MU-NLPC/Calc-aqua_rat huggingface dataset:
If 12 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?
Options
A) 127 B) 237 C) 300 D) 450 E) 281

Solution: Explanation:   Let the required no of hectares be x. Then   Men --- Hectares---Days   12---------80---------24   36---------x---------30   More men, More hectares (Direct proportion)   More days, More hectares (Direct proportion)   x=36/12*30/24*80= 
36/12*30/24*80 = 300
300   Answer: 300
Answer: C
The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?  Pick one
A) 75	B) 65	C) 85	D) 95	E) 80

Solution: Total increase in weight = 8 × 2.5 = 20   If x is the weight of the new person, total increase in weight = x−65   => 20 = x - 65   => x = 20 + 65= 
20 + 65 = 85
85   Answer is 85.
Answer: C
X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 36days. How long will Y take to complete the work? Select the correct option:
A) 45
B) 12
C) 15
D) 18
E) 20

Solution: Work done by X in 8days = 8*1/40 = 1/5   Remaining work = 1 - 1/5 = 4/5   4/5 work is done by Y in 36days   Whole work will be done by Y in 36*5/4= 
36*5/4 = 45
45 days   45nswer is 45
Answer: A
Find the value of a/b + b/a, if a and b are the roots of the quadratic equation x2 + 12x + 3 = 0?  Choose the correct choice from the following choices:
A) 6
B) 7
C) 23
D) 17
E) 42

Solution: a/b + b/a = (a2 + b2)/ab = (a2 + b2 + a + b)/ab   = [(a + b)2 - 2ab]/ab   a + b = -12/1 = -12   ab = 3/1= 
3/1 = 3
3   Hence a/b + b/a= [(-12)2 - 2(3)]/3 = 126/3= 
126/3 = 42
42.   42)
Answer: E
By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?
Choose the most appropriate option.
A) 26%
B) 25%
C) 85%
D) 24%
E) 22%

Solution: SP = CP + g   150 SP = 150 CP + 30 SP   120 SP = 150 CP   120 --- 30 CP   100 --- ? => 25%   Answer: 25%
Answer: B
A cylindrical water tower with radius 2.5 m and height 4 m is 3/4 full at noon. Every minute, .08π m3 is drawn from tank, while .03π m3 is added. Additionally, starting at 1pm and continuing each hour on the hour, there is a periodic drain of 4π m3. From noon, how many hours will it take to drain the entire tank?
Choose the correct choice from the following answers:
A) 20 2/7  B) 20 6/7  C) 21  D) 21 3/7  E) 3

Solution: initial volume = (3/4)×∏×2.5²×4 = 18.75∏   Relative Drain/ min = .08∏ - .03∏ = .05∏ m³/min drain   Relative drain / hour .08  - .03= 
.08  - .03 = 0.05
.05∏ m³/min drain   Relative drain / hour= .05∏×60 = 3∏ m³/ hr   Every one hour starting from 1pm, 4∏ m³ of water is drained. It means that only at the hour the water is drained and NOT “in that 1 hour“   So after 1 hr the relative drain would be 3∏ + 4∏ = 7∏m³ of water drain   What i did initially was formed an equation 18.75∏   3  + 4= 
  3  + 4 = 7
7∏m³ of water drain   What i did initially was formed an equation 18.75∏= 7∏×n (n is the number of hrs) so ended up with 2.67. This wrong   Look at this way   after 2 hrs the amount of water drain will be 2.67×7∏ = 14∏ m³   Left over water in the tank after 2 hrs = 3∏ m³   From above we know that it take 1 more hour to drain that 3∏ m³.   So ans is 3hrs   3
Answer: E
Two cars were driven by R and B. They were 580 miles apart when they started driving towards each other.R's car had traveled at a speed of 20 miles per hour, 4 hours per day for 5 days when it had met B's car. If B had driven 3 hours per day for 5 days, what was B's speed in miles per hour?  Choose one.
A) 8  B) 9  C) 10  D) 11  E) 12

Solution: 1. At 20mph for 4 hours a day, then driver R was traveling 80 miles per day. When R met with B, R had already traveled 400 miles.   2. This means that driver B had traveled 580-400= 
580-400 = 180
180 miles upon meeting up with R. B traveled a total of 3 x 5= 15 hours (3hrs/day for 5 days). 180 miles / 15 hours = 12mph   3. Answer 12!
Answer: E
In a certain company, the ratio of the number of managers to the number of non-managers in any department must always be greater than 7 : 24. In the company, what is the maximum number of non-managers in a department that has 8 managers?  Choose the correct choice from the following choices:
A) 26
B) 27
C) 28
D) 29
E) 30

Solution: 8/7 * 24 = 27.4   The answer is 27.
Answer: B
A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it?  Pick
A) 56.27 % B) 56.65 % C) 56.65 % D) 58.25 % E) 52.25 %

Solution: a = 100 a2 = 10000   a = 125 a2 = 15625   ----------------   10000 --------- 5625   100 -------? => 56.25 %   Answer: 56.65 %
Answer: C
The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 196, what is the difference between the ages of Patrick and Monica? Pick:
A) 27
B) 64
C) 45
D) 72
E) 18

Solution: Ages of P and Mi=3x:5x   Ages of Mi and Mo=3x:5x   Rationalizing their ages. ratio of their ages will be 9x:15x:25x   Sum=49x=196   x=4   Difference if ages of Pa and Mo=25x-9x=16x25 -9= 
25 -9 = 16
16x=16*4= 
16*4 = 64
64   Answer 64
Answer: B
A trader mixes 26 kg of rice at Rs. 20 per kg with 30 kg of rice of other variety at Rs. 36 per kg and sells the mixture at Rs. 30 per kg. His profit percent is
Choices
A) No profit, no loss  B) 5%  C) 8%  D) 10%  E) None of these

Solution: C.P. of 56 kg rice = Rs. (26 x 20 + 30 x 36) = Rs. (520 + 1080) = Rs. 1600.   S.P. of 56 kg rice = Rs. (56 x 30) = Rs. 1680.   Gain =(80/1600)x 100	% = 5%.   ANSWER:5%
Answer: B
The present age of a father is 3 years more than three times the age of his son. Three years hence ,father's age will be 10 years more than twice the age of the son , Find the present age of the father.
Choose the correct choice from the following choices.
A) 33 years
B) 35 years
C) 31 years
D) 35 years
E) 40 years

Solution: Explanation :   Explanation :   Sol. Let the son's present age be xx years.   Then , father's present age = (3x+3)(3x+3) years   âˆ´âˆ´ (3x+3+3)=2(x+3)+10(3x+3+3)=2(x+3)+10   â‡” 3x+6 =2x+16â‡” 3x+6 =2x+16   â‡” x=10â‡” x=10   Hence , father's present age = (3x+3)(3x+3) = (3 x 10 + 3) years = 33 years.   33 yearsNSWER IS 33 years
Answer: A
The average of 6 no.'s is 2.80. The average of 2 of them is 2.4, while the average of the other 2 is 2.3. What is the average of the remaining 2 no's? Answers
A) 2.3  B) 2.6  C) 3.6  D) 3.7  E) 4.6

Solution: Sum of the remaining two numbers = (2.80 * 6) - [(2.4 * 2) + (2.3 * 2)]   = 16.80 - (4.8 + 4.6) = 16.80 - 9.40= 
16.80 - 9.40 = 7.4
7.40   Required average= (7.4 / 2)= 
(7.4 / 2) = 3.7
3.7   Answer : 3.7
Answer: D
Mother,her daughter and her grand child weighs 150 kg. daughter and her daughter(child) weighs 60 kg. child is 1/5th of her grand mother. What is the age of the daughter?  Choose the correct choice from the following answers
A) 46 B) 47 C) 42 D) 49 E) 50

Solution: mother + daughter + child = 150kg   daughter + child = 60kg   mother = 150 - 60= 
150 - 60 = 90
90kg   child= 1/5th of mother = (1/5)*90= 
(1/5)*90 = 18
18kg   So now daughter= 120 -(mother + child) = 150 - (90+18)= 
150 - (90+18) = 42
42kg   ANSWER:42
Answer: C
Divide $900 among A,B in the ratio 1:2. How many $ that A get?
Choose the correct choice from the following
A) $50
B) $300
C) $150
D) $250
E) $600

Solution: Sum of ratio terms = 1+2= 
1+2 = 3
3   A= 900*1/3= 
900*1/3 = 300
$300   Answer is $300
Answer: B
The sub-duplicate ratio of 9:25 is  Answers
A) 4:3 B) 1:2 C) 3:5 D) 1:4 E) 2:3

Solution: root(9):root(25)=3:5   ANSWER:3:5
Answer: C
Look at this series: 7, 10, 8, 11, 9, 12, ... What number should come next?	Select the correct option.
A) 10	B) 8	C) 7	D) 9	E) 12

Solution: Alternating addition and subtraction series. in first added second is subtracted.   => 10 is the next one   10NSWER 10
Answer: A
Rs. 6000 is lent out in two parts. One part is lent at 6% p.a simple interest and the other is lent at 10% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest? Choose one.
A) 5:1  B) 5:5  C) 5:8  D) 5:4  E) 5:3

Solution: Let the amount lent at 6% be Rs. x   Amount lent at 10% is Rs. (6000 - x)   Total interest for one year on the two sums lent   = 6/100 x + 10/100 (6000 - x) = 600 - 4x/100   => 600 - 1/25 x = 450 => x = 3750   Amount lent at 10% = 2250   Required ratio = 3750 : 2250 =75:45=15:9=5:3   Answer:5:3
Answer: E
Sara bought both German chocolate and Swiss chocolate for some cakes she was baking. The Swiss chocolate cost $3.6 per pound, and German chocolate cost $3 per pound. if the total the she spent on chocolate was $36 and both types of chocolate were purchased in whole number of pounds, how many total pounds of chocolate she purchased?
Choose the correct choice from the following answers:	A) 7	B) 8	C) 10	D) 15	E) 36/3

Solution: If there were all the expensive ones,3.6...   There would be 36/3.6 or 10 of them but since 3 $ ones are also there, answer has to be >10.....   If all were 3$ ones, there will be 36/3   Ans 36/3
Answer: E
What is the tens' digit W of the sum of the first 40 terms of 1, 11, 111, 1111, 11111, 111111, ...?
Pick: A) W=2 B) W=3 C) 4 D) 8 E) 9

Solution: All of the first 40 terms have 1 at the units place.   Except the first term, the tens digit of all the remaining 39 terms is 1.   So now if you do the addition   1 1   1 1   . . .   . . .   . . .   1 1   0 1   3 0   Answer is W=3
Answer: B
Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?	Choices:
A) Rs. 4, Rs. 23
B) Rs. 13, Rs. 17
C) Rs. 15, Rs. 14
D) Rs. 17, Rs. 13
E) Rs. 19, Rs. 15

Solution: Explanation:   Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.   Then, 2x + 3y = 77 ...(i) and   3x + 2y = 73 ...(ii)   Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.   Putting y = 17 in (i), we get: x = 13.   ANSWER IS Rs. 13, Rs. 17
Answer: B
For each color copy, Print Shop X charges $1.25 and Print Shop Y charges $2.75. How much greater is the charge for 40 color copies at Print Shop Y than at Print Shop X?  Choose the correct choice.
A) $48
B) $54
C) $60
D) $66
E) $72

Solution: The difference in the two prices is $2.75 - $1.25 = $1.50 for each color copy.   Each color copy will cost an extra $1.50 at Print Shop Y.   40*$1.50 2.75 -  1.25= 
2.75 -  1.25 = 1.5
$1.50 for each color copy.   Each color copy will cost an extra $1.50 at Print Shop Y.   40*$1.50 = $60   The answer is $60.40* 1.50= 
40* 1.50 = 60
$60   The answer is $60.
Answer: C
Two trains 150 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet?
Choose the correct choice from the following options:
A) 7.18  B) 7.12  C) 7.16  D) 7.55  E) 7.82

Solution: T = (150 + 165)/ (80 + 65) * 18/5   T = 7.82   Answer:7.82
Answer: E
A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?  Select the correct option.
A) 4
B) 7
C) 6
D) 8
E) 9

Solution: S = 600/40= 
600/40 = 15
15 mps   S= 3600/15= 
3600/15 = 240
240 sec= 4 min   4nswer: 4
Answer: A
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is? Pick
A) 37
B) 50
C) 77
D) 55
E) 22

Solution: Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 45 ==> x   = 50 km/hr.   Answer: 50
Answer: B
How many of the factors of 168 are divisible by 2?
Choose the correct choice from the following answers:	A) 4	B) 8	C) 10	D) 12	E) 16

Solution: 168 = 2^3*3*7   The total number of factors is (1+3)(1+1)(1+1) = 16   The odd factors are 1, 3, 7, and 21.   The number of even factors is 16-4= 
16-4 = 12
12   The answer is 12.
Answer: D
It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 12 minutes, how much time will she spend doing yoga? (rounded to minutes) Pick:
A) 10 min.	B) 41 min.	C) 17 min.	D) 23 min.	E) 20 min.

Solution: The ratio is 2:3 = gym:ride, so (12)(3/2) = 18 minutes at the gym, and   18 + 12= 
  18 + 12 = 30
30 minutes exercise, so (2/3)(30)= 20 minutes yoga.   Answer: 20 min.
Answer: E
A set consist of 2b-1 element. What is the number of subsets of this set which contain at most b-1 elements?	Choose the correct choice from the following answers
A) 2^(2b-2)
B) 2^(2b) - 2
C) 2^(2b) -1
D) 2^(2b)
E) 2^(2b-1)

Solution: I used b=3, so then we have   5!/2!3! + 5!/4!1! + 5!/0!5!    10 + 5 + 1= 
 10 + 5 + 1 = 16
16   So our target is 16   Now replace in answer choices   2^(2b-2) gives us 2^4= 16   Hence 2^(2b-2) is the correct option   Read carefully it says at most so keep in mind that picking a small number such as 3 will help you save time since you have to list fewer outcomes   2^(2b-2)void 2 since you will get 1 arrangement (b-1) and may be risky since 1 is a number with certain unique properties
Answer: A
A man goes from A to B at a speed of 35 kmph and comes back to A at a speed of 28 kmph. Find his average speed for the entire journey?  Select:	A) 38.9 kmph	B) 38.8 kmph	C) 38.1 kmph	D) 37.1 kmph	E) 37.8 kmph

Solution: Distance from A and B be 'd'   Average Speed = total distance/total time   Average Speed = (2d)/[(d/35) + (d/28]   = (2d)/[11d/140) => 38.1 kmph.   Answer:38.1 kmph
Answer: C
If 76 is divided into four parts proportional to 7, 5, 3, 4, then the smallest part is:
Choose one
A) 12	B) 88	C) 27	D) 92	E) 32

Solution: Explanation:   Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.   Smallest part = = 12   12nswer: 12) 12
Answer: A
J is 25% less than P and 20% less than T. T is w% less than P. What is the value of w?  Choose the most appropriate option:	A) 93.5	B) 90	C) 6.75	D) 6.25	E) 2

Solution: Usually We can solve every question of this type by choosing appropriate value of the Variable and deriving the value of other related variables.   Let, P = 400   then J = (75/100)*400= 
(75/100)*400 = 300
300   also J= (80/100)*T   i.e. T = 300*100/80= 
300*100/80 = 375
375   and T= [1-(w/100)]*P   i.e. 100-w = 100*T/P = 100*375/400= 
100*375/400 = 375/4 = around 93.75
93.75   i.e. w= 6.25   Answer: Option 6.25
Answer: D
Bob had x number of sweets and wanted to share it with his 6 friends. However, he could not divide x into 7 parts equally. He also found that he could not divide x equally into 6,5,4,3 or 2 parts either. He decided to throw one sweet away and found that he had enough sweets to divide into 7,6,5,4,3 or 2 equal parts. What is the smallest possible number of x?	Choices.
A) 421 B) 422 C) 423 D) 420 E) 541

Solution: x-1 is lcm of 7,6,5,4,3,2,1 i.e. 420   x-1=420   x=421   421NSWER:421
Answer: A
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P, Q and R respectively. What is the proportion of solution P in the liquid in the tank after 3 minutes?
Choose the correct choice from the following answers.
A) 3/11 B) 2/11 C) 1/11 D) 4/11 E) 1/11

Solution: Part filled by (A + 2/11 + C) in 3 minutes = 3(1/30 + 1/20 + 1/10) = 11/20   Part filled by A in 3 minutes = 3/30   Required ratio = 3/30 * 20/11 = 2/11   Answer:2/11
Answer: B
JOHN and ANDREW can finish John work 30 days if they work together. They worked together for 20 days and then ANDREW left. JOHN finished the remaining work in another 20 days. In how many days JOHN alone can finish the work?
Answers.
A) 30 days	B) 60 days	C) 65 days	D) 78 days	E) 80 days

Solution: Amount of work done by JOHN and ANDREW in 1 day = 1/30   Amount of work done by JOHN and ANDREW in 20 days = 20 × (1/30) = 20/30 = 2/3   Remaining work – 1 – 2/3 = 1/3   JOHN completes 1/3 work in 20 days   Amount of work JOHN can do in 1 day = (1/3)/20 = 1/60   => JOHN can complete the work in 60 days   60 days
Answer: B
Two trains travelling in the same direction at 108 and 90 kmph completely pass off another in 1 minute. If the length of the first train is 100 m, what is the length of the second train? Choose the correct choice:
A) 228	B) 266	C) 175	D) 200	E) 171

Solution: RS = 108 â€“ 90 = 18 * 5/18= 
18 * 5/18 = 5
5 mps   T= 60 sec   200 = 5 * 60= 
5 * 60 = 300
300 m   100   --------   200 m   Answer: 200
Answer: D
Jonathan’s grandparents lend $10,000 to Jonathan at a simple annual interest rate of 10%. He pays them back 5 years later. How much do they receive?  Choose the correct choice from the following choices:
A) 10,000∗0.1^5  B) 10,000∗0.5  C) 10,000∗1.5  D) 10,000∗1.1^5  E) (10,000∗0.1)^5

Solution: Let the principal be $1   So Interest for the $1 for 5 years at 10% Pa is -   1∗5∗10/100 => 0.50   Now Principal is $1 and Interest is $ 0.50 , so Amount to be returned is - $1 + $0.50 => $1.50   So, for $ 10,000 , amount to be returned is 10,000 * 1.50; Answer is (10,000∗1.5)
Answer: C
If K persons take y days to complete z similar jobs, how long does it take y persons to complete 1 such job?
Choose one:
A) z
B) x
C) x/y
D) z/x
E) y/z

Solution: the Q doesn't seem to be having the any correct answer as a choice..   since we are looking for days, lets keep days in end and work out a solution..   K person can do z jobs in y days..   so K person can do 1 job in y/z days..   and 1 person can do 1 job in y^2/z days..   so y person can complete 1 job in y^2/zy=y/z..   so the answer should be y/z=y/z
Answer: E
What least number mustbe subtracted from 427398 so that remaining no.is divisible by 15	Choose the correct choice from the following answers.
A) 354665677  B) 436557678  C) 457676788  D) 725117481  E) 567768788

Solution: Explanation:   On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted   Answer: Option 725117481
Answer: D
A car traveling at a certain constant speed takes 2 seconds longer to travel 1 kilometer than it would take to travel 1 kilometer at 120 kilometers per hour. At what speed, in kilometers per hour, is the car traveling? Options
A) 121.5	B) 122	C) 122.5	D) 113	E) 112.5

Solution: 112.5   120 * T = 1 km => T = 1/120 km/h   V*(T+2/3600) = 1   V (1/120 + 2/3600) = 1 => V = 112.5 km/h
Answer: E
The greatest ratio out of 2:3, 5:8, 3:2, 8:9 and 8:1 is?
Choose one:	A) 2:3	B) 3:2	C) 5:8	D) 8:1	E) 8:9

Solution: 2/3=0.666   5/8= 
5/8 = 5/8 = around 0.625
0.625   3/2= 
3/2 = 3/2 = around 1.5
1.5   8/9=0.888   8/1= 
8/1 = 8
8   ANSWER:8:1
Answer: D
Machine A and machine B are each used to manufacture 880 sprockets. It takes machine A 10 hours longer to produce 880 sprockets than machine B. Machine B produces 10% more sprockets per hour than machine A. How many sprockets per hour does machineAproduce?  Choose the correct answer.
A) 6 B) 6.6 C) 8.8 D) 100 E) 110

Solution: time taken by B = t   time taken by A = t+10   qty produced by A = q   qty produced by B = 1.1 q   for B: t(1.1q) =880   qt=800   for A: (t+10)(q) = 880   qt+10q=880   800+10q=880   q=8   so A can produce 8/hour.   then B can produce = 8(1.1)=8.8/hour.   8.8
Answer: C
A wildlife preserve is being planned for 6,000 rhinoceroses. The preserve is to contain a total of 10,000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousand acres should the preserve have in order to provide for the increased population?  Pick one.
A) 340 B) 330 C) 670 D) 310 E) 300

Solution: Number of rhinos = 6000   Watering area = 10,000 acres   Number of rhino to increase by 10 percent ,then number of rhino = 6600   Grazing area for a rhino = 100   Total grazing area for 6600 rhinos= 6600 * 100 = 6,60,000   Total area required for the wildlife preserve = 6,60,000 + 10,000 = 6,70,000 = 670 * 1000   Answer 670
Answer: C
Donald duck can can swim his pool downstream(with the pool current helping time) in exact 40 seconds and upstream(against the pool current) in a pool in exact 60 seconds. The length of pool is 2 kilometers.
How long Donald duck can cover distance of one side at a still pool (with no current). Choose one.
A) 44 minutes	B) 45 minutes	C) 43 minutes	D) 48 minutes	E) 50 minutes

Solution: D   48 minutes.   48 minutesonald duck's speed = X km/seconds   pool current speed = Y km/seconds   2/(X+Y) = 40   2/(X-Y) = 60   Solving the simultaneous equations gives X = 1/24   Therefore, to cover 2km will take 2/X = 48 seconds
Answer: D
A woman named Ranjani started a business investing Rs. 5,000. Roja joined him after six months with an amount of Rs. 5,000 and Sachin joined them with Rs. 10,000 after another six months. The amount of profit earned should be distributed in what ratio among Ranjani, Roja and Sachin respectively, 3 years after A woman started the business ?	Options
A) 7:6:10  B) 12:15:16  C) 42:45:56  D) 6 : 5 : 8  E) 6 : 4 : 3

Solution: Explanation :   Akash : Roja : Sachin = (5,000 x 36) : (5,000 x 30) : (10,000 x 24)   = 36 : 30 : 48 => 6 : 5 : 8   Answer : 6 : 5 : 8
Answer: D
In the quadrilateral PQRS d=8 cm, h1=4.4 cm and
h2=2.2 cm. Find the area
Choose the correct option
A) 21 B) 22 C) 23 D) 24 E) 26.4

Solution: area of quad.=1/2*any diagonal*(sum of 2 perpendiculars which is drawn on that diagona)   so 1/2*8*(4.4+2.2)= 
1/2*8*(4.4+2.2) = 26.4
26.4   ANSW26.4R:26.4
Answer: E
In printing test papers for Excel, Gayatri found that if she used Arial font size 10 instead of Times Roman font size 10 there was a reduction of 18% in the number of pages required for test papers. Further, if she reduced the font size from 10 to 9, the savings were 14% and 10% in Times Roman and Arial fonts respectively. If an test papers printing in Times Roman font size 9 is converted to Arial font size 9, what is the percentage reduction in the number of pages?  Options: A) 14.1 B) 14.2 C) 14.3 D) 14.4 E) 14.5

Solution: Ans.   From TR-10 to A - 10 there is a reduction of 18% in the number of pages. and From TR-10 to TR-9 14% reduction, A - 10 to A - 9 10% reduction.   Assume Test paper in TR- 10 is 100 pages. So in TR- 9 the number of pages are 100X 86% = 86   Now in 14.1-10 total pages are 100 X 82% = 82   Now in 14.1 - 9 total pages are 82 X 90% = 73.8   So total change in the number of pages = (86−73.8)/86×100 = 14.1   14.1nswer 14.1
Answer: A
John went on a diet 6 months ago when he weighed 224 pounds. If he now weighs 200 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 180 pounds?	Options:
A) 3
B) 3.5
C) 4
D) 4.5
E) 5

Solution: 224 - 200= 
224 - 200 = 24
24 pounds lost in 6 months    24/6= 
 24/6 = 4
4, so Joe is losing weight at a rate of 4 pounds per month.   ...in approximately how many months will he weigh 180 pounds?   A simple approach is to just list the weights.   Now: 200 lbs   In 1 month: 196 lbs   In 2 months: 192 lbs   In 3 months: 188 lbs   In 4 months: 184 lbs   In 5 months: 180 lbs   Answer: 5
Answer: E
If 4 spiders make 4 webs in 4 days, then 1 spider will make 1 web in how many days?	Pick: A) 1 B) 3 C) 5 D) 4 E) 6

Solution: Explanation :   Let the required number days be x.   Less spiders, More days (Indirect Proportion)   Less webs, Less days (4irect Proportion)   Spiders 1:4|   |::4:1   Webs 4:1|   => 1 * 4 * x = 4 * 1 * 4   => x = 4   Answer : 4
Answer: D
The ratio of investments of A, B and C is 5:6:7. If they share the profit in the ratio of 5:12:14, then find the ratio of their periods of investments. Select
A) 1:2:2
B) 3:5:6
C) 3:2:4
D) 2:4:3
E) 2:5:3

Solution: The ratio of investments of A, B and C is 5:6:7.   The ratio of shares of A, B and C is 5:12:14.   Therefore, Ratio of their periods of investments is   (5/5) : (12/6) : (14/7) = 1:2:2   1:2:2NSWER:1:2:2
Answer: A