MU-NLPC/Calc-aqua_rat huggingface dataset:
Five friends go to see a movie at the local movie theater and sit in a row together. If there are two friends who refuse to sit next to each other, how many 5-person seating arrangements are possible?
Choose the correct choice from the following:
A) 72  B) 90  C) 120  D) 140  E) 180

Solution: The number of ways to arrange 5 people in a row is 5! = 120   From this we want to subtract all the arrangements where the two friends are next to each other. If we consider them as one unit, then the number of arrangements of this 2-person unit and the 3 other friends is 4! And the number of arrangements of the two friends within this unit are 2 because the two friends can switch places. So the total number of arrangements of the 5 friends with the 2-person unit together is 4!*2   The total number of permutations where these two friends are not seated next to each other is 5! - 4!*2 = 120 - 48= 
120 - 48 = 72
72   The answer is 72.
Answer: A
P software has coding line 5% more than N, N software has coding line 5/2 more than M. M software has 108 lines of coding. find P lines.  Choose the correct choice:
A) 106	B) 107	C) 397	D) 109	E) 110

Solution: M s/w has 108 line of code   N s/w has = 108+108*5/2= 
108+108*5/2 = 378
378 line of code   P s/w 5% more N' code 378+18.9= 
378+18.9 = 396.9
396.9   or   397 line of code   ANSWER:397
Answer: C
When 5 fair coins are tossed simultaneously, in how many outcomes will the first and the last coin turn up heads?  Options
A) 1
B) 3
C) 8
D) 31
E) 30

Solution: With 5 coins being tossed, you might expect this question to be more difficult than it actually is. The prompt asks for the number of outcomes in which the first and fifth coins are both heads. To start, we can 'lock in' those options.   H _ _ _ H   Now we just have to focus on the possible outcomes for the remaining 3 coins. Mathematically, since each coin has 2 possible outcomes, there are (2)(2)(2) = 8 options.   You could also 'map out' the possibilities:   HHH   HHT   HTH   THH   TTT   TTH   THT   HTT   8 total options.   Final Answer:8
Answer: C
If z is a multiple of 8902, what is the remainder when z^2 is divided by 4?
Pick one:
A) 0
B) 1
C) 2
D) 3
E) It depends on z.

Solution: 2 is a factor of 8902, so 2 is a factor of z.   Then 2^2 = 4 is a factor of z^2.   Then the remainder when z^2 is divided by 4 is 0.   The answer is 0.
Answer: A
Sunita goes 30 km towards North from a fixed point, then after turning to her right she goes 15 km. After this she goes 30 km after turning to her right. How far and in what direction is she from her starting point?
Answers.
A) 45 km, East B) 15 km, East C) 45 km, West D) 45 Km, North E) None of these

Solution: Sunita moves 15 km right after she was moving towards north. That is she walked 15 kms towards east. Then she moves 30 kms right i.e. se comes in the same direction from which she started. Hence the displacement is only 15 km and that is towards east.   ANSWER:15 km, East
Answer: B
If 4 men or 6 boys can finish a work in 20 days. How long will 6 men and 11 boys take to finish the same work?  Choose one:
A) 10 days  B) 6 days  C) 4 days  D) 3 days  E) 8 days

Solution: 4 men = 6 boys   Then, 1 boy = 4/6 men = 2/3 men   11 boys = 2/3 × 11 men = 22/3 men   Then, 6 men + 11 boys = 6 + 22/3 men = 40/3 men   1 work done = 4 men × 20days   That is, 4 × 20 = 40/3 × ? days   ? days = 4 × 20 × 3/40 = 6 days   Answer : 6 days
Answer: B
Mr. James sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:	Choose the correct choice from the following choices:
A) broke even
B) lost 4 cents
C) gained 4 cents
D) lost 10 cents
E) gained 10 cents

Solution: A   broke even   20 % profit on $ 1.20   = $ 20/100 × 1.20   = $ 0.20 × 1.20   = $ 0.24   Similarly, 20 % loss on $ 1.20   = $ 20/100 × 1.20   = $ 0.20 × 1.20   = $ 0.24   Therefore, in one pipe his profit is $ 0.24 and in the other pipe his loss is $ 0.24.   Since both profit and loss amount is same so, it’s broke even.
Answer: A
A man sitting in a train which is traveling at 40 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?	Choose the correct choice from the following.
A) 50 kmph
B) 58 kmph
C) 62 kmph
D) 65 kmph
E) 72 kmph

Solution: Relative speed = 280/9 m / sec = ((280/9)*(18/5))= 
((280/9)*(18/5)) = 112
112 kmph.   Speed of goods train= (112 - 40)= 
(112 - 40) = 72
72 kmph.   Answer : 72 kmph
Answer: E
A train travels m miles in n hours. How many miles will it travel in x hours at the same rate?
Pick one: A) mnx B) m⁄n C) mx⁄n D) mx E) mn⁄x

Solution: Given Speed = m/n   To Find distance in x hours with same speed   Distance = speed * time   Distance = m/n*x = mx/n   Answer mx⁄n
Answer: C
A tradesman by means of his false balance defrauds to the extent of 20%? in buying goods as well as by selling the goods. What percent does he gain on his outlay? Select: A) 44% B) 48% C) 94% D) 45% E) 34%

Solution: g% = 20 + 20 + (20*20)/100= 
20 + 20 + (20*20)/100 = 44
44%   44%nswer: 44%
Answer: A
If a and b are positive integers and x = 4^a and y = 3^b, which of the following is a possible units digit of xy?  Select:
A) 0  B) 1  C) 5  D) 7  E) 8

Solution: The units digit of 4^a is either 4 or 6.   The units digit of 3^b is 3, 9, 7, or 1.   We can multiply the units digits together to see that the units digits of xy could be 2, 4, 6, or 8.   The answer is 8.
Answer: E
A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.300 when the rate to profit rises from 5 to 7 percent. Find the Capital of A?
Select
A) 5000 B) 10000 C) 15000 D) 2778 E) 1991

Solution: A:B:15000 = 2/3:1/6:1/6 = 4:1:1   x * 2/100 * 2/3 = 300   A's capital = 22500*2/3= 
22500*2/3 = 15_000
15000   Answer: 15000
Answer: C
At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years?
Answers.
A) 4 %  B) 5 %  C) 6 %  D) 7 %  E) 8 %

Solution: Sol.   Let sum = x. Then, S.I. = 2x/5, Time = 10 years.   ∴ Rate = [100 * 2x / x*5*10]% = 4%.   4 %nswer 4 %
Answer: A
The calendar of the year 2028 can be used again in the year?
Choose the correct choice from the following options:
A) 2041
B) 1951
C) 2056
D) 1971
E) 1973

Solution: Explanation:   Given year 2028 when divided by 4, leaves a remainder 0.   NOTE: When remainder is 0, 28 is added to the given year to get the result.   So, 2028 + 28 = 2056   Answer: 2056
Answer: C
If the cost price of 60 articles is equal to the selling price of 50 articles, then what is the percent profit?	Choose the correct choice:	A) 10%	B) 15%	C) 20%	D) 25%	E) 30%

Solution: Let x be the cost price of one article.   Let y be the selling price of one article.   50y = 60x   y = 1.2x   The answer is 20%.
Answer: C
Tabby is training for a triathlon. She swims at a speed of 1 mile per hour. She runs at a speed of 11 miles per hour. She wants to figure out her average speed for these two events. What is the correct answer for her?	Pick one.
A) 6 mph  B) 5.25 mph  C) 3.5 mph  D) 4 mph  E) 0.5 mph

Solution: (1 mph +11 mph)/2 = 6 mph   Correct option is: 6 mph
Answer: A
The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, its area is?
Options
A) 3000 sq m B) 1878 sq m C) 2789 sq m D) 26811 sq m E) 29762 sq m

Solution: 5x + 12x + 13x = 300 => x = 10   a = 50, b = 120, c = 130   S = (50 + 120 + 130)/2= 
(50 + 120 + 130)/2 = 150
150   3000 sq m   3000 sq mnswer:3000 sq m
Answer: A
A dealer sold two of his cattle for Rs. 500 each. On one of them he lost 10% on the other, he gained 10%. His gain or loss percent in the entire transaction was: Choose the correct choice from the following answers
A) 2	B) 1	C) 7	D) 9	E) 0

Solution: Explanation:   Loss%= (common gain or loss % / 10)2 = (10/10)= 
(10/10) = 1
1%.   Answer: 1) 1% loss
Answer: B
47% of the students in a class of 34 students has glasses or contacts. How many students in the class have either glasses or contacts?
Pick:  A) 15  B) 16  C) 17  D) 18  E) 19

Solution: a=r⋅b   a=r⋅b   47%=0.47a   47%=0.47a   =0.47⋅34   =0.47⋅34   a=15.98≈16   Option 16 is correct.
Answer: B
A certain clock marks every hour by striking a number of times equal to the hour, and the time require for a stroke is exactly equal to the time interval between strokes. At 6:00 the time lapse between the beginning of the first stoke and the end of the last stroke is 22 seconds. At 7:00, how many seconds elapse between the beginning of the first stroke and the end of the last stroke?  Choose the correct choice: A) 26 B) 29 C) 19 D) 30 E) 40

Solution: at 6'o clock, there would be 6 strikes. First strike, then a short interval, the second strike, then a short interval and so on till the 6th strike. So there would be in all 5 intervals between 6 strikes. Similarly, between 7 strikes, there would be 6 intervals.   According to the question, the time spent in the strike and the interval is same.   At 6'o clock, the 6 strikes and the 5 intervals together take 22 sec so each strike and each interval takes 2 secs.   26t 7'o clock, the 7 strikes and 6 intervals will take 2*(7+6)= 
2*(7+6) = 26
26 secs   26
Answer: A
A does a work in 15 days and B does the same work in 30 days. In how many days they together will do the same work ? Pick one
A) 5 days
B) 6 days
C) 8 days
D) 10 days
E) None of these

Solution: Explanation:   Firstly we will find 1 day work of both A and B, then by adding we can get collective days for them,   So,   A's 1 day work = 1/15   B's 1 day work = 1/30   (A+B)'s 1 day work =   (1/15+1/30)=1/10   So together they can complete work in 10 days.   Answer: 10 days
Answer: D
What is theleast number should be added to 1056, so the sum of the number is completely divisible by 23?	Pick one
A) 20	B) 23	C) 25	D) 27	E) 28

Solution: (1056 / 23) gives remainder 21   21 + 2= 
21 + 2 = 23
23, So we need to add 2   23
Answer: B
We give the following information about a race hedge.
There are 10 hurdles. The distance between consecutive two lines (that is to say which follow) is 9.14 m. There are 13.72 m between the starting line and the first line and the last hurdle between 14.02 m and line arrival. Each hurdle measures 106 cm in height.
What is the length(in centimeters) of the track?	Select the correct option:
A) 14060cm.
B) 12060cm.
C) 15060cm.
D) 11060cm.
E) None

Solution: Solution:   [13.72+(9.14*9)+14.02+[(106÷100)*10]] =>L=[13.72+82.26+14.02+10.6] =>L=120.6m = 12060cm.   Answer 12060cm.
Answer: B
The mass of the sun is approximately 2 × 10^30 kg and the mass of the moon is approximately 9 × 10^12 kg. The mass of the sun is approximately how many times the mass of the moon?  Choose the correct choice:
A) 4.0 × 10^(−18)  B) 2.5 × 10^17  C) 4.0 × 10^18  D) 2.5 × 10^19  E) 3.33 × 10^17

Solution: Mass of sun = x * Mass of moon   x = Mass of sun / Mass of moon = (3 × 10^30) / (9 × 10^12) = 3*3^-2*10^18 = 10^18/3 = 3.33*10^17   Ans. 3.33 × 10^17) 3.33 × 10^17
Answer: E
Diana took out a charge account at the General Store and agreed to pay 6% simple annual interest. If she charges $60 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments?
Options:	A) $62.40	B) $62.80	C) $63.20	D) $63.60	E) $64.00

Solution: 1.06*$60=$63.60   The answer is $63.60.1.06* 60= 
1.06* 60 = 63.6
$63.60   The answer is $63.60.
Answer: D
There are 7 girls and 3 chairs. In how many ways girls can occupy the chairs?  Pick:
A) 760  B) 210  C) 560  D) 740  E) 800

Solution: total girls = 7   total chairs = 3   1st chair can be occupy in 7ways   2nd chair can be occupy in 6ways   3rd chair can be occupy in 5ways   total number of ways = 7*6*5= 
7*6*5 = 210
210 ways   correct option is 210
Answer: B
Find the simple interest on $500 for 3 years at 10% per annum?	Options:	A) $250	B) $300	C) $500	D) $150	E) $100

Solution: SI = PTR/100   = 500*3*10/100= 
500*3*10/100 = 150
$150   Answer is $150
Answer: D
A bag contains 64 balls of eight different colours. There are eight of each colour (including red). What is the least number you would have to pick, without looking, to be sure of selecting 3 red balls?	Choose the correct choice from the following answers
A) 54  B) 60  C) 45  D) 38  E) 59

Solution: E   59   The first 56 balls could be of all colours except red. This would leave 8 balls, all of which are red, so any three chosen would be red.
Answer: E
In a group of 24 students, each student is registered for at least one of three classes – History, Math and English. 15 students are registered for History, 15 students are registered for Math, and 20 students are registered for English. If only three students are registered for all three classes, how many students are registered for exactly two classes?
Choose the correct answer:	A) 13	B) 10	C) 9	D) 20	E) 7

Solution: Each student is registered forat least one of three classesmeans thatthere are no students who are registered for none of the classes.   Total = {people in group A} + {people in group B} + {people in group C} - {people in exactly 2 groups} - 2*{people in exactly 3 groups} + {people in none of the groups}:   24 = 15 + 15 + 20 - {people in exactly 2 groups} - 2*3 + 0-->{people in exactly 2 groups}=20   Answer: 20
Answer: D
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 46 kg, then the weight of B is:	Choose one
A) 17 kg B) 20 kg C) 26 kg D) 31 kg E) 37 kg

Solution: let d sum of a, b, c is 3*45= 
3*45 = 135
135   and sum of a and b s 2*40= 
2*40 = 80
80   sum of b and c is 2 *46= 
2 *46 = 92
92   hence 80+92-144=37   ans=37   ANSW37 kgR:37 kg
Answer: E
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee. In how many ways can it be done? Choose the correct answer.
A) 756  B) 800  C) 956  D) 850  E) 650

Solution: We may have (3 men and 2 women) or (4 men and 1 woman) or (5 men only).   Required number of ways	= (7C3 x 6C2) + (7C4 x 6C1) + (7C5)   = (525 + 210 + 21)= 
(525 + 210 + 21) = 756
756.   756NSWER 756
Answer: A
If you divide 7^115 by 5, which remainder do you get?	Select:
A) 0
B) 1
C) 2
D) 3
E) 4

Solution: The units digit of 7^1 is 7.   The units digit of 7^2 is 9.   The units digit of 7^3 is 3.   The units digit of 7^4 is 1.   The units digit of 7^5 is 7.   etc...   The units digit of 7^n repeats in blocks of 4: {7, 9, 3, 1}   The remainder of 115/4 is 3.   So the units digit of 7^115 is 3.   The remainder of 7^115 / 5 is 3.   The answer is 3.
Answer: D
There is a train and car. The ratio between the speed of a train & a car is 24:19 respectively. Also, a bus covered a distance of 320 km in 5 hours. The speed of the bus is 2/3rd of the speed of the train. How many kilometers will the car cover in 5 hours?	Choose one.
A) 320	B) 340	C) 360	D) 380	E) 400

Solution: The speed of the bus is 320/5= 
320/5 = 64
64 km/hr   The speed of the train is  (64*3)/2= 
 (64*3)/2 = 96
96 km/hr   The speed of the car is   96/24 * 19= 
  96/24 * 19 = 76
76 km/hr   The distance covered by the car in 5 hours is 76 × 5= 380 km   The answer is 380.
Answer: D
A reduction of 5% in the price of sugar enables a lady to obtain 5kgs more for Rs.500, find the original price per kg? Answers:
A) 5.26
B) 5.0
C) 5.52
D) 6.2
E) 5.8

Solution: 5.26nswer:	 500*(5/100)= 
 500*(5/100) = 25
25 --- 5   ? --- 1=> Rs.5   500 --- 475   ? --- 5 => Rs.5.26.5.26nswer: 5.26
Answer: A
If 6 persons can do 6 times of a particular work in 6 days, then, 8 persons can do 8 times of that work in?
Choose the correct choice from the following options
A) 2 days	B) 6 days	C) 5 days	D) 7 days	E) 9 days

Solution: That is, 1 person can do one time of the work in 3 days.   Therefore, 8 persons can do 8 times work in the same 6 days itself.   6 days)
Answer: B
The roots of the equation ax2 + bx + c = 0 will be reciprocal if: Answers:
A) c = b B) c = 0 C) c = a D) c = U E) c = K

Solution: Let k be one of the root of the given equation.   According to the problem,   1/k will be the other root of the given equation.   We know that, product of the roots of the equation = c/a.   Therefore, k × 1/k = c/a.   or, 1 = c/a.   or, a = c [multiplying a on both sides].   The roots of the equation ax2 + bx + c = 0 will be reciprocal if a = c.   Therefore, a = c or c = a.   Answer: c = a
Answer: C
A man is running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a
120 metres long train. The train is running at 45 kmph in the same direction. How much time does it take for the train to pass the man?  Choices:	A) 46 sec	B) 36 sec	C) 18 sec	D) 22 sec	E) 30 sec

Solution: Distance covered = (240+120)= 
(240+120) = 360
360   relative speed= (45-9)= 
(45-9) = 36
36 km/hr     36*5/18= 
  36*5/18 = 10
10 m/s   req time= 360/10= 
360/10 = 36
36 sec   ANSWER 36 sec
Answer: B
A farmer used 1,034 acres of land for beans, wheat, and corn in the ratio of 5 : 2 : 4, respectively. How many W acres were used for corn? Select: A) 188 B) 258 C) 376 D) 470 E) 517

Solution: consider 5x acres of land used for bean   consider 2x acres of land used for wheat   consider 4x acres of land used for corn   Total given is 1034 acres   11x =1034   x = 94   land used for corn W= 4 * 94= 
4 * 94 = 376
376   correct option - 376
Answer: C
Edward invested five-ninths of his money at an annual rate of 2r% compounded semi-annually, and the remaining money at an annual rate of r% compounded annually. If after one year, Edward’s money had grown by one-thirds, the value of r is equal to which of the following?  Choose the correct choice from the following options:
A) 10% B) 15% C) 20% D) 25% E) 33%

Solution: X=Amount invested   5/9*X*(1+2r/2)^2+4/9*X*(1+r)=4/3X   Set X = 9 because we can pick any value   5*(1+r)^2+4(1+r)=12   5r^2+14r-3=0   Here you can use the formula for roots of a quadratic, but it is faster to guess and check using the answers   5*(1/5)^2+14(1/5)-3=5*(1/25)+14/5-3=1/5+14/5-3= 
1/5+14/5-3 = 0
0   ANSWER:20%
Answer: C
A sum of money is borrowed and paid back in two annual installments of Rs.882 each allowing 5% compound interest. The sum borrowed was :	Choose the correct choice from the following choices.
A) Rs.1620	B) Rs. 1640	C) Rs.1680	D) Rs.1700	E) Rs.1800

Solution: Principal = 882/(1+(5/100)) + 882/(1+(5/100)   = (882*20)/21+ (882*400)/441   =840 +800   = Rs.1640   ANSWER:Rs. 1640
Answer: B
One ton has 2300 pounds, and one pound has 16 ounces. How many packets containing wheat weighing 16 pounds and 4 ounces each would totally fill a gunny bag of capacity 13 tons?  Choose the most appropriate option
A) 1840  B) 1700  C) 2350  D) 2500  E) 8000

Solution: 16 pounds and 4 ounces= 16*16 + 4= 
16*16 + 4 = 260
260 ounces.   13 tons= 13*2300 pound = 13*2300*16 ounces.   Hence the answer is   (13*2300*16)/260= 
  (13*2300*16)/260 = 1_840
1840.   1840nswer: 1840.
Answer: A
One day a car rental agency rented 3/4 of its cars, including 4/5 of its cars with CD players. If 3/5 of its cars have CD players, what percent of the cars that were not rented had CD players?	Pick.
A) 23/40	B) 17/30	C) 12/25	D) 7/15	E) 3/10

Solution: The cars with CD players which were not rented is (1/5)(3/5) = 3/25 of all the cars.   The cars which were not rented is 1/4 of all the cars.   The percent of non-rented cars which had 12/25D players is (3/25) / (1/4) = 12/25   The answer is 12/25.
Answer: C
The population of a town increased from 1,25,000 to 1,50,000 in a decade. The average percent increase of population per year is :	Pick one:
A) 4.37%
B) 2%
C) 6%
D) 8.75%
E) None of these

Solution: Solution   Increase in 10 year= (150000 - 125000)= 
(150000 - 125000) = 25_000
25000.   Increase%=( 25000/125000x 100 )% = 20%   âˆ´ Required average = ( 20/10 )= 
( 20/10 ) = 2
2%   Answer 2%
Answer: B
Arun spent six lucky days in Las Vegas. On his first day he won a net amount of only $20, but on each of the following days, the daily net amount he won grew by d dollars. If Arun won a total net amount of $1620 during his stay in Las Vegas, how much did he win on the last day?
Answers.
A) 330
B) 500
C) 520
D) 540
E) 620

Solution: I drew a diagram:   1 - $20   2 -   3 -   4 - $320   5 -   6 -   Total: $1,620   Between 1 and 6 are 5 days where he won $1,600. This means he averaged $320 per day (1600/5). You can put $320 by 4 because it's the middle number. Now you just find the two points betwenn $20 and $320 (320-20 = 300 / 3= 
300 / 3 = 100
100). So each day, he earned $100 more. This means on day 6, Arun earned$520. Answer choice 520.
Answer: C
At the wholesale store you can buy an 8-pack of hot dogs for $1.55, a 20-pack for $3.05, and a 250-pack for $22.95. What is the greatest number of hot dogs you can buy at this store with $208?
Options:
A) 1,108	B) 2,100	C) 2,108	D) 2,160	E) 2,256

Solution: I think it should be D.   I can buy 8 250-pack for Rs 22.95*8= 
22.95*8 = 183.6
$183.60   Now, I can buy 8 20-pack for 3.05*8= 
3.05*8 = 24.4
$24.40   Now, I am left with only $1.15. I cannot but anything with this.   Hence Total Hotdogs= 250*8 + 20*5 = 2160
Answer: D
In a covering a certain distance, the speeds of A and B are in the ratio of 3:4. A takes 30 minutes more than B to reach the destination. The time taken by A to reach the destination is?	Options:
A) 8 hrs
B) 9 hrs
C) 2 hrs
D) 2 hrs
E) 9 hrs

Solution: Ratio of speeds = 3:4   Ratio of times taken = 4:3   Suppose A takes 4x hrs and B takes 3x hrs to reach the destination.   Then, 4x - 3x = 30/60 => x = 1/2   Time taken by A = 4x hrs = 4 * 1/2= 
4 * 1/2 = 2
2 hrs.   Answer:2 hrs
Answer: C
Today my car meter reads as 63736 kms. I notes that this is a palindrome. How many minimum kms i need to travel so my car meter find another palindrom.	Select
A) 100 kms
B) 115 kms
C) 110 kms
D) 200 kms
E) 120 kms

Solution: 200 kms   200 kms   63736+200 = 63536 , a palindrome
Answer: D
If Dave throws down a set dice twice, calculate the probability that one die would be an even while the other would be odd?	Select the correct option:
A) 1/6	B) 1/4	C) 1/2	D) 1	E) 1/3

Solution: The number of exhaustive outcomes for each throw is 36.   For both throws is= 64   Let E be the event of getting an even number on one die and an odd number on the other for each throw.   The event of getting either both even or both odd for each throw is = 18/36 = 1/2   The event of getting either both even or both odd for both throws is = 36/64 = 1/2   P(E) = 1 - 1/2   = 1/2.   Answer:c
Answer: C
There are 7 people and 4chairs. In how many ways people can occupy the chairs?
Choose the correct choice
A) 760  B) 840  C) 560  D) 740  E) 800

Solution: total people = 7   total chairs = 4   1st chair can be occupy in 7ways   2nd chair can be occupy in 6ways   3rd chair can be occupy in 5ways   4th chair can be occupy in 4ways   total number of ways = 7*6*5*4= 
7*6*5*4 = 840
840 ways   correct option is 840
Answer: B