MU-NLPC/Calc-aqua_rat huggingface dataset:
For the positive numbers, n, n + 1, n + 2, n + 7, and n +10, the mean is how much greater than the median? Choose the correct choice from the following answers
A) 0
B) 1
C) n+l
D) 2
E) n+3

Solution: Let’s first calculate the mean (arithmetic average).   mean = sum/quantity   mean = (n + n + 1 + n + 2 + n + 7 + n +10)/5   mean = (5n + 20)/5   mean = n + 4   Next, we determine the median. The median is the middle value when the terms are ordered from least to greatest. The terms ordered from least to greatest are as follows:   n, n + 1, n + 2, n + 7, n +10   The median is n + 2.   Finally we are asked how much greater the mean is than the median. To determine the difference we can subtract the smaller value (the median) from the larger value (the mean) and we get:   n + 4 – (n + 2) = n + 4 – n – 2 = 2   The answer is 2
Answer: D
A Cistern is filled by pipe A in 9 hrs and the full Cistern can be leaked out by an exhaust pipe B in 10 hrs. If both the pipes are opened in what time the Cistern is full? Choose the correct option
A) 45  B) 90  C) 1/10  D) 1/90  E) 60

Solution: Explanation :   Work down by the inlet in 1 hr = 1 /9   Work done by outlet in 1 hr 1/10   Net part filled in 1 hr = 1/9 - 1/10 = 1/90   The Cistern will be full in 90 hrs.   Hint: Take the reciprocals.   Answer : 90
Answer: B
By selling 14 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?	Choose the correct choice from the following answers
A) 28
B) 26
C) 25
D) 23
E) 21

Solution: 80% --- 14   120% --- ?   80/120 * 14 = 21   Answer:21
Answer: E
A card is drawn at random from a deck of cards. Find the probability of getting the 3 of diamond?  Options:
A) 1/52  B) 1/26  C) 2/37  D) 1/14  E) 1/27

Solution: Let n(S) = sample space and here n(s) = 52   n(E) = event of getting the 3 diamond = 1   therefore probability = p = n(E) / n(S)   =1/52   My answer is (1/52)
Answer: A
The average age of 8 men is increased by years when two of them whose ages are 21 years and 23 years are replaced by two new men. The average age of the two new men is Choose the correct choice.
A) 22  B) 30  C) 99  D) 28  E) 17

Solution: Explanation:   Total age increased = (8 * 2)= 
(8 * 2) = 16
16 years.   Sum of ages of two new men= (21 + 23 + 16)= 
(21 + 23 + 16) = 60
60 years   Average age of two new men= (60/2)= 
(60/2) = 30
30 years   Answer: 30
Answer: B
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train? Select the correct option:
A) 158  B) 159  C) 155  D) 112  E) 150

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 9= 
50/3 * 9 = 150
150 m   Answer: 150
Answer: E
AB
+BA
___
161
In the addition problem above, A and B represent digits in two different two-digit numbers. What is the sum of A and B?  Choose the correct choice
A) 6
B) 13
C) 9
D) 11
E) 14

Solution: two ways to do it..   1) straight logic..   we can see that ones digit is 1 when units digit B and A are added..   only 13 fits in..   13
Answer: B
How many numbers between 0 and 1270 have a prime tens digit and a prime units digit?	Select.
A) 186	B) 192	C) 198	D) 204	E) 210

Solution: From 1-9 there are 4 prime numbers {2, 3, 5, 7}. The 10s and 1s of the number must be made with these numbers. The total number of combinations is  4*4= 
 4*4 = 16
16. Thus every set of 100 consecutive positive integers has 16 such numbers.   From 0 to 1200, there  16*12= 
 16*12 = 192
192 such numbers.   From 1201 to 1270, the 10s units can only use 3 numbers {2, 3, 5}. 3*4=12.   The total number is then  192+12= 
 192+12 = 204
204   The answer is 204.
Answer: D
In an office, totally there are 1800 employees and 60% of the total employees are males. 30% of the males in the office are at-least 50 years old. Find the number of males aged below 50 years?	Choose the correct choice from the following.
A) 756	B) 750	C) 600	D) 760	E) None of these

Solution: Number of male employees = 1800* 60/100= 
1800* 60/100 = 1_080
1080   Required number of male employees who are less than 50 years old= 1080* (100 - 30)%   = 1080* 70/100= 
1080* 70/100 = 756
756.   756NSWER:756
Answer: A
A can complete a project in 20 days while B can complete same project in 30 days. If A and B start working together and A leaves the work 5 days before completion of project, then in how many days the project will be completed?
Select:  A) 15  B) 19  C) 20  D) 21  E) 22

Solution: A's 1day work=1/20;   B's 1day work=1/30;   (A+B) 1day work=(1/20+1/30)=1/12;   It is given that A leaves the work 5 days before completion of the project..   Thus,B alone does the remaining job in 5 days.   So,In 5 days ,B can do 1/6 w ..   Thus,(A+B) have worked (1-1/6)=5/6 w..   (A+B)can do 1/12 work in 1 day...   They did 5/6 w in 10 days.   Total days=(10+5)= 
(10+5) = 15
15   15NSWER:15
Answer: A
Charles walks over a railway-bridge. At the moment that he is just ten meters away from the middle of the bridge, he hears a train coming from behind. At that moment, the train, which travels at a speed of 90 km/h, is exactly as far away from the bridge as the bridge measures in length. Without hesitation, Charles rushes straight towards the train to get off the bridge. In this way, he misses the train by just four meters! If Charles had rushed exactly as fast in the other direction, the train would have hit him eight meters before the end of the bridge.
What is the length of the railway-bridge? Pick.
A) 37 B) 44 C) 73 D) 52 E) 48

Solution: B   44 m   Let the length of the bridge be x meters.   Running towards the train, Charles covers 0.5x-10 meters in the time that the train travels x-4 meters. Running away from the train, Charles covers 0.5x+2 meters in the time that the train travels 2x-8 meters.   44ecause their speeds are constant, the following holds:   (0.5x-10) / (x-4) = (0.5x+2) / (2x-8)   which can be rewritten to   0.5x2 - 24x + 88 = 0   Using the quadratic formula we find that x=44, so the railway-bridge has a length of 44 meters.
Answer: B
The averge score of a cricketer for ten matches is 38.9 runs. If the average for the first six matches is 42. Then find the average for the last four matches? Choose the correct choice from the following answers.
A) 33.25	B) 33.5	C) 34.25	D) 35	E) 36

Solution: sum of last 4 matches = (10 × 38.9) – (6 × 42)   = 389 – 252 = 137   Average =   137/4= 
137/4 = 137/4 = around 34.25
34.25   ANSWER:34.25
Answer: C
When positive integer q is divided by 13, the remainder is 2. When n is divided by 8, the remainder is 5. How many such values are less than 180?
Choose the correct choice from the following answers:
A) 0	B) 1	C) 2	D) 3	E) 4

Solution: the equation that can be formed q is 13x+2=8y+5..   13x-3=8y...   as we can see x can take only odd values as the RHS will always be even..   Also x can take values till 13 as 13*14>180..   now we have to substitue x as 1,3,5,7,9,11,13...   once we find 7 fitting in , any other value need not be checked as every 4th value will give us answer so next value will be 15..   ans 1.. 1
Answer: B
If Rs.20 is the True Discount on Rs260due after a certain time.What wil be true discount on the same sum due after half of the former time, the rate of interest being the same?  Options:
A) Rs.9.40	B) Rs.10.14	C) Rs.10.40	D) Rs.9.14	E) None of these

Solution: Explanation:   Simple Interest on Rs. (260-20) for a gven time= Rs.20   Simple Interest on Rs. (260-20) for a half time = Rs.10   True Discount on Rs.250 = Rs.10   True Discount on Rs.260 = R(s10/250x260 ) = Rs. 10.40   Answer: Rs.10.40
Answer: C
Gasoline varies in cost from $0.94 to $1.14 per gallon. If a car’s mileage varies from 16 to 24 miles per gallon, what is the difference between the most and least that the gasoline for a 480-mile trip will cost? Choose the most appropriate option
A) $15.20
B) $15.30
C) $15.40
D) $15.50
E) $15.60

Solution: Solution:   We know that the per gallon cost of gasoline varies from $0.94 - $1.14.   Now we want to find the MAXIMUM difference between the least amount of money spent on gasoline and the largest amount of money spent i.e. to calculate max. trip cost - min. trip cost.   Mileage is given to be 16 to 24 miles per gallon, thus to travel 480 miles you will need gasoline in the range 480/24 to 480/16 which is 20 to 30 gallons.   So, for these 20 gallons and 30 gallons of gasoline the cost is as follows: (divide this task into 2 parts, 1 for 30 gallons and 2nd one for 20 gallons).   $15.40ase 1: for 30 gallons the cost is 30*0.94 to 30*1.14 which is $28.20 to $34.20   $15.40ase 2: for 20 gallons the cost is 20*0.94 to 20*1.14 which is $18.80 to $22.80   Thus, the maximum cost of the 480 mile trip is $34.20 and minimum is $18.80   so the difference is $34.20 - $18.80 = $15.40   Answer: $15.40 34.20 -  18.80= 
 34.20 -  18.80 = 15.4
$15.40   Answer: $15.40
Answer: C
-20 , -16 , -12 , -8 ....
In the sequence above, each term after the first is 6 greater than the preceding term. Which of the following could not be a term in the sequence?	Options: A) 0 B) 200 C) 444 D) 660 E) 780

Solution: Ans :200   Since 200 is not divisible by 6 , all the other options are divisible by 6
Answer: B
A man swims downstream 70 km and upstream 30 km taking 10 hours each time; what is the speed of the current?  Select the correct option: A) 1 B) 4 C) 2 D) 6 E) 8

Solution: 70 --- 10 DS = 7   ? ---- 1   30 ---- 10 US = 3   ? ---- 1 S = ?   S = (7 - 3)/2= 
(7 - 3)/2 = 2
2   Answer: 2
Answer: C
A mixture contains milk and water in the ratio 3:2. On adding 10 liters of water, the ratio of milk to water becomes 2:3. Total quantity of milk & water before adding water to it?  Choose the correct answer:
A) 30	B) 40	C) 20	D) 10	E) 25

Solution: milk:water = 3:2   after adding 10 liters of water   milk:water = 2:3   Olny water patrs increase when mixture of water   milk:wate = 3:2 = 2*(3:2) = 6:4   after adding 10 liters of water   milk:water = 2:3 = 3*(2:3) = 6:9   Option '20'
Answer: C
The average of first 50 non-zero positive integers is  Choose the correct choice from the following.
A) 11.5	B) 25.5	C) 22	D) 25	E) 27

Solution: Explanation :   Sum of first n non-zero positive integers n(n + 1)/2   So, average of first n non-zero positive integers n(n + 1)/2n = (n + 1)/2   => (50 + 1)/2= 
(50 + 1)/2 = 51/2 = around 25.5
25.5   Answer : 25.5
Answer: B
Alan buys 4 TVs, a 26 inch, a 28 inch, a 30 inch, and a 32 inch, for his new house. Each TV costs $200 more than the size below it. Alan spends a total of $4,600. How much would he have spent if he had bought only the 28 inch and 30 inch TVs? Choose the correct option.
A) 850  B) 1,100  C) 1,700  D) 2,550  E) 2,300

Solution: Assume the cost of the least sized (26 Inch) TV = x   Cost of 28 inches TV = x + 200   Cost of 30 inches TV = x + 400   Cost of 32 inches TV = x + 600   Total cost = 4x + 1200 = 4600   Therefore x = 3400/4= 
3400/4 = 850
850   Price of 28inch + 30 inch= 1050 + 1250= 
1050 + 1250 = 2_300
2300   Option 2,300
Answer: E
Triangle STV has sides ST = TV = 5, and SV = 6. What is the area?
Choose the correct choice from the following answers.
A) 8
B) 10
C) 12
D) 14
E) 16

Solution: Let the base B of the triangle be SV = 6. Then we need to find the height H.   H^2 = 5^2 - 3^2 = 16 and then H = 4.   The area is (1/2)*B*H = 3*4= 
3*4 = 12
12   The answer is 12.
Answer: C
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. Find the time required by the first pipe to fill the tank ?	Pick one:
A) 10 hours	B) 15 hours	C) 17 hours	D) 18 hours	E) 19 hours

Solution: Explanation:   Suppose, first pipe alone takes x hours to fill the tank .   Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.   As per question, we get   1/X + 1/X-5 =1/X-9   =>xâˆ’5+x/ X(xâˆ’5)=1/X-9   =>(2xâˆ’5)(xâˆ’9)=x(xâˆ’5)   =>x2âˆ’18x+45=0   After solving this euation, we get   (x-15)(x+3) = 0,   As value can not be negative, so x = 15   ANSWER IS 15 hours
Answer: B
The probability that a number selected at random from the first 50 natural numbers is a composite number is  Choose the correct choice from the following:	A) 17/20	B) 17/25	C) 17/29	D) 17/27	E) 17/21

Solution: The number of exhaustive events = ⁵⁰C₁ = 50.   We have 15 primes from 1 to 50.   Number of favourable cases are 34.   Required probability = 34/50 = 17/25.   Answer:17/25
Answer: B
Ages of two persons differ by 14 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age  Pick
A) 12,28	B) 13,27	C) 16,32	D) 18,34	E) 19,34

Solution: Explanation:   Let the age of younger person is x,   Then elder person age is (x+14)   => 3(x-6) = (x+14-6) [6 years before]   => 3x-18 = x+8   => x = 13   So other person age is x + 14 = 27   Answer: Option 13,27
Answer: B
A foreign language club at Washington Middle School consists of n students, 2/5 of whom are boys. All of the students in the club study exactly one foreign language. 1/3 of the girls in the club study Spanish and 3/4 of the remaining girls study French. If the rest of the girls in the club study German, how many girls in the club, in terms of n, study German?  Choices:
A) 2n/5	B) n/3	C) n/5	D) 2n/15	E) n/10

Solution: 2/5 of the students are boys, thus 3/5 of the students are girls.   1/3 of the girls in the club study Spanish and 3/4 of the remaining girls study French.   Thus 1/4 of 2/3 = 1/6 of the girls study German.   Since girls comprise 3/5 of the students, then 3/5*1/6=1/10 of students are girls who study German.   The answer is n/10.
Answer: E
A semicircular cubicle has a radius of 14. What is the approximate perimeter of the cubicle?
Pick:
A) 55
B) 86
C) 25
D) 72
E) 35

Solution: perimeter of a circle =2pi*r   perimeter of a semicircle = pi*r + 2r   aprox perimiter = 3.14*14 + 2*14= 
3.14*14 + 2*14 = 71.96
71.96 approximately 72   answer 72
Answer: D
Jack went on a diet 6 months ago when he weighed 222 pounds. If he now weighs 198 pounds and continues to lose at the same average monthly rate, in approximately how many months will he weigh 180 pounds? Options: A) 3 B) 3,5 C) 4 D) 4,5 E) 5

Solution: Joe lost his weigh 24 pounds during 6 months. That means that he lost 4 pounds per month. He should lose more 18 pounds to be 180 pounds.   So it would take   18/4= 
  18/4 = 9/2 = around 4.5
4.5 months.   Correct answer is 4,5
Answer: D
Seven different books (A, B, C, D,E,F,G and H) are to be arranged on a shelf. Books A and B are to be arranged first and second starting from the right of the shelf. The number of different orders in which books C, D,E,F and G may be arranged is
Choose one:
A) 9!  B) 12!  C) 5!  D) 25!  E) 18!

Solution: Solution   Since books A and B are arranged first and second, only books C,D,E,F and G will change order. Therefore it an arrangement problem involving 5 items and the number of different order is given by   5!   Answer 5!
Answer: C
If two resistors, A(R1) and B(R2) stand in parallel with each other in electrical wire, the total resistor appears as R1R2/(R1+R2). If three resistors, A(R1), B(R2), and C(2R2) stand in parallel in electrical wire, what is the ratio Q of the resistors’ sum of A and C to the resistors’ sum of A and B?  Choose the correct answer:
A) 2(R1+R2):(R1+2R2)
B) (R1+R2):(R1+2R2)
C) (2R1+R2):(R1+2R2)
D) 2(R1+R2):(2R1+R2)
E) 2(R1-R2):(R1+2R2)

Solution: two resistors A (r1) and B (r2).   total or sum of two resistors appear as   r1r2/r1+r2. It is looks like inversion of sum of rates.   1/r1+1/r2= r1+r2/r1r2.   same way sum of A(r1) and c(2r2)=1/r1+1/2r2   =2r2+r1/r12r2.   inversion rate = r12r2/2r2+r1.   ratio of sum of a and c/sum of a and b=2r2r1/2r2+r1*r1+r2/r1r2   Q=2(r1+r2)/2r2+r1.2(R1+R2):(R1+2R2)
Answer: A
What is the median from the below series
5, 8, 11, 6, 10, 4, 18, 16, 13, 12 and 14 Answers.
A) 11	B) 5	C) 12	D) 13	E) 10

Solution: Ordering the data from least to greatest, we get:   4, 5, 6, 8, 10, 11, 12, 13, 14, 16, 18   The median number was 11. (Five numbers were higher than 11 and five were lower.)   11
Answer: A
A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?
Choose the correct choice
A) 32:48 B) 32:49 C) 32:45 D) 32:42 E) 32:41

Solution: A : B   (8000*4)+(4000*8) : (9000*6)+(6000*6)   64000 : 90000   32 : 45.Answer:32:45
Answer: C
Of the 800 employees of Company X, 80 percent have been with the company for at least ten years. If y of theselong-termmembers were to retire and no other employee changes were to occur, what value of y would reduce the percent oflong-termemployees in the company to 50 percent ?
Choose the correct answer:
A) 200
B) 160
C) 112
D) 480
E) 56

Solution: The # oflong-termemployees is 80%*800=640.   After y of them retire new # oflong-termemployees would become 640-y.   Total # of employees would become 800-y.   We want 640-y to be 60% of 800-y --> 640-y=(800 -y)*50% --> y = 480.   Answer: 480.
Answer: D
boring a well 60 m depth, the cost is
Rs.4/– for the first meter. The cost of each successive meter
increases by Rs.3/–. What is the cost of boring the entire well?
Pick one:
A) 5550  B) 5450  C) 5650  D) 5780  E) 5980

Solution: as it is increased by 3 rupees so   4+7+10+13........   first term a=4   difference=d=3 then   60th term=a+59d=181   total cost=n/2(a+l)=60/2(4+181)=5550   5550NSWER:5550
Answer: A
7 people (A, B, C, D, E, F and G) go to a movie and sit next to each other in 7 adjacent seats in the front row of the theater.
How many different arrangements are possible? If A will not sit to the left of F and F will not sit to the left of E. How many different arrangements are possible. Choose one: A) 7!/2 B) 7!/3 C) 7!/4 D) 7!/5 E) 7!/6

Solution: 7 people can be arranged in a row in 7! ways.   Now, three people among those 7 can be arranged in 3! = 6 ways:   AFE   AEF   EAF   EFA   FAE   FEA   From the 6 arrangements above only EFA is possible (A is not to the left of F and F is not to the left of E), so out of total 7! ways only in 1/6th of the arrangements they are sitting as they want.   Answer: 7!/6 (7!/6).
Answer: E
Five years ago, the average age of A and B was 15 years. Average age of A, B and C today is 20 years. How old will C be after 14 years?	Pick.
A) 30	B) 34	C) 40	D) 50	E) 60

Solution: Explanation :   (A + B), five years ago = (15 * 2)= 
(15 * 2) = 30
30 years.   (A+B), now= (30+5*2)= 
(30+5*2) = 40
40 years.   (A + B + C), now= (20 x 3) years =60 years.   C, now = (60 - 40)= 
(60 - 40) = 20
20 years.   C, after 14 years= (20 + 14)= 
(20 + 14) = 34
34 years.   Answer : 34
Answer: B
A soccer store typically sells replica jerseys at a discount of 30 percent to 50 percent off list price. During the annual summer sale, everything in the store is an additional 20 percent off the original list price. If a replica jersey's list price is $80, approximately what W percent of the list price is the lowest possible sale price?  Choose one
A) 20 B) 25 C) 30 D) 40 E) 50

Solution: Let the list price be 2x   for min sale price, the first discount given should be 50%, 2x becomes x here   now, during summer sale additional 20% off is given ie sale price becomes 0.8x   it is given lise price is $80   => 2x = 80   => x = 40   and 0.8x = 32   so lowest sale price is 32, which W is 40% of 80   hence, 40 is the answer
Answer: D
The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?  Choose the correct option.
A) 10522  B) 10528  C) 10560  D) 10529  E) 10561

Solution: Let the rate of interest be R% p.a.   4400{[1 + R/100]2 - 1} = 11193.60   [1 + R/100]2 = (44000 + 11193.60)/44000   [1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625   [1 + R/100]2 = 784/625 = (28/25)2   1 + R/100 = 28/25   R/100 = 3/25   Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100   =Rs.10560   Answer: 10560
Answer: C
After 114 liters of petrol were poured into the tank, it was still 5% empty. How much petrol must be poured into the tank in order to fill it? Pick one.
A) 7 liters
B) 4 liters
C) 3 liters
D) 2 liters
E) 6 liters

Solution: 95% ----------- 114   5% ------------ ?   => 6 liters   Answer: 6 liters
Answer: E
By selling a pen for Rs.15, a man loses one sixteenth of what it costs him.The cost price of the pen is	Choose the correct choice from the following options
A) Rs.16
B) Rs.18
C) Rs.20
D) Rs.21
E) None

Solution: Solution   Let the C.P be Rs.x.Then,   x-15=x/16	‹=›x-x/16 = 15   15x/16=15   x = 16.   Therefore, C.P= Rs.16.   Rs.16nswer Rs.16
Answer: A
A and B invests Rs.10000 each, A investing for 6 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.4500, find their shares? Select the correct option.
A) 1500,6000 B) 4500,3000 C) 3500,3000 D) 1500,3000 E) 2500,3000

Solution: The ratio of their profits A:B = 6:12 =1:2   Share of A in the total profit = 1/3 * 4500 = Rs.1500   Share of B in the total profit = 2/3 * 4500 = Rs.3000   Answer:1500,3000
Answer: D
Running at their respective constant rates, machine X takes 2 days longer to produce w widgets than machine Y. At these rates, if the two machines together produce 5/4 w widgets in 3 days, how many days would it take machine X alone to produce 1w widgets?
Choose the correct choice from the following choices
A) 4
B) 6
C) 8
D) 10
E) 12

Solution: Let Y produce w widgets in y Days   Hence, in 1 day Y will produce w/y widgets.   Also, X will produce w widgets in y+2 days (given, X takes two more days)   Hence, in 1 day X will produce w/y+2 widgets.   Hence together X and Y in 1 day will produce {w/y + w/y+2} widgets.   Together X and Y in 3 days will produce = 3 * [{w/y + w/y+2}] widgets.   It is given that in 3 days together they produce (5/4)w widgets.   Equating, 3 * [{w/y + w/y+2}] = (5/4)w   Take out w common and move 3 to denominator of RHS   w{1/y + 1/(y+2)} = (5/12)w   Canceling w from both sides   {1/y + 1/(y+2)} = 5/12   2y+2/y(y+2) = 5/12   24y+24=5y^2 + 10y   5y^2-14y-24=0   5y^2-20y+6y-24=0   5y(y-4)+6(y-4)=0   (5y+6)+(y-4)=0   y=-6/5 or y=4   Discarding y=-6/5 as no of days cannot be negative   y=4   hence it takes Y, 4 days to produce w widgets.   Therefore, it will take X  (4+2)= 
 (4+2) = 6
6 days to produce w widgets.   Hence it will take X 1*6= 
1*6 = 6
6 days to produce 1w widgets.   Answer : 6
Answer: B
1200 boys and 800 girls are examined in a test; 4% of the boys and 30% of the girls pass. The percentage of the total who failed is ?  Choose the correct option:
A) A)63.3%
B) B)52.4%
C) C)62.8%
D) D)75.4%
E) E)69.1%

Solution: Total number of students = 1200+800= 
1200+800 = 2_000
2000   Number of students passed= (42% of 1200+30% of 800) = 504+240= 
504+240 = 744
744   number of failures= 1256*100/2000= 
1256*100/2000 = 314/5 = around 62.8
62.8%   Answer is 62.8%
Answer: C
Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 70, what is the greatest possible value of Q minus R?	Choose the correct choice from the following options:  A) 63  B) 64  C) 65  D) 66  E) 67

Solution: A two-digit integer "ab" can be expressed algebraically as 10a+b.   Q-R=(10a+b)-(10b+a)=9(a-b)<70.   The greatest multiple of 9 which is less than 70 is 63.   The answer is 63.
Answer: A
A salt manufacturing company produced a total of 5000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year? Select:
A) 180
B) 185
C) 190
D) 195
E) 200

Solution: Total production of salt by the company in that year = 5000 + 5100 + 5200 + .... + 6100 = 66600.   Average monthly production of salt for that year = 66600/365 = 185   ANSWER:185
Answer: B