In an acute triangle  $ABC$  let  $K,L,$  and  $M$  be the midpoints of sides  $AB,BC,$  and  $CA,$  respectively. From each of  $K,L,$  and  $M$  drop two perpendiculars to the other two sides of the triangle; e.g., drop perpendiculars from  $K$  to sides  $BC$  and  $CA,$  etc. The resulting  $6$  perpendiculars intersect at points  $Q,S,$  and  $T$  as in the figure to form a hexagon  $KQLSMT$  inside triangle  $ABC.$  The area of triangle $ABC$ is $n$ times of the area of hexagon  $KQLSMT$. Find the value of $n$

[asy]import graph; size(10cm); 
real labelscalefactor = 0.5; 
pen dps = linewidth(0.7) + fontsize(10); defaultpen(dps); 
pen dotstyle = black; 
real xmin = 11.888712276357234, xmax = 17.841346447833423, ymin = 10.61620970860601, ymax = 15.470685507068502;
pen zzttqq = rgb(0.6,0.2,0.); pen qqwuqq = rgb(0.,0.39215686274509803,0.); 
pair A = (12.488234161849352,12.833838721895551), B = (16.50823416184936,15.093838721895553), C = (16.28823416184936,11.353838721895551), K = (14.498234161849355,13.963838721895552), L = (16.39823416184936,13.223838721895552), M = (14.388234161849356,12.093838721895551), D = (13.615830174638527,13.467760858438725), F = (15.75135711740064,11.562938202365055), G = (15.625830174638523,14.597760858438724), H = (16.435061748056253,13.849907687412797), T = (14.02296781802369,12.74356027153236), Q = (16.032967818023693,13.873560271532357), O = (16.325061748056253,11.979907687412794); 

draw(A--B--C--cycle, zzttqq); 
draw((13.426050287639166,13.361068683160477)--(13.532742462917415,13.171288796161116)--(13.722522349916774,13.277980971439364)--D--cycle, qqwuqq); 
draw((14.054227993863618,12.223925334689998)--(14.133240861538676,12.426796211152979)--(13.930369985075695,12.505809078828037)--(13.851357117400637,12.302938202365056)--cycle, qqwuqq); 
draw((16.337846386707046,12.19724654447628)--(16.12050752964356,12.210031183127075)--(16.107722890992765,11.992692326063588)--O--cycle, qqwuqq); 
draw((15.830369985075697,11.765809078828037)--(15.627499108612716,11.844821946503092)--(15.54848624093766,11.641951070040111)--F--cycle, qqwuqq); 
draw((15.436050287639164,14.491068683160476)--(15.542742462917412,14.301288796161115)--(15.73252234991677,14.407980971439365)--G--cycle, qqwuqq); 
draw((16.217722890992764,13.86269232606359)--(16.20493825234197,13.645353469000101)--(16.42227710940546,13.63256883034931)--H--cycle, qqwuqq); 
Label laxis; laxis.p = fontsize(10); 
xaxis(xmin, xmax, Ticks(laxis, Step = 1., Size = 2, NoZero),EndArrow(6), above = true); 
yaxis(ymin, ymax, Ticks(laxis, Step = 1., Size = 2, NoZero),EndArrow(6), above = true);  
draw(A--B, zzttqq); 
draw(B--C, zzttqq); 
draw(C--A, zzttqq); 
draw(M--D); 
draw(K--(13.851357117400637,12.302938202365056)); 
draw(F--L); 
draw(L--G); 
draw(K--H); 
draw(M--O); 
dot(A,dotstyle); 
label(" $A$ ", (12.52502834296331,12.93568440300881), NE * labelscalefactor); 
dot(B,dotstyle); 
label(" $B$ ", (16.548187989892043,15.193580123223922), NE * labelscalefactor); 
dot(C,dotstyle); 
label(" $C$ ", (16.332661580235147,11.457789022504372), NE * labelscalefactor); 
dot(K,linewidth(3.pt) + dotstyle); 
label(" $K$ ", (14.536608166427676,14.02357961365791), NE * labelscalefactor); 
dot(L,linewidth(3.pt) + dotstyle); 
label(" $L$ ", (16.43529320388129,13.28463192340569), NE * labelscalefactor); 
dot(M,linewidth(3.pt) + dotstyle); 
label(" $M$ ", (14.433976542781535,12.155684063298134), NE * labelscalefactor); 
dot(D,linewidth(3.pt) + dotstyle); 
dot((13.851357117400637,12.302938202365056),linewidth(3.pt) + dotstyle); 
dot(F,linewidth(3.pt) + dotstyle); 
dot(G,linewidth(3.pt) + dotstyle); 
dot(H,linewidth(3.pt) + dotstyle); 
dot((15.922967818023695,12.003560271532354),linewidth(3.pt) + dotstyle); 
label(" $S$ ", (15.96318773510904,12.063315602016607), NE * labelscalefactor); 
dot(T,linewidth(3.pt) + dotstyle); 
label(" $T$ ", (14.064502697655428,12.802263292268826), NE * labelscalefactor); 
dot(Q,linewidth(3.pt) + dotstyle); 
label(" $Q$ ", (16.076082521119794,13.931211152376383), NE * labelscalefactor); 
dot(O,linewidth(3.pt) + dotstyle); 
clip((xmin,ymin)--(xmin,ymax)--(xmax,ymax)--(xmax,ymin)--cycle);[/asy]

Answer: $2$