MU-NLPC/Calc-aqua_rat huggingface dataset:
Each person in Room A is a student, and 1/6 of the students in Room A are seniors. Each person in Room B is a student, and 5/7 of the students in Room B are seniors. If 1 student is chosen at random from Room A and 1 student is chosen at random from Room B, what is the probability that exactly 1 of the students chosen is a senior?	Choose the correct choice from the following
A) 5/42
B) 37/84
C) 9/14
D) 16/21
E) 37/42

Solution: Probability of choosing senior from Room A=1/6, Non senior=5/6   Probability of choosing senior from Room B=5/7, Non senior=2/7   Reqd probability= (1/6*2/7)+(5/7*5/6)=27/42=9/14   Answer 9/14
Answer: C
if 1/8 of a pencil is black ½ of the remaining is white and the remaining 3 ½ is blue find the total length of the pencil?	Select the correct option.
A) 8	B) 5	C) 7	D) 6	E) 4

Solution: Let the total length be xm   Then black part =x/8cm   The remaining part=(x-x/8)cm=7x/8cm   White part=(1/2 *7x/8)=7x/16 cm   Remaining part=(7x/8-7x/16)=7x/16cm   7x/16=7/2   x=8cm   8nswer is 8.
Answer: A
Cars P and Q are approaching each other on the same highway. Car P is moving at 47 mph northbound and Car Q is moving at 53 mph southbound. At 2:00 pm, they are approaching each other and 190 miles apart. Eventually they pass each other. At what clock time are they moving away from each other and 35 miles apart?  Pick one
A) 3:30 pm	B) 3:45 pm	C) 4:00 pm	D) 4:15 pm	E) 4:30 pm

Solution: Total distance, which should be covered by both cars is   190+35= 
  190+35 = 225
225 miles.   Let t be the time so the equation will be 47t+53t=225 thus,   t=2.25 hours   Answer: 4:15 pm
Answer: D
Jimâ€™s Taxi Service charges an initial fee of $2.0 at the beginning of a trip and an additional charge of $0.35 for each 2/5 of a mile traveled. What is the total charge for a trip of 3.6 miles?	Pick one
A) $5.15  B) $4.45  C) $4.80  D) $5.05  E) $5.40

Solution: Let the fixed charge of Jimâ€™s Taxi Service = 2 $   and charge per 2/5 mile(.4 mile) = .35$   Total charge for a trip of 3.6 miles = 2 + (3.6/.4) * .35   = 2 + 9*.35= 
2 + 9*.35 = 5.15
5.15 $   $5.15nswer $5.15
Answer: A
The graphs of the two linear equations ax + by = c and bx - ay = c, where a, b and c are all not equal to zero, Choose the correct answer
A) are parallel
B) intersect at one point but not perpendicular
C) intersect at two points
D) perpendicular
E) none of the above

Solution: find the slopes of the two lines   a x + b y = c , slope m1 = - a / b   b x - a y = c , slope m2 = b / a   m1*m2 = (- a / b)(b / a) = - 1   The two lines are perpendicular   ANSWER : perpendicular
Answer: D
In a class, there are 20 boys whose average age is decreased by 2 months, when one boy aged 16 years replaced by a new boy. The age of the new boy is?	Select: A) 12 years 8 months B) 15 years C) 16 years 4 months D) 17 years 10 months E) 17 years

Solution: Total decrease = (20 x 2) months   = 3 years 4 months   Age of the new boy   = 16 years - 3 years 4 months.   = 12 years 8 months.   12 years 8 monthsNSWER:12 years 8 months
Answer: A
Sally bought a dozen items at 120.00 per dozen. What will Sally have to sell each item for to generate a 15% profit?  Choose the correct option.
A) 10.15	B) 11.5	C) 15.0	D) 21.5	E) 150.0

Solution: C.P. is  120/12= 
 120/12 = 10
10   Desired profit=15%   The calculation for markup is (C.P.*desired profit/100)=10*15/100= 
10*15/100 = 3/2 = around 1.5
1.5   The calculation for final sale price=C.P.+markup=10+1.5= 
10+1.5 = 11.5
11.5   ANSWER:11.5
Answer: B
In an examination a pupil's average marks were 63 per paper. If he had obtained 22 more marks for his Geography paper and 2 more marks for his History paper, his average per paper would have been 65. How many papers were there in the examination?	Choose the correct choice from the following options
A) 8  B) 9  C) 10  D) 11  E) 12

Solution: Let the number of papers be x. Then,   63x + 22 + 2 = 65x   = 2x = 24   = x = 12.   ANSW12R:12
Answer: E
log3 N+log15 N what is 3 digit number N that will be whole number	Select.
A) 3375  B) 7292  C) 8291  D) 3929  E) 2727

Solution: No of values N can take is 1   15^3=3375   3375NSWER:3375
Answer: A
The largest 4 digit number exactly divisible by 88 is?
Choose the correct choice: A) A)9944 B) B)9954 C) C)9967 D) D)9969 E) E)9970

Solution: Largest 4-digit number = 9999   88) 9999 (113   88   ----   119   88   ----   319   264   ---   55   ---   Required number = (9999 - 55)= 
(9999 - 55) = 9_944
9944.   9944)
Answer: A
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?  Choose the correct choice from the following.
A) 277 m
B) 268 m
C) 276 m
D) 150 m
E) 125 m

Solution: Speed=(60 * 5/18) m/sec = (50/3) m/sec Length of the train   = (Speed x Time) = (50/3 * 9)= 
(50/3 * 9) = 150
150 m.   Answer:150 m
Answer: D
Find 10th term in the series 1, 3, 5, 7, ...
Choose the correct choice from the following choices
A) 19
B) 20
C) 21
D) 22
E) 23

Solution: SOLUTION:   a = 1   d = 3 – 1 = 2   10th term, t10 = a + (n-1)d = 1 + (10 – 1)2 = 1 + 18= 
1 + 18 = 19
19   19NSWER IS 19
Answer: A
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 3 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each?  Choose the correct choice from the following answers:
A) s.2718	B) s.4586	C) s.4597	D) s.4530	E) s.4528

Solution: Area of the four walls = 2h(l + b)   Since there are doors and windows, area of the walls = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3) = 906 sq.ft.   Total cost = 906 * 3   =Rs.2718   s.2718nswer: s.2718
Answer: A
A sum was put at simple interest at a certain rate for 3 years Had it been put at 3% higher rate, it would have fetched 81 more. Find the sum.
Choices
A) 500	B) 600	C) 700	D) 800	E) 900

Solution: Difference in S.I. = P×T/100(R1−R2)   ⇒ 81 = P×3x3/100(∵ R1 - R2 = 2)   ⇒ P = 81×100/3x3=900   Answer 900
Answer: E
A car travels the first 1/3 of certain distance with a speed of 12km/hr the next 1/3 distance with a speed of 20 km/hr, and the last 1/3 distance with a speed of 60 km/hr. the average speed of the car for the whole journey is?  Choose the correct choice from the following choices.
A) 12km/hr  B) 20km/hr  C) 89km/hr  D) 52km/hr  E) 79km/hr

Solution: Let the whole distance travelled be x km   and the average speed of the car for he whole journey be y km/hr   then (x/3)/12+(x/3)/20+(x/3)/60=x/y   x/36+x/60+x/180=x/y   1/20y=1   y=20km/hr   Answer(20km/hr)
Answer: B
If a sum of money doubles itself in 8 years at simple interest, the ratepercent per annum is Choose the correct choice from the following options
A) 12 B) 12.5 C) 13 D) 13.5 E) 14

Solution: Explanation:   Let sum = x then Simple Interest = x   Rate = (100 * x) / (x * 8) = 12.5   Option 12.5
Answer: B
Find the least number which when divided by 5,6,7, and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.
Choose the correct answer.
A) 1683  B) 1753  C) 1523  D) 1433  E) None of them

Solution: L.C.M. of 5,6,7,8 = 840.   Therefore, Required number is of the form 840k + 3   Least value of k for which (840k + 3) is divisible by 9 is k = 2.   Therefore, Required number = (840 X 2 + 3)=1683   1683nswer is 1683.
Answer: A
26 buses are running between two places P and Q. In how many ways can a person go from P to Q and return by a different bus? Choose the correct choice from the following:
A) 625
B) 650
C) 576
D) 600
E) 700

Solution: we can go in any bus out of the 26 buses.   Hence He can go in 26 ways.   Since we can not come back in the same bus that he used for travelling,   we can return in 25 ways.   Total number of ways = 26 x 25 = 650   ANSWER:650
Answer: B
A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.600 more. What was the Sum?	Options: A) Rs.1200 B) Rs.1300 C) Rs.1400 D) Rs.1500 E) Rs.1600

Solution: At 5% more rate, the increase in S.I for 10 years = Rs.600 (given)   So, at 5% more rate, the increase in SI for 1 year = 600/10 = Rs.60/-   i.e. Rs.60 is 5% of the invested sum   So, 1% of the invested sum = 60/5   Therefore, the invested sum = 60 × 100/5 = Rs.1200 Rs.1200nswer: Rs.1200
Answer: A
Positive integer x has p factors; 3x has 3 factors; Which of the following values can p take?
I. 1
II. 2
III. 3  Select the correct option.
A) II or III	B) I or III	C) I or II	D) only I	E) only II

Solution: Squares have odd number of factors.The square which is a multiple of 3 is 9.   3 has factors 1,3 .   Therefore 2 factors   Answer only II
Answer: E
Jeff has 252 ounces of peanut butter in 16, 28. and 40 ounce jars. He has an equal number of each sized jar. How many jars of peanut butter does Jeff have?	Choose the correct choice from the following
A) 9	B) 8	C) 7	D) 10	E) 11

Solution: Let p equal the number of each sized jarThen 16p + 28p + 40p = 25284p = 252p = 3Therefore, the total number of jars of peanut butter Jeff has = 3p = 99nswer: 9
Answer: A
Bricks are sold in packages of eight or thirteen only. If Timmy, a builder, bought 144 bricks exactly, what could be the number of large packs Timmy bought?
Choose the correct answer.
A) 12
B) 5
C) 6
D) 8
E) 7

Solution: Let number of packs of eight = e   let number of packs of thirteen = t   8e + 13t = 144   Now , we need to test for values of t .   Since sum 144 is even and 8s will always be even , t can't be odd .   Now , we can test for values e = 12 , 8 and 6   8*5 + 13*8 = 40 + 104= 
40 + 104 = 144
144   Answer 8
Answer: D
Lagaan is levied on the 60 percent of the cultivated land. The revenue department collected total Rs. 3,84,000 through the lagaan from the village of Mettur. Mettur, a very rich farmer , paid only Rs.480 as lagaan. The percentage of total land of Mettur over the total taxable land of the village is:  Answers:
A) 0.20833  B) 1.23455  C) 2.45466  D) 5.54353  E) 6.45343

Solution: Total land of Sukhiya = \inline \frac{480x}{0.6} = 800x   \therefore Cultivated land of village = 384000x   \therefore Required percentage = \inline \frac{800x}{384000}\times 100 = 0.20833   0.20833
Answer: A
Two circular frames are kept one above the other. Frame X has a diameter of 16 cm and Frame Y has a diameter of 12 cm. What fraction of the surface of Frame X is not covered by Frame Y?	Pick one:
A) 3/5  B) 7/16  C) 12/16  D) 24/12  E) 2/3

Solution: The questions asks us to find the surface which is not covered by the Frame Y i.e., area of the surface not covered.   Where as circumference is the length along the edge of the circle,   2*pi*r implies the length of the curve   pi*r^2 implies area enclosed by that curve..hence Area of the circle is considered for this problem   Area of the Frame Y=pi* r^2, where r=6   =>pi*36   Area of the Frame X=pi*64   Surface not covered by the Frame Y=pi*64-pi*36=Pi*28   fraction of Frame X's surface is not covered by a Frame Y= Pi*28/total area of the Frame X   =28/64=7/16   Answer is 7/16
Answer: B
The product of two numbers is 192 and the sum of these two numbers is 28. What is the smaller of these two numbers?  Choose the correct answer:	A) 10	B) 12	C) 14	D) 15	E) 16

Solution: Solution   Let the number be x and (28 - x)	= Then,   x (28 - x) = 192   ‹=›x2 - 28x + 192 = 0.   ‹=›(x - 16) (x - 12) = 0   ‹=›x = 16 or x = 12.   Answer 12
Answer: B
My grandson is about as many days as my son in weeks, and my grandson is as many months as I am in years. My grandson, my son and I together are 120 years. Can you tell me my age in years ?	Choose one.
A) 70
B) 69
C) 82
D) 89
E) 72

Solution: Let m be my age in years. If s is my son's age in years, then my son is 52s weeks old. If g is my grandson's age in years, then my grandson is 365g days old. Thus,   365g = 52s.   Since my grandson is 12g months old,   12g = m.   Since my grandson, my son and I together are 120 years,   g + s + m = 120.   The above system of 3 equations in 3 unknowns (g, s and m) can be solved as follows.   m / 12 + 365 m / (52 x 12) + m = 120 or   52 m + 365 m + 624= 
+ 624 = 624
624 x 120 or   m= 624 x 120 / 1041 = 72.
Answer: E
Find the unit digit in
(544)102+(544)103  Choose one.
A) 2
B) 4
C) 0
D) 1
E) 3

Solution: Explanation:   Required digit is =   (4)102+(4)103   as   (4)2   gives unit digit 6 so   (4)102   unit digit is 6 and   (4)103   unit digit is, unit digit of   6×4   = 4, so answer will be unit digit of 6 + 4 = 0   Option 0
Answer: C
A customer pays 50 dollars for a coffee maker after a discount of 20 dollars
What is the original price of the coffe maker?  Choose the correct choice from the following answers: A) 50 B) 40 C) 70 D) 60 E) 20

Solution: Let x be the original price.   x - 20 = 50   x - 20 + 20 = 50 + 20   x + 0 = 70   x = 70
Answer: C
For any non-zero a and b that satisfy |ab| = ab and |a| = a
|b - 4| + |ab - b| = ?	Answers
A) ab-4	B) 2b - ab - 4	C) ab+4	D) ab - 2b + 4	E) 4-ab

Solution: |ab| = ab and |a| = -a   => b is also negative.   So   |b-4| + |ab -b|   = (b-4) + ab - b ( as ab is positive and -b is positive, so expression is totally positive)   =b-4+ab-b   =ab-4   ab-4nswer -ab-4
Answer: A
A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?	Select the correct option.
A) 9:1
B) 4:2
C) 5:2
D) 9:2
E) 9:0

Solution: Milk = 3/5 * 20= 
3/5 * 20 = 12
12 liters, water= 8 liters   If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters.   Remaining milk = 12 - 6= 
12 - 6 = 6
6 liters   Remaining water= 8 - 4= 
8 - 4 = 4
4 liters   10 liters of pure milk are added, therefore total milk= (6 + 10)= 
(6 + 10) = 16
16 liters.   The ratio of milk and water in the new mixture= 16:4 = 4:1   If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 * 10= 
4/5 * 10 = 8
8 liters.   Amount of water removed= 2 liters.   Remaining milk = (16 - 8)= 
(16 - 8) = 8
8 liters.   Remaining water= (4 -2)= 
(4 -2) = 2
2 liters.   The required ratio of milk and water in the final mixture obtained= (8 + 10):2 = 18:2 = 9:1.   9:1nswer:9:1
Answer: A
Sally has to pick her son up at 2 p.m. It is now 12:30 p.m. She has to travel 53 miles to get her son from camp. What time should she leave to pick her on up with the closest time to 2 p.m, without being late, given the distance of 53 miles with a constant speed of 50 mph? Pick one
A) She needs to leave at 12:53 pm B) She needs to leave at 12:57 p.m C) She needs to leave at 1:03 p.m D) She cannot get there in time. E) She needs to leave at 1:15 p.m

Solution: B, she is traveling 50 miles per hour and needs to travel 53 miles. Given that 50/53= 1.03 so approximately 1 hour and 3 minutes. 2 p.m- 1 hour 3 minutes= 12:57 pm. While She needs to leave at 12:53 pm gets her there on time it is not as close to 2pm.
Answer: A
If A and B are digits and 5AB is a 3-digit number that is divisible by 10, which of the following is a possible product of A and C?
Choose the correct choice
A) 57 B) 21 C) 52 D) 38 E) 50

Solution: Key to this question is to remember the fact that a number divisible by 10 must end with only 0 (i.e B).   If B had to be 0, product should also be 0 regardless of A.   Only one answer choice meets the requirement.   Ans 50.
Answer: E
A pipe can fill a cistern in 20 minutes whereas the cistern when fill can be emptied by a leak in 28 minutes. When both pipes are opened, find when the cistern will be full?  Choose the correct choice:
A) 65 minutes B) 76 minutes C) 70 minutes D) 62 minutes E) 52 minutes

Solution: 1/20 - 1/28   = 1/70   70 minutes   Answer:70 minutes
Answer: C
If the tens digit x and the units digit y of a positive integer n are reversed, the resulting integer is 27 less than n. What is y in terms of x ?	Choose the correct choice from the following:
A) 10 - x
B) 9 - x
C) x + 3
D) x - 3
E) x - 9

Solution: Original Digits=xy i.e. Number=10x+y   After reversing the digits:   Digits=yx i.e. Number=10y+x   10y+x is 27 less than 10x+y   10x+y-27=10y+x   10x-x-27=10y-y   9x-27=9y   x-3=y   OR   y=x-3   Ans:x - 3
Answer: D
A polling company surveyed a certain country, and it found that 35% of that country’s registered voters had an unfavorable impression of both of that state’s major political parties and that 20% had a favorable impression only of Party Q. If one registered voter has a favorable impression of both parties for every two registered voters who have a favorable impression only of Party B, then what percentage of the country’s registered voters have a favorable impression of both parties (assuming that respondents to the poll were given a choice between favorable and unfavorable impressions only)?  Choose one:
A) 15
B) 20
C) 30
D) 35
E) 45

Solution: S=100   not( Q and B ) =35   only Q=20   (Q and B)/B=1/2   let ( Q and B ) =x   only B =2x   so now, 20+35+x+2x=100   x= 15   15 ans
Answer: A
A textile manufacturing firm employees 50 looms. It makes fabrics for a branded company. The aggregate sales value of the output of the 50 looms is Rs 5,00,000 and the monthly manufacturing expenses is Rs 1,50,000. Assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms. Monthly establishment charges are Rs 75000. If one loom breaks down and remains idle for one month, the decrease in profit is:	Select the correct option:
A) 13000
B) 7000
C) 10000
D) 5000
E) None of these

Solution: Explanation :   Profit = 5,00,000−(1,50,000+75,000) =Rs. 2,75,000.   Since, such loom contributes equally to sales and manufacturing expenses.   But the monthly charges are fixed at Rs 75,000.   If one loan breaks down sales and expenses will decrease.   New profit :-   =>500000×(49/50)−150000×(49/50)−75000.   =>Rs 2,68,000.   Decrease in profit   =>2,75,000−2,68,000   =>Rs. 7,000.   Answer : 7000
Answer: B
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 70 as remainder. Find the no. is? Choose the correct choice from the following options.
A) 145646	B) 236578	C) 645353	D) 456546	E) 220070

Solution: (555 + 445) * 2 * 110 + 70 = 220000 + 70= 
220000 + 70 = 220_070
220070   220070
Answer: E
For any positive integer n, the sum of the first n positive integers equals n(n+1)/2. What is the sum of all the even integers between 99 and 151?
Select:
A) 2050 B) 2350 C) 2650 D) 2950 E) 3250

Solution: 100 + 102 + ... + 150 =   100*26 + (2+4+...+50) =   100*26 + 2*(1+2+...+25) =   100*26 + 2(25)(26)/2 =   100*26 + 25*26 = 125(26) = 3250   The answer is 3250.
Answer: E
A can do a job in 10 days and B can do it in 30 days. A and B working together will finish twice the amount of work in ------- days? Choose the correct choice
A) 14 days	B) 15 days	C) 22 days	D) 11 days	E) 19 days

Solution: 15 days   1/10 + 1/30 = 2/15   15/2 *2= 
15/2 *2 = 15
15 days
Answer: B
A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is: Choose the correct choice:	A) 12 kg	B) 60 kg	C) 72 kg	D) 96 kg	E) None of these

Solution: Explanation:   Volume of water displaced = (3 x 2 x 0.01) m3   = 0.06 m3.   ∴ Mass of man = Volume of Water displaced x Density of water   = (0.06 x 1000)kg   = 60 kg.   Answer: 60 kg
Answer: B
A man took loan from a bank at the rate of 10% p.a. simple interest. After 3 years he had to pay Rs. 3000 interest only for the period. The principal amount borrowed by him was:  Choose one
A) 8000  B) 10000  C) 11000  D) 12000  E) 13000

Solution: Principal = (100X3000)/(10X3)= Rs. 10000   answer : 10000
Answer: B
The ratio between the speeds of two trains is 8: 9. If the second train runs 270 kms in 3 hours, then the speed of the first train is ?
Choose the most appropriate option:
A) 85 km/hr B) 835 km/hr C) 80 km/hr D) 82 km/hr E) None of these

Solution: Explanation:   Let the speeds of two trains be 8X and 9X km/hr.   9/X=270/3=>X=10Km/hr   So speed of first train is   10*8= 
  10*8 = 80
80 km/hr   Option 80 km/hr
Answer: C
An unbiased cubic die is thrown.What is the probability of getting a multiple of 2 or3?	Choose one
A) 1/2  B) 1  C) 1/6  D) 4/6  E) 5/6

Solution: Here S={1,2,3,4,5,6}   Let E be the event of getting the multiple of 3   then ,E={3,6}   Let F be the event of getting the multiple of 2   then ,E={2,4,6}   Let G be the event of getting the multiple of 2 and 3   then ,G={2,3,4,6}   P(G)=n(G)/n(S)=4/6   ans 4/6
Answer: D
In an election only two candidates contested. A candidate secured 70% of the valid votes and won by a majority of 174 votes. Find the total number of valid votes?  Pick one:
A) 435	B) 570	C) 480	D) 520	E) 550

Solution: Let the total number of valid votes be x.   70% of x = 70/100 * x = 7x/10   Number of votes secured by the other candidate = x - 7x/100 = 3x/10   Given, 7x/10 - 3x/10 = 174 => 4x/10 = 174   => 4x = 1740 => x = 435.   435NSWER:435
Answer: A
Mrs. A. invested $21,000; part at 5%, and part at 8%. The total interest on the investment was $1,470. How much did she invest at each rate?	Choose one:
A) x=$15,000, y =$30,000	B) x=$12,000, y =$24,000	C) x=$8,000, y =$16,000	D) x=$10,000, y =$20,000	E) x=$7,000, y =$14,000

Solution: I approached this question like a mixture problem.   I don't like the wordingpartat 5% andpartat 8% because we have variables x and y in the answer choices and I have no idea which one is x or y.   Anyway here's how I did it.   0.05(x) + 0.08(y) = 0.07(x+y)   0.01(y) = 0.02(x)   y = 2x   Note: 0.07(x+y) because $1,470 is 7% of 21,000   In which answer choice is y = 2(x)   Answer x=$7,000, y =$14,000
Answer: E
In a class, 30 students pass in English and 20 students in Math, while some students among these pass in both. How many more students do only English as compared to those doing only Maths?
Choose one:	A) 10	B) 15	C) 20	D) 25	E) Indeterminate

Solution: Let us consider tht x student are tohse who passed in both English and Maths...   So first we remove x student from both of them   Therefore,   English = 30-x   Maths = 20-x   Now, Number of Students more in English = (30-x)-(20-x)   = 30-x-20+x   = 10   10NSWER:10
Answer: A
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?  Choose the correct answer:  A) 230 m  B) 270m  C) 643m  D) 832m  E) 270m

Solution: Speed =	(72 x	5/18)m/sec	= 20 m/sec.   Time = 26 sec.   Let the length of the train be x metres.   Then,	x + 250/26	= 20   x + 250 = 520   x = 270.   Answer:270m
Answer: B
The errand service company gets a discount at the fuel center when they fill up more than 4 cars at a time. The service is $1.10 per vehicle and .30 cents per liter of fuel. On Monday , they will fill 3 vans and 3 cars. The cars are 25 liters each and the vans are 60% bigger. How much will it cost to fill up all vehicles if they are empty?
Select the correct option
A) $65.50 B) $68.10 C) $67.50 D) $68.50 E) $65.10

Solution: Lots of calculations.   1.10*6 + 3*25*.30+ 25*(8/5)*3*.30= 
1.10*6 + 3*25*.30+ 25*(8/5)*3*.30 = 65.1
$65.10   The correct option is $65.10.
Answer: E
It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010? Choose the correct choice from the following choices.
A) Friday B) Saturday C) Sunday D) Wednesday E) WednSDA

Solution: n 31st December, 2005 it was Saturday.   Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1)= 
(1 + 1 + 2 + 1) = 5
5 days.   On 31st December 2009, it was Thursday.   Thus, on 1st Jan, 2010 it is Friday.   Fridaynswer: Friday
Answer: A
Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business? Choose the most appropriate option:	A) 12:15:17	B) 12:15:16	C) 12:15:10	D) 12:15:155	E) 12:15:11

Solution: Aman : Rakhi : Sagar = (70000 * 36) : (105000 * 30) : (140000 * 24)   = 12:15:16   Answer: 12:15:16
Answer: B