Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = size(i) - frendCnt[i] - 1
    for j in bloc[i]:
      if same(i, j):
           ans -= 1
    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N + 1)]
rank = [0] * (N + 1)
frendCnt = [0] * (N + 1)
bloc = [[] for _ in range(N + 1)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

#for i in range(K):
#    c, d = map(int, input().split())
#    c -= 1
#    d -= 1
#    bloc[c].append(d)
#    bloc[d].append(c)

#for i in range(N):
#    ans = uCnt(i) - frendCnt[i] - 1
#    for j in bloc[i]:
#      if same(i, j):
#           ans -= 1
#    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N + 1)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N + 1)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

#for i in range(K):
#    c, d = map(int, input().split())
#    c -= 1
#    d -= 1
#    bloc[c].append(d)
#    bloc[d].append(c)

#for i in range(N):
#    ans = uCnt(i) - frendCnt[i] - 1
#    for j in bloc[i]:
#      if same(i, j):
#           ans -= 1
#    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

#for i in range(K):
#    c, d = map(int, input().split())
#    c -= 1
#    d -= 1
#    bloc[c].append(d)
#    bloc[d].append(c)

#for i in range(N):
#    ans = uCnt(i) - frendCnt[i] - 1
#    for j in bloc[i]:
#      if same(i, j):
#           ans -= 1
#    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

#for i in range(N):
#    ans = uCnt(i) - frendCnt[i] - 1
#    for j in bloc[i]:
#      if same(i, j):
#           ans -= 1
#    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = uCnt(i) - frendCnt[i] - 1
    for j in bloc[i]:
       if same(i, j):
           ans -= 1
    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
import sys
input = sys.stdin.readline

def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = uCnt(i) - frendCnt[i] - 1
    for j in bloc[i]:
       if same(i, j):
           ans -= 1
    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(M):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = uCnt(i) - frendCnt[i] - 1
    for j in bloc[i]:
       if same(i, j):
           ans -= 1
    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(N):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = uCnt(i) - len(bloc[i]) - frendCnt[i] - 1
    print(ans, end=' ')

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')

Buggy python submission (verdict: Runtime Error):
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]

def same(x, y):
    if find(x) == find(y):
        return True
    else:
        return False

def unite(x, y):
    x = find(x)
    y = find(y)
    if x == y:
        return
    if rank[x] > rank[y]:
        x, y = y, x
    par[x] += par[y]
    par[y] = x

def uCnt(x):
    return -par[find(x)]

N, M, K = map(int, input().split())
par = [-1 for i in range(N)]
rank = [0] * N
frendCnt = [0] * N
bloc = [[] for _ in range(N)]
for i in range(N):
    a, b = map(int, input().split())
    a -= 1
    b -= 1
    frendCnt[a] += 1
    frendCnt[b] += 1
    unite(a, b)

for i in range(K):
    c, d = map(int, input().split())
    c -= 1
    d -= 1
    bloc[c].append(d)
    bloc[d].append(c)

for i in range(N):
    ans = uCnt(i) - len(bloc[i]) - frendCnt[i] - 1
    print(ans)

Fixed submission:
import sys
input = sys.stdin.readline

n,m,k = map(int,input().split())

#Union Find

#xの根を求める
def find(x):
    if par[x] < 0:
        return x
    else:
        par[x] = find(par[x])
        return par[x]
#xとyの属する集合の併合
def unite(x,y):
    x = find(x)
    y = find(y)

    if x == y:
        return False
    else:
        #sizeの大きいほうがx
        if par[x] > par[y]:
            x,y = y,x
        par[x] += par[y]
        par[y] = x
        return True

#xとyが同じ集合に属するかの判定
def same(x,y):
    return find(x) == find(y)

#xが属する集合の個数
def size(x):
    return -par[find(x)]

#初期化
#根なら-size,子なら親の頂点
par = [-1]*n

num = [0]*n

for i in range(m):
    a,b = map(int,input().split())
    unite(a-1,b-1)
    num[a-1] += 1
    num[b-1] += 1

edge = [[] for i in range(n)]

for i in range(k):
    c,d = map(int,input().split())
    edge[c-1].append(d-1)
    edge[d-1].append(c-1)


for i in range(n):
    cnt = size(i) - num[i] - 1
    for e in edge[i]:
        if same(e,i):
            cnt -= 1
    print(cnt,end=' ')