Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        power = 1
        for s in S[::-1]:
            ints += int(s) * power
            r = ints % P
            rcounts[r] += 1
            power *= 10
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        for i in range(len(S)):
            s = int(S[i:N])
            r = s % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            if v > 1:
                c += v*(v-1)//2
        return c
    print(solve(N, P, S))


Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        for i in range(len(S)):
            s = int(S[i:N])
            r = s % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            if v > 1:
                c += v*(v-1)//2
        return c
    print(solve(N, P, S))


Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        dicmodp = {}
        dicmodp[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        for i in range(len(S)):
            s = int(S[i:N])
            r = s % P
            dicmodp.setdefault(r, 0)
            dicmodp[r] += 1
        c = 0
        for k, v in dicmodp.items():
            if v > 1:
                c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    c = 0
    for i in range(N-1, -1, -1):
        if int(S[i]) % P == 0:
            # 以降桁を増やしてもOK
            c += i+1
    print(c)
else:
    dicmodp = {}
    dicmodp[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
    for i in range(len(S)):
        s = int(S[i:N])
        r = s % P
        dicmodp.setdefault(r, 0)
        dicmodp[r] += 1
    c = 0
    for k, v in dicmodp.items():
        if v > 1:
            c += v*(v-1)//2
    print(c)

Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()
lenp = len(str(P))
c = 0

if P == 2 or P == 5:
    c = 0
    for i in range(N-1, -1, -1):
        if int(S[i]) % P == 0:
            # それ以降桁を増やしてもOK
            c += i+1
    print(c)
else:
    S = [int(S[i:N]) for i, s in enumerate(tuple(S))]

    dicmodp = {}
    dicmodp[0] = 1
    for s in S:
        r = s % P
        dicmodp.setdefault(r, 0)
        dicmodp[r] += 1
    c = 0
    for k, v in dicmodp.items():
        if v > 1:
            c += v*(v-1)//2
    print(c)


Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))

Buggy python submission (verdict: Time Limit Exceeded):
N, P = map(int, input().split())
S = input()
c = 0
for i in range(N):
    for j in range(i+1, N+1):
        s = S[i:j]
        c += (int(s) % P == 0)
print(c)

Fixed submission:
N, P = map(int, input().split())
S = input()

if P == 2 or P == 5:
    def solve25(N, P, S):
        c = 0
        for i in range(N-1, -1, -1):
            if int(S[i]) % P == 0:
                # 以降桁を増やしてもOK
                c += i+1
        return c
    print(solve25(N, P, S))
else:
    def solve(N, P, S):
        rcounts = [0] * P
        rcounts[0] = 1 # sそのものが割り切れた場合に引き算する相手がいないから
        ints = 0
        for i, s in enumerate(S[::-1]):
            ints += int(s) * pow(10, i, P)
            r = ints % P
            rcounts[r] += 1
        c = 0
        for v in rcounts:
            c += v*(v-1)//2
        return c
    print(solve(N, P, S))