MU-NLPC/Calc-aqua_rat huggingface dataset:
The average age of 15 students of a class is 15 years. Out of these, the average age of 4 students is 14 years and that of the other 10 students is 16 years. The age of the 15th student is
Choose one
A) 9 years B) 11 years C) 14 years D) 21 years E) 9 years

Solution: Solution   Age of the 15th student	=[15x15-(14x4+16x10)]   = (225 - 216)= 
(225 - 216) = 9
9 years.   Answer 9 years
Answer: E
If x and y are positive real numbers such that x + y = 1, which of the following could be the value of 100x + 700y?
I. 90
II. 250
III. 699 Choose one: A) II only B) III only C) I and II D) I and III E) II and III

Solution: We know that x and y are both between 0 and 1.   The minimum limit of 100x + 700y is 100, when x is close to 1 and y is close to 0.   The maximum limit of 100x + 700y is 700, when x is close to 0 and y is close to 1.   The expression can take on any value between 100 and 700.   The answer is II and III.
Answer: E
In the first 8 overs of a cricket game, the run rate was only 2.3 What should be the rate in the remaining 20 overs to reach the target of 260 runs?
Pick:  A) 12.08  B) 12.18  C) 12.0  D) 6.19  E) 6.21

Solution: Required run rate   = [260- (2.3 * 8)]/20   = 241.60/20= 
241.60/20 = 12.08
12.08   12.08nswer:12.08
Answer: A
After an ice began to melt out from the freezer, in the first hour lost 3/4, in the second hour lost 3/4 of its remaining. If after two hours, the volume is 0.2 cubic inches, what is the original volume of the cubic ice, in cubic inches?
Pick one: A) 2.5 B) 3.2 C) 4.0 D) 6.5 E) 8.0

Solution: Let initial volume of ice be = x   Ice Remaining after 1 hour = x - 0.75x = 0.25x   Ice Remaining after 2 hour = (1/4)x - (3/4 * 1/4 * x) = (1/16)x   (1/16)x = 0.2   x = 3.2   Alternate solution: Try to backsolve.   Initial volume = 3.2   After one hour --> (1/4)3.2 = 0.8   After two hours --> (1/4)0.8 = 0.2   Answer: 3.2
Answer: B
In a box, there are 10 red, 6 blue and 5 green balls. One ball is picked up randomly. What is the probability that it is neither red nor blue?  Pick: A) 4/51 B) 10/21 C) 7/12 D) 6/21 E) 13/17

Solution: Total number of balls = 10+6+5= 
10+6+5 = 21
21   E= event that the ball drawn is neither red nor blue   = event that the ball drawn is blue   n(E) = 6   P(E) = 6/21   Answer is 6/21
Answer: D
A man has Rs. 192 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ? Select.
A) 37
B) 36
C) 22
D) 90
E) 28

Solution: Let number of notes of each denomination be x.   Then, x + 5x + 10x = 192 16x = 192 x = 12.   Hence, total number of notes = 3x = 36.   Answer:36
Answer: B
If a, b, q are integers, 33 = abq, and a < b < q, what is the smallest possible value of a?	Choose the correct choice from the following choices:
A) -33
B) -3
C) 1
D) 3
E) 11

Solution: Given : a * b * q = 33.   33 is a Positive Odd number.Side Note:Thus, all 3 numbers will be odd.   Prime factorization will also give you numbers. 1, 3, 11. The 3 numbers will be combination of these 3 numbers with possible variation in sign(+/-).   We could have any 2 digits as negative. --> negative * negative * positive. We have negative values in answer option, so eliminate C, D and E from answer choices.   -33 * -1 * 1= 
-33 * -1 * 1 = 33
33.   Correct answer is -33
Answer: A
Six points lie on the circumference of a ellipse. What is the positive difference between the number of triangles and the number of quadrilaterals that can be created by connecting these points?
Choose the correct option
A) 4  B) 6  C) 5  D) 15  E) 20

Solution: Number of triangles can be formed out of 6 points= 6C3=20   Number of quadrilaterals can be formed out of 6 points= 6C4=15   20-15= 
20-15 = 5
5.   Answer=5
Answer: C
What is the value of: 7^9 - 7^11 ?	Choose the correct choice:
A) -7^20 B) 7^-3 C) -49^20 D) -48(7^9) E) 50(7^9)

Solution: 7^9 - 7^11 = 7^9 (1 - 7^2) = 7^9 (1 - 49) = -48 (7^9), Answer -48(7^9).
Answer: D
Two letters from the word FARTHING are selected at random. What is the probability that at least one of the selected letters is a consonant?
Two letters from the word FARTHING are selected at random. What is the probability that at least one of the selected letters is a consonant?
Pick one.
A) A)1/500	B) B)1/28	C) C)27/28	D) D)124/125	E) E)499/500

Solution: There are 6 consonants and 2 vowels in FARTHING.   probability that at least one of the selected letters is a consonant = 1 - (Probability of both vowels)   Probability of both vowels = 227/282/827/282 = 1/28   So, Answer is 1 - 1/28 = 27/28 ------> 27/28.
Answer: C
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train.
Pick one:
A) 150 m
B) 155 m
C) 180 m
D) 190 m
E) 205 m

Solution: 150 mnswer: Option 150 m   Speed = 60*(5/18) m/sec = 50/3 m/sec   Length of Train (distance) = speed * Time     (50/3) * 9= 
  (50/3) * 9 = 150
150 meter
Answer: A
To reach her destination, Jeanette must drive 90 miles. If she drives 6 miles every 7 minutes, how much time will it take her to reach her destination?  Choose the correct choice from the following:
A) 2 hours and 2 minutes
B) hours and 45 minutes
C) 2 hours and 10 minutes
D) 2 hours and 12 minutes
E) 2 hours and 15 minutes

Solution: 7 minute for 6 miles how much for 90? minutes for 1(7/5) mile multiplied by 90 miles.   7*90/6= 
7*90/6 = 105
105> 1 hours 45 min answer is hours and 45 minutes
Answer: B
When the number 1y92355 is exactly divisible by 11, then the smallest whole number in place of y is?
Choose one:
A) 1 B) 3 C) 7 D) 9 E) 0

Solution: The given number =1y92355   Sum of the odd places =5+3+9+1= 
5+3+9+1 = 18
18   Sum of the even places= 5+2+y   (Sum of the odd places)- (Sum of even places) = Number (exactly divisible by 11)   18-(7+y) = divisible by 11   11 � y = divisible by 11.   Y must be 0, to make given number divisible by 11.   0
Answer: E
Sonika deposited Rs.8000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much?
Answers
A) 9680  B) 9687  C) 96809  D) 9683  E) 9682

Solution: (8000*3*2)/100= 
(8000*3*2)/100 = 480
480   9200   --------   9680   9680nswer: 9680
Answer: A
In the faculty of Reverse-Engineering, 226 second year students study numeric methods, 423 second year students study automatic control of airborne vehicles and 134 second year students study them both. How many students are there in the faculty if the second year students are approximately 70% of the total? Choices:
A) 515.
B) 545.
C) 618.
D) 644.
E) 736.

Solution: Answer is E :736   Solution : Total number of students studying both are 423 + 226 - 134= 
423 + 226 - 134 = 515
515 (Subtracting the 134 since they were included in the both the other numbers already).   So 70% of total is 515, so 100% is approx. 736.
Answer: E
Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent of the lights that are on are supposed to be off?	Pick one:
A) 22(2/9)%	B) 16(2/3)%	C) 11(1/9)%	D) 10%	E) 5%

Solution: a= number of lights supposed to be on   b= number of lights supposed to be off   total = a+b   no of lights that are on = 0.8(a+yb   Light that are supposed to be on but are actually off = 10% of a   Light that are supposed to be on are on = 90% of a   Light that aare supposed to be but are on = 40% of b   Light that aare supposed to be off are off = 60% of b   0.9a + 0.4b = 0.8 (a+b)   a = 4b   Suppose total Lights = 100   so, a = 80 and b = 20   No of lights that are on are on but are supposed to be off = 40% of b = 0.4 (20) = 5   So, the % of lights that are on are supposed to be off = 5/100 = 5%   ANSW5%R:5%
Answer: E
If p is the product of the integers from 1 to 30, inclusive, what is the greatest integer k for which 3^k is a factor of p ?	Choose the correct choice from the following options:
A) 10	B) 12	C) 14	D) 16	E) 18

Solution: Thus proceeding with the "300 + k" assumption, we get:   P = 30!   Option A: 310   => 310 = 2 * 5 * 31   => 31 is a prime and is not present in 30!   Thus 310 is not a factor of P   => A is Eliminated   Option 12: 312   => 312 = 2^3 * 3 * 13   Thus 312 is a factor of P   => 12 is the correct answer !   Option C: 314   => 314 = 2 * 157   => 157 is a prime and is not present in 30!   Thus 314 is not a factor of P   => C is Eliminated   Option D: 316   => 316 = 2^2 * 79   => 79 is a prime and is not present in 30!   Thus 316 is not a factor of P   => D is Eliminated   Option E: 318   => 310 = 2 * 3 * 53   => 53 is a prime and is not present in 30!   Thus 318 is not a factor of P   => E is Eliminated   ANS: 12
Answer: B
A can give B 100 meters start and C 200 meters start in a kilometer race. How much start can B give C in a kilometer race?
Choose the correct choice from the following choices
A) 111.12 B) 888.55 C) 200.05 D) 400.04 E) 250.5

Solution: A runs 1000 m while B runs 900 m and C runs 800 m.   The number of meters that C runs when B runs 1000 m,   = (1000 * 800)/900 = 8000/9 = 888.88 m.   B can give C = 1000 - 888.88= 
1000 - 888.88 = 111.12
111.12 m.   111.12NSWER 111.12
Answer: A
A train 2500 m long can cross an electric pole in 50 sec and then find the speed of the train?  Choose the correct choice from the following:
A) 178 B) 180 C) 182 D) 184 E) 186

Solution: Length = Speed * time   Speed = L/T   S = 2500/50= 
2500/50 = 50
50 M/Sec   Speed= 50*18/5 (To convert M/Sec in to Kmph multiply by 18/5)   Speed = 180 Kmph   Answer:180
Answer: B
How many kilograms of sugar costing Rs. 9 per kg must be mixed with 27 kg of sugar costing Rs. 7 per kg so that there may be a gain of 10 % by selling the mixture at Rs. 9.24 per kg?
Choose the correct option: A) 60 B) 50 C) 55 D) 63 E) 70

Solution: Selling price of 1kg = 924   profit = 10%   cost = 100/(100+profit%)*SP     100/(100+10)*9.24= 
  100/(100+10)*9.24 = 8.4
8.4   Mean price= (8.4-7=1.4) (9-8.4=0.6)   =>1.4:0.6=14:6 = 7:3   3x=27*7=63   ANSWER 63
Answer: D
A train traveling at 100 kmph overtakes a motorbike traveling at 64 kmph in 40 seconds. What is the length of the train in meters?
Choose one:
A) 1777 meters
B) 1822 meters
C) 400 meters
D) 1111 meters
E) None of these

Solution: Explanation :   When a train overtakes another object such as a motorbike, whose length is insignificant compared to the length of the train, the distance traveled by the train is equal to the length of the train.   Because the motorbike is also moving, we have to take the relative speed between the train and the motorbike and not just the speed of the train.   The length of the train = distance traveled by the train while overtaking the motorbike = relative speed between the train and the motorbike * time taken   In this case, as both the objects i.e., the train and the motorbike are moving in the same direction, the relative speed between them = difference between their respective speeds = 100 - 64= 
100 - 64 = 36
36 kmph.   Distance traveled by the train while overtaking the motorbike= 36 kmph * 40 seconds.   The final answer is in meters and the speed is given in kmph and the time in seconds.   So let us convert the given speed from kmph to m/sec.   1 kmph = 518518 m/sec   Therefore, 36 kmph = 36 * 518518 = 10 m/sec.   Relative speed = 10 m/sec. Time taken = 40 seconds.   Therefore, distance traveled = 10 * 40= 
10 * 40 = 400
400 meters.
Answer: B
A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man? Select the correct option.
A) 6.24 km B) 6 km C) 8.84 km D) 5.66 km E) 10 km

Solution: M = 9   S = 1.2   DS = 10.2   US = 7.8   x/10.2 + x/7.8 = 1   x = 4.42   D = 4.42 * 2= 
4.42 * 2 = 8.84
8.84   ANSWER:8.84 km
Answer: C
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 3125 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period. Choose the correct choice from the following answers:  A) 1631  B) 1531  C) 1533  D) 1535  E) 1536

Solution: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate A, B, C,D The answer to be E   Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.   If x = initial number of trees = 1536   Year 1 = 5/4x   Year 2 = (5/4)(5/4)x   Year 3 = (5/4)(5/4)(5/4)x   Year 4 = (5/4)(5/4)(5/4)(5/4)x   Only for Answer D: (5/4)(5/4)(5/4)(5/4)1536 = 3750   Hence, correct answer = 1536
Answer: E
The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:  Pick
A) 17 kg
B) 20 kg
C) 26 kg
D) 31 kg
E) 32 kg

Solution: Explanation:   Let A, B, C represent their respective weights. Then, we have:   A + B + C = (45 x 3) = 135 .... (i)   A + B = (40 x 2) = 80 .... (ii)   B + C = (43 x 2) = 86 ....(iii)   Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)   Subtracting (i) from (iv), we get : B = 31.   B's weight = 31 kg.   ANSWER IS 31 kg
Answer: D
A piece of work can finish by a certain number of men in 100 days. If however, there were 10 men less,
it would take 10 days more for the work to be finished. How many men were there originally?
Choose the correct answer:
A) 75 B) 82 C) 100 D) 110 E) 120

Solution: Expl: Originally let there be x men.   Less men, more days (Indirect)   :. (x-10): x : : 100 :110 or x-10/x = 100/110   or 11x-110 = 10x or x =110   So, originally there were 110 men.   Answer: 110
Answer: D
There are 24 students in Chad’s class. He brought 29 cookies to pass out
for his birthday. How many cookies will each student get? Will there be
any cookies left over?
Select the correct option: A) 1-9 B) 1-7 C) 2-8 D) 1-5 E) 3-10

Solution: 29/24 = 1 R 5 Chad will give each student 1 cookie and there will be 5   cookies left over   correct answer 1-5
Answer: D
A magician holds one six-sided die in his left hand and two in his right. What is the probability the number on the dice in his left hand is greater than the sum of the dice in his right? Choose the correct option
A) 7/108
B) 5/54
C) 1/9
D) 2/17
E) 1/4

Solution: The least sum of the numbers of the two dice in the right hand is 2. The maximum sum of the numbers on these two dice can be 5, for the left hand dice to be able to have a greater number.   Therefore the number on the dice in the left hand must be 3 or more.   Number of ways to get a sum of 2 with the two dice in the right hand= 1   Number of ways to get a sum of 3 with the two dice in the right hand= 2   Number of ways to get a sum of 4 with the two dice in the right hand= 3   Number of ways to get a sum of 5 with the two dice in the right hand= 4   Therefore required probability = P(two right dice have a sum of 2)*P(left dice has 3) + P(right dice have sum of 2 or 3)*P(left dice has 4) + P(two right dice have a sum of 2,3, or 4)*P(left dice has 5) + P(two right dice have a sum of 2,3,4,or 5)*P(left dice has 6)   = (1/36)*(1/6) + (3/36)*(1/6) + (6/36)*(1/6) + (10/36)*(1/6)   = (1/216) * (1+3+6+10)   = 20/216   = 5/54   Option 5/54
Answer: B
There are 6 ladies and 4 gents to dine at a round table. In how many ways can they seat themselves so that no two gents are seated together. Choose the correct answer
A) 85400  B) 36400  C) 86400  D) 14400  E) 88600

Solution: First arrange the ladies. This is a circular arrangment. 6 Gents can be arranged in 5! ways.   Now there are 6 spaces (space in between two ladies) and we have to seat 5 gents there.   First select 4 places out of 5 available places. can be done in 5C4ways. Then arrange 5 gents there in 5! ways.   Total: 5!*5C4*4! = 14400   14400 is the answer.
Answer: D
A man covered a certain distance at some speed. If he had moved
3 kmph faster, he would have taken 40 minutes less. If he had moved
2 kmph slower, he would have taken 40 minutes more. What is the distance in km? Choose the correct choice.
A) 40
B) 30
C) 35
D) 60
E) 55

Solution: speed= 2v1v2/v1-v2=2*3*2/3-2=12 km/hr   dist=12*40/16(1+12/3)=40 km   40NSWER 40
Answer: A
The average score of a cricketer for twelve matches is 48 runs. If the average for first eight matches is 40, then average for last four matches is  Choose one:	A) 33.25	B) 89	C) 64	D) 68	E) 90

Solution: Explanation:   =(48×12)−(40×8)/4   =(576−320)/4=64   Answer: Option 64
Answer: C
Last year’s receipts from the sale of greeting cards during the week before Mother’s Day totaled $239 million, which represented 10 percent of total greeting card sales for the year. Total greeting card sales for the year totaled how many million dollars?
Choose the correct choice from the following answers.
A) 2,390
B) 2,100
C) 1,890
D) 1,701
E) 210

Solution: 10% ---- 239 millions   for 100% => ( 239 * 100% )/10% = 2390.   Option 2,390.( 239 * 100  )/10= 
( 239 * 100  )/10 = 2_390
2390.   Option 2,390.
Answer: A
If A^5 + B^5 = 2500, then the greatest possible value of A is between Choose the correct option:  A) 0 and 3  B) 3 and 6  C) 6 and 9  D) 9 and 12  E) 12 and 15

Solution: for the greatest possible value of A^5, we must minimize the value of B^5 i.e. lets say B^5 = 0   then we need to find a number A such that A^5 < 2500. 4^5 = 1024 and 5^5 = 3125 so we can say that the maximum possible value of A can be a little more than 4 hence answer = between 3 and 6   hence 3 and 6
Answer: B
Two trains of equal are running on parallel lines in the same direction at 52 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? Pick one.
A) 50 m B) 72 m C) 80 m D) 82 m E) 84 m

Solution: Let the length of each train be x m.   Then, distance covered = 2x m.   Relative speed = 52 - 36= 
52 - 36 = 16
16 km/hr.= 16 * 5/18 = 40/9 m/sec.   2x/36 = 40/9 => x = 80.   ANSWER:80 m
Answer: C
At Deluxe paint store, Fuchsia paint is made by mixing 5 parts of red paint with 3 parts of blue paint. Mauve paint is made by mixing 3 parts of red paint with 5 parts blue paint. How many liters of blue paint must be added to 40 liters of Fuchsia to change it to Mauve paint? Pick one: A) 9 B) 12 C) 15 D) 16 E) 26.6

Solution: in 40 liters, Red = 5/8 * 40= 
5/8 * 40 = 25
25 and Blue= 15   so, 25/(15+x) = 3/5   or, x = 26.6 (Answer 26.6)
Answer: E
If 6 (A's capital) = 8 (B's capital) = 10 (C's capital). Then the ratio of their capitals is:  Choose the correct choice.
A) 3:4:5 B) 12:15:20 C) 20:15:12 D) 6:8:10 E) 8:4:12

Solution: Explanation:   6A = 8B = 10 20:15:12   A:B:20:15:12 = 1/6:1/8:1/10   = 20:15:12   ANSWER IS 20:15:12
Answer: C
Find the probability that a leap year selected at random will not have 53 Sundays Options
A) 6/7
B) 5/7
C) 4/7
D) 3/7
E) 2/7

Solution: There are 366 days in a leap year: 52 weeks and 2 more days. So, 52 Sundays and 2 days.   These 2 days can be: {Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat,Sun} and {Sun, Mon} (7 cases). In order to have 53 Sundays we should have either {Sat,Sun} or {Sun, Mon} case.   The probability of that is 2/7.   So, probability of not having 53 sundays is 1 - 2/7 = 5/7   Answer: 5/7.
Answer: B
Seven children â€” A, B, C, D, E, F, and G â€” are going to sit in seven chairs in a row. Children A & B must sit next to each other, and child C must be somewhere to the right of A & B. How many possible configurations are there for the children?
Choose the correct choice from the following options:
A) 600	B) 720	C) 1440	D) 4320	E) 4800

Solution: This problem is a notch harder than anything you are likely to see on the GMAT. If you can master the principles in this problem, you certainly will be able to handle almost any problem the GMAT could concoct.   First, consider the restriction of A & B. As with problem #1 above, there are 12 possibilities for A & B, counting both position and order.   Now, put the other five in any order â€” thatâ€™s 120 possibilities, for a total number of configurations of 1440. That number does not take into account the restriction with C.   Think about those 1440 configurations. In exactly half of them, C will be to the right of A & B, and exactly half, C will be to the left of A & B. Therefore, in  (1/2)*1440= 
 (1/2)*1440 = 720
720 configurations, C will be to the right of A & B. Answer= 720
Answer: B
On an order of 4 dozen boxes of a consumer product, a retailer receives an extra dozen free. This is equivalent to allowing him a discount of:  Choose the correct choice from the following choices:
A) 10%
B) 20%
C) 30%
D) 40%
E) 50%

Solution: Clearly, the retailer gets 1 dozen out of 5 dozens free.   Equivalent discount = 1/5 * 100= 
1/5 * 100 = 20
20%.   Answer 20%) 20%
Answer: B
Pipe A runs 60 liters of water per minute into a pool that has a total volume of 3,600 liters. Pipe B fills a third of the pool in 12 hours.
Working together how long will it take both pipes to fill the pool?	Choose the correct choice from the following answers.
A) 2 hours and 36 minutes  B) 36/37 hours  C) 9 hours and 12 minutes  D) 15 hours  E) 1 hour and 48 minutes.

Solution: Pipe A has a rate of 60 liters per minute which equals a rate of 3600 liters per hour.   Pipe B has a rate of 100 liters per hour.   100 + 3600 (A+B) = Together they have a rate of 3700 liters per hour.   3600 (The pool) / 3700 = 36/37 hours   Answer -36/37 hours
Answer: B
At what rate percent per annum will the simple interest on a sum of money be 6/5 of the amount in 10 years?	Choose the correct choice from the following answers
A) 4%	B) 7%	C) 9%	D) 3%	E) 12%

Solution: Let sum = x. Then, S.I. = 6x/5, Time   = 10 years.   Rate = (100 * 6x) / (x * 5 * 10)   = 12%   Answer:12%
Answer: E
Angela, Bernie, and Colleen can complete a job, all working together, in 3 hours. Angela and Bernie, working together at their respective rates, can complete the same job in 5 hours. How long would it take Colleen, working alone, to complete the entire job?	Select.
A) 7.5 hours B) 10 hours C) 12 hours D) 16 hours E) 20 hours

Solution: A+B+C complete the job in 3 hours.   A+B complete the job in 5 hours.   A+B and C complete the job in 3 hours -->1/(A+B) + 1/C = 1/3-->1/5+1/C=1/3 ----> C=7.5 hours. 7.5 hoursNS 7.5 hours
Answer: A
HCF and LCM two numbers are 16 and 396 respectively. If one of the numbers is 36, then the other number is?	Choose the correct choice from the following options:
A) 36  B) 66  C) 132  D) 176  E) 364

Solution: 16 * 396 = 36 * x   x = 176   ANSWER:176
Answer: D
A man has Rs. 312 in the denominations of one-rupee notes, five-rupee notes and twenty-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?	Choose the correct choice from the following answers:	A) 36	B) 24	C) 28	D) 32	E) 38

Solution: Explanation :   Let the number of notes of each denomination be x   Then, x + 5x + 20x = 312   => 26x = 312   => x = 312/26= 
312/26 = 12
12   the total number of notes that he has= 3x = 3 × 12 = 36   36nswer : 36
Answer: A
If shares of two persons in profits are Rs.400 and Rs.500 then ratio of their capitals is	Choose one:
A) 3:4	B) 4:5	C) 4:3	D) 1:3	E) 1:2

Solution: profit=time*capital   so 400:500=4:5   ANSWER:4:5
Answer: B