CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
#include<iostream>
#include<vector>

int now (int n;vector<int>jump;intp){
    int step
    if (p=n-1){
        return 1 ;
    }
    if (p=n-2){
        return 2;
    }
    step = now(n,jump,p+1);
    return step;
}
   

int main(){
    int n;
    cin>>n;
    vector<int> jumps(n);
    cin>>n;
    for(i=0,i<n,i++){
        cin>> jumps[i];
    }
    cout<<now(n,jump 0);
    
}

Grading criterion: Accumulating total path
Rating A: Correctly accumulates the total path at each recursion step

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
int rec(int a,int ar[],int copy,int i=0){
    if(a==0)
    return -1;
    int num=ar[i++];
    for(int i=1;i<=num;i++){
        if(i+a>=copy+2)
        return 0;
        return 1+rec(a-i,ar,copy,i);
    }
}
int main(){
    Memo obj;
    int n;
    cin>>n;
    int copy=n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    cout<<rec(n,jumps,copy);
}

Grading criterion: Accumulating total path
Rating A: Correctly accumulates the total path at each recursion step

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
int dispath(int jumps[],int n,int ways,int i){
    if(i==n){
        return 0;
    }
    if(i<n){
        for(int k=(i+1);k<(i+jumps[i]);k++){
        return dispath(jumps,n,ways+1,k);
        }
    }
    return ways+2;
}
int main(){
    int n;
    cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    cout<<dispath(jumps,n,0,0);
}

Grading criterion: Accumulating total path
Rating A: Correctly accumulates the total path at each recursion step

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

int main(){    
    int n;
    cin>>n;
    int jump[n];
    for(int i=0; i<n; i++){
        cin>>jump[i];
    }
    int count=0;
    for(int i=0; i<n; i++){
        for(int j=i; j<n; j++){
            if(i+jump[i]<(n-1-i)){
                count++;
            }
        }
    }
    cout<<count;
}

Grading criterion: Accumulating total path
Rating A: Correctly accumulates the total path at each recursion step

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int ways=0;
int calcways(int n, int jumps[]);
int n;
int main(){
    
    cin>>n;
    int jumps[n];
    cin>>jumps[n];
    for(int i=0;i<n;i++){
        int inp;
        cin>>inp;
        jumps[i]=inp;
    }
    
    cout<<calcways(n, jumps)-1;
  
    

    
}

int calcways(int m, int jumps[]){
    if (m==0){
        return ways;
    }
    for(int i=0;i<m;i++){
        if(m-1-(jumps[i])>=0){
            ways++;
            ways=ways+calcways(i+1, jumps);

        }
    }
    
        
    

}

Grading criterion: Accumulating total path
Rating A: Correctly accumulates the total path at each recursion step

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int numofways(int a);

int main(){
    int n;
    cin>>n
    int a[n];
    for(int i=0;i<n; i++)
    {
        cin>>a[i];
    }
    

}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int ways(int pos,int arr[],int n){
    if(pos==(n-1)) return 1;
    int total;
    for(int i=pos;i<=pos+arr[pos];i++){
        total+= ways(i,arr,n);
    }
    return total;


}
int main(){
    int n;
    cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    int Totalways;
    Totalways= ways(0,jumps,n);
    cout<<Totalways;

}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int main () {
    int n;
    cin >> n;
    int jumps[n];
    for(int i=0;i<n;i++)
     cin >> jumps[i];
     int d=0;
       for(int i=0;i<n;i++) {
       if(a[i]=n)
       d++;
     }
        for(int i=0;i<n;i++) {
            for(int j=1;)
        }

     

}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int f(int n, int i , int jumps[]){
    if(i=n-2){
        return 1;
    }
    int my;
    if(jumps[i] > n-1-i){
      my = (n-1-i)*(n-i)/2 ;
    }
    else my = jumps[i] ;
    return f(n,i,jumps) = f(n,i+1,jumps) +  my;
}
int main(){
    int n;
    cin >> n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin >> jumps[i];
    }
return f(n,0,jumps) ;
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int f(int a,int b[],int k,int n){
    int s=0;
       if(a==0 && k==1){
             return 1;
       }
       if(a==0 && k==0){
            return 0;
       }
       for(;a>0;a--){
        if(b[a]>=n-a){
         s=s+f(a-1,b,k,n);
        }
       }
       return s;
    }//not able to use the value of n in function.
int main(){
    int n,p;
    cin >> n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin >> jumps[i];
    }
    if(jumps[0]<n){
        p=0;
    }
    else{
        p=1;
    }
    f(n,jumps,p,n);
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
int TotalnoOfways(int P,arr[])
{
    
    int*ptr=arr;
    int k=0,s=0;
    int NoOfjumps;
    if(ptr==&arr[N-1]){
         k++;
    }
    NoOfjumps=s+1;
    u=NoOfjumps;
    for(int  u=0;u<s+arr[s];u++){
        while(ptr!=&arr[N-1]){
        ptr=&(arr[NoOfjumps]); 
        
     
    }
    ptr=&arr[s+1];
    k=k+TotalnoOfway(s-1);

}
}

int main(){
    int N;
    cin<<N;
    int Jumps[N];
    
    for(int j=0;j<N;j++)
    {
        cin<<Jumps[j];
    }
    cout<<TotalnoOfways(int N,Jumps[])<<endl;
    





}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B