CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include<vector>
using namespace std ;
void  reverse ( int A[] , int n ){
  for (int i=0; i<n; i++ ){
    cin>>A[i];
  }
  for(int i=n-1; i>=0; i--){
    cout<<A[i]<< " " ;
  }
  cout<<endl;
  
}
int main (){
    int n,a;
    cin>>n;
    int A[n] = {}; 
    reverse(A,n );
    
   for (int i=0; i<n-1; i++){
  if( A[i]== A[i+1] ) 
  cout <<"B"<<endl;

 else  if (A[i]<=A[i+1]) cout<<" A" <<endl;

 else if ( A[i]>=A[i+1]) cout<< " D " <<endl ;

 else  cout<<" N"<<endl;
  } 
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using std::cout; using std::cin; using std::endl;
int main() {
const int Num= 100;
char text[Num], tmp;
int n; cin >> n;
if (n>2*Num + 1) {
cout<<"Text too long!"<< endl; 
return -1;
}
for (int i=0; i<n/2; i++) cin >> text[i]; 
if (n%2) cin >> tmp; 
for (int i=n/2-1; i>=0; i--) { 
if (cin >> tmp, text[i] != tmp) {
cout << "Not a palindrome!" << endl; return 1;
}
}
cout << "Palindrome!" << endl;
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: C
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main() {
    int n;
    cin>>n;
    int nums[n];
    for(int i=0; i<n; i++) {
        cin>>nums[i];
    }
    int B[n];
    for(int i=0; i<n; i++) {
        B[i] = nums[n-i-1];
    }
    for(int i=0; i<n; i++) {
        cout << B[i] << " ";
    }
    bool asc=false, desc=false;
    for(int i=0; i<n-1; ++i) {
        if(nums[i+1]>=nums[i]) 
        asc = true;
        else {
            asc = false;
            break;
            }
    }
    for(int i=0; i<n-1; ++i) {
        if(nums[i+1]<=nums[i]) 
        desc = true;
        else {
            desc = false;
            break;
        }
    }

    if(asc && desc) {
        cout<<"B";
    }
    else if(asc) {
        cout << "A";
    }
    else if(desc) {
        cout<<"D";
    }
    else cout << "N";
    }

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
+#include<array>
using namespace std;
void reverse(array[n], int n){
    int start=0 ;
    int end =size-1;
    if(start<end){
        swap(start,end);
        start++ ;
        end--;
    }
    return ;
    }

int main(){
    int n;
    cin>> n;
    
    int array[n];
    for (int i=0; i<n ;i++){
        cin>> array[i];
    
    }
    reverse(array[n], n);
    for (int i=0;i<n;i++){
        cout<<array[i];
    }
    char c;
    for(int i=0;i<num.size();i++){
      if (num[i]==num[i+1]){
        cout<< c='B';
      }
      if( num[i]>num[i+1]){
        cout<< c='D';
      }
      if(num[i+1]>num[i]){
        cout<< c='A';}
        if(num[i] !=num[i+i=1] && num[i]!>num[i+1] &&num[i]!<num[i+1]){
            cout<< c='N';
        }
        }
      }

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std; 


bool isAsc(int nums[],int n){
    for ( int j = 0; j<n-1; j++ ){
        if(nums[j+1]<nums[j]){ return false;}
        else continue;
    }
    return true;
}

bool isDec(int nums[],int n){
    for ( int j = 0; j<n-1; j++ ){
        if(nums[j+1]>nums[j]){ return false;}
        else continue;
    }
    return true;
}

bool isCon(int nums[],int n){
    for ( int j = 0; j<n-1; j++ ){
        if(nums[j+1]!=nums[j]){ return false;}

    }
    return true;
}
int main(){
int n; 
cin>>n;
int nums[n];
for(int i = 0 ; i<n ; i++){ 
cin>>nums[i];
}
for( int i=n; i>0 ; i--){
    cout<<nums[i-1]<<" ";
}
cout<<endl;
 if(isCon(nums,n)){cout<<"B";}
else if(isAsc(nums,n)){cout<<"A";}
else if(isDec(nums,n)){cout<<"D";}

else { cout<<"N";}
return 0;
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    bool ascend=true,descend=true,equal=true;
    int n;
    cin>>n;
    int nums[n];
    for(int i=0;i<n;i++){
        cin>>nums[i];
    }
    for(int i=0;i<n;i++){
        cout<<nums[n-i-1]<<" ";
    }
    cout<<endl;
    for(int i=0;i<n-1;i++){
        if(!(nums[i]==nums[i+1])){
        equal = false;
            
        }
        
        }
        

          for(int i=0;i<n-1;i++){
  if(nums[i]>nums[i+1])
        {ascend=false;
        equal=false;
        }
    }
    for(int i=0;i<n-1;i++){
        if(nums[i]<nums[i+1]){
            descend=false;
            equal=false;

        }
    }
    if(equal==true){
        cout<<"B";
    }
    else if(ascend==true){
        cout<<"A";
    }

    else if(descend==true){
        cout<<"D";
    }
    else{cout<<"N";}
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
using std::cout; using std::cin; using std::endl;

void f(int arr1[], int n) {
for (int i=0; i<n; i++) cin >> arr1[i];
}


int main(){
    int n;
    cin >> n;
    
    int arr1[n];
    f(arr1,n);
    
    int arr2[n];
    for(int i=0;i<n;i++){
        arr2[i]=arr1[n-i-1];
    }
    cout<<arr2[n]<<endl;
    if(
    for(int i=1;i<n;i++){
        if(arr2[i]>arr2[i-1])
    })
    {cout<<"A"<<endl;}
    else if(
    for(int i=1;i<n;i++){
        if(arr2[i]<arr2[i-1])
    }
    cout<<"D"<<endl;)
else if(
    for(int i=1;i<n;i++){
        if(arr2[i]==arr2[i-1])
    }
    cout<<"B"<<endl;)
else {
    cout<<N<<endl;
}
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>

void reverse(int n, int R[]) {

    for(int k=0; k<(n/2); k++) {
        int temp=R[k];
        R[k]=R[n-1-k];
        R[n-1-k]=temp;
    }
    for(int m=0; m<n; m++) {
        std::cout<<R[m]<<" ";
    }    
}

int main () {
    int n;
    std::cin>>n;
    int nums[n];

    for(int i=0; i<n; i++) {
        std::cin>>nums[i];
    }
    
    reverse(n,nums);
    std::cout<<std::endl;

//since the order is reversed, result would be opposite

    for(int j=0; j<n-1; j++) {
        if(nums[j+1]>nums[j])
            std::cout<<"D";
    
        else if(nums[j+1]<nums[j])
            std::cout<<"A";
        
        else if(nums[j]=nums[j+1])
            std::cout<<"B";
        
        else 
            std::cout<<"N";
    }
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: B
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int swap(int x,int y){
    int temp;
    temp=x; x=y ; y=temp;
}
int main(){
    int n;
    cin>>n;
    int nums[n];
    for (int i=0;i<n;i++){
        cin>> nums[i];
    }
    for (int i=0;i<n/2;i++){
        swap(nums[i],nums[n-i-1]);
        
    }
    for(int i=0;i<n;i++){
        cout<< nums[i];
    }
    cout<< endl;
    for(int i=0;i<n;i++){
    if ( nums[i]=nums[i+1])
    cout<< 'B'; break;
    if ( nums[i]>nums[i+1])
    cout<< 'D'; break;
    if ( nums[i]<nums[i+1])
    cout << 'A'; break;
    else 
    cout << 'N';
    } 
    
    
    
    

}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std; 
int main(){
    int N;
    bool status1=true,status2=true,status3=true,status4=true;
    cin>>N;
    int nums[N];
    for(int i=0;i<N;i++){
        cin>>nums[i];
    }
    for(int i=N-1;i>=0;i--){
        cout<<nums[i]<<' ';
    }
    cout<<endl;
    for(int i=0;i<N-1;i++){
       if (nums[i]==nums[i+1]) status1=false;
       if(status1) {cout<<"N";
       return 0;}   }
       if(status1==false) cout<<"B";
       for(int i=0;i<N-1;i++){
       if (nums[i]<=nums[i+1]) status2=false;
       if(status2) {cout<<"N";
       return 0;}   }
       if(status2==false) cout<<"A";
       for(int i=0;i<N-1;i++){
       if (nums[i]>=nums[i+1]) status3=false;
       if(status3) {cout<<"N";
       return 0;}   }
       if(status3==false) cout<<"D";
return 0;
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A