Buggy python submission (verdict: Time Limit Exceeded):
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
    
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)
#print(A_dict)

N = H*W+1
edges = []

for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    edges.append((s,g,cost))

from collections import defaultdict
graph = defaultdict(lambda:{})
for x,y,z in edges:
    graph[x][y] = z
for i in range(N):
    graph[i][i] = 0 #自身のところに行くコストは０
    
from heapq import heappush, heappop    
def dijkstra(graph, start, N):
    A = [None] * (N+1)
    queue = [(0, start)]
    while queue:
        path_len, v = heappop(queue)
        if A[v] is None: # v is unvisited
            A[v] = path_len
            for w, edge_len in graph[v].items():
                if A[w] is None:
                    heappush(queue, (path_len + edge_len, w))

    # to give same result as original, assign zero distance to unreachable vertices             
    return [0 if x is None else x for x in A]

dist = {}
for i in range(1, D+1):
    dist[i] = dijkstra(graph, i, N)
#print(dist)
for l, r in LR:
    idx = r%D
    if idx == 0:
        idx = D
    print(dist[idx][r]-dist[idx][l])
        




Fixed submission:
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)

# costの辞書化
from collections import defaultdict
cost_dict = defaultdict(lambda: {})
N = H*W+1
for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    cost_dict[s][g] = cost
    

dist = defaultdict(lambda: {})
for i in range(1, D+1):
    dist[i][i] = 0
    s = i
    g = i+D
    while g < N:
        dist[i][g] = dist[i][s] + cost_dict[s][g]
        s = g
        g = s + D

    
#print(dist)
for l, r in LR:
    idx = r%D
    if idx == 0:
        idx = D
    print(dist[idx][r]-dist[idx][l])

Buggy python submission (verdict: Time Limit Exceeded):
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
    
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)
#print(A_dict)

N = H*W+1
edges = []
graph = [[float("inf") for i in range(N)] for i in range(N)] 
for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    edges.append((s,g,cost))
for x,y,z in edges:
    graph[x][y] = z
for i in range(N):
    graph[i][i] = 0 #自身のところに行くコストは０
    
from collections import defaultdict
dist = defaultdict(lambda: {})

for i in range(1, N):
    dist[i][i] = 0
    d = 0
    s = i
    g = i+D
    while g < N:
        dist[i][g] = dist[i][s]+graph[s][g]
        s = g
        g = s+D
#print(dist)
for l, r in LR:
    print(dist[l][r])
        




Fixed submission:
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)

# costの辞書化
from collections import defaultdict
cost_dict = defaultdict(lambda: {})
N = H*W+1
for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    cost_dict[s][g] = cost
    

dist = defaultdict(lambda: {})
for i in range(1, D+1):
    dist[i][i] = 0
    s = i
    g = i+D
    while g < N:
        dist[i][g] = dist[i][s] + cost_dict[s][g]
        s = g
        g = s + D

    
#print(dist)
for l, r in LR:
    idx = r%D
    if idx == 0:
        idx = D
    print(dist[idx][r]-dist[idx][l])

Buggy python submission (verdict: Time Limit Exceeded):
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
    
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)
#print(A_dict)
    
def warshall_floyd(d, n):
    # d: グラフ二次元リスト
    # n: 頂点数 (0始まり)
    #d[i][j]: iからjへの最短距離
    for k in range(n):
        for i in range(n):
            for j in range(n):
                if d[i][j] > d[i][k] + d[k][j]:
                    d[i][j] = d[i][k] + d[k][j]
    return d

N = H*W+1
graph = [[float("inf") for i in range(N)] for i in range(N)] 
edges = []

for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    edges.append((s,g,cost))

for x,y,z in edges:
    graph[x][y] = z
for i in range(N):
    graph[i][i] = 0 #自身のところに行くコストは０
shortest = warshall_floyd(graph, N)

for l, r in LR:
    print(shortest[l][r])

Fixed submission:
import sys
input = sys.stdin.readline
H, W, D = map(int, input().split())

A = []
for _ in range(H):
    a = list(map(int, input().split()))
    A.append(a)

Q = int(input())
LR = []
for _ in range(Q):
    l, r = map(int, input().split())
    LR.append((l, r))
# H*Wのマスをマスの数値をkeyにした辞書にする
A_dict = {}
for i, sub_a in enumerate(A):
    for j, a in enumerate(sub_a):
        A_dict[a] = (i+1, j+1)

# costの辞書化
from collections import defaultdict
cost_dict = defaultdict(lambda: {})
N = H*W+1
for i in range(1, N):
    s = i
    g = i+D
    if g >= N:
        break
    cost = abs(A_dict[s][0]-A_dict[g][0])+abs(A_dict[s][1]-A_dict[g][1])
    cost_dict[s][g] = cost
    

dist = defaultdict(lambda: {})
for i in range(1, D+1):
    dist[i][i] = 0
    s = i
    g = i+D
    while g < N:
        dist[i][g] = dist[i][s] + cost_dict[s][g]
        s = g
        g = s + D

    
#print(dist)
for l, r in LR:
    idx = r%D
    if idx == 0:
        idx = D
    print(dist[idx][r]-dist[idx][l])