Buggy python submission (verdict: Time Limit Exceeded):
def upperbound(nums, value):
    low = 0
    high = len(nums)
    while low < high:
        mid = (low + high) >> 1
        if value > nums[mid]:
            low = mid + 1
        else:
            high = mid
    return low


n = int(input())
ar = list(map(int, input().split()))
ar.sort()
total = 0
for i in range(n):
    for j in range(i + 1, n):
        sum2edge = ar[i] + ar[j]
        index = upperbound(ar, sum2edge)
        if index > j:
            total += (index - j - 1)
print(total)

Fixed submission:
def findnumberofTriangles(arr): 
  
    # Sort array and initialize count as 0 
    n = len(arr) 
    arr.sort() 
    count = 0
  
    # Fix the first element. We need to run till n-3 as 
    # the other two elements are selected from arr[i+1...n-1] 
    for i in range(0,n-2): 
  
        # Initialize index of the rightmost third element 
        k = i + 2
  
        # Fix the second element 
        for j in range(i+1,n): 
  
            # Find the rightmost element which is smaller 
            # than the sum of two fixed elements 
            # The important thing to note here is, we use 
            # the previous value of k. If value of arr[i] + 
            # arr[j-1] was greater than arr[k], then arr[i] + 
            # arr[j] must be greater than k, because the array 
            # is sorted. 
            while (k < n and arr[i] + arr[j] > arr[k]): 
                k += 1
  
            # Total number of possible triangles that can be 
            # formed with the two fixed elements is k - j - 1. 
            # The two fixed elements are arr[i] and arr[j]. All 
            # elements between arr[j+1] to arr[k-1] can form a 
            # triangle with arr[i] and arr[j]. One is subtracted 
            # from k because k is incremented one extra in above 
            # while loop. k will always be greater than j. If j 
            # becomes equal to k, then above loop will increment k, 
            # because arr[k] + arr[i] is always greater than arr[k] 
            if(k>j): 
                count += k - j - 1
  
    return count 

n = int(input())
ar = list(map(int, input().split()))
print(findnumberofTriangles(ar))

Buggy python submission (verdict: Time Limit Exceeded):
from itertools import combinations
n = int(input())
ar = list(map(int, input().split()))
total = 0
for a, b, c in combinations(ar, 3):
    if a + b > c and b + c > a and c + a > b:
        total += 1
print(total)

Fixed submission:
def findnumberofTriangles(arr): 
  
    # Sort array and initialize count as 0 
    n = len(arr) 
    arr.sort() 
    count = 0
  
    # Fix the first element. We need to run till n-3 as 
    # the other two elements are selected from arr[i+1...n-1] 
    for i in range(0,n-2): 
  
        # Initialize index of the rightmost third element 
        k = i + 2
  
        # Fix the second element 
        for j in range(i+1,n): 
  
            # Find the rightmost element which is smaller 
            # than the sum of two fixed elements 
            # The important thing to note here is, we use 
            # the previous value of k. If value of arr[i] + 
            # arr[j-1] was greater than arr[k], then arr[i] + 
            # arr[j] must be greater than k, because the array 
            # is sorted. 
            while (k < n and arr[i] + arr[j] > arr[k]): 
                k += 1
  
            # Total number of possible triangles that can be 
            # formed with the two fixed elements is k - j - 1. 
            # The two fixed elements are arr[i] and arr[j]. All 
            # elements between arr[j+1] to arr[k-1] can form a 
            # triangle with arr[i] and arr[j]. One is subtracted 
            # from k because k is incremented one extra in above 
            # while loop. k will always be greater than j. If j 
            # becomes equal to k, then above loop will increment k, 
            # because arr[k] + arr[i] is always greater than arr[k] 
            if(k>j): 
                count += k - j - 1
  
    return count 

n = int(input())
ar = list(map(int, input().split()))
print(findnumberofTriangles(ar))