CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;

    int count(int n, int k){
        if(k=n+1 || k==0 || n==0){
            return 0;
        }
return count(n-1,k);
    }
    int main(){
        int n,k;
        cin>>n>>k;
cout<<count(n,k)<<endl;
return 0;
    }

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;

int bs(int n, int k){
    if(n>k){
        if(k==1) return n;
        else if(n==0) return 0;
        else if(n==1) return 1;
        else if(n==2 && k==2) return 0;
        else if(n==2 && k==0) return 1; 
        else if(n>2 && k>1){
            return (bs(n-1,k)+bs(n-2,k-1));
    }
    }
    else if(n==k && n==1) return 1;
    else return 0;

}

int main(){
    int n,k;
    cin>>n>>k;
    int res=bs(n,k);
    cout<<res;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include <iostream>
using namespace std;


int give(int n,int k){
  
   
    if(k>(n/2)+1){
        return 0;
        
    }

    else{
        return 1;
    }

     return give(n-1,k) + give(n-2,k-1);
    
    

   


    
}

int main(){
    int a,b;
    cin >> a >> b;

    cout << give(a,b);
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;
int fact(int n) {
     if(n < 3) return -1; 
     if(k > 1) return 1; 
     return n *fact(n-1);         
     int main() {
    int n;
    cin >> n;
    int n = fact(4);
    ans == 3 cout << "Not defined" : cout >> ans ;
  }
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include <iostream>
using namespace std;

int countbinary(int n, int k){
    if ((n+1)/2 < k) return 0;
    if (k==0) return 0;
    if (k==1) return n;
    if (n==0) return 0;
    if (n==1) return 1;

    return countbinary(n-1,k)+countbinary(n-2,k-1);

}

int main(){
    int n, k;
    cin >> n >> k;
    cout << countbinary(n, k);
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;

int Bin(int n, int k){

    if(k==0) return 1;

    if(k==1 and n==1) return 1;

    if(k==n) return 0;



    return Bin(n-1,k)+Bin(n-2,k-1);
}



int main(){

    int n,k;
    cin>>n>>k;

    cout<<Bin(n,k);

}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
main_program ();
{
    int a,b;
    cin >> a >> " " >> b;
    if ( a % 2 =0 && b % 2 = 0){
        cout << a + b /2  ;
    }
    else if ( ! a%2 =0 || ! b%2 =0){
        cout << a-b-1 ;
    }
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include <iostream>
using namespace std;

int possibleStrings(int n,int k)
{
    int count =0;
    if (k==0) return count=1;
    if(n==1&&k==1) return count =1;
    if (n==2&&k==1) return count=2;
    if (n<k) return count=0;
   
    count= possibleStrings(n-1,k) + possibleStrings(n-2,k-1);
    return count;

}
int main()
{
    int n, k;
    cin>>n>>k;
    cout << possibleStrings(n,k);
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using  namespace std;
int B(int n,int k){ 
    if(k<0)return 0;
   if(n==1 && (k==1 || k==0))return 1;
   return B(n-1,k)+B(n-2,k-1);
}
int main(){
    int n,k;
    cin>>n>>k;
    int res=B(n,k);
    cout<<res<<endl;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using name space std;
int abd(int& n,int& k){
    if(k==n,k==0){
        return 1;
        abd(n,k)=abd(n-1,k)+b(n-2,k-1)
    }
}
int main{
    int n;
    cin>>n;
    int k; cin>>k;
    string s;
    cin>>s;
    cout<<abd;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: B
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include <iostream>
using namespace std ;

int binarystrings(int n , int k){
    if(n<k){
        return 0 ;
    }
    if(n==k){
        return 0 ;
    }
    if(n==1){
        return 1 ;
    }
    if(k==1){
        return n ;
    }
    return binarystrings(n-1,k)+binarystrings(n-2,k-1) ;
}
int main(){
    int n , k ;
    cin >> n >> k ;
    cout << binarystrings(n,k) << endl ;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;

int B(int n, int k){
    if(n%2==0 && k>n/2) return 0;
    //if(n%2==0 && k==n/2) return 1;
    if(n%2!=0 && k>(n/2)+1) return 0;
    //if(n%2!=0 && k==(n/2)+1) return 1;
    if(k<0 || n<0 || k>n) return 0;
    if(k==0) return 1;
    if(n==1) return 1;
    if(n==2 && k==1) return 2;
    return B(n-1, k) + B(n-2, k-1);
}
int main(){
    int n, k;
    cin>>n>>k;
    cout<<B(n,k);
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: Write a C++ program to count the number of binary strings (strings containing only '0' and '1') of length 'n' that contain exactly 'k' pairs of consecutive 1s. You must deduce the logical stopping points (base cases) for your recursion by considering the physical constraints of binary strings. For example, consider what happens when 'k' is 0, what the maximum number of consecutive pairs could possibly be in a string of length 'n', or if it is physically possible to have 1 pair in a string of length 1.

Code Requirements:

1. Input:
Read two integers 'n' and 'k' from the user.

'n' is the length of the binary string.

'k' is the number of consecutive pairs of 1s required.

2. Recursive Function & Base Cases:
Define a recursive function Bin(int n, int k) that returns the number of valid binary strings. Do not use arbitrary or hardcoded base cases. You must logically deduce and implement the correct base cases based on the physical constraints described in the context above.

3. Recursive Relation:
The function must follow this specific recursive relationship:
Bin(n, k) = Bin(n-1, k) + Bin(n-2, k-1)

4. Function Call:
Call the recursive function from the main() function and print the result.

Student submission:
#include<iostream>
using namespace std;
int Combination(int n, int k){
    if(k==0 || k==n)
    return 1;
    else
    return Combination(n-1,k)+Combination(n-2,k-1);
}
int fac(int k){

if(k==1)
return 1;
else
return k*fac(k-1);
}
int main(){
    int n,k;
    cin>>n>>k;
    if(Combination(n,k)>fac(k)/2)
   cout<<Combination(n,k)-fac(k)/2<<endl;
   else
   cout<<"0"<<endl;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A