MU-NLPC/Calc-aqua_rat huggingface dataset:
Every month a man consumes 25 kg rice and 9 kg wheat. The price of rice is 20% of the price of wheat and thus he spends total Rs. 350 on the rice and wheat per month. If the price of wheat is increased by 20% then what is the percentage reduction of rice consumption for the same expenditure of Rs. 350? Given that the price of rice and consumption of wheat is constant :	Choose the correct option:
A) 40%	B) 25%	C) 36%	D) 24%	E) Cannot determined

Solution: Solution: Let the price of wheat is x per kg. Then price of wheat will be 5x per kg.   Expenditure on rice = 25*x = 25x.   Expenditure of wheat = 9*5= 
9*5 = 45
45x.   Total cost,   25x + 45x= 350.   70x = 350.   x = 5.   Hence, price of Rice = Rs. 5 per kg.   Price of wheat = 25 per kg.   Now, price of wheat = 25 ---- 20% ↑----> Rs. 30 per kg.   Let the new amount of rice is N kg, then   N*5 + 9*30 = 350.   N = 16 kg.   %decrease in the amount of rice = [(25-16)*100]/25 = 36%   Answer: Option 36%(25-16)*100 /25= 
(25-16)*100 /25 = 36
36%   Answer: Option 36%
Answer: C
How much water must be added to 52 litres of milk at 1 1⁄2 litres for 20 so as to have a mixture worth 10 2⁄3 a litre?
Choose the correct choice from the following answers:  A) 10 litres  B) 13 litres  C) 15 litres  D) 18 litres  E) None of these

Solution: C.P. of 1 litre of milk = (20 × 2⁄3) = 40⁄3   ∴ Ratio of water and milk = 8⁄3 : 32⁄3 = 8 : 32 = 1 : 4   ∴ Quantity of water to be added to 52 litres of milk   = (1⁄4 × 52) litres = 13 litres.   Answer 13 litres
Answer: B
Look at this series: 53, 53, 43, 43, 33, 33, ... What number should come next?
Select the correct option
A) 50 B) 40 C) 23 D) 13 E) 10

Solution: In this series, each number is repeated, then 10 is subtracted to arrive at the next number.   Answer is 23
Answer: C
In how much time will a train of length 100 m, moving at 34 kmph cross an electric pole?
Choose the correct choice from the following options:  A) 15.59 sec  B) 12.59 sec  C) 10.59 sec  D) 11.59 sec  E) 15 sec

Solution: Convert kmph to mps. 34 kmph = 34 * 5/18 = 9.44 mps.   The distance to be covered is equal to the length of the train.   Required time t = d/s = 100/9.44 = 10.59 sec.   ANSWER:10.59 sec
Answer: C
The savings of employee equals income minus expenditure.If the income of A,B,C are in the ratio 1:2:3 and their expense ratio 3:2:1 then what is the order of the employees in increasing order of their size of their savings?  Choose one:  A) 22  B) 281  C) A<B<C  D) 28  E) 272

Solution: As the the ratio of their incomes are in ascending order, and their expenses are in descending order, their savings also in their incomes order.   So savings order = A < 281 < C   Answer:281
Answer: B
Maxwell leaves his home and walks toward Brad's house at the same time that Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 36 kilometers, Maxwell's walking speed is 3 km/h, and Brad's running speed is 6 km/h. What is the distance traveled by Maxwell when they meet in the middle?  Choose the correct choice from the following answers:
A) 12	B) 14	C) 15	D) 13	E) 11

Solution: Consider Max starts from Point A and Brad Starts from Point B and move towards each other.   Assume they shall meet at point O after Time 'T'. The question asks us to find OA.   From the question stem we can make out :- Distance O12 = 50km - Distance OB   => 3xT = 36 - 6xT (i.e distance =Speed x Time)   => 9T = 36   Hence T = 4   O12 = 3 x 4 = 12 Km   12nswer : 12
Answer: A
Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. What are the marks obtained by them? Pick one:  A) 42, 33  B) 42, 31  C) 40, 33  D) 39, 33  E) 41, 35

Solution: Let the marks secured by them be x and (x + 9)   Then sum of their marks = x + (x + 9) = 2x + 9   Given that (x + 9) was 56% of the sum of their marks   =>(x+9) = 56/100(2x+9)   =>(x+9) = 14/25(2x+9)   => 25x + 225 = 28x + 126   => 3x = 99   => x = 33   Then (x + 9) = 33 + 9= 
33 + 9 = 42
42   Hence their marks are 33 and 42   42, 33)
Answer: A
There are three prizes to be distributed among ten students. If no students gets more than one prize, then this can be done in?  Choose one:
A) 10 B) 45 C) 95 D) 120 E) None of these

Solution: Explanation :   3 prize among 10 students can be distributed in 10C3 ways = 120 ways.   Answer : 120
Answer: D
Difference between two numbers is 5, six times of the smaller lacks by 10 from the four times of the greater. Find the numbers?  Pick one.
A) 10,5 B) 9,7 C) 11,9 D) 13,11 E) 13,9

Solution: Explanation:   x – y = 5   4x – 6y = 10   x = 10 y = 5   10,5)
Answer: A
Two numbers are in the ratio 3:5. If 9 be subtracted from each, they are in the ratio of 9:17. The first number is? Choose the correct option.
A) 36
B) 76
C) 98
D) 27
E) 24

Solution: (3x-9):(5x-9)   = 9:17   x = 12 => 3x   = 36   36nswer:36
Answer: A
An urn contains 10 balls, numbered from 1 to 10. If 2 balls are selected at random with replacement from the urn, what is the probability F that the sum of the 2 numbers on the balls will be even?
Choose the correct option.
A) 25%
B) 37.5%
C) 50%
D) 62.5%
E) 75%

Solution: Correct Answer: C   Since there are 5 even numbered balls and 5 odd numbered balls, the probability F of selecting either an even or an odd is 5/10= 1/2. In order for the sum of the numbers on the two balls to be even, either both numbers must be even or both numbers must be odd; one even and one odd number would add to an odd number. The probability of selecting two even numbers is:   1/2 * 1/2= 1/4   The probability of selecting two odd numbers is also:   1/2 * 1/2= 1/4   Adding both probabilities gives 1/4+1/4= 1/2 , or 50%, as the probability that the sum of the numbers will be even. Thus, the correct answer is (50%).
Answer: C
If (z + 3)/5 is an integer, what is remainder when z is divided by 5?  Options:
A) 2	B) 3	C) 4	D) 5	E) 6

Solution: 2ssume the answer choices as the value of z   2) 2; (2+3)/5 = 1 satisfies the equation   B) 3; (3+3)/5 = 1.2 Not an integer   C) 4; (4+3)/5 = 1.4 Not an integer   D) 5; (5+3)/5 = 1.6 Not an integer   E) 6; (6+3)/5 = 1.8 Not an integer   2nswer: 2
Answer: A
A round table conference to be held between 20 delegates of 20 countries. In how many ways can they seated if two particular delegates are always to sit together?	Choose the correct answer:  A) 14!*5!  B) 22!*7!  C) 18!*2!  D) 28!*1!  E) 16!*3!

Solution: Regarding two particular delegates who are to sit together as on one person, we have only   18+1= 
  18+1 = 19
19 persons.these 19 persons can be seated at the round table in 18! ways.   But two particular persons can be arranged among themselves in 2! ways.   Required number=18!*2!   Answer is 18!*2!
Answer: C
Dany bought a total of 24 game cards some of which cost $0.25 each and some of which cost $0.15 each. If Dany spent $4.2 to buy these cards, how many cards of each type did he buy?	Select the correct option: A) 4 B) 10 C) 7 D) 18 E) 12

Solution: Let X be the number of cards that cost $0.25 each and Y the number of cards that cost $0.15 each. The total number of cards is 24. Hence   X + Y = 24   If X is the number of cards at $0.25, then the X cards cost   0.25 X   If Y is the number of cards at $0.15, then the Y cards cost   0.15 Y   The total cost of the X cards and the the Y cards is known to be $4.2 and also given by   0.25 X + 0.15 Y = 4.2   We now need to solve the system of equations   X + Y = 24   0.25 X + 0.15 Y = 4.2   The first equation gives Y = 24 - X. Substitute y by 24 - x in the second equation and solve   0.25 X + 0.15 (24 - X) = 4.2   X(0.25 - 0.15) + 3.6 = 4.2   0.1 X = 0.6   X = 6 and Y = 24 - 6= 
24 - 6 = 18
18   correct answer 18
Answer: D
For a certain set of numbers, if x is in the set, then x - 1 is also in the set. If the number 1 is in the set , which of the following must also be in the set ?
a) 4
b) 0
c) -3  Pick one:
A) a only,  B) b only,  C) a and b only  D) c only,  E) b and c only

Solution: Notice that the question asks which of the following MUST be in the set, not COULD be in the set.   Since 1 is in the set, then so must be   1-1= 
  1-1 = 0
0. Similarly, since 0 is in the set, then so must be 0-3=-3. Could 4 and -1 be in the set? Certainly, but we don't know that for sure.   Answer: E.   Regarding your question: we don't know which is the source integer in the set, if it's 1, then 4 won't be in the set but if the source integer is say 7, then 4 will be in the set. So, 4 may or may not be in the set.
Answer: E
Find the amount on Rs.5000 in 2 years, the rate of interest being 20% per first year and 25% for the second year?  Select the correct option.
A) 3377
B) 2678
C) 5460
D) 7500
E) 1671

Solution: 5000 * 120/100 * 125/100= 
5000 * 120/100 * 125/100 = 7_500
> 7500   Answer: 7500
Answer: D
five children — A, B, C, D, E, F, and G — are going to sit in seven chairs in a row. Children AB must sit next to each other, and child C must be somewhere to the right of AB. How many possible configurations are there for the children? Choose the correct answer.
A) 600  B) 560  C) 1440  D) 4320  E) 4800

Solution: A, B, C, D, E, F, G- seven children, of which AB must sit next to each other. Considering them as one X (A, B), we have X, C, D, E, F, G. These can be arranged in 6! ways. But A,B can arrange themselves in 2! ways. So a total of 6!*2! ways = 1440. Since in exactly half of them, C will be to the right of AB, and exactly half, C will be to the left of AB, therefore 1440/2 = 560.   560 is the right answer.
Answer: B
The present age of a father is 3 years more than three times the age of his son.Three years hence,father as age will be 13 years more than twice the age of the son.Find the present age of the father.  Choose the correct choice from the following options
A) 88	B) 77	C) 33	D) 42	E) 55

Solution: Explanation:   Let the present age be 'x' years. Then father's present age is 3x+3 years. Three years hence (3x+3)+3=2(x+3)+13 x=13 Hence father's present age = 3x+3 =[ (3 x 13) + 3] = 42 years.   Answer: 42
Answer: D
20 throws of a die produces following results
SCORE -- NUMBER OF OCCURRENCES
---1-------------------4
---2-------------------3
---3-------------------5
---4-------------------2
---5-------------------2
---6-------------------4
What is the probability P that one more throw to this series will increase the mean score? Choose the correct option:
A) 1/6	B) 1/3	C) 1/2	D) 2/3	E) 5/6

Solution: I get the mean as 67/20 --> 3.35. Thus in order to raise this mean we would need a 4,5,or 6.   Thus probability P is 1/2.1/2
Answer: C
In how many ways can an answer key for a quiz be written if the quiz contains 5 true-false questions followed by 2 multiples-choice questions with 4 answer choices each, if the correct answers to all true-false questions cannot be the same?  Choose the correct choice from the following:
A) 160  B) 320  C) 480  D) 600  E) 720

Solution: There are 2^5 = 32 possibilities for the true-false answers.   However we need to remove two cases for TTTTT and FFFFF.   There are  4*4= 
 4*4 = 16
16 possibilities for the multiple choice questions.   The total number of possibilities is  30*16= 
 30*16 = 480
480.   The answer is 480.
Answer: C
A square is drawn inside a right-angled triangle with the two perpendicular sides as 12 cm and 8 cm. what is the side of the largest possible square that can be drawn? Pick
A) 4 cm
B) 4.8 cm
C) 4.5 cm
D) 4.4 cm
E) 5 cm

Solution: consider the origin as the point of right angle thus (8,0)and (0,12) are the 2 vertices. equation of hypotenuse : 8y+12x=96.   now solve this with y=x(the diagonal of the largest square)   x=4.8, y=4.8 .   ANSWER:4.8 cm
Answer: B
A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years. Choose the correct choice from the following:
A) 2777
B) 3120
C) 6877
D) 1699
E) 1667

Solution: Let A be the amount received at the end of the three years.   A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]   A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)   A = Rs.7920   So the interest = 7920 - 4800 = Rs.3120   Answer: 3120
Answer: B
By selling an article for $90, a person gains $15. What is the gain %? Select the correct option.
A) 25%  B) 30%  C) 50%  D) 20%  E) 10%

Solution: S.P. = $90   Gain = $15   C.P. = 90-15= 
90-15 = 75
75   Gain%= 15/75 * 100= 
15/75 * 100 = 20
20%   Answer is 20%
Answer: D
Three friends (Tony, Ben and George) are employees of a company. Their respective salaries are in the ratio of 3 : 4 :5. Ben and George's salaries together is Rs. 8550. By what percent is George's salary than that of Sarah?  Choose the correct option.
A) 61.7%
B) 46.7%
C) 66.7%
D) 63.7%
E) 62.7%

Solution: Explanation:   Let the salaries be 3x, 4x and 5x respectively.   Then,4x + 5x = 8550 => x = 950.   Tony's salary = Rs. 2850, , , Ben's salary = Rs. 3800, and and George's salary Rs. 4750.   Excess of George's salary over Tony's=[ (1900 /2850) x 100] = 66.7%.   Answer: 66.7%
Answer: C
4000 was divided into two parts such a way that when first part was invested at 3% and the second at 5%, the whole annual interest from both the investments is Rs.144, how much was put at 3%?  Choose the correct choice from the following choices:
A) 2808
B) 2829
C) 2800
D) 2829
E) 2821

Solution: (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144   3x/100 + 200 – 5x/100 = 144   2x/100 = 56 è x = 2800   Answer:2800
Answer: C
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?  Options:	A) 8	B) 12	C) 6	D) 2	E) 4

Solution: Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   => l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   => (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 => l + b = 14   12(l + b)2 = 49lb   => 12(14)2 = 49lb   => lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
8 - 6 = 2
2m.   ANSWER:2
Answer: D
70,75, 76,75,90,105,105,130,130,130
The list consists of the times in seconds that it took each of the 10 school children to run a distance of 400 mts . If the standard deviation of the 10 running times is 22.4, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times.	Choose the correct choice from the following choices: A) 1 B) 2 C) 3 D) 4 E) 5

Solution: How many of the 10 running times are more than one SD below the meanmeans how many data points from given 10 are less thanmean-1SD.   We are given that SD=22.4, so we should find mean --> mean=100 --> there are only 4 data points below  100-22.4= 
 100-22.4 = 77.6
77.6, namely 70,75, 76 and 75.   Answer: 4.
Answer: D
In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?  Choose the correct answer
A) 18
B) 36
C) 45
D) 54
E) None of these

Solution: Let R, G and B represent the number of balls in red, green and blue boxes respectively.   Then, .   R + G + B = 108 ...(i),   G + R = 2B ...(ii)   B = 2R ...(iii)   From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.   Putting G = 3R and B = 2R in (i), we get:   R + 3R + 2R = 108 6R = 108 R = 18.   Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.   ANSWER:54
Answer: D
There are three foam generators in the factory, each of the first two can generate 8 liters of foam in one hour and the third can generate 18 liters in an hour. The three generators start working together at the same time and after one hour and a half one of the first generators stops working and two hours after that the third generator stops working and only one generator is left. If 5 hours after they all started to work the last generator stops working, how many liters of foam were generated?  Choose the correct choice from the following options
A) 120.  B) 132.  C) 146.  D) 154.  E) 115

Solution: Let the foam generators capacity be -   A = 8 lit/hr   B = 8 lit/hr   C = 18 lit/hr   Total foam generation in 1 hour will be 34 lit ( 8 + 8 + 18 ) ; since in 1 and 1/2 hr they will generate   34 + 17= 
  34 + 17 = 51
> 51 litres...   Now one of the first generators stops working ( Say A stops working ) , so we have -   B= 8 lit/hr   C = 18 lit/hr   Total foam generation in 2 hour will be 52 litres {2 (8+18)}   The third generator stops working and now only B works for the remaining time 1 and 1/2 ( 5 - 1 and 1/2 - 2 )...   Foam generated by B will be  3/2 * 8= 
 3/2 * 8 = 12
> 12 litres   So, total foam generated will be 115 Litres ( 51 + 52 + 12 ) ; hence answer will be (115)
Answer: E
In a game, one player throws two fair, six-sided die at the same time. If the player receives at least a two or a one on either die, that player wins. What is the probability that a player wins after playing the game once? Choose the correct answer.
A) 1/3  B) 4/9  C) 5/9  D) 2/3  E) 3/4

Solution: We're looking for the number of outcomes that include AT LEAST a 1 or a 2.   #getting a one in 1st die = {(1,1), (1,2), ...(1,6) }= 6   #getting a one in 2nd die {(3,1), ...(5,1),(6,1) } = 4 [exclude 1,1 and 2,1] since it will be counted twice   #getting a two in 1st die {(3,1), (3,2), ...(3,6) }= 6   #getting a two in 1st die {(3,2), (4,2), ...(6,2) } = 4 [exclude 1,2 and 2,2] since it will be counted twice   Total possibities = 20   Probability of rolling at least a 1 or a 2 on two dice: 20/36 = 5/9   5/9
Answer: C
A rectangular field has a length 10 meters more than it is width. If the area of the field is 144, what is the length (in meters) of the rectangular field? Choose the correct choice from the following answers.
A) 16  B) 18  C) 20  D) 22  E) 24

Solution: area = l * w = (L) * (L-10) = 171   trial and error:    20*10= 
 20*10 = 200
200 (too high)   19*9= 
19*9 = 171
171 (too high)   18*8= 
18*8 = 144
144   The length is 18 meters.   The answer is 18.
Answer: B
Find the smallest number which leaves 22,35, 48 and 61 as remainders when divided by 26, 39, 52 and 65 respectively. Choose the correct choice from the following options.
A) 67 B) 26 C) 99 D) 26 E) 91

Solution: Answer: 26
Answer: D
8, 12, 18, 27, 40.5, (...)	Options
A) 62  B) 60.75  C) 60.5  D) 60.25  E) 60

Solution: 8   (8×3)÷ 2 = 12   (12×3)÷ 2 = 18   (18×3)÷ 2 = 27   (27×3)÷ 2 = 40.5   (40.5×3)÷ 2 = 60.75   Answer is 60.75.
Answer: B
In the faculty of Reverse-Engineering, 100 second year students study numeric methods, 100 second year students study automatic control of airborne vehicles and 25 second year students study them both. How many students are there in the faculty if the second year students are approximately 50% of the total?
Choose one:
A) 340
B) 335
C) 370
D) 360
E) 350

Solution: Total number of students studying both are 100 + 100 - 25= 
100 + 100 - 25 = 175
175 (Subtracting the 25 since they were included in the both the other numbers already).   So 50% of total is 175, so 100% is 350   Answer is 350
Answer: E
Which of the following list a prime number ?
Choices.
A) 1	B) 4	C) 8	D) 7	E) 10

Solution: D   7   Clearly, 7 is a prime number.   Answer is 7
Answer: D
The average weight of A, B and C is 65 kg. If the average weight of A and B be 60 kg and that of B and C be 70 kg, then the weight of A is:	Select the correct option: A) 55 kg B) 65 kg C) 75 kg D) 45 kg E) 63 kg

Solution: EXPLANATION   Let A, B, C represent their respective weights. Then, we have:   A + B + C = (65 x 3) = 195 â€¦. (i)   A + B = (60 x 2) = 120 â€¦. (ii)   B + C = (70 x 2) = 140 â€¦.(iii)   Adding (ii) and (iii), we get: A + 2B + C = 260 â€¦. (iv)   Subtracting (i) from (iv), we get : B = 65.   SUBSTITUTING B IN (ii)   A+65=120   A=55   Aâ€™s weight = 55 kg.   55 kgnswer 55 kg
Answer: A
0.002 x 0.5 = ? Pick:
A) 0.0001	B) 0.001	C) 0.01	D) 0.1	E) NONE OF THESE

Solution: Explanation:   2 x 5 = 10.   Sum of decimal places = 4   0.002 x 0.5 = 0.001   Answer- 0.001
Answer: B
If 2x = 3y = 10, then 3xy = ? Choose the correct option:
A) 100	B) 200	C) 120	D) 50	E) 20

Solution: 2x = 10;x=5   3y = 10;y=10/3   Multiply: 3xy=3*5*10/3= 
3*5*10/3 = 50
50   Answer: 50.
Answer: D
Dany bought a total of 26 game cards some of which cost $0.25 each and some of which cost $0.15 each. If Dany spent $4.2 to buy these cards, how many cards of each type did he buy? Choose the correct choice from the following choices:
A) 4 B) 10 C) 7 D) 23 E) 12

Solution: Let X be the number of cards that cost $0.25 each and Y the number of cards that cost $0.15 each. The total number of cards is 26. Hence   X + Y = 26   If X is the number of cards at $0.25, then the X cards cost   0.25 X   If Y is the number of cards at $0.15, then the Y cards cost   0.15 Y   The total cost of the X cards and the the Y cards is known to be $4.2 and also given by   0.25 X + 0.15 Y = 4.2   We now need to solve the system of equations   X + Y = 26   0.25 X + 0.15 Y = 4.2   The first equation gives Y = 26 - X. Substitute y by 26 - x in the second equation and solve   0.25 X + 0.15 (26 - X) = 4.2   X(0.25 - 0.15) + 3.9 = 4.2   0.1 X = 0.3   X = 3 and Y = 26 - 3= 
26 - 3 = 23
23   correct answer 23
Answer: D
The ratio of the length and the breadth of a rectangle is 4 : 3 and the area of the rectangle is 6912 sq cm. Find the ratio of the breadth and the area of the rectangle?
Choose the most appropriate option
A) 1:96
B) 1:28
C) 2:28
D) 1:29
E) 1:12

Solution: Let the length and the breadth of the rectangle be 4x cm and 3x respectively.   (4x)(3x) = 6912   12x2 = 6912   x2 = 576 = 4 * 144 = 22 * 122 (x > 0)   => x = 2 * 12= 
2 * 12 = 24
24   Ratio of the breadth and the areas= 3x : 12x2 = 1 : 4x   = 1:96.   1:96nswer:1:96
Answer: A
If x+y=-10, and x=25/y, what is the value of x^2+y^2?  Choose the most appropriate option: A) 55 B) 65 C) 50 D) 75 E) 85

Solution: x^2 + y^2 should make you think of these formulas:   (x+y)(x+y) = x^2+y^2+2xy   We already know (x+y) = -10 and x*y = 25   (x+y)(x+y) = (-10)(-10) = x^2+y^2+2*(25)   x^2+y^2 = 100 - 50= 
100 - 50 = 50
50   Answer : 50
Answer: C
The cricket team of 11members is 26yrs old & the wicket keeper is 3 yrs older. If the ages ofthese 2are excluded, the average age of theremaining players is 1 year less than the average age of the whole team. What is the average age of the team ?  Pick one.
A) 19	B) 21	C) 23	D) 25	E) 27

Solution: Let the average age of the whole team be x years.   11x - (26 + 29) = 9 (x - 1)   => 11x - 9x = 46   => 2x = 46   => x = 23.   So, average age of the team is 23 years.   23
Answer: C
The side of a rhombus is 26 m and length of one of its diagonals is 20 m. The area of the rhombus is?
Choose the correct option:  A) 237  B) 267  C) 298  D) 480  E) 291

Solution: 262 – 102 = 242   d1 = 20 d2 = 48   1/2 * 20 * 48= 
1/2 * 20 * 48 = 480
480   Answer: 480
Answer: D
Find the ratio in which rice at Rs.7.00 a kg be mixed with rice at Rs.5.70 a kg to produce a mixture worth Rs.6.30 a kg? Choose one.
A) 1 : 3
B) 2 : 3
C) 3 : 4
D) 6 : 7
E) None of these

Solution: Solution   Required ratio = 60 : 70 = 6 : 7   Answer 6 : 7
Answer: D
ABCDEFGH is an equiangular octagon with side lengths 2,4√2,1,3√2,2,3√2,3,and 2√2
in that order. Compute the area of the octagon.
Choose the correct choice from the following:	A) 25	B) 35	C) 45	D) 55	E) 65

Solution: The octagon can be inscribed in a square with side length 8. The four right triangles   at the vertices of the square have a combined area of  2 + 8 + 9/2 + 9/2= 
 2 + 8 + 9/2 + 9/2 = 19
19, giving a remaining   area of 64- 19= 
64- 19 = 45
45 .   correct answer 45
Answer: C
Two trains of equal are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is?	Options:
A) 50
B) 99
C) 77
D) 26
E) 23

Solution: Let the length of each train be x m.   Then, distance covered = 2x m.   Relative speed = 46 - 36= 
46 - 36 = 10
10 km/hr.= 10 * 5/18 = 25/9 m/sec.   2x/36 = 25/9 => x = 50.50nswer: 50
Answer: A