MU-NLPC/Calc-aqua_rat huggingface dataset:
By selling 50 meters of cloth. I gain the selling price of 15 meters. Find the gain percent? Pick one:
A) 42 6/4%  B) 42 9/7%  C) 42 2/7%  D) 42 6/7%  E) 42 6/8%

Solution: SP = CP + g   50 SP = 50 CP + 15 SP   35 SP = 50 CP   35 --- 15 CP gain   100 --- ? => 42 6/7%   Answer: 42 6/7%
Answer: D
Two vessels having volumes in the ratio 3:5 are filled with water and milk solutions. The ratio of milk and water in the two vessels are 3:1 and 6:4 respectively. If the contents of both the vessel are empties into a larger vessel, find the ratio of milk and water in the larger vessel.  Select:
A) 26:11
B) 23:11
C) 21:11
D) 24:11
E) 25:11

Solution: Vessel A = 300 gallons --> milk = 225, water = 75;   Vessel B = 500 gallons --> milk = 300, water = 200;   Vessel A + B = 800 gallons --> milk = 525, water 275   The ratio =525/275 -->21:11   Answer: 21:11
Answer: C
How many two digit numbers of distinct digits can be formed by using digits 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 9?
Options
A) 2
B) 3
C) 4
D) 5
E) 6

Solution: CONCEPT: A number will be divisible by 9 if sum of all the digits of the number is divisible by 9   Here the Possible sum of the two distinct digits can be 9 only in order to satisfy the given condition   If sum of Digits = 9, No. = 27, 36, 45, 54, 63, 72 --- 6 Cases   Answer: option 6
Answer: E
The G.C.D. of 1.08, 0.36 and 0.9 is: Choose the correct answer.
A) 0.03
B) 0.9
C) 0.18
D) 0.2
E) 0.21

Solution: Given numbers are 1.08, 0.36 and 0.90.   H.C.F. of 108, 36 and 90 is 18,   H.C.F. of given numbers = 0.18.   Answer: Option 0.18
Answer: C
Set A: {1, 3, 4, 6, 9, 12, 16}
If three numbers are randomly selected from set A without replacement, what is the probability that the sum of the three numbers is divisible by 4? Choose the most appropriate option:
A) 3/14  B) 2/7  C) 9/14  D) 5/7  E) 1/35

Solution: using probability you can solve: 3/7*2/6*1/5=1/35.   Ans 1/35
Answer: E
There are 12 pieces of radioactive metal K that look identical. 11 of the pieces give the same radiation count when measured, the 12th piece is a counterfeit and gives a different radiation level, which may be more or less than the other 11. We are given a radiation scale, which can take 2 sets of samples and compare their added up radiation levels to tell us if the sums are the same or if different, which set has the higher level of radiation. What is the minimum number of comparisons we need on this scale to identify the counterfeit sample and to also determine whether it has more or less radiation than the other samples ?  Pick one:  A) 2  B) 3  C) 4  D) 5  E) 6

Solution: First of all if you are down to just 3 pieces and you know that if the offending piece is less or more active, then it takes exactly 1 measurement to find out the offending piece. So you know you have to reduce the problem to three.   Now when you are down to either A or B after measurement 1, you need the next measurement to (a) reduce the problem set to 3 and (b) to know whether anser is more or less. Now you cannot compare a group of 4 to 4, as in the best case it will only reduce the problem to 4 elements which is not good enough.   If you have to choose a set of 3 to compare, you cannot pick any 3 on the same side from the same set (A or B) because if you do this, a quick check will show you that in every choice there is a case where you can only get down to 4 elements. Eg. If you weighed {1,2,3} v/s {5,9,10} and they were equal you're problem would only reduce to {4,6,7,8}   The easiest way to solve this then is to compare 3 to 3, and make sure each side has elements from both AB such that whatever the measurement outcome in the worst case the problem reduces to 3 elements only. Which is why the sets {1,5,9} and {2,6,7} OR {A,B,C}{A,B,B}. The extra element from C is just taken to make the problem symmetric so to say, we have 8 elements and we make it 9, to compose 3 sets of 3 each.=3
Answer: B
The unit digit in the product 1457*7863*4575*9719 is? Pick one
A) 5  B) 1  C) 2  D) 3  E) 4

Solution: Unit digit in the given product = unit digit in 7*3*5*9 = 5   5nswer is 5
Answer: A
A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5.4 hours, then the distance covered at 40 kmph is	Choose the correct choice from the following
A) 130 km	B) 120km	C) 100km	D) 140km	E) 148

Solution: Let the partial distance covered at 40 kmph be X   Let the another partial distance covered at 60 kmph be (250 - x)   Thus, x/40 - (250 - x)/60 = 5.4   or, x/40 + (250 - x)/60 = 5.4   or, (3x + 500 - 2x)//120 = 5.4   or 500 + x = 648   x=148   ANSW148R:148
Answer: E
The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 39 degrees. Find the temperature on Friday?  Choose the correct choice:
A) 65 degrees  B) 73 degrees  C) 31 degrees  D) 34 degrees  E) 74 degrees

Solution: M + Tu + W + Th = 4 * 48= 
4 * 48 = 192
192   Tu + W + Th + F= 4 * 46= 
4 * 46 = 184
184   M= 39   Tu + W + Th = 192 -39= 
192 -39 = 153
153   F= 184 – 153 = 31   Answer:31 degrees
Answer: C
The distance from City A to City B is 150 miles. While driving from City A to City B, Cara drives at a constant speed of 30 miles per hour. Dan leaves City A 90 minutes after Cara. What is the minimum constant speed in miles per hour that Dan must exceed in order to arrive in City B before Cara?
Select the correct option
A) 42.85  B) 44  C) 46  D) 48  E) 50

Solution: The time it takes Cara to drive to City B is 150 / 30= 
150 / 30 = 5
5 hours.   Dan needs to take less than 3.5 hours for the trip.   Dan needs to exceed a constant speed of 150 / 3.5= 42.85 miles per hour.   The answer is 42.85.
Answer: A
Two pipes A and B can separately fill a tank in 2 minutes and 15 minutes respectively. Both the pipes are opened together but 4 minutes after the start the pipe A is turned off. How much time will it take to fill the tank?	Choose one:
A) 17 min
B) 10 min
C) 90 min
D) 18 min
E) 20 min

Solution: 4/12 + x/15 = 1   x = 10   Answer: 10 min
Answer: B
The number of bacteria in a petri dish increased by 50 percent every 2 hours. If there were 108 million bacteria in the dish at 4: 00 p.m., at what time were there 32 million bacteria in the dish?  Choose the correct option:
A) 6: 00 p.m.	B) 8: 00 p.m.	C) 6: 00 a.m.	D) 8: 00 a.m.	E) 10: 00 a.m.

Solution: Given:   The number of bacteria in a petri dish increased by 50 percent every 2 hours   There were 108 million bacteria in the dish at 2: 00 p.m   Since the bacteria is increasing by 50% every 2 hours, this means that the number is multiplied by 1.5 every 2 hours.   Required: At what time were there 32 million bacteria in the dish?   Assume that there were n intervals of 2 hours between 32 million and 108 million.   32 * (1.5)^n = 108   (3/2)^n = 108/32 = 27/8 = (3/2)^3   Hence n = 3 intervals.   Each interval was of 2 hours. Therefore, the number of hours = 6   Subtracting 6 hours from 4 PM, we get 10 AM as the answer.   Option 10: 00 a.m.
Answer: E
Three interviewers, E, F, and G are interviewing 40 applicants. Only with three interviewers' admission can an applicant be admitted. If interviewer E admitted F applicants, G admitted 17 applicants, and C admitted 20 applicants, at least how many applicants get the admission?	Choose one:
A) 12 B) 2 C) 6 D) 8 E) 0

Solution: If E admitted 15 are overlapping with F admission of 17 But G does not overlap with anybody.   Then no student will get nod from all the 3.   Hence 0 student will get admission.   Answer : 0
Answer: E
There were 36,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold 7 times as many paperback copies as hardback copies were sold. If a total of 441,000 copies of the novel were sold in all, how many paperback copies were sold?	Choices:
A) 45,000 B) 360,000 C) 354,300 D) 392,000 E) 396,900

Solution: Say x was the # of hardback copies sold from the time the first paperback copy was sold.   Then the total # of paperback copies sold was 9x;   Hence the total # of copies sold was (hardback)+(paperback)=(36+x)+(7x)=441 --> x=50.6.   So, the total # of paperback copies sold was 7x=7*50.6=354.3 or 354,300.   Answer: 354,300.
Answer: C
Anil can do a work in 15 days while Sunil can do it in 25 days. How long will they take if both work together?	Choose the correct choice from the following answers:  A) 9 3/9  B) 9 3/7  C) 9 3/8  D) 9 3/2  E) 9 3/1

Solution: 1/15 + 1/25 = 8/75   75/8 = 9 3/8 days   Answer:9 3/8
Answer: C
A glass was filled with 24 ounces of water, and 0.06 ounce of the water evaporated each day during a 12-day period. What percent of the original amount of water evaporated during this period?
Choose the correct choice from the following options:
A) 0.003%
B) 0.03%
C) 3%
D) 2%
E) 30%

Solution: In 12 days 12*0.06= 
12*0.06 = 0.72
0.72 ounces of water evaporated, which is 0.72/24âˆ—100=3 of the original amount of water.   Answer: 3%.
Answer: C
Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 40 pages per hour. If Tom starts reading a novel at 4:30, and Jan begins reading an identical copy of the same book at 5:20, at what time will they be reading the same page? Choose one.
A) 9:30  B) 9:00  C) 8:40  D) 7:50  E) 7:00

Solution: Relative speed =jan - Tom =10 pages per hour = 1/6 page per minute   time diff =50 minutes   by the time Jan started ToM already finished   (30/60)*50= 
  (30/60)*50 = 25
25 pages   time taken= 25 /(1/6) =25*6= 
25*6 = 150
150 minutes=7:50   ANSWER:7:50
Answer: D
If the sum of the 4th term and the 12th term of an arithmetic progression is 30, what is the sum of the first 15 terms of the progression?
Select the correct option:
A) 250
B) 275
C) 260
D) 225
E) 230

Solution: 4th term + 12th term = 30   i.e., (a+3d)+(a+11d) = 30   Now, Sum of first 15 terms = (15/2) * [2a + (15-1)d]   = (15/2) * [2a + 14d]   = (15/2) * 30 --------------- From (1)   =225   Answer : 225
Answer: D
four children, Arya, Betsy, Chen, Daniel, Emily, and Franco, are to be seated in a single row of six chairs. If Betsy cannot sit next to Emily, how many different arrangements of the six children are possible? Pick one.
A) 24  B) 480  C) 540  D) 720  E) 840

Solution: Since it is more time consuming and error prone to find ways Betsy and E not sitting together, It is better we find ways in which they will be together and then subtract from total ways..   total ways = 6!..   ways B and E will be sitting together..   take both B and E as one, then these two together with other 4 can sit in 5! ways ...   Also B and E can sit within themselves in 2! ways..   so the answer required = 6!-2*5!=24..   ans 24
Answer: A
An engineer designed a ball so that when it was dropped, it rose with each bounce exactly one-half as high as it had fallen. The engineer dropped the ball from a 20-meter platform and caught it after it had traveled 59.4 meters. How many times did the ball bounce? Choose the correct choice from the following answers:
A) 5 B) 6 C) 7 D) 8 E) 9

Solution: Ans: 6   Division of total diatance travelled will be 20+20+10+5+2.5+1.25+0.6 ANS 6
Answer: B
Jonathan’s grandparents lend $20,000 to Jonathan at a simple annual interest rate of 10%. He pays them back 5 years later. How much do they receive? Select:
A) 20,000∗0.1^5  B) 20,000∗1.5  C) 20,000∗0.5  D) 20,000∗1.1^5  E) (20,000∗0.1)^5

Solution: if you are like me and have used S.I = P x R x T formula in school, then while the question is asking for Amount in 5 years. so (20,000∗1.5) 20,000∗ 1.5   Ans : 20,000∗1.5
Answer: B
Find the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1:2?
Choose the correct answer.
A) 1:2 B) 2:3 C) 2:9 D) 2:1 E) 2:2

Solution: 1:2   1:2nswer: 1:2
Answer: A
Look at this series: 42, 36, 39, __, 42, 45, 42, 48, ... What number should fill the blank?
Choices:	A) 40	B) 48	C) 46	D) 42	E) 52

Solution: 42   42   In this series, 3 is added to the previous number; the number 42 is inserted as every third number.
Answer: D
A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?  Pick.
A) 126 ways	B) 516 ways	C) 154 ways	D) 108 ways	E) 145 ways

Solution: The boy can select one trouser in nine ways.   The boy can select one shirt in 12 ways.   The number of ways in which he can select one trouser and one shirt is   9 * 12= 
  9 * 12 = 108
108 ways.   Answer: 108 ways
Answer: D
A sum of Rs. 2665 is lent into two parts so that the interest on the first part for 8 years at 3% per annum may be equal to the interest on the second part for 3 years at 5% per annum. Find the second sum?	Choose the correct answer:
A) 2888
B) 2677
C) 2998
D) 1640
E) 1987

Solution: (x*8*3)/100 = ((2665 - x)*3*5)/100   24x/100 = 39975/100 - 15x/100   39x = 39975 => x = 1025   Second sum = 2665 – 1025 = 1640   Answer:1640
Answer: D
A pharmaceutical company received $5 million in royalties on the first $25 million in sales of generic equivalent of one of its products and then $10 million in royalties on the next $100 million in sales. By approximately what percent did the ratio of royalties to sales decrease from the first $25 million in sales to the next $100 million in sales?	Choose the correct choice from the following choices.
A) 50%
B) 65%
C) 70%
D) 75%
E) 80%

Solution: change in ratio of royalties to sales = 5/25 -10/100 = 1/10   % decrease = (1/10)/(5/25) *100= 
(1/10)/(5/25) *100 = 50
50%   50%nswer: 50%)
Answer: A
A certain rectangular crate measures 20 feet by 20 feet by 20 feet. A cylindrical gas tank is to be made for shipment in the crate and will stand upright when the crate is placed on one of its six faces. What should the radius of the tank be if it is to be of the largest possible volume? Choose the correct option:
A) 4
B) 5
C) 6
D) 8
E) 10

Solution: For max volume of cylinder (pi*r^2*h) we need to max out r^2*h. We don't know what the dimensions of the crate refer to. . Therefore for max vol base should be 20x20 i.e. of radius   20/2= 
  20/2 = 10
10   10
Answer: E
The sector of a circle has radius of 21 cm and central angle 45o. Find its perimeter?
Choose the most appropriate option.
A) 91.5 B) 92 C) 93 D) 94 E) 58.5

Solution: Perimeter of the sector = length of the arc + 2(radius)   = (45/360 * 2 * 22/7 * 21) + 2(21)   = 58.5 cm   Answer: Option 58.5
Answer: E
Fidget Spinners are sold in packages of four or seven only at the corner shop. If Borris bought 98 Fidget Spinners exactly, what could be the number of larger packs Borris bought?
Choose the correct option.
A) 5
B) 9
C) 8
D) 7
E) 10

Solution: Let number of packs of four = f   let number of packs of seven = s   4f + 7s = 98   Now , we need to test for values of s .   Since sum 98 is even and 4f will always be even, 7s must also be even.   Now , we can test for values = 8 and 10   7*10 + 4*7 = 70 + 28= 
70 + 28 = 98
98   Answer 10
Answer: E
If the annual rate of simple interest increases from 10% to 12 1/2 %, a man's yearly income increases by Rs. 1250. His principal in Rs. is?  Choose the correct choice from the following answers:	A) 34377	B) 50000	C) 777768	D) 2777	E) 27811

Solution: Let the sum be Rs. x. Then,   (x * 25/2 * 1/100) - (x * 10 * 1)/100 = 1250   25x - 20x = 250000   x = 50000   Answer: 50000
Answer: B
How many cuboids of length 5 m, width 3 m and height 2 m can be farmed from a cuboid of 12 m length, 14 m width and 10 m height.	Choose one
A) 82 B) 56 C) 80 D) 56 E) 100

Solution: (12 Ã— 14 Ã— 10)/(5 Ã— 3 Ã— 2) = 56   Answer is 56.
Answer: B
The length of rectangle is thrice its breadth and its perimeter is 104 m, find the area of the rectangle?
Choose the correct choice from the following options:
A) 507 sq m  B) 356 sq m  C) 452 sq m  D) 428 sq m  E) 525 sq m

Solution: 2(3x + x) = 104   l = 39 b = 13   lb = 39 * 13= 
39 * 13 = 507
507   507 sq mNSWER:507 sq m
Answer: A
Two trains are running in opposite directions with the same speed. If the length of each train is 180 m and they cross each other in 12 sec, then the speed of each train is?
Choices
A) 54  B) 26  C) 36  D) 99  E) 27

Solution: Let the speed of each train be x m/sec.   Then, relative speed of the two trains = 2x m/sec.   So, 2x = (180 + 180)/12 => x = 15   Speed of each train = 15 m/sec.   = 15 * 18/5= 
15 * 18/5 = 54
54 km/hr.   54nswer: 54
Answer: A
Which of the following numbers has more than two distinct prime factors?  Choose the correct answer:  A) 385  B) 422  C) 425  D) 471  E) 500

Solution: 385=5*7*11   422=2*211   425=5^2*17   471=3*157   500=2^2 * 5^3   385 has 3 distinct prime factors   385nswer 385
Answer: A
A certain lab experiments with white and brown mice only. In one experiment, 2/3 of the mice are white. If there are 7 brown mice in the experiment, how many mice in total are in the experiment?  Choose the most appropriate option: A) 39 B) 33 C) 26 D) 21 E) 10

Solution: Let total number of mice = M   Number of white mice = 2/3 M   Number of brown mice = 1/3 M = 7   => M = 21   Answer 21
Answer: D
A train passes a station platform in 36 seconds and a man standing on the platform in 23 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?  Answers:  A) 37  B) 240  C) 288  D) 195  E) 211

Solution: Speed = (54 * 5/18) m/sec = 15 m/sec. Length of the train = (15 x 23)m = 345 m. Let the length of the platform be x meters. Then, (x + 345)/36 = 15 ==> x + 345 = 540 ==> x = 195 m.Answer: 195
Answer: D
The dimensions of a room are 25 feet * 15 feet * 12 feet. What is the cost of white washing the four walls of the room at Rs. 2 per square feet if there is one door of dimensions 6 feet * 3 feet and three windows of dimensions 4 feet * 3 feet each? Pick one
A) s.4528	B) s.1812	C) s.4527	D) s.4530	E) s.4521

Solution: Area of the four walls = 2h(l + b)   Since there are doors and windows, area of the walls   = 2 * 12 (15 + 25) - (6 * 3) - 3(4 * 3)   = 906 sq.ft.   Total cost = 906 * 2   = Rs.1812   Answer:s.1812
Answer: B
Large, medium and small ships are used to bring water. 4 large ships carry as much water as 7 small ships; 3 medium ships carry as much water as 2 large ships and 1 small ship. If 15 large, 7 medium and 14 small ships, each made 36 journeys to bring a certain quantity of water , then in how many journeys will 12 large, 14 medium and 21 small ships bring the same quantity of water?	Choose the correct choice from the following.
A) 29 journeys  B) 30  C) 20  D) 50  E) 55

Solution: Explanation :   Here, Large, Medium and Small ships are denoted by the symbol L, M and S.   Now, according to the question,   4L = 7S. ------(i)   3M = 2L + S. ------(ii)   Using above equations, the ratios of the capacity of the Large, Medium and Small ships are :-   7: 6 : 4.   Let, the number of journeys required be x. Since, quantity of water remains the same, so :-   =((15×7+7×6+14×4)36) = x (12×7+14×6+21×4).   =>((15×7+7×6+14×4)36) / (12×7+14×6+21×4)= x   =>x=7308/252   =>x=29.   29 journeysnswer : 29 journeys
Answer: A
A mixed doubles tennis game is to be played between two teams. There are four married couples. No team is to consist of a husband and his wife. What is the maximum number of games that can be played.  Select the correct option
A) 12  B) 21  C) 36  D) 42  E) 46

Solution: Let's denote the four couples by (A,a), (B,b), (C,c), and (D,d) where A,B,C,D are the husbands and a,b,c,d are the wives.   For a games, let's choose first the husbands. We have 4C2=4*3/2= 
4*3/2 = 6
6 possibilities. Now we know that the final number of games will be a multiple of 6, so we are down to two choices, C and D.   Once husbands were chosen, say A and B, let's count how many possibilities we have to choose their partners under the given restrictions.   We can choose a and b and we have to pair them as (A,b) and (B,a) - 1 possibility.   We can choose one of the wives, a or b, but we have to pair her with the other husband and in addition, we have to choose another partner for the second husband.   This we can do in 2*2= 
2*2 = 4
4 ways, as there are two possibilities to choose from a and b, then we have 2 possibilities to choose the other wife, c or d - 4 possibilities   Finally, we can choose the other two wives, c and d, and we have two possibilities to team them up with the men, (A,c), (B,d) or (A,d), (B,c) - 2 possibilities.   In conclusion, for every pair of husbands, we have 1 + 4 + 2= 
1 + 4 + 2 = 7
7 possibilities to choose their partners for the game.   Total number of possibilities 6 * 7= 
6 * 7 = 42
42.   Answer 42.
Answer: D
A triangle has a perimeter 14. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?  Choose the correct choice from the following: A) 6 B) 7 C) 8 D) 9 E) 5

Solution: The SHORTER sides have integral lengths equal to x and x + 1   Let the longest side be 'a'   So, a + x + (x +1) = 14   a + 2x = 13.......eqn (1)   We know that the sum of the lengths of the shorter sides has to be more than the length of the longer one. i.e 2x+1> a   a =6   6
Answer: A
If a mixture is 1⁄2 alcohol by volume and 3⁄2 water by volume, what is the ratio of the volume of alcohol to the volume of water in this mixture?  Choose the correct choice: A) 3⁄7 B) 4⁄7 C) 3⁄4 D) 4⁄3 E) 7⁄4

Solution: Should be a sub-600 level Q..   volume= {1/2}/{3/2}=1/3   3⁄4
Answer: C
David has d books, which is 3 times as many as Jeff and 3/2 as many as Paula. How many books do the three of them have altogether, in terms of d?
Choose the correct choice from the following answers:
A) 2*d
B) 7/3*d
C) 10/3*d
D) 7/2*d
E) 9/2*d

Solution: Although we could plug in a real value for d, the problem can be just as easily solved by setting up equations. However, let’s start by defining some variables. Since we are given that David has d books, we can use variable d to represent how many books David has.   number of books David has = d   number of books Jeff has = j   number of books Paula has = p   We are given that David has 3 times as many books as Jeff. We can now express this in an equation.   d = 3j   d/3 = j   We are also given that David has ½ as many books as Paula. We can also express this in an equation.   d = (3/2)p   2d/3 = p   Notice that we immediately solved forj in terms of d and p in terms of d. Getting j and p in terms of d is useful when setting up our final expression. We need to determine, in terms of d, the sum of the number of books for David, Jeff, and Paula. Thus, we have:   d + d/3 + 2d/3   =2d   The answer is 2*d
Answer: A
What comes next in the series?
16 72 38 94 50 __ Select:	A) 11	B) 25	C) 17	D) 19	E) 16

Solution: E   16   Each number reverses the previous number and adds 1 to each digit. Thus, in the first two terms, 16 reversed is 61, which then changes to 72. In the penultimate term, 50 reversed becomes 05, which in turn becomes 16 - by adding 1 to each digit.
Answer: E
Johnny bought six peanut butter cans at an average price (arithmetic mean) of 38.0¢. If Johnny returned two cans to the retailer, and the average price of the remaining cans was 31¢, then what is the average price, in cents, of the two returned peanut butter cans?
Choose one:  A) 5.5  B) 11  C) 52  D) 66  E) 67.5

Solution: Total price of six cans = 6*38.0= 
6*38.0 = 228
228   Total price of 4 cans= 4*31= 
4*31 = 124
124   Total rice of two cans= 228 - 124= 
228 - 124 = 104
104   Average price of two cans= 104/2= 
104/2 = 52
52 c   Another way to do it is this:   Assume that the four leftover cans were of 31c each. The avg was 38c initially because the two cans were 38c each and were providing another 7c of cost to other 4 cans.   So cost of the two cans= 2*38 + 4*7= 
2*38 + 4*7 = 104
104   Avg cost of the two cans= 104/2= 
104/2 = 52
52c   Answer (52)
Answer: C
A boy goes to his school from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming. the distance between his house and school is : Select:  A) 4.5 km  B) 5.5 km  C) 6 km  D) 7 km  E) None

Solution: Sol.   Average speed = [2*3*2 / 3+2] km/hr = 12/5 km/hr.   Distance travelled = [12/5 * 5= 
12/5 * 5 = 12
12 km.   ∴ Distance between house and school= [12/2= 
12/2 = 6
6 km.   Answer 6 km
Answer: C