HDTenEightyP/NetNews huggingface dataset:
From: BANDA@AUSVM1.VNET.IBM.COM ("Venu Prabhakar Banda")
Newsgroups: rec.puzzles
Subject: More Math Problems
Date: 8 Apr 92 19:53:06 GMT

Hi Folks,

  Here are some more interesting math problems. Hopefully they are
all new to this newsgroup (at least I have not seen these in the
last year).....

1. Show that (2222^5555 + 5555^2222) is divisible by 7?
   (No, I have not made any mistake and yes "^" is the symbol
    for exponentiation). This was actually given to us in high
    school back in India (Not a very difficult problem, but we
    could not solve it then. After looking at the solution, I must
    add that it is not a very difficult problem, requiring very
    elementary knowledge of mathematics)

2. Consider the following sum.

    S = 1 + 50 + 50^2 + 50^3 + .... + 50^999

    Determine the last 1000 digits of S
    (This requires some knowledge of number theory, specifically the
     periodicity of the decimal expansion of numbers of the form 1/p).

3. Let S denote the set of numbers represented by the regular
   expression 1(01)*, i.e, numbers with alternating 0's and 1's that
   begin and end in 1.

   How many primes are there in S? (the numbers are in decimal)

   (This appeared in the Putnam exam. I don't remember the year. I
    have not yet figured out this one).....

Enjoy......

Cheers,

Venu
====
From: pfalstad@phoenix.Princeton.EDU (Paul Falstad)
Newsgroups: rec.puzzles
Subject: Re: order of numbers?
Date: 6 Apr 92 19:05:47 GMT
Distribution: rec
Organization: League For Fighting Chartered Accountancy
Originator: news@ernie.Princeton.EDU

dant@logos.wr.tek.com (Dan Tilque) wrote on 6 Apr 92 17:01:18 GMT:
>> > 	2, 9, 8, 4, 5, 7, 6, 3, 1
>
>When I came up with the last of the above three lists, I was not
>choosing numbers at random (although I made an error and put a seven in
>the last position where there should have been a 1--corrected in this
>article).  Question: what language is it?  (And what is zero in that
>language?  Something I never learned.)

Spoilers...

Latin.

The Romance languages are similar:
5, 2, 8, 9, 4, 7, 6, 3, 1

and

5, 2, 9, 8, 4, 7, 6, 3, 1

The zero really wasn't invented when Latin was spoken.  My Latin dictionary
says that you should use "nihil", meaning "nothing", when translating
the word "zero".

>	8, 3, 1, 5, 9, 7, 6, 4, 2

I'll guess German, based on where the "2" is.

>All four of these lists, 7 comes in the sixth position.  I wonder if this
>is only a coincidence.

Aren't all these languages derived from a common ancestor?  Indo-European,
or something.

Two more:

2, 1, 9, 6, 7, 8, 5, 4, 3

1, 4, 5, 7, 3, 8, 6, 2, 9
-- 
Paul Falstad, pfalstad@phoenix.princeton.edu | 10 PRINT "PRINCETON CS"
[Your blood pressure just went up.]          | 20 GOTO 10
Newsgroups: rec.puzzles
From: meng@idt.unit.no (Tore Mengshoel)
Subject: Re: order of numbers?
Reply-To: meng@idt.unit.no (Tore Mengshoel)
Organization: Div. of CS & Telematics, Norwegian Institute of Technology
Distribution: rec
Date: Mon, 6 Apr 92 17:02:43 GMT


In article <DM.92Apr5220055@stekt2.oulu.fi>, dm@stekt2.oulu.fi (Hannu Helminen ti) writes:
|> [stuff deleted]
|> 
|> While I am at it, heres another one:
|> What is the next one in this sequence
|>           _ _   _  _
|>   |\ /|  ( v ) ( \/ ) |\ /|
|>   | v |   \ /   >  < _|_v_|_
|>  _|___|_ __v__ (_/\_) |   |
|>

two fives facing each other. This is veeeeery old.
                                
|> That is, first letter M with a bar under it, 
|> than a heart with a bar under it,
|> then a flower (or a clover) with four "leaves"
|> then again letter M, but a bar in the middle.
|> 
|> > -- 
|> > dik t. winter, cwi, kruislaan 413, 1098 sj  amsterdam, nederland
|> > dik@cwi.nl
|> --
|> 
|>    _| _ _    Hannu    dm@stekt.oulu.fi    // Does anybody else in here
|>   (_|| | )  Helminen dm@rainbow.oulu.fi \X/ feel the way I do?

Tore
From: torbenm@diku.dk (Torben AEgidius Mogensen)
Newsgroups: rec.puzzles
Subject: Re: A question of time (partial spoiler)
Date: 15 Apr 92 13:30:59 GMT
Organization: Department of Computer Science, U of Copenhagen

tolman%asylum.utah.edu@cs.utah.edu (Kenneth Tolman) writes:

>Professor Doofus looked at the clock on his wall and exclaimed "holy smoke",
>and then waddled down the stairs. 

>His watch ticked loudly, but his blurry vision kept him from seeing the hands. 

>He counted out 5 minutes by the time he arrived at the downstairs clock.

>"My Gosh" he said, "3 hours and 5 minutes have passed since I left the
> upstairs clock"


>As it turned out, 5 minutes HAD passed, not 3 hours and 5 minutes. Also,
>both clocks were correct.

>What time was it when he embarked on his journey down stairs?

>(This may be tricky)

Well, if Doofus is a professor of astronomy, it might be that the
clock on his wall shows star time. Thus we need to find out the exact
time when star time is 3 hours behind normal time.

	Torben Mogensen (torbenm@diku.dk)
From: tom@ulysses.att.com (Tom Smith)
Newsgroups: rec.puzzles
Subject: Can I get the FAQ, please?
Keywords: neophyte
Date: 9 Apr 92 18:26:22 GMT
Organization: AT&T Bell Laboratories, Murray Hill

I have seen many references to the FAQ list since I started
reading this newsgroup a few days ago.  I requested riddle.p
only to discover that only contains "situation puzzles."

Can someone tell me where I can get a copy of the general
FAQL, please?

Thanks,
Tom Smith.
tom@ulysses.att.com
Newsgroups: rec.puzzles
From: surya@watson.ibm.com (Surya Mohanty)
Subject: Re: Sequence puzzle, retry after mailer problems
Date: Thu, 09 Apr 1992 14:13:54 GMT
Reply-To: surya@rothko.watson.ibm.com (Surya Mohanty)
Disclaimer: This posting represents the poster's views, not necessarily those of IBM
Organization: IBM T.J. Watson Research Center

Answer 
1, 11, 21, 1211, 111221, 
 312211
From: csz55@seq1.keele.ac.uk (Christopher Wrigley)
Newsgroups: rec.puzzles
Subject: Re: Dying young (solved)
Date: 9 Apr 92 11:05:59 GMT
Organization: University of Keele, England

From article <7463@uqcspe.cs.uq.oz.au>, by warwick@cs.uq.oz.au (Warwick Allison):
> farrell@coral.cs.jcu.edu.au (John Farrell) writes:
> 
>>warwick@cs.uq.oz.au (Warwick Allison) writes:
> 
> 
> Okay, then how does the puzzle change if all of the 100 people are
> members of your family (4 brothers, 5 sisters, 2 parents, 4 uncles,
> 6 aunts, 30 cousins, 4 sons, 5 daughters, 19 granddaughters and
> 20 grandsons).
> 

In that case, the subject header would not be 'dying _young"!   :-)
Newsgroups: rec.puzzles
From: hemmady@Cadence.COM (Shankar Hemmady)
Subject: How do you number a dice?
Organization: Cadence Design Systems, Inc.
Date: Tue, 7 Apr 1992 22:17:54 GMT



This is a puzzle on combinatorics.

You are given several unnumbered cubical Dices (sp?).  Your objective is to
number the faces of each dice from 1 to 6.

If the dices look identical then how many unique dices can you construct?

If you give me two dices with presumably different numberings, then I must
not be able to find a one-to-one correspondence (or an equivalence relation)
between the faces numbered on the two dices.



A related but simpler problem is:

	Instead of a cubical dice, if I were to give you several tetarhedral
(regular pyramids) dices, then how many unique numbering schemes can I assign
to the four faces of such dices?  
(Incidentally, the soultion to this problem is used in stereochemistry)


-Shankar Hemmady
hemmady@cadence.com
From: BANDA@AUSVM1.VNET.IBM.COM ("Venu Prabhakar Banda")
Newsgroups: rec.puzzles
Subject: Math Problem
Date: 7 Apr 92 13:37:11 GMT

Problem: Show that (4444 ** 4444) is divisible by 9

Cheers,

Venu
====
Newsgroups: rec.puzzles
From: amorgan@Xenon.Stanford.EDU (Crunchy Frog)
Subject: Re: Math Problem
Organization: Computer Science Department, Stanford University.
            <CU311HL@math.fu-berlin.de>
Date: Tue, 7 Apr 1992 23:27:00 GMT

In article <CU311HL@math.fu-berlin.de> 
  guckes@math.fu-berlin.de (Sven Guckes) writes:
>BANDA@AUSVM1.VNET.IBM.COM ("Venu Prabhakar Banda") writes:
>
>>Problem: Show that (4444 ** 4444) is divisible by 9
>>
>>Cheers,
>>
>>Venu
>>====
>
>	4444 * 4444 = 6583045 * 3 + 1
>
>	Boring puzzle. ;)

Sorry dude, 4444**4444 is 4444^4444, not what you wrote.  I don't,
however, think that 4444**4444 *is* divisible by 9 (evenly, that is).
It can only be divisible by 9 if it is divisible by 3, which can only
be if 4444 is divisible by 3.  It isn't.

What am I missing?

C Frog
Newsgroups: rec.puzzles
From: farrell@coral.cs.jcu.edu.au (John Farrell)
Subject: Re: Dying young
Organization: James Cook University
Date:  9 Apr 92 01:54:35 GMT

In this problem (in which I have been mistakenly assuming there are 99 other
people, when in fact there are 100), we have the following answers.

(i) If I am trying to maximise my chances of survival, I should never press
the button.

(ii) If I am trying to maximise the number of survivors, and when one person
presses the button the rest go free immediately, then I should press the
button at the first opportunity, because then there will be 100 survivors and
1 dead person (me) every time, which is optimal.

(iii) If I am trying to maximise the number of survivors, and any number of
people can press the button and they all die and then any who didn't go free
at the end of the hour, then I should press the button about 1 in 20 times
according to Mr Hsieh's calculus.

  Have we finished now?


Friendless
Newsgroups: rec.puzzles
From: quinn@EE-CF.Stanford.EDU (Christine A. Quinn)
Subject: Weird puzzles just for a diversion
Followup-To: rec.puzzles
Summary: Only if you have nothing better to think about
Keywords: probability,infinity
Organization: Stanford University
Date: Tue, 14 Apr 92 23:01:44 GMT

Hi puzzlers.

Here are some really weird puzzles.  Although I have a degree
in Mathematics, I never did take any prob&stat classes.  
(Besides I can't recall the last time I did any REAL math)
I can't imagine if these are even feasible but I've been
thinking of them lately and thought they'd be a slight change
to the usual 'complete this sequence' and 'prime factorizations'.

Puzzle 1: The other day I was walking along a dirt road with
my six year old son.  The road had cracked from exposure to
rain and sun and had odd shapes created everywhere from the cracks.
My son noted that one of the shapes looked like the state of
Missouri (a precocious boy, I'll admit).  Then he asked, and
I pass this on to you: "Mom, could we find all of the United States
in these cracked shapes?"  (modify to fit your country/world
as appropriate)

Puzzle 2: When I read news groups I often look to see if
there is someone I know who has posted.  I figure from all
of the people I have know in high school and college and
in my three (so far) jobs, there must be someone I know that
posts.  Of course, I have seen someone I know - but it 
turned out to be someone I met at a USENIX conference and
hence not so surprising.  I don't recall ever seeing someone
from high school.  I once saw someone who had the same
name as someone I knew from a job overseas but when I sent
mail it turned out to be someone else.  So the question:
what's the likelihood on any given day while reading
netnews you'll see a posting from someone you know?
Don't count someone you know as someone whose posts you
see all the time.  You have to really know the person.

Puzzle3:  Are there an infinite number of songs
that can be written? in a paticular style (e.g. rock-n-roll)?
of a certain length?

Okay, perhaps these aren't quite legitimate.  They certainly
aren't the usual rec.puzzles fare.  Maybe it'll be fun to think 
of them anyway.  My apologies if they are seen as just plain 
stupid.  Sorry, I don't have any answers to these, although 
I have my ideas based solely on intuition.

-chris quinn

-----------------------------------------------------------------
Amidst the lists and unix quotes,       |  Christine A. Quinn
With awkish scripts and starkest posts, |  Stanford University
She pounds the keys and C's the most,   |  Electrical Engineering
and still insists she frees the host.   |    Computer Facility
--
-----------------------------------------------------------------
Amidst the lists and unix quotes,       |  Christine A. Quinn
With awkish scripts and starkest posts, |  Stanford University
She pounds the keys and C's the most,   |  Electrical Engineering
and still insists she frees the host.   |    Computer Facility
Newsgroups: rec.puzzles
From: macster@IASTATE.EDU (Michael C Mccarty)
Subject: Re: Math Problem (Solution?)
Reply-To: macster@IASTATE.EDU (Michael C Mccarty)
Organization: Iowa State University
Date: Wed, 8 Apr 1992 09:23:57 GMT

	An interestion point was just brought up... Does the number have to be in base
10?  If base 8 is used, the number is then divisible by 9:

4444^4444 (base 8) = 2340^2340 (base 10)=
((9*260)^260)^9=
(9^260)^9*(260^260)^9

	The problem is nine is not '9' but '11' in base 8. Does he/she switch bases in
the middle of the problem?  Or am I just using the wrong base?  Either seems
very possible.  The only reason I used base 8 is that I'm lazy and that is the
only base on my calculator that works.  Better solutions?

					Mike
Newsgroups: rec.puzzles
From: dbrooks@osf.org (David Brooks)
Subject: Re: Math Problem
Followup-To: rec.puzzles
Reply-To: dbrooks@osf.org (David Brooks)
Organization: Open Software Foundation
Date: Tue, 7 Apr 1992 22:38:49 GMT

BANDA@AUSVM1.VNET.IBM.COM ("Venu Prabhakar Banda") writes:
>Problem: Show that (4444 ** 4444) is divisible by 9

This number is so large that arithmetic is warped in its vicinity, and
relativistic effects must be taken into account.  Factors are generated
that are not accounted for by classical arithmetic (which claims that the
number is 7 mod 9, if my mental arithmetic is still working).

Parity arguments suggest the overwhelming likelihood of creation, ex
nihilo, of factor-antifactor pairs equalling 3i and -3i.  QED.
-- 
David Brooks				dbrooks@osf.org
Systems Engineering, OSF		uunet!osf.org!dbrooks
From: grayt@Software.Mitel.COM (Tom Gray)
Newsgroups: rec.puzzles
Subject: Is this another oldie? was Re: 2 oldies
Date: 10 Apr 92 12:46:26 GMT
Organization: Mitel. Kanata (Ontario). Canada.


Extend the sequence;

D L F R T S 


-- 
i.sinature
Newsgroups: rec.puzzles
From: orange@alfred.carleton.ca (Paul Vallee)
Subject: Brick Problem (crude ASCII)
Summary: Draw a line through every side of a three row bricklike structure
Keywords: brick, graphical, puzzle
Organization: Carleton University
Date: Mon, 6 Apr 1992 17:16:20 GMT


Here's one I've been toying around with while bored in class for
awhile, but I've ony managed to solve one of them.  An uncle described
these to me as being solvable, so don't give up... (that is, if you
believe my uncle. :)
I myself have only been able to solve one of them.  I won't tell you which.

Ok, here, in crude ascii, is a picture of a brick wall, with three
bricks on top, two on the middle row, and three again on the bottom
row.
The object is to draw a curvilinear line through every wall of every
brick, without going through any given wall more than *once*.
Note:  Bricks in the middle row have *six* walls, ok?  I can't think
of a better way to describe this.  Center bricks on the top and bottom
rows have *five* walls.

  |----|-----|----|
  |    |     |    |
  |----|--|--|----|
  |       |       |
  |----|--|--|----|
  |    |     |    |
  |----|-----|----|

To simplify your description of a solution, here is a lettering scheme
we may convene to use:

     a    b     c
  |----|-----|----|
d |  e |  f  |  g | h
  |----|--|--|----|
i |   j   |    k  | l
  |----|--|--|----|
m |  n |  o  |  p | q
  |----|-----|----|
     r    s     t

i.e. To describe a solution beginning at o, and going to the right,
o, p, q, l, k, g, h, etc...  get the picture?


Same problem, different brick layout...


  |-------|-------|
  |       |       |
  |----|--|--|----|
  |    |     |    |
  |----|-----|----|
  |       |       |
  |-------|-------|

      a       b
  |-------|-------|
c |   d   |   e   | f
  |----|--|--|----|
g |  h |  i  |  j | k
  |----|-----|----|
l |   m   |   n   | o
  |-------|-------|
      p       q


Good luck...


-- 


orange@ccs.carleton.ca ------- Paul Vallee ---- 542429@acadvm1.uottawa.ca
------------Home: (613)569-1068 --------- Work: (613)995-6921------------
"Like chewing on glass, and burning my fingers,
        I'm not the one who's run out of lies..." - Stigmata, by Ministry
Newsgroups: rec.puzzles
From: ronnie@cisco.com (Ronnie B. Kon)
Subject: Re: Dying young
Organization: cisco Systems, Incorporated
Date: Fri, 10 Apr 1992 01:36:48 GMT

In article <1992Apr6.175229.23741@hellgate.utah.edu>, tolman%asylum.utah.edu@cs.utah.edu (Kenneth Tolman) writes:
|> 
|> You are put in a room by evil Nazi's.  There is a button in front of you.  If
|> you press the button, you will die.  However, there are 100 other people in
|> similar rooms.  If no one pushes their button before 12:00, everyone dies.  You
|> have no way to know if the other people have pushed theirs or not. 
|> It is now 11:50. What do you do?

It depends on who's in the other rooms.  If they are strangers, then no, I
doubt I push the button.  If my wife or daughter is in one, I push the button
and pray that they have the faith in me not to push theirs.

What an infinitely depressing problem.

-------------------------------------------------------------------------------
Ronnie B. Kon           |  "If you vote Republican, does that make you
ronnie@cisco.com        |   an accomplice to their crimes?"
(415) 688-4592          |                  -- Bongo, Life in Hell
-------------------------------------------------------------------------------
Newsgroups: rec.puzzles
From: trump@elaine30.Stanford.EDU (Michael Jason Lewis)
Subject: Re: Dying young
Organization: DSG, Stanford University
Date:  7 Apr 92 00:40:52 GMT

tolman%asylum.utah.edu@cs.utah.edu (Kenneth Tolman) writes:

>You are put in a room by evil Nazi's.  There is a button in front of you.  If
>you press the button, you will die.  However, there are 100 other people in
>similar rooms.  If no one pushes their button before 12:00, everyone dies.  You
>have no way to know if the other people have pushed theirs or not. 
>It is now 11:50. What do you do?

Hm.  I think I would not push the button and hope that one of the other 100
people has some sort of martyrdom complex.  Offhand, considering my personal
survival instinct, I wouldn't do anything that insured my death.

- Mike Lewis
trump@leland.stanford.edu
From: tdh@ksr.com (Dave Hudson)
Newsgroups: rec.puzzles
Subject: Re: 1992-04-09 WSJ puzzle
Date: 11 Apr 92 13:33:29 EDT
Organization: Kendall Square Research Corp.

>There was a little puzzle in the WSJ the other day.  It asked for
>the maximum number of enclosed volumes created by three
>interpenetrating cubes.  I presume that "interpenetrating" meant
>"volumes mutually intersecting" and that "enclosed volumes" meant
>"volumes bounded by pieces of faces of the cubes"; for example, if you
>were to rotate a cube 45 degrees about the centers of two opposite
>faces, and intersect it with its previous self, you'd get nine
>enclosed volumes, or if two cubes got squashed together slightly at
>one corner there'd be only three enclosed volumes.  (Different
>interpretations of the puzzle's wording did not seem interesting.)

It occurred to me that I was construing my own interpretation of the
puzzle too narrowly.  The correct answers for the examples I gave
above were 264 and 6, not 9 and 3, respectively.  The three-cube
answer similarly explodes, but in a more complicated way.  The two-cube
answer is still trivial, however.

> Are there any techniques for solving this for three cubes other than
> visualization (not including pounding one's head :-) )?  What branches
> of specialized knowledge do they depend on?

> David G. Caraballo suggested also asking for a solution generalized for
> N cubes.  Whew!  The three-cube question alone reportedly appeared in
> a difficult test.

I will try to cancel the original article.

				David Hudson
From: coop1w13@bnr.ca (Mike Hammond)
Newsgroups: rec.puzzles
Subject: SPOILERS: Isaac Asimov's mysteries puzzle
Date: 11 Apr 92 01:44:50 GMT
Reply-To: coop1w13@bnr.ca
Organization: BNR Ottawa, Fibre Systems Development

Spoilers for a tough puzzle. (The only reason I know this is because I
happened to read that particular issue of Isaac Asimov's Science Fiction
Magazine. By the way, isn't this a puzzle of Martin Gardener?)















































































In article <3847@shum.huji.ac.il>, yehuda@shuldig.huji.ac.il (Jonathan Berlinger) writes:
|> Donn't know if anyone heard this one yet, so:
|> 
|> Why does>	Christmas = Halloween
|> 
|> Hint below:
|> 
|>  
|> Hint: look at the dates.
|> 
|> -- 
|> 
|> Jon Berlinger				"Shade and Sweet Water"
|> yehuda@cs.huji.ac.il

Well, December 25 is 12/25, while October 31 is 10/31. Note that 25 in base
12 is equal to 31 in base 10. Thus Christmas=Hallowe'en.

=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
|      Mike Hammond       | ``Yes, I'm...too wascally for Bugs Bunny,   |
|      Co-op Student      |   too wascally for Bugs Bunny,              |
|       BNR Ottawa        |   so wascally...it's almost funny!''        |
|    and University of    |                      ``I'm Too Wascally'',  |
|        Waterloo         |                       Right Said Fudd       |
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
From: sharkey@robots.ox.ac.uk (Paul Sharkey)
Newsgroups: rec.puzzles
Subject: Afterwards
Date: 14 Apr 92 09:12:05 GMT
Organization: Robotics Research Group, Engineering Science Dept, Oxford, UK.
Originator: sharkey@oberon.robots

Afterwards is a 10 letter word that can be "touch-typped" using one
hand. Can anyone better that?

I suppose I have to put in the usual "rules" to avoid the usual crop
of smartarse answers like "I can type antidisestablishmentarianism
with one finger" : QWERTY keyboard, all keys to left of and
including TGB are exclusively left-handed, otherwise righthanded.

P.
From: adams@spss.com (Steve Adams)
Newsgroups: rec.puzzles
Subject: Re: Simple NT problem
Date: 14 Apr 92 21:04:11 GMT
Organization: SPSS Inc.

benham@anion.serum.kodak.com (Todd Benham (x37354)) writes:

>In article <1992Apr13.160726.9198@watson.ibm.com> surya@rothko.watson.ibm.com (Surya Mohanty) writes:
>>If a and b are positivite integers and if 
>>     1+ a^2 + b^2
>>k= --------------
>>       a*b
>>is also an integer then prove that k is equal to 3.
  ^^^^^^^^^^^^^^^^^^

>a=2,b=4 .: k=21/8

>You must be mistaken.
No, 21/8 is not an integer.  He says prove that for all integer solutions of
the equation, k=3.  I haven't worked on this at all, but he does specify
that the proof is for integer results only.

 -Steve
--
 The opinions expressed above are those of the author and not SPSS, Inc.
                        -------------------
     adams@spss.com                           Phone: (312) 329-3522
     Steve Adams                              Fax:   (312) 329-3558
From: ts@cup.portal.com (Tim W Smith)
Newsgroups: rec.puzzles
Subject: Re: SPOILERS: Isaac Asimov's mysteries puzzle
Date: Tue, 14 Apr 92 07:36:16 PDT
Organization: The Portal System (TM)

> Well, December 25 is 12/25, while October 31 is 10/31. Note that 25 in base
> 12 is equal to 31 in base 10. Thus Christmas=Hallowe'en.

25 in base 12 is 29 in base 10.
Newsgroups: rec.puzzles
From: farrell@coral.cs.jcu.edu.au (John Farrell)
Subject: Re: A simple number puzzle
Organization: James Cook University
Date:  8 Apr 92 23:15:58 GMT

In <1992Apr7.202400.26466@Cadence.COM> hemmady@Cadence.COM (Shankar Hemmady) writes:
>"My child's age raised to itself gives my age.
>If my wife is younger than me by my child's age
>and if we are LIVE humans, then what are our ages?"

  It's too easy. I'm not saying.


Friendless