### BUGGY CODE ###

# Fast IO (only use in integer input)

import os,io
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline

N = int(input())
Resident = []
for i in range(N):
    x,y,p = map(int,input().split())
    Resident.append((x,y,p))

def abs(N):
    if N >= 0:
        return N
    else:
        return -N

minCost = [-1] * (N+1)

preCalRange = 1 << N

horizontalLineDistance = []
verticalLineDistance = []

for i in range(preCalRange):
    railRoad = bin(i)[2:]
    railRoad = '0' * (N - len(railRoad)) + railRoad
    horizontalLineDistance.append([])
    verticalLineDistance.append([])
    for j in range(N):
        horizontalLineDistance[i].append(min(abs(Resident[j][0]),abs(Resident[j][1])))
        verticalLineDistance[i].append(min(abs(Resident[j][0]),abs(Resident[j][1])))
        for k in range(N):
            if railRoad[k] == '1' and abs(Resident[j][0] - Resident[k][0]) < horizontalLineDistance[i][j]:
                horizontalLineDistance[i][j] = abs(Resident[j][0] - Resident[k][0])
            if railRoad[k] == '1' and abs(Resident[j][1] - Resident[k][1]) < verticalLineDistance[i][j]:
                verticalLineDistance[i][j] = abs(Resident[j][1] - Resident[k][1])

totalCases = 3 ** N

for i in range(totalCases):
    railRoad = []
    tmp = i
    for j in range(N):
        railRoad.append(tmp % 3)
        tmp //= 3
    horizontalCount = 0
    verticalCount = 0
    numNewRailroad = 0
    for j in range(N):
        if railRoad[j] == 1:
            numNewRailroad += 1
            horizontalCount += 1 << j
        if railRoad[j] == 2:
            verticalCount += 1 << j
            numNewRailroad += 1
    minDistance = []
    for j in range(N):
        minDistance.append(min(horizontalLineDistance[horizontalCount][j], verticalLineDistance[verticalCount][j]))

    cost = 0
    for j in range(N):
        cost += Resident[j][2] * minDistance[j]
    if minCost[numNewRailroad] == -1 or minCost[numNewRailroad] > cost:
        minCost[numNewRailroad] = cost
for elem in minCost:
    print(elem)


### FIXED CODE ###

# Fast IO (only use in integer input)

# TLE

import os,io
input=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline

def main():

    N = int(input())
    Resident = []
    for i in range(N):
        x,y,p = map(int,input().split())
        Resident.append((x,y,p))

    def abs(N):
        if N >= 0:
            return N
        else:
            return -N

    minCost = [float("inf")] * (N+1)

    preCalRange = 1 << N

    horizontalLineDistance = []
    verticalLineDistance = []

    for i in range(preCalRange):
        railRoad = bin(i)[2:]
        railRoad = '0' * (N - len(railRoad)) + railRoad
        horizontalLineDistance.append([])
        verticalLineDistance.append([])
        for j in range(N):
            horizontalLineDistance[i].append(min(abs(Resident[j][0]),abs(Resident[j][1])))
            verticalLineDistance[i].append(min(abs(Resident[j][0]),abs(Resident[j][1])))
            for k in range(N):
                if railRoad[k] == '1' and abs(Resident[j][0] - Resident[k][0]) < horizontalLineDistance[i][j]:
                    horizontalLineDistance[i][j] = abs(Resident[j][0] - Resident[k][0])
                if railRoad[k] == '1' and abs(Resident[j][1] - Resident[k][1]) < verticalLineDistance[i][j]:
                    verticalLineDistance[i][j] = abs(Resident[j][1] - Resident[k][1])

    power2 = [1]
    for i in range(N):
        power2.append(power2[-1] * 2)
    loopCount = power2[N]
    for i in range(loopCount):
        numNewRailroad = bin(i)[2:].count('1')
        j = i
        while j >= 0:
            j &= i
            goodList1 = horizontalLineDistance[j]
            goodList2 = verticalLineDistance[i - j]
            cost = 0
            for k in range(N):
                cost += Resident[k][2] * min(goodList1[k], goodList2[k])
            if minCost[numNewRailroad] > cost:
                minCost[numNewRailroad] = cost
            j -= 1
    for elem in minCost:
        print(elem)

main()