MU-NLPC/Calc-aqua_rat huggingface dataset:
A bowl was filled with 10 ounces of water, and 0.012 ounce of the water evaporated each day during a 50-day period. What percent of the original amount of water evaporated during this period?
Choose the correct choice from the following answers:
A) 0.004%
B) 0.04%
C) 0.40%
D) 6%
E) 40%

Solution: Total amount of water evaporated each day during a 50-day period = .012 * 50   =.012 * 100/2   = 1.2/2= 
1.2/2 = 0.6
.6   percent of the original amount of water evaporated during this period= (.6/10) * 100= 
(.6/10) * 100 = 6
6 %   Answer 6%
Answer: D
By selling 12 toffees for a rupee, a man loses 20%. How many for a rupee should be sell to get a gain of 20%? Choose the correct choice from the following answers:  A) 5  B) 8  C) 10  D) 15  E) 20

Solution: Explanation:   Let S.P. of 12 toffees be Rs. x.   Then, 80:1 = 120:x or x = 120/180 = 3/2   For Rs. 3/2, toffees sold = 12.   For Re. 1, toffees sold = 12 * 2/3= 
12 * 2/3 = 8
8   ANSWER IS 8
Answer: B
If John invested $ 1 at 6 percent interest compounded annually, the total value of the investment, in dollars, at the end of 4 years would be	Choose the correct choice from the following options:
A) (1.5)^4
B) 4(1.5)
C) (1.05)^4
D) 1 + (0.05)^4
E) (1.06)^4

Solution: In this prompt, the answer choices show that we don't actually have to calculate anything - we just need to 'format' the calculation correctly. We're told that the interest is COMPOUNDED ANNUALLY, so we need the Compound Interest Formula, with a Principal of $1, an R of 5% (which would 'translate' as .05) and a T of 4. We'd have....   (1.06)^4
Answer: E
2, -6, 18, -54, 162, (...)  Choose the most appropriate option:
A) 486	B) 422	C) -422	D) -468	E) -486

Solution: 2 × -3 = -6   -6 × -3 = 18   18 × -3 = -54   -54 × -3 = 162   162 × -3 = -486   Answer is -486.
Answer: E
A trader bought a car at 20% discount on its original price. He sold it at a 40% increase on the price he bought it. What percent of profit did he make on the original price?	Options
A) 12%
B) 19%
C) 15%
D) 14%
E) 22%

Solution: Original price = 100   CP = 80   S = 80*(140/100)= 
80*(140/100) = 112
112   100 - 112= 12%   12%nswer:12%
Answer: A
A man can row his boat with the stream at 22 km/h and against the stream in 10 km/h. The man's rate is? Choose the correct choice from the following answers
A) 1 kmph
B) 6 kmph
C) 7 kmph
D) 4 kmph
E) 9 kmph

Solution: Explanation:   DS = 22   US = 10   S = ?   S = (22 - 10)/2= 
(22 - 10)/2 = 6
6 kmph   Answer: 6 kmph
Answer: B
Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.2880?	Choose the correct choice from the following options.
A) 8100 B) 3388 C) 7767 D) 2009 E) 3645

Solution: 2880* 9/8 * 9/8= 
2880* 9/8 * 9/8 = 3_645
3645   Answer: 3645
Answer: E
Rahim travels 4 Kms in 15 minutes and another 4 Kms in 5 mins. Deepak travels at the average speed of Rahim. Then what could be the distance covered by him in 50 minutes:	Choose the correct choice from the following answers:
A) 10.m. B) 12 km. C) 20 km. D) 13.5km. E) 15.5km.

Solution: Distence=8kms,time=20mins;   the ditence covered by him in 50mins=50*8/20= 
50*8/20 = 20
20km   ANSWER:20 km.
Answer: C
If the positive integer x is a multiple of 3 and the positive integer y is a multiple of 3, then xy must be a multiple of which of the following?
I. 3
II. 12
III. 9	Choose the correct choice from the following answers:
A) II only  B) I and III only  C) I and II only  D) II and III only  E) I, II, and III

Solution: x=3a   y=3b   xy=9ab   where a,b are integers   Hence , xy will always be divisible by 3,9 .   I and III only is the answer.
Answer: B
A man buys a cycle for Rs. 800 and sells it at a loss of 15%. What is the selling price of the cycle?
Pick one
A) s. 1090	B) s. 1160	C) s. 680	D) s. 520	E) s. 700

Solution: S.P. = 85% of Rs. 800 = Rs.85/100x 800 = Rs. 680   ANSWER :s. 680
Answer: C
If n divided by 7 has a remainder of 2, what is the remainder when 5 times n is divided by 7?
Answers:	A) 1	B) 2	C) 3	D) 5	E) 6

Solution: As per question => N=7P+2 for some integer p   hence 5N => 35Q + 10 => remainder =>10 for some integer Q   Alternatively => N=2 > 5N=> 10 => 10 divided by 7 will leave a remainder 3   hence 3
Answer: C
If the simple interest on a sum of money for 2 years at 5% per annum is Rs.50, what is the compound interest on the same at the same rate and for the same time?  Options: A) Rs.51.25 B) Rs.52 C) Rs.54.25 D) Rs.60 E) None

Solution: Solution   Sum	=Rs.(50 x 100/2x5)   = Rs. 500.   Amount	=[Rs.(500 x(1+5/100)²]   = Rs(500x21/20x21/20).   =Rs. 551.25   C.I	= Rs. (551.25 - 500)   = Rs. 51.25   Rs.51.25nswer Rs.51.25
Answer: A
Find the product of the local value and absolute value of 6 in 564823	Choices:
A) 8000	B) 16000	C) 12000	D) 18000	E) 360000

Solution: Explanation:   Place value = Local value   Face value = Absolute value   The place value of 6 in 564823 is 6 x 10000 = 60000   The face value of 6 in 564823 is nothing but 6.   => 60000 x 6 = 360,000   Answer: Option 360000
Answer: E
In how much time will a train of length 130 m, moving at 36 kmph cross an electric pole?  Select the correct option
A) sec
B) sec
C) sec
D) sec
E) sec

Solution: Convert kmph to mps. 36 kmph = 36 * 5/18= 
36 * 5/18 = 10
10 mps.   The distance to be covered is equal to the length of the train.   Required time t= d/s = 130/10= 
130/10 = 13
13 sec.   Answer:sec
Answer: D
The original price of a certain TV set is discounted by s percent, and the reduced price is then discounted by 2s percent. If P is the original price of the TV Set, which of the following represents the price of the television set after the two successive discounts?	Options.
A) P(1 - 0.03x + 0.02x^2)
B) P(1 - 0.03s + 0.0002s^2)
C) P(1 - 0.03x + 0.002x^2)
D) P(1 - 2x^2)
E) P(1 - 3x + 2x^2)

Solution: Youcansolve this problem with number plugging.   Say the original price was $10 and s=50. Then after the first reduction the price would become $5 and after the second reduction of   2*50= 
  2*50 = 100
100% the rprice would become $0.   Now, since P is not zero, then the expression in the brackets must be zero for s=50. Only answer choice B works.   Answer: B.   On this problem - number pluggin is not giving me the answer.. I initially used s = 10, then 2s = 20 and P = 100. Answer should after both consecutive discounts = 72. I plug in the respective values and I keep getting 68. Can you double check my math.   100 (1-0.03(10) + 0.0002 (10)^2)   100 (1-0.3 + 0.0002 (100))   100 (0.7 + 0.02)   100 (0.68) = 68????   double check my math. Am I missing something? I also plugged in your numbers and still did not get zero as final answer with choice P(1 - 0.03s + 0.0002s^2)..
Answer: B
A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 1:3 and B:C = 1:5. If the total runs scored by all of them are 95, the runs scored by C are?
Select the correct option: A) 20.23 B) 20.13 C) 75 D) 20.93 E) 10.93

Solution: A:B = 1:3   B:75 = 1:5   A:B:75 = 1:3:15   15/19 * 95= 
15/19 * 95 = 75
75   ANSWER:75
Answer: C
There are 15 stamps from which two stamps will be selected. Tom has five stamps which are same as five of the ten stamps to be selected. What is the probability that two stamps selected will not be one of the stamps that Tom has?	Choose the most appropriate option
A) 3/7
B) 8/15
C) 6/17
D) 5/18
E) 7/15

Solution: the highlighted portion is NOT clear and poorly written, But I believe you mean that Tom has five stamps of the 15 from which two are being selected..   so we have ONLY 10 which can be selected..   P=10/15∗9/14=3/7   3/7NSWER:3/7
Answer: A
During the first two weeks of June, the total rainfall in Springdale was 40 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall in inches during the second week of June?  Pick one:  A) 15  B) 18  C) 21  D) 24  E) 27

Solution: Let x be the rainfall in the first week. Then 1.5x was the rainfall in the second week.   2.5x = 40   x = 16   The rainfall during the second week was  1.5 * 16= 
 1.5 * 16 = 24
24 inches   The answer is 24.
Answer: D
On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is:	Select.
A) Rs. 45
B) Rs. 50
C) Rs. 55
D) Rs. 60
E) Rs. 60

Solution: (C.P. of 17 balls) - (S.P. of 17 balls) = (C.P. of 5 balls)   C.P. of 12 balls = S.P. of 17 balls = Rs.720.   C.P. of 1 ball = Rs.720/12	= Rs. 60.   Answer: Option Rs. 60
Answer: D
A sock drawer contains 3 socks, each one a different solid color. The colors of the socks are red, orange and violet. If a person reaches into the drawer and pulls out two socks, how many different color combinations are possible in the selected pair of socks?	Choose the correct choice from the following answers
A) 12 B) 15 C) 21 D) 3 E) 42

Solution: Since the order in which we select the socks does not matter , we can use combinations.   We can select 2 socks from 3 socks in 3C2 ways.   3C2 = 3   Answer : 3
Answer: D
A shopkeeper buys two articles for Rs.1000 each and then sells them, making 60% profit on the first article and 60% loss on second article. Find the net profit or loss percent?
Choose the correct option:  A) 200  B) 278  C) 282  D) 202  E) 600

Solution: Profit on first article = 60% of 1000 = 600.   This is equal to the loss he makes on the second article. That, is he makes neither profit nor loss.   Answer: 600
Answer: E
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 265 m long?
Choose the correct answer.
A) 50	B) 99	C) 88	D) 77	E) 21

Solution: :   Speed = 45 * 5/18 = 25/2 m/sec   Total distance covered = 360 + 265= 
360 + 265 = 625
625 m   Required time= 625 * 2/25= 
625 * 2/25 = 50
50 sec   50nswer:50
Answer: A
-20 , -16 , -12 , -8 ....
In the sequence above, each term after the first is 3 greater than the preceding term. Which of the following could not be a term in the sequence?
Options.
A) 0
B) 200
C) 441
D) 663
E) 762

Solution: Ans : 200   Since 762 is not divisible by 3 , all the other options are divisible by 3
Answer: B
If x and y are integers such that |y + 3| ≤ 3 and 2y – 3x + 6 = 0, what is the least possible value T of the product xy?  Pick:	A) -12	B) -3	C) 0	D) 2	E) None of the above

Solution: How to deal with inequalities involving absolute values? First example shows us the so callednumber case   In this case we have |y + 3| ≤ 3 which is generalized |something| ≤ some number. First we solve as if there were no absolute value brackets:   y + 3 ≤ 3   y ≤ 0   So y is 0 or negative   Second scenario - remove the absolute value brackets. Put a negative sign around the other side of the inequality,ANDflip the sign:   y + 3 >= -3   y >= -6   Therefore we have a possible range for y: -6=<y<=0   Ok, so far so good, we're half way through. What about x?   Here's the formula: 2y – 3x + 6 = 0, rewrite it as 2y + 6 = 3x.   You can say that 2y + 6 is a multiple of 3 (=3x). So all values which must be integer must also satisfy this constraint. I'm just saying that, so it's easier to evaluate all the possible numbers (-6, -3, 0). If you plug in y = 0, x will be 2 and xy = 0 as the lowest possible value T.   Hence, Answer 0hoice 0 is the one to go.
Answer: C
In a certain alphabet, 8 letters contain a dot and a straight line. 24 letters contain a straight line but do not contain a dot. If that alphabet has 40 letters, all of which contain either a dot or a straight line or both, how many letters contain a dot but do not contain a straight line?  Choose the correct answer: A) 4 B) 8 C) 14 D) 20 E) 28

Solution: We are told that all of the letters contain either a dot or a straight line or both, which implies that there are no letters without a dot and a line (no line/no dot box = 0).   First we find the total # of letters with lines:  8 +24= 
 8 +24 = 32
32;   Next, we find the total # of letters without line:  40 - 32= 
 40 - 32 = 8
8;   Finally, we find the # of letters that contain a dot but do not contain a straight line:  8- 0= 
  8- 0 = 8
8.   8
Answer: B
A man invests Rs. 6,000 at the rate of 5% per annum. How much more should he invest at the rate of 8%, so that he can earn a total of 6% per annum?  Choose the correct answer.
A) Rs. 1200  B) Rs. 1300  C) Rs. 1500  D) Rs. 3000  E) None of these

Solution: Explanation :   Interest on Rs.6000 at 5% per annum = ( 6000 × 5 × 1) / 100 = Rs. 300   Let his additional investment at 8% = x   Interest on Rs.x at 8% per annum = ( x × 8 × 1 ) / 100 = 2x/25.   To earn 6% per annum for the total, interest = (6000 + x) × 6 × 1/100.   => 300 + 2x/25 = (6000 + x) × 6 × 1/100.   => 30000 + 8x = (6000 + x) × 6.   => 30000 + 8x = 36000 + 6x.   => 2x=6000.   => x=3000.   Answer : Rs. 3000
Answer: D
When a certain number X is divided by 63, the remainder is 11. What is the remainder when X is divided by 9? Pick one
A) 2
B) 3
C) 4
D) 5
E) 6

Solution: When a certain number X is divided by 63, the remainder is 11. What is the remainder when X is divided by 9?   Putting a value say x = 11 we get remainder as 11 when divided by 63.   When 11 divided by 9 we get 2 as remainder.   2 is the answer.
Answer: A
Three pipes of same capacity can fill a tank in 8 hours. If there are only two pipes of same capacity, the tank can be filled in.	Select:
A) 17 hours B) 12 hours C) 16 hours D) 24 hours E) None of these

Solution: Explanation:   The part of the tank filled by three pipes in one hour = 1/8   => The part of the tank filled by two pipes in 1 hour = 2/3 * 1/8 = 1/12.   The tank can be filled in 12 hours.   ANSWER IS 12 hours
Answer: B
The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years? Choose the correct choice from the following answers
A) 7:5	B) 7:0	C) 7:3	D) 7:2	E) 7:8

Solution: Let P's age and Q's age be 6x and 7x years respectively.   Then, 7x - 6x = 4 => x = 4   Required ratio = (6x + 4) : (7x + 4)   28 : 32 = 7:8.Answer: 7:8
Answer: E
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Choices: A) 3/4 B) 1/4 C) 3/8 D) 7/8 E) 5/8

Solution: Explanation:   Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}   Let E = event of getting at most two heads.   Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.   P(E) =n(E)/n(S)= 7/8	.   ANSWER : 7/8
Answer: D
Two numbers are in the ratio 3:5. If 9 be subtracted from each, they are in the ratio of 9:17. The first number is:  Choose the most appropriate option.
A) 36 B) 77 C) 88 D) 55 E) 221

Solution: (3x-9):(5x-9) = 9:17   x = 12 => 3x = 36   36nswer: 36
Answer: A
How many 4-digit numbers (ABCD) can be formed such that |A – D| = 2? Choose the most appropriate option.
A) 2,000
B) 1,900
C) 1,800
D) 1,600
E) 1,500

Solution: Digit A can be filled in 9 ways (excluding 0)   Digit B can be filled in 10 ways   Digit 1,800 can be filled in 10 ways   Digit D can be filled in 2 ways (because of modulus A-D )   The answer will be  9*10*10*2= 
 9*10*10*2 = 1_800
1800   Ans 1,800
Answer: C
The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 45 kmph, find the speed of the stream?
Choose the correct choice from the following options.
A) 15	B) 88	C) 14	D) 12	E) 17

Solution: The ratio of the times taken is 2:1.   The ratio of the speed of the boat in still water to the speed of the stream = (2+1)/(2-1)= 
(2+1)/(2-1) = 3
3/1= 
3/1 = 3
3:1   Speed of the stream= 45/3= 
45/3 = 15
15 kmph.   15nswer:15
Answer: A
Village X has a population of 68000, which is decreasing at the rate of 1200 per year. Village Y has a population of 42000, which is increasing at the rate of 800 per year .in how many years will the population of the two villages be equal?  Choose the correct answer
A) 13	B) 15	C) 16	D) 12	E) 11

Solution: Let the population of two villages be equal after p years   Then,68000-1200p=42000+800p   2000p=26000   p=13   13nswer is 13.
Answer: A
Shweta buys a product at 25% discount rate. At what % over the cost price should she sell the product to make an overall 25% profit over the listed price?	Choose the most appropriate option
A) 66.67% B) 66.69% C) 66.63% D) 66.64% E) 66.61%

Solution: Let the listed price of the product be x   Hence, at 25% discount rate the Cost Price will become: 3x/4   Now to make an overall profit of 25% over listed price:   SP = CP+(25/100)CP   => SP = x+x/4   =>SP = 5x/4   =>Selling Price over Cost price: (5x/4)-(3x/4)   =>x/2   =>%Selling price over Cost price: (x/2)/(3x/4)*100   =>   66.67%NSWER: 66.67%
Answer: A
If each year the population of the country grows by 10%, how many years will elapse before the population of the country doubles?
Pick.
A) 3	B) 4	C) 5	D) 7	E) 8

Solution: Till Year 2000, population is 100 .   Year 2001: Population becomes 110 ............. 1 Year elapsed   Year 2002: Population becomes 121 ............. 2 Year elapsed   Year 2003: Population becomes>133 ............. 3 Year elapsed   Year 2004: Population becomes> 146 .................. 4 year elapsed   Year 2005: Population becomes> 160 .................. 5 year elapsed   Year 2006: Population becomes> 176 .................. 6 year elapsed   Year 2007: Population becomes> 193 .................. 7 year elapsed   Year 2008: Population > 200 .................. 8 year elapsed   Answer:8
Answer: E
The ratio of the present ages of P and Q is 3:4. 5 years ago, the ratio of their ages was 5:7. Find the their present ages?	Choose the correct choice from the following options: A) 30,40 B) 25,30 C) 50,60 D) 20,40 E) 10,20

Solution: Answer: Option A   Their present ages be 3X and 4X.   5 years age, the ratio of their ages was 5:7, then (3X - 5):(4X - 5) = 5:7   X = 35 - 25 => X = 10.   Their present ages are: 30, 40.
Answer: A
The number of cars present at a particular time was measured at 2,999 different locations on Tuesday and on Wednesday. The number of locations that had more cars on Wednesday was 10% higher than the number of locations that had more cars on Tuesday. How many of the locations had more cars on Tuesday?	Choose one.
A) 1,428	B) 1,633	C) 1,860	D) 2,460	E) 2,829

Solution: The question states that all these 2,999 locations were measured twice, once on each day.   It also breaks the 2,999 into two groups, the higher-on-Tuesday locations and the higher-on-Wednesday locations, which we can call T and W.   Therefore, we can write two equations:   For each of the first and second day count of locations, T + W = 2999   But, for the second day count, W = 1.10 T   i.e. for Second day count, T + 1.10T = 2999   i.e. 2.10 T = 2999   i.e. T = 1428   1,428
Answer: A
On dividing a certain number by 234, we get 43 as remainder. If the same number is divided by 13, what will be the remainder? Choose the correct choice from the following options.
A) 6	B) 9	C) 4	D) 7	E) 8

Solution: Description :   Solution : suppose that on dividing the given number by 234,   we get quotient=x and remainder= 43   then, number= 234*x+43----> (1).   => (13*18x)+(13*3)+4   => 13*(18x+3)+4.   So, the number when divided by 13 gives remainder=4.   Answer :(4)
Answer: C
The average mark of the students of a class in a particular exam is 80. If 5 students whose average mark in that exam is 50 are excluded, the average mark of the remaining will be 90. Find the number of students who wrote the exam.
Select the correct option.
A) 20 B) 27 C) 25 D) 99 E) 21

Solution: Let the number of students who wrote the exam be x.   Total marks of students = 80 x.   Total marks of (x - 5) students = 90(x - 5)   80x - (5 * 50) = 90(x - 5)   200 = 10x => x = 20.20nswer: 20
Answer: A
Two pipes A and B can fill a tank in 4 and 5 hours respectively. If they are turned up alternately for one hour each, the time taken to fill the tank is?
Select
A) 4 hrs 27 min  B) 4 hrs 24 min  C) 4 hrs 74 min  D) 4 hrs 54 min  E) 4 hrs 21 min

Solution: 1/4 + 1/5 = 9/20   20/9 = 2 2/9   9/20 * 2 = 9/10 ---- 4 hours   WR = 1 - 9/10 = 1/10   1 h ---- 1/4   ? ----- 1/10   2/5 * 60= 
2/5 * 60 = 24
24= 4 hrs 24 min   Answer:4 hrs 24 min
Answer: B
The perimeters of two squares are 80 cm and 64 cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares.	Choices.
A) 42cm  B) 44cm  C) 46cm  D) 48cm  E) 49cm

Solution: Explanation:   Side of first square = (80/4)= 
(80/4) = 20
20 cm;   Side of second square= (64/4)= 
(64/4) = 16
16 cm.   Area of third square= [(20)2 - (16)2] cm2 = (400 - 256) cm2 = 144 cm2.   Side of third square = (144)(1/2) cm = 12 cm.   Required perimeter = (12 x 4) cm = 48 cm.   Answer: Option 48cm
Answer: D
The work done by a woman in 8 hours is equal to the work done by a man in 6 hours and by a boy in 12 hours. If working 6 hours per day, 9 men can complete a work in 6 days then in how many days can 12 men, 12 women and 12 boys together finish the same work by working 8 hours per day?	Choose the most appropriate option:
A) 1 1⁄3 days
B) 3 2⁄3 days
C) 3 days
D) 1 1⁄2 days
E) None of these

Solution: 8W = 6M = 12B   12M + 12W + 12B Þ 12M + 9M + 6M = 27M   \9 men can complete the work by working 1 hour per day in 6 × 6 days   \27 men working 8 hours per day  12  + 9  + 6= 
 12  + 9  + 6 = 27
27M   \9 men can complete the work by working 1 hour per day in 6 × 6 days   \27 men working 8 hours per day= 6×6×9/27×8=112days   Answer 1 1⁄2 days
Answer: D
What is the dividend? Divisor is 9, the quotient is 49, and the remainder is 52. Choose the correct choice from the following choices.
A) Undetermined
B) 0
C) 1
D) 546
E) 493

Solution: Dividend= Divisor * Quotient + Remainder   ?= 9 * 49 + 52   441 + 52= 
441 + 52 = 493
493   (e.g. Answer: 493)
Answer: E
A, B and C started a business with investment of Rs. 8000. Rs. 20000 and Rs. 32000. What is the share of B in the total profit of Rs. 5400 at the end of 1 year?	Choose one
A) Rs. 2880	B) Rs. 720	C) Rs. 1800	D) Rs. 1650	E) None of these

Solution: Explanation:   Ratio of capitals of A, B and C   = 8000 : 20000 : 32000 = 2 : 5 : 8   .: B's share = Rs. [(5/15) × 5400] = Rs. 1800   Answer: Option Rs. 1800
Answer: C
Integer m has 4 different prime factors and n has 3 different prime factors. If m and n has the greatest common factor of 15, how many different prime factors does mn have?  Choose the correct choice from the following answers.
A) 4
B) 5
C) 6
D) 7
E) 8

Solution: As m and n has GCF of 15, 3*5 should be common factor for both m and n.   m=3*5*p1*p2   n=3*5*p3   mn=3^2*5^2*p1*p2*p3   mn has prime numbers of 3,5,p1,p2p3   5
Answer: B
A, Band C can do a piece of work in 11 days, 5 days and 55 days respectively, working alone. How soon can the work be done if A is assisted by Band C on alternate days? Pick: A) 5 days B) 8 days C) 9 days D) 10 days E) 11 days

Solution: (5 days+B)'s 1 day's work = 1/11+1/5 = 16/55   (5 days+C)'s 1 day's work = 1/11+1/55 = 6/55   work done in 2 day's = 16/55+6/55 = 2/5   2/5th work done in 2 days   work done= 5/2*2= 
5/2*2 = 5
5 days   5 daysNSWER:5 days
Answer: A
Which one of the given numbers is divisible by 11?	Choose the correct choice from the following answers.
A) 4823718
B) 8423718
C) 8432718
D) 4132788
E) 4852718

Solution: Explanation:   4132788 = (4+3+7+8) – (1+2+8)= 
(1+2+8) = 11
11   So, the given number is divisible by 11   Answer:4132788
Answer: D
Cn = 2Cn-1 + 4 and Qn = 4Qn-1 + 8 for all n > 1. If C5 = Q4 and C7 = 316, what is the first value of n for which Qn is an integer? Choose the correct choice from the following.
A) 1	B) 2	C) 3	D) 4	E) 5

Solution: Assuming I have understood the symbols used correctly answer is 3- 3   37 = 2S6 +4 = 316   36 = 312/2= 
312/2 = 156
156= 235 + 4   35 = 152/2= 
152/2 = 76
76= Q4   Q4 = 4Q3 + 8 = 76   Q3 = 68/4= 
68/4 = 17
17   Q3= 4Q2 + 8 = 17   Q2 = 9/4= 
9/4 = 9/4 = around 2.25
2.25   Q2= 4Q1 + 8   Q1 will not be integer
Answer: C
RAJA complete a journey in 10 hours. He travels first half of the journey at the rate of 21 km/hr and second half at the rate of 24 km/hr. Find the total journey in km. Pick:
A) 200 km
B) 250 km
C) 224 km
D) 255 km
E) 260 km

Solution: consider x -- > (1/2)x/21 + (1/2)x/24 = 10   ==> x/21+x/24 = 20   15x = 168 * 20   ==> 224km   ANSWER 224 km
Answer: C