MU-NLPC/Calc-aqua_rat huggingface dataset:
The ‘moving walkway’ is a 300-foot long walkway consisting of a conveyor belt that moves continuously at 3 feet per second. When Bill steps on the walkway, a group of people that are also on the walkway stands 120 feet in front of him. He walks toward the group at a rate of 3 feet per second. Once Bill reaches the group of people, he stops walking and stands with them until the walkway ends. What is Bill’s average rate W of movement for his trip along the moving walkway? Choose one.
A) 2 feet per second  B) 2.5 feet per second  C) 3 feet per second  D) 4 feet per second  E) 5 feet per second

Solution: A, B, and C don't make ANY sense! we know for some time...(a majority of the 300ft) Bill will walk at a pace of 6ft per second...and then at some later time he will stop and move at 3 ft per second... The average W MUST bebetween3-6 ft per second or the Earth is FLAT!!!.   So we are down to DE, D doesn't make sense on a weighted averages level because we know when Bill gets on the walkway the patrons are already 40% of the way down the 300ft walkway AND they are still moving at half the rate of Bill!! So for Bill to average 4 ft per second he would have had to spend a majority of the 300 ft at 3ft per second because 4 is much closer (when you factor in the size of the values we're dealing with 2 is double 1) to 3 than to 6. We know from the information that isn't possible. Billmust havespent the majority of his time at 6 ft per second before he stopped walking. That leaves only answer 5 feet per second as plausible.
Answer: E
If A = d% of y and B = y% of d, then which of the following is true? Select the correct option
A) 1) A is smaller than B. B) 2) A is greater than B C) 3) Relationship between A and B cannot be determined. D) 4) If x is smaller than y, then A is greater than B. E) 5) None of the above

Solution: Basically A = B = dy/100   None of the options mentions this; hence 5) None of the above.
Answer: E
A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 64 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ? Choose the correct choice from the following choices
A) 16% B) 32% C) 48% D) 82% E) 92%

Solution: This is easiest to solve with a bell-curve histogram. m here is equal to µ in the Gaussian normal distribution and thus m = 50% of the total population.   So, if 64% is one st.Dev, then on either side of m we have  64/2= 
 64/2 = 32
32%. So, 32% are to the right and left of m (= 50%). In other words, our value m + d = 50 + 32= 
50 + 32 = 82
82% goingfrom the mean m, to the right of the distributionin the bell shaped histogram.. This means that 82% of the values are below m + d.   Like I said, doing it on a bell-curve histogram is much easier to fullygethow this works, or you could apply GMAT percentile jargon/theory to it   82%
Answer: D
If |x + 10| = 10 what is the sum of all the values of x.
Pick one.
A) 20 B) 40 C) -20 D) 0 E) -40

Solution: There will be two cases   x+10= 
+10 = 10
10 and x+10= -10   Solve for x => x=10-10=> x=0 or x= -10 - 10 => x= -20   The sum of both values will be 0 + -20 =-20   Answer is -20
Answer: C
Machine A produces 100 parts twice as fast as Machine B does. Machine B produces 100 parts in 80 minutes. If each machine produces parts at a constant rate, how many parts does Machine A produce in 20 minutes?  Choose the correct choice.
A) 60  B) 80  C) 70  D) 40  E) 50

Solution: Machine B produces 100 part in 80 minutes. Machine A produces 100 parts twice as fast as B, so Machine A produces 100 parts in  80/2= 
 80/2 = 40
40 minutes.   Now, Machine A produces 100 parts in 40 minutes which is 100/40= 10/4 parts/minute.   10/4 parts X a total of 20 minutes = 10/4 * 20= 
10/4 * 20 = 50
50   50
Answer: E
How many positive integers Q less than 10,000 are such that the product of their digits is 210?
Select
A) 24 B) 30 C) 48 D) 54 E) 72

Solution: 210 is the answer when 2, 3, 5 and 7 are multiplied. 210 can also be arrive using 5,6 and 7 and 1, 5, 6 and 7.   So sum of arrangements of 2357, 567 and 1567. This translates to 4! +3! + 4!, this equals to  24 + 6 + 24= 
 24 + 6 + 24 = 54
54, 54 is the answer.
Answer: D
A 50 ml after-shave lotion at 30% alcohol is mixed with 30 ml of pure water. What is the percentage of alcohol in the new solution?	Choose the correct choice from the following options.
A) 16.75%
B) 17.75%
C) 18.75%
D) 19.75%
E) None of these

Solution: The amount of the final mixture is given by   50 ml + 30 ml = 80 ml   The amount of alcohol is equal to the amount of alcohol in pure water ( which is 0) plus the amount of alcohol in the 30% solution. Let x be the percentage of alcohol in the final solution. Hence   0 + 30% 50 ml = x (80)   Solve for x   x = 0.1817 = 18.75%   Answer 18.75%
Answer: C
We have 5 people and 3 chairs. In how many ways chairs can be occupy?  Select: A) 58 B) 42 C) 60 D) 72 E) 80

Solution: no. of ways they can be occupy = 5*4*3= 
5*4*3 = 60
60   Answer is 60
Answer: C
Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is equal to 760.  Choose the correct choice from the following answers:
A) 120 ,122 , 124 ,126
B) 120 ,122 , 124 ,128
C) 120 ,121 , 122 ,123
D) 123 ,125 , 127 ,129
E) None of these

Solution: Let x, x + 2, x + 4 and x + 6 be the four integers. The sum of the first two   x + (x + 2)   twice the sum of the last two is written as   2 ((x + 4) + (x + 6)) = 4 x + 20   sum of the first two added to twice the sum of the last two is equal to 760 is written as   x + (x + 2) + 4 x + 20 = 760   Solve for x and find all four numbers   x = 123 , x + 2 = 125 , x + 4 = 127 , x + 6 = 129   Answer 123 ,125 , 127 ,129
Answer: D
The value of a machine depreciates at 20% per annum. If its present value is Rs. 1,50,000, at what price should it be sold after two years such that a profit of Rs. 25,000 is made?	Pick one
A) Rs. 1,10,000 B) Rs. 1,20,000 C) Rs. 1,24,000 D) Rs. 1,21,000 E) None of these

Solution: The value of the machine after two years = 0.8 * 0.8 * 1,50,000 = Rs. 96,000   SP such that a profit of Rs. 25,000 is made = 96,000 + 25,000 = Rs. 1,21,000   ANSWER:Rs. 1,21,000
Answer: D
The difference between a two-digit number and the number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?  Choices
A) 3	B) 4	C) 9	D) 11	E) None of these

Solution: Answer: Option B   Let the ten's digit be x and unit's digit be y.   Then, (10x + y) - (10y + x) = 36   9(x - y) = 36   x - y = 4.
Answer: B
A factory has a fixed cost of $44,000 a month, and a cost of $2.5 for every item produced. If the selling price of a single item is $5, what is the number of items must be sold monthly for the factory to cover its cost exactly?
Choose the correct answer.
A) 9,000  B) 14,000  C) 17,600  D) 22,500  E) 27,000

Solution: selling price - 17,600ost price = 2.5 so per unit profit =2.5   cost to recover =44000   no of items required = 44000/2.5= 
44000/2.5 = 17_600
17600   Answer: 17,600
Answer: C
What is the twenty-fifth decimal to the right in the fraction 10/11?	Choose one.
A) 1	B) 3	C) 5	D) 7	E) 9

Solution: 10/11 = 0.9090909090...   The odd-numbered decimal places are 9.   The answer is 9.
Answer: E
Distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of the train during the whole journey? Choose the correct choice from the following options.
A) 67.0 km /hr
B) 67.2 km /hr
C) 69.0 km /hr
D) 69.2 km /hr
E) None

Solution: Solution   Required average speed	=(2xy / x+y)km/hr   = 2 x 84 x 56 /(84 + 56)   = (2 x 84 x 85 /140)   = 67.2 km/hr.   Answer 67.2 km /hr
Answer: B
If the numerator of a fraction be increased by 20% and its denominator be diminished by 10%, the value of the fraction is 20/21. Find the original fraction ?  Choose one.
A) 1/2  B) 3/5  C) 4/7  D) 5/7  E) 7/9

Solution: Let the original fraction be x/y   Then, 120% of x/90% of y = 20/21   120x/90y = 20/21   x/y = 5/7   Answer is 5/7
Answer: D
The average of runs of a cricket player of 10 innings was 42. How many runs must he make in his next innings so as to increase his average of runs by 4?
Choose the correct choice:
A) 87  B) 86  C) 28  D) 76  E) 80

Solution: Average after 11 innings = 46   Required number of runs   = (46* 11) - (42* 10) = 506 - 420= 
506 - 420 = 86
86.   Answer: 86
Answer: B
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either red or green?  Pick one
A) 53/105  B) 43/105  C) 42/105  D) 32/105  E) 46/105

Solution: given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are red = 4Câ‚‚/Â¹âµCâ‚‚ = (3 * 2)/(15 * 14) = 3/21   Probability that both are green = 6Câ‚‚/Â¹âµCâ‚‚ = (2 * 1)/(15 * 14) = 1/105   Probability that one red and other is green = (4Câ‚ * 6Câ‚)/Â¹âµCâ‚‚ = (2 * 3 * 2)/(15 * 14) = 27/105   Required probability = 3/21 + 1/105 + 27/105   = 43/105   Answer:43/105
Answer: B
The area of one square is x^2 + 12x + 36 and the area of another square is 4x^2 − 12x + 9. If the sum of the perimeters of both squares is 64, what is the value of x?	Select the correct option.
A) 0  B) 4.3  C) 2.5  D) 4.67  E) 10

Solution: spotting the pattern of equations both are in form of (X+C)^2 so   A1= (x+6)^2A2= (2x-3)^2   L1= x+6 L2= 2x-3   P1 = 4( x+6)P2=4(2x-3)   P1+P2=64   4( x+6) +4(2x-3)=64..............> X=4.3   Answer: 4.3
Answer: B
By how much is 70% of 120 greater than 35% of 200.  Choose the correct choice from the following answers: A) 15 B) 14 C) 13 D) 16 E) 17

Solution: (70/100) * 120 â€“ (35/100) * 200   84 - 70= 
84 - 70 = 14
14   Answer: 14
Answer: B
A vendor purchases binder clips at 12 for rs60.How many clips should he sell for rs60 to earn a profit of 20%?	Choose the correct choice from the following options.
A) 5
B) 8
C) 6
D) 10
E) 12

Solution: Profit of 20% means he should sell the 12 clips for 72 Rs   so for 60 Rs he should sell 10 clips   ANSWER:10
Answer: D
Before being simplified, the instructions for computing income tax in Country R were to add 2 percent of one's annual income to the average (arithmetic mean) of 100 units of Country R's currency and 1 percent of one's annual income. Which of the following represents the simplified formula for computing the income tax, in Country R's currency, for a person in that country whose annual income is X?  Choose the correct choice from the following options
A) 50X/200
B) 50+3X/100
C) 50+X/40
D) 100+X/50
E) 100+3X/100

Solution: 50+X/40=50+X/40
Answer: C
35 percent of the women in a college class are science majors, and the non-science majors make up 70% of the class. What percentage of the men are non-science majors if 40% of the class are men?	Choose the correct choice from the following answers:
A) 37.5
B) 27.5
C) 77.5
D) 87.5
E) 93.5

Solution: 3.5/k + 2/m = 6/t   Assuming total # is 100 :   [Science - Women] will have -> 0.35 * 60 = 21   [Non-Science-Women] will have -> 39   [Science-Men] will have = 30-21= 
30-21 = 9
9   [Non-Science-men] will have - 31   S0 31/40 * 100= 77.5%   Answer -77.5
Answer: C
During a particular equestrian competition, the rider and his horse have 5 fences to jump. If the rider falls off during a jump, the rider is disqualified. The probability of the rider falling off on a jump is 12/35. What is the least number of fences that the rider can jump before the probability of falling off at least once is more than 50%. Select:
A) 1
B) 5
C) 4
D) 2
E) 3

Solution: Rule of Subtraction: P(A) = 1 - P(A')   Rule of Multiplication: P(A ∩ B) = P(A) P(B)   The probability that the rider falls at least once in 2 jumps is 1- (23/35)^2 = 1 - 529/1,225 = 696/1,225 < 50%.   The probability that the rider falls at least once in 3 jumps is 1- (23/35)^3 = 1 - 12,167/42,875 = 30,708/42,875 > 50%.   Answer: 3
Answer: E
Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/5, 1/2 and 5/8, respectively, what is the probability that Xavier and Yvonne, but not Zelda, will solve the problem?	Options: A) 11/8 B) 3/80 C) 9/64 D) 5/64 E) 3/64

Solution: P(Xavier will solve)=1/5   P(Yvonne will solve)=1/2   P(Zelda will NOT solve) = 1- 5/8 = 3/8.   Now, we need to multiply all this Ps to find an answer:   p= (1/5)*(1/2)*(3/8) = 3/80.   Ans. 3/80.
Answer: B
A and B put in Rs.300 and Rs.400 respectively into a business. A reinvests into the business his share of the first year's profit of Rs.210 where as B does not. In what ratio should they divide the second year's profit? Select.
A) 39:40	B) 39:48	C) 39:43	D) 39:46	E) 39:42

Solution: 3: 4   39:40 = 3/7*210= 
3/7*210 = 90
90   390: 400   39:40   39:40nswer: 39:40
Answer: A
In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 40, the dividend is:	Pick:
A) A)5322
B) B)5330
C) C)4040
D) D)5340
E) E)5342

Solution: Divisor = (5 * 40)= 
(5 * 40) = 200
200= 10 * Quotient = Divisor   => Quotient = 200/10= 
200/10 = 20
20   Dividend= (Divisor * Quotient) + Remainder   Dividend = (200 * 20) + 40= 
(200 * 20) + 40 = 4_040
4040.   4040
Answer: C
How many of the positive factors of 36 , 84 and how many common factors are there in numbers? Choose the correct answer
A) 2
B) 4
C) 3
D) 5
E) 6

Solution: factors of 36 - 1, 2, 3, 4, 6, 9, 12, 18, 36   factors of 84 - 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84   Comparing both, we have six common factors of 36 and 84- 1,2,3,4,6,12,   Answer(6)
Answer: E
A train running at the speed of 60 km/hr crosses a pole in 12 sec. What is the length of the train?  Choose the correct choice from the following options.
A) 120 m B) 200 m C) 324 m D) Cannot be determined E) None of these

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 12= 
50/3 * 12 = 200
200 m   ANSWER:200 m
Answer: B
X and Y started a business with capitals Rs. 20000 and Rs. 25000. After few months Z joined them with a capital of Rs. 30000. If the share of Z in the annual profit of Rs. 50000 is Rs. 14000, then after how many months from the beginning did Z join?  Select
A) 1  B) 5  C) 6  D) 8  E) 9

Solution: Investments of X, Y and Z respectively are Rs. 20000, Rs. 25000 and Rs. 30000   Let investment period of Z be x months.   Ratio of annual investments of X, Y and Z is (20000 * 12) : (25000 * 12) : (30000 * x)   = 240 : 300 : 30x = 8 : 10 : x   The share of Z in the annual profit of Rs. 50000 is Rs. 14000.   => [x/ (18 + x)] 50000 = 14000 => [x/ (18 + x)] 25 = 7   => 25x = 7x + (18 * 7) => x = 7 months.   Z joined the business after (12 - 7) months. i.e., 5 months.Answer: 5
Answer: B
Which one of the following is not a prime number?	Pick one.
A) 88	B) 60	C) 73	D) 91	E) 82

Solution: D   91   91 is divisible by 7. So, it is not a prime number.
Answer: D
The average of non-zero number and its square is 5 times the number. The number is? Choose the correct choice from the following answers:
A) 9  B) 8  C) 6  D) 4  E) 3

Solution: Let the number be x. Then,   (x + x2)/2 = 5x => x2 - 9x = 0   => x(x - 9) = 0   => x = 0 or x = 9   So, the number is 9.   9nswer:9
Answer: A
Out of 7 constants and 4 vowels how many words of 3 consonants and 2 vowels can be formed?  Pick
A) 210 B) 25000 C) 25200 D) 250 E) 20000

Solution: Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)   = 7252003 * 4252002   = 210   Number of groups each having 3 consonants and 2 vowels = 210   Each group contains 5 letters   Number of ways of arranging 5 letters among themselves   = 5! = (5 * 4 * 3 * 2 * 1)   = 210   Required number of words = (210 * 210)   = 25200   ANSWER 25200 25200
Answer: C
Pradeep has to obtain 40% of the total marks to pass. He got 200 marks and failed by 20 marks. The maximum marks are	Choose the correct option
A) 300  B) 600  C) 550  D) 1000  E) 900

Solution: Explanation :   Let their maximum marks be x.   Then, 40% of x = 200 + 20   =>40/100x= 220   x = (22000/40)= 
(22000/40) = 550
550.   Answer : 550
Answer: C
A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long? Choose the correct answer.
A) 87 sec
B) 89 sec
C) 17 sec
D) 18 sec
E) 97 sec

Solution: Speed = 240/24= 
240/24 = 10
10 m/sec.   Required time= (240 + 650)/10= 
(240 + 650)/10 = 89
89 sec.   Answer:89 sec
Answer: B
Consider a right triangle YBC with length of sides being x,y and z where y represents the hypotenuse , Which of these represent the radius of the circle which is inscribed in triangle YBC	Choose the correct option:  A) [A] x+y+z/3  B) [B] x-y+z/3  C) [C] x-y+z/2  D) [D] (x^2 + y^2 + z^2)/3  E) [E] cannot be determined

Solution: Radius of a circle inscribed in the right triangle YBC r = (x + z - y)/2 where y is the hypotenuse and x and y are other two sides.   Answer: [C] x-y+z/2
Answer: C
Ram and Shyam have a cube each. Ram paints four faces of cube with red color and rest with blue color. Ram asks Shyam to paint his cube as well with some sides red and some side blue. They now start rolling the cubes simultaneously. After doing this for very long Ram observes that probability of both cubes coming up with same color is 1/3. How many faces of his cube did Shyam paint red ?  Choose one.
A) 0  B) 2  C) 3  D) 4  E) 5

Solution: Explanation :   Let Shyam paints n faces of the cube red. So faces painted blue = (6-n)   Probability that both show up same color is: (probability both show red) + (probability both show blue)   = 4/6 * n/6 + 2/6 * (6-n)/6   = (2n + 6)/18   But as given, (2n + 6)/18 = 1/3 => n = 0   So Shyam hasn't painted any of the face with red color.   0nswer : 0
Answer: A
CP of 2 buffaloes are $30,000. By selling 1 at a loss of 15% and other at a profit of 19%, he foundthat SP of both buffaloes is the same. Find the CP of each?
Select:
A) $9,500 B) $10,500 C) $11,500 D) $12,000 E) $12,500

Solution: Let the C.P of 1st buffalo = x   ∴C.P of 2nd buffalo = 30,000 - x   S.P of 1st buffalo = ( 100 - loss% )   ------------------- x C.P   100   S.P = 100 - 15x   -----------= 85x/ 100   100   S.P of 2nd buffalo = ( 100 - Profit%)   --------------------- x C.P   100   S.P = (100 + 19)(30,000- x) 119(30,000 -x)   -------------------- = ----------------   100 100   S.P of 1st buffalo = S.P of 2nd buffalo   85x/ 100 = 119 ( 30,000 - x)/ 100   ⇒ 85x = 119(30,000 - x)   ⇒ 85x = 3,570,000 - 119x   ⇒ 85x + 119 x = 3,570,000   ⇒ 204x = 3,570,000   ⇒ x = 3,570,000 / 204   ⇒ x = $17,500   C.P of 1st buffalo = $17,500   C.P of 2nd buffalo = 30,000 - 17,500 = $12,500   $12,500
Answer: E
A person goes to his office at 1/3rd of the speed at which he returns from his office. If the avg speed during the whole trip is 12m/h. what is the speedof the person while he was going to his office?	Choose the correct choice from the following choices
A) 8km/h  B) 9km/h  C) 10km/h  D) 11km/h  E) 13km/h

Solution: u = k , v= 3k   \inline \therefore \frac{2uv}{u+v}\: \: \Rightarrow \frac{2\times k\times 3k}{(k+3k)}=12   \inline \Rightarrow 1.5k = 12   \inline \Rightarrow k=8km/h   8km/h
Answer: A
An unbiased die is tossed.Find the probability of getting a multiple of 3.  Choose the correct choice from the following options: A) 1/3 B) 1/9 C) 1/2 D) 7/3 E) 1/0

Solution: Explanation:   Here S = {1,2,3,4,5,6}   Let E be the event of getting the multiple of 3   Then, E = {3,6}   P(E) = n(E)/n(S) = 2/6 = 1/3   1/3nswer: 1/3) 1/3
Answer: A
1234+123+12+X=1221.Find the value of X.  Answers:
A) 10	B) 148	C) 12	D) 13	E) 189

Solution: x=1234+123+12-1221= 
1234+123+12-1221 = 148
148   CORRECT ANSWER : 148
Answer: B
One of the below words are odd one out. can you identify it?
first second third forth fifth sixth seventh eighth nine ten eleven twelve thirteen fourteen fifteen sixteen
Choose the correct choice from the following answers
A) forth. It should be spelled as fourth	B) 4	C) 14	D) 15	E) 16

Solution: Correct Answer : A   forth. It should be spelled as fourth
Answer: A
Together, 15 type A machines and 7 type B machines can complete a certain job in 4 hours. Together 8 type B machines and 15 type C machines can complete the same job in 11 hours. How many hours T would it take one type A machine, one type B machine, and one type C machine working together to complete the job (assuming constant rates for each machine)?
Select.
A) 22 hours	B) 30 hours	C) 44 hours	D) 60 hours	E) It cannot be determined from the information above.

Solution: Say the rates of machines A, B and C are a, b, and c, respectively.   Together 15 type A machines and 7 type B machines can complete a certain job in 4 hours --> 15a + 7b = 1/4;   Together 8 type B machines and 15 type C machines can complete the same job in 11 hours --> 8b + 15c = 1/11.   Sum the above: 15a + 15b + 15c = 1/4 + 1/11 = 15/44 --> reduce by 15: a + b + c = 1/44 --> so, the combined rate of the three machines is 1/44 job/hour --> time is reciprocal of the rate, thus machines A, B and C can do the T job in 44 hours.   Answer: 44 hours.
Answer: C
The area of a square is equal to five times the area of a rectangle of dimensions 125 cm * 64 cm. What is the perimeter of the square?  Options
A) 287	B) 800	C) 277	D) 299	E) 211

Solution: Area of the square = s * s = 5(125 * 64)   => s = 25 * 8= 
25 * 8 = 200
200 cm   Perimeter of the square= 4 * 200= 
4 * 200 = 800
800 cm.   Answer:800
Answer: B
Three cars driven by Mike, Scott and Jenny start driving around a circular race course of length 540m from the same point simultaneously in the same direction at speeds of 9 m/s, 15 m/s and 27 m/s respectively. When will they meet for the first time after they started moving? Pick:
A) 180 seconds B) 45 seconds C) 90 seconds D) 60 seconds E) 270 seconds

Solution: If they all meet after T seconds, it means they covered the distances 9T, 15T, and 27T respectively.   Since they all arrive to the same spot, it means that the differences taken pairwise between the distances must be positive integer multiples of the length of the track, which is 540m. So, 6T, 12T, and 18T must all be multiples of 540. 6T multiple of 540 means T multiple of 90. The smallest T with this property is 90 and is on the list of answers.   Answer 90 seconds.
Answer: C
If the volume of the cube is 729, then the surface area of the cube will be Select
A) 486 B) 255 C) 2866 D) 265 E) 872

Solution: Explanation:   \inline \fn_jvn a^3=729; a=9   surface area= (6 x 9 x 9) = 486\inline \fn_jvn cm^2   486nswer: 486) 486 sq.cm
Answer: A
Ravi can do a piece of work in 24 days while Prakash can do it in 40 days. In how many days will they finish it together?
Pick.
A) 15  B) 16  C) 17  D) 18  E) 10

Solution: 1/24 + 1/40 = 1/15   15 days   15nswer: 15
Answer: A
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 2.5 kmph, find his average speed for the total journey ?	Choose the correct option:	A) 3.1 kmph	B) 5 kmph	C) 6 kmph	D) 4 kmph	E) 7 kmph

Solution: Explanation:   Speed of Man = 4.5 kmph   Speed of stream = 2.5 kmph   Speed in DownStream = 7 kmph   Speed in UpStream = 2 kmph   Average Speed = (2 x 7 x 2)/9 = 3.1 kmph.   3.1 kmphnswer: 3.1 kmph
Answer: A
The sum of two numbers is 16 and their difference is 4. Find their product.	Choose the correct choice from the following:
A) 104	B) 114	C) 315	D) 325	E) 60

Solution: Let the numbers be x and y.   Then x + y = 16 and x - y = 4   x = 10; y = 6   xy = 10 * 6= 
10 * 6 = 60
60   ANSW60R: 60
Answer: E
A driver covers a certain distance by car driving at 40 km/hr and returns back to the starting point riding on a scooter at 10 km/hr. What was the average speed for the whole journey? Choose the correct choice from the following answers.
A) 12 km/h  B) 14 km/h  C) 16 km/h  D) 18 km/h  E) 20 km/h

Solution: time 1 = d / 40   time 2 = d / 10   total time = d/40 + d/10 = d/8   average speed = total distance / total time = 2d / (d/8) = 16 km/h   The answer is 16 km/h.
Answer: C