Must a continuous function -LSB- math -RSB- f : \ mathbb -LCB- R -RCB- ^ n \ to \ mathbb -LCB- R -RCB- -LRB- n > 1 -RRB- -LSB- / math -RSB- , such that its integral along any straight line is -LSB- math -RSB- 0 -LSB- / math -RSB- , be -LSB- math -RSB- 0 -LSB- / math -RSB- everywhere ?
If function f -LRB- x -RRB- has a x-intercept r , why does -LRB- x-r -RRB- divide the function with a zero remainder ?