Buggy python submission (verdict: Time Limit Exceeded):
from itertools import accumulate
n, k = map(int, input().split())
As = list(map(int, input().split()))

acc = [0]+list(accumulate(As))
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 計算
now = 0
for d in range(40,-1,-1):
    cnt = 0
    for s in sums:
        # 上から見て、bitが立っている数がk個以上かどうか
        # 最上位がkこ未満だったら、そのbitはもう使わない
        # 1000 -> 1100 -> 1100 -> 1101 みたいな絞り込み
        if s & (now|(1<<d)) == now|(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now |= 1<<d
print(now)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import accumulate
n, k = map(int, input().split())
As = list(map(int, input().split()))

acc = [0]+list(accumulate(As))
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 計算
ans = 0
now = 0
for d in range(40,-1,-1):
    cnt = 0
    for s in sums:
        # 上から見て、bitが立っている数がk個以上かどうか
        # 最上位がkこ未満だったら、そのbitはもう使わない
        # 1000 -> 1100 -> 1100 -> 1101 みたいな絞り込み
        if s & (now|(1<<d)) == now|(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now |= 1<<d
print(now)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import accumulate
n, k = map(int, input().split())
As = list(map(int, input().split()))

acc = [0]+list(accumulate(As))
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 計算
ans = 0
now = 0
for d in range(40,-1,-1):
    cnt = 0
    for s in sums:
        # 上から見て、bitが立っている数がkこ以上かどうか
        # 1000 -> 1100 -> 1100 -> 1101 みたいな絞り込み
        # 何故か、
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Buggy python submission (verdict: Time Limit Exceeded):
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Buggy python submission (verdict: Time Limit Exceeded):
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        # print(i,j,s)
        sums.append(s)
        for d in range(50):
            if s & (1<<d):        
                dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

ex = [a for a in sums if a&(1<<mx)]
ans = 0
from itertools import combinations
for l in combinations(ex, k):
    ret = l[0]
    for e in l[1:]:
        ret &= e
    ans = max(ret, ans)
print(ans)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)

Buggy python submission (verdict: Time Limit Exceeded):
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        # print(i,j,s)
        sums.append(s)
        for d in range(50):
            if s & (1<<d):        
                dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

ex = [a for a in sums if a&(1<<mx)]
ans = 0
from itertools import combinations
for l in combinations(ex, k):
    ret = l[0]
    for e in l[1:]:
        ret &= e
    ans = max(ret, ans)
print(ans)

Fixed submission:
n, k = map(int, input().split())
As = list(map(int, input().split()))

from itertools import accumulate
acc = [0]+list(accumulate(As))
dp = [0] * 50
mx = 0
sums = []
for i in range(n+1):
    for j in range(i+1,n+1):
        s = acc[j]-acc[i]
        sums.append(s)

# 最大の桁数
for d in range(50):
    if max(sums) & (1<<d):
        mx = max(mx, d)
        dp[d] += 1
mx = 0
for i in range(50):
    if dp[i] >= k:
        mx = max(mx,i)

# 計算
ans = 0
now = 0
for d in range(50,-1,-1):
    cnt = 0
    for s in sums:
        if s & (now+(1<<d)) == now+(1<<d):
            cnt += 1
    # print(d,cnt)
    if cnt >= k:
        now += 1<<d
print(now)