MU-NLPC/Calc-aqua_rat huggingface dataset:
A FIVE DIGIT NUMBER IS FORMED BY USING THE DIGITS 0,1,2,3,4 WITH OUT REPETITIONS . WHAT IS THE PROBABILITY THE NUMBER IS DIVISIBLE BY4?	Options:
A) 1/5	B) 5/6	C) 2/5	D) 7/3	E) 2/7

Solution: If a number is divisible by 4 the last 2 digits of the number has to be divisible by 4.   If the number ends with 10: Number of possibilities = 3 * 2 * 1= 
3 * 2 * 1 = 6
6   number ends with 20: Possibilities= 3 * 2 * 1= 
3 * 2 * 1 = 6
6   number ends with 30: Possibilities= 6   number ends with 12: Possibilities = 6   number ends with 14: Possibilities = 6   number ends with 32: Possibilities = 6   number ends with 34: Possibilities = 6   number ends with 24: Possibilities = 6   Total number of possibilities with restriction = 6*8= 
6*8 = 48
48   Total number of possibilities without restriction= 5! = 120   Probability = 48/120 = 2/5   Answer: 2/5
Answer: C
How many 4 digit numbers can be formed with the digits 0, 1, 2, 3, 4, 5, 6 and 2? Select the correct option.
A) a. 220	B) b. 249	C) c. 432	D) d. 216	E) e. 288

Solution: Taking Question with it's same language as given   To make number divisible by 5, the unit digit should be either 0 or 5 only   Case 1: If unit digit is fixed as zero   With two6s The choice to fill the remaining three digits = 3C2 x 5 = 15   With all remaining 3 digits different, The choice to fill the remaining three digits = 6 x 5 x 4= 120   Total Such cases = 120+15= 
120+15 = 135
135   Case 2: If unit digit is fixed as Five   With two6s and one0The choice to fill the remaining three digits= 2 [6605 or 6065]   With two6s and without0The choice to fill the remaining three digits = 3C2 x 4 = 12   With all remaining 3 digits different, and one0The choice to fill the remaining three digits = 2 (ways to place zero) x 5 x 4= 40   With all remaining 3 digits different, and without0The choice to fill the remaining three digits = 3 x 5 x 4= 60   Total Such cases = 2+12+40+60= 
2+12+40+60 = 114
114   Total numbers= 135+114 = 288   ANSWe. 288R OPTION e. 288
Answer: E
Sum of two numbers prime to each other is 15 and their L.C.M. is 56. What are the numbers? Choose the correct answer.
A) 9 and 8  B) 5 and 10  C) 7 and 9  D) 7 and 8  E) 10 and 8

Solution: As two numbers are prime, only options satisfy ie option A and 7 and 8 and C   but option 7 and 8 will make the product of numbers i.e 56   ANSWER:7 and 8
Answer: D
If A speaks the truth 75% of the times, B speaks the truth 60% of the times. What is the probability that they tell the truth at the same time
Answers:
A) 0.49 B) 0.48 C) 0.45 D) 0.482 E) 0.411

Solution: Explanation:   Probability that A speaks truth is 75/100= 
75/100 = 3/4 = around 0.75
0.75   Probability that B speaks truth is   60/100= 
  60/100 = 3/5 = around 0.6
0.6   Since both A and B are independent of each other   So probability of A intersection B is P(A) × P(B)=0.75 × 0.6 = 0.45   Answer: 0.45
Answer: C
The salary of Mr. X is 30% more than that of Mr. Y . Find what percent of Mr. Y’s salary is less than Mr. X’s?  Choose the correct choice from the following
A) 23 1/8% B) 23 7/3% C) 23 1/3% D) 23 1/3% E) 53 3/3%

Solution: y=100	x=130   130---------30   100---------? => 23 1/3%   Answer:23 1/3%
Answer: C
A bag of potatoes weighs 50 lbs divided by half of its weight. How much does the bag of potatoes weight?  Choose the correct answer:
A) 20 lb
B) 30 lb
C) 10 lb
D) 15 lb
E) 5 lb

Solution: Sol.   50÷5 = 10.   Answer : 10 lb
Answer: C
If xy > 0, which of the following must be negative? Answers.
A) -x/y
B) xy
C) x/y
D) 2xy
E) 2x/y

Solution: - / + = -   -x/ynswer : -x/y
Answer: A
The length of the bridge, which a train 140 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answers.
A) 200 m B) 235 m C) 245 m D) 250 m E) 270 m

Solution: Let the length of the bridge:L   The equation now is L+140/12.5m/s(45km/hr or12.5m/s)=30   Solving, L =235m   ANSWER:235 m
Answer: B
Which is a better investment 5% stock at 412 or 3 3/2 stock at 360? Choose the correct option:
A) 5% stock at 412
B) Both are equally good
C) Cannot be compared, as the total amount of investment is not given
D) None
E) 3 3/2 stock at 360

Solution: Let investment in each case be Rs. (412 x 360).   Income in 1st case = Rs.5 x 412 x 360/412	= Rs. 1800.   Income in 2nd case = Rs.9 x 412 x 360/(2*117)	= Rs. 5704.6   Clearly, 3 3/2 stock at 360 is better.   ANSW3 3/2 stock at 360R:3 3/2 stock at 360
Answer: E
A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1900. The difference between the profit shares of A and C is?  Choose the correct choice from the following options:
A) 288	B) 760	C) 155	D) 600	E) 441

Solution: Ratio of investments of A, B and C is 8000 : 10000 : 12000 = 4 : 5 : 6   And also given that, profit share of B is Rs. 1900   => 5 parts out of 15 parts is Rs. 1900   Now, required difference is 6 - 4= 
6 - 4 = 2
2 parts   Required difference= 2/5 (1900) = Rs. 760   Answer:760
Answer: B
66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length if the wire in meters will be:	Choose the correct option.
A) 76 m B) 80 m C) 84 m D) 88 m E) 90 m

Solution: Explanation:   Let the length of the wire be h   Radius=1/2mm=1/20cm   πr2h=66   (22/7)*(1/20)*(1/20)*h=66   =>h=(66∗20∗20∗7) / 22   =8400cm   =84m   ANSWER IS 84 m
Answer: C
4 professors and 6 students are being considered for membership on a supervisory committee which must consist of 3 people. If the committee has to include at least 1 professor, how many ways can this committee be formed? Choose the correct choice from the following answers:  A) 36  B) 60  C) 72  D) 80  E) 100

Solution: combinations:   1 professor 2 students   students: 6 x 5 / 2 = 15   15*4= 
15*4 = 60
60   2 professors 1 student   4 x 3 / 2= 6   6*6= 
6*6 = 36
36   3 professors     4/1= 
  4/1 = 4
4   60 + 36 + 4= 
60 + 36 + 4 = 100
100   ANS:100
Answer: E
A,B,C together can do a work in 8 days. A alone can do the work in 30 days and B alone can do the same work in 20 days. Find in what time C alone can do that work?  Choose the correct choice:
A) 16days  B) 20.8days  C) 24days  D) 28.5days  E) 32.4days

Solution: The required answer is = 8*30*20 / 30*20-8(30+20)   = 4800/200= 
4800/200 = 24
24days   Answer is 24days
Answer: C
Find the value of 72519 x 9999 = m?
Choose the correct choice:	A) 345466221	B) 345455672	C) 353456678	D) 725117481	E) 789545233

Solution: 72519 x 9999 = 72519 x (10000 - 1)   = 72519 x 10000 - 72519 x 1   = 725190000 - 72519= 
725190000 - 72519 = 725_117_481
725117481   725117481
Answer: D
The compound interest on $ 30,000 at 7% per annum is $4347. The period (in years) is:
Pick one
A) 2  B) 21/2  C) 3  D) 4  E) 5

Solution: 2mt = $(30000+4347)= 
(30000+4347) = 34_347
$34347   let the time be n yrs then 30000(1+7/100)^n=34347   (107/100)^n=34347/30000=(107/100)^2   n = 2 yrs   2NSWER 2
Answer: A
It is known that no more than 8 children will be attending a party. What is the smallest number of cookies that must be brought to the party so that each child receives the same number of cookies?
Choose the correct choice from the following answers.
A) 35	B) 105	C) 180	D) 210	E) 840

Solution: The question states that there are no more than 8 children in the party. Thus, the possibility is that there could be 1, 2, 3, 4, 5, 6,7 or 8 children.   If you assume answer as 35 and there are 3 children, you may not distribute be able to distribute cookies equally.   similarly if there were 105 cookies, and 2 children, cookies cannot be distributed equally.   or if there were 210 cookies, and 4 children, cookies cannot be distributed equally.   Thus, the question asks for a number of cookies which can be distributed to any number of children (from 1 to 8).   And therefore the smallest number of cookies would be lcm of (1, 2, 3, 4, 5, 6, 7,8), i.e., 840.   Answer (840)
Answer: E
A, B and C rents a pasture for Rs.435. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?  Select the correct option
A) 120 B) 227 C) 268 D) 198 E) 176

Solution: 12*8 :16*9 = 18*6   8: 12: 9   8/29 * 435= 
8/29 * 435 = 120
120   120nswer:120
Answer: A
Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major?
Choose one
A) 1/15 B) 1/5 C) 4/15 D) 1/3 E) 2/5

Solution: tot students=x   1st year student=x/2----> non majaor=4/5(x/2)-----> maj=1/5(x/2)   2nd year student=x/2---->maj=1(1/5(x/2))=1/10(x)--->non major=x/2-1/10(x)=2/5(x)   hence 2/5   2/5
Answer: E
Mother is aged thrice than her daughter Silvia. After 8 years, he would be 2(1/2) times of Silvia’s age. After 8 years, how many times would she be of Silvia’s age?	Choose the correct choice from the following: A) 2 years B) 4 years C) 3 years D) 5 years E) 6 years

Solution: A   2 years   Let Silvia’s current age is A years.   Then, mom’s current age = (A + 3A) years = 4A years.   (42 years + 8) = (5/2) (2 years + 8)   => 82 years + 16 = 52 years + 40   => 32 years = 24   2 years = 8   Needed ratio = { (42 years + 16)/(2 years+16) }   = 48/24= 
48/24 = 2
2
Answer: A
One fish tank is half full. After adding 10 gallons the tank is 7/8 of the tank. Calculate the capacity of the fish tank.
Choose the correct choice from the following answers.
A) 80/3 gallons  B) 90/3 gallons  C) 70/3 gallons  D) 60/3 gallons  E) 50/3 gallons

Solution: If x is capacity of full tank, then   x*(7/8-1/2) =10   x*3/8=10   x= 80/3 gallons   80/3 gallonsNSWER:80/3 gallons
Answer: A
Raji,Lakshmi and Priya enter into partnership. Raji invests some money at the beginning, Lakshmi invests double the amount after 6 months, and Priya invests thrice the amount after 8 months. If the annual gain be Rs.12000. Priya's share is?	Choose the correct choice from the following answers
A) 2500  B) 3500  C) 4500  D) 2800  E) 4000

Solution: x* 12 : 2x* 6: 3x* 4   1:1:1   1/3 * 12000= 
1/3 * 12000 = 4_000
4000   Answer: 4000
Answer: E
Present ages of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. What is X's present age in years?
Select the correct option:
A) 35 years
B) 77 years
C) 55 years
D) 44 years
E) 33 years

Solution: Let the present ages of X and Y be 5x and 6x years respectively.   Then, (5x + 7)/(6x + 7) = 6/7   7(5x + 7) = 6(6x + 7) => x = 7   X's present age = 5x = 35 years.35 yearsnswer: 35 years
Answer: A
In how many different number of ways a Committee of 3person of can be selected from 4boys and 3girls such that at least 1 girl is included in the committe  Choose the correct choice from the following choices:
A) 30  B) 29  C) 31  D) 17  E) 85

Solution: 1G 2B 2G 1B 3G   =(3311*4312)+(3312*4311)+3313   =(3*6)+(3*4)+1   =18+12+1= 
18+12+1 = 31
31   Total 4M 3W   7313=35   4313=4   At least one girl = total - with out girl   At least one girl =35-4= 
35-4 = 31
31   31)
Answer: C
The area of a parallelogram is 1764sq m and its base is nine times size of the corresponding altitude. Then the length of the base is?  Choose the correct choice from the following answers:	A) 21	B) 9	C) 11	D) 14	E) 7

Solution: 9x * x = 1764 => x   = 14   Answer: 14
Answer: D
In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 3 metres then what will be the area of the square so formed?  Choose the most appropriate option:	A) Cannot be determined	B) 2600 cm2	C) 2500 cm2	D) 1296 cm2	E) None of these

Solution: Let the side of the square be x m.   ∴ Perimeter of the square = 48 × 3 = 4x ∴ x = 36 m   ∴ Area = (36)2 = 1296 m2   Answer 1296 cm2
Answer: D
After decreasing 20% in the price of an article costs Rs.200. Find the actual cost of an article?  Choose the correct answer:
A) 280 B) 250 C) 260 D) 270 E) 300

Solution: CP* (80/100) = 200   CP= 2.5* 100 => CP = 250   Answer: 250
Answer: B
During a certain two-week period, 76 percent of the movies rented from a video store were comedies, and of the remaining movies rented, there were 5 times as many dramas as action movies. If no other movies were rented during that two-week period and there were A action movies rented, then how many comedies, in terms of A, were rented during that two-week period?	Choose one:
A) 16A
B) 19A
C) 17A
D) 18A
E) 20A

Solution: Total movies = 100.   Comedies = 76.   Action + Drama = 24. Since there were 5 times as many dramas as action movies, then Action + 5*Action = 24 --> Action = A = 4.   Comedies = 76 = 19A.   Answer: 19A.
Answer: B
A store sells branded shirts for $20 each and unbranded shirts $16 each. On every branded shirt, the store makes a profit of $6 while on every unbranded shirt it makes a profit of $4. If on a given day the store's sales amounted to $960, which of the following cannot be the profit made on that day? Choose the correct choice from the following answers:	A) $264	B) $268	C) $270	D) $272	E) $276

Solution: $270 is the only option that does not satisfy a combination of integer number sales of branded and unbranded shirts sales. Answer: $270
Answer: C
A fruitseller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%.At what price per kg,he should have sold them to make a profit of 5% ?
Select the correct option:
A) Rs.11.81 B) Rs.12 C) Rs.12.25 D) Rs.12.31 E) None

Solution: Solution   80 : 9 = 105 : x or x =(9x105/80) = 11.81.   Hence, S.P. per kg. = Rs.11.81.   Rs.11.81nswer Rs.11.81
Answer: A
A motorcyclist goes from Bombay to Pune, a distance of 192 kms at an average of 32 kmph speed. Another man starts from Bombay by car 2 ½ hours after the first, and reaches Pune ½ hour earlier. What is the ratio of the speed of the motorcycle and the car?
Choose the correct choice from the following options.
A) 3:5 B) 4:5 C) 2:5 D) 2:4 E) 2:7

Solution: T = 160/32= 
160/32 = 5
5 h   T= 5 - 3= 
5 - 3 = 2
2   Time Ratio= 5:2   Speed Ratio = 2:5   ANSWER:2:5
Answer: C
A shipment of 1500 heads of cabbage, each of which was approximately the same size was purchased for $600.The day the shipment arrived 2/3 of the heads were sold, each at 25% above the cost per head.The following day the rest were sold at a price per head equal to 10% less than the price each head sold for the day before.what was the gross profit E on this shipment? Options:
A) a) $100 B) b) $115 C) c) $125 D) d) $130 E) e) $135

Solution: I recommend one should use fractions to solve this one rather than converting it into decimals   Sol:   1500 heads -> $600   1 head -> $600/1500   1 head -> $(2/5)   25% more of (2/5) -> 125/100 * 2/5 = $(1/2)   He sold   2/3*1500= 
  2/3*1500 = 1_000
1000 heads for $(1/2) per head   Total revenue by selling 1000 heads= 1000 * 1/2= 
1000 * 1/2 = 500
$500   Heads left: 500   c) $125ost per head: 90% of the previous price: 90/100 * 1/2= $(9/20)   Total revenue by selling 500 heads = 9/20 * 500= 
9/20 * 500 = 225
225   Total revenue after selling 1500 cabbage heads - 225+500= $725   Money spent on the purchase: $600   Profit E= 725-600= 
725-600 = 125
$125   Ans:c) $125
Answer: C
The sum of first five prime numbers is:
Select:  A) 28  B) 72  C) 55  D) 33  E) 58

Solution: A   Required sum = (2 + 3 + 5 + 7 + 11)= 
(2 + 3 + 5 + 7 + 11) = 28
28.   Note: 1 is not a prime number.   Definition: 28 prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself.
Answer: A
The circumference of a circle is equal to 72 pi. Find the radius of this circle.
Choices:  A) 35  B) 36  C) 37  D) 38  E) 39

Solution: The circumference of a circle is given by   C = 2 pi r, where r is the radius of the circle.   Substitute C by 72 pi to obtain the equation   72 pi = 2 pi r   Simplify and solve for r to obtain   r = 36   Answer 36
Answer: B
There are three numbers. 5/7th of the first number is equal to 48% of the second number. The second number is 1/9th of the third number. If the third number is 1125, then find 25% of the first number?
Choose the correct choice from the following choices:
A) 16
B) 18
C) 12
D) 21
E) 10

Solution: Let the first number and the second number be F and S respectively.   5/2 F = 48/100 S ----> (1)   S = 1/9 * 1125 ----  (1)= 
----  (1) = 1
1/9 * 1125= 
1/9 * 1125 = 125
125   (1)=> 5/7 F = 48/100 * 125   => F = 84   25% of F = 1/4 * 84= 
1/4 * 84 = 21
21.   Answer: 21
Answer: D
A rectangular field has to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required? Pick:
A) 80
B) 82
C) 84
D) 88
E) 86

Solution: Area of the field =680 sq. feet.   Length of the adjacent sides are   20 feet and 68020=34 feet.   Required length of the fencing   =20+34+34= 
20+34+34 = 88
88 feet   Answer is 88.
Answer: D
Anil purchases two books for Rs.100. He sells first at loss of 5% and second al 20% profit. If he gets Overall profit of 5% then what is cost of first book?
Choose one.
A) Rs.45
B) Rs.60
C) Rs.55
D) Rs.58
E) Rs.56

Solution: If cost of first book=x then second book=100-x   According to given condition x*(95/100) + (100-x)*(120/100) =100*(105/100) or   0.95x +120 -1.2x=105   x=60   ANSWER:Rs.60
Answer: B
A group of boy scouts and girls scouts is going on a rafting trip. 80% of the scouts arrived with signed permission slips. If 40% of the scouts were boy scouts and 75% of the boy scouts arrived with signed permission slips, then what percentage of the girl scouts arrived with signed permission slips? Round to the nearest percent.
Choices
A) 79
B) 81
C) 82
D) 83
E) 85

Solution: 40% were boy scouts so 60% (100-40=60) were girl scouts.   # of boy scouts with permission slips signed + # of girl scouts with permission slips signed = total # with permission slip signed   (75% of 40% of the total going) + (?% of 60% of the total going) = 80% of the total going   We can let the "total going" = 100 arbitrarily since we only care about the percent (of girl scouts w/ permission signed)   .75*.40*100 + x*.60*100 = .80*100   30 + x*60 = 80   60x=50   x=50/60   x=.833333   converting this to a percent, we have 83%   83
Answer: D
Ifaequals the sum of the even integers from 2 to 20, inclusive, andbequals the sum of the odd integers from 1 to 19, inclusive, what is the value of a + b ? Options.
A) 110 B) 100 C) 190 D) 200 E) 210

Solution: Answer is 10   Yes! there is really a faster way to solve it.   Sum of consecutive odd or even integers = (no. of odd or even ints) * (first int + last int) / 2   Here A = sum of even ints from 2 to 20, inclusive   number of even ints = 10,   first int + last int = 2+20= 
2+20 = 22
22   A= 10*22 / 2= 
10*22 / 2 = 110
110   B= sum of odd ints from 1 to 19, inclusive   number of odd ints = 10,   first int + last int = 1+19= 
1+19 = 20
20   A= 10*20 / 2= 
10*20 / 2 = 100
100   A+B= 110 + 100= 
110 + 100 = 210
210   Ans :210
Answer: E
We bought 85 hats at the store. Blue hats cost $6 and green hats cost $7. The total price was $540. How many green hats did we buy? Choose one
A) A)36	B) B)30	C) C)40	D) D)42	E) E)44

Solution: Let B be the number of blue hats and let G be the number of green hats.   B+G=85.   B=85-G.   6B+7G=540.   6(85-G)+7G=540.   510-6G+7G=540.   G=540-510= 
540-510 = 30
30.   The answer is 30.
Answer: B
If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?	Choices:
A) 157
B) 162
C) 882
D) 155
E) 101

Solution: 12 m/s = 12 * 18/5 kmph   3 hours 45 minutes = 3 3/4 hours = 15/4 hours   Distance = speed * time = 12 * 18/5 * 15/4= 
12 * 18/5 * 15/4 = 162
162 km.   Answer: 162
Answer: B
The price of a certain house this year is $140,000, which is 25 percent greater than the cost of the house last year. What was the price of the house last year?
Choices:
A) $112,000
B) $114,000
C) $116,000
D) $118,000
E) $120,000

Solution: The price of the house last year was $140,000/1.25=$112,000   The answer is $112,000.
Answer: A
The ratio between x and y is 8/3; x is multiplied by x and y is multiplied by y , what is the ratio between the new values of x and y?  Choose the most appropriate option:
A) 8/3 B) 3/8 C) 1 D) 64/9 E) It Cannot Be Determined

Solution: Ratio = 7k/9k = 7/9, 14/18, etc.   x is multiplied by x and y is multiplied by y --> (7k*7k)/(9k*9k) = 49k^2 / 81k^2 =49/81 =7/9   8/3nswer: 8/3
Answer: A
A function g(n), where n is an integer, is defined as the product of all integers from 1 to n. How many of the followings must be a prime number?
g(7) + 2; g(7) + 3; g(7) + 4; and g(7) + 5?	Choose the correct choice
A) 1
B) 2
C) 3
D) 4
E) none

Solution: g(7) is the product of all integers from 1 to 7, so g(7) = 7!   Thus g(7) is a multiple of all the integers from 1 to 7.   Then g(7) is a multiple of 2, 3, 4, and 5.   2 divides g(7)+2   3 divides g(7)+3   4 divides g(7)+4   5 divides g(7)+5   The answer is none.
Answer: E
Three unbased coins are tossed. the probability of getting at least two head is ?
Pick:  A) 1/4  B) 1/2  C) 3/4  D) 2/3  E) 2/5

Solution: S={TTT,TTH,THT,HTT,THH,HTH,HHT,HHH}   E be the event of getting at least two head is {THH,HTH,HHT,HHH}   P(E)=n(E)/n(S)=4/8=1/2   Answer(1/2)
Answer: B
The distance light travels in one year is approximately 5,890,000,000,000 miles. The distance light travels in 100 years is  Choose the correct choice from the following answers
A) A) 587 × 108 miles  B) B) 587 × 1010 miles  C) C) 587 × 10-10 miles  D) D) 589 × 1012 miles  E) E) 587 × 10-12 miles

Solution: The distance of the light travels in 100 years is:   5,890,000,000,000 × 100 miles.   = 589,000,000,000,000 miles.   = 589 × 1012 miles.   The answer is (589 × 1012 miles)
Answer: D
Adding 35% of x to x is equivalent to multiplying x by which of the following? Select the correct option:
A) 12.5
B) 1.05
C) 1.35
D) 1.2
E) 1.25

Solution: 135x/100= 1.35*x   ANSWER:1.35135 /100= 
135 /100 = 27/20 = around 1.35
1.35*x   ANSWER:1.35
Answer: C
A, B, C rent a pasture. A puts 10 oxen for 7 months, B puts 12 oxen for 5 months and C puts 15 oxen for 3 months for grazing. If the rent of the pasture is Rs. 175, how much must C pay as his share of rent? Pick.
A) Rs. 45	B) Rs. 50	C) Rs. 55	D) Rs. 60	E) None

Solution: Solution: A : B : C = (10 * 7) : (12 * 5) : (15 * 3) = 70 : 60 : 45 = 14 : 12 : 9.   C's rent = Rs.(175 * 9/35) = Rs. 45.   Rs. 45nswer: Option Rs. 45
Answer: A
A company has two models of computers, model X and model Y. Operating at a constant rate, a model X computer can complete a certain task in 60 minutes and a model Y computer can complete the same task in 30 minutes. If the company used the same number of each model of computer to complete the task in 1 minute, how many model X computers were used?  Select
A) 18 B) 16 C) 15 D) 17 E) 20

Solution: Let's say 1 work is processing 60 gb of data.   Model X : 1 gb per min   Model Y : 2 gb per min   Working together, 1 X and 1 Y = 3 gb per min   So, 20 times as many computers would work at 60 gb per min.   So no. of X =20   Answer is 20
Answer: E
A set M contains element all even number between 1 and 23 and all odd numbers 24 and 100. if all the elements of the set multiplied than how many trailing 0 , resulting number will contains?  Choose the correct answer:
A) 10
B) 12
C) 9
D) 8
E) 7

Solution: m={10,20 } &{25,35,45,55,65,75,85,95}   in set m number of 5 is 12.   ANSWER:12
Answer: B
If the ratio of boys to girls in a class is B and the ratio of girls to boys is G; then 3 (B + G) is ? Choose the correct choice from the following answers:
A) Equal to 3	B) Less than 3	C) More than 3	D) Less than 1/3	E) none of these

Solution: Let number of boys = x   Let number of girls = y   Therefore x/y = B and y/x = G   3(B + G) = 3[(x/y) + (y/x)] = 3[(x2 + y2)/xy] > 3   ANSWER:More than 3
Answer: C
Two trains 200m and 160m long run at the speed of 68kmph and 40kmph in opposite directions in parallel tracks. The time which they take to cross each other is? Answers: A) 5.6sec B) 8.9sec C) 10.8sec D) 12 sec E) 15sec

Solution: Relative speed = 68+40= 
68+40 = 108
108kmph * 5/18= 30 m/s   12 secistance covered in crossing each other = 200+160= 
200+160 = 360
360m   Required time= 360*1/30= 
360*1/30 = 12
12 sec   Answer is 12 sec
Answer: D