MU-NLPC/Calc-aqua_rat huggingface dataset:
Sachin is younger than Rahul by 7 years. If the ratio of their ages is 5:12, find the age of Sachin Choose the correct option.
A) 9
B) 24.8
C) 2
D) 3
E) 5

Solution: 5xplanation:   If Rahul age is x, then Sachin age is x - 7,   so,   12x - 84 = 5x   7x = 84   x = 12   So Sachin age is   12 - 7= 
  12 - 7 = 5
5   Answer: 5) 5
Answer: E
A, B and C enter into a partnership. They invest Rs. 40,000, Rs. 80,000 and Rs. 1,20,000 respectively. At the end of the first year, B withdraws Rs. 40,000, while at the end of the second year, C withdraws Rs. 80,000. IN what ratio will the profit be shared at the end of 3 years?	Answers: A) 3:4:8 B) 3:4:7 C) 3:4:4 D) 3:4:2 E) 3:4:1

Solution: A:3:4:7:C   = (40000 * 36) : (80000 * 12 + 40000 * 24) : (120000 * 24 + 40000 * 12)   = 144:192:336   = 3:4:7   Answer: 3:4:7
Answer: B
If b> 0, a> 0, and (b^2)a= b,then which of the following MUST equal b?	Choose the correct choice
A) 1/(a^2) B) B.1/a C) A D) A^2 E) A^2 – 2b+1

Solution: B.1/a^2A=B.1/a   B.1/a^2A-B.1/a=0   B.1/a(ba-1)=0   Since B.1/a>0 then   B.1/aa-1=0   B.1/a=1/a   Ans:B.1/a
Answer: B
If a train, travelling at a speed of 18 kmph, crosses a pole in 5 sec, then the length of train is?  Select the correct option.
A) 281 m
B) 25 m
C) 50 m
D) 125 m
E) 75 m

Solution: 25 m   25 m = 18 * 5/18 * 5= 
18 * 5/18 * 5 = 25
25 m
Answer: B
In one hour, a boat goes 15 km/hr along the stream and 11 km/hr against the stream. The speed of the boat in still water (in km/hr) is:  Answers.
A) 12 kmph B) 13 kmph C) 14 kmph D) 15 kmph E) 16 kmph

Solution: Explanation:   Let the speed downstream be a km/hr and the speed upstream be b km/hr, then   Speed in still water =1/2(a+b) km/hr   Rate of stream = 1/2(a−b) km/hr   Speed in still water = 1/2(15+11) kmph = 13 kmph.   Answer: Option 13 kmph
Answer: B
In a class of 140 students, 60% of them passed. By what percent is the number of students who passed more than the number of failed students?  Choose the correct choice.
A) 70%	B) 90%	C) 72%	D) 50%	E) 53%

Solution: Number of students passed = 60% of 140 = 60/100 * 140= 
60/100 * 140 = 84
84   Number of students failed= 140 - 84= 
140 - 84 = 56
56.   Required percentage= 28/56 * 100= 
28/56 * 100 = 50
50%.   Answer: 50%
Answer: D
Train X crosses a stationary train Y in 60 seconds and a pole in 25 seconds with the same speed. The length of the train X is 300 m. What is the length of the stationary train Y?
Choose the correct choice from the following answers:	A) 185 m	B) 420 m	C) 167 m	D) 176 m	E) 168 m

Solution: Let the length of the stationary train Y be LY   Given that length of train X, LX = 300 m   Let the speed of Train X be V.   Since the train X crosses train Y and a pole in 60 seconds and 25 seconds respectively.   => 300/V = 25 ---> ( 1 )   (300 + LY) / V = 60 ---> ( 2 )   From (1) V = 300/25= 
300/25 = 12
12 m/sec.   From (2) (300 + LY)/12= 60   => 300 + LY = 60 (12) = 720   => LY = 720 - 300= 
720 - 300 = 420
420 m   Length of the stationary train= 420 m   Answer:420 m
Answer: B
A batsman makes a score of 66 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
Answers:
A) 25	B) 31	C) 27	D) 29	E) 18

Solution: Let the average after 17 innings = x   Total runs scored in 17 innings = 17x   Average after 16 innings = (x-3)   Total runs scored in 16 innings = 16(x-3)   Total runs scored in 16 innings + 66 = Total runs scored in 17 innings   => 16(x-3) + 66 = 17x   => 16x - 48 + 66 = 17x   => x = 18   Answer is 18.
Answer: E
In what ratio must wheat at Rs.3.20 pe rkg be mixed with wheat at Rs.2.90 per kg so that the mixture be worth Rs.3.08 per kg  Choices:  A) 3:4  B) 3:2  C) 3:5  D) 3:7  E) 2:3

Solution: If 2 ingredients are mixed, then the required ratio is given by, the rule of allegation C.P of a unit quantity of cheaper (c) C.P. of a unit quantity of dearer (d)   Mean Price (m) d-m m-c  Required ratio is cheaper quantity : dearer quantity = (d-m) : (m-c) Answer with Explanation:   Given   i. C.P of a unit quantity of I kind (p) = 3.20 ii. C.P of a unit quantity of II kind (p) = 2.90 iii. Mean price (p) = 3.08 iv. d – m = 3.08 – 2.90 = 0.18 v. m – c = 3.20 – 3.08 = 0.12  Required ratio = 0.18 : 0.12 = 3 : 2   Answer:3:2
Answer: B
Timothy leaves home for school, riding his bicycle at a rate of 6 miles per hour. Fifteen minutes after he leaves, his mother sees Timothy’s math homework lying on his bed and immediately leaves home to bring it to him. If his mother drives at 36 miles per hour, how far (in terms of miles) must she drive before she reaches Timothy?
I think is a 700 level problem but I tag it as 600/700, let me know. Either way I hope in an explanationThanks  Choose the correct answer:  A) 1/3  B) 9/5  C) 4  D) 9  E) 12

Solution: In 15 mins, Timothy travels=6/4 miles.   Now, let his mother takes x hours to reach him, traveling at 36mph.   So, 36x=6x+6/4   x=1/20 hrs.   Thus, the distance traveled by his mother to reach= 36*1/20=9/5 miles. Ans 9/5
Answer: B
A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is?
Choose the correct choice from the following answers: A) 1 kmph B) 2 kmph C) 3 kmph D) 7 kmph E) 8 kmph

Solution: DS = 6   US = 4   S = ?   S = (6 - 4)/2= 
(6 - 4)/2 = 1
1 kmph   1 kmphnswer:1 kmph
Answer: A
There is a sequence A(n) such that A(n+1)=2A(n)-1 and A(1)=3, where n is a positive integer. What is the value of A(76)-A(75)?  Choose the correct option
A) 2^22+1	B) 2^23+1	C) 2^23+1	D) 2^24	E) 2^75

Solution: A1= 3   A2= 2*3-1= 
2*3-1 = 5
5   A3= 2*5-1= 
2*5-1 = 9
9   A4= 2*9-1= 
2*9-1 = 17
17   We can notice that there is a squence   A2-A1= 2^1   A3-A2= 2^2   A4-A3= 2^3   Hence A76-A75= 2^75   2^75 is the answer
Answer: E
A man swims downstream 72 km and upstream 45 km taking 9 hours each time; what is the speed of the current?	Choose the most appropriate option:
A) 1.7	B) 1.5	C) 1.2	D) 1.1	E) 1.9

Solution: 72 --- 9 DS = 8   ? ---- 1   45 ---- 9 US = 5   ? ---- 1 S = ?   S = (8 - 5)/2= 
(8 - 5)/2 = 3/2 = around 1.5
1.5   Answer: 1.5
Answer: B
By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 7 p.c?
Choose the most appropriate option
A) 28000
B) 29000
C) 37000
D) 37200
E) 40000

Solution: Option B   Explanation:   CP + CP/8 = 45000   CP = 40000   SP = 40000*(93/100)= 
40000*(93/100) = 37_200
37200   Option 37200
Answer: D
In order to fence a square Manish fixed 48 poles. If the distance between two poles, is 4 metres then what will be the area of the square so formed?	Choose the correct choice from the following answers.
A) Cannot be determined B) 2600 cm2 C) 2500 cm2 D) 3025 cm2 E) 2304 cm2

Solution: Let the side of the square be x m.   ∴ Perimeter of the square = 48 × 4 = 4x ∴ x = 48 m   ∴ Area = (48)2 = 2304 m2   Answer 2304 cm2
Answer: E
If 0.75 : x :: 3 : 8, then x is equal to:
Choices
A) A)2.12  B) B)2.2  C) C)1.25  D) D)1.3  E) E)2.0

Solution: (x * 3) = (0.75 * 8)= 
(0.75 * 8) = 6
6/3= 
6/3 = 2
2   Answer= 2.0
Answer: E
The cost of 3 kg of sugar is $90. What will the cost of 8 kg of sugar be?  Options:
A) 120	B) 140	C) 180	D) 220	E) 240

Solution: 3 kg costs $90   1 kg costs $30   8 kg costs $240   The answer is 240.
Answer: E
How many 3-digit numbers are completely divisible 6 ? Answers.
A) A)100 B) B)150 C) C)200 D) D)250 E) E)300

Solution: 3-digit number divisible by 6 are: 102, 108, 114,... , 996   This is an A.P. in which a = 102, d = 6 and l = 996   Let the number of terms be n. Then tn = 996.   a + (n - 1)d = 996   102 + (n - 1) x 6 = 996   6 x (n - 1) = 894   (n - 1) = 149   n = 150   Number of terms = 150.   150)
Answer: B
Nitin borrowed some money at the rate of 4% p.a. for the first three years, 9% p.a. for the next five years and 13% p.a. for the period beyond eight years. If the total interest paid by him at the end of eleven years is Rs. 8160, how much money did he borrow? Select.
A) Rs. 9451.84
B) Rs. 8014.54
C) Rs. 8000
D) Rs. 8242.42
E) Rs. 8542.54

Solution: Let the sum be Rs. x. Then,   [(x * 4 * 3)/100] + [(x * 9 * 5)/100] + [(x * 13 * 3)/100] = 8160   12x + 45x + 39x = (8160 * 100)   99x = 816000 => x = 8242.42.   ANSWER:Rs. 8242.42
Answer: D
The Average of 11 results is 16, if the average of the 1st 6 results is 58 & that of the last 63. Find the 6th result.	Pick
A) 60  B) 59  C) 62  D) 66  E) 58

Solution: 6th result = (58*6+63*6-60*11)= 
(58*6+63*6-60*11) = 66
66   Answer is 66
Answer: D
A certain country had a total annual expenditure of $4.8 x 10^11 last year. If the population of the country was 240 million last year, what was the per capita expenditure?	Choose one:  A) $ 500  B) $1,000  C) $2,000  D) $3,000  E) $5,000

Solution: Total expenditure / Population = per capita expenditure   Hence, (4,8 x 10^11) / 240 000 000 = (4,8 x 10^11) / (2,4 x 10^8) = 2 x 10^(11-8) =   2 x 10^3 = 2000.   Answer is $2,000.
Answer: C
If Q is an odd number and the median of Q consecutive integers is 140, what is the largest of these integers? Answers.
A) Q/2 + 139 B) (Q - 1)/2 + 140 C) Q/2 + 140 D) (Q + 139)/2 E) (Q + 140)/2

Solution: Consider the easiest case, say Q=3, then;   Set = {139, 140, 141};   The largest integer = 141.   Now, plug Q=3 into the answers to see which yields 141.   Answer: (Q - 1)/2 + 140.
Answer: B
The ratio of two quantities is 1 to 4. If each of the quantities is increased by 5, what is the ratio of these two new quantities? Answers.
A) 3/4	B) 8/9	C) 18/19	D) 23/24	E) It cannot be determined from the information given

Solution: 1/4 = 1x/4x   we need to find out (1x+5)/(4x+5) off course we cannot solve this to arrive at any rational number hence It cannot be determined from the information given.
Answer: E
If the sum of 7 consecutive integers is x, which of the following must be true?
I. x is an even number
II. x is an odd number
III. x is a multiple of 7  Pick one:
A) I only  B) III only  C) II only  D) I and III  E) II and III

Solution: I. If you start off with an even number, the sum (x) is even, and if you start off with an odd number the sum (x) is odd. Therefore this is not always true.   II. Same as above. This need not be always true.   III. Say, the first number is p. Then the sum of the five numbers = p + (p+1) + (p+2)...... + (p+4)   = 7p + 14 = 7 (p+2) => divisible by 7. There this must be true in all cases.   Therefore III only is the answer.
Answer: B
SCORE INTERVAL----------------NUMBER OF SCORES
50-59-------------------------- 2
60-69-------------------------- 4
70-79--------------------------10
80-89--------------------------27
90-99--------------------------18
The table above shows the distribution of test scores for a group of management trainees. Which score interval contains the median of the 61 scores?	Choose the correct choice from the following choices
A) 30 B) 32 C) 31th(80-89) D) 34 E) 36

Solution: Total scores= 2+4+10+27+18= 
2+4+10+27+18 = 61
61, which is odd, therefore the median is the Floor(61/2)+1= 31th score. And the 31th score is in the 80-89 range, because 50-79 only reference 28 scores.   31th(80-89)
Answer: C
By selling 18 pencils for a rupee a man loses 20%. How many for a rupee should he sell in order to gain 20%?	Choose the most appropriate option:  A) 8  B) 12  C) 6  D) 4  E) 9

Solution: 80% --- 18   120% --- ?     80/120 * 18= 
  80/120 * 18 = 12
12   Answer:12
Answer: B
The age of man is three times the sum of the ages of his two sons.Five years hence,his age will be double of the sum of the ages of his sons.The father’s present age is :  Answers:  A) 40 years  B) 45 years  C) 50 years  D) 55 years  E) 75 years

Solution: Solution   Let the sum of present ages of the two sons be x years.   Then,father's present age = 3x years.   ∴ (3x + 5)=2 (x +10) ⇔ 3x + 5 = 2x + 20 ⇔ x =15.   Hence,father's present age = 45 years. Answer 45 years
Answer: B
How many cubes of 10 cm edge can be put in a cubical box of 1 m edge?  Answers
A) 1
B) 10
C) 100
D) 1000
E) None

Solution: Sol.   Number of cubes = [100 * 100 * 100 / 10 * 10 * 10] = 1000.   Answer 1000
Answer: D
Paulson spends 75% of his income. His income is increased by 20% and he increased his expenditure by 10%.Find the percentage increase in his savings	Answers:  A) 30%  B) 35%  C) 40%  D) 45%  E) 50%

Solution: Let the original income=Rs.100 . Then , expenditure=Rs.75 and savings =Rs.25   New income =Rs.120 , New expenditure =   Rs.((110/100)*75)=Rs.165/2   New savings = Rs.(120-(165/2)) = Rs.75/2   Increase in savings = Rs.((75/2)-25)=Rs.25/2   Increase %= ((25/2)*(1/25)*100)= 
((25/2)*(1/25)*100) = 50
50%.   ANSW50%R 50% 50%
Answer: E
8 men, working 8 hours a day can complete a work in 18 days. How many hours a day must 12 men work to complete the same work in 12 days?  Choose the correct choice from the following options:	A) 6	B) 7	C) 8	D) 9	E) 10

Solution: The number of hours required to complete the work is 8*8*18= 
8*8*18 = 1_152
1152   12 × 12 × (x)= 1152   x = 8   The answer is 8.
Answer: C
There are 17 teams in the hockey league, and each team faces all the other teams 10 times each. How many games are played in the season?  Choose the correct answer:	A) 980	B) 1150	C) 1360	D) 1540	E) 1720

Solution: The number of ways to choose two teams is 17C2 = 17*16/2= 
17*16/2 = 136
136   The total number of games in the season is  10*136= 
 10*136 = 1_360
1360.   The answer is 1360.
Answer: C
What will come in place of the x in the following Number series? 73205, 6655, 605, 55, x	Choose the correct choice from the following options
A) 35678 B) 73205 C) 75653 D) 86554 E) 87565

Solution: (73205)   5 x 11 = 55, 55 x 11 = 605, 605 x 11 = 6655, 6655 x 11 = 73205
Answer: B
A can do a piece of work in 40 days; B can do the same in 30 days. A started alone but left the work after 10 days, then B worked at it for 10 days. C finished the remaining work in 10 days. C alone can do the whole work in?  Choose the correct option.
A) 24  B) 55  C) 66  D) 21  E) 11

Solution: 10/40 + 10/30 + 10/x = 1   x = 24 days   24nswer: 24
Answer: A
From a pack of cards, two cards are drawn one after the other, with replacement. What is the probability that the first card is a club and the second card is a king?	Choose the correct choice from the following options.
A) 2/13 B) 1/26 C) 5/26 D) 1/52 E) 17/52

Solution: P(club) = 1/4   P(king) = 1/13   P(club then a king) = 1/4 * 1/13 = 1/52   The answer is 1/52.
Answer: D
The ages of Ashley and Mary are in the ratio 4:7. The sum of their ages is 22. Find the ages of Ashley . Choose the most appropriate option
A) 7
B) 8
C) 9
D) 10
E) 11

Solution: a:m=4:7   let the ages of a & m be x &22-x   x/22-x=4/7   x=8   a=8yrs   ANSWER:8
Answer: B
The average (arithmetic mean) of y numbers is x. If 25 is added to the set of numbers, then the average will be x - 5. What is the value of y in terms of x ?  Choose one.
A) x/6 - 6	B) x/6 - 5	C) x/7 - 5	D) x/5 - 7	E) x/5 - 6

Solution: (A1 + A2 + .. + Ay)/y = x   (A1 + A2 + .. + Ay + 25)/(y+1) = x - 5   => (xy + 25)/(y+1) = x - 5   => xy + 25 = yx -5y + x - 5   => 30 = x - 5y   => 5y = x - 30   => y = x/5 - 6   x/5 - 6
Answer: E
A certain quantity of 45% solution is replaced with 25% solution such that the new concentration is 35%. What is the fraction of the solution that was replaced?  Choose the correct answer:
A) 1/4	B) 1/3	C) 1/2	D) 2/3	E) 3/4

Solution: Let's say that the total original mixture A is 100 ml   The original mixture A thus has 45 ml of alcohol out of 100 ml of solution   You want to replace some of that original mixture A with another mixture B that contains 25 ml of alcohol per 100 ml. Thus, the difference between 45 ml and 25 ml is 20 ml per 100 ml of mixture. This means that every time you replace 100 ml of the original mixture A by 100 ml of mixture B, the original alcohol concentration will decrease by 20%. The question says that the new mixture, let's call it C, must be 35% alcohol, a decrease of only 10%. Therefore, 10 out of 20 is 1/2 and 1/2 is the answer.
Answer: C
4 professors and 6 students are being considered for membership on a supervisory committee which must consist of 2 people. If the committee has to include at least 2 professor, how many ways can this committee be formed?
Choose the correct choice from the following choices.
A) 36 B) 60 C) 72 D) 80 E) 64

Solution: you count up combinations twice.   4*9*8... and let me name 6 with students A,B,C,..,F   after choosing a professor, when you choose Student A and B, you can choose A first, then B. Or B first, then A. Both combination are same.   I don't think that's the only mistake.   64 is a factor of = 2^2*4^2   64 is a factor of = 2^4*2^2.   These are very different numbers and you cannot divide 64 with something to get to 64. ANS 64
Answer: E
A man sells a horse for Rs.1200 and loses something, if he had sold it for Rs.1500, his gain would have been trible the former loss. Find the cost price of the horse?	Options: A) 700 B) 800 C) 875 D) 1000 E) 900

Solution: 875P = SP + 1875P = SP - g   1200 + x = 1500 -3x   4x = 300 => x = 75   875P = 800 + 75= 
800 + 75 = 875
875   Answer: 875
Answer: C
Peter read Q books last year, and Nikki read N books last year. If Peter read 35 more books than Nikki last year, which of the following reflects this relationship? Choose the correct choice from the following:
A) Q > 35N	B) Q < N − 35	C) Q > N + 35	D) Q = N − 35	E) Q = N + 35

Solution: Peter read Q books last year, and Nikki read N books last year. If Peter read 35 more books than Nikki last year, which of the following reflects this relationship?   A. Q > 35N   B. Q < N − 35   C. Q > N + 35   D. Q = N − 35   E. Q = N + 35   Since Peter read more books than Nikki we have Q>N. Moreover since Peter reads 35 more books than Nikki easily we can have Q=N+35.   So the answer is (Q = N + 35).
Answer: E
A 4-person task force is to be formed from the 4 men and 3 women who work in Company G's human resources department. If there are to be 2 men and 2 women on this task force, how many different task forces can be formed?	Choose the correct choice from the following options:
A) 14
B) 18
C) 35
D) 56
E) 144

Solution: The number of ways to choose 2 men out of 4 is C24=6;   The number of ways to choose 2 women out of 3 is C23=3.   Principle of Multiplication says that if one event can occur in mm ways and a second can occur independently of the first in nn ways, then the two events can occur in mnmn ways.   Thus the number of ways to choose 2 men AND 2 women is  6*3= 
 6*3 = 18
18.   Answer: 18.
Answer: B
{-10, -6, -5, -4, -2.5, -1, 0, 2.5, 4, 6, 7, 10}
A number is to be selected at random from the set above. What is the probability that the number will be a solution to the equation (x-4)(x+9)(2X+5) = 0?
Select the correct option.
A) 1/12
B) 1/6
C) 1/4
D) 1/3
E) 1/2

Solution: x = -2.5   Prob =1/12   1/12nswer - 1/12
Answer: A
Set M contains numbers that satisfy the condition that, if integer x is in the set then x+3 will also be in the set M. If -3 is one of the value in the set, which of the following numbers must also be present in the set M.
I. 3
II. -10
III.1  Select the correct option
A) I only  B) II only  C) I and II only  D) II and III only  E) I, II and III

Solution: Notice that we are askedwhich of the following numbers MUST also be present in the set MnotCOULD be in the set.   Now, if -3 is in the set, then -3+3= 
-3+3 = 0
0mustbe in the set. Since 0 is in the set then   0+3= 
  0+3 = 3
3mustbe in the set and 6 also. Could -8 or 1 be in the set? sure no.   I onlynswer: I only.
Answer: A
If a choir consists of 5 boys and 7 girls, in how many ways can the singers be arranged in a row, so that all the boys are together? Do not differentiate between arrangements that are obtained by swapping two boys or two girls.  Answers: A) 120 B) 30 C) 24 D) 11 E) 8

Solution: There are 7 possibilities:   bbbbbggggggg   gbbbbbgggggg   ggbbbbbggggg   gggbbbbbgggg   ggggbbbbbggg   gggggbbbbbgg   ggggggbbbbbg   gggggggbbbbb   Think of all 5 boys as a single unit. Together with 7 girls it makes a total of 8 units. The difference between the arrangements is the position of the boys (as a single unit). So the problem reduces to finding the number of unique patterns generated by changing the position of the boys who can occupy 1 of 8 available positions. If the number of available unique positions is 8, then the number of unique patterns equals 8 as well.   Answer: 8.
Answer: E
A, Band C enter into partnership. A invests 3 times as much as B and B invests two-third of what C invests. At the end of the year, the profit earned is Rs. 4400. What is the share of B ?	Answers:
A) 1100  B) 800  C) 1400  D) 1200  E) None of them

Solution: Let C's capital = Rs. x. Then, B's capital = Rs. (2/3)x   A’s capital = Rs. (3 x (2/3).x) = Rs. 2x.   Ratio of their capitals = 2x : (2/3)x :x = 6 : 2 : 3.   Hence, B's share = Rs. (4400 x (2/11))= Rs. 800.   Answer is 800
Answer: B
A farmer spent $35 on feed for chickens and goats. He spent 40% money on chicken feed, which he bought at a 50% discount off the full price, and spent the rest on goat feed, which he bought at full price. If the farmer had paid full price for both the chicken feed and the goat feed, what amount would he have spent on the chicken feed and goat feed combined? Choose the correct choice from the following answers.
A) $37.80
B) $49
C) $39.20
D) $39.50
E) $40.60

Solution: A farmer spent 40% money on chicken feed, so he spent 0.4*$35=$14 on chicken feed, thus he spent the remaining 35-14 0.4* 35= 
 0.4* 35 = 14
$14 on chicken feed, thus he spent the remaining   35-14= 
  35-14 = 21
$21 on goat feed.   Now, since he bought chicken feed at a 20% discount then the original price of it was x*0.5=$14 --> x=$28.   Therefore if the farmer had paid full price for both the chicken feed and the goat feed, then he would he have spent   28+21= 
  28+21 = 49
$49.   Answer: $49.
Answer: B
What is the simple interest rate per annum on an investment that took up to 12.5 years to double its initial amount?  Choose the most appropriate option.
A) 10  B) 6  C) 12  D) 4  E) 8

Solution: P = (P*SI*12.5)/100   100P = P*SI*12.5   100 = 12.5SI   Therefore SI = 8%   8= 8
Answer: E
The speed of a boat in upstream is 60 kmph and the speed of the boat downstream is 80 kmph. Find the speed of the boat in still water and the speed of the stream?
Choose the correct answer.
A) 10 kmph
B) 20 kmph
C) 19 kmph
D) 17 kmph
E) 14 kmph

Solution: Speed of the boat in still water = (60+80)/2= 
(60+80)/2 = 70
70 kmph. Speed of the stream= (80-60)/2= 
(80-60)/2 = 10
10 kmph.   10 kmphnswer:10 kmph
Answer: A
A certain pair of used shoes can be repaired for $13.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $32.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
Choose the correct choice from the following answers:
A) 17.69
B) 14.85
C) 21.3
D) 16.5
E) 18.51

Solution: 1) Cost of repairing = 13.5 ( for one year ), Therefore for 2 years it would be$ 27.   2) Cost of new pair which will last for 2 years is$ 32.   Percentage change formula =( Final value - Initial value ) / ( Initial Value ) * 100. In this case the final value would be the price of new shoe initial value would be the cost of repairing the old shoe.   I.e ( 32 - 27 ) / ( 27 ) * 100 = 18.51 %.   Ans is 18.51
Answer: E
How many cubes of 5cm edge can be cut out of a cube of 20cm edge  Answers.
A) 36 B) 64 C) 216 D) 484 E) None of these

Solution: Explanation:   number of cubes=(20 x 20 x 20) / (5 x 5 x 5) = 64   Answer: 64
Answer: B
If man pays 20 for each km which he travels by taxi
and 10 for each km which he travels by bus. If in one
week he payed 800 for traveling 60 km. How many kilometers did he travel by taxi ?  Choices.
A) 23	B) 78	C) 27	D) 29	E) 20

Solution: Let the distance covered by the taxi be 'x' km. Then, distance covered by bus = (60 – x) km. 20x + 10 (60 – x)⇒20x + 600 – 10x = 800 10x = 200 ⇒ x = 20 km. He traveled 20 km by taxi.   Answer:20
Answer: E