MU-NLPC/Calc-aqua_rat huggingface dataset:
The sum of five numbers is 750. The average of the first two numbers is 75 and the third number is 130. Find the average of the two numbers?  Choose the correct choice from the following answers:	A) 220	B) 225	C) 230	D) 235	E) 240

Solution: Let the five numbers be P, Q, R, S and T.   => P + Q + R + S + T = 750.   (P + Q)/2 = 75 and R = 130   P + Q = 150 and R = 130   P + Q + R = 280   S + T = 750 - (P + Q + R) = 470   Average of the last two numbers   = (S + T)/2 = 235   Answer:235
Answer: D
The number of sequences in which 7 players can throw a ball, so that the youngest player may not be the last is?
Choose the correct option
A) 4389 B) 8369 C) 4320 D) 4356 E) 3537

Solution: x Not younger_______ ↑   The last ball can be thrown by any of the remaining 6 players. The first 6 players can throw the ball in ⁶P₆ ways.   The required number of ways = 6(6!) = 4320   Answer:4320
Answer: C
If Jake loses 8 pounds, he will weigh twice as much as his sister Kendra. Together they now weigh 287 pounds. What is Jake’s present weight, in pounds?  Choose the correct choice:
A) 178 B) 182 C) 186 D) 190 E) 194

Solution: J + K = 287 and so K = 287 - J   J - 8 = 2K   J - 8 = 2(287-J)   3J = 582   J = 194   The answer is 194.
Answer: E
A number x is mistakenly divided by 10 instead of being multiplied by 10. what is the percentage error in the result?
Pick.
A) -99%
B) -100%
C) +99%
D) +100%
E) None

Solution: Solution: Actual result = 10x   By mistake it has been divided by 10 = x /10   % change = [10x -(10 /x) /10x] *100 = 99   = - 99%.   Since, actual value is greater than the wrong value.   Alternatively,   Let, x = 10   Actual result = 10 * 10= 
10 * 10 = 100
100   wrong result= 10 /10= 
10 /10 = 1
1.   Change= (1 -100) = -99   % change = -99%.   -99%nswer: Option -99%
Answer: A
A man buys an item at Rs. 1200 and sells it at the loss of 20 percent. Then what is the selling price of
that item	Choices
A) Rs. 660
B) Rs. 760
C) Rs. 860
D) Rs. 960
E) None of these

Solution: Explanation:   Here always remember, when ever x% loss,   it means S.P. = (100 - x)% of C.P   when ever x% profit,   it means S.P. = (100 + x)% of C.P   So here will be (100 - x)% of C.P.   = 80% of 1200   = 80/100 * 1200= 
80/100 * 1200 = 960
960   Answer: Rs. 960
Answer: D
10 books are placed at random in a shelf. The probability that a pair of books will always be together is?  Choose the correct choice from the following answers
A) 1/7  B) 1/9  C) 1/5  D) 1/8  E) 1/2

Solution: 10 books can be rearranged in 10! ways consider the two books taken as a pair then number of favourable ways of getting these two books together is 9! 2!   Required probability = 1/5   Answer: 1/5
Answer: C
An automobile parts supplier charges $25 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 25 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets?	Choose the correct choice from the following options
A) 1305	B) 1545	C) 1375	D) 1345	E) 1455

Solution: $25 per packet of gasket in case a customer orders less than 10   in case a customer orders > 10 price per gasket = 25*4/5= 
25*4/5 = 20
20   a certain week the supplier sold 60 gasket   1.he sold 25 % of the gaskets to X= 15 gaskets = 25*10 + 20 *5 = 250 + 100= 
250 + 100 = 350
350   2.he sold 15 % of the gaskets to Y= 9 gaskets = 25*9= 
25*9 = 225
225   3.he sold remaining 60% to z=36 gaskets = 25*10= 
25*10 = 250
250 + 20*26= 
250 + 20*26 = 770
770   thus ,total money earned   350+225+770= 
350+225+770 = 1_345
1345   Answer is 1345
Answer: D
Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent T of the original cost?
Choose the correct answer.
A) T=200 B) T=600 C) T=800 D) T=1600 E) T=50

Solution: Original Cost C1=t1*b1^4   New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1   C2=t2*(2b1)^4   =16(t1 * b1^4)   =16C1   16 times C1=>1600% of C1   Ans T=1600=1600
Answer: D
Find the value of 72519 x 9999 = m?  Select the correct option: A) 234567745 B) 674225565 C) 570909643 D) 725117481 E) 768965324

Solution: 72519 x 9999 = 72519 x (10000 - 1)   = 72519 x 10000 - 72519 x 1   = 725190000 - 72519= 
725190000 - 72519 = 725_117_481
725117481   725117481
Answer: D
A is twice as good a workman as B and together they complete a work in 12 days. In how many days A alone can do the work?
Pick one.
A) 32  B) 33  C) 34  D) 35  E) 36

Solution: A’s one day’s work : B’s one day’s work= 2:1   (A+B)’s one day’s work= 1/12   B’s one day’s work= 1/12 *1/3 = 1/36   B alone can do the work in 36 days   ANSW36R:36
Answer: E
In how many ways can a group of 4 men and 2 women be made out of a total of 6 men and 4 women?  Choose the correct choice from the following answers
A) 63
B) 67
C) 70
D) 90
E) 80

Solution: We need to select 4 men from 6 men and 2 women from 4 women. Number of ways to do this= 6C4 × 4C29090)
Answer: D
What will come in place of the x in the following Number series? 11, 14, 19, 22, 27, 30, x Choose the correct choice from the following:  A) 29  B) 31  C) 23  D) 35  E) 39

Solution: (35)   The pattern is + 3, + 5, + 3, + 5, …………   So the missing term is = 30 + 5= 
30 + 5 = 35
35.
Answer: D
what is the angle between the hands of a clock when time is 10:20?  Choose the correct choice from the following:
A) 90deg	B) 75deg	C) 45deg	D) 15deg	E) 30deg

Solution: 90degngle between two hands =   20h - 11/2 m = 20*10 - 20*11/2 = 200 - 110= 
200 - 110 = 90
90deg   90degNSWER:90deg
Answer: A
Two hoses are pouring water into an empty pool. Hose 1 alone would fill up the pool in 6 hours. Hose 2 alone would fill up the pool in 5 hours. How long would it take for both hoses to fill up two-thirds of the pool?	Choose the correct option.
A) 5/12 hours  B) 5/8 hours  C) 20/11 hours  D) 12/7 hours  E) 12/5 hours

Solution: Hose 1 would fill the pool alone in 6 hours   i.e. 1 Hour work of Hose 1 = 1/6   Hose 2 would fill the pool alone in 5 hours   i.e. 1 Hour work of Hose 2 = 1/5   i.e. 1 Hour work of Hose1 and Hose2 together = (1/6)+(1/5) = (11/30)   i.e. (11/30) work can be finished by Hose1 and Hose2 together in 1 hour   i.e. (2/3) work can be finished by Hose1 and Hose2 together in 1*(30/11)*(2/3) = 20/11hour   Answer: Option 20/11 hours
Answer: C
The difference between the simple interest and the compound interest (compounded yearly)earned on a sum of money at the end of four years at the rate of 10 percent per annum is Rs.256.40. Find the sum. Choose the correct choice from the following:
A) Rs.6,000  B) Rs.4,000  C) Rs.5,000  D) Rs.4500  E) Rs.5500

Solution: SI=(P*10*4)/100= 4p/10   CI=P(1+10/100)^4-P =4641P/100   CI-SI=   4641P/100-4P/100=256.40   P=4000   ANSWER:Rs.4,000
Answer: B
The cash realised on selling a 14% stock is Rs.105.25, brokerage being 1/4% is?  Answers.
A) 366 B) 106 C) 102 D) 105 E) 122

Solution: Cash realised= Rs. (105.25 - 0.25)   = Rs. 106.   Answer: 105
Answer: D
Tom began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after Tom? Choose the correct choice from the following options:
A) 35	B) 55	C) 39	D) 40	E) 60

Solution: Carla starts 30 minutes later and it takes 3 hr for carla to meet Tom   So Tom total time travelled = 3hr + 30= 
+ 30 = 30
30 * (3 1/2)= 105   so carla need to travle 105 to meet Tom in 3 hrs   speed of carla = 105/3= 
105/3 = 35
35 miles per hour   35nswer is 35
Answer: A
The simple interest on Rs.12000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for five years at the same rate of interest?
Choose the most appropriate option.
A) 3052.83 B) 3052.22 C) 3052.08 D) 3052.8 E) 3052.13

Solution: R = 100 I / PT   => R = (100 * 7200)/ (12000 * 5)= 
(100 * 7200)/ (12000 * 5) = 12
12%   CI= P{ [1 + R /100]n - 1}   = 12000 { [ 1 + 12 / 100]2 - 1}   = Rs.3052.80   Answer: 3052.8
Answer: D
The smallest number which when added to 4, the sum is exactly divisible by 24, 36, 48 and 60 is:  Choose the most appropriate option
A) 327 B) 716 C) 256 D) 299 E) 111

Solution: nation: 2 24 36 48 60 2 12 18 24 30 3 6 9 12 15 2 2 3 4 5 1 3 2 5 ∴ LCM of 24, 36, 48, 60 = 2 × 2 × 3 × 2 × 3 × 2 × 5 = 720. ∴ Required number = 716   Answer:716
Answer: B
The sum of the first 50 positive even integers is 2550. What is the sum R of even integers from 102 to 200 inclusive?
Select:  A) 5100  B) 7550  C) 10100  D) 15500  E) 20100

Solution: My solution is:   First 50 even integers:   2   4   6   8   <...>   Integers from 102 to 200   102   104   106   108   <...>   We notice that each integer from the second set is 100 more than the respective integer in the first set. Since we have 50 even integers from 102 to 200, then:   R=2550+(100*50)=7550.7550
Answer: B
A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 26 sec respectively. What is the speed of the train?	Choose the correct choice from the following answers:
A) 89  B) 23  C) 52.8  D) 79.2  E) 67

Solution: Let the length of the train be x m and its speed be y m/sec.   Then, x/y = 8 => x = 8y   (x + 264)/26 = y   y = 14.67   Speed = 14.67 m/sec = 14.67 * 18/5 = 52.8 km/hr.   Answer: Option 52.8
Answer: C
If Susan takes 10 seconds to run y yards, how many minutes will it take her to run x yards at the same rate?	Choose the correct choice from the following:
A) xy/10
B) 10x/(60y)
C) 60xy/10
D) xy/540
E) 540x/y

Solution: The answer is B.   She runs x yards in 10x/y seconds =10x/60y minutes.
Answer: B
For how many values of M, is |||M - 5| -10| -5| = 2?
(Those ls are mods) Choose the correct choice from the following choices
A) 0 B) 2 C) 4 D) 8 E) More than 8

Solution: I think its 8   |||M-5|-10|-5| =2   let |M-5| = a which makes above   ||a-10|-5| =2   let |a-10| = b which makes   |b-5| = 2   now for the above b can take 3, 7   for every b =3 a can have 13, 7   and for b = 7 a can have 17 and 3   so 'a' has four solutions 13, 7, 17 and 3   for a = 13; x has 18 or -8 thus has 2 for every combination hence 4x2 = 8   answer 8
Answer: D
Rakesh travelled 1800 kilometre by air which formed 3/5 of the total journey. He travels 1/4 of the trip by car and the remaining trip by train. Find the distance travelled by train.  Select the correct option.
A) 350	B) 450	C) 550	D) 650	E) None of these

Solution: Explanation :   3/5 of D = 1800. So D = 3000 km,   so distance travelled by train = 3000 – 1800 – 1/4 of 3000 = 450   Answer – 450
Answer: B
If a(a - 6) = 27 and b(b - 6) = 27, where a ≠ b, then a + b = Pick:
A) −48	B) −2	C) 6	D) 46	E) 48

Solution: i.e. if a =-3 then b = 9   or if a = 9 then b =-3   But in each case a+b = -3+9= 
-3+9 = 6
6   Answer: option 6
Answer: C
The average age of the mother and her six children is 12 years which is reduced by 5 years if the age
of the mother is excluded. How old is the mother Select: A) 40 B) 41 C) 42 D) 43 E) 44

Solution: Answer: Option 42
Answer: C
At present, the ratio between the ages of Arun and Deepak is 4:3. After 6 years, Arun's age will be 34 years. What is the age of Deepak at present?	Options.
A) 77 years B) 15 years C) 21 years D) 88 years E) 55 years

Solution: Let the present ages of Arun and Deepak be 4x and 3x years respectively.   Then, 4x + 6 = 34 => x = 7   Deepak's age = 3x = 21 years.   Answer: 21 years
Answer: C
Audrey 4 hours to complete a certain job. Ferris can do the same job in 3hours. Audrey and Ferris decided to collaborate on the job, working at their respective rates. While Audrey worked continuously, Ferris took 2 breaks of equal length. If the two completed the job together in 2 hours, how many minutes long was each of Ferris’ breaks ? Choices:
A) 5	B) 15	C) 17	D) 20	E) 25

Solution: Audery and Ferris collective Work rate:   1/4 + 1/3 = 7/12   Collective work Time = 12/7 = 1.7 Hrs   Job Was actually done in = 2 (Includes breaks)   15reaks = Actual time taken - Collective work time   = 2 - 1.7= 
2 - 1.7 = 0.3
.3 Hrs= 1/2   so ferrais took 2 breaks   =.3/2= 
.3/2 = 0.15
.15 hrs= 15 m   so Answer is 15) 15 mins
Answer: B
A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 40%?
Choose the correct choice from the following answers:
A) 700	B) 882	C) 772	D) 652	E) 271

Solution: Cost price = Rs.500   profit = 40% of 500 = Rs.200   Selling price = Cost price + Profit   = 500 + 200= 
500 + 200 = 700
700   700nswer:700
Answer: A
A women purchased 3 towels @ Rs.100 each, 5 towels @ Rs.150 each and two towels at a certain rate which is now slipped off from his memory. But she remembers that the average price of the towels was Rs.170. Find the unknown rate of two towels?	Choose the correct choice from the following choices
A) A)400  B) B)650  C) C)500  D) D)550  E) E)600

Solution: 10 * 170= 
10 * 170 = 1_700
1700   3 * 100 + 5 * 150= 
3 * 100 + 5 * 150 = 1_050
1050   1700 – 1050= 650   650
Answer: B
The simple interest on Rs.12000 at a certain rate of interest in five years is Rs.7200. Find the compound interest on the same amount for five years at the same rate of interest.  Choose the correct choice from the following choices:
A) 3052.89  B) 3052.86  C) 3092.8  D) 3052.8  E) 3052.81

Solution: R = 100 I / PT   => R = (100 * 7200)/ (12000 * 5)= 
(100 * 7200)/ (12000 * 5) = 12
12%   CI= P{ [1 + R /100]n - 1}   = 12000 { [ 1 + 12 / 100]2 - 1} = Rs.3052.80.Answer: 3052.8
Answer: D
If the radius of a circle is increased by 12%, then the area of the circle
Choose the correct option:	A) decreases by 25.44%	B) increases by 25.44%	C) no change in area	D) decreases by 12%	E) none

Solution: A1=pi(100)^2   A2=pi(112)^2   so (A2-A1)/A1*100=25.44   ANSWER:increases by 25.44%
Answer: B
Which of the following is the Highest Common Factor of 121, 99 and 77? Choose the correct choice.
A) 8 B) 10 C) 6 D) 14 E) 11

Solution: the Highest Common Factor is 11Ans is :11
Answer: E
A certain car can travel 40 minutes on a gallon of gasoline at 60 miles per hour. If the car had started with a full tank and had 8 gallons of gasoline left in its tank at the end, then what percent of the tank was used to travel 120 miles at 60 mph?	Pick one:
A) 15%  B) 20%  C) 27.27%  D) 30%  E) 40%

Solution: Let, Tank capacity = T gallon   Used Fuel = (T-8) gallons   Distance Travelled (@60 miles/hr) = 80 miles   Distance travelled in 1 gallon = Distance travelled in 40 mins (@60 miles/hr) = (60/60)*40= 
(60/60)*40 = 40
40 miles   Fuel used to travel 120 miles= (120/40)= 
(120/40) = 3
3 gallon   i.e. Used fuel= (T-8) = 3 gallon   i.e. T = 10 Gallons   i.e. Used Fuel = (3/11)*100 =27,27%   27.27%
Answer: C
Two trains of equal lengths take 10 sec and 15 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction?
Choose the correct choice from the following answers: A) 65 sec B) 12 sec C) 77 sec D) 44 sec E) 11 sec

Solution: Speed of the first train = 120/10= 
120/10 = 12
12 m/sec.   Speed of the second train= 120/5 = 8 m/sec.   Relative speed = 12 + 8= 
12 + 8 = 20
20 m/sec.   Required time= (120 + 120)/20= 
(120 + 120)/20 = 12
12 sec.   Answer: 12 sec
Answer: B
John and Tony began business with Rs.12000 and Rs.14000 after 8 months, John withdraws Rs.2000 and Tony withdraws Rs.4000. At the end of the year, their profits amounted to Rs.4500 find the share of Tony.
Select the correct option.
A) 2375
B) 2325
C) 2300
D) 3375
E) 3300

Solution: (12*8 + 10*4):(14*8 + 10*4)   17:19   19/36 * 4500= 
19/36 * 4500 = 2_375
2375. 2375nswer: 2375
Answer: A
If y is the smallest positive integer such that 7,700 multiplied by y is the square of an integer, then y must be Choose the correct choice from the following:	A) 29	B) 58	C) 63	D) 74	E) 77

Solution: 7700= 5*5*2*2* 7*11= 
 7*11 = 77
77   Ans: 77
Answer: E
A completes a work in 3 days and B complete the same work in 6 days. If both of them work together, then the number of days required to complete the work will be?  Options:
A) 2 days
B) 11 days
C) 21 days
D) 22 days
E) 24 days

Solution: If A can complete a work in x days and B can complete the same work in y days, then, both   of them together can complete the work in x y/ x+ y days   Therefore, here, the required number of days = 3 Ã— 6/ 9 = 2 days.   Option '2 days'
Answer: A
The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by a young member. Find how much younger is the new member?  Choose the correct choice from the following:
A) 40  B) 50  C) 60  D) 70  E) 80

Solution: Let the members be Old Having age O + other 9 having ages x and New one having age Y   Sum of their ages = (Y + 9 × x) and average = (Y + 9 × x)/10   Before 4 years sum was (O + 9 x – 10 × 4) and average = (O + 9 x – 10 × 4) /10   equating, Y + 9 x = O + 9x – 40   Y = O – 40   Younger is 40 years younger than Old one.   40NSWER:40
Answer: A
By selling 12 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?  Choices.
A) 8	B) 7	C) 6	D) 5	E) 1

Solution: Explanation:   80% --- 12   120% --- ?     80/120 * 12= 
  80/120 * 12 = 8
8   8nswer: 8
Answer: A
To asphalt 1km road, 30 men spent 12 days working 8 hours per day. How many days, 20 men will spend to asphalt a road of 2km working 10 hours a day? Answers:  A) 28.8  B) 30  C) 32  D) 34  E) 36

Solution: Man-hours required to asphalt 1 km road=30*12*8= 
30*12*8 = 2_880
2880   Man-hours required to asphalt 2 km road=2880*2= 
2880*2 = 5_760
5760   Man-hours available per day=20*10= 
20*10 = 200
200   Therefore number of days=5760/200= 
5760/200 = 144/5 = around 28.8
28.8 days   28.8ns=28.8
Answer: A
Kiran is younger than Bineesh by 7 years and their ages are in the respective ratio of 7:9. How old is Kiran?
Answers:
A) 22.5
B) 24.5
C) 23.5
D) 25.5
E) 26.5

Solution: Let age of Kiran and 24.5ineesh be 7x and 9x respectively   7x=9x−7x=72=3.5   Kiran's age =7x=7×3.5=24.5   Answer is 24.5.
Answer: B
A can do a piece of work in 12 days. He worked for 15 days and then B completed the remaining work in 10 days. Both of them together will finish it in.	Choose the correct choice from the following options
A) 12 1/2 days
B) 10 1/2 days
C) 12 1/3 days
D) 10 1/3 days
E) 11 1/2 days

Solution: Explanation:   15/25 + 10/x = 1 => x = 25   1/25 + 1/25 = 2/25   25/2 = 12 1/2 days   12 1/2 daysnswer 12 1/2 days
Answer: A
A man took loan from a bank at the rate of 5% p.a. S.I. After 13 years he had to pay Rs. 1300 interest only for the period. The principal amount borrowed by him was? Options
A) 1750	B) 4000	C) 3500	D) 2000	E) 1000

Solution: Principal = (100 * 1300) / (5 * 13)   = Rs.2000   Answer: 2000
Answer: D
If A:B = 1/5: 1/3 B:C = 1/2:1/3 then A:B:C? Choose the correct answer
A) 9:6:6
B) 9:6:8
C) 9:6:2
D) 9:6:4
E) 9:15:10

Solution: A:B = 1/5:1/3 = 3:5   B:C = 1/2:1/3 = 3:2   --------------------   A:B:C = 9:15:10   Answer:9:15:10
Answer: E
When x is even, [x] = x/2 + 1, when x is odd [x] = 2x + 1 then [7]*[8] = ? Choices
A) [22]	B) [44]	C) [75]	D) [88]	E) [90]

Solution: [7]*[8]=(7*2+1)(8/2+1)   =[75].   Ans -[75]
Answer: C
there are two cubes with ratio between volume is 125:64. then what is the value of length of each cube?	Choose the correct choice from the following answers
A) 25:16
B) 16:25
C) 4:5
D) 5:4
E) 150:96

Solution: given   6a12:a22=150:96   then a12:a22=25:16   a1:a2=5:4   so the answer is 5:4
Answer: D
A lemonade stand sold only small and large cups of lemonade on Tuesday. 3/5 of the cups sold were small and the rest were large. If the large cups were sold for 7/24 as much as the small cups, what fraction of Tuesday's total revenue was from the sale of large cups?	Choose the correct answer:
A) (a) 7/16  B) (b) 7/15  C) (c) 10/21  D) (d) 17/35  E) (e) 7/43

Solution: This problem is very good example how easy and quick plug-in method might be.   Let the total # of cups be 10.   # of small cups sold 3/5*10= 
3/5*10 = 6
6;   # of large cups sold  10-6= 
 10-6 = 4
4;   Let the price of small cup be $6, then the price of larges cup would be 7/24*6=$7/4;   Revenue from small cups: 6*$6=$36;   Revenue from large cups cups: 4*$7/4  6* 6= 
  6* 6 = 36
$36;   Revenue from large cups cups: 4*$7/4=$7;   Fraction of total revenue from large cups: 7/(36+7) 4* 7/4= 
 4* 7/4 = 7
$7;   Fraction of total revenue from large cups: 7/(36+7)=7/43.   Answer:(e) 7/43.
Answer: E
Mark purchases a dozen items for $240.00. If Mark sells each item for $30.00 what is his markup%? Select:
A) 10	B) 50	C) 75	D) 100	E) 125

Solution: C.P.=240/12= 
240/12 = 20
20   S.P.=30   markup%=((S.P.-C.P.)/C.P.)*100=((30-20)/20)*100= 
((30-20)/20)*100 = 50
50%   ANSWER:50
Answer: B
If a particular player is always chosen, in how many ways can a cricket-be chosen out of 15 players?  Choose the correct choice from the following.
A) 1100  B) 1134  C) 1240  D) 1340  E) 1365

Solution: A particular player is always chosen, it means that 10 players are selected out of the remaining 14 players.   =. Required number of ways = 14C10 = 14C4   = 14!/4!x19! = 1365   1365
Answer: E
45 x ? = 40% of 900 Choose one
A) 16.2
B) 4
C) 5
D) 500
E) 8

Solution: Answer   Let 45 x A = (40 x 900)/100   ∴ A = (40 x 9)/45 = 8   Correct Option: 8
Answer: E
A pupil's marks were wrongly entered as 83 instead of 63. Due to that the average marks for the class got increased by half. The number of pupils in the class is :
Choose the correct option:  A) 45  B) 40  C) 39  D) 37  E) 38

Solution: Explanation:   Let there be x pupils in the class.   Total increase in marks = (x * 1/2) = x/2.   x/2 = (83 - 63) => x/2 = 20 => x = 40. Answer: 40
Answer: B
Find out the C.I on Rs.4000 at 4% p.a. compound half-yearly for 1 1/2 years	Pick one:  A) 244.83  B) 306.07  C) 306.04  D) 306.03  E) 306.01

Solution: 244.83 = 4000(51/50)3   = 4244.832   4000   -----------   244.83   244.83nswer:244.83
Answer: A
In a mixed college 160 students are there in one class. Out of this 160 students 3/5 students are girls. How many boys are there ?  Choose the correct option
A) A)40 B) B)64 C) C)80 D) D)120 E) E)140

Solution: Total Number of Students :160   Total Girls :   160*3/5= 
  160*3/5 = 96
96   Total 64oys : 160-96= 
160-96 = 64
64   Answer is 64
Answer: B
The area of the square formed on the diagonal of a rectangle as its side is 108 1/3 % more than the area of the rectangle. If the perimeter of the rectangle is 28 units, find the difference between the sides of the rectangle? Choose one:
A) 5m  B) 3m  C) 9m  D) 2m  E) 4m

Solution: Let the sides of the rectangle be l and b respectively.   From the given data,   (√l2 + b2) = (1 + 108 1/3 %)lb   => l2 + b2 = (1 + 325/3 * 1/100)lb   = (1 + 13/12)lb   = 25/12 lb   => (l2 + b2)/lb = 25/12   12(l2 + b2) = 25lb   Adding 24lb on both sides   12l2 + 12b2 + 24lb = 49lb   12(l2 + b2 + 2lb) = 49lb   but 2(l + b) = 28 => l + b = 14   12(l + b)2 = 49lb   => 12(14)2 = 49lb   => lb = 48   Since l + b = 14, l = 8 and b = 6   l - b = 8 - 6= 
8 - 6 = 2
2m.   Answer: 2m
Answer: D
100 + 50 * 2 = ?	Choices:
A) 200  B) 150  C) 100  D) 300  E) 400

Solution: Explanation:   200fter applying BOM200S rule,   First Multiplication will be done then addition   So it will be  100 + 100= 
 100 + 100 = 200
200   Option 200
Answer: A
The G.C.D. of 1.08, 0.36 and 0.8 is: Select the correct option: A) 0.04 B) 0.9 C) 0.18 D) 0.108 E) 0.118

Solution: Given numbers are 1.08, 0.36 and 0.80. H.C.F. of 108, 36 and 80 is 18,   H.C.F. of given numbers = 0.04.   0.04nswer: Option 0.04
Answer: A
If X = Y/Z, -1 < Z < 0 and 4 < Y, which of the following is correct?
Options:
A) X > 4.
B) 0 < X <4.
C) -4 < X < 0
D) X < -4.
E) X < -20

Solution: Y is +ve & Z is -ve   Eliminate A & B   For min. value max. numerator and minimize denominator   take Y=4.1 & X=-0.9   X=4.1/-0.9   X<-4   Ans X < -4.
Answer: D