From: ted4646@rigel.tamu.edu (cartoon boy)
Newsgroups: rec.arts.sf.starwars
Subject: Re: RPG - "Haste"-question
Date: 28 Dec 1992 18:43 CST
Organization: Texas A&M University, Academic Computing Services
Distribution: world
NNTP-Posting-Host: rigel.tamu.edu
Summary: Haste and multiple actions penalty?
News-Software: VAX/VMS VNEWS 1.41    

In article <1992Dec27.215232.12343@ifi.unizh.ch>, knecht@avalon.physik.unizh.ch (knecht roland) writes...
> 
>Hi there!
> 
>I have one question about the haste rules in the SWRPG Rules Companion and
>the multiple action penalty.

Actually, the haste section in the rules is kind of confusing to me too, the
way it is laid out.

>Maybe it's just because I'm swiss and english is a foreign language to me
>(as you will notice :-)   ).

Naw.

>In combat a player declares an action (a shot)
>and a "haste". That will be two actions (Penalty 1D)... right?
> 
>If the player declares an action and double haste, will that be two
>actions ("action" and "double haste" - Penalty 1D) or three actions
>("action" + "haste"+ "haste" - Penalty 2D)?



>The player declares two actions (2 shots) and a "haste". Does the
>haste-action affect both shots or just one of them? Does every "normal"
>action need a separate "haste-action"?

The haste applies for only one of the shots (if they were to different targets,
the player would have to declare which one was hasted).

>The player declares three actions (shots). The first shall be with
>tripple-haste, the second with double-haste and the last with normal
>haste. Would that be 6 haste-actions (3+2+1) or 3 (tripple-haste) or just
>one (one "tripple-haste-action")?

The player is actually declaring NINE actions.  see below for why.


>Greetings!

>Roland Knecht

Okay, here goes:

when a player declares a HASTE action, the action and the haste are counted 
separately when adding total actions.  

example:  Dave Bowman  declares a hasted blaster shot at Reggie Oldham.
Dave is shooting once and hasting once, so his character gets a -1d penalty, 
but acts before anyone else that round.

for each haste used, the action occurs sooner.  

example:  Dave double hastes his shot at Reggie.  That's two hastes and one
shot for a total of three actions.  So Dave has a -2d action (but his blaster
skill is 6d, so he uses only 4d when firing).  This allows him to shoot before
anyone not declaring haste actions or declaring just one haste action.

If someone does multiple actions at different hastes, the actions all add up 
to find the penalty and then the actions are resolved in order of haste.

example:  Dave Bowman sees 9-Jack-9, his old enemy.  Jack declares two hasted
shots at Dave.  Dave declares a double hasted blaster shot and a combat dodge.
Because Dave is being fired at by a hasted shot, his dodge must also be hasted.
9-Jack-9 is: hasting and firing, hasting and firing.  this is four actions or
-3d.  Dave is: hasting, hasting, and firing; hasting and combat dodging.  That's
five actions for a total of -4d.  What actually happens this round is:
Dave gets his double hasted shot off first (and that action is resolved), then
Dave dodges (at -4d, like his shot) and Jack fires twice at Dave (at -3d each 
time).

-thomas

Stupid things to say in the Star Wars Universe:

#6:  "X-wing fighters pose no threat to this battle station."  *BOOM*


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