Grass-G/jee-main-questions huggingface dataset:
Subject: Chemistry — Inorganic Chemistry — P-block Halogen
Difficulty: Moderate

Question: Concentrated hydrochloric acid when kept in open air sometimes
produces a cloud of white fumes. This is due to

1) strong affinity of HCl gas for moisture in air results in forming
of droplets of liquid solution which appears like a cloudy smoke.
2) strong affinity for water, conc. HCl pulls moisture of air
towards self. The moisture forms droplets of water and hence the
cloud.
3) conc. HCl emits strongly smelling HCl gas all the time.
4) oxygen in air reacts with emitted HCl gas to form a cloud of
chlorine gas.
lkUnz gkbMªksDyksfjd vEy dks tc
 lQsn vHkz izkIr gksrs gSaA;g bl dkj.k gksrk

Correct option: 4

Solution:
4HCI + O_2 → 2CI_2 + 2H_2O white fumes cloud ¼lQsn /kqze
vHkz ¼ckny½½A
Subject: Chemistry —  — 

Question: From the data provided, calculate the bond energy of a C -- H bond.
DH_f of C_2H_2(g) = 225 kJ/mole, DHsublimation of Cgraphite = 705 kJ
DH_f of H(g) = 165 kJ, C C bond energy = 815 kJ.

1) 350 kJ
2) 500 kJ
3) 242.5 kJ
4) 150 kJ


Solution:
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Moderate

Question: In which of the following reactions, increase in the volume at
constant temperature don't effect the number of moles of at equilibrium:
ij eksyks

1) 2NH3[IMAGE] N2 + 3H2
2) C (g) + (1/2) O2 (g)[IMAGE] CO (g)
3) H2 (g) + O2 (g)[IMAGE] H2O2 (g)
4) None of these. bu sbZ ugha

Correct option: 4

Solution:
If in the reaction the ratio of number of moles of reactants to
products in same i.e., 1: 1, then change in volume will not alter the
number of moles.
leku gksrk rc vk;ru ifjorZu
Subject: Chemistry — Organic Chemistry — Biomolecules
Difficulty: Easy

Question: Glucose gives silver mirror with Tollen's reagent. It shows the
presence of

1) An acidic group
2) An alcoholic group
3) A ketonic group
4) An aldehydic group


Solution:
Glucose + Tollen's reagent $\rightarrow$
Subject: Chemistry — P-block VA, VIA, VIIA elements — General facts about elements
Difficulty: Moderate

Question: Nitrogen is best obtained by the thermal decomposition of which
one of the following

1) NH4Cl
2) NH4NO3
3) AgNO3
4) NH4NO2

Correct option: 4

Solution:
NH4Cl gives NH3, NH4NO3 gives N2O and AgNO3 gives NO
Subject: Chemistry — Physical Chemistry — Ionic Equilibrium
Difficulty: Moderate

Question: In a saturated solution of Ag2SO4, silver ion concentration is 3
× 10-2 M. Its solubility product is ____ × 10-5: Assume no
reaction of cation/anion.
foys;rk xq.kuQy ____ × 10-5


Answer: 1.35

Solution:
Ag2CO3[IMAGE] 2Ag+ + CO32-
2s s
Here = 2 s = 2 × 10-4 M $\Rightarrow$ s = 1 × 10-4 M
$\therefore$ Ksp = 4s3 = 4(3 × 10-2)3 = 1.35 × 10-5
Subject: Chemistry — Organic Chemistry — Aromatic Compounds
Difficulty: Tough

Question: How many N atom are present in final product
[IMAGE] Final product.


Answer: 0

Solution:
Subject: Chemistry — Inorganic Chemistry — Chemical Bonding
Difficulty: Moderate

Question: Which of the following contains both electrovalent and covalent
bonds ?

1) CH4
2) H2O2
3) NH4Cl
4) none

Correct option: 3

Solution:
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: Benzene and naphthalene form an ideal solution at room
temperature. For this process, the true statement(s) is (are):
bl izØe

1) $\Delta G$ is positive $\Delta G$ A
3) $\Delta S_{surroundings\ } = 0$
4) $\Delta H = 0$

Correct option: 3

Solution:
$\Delta G = - \ ve\ $ $\Delta S_{systen\ } = + \ ve\ $ Always
for solution formation.
$\Delta S_{surr.\ } = 0$ No heat exchange between solution and
surrounding.
$\Delta H = 0$ For ideal solution.
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: Benzene and toluene form nearly ideal solutions. At 20ºC, the
vapour pressure of benzene is 75 torr and that of toluene is 22 torr.
The partial vapour pressure of benzene at 20 ºC for a solution
containing 78 g of benzene and 46 g of toluene in torr is:
csathu rFkk VkWyqbZu yxHkx cukrs gSaA 20ºC ij] casthu
g rFkk VkWyqbZu ds 46 g fy, 20º C ij csathu


Answer: 50

Solution:
$P_{B} = P_{B}^{0}XB$ $P_{B}^{0} = 75\ torr\ $
$X_{B} = \frac{78/78}{(78/78) + (46/92)} = \frac{1}{1 + 0.5} = \frac{1}{1.5}P_{B} = 75 \times \frac{1}{1.5} = 50\ torr.\ $
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: The radial probability distribution curve of an orbital of H has
4 local mixima. If orbital has 3 angular node then orbital will be

1) 7f
2) 8f
3) 7d
4) 8d

Correct option: 1

Solution:
$n\mathcal{- l} = 4$
$\mathcal{l =}3$
n = 7: so 7f
Subject: Chemistry —  — 

Question: (C) is: (C)



Solution:
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Tough

Question: What is the minimum mass of CaCO_3 (s), below which it
decomposes completely, required to establish equilibrium in a 6.50 litre
container for the reaction:
${CaCO}_{3}(s) \rightleftharpoons CaO(s) + {CO}_{2}(g)$; K_c = 0.05

1) 32.5 g
2) 24.6 g
3) 40.9 g
4) 8.0 g

Correct option: 1

Solution:
K_C = [CO_2] = 0.05 mole/litre
so moles of CO_2 = 6.50 × 0.05 moles = 0.3250 moles
${CaCO}_{3}(s) \rightleftharpoons CaO(s) + {CO}_{2}(g)$
1 mole of CO_2 = 1 mole of CaCO_3
0.3250 moles of CO_2 = 0.3250 moles of CaCO_3 = 0.3250 × 100 g of
CaCO_3 = 32.5 gm of CaCO_3
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: The inter metallic compound LiAg crystallizes in cubic lattice
in which both lithium and silver have coordination number of eight. The
crystal class is.

1) Simple cube
2) Body-centered cube
3) Face-centered cube
4) None of these

Correct option: 2

Solution:
In Body-centered cube an atom have coordination number of eight
Subject: Chemistry — Organic Chemistry — Organic Chemistry
Difficulty: Moderate

Question: In which of the following pairs of carbanion the first one is
more stable than second.


Correct option: 2

Solution:
Stability of carbanion µ -I effect, -m effect.
[IMAGE] (due to $p\pi - d\pi$ back bonding).
[IMAGE] (stability of anion, sp > sp2 > sp3)
[IMAGE] (stability order of carbanion inversely related to +I)
Subject: Chemistry — Halogen — Properties of Halogen containing compounds
Difficulty: Easy

Question: In which case formation of butane nitrile is possible

1) $C_{3}H_{7}Br + KCN$
2) $C_{4}H_{9}Br + KCN$
3) $C_{3}H_{7}OH + KCN$
4) $C_{4}H_{9}OH + KCN$

Correct option: 1

Solution:
$C_{3}H_{7}Br + KCN \rightarrow C_{3}H_{7}CN + KBr$
In IUPAC system the carbon of functional group also take in numbering.
So $C_{3}H_{7}CN$ is butane nitrile.
gy IUPAC iz.kkyh
Subject: Chemistry — P-block — Properties of Elements
Difficulty: Moderate

Question: Hot concentrated HNO3 converts graphite into

1) graphite oxide
2) benzene hexacarboxylic acid
3) both (A) and (B)
4) none of the above

Correct option: 2

Solution:
Graphite changes to Mellitic acid also called benzene
hexa-carboxylic acid with hot concentrated HNO
Subject: Chemistry —  — Voids
Difficulty: Moderate

Question: In a hypothetical solid C atoms form CCP lattice with A atoms
occupying all the Tetrahedral Voids and B atoms occupying all the
octahedral voids. A and B atoms are of the appropriate size such that
there is no distortion in the CCP lattice. Now if a plane is cut(as
shown) then type of voids and their numbers which are present at the
cross section would be.

1) O.V = 3, T.V. = 4
2) O.V. = 2, T.V. = 4
3) O.V. = 1, T.V. = 2
4) O.V. = 0, T.V. = 4

Correct option: 1

Solution:
[IMAGE] ® Octahedral void, at edge center &
body center.
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: S_1: Photoelectric effect can be explained on the basis of
wave nature of electromagnetic radiations. -
S_2: An orbital represented by n = 2,= 1 is dumb-bell shaped.
S_3: d_xy orbital has zero probability of finding electrons
along X-axis and Y-axis.
S_1: 
 
S_2: n = 2,= 1 (dumb-bell) 

S_3: X Y

1) FTF (2) FTT
3) TFT
4) TFF

Answer: 2

Solution:
S_1:Photoelectric effect can be explained on the basis of
particle nature of electromagnetic radiations.
S_2: n = 2, = 1 [IMAGE] 2p-orbital
[IMAGE] dumb-bell shaped.
S_3: d_xy orbital has its lobes directed at an angle of 45º
from X-axis and Y-axis. So, it has zero probability of finding
electrons along X-axis and Y-axis.
S_1: 
 
S_2: n = 2,= 1 [IMAGE] 2p-d{kd
[IMAGE] = (dumb-bell)
S_3: d_xy X- Y- 45º, X- Y
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Tough

Question: [IMAGE] P (major), P is:
[IMAGE] P (eq[;), P


Correct option: 3

Solution:
Subject: Chemistry — Inorganic Chemistry — S-block
Difficulty: Easy

Question: Select the correct statement with respect to alkali metals.

1) Melting point decrease with increasing atomic number.
2) Potassium is lighter than sodium.
3) Salts of Li to Cs impart characteristic colour to an oxidising
flame (of Bunsen burner).
4) All of these.

Correct option: 4

Solution:
(1) Down the group due to increase in size the strength of
metallic bond decreases and so, melting point decreases.
(2) Atomic volume of K is larger as compared to Na. Increase in atomic
mass does not over come the effect of increase atomic volume in case of
potassium.
(3) They have low ionisation energies because of their larger atomic
size. The heat from the flame excites the outer most orbital electron
to a higher energy level. When the excited electrons come back to the
ground state, there is emission of radiation in the visible region.
Hence, salts of Li to Cs impart characteristic colour to an oxidising
flame (of Bunsen burner).
Subject: Chemistry — Inorganic Chemistry — P-block
Difficulty: Moderate

Question: Aluminium is extracted by the electrolysis of

1) alumina
2) bauxite
3) molten cryolite.
4) alumina mixed with molten cryolite

Correct option: 4

Solution:
Alumina is mixed with cryolite, in molten state which make
alumina good conductor and lowers the fusion temperature also.
Subject: Chemistry — Physical Chemistry — Chemical and Ionic Equilibrium
Difficulty: Moderate

Question: The equilibrium concentration of X, Y and Y X_2 5lare
4,2 and 2 moles respectively for the equilibrium 2X + Y = YX_2.
The value of K_c. is

1) 0.625
2) 0.0625
3) 6.25
4) 0.00625

Correct option: 2

Solution:
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: The quantum numbers of four electrons (e1 to e4) are given below:
 -------------------------------------
 n l m s
 ------- ------- ------- ------ ----------
 e1 3 0 0 $$+ 
 e2 4 0 0 $$+ 
 e3 3 2 -2 $$- 
 e4 4 1 -1 $$+ 
 -------------------------------------
The correct order of decreasing energy of these electrons is

1) e4> e3 > e2 > e1
2) e2 > e3 > e4 > e1
3) e3 > e2 > e4 > e1
4) e1 > e4 > e2 > e3

Correct option: 1

Solution:
e1 = 3s
e2 = 4s
e3 = 3d
e4 = 4p
Subject: Chemistry —  — 

Question: are INTEGER ANSWER TYPE Questions.
(The answer of each of the questions is 2 digits integer)]



Solution:
Subject: Chemistry — Organic Chemistry — Some Basic Principles and Techniques
Difficulty: Moderate

Question: What is number of delocalised lone pairs in the following
compound?

1) 2
2) 3
3) 4
4) 5

Correct option: 1

Solution:
Bridge head N is not delocalized electron.
Subject: Chemistry — Physical Chemistry — Metallurgy
Difficulty: Moderate

Question: Extraction of copper by smelting uses silica as an additive tore
move

1) Cu_2 S
2) FeO
3) FeS
4) Cu_2 O

Correct option: 2

Solution:
The reaction involved in the smelting process is given by,
$Q = \frac{\pi r^{4}}{8\eta}\frac{\Delta P}{L}$
$\frac{P_{1}r_{1}^{4}}{l_{1}} = \frac{P_{2}r_{2}^{4}}{l_{2}}$
In this prosses
$\frac{P_{r_{1}}^{4}}{l_{1}} = \frac{4P_{1}r_{2}^{4}}{\frac{I_{1}}{4}}$
 forms the flux and $u_{initial\ } = \frac{5}{2}$ NRT 
$r_{2}^{4} = \frac{r_{1}^{4}}{16}$
$r_{2} = \frac{r_{1}}{2}$
forms the gangue which results in the formation of
$u_{final\ } = \frac{3}{2}(2nRT) + \frac{5}{2}(N - n)RT$
$= \frac{1}{2}nRT + \frac{5}{2}NRT$
Subject: Chemistry — Organic Chemistry — Biomolecules
Difficulty: Tough

Question: Observation of "Rhumann's purple" is a confirmatory test
forthe presence of

1) Reducing sugar
2) Cupric ion
3) Protein
4) Starch

Correct option: 3

Solution:
The Ninhydrin test helps in detecting the presence of 170Hz.
[IMAGE] The purple colored product is also known as "Rhumann'spurple"
Subject: Chemistry — Organic Chemistry — Chemistry in everyday life
Difficulty: Moderate

Question: Aspirin is chemically

1) Methyl salicylate
2) Ethyl salicylate
3) Acetyl salicylic acid
4) o-hydroxy benzoic acid

Correct option: 3

Solution:
Aspirin an antibiotic chemically Acetyl Salicylic acid
Subject: Chemistry — Physical Chemistry — 
Difficulty: Easy

Question: During depression of freezing point in a solution, the following
are in equilibrium

1) Liquid solvent-solid solvent
2) Liquid solvent-solid solute
3) Liquid solute-solid solute
4) Liquid solute-solid solvent
 fgekad ds voueu

Correct option: 1

Solution:
Only solvent molecule under go solidification. So liquid
solvent and solid solvent remain in equilibrium.
dsoy foyk;d v.kqvksa dk gh Bkslhdj.k gksrk gSA blfy, nzo foyk;d,oa Bksl
foyk;d lkE
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: [IMAGE] A and B respectively are

1) o-bromostyrene, benzoic acid
2) p-bromostryrene, benzaldehyde
3) m-bromostyrene, benzaldehyde
4) Styrene dibromide, benzoic acid.
[IMAGE] A

Correct option: 4

Solution:
Subject: Chemistry — IUPAC and Structural Isomerism — Functional Isomerism
Difficulty: Moderate

Question: A compound having straight chain of five carbon atoms has one
ketone group and two methyl groups on different-different carbon atoms.
The IUPAC name of the compound is

1) 2,4-Dimethyl-3-oxopentane
(2) 2,4-Dimethylpentan-3-one
3) 3,4-Dimethyl-2-oxopentane
4) 3,3-Dimethylpentan-2-one

Correct option: 2

Solution:
[IMAGE] 2,4-Dimethylpentan-3-one 3,4-Dimethylpentan-2-one
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: To prepare But-2-yne from 2, 2, 3, 3-Tetrachlorobutane, reagent
used is

1) Zinc dust / $\Delta$
2) Sodamide
3) Alc. KOH
4) aq. KOH
vfHkdeZd gksxk

Correct option: 1

Solution:
Subject: Chemistry —  — Simple Cubic Structure & BCC
Difficulty: Moderate

Question: Consider a Body Centered Cubic(bcc) arrangement, let de, dfd,
dbd be the distances between successive atoms located along the edge,
the face-diagonal, the body diagonal respectively in a unit cell.Their
order is given by

1) de< dfd < dbd
2) dfd > dbd > de
3) dfd> de> dbd
4) dbd > de> dfd,

Correct option: 3

Solution:
$d_{fd} = \sqrt{2}a$
$d_{bd} = \frac{\sqrt{3}a}{2}$
$\therefore d_{fd} > d_{e} > d_{bd}$