Number of neutrons present in \\\\(1.7\\\\) g of ammonia is:
Let us consider the problem.For, moles of \\\\(N{H_3} = \\frac{{1.7}}{{17}} = 0.1\\\\)Let the Neutrons in 1 molecules of \\\\(N{H_3} = 7 + 3 \ imes 0 = 7\\\\)Hence,Number of Neurons \\\\(= 0.1 \ imes {N_A} \ imes 7\\\\)The correct answer is \\\\(0.7{N_A}\\\\)