CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
	int n,k=1;
	cin>>n;
	repeat(n){
		if (k%2==1){
			repeat(k){
				cout<<"o";
			}
			int j=0;
			repeat(n-k){
				if (j%2==1){
					cout<<"o";
				}
				else cout<<"x";
				j++;
			}
			cout<<endl;

		}
		else {
			repeat(k){
				cout<<"x";
			}
			int j=0;
			repeat(n-k){
				if (j%2==1){
					cout<<"x";
				}
				else cout<<"o";
				j++;
			}
			cout<<endl;
		}
		k++;
	}
}

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
        int n;
        cin >> n;
        if (n % 2 == 0){
        for (int j = 1; j <= n; j++) {
                if (j % 2 == 1){
                        repeat(j){
                                cout << "o";}
                        repeat((n - j - 1)/2){
                                cout << "xo";}
                        cout << "x";
                        cout << endl;
                }
                else {
                        repeat (j) {
                        cout << "x";
                }
                        repeat((n-j)/2){
                                cout << "ox";
                        }
                cout << endl;
                }
        }

        }
        else {
                for (int j = 1; j <=n; j++) {
                        if (j % 2 == 1){
                                repeat(j) {
                                        cout << "o";
                                }
                                repeat ((n-j)/2){
                                        cout << "xo" ;
                                }
                                cout << endl;
                        }
                        else {
                                repeat (j){
                                        cout << "x";
                                }
                                repeat ((n-j-1)/2){
                                        cout << "ox";
                                }
                                cout << "o";
                                cout << endl;
                        }
                }
        }
}

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include <simplecpp>
main_program{
        int n;
        cin >> n;
        int i=1;
        if(n%2==0){
                repeat(n/2){
                        repeat(i){
                                cout << "o";
                        }
                        cout << "x";
                        repeat(n/2-1-i/2){
                                cout << "o" << "x";
                        }
                        cout << endl;
                repeat(i+1){
                        cout << "x";
                }
             
                if (n/2-2-i/2>=0){
                    cout << "o";
                        repeat(n/2-2-i/2){
                                cout << "x" << "o";
                        }
                
                        cout << "x" << endl;
                        i=i+2;
                }}}
                else{
                        repeat(n/2){
                        repeat(i){
                                cout << "o";
                        }
                        cout << "x";
                        repeat(n/2-1-i/2){
                                cout << "o" << "x";
                        }
                        cout << "o" << endl;
                        repeat(i+1){
                        cout << "x";
                }
                cout << "o" ;
                if (n/2-2-i/2>0){
                        repeat(n/2-2-i/2){
                                cout << "x" << "o";
                        }
                }
                        
                        i=i+2;}
                        repeat(n){
                                cout << "o" ;}
                        cout << endl;
                }
        }

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: B
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include <simplecpp>

main_program{
	int n;
	cin >> n;
	for(int i=1;i<n+1;i++){
		repeat(i){
			if(i%2==0) cout << "x";
			else  cout << "o";
		}
		if(i%2==0) {
			repeat((n-i)/2) {cout << "ox";}
			if(n%2 ==1) {cout << "o";}
		}
		else{
			repeat((n-i)/2) {cout << "xo";}
			if(n%2==0) { cout << "x";}
		}
		cout << endl;
	}
}

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program {
    int n;
    cin>>n;
    for (int i=0; i<n; i++) {
            if (i%2==0) {
                repeat (i+1) {
                    cout<<"o";
                }
                repeat ((n-i-1)/2) {
                    cout<<"xo";
                }
                if ((n-i-1)%2==1) cout<<"x";
                else cout<<"";
            }
            else {
                repeat (i+1) {
                    cout<<"x";
                }
                repeat ((n-i-1)/2) {
                    cout<<"ox";
                }
                if ((n-i-1)%2==1) cout<<"o";
                else cout<<"";
            }
            cout<<endl;
    }
}

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a program to accept an integer n and print an n x n square grid filled with alternating concentric L-shaped patterns using the characters 'o' and 'x'.

The pattern always starts with the character 'o'.

The next row and column are filled with 'x', forming an L shape flipped on the vertical axis.

Then again with 'o', alternating until the entire grid is filled.

Examples

Input:
4

Output:
oxox
xxox
ooox
xxxx

Input:
7

Output:
oxoxoxo
xxoxoxo
oooxoxo
xxxxoxo
oooooxo
xxxxxxo
ooooooo


Input Format

An integer n.


Output Format

Print the n x n pattern of concentric L shapes using 'o' and 'x'.


Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the output.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
        int n, i, j;
        cin >> n;
        for(i=1;i<=n;i++){
                for(j=1;j<=n;j++){
                        if(j<=i){
                        if(i%2!=0){
                                repeat(i)
                                        cout << "0 ";
                        }
                        else{
                                repeat(i)
                                        cout << "x ";
                        }
                        j=j+i;
                        }
                        if(j>i && j<=n){
                                 if(j%2!=0){
                                cout << "0 ";
                        }
                        else{
                                cout << "x ";
                        }
                        }
                }
        cout << endl;
        }
}

Grading criterion: Space and New line
Rating A: Correctly prints new line chracter for printing the pattern on n lines

Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include <iostream>

using namespace std;

bool isprime(int n){
int k = 0;
if(n == 2) return true;
if(n == 3) return true;
for(int j = 2; j < n;j++){
if(n % j == 0){
k++;
break;
}
}
if(k == 0) return true;
else return false;
}

int main(){
int n,i;
cin >> n;
if(n > 5){
for(i = 2; i < n;i++){
if(isprime(i) == true && n % i == 0) cout << i << endl;
}
}
if(n == 2) cout << "2";
if(n == 3) cout << "3";
if(n == 4) cout << "2";
if(n == 5) cout << "5";
if(isprime(n)) cout << n;
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include<iostream>
#include<cmath>

using namespace std;
int nthPrimeNumber(int n)

{
	int i,j,k,p;
	k=2;
	j=0;
	p=1;
	while(p<=n)
	{
		j=0;
		for (i=2;i<=sqrt(k);i++)
		{
			if (k%i==0)
			{
				j++;
			}

		}
	k++;
	if (j==0)
	{
		p++;
	
	}
	}
	return k-1;

}

int main()
{
	int n,i,j;
	cin>>n;
	i=1;
	while (nthPrimeNumber(i)<=sqrt(n))
	{
	i++;
	}
	for (j=1;j=(i-1);j++)
	{
		if (n%nthPrimeNumber(j)==0)
		{
			cout<<nthPrimeNumber(j)<<endl;
		}
	}
		
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include<iostream>
using namespace std;
bool isPrime(int N)
{
int i = 2;
bool flag = true;
for(i = 2;i<N;i++)
{
if(N%i == 0)
{
flag = 0;
break;
}
}
return flag;
}
int nextPrime(int N)// to return the prime number immediately  after N
{
int i = N+1;
while(true)
{
if(isPrime(i))
return i;
i++;
}
}
int main()
{
int n,temp , flag = 0, prime = 2;// temp variable as a copy of n to retain its value
cin >> n;
temp = n;
while(temp !=1)
{
while(true)
{
if(temp % prime == 0)
{
flag = 1;
temp /= prime;
}
else
break;
}
if(flag == 1)
cout << prime << endl;
flag = 0;
prime = nextPrime(prime);
}
return 0;
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: B
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include<iostream>
using namespacestd;
int main(){

	int n,k;
	cin>>n;
	if (n%2==0){
	while(n%2==0)}
	cout<<"2";

	for(k>=3;k<=n;k=k+2){
		if(n%k==0)
		{
		cout<<k;
		}
	}
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include<simplecpp>
main_program{
int n;int k=3;
cin>>n;
if (n%2==0){
cout<<"2"<<endl;}
while(n%2==0)
{n=n/2;}
while(k<=n)
{if (n%k==0){
cout<<k<<endl;}
while(n%k==0)
{n=n/k;}
k=k+2;
}}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include <iostream>
using namespace std;
int main(){
	int n;
	cin>>n;
	if (n%2==0){
		cout<<2<<endl;
		while (n%2==0) n=n/2;
	}
	{
		for (int i=3;i<=n;i=i+2){
			if (n%i==0){
				cout<<i<<endl;
				while (n%i==0) n=n/i;
			}
		}
	}
	return(0);
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C
Problem: Write a C++ program to take a positive integer n as input from the user and print out its unique prime factors. For this, do the following: While n is divisible by 2, print the number 2 and divide n by 2. After that, the number is no longer even. While n is divisible by k=3, print the number 3 and divide n by 3. After k no longer divides n, increase k by 2 and repeat. 

Input Format - integer n
Output Format - All prime factors, each one printed on a new line. 

Constraints
n is a positive integer such that n>=2

Sample input and output
Input - 45
Output - 3 5
Explanation:45 can be expressed as 3x3x5 . Hence its prime factors are 3 and 5


Note:Do not write any C++ statements for printing general messages. For example, the following should NOT be present in your program:cout << "Enter a number:",cout << "The computed answer is", etc.cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the programThe solution file name should be an C_Q2.cpp

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,k=3;
cin>>n;
if(n%2==0)cout<<2;
while(n%k==0){
cout<<k;
k=k+2;
}
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Okay Commented
Rating C: Poor or No Comment
Rating D: 0
Assigned grade: C