Buggy python submission (verdict: Runtime Error):
from collections import Counter
N = int(input())
A = list(map(int, input().split()))

if N % 3 != 0:
    ans = "Yes" if sum(A) == 0 else "No"
else:
    B = Counter(A)
    keys = tuple(B.keys())
    vals = tuple(B.values())
    if len(B) == 3:  # 3種類ならa^b^cかつNa==Nb==NCでおけ
        a, b, c = keys
        Na, Nb, Nc = vals
        if Na == Nb and Nb == Nc:
            a, b, c = keys
            ans = "No" if a ^ b ^ c else "Yes"
        else:
            ans = "No"
    elif len(B) == 2:  # 2種類なら、a^a==0かつb==0かつNa==2Nbでおけ
        a, b = keys
        Na, Nb = vals
        if a == 0:
            ans = "Yes" if Na == 2*Nb else "No"
        elif b == 0:
            ans = "Yes" if 2*Na == Nb else "No"
        else:
            ans = "No"
    elif len(B) == 1:
        a = keys[0]
        ans == "Yes" if a == 0 else "No"
    else:
        ans = "No"


print(ans)


Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int, input().split()))


def xor_circle(N, A):
    if sum(A) == 0:
        return "Yes"
    if N % 3 != 0:
        return "No"

    B = Counter(A)
    if len(B) == 3:
        a, b, c = B.keys()
        Na, Nb, Nc = B.values()
        if a ^ b ^ c == 0 and Na == Nb == Nc:
            return "Yes"
        else:
            return "No"
    elif len(B) == 2:
        a, b = B.keys()
        Na, Nb = B.values()
        if a == 0 and 2*Na == Nb:
            return "Yes"
        elif b == 0 and Na == 2*Nb:
            return "Yes"
        else:
            return "No"
    else:
        return "No"


ans = xor_circle(N, A)
print(ans)

Buggy python submission (verdict: Runtime Error):
from collections import Counter
N = int(input())
A = list(map(int, input().split()))

if N % 3 != 0:
    ans = "Yes" if sum(A) == 0 else "No"
else:
    B = Counter(A)
    keys = tuple(B.keys())
    vals = tuple(B.values())
    if len(B) == 3:  # 3種類ならa^b^cかつNa==Nb==NCでおけ
        a, b, c = keys
        Na, Nb, Nc = vals
        if Na == Nb and Nb == Nc:
            a, b, c = keys
            ans = "No" if a ^ b ^ c else "Yes"
        else:
            ans = "No"
    elif len(B) == 2:  # 2種類なら、a^a==0かつb==0かつNa==2Nbでおけ
        a, b = keys
        Na, Nb = vals
        if a == 0:
            ans = "Yes" if Na == 2*Nb else "No"
        elif b == 0:
            ans = "Yes" if 2*Na == Nb else "No"
        else:
            ans = "No"
    elif len(B) == 1:
        a = keys[0]
        ans == "Yes" if a == 0 else "No"


print(ans)


Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int, input().split()))


def xor_circle(N, A):
    if sum(A) == 0:
        return "Yes"
    if N % 3 != 0:
        return "No"

    B = Counter(A)
    if len(B) == 3:
        a, b, c = B.keys()
        Na, Nb, Nc = B.values()
        if a ^ b ^ c == 0 and Na == Nb == Nc:
            return "Yes"
        else:
            return "No"
    elif len(B) == 2:
        a, b = B.keys()
        Na, Nb = B.values()
        if a == 0 and 2*Na == Nb:
            return "Yes"
        elif b == 0 and Na == 2*Nb:
            return "Yes"
        else:
            return "No"
    else:
        return "No"


ans = xor_circle(N, A)
print(ans)