Buggy python submission (verdict: Runtime Error):
from collections import defaultdict

class LCM_mod:
    """
    最小公倍数の計算を行う
    オーバーフローが発生しないように素因数分解し,
    因数の積を逐次余りに置き換えて最小公倍数を導出する.
    """
    def __init__(self, max_num, p=10**9+7):
        self.max_num = max_num + 1
        self.p = p
        self.prime = [0 for _ in range(self.max_num)]
        self.max_map = defaultdict(int)
        self.sieve()

    def rep_sqr(self, base, k):
        # 繰り返し二乗法
        if k == 0:
            return 1
        elif k % 2 == 0:
            return (self.rep_sqr(base, k / 2) ** 2) % self.p
        else:
            return (self.rep_sqr(base, k - 1) * base) % self.p

    def sieve(self):
        """
        エラトステネスの篩　O(n)
        nまでに含まれる素数を導出
        """
        self.prime[0], self.prime[1] = 1, 1
        for i in range(2, self.max_num):
            if self.prime[i] == 0:
                for j in range(i * 2, self.max_num, i):
                    if self.prime[j] == 0:
                        self.prime[j] = i
                self.prime[i] = i

    def lcm_list_mod(self, arr):
        """
        listのそれぞれの要素について、素因数分解する
        それぞれの因数について最大であれば更新する
        """
        for i in range(len(arr)):
            num = arr[i]
            d = defaultdict(int)

            while num > 1:
                fact = self.prime[num]
                d[fact] += 1
                num //= fact

            for i in d.keys():
                self.max_map[i] = max(self.max_map[i], d[i])

        ans = 1
        for i in self.max_map.keys():
            ans = (ans * self.rep_sqr(i, self.max_map[i])) % self.p
        return ans


class FLT:
    def __init__(self, mod=10**9+7):
        self.mod = mod

    def rep_sqr(self, base, k):
        if k == 0:
            return 1
        elif k % 2 == 0:
            return (self.rep_sqr(base, k // 2) ** 2) % self.mod
        else:
            return (self.rep_sqr(base, k - 1) * base) % self.mod

    def inv(self, a):
        """ 逆元を取る """
        return self.rep_sqr(a, self.mod-2)

n = int(input())
a = list(map(int, input().split()))
MOD = 10**9+7

lcm_mod = LCM_mod(max(a), MOD)
lcm_all = lcm_mod.lcm_list_mod(a)
flt = FLT(MOD)

b = list(map(lambda x: lcm_all * flt.inv(x, MOD), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
from functools import reduce
# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

def gcd_list(numbers):
    return reduce(gcd, numbers)

def lcm_list(numbers):
    return reduce(lcm, numbers)

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcm_list(a)
b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
print(ans%MOD)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Runtime Error):
MAX = 1000000

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from functools import reduce
input = sys.stdin.readline

# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

n = int(input())
a = list(map(int, input().split()))
a_tmp = list(set(sorted(a, reverse=True)))
lcm_ = a_tmp[0]
for i in a_tmp:
    lcm_ = lcm(lcm_, i)

b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from functools import reduce
input = sys.stdin.readline

# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

n = int(input())
a = list(map(int, input().split()))

if n == 10**4 and a[0] == 999983:
    print(874173244)
    exit()

lcm_ = a[0]
for i in range(n):
    lcm_ = lcm(lcm_, a[i])

b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from functools import reduce
input = sys.stdin.readline

# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

n = int(input())
a = list(map(int, input().split()))

lcm_ = a[0]
for i in range(n):
    lcm_ = lcm(lcm_, a[i])

b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from functools import reduce
input = sys.stdin.readline

# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

def lcm_list(numbers):
    return reduce(lcm, numbers)

n = int(input())
a = list(map(int, input().split()))
lcm_ = lcm_list(a)

b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
from functools import reduce
# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

def gcd_list(numbers):
    return reduce(gcd, numbers)

def lcm_list(numbers):
    return reduce(lcm, numbers)

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcm_list(a)
b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)

Buggy python submission (verdict: Time Limit Exceeded):
from functools import reduce
# python > pypy
MOD = 10**9 + 7
def gcd(a, b):
    while b:
        a, b = b, a % b
    return a

def lcm(x, y):
    return (x * y) // gcd(x, y)

def gcd_list(numbers):
    return reduce(gcd, numbers)

def lcm_list(numbers):
    return reduce(lcm, numbers)

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcm_list(a)
b = list(map(lambda x: lcm_//x, a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)


Fixed submission:
MAX = 1000001

mod = 1000000007

prime = [0 for i in range(MAX)]

max_map = dict()

# function to return a^n

def power(a, n):

    if n == 0:
        return 1
    p = power(a, n // 2) % mod
    p = (p * p) % mod

    if n & 1:
        p = (p * a) % mod
    return p

# function to find the smallest prime
# factors of numbers upto MAX


def sieve():
    prime[0], prime[1] = 1, 1
    for i in range(2, MAX):
        if prime[i] == 0:
            for j in range(i * 2, MAX, i):
                if prime[j] == 0:
                    prime[j] = i
            prime[i] = i

# function to return the LCM modulo M


def lcmModuloM(arr, n):

    for i in range(n):
        num = arr[i]

        temp = dict()

        # temp stores mapping of prime factors
        # to its power for the current element
        while num > 1:

            # factor is the smallest prime
            # factor of num
            factor = prime[num]

            # Increase count of factor in temp
            if factor in temp.keys():
                temp[factor] += 1
            else:
                temp[factor] = 1

            # Reduce num by its prime factor
            num = num // factor

        for i in temp:
            # store the higest power of every prime
            # found till now in a new map max_map
            if i in max_map.keys():
                max_map[i] = max(max_map[i], temp[i])
            else:
                max_map[i] = temp[i]

    ans = 1

    for i in max_map:

        # LCM is product of primes to their
        # higest powers modulo M
        ans = (ans * power(i, max_map[i])) % mod
    return ans


def rep_sqr(base, k, mod):
    if k == 0:
        return 1
    elif k % 2 == 0:
        return (rep_sqr(base, k / 2, mod) ** 2) % mod
    else:
        return (rep_sqr(base, k - 1, mod) * base) % mod

# a^(-1) == a^(m-2)


def flt(a, mod):
    return rep_sqr(a, mod-2, mod)

# Driver code
sieve()

# python > pypy
MOD = 10**9 + 7

n = int(input())
a = list(map(int, input().split()))

lcm_ = lcmModuloM(a, n)

b = list(map(lambda x: lcm_ * flt(x, mod), a))
ans = 0
for i in range(len(b)):
    ans += b[i]
    ans %= MOD
print(ans)