Buggy python submission (verdict: Time Limit Exceeded):
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
K = 4001 #適当
kk = int((K-1)/2)
dp = [[[False]*K for _ in range(W)] for _ in range(H)]
 
dp[0][0][kk+diff[0][0]] = True
dp[0][0][kk-diff[0][0]] = True
 
for i in range(H):
    for j in range(W):
        a= min((i+j)*80,kk)
        for k in range(kk-a,kk+a+1):
            if i-1>=0:
                if k+diff[i][j]<K:
                    if dp[i-1][j][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i-1][j][k-diff[i][j]]:
                        dp[i][j][k] =True
            if j-1>=0:
                if k+diff[i][j]<K:
                    if dp[i][j-1][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i][j-1][k-diff[i][j]]:
                        dp[i][j][k] =True
ans = K

for k in range(K):
    if dp[-1][-1][k]:
        ans = min(ans,abs(k-kk))
print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
#dp[i][j]にはkという数字にたどり着けるかどうかを示す2進数を入れる

dp = [[False]*W for _ in range(H)]
ofs = 80*(H+W)


dp[0][0]=(1<<(ofs+diff[0][0]) | 1>>(ofs-diff[0][0]))
 
for i in range(H):
    for j in range(W):
        if i>0:
            dp[i][j]|=(dp[i-1][j]<<diff[i][j] | dp[i-1][j]>>diff[i][j])
        if j>0:
            dp[i][j]|=(dp[i][j-1]<<diff[i][j] | dp[i][j-1]>>diff[i][j])


#0のところから見て，最初に1が出てきたところが答え
for k in range(ofs):
    if (dp[-1][-1]>>(k+ofs)&1):
        print(k)
        break

Buggy python submission (verdict: Time Limit Exceeded):
H,W = map(int,input().split())
A = [list(map(int, input().split())) for _ in range(H)]
B = [list(map(int, input().split())) for _ in range(H)]
 
#差分だけで良い，これを*1 or -1していく
diff = [[0]*W for _ in range(H)]
for i in range(H):
    for j in range(W):
        diff[i][j] = abs(A[i][j] - B[i][j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
K = 6401 #適当
kk = int((K-1)/2)
dp = [[[False]*K for _ in range(W)] for _ in range(H)]
 
dp[0][0][kk+diff[0][0]] = True
dp[0][0][kk-diff[0][0]] = True
 

for i in range(H):
    for j in range(W):
        a= min((i+j)*80,kk)
        for k in range(kk-a,kk+a+1):
            if i-1>=0:
                if k+diff[i][j]<K:
                    if dp[i-1][j][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i-1][j][k-diff[i][j]]:
                        dp[i][j][k] =True
            if j-1>=0:
                if k+diff[i][j]<K:
                    if dp[i][j-1][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i][j-1][k-diff[i][j]]:
                        dp[i][j][k] =True
ans = K


for k in range(K):
    if dp[H-1][W-1][k]:
        ans = min(ans,abs(k-kk))
print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
#dp[i][j]にはkという数字にたどり着けるかどうかを示す2進数を入れる

dp = [[False]*W for _ in range(H)]
ofs = 80*(H+W)


dp[0][0]=(1<<(ofs+diff[0][0]) | 1>>(ofs-diff[0][0]))
 
for i in range(H):
    for j in range(W):
        if i>0:
            dp[i][j]|=(dp[i-1][j]<<diff[i][j] | dp[i-1][j]>>diff[i][j])
        if j>0:
            dp[i][j]|=(dp[i][j-1]<<diff[i][j] | dp[i][j-1]>>diff[i][j])


#0のところから見て，最初に1が出てきたところが答え
for k in range(ofs):
    if (dp[-1][-1]>>(k+ofs)&1):
        print(k)
        break

Buggy python submission (verdict: Runtime Error):
H,W = map(int,input().split())
A = [list(map(int, input().split())) for _ in range(H)]
B = [list(map(int, input().split())) for _ in range(H)]
 
#差分だけで良い，これを*1 or -1していく
diff = [[0]*W for _ in range(H)]
for i in range(H):
    for j in range(W):
        diff[i][j] = abs(A[i][j] - B[i][j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
K = 6401 #適当
kk = int((K-1)/2)
dp = [[[False]*K for _ in range(W)] for _ in range(H)]
 
dp[0][0][kk+diff[0][0]] = True
dp[0][0][kk-diff[0][0]] = True
 

for i in range(H):
    for j in range(W):
        a= min((i+j)*80,K)
        for k in range(kk-a,kk+a):
            if i-1>=0:
                if k+diff[i][j]<K:
                    if dp[i-1][j][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i-1][j][k-diff[i][j]]:
                        dp[i][j][k] =True
            if j-1>=0:
                if k+diff[i][j]<K:
                    if dp[i][j-1][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i][j-1][k-diff[i][j]]:
                        dp[i][j][k] =True
ans = K


for k in range(K):
    if dp[H-1][W-1][k]:
        ans = min(ans,abs(k-kk))
print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
#dp[i][j]にはkという数字にたどり着けるかどうかを示す2進数を入れる

dp = [[False]*W for _ in range(H)]
ofs = 80*(H+W)


dp[0][0]=(1<<(ofs+diff[0][0]) | 1>>(ofs-diff[0][0]))
 
for i in range(H):
    for j in range(W):
        if i>0:
            dp[i][j]|=(dp[i-1][j]<<diff[i][j] | dp[i-1][j]>>diff[i][j])
        if j>0:
            dp[i][j]|=(dp[i][j-1]<<diff[i][j] | dp[i][j-1]>>diff[i][j])


#0のところから見て，最初に1が出てきたところが答え
for k in range(ofs):
    if (dp[-1][-1]>>(k+ofs)&1):
        print(k)
        break

Buggy python submission (verdict: Time Limit Exceeded):
H,W = map(int,input().split())
A = [list(map(int, input().split())) for _ in range(H)]
B = [list(map(int, input().split())) for _ in range(H)]

#差分だけで良い，これを*1 or -1していく
diff = [[0]*W for _ in range(H)]
for i in range(H):
    for j in range(W):
        diff[i][j] = abs(A[i][j] - B[i][j])

#i,jマスにおいて，偏りがkになれるかどうかでDP
K = 4001 #適当
kk = int((K-1)/2)
dp = [[[False]*K for _ in range(W)] for _ in range(H)]

dp[0][0][kk+diff[0][0]] = True
dp[0][0][kk-diff[0][0]] = True

                 

for i in range(H):
    for j in range(W):
        for k in range(K):
            if i-1>=0:
                if k+diff[i][j]<K:
                    if dp[i-1][j][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i-1][j][k-diff[i][j]]:
                        dp[i][j][k] =True
            if j-1>=0:
                if k+diff[i][j]<K:
                    if dp[i][j-1][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i][j-1][k-diff[i][j]]:
                        dp[i][j][k] =True

ans = K
for k in range(K):
    if dp[H-1][W-1][k]:
        ans = min(ans,abs(k-kk))

print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
#dp[i][j]にはkという数字にたどり着けるかどうかを示す2進数を入れる

dp = [[False]*W for _ in range(H)]
ofs = 80*(H+W)


dp[0][0]=(1<<(ofs+diff[0][0]) | 1>>(ofs-diff[0][0]))
 
for i in range(H):
    for j in range(W):
        if i>0:
            dp[i][j]|=(dp[i-1][j]<<diff[i][j] | dp[i-1][j]>>diff[i][j])
        if j>0:
            dp[i][j]|=(dp[i][j-1]<<diff[i][j] | dp[i][j-1]>>diff[i][j])


#0のところから見て，最初に1が出てきたところが答え
for k in range(ofs):
    if (dp[-1][-1]>>(k+ofs)&1):
        print(k)
        break

Buggy python submission (verdict: Time Limit Exceeded):
H,W = map(int,input().split())
A = [list(map(int, input().split())) for _ in range(H)]
B = [list(map(int, input().split())) for _ in range(H)]


#差分だけで良い，これを*1 or -1していく
diff = [[0]*W for _ in range(H)]
for i in range(H):
    for j in range(W):
        diff[i][j] = abs(A[i][j] - B[i][j])

#i,jマスにおいて，偏りがkになれるかどうかでDP
K = 6401 #適当,[-3200,3200]
kk = int((K-1)/2)
dp = [[[False]*K for _ in range(W)] for _ in range(H)]

dp[0][0][kk+diff[0][0]] = True
dp[0][0][kk-diff[0][0]] = True

for i in range(H):
    for j in range(W):
        for k in range(K):
            if i-1>=0:
                if k+diff[i][j]<K:
                    if dp[i-1][j][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i-1][j][k-diff[i][j]]:
                        dp[i][j][k] =True
            if j-1>=0:
                if k+diff[i][j]<K:
                    if dp[i][j-1][k+diff[i][j]]:
                        dp[i][j][k] =True
                if k-diff[i][j]>=0:
                    if dp[i][j-1][k-diff[i][j]]:
                        dp[i][j][k] =True

ans = K
for k in range(K):
    if dp[H-1][W-1][k]:
        ans = min(ans,abs(k-kk))

print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

H,W = map(int,input().split())
#差分だけで良い，これを*1 or -1していく
diff = [list(map(int, input().split())) for _ in range(H)]

for i in range(H):
    B = list(map(int,input().split()))
    for j in range(W):
        diff[i][j] = abs(diff[i][j] - B[j])
        
 # i,jマスにおいて，偏りがkになれるかどうかでDP
#dp[i][j]にはkという数字にたどり着けるかどうかを示す2進数を入れる

dp = [[False]*W for _ in range(H)]
ofs = 80*(H+W)


dp[0][0]=(1<<(ofs+diff[0][0]) | 1>>(ofs-diff[0][0]))
 
for i in range(H):
    for j in range(W):
        if i>0:
            dp[i][j]|=(dp[i-1][j]<<diff[i][j] | dp[i-1][j]>>diff[i][j])
        if j>0:
            dp[i][j]|=(dp[i][j-1]<<diff[i][j] | dp[i][j-1]>>diff[i][j])


#0のところから見て，最初に1が出てきたところが答え
for k in range(ofs):
    if (dp[-1][-1]>>(k+ofs)&1):
        print(k)
        break