MU-NLPC/Calc-aqua_rat huggingface dataset:
A train crosses a bridge of length 150 m in 7.5 seconds and a lamp post on the bridge in 2.5 seconds. What is the length of the train in metres?	Options:  A) 37.5 m  B) 75 m  C) 25 m  D) 80 m  E) 30 m

Solution: Let Length of Train = L   Case-1: Distance = 150+L (While crossing the bridge)   Time = 7.5 Seconds   i.e. Speed = Distance / Time = (150+L)/7.5   Case-2: Distance = L (While passing the lamp post)   Time = 2.5 Seconds   i.e. Speed = Distance / Time = (L)/2.5   But Since speed has to be same in both cases so   (150+L)/7.50 = (L)/2.5   i.e. 3L = L + 150   i.e. 2L = 150   i.e. L = 75   Answer: option 75 m
Answer: B
John invested $ 10,000 in a savings bank account that earned 2% simple interest. Find the interest earned if the amount was kept in the bank for 4 years. Choose the correct answer.
A) 600 B) 800 C) 850 D) 900 E) 950

Solution: Principle P = $ 10,000 Time Period T =4 years and Rate of Interest = 2% = 0.02   Plugging these values in the simple Interest formula,   I = PX T X R   = 10,000 X 4 x 0.02   = $ 800   Interest earned for the investment = $ 800   answer :800
Answer: B
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for $80 to incur a loss 20%? Choose the correct choice: A) 45 B) 36 C) 40 D) 50 E) 48

Solution: Production cost per article: $60*(100%-20%) / 20 = $2.40   Required production costs for a loss of 20%: $80*(100% + 20%) = $96   Number of articles to be sold for $96 to incur a 20% loss: $96/ $2.40 = 40   Thus, solution 40 is correct.96/  2.40= 
96/  2.40 = 40
40   Thus, solution 40 is correct.
Answer: C
The sum of five numbers is 655. The average of the first two numbers is 85 and the third number is 125. Find the average of the two numbers?
Pick one:
A) 180
B) 170
C) 190
D) 175
E) 200

Solution: P + Q + R + S + T = 655.   (P + Q)/2 = 85 and R = 125   P + Q = 170 and R = 125   P + Q + R = 295   S + T = 655 - (P + Q + R) = 360   Average of the last two numbers = (S + T)/2 = 180.   180NSWER 180
Answer: A
Tomy's age 20 years hence will be thrice his age four years ago. Find Tomy's present age? Choose the correct choice from the following answers:
A) 12 years  B) 16 years  C) 15 years  D) 17 years  E) 18 years

Solution: Let MTomy's present age be 'x' years.   x+ 20 = 3(x- 4)   => 2x = 32 => x = 16 years.   16 years
Answer: B
Each week, Harry is paid X dollars per hour for the first 30 hours and 1.5X dollars for each additional hour worked that week. Each week, James is paid X dollars per hour for the first 40 hours and 2X dollars for each additional hour worked that week. Last week James worked a total of 47 hours. If Harry and James were paid the same amount last week, how many hours did Harry work last week?
Choose the correct choice from the following answers.
A) 35  B) 36  C) 37  D) 38  E) 46

Solution: Amount earned by James = 40*x + 7*2x = 54x   Therefore, Amount earned by Harry = 54x   But we know the amount Harry earned assuming working y hours (y>30) is 30*x + (y-30)*1.5x   [[We know y>30 because in 30h the most Harry could earn is 30x, but he has earned 54x]]   So x*(1.5y -45 +30) = 54x   Or x*(1.5y - 15) = 54x   So 1.5y - 15 = 54   So 1.5y = 69   So y = 46   Answer is 46
Answer: E
The surface of a cube is 24sq cm. Find its volume?	Answers
A) 8cc  B) 9cc  C) 2cc  D) 4cc  E) 6cc

Solution: 6a2 = 24   a = 2 => a3 = 8cc   8ccnswer: 8cc
Answer: A
The age of man is three times the sum of the ages of his two sons. Eight years hence,his age will be double of the sum of the ages of his sons.The fatherâ€™s present age is :  Choose the correct answer
A) 40 years
B) 45 years
C) 50 years
D) 55 years
E) 72 years

Solution: Solution   Let the sum of present ages of the two sons be x years.   Then,father's present age = 3x years.   âˆ´ (3x + 8)=2 (x +16) â‡” 3x + 8 = 2x + 32 â‡” x =24.   Hence,father's present age = 72 years. Answer 72 years
Answer: E
An investor purchased 100 shares of stock X at 6 1/8 dollars per share and sold them all a year later at 18 dollars per share. If the investor paid a 2 percent brokerage fee on both the total purchase price and the total selling price, which of the following is closest to the investor's percent gain on this investment?
Choose the correct answer:
A) 189%	B) 240%	C) 280%	D) 300%	E) 380%

Solution: If the purchase price was 6$ per share then the investor would have made a profit of 200%.   Since the purchase price is slightly more than 6$ the profit would be slightly less than 200%.   Also a 2% brokerage is negligible and it brings down the profit percentage only by a small value. Approximation is very useful to solve these kind of problems as the answer choices are far apart.   189%nswer: 189%
Answer: A
If 10 litres of an oil of Rs.50 per litres be mixed with 5 litres of another oil of Rs.66 per litre then what is the rate of mixed oil per litre? Select the correct option:
A) Rs.49.17
B) Rs.51.03
C) Rs.54.17
D) Rs.55.33
E) None of the above

Solution: 50*10= 
50*10 = 500
500   66*5= 
66*5 = 330
330   830/15= 55.33   ANSWER:Rs.55.33
Answer: D
In a certain quiz that consists of 10 questions, each question after the first is worth 4 points more than the preceding question. If the 10 questions on the quiz are worth a total of 300 points, how many points is the third question worth?	Choose one:	A) 22	B) 24	C) 26	D) 20	E) 28

Solution: x   x+4   x+8   x+12   x+16   x+20   x+24   x+28   x+32   x+36   10x+180=300   10x=120   x=12   3rd question = x+8 = 12+8= 
12+8 = 20
20   Answer 20
Answer: D
There are 85 doors marked with numbers 1 to 85. And there are 85 individuals marked 1 to 85.
An operation on a door is defined as changing the status of the door from open to closed or vice versa. All doors are closed to start with.
Now one at a time one randomly picked individual goes and operates the doors. The individual however operates only those doors which are a multiple of the number he/she is carrying. For e.g. individual marked with number 5 operates the doors marked with the following numbers: 5, 10, 15 ... 85.
If every individual in the group get one turn then how many doors are open at the end?  Choose the correct answer.
A) 0
B) 1
C) 2
D) 8
E) 9

Solution: Let us start with 1.   When 1 goes, all the doors are open since every number is a multiple of 1.   Also 1 will remain opened since 1 is not a multiple of any number.   Prime numbers can only be operated by people with prime numbers.   So 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59, 61,67,71,73,79,83 will be closed when people with respective numbers perform operations on them.   From the other numbers, only those numbers will remain opened on which even number of operations are performed including the operation performed by number 1.   This is possible only for perfect squares which are 4,9 ... 81.   So our numbers are 1,4,9,16,25,36,49,64,81.   Answer:- 9
Answer: E
A 12 month project had a total budget of $42,000. After eight months, the project had spent $23,700. At this point, how much was the project under budget?	Pick: A) $4100 B) $4300 C) $4500 D) $4700 E) $4900

Solution: Each month, the project should spend $42,000 / 12 = $3500.   In 8 months, the project should spend 8*$3500=$28,000.   The project is under budget by $28,000 - $23,700 = $4300.   The answer is $4300.
Answer: B
If M is the least positive integer that is divisible by every integer from 4 to 12 inclusive, then M/11 is = Choose the correct choice from the following answers
A) 40320	B) 27720	C) 20160	D) 6720	E) 2520

Solution: The integer should be divisible by: 4, 5, 6, 7, 8, 9, 10, 11 and 12, that is 2^2, 5, 2*3, 7, 2^3, 3^2, 2*5, 11, 3*2^2. The least common multiple of these integers is the product of 11, 7, 5, 3^2 and 2^3. Then, M/11 is (11 * 7 * 5 * 3^2 * 2^3)/11 = 7*5*9*8= 
7*5*9*8 = 2_520
2520.   Answer: 2520.
Answer: E
in a bus left side are 15 seats available,3 few seats in right side because in rear exit door .Each seat hold 3 people.In addition ,there is a seat back can sit 9 people all together .how many people can sit in a bus?	Select the correct option.
A) 52	B) 49	C) 95	D) 90	E) 66

Solution: Right Side =15 seat   Left Side =15-3 (3 few seat in right side)= 12 seat   Total= 15+12= 
15+12 = 27
27   People can seat in 27 seat= 27*3= 
27*3 = 81
81   People can seat in Last Seat= 9   Total People can seat= 81+9= 
81+9 = 90
90   ANSWER:90
Answer: D
If n = 2×3×5×7×11×13×14, then which of the following statements must be true?
I. n^2 is divisible by 600
II. n + 19 is divisible by 19
III. (n + 4)/2 is even  Pick:
A) I only
B) II only
C) III only
D) None of the above
E) I and III

Solution: Statement I: 600 = (2^3)*(3)*(5^2) this is true.   Statement 2 Since n is divisible by 19 so n+19 is also divisible by 19. So this is NOT true.   Statement 3: (n+4)/2 = n/2 + 2   So, ODD + 2 cannot be even.   So this is true.   Hence option (I and III).
Answer: E
The cost of carpeting a room 18 m long with a carpet 75 cm wide at 4.50 per metre is 810. The breadth of the room is:	Choose the correct option
A) 7 m	B) 7.5 m	C) 8 m	D) 8.5 m	E) None of these

Solution: Length of the carpet = TotalCost/Rate/m   = (8100⁄45)m = 180 m.   Area of the room = Area of the carpet   = (180 × 75⁄100) m2 = 135 m2   ∴ 7.5 mreadth of the room = AreaLength=135/18= 
135/18 = 15/2 = around 7.5
7.5 m   Answer 7.5 m
Answer: B
Average of prime numbers ranging 1 to 50 is? Choose the correct option:
A) 23 B) 22.86 C) 21.86 D) 21 E) 21.95

Solution: Explanation:   Average = (2+3+5+7+11+13+17+19+23+29+31+37+41+43+47)/15 = 328/15= 21.8666   Answer is 21.86
Answer: C
Find the compound ratio of (3:4), (4:5) and (1:2) is Options:  A) 1:2  B) 2:3  C) 3:10  D) 4:10  E) 3:2

Solution: Required ratio = 3/4 * 4/5 * 1/2 = 3/10= 3:10   Answer is 3:10
Answer: C
A sum fetched a total simple interest of Rs. 6016.75 at the rate of 8 p.c.p.a. in 5 years. What is the sum?
Answers.
A) Rs. 16241.875	B) Rs. 15041.85	C) Rs. 15401.875	D) Rs. 15041.875	E) None of these

Solution: Explanation:   Principal = Rs 100 x 6016.75/ 8 x 5   = Rs. 601675/40   = Rs. 15041.875   Answer: Option Rs. 15041.875
Answer: D
A woman can do a piece of work in 40 days. Man is 25% more efficient than Woman. In how many days a man can do the same piece of work? Choose the correct answer
A) 32 days
B) 33 days
C) 35 days
D) 54 days
E) 62 days

Solution: The ratio of the efficiencies of a woman and man = 100 : 125   = 4 : 5   The ratio of the days taken by woman and man to finish the work = 5 :4   Woman takes 32 days to finish the work.=> 5 parts = 40   The number of days taken by man to finish the work = 4 parts = 40/5x 4 = 32 days   32 days
Answer: A
A train is 510 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?
Choose the correct answer:
A) 76 seconds
B) 18 seconds
C) 52 seconds
D) 19 seconds
E) 45 seconds

Solution: Speed = 45 Km/hr = 45*(5/18) m/sec = 25/2 m/sec   Total distance = 510+140= 
510+140 = 650
650 meter   Time= Distance/speed   = 650 * (2/25)= 
650 * (2/25) = 52
52 seconds   Answer: 52 seconds
Answer: C
In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples? Select
A) 5/21
B) 5/28
C) 5/25
D) 5/23
E) 5/22

Solution: Number of ways of (selecting at least two couples among five people selected)   As remaining person can be any one among three couples left.   Required probability   = (10 * 6)/252 = 5/21   5/21nswer: 5/21
Answer: A
How many two digit numbers of distinct digits can be formed by using digits 1, 2, 3, 4, 5, 6 and 7 such that the numbers are divisible by 3?
Choose the correct choice from the following answers.
A) 9
B) 10
C) 11
D) 12
E) 14

Solution: A number will be divisible by 3 if sum of all the digits of the number is divisible by 3   Here the Possible sum of the two distinct digits can be 3, 6, 9 and 12 only in order to satisfy the given condition   If sum of Digits = 3, No. = 12, 21 --- 2 Cases   If sum of Digits = 6, No. = 15, 24, 42, 51 --- 4 Cases   If sum of Digits = 9, No. = 27, 36, 45, 54, 63, 72 --- 6 Cases   If sum of Digits = 12, No. = 57, 75 --- 2 Cases   Total Cases = 2+4+6+2= 
2+4+6+2 = 14
14 cases   Answer: option 14
Answer: E
2+3=8,
3+7=27,
4+5=32,
5+8=60,
6+7=72,
7+8=??
Solve it?
Select.
A) 78	B) 98	C) 88	D) 68	E) 58

Solution: 98   98   2+3=2*[3+(2-1)]=8   3+7=3*[7+(3-1)]=27   4+5=4*[5+(4-1)]=32   5+8=5*[8+(5-1)]=60   6+7=6*[7+(6-1)]=72   therefore   7+8=7*[8+(7-1)]=98   x+y=x[y+(x-1)]=x^2+xy-x
Answer: B
A train 110 m long is running with a speed of 80 km/hr. In what time will it pass a man who is running at 8 km/hr in the direction opposite to that in which the train is going?
Choose the correct option.
A) 5  B) 6  C) 4.5  D) 8  E) 9

Solution: Speed of train relative to man = 80 + 8= 
80 + 8 = 88
88 km/hr.= 88 * 5/18 = 220/9 m/sec.   Time taken to pass the men = 110 * 9/220= 
110 * 9/220 = 9/2 = around 4.5
4.5 sec.   Answer: Option 4.5
Answer: C
There r 4 prime numbers in ascending order. The multiplication of first 3 is 385 and that of last 3is 1001. what is the last number is	Choose the correct choice from the following options:	A) 9	B) 10	C) 12	D) 13	E) 14

Solution: Explanation:   abcbcd=3851001=>ad=513   abcbcd=3851001=>ad=513   So d = 13   13
Answer: D
Of a certain group of 100 people, 40 graduated from High School K, 65 graduated from College Y, and 30 live in City Z. What is the greatest possible number of people in this group who did not graduate from High School K, did not graduate from College Y, and do not live in City Z ?  Choose the correct answer: A) 5 B) 15 C) 35 D) 65 E) 85

Solution: 1. k+y+z+ky+yz+kz+kyz+ none=100. Fornoneto be maximum others have to be minimum   2. We know the underlined portions sum to 65 and that is the minimum value of others   3. Maximumnone= 100-65= 
100-65 = 35
35=35
Answer: C
Find compound interest on $ 12000 at 15% per annum for 2 years 4 months, compounded annually.	Choose the correct choice from the following choices:
A) 4663.5 B) 4203.5 C) 4303.5 D) 4403.5 E) 4103.5

Solution: Time = 2 years 4 months = 2(4/12) years = 2(1/3) years.   Amount = $ [12000 X (1+­(15/100))2 X (1+((1/3)*15)/100)]   =$ [12000 * (23/20) * (23/20) * (21/20)= 
12000 * (23/20) * (23/20) * (21/20) = 33_327/2 = around 16_663.5
$ 16663.50	.   :. C.I.= Rs. (16663.50 - 12000) = $ 4663.50   4663.5nswer 4663.5.
Answer: A
Pam and Stanley packed several boxes with reams of paper. While both packed, Pam packed 40% of the boxes. After Pam stopped, Stanley packed the same number of boxes that he had packed while working with Pam. What is the ratio of the number of boxes Pam packed to the number of boxes Stanley packed?
Choose the correct choice from the following: A) 2 to 6 B) 1 to 3 C) 3 to 5 D) 3 to 4 E) 3 to 2

Solution: Correct Answer: A   Solution: A. We know that when Pam and Stanley were both working, the ratio was 2 boxes by Pam to 3 boxes by Stanley. We also know that Stanley continued working after Pam stopped. He packed as many boxes alone as he had packed whlie working with Pam, effectively doubling his number of boxes. Thus, the ratio of Pam's boxes to Stanley's boxes is 2 to 6. 2 to 6nswer 2 to 6 is correct.
Answer: A
Let d > c > w > a. If c is twice as far from a as it is from d, and w is twice as far from c as it is from a, then (d - w)/(d - a) = ?  Choose the correct choice from the following:
A) 2/9 B) 1/3 C) 2/3 D) 7/9 E) 3/2

Solution: Draw a number line and label with x and y. You would have:   Before calculating recognize it would be more effcient to express x or y in terms of the other. here 2x = 3y so x =3/2 y.   Now you can calculate d -w and d -a   d - w= x +2y = 7/2 y   d - a = x + 2x = 3x = 9/2y   7/9ividing both you get: 7/9   Answer 7/9
Answer: D
An article costs Rs. 600. What should be the marked price of an article so that after 10% discount, the trader makes 20% profit?	Select the correct option:  A) Rs. 800  B) Rs. 950  C) Rs. 1100  D) Rs. 1040  E) None of these

Solution: Explanation:   Cost price of article = Rs. 600   Profit % = 20%   Therefore,   selling price of article = 120% of C.P.   = (120 / 100) * 600 = Rs. 720   Marked price = ?   Discount % = 10%   S.P. = Rs. 720   90% of M.P. = S.P.   90/100 * M.P. = 720   M.P. = 720 * (100/90) = Rs. 800   Rs. 800NSWER Rs. 800
Answer: A
The sum of three integers is 22. The largest integer is 3 times the middle integer, and the smallest integer is 13 less than the largest integer. What is the product of the three integers?	Choose the most appropriate option:  A) 130  B) 140  C) 150  D) 160  E) 170

Solution: Let x be the middle integer. Then the largest is 3x and the smallest is 3x - 13.   3x - 13 + x + 3x = 22   x = 5   The three integers are 2, 5, and 15.   The product is 2*5*15= 
2*5*15 = 150
150   The answer is 150.
Answer: C
In how many ways can 7 beads can be arranged to form a necklace?	Choices
A) 360  B) 780  C) 23  D) 10  E) 89

Solution: Number of arrangements possible   =12(7−1)!=12×6!=12×6×5×4×3×2×1=360   360nswer is 360
Answer: A
A father left a will of Rs.35 lakhs between his two daughters aged 8.5 and 16 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.35 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?	Choose the correct choice from the following choices:
A) 22 lakhs
B) 21 lakhs
C) 28 lakhs
D) 67 lakhs
E) 18 lakhs

Solution: Explanation:   Let Rs.x be the amount that the elder daughter got at the time of the will. Therefore, the younger daughter got (3,500,000 - x).   The elder daughter’s money earns interest for  (21 - 16)= 
 (21 - 16) = 5
5 years @ 10% p.a simple interest.   The younger daughter’s money earns interest for (21 - 8.5)= 
(21 - 8.5) = 12.5
12.5 years @ 10% p.a simple interest.   As the sum of money that each of the daughters get when they are 21 is the same,   Answer: 21 lakhs) 21 lakhs
Answer: B
The owner of a furniture shop charges his customer 25% more than the cost price. If a customer paid Rs. 8400 for a computer table, then what was the cost price of the computer table?  Choose the correct choice from the following
A) Rs. 5725
B) Rs. 5275
C) Rs. 6275
D) Rs. 6720
E) None of these

Solution: CP = SP * (100/(100 + profit%))   = 8400(100/125) = Rs. 6720.   ANSWER:Rs. 6720
Answer: D
1,235
1,253
1,325
.....
....
+5,321
The addition problem above shows four of the 24 different integers that can be formed by using each of the digits 1,2,3,5 exactly once in each integer. What is the sum of these 24 integers? Choose the correct option
A) 73,326
B) 78,524
C) 84,820
D) 89,918
E) 95,560

Solution: In each of the units, tens, hundreds, and thousands place, each digit will appear 6 times.   Then the sum equals 6(1111)+6(2222)+6(3333)+6(5555) = 73,326   The answer is 73,326.
Answer: A
Mark and Ann together were allocated n boxes of cookies to sell for a club project. Mark sold 8 boxes less than n and Ann sold 2 boxes less than n. If Mark and Ann have each sold at least one box of cookies, but together they have sold less than n boxes, what is the value of n?	Select.
A) 5	B) 6	C) 7	D) 8	E) 9

Solution: if n =9   mark sold 1 box   and Ann sold 7 boxes   total 8 < 9   Answer:9
Answer: E
When Q is divided by N, the quotient is R and the remainder is E. Which of the following expressions is equal to E?  Select
A) RN + Q	B) RN - Q	C) Q - RN	D) QN - R	E) Q/R

Solution: Q/N = R + E/N   Q -RN = E   Amswer: Q - RN
Answer: C
A car starts from A for B travelling 20 km an hour.1 1/2 hours later another car starts from A and travelling at the rate of 30 km an hour reaches B 2 1/2 hours before the first car. Find the distance from A to B.
Choose the correct choice from the following choices
A) 280 km  B) 260km  C) 240km  D) 340km  E) None of these

Solution: Let the distance between A and B be x   The second car stars 1.5 hour later and reaches 2.5 hour early then first car   so the time difference is 4 hours.   Thus, x/20 - x/ 30 = 4   or, x = 240   ANSWER:240km
Answer: C
Find the lowest common multiple of 24, 36 and 40.
Choose the correct choice from the following
A) 120 B) 240 C) 360 D) 480 E) 530

Solution: 2 | 24 - 36 - 40   --------------------   2 | 12 - 18 - 20   --------------------   2 | 6 - 9 - 10   -------------------   3 | 3 - 9 - 5   -------------------   | 1 - 3 - 5   L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.   Answer: Option 360
Answer: C
Machine A produces pencils at a constant rate of 9000 pencils per hour, and machine B produces pencils at a constant rate of 7000 pencils per hour. If the two machines to gather must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time Q, in hours, that machine B must operate?	Pick one.
A) 4 B) 4 2/3 C) 5 1/3 D) 6 E) 6 1/4

Solution: Machine A produces pencils at a constant rate of 9,000 pencils per hour, and machine B produces pencils at a constant rate of 7,000 pencils per hour. If the two machines together must produce 100,000 pencils and if each machine can operate for at most 8 hours, what is the least amount of time Q, in hours, that machine B must operate?   a) 4   b) 4 and 2/3   c) 5 and 1/3   d) 6   e) 6 and 1/4   To minimize the time that machine B must operate we must maximize the time machine A can operate, so make it operate 8 hours. In 8 hours machine A will produce 8*9,000=72,000 pencils, so 100,000-72,000=28,000 pencils are left to produce, which can be produced by machine B in 28,000/7,000=4 hours.   4nswer: 4.
Answer: A
A 21 cm long wire is to be cut into two pieces so that one piece will be 2/5th of the other, how many centimeters will the shorter piece be?  Choose the correct choice from the following choices
A) 12
B) 6
C) 88
D) 77
E) 14

Solution: 1: 2/5 = 5: 2   2/7 * 21= 
2/7 * 21 = 6
6   Answer: 6
Answer: B
Each of the 59 members in Peter's school class is required to sign up for a minimum of one and a maximum of three academic clubs. The three clubs to choose from are the poetry club, the history club, and the writing club. A total of 22 students sign up for the poetry club, 27 students for the history club, and 28 students for the writing club. If 6 students sign up for exactly two clubs, how many students sign up for all three clubs? Select:  A) 2  B) 5  C) 6  D) 8  E) 9

Solution: Each of the 59 members in Peter's school class is required to sign up for a minimum of one and a maximum of three academic clubs. Total = G1 + G2 + G3 - (# In exactly 2) - 2*(# in 3 sets)   59 = 22+27+28 - (6) - 2x   so, # In 3 sets = 6=6
Answer: C
A driver took a trip consisting of three segments at three different speeds. The driver drove a distance of (7D) at a speed of (2V), then a distance of (10D) at a speed of (3V), then a distance of D at a speed of (6V). In terms of D and V, what was the total time of the trip? Choose the most appropriate option.
A) 3D/V B) 4D/V C) 5D/V D) 6D/V E) 7D/V

Solution: The total time of the trip was:   7D/2V + 10D/3V + D/6V =   42D/12V + 40D/12V + 2D/12V =   84D/12V = 7D/V   The answer is 7D/V.84 /12= 
84 /12 = 7
7D/V   The answer is 7D/V.
Answer: E
A certain no. when divided by 50 leaves a remainder 25, what is the remainder if the same no.be divided by 15?  Choose one.
A) 3	B) 4	C) 5	D) 8	E) 9

Solution: Explanation:   50 + 25= 
50 + 25 = 75
75/15= 
75/15 = 5
5 (Remainder)   5
Answer: C
The bankers discount of a certain sum of money is Rs. 576 and the true discount on the same sum for the same time is Rs. 480. The sum due is: Choose the correct choice.
A) 2880  B) 2870  C) 2860  D) 2850  E) 2840

Solution: Sum = (B.D*T.D)/(B.D-T.D)   (576*480)/576-480;   2880   2880NSWER:2880
Answer: A
Q is a set of six distinct prime numbers. If the sum of the integers in Q is even and the number x is a member of Q, then what is the least value that x can be?
Choose the correct answer:
A) 2 B) 3 C) 4 D) 5 E) 7

Solution: 2 + 3 + 5 + 7 + 11 + 13= 
2 + 3 + 5 + 7 + 11 + 13 = 41
41 (Discard as sum is ODD)   3 + 5 + 7 + 11 + 13 + 17= 
3 + 5 + 7 + 11 + 13 + 17 = 56
56 (Sum is even)   Least number= 3   3
Answer: B
Can anyhow help me with an easy solution for this
2, 3, 9, 5, 6, 81, 6, 7, ?
Answers: A) 256 B) 221 C) 121 D) 144 E) 169

Solution: 2, 3, 9, 5, 6, 81, 6, 7, ?   2+73=5 and   5-2= 
  5-2 = 3
3 and 3^2=9   5+6= 
5+6 = 11
11 and   11-2= 
  11-2 = 9
9 and 9^2=81   6+7= 
6+7 = 13
13 and   13-2= 
  13-2 = 11
11 and 11^2=121   ANSWER:121
Answer: C