CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,r,rev=0,a=n;
cin>>n;
while(n>0)
{
	r=n%10;

	rev=rev*10+r;
	n=n/10;}
cout<<rev;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
	int n,y,x,r;
	 cin>>n;
	x=1;
	y=0;
	 while(x!=0&&n>0){
		    	 r=n%10;
		     	x=n/10;
		     	y=y*10+r;
		     	n=x;
		    	}
           	cout<<y;
	}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{	int n,d,p=0;
	cin>>n;
	for(int m=n;m>0 ; m/=10)
	{	int d=m%10;
		p=p*10+d;
	}
	cout<<p;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main(){

int n;
cin>>n;
int m=0;
while(n){
m=10*m+n%10;
n=n/10;
}
cout<<m<<endl;
return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main()
{
int n;
cin>>n;
while(n>0){
if(n%10==0){n=n/10;}
if (n%10!=0){
cout<<(n%10);
n= (n-(n%10))/10;}
}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>

using namespace std;

int main() {

	int n;

	cin >> n;

	int nrev = 0, nc = n;

	int d = 0;

	while (nc > 0) {

		d++;
		nc /= 10;

	}

	for (int i = 0; i < d; i++) {

		nrev += (n % 10) * pow(10, d - i - 1);
		n /= 10;

	}

	cout << nrev;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
  using namespace std;
 int main(){
 int n,x,y;
 cin>>n;
  int a=n/1000;
  int b=(n/100)%10;
  int c=(n/10)%100 ;
  int d=n%10;
  cout<<d;
  if(c>0) cout<<c;
  if(b>0) cout<<b;
  if(a>0) cout<<a;







}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int y=1,i,n,m,x=10;
cin>>n;
m=n%10;

while((n/10)!=0){
y++;
}
for(i=1;i<y;i++){
x=x*10;
m=m*10+((m%x)/x)*10;
}
cout<<m;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <simplecpp>
main_program{
int n,m,i;
cin>>n;
i=0;
bool flag1;
m=n;
while(n>0){
flag1 = m%10==i;
if(!flag1) break;
m=m/10;}

n=m;
for(i=n;i>0;i=i/10){
int a;
a= n%10;
cout<<a;
n=n/10;};
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>

using namespace std;

int main()
{

 int n,m=0;
 cin>>n;

 int d;

 while(n>0)
 {
   d=n%10;
   m=m*10 +d;
   n=n/10;
 }

 cout<<m;
 return 0;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main(){
 int n,reverse=0,rem;
cin>>n;
while(n!=0){
     rem=n%10;
     reverse=reverse*10+rem;
     n/=10;}
     cout<< reverse<< endl;
     return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
	int a,b=0;
	cin >> a;
	while(a!=0){
		b=b*10 + (a%10);
		a=a/10;
	}
	cout << b;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
int n,m=0,d=0,p=1;
cin>>n;
for(int digits=0;n/(int)(pow(10,digits))>=1;digits++){d=digits;};
while(p<d+1){
m=n/(int)pow(10,d);
m=m+(n/(int)pow(10,d-p)*10-(n/(int)pow(10,d-p+1))*(int)pow(10,p));
p++;
}
cout<<m;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
while(n%10==0){n=n/10;}
int m=0;
while(n>0){
int k;
k=n%10;
m=m*10+k;
n=n/10;}
cout<<m;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
	int n,d=1,r=1,dig;
	cin>>n;
	if(n==1) cout<<d;
	for(int i=1;d<=n;i++){
			d=pow(10,i);
			r=pow(10,i-1);
			dig=(n%d-n%r)/(pow(10,i-1));
			if(dig!=0)cout<< dig;
			}
	
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m,k;
int r; cin>>n;r=n%10;
if(r!=0){
while(n>0){
r=n%10;
n=n/10;
cout<<r;
}
}
if(r==0){
while(r==0){
m=n=n/10;
k=r=n%10;}
while(m>0){
k=m%10;
m=m/10;
cout<<k;}


}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main() {
	int n; cin >> n;
	int j = n;
	int m = 0;
	while (j!=0) {
		m = m*10 + j%10;
		j/=10;
	}
	cout << m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
int m =(n/10);
 int q =(n-m);
int a=n/100;
int b=(n-a)/10;
int c=n-(a+b);
int d=n/1000;
int e=(n-d)/100;
int f=(n-(d+e))/10;
int g=n-(d+e+f);
 if (n<10)
 cout<<n;

 else if (n<100) 
 cout<<q<<m;

 else if (n<1000) 
cout<<c<<b<<a;

else if (n<10000) 
cout<<g<<f<<e<<d;

return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{


int m,rem,reverse_number=0;
cin>>m;

while(m!=0){
rem=m%10;
  if(rem==0)
  cout<<"";
  if(rem!=0){
  reverse_number=reverse_number*10+rem;
  }
m=m/10;
} 

cout<<reverse_number;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

int main(){

int n;
cin>>n;
int y=n;
int m=0;
int i=0;
while(n>0){
		n=(n-n%10)/10;
		i++;    }
int x=i;
int k=1;
n=y;
while(k<=x){
		m=m+(n%10)*pow(10,i-1);
		n=(n-n%10)/10;
		i--; k++;     }

cout<<m;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
	//declearing variables and taking input
	int n,m=0,digit=0;
	cin>>n;
	while (n>0){
		if (n%10 !=0){
			digit = n%10;
			m = m*10 +digit ;
			n /=10;
		}else{
			n /=10;
			continue;
		}
	}//output
	cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m;
cin>>n;
m = left(n);
cout<<"m";
return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
  int n,m=0,rem;
  cin>>n;
  while(n/10>0){
    rem=n%10;
    m=m*10+rem;
    n=n/10;
   }
  cout<<m*10+n;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <simplecpp>
main_program {
	int n,m=0,nd=1; cin>>n;
	for(int i=n;i>0;i=i/10){
		nd=nd*10;
	}
	nd=nd/10;
	for(int i=n;i>0;i=i/10){
		int d=n%10;
		n=n/10;
		m=m+d*nd;
		nd=nd/10;
	}
	cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m;
cin>>n;
m=0;
while(n>0){
m=10*m+(n%10);
n=n/10;


}
cout<<m;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n;
cin>>n;
int m;
m=0;
int r;
r=n;
while(r>0)
{
m=m*10+r%10;
r=r/10;
}
cout<<m;
return 0;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
  int n,k=0,m=0,b=0;cin>>n;
  k=log10(n)+1;
  for(int i=0;i<k;i++){
  b=n%10;if(b!=0){cout<<b;}
  m=m+b*(pow(10,n-i-1));
  n=n/10;}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;

int main(){
int k;
cin>>k;

while(k%10 == 0){
    k=k/10;
}
int digit,number=0,m=1,n=10;
while(k/n != 0){
    n=10*n;
    m++;
}

for(int i=1; i<=m; i++)
{
    digit=k%10;
    k=k/10;
    number=number*10+digit;
}
cout<<number;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m=0,digit;
cin>>n;
while(n>0)
{
 digit=n%10;
 n=n/10;
 if (m==0)
{
  if(digit==0) continue;
}
 m=m*10+digit;
}
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
	
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
int main(){
int n;
std::cin>>n;
while(n%10==0){n=n/10;}
while(n>0){std::cout<<n%10;n=n/10;}}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main (){
	int n;
	cin>>n;

	int digit;
	int rev=0;
	while (n>0){
		digit = n%10;
		rev=rev+digit;
		n=n/10;
		if(n>0){rev=rev*10;}
	}

	cout<<rev;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
#include<cmath>
main_program{
	double n,a,c;
	int b,d;
	cin>>n;
	while(n>0){
		a=n/10;
	    b=n/10;
	    c=a-b;
	    d=c*10;
		if(d!=0){cout<<d;}
		
		n=b;
	}
	
	
	
	

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
    int rev=0,r,n;
    cin>>n;
    r=n/10;
    while(n>0){r=n%10;
        rev=rev*10+r;
        n=n/10;
        
    }
    cout<<rev;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B