Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt
from itertools import permutations

def root_search(order, cost, wf, V): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = [] #一段階前の確定した道順
    pre_hold.append((0, "0", set() | order, 0)) #cost, pass, left, id
    hold_size = 0
    for i in range(type_num):
        for pre_cost, pre_pass, to_search, pre_id in pre_hold:
            for key in to_search:
                heappush(hold, (pre_cost + wf[pre_id][key] / sqrt(cost[key][1]), " ".join([pre_pass, str(key)]), to_search - {key}, key))
                hold_size += 1
        pre_hold = []

        for _ in range(min(hold_size, 4)):
            pre_hold.append(heappop(hold))
        hold = []
        hold_size = 0
 
    ans_cost, ans_pass, ans_search, ans_id = pre_hold[0]
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)
 
    return pass_list


def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf):
    d = 0
    c = 0.1 * store_hold /wf[current_id][0]
    for key in order:
        if cost[key][1]   / wf[current_id][key] > c: return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i, j in permutations(range(V), 2):
            if wf[i][j] > wf[i][k] + wf[k][j]:
                wf[i][j] = wf[i][k] + wf[k][j]
                next_id[i][j] = next_id[i][k]

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = dict()
    root_list = []
    cost = dict()
    for i in range(V): 
        store_list[i] = 0
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_hold = 0
                root_list = root_search(order, cost, wf, V)
                    
                current_id = heading = final_dist = 0

                final_dist = root_list[1] #次の行先の決定
                root_pointer = 1
                root_size = len(root_list)
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order.remove(heading) 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                for j in range(root_pointer, root_size - 1):
                    if cost[root_list[j + 1]][0] > 0:
                        final_dist = root_list[j + 1]
                        root_pointer = j + 1
                        if current_id > 0 and store_hold > 0:
                            final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)
                        break
                else: final_dist = 0

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt
from itertools import permutations

def root_search(order, cost, wf, V): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = [] #一段階前の確定した道順
    pre_hold.append((0, "0", set() | order, 0)) #cost, pass, left, id
    hold_size = 0
    for i in range(type_num):
        for pre_cost, pre_pass, to_search, pre_id in pre_hold:
            for key in to_search:
                heappush(hold, (pre_cost + wf[pre_id][key] / sqrt(cost[key][1]), " ".join([pre_pass, str(key)]), to_search - {key}, key))
                hold_size += 1
        pre_hold = []

        for _ in range(min(hold_size, 3)):
            pre_hold.append(heappop(hold))
        hold = []
        hold_size = 0
 
    ans_cost, ans_pass, ans_search, ans_id = pre_hold[0]
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)
 
    return pass_list


def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf):
    d = 0
    c = store_hold * (1000/wf[current_id][0])
    for key in order:
        if cost[key][1]  * (10000 / wf[current_id][key])> c: return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i, j in permutations(range(V), 2):
            if wf[i][j] > wf[i][k] + wf[k][j]:
                wf[i][j] = wf[i][k] + wf[k][j]
                next_id[i][j] = next_id[i][k]

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = dict()
    root_list = []
    cost = dict()
    for i in range(V): 
        store_list[i] = 0
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_hold = 0
                root_list = root_search(order, cost, wf, V)
                    
                current_id =  0

                final_dist = root_list[1] #次の行先の決定
                root_pointer = 1
                root_size = len(root_list)
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                for j in range(root_pointer, root_size - 1):
                    if cost[root_list[j + 1]][0] > 0:
                        final_dist = root_list[j + 1]
                        root_pointer = j + 1
                        if current_id > 0 and store_hold > 0:
                            final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)
                        break
                else: final_dist = 0

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt
from itertools import permutations

def root_search(order, cost, current_id, wf, V): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = deque() #一段階前の確定した道順
    initial = set() | order
    pre_hold.append((0, str(current_id), initial, current_id)) #cost, pass, left, id, time
    hold_size = 0
    for i in range(type_num):
        while pre_hold:
            pre_cost, pre_pass, to_search, pre_id = pre_hold.popleft()
            for key in to_search:
                new_cost = pre_cost + wf[pre_id][key] / sqrt(cost[key][1])
                new_pass = pre_pass + " " + str(key)
                heappush(hold, (new_cost, new_pass, to_search - {key}, key))
                hold_size += 1
        for _ in range(min(hold_size, 3)):
            item = heappop(hold)
            pre_hold.append(item)
        hold = []
        hold_size = 0
 
    ans_cost, ans_pass, ans_search, ans_id = pre_hold.popleft()
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)
 
    return pass_list


def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf):
    d = 0
    c = store_hold * (1000/wf[current_id][0])
    for key in order:
        if cost[key][1]  * (10000 / wf[current_id][key])> c: return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i, j in permutations(range(V), 2):
            if wf[i][j] > wf[i][k] + wf[k][j]:
                wf[i][j] = wf[i][k] + wf[k][j]
                next_id[i][j] = next_id[i][k]

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = dict()
    root_list = []
    cost = dict()
    store_time = set()
    for i in range(V): 
        store_list[i] = 0
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1
            store_time |= {t}

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_time = set()
                store_hold = 0
                root_list = root_search(order, cost, 0, wf, V)
                    
                current_id =  0

                final_dist = root_list[1] #次の行先の決定
                root_pointer = 1
                root_size = len(root_list)
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                for j in range(root_pointer, root_size - 1):
                    if cost[root_list[j + 1]][0] > 0:
                        final_dist = root_list[j + 1]
                        root_pointer = j + 1
                        if current_id > 0:
                            final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)
                        break
                else: final_dist = 0

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt
from itertools import permutations

def root_search(order, cost, current_id, wf, V, F): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = deque() #一段階前の確定した道順
    initial = set() 
    initial |= order
    pre_hold.append((0, str(current_id), initial, current_id)) #cost, pass, left, id, time
    for _ in range(type_num):
        pre_hold_size = len(pre_hold)
        for _ in range(pre_hold_size):
            pre_cost, pre_pass, to_search, pre_id = pre_hold.popleft()
            for key in to_search:
                new_cost =  -1 * pre_cost + wf[pre_id][key] / sqrt(cost[key][1])
                new_pass = pre_pass + " " + str(key)
                heappush(hold, (-1 * new_cost, new_pass, to_search - {key}, key))
                if len(hold) > 3: trush = heappop(hold)
        hold_size = len(hold)
        for _ in range(hold_size):
            item = heappop(hold)
            pre_hold.append(item)

    ans_cost, ans_pass, ans_search, ans_id = pre_hold.pop()
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)

    return pass_list

def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf):
    d = 0
    c = store_hold * (1000/wf[current_id][0])
    for key in order:
        if cost[key][1]  * (10000 / wf[current_id][key])> c: return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i, j in permutations(range(V), 2):
            if wf[i][j] > wf[i][k] + wf[k][j]:
                wf[i][j] = wf[i][k] + wf[k][j]
                next_id[i][j] = next_id[i][k]

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = dict()
    root_list = []
    cost = dict()
    store_time = set()
    for i in range(V): 
        store_list[i] = 0
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1
            store_time |= {t}

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_time = set()
                store_hold = 0
                root_list = root_search(order, cost, 0, wf, V, F)
                    
                current_id =  0

                final_dist = root_list[1] #次の行先の決定
                root_pointer = 1
                root_size = len(root_list)
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                for j in range(root_pointer, root_size - 1):
                    if cost[root_list[j + 1]][0] > 0:
                        final_dist = root_list[j + 1]
                        root_pointer = j + 1
                        if current_id > 0:
                            final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)
                        break
                else: final_dist = 0

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt

def root_search(order, cost, current_id, wf, V, F): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = deque() #一段階前の確定した道順
    next_search = deque()
    initial = set() 
    initial |= order
    pre_hold.append((0, str(current_id), initial, current_id)) #cost, pass, left, id, time
    for i in range(type_num): 
        for _ in range(len(pre_hold)):
            pre_cost, pre_pass, to_search, pre_id = pre_hold.popleft()
            for key in to_search:
                new_cost =  -1 * pre_cost + wf[pre_id][key] / sqrt(cost[key][1] / F[key])
                new_pass = pre_pass + " " + str(key)
                heappush(hold, (-1 * new_cost, new_pass, to_search - {key}, key))
                if len(hold) > 4: trush = heappop(hold)
        for _ in range(len(hold)):
            item = heappop(hold)
            pre_hold.append(item)

    ans_cost, ans_pass, ans_search, ans_id = pre_hold.pop()
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)

    return pass_list

def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf):
    d = 0
    c = store_hold * (1000/wf[current_id][0])
    for key in order:
        if cost[key][1]  * (10000 / wf[current_id][key])> c:
            return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = dict()
    root_list = []
    cost = dict()
    store_time = set()
    for i in range(V): 
        store_list[i] = 0
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1
            store_time |= {t}

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_time = set()
                store_hold = 0
                root_list = root_search(order, cost, 0, wf, V, F)
                    
                current_id = heading = final_dist = 0
                root_pointer = 0

                final_dist = root_list[root_pointer + 1] #次の行先の決定
                root_pointer += 1
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                final_dist = root_list[root_pointer + 1]
                root_pointer += 1

                if current_id > 0:
                    final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt

def root_search(order, cost, current_id, wf, V, F): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = deque() #一段階前の確定した道順
    next_search = deque()
    initial = set() 
    initial |= order
    pre_hold.append((0, str(current_id), initial, current_id)) #cost, pass, left, id, time
    for i in range(type_num): 
        while pre_hold:
            pre_cost, pre_pass, to_search, pre_id = pre_hold.popleft()
            for key in to_search:
                new_cost =  -1 * pre_cost + wf[pre_id][key] / sqrt(cost[key][1] / F[key])
                new_pass = pre_pass + " " + str(key)
                heappush(hold, (-1 * new_cost, new_pass, to_search - {key}, key))
                if len(hold) > 3: trush = heappop(hold)
        while hold:
            item = heappop(hold)
            pre_hold.append(item)

    ans_cost, ans_pass, ans_search, ans_id = pre_hold.pop()
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)

    return pass_list

def decide_next_dst(cost, order, current_id, final_dist, store_hold, wf, F):
    d = 0
    c = (wf[current_id][0] + wf[0][final_dist]) / sqrt(store_hold) 
    if wf[current_id][final_dist] / sqrt(cost[final_dist][1] / F[final_dist]) > c: return 0
    return final_dist

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = [0] * V
    root_list = []
    cost = dict()
    store_time = set()
    for i in range(V): 
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1
            store_time |= {t}

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_time = set()
                store_hold = 0
                root_list = root_search(order, cost, 0, wf, V, F)
                    
                current_id = heading = final_dist = 0
                root_pointer = 0

                final_dist = root_list[root_pointer + 1] #次の行先の決定
                root_pointer += 1
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                final_dist = root_list[root_pointer + 1]
                root_pointer += 1

                if current_id > 0 and cost[final_dist][1] > 0 and store_hold > 0 and F[final_dist] > 0:
                    final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf, F)

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush
from math import sqrt

def root_search(order, cost, current_id, wf, V): #店舗から出るときの探索
    type_num = len(order)
    hold = [] #holdで上位n個のみ保持し、最後に残ったものをpre_holdに移す
    heapify(hold)
    pre_hold = deque() #一段階前の確定した道順
    next_search = deque()
    initial = set()
    initial |= order
    pre_hold.append((0, str(current_id), initial, current_id)) #cost, pass, left, id, time
    for i in range(type_num):
        while pre_hold:
            pre_cost, pre_pass, to_search, pre_id = pre_hold.popleft()
            for key in to_search:
                new_cost =  -1 * pre_cost + wf[pre_id][key] / sqrt(cost[key][1])
                new_pass = pre_pass + " " + str(key)
                heappush(hold, (-1 * new_cost, new_pass, to_search - {key}, key))
                if len(hold) > 3: trush = heappop(hold)
        while hold:
            item = heappop(hold)
            pre_hold.append(item)

    ans_cost, ans_pass, ans_search, ans_id = pre_hold.pop()
    pass_list = [int(v) for v in ans_pass.split()]
    pass_list.append(0)

    return pass_list

def decide_next_dst(cost, order, current_id, final_dist, store_cost, wf):
    d = 0
    c = store_cost * (1000/wf[current_id][0])
    for key in order:
        if cost[key][1]  * (10000 / wf[current_id][key])> c:
            return final_dist
    return 0

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    #グラフの直径を求める
    dmax = 0
    for i in range(V): dmax = max(dmax, max(wf[i]))

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    driver_hold = 0
    root_pointer = 0
    store_list = [0] * V
    root_list = []
    cost = dict()
    store_time = set()
    for i in range(V): 
        cost[i] = [0, 0]
    store_hold = 0

    for t in range(T):
        N = int(input())
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            store_hold += 1
            store_list[dst - 1] += 1
            store_time |= {t}

        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                driver_hold += store_hold
                for key in order: 
                    cost[key][1] += 0.5 * cost[key][0] + store_list[key]
                    cost[key][0] += store_list[key]
                    store_list[key] = 0
                stuck_order = set()
                store_time = set()
                store_hold = 0
                root_list = root_search(order, cost, 0, wf, V)
                    
                current_id = heading = final_dist = 0
                root_pointer = 0
                len_root = len(root_list) 

                final_dist = root_list[root_pointer + 1] #次の行先の決定
                root_pointer += 1
                
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][0]
                cost[heading] = [0, 0]
 
            current_id = heading #現在地の更新
            if current_id == final_dist:
                final_dist = root_list[root_pointer + 1]
                root_pointer += 1

                if current_id > 0:
                    final_dist = decide_next_dst(cost, order, current_id, final_dist, store_hold, wf)

                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            command[t] = heading + 1

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()




Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()

Buggy python submission (verdict: Time Limit Exceeded):
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def solve():
    inf = 100000000
    input = sys.stdin.readline
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)
    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    for k in range(V):
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 
    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    for t in range(T):
        N = int(input()) #注文の発生
        if N == 1:
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
        Nput = int(input())
        if Nput > 0:
            putid = [int(input()) for p in range(Nput)]

        if dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
            
        
        elif heading == 0: #店にいるときの処理
            order |= stuck_order
            stuck_order = set()
            if order == {}: print(-1, flush = True)
            else:
                for k in order:
                    final_dist = k
                    heading = next_id[0][k]
                    dist_left = edge[0][heading] - 1
                    print(heading + 1, flush= True)
                    break
        
        else: #家にいるときの処理
            if heading in order: order -= {heading} #荷物の積み下ろし

            if len(order) > 0: #まだ配達すべき荷物があるとき
                for k in order:
                    current = heading
                    final_dist = k
                    heading = next_id[current][final_dist]
                    dist_left = edge[current][heading] - 1
                    print(heading + 1, flush = True)
                    break
                
            else: #荷物が無いので店に戻る
                final_dist = 0
                current = heading
                heading = next_id[current][final_dist]
                dist_left = edge[current][heading] - 1
                print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": break
        else:
            Nar = int(input())
            if Nar > 0: arc = [int(input()) for a in range(Nar)]
        
    #print(wf)
    #print(next_id)

    return 

if __name__ == "__main__":
    solve()

Fixed submission:
import sys
from collections import deque
from heapq import heapify, heappop, heappush

def decide_next_dst(cost, order):
    d = 0
    c = 0
    for key in order:
        if cost[key][0] > c:
            d = key
            c = cost[key][0]
    return (d, c)

def solve():
    inf = 10000000000
    
    V, E = map(int, input().split())
    edge = dict()
    wf = dict()
    next_id = dict() #iからjに行くときにiの次に訪れる地点
    for i in range(V):
        edge[i] = dict()
        wf[i] = dict()
        next_id[i] = dict()
        for j in range(V):
            edge[i][j] = (0 if i == j else inf)
            next_id[i][j] = j
            wf[i][j] = (0 if i == j else inf)

    for _ in range(E):
        u, v, d = map(int, input().split())
        edge[u - 1][v - 1] = d
        edge[v - 1][u - 1] = d
        wf[u - 1][v - 1] = d
        wf[v - 1][u - 1] = d

    #全頂点最短経路と目的の頂点に向かうとき次に行くべき頂点の復元
    for k in range(V): 
        for i in range(V):
            for j in range(V):
                if wf[i][j] > wf[i][k] + wf[k][j]:
                    wf[i][j] = wf[i][k] + wf[k][j]
                    next_id[i][j] = next_id[i][k] 

    F = [int(f) for f in input().split()]
    T = int(input())
    order = set()
    stuck_order = set()

    command = [None] * T
    heading = 0 #次に向かう地点
    dist_left = 0 #次に向かう地点までの残り距離
    final_dist = 0
    stuck_cost = [[0, 0] for _ in range(V)] 
    cost = [[0, 0] for _ in range(V)] 
    driver_hold = 0
    store_hold = 0
    current_id = 0

    for t in range(T):
        N = int(input()) 
        for i in range(N):
            new_id, dst = map(int, input().split())
            stuck_order |= {dst - 1}
            stuck_cost[dst - 1][0] += (5000 - t) ** 2
            stuck_cost[dst - 1][1] += 1
            store_hold += 1
        Nput = int(input()) #とりあえずジャッジから来る入力を受けておく(使用しない)
        for np in range(Nput):
            putid = int(input())

        if heading == dist_left == 0: #店舗に止まっている場合
            current_id = 0
            if store_hold == driver_hold == 0: 
                    print(-1, flush = True)
            else:
                order |= stuck_order
                for key in order: 
                    cost[key][0] += stuck_cost[key][0]
                    cost[key][1] += stuck_cost[key][1]
                    driver_hold += stuck_cost[key][1]
                    stuck_cost[key] = [0, 0]
                stuck_order = set()
                store_hold = 0

                final_dist, max_hold = decide_next_dst(cost, order) #次の行先の決定
                heading = next_id[0][final_dist]
                dist_left = edge[0][heading] - 1
                print(heading + 1, flush = True)

        elif dist_left > 0: #移動中の場合そのまま移動を続ける
            dist_left -= 1
            print(heading + 1, flush = True)
        
        else: #店舗以外の頂点にいるとき
            if heading in order and heading > 0: #顧客のいる場所で荷物を積み下ろすとき
                order -= {heading} 
                driver_hold -= cost[heading][1]
                cost[heading] = [0, 0]

            current_id = heading #現在地の更新
            if len(order) > 0: #まだ配達すべき荷物があるとき
                if current_id == final_dist: #目的地に到着したときは残りの荷物で先に運ぶべき荷物を選ぶ
                    final_dist, max_hold = decide_next_dst(cost, order)
                    if driver_hold < store_hold or store_hold > 20: final_dist = 0  #荷物が店に溜まっているうえ一度に掃ける個数が少ないので店に戻る
            else: final_dist = 0 #荷物が無いので店に戻る
                
            heading = next_id[current_id][final_dist]
            dist_left = edge[current_id][heading] - 1
            print(heading + 1, flush = True)

        verdict = input()
        if verdict == "NG": sys.exit()
        Narc = int(input())
        for _ in range(Narc):
                achieve = int(input())

    return 0

if __name__ == "__main__":
    solve()