Dludora/DAIL-BIRD huggingface dataset:
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Tell the Id number of the business with the most number of violations. Id number for that business refers to business_id; the most number of violations refers to MAX(COUNT(business_id)); */
SELECT 
SELECT business_id FROM violations GROUP BY business_id ORDER BY COUNT(business_id) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Give the name of the business which met all the required standards during the unscheduled routine inspection on 2016/9/28. met all the required standards refers to score = 100; unscheduled routine inspection on 2016/9/28 refers to type = 'Routine - Unscheduled' where date = '2016-09-28'; */
SELECT 
SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = 100 AND T1.`date` = '2016-09-28' AND T1.type = 'Routine - Unscheduled'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which business had the most number of high risk violations? Give the name of the business. the most number of high risk violations refers to MAX(COUNT(business_id)) where risk_category = 'High'; */
SELECT 
SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' GROUP BY T2.name ORDER BY COUNT(T2.name) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many kinds of violations did "Stacks Restaurant" have on 2016/10/4? "Stacks Restaurant" is the name of the business; date = '2016-10-04'; */
SELECT 
SELECT COUNT(DISTINCT T1.violation_type_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Stacks Restaurant' AND T1.`date` = '2016-10-04'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Give the description of the moderate risk violation which "Chez Fayala, Inc." had on 2016/7/1. "Chez Fayala, Inc." is the name of the business; moderate risk violation refers to risk_category = 'Moderate Risk'; date = '2016-07-01'; */
SELECT 
SELECT T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Chez Fayala, Inc.' AND T1.`date` = '2016-07-01' AND T1.risk_category = 'Moderate Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which business had the lowest score for the unscheduled routine inspection on 2016/9/26? Give the name of the business. the lowest score for unscheduled routine inspection refers to type = 'Routine - Unscheduled' where MIN(score); date = '2016-09-26'; */
SELECT 
SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE score = ( SELECT MIN(score) FROM inspections WHERE `date` = '2016-09-26' AND type = 'Routine - Unscheduled' ) AND T1.`date` = '2016-09-26' AND T1.type = 'Routine - Unscheduled'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Provide the name of the business which had the most number of inspections because of complaint. the most number of inspections because of complaint refers to type = 'Complaint' where MAX(business_id); */
SELECT 
SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.type = 'Complaint' GROUP BY T2.name ORDER BY COUNT(T1.business_id) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many unscheduled routine inspections did "Soma Restaurant And Bar" have? "Soma Restaurant And Bar" is the name of the business; unscheduled routine inspections refer to type = 'Routine - Unscheduled'; */
SELECT 
SELECT COUNT(T1.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Soma Restaurant And Bar' AND T1.type = 'Routine - Unscheduled'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Give the address of the business with the most number of the low risk violations. the most number of the low risk violations refers to MAX(COUNT(business_id)) where risk_category = 'Low Risk' ; */
SELECT 
SELECT T2.address FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'Low Risk' GROUP BY T2.address ORDER BY COUNT(T1.business_id) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which business was the first one to get a low risk violation because of "Permit license or inspection report not posted"? Give the name of the business. low risk violation because of "Permit license or inspection report not posted" refers to risk_category = 'Low Risk' where description = 'Permit license or inspection report not posted'; business was the first one refers to name where MIN(date); */
SELECT 
SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.`date` = ( SELECT MIN(`date`) FROM violations WHERE risk_category = 'Low Risk' AND description = 'Permit license or inspection report not posted' ) AND T1.risk_category = 'Low Risk' AND T1.description = 'Permit license or inspection report not posted'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: For the business which got the most number of violations, how many inspections did it have? */
SELECT 
SELECT COUNT(T2.business_id) FROM violations AS T1 INNER JOIN inspections AS T2 ON T1.business_id = T2.business_id GROUP BY T1.business_id ORDER BY COUNT(T1.business_id) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: For the business whose business certificate number is 304977, how many violations did it have on 2013/10/7? date = '2013-10-07'; */
SELECT 
SELECT COUNT(T1.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.business_certificate = '304977' AND T1.`date` = '2013-10-07'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the average score for "Chairman Bao" in all its unscheduled routine inspections? DIVIDE(SUM(score where type = 'Routine - Unscheduled' and name = 'Chairman Bao'), COUNT(type = 'Routine - Unscheduled' where name = 'Chairman Bao')); */
SELECT 
SELECT CAST(SUM(CASE WHEN T2.name = 'Chairman Bao' THEN T1.score ELSE 0 END) AS REAL) / COUNT(CASE WHEN T1.type = 'Routine - Unscheduled' THEN T1.score ELSE 0 END) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What percentage of the violations for "Melody Lounge" are moderate risks? DIVIDE(COUNT(risk_category = 'Moderate Risk' where name = 'Melody Lounge'), COUNT(business_id where name = 'Melody Lounge')) as percentage; */
SELECT 
SELECT CAST(SUM(CASE WHEN T2.risk_category = 'Moderate Risk' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T2.business_id) FROM businesses AS T1 INNER JOIN violations AS T2 ON T1.business_id = T2.business_id WHERE T1.name = 'Melody Lounge'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many eateries are located in Hayward? eateries in Hayward refer city = 'HAYWARD'; */
SELECT 
SELECT COUNT(business_id) FROM businesses WHERE city = 'HAYWARD'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many establishments have an inspection score of no more than 50? establishments have the same meaning as businesses; inspection score of no more than 50 refers to score < 50; */
SELECT 
SELECT COUNT(DISTINCT business_id) FROM inspections WHERE score < 50
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many eateries applied in 2012? eateries applied in 2012 refer to business_id where application_date between '2012-01-01' and '2012-12-31'; */
SELECT 
SELECT COUNT(business_id) FROM businesses WHERE STRFTIME('%Y', application_date) = '2012'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many foodborne illness investigations were done in 2014? foodborne illness investigations refer to inspections where type = 'Foodborne Illness Investigation'; investigations in 2014 refers to date between '2014-01-01' and '2014-12-31'; */
SELECT 
SELECT COUNT(business_id) FROM inspections WHERE STRFTIME('%Y', `date`) = '2014' AND type = 'Foodborne Illness Investigation'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many owners have 5 or more establishments? 5 or more establishments COUNT(business_id) > = 5; */
SELECT 
SELECT COUNT(T1.owner_name) FROM ( SELECT owner_name FROM businesses GROUP BY owner_name HAVING COUNT(owner_name) > 5 ) T1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What are the names of the establishments that met all of the required standards in 2013? establishments have the same meaning as businesses; met all of the required standards refers to score = 100; year(date) = 2013 */
SELECT 
SELECT DISTINCT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2013' AND T1.score = 100
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: In 2016, which city has the highest number of establishments with the highest health and safety hazards? the highest health and safety hazards refer to risk_category = 'High Risk'; year(date) = 2016; establishments has the same meaning as businesses; */
SELECT 
SELECT T2.city FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2016' AND T1.risk_category = 'High Risk' GROUP BY T2.city ORDER BY COUNT(T2.city) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the name of the establishment with the lowest inspection score of all time? the lowest inspection score refers to MIN(score); */
SELECT 
SELECT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = ( SELECT MIN(score) FROM inspections )
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many high risks violations did the Tiramisu Kitchen violate? Tiramisu Kitchen is the name of the business; high risks violations refer to risk_category = 'High Risk'; */
SELECT 
SELECT COUNT(T1.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen' AND T1.risk_category = 'High Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many establishments with the tax code H24 have complaint inspections of 5 or more? establishments with the tax code H24 refer to business_id where tax_code = 'H24'; complaint inspections of 5 or more refer to inspections where type = 'Complaint' and COUNT(business_id) ≥ 5; */
SELECT 
SELECT COUNT(*) FROM ( SELECT T1.business_id FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.tax_code = 'H24' AND T1.type = 'Complaint' GROUP BY T1.business_id HAVING COUNT(T1.business_id) > 5 ) T3
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: In 2013, what are the names of the establishments with contaminated or adulterated food? establishments have the same meaning as businesses; contaminated or adulterated food refers to violations where description = 'Contaminated or adulterated food'; date = '2013'; */
SELECT 
SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2013' AND T1.description = 'Contaminated or adulterated food'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Among the establishments with a postal code of 94102, how many establishments have a score of 90 or more in 2015? establishment has the same meaning as business; score of 90 or more refers to score ≥ 90; year(date) = 2015; */
SELECT 
SELECT COUNT(DISTINCT T2.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id INNER JOIN inspections AS T3 ON T2.business_id = T3.business_id WHERE STRFTIME('%Y', T1.`date`) = '2015' AND T2.postal_code = '94102' AND T3.score > 90
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What are the names of the establishments that met all the required standards for 4 consecutive years? establishment has the same meaning as business; score of 90 or more refers to score ≥ 90; year(date) = 2015; ; met all required standards for 4 consecutive years refers to COUNT(year(date)) = 4 where score = 100; */
SELECT 
SELECT DISTINCT T4.name FROM ( SELECT T3.name, T3.years, row_number() OVER (PARTITION BY T3.name ORDER BY T3.years) AS rowNumber FROM ( SELECT DISTINCT name, STRFTIME('%Y', `date`) AS years FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = 100 ) AS T3 ) AS T4 GROUP BY T4.name, date(T4.years || '-01-01', '-' || (T4.rowNumber - 1) || ' years') HAVING COUNT(T4.years) = 4
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Between 2014 to 2016, what is the average inpsection score of the establishment owned by Yiu Tim Chan in 808 Pacific Ave, San Francisco? average inspection score refers to avg(score); establishment owned by Yiu Tim Chan refers to business_id where owner_name = 'Yiu Tim Chan'; Between 2014 to 2016 refers to year(date) between 2014 and 2016; address = '808 Pacific Ave'; city = 'San Francisco'; */
SELECT 
SELECT AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) BETWEEN '2014' AND '2016' AND T2.owner_name = 'Yiu Tim Chan' AND T2.address = '808 Pacific Ave' AND T2.city = 'San Francisco'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the average score of the establishments owned by the owner with the highest number of establishments? average score refers avg(score); owner with the highest number of establishments refers to owner_name where MAX(COUNT(business_id)); */
SELECT 
SELECT AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.owner_name ORDER BY COUNT(T2.business_id) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the name of the establishment with the highest number of low risk violations in 2014? establishment with the highest number of low risk violations refers to business_id where MAX(COUNT(risk_category = 'Low Risk')); year(date) = 2014; */
SELECT 
SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2014' AND T1.risk_category = 'Low Risk' GROUP BY T2.name ORDER BY COUNT(T2.business_id) DESC LIMIT 1