MU-NLPC/Calc-aqua_rat huggingface dataset:
Eighty percent of the lights at Hotel California are on at 8 p.m. a certain evening. However, forty percent of the lights that are supposed to be off are actually on and ten percent of the lights that are supposed to be on are actually off. What percent K of the lights that are on are supposed to be off?  Choose the correct option
A) 22(2/9)%  B) 16(2/3)%  C) 11(1/9)%  D) 10%  E) 5%

Solution: Is the Answer D.   let me try..   Let the light which are supposed to be OFF = SO   Let the light which are supposed to be ON = SN   Let the light which are ACTUALLY OFF = AO   Let the light which are ACTUALLY ON = AN   Let the total no. of lights be 100,   So ACTUALLY ON lights = 80   And ACTUALLY OFF lights = 20   Also given >> forty percent of the lights that are supposed to off are actually on >>> (40/100)*SO are ACTUALLY ON   it means >>> (60/100)*SO are ACTUALLY OFF   Also given >> ten percent of the lights that are supposed to be on are actually off >>> (10/100)*SN are ACTUALLY OFF   it means >>> (90/100)*SN are ACTUALLY ON   So, Total ACTUALLY ON lights = (40/100)*SO + (90/100)*SN = 80   and Total ACTUALLY OFF lights = (60/100)*SO + (10/100)*SN = 80   From here we get SO = 20   we need to find: What percent of the lights that are on are supposed to be off >>> So light ACTUALLY ON are 80 and light which are ACTUALLY ON, which are supposed to be OFF = (40/100)*SO = 8.   So (8/80)*100= 
(8/80)*100 = 10
10%.10%
Answer: D
The number N is 5,2H7, where H represents the ten's digit. If N is divisible by 3, what is the value of H?
Pick:
A) 3 B) 8 C) 5 D) 6 E) 4

Solution: If the number is divisible by 3, the sum of the digits must also be divisible by 3. Only 4 yields such a number.   Answer: 4
Answer: E
The jogging track in a sports complex is 640 m in circumference. Lata and Geeta start from the same point and walk in opposite directions at 4.2 km/hr and 3.8 km/hr respectively. They will meet for the first time in?	Select:
A) 2.9 min
B) 3.9 min
C) 4.2 min
D) 4.8 min
E) 5.6 min

Solution: Clearly, the two will meet when they are 640 m apart.   To be (4.2 + 3.8)= 
(4.2 + 3.8) = 8
8.0 km apart, they take 1 hour.That is 60 min.   To be 640 m apart, they take    (640/8000 * 60)= 
 (640/8000 * 60) = 24/5 = around 4.8
4.8 min.   Answer: 4.8 min
Answer: D
A man can row downstream at the rate of 12 Km/hr and upstream at 8 Km/hr. Find man's rate in still water and the rate of current?
Choose one.
A) 9,6	B) 6,3	C) 9,3	D) 10,2	E) None of these

Solution: Explanation:   Rate of still water = 1/2 (12 + 8) = 10 Km/hr   Rate of current = 1/2 (12-8) = 2 Km/hr   Answer: Option 10,2
Answer: D
Which of the following CANNOT be a product of two distinct positive integers x and y?  Choose the correct choice from the following:
A) x
B) y
C) 3y + 2x
D) y - x
E) yx

Solution: In these questions it is best to take an example as if something is true for all positive integers than it as to be true for the smallest and the easiest integers to work with   take x = 1 and y = 2 and work with the options   xy = 2   A) x take x =2, y = 1   B) y take x = 1 y = 2   C) 3y + 2x Seems tricky, lets see other options and then come back to it.   D) y - x take y = 1 and x = 2 --> y - x = -1 .. How the hell can product of two positive integers be negative ?? or less than each of them?   E) yx Always true   You don't even have to worry what C is !   ans y - x
Answer: D
How much greater is the combined area in square inches of the front and back of a rectangular sheet of paper measuring 11 inches by 15 inches than that of a rectangular sheet of paper measuring 7.5 inches by 11 inches? Choices:
A) 50%  B) 87%  C) 100%  D) 187%  E) 200%

Solution: Let's just look at the dimensions (no calculation needed).   With dimension 11 the same, the other dimension 15 is twice 7.5   Then the area will be double which means 100% greater.   The answer is 100%.
Answer: C
For which of the following values of n is (300+n)/n NOT an integer?  Choose the correct choice from the following options.
A) 1 B) 2 C) 3 D) 4 E) 7

Solution: Solution:   This problem is easiest solved by plugging in each answer choice.   A) (300 + 1)/1 = 301/1= 
301/1 = 301
301   Answer choice A yields an integer.   B) (300 + 2)/2= 302/2= 
302/2 = 151
151   Answer choice B yields an integer.   C) (300 + 3)/3= 303/3= 
303/3 = 101
101   Answer choice C yields an integer.   D) (300 + 4)/4= 304/4= 
304/4 = 76
76   Answer choice D yields an integer.   E) (300 + 7)/7= 307/7 = 43, remainder 6   Answer choice E DOES NOT yield an integer.   Thus, the correct answer is answer choice 7.
Answer: E
4 dice are thrown simultaneously on the board. Find the probability show the same face? Choose the correct answer:
A) 2/113
B) 1/215
C) 1/216
D) 3/113
E) 4/113

Solution: The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:   =6×6×6×6=64=6×6×6×6=64   n(S)=64n(S)=64   Let XX be the event that all dice show the same face.   X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}X={(1,1,1,1,),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6)}   n(X)=6n(X)=6   Hence required probability,   =n(X)n(S)=664=n(X)n(S)=664   =1/216   1/216
Answer: C
Two trains 190 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose the correct choice from the following answers.
A) 10.7 B) 10.9 C) 10.6 D) 12.6 E) 18.8

Solution: Relative speed = 60 + 40= 
60 + 40 = 100
100 km/hr.= 100 * 5/18 = 250/9 m/sec.   Distance covered in crossing each other = 190 + 160= 
190 + 160 = 350
350 m.   Required time= 350 * 9/250= 
350 * 9/250 = 63/5 = around 12.6
12.6 sec.   Answer:12.6
Answer: D
A dishonest dealer professes to sell goods at the cost price but uses a weight of 900 grams per kg, what is his percent? Select
A) 11.11%
B) 25%
C) 22%
D) 29%
E) 45%

Solution: 900 --- 100   100 --- ? => 11.11%   11.11%nswer:11.11%
Answer: A
After running a series of television advertisements, a leading beverage producer saw its sales increase by 50% to $1 million dollars per month. Prior to the advertising campaign, about how many dollars in sales did the company average per day?  Select the correct option:
A) $1.25 million  B) $22,000  C) $750,000  D) $27,000  E) $10,000

Solution: Let sales in previous month = X   1.5 X=1,000,000   3/2 X= 1,000,000 ..........> X=666,666   sales per day= 666,666/30= less than 25,000 so closest number is 22,000   Answer: $22,000
Answer: B
In school there are some bicycles and 4 wheeler wagons.one Tuesday there are 190 wheels in the campus.How many bicycles are there? Choose one.
A) 35  B) 36  C) 37  D) 38  E) 39

Solution: Let no. of bicycles be x   & no. of wagons be y   so, 2x+4y=190   by solving, we get   no. of bicycles=39 (wheels=>2*39= 
2*39 = 78
78)   no. of wagons=28 (wheels=>4*28= 
4*28 = 112
112)   ANSW39R:39
Answer: E
A university cafeteria offers 4 flavors of pizza - pepperoni, chicken, Hawaiian and vegetarian. If a customer has an option (but not the obligation) to add extra cheese, mushrooms or both to any kind of pizza, how many different pizza varieties are available ?
Choices:
A) 4  B) 8  C) 12  D) 16  E) 32

Solution: There are 4 flavors of pizza and each can be:   1. Without cheese and mushrooms;   2. With cheese;   3. With mushrooms;   4. With cheese and mushrooms.   So, the total number of pizza varieties is  4*4= 
 4*4 = 16
16.   Answer: 16.
Answer: D
A feed shop sells two varieties of birdseed: Product A, which is 40% millet and 60% sunflower, and Product B, which is 65% millet and 35% safflower. If a customer purchases a mix of the both types of birdseed that is 50% millet, what percent of the mix is Product A?	Choose the correct answer
A) 50%	B) 55%	C) 60%	D) 40%	E) 45 %

Solution: Yes there is a simple method :   Consider the following method   Product A : 40% millet and 60% sunflower   Product B : 65% millet and 35% safflower   Mix : 50% millet   Here the weighted average is 50%,   Now Product A has 40% millet, which is 10% less than the weighted average of mix = - 0.10 A --------------- I   Similarly, Product B has 65 % millet, which is 15 % more than the weighted average of mix = + 0.15 B ------------ II   Now, both Product A and Product B are combined to give a 50% mix containing millet, so equate I and II   implies, 0.10 A = 0.15 B   Therefore A/B = 0.15/0.10 = 3/2   A : B : (A + B) = 3 : 2 : (3+2) = 3 : 2 : 5   We have to find, percent of the mix is Product A i.e. A : (A + B) = 3 : 5 = (3 / 5) * 100= 
(3 / 5) * 100 = 60
60 %   Here is a pictorial representation :   Product A= 40%------------------------10% or 0.10 below average, A times-----------------Total below = - 0.10 A   ----------------------------------------------------------------------------------------Average = 50% or 0.50   Product B = 65 %--------------------------15% or 0.15 above average, B times-----------------Total above = + 0.15 B   Since the amount below the average has to equal the average above the average; therefore,   0.10 A = 0.15 B   A/B = 3/2   A:B: Total = 3:2:5   A/Total = 3:5 = 60 %   Answer: 60%
Answer: C
Ramesh completes a piece of work in 4 days, Ranjith completes the same work in 20 days. If both of them work together, then the number of days required to complete the work is?  Choose the correct choice from the following.
A) 6 days B) 8 days C) 10 days D) 12 days E) 3.33 days

Solution: If A can complete a work in x days and B can complete the same work in y days, then, both   of them together can complete the work in x y/ x+ y days.   That is, the required No. of days =4 × 20/24 = 3.33 days   Answer : 3.33 days
Answer: E
If x = 3y, where y is a prime number greater than 2, how many different positive even divisors does x have, including x?  Choose the correct choice from the following options:
A) 0  B) 1  C) 2  D) 3  E) It cannot be determined from the information given

Solution: For x to have even divisors, xx has to be an even number.   We know that x=3y, where yy is a prime number greater than 2. As 2 is the only even prime number, y has to be an odd prime number.   This means that x must also be an odd number, since odd x odd = odd.   As x is odd, it cannot have any even divisors.   Therefore, 0 is the correct answer.
Answer: A
21 friends went to a hotel and decided to pay the bill amount equally. But 20 of them could pay Rs. 30 each as a result 21st has to pay Rs. 200 extra than his share. Find the amount paid by him.  Choose the correct option:	A) 120	B) 250	C) 110	D) 220	E) None

Solution: Explanation:   Average amount paid by 20 persons = Rs. 30   Increase in average due to Rs. 200 paid extra by the 21st men = Rs. 200/20= Rs. 10   Therefore, Average expenditure of 21 friends = Rs. 30 + Rs. 10 = Rs. 40   Therefore, Amount paid by the 21st men = Rs. 40 + Rs. 200 = Rs. 240   Correct Option: None
Answer: E
A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 340 m long?
Choices
A) 38 sec B) 35 sec C) 44 sec D) 40 sec E) 56

Solution: Speed = 45 km/hr = 45 Ã— (5/18) m/s   = 150/12 = 50/4 = 25/2 m/s   Total distance = length of the train + length of the platform   = 360 + 340= 
360 + 340 = 700
700 meter   Time taken to cross the platform= 700/(25/2) = 700 Ã— 2/25 = 56 seconds   ANSW56R:56
Answer: E
Bani has only pennies, dimes, and nickels in a jar. The jar has at least 1 but no more than 4 pennies. If the jar has at least 1 nickel and 1 dime, which of the following could NOT be the total amount of money in the jar? Choose the correct answer:
A) 71
B) 72
C) 73
D) 74
E) 75

Solution: Let there be a pennies , b nickels and c dimes   so total amount can be 1+5b+10c cents to 4+5b+10c   as you can see the equation of total whenever divided by 5 would leave a remainder from 1 to 4 ( as pennies can only be from 1 to 4 and hence a is limited to values from 1 to 4)   So the total can never be divisible by 5 and hence only 75 that is c is the option which is divisible by 5.   so answer is 75
Answer: E
A shopkeeper loses 15%,if an article is sold for Rs. 102. What should be the selling price of the article to gain 20%?
Choose the correct answer.
A) 333 B) 144 C) 188 D) 199 E) 121

Solution: Given that SP = Rs. 102 and loss = 15%   CP = [100(SP)]/(100 - l%) = (100 * 102)/85 = 20 * 6 = Rs. 120.   To get 20% profit, New SP = [(100 + p%)CP]/100 = (120 * 120)/100 = Rs. 144.Answer: 144
Answer: B
A bus from city M is traveling to city N at a constant speed while another bus is making the same journey in the opposite direction at the same constant speed. They meet in point P after driving for 2 hours. The following day the buses do the return trip at the same constant speed. One bus is delayed 24 minutes and the other leaves 36 minutes earlier. If they meet 24 miles from point P, what is the distance R between the two cities?
Choose the correct choice from the following answers:  A) 48  B) 72  C) 96  D) 120  E) 192

Solution: Hmmm I did this question a while ago and got it wrong so trying again   Rate x time = distance.   For the initial trip lets the distance R to the midpoint be represented by P.   EQN1: R x 2 = P   For the second trip we know one bus left late and one left early. Together this is just a tricky way of saying one bus left an hour after the other. We know the total trip takes 4 hours (since getting to P is 2 hours). The second trip can be represented by:   Since the trip takes 4 hours if a bus leaves one hour early, the reminaining 3 hours are split between the two buses, ie. 1 + 3/2 = 2.5   EQN2: R x 2.5 = P + 24   EQN2-EQN1 : 0.5R=24   R=48   So the distance is rate x time = 48 x 4 = 192.   ANS = 192
Answer: E
If 9 is a factor of 2y, then which of the following may not be an integer?	Choose the correct answer.
A) 6y/54 + 2y/3	B) (4y-18)/9	C) (2y+27)/9	D) (81-4y^2)/81	E) (2y-3)/3

Solution: I got the right answer A after plugging in 18 for y.   While going through Kaplan's explanation, I couldn't understand the part about choice A.   "6y/54 + 2y/3 = 3/6 * 2y/9 + 2y/3.   Since 9 is a factor of 2y, 3 is also factor of 2y. So 2y/3 is an integer, as is 2y/9. But 3/6 = 1/2, so if 2y/9 is not even, the expression 3/6 * 2y/9 will not be even."   But, isn't 2y/9 always even? 9 is a factor of 2y, which means that we could have 2(9), 2(2)(9), 2(3)(9), and so forth. The 9 in the denominator cancels out the 9 in the numerator. So we are left with 2 * something. So 2y/9 is even.6y/54 + 2y/3
Answer: A
3 buffaloes eat as much as 4 cows or 2 oxen. At a farm there are 15 buffaloes, 8 oxen and 24 cows. The fodder for these cattle is available for 24days. If 8 more cows & 9 more buffaloes are brought in, how long will the fodder last?
Select the correct option
A) 10 B) 12 C) 13 D) 18 E) 21

Solution: Sol. 2 oxen = 3 buffaloes = 4 cows 8 oxen = 16 cows and 15 buffaloes = 20 cows 16 cows + 20 cows + 24 cows = 60 cows Since fodder is available for 60 cows for 24 days   So fodder will be available for  (60 + 8 + 12)= 
 (60 + 8 + 12) = 80
80 cows c 24x60 .0 .   for-^—=18 days.   18
Answer: D
A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are
drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid
P was contained in the container initially?
Pick one:
A) 23
B) 21
C) 19
D) 17
E) 18

Solution: Explanation :   Let's initial quantity of P in the container be 7x and initial quantity of Q in the container be 5xNow 9   litres of mixture are drawn off from the containerQuantity of P in 9 litres of the mixtures drawn off =   9×712=6312=214Quantity of Q in 9 litres of the mixtures drawn off = 9×512=4512=154HenceQuantity of   P remains in the mixtures after 9 litres is drawn off =7x−214Quantity of Q remains in the mixtures after 9   litres is drawn off =5x−154Since the container is filled with Q after 9 litres of mixture is drawn   off,Quantity of Q in the mixtures=5x−154+9=5x+214Given that the ratio of P and Q becomes 7 :   9⇒(7x−214):(5x+214)=7:9⇒(7x−214)(5x+214)=7963x−(9×214)=35x+(7×214)28x=(16×214)x=(16×214×28)   litres of P contained in the container initially = 7x=(7×16×214×28)=16×214×4=21   Answer : Option 21
Answer: B
A certain university will select 2 of 3 candidates eligible to fill a position in the mathematics department and 4 of 5 candidates eligible to fill 2 identical positions in the computer science department. If none of the candidates is eligible for a position in both departments, how many different sets of 3 candidates are there to fill the 3 positions?	Choices:
A) 42 B) 10 C) 40 D) 65 E) 15

Solution: 3C2*5C4 = 3*5= 
3*5 = 15
15   the answer is (15)
Answer: E
How many even integers n, such that 20<=n<=180 are of the form 3k+4, where k is any natural number?  Pick one.
A) 24
B) 27
C) 30
D) 33
E) 36

Solution: The first number is 22 = 16+6(1).   We can continue adding 6 to make a list: 22, 28, 34,...   The last number is 278 = 16+6(27)   There are 27 numbers in the list.   The answer is 27.
Answer: B
There are 12 dozen mangoes in a box. If there are 43
such boxes, how many mangoes are there in all the
boxes together?	Choose the correct choice from the following answers
A) 516
B) 3096
C) 6192
D) 628
E) None

Solution: Number of mangoes = 12 dozens   = 12 × 12 = 144   ∴ Number of mangoes in 43 boxes   = 43 × 144 = 6192   Answer 6192
Answer: C
3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?	Options:
A) 34% B) 56% C) 57% D) 67% E) 78%

Solution: Total number of votes polled = (1136 + 7636 + 11628)= 
(1136 + 7636 + 11628) = 20_400
20400   So, Required percentage= 11628/20400 * 100= 
11628/20400 * 100 = 57
57%   57%
Answer: C
K is a 3 digit number such that the the ratio of the number to the sum of its digits is least.What is the difference between the hundreds and tens digit?  Choose the correct choice from the following:
A) 9
B) 8
C) 7
D) 6
E) 5

Solution: Explanation :   This is only possible only when the hundreds digit has the least value and tens and units has the highest value.so we could get the highest possible sum but possible lowest number.so by this logic this number could only be 199.so the difference is 8.   note:remember a number given as abc i.e abc=aX100+bX10+c.   so 123=1X100+2X10+3.   Answer : 8
Answer: B
An inlet pipe can fill the tank in 30 minutes. B an outlet pipe can empty the tank in 45 minutes. In what time the tank be filled if both pipes work simultaneously? Choose the most appropriate option
A) 90 minutes B) 80 minutes C) 70 minutes D) 60 minutes E) 50 minutes

Solution: Time taken to fill the tank= LCM = 90   = Ratio= 30:45=2:3   = 90/(3 - 2)= 
90/(3 - 2) = 90
90/1= 
90/1 = 90
90 minutes   90 minutesNSWER:90 minutes
Answer: A
The average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher? Select the correct option
A) 44  B) 48  C) 45  D) 43  E) 50

Solution: Total age = 22 * 21   tot age of all stu + age of the teacher = 23*22   age of the teacher = 23*22-22*21= 
23*22-22*21 = 44
44   44NSWER 44
Answer: A
Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?	Choose the correct choice from the following options.
A) Rs.530	B) Rs.540	C) Rs.550	D) Rs.560	E) Rs.570

Solution: A+Rs.540+C = 1170   4A = 3Rs.540 = 2C = x   A:Rs.540:C = 1/4:1/3:1/2 = 3:4:6   6/13 * 1170 = Rs.540   Rs.540
Answer: B
Camel and carriage for Rs. 5000. He SP the camel at a gain of 20% and the carriage at a loss of 10%. If he gains 3% on the whole, then find the CP of the camel?  Select the correct option
A) Rs.2166.67  B) Rs.2234  C) Rs.2345.13  D) Rs.2456.34  E) Rs.2550.34

Solution: Now, in this numerical, there is no common loss and gain %.   Hence, solve it making equations.   Let cost price of camel be x.   As cost of camel and carriage = Rs 5000   Cost of carriage = Rs. (5000 – x)   After selling camel he gains 20% and on carriage a loss of 10%. But on the whole he gains 3%.   Therefore,   20% of x – 10 % of (5000 – x) = 3 % of 5000   20 × x – 10 × (5000 – x) = 3 × 5000   100 100 100   x – (5000 – x) = 150   5 10   10x – (5000 – x) × 10 = 150 × 10   5 10   2x-5000+x=1500   3x=1500+5000   x=2166.67   The cost of camel = Rs.2166.67   Option (Rs.2166.67) is the correct answer
Answer: A
If two students are made to sit in a row, then 6 don't have seats. If 6 students are made to sit in a row, then three rows are empty. How many students have to sit a row such that each row has equal number of students and all students are seated?	Choose the correct choice: A) 0 B) 3 C) 4 D) 5 E) 9

Solution: Let there be a rows.   Then 2a + 6 = 6(a-3) [equating the number of students]   => a= 6   and total number of students = 18   Therefore 3 students much sit in each row such that each row has an equal number of students and all students are seated.   Option (3)
Answer: B
Find the value of k for which there are infinite solutions for the given set of equations.
5x + 2y = k and 10x + 4y = 3	Choose the correct choice from the following:
A) 3/0	B) 3/2	C) 3/1	D) 3/8	E) 3/4

Solution: For the two sets of equation to have infinite solutions, we have 510=24=k3510=24=k3. Hence, k = 3/2   Answer:	3/2
Answer: B
If n is an integer greater than 8, which of the following must be divisible by 3?	Choose the correct option
A) 1. n (n+1) (n-4) B) 2. n (n+2) (n-1) C) 3. n (n+3) (n-5) D) 4. n (n+4) (n-2) E) 5. n (n+5) (n-6)

Solution: We need to find out the number which is divisible by three,   In every 3 consecutive integers, there must contain 1 multiple of 3.   So n+4 and n+1 are same if we need to find out the 3's multiple. replace all the numbers which are more than or equal to three   1. n (n+1) (n-4) = > n(n+1)(n-1) = > (n-1)n(n+1)   2. n (n+2) (n-1) = > n(n+2)(n-1) = > (n-1)n(n+1)   3. n (n+3) (n-5) = > n(n+0)(n-2) = > (n-2)n(n)   4. n (n+4) (n-2) = > n(n+1)(n-2) = > (n-2)n(n+1)   5. n (n+5) (n-6) = > n(n+2)(n-0) = > (n)n(n+2)   from the above onlyoption Ais product of consecutive three numbers.   3. n (n+3) (n-5)
Answer: C
Due to 10% decrease in the price of sugar and John can buy 5kg more sugar in Rs100 , then find the CP of sugar?  Choose the correct choice from the following answers:
A) Rs. 1(2/9)
B) Rs. 2(2/9)
C) Rs. 2(1/9)
D) Rs. 4(2/9)
E) Rs. 3(1/9)

Solution: Here r = 10 % ,x = 100 and A = 5 kg   Actual price of sugar = 10*100/((100-10 )*5) = Rs. 2(2/9)   Rs. 2(2/9)
Answer: B
A work which could be finished in 9 days was finished 3 days earlier after 10 more men joined. The number of men employed was?
Choose the correct choice from the following answers: A) 8 B) 9 C) 10 D) 20 E) 30

Solution: x ------- 6   (x + 10) ---- 3   x * 6 = (x + 10)3   x = 10   ANSWER:10
Answer: C
36 is divided in 2 parts such that 8 times the first part added to 3 times the second part makes 203. What is the first part?  Pick one
A) 19	B) 88	C) 267	D) 26	E) 28

Solution: Explanation:   Let the first part be x.   8x + 3 (36 – x) = 203   8x + 108 – 3x = 203   5x + 108 = 203   5x = 95   x = 19   19NSWER: 19
Answer: A
In a nationwide poll, N people were interviewed. If 1/5 of them answered yes to question 1, and of those, 1/4 answered yes to question 2, which of the following expressions represents the number of people interviewed who did NOT answer yes to both questions? Choose the correct choice from the following choices:
A) N/9  B) 8N/9  C) 19N/20  D) 31N/40  E) 37N/40

Solution: The number of people who answered yes to both questions is (1/4)(1/5)N = N/20   The number of people who did not answer yes to both is 1 - N/20 = 19N/20   The answer is 19N/20.
Answer: C
The cost price of 60 articles is the same as the selling price of x articles. If the profit is 20%, what is x?	Choose the correct answer:
A) 42	B) 45	C) 48	D) 50	E) 54

Solution: Let the cost price = y   The cost price of 60 articles = 60y   The selling price of x articles = 1.20y*x   1.20y*x = 60y   x = 60 / 1.2= 
60 / 1.2 = 50
50   The answer is 50.
Answer: D