### BUGGY CODE ###

from collections import defaultdict,deque
from heapq import heappush, heappop
from itertools import permutations
import sys
import math
import bisect
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
    res = list(sys.stdin.readline())
    if res[-1] == "\n":
        return res[:-1]
    return res
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007
"""
#N,K,Mが入力
    n,k,m=LI() 
    #N
    #x1 y1
    #.  .
    #xn ynが入力
    N=I()
    p=LIR(N)
    print(n,k,m,p)
"""
############################## ユニオン木(union tree) ###################################
#uf=UnionFind(n)と使う
# print(uf.roots())
# print(uf.all_group_members())
class UnionFind:
    def __init__(self, n):
        self.n=n
        self.par = [-1 for i in range(self.n+1)]
        self.rank = [0 for i in range(self.n+1)]#素集合でないとrankは意味がなさそう,素集合であればrank kには少なくとも2^k要素がある。
    
    # 検索
    def find(self, x):
        # if self.par[x] == x:
        if self.par[x] <0:
            return x
        else:
            self.par[x] = self.find(self.par[x])
            return self.par[x]

    # 併合
    def union(self, x, y):
        x = self.find(x)
        y = self.find(y)
        if x==y:
            return
        if self.rank[x] < self.rank[y]:
            self.par[x] = y
        else:
            self.par[y] = x
            if self.rank[x] == self.rank[y]:
                self.rank[x] += 1
        
    # 同じ集合に属するか判定
    def same(self, x, y):
        return self.find(x) == self.find(y)

    #要素xが属するグループに属する要素をリストで返す
    def members(self, x):
        root = self.find(x)
        return [i for i in range(self.n+1) if self.find(i) == root]

    #すべての根の要素をリストで返す
    def roots(self):
        return [i for i, x in enumerate(self.par) if x<0]

    #グループの数を返す
    def group_count(self):
        return len(self.roots())

    #{ルート要素: [そのグループに含まれる要素のリスト], ...}の辞書を返す
    def all_group_members(self):
        return {int(r):self.members(r) for r in self.roots()}

    def __str__(self):
        return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())
   

def resolve():
    n,m=LI()
    s=LIR(m)
    ans=[0 for i in range(m)]
    u=UnionFind(n-1)
    buf=n*(n-1)//2
    ans[0]=buf
    for i in range(m):#後ろからiつ目までは橋が壊れていない
        if i>0:
            a=s[m-1-(i-1)][0]-1
            b=s[m-1-(i-1)][1]-1
            if(u.same(a,b)==False):
                buf-=len(u.members(a))*len(u.members(b))
                u.union(a,b)
            ans[i]=buf
        #d=u.all_group_members()
        #roots=u.roots()
        #lroots=len(roots)
        #for ri in range(lroots):
        #for rj in range(lroots):
        #        if(ri>=rj):continue
        #        buf+=len(d[roots[ri]])*len(d[roots[rj]])
        #ans[m-1-i]=buf

    for i in (reversed(range(m))):
        print(ans[i])    

import sys
from io import StringIO
import unittest

class TestClass(unittest.TestCase):
    def assertIO(self, input, output):
        stdout, stdin = sys.stdout, sys.stdin
        sys.stdout, sys.stdin = StringIO(), StringIO(input)
        resolve()
        sys.stdout.seek(0)
        out = sys.stdout.read()[:-1]
        sys.stdout, sys.stdin = stdout, stdin
        self.assertEqual(out, output)
    def test_入力例_1(self):
        input = """4 5
1 2
3 4
1 3
2 3
1 4"""
        output = """0
0
4
5
6"""
        self.assertIO(input, output)
    def test_入力例_2(self):
        input = """6 5
2 3
1 2
5 6
3 4
4 5"""
        output = """8
9
12
14
15"""
        self.assertIO(input, output)
    def test_入力例_3(self):
        input = """2 1
1 2"""
        output = """1"""
        self.assertIO(input, output)

if __name__ == "__main__":
    # unittest.main()
    resolve()

### FIXED CODE ###

from collections import defaultdict,deque
from heapq import heappush, heappop
from itertools import permutations
import sys
import math
import bisect
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def I(): return int(sys.stdin.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
    res = list(sys.stdin.readline())
    if res[-1] == "\n":
        return res[:-1]
    return res
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007
"""
#N,K,Mが入力
    n,k,m=LI() 
    #N
    #x1 y1
    #.  .
    #xn ynが入力
    N=I()
    p=LIR(N)
    print(n,k,m,p)
"""
############################## ユニオン木(union tree) ###################################
#uf=UnionFind(n)と使う
# print(uf.roots())
# print(uf.all_group_members())
class UnionFind:
    def __init__(self, n):
        self.n=n
        self.par = [-1 for i in range(self.n+1)]
        self.rank = [0 for i in range(self.n+1)]#素集合でないとrankは意味がなさそう,素集合であればrank kには少なくとも2^k要素がある。
    
    # 検索
    def find(self, x):
        # if self.par[x] == x:
        if self.par[x] <0:
            return x
        else:
            self.par[x] = self.find(self.par[x])
            return self.par[x]

    # 併合
    def union(self, x, y):
        x = self.find(x)
        y = self.find(y)
        if x==y:
            return
        if self.rank[x] < self.rank[y]:
            self.par[y]+=self.par[x]
            self.par[x] = y
        else:
            self.par[x]+=self.par[y]
            self.par[y] = x
            if self.rank[x] == self.rank[y]:
                self.rank[x] += 1
        
    # 同じ集合に属するか判定
    def same(self, x, y):
        return self.find(x) == self.find(y)

    #要素xが属するグループに属する要素をリストで返す
    def members(self, x):
        root = self.find(x)
        return [i for i in range(self.n+1) if self.find(i) == root]

    def size(self, x):
        return -self.par[self.find(x)]

    #すべての根の要素をリストで返す
    def roots(self):
        return [i for i, x in enumerate(self.par) if x<0]

    #グループの数を返す
    def group_count(self):
        return len(self.roots())

    #{ルート要素: [そのグループに含まれる要素のリスト], ...}の辞書を返す
    def all_group_members(self):
        return {int(r):self.members(r) for r in self.roots()}

    def __str__(self):
        return '\n'.join('{}: {}'.format(r, self.members(r)) for r in self.roots())
   

def resolve():
    n,m=LI()
    s=LIR(m)
    ans=[0 for i in range(m)]
    u=UnionFind(n-1)
    buf=n*(n-1)//2
    ans[0]=buf
    for i in range(m):#後ろからiつ目までは橋が壊れていない
        if i>0:
            a=s[m-1-(i-1)][0]-1
            b=s[m-1-(i-1)][1]-1
            if(u.same(a,b)==False):
                buf-=(u.size(a))*(u.size(b))
                u.union(a,b)
            ans[i]=buf
            # print(u.all_group_members())
        #d=u.all_group_members()
        #roots=u.roots()
        #lroots=len(roots)
        #for ri in range(lroots):
        #for rj in range(lroots):
        #        if(ri>=rj):continue
        #        buf+=len(d[roots[ri]])*len(d[roots[rj]])
        #ans[m-1-i]=buf

    for i in (reversed(range(m))):
        print(ans[i])    

import sys
from io import StringIO
import unittest

class TestClass(unittest.TestCase):
    def assertIO(self, input, output):
        stdout, stdin = sys.stdout, sys.stdin
        sys.stdout, sys.stdin = StringIO(), StringIO(input)
        resolve()
        sys.stdout.seek(0)
        out = sys.stdout.read()[:-1]
        sys.stdout, sys.stdin = stdout, stdin
        self.assertEqual(out, output)
    def test_入力例_1(self):
        input = """4 5
1 2
3 4
1 3
2 3
1 4"""
        output = """0
0
4
5
6"""
        self.assertIO(input, output)
    def test_入力例_2(self):
        input = """6 5
2 3
1 2
5 6
3 4
4 5"""
        output = """8
9
12
14
15"""
        self.assertIO(input, output)
    def test_入力例_3(self):
        input = """2 1
1 2"""
        output = """1"""
        self.assertIO(input, output)

if __name__ == "__main__":
    # unittest.main()
    resolve()