HDTenEightyP/NetNews huggingface dataset:
From: farrell@coral.cs.jcu.edu.au (John Farrell)
Subject: Re: Dying young (solved)
Organization: James Cook University
Date:  7 Apr 92 07:05:37 GMT

In <7458@uqcspe.cs.uq.oz.au> warwick@cs.uq.oz.au (Warwick Allison) writes:
>One thing is clear.  The more Ws there are in the world, the better :-)

  Indeed. The more Ws there are, the better it is to be a J! Are you trying to
insinuate that by being a nice guy, I encourage other people to be nice guys,
and hence improve the chances that someone else is nice first? Great idea, as
long as we had time to arrange it before the bloody Nazis got us! It is not
the survival of thousands of Js I am worried about, just this one!

J
From: dant@logos.wr.tek.com (Dan Tilque)
Newsgroups: rec.puzzles
Subject: Re: Definitions
Date: 12 Apr 92 05:08:39 GMT
Organization: Upper Left Coast Liberation Army

dwilson@cvbnet.prime.com (David Wilson x5694 4-1600) writes:
>
>    decade: adj.  Any sweetened drink containing 10% real fruit juice.

     decade: n. A sweetened drink made from Vaxen

---
Dan Tilque	--	dant@logos.WR.TEK.COM
From: kontos@clipper.ingr.com (Thorne Kontos)
Newsgroups: rec.puzzles
Subject: Re: Circular number puzzle
Summary: Solution time < 2 minutes
Date: 7 Apr 92 21:45:59 GMT
Organization: Intergraph Advanced Processor Division - Palo Alto, CA

In article <92090.132433SHERE@SLACVM.SLAC.STANFORD.EDU>, SHERE@SLACVM.SLAC.STANFORD.EDU writes:
> Here's a "Circular" number puzzle for you all.....
> 
>               ABCDEF * 2 = CDEFAB
>               ABCDEF * 3 = BCDEFA
>               ABCDEF * 4 = EFABCD
>               ABCDEF * 5 = FABCDE
>               ABCDEF * 6 = DEFABC
> 
> Every "A" is the same number, as is every other letter.
> No two letters are the same number.  No zeros.
> It is possible.  Good luck.





Once you determine A=1, the rest of the digits fall into place
quickly...




Therefore:


The solution is:
A=1, B=4, C=2, D=8, E=5, F=7
From: Bob.Thomson@f355.n632.z3.fx.cec.edu.au (Bob Thomson)
Newsgroups: rec.puzzles
Subject: Total squares in a grid
Date: Mon, 13 Apr 1992 09:19:00 +1000

Can you give me a formula to determine the total number of squares in a grid. The formula must work for any size grid.

eg.

  ---- ---- ----
 |    |    |    |
  ---- ---- ----
 |    |    |    |     This is a 3 X 4 grid which contains a total of
  ---- ---- ----      20 squares.
 |    |    |    |
  ---- ---- ----
 |    |    |    |
  ---- ---- ----

There is a formula to do this.

 * SLMR 2.1a * Did you ever stop to think and forget to start again?


 * Origin: A.I.M. - A)ccess I)n M)elbourne    (3:632/355)
From: surya@watson.ibm.com (Surya Mohanty)
Newsgroups: rec.puzzles
Subject: Fill in the blanks.
Date: 10 Apr 92 20:35:58 GMT
Reply-To: surya@rothko.watson.ibm.com (Surya Mohanty)
Followup-To: (Guess the next 3 numbers in the sequence)
Organization: IBM T.J. Watson Research Center
Disclaimer: This posting represents the poster's views, not necessarily those of IBM

What are the next three numbers in the sequence and why ?

3 5 11 17 31 41 67 - - - ?
From: dwilson@cvbnet.prime.com (David Wilson x5694 4-1600)
Newsgroups: rec.puzzles
Subject: Definitions
Date: 10 Apr 92 14:39:57 GMT
Organization: Computervision, A Prime Computer Company, Bedford, MA, USA
Originator: dwilson@wrench


    ataxial: adj.  Preferring to traverse Manhattan on foot.

    briefly: n.  An agricultural pest harmful to French cheeses.

    cherish: adj.  Prone to indulge in sexual exhibitionism
	inappropriate to one's advancing age.

    decade: adj.  Any sweetened drink containing 10% real fruit juice.

    lassitude: n.  The ability, in dire circumstances, to communcate
	detailed information via barking, whining, and pawing the
	ground.

    molecule: n.  Any of several tiny burrowing animals.

    monogrammed: adj.  Having one living grandmother.

    precarious: adj.  Refers to the condition of a tooth just prior
	to the formation of a cavity.

    prelate: adj.  On time.

    thesuarus: n.  Dinosaur of the late Jurassic period, notable
	for engaging in religious rituals.  An anomaly to both
	creationists and evolutionists.

    yellow: n.  Swedish fruit-flavored gelatin dessert.


-- 
David W. Wilson (dwilson@cvbnet.prime.com)
J.H.Whitney (was Prime Computer (was Computervision Corp.)), Bedford, MA
Disclaimer: "Truth is just truth...You can't have opinions about truth."
- Peter Schikele, introduction to P.D.Q. Bach's oratorio "The Seasonings."
From: ecarsten@next1.cs.umr.edu (Edward Carstens)
Newsgroups: rec.puzzles
Subject: factorial puzzle
Date: 7 Apr 92 19:59:26 GMT


How many zeros are at the end of the number, 1000! ?

(Of course there are 3 zeros at the end of 1000 but the question asks for 1000  
factorial.)

-Ed Carstens
Creator of JugglePro
From: moews@math.berkeley.edu (David Moews)
Newsgroups: rec.puzzles
Subject: Re: The street where I live (SPOILER)
Date: 17 Apr 92 06:11:25 GMT
Distribution: world
Organization: UC Berkeley Math Department
NNTP-Posting-Host: phnom-penh.berkeley.edu
Originator: moews@phnom-penh.berkeley.edu

In article <1992Apr17.010752.1370@clipper.ingr.com>,
   kontos@clipper.ingr.com (Thorne Kontos) writes:
|...
|Clarence: Like you and me, Cuthbert, those three people all live
|          on Calculation Crescent, and the numbers of their houses
|          add up to twice the number of your house. Multiplied
|          together their three numbers make 1260. The numbers of
|          our five houses are, of course, all different.
|
|Cuthbert: That doesn't tell me what their numbers are.
|
|Clarence: That's true. But it will if I give you the additional
|          information that the nymber of my house is greater than
|          that of any of yours.
|
|I thought to myself, the numbers of the houses on Calculation
|Crescent run from 2 to 222. After some quick calculations, I knew
|where Cuthbert, Clarence, and the other three lived....

(Spoiler)

The sum of those three people's house numbers is even, so either they
are all even or two are odd and one is even.  But 1260 = 2.2.3.3.5.7,
so we only have 2 factors of 2 available, and they can't all be even; hence 
one is even and the other two are odd.  The numbers will then be 4x, y, and z,
where xyz = 3.3.5.7.  Also, y and z are unequal, and neither y nor z is 1.
There are then 15 possibilities, which we list as (4x,y,z,4x+y+z):

2.2.3.7   3      5     92
2.2.3.5   3      7     70
2.2.3.3   5      7     48
2.2.5     3.3    7     36
2.2.5     3      3.7   44
2.2.7     3.3    5     42
2.2.7     3      3.5   46
2.2.3     5.7    3     50
2.2.3     3.5    7     34
2.2.3     3.7    5     38
2.2       3.3    5.7   48
2.2       3.3.5  7     56
2.2       3.3.7  5     72
2.2       3.5.7  3    112 
2.2       3.5    3.7   40

Since Cuthbert can't immediately tell what the numbers are, the sum must
be 48, since 48 is the only number that's the sum of two different triples.
Hence Cuthbert's number is 24 and the three numbers are either 5, 7, and 36,
or 4, 9, and 35.  Then for Clarence's second statement to be possible and
yield information, Clarence's number must be 36, and the three
house numbers are then 4, 9, and 35.
-- 
David Moews                               moews@math.berkeley.edu
Newsgroups: rec.puzzles
From: csmith@onetouch.COM (Craig Smith)
Subject: Re: 2 oldies  <*SPOILER*>
Organization: MCS/OneTouch, Inc.
Date: Wed, 08 Apr 92 20:54:42 GMT

sjs@hood.hood.caltech.edu (Stephen Speicher) writes:

>These are two simple old ones - but cute.

>1. Consider the sequence O T T F F . .
>   What are the next two letters - and why?

O  T  T  F  F  S  S
n  w  h  o  i  i  e
e  o  r  u  v  x  v
      e  r  e     e
      e           n

>2. Consider the letters H I J K L M N O
>   There is a one-word solution to this.
Question?

>Stephen
>sjs@hood.hood.caltech.edu
-- 
:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
:: Craig Smith                                         csmith@onetouch.COM ::
:: Columbus, OH                                  ...!uunet!onetouch!csmith ::
::::::::::::::: "Life is a fulltime occupation."--Gene Kalman :::::::::::::::
Newsgroups: rec.puzzles
From: corby@zaphod.ssf-sys.DHL.COM (Corby Anderson)
Subject: Re: Is 'w' ever a vowel
Reply-To: corby@ssf-sys.DHL.COM (Corby Anderson)
Organization: DHL Systems, Inc., San Mateo, CA  94402
Date: Sat, 11 Apr 1992 01:14:50 GMT
Followup-To: rec.puzzles

In article <69377@bcsaic.UUCP> gah2468@bcsaic.UUCP (Geoffrey Hazel) writes:
>In article <1992Mar12.080120.14159@hemlock.cray.com> jsy@yahweh.cray.com (Jeff Young) writes:

>So I add to the question: is W ever a vowel? ( it certainly must be a rare
>occurence [sic]).

The only example of this I can think of (off the top of my head) is
"cwm", which is one of those foreign words you find in American
dictionaries.  It's Welsh, and it is a "small hollow, often containing
a small lake, occurring at the upper end of a mountain valley"
(American Heritage Dictionary [ick])
Newsgroups: rec.puzzles,soc.culture.indian
From: amorgan@Xenon.Stanford.EDU (Crunchy Frog)
Subject: Re: A (Not So Obviously) simple number puzzle
Organization: Computer Science Department, Stanford University.
Date: Wed, 8 Apr 1992 02:42:08 GMT

In article <1992Apr08.002211.8703@ecst.csuchico.edu> 
  vivek@ecst.csuchico.edu (Vivek R. Prabhu) writes:
>In article <1992Apr7.202400.26466@Cadence.COM> 
  hemmady@Cadence.COM (Shankar Hemmady) writes:
>>
>>The puzzle goes as follows:
>>
>>"My child's age raised to itself gives my age.
>>If my wife is younger than me by my child's age
>>and if we are LIVE humans, then what are our ages?"
>>
>>- Shankar Hemmady
>>hemmady@cadence.com
>>
>
>If we let the wife's age = y yrs.
>Then the wife's age i.e. y = (x**x - x) yrs.
>
>Hence we have an equation y = x(x**(x-1) - 1) yrs.
>
>This is representative of the equation (x**2 - 1)
>
>Hence (x - 1) = 2

You seem to be implying that this is the only solution.  Why, other than
basic biology, couldn't x = 2 or x = 4 be solutions of the original
problem?

For that matter, why go about it in such a round about fashion?  Why not
say "Could the child be 1?  Nope, Dad would be 1 too.  Could the child
be 2?  Unlikely, Dad would be 8.  Could the child be 3?  Sure, that would
make Dad 3**3 or 27 and Mom would be 24."?

Easy.

>Regards,
>Vivek.

C Frog
From: tdh@ksr.com (Dave Hudson)
Newsgroups: rec.puzzles
Subject: 1992-04-09 WSJ puzzle
Date: 10 Apr 92 20:10:53 EDT
Organization: Kendall Square Research Corp.

There was a little puzzle in the WSJ the other day.  It asked for
the maximum number of enclosed volumes created by three
interpenetrating cubes.  I presume that "interpenetrating" meant
"volumes mutually intersecting" and that "enclosed volumes" meant
"volumes bounded by pieces of faces of the cubes"; for example, if you
were to rotate a cube 45 degrees about the centers of two opposite
faces, and intersect it with its previous self, you'd get nine
enclosed volumes, or if two cubes got squashed together slightly at
one corner there'd be only three enclosed volumes.  (Different
interpretations of the puzzle's wording did not seem interesting.)

After a little mulling and a lot of counting, the best that I could
come up with for three cubes was 67.  The counting was by far the
hardest part, and I'm still not sure I counted correctly; for a while,
misrevisualizing, I thought that the very same configuration held only
43.

The solution for two cubes is quite straightforward and simple.  If I
were a masochist, I'd try to apply my two-cube method iteratively to
my two-cube result in order to get the three-cube solution.  Are there
any techniques for solving this for three cubes other than
visualization (not including pounding one's head :-) )?  What branches
of specialized knowledge do they depend on?

David G. Caraballo suggested also asking for a solution generalized for
N cubes.  Whew!  The three-cube question alone reportedly appeared in
a difficult test.

				David Hudson
Newsgroups: rec.puzzles
From: tolman%asylum.utah.edu@cs.utah.edu (Kenneth Tolman)
Subject: Re: Where's the rest of these riddles?
Date: 9 Apr 92 21:25:50 MDT
Organization: University of Utah CS Dept

The real reason that pigs fail algebra is because the buffalos live there.

OK, so why does a mouse when it spins?

The higher, the fewer.

So what is the difference between a duck?

One of its legs is both the same.

Why does a chicken?

Because the egg did first.

When the cow does anyone?

 
Newsgroups: rec.puzzles,soc.culture.indian
From: fb78@sol.acs.unt.edu (Ganesh Gopalakrishnan)
Subject: Re: A simple number puzzle
Organization: University of North Texas
Date: Tue, 14 Apr 1992 14:00:46 GMT

What is the big deal? Maybe he WANTED to share the puzzle with other
Indian netters who MIGHT BE interested. No policing, please, and let
EVERYONE enjoy their freedom! - Ganesh

Newsgroups: rec.puzzles
From: jes@kodiak.si.macsch.com (John Schiermeier)
Subject: Re: order of numbers?
Organization: The MacNeal-Schwendler Corporation
Distribution: rec
Date: Thu, 9 Apr 92 19:36:43 GMT

In article <1992Apr6.190547.27198@Princeton.EDU> pfalstad@phoenix.Princeton.EDU (Paul Falstad) writes:
>dant@logos.wr.tek.com (Dan Tilque) wrote on 6 Apr 92 17:01:18 GMT:
>
>>	8, 3, 1, 5, 9, 7, 6, 4, 2
>
>I'll guess German, based on where the "2" is.
>
Almost German, but not quite:
  acht, drei, eins, funf, neun, sieben, sechs, view, zwei
so the seven and six should be reversed if German was intended.
Zero is null, and so would be after the nine.

john
j_schiermeier@macsch.com
From: warwick@cs.uq.oz.au (Warwick Allison)
Newsgroups: rec.puzzles
Subject: Re: Dying young
Date: 7 Apr 92 01:24:28 GMT
Reply-To: warwick@cs.uq.oz.au

tolman%asylum.utah.edu@cs.utah.edu (Kenneth Tolman) writes:

>You are put in a room by evil Nazi's.  There is a button in front of you.  If
>you press the button, you will die.  However, there are 100 other people in
>similar rooms.  If no one pushes their button before 12:00, everyone dies.  You
>have no way to know if the other people have pushed theirs or not. 
>It is now 11:50. What do you do?

1. Assume everyone else does whatever you do.

2. Pick a number between 1 and 100 (using dice).  If the number is 1 or
two, push the button.  

I'm not very good at probability (I have two sisters, one of which is
younger than the other), but there must be some assignment of probabilities
that is optimal, since 100% and 0% are both fatal (all people die).




Warwick.
--
  _-_|\      warwick@cs.uq.oz.au            / pinots pintos /
 /     * <-- Computer Science Department,  / piston pitons /
 \_.-._/     University of Queensland,    / points potins /
      v      Brisbane, Australia.        / ------ ------ /
Newsgroups: rec.puzzles
Subject: Re: 1992-04-09 WSJ puzzle
From: dmi@peregrine.peregrine.com (Dean Inada)
Date: 11 Apr 92 09:45:15 GMT
Reply-To: dmi@peregrine (Dean Inada)
Organization: Peregrine Systems, Inc.

In article <11373@ksr.com> tdh@ksr.com (Dave Hudson) writes:
>There was a little puzzle in the WSJ the other day.  It asked for
>the maximum number of enclosed volumes created by three
>interpenetrating cubes.  I presume that "interpenetrating" meant
Another question:
How many configurations are there that yield the maximum number?
>
>David G. Caraballo suggested also asking for a solution generalized for
>N cubes.  Whew!  The three-cube question alone reportedly appeared in
>a difficult test.
By Ron Hoeflin, in Omni.

Generalising for N <= 5 seems to be particularly interesting.
From: dwr2560@zeus.tamu.edu (RING, DAVID WAYNE)
Newsgroups: rec.puzzles
Subject: Re: More Math Problems
Date: 9 Apr 92 17:34:00 GMT
Organization: Texas A&M University, Academic Computing Services
News-Software: VAX/VMS VNEWS 1.41

BANDA@AUSVM1.VNET.IBM.COM ("Venu Prabhakar Banda") writes...
>3. Let S denote the set of numbers represented by the regular
>   expression 1(01)*, i.e, numbers with alternating 0's and 1's that
>   begin and end in 1.
>   How many primes are there in S? (the numbers are in decimal)

*** SPOILER ***


1

numbers with even # of 1's are divisible by 101. (101 is prime of course)
numbers with odd # of 1's can be factored (except 1). For example

101010101 = 11111 * (10000-1000+100-10+1)

Dave Ring
dwr2560@zeus.tamu.edu
Newsgroups: rec.puzzles
From: bmesmer@occs.cs.oberlin.edu (Carl Muckenhoupt)
Subject: Re: The Philosopher's Puzzle... 
Organization: Oberlin College Computer Science
Date: Thu, 9 Apr 1992 23:31:36 GMT

Think: "If my head is clean, then Hylas there must think it strange that
Philomena is laughing, because Hylas can't see anyone that Philomena might
be laughing at. He would then conclude that Philomena is laughing at HIM!
And of course he would then stop laughing, act embarassed, check his head,
etc. Hmm. I don't see Hylas doing that. It must be that I am as soiled
as they! Unless, of course, Hylas simply hasn't figured it out yet. Hmm...
Maybe I should wait a minute before doing anything. After all, who knows
how fast a reasoner he is? Wait, there he goes! He's stopped laughing...
he's feeling his head... yes! I'm safe! But wait a minute. What if he simply
followed the same line of reasoning that I did, and came to the conclusion
that his head was soiled on the basis that mine was and Philomena's was and
we were both laughing? I CAN'T TELL! Aaargh. O the heck, I'm feeling my
head."

NB: This uncertainty grows in proportion to the number of participants.


--

Carl Muckenhoupt        bmesmer@occs.cs.oberlin.edu
"As a lyricist you become sensitive to certain things. You become aware
that there aren't very many words that rhyme with 'love'. There are a lot
more words that rhyme with 'hate' than with 'love'. You've got 'above'
and 'dove' and 'glove' and 'shove' and that's about it."
                        - Peter Shickele


Newsgroups: rec.puzzles
From: flint@hinault.cs.curtin.edu.au (Daniel Baldoni)
Subject: Re: SPOILERS: Isaac Asimov's mysteries puzzle
Organization: Curtin University of Technology
Date: Mon, 13 Apr 1992 07:22:46 GMT

In <1992Apr11.014450.25843@bmerh2.bnr.ca> coop1w13@bnr.ca (Mike Hammond) writes:
>Spoilers for a tough puzzle. (The only reason I know this is because I
>happened to read that particular issue of Isaac Asimov's Science Fiction
>Magazine. By the way, isn't this a puzzle of Martin Gardener?)
>
>In article <3847@shum.huji.ac.il>, yehuda@shuldig.huji.ac.il (Jonathan Berlinger) writes:
>|> Donn't know if anyone heard this one yet, so:
>|> 
>|> Why does>        Christmas = Halloween
>|> 
>|> Hint below:
>|> 
>|>  
>|> Hint: look at the dates.
>
>Well, December 25 is 12/25, while October 31 is 10/31. Note that 25 in base
>12 is equal to 31 in base 10. Thus Christmas=Hallowe'en.

No way.

     25(base 12) = 2 * 12 + 5 * 1
                 = 24 + 5
                 = 29 <> 31(base 10)

--
		Daniel Baldoni

--------------------------------------------+----------------------------------
Phone:    +61-9-351-7667                    | School of Computing Science,
InterNet: flint@cs.curtin.edu.au            | Curtin University of Technology,
--------------------------------------------+ GPO Box U1987, Perth,
#include <std/disclaimer.h>                 | Western Australia, 6001
--------------------------------------------+----------------------------------
"Any time there's something so ridiculous (...) that no rational systems
 programmer would even consider trying it, they send for me"
  - Paraphrased from "King of the Murgos" by David Eddings
From: Marc.Costaldi@f2050.n391.z1.FidoNet.Org (Marc Costaldi)
Sender: UUCP@p0.f1060.n391.z1.FidoNet.Org
Newsgroups: rec.puzzles
Subject: trvia
Date: 11 Apr 92 14:44:00 EST

Got a problem need some help with:

An architect was asked to design a square house with the window in each
wall 
having a southern exposure. How was this done?

any ideas?

Marc.Costaldi@f2050.n391.z1.fidonet.org

-------  
 
---
 * Origin: FireHouse BBS    Buring the others DOWN! 273-9580 (1:391/2050)
From: lordSnooty@cup.portal.com (Andrew - Palfreyman)
Newsgroups: rec.puzzles
Subject: Re: trvia
Date: Mon, 13 Apr 92 16:48:18 PDT
Organization: The Portal System (TM)

Marc.Costaldi@f2050.n391.z1.fidonet.org:
: Got a problem need some help with:
: 
: An architect was asked to design a square house with the window in each wall 
: having a southern exposure. How was this done?

Presumably this is the hoary old chestnut about being at the North Pole.
 --------------------------------------------------------------------------
| lord snooty @the giant | wolfpack, silver, down to the water             |
| poisoned electric head |              andrew palfreyman@cup.portal.com   |
 --------------------------------------------------------------------------
From: meng@idt.unit.no (Tore Mengshoel)
Newsgroups: rec.puzzles
Subject: Re: A simple sequence of numbers ...
Date: 9 Apr 92 15:41:49 GMT
Reply-To: meng@idt.unit.no (Tore Mengshoel)
Organization: Div. of CS & Telematics, Norwegian Institute of Technology

In article <1992Apr7.220710.27512@Cadence.COM>, hemmady@Cadence.COM (Shankar Hemmady) writes:
|> 
|> 
|> Continue this sequence:
|> 
|> 	3, 3, 5, 4, 4, 3, 5, 5, 4, 3, ...
|>
e.g. 3, 5, 4, 4, 3, 3, 5, 5, 4, 3, .... 
|> 
|> -Shankar Hemmady
|> hemmady@cadence.com

Tore
From: kontos@clipper.ingr.com (Thorne Kontos)
Newsgroups: rec.puzzles
Subject: The street where I live (Calculation Crescent)
Keywords: This one IS NOT EASY!
Date: 17 Apr 92 01:07:52 GMT
Distribution: na
Organization: Intergraph Advanced Processor Division - Palo Alto, CA

An overheard conversation:

Clarence: Like you and me, Cuthbert, those three people all live
          on Calculation Crescent, and the numbers of their houses
          add up to twice the number of your house. Multiplied
          together their three numbers make 1260. The numbers of
          our five houses are, of course, all different.

Cuthbert: That doesn't tell me what their numbers are.

Clarence: That's true. But it will if I give you the additional
          information that the nymber of my house is greater than
          that of any of yours.

I thought to myself, the numbers of the houses on Calculation
Crescent run from 2 to 222. After some quick calculations, I knew
where Cuthbert, Clarence, and the other three lived.

What is Cuthbert's address?
What is Clarence's address?
What are the addresses of the "other three"?
From: matthew@ntl02.decnet.nokia.fi (Matthew Faupel)
Newsgroups: rec.puzzles
Subject: Re: Crpytic Puzzle Solving
Date: 9 Apr 92 15:47:37 GMT
Organization: Nokia Telecommunications, Cambridge, UK

>>>>> On 8 Apr 92 15:29:11 GMT, js06+@andrew.cmu.edu (Jason Lee Smith) said:

Jason> Does anybody have a guide to; Cryptic puzzle solving that they'd  be
Jason> willing to post to the net. I think I need a refresher course, the only
Jason> clues I seem to be able to get, lately, are anagrams.

I don't have one as yet, but I was thinking of writing one sometime soon if
no-one else has done so.  Expect to see it in a couple of week's time.


Matthew
--
---* Amnesiac the Wizard *------------------* matthew@uk.tele.nokia.fi *---
 Opinions expressed here are not those of my company.    | NB. ntl02 is EN
 They're not even my own; I plagiarised the lot of them! | TEE EL ZERO TWO
---* matthew@ntl02.decnet.nokia.fi *------------------* Matthew Faupel *---
Newsgroups: rec.puzzles