MU-NLPC/Calc-aqua_rat huggingface dataset:
a is x % of b, b is x% more than a. Find x.
Select the correct option.
A) 50%
B) 62%
C) 75%
D) 37%
E) 39%

Solution: DETAILED SOLUTION   a = bx   b = a (1 + x), substituting this in the previous equation, we get   x (x + 1) = 1   x2 + x - 1 (  + 1)= 
(  + 1) = 1
1   x2 + x - 1= 0   or x is approximately 0.62 or 62%.   Correct Answer: (62%).
Answer: B
A train 110 m long travels at 60 kmph. How long does it take to pass a telegraph post by the side of the track ?	Choose the correct answer:	A) 3.4	B) 2.4	C) 6.6	D) 2.8	E) 2.6

Solution: Speed of train = 60 ×5/18 m/s = 50/3 m/s ∴ Time taken to cross the telegraph post = 110/(50/3)= 
110/(50/3) = 33/5 = around 6.6
6.6 seconds   Answer: 6.6
Answer: C
The distance between two cities A and B is 465 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
Choose the correct answer:  A) 09  B) 07  C) 12  D) 05  E) 03

Solution: Explanation:   Suppose they meet x hrs after 8 a.m   then,   [Distance moved by first in x hrs] + [Distance moved by second in (x-1) hrs] = 465   Therefore, 60x + 75(x-1) = 465   => x=3.   So,they meet at (8+4) i.e, 12 noon   Answer: 12)
Answer: C
Can you solve the alphametic?
ENLIST + SILENT + LISTEN = ANAGRAM Choose the most appropriate option
A) 1816412  B) 1416312  C) 1516312  D) 1216312  E) 1116312

Solution: Correct Answer : B   assume numeric values for alphabetics. like a=0, b=1, c=2, c=3, d=4, e=5,...   solution   547809+087549+780954 = 1416312
Answer: B
A man is 35 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
Pick one.
A) 14 years
B) 18 years
C) 20 years
D) 22 years
E) 33 years

Solution: Let the son's present age be x years. Then, man's present age = (x + 24) years.   (x + 35) + 2 = 2(x + 2)   x + 37 = 2x + 4   x = 33.   answer :33 years
Answer: E
If (x + 2)(x - a) = px2x2 + qx + 8, what are the values of the constants a, p and q?  Choose the correct choice:
A) 299	B) 278	C) -4,1,6	D) 2378	E) 2771

Solution: (x + 2)(x - a) = px2px2 + qx + 8   ⇒x2⇒x2 + 2x - ax - 2a = px2px2 + qx + 8   ⇒x2⇒x2 + (2 - a) x - 2a = px2px2 + qx + 8   Equating the coefficients of x2x2 , x and constant terms on both sides.   p = 1; q = 2 - a   -2a = 8   Solving, we get a = -4, p = 1, q = 6   Answer:-4,1,6
Answer: C
A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs, 6500 ?
Choose the correct choice from the following answers:
A) 4991
B) 3435
C) 2365
D) 2443
E) 2349

Solution: Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.   Required sale = Rs.[(6500 x 6) - 34009]   = Rs. (39000 - 34009)   = Rs. 4991.   4991nswer: 4991
Answer: A
A certain number when divided by 80 leaves a remainder 25, what is the remainder if the same no.be divided by 15?  Choose the correct choice from the following answers
A) 4
B) 5
C) 6
D) 7
E) 9

Solution: Explanation:   80 + 25= 
80 + 25 = 105
105/15= 
105/15 = 7
7 (Remainder)   7
Answer: D
Write 870,000,000,000 in scientific notation.	Select
A) 8.7 * 10^11	B) 800.900 * 10^11	C) 8.900 * 10^11	D) 80.9000* 10^11	E) 08.900 * 10^11

Solution: a * 10 n , where a is a real number such that 1 * |a| < 10 and n is an integer.   870,000,000,000 = 8.7* 100,000,000,000 = 8.7 * 10 11**   correct answer 8.7 * 10^11
Answer: A
Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 13 cm. Choose one: A) 335 cm2 B) 885 cm2 C) 285 cm2 D) 247 cm2 E) 725 cm2

Solution: Area of a trapezium = 1/2 (sum of parallel sides) * (perpendicular distance between them)   = 1/2 (20 + 18) * (13)   = 247 cm2   Answer: 247 cm2
Answer: D
A sum of Rs.4800 is invested at a compound interest for three years, the rate of interest being 10% p.a., 20% p.a. and 25% p.a. for the 1st, 2nd and the 3rd years respectively. Find the interest received at the end of the three years.	Choose the correct choice from the following answers.
A) 8120
B) 3120
C) 8776
D) 2879
E) 1267

Solution: Let A be the amount received at the end of the three years.   A = 4800[1 + 10/100][1 + 20/100][1 + 25/100]   A = (4800 * 11 * 6 * 5)/(10 * 5 * 4)   A = Rs.7920   So the interest = 7920 - 4800 = Rs.3120   Answer: 3120
Answer: B
A tank is filled to one quarter of its capacity with a mixture consisting of water and sodium chloride. The proportion of sodium chloride in the tank is 50% by volume and the capacity of the tank is 24 gallons. If the water evaporates from the tank at the rate of 0.5 gallons per hour, and the amount of sodium chloride stays the same, what will be the concentration of water in the mixture in 2 hours?	Choose the correct choice from the following choices:
A) 32% B) 36% C) 40% D) 44% E) 48%

Solution: The number of gallons in the tank is (1/4)24 = 6 gallons   The amount of sodium chloride is 0.5(6) = 3 gallons   At the start, the amount of water is 0.5(6) = 3 gallons   After 2 hours, the amount of water is 3 - 0.5(2) = 2 gallons   The concentration of water is 2 / (3+2) = 2/5 = 40%   The answer is 40%.
Answer: C
David is 18 years older than his daughter Rosy. In 6 years David will be twice as old as Rosy. What is Rosy current age.	Choose the most appropriate option.
A) 12	B) 14	C) 18	D) 24	E) 23

Solution: Now: Rosy = x, David =x+18   In 6 years Rosy = x+6, David = x+18+6 or 2(x+6)   x+24= 2x+12   x= 12   Rosy is 12 years old   12nswer : 12
Answer: A
Light glows for every 14 seconds . How many times did it between 1:57:58 and 3:20:47 am
Select.
A) 381 B) 382 C) 383 D) 384 E) 355

Solution: the diff in sec between 1:57:58 and 3:20:47 is 4969 sec, 4969/14 = 354   so total 355 times light ll glow   ANSW355R:355
Answer: E
The area of the cardboard(in cm2) needed to make a box of size 25 cm * 15 cm * 8 cm will be?	Options
A) 1390 cm2	B) 695 cm2	C) 1280 cm2	D) 1220 cm2	E) 1240 cm2

Solution: 2(25 * 15 + 15 * 8 + 25 * 8)   2(375 + 120 + 200) => 1390   1390 cm2NSWER:1390 cm2
Answer: A
What annual installment will discharge a debt of Rs. 4600 due in 4 years at 10% simple interest?
Choose the most appropriate option:
A) 1000 B) 1030 C) 1100 D) None of these E) 1101

Solution: Let the 1st installment = 100/-   It is 3yrs before due   IInd is 2yr before due   III3rd is 1yr before due   IVth is 0 yrs before due   On 1st installment interest will be paid for 3yrs   2nd installment interest will be paid for 2yrs   3rd installment interest will be paid for 1yr   4th installment interest will be paid for 0yr   Interest = P[(100(3+2+1+0)x10)/100] = 60/-   Total loan discharged = 4*100+60/- = 460/-   Now installment of 100/- loan discharged = 460/-   Loan discharged 4600/- ? Installment = 1000/-   1000nswer: 1000.
Answer: A
What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?	Choose the correct choice.
A) 1108  B) 1683  C) 2000  D) 3300  E) 4000

Solution: LCM of 5,6,7 and 8 = 840   hence => (840*1)+3= 
(840*1)+3 = 843
843 which is not divisible by 9   if k= 2, no = (840*2)+3= 
(840*2)+3 = 1_683
1683 is divisble by 9   ANSWER 1683
Answer: B
What approximate value should come in place of question mark (?) in the following equation
287.532 + 1894.029 – 657.48 = 643.095 + ? Choices
A) 870  B) 790  C) 880  D) 770  E) 890

Solution: ? = 285 + 1895 – 655 – 645 or, ? = 880   Answer 880
Answer: C
If 5400 mn = k^4, where m, n, and k are positive integers, what is the least possible value of 2m + n?
Select the correct option
A) 11
B) 18
C) 20
D) 25
E) 35

Solution: k^4=5400∗mn   k^4=3^3.2^3.5^2.mn   In order to make RHS a perfect power of 4, we require it to be multiplied by 3, 2 & 5^2   mn=3.2.5^2   mn = 150 = 10 * 15 (Least possible)   Answer = 2*10 + 15= 
2*10 + 15 = 35
35   ANSW35R:35
Answer: E
A sum of money becomes triple itself in 5 years at simple interest. How many years will it become five times at the same rate? Choices:
A) 12 Â½ years  B) 62 Â½ years  C) 18 Â½ years  D) 10 Â½ years  E) 12 Â½ years

Solution: 100 ---- 200 ---- 5   200 ---- 5   100 ---- 2 1/2   ------------------   500 ---- 10 Â½ years   Answer:10 Â½ years
Answer: D
Which of the following is satisfied with |x-4|+|x-3|<4? Choose the correct choice from the following choices:
A) 1<x<5  B) 2<x<5  C) 1.5<x<5.5  D) 2.5<x<4  E) 3<x<4

Solution: --> If there is addition when there are 2 absolute values, you can just ignore the middle. That is, |x-4|+|x-3|<4 -> |x-4+x-3|<4 -> |2x-7|<4, -4<2x-7<4, 3<2x<11, 3/2<x<11 -="" 2=""> 1.5<x<5.5   Therefore, the answer is 1.5<x<5.5.</x<11>
Answer: C
Salley's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Salley makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?	Choose the most appropriate option:
A) 15 B) 24 C) 25 D) 26 E) 13

Solution: day 0- payment of $7 is made in the morning (after 12 am midnight)   day 1 onwards (after 12 am midnight) internet service will begin and will run for  7*2= 
 7*2 = 14
14 days i.e. at the end of day 15 balance will be zero.   now salley can still use the internet till her debt reaches $5 which means total of  5*2= 
 5*2 = 10
10 days.   now the question states for how many days, including today, will she be connected to the internet without any additional paymentsi.e. we will have to include day0 also in our final answer. therefore total no. of days=1+14+10= 
1+14+10 = 25
25=25
Answer: C
Rs.1010/- distributed among A,B and C such that on decreasing their shares by RS.25,RS.10 and RS.15 respectively, The balance money would be divided among them in the ratio 3:2:5. Then, C’s share is:?  Pick:
A) Rs.485 B) Rs.495/- C) Rs.575 D) Rs.685 E) Rs.592

Solution: A:Rs.495/-:C = 3:2:5   Total parts = 10   C's share is = 5 parts   10-----> Rs.960/-   3 -----> Rs.480/-   A's total =480 + 15 = Rs.495/-   Rs.495/-)
Answer: B
A boat round trip in a river goes upstream at an average speed of 30 miles per hour. On the trip back downstream boat goes at an average speed of 90 miles per hour. What is her approximate average speed for the round trip in miles per hour? Pick
A) 40 B) 45 C) 60 D) 61.7 E) 70

Solution: Average speed = total distance/total time   Here distance upstream and back is same as boat follows the same route.   D = 30T1 and D=90T2   Therefore, T1 = D/30 and T2 = D/90   T1+T2 = 4d/90   Therefore, average speed = 2d/4d/90   =2d * 90/4d   Answer is 45   Answer is 45
Answer: B
The sum of all solutions for x in the equation x^2 – 8x + 21 = |x – 4|+ 3 is equal to: Answers:
A) –7
B) 7
C) 20
D) 12
E) 14

Solution: x^2 - 8x + 18 = |x-4|   RHS can be -ve or +ve   x^2 - 9x + 22 = 0   x^2 - 7x + 14 = 0   x= 11,7,2   We test all 3 values in original equation, all ok.   Thus, Sum = 11 + 7 +2= 
11 + 7 +2 = 20
20   Ans (20)
Answer: C
A, B and C rents a pasture for Rs.870. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should C pay?  Select:
A) 270  B) 297  C) 278  D) 208  E) 277

Solution: 12*8 :16*9 = 18*6   8: 12: 9   9/29 * 870= 
9/29 * 870 = 270
270   270nswer:270
Answer: A
A train traveling at 42 kms/ hr passes a cyclist going in the same direction in 9 secs. If the cyclist had been going in the opposite direction, the train would have passed him in 5 secs. Find the length of the train.	Choose the correct choice from the following answers:
A) 75 meters
B) 60 meters
C) 90 meters
D) 80 meters
E) 70 meters

Solution: Let the length of the train be x meter   and the speed of the cyclist is y m/s   Now when the train and the cyclist are in the same direction, the relative speed is :(35/3-y)m/s[converting 42km/h to m/s-35/3m/s]   Now distance/relative speed =9 seconds   Substituting the values, we get x+9y.....................(1)   Similarly calculate the relative speed when they are in the opposite direction   The relative speed is (35/3+y)   Now distance/relative speed is equivalent to 5 seconds   Substituting the values, we get the equation   3x-15y=175.................................(2)   Solving (1) and (2), we get x=75 meters   75 metersNSWER:75 meters
Answer: A
Twenty eight meters of wire is available to fence off a flower bed in the form of a circular sector. What must the radius of the circle in meters be, if we wish to have a flower bed with the greatest possible surface area? Choose the correct choice from the following options
A) 2√2  B) 2√5  C) 5  D) 7  E) none of these

Solution: Area of Sector, A = x/360*pi*r^2   Circumference of the sector = 28   => x/360*2*pi*r +2r= 28   => 2A/r+2r=28   => A= r14-r^2   = r14-r^2   We will now max using derivations   Max value of A will found at A=0   i.e 14-2r=0   r=7   7
Answer: D
A car is traveling 68 kilometers per hour. How many meters does the car travel in one minute?
Choose the correct choice from the following:
A) 1,250 meters / minute	B) 1,133 meters / minute	C) 1,450 meters / minute	D) 1,550 meters / minute	E) 1,650 meters / minute

Solution: Convert hour into minutes ( 1 hour = 60 minutes) and kilometers into meters (1 km = 1000 m) and simplify   68 kilometers per hour = 68 km/hr   = (68 * 1000 meters) / (60 minutes) = 1,133 meters / minute   correct answer 1,133 meters / minute
Answer: B
In a kilometer race, A beats B by 80 meters or 10 seconds. What time does A take to complete the race?
Choose the correct choice from the following answers
A) 290 sec B) 190 sec C) 199 sec D) 115 sec E) 193 sec

Solution: Time taken by B run 1000 meters   = (1000 * 10)/80= 
(1000 * 10)/80 = 125
125 sec.   Time taken by A= 125 - 10= 
125 - 10 = 115
115 sec.   Answer: 115 sec
Answer: D
IF 2+3=10 ; 2+5=27 ; 2+7=53 Then 2+11=? Choose one.
A) 124
B) 129
C) 128
D) 125
E) 120

Solution: 2^0 + 3^2= 1 + 9= 
1 + 9 = 10
10   2^1 + 5^2= 2 + 25= 
2 + 25 = 27
27   2^2 + 7^2= 4 + 49= 
4 + 49 = 53
53   and   2^3 + 11^2= 8 + 121= 
8 + 121 = 129
129   ANSWER:129
Answer: B
Find the no.of ways of arranging the boy and 8 guests at a circular table so that the boy always sits in a particular seat? Pick.
A) 4!	B) 8!	C) 10!	D) 11!	E) 12!

Solution: Ans.(B)   Sol. Total number of persons = 9 Host can sit in a particular seat in one way. Now, remaining positions are defined relative to the host. Hence, the remaining can sit in 8 places in 8P8 = 8! Ways ... The number of required arrangements = 8! x 1= 8! = 8! ways
Answer: B
The C.P of 15 books is equal to the S.P of 20 books. Find his gain% or loss%?
Answers
A) 16 2/3%
B) 16 2/8%
C) 16 2/5%
D) 16 2/1%
E) 25%

Solution: 15 CP = 20 SP   20--- 5 CP loss   100 --- ? => 25% loss.Answer: 25%
Answer: E
The lengths of the diagonals of a rhombus are 20 and 48 meters. Find the perimeter of the rhombus?
Pick one
A) 150 merters B) 125 meters C) 96 meters D) 104 meters E) 152 meters

Solution: Below is shown a rhombus with the given diagonals. Consider the right triangle BOC and apply Pythagora's theorem as follows   BC 2 = 10^2 + 24^2   and evaluate BC   BC = 26 meters.   We now evaluate the perimeter P as follows:   P = 4 * 26= 
4 * 26 = 104
104 meters.   Answer is 104 meters
Answer: D
At present, the ratio between the ages of Arun and Deepak is 4:7. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present?  Choices:
A) 17 years  B) 35 years  C) 18 years  D) 12 years  E) 19 years

Solution: Let the present ages of Arun and Deepak be 4x and 7x years respectively.   Then, 4x + 6 = 26 => x   = 5   Deepak's age   = 7x   = 35 years.   Answer:35 years
Answer: B
A survey was sent to 90 customers, 15 of whom responded. Then the survey was redesigned and sent to another 50 customers, 9 of whom responded. By approximately what percent did the response rate increase from the original survey to the redesigned survey? Options:
A) 2%
B) 5%
C) 8%
D) 28%
E) 63%

Solution: Rate of first survey = 15/90   Rate of second survey = 9/50   % Response rate increase (9/50-15/90)/(15/90) = 8%   Answer is 8% = 8%
Answer: C
What is the lowest possible common multiple of 2 distinct integers, each greater than 135?  Choices:
A) 136*136
B) 136*137
C) 272
D) 136
E) 137

Solution: The least common multiple of two numbers greater than 135 is 2(136) = 272, where the two distinct integers are 136 and 272.   The answer is 272.
Answer: C
Two assembly line inspectors, Lauren and Steven, inspect widgets as they come off the assembly line. If Lauren inspects every fifth widget, starting with the fifth, and Steven inspects every third, starting with the third, how many of the 99 widgets produced in the first hour of operation are not inspected by either inspector?
Choose one:
A) 35 B) 40 C) 45 D) 50 E) 55

Solution: Widgets inspected by Lauren: ((95-5)/5)+1=18+1= 
18+1 = 19
19   Widgets inspected by Steven: ((96-3)/3)+1=31+1= 
31+1 = 32
32   Widgets inspected by both: ((90/15)+1=7   Total :   19+32 -7= 
  19+32 -7 = 44
44   hence, widgets not inspected: 99-44= 
99-44 = 55
55   Option 55
Answer: E
The famous Denali Star train starts from anchorge & travels towards fair banksat speed 50 mph.After some time another train Glacier Discovery Train( At parallel track) at fair banks And moves towards Anchorge at a speed of 70 mph. Both the trains Denali star & Glacier discovery have a length 1/6 miles each .After the trains meet how many seconds will faster train take to overtake the slower one?	Pick one
A) 10 sec
B) 11 sec
C) 12 sec
D) 13 sec
E) 14 sec

Solution: total distance = (1/6)+(1/6) = 1/3 miles   relative speed = (50+70)= 
(50+70) = 120
120 mph   time taken= (1/3)/(120) hours = 10 seconds   10 secNSWER:10 sec
Answer: A
in a triangle sides of triangle are ac=ln(n),
ab=ln(8),bc=ln(50).
what is the possible value of n? Choose the correct choice:
A) 394
B) 395
C) 385
D) 398
E) 399

Solution: sum of 2sides of the triangle should be greater than the third side   therefore,ln(50)+ln(8)>ln(n)   Now according to the log property;log(a)+log(b)=log(a*b)   So,ln(50*8)>ln(n)   400>n;   Bt the options are;   390,395,392and 398.   So 0 and 400 wont be included,so the ans is 398.   ANSWER:398
Answer: D
What is the unit digit in {(6374)1793 x (625)317 x (341491)}?
Choose the most appropriate option:
A) 0
B) 1
C) 2
D) 3
E) 4

Solution: Unit digit in (6374)1793 = Unit digit in (4)1793   = Unit digit in [(42)896 x 4]   = Unit digit in (6 x 4) = 4   Unit digit in (625)317 = Unit digit in (5)317 = 5   Unit digit in (341)491 = Unit digit in (1)491 = 1   Required digit = Unit digit in (4 x 5 x 1) = 0.   0)
Answer: A
If the list price of a book is reduced by Rs 5 then a person can buy 2 more books for Rs 300.the original cost of the book is Answers:
A) 25 B) 30 C) 15 D) 20 E) 22

Solution: A list price   30 No of book   Ax30 = 300   (A-5)x(30+2) = 300   2A-530+A30-10=300   2A-530=10   (2A-10)A=300x5   AA-5A = 150x5 = 750   A=30   ANSWER:30
Answer: B
how many positive integers less than 1960 are such that the product of their digits is 10.
Pick:
A) 220 B) 230 C) 280 D) 220 E) 240

Solution: 1960 is divisible by 10 ( or 2*5) = 196   196 is divisible by 4 = > 49   49 = 7 *7   hence 1960 is divisible by 2,4,5, 7 ,7   if there were only one 7,   i.e if the problem were 280   280
Answer: C
Express the following as a fraction 56%	Select:
A) 13/50 B) 17/30 C) 11/25 D) 14/25 E) 14/19

Solution: 56% = 56/100   = 14/25   Answer is 14/25.
Answer: D
A and B invests Rs.8000 and Rs.9000 in a business. After 4 months, A withdraws half of his capital and 2 months later, B withdraws one-third of his capital. In what ratio should they share the profits at the end of the year?  Options
A) 32:99
B) 82:31
C) 32:45
D) 34:89
E) 35:21

Solution: A : B   (8000*4)+(4000*8) : (9000*6)+(6000*6)   64000 : 90000   32 : 45   Answer:32:45
Answer: C
What is the least number which when divided by 5, 6, 9 and 12 leaves remainder 4 in each care?	Choose the correct answer.
A) 130	B) 140	C) 156	D) 184	E) 196

Solution: Explanation:   LCM of 5, 6, 9 and 12 is 180   Required number = 180 + 4= 
180 + 4 = 184
184   Answer: Option 184
Answer: D
In given series 56, 72, 90, 110, 132, 150 only one number is incorrect. Find out that wrong number	Choose the correct choice from the following:
A) 140  B) 150  C) 120  D) 170  E) 160

Solution: The numbers are   7 x 8=56   8 x 9=72   9 x 10=90   10 x 11=110   11 x 12=132   12 x 13=156   So, 150 is wrong.   ANSWER:150
Answer: B
Hammers and wrenches are manufactured at a uniform weight per hammer and a uniform weight per wrench. If the total weight of two hammers and two wrenches is one-third that of 8 hammers and 5 wrenches, then the total weight of one wrench is how many times that of one hammer?	Options
A) 1/2  B) 2/3  C) 1  D) 3/2  E) 2

Solution: x be the weight of a hammer and y be the weight of a wrench.   (2x+2y)=1/3*(8x+5y)   3(2x+2y)=(8x+5y)   6x+6y=8x+5y   y=2x   Ans - 2
Answer: E
Two pipes A and B can fill a cistern in 15 and 20 minutes respectively, and a third pipe C can empty it in 30 minutes. How long will it take to fill the cistern if all the three are opened at the same time?	Choose the correct choice from the following choices:
A) 17 1/4 min B) 12 min C) 17 1/7 min D) 17 1/8 min E) 17 5/7 min

Solution: 1/15 + 1/20 - 1/30 = 5/60 = 1/12   12/1= 
12/1 = 12
12   Answer:12 min
Answer: B
Express a speed of 72 kmph in meters per second?	Select the correct option
A) 10 mps  B) 76 mps  C) 20 mps  D) 97 mps  E) 16 mps

Solution: 72 * 5/18= 
72 * 5/18 = 20
20 mps   Answer:20 mps
Answer: C
If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is  Choose the correct choice from the following.
A) 1/7
B) 1/2
C) 1/6
D) 1/3
E) 1/1

Solution: The number of exhaustive outcomes is 36.   Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2   P(E) = 1 - 1/2 = 1/2.   Answer:1/2
Answer: B
In a class, 6 students can speak Gujarati, 15 can speak Hindi and 6 can speak Marathi. If two students can speak two languages and one student can speak all the three languages, then how many students are there in the class Choose the correct choice from the following choices
A) 21	B) 22	C) 23	D) 24	E) 25

Solution: n(AU22UC)=6+15+6-2-2-2+1= 
6+15+6-2-2-2+1 = 22
22   ANSWER:22
Answer: B
Mike and Fritz ran a 30-mile Marathon. Mike ran 10 miles at 10 miles per hour and then ran at 5 miles per hour for the remaining 20 miles.Fritz ran the first one-third (by time) of the run at 10 miles per hour and the remaining two-thirds of the run at 5 miles per hour. How much time in hours did Fritz take to complete the Marathon?
Choose the most appropriate option:
A) 3
B) 3.5
C) 4
D) 4.5
E) 5

Solution: Let total time= t   F travelled at rate 10mph for t/3 time and 5mph for 2t/3 time   d= s1t1+s2t2   30= 10*t/3 + 5*2t/3   30= 20t/3   t= 4.5   4.5 is the answer
Answer: D
A is thrice as efficient as B and is, therefore, able to finish a piece of work 10 days earlier than B. In how many days A and B will finish it together? Pick one
A) 3 days	B) 2 days	C) 5 days	D) 6 days	E) 7 days

Solution: 5 days   5 days   W5 days = 3:1   WT = 1:3   x 3x   1/x – 1/3x = 1/10   x = 20/3   3/20 + 1/20 = 1/5 => 5 days
Answer: C
A trumpet section includes two musicians. If they hold an audition to determine chair order within the section, and there are to be no ties, how many distinct chair orders can result?	Pick one:
A) 240
B) 125
C) 120
D) 100
E) 2

Solution: We have a word problem using permutations. We must identify the number of total items in the group. There are two possible musicians who could be placed in the first chair. To determine the number of possible orderings, we multiply these numbers, which we can express as 2!. Now 2! = (2)(1) = 2=2
Answer: E