MU-NLPC/Calc-aqua_rat huggingface dataset:
In expressing a length 81.478 km as nearly as possible with three significant digits, find the percentage error? Choose the correct choice from the following choices:
A) 0.075% B) 0.156% C) 0.027% D) 0.048% E) 0.152%

Solution: Error = 81.5-81.478= 
81.5-81.478 = 0.022
0.022   Required percentage= (0.022/81.478)*100 = 0.027%   Answer is 0.027%
Answer: C
In a certain business school class, p students are accounting majors, q students are finance majors, r students are marketing majors, and s students are strategy majors. If pqrs = 1,155, and if 1< p < q < r < s, how many students in the class are accounting majors?  Choose the correct choice from the following options:	A) 3	B) 5	C) 8	D) 11	E) 17

Solution: Prime factorization of the product   pqrs = 1155   = 3* 5 *7 * 11   Since 1< p < q < r < s   Number of students who are accounting majors , p = 3   3nswer 3
Answer: A
How many ways are there to award a gold, silver and bronze medal to 13 contending teams? Choose the correct choice from the following.
A) 13 x 12 x 11	B) 10!/(3!7!)	C) 10!/3!	D) 360	E) 300

Solution: we clearly know that there can be only one winning team which deserves the gold medal. we can do the selection in 13 ways   if gold medal is given to 1 of the teams then only possible 12 teams can be considered for silver medal. we can do selection in 12 ways   similarly if gold and silver medals are awarded then only remaining 11 teams can be considered for a bronze medal. we can do the selection in 11 ways   Total number of ways to select the 3 possible medal winners = 13 * 12 * 11   Correct answer - 13 x 12 x 11
Answer: A
A and B walk around a circular track. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other before 9.30 a.m. ?	Choose the correct choice from the following options.
A) 9.90 a.m  B) 9.90 a.m  C) 9.30 a.m  D) 9.80 a.m  E) 3.30 a.m

Solution: Relative speed = 2 + 3= 
2 + 3 = 5
5 rounds per hour.   So, they cross each other 5 times in an hour and 2 times in half an hour.   Hence, they cross each other 7 times before 9.30 a.m   Answer:9.30 a.m
Answer: C
When a certain number X is divided by 143, the remainder is 37. Which of the following numbers, if added to X, would result in a number divisible by 13?  Pick.
A) 7	B) 21	C) 34	D) 2	E) 55

Solution: Now X= 143q + 45 = 11*13*q + 37..so we have to make only 37 div by 13..   37 + 2= 
37 + 2 = 39
39 divisible by 13 . add 2 to 37   ans 2
Answer: D
A can do 1/3rd the work in one day where as B can do it full. B can also do 1/3rd the work of C in one day. Ratio in their efficiency will be?  Choose the correct choice.
A) 4:3:9  B) 2:3:9  C) 1:3:9  D) 1:3:5  E) 1:2:9

Solution: W1:3:9 of A: B = 1:3   B: 1:3:9 = 1:3   ---------------------   A: B: 1:3:9 = 1:3:9   ANSWER:1:3:9
Answer: C
In the quadratic equation ax2 - 5x - 24 = 0, if the sum of two roots is 1, what is the product of the two roots? Select
A) 13  B) -24  C) -12  D) 12  E) 24

Solution: Explanation:   The sum of the roots of the quadratic equation ax2+ bx + c = 0 are (-b/a) and the product of the roots are (c/a).   Thus, in the equation ax2 - 11x + 40 = 0, where a = a, b = - 5 and c = -24.   we get, sum of the roots =5 / a = 5   a = 1   Product of the roots = -24 / 1 = -24   ANSWER:-24
Answer: B
For an employee to qualify for early retirement at a certain company, the sum of the employee’s age and years of service must be at least 76, If Sue was K years old when she was hired by the company, what is the minimum age at which she could possibly qualify for early retirement?
Choose the correct choice from the following.
A) K+38 B) 2K+38 C) (76+K)/2 D) (76-K)/2 E) 2(76-K)

Solution: Let y be the years of service at the company.   After y years of service, Sue's age will be K + y.   Sue can retire when (K+y) + y = 76   y = (76 - K)/2   Then Sue's age will be K + y = K + (76 - K)/2 = (76+K) / 2   The answer is (76+K)/2.
Answer: C
In a house a hall is 20 m long, 15m wide and 5m high. Its interior has to be covered with mat. What will be the total expenditure if it costs Rs. 30 per square m?	Choose the correct answer.
A) s.28500	B) s.50000	C) s.57000	D) s.60000	E) s.62000

Solution: Length (l) = 20 m, Breadth (b) = 15 m and Height (h) = 5 m   Total area of the hall to be covered with mat = 2(lb + bh + hl)   = 2(20 * 15 + 15 * 5 + 5 * 20)   =2(300 + 75 + 100)   = 2 * 475= 
2 * 475 = 950
950 sq. m   Total expenditure= 30 * 950   = Rs.28,500   s.28500
Answer: A
A man is 28 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is? Choose the most appropriate option.
A) 16  B) 19  C) 15  D) 26  E) 10

Solution: Let the son's present age be x years.   Then, man's present age = (x + 28) years.   (x + 28) + 2 = 2(x + 2)   x + 30 = 2x + 4   => x = 26.   Answer: 26
Answer: D
Tough and Tricky questions: Probability.
Medical analysts predict that a quarter of all people who are infected by a certain biological agent could be expected to be killed for each day that passes during which they have not received an antidote. What fraction of a group of 1,000 people could be expected to be killed if infected and not treated for three full days?	Choose the correct choice from the following answers:
A) 37/64 B) 8/27 C) 2/3 D) 19/27 E) 65/81

Solution: At the end of each day we will have 3/4 alive. So after 3 days we will have (3/4)^3 people alive. Therefore, fraction of dead people will be 1-(3/4)^3=37/64.   The correct answer is 37/64.
Answer: A
you need to pick a card at random from pack of 52 cards.
what are the chances of that card to be a jack or a king ? Choose the correct choice:  A) 2/15  B) 1/16  C) 3/25  D) 2/13  E) 2/26

Solution: D   2/13   There 4 kings & 4 jacks, which implies there are 8 cards that can satisfy the above problem.   =>8/52   => 2/13
Answer: D
Find the compound interest on $ 26,000 at 20% per annum for 9 months, compounded quarterly
Choose the correct answer.
A) 2532.93 B) 2552.26 C) 2524.23 D) 4098.25 E) 2512.23

Solution: Principal = $ 26000; Time = 9 months =3 quarters;   Rate = 20% per annum = 5% per quarter.   Amount = $ [26000 x (1+(5/100))^3] = $ 30098.25   CI. = $ (30098.25 - 26000)= 
(30098.25 - 26000) = 4_098.25
$ 4098.25   Answer 4098.25.
Answer: D
How many multiples of 8 are less than 1600, and also multiples of 64?
Choose the correct choice from the following options
A) 25
B) 28
C) 62
D) 83
E) 89

Solution: The LCM of 8 and 64 is 64. Divide   1600/64= 
  1600/64 = 25
25.xxx. So 25 is your answer.
Answer: A
If the area of a triangle with base 6 cm is equal to the area of a square with side 6 cm, then the altitude of the triangle is  Choose the correct choice:
A) 12 cm	B) 10 cm	C) 11 cm	D) 15 cm	E) 20 cm

Solution: area of square = 6^2 = 36   area of triangle = 36   1/2 bh = 36   h = 12 cm   12 cmNSWER 12 cm
Answer: A
x - y = 3
2x = 2y + 8
The system of equations above has how many solutions?
Options:	A) None	B) Exactly one	C) Exactly two	D) Exactly three	E) Infinitely many

Solution: x-y=3 ---------------1   2x=2y+8 ---------------2   Divide equation 2 by 2:   2x/2=(2y+8)/2   x=y+4   x-y=4----------------3   Equation 1 and 3 are equation has no solution   Nonens:None
Answer: A
In a certain store, the profit is 400% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?  Answers: A) 30% B) 70% C) 100% D) 250% E) 75%

Solution: Let C.P. = Rs. 100. Then, profit = Rs. 400, S.P. = Rs. 500   New C.P. = 125% of Rs. 100 = Rs. 125.   New S.P. = Rs. 500   Profit = 500 - 125 = Rs. 375   Required percentage = 375/500 * 100= 
375/500 * 100 = 75
75%   ANSW75%R:75%
Answer: E
A grocer has a sale of Rs. 2435, Rs. 2920, Rs. 2855, Rs. 3230 and Rs. 2560 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 2500?
Choose the correct choice from the following:
A) 5000
B) 4000
C) 1000
D) 6000
E) 8000

Solution: Total sale for 5 months = Rs. (2435 + 2920 + 2855 + 3230 + 2560) = Rs. 14000.   Required sale = Rs. [ (2500 x 6) - 14000 ]   = Rs. (15000 - 14000)   = Rs. 1000   Answer: Option 1000
Answer: C
A man can hit the target once in five shots. If he fires four shots in succession, what is the probability that he will hit the target? Choose the correct choice from the following options:
A) 1 B) 1/625 C) 181/256 D) 369/625 E) 185/625

Solution: In four shots he can hit once,twice,thrice,all hit   the probability of hitting the target is p(1hit out of 4)+P(2hit out of 4)+p(3hit out of 4)+p(All hit)   it is total probability-probability of not hitting the target   =>1-(4/5*4/5*4/5*4/5)   =>369/625   ANSWER:369/625
Answer: D
I bought two houses for Rs. 48 L. I sold one at a loss of 10% and other at a gain of 20% and then I found each house was sold at the same price. Find the cost of the house sold at a loss? Pick one:
A) A)65 B) B)28 C) C)43 D) D)18 E) E)42

Solution: x*(90/100)   = (48 - x)120/100   x = 27.4   Answer:28
Answer: B
find term of sequence from below series?
1,3,5,7,9,....50 Choose the correct choice from the following options.
A) 1235 B) 1458 C) 1600 D) 1809 E) 2500

Solution: This is an arithmetic progression, and we can write down   a=1a=1 ,d=2d=2 , n=50n=50 .   We now use the formula, so that   Sn=12n(2a+(n−1)l)Sn=12n(2a+(n−1)l)   S50=12×50×(2×1+(50−1)×2)S50=12×50×(2×1+(50−1)×2)   =25×(2+49×2)=25×(2+49×2)   =25×(2+98)=25×(2+98)   =2500=2500   2500
Answer: E
R and B are integers. The expression (R+1)(B+1) is even. What can be said about R and B? Options.
A) They are both even numbers. B) At least one of them is even. C) At least one of them is odd. D) They are both odd. E) Nothing can be said surly on R and B

Solution: Odd x Odd = Odd   Odd x Even = Even   Even x Even = Even   To fulfill condition Either (R+1) or (B+1) needs to be Even   So either R or B needs to be odd   Or Atleast one of them is odd.   Atleast one of them is odd=At least one of them is odd.
Answer: C
In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 23 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture.  Pick:
A) 9/8  B) 4/1  C) 2/3  D) 3/4  E) 3/2

Solution: Given that Milk/Water=4x/x and 4x+x=45 --> x=9.   Thus Milk=4x=36 liters and Water=x=9 liters.   New ratio = 36/(9+23) = 36/32 = 9/8.   9/8nswer: 9/8.
Answer: A
A women walking at 4 Kmph reaches her office 8 minutes late. If she walks at 8 Kmph, she reaches there 8 minutes earlier. How far is the office from her house?	Select:
A) 2 2/15 Km
B) 3 1/5 Km
C) 4 1/3 Km
D) 5 Km
E) 5 1/3 Km

Solution: Formula = S1*S2/S2-S1 * T1+T2/60   = 4*8/4 * 16/6   = 8* 16/60   = 8 * 4/15   = 2 2/15 Km   2 2/15 Km
Answer: A
By looking at a rectangular box, a carpenter estimates that the length of the box is between 2 to 2.1 meters, inclusive, the breadth is between 1 to 1.1 meters, inclusive and the height is between 2 to 2.1 centimeters, inclusive. If the actual length, breadth and height of the box do indeed fall within the respective ranges estimated by the carpenter, which of the following is the closest to the maximum possible magnitude of the percentage error W that the carpenter can make in calculating the volume of the rectangular box? Choose the correct choice from the following choices:
A) 1% B) 3% C) 10% D) 18% E) 22%

Solution: the dimensions are between 2-2.1, 1-1.1 and 2-2.1..   so MAX error in Volume=?..   IMPORTANT POINTS TO NOTE   1) Max ERROR would be when actuals and estimate are at the extreme ends..   2) BUT what about MAX % ERROR--   It will be when the base is the lowest...   so the ACTUALS should be lowest or at lower end and the ESTIMATE at the higher end..   SOLUTION   Actuals= 2*2*1=4..   Estimate=2.1*2.1*1.1=4.841..   Max % error W=(4.841-4)/4 *100= 84.1/4 = 21.25%..   21.25% is closest to 22% in the choices..   ans 22%
Answer: E
A special municipal payroll tax charges not tax on a payroll less than $300,000 and only 1% on a company’s payroll above $300,000. If Belfried Industries paid $200 in this special municipal payroll tax, then they must have had a payroll of?  Choose the correct answer:	A) $180,000	B) $202,000	C) $230,000	D) $400,000	E) $2,200,000

Solution: ANSWER : C , ( with different approach) :   The 300 paid is 1% of the additional amount above 200,000. Let it be X   Now 1% of X = 300   Therefore X= 30,000   Total = 200,000 + X= 230,000
Answer: C
If o and p are even integers, which of the following is an odd integer?	Choose the correct choice
A) op + 2	B) o(p − 1)	C) o(o + 5)	D) 3o + 4p	E) (o + 3)(p − 1)

Solution: If o and p are even integers, then:   A. op + 2: even + even = even   B. o(p − 1): even(odd) = even   C. o(o + 5): even(odd) = even   D. 3o + 4p: even + even = even   E. (o + 3)(p − 1): (odd)(odd) = odd.   Answer is (o + 3)(p − 1).
Answer: E
$500 will become $1000 in 2 years find the rate of interest?
Choose the correct answer:
A) A)10% B) B)20% C) C)25% D) D)30% E) E)50%

Solution: SI = simple interest = A-P = 1000-500= 
1000-500 = 500
$500   R= 100SI/PT = 100*500/500*2 =50%   Answer is 50%
Answer: E
Working together at their respective constant rates, Machine A and Machine B can produce 1,500 units in 8 hours. Working alone, Machine B would complete that same output in 50% more time. If Machine A were to work on its own for an 8-hour shift, what percent of the 1,500 unit total would it produce?  Choices:
A) 25	B) 36	C) 30	D) 67	E) 75

Solution: 1/A+1/B= 1/T   1/A +1/14= 1/8 (50% more of 8 is 14)   1/A= 1/24   Machine A can produce 1500 units in 24 hrs, so it can produce  1500*8/24= 
 1500*8/24 = 500
500 units is 8 hrs.   500 is 30% of 1500.   30 is the answer
Answer: C
Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is?  Options:	A) 48	B) 77	C) 55	D) 27	E) 21

Solution: Relative speed = 60 + 90= 
60 + 90 = 150
150 km/hr.= 150 * 5/18 = 125/3 m/sec.   Distance covered = 1.10 + 0.9= 
1.10 + 0.9 = 2
2 km= 2000 m.   Required time = 2000 * 3/125= 
2000 * 3/125 = 48
48 sec.   Answer: 55
Answer: C
A certain car can travel 56 kilometers on a liter of fuel. If the fuel tank’s contents decrease by 3.9 gallons over a period of 5.7 hours as the car moves at a constant speed, how fast is the car moving, in miles per hour? (1 gallon = 3.8 liters; 1 mile = 1.6 kilometers)  Select the correct option
A) 52	B) 65	C) 78	D) 91	E) 104

Solution: Fuel used 3.9 gallons ;convert to liters--> 3.9 x 3.8 liters   Time = 5.7 hours   1 mile = 1.6 kilometers ;convert to miles--> 1km = 1/1.6 mile   Speed (km/hour)  --  1= 
  --  1 = 1
1/1.6 mile   Speed (km/hour)= 91/T = 56(km*) x 3.9 x 3.8 / 5.7   replace (km*) to miles ; multiply by 1/1.6 mile   Speed (miles/hour)= 56 x 3.9 x 3.8 / 5.7 x 1.6 = 78 miles/hour   Ans :91   PS :i felt the factors were easy to cancel out ,so didn't require much rounding off   = 56 x 3.9 x 3.8 / 5.7 x 1.6   = 91   91
Answer: D
Which of the following integers has the most number of divisors? Answers.
A) 176	B) 180	C) 190	D) 200	E) 215

Solution: 99 = 1*3*3*11= 
1*3*3*11 = 99
> divisors of 99 are 1,3,11,9,33 and 99   101= 1*101   divisors 182 are 1,2,7,13,14,26,91 and 182   176=is most no of divisors   176NSWER 176
Answer: A
A cube of side one meter length is cut into small cubes of side 5 cm each. How many such small cubes can be obtained?	Choose the correct choice from the following answers:	A) 2878	B) 8000	C) 1000	D) 2997	E) 2701

Solution: Along one edge, the number of small cubes that can be cut   = 100/5= 
100/5 = 20
20   Along each edge 5 cubes can be cut. (Along length, breadth and height). Total number of small cubes that can be cut= 20 * 20 * 20= 
20 * 20 * 20 = 8_000
8000   Answer: 8000
Answer: B
Local kennel has cats and dogs in the ratio of 6:8. If there are 10 fewer cats than dogs, how many dogs are in the kennel?	Options:	A) 30	B) 35	C) 45	D) 50	E) 40

Solution: Lets work with the data given to us. We know that there ratio of cats to dogs is 6:8 or   cats 6   dogs 8   we can write number of cats as 6x and number of dogs as 8x and we know that 8x-6x= 10(therefore 2x = 10 => x=5)   Then # of dogs = 8x5= 40   Answer is 40
Answer: E
Out of 10 persons working on a project, 4 are graduates. If 3 are selected, what is the probability that there is at least one graduate among them? Choose the correct choice:
A) 5/5  B) 5/9  C) 5/1  D) 5/6  E) 5/2

Solution: P(at least one graduate) = 1 - P(no graduates)   = 1 - 6C1/10C3   = 1 - (6 * 5 * 4)/(10 * 9 * 8)   = 5/6   Answer:5/6
Answer: D
A security guard at a certain store is instructed to check the receipt of one out of every five customers as they are leaving the store. If, on the guard's shift, 13 customers leave the store, how many different samples of customers could have been selected to have their receipts checked?
Pick one
A) 20 B) 78 C) 59 D) 90 E) 100

Solution: to choose the sample of 2 customers from 13. it can be done 13C2 possible ways.   So the answer is B. 78
Answer: B
a = 5^15 - 625^3 and a/x is an integer, where x is a positive integer greater than 1, such that it does NOT have a factor p such that 1 < p < x, then how many different values for x are possible?
Choose the correct choice:  A) None  B) One  C) Two  D) Three  E) Four

Solution: a= 5^15 - 625^3 => 5^15 - (5^4)^3 => 5^15 - 5^12 = 5^12(5^3 - 1) = 5^12*124   124 = 31*4   a/x is integer   For condition of 2<p<x only 5 and 31 satisfies this   Hence answer is Two
Answer: C
A positive integer n is called a “good” number if n3 + 7n − 133 = m3 for
some positive integer m. What is the sum of all “good” numbers? Select:
A) 24 B) 25 C) 29 D) 30 E) 0

Solution: We consider the size of m relative to n. If m = n, then n is a good number if and only if   7n = 133. In this case, we get 19 is a good number. Now, suppose that m n + 1. Then   n3 + 7n − 133 = m3 (n + 1)3 = n3 + 3n2 + 3n + 1   so that 3n2 − 4n + 134 0. For positive integers n, it is easy to see that this is impossible. It   remains to consider m n − 1. For such m, we have   n3 + 7n − 133 = m3 (n − 1)3 = n3 − 3n2 + 3n − 1   which implies 3n2 + 4n − 132 0. It follows here that n 6. One checks that   63 + 7 · 6 − 133 = 53 and 53 + 7 · 5 − 133 = 33,   so 6 and 5 are good numbers. For n 4, we see that n3 +7n−133 < 0 and, hence, n3 +7n−133   cannot equalm3 for a positive integerm. Therefore, the sum of all good numbers is   19+6+5= 
  19+6+5 = 30
30.   correct answer 30
Answer: D
Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win ?  Choose the correct choice from the following choices.
A) £ 9	B) £ 11	C) £ 13	D) £ 15	E) None of the these

Solution: Explanation:   Let money with Ken = x. Then, money with Mac = x + £ 3.   Now, 3x = (x + x + £ 3) + £ 2 x = £ 5.   Therefore Total money with Mac and Ken = 2x + £ 3 = £ 13.   Answer: £ 13
Answer: C
What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 15 nor by 20?  Choose the correct choice:
A) 887  B) 678  C) 765  D) 345  E) 256

Solution: In 1000 consecutive numbers, number of multiples of 15 = 1000/15 = 66 (Ignore decimals)   In 1000 consecutive numbers, number of multiples of 20 = 1000/20= 
1000/20 = 50
50   Number of multiples of 15*20 i.e. 300= 1000/300 = 3   Number of integers from 1 to 1000 that are divisible by neither 15 nor by 20 = 1000 - (66 + 50 - 3) {Using the concept of sets here) = 887   887nswer is 887
Answer: A
Four-ninths of a drink mix is dye and the rest is sugar. When the mix is added to water a gallon of drink is made that is 8% sugar. What percentage of the gallon is dye? Choose the most appropriate option.
A) 6 B) 6.4 C) 7.5 D) 8 E) 24

Solution: The proportion of Dye and sugar will remain constant.   Dye/Sugar = (4/9)/(5/9) = x/8   => 4/5 = x/8 => x = 4*8/5= 
4*8/5 = 32/5 = around 6.4
6.4   Answer is 6.4
Answer: B
Little John had $10.10. He spent $3.25 on sweets and gave to his two friends $2.20 each. How much money was left?
Choose the correct option:
A) $2.45
B) $2.54
C) $2.35
D) $2.48
E) $2.49

Solution: John spent and gave to his two friends a total of   3.25 + 2.20 + 2.20= 
3.25 + 2.20 + 2.20 = 7.65
$7.65   Money left    10.10 - 7.65= 
 10.10 - 7.65 = 2.45
$2.45   $2.45nswer :$2.45
Answer: A
What is the probability of randomly selecting one of the shortest diagonals from all the diagonals of a regular 9-sided polygon)?
Answers
A) 1/2
B) 1/3
C) 1/4
D) 1/6
E) 1/9

Solution: From any vertex, there are two vertices on sides, which do not make a diagonal but a side.   So the remaining n-3 vertices make diagonals.   There are 2 of these diagonals which are the shortest.   The probability of choosing one of the shortest diagonals is 2/6 = 1/3.   The answer is 1/3.
Answer: B
A man invests some money partly in 12% stock at 105 and partly in 8% stock at 88. To obtain equal dividends from both, he must invest the money in the ratio.	Answers.
A) 35:44 B) 34:44 C) 22:44 D) 20:40 E) 50:45

Solution: In case of stock1, if he invest Rs.105, he will get a dividend of Rs.12 (assume face value = 100)   In case of stock2, if he invest Rs.88, he will get a dividend of Rs.8 (assume face value = 100)   ie, if he invest Rs.(88*12)/8, he will get a dividend of Rs.12   Required ratio = 105 : (88 × 12)/8 = 105 : (11 × 12) = 35 : (11 × 4) = 35 : 44   35:44nswer is 35:44.
Answer: A
A car dealership has 40 cars on the lot, 15% of which are silver. If the dealership receives a new shipment of 80 cars, 45% of which are not silver, what percentage of total number of cars are silver?  Choose the correct choice from the following.
A) 30% B) 35% C) 40% D) 45% E) 50%

Solution: The number of silver cars is 0.15*40 + 0.45*80= 
0.15*40 + 0.45*80 = 42
42   The percentage of cars which are silver is 42/120= 35%   The answer is 35%.
Answer: B
In an exam, Amar scored 64 percent, Bhavan scored 36 percent and Chetan 44 percent. The maximum score awarded in the exam is 800. Find the average mark scored by all the three boys?
Choose the correct answer: A) 384 B) 288 C) 277 D) 299 E) 212

Solution: 384verage mark scored by all the three boys   = [64/100 (800) + 36/100 (800) + 44/100 (800)] / 3   = 384   384nswer: 384
Answer: A
A set of numbers has the property that for any number t in the set, t + 5 is in the set. If -1 is in the set, which of the following must also be in the set?
I. -3
II. 4
III. 5	Pick
A) I only  B) II only  C) I and II only  D) II and III only  E) I, II, and III

Solution: The question is which of the followingmustbe in the set, notcouldbe in the set.   If -1 is in the set so must be   -1+5= 
  -1+5 = 4
4, as 4 is in the set so must be   4+5= 
  4+5 = 9
9, as 9 is in the set so must be   9+5= 
  9+5 = 14
14 and so on.   Answer: II only.
Answer: B
A scooter costs 30,000 when it is brand new. At the end of each year, its value is only 80% of what it was at the beginning of the year. What is the value of the scooter at the end of 3 years?	Choose the correct choice from the following options: A) 10,000 B) 12,500 C) 12,800 D) 12,000 E) 15,360

Solution: After first year, the value of the scooter = 24,000   After second year, the value of scooter = 19,200   After third year, the value of scooter = 15,360   Answer 15,360
Answer: E
When 2 is added to half of one-third of one-fifth of a number, the result is one-fifteenth of the number. Find the number?  Choose the correct option: A) 40 B) 65 C) 73 D) 60 E) 80

Solution: 60   60   Let the number be   2 + 1/2[1/3(a/5)] = a/15   => 2 = a/30 => a = 60
Answer: D
Martin buys a pencil and a notebook for 80 cents. At the same store, Gloria buys a notebook and an eraser for 95 cents, and Zachary buys a pencil and an eraser for 55 cents. How many cents would it cost to buy three pencils, three notebooks, and three erasers? (Assume that there is no volume discount.) Choose one.
A) 305
B) 325
C) 345
D) 365
E) 385

Solution: pencil + notebook = 80   notebook + eraser = 95   pencil + eraser = 55   Let's add all three equations.   2 pencils + 2 notebooks + 2 erasers = 230 cents   The cost to buy 3 of each would be (3/2)(230) = 345   The answer is 345.
Answer: C