Buggy python submission (verdict: Runtime Error):
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-11

#DP
L = int(input())
DP = [0 for i in range(5)]

def cost(a):
    if a:
        return [a, a%2, (a+1)%2, a%2, a]
    else:
        return [0, 2, 1, 2, 0]

for i in range(L):
    n = [min(DP[:i+1]) for i in range(5)]
    cos = cost(a)
    DP[4] = n[4] + cos[4]
    DP[3] = n[3] + cos[3]
    DP[2] = n[2] + cos[2]
    DP[1] = n[1] + cos[1]
    DP[0] = n[0] + cos[0]

print(min(DP))

Fixed submission:
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP

L = int(input())
A = [int(input()) for i in range(L)]

DP = [[float("inf") for i in range(5)] for j in range(L+1)]
for i in range(5):
    DP[0][i] = 0

def cost(s, i, A):
    if s == 0 or s == 4:
        return A[i]
    elif s == 1 or s == 3:
        if A[i] > 0:
            if A[i]%2 == 0:
                return 0
            else:
                return 1
        else:
            return 2
    else:
        if A[i]%2 == 1:
            return 0
        else:
            return 1

for i in range(L):
    for j in range(5):
        for k in range(j,5):
            DP[i+1][k] = min(DP[i+1][k], DP[i][j]+ cost(k, i, A))



print(min(DP[L]))

Buggy python submission (verdict: Time Limit Exceeded):
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP
import numpy as np
L = int(input())
A = [int(input()) for i in range(L)]

DP = np.zeros(5, dtype = int)

def cost(a:int) -> np.array:
    if a:
        return np.array([a,a%2,(a+1)%2,a%2,a])
    else:
        return np.array([0,2,1,2,0])

for i in range(L):
    n  = np.array([np.min(DP[:i+1]) for i in range(5)])
    DP = n + cost(A[i])

print(np.min(DP))

Fixed submission:
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP

L = int(input())
A = [int(input()) for i in range(L)]

DP = [[float("inf") for i in range(5)] for j in range(L+1)]
for i in range(5):
    DP[0][i] = 0

def cost(s, i, A):
    if s == 0 or s == 4:
        return A[i]
    elif s == 1 or s == 3:
        if A[i] > 0:
            if A[i]%2 == 0:
                return 0
            else:
                return 1
        else:
            return 2
    else:
        if A[i]%2 == 1:
            return 0
        else:
            return 1

for i in range(L):
    for j in range(5):
        for k in range(j,5):
            DP[i+1][k] = min(DP[i+1][k], DP[i][j]+ cost(k, i, A))



print(min(DP[L]))

Buggy python submission (verdict: Time Limit Exceeded):
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP
import numpy as np
L = int(input())
A = [int(input()) for i in range(L)]

DP = np.zeros(5, dtype = int)

def cost(a):
    if a:
        return np.array([a,a%2,(a+1)%2,a%2,a])
    else:
        return np.array([0,2,1,2,0])

for i in range(L):
    n  = np.array([np.min(DP[:i+1]) for i in range(5)])
    DP = n + cost(A[i])

print(np.min(DP))

Fixed submission:
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP

L = int(input())
A = [int(input()) for i in range(L)]

DP = [[float("inf") for i in range(5)] for j in range(L+1)]
for i in range(5):
    DP[0][i] = 0

def cost(s, i, A):
    if s == 0 or s == 4:
        return A[i]
    elif s == 1 or s == 3:
        if A[i] > 0:
            if A[i]%2 == 0:
                return 0
            else:
                return 1
        else:
            return 2
    else:
        if A[i]%2 == 1:
            return 0
        else:
            return 1

for i in range(L):
    for j in range(5):
        for k in range(j,5):
            DP[i+1][k] = min(DP[i+1][k], DP[i][j]+ cost(k, i, A))



print(min(DP[L]))

Buggy python submission (verdict: Runtime Error):
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP

L = int(input())
A = [int(input()) for i in range(L)]

DP = [[float("inf") for i in range(5)] for j in range(L+1)]
for i in range(L+1):
    DP[0][i] = 0

def cost(s, i, A):
    if s == 0 or s == 4:
        return A[i]
    elif s == 1 or s == 3:
        if A[i] > 0:
            if A[i]%2 == 0:
                return 0
            else:
                return 1
        else:
            return 2
    else:
        if A[i]%2 == 1:
            return 0
        else:
            return 1

for i in range(L):
    for j in range(5):
        for k in range(j,5):
            DP[i+1][k] = min(DP[i+1][k], DP[i][j]+ cost(k, i, A))



print(min(DP[L]))

Fixed submission:
#https://atcoder.jp/contests/yahoo-procon2019-qual/tasks/yahoo_procon2019_qual_d
#2019-02-10

#DP

L = int(input())
A = [int(input()) for i in range(L)]

DP = [[float("inf") for i in range(5)] for j in range(L+1)]
for i in range(5):
    DP[0][i] = 0

def cost(s, i, A):
    if s == 0 or s == 4:
        return A[i]
    elif s == 1 or s == 3:
        if A[i] > 0:
            if A[i]%2 == 0:
                return 0
            else:
                return 1
        else:
            return 2
    else:
        if A[i]%2 == 1:
            return 0
        else:
            return 1

for i in range(L):
    for j in range(5):
        for k in range(j,5):
            DP[i+1][k] = min(DP[i+1][k], DP[i][j]+ cost(k, i, A))



print(min(DP[L]))