MU-NLPC/Calc-aqua_rat huggingface dataset:
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: Select:
A) 21/46
B) 20/81
C) 50/90
D) 83/96
E) 24/81

Solution: Let S be the sample space and E be the event of selecting 1 girl and 2 boys.   Then, n(S)	= Number ways of selecting 3 students out of 25   = 25C3 `   =(25 x 24 x 23)   (3 x 2 x 1)   = 2300.   n(E)	= (10C1 x 15C2)   =[10 x(15 x 14)/(2 x 1)]   = 1050.   P(E) = n(E)/n(S) = 1050/2300 = 21/46.   21/46nswer:21/46
Answer: A
Here is another problem from Bhaskaracharya's Lilavati:
The square root of half the number of bees in a swarm has flown out upon a jasmine bush; eight ninths of the whole swarmhas remained behind; one female bee flies about the male that it buzzing within the lotus flower into which he was allured in the night by its sweet odour, but is now imprisoned in it. Tell me the number of bees?	Choose the correct choice from the following answers:	A) 33	B) 72	C) 54	D) 13	E) 59

Solution: 72   There were 72 bees.
Answer: B
How much time will it take for an amount of Rs. 900 to yield Rs. 81 as interest at 4.5% per annum of simple interest?  Choose the most appropriate option
A) 1 year
B) 2 years
C) 3 years
D) 4 years
E) 5 years

Solution: Explanation:   P = Rs.900   SI = Rs.81   T = ?   R = 4.5%   T= (100×SI)/PR = (100 × 81)/(900 × 4.5) = 2 years   Answer: Option 2 years
Answer: B
A man complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. Answers:  A) 220 km  B) 224 km  C) 230 km  D) 234 km  E) 240 km

Solution: 0.5x/21 + 0.5x/24 = 10   x/21 + x/24 = 20   15x = 168 x 20   x = (168 x 20)/15 = 224 km.   answer 224 km
Answer: B
A train leaves Delhi at 9 a.m. at a speed of 30 kmph. Another train leaves at 2 p.m. at a speed of 35 kmph on the same day and in the same direction. How far from Delhi, will the two trains meet?  Choose the correct answer
A) 1050 km  B) 1150 km  C) 1250 km  D) 1550 km  E) 850 km

Solution: D = 30 * 5= 
30 * 5 = 150
150   RS= 35 – 30 = 5   T = 150/5= 
150/5 = 30
30   D= 35 * 30= 
35 * 30 = 1_050
1050 km   1050 kmNSWER:1050 km
Answer: A
A retailer buys 80 pens at the market price of 36 pens from a wholesaler, if he sells these pens giving a discount of 1%, what is the profit % ? Select the correct option.
A) 110  B) 115  C) 112  D) 118  E) 120

Solution: let the market price of each pen be $1   then, Cost Price of 80 pens = $ 36 Selling Price of 80 pens =99% of $80=$ 79.20   profit %=((43.20*100)/36)= 
((43.20*100)/36) = 120
120%   Answer 120)120
Answer: E
Pipe A can fill a tank in 6 hours, pipe B in 18 hours and pipe C in 36 hours. If all the pipes are open, in how many hours will the tank be filled ?
Choose the correct option.
A) 2.5 hours B) 2 hours C) 4 hours D) 3 hours E) None of these

Solution: Explanation:   Part filled by A in 1 hour = 1/6   Part filled by B in 1 hour = 1/18   Part filled by C in 1 hour = 1/36   Part filled by (A+B+C) in 1 hour =   1/6+1/18+1/36=9/36   So all pipes will fill the tank in 4 hours.   Option 4 hours
Answer: C
A has work in 6 days and B has work in 8 days.What will be the days that A and B are worked together?
Pick one:
A) 24/7 B) 7/24 C) 7 D) 24 E) 10

Solution: A's one day work=1/6   B's one day work=1/8   A+B=1/6+1/8=7/24(one day)   They work together in 24/7 days.   24/7nswer:option 24/7
Answer: A
Rs 4000 is divided into two parts such that one part is put out at 3% and the other at 5%. If the annual interest earned from both the investments be Rs 144, find the first part.	Pick one
A) Rs 4000	B) Rs 2800	C) Rs 3800	D) Rs 3500	E) Rs 3100

Solution: Explanation :   Average rate = (144/4000)*100= 
(144/4000)*100 = 18/5 = around 3.6
3.6   Ratio= 14:6 = 7:3   So, first part = (7/10)*4000= 
(7/10)*4000 = 2_800
Rs 2800.   Answer : Rs 2800
Answer: B
Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?	Choose the correct option.
A) 4 B) 6 C) 4 D) 3 E) 7

Solution: 9261 = 8000(21/20)N   (21/20)3   = (21/20)N => N = 3   Answer: 3
Answer: D
In a race with 30 runners where 8 trophies will be given to the top 8 runners (the trophies are distinct: first place, second place, etc), how many ways can this be done?	Choose the correct choice from the following answers.
A) 8^8 ways	B) 8^9 ways	C) 7^8 ways	D) 8^7 ways	E) 8^6 ways

Solution: 8 people can be prized with 8 distinct prizes in 8^8 ways   8^8 waysNSWER:8^8 ways
Answer: A
A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? Choose one: A) 120 metres B) 180 metres C) 324 metres D) 150 metres E) 100 meters

Solution: Speed=60 x5/18m/sec=50/3	m/sec.   Length of the train = (Speed x Time).   Length of the train =	50/3	x 9m = 150 m.   ANSWER:150 metres
Answer: D
for a computer a password uses five digits from 0 to 9, inclusive. What is the probability that the digits of the password solely consist of prime numbers or zero?  Choose one: A) A)1/32 B) B)1/16 C) C)1/8 D) D)2/5 E) E)1/2

Solution: Favorable outcomes will be obtained by making Password using {0, 2, 3, 5, 7} i.e. 5 digits   Total Such Passwords = 5*5*5*5*5 = 5^5   Total Possible Password = 10*10*10*10*10 = 10^5   Probability = (5^5) / (10^5) = 1/2^5 = 1/32   1/32nswer: option 1/32
Answer: A
What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 50?  Choose one:
A) A)Rs.3400
B) B)Rs.3948
C) C)Rs.3988
D) D)Rs.3949
E) E)Rs.3923

Solution: Let the side of the square plot be a ft.   a2 = 289 => a = 17   Length of the fence = Perimeter of the plot = 4a = 68 ft.   Cost of building the fence = 68 * 50 = Rs.3400   Rs.3400nswer: Rs.3400
Answer: A
Maths, Physics and chemistry books are stored on a library shelf that can accommodate 25 books. Currently, 20% of the shelf spots remain empty. There are twice as many maths books as physics books and the number of physics books is 4 greater than that of chemistry books. Among all the books, 12 books are soft cover and the remaining are hard-cover. If there are a total of 7 hard-cover books among the maths and physics books. What is the probability W, that a book selected at random is either a hard cover book or a chemistry book? Choose the correct answer:
A) 1/10  B) 3/20  C) 1/5  D) 1/4  E) 9/20

Solution: First phase of this problem requires you to determine how many mathematics and chemistry books are even on the shelf. To do so, you have the equations:   m + p + c = 20 (since 4/5 of the 25 spots are full of books)   m = 2p   p = 4 + c   From that, you can use Substitution to get everything down to one variable.   c = p - 4   m = 2p   p = p   Then (p - 4) + 2p + p = 20, so 4p = 24 and p = 6. That means that there are 12 math, 6 physics, and 2 chemistry books on the shelf.   With those numbers, you also know that there are 8 total hardcovers, 1 of which is chemistry. So if your goal is to get either a hardcover or a chemistry, there are 9 ways towin- either one of the 7 hardcovers that aren't chemistry or the two chemistry books. So out of the 20 total, W=9 provide the desired outcome, making the answer 9/20.
Answer: E
If a = 1 and b = -2, then (2a^2 + b)(m + y) + (a + b)(m - y) =	Options:  A) 0  B) 2x  C) y - m  D) x - y  E) x + y

Solution: Putting A=1 and B = -2 => 2A^2-B=0 ; so the first part of the term is zero   with second term => (1-2) *(m+y)=y-m => Smash y - m
Answer: C
The number of sequences in which 7 boys can throw a apple, so that the youngest player may not be the last is Options:
A) 2300
B) 2400
C) 4320
D) 4500
E) 4550

Solution: The last ball can be thrown by any of the remaining 6 players.   The first 6 players can throw the ball in ⁶P₆ ways.   The required number of ways = 6(6!) = 4320   4320
Answer: C
The sum of the factors of a number is 124. What is the number?
Choose the correct choice from the following:	A) Number lies between 40 and 50	B) Number lies between 50 and 60	C) Number lies between 60 and 80	D) More than one such number exists	E) None of these

Solution: Solution:   Any number of the form paqbrc will have (a + 1) (b + 1)(c + 1) factors, where p, q, r are prime. (This is a very important idea)   For any number N of the form paqbrc, the sum of the factors will be (1 + p1 + p2 + p3 + …+ pa) (1 + q1 + q2 + q3 + …+ qb) (1 + r1 + r2 + r3 + …+ rc).   Sum of factors of number N is 124. 124 can be factorized as 22 * 31. It can be written as 4 * 31, or 2 * 62 or 1 * 124.   2 cannot be written as (1 + p1 + p2…pa) for any value of p.   4 can be written as (1 + 3)   So, we need to see if 31 can be written in that form.   The interesting bit here is that 31 can be written in two different ways.   31 = (1 + 21 + 22 + 23 + 24)   31 = ( 1 + 5 + 52)   Or, the number N can be 3 * 24 or 3 * 52. Or N can be 48 or 75 . Option More than one such number exists
Answer: D
Which of the following are divisible by both 2 and 3?
I. 234,124,422
II. 88,865,544,264
III. 5,555,554,678	Choose the correct choice from the following choices:
A) I​ only  B) I and II​  C) II and III  D) II Only  E) I​ and III

Solution: III. is not divisible by 2 & 3   I. is divisible by 3 since sum of the digits is 24 , which is divisible by 3   II. is divisible by 3 since sum of the digits is 60 , which is divisible by 3   Thus among the given options only (I and II​) holds true.
Answer: B
In a restaurant, the profit is 120% of the cost. If the cost increases by 12% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Choose the correct option:
A) 30%  B) 49%  C) 90%  D) 100%  E) None of these

Solution: Explanation :   Let C.P.= Rs. 100. Then, Profit = Rs. 120, S.P. = Rs. 220.   New C.P. = 112% of Rs. 100 = Rs. 112   New S.P. = Rs. 220.   Profit = Rs. (220 - 112) = Rs. 108.   Required percentage = (108 /220 *100) % = 49 % appox   Answer : 49%
Answer: B
275 metres long yard, 26 trees are palnted at equal distances, one tree being at each end of the yard. What is the distance between 2consecutive trees  Choose the correct option
A) 11  B) 12  C) 14  D) 16  E) 17

Solution: 26 trees have 25 gaps between them,   Required distance (275/25)= 
(275/25) = 11
11   11
Answer: A
A train travelling at a speed of 75 mph enters a tunnel miles long. The train is mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges? Choose the correct choice from the following choices:  A) 2  B) 3  C) 5  D) 7  E) 8

Solution: Explanation:   Total distance covered =miles   =miles   Time taken = hrs   = hrs   = min   = 3 min   Answer: 3) 3 min
Answer: B
Minute hand overlaps hour hand in 65 mins. In how many days it will gain 1440 hours ?
Pick one
A) 58.384 days	B) 59.384 days	C) 57.384 days	D) 69.384 days	E) 55.384 days

Solution: In this problem , it has considered that 65 mins = 1hr   so mins has increased by 5 mins so multiply 5*24= 
5*24 = 120
120 mins extra ,   That is now per day it adds 2hr extra so divide 1440/26=59.384 days   ANSWER:59.384 days
Answer: B
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that all the four bulbs are defective.	Choose the correct choice from the following options
A) 1/126 B) 1/127 C) 1/26 D) 1/129 E) 1/261

Solution: Out of nine, five are good and four are defective.   Required probability = â´Câ‚„/â¹Câ‚„ = 1/126   1/126nswer: 1/126
Answer: A
How many seconds will a 700 metre long train take to cross a man walking with a speed of 3 km/hr in the direction of the moving train if the speed of the train is 63 km/hr?	Select
A) 25  B) 30  C) 42  D) 45  E) 50

Solution: Relative speed of the train=63-3= 
63-3 = 60
60kmph=60*5/18=50/3 m/sec   t=700*3/50= 
700*3/50 = 42
42sec   ANSWER:42
Answer: C
A soft drink company had 6000 small and 15000 big bottles in storage. If 11% of small 12% of big bottles have been sold, then the total bottles remaining in storage is  Pick one
A) 15360  B) 16010  C) 15060  D) 14930  E) 18540

Solution: 6000 + 15000 - (0.11*6000 + 0.12*15000)= 
6000 + 15000 - (0.11*6000 + 0.12*15000) = 18_540
18540.   Answer: 18540.
Answer: E
60 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is :	Choose the correct choice:
A) 33	B) 45	C) 26	D) 28	E) 19

Solution: Explanation:   Let the two parts be (60 - x) and x.   Then, 10 (60 - x) + 22x = 780   => 12x = 180   => x = 15.   Bigger part = (60- x) = 45.   Answer: 45) 45
Answer: B
John had a stock of 400 pens in his bookshop. He sold 50 on Monday, 25 on Tuesday, 80 on Wednesday, 100 on Thursday and 85 on Friday. What percentage of the pens were not sold?  Choose the correct option:
A) 15%  B) 25%  C) 86%  D) 42%  E) 55%

Solution: Let N be the total number of pens sold. Hence   N = 50 + 25+ 80 +100 + 85= 
50 + 25+ 80 +100 + 85 = 340
340   Let M be the pens NOT sold   M= 400 - N = 400 - 340 = 798   Percentage   pens not sold / total number of books = 60/400= 
60/400 = 3/20 = around 0.15
0.15= 15%   correct answer 15%
Answer: A
The ratio of 2 numbers is 2:7 and their H.C.F. is 18. Their L.C.M. is ?
Choose the correct choice:
A) 252	B) 243	C) 521	D) 361	E) 600

Solution: Let the numbers be 2x and 7x   Their H.C.F. = 18   so the numbers are 2*18 , 7*18 = 36,126   L.C.M. = 252   252nswer is 252
Answer: A
In a certain group of 9 members, 3 members teach only French and the rest teach only Spanish or German. If the group is to choose 5-member committee, which must have at least 1 member who teaches French, how many different committee can be chosen ?  Select:
A) 80
B) 90
C) 120
D) 110
E) 100

Solution: 120ase 1   1french 4either German or Spanish: 31201 * 61204 = 45   120ase 2   2french 3either German or Spanish: 31202 * 61203 = 60   120ase 3   3french 2either German or Spanish = 31203 * 61202 = 15   Answer is 120 = 120
Answer: C
Sides of a rectangular park are in the ratio 3: 2 and its area is 2460sq m, the cost of fencing it at 50 ps per meter is? Options:
A) s.122 B) s.129 C) s.129.76 D) s.120 E) s.121

Solution: 3x * 2x = 2460 => x = 20.24   2(79.76 + 50) = 259.52 m   259.52 * 1/2 = Rs.129.76   Answer:s.129.76
Answer: C
Rs.850 is divided so that 4 times the first share, twice the 2nd share and twice the third share amount to the same. What is the value of the first share?	Pick one.
A) s400	B) s500	C) s850	D) s540	E) s170

Solution: A+B+C = 850   4A = 2B = 2C = x   A:B:C = 1/4:1/2:1/2 = 1:2:2   1/5* 850= 
1/5* 850 = 170
Rs170   Answer:s170
Answer: E
If two dice are thrown simultaneously, then find the probability that the sum of numbers appeared on the dice is 4? Pick
A) 5/6	B) 7/36	C) 5/36	D) 3/36	E) 12/36

Solution: The sum of numbers appeared is 4.   Therefore, the required probability = n(E)/n(S) = 3/36.   ANSWER:3/36
Answer: D
Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage Q.  Choose one:
A) 16.8%
B) 17.4%
C) 17.9%
D) 18.5%
E) 19.1%

Solution: Given: Selling price of an Apple = 23 --> Cost price = 23/1.15= 
23/1.15 = 20
20   Selling price of an orange= 10 --> Cost price = 10/1.25= 
10/1.25 = 8
8   A > O   23*(A) + 10*(O)= 653   653 - 23*(A) has to be divisible by 10 --> Units digit has to be 0   Values of A can be 1, 11, 21, 31, .... --> 1 cannot be the value   17.4%etween 11 and 21, If A = 11, O = 30 --> Not possible   If A = 21, O = 17 --> Possible   Cost price = 20*21 + 8*17 = 420 + 136= 
420 + 136 = 556
556   Profit= 653 - 556= 
653 - 556 = 97
97   Profit% Q= (97/556)*100 = 17.4%   Answer: 17.4%
Answer: B
Three candidates contested an election and received 3408, 22908 and 34884 votes respectively. What percentage of the total votes did the winning candidate get ?
Options: A) 57% B) 45% C) 75% D) 86% E) 95%

Solution: Explanation :   Total number of votes polled = (3408 + 22908 + 34884)= 
(3408 + 22908 + 34884) = 61_200
61200.   Required percentage= (34884/ 61200100)%   = 57%.   57%nswer : 57%
Answer: A
Chuck's apple tree produces 4 apples for every 2 branches. There are 8 branches on his tree. how many apples will Chuck's tree produce? Choose the correct option
A) 16  B) 8  C) 2  D) 4  E) 32

Solution: 4 apples for every 2 branches = 2 apples for every 1 branch   2 apples for 1 branch (8 branches) = 2 apples x 8 branches = 16 apples   16nswer is 16
Answer: A
Priya invested some money in 5% stock at 200.If David wants to invest in an equally good 20% stock ,he must purchase a stock worth of :  Choose the correct choice:  A) Rs. 400  B) Rs. 600  C) Rs. 800  D) Rs. 600  E) Rs. 500

Solution: Solution   For an income of Rs. 5, investment = Rs. 200   For an income of Rs. 20, investment = Rs.(200/5x20) = Rs. 800   Answer Rs. 800
Answer: C
How many odd 4-digit positive integers W that are multiples of 5 can be formed without using the digit 3?
Pick one:
A) 648
B) 729
C) 900
D) 1296
E) 3240

Solution: I choose A.   Possible n° of 1st digit: 8 (0 can't be the first number, or else it wouldn't have 4 digits. 3 is exlcuded)   Possible n° of 2nd digit: 9 (3 is excluded)   Possible n° of 3rd digit: 9 (3 is excluded)   Possible n° of 4th digit: 1 (a number is a multiple of 5 if it ends in 5 or 0, here we are asked for the odd numbers, hence the last digit can't be 0)   So, W=8*9*9*1= 
8*9*9*1 = 648
648 (648)
Answer: A
A and B are running around a circular track of length 120 meters with speeds 12 m/s and 6 m/s in the same direction. When will they meet for the first time?  Choose the most appropriate option:
A) A meets C  B) A meets B  C) A meets D  D) A meets A  E) A meets G

Solution: A meets B when A covers one round more than B.   A's relative speed = (12 - 6) m/s. So he takes 120 / 6 seconds to gain one extra round.   So after 20 seconds A meets B.   Answer:A meets B
Answer: B
If W is the set of all the integers between 29 and 99, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers?  Choose the correct choice from the following options.
A) 26 B) 32 C) 33 D) 34 E) 47

Solution: Multiples of 2 from 29 to 99=Multiples of 2 from 1 to 99-Multiples of 2 from 1 to 28=[99/2]-[28/2]=49-14= 
49-14 = 35
35   Multiples of 3 from 29 to 99=Multiples of 3 from 1 to 99-Multiples of 3 from 1 to 28=[99/3]-[28/3]=33-9= 
33-9 = 24
24   Multiples of2 and 3 bothi.e.6 from 29 to 99=Multiples of 6 from 1 to 99-Multiples of 6 from 1 to 28=[99/6]-[28/6]=16-4= 
16-4 = 12
12   These 8 Numbers have been counted twice in both the above calculation while calculating multiples of 2 and 3   i.e. Total Numbers in W= 35 + 24 - 12= 
35 + 24 - 12 = 47
47   Answer Option 47
Answer: E
If the sides of a triangle are 26 cm, 24 cm and 15 cm, what is its area?
Choose the correct answer:  A) 120  B) 772  C) 180  D) 266  E) 2848

Solution: The triangle with sides 26 cm, 24 cm and 15 cm is right angled, where the hypotenuse is 26 cm.   Area of the triangle = 1/2 * 24 * 15= 
1/2 * 24 * 15 = 180
180 cm2   Answer: 180
Answer: C
A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 45 more than the correct answer. Find the number.  Choose the most appropriate option.
A) 60  B) 80  C) 100  D) 120  E) 140

Solution: Let the number be x.   (5/4) * x = (4/5)*x + 45   25x = 16x + 900   9x = 900   x = 100   The answer is 100.
Answer: C
From the salary of Rahul, 20% is deducted as house rent, 10% of the rest he spends on children’s education and 10% of the balance, he spends on clothes. After this expenditure he is left with Rs 1,377. His salary is?
Choose the correct choice from the following choices:	A) Rs 2,125	B) Rs 2,040	C) Rs 2,100	D) Rs 2,200	E) Rs 3,200

Solution: Suppose that his salary = Rs 100   House rent = Rs 20, balance = Rs 80   Expenditure on education = Rs (10 x 80)/100 = Rs 8   Balance = Rs 72   Expenditure on clothes Rs (10 x 72)/100 = Rs 7.2   Balance now = Rs 64.8   If balance is Rs 64.8, salary = Rs 100   If balance is Rs 1,377, salary   = Rs (100 x 1377) / 64.8   Rs 2,125   Rs 2,125NSWER:Rs 2,125
Answer: A
A father said to his son, "I was as old as you are at present at the time of your birth." If the father's age is 38 years now, the son's age five years back was
Choose the correct choice from the following choices.
A) 14 years.	B) 19 years	C) 33 years	D) 38 years	E) None

Solution: Solution   Let the son's present age be x years.   Then	(38-x)=x   2x=38   x=19.   Therefore son's age 5 years back	=(19-5)= 
(19-5) = 14
14 years.   14 years.nswer 14 years.
Answer: A
The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle? Choices.
A) 18 CM  B) 16 CM  C) 40 CM  D) 20 CM  E) 50 CM

Solution: LET BRESDTH X 40 CMM   LENGTH = 2X 40 CMM   NEW L = (2X-5) 40 CMM   NEW BREADTH = (X + 5)   NEW AREA = (2X - 5 ) SQ 40 CMM   = (2X - 5 ) (X + 5 ) = 2X2+75   X = 20 40 CMM   L = 2X - 2 = 2 * 20= 
2 * 20 = 40
40 40 CMM   ANSWER 40 CM
Answer: C
The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?  Choose one:
A) 29
B) 40
C) 99
D) 28
E) 12

Solution: Speed downstream = 60 + 20= 
60 + 20 = 80
80 kmph   Speed upstream= 60 - 20= 
60 - 20 = 40
40 kmph   Answer: 40
Answer: B
In a village there are 150 men and 90 women in present time.if in next year population will be P=(a^2 +b^2)^1/2 , and in every year men are reduces 12%.what is population of after 2 year.  Choose the correct choice from the following answers:
A) 139	B) 141	C) 142	D) 143	E) 144

Solution: next year total population=[150^2+90^2]^.5=174.92=175   man decreased by 11% so total man =150*.88= 
150*.88 = 132
132   women will be= 175-132= 
175-132 = 43
43   so population after two years= [135^2+43^2]^.5=138.8=139   so population after two year= 139   139NSWER:139
Answer: A
8 identical machines, working alone and at their constant rates, take 6 hours to complete a job lot. How long would it take for 6 such machines to perform the same job?	Choices.
A) 2.25 hours B) 8 hours C) 12 hours D) 14.25 hours E) 16 hours

Solution: Let each machine do 1 unit of work for 1 hour   8 machines --> 8 units of work in 1 hour   For 6 hours = 8*6= 
8*6 = 48
48 Units of total work is done.   Now this 48 Units of total work must be done by 6 machines   6units of work(6 machines) ---> 1 hour   for 48 Units of work   6*8 ---> 1*8 hours   8 hours 8 hours
Answer: B
A started a business with an investment of Rs. 70000 and after 6 months B joined him investing Rs. 120000. If the profit at the end of a year is Rs. 78000, then the share of A is? Choose the correct choice from the following choices.
A) s.42028  B) s.42000  C) s.42003  D) s.42029  E) s.24029

Solution: Ratio of investments of A and B is (70000 * 12) : (120000 * 6) = 7 : 6   Total profit = Rs. 78000   Share of s.42000 = 7/13 (78000) = Rs.42000   Answer: s.42000
Answer: B
Find smallest prime number is:	Choose the correct choice from the following choices.
A) 6 B) 18 C) 7 D) 15 E) 11

Solution: 7   7
Answer: C
Simplify: 8888 + 888 + 88 + 8
Pick:
A) 9872	B) 9782	C) 9827	D) 9287	E) None of them

Solution: 8888   888   88   8   -------   9872   9872nswer is 9872.
Answer: A
Aphid and Ladybug are investors in a pineapple farm. Aphid owns a 30% stake in it, and Ladybug owns the remaining 70%. The profits this year in pineapples and pineapple byproducts total five million zenny (the national currency of their land). How much zenny should Aphid receive?
Pick one.
A) 50000 zenny	B) 100000 zenny	C) 150000 zenny	D) 200000 zenny	E) 250000 zenny

Solution: A = 30   B = 70   A share 3 parts & B share 7 parts   Total 10 parts -----> 5000000   ----> 1 part -------> 500000   A share = 3 parts -----> 150000   150000 zenny
Answer: C