MU-NLPC/Calc-aqua_rat huggingface dataset:
Two trains leave the same train station at 6:00 am and 7:00 am and they travel at 100 kph and 125 kph respectively. How many kilometers from the train station will the two trains be together?
Options
A) 450 B) 475 C) 500 D) 525 E) 550

Solution: At 7:00, the first train is 100 km ahead.   The second train gains 25 km each hour.   The time it takes the second train to catch the first train is 100 / 25= 
100 / 25 = 4
4 hours.   In this time, the second train travels   4*125= 
  4*125 = 500
500 km.   The answer is 500.
Answer: C
A person, by selling an article at three-fourths of the list price incurs a loss of 20%. Find the profit percentage if he sells at the list price?  Choose the correct choice from the following choices:
A) 25 %	B) 6.66 %	C) 5.45 %	D) 30 %	E) None

Solution: Sol.   0.75 MP = 0.8 CP (since 20% loss) So, MP = 1.0666CP ⇒ 6.66% gain.   Answer 6.66 %
Answer: B
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero? Select:
A) 19  B) 20  C) 22  D) 45  E) 52

Solution: A   19   Average of 20 numbers = 0. Sum of 20 numbers (0 x 20) = 0. It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Answer: A
A high school has 400 students 1/2 attend the arithmetic club, 5/8 attend the biology club and 3/4 attend the chemistry club. 3/8 attend all 3 clubs. If every student attends at least one club how many students attend exactly 2 clubs. Select.
A) 35 B) 45 C) 55 D) 60 E) 50

Solution: A-Club has 200 members (1/2 of 400)   B-Club has 250 members (5/8 of 400)   C-Club has 300 members (3/4 of 400)   We can create an equation to solve this:   200+250+150 = n + x + 2y   where n is the number of students, x is the number of students in two clubs, and y is the number of students in three clubs.   The question provides y for us (150).   750 = 400 + x + 300   x = 50   50
Answer: E
The average age of a husband and his wife was 17 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is : Choose the correct choice from the following answers:
A) 55/3  B) 15  C) 19  D) 287  E) 27

Solution: Explanation:   Sum of the present ages of husband, wife and child = (17 * 2 + 5 * 2) + 1= 
(17 * 2 + 5 * 2) + 1 = 45
45 years.   Required average= (45/3)= 
(45/3) = 15
15years.   Answer: 15
Answer: B
The sum of three consecutive odd numbers is 20 more than the first of these numbers. What is the middle number?  Pick:
A) 5
B) 7
C) 9
D) 11
E) 10

Solution: Solution   Let the numbers be x, x+2,x+4   Then x,(x+2)+(x+4)= x+20   ‹=›2x = 14   ‹=›x= 7.   Therefore Middle number = x+2 = 9.   Answer 9
Answer: C
Two cyclists are running on a circular track of 600m.They start from the same point A at the same time.If they meet for the first time at a point 200 m from A, which of the following could be the possible ratio of their speeds?  Choose the most appropriate option:  A) 1:2  B) 2:3  C) 3:5  D) 5:7  E) 7:11

Solution: well, the key aspect of this question is the distance mentioned, when they met for the first time, which is 200m away from the starting point. This distance between their first meeting can be less than 600 in only two circumstance.   1) if both are travelling in the same direction and one of them has been given a head start say by few meters.   2) or if both are travelling in the opposite direction.   now since they start their journey at the same time. hence option 1 is ruled out. hence they must be running in the opposite direction. hence answer should be 1:2   Why?? here is a solution   1:2s here time is constant, therefore, distance traveled will be directly proportional to the the respective velocities/speed of the two runners.(d1/d2=v1/v2)   now one of them has covered 200m, therefore other must have covered 400m, therefore ratio of their speeds/velocities will be 1:2   1:2
Answer: A
During the break of a football match, the coach will make 3 substitutions. If the team consists of 13 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?
Choose the correct choice from the following answers:
A) 21/55	B) 18/44	C) 42/143	D) 28/44	E) 36/55

Solution: Required probability = no. of favorable outcome/ total no. of outcomes   out of 13 players any 3 can be selected in 1342/1433 ways   after removing 2 forwards any 3 players can be selected from the remaining 9 players in 942/1433 ways   thus required probability = 942/1433/1342/1433 =42/143
Answer: C
A professional janitor can clean a certain high school in (500-20) minutes, working at a constant rate. A student sentenced to detention can clean that same high school in 20 hours, also working at a constant rate. If the student is paid $7 total per hour and the janitor is paid $21 per hour, how much more would it cost the school to pay the janitor to do the job himself than it would to pay the student and the janitor to do the job together?
Pick:  A) -$56  B) -$6  C) $0  D) $6  E) $8

Solution: A professional janitor can clean a certain high school in (500-20)/60 or 8 hours   So (applying rule #1), the janitor can clean 1/8 of the school in ONE HOUR   A student sentenced to detention can clean that same high school in 20 hours   So (applying rule #1), the student can clean 1/20 of the school in ONE HOUR   So, COMBINED, the student and janitor can clean (1/8 + 1/20) of the school in ONE HOUR   1/8 + 1/20 = 5/40 + 2/40 = 7/40   So, in ONE HOUR they can clean 7/40 of the school.   Applying rule #2, it will takethem40/7 hoursto clean the ENTIRE school.   The janitor earns $21/hour and the student earns $7/hour, so their combined rate is$28/hour.   Theircombined wages= (pay rate)(time) = ($28/hour)(40/7 hours) =$160   Working ALON$8, the janitor takes 8 hours and earns $21/hour   So, working alone, the janitor's earnings = (pay rate)(time) = ($21/hour)(8 hours) =$168   $168-$160= $8, so the answer is $8 168- 160= 
 168- 160 = 8
$8, so the answer is $8
Answer: E
By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?
Choose one:	A) 7	B) 5	C) 8	D) 12	E) 15

Solution: 80% --- 12   120% --- ?     80/120 * 12= 
  80/120 * 12 = 8
8   ANSWER 8
Answer: C
The length of a train and that of a platform are equal. If with a speed of 108 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is? Choose the correct choice from the following options.
A) 299 B) 266 C) 299 D) 900 E) 261

Solution: Speed = [108 * 5/18] m/sec = 30 m/sec; Time = 1 min. = 60 sec.   Let the length of the train and that of the platform be x meters.   Then, 2x/60 = 30 => x = 30 * 60 / 2= 
30 * 60 / 2 = 900
900   Answer: 900
Answer: D
What is value of x if 32-y=16x-y?
Choose the correct choice from the following options
A) 1 B) 3 C) 4 D) 2 E) 6

Solution: 32-y=16x-y   32=16x-y+y   16x=32   x=2   Answer is option 2
Answer: D
A bag contains 15 red jellybeans and 15 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue?  Select the correct option.
A) 9/100 B) 2/19 C) 1/8 D) 3/20 E) 3/10

Solution: Method-1   10 red jellybeans and 10 blue jellybeans   Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140   Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all Blue out of 10 Blue = 10C3 = 120   Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3   Probability = 120 / 1140 = 2/19   Answer: option B   Method-2   Probability of First jelly bean to be Blue = 10/20 [Total 10 Blue out of total 20 jellybeans]   Probability of Second jelly bean to be Blue = 9/19 [Total 9 Blue remaining out of total 19 jellybeans remaining]   Probability of Third jelly bean to be Blue = 8/18 [Total 8 Blue remaining out of total 18 jellybeans remaining]   Required Probability = (10/20)*(9/19)*(8/18) = 3/10   Answer: option 3/10
Answer: E
If a coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 6 times, what is the probability that it will land heads up on all 6 flips?
Choices
A) 1/6  B) 1/8  C) 1/32  D) 1/2  E) 1/64

Solution: (1/2) * (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/64 Answer: 1/64
Answer: E
4 dice are thrown simultaneously on the board. Find the probability show the same face.	Choose the correct choice from the following choices
A) 1/113  B) 1/115  C) 1/216  D) 2/113  E) 3/111

Solution: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:   =6×6×6×6=64=6×6×6×6=64   n(S)=64n(S)=64   Let XX be the event that all dice show the same face.   X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}   n(X)=6n(X)=6   Hence required probability,   =n(X)n(S)=664=n(X)n(S)=664   =1/216   1/216
Answer: C
Steve traveled the first 2 hours of his journey at 30 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?	Choose the correct choice
A) 68 mph  B) 56.67 mph  C) 60 mph  D) 64 mph  E) 66.67 mph

Solution: Answer   Average speed of travel = Total distance travelled/Total time taken   Total distance traveled by Steve = Distance covered in the first 2 hours + distance covered in the next 3 hours.   Distance covered in the first 2 hours = speed * time = 30 * 2= 
30 * 2 = 60
60 miles.   Distance covered in the next 3 hours= speed * time = 80 * 3= 
80 * 3 = 240
240 miles.   Therefore, total distance covered= 60 + 240= 
60 + 240 = 300
300 miles.   Total time taken= 2 + 3= 
2 + 3 = 5
5 hours.   Hence, average speed= Total distance travelled/Total time taken=300/5= 
300/5 = 60
60 miles per hour.   60 mphhoice 60 mph
Answer: C
A “palindromic integer” is an integer that remains the same when its digits are reversed. So, for example, 43334 and 516615 are both examples of palindromic integers. How many 6-digit palindromic integers are both even and greater than 400,000?	Pick one.
A) 200 B) 216 C) 300 D) 400 E) 2,500

Solution: first digit=last digit=4 or 6 or 8 so three possibilities..   second =fifth= any of ten digits   third =fourth= any of ten digits..   so total integers=3*10*10= 
3*10*10 = 300
300   ANSWER:300
Answer: C
Last year the range of the annual fees of the 50 courses in a college was $300. If the annual fees of each of the 50 courses this year is 10 percent greater than it was last year, what is the range of the annual fees of the 50 courses this year?	Select the correct option:
A) $270  B) $300  C) $330  D) $360  E) $630

Solution: let the lowest fees x.   Therefore, highest fees is x +300.   Now fees of each course is increased by 10%.   Therefore the fees will remain arranged in the same order as before.   or Lowest fees = 1.1x and Highest = 1.1 * (x+300)   or Range = highest - lowest = 1.1 * (x+300) - 1.1x   = 330, Hence, $330
Answer: C
If a and b are different positive integers and a + b = a(a + b), then which of the following must be true?
I. a = 1
II. b = 1
III. a = b = 0
Choices.
A) I only  B) II only  C) III only  D) I and II  E) I and III

Solution: a has to equal a squared, and that only works if a is 1. both cannot be 0.   I onlynswer : I only
Answer: A
2^5*3^3*2^4*3 =
Choose one:  A) 3^5*2^5  B) 2^9*3^4  C) 2^4*3^9  D) 5^8  E) 6^10

Solution: 2^5*3^3*2^4*3 =   A) 3^5*2^5   B) 2^9*3^4   C) 2^4*3^9   D) 5^8   E) 6^10   If the base is same, powers are added so that follows B) 2^9*3^4.   Hence the answer is 2^9*3^4
Answer: B
The distance between two towns is 380 km. At the same moment, a passenger car and a truck start moving towards each other from different towns. They meet 4 hours later. If the car drives 5 km/hr faster than the truck, what is the truck's speed?  Choose the correct choice.
A) 35km/hr  B) 40km/hr  C) 76km/hr  D) 60km/hr  E) 50km/hr

Solution: The main idea used in this kind of problems is that the distance equals speed multiplied by time S=V⋅tS=V⋅t   V (km/hr)	t (hr)	S (km)   Car	x + 5	4	4(x +5)   Truck	X	4	4x   4(x+5)+4x=380   4x+4x=380−20   8x=360   x=360/8= 
360/8 = 45
45   Therefore the truck's speed is 45 km/hr, and the car's speed is 50 km/hr.   correct answer 50km/hr
Answer: E
The cost price of 20 articles is the same as the selling price of
x articles. If the profit is ,25%, find the value of x  Choose the correct choice from the following: A) 16 B) 17 C) 19 D) 20 E) 25

Solution: 25=(20-X)100/X   X=4(20-X)   X=16   16NSWER 16
Answer: A
A jogger running at 9 kmph along side a railway track is 260 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?  Choices.
A) 3.6 sec  B) 38 sec  C) 36 sec  D) 72 sec  E) None of these

Solution: Speed of train relative to jogger   = (45 – 9) km/h = 36 km/h   = (36 × 5⁄18) m/sec = 10 m/sec   Distance to be covered = (260 + 120)= 
(260 + 120) = 380
380 m.   ∴ Time taken= (380⁄10) sec = 38 sec.   Answer 38 sec
Answer: B
Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:	Answers.
A) 2/109  B) 7/109  C) 8/223  D) 14/263  E) 13/102

Solution: n(S) =(52 x 51)/(2 x 1)= 1326.   Let E = event of getting 1 spade and 1 heart.   n(E)	= number of ways of choosing 1 spade out of 13 and 1 heart out of 13   = (13 x 13)   = 169.   P(13/102) = n(13/102)/n(S)169/1326=13/102   Answer 13/102
Answer: E
A person lent out some money for 1 year at 6% per annum simple interest and after 18 months, he again lent out the same money at a simple interest of 24% per annum. In both the cases, he got Rs.4704. Which of these could be the amount that was lent out in each case if interest is paid half-yearly?
Choose the correct choice from the following answers.
A) 2200	B) 3000	C) 3200	D) 4200	E) 5000

Solution: If interest is paid half yearly,   in first case , r=3% per 6 months   for 18 months, I=( P*3*3)/100 ; here r=3% and t=3 as interest for 18 months in t=18/6   for next 6 month (i.e 24 months) I= (P*3*4)/100 =12P/100   second case,   After 18 months, same amount is lent out   r=12%   for 6 month i.e, first interest for t=1 , I=(12*1*P)/100=12P/100   For both cases , he got 4704   In above case , both cases have same interest as 12P/100   i.e P+12P/100=4704;   P=4200   ANSWER:4200
Answer: D
If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?
Choose the correct choice from the following options:
A) 120
B) 278
C) 292
D) 234
E) 287

Solution: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.   120rea of the triangle = 1/2 * 24 * 10= 
1/2 * 24 * 10 = 120
120 cm2   120nswer:120
Answer: A
In a partnership between A, B and C. A's capital is Rs.10000. If his share of a profit of Rs.1200 is Rs.400 and C's share is Rs.330, what is B's capital? Answers.
A) Rs.20750	B) Rs.22750	C) Rs.21750	D) Rs.21200	E) Rs.21320

Solution: 400 + 330= 
400 + 330 = 730
730   1200 - 330= 
1200 - 330 = 870
870   400 ---- 10000   870 ---- ?=>21750   ANSWER:Rs.21750
Answer: C
A and B together have USD. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
Choose the correct answer
A) USD 460  B) USD 484  C) USD 550  D) USD 664  E) None of above

Solution: 4/5 A= 2/5 USD 484   => A=(2/5 * 15/4) USD 484   => A=3/2 USD 484   =>A/USD 484= 3/2   => A:USD 484 =3:2   Therefore USD 484's Share =USD (1210 * 2/5)= 
(1210 * 2/5) = 484
USD 484   Answer is USD 484
Answer: B
The area of sector of a circle whose radius is 12 metro and whose angle at the center is 42° is? Pick one: A) 26.4 m2 B) 39.6 m2 C) 52.8 m2 D) 79.2 m2 E) 80.2 m2

Solution: Explanation:   42/360 * 22/7 * 12 * 12= 
42/360 * 22/7 * 12 * 12 = 264/5 = around 52.8
52.8 m2   ANSWER IS 52.8 m2
Answer: C
Which of the following options is an appropriate approximate value in the following equation’? 5 2/3 of 234.92+39% of 1205= ? - 625.7	Choose the correct choice from the following
A) 2326.85 B) 2426.85 C) 2526.85 D) 2436.85 E) 2427.85

Solution: 5 2/3 of 234.92+39% of 1205= ? - 625.7   17/3 of 234.92+39/100 of 1205= ? - 625.7   1331.2+469.95= ? - 625.7   1331.2+469.95 + 625.7= 
1331.2+469.95 + 625.7 = 2_426.85
?   ≈ 2426.85   Answer 2426.85
Answer: B
What is the greatest possible (straight line) distance, between any two points on a hemisphere of radius 1?
Choose the correct choice from the following choices.
A) 0.5 B) 1 C) π/2 D) 2 E) π

Solution: Maximum distance straight line is diameter   d = 2r = 2..   ANS option 2.
Answer: D
A 600 meter long train crosses a signal post in 40 seconds. How long will it take to cross a 3 kilometer long bridge, at the same speed?	Choose the correct choice from the following answers.
A) 4 min  B) 2 min  C) 8 min  D) 9 min  E) 5 min

Solution: S = 600/40= 
600/40 = 15
15 mps   S= 3600/15= 
3600/15 = 240
240 sec= 4 min   4 minnswer: 4 min
Answer: A
Tom runs everyday for exercise and running burns 500 calories/mile. If Tom wants to lose 10 pounds, how many miles for how many days does Tom have to run in total. (Assume it takes 3000 calories to lose 1 pound of weight)	Choose the correct answer
A) 3 miles for 10 days	B) 1 mile for 20 days	C) 10 miles for 6 days	D) 5 miles for 2 days	E) 15 miles for 10 days

Solution: It takes 3000 calories to lose 1 pound, which means it takes 30000 calories to lose 10 pounds. If running 1 mile burns 500 calories, Tom would need to run 10 miles = 5000 calories for 6 days = 5000 * 6= 
5000 * 6 = 30_000
30000. None of the other answers would give 30000. Correct Option: 10 miles for 6 days. Answer: 10 miles for 6 days
Answer: C
The greatest possible length which can be used to measure exactly the length 7m, 3m 85cm, 12 m 95 cm is	Pick one:  A) 22  B) 27  C) 35  D) 87  E) 98

Solution: Explanation:   Required Length = H.C.F of 700 cm, 385 cm and 1295 c   = 35 cm.   Answer: 35) 35 cm
Answer: C
The number of words from the letters of the words BHARAT in which B and H will never come together, is
Pick one:
A) 360
B) 240
C) 120
D) None of these
E) Cannot be determined

Solution: Solution   There are 6 letters in the word BHARAT, 2 of them are identical.   Hence total number of words with these letter = 360   Also the number of words in which B and H come together = 120   ∴ The required number of words = 360 – 120 = 240. Answer 240
Answer: B
Dravid is 9 years older than his daughter Rosy. In 3 years Dravid will be twice as old as Rosy. What is Rosy current age.  Choose the correct choice from the following answers:	A) 6	B) 8	C) 10	D) 7	E) 11

Solution: Now: Rosy = x, Dravid =x+9   In 3 years Rosy = x+3, Dravid = x+9+3 or 2(x+3)   x+12= 2x+6   x= 6   Rosy is 6 years old   6nswer : 6
Answer: A
Letters of alphabets no from 1 to 26 are consecutively with 1 assigned to A and 26 to Z. By 27th letter we mean A, 28th B. In general 26m+n, m and n negative intezers is same as the letters numbered n.
Let P = 6, strange country military general sends this secret message according ot the following codification scheme. In codifying a sentence, the 1st time a letter occurs it is replaced by the pth letter from it. 2nd time if occurred it is replaced by P^2 letter from it. 3rd time it occurred it is replaced by p^3 letter from it. What is the code word for ABBATIAL  Pick:
A) DFHASDO  B) HDFAHLOU  C) LDOIHYAD  D) GHLKZOIR  E) LODIHFAD

Solution: A should be coded as 1+6 = G (it occurred for first time)   B should be coded as 2+6 = H (it occurred for first time)   B Should be coded as 2 + 36= 
2 + 36 = 38
38 - 26= 
38 - 26 = 12
12= L (it occurred for second time)   Option GHLKZOIR is correct
Answer: D
Roses can be purchased individually for $6.30, one dozen for $36, or two dozen for $50. What is the greatest number of roses that can be purchased for $680?  Options
A) 156	B) 162	C) 316	D) 324	E) 325

Solution: Buy as many $50 deals as possible. We can by   650/50= 
  650/50 = 13
13 two dozen roses, thus total of 13*24= 
13*24 = 312
312 roses.   We are left with   680 - 650= 
  680 - 650 = 30
$30. We can buy 30/6.3= ~4 roses for that amount.   Total = 312 + 4= 
312 + 4 = 316
316.   Answer: 316.
Answer: C
The class mean score on a test was 40, and the standard deviation was 15. If Jack's score was within 2 standard deviations of the mean, what is the lowest score he could have received? Choose the correct choice from the following options
A) 20
B) 31
C) 45
D) 90
E) 89

Solution: 1 SD from the mean is ADDING and Subtrating the amount if standard deviation from the mean one time. 2 SD from the mean is ADDING and Subtracting TWICE.   1SD from the mean ranges from 25 to 55, where 55 is within SD above the mean and 25 within 1SD below the mean   2SD=15 TWICE=30 from the the mean, which is 55 to 25, where 55 is within 2 SD above the mean AND 30 is within 2 SD below the mean.   20nswer = 20
Answer: A
John purchased some shirts and trousers for $1300. He paid $500 less for the shirts than he did for the trousers. If he bought 5 shirts and the cost of a shirt is $20 less than that of a trouser, how many trousers did he buy?	Options:
A) 4
B) 5
C) 6
D) 7
E) 9

Solution: Given that the total purchase of two items cost 1300   So the average purchase of one item will cost  1300/2= 
 1300/2 = 650
650.   Its given as total shirt cost 500$ less. Hence Total Shirt cost= 650 - 250 and Total trouser cost = 650 + 250   5 shirts = 400$ ==> One shirt = 80$   One trouser = 80 + 20= 
80 + 20 = 100
100$   Total trousers=900 / 100= 
900 / 100 = 9
9.   9
Answer: E
P and Q started a business investing Rs. 45,000 and Rs. 10,000 respectively. In what ratio the profit earned after 2 years be divided between P and Q respectively? Choose the correct choice from the following answers
A) 9:2 B) 4:5 C) 9:3 D) 17:9 E) 17:4

Solution: P:Q = 45000 : 10000   = 9:2   9:2nswer:9:2
Answer: A
A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?	Choose one
A) 7  B) 9  C) 8  D) 4  E) 5

Solution: 25 = E/(1000 - E) * 100   1000 - E = 4E   1000 = 5E => E = 200   1000 - 200 = 8   Answer:8
Answer: C
A sum of money is put out at compound interest for 2 years at 20%. It would fetch Rs.723 more if the interest were payable half-yearly, then it were pay able yearly. Find the sum.	Select:	A) 22200	B) 21897	C) 28799	D) 30000	E) 32782

Solution: P(11/10)^4 - P(6/5)^2 = 723   P = 30000   Answer: 30000
Answer: D
The negative and positive charge symbols are assigned (in that order) to the:	Choose the most appropriate option.
A) 22	B) 77	C) 77	D) 88	E) 21

Solution: Answer: Option 77
Answer: B
Albert invested Rs. 8000 in a scheme for 2 years at compound interest rate 5% p.a. How much amount will Albert get on maturity of the fixed deposit?
Choose the correct choice from the following choices:
A) 8840
B) 2776
C) 2998
D) 2662
E) 8820

Solution: Amount = [8000 * (1 + 5/100)2]   = 8000 * 21/20 * 21/20   = Rs. 8820   Answer: 8820
Answer: E
P is three times as fast as Q and working together, they can complete a work in 42 days. In how many days can Q alone complete the work?	Choose the correct choice from the following.
A) 16
B) 77
C) 56
D) 55
E) 778

Solution: P = 3Q   P + Q = 3Q + Q = 4Q   These 4Q people can do the work in 42 days, which means Q can do the work in 168 days.   Hence, P can do the work in 56 days.   Answer:56
Answer: C
Tom is 7 years older than Sam, and Jack is thrice as old as Tom. If S is Sam’s age and J is Jack’s age, what is the relationship between S and J? Choices:
A) J = 3S + 10  B) J = 3S + 21  C) J = 3S + 5  D) J = 3S − 11  E) J = 3S − 4

Solution: T=S+7 and J=3T --> J=3S+21   Answer J = 3S + 21
Answer: B
If the least common addition of two prime numbers x and y is 36, where x < y, then the value of 4x + y is
Pick one
A) 32 B) 45 C) 59 D) 73 E) 87

Solution: (x+y) = 36 and both x an y are prime.   The only values of x and y can be 17 and 19 (x = 17 and y = 19)   4x + y = 4*17 + 19= 
4*17 + 19 = 87
87   Correct Option: 87
Answer: E