If tan theta + sec theta = 2 then what is tan theta is equal to ?
If theta is the angle between the diagonals of a parallelogram ABCD whose vertices are A -LRB- 0,2 -RRB- , B -LRB- 2,-1 -RRB- , C -LRB- 4,0 -RRB- and D -LRB- 2,3 -RRB- . show that tan theta = 2 ?