m1800 - 400= 
1800 - 400 = 1_400
1400m   CORRECT ANSWER : Option: 1400 m
Answer: B
(935421 x 625) = ? Choose the most appropriate option:  A) 542622125  B) 584632125  C) 544638125  D) 584638125  E) None of these

Solution: Explanation :   935421 × 625 = 935421 × 54 = 935421 × (10/2)4 = (935421 × 10000)/16 = 584638125. Answer : Option 584638125
Answer: D