So I can see here that I have removed the DC part but the change in the optical power can be negative of course this implies that this does not imply that the power itself is going negative but please remember this is only the change in the optical power so what we have obtained here is that we have obtained a oh sorry there is a Ps/2 also I am sorry I forgot to put that one, so this change in the optical power is this follow where k ˈ is a very small number so this would essentially be the output right so you have now seen that come you know if you are looking at the change in the optical power that can be a linear function of the applied m(t) right.
इसलिए मैं यहां देख सकता हूं कि मैंने डीसी पार्ट को हटा दिया है, लेकिन ऑप्टिकल पावर में बदलाव इस तरह से नकारात्मक हो सकता है, इसका मतलब यह है कि इसका मतलब यह नहीं है कि पावर खुद नकारात्मक हो रही है, लेकिन कृपया याद रखें कि यह केवल ऑप्टिकल पावर में बदलाव है इसलिए हमने यहां जो प्राप्त किया है, वह यह है कि हमने एक ओह सॉरी प्राप्त किया है, एक पीएस / 2 भी है।