MU-NLPC/Calc-aqua_rat huggingface dataset:
The size of the obtuse angle of a rhombus is twice the size of its acute angle. The side length of the rhombus is equal to 10 feet. Find its area. Choose the correct choice from the following answers.
A) 90.56 ft.sq	B) 87.5 ft.sq	C) 86.6 ft.sq	D) 75.85 ft.sq	E) 92.52 ft.sq

Solution: A rhombus has 2 congruent opposite acute angles and two congruent opposite obtuse angles. One of the properties of a rhombus is that any two internal consecutive angles are supplementary. Let x be the acute angle. The obtuse angle is twice: 2x. Which gives the following equation.   x + 2 x = 180 degrees.   Solve the above equation for x.   3x = 180 degrees.   x = 60 degrees.   We use the formula for the area of a triangle that uses the side lengths and any one of the angles then multiply the area by 2.   area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)   = 86.6 feet square (rounded to 1 decimal place)   Answer is 86.6 ft.sq
Answer: C
Anand starts from a point P towards point Q, where PQ = 100 km. After 1 hour, Ram starts from P and catches up with Anand after 2 more hours. After meeting they continue to travel towards Q. On reaching Q, Ram reverses his direction and meets Anand 6 hours after the first meeting. Find Anand's speed. Options.
A) (45/7) kmph B) (60/7) kmph C) (40/7) kmph D) (30/7) kmph E) (200/21) kmph

Solution: Let the first meeting point be at a distance of x km from P, the remaining distance until Q would be (100-x) km   Anand traveled this x kms in 3 hours, making his speed x/3 kmph   Ram traveled the same x kms in 2 hours, making his speed x/2 kmph   So, in 6 hours:   Anand will cover=6x/3=2x km   Ram will cover6 /3= 
6 /3 = 2
2x km   Ram will cover=6x/2=3x km   And between their first meeting point and second, they both together covered a distance of 2(90-x) km.   2x+3x6 /2= 
6 /2 = 3
3x km   And between their first meeting point and second, they both together covered a distance of 2(90-x) km.   2x+3x=2(100-x)   5x=200-2x   7x=200   x=200/7 km   Anand's speed=x/3=200/(3*7)=200/21 kmph   Ans:(200/21) kmph
Answer: E
Of the b students at a certain college, x are studying French and y are studying German. If w are studying both French and German, which of the following expresses the number of students at the college not studying either French or German ? Options:  A) b + w- x- y  B) b - w- x- y  C) b- w - x + y  D) w + x + y- z  E) w - x - y - z

Solution: {Total} = {French} + {German} - {Both} + {Neither}   b = x + y - w + {Neither}   {Neither} = b + w - x - y.   b + w- x- ynswer: b + w- x- y.
Answer: A
The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?  Choose one:  A) 28  B) 27  C) 15  D) 19  E) 12

Solution: Total members in the group = 7   Average amount = Rs. 20   Total amount with them = 7 * 20 = Rs. 140   One number has Rs. 50. So, the amount with remaining 6 people = 140 - 50 = Rs. 90   The average amount with them = 90/6 = Rs. 15.   Answer: 15
Answer: C
If (55^55+55) is divided by 56, then the remainder is:?	Choices
A) 54 B) 55 C) 53 D) 56 E) 57

Solution: Solution: (x^n+1) is divisible by (x+1), when n is odd.   .'. (55^55+1) is divisible by   (55+1)= 
  (55+1) = 56
56. when (55^55+1)+54 is divided by 56,   the remainder is 54.   54nswer 54
Answer: A
If 3^z is a factor of 30!, which of the following could be the value of z?  Answers
A) 10  B) 12  C) 13  D) 14  E) 16

Solution: 3^z is a factor of 30!, what values can z take.   Powers of 3 in 30! = [30/3] + [30/9] +[30/27] , where [x] is the integral part of x   Powers of 3 in 30! = 10 + 3 + 1= 
10 + 3 + 1 = 14
14   Hence the maximum value of 3^z in 30!= 3^14   Correct Option: 14
Answer: D
161?85?65?89=100
then use + or - in place of ? and take + as m,- as n then find value of m-n
Choose the correct answer
A) 3  B) -1  C) 1  D) -3  E) 2

Solution: 161-85-65+89= 
161-85-65+89 = 100
100   so m=1, n=2 => (m-n)=-1   ANSWER:-1
Answer: B
A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train?
Choices:
A) 36 B) 77 C) 54 D) 33 E) 99

Solution: D = 100 + 125= 
100 + 125 = 225
225   T= 15   S = 225/15 * 18/5= 
225/15 * 18/5 = 54
54 kmph   Answer: 54
Answer: C
The speed of a car is 20 km in the first hour and 30 km in the second hour. What is the average speed of the car?  Choose one:
A) 25 kmph	B) 85 kmph	C) 34 kmph	D) 23 kmph	E) 45 kmph

Solution: S = (20 + 30)/2= 
(20 + 30)/2 = 25
25 kmph   25 kmphnswer:25 kmph
Answer: A
The ratio between the number of sheep and the number of horses at the Stewart farm is 5 to 7, If each horse is fed 230 ounces of horse food per day and the farm needs a total 12,880 ounces of horse food per day, what is the number of sheep in the farm?	Choose the correct choice from the following choices:  A) 18  B) 28  C) 40  D) 56  E) 60

Solution: Let the number of sheeps and horses be 4x and 7x.   Now total number of horses = total consumption of horse food/consumption per horse = 12880/230= 
12880/230 = 56
56, which is equal to 7x.=> x = 8   Sheeps = 5x = 5*8= 
5*8 = 40
40. Hence 40.
Answer: C
In a Question paper there are 3 multiple choice questions. Each question has 4 choices with only one choice as the correct answer. What is the total number of ways in which a candidate will not get all the 3 answers correct?
Options
A) 19  B) 85  C) 63  D) 54  E) 64

Solution: A candidate can answer the test in 4^3 number of ways (each question has 4 choices and we have total of 3 questions). Now, out of these cases there will be only one case when the candidate answered all the four questions correct. Therefore the total number of ways in which a candidate will NOT get all the four answers correct is 4^3-1=63.   Answer: D.
Answer: C
An inspector rejects 0.08% of the meters as defective, How many meters he examine to reject 2 meteres  Pick one
A) 1200 B) 2400 C) 1400 D) 2500 E) None of these

Solution: Explanation:   It means that 0.08% of x = 2   =>(8/ 100×100×x)=2=>x=2×100×100/ 8=>x=2500   Option 2500
Answer: D
7^6n -1^ 6n When n is an integer > 0 is divisible by Choose the correct choice from the following:
A) 119 B) 127 C) 134 D) 145 E) 154

Solution: 127   127
Answer: B
Henry professes to sell his goods at the cost price but he made use of 750 grams instead of a kg, what is the gain percent?  Choose the correct choice from the following options:
A) 12 1/3% B) 13 1/3% C) 14 1/3% D) 15 1/3% E) 16 1/3%

Solution: 750 --- 100   100 --- ? => 13 1/3%   Answer:13 1/3%
Answer: B
After doing 3/5 of the Biology homework on Monday night, Sanjay did 1/3 of the remaining homework on Tuesday night. What fraction of the original homework would Sanjay have to do on Wednesday night to complete the Biology assignment ? Choose the correct choice.
A) 1/15  B) 2/15  C) 4/15  D) 2/5  E) None of these

Solution: Sol.(c) Remaining homework on Monday night   = 1 - (3/5) = 2/5   Work done on Tuesday night   = 1/3 of 2/5 = 2/15   Remaining homework to complete the biology assignment   = 2/5 - 2/15 = (6 - 2)/15 = 4/15   Answer 4/15
Answer: C
In one hour,a boat goes 16 km along the stream and 6 km against the stream.The speed of the boat in still water (in km/hr) is :
Options
A) 3 B) 11 C) 8 D) 9 E) 10

Solution: Solution   Speed in still water =1/2(16+6)kmph.= 11 kmph. Answer 11
Answer: B
The average score in an examination of 10 students of a class is 55. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 40 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is Choose the correct choice from the following answers:	A) 97	B) 99	C) 98	D) 96	E) 94

Solution: The average score in an examination of 10 students of a class is 55 --> the total score = 10*55= 
10*55 = 550
550;   The 5 smallest scores have an average of 50 --> the total score of the 5 smallest scores= 250.   From above, the total score of the 5 largest scores = 550 - 250= 
550 - 250 = 300
300.   Say the 5 largest scores are a, b, c, d, and e (where a<b<c<d<e, since each of the top five scorers had distinct scores). We want to maximize e. To maximize e, we need to minimize a, b, c, and d. The least value of a, is 50 (The least score of the top 5 , a, should be equal to the highest of the bottom 5 and to minimize the highest of the bottom 5, all scores from the bottom 5 should be equal). In this case the least values of b, c, and d are 56, 57, and 58 respectively:   a + b + c + d + e= 50 + 51 +52 + 53 + e = 300;   e = 94.   Answer: 94.
Answer: E
A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time C it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?	Choose the correct choice from the following:  A) 0.8(80 – y)  B) 0.8 + 0.0025y  C) 80/y – 1.25  D) 80/1.25y  E) 80 – 0.25y

Solution: This may be a case of bad numberpicking but it worked for me.   80 houses. Let's say that y=40 houses are painted at the rate x=10 houses per week <=> 1/10 week per house. 40*1/10 = 4 houses per week will be painted at this rate.   80-y = 80-40= 
80-40 = 40
40 houses are to be painted at the faster rate. X*1,25=12,5 houses per week <=> 1/12,5 weeks per house * 40 houses = 40/12,5 = 80/25 = 320/100 = 3,2 weeks.   Which means finishing all houses at normal rate C=> 2*4= 
2*4 = 8
8 weeks. Faster rate= 4+3,2 = 7,2 weeks.   7,2/8 = 9/10 = 0,9. Insert y=40 in equations and it is clear that only (0.8 + 0.0025y) gives us 0,9.
Answer: B
X can finish a work in 21 days. Y can finish the same work in 15 days. Yworked for 10 days and left the job. how many days does X alone need to finish the remaining work? Choose the correct choice from the following
A) 3	B) 5	C) 7	D) 8	E) 9

Solution: Work done by X in 1 day = 1/21   Work done by Y in 1 day = 1/15   Work done by Y in 10 days = 10/15 = 2/3   Remaining work = 1 – 2/3 = 1/3   Number of days in which X can finish the remaining work = (1/3) / (1/21)= 
(1/3) / (1/21) = 7
7   7
Answer: C
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold 9 times as many paperback copies as hardback copies were sold. If a total of 436,000 copies of the novel were sold in all, how many paperback copies were sold?	Answers:
A) 45,000  B) 360,000  C) 364,500  D) 392,000  E) 396,900

Solution: Say x was the # of hardback copies sold from the time the first paperback copy was sold.   Then the total # of paperback copies sold was 9x;   Hence the total # of copies sold was (hardback)+(paperback)=(36+x)+(9x)=436 --> x=40.   So, the total # of paperback copies sold was 9x=9*40= 
9*40 = 360
360 or 360,000.   Answer: 360,000.
Answer: B
If Rs. 561 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively?  Choose the correct choice from the following answers.
A) s.300  B) s.360  C) s.396  D) s.368  E) s.323

Solution: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4   A:B = 2:3 and B:C = 1:4 = 3:12   A:B:C = 2:3:12   A;s share = 561 * 2/17 = Rs. 66   B's share = 561 * 3/17 = Rs. 99   C's share = 561 * 12/17 =Rs.396.   Answer:s.396
Answer: C
What is the value of n if the sum of the consecutive odd intergers Y from 1 to n equals 169?
Choose the correct option:
A) 47
B) 25
C) 37
D) 33
E) 29

Solution: Before you tackle this question you must first understand that the question is comprised of two key parts, 1st is finding out how manytermsis in that sequence and 2nd whatactual number valuethat term is. In an arithmetic progression, in this case consecutive odd integers 1, 3, 5, ...., there are two set of rules.   Rule #1 (Arithmetic Sequence): xn = a + d(n-1) Identifies what the actual # in the sequence would be. Each number in the sequence has a term such as 1(is the first term), 3(is the second term) and so on. So if I were to ask you to find out what the 10th term is of that sequence you would use that formula to find that value.   a=1 (first term)   d=2 (the common difference) remember in the sequence 1, 3, 5, 7 the common difference is always 2   *On a side note we use n-1 because we don't have d in the first term, therefore if we were solving for the first term we would get 0 as n-1 and 0 times d would give us 0, leaving only the first term. This works regardless what your first term is in any sequence.   But remember the question asksWhat is thevalueof n if the sum of the consecutive odd integers from 1 to n equals 169?which means we first need a consecutive sequence that sums up to 169 and than find what the value of the n is, in this case it would be the last number in that sequence. In order to find that we first need to knowhow many terms(how many of the n there is) in order to be able to plug n in this formula given we know what the sum is. For that to happen we need to use Rule #2.   Rule #2 (Summing an arithmetic series): 169 = n/2(2a+(n-1)d). Given the question gives us what the sum is (169 in this case) we would simply use this formula to solve for n. Once we solve for n (13 in this case) we can simply plug n into the first formula (rule 1) and find the value.   It feels very confusing and difficult at first, but once you identify the steps all you need to do is plug and play. We have the sum (169) of a sequence, the number of terms in that sequence is (unknown). Rule #2 tells us how many numbers there are in that sequence and Rule #1 gives us what that last term is.
Answer: B
Find the largest 2 digit number which is exactly divisible by 88?  Choose the correct choice from the following
A) 88
B) 89
C) 99
D) 54
E) 90

Solution: Largest 2 digit number is 99   88fter doing 99 ÷ 88 we get remainder 11   Hence largest 2 digit number exactly divisible by 88 = 99 - 11= 
99 - 11 = 88
88   88
Answer: A
A certain sum of money is divided among A, B and C so that for each Rs. A has, B has 65 paisa and C 40 paisa. If C's share is Rs.56, find the sum of money? Options.
A) 288  B) 287  C) 72  D) 205  E) 267

Solution: A:287:C = 100:65:40   = 20:13:8   8 ---- 56   41 ---- ? => Rs.287   Answer: 287
Answer: B
Three partners started a business with Rs. 80000. At the end of the year they receive Rs. 1800. Rs. 3000 and Rs. 4800 as profit. Find the investment of the second person.  Answers: A) Rs. 2700 B) Rs. 40000 C) Rs. 25000 D) Rs. 32000 E) None of these

Solution: Explanation:   The ratio of profit of the three persons   = 1800 : 3000 : 4800 = 3 : 5 : 8   .: investment of the second person = Rs.[(5/16) × 80000]   = Rs. 250000   Answer: Option Rs. 25000
Answer: C
There are 35 students in a hostel. If the no. of students increases by 6, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
Choose the most appropriate option
A) s. 34.83
B) s. 39.83
C) s. 42.83
D) s. 48.83
E) s. 54.83

Solution: Suppose the average join the mess , total expenditure = 35x + 42   Now, the average expenditure = (35x + 42)/ (35 + 6) = x – 1   or, 35x + 42 = 41x – 41   or, x = 13.83   Thus the original expenditure of the mess = 35 x 13.83=484.167   Therefore x-1 = 12.83   hence 42 x 12.83 =539   539 - 484.17 = Rs. 54.83   s. 54.83
Answer: E
if Juan takes 13 seconds to run y yards, how many seconds will it take him to run x yards at the same rate?	Choose the correct choice from the following choices
A) 11x/y
B) 11y/x
C) x/11y
D) 11/xy
E) 13x/y

Solution: Answer is E   The rate of running hards: 13 minutes per y hards.   Thus the time for running x hards = x hards * 13 minutes/y hards = 13x/y
Answer: E
In a survey of political preferences, 78% of those asked were in favour of at least one of the proposals: I, II and III. 50% of those asked favoured proposal I, 30% favoured proposal II, and 20% favoured proposal III. If 5% of those asked favoured all three of the proposals, what Z percentage of those asked favoured more than one of the 3 proposals.
Choose the correct choice:
A) 10
B) 12
C) 17
D) 22
E) 30

Solution: Bunuel, my answer for exactly 2 people was 17 and this was my approach:   100%=(A+B+17)-(AnB+An17+Bn17)-5%+22% which leads me to   Z=100%=(50+30+20)-(at least 2 people)-5%+22%.17
Answer: C
If taxi fares were $8.00 for the first 1/5 mile and $0.8 for each 1/5 mile there after, then the taxi fare for a 8-mile ride was  Select
A) $39.00 B) $39.10 C) $39.25 D) $39.30 E) $39.20

Solution: In 8 miles , initial 1/5 mile charge is $8   rest of the distance = 8 - (1/5) = 39/5   rest of the distance charge = 39(0.8) = $31.2 (as the charge is 0.8 for every 1/5 mile)   => total charge for 4 miles = 8+31.2= 
8+31.2 = 39.2
39.2   Answer is $39.20
Answer: E
A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleable and there are 12 unsaleable mangoes in the crate then how many mango are there in the crate?	Choose the most appropriate option.
A) 480  B) 680  C) 980  D) 280  E) 380

Solution: Let the total no of mangoes in the crate be x   Then the no of bruised mango = 1/30 x   Let the no of unsalable mangoes =3/4 (1/30 x)   1/40 x =12   x=480   480nswer is 480.
Answer: A
A train is moving at 6/7 of its usual speed. The train is 15 minutes too late. What is the usual time (in hours) for the train to complete the journey?
Choose the correct answer:
A) 1  B) 1.5  C) 2  D) 2.5  E) 3

Solution: new time = d / (6v/7) = 7/6 * usual time   15 minutes represents 1/6 of the usual time.   The usual time is 1.5 hours.   The answer is 1.5.
Answer: B
In a certain region, the number of children who have been vaccinated against rubella is twice the number who have been vaccinated against mumps. The number who have been vaccinated against both is twice the number who have been vaccinated only against mumps. If 7,000 have been vaccinated against both, how many have been vaccinated only against rubella?  Options.
A) 2,5000  B) 7,500  C) 10,000  D) 14,000  E) 17,500

Solution: Use a single variable as far as possible.   Number vaccinated only against mumps = x   Number vaccinated against both = 2x = 7000 (so x = 3500)   Then, number vaccinated against mumps (including both) = x + 2x = 3x   Number vaccinated against rubella = 2*3= 
2*3 = 6
6x   Then, number vaccinated against only rubella= 6x - 2x = 4x 6  - 2= 
6  - 2 = 4
4x= 4*3500 = 14,000   Answer (14,000)
Answer: D
A sum of Rs. 2717 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?
Choose the correct choice from the following options: A) 1672 B) 1640 C) 1677 D) 1698 E) 1679

Solution: (x*8*3)/100 = ((2717 - x)*3*5)/100   24x/100 = 40755/100 - 15x/100   39x = 40755 => x = 1045   Second sum = 2717 â€“ 1045 = 1672   1672nswer:1672
Answer: A
An art gallery owner is hanging paintings for a new show. Of the six paintings she has to choose from, she can only hang two on the main wall of the gallery. Assuming that she hangs as many as possible on that wall, in how many ways can she arrange the paintings? Choices
A) 18	B) 30	C) 64	D) 120	E) 216

Solution: Arrangment means permutations questions..   6P2 = 6!/2! = 30.   IMO option 30 is correct answer..
Answer: B
If the average of 8x and 8y is greater than 120, and x is twice y, what is the least integer value of x ?	Select the correct option.
A) 20
B) 25
C) 30
D) 32
E) 42

Solution: Substitution can be used in the following way:   Always start with the equation: x = 2y. It is more straight forward to manage as compared to the inequality.   Substitute y = x/2, not the other way because you need to find the minimum value of x. So you can get rid of y.   Now go on to the inequality. So 8y = 8x/2 = 4x   Now average of 8x and 4x is greater than 120. Average of 8x and 4x is 6x. So,   6x > 120   x > 20   20nswer : 208 /2= 
8 /2 = 4
4x   Now average of 8x and 4x is greater than 120. Average of 8x and 4x is 6x. So,   6x > 120   x > 20   20nswer : 20
Answer: A
Sum of the squares of 3 no.'s is 267 and the sum of their products taken two at a time is 131. Find the sum?
Select.
A) 20  B) 24  C) 26  D) 23  E) 30

Solution: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 267 + 2* 131   a + b + c = √529 = 23   23
Answer: D
A train of 24 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long?
Choose the correct choice from the following answers
A) 7 mins	B) 3 mins	C) 8 mins	D) 9 mins	E) 6 mins

Solution: D = 25 * 60 + 1500= 
25 * 60 + 1500 = 3_000
3000 m   T= 3000/60 * 18/5= 
3000/60 * 18/5 = 180
180 sec= 3 mins   Answer:3 mins
Answer: B
It was Sunday on Jan. 1,2006.What was the day of the week on Jan 1,2010 ?  Choose the most appropriate option.
A) Sunday B) Saturday C) Friday D) Wednesday E) None of these

Solution: Solution   On 31st December,2005 it was Saturday.   Number of odd days from the year 2006 to the year 2009   =(1 + 1 + 2 + 1)= 
(1 + 1 + 2 + 1) = 5
5 days   On 31st December 2009,it was Thursday.   Thus,on 1st Jan,2010 it is Friday. Answer Friday
Answer: C
A 300 meter long train running at the speed of 120 kmph crosses another train running in the opposite direction at the speed of 80 kmph in 9 seconds.What is the lenght of other train. Choose the correct option
A) 210m  B) 220m  C) 230m  D) 240m  E) 200m

Solution: Relative speeds=(120+80)km/hr   =200km/hr=(200*5/18)m/s=(500/9)m/s   let length of train be xm   x+300/9=500/9   x=200   Ans is 200m   ANSW200mR:200m
Answer: E
Pipe A that can fill a tank in an hour and pipe B that can fill the tank in half an hour are opened simultaneously when the tank is empty. Pipe B is shut 10 minutes before the tank overflows. When will the tank overflow? Choose the correct answer:
A) 37 mins  B) 35 mins  C) 40 mins  D) 32 mins  E) 36 mins

Solution: The last 10 minutes only pipe A was open. Since it needs 1 hour to fill the tank, then in 10 minutes it fills 1/5th of the tank, thus 5/6 of the tank is filled with both pipes open.   The combined rate of two pipes is  1 + 2= 
 1 + 2 = 3
3 tanks/hour, therefore to fill 5/6th of the tank they need (time)= (work)/(rate) = (5/6)/3 = 5/18 hours = 27 minutes.   Total time = 10+ 27= 
10+ 27 = 37
37 minutes.   37 minsnswer: 37 mins.
Answer: A
If a car went the first third of the distance at 80 kmh, the second third at 24 kmh, and the last third at 60 kmh, what was the average speed of the car for the entire trip?	Choose the correct option:
A) 36 kmh	B) 40 kmh	C) 42 kmh	D) 42 kmh	E) 50 kmh

Solution: Assume 42 kmh/3 = 240 (this number is convenient because it is divisible by 80, 24 and 60)   So:   240 = 80*T1 = 3 hrs   240 = 24*T2 = 10 hrs   240 = 60*T3 = 4 hrs   T = T1 + T2 + T3 = 17 hrs   42 kmh = RT   (240*3) = R*17   R = 42   ANSWER: 42 kmh
Answer: D
16 people can write 52 book in 12 days working 8 hour a day.then in how many day 206 can be written by 64 people?	Choose the correct choice
A) 309/26
B) 309/28
C) 309/22
D) 319/26
E) 339/26

Solution: work per day epr hour per person= 52/(12*8*16) // eq-1   people= 64; let suppose day=p; per day work for 8 hours   acc. to condition   work per day epr hour per person= 206/(p*8*64) // eq-2   eq-1==eq-2;   p= 309/26   309/26NSWER:309/26
Answer: A
The average age of 18 students of a class is 18 years. Out of these, the average age of 5 students is 14 years and that of the other 9 students is 16 years, The age of the 18th student is
Answers.
A) 101 B) 66 C) 110 D) 160 E) 12

Solution: Explanation:   Age of the 18th student = [18 * 18 - (14 * 5 + 16 * 9)] = (324-214)= 
(324-214) = 110
110 years.   Answer: 110
Answer: C