# coding: utf-8
import array, bisect, collections, copy, heapq, itertools, math, random, re, string, sys, time
sys.setrecursionlimit(10 ** 7)
INF = 10 ** 20
MOD = 10 ** 9 + 7


def II(): return int(input())
def ILI(): return list(map(int, input().split()))
def IAI(LINE): return [ILI() for __ in range(LINE)]
def IDI(): return {key: value for key, value in ILI()}


def read():
    R, C, N = ILI()
    num_point = []
    for __ in range(N):
        x_1, y_1, x_2, y_2 = ILI()
        num_point.append([(x_1, y_1), (x_2, y_2)])
    return R, C, N, num_point


# 周上を (0, 0) を原点として反時計回りに 1 本の数直線とした時の point の座標を返す．
# 周上にあるかの判定も行う．
def change_edge_point(R, C, point):
    x, y = point
    if 0 < x < C and 0 < y < R:
        return False
    if y == 0:
        return x
    elif y == R:
        return C + R + C - x
    if x == 0:
        return C + y
    elif x == R:
        return C + R + C + R - y


def solve(R, C, N, num_point):
    point_double = []
    for point in num_point:
        print(point)
        p_1, p_2 = point
        ret_1 = change_edge_point(R, C, p_1)
        ret_2 = change_edge_point(R, C, p_2)
        print(ret_1)
        print(ret_2)
        if ret_1 is False or ret_2 is False:
            continue
        point_double.append((min(ret_1, ret_2), max(ret_1, ret_2)))

    for p_1, p_2 in itertools.combinations(point_double, 2):
        if p_1[0] == p_2[0] or p_1[1] == p_2[1]:
            return "NO"

        if p_1[0] < p_2[0]:
            if p_1[1] > p_2[1]:
                continue
            else:
                return "NO"
        elif p_1[0] > p_2[0]:
            if p_1[1] < p_2[1]:
                continue
            else:
                return "NO"

    return "YES"


def main():
    params = read()
    print(solve(*params))


if __name__ == "__main__":
    main()


### FIXED CODE ###

# coding: utf-8
import array, bisect, collections, copy, heapq, itertools, math, random, re, string, sys, time
sys.setrecursionlimit(10 ** 7)
INF = 10 ** 20
MOD = 10 ** 9 + 7


def II(): return int(input())
def ILI(): return list(map(int, input().split()))
def IAI(LINE): return [ILI() for __ in range(LINE)]
def IDI(): return {key: value for key, value in ILI()}


def read():
    R, C, N = ILI()
    num_point = []
    for __ in range(N):
        x_1, y_1, x_2, y_2 = ILI()
        num_point.append([(x_1, y_1), (x_2, y_2)])
    return R, C, N, num_point


# 周上を (0, 0) を原点として反時計回りに 1 本の数直線とした時の point の座標を返す．
# 周上にあるかの判定も行う．
def change_edge_point(R, C, point):
    x, y = point
    if x == 0:
        return R * 2 + C + (C - y)
    if x == R:
        return R + y
    if y == 0:
        return x
    if y == C:
        return R + C + (R - x)


def solve(R, C, N, num_point):
    point_double = []
    for ind, point in enumerate(num_point):
        p_1, p_2 = point
        if ((p_1[0] == 0 or p_1[0] == R) or (p_1[1] == 0 or p_1[1] == C)) and ((p_2[0] == 0 or p_2[0] == R) or (p_2[1] == 0 or p_2[1] == C)):
            point_double.append((ind + 1, change_edge_point(R, C, p_1)))
            point_double.append((ind + 1, change_edge_point(R, C, p_2)))
    point_double.sort(key=lambda  x: x[1])
    stack = []
    for point in point_double:
        if len(stack) == 0:
            stack.append(point[0])
            continue
        if point[0] == stack[-1]:
            stack.pop()
        else:
            stack.append(point[0])
    
    if len(stack) == 0:
        return "YES"
    else:
        return "NO"
    

def main():
    params = read()
    print(solve(*params))


if __name__ == "__main__":
    main()