MU-NLPC/Calc-aqua_rat huggingface dataset:
The diagonals of a rhombus are 15 cm and 20 cm. Find its area?
Choose the correct choice from the following options:
A) 158
B) 129
C) 150
D) 123
E) 117

Solution: 1/2 * 15 * 20= 
1/2 * 15 * 20 = 150
150   Answer:150
Answer: C
Calculate the mean of each data set {9,10,11,7,13}
Choose the correct choice from the following options:
A) 4  B) 5  C) 8  D) 9  E) 10

Solution: mean of Data set A = (9+10+11+7+13)/5= 
(9+10+11+7+13)/5 = 10
10   mean of Data set B= (10+10+10+10+10)/5= 
(10+10+10+10+10)/5 = 10
10   mean of Data set C= (1+1+10+19+19)/5= 
(1+1+10+19+19)/5 = 10
10   Option 10
Answer: E
Two highways start from a point P and meet again at the point Q. Between P and Q there are 5 subways, joining the highways at 5 different places. How many different routes are possible for a journey from P to Q?
Select the correct option:	A) 12	B) 16	C) 24	D) 32	E) 64

Solution: If one starts its journey from point P, one has 2 options ( to go via either highway)... When he reaches 1st subway point he has again, 2 options, to continue on the highway or to go through subway., When he reaches next subway, he will have same two options, of course we are considering that he doesn't return from any point.   Since, there are 5 subways, he has the option of choosing from 2 choices 6 times (one when he just starts his journey). So, total ways he can reach is destination is 2^6 = 64.   ANSW64R:64
Answer: E
There are 9 people and 7 chairs. In how many different ways people can occupy the chairs? Choose the most appropriate option.
A) 405
B) 504
C) 404
D) 505
E) 506

Solution: number of ways = 9*8*7= 
9*8*7 = 504
504   Answer is 504
Answer: B
Canister C is 1/2 full of water and canister D, which has twice the capacity of canister C, is 1/3 full of water. If the water in canister D is poured in canister C until canister C is completely full of water, canister D will still contain what fraction of its capacity of water?	Select the correct option:
A) 0	B) 1/36	C) 1/12	D) 1/6	E) 1/4

Solution: Say canister C has a capacity of 6 liters. It's half full, thus there can be poured 3 liters of water.   Canister B is 12 liters and there are 4 liters of water. We can pour 3 liters from D to C and 1 liter will still be left in D, which is 1/12 of its total capacity.   Answer: 1/12.
Answer: C
A cistern 10 meters long and 4 meters wide contains water up to a depth of 1 meter 25 cm. What is the total area of the wet surface?	Choose the correct choice from the following options.
A) 45 B) 55 C) 65 D) 75 E) 85

Solution: Area of the wet surface = [2(lb + bh + lh) - lb]   = 2(bh + lh) + lb   = [2 (4 x 1.25 + 10 x 1.25) + 10 x 4]   = 75   The answer is 75.
Answer: D
If set A={2,2,2,....,n times} , set B={4,4,4,4....m times} and set C={11,11,11...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?
Options:  A) a) k(n+m+mn)+ k  B) b) k^2(mn+n/m)  C) c) (1+n+m+mn)(k+1)  D) d) kmn(k+m+n)  E) e) None of the above.

Solution: a) how many 2's are included?   b) how many 3's are included?   and   c) how many 11's are included?   For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.   NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.   The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:   (mn + m + n + 1)(k + 1).   Mike   c) (1+n+m+mn)(k+1)
Answer: C
Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 2 days? Choose the correct answer.
A) 2/5
B) 1/6
C) 1/4
D) 1/9
E) 2/6

Solution: A's one day's work = 1/30   B's one day's work = 1/45   (A + B)'s one day's work = 1/30 + 1/45 = 1/18   The part of the work completed in 2 days = 2 (1/18) = 1/9.   ANSWER 1/9
Answer: D
A woman named Susila started a business investing Rs. 25,000. Roja joined him after six months with an amount of Rs. 50,000 and Sachin joined them with Rs. 75,000 after another six months. The amount of profit earned should be distributed in what ratio among Susila , Roja and Sachin respectively, 3 years after Aman started the business ?
Choose the correct choice from the following choices: A) 7:6:10 B) 12:15:16 C) 42:45:56 D) 3 : 5 : 6 E) 12:15:18

Solution: Explanation :   Akash : Roja : Sachin = (25,000 x 36) : (50,000 x 30) : (75,000 x 24)   = 36 : 60 : 72 => 3 : 5 : 6   Answer : 3 : 5 : 6
Answer: D
Tough and Tricky questions: Combinations.
Four students - 2 boys and 2 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?  Choose the correct choice from the following answers.
A) 8  B) 36  C) 72  D) 240  E) 720

Solution: We can have 2 arrangements:   BGBG or GBGB   2!*2!*2 = 2*2*2= 
2*2*2 = 8
8 ways.   Ans. 8) 8
Answer: A
SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69--------------------------10
70-79--------------------------16
80-89--------------------------5
90-99--------------------------2
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 35 scores?
Choose the correct option
A) 16th  B) 20th  C) 22th  D) 24th  E) 18th(70-79)

Solution: Total scores= 2+10+16+5+2= 
2+10+16+5+2 = 35
35, which is odd, therefore the median is the Floor(35/2)+1= 18th score. And the 18th score is in the 70-79 range, because 50-69 only reference 12 scores.   18th(70-79)
Answer: E
Ramu bought an old car for Rs. 36400. He spent Rs. 8000 on repairs and sold it for Rs. 68400. What is his profit percent?
Choose the correct choice from the following answers:
A) 16%
B) 17%
C) 18%
D) 54%
E) 13%

Solution: Total CP = Rs. 36400 + Rs. 8000   = Rs. 44400 and SP = Rs. 68400   Profit(%)   = (68400 - 44400)/44400 * 100   = 54%   Answer: 54%
Answer: D
What are the last two digits of 63*35*37*82*71*412  Choose the correct choice from the following:	A) 10	B) 30	C) 40	D) 70	E) 80

Solution: We know that to find the last two digits, we need to find the remainder we get when we divide the product by 100.   Remainder of (63*35*37*82*71*41)/ 100   Note that we can simplify this expression by canceling out the 5 and 2 in the numerator and denominator. But before we do that, here is an important note:   Note: We cannot just cancel off the common terms in the numerator and denominator to get the remainder. But, if we want to cancel off to simplify the question, we can do it, provided we remember to multiply it back again.   So say, we want to find the remainder when 14 is divided by 10 i.e. 14/10 (remainder 4). But we cancel off the common 2 to get 7/5. The remainder here will be 2 which is not the same as the remainder obtained by dividing 14 by 10. But if we multiply 2 back by 2 (the number we canceled off), the remainder will become 2*2= 
2*2 = 4
4 which is correct.   Take another example to reinforce this – what is the remainder when 85 is divided by 20? It is 5.   We might rephrase it as – what is the remainder when 17 is divided by 4 (cancel off 5 from the numerator and the denominator). The remainder in this case is 1. We multiply the 5 back to 1 to get the remainder as 5 which is correct.   So keeping this very important point in mind, let’s go ahead and cancel the common 5 and 2.   We need the   Remainder of (63*7*37*41*71*41*5*2)/10*5*2   Remainder of (63*7*37*41*71*41)/10   Now using concept 2, let’s write the numbers in form of multiples of 10   Remainder of (60+3)*7*(30+7)*(40+1)*(70+1)*(40+1)/10   Remainder of 3*7*7*1*1*1/10   Remainder of 147/10= 7   Now remember, we had canceled off 10 so to get the actual remainder so we need to multiply by 10: 7*10 = 70.   When 63*35*37*82*71*41 is divided by 100, the remainder is 70. So the last two digits of 63*35*37*82*71*41 must be 80.   Answer (80)
Answer: E
A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 240 m long?  Pick one.
A) 38 sec  B) 35 sec  C) 44 sec  D) 48 sec  E) none of these

Solution: Speed = 45 km/hr = 45 Ã— (5/18) m/s   = 150/12 = 50/4 = 25/2 m/s   Total distance = length of the train + length of the platform   = 360 + 240= 
360 + 240 = 600
600 meter   Time taken to cross the platform= 600/(25/2) = 600 Ã— 2/25 = 48 seconds   ANSWER:48 sec
Answer: D
P and Q invested in a business. The profit earned was divided in the ratio 2 : 3. If P invested Rs 30000, the amount invested by Q is  Choose the correct choice from the following options:
A) 30000 B) 50000 C) 45000 D) 20000 E) 60000

Solution: Let the amount invested by Q = q   30000:q=2:3   ⇒30000×3=2q   ⇒q=(30000×3)/2=45000   Answer is 45000.
Answer: C
If n = 2×3×5×7×11×23, then which of the following statements must be true?
I. n2 is divisible by 600
II. n + 19 is divisible by 19
III. is even n+4 / 2 = even
IV. n is divisible by 35	Choose the correct option.
A) I only	B) b- II only	C) none and IV only	D) I and III only	E) e None

Solution: 2×3×5×7×11×23 =53130   I. not divisible by 600   II 53130+19=39149 not divisible by 19   III. 53130+4/2= odd= 26567   iv. divisible by 35   none and IV only
Answer: C
Working together, Jose and Jane can complete an assigned task in 15 days. However, if Jose worked alone and complete half the work and then Jane takes over the task and completes the second half of the task, the task will be completed in 45 days. How long will Jose take to complete the task if he worked alone? Assume that Jane is more efficient than Jose  Choose the correct answer:
A) 26 days
B) 31 days
C) 50 days
D) 65 days
E) 36 days

Solution: Assume:   Jose does 1 job in x days, so Jose does 1/x job in a day   Jane does 1 job in y days, so Jane does 1/y job in a day   Together, they does (x+y)/xy job in a day. This is equals to 1/20. So   (x+y)/xy = 1/15   15(x+y) = xy   Next, we're told 1 job takes 45 days to complete if Jose and Jane each does half the work. So since Jose does 1 job in x days, he wil need x/2 days to do half the job. Jane similarly will need y/2 days to do the other half.   x/2 + y/2 = 45   x+y = 90   So   xy = 1350   The answer choices are:   25 days   30 days   60 days   65 days   36 days   From the answer choices, So I'll go for 50 days for Jose and 27 days for Jane.   Answer : 50 days
Answer: C
The average of 65 numbers is 40. If two numbers, 83 and 60 are discarded, then the average of the remaining numbers is nearly
Choose one:
A) 28.32 B) 39 C) 38.78 D) 29 E) 30

Solution: Explanation :   Total sum of 63 numbers = (65 40) (83 +60) = 2600 143 = 2457   Average = 2457/63= 
2457/63 = 39
39   Answer : 39
Answer: B
If the price of the commodity is increased by 50% by what fraction must its consumption be reduced so as to keep the same expenditure on its consumption?
Pick one
A) 1/4 B) 1/3 C) 1/2 D) 2/3 E) None

Solution: Solution: Let the initial price of the commodity be 100.   After 50% increase in price, It will become,   100 ------50% increase----> 150.   Now, we have to reduce the consumption to keep expenditure 100.   Increase in price= 150 - 100= 
150 - 100 = 50
50   We have to reduce the consumption,= (50/150)*100 = 1/3 or 33.33%   Other Method:   Here, we use, Final product constant graphic.   100 ==50% up== 150===33.33% down===>100.   Consumption Reduce = 33.33% = 1/3.   Answer: Option 1/3
Answer: B
In a race with 10 competitors, the first-place finisher receives a gold medal, and the second-place finisher receives a silver medal. If there are no ties, in how many different ways may these two medals be awarded? Answers.
A) 90 B) 120 C) 720 D) 840 E) 68

Solution: Well in this case since there are 2 positions and they can be taken by 2 persons only ,so order matters over here .For gold there are 10 choices and for silver 9 remain (one who got gold cannot be given silver).   So total possibilities=10*9   Correct answer 90=90
Answer: A
Find the odd man out. 14,35,49,60,70 Options.
A) 14  B) 35  C) 49  D) 60  E) 70

Solution: All except 60 are multiples of 7   Answer is 60
Answer: D
50 men can complete a work in 65 days.Five days after started the work, 20 men left the group. In how many days can the remaining work be completed?	Choose the correct choice from the following answers.
A) 327  B) 799  C) 2778  D) 277  E) 100

Solution: After 5 days, the following situation prevails.   50 men can complete the work in 60 days.   30 men can complete the work in ? days.   M1 D1 = M2 D2   => 50 * 60 = 30 * D2   => D2 = (50 * 60)/30= 
(50 * 60)/30 = 100
100 days.   Answer:100
Answer: E
A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. In what ratio will the profit be shared at the end of 3 years ? Choose the correct answer:
A) 3 : 4 : 6
B) 3 : 4 : 7
C) 3 : 4 : 9
D) 3 : 4 : 1
E) 3 : 4 : 3

Solution: Explanation:   A : B : C = (40000 x 36) : (80000 x 12 + 40000 x 24) : (120000 x 24 + 40000 x 12)   = 144 : 192 : 336   = 3 : 4 : 7.   Answer: 3 : 4 : 7) 3 : 4 : 7
Answer: B
On a business trip, 30 percent of 60 sales representatives will be given accommodations at Hotel XYZ and the remaining 70 percent will be given accommodations at Hotel ABC. However, 40 percent of the sales representatives prefer to stay at Hotel XYZ and 60 percent prefer to stay at Hotel ABC. What is the highest possible number of sales representatives NOT given accommodations at the hotel they prefer?
Choose the correct choice from the following answers:
A) 36
B) 39
C) 42
D) 45
E) 48

Solution: 18 people stay in XYZ and 42 people stay in ABC.   24 people prefer XYZ and 36 people prefer ABC.   Let's put all 24 people who prefer XYZ in hotel ABC.   Then 18 people who prefer ABC will stay in XYZ.   The highest possible number who are not given their preference is 24+18= 
24+18 = 42
42.   The answer is 42.
Answer: C
80 is increased by 50%. Find the final number.  Choose the correct choice from the following options.
A) 100	B) 110	C) 120	D) 30	E) 160

Solution: Final number = Initial number + 50%(original number) = 80 + 50%(80) = 80 + 40= 
80 + 40 = 120
120.   Answer 120
Answer: C
A and B enter into a partnership with respective capitals of Rs. 20,000 and Rs. 40,000. At the end of the year, the total profit is Rs. 36,000. If A receives Rs. 15,000 as both his salary and profit, then what is his salary?
Choices
A) Rs. 2000  B) Rs. 4000  C) Rs. 3500  D) Rs. 3000  E) None of these

Solution: Explanation:   A's capital : B 's capital   20000 : 40000 = 1 : 2   Since, the time period is fixed, the profit is distributed in the ratio of capital 1 : 2   Profit of A = (1/3) * 36,000 = Rs. 12,000   Salary of A = Rs. (15000 – 12000) = Rs. 3000   ANSWER: Rs. 3000
Answer: D
The C.P of 21 articles is equal to S.P of 18 articles. Find the gain or loss percent.
Choose the correct answer.
A) 10%	B) 18 1/3%	C) 16 2/3 %	D) 20%	E) 30%

Solution: Let C.P of each article be Re. 1.   Then C.P of 18 articles = Rs. 18,   S.P of 18 articles = Rs. 21.   Gain % = ( 3/18 * 100 ) % = 16 2/3   ANSWER:16 2/3 %
Answer: C
The "length" of a positive integer greater than 1 is the number of prime numbers, including repeats, that are factors of that integer. For instance, the length of 20 is 3, because 2×2×5=202×2×5=20. What is the length of 5,950? Choose the correct choice:
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: 5950   =5x1190   =5x5x238   =5x5x2x118   =5x5x2x2x59   5 prime factors including repeats   Answer 5
Answer: E
How many no.'s with 3 different digits, 2, 3, 5, 6, 7 and 9, which are divisible by 5?  Choices:
A) 10	B) 20	C) 40	D) 45	E) 50

Solution: Since each desired number is divisible by 5, so we must have 5 at the unit place. So, there is 1 way of doing it.   The tens place can now be filled by any of the remaining 5 digits (2, 3, 6, 7, 9). So, there are 5 ways of filling the tens place.   The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.   Required number of numbers = (1 x 5 x 4) = 20   20
Answer: B
Two trains are running in opposite directions with the same speed. If the length of each train is 100 m and they cross each other in 10 sec, then the speed of each train is?  Choose the correct choice from the following answers.
A) 22
B) 18
C) 36
D) 88
E) 21

Solution: Let the speed of each train be x m/sec.   Then, relative speed of the two trains = 2x m/sec.   So, 2x = (100 + 100)/10 => x = 5   Speed of each train = 5 m/sec.   = 5 * 18/5 =- 18 km/hr.Answer: 18
Answer: B
If 20 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip?	Answers:  A) 95  B) 90  C) 85  D) 80  E) 75

Solution: Let x be the number of students in the school. 0.2x students went to the trip and took more than 100$. They compose   (100-75)= 
  (100-75) = 25
25% of all students who went to the trip. Therefore the toal of 0.2x/0.25=0.8x students went to the camping which is 80%.   The answer is 80  0.2 /0.25= 
  0.2 /0.25 = 0.8
0.8x students went to the camping which is 80%.   The answer is 80
Answer: D
If the sum of the interior angles of a regular polygon measures up to 540 degrees, how many sides does the polygon have?  Choices:	A) 7	B) 5	C) 3	D) 8	E) None of these

Solution: 5 sides...Answer is 5
Answer: B
On a 20 mile course, Bil bicycled at an average rate of 30 miles per hour for the first 12 minutes and without a break, ran the rest of the distance at an average rate of 8 miles per hour. How many minutes did Pat take to cover the entire course? Pick one:	A) 75	B) 105	C) 117	D) 150	E) 162

Solution: At an average rate of 30 miles per hour in 12 minute (1/5 hours) Bil covers (distance) = (time) * (rate) = 1/5*30= 
1/5*30 = 6
6 miles, thus she should cover the remaining distance of  20 - 6= 
 20 - 6 = 14
14 miles at an average rate of 8 miles per hour.   To cover 14 miles at an average rate of 8 miles per hour Pat needs (time)= (distance)/(rate) = 14/8= 
14/8 = 7/4 = around 1.75
1.75 hours= 105 minutes.   Therefore Bil needs total of   12 + 105= 
  12 + 105 = 117
117 minutes to cover the entire course.   Answer: 117.
Answer: C
96 64 128 192 128 256 288 192 ?  Choose the most appropriate option
A) 367	B) 384	C) 374	D) 284	E) 484

Solution: After 3 terms the series repears. So 4th 5th 6th term are 2* 1st 2nd and 3rd term repectively. While the 7th 8th 9th are 3* 1st 2nd 3rd terms. So ans=128*3= 
128*3 = 384
384   ANSWER:384
Answer: B
Which of the following values is the greatest Answers:	A) a) 11% of 89	B) b) 22% of 78	C) c) 45% of 67	D) d) 44% of 56	E) e) 55% of 45

Solution: Are you sure that you checked the answer key correctly? I just signed up forVeritas(haven't started yet, not until March) but I have access to the materials and the answer key I'm looking at says c) 45% of 67
Answer: C
At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?	Choose the correct choice from the following answers.
A) 17 years	B) 15 years	C) 18 years	D) 12 years	E) 19 years

Solution: Let the present ages of Arun and Deepak be 4x and 3x years respectively.   Then, 4x + 6 = 26 => x   = 5   Deepak's age   = 3x   = 15 years.   Answer:15 years
Answer: B
If integers ending in zero are excluded, what is the units digit of the product of the even integers from 202 to 298, inclusive?  Choose the correct answer:
A) 2 B) 4 C) 6 D) 8 E) 9

Solution: In such questions, it is of utmost importance that you select the list in a smart way.   Following will be the list of even integers:   202, 204, 206, 208 - Units digit of the product = units digit of 2*4*6*8 = 4   212, 214, 216, 218   222, 224, 226, 228   232, 234, 236, 238   .   .   .   .   282, 284, 286, 288   292, 294, 296, 298   We have 10 such sets, the units digit of which is 4   Hence the units digit of the whole product = units digit of 4^10   Since the cyclicity of 4 is 2, units digit of 4^10 = units digit of 4^2 = 6   6orrect Option: 6
Answer: C
On a two-dimensional coordinate plane, the line A = x^2 - x^3 touches the x-axis in how many places?
Choose the correct choice from the following choices.
A) 0 B) 1 C) 2 D) 3 E) 4

Solution: Apparently it's A = x^2 - x^3 instead of A = x^2 - A^3.   In this case: the x-intercept is the value(s) of x for A = 0.   0 = x^2 - x^3;   0 = x^2(1 - x);   x = 0 or x = 1.   Answer: 2.
Answer: C
A pipe can empty the tank in 8 hours and another fill 6 litres in 1 min. If both pipe opened, the tank is emptied in 12 hours. The capacity of tank is ?	Select:
A) 8000
B) 8240
C) 8440
D) 8640
E) 8840

Solution: Let Capacity of the Tank is 100%.   First Pipe can empty the tank in = 8 hours = 8 * 60= 
8 * 60 = 480
480 min   Work rate of the pipe= X/480 litre per min.   The work rate of both pipe = X/(12*60) litre per min =   (X/480) - (X/720 )= Work rate of Second pipe   720X - 480X = 6 litere * 720 *480   240X = 6*720*480   X = 8640 litres   ANSWER :OPTION 8640
Answer: D
If f(a)=2a+3, what is the value of (f(2a)+f(a)) ? Pick
A) 2a-4	B) 6a+6	C) 9a+5	D) 6a+12	E) 3a+5

Solution: f(a)=2a+3   f(2a)= 4a+3   (f(2a)+f(a)) = 4a+3+2a+3 = 6a+6   Answer is 6a+6
Answer: B
A monkey ascends a greased pole 20 metres high. He ascends 2 metres in first minute and slips down 1 metre in the alternate minute. In which minute, he reaches the top ?
Select:  A) 21st  B) 22nd  C) 23rd  D) 24th  E) 37th

Solution: In 2 minutes, he ascends = 1 metre   âˆ´ 18 metres, he ascends in 36 minutes.   âˆ´ He reaches the top in 37th minute.   Answer 37th
Answer: E
Into a bag there are 20 honey and 5 cherry candies. If a boy pick only two candies simultaneous and randomly, what is the probability that he picks one candy of each flavor?
Options
A) 2/25
B) 1/50
C) 1/12
D) 1/6
E) 1/3

Solution: We are told that we have 25 candies, 20 honey and 5 cherry candies. The candies are picked simultaneous and randomly, C1 and C2, in different flavors. There are two acceptable outcomes: 1) C1 is honey and C2 is cherry; 2) C1 is cherry and C2 is honey. Let's go: 1) C1 = (20/25)(5/24)= 1/6 chance of this happening. 2) C2 = (5/25)(20/24) = 1/6 chance of this happening. Then: (1/6)+(1/6)= 1/3, chance of getting the result that you wanted. Answer 1/3.
Answer: E
After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
Options.
A) 19 days B) 10 days C) 20 days D) 12 days E) 15 days

Solution: Explanation:   1/3 ---- 6   1 -------?   A = 18   R = 1/18 * 60/100 = 1/30   1 ----- 1/30   2/3 ----? => 20 days   Answer: 20 days
Answer: C
If a, b, and c are consecutive positive even integers and a > b > c, which of the following could be equal to a - b + c ? Answers: A) 6 B) 2 C) 4 D) -3 E) -4

Solution: consectutive even , X , X + 2 , X + 4 where X = Even   now subtract X - (X+2) + (X+4)   doing this leaves us with X + 2   what even number can we substitute in X to yield an answer choice   4 works 4 (plug in 2 for X)
Answer: C
What is the Compound Interest on Rs.4500 at 5% p.a. compounded half-yearly for 3 1/2 years.
Choose the correct choice from the following answers:  A) Rs. 859.09  B) Rs. 349.09  C) Rs. 449.09  D) Rs. 749.09  E) Rs. 849.09

Solution: Compound interest : A = P(1 + r/n)nt   A = 5,349.09   C.I. >> 5,349.09 - 4500 >> Rs. 849.09   Answer:Rs. 849.09
Answer: E