MU-NLPC/Calc-aqua_rat huggingface dataset:
A grocer has a sale of Rs. 5266, Rs. 5744, Rs. 5864, Rs. 6122 and Rs. 6588 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 5750?	Choices:
A) 4016
B) 4076
C) 4816
D) 4916
E) 5916

Solution: Total sale for 5 months = Rs. (5266 + 5744 + 5864 + 6122+ 6588) = Rs. 29584.   Required sale = Rs. [ (5750 x 6) - 34500 ]   = Rs. (34500 - 29584)   = Rs. 4916.   ANSWER:4916
Answer: D
The simple interest and the true discount on a certain sum for a given time and at a given rate are Rs. 90 and Rs. 80 respectively. The sum is:  Choose the correct choice from the following options:
A) 1360
B) 1450
C) 720
D) 1800
E) None

Solution: Sol.   Sum = S.I. * T.D. / (S.I)-(T.D.) = 90 * 80 / (90 - 80) = Rs.720.   Answer 720
Answer: C
How many different ways can you select a pilot and a co pilot if you have 80 people to choose from?
Choose the correct option
A) 199
B) 200
C) 398
D) 4950
E) 6320

Solution: You are not just choosing two from 80. Each of the two people chosen fills a particular slot. The first filling the pilot slot and the second filling the copilot slot is different from the first filling the copilot slot and the second filling the pilot slot.   So the answer is in a sense (80C2) x 2 = 6320=6320
Answer: E
If B and C are digits and 8BC is a 3-digit number that is divisible by 4, which of the following is a possible product of B and C?
Choose one
A) 1  B) 2  C) 5  D) 6  E) 14

Solution: Try with the options -   A. If BC = 1 , both B and C must be 1   B. If BC = 2 , either B or C must be 1 or 2 ; In that case sum of the digits will be 8 + 1 + 2= 
8 + 1 + 2 = 11
11 which is not divisible by 3   C. If BC= 5 , either B or C must be 1 or 5 ; In that case sum of the digits will be 8 + 1 + 5= 
8 + 1 + 5 = 14
14 which is not divisible by 3   D. If BC= 6 , then we can have the following possibilities   i. Either B or C must be 2 or 3 ; In that case sum of the digits will be 8 + 2 + 3= 
8 + 2 + 3 = 13
13 which is not divisible by 3   ii. Either B or C must be 1 or 6 ; In that case sum of the digits will be 8 + 1 + 6= 
8 + 1 + 6 = 15
15 which is divisible by 3   E. If B5= 14 , then either B or 5 must be 2 or 7 ; In that case sum of the digits will be 8 + 2 + 7= 
8 + 2 + 7 = 17
17 which is not divisible by 4   Thus answer is (5)
Answer: C
A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 45, what is the total amount?	Choose the correct choice from the following choices:
A) 115
B) 116
C) 195
D) 118
E) 119

Solution: x:y:z = 100:45:50   20:9:10   9 --- 45   39 --- ? => 195   ANSWER:195
Answer: C
The area of an isosceles trapezoid with sides of length 5 and bases of length 7 and 13 is?  Pick one:
A) 40	B) 41	C) 42	D) 43	E) 44

Solution: Isosceles trapezoid indicates that if we draw perpendicular from two vertex of the smaller side, the longer side with side 13 will be divided into 3 parts= 7, 3 and 3 (Making one square and two right triangles)   For the right triangle, height will be= (5^2-3^2)^1/2= 4   40nd the area of trapezoid = 1/2 (B1+B2)H= 1/2*20*4= 
1/2*20*4 = 40
40   40
Answer: A
Anil and Suresh are working on a special assignment. Anil needs 6 hours to type 32 pages on a computer and Suresh needs 5 hours to type 40 pages. If both of them work together on two different computers, how much time is needed to type an assignment of 150 pages? Choose the correct choice from the following answers.
A) 11 hours 15 mins  B) 8 hours  C) 9 hours  D) 7 hours  E) 6 hours

Solution: Pages typed by 11 hours 15 minsnil in 1 hour = 32/6 = 16/3   Pages typed by Suresh in 1 hour = 40/5= 
40/5 = 8
8   Pages typed by 11 hours 15 minsnil and Suresh in 1 hour= 16/3 + 8 = 40/3   Time taken to type 150 pages when 11 hours 15 minsnil and Suresh work together = 150 × 3 /40 = 45/4   = 11 ¼ hours = 11 hour 15 minutes   11 hours 15 minsnswer is 11 hours 15 mins.
Answer: A
Eight persons in an organization including X and Y were to be divided in two groups of 4 members each. The total number of groups containing both X and Y is what fraction of the total number of groups which can be formed? Choose the correct choice from the following answers
A) 1/4
B) 3/14
C) 4/14
D) 1/10
E) 11/14

Solution: The fraction is nothing but the probability..   Number to choose 4 out of 8= 8C4..   Number to choose X and Y and 2 from remaining 6=6C2..   prob of X and Y choosen=6C2/8C4= {6!/4!2!}/{8!/4!4!}..   6!4!4!/8!4!2!=3/2*7=3/14   Answer : 3/14
Answer: B
Henry has to secure 70% marks to clear his exam of class 6th.
He got 110 marks and failed by 100 marks.
What is the maximum marks ?  Choices:
A) 200	B) 300	C) 400	D) 500	E) 600

Solution: B   300   To pass the exam ravish needs 110 + 100= 
110 + 100 = 210
210 marks.=> (210/70) *100= 
(210/70) *100 = 300
300
Answer: B
In which year was the difference between Jyothi's and Arun's monthly income the second highest? Choose the correct choice from the following answers
A) A76
B) 66
C) 27
D) 28
E) 11

Solution: Answer:11
Answer: E
The price of 3 pants and 6 t-shirts is Rs. 750. With the same money one can buy 1 pant and 12 t-shirts. If one wants to buy 8 t-shirts, how much shall she have to pay ?
Options:
A) 150
B) 250
C) 400
D) 450
E) 550

Solution: Let the price of a pant and a t-shirt be Rs. x and Rs. y respectively.   Then, 3x + 6y = 750 .... (i)   and x + 12y = 750 .... (ii)   Divide equation (i) by 3, we get the below equation.   = x + 2y = 250. --- (iii)   Now subtract (iii) from (ii)   x + 12y = 750 (-)   x + 2y = 250   ----------------   10y = 500   ----------------   y= 50   cost of 8 t-shirts = 8*50= 
8*50 = 400
400   Answer : 400
Answer: C
Each of the integers from 0 to 8, inclusive, is written on a separate slip of blank paper and the ten slips are dropped into hat. If the slips are then drawn one at a time without replacement, how many must be drawn to ensure that the numbers on two of the slips drawn will have a sum of 9? Choose one:
A) 3
B) 4
C) 5
D) 6
E) 7

Solution: Answer is 6. In the worst case, you could end up drawing 0,1,2,3,4,5. th draw will result in either of 6,7,8 which would result in the numbers adding to 9.   6
Answer: D
x and y are positive integers. If xy + 3x is odd, then which of the following must be even?	Select the correct option: A) x B) y C) 3 + y D) xy − x E) x^2 − y

Solution: Given that xy + x is odd, which means x(y+3) is odd.   Product of two nos. will be odd only if both the nos. are odd.   Hence x is odd, y+3 is also odd.   y+3 is odd means y is even. Answer will be 3 + y.
Answer: C
Evaluate : 2.5 + 0.0005
Select:  A) 2000  B) 3000  C) 1000  D) 5000  E) 4000

Solution: 25/0.0005 = (25*10000) / (0.0005*10000) = 25000 / 5= 
25000 / 5 = 5_000
5000   Answer is 5000.
Answer: D
The least number which when divided by 2, 3, 5 and 6 leaves a remainder 3, but when divided by 9 leaves no remainder, is
Choose the most appropriate option:
A) 16  B) 63  C) 73  D) 83  E) None of these

Solution: Explanation:   L.C.M of 2, 3, 5, 6 = 30   therefore Required Number is of the form 30k+3.   Least value of k for which (30k+3) is divisible by 9 is k = 2   therefore Required Number = (30 x 2+3)=63. Answer: 63
Answer: B
Which of the following expressions CANNOT have a negative value Pick one
A) |a + b| + |a – b|
B) |a + b| – |a|
C) |2a + b| – |a + b|
D) a^2 - b^2 – 2|ab|
E) |a^3 + b^3| – a – b

Solution: Whenever you are required to find if the equation is a perfect square or not, try to bring everything in the form of a perfect square as they are always positive.   Of the given options, only option D can be written in from of a perfect square.   |a + b| + |a – b|   This will always be positive.   Correct Option: |a + b| + |a – b|
Answer: A
In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 16 percent of revenues. The profits in 2009 were what percent of the profits in 2008?	Choose the most appropriate option.
A) 80%	B) 105%	C) 120%	D) 124.2%	E) 128%

Solution: x = profits   r= revenue   x/r = 0,1   x= 10   r=100   2009:   r=80   x/80 = 0,16 = 16/100   x= 80*16/100= 
80*16/100 = 64/5 = around 12.8
12.8   12.8/10= 1,28 = 128%, Answer 128%
Answer: E
Two identical circles intersect such that their centers and the points at which they intersect form a square of side 2 cm. What is the area of the region where the two circles intersect?	Select:  A) pi^2 - 2  B) 2pi - 4  C) 4 - pi  D) 4 - pi/2  E) 2 - pi/4

Solution: Drawing a diagram, we see that the radius of the circle equals the side of the square.   The area of intersection is: pi*r^2/4 - (r^2-pi*r^2/4) = pi*r^2/2 - r^2 = 2pi - 4   The answer is 2pi - 4.
Answer: B
Probability of Cristiano Ronaldo scoring a penalty is twice than the probability of missing it. In a World cup he takes 5 penalties, What is the probability of scoring 3 penalties among the 5?
a) 5 *2 *((2/3)^3 * (1/3)^2)
b) 1-((2/3)^3 * (1/3)^2)
c) 1-((2/3)^2 * (1/3)^3)
d) None of the above.  Choose one
A) 5 *2 *((2/3)^3 * (1/3)^2)
B) 5 *2 *((2/3)^3 * (1/3)^9)
C) 5 *2 *((2/3)^3 * (1/3)^7)
D) 5 *2 *((2/3)^3 * (1/3)^5)
E) 5 *2 *((2/3)^3 * (1/3)^1)

Solution: Explanation:   We have to use Binomial distribution to solve this question as Ronaldo scoring penalty and not scoring penalty are Dichotomous in nature.   Success + Failure = 1   2x + x = 1   So x = 1/3   Probability of scoring a penalty = p = 2/3 and Not scoring it = q = 1/3   Probability of scoring exactly 'r' of 'n' trials = P(x=r)=nCr.pr.qn−rP(x=r)=nCr.pr.qn−r   P(x=3)=5C3.(23)3.(13)5−3P(x=3)=5C3.(23)3.(13)5−3   = 10.(23)3.(13)210.(23)3.(13)2   5 *2 *((2/3)^3 * (1/3)^2)nswer:5 *2 *((2/3)^3 * (1/3)^2)
Answer: A
The sum of two numbers is 66. How much should be added to the sum for it to be exactly divisible by 9 leaving 0 as the reminder?
Choose the correct choice from the following answers:
A) 6
B) 7
C) 8
D) 9
E) 1

Solution: The sum is 66 .Adding 6 to 66 = 66+6= 
66+6 = 72
72.   72 is exactly divisible by 9 leaving 0 as the reminder=8. So the answer is 6=6
Answer: A
A completes a work in 6 days and B complete the same work in 12 days. If both of them work together, then the number of days required to complete the work will be? Pick:
A) 4 days
B) 11 days
C) 21 days
D) 22 days
E) 24 days

Solution: If A can complete a work in x days and B can complete the same work in y days, then, both   of them together can complete the work in x y/ x+ y days   Therefore, here, the required number of days = 6 Ã— 12/ 18 = 4 days.   Option '4 days'
Answer: A
In May, the grounds keeper at Spring Lake Golf Club built a circular green with an area of 64π square feet. In August, he doubled the distance from the center of the green to the edge of the green. What is the total area of the renovated green? Options.
A) 100PI B) 144PI C) 196PI D) 256PI E) 78

Solution: AREA OF CIRCLE 64PI SQ FEET =PI R^2 THEREFORE R =8   NOW GREEN RA256PII 256PIOUBLE256PI I.E R =16 AREA =256 PI   256PI
Answer: D
A can do a piece of work in 18 days, B in 27 days, C in 36 days. They start worked together . But only C work till the completion of work. A leaves 4 days and B leaves 6 days before the completion of work. In how many days work be completed? Choose the correct choice from the following answers:
A) 12	B) 15	C) 14	D) 13	E) 11

Solution: Explanation:   Let the work be completed in x days   (x-4)days of 12 + (x-6)days of B + x days of C = 1   =>x-4/18 + x-6/27 + x/36 = 1   => 13 x-48 /108 =1   x=12   Total time = 12 days   12NSWER IS 12
Answer: A
A goods train runs at the speed of 72 km/hr and crosses a 280 m long platform in 26 sec. What is the length of the goods train?  Select the correct option
A) 278	B) 166	C) 151	D) 240	E) 109

Solution: Speed = 72 * 5/18= 
72 * 5/18 = 20
20 m/sec.   Time= 26 sec.   Let the length of the train be x meters.   Then, (x + 280)/26 = 20   x = 240 m.   Answer:240
Answer: D
If x and y are different prime numbers, each greater than 4, which of the following must be true?
I. x+y is an even integer
II. xy is an odd integer
III. (x/y) is not an integer  Choose one
A) III only	B) I,II and III	C) I only	D) II only	E) I,II only

Solution: This question tests your knowledge about the effect of addition and multiplication on odd and even numbers:   Even + Even = Even   Odd + Even = Odd   Odd + Odd = Even   Even * Even = Even   Odd * Even = Even   Odd * Odd = Odd   Given: x and y are different prime numbers, both greater than 4   Statement I: x+y is an even integer   Since x and y are prime numbers greater than 4, they will be odd   Therefore sum will be even.   Correct   Statement II: xy is an odd integer   Since x and y are prime numbers greater than 4, they will be odd   Therefore multiplication will be odd.   Correct   Statement III: (x/y) is not an integer   Since x and y are prime integers, therefore they will not have any common factor apart from 1   Hence (x/y) will not be an integer   Correct   Hence all three statements I, II and III are correct   Answer : I,II and III
Answer: B
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?	Choose the correct answer:
A) 4 years  B) 8years  C) 10 years  D) 12 years  E) None of these

Solution: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.   Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50   5x = 20   x = 4.   Age of the youngest child = x = 4 years.   4 yearsNSWER:4 years
Answer: A
A certain sum of money at simple interest amounted Rs.645 in 12 years at 5% per annum, find the sum?  Select.
A) 403  B) 410  C) 500  D) 340  E) 455

Solution: 645 = P [1 + (12*5)/100]   P = 403   403nswer: 403
Answer: A
The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person	Pick
A) 22
B) 66
C) 77
D) 30
E) 88

Solution: Let's take the present age of the elder person = x   and the present age of the younger person = x – 16   (x – 6) = 3 (x-16-6)   => x – 6 = 3x – 66   => 2x = 60   => x = 60/2= 
60/2 = 30
30   Answer: 30
Answer: D
There are 11 women and 8 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible?	Choose the correct choice from the following options: A) 120 B) 720 C) 1,540 D) 1,520 E) 1,980

Solution: Answer is E. Can somebody tell me what answer I may have found if I had added the 11C2 and 8C2 (55+28=83)?   I'm guessing that would've been the number of 2-member committees which had men and women separately. Is that right?   1,540
Answer: C
a and b are positive integers less than or equal to 9. If a and b are assembled into the six-digit number abab, which of the following must be a factor of abab?  Choose the correct choice from the following
A) 3 B) 4 C) 5 D) 6 E) none of the above

Solution: 4848 when divided by 3 gives the result 1212   CONCEPT: Rule of Divisibility of 4 isIf sum of the digits of the Number is divisible by 4 then the number will be divisible by 2   SUm of the digits of No. 4848 is 27 which is divisible by 4 hence the Number 4848 will be divisible by 4   4
Answer: B
An alloy of copper and zinc contains copper and zinc in the ratio 3 : 5. Another alloy of copper and zinc contains copper and zinc in the ratio 6 : 2. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc? Choose the most appropriate option.
A) 1:2  B) 2:2  C) 2:5  D) 2:6  E) 2:7

Solution: Let Alloy_1 be x units, and let Alloy_2 be y units.   So, fraction of copper in Alloy_1 = 3x/8, and fraction of zinc in Alloy_1 = 5x/8.   Similarly, fraction of copper in Alloy_2 = 6y/8, and fraction of zinc in Alloy_2 = 2y/8.   Mixing them, we get   copper = 3x/8 +6y/8; zinc = 5x/8 + 2y/8.   So, 3x+6y = 5x+2y   -> 2x = 4y   -> x/y = 2/4 = 1/2   So, they must be mixed in the ratio 1 : 2   1:2nswer : 1:2
Answer: A
By selling 15 pencils for a rupee a man loses 25%. How many for a rupee should he sell in order to gain 25%?
Choose the correct choice from the following answers.
A) 8 B) 9 C) 7 D) 6 E) 4

Solution: 75% --- 15   125% --- ?     75/125 * 15= 
  75/125 * 15 = 9
9   Answer: 9
Answer: B
A sum of Rs. 2900 amounts to Rs. 3422 in 3 years. Had the rate of interest be 5% higher then what would the sum amount in the same time period?	Choose the correct choice: A) Rs. 4465 B) Rs. 3683 C) Rs. 3596 D) Rs. 3857 E) None of these

Solution: 3422=2900+(2900*R*3/100)   R=6   If R is 5 more.   Then R=11   Sum=2900+(2900*11*3/100)= 
2900+(2900*11*3/100) = 3_857
3857   ANSWER:Rs. 3857
Answer: D
A school bus travels from Veldhoven to Roosendaal. There are four children in the bus. Each child has four backpacks with him. There are four dogs sitting in each backpack. Every dog has four puppies with her. All these dogs have four legs, with four toes at each leg.
What is the total number of toes in the bus?
Pick.
A) 4789 B) 5170 C) 4902 D) 4490 E) 5538

Solution: B   5170   The total number of toes is 5170.   The puppies: 4 children × 4 backpacks × 4 dogs × 4 puppies × 4 legs × 4 toes = 4096   Plus the dogs: 4 children × 4 backpacks × 4 dogs × 4 legs × 4 toes = 1024   Plus the children: 4 children × 2 legs × 5 toes = 40   Plus the driver of the school bus: 2 legs × 5 toes = 10   4096+1024+40+10= 
4096+1024+40+10 = 5_170
5170   This gives the following total number of toes: 5170
Answer: B
An oblong piece of ground measures 19m 2.5dm by 12m 5dm. From the centre of each side a path 2m wide goes across to the centre of the opposite side. Find the cost of paving these paths at the rate of rs.1.32 per sq m?  Answers:	A) Rs. 43.6	B) Rs. 78.65	C) Rs 54.75	D) Rs. 344	E) Rs. 34.4

Solution: Area of path horizontal=20*192.5= 
20*192.5 = 3_850
3850 dm^2   Area of path vertical=20*125= 
20*125 = 2_500
2500 dm^2   Since center path is covered twice so total area=(3850+2500)-(20*20)= 
(3850+2500)-(20*20) = 5_950
5950 dm^2   total cost=1.32*59.5 m^2=78.54   ANSWER:Rs. 78.65
Answer: B
x and y are positive integers. When x is divided by 17, the remainder is 3, and when x is divided by 19, the remainder is 1. When y is divided by 14, the remainder is 5, and when y is divided by 21, the remainder is 12. What is the least possible value of y - x?  Choose the most appropriate option.
A) 15	B) 13	C) 11	D) 14	E) 18

Solution: When x is divided by 17, the remainder is 3: So, the possible values of x are: 3, 20, 37,54 , etc.   When x is divided by 19, the remainder is 1: So, the possible values of x are: 1,20... STOP. Since both lists include 20, the smallest possible value of x is 20.   When y is divided by 14, the remainder is 5: So, the possible values of y are: 5, 19, 33,47 etc.   When y is divided by 21, the remainder is 12: So, the possible values of y are: 12, 33, ...STOP. Since both lists include 33, the smallest possible value of y is 33   Since the smallest possible values of x and y are 20 and 33 respectively, the smallest possible value of y - x is 13. So,13 is the correct answer to the original question.
Answer: B
Insert the missing number
100,91,....,76,70
Select the correct option.
A) 82	B) 83	C) 84	D) 81	E) 80

Solution: Missing number: 83   Answer: 83
Answer: B
1/(√2-1)=?	Choose the most appropriate option
A) 9+4√5
B) 9-4√5
C) √2+1
D) 9-2√5
E) 4+9√5

Solution: This question requires us to rationalize (fix) the denominator.   For more on this technique, seehttps://www.gmatprepnow.com/module/gmat ... video/1044   Given: 1/(√2-1)   Multiply top and bottom by the √2+1ONJUGATE of √2-1, which is √2+1   So, 1/(√2-1) = (1)(√2+1)/(√2-1)(√2+1)   = (√2+1)/(1)   = √2+1   =   √2+1
Answer: C
what will be the next number in the following series??
4,18,...,100,180,294	Choose the correct choice from the following answers: A) 32 B) 36 C) 40 D) 44 E) 48

Solution: 2x2x1=4;   3x3x2=18;   4x4x3=48;   5x5x4=100;   6x6x5=180;   7x7x6=294;   so answer is 48.   ANSW48R:48
Answer: E
Two machines, Y and Z, work at constant rates producing identical items. Machine Y produces 13 items in the same time Machine Z produces 14 items. If machine Y takes 28 minutes to produce a batch of items, how many minutes does it take for machine Z to produce the same number of items?	Pick one.
A) 26  B) 9  C) 9 1/2  D) 12  E) 13 1/2

Solution: rate z/rate y=14/13   time z/time y=13/14   (13/14)*28= 
(13/14)*28 = 26
26 minutes   26
Answer: A
A sequence consists of 16 consecutive even integers written in increasing order. The sum of the first 8 of these even integers is 472. What is the sum of the last 8 of the even integers? Choose the correct answer.
A) 588 B) 594 C) 600 D) 606 E) 612

Solution: The sum of the first 8 numbers is: x + (x+2) +...+ (x+14) = 472   The sum of the next 8 numbers is: (x+16) + (x+2+16) +...+ (x+14+16) =   472 + 8(16) = 472 + 128= 
472 + 128 = 600
600   The answer is 600.
Answer: C
Last year, a certain public transportation system sold an average (arithmetic mean) of 41,000 tickets per day on weekdays (Monday through Friday) and an average of 15,000 tickets per day on Saturday and Sunday. Which of the following is closest to the total number of tickets sold last year?	Choose the correct choice from the following choices
A) 1 million B) 1.25 million C) 10 million D) 12.2 million E) 125 million

Solution: If you type that into the calculator, it results in 12.3 mil   [D], 12.2 mil, is the correct answer... see 2 posts above for quick approx method
Answer: D
The sum of all the integers s such that -26 < s < 24 is  Choose the correct choice from the following:
A) 0  B) -2  C) -25  D) -49  E) -51

Solution: Easy one -   -25, -24, -23,-22,...... -1,0, 1, 2...., 22, 23   Cancel everyhitng and we're left with - -25 and -24 s= -49.   -49 is the answer.
Answer: D
If (x – 2)^2 = 144, which of the following could be the value of 2x?  Choose one
A) –26  B) –22  C) –11  D) 12  E) -20

Solution: You can also get to the answer by backsolving using answer choices   Starting with x = -10   (x – 2)^2 = 144   (-10– 2)^2 = 144 =====> (-12)^2 = 144 Bingo, Clearly, among the answer choices only -10 will result in 144 in the equation so x must be -10,   Then 2x = 2 * -10 = -20   Answer: -20
Answer: E
3 workers transfer a tool weighing 120kg in 12 seconds. How many men are required to transfer it in 9 seconds?	Pick one
A) 4	B) 5	C) 6	D) 7	E) 8

Solution: We have, M1D1H1 = M2D2H2   3*120*12 = M2*120*9   M2 = 3*120*12/120*9 = 4   4NSWER:4
Answer: A
A batch of cookies was divided amomg 6 tins: 2/3 of all the cookies were placed in either the blue or the green tin, and the rest were placed in the red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin
Pick one.
A) 15/2 B) 9/4 C) 5/9 D) 5/7 E) 9/7

Solution: This will help reduce the number of variables you have to deal with:   G + B = 2/3   R = 1/6   B = 1/4   We can solve for G which is 5/12   What fraction (let it equal X) of the cookies that were placed in the other tins were placed in the green tin?   So..   X*(G+R)=G   X*(5/12 + 1/6) = 5/12   X = 5/7   ANSWER: 5/7
Answer: D
Each child has 12 crayons and 24 apples. If there are 18 children, how many crayons are there in total? Select the correct option.
A) 220 B) 65 C) 216 D) 219 E) 230

Solution: 12*18= 
12*18 = 216
216.Answer is 216.
Answer: C
A bag is bought for Rs.400 and sold at a gain of 35% find its selling price  Choose one:
A) A)Rs.460/-
B) B)Rs.470/-
C) C)Rs.480/-
D) D)Rs.500/-
E) E)Rs.520/-

Solution: 100 % ------> 400 (100 * 4 = 400)   135 % ------> 540 (135 * 4 = 540)   Selling price = Rs.540   Answer : Rs.520/-
Answer: E