MU-NLPC/Calc-aqua_rat huggingface dataset:
The probability that A speaks truth is 1/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?	Choose the correct choice from the following answers.
A) 16/35  B) 16/39  C) 16/36  D) 18/33  E) 18/32

Solution: If both agree stating the same fact, either both of them speak truth of both speak false.   Probability = 1/5 * 4/7 + 4/5 * 3/7   = 4/35 + 12/35 = 16/35   16/35nswer: 16/35
Answer: A
A rectangular room has the rectangular shaped rug shown as above figure such that the rug’s area is 140 square feet and its length is 4 feet longer than its width. If the uniform width between the rug and room is 4 feet, what is the area of the region uncovered by the rug (shaded region), in square feet? Choose the correct choice from the following:
A) 32  B) 36  C) 40  D) 46  E) 256

Solution: Rug's area = 140   which is (x) x (4+x) = 140   so x= 10   rug maintains a uniform distance of 4 feet   so room has dimension 10+8 and 14+8 i.e. 18 and 22   area of room 18x22 = 396   area covered is 140   so uncovered area is 396-140= 
396-140 = 256
256 (ANSW256R 256)
Answer: E
Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM?  Choose the correct choice from the following options:  A) 9 kmph  B) 11 kmph  C) 12 kmph  D) 15 kmph  E) 18 kmph

Solution: Let the distance travelled by x km.   Then, x - x = 2   10 15   3x - 2x = 60   x = 60 km.   Time taken to travel 60 km at 10 km/hr = 60 hrs = 6 hrs.   10   So, Robert started 6 hours before 2 P.M. i.e., at 8 A.M.   Required speed = 60 kmph. = 12 kmph.   5   12 kmph
Answer: C
A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 210 kilometers?	Pick.
A) 8.25 gallons
B) 7.5 gallons
C) 6.55 gallons
D) 5.25 gallons
E) 4.5 gallons

Solution: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 210 kilometers?   210 / 40= 
210 / 40 = 21/4 = around 5.25
5.25 * 1= 
5.25 * 1 = 5.25
5.25 gallons correct answer 5.25 gallons
Answer: D
Carolyn bought 16 gumballs, Lew bought 12 gumballs, and Bob bought X gumballs. The average (arithmetic mean) number of gumballs the three bought is between 19 and 25, inclusive. What is the difference between the greatest number and the smallest number of gumballs Carey could have bought? Choose the correct choice from the following answers
A) 20  B) 22  C) 24  D) 26  E) 18

Solution: Smallest gumballs = (19-16) + (19-12) +19= 
(19-16) + (19-12) +19 = 29
29   Largest gumballs= (25-16) + (25-12) +25= 
(25-16) + (25-12) +25 = 47
47   Difference= 47 - 29= 
47 - 29 = 18
18   18
Answer: E
Exactly 28% of the reporters for a certain wire service cover local politics in Country X. If 30% of the reporters who cover politics for the wire service do not cover local politics in Country X, what percent of the reporters for the wire service do not cover politics? Options: A) 20% B) 42% C) 44% D) 60% E) 84%

Solution: Let's assume there are 100 reporters --> 28 reporters cover local politics.   Now, as 30% of the reporters who cover all politics do not cover local politics then the rest 70% of the reporters who cover politics do cover local politics, so if there are x reporters who cover politics then 70% of them equal to 28 (# of reporters who cover local politics): 0.7x=28 --> x=40, hence 40 reporters cover politics and the rest 100-40= 
100-40 = 60
60 reporters do not cover politics at all.   Answer: 60%.
Answer: D
A certain country had a total annual expenditure of $1.2 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure?	Choose the correct choice:
A) $ 500
B) $1,000
C) $2,000
D) $3,000
E) $5,000

Solution: Total expenditure / Population = per capita expenditure   Hence, (1,2 x 10^11) / 240 000 000 = (12 x 10^10) / (2,4 x 10^8) = 5 x 10^(10-8) =   5 x 10^2 = 500.   $ 500nswer is $ 500.
Answer: A
8796 x 223 + 8796 x 77 = ?
Choose one
A) 2736900	B) 2738800	C) 2658560	D) 2716740	E) None of them

Solution: =8796 x (223+77) (by distributive law)   =8796 x 300   =2638800   Answer is 2738800
Answer: B
The no. of gift pack bought by Dexter is 1 more than the price, in rupees, of each gift pack. The amount of Rs.380 which Dexter had, fell short of the required amount. What is theamount by which he might have fallen short.  Choose the correct option
A) 20
B) 40
C) 50
D) 60
E) 90

Solution: Let the price of gift pack be 'aa'   Then number of packs bought =a+1=a+1   Hence total cost is a(a+1)a(a+1)   It is given that 380<a(a+1)380<a(a+1)   If a=19a=19, the total cost =19×20=380=19×20=380   Dexter would not have fallen short, If:   a=20a=20, a(a+1)=420a(a+1)=420   So he would have fallen short by Rs 40.   This is the minimum amount by which he may have fallen short.   40
Answer: B
Last month, John rejected 0.5% of the products that he inspected and Jane rejected 0.8 percent of the products that she inspected. If total of 0.75 percent of the products produced last month were rejected, what fraction of the products did Jane inspect?  Pick.
A) 1/6  B) 1/2  C) 5/8  D) 5/6  E) 15/16

Solution: X - fraction of products Jane inspected   (1 - X) - fraction of products John inspected   0.8(X) + 0.5(1-X) = 0.75   0.3X = 0.75 - 0.5= 
0.75 - 0.5 = 0.25
0.25/0.3   X= 5/6   Therefore the answer is 5/6: 5/6.
Answer: D
If x and y are integers such that (x+1)^2 is less than or equal to 9 and (y-1)^2 is less than 64, what is the sum of the maximum possible value of xy and the minimum possible value of xy?  Options.
A) -16
B) -8
C) 0
D) 14
E) 16

Solution: (x+1)^2 <= 9   x <= 2   x >= -4   (y-1)^2 < 64   y < 9   y > -7   Max possible value of xy is -4 × -6 = 24   minimum possible value of xy is -4 × 8 = -32   -32 + 24 = -8   Answer : -8
Answer: B
Suppose you have access to a large vat of distilled water, several gallons large. You have two precise measuring pipettes, one to measure exactly 1/5 of an ounce and one to measure exactly 1/6 of an ounce. You can pour precisely measured amounts into a beaker, which initially is empty. You can use either pipette to remove distilled water from the vat or from the beaker and use either pipette to dispense water into either of those receptacles, but you cannot use either pipette to take any quantity of distilled water other than the amount for which it is designed. Which of the following represents, in ounces, a precise amount of distilled water you can transfer from the vat to the beaker?
I. 1/6
II. 1/7
III. 1/12  Choose the correct choice from the following answers: A) I only B) III only C) 1/30 and 11/30 D) II and III only E) I, II, and III

Solution: 1/5-1/6=1/30   1/5+1/6=11/30   Answer: 1/30 and 11/30
Answer: C
A year ago the proportion between Sham and Amir’s age was 4:3. 1 year hence the proportion of their ages will be 5:4. The total of their current ages is :	Pick.
A) 16 years	B) 17 years	C) 18 years	D) 19 years	E) 20 years

Solution: 16 years   16 years   16 years year ago, Sham’s age = 416 years years   16 yearsnd, 16 yearsmir’s age = 316 years years   Current age of Sham = (416 years + 1) years   Current age of 16 yearsmir = (316 years + 1) years   1 year hence, Sham’s age = (416 years + 2) years   and 16 yearsmir’s age = (316 years + 1) years   So,   { (416 years + 2)/(316 years +2) } = 5 /4   => 16 + 8 = 1516 years + 10   or, 16 years = 2   Total of their current ages = 416 years + 1 + 316 years + 1   = 7(16 years) + 2   = 7(2) + 2 = 16 years.
Answer: A
The total marks obtained by a student in Mathematics and Physics is 60 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together.  Select
A) 40
B) 99
C) 77
D) 66
E) 12

Solution: Let the marks obtained by the student in Mathematics, Physics and Chemistry be M, P and C respectively.   Given , M + C = 60 and C - P = 20 M + C / 2 = [(M + P) + (C - P)] / 2 = (60 + 20) / 2= 
(60 + 20) / 2 = 40
40.   40nswer: 40
Answer: A
What approximate value should come in place of question mark (?) in the following equation
287.532 + 1894.029 – 657.48 = 843.095 + ?  Choose the correct choice from the following answers.
A) 870 B) 790 C) 680 D) 770 E) 890

Solution: ? = 285 + 1895 – 655 – 845 or, ? = 680   Answer 680
Answer: C
A van takes 5 hours to cover a distance of 435 km. What speed in kph should the van maintain to cover the same distance in 3/2 of the previous time?  Options.
A) 50
B) 52
C) 54
D) 56
E) 58

Solution: (3/2)*5= 
(3/2)*5 = 15/2 = around 7.5
7.5 hours   435 / 7.5= 
435 / 7.5 = 58
58 kph   The answer is 58.
Answer: E
What is the CP of Rs 100 stock at 8 discount, with 1/5% brokerage? Choose the correct choice from the following choices
A) 99.6 B) 96.2 C) 97.5 D) 92.2 E) None of these

Solution: Explanation:   Use the formula,   CP= 100 â€“ discount + brokerage%   CP= 100-8+1/5   92.2   Thus the CP is Rs 92.2.   ANSWER 92.2
Answer: D
A TV is purchased at Rs. 5000 and sold at Rs. 4000, find the lost percent.  Choose one:	A) 10%	B) 20%	C) 25%	D) 28%	E) 30%

Solution: Explanation:   We know, C.P. = 5000   S.P. = 4000   Loss = 5000 - 4000= 
5000 - 4000 = 1_000
1000   Loss%=(LossCost∗100)%=(10005000∗100)%=20%   ANSWER IS 20%
Answer: B
A glass was filled with 10 ounces of water, and 0.03 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period?
Select
A) 0.006% B) 0.06% C) 0.6% D) 6% E) 60%

Solution: We are given that 0.03 ounces of water evaporated EACH DAY. Furthermore, we know that this process happened over a 20-DAY PERIOD. To calculate the total amount of water that evaporated during this time frame we need to multiply 0.01 by 20. This gives us:   0.03 x 20 = 0.6 ounces   Finally, we are asked for “What percent” of the original amount of water evaporated during this period. To determine this percentage, we have to make sure we translate the expression correctly. We can translate it to:   (Amount Evaporated/Original Amount) x 100%   (0.6/10) x 100%   (6/100) x 100% = 6%   Answer 6%
Answer: D
An investor purchased 100 shares of stock X at 6 1/8 dollars per share and sold them all a year later at 12 dollars per share. If the investor paid a 2 percent brokerage fee on both the total purchase price and the total selling price, which of the following is closest to the investor's percent gain on this investment?
Pick one
A) 192%	B) 94%	C) 280%	D) 300%	E) 380%

Solution: If the purchase price was 6$ per share then the investor would have made a profit of 100%.   Since the purchase price is slightly more than 6$ the profit would be slightly less than 100%.   Also a 2% brokerage is negligible and it brings down the profit percentage only by a small value. Approximation is very useful to solve these kind of problems as the answer choices are far apart.   Answer:94%
Answer: B
The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 70 per cent. The two reductions together are equal to a single reduction of	Pick one:
A) 45%  B) 40%  C) 35%  D) 77.5%  E) 30%

Solution: Price = p   initially price reduced by 25% which means new price is 3/4P   Now on this new price further 70percent is reduced which means the new price is merely 30percent of 3/4P   ==> (3/4)x(3/10)P = 9/40P is the new price after both deduction which is 22.5percent of the original value P. This implies this entire series of deduction is worth having discounted 77.5% of P. So answer is 77.5% = 77.5%
Answer: D
In a mixture of 13 litres, the ratio of milk and water is 3 : 2. If 3 liters of this mixture is replaced by 3 liters of milk, then what will be the ratio of milk and water in the newly formed mixture?  Choose the correct choice from the following options.
A) 10 : 3  B) 8 : 5  C) 9 : 4  D) 1 : 1  E) 2:3

Solution: EXPLANATION:   Given: Total quantity of mixture = 13 liters   3 litres of mixture is removed from the container – So, let's forget this altogether!   Now, you are left with only 10 litres of mixture in 3:2 ratio.   Milk in 10 litres mix = 10 x	3/(2+3)= 6 litres   Water in 10 litres mix = 10 x	2/(2+3)= 4 litres   We add 3 litres milk to this.   So, milk in new mix is = 6 liters + 3 litres = 9 litres   Water= 4 litres   Ratio of milk : water = 9 : 4   ANSWER IS 9 : 4
Answer: C
In a certain random experiment, exactly one of the outcomes A, B, and D will occur. In each random experiment, the probability that outcome A will occur is 1/3 , and the probability that outcome B will occur is 1/3. What is the probability that when the random experiment is conducted 6 independent times, each of outcomes A, B, and D will occur twice?	Choose the correct choice from the following options.
A) 5/243  B) 1/12  C) 10/81  D) 1/6  E) 16/81

Solution: Number of ways in which a group of 2A,2B,2D can be formed in any order = 6!/(2!*2!*2!) [ formula for total of 6 items with 2 each of similar kind)   Total number of ways in which the die can be thrown independently = _ _ _ _ _ _ ; there are 6 places .First can be filled in 3 different ways A/B/D; Second in 3 diff ways again and so on.   So total number of ways = 3X3X3X3X3X3 = 3^6   There fore probability = 6!/(2!x2!x2!) by 3^6 = 90/3^6 = 10/81 Answer 10/81
Answer: C
Bunny's brother Sunny is 562 days older to him while his sister Jenny is 75 weeks older to Sunny. If Jenny was born on Tuesday, on which day was Bunny born?	Select the correct option:	A) Monday	B) Tuesday	C) Friday	D) Saturday	E) Thursday

Solution: 562-(75*7)= 
562-(75*7) = 37
37   37--------7*5=35   remaing 2+tuesday   ans:thursday   ANSWThursdayR:Thursday
Answer: E
39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 3 hours a day, complete the work?	Choose the correct choice from the following options: A) 10 B) 26 C) 14 D) 15 E) 16

Solution: Let the required number of days be x.   Less persons, More days (Indirect Proportion)   More working hours per day, Less days (Indirect Proportion)   Persons	30	:	39	:: 12 : x   Working hours/day	3	:	5   30 x 3 x x = 39 x 5 x 12   x =	(39 x 5 x 12)/(30 x 3)   x = 26.   ANSWER:26
Answer: B
Carol and Jordan draw rectangles of equal area. If Carol's rectangle measures 5 inches by 24 inches and Jordan's rectangle is 2 inches long, how wide is Jordan's rectangle, in inches?  Choose one
A) 65
B) 63
C) 52
D) 60
E) 68

Solution: Area of Carol's rectangle = 24*5= 
24*5 = 120
120   Let width of Jordan's rectangle= w   Since , the areas are equal   2w = 120   =>w = 60   Answer 60
Answer: D
Find the equation of a line which passes through A(4, -1) and is parallel to x axis.  Choose one: A) y=-2 B) y=3 C) y=2 D) y=-1 E) y=0

Solution: The slope of a line which is parallel to x-axis is zero. So   y+1=0(x−4)→y+1=0→y=−1   ANSWER : y=-1 y=-1
Answer: D
A function g(n), where n is an integer, is defined as the product of all integers from 1 to n. How many of the followings must be a prime number?
g(12) + 5; g(12) + 6; g(12) + 7; and g(12) + 8?
Choose the correct choice from the following answers
A) 1	B) 2	C) 3	D) 4	E) none

Solution: g(12) is the product of all integers from 1 to 12, so g(12) = 12!   Thus g(12) is a multiple of all the integers from 1 to 12.   Then g(12) is a multiple of 7, 8, 9, and 10.   7 divides g(12)+7   8 divides g(12)+8   9 divides g(12)+9   10 divides g(12)+10   The answer is none.
Answer: E
The value of P, when 4864 x 9P2 is divisible by 12, is:
Pick.
A) 2  B) 5  C) 8  D) 9  E) 1

Solution: Since 4864 is divisible by 4, so 9P2 must be divisible by 3.   Therefore (11+P) must be divisible by 3.   Therefore least value of P is 1   ANSW1R:1
Answer: E
A black box contains eight marbles, of which three are red, and the rest are blue. A white box contains five marbles, of which two are red, and the rest are blue. If two marbles are chosen from the black box at random, and one marble is chosen from the white box at random, what is the probability that all marbles will be blue? Select the correct option:
A) 3/14	B) 3/8	C) 5/13	D) 8/13	E) 17/20

Solution: From the prompt we know about 2 boxes and the marbles within each:   The black box contains   3 red   5 blue   8 total   The white box contains   2 red   3 blue   5 total   We're told to pull 2 marbles from the black box and 1 marble from the white box. We're asked for the probability that ALL marbles pulled will be BLUE.   Let's start with the 1st marble you pull from the black box....   The probability that it's blue is 5/8   Once you pull that first marble, there's 1 fewer blue marble in the black box.   When you grab the 2nd marble from the black box....   The probability that it's blue is 4/7   For the 3rd marble, we pull from the white box.   The probability that it's blue is 3/5   Now, we multiply the results: (5/8)(4/7)(3/5) = 3/14   3/14
Answer: A
How many kilograms of sugar costing Rs/.9 per kg must be mixed with 27kg of sugar costing Rs.7 per kg so that there may ba gain of 10% by selling the mixture at Rs.9.24 per kg Answers.
A) 22  B) 63  C) 88  D) 26  E) 18

Solution: i. If S.P and gain are given, C.P =        PxS gain . %100 100 Rs. ii. The rule of allegation  Required ratio is cheaper quantity : dearer quantity = (d-m) : (m-c) Answer with Explanation: Step I : S.P of 1 kg of mixture = Rs. 9.24 Gain = 10%    C.P of 1 kg of mixture =        24.9 10100 100 x = Rs. 8.40  Mean price = Rs. 8.40/- Step (ii) By the rule of allegation vi. C.P of 1 kg of sugar of I kind (p) = 900 vii. C.P of 1 kg of sugar of II kind (p) = 700 viii. Mean price (p) = 840 ix. d – m = 900 - 840= 
900 - 840 = 60
60 x. m – c= 840 – 700 = 140  Required ratio = 140 : 60 = 7 : 3 Step (iii) Let x kg of sugar of I kind be mixed with 27 kg of II kind    7 : 3 = x : 27  7/3 = x/27  x = 7/3 x 27 = 63 kg.   Answer:63
Answer: B
Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
Year	Item of Expenditure
Salary	Fuel and Transport	Bonus	Interest on Loans	Taxes
1998	288	98	3.00	23.4	83
1999	342	112	2.52	32.5	108
2000	324	101	3.84	41.6	74
2001	336	133	3.68	36.4	88
2002	420	142	3.96	49.4	98
The ratio between the total expenditure on Taxes for all the years and the total expenditure on Fuel and Transport for all the years respectively is approximately? Choose the most appropriate option
A) 10:13
B) 15:18
C) 5:8
D) 15:21
E) 15:23

Solution: Required ratio   =	[	(83 + 108 + 74 + 88 + 98)	]   (98 + 112 + 101 + 133 + 142)   =	[	451	]   586   =	1   1.3   =	10/ 13   10:13nswer is 10:13
Answer: A
The length of a rectangle is increased to 2 times its original size and its width is increased to 3 times its original size. If the area of the new rectangle is equal to 1800 square meters, what is the area of the original rectangle?  Choose the correct choice from the following choices:
A) 300 square meters B) 400 square meters C) 500 square meters D) 600 square meters E) 700 square meters

Solution: If L and W be the original length and width of the rectangle and its area is given by   L ? W   After increase the length becomes 2 L and the width becomes 3 W. The area is then given by (2 L) ? (3 W) and is known. Hence   (2 L) ? (3 W) = 1800   Solve the above equation to find L ? W   6 L ? W = 1800   L ? W = 1800 / 6= 
1800 / 6 = 300
300 square meters , area of original rectangle   correct answer 300 square meters
Answer: A
If a - b = 3 and a^2 + b^2 = 27, find the value of ab.  Pick:
A) 12	B) 15	C) 10	D) 18	E) 9

Solution: 2ab = (a^2 + b^2) - (a - b)^2   = 27 - 9= 
27 - 9 = 18
18   ab= 9.   Answer is 9.
Answer: E
John bought a total of 20 Mangoes and Oranges. Each Mango costs 80 cents and each orange costs 60 cents. If the average price of the 20 mangoes and oranges that John originally purchased was 69 cents, then how many oranges needs to return to raise the average price of his purchase to 72 cents?  Choose the correct choice from the following answers.
A) 4	B) 5	C) 6	D) 7	E) 8

Solution: Let number of mangoes be x, number of oranges be 12-x   0.80x +(20-x)0.60/20 = 0.69   solving for x, we get x = 9 --> Mangoes 9, Oranges 11   Now, number of oranges to be returned be y   0.80*9 + (11-y)*0.60/20-y = 0.72   solving for y, y = 5   Ans: 5
Answer: B
P cycles at a speed of 4 m/s for the first 8 seconds, 5 m/s for the next 8 seconds, 6 m/s for the next 8 and so on. Q cycles at a constant speed of 6.5 m/s throughout. If P and Q had to cycle for a 400 m race, how much lead in terms of distance, can P give Q and still finish at the same time as Q? Choose one.
A) 43.4 m
B) 56.6 m
C) 32.1 m
D) P cannot give a lead as Q is always ahead of P
E) None of these

Solution: DETAILED SOLUTION   Distance covered by P in 8 sec = 4 * 8= 
4 * 8 = 32
32 m   Distance covered by P in 16 sec= 32 + 5 *8= 
32 + 5 *8 = 72
72 m   Distance covered by P in 24 sec= 72 + 6 * 8= 
72 + 6 * 8 = 120
120 m   Distance covered by P in 32 sec= 120 + 7 * 8= 
120 + 7 * 8 = 176
176 m   Distance covered by P in 40 sec= 176 + 8 * 8= 
176 + 8 * 8 = 240
240 m   Distance covered by P in 48 sec= 240 + 9 * 8= 
240 + 9 * 8 = 312
312 m   Total distance in 48 sec= 312m   To cover balance 86 m with speed = 10 m/sec, time taken = 86/10= 
86/10 = 43/5 = around 8.6
8.6 sec   So P would finish 400 m in 48 + 8.6= 
48 + 8.6 = 56.6
56.6 seconds.   In 56.6 seconds, Q cycles  56.6 * 6.5= 
 56.6 * 6.5 = 367.9
367.9 m or B should have a 32.1 m lead to result in a dead heat.   32.1 mORRE32.1 mT ANSWER 32.1 m
Answer: C
What is the area of a square field whose diagonal of length 18 m?  Choose the correct choice from the following answers: A) 120 sq m B) 250 sq m C) 200 sq m D) 180 sq m E) 100 sq m

Solution: d2/2 = (18 * 18)/2 = 180   ANSWER:180 sq m
Answer: D
Sari and Ken climb up a mountain. At night, they camp together. On the day they are supposed to reach the summit, Sari wakes up at 06:00 and starts climbing at a constant pace. Ken starts climbing only at 08:00, when Sari is already 800 meters ahead of him. Nevertheless, Ken climbs at a constant pace of 500 meters per hour, and reaches the summit before Sari. If Sari is 50 meters behind Ken when he reaches the summit, at what time did Ken reach the summit?
Choose the correct choice from the following choices.
A) 16.3 B) 13:30 C) 14:00 D) 15:00 E) 15:30

Solution: Both Sari and Ken climb in the same direction.   Speed of Sari = 800/2= 
800/2 = 400
400 meters/hr (since she covers 800 meters in 2 hrs)   Speed of Ken= 500 meters/hr   At 8:00, distance between Ken and Sari is 800 meters. Ken needs to cover this and another 50 meters.   Time he will take = Total distance to be covered/Relative Speed = (800 + 50)/(500 - 400)= 
(800 + 50)/(500 - 400) = 17/2 = around 8.5
8.5 hrs   Starting from 8:00, in 8.5 hrs, the time will be 16:30   16.3nswer (16.3)
Answer: A
The number X is 200% of Y. The number Z increased by 200% is 50% of X. What percentage of Z is Y?
Pick one.
A) 33.3%	B) 100%	C) 200%	D) 300%	E) 333%

Solution: Picking Numbers:   Start with Z as question asks in terms of Z.   Let Z =100, thus, X=600 and Y=300 from question stems.   Hence Y is 300% of Z.   Ans 300%.
Answer: D
A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 9 salespeople on staff, how many different arrangements of winners are possible?	Choose the correct option:  A) 1,728  B) 1,440  C) 1,320  D) 504  E) 6

Solution: [quote=Bunuel]A company plans to award prizes to its top 3 salespeople, with the largest prize going to the top salesperson, the next-largest prize to the next salesperson, and a smaller prize to the third-ranking salesperson. If the company has 9 salespeople on staff, how many different arrangements of winners are possible?   9*8*7= 
9*8*7 = 504
504   Answer : 504
Answer: D
Mr. Hernandez, who was a resident of State X for only 8 months last year, had a taxable income of $22,500 for the year. If the state tax rate were 6 percent of the year’s taxable income prorated for the proportion of the year during which the taxpayer was a resident, what would be the amount of Mr. Hernandez’s State X tax for last year?	Options
A) $900	B) $720	C) $600	D) $300	E) $60

Solution: Total tax for the year = 22,500 x 6% = 1350   As stated Annual tax is prorated as per the duration of stay.   Prorated Tax = 1350 (8/12) = 900   $900nswer $900
Answer: A