### BUGGY CODE ###

import sys
import heapq
import re
from itertools import permutations
from bisect import bisect_left, bisect_right
from collections import Counter, deque
from fractions import gcd
from math import factorial, sqrt
INF = 1 << 60
mod = 1000000007
sys.setrecursionlimit(10 ** 7)
input = sys.stdin.readline

# UnionFind
class UnionFind():
    def __init__(self, n):
        self.n = n
        self.parents = [-1] * n

    def find(self, x):
        if self.parents[x] < 0:
            return x
        else:
            self.parents[x] = self.find(self.parents[x])
            return self.parents[x]

    def union(self, x, y):
        x = self.find(x)
        y = self.find(y)

        if x == y:
            return

        if self.parents[x] > self.parents[y]:
            x, y = y, x

        self.parents[x] += self.parents[y]
        self.parents[y] = x

    def size(self, x):
        return -self.parents[self.find(x)]

    def same(self, x, y):
        return self.find(x) == self.find(y)

    def members(self, x):
        root = self.find(x)
        return [i for i in range(self.n) if self.find(i) == root]

    def roots(self):
        return [i for i, x in enumerate(self.parents) if x < 0]

    def group_count(self):
        return len(self.roots())

    def all_group_members(self):
        return {r: self.members(r) for r in self.roots()}

    def __str__(self):
        return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())

# ダイクストラ
def dijkstra_heap(s, edge, n):
    #始点sから各頂点への最短距離
    d = [10**20] * n
    used = [True] * n #True:未確定
    d[s] = 0
    used[s] = False
    edgelist = []
    for a,b in edge[s]:
        heapq.heappush(edgelist,a*(10**6)+b)
    while len(edgelist):
        minedge = heapq.heappop(edgelist)
        #まだ使われてない頂点の中から最小の距離のものを探す
        if not used[minedge%(10**6)]:
            continue
        v = minedge%(10**6)
        d[v] = minedge//(10**6)
        used[v] = False
        for e in edge[v]:
            if used[e[1]]:
                heapq.heappush(edgelist,(e[0]+d[v])*(10**6)+e[1])
    return d

#　素因数分解
def factorization(n):
    arr = []
    temp = n
    for i in range(2, int(-(-n**0.5//1))+1):
        if temp%i==0:
            cnt=0
            while temp%i==0:
                cnt+=1
                temp //= i
            arr.append([i, cnt])

    if temp!=1:
        arr.append([temp, 1])

    if arr==[]:
        arr.append([n, 1])

    return arr

# ここから書き始める
# Colorful Leaderboard 
# n = int(input())
# a = list(map(int, input().split()))
# s = [0] * 8
# cnt = 0
# for i in a:
#     if i < 3200:
#         s[i // 400] = 1
#     else:
#         cnt += 1
# # print(s)
# maximum = sum(s) + cnt
# minimum = sum(s)
# print(minimum, maximum)

def dfs(total, index):
    if index == n:
        if total % 10 != 0:
            return total
        return 0
    return max(dfs(total + s[index], index + 1), dfs(total, index + 1))

n = int(input())
s = [0] * n
for i in range(n):
    s[i] = int(input())
ans = dfs(0, 0)
print(ans)


### FIXED CODE ###

import itertools
import math
import sys
from collections import Counter
from fractions import gcd
from functools import reduce
import sys
sys.setrecursionlimit(4100000)

INF = 1 << 60

# ここから書き始める
n = int(input())
s = [int(input()) for i in range(n)]
if sum(s) % 10 != 0:
    print(sum(s))
else:
    s.sort()
    for i in s:
        if i % 10 != 0:
            print(sum(s) - i)
            break
    else:
        print(0)