SCHEMA:
CREATE TABLE Apartment_Buildings (building_address VARCHAR, building_id VARCHAR); CREATE TABLE Apartments (building_id VARCHAR, bathroom_count INTEGER)
User Question:
Show the addresses of the buildings that have apartments with more than 2 bathrooms.


SELECT T1.building_address FROM Apartment_Buildings AS T1 JOIN Apartments AS T2 ON T1.building_id = T2.building_id WHERE T2.bathroom_count > 2