Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal:
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now][1:]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[i] for i in range(n)]

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Runtime Error):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or connection[1000000*now + goal] == 1:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now][1:]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[i] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now][1:]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[i] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now][1:]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[i] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Runtime Error):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [None]*n
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            connection[1000000*goal + start] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Runtime Error):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            connection[1000000*goal + start] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    connection[1000000*inp[0] + inp[1]] = 1
    connection[1000000*inp[1] + inp[0]] = 1

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = [start]
    while unvisited:
        now = unvisited[0]
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            connection[1000000*goal + start] = 1
            return "yes"
        unvisited = unvisited[1:]
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    c[1000000*inp[0] + inp[1]] = 1
    c[1000000*inp[1] + inp[0]] = 1

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Runtime Error):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            connection[1000000*goal + start] = 1
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    c[1000000*inp[0] + inp[1]] = 1
    c[1000000*inp[1] + inp[0]] = 1

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or (1000000*now + goal) in connection:
            connection[1000000*start + goal] = 1
            connection[1000000*goal + start] = 1
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = {}

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    c[1000000*inp[0] + inp[1]] = 1
    c[1000000*inp[1] + inp[0]] = 1

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in c[now]:
            c[start].add(goal)
            c[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = [set() for i in range(n)]

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    c[inp[0]].add(inp[1])
    c[inp[1]].add(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in connection[now]:
            connection[start].add(goal)
            connection[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [[] for i in range(n)]
c = [set() for i in range(n)]

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].append(inp[1])
    g[inp[1]].append(inp[0])
    c[inp[0]].add(inp[1])
    c[inp[1]].add(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in connection[now]:
            connection[start].add(goal)
            connection[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [set() for i in range(n)]
c = [set() for i in range(n)]

for i in range(m):
    inp = list(map(int, input().split()))
    g[inp[0]].add(inp[1])
    g[inp[1]].add(inp[0])
    c[inp[0]].add(inp[1])
    c[inp[1]].add(inp[0])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Runtime Error):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in connection[now]:
            connection[start].add(goal)
            connection[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [set() for i in range(n)]
c = [set() for i in range(n)]

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)
    c[a].add(b)
    c[b].add(inp[a])

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal, connection):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in connection[now]:
            connection[start].add(goal)
            connection[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [set() for i in range(n)]
c = [set() for i in range(n)]

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)
    c[a].add(b)
    c[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t, c))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start, goal):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        if now == goal or goal in graph[now]:
            graph[start].add(goal)
            graph[goal].add(start)
            return "yes"
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return "no"

n, m = map(int, input().split())
g = [set() for i in range(n)]

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    print(bfs(g, s, t))

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    for key in visited.keys():
        graph[key].update(visited.keys())

n, m = map(int, input().split())
g = [set() for i in range(n)]

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    bfs(g, s)
    if t in g[s]:
        print("yes")
    else:
        print("no")

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)

Buggy python submission (verdict: Time Limit Exceeded):
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")

Fixed submission:
from collections import deque

def bfs(graph, start):
    visited = {start: None}
    unvisited = deque()
    unvisited.append(start)
    while unvisited:
        now = unvisited.popleft()
        for next in graph[now]:
            if not (next in visited):
                unvisited.append(next)
                visited[next] = now
    return visited

n, m = map(int, input().split())
g = [set() for i in range(n)]
group = []

for i in range(m):
    a, b = map(int, input().split())
    g[a].add(b)
    g[b].add(a)

q = int(input())

for i in range(q):
    s, t = map(int, input().split())
    for j in range(len(group)):
        if s in group[j] and t in group[j]:
            print("yes")
            break
        elif s in group[j]:
            print("no")
            break
    else:
        group_tmp = set(bfs(g, s).keys())
        if t in group_tmp:
            print("yes")
        else:
            print("no")
        group.append(group_tmp)