Buggy python submission (verdict: Time Limit Exceeded):
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return math.factorial(j) // math.factorial(2) // math.factorial(j - 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  res_list[m] = s - combs[m] + ncr(A_c[m] - 1)

for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))

Fixed submission:
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return int(j * (j-1) / 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  res_list[m] = s - combs[m] + ncr(A_c[m] - 1)

for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))

Buggy python submission (verdict: Time Limit Exceeded):
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

# res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return math.factorial(j) // math.factorial(2) // math.factorial(j - 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  cnt = combs[m]

  n = s
  n -= cnt # the only inaccurate entry
  n += ncr(A_c[m] - 1)
  res_list[m] = n

res = []
# for k in range(N):
#   res += '\n' + str(res_list[A[k]])
# print(res[1:])
for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))

Fixed submission:
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return int(j * (j-1) / 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  res_list[m] = s - combs[m] + ncr(A_c[m] - 1)

for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))

Buggy python submission (verdict: Time Limit Exceeded):
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = []

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return math.factorial(j) // math.factorial(2) // math.factorial(j - 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for k in range(N): # k = k - 1
  m = A[k] # value of k
  cnt = combs[m] # number of combinations for k

  n = s
  n -= cnt # the only inaccurate entry
  n += ncr(A_c[m] - 1)
  res.append(n)

print('\n'.join([str(s) for s in res]))

Fixed submission:
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return int(j * (j-1) / 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  res_list[m] = s - combs[m] + ncr(A_c[m] - 1)

for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))

Buggy python submission (verdict: Time Limit Exceeded):
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = []

for k in range(1, N + 1):
  A_tmp = list(A) # list() to make a new copy and avoid editing the original list
  del A_tmp[k - 1]
  A_tmp = Counter(A_tmp)

  n = 0
  for i in range(len(A_tmp)):
    j = list(A_tmp.values())[i]
    if j >= 2:
      n += math.factorial(j) // math.factorial(2) // math.factorial(j - 2)
  res.append(n)



print('\n'.join([str(s) for s in res]))

Fixed submission:
N = int(input())
A = [int(k) for k in input().split(' ')]

from collections import Counter 
import math 

res = [] # solution for each key in A
res_list = {} # solution for each value in A

# counter ver
A_c = Counter(A)
l = len(A_c)

def ncr(j):
  return int(j * (j-1) / 2) if j >= 2 else 0

# store ncr for each value 
combs = {k: ncr(v) for k, v in A_c.items()}

s = sum(combs.values())
  
for m in A_c.keys():
  res_list[m] = s - combs[m] + ncr(A_c[m] - 1)

for k in range(N):
  res.append(res_list[A[k]])
print('\n'.join([str(s) for s in res]))