Buggy python submission (verdict: Time Limit Exceeded):
def checkxor(a,b):
    zero = set([0])
    for x in a:
        temp = set()
        for y in zero:
            temp.add(x^y)
        zero |= temp
    one = set([0])
    for x in b:
        temp = set()
        for y in one:
            c = x ^ y
            if c not in zero:
                return False
            else:
                temp.add(c)
        one |= temp
    return True

T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    if S[-1] == '1':
        print('1')
    elif S.count('0') == len(S):
        print('0')
    else:
        zeros = []
        ones = []
        for j in range(len(S)):
            if S[j] == '1':
                ones.append(A[j])
                current = 1
                break
        for k in range(j+1,len(S)):
            if S[k] == '1':
                if current == 1:
                    ones.append(A[k])
                else:
                    if checkxor(zeros,ones) == False:
                        print('1')
                        break
                    else:
                        ones.append(A[k])
                        current = 1
            else:
                if current == 0:
                    zeros.append(A[k])
                else:
                    zeros.append(A[k])
                    current = 0
        if checkxor(zeros,ones) == False:
            print('1')
        else:
            print('0')

Fixed submission:
T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    base = []
    for i in range(1,N+1):
        temp = A[-i]
        for x in base:
            temp = min(temp,temp^x)
        if temp != 0:
            if S[-i] == '1':
                print('1')
                break
            else:
                base.append(temp)
    else:
        print('0')

Buggy python submission (verdict: Time Limit Exceeded):
def listxor(a):
    count = [0] * (len(max(a))-2)
    
def checkxor(a,b):
    zero = set([0])
    for x in a:
        temp = set()
        for y in zero:
            temp.add(x^y)
        zero |= temp
    one = set([0])
    for x in b:
        temp = set()
        for y in one:
            c = x ^ y
            if c not in zero:
                return False
            else:
                temp.add(x^y)
        one |= temp
    return True

T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    if S[-1] == '1':
        print('1')
    elif S.count('0') == len(S):
        print('0')
    else:
        zeros = []
        ones = []
        for j in range(len(S)):
            if S[j] == '1':
                ones.append(A[j])
                current = 1
                break
        for k in range(j+1,len(S)):
            if S[k] == '1':
                if current == 1:
                    ones.append(A[k])
                else:
                    if checkxor(zeros,ones) == False:
                        print('1')
                        break
                    else:
                        ones.append(A[k])
                        current = 1
            else:
                if current == 0:
                    zeros.append(A[k])
                else:
                    zeros.append(A[k])
                    current = 0
        if checkxor(zeros,ones) == False:
            print('1')
        else:
            print('0')

Fixed submission:
T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    base = []
    for i in range(1,N+1):
        temp = A[-i]
        for x in base:
            temp = min(temp,temp^x)
        if temp != 0:
            if S[-i] == '1':
                print('1')
                break
            else:
                base.append(temp)
    else:
        print('0')

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import combinations
from functools import reduce
from operator import xor

def checkxor(a,b):
    zero = set()
    for i in range(1,len(a)+1):
        for x in combinations(a,i):
            zero.add(reduce(xor,x))
    for i in range(1,len(b)+1):
        for x in combinations(b,i):
            if reduce(xor,x) not in zero:
                return False
    return True

T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    if S[-1] == '1':
        print('1')
    elif S.count('0') == len(S):
        print('0')
    else:
        zeros = []
        ones = []
        for j in range(len(S)):
            if S[j] == '1':
                ones.append(A[j])
                current = 1
                break
        for k in range(j+1,len(S)):
            if S[k] == '1':
                if current == 1:
                    ones.append(A[k])
                else:
                    if checkxor(zeros,ones) == False:
                        print('1')
                        break
                    else:
                        ones.append(A[k])
                        current = 1
            else:
                if current == 0:
                    zeros.append(A[k])
                else:
                    zeros.append(A[k])
                    current = 0
        if checkxor(zeros,ones) == False:
            print('1')
        else:
            print('0')

Fixed submission:
T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    base = []
    for i in range(1,N+1):
        temp = A[-i]
        for x in base:
            temp = min(temp,temp^x)
        if temp != 0:
            if S[-i] == '1':
                print('1')
                break
            else:
                base.append(temp)
    else:
        print('0')

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import combinations
from functools import reduce
from operator import xor

def checkxor(a,b):
    zero = set()
    one = set()
    for i in range(1,len(a)+1):
        for x in combinations(a,i):
            zero.add(reduce(xor,x))
    for i in range(1,len(b)+1):
        for x in combinations(b,i):
            one.add(reduce(xor,x))
    if zero == one:
        return True
    else:
        return False

T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    if S[-1] == '1':
        print('1')
    elif S.count('0') == len(S):
        print('0')
    else:
        zeros = []
        ones = []
        for j in range(len(S)):
            if S[j] == '1':
                ones.append(A[j])
                current = 1
                break
        for k in range(j+1,len(S)):
            if S[k] == '1':
                if current == 1:
                    ones.append(A[k])
                else:
                    if checkxor(zeros,ones) == False:
                        print('1')
                        break
                    else:
                        ones.append(A[k])
                        current = 1
            else:
                if current == 0:
                    zeros.append(A[k])
                else:
                    zeros.append(A[k])
                    current = 0
        if checkxor(zeros,ones) == False:
            print('1')
        else:
            print('0')

Fixed submission:
T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    base = []
    for i in range(1,N+1):
        temp = A[-i]
        for x in base:
            temp = min(temp,temp^x)
        if temp != 0:
            if S[-i] == '1':
                print('1')
                break
            else:
                base.append(temp)
    else:
        print('0')

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import combinations
from functools import reduce
from operator import xor

def checkxor(a,b):
    zero = set()
    one = set()
    for i in range(1,len(a)+1):
        for x in combinations(a,i):
            zero.add(reduce(xor,x))
    for i in range(1,len(b)+1):
        for x in combinations(b,i):
            one.add(reduce(xor,x))
    if zero == one:
        return True
    else:
        return False

T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    if S[-1] == '1':
        print('1')
    elif S.count('0') == len(S):
        print('0')
    else:
        zeros = []
        ones = []
        for j in range(len(S)):
            if S[j] == '1':
                ones.append(A[j])
                current = 1
                break
        for k in range(j+1,len(S)):
            if S[k] == '1':
                if current == 1:
                    ones.append(A[k])
                else:
                    if checkxor(zeros,ones) == False:
                        print('1')
                        break
                    else:
                        ones.append(A[k])
                        current = 1
            else:
                if current == 0:
                    zeros.append(A[k])
                else:
                    zeros.append(A[k])
                    current = 0
        if checkxor(zeros,ones) == False:
            print('1')
        else:
            print('0')

Fixed submission:
T = int(input())
for i in range(T):
    N = int(input())
    A = list(map(int, input().split()))
    S = input()
    base = []
    for i in range(1,N+1):
        temp = A[-i]
        for x in base:
            temp = min(temp,temp^x)
        if temp != 0:
            if S[-i] == '1':
                print('1')
                break
            else:
                base.append(temp)
    else:
        print('0')