Grass-G/jee-main-questions huggingface dataset:
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Tough

Question: The degree of dissociation of SO_3 is a at equilibrium pressure
P_0.
Kp for $2{SO}_{3}(g) \rightleftharpoons 2{SO}_{2}(g) + O_{2}(g)$ is

1) $\left\lbrack \left( P_{0}\alpha^{3} \right)/2(1 - \alpha)^{3} \right\rbrack$
2) $\left\lbrack \left( P_{0}\alpha^{3} \right)/(2 + \alpha)(1 - \alpha)^{2} \right\rbrack$
3) $\left\lbrack \left( P_{0}\alpha^{2} \right)/2(1 - \alpha)^{2} \right\rbrack$
4) None of these

Correct option: 2

Solution:
2SO_3(g) $\rightleftharpoons$ 2SO_2 (g) + O_2(g)
t = 0 a 0 0
t =t a(1-α) aα $a\left( \frac{\alpha}{2} \right)$
Total mole at eq. $= a\left( 1 + \frac{\alpha}{2} \right)$
$P_{SO_{3}} = \left( \frac{1 - \alpha}{1 + (\alpha/2)} \right)P_{0} = \left\lbrack \frac{2(1 - \alpha)}{2 + \alpha} \right\rbrack \times P_{0}$
$P_{SO_{2}} = \left( \frac{\alpha}{1 + (\alpha/2)} \right)P_{0} = \left( \frac{2\alpha}{2 + \alpha} \right) \times P_{0}$
${PO}_{2} = \left( \frac{\frac{\alpha}{2}}{1 + \left( \frac{\alpha}{2} \right)} \right)P_{0}$
$K_{P} = \frac{\frac{4\alpha^{2}\left( P^{\circ} \right)^{2}}{(2 + \alpha)^{2}} \times \left( \frac{\alpha}{2 + \alpha} \right) \times P^{0}}{\frac{4(1 - \alpha)^{2}}{\lbrack 2 + \alpha\rbrack^{2}} \times \left( P_{0} \right)^{2}} = \left\lbrack \frac{\alpha^{3}p^{0}}{(2 + \alpha)(1 - \alpha)^{2}} \right\rbrack$
Subject: Chemistry — Physical Chemistry — Chemical Bonding
Difficulty: Moderate

Question: How many of these species are paramagnetic?
 ?


Answer: 04

Solution:
Subject: Chemistry — Organic Chemistry — Inductive effect
Difficulty: Easy

Question: Which of the following alkyl group has the maximum + I effect?

1) (CH3)2CH
2) (CH3)3C
3) CH3CH2
4) CH3

Correct option: 2

Solution:
Order of [IMAGE].
Subject: Chemistry — Physical Chemistry — Atomic Structure
Difficulty: Moderate

Question: Find minimum possible values of missing digits (X, Y, Z) in the
following set of quantum numbers and calculate sum of X, Y and Z.
 -----------------------------------------------
 n [IMAGE] $$|m|$$ s
 ------------ ----- ------------ ------- ----------
 Set (I) 5 2 x $$- 
 Set (II) Y 3 0 $$+ 
 Set (III) 3 Z 1 $$


Answer: 5

Solution:
X = 0, Y = 4, Z = 1
X + Y + Z = 0 + 4 + 1 = 5
Subject: Chemistry — Physical Chemistry — Real Gases
Difficulty: Moderate

Question: A gas obeys the equation of state P(V - b) = RT (The parameter
b is a constant). The slope for an isochore will be

1) Negative
2) Zero
3) R/(V - b)

Correct option: 3

Solution:
$P(V - b) = RT;P = \frac{RT}{(V - b)}$
$P = \left( \frac{R}{(V - b)} \right)T + 0$
Subject: Chemistry — Inorganic Chemistry — Chemical Bonding
Difficulty: Easy

Question: The correct sequence of increasing covalent character is
represented by

1) $LiCl < NaCl < BeCl_{2}$
2) ${BeCl}_{2} < NaCl < LiCl$
3) $NaCl < LiCl < {BeCl}_{2}$
4) ${BeCl}_{2} < LiCl < NaCl$

Correct option: 3

Solution:
Order of polarising power$Be^{+ +} > Li^{+} > Na^{+}$Hence
order of covalent character
${BeCl}_{2} > LiCl > NaCl$
Subject: Chemistry —  — 

Question: In the reaction shown below, the major product(s) formed is/are



Solution:
[IMAGE] since [IMAGE] is more basic.
The resulting amide will fail to react further. Had it been possible,
imied formation would have occured at both the sites.
Subject: Chemistry — Organic Chemistry — HALOALKANES & HALOARENES
Difficulty: Moderate

Question: The compound formed on heating chlorobenzene with chloral in the
presence of concentrated sulphuric acid, is

1) Freon
2) DDT
3) Gammexene
4) Hexachloroethane

Correct option: 2

Solution:
DDT is prepared by heating chlorobenzene and chloral with
concentrated sulphuric acid
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Tough

Question: The number of stereoisomers obtained by bromination of
trans-2-butene is:
Vªkal-2-C;wVhu


Answer: 1

Solution:
Subject: Chemistry — Surface Chemistry — Adsorption
Difficulty: Moderate

Question: 3 gram of activated charcoal was added to 50 mL of acetic acid
solution (0.06N) in a flask. After an hour it was filtered and the
strength of the filtrate was found to be 0.042 N. The amount of acetic
acid adsorbed (per gram of charcoal) is


Answer: 18

Solution:
Initial mmoles of CH3COOH = 0.06 × 50
Final mmoles of CH3COOH = 0.042 × 50
Hence, mass of CH3COOH adsorbed per gram of charcoal
$= \frac{(0.06 - 0.042) \times 50 \times 10^{- 3} \times 60 \times 10^{3}}{3} = 18mg$
Subject: Chemistry — Chemical Bonding — VBT, Overlapping of orbital
Difficulty: Moderate

Question: Which of the following overlaps is z-axis to be the internuclear axis]?
(a) $2p_{y} + 2p_{y} \rightarrow \pi 2p_{y}$ (b)
$2p_{z} + 2p_{z} \rightarrow \sigma 2p_{z}$
(c) $2p_{x} + 2p_{x} \rightarrow \pi 2p_{x}$ (d)
$1s + 2p_{y} \rightarrow \pi(1s - 2p_{y})$

4) None of these

Correct option: 3

Solution:
Subject: Chemistry — Physical Chemistry — Some Basic Concepts of Chemistry
Difficulty: Moderate

Question: A bottle of H_3PO_4 solution contains 70 acid by mass. If the
density of the solution is 1.54 g cm^-3, the volume of the H_3PO_4
solution required to prepare 1 L of 1 M solution is

1) 91mL
2) 45mL
3) 30mL
4) 23mL

Correct option: 1

Solution:
70 W/W H_3PO_4
70g H_3PO_4 in 100g / cm^3
P = 1.5 g/ cm^3 M = $\frac{70}{98} \times \frac{1000}{100}$ × 1.54 = 11
11 × V = 1 × 1000
V = 90.9[IMAGE] 91
Subject: Chemistry — Organic Chemistry — Steric Inhibition of Resonance (SIR Effect)
Difficulty: Moderate

Question: Maximum extent of steric inhibition of resonance can be expected
in


Correct option: 3

Solution:
[IMAGE] go out of plane due to repulsion (SIR is
observe in ortho substituted aromatic ring).
Subject: Chemistry — Physical Chemistry — Some Basic Concepts of Chemistry
Difficulty: Moderate

Question: Suppose 40 w/w aqueous solution of glucose (C_6H_12O_6) and
20 w/w aqueous solution of urea(NH_2CONH_2) have equal molarity, then
which solution has higher density

1) Both have equal density
2) Glucose solution
3) Urea solution
4) Cannot be predicted

Correct option: 2

Solution:
Given: M_1 = M_2
$\frac{10d_{1}x_{1}}{M_{1}} = \frac{10d_{2}x_{2}}{M_{2}}$
$\therefore\frac{d_{1}}{d_{2}} = \frac{x_{2}}{x_{1}} \times \frac{M_{1}}{M_{2}} = \frac{20}{40} \times \frac{180}{60}\ \ \ \ \ \ \ = \frac{3}{2}$
Thus, d_1> d_2
Subject: Chemistry — Physical Chemistry — Equivalent Concept
Difficulty: Moderate

Question: The oxidation state of chromium in the final product formed by
the reaction between KI and acidified potassium dichromate solution is



Solution:
${\overset{+ 6}{{Cr}_{2}O_{7}}}^{2 -} + 14H^{+} + 6I \longrightarrow {Cr}^{+ 3}\ _{1}^{3} + 7H_{2}O + 3I_{2}$
Subject: Chemistry — Surface Chemistry — Coagulation, Protection And application of colloid
Difficulty: Easy

Question: For the coagulation of 200 mL of As2S3 solution, 10 mL of 1 M
NaCl is required. What is the coagulating value (number of milli moles
of solute needed for coagulation of 1 liter of solution) of NaCl.

1) 200
2) 100
3) 50
4) 25

Correct option: 3

Solution:
10 ml of 1 M NaCl contains NaCl = 10 × 1 = 10 milli mole
200 ml of As2S3 required NaCl for the coagulation = 10 milli mole
[IMAGE] 1000 ml of As2S3 required NaCl for the
coagulation = 10 × 1000/200 = 50 milli mole
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Tough

Question: One mole of an ideal gas is allowed to expand reversibly and
adiabatically from a temperature of[IMAGE]. If the work
done during the process is[IMAGE], then final temperature
of the gas is[IMAGE]

1) 100 K
2) 150 K
3) 195 K
4) 225 K

Correct option: 2

Solution:
Given number of moles = 1
Initial temperature [IMAGE] Work done by the system [IMAGE] It will be [IMAGE] because work is done by the system.
Heat capacity at constant volume [IMAGE] We know that work done
Subject: Chemistry — Physical Chemistry — Chemical and Ionic Equilibrium
Difficulty: Moderate

Question: What will be the sum of pH and pOH in an aqueous solution?

1) 7
2) pk_w
3) Zero
4) 1

Correct option: 2

Solution:
$MX_{2} = M^{+} + \frac{2X^{-}}{(25)^{2}};K_{m} = 4S^{3}
$
$S = \sqrt[3]{\frac{K_{ip}}{4}} = \sqrt[3]{\frac{1 \times 10^{- 11}}{4}} = 1.35 \times 10^{- 4}$
Subject: Chemistry — Organic Chemistry — IUPAC Nomenclature
Difficulty: Moderate

Question: Aspirin is known as

1) Acetyl salicylic acid
2) Phenyl salicylate
3) Acetyl salicylate
4) Methyl salicylic acid

Correct option: 1

Solution:
[IMAGE] Aspirin (Acetyl salicylic acid)
Subject: Chemistry — Coordination Compounds — Isomerism in Coordination compounds
Difficulty: Moderate

Question: The number of geometrical isomer of [Co(NH3)3(NO3)3] are

1) 0
2) 2
3) 3
4) 4

Correct option: 2

Solution:
[Co(NH3)3(NO3)3] exists in following to isomeric forms.
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Easy / Moderate/ Tough m

Question: For the reaction:
$C_{2}H_{5}OH(\mathcal{l}) + 3O_{2}(g) \longrightarrow 2{CO}_{2}(g) + 3H_{2}O(g)$
if
$\Delta U^{o} = - 1373kJ{mol}^{- 1}$ at 298 K. Calculate$\ \Delta H^{o}$



Solution:
$\Delta H^{o} = \Delta U^{o} + \Delta n_{g}RT$
$= - 1373 + 2 \times \frac{8.314 \times 298}{1000}$
$= - 1368\ kJ{\ mol}^{- 1}$
Subject: Chemistry — Organic Chemistry — Biomolecules
Difficulty: Moderate

Question: Starch is converted into maltose by the

1) Maltase
2) Invertase
3) Zymase
4) Diastase

Correct option: 4

Solution:
Diastase enzyme converts starch into maltose.
Subject: Chemistry —  — 

Question: Which of the following is an example of additional polymerization?

1) Proteins
2) Teflon
3) Nylon-66
4) Glyptal(Polyester)


Solution:
(2) Teflon
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: If 20 g of a solute was dissolved in 500 ml of water and osmotic
pressure of the solution was found to be 600 mm of Hg at 15ºC, then
molecular weight of the solute is

1) 1000
2) 1200
3) 1400
4) 1800

Correct option: 2

Solution:
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: But-1-ene may be converted to butane by reaction with:
C;wV-1-bZu

1) Zn - HCl
2) Sn - HCl
3) Zn - Hg
4) Pd / H

Correct option: 4

Solution:
Subject: Chemistry — Organic Chemistry — Aromatic compound
Difficulty: Moderate

Question: Nitrobenzene can be prepared from benzene by using a mixture of
conc. $HNO_{3}$ and conc. $H_{2}SO_{4}$.In the nitrating mixture,
$HNO_{3}$ acts as a

1) Base
2) Acid
3) Reducing agent
4) Catalyst

Correct option: 1

Solution:
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Moderate

Question: Heat of formation in the reaction[IMAGE] is
___________kcal


Answer: 22

Solution:
Subject: Chemistry — Chemical Bonding — Back bonding
Difficulty: Moderate

Question: For BF3 molecule which of the following is true?

1) B-atom is sp2 hybridized.
2) There is a pp-pp back bonding in this molecule.
3) Observed B-F bond length is found to be less than the expected
bond length.
4) All of these

Correct option: 4

Solution:
[IMAGE] Decrease in B-F bond length is due to delocalized
$p_{\pi}$-$p_{\pi}$ bonding between filled p-orbital of F atom and
vacant p-orbital of B atom.
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: Copper crystallises in fcc with a unit cell length of 361 pm.
What is the radius of copper atom?


Answer: 127

Solution:
In fcc unit cell 4r = $\sqrt{2}a$ [r = radius of Cu atom, a =
So $r = \frac{\sqrt{2}a}{4}$
$r = \frac{\sqrt{2} \times 361}{4} = 127pm$
Subject: Chemistry — Inorganic Chemistry — P-block Halogen
Difficulty: Easy

Question: The reaction, 3ClO- (aq) → ClO3- (aq) + 2Cl- (aq) is an
example of

1) Oxidation reaction
2) Reduction reaction
3) Disproportionation reaction
4) Decomposition reaction

Correct option: 3

Solution:
It is a type of disproportionation reaction because an ion is
oxidised as well as reduced in the reaction.
Subject: Chemistry — Inorganic Chemistry — Environmental Chemistry
Difficulty: Easy

Question: The BOD value of clean water is


Answer: 5

Solution:
Explanation: Biological oxygen demand (BOD) value is the amount
of oxygen needed to decompose the organic material present in the water.
For pure or clean water BOD value is < or = 5 ppm.
Subject: Chemistry — Physical Chemistry — Ionic Equilibrium
Difficulty: Moderate

Question: pH of a solution obtained by mixing equal volumes of 0.1 M
Triethyl amine (K_b = 6.4 × 10^-5) & $\frac{4}{45}$ M NH_4OH (K_b =
1.8 × 10^-5) will be

1) 11.3
2) 10.3
3) 12.3
4) 11.45

Correct option: 1

Solution:
$\left\lbrack {OH}^{-} \right\rbrack = \sqrt{\left( 0.1 \times 6.4 + \frac{4 \times 1.8}{45} \right) \times 10^{- 5}}$
= 0.002M $\therefore$ pH = 11.3
Subject: Chemistry —  — 

Question: has four choices

1) ,
2) ,
3) ,
4) out of which ONLY ONE is correct]


Solution:
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: How many chiral compounds are possible on monochlorination of 2-
methyl butane ?
2- esfFky C;wVsu


Answer: 4

Solution:
[IMAGE] Four monochloro derivatives are chiral.
Subject: Chemistry — Organic Chemistry — Amines
Difficulty: Moderate

Question: Fluorination of an aromatic ring is easily accomplished
bytreating a diazonium salt with HBF_4. Which of the following
conditions is correct about this reaction?

1) Only heat

Correct option: 1

Solution:
An aromatic ring undergoes fluorination reaction under
thefollowing reaction.
[IMAGE] Heat is necessary for the reaction to take place. Thus, the
firstcondition is correct for the given reaction.
Subject: Chemistry — Organic Chemistry — Organic Chemistry
Difficulty: Easy

Question: Among the following compounds (I-III) the correct order in
reaction with an electrophile reagent is.

1) II > III > I
2) III < I < II
3) I > II > III
4) I = II > III

Correct option: 3

Solution:
I > II > III
[IMAGE] Methoxy group is electron releasing it increases electron density of
benzene nucleus, while -NO_2 decreases electron density of
benzene.
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Easy

Question: The entropy changed involved in the conversion of 1 mole of
liquid water at 373 K to vapor at the same temperature will be


Correct option: 2

Solution:
Subject: Chemistry — Inorganic Chemistry — Periodic Properties
Difficulty: Moderate

Question: Electronic configuration of four elements A, B, C and D are
given below:
(A) 1s^22s^22p^6
(B) 1s^22s^22p^4 (C) 1s^22s^22p^63s^1
(D) 1s^22s^22p^5
Which of the following is the correct order of increasing tendency to
gain electron ?

1) A < C < B < D
2) A < B < C < D
3) D < B < C < A
4) D < A < B < C

Correct option: 1

Solution:
(A) Ne: 1s^22s^22p^6
(B) O: 1s^22s^22p^4
(C) Na: 1s^22s^22p^63s^1
(D) F: 1s^22s^22p^5
Subject: Chemistry —  — 

Question: A greenish yellow gas reacts with an alkali metal hydroxide to form
a halite which can be used in fire works and safety metals. The gas and
halite respectively are

4) None of these


Solution:
Subject: Chemistry —  — 

Question: Variation of resistance with increase in cell constant gives graph
of the type

4) Cell constant[IMAGE] Cell


Solution:
Subject: Chemistry — S-block — Carbonates, Bicarbonates
Difficulty: Moderate

Question: 2(Na2CO3. NaHCO3.
Which of the following is not product of this reaction?

1) Na2CO3
2) CO2
3) H2O
4) Na2O

Correct option: 4

Solution:
2(Na2CO3.NaHCO3.2H2O)[IMAGE] 3Na2CO3 + CO2 + 5H2O
(trona)
Subject: Chemistry — Organic Chemistry — Hydrocarbon
Difficulty: Moderate

Question: Write the major product of following reactions.

4) None of these

Correct option: 1

Solution:
Subject: Chemistry — Organic Chemistry — Some Basic Principles and Techniques
Difficulty: Tough

Question: Which of the following compound will not liberate CO_2 gas on
reaction with sodium bicarbonate ?

1) Picric acid
2) Aspirin
3) Salicylic acid
4) Carbolic acid

Correct option: 4

Solution:
(1) Picric
Subject: Chemistry — Organic Chemistry — Stereoisomerism
Difficulty: Moderate

Question: Sum of total no. of stereoisomers (A) and total no. of fractions
(B) for the compound [IMAGE] is


Answer: 06

Solution:
02+04=06
[IMAGE] Enantiomers Enantiomers
Subject: Chemistry — Physical Chemistry — Chemical Equilibrium
Difficulty: Moderate

Question: The equilibrium constant for the reaction,
SO3(g)[IMAGE] SO2(g) + $\frac{1}{2}$ O2(g)
is KC = 4.9 × 10-2. The value of KC for the reaction 2SO2(g) +
O2(g)[IMAGE] 2SO3(g) will be:
fuEu vfHkfØ;k] SO3(g)[IMAGE] SO2(g) + $\frac{1}{2}$ O2(g)
 fLFkjkad KC = 4.9 × 10-2
O2(g)[IMAGE] 2SO3(g)


Answer: 416

Solution:
SO3(g)[IMAGE] SO2(g) + O2(g)
$\frac{\left\lbrack {SO}_{2} \right\rbrack\left\lbrack O_{2} \right\rbrack^{\frac{1}{2}}}{\left\lbrack {SO}_{3} \right\rbrack}$
=K_C = 4.9 × 10^-2......(i)
SO3(g) + 1/25 O2(g)[IMAGE] SO3(g)......(ii)
$\frac{\left\lbrack {SO}_{3} \right\rbrack}{\left\lbrack {SO}_{2} \right\rbrack\left\lbrack O_{2} \right\rbrack^{1/2}} = K_{C}^{'} = \frac{1}{4.9 \times 10^{- 2}}$
For 2SO2(g) + O2(g)[IMAGE] 2SO3 (g)
$\frac{\left\lbrack {SO}_{3} \right\rbrack^{2}}{\left\lbrack {SO}_{2} \right\rbrack^{2}\left\lbrack O_{2} \right\rbrack} = K_{C}^{2} = \frac{1}{4.9 \times 4.9 \times 10^{- 4}} = \frac{10000}{24.01}$
= 416.49
Subject: Chemistry — Inorganic Chemistry — Periodic Properties
Difficulty: Moderate

Question: The electron gain enthalpy of a hypothetical element is -3
eV per atom. How much energy in kCal is released when 10 g of are
completely converted to A-
ions in gaseous state ?
(Take: 1 eV per atom = 23 kCal mol^-1, Molar mass of A = 30 g)



Solution:
23
No. of moles of A= 1/3 mol
Energy released= 1/3 X 3 X 23kCal = 23 kCal
Subject: Chemistry — Organic Chemistry — Chemistry in everyday life
Difficulty: Moderate

Question: Further growth of cancerous cells in the body is arrested by

1) Physiotherapy
2) Chemotherapy
3) Electrotherapy
4) Psychotherapy

Correct option: 2

Solution:
Paul Ehrlich, the father of chemotherapy defined it to injure or
destroy infection microorganism by the use of drugs without causing any
injury to the host.
Subject: Chemistry — Organic Chemistry — Organic Chemistry
Difficulty: Moderate

Question: The number of enantiomers of the compound


Answer: 4

Solution:
[IMAGE] Number of enantiomers = 2^n (n = asymmetric Carbon atom) = 2^2 =
Subject: Chemistry — Physical Chemistry — Thermodynamics
Difficulty: Moderate

Question: In the combustion of 2.0 gm of methane 25 kcal heat is
liberated; heat of combustion of methane would be
____________________ kcal


Answer: 200

Solution:
${CH}_{4} + 2O_{2} \rightarrow {CO}_{2} + 2H_{2}O$
$\ $Molecular weight of CH_4 = 12 + 4 = 16
$\therefore$ On the combustion of 2.0 gm of methane = 25.0 kcal
On the combustion of 16.0gm $= \frac{25 \times 16}{2}$ = 200 kcal.
Subject: Chemistry — Physical Chemistry — 
Difficulty: Moderate

Question: The vapour pressure of benzene at a certain temperature is 640
mm of Hg. A non-volatile and non-electrolyte solid weighing 2.175
g is added to 39.08 g of benzene. The vapour pressure of the
solution is 600 mm of Hg. What is the molecular weight of solid
substance?

1) 49.50
2) 59.6
3) 69.5
4) 79.8

Correct option: 3

Solution:
[IMAGE] m = 69.
Subject: Chemistry —  — 

Question: The cell: Sn(s) | Sn^2+ || Cu^+ | Cu
[IMAGE] is completely discharged.
What will be the value of



Solution:
Subject: Chemistry — Physical Chemistry — Ionic Equilibrium
Difficulty: Moderate

Question: If the solubility product of a salt MX is 3 × 10-10 at 0ºC,
determine _____ × 10-5 mol/L solubility.
fn 0ºC ij yo.k MX xq.kuQy 3 × 10-10 gS] rks _____ ×


Answer: 1.73

Solution:
Let the solubility of salt MX be x mol/L
ekuk fd yo.k MX x A
MX[IMAGE] M+ + X-
Ksp = x2 = 3 × 10-10
$\Rightarrow$ x = 1.73 × 10-5 mol/L