MU-NLPC/Calc-aqua_rat huggingface dataset:
A paint crew gets a rush order to paint 80 houses in a new development. They paint the first y houses at a rate of x houses per week. Realizing that they'll be late at this rate, they bring in some more painters and paint the rest of the houses at the rate of 1.25x houses per week. The total time R it takes them to paint all the houses under this scenario is what fraction of the time it would have taken if they had painted all the houses at their original rate of x houses per week?	Choose the correct choice.
A) 0.8(80 – y)
B) 0.8 + 0.0025y
C) 80/y – 1.25
D) 80/1.25y
E) 80 – 0.25y

Solution: This may be a case of bad numberpicking but it worked for me.   80 houses. Let's say that y=40 houses are painted at the rate x=10 houses per week <=> 1/10 week per house. 40*1/10 = 4 houses per week will be painted at this rate.   80-y = 80-40= 
80-40 = 40
40 houses are to be painted at the faster rate. X*1,25=12,5 houses per week <=> 1/12,5 weeks per house * 40 houses = 40/12,5 = 80/25 = 320/100 = 3,2 weeks.   Which means finishing all houses at normal rate R=> 2*4= 
2*4 = 8
8 weeks. Faster rate= 4+3,2 = 7,2 weeks.   7,2/8 = 9/10 = 0,9. Insert y=40 in equations and it is clear that only (0.8 + 0.0025y) gives us 0,9.
Answer: B
there is park of length 100 m and width 80m.there is path in middle of park across the length and breadth crossing each other.the breadth of path 3m.what % of park used for path?  Choose the correct choice from the following options
A) 5.53	B) 6.63	C) 4.43	D) 8.61	E) 5.81

Solution: area of park=100*80= 
100*80 = 8_000
8000m2.   area of path=100*3+80*3-3*3=300+240-9=540-9= 
540-9 = 531
531m2.   %of path=531/8000*100= 
531/8000*100 = 531/80 = around 6.6375
6.6375%   answer 6.63
Answer: B
Tina and Rebecca had the same number of candies. Tina gave Rebecca 20 candies so that now Rebecca has five times as many candies as Tina has. Rebecca has now how many candies initially?	Choose the correct choice.
A) 36  B) 48  C) 50  D) 55  E) 60

Solution: T = R   T - 24 ;R + 24   R + 24 = 5 ( T - 24 )   R + 24 =5T - 120   R - 5T = - 144   We knowR = T, so   R - 5T = - 144   Or, R - 5R = -144   Or, - 4R = - 144   Or, R = 36( This is the initital no of Candies Rebecca had)   36nswer will be (36) 36
Answer: A
One fast typist type some matter in 4hrs and another slow typist type the same matter in 6hrs. If both do combine in how much time they will take to finish.	Choose the most appropriate option
A) 10 hr
B) 1 hr
C) 2 hr 24 mins
D) 3 hr 4 mins
E) 4 hr 10 mins

Solution: Fast's 1 hr work = 1/4   slow's 1 hr work = 1/6   1/4 + 1/6 = 5/12   they ll finish in 12/5hrs= 2 2/5 ==> 2 hr 24 mins   ANSWER:2 hr 24 mins
Answer: C
Rs.4500 amounts to Rs.5544 in two years at compound interest, compounded annually. If the rate of the interest for the first year is 12%, find the rate of interest for the second year? Choose one:  A) 5544  B) 2288  C) 6776  D) 1877  E) 1981

Solution: Let the rate of interest during the second year be R%. Given,   4500 * {(100 + 12)/100} * {(100 + R)/100} = 5544   R = 10%   5544nswer:5544
Answer: A
Current ages of Rahim and Thomas are in the ratio of 5 : 4 correspondingly. 0.5 decades hence, the ratio of their ages will become 11 : 9 correspondingly, What is Thomasâ€™s current age in years? Choose the correct choice from the following:
A) 24 years
B) 44 years
C) 34 years
D) 40 years
E) 84 years

Solution: 40 years   If current ages of Rahim and Thomas be 5A years and 4A years correspondingly   Then, 5A + 5 = 11   4A + 5 = 9   9(5A + 5)4  + 5= 
4  + 5 = 9
9   9(5A + 5)=11(4A + 5)   A = 10   Thomasâ€™s current age = 4A   = 40 years.   40 years
Answer: D
120 candies are distributed to children with the same number of candies for each child. What can’t be the range which includes the number of children? Answers:
A) 1~10
B) 10~20
C) 20~30
D) 45~55
E) 55~65

Solution: 120 = 2^3*3*5   There are factors in each range except for 45~55   The answer is 45~55.
Answer: D
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?
Choose the correct choice
A) 30 minutes	B) 45 minutes	C) 1 hour	D) 1 hour 15 min	E) None

Solution: Sol.   Rate downstream = [16/2= 
16/2 = 8
8 kmph; Rate upstream= [16/4= 
16/4 = 4
4 kmph.   ∴ Speed in still water= 1/2(8+4) kmph = 6 kmph.   Answer 1 hour 15 min
Answer: D
The length of the bridge, which a train 130 m long and traveling at 45 km/hr can cross in 30 sec is?
Choose the correct choice from the following choices.
A) 249
B) 247
C) 245
D) 2882
E) 212

Solution: Speed = 45 * 5/18 = 25/2 m/sec.   Time = 30 sec   Let the length of bridge be x meters.   Then, (130 + x)/30 = 25/2   x = 245 m.   Answer: 245
Answer: C
I. a2 - 7a + 12 = 0,
II. b2 - 3b + 2 = 0 to solve both the equations to find the values of a and b?
Choose one:	A) if a < b	B) if a ≤ b	C) if the relationship between a and b cannot be established	D) if a > b	E) if a ≥ b

Solution: I.(a - 3)(a - 4) = 0   => a = 3, 4   II. (b - 2)(b - 1) = 0   => b = 1, 2   => a > b   ANSWER:if a > b
Answer: D
Martha has the unique talent of being able to guess other people’s height and weight. For every three people that Martha meets, she consistently guesses the people’s correct height two times, and for every seven people that she meets, she consistently guesses the people’s correct weight five times. If Martha meets three people and her success rate remains constant, what is the probability that Martha correctly guesses a person’s weight and height at least once?
Choose the correct answer.
A) 8/27	B) 2/5	C) 49/81	D) 98/125	E) 7930/9261

Solution: Probability that she guesses the height correctly P(h)=2/3   Probability that she guesses the weight correctlyP(w)=5/7   Probability that she guesses both weight and height correctly(P(h)*P(w))=2/3 * 5/7= 10/21   Now the Q asks about the probability of this happening atleast once.   We calculate it by finding the probability of not being able to guess in any of the three occasions.   Probability of not being able to guess any no. of times =1-10/21=11/21   For all three occasions P(A)=11/21 * 11/21 * 11/21=1331/9261   Probability of the event happening atleast once=1- P(A)=1-1331/9261=7930/9261   Ans should be 7930/9261
Answer: E
If 9 men working 6 hours a day can do a work in 88 days. Then 6 men working 8 hours a day can do it in how many days?	Pick one
A) 78 days. B) 99 days. C) 49 days. D) 48 days. E) 67 days.

Solution: B   99 days.   From the above formula i.e (m1*t1/w1) = (m2*t2/w2)   so (9*6*88/1) = (6*8*d/1)   on solving, d = 99 days.
Answer: B
The moon revolves around the earth at a speed of approximately 1.04 kilometers per second. This approximate speed is how many kilometers per hour?	Choose one.
A) 60
B) 61.2
C) 3,744
D) 3,600
E) 3,672

Solution: moon revolves around the earth at a speed of 1.02kilometers per second.   one hour equal to 60 minutes.   one minute equals to 60 seconds. so one hour equals to 3600seconds.   so one hour, speed= 1.04*3600= 
1.04*3600 = 3_744
3744kilometers per hour.   Option 3,744 is correct
Answer: C
By selling an article at $800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?	Choose the correct choice from the following answers.
A) $580
B) $450
C) $480
D) $400
E) $440

Solution: $480   $480   SP = 800   Profit = 25%   $480P = (SP)*[100/(100+P)]   = 800 * [100/125]   = 640   Loss 800 *  100/125= 
800 *  100/125 = 640
640   Loss= 25% = 25% of 640 = $160   SP = $480P - Loss = 640 - 160= 
640 - 160 = 480
$480
Answer: C
A train 300 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is? Choose one
A) 298 m	B) 279 m	C) 500 m	D) 289 m	E) 1000 m

Solution: Speed = 78 * 5/18 = 65/3 m/sec.   Time = 1 min = 60 sec.   Let the length of the train be x meters.   Then, (300 + x)/60 = 65/3   x = 1000 m.   Answer: 1000 m
Answer: E
In the Bargaining Bazar everyone purchase with a fair bargaining, so the traders markup the prices too much. A trader marked up an article at Rs. M expected huge profit if it is sold on marked price. But a customer purchased it at M/2 with his fine bargaining skills, so the expected profit of the trader diminished by 66.66%. What is the percentage discount fetched by the customer through bargaining?	Choose the correct choice:
A) 33.33%
B) 50%
C) 60%
D) 66.66%
E) None of these

Solution: Solution: MP = M   SP = M/2   % Discount = [(M/2) /M] *100 = 50%.   Answer: Option 50%
Answer: B
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B? Choices.
A) 8
B) 9
C) 10
D) 11
E) 12

Solution: Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.   (2x + 2) + 2x + x = 27   5x = 25   x = 5.   Hence, B's age = 2x = 10 years.   ANSWER 10
Answer: C
When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 39, what is the remainder when k is divided by 7?
Choose the correct choice:
A) 4  B) 5  C) 6  D) 3  E) 7

Solution: Cant think of a straight approach but here is how I solved it:   K is divided by 5 and remainder is 2. This means k = 5n + 2 (n is an integer)   so the possible values of K = {2, 7, 12, 17, 22, 27, 32, 37} (less than 39)   Secondly, if K is divided by 6, the remainder is 5 => k= 6m + 5   so the possible value set for k = {5, 11, 17, 23, 29,35} (less than 39)   17 is the only common number in both the sets. Hence k = 17   Answer : 3
Answer: D
The sum of three consecutive multiples of 3 is 72. What is the larget number?  Pick:
A) 26  B) 27  C) 46  D) 57  E) None

Solution: Sol.   Let the numbers be 3x, 3x + 3 and 3x + 6.   Then, 3x + (3x + 3) + (3x + 6) = 72 ⇔ 9x = 63 ⇔ x = 7.   ∴ Largest number = 3x +6 = 27.   Answer 27
Answer: B
For how many integers pair (x,y) satisfies the result
(1/x)+((1/y)=1/12  Select the correct option:
A) 12 B) 6 C) 29 D) 16 E) 32

Solution: Now let’s look at this question from the perspective of number theory.   1/x + 1/y = 1/12   12x + 12y = xy   12x + 12y – xy =0   We need to factorize it and for that we subtract 144 from left and right parts.   12x – xy +12y – 144 = -144   (x-12)(12-y) = -144   (x-12)(y-12) = 144   Now we need to represent 144 as a product of 2 factors and find out our pairs of x and y.   (1*144) (2*72) (3*48) (4*36) (6*24) (8*18) (9*19) and 12*12.   All factor pairs (except 12*12) can be written in reverse order, so we have total 15 positive solutions.   Because we have product, x and y can also take negative values. Using same logic we got 15 negative solutions, but in this case we need to discard (-12)*(-12), because it will give us x=0, y=0. In this point the original equation is undetermined (we can’t divide by zero).   Hence we have total number of integer pairs   15 + 14= 
  15 + 14 = 29
29   ANSWER:29
Answer: C
The function f is defined for all positive integers s by the following rule. f(s) is the number of positive integers each of which is less than s and has no positive factor in common with s other than 1. If t is any prime, number then f(t)=	Choose the correct choice from the following answers:
A) (t-1)/2
B) t-2
C) (t+1)/2
D) t-1
E) 2

Solution: If not the wording the question wouldn't be as tough as it is now. The GMAT often hides some simple concept in complicated way of delivering it.   This question for instance basically asks: how many positive integers are less than given prime number t which have no common factor with t except 1.   Well as t is a prime, all positive numbers less than t have no common factors with t (except common factor 1). So there would be t-1 such numbers (as we are looking number of integers less than t).   For example: if t=5 how many numbers are less than t having no common factors with 5: 1, 2, 3, 4, 5,--> 5-1=4.   Answer: t-1.
Answer: D
here are 6 periods in each working day of a school. In how many ways can one organize 5 subjects such that each subject is allowed at least one period? Options:
A) 2300 B) 4500 C) 1200 D) 5200 E) 1800

Solution: 5 subjects can be arranged in 6 periods in 6P5 ways.   Any of the 5 subjects can be organized in the remaining period (5C1 ways).   Two subjects are alike in each of the arrangement. So we need to divide by 2! to avoid overcounting.   Total number of arrangements   = 6P5× 5C1 /2!=1800   Ans: 1800
Answer: E
If the LCM of 8, 11, 15, and x is 25080, which of the following
could be x?	Choices
A) 12 B) 16 C) 13 D) 18 E) 19

Solution: Using elimination method, eliminate the option to arrive at 19   if x is replaced by 19 and the LCM is calculated you arrive at 25080   19
Answer: E
In a class, the average age of 28 boys is 12 years and the average of 20 girls is 8 years. what is the average age of the whole class?	Choose the most appropriate option
A) 10.3 Years	B) 12.3 Years	C) 12.6 Years	D) 13 Years	E) 15 Years

Solution: Total age of 48 students   (28X 12+20 X 8) = 496   10.3 Yearsverage = 496/48 = 10.3 Years   10.3 Years
Answer: A
A box contains 3 blue marbles, 4 red, 6 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either blue or yellow? Choose one:  A) 2/22  B) 2/20  C) 2/21  D) 2/23  E) 2/29

Solution: Given that there are three blue marbles, four red marbles, six green marbles and two yellow marbles. Probability that both marbles are blue = (3 * 2)/(15 * 14) = 1/35   Probability that both are yellow = (2 * 1)/(15 * 14) = 1/105   Probability that one blue and other is yellow = (2 * 3 * 2)/(15 * 14) = 2/35   Required probability = 1/35 + 1/105 + 2/35   = 3/35 + 1/105 = 1/35(3 + 1/3)   = 10/(3 * 35) = 2/21   Answer:2/21
Answer: C
if the selling price of an object is rs.2300 and the profit percent is 15,what is the cost price?	Choose the correct choice:
A) 1995  B) 1945  C) 2000  D) 2645  E) 2745

Solution: cp=Sp/1.15=2300/1.15= 
2300/1.15 = 2_000
2000   ANSWER:2000
Answer: C
A’s speed is 20/15 times that of B. If A and B run a race, what part of the length of the race should A give B as a head start, so that the race ends in a dead heat?	Choose the correct choice from the following choices: A) 1/17 B) 3/17 C) 1/10 D) 5/20 E) 3/10

Solution: We have the ratio of A’s speed and B’s speed. This means, we know how much distance A covers compared with B in the same time.   This is what the beginning of the race will look like:   (Start) A_________B______________________________   If A covers 20 meters, B covers 15 meters in that time. So if the race is 20 meters long, when A reaches the finish line, B would be 5 meters behind him. If we want the race to end in a dead heat, we want B to be at the finish line too at the same time. This means B should get a head start of 5 meters so that he doesn’t need to cover that. In that case, the time required by A (to cover 20 meters) would be the same as the time required by B (to cover 15 meters) to reach the finish line.   So B should get a head start of 5/20th of the race.   Answer (5/20)
Answer: D
Lucy invested $10,000 in a new mutual fund account exactly three years ago. The value of the account increased by 10 percent during the first year, increased by 5 percent during the second year, and decreased by 10 percent during the third year. What is the value of the account today? Select the correct option: A) $10,350 B) $10,395 C) $10,500 D) $11,500 E) $12,705

Solution: Value after 1 year: 10,000 * 1.1 = 11,000   Value after 2 years: 11,000 * 1.05 = 11,550   Value today: 11,550 * 0.9 = 10,395   Answer $10,395 is correct.
Answer: B
The age of Somu is one-third his father's. 9 years back he was one-fifth of his father's age. What is his persent age ? Pick one
A) 11	B) 18	C) 14	D) 12	E) 10

Solution: Explanation :   Let Somu's age be x and that of his father be 3x.   So, x - 9 = 3x - 9/5 = x = 18   Answer : Option 18
Answer: B
In an examination it is necessary for a candidate to get 45 % of the maximum marks to pass. A candidate who gets 180 marks, fails by 45 marks. Find the maximum marks.
Select.
A) 450 B) 600 C) 500 D) 550 E) 650

Solution: Let max . mark = x   pass mark =45x/100   180 = 45x/100-45   x = 180*100-4500/45 =500   ANSWER:500
Answer: C
In a kickball competition of 5 teams, how many possible matches can each team play with each other?	Select:  A) 10  B) 16  C) 24  D) 36  E) 54

Solution: 5C2 = 10   Option 10
Answer: A
Find the missing in the series: 70, 54, 45, 41,___
Choose the correct choice.
A) 22
B) 287
C) 2679
D) 2767
E) 2771

Solution: Answer:287
Answer: B
Tough and Tricky questions: Word Problems.
In a rare coin collection, one in six coins is gold, and all coins are either gold or silver. If 10 silver coins were to be subsequently traded for an additional 10 gold coins, the ratio of gold coins to silver coins would be 1 to 2. Based on this information, how many gold coins would there be in this collection after the proposed trade?	Pick one.
A) 50 B) 60 C) 180 D) 200 E) 300

Solution: The correct answer is 300.
Answer: E
If x and y are even integers, which of the following is an odd integer? Choices
A) x+y+1
B) x+y
C) x-y
D) xy
E) x * y^2

Solution: even + odd = odd   even + even = even   even - even = even   even * even = even   x+y+1nswer : x+y+1
Answer: A
In a simultaneous throw of pair of dice .find the probability of getting the total more than 7?  Options:  A) 12/5  B) 5/12  C) 6/4  D) 2/3  E) 4/7

Solution: Here n(S)=(6*6)= 
(6*6) = 36
36   let E=event of getting a total more than 7   ={(2,6),(3,5),(3,6),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)}   P(E)=n(E)/n(S)=15/36=5/12   Option 5/12
Answer: B
A shopkeeper sells 400 metres of cloth for $18000 at a loss of Rs.5 per metre. Find his cost price for one metre of cloth? Choose the correct choice from the following answers.
A) $20
B) $43
C) $50
D) $70
E) $40

Solution: $50   $50   SP per metre = 18000/400= 
18000/400 = 45
$45 Loss per metre= $5 $50P per metre = 45 + 5= 
45 + 5 = 50
$50
Answer: C
Calculate the different number of ways 2 boys and 1 girls can sit on a bench?
Choose the correct choice from the following:  A) 6  B) 4  C) 5  D) 3  E) 2

Solution: npn = n!   3p3 = 3 × 2 × 1 = 6   6
Answer: A
Mr Sridharan invested money in two schemes A and B,offering compound interest @ 8 p.c.p.a. and 9 p.c.p.a.respectively. If the total amount of interest accured through the two schemes together in two years was 4818.30 and the total amount invested was 27,000, what was the amount invested in Scheme A?	Choose the correct choice from the following choices.
A) 15,000
B) 13,500
C) 12,000
D) Cannot be determined
E) None of these

Solution: Let, in scheme A, Sridharan invest x.   Then, his investment in scheme B = (27000 – x).   Now,   x(1+8100)2+(2700−x)(1+9100)2   – 27000 = 4818.30   or, x(1.08)2 + (27000 – x)(1.09)2 = 31818.30   or, 1.1664x + 32078.7 – 1.1881x = 31818.30   or, 0.0217x = 260.4   or, x = 260.4⁄0.0217 = 12000   Answer 12,000
Answer: C
A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 800 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?  Choose the correct choice: A) 2880. B) 4860. C) 5780. D) 5760. E) 6380.

Solution: 1 windmill:   Normal 5760.ay = 800 kw/h   Stormy 5760.ay = 800*1.2= 
800*1.2 = 960
960 kw/h   3 windmills for 2 hours on stormy day     960*3*2= 
  960*3*2 = 5_760
5760   Answer: 5760.
Answer: D
For positive integers n, the integer part of the nth term of sequence C equals n, while the infinite decimal part of the nth term is constructed in order out of the consecutive positive multiples of n, beginning with 2n. For instance, C_1 = 1.2345678…, while C_2 = 2.4681012… The sum of the first seven terms of sequence C is between: Options.
A) 28 and 29 B) 29 and 30 C) 30 and 31 D) 31 and 32 E) 32 and 33

Solution: First, construct the first seven terms, though only out to a few decimal places, following the given pattern.   C_1 = 1.23…   C_2 = 2.46…   C_3 = 3.69…   C_4 = 4.812…   C_5 = 5.10…   C_6 = 6.12…   C_7 = 7.14…   Now, to add up the first seven terms, you should be strategic about how many decimal places to keep. You can drop the hundredths place and get a good approximation with the tenths place—and if you find the sum too close to a boundary between choices, then you can refine your answer if necessary.   1.2 + 2.4 + 3.6 + 4.8 + 5.1 + 6.1 + 7.1= 
1.2 + 2.4 + 3.6 + 4.8 + 5.1 + 6.1 + 7.1 = 30.3
30.3   Including more decimal places would only add a couple of tenths to the sum—not enough to tip the sum over 31.   The correct answer is 30 and 31.
Answer: C
Annie and Sam set out together on bicycles traveling at 15 and 12 km per hour respectively. After 40 minutes, Annie stops to fix a flat tire. If it takes Annie 30 minutes to fix the flat tire and Sam continues to ride during this time, how many minutes will it take Annie to catch up with Sam assuming that Annie resumes riding at 15 km per hour?
Select:
A) 20 B) 40 C) 60 D) 80 E) 100

Solution: Annie gains 3 km per hour (or 1 km every 20 minutes) on Sam.   After 40 minutes Annie is 2 km ahead.   Sam rides 1 km every 5 minutes.   In the next 30 minutes, Sam rides 6 km so Sam will be 4 km ahead.   It will take Annie 80 minutes to catch Sam.   The answer is 80.
Answer: D
Twenty percent of Country Y's yearly exports come from fruit exports. One-fourth of all fruit exports from Country Y are orange exports. If country Y generates $40 million from its orange exports, how much money does it generate from its yearly total of exports?
Select:
A) $21.25m  B) $800m  C) $106.25m  D) $127.5m  E) $153m

Solution: 20/100*1/4*(total) = 40   1/20*(total) = 40   (total) = 40*20= 
40*20 = 800
800   Answer: $800m
Answer: B
P alone can complete a job in 4 days. The work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together?  Choose the correct choice from the following answers:
A) 1.5 B) 2.0 C) 2.5 D) 3.0 E) 3.5

Solution: P's rate is 1/4   Q's rate is 1/12   The combined rate is 1/4 + 1/12 = 1/3   If they work together, the job will take 3 days.   The answer is 3.0.
Answer: D
A man can do a piece of work in 5days, but with the help of his son, he can finish it in 2days. In what time can the son do it alone? Choose the correct choice from the following choices
A) 3 1/3 B) 5 1/2 C) 7 1/2 D) 6 E) 9 1/2

Solution: Son's 1day work = 1/2 - 1/5 = 3/10   Son alone can do the work in 10/3days = 3 1/3 days   3 1/3nswer is 3 1/3
Answer: A
A computer manufacturer produces a certain electronic component at a cost of $80 per component. Shipping costs for delivering the components are $3 per unit. Further, the manufacturer has costs of $16,500 a month related to the electronic component regardless of how many it produces. If the manufacturer produces and sells 150 components a month, what is the lowest price it can sell them for such that the costs don't exceed the revenues? Choose one:
A) $193  B) $82  C) $110  D) $138  E) $192

Solution: This question can be solved easily using a equation model.   150*p = 16500(fixed cost) + 150*80+150*3.   = 16500+ 12000+ 450   P = 193   $193
Answer: A
If a 3-member subcommittee is to be formed from a certain 8-member committee, how many different such subcommittee are possible? Choose the correct choice.
A) 6 B) 18 C) 56 D) 108 E) 216

Solution: 1st member can be selected in 8 ways   2nd can be selected in 7 ways   3rd can be selected in 6 ways   So total ways : 336   But to avoid the similar scenarios 336/3!=56   ANS:56
Answer: C
Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 7 days?  Choose the correct choice.
A) 2/5 B) 7/18 C) 1/4 D) 1/9 E) 2/6

Solution: A's one day's work = 1/30   B's one day's work = 1/45   (A + B)'s one day's work = 1/30 + 1/45 = 1/18   The part of the work completed in 7 days = 7 (1/18) = 7/18.   ANSWER 7/18
Answer: B
The sum of digits of a two digit number is 11,The difference between the digits is 5. Find the number  Pick one:	A) 85	B) 94	C) 83	D) 72	E) None

Solution: Description :   => x+y=11, x-y=5   Adding these 2x =16   => x=8, y=3.   Thus the number is 83   Answer 83
Answer: C