Buggy python submission (verdict: Runtime Error):
from math import gcd
MAX = 10**6

sieve = [i for i in range(MAX+1)]

p = 2
while p * p <= MAX:
    if sieve[p] == p:
        for i in range(p*2, MAX+1, p):
            if sieve[i] == i:
                sieve[i] = p
    p += 1


N = int(input())
A = list(map(int, input().split()))
pf = []

for a in A:
    tmp = set()
    b = a
    while b != 1:
        tmp.add(sieve[b])
        b //= sieve[b]
    pf.append(tmp)


soin = [0] * (10 ** 6 + 1)
for f in pf:
    for n in f:
        soin[n] += 1

if max(soin[2:]) <= 1:
    print('pairwise coprime')
    exit()


setwise = a[0]

for a in A:
    setwise = gcd(setwise, a)
    
if setwise == 1:
    print('setwise coprime')
else:
    print('not coprime')

Fixed submission:
#!/usr/bin/env python3

import sys
from math import gcd
from collections import Counter
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

N = int(input())
A = list(map(int, input().split()))

dup = False
dup_key = None
counter = Counter(A)
for key, val in counter.items():
    if val > 1:
        dup = True
        if dup_key is None:
            dup_key = key
        else:
            dup_key = max(dup_key, key)


def max_gcd_pair(S):
    # Assumption 1: S is the list of numbers
    # Assumption 2: There are no duplicates in S
    s = set(S)
    m = max(S)
    res = 1
    i = m
    while i > 0:
        a = i
        cnt = 0
        while a <= m: # a maxed at max of the list
            if a in s:
                cnt += 1
            a += i
        if cnt >= 2:  # we have found the result
            res = i
            break
        i = i - 1
    return res


pair = max_gcd_pair(A)
if dup:
    pair *= dup_key

if pair == 1:
    print('pairwise coprime')
    sys.exit()


setw = A[0]
for j in range(N):
    setw = gcd(setw, A[j])
if setw == 1:
    print('setwise coprime')
else:
    print('not coprime')

Buggy python submission (verdict: Time Limit Exceeded):
import numpy as np
MAX = 10**6
 
sieve = [i for i in range(MAX+1)]
 
p = 2
while p * p <= MAX:
    if sieve[p] == p:
        for i in range(p*2, MAX+1, p):
            if sieve[i] == i:
                sieve[i] = p
    p += 1
 
 
N = int(input())
A = list(map(int, input().split()))
pf = []
 
for a in A:
    tmp = set()
    b = a
    while b != 1:
        tmp.add(sieve[b])
        b //= sieve[b]
    pf.append(tmp)
 
 
soin = [0] * (10 ** 6 + 1)
for f in pf:
    for n in f:
        soin[n] += 1
 
if max(soin[2:]) <= 1:
    print('pairwise coprime')
    exit()
 
flag = np.gcd.reduce(A)
 
if flag == 1:
    print('setwise coprime')
else:
    print('not coprime')

Fixed submission:
#!/usr/bin/env python3

import sys
from math import gcd
from collections import Counter
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

N = int(input())
A = list(map(int, input().split()))

dup = False
dup_key = None
counter = Counter(A)
for key, val in counter.items():
    if val > 1:
        dup = True
        if dup_key is None:
            dup_key = key
        else:
            dup_key = max(dup_key, key)


def max_gcd_pair(S):
    # Assumption 1: S is the list of numbers
    # Assumption 2: There are no duplicates in S
    s = set(S)
    m = max(S)
    res = 1
    i = m
    while i > 0:
        a = i
        cnt = 0
        while a <= m: # a maxed at max of the list
            if a in s:
                cnt += 1
            a += i
        if cnt >= 2:  # we have found the result
            res = i
            break
        i = i - 1
    return res


pair = max_gcd_pair(A)
if dup:
    pair *= dup_key

if pair == 1:
    print('pairwise coprime')
    sys.exit()


setw = A[0]
for j in range(N):
    setw = gcd(setw, A[j])
if setw == 1:
    print('setwise coprime')
else:
    print('not coprime')

Buggy python submission (verdict: Runtime Error):
import numpy as np
MAX = 10**6

sieve = [i for i in range(MAX+1)]

p = 2
while p * p <= MAX:
    if sieve[p] == p:
        for i in range(p*2, MAX+1, p):
            if sieve[i] == i:
                sieve[i] = p
    p += 1


N = int(input())
A = list(map(int, input().split()))
pf = []

for a in A:
    tmp = set()
    b = a
    while b != 1:
        tmp.add(sieve[b])
        b //= sieve[b]
    pf.append(tmp)


soin = [0] * (10 ** 6 + 1)
for f in pf:
    for n in f:
        soin[n] += 1

if max(soin[2:]) <= 1:
    print('pairwise coprime')
    exit()

flag = np.gcd.reduce(A)

if flag == 1:
    print('setwise coprime')
else:
    print('not coprime')

Fixed submission:
#!/usr/bin/env python3

import sys
from math import gcd
from collections import Counter
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
sys.setrecursionlimit(10 ** 7)

N = int(input())
A = list(map(int, input().split()))

dup = False
dup_key = None
counter = Counter(A)
for key, val in counter.items():
    if val > 1:
        dup = True
        if dup_key is None:
            dup_key = key
        else:
            dup_key = max(dup_key, key)


def max_gcd_pair(S):
    # Assumption 1: S is the list of numbers
    # Assumption 2: There are no duplicates in S
    s = set(S)
    m = max(S)
    res = 1
    i = m
    while i > 0:
        a = i
        cnt = 0
        while a <= m: # a maxed at max of the list
            if a in s:
                cnt += 1
            a += i
        if cnt >= 2:  # we have found the result
            res = i
            break
        i = i - 1
    return res


pair = max_gcd_pair(A)
if dup:
    pair *= dup_key

if pair == 1:
    print('pairwise coprime')
    sys.exit()


setw = A[0]
for j in range(N):
    setw = gcd(setw, A[j])
if setw == 1:
    print('setwise coprime')
else:
    print('not coprime')