MU-NLPC/Calc-aqua_rat huggingface dataset:
Anthony and Michael sit on the six member board od directors for compnay X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?
Pick one
A) 20%	B) 30%	C) 40%	D) 50%	E) 60%

Solution: First approach:   Let's take the group with Michael: there is a place for two other members and one of them should be taken by Anthony, as there are total of 5 people left, hence there is probability of 2/5=40%.   Second approach:   Again in Michael's group 2 places are left, # of selections of 2 out of 5 5C2=10 - total # of outcomes.   Select Anthony - 1C1=1, select any third member out of 4 - 4C1=4, total # =1C1*4C1=4 - total # of winning outcomes.   P=# of winning outcomes/# of outcomes=4/10=40%   Third approach:   Michael's group:   Select Anthony as a second member out of 5 - 1/5 and any other as a third one out of 4 left 4/4, total=1/5*4/4=1/5;   Select any member but Anthony as second member out of 5 - 4/5 and Anthony as a third out of 4 left 1/4, total=4/5*1/4=1/5;   Sum=1/5+1/5=2/5=40%   Fourth approach:   Total # of splitting group of 6 into two groups of 3: 640%3*340%3/2!=10   # of groups with Michael and Anthony: 140%1*140%1*440%1=4   P=4/10=40%   Answer: 40%.
Answer: C
A man decides to buy a nice horse. He pays $60 for it, and he is very content with the strong animal. After a year, the value of the horse has increased to $70 and he decides to sell the horse. But already a few days later he regrets his decision to sell the beautiful horse, and he buys it again. Unfortunately he has to pay $80 to get it back, so he loses $10. After another year of owning the horse, he finally decides to sell the horse for $90. What is the overall profit the man makes?
Choose the correct choice from the following.
A) 20 profit B) 10 profit C) 25 profit D) 30 profit E) 28 profit

Solution: 70-60= 
70-60 = 10
10 profit    90-80= 
 90-80 = 10
10 profit   ---------------------   Total=20 profit   20 profitNSWER:20 profit
Answer: A
When throwing 2 dices, and looking at the sum of numbers on the dices - what is the probability to have a sum which is smaller than 5?	Pick
A) 1/9 B) 1/6 C) 1/2 D) 1/3 E) 32/36

Solution: a dice is composed of 6 numbers - 1,2,3,4,5,6.   When trowing 2 dices - there are 36 options (6X6=36).   If we want the sum of two dices to be< 5 there are those options: (1,1), (1,2), (2,1), (1,3), (3,1), (2,2) - total of 6 options.   Therefore - the probability to have a sum which is smaller than 5 is 6/36=1/6.   Answer:1/6
Answer: B
Anup start a bike at 6am. and rides it at 60kmph. Raghu started at 7pm with his car at 80kmph. When will Raghu overtake Anup?
Choose the correct choice from the following answers
A) 8:30am  B) 9:40am  C) 10:00am  D) 12:00pm  E) 11:10am

Solution: Suppose bike is overtaken by car xhrs after 6am   Distance covered by the bike in x hrs = distance covered by the car in x-1 hr   60x = 80(x-1)   20x = 80   x = 4 hrs   Required time = 6+4= 
6+4 = 10
10:00am   Answer is 10:00am
Answer: C
Sandy invested a certain sum of money at 8% p.a. simple interest for 'n' years. At the end of 'n' years, Sandy got back 2 times the original investment. What is the value of n?
Choose the correct choice from the following options
A) 12.5	B) 18.5	C) 24.5	D) 30.5	E) 36.5

Solution: n* 0.08 * principal + principal = 2 * principal   n * 0.08 = 1   n = 12.5 years   The answer is 12.5.
Answer: A
When two dice are rolled, what is the probability that the sum of the two numbers is 8?	Choose the correct choice from the following choices
A) 1/9 B) 2/9 C) 1/3 D) 2/3 E) None of the above

Solution: We have 5 outcomes that satisfy the question:   2-6   3-5   4-4   5-3   6-2.   the probability is (1/6*1/6)*5= 5/36.   I think the answer is None of the above
Answer: E
If a taxi driver charges x cents for the first quarter-mile of a trip and (x/5) cents for each additional quarter-mile, what is the charge, in cents, for a trip whose distance in miles is the whole number y?  Choose the most appropriate option.
A) (x+xy)/125  B) (4x + 4xy)/5  C) (4x+xy)/500  D) (4x+xy)/5  E) xy/25

Solution: let Y be 1 mile   x= 20 cents   as per given info   in 1 mile we have 4 quarter mile   so for the first mile x=20 cents and x/5 cents =20/5= 
20/5 = 4
4 cents for every additional quarter mile   so total=20+4+4+4= 
20+4+4+4 = 32
32 cents charge for complete ride.   we just substitute our values in the given options and we get our ans (4x + 4xy)/5.
Answer: B
A man sells an article at a gain 15%. If he had bought it at 10% less and sold it for 8 less, he would have gained 25%. Find the cost price of the article.
Options
A) 150	B) 160	C) 170	D) 180	E) 320

Solution: Let the C.P. be 100   First S.P. = 115   Second C.P. = 90   Second S.P = 125% of 90 = 112.50   Difference of two selling prices is 115 – 112.50 = 2.50 and C.P. of the article is 100   But actual difference is 8.   ∴ C.P. = 100⁄2.50 × 8 = 320.   Answer 320
Answer: E
It is known that no more than 4 children will be attending a party. What is the smallest number of cookies that must be brought to the party so that each child receives the same number of cookies?	Choose the correct answer
A) 35	B) 105	C) 12	D) 210	E) 420

Solution: The question states that there are no more than 4 children in the party. Thus, the possibility is that there could be 1, 2, 3 or 4 children.   If you assume answer as 35 and there are 3 children, you may not distribute be able to distribute cookies equally.   similarly if there were 105 cookies, and 2 children, cookies cannot be distributed equally.   or if there were 210 cookies, and 4 children, cookies cannot be distributed equally.   Thus, the question asks for a number of cookies which can be distributed to any number of children (from 1 to 4).   And therefore the smallest number of cookies would be lcm of (1, 2, 3, 4), i.e.,12   Answer (12)
Answer: C
The average marks obtained by 120 cndidates in a certainexaminationis 35.if the average marks of passed candidate is 39 and that of the failedcandidates is 15,what is the number of candidates who passed the examination  Pick one:
A) 14 years B) 14 years 5 month C) 14 years 8 month D) 15 years 1 month E) 15 years 8 month

Solution: (d) Let No. of passed candidates are x   So, x * 39 + (120 – x) 15= 120 * 35   x = 100   2.(a) Total increase = 8 * 2= 
8 * 2 = 16
16 years   So, total age of two women= 35 + 45 +16= 
35 + 45 +16 = 96
96   Average age of two women=96/2= 
96/2 = 48
48 years   3(d) Total decrease= 20 * 2= 
20 * 2 = 40
40 month= 3 years 4 month   So, age of new boy = 18 years – 3 years 4 month   = 14 years 8 month   14 years 8 month
Answer: C
What is the smallest integer X such that 2X+2 is divisible by 33, 44, 55, and 666?  Choose the correct option
A) X = 53186760  B) X = 26593379  C) X = 73260  D) X = 36629  E) X = 6666

Solution: 33 = 3 * 11   44 = 2 * 2 * 11   55 = 5 * 11   666 = 2 * 3 * 3 * 37   So 2X+2 = 2 * 2 * 3 * 3 * 5 * 11 * 37= 
2 * 2 * 3 * 3 * 5 * 11 * 37 = 73_260
73260, and X= (73260 - 2)/2= 
(73260 - 2)/2 = 36_629
36629, which is option X= 36629.
Answer: D
The area of a rectangular plot is 15 times its breadth. If the difference between the length and the breadth is 10 metres, what is its breadth? Choose the correct choice from the following choices
A) 10 metres B) 5 metres C) 7.5 metres D) Data inadequate E) None of these

Solution: L × 5 metres = 15 × 5 metres   ∴ L = 15 m   and L – 5 metres = 10   ∴ 5 metres = 15 – 10 = 5 m   Answer 5 metres
Answer: B
Given that x = 2^b – (8^35 + 16^5), which of the following values for b yields the lowest value for |x|?
Choose the correct choice.
A) 104
B) 105
C) 106
D) 107
E) 125

Solution: 8^35 + 16^5 = 2^105 + 2^20   Compared to 2^105, the value of 2^20 is negligible.   2^105 - (2^105 +2^20) will minimize the value of |x|.   The answer is 105.
Answer: B
For any real number x, the operatoris defined as:
(x) = x(2 − x)
If p + 1 =(p + 1), then p =	Choose the correct option.
A) -2 B) 0 C) 1 D) 2 E) 3

Solution: (x) = x(2 − x)   (p + 1) = (p + 1)(2 - p - 1) = (1-p)(p+1)   We are given that p + 1 =(p + 1)   Therefore (1-p)(p+1) = (p + 1)   Or (p + 1) + (p-1)(p+1) = 0   (p + 1)(p - 1) = 0   p = -1,p=1   Option 1
Answer: C
There are 6 working days in a regular week and for each day, the working hours are 10. A man earns Rs. 2.10 per hour for regular work and Rs. 4.20 per hour for overtime. If he earns Rs.525 in 4 weeks, how many hours did he work?	Choose one
A) 225
B) 235
C) 215
D) 255
E) 245

Solution: egular working hours in 4 weeks = (4 × 6 × 10) = 240 hours   Amount earned by working in these regular working hours   = 240 × 2.10 = Rs.504   Additional amount he earned = 525 - 504 = Rs.21   Hours he worked overtime = 21/4.2 = 210/42= 
210/42 = 5
5 hours   Total hours he worked= 240 + 5= 
240 + 5 = 245
245 hours   Answer is 245.
Answer: E
In the Hillside summer camp there are 50 children. 80% of the children are boys and the rest are girls. The camp administrator decided to make the number of girls only 10% of the total number of children in the camp. How many more boys must she bring to make that happen?  Choose the correct choice from the following:
A) 55
B) 50
C) 40.
D) 30.
E) 25.

Solution: Given there are 50 students , 80% of 50 = 40 boys and remaining 10 girls.   Now here 80% are Boys and 20% are Girls.   Now question is asking about how many boys do we need to add, to make the girls percentage to 20 or 20%..   If we add 50 to existing 40 then the count will be 90 and the girls number will be 10 as it.   Now boys are 90% and girls are 10%. ( out of 100 students = 90 boys + 10 girls ).   IMO option 50 is correct.
Answer: B
12 men complete a work in 9 days. After they have worked for 6 days, 6 more men join them. How many days will they take to complete the remaining work?  Choose the correct choice from the following:  A) 2  B) 3  C) 4  D) 5  E) 6

Solution: 1 man's 1 day work = 1/108   12 men's 6 day's work = 1/9 * 6 = 2/3   Remaining work = 1 - 2/3 = 1/3   18 men's 1 day work = 1/108 * 18 = 1/6   1/6 work is done by them in 1 day.   1/3 work is done by them in  6 * 1/3= 
 6 * 1/3 = 2
2 days.   2nswer: 2
Answer: A
If |p+q|=|p-q|, then p*q must be equal to:	Pick one.
A) 0 B) -2 C) -1 D) 1 E) 1

Solution: Solution 1: Distance perspective   |p-q| = |p+q| ==> The distance of p and q is equal to the distance of p and -q.   <=======(-q)=======0=======(q)======>   Only 0 is the value that has a distance equal to q and -q.   Solution 2:   |p-q| = |p+q| (square both)   p^2 -2pq + q^2 = p^2 + 2pq + q^2   4pq = 0   pq = 0   0nswer: 0
Answer: A
In what time a sum of money double itself at 7% per annum simple interest?  Pick:
A) 33 1/8%
B) 33 1/3%
C) 14 2/7%
D) 32 1/3%
E) 23 1/3%

Solution: P = (P*7*R)/100   R = 14 2/7%   Answer: 14 2/7%
Answer: C
Franklin has s pairs of shoes, which is 1/5 as many as Bailey and twice as many as Smith. In terms of s, how many pairs of shoes do the three of them have combined? Answers:
A) 7/2*s
B) 2s
C) 13/2*s
D) 4s
E) 15/2*s

Solution: == s +5s + s/2 ==> 6s + 1/2 s = 13/2*s   Ans .13/2*s
Answer: C
On 3,000 invested at a simple interest rate 6 p.c.p.a, 900 is obtained as interest in certain years. In order to earn 1,600 as interest on 4,000 in the same number of years, what should be the rate of simple interest?
Choose the correct choice from the following choices
A) 7 p.c.p.a. B) 8 p.c.p.a. C) 9 p.c.p.a. D) Data inadequate E) None of these

Solution: Time = 900×100/3000×6 = 5 years   Rate = 1600×100/5×4000 = 8%   Answer 8 p.c.p.a.
Answer: B
Mukesh borrowed a sum of Rs. 10000 at simple interest from a bank. After two years he takes Rs. 12000 more as loan and discharge all the debt at the end of next 3 years depositing Rs. 27160 to the bank. What is the rate of interest per annum?
Choose the correct choice from the following options
A) 5% B) 6% C) 8% D) 10% E) None of these

Solution: si=27160-(principal amount)=27160-22000= 
27160-22000 = 5_160
5160.   now,(10000*5*R/100) + (12000*3*R/100)=5160.   500R+360R=5160.....Rate=6%.   ANSWER:6%
Answer: B
The speeds of three asteroids were compared. Asteroids X-13 and Y-14 were observed for identical durations, while asteroid Z-15 was observed for 2 seconds longer. During its period of observation, asteroid Y-14 traveled three times the distance X-13 traveled, and therefore Y-14 was found to be faster than X-13 by 4000 kilometers per second. Asteroid Z-15 had an identical speed as that of X-13, but because Z-15 was observed for a longer period, it traveled five times the distance X-13 traveled during X-13's inspection. Asteroid X-13 traveled how many kilometers during its observation?  Options
A) 500	B) 1,600/3	C) 1,000	D) 1,500	E) 2,500

Solution: ST+2S = 5ST   T+2 = 5T   2=4T   t= 1/2   We are looking for distance (d=s*t) so we need to solve for speed now that we have time.   Speed y14 - speed x13   Speed = d/t   3d/t - d/t = 4000 (remember, t is the same because both asteroids were observed for the same amount of time)   2d = 4000   2 = 2000   d=s*t   d=2000*(1/2)= 
2000*(1/2) = 1_000
1000   ANSWER: 1,000
Answer: C
Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 8 as quotient and the 15 as remainder  Options:  A) 1235  B) 1557.9  C) 1378  D) 1635  E) 1489

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1365 = 8x + 15   7x = 1350   x = 192.9   Large number = 192.9+1365= 
192.9+1365 = 1_557.9
1557.9   1557.9
Answer: B
Indu gave Bindu Rs.5000 on compound interest for 2 years at 4% per annum. How much loss would Indu has suffered had she given it to Bindu for 2 years at 4% per annum simple interest? Choose the correct choice from the following options.
A) 1	B) 2	C) 7	D) 4	E) 8

Solution: 5000 = D(100/4)2   D = 8   Answer:8
Answer: E
Four staff members at a certain company worked on a project. The amounts of time that the four staff members worked on the project were in the ratio 2 to 3 to 5 to 6. If one of the four staff members worked on the project for 15 hours, which of the following CANNOT be the total number of hours that the four staff members worked on the project?	Answers
A) 120 B) 80 C) 48 D) 192 E) 40

Solution: Four members worked in ration 2:3:5:6, hence as everyone mentioned, individual work could be taken as 2x, 3x,5x, and 6x. Also this gives us total work as 16x.   But we are told that one of these individual works is 15hrs. hence, possible scenarios, if   (1)2x =15 => 16x = 120 (2) 3x =15 => 16x = 80 (3) 5x =15 => 16x = 48 (4) 6x =15 => 16x = 40   Hence Answer is 192 192 which can not be any of these.
Answer: D
Anil and suresh started a business with Rs.50,000 and 40,000 respectively. After 6 months Rakesh joined them with capital of Rs.60,000 They got a profit of Rs.6000, then profit of Rakesh is Select the correct option:
A) Rs.1500
B) Rs.3000
C) Rs.2000
D) Rs.1000
E) Rs.4000

Solution: Ratio of investments of Anil, Suresh & Rakesh=(50000*12) : (40000*12) : (60000*6)=5 : 4 : 3   Profit of Rakesh in Rs. 6000 = 3*6000/(5+4+3)= 
3*6000/(5+4+3) = 1_500
1500   Rs.1500NSWER:Rs.1500
Answer: A
A jogger running at 9 km/hr along side a railway track is 240 m ahead of the engine of a 100 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger?  Select:	A) 28 sec	B) 16 sec	C) 34 sec	D) 18 sec	E) 17 sec

Solution: Speed of train relative to jogger = 45 - 9= 
45 - 9 = 36
36 km/hr.= 36 * 5/18= 
36 * 5/18 = 10
10 m/sec.   Distance to be covered= 240 + 100= 
240 + 100 = 340
340 m.   Time taken= 340/10= 
340/10 = 34
34 sec.   Answer:34 sec
Answer: C
The percentage increase in the area of a rectangle, if each of its sides is increased by 20%	Choose the correct choice from the following answers.
A) 33  B) 37  C) 44  D) 99  E) 277

Solution: Explanation:   Let original length = x metres and original breadth = y metres.   Original area = xy   Increased length = and Increased breadth =   New area =   The difference between the Original area and New area is:   Increase % == 44%]   Answer: 44) 44%
Answer: C
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.	Select the correct option
A) 20/61	B) 20/63	C) 20/62	D) 20/87	E) 20/18

Solution: Required probability   = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126   = 20/63   Answer: 20/63
Answer: B
The telephone company wants to add an area code composed of 2 letters to every phone number. In order to do so, the company chose a special sign language containing 224 different signs. If the company used 222 of the signs fully and two remained unused, how many additional area codes can be created if the company uses all 224 signs?	Choose one
A) 246  B) 248  C) 892  D) 15,128  E) 20,256

Solution: # of 2-letter codes possible from 224 different signs = 224*224.   # of 2-letter codes possible from 222 different signs = 222*222.   The difference= 224^2 - 222^2 = (224 - 222)(224 + 222) = 892.   Answer: 892.
Answer: C
How many different positive integers exist between 10^4 and 10^5, the sum of whose digits is equal to 2?	Choose the correct choice from the following choices:
A) 3
B) 4
C) 5
D) 6
E) 7

Solution: 10001   10010   10100   11000   20000   TOTAL NO. =5   5
Answer: C
Molly's age in 18 years will be six times her age seven years ago. What is Molly's present age?
Choose the most appropriate option
A) 8  B) 9  C) 10  D) 12  E) 15

Solution: Let x be Molly's present age.   x + 18 = 6(x-7)   x = 12   The answer is 12.
Answer: D
Two goods trains each 125 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?  Choose the correct choice from the following choices.
A) 40 B) 12 C) 48 D) 51 E) 44

Solution: Relative speed = 45 + 30= 
45 + 30 = 75
75 km/hr.   75 * 5/18= 125/6 m/sec.   Distance covered = 125 + 125= 
125 + 125 = 250
250 m.   Required time= 250 * 6/125= 
250 * 6/125 = 12
12 sec.   Answer: Option 12
Answer: B
A car covers a certain distance at aspeed of 240 kmph in 5 hours. To cover the same distance in 1hr, it must travel at a speed of?	Answers.
A) 567 km/hr B) 678 km/hr C) 782 km/hr D) 789 km/hr E) 720 km/hr

Solution: Distance = (240 x 5) = 1200 km.   Speed = Distance/Time   Speed = 1200/(5/3) km/hr. [We can write 1 hours as 5/3 hours]   Required speed = 1200 x 3 km/hr = 720 km/hr.   5   720 km/hr
Answer: E
If (2^14)(25^S) = 5(10^m) what is the value of m ?	Choose the most appropriate option
A) 7	B) 8	C) 15	D) 16	E) 14

Solution: given   2^14 * 25^s = 5 * 10^2   => 2^14 * 5^(2s) = 2^m * 5^(m+1)   Ans 14   on comparing the power of 2 => m=14
Answer: E
How many integers between 7000 and 8000 that have distinct digits and increase from left to right ?  Pick one:
A) 30  B) 48  C) 60  D) 20  E) 100

Solution: Since the numbers must be distinct and increasing from left to right,   The only arrangements we could come-up with are:   745_ --> 4   746_ --> 3   747_ --> 2   748_ --> 1   756_ --> 3   757_ --> 2   758_ --> 1   767_ --> 2   768_ --> 1   778_ --> 1   Number of integers =20   20
Answer: D
Some of the 50% solution of acid was removed and this was replaced with an equal amount of 14% solution of acid. As a result, a 23% solution of acid was obtained. What fraction of the original solution was replaced?  Choose the correct option:  A) 1/2  B) 1/3  C) 2/3  D) 3/4  E) 4/5

Solution: Let x be the fraction of the original solution that was replaced.   0.5*(1-x)+0.14(x)=0.23   0.36x=0.27   x=3/4   The answer is 3/4.
Answer: D
What will be the output of the following code statements?
Integer a = 12, b = 45, c = 6 print (a × b / c) – c  Choose the most appropriate option
A) 65 B) 84 C) 29 D) 26 E) 81

Solution: Explanation:   Apply 84ODMAS rule   12 × 45 = 540/6-6 =90 –6 =84   Answer:84
Answer: B
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The sum of the first 51 positive even integers is 2550. What is the sum of the even integers from 100 to 200 inclusive? Pick:  A) 5,100  B) 7,650  C) 10,100  D) 15,500  E) 20,100

Solution: even numbers from 100 to 200=100/2+1= 
100/2+1 = 51
51   Sum= (200+100)x51/2=7650   So 7,650 is the ans.
Answer: B
In the list 3, 3, 4, 5, 5, 5, 5, 7, 11, 21, what fraction of the data is less than the mode?  Choose the correct choice from the following:
A) 2/9	B) 3/10	C) 2/5	D) 2/3	E) 7/9

Solution: Mode: The mode of any set is the term which has the highest frequency (Occurrence)   Highest frequent term in the set is 5 (with frequency 4) hence   Mode = 5   three terms (3, 3, 4) out of a total of 10 terms are less than mode of the set.   Fraction of set that are less than Mode of set = 3/10   Answer: Option 3/10
Answer: B
On a game show, there are three tables. Each table has three boxes (one Zonk!, one cash prize, and one Grand Prize). The contestant can choose one box from each table for a total of three boxes. If any of the boxes are a Zonk!, the contestant loses everything. What is the probability of getting NO Zonk! from any of the three boxes chosen?	Pick one:  A) 1/5  B) 1/3  C) 8/27  D) 1/27  E) 7/8

Solution: NO Zonk!:   1st box = No Zonk! = 2/3   2nd box = NO Zonk! = 2/3   3rd box = No Zonk! = 2/3   (2/3)(2/3)(2/3) = 8/27   8/27 is the probability of NO Zonk!, so...   Answer: 8/27
Answer: C
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 6 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?	Choose the correct choice from the following answers:
A) s.4529
B) s.4586
C) s.4597
D) s.4530
E) s.5436

Solution: Area of the four walls = 2h(l + b)   Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.   Total cost = 906 * 6   =Rs.5436   Answer: s.5436
Answer: E
How many total number of ways in which b distinct objects can be put into two different boxes is	Select the correct option.
A) n2
B) 2n
C) 2b
D) 3n
E) None of these

Solution: Let the two boxes be B1 and B2. There are two choices for each of the b objects. So, the total number of ways is   2 × 2 ×.....× 2 (b times ) = 2b   Answer 2b
Answer: C
What is the next number in the sequence : 13,17,25,32,37,47,58,71__?  Choose the correct choice from the following choices:  A) 78  B) 79  C) 71  D) 76  E) 73

Solution: next no. = previous + (sum of digits)   13 + (1+3)= 
13 + (1+3) = 17
17   17 + (1+7)= 
17 + (1+7) = 25
25   25 + (2+5)= 
25 + (2+5) = 32
32   32 + (3+2)= 
32 + (3+2) = 37
37   37 + (3+7)= 
37 + (3+7) = 47
47   47 + (4+7)= 
47 + (4+7) = 58
58   58 +(5+8)= 
58 +(5+8) = 71
71   71 + (7+1)= 
71 + (7+1) = 79
79   ANSWER:79
Answer: B
Simplify: (4 – 6) – (12+17+3)-(3+5) Choose the correct choice: A) -10 B) -42 C) -44 D) -41 E) 50

Solution: Solution:   (4-6)-(12+17+3)-(3+5)   =(-1)-32-8   =-1-32-8   =-33-8   -41   Answer: (-41)
Answer: D
An error 2% in excess is made while measuring the side ofa square. The % of error in the calculated area of the square is? Choose the correct choice from the following answers.
A) 4.00%	B) 4.04%	C) 4.25%	D) 4.30%	E) 4.45%

Solution: 100 cm is read as 102 cm.   A1 = (100 x 100) cm2 and A2 (102 x 102) cm2.   (A2 - A1) = [(102)2 - (100)2]   = (102 + 100) x (102 - 100)   = 404 cm2.   Percentage error = 404 x 100 % = 4.04%   100 x 100   4.04%
Answer: B
Country C imposes a two-tiered tax on imported cars: the first tier imposes a tax of 16% of the car's price up to a certain price level. If the car's price is higher than the first tier's level, the tax on the portion of the price that exceeds this value is 8%. If Ron imported a $14,000 imported car and ended up paying $1440 in taxes, what is the first tier's price level?
Choose the correct choice from the following answers.
A) $1600  B) $6000  C) $6050  D) $7050  E) $4000

Solution: Let T be the tier price, P be total price = 14000   Per the given conditions:   0.16T + 0.08(P-T) = 1440 ----> T= 8000. $4000 is the correct answer.
Answer: E
If (x+3)^2/(3x+29)=2, then the difference between the two possible values of x is: Select.
A) 8	B) 10	C) 12	D) 14	E) 16

Solution: (x+3)^2/(3x+29)=2   (x+3)^2=2(3x+29)   x^2+6x+9=6x+58   x^2-49=0   (x-7)(x+7)=0   x=7 or x=-7   The answer is 14.
Answer: D