Question: Treat the four vertically arranged images on the left as “Process One,” and the four vertically arranged images on the right as “Process Two.” If a goldfish is placed into the beaker at the starting state of each process, and ignoring any toxicity of the dye, in which beaker would the goldfish obtain more dissolved oxygen?
A. In the beaker of “Process One”
B. In the beaker of “Process Two”
C. There is no significant difference in dissolved oxygen between the two beakers
D. The addition of dye would first deplete the dissolved oxygen in the beaker of “Process Two.”
Clues:
1. The images in the right column ("Process Two") show condensation (small water droplets) on the upper, outer surface of the beaker.
2. The images in the left column ("Process One") do not show any condensation on the beaker.
3. In "Process One", the pink dye diffuses slowly and tends to sink to the bottom of the beaker.
4. In "Process Two", the pink dye diffuses rapidly and turbulently, quickly mixing with the entire volume of water.
5. In the final frame of "Process One", the water is not uniformly mixed; a concentrated layer of red dye is at the bottom.
6. In the final frame of "Process Two", the water is uniformly mixed and has a consistent pink color throughout.
Answer: A
Category: Physics