MU-NLPC/Calc-aqua_rat huggingface dataset:
R and S start walking each other at 10 AM at the speeds of 3 km/h and 4 km/h respectively. They were initially 17.5 km apart. At what time do they meet?	Choose the correct choice
A) 2 : 30 PM B) 11 : 30 AM C) 1 : 30 PM D) 12 : 30 PM E) None of these

Solution: Let after t hours they meet then,   3t + 4t = 17.5 ⇒ t = 25   ∴ Time = 10 am + 2.5 h = 12 : 30 am   Answer 12 : 30 PM
Answer: D
3 buffaloes eat as much as 4 cows or 2 oxen. At a farm, there are 15 buffaloes, 8 oxen, and 24 cows. The fodder for these cattle is available for 24 days. If 60 more cows and 30 more buffaloes are brought in, how many days will the fodder last?
Select the correct option:  A) 6  B) 9  C) 12  D) 15  E) 18

Solution: 2 oxen = 3 buffaloes = 4 cows   Also: 15 buffaloes + 8 oxen + 24 cows   = 10 oxen + 8 oxen + 12 oxen = 30 oxen   There is enough fodder for 1 oxen for 30*24 days.   60 cows + 30= 
+ 30 = 30
30 oxen + 20 oxen= 50 oxen   The new total is equal to 80 oxen instead of 30 oxen.   30*24 / 80= 
30*24 / 80 = 9
9 days   The answer is 9.
Answer: B
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 3 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 8 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?	Choose the most appropriate option.
A) 60
B) 72
C) 84
D) 96
E) 108

Solution: D is the answer....   96 = TS where 96=distance, T=Time and S=Speed   To travel half distance, (2+3T) = 8T ==> T = 2/5 ==> 24 minutes   To travel double distance, 2(2+3T) = 8T ==> 2 ==> 120 minutes   96ifference, 96 minutes   96
Answer: D
The area of a sector of a circle of radius 5 cm formed by an arc of length 4 cm is? Options
A) 8.78  B) 8.67  C) 8.75  D) 10  E) 8.28

Solution: (5 * 4)/2= 
(5 * 4)/2 = 10
10   Answer:10
Answer: D
A merchant gets a 5% discount on each meter of fabric he buys after the first 2,000 meters and a 7% discount on every meter after the next 1,500 meters. The price, before discount, of one meter of fabric is $2, what is the total amount of money the merchant spends on 5,500 meters of fabric?  Choices.
A) $7,360
B) $8,540
C) $9,720
D) $10,570
E) $11,680

Solution: For first 2000 meters he does not get any discount.   The price is  2*2000= 
 2*2000 = 4_000
$4000   For next 1500 meters, he gets a 5% discount.   The price is  1.9*1500= 
 1.9*1500 = 2_850
$2850   For the next 1500 meters, he gets a 7% discount.   The price is  1.86*2000= 
 1.86*2000 = 3_720
$3720   The total price is $4000 + $2850 + $3720= $10,570   The answer is $10,570.
Answer: D
Find (7x + 2y ) / (x-2y) if x/2y = 3/2 ?
Pick
A) 23
B) 25
C) 26
D) 27
E) 29

Solution: x/2y=3/2   =>x=6y/2=3y   6 /2= 
6 /2 = 3
3y=>(7x+2y)/(x-2y)=((7*(3y))+2y)/(3y-2y)   =>23y/y((7*(3 ))+2 )/(3 -2 )= 
((7*(3 ))+2 )/(3 -2 ) = 23
>23y/y=23   23NSWER:23
Answer: A
If A can finish a work in 12 days and B can finish same work in 15 days.then they together can finish that work in how many days?	Choose the correct choice from the following answers: A) 15 B) 12 C) 20/3 D) 8 E) 10/3

Solution: A work in 1 hour=1/12,B work in 1 hour=1/15   [A+B] work in 1 hour=[1/12+1/15] = 3/20   Time take by both to finish the work=20/3hour   Answer 20/3
Answer: C
Convert the following units:
(a) 60 cm² in mm²	Choose the most appropriate option
A) 600 mm²	B) 1600 mm²	C) 6000 mm²	D) 600 mm²	E) 6600 mm²

Solution: 60 cm² in mm²   1 cm = 10 mm   1 cm² = 100 mm²   Therefore, 60 cm² = 60 × 100 mm²   = 6000 mm²   ANSWER : OPTION 6000 mm²
Answer: C
The ratio between the perimeter and the width of a rectangle is 5 : 1. If the area of the rectangle is 294 sq. cm, what is the length of the rectangle? Choose the correct answer:
A) 15 cm B) 18 cm C) 21 cm D) 24 cm E) 27 cm

Solution: 2L+2W = 5W   L = 3W/2   W*L = 294   3W^2/2 = 294   W^2 = 196   W = 14   L = 3(14)/2 = 21   The answer is 21 cm.
Answer: C
A and B ran, at their respective constant rates, a race of 480 m. In the first heat, A gives B a head start of 48 m and beats him by 1/10th of a minute. In the second heat, A gives B a head start of 144 m and is beaten by 1/30th of a minute. What is B’s speed in m/s?
Choose the correct choice from the following choices:
A) 12
B) 14
C) 16
D) 18
E) 20

Solution: Let x be the speed of B.   Write the equation:   (480-48)/x (time of B for first heat) - 6 (seconds, time B lost to 12 first heat) = TIME OF 12 (in both heats 12 runs with constant rate, so the time for first and second heats are the same)=(480-144)/x (time of B for second heat) + 2 (seconds, time B won to 12 second heat)   (480-48)/x-6=(480-144)/x+2   x=12   12nswer: 12.
Answer: A
a factory produce certain no of car a day finds that increase in production efficiency by 12 1/2% then they produce 20 cars per day.how many cars produced in a day when their efficiency is 20% less  Select the correct option:	A) 12	B) 13	C) 14	D) 15	E) 16

Solution: et effi. is x   x+(25x/1000=20   or, x=18(apprx)   now, x-(20% of x)= 18-(20% of 18)=14   ANSWER:14
Answer: C
The equation relates the values (R - 3)/28 = (S + 8)/35 of two linked currencies, where R is the value in dollars of one currency and S is the value in dollars of the other currency. Which of the following equations can be used to convert dollar values from the R currency to the S currency?
Pick one.
A) S = (5R - 47)/4
B) S = (4R + 47)/5
C) S = (5R + 17)/4
D) S = (4R - 17)/5
E) S = 5R/4 - 12

Solution: R - 3)/28 = (S + 8)/35   (R - 3)/4 = (S + 8)/5   5(R - 3)/4 = s+8.   5R-47/4 = S   Option S = (5R - 47)/4.
Answer: A
Simple interest on a certain sum at a certain annual rate of interest is 1/3 of the sum. If the numbers representing Time is three times the Rate percent , then the Rate is:	Choices:  A) 1 1/3 %.  B) 2 1/3 %.  C) 3 1/3 %.  D) 4 1/3 %.  E) 5 1/3 %.

Solution: Explanation :   Let sum = x. Then, S.I. = x/3   Let N =3R   [x * 3R * R / 100] = x/3? R^2 = 100/9   R = 10/3 = 3 1/3%.   Hence, Rate = 3 1/3 %.   Answer : 3 1/3 %.
Answer: C
The third smallest prime number is?	Answers:  A) 67  B) 71  C) 79  D) 83  E) 89

Solution: The third smallest prime number is 79.   79)
Answer: C
One out of every 2000 computer chips is defective. If 2 out of every 30 defective chips have defective processors and there are 30 defective processors in the first batch, how many computer chips are there in the first batch?
Choose the correct option:
A) 450	B) 900	C) 90,000	D) 450,000	E) 900,000

Solution: (D) Read the whole question to get the feel of what they are asking you to find. Then start with the smallest amount and work your way outwards. We are told that two out of every 30 defective chips have a defective processor. Let x be the total number of defective processors in the batch. Because we know 2 out of every 30 defective chips will have defective processors, and the total number of defective processors in the batch is 30, we can write out an equation: (2/30)x = 30. This can be simplified to (1/15)x = 30. Multiplying each side by 15, we arrive at x = 450. This tells us that there are 450 defective chips in the whole batch. Because we know that 1 out of every 1000 chips is defective, we can set up a proportion. If 1 out of every 2000 chips is defective, then 450 out of y chips would be defective, where y is the total number of chips in the batch. This can be set up as an equation as follows: 1/2000 = 450/y. Solve for y and you will get the total number of chips in the batch: 900,000.   The answer is (900,000).
Answer: E
In what ratio should two varieties of sugar of Rs.18 per kg and Rs.24 kg be mixed together to get a mixture whose cost is Rs.20 per kg?  Choose the correct choice from the following answers:
A) 1:3  B) 3:1  C) 1:2  D) 2:1  E) 3:4

Solution: Explanation:   =4:2=2:1   ANSWER IS 2:1
Answer: D
Mary has a monthly salary of $1200. She spends $280 per month on food. What percent of her monthly salary does she spend on food?  Select:	A) 22%	B) 23%	C) 24%	D) 25%	E) 26%

Solution: Solution to Problem 2:   The part of her salary that is spent on food is $280 out of her monthly salary of $1200   percent = part / whole = 280 / 1200 = 0.23 (rounded to 2 decimal places)   Multiply and divide 0.23 by 100 to convert in percent   percent = 0.23 * 100 / 100 = 23 / 100 = 23%   Answer 23%
Answer: B
If X = the product of four distinct prime numbers, how many factors does X have besides 1 and itself? Choose the correct choice from the following answers.
A) 10	B) 11	C) 12	D) 13	E) 14

Solution: Let's take the four primes: 2, 3, 5 and 7 --> each of the 4 primes will be a factor of the product   All the possible combinations of the four primes will be factors (10 possible combinations):   2x3   2x5   2x7   3x5   3x7   5x7   2x3x5   2x3x7   2x5x7   3x5x7   Thus, in total there are   10 + 4= 
  10 + 4 = 14
14 factors.   ANSW14R:14
Answer: E
What should come in place of the question mark (?) in the following equation?
12400 + 6899 = 610+ ?	Select:
A) 12345
B) 56894
C) 18689
D) 23478
E) 94561

Solution: 12400 + 6899 = 610+ ?   12400 + 6899 – 610 = 18689   Answer 18689
Answer: C
A person can row at 9 kmph and still water. He takes 8 1/2 hours to row from A to B and back. What is the distance between A and B if the speed of the stream is 1 kmph?	Options
A) 60 km  B) 87 km  C) 38 km  D) 67 km  E) 20 km

Solution: Let the distance between A and B be x km.   Total time = x/(9 + 1) + x/(9 - 1) = 8.5   => x/10 + x/8 = 17/2 => (4x + 5x)/40 = 17/2 => x   = 38 km.   Answer:38 km
Answer: C
The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period? Select
A) Rs.10176	B) Rs.10287	C) Rs.10560	D) Rs.10227	E) Rs.11827

Solution: Explanation:   Let the rate of interest be R% p.a.   4400{[1 + R/100]2 - 1} = 11193.60   [1 + R/100]2 = (44000 + 11193.60)/44000   [1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625   [1 + R/100]2 = 784/625 = (28/25)2   1 + R/100 = 28/25   R/100 = 3/25   Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100   =Rs.10560   Answer: Rs.10560
Answer: C
A test has 120 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers?	Pick
A) 11	B) 13	C) 15	D) 17	E) 19

Solution: A correct answers get you 1 point, an incorrect answer gets you MINUS 1/4 point and a skipped question gets you 0 points. Since there are 200 total questions, there are a variety of ways to get a total of 40 points.   Let C be the number of correct answers and let I be the number of incorrect answers.   To get 40 points, a test taker must have at least 40 correct answers. Then C=> 40.   For every correct question above 40, the test taker has 4 incorrect answers.   Then, the I = 4*(C - 40).   Also, I + C <= 120. Thus 5C <= 280 and so C <= 56.   Then 40 <= C <= 56 and C can have 17 possible values.   The answer is 17.
Answer: D
A man can reach certain place in 50hours. If he reduces his speed by 1/10th, he goes 400km less in time. Find his speed?	Choose the correct answer:
A) 20km/hr  B) 30km/hr  C) 40km/hr  D) 80km/hr  E) 60km/hr

Solution: Let the speed be x km/hr   50x-50* 9/10 *x = 400   50x - 45x = 400   5x = 400   x = 80km/hr   Answer is 80km/hr
Answer: D
A shopkeeper loses 15%,if an article is sold for Rs. 102. What should be the selling price of the article to gain 20%? Choose the correct choice.
A) Rs.147
B) Rs.148
C) Rs.144
D) Rs.129
E) Rs.112

Solution: Given that SP = Rs. 102 and loss = 15%   CP = [100(SP)]/(100 - l%) = (100 * 102)/85 = 20 * 6   = Rs. 120.   To get 20% profit, New SP = [(100 + p%)Rs.144P]/100   = (120 * 120)/100   = Rs.144   Answer:Rs.144
Answer: C
The sum of the ages of 5 children born at the intervals of 3 year each is 60 year. what is the age of the eldest child ? Choose the correct option:
A) 4 year B) 18 year C) 10 year D) None of these E) 9 year

Solution: Solution   let the ages of the children be x,(x + 3),(x + 6),(x + 9) and (x + 12) year.   then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 60 â‡” 5 x = 30 â‡” x= 6.   âˆ´ Age of the eldest child = x +12= 6 +12= 
6 +12 = 18
18 years. Answer 18 year
Answer: B
There are 35 students in a hostel. If the no. of students increases by 7, the expenses of the mess increase by Rs.42/day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess?
Choices.
A) Rs. 34	B) Rs. 39	C) Rs. 42	D) Rs. 48	E) Rs. 49

Solution: Suppose the average join the mess , total expenditure = 35x + 42   Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1   or, 35x + 42 = 42x – 42   or, x = 12   Thus the original expenditure of the mess = 35 x 12 = Rs. 42   Rs. 42
Answer: C
Total number of people attending a party is 600. 70% of the men are wearing black shirt and rest are wearing red. If 60% of the total people are women then how many men are wearing red shirts?	Choose the correct choice from the following choices.
A) 168
B) 72
C) 56
D) 170
E) 60

Solution: Number of woman in the party = 0.60*600= 
0.60*600 = 360
360   number of men in the party= 600-360= 
600-360 = 240
240   % of men wearing red shirts= 100-70= 
100-70 = 30
30%   number of men wearing red shirt= 0.30*240= 
0.30*240 = 72
72. 72 is the correct answer
Answer: B
Find the odd man out
253, 136, 352, 327, 631, 244
Answers
A) 327  B) 136  C) 352  D) 631  E) 531

Solution: The sum all three digits comes to 10 except 327   327NSWER:327
Answer: A
The speeds of 3 trains in the ratio 3:9:12. The ratio between time taken by them to travel the same distance is?
Options:
A) 12:4:3
B) 1:2:3
C) 4:8:9
D) 6:5:2
E) 4:8:7

Solution: Ratio of time taken is = 1/3 : 1/9 : 1/12 = 12:4:3   12:4:3nswer is 12:4:3
Answer: A
Ram has passed his exam of 5 subject in 85% of marks. He has gotten 90, 75, 98 and 72 marks in four subjects. Therefore what is his marks in the fifth subject? Pick one:
A) 75
B) 85
C) 95
D) 90
E) 84

Solution: EXPLANATION   Total marks of 4 subjects = (90 + 75 + 98 + 72 )= 
(90 + 75 + 98 + 72 ) = 335
335   Marks of 5th subject= [ (85 x 5) – 335 ]   = (425 – 335)   = 90.   Answer 90
Answer: D
A grocer has a sale of Rs. 2500, Rs. 6500, Rs. 9855, Rs. 7230 and Rs. 7000 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7500?  Choose the correct choice from the following answers.
A) s. 49180  B) s. 49910  C) s. 11915  D) s 6997  E) s. 5000

Solution: Total sale for 5 months = Rs. (2500 + 6500 + 9855 + 7230 + 7000 ) = Rs. 33085.   Required sale = Rs. [ (7500 x 6) -33085]   = Rs. (45000 - 33085)   = Rs. 11915.   s. 11915
Answer: C
The cost price of 16 articles is equal to the selling price of 11 articles. Find the profit percent? Choose the correct choice:	A) 48 2/91%	B) 45 5/11%	C) 48 9/11%	D) 48 2/91%	E) 42 2/11%

Solution: 16 CP = 11 SP   11 --- 2 CP   100 --- ? =>45 5/11%   Answer:45 5/11%
Answer: B
Pat, Kate, and Mark charged a total of 144 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate? Choices:  A) 18  B) 80  C) 72  D) 90  E) 108

Solution: 80   all u do is do   2:1:6=>2x+x+6x=144=>x= 16   32:16:96   96-16= 
96-16 = 80
80   Answer 80
Answer: B
How many number of weights do u need to weigh 31 kg of rice if u have only one 1kg weights stone ?	Choose the correct option
A) 30	B) 31	C) 5	D) 4	E) 3

Solution: first measure 1kg rice by 1 kg weight   then use this 2kg (1kg rice+ 1 kg weight) to measure 2kg rice   now combine this to get 3kg rice + 1 kg weight to measure 4 kg rice   add this newly measure 4kg + 3kg + 1kg weight to measure 8 kg   add this 8kg+ 4kg + 3kg + 1kg weight to measure 16 kg rice   now combining all u get 31 kg rice + 1 kg weight   so the answer is 5   ANSWER:5
Answer: C
If tuesday falls on 4th of month, then which day will fall three days after the 24th ?	Choices:
A) SUNDAY
B) tuesday
C) monday
D) thursday
E) friday

Solution: Explanation:   The 4th day is tuesday, then 11, 18, 25th also tuesdays   Then 3 days after 24th is 27th, which is thursday   Answer: thursday) thursday
Answer: D
If the sum of two numbers is 42 and their product is 437, then find the
absolute difference between the numbers.
Choose the correct choice from the following answers:
A) 2 B) 4 C) 3 D) 1 E) 0

Solution: Let the numbers be x and y. Then, x + y = 42 and xy = 437   x - y = sqrt[(x + y)2 - 4xy] = sqrt[(42)2 - 4 x 437 ] = sqrt[1764 – 1748] = sqrt[16] = 4.   Required difference = 4.   Answer is 4.
Answer: B
A student got 74% in math and 84% in history. To get an overall average of 75%, how much should the student get in the third subject?
Choose the correct choice from the following.
A) 61%  B) 63%  C) 65%  D) 67%  E) 69%

Solution: 74 + 84 + x = 3*75   x = 67   The answer is 67%.
Answer: D
In one hour, a boat goes 11 km along the stream and 7 km against the stream. the sped of the boat in still water (in km/hr) is :  Choose one
A) 3
B) 5
C) 8
D) 9
E) 10

Solution: Solution   Speed in still water= 1/2(11+7) km/hr= 9kmph. Answer 9
Answer: D
The current birth rate per ten thousand is 620, whereas corresponding death rate is 110 per ten thousand. The net growth rate in terms of population increase in percent is given by
Answers:
A) 6.5 B) 4.5 C) 5.5 D) 5.2 E) 5.1

Solution: Sol.   Net growth on 1000 = (620 - 110)= 
(620 - 110) = 510
510.   Net growth on 100= (510/10000 Ã— 100)% = 5.1%.   Answer: 5.1
Answer: E
The cash difference between the selling prices of an article at a profit of 4% and 6% is Rs. 3. The ratio of the two selling prices is:	Options.
A) 51:52
B) 52:53
C) 51:53
D) 52:55
E) 53:54

Solution: Explanation:   Let C.P. of the article be Rs. x.   Then, required ratio = 104% of x / 106% of x   = 104/106 = 52/53 = 52:53   ANSWER IS 52:53
Answer: B
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was: Select the correct option
A) 14 years B) 19 years C) 33years D) 38 years E) 3 years

Solution: Let the son's present age be x years. Then, (38 - x) = x   2x = 38.   x = 19.   Son's age 5 years back (19 - 5)= 
(19 - 5) = 14
14 years.   14 yearsNSWER:14 years
Answer: A
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
Choices
A) 209 B) 145 C) 321 D) 521 E) 130

Solution: We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys).   Required number   of ways	= (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4)   = (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2)   = (24 + 90 + 80 + 15)= 
(24 + 90 + 80 + 15) = 209
209.   209ns: 209
Answer: A
What is the remainder when 6^381 is divided by 5 ?	Choose one.
A) 0  B) 1  C) 2  D) 3  E) 4

Solution: I also agree that the remainder is '1' (using the last digit of the powers of 7). Could we have the official answer please?1
Answer: B
Which of the following is(are) true for a@b=b@a?
I. a@b=ab+ba
II. a@b=(a+b+1)(a-b)
III. a@b=(a/b)+(b/a) Choose the correct option:
A) only Ⅰ B) only Ⅱ C) only Ⅲ D) only ⅠⅢ E) only ⅡⅢ

Solution: -> If I. a@b=ab+ba, a@b=ab+ba=ba+ab=b@a (O).   If II. a@b=(a+b+1)(a-b), a@b=(a+b)(a-b)≠(b+a)/(b-a)=b@a (X).   If III.a@b=(a/b)+(b/a), a@b=(a/b)+(b/a)=(b/a)+(a/b)=b@a (O).   Thus, ⅠⅢ are the answers. Therefore, only ⅠⅢ is the answer.
Answer: D
How many integers from 1 to 100 exist such that each is divisible by 5 and also has 5 as a digit ?	Choose the correct choice from the following:
A) 10
B) 12
C) 11
D) 20
E) 25

Solution: 5,15,25,35,40,50,55,65,75,85,95   So there are total 11 such type of numbers.   ANSWER :11
Answer: C
The difference between a two-digit number obtained by interchanging the positions of its digits is 36. What is the difference between the two digits of that number?  Choose the correct choice from the following:	A) 4	B) 9	C) 3	D) Cannot be determined	E) None of theses

Solution: Let the two-digit number be 10x + y.   Then, (10x + y) – (10y + x) = 36   or x – y = 4   4nswer 4
Answer: A
train having a length of 240 metre passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 metre?	Pick one:  A) 89 sec  B) 100 sec  C) 90 sec  D) 85 sec  E) 99 sec

Solution: speed = 240/24= 
240/24 = 10
10 m/s   req time= 240+650/10 = 89 sec   89 secNSWER 89 sec
Answer: A
A 2-year certificate of deposit is purchased for R dollars. If the certificate earns interest at a n annual rate of 6 percent compound quarterly, which of the following represents the value, in dollars, of the certificate at the end of 2 years? Pick
A) k(1.06)^2  B) k(1.06)^8  C) k(1.015)^2  D) R(1.015)^8  E) k(1.03)^4

Solution: Annual Rate of interest= 6%   Quaterly rate of interest= 6/4= 
6/4 = 3/2 = around 1.5
1.5%   Now, periods of compounding in 2 years= 8 (8 quarters)   Thus R(1.015)^8   Answer: R(1.015)^8
Answer: D
The price of a vehicle, passing through three hands, rises on the whole by 65%. If the first and the second sellers earned 20% and 25% profit respectively. Find the percentage profit earned by the third seller. Select the correct option.
A) 20%
B) 5%
C) 15%
D) 10%
E) None of these

Solution: Explanation :   Solution: Let the original price of the vehicle be Rs. X and let the profit earned by the third seller be Y%.   Then, (100+Y)% of 125% of 120% of X = 165% of X.   [(100+Y)/100 * 125/100 * 120/100 * X] =165/100 * X.   100+Y = 165*100*100/(125*120)= 
165*100*100/(125*120) = 110
110=> Y= 10%   Answer : 10%
Answer: D
At 6'o clock clock ticks 6 times. The time between first and
last ticks was 30sec. How much time it takes at 12'o clock.  Choose the correct option:
A) 60sec B) 62sec C) 66sec D) 64sec E) 76sec

Solution: At 6'0 clock, clock ticks 6 times.   So, there must be 5 intervals between clock ticks.   Time Between first and last ticks = 30sec   So, 1 interval = 30/5= 
30/5 = 6
6sec   So 6'o clock 5 *6= 
5 *6 = 30
30sec   7'o clock 6 *6= 
6 *6 = 36
36sec   .   .   .   10'o clock 9 *6= 
9 *6 = 54
54sec   11'o clock 10*6= 
10*6 = 60
60sec   12'o clock 11*6= 
11*6 = 66
66sec   So, 66sec at 12'o clock.   ANSWER:66sec
Answer: C
If A and B are two events such that P (A) = 3/4, P (B) = 1/2 and P (A n B) = 3/4,
find P (not A and not B).
Pick.
A) A)1	B) B)1/2	C) C)1/3	D) D)1/4	E) E)1/5

Solution: P(not A and not B) = 1 - (P(A) + P(B) - P(AB))   which you might find somewhere in your text.   Substituting in our probabilities we get:   P(not A and not B) = 1 - (3/4 + 1/2 - 3/4)   P(not A and not B) = 1 - (1/2)   P(not A and not B) = 1/2.   1/2
Answer: B
What sum of money will produce Rs.70 as simple interest in 4 years at 3 1/2 percent? Choose the correct choice:
A) 263	B) 500	C) 367	D) 368	E) 339

Solution: 70 = (P*4*7/2)/100   P = 500   Answer: 500
Answer: B
The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 8 years hence? Choose the correct choice from the following options
A) 22	B) 76	C) 70	D) 98	E) 71

Solution: A + B = 60, A = 2B   2B + B = 60 => B = 20 then A = 40.   8 years, their ages will be 48 and 28.   Sum of their ages = 48 + 28= 
48 + 28 = 76
76.   Answer: 76
Answer: B
Find HCF of 4/5, 8/35, 2/15, 6/25 ? Pick one: A) 2/125 B) 6/360 C) 2/525 D) 2/720 E) 3/680

Solution: We know that the H2/525F for fraction can be calculated as:   H2/525F = (H2/525F of numerators) / (L2/525M of denominators)   = (H2/525F of 4, 8, 2, 6) / (L2/525M of 5, 35, 15, 25)   = 2 / (5 x 7 x 3 x 5)   = 2 /525   Ans - 2/525
Answer: C