MU-NLPC/Calc-aqua_rat huggingface dataset:
If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability W that N is divisible by 3?  Choices
A) 1/3  B) ¼  C) 9/25  D) 5/16  E) 0

Solution: Prime digits are: 2, 3, 5, 7   Total number of 2 digit #s with both digits prime are:   4*4= 
  4*4 = 16
16   out of these numbers divisible by 3= 33, 27, 57, 72 and 75. I had to find the numbers manually using the 4 numbers above.   => prob = 5/16.   Ans D. Took me 3:20 mins.
Answer: D
In 2008, the profits of Company N were 10 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 10 percent of revenues. The profits in 2009 were what percent of the profits in 2008? Choose the correct choice from the following answers:
A) 80% B) 105% C) 120% D) 124.2% E) 138%

Solution: x = profits   r= revenue   x/r = 0,1   x= 10   r=100   2009:   r=80   x/80 = 0,10 = 10/100   x= 80*10/100= 
80*10/100 = 8
8   8/10= 
8/10 = 4/5 = around 0.8
0.8= 800%, 80%nswer 80%
Answer: A
An order was placed for the supply of a carpet whose breadth was 6 m and length was 1.44 times the breadth. What be the cost of a carpet whose length and breadth are 40% more and 25% more respectively than the first carpet. Given that the ratio of carpet is Rs. 45 per sq m?	Choose the correct option:
A) 4882.40 B) 8082.40 C) 4002.40 D) 4082.40 E) 9082.40

Solution: Explanation:   Length of the first carpet = (1.44)(6) = 8.64 cm   Area of the second carpet = 8.64(1 + 40/100) 6 (1 + 25/100)   = 51.84(1.4)(5/4) sq m = (12.96)(7) sq m   Cost of the second carpet = (45)(12.96 * 7) = 315 (13 - 0.04) = 4095 - 12.6 = Rs. 4082.40   Answer: Option 4082.40
Answer: D
A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 7 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Pick.
A) 9.5  B) 9.4  C) 9.3  D) 9.2  E) 9.1

Solution: Net part filled in 1 hour = (1/4 - 1/7) = 3/28   The cistern will be filled in 28/3 hrs i.e., 9.3 hrs.Answer: 9.3
Answer: C
A dishonest person wants to make a profit on the selling of milk. He would like to mix water (costing nothing) with milk costing 33 $ per litre so as to make a profit of 70% on cost when he sells the resulting milk and water mixture for 36$. In what ratio should he mix the water and milk?	Choose the correct answer
A) 1:120 B) 67:120 C) 67:8 D) 8:120 E) 1:2

Solution: First of all, let's consider 1 liter of the stuff he is going to sell --- naive customers think it's pure milk, but we know it's some milk-water mixture. He is going to sell this liter of milk-water for $36.   This $36 should be a 20% increase over cost. Here, we need to think about percentage increases as multipliers.   Using multipliers   (cost)*1.70 = $36   cost = 36/1.7= 360/12= 
360/12 = 30
$30   If he wants a 70% increase over cost on the sale of one liter of his milk-water, the cost has to be $21.17   Well, a liter of milk costs $33, so if he is going to use just $30 of milk in his mixture, that's 21.17/33= 120/187 of a liter. If milk is 120/87 of the liter, then water is 67/187 of the liter, and the ratio of water to milk is 67:120. Answer choice(67:120)
Answer: B
The cost C, in dollars, to remove p percent of a certain pollutant from a pond is estimated by using the formula C = 100,000p/(100 - p). According to this estimate, how much more would it cost to remove 90 percent of the pollutant from the pond than it would cost to remove 60 percent of the pollutant?  Choose one.
A) $300,000 B) $100,000 C) $50,000 D) $10,000 E) $5,000

Solution: To remove 90% of pollutant   C= 100,000(90)/(100-90) = 900,000   To remove 60% of pollutant   C' = 100,000(60)/(100-60) = 600,000   Difference = C - C' = 300,000   $300,000nswer - $300,000
Answer: A
A classroom has equal number of boys and girls. FIVE girls left to play kho-kho, leaving twice as many boys as girls in the classroom. What was the total number of girls and boys present initially?	Choose the correct choice
A) 16  B) 24  C) 32  D) 48  E) 20

Solution: after 5 girls left remaining 5 girls   now boys 10 are twice as many as remaining girls.   initially boys=10 and girls=10.   ANSW20R:20
Answer: E
Without stoppages a train travels a certain distance with an average speed of 120 kmph and with stoppages it covers the same distance with an average speed of 90 kmph. What is the time in minutes per hour for which train stops?  Choices
A) 5 min/hr  B) 6 min/hr  C) 12 min/hr  D) 16 min/hr  E) 15 min/hr

Solution: Pick a smart number for the distance. lets say LCM 360   Without = 360/120= 
360/120 = 3
3 hours   With= 360/90= 
360/90 = 4
4 hours   So in a trip of 4 hours, 1 hour is spent in stoppages   Hence, 60/4= 15 min/hr on stoppages   Answer : 15 min/hr
Answer: E
A number is increased by 60 % and then decreased by 60 %. Find the net increase or decrease per cent.
Choose the correct choice from the following options:  A) 19%  B) 18%  C) 27%  D) 33%  E) 36%

Solution: Let the number be 100.   Increase in the number = 60 % = 60 % of 100   = (60/100 Ã— 100)   = 60   Therefore, increased number = 100 + 60= 
100 + 60 = 160
160   This number is decreased by 60 %   Therefore, decrease in number= 60 % of 160   = (60/100 Ã— 160)   = 9600/100= 
9600/100 = 96
96   Therefore, new number= 160 - 96= 
160 - 96 = 64
64   Thus, net decreases= 100 - 64= 
100 - 64 = 36
36   Hence, net percentage decrease= (36/100 Ã— 100) %   = (3600/100)= 
(3600/100) = 36
36 %   Answer:36%
Answer: E
A fruit seller sells mangoes at the rate of Rs.13 per kg and thereby loses 25%. At what price per kg, he should have sold them to make a profit of 15%?  Select the correct option
A) Rs.11.81 B) Rs.19.93 C) Rs.12.25 D) Rs.12.31 E) None

Solution: Solution   75 : 13 = 115 : x   x= (13Ã—115/75)   = Rs.19.93   Hence, S.p per Kg	= Rs.19.93   Answer Rs.19.93
Answer: B
Beverley rode 5 1/4 miles in 1 hours and 30 minutes. What was her average rate of speed in miles per hour? Options:
A) 3	B) 3 1/4	C) 3 1/2	D) 3 3/4	E) 4

Solution: 3 3/4 = 5(1/4) = 21/4   T = 1(1/2) = 3/2 = 6/4   S = 3 3/4/T = 3 3/4   Answer = 3 3/4
Answer: D
In a class of 50 students, 20 play SNOOKER, 15 play Cricket and 11 play Football. 7 play both SNOOKER and Cricket, 4 play Cricket and Football and 5 play SNOOKER and football. If 18 students do not play any of these given sports, how many students play exactly two of these sports?  Choose the correct answer:
A) 10  B) 12  C) 34  D) 45  E) 566

Solution: Notice that7 play both SNOOKER and Cricket does not mean that out of those 7, some does not play Football too. The same for Cricket/Football and SNOOKER/Football.   [color=#ffff00]{Total}={SNOOKER}+{Cricket}+{Football}-{HC+CH+HF}+{All three}+{Neither}For more check ADVANCED OVERLAPPING SETS PROBLEMS   [/color]   50=20+15+11-(7+4+5)+{All three}+18 --> {All three}=2;   Those who play ONLY SNOOKER and Cricket are 7-2= 
7-2 = 5
5;   Those who play ONLY Cricket and Football are  4-2= 
 4-2 = 2
2;   Those who play ONLY SNOOKER and Football are  5-2= 
 5-2 = 3
3;   Hence, 5+2+3=10 students play exactly two of these sports.   10nswer: 10.
Answer: A
How many numbers from 2 to 8 are exactly divisible by 2?	Select the correct option: A) A)2 B) B)4 C) C)5 D) D)7 E) E)8

Solution: 2/2= 
2/2 = 1
1 and   8/2= 
  8/2 = 4
4   4- 1= 
4- 1 = 3
3   3 + 1= 
3 + 1 = 4
4 Numbers.   Answer : 4
Answer: B
If set A={2,2,2,....,n times} , set B={3,3,3,3....m times} and set C={13,13,13...k time} , then in terms of m,n and k , how many possible subsets from sets A,B, and C can be created ?	Select
A) a) k(n+m+mn)+ k
B) b) (1+n+m+mn)(k+1)
C) c) k^2(mn+n/m)
D) d) kmn(k+m+n)
E) e) None of the above.

Solution: a) how many 2's are included?   b) how many 3's are included?   and   c) how many 11's are included?   For the number of 2, we could have zero 2's, or one 2, or two 2's, all the way up to n 2's. That's (n + 1) possibilities for the 2's. Similarly, (m + 1) possibilities for the 3's and (k + 1) possibilities for the 11's. We simply multiply these three numbers.   NOTICE that one set, the set that includes no 2's, no 3's, and no 11's, is included. This is known in mathematics as thenull set, sometimes called the empty set, a set with no members. Technically, this is a subset of every possible set, but that's a technical detail of set theory that goes well beyond what the GMAT would expect students to know. Even the the calculation is not that difficult, some of the technical aspects of this question are not in line with the GMAT's expectations.   The number of subsets is (m + 1)(n + 1)(k + 1). The answer is not given in that form. Instead, the first two factors have been FOILed together:   (mn + m + n + 1)(k + 1).   Mike   b) (1+n+m+mn)(k+1)
Answer: B
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. Find the length of the train?	Pick one
A) 150  B) 872  C) 287  D) 288  E) 212

Solution: Speed = 60*(5/18) m/sec = 50/3 m/sec   Length of Train (Distance) = Speed * Time     (50/3) * 9= 
  (50/3) * 9 = 150
150 meter   150nswer:150
Answer: A
Cecilia, Robbie, and Briony all bought stamps. The number of stamps Cecilia purchased was equal to a single digit. The number of stamps only one of them purchased was divisible by 7. The number of stamps one of them bought was an even number. Which of the following could represent the numbers of stamps each purchased? Choices.
A) 3, 8, 24
B) 7, 9, 17
C) 6, 9, 12
D) 5, 15, 18
E) 9, 10, 13

Solution: I didnt get your point on eliminating D.   The number of stamps only one purchased was divisible by 7.Could that not be Cecilia with 9 stamps.   I choose this and marked 5, 15, 18.
Answer: D
The profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448. What should be the sale price for making 45% profit?  Choose one.
A) $480  B) $450  C) $928  D) $870  E) $660

Solution: Let C.P. = $ x.   Then, 832 - x = x - 448   2x = 1280 => x = 640   Required S.P. = 145% of $ 640 = $ 928.   $928
Answer: C
If the sides of a cube are in the ratio 9:5. What is the ratio of their diagonals?
Choose the correct choice from the following choices:
A) 9:5 B) 16:9 C) 4: D) 3:4 E) 3:8

Solution: Explanation:   Diagonal of a Cube=a√3 where a is side   a1:a2 = 9:5   d1:d2 = 9:5 where√3 cancelled both side   9:5NSWER:9:5
Answer: A
Both Robert and Alice leave from the same location at 8:00 a.m. driving in the same direction, but in separate cars. Robert drives 60 miles per hour while Alice drives 80 miles per hour. After 6 hours, Alice’s car stops. At what time will Robert’s car reach Alice’s car?
Choose the correct choice from the following options
A) 1 p.m.	B) 3 p.m.	C) 4 p.m.	D) 8 p.m.	E) 9 p.m.

Solution: 8:00 am so 6 hours later is 2:00 pm   In six hours, Robert will have driven  6*60= 
 6*60 = 360
360 miles   In six hours, Alive will have driven 6*80= 
6*80 = 480
480 miles   So Robert needs  480-360= 
 480-360 = 120
120 miles do catch Alice up.   So at 60 mph, he will need 2 hours   2:00 pm + 2 hours= 4:00 pm   ANS : 4 p.m.
Answer: C
X percents of the rooms are suits, Y percent of the rooms are painted light blue. Which of the following best represents the least percentage of the light blue painted suits?	Choose the correct answer:
A) X-Y B) Y-X +100 C) 100X-Y D) X+Y-100 E) 100-XY

Solution: Using the simple formula   100 = X + Y - BOTH - > Here X = % of Suits , Y = % of light blue painted rooms and BOTH = % of suits painted in light blue colour   So now, BOTH = X+Y -100 and now you can manipulate the value of X and Y to get the max and minimum values.   Hence Answer X+Y-100
Answer: D
If a - b = 5 and a2 + b2 = 29, find the value of ab.
Select the correct option:
A) 6	B) 8	C) 10	D) 11	E) 2

Solution: 2ab = (a2 + b2) - (a - b)2   = 29 - 25= 
29 - 25 = 4
4   ab= 2.   Answer: 2
Answer: E
In a store, the profit is 320% of the cost. If the cost increases by 25% but the SP remainsconstant, approximately what %of the sp is the profit? Choose the correct choice
A) 30%  B) 70%  C) 80%  D) 90%  E) 100%

Solution: Let C.P. = Rs. 100. Then, profit = Rs. 320, S.P. = Rs. 420   New C.P. = 125% of Rs. 100 = Rs. 125.   New S.P. = Rs. 420   Profit = 420 - 125 = Rs. 295   Required percentage = 295/420 * 100 = 1475/21 = 70%   70%
Answer: B
ashok and pyarelal invested money together in a business and share a capital of ashok is 1/9 of that of pyarelal.if the incur a loss of Rs 1000 then loss of pyarelal?	Pick:
A) 600
B) 700
C) 800
D) 900
E) 1000

Solution: Let the capital of Pyarelal be x, then capital of Ashok=x/9   So ratio of investment of Pyarelal and Ashok = x : x/9 =9x : x   Hence out of the total loss of 1000, loss of Pyarelal= 1000*9x/10x=900   ANSWER:9001000*9 /10= 
1000*9 /10 = 900
900   ANSWER:900
Answer: D
A and B start from Opladen and Cologne respectively at the same time and travel towards each other at constant speeds along the same route. After meeting at a point between Opladen and Cologne, A and B proceed to their destinations of Cologne and Opladen respectively. A reaches Cologne 40 minutes after the two meet and B reaches Opladen 70 minutes after their meeting. How long did A take to cover the distance between Opladen and Cologne?	Select the correct option.
A) 1 hour  B) 1 hour 10 minutes  C) 2 hours 30 minutes  D) 1 hour 20 minutes  E) 2 hours 10 minutes

Solution: v1 and V2 are speeds.   v1.t /70 = v2   v2.t/40 = v1   v1/v2 = 7/4   which train A would 70. 4/7 mins to cover the same distance     40 + 40= 
  40 + 40 = 80
80 mins (ANS 1 hour 20 minutes)
Answer: D
The ratio R, by volume of soap to alcohol to water in a 76 litre solution is 2: 50: 100 . The solution is then altered by adding more soap, alcohol and water.After this alteration the ratio, by volume of soap to water in the solution doubles whereas the ratio, by volume of soap to water remains the same as before. What COULD BE the resulting volume.  Choose the most appropriate option:
A) 79 litres B) 78 litres C) 77 litres D) 152 liters E) 304 litres

Solution: I guess it should be   the ratio R, by volume ofsoaptowaterin the solutiondoubleswhereas the ratio, by volume ofalocoholtowaterremains thesameas before   2:50: 100 => 1 : 25 : 50. If we add all the parts, we get 76 liters   So we have 1 liters of Soap, 25 liters of Alcohol and 50 liters of Water.   Now as per the Question, Soap : Water doubles but alcohol to water remains the same.   So Soap becomes 2 liters, Alcohol remains 25 liters and Water remains at 50 liters.   Hence 77 liters - Option 77 litres)
Answer: C
Three people took GMAT practice tests in which the minimum and maximum possible scores are 200 and 800, respectively. They each took a test 3 times, and no one scored below 400 or over 700. If the individual ranges of the three people's scores in those 3 practice tests were 40, 70 and 100, what is the difference between the maximum and minimum possible ranges of all their scores put together.
Choose the correct choice from the following answers: A) 70 B) 80 C) 100 D) 140 E) 200

Solution: According to the information in the question the maximum range would be between 400 and 700(300). The minimum range would be the greatest range for any one individual, which is listed in the problem as 100. So the difference between these would be 300-100 or 200.   Answer:200
Answer: E
A dishonest dealer uses a scale of 80 cm instead of a metre scale and claims to sell at cost price. His profit is	Choose the correct choice from the following choices:	A) 9%	B) 10%	C) 25%	D) None of these	E) Cannot be determined

Solution: Solution   Gain%	= (20 / 80 x 100)%   = 25%   Answer 25%
Answer: C
If an amount of Rs 15,487 is divided equally among
76 students, approximately how much amount will
each student get?
Choose the correct choice from the following answers:
A) Rs 206
B) Rs 210
C) Rs 204
D) Rs 218
E) None

Solution: Amount received by each student = 15487/76 ≈ Rs   204   Answer Rs 204
Answer: C
If 89/99 = 0.898, what is the 83rd digit to the right of the decimal point of the fraction?	Options.
A) 5
B) 2
C) 8
D) 7
E) 9

Solution: we are not concerned what 89/99 means..   we have to look at the decimal..   0.898 means 0.898989....   so right of decimal, all ODD numbered are 8 and all EVEn numbered are 9..   here 83 is ODD, so ans is 8   Answer is 8
Answer: C
There is a swimming match that is single elimination meaning that after one loss the team is out. There are 50 swimmers in this match. How many matches are swam?  Choose one
A) 25	B) 50	C) 49	D) 15	E) 10

Solution: C   The number of matches always adds up to one less than the number of matches in a single elimination tournament. You may calculate it any way. Therefore, 49 races were swam.
Answer: C
A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?  Choose the correct choice.
A) 238 ways  B) 287 ways  C) 266 ways  D) 108 ways  E) 121 ways

Solution: Explanation:   The boy can select one trouser in nine ways.   The boy can select one shirt in 12 ways.   The number of ways in which he can select one trouser and one shirt is   9 * 12= 
  9 * 12 = 108
108 ways.   Answer: 108 ways
Answer: D
If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in
Rs.) in a period of 3 years is  Choose the correct choice from the following answers:
A) Rs. 154.50
B) Rs. 155.50
C) Rs. 156.50
D) Rs. 157.50
E) None of these

Solution: Explanation:   We need to calculate the profit of B.   It will be,   SI on the rate B lends - SI on the rate B gets   Gain of B=157.50=3500×11.5×3100−3500×10×3100   Answer: Rs. 157.50
Answer: D
A train 200 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train?	Choose the correct choice from the following options: A) 5 sec B) 9 sec C) 12 sec D) 18 sec E) 15 sec

Solution: Answer : C.   Speed of the train relative to man = (68 - 8) kmph   = (60* 5/18) m/sec = (50/3)m/sec   Time taken by the train to cross the man   = Time taken by It to cover 200 m at 50/3 m / sec = 200 *3/ 50= 
200 *3/ 50 = 12
12sec
Answer: C
If c = (1/10)a and b = 5c, then which of the following represents the result of a^2+b^2+c^2 in terms of c Select
A) 25c^2	B) 56c^3	C) 52c	D) 126c^2	E) 110c^2

Solution: a = 10c and b =5c.   a^2+b^2+c^2 = (10c)^2+(5c)^2+c^2 = 126c^2.   Answer is 126c^2
Answer: D
Due to 10% decrease in the price of sugar and John can buy 4kg more sugar in Rs100 , then find the CP of sugar?
Choices:
A) s. 1(2/9)
B) s. 2(7/9)
C) s. 2(1/9)
D) s. 3(2/7)
E) s. 4(2/9)

Solution: Here r = 10 % ,x = 100 and A = 4 kg   Actual price of sugar = 10*100/((100-10 )*4) = Rs. 2(7/9)   s. 2(7/9)
Answer: B
From a group of boys and girls,15 girls leave.There are then left 2 boys for each girl.After this,45 boys leave.There are then 5 girls for each boy.Find the number of girls in the beginning? Pick:
A) 20
B) 30
C) 40
D) 50
E) 60

Solution: 15 girls leave,B+(g-15)=0   then,B=2*(g-15)---------------------->>>1   45 boys leave,(b-45)+(g-15)=0   then,(g-15)=5(b-45)   Hence,the number of girls in the beginning are,   5(b-45)-(g-15)=0------------------->>>2   put 1 in 2, we get,   5(2*(g-15)-45)-(g-15)=0   10g-150-225-g+15=0   9g-360=0   9g=360   g=40   ANSWER:40
Answer: C
If x is a positive integer, then the least value of x for which x! is divisible by 100,000 is?
Can someone please explain intuitively what the question is asking?  Choices.
A) 5
B) 9
C) 12
D) 20
E) 30

Solution: In order x! to be divisible by 1,000, it should have at least 3 trailing zeros. A trailing 0 in factorial of a number is produced by 2 and 5 in it:   2*5= 
  2*5 = 10
10. So, we need 10 to be in x! at least in power of 3.   5!= 120 has 1 trailing zeros.   10! will have 2 trailing zeros.   15! will have 3 trailing zeros.   20! will have 5 trailing zeros.   Answer: 20.
Answer: D
Find the average of first 40 natural numbers?  Choose the correct choice from the following choices:
A) 12.6 B) 20.5 C) 22.9 D) 30.5 E) 32.1

Solution: Sum of first n natural numbers = n(n+1)/2   sum of first 40 natural numbers = 40*41/2= 
40*41/2 = 820
820   average= 820/40= 
820/40 = 41/2 = around 20.5
20.5   Answer is 20.5
Answer: B
Two trains, each 100 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is? Select.
A) 76 km/hr	B) 66 km/hr	C) 60 km/hr	D) 67 km/hr	E) 22 km/hr

Solution: Let the speed of the slower train be x m/sec.   Then, speed of the train = 2x m/sec.   Relative speed = ( x + 2x) = 3x m/sec.   (100 + 100)/8 = 3x => x = 25/3.   So, speed of the faster train = 50/3 = 50/3 * 18/5= 
50/3 * 18/5 = 60
60 km/hr.   Answer:60 km/hr
Answer: C
What is the measure of the radius of the circle that circumscribes a triangle whose sides measure 7, 24 and 25?	Select.
A) 2.5  B) 6.5  C) 12.5  D) 14  E) 16

Solution: Some of pyhtagron triplets we need to keep it in mind.   Like {( 2,3,5) , ( 5,12,13) ,( 7, 24,25), ( 11, 60,61).   So now we know the triangle is an right angle triangle. The circle circumscribes the triangle.   The circumraduis of the circle that circumscribes the right angle triangle = hypotanse / 2 = 25 / 2= 
25 / 2 = 25/2 = around 12.5
12.5   Ans. 12.5
Answer: C
How many plants will be there in a circular bed whose outer edge measure 35 cms, allowing 4 cm2 for each plant ? Choose the correct choice:
A) 18  B) 750  C) 24  D) 19  E) None of these

Solution: 24ircumference of circular bed = 35 cm   Area of circular bed = (35)2â„4Ï€   Space for each plant = 4 cm2   âˆ´ Required number of plants   = (35)2â„4Ï€ Ã· 4 = 24.36 = 24(approx)   Answer 24
Answer: C
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 1.4 km respectively. The time taken by the slower train to cross the faster train in seconds is?
Select.
A) 60  B) 277  C) 48  D) 99  E) 22

Solution: Relative speed = 60 + 90= 
60 + 90 = 150
150 km/hr.= 150 * 5/18 = 125/3 m/sec.   Distance covered = 1.10 + 1.4= 
1.10 + 1.4 = 2.5
2.5 km= 2500 m.   Required time = 2500 * 3/125= 
2500 * 3/125 = 60
60 sec.   60nswer:60
Answer: A
(0.0066)(3.6) / (0.04)(0.1)(0.006)=  Choose one.
A) 990
B) 99.0
C) 9.9
D) 0.99
E) 0.099

Solution: (0.0066)(3.6) / (0.04)(0.1)(0.006)=0.0060 * 360/4 * (0.1)(0.006)   = 0.066*90/1 * 0.006 = 66*90/6 = 11*90= 
11*90 = 990
990   990nswer : 990
Answer: A
Which of the following points is symmetric with y=x at (2,3)?  Choices:  A) (-2,-1)  B) (-2,1)  C) (2,1)  D) (3,2)  E) (-1,2)

Solution: We can think of line y = x as a mirror. Any point (x,y) becomes (y,x) when it isreflectedover the mirror. Reverse the coordinate and keep the same sign. These two points will be symmetric to the line y = x.   (2,3) would become (3,2).   Answer ((3,2)).
Answer: D
Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?	Choose the correct choice from the following options:
A) 10508  B) 10567  C) 10528  D) 10512  E) 10500

Solution: Simran : Nanda = (50000 * 36) : (80000 * 30) = 3:4   Simran's share = 24500 * 3/7 = Rs. 10500   Answer:10500
Answer: E
The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?	Choose the correct choice
A) 22
B) 27
C) 15
D) 77
E) 16

Solution: Total members in the group = 7   Average amount = Rs. 20   Total amount with them = 7 * 20 = Rs. 140   One number has Rs. 50. So, the amount with remaining 6 people = 140 - 50 = Rs. 90   The average amount with them = 90/6 = Rs. 15.   Answer: 15
Answer: C