MU-NLPC/Calc-aqua_rat huggingface dataset:
10 distinct integers are arranged in ascending order. The range of the first 7 is 25 and that of last 7 is 30. What is the maximum range U of the 10 numbers? Answers.
A) 25  B) 27  C) 30  D) 52  E) 55

Solution: Positions: 1 2 3 4 5 6 7 8 9 10   Given: 1st position = x; 4th position = a; 7th position = y; 10th position = b   y - x = 25   Let x be 0 and y = 25. We are asked to maximize the range and the integers are distinct.   b - a = 30 --> b = 30 + a   In order to increase the range, we have to maximize the value of 'b'.   'b' can be maximized by taking the max value of 'a'.   From the assumed values, maximum value of 'a' can be 22.   Therefore, b = 30 + 22= 
30 + 22 = 52
52   Range U= 52 - 0= 
52 - 0 = 52
52   Answer: 52
Answer: D
Sequence F consists of 16 consecutive integers. If -6 is the least integer in sequence F, what is the range of the positive integers in sequence F? Options:
A) 16
B) 15
C) 9
D) 8
E) 7

Solution: Since set F consists of 16 consecutive integers and -6 is the least integer then set F is consecutive integers from -6 to 9, inclusive: 9-(-6)+1= 
9-(-6)+1 = 16
16.   The range of positive integers in sequence F is 9-1= 
9-1 = 8
8.   Answer: 8.
Answer: D
A tourist purchased a total of $1,500 worth of traveler’s checks in $10 and $50 denominations, During the trip the tourist cashed 7 checks and then lost all of the rest. If the number of $10 checks cashed was three more or three less than the number of $50 checks cashed, what is the minimum possible value of the checks that were lost?
Choose one:
A) $1,230
B) $1,310
C) $1,290
D) $1,270
E) $1,150

Solution: Let the number of $10 checks cashed beT   Let the number of $50 checks cashed beF   7 checks cashed;   T+F=7   Now; T can be F+3 OR T can be F-3   Let's check both conditions;   T=F+3   T+F=7   F+3+F=7   2F=4   F=2   T=5   Value cashed = 2*50+5*10= 
2*50+5*10 = 150
$150   Let's check the other condition as well;   T=F-3   T+F=7   F-3+F=7   2F=10   F=5   T=2   Value cashed = 5*50+2*10= 
5*50+2*10 = 270
$270   The more money he cashes, the less loss he incurs. Thus, we must consider the latter case.   Value cashed= $270   Value lost = 1500-270= 
1500-270 = 1_230
$1230   $1,230ns:$1,230
Answer: A
A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?
Select the correct option.
A) 81 B) 75 C) 72.63 D) 73 E) 76

Solution: 25% in 100 lts is 25. So water = 100-25= 
100-25 = 75
75 lts. 30% of 90 lts= 27. So water in 2nd mixture = 90-27= 
90-27 = 63
63 lts. Now total quantity= 100 + 90= 
100 + 90 = 190
190 lts. Total water in it will be 75 + 63= 
75 + 63 = 138
138 lts. % of water= (100*138)/190 = 72.63   ANSWER:72.63
Answer: C
What will be the next sequence in this series?
10,24,130,336,1342,_____? Choose the correct answer
A) 2174  B) 2184  C) 2284  D) 2884  E) 2984

Solution: 2^3 + 2 = 10   3^3 - 3 = 24   5^3 + 5 = 130   7^3 - 7 = 336   11^3 + 11 = 1342   2,3,5,7,11,13,... prime no.s   next is ( 13^3 - 13 ) = 2184   ANSWER:2184
Answer: B
A grocer has a sale of Rs. 6345, Rs. 6927, Rs.6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?	Choose the most appropriate option.
A) Rs. 3000  B) Rs. 4991  C) Rs. 5991  D) Rs. 6001  E) NOne

Solution: Sol.   Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562)   = Rs. 34009.   ∴ Required sale = Rs.[(6500 x 6) - 34009]   = Rs. (39000 - 34009)   = Rs. 4991.   Answer Rs. 4991
Answer: B
The youngest of 4 children has siblings who are 3, 6, and 7 years older than she is. If the average (arithmetic mean) age of the 4 siblings is 30, what is the age of the youngest sibling? Choose one:	A) 22	B) 23	C) 24	D) 25	E) 26

Solution: x + (x+3) + (x+6) + (x+7) = 120   4x + 16 = 120   4x = 104   x = 26   The answer is 26.
Answer: E
People standing in a straight line are wearing alternating colored shirts. The pattern of shirts begins with red, followed by green, blue, white and yellow. This pattern continues (red, green, blue, white and yellow) until it ends with a white shirt. If there are more than 5 people in line, which of the following cannot be the number of people in the line?  Choose one:
A) 29 B) 39 C) 54 D) 64 E) 75

Solution: The correct answer should not take the form: 5x + 4. Hence, it is 75
Answer: E
What is the CP of Rs 100 stock at 9 discount, with 1/5% brokerage?	Answers:	A) 96.9	B) 96.3	C) 91.2	D) 96.7	E) 96.21

Solution: Explanation:   Use the formula,   CP= 100 â€“ discount + brokerage%   CP= 100-9+1/5   91.2   Thus the CP is Rs 91.2.   ANSWER: 91.2
Answer: C
By travelling at 40 kmph, a person reaches his destination on time. He covered two-third the total distance in one-third of the total time. What speed should he maintain for the remaining distance to reach his destination on time?
Choose one:	A) 20 kmph	B) 15 kmph	C) 17 kmph	D) 16 kmph	E) 19 kmph

Solution: Let the time taken to reach the destination be 3x hours. Total distance = 40 * 3= 
40 * 3 = 120
120x km   He covered 2/3 * 120= 
2/3 * 120 = 80
80x km in 1/3 * 3x= x hours So, the remaining 40x km, he has to cover in 2x hours. Required speed = 40x/2x   =20 kmph.   20 kmphnswer: 20 kmph40 /2= 
40 /2 = 20
20 kmph.   20 kmphnswer: 20 kmph
Answer: A
If s, t, and p are consecutive integers such that s > t > p and the sum of s, t, and p is a multiple of 10, which of the following could be the value of s?
Choose the correct answer:
A) 0 B) 1 C) 9 D) 10 E) 12

Solution: We're given a very specific set of restrictions in this prompt:   1) S, T and P are CONSECUTIVE INTEGERS   2) S > T > P   3) S+T+P = a multiple of 10   We're asked which of the 5 answer COULD be the value of S given these restrictions. Rather than staring at the screen or doing layered math, we canbrute forcethe answers until we find one that fits these restrictions..   Answer A: S = 0   In this case, the numbers would be 0, -1, and -2. The sum = -3 which is NOT a multiple of 10. Eliminate A.   Answer B: S = 1   In this case, the numbers would be 1, 0, and -1. The sum = 0 which IS a multiple of 10. B IS the answer.   Final Answer:   1
Answer: B
In a certain game, you perform three tasks. You flip a quarter, and success would be heads. You roll a single die, and success would be a even. You pick a card from a full playing-card deck, and success would be picking a ten with red color card. If exactly one of these three tasks is successful, then you win the game. What is the probability of winning?  Select:
A) 9/104
B) 51/104
C) 25/52
D) 1/52
E) 51/52

Solution: Event(1): Probability of getting head in a flip of coin = 1/2   Event(2): Probability of getting even in a roll of dice = 3/6 = 1/2   Event(3): Probability of getting ten with red color in a pack of card = 2/52 = 1/26   Probability of winning is having exactly one successful event is:   P(success 1)* P(Fail 2)* P(Fail 3) + P(Fail 1)* P(Success 2)* P(Fail 3) + P(Fail 1)* P(Fail 2)* P(Success 3)   = 1/2*1/2*25/26 +1/2*1/2*25/26 +1/2*1/2*1/26   =25/104 + 25/104 +1/104   =51/104   Answer :51/104
Answer: B
When tossing two coins once, what is the probability of heads on both the coins? Choose the most appropriate option:
A) 1/4
B) 1/2
C) 3/4
D) None of these
E) 2/5

Solution: Total number of outcomes possible when a coin is tossed = 2 (∵ Head or Tail)   Hence, total number of outcomes possible when two coins are tossed, n(S) = 2 × 2 = 4   (∵ Here, S = {HH, HT, TH, TT})   E = event of getting heads on both the coins = {HH}   Hence, n(E) = 1   P(E) = n(E)n(S)=1/4   1/4nswer is 1/4
Answer: A
One night 20 percent of the female officers on a police force were on duty. If 100 officers were on duty that night and half of these were female officers, how many female officers were on the police force?  Select
A) 90
B) 180
C) 250
D) 500
E) 1,000

Solution: Let total number of female officers in the police force = F   Total number of officers on duty on that night = 100   Number of female officers on duty on that night = 100/2= 
100/2 = 50
50   (20/100)*F=50   =>F = 250   Answer 250
Answer: C
What is the greater of the two numbers whose product is 2496, given that the sum of the two numbers exceeds their difference by 64?  Select the correct option:	A) A)96	B) B)108	C) C)110	D) D)78	E) of these

Solution: Let the greater and the smaller number be g and s respectively.   gs = 2496   g + s exceeds g - s by 64 i.e., g + s - (g - s) = 64   i.e., 2s = 64 => s = 32.   g = 2496/s = 78.   ANSWER:78
Answer: D
On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?	Choices:
A) Tuesday B) Monday C) Sunday D) Wednesday E) Friday

Solution: The year 2004 is a leap year. It has 2 odd days.   The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.   Hence, this day is Sunday.   Answer: Option Sunday
Answer: C
The function f is defined for all positive integers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is prime, then f(p) =	Choices: A) P-1 B) P-2 C) (P+1)/2 D) (P-1)/2 E) 2

Solution: This question is wordy and confused me at first. If P is prime it's only factors are P and 1. So no number below it will have a common factor with it except 1. Therefore answer should just be P-1.   P-1NS = P-1
Answer: A
Find the principle on a certain sum of money at 5% per annum for 2 2/5 years if the amount being Rs.1680?  Choose one
A) 1500	B) 2777	C) 2889	D) 27670	E) 2771

Solution: 1680 = P [1 + (5*12/5)/100]   P= 1500.1500nswer:1500
Answer: A
21 ball numbered 1 to 21. A ballis drawn and then another ball is drawn without replacement.
Choose the correct choice from the following options.
A) 5/34 B) 3/37 C) 9/42 D) 5/41 E) 7/43

Solution: The probability that first toy shows the even number,   =1021=1021   Since, the toy is not replaced there are now 9 even numbered toys and total 20 toys left.   Hence, probability that second toy shows the even number,   =920=920   Required probability,   =(1021)×(920)=(1021)×(920)   =9/42   9/42
Answer: C
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?  Choose the correct choice from the following choices
A) 8m B) 7m C) 5m D) 2m E) 1m

Solution: Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   => l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   => (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 => l + b = 14   12(l + b)2 = 49lb   => 12(14)2 = 49lb   => lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
8 - 6 = 2
2m.   Answer:2m
Answer: D
Find the value of 582964 x 99999 = m?  Pick one:
A) 58210607666	B) 58310607896	C) 58295817036	D) 58591650836	E) 58310692816

Solution: 582964 x 99999 = 582964 x (10000 - 1)   = 582964 x 100000 - 582964 x 1   = 58296400000 - 582964= 
58296400000 - 582964 = 58_295_817_036
58295817036   58295817036
Answer: C
Maddie has 4 apples, if she give 2 to mike, how many does she have left?	Choose the correct option
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: 4-2= 
4-2 = 2
2   B. 2
Answer: B
The distance of the college and home of Rajeev is 80km. One day he was late by 1 hour than the normal time to leave for the college, so he increased his speed by 4km/h and thus he reached to college at the normal time. What is the changed (or increased) speed of Rajeev?	Choices
A) 60 km/h B) 10 km/h C) 60 km/h D) 20 km/h E) 90 km/h

Solution: Explanation:   Let the normal speed be x km/h, then   x = 16 km/h   (x + 4) = 20 km/h   Therefore increased speed = 20 km/h   Answer: 20 km/h
Answer: D
loga(ab)=x then logb(ab) is  Choose one.
A) x/x-1	B) x/x+1	C) x(x-1)	D) x(x+1)	E) x+1

Solution: loga(ab)=x   log(ab)/log(a)=x   log(b)/log(a)=x-1   log(a)/log(b)=1/x-1   1+log(a)/log(b) = 1+ 1/x-1   logb(ab) = x/x-1   x/x-1NSWER x/x-1
Answer: A
The greatest possible length which can be used to measure exactly the length 9m, 4m 90cm, 11 m 20 cm is Choose the correct choice from the following options
A) 15 cm  B) 25 cm  C) 10 cm  D) 12 cm  E) 43 cm

Solution: Explanation:   Required Length = H.C.F of 900 cm, 490 cm and 1120 c   = 10 cm. Answer: 10 cm
Answer: C
For any positive number x, the function [x] denotes the greatest integer less than or equal to x. For example, [1] = 1, [1.367] = 1 and [1.999] = 1. If k is a positive integer such that k^2 is divisible by 45 and 80, what is the units digit of k^3/4000 ?  Choose the correct option
A) 0
B) 1
C) 27
D) 54
E) Cannot be determined

Solution: Factorization of 45 = 3*3*5   Factorization of 80 = 5 * 2^4   Means the smallest value of K is \sqrt{3^2*5*2^4}=3*5*2^2   K^3=3^3*5^3*2^6*X=3^3*2*4000*X where X can be any integer   K^3/4000=3^3*2*X=54X which obviously has different units digit depending on X   ANSWER:54
Answer: D
A 2-year certificate of deposit is purchased for W dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years? Choose the correct choice from the following answers.
A) k(1.06)^2 B) k(1.06)^8 C) k(1.015)^2 D) W(1.015)^8 E) k(1.03)^4

Solution: Annual Rate of interest= 6%   Quaterly rate of interest= 6/4= 
6/4 = 3/2 = around 1.5
1.5%   Now, periods of compounding in 2 years= 8 (8 quarters)   Thus W(1.015)^8   Answer: W(1.015)^8
Answer: D
If difference between compound interest and simple interest on a sum at 10% P.a. for 2 years is Rs.65 then sum is  Answers.
A) s.5000  B) s.6500  C) s.5800  D) s.6000  E) s.6200

Solution: p(r/100)^2=C.I-S.I   P(10/100)^2=65   6500   ANSWER:s.6500
Answer: B
Find the number of zeroes in the expression 15*32*25*22*40*75*98*112*125
Pick:
A) 9 B) 8 C) 7 D) 6 E) 5

Solution: Maximum power of 5 in the above expression can be calculated like this. Count all the powers of 5 in the above expression. So number of zeroes are 9.   9nswer: 9
Answer: A
A trader marks his books 10% more than the cost price. If he allows 20% discount, then find his gain or loss percent?
Choose the correct choice from the following:
A) 2% profit  B) 12% loss  C) 4% loss  D) No profit No loss  E) None of these

Solution: Let CP of an book = 100   MP of an book = 110   Discount 20 % on 110 = 22   SP of the book = 110 - 22= 
110 - 22 = 88
88   LOSS= 12%   Answer : 12% loss
Answer: B
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If four marbles are picked at random, what is the probability that none is blue?
Choose the correct option
A) 33/67	B) 33/91	C) 33/19	D) 33/18	E) 33/91

Solution: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. When four marbles are picked at random, then the probability that none is blue is   = ¹²C₄/¹⁵C₄   = (12 * 11 * 10 * 9)/(15 * 14 * 13 * 12)   = 33/91   Answer: 33/91
Answer: B
Robin is traveling from one end of a forest to the other. In order to find her way back, she is leaving morsels of bread in the following pattern: 2 morsels of wheat, 3 morsels of white, and 1 morsel of rye. The pattern repeats after she leaves the morsel of rye. If Robin drops 1994 morsels of bread, what are the last 3 morsels of bread that she drops?
Choose the correct choice:
A) R,w,w  B) wheat − wheat − white  C) white − rye − wheat  D) white − white − white  E) white − white − rye

Solution: Q is nothing BUT asking about remainder..   total morsels thrown before the pattern is repeated = 2+3+1 = 6..   so REMAINDER when 1994 is div by 6..   1992 is EVEN and also div by 3, so remainder is 2..   Last 3 of morsels are 1992-1993-1994   so he uses the last of morsel of pattern in 1992 two of the first morsels of the pattern in 1993 and 1994, and the pattern is w, w, W, W, W, R..   ans R-w-w   R,w,w
Answer: A
George went to the supermarket with a red and a green bag and bought 10 carrots and 6 radishes. On the way back he divided the vegetables between the two bags in such a way that no bag was left empty. What is the maximum number of ways in which he can divide the vegetables between the two bags? Choices:
A) 60	B) 120	C) 600	D) 2^16	E) 2^16 - 2

Solution: Each carrot or radish can go into either red or green bag. So for Each vegetable there are 2 ways they can end up.   Like that for 16( 10 carrot + 6 raddish) there are 2^16 ways. But this includes the cases where all the 16 are in either red or green bag.   So answer is 2^16-2.   ANSW2^16 - 2R:2^16 - 2
Answer: E
A rectangular of certain dimensions is chopped off from one corner of a larger rectangle as shown. AB = 8 cm and BC = 4 cm. The perimeter of the figure ABCPQRA (in cm) is :	Choose one
A) 24
B) 28
C) 36
D) 48
E) None of these

Solution: Solution   Required perimeter = (AB + BC +CP + PQ + QR + RA)   = AB + BC + (CP + QR) + (PQ + RA)   = AB + BC + AB + BC = 2(AB + BC)   = [2(8 + 4 )] cm = 24 cm. 24nswer 24
Answer: A
Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/8 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent?	Choose the correct choice from the following answers:  A) 11/30  B) 29/60  C) 17/24  D) 19/30  E) 11/15

Solution: Let s assume the platinum card spending limit =x   Gold card spending limit will be =x/2   balance on gold card is =x/2*1/3=x/6   Platinum card unspent limit is= x-1/8x=7/8x   So if gold card balance is transferred then the rest unspent will be   7/8x-x/6=17/24x   So the ans is 17/24
Answer: C
At a certain laboratory, chemical substance are identified by an unordered combination of three different colors. If no chemical may be assigned the same three colors as any other, what is the maximum number of substances that can be identified using seven colors?
Select
A) 21  B) 35  C) 105  D) 135  E) 210

Solution: Combinations = N!/[K!(N-K)!] where N is the total number of items and K is the size of the subgroup   Here, we have 7 colors and we're choosing combinations of 3. Plugging those values in, we get...   7!/(3!4!) = (7)(6)(5)/(3)(2)(1) = (7)(5) = 35 combinations of 3 colors.   Final Answer:35
Answer: B
A sum of money at simple interest amounts to Rs. 840 in 3 years and to Rs. 854 in 4 years. The sum is:
Choose the correct choice from the following answers
A) 647  B) 798  C) 654  D) 847  E) 976

Solution: S.I. for 1 year = Rs. (854 - 840) = Rs. 14.   S.I. for 3 years = Rs.(14 x 3) = Rs. 42.   Principal = Rs. (840 - 42) = Rs. 798.   Answer:798
Answer: B
A hardware store purchased tools at 1/4 of their list price and sold them for 75% of the list price. What is his percent gain?  Choose one:
A) 75
B) 125
C) 200
D) 225
E) 300

Solution: 200ost = 1/4= 
1/4 = 1/4 = around 0.25
.25*LSale= .75 List Price = .75*LGain Ratio = (Sale - 200ost) / 200ost = (.75*L - .25*L) / .25*L = .5*L / .25*L = 2.0Gain Percent = 100 * Gain Ratio = 100 * 2.0= 
100 * 2.0 = 200
200%= Answer 200
Answer: C
A football coach must choose 5 freshers from a team of 11 players. How many different ways can the coach choose the freshers?	Choose the correct choice from the following choices
A) 462  B) 650  C) 729  D) 800  E) 890

Solution: Choose 5 starters from a team of 11 players. Order is not important.   \inline {\color{Black} 11C_{5}}=462   462
Answer: A
The banker's gain on a sum due 6 years hence at 12% per annum is Rs. 756. What is the banker's discount? Pick one
A) 1240
B) 1120
C) 1190
D) 1806
E) None of these

Solution: Explanation :   TD = (BG ×100)/TR = (756×100)/(6×12) = Rs. 1050   BG = B1806 – T1806   => 756 = B1806 - 1050   => B1806 = 1050+ 756= 
1050+ 756 = 1_806
1806 Answer : Option 1806
Answer: D
The smallest number when increased by " 1 " is exactly divisible by 2, 8, 24, 36 is:  Options
A) 71	B) 70	C) 72	D) 73	E) 36

Solution: LCM = 72   72 - 1= 
72 - 1 = 71
71   71NSWER:71
Answer: A
A house wife saved $5 in buying an item on sale. If she spent $48 for the item, approximately how much percent she saved in the transaction?	Select:
A) 8% B) 9% C) 10% D) 11% E) 12%

Solution: Actual price = 48+5= 
48+5 = 53
$53   Saving= 5/48 * 100 = 100/11 = 10% approximately   Answer is 10%
Answer: C
Income and expenditure of a person are in the ratio 4 : 3. If the income of the person is Rs. 20000, then find his savings? Choose the correct choice from the following
A) Rs.3600 B) Rs.3603 C) Rs.3639 D) Rs.3632 E) Rs.5000

Solution: Let the income and the expenditure of the person be Rs. 4x and Rs. 3x respectively.   Income, 4x = 20000 => x = 5000   Savings = Income - expenditure = 4x - 3x = x   So, savings = Rs.5000   Answer: Rs.5000
Answer: E
There are 640 students in a school. The ratio of boys and girls in this school is 3:5. Find the total of girls & boys are there in this school?  Choices.
A) 320  B) 345  C) 375  D) 380  E) 400

Solution: In order to obtain a ratio of boys to girls equal to 3:5, the number of boys has to be written as 3 x and the number of girls as 5 x where x is a common factor to the number of girls and the number of boys. The total number of boys and girls is 640. Hence   3x + 5x = 640   Solve for x   8x = 640   x = 80   Number of boys   3x = 3 × 80 = 240   Number of girls   5x = 5 × 80 = 400   400
Answer: E
Which of the following numbers is the largest?	Choose the correct option:
A) 10000-100  B) 2-10000  C) 1000-1000  D) 5-4000  E) 3-2000

Solution: The choices are a little easier to compare written this way:   (a) (104)100 = 10400 (b) (210)1000 > (103)1000 = 103000 (c) (103)1000 = 103000   (d) (54)1000 < (103)1000 = 103000 (e) (32)1000 < 101000   The answer is clear   correct answer 2-10000
Answer: B
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years
Choose the correct choice from the following options:	A) 306.09	B) 306.07	C) 306.04	D) 306.03	E) 306.01

Solution: A = 5000(51/50)3   = 5306.04   5000   -----------   306.04   Answer:306.04
Answer: C
A certain sum of money at simple interest amounted Rs.640 in 10 years at 3% per annum, find the sum? Choices.
A) 442.3 B) 492.3 C) 592.3 D) 402.3 E) 472.3

Solution: 640 = P [1 + (10*3)/100]   P = 492.30   ANSWER:492.3
Answer: B
By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 30%?
Choose the most appropriate option:	A) s.429	B) s.480	C) s.429	D) s.488	E) s.419

Solution: SP = 800   Profit = 25%   CP = (SP)*[100/(100+P)]   = 800 * [100/125]   = 640   Loss 800 *  100/125= 
800 *  100/125 = 640
640   Loss= 30% = 30% of 640 = Rs.192   SP = CP - Loss = 640 - 192   = Rs.448   Answer:s.488
Answer: D
Of the following, which is greater than 1/2 ?
Indicate ALL such fractions Choose one: A) 4/9 B) 4/7 C) 4/3 D) 4/2 E) 4/6

Solution: One way to deal with fractions is to convert them all to decimals.   In this case all you would need to do is to see which is greater than 0.5.   Otherwise to see which is greater than ½, double the numerator and see if the result is greater than the denominator. In B doubling the numerator gives us 8, which is bigger than 7.   Answer: 4/7
Answer: B
In how many different ways can the letters of the word "POLICE" be rearrangement? Pick one
A) 710
B) 725
C) 720
D) 770
E) 722

Solution: Option '720'   The total number of arrangements is   6P6 = 6! = 720
Answer: C
Sandhiya purchased a briefcase with an additional 10% discount on the reduced price after deducting 20% on the labelled price. If the labelled price was Rs. 1400, at which price did she purchase the briefcase? Choose one
A) Rs. 980	B) Rs. 999	C) Rs. 1008	D) Rs. 1120	E) None

Solution: Solution   C.P. 90% of 80% of Rs. 1400	= Rs.(90/100x80/100x1400)   ‹=›Rs. 1008.   Answer Rs. 1008
Answer: C