MU-NLPC/Calc-aqua_rat huggingface dataset:
66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length of the wire in metres will be:
Select the correct option
A) 66  B) 84  C) 80  D) 72  E) 68

Solution: Let the length of the wire be h.   Radius =1/2mm=1/20cm.	Then,   (22/7)x (1/20) x (1/20) x h = 66.   h = (66 x 20 x 20 x 7)/22 = 8400 cm = 84 m.   ANSWER 84
Answer: B
Mixture of milk & water has been kept in two separate bowl. Ratio of milk to water in one of the bowls is 5 : 1 and that in the other bowl 7 : 2. In what ratio the mixtures of these 2 bowl should be added together so that the quantity of milk in the new mixture may become 80%? Choose the correct choice from the following answers:
A) 2:3  B) 1:3  C) 2:5  D) 3:7  E) 4:5

Solution: Lett. mixtures of the two containers be added together in the ratio of x   = = [ixoox l00%   Since the percentage quantity ofmilk in the new mixture is SO% — so% (45x + 42y) x 5 4 x 54(x y) 225x 210y 216.3E+216y   9x=6y   x:y=2:3   2:3
Answer: A
The sale price sarees listed for Rs.390 after successive discount is 15% and 25% is? Pick one
A) 298  B) 237  C) 248  D) 876  E) 291

Solution: 390*(85/100)*(75/100)   = 248   Answer: 248
Answer: C
In a market there are men and horses. In all, there are 22 heads and 66 feet. How many men and how many horses are in the market?	Select the correct option:
A) 8 men and 14 horses. B) 7 men and 14 horses. C) 6 men and 14 horses. D) 5 men and 14 horses. E) 11 men and 11 horses.

Solution: 11 men and 11 horses.   Let M = men and H = horses. We can come up with 2 equations.   M + H = 22   2M + 4H= 66   Solving the 2 equations will give 11 men and 11 horses.   Answer 11 men and 11 horses.
Answer: E
A train met with an accident 80km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?	Choose the correct answer.
A) 60 km/hr B) 55 km/hr C) 65 km/hr D) 80 km/hr E) 48 km/hr

Solution: let the original speed be 6x. A/q, traveling 80 km at 5/6th of original speed costs him 12 minutes etc   80/5x =80/6x +12/60 -> x =10 , 8x= 80.   Ans 80 km/hr
Answer: D
An investor deposited $10,000 to open a new savings account that earned 12 percent annual interest, compounded quarterly. If there were no other transactions in the account, what was the amount of money in the account 6 months after the account was opened?  Choose one.
A) $10,300 B) $10,303 C) $10,600 D) $10,609 E) $10,900

Solution: The amount in the account after 6 months is 1.03*1.03($10,000) = $10,609.   The answer is $10,609.
Answer: D
In a deck of cards there are 52 cards numbered from 1 to 13. There are 6 cards of each number in the deck. If you insert 12 more cards with the number 10 on them and you shuffle the deck really good, what is the probability to pull out a card with a number 10 on it?	Choose one:
A) 1/4. B) 4/17. C) 5/29. D) 4/13. E) 9/32

Solution: 6+12 tens/52+12 total cards=18/64=9/32   9/32
Answer: E
A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail  Choose the correct answer:
A) 2/4
B) 1/3
C) 2/3
D) 3/6
E) 1/4

Solution: Sample space S = { HH, HT, T1, T2, T3, T4, T5, T6 }   Let A be the event that the die shows a number greater than 4 and 1/3 be the event that the first throw of the coin results in a tail then,   A = { T5, T6 }   1/3 = { T1, T2, T3, T4, T5, T6 }   Required probability = ( 2/8)/(6/8)=1/3   ANSWER:1/3
Answer: B
The average of six results is 15 and that of the first five is 13. The sixth result is?
Options
A) 20  B) 25  C) 15  D) 22  E) 18

Solution: 6 * 15 â€“ 5 * 13 = 25   Answer: 25
Answer: B
The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 18 greater than the actual number and the second number added is 13 instead of 31. Find the correct average.	Choose the correct choice from the following
A) 40.2  B) 40.4  C) 40.6  D) 40.8  E) None of the above

Solution: Sum of 10 numbers = 402   Corrected sum of 10 numbers   = 402 – 13 + 31 – 18 = 402   Hence, new average = 402⁄10 = 40.2   40.2nswer 40.2
Answer: A
The numbers in which of the following pairs do NOT have a pair of distinct prime divisors in common ?
Choose one:
A) 10 and 20  B) 12 and 18  C) 24 and 32  D) 21 and 63  E) 22 and 88

Solution: 32 has only one prime 2 (32=2^5) in its prime factorization, so it can not have a PAIR of distinct prime divisors in common with ANY of the numbers.   Answer: 24 and 32.
Answer: C
The difference between the value of a number increased by 12.5% and the value of the original number decreased by 25% is 30. What is the original number E?	Select the correct option
A) 60 B) 80 C) 40 D) 120 E) 160

Solution: (1 + 1/8)x - (1 - 1/4)x = 30   (9/8)x - (3/4)x = 30   x = 80=E   Answer: 80
Answer: B
There are 16 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season?  Choices
A) 750
B) 900
C) 1050
D) 1200
E) 1350

Solution: The number of ways to choose two teams is 16C2 = 16*15/2= 
16*15/2 = 120
120   The total number of games in the season is  10*120= 
 10*120 = 1_200
1200.   The answer is 1200.
Answer: D
Out of the five integral numbers C is the average of A and D. B is greater than C and less than D.Also B is the average of A and E . The middle most number in the sequence ? Options.
A) A  B) B  C) C  D) D  E) E

Solution: D _ C _ A --------(1)   D > B > C --------(2)   from (1) and (2)   D > B > C > A ---------(3)   Again E _ B _ A   But B > A, from (3)   So E > D > B > C > A [ Since B is the average of E and A so it is eqidistant from both E and A]   Answer: B
Answer: B
At what rate percent per annum will the simple interest on a sum of money be 4/5 of the amount in 10 years? Options
A) 4%
B) 7%
C) 8%
D) 3%
E) 1%

Solution: Let sum = x. Then, S.I. =4x/5, Time   = 10 years.   Rate = (100 * 4x) / (x * 5 * 10)   = 8%   Answer: 8%
Answer: C
Three pipes A,B and C are attached to a tank.A and B can fill it in 20 and 30 minutes respectively while C can empty it in 15 minutes.If A,B and C are kept open successively for 1 minute each, how soon will the tank be filled?	Choose the correct answer:
A) 165 min
B) 166 min
C) 167 min
D) 168 min
E) 169 min

Solution: the term successively and NOT SIMULTANEOUSLY.AT THE END OF 3 mts, i/60 part of the tank is filled.we have to consider a three-minute block starting from 3 mts, 6 mts,9 mts....etc upto 177 mts. at the end of 165 mts,55/60 part of the tank was filled. at the end of the next suceessive minutes,i.e, 166,167th minute, the part filled is 5/60.so 55/60+5/60. this means the whole tank is filled at the end of 167 th minute.   ANSWER:167 min
Answer: C
A certain club has exactly 5 new members at the end of its first week. Every subsequent week, each of the previous week's new members (and only these members) brings exactly L new members into the club. If y is the number of new members brought into the club during the twelfth week, which of the following could be y?	Choose the correct answer:
A) 5^1/12	B) 3^11 * 5^11	C) 3^12 * 5^12	D) 3^11 * 5^12	E) 60^12

Solution: At the end of the first week, there are 5 new members;   At the end of the second week, there are 5L new members (since each 5 new members from the previous week brings L new members);   At the end of the third week, there are 5L^2 new members (since each 5L new members from the previous week brings L new members);   ...   At the end of the twelfth week, there are 5L^11 new members (since each 5L^10 new members from the previous week brings L new members).   We are given that 5L^11=y. Out of the answers only D yields integer value for L: 5L^11=3^11 * 5^12 --> L=3*5= 
3*5 = 15
15.   Answer: 3^11 * 5^12.
Answer: D
a' and 'b' are positive integers such that their LCM is 20 and their HCF is 1. What is the addition between the maximum and minimum possible values of 'a - b'?  Choose the correct choice from the following answers.
A) 0  B) 12  C) 24  D) 26  E) 18

Solution: possible values of a and b can be 5,4; 4,5 and 1,20; 20,1   maximum possible value for a-b is   20-1= 
  20-1 = 19
19   minimum possible value for a-b is 1-20=-19   19-19= 
19-19 = 0
0 ans is 0
Answer: A
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train? Choose the correct choice from the following choices.
A) 28	B) 27	C) 299	D) 277	E) 150

Solution: Speed = 60 * 5/18 = 50/3 m/sec   Length of the train = speed * time = 50/3 * 9= 
50/3 * 9 = 150
150 m   Answer: 150
Answer: E
A book club rented the party room of a local restaurant to meet and discuss its current novel over dinner. The total charge, including food and service, was $ 950. If each member of the club paid at least $ 42, then what is the greatest possible number of members in the club?  Choose the correct choice.
A) 19 B) 20 C) 21 D) 25 E) 23

Solution: Given: Each person spends $42.   By looking at the options, we see that if there were 20 members, each person will spend atleast $42.   Hence the greatest number of members = 22.6. Option 23
Answer: E
Set B consists of the following unique integers: -2, 17, 3, n, 2, 15, -3, and -27; which of the following could be the median of set B?	Choose the correct choice from the following answers:
A) 6
B) 4
C) 1
D) 7
E) 76

Solution: Whenever a question asks you to deal with the MEDIAN of a group of numbers, you MUST put the numbers in order from least to greatest (or at the very least,group offthe numbers so that you can restrict the potential value of the median).   Here, we have 8 values (one of the values is the variable N). We're told that the values are UNIQUE, so N CANNOT be any of the other 7 values listed. We're asked which of the following answers COULD be the median, so if we determine that one of the answer choices is a POSSIBLE median, then we can stop working....   Since the group includes 8 values, the median will be the AVERAGE of the 4th and 5th values...   Putting the 7 numbers in order, we have:   -27, -3, -2, 2, 3, 15, 17   This means that the2will either be the 4th term or the 5th term (depending on the value of N).   IF....   N is REALLY BIG, then the 4th and 5th terms will be 2 and 3, so the median will = 2.5   N is REALLY SMALL, then the 4th and 5th terms will be -2 and 2, so the median will = 0   Neither of those answers is among the choices though, so N must be something relativelycloseto 2.....   IF....   N = 0, then the 4th and 5th terms will be 0 and 2, so the median will = 1. That answer IS among the choices, so we're done.   1
Answer: C
A baker filled with a measuring cup with a cup water. He poured 1/2 of the water into the batter, and then spilled 1/8 of the water on the floor. How much water will the baker needed to add what is left in the cup to have 50% more than what he started with?  Choose the correct choice from the following choices.
A) 1/8 cup	B) 3/8 cup	C) 1/4 cup	D) 1/2 cup	E) 9/8 cup

Solution: 3/4 is the original water in cup .half in batter.So left is 3/8 out which 1/8 is spilled out.So again left with 2/8.   so 50% more than what he started was = 8/8+1/2*(3/4)=11/8   Amount of water needed to add = 11/8 - 2/8=9/8   ANSW9/8 cupR:9/8 cup
Answer: E
One thief entered a cave where he found a pile of diamonds. At first he thought of taking all. But listening to his conscience he thought of taking only half of them. But while returning he picked up two more from the pile. After that Second thief entered the cave and bagged half of remaining diamonds and picked up two more while returning. Later third thief entered and did the same. Even the fourth thief did the same. When the fifth thief entered he found only one diamond in the cave. How many diamonds are there in the cave at first.	Choose the correct choice.
A) 74
B) 75
C) 76
D) 77
E) 78

Solution: When 5th thief entered-1 diamond   When 4th thief entered -(1+2)*2=6 diamonds   When 3rd thief entered -(6+2)*2=16 diamonds   When 2nd thief entered -(16+2)*2=36 diamonds   When 1st thief entered -(36+2)*2=76 diamonds   ANSWER:76
Answer: C
If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 8 m of the same rod?	Choose the correct choice:  A) 22.8 kg  B) 25.6 kg  C) 28 kg  D) 30.4 kg  E) None of these

Solution: Explanation :   Let the required weight be x kg. Then, Less length, Less weight (30.4 kgirect Proportion)   => 11.25 : 8 :: 42.75 : x   => 11.25 x x = 8 x 42.75   => x = (8 x 42.75) / 11.25   => x = 30.4   Answer : 30.4 kg
Answer: D
A set of 13 different integers has median of 25 and a range of 25. What is greatest possible integer that could be in this set?
Choose the most appropriate option.
A) 32 B) 37 C) 40 D) 43 E) 41

Solution: The correct answer is E.   A set of 13 different integers has median of 25 and a range of 25. What is greatest possible integer that could be in this set?   Given 15 different integers, lets say   n1, n2, n3, n4, n5, n6, n7, n8, n9, n10, n11, n12, n13, n14, n15   Also given median is 25 i.e. n8 = 25   n1, n2, n3, n4, n5, n6, n7, 25, n9, n10, n11, n12, n13, n14, n15   As each integer is different we need to find the maximum values for all those numbers before the median.   the maximum value n7 can have is one less then the median i.e. 24, similarly n6 will be one less than 24 i.e. 23 ... using this process the values for all number before the median would be..   18, 19, 20, 21, 22, 23, 24, 25, n9, n10, n11, n12, n13, n14, n15   Also given the range is 25 i.e. n15 - n1 (18) = 23   The maximum value n15 can have is 23+ n1 (18) = 41   41
Answer: E
Of the 10 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
Choose the correct choice from the following answers:
A) 22 B) 50 C) 56 D) 70 E) 105

Solution: another approach :   one scenario : [WWWM]   now we have 5 ways for the first women , 4 ways for the 2nd women and , 3 ways for the third women.   and 5 ways to select one man   so   5*4*3*5= 
  5*4*3*5 = 300
300   now the three women are same so combinations with win them are irrelevant the 3 women can we arranged in 3! ways   hence 300/3!= 300/6= 
300/6 = 50
50   50
Answer: B
I had a certain amount of candies with me. I gave half of them with one more to my first son. Then, I gave the remaining half with one more to the younger son. Now I was left with just one candy.
How much candies did I have in the beginning? Choose the correct choice from the following choices:
A) 10	B) 15	C) 22	D) 25	E) 12

Solution: A   I had 10 candies in the beginning.   Explanation:   Let us take and solve this problem in the reverse direction.   At the end, I was left with 1 candy. Let me take the extra one candy back from my younger son. Now since I gave him half of what I had, we must be having the same number of candies. I have 2, which means he also have 2. This implies that I was left with 4 candies after I gave some to the elder son.   Let me take back the extra candy from my elder son now. Now I have 5 candies. Since I gave him half of what I had, he must be having 5 candies as well. Thus, I had 10 candies in the beginning.
Answer: A
Two employees X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? Select the correct option:	A) Rs.250	B) Rs.280	C) Rs.290	D) Rs.299	E) Rs.300

Solution: Let the amount paid to X per week = x   and the amount paid to Y per week = y   Then x + y = 550   But x = 120% of y = 120y/100 = 12y/10   ∴12y/10 + y = 550   ⇒ y[12/10 + 1] = 550   ⇒ 22y/10 = 550   ⇒ 22y = 5500   ⇒ y = 5500/22 = 500/2 = Rs.250   Rs.250
Answer: A
Three numbers are in the ratio 3:4:5 and their L.C.M. is 1800. Their H.C.F is? Pick
A) 20	B) 30	C) 40	D) 50	E) 60

Solution: Let the numbers be 3x,4x and 5x   their L.C.M. = 60x   60x = 1800   x = 30   The numbers are 3*30 , 4*30 , 5*30   Hence required H.C.F. = 30   Answer is 30
Answer: B
There are some pigeons and hares in a zoo. If heads are counted, there are 200. If legs are counted, there are 880. The number of hares in the zoo is? Choose the correct choice:
A) 90
B) 99
C) 77
D) 66
E) 240

Solution: 200*2= 
200*2 = 400
400   880   -----   480   1----2   ?----480= 240   Answer:240
Answer: E
A and B complete a work in 3 days. A alone can do it in 9 days. If both together can do the work in how many days? Select.
A) 3.75 days	B) 4.75 days	C) 3.25 days	D) 3.15 days	E) 2.75 days

Solution: 1/3 + 1/9 = 4/9   9/4 = 4.75 days   Answer: 4.75 days
Answer: B
There are 11 cans in the refrigerator. 6 of them are red and 5 of them are blue. In how many ways we can remove 8 cans so that at least one red and at least one blue cans to remain the refrigerator.	Select
A) 460  B) 490  C) 493  D) 455  E) 445

Solution: Answer: 445
Answer: E
What is the probability, to 3 decimal places, that at least two people in a room share the same birthday if there are eleven people in the room? (Assume nobody was born on a leap year)
Answers:
A) 0.027 B) 0.03 C) 0.076 D) 0.141 E) 0.271

Solution: First, find the probability that nobody has the same birthday: 364/365 * 363/365 * 362/365 * ... * 356/365 * 355/365 = 0.859. Then the correct answer is  1 - 0.859= 
 1 - 0.859 = 0.141
0.141, so the correct answer is 0.141
Answer: D
The average of first 10 natural numbers is?  Select:
A) 5.7
B) 5.5
C) 5.4
D) 5.2
E) 5.9

Solution: Sum of 10 natural no. = 110/2= 
110/2 = 55
55   Average= 55/10= 
55/10 = 11/2 = around 5.5
5.5   Answer: 5.5
Answer: B
A farmer is planting a row consisting of 4 unique apple trees and 5 unique orange trees. How many ways are there for the farmer to plant the trees such that no apple tree is adjacent to another apple tree and no orange tree is adjacent to another orange tree? Choose the correct option:
A) 512
B) 5760
C) 1,024
D) 1,152
E) 10,080

Solution: 2 possible arrangements are possible   AOAOAOAO   OAOAOAOA   2 unique type of trees are present consisting of 4 trees each   4 apple trees can be arranged in 4! ways   4 orange trees can be arranged in 4! ways   as 2 arrangements are possible   total arrangements = 2 *4! * 5! = 5760   correct answer option 5760
Answer: B
A tap can fill a tank in 6 hours. After half the tank is filled three more similar taps are opened. What is the total time taken to fill the tank completely?  Choose the correct answer.
A) 3 hrs 48 min B) 3 hrs 45 min C) 3 hrs 85 min D) 3 hrs 75 min E) 3 hrs 25 min

Solution: Time taken by one tap to fill the tank = 3 hrs.   Part filled by the taps in 1 hour = 4 * 1/6 = 2/3   Remaining part = 1 - 1/2 = 1/2   2/3 : 1/2 :: 1 : x   x = 1/2 * 1 * 3/2 = 3/4 hrs. i.e., 45 min   So, total time taken = 3 hrs 45 min.   Answer: 3 hrs 45 min
Answer: B
A man can row 7 ½ kmph in still water.if in a river running at 1.5 km/hr an hour,it takes him 50 minutes to row to a place and back,how far off is the place?	Pick:
A) 1.5 km  B) 1 km  C) 2.5km  D) 2 km  E) 3 km

Solution: Speed downstream =(7.5+1.5)km/hr=9 km/hr;   Speed upstream=(7.5-1.5)= 
(7.5-1.5) = 6
6kmph.   Let the required distance be x km.then,   x/9+x/6=50/60.   2x+3x=(5/6*18)   5x=15   x=3.   Hence,the required distance is 3km.   Answer is 3 km.
Answer: E
In an election between two candidates, the winner has a margin of 10% of the votes polled. If 4000 people change their mind and vote for the loser, the loser would have won by a margin of 10% of the votes polled. Find the total number of votes polled in the election?	Select the correct option.
A) 16000
B) 10000
C) 40000
D) 12000
E) 5000

Solution: Winner - Looser   55% - 45%   If 4000 people change their mind and vote for the loser:   Winner - Looser   45% - 55%   Thus 4,000 people compose 25% of all voters, which means that the total number of votes is   40,000   Answer: 40000
Answer: C
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 48 years now, the son's age five years back was:  Select:	A) A)14	B) B)67	C) C)19	D) D)89	E) E)34

Solution: Let the son's present age be x years. Then, (48 - x) = x   2x = 48.   x = 24.   Son's age 5 years back (24 - 5)= 
(24 - 5) = 19
19 years.   Answer:19
Answer: C
What is the probability for a family with four children to have a girl and three boys (assuming the probability of having a boy or a girl is equal)?	Select
A) 1/2  B) 1/3  C) 1/4  D) 1/8  E) 1/16

Solution: One possible case is: girl - boy - boy - boy   The probability of this is 1/2*1/2*1/2*1/2 = 1/16   There are 4C3 = 4 such cases so we should multiply by 4.   P(one girl and three boys) = 4/16 = 1/4   The answer is 1/4.
Answer: C
Tom opened a shop investing Rs.3000. Jose joined him 2 months later, investing Rs.4000. They earned a profit of Rs.4230 after completion of one year. What will be Jose's share of profit? Choose the correct answer:
A) 2000 B) 2200 C) 2309 D) 2350 E) 3250

Solution: SoL = ~s- So Anju’s share = [5/9] x 4230 = 2350   2350
Answer: D
Working alone, Printers X, Y, and Z can do a certain printing job, consisting of a large number of pages, in 12, 40, and 50 hours, respectively. What is the ratio of the time it takes Printer X to do the job, working alone at its rate, to the time it takes Printers Y and Z to do the job, working together at their individual rates? Select the correct option.
A) 4/11 B) 1/2 C) 15/22 D) 200/9 E) 11/4

Solution: P1 takes 12 hrs   Rate for P2P3 together = 1/40 + 1/50 = 9/200   Therefore they take 200/9   Ratio = 200/9 = 200/9
Answer: D
If X is to be chosen at random from the integers between 1 to 7, inclusive, and Y is to be chosen at random from the integers between 8 and 12, inclusive, what is the probability that X + Y will be even?	Choose the correct choice from the following answers:
A) 2/5  B) 3/7  C) 5/7  D) 17/35  E) 24/35

Solution: X+Y will be even if X and Y are both even or both odd.   P(X and Y are both even) = 3/7*3/5 = 9/35   P(X and Y are both odd) = 4/7*2/5 = 8/35   P(X+Y is even) = 9/35 + 8/35 = 17/35   The answer is 17/35.
Answer: D
A, B and C can do a piece of work in 24 days, 30 days and 40 days respectively. They began the work together but C left 4 days before the completion of the work. In how many days was the work completed? Choose one:
A) 33 B) 77 C) 66 D) 11 E) 99

Solution: One day work of A, B and C = 1/24 + 1/30 + 1/40 = 1/10 Work done by A and B together in the last 4 days = 4*(1/24 + 1/30) = 3/10   Remaining work = 7/10   The number of days required for this initial work = 7 days.   The total number of days required = 4 + 7= 
4 + 7 = 11
11 days.   Answer:11
Answer: D
A reduction of 30% in the price of oil enables a house wife to obtain 5kgs more for Rs.800, what is the reduced price for kg? Answers
A) 46	B) 47	C) 48	D) 49	E) 50

Solution: 800*(30/100)= 
800*(30/100) = 240
240 ---- 5   ? ---- 1=> Rs.48   Answer: 48
Answer: C
The number of positive integer solutions for the equation x +y +z + t = 30 is  Choices:
A) 3854	B) 3654	C) 3764	D) 3960	E) 4964

Solution: The number of positive integer solutions for the equatio fx1+x2+⋯+xn=k   (k-1)C(n-1)- where k is the number and n is number of variable in the equation.   30-1 C 4-1 = 29C3 = 3654   Answer : 3654
Answer: B
Michael cashed a check for $1,100 and received only $10 and $50 bills in return. During the course of a day, he used 15 bills and then lost the rest of the money. If the number of $10 bills used was either one more or one less than the number of $50 bills used, what is the minimum possible amount of money that was lost?
Choose the correct choice from the following:
A) $630
B) $800
C) $770
D) $730
E) $700

Solution: 1. 15 bills spent   2. Number of $10 bills is one more or one less than number of $50 bills.   So, 2 choices   1. 7*10 + 8*50 = $470   2. 8*10 + 7*50 = $430   Least money lost implies most money spent. i.e $470   Therefore, lost money = 1100 - 470= 
1100 - 470 = 630
630.   $630nswer $630
Answer: A