MU-NLPC/Calc-aqua_rat huggingface dataset:
The average age of 40 students is 8 years. If the age of teacher is also included , then their average age increases by half a year. What is the age of the teacher? Choose one.
A) 45 years  B) 48.5 years  C) 28.5 years  D) 26.5 years  E) 29.5 years

Solution: Exp. Total age of 40 students = 40*8= 
40*8 = 320
320   Let the age of the the teacher be x, Then (320+x)/41= 8+1/2 =8 ½.   320+x =17/2*41 =697/2= 
697/2 = 697/2 = around 348.5
348.5, x=348.5-320= 
348.5-320 = 28.5
28.5   Answer: 28.5 years
Answer: C
A, B and C have Rs.300 between them, A and C together have Rs.200 and B and C Rs.350. How much does C have?  Choose the most appropriate option:	A) A)250	B) B)249	C) C)248	D) D)247	E) E)246

Solution: 250+B+C = 300   250+C = 200   B+C = 350   --------------   250+B+2C = 550   250+B+C = 300   ----------------   C = 250   250nswer:250
Answer: A
Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old?
Choose the most appropriate option
A) 30
B) 80
C) 100
D) 130
E) 150

Solution: 20 stamps are both foreign and more than 10 years old.   70 stamps are foreign only.   30 stamps are 10 years old only.   The number of remaining stamps is  200 - (20+70+30)= 
 200 - (20+70+30) = 80
80   The answer is 80.
Answer: B
If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4960 , R will receive	Choose the correct choice from the following options:
A) 600 B) 700 C) 800 D) 960 E) None of these

Solution: Explanation :   Let P's capital = p, Q's capital = q and R's capital = r   Then   4p = 6q = 10r   => 2p = 3q = 5r   =>q = 2p/3   r = 2p/5   P : Q : R = p : 2p/3 : 2p/5   = 15 : 10 : 6   R's share = 4960 * (6/31) = 160*6= 
160*6 = 960
960. Answer : Option 960
Answer: D
The number of livestock in a farm at the beginning of year 2000 was 140,000. During the year, the number increased by p%. During the next year 2001, there was a famine and the number decreased by q%. A census at the end of year 2001 revealed that the number of livestock in the farm was 140,000. Which of the following expressions is correct?	Choose the correct choice from the following.
A) There is no relation between p and q	B) q > p	C) p = q	D) With the exception of 1 instance, p will be equal to q	E) p > q

Solution: Number plugging in will be best strategy for this question.   Let p = 5%,   Per the question 100000(1.05)(1-q/100) = 100000 ---> q = 4.7%. Thus p > q and hence p > q is the correct answer.
Answer: E
A and B can together finish a work in 10days. They worked together for 5days and then B left. After another 5days, A finished the remaining work. In how many days A alone can finish the job?	Pick:
A) 10 B) 15 C) 20 D) 5 E) 30

Solution: 10+B 5days work = 5*1/10 = 1/2   Remaining work = 1-1/2 = 1/2   1/2 work is done by 10 in 5days   whole work will be done by 10 in  5*2= 
 5*2 = 10
10days   10nswer is 10
Answer: A
Four hundred students at College Q study a foreign language. Of these, 190 of those students study French, and 260 study Spanish. If at least 105 students who study a foreign language at College Q study neither French nor Spanish, then the number of students who study Spanish but not French could be any number from	Choose the most appropriate option:
A) 10 to 40
B) 40 to 100
C) 60 to 100
D) 60 to 105
E) 70 to 110

Solution: 190 students study French   210 students do not study French   260 students study Spanish   140 students do not study Spanish   105 students study neither French nor Spanish   210-140= 
210-140 = 70
70   210-105=90   D. 60 to 105
Answer: D
40% of x is greater than 1/3rd of x by 110.what is x?	Choose the correct choice.
A) 1100	B) 2100	C) 1300	D) 1650	E) 1400

Solution: 4x/10-x/3=110   1x/15=110   x=1650   ANSWER:1650
Answer: D
The average weight of 4 person's increases by 1.5 kg when a new person comes in place of one of them weighing 95 kg. What might be the weight of the new person?	Choose the correct choice from the following answers
A) 101 kg  B) 103.4 kg  C) 105 kg  D) Data inadequate  E) None of these

Solution: Total weight increased = (4 x 1.5) kg = 6 kg.   Weight of new person = (95 + 6)= 
(95 + 6) = 101
101 kg.   101 kgnswer: Option 101 kg
Answer: A
Anne has pouches of grain that she wants to divide between the different areas of the petting zoo. Unfortunately, Anne's pouches of grain don't divide evenly. It turns out that in order for the pouches of grain to divide evenly, Anne will have to purchase two additional pouches of grain, and not visit two of the petting zoo areas. Which of the following can describe the initial number of grain pouches, and the initial number of areas in the petting zoo (in the order areas of the petting zoo; pouches of grain)?	Choose the correct choice from the following answers:
A) 20; 5.	B) 16; 5.	C) 12; 4	D) 30; 4	E) 21; 7

Solution: Option B) Initially 16 petting zoo areas, then decreased to 14 petting zoo areas; and Initially 5 pouches of grain, then icreased to 7 pouces of grain fits the requirement.   14 / 7= 
14 / 7 = 2
2 pouches of grain per petting zoo area
Answer: B
A group of tourists wants to visit at least three of the four cities A, B, C, and D. How many travel itineraries can they make? All cities are connected to one another and please note that visiting the same cities in a different order counts as a different itinerary.	Choose the correct choice from the following choices:  A) 24  B) 36  C) 48  D) 60  E) 64

Solution: The number of ways to choose three cities is 4C3=4.   The number of itineraries for each group of 3 cities is 3!.   So the number of itineraries to three cities is 4*3!=24.   The number of ways to choose four cities is 4C4=1.   The number of itineraries for the group of 4 cities is 4!.   So the number of itineraries to four cities is 4!=24.   The total number of itineraries is   24+24= 
  24+24 = 48
48.   The answer is 48.
Answer: C
2/3rd of the boys and 3/4th of the girls of a school participate in a function. If the no.of participating students is 550, out of which 150 are girls, what is the total no.of students in the school?  Choose the correct choice:
A) 620
B) 780
C) 800
D) 880
E) 900

Solution: Let total number of boys be x and total number of girls be y. y=400=>x = 600and^= I50=>y = 200 Now, x + y = 800   800
Answer: C
The owner of a furniture shop charges his customer 20% more than the cost price. If a customer paid Rs. 3000 for a computer table, then what was the cost price of the computer table?
Choose the correct option:
A) 2500	B) 2772	C) 1991	D) 6725	E) 2099

Solution: CP = SP * (100/(100 + profit%))   = 3000(100/120) = Rs. 2500.   2500nswer: 2500
Answer: A
If f(x) =6* (x^4 - 1)/(x^2), what is f(1/x) in terms of f(x)?  Pick:
A) f(x) B) -f(x) C) 1/f(x) D) -1/f(x) E) -6*f(x)

Solution: f(1/x) =6* ((1/x)^4 - 1) / ((1/x)^2)   = 6*((1/x^4) - 1) / (1/x^2)   = 6*((1-x^4)/(x^4)) / (1/x^2)   = 6*(1-x^4)/(x^2)   = - 6*( (x^4) -1) / (x^2)   = -6f(x)   Answer is -6*f(x).
Answer: E
Mangoes, Oranges and Apples in a fruit shop are in the ratio of 10: 2 : 3. If there are 120 Mangoes, the number of Apples in the shop is:.  Choose the correct choice:
A) 36  B) 42  C) 72  D) 400  E) 56

Solution: Explanation :   Let Mangoes = 10x, Oranges = 2x & Apples = 3x. Now, 10x = 120 hence x = 12.   Number of Apples = 3x = 36.   36nswer : 36
Answer: A
The average age of a group of 10 persons was decreased by 3 years when one person, whose age was 42 years, was replaced by a new person. Find the age of the new person?  Choose the correct option:	A) 11	B) 19	C) 12	D) 17	E) 14

Solution: Initial average age of the 10 persons be P.   Age of the new person Q.   Sum of the ages of the initial 10 persons = 10P   New average = (P-3) 10(P-3) = 10P - 42 + Q => Q   = 12   Answer: 12
Answer: C
There are 3 classes having 20, 24 and 30 students respectively having average marks in
an examination as 20,25 and 30 respectively. The three classes are represented by A, B and C and you have the following information about the three classes.
a. In class A highest score is 22 and lowest score is 18
b. In class B highest score is 31 and lowest score is 23
c. In class C highest score is 33 and lowest score is 26.
Options
A) can't be determined in both cases  B) definite decrease in both cases  C) definite increase in both cases  D) will remain constant in both cases  E) will remain constant in both cases21

Solution: Ans: B   Explanation:   Class A average is 20. And their range is 18 to 22   Class B average is 25. And their range is 23 to 31   Class A average is 30. And their range is 26 to 33   If 5 students transferred from A to B, A's average cannot be determined but B's average comes down as the highest score of A is less than lowest score of B.   If 5 students transferred from B to C, C's average cannot be determined the B's range fo marks and C's range of marks are overlapping.   can't be determined in both casesnswer:can't be determined in both cases
Answer: A
The price of a jewel, passing through three hands, rises on the whole by 65%. If the first and second sellers earned 20% and 25% profit respectively, find the percentage profit earned by the third seller.	Select:
A) 10% B) 22% C) 18% D) 12% E) 15%

Solution: Let the original price of the jewel be Rs. P and let the profit earned by the third seller   be x%.   Then, ( 100 +x )% of 125% of 120% of P = 165% of p   [ ( 100+x )/100*125/100*120/100* P ] = [ 165/100* P ]   ( 100 + X ) = 165*100*100/125*120 = 110,   X = 10%.   10%NSWER:10%
Answer: A
A ship sails out to a mark at the rate of 19 kmph. and sails back at the rate of 13 kmph. The average rate of sailing is ?	Choose the correct option.
A) 15 km/hr  B) 12 km/hr  C) 12.5 km/hr  D) 25 km/hr  E) None

Solution: Answer   Average = ( 2uv / u +v ) km/hr   = ( 2 x 19 x 13 ) / (19 +13 ) km/hr.   = 15 km/hr.   Correct Option: 15 km/hr
Answer: A
Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 30 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?	Options.
A) 12 sec  B) 24 sec  C) 48 sec  D) 60 sec  E) 62 sec

Solution: Relative speed = 30 + 30= 
30 + 30 = 60
60 km/hr.   60 * 5/18= 50/3 m/sec.   Distance covered = 500 + 500= 
500 + 500 = 1_000
1000 m.   Required time= 1000 * 3/50= 
1000 * 3/50 = 60
60 sec.   ANSWER:60 sec
Answer: D
If x is positive integer,y is negative integer, and 3x + 2y = 13, which of the following could be the value of x ?  Choose the correct choice from the following answers:
A) 9
B) 10
C) 12
D) 13
E) 4

Solution: Use answer options to solve this problem -   Put x= 9   3x+2y=13   3(9)+2y=13   27+2y=13   2y=13-27;2y=-14   y=-7(y is negative integer)   9nswer will be (9)
Answer: A
Some of the workers at a hedge fund are analysts; the others are not analysts. There are a total of 2x/3 analysts at the hedge fund. A total of x hedge fund workers have an MBA. Furthermore, x/3 analysts have an MBA, y/4 of the hedge fund workers are neither analysts nor have an MBA, and 70 workers are not analysts. If there are y total workers at the hedge fund, x is equal to which of the following?
Choose the correct choice from the following answers:  A) 45  B) 50  C) 63  D) 75  E) 80

Solution: AnalystsNot AnalystsTotal   MBAx/32x/3x   No MBAy/4   Total2x/350y   We are asked for the value of x.   From the table: 2x/3 = y - 70   y - 70 + (y/4) = 70   5y/4 = 140   y = 112   2x/3 = 112 - 70= 
112 - 70 = 42
42   x= 126/2= 
126/2 = 63
63   Answer: 63
Answer: C
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is:
Choose the correct choice from the following answers.
A) 4 B) 6 C) 5 D) 7 E) 9

Solution: N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)   = H.C.F. of 3360, 2240 and 5600 = 1120.   Sum of digits in N = ( 1 + 1 + 2 + 0 )= 
( 1 + 1 + 2 + 0 ) = 4
4   4nswer: Option 4
Answer: A
If the true discount on a sum due 3 years hence at 14% per annum be Rs. 168, the sum due is:  Choose the correct choice from the following options:
A) 698  B) 768  C) 1430  D) 1980  E) None

Solution: Sol.   P.W. = 100 * T.D./R * T = 100 * 168 / 14 * 2 = 600.   ∴ Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.   Answer 768
Answer: B
William earned $9.50 an hour. He worked 40 hours one week and received a bonus
of $75.00. How much did he earn that week?	Choose the correct answer: A) $455.00 B) $555.00 C) $655.00 D) $755.00 E) $855.00

Solution: Multiply $9.50 x 40 = $380.00   $455.00dd bonus $75.00 + $380.00= $455.00   $380.00   + 75.00   $455.00   correct answer $455.00 75.00 +  380.00= 
 75.00 +  380.00 = 455
$455.00   $380.00   + 75.00   $455.00   correct answer $455.00
Answer: A
Find the unit's digit in the product 2467 153 * 34172?	Choices
A) 1  B) 3  C) 2  D) 5  E) 7

Solution: Unit's digit in the given product=Unit's digit in 7 153 * 172   Now 7 4 gives unit digit 1   7 152 gives unit digit 1   7 153 gives  1*7= 
 1*7 = 7
7.Also 172 gives 1   Hence unit's digit in the product=7*1= 
7*1 = 7
7.   Option 1
Answer: A
Find the surface area of a 10cm*4cm*3cm brick.	Pick one.
A) 154 cm square B) 156 cm square C) 160 cm square D) 164 cm square E) None of these

Solution: Explanation:   Surface area of a cuboid = 2(lb+bh+hl) cm square   So,   Surface area of a brick = 2(10*4+4*3+3*10) cm square   = 2(82) cm square = 164 cm square   Option 164 cm square
Answer: D
The banker's discount on a sum of money for 3 years is Rs. 1116. The true discount on the same sum for 4 years is Rs. 1200. What is the rate per cent?	Choose the correct choice from the following choices:
A) 8%	B) 12%	C) 10%	D) 6%	E) 7%

Solution: Explanation :   BD for 3 years = Rs. 1116   BD for 4 years = 11163 × 4 = Rs. 1488   TD for 4 years = Rs. 1200   F = BD × TD(BD – TD) = (1488 × 1200)/(1488–1200) = (1488×1200)/288   = (124 × 1200)/24 = (124 × 100)/2 = 62 × 100 = Rs. 6200   => Rs.1488 is the simple interest on Rs. 6200 for 4 years   ⇒ 1488 = (6200 × 4 × R)/100   ⇒ R = (1488 × 100)/(6200 × 4)   = (372 × 100)/6200 = 372/62= 
372/62 = 6
6% Answer : Option 6%
Answer: D
If the average (arithmetic mean) of a and b is 100, and c – a = 120, what is the average of b and c?	Pick:  A) 150  B) 140  C) 160  D) 170  E) 180

Solution: a+b/2 = 100   => a+b = 200   a = c - 120...sub this value   c-120+b = 200   =>c+b = 320   =>c+b/2 = 160   Answer : 160
Answer: C
In the x-y plane, the area of the region bounded by the graph of |x+y| + |x-y| = 8 is  Choose the correct choice from the following answers:  A) 8  B) 12  C) 256  D) 20  E) 24

Solution: I've never seen such kind of question in GMAT before.   OK there can be 4 cases:   |x+y| + |x-y| = 8   A. x+y+x-y = 8 --> x=4   B. x+y-x+y = 8 --> y=4   C. -x-y +x-y= 8 --> y=-4   D. -x-y-x+y=8 --> x=-4   The area bounded by 4 graphs x=4, x=-4, y=4, y=-4 will be square with the side of 4 so the area will be 16*16= 
16*16 = 256
256   Answer: 256
Answer: C
A bowl has only 7 apples and 7 bananas. If one piece of fruit is selected from the bowl at random, and a second piece is selected from the bowl without replacing the first, what is the probability that both pieces of fruit chosen are apples?
Pick one
A) 1/10
B) 1/5
C) 2/9
D) 2/5
E) 3/13

Solution: 7/14 * 6/13   =3/13   E. 3/13
Answer: E
There are 7 players in a bowling team with an average weight of 121 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight?	Choose the correct choice from the following answers
A) 115 Kg. B) 118 Kg. C) 113 Kg. D) 110 Kg. E) 112 Kg.

Solution: The New average will be= (121*7+110+60)/9= 
(121*7+110+60)/9 = 113
113 kgs   113 Kg. is the answer
Answer: C
Can you find next number in tricky mathematical series below?
111 , 113 , 117 , 119 , 123 , 137 ?  Choose the correct choice from the following.
A) 151
B) 161
C) 171
D) 131
E) 121

Solution: Solution:   151 (131+20)   Explanation:   1st 7 prime numbers post 100 are   101 , 103 , 107 , 109 , 113 , 127 , 131   ...151dding 20 to numbers   121 , 123 , 127 , 129 , 133 , 147 , 151   151nswer 151
Answer: A
A and B working separately can do a piece of work in 9 and 12 days respectively, If they work for a day alternately, A beginning, in how many days, the work will be completed? Select the correct option.
A) 9 days  B) 11 days  C) 8 days  D) 10 1/4 days  E) None of them

Solution: (A + B)'s 2 days' work =(1/9+1/12)=7/36   Work done in 5 pairs of days =(5*7/36)=35/36   Remaining work =(1-35/36)=1/36   On 11th day, it is A’s turn. 1/9 work is done by him in 1 day.   1/36 work is done by him in(9*1/36)=1/4 day   Total time taken = (10 + 1/4) days = 10 1/4days.   Answer is 10 1/4 days.
Answer: D
There are two numbers. If 30% of the first number is added to the second number, then the second number increases to its six-fifth. What is the ratio of the first number to the second number?
Pick:
A) 1 : 4  B) 4 : 5  C) 3 : 5  D) 5 : 8  E) 2 : 3

Solution: Let the two numbers be x and y.   (3/10) * x + y = (6/5) * y   (3/10) * x = (1/5) * y   x/y = 10/15 = 2/3   The answer is 2 : 3.
Answer: E
If q is an odd integer, which of the following must also be odd?  Choose the most appropriate option:  A) 6q + 4  B) q + q  C) 3q + 3  D) 2q + q  E) q^2 + 1

Solution: Things to keep in mind:   Odd + odd = even   Odd + even = odd   Odd*odd = odd   Odd*even = even   On checking each option   A. 6q + 4   6q = even, 6q + 4 = even + even = even.   B. q + q   Odd + odd = even. This will be even   C. 3q + 3   3q = odd, 3q + 3 = odd + odd = even   D. 2q + q   2q = even, 2q +q = even + odd = odd   E. q^2 + 1   q^2 = odd, q^2 + 1 = odd + odd = even   Correct option: 2q + q
Answer: D
The average age of a group of 5 members is 20 years. Two years later, a new member joins the group. The average age of the group becomes 20 years. What is the age of the new member ?
Pick one.
A) 20 years  B) 21 years  C) 10 years  D) 23 years  E) 24 years

Solution: The average age of a group of 5 members is 20 years --> the sum of the ages is  5*20= 
 5*20 = 100
100;   Two years later the sum of the ages of these 5 members would be 100+5*2= 
100+5*2 = 110
110;   Now, say the age of the new member is x years, so the sum of the ages of a new 6 member group is 110+x. Since given that the average age of this group of 6 members is 20 years then: 20*6=110+x --> x=10.   Answer: 10 years.
Answer: C
If M and N are positive integers, and the remainder obtained when M is divided by N is the same as the remainder obtained when N is divided by M, which of the following is a possible value of MN? Choose one:
A) 62	B) 55	C) 42	D) 35	E) 16

Solution: I am not too sure on this. I guess it is possible only when M and N are both same. If they are both same, MN must be a perfect square.   16 is a perfect square.   Ans:16
Answer: E
A is half good a work man as B and together they finish a job in 15 days. In how many days working alone B finish the job?
Choose the correct choice.
A) 23	B) 22	C) 45/2	D) 36	E) 48

Solution: 45/2   45/2   W45/2 = 1:2   2x + x = 1/15 => x = 1/45   2x = 2/45 => 45/2 days
Answer: C
Bobby bought 2 shares, and which he sold for $96 each. If he had a profit of 80% on the sale of one of the shares but a loss of 80% on the sale of the other share, then on the sale of both shares Bobby had...  Options.
A) a profit of 10 B) a profit of 8 C) a loss of 800 D) a loss of 342 E) neither a profit nor a loss

Solution: Cost of the first stock: 96/1.8=53.33, so profit from it  96-53.33= 
 96-53.33 = 42.67
42.67   Cost of the second stock:   96/0.2= 
  96/0.2 = 480
480, so loss from it 96-480=-384   Overall loss 42.67-384=-342   Answer: a loss of 342.
Answer: D
Denise is trying to open a safe whose combination she does not know.
IF the safe has 4000 possible combinations,and she can try 75 different
possibilities,what is the probability that she does not pick the one
correct combination.	Options:  A) 1  B) 159/160  C) 157/160  D) 4 3/160  E) 0

Solution: When trying the first time the probability Denise doesn't pick the correct combination=3999/4000   Second time, as the total number of possible combinations reduced by one, not picking the right one would be 3998/3999.   Third time 3997/3998   ...   And the same 75 times.   So we get: 3999/4000∗3998/3999∗...∗3925/39263999/4000∗3998/3999∗...∗3925/3926 every denominator but the first will cancel out and every nominator but the last will cancel out as well.   We'll get 3925/4000=157/160.   Answer: 157/160.
Answer: C
A man purchased a grinder for Rs. 600 and sold it at a profit of 12%. The selling price is: Choose the correct option
A) Rs. 672 B) Rs. 812 C) Rs. 684 D) None of these E) Cannot be determined

Solution: s.p.=112/100 × 600=672   Rs. 672nswer: Rs. 672
Answer: A
Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is ?  Select
A) 5/16
B) 5/12
C) 5/87
D) 5/56
E) 5/38

Solution: Using question number 11 and 12, we get the probability as   1 - (1/36 + 5/9) = 5/12   Answer:5/12
Answer: B
If a train, travelling at a speed of 90 kmph, crosses a pole in 4 sec, then the length of train is? Choose the correct choice from the following answers:
A) 281
B) 125
C) 288
D) 100
E) 121

Solution: 100 = 90 * 5/18 * 4= 
90 * 5/18 * 4 = 100
100 m   Answer: 100
Answer: D
X divided by Y equals 6.32 what is a possible remainder?	Pick: A) 2 B) 4 C) 6 D) 8 E) 7

Solution: With the decimal being 32/100, the simplest form is 8/25. If the divisor is a multiple of 25, the remainder must be a multiple of 8. The only number that is so is 8. Answer 8.
Answer: D
A dishonest dealer professes to sell goods at the cost price but uses a weight of 723 grams per kg, what is his percent?  Choose the correct choice from the following answers:  A) 38.3%  B) 25%  C) 77%  D) 99%  E) 12%

Solution: 723 --- 277   100 --- ? => 38.3%   38.3%nswer: 38.3%
Answer: A
Find the area of a parallelogram with base 32 cm and height 15 cm. Choose the correct choice from the following answers:  A) 200  B) 384  C) 345  D) 480  E) 242

Solution: Area of a parallelogram = base * height = 32 * 15= 
32 * 15 = 480
480 cm2   Answer: Option 480
Answer: D
During the first two weeks of February, the total rainfall in Springdale was 20 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of February?	Choose the most appropriate option
A) 5	B) 6	C) 9	D) 10	E) 12

Solution: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.   2.5x = 20   x = 8   The rainfall during the second week was  1.5 * 8= 
 1.5 * 8 = 12
12 inches   The answer is 12.
Answer: E
A train covers a distance of 100km in 1 hour. If its speed is decreased by 10km/hr, the time taken by the car to cover the same distance will be?
Choose the correct choice:
A) 1hr
B) 1hr 6min
C) 50min
D) 1hr 30min
E) 1hr 45min

Solution: Speed = 100/1= 
100/1 = 100
100km/hr   New speed= 100-10= 
100-10 = 90
90 km/hr   Time taken= 100/90 = 1hr 6min   Answer is 1hr 6min
Answer: B
If 8 men and 2 boys working together, can do seven times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time? Pick one:
A) 1:5	B) 2:3	C) 3:8	D) 5:1	E) 5:2

Solution: 8M + 2B = 7(1M + 1B)   8M + 2B = 7M + 7B   1M = 5B   The required ratio of work done by a man and a boy = 5:1   Answer:5:1
Answer: D
An empty pool being filled with water at a constant rate takes 3 hours to fill to 3/5 of its capacity. How much more time will it take to finish filling the pool?
Pick one:
A) 5 hr 30 min  B) 5 hr 20 min  C) 4 hr 48 min  D) 3 hr 12 min  E) 2 hr 00 min

Solution: (3/5) of a pool/ 2 hours = 1/5 (the rate)   (1 pools/5 hours) = (2/5* pool)/ x hours   Cross multiply x = (2/5) 5   x = 2   2 hr 00 min
Answer: E
One train is traveling 72 kmph and other is at 10 meters a second. Ratio of the speed of the two trains is?
Pick one.
A) 5:4	B) 5:6	C) 2:1	D) 5:4	E) 5:1

Solution: 72 * 5/18 = 10   20:10 => 2:1   Answer: 2:1
Answer: C
11 times a number gives 132. The number is	Pick one
A) 11 B) 12 C) 13.2 D) None E) Cannot be determined

Solution: Explanation:   Let the number be 'N'   11×N=132⇒N=12   Correct Option: 12
Answer: B