MU-NLPC/Calc-aqua_rat huggingface dataset:
During a car trip, Maria stopped to rest after she traveled 1/2 of the total distance to her destination. she stopped again after she traveled 1/4 of the distance remaining between her first stop and her destination, and then she drove the remaining 150 miles to her detination. What was the total distance, in miles from Maria's starting point to her destination? Select the correct option
A) 280 B) 320 C) 360 D) 400 E) 480

Solution: Easy 400 is the answer.   3/4 ( x/2) = 150   x = 150 * 8 /3= 
150 * 8 /3 = 400
400.   Answer 400
Answer: D
There is a 30% increase in the price of an article in the first year, a 20% decrease in the second year and a 10% increase in the next year. If the final price of the article is Rs.4576 , then what was the price of the article initially?  Choose the correct answer.
A) Rs.5000	B) Rs.3000	C) Rs.4000	D) Rs.2000	E) Rs.6000

Solution: Let the price of the article, four years age be Rs. 100 in the 1st year, price of the article = 100 + 30 = Rs. 130. In the 2nd year, price = 130 - 20% of 130 = 130 - 26 = Rs. 104.   In the 3rd year, price = 104 + 10% of 104 = 104 + 10.4 = Rs. 114.40.   But present price of the article is Rs. 4576   for 114.4 ---> 100 ; 4576 ---> ?   Required price = (4576 * 100)/114.4 = 40 * 100 = Rs.4000.   Answer:Rs.4000
Answer: C
At the Boonsoft Museum, 1 out of every 3 paintings are abstract. If 1 out of every 4 abstract paintings are by Van Heymoe, and there are 20 paintings by Van Heymoe in the museum, how many paintings total are there in the museum?  Select.
A) 40
B) 250
C) 240
D) 300
E) 350

Solution: Proportions: Let P = hats, and Pa = abstract paintings, and Pav = abstract paintings by Van Heymoe.   20Pav/xPa = 1Pav/4Pa   xPa = 80Pa   80Pa/yP = 1Pa/3P   yP = 240P   Answer: 240
Answer: C
If a certain sample of data has a mean of 11.0 and the value 20.0 is more than 2.5 standard deviations from the mean, which of the following could be the standard deviation of the sample
Choose the correct choice from the following options
A) 14.75 B) 3.55 C) 4.25 D) 4.0 E) 2.75

Solution: 20.0 is more than 2.5 standard deviations from 11 --> 20 > 11 + 2.5*{SD} --> 2.5*{SD} < 9 --> {SD} < 3.6. Only option B offers the standard deviation less than 3.6.   Answer: 3.55
Answer: B
A man buys 10 lts of liquid which contains 20% of the liquid and the rest is water. He then mixes it with 15 lts of another mixture with 30% of liquid. What is the % of water in the new mixture?	Choose the most appropriate option:	A) 74	B) 84	C) 94	D) 49	E) 47

Solution: 20% in 10 lts is 2. So water = 10-2= 
10-2 = 8
8 lts. 30% of 15 lts= 4.5. So water in 2nd mixture = 15-4.5= 
15-4.5 = 10.5
10.5 lts. Now total quantity= 10 + 15= 
10 + 15 = 25
25 lts. Total water in it will be 8 + 10.5= 
8 + 10.5 = 18.5
18.5 lts. % of water= (100*18.5)/25= 
(100*18.5)/25 = 74
74   74NSWER:74
Answer: A
The C.I. on a certain sum for 2 years at 10% per annum is Rs. 525. The S.I. on the same sum for double the time at half the rate percent per annum is?
Choose the correct choice from the following
A) Rs. 400 B) Rs. 500 C) Rs. 600 D) Rs. 800 E) Rs. 900

Solution: Let the sum be Rs. P. Then,   [P(1 + 10/100)2 - p] = 525   P[(11/10)2 - 1] = 525   P = (525 * 100) / 21= 
(525 * 100) / 21 = 2_500
2500   Sum= Rs. 2500   So, S.I. = (2500 * 5 * 4)/100 = Rs. 500   ANSWER:Rs. 500
Answer: B
In a class of 140 students, 60% of them passed. By what percent is the number of students who passed more than the number of failed students? Choose the correct choice from the following choices
A) 70%
B) 80%
C) 58%
D) 50%
E) 53%

Solution: Number of students passed   = 60% of 140 = 60/100 * 140= 
60/100 * 140 = 84
84   Number of students failed= 140 - 84= 
140 - 84 = 56
56.   Required percentage= 28/56 * 100= 
28/56 * 100 = 50
50%.   Answer:50%
Answer: D
If y is the smallest positive integer such that 8,820 multiplied by y is the square of an integer, then y must be	Choose the correct choice from the following options.
A) 2  B) 5  C) 6  D) 7  E) 14

Solution: i just tried plugging in the numbers and found out that   5*8820 = 44, 100, which is a square of 210   5
Answer: B
If 20 men take 15 days to to complete a job, in how many days can 25 men finish that work?
Choose the correct choice from the following answers.
A) 12
B) 66
C) 77
D) 8
E) 6

Solution: Ans. 12 days
Answer: A
What sum of money put at C.I amounts in 2 years to Rs.8820 and in 3 years to Rs.9261?  Choose one:
A) 8000 B) 2277 C) 2678 D) 1276 E) 1871

Solution: 8820 ---- 441   100 ---- ? => 5%   x *105/100 * 105/100 = 8820   x*1.1025=8820   x=8820/1.1025= 
8820/1.1025 = 8_000
> 8000   8000nswer:8000
Answer: A
If m times the mth series of an A.P. is equal to n times its nth series, what is the (m+n)th term of the A.P. ?
Options
A) 0
B) m
C) n
D) mn
E) None of these

Solution: Explanation :   Here's the solution :   mth term of an A.P.   Am = a + (m-1)d-------------------------------(1)   nth term of an A.P.   0n = a + (n+1)d--------------------------------(2)   [Here a= First term of an 0.P   d= difference between two consecutive terms ]   Now , 0ccording to the question;   m*0m = n*0n   m(a + (m-1)d)= n(a + (n-1)d)   m(a + md - d)= n(a + nd - d)   am + m2d-md = an + n2d - nd   a(m-n)+ (m2-n2)d -(m-n)d = 0   a(m-n)+ (m-n)(m+n)d -(m-n)d= 0   (m-n)[a + (m+n)d - d ]= 0   [a + (m+n)d - d ]= 0   [a + (m+n-1)d ]= 0-------------------------------------(3)   Hence , 0ccording to equation (3)   0m+n = 0   Hence (0) is the correct answer   0nswer : 0
Answer: A
If there are 200 questions in a 3 hr examination. Among these questions are 10 type A problems, which requires twice as much as time be spent than the rest of the type B problems. How many minutes should be spent on type A problems?
Pick
A) 17.14286 min
B) 62 min
C) 70.1346 min
D) 74 min
E) 76.1346 min

Solution: x=time for type B prolems   2x=time for type 17.14286 min problem   total time=3hrs=180min   190x+10*2x=180   x=180/210   x=0.72   time taken for type 17.14286 min problem=10*2*0.857143= 
10*2*0.857143 = 17.14286
17.14286min   17.14286 minNSWER:17.14286 min
Answer: A
Seven cards numbered from 1 to 7 are placed in an empty bowl. First one card is drawn and then put back into the bowl, and then a second card is drawn. If the cards are drawn at random and if the sum of the numbers on the cards is 9, what is the probability that one of the two cards drawn is numbered 5? Choose the correct choice from the following answers.
A) 1/2 B) 1/3 C) 1/5 D) 2/5 E) 2/7

Solution: There are 6 ways to get a total sum of 9.   2 of these ways include the number 5.   The probability that one of the cards is a 5 is 2/6 = 1/3   The answer is 1/3.
Answer: B
The list price of an article is Rs.65. A customer pays Rs.56.16 for it. He was given two successive discounts, one of them being 10%. The other discount is?
Choose the correct choice from the following choices
A) 8%	B) 4%	C) 6%	D) 3%	E) 2%

Solution: 65*(90/100)*((100-x)/100)   = 56.16   x = 4%   Answer: 4%
Answer: B
If n is a natural number, then 6n^2 + 6n is always divisible by?	Choose one.
A) 6 only  B) 6 and 12 both  C) 12 only  D) 18 only  E) 20 only

Solution: 6n^2 + 6n = 6n(n+1), which is always divisible by 6 and 12 both, since n(n+1) is always even.   Answer is 6 and 12 both
Answer: B
A watch was sold at a loss of 10%. If it was sold for Rs.500 more, there would have been a gain of 10%. What is the cost price?
Pick
A) 1000	B) 2998	C) 2500	D) 2788	E) 2991

Solution: 90%   110%   --------   20% ---- 500   100% ---- ? => Rs.2500   Answer:2500
Answer: C
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:  Select the correct option
A) 14 years	B) 19 years	C) 33 years	D) 38 years	E) 42 years

Solution: Let the son's present age be x years. Then, (38 - x) = x   2x = 38.   x = 19.   Son's age 5 years back (19 - 5)= 
(19 - 5) = 14
14 years.   14 yearsnswer: Option 14 years
Answer: A
Cereal A is 10% sugar by weight, whereas healthier but less delicious Cereal B is 3% sugar by weight. To make a delicious and healthy mixture that is 5% sugar, what should be the ratio of Cereal A to Cereal B, by weight?
Choose the correct answer
A) 2:5  B) 2:7  C) 1:6  D) 1:4  E) 1:3

Solution: Ratio of 2:5 / Ratio of B = (2:5verage Wt of Mixture - Wt of B)/(Wt of 2:5 - 2:5verage Wt of Mixture)   => Ratio of 2:5 / Ratio of B = (5 - 3)/(10 - 5) = 2/5   So they should be mixed in the ratio 2:5   2:5nswer - 2:5
Answer: A
Given distinct positive integers 1, 12, 3, x, 2, and 9, which of the following could be the median? Choose one:  A) 1  B) 3  C) 6  D) 8  E) 9

Solution: The median of a set with even number of terms is the average of two middle terms when arranged in ascending (or descending) order.   Arrange numbers in ascending order: 1, 2, 3, 9, 11, and x.   Now, x can not possibly be less than 3 as given that all integers are positive and distinct (and we already have 1, 2, and 3).   Next, if x is 3<x<9 then the median will be the average of 3 and x. As all answers for the median are integers, then try odd values for x:   If x=5, then median=(3+5)/2= 
(3+5)/2 = 4
4 --> not among answer choices;   If x=7, then median=(3+7)/2= 
(3+7)/2 = 5
5 --> not among answer choices;;   If x is more than 9 so 10 or more then the median will be the average of 3 and 9 so  (3+9)/2= 
 (3+9)/2 = 6
6 (the maximum median possible).   Answer: 6
Answer: C
Four faces of a fair die are Yellow, three faces red and one blue.The die is tossed three
times. The probability that the colours, yellow, red and blue appear in the first, second and
third tosses respectively is
Choose the correct answer:  A) 1/36  B) 1/18  C) 1/32  D) 1/37  E) None of these

Solution: Probability of getting yellow color = P(Y) = 4/6 = 2/3   Probability of getting red color = P(R) = 3/6 = 1/2   Probability of getting blue color = P(1/18) = 1/6   So, the probability that the colors yellow, red and blue appear in first, second and third toss respectively= P(Y ∩ R ∩ 1/18) = P(Y) x P(R) x P(1/18) = 2/3 x 1/2 x 1/6 = 1/18   ANSWER:1/18
Answer: B
A man buys a cycle for Rs.1400 and sells it at a loss of 20%. What is the selling price of the cycle?	Select:
A) Rs.1090 B) Rs.1160 C) Rs.1120 D) Rs.1202 E) NONE

Solution: Solution   S.P	= 80% of Rs.1400   = Rs.(80/100×1400)   Rs.1120.   Answer Rs.1120
Answer: C
How many seconds does Puja take to cover a distance of 500 m, if she runs at a speed of 30 km/hr?	Choose the correct choice from the following answers
A) 60 sec  B) 82 sec  C) 95 sec  D) 100 sec  E) 120 sec

Solution: Hint:   Time =	Distance / Speed   We see that the distance is given in metres while the speed is given in km/hr and the answer is asked in seconds.   So, convert km/hr into m/s by multiplying	5 /18	m/s to the given value of speed.   30	km / hr	= 30 x	5 /18	=	75 /9 m/sec   i.e. Place these values in the formula:   Time = 500 x	9 / 75= 60 sec   60 secNSWER IS 60 sec
Answer: A
If 1/a^2 + a^2 represents the diameter of circle O and 1/a + a = 5, which of the following best approximates the circumference of circle O? Choose the correct choice from the following choices.
A) 28	B) 22	C) 20	D) 16	E) 12

Solution: Given that (1/a)+a =3   Square both sides of the equation:   We get,   [(1/a)^2 + a^2 + 2*(1/a)*a] = 9   => (1/a)^2 + a^2 + 2 = 9   => (1/a)^2 + a^2 = 7 ----------------- (1)   Diameter D = (1/a)^2 + a^2   = 7 (From (1))   So Radius = D/2 = 7/2   Circumference = 2*Pi*r   = 2*(22/7)*(7/2)   =28   So the answer should be 28.
Answer: A
In how many different number of ways 5 men and 2 women can sit on a shopa which can accommodate persons?	Choose one:
A) 170  B) 180  C) 200  D) 210  E) 220

Solution: Option '210'   7p3 = 7 × 6 × 5 = 210
Answer: D
A certain junior class has 1,200 students and a certain senior class has 800 students. Among these students, there are 60 siblings pairs, each consisting of 1 junior and 1 senior. If 1 student is to be selected at random from each class, what is the probability that the 2 students selected at will be a sibling pair?  Choose the correct choice from the following answers: A) 3/40,000 B) 1/3,600 C) 9/2,000 D) 1/60 E) 1/16,000

Solution: Total number of ways of choosing one student from each group is = 800 * 1200   Number of cases in which a sibling pair will be got is = 60   Thus the probability that the 2 students selected will be a sibling pair is   = 60 /(800 * 1200)   = 1/16,000   1/16,000
Answer: E
The greatest number which on dividing 1657 and 2037 leaves remainders 10 and 7 respectively, is:
Choices
A) 123 B) 1 C) 235 D) 305 E) 505

Solution: Explanation:   Required number = H.C.F. of (1657 - 10) and (2037 - 7)   = H.C.F. of 1647 and 2030 = 1. Answer: 1
Answer: B
The number of cars present at a particular time was measured at 4,999 different locations on Tuesday and on Wednesday. The number of locations that had more cars on Wednesday was 20% higher than the number of locations that had more cars on Tuesday. How many of the locations had more cars on Tuesday? Choose the correct choice
A) 1,159
B) 1,333
C) 1,860
D) 2,160
E) 2,272

Solution: The question states that all these 4,999 locations were measured twice, once on each day.   It also breaks the 4,999 into two groups, the higher-on-Tuesday locations and the higher-on-Wednesday locations, which we can call T and W.   Therefore, we can write two equations:   For each of the first and second day count of locations, T + W = 4999   But, for the second day count, W = 1.20 T   i.e. for Second day count, T + 1.20T = 4999   i.e. 2.20 T = 4999   i.e. T = 2272   2,272
Answer: E
ind next number in the series
23 21 24 19 26 15 28 11 30 7 36 ?
Options:  A) 12  B) 20  C) 5  D) 40  E) 34

Solution: C   5   23-2= 
23-2 = 21
21   21+3= 
21+3 = 24
24   24-5= 
24-5 = 19
19   19+7= 
19+7 = 26
26   26-11= 
26-11 = 15
15   15+13= 
15+13 = 28
28   28-17= 
28-17 = 11
11   11+19= 
11+19 = 30
30   30-23= 
30-23 = 7
7   7+29= 
7+29 = 36
36   36-31= 
36-31 = 5
5   (2,3,5,7,11,13,17,19,23,29,31,37,41,43... are Prime Numbers)
Answer: C
The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay ?  Select the correct option:
A) 2500 B) 2700 C) 2200 D) 2900 E) 2400

Solution: Let the price of a saree and a shirt be Rs. x and Rs. y respectively.   Then, 2x + 4y = 1600 .... (i)   and x + 6y = 1600 .... (ii)   Divide equation (i) by 2, we get the below equation.   => x + 2y = 800. --- (iii)   Now subtract (iii) from (ii)   x + 6y = 1600 (-)   x + 2y = 800   ----------------   4y = 800   ----------------   Therefore, y = 200.   Now apply value of y in (iii)   => x + 2 x 200 = 800   => x + 400 = 800   Therefore x = 400   Solving (i) and (ii) we get x = 400, y = 200.   Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.   Answer is 2400.
Answer: E
Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choose one.
A) 11 B) 12 C) 13 D) 14 E) 15

Solution: Speed of the first train = 120/10= 
120/10 = 12
12 m/sec.   Speed of the second train= 120/5 = 8 m/sec.   Relative speed = 12 + 8= 
12 + 8 = 20
20 m/sec.   Required time= (120 + 120)/20= 
(120 + 120)/20 = 12
12 sec.   Answer: Option 12
Answer: B
A can do a piece of work in 20 days. B in 15 days A and C in 12 days. In how many days can A finish the work if he is assisted by B on one day and C on the next, alternately?	Pick:	A) 7 days	B) 8 days	C) 5 days	D) 4 days	E) 2 days

Solution: A + 8 days = 1/20 + 1/15 = 7/60   A + C = 1/20 + 1/12 = 8/60   7/60 + 8/60 = 15/60 = 1/4   4 days * 2 = 8 days   Answer: 8 days
Answer: B
In a class 30 students play cricket, 40 students play football and 20 play none of the two games.
If there are 80 students exactly in the class, how many play exactly ONE of the two games?
Choices:
A) 40
B) 50
C) 80
D) 85
E) 90

Solution: n(C) = 30, n(F) = 40 and n(C' or F') = 20   => n(C or F) = 80 - 20= 
80 - 20 = 60
60   also, n(C or F)= n(C) + n(F) - n(C and F)   => 60 = 30 + 40 - n(C and F)   i.e. n(C and F) = 10   so, 30 - 10 = 20 students play just football and 40 - 10= 
40 - 10 = 30
30 students play just cricket=> 20 + 30= 
20 + 30 = 50
50 students play exactly ONE game   50)
Answer: B
47% of the students in a class of 40 students has glasses or contacts. How many students in the class have either glasses or contacts?
Choose the correct option:
A) 15 B) 16 C) 17 D) 18 E) 19

Solution: a=r⋅b   47%=0.47a   =0.47⋅40   a≈19   Option 19 is correct.
Answer: E
If there are only 2 wheelers and 4 wheelers parked in a school located at the heart of the city, find the number of 4 wheelers parked there if the total number of wheels is 70?
Answers.
A) 11
B) 12
C) 13
D) 14
E) 17

Solution: four wheeler=17*4= 
17*4 = 68
68(max)   2 wheel=1   so no of 4 wheeler=17   ANSW17R:17
Answer: E
A problem is given to 3 students A, B and C whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the chance that the problem is solved.
Choose one:  A) 2/3  B) 1/2  C) 1/4  D) 3/4  E) 3/7

Solution: Explanation :   P(A) = 1/2, P(~A) = 1 - (1/2) = 1/2. [ Prob. of not solving A ]   P(B) = 1/3, P(~B) = 1 - (1/3) = 2/3. [ Prob. of not solving B ]   P(C) = 1/4, P(~C) = 1 - (1/4) = 3/4. [ Prob. of not solving C ]   The problem is solved means atleast one of A,B and C will solve the problem.   Whenever 'at least one' is present it is easier to do the problem by using the complement of the event (opposite of the event i.e problem not solved )   P (problem is not solved)   = P(~A~B~C)   = P(~A) x P(~B) x P(~C).   = (1/2) x (2/3) x (3/4).   = 1/4.   P (problem is solved i.e atleast one solves)   = 1 - P(~A~B~C).   = 1 - (1/4).   = 3/4.   Answer : 3/4
Answer: D
In one hour a boat goes 6 km/hr along the stream and 14 km/hr against the stream. The speed of the boat in still water(in km/hr) is?
Choose the correct choice from the following choices:  A) 20 km/hr  B) 10 km/hr  C) 15 km/hr  D) 30 km/hr  E) 40 km/hr

Solution: Explanation:   Speed of boat in still water = 1/2 (Speed downstream + speed up stream)   = 1/2 (6 + 14) = 1/2 x 20   = 10 km/hr   Answer: Option 10 km/hr
Answer: B
A completes a work in 12 days and B complete the same work in 24 days. If both of them work together, then the number of days required to complete the work will be ?
Choose the correct choice
A) 8 days	B) 10 days	C) 12 days	D) 14 days	E) 16 days

Solution: If A can complete a work in x days and B can complete the same work in y days, then, both   of them together can complete the work in x y/ x+ y days   Therefore, here, the required number of days = 12 × 24/ 36 = 8 days.   8 days)
Answer: A
Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of
A, B, C and D is  Choose the correct choice from the following answers:	A) 90	B) 98	C) 120	D) Data is not adequate	E) None of these

Solution: Answer: Option Data is not adequate
Answer: D
If a man can cover 10 metres in one second, how many kilometres can he cover in 3 hours 45 minutes? Choose the correct choice
A) 135 km  B) 125 km  C) 115 km  D) 105 km  E) 235 km

Solution: 10 m/s = 10 * 18/5 kmph   3 hours 45 minutes = 3 3/4 hours = 15/4 hours   Distance = speed * time = 10 * 18/5 * 15/4= 
10 * 18/5 * 15/4 = 135
135 km.   135 kmNSWER:135 km
Answer: A
In a group of ducks and cows, the total number of legs are 30 more than twice the no. of heads. Find the total no.of buffaloes.	Choose the correct option.
A) 11  B) 12  C) 14  D) 15  E) 18

Solution: Let the number of buffaloes be x and the number of ducks be y   => 4x + 2y = 2 (x + y) + 30   => 2x = 30 => x = 15   15
Answer: D
There are 10 points on a circle. A hexagon can be formed by linking 6 of the 10 points. How many such hexagons are possible?
Pick.
A) 60  B) 120  C) 200  D) 210  E) 600

Solution: 6 points can be selected out of 10 points in 10C6 ways   =10 !/6!*4!=210   Ans 210
Answer: D
One robot builds a robot in 1 hour, another one builds a robot in 2 hours. The 2 robots work together and when a new robot is complete, it joins the others, working at a constant rate of one robot in 2 hours. How much time will it take until there are 4 robots altogether, if the robots build only one robot at a time?
Choose the most appropriate option
A) 70 min	B) 94 min	C) 110 min	D) 112 min	E) 120 min

Solution: First the 2 robots work at the rate of   1 + 1/2 = 3/2   so they complete one robot in 2/3 rd of an hour = 40 minutes - (1)   Now the 3 robots work together at the rate of   1 + 1/2 + 1/2 = 4/2= 
4/2 = 2
2/1   so they complete one robot in 1/2 an hour,i.e 30 minutes - (2)   70 minnd now we have 4 robots   So Total= (1) + (2) = 70 minutes   70 minnswer - 70 min
Answer: A
After taking N tests, each containing 100 questions, John had an average of 70% of correct answers. How much does John need to score on the next test to make his average equal 73%?
M13-03. Select the correct option:  A) N−35  B) N+72  C) 2N+70  D) 2N+74  E) 2N−35

Solution: Say N=1.   So, after 1 test John has 70 correct answers.   In 2 tests, so in 200 questions he needs to have  0.73*200= 
 0.73*200 = 146
146 correct answers, so in the second test he must get   146-70= 
  146-70 = 76
76 questions correctly.   Now, plug N=1 into the answer choices to see which one yields 76. Only option D fits.   Answer: 2N+74.
Answer: D
A bank pays interest to its customers on the last day of the year. The interest paid to a customer
is calculated as 10% of the average monthly balance maintained by the customer. John is a
customer at the bank. On the last day, when the interest was accumulated into his account, his
bank balance doubled to $5760. What is the average monthly balance maintained by John in his
account during the year?  Answers:
A) 2840 B) 28800 C) 6840 D) 7540 E) 28400

Solution: bank balance is doubled with accumulation of interest tp 5760..   this means INTEREST is   5760/2= 
  5760/2 = 2_880
2880 for entire year..   although since interest is 10% of avg MONthly balance, it becomes 28800..   28800
Answer: B
A Cuban cigar would cost 4 dollar less than 1.5 times a French cigar, had the French cigar cost 0.7 dollar less than it does now. An Arabian cigar costs 50 cents more than 1.5 times the Cuban cigar. The three cigars together cost 74.7 dollars. What is the price of the French cigar?
Select the correct option.
A) 11.8$.	B) 23$.	C) 13.7$.	D) 35$.	E) 37.4$.

Solution: The three cigars together cost 74.7 dollars. If each cost the same , they would have cost a little less than 25 dollars each.   From the given data we know French cigar < Cuban cigar < Arabic cigar   and each is more expensive 1.5 times. Therefore eliminate options A,D,E straightaway . Since French cigar is at least 1.5 times cheaper we know B cannot be the answer.   Therefore 13.7$. is the answer.
Answer: C
Set Q consists of integers {3, -8, Y, 19, -6} and set B consists of integers {k, -3, 0, 16, -5, 9}. Number L represents the median of set Q, number M represents mode of set B and number Z = L^M. If Y is an integer greater than 21, for what value of k will Z be a divisor of 26? Pick
A) -2  B) -1  C) 0  D) 1  E) 2

Solution: A = {3,-8,Y,19,-6}   B = {k,-3,0,16,-5,9}   Y > 21   So L = Median of Q = 3   M = Mode of Set B   Z = (3)^M   If Z is a divisor of 26, (3)^M = 1 because 26 does not have 3 as a factor   => M = 0   Hence k = 0, as M is mode and 0 will be the most frequently occuring number in set B.   Answer - 0
Answer: C
A car traveled from San Diego to San Francisco at an average speed of 66 miles per hour. If the journey back took twice as long, what was the average speed of the trip?
Choose the correct choice from the following options: A) 24. B) 32. C) 36. D) 42. E) 44.

Solution: Let the time taken be = x   One way distance = 66x   Total distance traveled = 2 * 66= 
2 * 66 = 132
132x   Total time taken= x + 2x = 3x   Average speed = 132x/3x = 44   Answer: 44.132 /3= 
132 /3 = 44
44   Answer: 44.
Answer: E