Buggy python submission (verdict: Runtime Error):
def main():
    a,b=map(lambda x: set(prime_factorize(int(x))),input().split())
    print(len(a&b)+1)

@lru_cache(maxsize=None)
def primes(n:int) -> list:
    '''n以下の全素数をlistで返す'''
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

# 素数判定（単純な素数判定なら十分早い。大量にやる場合はX in primesがよさそう）
@lru_cache(maxsize=None)
def is_prime(n: int) -> bool:
    '''引数nが素数であればTrue、そうでなければFalseを返す'''
    if n == 1:
        return False
    elif n == 2:
        return True
    elif n % 2 == 0:
        return False
    
    for i in range(3, int(n**0.5)+1, 2):
        if n % i == 0:
            return False
    return True

# 素因数分解
@lru_cache(maxsize=None)
def prime_factorize(n: int) -> list:
    '''引数nの素因数分解結果のlistを返す。'''
    arr = []
    # 2で割り続け奇数まで還元する
    while n % 2 == 0:
        arr.append(2)
        n //= 2
    # sqrt(n)までの素数で試し割
    for f in primes(int(n**0.5)):
        while n % f == 0:
            arr.append(f)
            n //= f
    if n != 1:
        arr.append(n)
    return arr

#約数リスト
def make_divisors(n: int) -> list:
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]
        
if __name__ == "__main__":
    main()

Fixed submission:
from functools import lru_cache

def main():
    a,b=map(lambda x: set(prime_factorize(int(x))),input().split())
    print(len(a&b)+1)

@lru_cache(maxsize=None)
def primes(n:int) -> list:
    '''n以下の全素数をlistで返す'''
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

# 素数判定（単純な素数判定なら十分早い。大量にやる場合はX in primesがよさそう）
@lru_cache(maxsize=None)
def is_prime(n: int) -> bool:
    '''引数nが素数であればTrue、そうでなければFalseを返す'''
    if n == 1:
        return False
    elif n == 2:
        return True
    elif n % 2 == 0:
        return False
    
    for i in range(3, int(n**0.5)+1, 2):
        if n % i == 0:
            return False
    return True

# 素因数分解
@lru_cache(maxsize=None)
def prime_factorize(n: int) -> list:
    '''引数nの素因数分解結果のlistを返す。'''
    arr = []
    # 2で割り続け奇数まで還元する
    while n % 2 == 0:
        arr.append(2)
        n //= 2
    # sqrt(n)までの素数で試し割
    for f in primes(int(n**0.5)):
        while n % f == 0:
            arr.append(f)
            n //= f
    if n != 1:
        arr.append(n)
    return arr

#約数リスト
def make_divisors(n: int) -> list:
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]
        
if __name__ == "__main__":
    main()

Buggy python submission (verdict: Time Limit Exceeded):
def make_divisors(n):
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]

import itertools
import math
def main():
    a,b=map(int,input().split())
    x=[y for y in make_divisors(a) if b%y==0]
    ans = 0
    for e in itertools.product([0,1], repeat=len(x)):
        t = [x[i] for i,v in enumerate(e) if v==1]
        for i, j in itertools.combinations(t, 2):
            if math.gcd(i, j) != 1:
                break
        else:
            ans = max(ans, e.count(1))
    print(ans)
                
if __name__ == "__main__":
    main()

Fixed submission:
from functools import lru_cache

def main():
    a,b=map(lambda x: set(prime_factorize(int(x))),input().split())
    print(len(a&b)+1)

@lru_cache(maxsize=None)
def primes(n:int) -> list:
    '''n以下の全素数をlistで返す'''
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

# 素数判定（単純な素数判定なら十分早い。大量にやる場合はX in primesがよさそう）
@lru_cache(maxsize=None)
def is_prime(n: int) -> bool:
    '''引数nが素数であればTrue、そうでなければFalseを返す'''
    if n == 1:
        return False
    elif n == 2:
        return True
    elif n % 2 == 0:
        return False
    
    for i in range(3, int(n**0.5)+1, 2):
        if n % i == 0:
            return False
    return True

# 素因数分解
@lru_cache(maxsize=None)
def prime_factorize(n: int) -> list:
    '''引数nの素因数分解結果のlistを返す。'''
    arr = []
    # 2で割り続け奇数まで還元する
    while n % 2 == 0:
        arr.append(2)
        n //= 2
    # sqrt(n)までの素数で試し割
    for f in primes(int(n**0.5)):
        while n % f == 0:
            arr.append(f)
            n //= f
    if n != 1:
        arr.append(n)
    return arr

#約数リスト
def make_divisors(n: int) -> list:
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]
        
if __name__ == "__main__":
    main()

Buggy python submission (verdict: Time Limit Exceeded):
import itertools
import fractions as math

def make_divisors(n):
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]

def main():
    a, b = map(int, input().split())
    k = []
    for i in make_divisors(a):
        if i > b:
            break
        elif b % i == 0:
            k.append(i)
    count = 0
    for i in itertools.product([0,1], repeat=len(k)):
        if i.count(1) < 1:
            continue
        l = [k[j[0]] for j in enumerate(i) if j[1] == 1]
        for x, y in itertools.combinations(l, 2):
            if math.gcd(x, y) != 1:
                break
        else:
            count = max(count, len(l))
    print(count)
                
if __name__ == '__main__':
    main()

Fixed submission:
from functools import lru_cache

def main():
    a,b=map(lambda x: set(prime_factorize(int(x))),input().split())
    print(len(a&b)+1)

@lru_cache(maxsize=None)
def primes(n:int) -> list:
    '''n以下の全素数をlistで返す'''
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

# 素数判定（単純な素数判定なら十分早い。大量にやる場合はX in primesがよさそう）
@lru_cache(maxsize=None)
def is_prime(n: int) -> bool:
    '''引数nが素数であればTrue、そうでなければFalseを返す'''
    if n == 1:
        return False
    elif n == 2:
        return True
    elif n % 2 == 0:
        return False
    
    for i in range(3, int(n**0.5)+1, 2):
        if n % i == 0:
            return False
    return True

# 素因数分解
@lru_cache(maxsize=None)
def prime_factorize(n: int) -> list:
    '''引数nの素因数分解結果のlistを返す。'''
    arr = []
    # 2で割り続け奇数まで還元する
    while n % 2 == 0:
        arr.append(2)
        n //= 2
    # sqrt(n)までの素数で試し割
    for f in primes(int(n**0.5)):
        while n % f == 0:
            arr.append(f)
            n //= f
    if n != 1:
        arr.append(n)
    return arr

#約数リスト
def make_divisors(n: int) -> list:
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]
        
if __name__ == "__main__":
    main()

Buggy python submission (verdict: Runtime Error):
import math
import itertools

def make_divisors(n):
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]

def main():
    a, b = map(int, input().split())
    k = []
    for i in make_divisors(a):
        if i > b:
            break
        elif b % i == 0:
            k.append(i)
    count = 0
    for i in itertools.product([0,1], repeat=len(k)):
        if i.count(1) < 1:
            continue
        l = [k[j[0]] for j in enumerate(i) if j[1] == 1]
        for x, y in itertools.combinations(l, 2):
            if math.gcd(x, y) != 1:
                break
        else:
            count = max(count, len(l))
    print(count)
                
if __name__ == '__main__':
    main()

Fixed submission:
from functools import lru_cache

def main():
    a,b=map(lambda x: set(prime_factorize(int(x))),input().split())
    print(len(a&b)+1)

@lru_cache(maxsize=None)
def primes(n:int) -> list:
    '''n以下の全素数をlistで返す'''
    is_prime = [True] * (n + 1)
    is_prime[0] = False
    is_prime[1] = False
    for i in range(2, int(n**0.5) + 1):
        if not is_prime[i]:
            continue
        for j in range(i * 2, n + 1, i):
            is_prime[j] = False
    return [i for i in range(n + 1) if is_prime[i]]

# 素数判定（単純な素数判定なら十分早い。大量にやる場合はX in primesがよさそう）
@lru_cache(maxsize=None)
def is_prime(n: int) -> bool:
    '''引数nが素数であればTrue、そうでなければFalseを返す'''
    if n == 1:
        return False
    elif n == 2:
        return True
    elif n % 2 == 0:
        return False
    
    for i in range(3, int(n**0.5)+1, 2):
        if n % i == 0:
            return False
    return True

# 素因数分解
@lru_cache(maxsize=None)
def prime_factorize(n: int) -> list:
    '''引数nの素因数分解結果のlistを返す。'''
    arr = []
    # 2で割り続け奇数まで還元する
    while n % 2 == 0:
        arr.append(2)
        n //= 2
    # sqrt(n)までの素数で試し割
    for f in primes(int(n**0.5)):
        while n % f == 0:
            arr.append(f)
            n //= f
    if n != 1:
        arr.append(n)
    return arr

#約数リスト
def make_divisors(n: int) -> list:
    lower_divisors , upper_divisors = [], []
    i = 1
    while i*i <= n:
        if n % i == 0:
            lower_divisors.append(i)
            if i != n // i:
                upper_divisors.append(n//i)
        i += 1
    return lower_divisors + upper_divisors[::-1]
        
if __name__ == "__main__":
    main()