CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main(){

	long unsigned int n,m=0,d;
	cin>>n;
	while(n>0){
	
		d = n%10;
		m = m*10; m = m + d;
		n = n - d; n = n/10;
	
	}
	
	cout<<m;

return 0;}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
int n,r,sum=0,m;cin>>n;
while(n>=1)
{r=n%10;
sum=(sum*10)+r;
n=n/10;
}
cout<<sum;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int pow(int a, int b) {
	int result = 1;
	for (int i = 0; i < b; i++) result *= a;
	return result;
}

int getLen(int n) {
	int result = 0;
	while ((n / pow(10, result)) > 0) result++;
	return result;
}

int main() {
	int n; cin >> n;
	int m = n;
	int len = getLen(n);
	int result = 0;
// *** make sure zero case is satisfied
for (int i = 1; i <= len; i++) {
	int val = 0;
	val = m / pow(10, i-1);
	val -= 10*(m / pow(10, i));
	result += val * pow (10, len - i);
}
cout << result << endl;
return 0;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
int n,num=0;
cin>>n;
int remainder;
for(int i=1;1<=n;i++){
remainder=n%10;
n/=10;
num=num*10;
num+=remainder;
}
cout<<num;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
long long int n, m=0, num; cin>>n; num=n;
while(n)
{
m*=10;
m+=(n%10);
n/=10;
}
cout<<m;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;

int main(){
	
	unsigned long long n; cin>>n; 
	unsigned long long ans = 0;

	while(n>0){
		ans *= 10;
		ans += n%10;
		n /= 10;
	}

	cout<<ans;



	return 0;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
 unsigned int n,rev;
 rev = 0;
 cin>>n;
 //First we try to find the number  of digits of  n
 int i = 0;
 int temp = n;
 while(temp!=0)
      {
       i++;
       temp= temp/10;
      }
// Now, we just take every digit of n and multiply it by a suitable power of 10 to get the reverse number
 int j = 0;
 while(n!=0)
      {
       unsigned int k = n%10;
       int l = i - j - 1;
       unsigned int m = pow(10,l);
       unsigned int p = k*m;
       rev = rev + p;
       j++;
       n=n/10;
      }
 cout<<rev;
 return 0 ;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
int numval,digit,revval=0.0;
cin >> numval;
while(numval!=0)
{
digit=numval%10;
revval=(revval*10)+digit;
numval=numval/10;
}
cout << revval;








}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main() {

	int n; cin >> n;
	int digit;
	int reverse=0;
	
	while (n>0)
	{	
		digit = n%10;
		n = n/10;
		reverse = (reverse*10)+digit;
	}
	
cout << reverse;	
	}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
# include <iostream>
# include <cmath>
using namespace std; 
int main(){
long int n;
cin>>n;
int digit,rev=0;
while (n!=0){
digit=n%10;
rev=(rev*10)+digit;	
n=n/10;			  
}
cout<<rev;	
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int pow(int m,int n){
int i,z=1;
  for(i=1;i<=n;i++){
  z=z*m;
  }
return z;
}
int numdigits(int N){
int i,r;
  for(i=1;i>0;i++){
  r=(N%pow(10,i));
  if(r==N){break;}
  }
return i;
}
int p(int N,int p){
int l=(N%pow(10,p)-N%pow(10,p-1))/pow(10,p-1);
return l;
}
int main(void){
int N,k,i,j;
cin>>N;
k=numdigits(N);
  for (i=1;i<=k;i++){
  if(p(N,i)==0){continue;}
  else if(p(N,i)!=0){break;}
  }
if(i==k+1){cout<<0;}
else{
for(j=i;j<=k;j++){
cout<<p(N,j);
}
}
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
unsigned int n;
cin>>n;
int z=0;
while(1){
int k=n%10;
z=z*10+k;
n/=10;
if(n==0) break;
}
cout<<z;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
long long int T;
cin>>T;
int k;
k=T%10;
if (k==0)T=T/10;
else {cout<<k;
      T=T-k;
      T=T/10;}
while(T>0){
k=T%10;
cout<<k;
T=T-k;
T=T/10;}
return 0;}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
	int n;
	cin>>n;
	while(n>0){
		if(n%10!=0){break;}
		n=n/10;
	}
	while(n>0){
		cout<<n%10;
		n=n/10;
	}
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;

int main(){
	long int n = 0;

	cin >> n;
	for (int x = 0; n != 0;){
		if (n%10 != 0 || x != 0){
			cout << n%10;
			x++;
		}
		n = n/10;
	}

	return 0;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main (){
int n;
cin>>n;
int r=0;
int m=0;
if (n==0) {
cout<<"0";
}
while(n!=0){
r=n%10;
n=n/10;
m=(m*10)+r;
}
cout<<m;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
	int n, m, i, reverse_num=0;
	cin>>n;
	while(n !=0){
		reverse_num = 10*reverse_num + (n%10);//adds the last digit of updated no. to reverse_num 
		n=n/10;
	}
	cout<<reverse_num;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n, rev=0, digit;
cin >> n;
while (n%10!=0){
digit=n%10;
rev=rev*10+digit;
n=n/10;
}
cout << rev;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n;cin>>n;
while(n%10==0)n=n/10;
while(n/10!=0){
cout<<n%10;
n=n/10;


}
cout<<n%10;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
int n,x;
cin>>n;
while(n>0)
{
x=n%10;
n=(n-x)/10;
cout<<x;
}
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m=0;
cin >> n;
float val1=n;
int val2=n,dig=0,temp;
do { dig+=1;
     val1=val1/10;}while(val1>=1);
for (int i=1;i<=dig;i++){
 temp=val2%10;
 if (temp!=0){
            for(int j=1;j<=(dig-i);j++){temp=temp*10;}
            m=m+temp;}
 val2=int(val2/10);
 }
cout << m;





}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream> 
using namespace std ;
int main (){

	int n ;
	cin >> n ;
	do  {
	if (n%10!=0) break ;
	n=(n-n%10)/10;
	}
	while (n%10==0);
int x=0;
	do {
	int a=n%10 ;
	n=(n-a)/10 ;
	x=x*10+a;
	}
	while (n!=0) ;
	cout << x;
	return 0 ;
	}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,i;
cin>>n;
while(n/10!=0){
i=n%10;

n=n/10;
if(i!=0)
cout<<i;
}

cout<<n;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
unsigned long long int n;
cin>>n;
for(int i=n%10;i==0;i=n%10)n=n/10;
for(int p=n;p!=0;p=n/10){int t=n%10;cout<<t;n=n/10;}
if(n!=0)cout<<n;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main()
{int m=0, n;
cin>>n;
if (n==0) cout<<0;
else{
	int l, j=1;
	for (int i=0; ; ++i)
	{	if (floor(n/j)==0) break;
		j*=10;
		l=i+1;
	}
	j=1;
	int a=1, d;
	for (int p=0;p<(l-1); ++p) a=a*10;
	for (int g=0; g<l; ++g)
	{	d=(n%(j*10)-n%j)/j;
		m=m+ d*a;
		a=a/10;
		j*=10;
	}
	cout<<m;
}
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>

main_program{
	unsigned long long int n;
	cin >> n;
	unsigned long long int i = 0;
	while (n>0){
		i = i*10 + n%10;
		n=(n-n%10)/10;
	}
	cout << i;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
int n;
cin>>n;
while(n%10==0){
n=n/10;}
do{
cout<<n%10;
n=(n-(n%10))/10;}
while(n!=0);
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,m,i,NumDig,a,j;
cin>>n;
i=0;
a=n;
m=0;
while(a!=0)
{
a=a/10;
i++;
}
a=n;
for(j=1;j<=i;j++)
{
NumDig=a%10;
m=NumDig*pow(10,(i-j))+m;
a=a/10;
}
cout<<m;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n;
cin >> n;
int digits = log10(n)+1;
int d = 0; int f = 0;
for (int i = 0; i < digits && d==0; i++)
{
int r = pow(10,i+1);
d = (n%r)/pow(10,i);
f = i;
};
for (int i = f; i < digits; i++)
{
int r = pow(10,i+1);
d = (n%r)/pow(10,i);
cout << d;
};
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>

int main(){
using namespace std;
int m,i=0,n,k=0,dig=1;
cin >> n;
m=n;

while(m>0){
m=n;
m=m/pow(10,dig);
dig=dig +1;
}
dig=dig-2;

while(dig>=0){
i=n%10;
n=(n-n%10)/10;
k=k+i*pow(10,dig);
dig--;
}
cout<<k;
return 0;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
        long long int n, m=0;
        cin>>n;
        while (n>0){
                m=m*10+n%10;
                n=n/10;
        }
        cout<< m;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <simplecpp>

main_program{
	long long int n = 0, sum = 0;
	cin >> n;
	long long int copy = n;
	int rem = 0;
	while(copy%10 == 0){
		copy /= 10;
	}
	while(copy>0){
		rem = copy%10;
		sum = (sum +rem)*10;
		copy/=10;
	}
	sum/=10;
	cout << sum;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
	unsigned int n; cin>>n;
	unsigned int N;
	int i=0;
	N=n;
	while(N>0)
	{
	N/=10;
	i++;
	}
	int rem,j;
	unsigned int m=0;
	while(n>0)
	{
	rem=n%10;
	n/=10;
	m+=rem*pow(10,i-1);
	i--;
	}
	cout<<m;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: C
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
#include <cmath>
using namespace std;
int main(){
int n,m=0;
cin>>n;
int i=0;
int k=0;
while(n/10 !=0){
	k=n%10;
	n=n/10;
	m= 10*m+k;
	i++;
		}
cout<<m*10+n;
}

Grading criterion: Quality and number of Comments
Rating A: Well Commented and Formatted
Rating B: Ok Commented or Ok Formatted
Rating C: Poor Comments and Formatting
Rating D: 0
Assigned grade: B