MU-NLPC/Calc-aqua_rat huggingface dataset:
John professes to sell his goods at the cost price but he made use of 800 grams instead of a kg, what is the gain percent? Choose the correct choice from the following:
A) 12 1/3%  B) 12 1/4%  C) 12 2/3%  D) 12 2/1%  E) 12 1/2%

Solution: 800 --- 100   100 --- ? => 12 1/2%   Answer:12 1/2%
Answer: E
If a card is drawn from a well shuffled pack of cards, the probability of drawing a spade or a king is?
Pick one:  A) 4/16  B) 4/19  C) 4/12  D) 4/13  E) 4/11

Solution: P(SᴜK) = P(S) + P(K) - P(S∩K), where S denotes spade and K denotes king.   P(SᴜK) = 13/52 + 4/52 - 1/52 = 4/13   Answer:4/13
Answer: D
A rope of which a calf is tied is increased from 12 m to 23 m, how much additional grassy ground shall it graze?
Choose the correct option: A) 1298 B) 1228 C) 1210 D) 1782 E) 1762

Solution: π (232 – 122)   = 1210   Answer:1210
Answer: C
A cistern is filled by a tap in 3 1/2 hours. Due to leak in the bottom of the cistern, it takes half an hour longer to fill the cistern. If the cistern is full how long will it take the leak to empty it? Select.
A) 7 hours
B) 8 hours
C) 14 hours
D) 28 hours
E) 24 hours

Solution: 2/7 - 1/x = 1/4   x = 28   ANSWER:28 hours
Answer: D
Two cards are drawn at random from a pack of 52 cards.what is the probability that either both are black or both are queen
Choices.
A) 45/78 B) 15/48 C) 36/91 D) 451/75 E) 55/221

Solution: WE HAVE N(S)=52C2=(52*51)/(2*1)= 
(52*51)/(2*1) = 1_326
1326.   L55/221T A=55/221V55/221NT OF G55/221TTING BOTH BLACK CARDS   B=55/221V55/221NT OF G55/221TTING BOTH QU55/22155/221NS   A∩B=55/221V55/221NT OF G55/221TTING QU55/22155/221N OF BLACK CARDS   N(A)=26C2=(26*25)/(2*1)= 
(26*25)/(2*1) = 325
325,   N(B)=4C2=(4*3)/(2*1)= 
(4*3)/(2*1) = 6
6 AND   N(A∩B)=2C2=1   P(A)=N(A)/N(S)=325/1326;   P(B)=N(B)/N(S)=6/1326 AND   P(A∩B)=N(A∩B)/N(S)=1/1326   P(A∩B)=P(A)+P(B)-P(A∩B)=(325+6-1/1326)=330/1326=55/221   Ans: 55/221
Answer: E
Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old his son. Then the sum of the present ages of the son and the father is:
Select.
A) 54	B) 72	C) 105	D) 108	E) 51

Solution: Answer: Option D   Let the present ages of the father and son be 2x and x years respectively.   Then, (2x - 18) = 3(x - 18) => x = 36   Required sum = (2x + x) = 108 years.
Answer: D
The speed of a boat in still water in 42 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 44 minutes is:  Choices
A) 86.6 km
B) 46.6 km
C) 33.7 km
D) 35.6 km
E) 26.6 km

Solution: Speed downstream = (42 + 4)= 
(42 + 4) = 46
46 kmph   Time= 44 minutes =44/60 hour = 11/15 hour   Distance travelled = Time × speed =11/15×46 = 33.7 km   ANSWER:33.7 km
Answer: C
If the compound interest (compounded Yearly) on a certain sum for 2 years at 3% is Rs.101.50 then what will be the corresponding simple interest?  Select
A) Rs.98.25  B) Rs.101.00  C) Rs.90.00  D) Rs.95.50  E) Rs.75.50

Solution: simple interest=50+50   compound interest=50+(50+50*0.3)=101.50   ANSWER:Rs.101.00
Answer: B
It takes 60 identical printing machines 4 hours to print 200,000 cards. How long would it take 50 of these machines to print the same total? Pick:
A) 10 hr
B) 5 hr
C) 6 hr
D) 4 hr 30 min
E) 5 hr 12 min

Solution: 50% of 60 = 40% or 0.30   4 hr x 60 min = 240 min   240 min x 0.30 = 72 min or 1 hr and 12 min   1 hr and 12 min + 4 hr = 5 hr and 12 min   Answer is 5 hr 12 min
Answer: E
For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n, inclusive. If p is the smallest prime factor of h(100) +1, then p is?
Select the correct option.
A) Between 2 and 20
B) Between 10 and 20
C) Between 20 and 30
D) Between 30 and 40
E) Greater than 40

Solution: h(n) = the product of all even integers from 2 to n inclusive   => h(100) + 1 = (2 * 4 * 6 * 8 * ....... * 100) + 1   = 2^50 * (1*2*3*4*......*50) + 1   As all the numbers from 2 to 50 are factors of 2^50 * (1*2*3.....*50), none of these can be factors of 2^50 *   (1*2*3*4*......*50) + 1 (i.e. of h(100)+1)   Therefore the smallest prime factor of h(100) + 1 is greater than 50.   This corresponds to option (Greater than 40)
Answer: E
A train running at the speed of 70 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following answers
A) 298 m	B) 175 m	C) 208 m	D) 988 m	E) 299 m

Solution: Speed = 70 * 5/18 = 175/9 m/sec   Length of the train = speed * time = 175/9 * 9= 
175/9 * 9 = 175
175 m   Answer:175 m
Answer: B
The Carson family will purchase three used cars. There are two models of cars available, Model A and Model B, each of which is available in six colors: blue, black, red, and green. How many different combinations of three cars can the Carsons select if all the cars are to be different colors? Select
A) 24	B) 32	C) 48	D) 60	E) 192

Solution: I have no idea how you got 8C8, 7C6 and 4C1.   I could have understood 8C1*6C1*4C1 (I have explained why this doesn't work in the post above)   The best way to solve it is by first selecting 3 colors out of the given 4 in 4C3 ways. (say, you got black, red and green)   Now for each color, you have 2 choices - model A or B   So you select a model in 2 ways.   No of ways of selecting the 3 cars = 6C3 * 2 * 2 * 2 = 192   Well, my logic was   The number of ways of selecting r objects from n different objects is nCr.   We have 8 options and can select either of the 8 as the first - 8C8   One car is gone and one becomes a forbidden choice so we have 7 options and need to select either of the 6 as the first - 7C6   Two cars are gone and two becomes a forbidden choice so we have 6 options and need to select either of the 4 as the first - 6C4   192
Answer: E
A garrison of 1000 men has provisions for 60 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement?  Choose the correct option: A) 1000 B) 2250 C) 60 D) 45 E) 1250

Solution: 1000 ---- 60   1000 ---- 45   x ----- 20   x*20 = 1000*45   x = 2250   1000   -------   1250   Answer: 1250
Answer: E
Two trains of equal lengths take 10 sec and 8 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choices
A) 22  B) 12  C) 9  D) 99  E) 21

Solution: Speed of the first train = 120/10= 
120/10 = 12
12 m/sec.   Speed of the second train= 120/8= 
120/8 = 15
15 m/sec.   Relative speed= 12 + 15= 
12 + 15 = 27
27 m/sec.   Required time= (120 + 120)/27 = 9 sec.   Answer: 9
Answer: C
The average weight of 7 person's increases by 6.2 kg when a new person comes in place of one of them weighing 76 kg. What might be the weight of the new person?
Choose the correct choice from the following answers: A) 160 kg B) 175 kg C) 180.7 kg D) 119.4 kg E) 190.8 kg

Solution: Total weight increased = (7 x 6.2) kg = 43.4 kg.   Weight of new person = (76 + 43.4)= 
(76 + 43.4) = 119.4
119.4 kg   Option 119.4 kg
Answer: D
Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is? Choose the correct answer
A) 288
B) 277
C) 298
D) 125
E) 272

Solution: 3x * 2x = 3750 => x = 25   2(75 + 50) = 250 m   250 * 1/2 = Rs.125.Answer:298
Answer: C
A boatman can row 96 km downstream in 8 hr. If the speed of the current is 4 km/hr, then find in what time he will be able to cover 8 km upstream ?	Options
A) 1.5 hrs  B) 1 hrs  C) 2.5 hrs  D) 2 hrs  E) 3 hrs

Solution: Explanation:   Speed in downstream = 96/8= 
96/8 = 12
12 kmph   Speed of current= 4 km/hr   Speed of the boatman in still water = 12 â€“ 4 = 8 kmph   Speed in upstream = 8 â€“ 4 = 4 kmph   Time taken to cover 8 km upstream = 8/4= 
8/4 = 2
2 hours.   ANSWER IS 2 hrs
Answer: D
How many integer values T are there for x such that 1 < 3x + 5 < 17?  Choose one:
A) Two
B) Three
C) Four
D) Five
E) Six

Solution: 1 < 3x + 5 < 17   => -4 < 3x < 12   => -4/3 < x < 4   x can take integer values T -1,0 , 1 , 2 , 3   Answer Five
Answer: D
In a kilometer race, A beats B by 80 meters or 10 seconds. What time does A take to complete the race?
Choices
A) 199 sec B) 190 sec C) 726 sec D) 127 sec E) 115 sec

Solution: Time taken by B run 1000 meters   = (1000 * 10)/80= 
(1000 * 10)/80 = 125
125 sec.   Time taken by A= 125 - 10= 
125 - 10 = 115
115 sec.   Answer: 115 sec
Answer: E
What is the maximum number of pieces of birthday cake of size 5” by 5” that can be cut from a cake 15” by 15”?
Choose the correct choice from the following options.
A) 5	B) 10	C) 16	D) 20	E) 9

Solution: The prompt is essentially asking for the maximum number of 5 x 5 squares that can be cut from a larger 15 by 15 square. Since each 'row' and each 'column' of the larger square can be sub-divided into 3 'pieces' each, we have (3)(3) = 9 total smaller squares (at maximum).   9
Answer: E
The average of marks obtained by 120 boys was 36. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is?  Choose the correct choice from the following
A) 105 B) 110 C) 120 D) 130 E) 140

Solution: Let the number of boys who passed = X.   Then, 39 x X + 15 x (120 - X) = 120 x 36   24X = 4320 - 1800   => X = 2520/24= 
2520/24 = 105
105.   Hence, the number of boys passed= 105.   105NSWER:105
Answer: A
A bike covers a certain distance at the speed of 66km/h in 8 hrs. If the bike was to cover the same distance in approximately 6 hrs, at what approximate speed should the bike travel?
Choose the most appropriate option
A) 85 km/h B) 85.34 km/h C) 87.67 km/h D) 90.25 km/h E) 88 km/h

Solution: Ans.(E)   Sol. Total distance = 66 × 8 = 528 km   Now speed = 528/6= 
528/6 = 88
88 km/h
Answer: E
The distance light travels in one year is approximately 5,860,000,000,000 miles. The distance light travels in 100 years is
Choose the correct choice from the following options
A) A) 587 × 108 miles	B) B) 587 × 1010 miles	C) C) 587 × 10-10 miles	D) D) 586 × 1012 miles	E) E) 587 × 10-12 miles

Solution: The distance of the light travels in 100 years is:   5,860,000,000,000 × 100 miles.   = 586,000,000,000,000 miles.   = 586 × 1012 miles.   The answer is (586 × 1012 miles)
Answer: D
The difference between the simple interest received from two different sources on Rs.1900 for 3 years is Rs.13.50. The difference between their rates of interest is  Select
A) 0.13%
B) 0.23%
C) 0.33%
D) 0.43%
E) 0.53%

Solution: (1900xR1x3)/100-(100xR2x3)/100 =13.50   5700(R1-R2)=1350   R1-R2 = 1350/5700=0.23%   answer : 0.23%
Answer: B
In August,a cricket team that played 120 matches won 24% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?	Choose the correct choice from the following answers.
A) 40	B) 52	C) 68	D) 70	E) 98

Solution: let the no of matches played more=x   so,   (120+x)*52/100=28.8+x   by solving we get x=70   ANSWER:70
Answer: D
Three candidates contested an election and received 1136, 7636 and 12000 votes respectively. What percentage of the total votes did the winning candidate get?  Pick one.
A) 46%  B) 58%  C) 74%  D) 63%  E) 68%

Solution: 58%   12000/(1136 + 7636 + 12000) = 58%.
Answer: B
How many numbers from 29 to 79 are exactly divisible by 11?	Choose one
A) 4	B) 6	C) 8	D) 5	E) 7

Solution: Numbers=(79/11)-(29/11)   =7-2= 
7-2 = 5
5 numbers   Option 5 is answer
Answer: D
John bought 2 shares and sold them for $97 each. If he had a profit of 20% on the sale of one of the shares but a loss of 20% on the sale of the other share, then on the sale of both shares John had	Options.
A) a profit of $10 B) a profit of $8 C) a loss of $6 D) a loss of $10 E) neither a profit nor a loss

Solution: $ Profit of the share sold at 20% profit =   120-97   20-?   $17 profit on the sale of 1 share.   $ Loss of the share sold at 20% loss=   80-97   20-?   $24 loss on the sale of 1 share.   17-23=Loss of $6   Answer: a loss of $6
Answer: C
If 4 (A's capital) = 6 (B's capital) = 10 (C's capital), then out of a profit of Rs. 31, C will receive  Select the correct option
A) 6	B) 5	C) 8	D) 10	E) 12

Solution: Explanation:   Let 4A = 6B = 1OC = k. Then, A = k/4, B = k/6, and C =k/10 .   A : B :C = k/4 : k/6 : k/10 = 15 : 10 : 6.   Hence, C's share (31 * 6/31) = Rs, 6.   6nswer: 6) Rs.6
Answer: A
There are 3 teams each with 8 basket players. How many combinations are there if we were to pick 2 players from the 3 teams such that no team was picked twice?
Select:
A) 50
B) 23
C) 192
D) 28
E) 45

Solution: There are altogether three arrangements, which are we can select two members each from team A and B, each from team A and C, and each from team B and C. For each arrangement, there are altogether 64 possibilities (8*8) since each team has 8 players. So there are a total of 192 possibilities (64*3). I hope this method is easier for you to understand.
Answer: C
What is the smallest positive integer x such that 80-x is the cube of a positive integer	Select:
A) 16  B) 12  C) 47  D) 9  E) 12

Solution: Given 80-x is a perfect cube   so we will take 64= 4*4*4   80-x = 64   x =80-64= 
80-64 = 16
16   correct option is 16
Answer: A
A river 2m deep and 45 m wide is flowing at the rate of 3 kmph the amount of water that runs into the sea per minute is? Options:	A) 4500	B) 3889	C) 2777	D) 1299	E) 2791

Solution: (3000 * 2 * 5)/60   = 4500 M3   4500nswer: 4500
Answer: A
A dealer offers a cash discount of 20%. Further, a customer bargains and receives 20 articles for the price of 15 articles. The dealer still makes a profit of 20%. How much percent T above the cost price were his articles marked? Choose the correct choice from the following choices
A) 100%
B) 80%
C) 75%
D) 66+2/3%
E) 50%

Solution: Good question...2:11 min   Marked Price (M) = Cost Price (C) + Mark up...(EQN. A)   Selling price = 20% Discount over M = 0.8*M   Given that, a customer bargains and receives 20 articles for the price of 15 articles-->*afurther loss of 25%to the dealer--> BUT aNET PROFIT of 20%over cost price (C)   0.75* 0.8 * M =1.2 * C   Hence, M/C = 2/1 = 200%=T   From Eqn. A , (C + Mark up)/C = 200% -->Mark up / C = 100%   Ans. 100%
Answer: A
Given a Number 123456, from this number put any three values in numerator and remaining three are in denominator. So how many values you can make from this number less than 1/5.
Choose the correct choice from the following options:
A) 2 B) 6 C) 7 D) 87 E) 81

Solution: Explanation:   If the given value is 120, then denominator should be slightly greater than 600. If for 130, it is 650. So if we take numerator as 132, then denominator should be greater than 660 which is not possible as we have only 5 and 4 available. So numerator is less than 130. The following numbers are possible.   123/654, 123/645, 124/635, 124/653, 125/634, 125/643.   Answer:87
Answer: D
A trader sells 85 meters of cloth for Rs. 8925 at the profit of Rs. 15 per metre of cloth. What is the cost price of one metre of cloth?
Choose the correct choice from the following options
A) 21
B) 28
C) 90
D) 26
E) 11

Solution: Explanation:   SP of 1m of cloth = 8925/85 = Rs. 105   CP of 1m of cloth = SP of 1m of cloth - profit on 1m of cloth   = Rs. 105 - Rs. 15 = Rs. 90.   Answer: 90
Answer: C
10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.130000, find the cost of a camel?  Pick.
A) s.9800  B) s.3800  C) s.9800  D) s.5200  E) s.6880

Solution: Cost of the camel = P   10 camels = 24 horses   16 horses = 4 oxen   6 oxen = 4 elephants   10 elephants = Rs.130000   P = Rs.[(24 * 4 * 4 * 130000)/(10 * 16 * 6 * 10)]   P = Rs.(49920000/9600) => P = Rs.5200   Answer:s.5200
Answer: D
If (1/5)^m * (1/4)^2 = 1/((10)^4), then m =  Select the correct option
A) 4	B) 5	C) 6	D) 3	E) 2

Solution: 1/5^m *1/4^2= 1/ 2^4*5^4   2^4*5^4/2^4 =5^m or 5^4 =5^m   therefore m=4   4
Answer: A
How many 1's are there preceded by 2 but not followed by 7?
5 9 3 2 1 7 4 2 6 9 7 4 2 1 3 2 8 7 4 1 3 8 3 2 5 6 7 4 3 9 5 8 2 0 1 8 7 4 6 3	Choose the correct choice from the following choices.
A) 4  B) 5  C) 6  D) 1  E) 9

Solution: 2 1 3   Only at these places 1 is preceded by 2 but not followed by 7   Answer: 1
Answer: D
What least number must be added to 1056, so that the sum is completely divisible by 23 ?
Choose the correct choice from the following answers:
A) 2	B) 3	C) 18	D) 21	E) None of these

Solution: 23) 1056 (45   92   ---   136   115   ---   21   ---   Required number = (23 - 21)= 
(23 - 21) = 2
2.   2nswer: 2
Answer: A
A certain car dealership offers its newest model in ten exterior and ten interior colors. If the seven interior colors are identical to the seven exterior colors, and the dealership sells every pair of colors except those that would result in a car with an identically colored interior and exterior, how many different color combinations are possible?
Choose the correct choice:
A) 45	B) 81	C) 90	D) 10!/2!	E) 10!

Solution: I lined up the 10 different colours for Exterion and Interior like this:   E: A B C D E F G H I J   I: A B C D E F G H I J   I calculated the number of combinations:   10*10= 
  10*10 = 100
100 combinations.   But, from these 100 we need to delete sth: the same colours.   There are 10 possible pairs of coulours that will be the same. So, I deleted these 10 pairs from 100, resulting in 45.   Mind here, that the 10 do not result in 20 colours, because 1 pair is one unit that is not allowed. So, 10 units are not allowed (surprised that 80 wasn't among the answer options to confuse test takers...).   45
Answer: A
In a group of 25 factory workers, 17 have brown eyes. Six of the women do not have brown eyes. How many of the 11 men have brown eyes.
Choose the correct choice from the following: A) 10 B) 9 C) 8 D) 7 E) 4

Solution: Total number of worker (M+W): 25   No. of men (M): 11 (Inferred fromHow many of the 11 men)   No. of women (W): 14   Total no. of workers who have brown eyes (B): 17   No. of women who do not have brown eyes: 6   Therefore, no. of women who have brown eyes: W - 6 = 14 - 6= 
14 - 6 = 8
8   Remaining 9 are men. (B - 8= 17 - 8= 
17 - 8 = 9
9)   So 9 out of 11 men have brown eyes.   9
Answer: B
The ratio of two numbers is 3:4 and their sum is 28. The greater of the two numbers is?
Select the correct option
A) 8
B) 10
C) 16
D) 18
E) 22

Solution: 3:4   Total parts = 7   = 7 parts --> 28 (7 × 4 = 28)   = 1 part ---->4 (1 × 4 = 4)   = The greater of the two number is = 4   = 4 parts ----> 16 (4 × 4 = 16)   16
Answer: C
If Q is a positive integer, which of the following must be odd? Pick.
A) Q+1  B) Q^2+Q  C) Q^2+Q+1  D) x^2−1  E) 3x^2−3

Solution: A. Q+1 = can be odd or even. Since O + O =E or E + O = O   B. Q^2 + Q = Q(Q+1). Since from the above derivation we already know the term Q+1 can be Odd or Even, directly substitute here. Q(ODD) = Even (When Q is Even) or Q(EVEN) = EVEN [When Q is ODD]   C. Here's the answer. Since we know the term Q^2 + Q can always take a EVEN number, EVEN + 1 = ODD   Hence Q^2+Q+1.
Answer: C
Set S consists of all prime numbers less than 10. If two numbers are chosen from et S at random, what is the probability that the product of these numbers will be greater than the product of the numbers which were not chosen?  Select the correct option:
A) 1/3
B) 2/3
C) 1/2
D) 7/10
E) 4/5

Solution: Prime integers below 10: 2, 3, 5, 7   Total outcomes: Number of ways you can choose 2 from 4 = 4C2=6pairs4C2=6pairs   No. of ways for Event: Pairs that will have products greater than product of pairs not selected i.e. (3,5), (3,7), (5,7) =3pairs=3pairs   Probability = number of ways/Total outcomes =3/6=1/2=3/6=1/2   Hence choice(1/2) is correct.
Answer: C
A paint store mixes 3/4 pint of red paint and 2/3 pint of white paint to make a new paint color called Perfect Pink. How many pints of red paint would be needed to make 36 pints of Perfect Pink paint?
Choose the correct choice from the following answers.
A) 9
B) 16
C) 19
D) 25 1/3
E) 28 1/2

Solution: 3/4 pint is required to make 3/4 + 2/3 = 17/12 pint of perfect pink   so 17/12 pint requires 3/4 pint of red..   1 pint will require 3/4 * 12/17=9/17..   36 pints will require 9/17 * 36= 19 pints..   19
Answer: C
How many combinations of three letters taken from letters (b, b, c, c, d,d) are possible?  Choose one:	A) 12	B) 13	C) 5	D) 6	E) 7

Solution: So 3C3 for bcd - 1 choice   2 more for dd(b,c )   2 more for bb(d,c )   2 more for cc(d,b )   total 7   Ans :7
Answer: E
There are 6 more women than there are men on a local co-ed softball team. If there are a total of 16 players on the team, what is the ratio of men to women?
Choose the correct choice from the following:
A) 10/16
B) 6/16
C) 4/16
D) 6/10
E) 5/11

Solution: w = m+6   w+m = 16   m+6+m = 16   2m = 10   m = 5   w = 11   ratio:5:11   Ans: 5/11
Answer: E
A quantity of tea is sold at Rs. 5.75 per kilogram. The total gain by selling the tea at this rate is Rs. 60. Find the quantity of tea being sold if a profit of 15% is made on the deal.
Options:
A) 80kg.
B) 90kg.
C) 70kg.
D) 60kg.
E) 50kg.

Solution: say total cost price of tea is x.   then total profit at a rate of 15% is=(15x/100)   according to question,   15x/100=60   so x=400   c.p of the tea is 400.so total selling price will be=(400+60)= 
(400+60) = 460
460   so the quantity of the tea will be=(460/5.75)= 
(460/5.75) = 80
80kg.   80kg.NSWER:80kg.
Answer: A
Last year, sales at Company Dopler were 10% greater in February than in January, 5% less in March than in Feb, 5% greater in April than in March, 10% less in May than in April, and 10% greater in June than in May. In which month were sales closest to Jan?  Choose the correct choice from the following answers.
A) Feb
B) April
C) Mar
D) May
E) June

Solution: Jan = $100   10% greater in February than in January ---> Feb = $110   10% less in March than in Feb ---> Mar = $99   5% greater in April than in March ---> Apr = $103.95   10% less in May than in April ---> May $93.55   10% greater in June than in May --->Jun = $102.90   Answer : Mar
Answer: C
A watch passes through three hands and each person gains 25%. If the third person sells it for $375, what did the first person pay for it?	Select the correct option
A) $184  B) $188  C) $192  D) $196  E) $200

Solution: 1.25*1.25*1.25 * original price = 375   (5/4)^3 * original price = 375   original price = 64*375 / 125= 
64*375 / 125 = 192
$192   The answer is $192.
Answer: C
A train 280 m long, running with a speed of 63 km/hr will pass a tree in?
Select the correct option
A) 17 sec	B) 16 sec	C) 18 sec	D) 14 sec	E) 12 sec

Solution: Speed = 63 * 5/18   = 35/2 m/sec   Time taken = 280 * 2/35= 
280 * 2/35 = 16
16 sec   Answer: 16 sec
Answer: B
What approximate value should come in the place of question mark(?) in the following equation?
98.98 ÷ 11.03 + 7.014 × 15.99 = (?)2 Choose the correct choice from the following options:  A) 131  B) 144  C) 12  D) 121  E) 11

Solution: 98.98 ÷ 11.03 + 7.014 × 15.99 = (?)2   Suppose ? = x   Then 99 ÷ 11 + 7 × 16 + ≈ 121   (taking approximate value)   ∴ x = 11   Answer 11
Answer: E
The value of a machine depreciates at 24% per annum. If its present value is $1,50,000, at what price should it be sold after two years such that a profit of $24,000 is made? Choose the correct choice from the following choices
A) $250640 B) $430640 C) $120640 D) $110640 E) $150640

Solution: The value of the machine after two years = 0.76 * 0.76 * 1,50,000 = $86,640   SP such that a profit of $24,000 is made = 86,640 + 24,000 = $1,10,640   $110640
Answer: D