function makeyogurt ($type = "acidophilus", $flavour) {return "Making a bowl of $type $flavour.\n";} echo makeyogurt ("raspberry"); / / won't work as expected
?php function faireunyaourt ($type = "acidophilus", $flavour) {return "Préparer un bol de $type $flavour.\n";} echo faireunyaourt ("framboise"); / / ne fonctionne pas comme voulu?