Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n = 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5 + 4)
Ds = [0] * (2 * 10 ** 5 + 4)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5 + 4):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5 + 4):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      if (d == 0):
        print(0)
      else:
        print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      if (d == 0):
        print(0)
      else:
        print(solve2(D - Ds[n-i-1], d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      if (d == 0):
        print(0)
      else:
        print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      if (d == 0):
        print(0)
      else:
        print(solve2(D - Ds[n-i-1], d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      print(solve2(D - Ds[n-i-1], d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) + d
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      print(solve2(D - Ds[n-i-1], d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
_d = (2 * 10 ** 5) // d
D = X % d + (d * _d) * d
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(U + Us[n-i-1], u))
    else:
      print(solve2(D - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Runtime Error):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
  
Us[0] = 1 % u
Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i-1] * 2) % u
  Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(X <= 2 * 10 ** 5 + 1):
    if(x[i] == '0'):
      print(solve2(X + 2 ** (n - i - 1), u))
    else:
      print(solve2(X - 2 ** (n - i - 1), d))
  else:
    if(x[i] == '0'):
      print(solve2(X + Us[n-i-1], u))
    else:
      print(solve2(X - Ds[n-i-1], d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
for i in range(n):  
  if(x[i] == '0'):
    print(solve2(X + 2 ** (n-i-1), u))
  else:
    print(solve2(X - 2 ** (n-i-1), d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
for i in range(n):  
  if(x[i] == '0'):
    print(solve2(X + 2 ** (n-i-1), u))
  else:
    print(solve2(X - 2 ** (n-i-1), d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5 + 1):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1 :n]
  if(x[i] == '0'):
    print(solve2(int(_x, 2), u))
  else:
    print(solve2(int(_x, 2), d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'
    

def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1 :n]
  if(x[i] == '0'):
    print(solve2(int(_x, 2), u))
  else:
    print(solve2(int(_x, 2), d))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, count, d):
  if (i <= 2 * 10**5):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve2(i % d, count + 1, d)


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1 :n]
  if(x[i] == '0'):
    print(solve2(int(_x, 2), 0, u))
  else:
    print(solve2(int(_x, 2), 0, d))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 + 1 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, count):
  if (i <= 2 * 10**5 + 1):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1:n]
  print(solve2(int(_x, 2), 0))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
#! /Library/Frameworks/Python.framework/Versions/3.7/bin/python3
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= 2 * 10**5 + 1 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1:n]
  print(solve(int(_x, 2), 0))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n

if (z == x):
  u = n - 1
  d = n - 1
elif (z == o):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1

def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i <= n and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


ans = [0] * (2 * 10 ** 5 + 1)
for i in range(1, 2 * 10 ** 5):
  ans[i] = solve(i, 0)
for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1 :n]
  print(solve(int(_x, 2),0))


Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))

Buggy python submission (verdict: Time Limit Exceeded):
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def toggle(i):
  if (i == '1'):
    return '0'
  else:
    return '1'


def solve(i, count):
  if (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


for i in range(n):
  if(i == 0):
    _x = toggle(x[0]) + x[1: n]
  elif (i == n - 1):
    _x = x[:i] + toggle(x[n - 1])
  else:
    _x = x[:i] + toggle(x[i]) + x[i + 1 :n]
  print(solve(int(_x, 2),0))

Fixed submission:
import sys
sys.setrecursionlimit(10 ** 6)

n = int(input())
x = input()
z = '1' * n
o = '0' * n
X = int(x, 2)

if (n == 1 and x == '1'):
  print(0)
  exit()

if (z == x):
  u = n - 1
  d = n - 1
elif (o == x):
  u = 1
  d = 1
else:
  tmp = len(list(filter(lambda x: x == '1', x)))
  u = tmp + 1
  d = tmp - 1


def popcount(i):
  return i % len(list(filter(lambda x: x == '1', format(i, 'b'))))


def solve(i, count):
  if (i <= 2 * 10**5 and ans[i] != 0):
    return count + ans[i]
  elif (i == 0):
    return count
  else:
    return solve(popcount(i), count + 1)


def solve2(i, div):
  if (i <= 2 * 10**5):
    return ans[i]
  else:
    return ans[i % div] + 1


ans = [0] * (2 * 10 ** 5 + 4)
_u = (2 * 10 ** 5) // u
U = X % u + (u * _u) + u
if(d != 0):
  _d = (2 * 10 ** 5) // d
  D = X % d + (d * _d) * 2 + d * 2
Us = [0] * (2 * 10 ** 5)
Ds = [0] * (2 * 10 ** 5)
for i in range(1, 2 * 10 ** 5 + 4):
  ans[i] = solve(i, 0)
Us[0] = 1 % u
if(d != 0):
  Ds[0] = 1 % d
for i in range(1, 2 * 10 ** 5):
  Us[i] = (Us[i - 1] * 2) % u
  if(d != 0):
    Ds[i] = (Ds[i-1] * 2) % d

for i in range(n):
  if(x[i] == '0'):
    print(solve2(U + Us[n-i-1], u))
  else:
    if (d == 0):
      print(0)
    else:
      print(solve2(D - Ds[n-i-1], d))