Definition: In this task, you are given commands (in terms of logical operations) and natural interpretation of the given command to select relevant rows from the given table. Your job is to generate a label "yes" if the interpretation is appropriate for the command, otherwise generate label "no". 
 Here are the definitions of logical operators: 
 1. count: returns the number of rows in the view. 
 2. only: returns whether there is exactly one row in the view. 
 3. hop: returns the value under the header column of the row. 
 4. and: returns the boolean operation result of two arguments. 
 5. max/min/avg/sum: returns the max/min/average/sum of the values under the header column. 
 6. nth_max/nth_min: returns the n-th max/n-th min of the values under the header column. 
 7. argmax/argmin: returns the row with the max/min value in header column. 
 8. nth_argmax/nth_argmin: returns the row with the n-th max/min value in header column. 
 9. eq/not_eq: returns if the two arguments are equal. 
 10. round_eq: returns if the two arguments are roughly equal under certain tolerance. 
 11. greater/less: returns if the first argument is greater/less than the second argument. 
 12. diff: returns the difference between two arguments. 
 13. filter_eq/ filter_not_eq: returns the subview whose values under the header column is equal/not equal to the third argument. 
 14. filter_greater/filter_less: returns the subview whose values under the header column is greater/less than the third argument. 
 15. filter_greater_eq /filter_less_eq: returns the subview whose values under the header column is greater/less or equal than the third argument. 
 16. filter_all: returns the view itself for the case of describing the whole table 
 17. all_eq/not_eq: returns whether all the values under the header column are equal/not equal to the third argument. 
 18. all_greater/less: returns whether all the values under the header column are greater/less than the third argument. 
 19. all_greater_eq/less_eq: returns whether all the values under the header column are greater/less or equal to the third argument. 
 20. most_eq/not_eq: returns whether most of the values under the header column are equal/not equal to the third argument. 
 21. most_greater/less: returns whether most of the values under the header column are greater/less than the third argument. 
 22. most_greater_eq/less_eq: returns whether most of the values under the header column are greater/less or equal to the third argument.

Positive Example 1 -
Input: Command: eq { hop { nth_argmax { all_rows ; attendance ; 3 } ; competition } ; danish superliga 2005 - 06 }, interpretation: select the row whose attendance record of all rows is 3rd maximum. the competition record of this row is danish superliga 2005-06.
Output: yes

Positive Example 2 -
Input: Command: eq { hop { argmax { all_rows ; duration } ; actor } ; lesley saweard }, interpretation: select the row whose duration record of all rows is maximum. the actor record of this row is lesley saweard.
Output: yes

Negative Example 1 -
Input: Command: eq { hop { nth_argmax { all_rows ; attendance ; 3 } ; competition } ; danish superliga 2005 - 06 }, interpretation: select the row whose attendance record of all rows is 3rd maximum. the competition record of this row is danish superliga 2005-06.
Output: no

Negative Example 2 -
Input: Command: eq { hop { nth_argmax { all_rows ; goal gain ; 3 } ; team } ; south china }, interpretation: select the rows whose name of county record fuzzily matches to veszprém. take the area (km square) record of this row. select the rows whose name of county record fuzzily matches to tolna.
Output: yes

Now complete the following example -
Input: Command: and { eq { hop { filter_eq { all_rows ; team 1 ; elche } ; 2nd leg } ; hop { filter_eq { all_rows ; team 1 ; numancia } ; 2nd leg } } ; and { eq { hop { filter_eq { all_rows ; team 1 ; elche } ; 2nd leg } ; 0 - 2 } ; eq { hop { filter_eq { all_rows ; team 1 ; numancia } ; 2nd leg } ; 0 - 2 } } }, interpretation: select the rows whose team 1 record fuzzily matches to elche . take the 2nd leg record of this row . select the rows whose team 1 record fuzzily matches to numancia . take the 2nd leg record of this row . the first record fuzzily matches to the second record . the 2nd leg record of the first row is 0 - 2 . the 2nd leg record of the second row is 0 - 2 .
Output: 


Answer: yes