MU-NLPC/Calc-aqua_rat huggingface dataset:
John weighs twice as much as Susan. Susan's weight is 60% of Sam's weight. Mark weighs 50% of Lynn's weight. Lynn weighs 140% of John's weight. Which of these 5 people weighs the least?  Choose the correct choice from the following options:
A) John  B) Susan  C) Sam  D) Mark  E) Lynn

Solution: John weighs twice as much as Susan --> J=2S --> John cannot weigh the least;   Susan's weight is 60% of Sam's weight --> S=0.6*Sam --> Sam cannot weigh the least;   Mark weighs 50% of Lynn's weight --> M=0.5*L --> Lynn cannot weigh the least;   Lynn weighs 140% of John's weight --> L=1.9*J --> John cannot weigh the least (we already know that);   As you can see the answer is either Susan (S) or Mark (M). To compare their weights we should express their weights in regards of the same person: M=0.5*L=0.5*(1.4*J)=0.7*J and from J=2S, S=0.5*J --> Susan weights the least: Susan's weight is 50% of that of John and Mark's weight is more than 50%of that of John.   Answer: Susan.
Answer: B
The sum of ages of 5 girls born at the intervals of 3 years each is 40 years. What is the age of the youngest girl	Pick
A) years	B) years	C) years	D) years	E) years

Solution: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.   Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 40   5x = 10   x = 2.   Age of the youngest child = x = 2 years.   years)
Answer: A
If x^3 < y^2 > z, which of the statements could be true?
I. x < y < z
II. x < z < y
III. y < x < z
Select:	A) I only	B) III only	C) I and II only	D) II and III only	E) I, II and III

Solution: Given : x^3 < y^2 > z   I. x < y < z is true for x = 3, y = 6, z = 7   II. x < z < y is true for x = 3 , y = 5 , z = 4   III. y < x < z is not true   Answer: option I and II only
Answer: C
Wendy begins sanding a kitchen floor by herself and works for 6 hours. She is then joined by Bruce, and together the two of them finish sanding the floor in 2 hours. If Bruce can sand the floor by himself in 20 hours, how long would it take Wendy to sand the floor by herself?  Choose the most appropriate option
A) 9/80 hours
B) 3/20 hours
C) 20/3 hours
D) 80/9 hours
E) 10 hours

Solution: Let Wendy finishes sanding the floor alone in W hours while B be the hours for Bruce.   Thus in 1 hour Wendy finishes 1/w of the work while Bruce finishes 1/B of the work.   If wendy works for 6 hours and is then joined by Bruce to finish the work in 2 more hours,   6/W + 2/W+2/B = 1 (1 denotes the total amount of work)   8/W + 2/B =1 and given B =20 hours.   Thus W = 80/9 hours , 80/9 hours is the correct answer.
Answer: D
An amount of Rs. 100000 is invested in two types of shares. The first yields an interest of 9% p.a and the second, 11% p.a. If the total interest at the end of one year is 9 3/4 %, then the amount invested in each share was?
Options
A) Rs. 52500; Rs. 47500	B) Rs. 62500; Rs. 37500	C) Rs. 72500; Rs. 27500	D) Rs. 82500; Rs. 17500	E) Rs. 72500; Rs. 17500

Solution: Let the sum invested at 9% be Rs. x and that invested at 11% be Rs. (100000 - x). Then,   (x * 9 * 1)/100 + [(100000 - x) * 11 * 1]/100 = (100000 * 39/4 * 1/100)   (9x + 1100000 - 11x)/100 = 39000/4= 
39000/4 = 9_750
9750   x= 62500   Sum invested at 9% = Rs. 62500   Sum invested at 11% = Rs. (100000 - 62500) = Rs. 37500.   ANSWER:Rs. 62500; Rs. 37500
Answer: B
what is summation of [3^k(28Ck)] (summation range 28 to k=0) where 28Ck is the number of ways of choosing k items from 28 items??  Answers: A) 4^28 B) 4^27 C) 4^26 D) 4^25 E) 4^24

Solution: The expansion of (1+x)^n=nC0 x^0+nC1 x^1+nC2 x^2+......   putting the value of x=3 and n=28 we get   (1+3)^28=28C0 3^0+28C1 3^1+28C2 3^2+28C3 3^3.......   which is the given summation we need to find hence,   ans= 4^28   4^28NSWER:4^28
Answer: A
If an integer is randomly chosen from the numbers 250 to 449, inclusive, what is the probability that all the digits of the number are even?	Choices
A) 3/5
B) 17/50
C) 1/8
D) 51/199
E) 1/4

Solution: Another method is to enumerate the hundreds and tens digits which are acceptable:   26   28   40   42   44   In each case, any of the 5 even digits (0, 2, 4, 6, 8) can take the units place.   So acceptable cases = 5*5= 
5*5 = 25
25   Total number of integers= 200   Probability = 25/200 = 1/8   ANSWER:1/8
Answer: C
Difference of two numbers is 1660. If 7.5% of the number is 12.5% of the other number , find the number ? Choose the correct choice from the following answers:  A) 1470  B) 4150  C) 3012  D) 4430  E) 5507

Solution: Let the numbers be x and y. Then , 7.5 % of x =12.5% of y   X = 125*y/75 = 5*y/3.   Now, x-y =1660   5*y/3 –y =1660   2*y/3= 1660   y =[ (1660*3)/2= 
(1660*3)/2 = 2_490
2490.   One number= 2490, Second number =5*y/3 =4150.   ANSWER 4150 4150
Answer: B
A and B together have Sterling 1220. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
Choose one.
A) Sterling 460
B) Sterling 488
C) Sterling 550
D) Sterling 664
E) None

Solution: Explanation: 4/15A = 2/5B   A = (2/5 x 15/4)B   A = 3/2 B   A/B = 3/2   A : B = 3 : 2.   B's share = Sterling (1220 x 2/5) = Sterling 488.   Answer: Option Sterling 488
Answer: B
A box contains nine slips that are each labeled with one number: 1, 2, 3, 5, 8, 13, 21 and 34 Two of the slips are drawn at random from the box without replacement. What is the probability that the sum of the numbers on the two slips is equal to one of the numbers left in the box?  Choose the correct choice from the following choices:
A) 7/72
B) 3/14
C) 7/36
D) 15/36
E) 21/36

Solution: Probability = No: of desired outcomes / Total No: of outcomes.   You are picking two slips out of 8 slips. So   Total No: of outcomes = 8C2 = 28   Desired outcome : sum of the numbers on the two slips is equal to one of the numbers left in the box. How many such outcomes are there?   If you look at the numbers closely, you will see that the following pair of numbers will give you the desired outcome.   (1,2) (2,3) (3,5) (5,8) (8,13) (13,21) . There are 6 such pairs. If the two numbers which I pick is from any of these 6 pairs, then I get my desired outcome.   So No: of desired outcomes = 6   Probability = 6/28 = 3/14   Answer :3/14
Answer: B
Shan starts from Barabanki to Fatehpur, 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shan is at least 20km/hour fasterthan the speed of Kajol. What is the min speed of Shan to overtake Ajay, before he meets Kajol? Pick.
A) 62.2 km/h
B) 63 km/h
C) 64.5 km/h
D) 66.5 km/h
E) 67.5 km/h

Solution: Let t be the time after Kajol starts, when she meets Ajay, then   \inline t=\frac{300}{(x+y)}   This should be less than 2.5 or (x+y)>120   Since y= \inline \frac{3x}{2} \inline \Rightarrow y>72   This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.   67.5 km/h)
Answer: E
The probability that a man will be alive for 10more yrs is 3/4 & the probability that his wife will alive for 10 more yrs is 1/5. The probability that none of them will be alive for 10 more yrs, is	Choose the correct option.
A) 1/2 B) 1 C) 2/3 D) 1/5 E) 2

Solution: Sol. Required probability = Pg.) x P(B) = (1— 1/5 x(1 —I) =: x 1=1/5   Ans.(1/5)
Answer: D
Grayson, a chemist, has 8 litres of a solution that contains 15% hydrochloric acid(HCI), plus unlimited 5% HCI solution. For a particular experiment, however, he needs to prepare some that contains 12% HCI. How much 5% HCI solution should be added to the 15% HCI solution to get the 12% HCI solution needed for the experiment? Answers:
A) 7.6 litres
B) 10 litres
C) 12.8 litres
D) 3.4 litres
E) 8.2 litres

Solution: 0.15(8)+0.05x = 0.12(8 + x)   Solve the equation.   0.15(8) + 0.05x = 0.12(8 + x)   1.2 + 0.05x = 0.96 + 0.12x   1.2 – 0.07x = 0.96   -0.07x = -0.24   x ≈ 3.4   Answer is 3.4 litres.
Answer: D
3 men or 6 women can do a piece of work in 20 days. In how many days will 12 men and 8 women do the same work? Options:  A) 15/9 days  B) 15/4 days  C) 18/4 days  D) 11/4 days  E) 35/4 days

Solution: 3M = 6W ---- 20 days   12M + 8W -----?   24W + 8 W = 32W ---?   6W ---- 20 32 -----?   6 * 20  24  + 8= 
 24  + 8 = 32
32W ---?   6W ---- 20 32 -----?   6 * 20= 32 * x => x = 15/4 days   Answer:15/4 days
Answer: B
Find the C.I. on Rs. 15,625 for 9 months at 16% per annum compounded quarterly?	Answers:
A) Rs.1939  B) Rs.1912  C) Rs.1951  D) Rs.1908  E) Rs.1213

Solution: P = Rs. 15625, n = 9 months = 3 quarters, R = 16% p.a. per quarter.   Amount = [15625 * (1 + 4/100)3]   = (15625 * 26/25 * 26/25 * 26/25)   = Rs. 17576 C.I.   = 17576 - 15625   = Rs.1951.   Answer:Rs.1951
Answer: C
A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-digit number 13b7, which is divisible by 11. Then, (a + b) = ?	Select.
A) 10 B) 11 C) 12 D) 15 E) 17

Solution: Explanation:   4 a 3 |   9 8 4 } ==> a + 8 = b ==> b - a = 8   13 b 7 |   Also, 13 b7 is divisible by 11 (7 + 3) - (b + 1) = (9 - b)   (9 - b) = 0   b = 9   (b = 9 and a = 1) (a + b) = 10.   10nswer: Option 10
Answer: A
If the annual increase in the population of a town is 10% and the present number of people is 11000, what will the population be in 2 years?	Choose the correct choice:
A) 12100  B) 15240  C) 12456  D) 11452  E) 13310

Solution: The required population is = 11000 (1 + 10/100)^2   = 11000 * 11/10 * 11/10= 
11000 * 11/10 * 11/10 = 13_310
13310   Answer is 13310
Answer: E
In the following series how many times the sum of two consecutive digits is even?
1 2 3 4 6 3 4 2 5 9 3 6 7 4 1 2 3 6 7 6 5 4 3  Answers:
A) 5
B) 2
C) 3
D) 4
E) 6

Solution: 4+6   4+2   5+9   9+3   so 4 times   ANSWER:4
Answer: D
Solve: 18800+470+20
Choose the correct choice.
A) 2
B) 5
C) 4
D) 0
E) 1

Solution: 18800+470+20=(18800/470)+20=40/20= 
40/20 = 2
2.   2nswer is 2.
Answer: A
45 men can complete a work in 18 days. Six days after they started working, 30 more men joined them. How many days will they now take to complete the remaining work?
Select:
A) 6.6	B) 10	C) 15	D) 7.2	E) 8

Solution: 45*18 men can complete the work in 1 day   1 man's 1 day work = 1/810   45 men 6 days work = 6*1/18 = 1/3   remaining work = 1-1/3 = 2/3   75 men's 1 day's work = 75/810 = 5/54   2/3 work is done by them in  54/5 * 2/3= 
 54/5 * 2/3 = 36/5 = around 7.2
7.2 days   Answer is 7.2
Answer: D
Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 16 hours and 81 hours respectively. The ratio of their speeds is?	Choose the correct answer
A) 4:9 B) 9:4 C) 4:5 D) 4:1 E) 4:2

Solution: Let us name the trains A and B.   Then, (A's speed) : (9:4's speed)   = √b : √a = √81 : √16   = 9:4   Answer:9:4
Answer: B
A bag contains 6 white and 4 black balls .2 balls are drawn at random. Find the probability that they are of same colour.  Choose the correct choice from the following answers.
A) 7/19
B) 7/15
C) 7/29
D) 7/12
E) 7/92

Solution: Let S be the sample space   Then n(S) = no of ways of drawing 2 balls out of (6+4) = \inline {\color{7/15lack}10C_{2}} = =45   Let E = event of getting both balls of same colour   Then,n(E) = no of ways (2 balls out of six) or (2 balls out of 4)   =\inline {\color{7/15lack}6C_{2}+4C_{2}} = = 15+6= 
15+6 = 21
21   Therefore, P(E)= n(E)/n(S) = 21/45 = 7/15   Answer: 7/15
Answer: B
A train 100 m long crosses a platform 125 m long in 15 sec; find the speed of the train? Choices:  A) 87 kmph  B) 65 kmph  C) 54 kmph  D) 16 kmph  E) 18 kmph

Solution: D = 100 + 125= 
100 + 125 = 225
225   T= 15   S = 225/15 * 18/5= 
225/15 * 18/5 = 54
54 kmph   Answer:54 kmph
Answer: C
Difference of two numbers is 1670. If 7.5% of the number is 12.5% of the other number , find the number ?
Choose the correct choice:
A) 2660, 1000 B) 3660, 2000 C) 3000, 4160 D) 2490, 4150 E) 2505, 4175

Solution: Let the numbers be x and y. Then, 7.5 % of x =12.5% of y   X = 125*y/75 = 5*y/3.   Now, x-y =1670   5*y/3 –y =1670   2*y/3= 1670   y =[ (1670*3)/2= 
(1670*3)/2 = 2_505
2505.   One number= 2505, Second number =5*y/3 =4175.   Answer 2505, 4175.
Answer: E
Their are two boxes containing a total number of 60 balls, each box has an equal number of red and blue balls. What is the probability of getting a red ball from one box and a blue ball from the other	Choose the correct option:
A) 1/2	B) 1/4	C) 1/16	D) 1/8	E) 1

Solution: The number of possible selections is 60.   Let E be the event of getting an even number on one die and an odd number on the other. Since there exist an equal number of blue and red balls, probability of picking a blue or red ball is = 30/60 = 1/2   P(E) = 1 - 1/2   = 1/2.   1/2nswer:1/2
Answer: A
Find the simple interest on Rs.500 for 9 months at 6 paisa per month? Pick one:
A) 337
B) 270
C) 287
D) 266
E) 281

Solution: I = (500*9*6)/100= 
(500*9*6)/100 = 270
270   Answer: 270
Answer: B
Peter invested an amount of Rs. 12,000 at the rate of 10% p.a simple interest and another amount at the rate of 20% p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14% p.a. Find the total amount invested?	Choose the most appropriate option.
A) 20000  B) 3888  C) 2677  D) 29812  E) 2322

Solution: Let the second amount be Rs. x. Then,   (12000 * 10 * 1)/100 + (x * 20 * 1)/100 = [(12000 + x) * 14 * 1] / 100   120000 + 20x = 16800 + 14x   x = 8000   Total investment = 12000 + 8000 = Rs. 20,000.   20000nswer: 20000
Answer: A
Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Renee will win? Options:  A) 5/6  B) 2/3  C) 1/2  D) 5/12  E) 3/9

Solution: There are 3*3= 
3*3 = 9
9 combinations (cases) possible. In 3 cases there will be a tie (rock-rock, scissors/scissors, paper/paper). Now, out of 6 cases left Jim and Renee have equal chances of winning, so in 3 cases Jim will win and in other 3 Renee will win. So the probability Renee winning the game is (favorable outcomes) / (total # of outcomes)= 3/9   Answer: 3/9.
Answer: E
A statue is being carved by a sculptor. The original piece of marble weighed 250 kg. In the first week 30 percent is cut away. In the second week 20 percent of the remainder is cut away. In the third week the statue is completed when 25 percent of the remainder is cut away. What is the weight of the final statue?
Choose the correct choice:
A) 105 kg  B) 103 kg  C) 108 kg  D) 125 kg  E) 117 kg

Solution: 105 kg   105 kg   250 × 0.7 × 0.8 × 0.75 = 105 kg.
Answer: A
A chair is bought for Rs.600/- and sold at a loss of 30% find its selling price  Pick one: A) s.420/- B) s.550/- C) s.560/- D) s.590/- E) s.580/-

Solution: 100 % ------> 600 (100 * 6 = 600)   70 % ------> 540 (70 * 6 = 420)   Selling price = Rs.420/-   s.420/-)
Answer: A
30 people attend a party. 4 men are single and the rest are there with their wives. There are no children in the party. In all 22 women are present. Then the number of married men at the party is ?	Choose the correct option: A) 5 B) 6 C) 4 D) 8 E) 9

Solution: Total people = number of men + number of women   30 = 4 + number of married men + 22   number of married men = 30- 22-4= 
30- 22-4 = 4
4 men   ANSWER: 4
Answer: C
The average age of a committee of 8 members is 40 years. A member aged 55 years
retired and his place was taken by another member aged 39 years . The average age of
present committee is;
Choose the correct choice from the following:
A) 39 years
B) 38 years
C) 36 years
D) 35 years
E) 34 years

Solution: Exp. Total age of the committee = 40*8= 
40*8 = 320
320,   Total age when a member is retired   and a new one was joined= 320-55 +39, =304   Average age of present committee = 304/8= 
304/8 = 38
38.   Answer: 38 years
Answer: B
Three positive integers a, b, and c are such that their average is 22 and a ≤ b ≤ c. If the median is (a + 11), what is the least possible value of c?	Choices.
A) 21 B) 23 C) 25 D) 27 E) 29

Solution: Solution:   We know that the average value is 22 therefore (a+b+c)/3 = 22   so a+b+c = 66   and b = a + 11   therefore a + (a + 11) + c = 66   The least value of c is when c = b   so take c = a + 11   hence, a + (a + 11) + (a + 11) = 66   i.e., a = 44/3 a non integer therefore c is not equal to b   so take c = b+1 therefore c = a+12   a + (a + 11) + (a + 12) = 66   i.e., a= 43/3 again a non integer therefore c is not equal to b+1   next take c= b+2 therefore c = a+13   a + (a + 11) + (a + 13) = 66   i.e., a=42/3= 
42/3 = 14
14   hence, a= 14, b = 25, and c = 27   Answer: 27
Answer: D
John was thrice as old as Tom 6 years ago. John will be 15/13 times as old as Tom in 6 years. How old is Tom today?  Choose the correct choice from the following options:
A) 5  B) 7  C) 9  D) 11  E) 13

Solution: J-6 = 3(T-6), so J = 3T-12   J+6 = 15/13 * (T+6)   13J + 78 = 15T + 90   13(3T-12) + 78 = 15T + 90   24T = 168   T = 7   The answer is 7.
Answer: B
A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is divisible by 2211, What is the value of n?	Choose the correct choice from the following.
A) 22
B) 134
C) 62
D) 122
E) 672

Solution: Factorise 2211.. 3*11*67..   So n has to be a multiple of largest prime number,61..   So n=2*61=134..   ans :134
Answer: B
The calendar for the year 2007 will be the same for the year  Pick.
A) 2017	B) 2018	C) 2014	D) 2016	E) 2015

Solution: Explanation:   For a year to have the same calendar with 2007 ,the total odd days from 2007 should be 0.   Year:	2007	2008	2009	2010	2011	2012	2013	2014	2015	2016	2017   Odd Days: 1 2 1 1 1 2 1 1 1 2 1   Take the year 2014 given in the choice.   Total odd days in the period 2007-2013 = 5 normal years + 2 leap year   = 5 x 1 + 2 x 2 = 9 odd days   = 2 odd day (As we can reduce multiples of 7 from odd days which will not change anything)   Take the year 2016 given in the choice.   Number of odd days in the period 2007-2015 = 7 normal years + 2 leap year   = 7 x 1 + 2 x 2 = 11 odd days   = 4 odd days   (Even if the odd days were 0, calendar of 2007 will not be same as the calendar of 2016 because 2007 is not a leap year whereas 2016 is a leap year. In fact, you can straight away ignore this choice due to this fact without even bothering to check the odd days)   Take the year 2017 given in the choice.   Number of odd days in the period 2007-2016 = 7 normal years + 3 leap year   = 7 x 1 + 3 x 2 = 13 odd days   = 6 odd days   Take the year 2018 given in the choice.   Number of odd days in the period 2007-2017 = 8 normal years + 3 leap year   = 8 x 1 + 3 x 2 = 14 odd days   = 0 odd day (As we can reduce multiples of 7 from odd days which will not change anything)   Also, both 2007 and 2018 are not leap years.   Since total odd days in the period 2007-2017 = 0 and both 2007 and 2018 are of same type, 2018 will have the same calendar as that of 2007   Answer: Option 2018
Answer: B
For an upcoming charity event, a male vocalist has agreed to sing 4 out of 6 “old songs” and 2 out of 5 “new songs.” How many ways can the singer make his selection?
Choose the correct option.
A) 25
B) 50
C) 150
D) 480
E) 600

Solution: Number of ways the vocalist can sing "old songs" = 15064=15   Number of ways the vocalist can sing "new songs" = 15052=10   Therefore total number of ways the singer can make the selection = (Number of ways the vocalist can sing "old songs")*(Number of ways the vocalist can sing "new songs")= 15*10= 
15*10 = 150
150   Answer: 150
Answer: C
An gun can take a maximum of four shots at an enemy plane moving away from it. The probability of hitting the plane at the 1st, 2nd, third and 4th shots are 1.4, 1.3, 1.2 & 1.1 respectively. What is the probability that the plane is hit when all the four shots are fired?	Choose the most appropriate option
A) 0.53435	B) 0.69766	C) 1.34354	D) 1.45465	E) 1.46566

Solution: Required probability:   =(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)=(0.4×0.7×0.8×0.9)+(0.6×0.3×0.8×0.9)+(0.6×0.7×0.2×0.9)+(0.6×0.7×0.8×0.1)+(0.4×0.3×0.8×0.9)+(0.4×0.7×0.2×0.9)+(0.4×0.7×0.8×0.1)+(0.6×0.3×0.2×0.9)+(0.6×0.3×0.8×0.1)+(0.6×0.7×0.2×0.1)+(0.4×0.3×0.2×0.9)+(0.6×0.3×0.2×0.1)+(0.4×0.3×0.8×0.1)+(0.4×0.7×0.2×0.1)+(0.4×0.3×0.2×0.1)   =0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002=0.2016+0.1296+0.756+0.336+0.864+0.504+0.224+0.324+0.144+0.0084+0.0216+0.0036+0.0096+0.0056+0.002   =0.6976=0.6976   Edit: Thank you Vaibhav for providing an alternative method.   Alternate Method:   probability that the plane is hit when all the four shots are fired,   P=1−probability of not hitting the targetP=1−probability of not hitting the target   =1−(0.6×0.7×0.8×0.9)=1−(0.6×0.7×0.8×0.9)   =1−0.3024=1−0.3024   =0.6976   0.69766
Answer: B
Find smallest number that you can write using all the vowels(A,E,O,I,U) exactly once?	Pick.
A) 5000	B) 6000	C) 1000	D) 4000	E) 3000

Solution: 5000   fIvE thOUs5000nd(5000)
Answer: A
A circular path of 13 m radius has marginal walk 2 m wide all round it. Find the cost of leveling the walk at 25p per m2?	Choose the correct choice from the following answers
A) Rs.43
B) Rs.23
C) Rs.44
D) Rs.20
E) Rs.41

Solution: π (152 - 132) = 176   176 * 1/4 = Rs.44   Answer: Rs.44
Answer: C
There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 4 days more? Pick one:
A) 3022
B) 3040
C) 3099
D) 3088
E) 3066

Solution: 760 ---- 22   760 ---- 20   x ----- 4   x*4 = 760*20   x = 3800   760   -------   3040   Answer: 3040
Answer: B
A person crosses a 1000 m long street in 5 minutes. What is his speed in km per hour?	Pick one:	A) 5.2 km/hr.	B) 8.2 km/hr.	C) 12.0 km/hr.	D) 3.2 km/hr.	E) 4.2 km/hr.

Solution: C   12.0 km/hr.   Speed=(1000/5 * 60) m/sec   = 3.33 m/sec.   12.0 km/hr.onverting m/sec to km/hr   =(3.33*18/5) km/hr   = 12.0 km/hr.
Answer: C
Which of the following is closest to the difference between sum Z of all proper fractions (fractions less than 1) in the form 1/x , where x is a positive digit, and the product of all proper fractions in the form y/(y+1), where y is a positive digit?
Choose the correct choice:
A) 2.82
B) 2.72
C) 1.82
D) 1.72
E) 0.82

Solution: Sum Z of all proper fractions (fractions less than 1) in the form 1/x, where x is a positive digit:   1/1 + 1/2 + 1/3 +.....+ 1/9   This is a harmonic progression. Harmonic progression is inverse of arithmetic progression.   Approximate sum of a harmonic progression with even number of terms = number of terms * (average of middle 2 terms)   Approximate sum of a harmonic progression with odd number of terms = number of terms * (middle term)   The actual sum will be slightly more than the approximation.   Here we have 9 terms (odd).   Sum = 9 * 1/5   = 9/5   Product of all proper fractions in the form y/(y+1), where y is a positive digit:   1/2 * 2/3 * 3/4 *.....*9/10   We will be left with 1/10.   Required = 9/5 - 1/10   = 1.8 - 0.1= 
1.8 - 0.1 = 1.7
1.7   Closest is 1.72   Answer (1.72).
Answer: D
926 + 9.026 + 0.926 + 9.0026 = ? Select the correct option
A) 944.9546  B) 944.1246  C) 944.4246  D) 944.9446  E) None of these

Solution: Explanation :   926 + 9.026 + 0.926 + 9.0026 = 944.9546. 944.9546nswer : Option 944.9546
Answer: A
If @ is a binary operation defined as the difference between an integer n and the product of n and 5, then what is the largest positive integer n such that the outcome of the binary operation of n is less than 12?  Choose the correct choice from the following: A) 1 B) 2 C) 3 D) 4 E) 5

Solution: @(n) = 5n - n   We need to find the largest positive integer such that 5n - n < 12.   Then 4n < 12 and n < 3.   The largest possible integer is n = 2.   The answer is 2.
Answer: B