Grass-G/jee-main-questions huggingface dataset:
Subject: Chemistry — Physical Chemistry — Electrochemistry
Difficulty: Moderate

Question: The Gibbs energy for the decomposition of ${Al}_{2}O_{3}$ at
500°C is as follows:
$\frac{2}{3}{Al}_{2}O_{3} \rightarrow \frac{4}{3}Al + O_{2};\Delta_{r}G = + 966{kJmol}^{- 1}$
The potential difference needed for electrolytic reduction of
${Al}_{2}O_{3}$ at 500° is at least


Answer: 2.5

Solution:
$\frac{2}{3}{Al}_{2}O_{3} \longrightarrow \frac{4}{3}Al + O_{2}$
$\Delta_{r}G = + 966kJ{mol}^{- 1} = 966 \times 10^{3}J{mol}^{- 1}$
$\Delta G = - nFE_{cell\ }$
$966 \times 10^{3} = - 4 \times 96500 \times E_{cell\ }$
$E_{cell\ } = 2.5V$
Subject: Chemistry — Coordination Compounds — Werner's Theory
Difficulty: Moderate

Question: Which of the following will exhibit maximum ionic conductivity?


Correct option: 1

Solution:
Conductivity a number of ions in the solution.
(1) [IMAGE] 4: 1 electrolyte.
It contains maximum number of ions i.e.
Subject: Chemistry — Inorganic Chemistry — D & F -Block Elements
Difficulty: Moderate

Question: [IMAGE] in basic medium is reduced to


Correct option: 2

Solution:
[IMAGE] is first reduced to manganate and then
to insoluble manganese dioxide. Colour change first from purple to green
and finally becomes colorless.
Subject: Chemistry — Physical Chemistry — Gaseous state
Difficulty: Easy

Question: Two vessels whose volumes are in the ratio 2: 1 contain
nitrogen and oxygen at 2500 mm and 1000 mm pressures respectively when
they are connected together what will be the pressure of the resulting
mixture (in meters) ?


Answer: 2

Solution:
$\frac{V_{N_{2}}}{V_{O_{2}}} = \frac{2}{1}$
$P_{N_{2}} = 2500mm,P_{O_{2}} = 1000mm$
$P_{now} = \frac{P_{N_{2}} \cdot V_{N_{2}} + P_{0_{2}} \cdot V_{0_{2}}}{V_{N_{2}} + V_{0_{2}}} = \frac{2500 \cdot V_{N_{2}} + 1000 \cdot \frac{V_{N_{2}}}{2}}{V_{N_{2}} + \frac{V_{N_{2}}}{2}}$
$= \frac{3000{VN}_{2} \cdot 2}{3VN_{2}} = 2000mm = 2m$
Subject: Chemistry — Periodic table — Oxidation states & Inert pair effect
Difficulty: Easy

Question: Which of the following is correct order of stability

1) Tl3+> Bi3+
2) PbO2> PbO
3) BiI5< BiF5
(D) Sn2+ = Ge2+

Correct option: 3

Solution:
BiI5 does not exists because of I- being very strong reducing
agent. So it reduces Bi5+ to Bi3+ and forms BiI
Subject: Chemistry — Inorganic Chemistry — Metallurgy
Difficulty: Easy

Question: of Fe in Alloy Invar is


Answer: 64

Solution:
of Fe in Alloy Invar is 64
Subject: Chemistry — Inorganic Chemistry — P-block nitrogen
Difficulty: Moderate

Question: Regular use of which of the following fertilizers increases the
acidity of soil?

1) Superphosphate of lime
2) Ammonium sulphate
3) Potassium nitrate
4) Urea
fdl mojZd e`nk

Correct option: 2

Solution:
(NH4)2SO4 + 2H2O → (2H+ + SO42-) + 2NH4OH
Strong acid Weakbase
(NH_4)_2 SO_4 on hydrolysis produces strong acid H_2SO_4, which
increases the acidity of the soil.
(NH4)2SO4 + 2H2O → (2H+ + SO42-) + 2NH4OH
çcy vEy nqcZy {kkj
(NH4)2 SO4 ds tyvi?kV~u ij çcy vEy H_2SO_4, curk
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Easy

Question: The number of $\pi$-bonds present in pent-1-en-4-yne is:
isUV-1-bZu-4-vkbZu v.kqvksa $\pi$cU/kksa


Answer: 3

Solution:
Pent-4-ene-1-yne
${CH}_{2} = CH - {CH}_{2} - C = CH$
No. of $\pi$ -bonds: $1(C = C) + 2(C \equiv C) = 3$
${CH}_{2} = CH - {CH}_{2} - C = CH$
$\pi$ - la $1(C = C) + 2(C \equiv C) = 3$
Subject: Chemistry — Inorganic Chemistry — Hydrogen And Its Compound
Difficulty: Moderate

Question: Electrolysis of fused sodium hydride liberate hydrogen at the

1) Anode
2) Cathode
3) Cathode and anode both
4) None of these

Correct option: 1

Solution:
$Na \rightleftharpoons {Na}^{+} + H^{-}$
At anode: $H^{-} \rightarrow H + e^{-}$
$H + H \rightarrow H_{2}$
Subject: Chemistry — Organic Chemistry — Organic compounds containing Nitrogen
Difficulty: Moderate

Question: Primary nitro compounds when crystalline solids which on
treatment with NaOH gives react with HNO_2 forms

1) Red solution
2) Blue solution
3) White precipitate
4) Yellow colouration

Correct option: 1

Solution:
Subject: Chemistry — Organic Chemistry — Hydrocarbons
Difficulty: Easy

Question: [IMAGE] No. of monochloro structure isomers in products is


Answer: 4

Solution:
Alkyl group of this molecule has four types of replaceable
hydrogen atoms
Subject: Chemistry — Chemical Bonding — H- Bonding
Difficulty: Moderate

Question: The number of water molecule (s) directly bonded to the metal
center in CuSO4. 5H2O is


Answer: 4

Solution:
Subject: Chemistry — Inorganic Chemistry — p-block elements
Difficulty: Easy

Question: No. of atoms in one molecule of sulphur is


Answer: 8

Solution:
Subject: Chemistry — Sub — Number of Structural Isomers
Difficulty: Moderate

Question: How many positional isomers are possible for
dimethylcyclohexane?

1) 3
2) 4
3) 5
4) 6

Correct option: 2

Solution:
Subject: Chemistry — Physical Chemistry — Chemical Kinetics
Difficulty: Moderate

Question: For a reaction, $X(g) \rightarrow Y(g) + Z(g)$ the half life
period is 10 min. In What period of time would the concentration of X be
reduced to 10 of original concentration.

1) 20 min
2) 33 min
3) 15min
4) 25 min

Correct option: 2

Solution:
$X(g) \rightarrow Y(g) + Z(g)$
The reaction is a first order reaction hence,
$K = \frac{0.693}{t_{1/2}} = \frac{2.303}{t}log\frac{a}{a - x} = \frac{0.693}{10\min}$
$= \frac{2.303}{t}log\frac{a}{a/10} = \frac{0.693}{10} = \frac{2.303}{t}log10$
$\therefore t = \frac{2.303 \times 10}{.693} = 33min$
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: A solid is made of two elements X and Z. The atoms Z are in
CCP arrangement while the atom X occupy all the tetrahedral sites.
What is the formula of the compound

1) XZ
2) XZ_2
3) X_2Z
4) X_2Z_3

Correct option: 3

Solution:
Tetrahedral sites one double comparable to octahedral sites
then ratio of X and Z respectively 2: 1 since formula of the
compound X_2 Z.
Subject: Chemistry — Inorganic Chemistry — Chemical Bonding
Difficulty: Easy

Question: The correct order of increasing C-O bond length of
$CO,{CO}_{3}^{2 -},{CO}_{2}$ is

1) ${CO}_{3}^{2 -} < {CO}_{2} < CO$
2) ${CO}_{2} < {CO}_{3}^{2 -} < CO$
3) $CO < {CO}_{3}^{2 -} < {CO}_{2}$
4) $CO < {CO}_{2} < {CO}_{3}^{2 -}$

Correct option: 4

Solution:
B.O. in CO i.e.$:\overset{-}{C} = \overset{+}{O}:$ is 3, that
of$O = C = O$is 2 while that of${CO}_{3}^{2 -}$ ion is 1.
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: The number of octahedral voids in a unit cell of a cubical
closest packed structure is


Answer: 4

Solution:
Number of atoms in the cubic close packed structure =
Subject: Chemistry —  — HCP & CCP structures
Difficulty: Tough

Question: Volume of HCP unit cell is

1) 24r3
2) 8r3
3) 16r3
4) 24r3

Correct option: 1

Solution:
Volume of hexagon:
[IMAGE] So [IMAGE] and Area of hexagonal
surface[IMAGE] volume of hexagon = area of base × height
Subject: Chemistry —  — 

Question: Among the following inter halogen compounds, the total number of
compounds that exist in the gaseous state at room temperature is



Solution:
[IMAGE] - Gases
[IMAGE] - liquids
Subject: Chemistry — Inorganic Chemistry — P-Block Element
Difficulty: Moderate

Question: Nitrogen is liberated by the thermal decomposition of only

1) NH_4 NO_2
2) NaN_3
3) (NH_4)_2 Cr_2 O_7
4) All the these

Correct option: 4

Solution:
NH_4 NO_2 [IMAGE] N_2 + 2H_2O
2NaN_3[IMAGE] 2Na + 3N_2
(NH_4)_2 Cr_2 O_7[IMAGE] N_2 + Cr_2
O_3 + 4H_2O
Subject: Chemistry — Organic Chemistry — Aldehydes, Ketones & Carboxylic Acids
Difficulty: Easy

Question: distinguished by testing with

1) Phenyl hydrazine
2) Hydroxylamine
3) Fehling solution
4) Sodium bisulphite

Correct option: 3

Solution:
Subject: Chemistry — Electrochemistry — Concept of △G
Difficulty: Moderate

Question: Given standard electrode potentials:
Fe3+ + 3e¯ → Fe; E° = -0.036 volt
Fe2+ + 2e¯ → Fe; E° = -0.440 volt
The standard electrode potential E° for Fe3+ + e¯ Fe2+

1) -0.476 volt
2) -0.404 volt
3) -0.440 volt
4) -0.772 volt

Correct option: 4

Solution:
[IMAGE] E° = 0.772 Volt
Subject: Chemistry —  — 

Question: In which of the following pairs both are monobasic, proton donor
acid when dissolved in water?

1) H_3PO_2, H_3BO_3
2) H_3PO_2, HClO_4
3) HClO_3, H_3BO_3
4) H_3PO_2, H_3PO_3


Solution:
[IMAGE] Both are monobasic and proton donor acid.
But H_3BO_3 is not proton donor acid.
H_3BO_3 + H_2O → [B(OH)_4]^¯ + H^+
H_3BO_3 is only Lewis acid because it accept OH¯ from water.
Subject: Chemistry —  — 

Question: The first noble gas compound formed was........... and reason
behind this discovery was.........

1) [IMAGE] ionization enthalpy IE of
[IMAGE] of Xe
2) [IMAGE] ionization enthalpy (IE) of
[IMAGE] of Xe
3) [IMAGE] ionization enthalpy (IE) of
[IMAGE] of Xe
4) [IMAGE] ionization enthalpy (IE) of
[IMAGE] of Xe


Solution:
(4) It is theoretical.
Subject: Chemistry — Isomerism — R/S & D/L Naming.
Difficulty: Moderate

Question: Which Fisher projection represents the given wedge dash
structure


Correct option: 1

Solution:
First decide the (R/S) configuration in wedge-dash and then
draw Fischer projection for same configuration.
Subject: Chemistry — Physical Chemistry — Ideal gases
Difficulty: Moderate

Question: A gaseous mixture of three gases A, B and C has a pressure of 10
atm. The total number of moles of all the gases is 10. If the partial
pressure of A and B are 3.0 and 1.0 atm respectively and if C has mol.
wt. of 2.0, what is the weight of C in g present in the mixture ?


Answer: 12

Solution:
Pressure of Total mixture = 10 atm
$P_{A} + P_{B} + P_{c} = 10$
$3 + 1 + P_{c} = 10 \Rightarrow P_{c} = 6\ atm\ $
Total moles of mixture = 10
$N_{A} + n_{B} + n_{C} = 10$
$\frac{P_{A}}{P_{B}} = \frac{n_{A}}{n_{B}} = \frac{3}{1} \Rightarrow \frac{P_{B}}{P_{C}} = \frac{n_{B}}{n_{C}} = \frac{1}{6}$
Let
$n_{A} = K \Rightarrow n_{B} = \frac{K}{3}n_{c} = \frac{1}{6}n_{B} = 2K$
$\Rightarrow K + \frac{K}{3} + 2K = 10 \Rightarrow \frac{K}{3} = \frac{n_{C}}{6} \Rightarrow n_{c} = 2K$
$\Rightarrow K\left( \frac{10}{3} \right) = 10K = 3, \Rightarrow n_{A} = 3$
$n_{B} = 1$
$n_{c} = 6$
weight of in mixture =.$\ = 2 \times 6 = 12$
Subject: Chemistry — Inorganic Chemistry — Coordination compounds final
Difficulty: Moderate

Question: Predict the hybridisation and geometry of the following
complexes.


Correct option: 2

Solution:
(2) In the paramagnetic octahedral complex, [Fe(CN)6]3-, the iron
ion is in +3 oxidation state and has the electronic configuration
represented as shown below.
Fe3+,[Ar]3d5 (CN)6]3- [IMAGE] d2sp3 hybrid orbital & octahedral.
(3) In the paramagnetic and tetrahedral complex the
manganese is in +2 oxidation state and the ion has the electronic
configuration 3d
Subject: Chemistry — Physical Chemistry — Gaseous state
Difficulty: Tough

Question: Two flask A & B have capacity of 1 litre and 2 litre
respectively. Each of them contain 1 mole of a gas. The temperature of
the flask are so adjusted that average speed of molecules in "A" is
twice that in "B" & pressure in flask "A" is x times of that in "B".
Then value of x is


Answer: 8

Solution:
$V_{A} = 1\ lit,V_{B} = 2\ lit$
${(u_{avg})}_{A} = 2 \cdot {(u_{avg})}_{B}$
$\sqrt{\frac{8RT_{A}}{\pi M}} = 2 \cdot \sqrt{\frac{8RT_{B}}{\pi M}}$
$\frac{T_{A}}{T_{B}} = \frac{4}{1}$
$P_{A} = \frac{n_{A} \cdot R \cdot T_{p}}{V_{A}} \cdot P_{B} = \frac{n_{B} \cdot R \cdot T_{B}}{V_{B}}$
$\frac{P_{A}}{P_{B}} = \frac{T_{A} \cdot V_{B}}{V_{A} \cdot T_{B}} = \frac{4}{1} \times \frac{2}{1} = 8$
Subject: Chemistry — Coordination Compounds — General introduction of complex salts and definitions to be
Difficulty: Moderate

Question: The donor sites of (EDTA)4- are ?

1) O atoms only
2) N atoms only
3) Two N atoms and four O atoms
4) Three N atoms and three O atoms

Correct option: 3

Solution:
It attaches to the central metal ion through four carboxylate
group oxygen atoms and the two amine nitrogen.
Subject: Chemistry — Chemical Kinetics — Complication in 1^stOrder Reaction
Difficulty: Tough

Question: The substance undergoes first order decomposition. The
decomposition follows two parallel first order reactions as:
[IMAGE] K1 = 1.26 × 10-4 sec-1 and K2 = 3.8 × 10-5 sec-1
The percentage distribution of B and C

1) 80 B and 20 C
2) 76.83 B and 23.17 C
3) 90 B and 10 C
4) 60 B and 40 C

Correct option: 2

Solution:
$\%\ of\ B = \frac{k_{1} \times 100}{k_{1} + k_{2}} = \frac{1.26 \times 10^{- 4} \times 100}{12.6 \times 10^{- 5} + 3.8 \times 10^{- 5}} = 76.83\%$
$\%\ of\ C = \frac{k_{2} \times 100}{k_{1} + k_{2}} = \frac{3.8 \times 10^{- 5} \times 100}{12.6 \times 10^{- 5} + 3.8 \times 10^{- 5}} = 23.17\%$
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: (CH_3)_3CMgCl on reaction with D_2O produces
(CH_3)_3CMgCl, D_2O

1) (CH_3)_3CD
2) (CH_3)_3OD
3) (CD_3)_3CD
4) (CD_3)_3OD

Correct option: 1

Solution:
Subject: Chemistry — Organic Chemistry — Organic compounds containing Nitrogen
Difficulty: Moderate

Question: The maximum number of NO_2 groups that can be introduced by
nitration in benzene is usually


Answer: 3

Solution:
[IMAGE] 3- nitro group can be introduced.
Subject: Chemistry — Inorganic Chemistry — Periodic properties
Difficulty: Tough

Question: Which of the following does not represent the correct order of
the property indicated

1) $Sc^{3 +} > Cr^{3 +} > Fe^{3 +} > Mn^{3 +}$ionic radii
2) $Sc < Ti < C < Mn$ Density
3) $Mn^{2 +} > Ni^{2 +} < CO^{2 +} < Fe^{2 +}$ionic radii
4) $FeO < CaO > MnO > CuO$Basic nature

Correct option: 1

Solution:
$Sc^{3 +} > Cr^{3 +} > Fe^{3 +} > Mn^{3 +}$the correct order
is${Cr}^{+ 3} > {Mn}^{+ 3} > {Fe}^{+ 3} > {Sc}^{+ 3}$
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: The quantum numbers of for the electron spin
represent

1) Rotation of the electron in clockwise and anticlockwise direction
respectively
2) Rotation of the electron in anticlockwise and clockwise direction
respectively
3) Magnetic moment of the electron pointing up and down respectively
4) Two quantum mechanical spin states which have no classical
analogue.

Correct option: 4

Solution:
Spin quantum numbers are not solution of Schrodinger's wave
equation. It is a an arbitrary number which has no physical meaning.
Subject: Chemistry — Amines — Chemical Reactions of Amines
Difficulty: Moderate

Question: ${CH}_{3}{CH}_{2}{CH}_{2}CN + 2H_{2}\overset{Pd}{\longrightarrow}$
Which of the following compound is formed in the above reaction?

1) ${CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$
2) ${CH}_{3}{CH}_{2}{CH}_{2}{NH}_{2}$
3) ${CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$
4) None of the above

Correct option: 2

Solution:
Alkyl nitriles are reduced using a metal like palladium,
platinum or nickel as a catalyst.
So,
${CH}_{3}{CH}_{2}{CH}_{2}CN + 2H_{2}\overset{Pd}{\longrightarrow}{CH}_{3}{CH}_{2}{CH}_{2}{CH}_{2}{NH}_{2}$
Subject: Chemistry — Chemical Bonding — Resonance and Bond order Calculation
Difficulty: Easy

Question: Among the species, which has the weakest carbon- oxygen bond

1) CO_2
2) CH_3COO^
3) CO
4) CO_3^2

Correct option: 4

Solution:
(1) CO_2 = 2
(2) CH_3COO^-= 1.5
(3) CO = 3
(4) CO_3^2- = 1.33
Subject: Chemistry — Coordination Compounds — Valence Bond Theory + Crystal Field Theory (Part-II)
Difficulty: Moderate

Question: The number of unpaired electrons in d6, low spin, octahedral
complex is

1) 4
2) 2
3) 1
4) 0

Correct option: 4

Solution:
In d6, octahedral complex all electron will be
paired because of higher CFSE.
Subject: Chemistry — Physical Chemistry — Real Gases
Difficulty: Moderate

Question: Which is/are correct for real gases?

1) [IMAGE] constant at constant high temperature
2) [IMAGE] constant at constant low temperature
3) [IMAGE] at high temperature

Correct option: 1

Solution:
Low P and high temperature gas behaves as an ideal gas.
$\therefore$ PV= constant and $\frac{PV_{m}}{RT} = 1$
Subject: Chemistry — Physical Chemistry — Gaseous state
Difficulty: Moderate

Question: The compressibility factor of a gas is less than unity at 273 K
and $V_{m}$ = 22.4 L therefore,

1) P > 1 atm
2) P = 1 atm
3) P < 1 atm
4) P = 2atm

Correct option: 3

Solution:
$Z = \frac{\left( PV_{m} \right)_{\text{real }}}{\left( PV_{\text{m }} \right)_{\text{ideal }}} = \frac{P_{\text{real }} \times 22.4}{1 \times 22.4} < 1$
$P_{\text{real }} < 1\text{ atm.}$
Subject: Chemistry — Organic Chemistry — Hydrocarbon]
Difficulty: Easy]

Question: Which of the following compounds on hydrolysis gives acetylene


Correct option: 1

Solution:
Subject: Chemistry — Organic Chemistry — HALOALKANES & HALOARENES
Difficulty: Easy

Question: Benzene reacts with chlorine to form benzene hexachloride in
presence of

1) Nickel
2) AlCl_3
3) Bright Sunlight
4) Zinc

Correct option: 3

Solution:
Subject: Chemistry — Inorganic Chemistry — P-Block Element
Difficulty: Moderate

Question: Which of the following is in the increasing order of the ionic
character?

1) PbCl_4 < PbCl_2 < CaCl_2 < NaCl
2) PbCl_2 < PbCl_4 < CaCl_2 < NaCl
3) PbCl_2 < PbCl_4 < NaCl < CaCl_2
4) PbCl_4 < PbCl_2 < NaCl < CaCl_2

Correct option: 1

Solution:
PbCl_4 < PbCl_2 < CaCl_2 < NaCl is the increasing
order of ionic character.
Subject: Chemistry — Organic Chemistry — Alcohols, Phenols and Ethers
Difficulty: Tough

Question: [IMAGE] In the above reaction A, B and C are the following compounds

1) C_6 H_6, C_6 H_5 NO_2 and aniline
2) C_6 H_6, dinitrobenzene and metanitroaniline
3) Toluene, metanitrobenzene and metatoluedine
4) C_6 H_6, C_6 H_5 NO_2 and hydrazobenzene

Correct option: 4

Solution:
Subject: Chemistry — Chemical Kinetics — Integrated Rate law : Second Order & Pseudo first order
Difficulty: Moderate

Question: Graph between concentration of the product and time of the
reaction A→B is of the
Hence graph between $- \frac{d\lbrack A\rbrack}{dt}$ and time will be
of the type


Correct option: 3

Solution:
From given graph x = Kt
i.e. it is a zero order
Subject: Chemistry — Inorganic Chemistry — P-block nitrogen
Difficulty: Moderate

Question: Which of the following statement is wrong?

1) The stability of hydrides increase from NH3 to BiH3 in group 15 of
the periodic table
2) Nitrogen cannot form dp-pp bond.
3) Single N - N bond is weaker than the single P - P bond.
4) N2O4 has two resonance structure

Correct option: 1

Solution:
The stability of hydrides decreases from NH3 to BiH3 which can
be observed from their bond dissociation enthalpy. The correct order is
NH3 < PH3 < AsH3 < SbH3 < BiH
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: Which one of the following aqueous solutions will exhibit
highest boiling point?

1) $0.01M{Na}_{2}{SO}_{4}$
2) $0.01M{KNO}_{3}$
3) 0.015 M urea
4) 0.015 M glucose

Correct option: 1

Solution:
Elevation in boiling point is a colligative property which
depends upon the number of solute particles. Greater the number of
solute particles in a solution, higher the extent of elevation in
boiling point.
${Na}_{2}{SO}_{4} \rightarrow 2{Na}^{+} + {SO}_{4}^{2 -}$
Subject: Chemistry — Organic Chemistry — Aldehydes, Ketones & Carboxylic Acids
Difficulty: Moderate

Question: Which of the following compound gives a ketone with Grignard
reagent

1) Formaldehyde
2) Ethyl alcohol
3) Methyl cyanide
4) Methyl iodide

Correct option: 3

Solution:
Subject: Chemistry —  — 

Question: Which among the following detergents is nonionic in character ?

1) Sodium lauryl sulphate
2) Pentaerythrityl stearate
3) Cetyltrimethyl ammonium chloride
4) Sodium n-dodecyl benzene sulphonate20. Identify the product formed
in the reaction


Solution:
(2) Pentaerythrityl stearate
Subject: Chemistry — Ideal Gas — Eudiometry
Difficulty: Tough

Question: When 100 ml of a O2 - O3 mixture was passed through turpentine,
there was reduction of volume by 20 ml. If 100 ml of such a mixture is
heated, what will be the increase in volume? [Hint: O3 is absorbed by


Answer: 10

Solution:
In the mix., volume of O3 = 20 ml, Volume of O2 = 80 ml
on heating 2O3 → 3O2
20 ml O3 will give × 20 = 30 ml O2
total volume = 80 + 30 = 110 ml
increase in volume = 110 - 100 = 10 ml.
Subject: Chemistry — S-block — Miscellaneous (Hydrides, Carbides, Nitrates)
Difficulty: Moderate

Question: Total number of atom in one molecule or formula unit of 
is?

1) 7
2) 3
3) 4
4) 5

Correct option: 1

Solution:
X = CaH2, Y = Ca(OH)2, Z = H2
Subject: Chemistry — Organic Chemistry — Hydrocarbons
Difficulty: Moderate

Question: How many alkenes give 2-methylbutane on catalytic hydrogenation?


Answer: 3

Solution:
Subject: Chemistry — Organic Chemistry — Alcohols, Phenols and Ethers
Difficulty: Moderate

Question: Salicylaldehyde can be prepared from
(a) Phenol and chloroform
(b) Phenol, chloroform and sodium hydroxide
(c) Phenol, carbon tetrachloride and NaOH
(d) None of these


Correct option: 2

Solution:
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: Which of the following is correct statement?
(A) The ratio of e/m value for H^+ & He^+ is 1: 2.
(B) The ratio of e/m value for He^+ & Li^2+ is 7: 8.
(C) The ratio of e/m value for Li^2+ & Be^3+ is 9: 8.
(D) The ratio of e/m value for [IMAGE] &
[IMAGE] is 1: 2.
 ?

1) H^+ He^+ e/m 1: 2 
(2) He^+ Li^2+ e/m 7: 8
3) Li^2+ Be^3+ e/m 9: 8
4) 2: 1

Answer: 2

Solution:
Ratio of e/m value for H^+ & He^+ = 4: 1
Ratio of e/m value for He^+ & Li^2+ = 7: 8
Ratio of e/m value for Li^2+ & Be^3+= 16: 21
Ratio of e/m value for [IMAGE] & [IMAGE] = 2: 1
H^+ He^+ e/m = 4: 1
He^+ Li^2+ e/m = 7: 8
Li^2+ Be^3+ e/m = 16: 21
 
 = 2: 1
Subject: Chemistry — Physical Chemistry — Redox Reaction
Difficulty: Moderate

Question: Which one of the following reactions does not involve either
oxidation or reduction?


Correct option: 3

Solution:
[IMAGE] In this reaction oxidation and reduction are not involved because
there is no change in oxidation number.
Subject: Chemistry — Organic Chemistry — Hydrocarbons
Difficulty: Easy

Question: [IMAGE] Final product is


Correct option: 1

Solution:
Subject: Chemistry — Chemical Kinetics — Experimental Method to calculate order and rate law of
Difficulty: Tough

Question: The reaction A(s) → 2 B(g) + C(g) is first order. The pressure
after 20 min and after very long time are 150 mm Hg and 225 mm Hg. The
value of rate constant and pressure after 40 min are

1) 0.05 In 1.5 min-1,200 mm
2) 0.5 In 2 min-1,300 mm
3) 0.05 In 3 min-1, 300 mm
4) 0.05 In 3 min-1, 200 mm

Correct option: 4

Solution:
A(s) → 2 B(g) + C(g)
$K = \frac{1}{t}{In}\left( \frac{P_{\infty} - P_{0}}{P_{\infty} - P_{t}} \right){\ \ \ \ \ \ \ \ P}_{0} = 0\ \ \ {\ \ \ \ \ \ \ \ \ \ \ P}_{t} = 150\ {\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ P}_{\infty} = 225$
$\frac{1}{20}In\lbrack\frac{225}{225 - 150}\rbrack \Rightarrow \frac{1}{20}In(\frac{225}{75}) = 0.05ln3$
$\frac{1}{20}ln(\frac{225}{75}) = \frac{1}{40}\ln\left( \frac{225}{225 \times P_{40}} \right) \Rightarrow {(\frac{225}{75})}^{2} = \frac{225}{225 \times P_{40}}$
$\frac{225}{75 \times 75} = \frac{1}{225 - P_{40}} \Rightarrow P_{40} = 200$
Subject: Chemistry —  — 

Question: [IMAGE] X is

1) NO


Solution:
Subject: Chemistry — Physical Chemistry — Electrochemistry
Difficulty: Moderate

Question: The passage of current liberates [IMAGE] at cathode
and [IMAGE] at anode. The solution is

1) Copper chloride in water
2) NaCl in water
4) Water

Correct option: 2

Solution:
Since discharge potential of water is greater than that of
sodium so water is reduced at
cathode instead of [IMAGE] Cathode: [IMAGE] Anode: [IMAGE]
Subject: Chemistry —  — 

Question: When a metal sulphate is heated in dry test tube, the colour changes
from blue to white. Then metal sulphate may be

4) None of these


Solution:
[IMAGE] (due to no crystal field splitting)
Blue White
Subject: Chemistry — Physical Chemistry — Ideal Gases
Difficulty: Moderate

Question: Which one of the following statements regarding helium is
incorrect?

1) It is used to fill gas balloons instead of hydrogen because it is
lighter and non-inflammable
2) It is used as a cryogenic agent for carrying out experiments at
low temperatures
3) It is used to produce and sustain powerful superconducting magnets
4) It is used in gas-cooled nuclear reactors

Correct option: 1

Solution:
RNA and DNA has ribose and deoxyribose sugars, which differs in
absence of hydroxy group at $2^{nd\ }$ carbon