MU-NLPC/Calc-aqua_rat huggingface dataset:
The Coen family consists of a father, a mother, two children and a dog. A photographer is about to take the family's picture. How many different arrangements (of standing in a row) does the photographer have, if it is known that the father insists of standing by his dog?  Select the correct option.
A) 12
B) 24
C) 30
D) 48
E) 120

Solution: We need to find the number of arrangements of Father, Mother, Child-1, Child-2, and a Dog, so that F and M are always together.   Consider F and D to be one unit, then we would have total of four units: {FD}, {C1}, {C2}, {M}. The number of arrangements of these four units is 4!, but F and D within their unit can be arranged in 2 ways: {FD} or {DF}, so total number of arrangements is 4!*2=48.   Answer: 48.
Answer: D
If x persons take y days to complete z similar jobs, how long does it take y persons to complete 1 such job?	Select the correct option:
A) z B) x C) x/y D) z/x E) x/z

Solution: X people * Y days ----> produce Z jobs ----- (1)   Now,   Y people * X days -----> must produce Z jobs ----- (2)   >>>> Hence, to produce 1 job, divide above equation (2) by Z.   Y people *(X/Z) days -----> 1 job   The answer should be X/Z.   ANSWx/zR:x/z
Answer: E
A man can row with a speed of 10 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is? Options.
A) 33
B) 15
C) 20
D) 99
E) 71

Solution: M = 10   S = 5   DS = 10 + 5= 
10 + 5 = 15
15   Answer: 15
Answer: B
Each year for 4 years, a farmer increased the number of trees in a certain orchard by 1/4 of the number of trees in the orchard of the preceding year. If all of the trees thrived and there were 12500 trees in the orchard at the end of 4 year period, how many trees were in the orchard at the beginning of the 4 year period.  Pick:
A) 5113
B) 5117
C) 5120
D) 8119
E) 10115

Solution: Trees increase by 1/4 the number of trees in preceding year. Hence, correct answer must be divisible by 4. Based on divisibility rules, if last 2 digits are divisible by 4 then the number is divisible by 4. Thus, we can eliminate A, B, D,E The answer to be C   Again, trees increase by 1/4 the number of trees in preceding year. Hence, the number of trees increase by 5/4 times the number of trees the preceding year.   If x = initial number of trees = 5120   Year 1 = 5/4x   Year 2 = (5/4)(5/4)x   Year 3 = (5/4)(5/4)(5/4)x   Year 4 = (5/4)(5/4)(5/4)(5/4)x   Only for Answer D: (5/4)(5/4)(5/4)(5/4) 5120 = 12500   Hence, correct answer = 5120
Answer: C
A father's age was 5 times his son's age 5 years ago and will be 3 times son's age after 2 years, the ratio of their present ages is equal to: Select the correct option.
A) 10/9 B) 10/8 C) 10/3 D) 10/6 E) 10/2

Solution: Explanation:   Let the Father's age = x, and Son's = y   x - 5 = 5(y – 5)   x + 2 = 3(y + 2)   Solving we get x/y = 10/3   Answer: 10/3
Answer: C
A bank offers 10% interest rate compounded annually. A person deposits Rs. 20,000 every year in his account. If he does not withdraw any amount, then how much balance will his account show after four years?
Pick:	A) Rs. 102102	B) Rs. 102220	C) Rs. 104202	D) Rs. 104222	E) Rs. 104233

Solution: Explanation:   Rs.20000 after 4 years = 20000(1+10/100)4 = 20000(11/10)4 = Rs. 29282   Rs.20000 after 3 years = 20000(1+10/100)3 = 20000(11/10)3 = Rs. 26620   Rs.20000 after 2 years = 20000(1+10/100)2 = 20000(11/10)2 = Rs. 24200   Rs.20000 after 1 year = 20000(1+10/100)1 = 20000(11/10) = Rs. 22000   Total amount after 4 years = 29282 + 26620 + 24200 + 22000 = Rs. 102102   Rs. 102102nswer: Option Rs. 102102
Answer: A
In a class of 140 students, 60% of them passed. By what percent is the number of students who passed more than the number of failed students? Choose the correct choice from the following answers
A) 90% B) 58% C) 59% D) 50% E) 53%

Solution: Number of students passed   = 60% of 140 = 60/100 * 140= 
60/100 * 140 = 84
84   Number of students failed= 140 - 84= 
140 - 84 = 56
56.   Required percentage= 28/56 * 100= 
28/56 * 100 = 50
50%.   Answer:50%
Answer: D
A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability W that all 3 jellybeans removed from the bag are blue?	Choose the correct choice:	A) 9/100	B) 2/19	C) 1/8	D) 3/20	E) 3/10

Solution: Method-1   10 red jellybeans and 10 blue jellybeans   Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140   Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all 2/19lue out of 10 2/19lue = 10C3 = 120   Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3   Probability W= 120 / 1140 = 2/19   Answer: option 2/19   Method-2   Probability of First jelly bean to be 2/19lue = 10/20 [Total 10 2/19lue out of total 20 jellybeans]   Probability of Second jelly bean to be 2/19lue = 9/19 [Total 9 2/19lue remaining out of total 19 jellybeans remaining]   Probability of Third jelly bean to be 2/19lue = 8/18 [Total 8 2/19lue remaining out of total 18 jellybeans remaining]   Required Probability = (10/20)*(9/19)*(8/18) = 2/19   Answer: option 2/19
Answer: B
Tap 'A' can fill the tank completely in 6 hrs while tap 'B' can empty it by 12 hrs. By mistake, the person forgot to close the tap 'B', As a result, both the taps, remained open. After 2 hrs, the person realized the mistake and immediately closed the tap 'B'. In how much time now onwards, would the tank be full?	Choose the correct answer.
A) 2 hours	B) 4 hours	C) 5 hours	D) 1 hour	E) None of these

Solution: Explanation :   Tap A can fill the tank completely in 6 hours   => In 1 hour, Tap A can fill 1⁄6 of the tank   Tap B can empty the tank completely in 12 hours   => In 1 hour, Tap B can empty 1⁄12 of the tank   i.e., In one hour, Tank A and B together can effectively fill 1⁄6 - 1⁄12 = 1⁄12 of the tank   => In 2 hours, Tank A and B can effectively fill 1⁄12 × 2= 1⁄6 of the tank.   Time taken to fill the remaining 1−(1/6) = 5/6 of the tank = (5/6)/(1/6)= 
(5/6)/(1/6) = 5
5 hours. Answer : Option 5 hours
Answer: C
A pipe can empty 1/4th of a cistern in 12mins. In 8 mins, what part of the cistern will be empty?
Answers
A) 2/3
B) 3/7
C) 4/9
D) 1/6
E) 4/7

Solution: 1/4 ---- 12   ? ----- 8 ==> 1/6   1/6
Answer: D
A shopkeeper sells his goods at cost price but uses a faulty meter that weighs 700 grams. Find the profit percent.	Select the correct option:
A) 100/7%
B) 100/23%
C) 100/19%
D) 100/13%
E) None of these

Solution: Explanation:   (100 + g) / (100 + x) = True measure / Faulty measure   x = 0   true measure = 1000   faulty measure = 700   100 + g / 100 + 0 = 1000 / 700   100+g = 10/7*100   g = 300/7 %   100/7%NSWER: 100/7%
Answer: A
An aeroplane travels distance 2500 km, 1200 km, and 500 km, at the rate of 500 km/h, 400 km/h and 250 km/h respectively. The average speed of the plane is :
Choices:
A) 420 km/h B) 410 km/h C) 430 km/h D) 415 km/h E) 440 km/h

Solution: time=distance/speed   time=2500/500+1200/400+500/250   5+3+2= 
5+3+2 = 10
10 hrs   speed=total distance/time   (2500+1200+500)/10   4200/10= 
4200/10 = 420
420 km/h   420 km/hNSWER:420 km/h
Answer: A
If (2^32 + 1) is completely divisible by a whole number, which of the following numbers is completely divisible by this number?  Pick one
A) (2^96+1) B) (7 × 223 ) C) (2^16 - 1) D) (2^15 + 1) E) (2^17 + 1)

Solution: Explanation:   Let   2   32   =   x   232=x.   Then   (   2   32   +   1   )   =   (   x   +   1   )   (232+1)=(x+1)   (2^96+1)ssume that   (   x   +   1   )   (x+1) is completely divisible by a whole number, N   (   2   96   +   1   )   =   (   2   32   )   3   +   1   =   (   x   3   +   1   )   =   (   x   +   1   )   (   x   2   −   x   +   1   )   (296+1)=(232)3+1=(x3+1)=(x+1)(x2−x+1)   if   (   x   +   1   )   (x+1) is completely divisible by N,   (   x   +   1   )   (   x   2   −   x   +   1   )   (x+1)(x2−x+1) will also be divisible by N   Hence   (   2   96   +   1   )   (2^96+1) is completely divisible N   (2^96+1))
Answer: A
96 is divided into two parts in such a way that seventh part of first and ninth part of second are equal. Find the smallest part? Options:  A) 38  B) 40  C) 42  D) 44  E) 45

Solution: Explanation:   x/7 = y/9 => x:y = 7:9   7/16 * 96= 
7/16 * 96 = 42
42   42
Answer: C
Find large number from below question The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 10 as remainder
Choose the correct choice:
A) 1636  B) 1346  C) 1378  D) 1635  E) 1489

Solution: Let the smaller number be x. Then larger number = (x + 1365).   x + 1365 = 6x + 10   5x = 1355   x = 271   Large number = 271+1365= 
271+1365 = 1_636
1636   1636
Answer: A
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 52 years now, the son's age five years back was: Choose the correct choice from the following
A) A)14	B) B)67	C) C)56	D) D)21	E) E)34

Solution: Let the son's present age be x years. Then, (52 - x) = x   2x = 52.   x = 26.   Son's age 5 years back (26 - 5)= 
(26 - 5) = 21
21 years.   Answer:21
Answer: D
A group of 8 friends want to play doubles tennis. How many different ways can the group be divided into 4 teams of 2 people?	Select the correct option:
A) 420 B) 2520 C) 168 D) 90 E) 105

Solution: C28∗C26∗C24∗C22/4!=105 , we are dividing by 4! (factorial of the # of teams) as the order of the teams does not matter. If 8 people are - 1, 2, 3, 4, 5, 6, 7, 8, then (1,2)(3,4)(5,6)(7,8) would be the same 4 teams as (5,6)(7,8)(1,2)(3,4), as we don't have team #1, team #2, ...   You can think about this in another way.   For the first person we can pick a pair in 7 ways;   For the second one in 5 ways (as two are already chosen);   For the third one in 3 ways (as 4 people are already chosen);   For the fourth one there is only one left.   So we have   7*5*3*1= 
  7*5*3*1 = 105
105   ANSW105R:105
Answer: E
Mandrake has to choose from 4 from 22 people. There are 3 girls, 5 boys , 14 children. What is total probability that he will choose 1G , 2B , 1C? Choose the correct choice from the following answers.
A) 1/7
B) 2/7
C) 3/61
D) 4/7
E) 5/7

Solution: (33/611 * 53/612 * 143/611)/ 223/614 = 3*10*14/7315= 360/7315=3/61   ANSWER:3/61
Answer: C
If nn is a positive integer and (n+1)(n+3)(n+1)(n+3) is odd, then (n+2)(n+4)(n+2)(n+4) must be a multiple of which one of the following?  Choose the correct choice from the following choices.
A) 2	B) 4	C) 6	D) 8	E) 9

Solution: (n+1)(n+3)(n+1)(n+3) is odd only when both (n+1)(n+1) and (n+3)(n+3) are odd. This is possible only when nn is even.   Hence, n=2mn=2m, where mm is a positive integer. Then,   (n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)(n+2)(n+4)=(2m+2)(2m+4)=2(m+1)2(m+2)=4(m+1)(m+2)   =4 * (product of two consecutive positive integers, one which must be even)=4 * (product of two consecutive positive integers, one which must be even) =4 * (an even number), and this equals a number that is at least a multiple of 8=4 * (an even number), and this equals a number that is at least a multiple of 8   Hence, the answer is (8).
Answer: D
A 180 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train? Choose the correct choice from the following answers
A) 320 meter	B) 225 meter	C) 230 meter	D) 235 meter	E) None of these

Solution: Explanation:   320 meters trains are running in opposite directions so their relative speed will get added   So, Relative speed = 120 +80= 
120 +80 = 200
200 kmph= 200*(5/18) = 500/9 m/sec   Let the length of other train is x meter then   x+180 /9=500 /9   =>x+180=500   =>x=320   So the length of the train is 320 meters   Option 320 meter
Answer: A
A retailer bought a machine at a wholesale price of $90 and later on sold it after a 10% discount of the retail price. If the retailer made a profit equivalent to 20% of the whole price, what is the retail price e of the machine? Select.
A) 81 B) 100 C) 120 D) 135 E) 160

Solution: Since the wholesale price was $90 and the profit was 20% of the wholesale price ([.2][90] = $18), the retail price would have to be above $108, but not that much greater than that.   Let's start by TESTing Answer C: $120....   If.....   Retail Price e= $120   10% discount off = $120 - (.1)(120) = 120 - 12= 
120 - 12 = 108
108   20% profit on wholesale price= 90 + (.2)(90) = 90 + 18= 
90 + 18 = 108
108   These two numbers MAT120H, so this MUST be the answer!   Final Answer:   [Reveal]Spoiler:   120
Answer: C
A fort of 2000 soldiers has provisions for 50 days. After 10 days some of them left and the food was now enough for the same period of 50 days as before. How many of them left?
Choose the correct option.
A) 400 B) 991 C) 881 D) 771 E) 551

Solution: 2000 ---- 50   2000 ---- 40   x ----- 50   x*50 = 2000*40   x=1600   2000   -------   400   400nswer: 400
Answer: A
6/7 of a certain number is 96. Find quarter of that number.
Choices:
A) 28  B) 29  C) 26  D) 281  E) 17

Solution: Explanation:   6/7x = 96   x = 112   y = x/4 = 112/4= 
112/4 = 28
28   28NSWER:28
Answer: A
If Rs.3250 be divided among Ram, Shyam and Mohan in the ratio of 1/2:1/3:1/4 then the share of each are? Choose the correct choice from the following options: A) Ram = Rs.1500, Shyam = Rs.1000, Mohan = Rs.750 B) Ram = Rs.2500, Shyam = Rs.500, Mohan = Rs.250 C) Ram = Rs.1200, Shyam = Rs.1300, Mohan = Rs.750 D) Ram = Rs.1600, Shyam = Rs.1350, Mohan = Rs.760 E) None

Solution: Explanation:   1/2:1/3:1/4 = 6:4:3   Ram = 6/13 * 3250= 
6/13 * 3250 = 1_500
1500   Shyam= 4/13 * 3250= 
4/13 * 3250 = 1_000
1000   Mohan= 3/13 * 3250= 
3/13 * 3250 = 750
750   Ram= Rs.1500, Shyam = Rs.1000, Mohan = Rs.750NSWER IS Ram = Rs.1500, Shyam = Rs.1000, Mohan = Rs.750
Answer: A
Find the volume & curved surface area of a cylinder with diameter of base 14 cm and height 60 cm.  Select the correct option:
A) 260 cm2  B) 2610 cm2  C) 2600 cm2  D) 2640 cm2  E) 264 cm2

Solution: Volume = pieR2H= pie x 72 x 60 = 9240	cm3   Curved surface area = 2pieRH = (2 x3.14 x 7 x 60) cm2 =2640 cm2   answer:2640 cm2
Answer: D
Today is Monday. After 61 days, it will be:	Choose the correct choice.
A) Monday B) Tuesday C) Friday D) Sunday E) saturday

Solution: Each day of the week is repeated after 7 days.   So, after 63 days, it will be Monday.   After 61 days, it will be Saturday.   Answer: Option saturday
Answer: E
A circular mat with diameter 28 inches is placed on a square tabletop, each of whose sides is 36 inches long. Which of the following is closest to the fraction of the tabletop covered by the mat?
Choose the correct choice from the following:
A) 2/2  B) 1/2  C) 3/2  D) 3/5  E) 6/5

Solution: SO we are looking for the area of the cloth over the area of the table   Area of the Cloth = (pi)(r)^2 which is about (22/7)(14)(14)   Area of the Table = (36)(36)   So the quick way to estimate is looking at the fraction like this:616/1296=308/648=154/324=77/162 nearest to 1/2   Answer: 1/2
Answer: B
A reduction of 40% in the price of bananas would enable a man to obtain 64 more for Rs.40. What is the reduced price/dozen?
Choices
A) 3
B) 4
C) 5
D) 7
E) 8

Solution: Sol. lie purchases 6a bananas mere for 4096 of Rs 40 or, Rs 16. Reduced price per do,. 3   3
Answer: A
Can you find out what day of the week was January 12, 1979? Choose the correct choice from the following options:
A) Friday. B) saturday C) sunday D) monday E) wednesday

Solution: 1979 = 1900yrs + 78yrs + (period from 1st Jan to 12th Jan 1979)   1900 yrs have 1 odd day(calculated as 1600yrs have 0 odd days, n 300yrs have 15 odd days i.e.15/7= 2 weeks+1 odd day.so,for 300yrs, it's 1 odd day.totally it's  0+1= 
 0+1 = 1
1odd day for 1900yrs).   78yrs= 19leap yrs +59 ordinary yrs   = 19 *2 +59 *1= 
19 *2 +59 *1 = 97
97days= 13weeks +6= 
+6 = 6
6 odd days   period from 1st Jan to 12th Jan 1979=12 days = 1week   + 5= 
  + 5 = 5
5 odd days   Therefore,   12th Jan 1979= 1+6+5= 
1+6+5 = 12
12days=1 week +5= 
+5 = 5
5 odd days   Therefore, 12th Jan 1979 was a Friday.   (Since,Sunday->0,Monday->1,...,Fri->5,sat->6)   Friday.NSWER:Friday.
Answer: A
If f(x) = x^4 – x^2 + ax^6 – 3, then f(b) – f(-b) will equal:
Choose the correct choice from the following choices.
A) 0	B) 2ab	C) 2ab^4	D) 8b^6 + 6	E) – 2b^2

Solution: f(x)=x^4 – x^2 + ax^6 – 3   f(b) = b^4 – b^2 + ab^6 – 3   f(-b) = b^4 – b^2 + ab^6 – 3   f(b) - f(-b) = b^4 – b^2 + ab^6 – 3 - b^4 + b^2 - ab^6 + 3   =0   0nswer 0
Answer: A
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.4 km respectively. The time taken by the slower train to cross the faster train in seconds is? Choose the correct option.
A) 48
B) 36
C) 7
D) 67
E) 15

Solution: :   Relative speed = 60 + 90= 
60 + 90 = 150
150 km/hr.= 150 * 5/18 = 125/3 m/sec.   Distance covered = 1.10 + 0.4= 
1.10 + 0.4 = 1.5
1.5 km= 1500 m.   Required time = 1500 * 3/125= 
1500 * 3/125 = 36
36 sec.   Answer: 36
Answer: B
Sunil deposited $6,000 to open a new savings account that earned 4 percent annual interest, compounded semi-annually. If there were no other transactions in the account, what the amount of money in Sunil account one year after the account was opened? Choose the correct choice from the following choices:
A) $6,200  B) $6,255  C) $6,200  D) $6,205  E) $6,244

Solution: Approach #1:   4 percent annual interest compounded semi-annually --> 2% in 6 moths.   For the first 6 moths interest was 2% of $6,000, so $120;   For the next 6 moths interest was 2% of $6,000,plus2% earned on previous interest of $120, so $120+$4=$124;   Total interest for one year was $120+$124  120+ 4= 
  120+ 4 = 124
$124;   Total interest for one year was $120+$124=$244, hence balance after one year was $6,000+ $244 120+ 124= 
 120+ 124 = 244
$244, hence balance after one year was $6,000+ $244=$6,244.   Answer: $6,244.
Answer: E
The true discount on a bill of Rs.1080 is Rs.180.The banker's discount is Answers:  A) 210  B) 212  C) 214  D) 216  E) None of these

Solution: Solution   P.W	= Rs.(1080 - 180)   = Rs. 900   S.I on Rs. 1080	=Rs.(180/900 x 1080)   = Rs. 216.   Answer 216
Answer: D
If 20 men can build a wall 66 metres long in 6 days, what length of a similar can be built by 86 men in 8 days?	Choose the correct choice from the following answers:
A) 53 m	B) 46 m	C) 94 m	D) 49 m	E) 64 m

Solution: Let the required length be x metres   More men, More length built (Direct Proportion)   Less days, Less length built (Direct Proportion)   Men 20: 35   Days 6: 3 : : 56 : x   Therefore (20 x 6 x x)=(35 x 3 x 56)x=(35 x 3 x 56)/120=49   Hence, the required length is 49 m.   Answer is 49 m
Answer: D
A man can row a boat at 30 kmph in still water. If the speed of the stream is 6 kmph, what is the time taken to row a distance of 60 km downstream?	Answers:	A) 30/18	B) 30/29	C) 30/12	D) 30/13	E) 30/82

Solution: Speed downstream = 30 + 6 = 26 kmph.   Time required to cover 60 km downstream = d/s = 60/36   = 30/18 hours.   30/18nswer:30/18
Answer: A
In what time will a train 100 m long cross an electric pole, it its speed be 136 km/hr? Choose one
A) 2.6 sec  B) 1.9 sec  C) 8.9 sec  D) 6.9 sec  E) 2.9 sec

Solution: Speed = 136 * 5/18   = 37.8 m/sec   Time taken = 100/37.8   = 2.6 sec.   2.6 secnswer: 2.6 sec
Answer: A
the government was giving out 10500 after 6 years of living in the United States and 15500 after 12 years of living in the United Sates. how much is the interest per year. Choose the correct answer.
A) 12%  B) 20%  C) 15%  D) 10%  E) 5%

Solution: for 6 years = (15500 - 10500)= 
(15500 - 10500) = 5_000
5000.   for 12 years= (5000x6)/6= 5000   Principal = (10500 - 5000)= 
(10500 - 5000) = 5_500
5500.   Hence, rate= (100 x 5000)/(5500x6)	% = 15% ANSWER :15%
Answer: C
The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 70% of the required amount. What is the net difference in the expenditure on that product?
Select the correct option.
A) 12.5%  B) 13%  C) 13.5%  D) 14%  E) 15%

Solution: Quantity X Rate = Price   1 x 1 = 1   0.7 x 1.25 = 0.875   Decrease in price = (0.125/1) × 100 = 12.5%   12.5%)
Answer: A
Ryan likes to collect sports cards for his favourite player. He has 32 cards for baseball players, 25 cards for football player and 47 for basketball players. What is the percentage of the number of cards for each sport in his collection?  Pick
A) 30.8%, 24%, 45.2% B) 30.7%, 25%, 45.2% C) 30.8%, 23%, 45.2% D) 30.8%, 22%, 45.2% E) None of these

Solution: Solution:   The total number of cards = 32 + 25 + 47= 
32 + 25 + 47 = 104
104   Baseball cards are 32/104 x 100= 30.8%   Football cards are 25/104 x 100 = 24%   Basketball cards are 47/104 x 100 = 45.2%   30.8%, 24%, 45.2%nswer 30.8%, 24%, 45.2%
Answer: A
In a car wheel, three spokes cover 20 degree. Then for the entire car,how many spokes are there?	Choose the correct choice from the following options.
A) 92  B) 128  C) 192  D) 216  E) 232

Solution: given, 3 spokes cover 20degrees,   so for 360 degrees.---->360*3/20=54..   so, for entire car, 4*54=216   ANSWER:216
Answer: D
A man buys Rs. 50 shares in a company which pays 10% dividend.If the man gets 12.5% on his investment,at what price did he buy the shares ? Options:
A) Rs. 37.50	B) Rs. 40	C) Rs. 48	D) Rs. 52	E) None

Solution: Solution   Dividend on 1 share = Rs. (10/100x50)=Rs.5   Rs. 12.50 is an income on an investment of Rs.100.   Rs. 5 is an income on an investment of Rs.(100x2/25x5)= Rs.40   ∴ Cost of 1 share = Rs. 40.   Answer Rs. 40
Answer: B
If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), what is the smallest possible positive value of n?
.
Choose the correct choice:  A) 25  B) 27  C) 45  D) 75  E) 125

Solution: If both 5^2 & 3^3 are factors, then they must be present in the number.   Leaving rest of the prime factors and splitting 6^2 into 3^2 * 2^3.   The number is lacking 5^2 & a 3, so that 5^2 and 3^3 is a factor.   Hence the smallest number is 5^2 * 3 = 75   ANSWER:75
Answer: D
How long will a boy take to run round a square field of side 35 metres. If he runs at the rate of 9km/hr ?	Choose the correct choice from the following options:
A) 56 sec  B) 1minute  C) 45sec  D) 58sec  E) 50sec

Solution: Speed = 9 km/hr = 9*5/18 = 5/2 m/sec   distance = 35*4= 
35*4 = 140
140 m   time taken= 140*2/5= 
140*2/5 = 56
56 sec.   56 secnswer is 56 sec
Answer: A
A class contains five juniors and five seniors. If one member of the class is assigned at random to present a paper on a certain subject, and another member of the class is randomly assigned to assist him, what is the probability R that both will be juniors? Choose the correct option:
A) 1/10 B) 1/5 C) 2/9 D) 2/5 E) 1/2

Solution: I think you're right. The other way to do it (but the long way) is to figure out the probability that it is not two Juniors.   2 seniors = P(Senior) * P(Senior) = 2/9   1 Senior and 1 Junior = (1/2) *(5/9)*2 = 5/9   Probability that it is not two Juniors is 5/9+2/9 = 7/9 so the probability R that it is two juniors is 1- (7/9) = 2/9.2/9
Answer: C
Two cyclist start on a circular track from a given point but in opposite direction with speeds of 7m/s and 8m/s. If the circumference of the circle is 600meters, after what time will they meet at the starting point?	Answers
A) 20sec  B) 15sec  C) 30sec  D) 50sec  E) 40min

Solution: They meet every 600/7+8 = 40sec   Answer is 40min
Answer: E
The average of 5 quantities is 9. The average of 3 of them is 4. What is the average of remaining 2 numbers? Select: A) 16.5 B) 10 C) 8 D) 9.5 E) None of these

Solution: 16.5NSWER: 16.5   (5x9-3x4)/2=16.5
Answer: A
Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178?	Choose the correct answer.
A) 2228 B) 2771 C) 2200 D) 2877 E) 1112

Solution: Explanation:   Let the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.   => (90%) of (110%) of x = Rs. 2178.   => (90/100)(110/100)x = 2178   => x = (2178 * 100)/(9 * 11)   => x = Rs. 2200   Answer:2200
Answer: C
The number 0.8 is how much greater than 1/8 ? Choose the most appropriate option:
A) ½ B) 27/40 C) 1/50 D) 1/500 E) 2/500

Solution: let x be the difference   then   .8-1/8=x   8/10-1/8=x   x=27/40   ans 27/40
Answer: B