CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
#include <vector>

using namespace std;
bool check1(vector <int> a, int n){
    for (int i=0;i<n-1;i++){
        if (a[i]==a[i+1]){
            continue;
        }
  else return 0;      
    }
return 1;
    }

bool check2(vector <int> a,int n){
    //ASCENDING ORDER
    for (int i=0;i<n;i++)
    {
     if (a[i]<=a[i+1])continue;
    else return 0;}
    if (!check1)return 1;
    else return 0;

}
bool check3(vector <int> a,int n){
    //descENDING ORDER
    for (int i=0;i<n;i++)
    {
     if (a[i]>=a[i+1])continue;
    else return 0;}
    if(!check1)return 1;
    else return 0;
}

int main(){
    vector<int> nums;
    int n;
    cin>>n;
    for (int i=0;i<n;i++){
        cin>>nums[i];
    }
 for (int i=n;i>=0;i--){
        cout<<nums[i];
    }
if (check1(nums,n))cout<<"B";
if(check2(nums,n))cout<<"A";
if (check3(nums,n)){cout<<"D";}
if (!check1(nums,n)  && !check2(nums,n) && !check3(nums,n))cout<<"N";
return 0;

}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main()
{
    int n;
    cin >> n;
    int  nums[n];
    bool flag;

    for(int i=0; i<n; i++)
    {
        cin >> nums[i];
    }

    for(int i=0; i< n/2; i++)
    {
       std::swap(nums[i], nums[n-i-1]);
    }
    
    for(int i=0; i<n; i++)
    {
        cout << nums[i] << " "; 
    }
    cout << endl;

    for(int i=0; i< n/2; i++)
    {
       std::swap(nums[i], nums[n-i-1]);
    }

    for(int i=0; i<n-1; i++)
    {
      if(nums[i]!= nums[i+1])
      {
      flag=false;
      break;
      }
    }
    if(flag) cout << "B" << endl;
    flag = false;

    for(int i=0; i<n-1; i++)
    {
        if(nums[i] < nums[i+1] || nums[i] == nums[i+1])
        {
        flag=true;
        }
        else 
        {
            flag = false;
            break;
        }
    }
    if(flag) cout << "A" << endl;
    flag=true;

    for(int i=0; i<n-1; i++)
    {
        if(nums[i] > nums[i+1]|| nums[i] == nums[i+1])
        {
        flag = true;
        }
        else 
        {
            flag = false;
            break;
        }
    }
    if(flag) cout << "D" << endl;
    flag=true;
    
    if(!flag) cout << "N" << endl;
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
#include <vector>

int main() {
	int n;
	
	std::vector<int> nums;
	
	std::cin >> n;
	
	int input;
	for (int i = 0; i < n; i++) {
		std::cin >> input;
		nums.push_back(input);
	}
	
	
	// printing in reverse
	for (int i = n - 1; i >= 0; i--) {
		std::cout << nums[i] << ' ';
	}
	std::cout << '\n';
	
	
	//checking ascending descending
	
	bool asc = true;
	bool desc = true;
	
	for (int i = 0; i < n - 1; i++) {
		if (nums[i + 1] > nums[i]) {
			desc = false;
		}
		if (nums[i + 1] < nums[i]) {
			asc = false;
		}
	}
	
	if (asc && desc) {
		std::cout << "B";
	}
	if (asc && !desc) {
		std::cout << "A";
	}
	if (!asc && desc) {
		std::cout << "D";
	}
	if (!asc && !desc) {
		std::cout << "N";
	}
	
	std::cout << '\n';
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main(){
    int n;
    cin >> n;
    vector<int> arr(n, 0);
    for (int i=0; i<n; i++){
        cin >> arr[i];
    }
    
    for (int i=n-1; i>=0; i--){
        cout << arr[i] << " ";
    }

    cout << endl;
    
    bool rev = 1;
    for (int i=0; i<n-1; i++){
        if (arr[i] == arr[i+1]) continue;
        else {
            rev = 0;
            break;
        }
    }
    bool asc = 1;
    vector<int> ascArr (arr);
    sort(ascArr.begin(), ascArr.end());
    for (int i=0; i<n; i++){
        if (arr[i] == ascArr[i]) continue;
        else {
            asc = 0;
            break;
        }
    }
    bool dsc = 1;
    vector<int> dscArr (arr);
    sort(dscArr.begin(), dscArr.end(), greater<int>());
    for (int i=0; i<n; i++){
        if (arr[i] == dscArr[i]) continue;
        else {
            dsc = 0;
            break;
        }
    }

    if (rev==1) cout << "B";
    else if (asc==1) cout << "A";
    else if (dsc == 1) cout << "D";
    else cout << "N";
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main (){
    const int Nmax = 100;
    char t[Nmax];
    int n;cin >> n;
    for (int i=0; i<n; i++) cin >> t[i];
    for (int i=0 ;i<n; i++) cout << t[n-i-1]<< " "<<endl;
    if (int i=0;t[i]=t[i+1]) cout << "B" <<" "<<endl;
    else if (int i=0;t[i]<= t[i+1])cout << "A" << " " << endl;
    else if (int i=0;t[i]>=t[i+1])cout << "D"<<endl;
    else {cout <<"N" << " "<<endl;
    }
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
using namespace std;

int main(){
    int n;cin>>n; char c;
    int A[n];
    for(int i =0; i<n; ++i){
        cin>>A[i];
    }
    for(int i =1; i<=n; ++i){
        cout<<A[n-i]<<" ";
    }
    cout<<endl;
    for(int i =0; i<n; ++i){
        
        if(A[i]!=A[i+1]) break;
        if(i==n-1) {cout<<"B";return 0;}
    }
    for(int i =0; i<n; ++i){
       
        if(!(A[i]<=A[i+1])) break;
        if(i==n-1) {cout<<"A"; return 0;}
    }
    for(int i =0; i<n; ++i){
        
        if(!(A[i]>=A[i+1])) break;
        if(i==n-2) {cout<<"D"; return 0;}
    }
    
    cout<<"N";           


}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;

void printReverse(int a[],int n){
for(int k=n;k>0;k--){
    cout<<a[k-1]<<" ";
}

}

bool ascending(int a[],int n){
    int i=0;
while(a[i]<=a[i+1]&&i<n-1){
    i++;
}
return (i==n-1);
}
bool descending(int a[],int n){
  int i=0;
while(a[i]>=a[i+1]&&i<n-1){
    i++;
}
return (i==n-1);

}


int main(){
int n;
cin>>n;
int arr[n];
for(int i=0;i<n;i++){
cin>>arr[i];
}
printReverse(arr,n);
cout<<endl;
if(ascending(arr,n)&& descending(arr,n))cout<<"B";
else if(ascending(arr,n)&& !descending(arr,n))cout<<"A";
else if(!ascending(arr,n)&& descending(arr,n))cout<<"D";
else if(!ascending(arr,n)&& !descending(arr,n))cout<<"N";
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;

int main()
{
    int n;
    cin>>n;
    int nums[n];
    
    for(int i=0; i<n; i++)
    {
        cin>>nums[i];
    }
    for(int i=0; i<n; i++)
    {
        cout<<nums[n-1-i]<<" ";
    }
    cout<<endl;
    
    int x=0;
    int y=0;
    for(int i=0; i<n-1; i++)
    {
        if(nums[i]<=nums[i+1])
        {
            x++;
        }
        else break;
       int y=0;
       for(int i=0;i<n-1; i++)
       {
        if(nums[i]>=nums[i+1])
        {y++;}
        else break;
       }
    }
       if(x==n-1 && x!=y)
       {
        cout<<'A';
       }
       if(y==n-1 && x!=y)
       {
        cout<<'D';
       }
        if(x!=n-1 && y!=n-1)
       {
        cout<<'N';
        }
       if(x==y)
       {
        cout<<'B';
       }
      

}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
using namespace std;

int main(){
    int n;
    //Input for size of array
    cin>>n;
    int num[n];
    //Take input for array
    for(int i=0; i<n;i++){
        cin>>num[i];
    }
    //reverse array
    for(int x=0;x<n/2; x++){
        swap(num[x],num[n-x-1]);
    }
    //print rev array
    for(int m=0; m<n; m++){
        cout<<num[m]<<" ";
    }

    //Assigning character
    bool asc=true;
    bool dec=true;
    bool con=true;
    //check const
    if(num[0]=num[n-1]){
        for(int t=0;t<n-1;t++){
            if(num[t]!=num[t+1]){
                con=false;
                break;
                }
        }
    }
    //Check increasing
    if(num[0]<num[n-1]){
        for(int r=0;r<n-1;r++){
            if(num[r]>=num[r+1]){
                asc=false;
                break;
                }
        }
    }
    //check decr
    if(num[0]>num[n-1]){
        for(int p=0;p<n-1;p++){
           if(num[p]>=num[p+1]){
                dec=false;
                break;
                }
        }
    }
    if(con==true){
        cout<<"B";
    }
    else if(asc==true){
        cout<<"A";
    }
    else if(dec==true){
        cout<<"D";
    }
    else {
        cout<<"N";
    }
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A