CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
long long int T;
cin>>T;
int k;
k=T%10;
if (k==0)T=T/10;
else {cout<<k;
      T=T-k;
      T=T/10;}
while(T>0){
k=T%10;
cout<<k;
T=T-k;
T=T/10;}
return 0;}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
	int n;
	cin>>n;
	while(n>0){
		if(n%10!=0){break;}
		n=n/10;
	}
	while(n>0){
		cout<<n%10;
		n=n/10;
	}
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;

int main(){
	long int n = 0;

	cin >> n;
	for (int x = 0; n != 0;){
		if (n%10 != 0 || x != 0){
			cout << n%10;
			x++;
		}
		n = n/10;
	}

	return 0;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main (){
int n;
cin>>n;
int r=0;
int m=0;
if (n==0) {
cout<<"0";
}
while(n!=0){
r=n%10;
n=n/10;
m=(m*10)+r;
}
cout<<m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
	int n, m, i, reverse_num=0;
	cin>>n;
	while(n !=0){
		reverse_num = 10*reverse_num + (n%10);//adds the last digit of updated no. to reverse_num 
		n=n/10;
	}
	cout<<reverse_num;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n, rev=0, digit;
cin >> n;
while (n%10!=0){
digit=n%10;
rev=rev*10+digit;
n=n/10;
}
cout << rev;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n;cin>>n;
while(n%10==0)n=n/10;
while(n/10!=0){
cout<<n%10;
n=n/10;


}
cout<<n%10;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
int n,x;
cin>>n;
while(n>0)
{
x=n%10;
n=(n-x)/10;
cout<<x;
}
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m=0;
cin >> n;
float val1=n;
int val2=n,dig=0,temp;
do { dig+=1;
     val1=val1/10;}while(val1>=1);
for (int i=1;i<=dig;i++){
 temp=val2%10;
 if (temp!=0){
            for(int j=1;j<=(dig-i);j++){temp=temp*10;}
            m=m+temp;}
 val2=int(val2/10);
 }
cout << m;





}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream> 
using namespace std ;
int main (){

	int n ;
	cin >> n ;
	do  {
	if (n%10!=0) break ;
	n=(n-n%10)/10;
	}
	while (n%10==0);
int x=0;
	do {
	int a=n%10 ;
	n=(n-a)/10 ;
	x=x*10+a;
	}
	while (n!=0) ;
	cout << x;
	return 0 ;
	}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,i;
cin>>n;
while(n/10!=0){
i=n%10;

n=n/10;
if(i!=0)
cout<<i;
}

cout<<n;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
unsigned long long int n;
cin>>n;
for(int i=n%10;i==0;i=n%10)n=n/10;
for(int p=n;p!=0;p=n/10){int t=n%10;cout<<t;n=n/10;}
if(n!=0)cout<<n;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{int m=0, n;
cin>>n;
if (n==0) cout<<0;
else{
	int l, j=1;
	for (int i=0; ; ++i)
	{	if (floor(n/j)==0) break;
		j*=10;
		l=i+1;
	}
	j=1;
	int a=1, d;
	for (int p=0;p<(l-1); ++p) a=a*10;
	for (int g=0; g<l; ++g)
	{	d=(n%(j*10)-n%j)/j;
		m=m+ d*a;
		a=a/10;
		j*=10;
	}
	cout<<m;
}
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>

main_program{
	unsigned long long int n;
	cin >> n;
	unsigned long long int i = 0;
	while (n>0){
		i = i*10 + n%10;
		n=(n-n%10)/10;
	}
	cout << i;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
int n;
cin>>n;
while(n%10==0){
n=n/10;}
do{
cout<<n%10;
n=(n-(n%10))/10;}
while(n!=0);
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,m,i,NumDig,a,j;
cin>>n;
i=0;
a=n;
m=0;
while(a!=0)
{
a=a/10;
i++;
}
a=n;
for(j=1;j<=i;j++)
{
NumDig=a%10;
m=NumDig*pow(10,(i-j))+m;
a=a/10;
}
cout<<m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n;
cin >> n;
int digits = log10(n)+1;
int d = 0; int f = 0;
for (int i = 0; i < digits && d==0; i++)
{
int r = pow(10,i+1);
d = (n%r)/pow(10,i);
f = i;
};
for (int i = f; i < digits; i++)
{
int r = pow(10,i+1);
d = (n%r)/pow(10,i);
cout << d;
};
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>

int main(){
using namespace std;
int m,i=0,n,k=0,dig=1;
cin >> n;
m=n;

while(m>0){
m=n;
m=m/pow(10,dig);
dig=dig +1;
}
dig=dig-2;

while(dig>=0){
i=n%10;
n=(n-n%10)/10;
k=k+i*pow(10,dig);
dig--;
}
cout<<k;
return 0;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
        long long int n, m=0;
        cin>>n;
        while (n>0){
                m=m*10+n%10;
                n=n/10;
        }
        cout<< m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <simplecpp>

main_program{
	long long int n = 0, sum = 0;
	cin >> n;
	long long int copy = n;
	int rem = 0;
	while(copy%10 == 0){
		copy /= 10;
	}
	while(copy>0){
		rem = copy%10;
		sum = (sum +rem)*10;
		copy/=10;
	}
	sum/=10;
	cout << sum;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	unsigned int n; cin>>n;
	unsigned int N;
	int i=0;
	N=n;
	while(N>0)
	{
	N/=10;
	i++;
	}
	int rem,j;
	unsigned int m=0;
	while(n>0)
	{
	rem=n%10;
	n/=10;
	m+=rem*pow(10,i-1);
	i--;
	}
	cout<<m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
int n,m=0;
cin>>n;
int i=0;
int k=0;
while(n/10 !=0){
	k=n%10;
	n=n/10;
	m= 10*m+k;
	i++;
		}
cout<<m*10+n;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;

int main(){
	long long int n,m;
	cin>>n;
	while(n>0){
		int temp=n%10;
		n/=10;
		m+=temp;
		m*=10;
		
	}
	cout<<(m/10);
	return 0;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <simplecpp>

main_program{

long long int n,reverse=0,length, i=0,remainder;
cin>>n;

length=to_string(n).length();
while (i<length){
	if (n%10==0){
		n/=10;
	};
	i+=1;
};

i=0;
length=to_string(n).length();
while (i<length){
	reverse=reverse*10;
	remainder=n%10;
	reverse=remainder+reverse;
	n=n/10;
	i+=1;
};







cout<<reverse;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
	int n,rev=0;
	cin>>n;
	while(n>0){
		rev=rev*10+n%10;
		n=n/10;
	if(n%10==0){
		n=n/10;
		while(n>0){
		rev=rev*10+n%10;
		n=n/10;}
	}}
	cout<<rev;
		
			  
			  }

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main()
{
int n,r,m=0,x=1,p=10,q=1,i;
cin>>n;
while (n>=p)
{x=x+1;
p=p*10;}
for(i=1;i<=x;i++)
{
r=n/p;
m+=10*r*q;
q=q*10;
p=p/10;
n-=r*q;}
cout<<m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

int main(){
int n,a,x,m=0,y=1;
cin>>n;
while(n/y>=10) y=y*10;
a=y;
for(int i=0;i<log(a)/log(10)+1;i=i+1)
{x=(n/y)%10;
 m=m+x*pow(10,i);
 y=y/10;
}
cout<<m;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{ 
int n,r;cin>>n;
	while(n>0){ 
	r=n%10;
    if(r==0){ n=n/10; continue;}
	else { 
	while(n>0){
		cout<<r;
		n=n/10;
		r=n%10;
	    }
	}
	}
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main() {
  int n,a=0,n1;
    cin>>n;
	if(n>0){
		while(n!=0){
		 n1=n%10;
   		 n=n/10;
   		 a=a*10+n1;
   		 }
		 cout<<a;
		}

}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
int N;
cin>>N;
int temp=N;
int sum=0;
int i;
int temp1=N;
for( i=1;temp/10!=0;i++)
{
temp=temp/10;}

for(int j=1;j<=i;j++){
int k=temp1%10;
sum=sum+(k*pow(10,i-j));
temp1=(temp1-k)/10;
}
cout<<sum;}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,r,rev=0,a=n;
cin>>n;
while(n>0)
{
	r=n%10;

	rev=rev*10+r;
	n=n/10;}
cout<<rev;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
	int n,y,x,r;
	 cin>>n;
	x=1;
	y=0;
	 while(x!=0&&n>0){
		    	 r=n%10;
		     	x=n/10;
		     	y=y*10+r;
		     	n=x;
		    	}
           	cout<<y;
	}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{	int n,d,p=0;
	cin>>n;
	for(int m=n;m>0 ; m/=10)
	{	int d=m%10;
		p=p*10+d;
	}
	cout<<p;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main(){

int n;
cin>>n;
int m=0;
while(n){
m=10*m+n%10;
n=n/10;
}
cout<<m<<endl;
return 0;
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main()
{
int n;
cin>>n;
while(n>0){
if(n%10==0){n=n/10;}
if (n%10!=0){
cout<<(n%10);
n= (n-(n%10))/10;}
}
}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>

using namespace std;

int main() {

	int n;

	cin >> n;

	int nrev = 0, nc = n;

	int d = 0;

	while (nc > 0) {

		d++;
		nc /= 10;

	}

	for (int i = 0; i < d; i++) {

		nrev += (n % 10) * pow(10, d - i - 1);
		n /= 10;

	}

	cout << nrev;

}

Grading criterion: Storing the reverse of number in a variable
Rating A: Correct output stored
Rating B: No output or wrong output stored
Rating C: 0
Rating D: 0
Assigned grade: A