MU-NLPC/Calc-aqua_rat huggingface dataset:
Machines P and Q are two different machines that cover jars in machine shop. When Machine P works alone, it covers 5 jars in m hours. When Machines P and Q work simultaneously at their respective rates, they cover 5 jars in n hours. In terms of m and n, how many hours does it take Machine Q, working alone at its constant rate, to cover 5 jars?  Select:
A) m B) n C) m+n D) 5n/25-mn E) m-n

Solution: working rate p = 5/m ; working rate pq =( 1/p +1/q)* n =5 or mn/5 +n/q =5 0r n/q = 5-mn/5 = 25-mn/5   q = 5n/25-mn   5n/25-mn
Answer: D
Free notebooks were distributed equally among children of a class. The number of notebooks each child got was one-eighth of the number of children. Had the number of children been half, each child would have got 16 notebooks. Total how many notebooks were distributed ? Choose the correct answer:
A) 412
B) 512
C) 312
D) 112
E) 122

Solution: Let total number of children be x.   Then, (x) x 1/8x = (x/2)x 16   = x = 64.   Number of notebooks = 1/8 x2 = (1/8	x 64 x 64)	= 512.   Answer is 512.
Answer: B
A man sells two articles for Rs.2850 each and he gains 32% on the first and loses 18% on the next. Find his total gain or loss?	Choose the correct choice from the following options: A) 9%loss B) 2%loss C) 7%loss D) 6%loss E) 1%loss

Solution: Explanation:   (32*18)/100   = 6%loss   Answer:6%loss
Answer: D
The perimeter of a square is 48 m. Find the area of the square.  Choose the most appropriate option
A) 161 mÂ². B) 144 mÂ². C) 166 mÂ². D) 169 mÂ². E) 273 mÂ².

Solution: Perimeter of square = 48 m   But perimeter of square = 4 Ã— side   Therefore, 4 Ã— side = 48 m   Therefore, side= 48/4= 
48/4 = 12
12m   Now, the area of the square= (side Ã— side)   Therefore, area of the square = 12 Ã— 12 mÂ² = 144 mÂ².   ANSWER : OPTION 144 mÂ².
Answer: B
In a division sum, the divisor is ten times the quotient and five times the remainder. If the remainder is 48, the dividend is: Choose the correct choice from the following.
A) 5336
B) 5340
C) 5342
D) 5345
E) 5808

Solution: Divisor = (5 * 48)= 
(5 * 48) = 240
240= 10 * Quotient = Divisor   => Quotient = 240/10= 
240/10 = 24
24   Dividend= (Divisor * Quotient) + Remainder   Dividend = (240 * 24) + 48= 
(240 * 24) + 48 = 5_808
5808   5808
Answer: E
Five bells first begin to toll together and then at intervals of 5, 10, 15, 20 and 25 seconds respectively. After what interval of time will they toll again together?  Choose the correct option.
A) 5 min B) 5.5 min C) 5.2 min D) 6.2 min E) None

Solution: LCM = 300/60= 
300/60 = 5
5 min   5 minNSWER:5 min
Answer: A
As x increases from 131 to 132, which of the following increases?
I) x−1/x
II) 17−1/x
III) (17+x)/x
Choose the correct choice from the following choices:
A) I only B) II only C) I,II only D) II,III only E) III only

Solution: On Increasing the value of x from 131 to 132   I) x−1/x will increase as 1/x will be very small and x will increase by 1 unit   II) 17−1/x Will Increase as the value of 1/x will decrease thereby increasing the value of 17-(1/x)   III) (17+x)/x = (17/x)+1 will Decrease as 1/x will decrease thereby decreasing the value of (17/x)   Answer:I,II only
Answer: C
16 men can complete a piece of work in 25 days. In how many days can 20 men complete that piece of work?	Select the correct option:
A) 27
B) 29
C) 20
D) 22
E) 12

Solution: 16 * 25 = 20 * x => x = 20 days   Answer:20
Answer: C
You have a rock solid dark chocolate bar of size 2 x 8. You need to break it and get 1 x 1 pieces of that chocolate.
If you can break that bar only along its length or breadth, how many times will you have to break to get the 1 x 1 pieces?	Choose the correct choice from the following
A) 12 times.
B) 13 times.
C) 14 times.
D) 15 times.
E) 16 times.

Solution: Solution:   There is a simple logic to solve this question.   The size of the chocolate is 2 x 8. Thus, you need to have 2 x 8 = 16 pieces.   Every time you break the chocolate, you will get one extra piece.   Thus, to get 16 pieces, you must break it  (16 - 1)= 
 (16 - 1) = 15
15 times.   Answer 15 times.
Answer: D
The price of an item is discounted 5 percent on day 1 of a sale. On day 2, the item is discounted another 10 percent, and on day 3, it is discounted an additional 15 percent. The price of the item on day 3 is what percentage of the sale price on day 1?
Pick one: A) 28% B) 40% C) 64.8% D) 76.5% E) 78%

Solution: Let initial price be 1000   Price in day 1 after 5% discount = 950   Price in day 2 after 10% discount = 855   Price in day 3 after 15% discount = 726.75   So, Price in day 3 as percentage of the sale price on day 1 will be = 726.75/950*100= 
726.75/950*100 = 76.5
> 76.5%   Answer will definitely be (76.5%)
Answer: D
A and B started a partnership business investing some amount in the ratio of 7 : 5. C joined then after six months with an amount equal to that of B. In what proportion should the profit at the end of one year be distributed among A, B and C?	Pick:
A) 4 : 9 : 8 B) 5 : 7 : 4 C) 6 : 10 : 5 D) 14 : 10: 5 E) 5 : 4 : 8

Solution: Let the initial investments of A and B be 7x and 5x.   A : B : C = (7x x 12) : (5x x 12) : (5x x 6) = 84 : 60 : 30   = 14 : 10 : 5.   ANSWER :14 : 10: 5
Answer: D
6 people meet for a business gathering. Each person shakes hands once with each other person present. How many handshakes take place? Options.
A) 30 B) 21 C) 18 D) 15 E) 10

Solution: Let's look at the logic.   Every person shakes hand with other '5'. So, 6 people shake hands with 6X5= 30 people   But in this 30 we have counted two times the total handshakes (m shakes hand with n and n shakes hand with m)   So just divide 30/2= 
30/2 = 15
15 total handshakes   Answer is 15
Answer: D
Find a two digit number, given that the sum of the digits is 9 and the difference of the digits is 3.? Pick one
A) 75  B) 63  C) 83  D) 94  E) 39

Solution: Using elimination method find which of the options fit the description of the number   ... from the option only 63 meets this description   sum of digits---6+3 = 9   difference of digits ---6-3 = 3   Answer 63.
Answer: B
If 20% of 30 is greater than 25% of a number by 2, the number is:  Select:
A) 16
B) 24
C) 20
D) 32
E) None of these

Solution: Explanation :   =>20/100 * 30 - 25/100 * x = 2   => x/4 = 4 so x = 16   16nswer : 16
Answer: A
8 liters of solution is removed from 20% milk solution and 8 liters of water is added to the solution. The resulting solution has 16% milk in it. What was the initial quantity of the 20% milk solution?  Answers
A) 40 Ltrs
B) 50
C) 60
D) 70
E) 80

Solution: Allegation method.   Concentration of 40 Ltrslcohol in original sol - 20%   Concentration of 40 Ltrslcohol in water -- 0%   Concentration of 40 Ltrslcohol in final sol -- 16%   40 Ltrsfter applying allegation as shown in figure they have to be mixed in 4:1 part   1 part is given as 8 ltr, so total initial volume is 5 part = 5*8= 
5*8 = 40
40 Ltrs   40 LtrsNSWER:40 Ltrs
Answer: A
A person can row at 10 kmph in still water. If the velocity of the current is 2 kmph and it takes him 30 hour to row to a place and come back, how far is the place?
Choose the most appropriate option.
A) 144km B) 30km C) 48km D) 12km E) 15km

Solution: Speed of down stream = 10+2= 
10+2 = 12
12kmph   speed of upstream= 10-2= 
10-2 = 8
8kmph   Let the required distance be xkm   x/12 + x/8= 30   2x+3x = 720   x = 144 km   144kmnswer is 144km
Answer: A
What will be the ratio of simple interest earned by certain amount at the same rate of interest for 5 years and that for 15 years?
Choose the correct choice from the following answers:
A) 3 : 2 B) 1 : 3 C) 2 : 3 D) 3 : 1 E) 2 : 1

Solution: Explanation :   Simple Interest = PRT/100   Here Principal(P) and Rate of Interest (R) are constants   Hence, Simple Interest ∝ T   Required Ratio = Simple Interest for 5 years/Simple Interest for 15 years   =T1/T2   =5/15   =1/3   =1:3   Answer : Option 1 : 3
Answer: B
Which of the following cannot be the range of a set consisting of 5 odd multiples of 11? Choose the correct choice from the following answers:
A) 44
B) 88
C) 45
D) 176
E) 352

Solution: Solution: sequence of 11 lets say sequence is 11n, 11(n+1), 11(n+2), 11(n+3), 11(n+4)   so range is 11n+44-11n = 44   if we put the different values of n we will get different but the range will be multiple of 44   and only 45 is not multiple of 44   Answer : 4511 +44-11= 
11 +44-11 = 44
44   if we put the different values of n we will get different but the range will be multiple of 44   and only 45 is not multiple of 44   Answer : 45
Answer: C
A new tower has just been built at the Verbico military hospital; the number of beds available for patients at the hospital is now 2 times the number available before the new tower was built. Currently, 1/3 of the hospital's original beds, as well as 1/5 of the beds in the new tower, are occupied. For the purposes of renovating the hospital's original wing, all of the patients in the hospital's original beds must be transferred to beds in the new tower. If patients are neither admitted nor discharged during the transfer, what fraction of the beds in the new tower will be unoccupied once the transfer is complete?	Answers.
A) 11/30  B) 29/60  C) 17/30  D) 19/30  E) 7/15

Solution: I think E - 7/15 is the correct answer.   Here goes:   Lets assume originally the number of beds = x   After the new tower, the total combined no of beds = 2x   So old = x, New = x   Now 1/3 of x are occupied and 1/5 of x are occupied which simplifies to (1/5)x   We are shifting 1/3 of x to the new ward so there will now be:   1/3 of x plus 1/5 of x occupied in the new ward. Add them up to get 8/15 of x   There are x beds in New Tower so ratio is:   (8/15)x / x = 8/15 of x   Subtract that from 15/15 of x and you get the number of un-occupied beds to total capacity of New Towerb=7/15.   7/15
Answer: E
If p is a positive integer and 10p/96 is an integer, then the minimum number of unique prime factors p could have is B:
Choose the most appropriate option:
A) B=1  B) B=2  C) B=3  D) B=4  E) B=5

Solution: 10p/96 should resolve to a integer => 5p/48 should resolve to an integer.   Hence p/48 should resolve to a integer.   48 -- > 2^4 * 3.   Hence p should have atleast 2^4*3 for p/48 to resolve to a int.   The unique prime factors in 2^4 * 3 is 2, 3 and hence the answer is B=2(2).
Answer: B
George baked a total of 150 pizzas for 7 straight days, beginning on Saturday. He baked 3/5 of the pizzas the first day, and 3/5 of the remaining pizzas the second day. If each successive day he baked fewer pizzas than the previous day, what is the maximum number of pizzas he could have baked on Wednesday?
Options:
A) 5 B) 6 C) 4 D) 3 E) 2

Solution: 3/5 of the 150 pizzas cooked on Saturday = 90 pizzas   3/5 of the remaining pizzas on Sunday = 36 pizzas   We're left with   (150-90-36)= 
  (150-90-36) = 24
24 pizzas for the remaining 5 days. The prompt tells us that each day has FEWER pizzas than the day before it, so we can't have duplicate numbers.   M T W TH F   8 7 6 2 1=24   W =6   6
Answer: B
Of the people who responded to a market survey, 200 preferred Brand X and the rest preferred Brand Y. If the respondents indicated a preference for Brand X over Brand Y by ratio of 4 to 1, how many people responded to the survey? Choose the correct choice from the following choices.
A) 80 B) 160 C) 250 D) 350 E) 480

Solution: Ratio = 4:1 => 4x respondents preferred Brand X and x preferred Brand Y   Since, no. of respondents who preferred Brand X = 200 => 4x=200 => x=50   Hence Total no. of respondents = 200 + 50= 
200 + 50 = 250
250   Hence 250 is the answer.
Answer: C
A wheel makes 1000 revolutions in covering a distance of 88 km. Find the radius of the wheel.	Options:
A) 14	B) 11	C) 28	D) 26	E) 18

Solution: Explanation:   Distance covered in one revolution = = 88m.   14nswer: 14) 14
Answer: A
In a group of 800 people, 1/5 play at least one instrument, 128 play two or more. What is the probability that one student play exactly one instrument?  Choose one:  A) 2/125  B) 3/125  C) C)2/25  D) 3/25  E) 1/25

Solution: P(playing 2 or more instruments) = 128/800 = 4/25.   Then, the probability of playing exactly one instrument is given by:   P(playing 1 or more instruments) - P(playing 2 or more instruments) = 1/5 - 4/25 = 1/25.   Answer 1/25.
Answer: E
P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 2 days. How many days more will P take to finish the work?	Choose one
A) 10  B) 15  C) 42  D) 20  E) 22

Solution: Let work done by P in 1 day = p,   Work done by Q in 1 day = q,   Work done by R in 1 day = r   p + q = 1/30   q + r = 1/24   r + p = 1/20   Adding all the above, 2p + 2q + 2r = 1/30 + 1/24+ 1/20 = 15/120 = 1/8   => p + q + r = 1/16   => Work done by P,Q and R in 1 day = 1/16   Work done by P, Q and R in 2 days = 2 × (1/16) = 2/16 = 1/8   Remaining work = 1 = 1/8 = 7/8   Work done by P in 1 day = Work done by P,Q and R in 1 day - Work done by Q and R in 1 day   = 1/16 – 1/24 = 1/48   Number of days P needs to work to complete the remaining work = (7/8) / (1/48)= 
(7/8) / (1/48) = 42
42   Option 42
Answer: C
Kim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Kim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Kim will win?	Choose the correct choice from the following:
A) 5/6 B) 2/3 C) 1/2 D) 5/12 E) 1/3

Solution: 1/3   probability of kim winning is basically the sum of three probabilities:   probability of kim picking rock and renee picking scissors = 1/3*1/3 = 1/9   probability of kim picking scissors and renee picking paper = 1/3*1/3=1/9   probability of kim picking paper and renee picking rock = 1/3*1/3=1/9   1/9 + 1/9 + 1/9 = 3/9 = 1/3=1/3
Answer: E
If a computer program generates three-digit odd numbers using the numbers 9, 7, 0, 4, and 1, and the digits can be repeated, what is the probability that the number formed from the program is a multiple of three?
A. B.
C.
D.
E. Answers
A) 1/2
B) 1/3
C) 1/5
D) 1/6
E) 1/7

Solution: 1) Lets first find TOTAL ways..   a) first/leftmost digit can be any of 5 except 0, so 4 ways   b) middle digit can be any of the 5. so 5 ways   c) the units digit can be ONLY odd- 1,7, and 9- so 3 ways   TOTAL = 4*5*3= 
4*5*3 = 60
60 ways   2) lets now find multiple of 3..   a) Digits not div by 3   7,4 and 1 will each leave remainder of 1 so they can be grouped together to form multiples of 3..   first place - 3 ways, second digit - 3 ways, and units digit ONLY 1 and 7 - 2ways   Total ways= 3*3*2= 
3*3*2 = 18
18   b) digits div by 3   9 and 0- No other digit can be used along with them as no other pair gives us sum of remainder as 3..   first place - 1 way, second digit - 2 ways, and units digit ONLY 9 - 1 way   Total ways= 1*2*1= 
1*2*1 = 2
2   TOTAL= 2+18= 
2+18 = 20
20   Prob=2060=132060=13   ANSWER:1/3
Answer: B
The expression x#y denotes the product of the consecutive multiples of 3 between x and y, inclusive. What is the sum of the exponents in the prime factorization of 21#42?
Options.
A) 23	B) 24	C) 25	D) 26	E) 27

Solution: 21#42   = 21*24*27*30*33*36*39*42   = 3^11 * 7^2 * 2^7 * 5^1 * 11^1 * 13^1   so total is = 11+2+7+1+1+1= 
11+2+7+1+1+1 = 23
23   23nswer 23
Answer: A
two watches (non- digital) one gained at the rate of 1 minute and the other lost at the rate of 1 minute daily were se correctly at noon on first january 1988. when will the watches indicate the same time next ? Choose the most appropriate option.
A) dec 27 1988 noon B) dec 27 1988 midnight C) dec 26 1988 noon D) dec 25 1988 noon E) dec 25 1988 midnight

Solution: every day clock1 is getting one minute gain means it will gain 12 hours lead on 25 dec & similarly every day clock2 is getting one minute loss means it will loss 12 hours lead on 25 dec.   Now from above analysis both the clock will display the same time at dec 25 midnight.   ANSWER:dec 25 1988 noon
Answer: D
The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero ?	Choose the correct choice from the following.
A) 0 B) 9 C) 8 D) 7 E) 6

Solution: Average of 20 numbers = 0.   Sum of 20 numbers = (0 * 20)= 
(0 * 20) = 0
0.   It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (- a).   0nswer: 0
Answer: A
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period(in years) is?	Pick one
A) 2
B) 7
C) 8
D) 6
E) 9

Solution: Explanation:   Amount = (30000 + 4347) = Rs. 34347   Let the time be n years. Then,   30000(1 + 7/100)n = 34347   = (107/100)n = 34347/30000 = (107/100)2   n = 2 years.   2nswer:2
Answer: A
The time taken by Mr.Dhoni to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 72 kmph, find the speed of the stream? Pick one:
A) 24 kmph  B) 25 kmph  C) 26 kmph  D) 30 kmph  E) 28 kmph

Solution: The ratio of the times taken is 2:1.   The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1)= 
(2+1)/(2-1) = 3
3/1= 
3/1 = 3
3:1   Speed of the stream= 72/3= 
72/3 = 24
24 kmph.   24 kmphnswer: 24 kmph
Answer: A
P software has coding line 5% more than N, N software has coding line 1/2 more than M. M software has 100 lines of coding. find P lines.	Options:
A) 106  B) 107  C) 108  D) 109  E) 158

Solution: M s/w has 100 line of code   N s/w has = 100+100*1/2= 
100+100*1/2 = 150
150 line of code   P s/w 5% more N' code 150+7.5= 
150+7.5 = 157.5
157.5   or   158 line of code   ANSW158R:158
Answer: E
A dishonest dealer professes to sell goods at the cost price but uses a weight of 850 grams per kg, what is his percent?
Choose the correct choice from the following answers:
A) 28%
B) 25%
C) 55%
D) 17.6%
E) 55%

Solution: 850 --- 150   100 --- ? => 17.6%   Answer: 17.6%
Answer: D
Can you deduce the pattern and find the next number in the series?
3, 24,81, 192, __?
Choose the correct choice from the following choices
A) 276	B) 277	C) 278	D) 279	E) 375

Solution: Solution:   375   375xplanation:   3 = 1^1^1 + 1^1^1 + 1^1^1   24 = 2^2^2 + 2^2^2 + 2^2^2   81 = 3^3^3 + 3^3^3 + 3^3^3   192 = 4^4^4 + 4^4^4 + 4^4^4   Thus the next number will be   375 =5^5^5 + 5^5^5 + 5^5^5   Answer 375
Answer: E
Of 200 people surveyed, 80 percent own a cellular phone and 45 percent own a pager. If all 200 people surveyed own a cellular phone, or a pager, or both, what percent of those surveyed either do not own a cellular phone or do not own a pager? Choose the correct choice from the following choices.
A) 35%	B) 45%	C) 55%	D) 65%	E) 75%

Solution: Straight forward answer if you follow 2x2 matrix method.. :)   cell , not cell   Pager - - 90   N. pag - - 110   160 40 200   Required = 110+90 = 150   therefore, 150/200 = 75%.   Answer: 75%
Answer: E
Two goods trains each 820 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?  Choose the correct choice from the following: A) 228 B) 27.32 C) 76.6 D) 78.72 E) 21

Solution: Relative speed = 45 + 30= 
45 + 30 = 75
75 km/hr.   75 * 5/18= 125/6 m/sec.   Distance covered = 820 + 820= 
820 + 820 = 1_640
1640 m.   Required time= 1640 * 6/125= 
1640 * 6/125 = 1_968/25 = around 78.72
78.72 sec.   Answer:78.72
Answer: D
A car is traveling 54 kilometers per hour. How many meters does the car travel in one minute?	Choose one.
A) 1,250 meters / minute  B) 1,350 meters / minute  C) 900 meters / minute  D) 950 meters / minute  E) 1,650 meters / minute

Solution: 900 meters / minuteonvert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify   54 kilometers per hour = 54 km/hr   = (54 * 1000 meters) / (60 minutes) = 900 meters / minute   correct answer 900 meters / minute
Answer: C
Find the face value of 7 in 942756	Options.
A) 7	B) 700	C) 7000	D) 70000	E) 70

Solution: Face value is the value of digit itself   face value of 7 = 7   7nswer : 7
Answer: A
The mean of 50 observations is 100. But later he found that there is decrements of 13 from each observations. what is the the updated mean is ?  Choose the correct choice from the following options:  A) 87  B) 97  C) 67  D) 57  E) 46

Solution: 87   87nswer is 87
Answer: A
What is the probability that the sum of two numbers that are selected randomly from a set of numbers will be greater than 6 if the given set is {2,4,6}
Choose the correct answer.
A) 5/3 B) 1/7 C) 1/2 D) 1/4 E) 1/3

Solution: First problem is 3C2 = 6 .. Not 20..   Point 2, your sum should be greater than 6, so these are the following possibilities you have   ({2,6},{4,6}) which leads to 2 pairs   So the probability is 2 on 6 or 1/3..   ANSW1/3R:1/3
Answer: E
The tax on a commodity is diminished by 20% and its consumption increased by 15%. The effect on revenue is?  Pick one
A) 7% decrease	B) 8% decrease	C) 9% decrease	D) 6% decrease	E) 4% decrease

Solution: 100 * 100= 
100 * 100 = 10_000
10000   80 * 115= 
80 * 115 = 9_200
9200   -----------   10000-----------800   100-----------?=> 8% decrease   Answer: 8% decrease
Answer: B
If goods be purchased for Rs.840 and one-fourth be sold at a loss of 20% at what gain percent should the remainder be sold so as to gain 20% on the whole transaction? Choose the correct choice from the following options:
A) 33 1/8% B) 33 7/3% C) 33 1/3% D) 33 8/3% E) 32 1/3%

Solution: 1/4 33 1/3%P = 210 SP = 21*(80/100) = 168   SP = 840*(120/100)= 
840*(120/100) = 1_008
1008   1008 - 168= 
1008 - 168 = 840
840   3/4 SP= 630   Gain = 210   630 --- 210   100 --- ? => 33 1/3%   Answer: 33 1/3%
Answer: C
Two-third of a positive number and 64/216 of its reciprocal are equal. The number is:	Options:
A) 5/12
B) 12/5
C) 25/144
D) 2/3
E) 146/25

Solution: Let the number be x. Then,   2/3 x = 64/216 * 1/x   x2 = 64/216 * 3/2 = 64/144 = 4/9   x = 2/3   ANSWER:2/3
Answer: D
In 1986 the book value of a certain car was 2/3 of the original price, and in 1988 its book value was 1/2 of the original purchase price. By what percent did the book value for this car decre ase from 1986 to 1988?
Select the correct option
A) 16 2/3 %	B) 25 percent	C) 33 1/3 %	D) 50%	E) 75%

Solution: 1986; 2/3   1988; 1/2   % decrease = change/original * 100   2/3−1/2 / 2/3∗100   1/6∗3/2∗100=14∗100=25   Answer: "25 percent"
Answer: B
In how many ways can the letters of the word, ‘TECHNOLOGY’ be arranged? Choose the correct choice from the following options.
A) 1804400
B) 1814400
C) 1714400
D) 1704400
E) 1724400

Solution: The word ‘TECHNOLOGY’ contains 10 letters namely 2O, 1T, 1E, 1C, 1H, 1N, 1L, 1G, 1Y.   Therefore, Required number of ways= 10!/(2!)(1!) (1!) (1!) (1!) (1!) (1!) (1!) (1!)   = 10! / 2!   = 10*9* 8*7*6*5*4*3*2*1/2*1= 
10*9* 8*7*6*5*4*3*2*1/2*1 = 1_814_400
1814400   ANSWER:1814400
Answer: B
A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?
Select the correct option
A) 45	B) 60	C) 75	D) 90	E) 105

Solution: Let number of notes of each denomination be x.   Then x + 5x + 10x = 480   16x = 480   x = 30.   Hence, total number of notes = 3x = 90.   Answer = 90
Answer: D
If f(x) = 3x^4 - 4x^3 - 2x^2 + 5x , then f(-1) =	Choose the correct answer.
A) -4  B) -2  C) 0  D) 2  E) 4

Solution: f(-1) = 3(-1)^4 - 4(-1)^3 - 2(-1)^2 + 5(-1) = 3+4-2-5= 
3+4-2-5 = 0
0   The answer is 0.
Answer: C
The speed of the boat in still water in 12 kmph. It can travel downstream through 45 kms in 3 hrs. In what time would it cover the same distance upstream?
Choose the correct answer:
A) 6 hours
B) 5 hours
C) 9 hours
D) 15 hours
E) 23 hours

Solution: Speed of the boat in still water = 12 km/hr   Speed downstream = 45⁄3 = 15 km/hr   Speed of the stream = 15-12= 
15-12 = 3
3 km/hr   Speed upstream= 12-3= 
12-3 = 9
9 km/hr   Answer is 5 hours   Time taken to cover 45 km upstream= 45⁄9 = 5 hours
Answer: B