MU-NLPC/Calc-aqua_rat huggingface dataset:
One day a car rental agency rented 3/4 of its cars, including 5/6 of its cars with CD players. If 3/5 of its cars have CD players, what percent of the cars that were not rented had CD players?  Choose the correct option:	A) 13/20	B) 11/15	C) 7/10	D) 4/7	E) 2/5

Solution: The cars with CD players which were not rented is (1/6)(3/5) = 1/10 of all the cars.   The cars which were not rented is 1/4 of all the cars.   The percent of non-rented cars which had CD players is (1/10) / (1/4) = 2/5   The answer is 2/5.
Answer: E
If the LCM of two integers I, J (where J> I and I>1) is I*J, then which of the following can not be true?	Choose the correct choice from the following options.
A) All Prime factors of I must be Prime factors of J.
B) Both I and J can be consecutive integers.
C) Both I and J can be Prime Numbers.
D) I and J do not share any Prime factors.
E) I and J do not have a common factor

Solution: If LCM of two numbers I and J is the product IJ then both numbers are Co- prime.   (Co-prime numbers are any two numbers which have an HCF of 1 i.e. when two numbers have no common prime factor apart from the number 1).   Numbers that can be Co-Prime are :   1) Two consecutive natural numbers.   2) Two consecutive odd numbers.   3) Two prime numbers.   4) One prime number and the other a composite number such that the composite number is not a multiple of the prime number.   With above four statements it can be concluded that Options B,C,D and E are all true.   Only Option A cannot be true.   Hence answer is All Prime factors of I must be Prime factors of J.
Answer: A
Total of ages of A,B and C at present is 90 years. If ratio of this ages is 2 : 3 : 4 what will be the age of C after 6 years?	Choose the correct choice:  A) 45 years  B) 42 years  C) 46 years  D) 37 years  E) None of the above

Solution: 2+3+4= 
2+3+4 = 9
9   4*(90/9)= 
4*(90/9) = 40
40yrs   after 6yrs=46   ANSWER:46 years
Answer: C
In a colony of 70 residents, the ratio of the number of men and women is 5 : 2. Among the women, the ratio of the educated to the uneducated is 1 : 4. If the ratio of the number of educated to uneducated persons is 8 : 27, then find the ratio of the number of educated to uneducated men in the colony?
Choose the correct choice from the following options.
A) A)1:4
B) B)1:1
C) C)1:8
D) D)1:9
E) E)1:3

Solution: Number of men in the colony = 5/7 * 70= 
5/7 * 70 = 50
50.   Number of women in the colony= 2/7 * 70 = 40.   Number educated women in the colony = 1/5 * 30= 
1/5 * 30 = 6
6.   Number of uneducated women in the colony= 4/5 * 50 = 24.   Number of educated persons in the colony = 8 /35 * 70= 
8 /35 * 70 = 16
16.   As 6 females are educated, remaining 10 educated persons must be men.   Number of uneducated men in the colony= 50 - 10= 
50 - 10 = 40
40.   Number of educated men and uneducated men are in the ratio 10 : 40 i.e., 1:4.   1:4nswer:1:4
Answer: A
Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month. Of the geese that survived the first month, 3/5 did not survive the first year. If 100 geese survived the first year and if no more than one goose hatched from each egg, how many goose eggs were laid at the pond?  Choose the most appropriate option.
A) 280 B) 400 C) 540 D) 500 E) 840

Solution: Of the goose eggs laid at a certain pond, 2/3 hatched and 3/4 of the geese that hatched from those eggs survived the first month:   2/3*3/4 = 1/2 survived the first month.   Of the geese that survived the first month, 3/5 did not survive the first year:   (1-3/5)*1/2 = 1/5 survived the first year.   100 geese survived the first year:   1/5*(total) = 100 --> (total) = 500.   Answer: 500.
Answer: D
One night a certain hotel rented 4/5 of its rooms, including 2/3 of their air conditioned rooms. If 3/5 of its rooms were air conditioned, what percent of the rooms that were not rented were air conditioned?	Choose the correct choice from the following answers:
A) 60%
B) 70%
C) 80%
D) 90%
E) 100%

Solution: The rooms which were not rented is 1/5   The AC rooms which were not rented is (1/3)*(3/5) = 1/5   The percentage of unrented rooms which were AC rooms is   (1/5) / (1/5)= 
  (1/5) / (1/5) = 1
1= 100%   The answer is 100%.
Answer: E
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and
second half at the rate of 24 km/hr. Find the total journey in km
Choose the correct choice:
A) 200 Km  B) 222 Km  C) 224 Km  D) 248 Km  E) None of these

Solution: Explanation:   Let time taken to travel the first half = x hr   Then time taken to travel the second half = (10 - x) hr   Distance covered in the the first half = 21x [because, distance = time*speed]   Distance covered in the the second half = 24(10 - x)   Distance covered in the the first half = Distance covered in the the second half   So,   21x = 24(10 - x)   => 45x = 240   => x = 16/3   Total Distance = 2*21(16/3) = 224 Km [multiplied by 2 as 21x was distance of half way]   Answer: 224 Km
Answer: C
A semicircle has a radius of 9. What is the approximate perimeter of the semicircle? Choose the correct choice:
A) 16
B) 25
C) 33
D) 46
E) 58

Solution: The perimeter of a circle is 2*pi*r.   The perimeter of a semicircle is 2*pi*r/2 + 2r = pi*r + 2r   The perimeter is pi*9 + 2*9 which is about 46.   The answer is 46.
Answer: D
The probability of two events A and B are 0.20 and 0.40 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________  Options:  A) 0.45  B) 0.4  C) 0.5  D) 0.55  E) 0.6

Solution: we are apply that formula..............   P(AorB)=P(A)+P(B)-P(A AN0.55 B)   =.20+.40-.15= 
.20+.40-.15 = 0.45
.45   but the probability of neither A nor B=1-.45= 
1-.45 = 0.55
0.55   ANSWER:0.55
Answer: D
A can work four times as fast as B. Together they can finish a job in 12 days. In how many days can A complete the job alone? Choose the correct choice from the following answers:
A) 14 B) 15 C) 16 D) 17 E) 18

Solution: B's rate is x and A's rate is 4x.   x + 4x = 1/12   x = 1/60   A's rate is 4x = 1/15   A can complete the job in 15 days.   The answer is 15.
Answer: B
100 identical coins each with probability 'pp' showing up heads & tossed.	Select:	A) 13/101	B) 11/101	C) 51/101	D) 53/102	E) 54/101

Solution: Let aa be the number of coins showing heads   Then, P(A=50)=P(A=51)P(A=50)=P(A=51)   ⇒10051/10150×P50×(1−P)50⇒10051/10151×P51×(1−P)49⇒10051/10150×P51×(1−P)50=10051/10151×P⇒51(1âˆ′P)=50P⇒P=51/101   51/101
Answer: C
If a#b = ab – b + b^2, then 3#4 =	Select: A) 2 B) 8 C) 15 D) 24 E) 35

Solution: Solution -   Simply substitute 3 and 4 in equation in the place of a and b respectively.   3#4 = 3*4 - 4 + 4^2 = 12 - 4 + 16= 
12 - 4 + 16 = 24
24. ANS 24
Answer: D
How many different four letter words can be formed (the words need not be meaningful using the letters of the word "MEDITERRANEAN" such that the first letter is E and the last letter is R?  Choose the correct choice from the following options:
A) 59 B) 77 C) 36 D) 99 E) 17

Solution: Explanation:   The first letter is E and the last one is R.   Therefore, one has to find two more letters from the remaining 11 letters.   Of the 11 letters, there are 2 Ns, 2Es and 2As and one each of the remaining 5 letters.   The second and third positions can either have two different letters or have both the letters to be the same.   Case 1: When the two letters are different. One has to choose two different letters from the 8 available different choices. This can be done in 8 * 7= 
8 * 7 = 56
56 ways.   Case 2: When the two letters are same. There are 3 options - the three can be either Ns or Es or As. Therefore, 3 ways.   Total number of possibilities= 56 + 3= 
56 + 3 = 59
59   59nswer: 59) 59
Answer: A
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is: Choose the correct choice from the following answers:
A) 101 B) 107 C) 111 D) 185 E) 186

Solution: Let the numbers be 37a and 37b.   Then, 37a x 37b = 4107   ab = 3.   Now, co-primes with product 3 are (1, 3).   So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).   Greater number = 111.   Answer: Option 111
Answer: C
A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 30.00?  Choose the correct choice from the following answers.
A) $ 10.00  B) $ 11.20  C) $ 14.40  D) $ 16.80  E) $ 18.00

Solution: For retail price = $30   First maximum discounted price = 30 - 30% of 30 = 30-9= 
30-9 = 21
21   Price after additional discount of 20%= 21 - 20% of 21 = 21 - 4.2= 
21 - 4.2 = 16.8
16.8   Answer: Option $ 16.80
Answer: D
About the number of pairs which have 20 as their HCF and 136 as their LCM, the conclusion can be  Pick.
A) only one such pair exists	B) only two such pairs exist	C) many such pairs exist	D) yes such pair exists	E) paid does not exists

Solution: Explanation:   HCF is always a factor of LCM. ie., HCF always divides LCM perfectly.   Correct Option: paid does not exists
Answer: E
If two different solutions of alcohol with a respective proportion of water to alcohol of 3:1 and 2:3 were combined, what is the concentration of alcohol in the new solution if the original solutions were mixed in equal amounts?
Choose one.
A) 30.0%  B) 36.6%  C) 42.5%  D) 44.4%  E) 60.0%

Solution: Alcohol: Water   First mixture -- 3:1 -- 15:5   Second mixture -- 2:3 -- 8:12   Equal amounts of the mixture were combined, hence the final mixture will be in the ratio -- (15+8): (5+12) -- 23:17   % of alcohol -- 17/(23+17) * 100   = (17/40) * 100= 
(17/40) * 100 = 85/2 = around 42.5
42.5   ANSWER:42.5%
Answer: C
How many prime numbers are between 25/8 and 213/6? Options
A) 6 B) 7 C) 8 D) 9 E) 10

Solution: 25/8 = 4-   213/6 = 36-   Prime numbers between 4 and 36 are 5, 7, 11, 13, 17, 19, 23, 29, and 31   - sign signifies that the number is marginally less .   Answer 9
Answer: D
Rs.20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?	Choose the correct choice from the following choices: A) 10.4 B) 11 C) 14.8 D) 15.4 E) none

Solution: Sol.   S.I. on Rs. (260 - 20) for a given time = Rs. 20.   S.I. on Rs. 240 for half the time = Rs. 10.   T.D. on Rs. 250 = Rs. 10.   ∴ T.D. on Rs. 260 = Rs. [10/250 * 260] = Rs. 10.40   10.4nswer 10.4
Answer: A
If m^(-1) = -1/6 then m^(-2) is equal to
Choose the correct choice:  A) -9  B) -3  C) -1/9  D) 1/9  E) 1/36

Solution: You made a mistake here.   You're right till   m^-2 = 1/m^2 and m^-1 = 1/m^1 = 1/m   given m^-1 1/  1= 
1/  1 = 1
1/m   given m^-1= -(1/6) so, 1/m = -(1/6) solving this, m = -6   Now, m^-2 = 1/m^2 = 1/(-6)^2 = 1/36 ANS 1/36
Answer: E
If the cost price of 165 chocolates is equal to the selling price of 150 chocolates, the gain percent is Choose the most appropriate option:
A) 8
B) 9
C) 10
D) 11
E) 12

Solution: Let C.P. of each chocolate be Re. 1.   Then, C.P. of 150 chocolates = Rs. 150; S.P. of 150 chocolates = Rs. 165.   Gain % = 15/150 * 100= 
15/150 * 100 = 10
10%   Answer:10
Answer: C
In a farm, 2000 seeds were planted wheat and 3000 rice seeds were planted. If 57 percent of the seeds in plot I germinated and 42 percent of the seeds in plot II germinated, what percent of the total number of planted seeds germinated? Pick.
A) 45.5%  B) 46.5%  C) 48.0%  D) 49.5%  E) 51.0%

Solution: Plot I: 57% of 2000 wheat seeds germinated, hence  0.57*2000= 
 0.57*2000 = 1_140
1140 seeds germinated.   Plot II: 42% of 3000 rice seeds germinated, hence  0.42*3000= 
 0.42*3000 = 1_260
1260 seeds germinated.   Thus (germinated)/(total)= (1140 + 1260)/(2000 + 3000) = 2400/5000 = 48% seeds germinated.   Answer: 48.0%.
Answer: C
Of the students at a certain high school, 90 percent took a course in algebra or geometry and 30 percent took courses in both. If the percent of students who took a course in algebra was 2 times the percent of students who took a course in geometry, what percent of the students took a course in algebra but not geometry?
Select the correct option:
A) 50%	B) 40%	C) 45%	D) 35%	E) 30%

Solution: You can also just use the formula   n(A or B) = n(A) + n(B) - n(A and B)   90 = 2X + X - 30   X = 40   2X = 80   This is the number of people who took algebra including those who took both. To get the number of people who took only algebra, 80 - 30 = 50%   50%nswer (50%)
Answer: A
If x and y are positive real numbers such that x + y = 1, which of the following could be the value of 100x + 400y?
I. 80
II. 250
III. 399  Options
A) II only	B) III only	C) I and II	D) I and III	E) II and III

Solution: We know that x and y are both between 0 and 1.   The minimum limit of 100x + 400y is 100, when x is close to 1 and y is close to 0.   The maximum limit of 100x + 400y is 400, when x is close to 0 and y is close to 1.   The expression can take on any value between 100 and 400.   The answer is II and III.
Answer: E
David obtained 72, 60, 35, 62 and 84 marks (out of 100) in English, Mathematics,Physics, Chemistry and Biology What are his average marks ?	Select the correct option:  A) 75  B) 62.6  C) 87  D) 165  E) 11

Solution: Explanation:   Average = (72 +60+ 35+ 62+84 )/ 5 = 313/5 = 62.6.   Answer:62.6
Answer: B
If a = (3)b and c = 5b, then which of the following represents the average (arithmetic mean) of a, b, and c, in terms of b ?  Choose the correct choice from the following answers
A) b/3
B) b/4
C) 2b
D) 3b
E) 5b

Solution: a = (3)b and c =5b.   The mean = (a + b + c)/3 = (3b + b + 5b)/3 = 3b.   Answer is 3b
Answer: D
By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is?  Pick one: A) 5 B) 6 C) 8 D) 9 E) 1

Solution: Marked price = Rs. 300   C.P. = 100/120 * 300 = Rs. 250   Sale price = 90% of Rs. 300 = Rs. 270   Required gain % = 20/250 * 100= 
20/250 * 100 = 8
8%.   Answer:8
Answer: C
In a workshop there are 3 kinds of beds, 3 kinds of closets, 2 kinds of shelves and 7 kinds of chairs. In how many ways can a person decorate his room if he wants to buy in the workshop one shelf, one bed and one of the following: a chair or a closet?
Pick.
A) 168. B) 80. C) 60. D) 48. E) 16.

Solution: ways to select one shelf = 2   ways to select one bed = 3   ways to select one of the following: a chair or a closet = 7+3= 
7+3 = 10
10   ways to select all of them together= 2*3*10= 
2*3*10 = 60
60   Hence, 60. is the answer.
Answer: C
The simple form of the ratio 4/3:3/7 is?  Choose the correct choice from the following choices:  A) 7:3  B) 10:3  C) 15:3  D) 25:3  E) 30:3

Solution: 4/3 : 3/7 = 21:9 = 7:3   7:3NSWER:7:3
Answer: A
16 chess players take part in a tournament. Every player plays twice with each of his opponents. How many games are to be played?	Choose the correct choice from the following answers: A) 190 B) 200 C) 210 D) 220 E) 240

Solution: 2*16C2 = 2*120= 
2*120 = 240
240   The answer is 240.
Answer: E
A vessel of capacity 90 litres is fully filled with pure milk. Nine litres of milk is removed from the vessel and replaced with water. Nine litres of the solution thus formed is removed and replaced with water. Find the quantity of pure milk in the final milk solution?	Choose one.
A) 72.9 B) 78.5 C) 25.4 D) 31.5 E) 70.5

Solution: Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.   Quantity of milk finally in the vessel is then given by [(T - y)/T]n * T   For the given problem, T = 90, y = 9 and n = 2.   Hence, quantity of milk finally in the vessel   = [(90 - 9)/90]2 (90) = 72.9 litres.   72.9NSWER 72.9
Answer: A
The calendar for the year 2001 is same for which of the following year?
Choose the correct option:
A) 2005 B) 2007 C) 2011 D) 2006 E) 2009

Solution: SOLUTION :   The total number of odd days from 2001 onwards should be zero.   Now, as an ordinary year adds 1 odd day and a leap year adds 2 odd days, we have:   2001, 2002, 2003, 2005, 2006 – 1 odd day each   2004 – 2 odd days   Hence, at the end of 2006 total number of odd days = 7 or 0   Therefore, the calendar for the year 2001 is repeated in the year 2007.   ANSWER IS 2007
Answer: B
A seven-digit phone number is divisible by 4. After adding the two digits of the area code the number is not divisible by 4, which of the following cannot be the area code?  Select.
A) 07.
B) 06.
C) 05.
D) 04.
E) 02.

Solution: Given that 7 digit number is divisible by 4   we know any number will not be divisible by 4 if the sum of all digits of the number is not the multiple of 4.   Hence looking at the option we can say that the number that should be added to the seven digit number must be 04 as adding it will make it divisible by 4... hence answer is 04.
Answer: D
How many trucks are there if each truck carrying 70 packages and total of 490 packages?
Choose the correct choice from the following options:
A) A)7
B) B)6
C) C)9
D) D)11
E) E)None of the above

Solution: Sol.   Total packages 490   Each truck carries 70 packages   = 490 / 70= 
490 / 70 = 7
7   7nswer : 7
Answer: A
If R is a positive integer, and R/15 = 8.2, what is the remainder when R is divided by 15? Choose the correct choice from the following
A) A.1	B) B.2	C) C.3	D) D.4	E) E.8

Solution: If R were a multiple of 15, the quotient R/15 would be an integer. The fact that it's a decimal tells us that 15 goes into R eight whole times and some decimal part of a time. This decimal part, 0.2 is the remainder divided by the divisor. Let B be the remainder.   B/15 = 0.2 = 1/5   B = (15)*(1/5)= 
(15)*(1/5) = 3
3   Answer=(C.3)
Answer: C
In shop contains 500 articles each of a cost of $10. He sold them at a price of $11. If the shop keeper has a order of 200 articles, how much profit he will get?	Choose the correct choice from the following answers:  A) A)2100  B) B)2000  C) C)1500  D) D)200  E) E)600

Solution: Total money after selling articles = 200*11= 
200*11 = 2_200
2200   cost price= 200*10= 
200*10 = 2_000
2000   profit= 200   correct option is 200
Answer: D
A man has some hens and cows. If the number of heads be 48 and the number of feet equals 144, then the number of hens will be:
Pick one:	A) 22	B) 23	C) 24	D) 26	E) 28

Solution: let hens be x and cows be y   now,   feet: x*2+y*4=144   heads: x*1+y*1=48   implies, 2x+4y=144 and x+y=48   solving these two equations, we get x=24 and y=24   Therefore, hens are 26.   ANSWER:24
Answer: C
There r 4 prime numbers in ascending order. The multiplication of first 3 is 385 and that of last 3is 1001. what is the last number is Answers.
A) 10
B) 12
C) 11
D) 13
E) 15

Solution: Explanation:   abcbcd=3851001=>ad=513   abcbcd=3851001=>ad=513   So d = 13   13
Answer: D
Which of the numbers below is the odd one out
1,3,7,13,24,21,31.	Choose one.
A) 3
B) 7
C) 21
D) 24
E) 31

Solution: 24 is the odd man.. diff between sucessive no.s are multiples of 2   ANSWER:24
Answer: D
Amar takes as much time in running 18 meters as a car takes in covering 48 meters. What will be the distance covered by Amar during the time the car covers 1.6 km?
Select the correct option
A) 277 B) 289 C) 269 D) 600 E) 122

Solution: 600istance covered by Amar = 18/4.8 (1.6km)   = 3/8(1600)   = 600 m   Answer: 600
Answer: D
What will be 60 percent of a number whose 200 percent is 90 ?	Choose the correct choice from the following options:  A) 144  B) 72  C) 27  D) None of these  E) Cannot be determined

Solution: Answer   ∵ 200% of N = 90   ⇒ N = (90 x 100) / 200 = 45   ∴ 60% of N = (60 x 45) / 100 = 27   27orrect Option: 27
Answer: C
Find the smallest number in a GP whose sum is 38 and product 1728	Pick one:
A) 12 B) 20 C) 8 D) All of these E) none of these

Solution: In GP :- a/r+a+ar....=38   a(1+r+r^2)=38r......eq1   Product a^3=1728   a=12   now put this value in eq1   12(1+r+r^2)=38r   r=2/3 and 3/2..so sallest number is 8   ANSWER:8
Answer: C
Of the teams competing in the world archery championships, Forty percent are from Europe. Half as many are from the United States and one twentieth are from Africa. What fraction of teams are from neither Europe, the US or Africa.  Choose the correct choice from the following answers
A) 13/20  B) 15/20  C) 13/15  D) 17/20  E) 7/17

Solution: Assume 100 total people.   40% of 100 = 40 --->Europeans   1/2 of 40 ---> 20 Americans   1/20 of 100 ---> 5 Africans   Now you would add them all up, and minus it by the total (100). 100 - 65= 35. So, 35 people out of 100 are not EU, US or Africans. 35/100 is also equal to 7/20.   So therefore, the answer is 7/17.
Answer: E
A jar full of whisky contains 30% alcohol. A part of this whisky is replaced by another containg 19% alcohol and now the percentage of alcohol was found to be 26%. What quantity of whisky is replaced ? Choose the correct choice from the following answers:
A) 1/3 B) 2/3 C) 2/5 D) 3/5 E) 4/5

Solution: Let us assume the total original amount of whiskey = 10 ml ---> 4 ml alcohol and 6 ml non-alcohol.   Let x ml be the amount removed ---> total alcohol left = 4-0.4x   New quantity of whiskey added = x ml out of which 0.19 is the alcohol.   Thus, the final quantity of alcohol = 4-0.4x+0.19x ----> (4-0.21x)/ 10 = 0.26 ---> x = 20/3 ml.   Per the question, you need to find the x ml removed as a ratio of the initial volume ---> (20/3)/10 = 1/3.   Hence, 1/3 is the correct answer.
Answer: A
At a dinner party, 5 people are to be seated around a circular table. 2 seating arrangements are considered different only when the positions of the people are different relative to each other. what is the total number E of different possible seating arrangements for the group?  Choose one
A) 5	B) 10	C) 24	D) 32	E) 120

Solution: 24ircular arrangements= (n-1)!   Hence (4!) = 24=E   Answer is 24
Answer: C
If a and b are both odd numbers, which of the following is an odd number?  Pick one
A) a + b
B) a + b + 2
C) ab+2
D) ab + 1
E) NOne

Solution: Sol.   Product of two odd numbers is always odd and adding 2 gives odd.   Answer ab+2
Answer: C
If y is 70% greater than x, than x is what % less than y? Select.
A) 18.7  B) 25.5  C) 33.3  D) 41.2  E) 54.4

Solution: y = 1.7x   x = y/1.7 = 10y/17   x is 7/17 less which is about 41.2% less than y.   The answer is 41.2.
Answer: D
31 of the scientists that attended a certain workshop were Wolf Prize laureates, and 14 of these 31 were also Nobel Prize laureates. Of the scientists that attended that workshop and had not received the Wolf prize, the number of scientists that had received the Nobel Prize was 3 greater than the number of scientists that had not received the Nobel Prize. If 50 of the scientists attended that workshop, how many of them were Nobel Prize laureates?
Choose one:
A) A)11	B) B)18	C) C)25	D) D)29	E) D)36

Solution: lets solve by creating equation..   W = 31..   Total = 50..   Not W = 50 -31= 19..   Now let people who were neither be x, so out of 19 who won Nobel = x+3..   so x+x+3=19 or x=8..   so who won Nobel but not Wolf = x+3 = 11..   But people who won BOTH W and N = 13..   so total who won N = 11+14 = 25..   25
Answer: C
The difference between the simple interest received from two different sources on Rs. 1500 for 3 years is Rs. 13.50. The difference between their rates of interest is? Choose the correct choice.
A) 0.9%	B) 0.4%	C) 0.3%	D) 0.2%	E) 0.1%

Solution: (1500 * R1 * 3)/100 - (1500 * R2 * 3)/100 = 13.50 4500(R1 - R2) = 1350   R1 - R2 = 0.3%   Answer: 0.3%
Answer: C
On dividing a number by 5, we get 5 as quotient and 0 as remainder. On dividing the same number by 11, what will be the remainder?
Select the correct option.
A) 5 B) 2 C) 7 D) 9 E) 3

Solution: Number = 5 * 5+ 0= 
5 * 5+ 0 = 25
25   11) 25 (2   22   --------   3   Required number= 0.   ANSW3R:3
Answer: E
A, B and C are partners. A receives 2/3 of profits, B and C dividing the remainder equally. A's income is increased by Rs.200 when the rate to profit rises from 5 to 7 percent. Find the Capital of B?
Answers:
A) 3999 B) 7799 C) 2500 D) 2772 E) 2912

Solution: A:B:2500 = 2/3:1/6:1/6 = 4:1:1   x * 2/100 * 2/3 = 200   B capital = 15000*1/6= 
15000*1/6 = 2_500
2500.Answer: 2500
Answer: C