MU-NLPC/Calc-aqua_rat huggingface dataset:
A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 15 unsaleable mangoes in the crate then how msny mango are there in the crate?	Select:
A) 100 mangoes  B) 110 mangoes  C) 120 mangoes  D) 150 mangoes  E) 125 mangoes

Solution: 150 mangoes   ANSWER:150 mangoes
Answer: D
One week, a certain truck rental lot had a total of 24 trucks, all of which were on the lot Monday morning. If 50% of the trucks that were rented out during the week were returned to the lot on or before Saturday morning of that week, and if there were at least 12 trucks on the lot that Saturday morning, what is the greatest number of different trucks that could have been rented out during the week?  Choices:
A) 24  B) 16  C) 12  D) 8  E) 4

Solution: N - Not rented trucks; R - Rented trucks   N + R = 24   N + R/2 = 12   R =24   24
Answer: A
A man saves Rs 350 at the end of each year and lends the money at 5% compound interest. How
much will it become at the end of 3 years.  Choose the correct choice:  A) Rs 662  B) Rs 2262.01  C) Rs 1158.54  D) Rs 1662.54  E) None of these

Solution: Explanation:   =[350(21/20×21/20×21/20)+350(21/20×21/20)+350(21/20)]=1158.54   Answer: Rs 1158.54
Answer: C
Larry, Michael, and Wilson have five donuts to share. If any one of the men can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed? Choices:
A) 21
B) 42
C) 120
D) 504
E) 5040

Solution: Larry, Michael, and Wilson have five donuts to share to get the answer, see how can we get sum5with 3 numbers.   1) 0,0,5 = 3 combinations or 3! /2!   2) 0,1,4 = 6 combinations or 3!   similarly   3) 0,2,3 = 6 combinations   4) 1,1,3 = 3 combination   5) 2,2,1 = 3 combination   total =21=21
Answer: A
What is the sum of the different positive prime factors of 1050?	Choose one:
A) 8
B) 10
C) 12
D) 14
E) 17

Solution: I think answer is 17: 17   1050 = 2*3*5*5*7   Sum of theDIFF17R17NTpositive prime factors = 2 + 3 + 5 + 7= 
2 + 3 + 5 + 7 = 17
17
Answer: E
A, B and C can do a piece of work in 7 days, 14 days and 28 days respectively. How long will they take to finish the work, if all the three work together?
Choose the correct choice from the following options:
A) 4	B) 9	C) 2	D) 11	E) None

Solution: 1/7 + 1/14 + 1/28 = 7/28 = 1/4   4ll three can finish the work in 4 days   4nswer: 4
Answer: A
For all even integers n, h(n) is defined to be the sum of the even integers between 2 and n, inclusive. What is the value of h(18)/h(10) ? Select:	A) 1.8	B) 3	C) 6	D) 18	E) 60

Solution: Mean = Median =(First+Last)/2   and Sum = Mean*Number of terms   h(18) = [(2+18)/2]*9 = 90   h(10) (2+18)/2 *9= 
(2+18)/2 *9 = 90
90   h(10)= (2+10)/2]*5 = 30   h(18)/h(10) (2+10)/2 *5= 
(2+10)/2 *5 = 30
30   h(18)/h(10)= (90) / (30)= 
(90) / (30) = 3
3   ANSWER:3
Answer: B
How many seconds will a train 100 meters long take to cross a bridge 150 meters long if the speed of the train is 36 kmph?
Choose the correct choice.
A) 26  B) 72  C) 25  D) 82  E) 27

Solution: Explanation:   D = 100 + 150= 
100 + 150 = 250
250   S= 36 * 5/18= 
36 * 5/18 = 10
10 mps   T= 250/10= 
250/10 = 25
25 sec   Answer: Option 25
Answer: C
Kamal started a business investing Rs 9000. After five months, Sameer joined with a capital of Rs 8000. If at the end of the year, they earn a profit of Rs. 6970, then what will be the share of Sameer in the profit ?
Choose the correct choice from the following answers: A) Rs 2380 B) Rs 2300 C) Rs 2280 D) Rs 2260 E) None of these

Solution: Solution: Now as per question, Kamal invested for 12 months and Sameer invested for 7 months.   So Kamal: Sameer = (9000*12):(8000*7)   = 108 : 56   = 27 : 14   Sameer Ratio in profit will be =(6970*14/41)= 
(6970*14/41) = 2_380
Rs 2380.   Rs 2380nswer: Option Rs 2380
Answer: A
Pipe A can fill a tank in 4 hours, pipe B in 8 hours and pipe C in 16 hours. If all the pipes are open, in how many hours will the tank be filled ?  Choose the correct answer:
A) 2.5 hours  B) 2 hours  C) 3.5 hours  D) 2.3 hours  E) None of these

Solution: Explanation:   Part filled by A in 1 hour = 1/4   Part filled by B in 1 hour = 1/8   Part filled by C in 1 hour = 1/16   Part filled by (A+B+C) in 1 hour =   1/4+1/8+1/16=7/16   So all pipes will fill the tank in 2.3 hours.   Option 2.3 hours
Answer: D
A train is moving at a speed of 132 km/hr. If the length of the train is 100 meters, how long will it take to cross a railway platform 120 meters long  Choose one.
A) 6 sec B) 7 ½ sec C) 8 sec D) 8 ½ sec E) 9 sec

Solution: Explanation:   Speed of train = 132 ×(5/18) m/sec = 110/3 m/sec.   Distance covered in passing the platform = (100 + 120)= 
(100 + 120) = 220
220 m.   Time taken=220 ×(3/110) sec =6 sec   6 secnswer: Option 6 sec
Answer: A
Surekha started a business investing Rs.25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajesh joined him with an amount of Rs. 35,000. In 2001, Surekha invested another additional amount of Rs.10,000 and Jay joined them with an amount of Rs.35,000. What will be Rajesh's share in the profit of Rs.2,70,000 earned at the end of 3 years from the start of the business in 1999?	Pick one:
A) Rs 45000  B) Rs 50000  C) Rs 90000  D) Rs 75000  E) None

Solution: Surekha:Rajesh:Jay= (25000×12+35000×12+45000×12):(35000×24) : (35000×12) = 1260000 : 840000 : 420000 = 3 : 2 : 1. Rajesh's share =Rs.(270000×2/6) = Rs.90000.   Answer Rs 90000
Answer: C
At a loading dock, each worker on the night crew loaded 2/3 as many boxes as each worker on the day crew. If the night crew has 5/6 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load?
Select the correct option.
A) 6/11
B) 7/12
C) 8/13
D) 9/14
E) 11/15

Solution: Let x be the number of workers on the day crew.   Let y be the number of boxes loaded by each member of the day crew.   Then the number of boxes loaded by the day crew is xy.   The number of boxes loaded by the night crew is (5x/6)(2y/3) = 5xy/9   The total number of boxes is xy + 5xy/9 = 14xy/9   The fraction loaded by the day crew is xy / (14xy/9) = 9/14   The answer is 9/14.
Answer: D
When positive integer N is divided by positive integer J, the remainder is 12. If N/J = 134.02, what is value of J?
Choose one
A) 300 B) 600 C) 500 D) 112 E) 620

Solution: 1) We know that   decimal part of decimal quotient ={remainder/divisor}   So 0.02, the decimal part of the decimal quotient, must equal the remainder, 12, divided by the divisor J.   0.02 = 12/J   0.02*J = 12   J = 12/0.02 = 1200/2= 
1200/2 = 600
600/1= 
600/1 = 600
600   So J= 600, answer = 600.
Answer: B
A train running at the speed of 54 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct answer.
A) 288	B) 279	C) 135	D) 272	E) 150

Solution: Speed = 54 * 5/18= 
54 * 5/18 = 15
15 m/sec   Length of the train= speed * time = 15 * 9= 
15 * 9 = 135
135 m   Answer: 135
Answer: C
Two quarts containing 2⁄3 water and 1⁄3 formula are mixed with three quarts containing 3⁄8 water and 5⁄8 formula. Approximately what percent of the combined five-quart mixture is water?
Select: A) 40% B) 45% C) 50% D) 55% E) 60%

Solution: Since we are asking of water in the end, lets concentrate on water only..   A solution has 2 quarts with fraction of water =2/3, almost 67%..   B solution has 3 quarts with fraction of water =3/8 almost 37%..   so the ratio A:B=2:3...   the average will therefore be closer to B % and will be 2/(2+3) of {67-37} away from B..   2/(2+3) of {67-37}= 2/5 * 30 =12..   so 37 +12= 
37 +12 = 49
49 nearly 50%   ANSWER:50%
Answer: C
The letters of the word 'SUBITI' are written in all possible orders and these words are written in alphabetical order. Then what is the rank of the word 'SUBITI'	Select
A) - 246  B) - 245  C) - 237  D) - 315  E) - 275

Solution: Total Number of Words = 6!/2! = 360 [(number of characters)/(repeating group )!]   After S, we have T and U.   Number of words starting with T = 5!/2! = 60   Number of words starting with U = 5!/2! = 60   So any word starting with S will have rank < 360 - 60(for Us) - 60(for Ts) = 240   Only option A < 240, so Answer is - 237.
Answer: C
A and B can do a work in 5 days and 10 days respectively. A starts the work and B joins him after 2 days. In how many days can they complete the remaining work?  Choose one.
A) 5 days
B) 4 days
C) 3 days
D) 6 days
E) 9 days

Solution: Explanation:   1/7 + 1/14 + 1/28 = 7/28 = 1/4 => 4 days   answer 4 days
Answer: B
A certain bus driver is paid a regular rate of $16 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $864 in total compensation, how many total hours did he work that week?	Choose the correct option.
A) 36
B) 40
C) 44
D) 48
E) 52

Solution: For 40 hrs = 40*16= 
40*16 = 640
640   Excess= 864-640= 
864-640 = 224
224   For extra hours=.75(16)=12+16= 
12+16 = 28
28   Number of extra hrs=224/28=56/7= 
56/7 = 8
8   Total hrs=40+8= 
40+8 = 48
48   Answer 48 48
Answer: D
Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?  Choose the correct choice from the following answers
A) 1378  B) 1800  C) 2738  D) 2778  E) 1928

Solution: Explanation:   Let the required number of bottles be x.   More machines, More bottles (Direct Proportion)   More minutes, More bottles (Direct Proportion)   machines & 6:10\\ time(in\; minutes) &1:4 \end{matrix}\right\}::270:x}   6 x 1 x x = 10 x 4 x 270   {10\times 4\times 270}{6}}   => x= 1800   Answer: 1800
Answer: B
A clock is set right at 8 a.m. The clock gains 10 minutes in 24 hours will be the true time when the clock indicates 1 p.m. on the following day?  Answers: A) 48 min. past 12. B) 20 min. past 12. C) 28 min. past 12. D) 18 min. past 12. E) 42 min. past 12.

Solution: Time from 8 a.m. on a day to 1 p.m. on the following day = 29 hours.   24 hours 10 min. of this clock = 24 hours of the correct clock.   hrs of this clock = 24 hours of the correct clock.   29 hours of this clock =(24 x 6/145 x 29) hrs of the correct clock   = 28 hrs 48 min of the correct clock.   Therefore, the correct time is 28 hrs 48 min. after 8 a.m.   This is 48 min. past 12.   48 min. past 12.nswer 48 min. past 12.
Answer: A
Of the integers between 100 and 799, inclusive, how many do not have digit 3 and 6?
Choose the most appropriate option.
A) 310  B) 520  C) 410  D) 420  E) 320

Solution: Options for the first digit 7-2(2 and 5)=5;   Options for the second digit 10-2= 
10-2 = 8
8;   Options for the third digit   10-2= 
  10-2 = 8
8;   Total numbers possible 5*8*8= 
5*8*8 = 320
320.   Answer: 320
Answer: E
How many different ways can you select a pilot and a co pilot if you have 70 people to choose from?	Select:
A) 199
B) 200
C) 398
D) 4830
E) 9900

Solution: You are not just choosing two from 70. Each of the two people chosen fills a particular slot. The first filling the pilot slot and the second filling the copilot slot is different from the first filling the copilot slot and the second filling the pilot slot.   So the answer is in a sense (70C2) x 2 = 4830.   Ans 4830
Answer: D
During one year, the population of town increased by 5% . If the total population is 9975 at the end of the second year , then what was the population size in the beginning of the first year ? Choose the correct option
A) 50000  B) 10000  C) 90000  D) 70000  E) 120000

Solution: Population in the beginning of the first year   = 9975/[1+(5/100)]*[1-(5/100)]   = [9975*(20/21)*(20/19)]   9975/ 1+(5/100) * 1-(5/100)= 
9975/ 1+(5/100) * 1-(5/100) = 9_975
[9975*(20/21)*(20/19)= 
9975*(20/21)*(20/19) = 10_000
10000.   Answer is 10000.
Answer: B
A train passes a station platform in 48 sec and a man standing on the platform in 40 sec. If the speed of the train is 36 km/hr. What is the length of the platform?	Choose the correct choice:
A) 80  B) 120  C) 60  D) 90  E) 50

Solution: Speed = 36 * 5/18= 
36 * 5/18 = 10
10 m/sec.   Length of the train= 10 * 40= 
10 * 40 = 400
400 m.   Let the length of the platform be x m . Then,   (x + 400)/48= 10 => x = 80 m.   80nswer: 80
Answer: A
How many odd, positive divisors does 520 have? Choose the correct answer
A) 6	B) 8	C) 12	D) 15	E) 24

Solution: Make a prime factorization of a number: 540=2^2*3^3*5 --> get rid of powers of 2 as they give even factors --> you'll have 3^3*5 which has (3+1)(1+1)=6 factors.   Another example: 60=2^2*3*5 it has (2+1)(1+1)(1+1)=12 factors out of which (1+1)(1+1)=4 are odd: 1, 3, 5 and 15 the same # of odd factors as 60/2^2=15 has.   6nswer: 6
Answer: A
When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 41, what is the remainder when k is divided by 7?	Choose the correct choice from the following answers:  A) 3  B) 4  C) 5  D) 6  E) 7

Solution: Cant think of a straight approach but here is how I solved it:   K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)   so the possible values of K = {2, 7, 12, 17, 22, 27, 32, 37} (less than 41)   Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5   so the possible value set for k = {5, 11, 17, 23, 29,35} (less than 41)   17 is the only common number in both the sets. Hence k = 17   3nswer : 3
Answer: A
The speed of a car is 90kmph. What is the speed in metres per second.
Choose the correct option:  A) 25 m/s  B) 40 m/s  C) 35 m/s  D) 28 m/s  E) 27 m/s

Solution: Explanation:   km/hr to m/sec conversion:   x km/hr = (x × 5/18) m/sec   90 × 5/18 = 25.   25 m/snswer: Option 25 m/s
Answer: A
If a man walks 24 Km at 8 Kmph, he will be late by 25min. if he walks 12 Kmph, how early the fixed time Will he reach?  Select:
A) 30 minutes	B) 25 minutes	C) 40 minutes	D) 35 minutes	E) 20 minutes

Solution: Time taken to cover 24 Km at the speed of 8 Kmph = 24/8= 
24/8 = 3
3 hours   Thus, right time was 2 hours 35 mintes   Now, time taken to cover 20 Km at the speed as 12 Kmph= 2 hours   Required time = 2 hours 35 minutes - 2 hours   = 35 minutes   ANSWER IS 35 minutes
Answer: D
In how many different ways can the letters of the word 'DETAIL' be arranged such that the vowels must occupy only the odd positions?
Choose the correct choice from the following options: A) 12 B) 36 C) 45 D) 96 E) 83

Solution: The word 'DETAIL' has 6 letters which has 3 vowels (EAI) and 3 consonants(DTL)   The 3 vowels(EAI) must occupy only the odd positions. Let's mark the positions as (1) (2) (3) (4) (5) (6). Now, the 3 vowels should only occupy the 3 positions marked as (1),(3) and (5) in any order.   Hence, number of ways to arrange these vowels   = 3P3 =3!=3×2×1=6   Now we have 3 consonants(DTL) which can be arranged in the remaining 3 positions in any order. Hence, number of ways to arrange these consonants   = 3P3=3!=3×2×1=6   Total number of ways   = number of ways to arrange the vowels × number of ways to arrange the consonants   =6×6=36   Answer: 36
Answer: B
10 meters of wire is available to fence off a flower bed in the form of a circular sector. What must the radius of the circle in meters be, if we wish to have a flower bed with the greatest possible surface area?
Choose the correct answer.
A) 5/2  B) 2√5  C) 5  D) 4√2  E) none of these

Solution: 5/2rea of Sector, 5/2 = x/360*pi*r^2   Circumference of the sector = 10   => x/360*2*pi*r +2r= 20   => 25/2/r+2r=10 OR 25/2 +2r^2=10r   => 5/2= r5-r^2   = r5-r^2   We will now max using derivations   i.e 5-2r=0   r=5/2   5/2
Answer: A
The radius of the two circular fields is in the ratio 3: 5 the area of the first field is what percent less than the area of the second?
Select:
A) 50%	B) 60%	C) 40%	D) 64%	E) 55%

Solution: Explanation:   r = 3 πr2 = 9   r = 5 πr2 = 25   25 π – 16 π   100 ---- ? => 64%   ANSWER IS 64%
Answer: D
4, 6, 12, 14, 28, 30, .. ?	Choose the correct choice:  A) 20  B) 40  C) no=60  D) 80  E) 100

Solution: C   60   The given sequence is a combination of two series 4, 12, 28, .... and 6, 14, 30, .... The pattern is +8, +16, +32. So, the missing number = (28 + 32)= 
(28 + 32) = 60
60
Answer: C
A bag contains 11 wool scarves, exactly one of which is red and exactly one of which is green. If Deborah reaches in and draws three scarves, simultaneously and at random, what is the probability that she selects the red scarf but not the green scarf?
Choose the correct option:
A) 8/19
B) 10/33
C) 12/55
D) 15/67
E) 20/83

Solution: Total possible ways to choose three scarves is 11C3 = 165   We need to choose the red scarf and two of 9 other scarves (not the green scarf).   The number of successful possibilities is 912/552 = 36   P(red scarf but not green scarf) = 36/165 = 12/55   The answer is 12/55.
Answer: C
Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is?
Choose the correct option
A) 15
B) 17
C) 19
D) 21
E) 26

Solution: Let the three integers be x, x + 2 and x + 4.   Then, 3x = 2(x + 4) + 3 x = 11.   Third integer = x + 4 = 15.   Option 15
Answer: A
How many two digit numbers are there such that the product of their digits after reducing it to the smallest form is a prime number? for example if we take 98 then 9*8=72, 72=7*2=14, 14=1*4=4. Consider only 4 prime numbers (2,3,5,7)
Select the correct option
A) 27	B) 28	C) 18	D) 99	E) 01

Solution: Explanation:   2 = 12 or 21 So 1×2, 2×1, 3×4, 4×3, 2×6, 6×2, 3×7, 7×3   3 = 13 or 31 So 1×3, 3×1   5 = 15, 51 So 1×5, 5×1, 3×5, 5×3, 7×5, 5×7   7 = 17 or 71 So 1×7, 7×1   15 = 3×5 = 5×3   So total 18 numbers = 12,13,15,17,21,26,31,34,35,37,43,51,53,57,62,71,73,75   Answer:18
Answer: C
A is a working partner and B is a sleeping partner in the business. A puts in Rs.15000 and B Rs.25000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is?	Pick one:  A) 2888  B) 2669  C) 2997  D) 4200  E) 2877

Solution: 15:25 => 3:5   9600*10/100= 
9600*10/100 = 960
960   9600 - 960= 
9600 - 960 = 8_640
8640   8640*3/8= 
8640*3/8 = 3_240
3240 + 960= 
3240 + 960 = 4_200
4200.Answer: 4200
Answer: D
Beginning in Town A, Biker Bob rides his bike 30 miles west, 6 miles north, 15 miles east, and then 18 miles north, to Town B. How far apart are Town A and Town B? (Ignore the curvature of the earth.) Options:	A) 27 miles	B) 25 miles	C) 24 miles	D) 28.3 miles	E) 23 miles

Solution: Using Pythagoras we have one side i,e total distance traveled in north direction = 18+6= 
18+6 = 24
24m   other being the base ie distance traveled west- distance traveled eat=30-15= 
30-15 = 15
15 m   now this third side or the distance between town A and Town B=24^2+ 15^2=sq root 801=28.3m   Answer : 28.3 miles
Answer: D
P and Q invested in a business. The profit earned was divided in the ratio 4 : 5. If P invested Rs 52000, the amount invested by Q is  Choose the correct answer:
A) 30000 B) 50000 C) 40000 D) 20000 E) 65000

Solution: Let the amount invested by Q = q   52000:q=4:5   ⇒52000×5=4q   ⇒q=(52000×5)/4=65000   Answer is 65000.
Answer: E
If the price of an article went up by 60%, then by what percent should it be brought down to bring it back to its original price?	Pick one.
A) 16 2/3%	B) 37 1/2%	C) 16 7/3%	D) 16 6/3%	E) 16 2/3%

Solution: Let the price of the article be Rs. 100.   60% of 100 = 60.   New price   = 100 + 60 = Rs. 160   Required percentage   = (160 - 100)/160 * 100   = 60/160 * 100   = 75/2   = 37 1/2%.   Answer:37 1/2%
Answer: B
What profit percent is made by selling an article at a certain price, if by selling at 2/3rd of that price, there would be a loss of 20%? Choose the most appropriate option:
A) 20%
B) 25%
C) 70%
D) 28%
E) 30%

Solution: SP2 = 2/3 SP1   CP = 100   SP2 = 80   2/3 SP1 = 80   SP1 = 120   100 --- 20 => 20%   20%nswer:20%
Answer: A
A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? Choose one.
A) 5 B) 6 C) 7 D) 8 E) 5

Solution: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr   [66 * 5/18] m/sec = [55/3] m/sec.   Time taken to pass the man = [110 * 3/55= 
110 * 3/55 = 6
6 sec   Answer: 6
Answer: B
The ratio of Ajay’s and Balu’s ages is 4: 5. If the difference between the present age of Balu and the age of Ajay 5 years hence is 3 years, then what is the total of present ages of Ajay and Balu? Choose the correct choice from the following choices:
A) 68 years
B) 72 years
C) 76 years
D) 64 years
E) 74 years

Solution: Let us consider Ajay as A and Balu as B.   Given A/B = 4/5   And B - (A + 5) = 3   B - A = 8   B = 8 + A   Now, A/(8 + A) = 4/5   A = 32 years   Therefore B = 40 years.   A   + 72= 
  + 72 = 72
72 years   ANSWER:72 years
Answer: B
If a and b are each greater than x and y, which of the following must be true?
I. ab < xy
II.a + b > x + y
III. |a| + |b| > |x| + |y|
Choose the most appropriate option:
A) I only B) II only C) I and II D) I and III E) I, II and III

Solution: I. a + b > x + y. Since a and b are each greater than x and y, then the sum of a and b will also be greater than the sum of x and y.   II. ab > xy. Not necessarily true, consider a = b = 0 and x = y = -1 --> ab = 0 < 1 = xy.   III. |a| + |b| > |x| + |y|. Not necessarily true, consider a = b = 0 and x = y = -1 --> |a| + |b| = 0 < 2 = |x| + |y|.   Answer: II only.
Answer: B
How many even integers n, such that 20<=n<=240 are of the form 3k+4, where k is any natural number?	Select the correct option:
A) 31 B) 33 C) 35 D) 37 E) 39

Solution: The first number is 22 = 16+6(1).   We can continue adding 6 to make a list: 22, 28, 34,...   The last number is 238 = 16+6(37)   There are 37 numbers in the list.   The answer is 37.
Answer: D
In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which 4 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond? Choose the correct choice:
A) 400 B) 625 C) 1,250 D) 2,500 E) 10,000

Solution: total fish = x   percentage of second catch = (4/50)*100= 
(4/50)*100 = 8
8%   so, x * 8%= 50   x = 625 ans. 625
Answer: B
The probability that A speaks truth is 3/5 and that of B speaking truth is 3/7. What is the probability that they agree in stating the same fact? Choose the correct option.
A) 17/35	B) 17/39	C) 17/36	D) 17/33	E) 17/32

Solution: If both agree stating the same fact, either both of them speak truth of both speak false.   Probability = 3/5 * 3/7 + 2/5 * 4/7   = 9/35 + 8/35 = 17/35   17/35nswer: 17/35
Answer: A
Two trains 125 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Choose the correct choice from the following answers:
A) 7.16 B) 7.16 C) 7.12 D) 7.15 E) 7.2

Solution: T = (125 + 165)/ (80 + 65) * 18/5= 
(125 + 165)/ (80 + 65) * 18/5 = 36/5 = around 7.2
7.2   Answer: 7.2
Answer: E
If Rs. 510 be divided among A, B, C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what C gets, then their shares are respectively: Choices
A) Rs. 60, Rs. 90, Rs. 389	B) Rs. 60, Rs. 90, Rs. 360	C) Rs. 60, Rs. 90, Rs. 368	D) Rs. 60, Rs. 90, Rs. 329	E) Rs. 60, Rs. 30, Rs. 329

Solution: (A = 2/3 B and B = 1/4 C) = A/B = 2/3 and B/C = 1/4   A:B = 2:3 and B:C = 1:4 = 3:12   A:B:C = 2:3:12   A;s share = 510 * 2/17 = Rs. 60   B's share = 510 * 3/17 = Rs. 90   C's share = 510 * 12/17 = Rs. 360.   Answer:Rs. 60, Rs. 90, Rs. 360
Answer: B
A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.482 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.	Pick.
A) 2200	B) 1897	C) 8799	D) 2000	E) 2782

Solution: P(11/10)4 - P(6/5)2 = 482   P = 2000   Answer: 2000
Answer: D
Find the area of circle whose radius is 70m?	Choose the correct choice
A) 28866  B) 23456  C) 76766  D) 16866  E) 15400

Solution: 22/7 * 70 * 70= 
22/7 * 70 * 70 = 15_400
15400   Answer: 15400
Answer: E