MU-NLPC/Calc-aqua_rat huggingface dataset:
Pipe A can fill a tank in 5 hours, pipe B in 10 hours and pipe C in 30 hours. If all the pipes are open, in how many hours will the tank be filled?
Choose the correct choice from the following:	A) 2	B) 2.5	C) 3	D) 3.5	E) None

Solution: Sol.   Part filled by (A + B + C) in 1 hour = (1/5 + 1/10 + 1/30) = 1/3.   ∴ All the three pipes together will fill the tank in 3 hours.   Answer 3
Answer: C
In a secondary school the seats for Maths, physics and social studies are in the ratio 8 : 5 : 7. there is a proposal to increase these seats by 75%, 40% and 50% respectively. What will be the new ratio?	Choose the correct choice from the following choices: A) 5 : 3 : 4 B) 4 : 2 : 3 C) 10 : 7 : 9 D) 1 : 3 : 4 E) None of these

Solution: Explanation :   Solution: Originally, let the number of seats for Maths, physics and social studies be 8x, 5x and 7x respectively.   Number of increased seats are (175% of 8x), (140% of 5x) and (150% of 7x).   i.e. (175*7x/100), (140*5x/100) and(150*7x/100) i.e. 14x, 7x and 21x/2.   .'. Required ratio = 14x : 7x : 21x/2 = 28x : 14x : 21x = 4 : 2 : 3   Answer : 4 : 2 : 3
Answer: B
X is 3 times as fast as Y and is able to complete the work in 40 days less than Y. Find the time in which they can complete the work together?
Options:
A) 15 days
B) 16 days
C) 17 days
D) 18 days
E) 19 days

Solution: If X can complete work in x days and y can complete work in 3x days.   Then 2x = 40   x= 20 days.   so X can complete work in 20 days and y can complete work in 60 days.   they can complete the work together in 1/(1/20 + 1/60) = 1/ (4/60)= 
1/ (4/60) = 15
15 days   15 daysNSWER:15 days
Answer: A
The C.P of 10 pencils is equal to the S.P of 12 pencils. Find his gain % or loss%? Choose the most appropriate option.
A) 18 2/3%  B) 58 2/3%  C) 16 2/3%  D) 46 2/3%  E) 6 2/3%

Solution: Option 16 2/3%   Explanation:   10 16 2/3%P = 12 SP   12 --- 2 16 2/3%P loss   100 --- ? => 16 2/3%
Answer: C
Of the 100 athletes at a soccer club, 40 play defense and 66 play midfield. If at least 20 of the athletes play neither midfield nor defense, the number of athletes that play both midfield and defense could be any number between
Options:
A) 10 to 20  B) 10 to 40  C) 26 to 40  D) 30 to 70  E) 40 to 70

Solution: First of all notice that since only 40 athletes play defense, then the number of athletes that play both midfield and defense cannot possibly be greater than 40.Eliminate D and E.   {Total} = {defense} + {midfield} - {both} + {neither}   100 = 40 + 66 - {both} + {neither}   {both} = {neither} + 6.   Since the least value of {neither} is given to be 20, then the least value of {both} is   20+6= 
  20+6 = 26
26.Eliminate A and B.   Answer: 26 to 40.
Answer: C
A and B started a business investing Rs. 21,000 and Rs. 28,000 respectively. Out of a total profit of Rs. 14,000, B’s share is :	Choices.
A) 7600
B) 7700
C) 7800
D) 7900
E) 8000

Solution: Ratio of their shares = 21000 : 28000 = 3 : 4.   B’s share = Rs. 14000 * 4/7   = Rs. 8000   ANSW8000R:8000
Answer: E
When positive integer N is divided by positive integer J, the remainder is 10. If N/J = 205.08, what is value of J?	Choose the correct choice from the following choices.
A) 125
B) 100
C) 75
D) 150
E) 50

Solution: When a number is divided by another number, we can represent it as : Dividend = Quotient * Divisor + Remainder   So, Dividend/Divisor = Quotient + Remainder/Divisor   Given that N/J = 205.08   Here 205 is the quotient.   Given that Remainder = 10   So, 205.08 = 205 + 10/J   So, J = 125   125nswer: 125
Answer: A
A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:  Choose the correct answer:
A) 18	B) 24	C) 42	D) 81	E) 90

Solution: Explanation:   Let the ten's and unit's digit be x and 8/x respectively.   Then,   (10x + 8/x) + 18 = 10 * 8/x + x   9x2 + 18x - 72 = 0   x2 + 2x - 8 = 0   (x + 4)(x - 2) = 0   x = 2   So, ten's digit = 2 and unit's digit = 4.   Hence, required number = 24.   ANSWER IS 24
Answer: B
For any integer k greater than 1, the symbol k* denotes the product of all the fractions of the form 1/t, where t is an integer between 1 and k, inclusive. What is the value of 1*/4* ?  Pick
A) 5  B) 5/4  C) 4/5  D) 1/4  E) 1/5

Solution: When dealing with 'Symbolism' questions, it often helps to 'play with' the Symbol for a few moments before you attempt to answer the question that's asked. By understanding how the Symbol 'works', you should be able to do the latter calculations faster.   Here, we're told that K* is the PRODUCT of all the fractions of the form 1/T, where T is an integer between 1 and K, inclusive.   Based on this definition....   IF....   K = 2   K* = (1/1)(1/2) = 1/2   IF....   K = 3   K* = (1/1)(1/2)(1/3) = 1/6   We're asked to find the value of 5*/4*   Now that we know how the Symbol 'works', solving this problem shouldn't be too difficult. You can actually choose to do the math in a couple of different ways....   5* = (1/1)(1/2)(1/3)(1/4)(1/5)   Don't calculate this just yet though....since we're dividing by 4*, many of those fractions will 'cancel out.'   4* = (1/1)(1/2)(1/3)(1/4)   We're looking for the value of:   (1/1)(1/2)(1/3)(1/4)(1/5) / (1/1)(1/2)(1/3)(1/4)   Since the first four fraction in the numerator and denominator cancel out, we're left with just one fraction:   4/5   5
Answer: A
Amber works 28 days a month at d dollars per day for m months out of the year. Which of the following represents her monthly pay? Choose the correct choice from the following answers
A) m/(20d)  B) 20d  C) 10md/6  D) 28d  E) 20md

Solution: ANSWER: 28d The passage states that she works 28 days a month at d dollars per day, so 28 d is her monthly pay
Answer: D
A certain university will select 1 of 7 candidates eligible to fill a position in the mathematics department and 2 of 11 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions? Choose the most appropriate option:
A) 42	B) 70	C) 140	D) 165	E) 385

Solution: Ans: 385   7C1 * 11C2   Answer 385)
Answer: E
At a florist shop on a certain day, all corsages sold for either $20 or $30. If 8 of the corsages that sold for $30 had instead sold for $20, then the store's revenue from corsages that day would have been reduced by 10 percent. What was the store's actual revenue from corsages that day?
Choose the correct choice from the following choices:
A) $200
B) $400
C) $600
D) $800
E) $1000

Solution: Let, No. of corsages @ $20 = x, no. of corsages @ $30 = y and revenue= r   so, 20x+30y=r.........(1)   Now,   Given the situation, 20(x+8) + 30(y-8)= r-.1r   => 20x+160+30y-240 = .9r   => 20x+30y = .9r+80............(2)   so, r = .9r+80   => r = 800   The answer is $800.
Answer: D
After getting 2 successive discounts, a shirt with a list price of Rs 150 is available at Rs 105. If the second discount is 12.55,find the first discount.
Choose the correct choice from the following answers
A) 22%
B) 18%
C) 24%
D) 17%
E) 20%

Solution: Let the first discount be x%   Then,87.5% of (100-x)% of 150= 105   =	87.5/100*(100-x)/100*450=150=>105=>100-x=(105*100*100)/(150*87.5)= 
(105*100*100)/(150*87.5) = 80
80   x=(100-80)= 
(100-80) = 20
20   first discount= 20%   Answer is 20%.
Answer: E
How many times digit 6 is used while writing numbers from 100 to 1100?  Options:
A) 648
B) 320
C) 252
D) 225
E) 26

Solution: There are 100 numbers which begin with 600   Next, In every 10 numbers such as 100 to 110, 110 to 120, 120 to 130 6 comes at least once. Number of such intervals = End limit - First no. / interval. Our range of numbers is 100 - 1000   1000 - 100= 
1000 - 100 = 900
900/10= 
900/10 = 90
90   Number of 10s interval in this is 90. So 90 '6s'   So far we have calculated 190.   The total now comes to 280. The nearest to which is 320. Hence 320.
Answer: B
Find large number from below question The difference of two numbers is 1355. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder
Choose the correct option.
A) 1234
B) 1265
C) 1350
D) 1467
E) 1623

Solution: Let the smaller number be x. Then larger number = (x + 1355).   x + 1355 = 6x + 15   5x = 1340   x = 268   Large number = 268+1355= 
268+1355 = 1_623
1623   1623
Answer: E
In the accounting branch of a commercial institute, the percentage of male and female workers is 48% and 52% respectively. In this branch, 40% of males and 20% of females are age 25 or older. If one of the workers is selected at random, what is the probability that the worker is under 25 years old? Options.
A) 0.3	B) 0.25	C) 0.45	D) 0.7	E) 0.9

Solution: Percentage of male worker = 48   Percentage of female worker = 52   Let total number of workers = 1000   number of male workers= 480   number of female workers = 520   Number of male age 25 or older = (4/10)*480= 
(4/10)*480 = 192
192   Number of female age 25 or older=(2/10)*520= 
(2/10)*520 = 104
104   Total number of workers 25 or older= 192+104= 
192+104 = 296
296   Total number of workers under 25= 1000 - 296= 
1000 - 296 = 704
704   Probability that a worker randomly selected is under 25 years old= 704/1000= 
704/1000 = 88/125 = around 0.704
.704   Alternatively , since the answer options are not close , we can use estimation here .   Percentage of male worker 25 or older= (4/10)*48 = 20 % approx   Percentage of female worker 25 or older = (2/10)*52 = 10 % approx   Percentage of total worker 25 or older = 30 %   Percentage of total worker under 25 = 70 %   Probability that a worker randomly selected is under 25 years old = .7   Answer 0.7
Answer: D
For a certain set of numbers, if x is in the set, then x - 3 is also in the set. If the number 2 is in the set , which of the following must also be in the set ?
a) 4
b) -4
c) -5 Select the correct option
A) a only, B) b only, C) c only, D) a and b only E) b and c only

Solution: Notice that the question asks which of the following MUST be in the set, not COULD be in the set.   Since 2 is in the set, then so must be 2-3=-1. Similarly, since -1 is in the set, then so must be -1-3=-4. Could 4 and -1 be in the set? Certainly, but we don't know that for sure.   Answer: B.   Regarding your question: we don't know which is the source integer in the set, if it's 1, then 4 won't be in the set but if the source integer is say 7, then 4 will be in the set. So, 4 may or may not be in the set.
Answer: B
The area of Circle O is added to its diameter. If the circumference of Circle O is then subtracted from this total, the result is 4. What is the area of Circle O?
Choose the correct choice from the following answers.
A) 2/π  B) 2  C) 8  D) 4  E) 4π

Solution: area+diameter-circumference=4   pi*r^2+2r=4+2pi*r   isolate r and get r(pi*r+2)=4+2pi*r   r=(4+2pi*r)/(pi*r+2) =>2(2+pi*r)/(pi*r+2)   r=2   Area = pi * r^2 => pi * 4   4π
Answer: E
Suppose that AB = AC = CD and
AD = BD. What is the measure of
6 ADC in degrees?	Choose the correct answer:	A) 24	B) 28	C) 32	D) 36	E) 40

Solution: Let be the measure of \ADC. Then since ADC is isosceles, we obtain that   the measures of \CAD and \DCA are and 180 􀀀 2, respectively. It follows that   \ACB has measure 2. Since ACB is isosceles, we obtain that the measures of \CBA   and \BAC are 2 and 180 􀀀 4, respectively. Since ADB is isosceles, we deduce that   the measures of \CBA and \BAD are the same. This gives that 2 = (180 􀀀 4) +   which implies 5 = 180. Therefore, = 36.   correct answer 36
Answer: D
In the coordinate plane, Line A has a slope of -1 and an x-intercept of 2. Line B has a slope of 5 and a y-intercept of -10. If the two lines intersect at the point (a,b), what is the sum a+b?	Choose the most appropriate option
A) 0 B) 1 C) 2 D) 3 E) 4

Solution: The equation of Line A is y = -x + 2   The equation of Line B is y = 5x - 10   5x - 10 = -x + 2   x = 2   y = 0   The point of intersection is (2,0) and then a+b = 2.   The answer is 2.
Answer: C
If the circus were to sell all of its 220 tickets for this month's performance at its usual price, the revenue from sales would be 10% greater than that collected last month. If the circus raised the ticket price by 5% and sold only 200 tickets as a result, what percent less would last month's revenue be compared to this month's revenue?	Pick one.
A) 2  B) 5  C) 100/21  D) 110/20  E) 9/4

Solution: Last months revenue can be calculated as 220x / 1.10 = 200x   Now consider the next statement - > if the price of ticket is hiked by 5% the new price is 1.05 x.   So the new revenue when only 200 tickets are sold 220  / 1.10= 
220  / 1.10 = 200
200x   Now consider the next statement - > if the price of ticket is hiked by 5% the new price is 1.05 x.   So the new revenue when only 200 tickets are sold= 200 * 1.05= 
200 * 1.05 = 210
210x.   We need to find the percentage difference ; so we have (new-old/new*100) 210x-200x/210x*100= 100/21   Answer: 100/21
Answer: C
The ratio of 2 numbers is 1:2 and their H.C.F. and L.C.M are 10 and 20. Find the numbers. Choose the correct choice from the following choices
A) 20, 10
B) 10, 20
C) 20, 30
D) 30, 20
E) 10, 10

Solution: Let the numbers be x and 2x   Their H.C.F. = 10   L.C.M = 20   ie) 2x^2 = 200   x^2 = 100, x = 10 t The numbers are x and 2x , ie)10, 20 respectively.   Answer is 10, 20
Answer: B
By how much is two-fifth of 500 greater than five - seventh of 210 ?
Select:
A) 50  B) 75  C) 120  D) None of these  E) Cannot be determined

Solution: Solution   2/5of 500 - 5/7 of 210 = 50.   50nswer 50
Answer: A
The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest?
Pick one:
A) 80 years  B) 70 years.  C) 20 years.  D) 30 years.  E) 20 years.

Solution: Present total age of the members = 26(5) = 130 years.   Present age of the youngest member = 10 years   Present total age of the remaining four members = 130 -10= 
130 -10 = 120
120 years   Their average age at the time of the birth of the youngest member= [120 - (4 * 10)] / 4 = 30 - 10= 
30 - 10 = 20
20 years.   Answer: 20 years.
Answer: C
If m and n are positive integers, and m=2n and k=2m, then -  Choices
A) 2m is a factor of k.	B) m/2 is a factor of k.	C) 3m is a factor of k/2.	D) k is a factor of m.	E) k is a factor of m/2.

Solution: m=2n --> m is even.   k=2m --> m is factor of k, thus m/2 = integer must also be a factor of k.   Answer: m/2 is a factor of k..
Answer: B
A and B began business with Rs.3000 and Rs.4000 after 8 months, A withdraws Rs.1000 and B advances Rs.1000 more. At the end of the year, their profits amounted to Rs.630 find the share of A?	Pick one
A) 240
B) 288
C) 266
D) 216
E) 123

Solution: (3*8 + 2*4):(4*8 + 5*4)   8:13   8/21 * 630= 
8/21 * 630 = 240
240   240nswer: 240
Answer: A
If |x^2 − 12| = x, which of the following could be the value of x?  Select:  A) -4  B) -3  C) 1  D) 2  E) 3

Solution: |x2−12|=x|x2−12|=x   |x2−12||x2−12|cannot be negative; anything that comes out of mod is always positive   so |x2−12|>0|x2−12|>0   Out of our options A= -4 B= -3 cannot be the right answer because none of them are greater than 0   Now only Option C=1 or D=2 or E=3 are contenders for right answers.   A quick Cursory crude calculation will tell you that 3 is the right choice   |−32−12|=3|−32−12|=3   |9−12|=3|9−12|=3   |−3|=3|−3|=3   3=33=3   ANSW3R IS 3
Answer: E
If log 27 = 1.437, then the value of log 9 is:  Select.
A) 0.934  B) 0.945  C) 0.954  D) 0.958  E) 0.998

Solution: log 27 = 1.437   log (3cube ) = 1.437   3 log 3 = 1.437   log 3 = 0.479   log 9 = log(3square ) = 2 log 3 = (2 x 0.479) = 0.958.   Answer: Option 0.958
Answer: D
P can do the work in 12 days and Q can do the same work in 15 days. If they work together for 4 days, what is the fraction of work that is left? Choose the correct answer: A) 1/5 B) 2/5 C) 7/15 D) 11/15 E) 23/30

Solution: 4/12 + 4/15 = 1/3 + 4/15 = 9/15 = 3/5 (completed work)   The work that is left is 1 - 3/5 = 2/5   The answer is 2/5.
Answer: B
A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. If field has a length that is twice its width, find the area of the field in square meters. Choose the correct option:
A) 10,000 square meters
B) 20,000 square meters
C) 30,000 square meters
D) 40,000 square meters
E) 50,000 square meters

Solution: Let us first find the distance d jogged   distance = rate ? time = (12 km / hr) ? 30 minutes   = (12 km/hr) ? 0.5 hr = 6 km   The distance of 6 km corresponds to 10 perimeters and therefore 1 perimeter is equal to   6 km / 10 = 0.6 km = 0.6 ? 1000 meters = 600 meters   Let L and W be the length and width of the field. The length is twice the width. Hence   L = 2 W   The perimeter is 600 meters and is given by   2 (L + W) = 600   Substitute L by 2 W   2 (2 W + W) = 600   Simplify and solve for W   4 W + 2 W = 600   6 W = 600   W = 100   Find L   L = 2 W = 200   Find the area A of the rectangle   A = L * W = 200 * 100 = 20,000 square meters   correct answer 20,000 square meters
Answer: B
A merchant marks his goods up by 40% and then offers a discount of 10% on the marked price. What % profit does the merchant make after the discount?
Choose the correct option:
A) 8%  B) 14%  C) 26%  D) 15%  E) 17%

Solution: Let the price be 100.   The price becomes 140 after a 40% markup.   Now a discount of 10% on 126.   Profit=126-100   26%   answer 26%
Answer: C
A committee of 6 is chosen from 6 men and 5 women so as to contain at least 2 men and 3 women. How many different committees could be formed?
Answers: A) 275 B) 700 C) 1404 D) 2620 E) 3510

Solution: The only cases possible are :   1. 2 men and 4 women : 6C2 * 5C4 = 75   2. 3 men and 3 women: 6C3*5C3 = 200   Rest of the cases will either have 1 or 0 men (not allowed) or will have 1 or 2 or 0 women (not allowed)   Total possible combinations = 75+200= 
75+200 = 275
275. Thus 275 is the correct answer.
Answer: A
The ratio of a to b is 4 to 5, where a and b are positive. If x equals a increased by 25 percent of a, and m equals b decreased by 40 percent of b, what is the value of m/x? Options
A) 2/5
B) 3/4
C) 4/5
D) 5/4
E) 3/5

Solution: a/b = 4/5   m/x = (3/5)*5 / (5/4)*4 = 3/5   The answer is 3/5.
Answer: E
A and B can do a piece of work in 6 days. With the help of C they finish the work in 3 days. C alone can do that piece of work in?
Choose the correct choice from the following answers:  A) 40 days  B) 16 days  C) 6 days  D) 5 days  E) 40 days

Solution: 6 days   6 days   6 days = 1/3 – 1/6 = 1/6 =>6 days
Answer: C
Sheela deposits Rs. 3400 in bank savings account. If this is 15% of her monthly income. What is her monthly income in?  Answers:  A) 22666  B) 20000  C) 25000  D) 22235  E) None of these

Solution: Explanation :   15% of income = Rs. 3400   100% of income = 3400 X 100/15 = Rs. 22666   22666nswer : 22666
Answer: A
In a box, there are 2 yellow, 4 grey and 4 white pencils. One pencil is picked up randomly. What is the probability that it is neither yellow nor grey?	Answers.
A) 2/5  B) 1/5  C) 3/5  D) 4/5  E) 5/6

Solution: Explanation :   Neither yellow nor grey means the pencil drawn is white.   Total number of outcomes = (2+4+4)= 
(2+4+4) = 10
10.   Number of Favourable outcomes= 4 = Number of white pencils.   Hence, Probability of the event = 4/10 = 2/5.   2/5nswer : 2/5
Answer: A
Which is the following is divisible by 11
Select the correct option:	A) A)4305	B) B)4825	C) C)6594	D) D)4905	E) E)4906

Solution: Explanation:   Sum of first 'n' natural numbers = n(n + 1)/2   Sum of first 9 natural numbers = 11(11 + 1)//2 = 11 x 6 = 66   Sum of first 99 natural numbers = 111(111 + 1)//2 = 111 x 60 = 6660   6660 - 66= 
6660 - 66 = 6_594
6594   Answer: Option 6594
Answer: C
A bag contains 2 red and 3 green balls. Another bag contains 4 red and 6 green balls. If one ball is drawn from each bag. Find the probability that one ball is red and one is green.  Answers
A) 19/20	B) 17/20	C) 21/25	D) 8/10	E) 9/40

Solution: Let A be the event that ball selected from the first bag is red and ball selected from second bag is green.   Let B be the event that ball selected from the first bag is green and ball selected from second bag is red.   P(A) = (2/5) x (6/10) = 6/25.   P(B) = (3/5) x (4/10) = 6/25.   Hence, the required probability is P(A) + P(B) which is nothing but 21/25.   ANSWER:21/25
Answer: C
If an object travels at five feet per second, how many feet does it travel in one hour?  Choices: A) 1700 B) 1900 C) 1400 D) 1600 E) 1800

Solution: If an object travels at 5 feet per second it covers 5x60 feet in one minute, and 5x60x60 feet in one hour.   Answer = 1800   Answer is 1800.
Answer: E
Which of the following options is an appropriate approximate value in the following equation’? 625.3 of 165.83+42% of 1560= ? - 625.7	Choose the most appropriate option:
A) 104875.3  B) 12825.3  C) 1034825.3  D) 104425.3  E) 104825.3

Solution: 625.3 of 165.83+42% of 1560= ? - 625.7   103693.5+506.1= ? - 625.7   103693.5+506.1 + 625.7= 
103693.5+506.1 + 625.7 = 104_825.3
?   ≈ 104825.3   Answer 104825.3
Answer: E
9 neighbors are to split the cost of topsoil. The cost of the 5 truck loads of dirt was $690.47. What is the least amount of money (in whole number of dollars) that they must add to bill if they wants to split this money evenly among his nine neighbors?	Choose the correct choice from the following options:
A) 690.48
B) 690.49
C) 690.5
D) 690.51
E) 690.52

Solution: If the bill was $690.47 dollars, how much money should be removed with 1 cent as the smallest unit?   This is equivalent to finding the first number that is divisible by 9 that occurs after 690.47.   In order to divide the sum in 9 parts, the amount must be divisible by 9   Divisibility rule of 9: The sum of the digits must be divisible by 9   Sum of digits of   6+9+0+4+7= 
  6+9+0+4+7 = 26
26. If you add 1 , the number is divisible by 9 (26 +1). 27 is divisible by 9.   Hence, we need to add 1 cent from this number for it to be divisible by 9.   Correct Option : 690.48
Answer: A
A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked at 7 miles per hour for 2 hours. How many miles in total did she walk?
Choose the correct answer
A) 24 B) 52 C) 58 D) 60 E) 62

Solution: First day - 18 miles with 3 miles per hours then total - 6 hours for that day   Second day - 4 miles per hour and 5 hours - 20 miles   Third day - 7 miles per hour and 2 hours - 14 miles   Total 18+20+14= 
18+20+14 = 52
52   Answer: option 52.
Answer: B
At the end of the first quarter, the share price of a certain mutual fund was 20 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 60 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter?  Choose the correct option:
A) 20% B) 25% C) 30% D) 33.33% E) 40%

Solution: Another method is to use the formula for 2 successive percentage changes:   Total = a + b + ab/100   60 = 20 + b + 20b/100   b = 33.33   Answer (33.33%)
Answer: D
A man can row upstream at 60 kmph and downstream at 90 kmph, and then find the speed of the man in still water?	Choose the correct choice from the following choices.
A) 75 kmph  B) 65 kmph  C) 30 kmph  D) 73 kmph  E) 65 kmph

Solution: US = 60   DS = 90   M = (60 + 90)/2= 
(60 + 90)/2 = 75
75   75 kmphnswer:75 kmph
Answer: A