Definition: In this task you are expected to write an SQL query that will return the data asked for in the question. An SQL query works by selecting data from a table where certain conditions apply. A table contains columns where every row in that table must have a value for each column. Every table has a primary key that uniquely identifies each row, usually an id. To choose which columns are returned you specify that after the "SELECT" statement. Next, you use a "FROM" statement to specify what tables you want to select the data from. When you specify a table you can rename it with the "AS" statement. You can reference that table by whatever name follows the "AS" statement. If you want to select data from multiple tables you need to use the "JOIN" statement. This will join the tables together by pairing a row in one table with every row in the other table (Cartesian Product). To limit the number of rows returned you should use the "ON" statement. This will only return rows where the condition specified after the statement is true, this is usually an equals operator with primary keys. You can also use the "WHERE" statement to specify that only rows with column values statisfying a certain condition, should be returned. The "GROUP BY" statement will group rows together that have equal column values for whatever columns follows the statement. The "HAVING" statement will return groups that statisfy whatever condition follows the statement. Any column(s) being returned from grouped rows must either be an aggregate function, (AVG, MAX, COUNT, SUM, ...) of a column, or the column(s) that the data was grouped by. To sort the returned data you can use the "ORDER BY" command which will order the data by whatever aggregate function or column follows the statement. The "DESC" statement will sort in descending order and the "ASC" statement will sort in ascending order. Finally, you can use the "LIMIT" statement to return a certain number of rows. When "*" is used in an SQL statement every column is returned. For example, SELECT * FROM table WHERE attribute = 1, will select every column from rows with the attribute column equal to 1.

Positive Example 1 -
Input: Find the id and city of the student address with the highest average monthly rental.
Output: SELECT T2.address_id ,  T1.city FROM Addresses AS T1 JOIN Student_Addresses AS T2 ON T1.address_id  =  T2.address_id GROUP BY T2.address_id ORDER BY AVG(monthly_rental) DESC LIMIT 1

Positive Example 2 -
Input: Show the facility codes of apartments with more than 4 bedrooms.
Output: SELECT T1.facility_code FROM Apartment_Facilities AS T1 JOIN Apartments AS T2 ON T1.apt_id  =  T2.apt_id WHERE T2.bedroom_count  >  4

Negative Example 1 -
Input: Show the average room count of the apartments that have booking status code "Provisional".
Output: SELECT Avg ( T1.bathroom_count ) FROM Apartments AS T1 JOIN Apartment_Bookings AS T2 ON T1.apt_id = T2.apt_id WHERE T2.booking_status_code = "Provisional"

Negative Example 2 -
Input: Show all product names and the total quantity ordered for each product name.
Output: SELECT product_name , Sum ( * ) FROM Products GROUP BY product_name

Now complete the following example -
Input: List the names of the browser that are compatible with both 'CACHEbox' and 'Fasterfox'.
Output: 


Answer: SELECT T3.name FROM web_client_accelerator AS T1 JOIN accelerator_compatible_browser AS T2 ON T2.accelerator_id  =  T1.id JOIN browser AS T3 ON T2.browser_id  =  T3.id WHERE T1.name  =  'CACHEbox' INTERSECT SELECT T3.name FROM web_client_accelerator AS T1 JOIN accelerator_compatible_browser AS T2 ON T2.accelerator_id  =  T1.id JOIN browser AS T3 ON T2.browser_id  =  T3.id WHERE T1.name  =  'Fasterfox'