Buggy python submission (verdict: Time Limit Exceeded):
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

tmp = [set() for _ in range(10**6+1)]
for i in range(2, int(10**6//(0.5))+1):
    for j in range(i, 10**6+1, i):
        tmp[j].add(i)


flag = False
for i in range(n-1):
    if len(tmp[a[i]] & tmp[max(a)]) > 0:
        flag = True
        break

if flag == False:
    print("pairwise coprime")
else:
    if reduce(gcd, a) == 1:
        print("setwise coprime")
    else:
        print("not coprime")

Fixed submission:
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

# sieve[n]は、その数を最初にふるいに落とした数を格納
def prime_factor_table(n):
    # sieveとはふるいの意味
    sieve = [i for i in range(n+1)]
    # n以下の整数を最初にふるい落とす数(√n以下に必ず存在)を求める.
    for i in range(2, int(n**0.5)+1):
        if sieve[i] == i:
            for j in range(2*i, n+1, i):
                if sieve[j] == j:
                    sieve[j] = i
    return sieve

sieve = prime_factor_table(10**6+1)

def prime_factor(n):
    # 素数は英語でprime number
    prime = set()
    while n > 1:
        prime.add(sieve[n])
        n //= sieve[n]
    return prime

for i, v in enumerate(a):
    if i == 0:
        tmp = prime_factor(v)
    else:
        prime = prime_factor(v)
        for j in prime:
            if j in tmp:
                if reduce(gcd, a) == 1:
                    print("setwise coprime")
                    exit()
                else:
                    print("not coprime")
                    exit()
            tmp.add(j)
print("pairwise coprime")

Buggy python submission (verdict: Time Limit Exceeded):
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

tmp = [set() for _ in range(10**6+1)]
for i in range(2, 10**6//2+1):
    for j in range(i, 10**6+1, i):
        tmp[j].add(i)

# acc = [set() for _ in range(n)]
# for i, v in enumerate(a):
#     if i == 0:
#         acc[i] = tmp[v]
#     else:
#         acc[i] = acc[i-1] | tmp[v]

flag = False
for i in range(n-1):
    if len(tmp[a[i]] & tmp[max(a)]) > 0:
        flag = True
        break

if flag == False:
    print("pairwise coprime")
else:
    if reduce(gcd, a) == 1:
        print("setwise coprime")
    else:
        print("not coprime")

Fixed submission:
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

# sieve[n]は、その数を最初にふるいに落とした数を格納
def prime_factor_table(n):
    # sieveとはふるいの意味
    sieve = [i for i in range(n+1)]
    # n以下の整数を最初にふるい落とす数(√n以下に必ず存在)を求める.
    for i in range(2, int(n**0.5)+1):
        if sieve[i] == i:
            for j in range(2*i, n+1, i):
                if sieve[j] == j:
                    sieve[j] = i
    return sieve

sieve = prime_factor_table(10**6+1)

def prime_factor(n):
    # 素数は英語でprime number
    prime = set()
    while n > 1:
        prime.add(sieve[n])
        n //= sieve[n]
    return prime

for i, v in enumerate(a):
    if i == 0:
        tmp = prime_factor(v)
    else:
        prime = prime_factor(v)
        for j in prime:
            if j in tmp:
                if reduce(gcd, a) == 1:
                    print("setwise coprime")
                    exit()
                else:
                    print("not coprime")
                    exit()
            tmp.add(j)
print("pairwise coprime")

Buggy python submission (verdict: Runtime Error):
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

tmp = [set() for _ in range(10**2+1)]
for i in range(2, 10**2//2+1):
    for j in range(i, 10**2+1, i):
        tmp[j].add(i)


flag = False
for i in range(n-1):
    if len(tmp[a[i]] & tmp[max(a)]) > 0:
        flag = True
        break

if flag == False:
    print("pairwise coprime")
else:
    if reduce(gcd, a) == 1:
        print("setwise coprime")
    else:
        print("not coprime")

Fixed submission:
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

# sieve[n]は、その数を最初にふるいに落とした数を格納
def prime_factor_table(n):
    # sieveとはふるいの意味
    sieve = [i for i in range(n+1)]
    # n以下の整数を最初にふるい落とす数(√n以下に必ず存在)を求める.
    for i in range(2, int(n**0.5)+1):
        if sieve[i] == i:
            for j in range(2*i, n+1, i):
                if sieve[j] == j:
                    sieve[j] = i
    return sieve

sieve = prime_factor_table(10**6+1)

def prime_factor(n):
    # 素数は英語でprime number
    prime = set()
    while n > 1:
        prime.add(sieve[n])
        n //= sieve[n]
    return prime

for i, v in enumerate(a):
    if i == 0:
        tmp = prime_factor(v)
    else:
        prime = prime_factor(v)
        for j in prime:
            if j in tmp:
                if reduce(gcd, a) == 1:
                    print("setwise coprime")
                    exit()
                else:
                    print("not coprime")
                    exit()
            tmp.add(j)
print("pairwise coprime")

Buggy python submission (verdict: Runtime Error):
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

tmp = [set() for _ in range(10**2+1)]
for i in range(2, 10**2//2+1):
    for j in range(i, 10**2+1, i):
        tmp[j].add(i)

acc = [set() for _ in range(n)]
for i, v in enumerate(a):
    if i == 0:
        acc[i] = tmp[v]
    else:
        acc[i] = acc[i-1] | tmp[v]

flag = False
for i in range(n-1):
    acc[i].remove(i)
    if len(acc[i] & acc[n-1]) != 0:
        flag = True
        break

if flag == False:
    print("pairwise coprime")
else:
    if reduce(gcd, a) == 1:
        print("setwise coprime")
    else:
        print("not coprime")

Fixed submission:
from math import gcd
from functools import reduce
n = int(input())
a = list(map(int, input().split()))

# sieve[n]は、その数を最初にふるいに落とした数を格納
def prime_factor_table(n):
    # sieveとはふるいの意味
    sieve = [i for i in range(n+1)]
    # n以下の整数を最初にふるい落とす数(√n以下に必ず存在)を求める.
    for i in range(2, int(n**0.5)+1):
        if sieve[i] == i:
            for j in range(2*i, n+1, i):
                if sieve[j] == j:
                    sieve[j] = i
    return sieve

sieve = prime_factor_table(10**6+1)

def prime_factor(n):
    # 素数は英語でprime number
    prime = set()
    while n > 1:
        prime.add(sieve[n])
        n //= sieve[n]
    return prime

for i, v in enumerate(a):
    if i == 0:
        tmp = prime_factor(v)
    else:
        prime = prime_factor(v)
        for j in prime:
            if j in tmp:
                if reduce(gcd, a) == 1:
                    print("setwise coprime")
                    exit()
                else:
                    print("not coprime")
                    exit()
            tmp.add(j)
print("pairwise coprime")