MU-NLPC/Calc-aqua_rat huggingface dataset:
My watch was correct at noon, after which it started to lose 17 minutes per hour until six hours ago it stopped completely. It now shows the time as 2.52 pm. What time is it now? Choose the correct choice:  A) 11 pm  B) 10 pm  C) 01 am  D) 03 am  E) 09 pm

Solution: 10 pm   10 pm   12 noon = 12 noon,   1 pm = 12.43,   2 pm = 1.26,   3 pm = 2.09,   4 pm = 2.52 + 6 hours = 10 pm.
Answer: B
How many miles is 320km?
Choose the most appropriate option:  A) 150miles  B) 175miles  C) 200miles  D) 225miles  E) 250miles

Solution: 200 miles   320/1.6= 
320/1.6 = 200
200   Answer:200miles
Answer: C
Kathleen can paint a room in 3 hours, and Anthony can paint an identical room in 5 hours. How many hours would it take Kathleen and Anthony to paint both rooms if they work together at their respective rates?  Choose the correct option
A) 8/15 B) 4/3 C) 15/8 D) 9/4 E) 15/4

Solution: kat---3 hrs---1 room ; so rate is work/time= 1/3   Anthony---5 hrs---1 room ; rate= 1/5   rate of kat and anthony together=1/3+1/5 = 8/15   But we are told that they both paint 2 rooms which are identical.   So; Work is 2 rooms, rate is 8/15,   total time required for both of them together to complete the work = 2/(8/15)= 30/8= 15/4   Hence Answer= 15/4
Answer: E
Which of the following will not be a correct option for b given the equation: b = x/2 + y/2^4 + z/4^3, where x,y and z are each equal to 1 or 0.	Options
A) 1/4  B) 1/16  C) 9/32  D) 1/32  E) 3/32

Solution: b = x/2 + y/2^4 + z/4^3   = x/2 + y/16 + z/64   = (16x + 2y + z) /64   Depending on whether a, b and c take 0 or 1   substitute 0 or 1 for the different values of x,y and z.   Answer 3/32
Answer: E
Lindsay can paint a room in 8 hours at a constant rate. If Lindsay paints the room for 4 hours and Joseph paints the rest of the room, who works at 1/2 constant rate of Lindsay. How long will it take for Joseph alone to paint the rest of the room? Choose the correct choice from the following options.
A) 4hrs	B) 8hrs	C) 10hrs	D) 12hrs	E) 16hrs

Solution: Lindsay will do 4/8 in 4 hrs, so Lindsay does 1/2 of the work ..   Therefore, Joseph will do the remaining 1/2 work alone..   As the speed of Joseph is 1/2 rate of Lindsay, Joseph will do the 1/2 work in same time that Lindsay takes to complete full job...   ans 8   8hrs
Answer: B
If a man walks to his office at ¾ of his usual rate, he reaches office 1/3 of an hour late than usual. What is his usual time to reach office? Choose one:
A) 1 hour
B) 8 hour
C) 9 hour
D) 6 hour
E) 2 hour

Solution: Speed Ratio = 1:3/4 = 4:3   Time Ratio = 3:4   1 -------- 1/3   3 --------- ? è 1 hour.1 hournswer:1 hour
Answer: A
Series D(n) is such that i*D(i) = j*D(j) for any pair of positive integers (i, j). If D(1) is a positive integer, which of the following is possible?
I. 2*D(100) = D(99) + D(98)
II. D(1) is the only integer in the series
III. The series does not contain negative numbers	Choose the correct choice from the following
A) I only  B) II only  C) IIII only  D) IIIII only  E) I, IIIII

Solution: First thing I want to understand is this relation: i*D(i) = j*D(j) for any pair of positive integers. I will take examples to understand it.   When i = 1 and j = 2, D(1) = 2*D(2)   So D(2) = D(1)/2   When i = 1 and j = 3, D(1) = 3*D(3)   So D(3) = D(1)/3   I see it now. The series is: D(1), D(1)/2, D(1)/3, D(1)/4 and so on...   II and III are easily possible. We can see that without any calculations.   II. D(1) is the only integer in the series   If D(1) = 1, then series becomes 1, 1/2, 1/3, 1/4 ... all fractions except D(1)   III. The series does not contain negative numbers   Again, same series as above applies. In fact, since D(1) is a positive integer, this must be true.   I. 2*IIIII only(100) = IIIII only(99) + IIIII only(98)   2*IIIII only(1)/100 = IIIII only(1)/99 + IIIII only(1)/98 (cancel IIIII only(1) from both sides)   2/100 = 1/99 + 1/98   Not true hence this is not possible   Answer (IIIII only)
Answer: D
Product of two co-prime numbers is 117. Their L.C.M should be Options:
A) 222	B) 117	C) 278	D) 767	E) 298

Solution: H.C.F of co-prime numbers is 1. So, L.C.M = \inline \fn_jvn \frac{117}{1} =117   Answer: 117
Answer: B
A train 400m long takes 10 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train?  Choose the correct choice from the following options.
A) A)175kmph	B) B)150kmph	C) C)162kmph	D) D)149kmph	E) E)100kmph

Solution: Let the speed of the train be x kmph   Speed of the train relative to man = x+5 = (x+5)*5/18 m/sec   400/[(x+5)*5/18] = 10   10(x+5) = 80*18   x = 149kmph   Answer is 149kmph
Answer: D
In the faculty of Reverse-Engineering, 100 second year students study numeric methods, 300 second year students study automatic control of airborne vehicles and 200 second year students study them both. How many students are there in the faculty if the second year students are approximately 40% of the total?  Select:
A) 550 B) 500 C) 600 D) 650 E) 700

Solution: Total number of students studying both are 100 + 300 - 200= 
100 + 300 - 200 = 200
200 (Subtracting the 200 since they were included in the both the other numbers already).   So 40% of total is 200, so 100% is 500   Answer is 500
Answer: B
When Rahul was born, his father was 35 years older than his brother and his mother was 25 years older than his sister. If Rahul's brother is 5 years older than him and his mother is 3 years younger than his father, how old was Rahul's sister when he was born ?	Choose the most appropriate option:
A) 11 years
B) 10 years
C) 12 years
D) 9 years
E) 8 years

Solution: When Rahul was born, his brother's age = 5 years; his father's age = (5 + 35)= 
(5 + 35) = 40
40 years,   his mother's age= (40 - 3)= 
(40 - 3) = 37
37 years;   his sister's age= (37 - 25)= 
(37 - 25) = 12
12 years.   Answer: Option 12 years
Answer: C
If (x+3)^2/(3x+65)=2, then the difference between the two possible values of x is:  Choose the correct choice from the following answers.
A) 16	B) 18	C) 20	D) 22	E) 24

Solution: (x+3)^2/(3x+65)=2   (x+3)^2=2(3x+65)   x^2+6x+9=6x+130   x^2-121=0   (x-11)(x+11)=0   x=11 or x=-11   The answer is 22.
Answer: D
By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?	Choose the correct choice from the following:
A) 7%.	B) 9%.	C) 8%.	D) 2%.	E) 3%.

Solution: Explanation:   Marked price = Rs. 300   C.P. = 100/120 * 300 = Rs. 250   Sale price = 90% of Rs. 300 = Rs. 270   Required gain % = 20/250 * 100= 
20/250 * 100 = 8
8%.   Answer: 8%.
Answer: C
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 2/3 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?
Choose one:
A) 1/16  B) 7/8  C) 9/64  D) 5/64  E) 3/64

Solution: P(Xavier will solve)=1/4   P(Yvonne will solve)=2/3   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/4)*(2/3)*(3/8) = 1/16.   Ans. 1/16.
Answer: A
A man invested Rs. 5050 in 5% stock at 99 and sold it when the price rose to Rs. 101. He invested the sale proceeds in 8% stock at 88. Find the change in man's income if the Brokerage is Rs. 2. Select
A) 150 B) 160 C) 170 D) 180 E) 190

Solution: Purchase price of the first stock = Rs.99 + Rs.2 = Rs.101   Number of stocks purchased in this case = 5050/101= 
5050/101 = 50
50   Since the face value is not given, it can be taken as Rs.100. So, dividend per share= Rs.5   Income = 50 × 5 = Rs.250   Sale Price of the stock = 101-2= 
101-2 = 99
99   Amount received by selling the stock= 50 × 99 = 4950   Then he invests this Rs.4950 in 8% stock at 88   Purchase price of this stock = 88+2= 
88+2 = 90
90   Number of stocks purchased in this case= 4950/90= 
4950/90 = 55
55   Since the face value is not given, it can be taken as Rs.100. So, dividend per share= Rs.8   Income = 55 × 8 = Rs.440   Change in income = 440-250 = Rs.190   Answer is 190.
Answer: E
There are 24 students in Chadâ€™s class. He brought 30 cookies to pass out
for his birthday. How many cookies will each student get? Will there be
any cookies left over?	Choose one:
A) 1-9  B) 1-7  C) 2-8  D) 1-6  E) 3-10

Solution: 30/24 = 1 R 6 Chad will give each student 1 cookie and there will be 6   cookies left over   correct answer 1-6
Answer: D
The cost of one photocopy is $0.02. However, a 25% discount is offered on orders of more than 100 photocopies. If Steve and Dinley have to make 80 copies each, how much will each of them save if they submit a single order of 160 copies?  Choose the correct option:
A) $0.32  B) $0.40  C) $0.45  D) $0.48  E) $0.54

Solution: If Steve and Dinley submit separate orders, each would be smaller than 100 photocopies, so no discount. Each would pay (80)*($0.02) = $1.60, or together, a cost of $3.20 --- that's the combinedno discount cost.   If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer  (80)*( 0.02)= 
 (80)*( 0.02) = 1.6
$1.60, or together, a cost of $3.20 --- that's the combinedno discount cost.   If they submit things together as one big order, they get a discount off of that $3.20 price ---- 25% or 1/4 of that is $0.80, the discount on the combined sale. They each effective save half that amount, or $0.40. Answer=($0.40).
Answer: B
3log3(-5) = ?  Answers
A) 1 B) undentified C) 3 D) 7 E) 5

Solution: Since -5 is not in the domain of function log3(x),   3log3(-5) is undefined   correct answer undentified
Answer: B
Of the five numbers in a sequence, the first term is 5,000, and each of the following terms is 20% of the previous term. What is the value range of the five numbers?  Pick.
A) 4,992
B) 9,750
C) 9,975
D) 9,984
E) 10,736

Solution: 1st number= 5,000   2nd number = 20% of 5,000= 1000   3rd number= 20% of 1000= 200   4th number = 20% of 200= 40   5th number= 20% of 40= 8   Range = 5,000-8= 4992   4,992 is the answer
Answer: A
In the first week of last month, Company X realized an average wholesale profit of $4284 per day from the sale of q units of Product Y. Which of the following CANNOT be the difference between Product Y’s sale price and cost per unit?  Choose the correct choice from the following answers:
A) $3 B) $4 C) $7 D) $13 E) $51

Solution: The key operator that everyone seems to have missed is the average. The average profit of $4284 per day is equivalent to a total profit of $29988 for the whole week.   Therefore, the difference between sale price and cost per unit is equal to $29988, which is divisible by all of the answer choices, except for 13.   So, $13 is the answer.
Answer: D
What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%?
Select:
A) 20% B) 29% C) 10% D) 80% E) 90%

Solution: SP2 = 2/3 SP1   CP = 100   SP2 = 80   2/3 SP1 = 80   SP1 = 120   100 --- 20 => 20%   20%nswer: 20%
Answer: A
Three models (S, T, and P) of cars are distributed among three showrooms. The number of cars in each showrooms must be equal and each model must be represented by at least one car in every showroom. There are 19 cars of Model S, 17 cars of Model T, and 15 cars of Model P. What is the maximum number of cars of model S in any showroom ?  Choices.
A) 17	B) 16	C) 15	D) 14	E) 13

Solution: The total number of cars is 51. So each showroom has 17 cars(since the number of cars in each showrooms should be equal   51/3= 
  51/3 = 17
17).   Moreover that the number of model S is maximum means that the numbers of model T and P should be minimum. Since each model must be represented by at least one car in every showroom that minimum number should be 1.   So Maximum number of model S is   17-2= 
  17-2 = 15
15.   The answer is (15)
Answer: C
A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 950 grams. Find the profit percent.  Choose the correct choice from the following choices.
A) 100/17%  B) 100/23%  C) 100/19%  D) 100/13%  E) None of these

Solution: Explanation:   (100 + g) / (100 + x) = True measure / Faulty measure   x = 0   true measure = 1000   faulty measure = 950   100 + g / 100 + 0 = 1000 / 950   100+g = 20/19*100   g = 100/19 %   ANSWER: 100/19%
Answer: C
If the speed of X kilometers per second is equivalent to the speed of Y kilometers per hour, what is Y in terms of X? (1 kilometer=1000 meters)
Options.
A) 15x/18  B) 6x/5  C) 18x/5  D) 60x  E) 3600000x

Solution: x=y/3600   y = 3600x   Answer : 60x
Answer: D
A walks around a circular field at the rate of one round per hour while B runs around it at the rate of six rounds per hour. They start in the same direction from the same point at 7.30 a.m. They shall first cross each other at?
Choose the correct option:
A) 12	B) 66	C) 77	D) 81	E) 71

Solution: Since A and B move in the same direction along the circle, so they will first meet each other when there is a difference of one round between the two.   Relative speed of A and B = 6 - 1= 
6 - 1 = 5
5 rounds per hour.   Time taken to complete one round at this speed= 1/5 hr = 12 min.   12nswer: 12
Answer: A
In an examination, 300 students appeared. Out of these students; 27 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.  Answers
A) 33 B) 57 C) 54 D) 99 E) 01

Solution: The number of students with first division = 27 % of 300 = 27/100 × 300 = 8100/100= 
8100/100 = 81
81   And, the number of students with second division= 54 % of 300   = 54/100 × 300   =16200/100= 
16200/100 = 162
162   Therefore, the number of students who just passed= 300 – (81 + 162) = 57   Answer:57
Answer: B
If grapes are 93% water and raisins are 16% water, then how many kilograms did a quantity of raisins, which currently weighs 8 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) Choices: A) 92 B) 96 C) 100 D) 104 E) 108

Solution: Let x be the original weight.   The weight of the grape pulp was 0.07x.   Since the grape pulp is 84% of the raisins, 0.07x = 0.84(8).   Then x = 12*8= 
12*8 = 96
96 kg.   The answer is 96.
Answer: B
In an examination, there are 100 questions divided into three groups A, B and C such that each group contains at least one question. Each question in group A carries 1 mark, each question in group B carries 2 marks and each question in group C carries 3 marks. It is known that the questions in group A together carry at least 60% of the total marks.
If group B contains 23 questions, then how many questions are there in Group C?  Select:	A) 1	B) 2	C) 3	D) 4	E) 5

Solution: Explanation :   Since group B contains 23 questions, the marks associated with this group are 46.   Now, check for option (1), if group (C) has one question, the marks associated with this group will be 3. Thus total marks will be 49.   total number of questions = 100, group (A) will have 76 questions, the corresponding weightage being 76 marks.   1nswer : 1
Answer: A
A person travelled from his house to office at 45km/hr and office to house at 55km/hr. Then find the average speed?  Options.
A) 49km/hr  B) 49.5km/hr  C) 50km/hr  D) 50.5km/hr  E) 51km/hr

Solution: Average speed = (2*45*55)/(45+55)= 
(2*45*55)/(45+55) = 99/2 = around 49.5
49.5km/hrAnswer is 49.5km/hr
Answer: B
Five years ago the average of the ages of A and B was 40 years and now the average of the ages of B and C is 48 years. What will be the age of the B ten years hence? Choose the correct choice:
A) 22
B) 77
C) 26
D) 96
E) 51

Solution: Let the present ages of A, B and C be a, b and c respectively.   Given, [(a - 5) + (b - 5)] / 2 = 40 => a + b = 90 --- (1)   (b + c)/2 = 48 => b + c = 96 --- (2)   From (1) and (2), we cannot find b.   Answer: 96
Answer: D
Alok ordered 16 chapatis, 5 plates of rice, 7 plates of mixed vegetable and 5 ice-cream cups. The cost of each chapati is Rs.6, that of each plate of rice is Rs.45 and that of mixed vegetable is Rs.70. The amount that Alok paid the cashier was Rs.961. Find the cost of each ice-cream cup?  Choose the correct choice from the following choices
A) 25  B) 30  C) 29  D) 12  E) 20

Solution: Explanation:   Let the cost of each ice-cream cup be Rs.x   16(6) + 5(45) + 7(70) + 6(x) = 961   96 + 225 + 490 + 5x = 961   5x = 150 => x = 30.   Answer:30
Answer: B
Working alone at its constant rate, pump P pumped out ¼ of the water in a tank in 2 hours. Then pumps Q and R started working and the three pumps, working simultaneously at their respective constant rates, pumped out the rest of the water in 3 hours. If pump Q, working alone at its constant rate, would have taken 18 hours to pump out the rest of the water, how many hours would it have taken pump R, working alone at its constant rate, to pump out all of the water that was pumped out of the tank?	Choices
A) 6	B) 12	C) 15	D) 18	E) 24

Solution: Rate of pump P = 1/8   3 hours are required to pump out the remaining (3/4)ths of tank --> 1 hr to pump out 1/4   Rate of P + Rate of Q + Rate of R = 1/4   Rate of Q + Rate of R = 1/4 - 1/8 = 1/8   Q takes 18 hours to pump out the remaining (3/4)ths of tank --> 6 hrs per (1/4)ths --> 24 hrs to pump out fully.   Rate of Q = 1/24   1/24 + Rate of R = 1/8   Rate of R = 1/8 - 1/24 = 1/12   Time required to pump out all the water by R = 12 hrs   Answer: 12
Answer: B
A and B together can do a work in 4 days. If A alone can do it in 14 days. In how many days can B alone do it?
Choose the correct choice from the following options:  A) 10  B) 6  C) 77  D) 55  E) 21

Solution: 1/4 – 1/12 = 1/6   => 6   Answer: 6
Answer: B
Jane covered a distance of 310 miles between city A and city B taking a total of 5 hours. If part of the distance was covered at 60 miles per hour speed and the balance at 80 miles per hour speed, how many hours did she travel at 60 miles per hour?  Choose the correct choice:	A) 2 hours 30 minutes	B) 3 hours	C) 2 hours	D) 1 hour 30 minutes	E) None of these

Solution: Answer   Let Jane travel 'x' at 60 miles per hour.   As the total time taken to cover 340 miles is 5 hours, Jane would have traveled (5 - x) hours at 80 miles per hour.   Distance covered at 60 miles per hour = Speed * time = 60 * x = 60x miles.   Distance covered at 80 miles per hour = Speed * time = 80 (5 - x) = 400 - 80x miles.   Total distance covered = Distance covered at 60 miles per hour + Distance covered at 80 miles per hour.   Therefore, total distance = 60x + 400 - 80x.   Total distance travelled = 340 miles.   Therefore, 310 = 60x + 400 - 80x   20x = 30 or x = 1 hours 30 minutes.   Choice 1 hour 30 minutes
Answer: D
How many 4 letter words are formed using the letters of the word ORIGINAL ?	Choose the correct choice from the following answers:
A) 1290	B) 1680	C) 1780	D) 1490	E) 1260

Solution: The number of letters in the given word is 4   The number of 4 letter words that can be formed using these four letters is 8P4=8*7*6*5= 
8*7*6*5 = 1_680
1680   Answer:1680
Answer: B
From given equation find the value of x: 2x² + 9x − 5 Choose one.
A) 1/2 B) 1 C) 1 1/2 D) 1 1/3 E) 2

Solution: That quadratic is factored as follows:   2x² + 9x − 5 = (2x − 1)(x + 5).   Lesson 17.   Now, it is easy to see that the second factor will be 0 when x = −5.   As for the value of x that will make   2x − 1 = 0,   we must solve that little equation. (Lesson 9.)   We have:   2x = 1   x = 1   2   The solutions are:   x = 1/2 or −5   1/2
Answer: A
The profit earned alters selling an article for ₹ 996 is the same as loss incurred after selling the article for ₹ 894. What is the cost price of the article?
Choose the correct choice from the following.
A) 22 B) 878 C) 87 D) 77 E) 91

Solution: Answer:91
Answer: E
By selling 95 pens, a trader gains the cost of 19 pens. Find his gain percentage?	Select:
A) 20%
B) 21%
C) 22%
D) 23%
E) 24%

Solution: Let the CP of each pen be Rs. 1.   CP of 95 pens = Rs. 95   Profit = Cost of 19 pens = Rs. 19   Profit% = 19/95 * 100= 
19/95 * 100 = 20
20%   20%nswer:20%
Answer: A
A train running at the speed of 54 km/hr crosses a pole in 9 seconds. Find the length of the train?
Choose the correct choice from the following options.
A) 150 meter  B) 299 meter  C) 135 meter  D) 155 meter  E) 144 meter

Solution: Speed = 54*(5/18) m/sec = 15 m/sec   Length of Train (Distance) = Speed * Time     (15) * 9= 
  (15) * 9 = 135
135 meter   Answer: 135 meter
Answer: C
Last year vivek saved 10% of his annual earnings, this year he earned 5% more than last year and he saved 12% of his annual earnings. The amount saved this year was what percentage of the amount saved last year?	Choose the correct answer
A) 124%
B) 126%
C) 128%
D) 122%
E) 1005

Solution: suppose total earning 10000   10% saving=1000   this yr 5% more income than prev yr=10500   12% saving = 1260   percentage of amount saved = (1260/1000)*100= 
(1260/1000)*100 = 126
126%   ANSWER:126%
Answer: B
The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles?  Choose one
A) 4372 sq m	B) 4317 sq m	C) 4312 sq m	D) 4372 sq m	E) 4712 sq m

Solution: Let the radii of the smaller and the larger circles be s m and l m respectively.   2∏s = 264 and 2∏l = 352   s = 264/2∏ and l = 352/2∏   Difference between the areas = ∏l2 - ∏s2   = ∏{1762/∏2 - 1322/∏2}   = 1762/∏ - 1322/∏   = (176 - 132)(176 + 132)/∏   = (44)(308)/(22/7) = (2)(308)(7) = 4312 sq m   Answer:4312 sq m
Answer: C
A man has Rs. 240 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?	Answers.
A) 37
B) 38
C) 22
D) 45
E) 28

Solution: Let number of notes of each denomination be x.   Then, x + 5x + 10x = 240 16x = 240 x = 15.   Hence, total number of notes = 3x = 45.   Answer:45
Answer: D
Twenty four men can do a work in 32 days. How many men are required to complete the work in 12 days?  Choose the correct choice: A) 32 B) 10 C) 64 D) 40 E) 60

Solution: C   64   We have M1 D1 = M2 D2   So, 24 * 32 = M2 * 12 => M2 = 64.   Answer is 64
Answer: C
Nowhere in the passage it is mentioned that they are of lackadaisical (means – arrogant, apathetic, careless etc.,) or selfish; nor they have any authority, whatsoever. If they really have bureaucratic authority, they would not be middle class people.	Pick
A) 27
B) 29
C) 77
D) 16
E) 11

Solution: 27nswer:	27
Answer: A
$1200 is invested at a given interest rate for two years. The difference between the simple 2-year non-compounded return at the end of the two years and an annually compounded return is $132. What is the interest rate?
Pick
A) 10%
B) 11%
C) 12%
D) 13%
E) 14%

Solution: For first year there will not be any difference in interest accrued using either Non-compounded or compounded rate. This means that the difference that has accrued must be the result of one year simple interest rate.   Option A will give 120   Option 11% will give 132 - Our Answer   Answer 11%
Answer: B
What is x if x + 2y = 10 and y = 3?  Pick one.
A) 1 B) 2 C) 3 D) 4 E) 5

Solution: Substitute y by 3 in x + 2y = 10   x + 2(3) = 10   x + 6 = 10   If we substitute x by 4 in x + 6 = 10, we have 4 + 6= 
4 + 6 = 10
10. Hence   x= 4   correct answer 4
Answer: D
If a and b are positive integers such that a/b = 3.42, which of the following must be a divisor of a Choose the correct choice from the following answers.
A) 57 B) 32 C) 45 D) 26 E) 20

Solution: a/b = 3.42   a/b = 342/100   a/b = 171/50   a = 171/50*b   We require to find from the available 5 options that must be a divisor of a"   This also means which of the following 5 options can divide 171 evenly   (Ignore b as its value unknown; Ignore 50 as in denominator)   Only option 57 = 57 best fits in   57nswer = 57   57NSWER:57
Answer: A