MU-NLPC/Calc-aqua_rat huggingface dataset:
January 1, 2008 is Thursday. What day of the week lies on Jan 1, 2009?	Options:  A) Saturday  B) Wednesday  C) Thursday  D) Tuesday  E) Monday

Solution: Explanation:   Number of odd days in 2008 = 2 (since it is a leap year)   (we have taken the complete year 2008 because we need to find out the odd days from 01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)   Given that January 1, 2008 is Thursday.   Hence January 1, 2009 = (Thursday + 2 odd days) = Saturday   Saturdaynswer: Option Saturday
Answer: A
Robert spent $30 in buying raw materials, $105 in buying machinery and 10% of the total amount he had as cash with him. What was the total amount?	Choose the correct choice from the following answers
A) A)$150	B) B)$210	C) C)$250	D) D)$160	E) E)$200

Solution: Let the total amount be x   then, (100-10)% of x = 30+105   90% of x = 135   90x/100 = 135   x = $150   $150nswer is $150
Answer: A
A and B started a business investing Rs. 60,000 and Rs 45,000 respectively. In what ratio the profit earned after 2 years be divided between A and B respectively? Pick one:
A) 3:2  B) 4 : 3  C) 18:20  D) 1:4  E) 18:4

Solution: A: 4 : 3 = 60000 : 45000 = 4 : 3   ANSWER:4 : 3
Answer: B
AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?  Choose the correct answer
A) 1	B) 3	C) 7	D) 9	E) Cannot be determined

Solution: AB and CD are two digit integers, their sum can give us only one three digit integer of a kind of AAA it's 111.   So, A=1. 1B+C9=111   Now, C can not be less than 9, because no to digit integer with first digit 1 (mean that it's<20) can be added to two digit integer less than 90 to have the sum 111 (if C9<90 meaning C<9 C9+1B<111) --> C=9   Answer: 9.
Answer: D
A certain company reported that the revenue on sales increased 40 % from 2000 to 2003, and increased 90 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005? Pick.
A) 50 % B) 36 % C) 30 % D) 32 % E) 29 %

Solution: Assume the revenue in 2000 to be 100. Then in 2003 it would be 140 and and in 2005 190, so from 2003 to 2005 it increased by (190-140)/140=50/140=~29%.   Answer: 36 %
Answer: B
On dividing 123 by a number, the quotient is 7 and the remainder is 4. Find the divisor. Choose the correct choice from the following answers: A) 15 B) 16 C) 17 D) 18 E) 19

Solution: d = (D-R)/Q   = (123 - 4)/7   = 119/7= 
119/7 = 17
17   17
Answer: C
A can do a work in 6 days , B can do a work in 8 days and C can do it in 12 days. B left work after 6 days. For how many number of days should A and C should work together to complete the remaining work ?  Choices:
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: b work 1/8 * 6=3/4   remaining work =1-3/4=1/4   a and c work together =1/6+1/12=3/12=1/4   take reciprocial 4 * remaining work =4 *1/4= 
4 *1/4 = 1
1   1NSWER:1
Answer: A
David invested certain amount in three different schemes A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme C was 150% of the amount invested in Scheme A and 240% of the amount invested in Scheme B, what was the amount invested in Scheme B?
Pick:
A) Rs.5000	B) Rs.2000	C) Rs.6000	D) Rs.3000	E) Rs.4000

Solution: Explanation :   Let x , y and x be his investments in A, B and C respectively. Then   Then, Interest on x at 10% for 1 year   + Interest on y at 12% for 1 year   + Interest on z at 15% for 1 year   = 3200   x×10×1/100+y×12×1/100+z×15×1/100=3200   ⇒10x+12y+15z=320000−−−(1)   Rs.5000mount invested in Scheme C was 240% of the amount invested in Scheme B   =>z=240y/100=60y/25=12/y5−−−(2)   Rs.5000mount invested in Scheme C was 150% of the amount invested in Scheme Rs.5000   =>z=150x/100=3x/2   =>x=2z/3=2/3×12y/5=8y/5−−−(3)   From(1),(2) and (3),   10x + 12y + 15z = 320000   10(8y/5)+12y+15(12y/5)=320000   16y+12y+36y=320000   64y=320000   y=320000/64=10000/2= 
10000/2 = 5_000
5000   i.e.,Rs.5000mount invested in Scheme B= Rs.5000   Rs.5000nswer : Option Rs.5000
Answer: A
What is the greatest value of n such that 4^n is a factor of 23! ? Pick:
A) 8	B) 4	C) 7	D) 5	E) 9

Solution: Pretty simple, really.   If m = 9, then 4m = 36, which is 18x2, both of which are included in 23!   Since 9 is the largest number here, its the answer.   Answer is 9
Answer: E
In what ratio should a variety of rice costing $6 per kg be mixed with another variety of rice costing $8.75 per kg to obtain a mixture costing $7.50 per kg?	Choose the correct choice from the following answers.
A) 4/7	B) 5/6	C) 5/9	D) 4/8	E) 3/8

Solution: 5/6   5/6   Let us say the ratio of the quantities of cheaper and dearer varieties = x : y   5/6y the rule of allegation, x/y = (87.5 - 7.50) / (7.50 - 6) = 5/6
Answer: B
Pipe A can fill a tank in 6 hours, pipe B in 12 hours and pipe C in 36 hours. If all the pipes are open,in how many hours will the tank be filled ?	Pick one.
A) 3.2	B) 3	C) 3.3	D) 3.5	E) 3.6

Solution: 1/6+1/12+1/36=10/36=1/3.6. so 3.6 hrs   ANSW3.6R:3.6
Answer: E
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. Time required by the first pipe to fill the tank is	Choose the correct choice:
A) 30 hours	B) 15 hours	C) 10 hours	D) 6 hours	E) 7 hours

Solution: Explanation:   Suppose the first pipe alone can fill the tank in x hours. Then,   second pipe alone can fill the tank in (X-5)hours,   third pipe alone can fill the tank in(xâˆ’5)-4=(xâˆ’9)hours.   Part filled by first pipe and second pipe together in 1 hr= Part filled by third pipe in 1 hr   We can not take the value (xâˆ’3)because,(xâˆ’9)becomes negative which is not possible, because the third pipe can fill the tank in(xâˆ’9) hours.   Hence, x=15   ANSWER IS 15 hours
Answer: B
The average of 10 numbers is calculated as 16. It is discovered later on that while calculating the average, the number 55 was incorrectly read as 25, and this incorrect number was used in the calculation. What is the correct average?	Choose the correct choice from the following
A) 17
B) 19
C) 25
D) 31
E) 46

Solution: The total sum of the numbers should be increased by 30.   Then the average will increase by  30/10= 
 30/10 = 3
3.   The correct average is 19.   The answer is 19.
Answer: B
The factorial expression 10!/5! is divisible by which of the following integers?	Choices:  A) 5  B) 31  C) 21  D) 11  E) 19

Solution: 10!/5! => 10 x 9 x 8 x 7 x 6   (5) 5 Can divide 10   (B) 31 None of the Multiplicands present   (C) 21 None of the Multiplicands present   (D) 11 None of the Multiplicands present   (E) 19 None of the Multiplicands present   Hence answer will be (5)
Answer: A
If from a group of 5 people, an old member is replaced by a new one, the average age is same as it was 3 years ago. What is the difference between the ages of the old member and the new one?
Choose the correct option.
A) 12 B) 15 C) 11 D) 18 E) 16

Solution: Explanation:   The present average age is (x + 3) when the old member is present and it equals to x when an old member is replaced by a new one.   The difference in the ages of the old member and the new one is equal to the difference in the total age before and after the replacement = 15 years.   ANSWER: 15
Answer: B
The ratio of the present ages of Sunitha and Vinitha is 4:5. Six years hence the ratio of their ages will be 14:17. What will be the ratio of their ages 12 years hence ?  Choose the correct choice:
A) 15:19
B) 13:15
C) 16:19
D) 17:19
E) 14: 16

Solution: Suppose the present ages of sunitha and vinitha be 4x and 5x years respectively.   six years hence   4x + 6 / 5x + 6 = 14/17   or 68x + 102 = 70x + 84   or x= 9   Ratio of ages of sunita and vinita after 12 years   4x + 12 : 5x + 12 = 48 : 57 = 16 : 19 ANSWER :16:19
Answer: C
A total of 324 coins of 20 paise and 25 paise make a sum of Rs. 71. The number of 25-paise coins is	Select the correct option:
A) 120  B) 124  C) 144  D) 200  E) 220

Solution: Explanation:   Let the number of 20-paise coins be x. Then, number of 25-paise coins = (324 - x).   Therefore 0.20 x x + 0.25 (324 - x) = 71 20x + 25 (324 - x) = 7100   5x= 1000 x = 200. Hence, number of 25-paise coins = (324 - x) - 124.   Answer:124
Answer: B
There are 600 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?  Choose the correct choice from the following answers:  A) 225  B) 257  C) 375  D) 380  E) 390

Solution: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 600. Hence   3x + 5x = 600   Solve for x   8x = 600   x = 75   Number of boys   3x = 3 × 75 = 225   Number of girls   5x = 5 × 75 = 375   375
Answer: C
If a person walks at 15 km/hr instead of 9 km/hr, he would have walked 20 km more. The time traveled by him is? Choose one:
A) 8 hours  B) 9/5 hours  C) 10/3 hours  D) 6 hours  E) 11/3 hours

Solution: Let the actual distance traveled be x km. Then,   x/9 = (x + 20)/15   5x - 3x = 60 =>x = 30 km.   travel time is = 30/9 hours = 10/3 hours   Answer :10/3 hours
Answer: C
A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, C receives:	Options.
A) s. 14,000
B) s. 14,200
C) s. 4,400
D) s. 8,400
E) s. 4,800

Solution: Let C = x.   Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.   So, x + x + 5000 + x + 9000 = 50000   3x = 36000   x = 12000   A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.   C's share = Rs. (35000 x 12/50) = Rs. 8,400.   s. 8,400
Answer: D
A box contains 1 red balls and 5 black balls. One by one, every ball is selected at random without replacement. What is the probability that the fourth ball selected is black? Choices:
A) 1/4	B) 1/2	C) 1/2	D) 5/8	E) 2/3

Solution: My complicated version of your simple approach   Let the 5 black balls be BBBBB and 1 Red Balls be R   They can be arranged in 6 slots _ _ _ _ _ _ _ _   in (6!)/ (5!x1!)   If the fourth slot is Black ball then the arrangement will be to fill   _ _ _ B _ _ _ _   we have 5 slots and 4 Black (BBBB) and 1 Red (R)   They can be arranged in (5!)/ (4!x1!)   Hence required probability = [(6!)/ (5!x1!)]/[(5!)/ (4!x1!)]   =6/5   1/2
Answer: C
How many different ways can a group of 8 people be divided into 4 teams of 2 people each? Pick one:
A) 56 B) 105 C) 75 D) 120 E) 112

Solution: The required answer is = 8!/(4!*2!*2!*2!*2!) = 105   Answer is 105
Answer: B
As part of her MBA program, Karen applied for three different Spring Break outreach projects, each of which selects its students by a random lottery of its applicants. If the probability of her being accepted to each individual project is 60%, what is the probability that Karen will be accepted to at least one project? Pick one.
A) 4/5	B) 19/25	C) 37/50	D) 98/125	E) 117/125

Solution: Since the probability of Karen's being accepted to each individual project is 60%, the probability of her not being accepted to each project is 40%. The probability that she will be accepted to none is, therefore, (2/5)*(2/5)*(2/5)=8/125.   P(Karen will be accepted to at least one project) = 1 - (8/125) = 117/125.   The answer is 117/125.
Answer: E
Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 22 years. What is Deepak present age?	Select the correct option.
A) 22 B) 15 C) 77 D) 266 E) 12

Solution: Present age is 4x and 3x,   => 4x + 6 = 22 => x = 4   So Deepak age is = 3(4) = 12   Answer: 12
Answer: E
An urn contains 4 white 6 black and 8 red balls .Three balls are drawn at random from the bag.the probability that all of them are white are???? Choose the correct choice from the following choices:	A) 4/24	B) 8/24	C) 7/24	D) 1/24	E) 6/24

Solution: 4c3/18c3=4/816=1/24   ANSWER:1/24
Answer: D
If a, b, c, d, e and f are integers and (ab + cdef) < 0, then what is the maximum number A of integers that can be negative?  Choose the correct choice:
A) 2	B) 3	C) 4	D) 5	E) 6

Solution: Minimuum should be 1   Maximum should be 4:   1 out of a or b to make the multiplication negative   3 out of c, d, e or f to make the multiplication negative.   Negative+Negative<0   Answer:C   maximum will be 5..   you dont require both the multiplicatin to be negative for entire equation to be negative...   any one a or b can be negative to make ab negative and it can still be more(away from 0) than the multiplication of 4 other -ve numbers...   actually by writing minimum required as 1 out of 6,you are actually meaning 5 out of 6 also possible as you will see A=5 or 1 will give you same equation..   ans 5
Answer: D
In how many ways the letters of the word MAXICABE be arranged?	Choose the correct answer:  A) 32,230 ways.  B) 20,320 ways.  C) 30,320 ways.  D) 40,320 ways.  E) 42,320 ways.

Solution: Total ways of arranging the letters = 8! = 40,320 ways.   40,320 ways.)
Answer: D
Bill has a small deck of 10 playing cards made up of only 2 suits of 5 cards each. Each of the 5 cards within a suit has a different value from 1 to 5; thus, there are 2 cards in the deck that have the same value. Bill likes to play a game in which he shuffles the deck, turns over 4 cards, and looks for pairs of cards that have the same value. What is the chance that Bill finds at least one pair of cards that have the same value?
Choose the correct answer:
A) 7/15
B) 9/16
C) 11/18
D) 13/21
E) 16/25

Solution: P(no pairs) = 8/9*6/8*4/7 = 8/21   P(at least one pair) = 1 - 8/21 = 13/21   The answer is 13/21.
Answer: D
Six dots are evenly spaced on the circumference of a circle. How many combinations of three dots can we make from these 6 dots that do not form an equilateral triangle?	Choose the correct option
A) 18 B) 17 C) 16 D) 15 E) 14

Solution: The total number of ways we can choose three dots is 6C3=20.   We can form two equilateral triangles from these six dots.   There are  20 - 2= 
 20 - 2 = 18
18 combinations which do not form an equilateral triangle.   The answer is 18.
Answer: A
How many seconds will it take for a car that is traveling at a constant rate of 120 miles per hour to travel a distance of 77 yards?	(1 mile = 1,160 yards)	Choose the most appropriate option:	A) 1.25	B) 1.31	C) 1.58	D) 1.87	E) 2.3

Solution: speed = 120 miles/hr = 58.67 yard/s   distance = 77 yards   time = distance/speed   =77/58.67   =1.31 sec   ans - 1.31
Answer: B
A team of 6 cooks is chosen from 7 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
Choose the correct choice from the following:  A) 140  B) 320  C) 560  D) 455  E) 840

Solution: Only possible combinations are a team of 2M, 4 W or 3M,3W.   Possible ways to make a team of 2M,4W = 7C2 * 5C4 =21*5= 
21*5 = 105
105   Possible ways to make a team of 3M,3W= 7C3* 5C3 = 35*10= 
35*10 = 350
350   Total possible ways= 105+350= 
105+350 = 455
455   Ans 455 it is.
Answer: D
The average of 7 consecutive numbers is 20. The largest of these numbers is :  Options.
A) 22	B) 20	C) 23	D) 21	E) 92

Solution: Explanation:   Let the numbers be x, x + 1, x + 2, x + 3, x + 4, x + 5 and x + 6,   Then (x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6)) / 7 = 20.   or 7x + 21 = 140 or 7x = 119 or x =17.   Latest number = x + 6 = 23.   Answer: 23
Answer: C
mixture contains alcohol and water in the ratio 4 : 3. If 7 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture.	Select the correct option
A) 10
B) 99
C) 5
D) 22
E) 29

Solution: Let the quantity of alcohol and water be 4x litres and 3x litres respectively   28x = 4(3x+5)   16x = 20   x = 1.25   Quantity of alcohol = (4 x 1.25) litres = 5 litres.   Answer: 5
Answer: C
Aman can row 1km upstream in 20 min and back to his starting point in 12 min.How long would he take to row 1km in still water?.  Select the correct option:
A) 12 mins	B) 13 mins	C) 14 mins	D) 15 mins	E) 16 mins

Solution: If his speed is x mtr/min in still water and w mtr/minis speed of water, then   x-w= 1000/20= 
1000/20 = 50
50   x+w= 1000/12= 250/3   adding   2x= 50 + 250/3= 400/3   x=200/3 mtrs/min   time taken to row 1 kms in still water = 1000/(200/3)= 
1000/(200/3) = 15
15 mins.   ANSWER:15 mins
Answer: D
The length of a rectangle is two - fifths of the radius of a circle. The radius of the circle is equal to the side of the square, whose area is 1600 sq.units. What is the area (in sq.units) of the rectangle if the rectangle if the breadth is 10 units?
Choose the correct answer:	A) 140	B) 150	C) 160	D) 170	E) 180

Solution: Given that the area of the square = 1600 sq.units   => Side of square = √1600 = 40 units   The radius of the circle = side of the square = 40 units   Length of the rectangle = 2/5 * 40= 
2/5 * 40 = 16
16 units   Given that breadth= 10 units   Area of the rectangle = lb = 16 * 10= 
16 * 10 = 160
160 sq.units   Answer: Option 160
Answer: C
The length of a rectangular floor is more than its breadth by 200%. If Rs.361 is required to paint the floor at the rate of Rs.3/sq m, what would be the length of the floor?
Select the correct option.
A) 18 B) 19 C) 20 D) 22 E) 24

Solution: Let the length and the breadth of the floor be l m and b m respectively.   l = b + 200% of b = l + 2b = 3b   Area of the floor = 361/3 = 120.33 sq m   l b = 120.33 i.e., l * l/3 = 120.33   l^2 = 361 => l = 19.   19
Answer: B
For the set {2, 2, 3, 3, 4, 4, x}, which of the following values of x will most increase the standard deviation?  Choices.
A) 1	B) 2	C) 3	D) 4	E) (2)^2

Solution: Standard Deviation Step 1, as pointed out by others, is to find out the mean = 3   Step 2, For each number: subtract the Mean and square the result =   (1-3)^2=(-2)^2   (2-3)^2=(-1)^2   (3-3)^2 =(0)^2   (4-3)^2=(1)^2   (5-3)^2=(2)^2   Clearly (1-3)^2=(-2)^2 will give you the greatest value among all the other options.   Hence (2)^2
Answer: E
A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon? Choices:
A) 240	B) 377	C) 269	D) 277	E) 768

Solution: Let xx be the number of kilograms he sold in the morning.Then in the afternoon he sold 2x2x kilograms. So, the total is x+2x=3xx+2x=3x. This must be equal to 360.   3x=3603x=360   x=3603x=3603   x=120x=120   Therefore, the salesman sold 120 kg in the morning and 2⋅120=2402⋅120=240 kg in the afternoon.   240nswer:240
Answer: A
A certain number of persons can finish a piece of work in 100 days. If there were 10 persons less, it would take 10 more days finish the work. How many persons were there originally?
Options.
A) 90 B) 100 C) 110 D) 120 E) None of these

Solution: Explanation :   Assume that x persons can finish a piece of work in 100 days   Also it is given that (x-10) persons can finish a piece of work in 110 days (∵ 100 + 10 = 110)   More persons, less days(indirect proportion)   Hence we can write as   personsx:(x−10)}:: 110 : 100   ⇒ 100x = 110(x − 10)   ⇒ 100x = 110x − 1100   ⇒ 10x = 1100   ⇒ x = 1100/10= 
1100/10 = 110
110. Answer : Option 110
Answer: C
A, B, C enter into a partnership investing Rs. 35,000, Rs. 45,000 and Rs. 55,000 respectively. The respective shares of A, B, C in annual profit of Rs. 40,500 ?
Choose the correct answer:  A) Rs. 10,500, Rs. 13,500, Rs. 16,500  B) Rs. 10,500, Rs. 13,500, Rs. 16,509  C) Rs. 10,500, Rs. 13,500, Rs. 16,506  D) Rs. 10,500, Rs. 13,500, Rs. 16,5065  E) Rs. 10,500, Rs. 13,500, Rs. 16,5012

Solution: A:B:C = 35000 : 45000 : 55000 = 7:9:11   A's share = 40500 * 7/27 = Rs. 10500   B's share = 40500 * 9/27 = Rs. 13500   C's share = 40500 * 11/27 = Rs. 16500   Rs. 10,500, Rs. 13,500, Rs. 16,500nswer: Rs. 10,500, Rs. 13,500, Rs. 16,500
Answer: A
A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by: Choose the correct choice from the following answers
A) 11  B) 5  C) 2  D) 8  E) 4

Solution: Let the ten's digit be x and unit's digit be y.   Then, number 10x + y.   Number obtained by interchanging the digits = 10y + x.   (10x + y) + (10y + x) = 11(x + y)   which is divisible by 11.   11NSWER 11
Answer: A
If x^2 is divisible by 240 what is the least possible value of integer x?  Choices:
A) 120
B) 30
C) 90
D) 60
E) 12

Solution: 240 can be written as (2^4)*3*5.   For x^2 to be divisible by 240 it should contain at least 2^4 and 3 and 5 in its factors. We can leave out option E because 12 doesnt have 5 as one of its factor. Now if we check for option B, 30 can be written as 2*3*5, hence 30^ 2 will have 2 as the maximum power of 2, so we can leave out this option too.   Option D is the right answer if we follow the same method as we followed for other two previous options.   60 = (2^2)*3*5; 60^2 = (2^4)*(3^2)*(5^2). So it shows that 60^2 is divisible by 240 and hence the answer.   Answer : 60
Answer: D
Rs.1210 were divided among 3 person P, Q, R so that P:Q=5:4 and Q: R=9:10. Then R gets the amount.  Choose the correct choice from the following options
A) Rs. 300  B) Rs. 400  C) Rs. 480  D) Rs. 490  E) Rs. 500

Solution: P : Q = 5 : 4, Q : R = 9 : 10 = ( 9 x 4 / 9 ) : ( 10 x 4 / 9 ) = 4 : 40 / 9.   So, P : Q : R = 5 : 4 : 40 /9 = 45 : 36 : 40   Sum of ratio terms is = ( 45 + 36 + 40 )= 
( 45 + 36 + 40 ) = 121
121.   R share of amount is Rs (1210 x 40 / 121)= Rs. 400.   Rs. 400
Answer: B
If $10,000 is invested at x percent simple annual interest for n years, which of the following represents the total amount of interest, in dollars, that will be earned by this investment in the n years? Options.
A) 10,000(x^n) B) 10,000(x/100)^n C) 10,000n(x/100) D) 10,000(1+x/100)^n E) 10,000n(1+x/100)

Solution: The reasoning is from the following:   The formula for simple rate of interest is F = P(1+rt) where   F = future value   P = present value   r = rate   t = time   We can substitute x for r   n for t   and 10,000 in for P   F = 10,000(1+xn)   This formula will tell you the principal (original amount invested) + interest, but we only want interest, so the "1+" portion of the formula in unnecessary. -->   F = 10,000(xn)   Now, we need to get the x into terms of a percentage, so we divide x by 100 -->   F = 10,000(n * x/100)   If we move the n outside the brackets, we get -->   F = 10,000n(x/100)   ANSWER:10,000n(x/100)
Answer: C
A, B, C, D and E are 5 consecutive points on a straight line. If BC = 3CD, DE = 8, AB = 5 and AC = 11, what is the length of AE? Choices: A) 15 B) 17 C) 19 D) 21 E) 23

Solution: AC = 11 and AB = 5, so BC = 6.   BC = 3CD so CD = 2.   The length of AE is AB+BC+C21+21E = 5+6+2+8= 
5+6+2+8 = 21
21   The answer is 21.
Answer: D
A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets $500 more than D, what is D's share? Choose the correct choice from the following answers.
A) $1000
B) $1200
C) $1500
D) $1800
E) $2000

Solution: Let the shares of A, B, C and D be 5x, 2x, 4x and 3x respectively.   Then, 4x - 3x = 500   x = $500   D's share = 3x = 3*$500 = $1500   The answer is $1500.3* 500= 
3* 500 = 1_500
$1500   The answer is $1500.
Answer: C
A particular library has 75 books in a special collection, all of which were in the library at the beginning of the month. These book are occasionally loaned out through an inter-library program. If, by the end of the month, 65 percent of books that were loaned out are returned and there are 54 books in the special collection at that time, how many books of the special collection were loaned out during that month?  Choices:
A) 20
B) 30
C) 35
D) 40
E) 60

Solution: The total number of books is 75.   Let x be the number of books which were loaned out.   65% of books that were loaned out are returned.   35% of books that were loaned out are NOT returned.   Now, there are 54 books, thus the number of un-returned books is 75-54= 
75-54 = 21
21 books.   0.35x= 21   x = 60   The answer is 60.
Answer: E