MU-NLPC/Calc-aqua_rat huggingface dataset:
Brian is analyzing the performance of certain stocks. He finds that for the first fifteen days of a 30 day period, the daily closing price per share of Phoenix Pharma Inc. conformed to the function f(x)=0.4x+2f(x)=0.4x+2 , where x represents the day in the period. He found that for the last 15 days in the same period, the stock followed the function f(x)=(−1/7)x+9f(x)=(−1/7)x+9, where x represents the day in the period. Approximately what is the median closing price per share of Phoenix Pharma Inc. for the entire 30 day period?  Select the correct option.
A) 4.7	B) 5.55	C) 6.71	D) 8	E) 11.1

Solution: First 15 days: F1, x= 1 to 15 and f(x)= 2.4 to 8   Last 15 days: F2, x= 16 to 30 and f(x) = ~4.7 to ~6.7 (30th to 16th)   Median is average of 15th and 16th value when all of the above values are arranged in order   Do not try to calculate all the values. Go for the choices.   11.1 - outside the range of values   8- last value   6.71 - last value for the F2, so already we have 15 values less than 6.71. Additionally F1 has some values less.   4.7 - First value for the F2, so already we have 15 values greater than 4.7. Additionally F1 has some values greater.   Hence 5.55 must be the answer.   ANSWER:5.55
Answer: B
Set J consists of 10 consecutive even numbers. If the smallest term in the set is -4, what is the range of the positive integers in set J?  Choose the correct choice from the following options
A) 8	B) 12	C) 14	D) 16	E) 18

Solution: Since there are only 10 integers, another approach is the just list all 10.   We get: -4, -2,0,2, 4, 6, 8, 10, 12, 14   Range of POSITIVE INTEGERS =14-2= 
14-2 = 12
12   Answer: 12
Answer: B
Someone on a skateboard is traveling 15 miles per hour. How many feet does she travel in 30 seconds? (1 mile = 5280 feet)
Choose the most appropriate option:
A) 600 ft  B) 660 ft  C) 670 ft  D) 680 ft  E) 700 ft

Solution: per second => 15*5280 ft/60*60 =22 ft   30 seconds => 22 * 30= 
22 * 30 = 660
660 ft   Answer : 660 ft
Answer: B
A ratio between two numbers is 3 : 4 and their L.C.M. is 84. The first number is	Options:  A) 60  B) 45  C) 21  D) 15  E) None

Solution: Sol.   Let the required numbers be 3x and 4x. Then, their L.C.M. is 12x.   ∴ 12x = 84⇔ x = 7. Hence, the first number is 21.   Answer 21
Answer: C
The number x of cars sold each week varies with the price y in dollars according to the equation x = 800,000 – 50y. What would be the total weekly revenue T, in dollars, from the sale of cars priced at $ 15,000?
Choose the correct choice from the following options
A) 50,000
B) 750,000
C) 850,000
D) 7,500,000
E) T=750,000,000

Solution: number of cars sold = x=800000-50y   y=15000   x=800000-750000= 
800000-750000 = 50_000
50000   revenue from 50000 cars=15000*50000= 
15000*50000 = 750_000_000
750000000 T=750,000,000
Answer: E
On Saturday morning, Malachi will begin a camping vacation and he will return home at the end of the first day on which it rains. If on the first three days of the vacation the probability of rain on each day is 0.2, what is the probability that Malachi will return home at the end of the day on the following Monday?	Choose the correct choice from the following
A) 0.008 B) 0.128 C) 0.488 D) 0.512 E) 0.64

Solution: Probability of rain on Saturday OR Probability of rain on Sunday (given that it didn't rain on Saturday) OR Probability of rain on Monday (given that it didn't rain on Sunday)   = 0.2 + (0.8 x 0.2) + (0.8 x 0.8 x 0.2)   = 0.2 + 0.16 + (0.128 <- The actual answer!)   =0.488   ANSWER:0.488
Answer: C
What will come in place of the x in the following Number series? 6, 12, 21, x , 48
Answers.
A) 33  B) 45  C) 75  D) 56  E) 85

Solution: (A)   The pattern is + 6, + 9, + 12, +15 ………..   So the missing term is = 21 + 12= 
21 + 12 = 33
33
Answer: A
A person sells 36 oranges per rupee and suffers a loss of 4%. Find how many oranges per rupee to be sold to have again of 8%?
Select the correct option.
A) 30 B) 31 C) 32 D) 33 E) None of these

Solution: 1⁄36 : (100 - 4) :: x :   (100 + 8)= 
  (100 + 8) = 108
108/96×36=132   He sells 32 oranges per rupee.   Answer 32
Answer: C
A can do a job in 20 days and B can do it in 30 days. A and B working together will finish twice the amount of work in days?  Options.
A) 22 1/6 B) 24 C) 22 1/0 D) 22 1/9 E) 22 1/1

Solution: 1/20 + 1/30 = 5/60 = 1/12   12 = 12 *2= 
12 *2 = 24
24 days   Answer: 24
Answer: B
A walks at 10 kmph and 7 hours after his start, B cycles after him at 20 kmph. How far from the start does B catch up with A?	Answers.
A) 100km B) 140km C) 50km D) 120km E) 200km

Solution: Suppose after x km from the start B catches up with A. Then, the difference in the time taken by A to cover x km and that taken by B to cover x km is 7 hours.   x/10 - x/20 = 7   x = 140 km   Answer is 140km
Answer: B
A car travells the first 1/2 of certain distance with a speed of 10km/hr the next 1/4 distance witha a speed of 20 km/hr, and the last 1/4 distance with a speed of 60 km/hr. the average speed of the carfor the whole journey is?	Choose the correct answer:
A) 12km/hr
B) 15km/hr
C) 89km/hr
D) 52km/hr
E) 79km/hr

Solution: Let the whole distance travelled be x km   and the average speed of the car for he whole journey be y km/hr   then (x/2)/10+(x/4)/20+(x/4)/60=x/y   x/20+x/80+x/240=x/y   1/15y=1   y=15km/hr   Answer(15km/hr)
Answer: B
Two carpenters, working in the same pace, can build 2 desks in two hours and a half. How many desks can 4 carpenters build in 3 hours?  Choices
A) 2.4.
B) 3.6.
C) 4.8.
D) 5.5.
E) 6.4

Solution: W = 2 desks   T = 2.5 hrs   Rate of 2 carpenters = 2×R   Rate = work done/ time   2xR = 2/2.5   R = 1/2.5 = 2/5 (this is the rate of each carpenter)   Work done by 4 carpenters in 3 hrs = 4 × rate of each carpenter x time = 4× 2/5 × 3 =4.8 desks   4.8. is the correct answer.
Answer: C
A bag contains a certain number of 50 paise coins, 20 paise coins and 10 paise coins inthe ratio 3:4:5. If the total value of all the coins in the bag is Rs.630, find the number of 50 paise coins ?
Options.
A) 498	B) 488	C) 428	D) 528	E) 675

Solution: 50*3k + 20*4k + 10*5k = 63000   280k = 63000 => k =225   50p coins = 3k = 3*225= 
3*225 = 675
675   ANSW675R:675
Answer: E
The average of four results is 222 and that of the first three is 219. The fourth result is? Select the correct option:
A) 231	B) 201	C) 85	D) 192	E) 215

Solution: 4 * 222 â€“ 3 * 219 = 231   231nswer: 231
Answer: A
A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 267 metres long in 20 seconds. The length of the train (in metres) is:
Choose the correct choice from the following.
A) 178  B) 176  C) 175  D) 96  E) None of these

Solution: Explanation:   Let the length of train be L m.   Acc. to question   (267+L)/20 = L/8   2136+8L=20L   L= 2136/12= 
2136/12 = 178
178 m   178nswer 178
Answer: A
A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is? Choose the correct choice
A) 76 km/hr	B) 50 km/hr	C) 17 km/hr	D) 18 km/hr	E) 14 km/hr

Solution: Speed of the train relative to man   = (125/10) m/sec = (25/2) m/sec. [(25/2) * (18/5)] km/hr   = 45 km/hr. Let the speed of the train be x km/hr. Then, relative speed   = (x - 5) km/hr. x - 5   = 45 ==> x = 50 km/hr.   Answer: 50 km/hr
Answer: B
In a cinema hall for the matinee show which started at 2.30 pm and ended at 5.30 pm the vehicle parking lot had only three wheelers (auto rickshaws) and four wheelers. Today the wheels of the vehicles parked was counted and found to be 240. What could be the number of three wheelers parked therein ?	Choices:
A) 10	B) 48 wheelers	C) 37	D) 97	E) 12

Solution: 3X + 4y = 240   by substitute through options 48 is correct   Answer: 48 wheelers
Answer: B
To fill an art exhibit, the students in an art course are assigned to create one piece of artwork each in the following distribution: 1/3 are sculptures, 1/8 are oil paintings, 1/2 are watercolors, and the remaining 10 pieces are mosaics. How many students are in the art class?  Choose the correct choice from the following answers
A) 80 B) 120 C) 240 D) 320 E) 400

Solution: Let the total number of students in the art class = s   Distribution of artwork is as   1/3 are sculptures   1/8 are oil paintings   1/2 are watercolors, and the remaining 10 pieces are mosaics   (1/3)s +(1/8)s +(1/2)s + 10 = s   Since remaining 10 pieces are mosaics , (1/24)s = 10   s = 240   Answer 240
Answer: C
A garrison of 400 men had a provision for 31 days. After 26 days 275 persons re-enforcement leave the garrison. Find the number of days for which the remaining ration will be sufficient?	Pick:
A) 16 days B) 45 days C) 10 days D) 17 days E) 18 days

Solution: 400 --- 31   400 --- 5   125 --- ?   400*5 = 125*x => x =16 days.   16 daysnswer: 16 days
Answer: A
The population of a village is 12000. It increases annually at the rate of 24% p.a. What will be its population after 2 years?  Pick:
A) 14567
B) 18451
C) 18789
D) 18786
E) 14400

Solution: Formula :   ( After =100 denominator   Ago = 100 numerator)   12000 × 124/100 × 124/100 = 18451   18451
Answer: B
For each month of a given year except December, a worker earned the same monthly salary and donated one-tenth of that salary to charity. In December, the worker earned N times his usual monthly salary and donated one-fifth of his earnings to charity. If the worker's charitable contributions totaled one-sixth of his earnings for the entire year, what is the value of N? Choose the correct choice from the following choices:
A) 8/5  B) 22  C) 3  D) 11/3  E) 4

Solution: Let monthly salary for each of the 11 months except December was x, then   11x*1/10 + Nx*1/5 = 1/6(11x + Nx);   11/10 + N/5 = 1/6(11 + N)   11+2N/10 = 11+N/6 =>66+12N = 110+10N =>2N=44   N = 22   Answer: 22
Answer: B
A man gets a simple interest of Rs.300 on a certain principal at the rate of 5% p.a in two years. Find the compound interest the man will get on twice the principal in two years at the same rate?	Pick:
A) s.256 B) s.315 C) s.415 D) s.514 E) s.615

Solution: Let the principal be Rs.P   S.I at 5% p.a in 2 years on Rs.P = Rs.300   (P)(2)(5)/100 = 300   P = 3000   C.I on Rs.2P i.e., Rs.6000 at 5% p.a in two years   =6000{ [1 + 5/100]^2 - 1}   = 6000(41/400)   = Rs.615   Answer:s.615
Answer: E
A woman gains 20% by selling an article for a certain price. If the sells it at double the price, the percentage of profit will be:	Choose the correct choice: A) 60% B) 34% C) 140% D) 100% E) 55%

Solution: C   C.P. = Rs. x.   Then, S.P. = Rs. (12% of x) = Rs. 6x/5   New S.P. = 2 * 6x/5 = Rs. 12x/5   Profit = 12x/5 - x = Rs. 7x/5   Profit = 7x/5 * 1/x * 100 = 140%.
Answer: C
Jupiter travels around the sun at a speed of approximately 8.1 miles per second. The approximate speed is how many miles per hour?  Select
A) 20,180
B) 23,120
C) 26,140
D) 29,160
E) 32,240

Solution: 8.1 * 3600 = 29,160   The answer is 29,160.
Answer: D
If 12 men can reap 120 acres of land in 36 days, how many acres of land can 24 men reap in 62 days?	Choose the correct choice from the following answers:
A) 266.5	B) 413.3	C) 425.8	D) 189.3	E) 249.6

Solution: 12 men 120 acres 36 days   24 men ? 62 days   120 * 24/12 * 62/36   120 * 2 *31/18   240* 1.72 = 413.3   Answer:413.3
Answer: B
In the question A^B means A raised to the power of B. What is the value of A such that
X^2-11x+A and X^2 -14X +2A will have a common factor?  Choose the correct choice from the following:
A) -1/2
B) 24
C) -3
D) 20
E) 15

Solution: due to quadratic equation..... the factor will be like (x-a)(x-b)   lets assume (x-k) is the common factor the   x=k is the root of both the eqn   X^2-11X+A=0 , & X^2-14X+2A=0   satisfying these two equations we get   k^2-11k+A=0 ..................................(1)   k^2-14k+2A=0 ..................................(2)   on solving we will get   k=A/3   substituting this in eq 1 we get A=0 and A= 24   so A=24   ANSWER:24
Answer: B
Bob bikes to school every day at a steady rate of e miles per hour. On a particular day, Bob had a flat tire exactly halfway to school. He immediately started walking to school at a steady pace of y miles per hour. He arrived at school exactly t hours after leaving his home. How many miles is it from the school to Bob's home?
Select the correct option
A) (x + y) / t
B) 2(e + t) / ey
C) 2eyt / (e + y)
D) 2(e + y + t) / ey
E) x(y + t) + y(x + t)

Solution: If we choose for d (distance): 10 miles, for e 10 and for y 5.   t would be 90 minutes or 1,5 hours.   If I try this for answer choice 2eyt / (e + y) it fits.
Answer: C
Dany bought a total of 28 game cards some of which cost $0.25 each and some of which cost $0.15 each. If Dany spent $4.2 to buy these cards, how many cards of each type did he buy?  Answers
A) 4	B) 10	C) 7	D) 28	E) 12

Solution: Let X be the number of cards that cost $0.25 each and Y the number of cards that cost $0.15 each. The total number of cards is 28. Hence   X + Y = 28   If X is the number of cards at $0.25, then the X cards cost   0.25 X   If Y is the number of cards at $0.15, then the Y cards cost   0.15 Y   The total cost of the X cards and the the Y cards is known to be $4.2 and also given by   0.25 X + 0.15 Y = 4.2   We now need to solve the system of equations   X + Y = 28   0.25 X + 0.15 Y = 4.2   The first equation gives Y = 28 - X. Substitute y by 28 - x in the second equation and solve   0.25 X + 0.15 (28 - X) = 4.2   X(0.25 - 0.15) + 4.2= 4.2   0.1 X = 0   X = 0 and Y = 28 - 0= 
28 - 0 = 28
28   correct answer 28
Answer: D
One fourth of a solution that was 10% sugar by weight was replaced by a second solution resulting in a solution that was 20 percent sugar by weight. The second solution was what percent sugar by weight? Pick.
A) 65% B) 50% C) 22% D) 18% E) 8.5%

Solution: Say the second solution (which was 1/4 th of total) was x% sugar, then 3/4*0.1+1/4*x=1*0.20 --> x=0.5. Alternately you can consider total solution to be 100 liters and in this case you'll have: 75*0.1+25*x=100*0.20 --> x=0.5.   Answer: 50%.
Answer: B
Three pipes A, B and C can fill a tank in 7 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 8 hours. How many hours will take C alone to fill the tank?  Select:
A) 35/8  B) 38/7  C) 43/6  D) 49/4  E) 56/3

Solution: The rate of A+B+C is 1/7 of the tank per hour.   After 2 hours, the tank is 2/7 full.   The rate of A+B is 5/7 * 1/8 = 5/56 of a tank per hour.   The rate of C is 1/7 - 5/56 = 3/56   C can fill the tank in 56/3 hours.   The answer is 56/3.
Answer: E
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 50, what is the compound interest on the same sum at the rate and for the same time?
Choose the correct choice:
A) Rs. 51.25
B) Rs. 52
C) Rs. 54.25
D) Rs. 60
E) Rs. 70

Solution: Sum = (50 * 100) / (2 * 5) = Rs. 500   Amount = [500 * (1 + 5/100)2] = Rs. 551.25   C.I. = (551.25 - 500) = Rs. 51.25.   Rs. 51.25NSWER:Rs. 51.25
Answer: A
What number comes next in this Number series.
5 3 4 4 6 9 7 ?
*Hint: check calende
Choose the correct choice:	A) 8	B) 3	C) 6	D) 1	E) 7

Solution: E   8 (the number of letters in the month November)   8pril : 5 letters   May : 3 letters   June : 4 letters   July : 4 letters   8ugust: 6 letters   September : 9 letters   October : 7 letters
Answer: A
A and B start a business, with A investing the total capital of Rs.50000, on the condition that B pays A interest @ 10% per annum on his half of the capital. A is a working partner and receives Rs.1500 per month from the total profit and any profit remaining is equally shared by both of them. At the end of the year, it was found that the income of A is twice that of B. Find the total profit for the year?	Choose the correct option:
A) 59020	B) 59299	C) 59020	D) 59300	E) 59008

Solution: Interest received by A from B = 10% of half of Rs.50000 = 10% * 25000 = 2500.   Amount received by A per annum for being a working partner = 1500 * 12 = Rs.18000.   Let 'P' be the part of the remaining profit that A receives as his share. Total income of A = (2500 + 18000 + P)   Total income of B = only his share from the remaining profit = 'P', as A and B share the remaining profit equally.   Income of A = Twice the income of B   (2500 + 18000 + P) = 2(P)   P = 20500   Total profit = 2P + 18000   = 2*20500 + 18000= 
2*20500 + 18000 = 59_000
59000   Answer: 59300
Answer: D
What is the perimeter of a square field whose diagonal is 8√2?  Answers
A) 17 min B) 19 min C) 18 min D) 20 min E) 12 min

Solution: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages.   Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr.   stoppage time = 20/60 hrs   =20 min.   Answer: 20 min
Answer: D
100 people are attending a newspaper conference. 45 of them are writers and more than 36 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? Pick.
A) 26	B) 24	C) 18	D) 20	E) 22

Solution: {Total}={Writers}+{Editors}-{Both}+{Neither}.   {Total}=100;   {Writers}=45;   {Editors}>38;   {Both}=x;   {Neither}=2x;   100=45+{Editors}-x+2x --> x=55-{Editors}. We want to maximize x, thus we should minimize {Editors}, minimum possible value of {Editors} is 37, thus x={Both}=55-37= 
55-37 = 18
18.   Answer:18 .
Answer: C
A number is doubled and 5 is added. If the resultant is trebled, it becomes 111. What is that number?  Pick one:
A) 12 B) 29 C) 27 D) 16 E) 99

Solution: Explanation:   Let the number be x.   Therefore,   3(2x + 5) = 111   6x + 15 = 111   6x = 96   x = 16   ANSWER:16
Answer: D
Of the 200 students at University XYZ majoring in one or more of the engineering disciplines, 140 are majoring in electrical and 150 are majoring in mechanical. If at least 30 of the students are not majoring in either electrical or mechanical, then the number of students majoring in both electrical and mechanical could be any number from	Choose the correct choice from the following options:
A) 30 to 70 B) 70 to 100 C) 90 to 110 D) 130 to 150 E) 150 to 170

Solution: if there are 140 students majoring in electrical then there must be 60 person not majoring electrical at all, since both of the student not majoring electrical and mechanical is at least 30, so the number of the student who are not majoring electrical but majoring mechanical will be at least 30.   if there are 150 students majoring in mechanical there must be 50 students who are not majoring mechanical at all, since the number of the student who are not majoring electrical but majoring mechanical will be at least 30, hence the number of students both majoring mechanical and electrical will be at least 90   so there must be at least 90 students who major in both   see the answers option the only possible answer is 90 to 110 !
Answer: C
A windmill is taking advantage of strong air currents in order to produce electrical energy. On a typical day the wind speed is around 20 mph and in that speed the windmill produces 600 kw/h (kilowatts per hour). On a stormy day a windmill produces 20% more energy. How much kw/h can three windmills produce in two hours on a stormy day?
Choose the correct choice from the following choices
A) 2880. B) 4860. C) 5780 D) 4320 E) 6380.

Solution: Normal 4320ay = 600 kw/h   Stormy 4320ay = 600*1.2= 
600*1.2 = 720
720 kw/h   3 windmills for 2 hours on stormy day     720*3*2= 
  720*3*2 = 4_320
4320   Answer: 4320
Answer: D
What is the total number of prime numbers less than 65? Choose the correct choice from the following answers.
A) 17
B) 18
C) 19
D) 20
E) 21

Solution: Solution   Prime numbers less than 65 are	=18.   2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61   Their number is 18.   Answer 18
Answer: B
A, B, C together started a business. A invested Rs.400 for 5 months B invested Rs.1200 for 6 months and C Rs.1600 for 3 months. If they get a total profit of Rs.7000. Find the share of A?
Choose the correct answer:
A) 2999 B) 3000 C) 2777 D) 500 E) 17212

Solution: 1*5:3*6:4*3   5: 18: 12   5/35 * 3500= 
5/35 * 3500 = 500
500   Answer:500
Answer: D
In the equation ax^2 + bx + c = 0 a, b, and c are constants, and abc # 0. If one root of the equation is -2, and b = 4a then which of the following is c equal to?
Choose the correct choice from the following answers:
A) a/12
B) a/8
C) 4a
D) 8a
E) 12a

Solution: The sum of the roots is = -b/a = -4a/a = -4. Let the other root be x. Thus, x-2 = -4   x = -2. Again, the product of the roots is   -2*-2= 
  -2*-2 = 4
4. Thus, c/a=4. c = 4a.   4a.
Answer: C
If two dice are thrown together, the probability of getting an even number on one die and an odd number on the other is -.  Choose the correct choice from the following:
A) 1/4 B) 1/2 C) 3/4 D) 3/5 E) None of these

Solution: The number of exhaustive outcomes is 36.   Let E be the event of getting an even number on one die and an odd number on the other. Let the event of getting either both even or both odd then = 18/36 = 1/2   P(E) = 1 - 1/2 = 1/2.   ANSWER:1/2
Answer: B
There were totally 100 men.80 are married.75 have T.V, 85 have radio,70 have A.C. How many men have T.V, radio, A.C and also married?  Choose the correct choice from the following
A) 10	B) 12	C) 13	D) 14	E) 15

Solution: 100-(100-80)-(100-75)-(100-85)-(100-70)= 100-20-25-15-30=100-90= 
100-90 = 10
10   10NSWER:10
Answer: A
A number when divided by 296 leaves 75 as remainder when the same number is divided by 37 then the remainder will be?  Select
A) 2	B) 9	C) 6	D) 5	E) 1

Solution: let x=296q+75=(37*8q+37*2)+1   37*(8q+2)+1   thus when the number is divided by 37 the remainder is 1   Answer(1)
Answer: E
A university needs to select a nine-member committee on extracurricular life, whose members must belong either to the student government or to the student advisory board. If the student government consists of 9 members, the student advisory board consists of 8 members, and 6 students hold membership in both organizations, how many different committee are possible? Choose one
A) 44	B) 55	C) 66	D) 77	E) 88

Solution: student government + the student advisory board consists of  9 + 8= 
 9 + 8 = 17
17 members.   6 students hold membership in both, so they were counted twice.   The total number of people to choose from is 17 - 6= 
17 - 6 = 11
11   The number of ways to choose 9 members from 11 is 11C9= 55   The answer is 55.
Answer: B
If a coin is flipped, the probability that the coin will land tails is 1/2. If the coin is flipped 4 times, what is the probability that it will land tails up on the first 2 flips and not on the last 2 flips?  Choose one.
A) 1/4 B) 1/8 C) 1/2 D) 1/16 E) 1/32

Solution: (1/2) * (1/2) * (1/2) * (1/2) = 1/16 Answer: 1/16
Answer: D
Arrange the given words in the sequence in which they occur in the dictionary and choose the correct sequence.
1. Economic
2. Earlier
3. Each
4. Edition
5. Eager  Choose the correct option:  A) 3, 4, 1, 5, 2  B) 2, 1, 3, 5, 4  C) 3, 2, 4, 1, 5  D) 3, 5, 2, 1, 4  E) None of these

Solution: Explanation:   The correct alphabetical order is   Each, Eager, Earlier, Economic, Edition   ANSWER 3, 5, 2, 1, 4
Answer: D
On increasing the price of T.V. sets by 80%, their sale decreases by 20%. What is the effect on the revenue receipts of the shop ?	Select the correct option
A) 44	B) 5	C) 56	D) 2	E) 7

Solution: Explanation:   Let the price be = Rs.100, and number of units sold = 100   Then, sale value = Rs.(100 × 100) = Rs.10000   New sale value = Rs.(180 × 80) = Rs.14400   Increase% =4400/10000 × 100 = 44%   44nswer: 44
Answer: A
Margaret is 12 years more than twice the age of his son. The age of son is 12. Find the age of mother and find the difference between their ages Options.
A) 10yrs B) 24yrs C) 30yrs D) 40yrs E) 50yrs

Solution: Let, age of son x=12   Margaret is 12 years more than twice the age of his son, y = 8+2(x)   =12+2(12)   =12+24= 
12+24 = 36
36yrs   Difference= 36 - 12= 
36 - 12 = 24
24yrs   ANSWER:24yrs
Answer: B
The sum of ages of 5 children born 3 years different each is 65 yrs. What is the age of the Elder child?	Choose one:	A) 17	B) 19	C) 16	D) 18	E) 21

Solution: Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.   Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 65   5x = 35   x = 7.   x+12= 7+12= 
7+12 = 19
19   19
Answer: B