Buggy python submission (verdict: Runtime Error):
from math import gcd

"""
pairwise coprimeであるための条件は、全てのAに関して素因数に重複がないことである。
したがって、各Aに関して素因数分解を行う⇒各数の素因数の種類数をカウントし総和する。⇒全体の素因数の種類数をカウントし、先ほどの総和と比較する。
"""
N = int(input())
A = list(map(int,input().split()))
primes = set()
cnt = 0
for i in range(N):
    a = A[i]
    d = 2
    ceil = int(a**0.5)+1
    for d in range(2,ceil)
        if a % d == 0:
            cnt += 1
            primes.add(d)
            for _ in range(100):
                if a % d==0:
                    a //= d
                else:
                    break
        d += 1

if cnt == len(primes):
    print('pairwise coprime')
    exit()
g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print('setwise coprime')
else:
    print('not coprime')

Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int,input().split()))
countA = Counter(A)

#pairwiseかどうかを調べる
memo = [1]*(10**6+1)
memo[0] = 0
memo[1] = 0
for i in range(2,10**6+1):
    if memo[i] == 1:
        flag = False
        if i in countA:
            if countA[i] >= 2:
                break
            flag = True
        for j in range(i*2,10**6+1,i):
            if j in countA:
                if countA[j] >= 2:
                    break
                if flag:
                    break
                else:
                    flag = True
            memo[j] = 0
        else:
            continue
        break
else:
    print("pairwise coprime")
    exit()



#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")

Buggy python submission (verdict: Runtime Error):
from collections import Counter
N = int(input())
A = list(map(int,input().split()))
setA = set(A)

#pairwiseかどうかを調べる
memo = [1]*(10**6+1)
memo[0] = 0
memo[1] = 0
for i in range(2,10**6+1):
    if memo[i] == 1:
        flag = False
        if i in setA:
            flag = True
        for j in range(i*2,10**6+1,i):
            if j in setA:
                if flag:
                    break
                else:
                    flag = True
            memo[j] = 0
        else:
            continue
        break
elif len(setA) == len(A):
    print("pairwise coprime")
    exit()



#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")


Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int,input().split()))
countA = Counter(A)

#pairwiseかどうかを調べる
memo = [1]*(10**6+1)
memo[0] = 0
memo[1] = 0
for i in range(2,10**6+1):
    if memo[i] == 1:
        flag = False
        if i in countA:
            if countA[i] >= 2:
                break
            flag = True
        for j in range(i*2,10**6+1,i):
            if j in countA:
                if countA[j] >= 2:
                    break
                if flag:
                    break
                else:
                    flag = True
            memo[j] = 0
        else:
            continue
        break
else:
    print("pairwise coprime")
    exit()



#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")

Buggy python submission (verdict: Time Limit Exceeded):
from collections import Counter
N = int(input())
A = list(map(int,input().split()))

#pairwiseかどうかを調べる
primes = []
def primeFinder(n):
    memo = [1]*(n+1)
    memo[0] = 0
    memo[1] = 0
    for i in range(2,n+1):
        if memo[i] == 1:
            primes.append(i)
            for j in range(i*2,n+1,i):
                memo[j] = 0

primeFinder(10**6)
primes = {p:0 for p in primes}
"""
各Aiに関して素因数を算出。素因数を集計してカウントが2つある素因数がなければpairwise
"""
flag = True
for i in range(N):
    a = A[i]
    memo = []
    for d in primes.keys():
        if a%d == 0:
            memo.append(d)
            while a % d == 0:
                a //= d
    for d in memo:
      primes.pop(d)
    if a != 1:
        break
else:
    print("pairwise coprime")
    exit()


#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")


Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int,input().split()))
countA = Counter(A)

#pairwiseかどうかを調べる
memo = [1]*(10**6+1)
memo[0] = 0
memo[1] = 0
for i in range(2,10**6+1):
    if memo[i] == 1:
        flag = False
        if i in countA:
            if countA[i] >= 2:
                break
            flag = True
        for j in range(i*2,10**6+1,i):
            if j in countA:
                if countA[j] >= 2:
                    break
                if flag:
                    break
                else:
                    flag = True
            memo[j] = 0
        else:
            continue
        break
else:
    print("pairwise coprime")
    exit()



#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")

Buggy python submission (verdict: Time Limit Exceeded):
from collections import Counter
N = int(input())
A = list(map(int,input().split()))

primes = []
def primeFinder(n):
    memo = [1]*(n+1)
    memo[0] = 0
    memo[1] = 0
    for i in range(2,n+1):
        if memo[i] == 1:
            primes.append(i)
            for j in range(i*2,n+1,i):
                memo[j] = 0

primeFinder(10**6)
primeNums = primes
"""
各Aiに関して素因数を算出。素因数を集計してカウントが2つある素因数がなければpairwise
"""
count = Counter([])
for i in range(N):
    tmp = []
    a = A[i]
    i = 0
    while a != 1:
        d = primeNums[i]
        if a % d == 0:
            tmp.append(d)
        while a % d == 0:
            a //= d
        i += 1
    count += Counter(tmp)

for v in count.values():
    if v >= 2:
        break
else:
    print("pairwise coprime")
    exit()

def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

#setwise coprimeを判断
g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")


Fixed submission:
from collections import Counter
N = int(input())
A = list(map(int,input().split()))
countA = Counter(A)

#pairwiseかどうかを調べる
memo = [1]*(10**6+1)
memo[0] = 0
memo[1] = 0
for i in range(2,10**6+1):
    if memo[i] == 1:
        flag = False
        if i in countA:
            if countA[i] >= 2:
                break
            flag = True
        for j in range(i*2,10**6+1,i):
            if j in countA:
                if countA[j] >= 2:
                    break
                if flag:
                    break
                else:
                    flag = True
            memo[j] = 0
        else:
            continue
        break
else:
    print("pairwise coprime")
    exit()



#setwise coprimeを判断
def gcd(a,b):
    return a if b==0 else gcd(b,a%b)

g = A[0]
for i in range(1,N):
    g = gcd(g,A[i])
if g == 1:
    print("setwise coprime")
else:
    print("not coprime")