HDTenEightyP/NetNews huggingface dataset:
From: tara@uxa.cso.uiuc.edu (Lady Johanna Constantine)
Subject: Highlander Questions
Organization: University of Illinois at Urbana
Distribution: na
Date: Sun, 3 Jan 1993 06:33:22 GMT

Okay, I just saw Highlander: The Series for the first time.
I've seen four episodes.  I can't rememebr all the names, but
I think they were "Bad Day in Building A", "Free Fall", "Innocent
Man"  and something else.... "Roads Not Taken" I think, anyhow, 
I've got some questions.

Okay, so where were all these immortals during the Gathering in the
first movie?  I thought Connor and the Kurgen fought for the prize
because they were the last two, and that's how Connor got the prize.
But if Duncan, and Felice Martin, and Lucas and all the Immortals from
the seires were still alive, then why did Connor get the Prize?

Okay, so when they made the movie in 85 they had no idea they would
make a series some day, but how do they explain this in the series?
Were they ALL hiding out on holy ground in 85?

Okay, second question: Who trained Duncan?  He said that his sword was
given to him by a fellow MacLeod, so I assume he meant Connor, as
I saw a photo of Christophe Lambert with him in Starlog, so he must
have guest starred in the pilot,  so did COnnor give him a sword just
like his 400 years before?  The hilt looked just like Ramirez's sword
from the movie, but since Duncan said he'd hadd it for 4 centuries, it
can't be.

Are there any other immortal women besides the now deceased Felice Martin?

If Duncan was not born a MacLeod, but adopted, is this a hint that all
the immortals were?

Does the show take place in Seattle, Toronto or Vancouver?  I keep
getting confused.

Tessa seems french canadian, but I could eb wrong.

Does anyone esle find Richie totally annoying?

Okay, final question, just for Champaign/Urbana fans:

Where does this air down at U of I?  I've been watching Ch 50 in Chicago,
but I haven't seen Highlander down there.  Is it on and am I just missing
it, or is it on one of the stations the droms don't pick up like the other
Fox station,a dn the PBS that was runnign Robin of Sherwood.


cheers,

LJC
-- 
Lady Johanna Constantine* Tales and dreams are the shadow-truths that will
tara@uxa.cso.uiuc.edu   * endure when mere facts are dust, and ashes, and
Disclaimer - huh?       * forgot.      -Dream of the Endless (and Neil G.)
Church of Our Lady of the Perpetually Clueless, donations accepted......
Xref: sparky rec.arts.sf.tv:6303 rec.arts.tv:24664 rec.arts.tv.uk:6892
From: Edward_Lee_Whiteside@cup.portal.com
Newsgroups: rec.arts.sf.tv,rec.arts.tv,rec.arts.tv.uk
Subject: Re: REPOST: New SF TV Shows premiere info (TomorroW People upda
Date: Wed, 30 Dec 92 22:19:40 PST
Organization: The Portal System (TM)

In checking the new isssue of Orbit satellite guide, the new Tomorrow People
will air in Nickelodeon at 8 pm ET/PT Jan 25-28 with four one hour episodes.
The original U.K. airings were five half hour shows.  Not sure if this
means extra footage or a long rehash each episode.
Xref: sparky rec.arts.sf.tv:6182 rec.arts.tv:24395
From: eah4@po.CWRU.Edu (Elizabeth A. Hlabse)
Newsgroups: rec.arts.sf.tv,rec.arts.tv
Subject: QL in Entertainment Weekly
Date: 22 Dec 1992 13:23:49 GMT
Organization: Case Western Reserve University, Cleveland, OH (USA)
Reply-To: eah4@po.CWRU.Edu (Elizabeth A. Hlabse)
NNTP-Posting-Host: thor.ins.cwru.edu



Entertainment Weekly just came out with it's best and worst of 1992 and QL
made the list.  This is not something to be proud of.  It made the top 5
WORST list.  I quote.

	4. Quantum Leap (NBC) A sentamental choice,
	second year running.  With the episode in which Sam
	leapt into Lee Harvey Oswald, Quantum proved this
	year there's nothing more tedious than a fantasy
	show that thinks it's Serious Television.


The others in this worst list for TV were:
	1. Angel Street
	2. The Heights
	3. Picket Fences
	4. Quantum Leap
	5. L.A. Law

I would like to thank Don Bellisario for doing this.  If QL isn't on next
year, I think (and this is _all_ IMO) that we can blame him for trying to
make QL into something that it just isn't.  Yes, QL can give a message and
has done a wonderful job of doing so.  Walk a mile in my shoes --- and all
that kind of thing.  However, we don't want history according to Don B.

Flame away.  The fire proof suit is on.

-- 
             Beth Hlabse    eah4@po.CWRU.Edu     Assistant Sysop
                The Science Fiction and Fantasy Sig (GO SCIFI)
-------------------------------------------------------------------------------
                  Blessings of the season on you and yours.
From: wixer!cactus.org!wixer!pro-smof.cts.com!rfletcher@cactus.org (Robert Fletcher)
Newsgroups: rec.arts.sf.tv
Subject: Re: Space Ranger?????
Date: 31 Dec 1992 13:45:37 -0600
Organization: The SMOF-BBS: Science Fiction Online Since 1985 [512-467-7317]
NNTP-Posting-Host: cs.utexas.edu

  It looks like this show is one of the best kept secret. They did an even
better job the the "Star Wars" people.
  One thing tho, this show looks just like the game "Space Ranger" by
Origin System.
----
ProLine:  rfletcher@pro-smof
Internet: rfletcher@pro-smof.cts.com
UUCP:     crash!pro-smof!rfletcher
ARPA:     crash!pro-smof!rfletcher@nosc.mil

Xref: sparky rec.arts.sf.tv:6253 rec.arts.startrek.current:21328 rec.arts.tv:24529
From: Edward_Lee_Whiteside@cup.portal.com
Newsgroups: rec.arts.sf.tv,rec.arts.startrek.current,rec.arts.tv
Subject: REPOST: New SF TV Shows premiere info (ST:DS9, ime Trax, etc.)
Date: Sun, 27 Dec 92 00:17:53 PST
Organization: The Portal System (TM)

My original post went out with a subject header that may have caused people
looking for the ST:DS9 sat info to skip it, so here it is again....
REC.ARTS.SF.TV Guide to New SF Shows

by Lee Whiteside   (updated 12-22-92)


New sci-fi series premiere info (No Spoilers, unless you don't want to know
when they will air) for Star Trek: Deep Space Nine, Space Rangers,
Time Trax, The (New) Tomorrow People, Babylon 5.

Star Trek: Deep Space Nine

The series premieres the week of January 4th with the two hour movie
"The Emissary".  Hourly episodes will follow the next week.

Sat Feed Info (text from Mark Holtz's DS9 List):

The series premiere will be on the AT&T's Telstar 301 on the following times:

December 30th -  6:45 PM- 9:00 PM ET/3:45 PM- 6:00 PM PT - Transponder 19/10V
 January  2nd - 10:00 AM-12:15 PM ET/7:00 AM-12:15 PM PT - Transponder 19/10V
 January  3rd -  3:00 PM- 5:15 PM ET/   Noon- 2:15 PM PT - Transponder  9/ 5V

Audio is: 6.2 Left, 6.8 Right, 5.8 Mono.

Weekly hour shows sat feed info:

Jan  9 93 Jan 11-Jan 17 A Man Alone
Jan 16 93 Jan 18-Jan 24 Past Prologue
Jan 23 93 Jan 25-Jan 31 Babel

The series will be uplinked to the stations on AT&T's Telstar 301 on
Transponder 9 (Vertical Polarity)/5V at the following times:

Saturdays - 10:00 AM-11:00 AM ET/ 7:00 AM- 8:00 AM PT
Saturdays -  4:00 PM- 5:00 PM ET/ 1:00 PM- 2:00 PM PT
  Sundays -  4:00 PM- 5:00 PM ET/ 1:00 PM- 2:00 PM PT

Audio is: 6.2 Left, 6.8 Right, 5.8 Mono.


Space Rangers : Premieres on CBS on Wednesday, January 6th at 8 pm (ET/PT)/
7 pm (CT/MT)


Time Trax : Premieres on January 20th with a two hour movie with hourly
episodes the following week.  This is part of the new Prime Time
Entertainment Network (PTEN). 


The Tomorrow People - Nickelodeon - 8 p.m. ET Jan 25th.  It may run for five
straight nights at this time.  Five one hour episodes have been produced.


Babylon 5 - The Babylon 5 movie "The Gathering" premieres the week of
February 22nd on PTEN stations.  A series has not yet been commisioned.

Look for the B5/PTEN TV station list for stations airing Time Trax and
Babylon 5


Lee Whiteside   elw@cup.portal.com
Organization: Penn State University
Date: Wed, 30 Dec 1992 15:05:12 EST
From: <SML108@psuvm.psu.edu>
Newsgroups: rec.arts.sf.tv
Subject: Re: Harve Bennett? (Re: TV GUIDE ARTICLE: TIME TRAX)
 <C02wwL.DC5@acsu.buffalo.edu>

I personally think Time Trax will be a lame combo of Quantum Leap and
Trancers...  But don't take it from me, here's Grant Rosenberg, executive
producer of Time Trax on the subject of whether SELMA is a cheap clone
of Al from Quantum Leap from an interview in the Feb 93 issue of Starlog...

The premise of a time traveler with a holographic companion has led to some
comparisons with _Quantum Leap_.  Aware of possible criticism, Rosenberg is
quick to point out the contrasts between the two shows.  "The primary
difference is that Darien has moved from point A to point B and has made point
B home," he comments.  "It's not him going back to play in the 1919 World
Series or whatever.  Sam Beckett can come back as a child, a woman, a black
man or a dog.  Darien is Darien and he _stays_ the same.  Our show is more
action-oriented than _Quantum Leap_, which is really a weekly character
study.
  "In terms of the hlograms, we didn't feel here was a conflict.  The hologram
in _Quantum Leap_ is a cigar-chomping, wisecracking guy who comes in, makes a
few comments and leaves.  He serves his function for that show, and it's
very appropriate.  Ours is much more of a tool and an information base.  Selma
is used not so much in visual mode, but as a very advanced computer.  She's
much more multi-functioned than the companion in Quantum leap."

My only remaining question: is she _fully_ functional?

Scott
"If you haven't had a chocolate-covered dwarf in your shower, you haven't
 lived!" - Kathy Self, Herve Villechaize's love bunny
Newsgroups: rec.arts.sf.tv,rec.arts.tv
From: jlevine@apollo.HP.COM (Jennifer E. Levine)
Subject: Re: QL in Entertainment Weekly
Date: Wed, 23 Dec 1992 13:56:49 GMT
Organization: Hewlett-Packard Company, Chelmsford, MA

In article <1h80gbINNl6m@transfer.stratus.com>, savoia@sw.stratus.com (Rick Savoia) writes:

|> 
|> So, in other words, whoever made this list has a serious
|> problem with serious shows.  8 out of 10 of those are
|> comedies of some type.  I'll Fly Away is a serious but
|> good show and Batman is a cartoon.  Not a very valid
|> list in my opinion.  Sounds like whoever made this list
|> doesn't like to think while watching TV, but just sit
|> mindlessly and watch.  What a bozo.

True the list is mostly comedies however, I think that Batman 
is better than the average cartoon.

--Jennifer
jlevine@apollo.hp.com
From: kfl@access.digex.com (Keith F. Lynch)
Newsgroups: rec.puzzles
Subject: New Year's problem
Date: 31 Dec 1992 04:06:26 GMT
Organization: Express Access Public Access UNIX, Greenbelt, Maryland USA
Distribution: world
NNTP-Posting-Host: access.digex.com

What property did 1987 have, that no year after it will have until 2013?

What property did 1961 have, that no year after it will have until 6009?

Keith Lynch, kfl@access.digex.com
Newsgroups: rec.puzzles
From: ags@seaman.cc.purdue.edu (Dave Seaman)
Subject: Re: Lost solution
Organization: Purdue University
Date: Fri, 25 Dec 1992 06:27:30 GMT

In article <rbarnick-241292103910@cosadpm12.mitre.org> rbarnick@mitre.org (Barnie Barnick) writes:
>*****
>Tim,
>The answer is 4 and 19.  
>*****

Sorry, but 4 and 19 is not a solution. It is consistent with the first three
statements, but not with the fourth.

>In article <1992Dec22.193053.24084@bernina.ethz.ch>, timh@igc.ethz.ch (Tim
>Harvey) wrote:
>>    Mr. P.:  I do not know the two numbers.
>>    Mr. S.:  I knew that you didn't know the two numbers; I do not know the
>>             two numbers.
>>    Mr. P.:  Now I know the two numbers.
>>    Mr. S.:  Now I know the two numbers.

It is true that 4*19 = 76 can be alternately factored as 2*38, and therefore
Mr. P's first statement is correct.

It is also true that the sum 4+19=23 has the property that whenever you
partition it as 23 = a+b, with a and b greater than 1, the product a*b always
has an alternate factorization with both factors greater than 1. Therefore, Mr.
S's first statement is also correct.

It is also true that the product 4*19=76 cannot be refactored in a way that is
consistent with S's first statement. You can try 2*38=76, but then the sum
2+38=40 is inconsistent with S's first statement (exercise for the reader).
Therefore, Mr. P's second statement is correct. He has deduced that the numbers
are 4 and 19.

Now place yourself in S's position. You know that the sum is 23, and you also
know that P has deduced the numbers from the information he has available. It
is certainly possible, as we have seen, that P could have been given the sum
76, from which he deduced the original numbers. However, S does not know what
sum P was given. For all S knows, it is equally possible that P was given a
product of 112, from which he could have deduced that the numbers are 7 and 16.
Note that 7+16 also gives 23, the sum that S has, and it also is consistent
with the first three statements (another exercise for the reader). Therefore, S
is not in a position to deduce the numbers. They could be either (4,19) or
(7,16), and there is no way to tell which. Therefore, S must have been mistaken
when he said he knew the numbers.

But we are given that S and P do not make mistakes in logic, which is a
contradiction. Conclusion: the solution cannot be (4,19). As I pointed out in a
separate posting, the actual solution is (4,13).

--
Dave Seaman
ags@seaman.cc.purdue.edu
Newsgroups: rec.puzzles
From: hiraga@Csli.Stanford.EDU (Yuzuru Hiraga)
Subject: Direction of the sun
Organization: Stanford University CSLI
Date: Thu, 24 Dec 1992 01:26:36 GMT


# Heard from a Japanese colleague -- Sorry again if this is in the FAQL

Two boys, A and B, are watching the sunset.
A points to the sun and says:
"This is the direction where the sun is right now."
B replies:
"But don't you know that the rays take over 8 minutes to reach the Earth?
The sun is actually already below the horizon."
Which is correct?  Why? (Make it understandable to a ten year-old.)

# note: ignore subsidiary points like refraction by the atmosphere.

BONUS: What would the answer be under the Ptolemaic system?

-Yuzuru Hiraga
Newsgroups: rec.puzzles
From: potamian@apollo.HP.COM (Spyros Potamianos)
Subject: Re: Killers & Pacifist (SPOILER)
Date: Wed, 23 Dec 1992 19:34:59 GMT
Reply-To: potamian@hpl.hp.com
Organization: Hewlett-Packard Company

In article <Dec.22.08.29.06.1992.5984@romulus.rutgers.edu>, clong@romulus.rutgers.edu (Chris Long) writes:
|> In article <BzMrJ3.JHH@hplabs.hpl.hp.com>, Spyros Potamianos writes:
|> 
|> > Now the new variation: Everything remains the same, except for a slight
|> > change in the algorithm for selecting the two persons:
|> 
|> >     Randomly choose a killer. Then randomly select another person
|> >     (killer or pacifist).
|> 
|> Let there be 2k killers, p pacifists.  If you choose to be a killer,
|> P(survival)=1/(2k+1) by symmetry.  If you choose to be a pacifist,
|> P(survival)=1/(k+1) since as before we may ignore any interaction
|> between a killer and a different pacifist, hence we may pretend
|> we are the only pacifist; it's clear now that P=1/(k+1) since
|> we survive iff we don't take part in the first k interactions.
|> -- 
|> Chris Long, 265 Old York Rd., Bridgewater, NJ  08807-2618
|> 
|> "S.B., with an I.Q. of 161, failed to complete his course of study,
|> running away instead with his professor's wife."
|> H. J. Eysenck, _Know Your Own I.Q._

Hm... I tend to disagree... Lets say we have 4 killers and we are the only
pacifist. Then, the chance of surviving the first round is 3/4
(i.e. after the first killer is selected, the second person can either be
me or one of the 3 remaining killers).
Then if we survive the first round,in the second we have 2 killers, and
the chance of survival is 1/2. So, the total probability of survival is
3/4 * 1/2 = 3/8

Here is what I came up with:
Assume that I became a pacifist, and there are '2*K' killers and 'P'
pacifists (*including* myself)
Let a(k,p) be the probability of survival.

The first selected person is always a killer (according to the rules).
The probability of the second person being a killer is:
	(2*k-1)/(p+2*k-1)
The probability of the second person being me is:
	1/(p+2*k-1)
The probability of the second person being another pacifist is:
	(p-1)/(p+2*k-1)

In the first case the game continues with '2*K-2 = 2*(K-1)' killers and
'P' pacifists, in the second we die, and in the thrid we continue with
'2*K' killers and 'P-1' pacifists. So....

    a(k,p) = (2*k-1)/(p+2*k-1) * a(k-1,p) + (p-1)/(p+2*k-1) * a(k, p-1)

We also know that:
    a(0,p) = 1					/* no killers */
    a(1,1) = 1/2				/* 2 killers and me */
    a(k,1) = (2*k-1)/(2*k) * a(k-1, 1)		/* 2*K killers and me */

I haven't solved this equation though... Can anybody help???

Spyros Potamianos
potamian@hpl.hp.com
Newsgroups: rec.puzzles
From: mikem@ll.mit.edu
Subject: Re: New Year's problem
Organization: MIT Lincoln Laboratory
Date: Thu, 31 Dec 92 19:28:49 GMT

In article <1htrk2INNrql@mirror.digex.com> kfl@access.digex.com (Keith F. Lynch) writes:
>What property did 1987 have, that no year after it will have until 2013?
>
>What property did 1961 have, that no year after it will have until 6009?
>
>Keith Lynch, kfl@access.digex.com

Well, 1961 can be turned upside-down and it's still 1961.  The same can be
said for 6009.  But, if you assume a font equivalent to a 7-segment digital
display, the same can also be said for 2002.  I guess it just depends on
your choice of fonts.  Many computer fonts display the digit '1' so that
it is quite obviously not the same upside-down as right-side-up.


for 1987, it seems you're looking for a year in which it's possible to express
the date and time using the digits 0-9 exactly once - this first happened in 1987
on February 3 at 4:56 AM.  2/3/1987 04:56

or, if you don't like leading zeroes, 3/20/1987 4:56.

This feat is not possible for subsequent years, since there is always a repeated
digit in the year, until you get past 2012.

However, even in 2013, with no repeated digits, we have a problem.  You have to
somehow use the digits 4-9 in a time and date.  Try it.  You'll quickly see that
you can't compose a date and time which use all six digits between 4 and 9.

So it seems this isn't *really* a valid answer to the 1987/2013 puzzle.  Anyone
else care to offer a "better" solution?

-------------------------------------------------------------------------------
Michael Maciolek - mikem@ll.mit.edu --- VOICE (617)981-3174 - FAX (617)981-0189
Network Engineer - MIT Lincoln Laboratory - Computer Telecommunications Systems
-------------------------------------------------------------------------------
     "It works fine, provided you _want_ things to explode upon arrival."
From: mannj@acf9.nyu.edu (Jordan Mann)
Newsgroups: rec.puzzles
Subject: Re: Anagram Program
Date: 25 Dec 92 18:01:49 GMT
Organization: New York University

"John R Kennedy" <p00200@psilink.com> writes:

>Does anyone know where I can get the source code to an anagram program?
>I mean the kind that anagrams whole phrases, not just words.

>Thanks.
>The BitMan      p00200@psilink.com

>P.S.  Please don't just say "yes".

No.

:)

--
Jordan Mann at NYU      (mannj@cims.nyu.edu)
Newsgroups: rec.puzzles
From: matt@severian.chi.il.us (Matt Crawford)
Subject: Re: Guessing at random numbers.
Organization: The Chrome Plated Megaphone of Destiny
Date: Thu, 24 Dec 1992 04:25:05 GMT

Since you say "trying to find patterns in my behaviour is useless," I
assume that we play the game for several iterations.

As long as you don't alter the distribution that your generator picks
from between iterations, I think I can do a whole lot better than
50-50.  If you're allowed to change distributions, then if you know
my strategy, you can choose a sequence of distributions which thwarts
me.  (Even if you're required to give me the high or low number with
equal probability each time.)

My strategy: I guess "high" or "low" according to whether the number
you give me is higher or lower than the median of the numbers given
so far.  For the first iteration, I assume any median I wish, such as
zero.
__________________________________________________________
Matt Crawford       matt@severian.chi.il.us       Java Man

Newsgroups: rec.puzzles
From: russotto@eng.umd.edu (Matthew T. Russotto)
Subject: Re: New Year's problem
Date: Thu, 31 Dec 92 23:40:14 GMT
Organization: Project GLUE, University of Maryland, College Park

In article <1htrk2INNrql@mirror.digex.com> kfl@access.digex.com (Keith F. Lynch) writes:
>What property did 1987 have, that no year after it will have until
2013?

 |2000 - yr| = 13 :-) :-) :-).


>What property did 1961 have, that no year after it will have until 6009?

Reads the same upside down and right side up
-- 
Matthew T. Russotto	russotto@eng.umd.edu	russotto@wam.umd.edu
Some news readers expect "Disclaimer:" here.
Just say NO to police searches and seizures.  Make them use force.
(not responsible for bodily harm resulting from following above advice)
From: boll@CS.ColoState.EDU (dave boll)
Newsgroups: rec.puzzles
Subject: Monty Hall Puzzle RIP ....    PLEASE!!!!!
Date: 22 Dec 92 17:20:47 GMT
Organization: Colorado State University, Computer Science Department


  As a faithful reader and occasional poster on this newsgroup, I would like
  to make a suggestion. The next time someone posts to this group, 'proving'
  that the probability of getting the prize in the traditional Monty Hall
  puzzle is 1/2, could we all just ignore the post? Ditto for 'I have 2
  kids, one is a girl.....'. If you feel you must respond to articles like
  these, how about e-mail instead of news? I suspect I speak for more than
  just myself when I say I've had it up to here with posts answering 
  questions like these. Some people just ain't gonna change their minds
  no matter how loudly you shout, or how much real money you offer to
  show up their mistakes.          

  No flames to any one person intended here.


-- 
     ------------------------------------------------------------
     Dave Boll  boll@handel.cs.colostate.edu
                "The speed of time is 1 second per second"
     ------------------------------------------------------------
From: chris@questrel.com (Chris Cole)
Newsgroups: rec.puzzles
Subject: Re: FAQ list
Date: 1 Jan 93 17:34:12 GMT
Organization: Questrel, Inc.

In article <1992Dec31.203331.2300@sq.sq.com% msb@sq.sq.com (Mark Brader) writes:
%
%I guess Chris Cole, who maintains it, must be on holiday, so I'll
%take it upon myself to answer the recent questions about the FAQ list.
%
%The rec.puzzles FAQ list is now called the rec.puzzles archive, because
%it includes answers to a lot of puzzles that are not really all that
%frequently asked.  Because of this, it's also too big to be regularly
%reposted.  It was posted once in its entirety to news.answers and
%rec.puzzles a few months ago, which means that if you have access to
%anonymous FTP, you can get it from a site that archives news.answers.
%One of these is pit-manager.mit.edu (18.172.1.27), where the directory
%to look in is pub/usenet/news.answers/puzzles-faq.
%
%The archive is also available through an email server.  Send a message
%containing two lines of text:
%
%return_address YOUR-ADDRESS-GOES-HERE
%send index
%
%to the address archive-request@questrel.com, and it will send you a
%message of about 60K bytes containing an index of all the items, and a
%list of FTP sites.  If you omit the return_address line, it will use
%your From: address for the mail.
%
%There has been talk of making a true FAQ list, with only the most
%frequently occurring puzzles on it, but nobody has done this.


Thanks, Mark, for filling in.  I was indeed on holiday.

The only thing I have to add to this is that one of the volunteers for
maintaining the FAQ per se has been selected, and is now hard at work
on the FAQ.  This should be posted shortly, and will be posted
regularly.

The archive will only be posted every six months or so.
Newsgroups: rec.puzzles
From: "John R Kennedy" <p00200@psilink.com>
Subject: Anagram Program
Organization: BIT Engineering
Date: Tue, 22 Dec 1992 22:16:17 GMT
X-Mailer: PSILink-DOS (3.3)

Does anyone know where I can get the source code to an anagram program?
I mean the kind that anagrams whole phrases, not just words.

Thanks.
The BitMan      p00200@psilink.com

P.S.  Please don't just say "yes".
Newsgroups: rec.puzzles,can.general