MU-NLPC/Calc-aqua_rat huggingface dataset:
The output of a factory is increased by 10% to keep up with rising demand. To handle the holiday rush, this new output is increased by 40%. By approximately what percent would the output of the factory now have to be decreased in order to restore the original output?	Choose the most appropriate option
A) 20%  B) 24%  C) 30%  D) 35%  E) 79%

Solution: take it as original output =100.   to meet demand increase by 10%, then output=110.   to meet holiday demand , new output increase by 40% then output equals 154   To restore new holidy demand output to original 100.   final -initial/final*100   =54/154*100=35% approxiamately.   option 35% is correct.
Answer: D
A large delicatessen purchased X pounds of cheese for c dollars per pound. If d pounds of the cheese had to be discarded due to spoilage and the delicatessen sold the rest for s dollars per pound, which of the following represents the gross profit on the sale of the purchase? (gross profit equals sales revenue minus product cost)  Answers: A) s(X-d) - cX B) s(p − d) − pc C) c(p − d) − ds D) d(s − c) − pc E) pc − ds

Solution: Total cost price = c*X ............... (1)   Wastage = d pounds   Quantity sold = X-d   Selling price per pound = s   Total selling price = s(X-d) ........... (2)   Profit = (2) - (1)   = s(X-d) - cX   s(X-d) - cX
Answer: A
Find the average of the first 41 natural numbers?	Pick one.
A) 8 B) 9 C) 10 D) 11 E) 21

Solution: Average of the first 'n' natural numbers = (n + 1)/2   We get  (41 + 1)/2= 
 (41 + 1)/2 = 21
21   ANSW21R:21
Answer: E
If the sides of a triangle are 26 cm, 24 cm and 10 cm, what is its area?  Choose the correct choice from the following answers:	A) 120 cm2	B) 130 cm2	C) 312 cm2	D) 315 cm2	E) None of these

Solution: The triangle with sides 26 cm, 24 cm and 10 cm is right angled, where the hypotenuse is 26 cm.   120 cm2rea of the triangle = 1/2 * 24 * 10= 
1/2 * 24 * 10 = 120
120 cm2   120 cm2NSWER:120 cm2
Answer: A
A cricketer has a certain average for 10 innings. In the eleventh inning, he scored 108 runs, there by increasing his average by 6 runs. His new average is?	Choose the correct answer:
A) 48 runs	B) 72 runs	C) 62 runs	D) 54 runs	E) 45 runs

Solution: Let average for 10 innings be x. Then,   (10x + 108)/11   = x + 6   = 11x + 66   = 10x + 108   = x = 42.   New average = (x + 6)   = 48 runs.   48 runsnswer:48 runs
Answer: A
It takes 6 beavers 10 hours to build a certain dam, working at a uniform rate. If five beavers start to build the same dam at noon, and one beaver per hour is added beginning at 6:00 PM, at what time will the dam be complete? Answers:
A) 7:30 PM  B) 8:00 PM  C) 8:30 PM  D) 9:00 PM  E) 10:00 PM

Solution: The rate of 1 beaver is 1/60.   The amount of work done by 5 beavers in 6 hours is 5/60 *6 = 30/60   In the next hour, 6 beavers do 6/60 for a total of 36/60.   In the next hour, 7 beavers do 7/60 for a total of 43/60.   In the next hour, 8 beavers do 8/60 for a total of 51/60.   In the next hour, 9 beavers do 9/60 for a total of 60/60.   The dam will be completed at 10:00 pm.   The answer is 10:00 PM.
Answer: E
M is 30% of Q. Q is 20% of P. N is 50% of P. Find M:N ratio
Choices.
A) 1:25
B) 2:25
C) 3:25
D) 4:25
E) 5:25

Solution: Let p be 100   N = 50% of 100 (P=100) = 50   Q= 20% of 100 (P=100) = 20   M = 30% of 20 (Q=20) = 6   M:N = 6:50   M:N = 3:25   ANSWER:3:25
Answer: C
Two buses A and B leave the same bus depot, A towards the North and B towads the East. The bus A travels at a speed of 5 km/hr more than that of the bus B. If after four hours the distance between the two buses is 100 km, find the speed of the bus A.	Pick one:
A) 60 kmph B) 40 kmph C) 20 kmph D) 15 kmph E) 25 kmph

Solution: Let the speed of the bus B be x km/hr. Then the speed of the bus A will be ( x +5) kmph   Distance traveled in 4 hours is 4x and 4(x + 5) for the two buses respectively   (4x)2 + {4 (x + 5) }2 = (100)2   16x2 + 16x2 + 160x + 400 = 1000   32x2 +160x –9600 = 0   x2 + 5x –300 = 0 (x-15) (x +20 ) = 0   x = 15   :. Speed of the bus A = 15 +5= 
15 +5 = 20
20 kmph   ANSWER:20 kmph
Answer: C
A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?
Select the correct option:  A) 22  B) 27  C) 48  D) 99  E) 23

Solution: D = 540 + 180= 
540 + 180 = 720
720   S= 54 * 5/18= 
54 * 5/18 = 15
15 mps   T= 720/15= 
720/15 = 48
48 sec   Answer: 48
Answer: C
Group A has 6 boys and 3 girls, group B has 2 boys and 2 girls and group C has 4 boys and 2 girls. One student is selected from each of the group. Find the probability that one girl and two boys are among the three selected? Choices.
A) 3/45  B) 1/18  C) 29/10  D) 7/18  E) 7/27

Solution: Group A has 6 boys and 3 girls; 9   Group B has 2 boys and 2 girls; 4   Group C has 4 boys and 2 girls. 6   Selected group should have one girl and two boys.   Girl from A, boy from B, boy from C: 3/9*2/4*4/6 = 1/9;   Boy from A, girl from B, boy from C: 2/4*2/4*4/6 = 1/6;   Boy from A, boy from B, girl from C: 6/9*2/4*2/6 = 1/9.   Sum = 1/9 + 1/6 + 1/9 = 7/18.   Answer: 7/18.
Answer: D
587 x 999 = ? Pick: A) 586413 B) 587523 C) 614823 D) 615173 E) None of them

Solution: =587 x 999 = 587 x (1000-1)   =587 x 1000 - 587 - 1   =587000 - 587= 
587000 - 587 = 586_413
586413   586413nswer is 586413
Answer: A
If you cut a 20ft piece of wood into two pieces making one piece 4ft longer than the other. What size is the smaller piece?  Select.
A) 4ft
B) 6ft
C) 8ft
D) 10ft
E) 12ft

Solution: Total length is 20ft, one piece is 4ft longer (x+4), leaving the other piece to figure out (x).   (x)+ (x+4)=20   x+x+4-4=20-4   2x=16   2x/2=16/2= 
16/2 = 8
8   The piece is 8ft) 8ft.
Answer: C
If a continuous cable 10 meters long was marked off at intervals of 1/3 meter and also 1/5 meter, and then if the cable were cut at each mark, how many different size length of cable would result?	Choose the correct choice from the following:
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: In this particular example length (10 meter) is just extraneous information.   The location of the marks for 1/3 meter would be 5/15, 10/15, 15/15, etc...   The location of the marks for 1/5 meter would be 3/15, 6/15, 9/15, 12/15, 15/15, etc...   The distances between marks are 3/15, 2/15, and 1/15.   The answer is 3.
Answer: C
Thirty percent of forty percent of fifty is sixty percent of what percent of two-hundred ?  Choose one.
A) 0.5%
B) 1%
C) 5%
D) 50%
E) 500%

Solution: x percent can be written as x/100   So, we get: (30/100)(40/100)(50) = (60/100)(x/100)(200)   Simplify all fractions to get: (3/10)(2/5)(50) = (3/5)(x/100)(200)   Expand: 300/50 = 600x/500   Simplify: 6 = 6x/5   Multiply both sides by 5 to get: 30 = 6x   Solve: x = 5   Answer: 5%
Answer: C
A bottle contains a certain solution. In the bottled solution, the ratio of water to soap is 3:2, and the ratio of soap to salt is four times this ratio. The solution is poured into an open container, and after some time, the ratio of water to soap in the open container is halved by water evaporation. At that time, what is the ratio of water to salt in the solution? Choose the correct choice from the following answers
A) 1:1	B) 2:3	C) 3:2	D) 9:4	E) 36:8

Solution: Water:soap = 3:2   Soap:Salt=12:2   => For 12 soap, salt = 2   => For 2 Soap, salt = (2/12)*2 = 1/3   So, water:soap:salt = 3:2:1/3 = 36:24:4   After open container, water:soap:salt = 18:24:4   So, water:salt = 18:4 = 36:8   36:8
Answer: E
Of the science books in a certain supply room, 40 are on botany, 55 are on zoology, 90 are on physics, 50 are on geology, and 110 are on chemistry. If science books are removed randomly from the supply room, how many must be removed to ensure that 80 of the books removed are on the same area science?  Choose the most appropriate option.
A) 187 B) 256 C) 282 D) 304 E) 331

Solution: The worst case scenario is to remove all the books on botany, zoology, and geology.   Also we can remove 79 books each from physics and chemistry.   The total is  40 + 55 + 50 + 79 + 79= 
 40 + 55 + 50 + 79 + 79 = 303
303.   The next book removed must either be physics or chemistry, ensuring 80 books in that subject.   The answer is 304.
Answer: D
210 students were asked in a survey if they preferred Windows or Mac brand computers. 60 Students claimed that they preferred Mac to Windows brand computers. One third as many of the students who preferred Mac to Windows, equally preferred both brands. 90 of the students had no preference. How many of the students in the survey preferred Windows to Mac brand computers?
Choose the correct choice.
A) 25  B) 40  C) 50  D) 60  E) 75

Solution: We are told that60 Students claimed that they preferred Mac to Windows, which means that 60 preferred Mac but NOT Windows, so # of students who preferred Mac (P(A) as you wrote), does not equal to 60, it equals to 60+20 (20 is # of students who equally preferred both brands). Also we are asked to find # of the students who preferred Windows to Mac, so if you denote x as those who prefer Windows then you should calculate x-20.   So, if we use your formula it should be: 210={Mac}+{Windows}-{40oth}+{Neither}=(60+20)+x-20+90 --> x=60 (# of student who prefer Windows) --> # of the students who preferred Windows to Mac is x-20=40.
Answer: B
In a circuit board factory, all circuit boards that pass a verification process are certified. Every board that fails the verification process is indeed faulty, but 1/8 of those that pass are also faulty.
Approximately how many faulty circuit boards exist in a group of 3,200 circuit boards where 64 fail inspection? Choose the correct choice from the following options
A) 72
B) 192
C) 456
D) 256
E) 264

Solution: Total of 3,200 boards. All that fail verification are indeed faulty. So the 64 are indeed faulty. 1/8 those that pass are also faulty.   From the 3,200 we know 64 fail. So 3,136 must pass. Of these 1/8 are faulty. 3,136 divided by 8 gives you 392.   What one must do now is to add to the 392 which were not detected the actually detected faulty ones, namely the 64.   Total faulty: 456.   Answer: 456
Answer: C
In what time will a railway train 96 m long moving at the rate of 45 kmph pass a telegraph post on its way?
Choose the correct choice from the following answers
A) 3 sec B) 8 sec C) 5 sec D) 6 sec E) 7 sec

Solution: T =96/45 * 18/5 = 8 sec   ANSWER:8 sec
Answer: B
A watch was sold at a loss of 10%. If it was sold for Rs.168 more, there would have been a gain of 4%. What is the cost price?
Choose the correct choice from the following: A) s:1000 B) s:1067 C) s:1200 D) s:1028 E) s:1027

Solution: 90%   104%   --------   14% ---- 168   100% ---- ? =>   Rs:1200   Answer: s:1200
Answer: C
Sides of a rectangular park are in the ratio 4: 3 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?	Answers:
A) s.132.3 B) s.129 C) s.125 D) s.120 E) s.121

Solution: 4x * 3x = 3750 => x = 17.7   2(82.3 + 50) = 264.6 m   264.6 * 1/2 = Rs.132.3   s.132.3nswer:s.132.3
Answer: A
A train 225 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:	Choose the correct choice:
A) 86  B) 50  C) 12  D) 13  E) 67

Solution: Speed of the train relative to man = (225/10) m/sec = (45/2) m/sec. [(45/2) * (18/5)] km/hr = 81 km/hr. Let the speed of the train be x km/hr. Then, relative speed = (x - 5) km/hr. x - 5 = 81 ==> x = 86 km/hr.   86nswer: Option 86
Answer: A
The average of 45 results is 12. The average of first 22 of them is 15 and that of last 22 is 20. Find the 23 result?  Select:  A) 600  B) 480  C) 750  D) 650  E) 560

Solution: 23th result = sum of 45results - sum of 44 results   12*45-15*22+20*22 = 540-330+440= 
540-330+440 = 650
650   Answer is 650
Answer: D
The total age of A and B is 10 years more than the total age of B and C. C is how many years younger than A?  Choose the correct option
A) 12  B) 10  C) C is elder than A  D) Data inadequate  E) None

Solution: Solution   [(A+B) - (B+C)]	= 10   â€¹=â€ºA - C   = 10.   Answer 10
Answer: B
On increasing the number of lines in a page by 80, they become 240. What is the % of increase in the no. of lines in the page?  Pick
A) 20%	B) 305	C) 50%	D) 55%	E) 60%

Solution: Explanation : Number of pages increased = 80   Now , the number of pages of book = 240   Number of pages of the books before increase = 240 – 80 = 160   % increase in the number of pages in the book = 80 160   x 100% = 50%   50%
Answer: C
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?  Choose the correct choice from the following choices:
A) 12 years B) 15 years C) 17 years D) 19 years E) 21 years

Solution: Let the present ages of Arun and Deepak be 4x years and 3x years respectively.   4x + 6 = 26 4x = 20   x = 5.   Deepak's age = 3x = 15 years.   Answer: 15 years
Answer: B
The first photo shoot takes 3 minutes long and then the following shoots are taken at a rate of 20 seconds/shoot as the model is already at the scene. What is the maximum number of photo shoots taken under 10 minutes ?  Options:
A) 13	B) 14	C) 15	D) 20	E) 22

Solution: a must be an integer as it is the number shoots at a rate of 20sec/shoot   3*60 + 20a = 10*60   20a = 420   a = 21   The total number of shoots -->1 +21 = 22 and   23th shoot will be taken at 620 seconds which is above 10 minutes   ANSW22R: 22-- 1 +21= 
-- 1 +21 = 22
22 and   23th shoot will be taken at 620 seconds which is above 10 minutes   ANSW22R: 22
Answer: E
If after 500 grams of water were added to the 24%-solution of alcohol, the strength of the solution decreased by one-third, how much of the 24%-solution was used?
Choices.
A) 180 grams  B) 220 grams  C) 250 grams  D) 350 grams  E) 1000 grams

Solution: I too think 1000 grams should be the answer.   My reasoning is   The h20 content in 200 gms of water is 1   h20 content in 24% solution is 0.76   Resulting new solution's concentration decreases by one third means. Now it becomes 16% solution which means h20 content is 0.84   Let amount of solution be X   Then the equation can be set up   500*1 + 0.76X = 0.84 (X+500)   0.08X = 80   8X = 8000   X = 1000 (ANS 1000 grams)
Answer: E
There is enough provisions for 100 girls in a hostel for 50 days. If there were 20 men less, how long will the provision last?
Choose the correct choice from the following answers:  A) 250  B) 255  C) 260  D) 265  E) 270

Solution: We have, M1D1 = M2D2   100*50= 20* D2   D2 = 100*50/20= 
100*50/20 = 250
250 days.   250NSWER:250
Answer: A
Which of the following fractions R, if written as a decimal, would have a 2 in the thousandths place ?
Choose the correct option.
A) 3/11  B) 7/9  C) 1/8  D) 4/7  E) 1/6

Solution: (A) R=3/11 = 0.2727272727....   3/11nswer: 3/11
Answer: A
A box contains 21 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is  Choose the correct option:
A) 4/19
B) 7/19
C) 12/19
D) 21/95
E) 31/88

Solution: Solution   P( None is defective)   = 17C2 / 21C2   = 57/88.   P( at least one is defective)   = (1- 57/88)   = 31/88.   Answer 31/88
Answer: E
Sam’s car was fined when he gave Joe and Peter a ride, so they decided to help Sam pay the fine. Joe paid $8 more than 1/4 of the fine and Peter paid $8 less than 1/3 of the fine, leaving pay $15 less than 1/2 the fine to complete the payment. What fraction of the fine did Sam pay?	Pick:
A) $70
B) $72
C) $73
D) $74
E) $75

Solution: Call the fine F. Joe paid (1/4)F + 4 and Peter paid (1/3)F – 4, leaving (1/2)F – 5 left. If we add those three up, they should add up to F.   F = [(1/4)F + 8] + [(1/3)F – 8] + [(1/2)F – 15]   F = (1/4)F + (1/3)F + (1/2)F – 15   Multiply all terms by 12 to clear the fractions.   12F = 3F + 4F + 6F – 180   12F = 13 F – 180   –F = – 180   F = 180   Well, if the fine cost $180, then Sam paid the part not covered by Joe or Peter. Half the fine is $90, and Sam paid $15 less than this: $75   Answer = $75
Answer: E
On a two-dimensional coordinate plane, the line s = x^2 - x^3 touches the x-axis in how many places?	Choose the correct choice from the following choices:
A) 0 B) 1 C) 2 D) 3 E) 4

Solution: Apparently it's s = x^2 - x^3 instead of s = x^2 - s^3.   In this case: the x-intercept is the value(s) of x for s = 0.   0 = x^2 - x^3;   0 = x^2(1 - x);   x = 0 or x = 1.   Answer: 2.
Answer: C
What is R’s share of profit in a joit venture?
I.Q started business investing Rs. 80,000.
II.R joined him after 3 months.
III.P joined after 4 months with a capital of Rs. 1,20,000 and got Rs. 6000 as his share profit. Select the correct option:
A) All I, II and III	B) I and III only	C) II and III only	D) Even with all I, II and III, the answer cannot be arrived at	E) None of these

Solution: Explanation:   From I, II and III, we get P : Q : R = (120000 x 8) : (80000 x 12) : (x x 9).   Since R’s investment is not given, the above ratio cannot be give.   Given data is inadequate.   Answer None of these
Answer: E
At a meeting, 5 people are to be seated around a circular table. Two seating arrangements are considered different only when the positions of the people are different relative to each other. What is the total number of different possible seating arrangements for the group? Choose the correct answer.
A) 12	B) 24	C) 120	D) 144	E) 720

Solution: The number of arrangements of n distinct objects in a row is given by n!   The number of arrangements of n distinct objects in a circle is given by (n−1)!   "The difference between placement in a row and that in a circle is following: if we shift all object by one position, we will get different arrangement in a row but the same relative arrangement in a circle. So, for the number of circular arrangements of n objects we have:   R=n!-n=(n−1)!   (n−1)!=(5−1)!=24   Answer: 24
Answer: B
A certain kind of necklace is made from 9 silver, 6 red, and 3 black beads. What is the maximum number of these necklaces that can be made from 99 beads of each color ?
Choices: A) 8 B) 9 C) 10 D) 11 E) 15

Solution: Atleast 9 silver breads are needed to make a necklace, so irrespective of the combinations of red and black beads, the number of necklaces that can be formed will be   99/9= 
99/9 = 11
11   Answer:- 11
Answer: D
In the next Worldcup of cricket there will be 12 teams, divided equally in 2groups. Teams of eachgroup will play a match against each other. From each group 3 top teams will qualify for the next round. In this round each team will play against each others once. 4top teams of this round will qualify for the semifinal round, where they play the best of 3matches. The Minimum number of matches in the next World cup will be  Choose the correct choice from the following answers.
A) 34 B) 45 C) 53 D) 55 E) 59

Solution: The number of matches in first round,   = 6C2 +6C2;   Number of matches in next round,   = 6C2;   Number of matches in semifinals,   = 4C2;   Total number of matches,   = 6C2 +6C2+6C2+4C2+2.   = 53.   53
Answer: C
The least number which when increased by 7 each divisible by each one of 24, 32, 36 and 54 is :  Choose the correct choice from the following options: A) 857 B) 859 C) 869 D) 4320 E) None of these

Solution: Solution   Required number = (L.C.M. of 24, 32, 36, 54) - 7 = 864 - 7= 
864 - 7 = 857
857. 857nswer 857
Answer: A
The average of first four prime numbers greater than 20 is?
Choose the correct choice from the following
A) 10 B) 20 C) 30 D) 40 E) 50

Solution: 23 + 29 + 31 + 37= 
23 + 29 + 31 + 37 = 120
120/4= 
120/4 = 30
30   ANSWER:30
Answer: C
Bradley owns b video game cartridges. If Bradleyâ€™s total is one-fifth the total owned by Andrew and five times the total owned by Charlie, how many video game cartridges do the three of them own altogether, in terms of b?	Answers.
A) 16/3)b
B) 17/4)b
C) 13/4)b
D) 31/5)b
E) 7/12)b

Solution: Step 1: Categorize the problem   This problem is testing basic algebra and equations, with an extra layer of complexity by having variables in the answer choices.   Step 2: Think like the test maker   What is the key detail or key details in the problem? The key detail to immediately recognize is that the problem gives you Andrew and Charlieâ€™s totals in relation to Bradleyâ€™s total rather than giving you Bradleyâ€™s total in relation to the other two; and then the problem asks you to solve the problem in terms of b. This means that you have to relate Andrew and Charlieâ€™s values in relation to Bradleyâ€™s total. The test maker is attempting to force you to structure the problem in the opposite way that most people are used to structuring information. By gaining this insight, it makes it easier to solve the problem.   Step 3: Solve the problem   b = Bradleyâ€™s total   5b = Andrewâ€™s total   (1/5)b = Charlieâ€™s total   Add each total   b + 5b+ (1/5)b = 6b + (1/5)b = (30/5)b + (1/5)b = (31/5)b   Therefore,choose 31/5)b.
Answer: D
A train is 360 meter long is running at a speed of 52 km/hour. In what time will it pass a bridge of 140 meter length.
Select the correct option.
A) 24.62 seconds  B) 34.62 seconds  C) 44.62 seconds  D) 54.62 seconds  E) None of these

Solution: Explanation:   Speed = 52 Km/hr = 52*(5/18) m/sec   = 130/9 m/sec   Total distance = 360+140= 
360+140 = 500
500 meter   Time= Distance/speed   =500/130/9=34.62 seconds   Answer: 34.62 seconds
Answer: B
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?	Choose the correct choice from the following.
A) 120 metres  B) 180 metres  C) 324 metres  D) 150 metres  E) 160 metres

Solution: Explanation:   Speed=	60 X5/18 m/sec	=50/3m/sec   Length of the train = (Speed x Time).   Length of the train =50/3 X 9 m =150m   ANSWER IS 150 metres
Answer: D
A hiker walked for 3 days. She walked 18 miles on the first day, walking 3 miles per hour. On the second day she walked for one less hour but she walked one mile per hour, faster than on the first day. On the third day she walked at 5 miles per hour for 3 hours. How many miles in total did she walk?  Select the correct option
A) 53 B) 44 C) 58 D) 60 E) 62

Solution: First day - 18 miles with 3 miles per hours then total - 6 hours for that day   Second day - 4 miles per hour and 5 hours - 20 miles   Third day - 5 miles per hour and 3 hours - 15 miles   Total 18+20+15= 
18+20+15 = 53
53   53nswer: option 53.
Answer: A
In a game, a player can win by getting six consecutive tails in seven throws of a coin. What is the probability of winning if the player gets a tail on the first two throws?  Choose the most appropriate option:
A) 1/2
B) 1/4
C) 1/8
D) 1/16
E) 1/32

Solution: The only way to win is to get a tail on each of the next four throws.   P(four tails)=(1/2)^4=1/16   The answer is 1/16.
Answer: D
From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a black card and the second card is a king? Choose the correct choice from the following answers.
A) 1/26
B) 1/13
C) 3/52
D) 3/26
E) 15/26

Solution: P(black card) = 1/2   P(king) = 1/13   P(black card then a king) = 1/2 * 1/13 = 1/26   The answer is 1/26.
Answer: A
A can give B 200 meters start and C 400 meters start in a kilometer race. How much start can B give C in a kilometer race? Pick one
A) 111.12  B) 250  C) 111.64  D) 111.11  E) 101.12

Solution: A runs 1000 m while B runs 800 m and C runs 600 m.   The number of meters that C runs when B runs 1000 m,   = (1000 * 600)/800= 
(1000 * 600)/800 = 750
750 m.   B can give C= 1000 - 750= 
1000 - 750 = 250
250 m.   Answer:250
Answer: B
10^25 - 460 is divisible by all of the following except:  Choose the correct choice from the following.
A) A.11
B) B.9
C) C.5
D) D.4
E) E.3

Solution: The last three digits ( 1000 - 460 ) 540   540 is divisible by 3,4,9,5   540 is not evenly divisible by 11 so the answer is A.11) 11
Answer: A
Lilly has 10 fish and Rosy has 8 fish. In total, how many fish do they have in all?	Options:
A) 12
B) 14
C) 16
D) 18
E) 20

Solution: 10+8= 
10+8 = 18
18   The answer is 18.
Answer: D