MU-NLPC/Calc-aqua_rat huggingface dataset:
City I City II	City III	City IV	City V	City VI
City I
City II
City III
City IV
City V
City VI
In the table above, what is the least number of table entries that are needed to show the mileage between each city and each of the other five cities?  Choose the correct choice from the following answers:
A) 14
B) 15
C) 13
D) 12
E) 11

Solution: Easy way to go about this problem is we have 6*6= 
6*6 = 36
36 enteries in table the least number of enteries would be (36 - 6) /2 since 6 enteries represent the distances between same points .   Alternatively this can be solved as combination problem.   Correct Answer 15
Answer: B
|-4| (|-25|-|15|)= ??
Source: Preparation Material MBA Center	Choose the most appropriate option
A) 40 B) –60 C) 60 D) 75 E) 100

Solution: Absolute value will turn negatives into their positive 'equivalents', and will leave positives unchanged, so |-4| = 4, |-25| = 25, and |15| = 15. Getting rid of our absolute values we have:   |-4| (|-25|-|15|) = (4) (25 - 15) = 4*10= 
4*10 = 40
40
Answer: A
What distance (in meters) will be covered by a bus moving at 54 km/hr in 20 seconds? Choose the correct choice from the following answers:	A) 200	B) 250	C) 300	D) 350	E) 400

Solution: 54 km/hr = 54 * 5/18= 
54 * 5/18 = 15
15 m/s   distance= 15 * 20= 
15 * 20 = 300
300 meters   The answer is 300.
Answer: C
A watch was sold at a loss of 10%. If it was sold for Rs.140 more, there would have been a gain of 4%. What is the cost price?	Pick:  A) Rs.1000  B) Rs.1028  C) Rs.1029  D) Rs.1030  E) Rs.1028

Solution: 90%   104%   --------   14% ---- 140   100% ---- ? => Rs.1000   Rs.1000nswer: Rs.1000
Answer: A
A bicycle wheel has a diameter of 0.75m. How many complete revolutions does it make in 1km?
Options
A) 424 B) 448 C) 1408 D) 710 E) 223

Solution: 1 revolution = 3.14 * diameter.   Number of revolutions in 1km = 1000m / ( 3.14 * 0.75m ) = 424.6. Hence 424 complete revolutions.   424nswer 424
Answer: A
If 2x +3y = 30 and (x+y)/y = 11/8, then find the value of 5y + 6x Select the correct option
A) 72	B) 58	C) 64	D) 29	E) 34

Solution: Explanation:   The given equations are :   2x + 3y = 30 --------- (i)   and, (x+y)/y = 11/8   8x + 8y = 11y   8x – 3y =0 ----(ii)   Adding (i) & (ii), we get : 10 x = 30 or x = 3.   Put x = 3 in (i), we get : y = 8   Therefore, 5y + 6x = (5 * 8 + 6 * 3) = 40 + 18= 
40 + 18 = 58
58.   ANSWER: 58
Answer: B
A cycle is bought for Rs.1500 and sold for Rs.1620, find the gain percent?	Select
A) 11  B) 8  C) 10  D) 20  E) 12

Solution: 1500 ---- 120   100 ---- ? =>8%   Answer: 8
Answer: B
One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 250 of the attendees are neither female nor students, what is the total number of attendees at the convention?  Choose the correct choice from the following answers:
A) 600  B) 300  C) 1200  D) 1500  E) 1600

Solution: Let no. of Attendee are A.   Now As per the condition of the problem stated above .   We have following population in the convention as Attendee.   Total no. of females = [2/3]*A   Total no. of females as student : [1/6]*A   Total no. of students = [1/3]*A   Total no. of male as student = [1/6]*A   Total no. of males = A - [2/3]*A = [1/3]A   No. of males which are not student = [1/3]A - [1/6]*A = 250   Hence A = 1500   Total no of males who are not student will be the answer as it states it should be neither female nor student   So Answer is 1500
Answer: D
A basketball is dropped from a height of 20 feet. If it bounces back up to a height that is exactly half of its previous height, and it stops bouncing after hitting the ground for the fourth time, then how many total feet will the ball have traveled after 2 full bounces. Choose the correct choice from the following choices:
A) 50  B) 55  C) 60  D) 75  E) 80

Solution: Initial distance = 20 feet   first bounce = 10 feet up + 10 feet down = 20 feet   second bouche = 5 feet up + 5 feet down = 10 feet   total distance covered = 20+20+10+ = 50   50NSWER IS 50
Answer: A
A man completes of a job in 10 days. At this rate, how many more days will it takes him to finish the job?
Choose the correct choice from the following:
A) 6
B) 12
C) 7
D) 15
E) 5

Solution: Work done =5/8   Balance work =	(1 -5/8)=3/8   Let the required number of days be x.   Then,	(5/8):(3/8)= :: 10 : x   (5/8)* x =	(3/8)* 10   x =(3/8) * 10 *(8/5)= 
(3/8) * 10 *(8/5) = 6
6.   6nswer is 6.
Answer: A
How many three digit numbers R are divisible by 78 or 91? Choose the correct choice from the following
A) 17
B) 19
C) 20
D) 21
E) 22

Solution: The answer will be 19.   Explanation:   78= 2*3*13 now multiples of 78, 156 ....780, now   1000-780= 
  1000-780 = 220
220 only two more muktiples of 78 can exists. So total number of 3 digit Multiples of 78 are   9+2= 
  9+2 = 11
11   91= 13*7--Total number of three digit multiples --9   No remember we have a common multiples as well-- 13*7*6=91*6= 
91*6 = 546
546   So total number of multiples R--11+9 -1= 
--11+9 -1 = 19
19.   Hence Answer is 19.19
Answer: B
The HCF of two numbers is 42 and the other two factors of their LCM are 10 and 20. What is the largest number.  Choose the correct choice from the following choices: A) 462 B) 450 C) 840 D) 504 E) 555

Solution: Explanation:   H840F of the two numbers = 42   H840F will be always a factor of L840M   42 is factor of L840M   other two factors are 10 & 20   Then the numbers are (42 *10) and (42 x 20)   = 420 and 840   Answer: Option 840
Answer: C
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is?  Choose one: A) 1 : 3 B) 3 : 2 C) 3 : 4 D) 4 : 3 E) 3 : 5

Solution: Explanation:   Let the speeds of the two trains be x m/sec and y m/sec respectively.   Then, length of the first train = 27x metres,   and length of the second train = 17y metres.   ( 27x + 17y ) / (x+ y )= 23   => 27x + 17y = 23x + 23y   => 4x = 6y   => ( x/y ) = ( 3/2 )   Answer: Option 3 : 2
Answer: B
Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 14 percent alcohol by volume?
Choose the most appropriate option: A) 50 B) 100 C) 150 D) 200 E) 250

Solution: 14% is 4%-points higher than 10% but 16%-points lower than 30%.   Thus there should be 4 parts of solution X for 1 part of solution Y.   We should add 50 ml of solution Y.   The answer is 50.
Answer: A
NHAI employs 100 men to build a highway of 2km in 50 days working 8 hours a day. If in 25 days, they completed 1/3 part of work. than how many more employees should NHAI hire to finish it in time working 10 hours a day?
Choose the correct choice from the following answers:
A) 55
B) 60
C) 70
D) 50
E) 65

Solution: Explanation:   The given problem can be written in a tabular form like below: -   Men	Days	Hour	Work   Planned	100	50	8	1   Actual	100	25	8	1/3   Remaining	?	25	10	2/3   We can apply chain rule now.   Total men required to complete the remaining work = 100× (25/25) × (8/10) × (2/3)/ (1/3) = 160.   So additional men required = 160 - 100= 
160 - 100 = 60
60.   ANSWER IS 60
Answer: B
John had a stock of 1000 books in his bookshop. He sold 75 on Monday, 50 on Tuesday, 64 on Wednesday, 78 on Thursday and 135 on Friday. What percentage of the books were not sold?	Choose the correct choice:
A) 59.8%
B) 23.8%
C) 66.5%
D) 34.9%
E) 43.5%

Solution: Let N be the total number of books sold. Hence   N = 75 + 50 + 64 + 78 + 135= 
75 + 50 + 64 + 78 + 135 = 402
402   Let M be the books NOT sold   M= 1000 - N = 1000 - 402= 
1000 - 402 = 598
598   Percentage   Books not sold / total number of books= 598/1000 = 59.8 = 59.8%   correct answer 59.8%
Answer: A
The number of sailors on a ship is 78% more than the number of officers. The ratio of sailors to officers would be
Options:
A) 33:25	B) 47:20	C) 47:25	D) 89:50	E) 97:50

Solution: Sailor = 1.78 * Officer   Sailor/Officer = 1.78/1 = 178/100 = 89/50   Answer will be 89:50
Answer: D
The cost of 100 articles is equal to selling price of 90. Find the gain or loss percent?
Select.
A) 11%
B) 20%
C) 27%
D) 32%
E) 49%

Solution: C.P. of each article be $1   C.P. of 90 articles = 100   gain% = 10/90*100 = 11% approximately   11%nswer is 11%
Answer: A
A farm has chickens, cows and sheep. There are eight times the number of chickens and cows than sheep. If there are more cows than chickens or sheep, and together, cows and chickens have a total of 100 feet and heads, how many sheep live at the farm? Choose the correct option
A) 5  B) 8  C) 10  D) 14  E) 3

Solution: Chicken - ch   Cows - C   Sheep -S   ch+C=8S   C> ch and c>s   Each cow has 4 legs and 1 head   Each chicken has 2 legs and 1 head   So 5c+3ch=100 (sum of legs and head)   There are 2 possible solutions to this equation   c=22 and ch=30 or   c=14 and ch=10   Since from first equation where ch+c=8s   The sum of ch and c should be divisbile by 8. 20 is not so the only possible solution is c=14 and ch=10. So s=3   Answer : 3
Answer: E
On June 1 a bicycle dealer noted that the number of bicycles in stock had decreased by 4 for each of the past 5 months. If the stock continues to decrease at the same rate for the rest of the year, how many fewer bicycles will be in stock on September 1 than were in stock on January 1?	Choose one
A) 8
B) 12
C) 20
D) 32
E) 36

Solution: Jan 1 = C   Feb 1 = C - 4   March 1 = C - 8   April 1 = C - 12   May 1 = C - 16   June 1 = C - 20   July 1 = C - 24   Aug 1 = C - 28   Sept 1 = C - 32   32ifference between stock on September 1 than were in stock on January 1 will be -   C - ( C - 32 )= 32   Hence answer will be (32)
Answer: D
Out of 8 consonants and 5 vowels, how many words of 4 consonants and 3 vowels can be formed?	Pick one.
A) 15000 B) 352800 C) 25200 D) 214000 E) None of these

Solution: Solution   Number of ways of selecting (4 consonants out of 8) and (3 vowels out of 5)   nCr=n!/r!(n-r)!   8c4 x 5c3= (8x7x6x5/4x3x2x1)x(5x4x3/3x2x1) =70x10=700   Number of group,each having 4 consonants and 3 vowels = 700   Each group contains 7 letter.   Number of ways of arranging 7 letters among themselves   = 7 ! = (7 x 6 x 5 × 4 × 3 × 2 × 1) = 5040 .   So, Required number of words = (5040 × 700) = 352800 .Answer 352800
Answer: B
The probability that A speaks truth is 3/5 and that of B speaking truth is 4/7. What is the probability that they agree in stating the same fact?  Choices:	A) 18/35	B) 18/39	C) 18/36	D) 18/33	E) 18/32

Solution: If both agree stating the same fact, either both of them speak truth of both speak false.   Probability = 3/5 * 4/7 + 2/5 * 3/7   = 12/35 + 6/35 = 18/35   18/35nswer: 18/35
Answer: A
In how many different number of ways a combination of 3 persons can be selected from 4 men and 2 women?
Options
A) 160
B) 180
C) 200
D) 210
E) 220

Solution: 6C3 × 5C2   6C3   = 6!/(3! . 3!)   = (6 × 5 × 4)/(3 × 2)   = 5 × 4 = 20.   5C2   = 5!/(3! . 2!)   = 5 × 2 = 10   = 20 × 10 = 200.   200)
Answer: C
The value of a "Tin-Rin" stock in the stock market decreased by 15% in the last two years. The economic experts believe that the value of the stock will increase by 7% during the following year, which will make the value $440. What was the approximate price of the stock two years ago?	Choose the correct choice from the following options.
A) $473.
B) $464.
C) $455.
D) $445
E) $430.

Solution: Let the stock value was x.   x* 0.85 * 1.07= 440   x= 440/0.85*1.07= 490 (approximately)   $473. is the answer
Answer: A
A contractor undertakes to complete the construction of a tunnel 720 meters long in 240 days and employs 60 men for the purpose. After 120 days, he finds that only 240 meters of the tunnel is complete. How many more men should be employ in order to complete the work in time? Choose the correct choice from the following choices:
A) 22	B) 27	C) 60	D) 88	E) 12

Solution: In 120days, only 240m of the tunnel is constructed by 60 men.   The remaining 120days, 480m of the tunnel can be constructed by 120 men.   Additional number of men required = 120 - 60= 
120 - 60 = 60
60 men.   Answer: 27
Answer: B
K-numbers are positive integers with only 2's as their digits. For example, 2, 22, and 222 are K-numbers. The K-weight of a number n is the minimum number of K-numbers that must be added together to equal n. For example, the K-weight of 50 is 5, because 50 = 22 + 22 + 2 + 2 + 2. What is the K-weight of 750?  Options.
A) 10	B) 11	C) 12	D) 13	E) 15

Solution: 750 = 3*222 + (22*3) + 9*2   K weight of 600 = 3 +3+9= 
3 +3+9 = 15
15   Answer 15
Answer: E
A bag contains 30 red jellybeans and 30 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability that all 3 jellybeans removed from the bag are blue? Choices
A) 9/100  B) 2/19  C) 1/8  D) 1/20  E) 3/10

Solution: Method-1   10 red jellybeans and 10 blue jellybeans   Total Outcomes = No. of ways to choose 3 Jelly bean at random out of a total 20 jellybeans = 20C3 = 1140   Favourable Outcomes = No. of ways to choose 3 Jelly bean such that they are all Blue out of 10 Blue = 10C3 = 120   Probability = Favourable Outcomes / Total Outcomes = 10C3 / 20C3   Probability = 120 / 1140 = 2/19   Answer: option B   Method-2   Probability of First jelly bean to be Blue = 10/20 [Total 10 Blue out of total 20 jellybeans]   Probability of Second jelly bean to be Blue = 9/19 [Total 9 Blue remaining out of total 19 jellybeans remaining]   Probability of Third jelly bean to be Blue = 8/18 [Total 8 Blue remaining out of total 18 jellybeans remaining]   Required Probability = (10/20)*(9/19)*(8/18) = 1/20   Answer: option 1/20
Answer: D
Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?  Choose the most appropriate option.
A) 57%	B) 60%	C) 90%	D) 65%	E) 70%

Solution: Req percentage = 11628/20400*100= 
11628/20400*100 = 57
57%   57%NSWER 57%
Answer: A
At Winson's firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?  Choose the correct answer.
A) 700	B) 1000	C) 1300	D) 1600	E) 2000

Solution: At Winson's firm's annual revenue grows twice as fast as its costs. First solve for how much revenue is increasing each year:   R2008= R2007*(1+x)   R2009= R2007*(1+x)^2=1.44*R2007   (1+x)^2 = 1.44   1+x=1.2   x=0.2 aka revenue increases 20% each year and cost increases 10% annually   Next solve for R2007and 13002007:   R2007= 13002007- 1000   1.2*R2007- 1.1*13002007= 0   1.2*[13002007- 1000] - 1.1*13002007= 0   0.1*13002007= 1,200   13002007= 12,000   R2007= 11,000   Finally find 2009 profits:   Profit2009= 1.44*11,000 - 1.21*12,000   Profit2009= 15,840 - 14,520   Profit2009= 1320   Answer: 1300
Answer: C
A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 50 paisa. If the share of Y is RS. 18, what is the total amount?	Choose the correct choice from the following options
A) 115  B) 116  C) 117  D) 78  E) 119

Solution: x:y:z = 100:45:50   20:9:10   9 --- 18   39 --- ? => 78   ANSWER:78
Answer: D
In a group of cows and hens, the number of legs are 10 more than twice the number of heads. The number of cows is :
Choose the most appropriate option
A) 5 B) 6 C) 7 D) 10 E) 12

Solution: Let no of cows be x, no of hens be y.   So heads=x+y   Legs=4x+2y   Now, 4x+2y = 2(x+y)+ 10   2x = 10   x = 5.   5NSWER:5
Answer: A
If a < b < c , which of the following must be true?
(I) a < b^2
(II) b − a < c
(III) a^2 > b^2 > c^2
Choose one.
A) None B) I only C) II only D) III only E) II and III

Solution: (I) a < b^2. Not necessarily true fractions: try a=1/3 and b=1/2.   (II) b − a < c. Not necessarily true: try a=-1, b=0, and c=1.   (III) a^2 < b^2 < c^2. Not necessarily true: try a=1, b=2, and c=3.   None of the options must be true.   Nonenswer: None.
Answer: A
A company D has 45 percent of the employees are secretaries and 45 percent are salespeople. If there are 50 other employees of Company D, how many employees does Company D have?
Choose the correct choice from the following choices:
A) 500
B) 162
C) 180
D) 152
E) 250

Solution: Let the total number of employees in the company be x   % of secretaries = 45%   % of salespeople = 45%   % of of employees other than secretaries and salespeople = 100 - 90= 
100 - 90 = 10
10%   But this number is given as 50   so 10% of x= 50   x = 500   Therefore there a total of 500 employees in the company D   Correct answer - 500
Answer: A
3640 ÷ 14 × 16 + 340 = ?
Choose one
A) 0.7
B) 3525
C) 4480
D) None of these
E) Cannot be determined

Solution: Solution   Given exp. = 260 × 16 + 340 = 4160 + 340= 
4160 + 340 = 4_500
4500.   Answer None of these
Answer: D
The ratio of investments of two partners is 11:12 and the ratio of their profits is 2 : 3. If A invested the money for 8 months , find for how much time B invested his money?	Choose one
A) 11  B) 27  C) 28  D) 12  E) 19

Solution: Suppose A invested Rs.11 for 8 months and B invested Rs. 12 for x months.   Ratio of investments of 11 and B   = (11 x 8) : (12 x x)   = 88 : 12x   {88}/{12x}={2}/{3}\Rightarrow x=11   11nswer:11
Answer: A
To a sugar solution of 10 liters containing 50% sugar, 10 liter of water is added. The percentage of sugar in the new solution is?  Pick one
A) 25% B) 30% C) 15% D) 20% E) 18%

Solution: Quantity of sugar = 50*10/100= 
50*10/100 = 5
5kg   New percentage= 5/20 * 100= 
5/20 * 100 = 25
25%   25%nswer is 25%
Answer: A
Three runners W, B and C run a race, with runner W finishing 12m ahead of runner B and 18m ahead of runner C, while runner B finishes 8m ahead of runner C. Each runner travels entire distance at a constant speed. What was the length of the race?  Choose the correct answer
A) 36m B) 48m C) 60m D) 72m E) 84m

Solution: Let distance of race be x mtrs. Then when W finishes x m , B has run (x- 12)mtrs and C has run x-18 mtrs. so at this point B is 6 m ahead of C. Now to finish race b needs to run another 12 m, so he runs another 12 m. when B finishes race he is 8 m ahead of C. so last 12 m B has run, C has run 10 m.   as speeds are constant, we have equation,   x-12/ x-18 = 12/10 > x = 48.   Answer 48m
Answer: B
If m and n are positive integers, and m=2n and k=5m, then -	Choices:	A) 3m is a factor of k/2.	B) 2m is a factor of k.	C) m/2 is a factor of k.	D) k is a factor of m.	E) k is a factor of m/2.

Solution: m=2n --> m is even.   k=5m --> m is factor of k, thus m/2 = integer must also be a factor of k.   Answer: m/2 is a factor of k..
Answer: C
One out of every 500 light bulbs are defected. If 5 out of every 10 defected light bulbs have a broken glass and there are 20 broken glass light bulbs in the shipment, how many light bulbs total are there in the shipment? Select the correct option.
A) 2,000	B) 5,000	C) 10,000	D) 20,000	E) 52,000

Solution: out of 500 only 1 bulb is defective.So for 10 defective bulbs, we must have 5000 bulbs   Now out of these 10 bulbs, 5 bulbs, have broken glass   i.e 5 broken glass out of 5000 bulbs   20 broken glass will be from 20000 bulbs   Answer is 20,000
Answer: D
How much is 70% of 40 is greater than 4/5 of 25?
Choose the most appropriate option:
A) 12	B) 27	C) 18	D) 12	E) 8

Solution: (70/100) * 40 â€“ (4/5) * 25   28- 20= 
28- 20 = 8
8   Answer:8
Answer: E
If a sample of data has mean of 21 and SD of 3, which of the following values is more than 2.5 SDs from the mean?  Choose one:  A) a. 12  B) b. 13.5  C) c. 17  D) d. 23.5  E) e. 26.5

Solution: Value ismore than 2.5SDfrom the mean means that the distance between the mean and the value must be more than 2.5SD=7.5. So the value either < 21-7.5= 
 21-7.5 = 13.5
13.5 or >21+7.5=28.5.   a. 12nswer: a. 12.
Answer: A
Two numbers are less than a third number by 40% and 47% respectively. How much per cent is the second number less than the first ? Choose the correct answer
A) 95%  B) 88%  C) 85%  D) 90%  E) none of these

Solution: Here, x = 40 and y = 47   Therefore second number   = [[(100 - y)/(100 - x )] x 100 ]% of first number   = [[(100 - 47)/(100 - 40 )] x 100 ]% of first number   i.e, 88.3% of the first.   ANSWER:88%
Answer: B
A restaurant meal cost $37.50 and there was no tax. If the tip was more than 10 percent but less than 15 percent of the cost of the meal, then the total amount paid must have been between Choose the most appropriate option: A) $40 and $42 B) $42 and $44 C) $38 and $40 D) $37 and $39 E) $36 and $37

Solution: The total amount for the meal was between 37.5*1.1= 
37.5*1.1 = 41.25
41.25 and 37.5*1.15=43.125. Only option which covers all possible values of the meal is B.   Answer: $42 and $44.
Answer: B
The number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively. After Kaye gave Alberto 12 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 8:6. As a result of the gift, Kaye had how many more stamps than Alberto?
Choices:	A) 20	B) 30	C) 40	D) 32	E) 90

Solution: C   K1 = 5x   A1 = 3x   K2 = 5x - 12   A2 = 3x + 12   K2/A2 = 8/6   (5x-12)/(3x+12) = 8/6   6*(5x-12) = 8*(3x+12)   30x - 72 = 24x + 96   6x = 168   x = 28   K2 = 5*28 - 12= 
5*28 - 12 = 128
128   A2= 3*28 + 12= 
3*28 + 12 = 96
96   K2 - A2= 32   Answer : 32
Answer: D
Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 60 km/hr and 90 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Select the correct option
A) 48 B) 93 C) 24 D) 23 E) 12

Solution: Relative speed = 60 + 90= 
60 + 90 = 150
150 km/hr.   150 * 5/18= 125/3 m/sec.   Distance covered = 500 + 500= 
500 + 500 = 1_000
1000 m.   Required time= 1000 * 3/125= 
1000 * 3/125 = 24
24 sec.   Answer:24
Answer: C
Colin has an app on his phone that generates a random integer betwen 1 and 10. He generates
10 random numbers and computes the sum. Compute the number of distinct possible sums
Colin can end up with.  Choose the correct answer: A) 41 B) 32 C) 75 D) 91 E) 82

Solution: The maximum possible sum is 10 * 10= 
10 * 10 = 100
100. The minimum possible sum is 10.   Hence, there are   100 - 10 + 1= 
  100 - 10 + 1 = 91
91 possible sums   correct answer 91
Answer: D
One man traveled a distance of 61 km in 9hrs. He traveled partly on footat 4 km/hr and partly on bicycle ta 9 km/hr. The distance traveled on foot is? Choose the correct answer
A) 8 km	B) 12 km	C) 16 km	D) 18 km	E) 20 km

Solution: Let the distance travelled on foot be x km.   Then, distance travelled on bicycle = (61 -x) km.   So, x + (61 -x) = 9   4 9   9x + 4(61 -x) = 9 x 36   5x = 80   x = 16 km.   16 km
Answer: C
An express traveled at an average speed of 100 km/hr, stopping for 4 min after every 75 km. How long did it take to reach its destination 150 km from the starting point ?
Select.
A) 8 hrs 29 min
B) 6 hrs 28 min
C) 2 hrs 28 min
D) 6 hrs 28 min
E) 1 hr 34 min

Solution: Explanation:   Time taken to cover 150 km = 150/100 = 1 hr 30 mins   Number of stoppages = 150/75 - 1= 
150/75 - 1 = 1
1   Total time of stoppages= 4 x 1 = 4 min   Hence, total time taken = 1 hr 34 min.   Answer: 1 hr 34 min
Answer: E
How many quarters are equal to 7 dollars?	Choose the correct choice from the following options.
A) 1 B) 28 C) 12 D) 9 E) 7

Solution: 7 * 4= 
7 * 4 = 28
28 quarters   Answer : 28
Answer: B
If w is three times larger than n , and if 2n+3 is 20% of 25, what is the value of ? Choose one
A) 1 B) 2 C) 3 D) 6 E) 12

Solution: Then the wordings of question are misleading. Moreover, it'd also be a bad way to convey w=4n, if it really wanted to convey so.   From other questions that I have seen, proper wordings could be:   If w is three times as large as n   OR simply,   If w is three times n.3
Answer: C
What is the next number in this sequence: 39, 52, 65, 78, 91 ? Choose the correct choice
A) 107 B) 112 C) 104 D) 99 E) 109

Solution: By subtracting each number from the one after it, we can determine that the numbers are all multiples of 13. By adding 13 to the last number, you get the answer.   91 + 13= 
91 + 13 = 104
104   Answer: 104
Answer: C