MU-NLPC/Calc-aqua_rat huggingface dataset:
In a can, there is a mixture of milk and water in the ratio 4:3. If the can is filled with an additional 10 liters of milk, the can would be full and the ratio of milk and water would become 5:2. Find the capacity of the can?  Choices
A) 24
B) 26
C) 28
D) 30
E) 32

Solution: Let C be the capacity of the can.   (4/7)*(C-10)+10=(5/7)*C   4C-40+70=5C   C=30   The answer is 30.
Answer: D
The effective annual rate of interest corresponding to a nominal rate of 10% per annum payable half-yearly is?  Choose the most appropriate option.
A) 10.06% B) 10.25% C) 10.35% D) 16.09% E) 16.19%

Solution: Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 5/100)2] = Rs. 110.25 Effective rate = (110.25 - 100)= 
(110.25 - 100) = 10.25
10.25%   ANSWER:10.25%
Answer: B
A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it
Choose the correct answer: A) 40days B) 35days C) 30days D) 25days E) 10days

Solution: Explanation:   Suppose B takes x dáys to do the work.   As per question A will take   2∗3 /4∗x=3x /2days   (A+B)s 1 days work= 1/18   1/x + 2/3x = 1/18 or x = 30 days   Option 30days
Answer: C
In 150 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by:	Choose the correct choice from the following options: A) 20 m B) 25 m C) 22.5 m D) 9 m E) 30 m

Solution: Distance covered by B in 9 sec. =	150/45 x 9	m = 30 m.   A beats B by 30 metres.   Answer: Option 30 m
Answer: E
If a quarter kg of potato costs 60 paise, how many paise will 200gm cost ?
Select the correct option:
A) 45 paise
B) 46 paise
C) 47 paise
D) 48 paise
E) None of these

Solution: Explanation:   Quarter of Kg means 250 gm   Less weight, less price (Direct Proportion)   So,   250:200::60:x=>x=200∗60/ 250=>x=48   So 200 gm will cost 48 paise.   Option 48 paise
Answer: D
Find the odd man out. 15, 25, 30, 51, 85, 90, 115  Choose the correct option
A) 15  B) 25  C) 51  D) 90  E) 91

Solution: Explanation :   All except 51 are multiples of 5. Answer : Option 51
Answer: C
Find the area of a parallelogram with base 12 cm and height 48 cm? Choose the correct answer
A) 122 cm2 B) 576 cm2 C) 246 cm2 D) 42 cm2 E) 39 cm2

Solution: Area of a parallelogram   = base * height   = 12 * 48= 
12 * 48 = 576
576 cm2   Answer: 576 cm2
Answer: B
A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3840. They completed the work in 3 days with the help of C. How much is to be paid to C?	Select the correct option:
A) s. 380 B) s. 600 C) s. 420 D) s. 400 E) s. 480

Solution: s. 480xplanation :   Amount of work A can do in 1 day = 1/6   Amount of work B can do in 1 day = 1/8   Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24   Amount of work A + B + C can do = 1/3   Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24   work A can do in 1 day: work B can do in 1 day: work C can do in 1 day   = 1/6 : 1/8 : 1/24 = 4 : 3 : 1   Amount to be paid to C = 3840 × (1/8) = 480   Answer : Option s. 480
Answer: E
lexus car agency has 216 cars.he sold some cars at 9% profit and rest at 36% profit thus he gains 17% on the sale of all his cars.the no. of cars sold at 36% profit is?	Choose the correct choice:
A) 36 B) 64 C) 38 D) 39 E) 40

Solution: ratio of 36% profit cars to 9% profit cars = 8:19   so no. of cars sold at 36% profit = 216*8/27= 
216*8/27 = 64
64 cars   ANSWER:64
Answer: B
Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 63 more. What was his original selling price?	Choices:
A) $770  B) $660  C) $700  D) $990  E) $840

Solution: Let the original purchase price be X   So original selling price at 10% profit = 1.1X   If product is purchased at 10% less of original = 0.9X   Profit of 30% on this price = 1.3(0.9X)   He would have received $63 more in second scenario => 1.3(0.9X) - 1.1X = 63   => 0.07X = 63   => X = $900   Original purchase price = $900   Hence, original selling price (at 10% of profit) = 1.1(900) = $990   Option $990
Answer: D
Joe needs to paint all the airplane hangars at the airport, so he buys 360 gallons of paint to do the job. During the first week, he uses 1/2 of all the paint. During the second week, he uses 1/5 of the remaining paint. How many gallons of paint has Joe used?	Choose the correct answer
A) 18  B) 144  C) 175  D) 216  E) 250

Solution: Total paint initially = 360 gallons   Paint used in the first week = (1/2)*360= 
(1/2)*360 = 180
180 gallons.   Remaning paint= 180 gallons   Paint used in the second week = (1/5)*180= 
(1/5)*180 = 36
36 gallons   Total paint used= 216 gallons.   Option 216
Answer: D
For dinner, Sue ate 360 grams of fruit which was five times as much fruit as she ate for lunch, and three times as much fruit as she ate for breakfast. How much fruit did Sue eat in total?  Pick:
A) 552
B) 560
C) 568
D) 576
E) 584

Solution: For breakfast, Sue ate 360 / 3= 
360 / 3 = 120
120 grams.   For lunch, Sue ate 360 / 5= 
360 / 5 = 72
72 grams.   For dinner, Sue ate 360 grams.   The total is  120 + 72 + 360= 
 120 + 72 + 360 = 552
552 grams.   The answer is 552.
Answer: A
60 percent of Andrea's living room floor is covered by a carpet that is 4 feet by 9 feet. What is the area of her living room floor?  Choose the correct answer
A) 14.4 B) 180/7 C) 50.4 D) 60 E) 90

Solution: 60% of Area of the floor = 4*9= 
4*9 = 36
36 square feet   i.e. 100% Area of Floor= (36/60)*100= 
(36/60)*100 = 60
60 square feet   Answer: Option 60
Answer: D
If a wagon wheel had 10 more spokes, the angle between them would decrease by 6 degrees. Can you identify the number of spokes in the wheel?  Choose the correct choice from the following:
A) 20 spokes
B) 10 spokes
C) 30 spokes
D) 15 spokes
E) 25 spokes

Solution: 20 spokes   20 spokes   360/S = 20 spokes   360/(S +10) = 20 spokes – 6   Thus there are 20 spokes in the wheel.
Answer: A
(5!+6!+4!)/4!*0!*5*6=?
Choose one:
A) 4/5 B) 6/5 C) 5/6 D) 4/3 E) 9/8

Solution: 4!(5+30+1)/4!*1*5*6   36/30=6/5   answer 6/5
Answer: B
Three unbiased coins are tossed. What is the probability of getting 1 heads, 1 Tail? Choose the correct choice from the following options:  A) 3/4  B) 1/4  C) 3/8  D) 7/8  E) 2/8

Solution: Let, H --> Head , T --> Tail   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let 2/8 = event of getting 3 heads   Then 2/8 = {THT, HTH}   P(2/8) = n(2/8)/n(S) =2/8   Answer is 2/8
Answer: E
In how many ways can 5 boysand 2 girls be arranged at a table if 2 girls are never together?
Choose one:
A) 250 B) 256 C) 350 D) 360 E) 480

Solution: Total ways of arranging 7 person in a circle = 6! = 720 ways   If we consider two women as one, then we have   5+1= 
  5+1 = 6
6 persons. Arranging these six persons in circle will take= 5! = 120 ways   And two women can arrange themselves in 2! ways   Total ways in which two women sit together in circle = 5!*2! = 240 ways   Total ways in which two women doesn’t sit together in circle = 6! - 5!*2! = 720 - 240= 
720 - 240 = 480
480 ways   480
Answer: E
Aman started a business investing Rs. 70,000. Rakhi joined him after six months with an amount of Rs.. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business? Options.
A) 7 : 6 : 10
B) 12 : 15 : 16
C) 42 : 45 : 56
D) 12 : 18 : 26
E) Cannot be determined

Solution: Aman : Rakhi : Sagar =(70,000 x 36):(1,05,000 x 30):(1,40,000 x 24) = 12 : 15 : 16.   Answer: Option 12 : 15 : 16
Answer: B
Andrew started saving at the beginning of the year and had saved $150 by the end of the year. He continued to save and by the end of 2 years had saved a total of $540. Which of the following is closest to the percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year?
Choose the correct choice from the following answers:
A) 11%
B) 25%
C) 44%
D) 56%
E) 125%

Solution: Percent increase in the amount Andrew saved during the second year compared to the amount he saved during the first year.   Percentage Change = ( Change in value / Original value ) * 100   Percentage Change = [ (Saving in 2nd year - Saving in 1st year ) / Saving in 1st year ] * 100   Saving in 2nd year + Saving in 1st year = 540   Saving in 2nd year + 150 = 540   Saving in 2nd year = 540 - 150= 
540 - 150 = 390
390   Change in Value= 390 - 150= 
390 - 150 = 240
240   Original Value= 160   Percentage Increase = (160 / 150 ) * 100 = 160% ..... Answer 125%......
Answer: E
A can do a piece of work in 80 days. He works at it for 10 days & then B alone finishes the remaining work in 42 days. In how much time will A and B, working together, finish the work?	Choose the correct option.
A) 23 days	B) 25 days	C) 30 days	D) 33 days	E) 35 days

Solution: Work done by A in 10 days=10/80=1/8   Remaining work=(1-(1/8))=7/8   Now, work will be done by B in 42 days.   Whole work will be done by B in   (42*8/7)= 
  (42*8/7) = 48
48 days   Therefore, A's one day's work=1/80   B’s one day's work=1/48   (A+B)'s one day's work=1/80+1/48=8/240=1/30   Hence, both will finish the work in 30 days.   Answer : 30 days.
Answer: C
which number need to add to 859622 to get a number exactly divisible by 456?  Choices.
A) 389999  B) 543248  C) 798790  D) 795320  E) 859622

Solution: Dividend = Quotient * Divisor + Reminder   859622 / 456 gives quotient = 1885 and reminder = 62.   So, the next number divisible by 456 is 456 places infront of 456 * 1885   Which means 456 – 62 = 394 should be added to 859622.   859622
Answer: E
A thief steals at a car at 2.30 p.m. and drives it at 60 km/hr. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 km/hr. When will he overtake the thief?	Pick one:
A) 2 p.m  B) 6 p.m  C) 5 p.m  D) 7 p.m  E) 9 p.m

Solution: Suppose the thief is overtaken x hrs after 2.30 p.m.   Then, distance covered by the owner in (x - 1/2) hrs.   60x = 75(x - 1/2) => x = 5/2 hrs.   So, the thief is overtaken at 5 p.m.   Answer:5 p.m
Answer: C
X and Y run a 200 m race,where X beats Y by 20 m. To do a favor to Y, X starts 20 m behind the starting line in a second 200 m race. Both run at the same previous speed. Which of the following is true?  Options:
A) X Beats Y by 2m
B) Y Beats X by 10m
C) Y Beats X by 11m
D) Y Beats X by 1m
E) Y Beats X by 11m

Solution: Let's suppose that the speed of X is 20m/s and that the speed of Y is 18m/s.   So, in the first race, the results are the following:   X crosses the finish line in 10s. In other words, X has run 200m in 10 s.   In 10s, Y has run 180 meters.   Therefore, there is the difference of 20 meters mentioned in the question.   Now, let's review the second race.   In 11 seconds, X can complete the 200 meters race. We have to remember that X is 20 meters behind the starting line.   But in 11 seconds, Y has covered (180+18)= 
(180+18) = 198
198 meters. Also, it is important to notice that in 11 seconds Y cannot arrive to the finish line.   So, 200 - 198= 2 meter   X Beats Y by 2mnswer: X Beats Y by 2m
Answer: A
If x and y are unique prime integers, which of the following must be odd?
Choose the correct choice from the following answers:	A) xy^2	B) 2x+2y	C) 2x−2y	D) 2x/2y	E) x−y

Solution: Any number multiplied by 2 has to be an even number hence   Answer x−y
Answer: E
Tough and Tricky questions: Combinations.
The product of the digits of the four-digit number h is 48. No two digits of h are identical. How many different numbers are possible values of h? Choose the correct choice from the following answers.
A) 6 B) 12 C) 24 D) 36 E) 42

Solution: Answer = 24 = 24   Let number =abcd   Given that a*b*c*d = 48   a,b,c,d can be 1,2,3,8   Number of ways = 4*3*2= 
4*3*2 = 24
24
Answer: C
The cost price of a radio is Rs.1500 and it was sold for Rs.1230, find the loss %?  Choose the correct answer: A) 18% B) 19% C) 78% D) 48% E) 11%

Solution: 1500 ---- 270   100 ---- ? => 18%   18%nswer: 18%
Answer: A
What is (19^7+19) / 19? Answers.
A) 45225766 B) 46855821 C) 47045882 D) 48925947 E) 49325989

Solution: (19^7+19) / 19 =   19*(19^6+1) / 19 =   19^6 + 1   Clearly this is a number which ends with a 2 in the units place.   The answer is 47045882.
Answer: C
Rs.1500 is divided into two parts such that if one part is invested at 6% and the other at 5% the whole annual interest from both the sum is Rs.87. How much was lent at 5%?
Choose the correct option:	A) 388	B) 2998	C) 277	D) 300	E) 271

Solution: (x*5*1)/100 + [(1500 - x)*6*1]/100 = 87   5x/100 + 90 – 6x/100 = 87   x/100 = 3   => x = 300.Answer: 300
Answer: D
What is the % profit or loss, if the cost price of 4 mangoes is equal to the selling price of 9 mangoes?
Options:
A) 75.6%	B) 13.6%	C) 54.6%	D) 55.6%	E) 51.6%

Solution: Let the cost price of 1 mangoes be Rs 1   Cost of 9 mangoes = Rs 9   Selling price of 9 mangoes = 4   Gain/loss = 9 - 4= 
9 - 4 = 5
5   %=5/9âˆ—100= 55.6   Answer: 55.6%
Answer: D
The sum of two numbers is 30 and their difference is 10. Find their product.  Pick one
A) 104 B) 114 C) 315 D) 200 E) 335

Solution: Let the numbers be x and y.   Then x + y = 30 and x - y = 10   x = 20; y = 10   xy = 20 * 10= 
20 * 10 = 200
200   ANSWER:200
Answer: D
If (x + yi) / i = ( 7 + 9i ) , where x and y are real, what is the value of (x + yi)(x - yi)?	Choose the correct option:	A) 110	B) 120	C) 130	D) 140	E) 150

Solution: (x + yi) / i = ( 7 + 9i )   (x + yi) = i(7 + 9i) = -9 + 7i   (x + yi)(x - yi) = (-9 + 7i)(-9 - 7i) = 81 + 49= 
81 + 49 = 130
130   130ORRE130T ANSWER IS 1300130
Answer: C
How many of the following numbers are divisible by 132?
264, 396, 462, 792, 968, 2178, 5544, 6336
Choose the correct answer:	A) 4	B) 5	C) 6	D) 7	E) 8

Solution: A number is divisible by 132, if it is divisible by each one of 11, 3 and 4.   Clearly, 968 is not divisible by 3. None of 462 and 2178 is divisible by 4.   Each one of remaining 5 is divisible by each one of 11, 3 and 4 and therefore, by 132.   ANSWER:5
Answer: B
What decimal fraction is 20 ml of a litre ?	Choose one
A) .2	B) 0.002	C) .05	D) .02	E) None of these

Solution: Answer   Required fraction = 20/1000   = 2/100= 
2/100 = 1/50 = around 0.02
.02   Correct Option: .02
Answer: D
A crate of mangoes contains one bruised mango for every thirty mango in the crate. If three out of every four bruised mango are considerably unsaleble and there are 10 unsaleable mangoes in the crate then how msny mango are there in the crate? Choices
A) 100 mangoes	B) 110 mangoes	C) 120 mangoes	D) 130 mangoes	E) 125 mangoes

Solution: 100 mangoes   100 mangoesNSWER:100 mangoes
Answer: A
A can finish a work in 18 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day  Choose the correct option.
A) 1\5  B) 1\6  C) 1\7  D) 1\8  E) 1\9

Solution: Explanation:   Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question   So lets solve now,   A's 1 day work = 1/18   B's 1 day work = 1/9 [because B take half time than A]   (A+B)'s one day work =   (1/18+1/9)   =(1+2 /18)=1/6   So in one day 1/6 work will be done.   Option 1\6
Answer: B
A train moves fast a telegraph post and a bridge 264 m long in 8 sec and 20 sec respectively. What is the speed of the train? Pick
A) 22.3 km/hr B) 22.9 km/hr C) 29.2 km/hr D) 79.2 km/hr E) 19.2 km/hr

Solution: Let the length of the train be x m and its speed be y m/sec.   Then, x/y = 8 => x = 8y   (x + 264)/20 = y   y = 22   Speed = 22 m/sec = 22 * 18/5= 
22 * 18/5 = 396/5 = around 79.2
79.2 km/hr.   Answer:79.2 km/hr
Answer: D
If Q is a positive integer, and Q/15 = 8.2, what is the remainder when Q is divided by 15?
Choose the correct choice from the following answers
A) A.1	B) B.2	C) C.3	D) D.4	E) E.8

Solution: If Q were a multiple of 15, the quotient Q/15 would be an integer. The fact that it's a decimal tells us that 15 goes into Q eight whole times and some decimal part of a time. This decimal part, 0.2 is the remainder divided by the divisor. Let R be the remainder.   R/15 = 0.2 = 1/5   R = (15)*(1/5)= 
(15)*(1/5) = 3
3   Answer=(C.3)
Answer: C
If 2a = 4b = 10, then 40ab = Select the correct option: A) 50 B) 100 C) 250 D) 450 E) 500

Solution: 2a * 4b = 10 * 10= 
10 * 10 = 100
100   8 ab= 100   i.e. 40 ab = 500   Answer: Option 500
Answer: E
If 35 percent of 400 is 20 percent of x, then x =  Choose the correct answer.
A) 200	B) 350	C) 700	D) 900	E) 1,400

Solution: 5/100(400) = 2/10(x)   X = 700..   ANSWER:700
Answer: C
The following sets each have a mean of 10 and the standard deviations are given in variable form.
Set I = {10, 10, 10, 10, 10, 10}, standard deviation = P
Set II = { 7, 8, 9, 11, 12, 13}, standard deviation = R
Set III = {6, 6, 6, 14, 14, 14}, standard deviation = Q
Rank these three standard deviations from least to greatest.
Options
A) P, Q, R  B) P, R, Q  C) R, Q, P  D) Q, R, P  E) R, Q, P

Solution: SD is minimum when the terms are closer to the mean.   In set 1, we have all terms equal to mean. hence, its SD is 0.(The Lowest)   Comparing Set 2 and Set 3, Set 2 has terms more closer to mean than set 3. hence, Set 3 Sd is the highest.   So, Answer is R, Q, P
Answer: C
In a race with 20 competitors, the first-place finisher receives a gold medal, the second-place finisher receives a silver medal, and the third-place finisher receives a bronze medal. If there are no ties, in how many different ways may these three medals be awarded? Choose the correct choice.
A) 35	B) 120	C) 720	D) 840	E) 6,840

Solution: Well in this case since there are 3 positions and they can be taken by 3 persons only ,so order matters over here .For gold there are 20 choices ,for silver 19 remain (one who got gold cannot be given silver) and for bronze 18 choices remain.   So total possibilities=20*19*18   Correct answer 6,840=6,840
Answer: E
What percent is 400 gm of 1 kg?  Choose the correct choice from the following options:
A) 25% B) 40% C) 10% D) 8% E) 12%

Solution: 1 kg = 1000 gm   400/1000 Ã— 100 = 40000/1000= 
40000/1000 = 40
40 %   Answer is 40%
Answer: B
Three photographers, Lisa, Mike and Norm, take photos of a wedding. The total of Lisa and Mikes photos is 70 less than the sum of Mike's and Norms. If Norms photos number 10 more than twice the number of Lisa's photos, then how many photos did Norm Take?	Choose the correct answer.
A) 40 B) 50 C) 60 D) 80 E) 130

Solution: L+M=M+N-70 / N=2L+10   70=M+N-L-M   70=N-L   70=2L+10-L   60=L   2(60)+10=130   130
Answer: E
The timing of a college is from 12 p.m to 4.00 p.m. Five lectures are held in the given duration and a break of 5 minutes after each lecture is given to the students. Find the duration of each lecture.  Select:
A) 52 minutes
B) 45 minutes
C) 30 minutes
D) 48 minutes
E) 44 minutes

Solution: Explanation:   Total time a student spends in college = 4 hours 00 minutes = 240 minutes   As there are 5 lectures, the number of breaks between lectures is 4. Total time of the break = 20 minutes   Hence, the duration of each lecture is = (240 â€“ 20)/5   = 44 minutes   ANSW44 minutesR 44 minutes
Answer: E
If pq = p + q^2 – 2pq, for what value of q is pq equal to p for all values of p? Choose the correct option:	A) -2	B) -1	C) 1	D) 0	E) 2

Solution: C   p + q2 â€“ 2pq = p   => q2 - 2= 
2 - 2 = 0
0=> q (q - 2p) = 0   => q = 0 or q = 2p   im not following the logic you used here.. how did you replace pq with 0 could someone help explain it in MORE 0ETAI   0
Answer: D
A women sells 3 different size(in kgs) packs of sugar which are multiples of 1.A person who buys sugar should buy all types of packs.4 different people buys 20,21,23,29 kgs .what will the maximum and minimum amounts a person can buy?? Answers
A) 22  B) 33  C) 34  D) 54  E) 85

Solution: packet are 11,6 and 7   7+7+6= 
7+7+6 = 20
20   7+7+7= 
7+7+7 = 21
21   6+6+11= 
6+6+11 = 23
23   7+11+11= 
7+11+11 = 29
29   and min   6+6+6= 
  6+6+6 = 18
18   and max   11+11+11= 
  11+11+11 = 33
33   ANSWER:33
Answer: B
A fence consists of m lengths of fence that are each n feet long. A fence post separates each length of fence by its width of x feet. What is the total length Q of the fence including the fence posts on each end?
Choose the correct choice from the following answers: A) mn B) m(n + x) C) Q=m(n + x) + x D) m(n + x) + 2x E) 2mn

Solution: Notice that since a fence post separates each length of fence, then there will be m+1 posts, for example if there are m=2 fences, then there will be 3 posts: PFPFP. Thus the total length of the posts is (m+1)x.   The total length Q of the fence is mn, therefore the total length of the fence including the fence posts on each end is (m+1)x+mn=mx+x+mn=m(n+x)+x.   Answer: Q=m(n + x) + x.
Answer: C
At the end of the month, a certain ocean desalination plant’s reservoir contained 6 million gallons of water. This amount is twice the normal level. If this amount represents 60% of the reservoir’s total capacity, how many million gallons short of total capacity is the normal level?	Choose the correct answer
A) 15	B) 10	C) 5	D) 20	E) 25

Solution: the Q talks of total capacity, normal level, present level, shortage etc..   so it is all about not going wrong in these terms   6 MG= 60% of Total..   total = 6/.6= 
6/.6 = 10
10MG..   Normal level= 1/2 of 10=5MG..   shortage of normal level=10-5= 
10-5 = 5
5MG..   5
Answer: C
What least no. must be subtracted from 5026 so that remaining no.is divisible by 5? Choices.
A) 3  B) 4  C) 5  D) 6  E) 1

Solution: 1xplanation:   On dividing 5026 by 5 we get the remainder 1, so 1 should be subtracted   Option 1
Answer: E
A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women in 10 days. It
can be done by 9 men and 15 women in how many days ?
Choose the most appropriate option
A) 3 days  B) 4 days  C) 5 days  D) 6 days  E) None of these

Solution: Explanation:   To calculate the answer we need to get 1 man per day work and 1 woman per day work.   Let 1 man 1 day work =x   and 1 woman 1 days work = y.   => 6x+5y = 1/6   and 3x+4y = 1/10   On solving, we get x = 1/54 and y = 1/90   (9 men + 15 women)'s 1 days work =   (9/54) + (15/90) = 1/3   9 men and 15 women will finish the work in 3 days   3 daysnswer: 3 days
Answer: A
A man can row at 4 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?  Choose the correct option:
A) 2.4 km
B) 2.9 km
C) 3.4 km
D) 1.9 km
E) 5.6 km

Solution: Explanation:   Speed in still water = 4 kmph   Speed of the current = 1 kmph   Speed downstream = (4+1)= 
(4+1) = 5
5 kmph   Speed upstream= (4-1)= 
(4-1) = 3
3 kmph   Let the required distance be x km   Total time taken= 1 hour   â‡’ x/5+x/3=1   â‡’3x+5x=15   â‡’8x=15   â‡’x=1.9 km   Answer: Option 1.9 km
Answer: D