Dludora/DAIL-BIRD huggingface dataset:
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Among the incidents with the generic description of "BATTERY" in the IUCR classification, how many of them do not have arrests made? general description refers to primary_description; 'BATTERY' is the primary_description; do not have arrest made refers to arrest = 'FALSE' */
SELECT 
SELECT SUM(CASE WHEN T2.arrest = 'FALSE' THEN 1 ELSE 0 END) FROM IUCR AS T1 INNER JOIN Crime AS T2 ON T1.iucr_no = T2.iucr_no WHERE T1.primary_description = 'BATTERY'
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Please list the case numbers of all the crimes whose short description of the kind of crime is "Homicide 1st & 2nd Degree" in the FBI classification. "Homicide 1st & 2nd Degree" is the title */
SELECT 
SELECT T2.case_number FROM FBI_Code AS T1 INNER JOIN Crime AS T2 ON T1.fbi_code_no = T2.fbi_code_no WHERE T1.title = 'Homicide 1st & 2nd Degree'
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Among the incidents in January, 2018, how many of them were stated "against Property" in the FBI classification? in January 2018 refers to Substr(date, 1, 1) = '1' AND Substr(date, 5, 4) = '2018'; against property refers to crime_against = 'Property' */
SELECT 
SELECT SUM(CASE WHEN SUBSTR(T2.date, 5, 4) = '2018' THEN 1 ELSE 0 END) FROM FBI_Code AS T1 INNER JOIN Crime AS T2 ON T1.fbi_code_no = T2.fbi_code_no WHERE T1.crime_against = 'Property' AND SUBSTR(T2.date, 1, 1) = '1'
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: District commander Robert A. Rubio was responsible for how many incidents in January, 2018? in January 2018 refers to Substr(date, 1, 1) = '1' AND Substr(date, 5, 4) = '2018' */
SELECT 
SELECT SUM(CASE WHEN SUBSTR(T2.date, 5, 4) = '2018' THEN 1 ELSE 0 END) FROM District AS T1 INNER JOIN Crime AS T2 ON T1.district_no = T2.district_no WHERE T1.commander = 'Robert A. Rubio' AND SUBSTR(T2.date, 1, 1) = '1'
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Which district commander was responsible for more incidents in January, 2018, Robert A. Rubio or Glenn White? in January 2018 refers to Substr(date, 1, 1) = '1' AND Substr(date, 5, 4) = '2018'; 'Robert A. Rubio' and 'Glenn White' are both commander; responsible for more incident refers to Max(count(ward_no)) */
SELECT 
SELECT T1.commander FROM District AS T1 INNER JOIN Crime AS T2 ON T1.district_no = T2.district_no WHERE T1.commander IN ('Robert A. Rubio', 'Glenn White') AND SUBSTR(T2.date, 1, 1) = '1' AND SUBSTR(T2.date, 5, 4) = '2018' GROUP BY T1.commander
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Please list the blocks where all the incidents in the district commanded by Robert A. Rubio took place. "Robert A. Rubio" is the commander */
SELECT 
SELECT T2.block FROM District AS T1 INNER JOIN Crime AS T2 ON T1.district_no = T2.district_no WHERE T1.commander = 'Robert A. Rubio'
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: What is the average number of incidents per month in 2018 in the ward with the most population? in 2018 refers to date like '%2018%'; ward with most population refers to Max(Population); average number of incident per month refers to Divide(Count(ward_no), 12) */
SELECT 
SELECT COUNT(T1.ward_no) / 12 AS average FROM Ward AS T1 INNER JOIN Crime AS T2 ON T1.ward_no = T2.ward_no WHERE T2.date LIKE '%2018%' AND T1.Population = ( SELECT MAX(T1.Population) FROM Ward AS T1 INNER JOIN Crime AS T2 ON T1.ward_no = T2.ward_no WHERE T2.date LIKE '%2018%' )
/* Given the following database schema: */
CREATE TABLE Community_Area
(
    community_area_no   INTEGER
            primary key,
    community_area_name TEXT,
    side                TEXT,
    population          TEXT
)

CREATE TABLE District
(
    district_no   INTEGER
            primary key,
    district_name TEXT,
    address       TEXT,
    zip_code      INTEGER,
    commander     TEXT,
    email         TEXT,
    phone         TEXT,
    fax           TEXT,
    tty           TEXT,
    twitter       TEXT
)

CREATE TABLE FBI_Code
(
    fbi_code_no   TEXT
            primary key,
    title         TEXT,
    description   TEXT,
    crime_against TEXT
)

CREATE TABLE IUCR
(
    iucr_no               TEXT
            primary key,
    primary_description   TEXT,
    secondary_description TEXT,
    index_code            TEXT
)

CREATE TABLE Neighborhood
(
    neighborhood_name TEXT
            primary key,
    community_area_no INTEGER,
    foreign key (community_area_no) references Community_Area(community_area_no)
)

CREATE TABLE Ward
(
    ward_no                INTEGER
            primary key,
    alderman_first_name    TEXT,
    alderman_last_name     TEXT,
    alderman_name_suffix   TEXT,
    ward_office_address    TEXT,
    ward_office_zip        TEXT,
    ward_email             TEXT,
    ward_office_phone      TEXT,
    ward_office_fax        TEXT,
    city_hall_office_room  INTEGER,
    city_hall_office_phone TEXT,
    city_hall_office_fax   TEXT,
    Population             INTEGER
)

CREATE TABLE Crime
(
    report_no            INTEGER
            primary key,
    case_number          TEXT,
    date                 TEXT,
    block                TEXT,
    iucr_no              TEXT,
    location_description TEXT,
    arrest               TEXT,
    domestic             TEXT,
    beat                 INTEGER,
    district_no          INTEGER,
    ward_no              INTEGER,
    community_area_no    INTEGER,
    fbi_code_no          TEXT,
    latitude             TEXT,
    longitude            TEXT,
    foreign key (ward_no) references Ward(ward_no),
    foreign key (iucr_no) references IUCR(iucr_no),
    foreign key (district_no) references District(district_no),
    foreign key (community_area_no) references Community_Area(community_area_no),
    foreign key (fbi_code_no) references FBI_Code(fbi_code_no)
)

/* Answer the following: Among all the incidents with no arrest made, what is the percentage of them having a generic description of "BATTERY" in the IUCR classification? incident with no arrest made refers to arrest = 'FALSE'; general description refers to primary_description; "BATTERY" is the primary_description; percentage = Divide (Count(iucr_no where primary_description = 'BATTERY'), Count(iucr_no)) * 100 */
SELECT 
SELECT CAST(SUM(CASE WHEN T1.primary_description = 'BATTERY' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*)FROM IUCR AS T1 INNER JOIN Crime AS T2 ON T1.iucr_no = T2.iucr_no WHERE T2.arrest = 'FALSE'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many restaurants' owners are in California? restaurants' owners in California refer to owner_state = 'CA'; */
SELECT 
SELECT COUNT(owner_state) FROM businesses WHERE owner_state = 'CA'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many restaurants have met all requirements in the inspection? met all requirements in the inspection refers to score = 100; */
SELECT 
SELECT COUNT(score) FROM inspections WHERE score = 100
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Among the inspections carried out in 2016, how many of them are routine? inspections carried out in 2016 refer to YEAR(date) = 2016; routine inspections refer to type = 'Routine - Unscheduled'; */
SELECT 
SELECT COUNT(`date`) FROM inspections WHERE STRFTIME('%Y', `date`) = '2016' AND type = 'Routine - Unscheduled'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Please list the names of all the restaurants that have met all requirements in one inspection. met all requirements refers to inspections where score = 100; */
SELECT 
SELECT DISTINCT T2.name FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.score = 100
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Among the restaurants being inspected in 2016, how many of them are in San Francisco? inspected in 2016 refers to YEAR(date) = 2016; San Francisco refers to city in ('San Francisco', 'SF' ,'S.F.', 'SAN FRANCISCO'); */
SELECT 
SELECT COUNT(DISTINCT T2.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2016' AND T2.city IN ('San Francisco', 'SAN FRANCISCO', 'SF', 'S.F.')
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What was the type of inspection Tiramisu Kitchen had on 2014/1/14? Tiramisu Kitchen is the name of the business; inspection on 2014/1/14 refers to date = '2014-01-14'; */
SELECT 
SELECT T1.type FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.`date` = '2014-01-14' AND T2.name = 'Tiramisu Kitchen'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many low risk violations were found in the inspection on 2014/1/14 for Tiramisu Kitchen? Tiramisu Kitchen is the name of the business; inspection on 2014/1/14 refers to date = '2014-01-14'; low risk violations refer to risk_category = 'Low Risk'; */
SELECT 
SELECT COUNT(T1.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.`date` = '2014-01-14' AND T2.name = 'Tiramisu Kitchen' AND T1.risk_category = 'Low Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Please list the names of the restaurants that had a low risk violation in inspections in 2014. inspection in 2014 refers to year(date) = 2014; low risk violations refer to risk_category = 'Low Risk'; */
SELECT 
SELECT DISTINCT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE STRFTIME('%Y', T1.`date`) = '2014' AND T1.risk_category = 'Low Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the description of the low risk violation of Tiramisu Kitchen on 2014/1/14? Tiramisu Kitchen is the name of the business; 2014/1/14 refers to date = '2014-01-14'; low risk violations refer to risk_category = 'Low Risk'; */
SELECT 
SELECT T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.`date` = '2014-01-14' AND T2.name = 'Tiramisu Kitchen' AND T1.risk_category = 'Low Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Please list the descriptions of all the high risk violations of Tiramisu Kitchen. Tiramisu Kitchen is the name of the business; high risk violations refer to risk_category = 'High Risk'; */
SELECT 
SELECT DISTINCT T1.description FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' AND T2.name = 'Tiramisu Kitchen'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many routine inspections did Tiramisu Kitchen have? Tiramisu Kitchen is the name of the business; routine inspections refer to type = 'Routine - Unscheduled'; */
SELECT 
SELECT COUNT(T1.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.type = 'Routine - Unscheduled' AND T2.name = 'Tiramisu Kitchen'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Among the routine inspections of Tiramisu Kitchen, how many of them have a score of over 70? Tiramisu Kitchen is the name of the business; routine inspections refer to type = 'Routine - Unscheduled'; score of over 70 refers to score > 70; */
SELECT 
SELECT COUNT(T2.business_id) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen' AND T1.type = 'Routine - Unscheduled' AND T1.score > 70
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which restaurant had more low risk violation in inspections, Tiramisu Kitchen or OMNI S.F. Hotel - 2nd Floor Pantry? Tiramisu Kitchen and OMNI S.F. Hotel - 2nd Floor Pantry are names of the business; more low risk violations refer to MAX(COUNT(risk_category = 'Low Risk')); */
SELECT 
SELECT CASE WHEN SUM(CASE WHEN T2.name = 'OMNI S.F. Hotel - 2nd Floor Pantry' THEN 1 ELSE 0 END) > SUM(CASE WHEN T2.name = 'Tiramisu Kitchen' THEN 1 ELSE 0 END) THEN 'OMNI S.F. Hotel - 2nd Floor Pantry' ELSE 'Tiramisu Kitchen' END AS result FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'Low Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: How many high risk violations do the restaurants in San Francisco have in total? restaurants in San Francisco refer to business_id where city in ('San Francisco', 'SF', 'S.F.', 'SAN FRANCISCO'); high risk violations refer to risk_category = 'High Risk'; */
SELECT 
SELECT COUNT(T2.business_id) FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.city IN ('San Francisco', 'SF', 'S.F.', 'SAN FRANCISCO') AND T1.risk_category = 'High Risk'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which restaurant has the highest total number of high risk violations? the highest total number of high risk violations refer to MAX(COUNT(risk_category = 'High Risk')); */
SELECT 
SELECT T2.name FROM violations AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T1.risk_category = 'High Risk' GROUP BY T2.name ORDER BY COUNT(T2.name) DESC LIMIT 1
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: What is the average scores of Tiramisu Kitchen in all inspections? avg(score); */
SELECT 
SELECT AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id WHERE T2.name = 'Tiramisu Kitchen'
/* Given the following database schema: */
CREATE TABLE `businesses` (
  `business_id` INTEGER NOT NULL,
  `name` TEXT NOT NULL,
  `address` TEXT DEFAULT NULL,
  `city` TEXT DEFAULT NULL,
  `postal_code` TEXT DEFAULT NULL,
  `latitude` REAL DEFAULT NULL,
  `longitude` REAL DEFAULT NULL,
  `phone_number` INTEGER DEFAULT NULL,
  `tax_code` TEXT DEFAULT NULL,
  `business_certificate` INTEGER NOT NULL,
  `application_date` DATE DEFAULT NULL,
  `owner_name` TEXT NOT NULL,
  `owner_address` TEXT DEFAULT NULL,
  `owner_city` TEXT DEFAULT NULL,
  `owner_state` TEXT DEFAULT NULL,
  `owner_zip` TEXT DEFAULT NULL,
  PRIMARY KEY (`business_id`)
)

CREATE TABLE `inspections` (
  `business_id` INTEGER NOT NULL,
  `score` INTEGER DEFAULT NULL,
  `date` DATE NOT NULL,
  `type` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

CREATE TABLE `violations` (
  `business_id` INTEGER NOT NULL,
  `date` DATE NOT NULL,
  `violation_type_id` TEXT NOT NULL,
  `risk_category` TEXT NOT NULL,
  `description` TEXT NOT NULL,
  FOREIGN KEY (`business_id`) REFERENCES `businesses` (`business_id`)
)

/* Answer the following: Which business had the most number of inspections? Give the Id number for that business. the most number of inspections refers to MAX(COUNT(business_id)); Id number for that business refers to business_id; */
SELECT 
SELECT business_id FROM inspections GROUP BY business_id ORDER BY COUNT(business_id) DESC LIMIT 1