MU-NLPC/Calc-aqua_rat huggingface dataset:
The price of food in the area where the Sims family lives is scheduled to increase by 50% next year. Since the Sims family cannot afford an increase in their food bill, how much will they have to reduce consumption to keep their cost the same?  Choose the correct choice from the following answers:  A) 17%  B) 25.6%  C) none%  D) 33.3%  E) 50%

Solution: Solution: Let the current food expense be represented by Rs. 100.   The cost of food rises 50%. So, to buy same amount of food, they need to increase their expense,   = (100 + 50% of 100) = Rs. 150.   But, they want to keep food expense the same, so they have to cut Rs. by 50 to keep it to Rs. =100.   The % decrease in consumption is,   (50/150)*100 = 33.3%.   Mental Calculation Method;   100-----50%↑---→150------X%↓---→100.   Here, X = (50/125)*100 = 33.3%.   Answer: Option 33.3%
Answer: D
A committee of three people is to be chosen from 6 married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot both serve on the committee?  Choices.
A) 167 B) 190 C) 140 D) 180 E) 160

Solution: Total no of ways of choosing a committee = 12C3 = 220   No of ways to choose first couple = 6C1 = 6   No of ways to choose 1 person from remaining 10 = 10C1 = 10   Total number of ways of choosing a married couple to be in the same committee = 6*10= 
6*10 = 60
60   So, no of ways not choosing a married couple= 220-60= 
220-60 = 160
160   ANS:E. 160
Answer: E
Two trains of equal lengths take 10 sec and 12 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
Choose the correct choice from the following options.
A) 11  B) 12  C) 10.9  D) 14  E) 15

Solution: Speed of the first train = 120/10= 
120/10 = 12
12 m/sec.   Speed of the second train= 120/12= 
120/12 = 10
10 m/sec.   Relative speed= 12 + 10= 
12 + 10 = 22
22 m/sec.   Required time= (120 + 120)/22 = 10.9 sec.   Answer: Option 10.9
Answer: C
Which is equal to 11? Pick one:
A) 1.1 B) -11 C) 11/11 D) 11/1 E) 1/11

Solution: 11/1 is equal to 11.   Answer: 11/1
Answer: D
A water tank, having the shape of a rectangular prism of base 100 square centimeters, is being filled at the rate of 1 liter per minute. Find the rate at which the height of the water in the water tank increases. Express your answer in centimeters per minute.
Choose the correct choice from the following answers:
A) 30 cm B) 10 cm C) 50 cm D) 90 cm E) 70 cm

Solution: The volume of a rectangular prism is given by   area of base ? height   The rate at which the tank is being filled is 1 liter per minute which we need to convert   1 liter = 1 dm3   But 1 dm = 10 cm. Hence   1 liter = (10 cm)3 = 1000 cm3   The height h of the water is related to the volume by   volume = area of base *h   In one minute the volume increases by 1 liter or 1000 cm3 and the height increases by   h = volume / area of base = 1000 cm3 / 100 cm2 = 10 cm   correct answer 10 cm
Answer: B
A train 200 m long is running with a speed of 68 kmph. In what time will it pass a man who is running at 8 kmph in the same direction in which the train is going?  Pick.
A) 6 sec.	B) 7 sec.	C) 9 sec.	D) 12 sec.	E) None

Solution: Solution   Speed of the train relative to man	=( 68 - 8 )= 
( 68 - 8 ) = 60
60 Kmph= 60 x 5 / 18   =50/3 m/sec.   Time taken by it to cover 200 m at (50 /3)m/sec   = (200 x 3/50)sec   = 12 sec.   Answer 12 sec.
Answer: D
How many possible ways can 2 girls (Rebecca, Kate, Ashley) go on a date with 2 boys (Peter, Kyle, Sam)?  Choose the correct choice from the following answers.
A) 2
B) 4
C) 5
D) 6
E) 8

Solution: Any one girl can go with 2 boys.   and 2rd girl can go with remaining 1 boy   2! i.e 2 (2) is the answer
Answer: A
a man buys m no. of pens for rs. n each and sells n no. of pens for rs. m each. then what is the profit he have earned?	Choices
A) 0	B) 1	C) 2	D) 3	E) 4

Solution: c.p. of 1 pen=Rs n (given each)   so c.p. of m pens=rs mn   s.p. of 1 pen =rs m   so s.p. of n pens=rs mn   so profit =s.p.-c.p.=0(zero)   0NSWER:0
Answer: A
With an average speed of 40 km/hr a car reaches its destination on time. If it goes with an average speed of 35 km/h, it is late by 15 minutes. The total journey is? Choose the correct answer:
A) 30 km B) 40 km C) 70 km D) 80 km E) 90 km

Solution: Let the total journey be X km.   X/35 - X/40 = 15/60   Solving for X, we get X = 70   Therefore, total journey = 70 km.   ANSWER:70 km
Answer: C
If (t-8) is a factor of t^2-kt-45, then k=	Answers:
A) 16 B) 12 C) 2 D) 6 E) 14

Solution: t^2-kt-48 = (t-8)(t+m) where m is any positive integer.   if 48/8= 
48/8 = 6
6, then we know as a matter of fact that:   m= +6   and thus k = 8-6 = 12   t^2-kt-m = (t-a)(t+m) where a>m   t^2+kt-m = (t-a)(t+m) where a<m   t^2-kt+m = (t-a)(t-m)   t^2+kt+m = (t+a)(t+m)   12
Answer: B
The perimeter of a semi circle is 144 cm then the radius is?  Choose the correct choice from the following answers
A) 22 B) 28 C) 97 D) 26 E) 12

Solution: 36/7 r = 144 => r   = 28   Answer:28
Answer: B
Arun, Akash, Amir and Aswanth go for a picnic. When Arun stands on a weighing machine, Akash also climbs on, and the weight shown was 132 kg. When Akash stands, Amir also climbs on, and the machine shows 130 kg. Similarly the weight of Amir and Aswanth is found as 102 kg and that of Akash and Aswanth is 116 kg. What is Aswanth’s weight?	Select.
A) 58kg
B) 78 kg
C) 44 kg
D) 48 kg
E) None

Solution: arun+akash=132-----eq1   akash+amir=130------eq2   amir+aswanth=102------eq3   akash+aswanth=116-------eq4   solving eq 2 and 4   we get amir-aswanth=14-------eq5   now solving eq 3 and 5   we get aswanth=44   ANSWER:44 kg
Answer: C
The ratio between the speeds of two trains is 5: 6. If the second train runs 300 kms in 5 hours, then the speed of the first train is ?
Choose the correct choice from the following.
A) 60 km/hr
B) 50 km/hr
C) 55 km/hr
D) 65 km/hr
E) None of these

Solution: Explanation:   Let the speeds of two trains be 5X and 6X km/hr.   6/X=300/5=>X=10 Km/hr   So speed of first train is   10*5= 
  10*5 = 50
50 km/hr   Option 50 km/hr
Answer: B
A and B can do a piece of work in 21 and 24 days respectively. They started the work together and after some days A leaves the work and B completes the remaining work in 9 days. After how many days did A leave?	Pick one:
A) 5 days	B) 6 days	C) 7 days	D) 8 days	E) 9 days

Solution: In 9 days B completes 9/24 i.e., 3/8th of the work.   Hence 1 - 3/8 = 5/8th of the work is completed by A and B together.   i.e., x (1/21 + 1/24) = 5/8 => x = 7 days.   ANSWER:7 days
Answer: C
How many pieces of 75 cm can be cut from a rope 55.5 meters long?  Choose the correct choice from the following answers.
A) 30 B) 40 C) 60 D) None E) 74

Solution: 74xplanation :   Total pieces of 75 cm that can be cut from a rope of 55.5 meters long is   = (55.5 meters)/(75 cm)   = (55.5 meters)/(0.75 meters)   = 74   Answer : 74
Answer: E
The workforce of Company X is 60% female. The company hired 20 additional male workers, and as a result, the percent of female workers dropped to 50%.How many employees did the company have after hiring the additional male workers?
Answers.
A) 145	B) 188	C) 189	D) 190	E) 191

Solution: let x be the total worker then 0.6x =female worker and 0.4x is male worker then 20 male worker added   06x/(0.4x +20) = 50/100 or 60x = 50*( 0.4x+100) = 20x+ 5000 or 40x = 5000 , x = 500/4= 
500/4 = 125
125   total worker= 125 +20= 
125 +20 = 145
145   145
Answer: A
D is the set of all the multiples of 3 between 20 and 100. E is the set of all the factors of 400. Set D and Set E have how many numbers in common? Choose the correct choice from the following choices.
A) 0	B) 1	C) 3	D) 5	E) 12

Solution: D is a set of multiples of 3.   400 is NOT a multiple of 3, hence none of its factors is a multiple of 3.   Therefore, those two sets won't have any overlap.   0nswer: 0.
Answer: A
judith is practicing her dance steps along with her friends. In a particular sequence, all of them form a row. At that point, judithis standing on the 5th position from either end of the row.
Can you find out how many girls are practicing together?
Answers.
A) 4	B) 9	C) 7	D) 6	E) 8

Solution: As judith is 5th from either end of the row, it means that 4 girls are on one of her sides and 4 are present on the other.   4 + 4 + 1(judith herself) = 9.   Hence,9 girls are practicing the dance together.   correct answer is 9)9
Answer: B
The contents of a certain box consist of 24 mangos and 30 kiwis. How many kiwis must be added to the box so that exactly 30% of the pieces of fruit in the box will be mangos?	Choose the correct choice from the following:
A) 24
B) 26
C) 30
D) 46
E) 50

Solution: mango = (mango + kiwi + x)*0.3   24 = (30 + 24 + x)*0.3   x = 26.   Answer: 26.
Answer: B
A computer program generates a sequence of numbers a1, a2, a3, ... such that a1=1, a2=2, and ak=a(k-2)*4-1 for 2 < k < n for n=10. Find a6.
Choose the correct choice from the following answers
A) 19	B) 27	C) 31	D) 36	E) 41

Solution: a1=1   a2=2   a3=1*4-1= 
1*4-1 = 3
3   a4=2*4-1= 
2*4-1 = 7
7   a5=3*4-1= 
3*4-1 = 11
11   a6=7*4-1= 
7*4-1 = 27
27   27
Answer: B
In an examination, there were 2,000 candidates, out of which 900 candidates were girls and rest were Boys. If 38% of the boys and 32% of the girls passed, then the total percentage of failed candidates is?
Choose the correct answer:  A) 35.67%  B) 64.75%  C) 68.57%  D) 69.57%  E) none of these

Solution: Girls = 900, Boys = 1100   Passed = ( 38% of 1100 ) + ( 32% of 900)   = 418 + 288= 
418 + 288 = 706
706   Failed= 2000 - 706= 
2000 - 706 = 1_294
1294   Failed %= [(1294/2000) x 100]%   = 64.7%.   ANSWER:64.75%
Answer: B
If 45% of z is 60% of y and y is 75% of x, what percent of x is z? Answers
A) 200	B) 160	C) 100	D) 65	E) 50

Solution: (45/100)z = (60/100)y   and y = (75/100)x i.e. y = (3/4)x   i.e. (45/100)z = (60/100)*(3/4)x   i.e. z = (60*3)x/(45*4)   i.e. z = (1)x = (100/100)x   i.e. z is 100% of x   Answer: Option 100
Answer: C
If Rs.7500 are borrowed at C.I at the rate of 4% per annum, then after 2 years the amount to be paid is :  Options.
A) Rs.8082  B) Rs.7800  C) Rs.8100  D) Rs.8112  E) None

Solution: Explanation:   Amount = Rs. [7500(1+4/100)2]= Rs. [7500×26/25×26/25]=Rs.8112.   Correct Option: Rs.8112
Answer: D
If S is the sum of reciprocals of a list of consecutive integers from 25 to 34, inclusive, S is approximately equal to	Choose the correct choice from the following choices.
A) 0.1  B) 0.2  C) 0.33  D) 0.4  E) 0.5

Solution: We need to find the approximate value of 1/25+1/26+1/27+1/28+1/29+1/30+1/31+1/32+1/33+1/34. Now, the sum of these 10 terms will be very close to 10 times 1/30, which is 0.033*10=0.33.   Answer: 0.33.
Answer: C
250 metres long yard, 51 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees  Choose the correct option
A) 10  B) 12  C) 14  D) 16  E) 5

Solution: 51 trees have 50 gaps between them,   Required distance (250/50) = 15   5
Answer: E
sue has 3 apples. Billy has 5 apples. If billy steals all of sues apples and eats 1 how many does he have left? Options:
A) 2
B) 5
C) 6
D) 7
E) 8

Solution: 7 7
Answer: D
If x+|x|+y=7 and x+|y|-y=5 what is x+y=?	Choose the correct choice
A) 1 B) -1 C) 3 D) 5 E) 13

Solution: If x<0 and y<0, then we'll have x-x+y=7 and x-y-y=6. From the first equation y=7, so we can discard this case since y is not less than 0.   If x>=0 and y<0, then we'll have x+x+y=7 and x-y-y=6. Solving gives x=4>0 and y=-1<0 --> x+y=3. Since in PS questions only one answer choice can be correct, then the answer is C (so, we can stop here and not even consider other two cases).   Answer: C.   Adding both eqn we get 2x +IxI+IyI = 13   Now considering X <0 and y>0   2x-x +y = 13   we get x+y =5   Hence answer should be 5
Answer: D
A textile manufacturing firm employees 100 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 100 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:
Pick one.
A) 13000	B) 7000	C) 10000	D) 3500	E) None of these

Solution: Explanation :   Profit = 5,00,000âˆ’(1,50,000+75,000) =Rs. 2,75,000.   Since, such loom contributes equally to sales and manufacturing expenses.   But the monthly charges are fixed at Rs 75,000.   If one loan breaks down sales and expenses will decrease.   New profit :-   =>500000Ã—(99/100)âˆ’150000Ã—(99/100)âˆ’75000.   =>Rs 2,68,000.   Decrease in profit   =>2,75,000âˆ’2,71,500   =>Rs. 3,500.   Answer : 3500
Answer: D
The fourth proportional to 12, 20 and 30 is? Choices:
A) 21  B) 66  C) 55  D) 50  E) 61

Solution: (20*30)/12= 
(20*30)/12 = 50
50   Answer:50
Answer: D
The sum of the present ages of father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be?  Choose one:  A) 22  B) 287  C) 26  D) 20  E) 28

Solution: Let the present ages of son and father be x and (60 - x) years respectively.   Then, (60 - x) - 6 = 5(x - 6)   6x = 84 => x = 14   Son's age after 6 years = (x + 6) = 20 years.Answer: 20
Answer: D
The sides of the triangle are in the ratio 5:6:7 and its perimeter is 720cm. The length of the longest side is? Pick
A) 150cm	B) 200cm	C) 162cm	D) 220cm	E) 280cm

Solution: Ratio of sides = 5:6:7   Largest side = 720*7/18= 
720*7/18 = 280
280cm   Answer is 280cm
Answer: E
Three business people wish to invest in a new company. Each person is willing to pay one third of the total investment. After careful calculations, they realize that each of them would pay $8,200 less if they could find two more equal investors. How much is the total investment in the new business?
Choose the correct choice from the following options:  A) $61,500  B) $54,000  C) $21,000  D) $ 5,400  E) $ 3,600

Solution: Total Investment between 5: (x/5)   Total investment including 8200 less between 3 people(x-(8200*3))/3   Set both eq. equal to each other.   61,500   $61,500nswer $61,500)
Answer: A
While playing a certain dice game, Chris wins if the sum of the two dice is 5, at which point the game is over. If the game allows Chris three rolls in an attempt to win, what is the probability that Chris will win?
Choose the correct choice from the following answers:  A) 1/2  B) 17/36  C) 217/729  D) 11/36  E) 25/216

Solution: Probability of winning game = 1- Probability of losing game   Probability of losing game = (Probability of not getting sum 7 in any of the three attempts)   Ways of getting sum 5 = (1,4)(2,3)(3,2)(4,1)= 4 ways   Total ways of getting outcome on two dice =6*6= 
6*6 = 36
36   Probability of getting sum as 5 in any attempt=4/36=1/9   Probability of NOT getting sum as 5 in any attempt = 1-(1/9)= 8/9   Probability of losing game =(8/9)*(8/9)*(8/9)=512/729   I.e. Probability of wining game = 1-(512/729) = 217/729   Answer : Option 217/729
Answer: C
How many 3 digit numbers are completely divisible 6 ? Choose the correct choice from the following choices:
A) 146  B) 148  C) 150  D) 152  E) None of these

Solution: Explanation :   100/6 = 16, remainder = 4. Hence 2 more should be added to 100 to get the minimum   3 digit number divisible by 6.   => Minimum 3 digit number divisible by 6 = 100 + 2= 
100 + 2 = 102
102   999/6= 166, remainder = 3. Hence 3 should be decreased from 999 to get the maximum   3 digit number divisible by 6.   => Maximum 3 digit number divisible by 6 = 999 - 3= 
999 - 3 = 996
996   Hence, the 3 digit numbers divisible by 6 are 102, 108, 114,... 996   This is Arithmetic Progression with a= 102 ,d = 6, l=996   Number of terms = (l−a)/d + 1 = (996 − 102)/6 + 1 = 894/6 + 1 = 149 + 1= 
149 + 1 = 150
150. Answer : Option 150
Answer: C
David invested certain amount in three different schemes. A, B and C with the rate of interest 10% p.a., 12% p.a. and 15% p.a. respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in scheme C was 150% of the amount invested in scheme A and 240% of the amount invested in scheme B, what was the amount invested in scheme B?	Choose the correct choice from the following options.
A) 5000 B) 5007 C) 5006 D) 5026 E) 5002

Solution: Let x, y and z be the amount invested in schemes A, B and C respectively. Then,   (x * 10 * 1)/100 + (y * 12 * 1)/100 + (z * 15 * 1)/100 = 3200   10x + 12y + 15z = 320000   Now, z = 240% of y = 12/5 y   And, z = 150% of x = 3/2 x   x = 2/3 z = ( 2/3 * 12/5) y = 8/5 y   16y + 12y + 36y = 320000   y = 5000   Sum invested in scheme B = Rs. 5000.   5000nswer:5000
Answer: A
The total age of A and B is 16 years more than the total age of B and C. C is how many year younger than A	Select the correct option:	A) 11	B) 16	C) 13	D) 14	E) 15

Solution: Explanation:   Given that A+16= 
+16 = 16
16 + 16 + C=> A ? C = 16 + 16 ? 16 = 16   => C is younger than A by 16 years   Answer: Option 16
Answer: B
Call a number parents if it is composite but not divisible by 2, 3, or 5. The three smallest guardian numbers are 49, 77, and 91. There are 168 prime numbers less than 1000. How many parent numbers are there less than 1000?
Options.
A) a) 90
B) b) 97
C) c) 100
D) d) 106
E) e) 108

Solution: Start with the numbers from 1 - 1000. We have 1000 numbers.   Subtract the primes:     1000 - 168= 
  1000 - 168 = 832
832   Now, subtract the even numbers, divisible by 2. There are 500 even numbers in the set, but the first, 2 itself, has already been subtracted with the primes. There are 499 non-prime even numbers in the set, including 1000 itself. (1000 itself really shouldn't be included, because are looking for numbers less than 1000, but it gets subtracted in this step anyway, so it doesn't matter.)   832 - 499= 
832 - 499 = 333
333   Now, numbers divisible by 3. There are 333 factors of three between 1 and 1000, but first of all, one of those is the prime number 3, already subtracted, so exclude that --- 332. Of those, half are even, already counted, so that leaves  332/2= 
 332/2 = 166
166 non-prime odd multiples of 3.   333 - 166= 
333 - 166 = 167
167   Now, multiples of 5. There are 200 multiples of 5 up to 1000. Half are even, divisible by 10, so eliminate them --- 100 odd multiples of 5. Eliminate the prime number 5 itself, already counted --- 99 non-prime multiples of 5. Now, 1/3 of these are divisible by three, already counted, so we 2/3 of this number==> 66. There are 66 non-prime multiples of 5 that are not divisible by 3.   167 - 66= 
167 - 66 = 101
101   The last number that needs to be subtracted --- not prime, not composite, not a multiple of 2 or 3 or 5, is 1 itself. This is not composite, so it is not a parent.   101 - 1= 
101 - 1 = 100
100   That leaves 100 parent numbers. OA=(c) 100)
Answer: C
What is the next number: 3, 18, 258, __	Choose the correct option.
A) 2928 B) 3638 C) 4098 D) 4418 E) 5378

Solution: 4^0 + 2 = 3   4^2 + 2 = 18   4^4 + 2 = 258   4^6 + 2 = 4098   The answer is 4098.
Answer: C
What is remainder of the division (1525*1527*1529)/12?
Select
A) 0	B) 1	C) 2	D) 3	E) 4

Solution: remainder will be number/ 100 here as the divisor is two digit number = 12.   hence checking for the last two digits = 5*7*9 = 15   Thus remainder = 3.   Answer : 3
Answer: D
Andrew found $10 while cleaning his car. He found 15 quarters, 22 dimes, 5 pennies and 4 dollar bills. What % of the total amount he found were made up of coins?	Options.
A) 95 %  B) 90 %  C) 85 %  D) 70 %  E) 60 %

Solution: Number of runs made by running = (15 x 0.25 + 22 x .10 + 5 x 0.01)   = (15 x 0.25) + (22 x .10) + (5 x 0.01)   = 6   Now, we need to calculate 6 is what percent of 10.   => 6/10 * 100= 
6/10 * 100 = 60
60 %   60 %
Answer: E
One water pump can fill half of a certain empty tank in 8 hours. Another pump can fill half of the same tank in 8.5 hours. Working together, how long will it take these two pumps to fill the entire tank?	Answers: A) 8 7/13 B) 1 5/8 C) 3 1/4 D) 8 8/33 E) 3 1/2

Solution: One pump can fill a tank in 8 hours and another in 8.5 hours   so the rate at which both can half fill the tank is (1/8+1/8.5) => 33/136   Thus half of the tank can be filled in 136/33   so for filling the complete tank =>136/33*2 = 272/33 = 8 8/33   ANSWER:8 8/33
Answer: D
What is the measure of the radius of the circle inscribed in a triangle whose sides measure 8, 15 and 27 units?  Choices:	A) 8.5 units	B) 6 units	C) 3 units	D) 5 units	E) 2 units

Solution: Sides are 8, 15 and 27...thus it is right angle triangle Since 27^2 = 8^2 + 15^2   therefore, area = 1/2 * 15 * 8= 
1/2 * 15 * 8 = 60
60   We have to find in-radius   Therefore, area of triangle= S*r ....where S=semi-perimeter and r= in-radius   Now S=semi-perimeter = 27+15+8 /2 = 30   Thus , 60 =30*r   and hence r=in-radius= 2   Option 2 units
Answer: E
By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?	Choose the correct answer:
A) 38002
B) 38000
C) 38028
D) 38289
E) 380787

Solution: CP + CP/8 = 45000   CP = 40000   SP = 40000*(95/100)= 
40000*(95/100) = 38_000
38000   Answer: 38000
Answer: B
The C.I. on a certain sum for 2 years Rs.41 and the simple interest is Rs.40. What is the rate percent?  Choose the correct answer.
A) 3%  B) 5%  C) 6%  D) 2%  E) 7%

Solution: SI = 20 + 20   CI = 20 + 21   20 ---- 1   100 ---- ? => 5%   Answer:5%
Answer: B
If x + 1/x = 2 then find x2 + 1/x2	Choose the correct choice:	A) 1	B) 2	C) 3	D) 4	E) 5

Solution: If x+1/x= p   ==> x^2+1/x^2=p^2-2   Ans= 2^2-2=2   ANSWER:2
Answer: B
Mary got a weekly raise of $384. If she gets paid every other week, write an integer describing how the raise will affect her paycheck.  Choose the correct choice from the following.
A) 384
B) 374
C) 364
D) 394
E) 354

Solution: Let the 1st paycheck be x (integer).   Mary got a weekly raise of $ 384.   So after completing the 1st week she will get $ (x+384).   Similarly after completing the 2nd week she will get $ (x + 384) + $ 384.   = $ (x + 384 + 384)   = $ (x + 768)   So in this way end of every week her salary will increase by (384)$ 384.
Answer: A
A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most ?	Pick one
A) 177 B) 199 C) 215 D) 168 E) 167

Solution: Since each ring consists of six different letters, the total number of attempts possible with the three rings is   = 6 * 6 * 6= 
6 * 6 * 6 = 216
216. Of these attempts, one of them is a successful attempt.   Maximum number of unsuccessful attempts= 216 - 1= 
216 - 1 = 215
215.   Answer: 215
Answer: C
A company has 2 directors and 5 managers. How many different committees with 5 people can be chosen having at least 1 director?
Choose the correct choice from the following options.
A) 500	B) 720	C) 4500	D) 20	E) 55

Solution: atleast one means exactly one and more than one.   different committees with 5 people can be chosen having at least 1 director is   (2c1*5c4) + (2c2*5c3) = 20;   Hence 20.
Answer: D
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 165 m long?
Choose one
A) 40
B) 99
C) 88
D) 77
E) 42

Solution: :   Speed = 45 * 5/18 = 25/2 m/sec   Total distance covered = 360 + 165= 
360 + 165 = 525
525 m   Required time= 525 * 2/25= 
525 * 2/25 = 42
42 sec   Answer:42
Answer: E