MU-NLPC/Calc-aqua_rat huggingface dataset:
If x and y are different prime numbers less than ten, what must be true about the sum of x and y?  Options.
A) the sum is even B) the sum is odd C) the sum is less than ten D) the sum is greater than ten E) the sum is less than 13

Solution: This has to be solved by checking for each option:   Prime numbers less that 10 = 2, 3, 5, 7   A. the sum is even   May or may not be true. x = 3, y, = 5 -> True.   x = 2, y = 3 - True   B. the sum is odd   May or may not be true. x = 3, y, = 5 -> False.   x = 2, y = 3 - True   C. the sum is less than ten   May or may not be true x= 5, y = 7, Sum = 12   x = 2, y = 3. Sum = 5   D. the sum is greater than ten   May or may not be true x= 5, y = 7, Sum = 12   x = 2, y = 3. Sum = 5   E. the sum is less than 13   This will always be true.   Maximum sum = 7 + 5= 
7 + 5 = 12
12.   This is always less than 13.   Correct Option: the sum is less than 13
Answer: E
A dealer purchased an article at 3/4 of its list price and sold 50% more than the list price. Find his gain percent?	Choose the correct answer:
A) 180%
B) 190%
C) 100%
D) 170%
E) 900%

Solution: MP = 100   100%P = 75   SP = 150   ------   75 ---- 75   100 ---- ? => 100%   Answer: 100%
Answer: C
A group of 5 fishermen chartered a boat for a day to fish for flounder. The boat costs x dollars per day to rent. If the group can find 3 more fishermen on the docks who are willing to come aboard and share the rental costs, how much less will the rental cost be per person in terms of x? Choose the most appropriate option:
A) x/70	B) x/35	C) 3x/40	D) 3x/10	E) 3x/7

Solution: cost of boat per day = x   cost per person =x/5   if three more persons afre there, cost =x/8   difference = x/5-x/8   =3x/40   Ans 3x/40
Answer: C
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 38 minutes, then the slower pipe alone will be able to fill the tank in  Select the correct option.
A) 144 mins  B) 140 mins  C) 136 mins  D) 152 minw  E) None of these

Solution: Explanation:   Let the slower pipe alone fill the tank in x minutes   then faster will fill in x/3 minutes.   Part filled by slower pipe in 1 minute = 1/x   Part filled by faster pipe in 1 minute = 3/x   Part filled by both in 1 minute =   1/x+3/x=1/38   =>4/x=1/38   x=38∗4=152mins   Option 152 minw
Answer: D
A walks at 10 kmph and 3 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?	Pick one:
A) 100km  B) 150km  C) 60km  D) 120km  E) 200km

Solution: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 3 hours.   x/10 - x/20 = 3   x = 60 km   Answer is 60km
Answer: C
If x is an integer and (x)(x^4)(x^3) is positive, which of the following could be negative?	Choose the correct answer
A) x^4	B) (x)(x^3)	C) (x)(x)	D) x + x^11	E) 3x^2

Solution: A) X^4 - always positive (or 0).   B) X(X^3) = X^4 - Again always positive (or 0).   C) (x)(x) = X^2 - Again always positive (or 0).   D) x+x^11 - Could be -ve if x is -ve.   E) 3X^2 - again always positive (or 0)   Answer x + x^11.
Answer: D
Renu can do a piece of work in 6 days, but with the help of her friend Suma , she can do it in 4 days. In what time Suma can do it alone?	Choose the correct option:
A) 10	B) 12	C) 14	D) 15	E) 17

Solution: Renu’s one day’s work = 1/6   Suma’s one day’s work = 1/4 - 1/6 = 1/12   Suma can do it alone in 12 days.   ANSWER:12
Answer: B
2y - 3x = 2xy and x ≠ 0. If x and y are integers, which of the following could equal y? Choose the correct answer
A) 2 B) 1 C) 0 D) -2 E) 3

Solution: Plug in the answer choices in the equation from the question stem.   A) y = 2 >>> 4-3x = 4x >>> No value of x will satisfy this, not even 0. POE   B) y = 1 >>> 2 - 3x = 2x >>> Same, POE   C) y = 0 >>> -3x = 0 >>> x can not equal 0   D) y = -2 >>> -4 - 3x = -4x >>> Holds true for x = 4, no need to check E. This is the answer.   Answer -2
Answer: D
Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?	Select the correct option.
A) 30 B) 25 C) 15 D) 10 E) 5

Solution: Five kilograms of oranges contained 95% of water. If the next day the concentration of water decreased by 5%, what was the new weight of the oranges, in kilograms?   (A) 30   (B) 25   (C) 15   (D) 10   (E) 5   If B is the answer, then the question means that the concentration of water the newt day became 90%.   Out of 5 kilograms 95%, or 4.75 kilograms was water and 0.25 kilograms was non-water.   The next day, after some water evaporated, oranges became 90% water and 10% of non-water, so the next day 0.25 kilograms of non-water composed 10% of oranges, which means that the new weight of the oranges was x*0.10=0.25 --> x=25 kilograms.   Answer: 25.
Answer: B
The apartment on King-Williams street is an asset that its value is tramping about. From the year 1973 to 1983 it's value decreased by 16% and from 1983 to 1993 it's value increased by 16%. What is the value of the asset in 1993 if in 1973 it was worth $50,000?
Choose the correct choice from the following choices:
A) $48,720 B) $40,000. C) $38,976. D) $39,679. E) $36,796.

Solution: 50,000 *1.16*.84= Unit and tens digit of the expression is 6 and 7 respectively.   Only option $48,720 fulfills the condition and hence is the answer
Answer: A
There are 5 marbles in a bag - 2 are orange and 3 are blue. If two marbles are pulled from the bag, what is the probability W that at least one will be orange?
Choose the correct option:
A) W=7/10  B) W=3/5  C) W=2/5  D) W=3/10  E) 1/10

Solution: Method 1   Probability that at least one out of two marbles will be orange = 1 - Probability that both marbles are blue = 1- P(First marble is blue)*P(Second Marble is Blue) = 1- (3/5)(2/4) = 7/10   Method 2   Probability that at least one marble will be orange = P( First Marble is Orange)*P(Second Marble is Blue) + P (First Marble is Blue)*P(Second Marble is Orange) + P(First Marble is Orange) *P(Second Marble is Orange) = (2/5)*(3/4)*2 + (2/5)*(1/4) = 7/10   Method 3   Probabilty that at least one marble will be orange = 1 - Probability that both marbles are blue   = 1 - (Number of ways 2 blue marbles out of 3 can be pulled)/(Number of ways 2 marbles out of 5 can be pulled)   = 1 - 3C2/5C2   = 1-(3/10) = 7/10   W=7/10nswer :W=7/10
Answer: A
The perimeter of an isosceles right triangle is 14+14 sq rt 2. What is the length of the hypotenuse of the triangle?
Select.
A) 5
B) 6
C) 7
D) 8
E) 9.899

Solution: side of triangle is a then perimeter = a+ a +a.sqrt2 ( right angle and pythagorus) =2a +a .sqrt 2 = 14 + 14 Sqrt2 or,   a. ( 2+ sqrt2) =14(1 + sqrt2), a= 14*(1+sqrt2)/2+sqrt2 =14*2.414/3.414 = then hypotenuse = 9.899   9.899
Answer: E
In a kickball competition of 8 teams, how many possible matches can each team play with each other? Choices
A) 9 B) 16 C) 24 D) 28 E) 54

Solution: 8C2 = 28   Option 28
Answer: D
If k is the sum of the digits of integer m, and m=11n, where n is an integer, which of the following must be true?  Options: A) k is a multiple of 6 B) The sum of the digits of k is divisible by 3 C) m is a multiple of 10k D) k is divisible by 2 E) k is a multiple of 8

Solution: m= 11n i.e n =1,2,3 ,4 etc or -1,-2.-3 ,-4 then m =11,22,33,44 or -11 ,-22 ,-33 ,-44 then k 2,4,6,8 or -(1+1) , -(2+2) , -(3+3) ,-(4+4) .   ans k is divisible by 2
Answer: D
A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 8%. What was its profit on the items sold in February?	Choose the most appropriate option
A) 27.5%	B) 30%	C) 35%	D) 37.5%	E) 38%

Solution: Assume the total price = 100x   Price after 20% markup = 120x   Price after 25%further markup = 1.25*120= 
1.25*120 = 150
150x   Price after the discount= 0.92*150= 
0.92*150 = 138
138x   Hence total profit= 38%   Option 38%
Answer: E
Of the 5 numbers, whose average is 120, the first is one-fourth of the sum of the last 4. The first number is?	Choose the correct choice from the following choices: A) 83 B) 80 C) 50 D) 120 E) 60

Solution: Total of 5 numbers = 5 * 120= 
5 * 120 = 600
600   Let total of last 4 numbers= x   1st number = x/4   x+ x/4 = 600   5x = 2400 => x =480   1st number = 480/ 4= 
480/ 4 = 120
120   Answer :120
Answer: D
A train passes a station platform in 36 sec and a man standing on the platform in 20 sec. If the speed of the train is 54 km/hr. What is the length of the platform?
Pick:
A) 239 B) 240 C) 288 D) 282 E) 238

Solution: Speed = 54 * 5/18= 
54 * 5/18 = 15
15 m/sec.   Length of the train= 15 * 20= 
15 * 20 = 300
300 m.   Let the length of the platform be x m . Then,   (x + 300)/36= 15 => x = 240 m.   Answer: 240
Answer: B
Vijay sells a cupboard at 12% below cost price. Had he got Rs.1650 more, he would have made a profit of 12%. What is the cost price of the cupboard?
Choose the correct choice from the following answers: A) 7450 B) 14900 C) 7400 D) 6875 E) None of these

Solution: Explanation:   Cost price = 1650/(0.12 + 0.12) = 2086/0.24   = Rs.6875   ANSWER 6875
Answer: D
A worker can load one truck in 6 hours. A second worker can load the same truck in 8 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck?  Choose the correct choice:
A) 2.6
B) 2.8
C) 3.0
D) 3.2
E) 3.4

Solution: The workers fill the truck at a rate of 1/6 + 1/8 = 14/48 = 7/24 of the truck per hour.   Then the time to fill one truck is 24/7 which is about 3.4 hours.   The answer is 3.4.
Answer: E
From a bunch of four keys, three particular keys have to be used to open a combination lock, such that the second key can be used only after the first key and the third key can be used only after the second key. What are the chances of opening the lock in a random selection of three keys? Choose the correct choice.
A) 1/24
B) 1/36
C) 1/60
D) 1/80
E) 1/120

Solution: The probability is 1/4*1/3*1/2 = 1/24.   The answer is 1/24.
Answer: A
A contractor is engaged for 30days on the condition thathe receives Rs.25 for each day he works &is fined Rs.7.50 for each day is absent. He gets Rs.360 in all. For how many days was he absent?	Choose the correct answer.
A) 8
B) 12
C) 15
D) 17
E) 19

Solution: 30 * 25= 
30 * 25 = 750
750   360   -----------   380   25 + 7.50= 
25 + 7.50 = 32.5
32.5   390/32.5= 
390/32.5 = 12
12   12
Answer: B
On a certain transatlantic crossing, 10 percent of a ship's passengers held round-trip tickets and also took their cars aboard the ship. If 60 percent of the passengers with round-trip tickets did not take their cars aboard the ship, what percent of the ship's passengers held round-trip tickets?
Choose one:
A) 33 1/3% B) 40% C) 50% D) 25% E) 66 2/3%

Solution: On a certain transatlantic crossing, 20 percent of a ship’s passengers held round-trip tickets and also took their cars abroad the ship. If 60 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship’s passengers held round-trip tickets?   Solution: Let total number of passengers be 100   According to Q stem 40% of passengers who had round-trip tics have taken cars - let number of passengers with round trip be X then   40% of X = 10 => X= 25.   Answer 25%
Answer: D
If a number is subtracted from its square we get 272. Find the number?  Select the correct option:
A) 22  B) 29  C) 17  D) 29  E) 11

Solution: Explanation:   x2 â€“ x = 272 => x =17   Answer: 17
Answer: C
The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 245, what is the difference between the ages of Patrick and Monica? Choose the correct choice:  A) 27  B) 48  C) 80  D) 72  E) 18

Solution: Ages of P and Mi=3x:5x   Ages of Mi and Mo=3x:5x   Rationalizing their ages. ratio of their ages will be 9x:15x:25x   Sum=49x=245   x=5   Difference if ages of Pa and Mo=25x-9x=16x25 -9= 
25 -9 = 16
16x=16*5= 
16*5 = 80
80   Answer 80
Answer: C
What is the next number of the following sequence
108,58,50,8,?	Choose one
A) 40
B) 50
C) 30
D) 42
E) 35

Solution: 108-58= 
108-58 = 50
50   58-50= 
58-50 = 8
8   50-8= 
50-8 = 42
42   therefore next no. is 42   ANSWER:42
Answer: D
In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B the present age of B is	Choose the correct choice from the following options:
A) 37 B) 38 C) 39 D) 40 E) 41

Solution: let present age of A be a and B be b   a+10 = 2*(b-10)   => 2b-a = 30 ......(i)   a = b+9   =>2b-b-9 = 30   b=39   so the present age of b is 39 years   ANSWER:39
Answer: C
A store sells two kinds of birdseed. If brand a is 40% millet and 60% sunflower and brand b is 65% millet and 35% sunflower . A customers purchases a mix of the two types that is 50% millet. What percent is brand A Choose the most appropriate option:	A) 30	B) 40	C) 50	D) 60	E) 70

Solution: Let "a" and "b" be the amount of brand A and brand B respectively in the mixture.   Total amount of the mixture = a+b   Amount of millet in the mixture = 40% of a + 65 % b . This is also equal to 50% of the mixture as per the question i.e (a+b)/2   .4 a + .65 b = (a+b)/2 => .8a +1.3 b = a+b => .3b =.2 a => b =(2/3)a   We have to find the percent of brand A in the total mixture i.e (a/(a+b)) * 100 = (a/(a+(2/3)a))*100 = (3/5)*100= 
(3/5)*100 = 60
60%   ANSWER:60
Answer: D
Stuart bought a sweater on sale for 30% off the original price and another 25% off the discounted price. If the original price of the sweater was $120, what was the final price of the sweater?	Pick one:
A) $25.75  B) $35.75  C) $63  D) $ 45.75  E) $15.75

Solution: The price with 30% off   120 - 30% of 120 = 120 - (30 / 100) *120= 
120 - (30 / 100) *120 = 84
84   The price with another 25% off   84 - 25% of 84= 84 - (25/100)* 84= 
84 - (25/100)* 84 = 63
$63   correct answer $63
Answer: C
The list price of an article is Rs.68. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?	Choices: A) 3.23% B) 4.23% C) 5.23% D) 7.23% E) 8.23%

Solution: 68*(90/100)*((100-x)/100) = 56.16   x = 8.23%   ANSW8.23%R:8.23%
Answer: E
There are 48 people in a certain community who belong to the local golf club, tennis club or both clubs. If twice as many people belong to the tennis club as belong to the golf club, what could be the number of people who belong to both clubs?	Pick one
A) 1) 4 B) 2) 7 C) 3) 17 D) 4) 18 E) 5) 27

Solution: x -> Golf Club   2x -> Tennis Club   y -> both   x+2x-y = 48   3x - y =48   multiples of 3 greater than 48   51   54   57   60   63   66 - 18= 
66 - 18 = 48
48   IMO (4) 18)
Answer: D
A professional janitor can clean a certain high school in 8 hours, working at a constant rate. A student sentenced to detention can clean that same high school in (10*2) hours, also working at a constant rate. If the student is paid $7 total per hour and the janitor is paid $21 per hour, how much more would it cost the school to pay the janitor to do the job himself than it would to pay the student and the janitor to do the job together?	Choose the correct choice from the following choices.
A) -$56  B) -$6  C) $0  D) $6  E) $8

Solution: A professional janitor can clean a certain high school in 8 hours   So (applying rule #1), the janitor can clean 1/8 of the school in ONE HOUR   A student sentenced to detention can clean that same high school in (10*2) or 20 hours   So (applying rule #1), the student can clean 1/20 of the school in ONE HOUR   So, COMBINED, the student and janitor can clean (1/8 + 1/20) of the school in ONE HOUR   1/8 + 1/20 = 5/40 + 2/40 = 7/40   So, in ONE HOUR they can clean 7/40 of the school.   Applying rule #2, it will takethem40/7 hoursto clean the ENTIRE school.   The janitor earns $21/hour and the student earns $7/hour, so their combined rate is$28/hour.   Theircombined wages= (pay rate)(time) = ($28/hour)(40/7 hours) =$160   Working ALON$8, the janitor takes 8 hours and earns $21/hour   So, working alone, the janitor's earnings = (pay rate)(time) = ($21/hour)(8 hours) =$168   $168-$160= $8, so the answer is $8 168- 160= 
 168- 160 = 8
$8, so the answer is $8
Answer: E
If the average (arithmetic mean) of five consecutive integers is k + 2, then the product of the greatest and least integer is
Pick one: A) k^2 - 9 B) k^2 - 2k + 1 C) k^2 + 4k D) k^2 + 6k + 9 E) k^2 + 4k - 12

Solution: n = smallest number   n+4 = largest number   (n + n + 4)/2 = k+2   => (2n+4)/2 = k+ 2   => n + 2 = k + 2   => n = k   So Product of n and n+4 = (k)(k+4)   = k^2 + k   = k^2 + 4k   Answer - k^2 + 4k
Answer: C
If 313,252 football shoes need to be placed in boxes and each box can contain at most 11 pair of football shoes. How many pair of football shoes will be in the last unfilled box?
Options:
Pick one:
A) 5 football shoes
B) 3 football shoes
C) 4 football shoes
D) 7 football shoes
E) 9 football shoes

Solution: The number of football shoes that can be placed in boxes of 11 football shoes is the first number that is divisible by 11 that occurs before 313,252   In order to divide the sum in 11 parts, the amount must be divisible by 11   Divisibility rule of 11: Subtract the last digit from the remaining leading truncated number. If the result is divisible by 11, then so was the first number 313,252->31325-2=>3132-3= 
3132-3 = 3_129
3129->312-9=303->30-3=27   Hence, we need to remove 5 to this number for it to be divisible by 11   Correct Option: 5 football shoes
Answer: A
In the equation ax^2 + bx + c = 0 a, b, and c are constants, and abc # 0. If one root of the equation is -2, and b = 6a then which of the following is c equal to?  Answers
A) a/12  B) a/8  C) 6a  D) 8a  E) 12a

Solution: The sum of the roots is = -b/a = -6a/a = -6. Let the other root be x. Thus, x-2 = -6   x = -4. Again, the product of the roots is   -2*-4= 
  -2*-4 = 8
8. Thus, c/a= 8. c = 8a.   8a.
Answer: D
A car during its journey travels 30 minutes at a speed of 40 kmph, another 45 minutes at a speed of 80 kmph, and 2 hours at a speed of 50 kmph.The average speed of the car is Choose the correct choice from the following answers
A) 60.07 kmph  B) 55.38 kmph  C) 50.02 kmph  D) 44.02 kmph  E) None of these

Solution: First car travels 30 min at speed of 40 kmph   distance = 40 x 1/2 = 20 m   Then car travels 45 min at a speed of 80 kmph   distance = 45 min at speed of 80 kmph   distance = 80 x 3/4 = 60 m   at last it travels 2 hours at speed of 50 kmph   distance = 50 x 2 = 100 m   Total distance = 20 + 60 + 100= 
20 + 60 + 100 = 180
180   Total time= 1/2 + 3/4 + 2= 
1/2 + 3/4 + 2 = 13/4 = around 3.25
3.25   Average speed of the car= 180/3.25 = 55.38   ANSWER:55.38 kmph
Answer: B
A tourist purchased a total of $1,550 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was one more or one less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
Choose the correct option:  A) $1,430  B) $1,320  C) $1,290  D) $1,270  E) $1,150

Solution: since total cashed checks = 7 ans $10 check cashed = one less or more than $50 checks   Therefore either $10 checks = 3 and $50 checks = 4 OR $10 checks = 4 and $50 checks = 3   using this information 1st option gives us the maximum cashed value therefore if we negate this value from total value we will get minimum value of which checks have lost   Therfore   1550 - 230= 
  1550 - 230 = 1_320
1320 hence answer is $1,320
Answer: B
Two persons A and B can complete a piece of work in 40 days and 60 days respectively. If they work together, what part of the work will be completed in 6 days?  Choose the most appropriate option
A) 1/8 B) 1/3 C) 1/6 D) 1/2 E) 1/4

Solution: A's one day's work = 1/40   B's one day's work = 1/60   (A + B)'s one day's work = 1/40 + 1/60 = 1/24   The part of the work completed in 6 days = 6 (1/24) = 1/4.   Answer:1/4
Answer: E
Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat?
Pick one.
A) 5!
B) 8!
C) 9!
D) 11!
E) 12!

Solution: Ans.(B)   Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Answer: B
A trader has 60 kg of rice, a part of which he sells at 14% profit and rest at 6% loss. On the whole his loss is 4% . What is the quantity sold at 14% profit and that at 6% loss?  Choose one.
A) 6 and 54 kg  B) 10 and 40 kg  C) 15 and 35 kg  D) 20 and 30 kg  E) 40 and 30 kg

Solution: 6 and 54 kglligation Method   I P6 and 54 kgRT II P6 and 54 kgRT   14 (x1) -6 (x2)   \ /   x   / \   (x2-x) (x-x1)   2 18   1 9   Ratio of quantities sold at 14% profit and 6% loss = 1: 9   Quantity sold at 14% profit = 60/1+9 *1 = 6 kg   Quantity sold at 6% loss = 60/1+9 *9 = 54kg   6 and 54 kgNSWER:6 and 54 kg
Answer: A
Sum of products of three numbers taken two at a time is 131. Sum of squares of the three numbers is 138. What is the sum of the three numbers?	Choose the correct choice
A) 25
B) 30
C) 20
D) 22
E) 21

Solution: Explanation:   All the data given in the question points to the equation mentioned below:   Considering the three numbers to be a,b and c:   (a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca   Accordingly, substitute for a, b and c and solve:   => a2+b2+c2= 138, ab+bc+ac = 131. Thus, 2(ab+bc+ac)= 2*131= 
2*131 = 262
262   (a+b+c)2= 138+262= 
138+262 = 400
400.   Therefore, a+b+c= 20   ANSWER: 20
Answer: C
What annual payment will discharge a debt of Rs. 1025 due in 2 years at the rate of 5% compound interest?
Select:
A) Rs. 551.29 B) Rs. 551.25 C) Rs. 551.21 D) Rs. 551.22 E) Rs. 551.23

Solution: Explanation:   Let each installment be Rs. x. Then,   x/(1 + 5/100) + x/(1 + 5/100)2 = 1025   820x + 1025 * 441   x = 551.25   So, value of each installment = Rs. 551.25   Answer:Rs. 551.25
Answer: B
P is a prime number. If 6p is between 15 and 95, which of the following Y can be a value of 7p + 2?  Choose the correct choice from the following answers:
A) 15  B) Y=79  C) 121  D) 65  E) 21

Solution: [3,5,7,11,13] are prime numbers that fits this equation 15< 6X <95. Afterwards subtract 2 from all the answer n see if it's divisible by 7. Therefore A and E are out. Leaves out with B C D.   B =11   C =17   D = 9   Only 11 is the set of prime numbers that fit between 15 and 95. Therefore 79 is the answer.Y=79
Answer: B
If a trader sold two cars each at Rs. 325475 and gains 12% on the first and loses 12% on the second, then his profit or loss percent on the whole is?	Choose one:	A) 1.44%	B) 1.74%	C) 1.84%	D) 1.54%	E) 1.24%

Solution: SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.   In this case, there will be loss and percentage of loss is given by   = [(profit%)(loss%)]/100   = (12)(12)/100 % = 1.44%   1.44%nswer:1.44%
Answer: A
Peter rolls three dice at the same time. What is the probability that all the dices will show the same number? Choices.
A) a) 1/12	B) b) 1/36	C) c) 1/6	D) d) 1/36	E) e) 1/3

Solution: We can have 6 different outcomes on a dice.   Total outcomes on two dices = 6*6*6= 
6*6*6 = 216
216   We need only the cases when Peter the same number with all the dices, that means only the outcomes in which the numbers on all three dices are same   They can be {1, 1, 1}, {2, 2, 2}, {3, 3, 3}, {4, 4, 4}, {5, 5, 5}, {6, 6, 6}.   A total of 6 outcomes   Probability= favorable outcomes/ total outcomes = 6/216 = 1/36.   Option d) 1/36
Answer: D
A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. another man leaves the point give at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?  Choose the correct choice from the following options.
A) 7 a.m. B) 10 a.m. C) 9 a.m. D) 3 a.m. E) 6 a.m.

Solution: Explanation:   9 a.m.   Answer: Option 9 a.m.
Answer: C