MU-NLPC/Calc-aqua_rat huggingface dataset:
One-fourth of the boys and three-eighth of the girls in a school participated in the sports. What fractional part of the total student population of the school participated in the annual sports ?	Choices
A) 4/12
B) 5/8
C) 8/12
D) Data inadequate
E) None of these

Solution: Explanation:   Boys and girls ratio was not given.   Correct Option:Data inadequate
Answer: D
A room 13 m 47 cm long and 7m 77 cm broad is to be paved with square tiles. Find the least number of square tiles required to cover the floor.	Choose the correct choice from the following options.
A) 116636  B) 116406  C) 116647  D) 116291  E) 116675

Solution: Explanation:   Area of the room = (1347 x 777) cm2.   Size of largest square tile = H.C.F. of 1347 cm and 777 cm = 3 cm.   Area of 1 tile = (3 x 3) cm2.   Number of tiles required =(1347×777)/(3×3)=116291   Answer: Option 116291
Answer: D
A man has Rs. 240 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ? Select:	A) 45	B) 60	C) 75	D) 90	E) 45

Solution: Let number of notes of each denomination be x.   Then x + 5x + 10x = 240   16x = 240   x = 15.   Hence, total number of notes = 3x = 45.   Answer: Option 45
Answer: E
For the symbol, m”n=n^2−m for all values of m and n. What is the value of 4”3? Select
A) 5	B) 3	C) 2	D) 1	E) 0

Solution: 4”3= 9 - 4= 
9 - 4 = 5
5   5nswer: 5
Answer: A
The ratio of pens to pencils is 5 to 6. There are 8 more pencils than pens. How many pencils are there? Choose the correct choice from the following options:
A) 30 B) 32 C) 48 D) 55 E) 64

Solution: Let x equal the number of pens, and y the number of pencils.   Then, x = 5/6y.   We also know that x = y - 8. And so, we can substitute:   y - 8 = 5/6y   So to isolate y, we get:   1/6y = 8   And therefore:   y = 48   Answer: 48
Answer: C
Find √? /15= 4 ?  Select the correct option.
A) 76 B) 5776 C) 304 D) 3600 E) None

Solution: Answer   Let √N/15= 4   Then √N = 15 x 4 = 60   ∴ N = 60 x 60 = 3600.   Correct Option: 3600
Answer: D
We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 10, and the difference between the total number of strawberries and the total number of blueberries would increase by 50. Each blue box contains how many blueberries? Choose the most appropriate option:
A) 10  B) 15  C) 20  D) 25  E) 30

Solution: Let x be the number of blueberries in each blue box.   Then there are x+10 strawberries in each red box.   x+(x+10)=50   x = 20   The answer is 20.
Answer: C
Murali travelled from city A to city B at a speed of 40 kmph and from city B to city C at 60 kmph. What is the average speed of Murali from A to C given that the ratio of distances between A to B and B to C is 2 : 7?
A. 48 kmph	Select
A) 33	B) 54	C) 28	D) 27	E) 16

Solution: Let the distances between city A to B and B to C be 2x km and 7x km respectively.   Total time taken to cover from A to C   = (2x)/40 + (7x)/60 = (6x + 14x)/120 = 20x/120 = x/6 Average speed = (2x + 7x)/(x/6) = 54 kmph.   Answer: 54
Answer: B
A man can row with a speed of 25 kmph in still water. If the stream flows at 5 kmph, then the speed in downstream is?  Pick one:
A) A)25
B) B)28
C) C)20
D) D)21
E) E)30

Solution: M = 25   S = 5   DS = 25 + 5= 
25 + 5 = 30
30   Answer:30
Answer: E
In Cliff’s impressive rock collection, there are half as many igneous rocks as sedimentary rocks. Of the igneous rocks, 3/5 are shiny and the rest are matte, while 1/5 of the sedimentary rocks are shiny. If there are 30 shiny igneous rocks, how many total rocks does Cliff have? Choices
A) 30  B) 45  C) 60  D) 150  E) 135

Solution: We can start with the known quantity and then go on to find the others.   Shiny igneous ricks are 30. These are (3/5) of total igneous rocks.   (3/5)*Total igneous rocks = 30   Total igneous rocks = 30 * (5/3)= 
30 * (5/3) = 50
50   Total sedimentary rocks= 2*Total igneous rocks = 2*50= 
2*50 = 100
100   Total number of rocks= 50 + 100= 
50 + 100 = 150
150   Answer (150)
Answer: D
A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18000. A's share is?  Choose the correct choice:
A) 8876
B) 2765
C) 6000
D) 1298
E) 1261

Solution: x* 12 : 2x* 6: 3x* 4   1:1:1   1/3 * 18000= 
1/3 * 18000 = 6_000
6000   Answer:6000
Answer: C
If air is called green , green is called blue, blue is called tangerine, sky is called yellow, yellow is called water and water is called pink, then what is the color of clear sky ?	Pick.
A) Blue	B) Sky	C) Water	D) Tangerine	E) Black

Solution: Explanation:The colour of clear sky is 'blue' and as given, 'blue' is called 'tangerine'.So, the colour of clear sky is 'tangerine'.Answer: Tangerine
Answer: D
A store raised the price of an item by exactly 15 percent. Which of the following could NOT be the resulting price of the item?
Choose the correct option:
A) 115
B) 230
C) 345
D) 460
E) 300

Solution: If it raised the value by 15% then the resulting price is 1.15 times the original price. So the final answer has to be a multiple of 1.15. Check the answers.   115 - Yes   230 - Yes   345 - Yes   460 - Yes   300 - No   Answer : 300
Answer: E
Donovan took a math test and got 35 correct and 13 incorrect answers.
What was the percentage of correct answers? (Round to the nearest
hundredth) Pick one
A) 57.78%  B) 67.78%  C) 72.92%  D) 47.78%  E) 97.78%

Solution: 35 correct our of 48 total (35+13)   35/48   correct answer 72.92%
Answer: C
What is the two-digit number?
I.
The difference between the two-digit number and the number formed by interchanging the digits is 27.
II.
The difference between the two digits is 3.
III.
The digit at unit's place is less than that at ten's place by 3. Pick one:
A) I and II
B) II and III
C) All
D) I and either II or III
E) Even with all I, II and III, answer cannot be give.

Solution: Let the tens and units digit be x and y respectively.   I. (10x + y) - (10y + x) x - y = 3.   II. x - y = 3.   III. x - y = 3.   Thus, even all the given three statements together do not give the answer.   Correct answer is (Even with all I, II and III, answer cannot be give.).
Answer: E
The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?  Pick one: A) 11 B) 18 C) 92 D) 27 E) 28

Solution: Explanation:   => 2l + 2b = 5b   => 3b = 2l   b=(2/3)l   Then, Area = 216 cm2   => l x b = 216   => l x (2/3)l =216   => l2 = 324   l = 18 cm.   Answer: 18) 18
Answer: B
14. The sum and the product of two numbers are 25 and 144 respectively, the difference of the number is? Choose the correct choice from the following answers.
A) 7  B) 9  C) 8  D) 5  E) 4

Solution: x + y = 25   xy = 144   (x- y)2 = (x + y)2 â€“ 4xy   (x- y)2 = 625 â€“ 576 => (x â€“ y) = 7   7NSWER: 7
Answer: A
How long will it take a train travelling at 98kmph to pass an electric pole if the train is 140 m long Choose one
A) 6.15  B) 5.15  C) 3.15  D) 1.15  E) 7.15

Solution: Sol.   Speed = [ 98x5/18] m/sec =27.2 m / sec.   Time taken = (140/27.2)sec =5.15 sec.   Answer 5.15
Answer: B
A third of Arun’s marks in mathematics exceeds a half of his marks in English by 80.if he got 240 marks In two subjects together how many marks did he got in English?
Choose the correct choice
A) 180,60	B) 150,80	C) 140,70	D) 120,90	E) None of them

Solution: Let 180,60run’s marks in mathematics and english be x and y   Then 1/3x-1/2y=30   2x-3y=180……>(1)   x+y=240…….>(2)   solving (1) and (2)   x=180   and y=60   180,60nswer is 180,60.
Answer: A
15 men work 8 hours per day to complete the work in 10 days. To complete the same work in 8 days, working 15 hours a day, the number of men required?	Pick:	A) 10days	B) 11days	C) 9days	D) 8days	E) 12days

Solution: That is, 1 work done = 15 × 8 × 10   Then, 12 8 × 10 = ? × 15 × 8   ? (i.e. No. of men required) = 15 × 8 × 10/15× 8 = 10 days   10days)
Answer: A
If x, y, and z are positive integers and 3x = 2y = 4z, then the least possible value of x + y + z is	Select
A) 15
B) 25
C) 30
D) 42
E) 13

Solution: given 3x=2y=4z   x+y+z in terms of x   = x+(3x/2)+(3x/4) = 26x/8=13x/4   now checking with each of the answers and see which value gives a minimum integer value.   A x = 4/13*15 , not an integer   B,C,E can be ruled out similarly.   D is minimum value as x = 13*4/13= 
13*4/13 = 4
4   Answer is 13
Answer: E
How many integers between 4000 and 5000 that have distinct digits and increase from left to right ?	Select the correct option:
A) 10  B) 48  C) 60  D) 20  E) 600

Solution: Since the numbers must be distinct and increasing from left to right,   The only arrangements we could come-up with are:   445_ --> 4   446_ --> 3   447_ --> 2   448_ --> 1   456_ --> 3   457_ --> 2   458_ --> 1   467_ --> 2   468_ --> 1   478_ --> 1   Number of integers =20   20
Answer: D
A certain rectangular window is two times as long as it is wide. If its perimeter is 30 feet, what are its dimensions in terms of length by width? Choose the correct choice from the following answers:
A) 12 by 2  B) 11 by 3  C) 10.5 by 3.5  D) 10 by 5  E) 9 by 3

Solution: 2x+2y=30   x+y=15   x+2x=15   3x=15   x=5   Answer 10 by 5
Answer: D
4 gentlemen and 3 gentlewomen are candidates for 2vacancies. A voter has to vote for 2 candidates. In how many ways can one cast his vote?  Choices
A) 11  B) 12  C) 15  D) 16  E) 21

Solution: There are 7 candidates and a voter has to vote for any two of them.   So, the required number of ways is,   = 7C2 = 21.   21
Answer: E
125 students of a school are about embarking on a trip. What is the least number of vans needed to convey them given that each van will only take 10 students each?	Choose the correct choice from the following choices.
A) 12
B) 11
C) 13
D) 18
E) 10

Solution: To find the number of vans, we divide 125 by 10.   125/10 = 12 and remainder = 5   So 10 vans are needed to transport 125 students, and 1 van is needed to transport the 5 remaining students. A total of 11 vans are needed.   correct answer 11
Answer: B
Convert 0.36 in to a vulgar fraction ? Choose the correct choice from the following choices.
A) 18/50  B) 16/50  C) 17/50  D) 9/25  E) None

Solution: Answer   0.36 = 36/100 = 9/25   Correct Option: 9/25
Answer: D
A farm has only chickens and pigs. When the manager of the farm counted the heads of the animals on the farm, the number totaled up to 60. When the number of legs was counted, the number totaled up to 160. How many more chickens than pigs are there on the farm? Note: Each pig has 4 legs and each chicken had 2 legs. Select
A) 16	B) 20	C) 24	D) 28	E) 32

Solution: Let x be the number of chickens.   Then 60-x is the number of pigs.   2x+4(60-x)=160   2x=80   x=40 (chickens)   60-x=20 (pigs)   There are  40-20= 
 40-20 = 20
20 more chickens on the farm.   The answer is 20.
Answer: B
If the sides of a triangle are 26 cm, 25 cm and 10 cm, what is its area?	Select:
A) 120 B) 110 C) 130 D) 140 E) 125

Solution: The triangle with sides 26 cm, 25 cm and 10 cm is right angled, where the hypotenuse is 26 cm.   Area of the triangle = 1/2 * 25 * 10= 
1/2 * 25 * 10 = 125
125 cm2   Answer: Option 125
Answer: E
A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 30 times, A has killed:
Pick
A) 60 birds	B) 72 birds	C) 33 birds	D) 80 birds	E) 20 birds

Solution: Let the total number of shots be x. Then,   Shots fired by A =(5/8)x   Shots fired by B =(3/8)x   Killing shots by A =(1/3)of	(5/8)x=(5/24)x   Shots missed by B =(1/2) of (3/8)x	=(3/16)x   3x/16= 30 or x =(30 x 16)/3= 160.   Birds killed by A =(5x/24)	=(5/24*160)= 33.   Answer is 33 birds.
Answer: C
Each of four different locks has a matching key. The keys are randomly reassigned to the locks. What is the probability that exactly two of the keys fit the locks to which they are reassigned?
Choose the correct choice from the following answers:	A) 1/8	B) 1/6	C) 1/4	D) 3/8	E) 1/2

Solution: Total # of ways to assign the keys to the locks is 4!4!.   C^24 to choose which 2 keys will fit. Other 2 keys can be arranged only one way.   So P=1/4^24/4!=14   Answer: 1/4.
Answer: C
If the 1st of the month occurs on a Thursday, on which day of the week does the 20th occur?  Choose the most appropriate option.
A) Wednesday	B) Saturday	C) Tuesday	D) Thursday	E) Sunday

Solution: Each weekday is repeated every 7 days. The 20th of the month is 19 days after the 1st. 19 divided by 7 is 2, with a remainder of 5. Therefore, the 20th occurs on whichever day of the week is five days after the day we started on, meaning the 20th is a Tuesday. Answer: Tuesday
Answer: C
The difference of two numbers is 1340. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ?  Choose the correct choice from the following choices.
A) A)265  B) B)280  C) C)290  D) D)300  E) E)310

Solution: Let the smaller number be x. Then larger number = (x + 1340).   x + 1340 = 6x + 15   5x = 1325   x = 265   Smaller number = 265.   265)
Answer: A
How many five digit numbers can be formed using digits 0,1,2,3,4,5, Which are divisible by 3, whithout any of the digits repeating?	Choose the correct answer.
A) 15 B) 96 C) 120 D) 181 E) 216

Solution: First step:   We should determine which 5 digits from given 6, would form the 5 digit number divisible by 3.   We have six digits: 0,1,2,3,4,5. Their sum=15.   For a number to be divisible by 3 the sum of the digits must be divisible by 3. As the sum of the six given numbers is 15 (divisible by 3) only 5 digits good to form our 5 digit number would be 15-0={1, 2, 3, 4, 5} and 15-3={0, 1, 2, 4, 5}. Meaning that no other 5 from given six will total the number divisible by 3.   Second step:   We have two set of numbers:   {1, 2, 3, 4, 5} and {0, 1, 2, 4, 5}. How many 5 digit numbers can be formed using this two sets:   {1, 2, 3, 4, 5} --> 5! as any combination of these digits would give us 5 digit number divisible by 3. 5!=120.   {0, 1, 2, 4, 5} --> here we can not use 0 as the first digit, otherwise number won't be any more 5 digit and become 4 digit. So, total combinations 5!, minus combinations with 0 as the first digit (combination of 4) 4! --> 5!-4!=96   120+96= 
120+96 = 216
216   Answer: 216.
Answer: E
What is the sum of all 3 digit positive integers that can be formed using the digits 1, 5, and 8, if the digits are allowed to repeat within a number Q? Choose one:
A) 126
B) 1386
C) 3108
D) 308
E) 13986

Solution: As we are using digits 1,5, 8 and digits are allowed to repeat. Each of the unit, tenth and hundredth digit can be used by each of three digits.   So,Total possible numbers with these digits=3 X 3 X 3 =27.   First, As we have 27 three digit number, Sum will be for sure more than 2700..Eliminate options A,B,D   Second, If you imagine numbers Q with the given digits 1,5,8. We have numbers like 888,885,855,858,851. Sum is for sure more than 4000.Eliminate option C.   You are left withanswer 13986.
Answer: E
A is twice as good workman as B, and together they complete a work in 5 days. In how many days can the work be complete by B alone?  Select the correct option:
A) 35 days
B) 65 days
C) 45 days
D) 75 days
E) 15 days

Solution: B=3A   15 days   15 days
Answer: E
A FIVE DIGIT NUMBER IS FORMED BY USING THE DIGITS 1,2,3,4 WITH OUT REPETITIONS . WHAT IS THE PROBABILITY THE NUMBER IS DIVISIBLE BY2?	Choose the correct answer
A) 1/4	B) 5/6	C) 4/5	D) 7/3	E) 2/7

Solution: If a number is divisible by 2 the last 2 digits of the number has to be divisible by 2   If the number ends with 12: Number of possibilities = 3 * 2 * 1= 
3 * 2 * 1 = 6
6   number ends with 14: Possibilities= 6   number ends with 32: Possibilities = 6   number ends with 34: Possibilities = 6   number ends with 24: Possibilities = 6   Total number of possibilities with restriction = 6 *5= 
6 *5 = 30
30   Total number of possibilities without restriction= 5! = 120   Probability = 30/120 = 1/4   1/4nswer: 1/4
Answer: A
Two numbers are in the ratio of 15:11. If their H.C.F. is 13, find the numbers. Choose the correct choice from the following
A) 195,143	B) 185,133	C) 175,123	D) 165,113	E) None of them

Solution: Let the required numbers be 15.x and llx.   Then, their H.C.F. is x. So, x = 13.   The numbers are (15 x 13 and 11 x 13) i.e., 195 and 143.   195,143nswer is 195,143.
Answer: A
You enter a weight loss challenge game and manage to lose 15% of your body weight. For the final weigh in you are forced to wear clothes that add 2% to your weight. What percentage of weight loss is measured at the final weigh in?	Choose the correct choice from the following choices
A) 13.3%
B) 9.22%
C) 9%
D) 14%
E) 12%

Solution: (100%-15%)*(100%+2%) = 0.85*1.02 = 13.3%   The weigh in records your weight loss at 13.3%!   The 13.3%nswer is 13.3%
Answer: A
Score Interval Number of Scores
50-59 2
60-69 10
70-79 15
80-89 27
90-99 18
The table shows a distribution of test scores. Which score interval contains the median of the 72 scores?
Options:
A) a) 60-69
B) b) 70-79
C) c) 80-89
D) d) 90-99
E) e) Cannot determine.

Solution: 36th person   80-89 c) 80-89
Answer: C
A box contains2 blue marbles, 4 red marble, 3 green marbles and 2 yellow marbles. If two marbles are picked at random, what is the probability that they are either green or yellow? Choose the correct choice from the following answers
A) 5/11 B) 4/11 C) 3/11 D) 2/11 E) 1/11

Solution: Given that there are 2 blue marbles, 4 red marbles, 3 green marbles and 2 yellow marbles. Probability that both marbles are green = 3Câ‚‚/11Câ‚‚ = 3/55   Probability that both are yellow = Â²Câ‚‚/11Câ‚‚ = 1/55   Probability that one green and other is yellow = (3Câ‚ * Â²Câ‚)/11Câ‚‚ = 6/55   Required probability = 3/55 + 1/55 + 6/55   = 10/55=2/11   Answer:2/11
Answer: D
Let C represent a set of four distinct prime numbers. If the sum of the numbers in C is even and x is a member of C, then what is the least possible value that x can be? Choices: A) 1 B) 2 C) 3 D) 5 E) 7

Solution: We are told that C is a set of four distinct prime numbers, and the sum of the numbers in C is even. Since the question involves odds, evens and the smallest possible prime, you should immediately think of 2, the smallest prime number and the only even prime number.   If 2 were a member of the set, then we would have one even number and three odd numbers. Since such sum would always be odd, 2 cannot be a member of the set. Thus, all the members of C must be odd to yield an even sum.   Since all the members of the set must be odd prime numbers, the answer is the smallest odd prime number, which is 3.   The correct answer is choice (C).   Note:1 is not a prime number.
Answer: C
The total age of A & B is 12 years more than the total age of B & C. C is how many year younger than A.  Choose the correct choice from the following choices:
A) C is 12 years younger than A
B) C is 12 years younger than B
C) C is 12 years younger than C
D) C is 12 years younger than D
E) B is 12 years younger than A

Solution: Explanation:   From the given data A+B = 12+(B+C) A+B-(B+C) = 12 A-C=12 years. C is 12 years younger than C is 12 years younger than A   C is 12 years younger than Answer: C is 12 years younger than A
Answer: A
New age consultants have three consultants Gyani, Medha, and Buddhi. The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved. All three consultants are involved together in 6 projects. Gyani works with Medha in 14 projects. Buddhi has 2 projects with with Medha but without Gyani and 3 projects with Gyani but without Medha.
The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.
What is the number of projects in which Medha alone is involved?	Answers
A) Uniquely equal to zero B) Uniquely equal to 1 C) Uniquely equal to 4 D) Cannot be determined uniquely E) None of these

Solution: Explanation :   It is given that all the three consultants are involved in 6 projects together. So put 6 where all the three circles intersect.   Buddhi has 2 projects with Medha but without Gyani. i.e., Medha and Buddhi alone worked in 2 projects.   Also given, Buddi worked on 3 projects with Gyani but without Medha. i.e., Buddi and Gyani alone worked on 3 projects.   Gyani worked with Medha in 14 projects. These two worked together along with Buddhi in 6 projects. So Gyani and Medha alone worked on 14 - 6= 
14 - 6 = 8
8 Projects.   Lets us assume, Gyani, Buddhi and Medha alone worked on a, b, c projects.   It was given that The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved.=> a + b = 8 + 6 + 2 + c   => a + b = 16 + c ------------------ (1)   Also given The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.   The projects in which more than 1 consultant involved = 6 + 3 + 2 + 8= 
6 + 3 + 2 + 8 = 19
19.   Total projects= a + b + c + 8 + 3 + 2 + 6 = a + b + c + 19   => 2 × 19 - 1 = a + b + c + 19.   => a + b + c = 18.   => a + b = 18 - c.   Substituting this value in equation (1) we get,   => 18 - c = 16 + c.   => c = 1.   Answer : Uniquely equal to 1
Answer: B
If there are 5 pairs of twins, and a committee will be formed with 3 members. In how many ways this committee formed in a way that no siblings in a group? Choose the most appropriate option.
A) 32
B) 24
C) 56
D) 44
E) 80

Solution: Firstly, there are 5 ways to choose 3 groups from the 4 groups. Hence 5C3.   Next, with the 3 groups chosen, there are 2^3 choices of choosing either one of the siblings.   Hence, the total number of ways are 5C3 * (2^3) = 80   80
Answer: E
The average expenditure of a man for the first five months is Rs.180 and for the next seven months it is Rs.130. If he saves Rs.290 in that year, his monthly average income is :  Options.
A) Rs.140
B) Rs.150
C) Rs.160
D) Rs.175
E) none

Solution: Explanation:   Total income = Rs.(180Ã—5+130Ã—7+290)=Rs.2100   Average monthly income   = Rs. (2100/12)=Rs.175   Correct Option: Rs.175
Answer: D
A train 240 m long passed a pole in 24 seconds. How long will it take to pass a platform 650 m long?  Choose the correct choice from the following:	A) 65 sec	B) 89 sec	C) 100 sec	D) 150 sec	E) None

Solution: Sol.   Speed = [240/24] m/sec = 10 m/sec.   ∴ Required time = [240 + 650 / 10] sec   = 89 sec.   Answer 89 sec
Answer: B
A girl goes to her school from her house at a speed of 6km/hr and returns at a speed of 4 km/hr. If she takes 10 hours in going and coming back, the distance between her school and house is  Choose the correct choice:
A) 12 kms
B) 16 kms
C) 20 kms
D) 24 kms
E) None of above

Solution: Let distance be 24 kms10 = 24 kms/4 + 24 kms/6 Answer : 24 kms
Answer: D
The bankerâ€™s discount on Rs. 1600 at 5% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is : Select the correct option
A) 2 months B) 4 months C) 6 months D) 12 months E) None

Solution: Sol.   S.I. on Rs. 1600 = R.D. on Rs. 1680.   âˆ´ Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is S.I. on Rs. 1600 at 15%.   âˆ´ Time = [100 * 80 / 1600 * 5] year = 1year = 12 months.   Answer 12 months
Answer: D
If a 36 inches long strip cloth shrinks to 33 inches after being washed, how many inches long will the same strip remain after washing if it were 48 inches long?	Choose the correct choice from the following answers:
A) 47 inches  B) 44 inches  C) 45 inches  D) 46 inches  E) None

Solution: Solution: Shrinking of cloth,   = [(36-33)/36]*100.   = 100/12%   Second time the strip shrinks,   = (48*100)/1200= 
(48*100)/1200 = 4
4 inches   hence , the cloth remains= 48-4= 
48-4 = 44
44.   Answer: Option 44 inches
Answer: B