Buggy python submission (verdict: Time Limit Exceeded):
n = int(input())
V = list(map(int, input().split()))

one = V[::2]
two = V[1:][::2]

one_count={}
one_len=len(one)
for o in one:
    if o in one_count:
        one_count[o] += 1
    else:
        one_count[o] = 1

for k,v in one_count.items():
    one_count[k] = one_len-v
one_count[10**6]=one_len

two_len=len(two)
two_count={}

for t in two:
    if t in two_count:
        two_count[t] += 1
    else:
        two_count[t] = 1

for k,v in two_count.items():
    two_count[k] = two_len-v
two_count[10**6]=two_len


mins = 1000000

for one_key, one_value in one_count.items():
    for two_key, two_value in two_count.items():
        if one_key != two_key:
            if (one_value + two_value) < mins:
                mins = one_value + two_value
print(mins)

Fixed submission:
import heapq

n = int(input())
V = list(map(int, input().split()))

one = V[::2]
two = V[1:][::2]

one,two

one_count={}
one_len=len(one)
for o in one:
    if o in one_count:
        one_count[o] += 1
    else:
        one_count[o] = 1

for k,v in one_count.items():
    one_count[k] = one_len-v
one_count[10**6]=one_len
temp = [[k,v] for k,v in one_count.items()]
one = heapq.nsmallest(3,temp, key=lambda x: x[1])


two_len=len(two)
two_count={}

for t in two:
    if t in two_count:
        two_count[t] += 1
    else:
        two_count[t] = 1

for k,v in two_count.items():
    two_count[k] = two_len-v
two_count[10**6]=two_len
temp = [[k,v] for k,v in two_count.items()]
two = heapq.nsmallest(3,temp, key=lambda x: x[1])

mins = 1000000

for [one_key, one_value] in one:
    for [two_key, two_value] in two:
        if one_key != two_key:
            if (one_value + two_value) < mins:
                mins = one_value + two_value
print(mins)

Buggy python submission (verdict: Runtime Error):
import heapq



n = int(input())
V = list(map(int, input().split()))

one = V[::2]
two = V[1:][::2]

one_count={}
one_len=len(one)
values={}
for o in one:
    if o in values:
        values[o] += 1
    else:
        values[o] = 1

one_count[10**6]=one_len
for k,v in values.items():
    one_count[k] = one_len-v


    
two_len=len(two)
two_count={}
values={}

for t in two:
    if o in values:
        values[t] += 1
    else:
        values[t] = 1

two_count[10**6]=two_len
for k,v in values.items():
    two_count[k] = two_len-v




keys = list(set(V))
mins = 1000

for one_key, one_value in one_count.items():
    for two_key, two_value in two_count.items():
        if one_key != two_key:
            if one_value + two_value < mins:
                mins = one_value + two_value
print(mins)

Fixed submission:
import heapq

n = int(input())
V = list(map(int, input().split()))

one = V[::2]
two = V[1:][::2]

one,two

one_count={}
one_len=len(one)
for o in one:
    if o in one_count:
        one_count[o] += 1
    else:
        one_count[o] = 1

for k,v in one_count.items():
    one_count[k] = one_len-v
one_count[10**6]=one_len
temp = [[k,v] for k,v in one_count.items()]
one = heapq.nsmallest(3,temp, key=lambda x: x[1])


two_len=len(two)
two_count={}

for t in two:
    if t in two_count:
        two_count[t] += 1
    else:
        two_count[t] = 1

for k,v in two_count.items():
    two_count[k] = two_len-v
two_count[10**6]=two_len
temp = [[k,v] for k,v in two_count.items()]
two = heapq.nsmallest(3,temp, key=lambda x: x[1])

mins = 1000000

for [one_key, one_value] in one:
    for [two_key, two_value] in two:
        if one_key != two_key:
            if (one_value + two_value) < mins:
                mins = one_value + two_value
print(mins)