MU-NLPC/Calc-aqua_rat huggingface dataset:
In August,a cricket team that played 120 matches won 22% of the games it played.After a continuous winning streak,this team raised its average to 52%.How many matches did the team win to attain this average?
Choose one:
A) 40  B) 52  C) 68  D) 75  E) 98

Solution: let the no of matches played more=x   so,   (120+x)*52/100=26.4+x   by solving we get x=75   ANSWER:75
Answer: D
What is the least number that should be added to 1055, so the sum of the number is divisible by 23?
Choices:
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: (1055 / 23) gives a remainder 20 so we need to add 3.   The answer is 3.
Answer: C
Mr. Smith calculated the average of 10three digit numbers. But due to a mistake he reversed the digits of a number and thus his average increased by 49.5. The difference between the unit digit and hundreds digit of that number is :  Choose the most appropriate option
A) a) 4
B) b) 3
C) c) 2
D) d) 1
E) e) 5

Solution: Since the average increased by 49.5 and there were a total of 10 numbers, it means the incorrect number was 495 greater than the correct number.   Say, the correct number was abc (where a, b and c are the digits of the 3 digit number)   Then the incorrect number was cba.   100c + 10b + a - (100a + 10b + c) = 495   99c - 99a = 99(c - a) = 495   495 = 99*5 = 99(c - a)   So c - a = 5   Answer (e) 5)
Answer: E
If (5 - x)/(5 + x) = x, what is the value of x^2 + 6x - 5?  Choose the most appropriate option:	A) -6	B) -4	C) -2	D) 0	E) 3

Solution: (5-x) = x*(5+x)   (5-x) = 5x+x^2   0 = x^2+6x-5   The answer is 0.
Answer: D
If x and a are integers and (15^x + 15^(x+1))/4^a = 15^a what is the value of x?
Choose the most appropriate option:
A) 2
B) 3
C) 4
D) 5
E) Cannot be determined

Solution: \frac{15^x( 1+ 15)}{4^a} = 15^a   (15^x . 4^2 ) / 4^a = 15^a. 4^0   15^x . 4^(2-a) = 15^a. 4^0   Equating the powers, x = a; 2-a = 0; So x = a = 2=2
Answer: A
If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is ?
Choose the most appropriate option.
A) 1/4  B) 1/2  C) 1/8  D) 1/6  E) 1/1

Solution: The number of exhaustive outcomes is 36.   Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2   P(E) = 1 - 1/2 = 1/2.   Answer: 1/2
Answer: B
Pointing to a girl in the photograph, Amar said, "Her mother's brother is the only son of my mother's father." How is the girl's mother related to Amar ?
Pick one:
A) Mother
B) Sister
C) Aunt
D) Grandmother
E) Brother

Solution: Explanation:   Only son of Amar's mother's father — Amar's maternal uncle.   So, the girl's maternal uncle is Arnar's maternal uncle. Thus, the girl's mother is Amar's aunt.   Answer: Aunt
Answer: C
In a shop, 40% socks are white and rest are black. 60% socks are made of cotton and rest are made of wool. 25% white socks are made of cotton and 20 of the black socks are made of wool. How many black socks C are made of cotton?
Choose the correct answer.
A) 100
B) 80
C) 60
D) 50
E) 25

Solution: I'll prefer to solve this with plug n play method.   As we know, White Cotton socks are only 25% and Total Cotton socks is 60% - Hence Black Cotton socks C has to be [highlight]HIGH[/highlight]number. Thats why we've to pick high number... say 100 or 80.   100 fits perfectly after relevant calculations. Hence answer 100.
Answer: A
The speed of a boat in still water is 80kmph and the speed of the current is 30kmph. Find the speed downstream and upstream?	Answers.
A) 76,28 kmph  B) 110,30 kmph  C) 29,25 kmph  D) 26,10 kmph  E) 12,15 kmph

Solution: Speed downstream = 80 + 30= 
80 + 30 = 110
110 kmph   Speed upstream= 80 - 30= 
80 - 30 = 50
50 kmph   Answer: 110,30 kmph
Answer: B
On flipping 3 coins together what is the outcomes for at least two heads?
Choices:  A) {HHH, HHT, HTH, THH}  B) {HHT, HHT, HTH, THH}  C) {TTH, HHT, HTH, THH}  D) {TTT, HHT, HTH, THH}  E) None

Solution: Sample space, S = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}   Favorable outcomes for at least two heads   = favorable outcomes for exactly two heads and favorable outcomes for more than two heads   = {HHH, HHT, HTH, THH}   {HHH, HHT, HTH, THH}
Answer: A
The length of a rectangular field is 7/5 its width. If the perimeter of the field is 360 meters, what is the width of the field?
Pick one.
A) 50  B) 60  C) 70  D) 80  E) 75

Solution: Let L be the length and W be the width. L = (7/5)W   Perimeter: 2L + 2W = 360, 2(7/5)W + 2W = 360   Solve the above equation to find: W = 75 m and L = 105 m.   correct answer 75)75
Answer: E
If the price of gold increases by 50%, find by how much the quantity of ornaments must be reduced, so that the expenditure may remain the same as before? Pick one:	A) 331/8%	B) 331/3%	C) 381/3%	D) 231/3%	E) 361/3%

Solution: 100   150   ------   150-------50   100-------? => 331/3%   Answer: 331/3%
Answer: B
Rs. 730 were divided among Punith, Michael, Suresh in such a way that if Punith gets Rs. 3, then Michael gets Rs. 4 and if Michael gets Rs. 3.50 then Suresh gets Rs. 3. The share of Michael exceeds that of Suresh by
Options.
A) Rs 30
B) Rs 40
C) Rs 70
D) Rs 210
E) Rs 310

Solution: Explanation :   Let A = Punith, B = Michael, C = Suresh.   A:B = 3:4 and B:C = 7/2:3 = (8/7)*(7/2)*(8/7)*3 = 4:(24/7)   A : B : C = 3 :4: 24/7 = 21 : 28 : 24.   Bs share = Rs. [730 *(28/73)]= Rs. 280.   Cs share = Rs. [730 * (24/73)] = Rs. 240.   Difference of their shares = 40   Answer : Rs 40
Answer: B
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days? Choose the correct choice from the following choices.
A) 11:54:40 AM B) 11:56:24 AM C) 12:16:40 PM D) 11:54:24 AM E) 12:06:36 PM

Solution: Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.   Clock gains: 1% in the subsequent 6 days = 1% in 6*24*60 minutes = 86.40 minute in 6 days;   Net gain in 10 days = 86.40 - 32= 
86.40 - 32 = 54.4
54.4 minutes.   11AM + 54.4 minutes= 11:54 and 4/10th of a minute or 24 seconds.   Answer: 11:54:24 AM.
Answer: D
P is three times as old as Q. In 10 years, P will be twice as old as Q. How old was P three years ago?  Answers
A) 27  B) 30  C) 33  D) 36  E) 39

Solution: P = 3Q so Q = P/3   P+10 = 2(Q+10) = 2(P/3+10)   P/3 = 10   P = 30   Three years ago, P was 27.   The answer is 27.
Answer: A
A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price? Choices
A) 17% B) 72% C) 12% D) 82% E) 16%

Solution: Original price = 100   12%P = 80   S = 80*(140/100)= 
80*(140/100) = 112
112   100 - 112= 12%   Answer:12%
Answer: C
The true discount on a bill of Rs. 2260 is Rs. 360. What is the banker's discount?	Choices
A) Rs. 428	B) Rs. 422	C) Rs. 412	D) Rs. 442	E) None of these

Solution: Explanation :   F = Rs. 2260   TD = Rs. 360   PW = F - TD = 2260 - 360 = Rs. 1900   True Discount is the Simple Interest on the present value for unexpired time   =>Simple Interest on Rs. 1900 for unexpired time = Rs. 360   Banker's Discount is the Simple Interest on the face value of the bill for unexpired time   = Simple Interest on Rs. 2260 for unexpired time   =360/1900 × 2260 = 0.19 × 2260 = Rs. 428 Rs. 428nswer : Option Rs. 428
Answer: A
If n = 20! + 19, then n is divisible by which of the following?
I. 15
II. 17
III. 19	Choose the correct choice from the following
A) I only	B) II only	C) III only	D) I and II	E) II and III

Solution: 19 divides 20! so 19 also divides 20! + 19.   15 and 17 divide 20! so they do not divide 20! + 19.   The answer is III only.
Answer: C
A can fill the tank in 28hrs
B can fill the tank in 14 hrs
and C takes 7hrs.
If all three pipes are opened simultaneously ,how long it will take to fill the tank?	Choose the correct choice from the following options:
A) 4
B) 5
C) 6
D) 7
E) 8

Solution: Solution:time taken=(28*14*7*)/(28*14 + 14*7 + 28*7)   To solve this quicker find out LCM(28,14,7)   we get 28   Time taken =28/(28/28 + 28/14 + 28/7)   =28/(1+2+4)   =28/7= 
28/7 = 4
4   4nswer 4
Answer: A
There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
Pick one:	A) 100	B) 110	C) 112	D) 115	E) 119

Solution: Let the number of students in rooms A and B be x and y respectively.   Then, x - 10 = y + 10 x - y = 20 .... (i)   and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)   Solving (i) and (ii) we get: x = 100 , y = 80.   The required answer 100 = 100.
Answer: A
Three friends (Amar, Mohan and Sham) started partnership business by investing Rs. 1,00,000, Rs. 1,40,000 and Rs. 1,60,000 respectively. After eight months, Ramesh joins them with his capital of Rs. 50,000. If, at the end of the year, a profit of Rs. 30,500 was made, what would be the difference between the shares of Sham and Mohan?	Choose the correct choice from the following answers:
A) 1464
B) 1462
C) 2679
D) 2776
E) 9782

Solution: Explanation:   Amar invests Rs. 1,00,000 for 12 months : Mohan invests Rs. 1,40,000 for 12 months : Sham invests Rs.1,60,000 for 12 months : Ramesh invests Rs. 50,000 for 4 months   1464mar : Mohan : Sham : Ramesh = 30 : 42 : 48 : 5   Sham's share = (48/125) * 30,500 = 11712   Mohan's share = (42/125) * 30,500 = 10248   Difference between shares of Sham's and Mohan's = 1464   1464NSWER: 1464
Answer: A
the total age of A and B is 12 year more than the total age of B and C. C is how many years younger than A ?	Choose the correct choice from the following choices: A) 12 B) 24 C) data inadequate D) None of these E) 34

Solution: Solution   (A + B ) - (B + C) = 12 ⇔ A - C = 12. 12nswer 12
Answer: A
Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 110 mangoes.
Choose one:	A) 367	B) 380	C) 400	D) 406	E) 412

Solution: Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 120 mangoes.   Method 1:   Let price per mango = x. Let number of mangoes be n. Then, nx = 360.   Now price = 0.9x; number of mangoes = n + 12. Total amount = 0.9x*(n+12) = 360.   nx = 0.9nx + 10.8x => 0.1nx = 10.8x => n = 108 => x = 360/108 = 3.33   Original price of 110 mangoes = 110*3.33 = 367.   367nswer 367
Answer: A
5+3+2 = 151022
9+2+4 = 183652
8+6+3 = 482466
5+4+5 = 202541
THEN ;
7+2+5 = ? Choices
A) 253547 B) 143681 C) 143547 D) 147614 E) 255547

Solution: 143547   143547
Answer: C
In a mayoral election, Candidate X received 1/4 more votes than candidate Y, and Candidate Y received 1/6 fewer votes than Z. If Z received 24,000 votes how many votes did candidate X received?
Select:
A) 18000
B) 22000
C) 24000
D) 25000
E) 32000

Solution: Z=24 --> Y received 1/4 fewer votes than Z --> Y=Z-1/6*Z=20;   X received 1/4 more votes than Y --> X=Y+1/4*Y=25.   Answer: 25000.
Answer: D
The average (arithmetic mean) of 20, 40, and 60 is 5 more than the average of 10, 70, and what number?	Choose the correct choice from the following choices
A) 15 B) 25 C) 35 D) 45 E) 55

Solution: a1 = 120/3= 
120/3 = 40
40   a2= a1 -5 = 35   sum of second list = 35*3= 
35*3 = 105
105   therefore the number= 105 -80= 
105 -80 = 25
25   ANSWER:25
Answer: B
There are, in a certain league, 8 teams, and each team face another team for a total of 12 times. How many games are played in the season?	Choose one: A) 150 B) 121 C) 144 D) 180 E) 1200

Solution: By using the formula, t[n(n - 1) / 2], where t = no. of games between two teams and n = total no. of teams, we get: 144   Option 144.
Answer: C
Six years ago I was three times as old as my brother, and now I am twice as old my brother. Find my brother's age.
Choose the most appropriate option.
A) 8 years
B) 24 years
C) 12 years
D) 16 years
E) 26 years

Solution: Let brother's age = x   And my age = 2x   6 years ago:   24 yearsrother age = x-6   My age = 2x-6   I was 3 time his age then,   2x-6 = 3(x-6)   2x-6 = 3x-18   3x-2x = 18-6= 
18-6 = 12
12   24 yearsrother's age= 12years   My age now = 2x   = 2(12)   = 24years   ANSWER:24 years
Answer: B
A and B can do a piece of work in 3 days, B and C in 4 days, C and A in 5 days. How long will C take to do it?  Select the correct option:
A) 120/7 days	B) 110/11 days	C) 100/9 days	D) 90/13 days	E) 80/3 days

Solution: 2c = 1/4 + 1/5 – 1/3 = 7/60   c = 7/120 => 120/7 days   The answer is 120/7 days.
Answer: A
In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 5 metres then what will be the area of the square so formed?	Answers: A) Cannot be determined B) 2600 cm2 C) 2500 cm2 D) 3025 cm2 E) None of these

Solution: Let the side of the square be x m.   ∴ Perimeter of the square = 48 × 5 = 4x ∴ x = 60 m   ∴ Area = (60)2 = 3600 m2   Answer None of these
Answer: E
The simple interest accrued on an amount of Rs.49500 at he end of three is Rs.17820. What would be the compound interest accured on the same amount at teh same rate in the same period? (Round off your answer to two decimal places)?	Choose the correct choice from the following answers:  A) Rs.20043.94  B) Rs.20043.97  C) Rs.20043.99  D) Rs.20043.90  E) Rs.20043.91

Solution: Let the rate of interest be R% p.a.   (49500)(3)(R)/100 = 17820   495R = 5940   R = 12   CI on Rs.49500 at 12% p.a. for three years   = 49500{[1 + 12/100]3 - 1} = 69543.936 - 49500 = Rs.20043.94   when rounded off to two decimal places.   Rs.20043.94nswer:Rs.20043.94
Answer: A
To fill a tank, 25 buckets of water is required. How many buckets of water will be required to fill the same tank if the capacity of the bucket is reduced to two-fifth of its present ? Choose the correct choice from the following options.
A) 62.5 B) 65 C) 61 D) 64 E) 60

Solution: Let the capacity of 1 bucket = x.   Then, the capacity of tank = 25x.   New capacity of bucket = 2/5 x   Therefore, Required number of buckets = (25x)/(2x/5)   = (25x) x 5/2x   = 125/2= 
125/2 = 125/2 = around 62.5
62.5   62.5nswer is 62.5.
Answer: A
In a function they are distributing noble prize. In how many ways can 3 prizes be distributed among 4 boys when No boy gets more than one prize?	Choose the correct choice from the following options
A) 16	B) 18	C) 20	D) 24	E) 26

Solution: Sol. In this case, repetitions are not allowed. So, the first prize can be given in 4 ways. The second in 3 ways and the third in 2 ways. But fundamental principle, (4 x 3 x 2) ways = 24 ways   4: Or 4p = — 4:- 4X3X2X1- 24 ways   24
Answer: D
A man borrowed Rs. 800 at 10% per annum simple interest and immediately lent the whole sum at 10% per annum compound interest. What does he gain at the end of 2 years ?	Choose the correct choice from the following choices.
A) Rs. 6
B) Rs. 8
C) Rs. 10
D) Rs. 12
E) Rs. 14

Solution: S.I FOR RS.800 FR 2 YEARS IS RS.160, WHEREAS AMOUNT IS 168 RS. HENCE GAIN IS 168-160= 
168-160 = 8
8   ANSWER:Rs. 8
Answer: B
If a and b are nonzero integers such that a = 5b/2, then each of the following must be true EXCEPT  Choose the correct choice from the following options.
A) 0 < b/a < 1  B) ab is positive.  C) On the number line, b lies between 0 and a.  D) The ratio of a to b is equivalent to 10/4.  E) a – b is positive.

Solution: This question can be solved by TESTing VALUES. Based on its wording, you would likely need to do 2 TESTs to get to the correct answer though.   We're told that A and B are NONZERO INTEGERS and that A = 5B/2 or 2A = 5B. We're told that each of the answer is always true EXCEPT for one of them...   Before we get to the actual work, it's important to note a few details:   1) We are NOT told that A and B are positive - we're just told that they're NONZERO - that's interesting - it means that we have to consider the possibility that they're both NEGATIVE...   2) 4 of the answers will always be true, while one of them will EITHER be sometimes true OR never true. We'll have to keep working until we find 1 answer that is not true (for whatever reason) - that will be the solution to this question.   Since 2A = 5B, I'm going to run 2 pairs of TESTs at the same time...   A = 5   B = 2   AND   A = -5   B = -2   Answer A: 0 < B/A < 1   2/5 and -2/-5 both = 2/5. Answer A appears true.   Answer B: AB is positive   (2)(5) and (-2)(-5) both = +10. Answer B appears true.   Answer C: B is between 0 and A on the number line   0....2....5   -5....-2....0   Answer C appears true.   Answer D: A/B = 10/4   5/2 = -5/-2   10/4 = 5/2   Answer D appears true.   Answer E: A - B is positive     5 - 2= 
  5 - 2 = 3
3   -5 - (-2)= -3 *****This is NOT always true.   Final Answer:   a – b is positive.
Answer: E
For the past n days, the average (arithmetic mean) daily production at a company was 50 units. If today's production of 90 units raises the average to 52 units per day, what is the value of n ? Answers
A) 30 B) 19 C) 10 D) 9 E) 7

Solution: (average production for n days) * n = (total production for n days) --> 50n=(total production for n days);   (total production for n days) + 90 = (average production for n+1 days) * (n+1) --> 50n + 90 = 52 * (n+1) --> n=19.   Or as 40 extra units increased the average for n+1 days by 2 units per day then 40/(n+1)=2 --> n=19.   Answer:19.
Answer: B
A dishonest dealer professes to sell his goods at Cost Price but still gets 20% profit by using a false weight. What weight does he substitute for a kilogram?
Choose the correct option.
A) 855 1/2 grams  B) 833 1/3 grams  C) 833 1/2 grams  D) 875 2/7 grams  E) 865 2/7 grams

Solution: If the cost price is Rs.100, then to get a profit of 20%, the selling price should be Rs.120.   If 120kg are to be sold, and the dealer gives only 100kg, to get a profit of 20%.   How many grams he has to give instead of one kilogram(1000 gm).   120 gm ------ 100 gm   1000 gm ------ ?   (1000 * 100)/120 = 2500/3 = 833 1/3 grams.   ANSWER:833 1/3 grams
Answer: B
Which of the following represents the profit from the investment of x dollars at n percent compound annual interest for 7 years?  Choose the most appropriate option
A) 4x (1+n/100)^6 - x  B) 5x (1+n/100)^5- x  C) 3x (1+n/100)^4 - x  D) x (1+n/100)^4 - x  E) x (1+n/100)^7 - x

Solution: Amount after 7 years compounded yearly = x (1+n/100)^7   Thus profit = Final amount - original principle = x (1+n/100)^7 - x . Answer : x (1+n/100)^7 - x
Answer: E
A starts a business with a capital of Rs. 5,000. B joins in the business with Rs.2000 after some time. For how much period does B join, if the profits at the end of the year are divided in the ratio of 3 : 1?  Choose the correct choice:
A) 5 months B) 6 months C) 7 months D) 10 months E) None of these

Solution: Explanation :   Let B joins for x months. Then   A:B = 5000*12 : x* 2000 = 3 : 1   => 5*12 : 2x= 3 : 1   => 5*12/ 2x = 3/1= 
3/1 = 3
3=> 5*4 /2x = 1   => 10/x = 1   => x = 10. Answer : Option 10 months
Answer: D
A is half good a work man as B and together they finish a job in 14 days. In how many days working alone B finish the job? Select the correct option
A) 23	B) 22	C) 21	D) 36	E) 48

Solution: 21   21   W21 = 1:2   2x + x = 1/14 => x = 1/42   2x = 1/21 => 21 days
Answer: C
Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choose the correct choice from the following choices:
A) 10.9
B) 10.7
C) 10.3
D) 10.8
E) 10.2

Solution: Relative speed = 60 + 40= 
60 + 40 = 100
100 km/hr.= 100 * 5/18 = 250/9 m/sec.   Distance covered in crossing each other = 140 + 160= 
140 + 160 = 300
300 m.   Required time= 300 * 9/250 = 54/5= 
54/5 = 54/5 = around 10.8
10.8 sec.   'Answer: 10.8
Answer: D
There has been successive increases of 20% and then 10% in the price of gas from the previous month. By what percentage should a driver reduce gas consumption so that the expenditure does not change?	Options:
A) 16%
B) 20%
C) 24%
D) 28%
E) 32%

Solution: Let P be the original price per unit of gas.   Let x be the original gas consumption.   Let y be the reduced gas consumption.   y*1.1*1.2*P = x*P   y = x / (1.1*1.2) which is about 0.76x which is a decrease of about 24%.   The answer is 24%.
Answer: C
The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 17 terms of the arithmetic progression?  Pick one:
A) 300  B) 120  C) 150  D) 170  E) 270

Solution: n th term of A.P. is given by a+(n-1)d   4 th term = a+3d   12 th term = a+11d   Given a+3d+a+11d=20 --> 2a+14d=20 --> a+7d = 10   Sum of n term of A.P = n/2[2a+(n-1)d]   subsitiuing n = 17 ...we get 17/2[ 2a + 14d] = 17 [a+7d] = 17*10 = 170...   Answer is 170...
Answer: D
What is the least number which when divided by 6, 7, 9 and 18 leaves remainder 4 in each care?  Choose the correct answer
A) 130  B) 140  C) 136  D) 156  E) 166

Solution: Explanation:   LCM of 6, 7, 9 and 18 is 126   Required number = 126 + 4= 
126 + 4 = 130
130   130nswer: Option 130
Answer: A
If x, y, and z are consecutive positive integers greater than 1, not necessarily in that order, then which of the following is (are) true?
I. x > z
II. 2(x+ y) > 2z
III. yz > xz
IV. xy > y + z  Select:
A) I only B) II only C) II and III only D) II and IV only E) III and IV only

Solution: we do not know the values or the relative values but that the three are consecutive..   so the max difference in any two number is 2 and min 1..   lets see the choices..   I. x > z...   we do not know the values or the relative values... need not be true..   II. 2(x+ y) > 2z or x+ y > z   we take the worst case that z is teh largest and x and y are lowest possible..... so 2+3>4.. 5>4.. always true   III. yz > xz   we do not know the values or the relative values between x and y..need not be true   IV. xy > y + z   xy-y>z or y(x-1)>z...   again lets take the worst scenario..   we take the worst case that z is the largest and x and y are lowest possible..... so (2-1)3>4.. 3>4.. not true   only ii is true   ans II only
Answer: B
If Rs 1050 is divided into three parts, proportional to (1 / 3) : (3 / 4) : ( 4 / 6), then what is the first part?  Answers:
A) 500
B) 300
C) 200
D) 100
E) 150

Solution: EXPLANATION:   Given:   1050 =	1/3	:	3/4	:	4/6   1) L.C.M. of 3, 4 and 6 is 12   Therefore, multiply numerator and denominator of (1/3) with 4, to obtain denominator 12. Similarly multiply (3/4) with 3 and (4/6) with 2   4/12	:	9/12	:	8/12 = 4 : 9 : 8   2) If a number a is divided in three ratios x : y : z,   First Part:	ax/(x + y + z) ------- (a is the number divided)   Therefore,   First Part:	(1050 x 4) /(4 + 9 + 8)=200   ANSWER IS 200
Answer: C
A charity collected $1,499 from donors during the last month. If each donor gave at least $20, what is the greatest possible number of donors the charity could have?	Pick one
A) 77  B) 78  C) 79  D) 74  E) 65

Solution: Min fund = 20   Total = 1499   The closest multiple of 20 to 1499 is : 73   Which implies 73 people gave 20 and 1 person gave 39   Ans. 74
Answer: D
A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Pick one:
A) 299
B) 200
C) 240
D) 111
E) 161

Solution: Speed = [54 * 5/18] m/sec = 15 m/sec.   Length of the train = (15 * 20)= 
(15 * 20) = 300
300 m.   Let the length of the platform be x meters.   Then, x + 300 / 36= 15   x + 300 = 540   x = 240 m. Answer:240
Answer: C
Find the invalid no.from the following series 3, 7, 15, 27, 63, 127, 255
Pick
A) 3	B) 15	C) 27	D) 127	E) 255

Solution: Go on multiplying the number by 2 and adding 1 to it to get the next number.So, 27 is wrong.   27
Answer: C
If the number 52,1n6, where n represents the tens digit, is a multiple of 3, then the value of n could be which of the following? Answers:
A) 6	B) 5	C) 3	D) 4	E) 0

Solution: The sum of the digits 5 + 2 + 1 + n + 6 must be a multiple of 3   14 + n must be a multiple of 3   substituting the numbers n must = 4   Answer 4
Answer: D