MU-NLPC/Calc-aqua_rat huggingface dataset:
How many odd integers between 200 and 600 are there such that their tens digit is even?	Choose the correct choice from the following choices:
A) 20
B) 25
C) 100
D) 150
E) 200

Solution: The hundreds digit can take 4 values: 2, 3, 4 and 5;   The tens digit can take 5 values: 0, 2, 4, 6 and 8;   The units digit can take 5 values: 1, 3, 5, 7 and 9;   Total:   4*5*5= 
  4*5*5 = 100
100.   Answer: 100
Answer: C
In what time will Rs.4000 lent at 3% per annum on simple interest earn as much interest as Rs.5000 will earn in 5 years at 4% per annum on simple interest?
Choose one.
A) 8 1/3	B) 8 1/6	C) 8 1/2	D) 8 1/9	E) 8 1/4

Solution: (4000*3*R)/100   = (5000*5*4)/100   R = 8 1/3   8 1/3nswer: 8 1/3
Answer: A
If the area of a circle is 49pi square feet, find its circumference. Choose the correct choice from the following answers.
A) 14 pi feet  B) 28 pi feet  C) 38 pi feet  D) 48 pi feet  E) 58 pi feet

Solution: The area is given by pi *r* r. Hence   pi * r *r = 49 pi   r * r = 49; hence r = 49 feet   The circumference is given by   2 * pi * r = 2 * pi * 7 = 14 pi feet   correct answer 14 pi feet
Answer: A
In a set of three numbers,the difference between the largest and the second largest numbers is added to the smallest number.The average of the largest,second largest and the new number formed exceeds the average of the original three numbers by 5.The largest number exceeds the second largest number by how much ?  Choose the most appropriate option:
A) 5
B) 10
C) 15
D) 30
E) 60

Solution: Let the numbers in increasing order be A<B<C...   since the new number(N) increase the average of new set of numbers by 5 after replacing the smallest number,A,   the new number,N, exceeds the smallest,A, by  3*5= 
 3*5 = 15
15 or N=15+A..(1)   and what is the new number,N,---- C-B (diff in the largest and second largest)+A...(2)...   from (1) & (2) C-B=15...   Answer:-15
Answer: C
A train running at the speed of 60 km/hr crosses a pole in 12 seconds. What is the length of the train?	Choose one:  A) 187 m  B) 278 m  C) 876 m  D) 200 m  E) 267 m

Solution: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train   = (Speed x Time)   = (50/3 * 12)= 
(50/3 * 12) = 200
200 m.   Answer: 200 m
Answer: D
J is 25% less than P and 20% less than T. T is q% less than P. What is the value of q?	Choose one:
A) 93.5  B) 90  C) 6.75  D) 6.25  E) 2

Solution: Usually We can solve every question of this type by choosing appropriate value of the Variable and deriving the value of other related variables.   Let, P = 400   then J = (75/100)*400= 
(75/100)*400 = 300
300   also J= (80/100)*T   i.e. T = 300*100/80= 
300*100/80 = 375
375   and T= [1-(q/100)]*P   i.e. 100-q = 100*T/P = 100*375/400= 
100*375/400 = 375/4 = around 93.75
93.75   i.e. q= 6.25   Answer: Option 6.25
Answer: D
The owner of a furniture shop charges his customer 24% more than the cost price. If a customer paid Rs. 8587 for a computer table, then what was the cost price of the computer table? Answers:
A) 7297 B) 2977 C) 2871 D) 6925 E) 2981

Solution: Explanation:   CP = SP * (100/(100 + profit%))   = 8587(100/124) = Rs. 6925.   Answer: 6925
Answer: D
let S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1. Find the sum of all elements in S? Pick:
A) 1584
B) 7640
C) 5640
D) 7240
E) 6780

Solution: S is a set of all natural numbers less than 120 such that HCF of any element in S and 120 is 1.   Such numbers are,   S = {1, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113}   Sum of S = 1584.   1584NSWER:1584
Answer: A
If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is?
Choose one:  A) Rs.8082  B) Rs.7800  C) Rs.8100  D) Rs.8112  E) Rs.9000

Solution: Explanation:   A = 7500(26/25)2 = 8112   ANSWER IS Rs.8112
Answer: D
Calculate 12351 ÷ ? = 69
Select:
A) 179
B) 119
C) 129
D) 173
E) 156

Solution: Answer   Let 12351 ÷ ? = 69   Then X = 12351/69= 
12351/69 = 179
179.   Option: 179
Answer: A
find remainder when (10^3+9^3)^1000 divided by 12^3  Options.
A) 0
B) 1
C) 2
D) 3
E) 4

Solution: (10^3+9^3)^1000 / 12^3   = 1729^1000 / 1728   => (1728*1+1)^1000 / 1728   => 1^1000 / 1728   => rem = 1   ANSWER:1
Answer: B
How many seconds will a train 120 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?  Choose the correct choice from the following choices.
A) 17 sec
B) 21 sec
C) 25 sec
D) 27 sec
E) 29 sec

Solution: 27 sec = 120 + 150= 
120 + 150 = 270
270   S= 36 * 5/18= 
36 * 5/18 = 10
10 mps   T= 270/10= 
270/10 = 27
27 sec
Answer: D
A rectangular farm has to be fenced one long side, one short side and the diagonal. If the cost of fencing is Rs.10 per meter. The area of farm is 1200 m2 and the short side is 30 m long. How much would the job cost?	Select the correct option
A) 2387
B) 1298
C) 1128
D) 1237
E) 1200

Solution: l * 30 = 1200 l = 40   40 + 30 + 50= 
40 + 30 + 50 = 120
120   120 * 10= 
120 * 10 = 1_200
1200   1200
Answer: E
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 50 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad? Choose one:
A) 16  B) 18  C) 20  D) 24  E) 30

Solution: Time taken = Total Distance / Relative Speed   Total Distance = 50 kms   Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4= 
6+ 4 = 10
10 kms/hr   Time taken= 50 / 10= 
50 / 10 = 5
5 hrs   Distance traveled by Brad= Brad's speed * time taken = 6 * 5= 
6 * 5 = 30
30 kms... Answer - 30
Answer: E
When a Laptop is sold for Rs. 49,000, the owner loses 30%. At what price must that Laptop be sold in order to gain 30%? Choose the correct choice from the following.
A) 87000 B) 88000 C) 89000 D) 90000 E) 91000

Solution: 70 : 49000 = 130 : x   x = (49000 x 130)/70 = 91000.   Hence, S.P. = Rs. 91,000.   Answer: Option 91000
Answer: E
Find the cost of fencing around a circular field of diameter 16 m at the rate of Rs.3 a meter?	Select the correct option:
A) 150.84
B) 160.6
C) 150.45
D) 160.99
E) 180.4

Solution: 2 * 22/7 * 8 = 50.28   50.28 * 3= Rs.150.84   150.84nswer: 150.84
Answer: A
The difference between simple interest and compound interest on Rs.1400 for one year at 20% per annum reckoned half-yearly is: Choose the correct choice from the following.
A) $185.63
B) $852.36
C) $875.5
D) $989.9
E) $875.8

Solution: S.I= [(1400*20*1)/100= 
(1400*20*1)/100 = 280
$280.   C.I=[1400*(1+(5/100)^2)-1400]=$1269.8.   $989.9ifference=(1269.8-280)= 
(1269.8-280) = 989.8
$989.8   Answer($989.9)
Answer: D
Sambhu buys rice at Rs. 10/kg and puts a price tag on it so as to earn a profit of 20%. However, his faulty balance shows 1000 gm when it is actually 800 gm. What is his actual gain percentage ?
Choose the most appropriate option:
A) 20%  B) 30%  C) 50%  D) 40%  E) 60%

Solution: 1kg rice =Rs. 10 => 800gm actual cost =Rs. 8.   But he wants to earn a profit of 20% => 1kg = Rs.12.   Moreover his faulty balance shows 800 gm = 1000gm (1 kg)   => He sells 800 gm for Rs.12   Therefore the actual profit earned by him is (12-8)/8 * 100= 
(12-8)/8 * 100 = 50
50%   ANSWER:50%
Answer: C
In Town P, 60 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town P are females?	Choose the correct answer:  A) 20%  B) 25%  C) 30%  D) 35%  E) 40%

Solution: The percent of the population who are employed females is 60-48= 
60-48 = 12
12%   The percent of employed people who are female is 12% / 60%= 20%.   The answer is 20%.
Answer: A
Four contestants representing four different countries advance to the finals of a fencing championship. Assuming all competitors have an equal chance of winning, how many possibilities are there with respect to how a first-place and second-place medal can be awarded?  Choose the correct choice from the following answers.
A) 6  B) 7  C) 12  D) 16  E) 24

Solution: Number of ways First-place medal can be awarded to four contestants = 4   Number of ways Second-place medal can be awarded to contestants after awarding First-place medal =3   Therefore number of possibilities = 4 *3= 
4 *3 = 12
12   Answer: 12
Answer: C
If in a certain sequence of consecutive multiples of 50, the median is 625, and the greatest term is 750, how many terms that are smaller than 625 are there in the sequence? Pick one
A) 6
B) 7
C) 8
D) 12
E) 3

Solution: Since the median is 625 we know there must be a even number of integers because 50 is not a multiple of 625.   So the list around 625 must go. 600 (625) 650 700 750   Since we know there are 3 numbers greater than 625 then there must be 3 numbers less then 625.   3
Answer: E
A boatman goes 2 km against the current of the stream in 2 hour and goes 1 km along the current in 20 minutes. How long will it take to go 5 km in stationary water?	Choose the most appropriate option: A) 2 hr 30 min B) 2 hr C) 4 hr D) 1 hr 15 min E) None of these

Solution: Explanation :   Speed upstream = 2/2= 
2/2 = 1
1 km/hr   Speed downstream= 1/((20/60))= 
1/((20/60)) = 3
3 km/hr   Speed in still water= 1/2(3+1) = 2 km/hr   Time taken to travel 5 km in still water = 5/2 = 2(1/2) hours = 2 hour 30 minutes. 2 hr 30 minnswer : Option 2 hr 30 min
Answer: A
To a sugar solution of 3 litres containing 40% sugar, one litre of water is added. The percentage of sugar in the new solution is ? Answers.
A) 22% B) 15% C) 26% D) 40% E) 30%

Solution: Quantity of sugar = 40*3/100= 
40*3/100 = 6/5 = around 1.2
1.2kg   new percentage= (1.2*100/4)= 
(1.2*100/4) = 30
30%   Answer is 30%
Answer: E
If S is the sum of the reciprocals of the consecutive integers from 91 to 100, inclusive, which of the following is less than S?
I. 1/11
II. 1/10
III. 1/10
Choose the correct choice from the following:  A) II only  B) I only  C) III only  D) II and III only  E) I, II, and III

Solution: Since we summarize the reciprocals from 100 to 91, we can say also that we add ten numbers who are all (with one exception 1/100) greater than 1/100, so that the sum must be greater than 1/10.   On the other side we can say that we add the reciprocals from 91 to 100, so that the sum has to be less than the sum of ten times 1/91.   We can conclude that the sum has to be less than 1/9 but more than 1/10. That leaves us II only a as the only possible answer.
Answer: A
If a, b, and c are consecutive integers such that a < b < c and a is an even prime number, which of the following is true?
I. a + b + c > a^3
II. a × b × c < a^3
III. 4b < bc
Answers: A) I only B) II only C) III only D) II and III E) I, II, and III

Solution: Only 'A' is possible solution. If a is even prime number i.e 2, b is 3 and c is 4   Putting the values in the answers only 'I only' seems valid.
Answer: A
If the product of the integers from 1 to n is divisible by 210, what is the least possible value of n?	Choose the correct choice from the following options:
A) 7
B) 14
C) 21
D) 28
E) 35

Solution: 210 = 2 x 3 x 5 x 7   N must include at least up to the number 7.   The answer is 7.
Answer: A
The probability that A speaks truth is 5/9 and that of B speaking truth is 7/11. What is the probability that they agree in stating the same fact?
Choose the most appropriate option: A) 68/95 B) 12/85 C) 59/99 D) 33/39 E) None of these

Solution: If both agree stating the same fact, either both of them speak truth of both speak false.   Probability = 5/9 * 7/11 + 4/9 * 6/11   = 35/99 + 24/99 = 59/99   ANSWER:59/99
Answer: C
A car driver travels from the plains to the hill station, which are 200 km apart at an average speed of 40 km / hr. In the return trip, he covers the same distance at an average speed of 20 km / hr. The average speed of the car over the entire distance of 400 km / hr. Choose the most appropriate option.
A) 22 km/hr	B) 28.56 km/hr	C) 26.67 km/hr	D) 30 km/hr	E) None

Solution: Sol.   Average speed = (2×40×20 / 40 + 60) km/hr   = (80/3)km/hr   = 26.67 km/hr.   Answer 26.67 km/hr
Answer: C
If the selling price of 8 articles is same as the cost price of 10 articles. Find the gain or loss percentage?	Choose the correct answer: A) 25% B) 45% C) 35% D) 65% E) 55%

Solution: Let the C.P of each article be Re 1. Then,   S.P of 8 articles = C.P of 10 articles = Rs. 10   Now, C.P of 8 articles = Rs. 8, S.p of 8 articles = Rs 10   Gain = Rs ( 10 - 8 )= 
( 10 - 8 ) = 2
Rs 2.   Gain%= ( 2/8 × 100 ) % = 25%   25%nswer : 25%
Answer: A
Find the value of x when the average of 3x,(5x+6),(7x-4) is 51? Choose the correct choice from the following answers
A) 5
B) 10
C) 15
D) 12
E) 20

Solution: Average = (3x+5x+6+7x-4)/3 = (15x+3)/3 = 5x+1   5x+1 = 51   x = 50/5= 
50/5 = 10
10   Answer is 10
Answer: B
The average speed of a train running at a speed of 30 km/hr during the first 100 kilometres, at 40 km/hr during the second 100 kilometres and at 50 km/hr during the last 100 kilometres is nearly?
Answers
A) 38.5 km/hr  B) 38.3 km/hr  C) 40.0 km/hr  D) 39.2 km/hr  E) None of these

Solution: Time taken to cover first 100 kilometres = 100/3 = 3(1/3) hours   Time taken to cover second 100 kilometres =100/40 = 2(1/2) hours   Time take to cover last 100 kilometres = 100/2 = 2 hours   Total distance covered = 300 km.   Total time taken = 47/6 hours   Thus, average speed = 300/(47/6) = 38.3 km/hr.   ANSWER:38.3 km/hr
Answer: B
The age of man is three times the sum of the ages of his two sons.Five years hence,his age will be double of the sum of the ages of his sons.The father's present age is :	Choices.
A) 50 years B) 46 years C) 20 years D) 45 years E) 30 years

Solution: Let the sum of present ages of the two sons be x years.   then father's present age =3x years.   (3x+5)=2(x+10)   3x+5=2x+20   x=15.   Hence, father's present age =45 years.   Answer is 45 years
Answer: D
y w v t r p n
Next letter in the series Choose the correct answer:
A) L	B) M	C) N	D) O	E) P

Solution: y--w(y-2)   v--t(v-2)   r--p(r-2)   n--l(n-2)   so ans is l   LNSWER:L
Answer: A
On a certain number line, conditions are x<Y<z<U<v. xyzuv>0 Which of the following must be true?
I xy>0
II zu>0
III uv>0
Options:
A) I only
B) II only
C) I and II
D) III only
E) II and III only

Solution: Suppose, for the product to be greater than 0, we can two variables as -ve or four variables can be -ve.   We are given : I xy>0 II yz>0 III uv>0   case 1: x and y can be negative/positive and if they are... we get greater than 0.   case 2: we have zu , then z and u both can be negative/positive and if they are... we get greater than 0.   I and II
Answer: C
(0.96)(power 3) - (0.1)(power 3)/ (0.96)(power 2) + 0.096 + (0.1)(power 2) is: Choose the correct option.
A) 0.68  B) 0.086  C) 0.86  D) 0.068  E) None of them

Solution: Given expression   = (0.96) (power 3) - (0.1)(power 3) / (0.96)(power 2) + (0.96 x 0.1) + (0.1)(power 2)   = a (power 3) - b(power 3) / a(power 2) + ab + b(power 2)   = (a - b)   = (0.96 - 0.1)= 
(0.96 - 0.1) = 0.86
0.86   Answer is 0.86.
Answer: C
Peta has six times as many dimes as quarters in her piggy bank. She has 21 coins in her piggy bank totaling $2.55
How many of each type of coin does she have?	Choose the correct answer:  A) 4q & 20d  B) 5q & 15d  C) 3q & 18d  D) 6q & 16d  E) 2q & 19d

Solution: Let x be the number of quarters. Let 6x be the number of dimes   Since one quarter equals 25 cents, x quarters equals x × 25 cents or 25x cents   Since one dime equals 10 cents, 6x dimes equals 6x × 10 cents or 60x cents   Since one 1 dollar equals 100 cents, 2.55 dollars equals 2.55 × 100 = 255 cents   Putting it all together, 25x cents + 60x cents = 255 cents   85x cents = 255 cents   85x cents / 85 cents = 255 cents / 85 cents   x = 3   6x = 6 × 3 = 18   Therefore Peta has 3 quarters and 18 dimes   correct answer is 3q & 18d)3q & 18d
Answer: C
Two dice are thrown together. What is the probability that the sum of the number on the two faces is divided by 4 or 6
Choose the correct choice.
A) 1/3 B) 7/19 C) 7/9 D) 7/17 E) 7/18

Solution: Clearly n(S)=6*6= 
6*6 = 36
36   Let E be the event that the sum of the numbers on the two faces is divided by 4 or 6. Then   E={(1,3),(1,5),(2,2),(2,4),(2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(5,1),(5,3),(6,2),(6,6)}   n(E)=14.   Hence p(e)=n(e)/n(s)=14/36=7/18   answer option 7/18) 7/18
Answer: E
The average age of M boys is ‘b’ years and of ‘n’ girls ‘c’ years. The average age of all together is? Choose the correct choice from the following answers:	A) (mb – nc)/ (m + n) years	B) (mb + nc)/ (m - n) years	C) (mb + nc)/ (m + n) years	D) (mb – nc)/ (m - n) years	E) (mn – mc)/ (m - n) years

Solution: (mb + nc) / (m+ n)   Answer:(mb + nc)/ (m + n) years
Answer: C
The average mark of the students of a class in a particular exam is 65. If 5 students whose average mark in that exam is 20 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
Options.
A) 14  B) 25  C) 35  D) 45  E) 55

Solution: Let the number of students who wrote the exam be x.   Total marks of students = 75 x.   Total marks of (x - 5) students = 90(x - 5)   65x - (5 * 20) = 90(x - 5)   350 = 25x => x = 14   14NSWER:14
Answer: A
The function f is defined for all positive integers m by the following rule. f(m) is the number of positive integers each of which is less than m and has no positive factor in common with m other than 1. If q is any prime, number then f(q)=	Pick
A) q-2 B) q-1 C) (q+1)/2 D) (q-1)/2 E) 2

Solution: If not the wording the question wouldn't be as tough as it is now. The GMAT often hides some simple concept in complicated way of delivering it.   This question for instance basically asks: how many positive integers are less than given prime number q which have no common factor with q except 1.   Well as q is a prime, all positive numbers less than q have no common factors with q (except common factor 1). So there would be q-1 such numbers (as we are looking number of integers less than q).   For example: if q=8 how many numbers are less than 8 having no common factors with 8: 1, 2, 3, 4, 5, 6, 7 --> 8-1=7.   Answer: q-1.
Answer: B
The average age of father and his two sons is 27 years. The difference in age between the two sons is 4 years and five years ago the average age of the two sons was 12 years. What is the present age of the father?	Choose the most appropriate option
A) 34years  B) 47years  C) 64years  D) 27years  E) 37years

Solution: The average age of father and his two sons is 27 years.   The total age of father and his two sons is 81 years.   five years ago the average age of the two sons was 12 years.   Now the average age of the two sons is 17 years.   Now the total age of the two sons is 34 years.   age of father = 81-34= 
81-34 = 47
47 years   ANSWER:47years
Answer: B
A table is bought for Rs.940/- and sold at Rs.1040/- find the loss percentage  Choose the correct answer.
A) 10% Loss	B) 10% Gain	C) 20% Loss	D) 20% Gain	E) 30% Gain

Solution: Formula = (Selling price ~ Cost price)/Cost price * 100   = (1040 ~ 940)/940 = 10% gain   10% Gain
Answer: B
A salesperson receives a base salary of $1000 per month and a commission of 7.5% of the selling price of each item sold above the first 50 item. If this month she sold 370 items for $150 each, what will her monthly salary be?
Choose the most appropriate option
A) $1,500
B) $4,600
C) $2,100
D) $2,500
E) $2,800

Solution: Ans : 1000+ 7.5 % * 150 * (370-50) = $ 4600   ANSWER:$4,600
Answer: B
In how many different ways can change be provided for a one dollar bill using pennies (1 cent), nickels (5 cents), dimes (10 cents), and quarters (25 cents), if at least one of each type of coin must be included?	Pick one
A) 39 B) 42 C) 60 D) 65 E) 66

Solution: I. Case I = Four Quarters = this is impossible, because if we already have a dollar in quarters, then we cannot have any other coins. We can't have all four coins represented if we have four quarters.   Case I does not allow any ways.   II. Case II = Three Quarters (75 cents)   This allows for one dime. Two dimes would bring us up to $0.95, and we wouldn't have room for both pennies and nickels.   Subcase 1 = 3 Q, 1 D (85 cents)   1) one nickel (N) and 10 pennies (P)   2) 2 N and 5 P   Case II allows for a total of two ways.   III. Case III = Two Quarters (50 cents)   This allows for 1-4 dimes.   Subcase 1 = 2 Q, 4 D (90 cents)   (1 way) we could have 1 nickel   Subcase 2 = 2 Q, 3 D (80 cents)   (3 ways) we could have 1-3 nickels   Subcase 3 = 2 Q, 2 D (70 cents)   (5 ways) we could have 1-5 nickels   Subcase 4 = 2 Q, 1 D (60 cents)   (7 ways) we could have 1-7 nickels   Case III allows for a total of 16 ways   IV. Case IV = One Quarter (25 cents)   This allows for 1-6 dimes   Subcase 1 = 1 Q, 6 D (85 cents)   (2 ways) we could have 1-2 nickels   Subcase 2 = 1 Q, 5 D (75 cents)   (4 ways) we could have 1-4 nickels   Subcase 3 = 1 Q, 4 D (65 cents)   (6 ways) we could have 1-6 nickels   Subcase 4 = 1 Q, 3 D (55 cents)   (8 ways) we could have 1-8 nickels   Subcase 5 = 1 Q, 2 D (45 cents)   (10 ways) we could have 1-10 nickels   Subcase 6 = 1 Q, 1 D (35 cents)   (12 ways) we could have 1-12 nickels   Case IV allows for a total of 42 ways.   There's no other case, because we have to have at least one quarter and one dime. The total over the cases equals   Total = 0 + 2 + 16 + 42= 
0 + 2 + 16 + 42 = 60
60 ways.   OA=(60)
Answer: C
A library has an average of 510 visitors on Sunday and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is?  Choose the correct choice from the following choices:
A) 187  B) 279  C) 280  D) 285  E) 262

Solution: Since the month begins with a Sunday, so there will be five Sundays in the month.   Required average   = [(510 * 5) + (240 * 25)]/30 = 8550/30= 
8550/30 = 285
285.   Answer:285
Answer: D
In aquarium A there are 2 yellow fish and 2 green ones, in aquarium B there are 3 yellow fish and 4 green ones. An aquarium is chosen at random, what is the probability of picking up a green fish out of aquarium A?	Choose the correct choice: A) 1/2. B) 3/5. C) 1/4. D) 1/3. E) 2/3.

Solution: Probability of picking up one aquarium out of two= 1/2   probability of picking 1 green fish from aquarium A= 2/4=1/2   Hence the desired probability= 1/2*1/2= 1/4   1/4. is the answer
Answer: C
What is the smallest no. which must be added to 3245613 so as to obtain a sum which is divisible by 11?
Pick one
A) 1 B) 2 C) 4 D) 9 E) 3

Solution: For divisibility by 11, the difference of sums of digits at even and odd places must be either zero or divisible by 11.   For 3245613 , Difference =(3+4+6+3) -(2+5+1)=16-8= 
16-8 = 8
8.   The units digit is at odd place. So we add 3 to the number=> 3245613+3= 
3245613+3 = 3_245_616
3245616   Now , (3+4+6+6) -(2+5+1)=19-8= 
19-8 = 11
11=>11 is a multiple of 11 and hence 3245616 is also divisible by 11   3
Answer: E
4,7,15,31,35,19,11,?  Choices:
A) 5	B) 6	C) 7	D) 8	E) 9

Solution: Find the diff between each digits:   7-4= 
7-4 = 3
3   15-7= 
15-7 = 8
8   31-15= 
31-15 = 16
16   35-31= 
35-31 = 4
4   19-35=-16   11-19=-8   i.e. it shows a series 3,8,16,4,-16,-8,-3   that means next digit would be 8.   ANSWER:8
Answer: D
What will be the cost of gardening 1 meter boundary around a rectangular plot having perimeter of 340 meters at the rate of Rs. 10 per square meter ?  Choose one:
A) Rs. 3430	B) Rs. 3440	C) Rs. 3450	D) Rs. 3460	E) Rs. 3490

Solution: Explanation:   In this question, we are having perimeter.   We know Perimeter = 2(l+b), right   So,   2(l+b) = 340   As we have to make 1 meter boundary around this, so   Area of boundary = ((l+2)+(b+2)-lb)   = 2(l+b)+4 = 340+4= 
340+4 = 344
344   So required cost will be= 344 * 10= 
344 * 10 = 3_440
3440   Answer: Option Rs. 3440
Answer: B
TOM traveled the entire 80 miles trip. If he did the first 30 miles of at a constant rate 30 miles per hour and the remaining trip of at a constant rate 50 miles per hour, what is the his average speed, in miles per hour?  Choose the correct option.
A) 55 mph  B) 50 mph  C) 40 mph  D) 60 mph  E) 70 mph

Solution: avg speed = total distance/ total time = (d1+d2)/(t1+t2) = (30+50) / ((30/30)+(50/50)) = 80/2= 
80/2 = 40
40mph   40 mph
Answer: C