MU-NLPC/Calc-aqua_rat huggingface dataset:
Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 10 minutes earlier than usual. How much time did the man spend walking?  Choose the correct option:	A) 45 minutes	B) 50 minutes	C) 55 minutes	D) 52minutes	E) 35 minutes

Solution: As they arrived 10 minutes earlier than usual, they saved 10 minutes on round trip from home to station (home-station-home) --> 5 minutes in each direction (home-station) --> wife meets husband 5 minutes earlier the usual meeting time --> husband arrived an hour earlier the usual meeting time, so he must have spent waking the rest of the time before their meeting, which is hour-5minutes=55 minutes.   Answer: 55 minutes
Answer: C
In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m?
Pick one: A) 127.7 m B) 127.5 m C) 197.5 m D) 177.5 m E) 117.5 m

Solution: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m.   When B runs 900 m, distance that C runs = (900 * 700)/800 = 6300/8= 
6300/8 = 1_575/2 = around 787.5
787.5 m.   In a race of 1000 m, A beats C by   (1000 - 787.5)= 
  (1000 - 787.5) = 212.5
212.5 m to C.   In a race of 600 m, the number of meters by which A beats C= (600 * 212.5)/1000= 
(600 * 212.5)/1000 = 127.5
127.5 m.   Answer: 127.5 m
Answer: B
The mass of 1 cubic meter of a substance is 200 kilograms under certain conditions. What is the volume, in cubic centimeters, of 1 gram of this substance under these conditions? (1 kilogram = 1,000 grams and 1 cubic meter = 1,000,000 cubic centimeters)
Choose the correct choice from the following answers:  A) 0.8  B) 1.25  C) 8.0  D) 12.5  E) 5.0

Solution: Density is mass divided by volume. So density of the given substance will be mass/volume=200kg/1m^3=800 kg/m^3 or 1g/5cm^3=0.2 g/cm^3.   Next, ask yourself if 200,000 g is equivalent to 1,000,000 cubic centimeters then 1 g is equivalent to how many cubic centimeters? --> 1 g - 1,000,000/800,000 = 10/2= 
10/2 = 5
5 cubic centimeters.   Answer is 5.0
Answer: E
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?
Select:
A) 3:4
B) 3:0
C) 3:8
D) 3:2
E) 3:1

Solution: Let speed of the train = x kmph and speed of the car = y kmph   Time needed for traveling 600 km if 120 km by train and the rest by car = 8 hr   ⇒120x+(600−120)y=8⇒120x+480y=8.............(Equation 1)⇒15x+60y=1.............(Equation 1)   Time needed for traveling 600 km if 200 km by train and the rest by car = 8 hr 20 min   ⇒200x+(600−200)y=82060=813=253⇒200x+400y=253⇒8x+16y=13⇒24x+48y=1.............(Equation 2)Solving Equation1 and Equation2Here Equation1 = Equation2 = 1⇒15x+60y=24x+48y⇒12y=9x⇒4y=3x⇒xy=34⇒x:y=3:4   3:4nswer : 3:4
Answer: A
In a group of cows and hens, the number of legs are 14 more than twice the number of heads. The number of cows is	Pick:  A) 5  B) 7  C) 10  D) 12  E) 14

Solution: Explanation:   Let the number of cows be x and the number of hens be y.   Then, 4x + 2y = 2 (x + y) + 14 4x + 2y = 2x + 2y + 14 2x = 14 x = 7.   Answer: 7
Answer: B
Two trains, each 150 m long, moving in opposite directions, cross other in 8 sec. If one is moving twice as fast the other, then the speed of the faster train is?	Choose the correct choice from the following:  A) 90  B) 98  C) 60  D) 88  E) 12

Solution: Let the speed of the slower train be x m/sec.   Then, speed of the train = 2x m/sec.   Relative speed = ( x + 2x) = 3x m/sec.   (150 + 150)/8 = 3x => x = 25/2.   So, speed of the faster train = 50/2= 
50/2 = 25
25 * 18/5= 
25 * 18/5 = 90
90 km/hr.   90nswer:90
Answer: A
The sum of three consecutive odd numbers is always divisible by:
I. 2 II. 3 III. 5 IV. 6
Pick:
A) Only I  B) Only II  C) Only I and II  D) Only II and IV  E) None of these

Solution: Let the three consecutive odd numbers be (2x+1), (2x+3) and (2x+5). Their sum = (6x=9)= 3 (2x+3), which is always divisible by 3.   Answer: Only II
Answer: B
70, 75, 80, 85, 90, 105, 105, 130, 130, 130
The list shown consists of the times, in seconds, that it took each of 10 schoolchildren to run a distance of 400 on of meters. If the standard devastation of the 10 running times is 27.4 seconds, rounded to the nearest tenth of a second, how many of the 10 running times are more than 1 standard deviation below the mean of the 10 running times?
Choose the correct choice from the following options
A) one	B) two	C) three	D) four	E) five

Solution: The most time consuming part in this question is to define the mean. Under exam pressure and time pressure it is very easy to make mistake.   it is easier to group numbers:  130*3= 
 130*3 = 390
390; 105*2=210; 75+85=160; 70+80=150; 90;   Next stage combine results, again using more convenient ways to calculate: 390+210= 
390+210 = 600
600; 160+150=310; 90. 600+310+90=1000. Since there are 10 numbers the mean is 100. Questions asks to find the quantity of numbers one SD BELOW the mean, which is 100-27,4=72,6. There are only two numbers below 72,6. The answer is two
Answer: B
The average of first 10 odd numbers is?  Select:
A) 11  B) 10  C) 19  D) 16  E) 13

Solution: Sum of 10 odd no. = 100   Average = 100/10= 
100/10 = 10
10   Answer: 10
Answer: B
What percent is 2 minutes 24 seconds of an hour? Choose one.
A) 6% B) 2% C) 4% D) 5% E) 7%

Solution: %=144/60×60 = 4%   Answer: 4%
Answer: C
What approximate value should come in place of the question mark (?) in the following equation?
1.542 × 2408.69 + 2134.632 = ?
Choose the correct option
A) 4600
B) 4800
C) 5800
D) 6400
E) 3600

Solution: Explanation 3700 + 2100= 
3700 + 2100 = 5_800
5800   Answer 5800
Answer: C
Solve for x and check: 15x = 165 Choose the correct choice from the following choices:
A) 98
B) 165
C) 180
D) 253
E) None of these

Solution: Solution : Dividing each side by 15, we obtain   (15x/15)=(165/15)= 
(165/15) = 11
11   Check :   15x=165   (15*11)= 
(15*11) = 165
165   165=165   ANSWER : 165
Answer: B
If in a certain sequence of consecutive multiples of 50, the median is 825, and the greatest term is 1000, how many terms that are smaller than 825 are there in the sequence?  Pick one:
A) 6 B) 4 C) 8 D) 12 E) 13

Solution: Since the median is 825 we know there must be a even number of integers because 50 is not a multiple of 825.   So the list around 825 must go. 700 750 800 (825) 850 900 950 1000   Since we know there are 4 numbers greater than 825 then there must be 4 numbers less then 825.   answer:4
Answer: B
A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?  Choose the correct choice from the following options
A) 6A+7
B) 5A+1.
C) 5A-1.
D) 6A-5.
E) 6A-7.

Solution: A= C+2   => C = A-2   A= B+1   => B = A-1   Since the answer options contain variable A , we have to write B and C in terms of A .   2A +B +3C = 2A + (A-1) +3(A-2)   =2A + A-1 + 3A -6   =6A -7   Answer 6A-7.
Answer: E
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 4320 interest only for the period. The principal amount borrowed by him was:
Choose the correct choice from the following answers.
A) s. 12,000
B) s. 10,000
C) s. 15,000
D) s. 18,000
E) s. 20,000

Solution: Principal = Rs. (100 x 4320)/(12X3) = Rs. 12000. s. 12,000nswer: Option s. 12,000
Answer: A
Rs.8000 become Rs.9261 in a certain interval of time at the rate of 5% per annum of C.I. Find the time?
Choose the correct choice from the following choices:  A) 8  B) 7  C) 6  D) 3  E) 4

Solution: 9261 = 8000(21/20)N   (21/20)3 = (21/20)N => N = 3   Answer:3
Answer: D
The total of company C's assets in 1994 was 500% greater than the total in 1993, which in turn was 400% greater than the total in 1992. If the total of company C's assets in in 1992 was N dollars, which one of the following represents company C's assets in 1994:  Choose the correct option
A) 7N  B) 8N  C) 19N  D) 22N  E) 30N

Solution: Let's use actual numbers. Starting in 1992, let's say company C had $100 in assets.   In 1993, the total assets were 400% GR30NAT30NR, which means 1992 PLUS 400% of 1992:   $100 + 4x$100 = $100 + $400 = $500   In 1994, the total assets were 500% GR30NAT30NR than they were in 1993, which means 1993 PLUS 500% of 1993:   $500 + 5x$500 100 +  400= 
100 +  400 = 500
$500   In 1994, the total assets were 500% GR30NAT30NR than they were in 1993, which means 1993 PLUS 500% of 1993:   $500 + 5x$500= $500 + $2500 = $3000   This is 30 times the 1992 number, so the correct answer is 30N.500 +  2500= 
500 +  2500 = 3_000
$3000   This is 30 times the 1992 number, so the correct answer is 30N.
Answer: E
The cash difference between the selling prices of an article at a profit of 2% and 4% is Rs 3. The ratio of two selling prices is
Pick
A) 51:52	B) 52:53	C) 53:54	D) 54:55	E) 51:52

Solution: Explanation:   Let the Cost price of article is Rs. x   Required ratio = (102% of x) / (104% of x)   =102/104   =51/52 = 51:52.   Answer: 51:52
Answer: E
In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?  Select:
A) 100
B) 150
C) 50
D) 250
E) 75

Solution: Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.   Then, sum of their values = Rs. ((25x/100) + (10 x 2x/100)+(5 x 3x)/100= Rs. 60x/100   Therefore, 60x/100 = 30   x = 30 x 100/60 = 50.   Hence, the number of 5 p coins = (3 x 50) = 150.   Answer is 150.
Answer: B
A 300 m long train crosses a platform in 30 sec while it crosses a signal pole in 18 sec. What is the length of the platform?  Choose the correct answer.
A) 286 m
B) 350 m
C) 200 m
D) 278 m
E) 267 m

Solution: Speed = 300/18 = 50/3 m/sec.   Let the length of the platform be x meters.   Then, (x + 300)/30 = 50/3   x = 200 m.   Answer:200 m
Answer: C
If 4 men and 1 boy working together, can do two times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time?  Choose the correct choice from the following: A) 3:2 B) 2:1 C) 3:3 D) 1:2 E) 6:1

Solution: 4M + 1B =2(1M + 1B)   4M + 1B = 2M + 2B   2M = 1B   The required ratio of work done by a man and a boy = 1:2   1:2
Answer: D
What annual installment will discharge a debt of Rs.1092 due in 3 years at 12% simple interest?  Choose the correct choice from the following answers:
A) 442
B) 441
C) 440
D) 320
E) 532

Solution: Let the installment be Rs. X   If he keeps the total amount for 3 years, he have to pay the interest   of Rs. (1092*12*3)/100.   But he paid Rs. X after 1 year.   So he need not to pay interest for Rs. X for remaining 2 years. i.e he   need not to pay Rs. (X*12*2)/100.   And he paid another Rs. X after 2 years.   So he need not to pay interest for for remaining 1 years. i.e. Rs.   (X*12*1)/100.   So The total interest he has to pay is Rs. ((1092*12*3)/100) - [   ((X*12*2)/100) + ((X*12*1)/100) ].   So, The total amount he has to pay is Rs. 1092 + Rs.((1092*12*3)/100) -   [ ((X*12*2)/100) + ((X*12*1)/100) ].   The total amount he paid = 3X. ( because he paid Rs.X for three times)   1092 + ((1092*12*3)/100) - [ ((X*12*2)/100) + ((X*12*1)/100) ] = 3X   BY solving, we will get X = 442.   442NSWER:442
Answer: A
Divide Rs. 2379 into 3 parts so that their amounts after 2, 3 and 4 years respectively may be equal, the rate of interest being 5% per annum at simple interest. The first part is?  Choices:
A) 3378
B) 627
C) 276
D) 828
E) 112

Solution: Let the parts be x, y and [2379 - (x + y)]   x + (x * 2 * 5/100) = y + (y * 3 * 5/100) = z + (z * 4 * 5/100)   11x/10 = 23y/20 = 6z/5 = k   x = 10k/11, y = 20k/23, z = 5k/6   But x + y + z = 2379   10k/11 + 20k/23 + 5k/6 = 2379   k = (2379 * 11 * 23 * 6)/3965 = (3 * 11 * 23 * 6)/5   x = [10/11 * (3 * 11 * 23 * 6)/5= 
10/11 * (3 * 11 * 23 * 6)/5 = 828
828   Hence, the first part is Rs. 828.   Answer: 828
Answer: D
How many numbers are there between 200 and 800 which are divisible by both 5 and 7? Answers: A) 35 B) 16 C) 17 D) can’t be determined E) None of these

Solution: Answer C   Solution   In the given range, the last number which is divisible by both 5 and 7. i.e., 35 is 210 and the highest number is 770. So the total number of numbers between 200 and 800 which are divisible by both 5 and 7 is   (770-210/35)+ 1 = 17   Hence option 17
Answer: C
What is the greatest value of n such that 16^n is a factor of 18! ?
Choose the correct choice from the following options:
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: Another way to solve this question :   We know that 18 = 2 *3^2.   Hence, we need to find total number of 3s in 18! ( As out of 3 and 2 , we will have count of 3 least)   No. of 3s = 18/3= 
18/3 = 6
6/3= 
6/3 = 2
2.   Add the numbers in Bold, you will get total number of 3s= 8.   Hence, total number of 2^1 = 2/2= 
2/2 = 1
1   Hence, answer is 1. 1
Answer: A
The arithmetic mean of the scores of a group of students in a test was 52. The brightest 20% of them secured a mean score of 80 and the dullest 25% a mean score of 31. The mean score of remaining 55% is?  Choose the correct answer.
A) 51.4  B) 55  C) 56.4  D) 52.2  E) 60.8

Solution: Let the required mean score be x   20*80 + 25*31 + 55*x = 52*100   1600+775+55x = 5200   x = 51.4   51.4nswer is 51.4
Answer: A
The expression x#y denotes the product of the consecutive multiples of 3 between x and y, inclusive. What is the sum of the exponents in the prime factorization of 21#33?	Select the correct option
A) 12
B) 13
C) 14
D) 15
E) 16

Solution: First, let's translate the expression 21#33, using the definition given:   21#33 = 21×24×27×30×33   We need the prime factorization of this product.   Let's factor out 3 from each multiple.   21#33 = 3^6(7×8×9×10×11)   Now let's replace each consecutive integer with its prime factorization:   21#33 = 3^5(7×2^3×3^2×(2×5)×11)   Let's group the prime bases:   21#33 = 2^4×3^7×5×7×11   The sum of the exponents is  4 + 7 + 1 + 1 + 1= 
 4 + 7 + 1 + 1 + 1 = 14
14   The answer is 14.
Answer: C
In a class, the average age of 40 boys is 15 years and the average of 30 girls is 13 years. what is the average age of the whole class?  Choose the correct choice from the following:	A) 11 Years	B) 12.6 Years	C) 13 Years	D) 13.5 Years	E) 14.1 Years

Solution: Total age of 70 students   (40X 15+30 X 13) = 990   Average = 990/70 = 14.1 Years   14.1 Years)
Answer: E
In how many ways can 3 postcards can be posted in 5 postboxes?
Pick:  A) 100  B) 150  C) 175  D) 200  E) 125

Solution: First card can go into any of the five boxes,second can go into any of the five boxes.   Third card also can go into any of the five boxes   Number of ways=5*5*5= 
5*5*5 = 125
125 ways   Option 125
Answer: E
What is the equation of a circle of radius 8 units centered at (3, 2)?  Choices:
A) x^2 + y^2 + 6x – 4y = 23	B) x^2 + y^2 - 6x + 4y = 23	C) x^2 + y^2 + 6x + 4y = 23	D) x^2 + y^2 - 6x – 4y = 51	E) x^2 + y^2 - 6x – 4y = - 23

Solution: the equation of a circle with center at (a,b) and radius R is (X-a)^2+(Y-b)^2=R^2   => answer = (X-3)^2+(Y-2)^2=8^2   solving,,we get the equation in answer choice x^2 + y^2 - 6x – 4y = 51
Answer: D
John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.63 more than Jane, what was the original price of the dish?	Choose the most appropriate option.
A) 24  B) 34.8  C) 37.8  D) 42  E) 84

Solution: The difference between the amounts John paid and Jane paid is the deference between 15% of p and 15% of 0.9p:   0.15p - 0.15*0.9p = 0.63 --> 15p - 13.5p = 63 --> p = 42.   Answer: 42.
Answer: D
Two pipes A and B can fill a cistern in 20 and 10 minutes respectively, and a third pipe C can empty it in 40 minutes. How long will it take to fill the cistern if all the three are opened at the same time?  Choose the most appropriate option:	A) 19 1/7 min	B) 8 min	C) 17 1/7 min	D) 7 1/7 min	E) 7 2/7 min

Solution: 1/20 + 1/10 - 1/40 = 5/40   40/5= 
40/5 = 8
8   ANSWER:8 min
Answer: B
If x and y are positive integers and 5 + x + y + xy = 19, what is the value of x + y?  Choose the correct choice from the following: A) 3 B) 5 C) 6 D) 8 E) 9

Solution: Try each answer choices.   For A: 5 + 3 + xy = 19; xy = 11 (impossible, 11 prime number. 1 + 11 doesn't equal 3)   For B: 5 + 5 + xy = 19; xy = 9 (no combination of xy = 9 and x + y = 5)   For C: 5 + 6 + xy = 19; xy = 8 (x + y = 6; x = 2, y = 4 or x = 4, y = 2)   For D: 5 + 8 + xy = 19; xy = 6 (no combination of xy = 6 and x + y = 8)   For E: 5 + 9 + xy = 19; xy = 5 (impossible, 5 prime number. 1 + 5 doesn't equal 9)   Therefore, answer 6.
Answer: C
George's drawer has 10 loose black socks, 14 loose blue socks, and 8 loose white socks. If George takes socks out of the drawer at random, how many would he need to take out to be sure that he had at least two matching pairs of socks in two different colors? Choose one.
A) 13 B) 14 C) 15 D) 16 E) 17

Solution: The worst case scenario is choosing 14 blue socks. Then he would need 3 more socks to be sure of a matching pair of black socks or white socks.   The answer is 17.
Answer: E
Joe went up a certain hill at the rate of one and a half kilometers per hour and came down at the rate of four and a half kilometers per hour, so that it took just four hours to make the double journey. How far was it to the top of the hill ? Answers:
A) 3 km
B) 6 km
C) 4.5 km
D) km
E) none of the above

Solution: Assume the distance to the top of the hill (1 way) as: x   Now, speed=distance/time => time=distance/speed   So, for the first half of the journey, he traveled uphill at 1.5km/hr, so the time taken for the first leg of the journey is: x/1.5.   For the second half, he traveled downhill at 4.5km/hr, so the time taken for the second leg of the journey is: x/4.5   Now, the total time for the trip is given as 4 hrs.   Equating, (x/1.5)+(x/4.5)=4 => (3x+x)/4.5=4 => x=4.5 km   So, the distance one side is = 4.5 km.   The OA mentioned is 9km, which is exactly double of this distance, i.e., the total distance traveled during both legs of the journey, but the question only asked for the distance till the top of the hill, i.e., one way, so the answer should be 4.5km   4.5 kman someone assist me in understanding where am I wrong here?
Answer: C
The product of two negative integers, a and b, is a prime number p. If p is the number of factors of n, where n is NOT a perfect square, what is the value of the median of the four integers a, b, p, and n?
Choose the correct choice from the following options:
A) 0
B) 1/2
C) 1
D) 3/2
E) 2

Solution: All prime numbers are divisible by 1 and itself. now since product of a and b is a prime number P. therefore one of a and b is -1 and other is -P.   Also, all the perfect square have odd no. of factors. for e.g. a^2 will have 3 factors a,a^2 and 1. Since, n is not a perfect square therefore its no. of factors must be even and the only prime no. which is even is 2. therefore p=2,   now the median of numbers -2,-1,2 and n will be (-1+2)/2= 1/2   ANSWER:1/2
Answer: B
How many ways the letters of the word ‘BANKER’ can be arranged? Choose the correct choice from the following answers
A) 600  B) 650  C) 720  D) 750  E) 7880

Solution: 6P6   6!   720   720
Answer: C
It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),
when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 360, and 300 as the side’s lengths, what is the triangle’s area?  Choose the correct choice from the following answers.
A) 43,200	B) 36,200	C) 38,200	D) 42,200	E) 34,200

Solution: It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)),   when p=(a+b+c)/2,   -> P=(300+360+300)/2= 
(300+360+300)/2 = 480
480, area=√(480(480-300)(480-360)(480-300))=43,200. Therefore, the answer is 43,200.
Answer: A
For a finite sequence of non zero numbers, the number of variations in the sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is positive. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6,7,-9,8?  Choose one.
A) 1  B) 2  C) 3  D) 4  E) 5

Solution: The questions basically asks: how many pairs of consecutive terms are there in the sequence such that the product of these consecutive terms is positive.   2*(5)= 
2*(5) = 10
10=positive;   -4*(-6)= 
-4*(-6) = 24
24=positive;   So there are 2 pairs of consecutive terms.   Answer: 2
Answer: B
A, B and C started a partnership business by investing Rs.12000, Rs.16000, Rs.20000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
Choose the correct choice from the following answers:
A) 70000 B) 60000 C) 86400 D) 90000 E) 50000

Solution: A:B:86400 =12000:16000:20000   =3:4:5   Let total profit =p   Then pÃ—5/12=36000   p=(36000Ã—12)/5=86400   Answer is 86400.
Answer: C
A man spends 18% of his income in house rent, 22% of the rest on his children’s education, 28% of the rest miscellaneous causes. If he now posses Rs. 9877 then his income is?	Choices
A) A)Rs.21472  B) B)Rs.31472  C) C)Rs.41472  D) D)Rs.61479  E) E)Rs.56979

Solution: X * (82/100) * (78/100) * (72/100) = 9877   X * 0.82 * 0.78 * 0.72 = 9877   X = 9877/0.46   X = 21472   Rs.21472NSWER:Rs.21472
Answer: A
A group of Students take a test:
Two people scored 45
Two people scored 50
Then every other persons scores were 40,60,70,75,95,100
Which score that is greater than the median but less than the mean? Select the correct option:
A) 40
B) 50
C) 60
D) 70
E) 75

Solution: List in order: 40,45,45,50,50,60,70,75,95,100   The median = (the average of two middle terms) = (50 + 60)/2= 
(50 + 60)/2 = 55
55.   The mean= (the sum)/(# of terms) = 630/10= 
630/10 = 63
63.   The score of 60 is between 55 and 63.   Answer: 60.
Answer: C
Ram and Shakil run a race of 2000m. First Ram gives Shakil a start of 200m and beats him by 1 minute.Next Ram gives shakil a start of 6 min and is beaten by 1000 meters . Find the time in minutes in which Ram and Shakil can run the race seperately.
Choices
A) 12.18 B) 10.18 C) 10.12 D) 8.1 E) 8.2

Solution: LET r be velocity of ram and s be the velocity of Shakil then (2000/r)=(1800/s)-60......(1)   second case distance Shakil travel in 6 min=360s   again equating time for both 1000/r=(2000-360s)/s.......(2)   solving (1) &(2) we get   s=20/6   putting value in first we get time =480sec=8min   ANSWER:8.1
Answer: D
What least number must be subtracted from 427398 so that remaining no.is divisible by 13	Options.
A) 3  B) 5  C) 6  D) 7  E) 10

Solution: 10xplanation:   On dividing 427398 by 13 we get the remainder 10, so 10 should be subtracted   Answer: Option 10
Answer: E
A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 20 sec. What is the length of the platform?	Pick:
A) 389 m  B) 350 m  C) 285 m  D) 299 m  E) 219 m

Solution: Speed = 300/20= 
300/20 = 15
15 m/sec.   Let the length of the platform be x meters.   Then, (x + 300)/39= 15   => x = 285 m.   Answer:285 m
Answer: C
Water is leaking out from a cylinder container at the rate of 0.31 m^3 per minute. After 10 minutes, the water level decreases 1/9 meters. What is value of the radius in meters? Answers
A) 2
B) 3
C) 4
D) 6
E) 9

Solution: 10*0.31= 
10*0.31 = 3.1
3.1= pi*R^2*h   R^2 = 3.1 / (pi*1/9) which is about 9   R = 3   The answer is 3.
Answer: B
What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 58?  Pick:
A) 3944
B) 920
C) 7290
D) 6928
E) 3729

Solution: Explanation:   Let the side of the square plot be a ft.   a2 = 289 => a = 17   Length of the fence = Perimeter of the plot = 4a = 68 ft.   Cost of building the fence = 68 * 58 = Rs. 3944.   3944nswer: Option 3944
Answer: A