Buggy python submission (verdict: Time Limit Exceeded):
from heapq import heappop, heappush


def solve(n, m, s):
    q = [(0, 0)]
    curr = None
    for i in range(1, n + 1):
        if s[i] == '1':
            continue
        left_limit = max(0, i - m)
        while q and q[0][-1] < left_limit:
            heappop(q)
        if not q:
            return (-1,)
        prev = q[0]
        dice = i - prev[-1]
        curr = (prev[0] + 1,) + prev[1:-1] + (dice, i)
        heappush(q, curr)

    return curr[1:-1]


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))


Fixed submission:
from heapq import heappop, heappush


def solve(n, m, s):
    curr = n
    l = max(0, n - m)
    r = n
    ans = []
    while r > 0:
        for i, c in enumerate(s[l:r], start=l):
            if c == '0':
                dice = curr - i
                ans.append(dice)
                curr = i
                l = max(0, i - m)
                r = i
                break
        else:
            return (-1,)

    return reversed(ans)


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))

Buggy python submission (verdict: Time Limit Exceeded):
class SegTreeMin:
    """
    以下のクエリを処理する
    1.update:  i番目の値をxに更新する
    2.get_min: 区間[l, r)の最小値を得る
    """

    def __init__(self, n, INF):
        """
        :param n: 要素数
        :param INF: 初期値（入りうる要素より十分に大きな数）
        """
        n2 = 1 << (n - 1).bit_length()
        self.offset = n2
        self.tree = [INF] * (n2 << 1)
        self.INF = INF

    def update(self, i, x):
        """
        i番目の値をxに更新
        :param i: index(0-indexed)
        :param x: update value
        """
        i += self.offset
        self.tree[i] = x
        while i > 1:
            y = self.tree[i ^ 1]
            if y <= x:
                break
            i >>= 1
            self.tree[i] = x

    def get_min(self, a, b):
        """
        [a, b)の最小値を得る
        :param a: index(0-indexed)
        :param b: index(0-indexed)
        """
        result = self.INF

        l = a + self.offset
        r = b + self.offset
        while l < r:
            if r & 1:
                result = min(result, self.tree[r - 1])
            if l & 1:
                result = min(result, self.tree[l])
                l += 1
            l >>= 1
            r >>= 1

        return result


def solve(n, m, s):
    INF = 10 ** 18
    sgt = SegTreeMin(n + 1, (INF,))
    sgt.update(0, (0, 0))
    for i in range(1, n + 1):
        if s[i] == '1':
            continue
        r = i
        l = max(0, i - m)
        prev = sgt.get_min(l, r)
        if prev[0] == INF:
            return (-1,)
        dice = i - prev[-1]
        curr = (prev[0] + 1,) + prev[1:-1] + (dice, i)
        sgt.update(i, curr)
    return sgt.get_min(n, n + 1)[1:-1]


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))


Fixed submission:
from heapq import heappop, heappush


def solve(n, m, s):
    curr = n
    l = max(0, n - m)
    r = n
    ans = []
    while r > 0:
        for i, c in enumerate(s[l:r], start=l):
            if c == '0':
                dice = curr - i
                ans.append(dice)
                curr = i
                l = max(0, i - m)
                r = i
                break
        else:
            return (-1,)

    return reversed(ans)


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))

Buggy python submission (verdict: Time Limit Exceeded):
class SegTreeMin:
    """
    以下のクエリを処理する
    1.update:  i番目の値をxに更新する
    2.get_min: 区間[l, r)の最小値を得る
    """

    def __init__(self, n, INF):
        """
        :param n: 要素数
        :param INF: 初期値（入りうる要素より十分に大きな数）
        """
        n2 = 1 << (n - 1).bit_length()
        self.offset = n2
        self.tree = [INF] * (n2 << 1)
        self.INF = INF

    def update(self, i, x):
        """
        i番目の値をxに更新
        :param i: index(0-indexed)
        :param x: update value
        """
        i += self.offset
        self.tree[i] = x
        while i > 1:
            y = self.tree[i ^ 1]
            if y <= x:
                break
            i >>= 1
            self.tree[i] = x

    def get_min(self, a, b):
        """
        [a, b)の最小値を得る
        :param a: index(0-indexed)
        :param b: index(0-indexed)
        """
        result = self.INF

        l = a + self.offset
        r = b + self.offset
        while l < r:
            if r & 1:
                result = min(result, self.tree[r - 1])
            if l & 1:
                result = min(result, self.tree[l])
                l += 1
            l >>= 1
            r >>= 1

        return result


def solve(n, m, s):
    INF = 10 ** 18
    sgt = SegTreeMin(n + 1, (INF,))
    sgt.update(0, (0, 0))
    for i in range(1, n + 1):
        if s[i] == '1':
            continue
        r = i
        l = max(0, i - m)
        prev = sgt.get_min(l, r)
        if prev[0] == INF:
            return (-1,)
        dice = i - prev[-1]
        curr = (prev[0] + 1,) + prev[1:-1] + (dice, i)
        sgt.update(i, curr)
    return sgt.get_min(n, n + 1)[1:-1]


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))


Fixed submission:
from heapq import heappop, heappush


def solve(n, m, s):
    curr = n
    l = max(0, n - m)
    r = n
    ans = []
    while r > 0:
        for i, c in enumerate(s[l:r], start=l):
            if c == '0':
                dice = curr - i
                ans.append(dice)
                curr = i
                l = max(0, i - m)
                r = i
                break
        else:
            return (-1,)

    return reversed(ans)


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))

Buggy python submission (verdict: Runtime Error):
class SegTreeMin:
    """
    以下のクエリを処理する
    1.update:  i番目の値をxに更新する
    2.get_min: 区間[l, r)の最小値を得る
    """

    def __init__(self, n, INF):
        """
        :param n: 要素数
        :param INF: 初期値（入りうる要素より十分に大きな数）
        """
        n2 = 1 << (n - 1).bit_length()
        self.offset = n2
        self.tree = [INF] * (n2 << 1)
        self.INF = INF

    def update(self, i, x):
        """
        i番目の値をxに更新
        :param i: index(0-indexed)
        :param x: update value
        """
        i += self.offset
        self.tree[i] = x
        while i > 1:
            y = self.tree[i ^ 1]
            if y <= x:
                break
            i >>= 1
            self.tree[i] = x

    def get_min(self, a, b):
        """
        [a, b)の最小値を得る
        :param a: index(0-indexed)
        :param b: index(0-indexed)
        """
        result = self.INF

        l = a + self.offset
        r = b + self.offset
        while l < r:
            if r & 1:
                result = min(result, self.tree[r - 1])
            if l & 1:
                result = min(result, self.tree[l])
                l += 1
            l >>= 1
            r >>= 1

        return result


def solve(n, m, s):
    INF = 10 ** 18
    sgt = SegTreeMin(n + 1, (INF,))
    sgt.update(0, (0, 0))
    for i in range(1, n + 1):
        if s[i] == '1':
            continue
        r = i
        l = max(0, i - m)
        prev = sgt.get_min(l, r)
        if prev[0] == INF:
            return (-1,)
        dice = i - prev[-1]
        curr = (prev[0] + 1, *prev[1:-1], dice, i)
        sgt.update(i, curr)
    return sgt.get_min(n, n + 1)[1:-1]


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))


Fixed submission:
from heapq import heappop, heappush


def solve(n, m, s):
    curr = n
    l = max(0, n - m)
    r = n
    ans = []
    while r > 0:
        for i, c in enumerate(s[l:r], start=l):
            if c == '0':
                dice = curr - i
                ans.append(dice)
                curr = i
                l = max(0, i - m)
                r = i
                break
        else:
            return (-1,)

    return reversed(ans)


n, m = map(int, input().split())
s = input()
print(*solve(n, m, s))