Grass-G/jee-main-questions huggingface dataset:
Subject: Chemistry —  — 

Question: When CrCl3 is reacts with excess NaOH solution then green solution
"A" is obatined?
[IMAGE] The oxidation number of chromium in the compound "C" is

1) +10
2) +6
3) +3
4) None of these


Solution:
CrCl_3 + NaOH → Cr(OH)_3↓ (OH)_4]
Green ppt. Green solution (A)
Na[Cr(OH)_4] + H_2O_2 + NaOH [IMAGE] Na_2CrO_4 +
H_2O
(A) (B) yellow solution
Na_2CrO_4 + H_2O_2
[IMAGE] CrO_5 + NaOH
(C) blue solution
Subject: Chemistry — Organic Chemistry — Environmental Chemistry
Difficulty: Easy

Question: Green chemistry means such reactions which

1) produce colour during reactions.
2) reduce the use and production of hazardous chemicals.
3) are related to the depletion of ozone layer.
4) study the reactions in plants.

Correct option: 2

Solution:
Green chemistry involves such reactions which reduce the use
and production of hazardous or toxic chemical to reduce pollution from
environment.
Subject: Chemistry — Physical Chemistry — Redox Reaction
Difficulty: Moderate

Question: When SO_2 is passed through acidic solution of potassium
dichromate, then chromium sulphate is formed. Change in valency of
chromium is.

1) +4 to +2
2) +5 to +3
3) +6 to +3
4) +7 to 2

Correct option: 3

Solution:
[IMAGE] In this reaction chromium change from + 6 to +3 oxidation state.
Subject: Chemistry —  — 

Question: are INTEGER ANSWER TYPE Questions. (The answer of each of
the questions is 2 digits)



Solution:
Subject: Chemistry — Surface Chemistry — Emulsion, Micelle and Gel
Difficulty: Easy

Question: At CMC, the surfactant molecules

1) Decomposes
2) Become completely soluble
3) Associate
4) Dissociate

Correct option: 3

Solution:
Association occurs at CMC so colloid is formed.
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Easy

Question: The number of monochloro derivatives of isohexane is (Only
structural isomers)
vkblks gsDlsu


Answer: 5

Solution:
Subject: Chemistry — Physical Chemistry — Redox Reaction
Difficulty: Moderate

Question: $H_{2}O_{2}$ reduces $K_{4}Fe(CN)_{6}$

1) In neutral solution
2) In acidic solution
3) In non-polar solvent
4) In alkaline solution

Correct option: 2

Solution:
When $H_{2}O_{2}$ reduces
with$K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack$. It is present in
acidic solution.
$2K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack + H_{2}SO_{4} + H_{2}O_{2} \rightarrow$
$2K_{3}\left\lbrack Fe(CN)_{6} \right\rbrack + K_{2}SO_{4} + 2H_{2}O$
Subject: Chemistry — Organic Chemistry — Organic Chemistry
Difficulty: Easy

Question: Number of structural isomers of C_4 H_10 O is


Answer: 7

Solution:
C_4H_10O have 7 isomers out of which 4 are alcohols and
3 are ethers.
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: A atom forms an ion by the loss of three electrons. The ion has
an electronic configuration The symbol of the ion is

1) Fe^3+
2) Ni3^+
3) Co^3+
4) Mn^+3

Correct option: 3

Solution:
Ni: 4s^2
Subject: Chemistry — Physical Chemistry — 
Difficulty: Easy

Question: A solution of urea contains 8.6 gm/liter (mol. wt. 60.0. It is
isotonic with a5 solution of a nonvolatile solute. The molecular weight
of the solute will be

1) 348.9
2) 34.89
3) 3489
4) 861.2

Correct option: 1

Solution:
For two non-electrolytic solution if isotonic, $C_{1} = C_{2}$
$\therefore\frac{8.6}{60 \times 1} = \frac{5 \times 1000}{m.wt. \times 100}\therefore m = 348.9$
Subject: Chemistry — Organic Chemistry — Organic Reaction mechanisms-I
Difficulty: Moderate

Question: An alcohol (A), 0.22 g of this alcohol librates 56 ml of CH4 at
STP on reaction with CH3MgBr. Write the molecular weight of alcohol
which satisfies these conditions.

1) 88 gm
2) 55 gm
3) 66 gm
4) 80 gm

Correct option: 1

Solution:
$ROH + {CH}_{3}MgX \rightarrow {CH}_{4} + ROMgX$
Let molecular mass of alcohol is M
$\frac{56}{22400} = \frac{0.22}{M}$
$M = \frac{22400 \times 0.22}{56} = 88gm$
Subject: Chemistry — P-block VA, VIA, VIIA elements — Oxides, Hydroxides, Peroxides, Oxyacids
Difficulty: Easy

Question: Which of the following oxides is amphoteric in nature?

1) N2O3
2) P4O6
3) Sb4O6
4) Bi2O3

Correct option: 3

Solution:
Sb4O6 reacts with NaOH forming arsenite as well as HCl forming
SbCl
Subject: Chemistry — Physical Chemistry — Ionic Equilibrium
Difficulty: Moderate

Question: For a solution of weak triprotic acid H_3A
[IMAGE],[A^3-] = 10^-17 M. Determine pH of
solution. Report your answer as if you find data insufficient.


Answer: 4

Solution:
${HA}^{2 -}\ \ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ \ \ \ \ \ \ H^{+} + \ \ \ \ \ \ \ \ \ A^{3 -}$; K_a3 = 10^-13
t = eq; 10^-8 10^-17
$\frac{\left\lbrack H^{+} \right\rbrack \times 10^{- 17}}{10^{- 8}} = 10^{- 13}$
So, = 10^-4 M $\therefore$ pH = 4
Subject: Chemistry — Inorganic Chemistry — P-block nitrogen
Difficulty: Moderate

Question: Which of the following properties is not shown by NO ?
NO dkSu&lk fuEu xq.k iznf'kZr ugha djrk

1) It is dimagnetic in gaseous state
2) It is a neutral oxide
3) It combines with oxygen to form nitrogen dioxide
4) It's bond order is 2.5
NO dkSu&lk fuEu xq.k iznf'kZr ugha djrk

Correct option: 1

Solution:
NO is paramagnetic in gaseous state.
Subject: Chemistry — Organic Chemistry — Aldehydes, Ketones & Carboxylic Acids
Difficulty: Moderate

Question: [IMAGE] is oxidised to [IMAGE] using

2) Selenium dioxide
4) All of these

Correct option: 3

Solution:
Subject: Chemistry — Physical Chemistry — Redox Reaction
Difficulty: Moderate

Question: When sodium metal is dissolved in liquid ammonia, blue colour
solution is formed. The blue colour is due to


Correct option: 2

Solution:
vated [IMAGE] ions
(2) Solvated electrons
(3) Solvated [IMAGE] ions
(4) Solvated protons
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Easy

Question: If the equilibrium constant of the reaction
$2HI(g) \rightleftharpoons H_{2}(g) + I_{2}(g)$ is 0.25, find the
equilibrium constant of the reaction.
$\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)$


Answer: 04

Solution:
$H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)$
$K^{'} = \frac{1}{0.25} = 4$
For reaction
$\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)$
$K^{''} = \sqrt{4}$
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: p-nitro toluene on further nitration gives


Correct option: 1

Solution:
Subject: Chemistry — Chemical Bonding — MOT
Difficulty: Tough

Question: The common features of the species N22-, O2 and NO- are

1) bond order three and isoelectronic.
2) bond order two and isoelectronic.
3) bond order three but not isoelectronic.
4) bond order two but not isoelectronic.

Correct option: 3

Solution:
$N_{2}^{2 -}:\sigma 1s^{2}\sigma^{\star}1s^{2}\ \sigma 2s^{2}\sigma^{\star}2s^{2}\ \pi 2p_{x\ }^{2}\ \pi 2p_{y}^{2}\ \sigma 2p_{z}^{2}\ \pi 2p_{x}^{1}\pi^{*}2p_{y}^{1}$
O2, NO-O2$= \frac{10 - 6}{2} = 2$
Subject: Chemistry — Physical Chemistry — 
Difficulty: Easy

Question: Which of the following statements are correct in context of
point defects in a crystal ?

1) AgCl has anion Frenkel defect and CaF2 has Schottky defects
2) AgCl has cation Frenkel defects and CaF2 has anion Frenkel defects
3) AgCl as well as CaF2 have anion Frenkel defects
4) AgCl as well as CaF2 has Schottky defects

Correct option: 2

Solution:
Since Ag+ (cation) is smaller than Cl- (anion) & hence cation
is present in voids.
In CaF2, is smaller.
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: Hydroloration of isobutylene followed by oxidative alkaline
hydrolysis gives
vkblks C;wfVyhu

1) 1-butanol
2) 2-butanol
3) Isobutyl alcohol vkblks C;wfVy,Ydksgy
4) (CH_3)_3C-OH

Correct option: 3

Solution:
Subject: Chemistry — Inorganic Chemistry — p-block elements
Difficulty: Moderate

Question: Colour is imported to glass by mixing

1) Synthetic dyes
2) Metal oxide
3) Oxides of non-metal
4) Coloured salt

Correct option: 2

Solution:
Metal oxides of some salts are fused with glass to imported
colour of glass.
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Moderate

Question: The value of Kp for the reaction,
$2H_{2}O(g) + 2{Cl}_{2}(g) \rightleftharpoons 4HCl(g) + O_{2}(g)$ is
0.03 atm at 427º C, when the partial pressure are expressed in
atmosphere then the value of KC for the same reaction is

1) 5.23 × 10^-4
2) 7.34 × 10^-4
3) 3.2 × 10^-3
4) 5.43 × 10^-5

Correct option: 1

Solution:
$2H_{2}O(g) + 2{Cl}_{2}(g) \rightleftharpoons 4HCl(g) + O_{2}(g)$
Kp = 0.03 T = 427oC = 700 K
Kp = KC(RT)1
$K_{C} = \frac{K_{P}}{RT} = \left\lbrack \frac{0.03}{0.082 \times 700} \right\rbrack$
KC = 5.23 × 10-4
Subject: Chemistry — Inorganic Chemistry — Metallurgy
Difficulty: Tough

Question: How many of following are correctly matched for electrolytic
reducing in molten state.
Ore Reagent / Process Remark
(a) Al2O3 AlF3 and CaF2 added Decrease M.P.
(b) MgCl2 KCl, CaCl2 Increase conductivity
(c) NaCl AlCl3 Decrease M.P.
(d) AlF3 Haroult process Al form at cathode
(e) MgBr2 Dow process Br2 from at anode
(f) Al2O3 conc. NaOH Leaching process
(g) Carnellite Dow process Directly applied to Carnellite crystals.
xfyr voLFkk esa oS|qr vi?kV~ fy, fdrus feyku lgh gS
(a) Al2O3 AlF3 rFkk CaF2 a xyukad fcUnq 
(b) MgCl2 KCl, CaCl2 fof'k"V pkydrk esa o`f)
(c) NaCl AlCl3 xyukad fcUnq 
(d) AlF3 gSjkWYV izØe dSFkksM ls Al
(e) MgBr2 izØe,uksM ls Br2
(f) Al2O3 lkUnz NaOH fu{kkyu izØe
(g) dkusZykbV izØe dkusZykbV fØLVy:i ls ykxw

1) 5 (a, e, d, b, f)
2) 5 (a, b, d, e, f)
3) 5 (b, a, f, e, d)
4) 5 (a, b, c, e, f)

Correct option: 2

Solution:
In NaCl metallurgy CaCl2 and KF are added. Carnellite firstly
converted into anhydrous MgCl2 then undergo process.
gy NaCl /kkrqdeZ eas CaCl2 o KF feyk;s tkrs gSaA dkusZykbV bl izfØ;k
Subject: Chemistry — Physical Chemistry — Gaseous state
Difficulty: Tough

Question: Value of Vander Waal's constants a and b for a gas depends upon

1) moles
2) volume
3) pressure
4) Gas taken

Correct option: 4

Solution:
For different gases value of van der Waal's constants a and b is
different.
Subject: Chemistry — Inorganic Chemistry — Chemical Bonding
Difficulty: Tough

Question: How many of the following molecules has 75 p-character ?
BeCl_2(g), BCl_3, SiCl_4, AsF_5, H_2S, PH_3


Answer: 2

Solution:
Sp^3Hybridized molecules are SiCl_4, H_2S
Subject: Chemistry — Inorganic Chemistry — S-block
Difficulty: Easy

Question: On dissolving moderate amount of sodium metal in liquid NH3 at
low temperature, which one of the following does not occur?

1) Blue coloured solution is obtained
2) Na+ ions are formed in the solution
3) Liquid NH3 becomes good conductor of electricity
4) Liquid NH3 remains diamagnetic.

Correct option: 4

Solution:
Na + (x + y) NH3 (moderate amount) → [Na(NH3)x]+ +
The blue colour solution is attributed to the solvated electrons.
The blue color solution is highly conducting due to the presence of
mainly solvated electrons and solvated Na+ ions.
The blue color solution is not diamagnetic but paramagnetic due to the
presence of solvated unpaired electrons.
Subject: Chemistry — Physical Chemistry — Chemical Bonding
Difficulty: Easy

Question: Example of super octet molecule is

1) SF6
2) PCl5
3) IF7 (4) All of these


Solution:
In SF6, PCl5 and IF7 the valence shell has 12, 10 and 14
electrons. As all contain more than 8 electrons in their valence shell
they are example of super octet molecules.
gy SF6, PCl5 IF7 12, 10 14 
 8
Subject: Chemistry — Salt Analysis — IIB Group
Difficulty: Moderate

Question: When white crystalline precipitate of magnesium ammonium
arsenate is treated with acidified silver nitrate solution, precipitate
of silver arsenate is formed. The colour of precipitate is

1) Yellow
2) Brownish red
3) White
4) Brownish black
tc vkflZusV

Correct option: 2

Solution:
$Mg\left( {NH}_{4} \right)_{2}{AsO}_{4} + 3{Ag}^{+} \longrightarrow {Ag}_{3}{AsO}_{4} \downarrow + {Mg}^{2 +} + {NH}_{4}^{+}$
(Brownish red)
gy
$Mg\left( {NH}_{4} \right)_{2}{AsO}_{4} + 3{Ag}^{+} \longrightarrow {Ag}_{3}{AsO}_{4} \downarrow + {Mg}^{2 +} + {NH}_{4}^{+}$
¼Hkwjk yky½
Subject: Chemistry — Organic Chemistry — Some Basic Principles and Techniques
Difficulty: Easy

Question: In which of the following delocalisation of anion is not
possible?


Correct option: 3

Solution:
Octet of nitrogen is complete.
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: The van't Hoff factor for 0.1 M Ba(NO3)2 solution is 2.74. The
degree of dissociation is


Answer: 87

Solution:
Van't Hoff factor, $i = 1 + (n - 1)\alpha$
Here n = 3
So, $2.74 + 1 + (3 - 1)\alpha$
So, $\alpha = 0.87\ i.e.\ 87\%$
okWUV gkWQ esa] $i = 1 + (n - 1)\alpha$;gk¡ n = 3
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Moderate

Question: Internal energy is

1) Partly potential and partly kinetic
2) Totally kinetic
3) Totally potential
4) None of these

Correct option: 1

Solution:
The exact value of internal energy is not known as it includes
all type of energies of molecules constituting the given mass of matter
such as translational, vibrational, and rotational. The kinetic &
potential energy of the nuclei & electron within the individual
molecules and the manner in which the molecule are linked together etc.
$E = E_{translational\ } + E_{vibrational\ } + E_{rotational\ }$
Thus, we can say that internal energy is partly potential and partly
kinetic.
Subject: Chemistry — Physical Chemistry — Mole Concept
Difficulty: Moderate

Question: Total number of H_2 molecules that can be obtained from all
hydrogen atoms of 10 formula units of CH_3COONH_4 is:
CH_3COONH_4 10 
H2

1) 35 N_A
2) 140
3) 140 N_A (4) 35

Correct option: 4

Solution:
10 formula units of CH_3COONH_4 = 10 × 7 H-atoms =
[IMAGE] H_2 molecules = 35 H_2 molecules.
CH_3COONH_4 ds 10 lw=k bdkbZ;k = 10 × 7 H -ijek.kq =
[IMAGE] H_2 v.kq = 35 H_2 v.kq
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Moderate

Question: $E^{0}$ of combustion of isobutylene is -X kJ mol^-1. The
value of $\Delta H^{\circ}$ is

1) $= \Delta E^{0}$
2) $> \Delta E^{\circ}$
3) = 0
4) $< \Delta E^{\circ}$

Correct option: 4

Solution:
$\left( {CH}_{3} \right)_{2}C = {CH}_{2}(g) + 6O_{2}(g) \rightarrow 4{CO}_{2}(g) + 4H_{2}O(l)$
$ng = 4 - 6 = - 2$ (i.e, negative) 
We know that $H = \Delta E + \Delta ngRT$
$= \Delta E - (\Delta ng)RT(\because\Delta ng = - ve)$
$\therefore\Delta H < \Delta E$
Subject: Chemistry — Inorganic Chemistry — D & F -Block Elements
Difficulty: Moderate

Question: Which of the following compound expected to be colorless


Correct option: 3

Solution:
[IMAGE] As all the electrons are paired. It is expected to be colorless.
Subject: Chemistry — Equivalent Concept — Eudiometric/Eudiometric Titration, Calculation of Available
Difficulty: Moderate

Question: What can be the maximum percentage of available chlorine
possible in a given bleaching powder sample (Take formula of bleaching
powder as CaOCl2) ?

1) 52.9
2) 55.9
3) 58
4) 60

Correct option: 2

Solution:
The weight of available Cl2 from the given sample of
bleaching powder on reaction with dil acids or CO2 is called available
chlorine.
Max. of available of ${Cl}_{2} = \frac{71}{127} \times 100 = 55.9\%$
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Tough

Question: Match the reactants given in Column-I with the reagent given in
Column-II for the preparation of cyclobutane
Column-I Column-II
(A) [IMAGE] (p) $\Delta$, NH2 - NH2 /KOH
(D) Cl - CH2 - (CH2)2 - CH2 - Cl (s) Electrolysis, H_2 s cukus Wye - I ds
-II ft,A
dkWye - I dkWye - II
(A) [IMAGE] (p) $\Delta$, NH2 - NH2 /KOH
(D) Cl - CH2 - (CH2)2 - CH2 - Cl (s) oS|qr vi?kVu, H_2/Ni

1) (A) - (p, r) (C) - (s); (D) - (q)
2) (A) - (p, q) (C) - (s); (D) - (q)
3) (A) - (p, r) (C) - (q); (D) - (s)
4) (A) - (q, r) (C) - (r); (D) - (p)

Correct option: 1

Solution:
Subject: Chemistry —  — 

Question: Asseration: A solution of surcose in water
is dextroratatory. But on hydrolysis in the presence of little
hydrochloric acid, it becomes levoratatory.
Reason: Surcose hydrolysis gives unequal amounts of glucose and
fructose. As a result
of this change in sign of rotation is observed.

1) If both accretion and reason are true and reason is the correct
explanation of assertion
2) If both accretion and reason are true but reason is not the
correct explanation of assertion
3) If assertion is true but reason is false.
4) If both assertion and reason are false.


Solution:
Subject: Chemistry — Inorganic Chemistry — Metallurgy
Difficulty: Tough

Question: In extraction of metal how many of the following ores
calcination process is involved.
(i) Dolomite (ii) Malachite (iii) Calcite (iv) Copperpyrities (v)
Sylvine
(vi) Cryolite (vii) Siderite (viii) Iron pyrite (ix) Argentite
fuEu es ls fdrus fuekZ.k es fuLrkiu izØe lfEefyr gksrk gS
(i) MksyksekbV (ii) esyssdkbV (iii) dsylkbV (iv) dkWijik;jkbV (v)
flyokbu


Answer: 4

Solution:
(i) Dolomite CaCO3.MgCO3 (ii) Malachite CuCO3.Cu(OH)2
(iii) Calcite ZnCO3 (iv) Copperpyrities CuFeS2
(v) Sylvine KCl (vi) Cryolite Na3AlF6
(vii) Siderite FeCO3 (viii) Iron pyrite FeS2
(ix) Argentite Ag2S
So, answer is (i), (ii), (iii) and (vii)
gy (i) MksyksekbV CaCO3.MgCO3 (ii) esyssdkbV CuCO3.Cu(OH)2
(iii) dsylkbV ZnCO3 (iv) dkWijik;jkbV CuFeS2
(v) flyokbu KCl (vi) Øk;ksykbV Na3AlF6
(vii) flMsjkbV FeCO3 (viii) FeS2
(ix) vtsZUVkbV Ag2S
Subject: Chemistry — Surface Chemistry — Adsorption
Difficulty: Easy

Question: Finely divided catalyst has greater surface area and has greater
catalytic activity than the compact solid. If a total surface area of
6291456 cm2 is required for adsorption in a catalyzed gaseous reaction,
then how many splits should be made to a cube of exactly 1 cm in length
to achieve required surface area.
(Given: One split of a cube gives eight cubes of same size)

1) 60
2) 80
3) 20
4) 22

Correct option: 3

Solution:
Total surface area of eight cubes.
Subject: Chemistry — Organic Chemistry — Structure Identification & POC
Difficulty: Moderate

Question: Molecular formula C3H6O2 have two structures A & B. Structure A
releases CO2 gas with NaHCO3 but B does not. Compound B is fruity
smelling liquid. Write the structures & IUPAC name of A and B.



Solution:
CH3CH2COOH (Propanoic acid) → (A)
CH3COOCH3 (Methyl acetate) → (B) or HCOOC2H5
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Tough

Question: A2(g) and B2(g) having partial pressures 60 mm of Hg & 42 mm of
Hg respectively, are present in a closed vessel. At equilibrium, partial
pressure of AB(g) is 28 mm of Hg. If all measurements are made under
similar condition, then calculate percentage of dissociation of AB (g).
(Round of answers to nearest integer).


Answer: 72

Solution:
$A_{2}(g) + B_{2}(g) \rightleftharpoons 2AB(g)$
at t=0 60 42 0
at eq. (60-x) (42-x) (2x)
(Partial pressures)
$\Rightarrow 2x = 28 \Rightarrow x = 14$
$K_{p} = \frac{\left( P_{AB} \right)^{2}}{\left( P_{A_{2}} \right)\left( P_{B_{2}} \right)} = \frac{(28)^{2}}{(46)(28)} = \frac{14}{23}$
For $\Delta n_{g} = 0;K_{p} = K_{C_{1}} = \frac{14}{23}$
Let degree of dissociation for AB is, then
$2AB(g) \rightleftharpoons A_{2}(g) + B_{2}(g)\left( K_{C_{2}} = \frac{1}{K_{C_{1}}} = \frac{23}{14} \right)$
1 0 0
at t = 0 (1 - x) x x
$\frac{\left( \frac{x}{2} \right)\left( \frac{x}{2} \right)}{(1 - x)^{2}} = \frac{23}{14} \rightarrow \alpha = 0.719$
Hence percentage of dissociatin $= 0.719 \times 100 = 72\%$
Subject: Chemistry — Organic Chemistry — Biomolecules
Difficulty: Moderate

Question: On heating glucose with Fehling's solution we get a precipitate
whose colour is

1) Yellow
2) Red
3) Black
4) White

Correct option: 2

Solution:
Glucose + Fehling solution $\rightarrow$ Gluconic acid
+$\begin{matrix}
{Cu}_{2}O \\
(Red\ ppt)
\end{matrix}$
Subject: Chemistry — Isomerism — Structural Isomerism
Difficulty: Moderate

Question: What is the relation between 3-Ethylpentane and 3-Methylhexane?

1) Chain isomers
(B) Position isomers
(C) Functional isomers
(D) Relation

Correct option: 1

Solution:
[IMAGE] Carbon skeleton is different in both compounds.
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: One mole of a symmetrical alkene on ozonolysis gives two moles
of an aldehyde having a molecular mass of 44 u. The alkene is n-butene.
Find n.,d lefer,sYdhu ds,d vkst+ksuh vi?kVu djus ij,d,sfYMgkbM ds
nks eksy izkIr gksrs gSa,sYdhu n A n


Answer: 2

Solution:
$C_{n}H_{2n}O = 44$
$C_{n}H_{2n} = 44 - 16$
$C_{n}H_{2n} = 28$
$n = 2$
${CH}_{3} - CH = CH - {CH}_{3}\overset{O_{3}/Zn}{\rightarrow}{CH}_{3} - CH = O$
Subject: Chemistry — Inorganic Chemistry — Metallurgy
Difficulty: Moderate

Question: Select correct statement regarding silver extraction /
purification process.

1) When the lead-silver alloy is rich in silver, lead is removed by
the cupellation process.
2) Lead is removed from argentiferous lead by Parke's process.
3) Zinc forms an alloy with lead, from which lead is separated by
distillation.
4) Zinc forms an alloy with silver, from which zinc is separated by
distillation.

Correct option: 4

Solution:
(1) Cupellation is used when lead is present in traces.
(2) In argentiferous lead the silver is removed by Parke's process
because silver has higher solubility in molten zinc than lead.
(3) Silver has higher solubility in molten zinc than lead and thus
forms zinc-silver alloy from which zinc can be distilled off leaving
behind the silver.
(4) Silver has higher solubility in molten zinc and thus forms
zinc-silver alloy from which zinc can be distilled off leaving behind
the silver.
Subject: Chemistry — Organic Chemistry — Hydrocarbon]
Difficulty: Moderate]

Question: Which of the following alkanes can be synthesized by the Wurtz
reaction in good yield ?]

1) (CH3)2CH - CH2 - CH (CH3)2]
2) (CH3)2CH - CH2 - CH2 - CH (CH3)2]
3) CH3 - CH2 - C(CH3)2CH2 - CH3]
4) (CH3)3C - CH2 - CH2 - CH3]

Correct option: 2

Solution:
Symmetrical alkane with even no. of carbon atoms can be
prepared by Wurtz reaction.,Ydsu ftlesa le cZu ijek.kq gks oqVZ~l vfHkfØ tk ldrk
Subject: Chemistry — Physical Chemistry — Electrochemistry
Difficulty: Moderate

Question: On passing 3 ampere of electricity for 50 minutes, 1.8 gram metal
deposits. The equivalent mass of metal is

1) 20.5
2) 25.8
3) 19.3
4) 30.7

Correct option: 3

Solution:
Subject: Chemistry — Inorganic Chemistry — Chemical Bonding
Difficulty: Moderate

Question: Which of the following are planar ?

1) XeF_2, SF_4,PCl_5
2) PCl_5, SF_6, IF_7
3) H_2O, XeF_4, ClF_3
4) ${SF}_{4},\ {ClF}_{3},l_{3}^{-}$

Correct option: 3

Solution:
Planar molecules:
${XeF}_{2},{ClF}_{3},H_{2}O,I_{3}^{-},{XeF}_{4}$.
SF_4- See - Saw shape
PCl_5- Trigonal bipyramidal
SF_6- Square bipyramidal
IF_7- Pentagonal bipyramidal
Subject: Chemistry — Organic Chemistry — Polymer
Difficulty: Moderate

Question: Which of the following polymers is synthesized using a
freeradical polymerization technique ?

1) Teflon
2) Terylene
3) Melamine polymer
4) Nylon 6,6

Correct option: 1

Solution:
The free radical polymerization of
tetrafluoroethylenesynthesizes Teflon. This polymerization is a type of
vinylpolymerization and proceeds via free radical mechanism.
[IMAGE] Thus, out of all the given polymers, Teflon is the only polymerwhich is
synthesized using free radical polymerization.
Subject: Chemistry — Physical Chemistry — Redox Reaction
Difficulty: Easy

Question: Which of the following is not a reducing agent?

1) NaNO_2
2) NaNO_3
3) HI
4) SnCl_3

Correct option: 2

Solution:
NaNO_2, SnCl_3 and HI have reducing and oxidizing properties
but NaNO_3 have only oxidizing property.
Subject: Chemistry — Inorganic Chemistry — D and F block element
Difficulty: Moderate

Question: The transition metal ions responsible for color in ruby and
emerald are, respectively

1) ${Cr}^{3 +}\ and\ {Co}^{3 +}$
2) ${Co}^{3 +}\ and\ {Cr}^{3 +}$
3) ${Co}^{3 +}\ and\ {Co}^{3}$
4) ${Cr}^{3 +}\ and\ {Cr}^{3 +}$

Correct option: 4

Solution:
The transition metal ions -4500 J is responsible for color in
ruby and emerald.
Aluminum oxide is also known as ruby. It consists of chromium ions.
Each aluminum and chromium ion is surrounded by six oxide ions in an
octahedral manner. Emerald is composed of beryllium aluminum silicate
in which chromium ions is surrounded by six silicate ions. Thus, in
both the cases, chromium is responsible for color.