Buggy python submission (verdict: Time Limit Exceeded):
class UnionFind():
   def __init__(self, n):
       self.n = n
       self.parents = [-1] * n

   def find(self, x):
       if self.parents[x] < 0:
           return x
       else:
           self.parents[x] = self.find(self.parents[x])
           return self.parents[x]

   def union(self, x, y):
       x = self.find(x)
       y = self.find(y)

       if x == y:
           return

       if self.parents[x] > self.parents[y]:
           x, y = y, x

       self.parents[x] += self.parents[y]
       self.parents[y] = x

   def size(self, x):
       return -self.parents[self.find(x)]

   def same(self, x, y):
       return self.find(x) == self.find(y)

   def members(self, x):
       root = self.find(x)
       return [i for i in range(self.n) if self.find(i) == root]

   def roots(self):
       return [i for i, x in enumerate(self.parents) if x < 0]

   def group_count(self):
       return len(self.roots())

   def all_group_members(self):
       return {r: self.members(r) for r in self.roots()}

   def __str__(self):
       return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())

n,k,l = map(int,input().split())
uf1 = UnionFind(n)
uf2 = UnionFind(n)

for _ in range(k):
   p,q = map(int,input().split())
   p -= 1
   q -= 1
   uf1.union(p,q)

for _ in range(l):
   r,s = map(int,input().split())
   r -= 1
   s -= 1
   uf2.union(r,s)

pair = []
for i in range(n):
   pair.append((uf1.find(i), uf2.find(i)))

for i in range(n):
   print(pair.count(pair[i]))

Fixed submission:
class UnionFind():
   def __init__(self, n):
       self.n = n
       self.parents = [-1] * n

   def find(self, x):
       if self.parents[x] < 0:
           return x
       else:
           self.parents[x] = self.find(self.parents[x])
           return self.parents[x]

   def union(self, x, y):
       x = self.find(x)
       y = self.find(y)

       if x == y:
           return

       if self.parents[x] > self.parents[y]:
           x, y = y, x

       self.parents[x] += self.parents[y]
       self.parents[y] = x

   def size(self, x):
       return -self.parents[self.find(x)]

   def same(self, x, y):
       return self.find(x) == self.find(y)

   def members(self, x):
       root = self.find(x)
       return [i for i in range(self.n) if self.find(i) == root]

   def roots(self):
       return [i for i, x in enumerate(self.parents) if x < 0]

   def group_count(self):
       return len(self.roots())

   def all_group_members(self):
       return {r: self.members(r) for r in self.roots()}

   def __str__(self):
       return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())

n,k,l = map(int,input().split())
uf1 = UnionFind(n)
uf2 = UnionFind(n)

for _ in range(k):
   p,q = map(int,input().split())
   p -= 1
   q -= 1
   uf1.union(p,q)

for _ in range(l):
   r,s = map(int,input().split())
   r -= 1
   s -= 1
   uf2.union(r,s)

from collections import defaultdict
dic = defaultdict(int)
pair = []
for i in range(n):
   pair.append((uf1.find(i), uf2.find(i)))
   dic[(uf1.find(i), uf2.find(i))] += 1

for i in range(n):
   print(dic[pair[i]])

Buggy python submission (verdict: Time Limit Exceeded):
class UnionFind():
   def __init__(self, n):
       self.n = n
       self.parents = [-1] * n

   def find(self, x):
       if self.parents[x] < 0:
           return x
       else:
           self.parents[x] = self.find(self.parents[x])
           return self.parents[x]

   def union(self, x, y):
       x = self.find(x)
       y = self.find(y)

       if x == y:
           return

       if self.parents[x] > self.parents[y]:
           x, y = y, x

       self.parents[x] += self.parents[y]
       self.parents[y] = x

   def size(self, x):
       return -self.parents[self.find(x)]

   def same(self, x, y):
       return self.find(x) == self.find(y)

   def members(self, x):
       root = self.find(x)
       return [i for i in range(self.n) if self.find(i) == root]

   def roots(self):
       return [i for i, x in enumerate(self.parents) if x < 0]

   def group_count(self):
       return len(self.roots())

   def all_group_members(self):
       return {r: self.members(r) for r in self.roots()}

   def __str__(self):
       return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())

n,k,l = map(int,input().split())
uf1 = UnionFind(n)
uf2 = UnionFind(n)

for _ in range(k):
   p,q = map(int,input().split())
   p -= 1
   q -= 1
   uf1.union(p,q)

for _ in range(l):
   r,s = map(int,input().split())
   r -= 1
   s -= 1
   uf2.union(r,s)

for i in range(n):
   print(len(set(uf1.members(i)) & set(uf2.members(i))))

Fixed submission:
class UnionFind():
   def __init__(self, n):
       self.n = n
       self.parents = [-1] * n

   def find(self, x):
       if self.parents[x] < 0:
           return x
       else:
           self.parents[x] = self.find(self.parents[x])
           return self.parents[x]

   def union(self, x, y):
       x = self.find(x)
       y = self.find(y)

       if x == y:
           return

       if self.parents[x] > self.parents[y]:
           x, y = y, x

       self.parents[x] += self.parents[y]
       self.parents[y] = x

   def size(self, x):
       return -self.parents[self.find(x)]

   def same(self, x, y):
       return self.find(x) == self.find(y)

   def members(self, x):
       root = self.find(x)
       return [i for i in range(self.n) if self.find(i) == root]

   def roots(self):
       return [i for i, x in enumerate(self.parents) if x < 0]

   def group_count(self):
       return len(self.roots())

   def all_group_members(self):
       return {r: self.members(r) for r in self.roots()}

   def __str__(self):
       return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())

n,k,l = map(int,input().split())
uf1 = UnionFind(n)
uf2 = UnionFind(n)

for _ in range(k):
   p,q = map(int,input().split())
   p -= 1
   q -= 1
   uf1.union(p,q)

for _ in range(l):
   r,s = map(int,input().split())
   r -= 1
   s -= 1
   uf2.union(r,s)

from collections import defaultdict
dic = defaultdict(int)
pair = []
for i in range(n):
   pair.append((uf1.find(i), uf2.find(i)))
   dic[(uf1.find(i), uf2.find(i))] += 1

for i in range(n):
   print(dic[pair[i]])