CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main() {
    int n;
    int x;
    cin>>n;
    int arr[n];
    for(int i=0; i<n; i++){
        cin>>arr[i];
    }
    cin>>x;
    
    for(int i=n-1; i>=0; i--){
      cout<<arr[i]<<" ";
    }
    int sum=0;
    for(int i=0; i<n; i++){
        if(arr[i]>x){
            
            sum+=arr[i];
                   
        }
        
    }cout<<endl<<sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n, arr[100], x, sum=0;
    cin >> n;
    for(int i=0; i<n; i++){
        cin >> arr[i];
    }
    cin >> x;
    for(int i=n-1;i>=0; i--){
        cout<< arr[i]<<" ";
    }
    cout<< endl;
    for(int i=0; i<n; i++){
        if(arr[i]>x) sum+=arr[i];
    }
    cout<< sum<< endl;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int arr[n];
    for(int i=0;i<n;i++)cin>>arr[i];
    int x;
    cin>>x;
    for(int i=n-1;i>=0;i--)cout<<arr[i]<<" ";
    cout<<endl;
    int count=0;
    for(int i=0;i<n;i++)if(arr[i]>x)count=count+arr[i];
    cout<< count;
    
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;

int main() {
    int n; cin >> n;
    int A[100] = {};
    for(int i=0;i<n;i++) {
        cin >> A[i];
    }
    int X; cin >> X;
    for(int i=n-1;i>=0;--i) {
        cout << A[i] << " ";
    }
    cout << endl;
    int sum = 0;
    for(int i=0;i<n;i++) {
        if(A[i]>X) {
            sum = sum + A[i];
        }
    }
    cout << sum << endl;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std ;

int Sum(int arr[] , int n , int X){
    int sum = 0 ;
    for (int i=n-1 ; i>=0 ; i-- ){
        cout << arr[i] << " ";
        if (arr[i] > X){
            sum = sum +arr[i] ;
        }
    }
    cout << endl ;
    return sum;

}

int main(){
    int n;
    cin >> n;

    int arr[n] ;

    for (int i=0 ; i<n ; i++){
        cin >> arr[i] ;
    }

    int X ;
    cin >> X ;

    cout << Sum(arr , n , X)<< endl ;

    
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include <iostream>
using namespace std;





int N,n,x,sum=0;
int main(){
    cin>> N;
    int A[N]={0};
    for(int i=0; i<N; i++){
        cin>>n;
        A[i]=n;
    } 
    cin>>x;
    for (int i=N-1; i>=0; i--){
        cout<<A[i]<<" ";
    }
    cout<<endl;
    for (int i=0; i<N ;i++){
        if (A[i]>x){
            sum=sum+A[i];
        }
    }
    cout<<sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;

int main(){
    int n;
    cin>>n;
    int arr[n];
    for(int i=0; i<n; i++)
    {
        cin>>arr[i];
    }
    int num1;
    cin>>num1;
    int summation;
    for(int i=0; i<n; i++)
    {
        if (arr[i]>num1)
        summation+=arr[i];
    }

    for (int i=0; i<n; i++)
    {
        cout<<arr[n-1-i]<<" ";
    }
    cout<<endl;
    cout<<summation;
    return 0;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include <iostream>
using namespace std;

int main(){
    int n, x, sum=0; cin >>n;
    int arr[n];
    for (int &i: arr) cin >> i;
    cin >> x;
    for (int i=0; i<n; i++){
        cout << arr[n-i-1] << " ";
    }
    cout << endl;
    for (int i: arr){
        if (i > x) sum+=i;
    }
    cout << sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n,x,sum;
    cin>>n;
    int arr[n];
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    cin>>x;
    int i=0;
    while (i<n){
        if(arr[i]>x){
            sum=sum+arr[i];
        }
        i++;
    };
        
    
    for (int k=n-1;k>=0;k--){
        cout<<arr[k]<<" ";
    };
    cout<<" "<<endl;
    cout <<sum-2;
  
    }

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include <iostream>
using namespace std;

void swp(int& x, int& y) {
int tmp; tmp=x; x=y; y=tmp;
}
  int main(){
int sum = 0 , n , X ;
cin>>n;
int Arr[n];
for(int i =0;i<n;i++){
cin >> Arr[i];
    }
cin >> X;

for (int i =0; i<n/2; i++){
    swp ( Arr[i] , Arr [n-i-1] ) ;
}
for (int i=0;i<n;i++){
    cout<<Arr[i]<<" ";
    }
    cout<<endl; 
for (int i=0; i<n ; i++){
    if(Arr[i]> X){
        sum += Arr[i];
    }
}
cout << sum ;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;

int main(){
    int N;
    cin>>N;
    int arr[100];
    for(int i=0;i<N;++i){
        cin>>arr[i];
    }
    int X;
    cin>>X;

    for(int i=N-1;i>=0;--i){
        cout<<arr[i]<<" ";
    }
    cout<<endl;
    int sum=0;
    for(int i=0;i<N;++i){
        if(arr[i]>X) sum=sum+arr[i];
    }
    cout<<sum;

}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
 int n;
 int A[n];
 int x;
 cin>> n;
 for(int i=0;i<n;i++){
    cin>> A[i];
 }
cin>> x;
for (int i=(n-1);i>=0;i--){
    cout<< A[i]<< " ";
}
cout<< endl;
int sum=0;
for(int i=0; i<n;i++){
    if(A[i]>x){
        sum=sum+A[i];
    }
}
cout<< sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;

int main(){
    int n;
    cin >> n;
    int arr[n];
    for(int i=0;i<n;i++){
        cin >> arr[i];
    }
    int x;
    cin >> x;
    for(int i=n-1;i>=0;i--){
        cout << arr[i] << " ";
    }
    cout << endl;
    int sum = 0;
    for(int i=0;i<n;i++){
        if(arr[i]>x){
            sum+=arr[i];
        }
    }
    cout << sum;
    return 0;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
#include<vector>
using namespace std;
int main(){
    int n;cin>>n;
    vector<int> array;
    int a;
    for(int i=0;i<n;i++){
        cin>>a;
        array.push_back(a);
    }
    int k;cin>>k;
    int ans=0;
    for(int i=n-1;i>=0;i--){
        cout<<array[i]<<" ";
        if(array[i]>k){ans+=array[i];}
    }
    cout<<endl;
    cout<<ans;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
  using namespace std;
    int main()
      {
        int n;int sum=0;
        int X;
        cin>>n;
        int A[n];
        for(int i=0;i<n;i++)
          {
            cin>>A[i];
          }
        cin>>X;
        for(int i=0;i<n;i++)
          {
            if(X<A[i])
             {
                sum=sum+A[i];
             }
          }
        for(int i=n-1;i>=0;i--)
          {
            cout<<A[i]<<" ";
          }
        cout<<endl;
        cout<<sum;
       
      }

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
    int N;
    cin>>N;
    int arr[N];
    for(int i=0;i<N;i++){
        cin>>arr[i];
    }
    int k;
    cin>>k;
    for(int j=1;j<=N;j++){
        cout<<arr[N-j]<<" ";
    }
    cout<<endl;
    int result=0;
    for(int i=0;i<N;i++){
        if(arr[i]>k){
            result=result+arr[i];
        }
    }
    cout<<result;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main()
{
    int n;
    cin>>n;
    int arr[n];
    for(int i=0;i<n;i++)
    {
        cin>>arr[i];
    }
    int x;
    cin>>x;
    for(int j=n-1;j>=0;j--)
    {
        cout<<arr[j]<<" ";
    }
    cout<<"\n";
    int sum=0;
    for(int p=0;p<n;p++)
    {
        if(arr[p]>x) {
            sum=sum+arr[p];
        }
    }
    cout<<sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;

int main() {
    int N, X;
    cin >> N;
    int arr[N];
    for(int i = 0; i < N; i++) cin >> arr[i];
    cin >> X;

    int sum = 0;
    for(int i = N-1; i >= 0; i--) {
        cout << arr[i] << ' ';
        if(arr[i] > X) sum += arr[i];
    }
    cout << endl << sum;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
#include <vector>
using namespace std;
int main(){
int n;
cin>>n;
std::vector <int> a;
for (int i=0;i<n;i++){
    int y;
    cin>>y;
    a.push_back(y);
}
int x;
cin>>x;
int sum=0;
for (int i=0;i<n;i++){
    if (a[i]>x){
        sum+=a[i];
    }
}
for (auto i=a.end()-1;i>=a.begin();i--){
    cout<< *i<<" ";

}
cout<<endl<<sum;
    return 0;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program that performs the following operations:
1. Input:
   Accept an integer 'n' representing the size of an array.
   Accept 'n' integer elements and store them in the array.
   Accept another integer 'x'.

2. Reverse Printing:
   Print the array elements in reverse order separated by spaces

3. Sum Calculation:
   Calculate and display the sum of all elements greater than 'x'

### Input Format
n
A1 A2 A3 ... An
x

### Output Format
First line: elements of the array in reverse order
Second line: sum of all elements greater than 'x'

### Constraints
'1 ≤ n ≤ 1000'
'-10^6 ≤ A[i], x ≤ 10^6'

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n,x;
    cin>>n;
    int arr[n];
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    cin>>x;
    for(int i=n-1;i>=0;i--){
        cout<<arr[i]<<" ";
    }
    cout<<endl;
    int d=0;
    for(int i=0;i<n;i++){
        if(arr[i]>x){d=d+arr[i];}
    }
    cout<<d;
}

Grading criterion: Prints array/vector in reverse
Rating A: Correctly prints the array/vector in reverse order

Rating B: Some issue. 
Rating C: Major issue. 

Rating D: 0
Assigned grade: A