CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;
int ways( int arr[],int n, int currentposition =0){
    if (currentposition==(n-1)){
        return 1;
    }
    
    for (int i=1; i<arr[currentposition]; i++){
        currentposition+=i;
        return ways(arr,n,currentposition);
    }
}
int main(){
    int n;
    cin>>n;
    int jumps[n];
    for(int i=0; i<n; i++){
        cin>>jumps[i];
    }
    cout<< ways(jumps,n);
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

int totalnumberofdistinctpaths(){
    
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
#include<math.h>
using namespace std;

struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }

int jumps(int arr[],int& n){


		for(int i=0,;i<n;i++,){
		
                      for(int i=0; i<n;i++){
                 cout<< arr[i];

        }


}


int main(){
int n;
cin>>n;

int arr[n];
	for(int i=0; i<n;i++){
	cin>> arr[i];

	}
	
jumps(arr,n);






}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
void draw(double L, int level) {
if (level == 2) {
if (level == 0) { forward(L); return; }draw(L/3,1); left(60);
if (level == 1) {draw(L/3,1); right(120);
draw(L/3,0); left(60);
forward(L/3);draw(L/3,1); left(60);
draw(L/3,0); right(120);
forward(L/3);draw(L/3,1);
draw(L/3,0); left(60);
forward(L/3);
}
draw(L/3,0);
forward(L/3);
}
if (level == 3) ...
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
static const int NMAX = 90;
bool filled[NMAX] = {};
int memo[NMAX];
bool has(unsigned i) { return filled[i];}
int get(unsigned i){return memo[i];}
void add(unsigned i, int val) {

memo[i] = val; filled[i] = true;
}
};
int memoFib(unsigned n, Memo& memo) {
if (memo.has(n) )
return memo.get(n);
int ans = (n<=1)? n : memoFib(n-1,memo) + memoFib(n-2,memo);
memo.add(n,ans);
return ans;
}
int main()
{
    int n,sum=0;
    cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++)
    {
        cin>>jumps[i];
    }
    for(int i=0;i<n;i++)
    {
        sum+=memoFib(jumps[i],)
    }
    cout<<sum;
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#inlude <iostream>
using std::cout; using std::cin; using std::endl; using std::swap;

int main(){
    int n;
    cin>>n;
    int jumps[50]={0};
    for(int i=0; i<n; i++)  cin>>jumps[i];

}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostreaam>
using namespace std;
steps(int jumps[], int n){
    
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int extra=0;
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
int CalcJump(int jumps[],int n,Memo m,int pos=0)
{
  if(pos==n)return 0;
  int count=0;
  for(int i=0;i<pos;i++)
  {
    int t =pos-i-1;
    if(jumps[i]>=t) count++;
  }
  int tt=n-pos-1;
  
  if(jumps[pos]>=tt && tt!=1) extra+=count;
  return count+CalcJump(jumps,n,m,pos+1);
}


int main()
{
  int n;
  cin>>n;
  int jumps[n];
  for(int i=0;i<n;i++)
  { 
    cin>>jumps[i];
  }
  Memo m;
  int tot=CalcJump(jumps,n,m);
  cout<<tot-extra;

}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
   static const int jumps = 100;
   bool filled[jumps] = {};
   int memo[jumps];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
int main(){
    int n;
    cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    int count=0;

    for(int i=0;i<n;i++){
        for(int j=i+1;j<n;j++){
            if(i+jumps[j]<n){
                count++;
            }

        }
    }
    cout<<count;
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
#include<vector>
using namespace std;
void ways(int jumps[],int n,int pos,int *count){
    if(pos==n-1)
    {
        (*count)++;
    }
    if(pos<n){
        for(int k=1;k<=jumps[pos];k++)
        {
            if((pos+k)<n)
            {
                ways(jumps,n,pos+k,count);
            }
        }
    }
}
int main(){
    int n;
    cin>>n;
    int jumps[n];
    //maximum jumps from ith position
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    int count=0;
    ways(jumps,n,0,&count);
    cout<<count;
    
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int disPath(int arr[], int n, int index){
    if(n==0) return 0;
    if(n==1) return 1;
    for(int i=1; i<=arr[index]; i++){
        if((index+i)<n-1){
        return index+ disPath(arr, n, index+1);
        }
    }
}
int main(){
    int n, jumps[50];
    cin >> n;
    for(int i=0; i<n; i++){
        cin >> jumps[i];
    }
    int ans=disPath(jumps, n, 0);
    cout<< ans;
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
Memo mem;

int steps(int arr[100],int n,int ic=0){
    
    if(ic==n-1)return 1;
    if(ic>n-1)return 0;
    int m=0;
    int i=1;
    for(;i<=arr[ic] && i+ic<=n-1;i++){
        if(mem.has(i+ic)){
        m=m+mem.get(i+ic);
        }
        else
        m=m+steps(arr,n,ic+i);
    }
    mem.add(i+ic,m);
    return m;
    
}

int main(){
    
    int n;
    cin>>n;
    int arr[n];
    for(int i=0;i<n;i++)cin>>arr[i];
    int ways;
    ways=steps(arr,n);
    cout<<ways;
}

Grading criterion: Base condition
Rating A: Correctly handles the base conditions and returns 1 and 0 appropriately

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A