MU-NLPC/Calc-aqua_rat huggingface dataset:
In 1937, the ship of the great sailor SINBAD left an Egyptian port heading Ivory coast at T mile/month .
One month later another ship of the greatest pirate ever CHENG I SAO was 5000 miles due south of the same Egyptian port and heading due north at Y miles/month. Six months later after the leaving of Sinbad’s ship from Egyptian port, how far apart were the ships? [Ivory coast is in the west of Egypt]	Choose the correct choice:
A) { (6T)^2 + (5000-5y)^2 }^1/2
B) { (36x)^2 + (5000-7y)^2 }^1/2
C) { (16x)^2 + (5000-7y)^2 }^1/2
D) { (7x)^2 + (5200-7y)^2 }^1/2
E) { (2x)^2 + (300-7y)^2 }^1/2

Solution: The chinese ship sailed for 5 months i.e. 5Y miles @Y miles/month, therefore distance from Egyptian port is 5000-5Y. Since { (6T)^2 + (5000-5y)^2 }^1/2 is the only option with this value ...therefore { (6T)^2 + (5000-5y)^2 }^1/2 is the answer
Answer: A
After a storm deposits 120 billion gallons of water into the city reservoir, the reservoir is 80% full. If the original contents of the reservoir totaled 200 billion gallons, the reservoir was approximately what percentage full before the storm?  Choose the correct choice from the following options.
A) 45%
B) 48%
C) 50%
D) 58%
E) 65%

Solution: When the storm deposited 120 billion gallons, volume of water in the reservoir = 200 + 120= 
200 + 120 = 320
320 billion gallons   If this is only 80% of the capacity of the reservoir, the total capacity of the reservoir= 320/0.8= 
320/0.8 = 400
400 billion gallons   Therefore percentage of reservoir that was full before the storm= (200/400)*100= 
(200/400)*100 = 50
50%   Option 50%
Answer: C
A mixture of 70 litres of milk and water contains 10% water. How many litres of water should be added to the mixture so that the mixture contains 12 1/2% water?	Choose one:	A) 2	B) 8	C) 6	D) 3	E) 4

Solution: A   2   Quantity of milk in the mixture = 90/100 (70) = 63 litres.   After adding water, milk would form 87 1/2% of the mixture.   Hence, if quantity of mixture after adding x liters of water, (87 1/2) / 100 x = 63 => x = 72   Hence 72 - 70= 
72 - 70 = 2
2 litres of water must be added.
Answer: A
A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present? Choose the correct option:
A) 32 Yrs  B) 36 Yrs  C) 40 Yrs  D) 48 Yrs  E) None

Solution: Explanation:   Let the mother's present age be x years.   Then, the person's present age = (2/5)*x years.   ((2/5)*x)+8 = (1/2)(x+8)   2(2x + 40) = 5(x + 8)   x = 40.   Answer: 40 Yrs
Answer: C
By selling 15 pens for a rupee a woman loses 25%. How many for a rupee should he sell in order to gain 25%?
Choose the correct choice from the following:	A) 12	B) 14	C) 45	D) 10	E) 65

Solution: 10   85% --- 15   125% --- ?   85/125 * 15 = 10
Answer: D
James started from his house headed North. After walking a distance of 50 m. He turned to the left and walked 60 m. He then made a right turn and walked 30 m. After this he is to turn left at 90o degrees and to cover another 40 m. How many meters did James walk in total and what direction was he headed in when he left his house?  Answers:
A) 158/South  B) 10/East  C) South-West  D) 180/North  E) 180/North-West

Solution: Answer: 180/North-West
Answer: E
By selling an article for 96, double profit is obtained than the profit that would have been obtained by selling it for 84. What is the cost price of the article?	Select the correct option.
A) 72.0
B) 75.0
C) 70.00
D) 68.00
E) None of these

Solution: Let the cost price of the article be x.   Then,2(84 –x) = 96 – x   l68 – 2x= 96 – x \ x = 72   72.0nswer 72.0
Answer: A
What is the area of square field whose side of length 13 m? Options
A) 169	B) 196	C) 266	D) 288	E) 261

Solution: 13 * 13= 
13 * 13 = 169
169 sq m   169nswer: 169
Answer: A
If two positive numbers are in the ratio 1/8 : 1/5, then by what percent is the second number more than the first?	Pick one:
A) 70%
B) 90%
C) 60%
D) 50%
E) 65%

Solution: Given ratio = 1/8 : 1/5 = 5 : 8   Let first number be 5x and the second number be 8x.   The second number is more than first number by 3x.   Required percentage = 3x/5x * 100 = 60%.   Answer:60%3 /5  * 100= 
3 /5  * 100 = 60
60%.   Answer:60%
Answer: C
A circular rim A having a diameter of 24 inches is rotating at the rate of x inches/min. Another circular rim B with a diameter of 32 inches is rotating at the rate of y inches/min. What is the value of y in terms of x, if both the rims reach their starting positions at the same time after every rotation.  Options
A) 3x/4	B) 4x/5	C) 7x/5	D) 5x/7	E) 4x/3

Solution: t = S1/V1 = S2/V2   or, 24/x = 32/y   or, y = 24x/32 = 3x/4 (3x/4nswer 3x/4)
Answer: A
An employer has 7 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?
Pick:  A) a) 1,490  B) b) 132  C) c) 210  D) d) 60  E) e) 23

Solution: 7C3 * 4C2 = 210. Answer c) 210.
Answer: C
If you select two cards from a pile of cards numbered 1 to 10, what is the probability that the sum of the numbers is less than 5?	Choose the correct answer:
A) 1/45
B) 2/45
C) 2/15
D) 4/15
E) 1/5

Solution: The number of ways to choose two cards is 10C2=45.   There are 2 ways, {1,2} and {1,3}, to get a sum less than 5.   P(sum less than 5)=2/45   The answer is 2/45.
Answer: B
If each edge of cube increased by 25%, the percentage increase in
Answers:
A) 55 B) 52.25 C) 59.75 D) 51.75 E) 56.25

Solution: 100 × (125)/100 × (125)/100 = 156.25 => 56.25%   Answer is 56.25.
Answer: E
A circular rim 20 inches in diameter rotates the same number of inches per second as a circular rim 15 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim makes in terms of x ?  Pick.
A) 48pi/x  B) 75x  C) 48x  D) 80x  E) x/75

Solution: Revolutions - circumference of the rim.   => 20pi*X*60 = 15pi*Revolutions   => 4/3 *X *60 = Revolutions => 80X - Option 80x
Answer: D
36 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?  Choose the correct choice from the following choices
A) 12  B) 16  C) 13  D) 18  E) 19

Solution: Let the required number of days be x.   Less persons, More days (Indirect Proportion)   More working hours per day, Less days (Indirect Proportion)   Persons 30 : 36 :: 12 : x   Working hours/day 6 : 5   30 x 6 x x = 36 x 5 x 12   x = (36 x 5 x 12)/(30 x 6)   x = 12   12NSWER 12
Answer: A
A and B can do a piece of work in 12 days and 16 days respectively. Both work for 3 days and then A goes away. Find how long will B take to complete the remaining work?	Select
A) 6 days B) 8 days C) 5 days D) 9 days E) 4 days

Solution: 3/12 + (3 + x)/16 = 1   x = 9 days   Answer:9 days
Answer: D
M is a certain set of numbers with an average (arithmetic mean) of 10 and a standard deviation of 0.5. Q is a subset of M consisting of 5 terms. Exactly 80% of the numbers in Q are located within 2 standard deviations from the average of M. Which of the following could Q be? Choices
A) {3, 4, 5, 10, 11}  B) {3, 9, 10, 10, 11}  C) {3, 5, 9, 10, 16}  D) {1, 5, 7, 10, 11}  E) {5, 6, 7, 10, 12}

Solution: Exactly 80% of the numbers in Q, so 4 out of 5 numbers are from 10 - 2*{SD} = 9 to 10 + 2*{SD} = 11.   A. {3, 4,5, 10, 11} --> only 2 numbers are in this range. Discard.   B. {3,9, 10, 10, 11} --> 4 numbers are in this range. OK.   C. {3,5, 9, 10, 16} --> only 2 numbers are in this range. Discard.   D. {1,5, 7, 10, 11} --> only 2 numbers are in this range. Discard.   E. {5, 6, 7, 10, 12} --> only 1 number is in this range. Discard.   Answer: {3, 9, 10, 10, 11}.
Answer: B
A bus started its journey from Mumbai and reached Pune in 44min with its average speed of 50 km/hr. If the average speed of the bus is increased by 5km/hr, how much time will it take to cover the same distance?  Pick one
A) 20	B) 30	C) 35	D) 40	E) 50

Solution: Sol. 40istance between Ramgarh and 40evgarh =(50*44)/60=110/3   Average speed of the bus is increased by 5 km/hr then the   speed of the bus = 55 km/hr   Required time = 110/3*60/55= 
110/3*60/55 = 40
40 min   40
Answer: D
Express a speed of 36 kmph in meters per second?
Choose the correct option.
A) 10 mps  B) 76 mps  C) 26 mps  D) 97 mps  E) 16 mps

Solution: 36 * 5/18= 
36 * 5/18 = 10
10 mps   10 mpsnswer:10 mps
Answer: A
The sum of two number is 120 and their difference is 30. Find the numbers.	Choose the most appropriate option
A) 95,25	B) 55,65	C) 75,45	D) 65,55	E) 85,35

Solution: Let the two number be x and y. x+y =120.......(1) x- Y =30.........(2)   =>2X=150 =>X=75. x-y =30 =>y =45. The two numbers are 75,45 Ans : 75,45
Answer: C
Eight years ago Anita was P times as old as Ben was. If Anita is now 27 years old, how old is Ben now in terms of P ?	Choose the correct choice from the following answers.
A) 19/P + 8  B) P/19 +8  C) 17 - P/8  D) 17/P  E) 11.5P

Solution: let's call Ben age eight years ago is x   so eight years ago 19/P + 8nita was:  27-8= 
 27-8 = 19
19 years old   and eight years ago 19/P + 8nita was P times as old as Ben was=> 19/x = P   => x = 19/P   => Now Ben age will be : x+8 = 19/P+8   => the answer is 19/P + 8
Answer: A
There are three prizes to be distributed among seven students. If no students gets more than one prize, then this can be done in?  Choose the correct choice from the following options.
A) 10	B) 45	C) 35	D) 20	E) None of these

Solution: Explanation :   3 prize among 7 students can be distributed in 7C3 ways = 35 ways.   Answer : 35
Answer: C
A CHOCOLATE manufacturer produces 400 units of a certain model each month at a cost to the manufacturer of £40 per unit and all of the produced units are sold each month. What is the minimum selling price per unit that will ensure that the monthly profit (revenue from sales minus production costs) on the sales of these units will be at least £40,000? Options.
A) 123
B) 213
C) 440
D) 550
E) 540

Solution: 400(x-40)≥40,000   x-40≥400   x≥440   Answer: Option 440
Answer: C
What smallest number should be added to 4456 so that the sum is completely divisible by 6 ? Choose the correct choice:
A) 1
B) 5
C) 2
D) 3
E) 8

Solution: 4456 (742   42   --   25   24   --   16   12   --   4   => (6-4)= 
(6-4) = 2
2   ANSWER 2
Answer: C
A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 700 m long?	Choose the correct option.
A) 177
B) 190
C) 178
D) 124
E) 121

Solution: L = S*T   S= 1200/120= 
1200/120 = 10
10 m/Sec.   Total length (D)= 1900 m   T = D/S   T = 1900/10= 
1900/10 = 190
190 Sec   Answer: 190
Answer: B
One hour after Matthew started waking from t to y, a distance of 45km, Johnny started walking along the same road from y to t. Matthew's walking rate was 3 km per hour and Johnny's was 4km per hour, how many km had Johnny walked when they met?	Answers:
A) 24
B) 23
C) 22
D) 21
E) 19.5

Solution: Just an alternative method...   After the first hour the distance t is 42 km (45-3). Now the problem can be treated as if bothof them started at the same time. Since the speeds are in the ratio 3 : 4, the distances will also be in the same ratio. Splitting 42 in that ratio we get 18 : 24. So answer is 24.   Hence 24.
Answer: A
The ratio between the number of passengers travelling by I and II class between the two railway stations is 1 : 50, whereas the ratio of I and II class fares between the same stations is 3 : 1. If on a particular day Rs. 1,325 were collected from the passengers travelling between these stations, then what was the amount collected from the II class passengers?  Choose the correct choice from the following answers: A) Rs. 750 B) Rs. 1000 C) Rs. 850 D) Rs. 1250 E) None of these

Solution: Let x be the number of passengers and y be the fare taken from passengers.   3xy + 50xy = 1325 => xy = 25   Amount collected from II class passengers = 25 × 50 = Rs. 1250.   Answer:	Rs. 1250
Answer: D
If rupee one produces rupees nine over a period of 30 years, find the rate of simple interest?	Pick one:
A) 30 %
B) 22 3/2 %
C) 22 1/8 %
D) 22 1/2 %
E) 22 1/2 %

Solution: 9 = (1*30*R)/100   R = 30 %   30 %nswer:30 %
Answer: A
In a college the ratio of the numbers of boys to the girls is 8:5. If there are 135 girls, the total number of students in the college is?	Choices:	A) 562	B) 351	C) 452	D) 416	E) 512

Solution: Let the number of boys and girls be 8x and 5x   Then , 5x = 135   x= 27   Total number of students = 13x = 13*27= 
13*27 = 351
351   Answer is 351
Answer: B
The average height of 15 girls out of a class of 60 is 138 cm. and that of the remaining girls is 142 cm. The average height of the whole class is :	Choose the correct choice from the following answers
A) 132 cms  B) 141 cms  C) 142 cms  D) 152 cms  E) 161 cms

Solution: Explanation:   Average height of the whole class =(15×138+45×142/60)=141 cms   Answer 141 cms
Answer: B
Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? Choose the correct option
A) 10 B) 12 C) 15 D) 20 E) 18

Solution: Speed of the first train =	(120/10) m/sec = 12 m/sec.   Speed of the second train =(120/15)	m/sec = 8 m/sec.   Relative speed = (12 + 8)= 
(12 + 8) = 20
20 m/sec.   Therefore Required time=	[(120 + 120)/20= 
(120 + 120)/20 = 12
12 sec.   Answer :12
Answer: B
The probability that a man will be alive for 10more yrs is 1/3 & the probability that his wife will alive for 10 more yrs is 5/8. The probability that none of them will be alive for 10 more yrs, is	Choose the correct choice from the following
A) 1/8
B) 1/4
C) 2/3
D) 3/4
E) 2

Solution: Sol. Required probability = Pg.) x P(1/4) = (1— D x(1 —I) =: x 1=1/4   Ans.(1/4)
Answer: B
The distance from City A to City B is 100 miles. While driving from City A to City B, Bob drives at a constant speed of 40 miles per hour. Alice leaves City A 30 minutes after Bob. What is the minimum constant speed in miles per hour that Alice must exceed in order to arrive in City B before Bob?	Choose the correct choice from the following answers.
A) 45  B) 48  C) 50  D) 52  E) 54

Solution: The time it takes Bob to drive to City B is 100 / 40= 
100 / 40 = 5/2 = around 2.5
2.5 hours.   Alice needs to take less than 2 hours for the trip.   Alice needs to exceed a constant speed of 100 / 2= 
100 / 2 = 50
50 miles per hour.   The answer is 50.
Answer: C
The perimeter of a triangle is 36 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?
Choose the most appropriate option:	A) 38 cm2	B) 27 cm2	C) 45 cm2	D) 25 cm2	E) 35 cm2

Solution: Area of a triangle = r * s   Where r is the inradius and s is the semi perimeter of the triangle.   Area of triangle = 2.5 * 36/2= 
2.5 * 36/2 = 45
45 cm2   Answer: 45 cm2
Answer: C
If a class of 10 students has seven men, how many ways can the men and women be arranged in a circle so that no two men sit next to each other?  Pick one:
A) 7!6!  B) 5!5!  C) 4!4!  D) 10!  E) 10!/5!

Solution: for no two men to sit together, either all are in even or odd position   fix one at any one position then rest six can be fixed in 6! ways...   also rest seven position of women can be fixed in 7!..   total ways 7!6!   7!6!
Answer: A
The area of a parallelogram is 162sq m and its altitude is twice the corresponding base. Then the length of the base is?
Options:
A) 8  B) 9  C) 7  D) 62  E) 2

Solution: 2x * x = 162 => x= 9   Answer: 9
Answer: B
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 135 mangoes.	Pick
A) 360
B) 380
C) 400
D) 450
E) 412

Solution: Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.   Method 1:   Let price per mango = x. Let number of mangoes be n. Then, nx = 360.   Now price = 0.9x; number of mangoes = n + 12. Total amount = 0.9x*(n+12) = 360.   nx = 0.9nx + 10.8x => 0.1nx = 10.8x => n = 108 => x = 360/108 = 3.33   Original price of 135 mangoes = 135*3.33 = 450.   Answer 450
Answer: D
A train running at the speed of 45 km/hr crosses a pole in 16 seconds. Find the length of the train.  Choose the correct choice from the following answers.
A) 200	B) 188	C) 204	D) 288	E) 500

Solution: Speed = 45*(5/18) m/sec =25/2 m/sec   Length of Train (Distance) = Speed * Time     (25/2) * 16= 
  (25/2) * 16 = 200
200 meter   200nswer: 200
Answer: A
If (a-5)(b+2) = 0 which of the following must be true?
Choose the correct choice from the following answers
A) a = b
B) a > b
C) a < b
D) ab = -10
E) None of the above

Solution: (a-5)(b+2) = 0 means that EITHER a=5 OR b=-2. For example, if a=5, then y can be any number. The same way, if b=-2, then a can be any number.   Bunuel, although your solution is perfect, I would just point out arewordingsuggestion on your last comment. (a-5)(b+2) =0 means that a = 5 OR b =-2 (without the EITHER). Obviously both equalities COULD happen simultaneously, but they don't HAVNone of the above TO happen simultaneously in order for the equation in stem to be valid   Answer is None of the above
Answer: E
The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?	Choose the correct choice from the following options
A) 70 B) 25 C) 60 D) 80 E) 55

Solution: A + B = 60, A = 2B   2B + B = 60 => B = 20 then A = 40.   5 years, their ages will be 45 and 25.   Sum of their ages = 45 + 25= 
45 + 25 = 70
70.   70NSWER 70
Answer: A
If r = 199,999 and s = 991,999, which of the following is the units digit of r^3 + s^3?
Pick
A) 0 B) 1 C) 2 D) 8 E) 9

Solution: The exponents of 9 cycle between 9 (odd exponents) and 1 (even exponents).   Then the sum of r^3+s^3 will have the units digit of 9+9= 
9+9 = 18
18 as a units digit.   The answer is 8.
Answer: D
Two cars A and B start from Boston and New York respectively simultaneously and travel towards each other at constant speeds along the same route. After meeting at a point between Boston and New York the two cars A and B proceed to their respective destinations of New York and Boston. Car A reaches New York 10 minutes after the two cars have met and Car B reaches Boston 90 minutes after they have met. How long did Car A take to cover the distance between Boston and New York?
Choose the correct choice:
A) 1 hour
B) 1 hour 10 minutes
C) 2 hours 30 minutes
D) 50 minutes
E) 2 hours 10 minutes

Solution: Both cars leave at the same time   Both cars travel at constant speed   Stealing a useful piece of information from Paragkan:   If two objects A and B start from opposite points and, after having met en route, reach their respective destinations in a and b mins (or any other measure of time) respectively, then the ratio of their speeds   ratio of speed: (a/b) = sq. rt(b/a)   sq. rt(b/a)   sq. rt(90/10)   sq. rt(3/2)   So, for every three units of distance A travels, B travels two. Because we know the ratio of speed and the time it took B to travel the distance A hasn't yet covered, we can find the time it took A to cover the distance B did in 90 minutes.   90*(2/3)where 2/3 represents the lesser amount of time it took A to travel the distance B did in 90 minutes.   = 60 minutes.   Therefore, A took 10 minutes to travel the first portion then 60 minutes to travel the distance B did in 90 minutes. A spent (10+60)=50 minutes on the road.   D. 50 minutes
Answer: D
10^185 - 10^30 =
Which of the following best approximates the value of the expression above?  Choose the correct choice from the following choices:  A) 10^180  B) 10^179  C) 10^170  D) 10^160  E) 10^185

Solution: 10^185 - 10^30 =   Which of the following best approximates the value of the expression above?   Yes, answer 10^185 is correct. Note that we need approximate value of the given expression and as 10^(185) is much larger number than 10^(30) then 10^(30) is pretty much negligible in this case: 10^(185)-10^(30)=~10^(185).   Answer : 10^185
Answer: E
A bag contains 21 toys numbered 1 to 21. A toy is drawn and then another toy is drawn without replacement. Find the probability that both toys will show even numbers.	Choose the correct option:
A) 5/21
B) 9/42
C) 6/22
D) 4/21
E) 3/21

Solution: Since there are 10 even numbers in the given range, the probability that the first toy shows an even number = 10/21   Since the toy is not replaced, there are now 9 even numbered toys and total 20 toys left.   Hence, probability that the second toy shows an even number = 9/20.   Required probability = 10/21 x 9/20 = 9/42.   ANSWER:9/42
Answer: B
A vendor bought toffees at 6 for a rupee. How many for a rupee must he sell to gain 25%?  Choose the correct choice:
A) 2
B) 9
C) 6
D) 3
E) 5

Solution: C.P. of 6 toffees = Re. 1   S.P. of 6 toffees = 150% of Re. 1 = Rs. 3/2   For Rs. 3/2 , toffees sold = 6.   For Re. 1, toffees sold = 6 x3/2 = 9.   Answer 9
Answer: B
A hostel had provisions for 250 men for 40 days. If 50 men left the hostel, how long will the food last at the same rate?	Choices:
A) 30	B) 40	C) 50	D) 60	E) 65

Solution: A hostel had provisions for 250 men for 40 days   If 50 men leaves the hostel, remaining men = 250 - 50= 
250 - 50 = 200
200   We need to find out how long the food will last for these 200 men.   Let the required number of days= x days   More men, Less days (Indirect Proportion)   (men) 250 : 200 :: x : 40   250×40=200x   5×40=4x   x=5×10=50   ANSWER 50
Answer: C
By selling 150 mangoes, a fruit-seller gains the selling price of 30 mangoes. Find the gain percent?  Choices
A) 28%  B) 25%  C) 85%  D) 24%  E) 22%

Solution: SP = CP + g   150 SP = 150 CP + 30 SP   120 SP = 150 CP   120 --- 30 CP   100 --- ? => 25%   Answer: 25%
Answer: B
What least fraction should be added to
1/(2 × 3) + 1/(3 × 4) + 1/(4 × 5) + ....... + 1/(21 × 22)
so that the result is unity?	Answers:
A) 5/11 B) 6/11 C) 4/11 D) 7/11 E) 8/11

Solution: Explanation:   Given expression   = 1/(2 × 3) + 1/(3 × 4) + 1/(4 × 5) + ...... + 1/(21 × 22)   = (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + ..........   = (1/21 - 1/22) = 1/2 - 1/22 = 10/22 = 5/11   Thus, least fraction to be added = 1 - 5/11 = 6/11   Answer: Option 6/11
Answer: B
In the accounting branch of a commercial institute, the percentage of male and female workers is 48% and 52% respectively. In this branch, 40% of males and 20% of females are age 25 or older. If one of the workers is selected at random, what is the probability Q that the worker is under 25 years old?
Choose the correct choice from the following answers
A) 0.30	B) 0.25	C) 0.45	D) 0.70	E) 0.90

Solution: Percentage of male worker = 48   Percentage of female worker = 52   Let total number of workers = 1000   number of male workers= 480   number of female workers = 520   Number of male age 25 or older = (4/10)*480= 
(4/10)*480 = 192
192   Number of female age 25 or older=(2/10)*520= 
(2/10)*520 = 104
104   Total number of workers 25 or older= 192+104= 
192+104 = 296
296   Total number of workers under 25= 1000 - 296= 
1000 - 296 = 704
704   Probability that a worker randomly selected is under 25 years old= 704/1000= 
704/1000 = 88/125 = around 0.704
.704   Alternatively , since the answer options are not close , we can use estimation here .   Percentage of male worker 25 or older= (4/10)*48 = 20 % approx   Percentage of female worker 25 or older = (2/10)*52 = 10 % approx   Percentage of total worker 25 or older = 30 %   Percentage of total worker under 25 = 70 %   Probability that a worker randomly selected is under 25 years old Q= .7   Answer 0.70
Answer: D