MU-NLPC/Calc-aqua_rat huggingface dataset:
We bought a total of 90 books at the store. Math books cost $4 and history books cost $5. The total price was $396. How many math books did we buy?	Select.
A) 47  B) 54  C) 56  D) 61  E) 64

Solution: M + H = 90   H = 90 - M   4M + 5H = 396   4M + 5*(90 - M) = 396   M = 54   The answer is 54.
Answer: B
Kamalesh worked 27days and completed 75 percent of a particular work. Then he took the help of Lucifer and they together completed the remaining work in 5 days. How long will Lucifer take to complete the same work,if he is working alone
Choose the correct answer.
A) 10 DAYS B) 40 DAYS C) 45 DAYS D) 47 DAYS E) 49 DAYS

Solution: Kamlesh completed 75% of the work in 27 days. So,   Work rate of Kamlesh = 75/27 = 2.775 per day.   Kamlesh and Lucifer complted 25% remaining work in 5 days.Then   Work rate of Kamlesh and Lucifer, together = 25/5= 
25/5 = 5
5% per day.   So, Work rate of Lucifer= 5 - 2.77= 
5 - 2.77 = 2.23
2.23% per day.   To complete 100% work alone, Lucifer needs,= 100/2.23 = 45 days.   ANSWER : OPTION 45 DAYS
Answer: C
Find out the wrong number in the series.
6, 12, 48, 98, 384, 768, 3072
Choices.
A) 768 B) 384 C) 98 D) 488 E) 12

Solution: Each even term of the series is obtained by multiplying the previous term by 2.   2nd term = (1st term) x 2 = 6 x 2 = 12   4th term = (3rd term) x 2 = 48 x 2 = 96.   6th term = (5th term) x 2 = 384 x 2 =768.   4th term should be 96 instead of 98.   ANSWER:98
Answer: C
Two friends plan to walk along a 36-km trail, starting at opposite ends of the trail at the same time. If Friend P's rate is 25% faster than Friend Q's, how many kilometers will Friend P have walked when they pass each other? Choices:	A) 19	B) 20	C) 21	D) 22	E) 23

Solution: If Q complete x kilometers, then P completes 1.25x kilometers.   x + 1.25x = 36   2.25x=36   x = 16   Then P will have have walked   1.25*16= 
  1.25*16 = 20
20 km.   The answer is 20.
Answer: B
The ratio of boys to girls in Class A is 3 to 5. The ratio of boys to girls in Class B is 4 to 5. If the two classes were combined, the ratio of boys to girls in the combined class would be 17 to 22. If Class A has one more boy and two more girls than class B, how many girls are in Class A?  Choose the correct choice from the following answers:
A) 8	B) 9	C) 10	D) 11	E) 12

Solution: Since it is given that the ratio of boys to girls in Class A is 3 to 4 - so we can quickly eliminate the answer choices which are not multiples of 4.   so ans can either be 8 0r 12.   With 8 as answer - no of girls = 8   With 12 as answer - no of girls = 12   Now Class A has one more boy and two more girls than class B and also the ratio of boys to girls in Class B is 4 to 5.   So we are looking for number of girls in B to be divisible by 5.   With 8 as answer -> Girls = 8-2= 
8-2 = 6
6. (Not possible)   With 12 as answer -> Girls= 12-2 = 5.   So, answer = 10. ( 10)
Answer: C
A man has Rs. 320 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?  Select.
A) 45 B) 60 C) 75 D) 90 E) 105

Solution: Answer : B   Let number of notes of each denomination be x.   Then, x + 5x + 10x = 320   16x = 320   x = 20.   Hence, total number of notes = 3x = 60.
Answer: B
What is the CP of Rs 100 stock at 6 discount, with 1/5% brokerage?	Choose the correct choice from the following options:
A) 99.6
B) 96.2
C) 94.2
D) 98.25
E) None of these

Solution: Explanation:   Use the formula,   CP= 100 â€“ discount + brokerage%   CP= 100-6+1/5   94.2   Thus the CP is Rs 94.2.   ANSWER 94.2
Answer: C
In a survey of parents, exactly 5/6 of the mothers and 3/4 of the fathers held full-time jobs. If 60 percent of the parents surveyed were women, what percent of the parents did not hold full-time jobs? Choose the correct choice from the following options
A) 12%  B) 15%  C) 18%  D) 20%  E) 25%

Solution: Fathers without full-time jobs are 1/4*2/5 = 2/20 of all the parents surveyed.   Mothers without full-time jobs are 1/6*3/5 = 1/10 of all the parents surveyed.   The percent of parents without full-time jobs is 2/20 + 1/10 = 1/5 = 20%   The answer is 20%.
Answer: D
A company pays 12.5% dividend to its investors. If an investor buys Rs.50 shares and gets 25% on investment, at what price did the investor buy the shares? Choose one:	A) 6.25	B) 15	C) 10	D) 8	E) 7

Solution: Dividend = 12.5*50/100= 
12.5*50/100 = 6.25
6.25   25 income on investment rs 100   req==>6.25   6.25NSWER 6.25
Answer: A
What is the sum of all possible 3-digit numbers that can be constructed using the digits 2, 3, and 4 if each digit can be used only once in each number? Choose the correct choice from the following:  A) 1776  B) 1887  C) 1998  D) 2332  E) 2554

Solution: There are 6 possible arrangements of the three numbers.   Then each number will be in the hundreds, tens, and ones place two times each.   The sum is 2(222) + 2(333) + 2(444) = 1998   The answer is 1998.
Answer: C
In a kilometer race, A beats B by 50 meters or 10 seconds. What time does A take to complete the race? Pick one.
A) 667 sec  B) 190 sec  C) 888 sec  D) 288 sec  E) 999 sec

Solution: Time taken by B run 1000 meters = (1000 * 10)/50= 
(1000 * 10)/50 = 200
200 sec.   Time taken by A= 200 - 10= 
200 - 10 = 190
190 sec.   Answer: 190 sec
Answer: B
The length of the diagonal of a square is 12 cm. Find its area and perimeter.	Pick one
A) 31.84 cm B) 33.84 cm C) 35.84 cm D) 38.84 cm E) 38.92 cm

Solution: Diagonal of a square = 12 cm   Area of square = 1/2 (d)²   = 1/2 (12)²   = 1/2 × 12 × 12   = 72   Side of a square = √Area   = √72   = √(2 × 2 × 2 × 3 × 3)   = 2 × 3√2   = 6 × 1.41   = 8.46 cm   Perimeter of square = 4 × 8.46 = 33.84 cm   ANSWER OPTION :33.84 cm
Answer: B
The sum of four consecutive odd numbers is equal to the sum of 3 consecutive even numbers. Given that the middle term of the even numbers is greater than 101 and lesser than 200, how many such sequences can be formed?  Select.
A) 12	B) 17	C) 25	D) 33	E) 50

Solution: Sum of four consecutive odd numbers:   (2a - 3) + (2a - 1) + (2a + 1) + (2a + 3) = 8a   Sum of three consecutive even numbers:   (2b - 2) + 2b + (2b + 2) (2  - 3) + (2  - 1) + (2  + 1) + (2  + 3)= 
(2  - 3) + (2  - 1) + (2  + 1) + (2  + 3) = 8
8a   Sum of three consecutive even numbers:   (2b - 2) + 2b + (2b + 2) = 6b   Given 8a (2  - 2) + 2  + (2  + 2)= 
(2  - 2) + 2  + (2  + 2) = 6
6b   Given 8a= 6b or a/b = 3/4, a and b can be any integers. So, 'a' has to be a multiple of 3 and 'b' has to be a multiple of 4. Possible solutions are: a = 3, b = 4; a = 6, b = 8; a = 9, b = 12 etc   Since 101 < 2b < 200 i.e.   51 <= b < 100   Since b also has to be a multiple of 4, the values that b can take are 52, 56, 60, 64 ... 96   Number of values b can take = (Last term - First term)/Common Difference + 1 = (96 - 52)/4 + 12   12nswer:12
Answer: A
he greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is:  Choose the correct choice from the following answers:  A) 15 cm  B) 25 cm  C) 35 cm  D) 42 cm  E) 45 cm

Solution: Required length = H.C.F. of 700 cm, 385 cm and 1295 cm = 35 cm. Answer: Option 35 cm
Answer: C
The average of five results is 46 and that of the first four is 30. The fifth result is?  Select.
A) 50	B) 88	C) 77	D) 66	E) 110

Solution: 5 * 46 â€“ 4 * 30   = 110   Answer: 110
Answer: E
A train travels a certain distance taking 7 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 5 hrs.What is the distance traveled	Choose the correct choice from the following options:
A) 210 kms
B) 30 kms
C) 60 kms
D) 90 kms
E) 80 kms

Solution: let the speed in the forward journey be x km/hr, also   given time taken in fwd journey = 7 hrs   during return journey   speed=(x+12)km/hr   time=5hrs   nw distance travelled in both the cases is same therefore   forward journey distance=return journey distance   7x=5(x+12)   7x-5x=60   2x=60   x=30km/hr   therefore distance travelled= 30*7= 
30*7 = 210
210km   or=5*(30+12)= 
5*(30+12) = 210
210km   210 kmsNSWER:210 kms
Answer: A
A building contractor employs 20 male, 15 female and 5 child workers. To a male worker he pays Rs.25 per day, to a female worker Rs.20 per day and a child worker Rs.8 per day. The average wage per day paid by the contractor is?  Choose the correct option:
A) 13  B) 21  C) 77  D) 88  E) 11

Solution: 20 15 5   25 20 8   500 + 300 + 40= 
500 + 300 + 40 = 840
840/40= 
840/40 = 21
21'   Answer: 21
Answer: B
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?  Choose the correct option
A) 1/7	B) 1/11	C) 2/7	D) 2/9	E) 2/11

Solution: Explanation: P (getting a prize) = 10/(10+25) = 10/35 = 2/7   Option 2/7
Answer: C
If X = the product of three distinct prime numbers, how many factors does X have besides 1 and itself? Answers:
A) 6  B) 8  C) 10  D) 12  E) 14

Solution: Since X has 3 distinct prime factors, X has a total of 2^3 = 8 factors.   Besides 1 and itself, X has 6 factors.   The answer is 6.
Answer: A
Sunil purchases two books at Rs. 300 each. He sold one book 10% gain and other at 10% loss. What is the total loss or gain in percentage? Pick one:
A) 10% gain B) 1% loss C) no loss or no gain D) 1% gain E) 2%

Solution: tot cost = 300 + 300= 
300 + 300 = 600
600   total selling price    300 * 110/100 + 300 * 90/100= 
 300 * 110/100 + 300 * 90/100 = 600
600   total cost price= total selling price   hence there is neither loss nor gain   ANSWER no loss or no gain
Answer: C
Two sides of a triangle have length 6 and 8. Which of the following are possible areas of the triangle?
I. 2
II. 12
III. 22	Pick
A) I, II, and III	B) I and II only	C) II and III only	D) I and III only	E) II only

Solution: Answer = A. I, II, and III   With dimensions of only 2 sides given (for a triangle), this becomes an open ended question   I, II, and IIIny area is possible out of the three
Answer: A
Of the female students at Barkely University, 5/6 are on the honor roll. Of the male students, 2/3 are on the honor roll. If 3/5 of the students are female, what fraction of all the students are on the honor roll?  Choose the correct choice.
A) 5/9
B) 3/15
C) 23/30
D) 43/60
E) 53/90

Solution: for total students take LCM OF FACTIONS=6*5= 
6*5 = 30
30   Let female students=x,   so male students=30-x   Now,female stu. on honor roll=5/6(x) and male stu. on honor roll=2/3(30-x)   as given total female stu.=3/5(30)=18   female stu.=(5/6)*18= 
(5/6)*18 = 15
15   and male stu.=(2/3)*12= 
(2/3)*12 = 8
8   fraction of honor student=(15+8)/30=23/30.   23/30orrect answer is 23/30.
Answer: C
A man received a cheque. The amount in Rs. has been transposed for paise and vice versa. After spending Rs. 5 and 42 paise, he discovered he now had exactly 6 times the value of the correct cheque amount. What amount he should have received? Pick:	A) Rs 5.30	B) Rs 6.44	C) Rs 60.44	D) Rs 16.44	E) None of these

Solution: Explanation :   Option 4 :- on reversal will be 44Rs 16Ps, after spending 5Rs 42Ps, remaining will be around 40rs which is not 6 times 16Rs 44Ps.   Option 3 :- on reversal will lead a smaller value. Hence we can eliminate that as well.   Option 1 :- on reversal is 30Rs 5 Paise, after spending 5Rs 42Ps, remaining will be 24Rs 63Paise, 24Rs63Ps is not 6 times 5Rs30Paise.   Option 2 on reversal is 44Rs 06 Paise, after spending 5Rs 42Ps, remaining will be 38Rs 64Ps, which is 6 times 6Rs 44Paise. Hence Rs 6.44 is the answer.   We need not even consider option 4 and option 3 as reversed number itself is not 6 times the original number. Option 1 when reversed is odd, and when even (5Rs 42Ps) is subtracted from odd, we get a odd number, and an odd number cannot be 6 times another number   Answer : Rs 6.44
Answer: B
If an item that originally sold for A dollars was marked up by x percent and then discounted by K percent, which of the following expressions represents the final price of the item?
Choose the correct choice from the following options:
A) (10,000z + 100z(x – y) – xyz)/10,000	B) (A+ Ax/100) - K/100 ( A +Ax/100)	C) (100z(x – y) – xyz)/10000	D) (100z(y – x) – xyz)/10000	E) 10000 /(x – y)

Solution: value of item =A ..marked up by x% = Ax/100   total value = A +ax/100 .discounted by Y% on Total K/100 * ( A+Ax/100)   Final price =(A+ Ax/100) - K/100 ( A +Ax/100)   (A+ Ax/100) - K/100 ( A +Ax/100)
Answer: B
Which of the following number will completely divide (49^15)-1?  Select the correct option:
A) 8 is the number
B) 6
C) 22
D) 12
E) 14

Solution: x^n - 1 will be divisible by x+1 only when n is even.   49^15 - 1 = (7^2)^15 - 1 = 7^30 - 1 which is divisible by 7+1 i.e. 8   8 is the numbernswer is 8 is the number
Answer: A
A and B starts a business with Rs.8000 each, and after 4 months, B withdraws half of his capital . How should they share the profits at the end of the 18 months?	Choose the correct choice from the following answers:	A) 18:11	B) 18:15	C) 18:19	D) 18:121	E) 18:112

Solution: A invests Rs.8000 for 18 months, but B invests Rs.8000 for the first 4 months and then withdraws Rs.4000. So, the investment of B for remaining 14 months is Rs.4000 only.   18:11 : B   8000*18 : (8000*4) + (4000*14)   14400 : 88000   18:11:B = 18:11.18:11nswer:18:11
Answer: A
4 mat-weaves can weaves 4 mats in 4 days.At the same rate,how many mats would be woven by 8 mat-weaves in 8 days ?  Choices:
A) 4 B) 8 C) 12 D) 16 E) 17

Solution: Solution   Let the required number of mats be x.   More weaves,More mats (Direct Proportion)   More days,More mats (Direct Proportion)   ∴ 4 × 4 × x = 8 × 8 × 4 ⇔ x = (8x8x4)/(4x4)= 16. Answer 16
Answer: D
When positive integer x is divided by positive integer y, the remainder is 8. If x/y = 76.4, what is the value of y? Select:
A) 20 B) 22 C) 23 D) 24 E) 25

Solution: When positive integer x is divided by positive integer y, the remainder is 8 --> x=qy+8;   x/y=76.4 --> x=76y+0.4y (so q above equals to 76);   0.4y=8 --> y=20.   20nswer: 20.
Answer: A
A Bell Curve (Normal Distribution) has a mean of − 1 and a standard deviation of 1/8 . How many integer values V are within three standard deviations of the mean?  Choose the correct choice from the following choices:  A) 0  B) 1  C) 3  D) 6  E) 7

Solution: Got the question correctly -- the second item -- [highlight]bthe list of elements in the set is required.[/highlight] is not required.   With the new information, there is only one integer value (-1) that is between (-1.375, -0.625) i.e., falls within the three 3 SD range.1
Answer: B
If the number of 89n,870, where n represents the thousands digit, is a multiple of 9, then the value of n could be which of the following?	Choose the correct option.
A) 0
B) 1
C) 3
D) 4
E) 6

Solution: Divisibility rule of 9: The sum of the digits must be divisible by 9   i.e 8+9+n+8+7+0 = multiple 9   or, 32 + n = multiple of 9.   If n=4, 32 + n =36,which is a multiple of 9.   Hence answer is 4.
Answer: D
5% people of a village in Sri Lanka died by bombardment, 15% of the remainder left the village on account of fear. If now the population is reduced to 3443, how much was it in the beginning?
Choices:
A) 4264
B) 2776
C) 4400
D) 2871
E) 881

Solution: X * (95/100) * (85/100) = 3443   X = 4264   4264nswer:4264
Answer: A
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Pick
A) 177 m  B) 166 m  C) 776 m  D) 150 m  E) 176 m

Solution: Speed=(60 * 5/18) m/sec   = (50/3) m/sec Length of the train   = (Speed x Time)   = (50/3 * 9)= 
(50/3 * 9) = 150
150 m.   Answer:150 m
Answer: D
If r = 2^4 * 5^2 * 7 and s = 2 * 3^2 * 5, which of the following is equal to the greatest common divisor of r and s?	Select
A) 2 * 5 B) 2^2 * 5 C) 2^3 * 5^2 D) 2*3*5*7 E) 2^3 * 3^2 * 5^2 * 7

Solution: GCD = product of prime factors raised to the least power = 2 * 5   The answer is 2 * 5.
Answer: A
A company produces 72000 bottles of water everyday. If a case can hold 10 bottles of water .How many cases are required by the company to hold its one day production  Choose the correct answer:
A) 2000  B) 4500  C) 5000  D) 7200  E) 9000

Solution: Number of bottles that can be held in a case =10   Number of cases required to hold 72000 bottles = 72000/10= 
72000/10 = 7_200
7200 cases.   So the answer is 7200=7200
Answer: D
For any integer n greater than 1, [n denotes the product of all the integers from 1 to n, inclusive. How many prime numbers are there between [6 + 2 and [6 + 6, inclusive?  Pick:
A) None  B) One  C) Two  D) Three  E) Four

Solution: Given that [n denotes the product of all the integers from 1 to n, inclusive so, [6+2=6!+2 and [6+6=6!+6.   Now, notice that we can factor out 2 our of 6!+2 so it cannot be a prime number, we can factor out 3 our of 6!+3 so it cannot be a prime number, we can factor out 4 our of 6!+4 so it cannot be a prime number, ... The same way for all numbers between 6*+2=6!+2 and 6*+6=6!+6, inclusive. Which means that there are no primes in this range.   Nonenswer: None
Answer: A
The present worth of a bill due sometime hence is Rs. 1100 and the true discount on the bill is Rs.110.Find the banker's discount and the banker’s gain?
Choose the correct choice from the following:	A) Rs.111	B) Rs.120	C) Rs.121	D) Rs.125	E) None

Solution: Solution   T.D	=	√P.W x B.G   B.G	= (T.D)² / P.W   = Rs(110x110/1100)   = Rs.11.   B.D	= (T.D + B.G)   = Rs(110+11)   = Rs.121.   Answer Rs.121
Answer: C
The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum.  Pick one
A) Rs.18000
B) Rs.17000
C) Rs.18500
D) Rs.17500
E) None of these.

Solution: The simple interest for the first year is 10200/2 is Rs.5100 and compound interest for first year also is Rs.5100. The compound interest for second year on Rs.5100 for one year   So rate of the interest = (100 * 1530)/ (5100 * 1)= 
(100 * 1530)/ (5100 * 1) = 30
30% p.a.   So P= (100 * 10200)/ (30 * 2) = Rs.17000   ANSWER:Rs.17000
Answer: B
The marks obtained by Polly and Sandy are in the ratio 4:5 and those obtained by Sandy and Willy are in the ratio of 5:2. The marks obtained by Polly and Willy are in the ratio of...? Answers.
A) 2:1 B) 3:2 C) 4:3 D) 5:4 E) 6:5

Solution: Polly : Sandy = 4:5   Sandy : Willy = 5:2   Polly : Sandy : Willy = 4:5:2   Polly : Willy = 4:2 = 2:1   The answer is 2:1.
Answer: A
A bus trip of 550 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip?  Select the correct option.
A) 40
B) 45
C) 50
D) 55
E) 60

Solution: The time is the distance/speed. The time difference is 1 hour.   550/V - 550/(V+5) = 1   550(V+5) - 550V = (V)(V+5)   2750 = (V)(V+5)   50*55 = (V)(V+5)   V = 50 mph   The answer is 50.
Answer: C
If q is an integer greater than 6, which of the following must be divisible by 3? Select
A) Q(Q+1)(Q-4) B) N(N+2)(N-1) C) N(N+3)(N-5) D) N(N+4)(N-2) E) N(N+5)(N-6)

Solution: Now take Q = 3k , Q = 3k+1 Q = 3k+2..put in all the choices. If by putting all the values of Q we get it is divisible by 3, then it is correct answer choice.   A is correct. It will hardy take 10 sec per choice as we have to consider only 3k+1 and 3k+2.
Answer: A
In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m? Choose the correct option.
A) 122.9 m B) 127.5 m. C) 122.2 m D) 222.9 m E) 12289 m

Solution: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.   When B runs 900 m, distance that C runs = (900 * 700)/800   = 6300/8= 
6300/8 = 1_575/2 = around 787.5
787.5 m.   In a race of 1000 m, A beats C by   (1000 - 787.5)= 
  (1000 - 787.5) = 212.5
212.5 m to C.   In a race of 600 m, the number of meters by which A beats C= (600 * 212.5)/1000= 
(600 * 212.5)/1000 = 127.5
127.5 m.   Answer:127.5 m.
Answer: B
How many integers are between 7 and 120/9, inclusive?	Select
A) 5
B) 6
C) 7
D) 9
E) 10

Solution: 120/9 = 13.xx   We are not concerned about the exact value of 120/9 as we just need the integers.   The different integers between 7 and 120/9 would be 7, 8, 9, 10, 11, 12,13   Total number of integers = 7   Option 7
Answer: C
The salary of a worker is first increased by 15% and afterwards reduced by 15%. What is the net change in the worker's salary?
Choose the correct choice
A) 5.25% increase  B) 5.25% decrease  C) 2.25% increase  D) 2.25% decrease  E) no change

Solution: Let x be the original salary.   The final salary is 0.85(1.15x) = 0.9775x   The answer is 2.25% decrease.
Answer: D
In x-y plane, there is a right triangle ABC (∠B=90o). If the length of AC is 25 and the slope of line segment AC is 4/3, what is the length of AB?	Select:
A) 12 B) 18 C) 20 D) 28 E) 40

Solution: Slope = 20hange in Vertical Direction/20hange in Horizontal Direction = 4/3   20hange in Vertical Direction = 4x = AB   20hange in Horizontal Direction = 3x = B20   AB^2 + B20^2 = 25^2   16x^2 + 9x^2 = 625   25x^2 = 625   x^2 = 25   x = 5   Therefore AB = 5*4= 
5*4 = 20
20   Answer: 20
Answer: C
An express traveled at an average speed of 120 km/hr, stopping for 3 min after every 90 kn. How long did it take to reach its destination 600 km from the starting point? Options
A) 5 hrs 21 min	B) 4 hrs 21 min	C) 6 hrs 41 min	D) 5 hrs 15 min	E) 4 hrs 34 min

Solution: D   6 hrs 21 min   Time taken to cover 600 km = 600/120= 
600/120 = 5
5 hrs.   Number of stoppages= 600/90 - 1 = 5   Total time of stoppages = 3 * 5= 
3 * 5 = 15
15 min   Hence, total time taken= 5 hrs 15 min.
Answer: D
The set X = {10,11,12,13}. The set Y = {2,3,4,5}. We will randomly choose one element x from set X and one element y from set Y. What is the probability that x / y will be an integer?
Choices:	A) 9/16	B) 7/16	C) 5/16	D) 5/8	E) 3/8

Solution: The total number of x and y pairs is 4*4= 
4*4 = 16
16.   There are five pairs such that x / y is an integer.   The probability that x / y is an integer is 5/16.   The answer is 5/16.
Answer: C
A passenger sitting near the window in a train moving at 45 km/h, noticed that it took 3 sec. for the oncoming train to pass by. What was the speed of the oncoming train if the length of the oncoming train was 75 metres?	Choose the correct choice from the following options.
A) a)50km/h	B) b)52km/h	C) c)45km/h	D) d)60km/h	E) e)70km/h

Solution: im getting A   3 secs to pass a 75 mts train , therefore speed = 25 meters/sec   to convert m/s to km/hrs multiply by 3.6   25*3.6= 
25*3.6 = 90
90   so its  90-45= 
 90-45 = 45
45 .   c)45km/h
Answer: C
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest?
Choices:
A) 3.5 years  B) 4 years  C) 4.5 years  D) 5 years  E) 5.5 years

Solution: Time = (100 x 81)/(450 x 4.5) = 4 years.   Answer: Option 4 years
Answer: B
Find last two digits of the following expression (201*202*203*204*246*247*248*249)^2	Choose the correct choice from the following options.
A) 33Q76	B) 76	C) 20	D) 27	E) 200

Solution: To find the last two digits of a product take the last two digits in each number and multiply. 01*02*03......48*49 (use onscreen calculator)   this gives 76. So 762762 = 576 So last two digits are 76   Answer:76
Answer: B
In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of four metre is left from all sides of the boundary of the garden. What is the length of the garden? Choose the correct choice from the following:
A) 22
B) 24
C) 26
D) 28
E) 30

Solution: Between the 12 mango trees, there are 11 gaps and each gap has 2 meter length   Also, 4 meter is left from all sides of the boundary of the garden.   Hence, length of the garden = (11 Ã— 2) + 4 + 4 = 30 meter   Answer is 30.
Answer: E
A work can be finished in 16 days by 30 women. The same work can be finished in 10 days by sixteen men. The ratio between the capacity of a man and a woman is	Choices:
A) 3:1
B) 4:3
C) 2:3
D) 2:1
E) 2:4

Solution: Work done by 30 women in 1 day = 1/16   Work done by 1 woman in 1 day = 1/(16×30)   Work done by 16 men in 1 day = 1/10   Work done by 1 man in 1 day = 1/(10×16)   Ratio of the capacity of a man and woman =1/(10×16) : 1/(16×30) = 1/10 : 1/30   = 1/1 :1/3 = 3:1   Option 3:1
Answer: A