MU-NLPC/Calc-aqua_rat huggingface dataset:
If 10 percent of national ice cream sales are for strawberry flavored ice cream, 20 percent are chocolate, and 60 percent vanilla, what fraction of of total ice cream sales are for other flavors? Choose the correct choice.
A) 4/5	B) 3/5	C) 3/10	D) 1/5	E) 1/10

Solution: 100%-(10%+20%+60%)=10% of sales are for other flavors --> 10% 100 -(10 +20 +60 )= 
100 -(10 +20 +60 ) = 10
10% of sales are for other flavors --> 10% = 10/100 --  10= 
--  10 = 10
10/100= 1/10.   Answer: 1/10.
Answer: E
If m : n = 3 : 4 and n : o = 8 : 9, then m : o is :	Answers.
A) 1 :3	B) 3 :2	C) 2 : 3	D) 1 : 2	E) 2 : 1

Solution: m/n = m/n * n/o   =3/4 * 8/9   = 2/3.   So m : o = 2 : 3   ANSWER:2 : 3
Answer: C
The average score of a cricketer for ten matches is 38.9 runs. If the average for first six matches is 42, then average for last four matches is	Choose the correct choice from the following:	A) 33.25	B) 32.25	C) 34.25	D) 34.5	E) 35.5

Solution: Explanation:   =(38.9×10)−(42×6)/4   =(1216−750)4=34.25   Answer: Option 34.25
Answer: C
A salesperson receives a base salary of $1200 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 210 items for $150 each, what will her monthly salary be?	Pick one:  A) $1,500  B) $1,800  C) $2,100  D) $2,500  E) $3,000

Solution: Ans : 1200+ 7.5 % * 150 * (210-50) = $ 3000   Answer $3,000
Answer: E
Fresh fruit contains 68% water and dry fruit contains 20% water.How much dry fruit can be obtained from 100 kg of fresh fruits ? Choose the correct choice from the following answers:
A) 30 kg
B) 40 kg
C) 50 kg
D) 60 kg
E) 70 kg

Solution: The fruit content in both the fresh fruit and dry fruit is the same.   given,fresh fruit has 68% water.so remaining 32%(100-68) is fruit content.weight of fresh fruits is 100kg   dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.   fruit % in freshfruit = fruit% in dryfruit   32/100 * 100 = 80/100 * y   we get y = 40 kg   fruit pulp = 40 kg   so with water total amount = 40*100/80= 
40*100/80 = 50
50 kg   ANSWER:50 kg
Answer: C
Of the sixteen participants in a certain competition, half are male, and half of the males are younger than 18 years of age. If half of the female competitors are also younger than 18 years of age, into how many distinct groups of 4 competitors could the participants be divided if each group must contain two males under 18 years of age and 2 females over 18 years of age? Pick
A) 3  B) 4  C) 36  D) 9  E) 20

Solution: M under 18 - 4   F above 18 - 4   How many distinct groups can be formed now: 4c2 * 4c2 = 36   Answer : 36
Answer: C
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Select the correct option.
A) 4
B) 7
C) 9
D) 13
E) 15

Solution: Solution   Required number   = H.C.F of (91 - 43), (183 - 91) and (183 - 43)   = H.C.F of 48, 92 and 140   = 4.   4nswer 4
Answer: A
The mean of 50 observations was 36. It was found later that an observation 45 was wrongly taken as 23. The corrected new mean is
Choose the correct answer
A) 35.24 B) 36.14 C) 36.24 D) 36.44 E) None

Solution: Solution   Correct sum = (36x50+45-23)   = 1822.   âˆ´ Correct mean = 1822 / 50   = 36.44.   Answer 36.44
Answer: D
If the product of the integers w, x, y and z is 68, and if 0< w < x < y < z, what is the value of w + z? Choose the correct choice from the following options
A) 10	B) 5	C) 16	D) 18	E) 21

Solution: 24= 1* 2* 3* 4   So w = 1, x = 2, y = 3, z = 4   w + z = 1+ 4= 
1+ 4 = 5
5   Answer - 5
Answer: B
A certain truck uses 18 gallons of diesel fuel in traveling 220 miles. In order for the truck to travel the same distance using 10 gallons of diesel fuel, by how many miles per gallon must the truck’s fuel mileage be increased? Choose the most appropriate option:	A) 8	B) 9	C) 12	D) 15	E) 7

Solution: There are two sets 18G1 gallons and 10G2 gallons details given.   18 gallons covering 220 miles   Then 1 G1 is used to cover 15 miles.   Now for 10 G2 covering 220 miles.   then 1 G2 is used to cover 22 miles.   There must   22 - 15= 
  22 - 15 = 7
7miles per gallon increment is needed for 10 gallons to improve the mileage to cover 220 miles.   IMO 7 is correct answer.
Answer: E
The ratio of the number of boys and girls in a school is 3:2 Out of these 10% the boys and 25% of girls are scholarship holders. % of students who are not scholarship holders.?
Choose one:
A) 84%	B) 86%	C) 88%	D) 82%	E) 74%

Solution: let the boys are 3x and girls are 2x   so,no.of boys not holding scholorship is 3x-(30x/100)=27x/10   and no.of girls not holding scholorship is 2x-(50x/100)=3x/2   the total is (27x/10)+(3x/2)=42x/10   % of students not scholorship holders are (42x/10)*100/5x=84%   84%NSWER:84%(42 /10)*100/5= 
(42 /10)*100/5 = 84
84%   84%NSWER:84%
Answer: A
In the xy-plane, the line y = k is the perpendicular bisector of the line segment PQ and the line x = b is the perpendicular bisector of the line segment RQ. If the coordinates of the point R are (-b, -k), then what are the coordinates of the point P?	Choices.
A) (-5b, -5k)
B) (-3b, -3k)
C) (2b, 2k)
D) (3b, 3k)
E) (5b, 5k)

Solution: firstly the Question tells us that RQ and PQ are perpendicular at Q..   Now the coordinates of the point R are (-b, -k), so R is at a distance of 2b from line x and at dist of 2k from line Y..   as line X bisect RQ .... length of RQ =4b and coord (3b,-k)..   as line Y bisect PQ .... length of PQ =4k and coord (3b,3k).ans (3b, 3k)
Answer: D
If x and y are positive numbers and z = xy^2, a 50 percent increase in x and a 10 percent decrease in y would result in which of the following changes in z?
Choose the correct answer: A) decrease of 4.5% B) decrease of 14.5% C) increase of 4.5% D) increase of 21.5% E) increase of 35.5%

Solution: After the changes, z = 1.5x*(0.9y)^2 = (1.5*0.81)xy^2 = 1.215*z   The answer is increase of 21.5%.
Answer: D
Can you find the next letter in the series ?
S - T - I - L - N - T - F - Y - ?
Answers:
A) A	B) B	C) C	D) D	E) E

Solution: C   The answer is C.   These are letter of the question asked in reverse order.
Answer: C
A rectangular field has a length 10 meters more than it is width. If the area of the field is 200, what is the length (in meters) of the rectangular field?  Choose the correct choice:
A) 20  B) 22  C) 24  D) 26  E) 28

Solution: area = l * w = (L) * (L-10) = 200   trial and error:    19*9= 
 19*9 = 171
171 (too low)   20*10= 
20*10 = 200
200   The length is 20 meters.   The answer is 20.
Answer: A
Mike weighs twice as much as Mary. Mike's weight is 150% of Michelle's weight. Alan weighs 40% of Charlie's weight. Charlie weighs 180% of Mary's weight. Which of these 5 people weighs the highest?
Select:
A) Mary
B) Mike
C) Michelle
D) Alan
E) Charlie

Solution: Mary < Michelle < Mike   Alan < Charlie   Let x be Mary's weight.   Mike's weight is 2x and Charlie's weight is 1.8x.   The answer is Mike.
Answer: B
One week a certain van rental lot had a total of 20 vans, all of which were on the lot Monday morning. If 50 percent of the vans that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different vans that could have been rented out during the week?  Select.
A) 16
B) 18
C) 20
D) 8
E) 4

Solution: A) 16 vans rented means 4 were left and 8 were returned - 12 vans - good   Answer is (18)
Answer: B
Roy is now 8 years older than Julia and half of that amount older than Kelly. If in 4 years, Roy will be twice as old as Julia, then in 4 years what would be Roy’s age multiplied by Kelly’s age?  Choose the correct choice from the following:	A) 172	B) 180	C) 192	D) 200	E) 216

Solution: R = J+8 = K+4   R+4 = 2(J+4)   (J+8)+4 = 2J+8   J = 4   R = 12   K = 8   In 4 years (R+4)(K+4) = 16*12= 
16*12 = 192
192   The answer is 192.
Answer: C
how many words formed ACCIDENT without changing relative order of vowels?? Pick one
A) 360  B) 370  C) 380  D) 390  E) 400

Solution: Vowels: AIE = 1, since order of vowels must not be changed, so 3! should not be multiplied.   Rest: CCDNT = here we have 5 terms, with 1 common term 'C'.   So according to me ans should be :   (5+1)!/2!   = 6!/2!   =360   360NSWER:360
Answer: A
The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 10 cm. If the area of the trapezium is 250cm2 find the lengths of the parallel side  Choose the correct answer.
A) 27, 23  B) 25, 25  C) 24, 26  D) 23, 29  E) 24, 45

Solution: Explanation:   Let the two parallel sides of the trapezium be a cm and b cm.   Then, a-b = 4 ------ (1)   And, (1/2) x (a+b) x 10 = 475 =>(a+b) =((250 x 2)/10) => a + b = 50------- (2)   Solving 1 and 2, we get: a=27,b=23   So, the two parallel sides are 27 cm and 23 cm.   27, 23nswer: Option 27, 23
Answer: A
A pump can fill a tank with water in 10 hours. Because of a leak, it took 20 hours to fill the tank. The leak can drain all the water in ? Choose the correct choice:  A) 20hr  B) 10hr  C) 30hr  D) 14hr  E) 16hr

Solution: Work done by the leak in 1 hour = 1/10 - 1/20 = 1/20   Leak will empty the tank in 20 hours   20hrnswer is 20hr
Answer: A
A and B have the same number of marbles when they start playing. After some time A gains 20 marbles and later he loses 2/3rds of what he had. Now B has 4 times as many marbles as A has. What are the initial number of marbles that each of them had?  Pick:
A) 80
B) 90
C) 100
D) 110
E) 120

Solution: 100   ANSWER:100
Answer: C
The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 6 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible?	Choose one
A) 2 B) 4 C) 12 D) 6 E) 160

Solution: Actual miles/gallon is = 480/40= 
480/40 = 12
12 miles/gallon.   Current engine miles/gallon is 6 miles/gallon.   Additional 6 miles/gallon is required to match the actual mileage.   IMO option 6.
Answer: D
How many positive integers G less than 10,000 are such that the product of their digits is 210?	Choices:
A) 24	B) 30	C) 48	D) 54	E) 72

Solution: 210 is the answer when 2, 3, 5 and 7 are multiplied. 210 can also be arrive using 5,6 and 7 and 1, 5, 6 and 7.   So sum of arrangements of 2357, 567 and 1567. This translates to 4! +3! + 4!, this equals to  24 + 6 + 24= 
 24 + 6 + 24 = 54
54, 54 is the answer.
Answer: D
With both inlets open, a water tank will be filled with water in 52 minutes. The first inlet alone would fill the tank in 2 hours. If in every minutes the second inlet admits 50 cubic meters of water than the first, what is the capacity of the tank ?
Choose the correct option:  A) 9,000  B) 10,500  C) 11,750  D) 17,500  E) 19,500

Solution: The work Done by Inlet A and B together in 1 min = 1/52   The work Done by Inlet A (First Inlet) in 1 min = 1/120   The work Done by Inlet B (Second Inlet) in 1 min = (1/52)- (1/120) = 1/92   DIfference of Work done by B and A = B - A = 50 Cubic meter   i.e. (1/92)- (1/120) = 50 Cubic meter   = 19,500 Cubic Meter   Answer: option 19,500
Answer: E
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that atleast one bulb is good.	Options.
A) 125/129 B) 125/121 C) 125/126 D) 125/122 E) 125/124

Solution: Explanation:   Required probability = 1 - 1/126 = 125/126   Answer: 125/126
Answer: C
Find the value of x. (47% of 1442 - 36% of 1412) + 60 = x?
Choices
A) 1
B) 2
C) 3
D) 4
E) 5

Solution: 1) 1
Answer: A
Julie has $2000 saved in her bank account after this summer. She made money babysitting and delivering newspapers which she added to her previous savings. Julie babysat for 30 hours at $10/hr, she delivered papers for 40 hours at $7/hr. What % of her bank account was savings she had before this summer?  Choose the correct choice from the following answers:
A) 41 %	B) 51 %	C) 61 %	D) 71 %	E) 81 %

Solution: Total amount in the bank account minus new earnings = 2000 - (10 x 30 + 7 x 40)   = 2000 - (580)= 
2000 - (580) = 1_420
1420   Now, we need to calculate 1420 is what percent of 2000.=> 1420/2000 * 100= 
1420/2000 * 100 = 71
71 %   71 %
Answer: D
Rakesh's Mathematics test had 75 problems, 10 arithmetic, 30 algebra, 35 geometry problems. Although he answered 70% of arithmetic, 40% of arithmetic and 60% of geometry problems correctly, still he got less than 60% problems right. How many more questions he would have to answer more to get passed ?	Choose the correct choice from the following answers:
A) 5
B) 6
C) 7
D) 8
E) 9

Solution: Explanation :   Number of questions attempted correctly = (70% of 10 + 40% of 30 + 60% of 35)   = 7 + 12 + 21= 
7 + 12 + 21 = 40
40.   Questions to be answered correctly for 60%= 60% of total quotations   = 60 % of 75 = 45.   He would have to answer 45 - 40= 
45 - 40 = 5
5   5nswer : 5
Answer: A
90 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors?	Options.
A) 18 B) 16 C) 12 D) 10 E) 6

Solution: {Total}={Writers}+{Editors}-{Both}+{Neither}.   {Total}=90;   {Writers}=45;   {Editors}>38;   {Both}=x;   {Neither}=2x;   90=45+{Editors}-x+2x --> x=45-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 39, thus x={Both}=45-39= 
45-39 = 6
6.   Answer: 6.
Answer: E
The ratio E, by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.  Options:
A) 79 litres
B) 78 litres
C) 77 litres
D) 152 liters
E) 304 litres

Solution: I guess it should be   the ratio E, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before   2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters   So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.   Now as per the Question, Soap : Water doubles but alcohol to water remains the same.   So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.   Hence 77 liters - Option 77 litres)
Answer: C
The relationship between quantities m and n is expressed by the equation 15m = 5(n - 42). If the difference between the two chosen values of n is 30, what is the difference in the corresponding values of m?
Choices:  A) 30/11  B) 42/11  C) 60/11  D) 150/11  E) 10

Solution: Another Simple way   15m=5(n-42)   Assume n = 42 to make one side equal to 0   then 15m=0   and m = 0   Repeat it by assuming n as 42+30 i.e 72   15m= 5(72-42)   15m=150   m=150/15= 
150/15 = 10
10 - 0= 
10 - 0 = 10
10   Answer : 10
Answer: E
A loan has a variable interest rate that fluctuates between 6% and 8% of the base payment per month. If base payments remain at $400 each month and an additional monthly surcharge of 2% is added to the combined (base + interest), what would be the greatest possible payment due in any given month?
Pick:
A) $435.32	B) $436.48	C) $438.16	D) $440.64	E) $442.32

Solution: The maximum interest in one month is 8%*$400=$32.   The combined payment (base plus interest) is $400 + $32 = $432.   The greatest possible payment is: 1.02*$432  400 +  32= 
  400 +  32 = 432
$432.   The greatest possible payment is: 1.02*$432=$440.64.   The answer is $440.64.
Answer: D
Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 54 sec. The length of each train is?	Select:
A) 50
B) 26
C) 75
D) 28
E) 21

Solution: Let the length of each train be x m.   Then, distance covered = 2x m.   Relative speed = 46 - 36= 
46 - 36 = 10
10 km/hr.= 10 * 5/18 = 25/9 m/sec.   2x/54 = 25/9 => x = 75.   Answer: 75
Answer: C
John was thrice as old as Tom 6 yrs back. He will be 5/3 times as old as Tom 6 years hence. How old is Tom today?	Choose the correct answer
A) 8 B) 10 C) 12 D) 14 E) 16

Solution: Sol. RMBflSk -6 = 3 (Ravi - 6) ...(j)   and Rupesh + 6 = | (Ravi + 6) ...(ii)   Solving both the equations we get,   Ravi = 12 years.   12
Answer: C
Which one of the following is not a prime number? Choose the correct choice from the following answers.
A) 21	B) 34	C) 67	D) 91	E) 55

Solution: D   91 is divisible by 7. So, it is not a prime number.
Answer: D
A work can be finished in 15 days by twenty women. The same work can be finished in fifteen days by sixteen men. The ratio between the capacity of a man and a woman is	Choose one.
A) 4:3
B) 3:4
C) 2:3
D) 3:2
E) 5:4

Solution: Work done by 20 women in 1 day = 1/15   Work done by 1 woman in 1 day = 1/(15Ã—20)   Work done by 16 men in 1 day = 1/15   Work done by 1 man in 1 day = 1/(15Ã—16)   Ratio of the capacity of a man and woman =1/(15Ã—16) : 1/(15Ã—20) = 1/16 : 1/20   = 1/4 :1/5 = 5:4   Answer is 5:4.
Answer: E
A honey bee flies for 10 seconds, from a daisy to a rose. It immediately continues to a poppy, flying for 6 additional seconds. The distance the bee passed, flying from the daisy to the rose is 6 meters longer than the distance it passed flying from the rose to the poppy. The bee flies to the poppy at 3 meters per second faster than her speed flying to the rose. The bee flies how many meters per second from the daisy to the rose? Choose the correct choice from the following options:
A) 3
B) 5
C) 6
D) 8
E) 10

Solution: Let the speed be 's' and let the distance between rose and poppy be 'x'   The problem boils down to:   Rose to Poppy: s+3=x/6 ------- 1   Daisy to Rose: s=(x+6)/10------ 2   so from 1 we can re write x as x=6s+18   substitute the value of x in 2 gives us s=3 m/s   3
Answer: A
There are 4 copies of 5 different pens. In how many ways can they be arranged on a shelf?	Choose the correct choice from the following:
A) 20!/4! B) 20!/5(4!) C) 20!/(4!)^5 D) 20! E) 5!

Solution: There are 4 copies of 5 different pens.20!/((4!)^5)   Answer - 20!/(4!)^5
Answer: C
The sum of the squares of the first 15 positive integers (1^2 + 2^2 + 3^2 + . . . + 15^2) is equal to 1290. What is the sum of the squares of the second 15 positive integers (16^2 + 17^2 + 18^2 + . . . + 30^2) ?  Choose the correct option.
A) 2480 B) 3490 C) 6785 D) 8265 E) 9255

Solution: You'll never need a formula for the sums of squares on the actual GMAT. You don't need to use that formula here, though it's not all that straightforward to solve without one. Two different approaches:   16^2 + 17^2 + 18^2 + ... + 30^2 = (15 + 1)^2 + (15 + 2)^2 + (15 + 3)^2 + ... + (15 + 15)^2   Now we can expand each square; they are all in the (x + y)^2 = x^2 + 2xy + y^2 pattern.   = (15^2 + 2*15 + 1^2) + (15^2 + 4*15 + 2^2) + (15^2 + 6*15 + 3^2) + ... + (15^2 + 30*15 + 15^2)   Now we have fifteen 15^2 terms, so adding these gives 15*15^2 = 15^3 = 3375. We also have the entire sum 1^2 + 2^2 + ... + 15^2, which we know is equal to 1240. Finally adding the middle terms, we have:   2*15 + 4*15 + 6*15 + ... + 30*15 = 15(2 + 4 + 6 + .... + 30) = 15*2*(1 + 2 + 3 + ... + 15) = 15*2*8*15= 
15*2*8*15 = 3_600
3600   So the sum must be  3375 + 1240 + 3600= 
 3375 + 1240 + 3600 = 8_215
8215   Alternatively, we can use a different factoring pattern. We want to find the value of 30^2 + 29^2 + ... + 17^2 + 16^2. Well if we subtract 15^2 + 14^2 + .... + 2^2 + 1^2 from this, the answer will be 1240 less than what we want to find. So if we can find the value of   30^2 + 29^2 + ... + 17^2 + 16^2 - (15^2 + 14^2 + .... + 2^2 + 1^2)   then we can add 1240 to get the answer. Now grouping the terms above to get differences of squares, we have= (30^2 - 15^2) + (29^2 - 14^2) + ... + (16^2 - 1^2)   and factoring each of these using x^2 - y^2 = (x + y)(x - y), we have   = 45*15 + 43*15 + 41*15 + ... + 17*15 = 15(45 + 43 + 41 + ... + 17)   In brackets we have an equally spaced sum with fifteen terms, which we can evaluate using the familiar formula. So the above equals     15*15*62/2= 
  15*15*62/2 = 6_975
6975   and adding back the 1290, we get the answer of 8265. (ANS 8265)
Answer: D
If,
1 * 3 * 5 = 16
3 * 5 * 7 = 38
Then find,
11 * 13 * 15 =?  Pick:
A) 89 B) 49 C) 206 D) 38 E) 55

Solution: 206   206   (15 * 13) + 11= 
(15 * 13) + 11 = 206
206
Answer: C
A, B, C subscribe Rs. 50,000 for a business, A Subscribes Rs. 4000 more than B and B Rs. 5000 more thanC. Out of a total profit of Rs. 35,000, B receives :
Choose the correct choice from the following answers:
A) 11900 B) 14703 C) 37798 D) 13777 E) 14778

Solution: Explanation:   Let C = x. Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.   So, x + x + 5000 + x + 9000 = 50000 <=> 3x = 36000 <=>   x = 12000.   A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.   B's share = Rs. (35000 * 17/50 ) = Rs. 11,900.   11900nswer: 11900)
Answer: A
On Monday morning, Chris receives tickets to a baseball game that will be played at 7pm on the next evening that it does not rain. However, Chris is only in town until Wednesday morning, at which point he must fly to another city. If there is a 60% chance of rain each of the next two evenings, what is the probability that Chris will be able to attend the game?  Choose one:
A) 64%
B) 60%
C) 66%
D) 80%
E) 84%

Solution: Chris won't be able to attend the game if it be raining on Monday eveningandTuesday evening. The probability of that is 0.6*0.6 = 0.36. So, the probability that he will be able to attend is 1 - 0.36 = 0.64.   64%nswer: 64%.
Answer: A
A chair is bought for Rs.600/- and sold at a loss of 20% find its selling price Pick one:
A) s.480/-
B) s.550/-
C) s.560/-
D) s.590/-
E) s.580/-

Solution: 100 % ------> 600 (100 * 6 = 600)   80 % ------> 540 (80 * 6 = 480)   Selling price = Rs.480/-   s.480/-)
Answer: A
A train passes a station platform in 40 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Choose the correct choice from the following options.
A) 615 m	B) 240 m	C) 180 m	D) 197 m	E) 691 m

Solution: Speed = 54 * 5/18= 
54 * 5/18 = 15
15 m/sec.   Length of the train= 15 * 20= 
15 * 20 = 300
300 m.   Let the length of the platform be x m . Then,   (x + 300)/40= 15 => x   = 180 m   Answer: 180 m
Answer: C
A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon?
Answers.
A) 120 kg in the morning and 240 kg in the afternoon
B) 100 kg in the morning and 200 kg in the afternoon
C) 110 kg in the morning and 220 kg in the afternoon
D) 130 kg in the morning and 260 kg in the afternoon
E) 125 kg in the morning and 250 kg in the afternoon

Solution: Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2xx kilograms. So, the total is x+2x=3x. This must be equal to 360.   3x=360   x=360/3= 
360/3 = 120
120   Therefore, the salesman sold 120 kg in the morning and 2x120=240 kg in the afternoon.   120 kg in the morning and 240 kg in the afternoonnswer is 120 kg in the morning and 240 kg in the afternoon
Answer: A
A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.340 less than the sum lent. What was the sum lent? Choose one:
A) 277
B) 266
C) 321
D) 500
E) 782

Solution: P - 340 = (P*4*8)/100   P = 500   Answer: 500
Answer: D
In how many ways can 3-digit numbers be formed selecting 3 digits from 1, 1, 2, 3, 4? Choose one.
A) 5P3/(2!)  B) 4P3  C) 4^3  D) 4P3+3C1*(3!/2!)  E) 60 × 3!

Solution: Had it asked for all the different nos instead of 1,1,2,3,4 the ans would be: 5P3/2! = 30   In this solution we have also halved (divided by 2!) the numbers containing 2,3 and 4.   The numbers containing 2,3,4 are 6.   Add  6/2= 
 6/2 = 3
3 back to 30 and we get the answer i.e. 30+3=33.   Hence 4P3+3C1*(3!/2!) is the answer
Answer: D