MU-NLPC/Calc-aqua_rat huggingface dataset:
The simple interest on a sum of money will be Rs.600 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Choose the correct answer:
A) 2261
B) 2888
C) 1200
D) 2699
E) 2771

Solution: P --- 10 ---- 600   P --- 5 ----- 300   3P --- 5 ----- 900   ------   => 1200   Answer: 1200
Answer: C
How many such 3's are there in the following number sequence which are immediately Preceded by an odd number and immediately followed by an even number? 5 3 8 9 4 3 7 2 3 8 1 3 8 4 2 3 5 7 3 4 2 3 6  Pick: A) 1 B) 2 C) 3 D) 4 E) More than four

Solution: A is followed by B means : A comes first,B comes next   A preceded by B means : B comes first, A comes next   The sets which satisfy the condition is: 5 3 8   1 3 8   7 3 4   ANSWER:3
Answer: C
PR is tangent to a circle at point P. Q is another point on circle such that PQ is diameter of circle and RQ cuts circle at M. if radius of circle is 4 units and PR=6units. find ratio of triangle PMR to PQR.
Choose one:
A) 11/20
B) 3/5
C) 13/20
D) 18/25
E) 18/26

Solution: let PM = y   QM= x   MR = 10-x   In triangle PQM,   PM^2+QM^2 = PQ^2   => x^2+y^2=64 .....(1)   In triangle PMR,   PM^2+ MR^2= PR^2   y^2+(10-x)^2=36......(2)   solving for x and y   x=6.4   y=4.8   taking permineter of triangle PQR =24   perimeter of triangle PMR = 14.4   take ratio   14.4/24= 
  14.4/24 = 0.6
0.6   ANSWER:13/20
Answer: C
Find the day of the week on 16th July, 1776.  Choices
A) Tuesday	B) Wednesday	C) Monday	D) Thursday	E) None of these

Solution: 16th July, 1776 mean (1775 years + 6 months + 16 days)   Now, 1600 years have 0 odd days.   100 years have 5 odd days   75 years contain 18 leap years and 57 ordinary years and therefore (36 + 57) or 93 or 2 odd days.   ∴ 1775 years given  0 + 5 + 2= 
 0 + 5 + 2 = 7
7 and so 0 odd days.   Also number of days from 1st Jan. 1776 to 16th July,1776   Jan. Feb. March April May June July     31 + 29 + 31 + 30 + 31 + 30 + 16= 
  31 + 29 + 31 + 30 + 31 + 30 + 16 = 198
198 days= 28 weeks  + 2= 
 + 2 = 2
2 odd days   ∴ Total number of odd days= 0 + 2= 
0 + 2 = 2
2.   Hence the day on 16th July, 1776 was 'Tuesday'.   Tuesdaynswer Tuesday
Answer: A
A gambler has won 40% of his 40 poker games for the week so far. If, all of a sudden, his luck changes and he begins winning 70% of the time, how many more games must he play to end up winning 60% of all his games for the week?
Select the correct option
A) 50  B) 60  C) 70  D) 80  E) 90

Solution: Let x be the number of additional games the gambler needs to play.   0.4(40) + 0.7x = 0.6(x+40)   0.1x = 8   x = 80   The answer is 80.
Answer: D
What will be the compound interest on Rs. 25000 aŌer 3 years at the rate of 12 % per annum	Pick:
A) Rs 10123.20
B) Rs 10123.30
C) Rs 10123.40
D) Rs 10123.50
E) None of these

Solution: Explanation:   (25000×(1+12100)3)=>25000×2825×2825×2825=>35123.20   So Compound interest will be   35123.20 - 25000= 
  35123.20 - 25000 = 10_123.2
Rs 10123.20   Rs 10123.20nswer: Rs 10123.20
Answer: A
Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour? Select the correct option
A) 15 min	B) 18 min	C) 16 min	D) 20 min	E) 26 min

Solution: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.   Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.   stoppage time = 20/60 hrs   = 20 min   Answer: 20 min
Answer: D
Which of the following is a perfect square?
.	Choose the correct answer:
A) 649
B) 961
C) 1664
D) 2509
E) 100000

Solution: The best way would be to see the range in tens and solve after looking at the units digit   lets see all choices--   A. 649   20^2=400 and 30^2=900..   since only 3 and 7 have the perfect square ending in 9, we require to try only for 27 as it is more than 25^2, 625   it is not 27^2, as next square of 26 itself after 625 will be >625+2*25,675   actually 26^2 will be 25^2+25+26   B. 961   between 30^2 and 40^2...   only 1 and 9 have squares ending with one..   since it is very close to 30^2, 900.. it can be 31^2   CORRECT   C. 1664   between 40^2 and 50^2..   closer is 42, but that should be atleast 1600+41+42.. NO   D. 2509   between 50^2 and 60^2..   very close to 50^2 so next square of 51 will be at least 2500+51.. no   E. 100000   odd number of 0s, not possible   ANSWER:961
Answer: B
The difference between the local value and the face value of 3 in the numeral 62975143 is Choose the correct option:  A) 3  B) 2  C) 1  D) 0  E) 5

Solution: Explanation:   (Local value of 3) - (Face value of 3) = (3 - 3)= 
(3 - 3) = 0
0   0)
Answer: D
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number Options
A) 17 B) 15 C) 12 D) 8 E) 3

Solution: f the number is x,   Then, x + 17 =	60/x   x2 + 17x - 60 = 0   (x + 20)(x - 3) = 0   x = 3, -20, so x = 3 (as 3 is positive)   answer: 3
Answer: E
A can do a piece of work in 30 days. He works at it for 5 days and then B finishes it in 20 days. In what time can A and B together it?  Select the correct option.
A) 53 1/3 days  B) 13 1/3 days  C) 23 1/3 days  D) 33 1/3 days  E) 53 1/7 days

Solution: Explanation:   5/30 + 20/x = 1   x = 24   1/30 + 1/24 = 3/40   40/3 = 13 1/3 days   Answer:13 1/3 days
Answer: B
When a 192 meters long rod is cut down into small pieces of length 3.2 meters each. Then how many pieces are available ?	Choose the correct option:
A) 52
B) 68
C) 62
D) 67
E) 69

Solution: Answer   No. of pieces = Total length / Length of each piece   = 192/3.2= 
192/3.2 = 60
60   Option: 67
Answer: D
The length of one pair of opposite sides of a square is increased by 5 cm on each side the ratio of the length and the breadth of the newly formed rectangle becomes 3 : 2. What is the area of the original square? Choose the correct choice from the following options:
A) 25 sq.cm	B) 81 sq.cm	C) 120 sq.cm	D) 225 sq.cm	E) None of these

Solution: Let original length of each side = x cm.   Then, its area = (x2)cm2.   Length of rectangle formed = (x + 5) cm   and its breadth = x cm.   ∴ x+5/x=3/2 ⇔ 2x + 10 = 3x ⇔ x = 10   ∴ Original length of each side = 10 cm and its area = 100 cm2   Answer None of these
Answer: E
There are 60 doors marked with numbers 1 to 60. There are 60 individuals marked 1 to 60.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All the doors are closed to start with. One at a time, one randomly chosen individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For example, the individual marked with number 5 operates the doors marked with 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, and 60. If every individual in the group gets one turn, then how many doors are open at the end? Select the correct option:
A) 0
B) 2
C) 5
D) 7
E) 9

Solution: If a door is closed at the start, it requires an odd number of people to operate to be open at the end. Only the perfect squares have an odd number of factors.   The doors which are open at the end are: 1, 4, 9, 16, 25, 36, 49 for a total of 7 doors.   The answer is 7.
Answer: D
A ferry can transport 100 tons of vehicles. Automobiles range in weight from 1,800 to 3,200 pounds. What is the greatest number of automobiles that can be loaded onto the ferry? Select.
A) 115 B) 120 C) 110 D) 100 E) 90

Solution: to get maximum vehicles we must take into consideration the minimum weight i.e 1800 pounds here   since , 1 ton = 2000 pounds   78 tons will be 200,000 pounds   from the answer choices:   let max number of vehicles be 110   total weight will be = 110*1800= 
110*1800 = 198_000
198000 pounds , which is lesser than the maximum weight allowed .   Ans: 110
Answer: C
The sum of the present age of Henry and Jill is 40. What is their present ages if 11 years ago Henry was twice the age of Jill?
Choices:
A) and 27
B) and 24
C) and 23
D) and 29
E) of these

Solution: Let the age of Jill 11 years ago be x, age of Henry be 2x   x+11 + 2x+11 = 40   x = 6   Present ages will be 17 and 23   Answer : and 23
Answer: C
A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is :
Pick:
A) 120 m B) 140 m C) 240 m D) 300 m E) None

Solution: Sol.   Speed = [12/10 * 60] km/hr = [72 * 5/18] m/sec = 20 m/sec.   Length of the train = (speed * Time) = (20 * 6)= 
(20 * 6) = 120
120 m.   120 mnswer 120 m
Answer: A
The radius of a cone is 14 m, slant height is 20 m. Find the curved surface area?
Select.
A) 770	B) 550	C) 110	D) 880	E) 330

Solution: Cone curved surface area = πrl   22/7 × 14 × 120 = 44 × 20 = 880 m(power2)   Answer is 880.
Answer: D
If a and b are multiples of 5 then which are all the multiples of 5
1) a/b
2) a*b
3) a+b
4) a-b
5) a^b	Choose the correct choice from the following options:
A) 1,2,5 B) all of these C) 1,3 D) 2,3,4,5 E) 1,2,3,5

Solution: a*b a^b a+b a-b are multiples of 5 except a/b   ANSWER:2,3,4,5
Answer: D
The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:	Pick one.
A) 200
B) 210
C) 245
D) 230
E) 265

Solution: Speed = (45 * 5/18) m/sec = (25/2) m/sec. Time = 30 sec. Let the length of bridge be x meters. Then, (130 + X)/30 = 25/2 ==> 2(130 + X) = 750 ==> X = 245 m.   Answer: Option 245
Answer: C
If k is the sum of the digits of integer m, and m=13n, where n is an integer, which of the following must be true?	Options.
A) k is a multiple of 6 B) The sum of the digits of k is divisible by 3 C) m is a multiple of 10k D) k is divisible by 2 E) value of k contains prime number also

Solution: m= 13n i.e n =1,2,3 ,4 etc or -1,-2.-3 ,-4 then m =13,26,39,52 or -13 ,-26 ,-39 ,-52 then k 4,8,12,7, or -(1+3) , -(2+6) , -(3+9) ,-(5+2) .   ans value of k contains prime number also
Answer: E
If x,y ,and z are positive real numbers such that x+y-z =50 , y-z+x =60 , and z-x+y = 80, then find the z value? Choose the most appropriate option:
A) 10	B) 20	C) 5	D) 15	E) 25

Solution: x+y-z =50, ------1)   y-z+x =60 , ------2)   z-x+y = 80------3)   from (1)&(2)   2z=10   z=5   correct option is 5
Answer: C
At what approximate time between 4 and 5 am will the hands of a clock be at right angle? Choose the correct choice from the following
A) 4 : 40 am B) 4 : 38 am C) 4 : 35 am D) 4 : 39 am E) None of these

Solution: Here H × 30 = 4 × 30 = 120°.   (Since initially the hour hand is at 4. ∴ H = 4).   Required angle A = 90° and since, H × 30 > A° so, there will be two timings.   Required time T = 2⁄11(H × 30 ± A) minutes past H.   ∴ One timing = 2⁄11(4 × 30 + 90) minutes past 4   = 382⁄11 minutes past 4.   Or 4 : 38 approx.   Answer 4 : 38 am
Answer: B
A can do a piece of work in 90 days & Y can do it in 80 days. They began working together but A leaves after some days and then B completed the remaining work in 46 days. The number of days after which A left the work was?
Choose the most appropriate option: A) 10 days B) 11 days C) 16 days D) 17 days E) 18 days

Solution: A and B did the work for some days.   After that , B completed the remaining work in 46 days .   In 46 days, word done by B =   1   80   x 46 =   23   45   Remaining work = 1 – 23/45   = 17/45   Remaining work is done by both A and B together =   17/45x 90 x 80/90 + 80   = 16 days   16 days
Answer: C
The speed of a car is 90 km in the first hour and 30 km in the second hour. What is the average speed of the car?	Choose one
A) 50 kmph	B) 60 kmph	C) 75 kmph	D) 85 kmph	E) 90 kmph

Solution: Explanation:   S = (90 + 30)/2= 
(90 + 30)/2 = 60
60 kmph   60 kmph)
Answer: B
Two persons start at the same point, walk in opposite directions with 7 km/hr and 4.5 km/hr respectively.
What is the distance separated after 2 and half hrs?	Select the correct option
A) 26.250 km  B) 27.250 km  C) 28.750 km  D) 29.250 km  E) 25.250 km

Solution: As the two persons are moving in the opposite direction, so they will be separateed in 1 hour = 7 + 4.5= 
7 + 4.5 = 11.5
11.5 km.   They will be separated in 2.5 hours= 11.5 * 2.5= 
11.5 * 2.5 = 28.75
28.750 km   ANSWER:28.750 km
Answer: C
John can complete a given task in 20 days. Jane will take only 12 days to complete the same task. John and Jane set out to complete the task by beginning to work together. However, Jane was indisposed 4 days before the work got over. In how many days did the work get over from the time John and Jane started to work on it together?  Select the correct option:  A) 6  B) 10  C) 8  D) 7.5  E) 3.5

Solution: John 6*20= 
6*20 = 120
120   Jane   10*12= 
  10*12 = 120
120   In 4 days working alone John did: 4 Days * Rate= 4*6= 
4*6 = 24
24, so working together they did 120-24= 
120-24 = 96
96 --> Rate(A+B)*t=96 -> 16*t=96, t=6. hence the answer is 10 (John worked 4 days + 6 days they worked together = 10 days)
Answer: B
1, 5, 13, 25, 41, ? Choices:  A) 61  B) 56  C) 74  D) 57  E) 32

Solution: The pattern is + 4, + 8, + 12, + 16, +20   61nswer : 61.
Answer: A
B and C start a business with Rs.2000 and Rs.10000 respectively. Hoe should they share their profits at the end of one year? Choose the correct choice from the following answers:
A) 1:2  B) 1:3  C) 1:4  D) 1:5  E) 2:1

Solution: Explanation:   They should share the profits in the ratio of their investments.   The ratio of the investments made by B and C =   2000 : 10000 => 1:5   Answer:1:5
Answer: D
A merchant marks his goods up in such a way that the profit made on selling 30 articles is equal to the cost price of 20 articles. What is the % Q profit made by the merchant?
Choose the correct choice from the following answers:
A) 66.67 %  B) 50 %  C) 200 %  D) 100 %  E) 33.33 %

Solution: C.P of 1 article= $30(say)   C.P of 20 articles=30*20= 
30*20 = 600
$600   Now, C.P of 20 articles=Profit on 30 articles   Therefore, profit on 1 article=$600/30= 
600/30 = 20
$20   Profit Q%=(20/30)*100=66.67%   66.67 %nswer 66.67 %
Answer: A
Sreenivas sells a table to Shiva at 10% profit and Shiva sells it to Mahesh at 10% loss. At what price did Sreenivas purchase the table if Mahesh paid Rs. 2178? Choose the correct choice from the following
A) Rs. 2100 B) Rs. 2150 C) None of these D) Rs. 2200 E) Cannot be determined

Solution: Explanation :   et the cost price of table for Sreenivas be Rs. x and given that, cost price of table for Mahesh = Rs. 2178.=> (90%) of (110%) of x = Rs. 2178.=> (90/100)(110/100)x = 2178=> x = (2178 x 100)/(9 x 11)=> x = Rs. 2200   Answer : Rs. 2200
Answer: D
A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare,
the raƟo of the speed of the dog to that of the hare is  Pick one
A) 4:5
B) 9:5
C) 8:5
D) 9:2
E) None of these

Solution: Explanation:   Dog : Hare = (3*3) leaps of hare : 5 leaps of hare   = 9 : 5   Answer: 9:5
Answer: B
5 z – 3 < 3 z + 4, which of the following cannot be a value of z3z3 ? Pick one.
A) 0 B) 1 C) 8 D) 27 E) 6

Solution: 5z - 3z < 4 + 3   2z < 7   z < 3.5   z must be 4 for z^3 to be 64. On the other hand z an be 0, 1, 2, or 3 thus z^3 can be 0, 1, 8, or 27.   ANSWER:27
Answer: D
Two numbers N and 16 have LCM = 48 and GCF = 8. Find N.	Select the correct option:
A) 12
B) 24
C) 36
D) 48
E) 52

Solution: The product of two integers is equal to the product of their LCM and GCF. Hence.   16 × N = 48 × 8   N = 48 × 8 / 16 = 24   correct answer is 24)24
Answer: B
A can do a piece of work in 10 days and B can do the same work in 12 days. A and B worked together for 2 days. How many more days are required to complete the remaining work if they work together? Choose the correct choice from the following answers.
A) 3 (5/18) days B) 3 (7/11) days C) 3 (5/11) days D) 2 (5/11) days E) 3 (2/11) days

Solution: A can do 1/10 of the work in a day.   B can do 1/12 of the work in a 1 day.   Both of them together can do (1/10 + 1/12) part of work in 1 day = (6 + 5)/60 = 11/60   They take 60/11 days to complete the work together.   Given that they already worked for 2 days.   The number of days required to complete remaining work => 60/11 - 2 = 38/11 = 3 (5/11) days.   Answer:3 (5/11) days
Answer: C
What percent of a week is 3 days?	Choose one:  A) 50%  B) 45%  C) 42,85%  D) 23,33%  E) 40%

Solution: Explanation :   Total days in a week = 7   Required percentage = (3/7) Ã— 100 = 42,85%   Answer : Option 42,85%
Answer: C
The price of lunch for 14 people was $207 including a 15% gratuity for service. What was the average price per person, EXCLUDING the gratuity? Answers:
A) 11.73 B) 12.85 C) 13.8 D) 14 E) 15.87

Solution: Clearly 12.85 is the answer   I used POE here   Lets consider option (12.85)   14*12.85= 180 now 180(115/100)=207   => possible ANSWER IMO 12.85
Answer: B
A man buys Rs. 20 shares paying 9 % dividend. The man wants to have an interest of 12% on his money.The market value of each share is : Pick one: A) Rs. 12 B) Rs. 15 C) Rs. 18 D) Rs. 21 E) None

Solution: Solution   Dividend on Rs. 20 = Rs.(9/100x20) = Rs.9/5   Rs. 12 is an income on Rs. 100.   ∴ Rs.9/5 is an income on Rs. (100/12 X9/5)= Rs.15   Answer Rs. 15
Answer: B
A certain number of machines can do a work in 75 days. If there were 6 machine more it could be finished in 15days less. How many machines are there?  Answers.
A) 20  B) 24  C) 25  D) 30  E) 32

Solution: Number of machines = 6* (75-15)/15= 
6* (75-15)/15 = 24
24 machines   Answer is 24
Answer: B
A and B walk around a circular track. They start at 9 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 12:00 P.m.?
Options
A) 28  B) 27  C) 26  D) 25  E) 20

Solution: Sol.   Relative speed = (2 + 3)= 
(2 + 3) = 5
5 rounds per hour.   So, they cross each other 5 times in an hour.   Hence, they cross each other 20 times before 12:00 P.m.   Answer 20
Answer: E
Diesel costs Rs.4per lit and petrol costs 5.63 per litre. If the price of diesel rise by 10% a month and the price of petrol is unchanged.How many months will it take until a litre of Diesel costs more than a litre of petrol. Select the correct option
A) 9 months	B) 5 months	C) 6 months	D) 4 months	E) 2 months

Solution: Explanation :   =>In the First Month the price of the diesel would be 4*110/100= 
4*110/100 = 22/5 = around 4.4
4.4=>In the Second Month the price of the diesel would be 4.4*110/100= 
4.4*110/100 = 4.84
4.84=>In the Third Month the price of the diesel would be 4.84*110/100= 
4.84*110/100 = 5.324
5.324=>In the fourth Month the price of the diesel would be 5.324*110/100 = 5.85 which is higher than the   price of the petrol!   Answer : 4 months
Answer: D
The average of first seven multiples of 5 is:  Choose the correct option.
A) 20	B) 16	C) 15	D) 8	E) 10

Solution: Explanation :   (5(1+2+3+4+5+6+7)/7   = 5x28/7   = 20   20nswer : 20
Answer: A
What day of the week does May 28 2006 fall on
Choose the correct option: A) Saturday B) Monday C) Sunday D) Thursday E) Friday

Solution: Explanation:   28th May 2006 = (2005 years + period from 1-Jan-2006 to 28-May-2006)   We know that number of odd days in 400 years = 0   Hence the number of odd days in 2000 years = 0 (Since 2000 is a perfect multiple of 400)   Number of odd days in the period 2001-2005   = 4 normal years + 1 leap year   = 4 x 1 + 1 x 2 = 6   Days from 1-Jan-2006 to 28-May-2006 = 31 (Jan) + 28 (Feb) + 31 (Mar) + 30 (Apr) + 28(may)   = 148   148 days = 21 weeks  + 1= 
 + 1 = 1
1 odd day   Total number of odd days= (0 + 6 + 1)= 
(0 + 6 + 1) = 7
7 odd days= 0 odd day   0 odd day = Sunday   Hence May 28 2006 is Sunday.   Answer: Option Sunday
Answer: C
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is?	Select:
A) 266
B) 298
C) 269
D) 150
E) 277

Solution: Let the length of the train be x meters and its speed be y m/sec.   They, x / y = 15 => y = x/15   x + 100 / 25 = x / 15   x = 150 m.   Answer: 150
Answer: D
The ratio of the present ages of a man and his wife is 6 : 5. Which of the following can't be a possible ratio of their ages 35 years ago?
Pick one.
A) 4: 6  B) 5: 6  C) 6:6  D) 7: 6  E) 8: 6

Solution: 6x-35/5x-35 = 7/6   Therefore x=-35   Age cannot be negative.   Answer: 7: 6
Answer: D
A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Choose the correct choice from the following answers:
A) 4
B) 6
C) 5
D) 9
E) 8

Solution: Speed of train relative to man = (60 + 6) km/hr = 66 km/hr   [66 * 5/18] m/sec = [55/3] m/sec.   Time taken to pass the man = [110 * 3/55= 
110 * 3/55 = 6
6 sec   ANSWER:6
Answer: B
The average height of 40 girls out of a class of 50 is 169 cm. and that of the remaining girls is 167 cm. The average height of the whole class is :	Pick.
A) 138.9 cms B) 149.2 cms C) 168.6 cms D) 159.2 cms E) 142.5 cms

Solution: Explanation:   Average height of the whole class =(40×169+10×167/50)=168.6 cms   Answer 168.6 cms
Answer: C
The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 100. What is the manager's monthly salary ?	Pick:  A) 3600  B) 3890  C) 88798  D) 2789  E) 2891

Solution: Explanation:   Manager's monthly salary Rs. (1600 * 21 - 1500 * 20) = Rs. 3600.   3600nswer: 3600) 3600
Answer: A
If 10 is added to thrice a number and this sum is multiplied by 5, the result is the same as if the number is multiplied by 5 and 13 is added to the product. What is the number?
Choose the correct choice from the following answers:
A) -3.5  B) -3.7  C) -5  D) -9  E) 11

Solution: let the number be x;   5(10+3x)=5x+13;   x=-3.7   ANSWER:-3.7
Answer: B
If A's salary is 25% higher than B's salary,then how much percent is B's salary lower than A's?  Choose the correct choice from the following answers:
A) 22% B) 20% C) 25% D) 30% E) 10%

Solution: If A's salary is 25% higher than B's salary, means A's salary is Rs. 125 if B's salary is Rs 100. Then B 's salary is lower than A by  25*100/125= 
 25*100/125 = 20
20% .   ANSWER:20%
Answer: B
If A lends Rs.3500 to B at 10% per annum and B lends the same sum to C at 11.5% per annum then the gain of B in a period of 3 years is?
Select the correct option.
A) 157.5
B) 157.51
C) 157.57
D) 157.59
E) 157.52

Solution: (3500*1.5*3)/100= 
(3500*1.5*3)/100 = 157.5
> 157.50   157.5nswer: 157.5
Answer: A
A and B finish the job in 15 days.while A,B and C can finish it in 10 days . C alone will finish the job in  Pick one:  A) 40 days  B) 30 days  C) 60 days  D) 70 days  E) 50 days

Solution: Explanation:   10 = (15 * x)/(15 + x)   150+10x=15x   5x=150   X=30   Answer: Option 30 days
Answer: B
A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 550 m long?  Pick one.
A) 70sec	B) 72sec	C) 74sec	D) 76sec	E) 79sec

Solution: Speed = 240/24= 
240/24 = 10
10 m/sec.   Required time= (240 + 550)/10= 
(240 + 550)/10 = 79
79 sec.   Answer:79sec
Answer: E
A certain company reported that the revenue on sales increased 60 % from 2000 to 2003, and increased 80 % from 2000 to 2005. What was the approximate percent increase in revenue for this store from 2003 to 2005?  Options
A) 50 %  B) 40 %  C) 35 %  D) 32 %  E) 13 %

Solution: Assume the revenue in 2000 to be 100. Then in 2003 it would be 160 and and in 2005 180, so from 2003 to 2005 it increased by (180-160)/160=20/160=13%   Answer: 13 %.
Answer: E
daal is now being sold at rate Rs.20 a kg.During last month its rate was Rs 16 per kg.By How reduce percent should a family its consumption so as to keep the expenditure fixed? Pick one: A) 10% B) 20% C) 30% D) 40% E) 50%

Solution: Last month rate= 16 per kg   this month rate = 20 per kg   if 20=100% then 16= ?   therefore %= (16 * 100)/20= 
(16 * 100)/20 = 80
80%   to reduce consumption   100-80= 
  100-80 = 20
20%   ANSWER:20%
Answer: B
From the following choice, what is the equation of a line whose x-intercept is half as that of line 3x+4y=12 and y-intercept twice of same Options.
A) 3x+y=6 B) 3x+y=5 C) 3x+y=4 D) 3x+y=3 E) 2x+y=6

Solution: x/4 +y/3 = 1   x-intecept = 4   y-intecept = 3   new,   x-intecept = 2   y-intecept = 6   x/2 + y/6 = 1   3x+y=6   3x+y=6NSWER:3x+y=6
Answer: A