MU-NLPC/Calc-aqua_rat huggingface dataset:
The perimeter of a triangle is 28 cm and the inradius of the triangle is 2.5 cm. What is the area of the triangle?  Pick:
A) 28 cm2
B) 27 cm2
C) 29 cm2
D) 25 cm2
E) 35 cm2

Solution: Area of a triangle = r * s   Where r is the inradius and s is the semi perimeter of the triangle.   Area of triangle = 2.5 * 28/2= 
2.5 * 28/2 = 35
35 cm2   Answer: 35 cm2
Answer: E
A newly-wed couple is using a website to design an eBook Wedding Album to distribute to their friends and families. The template they have chosen has places for 3 large photos and 19 smaller photos. The couple has 5 large photos they could use for those three slots, and 21 smaller photos they could use for those 19 slots. Given these choices, how many different possible albums could they create?
Pick:
A) 2,100
B) 4,200
C) 5,040
D) 20,520
E) 84,000

Solution: MAGOOSHOFFICIAL SOLUTION:   For the large photos, we need 5C3, which we calculated in the article:   5C3 = 10   For the smaller photos, we need 21C19, which by symmetry must equal 21C2, and we have a formula for that. In fact, in the article above, we already calculated that 21C2 = 210.   Now, by the FCP, we just multiply these: total number of possible albums = 10*210= 
10*210 = 2_100
2100.   2,100nswer= 2,100
Answer: A
Two cars start from the same places in opposite directions. One is going towards north at 60 kmph and the other is going towards south 40kmph. What time will they take to be 100km apart?  Choose the correct answer.
A) 1hr	B) 2hrs	C) 3hrs	D) 4hrs	E) 5hrs

Solution: To be (60+40) km apart, they take 1 hour   To be 100 km apart, they take   1/100 *100= 
  1/100 *100 = 1
1 hr   1hrnswer is 1hr
Answer: A
Two teams are distributing information booklets. Team A distributes 60% more boxes of booklets than Team Z, but each box of Team A’s has 60% fewer booklets than each box of Team Z’s. Which of the following could be the total number of booklets distributed by the two groups?
Choose the correct choice from the following options.
A) 2,000	B) 3,200	C) 4,100	D) 4,800	E) 4,900

Solution: Let x be the no of booklets in each box that team distributes. So, Team A has 60% fewer - 0.4x.   Let y be the no. of boxes distributed by team Z. So, Team A distributes 60% more - 1.6y   Total booklets distributed by team A = xy   Total booklets distributed by team Z=0.64xy   Total booklets distributed = xy+0.64xy=1.64xy   As no. of booklets can only be integer, plugging the answer choice equal to 1.64xy should give an integer.   Choice A - 1.64xy=2000; xy=2000/1.64 = doesn't provide an integer value.   Similarly all answer choices, except choice C, fail to provide an integer value.   4,100hoice 4,100 = 4100/1.64= 
4100/1.64 = 2_500
2500 and is the correct answer.
Answer: C
Which of the following can be expressed as a terminating decimal?	Choose the most appropriate option.
A) 1/25 + 1/35  B) 1/225 + 1/1,250  C) 1/11,000 + 1/13,000  D) 1/75 + 1/35  E) 1/125 + 1/8

Solution: In such questions, it is always easier to find an answer instead of eliminating choices. Let us start with the simplest ones first.   A. 1/25 + 1/35 = 12/175 = 12/25*1/7   1/7 does is not a terminating decimal.   E. 1/125 + 1/8 = 8 + 125/ 1000 = 133/1000   This is a terminating decimal and our answer.   Correct Option: 1/125 + 1/8
Answer: E
The average score in an examination of 10 students of a class is 60. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 40 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is  Choices
A) 87	B) 95	C) 99	D) 100	E) 103

Solution: If the value of all other except the largest is 55..   Largest will be 60*10-55*9=600-495=105..   However the top 5 are distinct and the smallest of these can be 55, so remaining THREE will be 1,2,&3 more so total combined value will be 1+2+3 or 6 more..   Therefore the largest will be 6 less than max possible..... 105-6=99   ANSWER:99
Answer: C
Oranges are bought at 7 for Rs.3. At what rate per hundred must they be sold to gain 33%? Choose the correct option.
A) 57  B) 58  C) 59  D) 54  E) 55

Solution: 7 oranges bought for rs 3   1 orange cost =3/7   therefore for 100 oranges =100*(3/7)   gain =33%    300/7+(33/100)*300/7= 
 300/7+(33/100)*300/7 = 57
rate per hundred he want to sell   ans :57   57NSWER:57
Answer: A
The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 10%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ?  Select:
A) 45  B) 40  C) 35  D) 47.61  E) 30

Solution: Let the price of tea and coffee be x per kg in June.   Price of tea in July = 1.2x   Price of coffee in July = 0.9x .   In July the price of 1/2 kg (500gm) of tea and 1/2 kg (500gm) of coffee (equal quantities) = 50   1.2x(1/2) + 0.9x(1/2) = 50   => x =47.61   47.61
Answer: D
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective? Choose the correct choice from the following:
A) 1/126
B) 1/122
C) 1/129
D) 1/136
E) 1/126

Solution: Out of nine, five are good and four are defective. Required probability   = ⁴C₄/⁹C₄   = 1/126   Answer:1/126
Answer: E
The average of 12 result is 55. Average of the first 6 of them is 42 and that of the last 6 is 48. Find the 8th result? Choose the correct choice from the following options.
A) 35
B) 564
C) 526
D) 48
E) 50

Solution: Sum of all the 12 results = 12 * 55= 
12 * 55 = 660
660   Sum of the first 6 of them= 6 * 42= 
6 * 42 = 252
252   Sum of the last 6 of them= 6 * 48= 
6 * 48 = 288
288   So, the 8th number= 600 + 252 - 288= 
600 + 252 - 288 = 564
564.   564
Answer: B
After replacing an old member by a new member, it was found that the average age of five members of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member ? Choose the correct choice from the following options:
A) 12
B) 13
C) 14
D) 15
E) 16

Solution: Explanation:   i) Let the ages of the five members at present be a, b, c, d & e years.   And the age of the new member be f years.   ii) So the new average of five members' age = (a + b + c + d + f)/5 ------- (1)   iii) Their corresponding ages 3 years ago = (a-3), (b-3), (c-3), (d-3) & (e-3) years   So their average age 3 years ago = (a + b + c + d + e - 15)/5 = x ----- (2)   ==> a + b + c + d + e = 5x + 15   ==> a + b + c + d = 5x + 15 - e ------ (3)   iv) Substituting this value of a + b + c + d = 5x + 15 - e in (1) above,   The new average is: (5x + 15 - e + f)/5   Equating this to the average age of x years, 3 yrs, ago as in (2) above,   (5x + 15 - e + f)/5 = x   ==> (5x + 15 - e + f) = 5x   Solving e - f = 15 years.   Thus the difference of ages between replaced and new member = 15 years. Answer: 15
Answer: D
If x = a!, which of these following values of a is the least possible value (in this list) for which the last 8 digits of the integer x will all be zero?  Pick
A) 21  B) 29  C) 37  D) 41  E) 80

Solution: 2*5 will give one 0 at the end. We need 2^8*5^8 to get 8 zeroes at the end.   There are many 2's, so we need to find the first 8 appearances of 5.   These multiples of 5 are: 5, 10, 15, 20, 5*5, 30, 35...which gives us 8.   To have at least 8 zeroes at the end, a => 35.   The answer is 37.
Answer: C
Sreedhar and Sravan together can do a work in 25 days. With the help of Pavan, they completed the work in 8 days and earned Rs. 225. What is the share of Sravan, if Sreedhar alone can do the work in 75 days?  Choose the correct choice from the following options.
A) $42  B) $46  C) $48  D) $49  E) $41

Solution: C   $48   Sravan's one day's work = 1/25 - 1/75 = 2/75   Sravan worked for 8 days. So, his 8 days work = 8 * 2/75 = 16/75   Sravan completed 16/75th of total work.   So, his share is   16/75 * 225= 
  16/75 * 225 = 48
$48.
Answer: C
If logx y =100 and log2 x =10, then the values of y is	Answers.
A) 2(10)  B) 2 (100)  C) 2 (1000)  D) 2 (10000)  E) None of these

Solution: Solution   log2 x	= 10   x= 210   logx y	= 100   y= x100   =(210)100   y‹=›2(1000)   Answer 2 (10000)
Answer: D
P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?	Choose the correct choice from the following answers:
A) 9 days  B) 9 (3/5) days  C) 11 1/5 days  D) 13 days  E) 13 1/7

Solution: Amount of work P can do in 1 day = 1/16   Amount of work Q can do in 1 day = 1/12   Amount of work P, Q and R can together do in 1 day = 1/4   Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48   => Hence R can do the job on 48/5 days = 9 (3/5) days   9 (3/5) days)
Answer: B
In how many ways can a committee consisting of 4 men and 5 women be formed from a group of 7 men and 7 women?  Select.
A) 7C4 7C5 B) 4C7 5C7 C) 7C5 9C4 D) 9C4 7C5 E) NONE

Solution: Group consisting of 7 men and 7 women   4 men can be selected from 7 men in 7C4 ways   5 women can be selected from 7 women in 7C5 ways   Therefore, Total number of ways= 7C4 7C5   7C4 7C5NSWER:7C4 7C5
Answer: A
Each week, Harry is paid x dollars per hour for the first 24 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours If Harry and James were paid the same amount last week, how many hours did Harry work last week ? Choices
A) 35
B) 36
C) 37
D) 38
E) 39

Solution: 42x=24x+1.5x(H-24)   ==> 42=24+1.5(H-24)   ==> H-24 = 18/1.5= 
18/1.5 = 12
12=> H = 36   Answer is 36
Answer: B
At Jefferson Elementary School, the number of teachers and students (kindergarten through sixth grade) totals 510. The ratio of students to teachers is 16 to 1. Kindergarten students make up 1/8 of the student population and fifth and sixth graders account for 1/3 of the remainder. Students in first and second grades account for 1/4 of all the students. If there are an equal number of students in the third and fourth grades, then the number of students in third grade is how many greater or fewer than the number of students in kindergarten?
Choices:
A) 8 greater
B) 17 fewer
C) 28 fewer
D) 36 fewer
E) 44 fewer

Solution: Soln>> from the given ratio of 16:1 u can derive that ter are 480 students   KG= 1/8* 480= 
1/8* 480 = 60
60   5th and 6th graders= 1/3 * 384= 
1/3 * 384 = 128
128 (1/3 of remainder)   1st and 2nd grade= 1/4 * 480= 
1/4 * 480 = 120
120 ( 1/4 of all students)   equal number of students in 3rd and 4th=> 480 - 344= 
480 - 344 = 136
136 and   136/2= 
  136/2 = 68
68 each since equal number   (344 is the sum of remaining students)   thus 60-68=-8>>> therfore answer is 8 greater   8 greater
Answer: A
To produce an annual income of Rs. 800 from a 8% stock at 90, What is the amount of stock needed?  Select the correct option:
A) 10000	B) 11000	C) 12000	D) 13000	E) 14000

Solution: Since face value is not given, take it as Rs.100.   10000s it is an 8% stock, income (dividend) per stock = Rs.8   ie, For an income of Rs.8,amount of stock needed = Rs.100   For an income of Rs.800, amount of stock needed = 100×800/8=10000   10000nswer is 10000.
Answer: A
In Arun’s opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun’s weight is greater than 60 kg but less than 70 kg. His mother’s view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun? Choose the correct choice from the following:
A) 66 kg	B) 67 kg	C) 68 kg	D) 69 kg	E) None of these

Solution: Explanation:   Let Arun’s weight by X kg.   According to Arun, 65 < X < 72   According to Arun’s brother, 60 < X < 70.   According to Arun’s mother, X <= 68   The values satisfying all the above conditions are 66, 67 and 68.   Required average = [66+67+68/3]=[201/3= 
201/3 = 67
67kg   Answer 67 kg
Answer: B
The difference in compound interest earned on a deposit (compounded annually) in year 1 and year 2 is $ 40. Had the interest rate been three times its present value, the difference would have been how much?	Choose the correct option.
A) 40/3 B) 40 C) 120 D) 360 E) 420

Solution: CASE 1:   Deposit = $x;   Rate of increase = r.   Interest yearned in 1 year = xr. Deposit in 1 year = x + xr.   Interest yearned in 2 year = (x + xr)r.   The difference = (x + xr)r - xr = xr^2 = 40.   CASE 2:   Deposit = $x;   Rate of increase = 3r.   Interest yearned in 1 year = x(3r). Deposit in 1 year = x + 3xr.   Interest yearned in 2 year = (x + 3xr)3r.   The difference = (x + 3xr)3r - 3xr = 9xr^2. Since from CASE 1 we know that xr^2 = 40, then 9xr^2 = 9*40= 
9*40 = 360
360.   Answer: 360
Answer: D
Carrie likes to buy t-shirts at the local clothing store. They cost $9.95 each. One day, she bought 20 t-shirts. How much money did she spend? Choose the correct choice from the following answers:
A) $150
B) $248.75
C) $199
D) $171.6
E) $190

Solution: $9.95*20= 
9.95*20 = 199
$199. Answer is $199.
Answer: C
A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 2 hour to row to a place and come back, how far is the place?	Choose the correct choice from the following answers
A) 2.4 km
B) 4.8 km
C) 3.4 km
D) 4.4 km
E) 5.6 km

Solution: Explanation:   Speed in still water = 5 kmph   Speed of the current = 1 kmph   Speed downstream = (5+1)= 
(5+1) = 6
6 kmph   Speed upstream= (5-1)= 
(5-1) = 4
4 kmph   Let the required distance be x km   Total time taken= 2 hour   â‡’ x/6+x/4=2   â‡’2x+3x=24   â‡’5x=24   â‡’x=4.8 km   Answer: Option 4.8 km
Answer: B
A van takes 5 hours to cover a distance of 600 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time?	Pick one:
A) 80
B) 84
C) 88
D) 92
E) 96

Solution: (3/2)*5= 
(3/2)*5 = 15/2 = around 7.5
7.5 hours   600 / 7.5= 
600 / 7.5 = 80
80 kph   The answer is 80.
Answer: A
The sum of the ages of 5 children born at the intervals of 3 year each is 50 year. what is the age of the eldest child ?  Pick one:
A) 16 year
B) 8 year
C) 10 year
D) None of these
E) 9 year

Solution: Solution   let the ages of the children be x,(x + 3),(x + 6),(x + 9) and (x + 12) year.   then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50 â‡” 5 x = 20 â‡” x= 4.   âˆ´ Age of the eldest child = x+12 = 4 +12= 
4 +12 = 16
16 years. 16 yearnswer 16 year
Answer: A
A batsman makes a score of 110 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning.  Choose one: A) 40 B) 50 C) 60 D) 45 E) 56

Solution: Let the average after 11th inning = x   Then, average after 10th inning = x-5   10(x-5)+110 = 11x   x = 110-50= 
110-50 = 60
60   Answer is 60
Answer: C
In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together? Choose the correct answer:  A) 47200  B) 48000  C) 42000  D) 50400  E) 65400

Solution: Explanation:   The word 'CORPORATION' has 11 letters. It has the vowels 'O','O','A','I','O' in it and these 5 vowels should always come together. Hence these 5 vowels can be grouped and considered as a single letter. that is, CRPRTN(OOAIO).   Hence we can assume total letters as 7. But in these 7 letters, 'R' occurs 2 times and rest of the letters are different.   Number of ways to arrange these letters   =7!2!=7Ã—6Ã—5Ã—4Ã—3Ã—2Ã—12Ã—1=2520=7!2!=7Ã—6Ã—5Ã—4Ã—3Ã—2Ã—12Ã—1=2520   In the 5 vowels (OOAIO), 'O' occurs 3 and rest of the vowels are different.   Number of ways to arrange these vowels among themselves =5!3!=5Ã—4Ã—3Ã—2Ã—13Ã—2Ã—1=20=5!3!=5Ã—4Ã—3Ã—2Ã—13Ã—2Ã—1=20   Hence, required number of ways   =2520Ã—20=50400=2520Ã—20=50400   ANSWER IS 50400
Answer: D
In a factory, there are 80% technicians and 20% non-technicians. If the 80% of the technicians and 20% of non-technicians are permanent employees, then the percentage of workers who are temporary is?	Pick
A) 62% B) 68% C) 52% D) 22% E) 42%

Solution: Total = 100   T= 80 NT= 20   80*(20/100)=24 80*(20/100)=24   16 + 16= 
16 + 16 = 32
32=> 100 - 32= 
100 - 32 = 68
68%   Answer:68%
Answer: B
One-third of Rahul's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs. 1,80,000 as total savings, how much has he saved in Public Provident Fund?  Select the correct option.
A) 81000  B) 85000  C) 75000  D) 72000  E) 77000

Solution: Let savings in National Savings Certificate = x   and savings in Public Provident Fund = (180000 - x)   1/3x=1/2(180000−x)   ⇒2x=3(180000−x)   ⇒2x=540000−3x   ⇒5x=540000   ⇒x=540000/5= 
540000/5 = 108_000
108000   Savings in Public Provident Fund= (180000 - 108000)= 
(180000 - 108000) = 72_000
72000   Answer is 72000.
Answer: D
The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then	Choose the correct answer.
A) None of these B) x = y + z C) 2x = y + z D) x = 2y + 2z E) x = y + 2z

Solution: Explanation:   Average of 6 numbers = x   => Sum of 6 numbers = 6x   Average of the 3 numbers = y   => Sum of these 3 numbers = 3y   Average of the remaining 3 numbers = z   => Sum of the remaining 3 numbers = 3z   Now we know that 6x = 3y + 3z   => 2x = y + z   Answer: Option 2x = y + z
Answer: C
In how many ways 2 students can be chosen from the class of 20 students?  Pick one:
A) 190  B) 180  C) 240  D) 390  E) None

Solution: Solution: Number of ways = 20C2 = 20!/(2! 18!)   = 20*19/2= 
20*19/2 = 190
190.   190nswer: Option 190
Answer: A
1939392 * 625	Pick:	A) 1212120010	B) 1212120000	C) 1212120011	D) 1212121010	E) 1212121000

Solution: Explanation:   Trick: when multiplying with   5n   5n   then put n zeros to the right of multiplicand and divide the number with   2n   2n   So using this we can solve this question in much less   time.   1939392×5(4)=1939392000016=1212120000   Option 1212120000
Answer: B
In how many different number of ways 4 man and 3 woman can sit on a bench such that girls always sit together.
Options:
A) 700  B) 720  C) 730  D) 750  E) 770

Solution: Option '720'
Answer: B
Two employees X and Y are paid a total of Rs. 440 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?	Pick one
A) s.150	B) s.200	C) s.250	D) s.350	E) s.400

Solution: Let the amount paid to X per week = x   and the amount paid to Y per week = y   Then x + y = 440   s.200ut x = 120% of y = 120y/100 = 12y/10   âˆ´12y/10 + y = 440   â‡’ y[12/10 + 1] = 440   â‡’ 22y/10 = 440   â‡’ 22y = 4400   â‡’ y = 4400/22 = 400/2 = Rs.200   s.200)
Answer: B
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case Select.
A) 4	B) 7	C) 9	D) 13	E) 15

Solution: Explanation:   Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)   = H.C.F. of 48, 92 and 140 = 4.   4NSWER IS 4
Answer: A
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?  Choose the correct choice from the following options.
A) 6
B) 5
C) 7
D) 8
E) 2

Solution: 1 women's 1 day work = 1/70   1 child's 1 day work = 1/140   (5 women + 10 children)'s 1 day work   = (5/10 + 10/140) = (1/14 + 1/14) = 1/7   5 women and 10 children will complete the work in 7 days.   Answer:7
Answer: C
A cube of side one meter length is cut into small cubes of side 20 cm each. How many such small cubes can be obtained?  Choose the correct choice:
A) 2878
B) 2778
C) 1000
D) 120
E) 125

Solution: Along one edge, the number of small cubes that can be cut   = 100/20= 
100/20 = 5
5   Along each edge 20 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut= 5 * 5 * 5= 
5 * 5 * 5 = 125
125   Answer: 125
Answer: E
A man sold 18 toys for Rs. 25200, gaining thereby the cost price of 3 toy find the cost price of a toy	Pick.
A) s. 600  B) s. 800  C) s.500  D) s.900  E) s. 1200

Solution: Let the cost of one toy = X.   Then, cost of 18 toys = 18X.   Gain = 3X.   SP of 18 toys = Rs. 25200.   Gain = SP â€“ CP   3X = 25200 â€“ 18X   21X = 25200   X = Rs. 1200.   ANSWs. 1200R : OPTION s. 1200
Answer: E
If in a certain sequence of consecutive multiples of 50, the median is 625, and the greatest term is 850, how many terms that are smaller than 625 are there in the sequence?	Choose the correct choice from the following choices
A) 5 B) 7 C) 8 D) 12 E) 13

Solution: Since the median is 625 we know there must be a even number of integers because 50 is not a multiple of 625.   So the list around 625 must go. 600 (625) 650 700 750 800 850   Since we know there are 5 numbers greater than 625 then there must be 5 numbers less then 625.   5
Answer: A
23,8,34,81,33,... Choices.
A) 24	B) 25	C) 26	D) 27	E) 28

Solution: 23 : 2^3=8   34 : 3^4=81   33 : 3^3=27   ANSWER:27
Answer: D
If 2ab - 3c = 2a(b - c), which of the following must be true?  Choose the correct choice from the following choices
A) a=3/2 and c=0
B) a=1/2 and b=2
C) b=1 and c=0
D) a=1 or b=0
E) a=1/2 or c=0

Solution: 2ab-3c = 2a (b-c)   2ab - 3c = 2ab - 2ac   3c= 2ac   2ac-3c = 0   c(2a-3) = 0   Either c = 0; or a = 3/2   a=3/2 and c=0 is the answer
Answer: A
Anita has 360 apples. There are 60 students are studying in her class. She would like to give each student the same amount of apples, how much should she give to each student?  Options:	A) 12	B) 6	C) 9	D) 15	E) 7

Solution: 360/60= 
360/60 = 6
6   The answer is 6.
Answer: B
Find the length of the wire required to go 11 times round a square field containing 27889 m2.  Choose the most appropriate option:
A) 7348
B) 3388
C) 2667
D) 8766
E) 66711

Solution: a2 = 27889 => a = 167   4a = 668   668 * 11= 
668 * 11 = 7_348
7348   7348nswer: 7348
Answer: A
Mary received a 20% raise each month for three consecutive months. What was her salary after the three raises if her starting salary was $1,000 per month?
Choose the correct answer
A) $1,348 B) $1,500 C) $1,631 D) $1,728 E) $1,863

Solution: 1000 * 1.2 * 1.2 * 1.2 = 1000 * 1.728= 
1000 * 1.728 = 1_728
1728   Answer: $1,728
Answer: D
Five drainage pipes, each draining water from a pool at the same constant rate, together can drain a certain pool in 8 days. How many additional pipes, each draining water at the same constant rate, will be needed to drain the pool in 4 days?
Choose one
A) 5  B) 9  C) 10  D) 12  E) 15

Solution: This is an inverse proportional problem......   5 pipes in 8 days; So for 4 days, it will be = 8 x 5 / 4 = 10   So, 10-5 = 5   5nswer 5
Answer: A
A can do a work in 9 days and B can do the same work in 18 days. If they work together, in how many days will they complete the work?
Pick one.
A) 6 days B) 7 days C) 5 days D) 3 days E) 2 days

Solution: One day's work of A and B = 1/9 + 1/8 = (2+1)/18 = 1/6 So, the time taken to complete the work is 6 days.   6 daysnswer:6 days
Answer: A
A can contains a mixture of liquids A and B is the ratio 7:5. When 15 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter of liquid A was contained by the can initially?  Choose the most appropriate option.
A) 30  B) 35  C) 40  D) 45  E) 50

Solution: Ci*Vi = Cf*Vf   (7/12)*(V1 - 15) = (7/16)*V1   (V1 - 15)/V1 = 3/4   15 accounts for the difference of 1 on ratio scale so Initial volume = V1 = 4*15= 
4*15 = 60
60 litres.   7/12 of the initial mixture was liquid A so liquid A was   (7/12)*60= 
  (7/12)*60 = 35
35 litres.   Answer : 35
Answer: B
The compound interest on Rs. 20,000 at 8% per annum is Rs. 3,328. What is the period (in year)?
Choices:
A) 1 year  B) 4 years  C) 3 years  D) 2 years  E) 5 years

Solution: Explanation:   Let the period be n years.   Amount after n years = Rs.20000 + Rs.3328 = Rs. 23328   P(1+R/100)T=23328   20000(1 + 8/100)n = 23328   20000(108/100)n = 23328   (108/100)n = 23328/20000 = 11664/10000 = (108/100)2   n = 2 years   Answer: Option 2 years
Answer: D