MU-NLPC/Calc-aqua_rat huggingface dataset:
Richard has to paint a mural with seven horizontal stripes. He only has enough paint for four blue stripes, four white stripes, four black stripes, and four yellow stripes. If his patron wants at most two different colors in the mural, how many different ways can he paint the wall?
Choose the correct choice from the following options:
A) 420  B) 350  C) 700  D) 2,520  E) 5,040

Solution: Number of ways to choose 2 colors among 4 - 4c2   Number of ways that the chosen colors can be painted for 7 horizontal stripes - 2 (either (4,3) or (3,4))   Now the order,   the number of ways in which a particular color among the 2 chosen colors can be painted for 4 stripes is - 7c4   [Note: We don't need to calculate the ways for the remaining 3 stripes as they are obvious and already counted under this]   Total number of combinations - 4c2 * 2* 7c4 = 420   420
Answer: A
The parameter of a square is equal to the perimeter of a rectangle of length 16 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)  Choose one.
A) 28.99  B) 23.52  C) 23.51  D) 23.56  E) 23.57

Solution: Let the side of the square be a cm.   Parameter of the rectangle = 2(16 + 14) = 60 cm Parameter of the square = 60 cm   i.e. 4a = 60   A = 15   Diameter of the semicircle = 15 cm   Circimference of the semicircle   = 1/2(∏)(15)   = 1/2(22/7)(15) = 330/14 = 23.57 cm to two decimal places.Answer:23.57
Answer: E
The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. The S.I. on the same sum for double the time at half the rate percent per annum is?	Answers.
A) Rs.502	B) Rs.500	C) Rs.520	D) Rs.512	E) Rs.132

Solution: Let the sum be Rs. P. Then,   [P(1 + 10/100)2 - p] = 525   P[(11/10)2 - 1] = 525   P = (525 * 100) / 21= 
(525 * 100) / 21 = 2_500
2500   Sum= Rs. 2500   So, S.I. = (2500 * 5 * 4)/100   = Rs.500   Answer: Rs.500
Answer: B
1000 men have provisions for 18 days. If 400 more men join them, for how many days will the provisions last now?  Choices:
A) 12.9
B) 12.8
C) 12.6
D) 12.2
E) 12.1

Solution: 1000*18 = 1400*x   x = 12.8   Answer: 12.8
Answer: B
A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 25 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? Choose the correct choice from the following choices
A) 47.5% B) 44% C) 50% D) 35% E) 38%

Solution: Suppose enrollment in 1991 was 100   Then enrollment in 1992 will be 120   And enrollment in 1993 will be 120*1.25= 
120*1.25 = 150
150   Increase in 1993 from 1991= 150-100= 
150-100 = 50
50   Answer : 50%
Answer: C
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: Answers
A) 21
B) 21/41
C) 21/47
D) 21/45
E) 21/46

Solution: Let S be the sample space and E be the event of selecting 1 girl and 2 boys.   Then, n(S) = Number ways of selecting 3 students out of 25   = 25C3 `   = (25 x 24 x 23)   (3 x 2 x 1)   = 2300.   n(E) = (10C1 x 15C2)   = 10 x (15 x 14)   (2 x 1)   = 1050.   P(E) = n(E) = 1050 = 21 .   n(S) 2300 46
Answer: E
A circular ground whose diameter is 35 metres, has a 1.4 metre-broad garden around it. What is the area of the garden in square metres?	Choices
A) 160.16 B) 6.16 C) 122.66 D) Data inadequate E) None of these

Solution: Req. area = π[(17.5 + 1.4)2 – (17.5)2]   = 22⁄7 × (36.4 × 1.4)[since a2 - b2 = (a + b)(a - b)]   = 22 × 36.4 × 0.2 = 160.16 sq m   160.16nswer 160.16
Answer: A
Last year a certain bond yielded 5 percent of its face value in interest. If that interest was approximately 4 percent of the bonds selling price of $8,000, what is the bonds face value?
Choose one.
A) $6,000 B) $6,750 C) $6,400 D) $7,500 E) $9,375

Solution: Interest = 0.05*face value = 0.04*8,000 --> face value = 0.04*8,000/0.05 = 6,400.   Answer: $6,400.
Answer: C
If 100 microns = 1 decimeter, and 10,000 angstroms = 1 decimeter, how many angstroms equal 1 micron?  Choose the correct option:
A) 100  B) 10  C) 0.01  D) 0.0001  E) 0.0001

Solution: Given that 100 microns = 1 decimeter =10,000 angstroms   So, 1 micron = 10,000/100   =100   100nswer : 100
Answer: A
The product of all the prime numbers less than 15 is closest to which of the following powers of 10 ?	Choose the correct choice from the following choices.
A) 10^9
B) 10^8
C) 10^5
D) 10^6
E) 10^7

Solution: Product of Prime numbers less than 15 is 2*3*5*7*11*13   2*5= 
2*5 = 10
10 .   10*11*3*7*13= 10*10*3*10*10 (approximately) ~ Product will be >10^4 <10^6 i.e. 10^5   10^5 is the answer
Answer: C
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?  Pick one:	A) 33/998	B) 33/91	C) 33/99	D) 33/95	E) 33/92

Solution: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is = ¹²C₄/¹⁵C₄ = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12) =33/91.Answer: 33/91
Answer: B
If the sum of the first n positive integers is S, what is the sum of the first n negative even integers, in terms of S ?
Options: A) S/2 B) S C) 2S D) 2S + 2 E) 4S

Solution: Answer is 2S   Given sum of -1 -2 -3.....-n = S   sum of -2 , -4 , -6 ....-2n = 2[sum(-1 -2 -3....n) ] = 2S
Answer: C
A solution contains 8 parts of water for every 7 parts of Lemonade syrup. How many parts of the solution should be removed and replaced with water so that the solution will now contain 10% lemonade syrup?  Choose the correct choice from the following answers.
A) 1.5  B) 1.75  C) 2.14  D) 2.34  E) 2.64

Solution: Let the total solution is 150 L with 80 L water70 L syrup.   To make 10% syrup solution, the result solution must have 135 L syrup and 15 L syrup.   Therefore we are taking 55 L of syrup from initial solution and replacing with water.   using urinary method:   70 L syrup in 150 L solution   55 L syrup in 117.9 L solution   We started by multiplying 10   Now to get to the result we need to divide by 55 => amount of solution to be replaced with water = (117.9/55) = 2.14.   2.14orrect option : 2.14
Answer: C
12 men take 18 days to complete a job whereas 12 women in 18 days can complete 3â„5 of the same job. How many days will 10 men and 8 women together take to complete the same job?  Select the correct option.
A) 6 B) 13 1â„2 C) 14 3/5 D) Data inadequate E) None of these

Solution: 12 M Ã— 18 = 12 W Ã— 18 Ã— 5/3   \ w = 3/5 M   10M + 8W = 10M + 8 Ã— 3â„5M = 14 4/5 M   \14 4/5 men can complete the same work   in 12Ã—18/14 4/5=14 3/5days   Answer 14 3/5
Answer: C
Yearly subscription to professional magazines cost a company $940.00. To Make a 35% cut in the magazine budget, how much less must be spent?  Choices
A) 654 B) 655 C) 611 D) 657 E) 658

Solution: total cost 940   940*35/100= 
940*35/100 = 329
329   so the cut in amount is 329   the less amount to be spend is  940-329= 
 940-329 = 611
611   ANSWER:611
Answer: C
The entire contents of a full sack of flour can be used to make 15 cupcakes and 8 pizzas. The same full sack of flour can be used to make 9 cupcakes and 14 pizzas. If a full sack of flour is used to make only pizzas, how many pizzas can be made?
Select
A) 18 1/4
B) 18 1/2
C) 18 3/4
D) 19
E) 23

Solution: 15x+8y=9x+14y   x=y. Answer 23
Answer: E
How many two-digit numbers are there whose remainder when divided by 13 is 1, and whose remainder when divided by 6 is 5?  Choose the correct choice from the following:
A) 3	B) 4	C) 5	D) 6	E) 7

Solution: 2 digit numbers whose remainder when divided by 10 is 1 are   11 , 21 , 31 , 41 , 51 , 61 , 71 , 81 , 91   Out of above , numbers whose remainder when divided by 6 is 5 are   11 , 41 and 71   Answer 6
Answer: D
A boat can travel with a speed of 16 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 60 km downstream.  Select the correct option.
A) 2 hours.  B) 3 hours.  C) 4 hours.  D) 5 hours.  E) 6 hours.

Solution: Speed downstream = (16 + 4) km/hr = 20 km/hr.   Time taken to travel 60 km downstream = 60/20= 
60/20 = 3
3 hours.   Answer :3 hours.
Answer: B
The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is	Pick:	A) 22	B) 30	C) 99	D) 38	E) 27

Solution: total age increased = (8 * 2)= 
(8 * 2) = 16
16 years.   Sum of ages of two new men= (21 + 23 + 16)= 
(21 + 23 + 16) = 60
60 years   Average age of two new men= (60/2)= 
(60/2) = 30
30 years.   Answer: 30
Answer: B
Look at this series: XXIV, XX, __, XII, VIII, ... What number should fill the blank?	Choose the correct answer
A) XV
B) XVI
C) XII
D) VII
E) VI

Solution: XVI   XVI   This is a simple subtraction series; each number is 4 less than the previous number.
Answer: B
Rs.160 contained in a box consists of one rupee, 50 paisa and 25 paisa coins in the ratio 4:5:6. What is the number of 25 paisa coins? Choose the correct choice from the following answers:
A) 197
B) 219
C) 120
D) 165
E) 287

Solution: 4x 5x 6x   100 50 25   400x + 350x + 150x = 16000   x = 20   6x =120   Answer: 120
Answer: C
A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number age of the family now is?
Choose the correct choice from the following answers
A) 65  B) 67  C) 87  D) 85  E) 65

Solution: Let the number of wickets taken till the last match be x. Then,   (12.4x + 26)/(x + 5) = 12   = 12.4x + 26 = 12x + 60   = 0.4x = 34   = x = 340/4= 
340/4 = 85
85   Answer: 85
Answer: D
How many seconds will a 500 m long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?	Answers
A) 11 sec B) 30 sec C) 77 sec D) 14 sec E) 12

Solution: Speed of train relative to man = 63 - 3= 
63 - 3 = 60
60 km/hr.= 60 * 5/18 = 50/3 m/sec.   Time taken to pass the man = 500 * 3/50= 
500 * 3/50 = 30
30 sec.   Answer: 30 sec
Answer: B
A woman has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?	Choose one:
A) 80  B) 90  C) 100  D) 110  E) None

Solution: Explanation:   Let number of notes of each denomination be x.   Then x + 5x + 10x = 480   16x = 480   x = 30.   Hence, total number of notes = 3x = 90.   90)
Answer: B
At a reception, one-third of the guests departed at a certain time. Later two-fifths of the guests departed. Even later two-thirds of the remaining guests departed. If six people were left, how many were originally present at the party?  Choose the most appropriate option:	A) 28	B) 37	C) 20	D) 45 people	E) 27

Solution: Explanation:   Let Original members be x   First One third guest departed i.e x/3   Remaining guests = x – (x/3) = 2x/3   Now from the remaining (2x/3) two-fifths departed = 2/5(2x/3) = 4x/15   i.e. Now remaining guests will be (2x/3 – 4x/15) = 2x/5   Now from remaining (2x/5) two-thirds departed = 2/3(2x/5) = 4x/15   Now remaining guests = (2x/5 – 4x/15) = 2x/15   Given 2x/15 = 6 ⇒ x = 45   Answer: 45 people
Answer: D
Three students appear at an examination of Mathematics. The probability of their success are 1/3, 3/4, 1/5 respectively. Find the probability of success of at least two.
Options.
A) 11/30	B) 12/50	C) 13/30	D) 3/50	E) 4/50

Solution: The probability of success of at least two students will involve the following possibilities.   The first two students are successful, the last two students are successful, the first and third students are successful and all the three students are successful.   Therefore, the required probability = 1/3 x 3/4 x 4/5 + 3/4 x 1/5 x 2/3 + 1/3 x 1/5 x 1/4 + 1/3 x 3/4 x 1/5 = 11/30   11/30NSWER:11/30
Answer: A
Find the value of 4 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]  Select the correct option.
A) 800  B) 3200  C) 900  D) 1600  E) None

Solution: Answer   4 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]   = 4 x [(36 x 48 x 250) / (12 x 9 x 5)]   = 4 x 4 x 4 x 50 = 3200   Correct Option: 3200
Answer: B
A drink vendor has 20 liters of Maaza, 144 liters of Pepsi and 368 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required?	Select the correct option:
A) 135
B) 137
C) 142
D) 130
E) 133

Solution: The number of liters in each can = HCF of 20, 144 and 368 = 4 liters.   Number of cans of Maaza = 20/4= 
20/4 = 5
5   Number of cans of Pepsi= 144/4= 
144/4 = 36
36   Number of cans of Sprite= 368/4= 
368/4 = 92
92   The total number of cans required= 5 + 36 + 92= 
5 + 36 + 92 = 133
133 cans.   ANSW133R:133
Answer: E
The ratio of the number of boys and girls in a college is 7:8. If the percentage increase in the number of boys and girls be 20% and 10% respectively. What will be the new ratio?  Choose one.
A) 29:32
B) 21:34
C) 21:22
D) 31:20
E) 21:39

Solution: Originally, let the number of boys and girls in the college be 7x and 8x respectively.   Their increased number is (120% of 7x) and (110% of 8x).   i.e., (120/100 * 7x) and (110/100 * 8x)   i.e., 42x/5 and 44x/5   Required ratio = 42x/5 : 44x/5 = 21:22   Answer: 21:22
Answer: C
nine persons went to a hotel for taking their meals 8 of them spent Rs.12 each on their meals and the ninth spent Rs.8 more than the average expenditure of all the nine.What was the total money spent by them?
Select
A) 132  B) 451  C) 175  D) 145  E) 117

Solution: Sol: Let the average expenditure of all nine be Rs.x   Then 12*8+(x+8)=9x or 8x=104 or x=13.   Total money spent = 9x=Rs.(9*13)=Rs.117.   Ans: 117
Answer: E
(a-b)/(c/2)
In the expression above, a, b, and c are different numbers and each is one of the numbers 1, 2, or 4. What is the least possible value of the expression?
Choose the correct option: A) 1/4` B) 2/4 C) 4/2 D) 1/2 E) 3/4

Solution: (a-b)/(c/2)   = 2(a-b)/c   The expression will have the least value when numerator 2(a-b) is the smallest.   = 2(2-1)/4   =2/4   Answer 2/4
Answer: B
Sum of the squares of three numbers is 138 and the sum of their products taken two at a time is 131. Find the sum? Select
A) 20 B) 25 C) 26 D) 28 E) 29

Solution: (a + b + c)2 = a2 + b2 + c2 + 2(ab +bc + ca) = 138 + 2* 131   a + b + c = √400 = 20   20
Answer: A
A certain manufacturer produces items for which the production costs consist of annual fixed costs totaling $130,000 and variables costs averaging $10 per item. If the manufacturer’s selling price per item is $15, how many items the manufacturer produce and sell to earn an annual profit of $150,000?	Choices:	A) 2,858	B) 18,667	C) 21,429	D) 35,000	E) 56,000

Solution: Let the items manufactured or sold bex   130000+10x = 15x-150000   5x = 280000   x =56000   Ans:56,000
Answer: E
The HCF of two numbers is 40 and the other two factors of their LCM are 11 and 12. What is the largest number.	Options:	A) 462	B) 450	C) 488	D) 480	E) 555

Solution: Explanation:   HCF of the two numbers = 40   HCF will be always a factor of LCM   40 is factor of LCM   other two factors are 11 & 12   Then the numbers are (40 *11) and (40 x 12)   = 440 and 480   Answer: Option 480
Answer: D
The speed at which a man can row a boat in still water is 10 kmph. If he rows downstream, where the speed of current is 2 kmph, what time will he take to cover 60 metres? Options
A) 18 seconds	B) 34 seconds	C) 14 seconds	D) 12 seconds	E) 15 seconds

Solution: Speed of the boat downstream = 10 + 2= 
10 + 2 = 12
12 kmph= 12 * 5/18 = 10/3 m/s   Hence time taken to cover 60 m = 60*3/10= 
60*3/10 = 18
18 seconds.   18 secondsnswer: 18 seconds
Answer: A
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 80 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h, what is the distance traveled by Brad?
Select
A) 16  B) 48  C) 20  D) 24  E) 30

Solution: Time taken = Total Distance / Relative Speed   Total Distance = 80 kms   Relative Speed (Opposite side) (As they are moving towards each other speed would be added ) = 6+ 4= 
6+ 4 = 10
10 kms/hr   Time taken= 80 / 10= 
80 / 10 = 8
8 hrs   Distance traveled by Brad= Brad's speed * time taken = 6 * 8= 
6 * 8 = 48
48 kms... Answer - 48
Answer: B
Find the number of factors of 180 that are in the form (4*k + 2), where k is a non-negative integer?
Pick one:	A) 1	B) 2	C) 3	D) 4	E) 6

Solution: Make sure to follow posting guidelines (link in my signatures). Title of the thread must mention the first few words of the question itself.   As for the question, the most straightforward way is to list out the factors (this is fine for this question as 180 is a relatively small number). Number of factors of 180 (=2^2*3^2*5) = 18. So listing the factors gives us:   1, 180   2, 90   3, 60   4, 45   5, 36   6, 30   9, 20   10, 18   12, 15   As the question asks us about the factors of the form 4k+2 ---> eliminate all ODD factors. You are now left with   2,4,6,10,12,18,20,30,36,60,90,180   For the form 4k+2, the first few values are 2, 6, 10, 14, 18, 22, 26, 30 ... already giving you 5 factors (=2,6,10,18,30). You can stop here and mark 6 (6th one = 90) as the correct answer as 5 is not given.   For checking any particular factor whether they conform to the form 4k+2---> do the following   4k+2 = 36 ---> 4k = 34 --> this will NOT give you an integer value for k ---> reject. Proceed with others until you find all the values asked.   6 is thus the correct answer.
Answer: E
What is the greatest number which divides 29, 32, 38 and leaves same remainder in each case?
Choose one:
A) 2
B) 3
C) 4
D) 5
E) 6

Solution: Explanation:   HCF of differences between given numbers is the required answer   32 - 29= 
32 - 29 = 3
3   38 - 32= 
38 - 32 = 6
6   38 - 29= 
38 - 29 = 9
9   HCF of 3, 6, 9 is 3   Answer: Option 3
Answer: B
How many positive integers will divide evenly into 420?
Choose one
A) 8	B) 12	C) 16	D) 18	E) 20

Solution: 520 = 10*13*4 = 8*5*13 = 2^3*5*13   We need to positive integers will divide evenly into 520 or simply the factors of 520   If a number is of the form 2^a*3^b*5^c,   Total factors = (a+1)(b+1)(c+1)   Therefore, number of factors of 520 = (3+1)*(1+1)*(1+1) = 4*2*2 = 12   Option C12
Answer: B
A student chose a number, multiplied it by 3, then subtracted 138 from the result and got 102. What was the number he chose?	Choose the correct answer:	A) 80	B) 120	C) 130	D) 140	E) 150

Solution: Solution:   Let xx be the number he chose, then   3⋅x−138=102   3x=240   x=80   80nswer 80
Answer: A
Ajay spends 25 per cent of his salary on house rent, 5 percent on food, 10 percent travel, 10 percent on clothes and the remaining amount of Rs.20000 is saved. What is Ajayâ€™s income?  Pick: A) Rs.40000 B) Rs.80500 C) Rs.60700 D) Rs.70500 E) None of these

Solution: Explanation:   Savings = Income â€“ expenditure   100 â€“   (25+5+10+10)= 
  (25+5+10+10) = 50
50%   50% of income= Rs.20000   :. Income = 20000 x 100/50 = Rs. 40000.   Rs.40000nswer: Option Rs.40000
Answer: A
if you invested $25000 and received $35251 after 10 years. what was the interest rate?  Answers:  A) 0.15%  B) 0.25%  C) 0.04%  D) 0.50%  E) 0.40%

Solution: P=25000   I= 35251-25000= 
35251-25000 = 10_251
10251   t=10 years   10251=(25000)(r)(10)   10251=250000r   10251/250000   =.04   ANSW0.40%R:0.40%
Answer: E
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 14 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12	Choose the correct option
A) I only B) II only C) III only D) I and III only E) I, II, and III

Solution: I, II, and III   for 7 we will have mean as 7.16(approx) and median as 7 but for 3 we will have mean and median = 6.5 and for 12 we will have median and mean =8
Answer: E
What is the number of integers from 1 to 1100 (inclusive) that are divisible by neither 11 nor by 35?	Pick:  A) 884  B) 890  C) 892  D) 910  E) 945

Solution: Normally, I would use the method used by Bunuel. It's the most accurate. But if you are looking for a speedy solution, you can use another method which will sometimes give you an estimate. Looking at the options (most of them are spread out), I wont mind trying it. (Mind you, the method is accurate here since the numbers start from 1.)   In 1000 consecutive numbers, number of multiples of 11 = 1000/11 = 90 (Ignore decimals)   In 1000 consecutive numbers, number of multiples of 35 = 1000/35 = 28   Number of multiples of 11*35 i.e. 385 = 1000/385 = 2   Number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - (90 + 28 - 2) {Using the concept of sets here) = 945   Think: Why did I say the method is approximate in some cases?   Think what happens if the given range is 11 to 1010 both inclusive (again 1000 numbers)   What is the number of multiples in this case?   945
Answer: E
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is: Select.
A) 5 : 2
B) 7 : 3
C) 9 : 2
D) 13 : 4
E) 13 : 6

Solution: Let the present ages of father and son be x and y years respectively.   Then (x-10) = 3 (y-10) or   3y-x = 20 ------ (1)   and (x+10) = 2 (y+10) or   x-2y = 10 ----- (2)   (1) + (2) -> y = 30   Substituting y = 30 in equation (1) we get x = 70   Ratio of their ages = 70 : 30 or 7:3   ANSWER:7 : 3
Answer: B
A vendor sold two things at same cost of 15 RS with one item at 25%profit and other at 20%loss,by this transaction he made profit or loss by how much Choose the correct choice
A) 0.65 loss	B) 0.75 loss	C) 0.80 loss	D) 0.55 loss	E) 0.40 loss

Solution: CP when profit of 25% = 12   CP when loss of 20% = 18.75   Total CP = 30.75   Total SP = 30.00   Total loss = 0.75   ANSWER:0.75 loss
Answer: B
If 3 pounds of dried apricots that cost x dollars per pound are mixed with 4 pounds of prunes that cost y dollars per pound, what is the cost, in dollars, per pound of the mixture?  Choose the correct choice.
A) (3x + 4y)/5 B) (3x + 4y)/(x + y) C) (3x + 4y)/(xy) D) 5(3x + 4y) E) 3x + 4y

Solution: Total Cost = Weight(in pounds) * Price/pound;   To find Total cost/pound, Divide by total pounds.   Cost of Dried apricots = 3x;   Cost of prunes = 4y;   Cost per pound = (3x + 4y)/5;   (3x + 4y)/5ns is ((3x + 4y)/5).
Answer: A
What will be the cost of building a fence around a rectangular plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 50?	Choose the correct choice from the following choices.
A) A)Rs.3944  B) B)Rs.3948  C) C)Rs.3519.5  D) D)Rs.3949  E) E)Rs.3923

Solution: Let the side of the rectangle plot be a ft.   a*b = 289 =>1.7 b*b = 289   b = 13.03   a = 22.17   Length of the fence = Perimeter of the plot = 2(a+b) = 70.39 ft.   Rs.3519.5ost of building the fence = 70.39 * 50 = Rs.3519.5   Answer: Rs.3519.5
Answer: C
Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.20 of money? Select the correct option:
A) 1500
B) 1992
C) 9921
D) 2798
E) 2000

Solution: P = 20(100/10)2   => P = 2000   Answer: 2000
Answer: E
What is the last number in a sequence of 5 consecutive integers, given that their sum is 335?
Choose the correct choice from the following:
A) 69
B) 70
C) 68
D) 66
E) 67

Solution: The median is: 335/5= 
335/5 = 67
67. Middle position.   Middle position is also:  5/2= 
 5/2 = 5/2 = around 2.5
2.5, rounded up: 3rd position   3rd position is:  5-3= 
 5-3 = 2
2 positions away from the last position     67 + 2= 
  67 + 2 = 69
69   69nswer: 69
Answer: A