MU-NLPC/Calc-aqua_rat huggingface dataset:
A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $500 and $300 per unit, respectively. What is the fewest number of computer printers that the company can purchase?	Choose the correct option.
A) 2  B) 3  C) 4  D) 6  E) 8

Solution: The smallest amount that the company can spend is the LCM of 500 and 300, which is 1500 for each, which is total 3000.   The number of 1st type of computers which costing $500 = 1500/500= 
1500/500 = 3
3.   The number of 2nd type of computers which costing $300= 1500/300 = 3.   Total = 3+3= 
3+3 = 6
6   Answer is 6.
Answer: D
The income tax in the area where the Jones family lives is scheduled to increase by 12% next year. Since the Jones family cannot afford an increase in their tax bill, how much will they have to reduce income by to keep their cost the same? Select
A) 10.7% B) 10% C) 10.3% D) 10.9% E) 10.2%

Solution: Solution: Let the current tax be represented by Rs. 100.   The tax rate rises 12%. So, to continue to have the same income, they need to increase their tax,   = (100 + 12% of 100) = Rs. 112.   But, they want to keep tax expense the same, so they have to cut Rs. by 12 to keep it to Rs. =100.   The % decrease in income is,   (12/112)*100 = 10.7%.   Mental Calculation Method;   100-----12%↑---→112------X%↓---→100.   Here, X = (12/112)*100 = 10.7%.   10.7%nswer: Option 10.7%
Answer: A
At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether ? Answers:
A) 20
B) 45
C) 55
D) 90
E) 80

Solution: number of handshakes = 10C2= 10*9/2= 
10*9/2 = 45
45   ANSWER:45
Answer: B
A tank is filled in eight hours by three pipes A, B and C. Pipe A is twice as fast as pipe B, and B is twice as fast as C. How much time will pipe B alone take to fill the tank?
Choices:
A) 18 hours
B) 28 hours
C) 98 hours
D) 16 hours
E) 12 hours

Solution: 1/A + 1/B + 1/C = 1/8 (Given)   Also given that A = 2B and B = 2C   => 1/2B + 1/B + 2/B = 1/8   => (1 + 2 + 4)/2B = 1/8   => 2B/7 = 8   => B = 28 hours.   Answer:28 hours
Answer: B
Walking at 4/7 of its usual speed, a train is 9 minutes late. Find its usual time to cover the journey.	Choose the correct choice from the following answers:
A) 8min. B) 10min. C) 12min. D) 15min. E) 17min.

Solution: Explanation :   Solution: New speed = 4/7 of the usual speed. Let usual time be x.   .'. New time taken = 7/4 of usual time = 7x/4   so, (7x/4 ) - x = 9 min.   => 3x = 36   => x = 12 min.   Answer : 12min.
Answer: C
Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is
Choose the correct choice from the following answers
A) 17/28  B) 17/27  C) 17/19  D) 17/20  E) 17/22

Solution: n(S) = 20   n(Even no) = 10 = n(E)   n(Prime no) = 8 = n(P)   P(EᴜP) = 10/20 + 8/20 - 1/20 = 17/20   Answer: 17/20
Answer: D
What is the greatest of 3 consecutive integers whose sum is 30 ?
Choose the most appropriate option
A) 11
B) 7
C) 8
D) 9
E) 5

Solution: The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3   If the sum is 24, we need to solve the equation 3n + 3 + (  + 1) + (  + 2)= 
+ (  + 1) + (  + 2) = 3
3n + 3   If the sum is 24, we need to solve the equation 3n + 3= 30;   => 3n = 27;   => n = 9   The greatest of the three numbers is therefore   9 + 2= 
  9 + 2 = 11
11 11nswer: 11
Answer: A
A and B together can complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work? Options.
A) 2 days B) 3 days C) 6 days D) 5 days E) 8 days

Solution: Sol. (A + B)'s 1 day's work = (1/4). A's 1 day's work = (1/12).   B's 1 day's work =((1/4)-(1/12))=(1/6)   Hence, B alone can complete the work in 6 days.   Ans: 6 days
Answer: C
Two cars are traveling in the same direction along the same route. The red car travels at a constant speed of 30 miles per hour, and the black car is traveling at a constant speed of 50 miles per hour. If the red car is 20 miles ahead of the black car, how many hours will it take the black car to overtake the red car?
Choose the correct answer
A) 0.1  B) 0.6  C) 1  D) 1.2  E) 2

Solution: Option 1   20+30= 
20+30 = 50
50t   t=1
Answer: C
The sale price sarees listed for Rs.540 after successive discount is 5% and 2% is? Choose the correct choice from the following choices: A) 288 B) 500 C) 502 D) 540 E) 262

Solution: 540*(95/100)*(98/100)   = 502   Answer: 502
Answer: C
At what rate percent on simple interest will a sum of money double itself in 30 years?	Choose the correct choice from the following:
A) 3 1/3%
B) 3 1/8%
C) 3 7/3%
D) 3 1/7%
E) 3 1/1%

Solution: P = (P*30*R)/100   R = 3 1/3%   3 1/3%nswer: 3 1/3%
Answer: A
Three number are in the ratio of 3 : 4 : 5 and their L.C.M. is 900. What is their H.C.F.?
Choices:
A) 5
B) 15
C) 25
D) 35
E) 45

Solution: Let the numbers be 3x, 4x and 5x.   Then, their L.C.M. = 60x   60x = 900   x = 15   The numbers are (3 x 15), (4 x 15) and (5 x 15).   The H.C.F. is 15.   The answer is 15.
Answer: B
A jar of 264 marbles is divided equally among a group of marble-players. If 2 people join the group, each one would receive 1 marble less. How many people are there in the group today?	Choices
A) 20  B) 21.  C) 22  D) 23  E) 24

Solution: only 22 and 24 divide 264 perfectly,   assume initially, there are 22 people,, each will get 12 marbles   two people join, then 24 will get 11 marble each.   hence answer 24 = 24
Answer: E
If Jake loses 32 pounds, he will weigh twice as much as his sister. Together they now weigh 212 pounds. What is Jake’s present weight, in pounds?	Pick one:
A) 131
B) 135
C) 139
D) 152
E) 188

Solution: Lets say J is the weight of Jack and S is the wt of his sister.   If he loses 32 pounds, he s twice as heavy as his sister.   J-32=2*S   Also, together they weight 212 pounds   J+S=212   solvong the 2 equation ,we get J=152 pounds !   152
Answer: D
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships is:
Choose the correct choice from the following answers.
A) 173 m	B) 200 m	C) 273 m	D) 300 m	E) 373 m

Solution: Let AB be the lighthouse and C and D be the positions of the ships.   Then, AB = 100 m, ACB = 30° and ADB = 45°.   AB	= tan 30° =	1 AC = AB x 3 = 1003 m.   AC	3   AB	= tan 45° = 1 AD = AB = 100 m.   AD   CD = (AC + AD)	= (1003 + 100) m   = 100(3 + 1)   = (100 x 2.73) m   = 273 m.   Answer = 273 m
Answer: C
A candidate who gets 30% of the marks fails by 50 marks. But another candidate who gets 45% marks gets 25 marks more than necessary for passing. Find the number of marks for passing?  Choose the correct choice from the following answers: A) 100 Marks B) 200 Marks C) 280 Marks D) 371 Marks E) 827 Marks

Solution: 30% ------------ 50   45% ------------ 25   ----------------------   15% ------------- 75   30% -------------- ?     150 + 50= 
  150 + 50 = 200
200 Marks   Answer:200 Marks
Answer: B
Lake A has a duck population of 30 females and 36 males. Lake B’s duck population consists of the same ratio of females to males. If 5 new female ducks are added to Lake B and no other ducks are added or removed, the new total duck population of Lake B could be which of the following?  Choose the correct choice from the following choices:
A) 144  B) 105  C) 77  D) 51  E) 36

Solution: Lake A has a duck population of 30 females and 36 males --> the ratio is F:M = 30:36 = 5:6.   Lake B’s duck population consists of the same ratio of females to males --> F:M = 5:6.   77
Answer: C
P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?	Choose one.
A) 15 B) 24 C) 78 D) 96 E) 32

Solution: Explanation :   15mount of work P can do in 1 day = 1/20   15mount of work Q can do in 1 day = 1/30   15mount of work R can do in 1 day = 1/60   P is working alone and every third day Q and R is helping him   Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5   So work completed in 15 days = 5 × 1/5 = 1   Ie, the work will be done in 15 days   15NSWER:15
Answer: A
A store owner estimates that the average price of type A products will increase by 30% next year and that the price of type B products will increase by 20% next year. This year, the total amount paid for type A products was $3200 and the total price paid for type B products was $5800. According to the store owner's estimate, and assuming the number of products purchased next year remains the same as that of this year, how much will be spent for both products next year?
Pick.
A) $14,755	B) $15,325	C) $11,129	D) $16,225	E) $17,155

Solution: cost of type A products next year = 1.3 * 3200= 
1.3 * 3200 = 4_160
4160   cost of type B products next year= 1.2 * 5800= 
1.2 * 5800 = 6_960
6960   total 4169 + 6960= 
4169 + 6960 = 11_129
11129   ANSWER:$11,129
Answer: C
The number of boxes in a warehouse can be divided evenly into 5 equal shipments by boat or 24 equal shipments by truck. What is the smallest number of boxes that could be in the warehouse? Choose the correct choice from the following
A) 27	B) 33	C) 54	D) 81	E) 120

Solution: Answer is the LCM of 5 and 24   = 120   Answer 120
Answer: E
What will come in place of the x in the following Number series? 18, 22, 30, x ,78, 142 Select.
A) 35
B) 38
C) 46
D) 49
E) 52

Solution: (46)   The pattern is +4, +8, +16, +32, +64   So the missing term is = 30 + 16= 
30 + 16 = 46
46 .
Answer: C
A popular website requires users to create a password consisting of the digits {1,2,3,4,5}. If no digit may be repeated and each password must be at least 4 digits long, how many passwords are possible?  Choose the correct choice from the following choices:
A) 4! + 5!	B) 2 x 5!	C) 4! x 5!	D) 9!	E) 10!

Solution: If we choose the 5 different digits then they can be arranged in 5! ways.   The number of possible 4-digit passwords is 5*4*3*2 = 5!   The total number of passwords is 5! + 5! = 2*5!   The answer is 2 x 5!.
Answer: B
If x, y, and z are all factors of 15, which of the following must be true?
Choices:
A) The product xyz > 15
B) Either x = y, y = z, or x = z
C) x – y – z = even
D) The product xyz is odd
E) yz/x is an integer

Solution: All the factors of 15 are odd numbers.   The product of odd numbers is odd.   The answer is The product xyz is odd.
Answer: D
If n is an integer greater than 6, which of the following must be divisible by 10 ?
Options:
A) n(n + 1)(n – 4) B) n(n + 2)(n – 1) C) n(n + 3)(n – 5) D) n(n + 4)(n – 2) E) n(n + 5)(n – 6)

Solution: If n= 7 , then n+3 is divisible by 10 .   n(n + 3)(n – 5)
Answer: C
The workers of a factory is 10000. It decreases annually at the rate of 20% p.a. What will be its population after 4 years?	Choices
A) 8500	B) 7000	C) 5282	D) 4096	E) 5250

Solution: Formula :   ( After =100 denominator   Ago = 100 numerator)   10000 Ã— 80/100 Ã— 80/100 x 80/100 x 80/100 = 4096   4096
Answer: D
Several people are sitting around a round table playing a card game with a deck of 51 cards. Each person is dealt one card per deal, and the cards are dealt in a clockwise fashion. If Martin is dealt both the first card of the deck and the last card of the deck, which of the following could be the total number of people sitting at the table?
Choose the correct choice from the following.
A) 4 B) 5 C) 7 D) 11 E) 13

Solution: Let n be the number of people at the table.   If Martin gets the first and the last card, it means Martin got one more card than the others.   Thus 51/n has a remainder of 1 and so   51-1= 
  51-1 = 50
50 is a multiple of n.   The answer is 5.
Answer: B
If twenty four men and sixteen women work on a day, the total wages to be paid is 11,600. If twelve men and thirty seven women work on a day, the total wages to be paid remains the same. What is the wages paid to a man for a day’s work?
Answers
A) 33	B) 38	C) 37	D) 299	E) 22

Solution: Answer:38
Answer: B
Each of the 20 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 16 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
Choose the correct choice: A) 8 B) 10 C) 12 D) 14 E) 15

Solution: If the average of 10-pound and 20-pound boxes is 18, the ratio of 10-pound boxes:20-pound boxes is 1:4.   So out of 20 boxes, 4 are 10-pound boxes and 16 are 20-pound boxes.   If the average of 10 and 20-pound boxes is to be 16, the ratio of 10-pound boxes:20-pound boxes should be 2:3.   The number of 10 pound boxes remains the same so we still have 4 of them.   To get a ratio of 2:3, the number of 20-pound boxes must be 6.   We need to remove 10 of the 20-pound boxes.   The answer is 10.
Answer: B
If # is an operation which results in adding the digits of integer until a single digit is left, what is the probability J that a number picked up in first 90 positive integers will have the result of # as an odd digit ? Choose the correct choice from the following
A) (a) 4/10  B) (b) 4/9  C) (c) 1/2  D) (d) 6/10  E) (e) 5/9

Solution: Here is how I did it. Probably there may be better way to do it.   First of all let us find out what is the maximum sum we will get by adding digits of numbers from 1 to 90.   That will be 17 (8+9+17) Why did I calculate this? I will come to that in a moment.   So to get an odd digit by carrying out the operation #, the sum of the digits of the integer should be 1, 3, 5, 7, 9, 10, 12, 14, and 16 (Why not 18? Because we know the maximum sum can be 17)   Number of integers, whose digits add to 1: 1 and 10 = 2   Number of integers, whose digits add to 3: 3, 12, 21, 30 = 4   Number of integers, whose digits add to 5: 5, 14, 23, 32, 41, 50 = 6   Number of integers, whose digits add to 7: 7, 16, 25, 34, 43, 52, 61, 70 = 8   Number of integers, whose digits add to 9: 10 multiples of 9 up to 90 = 10   Number of integers, whose digits add to 10: 19, 28, 37, 46, 55, 64, 73, 82 = 8   Number of integers, whose digits add to 12: 39, 48, 57, 66, 75, 84 = 6   Number of integers, whose digits add to 14: 59, 68, 77, 86 = 4   Number of integers, whose digits add to 16: 79, 88 = 2   So in total there are  2+4+6+8+10+8+6+4+2= 
 2+4+6+8+10+8+6+4+2 = 50
50 such numbers   Probability J= 50/90 = 5/9   Correct answer (e) 5/9
Answer: E
Anne bought a computer for $2,000 and then paid a 5 percent sales tax, and Henry bought a computer for $1,800 and then paid a 12 percent sales tax. The total amount that Henry paid, including sales tax, was what percent less than the total amount that Anne paid, including sales tax?  Answers:
A) 3% B) 4% C) 7% D) 10% E) 12%

Solution: Cost of Computer = $2000   Sales tax = (5/100)*2000= 
(5/100)*2000 = 100
$100   Total Cost of Computer= 2000 + 100= 
2000 + 100 = 2_100
2100   For Henry   Cost of Computer= $1800   Sales tax = (12/100)*1800= 
(12/100)*1800 = 216
$216   Total Cost of Computer= 1800 + 216= 
1800 + 216 = 2_016
2016   % that Henry paid less than Anne= (2100 - 2016)*100/2100= 
(2100 - 2016)*100/2100 = 4
4%   Answer: Option 4%
Answer: B
(2^2+4^2+6^2+.....+18^2)=?
Pick
A) 1322  B) 2356  C) 6544  D) 1140  E) 7954

Solution: =(1x2)^2+(2x2)^2,+(2x3)^3+......(2x9)^2   =2^2 x (1^2+2^2+3^2+.......+9^2)   formula is =1/6 n(n+1)(2n+1)   =(4x1/6x9x10x19)   =(4x285)=1140   Answer is 1140
Answer: D
1=5,2=10,3=253,4=254,5=255,6=256,7=257,8=258 then 10=?  Choose the correct choice
A) 2 B) 255 C) 345 D) 445 E) 235

Solution: 1=5,2=10,3=253,4=254,5=255,6=256,7=257,8=258 then 10=?   10=2   check the first eqn.   2NSWER:2
Answer: A
We can rent a bike for x cents per minute for the first 15 minutes and then y cents for each additional minute. How much will it cost to rent a bike for z minutes, where z>15?	Choose the most appropriate option:
A) 15x+(z-15)y  B) 15x + zy  C) 15y +(z-15)x  D) x + zy  E) x + (z-15)y

Solution: The first 15 minutes cost 15x.   The next (z-15) minutes cost (z-15)y.   The total cost is 15x+(z-15)y.   The answer is 15x+(z-15)y.
Answer: A
In a kilometer race, If Abhishek gives Bharti a 40 m start, Abhishek wins by 19 sec. But if Abhishek gives Bharti a 30 sec start, Bharti wins by 40 m. Find the time taken by Bharti to run 5,000 m?  Choose the most appropriate option:  A) 150 sec  B) 750 sec  C) 450 sec  D) 825 sec  E) None of these

Solution: Explanation :   If Abhishek takes x seconds and 750 secharti takes y seconds to run 1 km, then:   =>y=150 sec and x=125 sec   =>x+19=960y/1000 and   =(960x/1000)+30=y   =>y=150 sec and x=125 sec   Answer =(150/1000)×500   = 750 sec   Answer : 750 sec
Answer: B
Find the arithmetic mean B of all roots of the following equation- see an attachment. Pick
A) 2
B) 1
C) 0.5
D) -1/3
E) 0.3

Solution: arithmetic mean B your answer C and E are same, can you correct one of them please. thanks.0.5
Answer: C
In a psychology school the grade of the students is determined by the following method: At the end of the first year the grade equals to twice the age of the student. From then on, the grade is determined by twice the age of the student plus half of his grade from the previous year. If Joey’s grade at the end of the first year is 44, what will be his grade at the end of the third year?
Choose the correct choice from the following
A) 44	B) 56	C) 82	D) 75	E) 80

Solution: Cool question!   There's a lot of information given here, so let's eat slow here.   Joey scores a 44 at the end of his first year. That means that he's currently 22 years old (since given per instruction, after the first year one's grade is determined by doubling his/her age).   Now, come next year, or his second year at this psychology school, he's technically 23 years old. To find out the second year's grade, we want to double his age PLUS half of his previous grade.   Well, his second year is then going to be 23(2) + 22 = 68.   Now let's tackle the main question: what's his grade going to be the third year?   Well, he will be at an age of 22 on his third year at this school. Again, to find out his third year's grade, you're going to double his age (24x2), plus half of his previous year's grade (as calculated for his second year, his grade is 68; therefore, 68/2)   Having said that, the final answer would be 24(2) + 68/2 = 48 + 34= 
48 + 34 = 82
82 --> (82)
Answer: C
2^(2x/3) = 2^(x/2)
What is the value of x ?  Choose the correct choice:
A) 2 B) 2/3 C) 1 D) 0 E) -2

Solution: 2x/3 = x/2   4x = 3x   4x-3x=0; x=0   Ans: 0
Answer: D
If population of certain city increases at the rate of 5%. If population in 1981 was 370440, then population in 1978 was?
Choose the correct choice from the following answers
A) 120000
B) 228788
C) 266891
D) 267689
E) 320000

Solution: X * (105/100) * (105/100) * (105/100) = 370440   X = 370440/1.157625= 
370440/1.157625 = 320_000
320000   Answer:320000
Answer: E
The product of the prime integers between 33 and 40, inclusive, is:	Select:  A) 50! – 40!  B) 99,029  C) 1,221  D) 2,021  E) 2,000

Solution: only prime number bet ween 43 and 50 inclusive are 43 and 47   thus   33*37= 
  33*37 = 1_221
1221   Ans: 1,221
Answer: C
Simplify: 896 x 896 - 204 x 204	Choose the most appropriate option:
A) 716200 B) 761200 C) 712600 D) 710612 E) 710262

Solution: = (896)^2 - (204)^2   = (896 + 204) (896 - 204)   = 1100 x 692 = 761200.   Answer is 761200
Answer: B
From a pack of cards two cards are drawn one after the other, with replacement. The probability that the first is a red card and the second is a king is -
Choose the correct choice.
A) 1/26
B) 3/52
C) 15/26
D) 11/26
E) 1/13

Solution: Explanation:   Let E1 be the event of drawing a red card.   Let E2 be the event of drawing a king .   P(E1 âˆ© E2) = P(E1) . P(E2)   (1/26s E1 and E2 are independent)   = 1/2 * 1/13 = 1/26   1/26NSWER IS 1/26
Answer: A
Of the 45 employees of a certain company, twice as many are in the sales department as are in all of the other departments combined. What is the number of employees in the sales department? Choose the correct answer
A) 15  B) 20  C) 30  D) 40  E) 45

Solution: This is ratio problem solving question.   I will prefer to use RMV box.   R M V   Sales 2 15 30   Other 1 15 15   Total 3 15 45   Answer is 30. i.e 30
Answer: C
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey?  Pick:
A) 5	B) 4	C) 6	D) 7	E) 8

Solution: M = 45   S = 1.5   DS = 6   US = 3   AS = (2 * 6 * 3) /9= 
(2 * 6 * 3) /9 = 4
4   Answer:4
Answer: B
A laborer is engaged for 30 days on the condition that he receives Rs.25 for each day he works and is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was he absent? Select the correct option
A) 7	B) 8	C) 9	D) 10	E) 11

Solution: 30 * 25= 
30 * 25 = 750
750   425   -----------   325   25 + 7.50= 
25 + 7.50 = 32.5
32.5   325/32.5= 
325/32.5 = 10
10   ANSWER:10
Answer: D
1024 people in village 720 speak tamil,562 speak english while 346 speak both. person who don not speack english or tamil speak hindi. what is probibility that person speak hindi  Choose the correct choice from the following choices
A) 13/128
B) 12/128
C) 11/126
D) 11/127
E) 11/128

Solution: n(t)=720   n(e)=562   n(t^e)=346   n(tUe)=720+562-346= 
720+562-346 = 936
936   Now, n(h)=1024-936= 
1024-936 = 88
88   p(h)=88/1024=11/128=0.085   ANSW11/128R:11/128
Answer: E
If a2+b2=177and ab=54 then find the value of a+b/a-b?
Pick one:	A) 5	B) 4	C) 2	D) 1	E) 3

Solution: (a+b)2=a2+b2+2ab=117+2*24=225   a+b=15   (a-b)2=a2+b2-2ab=117-2*54   a-b=3   a+b/a-b=15/3= 
15/3 = 5
5   5nswer is 5.
Answer: A
The area of rhombus is 150 cm square. The length of one of the its diagonals is 10 cm. The length of the other diagonal is:	Choose the correct option:
A) 15 cm
B) 20 cm
C) 25 cm
D) 30 cm
E) None of these

Solution: Explanation:   We know the product of diagonals is 1/2*(product of diagonals)   Let one diagonal be d1 and d2   So as per question   1/2∗d1∗d2=150   1/2∗10∗d2=150   d2=150/5= 
150/5 = 30
30   Option 30 cm
Answer: D
A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 180 kilometers? Pick
A) 4.5 gallons
B) 8 gallons
C) 9.5 gallons
D) 10 gallons
E) 11 gallons

Solution: Each 40 kilometers, 1 gallon is needed. We need to know how many 40 kilometers are there in 180 kilometers?   180 / 40= 
180 / 40 = 9/2 = around 4.5
4.5 *1 gallon correct answer 4.5 gallons
Answer: A
The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 8 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A? Pick.
A) 45	B) 65	C) 75	D) 89	E) 80

Solution: A + B + C = 3 *84= 
3 *84 = 252
252   A + B + C + D= 4 * 80= 
4 * 80 = 320
320 ---- (i)   So, D= 68& E = 68 + 8= 
68 + 8 = 76
76   B + C + D +E= 79 * 4= 
79 * 4 = 316
316 --- (ii)   From Eq. (i) & (ii)   A-80= 320 – 316 = 4   A = 80 +4 = 76 + 4= 
76 + 4 = 80
80   80
Answer: E
A man can row upstream at 7 kmph and downstream at 33 kmph, and then find the speed of the man in still water? Select the correct option.
A) 11
B) 77
C) 30
D) 20
E) 34

Solution: US = 7   20S = 33   M = (33 + 7)/2= 
(33 + 7)/2 = 20
20   Answer:20
Answer: D
(1+0.0001)/(0.04+100)
The value of the expression above is closet to which of the following?	Pick one:
A) 0.0001
B) 0.01
C) 0.1
D) 1
E) 10

Solution: Notice that we need approximate value of the fraction.   Now, the nominator is very close to 1 and the denominator is very close to 10, hence the value of the fraction is very close to 1/100=0.01.   Answer: 0.01.
Answer: B
The price of a certain painting increased by 20% during the first year and decreased by 25% during the second year. The price of the painting at the end of the 2-year period was what percent of the original price?	Choose one.
A) 102%  B) 90%  C) 120%  D) 85%  E) 95%

Solution: Easiest thing to do: Assume that price is 100   Price at the end of yr 1: 100+ 20 = 120   Price at the end of year 2 = 120 - 120*0.25 = 120*0.75= 
120*0.75 = 90
90   Hence required answer= (90/100)*100= 
(90/100)*100 = 90
90%   Answer is 90%.
Answer: B