Buggy python submission (verdict: Time Limit Exceeded):
import math
from collections import deque
S = input()
index = []
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        index.append(i - 1)
        index.append(i)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = []
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for r, l in zip(r_diff, l_diff):
    tmp_1 = math.ceil(r / 2)
    tmp_2 = math.ceil(l / 2)
    ans.append(tmp_1 + l - tmp_2)
    ans.append(r - tmp_1 + tmp_2)
q = deque(ans)    
answer = ""
for i in range(len(S)):
    if i in index:
        answer += str(q.popleft())
        answer += " "
    else:
        answer += "0 "
print(answer)        

Fixed submission:
import math
from collections import deque
S = input()
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = []
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for r, l in zip(r_diff, l_diff):
    tmp_1 = math.ceil(r / 2)
    tmp_2 = math.ceil(l / 2)
    ans.append(tmp_1 + l - tmp_2)
    ans.append(r - tmp_1 + tmp_2)
q = deque(ans)    
answer = ""

for i in range(len(S)):
    if 1 <= i <= len(S) - 2:
        if (S[i] == "L" and S[i - 1] == "R") or (S[i] == "R" and S[ i + 1] == "L"):
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == 0:
        if S[i + 1] == "L":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == len(S) - 1:
        if S[i - 1] == "R":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "

print(answer)

Buggy python submission (verdict: Time Limit Exceeded):
import math
from collections import deque
S = input()
index = []
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        index.append(i - 1)
        index.append(i)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = [0 for _ in range(len(index))] 
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for j, (r, l) in enumerate(zip(r_diff, l_diff)):
    tmp_1 = math.ceil(r / 2)
    tmp_2 = math.ceil(l / 2)
    ans[2 * j] += tmp_1 + l - tmp_2
    ans[2 * j + 1] += r - tmp_1 + tmp_2
q = deque(ans)    
for i in range(len(S)):
    if i in index:
        print(q.popleft(), end = " ")
    else:
        print(0, end =" ")

Fixed submission:
import math
from collections import deque
S = input()
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = []
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for r, l in zip(r_diff, l_diff):
    tmp_1 = math.ceil(r / 2)
    tmp_2 = math.ceil(l / 2)
    ans.append(tmp_1 + l - tmp_2)
    ans.append(r - tmp_1 + tmp_2)
q = deque(ans)    
answer = ""

for i in range(len(S)):
    if 1 <= i <= len(S) - 2:
        if (S[i] == "L" and S[i - 1] == "R") or (S[i] == "R" and S[ i + 1] == "L"):
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == 0:
        if S[i + 1] == "L":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == len(S) - 1:
        if S[i - 1] == "R":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "

print(answer)

Buggy python submission (verdict: Time Limit Exceeded):
import math
from collections import deque
S = input()
index = []
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        index.append(i - 1)
        index.append(i)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = [0 for _ in range(len(index))] 
hokan_index = []
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for j, (r, l) in enumerate(zip(r_diff, l_diff)):
    tmp = math.ceil(r / 2)
    ans[2 * j] += tmp
    ans[2 * j + 1] += r - tmp
    tmp = math.ceil(l / 2)
    ans[2 * j + 1] += tmp
    ans[2 * j] += l - tmp
q = deque(ans)    
answer = ""
for i in range(len(S)):
    if i in index:
        answer += str(q.popleft())
        answer += " "
    else:
        answer += "0 "
print(answer)        

Fixed submission:
import math
from collections import deque
S = input()
L_kyoukai = []
R_kyoukai = [0]
flag = False
for i in range(1, len(S)):
    if flag is False and S[i] == "L":
        L_kyoukai.append(i)
        R_kyoukai.append(i - 1)
        flag = True
    if flag is True and S[i] == "R":
        L_kyoukai.append(i - 1)
        R_kyoukai.append(i)
        flag = False
ans = []
L_kyoukai.append(len(S) - 1)
r_diff = [R_kyoukai[i + 1] - R_kyoukai[i] + 1 for i in range(0, len(R_kyoukai), 2)]
l_diff = [L_kyoukai[i + 1] - L_kyoukai[i] + 1 for i in range(0, len(L_kyoukai), 2)]
for r, l in zip(r_diff, l_diff):
    tmp_1 = math.ceil(r / 2)
    tmp_2 = math.ceil(l / 2)
    ans.append(tmp_1 + l - tmp_2)
    ans.append(r - tmp_1 + tmp_2)
q = deque(ans)    
answer = ""

for i in range(len(S)):
    if 1 <= i <= len(S) - 2:
        if (S[i] == "L" and S[i - 1] == "R") or (S[i] == "R" and S[ i + 1] == "L"):
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == 0:
        if S[i + 1] == "L":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "
    elif i == len(S) - 1:
        if S[i - 1] == "R":
            answer += str(q.popleft())
            answer += " "
        else:
            answer += "0 "

print(answer)