CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simplecpp>
float my_fmod(float x, float y) {
        while(x>y) {
                x=x-y;
        }
        return(x);
}
main_program {
        float x,y;
        cout<<fixed;
        cout.precision(3);
        cin>>x>>y;
        cout<<my_fmod(x,y)<<endl;
}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include <simplecpp>
double my_fmod(double x,double y){
while(x>=y){
x=x-y;
}
cout << fixed;
cout.precision(3);
cout<<x;
return(x);
 }
main_program{
double x,y;
cin>>x>>y;
my_fmod(x,y);
}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simplecpp>
main_program{
	float x=0,y=0;
	cin >> x >> y;
	
	 	while (x>y){
	 		float term=0;	
			term= x-y;
			x= term;}
	cout << fixed;
cout.precision(3); // print three digits after the decimal point		
	cout << x;
}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simplecpp>

	float my_fmod(float x, float y)
	{
		float ans;

		for(int i = 0; (x-i*y)>0; i++)
		{
			ans = x-i*y;

		}
		return ans;
	}
	
	main_program
	{
		float x,y;
		cin>>x>>y;

	        float value = my_fmod(x,y);
	        cout<<value; cout.precision(3);
		cout<<endl;
	}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simplecpp>
main_program{
	int t,y;
	cout <<t*y;
	cin >>t>>y;
}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simpelcpp>
main_program{
	float my_fmod(x,y){

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a program that directly implements the fmod function for the modulo operation on two real positive numbers, where fmod (x,y) = x t * y where t is the truncated (i.e., rounded towards zero) result of x/y. Compute the answer using only repeated subtraction.

The program should have a function named my_fmod that takes two arguments x and y. The answer should be returned back to the main function and should be printed in the main function.

Input Format

The input is two positive real numbers x and y separated by a space.

Output Format

Single line containing the fmod of x and y. Print 3 digits after the decimal point.

In order to force cout to always print 3 digits after the decimal point, do the following before printing the output with cout:

cout << fixed;

cout.precision(3); // print three digits after the decimal point

Note: Do not write any c++ statements for printing general messages. For example, the following should NOT be present in your program:
cout << "Enter a number:",
cout << "The computed answer is", etc.
cout should be used to print only the computed final output. In addition, do not print unnecessary spaces unless specified in the program.

Student submission:
#include<simplecpp>
main_program{
	float x,y;
	cin>> x>> y;
	cout<<fixed;
	cout.precision(3);
	cout<< fmod(x,y)<<endl;
}
		float fmod(int m, int n){
			float modulo=0.0;
			while(modulo>=0.0){
				modulo= m-n;
				m= modulo;
			}
			return modulo;
		}

Grading criterion: Is repeated subtraction approach is correctly implemented?
Rating A: if repeatedly subtracting divisor from dividend is done correctly in fmod function
Rating B: if the repeated subtraction is not done in fmod function
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program{

	int n,r;
	cin>>n;
	cin>>r;

	if(r>=1 && r<=n && n>=1 && n<=35000){
		long double a=1;
		for(int i=1; i<=r; i++){
	    a=a*(n+1-i)/i;} 
                     cout<<a;
	}}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: B
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program{
long double ncr,n,r,x;
cin>>n>>r;
x=2;
ncr=n;
while(x<r+1){
ncr=ncr*((n+1-x)/x);
x=x+1;
}
cout<<ncr;

}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: B
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include <simplecpp>
main_program
{
    int n; int r; int a; long double nca;
    cin >> n >>  r;
    nca = 1;
    if (r<=(n/2))
    {
    for (a=1; a<=r; a++)
    {
        nca = ((nca)*(n-a+1))/a ;
    }
    cout << nca;
    }
    else 
    {
       for (a=n; a>r; a--)
    {
        nca = ((nca)*a)/(n-a+1) ;  //cout << nca << endl;
    }
    cout << nca; 
    }
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: A
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<iostream>
using namespace std;

int main(){
	long long n, r, fact = 1.0;
	cin >> n >> r;
	for ( int i = n; i >= r;i--){
		long long mulli = n/(r*(n - r));
		fact *= mulli;
		n -= 1;
		r -= 1;}
	cout << fact << endl;
	//next i am going to do the calculation for n-r to 1 and then multiply both
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: D
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>

main_program{

	long n, r;
	cin>>n;
	cin>>r;
	long a=n; 
	long b=r;
	double long adi=1;
	double long adi2=1;

	repeat(r){

		adi=adi*a*1.0/(b);
		a--;
		b--;
	}

	b=r;

	repeat(n-r){

		adi2=adi2*a*1.0/(n-b);
		a--;
		b++;
	}

	cout<<adi*adi2;
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: A
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program
{
	long double n,r;
	cin>>n>>r;
	long double b=n;
	long double d=n-r;
	long double a=1;
	long double c=1;
	for(int i=1; i<=n-r; i++)
	{
		a=a*b;
		--b;
		c=c*d;
		--d;
	}
	long double ans=(a/c);
	cout<<ans;
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: C
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program{
long double c=1;
long double n,r;
int t=1;
while(t==r){
c*=(n-t+1)/t;
t=t+1
}
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: D
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program{
	long double  n,r;
	long double output=1;
	cin>>n>>r;
	long double a=n-r;

	while(n!=r){
	output*=(n/a);
	n--;
	a--;
	}
	cout<<output;
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: A
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>

main_program{
	int n,r;
	cin>>n>>r;
	 long double binom=1;
	
	if(r<n/2)
		r=n-r;
	
	int i=n-r;
	while(i>0){
		binom*=(n-i);
		binom/=(i);
		
		i--;
	}
	binom=(binom*n)/r;

	cout<<binom;// this code can only handle a difference in inputs of about // 3600 or so,after that it overflows into inf.
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: A
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
main_program{
long double a,b=1,r,n;
	cin>>n>>r;
	while(b<r){
		n=n*(n-b);
		b++;}
	b=r-1;
a=r;
	while(b>0&&b<=r-1){
		a=a*b;
		b--;}
	cout<<n/a;
}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: C
Problem: accept n and r from the user, compute nCr, and print the result. A naive approach would be to calculate the factorial of n, factorial of r, and factorial of n-r and then finally compute the result as given in the formulae above. However, calculating the factorial of a large number can be tricky, and the result may overflow due to the limitation of the size of data type. you are free to use other data types, including long double. you are free to use other data types, including long double.

Constraints:1 <= r <= n1 <= n <= 35000

Student submission:
#include<simplecpp>
long double c=1 ;
int n,r,a ;

main_program{
	cin>>n >>r ;
	for(a=1;a<=r;a++){
	        c=c/a;
		c=sqrt(c*(n-a+1));
//did this to keep c minimum

	        c=c*c;}
		cout<<c;



}

Grading criterion: Algorithm for calculating n-C-r
Rating A: The loop has the correct multiplying term to keep the value within range
Rating B: Tried a  loop with some term to keep the value within range, but not perfect
Rating C: Naive approach of calculating Factorials first, but 'correct'
Rating D: Code not done or completely wrong
Assigned grade: B