CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a program to accept two numbers from the user start and end and print the Pythagorean triplets within the range of start to end, both inclusive, but the triplets should not have any common factor. If no such triplets exist, then print 0. The triplets should be in increasing order.

Student submission:
#include<simplecpp>
main_program
{
	int start = 0;
	int end = 0;
	int commonfactor = 0;
	int notriplet = 1;
	cin >> start >>end;
	for(int a = start;a<=end;a++)
	{
		for(int b =a;b<=end;b++)
		{
		
			float c = sqrt(a*a+b*b);
			if(int(c)==c and c<=end)
			{
				for(int i = 2;i<=c;i++)
				{
					if(a%i==0 and b%i==0 and int(c)%i==0)
					{
						 commonfactor = 1;
						 break;
					}
				}
				if(commonfactor==0)
				{
					cout << a << " " << b << " " << c << endl;
					notriplet = 0;
				}	
			}
			commonfactor = 0;

		}
		

	}
	if(notriplet == 1)
	{
	cout << 0;
	}

}

Grading criterion: Overall program correctness
Rating A: Common requirements  of a Program are correct - i.e. header (includes, using namespace, etc) main syntax variables declaration overall syntax
Rating B: Problems are present in the code(eg: printing unnecessary strings, missing semicolons & braces, wrong/missing declarations, wrong header files)
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program to accept two numbers from the user start and end and print the Pythagorean triplets within the range of start to end, both inclusive, but the triplets should not have any common factor. If no such triplets exist, then print 0. The triplets should be in increasing order.

Student submission:
#include<simplecpp>
main_program{
	int n,i,b,c;
	cin>>n>>i;
	int a=n;
	b=n+1;
	c=n+2;
	while(c<=i-2){
	if(pow(a,2)+pow(b,2)==pow(c,2)){
		cout<<a <<b <<c;
	}
c++;

	}}

Grading criterion: Overall program correctness
Rating A: Common requirements  of a Program are correct - i.e. header (includes, using namespace, etc) main syntax variables declaration overall syntax
Rating B: Problems are present in the code(eg: printing unnecessary strings, missing semicolons & braces, wrong/missing declarations, wrong header files)
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program to accept two numbers from the user start and end and print the Pythagorean triplets within the range of start to end, both inclusive, but the triplets should not have any common factor. If no such triplets exist, then print 0. The triplets should be in increasing order.

Student submission:
#include<simplecpp>
main_program
{double a,b;
cin>>a>>b;
for(double i=a+1; i<=b; i++)
{
for(double j=i; j<=b-1; j++)
{
for(double k=b-1; k>=j; k--)
{
if((k*k==((i*i)+(j*j))))
{cout<<i<<" ";
cout<<j<<" ";
cout<<k<<" ";
}
}
}
}

}

Grading criterion: Overall program correctness
Rating A: Common requirements  of a Program are correct - i.e. header (includes, using namespace, etc) main syntax variables declaration overall syntax
Rating B: Problems are present in the code(eg: printing unnecessary strings, missing semicolons & braces, wrong/missing declarations, wrong header files)
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int nums[n];
    bool flag1=false,flag2=false,flag3=false,flag4=false,flag5=false,flag6=false;
    for(int i=0;i<n;i++){
        cin>>nums[i];
    }
    for(int i=n-1;i>=0;i--){
        cout<<nums[i]<<" ";
    }
    cout<<endl;
    int i;
    for( i=0;i<n;i++){
        for(int j=i;j<n;j++){
            if(nums[i]<=nums[j]){

            }else{
                flag4=true;
                break;
            }
        }
        if(flag4==true){break;}
    }
    if(i==n){
        flag1=true;
        cout<<"A";
    }
  int k;
    for( k=0;k<n;k++){
        for(int q=k;q<n;q++){
            if(nums[k]>=nums[q]){

            }else{
                flag5=true;
                break;
            }
        }
        if(flag5==true){break;}
    }
    if(k==n){flag2=true;
        cout<<"D";
    }
    int m;
    for( m=0;m<n;m++){
        for(int l=m;l<n;l++){
            if(nums[m]==nums[l]){

            }else{flag6=true;
                break;
            }
        }
        if(flag6==true){break;}
    }
    if(m==n){flag3=true;
        cout<<"B";
    }
    if(flag1==false&&flag2==false&&flag3==false){
  cout<<"N";
    }
    return 0;
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include<vector>
using namespace std;



int main(){
    int n;
    cin>>n;
    
 int A_nums[];
   
    

if  (both ascending and descending order) (constant values)
 return B;
else if  (ascending order (non-decreasing))
return A;
else if ( descending order (non-increasing)) 
 return  D;
else ( neither ascending nor descending order)
 return N;



}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include<vector>
using namespace std;

int main()
{
    int n;
    cin>>n;
    vector <int> nums (n);
    for(int i = 0; i < nums.size(); i++)
    {
        cin >> nums[i];
    }
    for(int i = (nums.size()-1); i>=0; i--)
    {
        cout<<nums[i]<<" ";
    }
    cout<<endl;
    for(int i=0;i<nums.size();i++)
    {
        if(nums[i]==nums[i+1])
        {
            cout<<"B";
            break;
        }
        else if(nums[i]<=nums[i+1])
        {
            cout<<"A";
            break;
        }
        else if(nums[i]>=nums[i+1])
        {
            cout<<"D";
            break;
        }
    }
    return 0;
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <vector>
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
using std::vector;

int main(){
    std::vector<int> nums;
    int n, t; cin >> n;
    char f;
    for(int i=0;i<n;i++){
        cin >> t;
        nums.push_back(t);
    }
    for(int i=0;i<n-1;i++){
        if(nums[i] == nums[i+1]) f = 'B';
        else{
            f = 'N';
            break;
        }
    }
    if(f=='N'){
    for(int i=0;i<n-1;i++){
        if(nums[i] >= nums[i+1]) f = 'D';
        else{
            f = 'N';
            break;
        }
    }}
    if(f=='N'){
    for(int i=0;i<n-1;i++){
        if(nums[i] <= nums[i+1]) f = 'A';
        else{
            f = 'N';
            break;
        }
    }}
    for(int i=n-1;i>=0;i--){
        cout << nums[i] << ' ';
    }
    cout << std::endl << f;
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin >> n;
    int arr[n];
    for(int i=0;i<n;i++){
        cin >> arr[i];
    }
    for(int i=0;i<n;i++){
        cout << arr[n-1-i] << " " ;
    }
    int a=0 ;
    for(int i=0;i<n-1;i++){
        if(arr[i]==arr[i+1]){
            a++;
        }
        else break ;
    }
    int b=0;
    for(int i=0;i<n-1;i++){
        if(arr[i]>=arr[i+1])
        b++;
    }
    int c=0;
    for(int i=0;i<n-1;i++){
        if(arr[i]<=arr[i+1])
        c++;
    }
    cout << endl ;
    if (a==n-1) 
    cout << "B" ;
   else if (b==n-1)
    cout << "D";
    else if (c==n-1)
    cout << "A";
    else cout << "N";
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int nums[n],temp;
    for(int i=0;i<n;i++){
        cin>>nums[i];
    }
    int countAD=0,countA=0,countD=0;
    for(int i=0;i<(n-1);i++){
        if(nums[i]==nums[n-1]){
            countAD+=1;
        }
    }
    for(int i=0;i<(n-1);i++){
        if(nums[i]<=nums[i+1] && nums[i]!= nums[n-1]){
            countA+=1;
        }
    }
    for(int i=0;i<(n-1);i++){
        if(nums[i]>=nums[i+1] && nums[i]!= nums[n-1]){
            countD+=1;
        }
    }
    if(n%2==0){
        for(int i=0;i<(n/2);i++){
            temp=nums[i];
            nums[i]=nums[n-i-1];
            nums[n-1-i]=temp;
        }
    }
    if(n%2==1){
        for(int i=0;i<((n+1)/2);i++){
            temp=nums[i];
            nums[i]=nums[n-i-1];
            nums[n-1-i]=temp;
        }
    }
    for(int i=0;i<n;i++){
        cout<<nums[i]<<" ";
    }
    cout<<endl;
    if(countAD==(n-1)){
        cout<<"B";
    }
    if(countA==(n-1)){
        cout<<"A";
    }
    if(countD==(n-1)){
        cout<<"D";
    }
    if(countAD!=(n-1) && countA!=(n-1) && countD!=(n-1)){
        cout<<"N";
    }
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
using namespace std;
#include<iostream>
void swap(int &a,int &b)
{
    int c;
    c=a;
    a=b;
    b=c;
}
int main()
{
    int n;
    cin>>n;
    int nums[n];
    int j=n-1;
    for(int i=0;i<n;i++)
     {
        cin>>nums[i];
     }
     for(int i=0;i<n;i++)
     {
        swap(nums[i],nums[j]);
        j--;
     }
     for(int i=0;i<n;i++)
     {
        cout<<nums[i]<<" ";
     }
      
    
    
     
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<simplecpp>
#include<vector>
main_program{
    vector<int> num;
    int n; cin>>n;
    for(int i=0; i<n; i++){
        cin>>num.begin()+i;
    }
    for(int i=0; i<n; i++){
        if(num.begin()+i>=num.begin()+(i+1)){cout<<"D";}
        else if(num.begin()+i<=num.begin()+(i+1)){cout<<"A";}
        else if(num.begin()+i=num.begin()+(i+1)){cout<<"B";}
        else{cout<<"N";}
    }
}

Grading criterion: Declaration of  array size and array
Rating A: correctly declares the flag variables, array/vector size and array/vector
Rating B: Some issue. 

Rating C: Major issue
Rating D: 0
Assigned grade: A