Buggy python submission (verdict: Runtime Error):
N = int(input())

import math
from collections import defaultdict
from itertools import product
#試し割法
def trial_division(n):
    #素因数を格納するリスト
    factor = []
    #2から√n以下の数字で割っていく
    tmp = int(math.sqrt(n)) + 1
    for num in range(2,tmp):
        while n % num == 0:
            n //= num
            factor.append(num)
    #リストが空ならそれは素数
    if not factor:
        return 'prime number'
    else:
        factor.append(n)
        return factor

fac = trial_division(N)
dic = defaultdict(int)
for n in fac:
    if n != 1:
        dic[n] += 1

a = []
for k, v in dic.items():
    a.append([k**j for j in range(v+1)])

tmp = list(product(*a))

ans = 0
for t in tmp:
    b = 1
    for j in t:
        b *= j
    if b >= 2:
        xx, yy = divmod(N, b-1)
        if xx == yy:
            ans += b - 1

print(ans)

Fixed submission:
from collections import Counter
from itertools import product

N = int(input())

def prime_decomposition(n):
    i = 2
    table = []
    while i * i <= n:
        while n % i == 0:
            n //= i
            table.append(i)
        i += 1
    if n > 1:
        table.append(n)
    return table

# 素因数分解で約数を計算する
primes = prime_decomposition(N)

# 素因数の種類と個数を数え上げる
counter = Counter(primes)
values = [[k**i for i in range(v+1)] for k, v in counter.items()]
p = product(*values)

# 全ての種類の素数×個数を計算して、約数の組み合わせを格納する
divisors = []
for v in p:
    div = 1
    for w in v:
        div *= w
    divisors.append(div)

# 条件にあう約数を選別してmを求め、答えに加算する
ans = 0
for i in divisors:
    j = N / i
    if (i > j + 1) & (i >= 1) & (j >= 1):
        ans += i - 1
print(ans)

Buggy python submission (verdict: Runtime Error):
N = int(input())

import math
from collections import defaultdict
from itertools import product
#試し割法
def trial_division(n):
    #素因数を格納するリスト
    factor = []
    #2から√n以下の数字で割っていく
    tmp = int(math.sqrt(n)) + 1
    for num in range(2,tmp):
        while n % num == 0:
            n //= num
            factor.append(num)
    #リストが空ならそれは素数
    if not factor:
        return 'prime number'
    else:
        factor.append(n)
        return factor

fac = trial_division(N)
dic = defaultdict(int)
for n in fac:
    if n != 1:
        dic[n] += 1

a = []
for k, v in dic.items():
    a.append([k**j for j in range(v+1)])

tmp = list(product(*a))

ans = 0
for t in tmp:
    b = 1
    for j in t:
        b *= j
    if b >= 2:
        xx, yy = divmod(N, b-1)
        if xx == yy:
            ans += b - 1

print(ans)

Fixed submission:
from collections import Counter
from itertools import product

N = int(input())

def prime_decomposition(n):
    i = 2
    table = []
    while i * i <= n:
        while n % i == 0:
            n //= i
            table.append(i)
        i += 1
    if n > 1:
        table.append(n)
    return table

# 素因数分解で約数を計算する
primes = prime_decomposition(N)

# 素因数の種類と個数を数え上げる
counter = Counter(primes)
values = [[k**i for i in range(v+1)] for k, v in counter.items()]
p = product(*values)

# 全ての種類の素数×個数を計算して、約数の組み合わせを格納する
divisors = []
for v in p:
    div = 1
    for w in v:
        div *= w
    divisors.append(div)

# 条件にあう約数を選別してmを求め、答えに加算する
ans = 0
for i in divisors:
    j = N / i
    if (i > j + 1) & (i >= 1) & (j >= 1):
        ans += i - 1
print(ans)