### BUGGY CODE ###

def main():
    class rolling_hash():
        def __init__(self, sequence, char_list=None):
            self.sequence = sequence  # 文字列
            self.seq_size = len(self.sequence)  # 文字列の長さ
            self.mod = 2**61-1  # mod
            if char_list is None:  # 使われている文字のリスト
                self.char_list = 'abcdefghijklmnopqrstuvwxyz'
            else:
                self.char_list = char_list
            self.base = len(self.char_list)+1  # 文字の種類数
            self.char_dict = {j: i+1 for i,
                              j in enumerate(self.char_list)}  # 文字と数値の対応表
            self.Hash_0start = [0]*(self.seq_size+1)  # 先頭からi-1文字目までのハッシュ値
            for i in range(self.seq_size):
                self.Hash_0start[i+1] = self.Hash_0start[i] + \
                    self.char_dict[self.sequence[i]] * \
                    pow(self.base, i, self.mod)

        def calc_hash(self, l, r):  # l文字目からr-1文字目までのハッシュ値
            return ((self.Hash_0start[r] - self.Hash_0start[l])
                    * pow(self.base, l*(self.mod-2), self.mod)) % self.mod

    n = int(input())
    a = list(map(int, input().split()))
    b = list(map(int, input().split()))

    memo = [0]*n

    for k in range(32):
        a1 = [i % 2 for i in a]
        a1 += a1
        a2 = [i ^ 1 for i in a1]
        b_hash = rolling_hash([i % 2 for i in b], [0, 1]).calc_hash(0, n)
        a1 = rolling_hash(a1, [0, 1])
        a2 = rolling_hash(a2, [0, 1])
        for i in range(n):
            if memo[i] is None:
                continue
            elif a1.calc_hash(i, i+n) == b_hash:
                pass
            elif a2.calc_hash(i, i+n) == b_hash:
                memo[i] += 2**k
            else:
                memo[i] = None
        a = [i // 2 for i in a]
        b = [i // 2 for i in b]

    for i, j in enumerate(memo):
        if j != None:
            print(i, j)


main()


### FIXED CODE ###

def main():
    mod = 2**31-1
    pow3 = [1]*200001
    p = 1
    i3 = pow(3, mod-2, mod)
    for i in range(1, 200001):
        p = p*3 % mod
        pow3[i] = p

    def rolling_hash(seq):
        h = 0
        for i, j in enumerate(seq):
            h += (j+1)*pow3[i]
        h %= mod
        H0s = [0]*n
        for i, j in enumerate(seq):
            H0s[i] = h
            h = (h-j-1+(j+1)*pn)*i3 % mod
        return H0s

    def rolling_hash2(seq):
        p = 0
        p2 = 0
        for i, j in enumerate(seq):
            p += (j+1)*pow3[i]
            p2 += (2-j)*pow3[i]
        return p % mod, p2 % mod

    n = int(input())
    a = list(map(int, input().split()))
    b = list(map(int, input().split()))
    m = max(a+b)
    a1 = [0]*n
    b1 = [0]*n
    memo = [0]*n
    cnt = n
    pn = pow3[n]

    for k in range(len(bin(m))-2):
        k2 = 2**k
        for i, j in enumerate(a):
            a1[i] = (j & k2) >> k
        for i, j in enumerate(b):
            b1[i] = (j & k2) >> k
        b_hash, b_hash2 = rolling_hash2(b1)
        A1 = rolling_hash(a1)
        for i, (j, k) in enumerate(zip(memo, A1)):
            if j is None:
                continue
            elif k == b_hash:
                pass
            elif k == b_hash2:
                memo[i] += k2
            else:
                memo[i] = None
                cnt -= 1
        if cnt == 0:
            return

    for i, j in enumerate(memo):
        if j is not None:
            print(i, j)


main()