Buggy python submission (verdict: Time Limit Exceeded):
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = r0_p + (2**(N-1-i) % c_p_cnt)
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = r0_m - (2**(N-1-i) % c_p_cnt)
    print(1 + solve(r % c_p_cnt))



Fixed submission:
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = (r0_p + pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = (r0_m- pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    print(1 + solve(r % c_p_cnt))

Buggy python submission (verdict: Runtime Error):
MAX = 2*10**5
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = r0_p + (2**(N-1-i) % c_p_cnt)
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = r0_m - (2**(N-1-i) % c_p_cnt)
    print(1 + solve(r % c_p_cnt))



Fixed submission:
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = (r0_p + pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = (r0_m- pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    print(1 + solve(r % c_p_cnt))

Buggy python submission (verdict: Runtime Error):
MAX = 2*10**5
def popcount(x):
    '''xの立っているビット数をカウントする関数
    (xは64bit整数)'''

    # 2bitごとの組に分け、立っているビット数を2bitで表現する
    x = x - ((x >> 1) & 0x5555555555555555)

    # 4bit整数に 上位2bit + 下位2bit を計算した値を入れる
    x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333)

    x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f # 8bitごと
    x = x + (x >> 8) # 16bitごと
    x = x + (x >> 16) # 32bitごと
    x = x + (x >> 32) # 64bitごと = 全部の合計
    return x & 0x0000007f
s_map = [0 for i in range(MAX+1)]
def solve(n):
    if n == 0:
        return 1
    if s_map[n] > 0:
        return s_map[n]
    s_map[n] = 1 + solve(n % popcount(n))
    return s_map[n]

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
amari_p = num_x % (p_cnt+1)
amari_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        amari = amari_p + 2**(N-1-i) % c_p_cnt
    else:
        c_p_cnt = p_cnt - 1
        amari = amari_m - 2**(N-1-i) % c_p_cnt
    print(solve(amari % c_p_cnt))



Fixed submission:
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = (r0_p + pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = (r0_m- pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    print(1 + solve(r % c_p_cnt))

Buggy python submission (verdict: Time Limit Exceeded):
MAX = 2*10**5
def popcount(x):
    '''xの立っているビット数をカウントする関数
    (xは64bit整数)'''

    # 2bitごとの組に分け、立っているビット数を2bitで表現する
    x = x - ((x >> 1) & 0x5555555555555555)

    # 4bit整数に 上位2bit + 下位2bit を計算した値を入れる
    x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333)

    x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f # 8bitごと
    x = x + (x >> 8) # 16bitごと
    x = x + (x >> 16) # 32bitごと
    x = x + (x >> 32) # 64bitごと = 全部の合計
    return x & 0x0000007f
s_map = [0 for i in range(MAX+1)]
def solve(n):
    if n == 0:
        return 1
    if s_map[n] > 0:
        return s_map[n]
    s_map[n] = 1 + solve(n % popcount(n))
    return s_map[n]

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
for i in range(N):
    c_p_cnt = p_cnt+1 if X[i] == '0' else p_cnt-1
    x = num_x + 2**(N-1-i) if X[i] == '0' else num_x - 2**(N-1-i)
    if x == 0:
        print(0)
    else:
        print(solve(x % c_p_cnt))



Fixed submission:
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = (r0_p + pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = (r0_m- pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    print(1 + solve(r % c_p_cnt))

Buggy python submission (verdict: Runtime Error):
MAX = 2*10**5
def popcount(x):
    '''xの立っているビット数をカウントする関数
    (xは64bit整数)'''

    # 2bitごとの組に分け、立っているビット数を2bitで表現する
    x = x - ((x >> 1) & 0x5555555555555555)

    # 4bit整数に 上位2bit + 下位2bit を計算した値を入れる
    x = (x & 0x3333333333333333) + ((x >> 2) & 0x3333333333333333)

    x = (x + (x >> 4)) & 0x0f0f0f0f0f0f0f0f # 8bitごと
    x = x + (x >> 8) # 16bitごと
    x = x + (x >> 16) # 32bitごと
    x = x + (x >> 32) # 64bitごと = 全部の合計
    return x & 0x0000007f
s_map = [0 for i in range(MAX+1)]
def solve(n):
    if n == 0:
        return 1
    if s_map[n] > 0:
        return s_map[n]
    s_map[n] = 1 + solve(n % popcount(n))
    return s_map[n]

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
for i in range(N):
    c_p_cnt = p_cnt+1 if X[i] == '0' else p_cnt-1
    x = num_x + 2**(N-1-i) if X[i] == '0' else num_x - 2**(N-1-i)
    print(solve(x % c_p_cnt))



Fixed submission:
def popcount(x):
    return bin(x).count("1")
def solve(n):
    if n == 0:
        return 0
    return 1+solve(n % popcount(n))

N = int(input())
X = input()
num_x = int(X, 2)
p_cnt = X.count('1')
if p_cnt == 1:
    for i in range(N):
        if X[i] == '1':
            print(0)
        elif i == N-1:
            print(2)
        else:
            print(1)
    exit()
r0_p = num_x % (p_cnt+1)
r0_m = num_x % (p_cnt-1)
for i in range(N):
    if X[i] == '0':
        c_p_cnt = p_cnt+1
        r = (r0_p + pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    else:
        c_p_cnt = p_cnt-1
        if c_p_cnt == 0:
            print(0)
            continue
        r = (r0_m- pow(2, (N - 1 - i), c_p_cnt)) % c_p_cnt
    print(1 + solve(r % c_p_cnt))