CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>

using namespace std;

float mysqrt(float s,float epsilon){

float x=1,x1=1; float a=2.0 ;


while(true){
              x=(x1+s/x1)/a ; x1+=epsilon ;
              
                if((x-x1)<epsilon ) break ;
                
           }
            return x ;
}

int main(){

float S,epsilon;

cin>>S>>epsilon;

cout<<fixed;

cout.precision(5);

cout<<mysqrt(S,epsilon);

}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<simplecpp>
double sqr(double s, double eps){
	double x,oldx;
	oldx = s;
	x = (oldx + (s/oldx))/2;
	while((oldx - x) > eps){
		oldx = x;
		x = (oldx + (s/oldx))/2;
	}
	return x;
}
main_program{
	double u,s,eps;
	cin >> s >> eps;
	cout << fixed;
	cout.precision(5);
	cout << sqr(s,eps);
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <simplecpp>
double mysqrt(double b, double S){
	return (b+S/b)/2.0;
}

main_program{
	long double S, x0, a, b, epsilon;
	cin>>S>>epsilon;
	x0=S;
	a=x0;
	b=(x0+S/x0)/2.0;
	while(fabs(a-b)>epsilon){
		a=b;
		b=mysqrt(b, S);
	}
	cout<<fixed;
	cout.precision(5);
	cout<<a<<endl;
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
double x,a=10,b,e;
cin>>x>>e;

while(true)
{
b=(a+x/a)/2;

if(abs(a-b)<e)break;

a=b;


}
int y=a*100000;
double t=y/100000.0;
cout<<t;

}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>

  using namespace std;

int main()    {
 int s xn;(n=>0);
  double epsilon (epsilon<=0.01);
  cin>>S>>xn; 
 {
   if (x1==x0+S/x0)
     repeat(n+1);
    cout<<"sqrt(s)=(x1-x0)x0;

  else cout"sqrt(s)=!(x1-x0)x0;

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <iostream>
using namespace std;

float getsqrt(int s,double eps){

  float result=5;
  float temp1=2, temp2=3;
  while(abs(temp1-temp2)>=eps){
    temp1=result;
    result=(result+(s/result))/2;
    temp2=result;
     }
    return result; }

int main(){
  int s;
  cin>>s;
  double eps;
  cin>>eps;
  if(s>0 && eps<=0.01){
   cout<< getsqrt(s,eps); } }

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
float sqrt(float S,float eps)
 {float x=1.0;
while (fabs(S-x*x) >eps)
{x=(x+S/x)/2;}
return x;}
int main()
{float S,eps;
cin>>S>>eps;
float root;
root=sqrt(S,eps);
cout<<fixed;
cout.precision(5);
cout<<root;}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
double S;double E;
cin>>S;//22b1009
cin>>E;
double x=1;double m;
do{
m=x;
x=(x+S/x)/2;
}while(fabs(m-x)>E);
cout<<fixed;
cout.precision(5);
cout<<x;
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
//22B1068
//square root finder
#include <cmath>
#include <iostream>
using namespace std;

double square_root(double S, double eps){
	double x1 = S / 2;
	do{
		x1 = (x1 + S / x1) / 2;
	}while(fabs((x1 - S / x1) / 2) > eps);

	return x1;

}


int main(){
	double S, eps;
	cin >> S >> eps;

	cout << fixed;
	cout.precision(5);
	cout << square_root(S, eps);


}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
void sqrt(double N,double eps,double g)
{
	double x1=g,x2=(x1+N/x1)/2;
	while(fabs(x2-x1)>eps)
	{
	x1=x2;
	x2=(x1+N/x1)/2;	
	}
	cout<<x2;
}
int main()
{
	double S,ep;
	cin>>S>>ep;
	double guess=S/2;
	sqrt(S,ep,guess);
	
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;

double sqrt( double S, double eps)
{double x=S/2;
double x1=x,x2;
x2=(x+S/x)/2;
while((x1-x2 > eps)||(x2-x1 >eps))
{ x1=x2;
  x2=(x1+S/x1)/2;}
return x1;}
 
int main() {
double S,eps;
cin>>S>>eps;
cout<<fixed;
cout.precision(5);
cout<<sqrt(S,eps);
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
#include<cmath>
#include<math.h>
using namespace std;
int main(){
	double S,epsilon;
	cin>>S;cin>>epsilon;
	double x[100000];
	x[0]=sqrt(S)+epsilon*100;
	x[1]=(x[0]+S/x[0])/2;
	int i=0;
	while((x[i+1]-x[i])>epsilon){
		x[i+2]=(x[i+1]+S/x[i+1])/2;i++;}
		cout<<fixed;
		cout.precision(5);
		cout<<x[i+1];
	}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<bits/stdc++.h>
using namespace std;
double f(double S,double epsilon)
{
double x=S/3;
while(fabs(((S/x)-x)/2)>epsilon)
{
x=(x+(S/x))/2;
}

return x;
}
int main()
{
double S;double epsilon;
cin>>S>>epsilon;
cout<<f(S,epsilon);
return 0;
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <iostream>
#include <cmath>
#include <string.h>
using namespace std;

double root (double num, double epsilon) {
 	float xa=0, xb=0;
 	xb=1;
 	while (fabs(xb - xa) > epsilon) {
	 xa=xb;
	 xb=(xb+(num/xb))/2;
	 }
	 return xa;
}

int main() {
double S=0;
double eps=0;
cin>>S>>eps;

//	 cout<<fixed;
//	 cout.precision(5);
//	 cout<<xa<<" "<<xb<<endl;
	
	cout<<fixed;
	cout.precision(5);
	cout<<root(S,eps);
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;
void  iterate(double s,double epsilon){
	int i=0;double x0=3;double x1=(double(  x0)+double ( s)/double ( x0))/2.0;
for(i=0;i<100;i++){
if(x1-x0>epsilon)
  x0=x1;
}if(x1-x0<=epsilon) cout<<x1;
 
cout<<fixed;
cout.precision(5);}
int main(){
	double  s;
	double epsilon;
	cin>>s>>epsilon;
	iterate(s,epsilon);
}

Grading criterion: Quality and number of comments
Rating A: Well Commented
Rating B: Ok Commented
Rating C: Poor or no comments
Rating D: 0
Assigned grade: C