MU-NLPC/Calc-aqua_rat huggingface dataset:
When positive integer x is divided by positive integer y, the result is 59.32. What is the sum R of all possible 2-digit remainders for x/y? Choices.
A) 560  B) 616  C) 672  D) 728  E) 784

Solution: ans B 616...   remainders = .32=32/100=8/25=16/50 and so on..   so two digit remainders are 16+24+32+....+96..   R=8(2+3+4....+12)=616.616
Answer: B
An amount of money was lent for 3 years. What will be the difference between the simple and the compound interest earned on it at the same rate?
I.	The rate of interest was 8 p.c.p.a.
II.	The total amount of simple interest was Rs. 1200. Answers:
A) I alone sufficient while II alone not sufficient to answer B) II alone sufficient while I alone not sufficient to answer C) Either I or II alone sufficient to answer D) Both I and II are not sufficient to answer E) Both I and II are necessary to answer

Solution: EXPLANATION   Given: T = 3 years.   I. gives: R = 8% p.a.   II. gives: S.I. = Rs. 1200.   Thus, P = Rs. 5000, R = 8% p.a. and T = 3 years.   Difference between C.I. and S.I. may be obtained.   answer is (Both I and II are necessary to answer).
Answer: E
When positive integer v is multiplied by positive integer n, the units digit of the product is 3. Which of the following are factors of n?
I. 8
II. 15
III. 30	Choose the correct option
A) I only
B) II only
C) I and II only
D) II and III only
E) None of the above

Solution: ans E..   we can tell the ans w/o using examples..   the units digit of product v*n is 3..   this means v and n are odd positive integers..   therefore n cannot have an even factor so 8 and 30 are out..   n cannot have a factor ending in 5 because in that case the units digit has to be 5 or 0... so 15 is also out
Answer: E
A certain store sold pens for $0.35 each and pencils for $0.25 each. If a customer purchased both pens and pencils from the store for a total of $1.60, what total number of pens and pencils did the customer purchase?	Choose the correct choice from the following choices:
A) 6
B) 9
C) 10
D) 11
E) 12

Solution: Answer: Algebraically, the question looks like this: 2.5 = 0.35x + 0.25y. There are six possible numbers of pencils that fit that requirement:   1 pen: $0.35 and 5 pencils for $0.25 each. That's 1 pens and 5 pencils for a total of 6 pens and pencils. Choice (6) is correct.
Answer: A
In the formula A = 22/7*b^2, if b is halved, then A is multiplied by	Choices.
A) 4  B) 1/8  C) 1/4  D) 8  E) 1/2

Solution: Say b=2 => A1 = 88/7   when r=1; A2 = 22/7   A2 = 1/4*A1.   Answer : 1/4
Answer: C
From a pack of 52 cards, one card is drawn at random. Find the probability that the drawn card is a club or a jack? Pick one
A) 17/52
B) 8/13
C) 4/13
D) 1/13
E) 2/13

Solution: Solution:   n(S) = 52   n(E) = 16   P(E) = n(E) / n(S) = 16/ 52   = 4/13   ANSWER IS 4/13
Answer: C
If the price of an article went up by 40%, then by what percent should it be brought down to bring it back to its original price?
Choose one.
A) 16 2/3%  B) 16 4/3%  C) 16 7/3%  D) 16 6/3%  E) 28 4/7%

Solution: Let the price of the article be Rs. 100.   40% of 100 = 40.   New price   = 100 + 40 = Rs. 140   Required percentage   = (140 - 100)/140 * 100   = 40/140 * 100   = 200/7   = 28 4/7%.   Answer:28 4/7%
Answer: E
Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 10 such machines produce in 4 minutes ?  Choose the correct choice from the following options.
A) 648 B) 1800 C) 2700 D) 10800 E) None of these

Solution: Solution   Let the required number of bottles be x.   More machines,More bottles (Direct Proportion)   More minutes,More bottles (Direct Proportion)   ∴ 6 × 1 × x = 10 × 4 × 270 ⇔ x = 10x4x270/6= 1800 . Answer 1800
Answer: B
The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 12 terms of the arithmetic progression?
Choose the correct choice from the following answers
A) 300 B) 120 C) 150 D) 170 E) 270

Solution: n th term of A.P. is given by a+(n-1)d   4 th term = a+3d   12 th term = a+11d   Given a+3d+a+11d=20 --> 2a+14d=20 --> a+7d = 10   Sum of n term of A.P = n/2[2a+(n-1)d]   subsitiuing n = 12 ...we get 12/2[ 2a + 14d] = 15 [a+7d] = 12*10 = 120...   Answer is 120...
Answer: B
In a practice paper at 2iim.com, questions were given from 5 topics. Out of the appearing students, 10% passed in all topics while 10% did not pass in any. Of the remaining, 20% passed in one topic only and 25% in two topics only. If 24% of the total students passed 4 topics only and 500 students passed in 3 topics only, find the total number of students who appeared in the examination?	Pick:
A) 2500	B) 2000	C) 1600	D) 4545	E) 6565

Solution: DETAILED SOLUTION   Let the number of appearing students be 100.   Pass only in 0 topic – 10   1 – 16 (20% of 80)   2 – 20 (25% of 80)   3 – 20% (100 – (16+20+24+20))   4 – 24%   5 – 20%   Therefore, 20% of x = 500 = ) x = 2500   Correct 2500nswer: 2500
Answer: A
In the junior basketball league there are 18 teams, 2/3 of them are bad and ½ are rich. What can't be the number of teams that are rich and bad? Select the correct option: A) 4. B) 6. C) 7. D) 8. E) 10

Solution: otal teams =18   bad teams=(2/3)*18= 
(2/3)*18 = 12
12   rich teams=9   so maximum value that the both rich and bad can take will be 9. so E= 10 can not be that value.   ANSW10R:10
Answer: E
A money lender lends Rs.2500 for six months at 20% p.a. rate. It the interest is reckoned quarterly than find the amount given after time limit?
Choose the correct choice:
A) 2205
B) 1978
C) 2834
D) 2827
E) 2756.25

Solution: A = 2500(21/20)2   = 2756.25   Answer: 2756.25
Answer: E
If a, b, c and g are non-zero integers, 3 ≥ c ≥ – 9 , 5 ≥ a ≥ –2 , 10 ≥b ≥ –1 , 4 ≥ g ≥ 1, then which of the following expresses the smallest possible value of ag/(bc)?	Select:
A) –90
B) –20
C) –10
D) 1/90
E) 15/4

Solution: ag have to be greatest from its range && bc to be smallest with -ve sign to became ag/bc smallest   A)-90 never possible case.(all nos. are integers and ag has max. 20 value)   B)-20 a=5,b=4 and b=1,c=-1 then it is possible   Option C,D,E are > -20....   Ans –20
Answer: B
The value of (4x10^7)(7x10^8) is closest to which of the following?  Pick.
A) 10^15  B) 10^12  C) 10^13  D) 10^14  E) 10^17

Solution: multiplying these we get,   28 x 10^7 x 10^8   = 2.8x 10^16   which is closer to 10^17   Answer: 10^17
Answer: E
The area of the floor of a room is 20 m2 that of a longer wall 15 m2 and of the shorter wall 12 m2, find the edge of the new cube?	Choose the correct choice from the following choices.
A) 450 m3 B) 100 m2 C) 60 m3 D) 400 m3 E) 500 m3

Solution: lb = 20 ; lh = 15 ; fh = 12   (lbh)2 = 20 * 15 * 12 => lbh = 60 m3   ANSWER:60 m3
Answer: C
Two men Amar and Bhuvan have the ratio of their monthly incomes as 6 : 5. The ratio of their monthly expenditures is 3 : 2. If Bhuvan saves one-fourth of his income, find the ratio of their monthly savings?	Choose the correct choice from the following answers.
A) 3 : 5	B) 3 : 10	C) 3 : 8	D) 1 : 2	E) 2:1

Solution: Let the monthly incomes of Amar and Bhuvan be 6x and 5x respectively.   Let the monthly expenditure of Amar and Bhuvan be 3y and 2y respectively.   Savings of Bhuvan every month = 1/4(5x)   = (His income) - (His expenditure) = 5x - 2y.   => 5x = 20x - 8y => y = 15x/8.   Ratio of savings of Amar and Bhuvan   = 6x - 3y : 1/4(5x) = 6x - 3(15x/8) : 5x/4 = 3x/8 : 5x/4   = 3 : 10.   ANSWER:3 : 10
Answer: B
Griffin has a bag of marbles that contains 6 black marbles and 6 red marbles. If he removes 3 marbles at random without replacing any of the marbles, what is the probability that all 3 marbles selected will be red?
Choose the correct answer:  A) 1/11  B) 2/33  C) 3/44  D) 4/55  E) 5/66

Solution: P(3 red marbles) = 6/12*5/11*4/10 = 1/11   The answer is 1/11.
Answer: A
A dishonest dealer professes to sell goods at the cost price but uses a false weight and gains 25%. Find his false weight age?
Pick:  A) 5 : 6  B) 3 : 4  C) 7 : 8  D) 8 : 9  E) None of these

Solution: 25 = E/(1000 - E) * 100   1000 - E = 4E   1000 = 5E => E = 200   ANSWER:7 : 8
Answer: C
In the class of 40 students, 30 speak Tamil and 20 speak Telugu. What is the lowest possible number of students who
speak both the languages?	Options:  A) 8  B) 10  C) 20  D) 30  E) 32

Solution: let the student who speaks hindi-x   let the student who speaks english-y   as (xuy)-(xny)=total   30+20-(xny)=40   =10   10)
Answer: B
24 oz of juice P and 25 oz of juice W are mixed to make smothies X and Y . The ratio of p to W in smothie X is 4 is to 1 and that in Y is 1is to 5.How many ounces of juice P are contained in the smothie X?	Select the correct option:	A) 5	B) 10	C) 15	D) 20	E) 25

Solution: Easy way to solve this question is start from the answer and then conform the information provided in the question.   we can start from option D i.e 20 ... as a quantity of juice P in X because it is the only one option that gets divided by 4 is 20 ... since in the X the juice P to W ratio is 4:1   this gives us that quantity of juice P in X = 20 therefore quantity of Juice W will be 5 ... hence ratio = 4:1   This will lead to quantity of juice P in X = 4 and quantity of Juice W = 20 ... hence ratio 1:5   if we calculate total Juice P = 24 and total of juice W = 25   it fits because totals are same as what mentioned in the question ...   thus ans is 20
Answer: D
The Carson family will purchase three used cars. There are two models of cars available, Model A and Model B, each of which is available in eight colors: blue, black, red, and green. How many different combinations of three cars can the Carsons select if all the cars are to be different colors?  Choose the correct answer:  A) 24  B) 32  C) 48  D) 60  E) 321

Solution: I have no idea how you got 8C8, 7C6 and 4C1.   I could have understood 8C1*6C1*4C1 (I have explained why this doesn't work in the post above)   The best way to solve it is by first selecting 3 colors out of the given 4 in 4C3 ways. (say, you got black, red and green)   Now for each color, you have 2 choices - model A or B   So you select a model in 2 ways.   No of ways of selecting the 3 cars = 6C3 * 2 * 2 * 2 = 321   Well, my logic was   The number of ways of selecting r objects from n different objects is nCr.   We have 8 options and can select either of the 8 as the first - 8C8   One car is gone and one becomes a forbidden choice so we have 7 options and need to select either of the 6 as the first - 7C6   Two cars are gone and two becomes a forbidden choice so we have 6 options and need to select either of the 4 as the first - 6C4   321
Answer: E
A bag contains an equal number of one rupee, 50 paise and 25 paise coins respectively. If the total value is 35, how many coins of each type are there?  Choose the correct choice from the following answers: A) 20 coins B) 30 coins C) 28 coins D) 25 coins E) None of these

Solution: Let number of each type of coin = x. Then,   1 × x + .50 × x + .25x = 35   ⇒ 1.75x = 35 ⇒ x = 20 coins   20 coinsnswer 20 coins
Answer: A
In the youth summer village there are 125 people, 50 of them are not working, 25 of them have families and 75 of them like to sing in the shower. What is the largest possible number of people in the village, which are working, that don't have families and that are singing in the shower?
Answers:  A) 75  B) 80  C) 85  D) 100  E) 90

Solution: total =125   not working =50   having family=25   like to sing in shower = 75   working=125-50= 
125-50 = 75
75   not having family= 125-25= 
125-25 = 100
100   like to sing in shower= 100   largest possible number is the lowest possible among the above   Thus 75   75
Answer: A
Average of five consecutive even numbers is 35. Find the greatest number in these five numbers?
Choose the correct choice from the following options:  A) 37  B) 38  C) 39  D) 41  E) 42

Solution: 39   Option '39'
Answer: C
The compound interest accrued on an amount of Rs.44000 at the end of two years is Rs.1193.60. What would be the simple interest accrued on the same amount at the same rate in the same period?  Answers:
A) Rs.10,840  B) Rs.10,720  C) Rs.10,560  D) Rs.10,280  E) None of these.

Solution: Let the rate of interest be R% p.a.   4400{[1 + R/100]2 - 1} = 11193.60   [1 + R/100]2 = (44000 + 11193.60)/44000   [1 + R/100]2 = 1 + 2544/1000 = 1 + 159/625   [1 + R/100]2 = 784/625 = (28/25)2   1 + R/100 = 28/25   R/100 = 3/25   Therefore R = 12 SI on Rs.44000 at 12% p.a. for two years = 44000(2)(12)/100   =Rs.10560   ANSWER:Rs.10,560
Answer: C
How many perfect squares are divisors of the product (1!)(2!)(3!)(4!)(5!)(6!)(7!)(8!)(9!)? Options:
A) 504 B) 672 C) 864 D) 936 E) 1008

Solution: N=(1!)(2!)(3!)(4!)(5!)(6!)(7!)(8!)(9!)   1!=1   2!=1*2   3!=1*2*3   4!=1*2*3*4   5!=1*2*3*4*5   6!=1*2*3*4*5*6   7!=1*2*3*4*5*6*7   8!=1*2*3*4*5*6*7*8   9!=1*2*3*4*5*6*7*8*9   N=(2^8)(3^7)(4^6)(5^5)(6^4)(7^3)(8^2)(9^1)   =(2^30)(3^13)(5^5)(7^3)   To find the number of perfect squares each exponent in the prime factorization must be even .   Comparing to the form (2^p)(3^q)(5^r)(7^s).   In this case,   p can take values from 0 to 30   q can take values from 0 to 13   r can take values from 0 to 5   s can take values from 0 to 3   Number of even exponents   p=16   q=7   r=3   s=2   Number of perfect squares= 16*7*3*2= 
16*7*3*2 = 672
672   Answer 672
Answer: B
In a dance competition the points in each round for the first,second,third and fourth position were 100,50,20,10 . No other points were given. Ashita participated in several rounds in the competition and the product of her score was 50000. In How many rounds did she participate?	Options
A) 3 B) 2 C) 1 D) 5 E) Cannot be determined

Solution: Correct answer is E because we are given that there won't be any points awarded for rounds other than 1st four position.   Thus, it may happen that she played 15 rounds out of only 5 rounds were there in which she was awarded some points.
Answer: E
A rectangular tiled patio is composed of 48 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 48 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout?
Choose the correct choice
A) 5 B) 6 C) 10 D) 13 E) 28

Solution: Suppose there are c columns and there are r rows   Original Situation   So, Number of tiles = c*r = 48   Also. Reach column has r tiles and each row has c tiles   New Situation   Number of tiles in each column is r-2 and number of tiles in each row is c+4   So, number of rows = r-2 and number of columns is c+4   So, Number of tiles = (r-2)*(c+4) = 48   Comparing both of them we get   c*r = (r-2)*(c+4)   => 4r -2c = 8   c = 2r - 4   Putting it in c*r=48   (2r-4)*r = 48   2r^2 - 4r - 48=0   r cannot be negative so r = 6   and c = 8   So, Answer will be 6
Answer: B
7 people, A, B, C, D, E, F and H, go to a movie and sit next to each other in 8 adjacent seats in the front row of the theatre. In how many different arrangements will there be at least one person between A and F?
Choose the correct choice from the following options
A) 8! - 7!2	B) 5! - 7!2	C) 6! - 7!2	D) 8! - 6!2	E) 8! - 9!2

Solution: We need to find at least one person between A and F which is equal to Total ways - No one between A and F   Eight people can be arranged in 8! ways.   No one between A and F is equal to 7!*2! (consider A and F as one. 7 people can be arranged in 7! and 8! - 7!2 and F in 2!)   So, total ways = 8! - 7!2   8! - 7!2NS:8! - 7!2
Answer: A
A man and a boy complete a work together in 24 days. If for the last 6 days man alone does the work then it is completed in 26 days. How long the boy will take to complete the work alone?
Choose the correct choice from the following answers:
A) 72 days  B) 20 days  C) 24 days  D) 36 days  E) 34 days

Solution: Explanation:   (man + boy)’s 1 day’s work = 1/24   Their 20 day’s work = 1/24 × 20 = 5/6   The remaining 1/6 work is done by the man in 6days   Therefore, the man alone will finish the work in 6 × 6 days = 36 days   Man’s 1 day’s work = 1/36   Therefore, boy’s 1 day’s work = 1/24 – 1/36 = 3 – 2 /72 = 1/72   Therefore, the Boy alone will finish the work in 72 days.   72 daysnswer: Option 72 days
Answer: A
Albert is 2 times Mary’s age and 4 times as old as Betty. Mary is 22 years younger than Albert. How old is Betty?  Answers:
A) 8  B) 9  C) 11  D) 15  E) 18

Solution: A = 2M = M+22= 
+22 = 22
22   A= 44   A = 4B, and so B = 11   The answer is 11.
Answer: C
The average (arithmetic mean) of four numbers is 4x + 1. If one of the numbers is x, what is the average of the other three numbers?	Choose the correct choice from the following options.
A) x + 1  B) 3x + 3  C) 5x + 4/3  D) 5x + 4  E) 15x + 12

Solution: If the average of four numbers is 4x + 1, then the sum of all four numbers if 4 * (4x + 1) = 16x + 12. If one of the numbers is x, then the average of the remaining three numbers would be: (16x + 4 - x)/3 = (15x + 4)/3 = 5x + 4/3.   Answer is 5x + 4/3.
Answer: C
In a college, 70% of total 100 Arts students are Locals. 50% of students from 200 Science students are locals and 85% of total 120 Commerce students are locals. What is the total percentage of locals from Arts, Science and Commerce.  Choose the correct choice from the following answers:	A) 56	B) 86.7	C) 25.7	D) 66	E) 64.7

Solution: locals from Arts = 70% of 100 = 70   locals from Science = 50% of 200 = 100   locals from Commerce = 85% of 120 = 102   total local percentage = (70+100+102)/(100+200+120) = 272/420 = 0.647   64.7
Answer: E
In an election a candidate who gets 60% of the votes is elected by a majority of 1300 votes. What is the total number of votes polled?
Options:
A) A)4500  B) B)5200  C) C)6900  D) D)7520  E) E)6500

Solution: Let the total number of votes polled be x   Then, votes polled by other candidate = (100-60)= 
(100-60) = 40
40% of x   60% of x - 40% of x= 1300   20x/100 = 1300   x = 1300*100/20= 
1300*100/20 = 6_500
6500   Answer is 6500
Answer: E
At a certain amateur bands rock show the ratio of freaks to nerds (N) to geeks is 1:2:3. If these are the only types of people in the crowd, and each person in the crowd has the same chance of yelling rock on!, what are the chances that the next person who yells rock on!will be a geek?  Choose the correct choice from the following choices
A) 1  B) 1/2  C) 1/3  D) 1/4  E) 1/6

Solution: Another approach is toassign some nice valuesfor the number of freaks, nerds and geeks.   Given: the ratio of freaks to nerds to geeks is 1:2:3   So, let's say there is: 1 freak, 2 nerds and3geeks for a TOTAL of6people.   P(next person who yellsrock on!is a geek) = (# of geeks in the crowd)/(TOTAL # of people in the crowd)   =3/6   = 1/2   Answer:   1/2
Answer: B
What is the product of all the possible values of x if x^2 - 9x + 20?	Select the correct option.
A) –29 B) –12 C) 12 D) 20 E) 168

Solution: Explanation:   => y= x^2 - 9x + 20   => y= (x-4) (x-5)   => x= 4, y= 5   Product y = (4)(5) = 20   answer option 20   ANSWER:20
Answer: D
An arithemetic sequence of numbers begins p, 2p + 2, 4p + 3... What is the 10th member of this sequence?  Choose the most appropriate option.
A) A)37	B) B)28	C) + 13	D) D)53	E) + 13

Solution: Common difference of an arithmetic series is constant.   2p+2-p=4p+3-2p-2   p=1   1, 4, 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37   Ans:28
Answer: B
A one-foot stick is marked in 1/4 and 1/6 portion. How many total markings will there be, including the end points? Choose the most appropriate option:
A) 8	B) 10	C) 12	D) 14	E) 16

Solution: LCM of 24 = 12   1/4 marking are (Table of 3) 0...... 3 ........... 6.......... 9 .......... 12   (Total = 5)   1/6 marking are (Table of 2) 0 ....... 2 ...... 4...... 6........ 8......... 12 ((Total = 6)   Overlapping markings are 0 ........ 6 ......... 12 (Total = 3)   Total markings = 5+6-3= 
5+6-3 = 8
8   8nswer= 8
Answer: A
Find the odd one out:
125, 106, 87, 76, 65, 58, 53 Options:
A) 33	B) 87	C) 26	D) 18	E) 222

Solution: Explanation:   This sequence represents a series in which from the reverse order a prime number is added:   53+5= 
53+5 = 58
58   58+7= 
58+7 = 65
65   65+11= 
65+11 = 76
76   76+13= 
76+13 = 89
89   89+17= 
89+17 = 106
106   106+19= 
106+19 = 125
125   Hence 87 is the answer.   ANSWER: 87
Answer: B
When running a mile during a recent track meet, Nuria was initially credited with a final time of 5 minutes, 30 seconds. Shortly after her run, officials realized that the timing mechanism malfunctioned. The stopwatch did not begin timing her until 2/7 of a minute after she began to run. If the time was otherwise correct, how long did it actually take Nuria to run the mile? Options
A) 5 minutes, 17.6 seconds	B) 5 minutes, 21.8 seconds	C) 5 minutes, 23.6 seconds	D) 5 minutes, 44.44 seconds	E) 6 minutes, 10.4 seconds

Solution: One approach:   The watch starts to work after Nuria began his running. It means the time should be greater than credited 5 minutes, 30 seconds. The only number is 5 minutes, 44.44 seconds.   Another approach:   2/7 close to 20 second when added to the 5 minutes, 30 seconds, it means it passes 5 minute 44.44 seconds   Answer: 5 minutes, 44.44 seconds
Answer: D
In a group of 400 readers who read science fiction or literacy works or both, 250 read science fiction and 230 read literacy works. How many read both science fiction and literacy works?	Choose the most appropriate option.
A) 70  B) 80  C) 90  D) 100  E) 110

Solution: Consider total number of reader n(S U L) = 400   People who read science fiction n(S) = 250   People who read literacy works n(L) = 230   both science fiction and literacy n(S ∩ L) = ?   n(S U L) = n(S)+ n(L) - n(S ∩ L)   400 = 250 + 230 - n(S ∩ L)   n(S ∩ L) = 480 - 400   n(S ∩ L) = 80   SO People read both science fiction and literacy works are 80   ANSWER:80
Answer: B
5 girls and 3 boys are arranged randomly in a row. Find the probability that:
1) there is one boy on each end.
2) There is one girl on each end. Select
A) 3/28 & 5/14  B) 5/28 & 3/14  C) 5/14 & 3/28  D) 3/28 & 1/14  E) 1/28 & 5/14

Solution: Total # of arrangements is 8!;   1. The # of arrangements where there is one boy on each end is C^2/3∗2∗6! where C^2/3C32 is # of ways to select which 2 boys will be on that positions, *2 # of way to arrange them on that position (A------B and B------A) and 6! is # of arrangements of 6 people left;   P=C^2/3∗2∗6!/8!=3/28   2. The # of arrangements where there is one girl on each end is C^2/5∗2∗7!, where C^2/5 is # of ways to select which 2 girls will be on that positions, *2 # of way to arrange them on that position (3/28 & 5/14------B and B------3/28 & 5/14) and 6! is # of arrangements of 6 people left;   P=C^2/5∗2∗6!/8!=5/14   3/28 & 5/14nswer: 3/28 & 5/14.
Answer: A
A Paul's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio of revenue from car sales in 1996 to revenue from truck sales in 1996?  Choose the correct answer:
A) 1:2	B) 4:5	C) 1:1	D) 3:2	E) 5:3

Solution: 1:2 Paul's company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996.1996- x----- y------- x+y   1997- x1---- y1-- x1+y1   x1= a*x .....(P)   y1= 1.07*y...(Q)   x1+y1/x+y = 1.01   solve using P and Q and find x/y
Answer: A
How many numbers from 29 to 79 are exactly divisible by 11?  Pick.
A) 1  B) 2  C) 6  D) 4  E) 5

Solution: Numbers=(79/11)-(29/11)   =7-2= 
7-2 = 5
5 numbers   Answer is option 5
Answer: E
. A, B and C invests Rs.2000, Rs.3000 and Rs.4000 in a business. After one year A removed his money; B and C continued the business for one more year. If the net profit after 2 years be Rs.3200, then A's share in the profit is? Choose the correct choice from the following
A) 2787	B) 288	C) 277	D) 400	E) 122

Solution: Explanation:   2*12 : 3*12 : 4*24   1: 3: 4   1/8 * 3200= 
1/8 * 3200 = 400
400   Answer: 400
Answer: D
On dividing 73 by a number, the quotient is 9 and the remainder is 1. Find the divisor?	Choose the correct option:  A) A)8  B) B)15  C) C)16  D) D)17  E) E)18

Solution: d = (D-R)/Q   = (73 - 1)/9   = 72/9= 
72/9 = 8
8   8)
Answer: A