MU-NLPC/Calc-aqua_rat huggingface dataset:
L.C.M of two numbers is 192 and there H.C.F is 16. If one of them is 48. Find the other	Pick.
A) 32	B) 64	C) 48	D) 68	E) 78

Solution: Explanation:   Product of two numbers = product of their L.C.M and H.C.F   48 x a = 192 x 16   a = (192 x 16)/48 = 64   Answer: Option 64
Answer: B
A Cistern is filled by pipe A in 8 hrs and the full Cistern can be leaked out by an exhaust pipe B in 12 hrs. If both the pipes are opened in what time the Cistern is full? Choose the most appropriate option:
A) 12 hrs B) 24 hrs C) 16 hrs D) 32 hrs E) None of these

Solution: Explanation :   Pipe A can fill 1⁄8 of the cistern in 1 hour.   Pipe B can empty 1⁄12 of the cistern in 1 hour   Both Pipe A and B together can effectively fill 1⁄8-1⁄12= 1⁄24 of the cistern in 1 hour   i.e, the cistern will be full in 24 hrs. Answer : Option 24 hrs
Answer: B
Among the employees of a certain company, 52 percent of the employees are male and 48 percent are female. In this company 60 percent of the male employees are married and 50 percent of the female employees are married. If one employee in the company is randomly selected, approximately what is the probability that he or she is NOT married?	Select:
A) 0.4
B) 0.3
C) 0.5
D) 0.6
E) 0.7

Solution: Much faster: draw 4 quadrants   ______________Male (52%)_____Female (48%)   Married :__________60%____________40%   Not Married:_______30%____________50%   Therefore: the probability of picking one random person Not Married (he or she) is: 0,52 x 0,30 + 0,50 x 0,50 = 0,15 + 0,25 (approx.)   Solution: approx. 0,4 (answer 0.4)
Answer: A
There are 50 employees in the office of ABC Company. Of these, 22 have taken an accounting course, 15 have taken a course in finance and 14 have taken a marketing course. Nine of the employees have taken exactly two of the courses and 3 employee has taken all three of the courses. How many of the 50 employees have taken none of the courses?  Pick:
A) 9  B) 8  C) 14  D) 10  E) 11

Solution: 50 Employees. Counting every different attendand to the courses we have:   Accounting: 22   Finance: 15   Marketing: 14   Which would add up to 51 different attendands, which is not possible.   Now 9 have taken exactly 2 courses, which means that there are 9 less different attendands. Say that 9 of the Finance attentands also attended Accounting.   51-9= 
51-9 = 42
42   3 Person has taken all three courses. As above, we subtract him from the number of different attendands. Since this time the person took all three courses, we have to substract him two times.   42-6= 
42-6 = 36
36.   Answer : 14
Answer: C
Define r* by the equation r* = π-r. Then ((−π)*)* =  Choose the correct option:
A) −2π  B) -1  C) −π  D) 2π  E) 4π

Solution: for r* f(f(−π)) = f(π − (−π)) = f(π + π) = f(2π) = π − 2π = −π=−π
Answer: C
In how many ways the word "DARKEST" can be arranged?	Choose the correct choice from the following answers:
A) 5040 B) 4506 C) 3450 D) 8900 E) Cannot be determined

Solution: Explanation :   The required number of ways = 7!   = 5040   5040nswer : 5040
Answer: A
A boat goes 100 km downstream in 10 hours, and 75 m upstream in 15 hours. The speed of the stream is?  Answers:
A) 1 B) 2 C) 3 D) 4 E) 5

Solution: DS = 6   US = 4   S = ?   S = (6 - 4)/2= 
(6 - 4)/2 = 1
1 kmph 1nswer: 1
Answer: A
A chartered bank offers a five-year Escalator Guaranteed Investment Certificate.In successive years it pays annual interest rates of 4%, 4.5%, 5%, 5.5%, and 6%, respectively, compounded at the end of each year. The bank also offers regular five-year GICs paying a fixed rate of 5% compounded annually. Calculate and compare the maturity values of $1000 invested in each type of GIC. (Note that 5% is the average of the five successive one-year rates paid on the Escalator GIC.) Choose the correct choice from the following answers
A) 1276.28 B) 1276.22 C) 1276.29 D) 1276.21 E) 1276.23

Solution: Explanation:   FV = $1000(1.04)(1.045)(1.05)(1.055)(1.06) = $1276.14   the maturity value of the regular GIC is   FV = $= $1276.28   1276.28nswer: 1276.28) 1276.28
Answer: A
Each side of a certain parallelogram has length 5. If the area of the parallelogram is 20. Which of the following is the measure of one of its angles? Pick:
A) 30 B) 45 C) 53.13 D) 90 E) 120

Solution: area of a parallelogram = b*h   b*h=20   h=20/5= 
20/5 = 4
4   sin theta=opp/hyp= 4/5   theta = sin inv of 4/5=53.13 deg   53.13
Answer: C
January 1, 2008 is Wednesday. What day of the week lies on Jan 1, 2009?  Pick one:	A) Saturday	B) Wednesday	C) Thursday	D) Tuesday	E) Friday

Solution: Explanation:   Number of odd days in 2008 = 2 (since it is a leap year)   (we have taken the complete year 2008 because we need to find out the odd days from 01-Jan-2008 to 31-Dec-2008, that is the whole year 2008)   Given that January 1, 2008 is Wednesday.   Hence January 1, 2009 = (Wednesday + 2 odd days) = Friday   Answer: Option Friday
Answer: E
Find the Value of X :log(x+1) + (log(x-1) = log8	Answers.
A) 5	B) 3	C) 6	D) 9	E) 8

Solution: Explanation:   log(x+1)(x-1) = log8   log(x^2-1) = log8   x^2-1 = 8   x^2 = 9   x = {-3, 3}   Testing for extraneous solutions eliminates -3 leaving you with:   x = 3   Answer 3
Answer: B
The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child ?  Pick:
A) 4 years B) 8 years C) 10 years D) 12 years E) None

Solution: Solution   Let the ages of the children be x,(x+3),(x+6),(x+9) and (x+12) years.   Then,	x+(x+3)+(x+6)+(x+9)+(x+12)=50   5x=20   x=4.   Age of the youngest child	=4 years.   4 yearsnswer 4 years
Answer: A
A plane flies 420 miles with the wind and 350 miles against the wind in the same length of time. If the speed of the wind is 23 mph, what is the speed of the plain in still air?  Choose the correct choice from the following options:
A) 196	B) 210	C) 216	D) 235	E) 253

Solution: The speed of the plane in still air = x miles/hour   The speed of the wind is 23 mph   Speed with the wind = (x + 23) mph   Speed against the wind = (x – 23) mph   Time = Distance/ Speed   According to the problem,   420/(x + 23) = 350/(x – 23)   420(x – 23) = 350(x + 23)   420x – 9660 = 350x + 805   420x – 350x = 8050 + 9660   70x = 17710   x = 17710/70= 
17710/70 = 253
253 ANSW253R : 253
Answer: E
If the time is currently 1:30 pm, what time will it be in exactly 643 hours? Choose the most appropriate option:	A) 5:30 am	B) 6:30 am	C) 7:30 am	D) 8:30 am	E) 9:30 am

Solution: 643 = 26(24) + 19/24   The time will be 19 hours later than 1:30 pm which is 8:30 am.   The answer is 8:30 am.
Answer: D
The ratio of the cost price and selling price is 2:3. The profit percent is?  Choose the correct choice from the following answers:
A) 20% B) 25% C) 50% D) 75% E) 100%

Solution: Let the C.P. = $2x   Then S.P. = $3x   Then, Gain = 3x-2x = $x   Gain% = x/2x *100 = 50%   Answer is 50%
Answer: C
In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?
Choose the correct choice:
A) 12  B) 15  C) 18  D) 24  E) 26

Solution: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways   4: Or 4p = — 4:- 4X3X2X1- 24 ways   24
Answer: D
A boy traveled from the village to the post-office at the rate of 12.5 kmph and walked back at the rate of 2 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village.  Choose the correct choice from the following choices.
A) 5 km
B) 7 km
C) 9 km
D) 10 km
E) 12 km

Solution: Explanation :   Solution: Average speed = 2xy/(x+y) km/hr   = (2*12.5*2)/(12.5+2) km/hr   = 50/14.5 km/hr.   Total distance = (50/14.5 * 29/5) km.   = 20 km.   Required distance = 20/2= 
20/2 = 10
10 km.   Answer : 10 km
Answer: D
The first flight out of Phoenix airport had a late departure. If the next three flights departed on-time, how many subsequent flights need to depart from Phoenix on-time, for the airport's on-time departure rate to be higher than 40%?
I will see what is the quickest way to solve it then I will provide the explanation
Choose one
A) 6  B) 2  C) 9  D) 10  E) 11

Solution: The following approach might be the easiest one and less error prone.   We need on-time departure rate to be higher than 4/10, so it should be at least 5/11, which means that 5 out of 11 flights must depart on time. Since for now 3 out of 4 flights departed on time then  5-3= 
 5-3 = 2
2 subsequent flights need to depart on-time.   Answer: 2.
Answer: B
There are 5 pairs of socks and 2 socks are worn from that such that the pair of socks worn are not of the same pair. what is the number of pair that can be formed. Choose the most appropriate option.
A) 19  B) 20  C) 30  D) 32  E) 25

Solution: First of all you should remember that there is a difference in left and right sock.   now no. of way to select any of the sock = 5   and for second = 4   so total methods = 5*4= 
5*4 = 20
20   ANSWER:20
Answer: B
Due to construction, the speed limit along an 4-mile section of highway is reduced from 55 miles per hour to 35 miles per hour. Approximately how many minutes more will it take to travel along this section of highway at the new speed limit than it would have taken at the old speed limit ? Choose the correct answer:
A) A) 3.12
B) B) 8
C) C) 2.49
D) D) 15
E) E) 24

Solution: Old time in minutes to cross 4 miles stretch = 4*60/55 = 4*12/11 = 4.36   New time in minutes to cross 4 miles stretch = 4*60/35 = 4*12/7 = 6.85   Time difference = 2.49   Ans:2.49
Answer: C
What least number must be subtracted from 427398 so that remaining no.is divisible by 10
Choose the correct choice.
A) 3
B) 5
C) 6
D) 7
E) 8

Solution: 8xplanation:   On dividing 427398 by 10 we get the remainder 8, so 8 should be subtracted   Answer: Option 8
Answer: E
A batsman in his 20th innings makes a score of 90, and thereby increases his average by 2. What is his average after the 20th innings? He had never been ’not out’. Select:	A) 52	B) 37	C) 39	D) 43	E) 42

Solution: 52verage score before 20th innings   = 90 - 2 × 20= 50   52verage score after 20th innings   => 50 + 2= 
50 + 2 = 52
52   52NSWER:52
Answer: A
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle?
Select
A) 6m B) 5m C) 2m D) 8m E) 3m

Solution: Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   => l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   => (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 => l + b = 14   12(l + b)2 = 49lb   => 12(14)2 = 49lb   => lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
8 - 6 = 2
2m.   Answer:8m
Answer: D
Four milkmen rented a pasture. A grazed 24 cows for 3 months; B 10 for 5 months; C 35 cows for 4 months and D 21 cows for 3 months. If A's share of rent is Rs. 2880, find the total rent of the field.	Pick one:
A) 3750  B) 3550  C) 4250  D) 2250  E) 13000

Solution: Ratio of shares of A, B, C, D = (24 x 3) : (10 x 5) : (35 x 4) : (21 x 3) = 72 : 50 : 140 : 63.   Let total rent be Rs. x. Then, A’s share = Rs. (72x)/325   (72x)/325=2880 = x=(2880 x 325)/72 = 13000   Hence, total rent of the field is Rs. 13000.   Answer is 13000.
Answer: E
What is the remainder when 3^30 is divided by 5?
Choose the correct answer.
A) 0 B) 1 C) 2 D) 3 E) 4

Solution: The units digit of powers of 3 follow a repeating cycle of four: {3, 9, 7, 1}   30 has the form 4k+2, so the units digit of 3^30 is 9.   The remainder when dividing by 5 is 4.   The answer is 4.
Answer: E
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is?  Select the correct option:  A) 8.09%  B) 6.07%  C) 1.09%  D) 6.09%  E) 2.09%

Solution: Explanation:   Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 - 100)= 
(106.09 - 100) = 6.09
6.09%   Answer: 6.09%
Answer: D
The perimeter of an isosceles right triangle is 8 + 8 sq rt 2. What is the length of the hypotenuse of the triangle?  Pick one:	A) 4	B) 5.656	C) 5	D) 6	E) 7

Solution: side of triangle is a then perimeter = a+ a +a.sqrt2 ( right angle and pythagorus) =2a +a .sqrt 2 = 8 + 8 Sqrt2 or,   a. ( 2+ sqrt2) = 8(1 + sqrt2), a= 8*(1+sqrt2)/2+sqrt2 =8*2.414/3.414 =0.707*8= 
0.707*8 = 5.656
5.656   5.656
Answer: B
Shekar scored 76, 65, 82, 67 and 85 marks in Mathematics, Science, Social studies, English and Biology respectively. What are his average marks?  Pick:	A) 65	B) 69	C) 75	D) 85	E) 90

Solution: Explanation :   Average= (76+65+82+67+85)/5 = 375/5= 
375/5 = 75
75   Hence average=75   Answer : 75
Answer: C
If cost of 15 eggs be 75 rupees, then find out the cost of 5 dozen eggs.
Choose the correct choice:
A) 300
B) 400
C) 500
D) 600
E) 700

Solution: Cost of 15 eggs = 75 rupees   Cost of 1 egg = 75/15= 
75/15 = 5
5 rupees,   Cost of 5 dozens, i.e. 5 x 12= 60 x 5 = 300   300nswer : 300
Answer: A
A student was asked to find the arithmetic mean of the numbers 3,11,7,9,15,13,8,19,17,21,14 and x. He found the mean to be 12. What should be the remainder in the place of x? Choose the correct choice from the following answers:
A) 5	B) 6	C) 7	D) 8	E) 9

Solution: We have (3+11+7+9+15+13+8+19+17+21+14+x) / 12 = 12   137+x = 144   x = 7   Answer is 7
Answer: C
Find the minimum value of 5cosA + 12sinA + 12
Choose the correct option.
A) -1  B) 1  C) 2  D) 3  E) None of these

Solution: Solution:   5cosA +12sinA + 12 = 13(5/13 cosA +12/13sinA) + 12   Now, for any values of B we can get sinB =5/13 and we can replace cosB = 12/13.   We see that our assumption is right because we satisfy the condition sin^2B + cos^2B=1 so we get 13(sinBcosA +cosBsinA) + 12 =13(sin(A+B))+12. Therefore we know that minimum value of sinx=-1 and greatest is 1 so the least value of the expression becomes when sin(-1+B) =-1 then the value of the whole term becomes 13.(-1) + 12 = -13 +12 = -1   -1nswer -1
Answer: A
The average (arithmetic mean) of 4 different integers is 70. If the largest integer is 90, what is the least possible value of the smallest integer?  Choices:
A) 1 B) 19 C) 29 D) 13 E) 33

Solution: Total of Integers=70*4= 
70*4 = 280
280   Lowest of the least possible integer is when the middle 2 intergers are at the maximum or equal to the highest possible integer.   But all integers are distinct. So if the largest integer is 90, then the middle 2 will be 88 and 89   Lowest of least possible integer= 280-(90+89+88)=280-267= 
280-267 = 13
13   Answer: 13
Answer: D
In a school with 620 students, the average age of the boys is 12 years and that of the girls is 11 years. If the average age of the school is 11 years 9 months, then the number of girls in the school is
Pick.
A) 150  B) 200  C) 155  D) 350  E) None

Solution: Sol.   Let the number of grils be x.   Then, number of boys = (620 - x).   Then, (11 3/4 × 620)   ⇔ 11x + 12(620 - x) ⇔ x = 7440 - 7285 ⇔ 155.   Answer 155
Answer: C
An article costing rs.300 is sold at 10% discount on a mark-up price. What is the selling price after
discount?	Options
A) 270	B) 116	C) 126	D) 136	E) 146

Solution: 300*90/100= 
300*90/100 = 270
270   270NSWER:270
Answer: A
A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?  Choose the correct choice from the following.
A) 9:1 B) 9:8 C) 9:2 D) 9:7 E) 9:6

Solution: Explanation:   Milk = 3/5 * 20= 
3/5 * 20 = 12
12 liters, water= 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6= 
12 - 6 = 6
6 liters   Remaining water= 8 - 4= 
8 - 4 = 4
4 liters   10 liters of pure milk are added, therefore total milk= (6 + 10)= 
(6 + 10) = 16
16 liters.   The ratio of milk and water in the new mixture= 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10= 
4/5 * 10 = 8
8 liters.   Amount of water removed= 2 liters.   Remaining milk = (16 - 8)= 
(16 - 8) = 8
8 liters.   Remaining water= (4 -2)= 
(4 -2) = 2
2 liters.   The required ratio of milk and water in the final mixture obtained= (8 + 10):2 = 18:2 = 9:1   9:1nswer: 9:1
Answer: A
The average age of three boys is 15 years. If their ages are in the ratio 3:5:7 the average age of the young boy is ______ years?	Answers
A) 18
B) 8
C) 9
D) 19
E) 17

Solution: avg of three boys is 15 years given ratio of their ages are 3:5:7   let x be the age   (3x+5x+7x)/3 =15 implies x=3   then the age of the young boy is 3x3=9   ANSWER:9
Answer: C
The number of ways in which six men and six women can be seated in a row, so that no two girls sit together is?  Pick one
A) 6! * ⁷P₆ B) 5! * 7 C) 6! * 7 D) 4! * 4 E) None

Solution: We can initially arrange the six boys in 6! ways.   Having done this, now three are seven places and six women to be arranged. This can be done in ⁷P₆ ways.   Hence required number of ways = 6! * ⁷P₆   6! * ⁷P₆
Answer: A
Medals are to be awarded to three teams in a 10-team competition. If one medal is gold, one medal is silver, and one medal is bronze, how many different ways are there to award the three medals to teams in the competition?  Choose the most appropriate option: A) 10!/7! B) 10!/(3!7!) C) 10!/3! D) 7!/3! E) 7!/94!3!)

Solution: Choosing 3 teams out of 10 when order of the teams matters - P310=10!7!   Or: choosing which 3 teams out of 10 will get the medals - C310C103 and arranging them - 3!3!, so total - C310∗3!=10!7!   Or:   1-2-3-4-5-6-7-8-9-10 (teams);   G-S-B-N-N-N-N-N-N-N (GSB - medals, N - no medal);   Permutation of 10 letters out of which 7 N's are identical is 10!7!10!7! (so you'll get 10!7!10!7! different ways of assigning the medals to the teams).   10!/7!nswer: 10!/7!.
Answer: A
In a 1000 m race, A beats B by 40 m and B beats C by 100 m. In the same race, by how many meters does A beat C?  Choose the correct answer:
A) 145 m B) 136 m C) 268 m D) 129 m E) 218 m

Solution: By the time A covers 1000 m, B covers  (1000 - 40)= 
 (1000 - 40) = 960
960 m.   By the time B covers 1000 m, C covers  (1000 - 100)= 
 (1000 - 100) = 900
900 m.   So, the ratio of speeds of A and C=   1000/960 * 1000/900 = 1000/864. So, by the time A covers 1000 m, C covers 864 m.   So in 1000 m race A beats C by 1000 - 864= 
1000 - 864 = 136
136 m.   Answer:136 m
Answer: B
In 1950, Richard was 4 times as old as Robert. In 1955, Richard was 3 times as old as Robert. In which year was Richard 1.75 times as old as Robert?	Choose the correct answer:
A) 1960
B) 1965
C) 1970
D) 1975
E) 1980

Solution: In 1950: Ri = 4 Ro -------------- eq1   In 1955: Ri +5 = 3(Ro+5)---------eq2   Thus in 1950, solving eq1 and eq2   Ro= 10 , Ri =40   Now for each year we can calculate:   1960: Ri = 50 , Ro =20   1965: Ri= 55, Ro=25   1980: Ri= 40, Ro = 70   Thus8Ans:1980
Answer: E
A train covers a distance of 12 km in 10 min. If it takes 10 sec to pass a telegraph post, then the length of the train is? Choose the correct answer.
A) 178 m B) 168 m C) 120 m D) 168 m E) 200 m

Solution: Speed = (12/10 * 60) km/hr = (72 * 5/18) m/sec   = 20 m/sec.   Length of the train = 20 * 10= 
20 * 10 = 200
200 m.   Answer: 200 m
Answer: E
find how many 4 digits no. is less then 1239 such that all 4 digits are distinct.  Choose the correct answer.
A) 68 B) 69 C) 70 D) 71 E) 72

Solution: case 1- 1000-1099- there are 56 distinct digits   case 2- 1200-1209- there are 7 distinct digits   case 3- 1230-1239(excluding 1239)- there are 6 distinct digits   hence, 56+7+6=69   ANSWER:69
Answer: B
A fruit seller sells mangoes at the rate of Rs.14 per kg and thereby loses 15%. At what price per kg, he should have sold them to make a profit of 15%?  Choose the most appropriate option:
A) Rs.11.81	B) Rs.12	C) Rs.18.94	D) Rs.12.31	E) None

Solution: Solution   85 : 14 = 115 : x   x= (14Ã—115/85)   = Rs.18.94   Hence, S.p per Kg	= Rs.18.94   Answer Rs.18.94
Answer: C
The average of six number is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. what is the average of the remaining three number ?	Choose the correct choice from the following choices.
A) 4.5 B) 4.6 C) 4.7 D) 4.8 E) None of these

Solution: solution:   Sum of the remaining three numbers = (3.95 × 6) - [(3.4 × 2) + (3.85 ×2)]   =23.70 -(6.8 + 7.7) = 23.70 - 14.5 = 9.20.   ∴ Required average =9.2/3 = 3.06 Answer None of these
Answer: E
How many four digit numbers have no repeat digits, do not contain zero, and have a sum of digits F equal to 28?	Choose the correct choice from the following
A) 14
B) 24
C) 28
D) 48
E) 96

Solution: First, look for all 4 digits without repeat that add up to 28. To avoid repetition, start with the highest numbers first.   Start from the largest number possible 9874.   Then the next largest number possible is 9865.   After this, you'll realize no other solution. Clearly the solution needs to start with a 9 (cuz otherwise 8765 is the largest possible, but only equals 26). With a 9, you also need an 8 (cuz otherwise 9765 is the largest possible, but only equals 27). With 98__ only 74 and 65 work.   So you have two solutions. Each can be rearranged in 4!=24 ways. So F=24+24=48.48
Answer: D
How many unique positive odd integers less than 80 are equal to the product of a positive multiple of 5 and an odd number?
Pick
A) 4  B) 8  C) 11  D) 12  E) 15

Solution: The Question basically asks how many positive odd integers less than 80 are odd multiples of 5   So we have 5,15,25,35,45,55, 65,75   =8   8
Answer: B
A man can row downstream at 18 kmph and upstream at 10 kmph. Find the speed of the man in still water and the speed of stream respectively?  Choose the correct choice from the following answers: A) 13,3 B) 12,6 C) 15,3 D) 14,4 E) None of these

Solution: Let the speed of the man in still water and speed of stream be x kmph and y kmph respectively.   Given x + y = 18 --- (1)   and x - y = 10 --- (2)   From (1) & (2) 2x = 28 => x = 14, y = 4.   ANSWER:14,4
Answer: D
Seven children — A, B, C, D, E, F, G and H— are going to sit in seven chairs in a row. The children CF have to sit next to each other, and the others can sit in any order in any remaining chairs. How many possible configurations are there for the children?	Select
A) 600
B) 720
C) 1440
D) 10080
E) 4800

Solution: for such questions , we can treat both as one then total person=7..   these 7 can be arranged in 7! ways.. but within these 7, one consists of two people who can be arranged in 2 ways CF or FC.. so ans =7!*2=10080   ans 10080
Answer: D
A “palindromic integer” is an integer that remains the same when its digits are reversed. So, for example, 43334 and 516615 are both examples of palindromic integers. How many 6-digit palindromic integers are both even and greater than 600,000?	Choose the correct answer.
A) 150	B) 200	C) 240	D) 300	E) 480

Solution: The first digit and last digit are the same so the 2 possibilities are 6 or 8.   The second and third digits can be any number from 0 to 9.   The total number of palindromic integers is   2*10*10= 
  2*10*10 = 200
200   The answer is 200.
Answer: B
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 19 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?
I. 3
II. 7
III. 12 Options.
A) I only  B) II only  C) III only  D) I and III only  E) I, II, and III

Solution: II only   for 7 we will have mean as 7.16(approx) and median as 7 but for 3 we will have mean and median = 6.5 and for 12 we will have median and mean =8
Answer: B