CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
        int n,k;
        cin>>n;
        for(int i=1;i<=n;i++){
                if (i*(i+1)/2>=10) cout<<i*(i+1)/2<<" ";
                else cout<<"0"<<i*(i+1)/2<<" ";
                k=i;
                for(int j=1;j<n+1-i;j++){
                        int a= i + k*(k+1)/2;
                        if(a>10) cout<<a<<" ";
                        else cout<<"0"<<a<<" ";
                        k++;
                }       
                cout<<endl;
        }       
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
//Including simplecpp in our program
#include<simplecpp>

//Writing our main program
main_program{
    //Creating variables
    int n,k,j,i,p;
    //Input of the side of triangle you want
    cin >> n;
    //Assigning initial values to each variable
    k = 1;
    j=1;
    i = 1;
    p=1;
    //Creating a loop for each line
    repeat(n){
        //Output of first integer on every line
        if(p<10){
        cout << 0 << p << " ";
        }
        else cout << p << " ";
        // Assigning a new variable to complete the line
        j = p;
        //Reassigning the difference between the first 2 terms on every line
        i=k;

        //Output of a horizontal line
        repeat(n-1){
            j+= i;
            i++;
            if(j<10){
            cout << 0 << j << " ";
            }
            else cout << j << " ";
    }
    //Creating a new line
    cout << endl;
    /* Increasing difference between the first 2 terms on every line,
    and the difference between the first terms of 2 consecutive lines */
    k = k+1;
    //Assigning value of first term of every horizontal line
    p += k;
    //Decreasing the length of each line by 1
    n = n-1;

    }


}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>

main_program{
        int n;
        cin >> n;
        int k = 1;
        for(int i = n; i>=1; i--){
                for(int j = 1; j<=i; j++){
                        int a;
                        a = (pow(j,2)/2.0) + (((2*k)-3)/2.0)*j + (pow(n+1-i,2) + (n+1-i))/2.0 + (1-k);
                        if(a<10) cout << "0" << a << " ";
                        else cout << a << " ";
                }
                cout << endl;
                k++;
        }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
        int n,n0,out=1,i=1,k=1,next=1,inc=2,a=0,m=0;
        cin>>n;
        n0=n;
        while(i<=n0){
                 a=a+m;
                out=next;
                next=next+inc-1;
                while(k<=n){
                          out=out+a;
                          if(out<10){cout<<"0";}
                         cout<<out<<" ";
                         a++;
                         k++;}
                k=1;
                a=0;
                m++;
                cout<<endl;
                n--;
                inc++;
                i++;
        }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
	int n;
	cin>>n;
	int a=0,j=0,k=1;
	int newn;
	
	int b=n;
repeat(n)
 {
	 int a=0;
		newn=(k*k+k)/2;
		repeat(b)
		{
		int m=newn+a;
		if(m<10)
			cout<<0<<m<<" ";
		else cout<<m<<" ";
		newn=m;
		a=a+1+j;
		}
		cout<<endl;
		k=k+1;
		j=j+1;
		b=b-1;
			
	}
	}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include <simplecpp>
main_program{
    int n;
    cin >>n;
    int l=1;
    int first =1,c=7;
    int b=n;
    int i=1,k=1;
    while(i<=n){
        int c=first;
        while(k<=b){
            if(c<10){
                cout << '0' << c<< ' ';
            }
            else{
            cout <<c<<' ';}
            c=c+l;
            k=k+1;
            l=l+1;
        }
        k=1;
        cout << endl;
        first =first + i+1;
        l= i+1;
        i=i+1;
        b=b-1;

    }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program{
    int n;
    cin >> n;
    for(int i =1;i<=n;i++){
        if(((i*i+i)/2)<9){
            cout <<"0"<<(i*i+i)/2<<" ";
        }
        else{
        cout << (i*i+i)/2 << " ";
        }
	    int d =i;
        for(int j=2;j<=n+1-i;j++){
           int Tr = ((i*i)+i)/2 + d;
           d=(j*j+(2*i-1)*j)/2;
           if(Tr>9){
           cout << Tr << " ";
        }
        else if(Tr<=9){
        cout <<"0"<<Tr<<" ";
        }
        }
        cout <<endl;
    }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include <simplecpp>
main_program{
    int n,sum; cin >> n;
    for (int i=1;i<=n;i++){
        for (int j=1;j<=(n-i+1);j++){
            sum=(j*j+(2*i-3)*j+(2+i*(i-1)))/2;
            if (sum<10) cout << '0';
            cout << sum << ' ';
        }
        cout << endl;
    }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
main_program
{
        int n;
        cin>>n;
        int l =n,k=1,f;
        int r=1, d1=1, d2=1;
        for (int j =n; j>=1;j--)
        {
                for(int i=l; i>=1; i--)
                {
                        if(i==l)
                        {
                                f=r;
                        }
                        if(r<10)
                        {
                                cout<<"0";
                        cout<<r;
                        }
                        else
                                cout<<r;
                        cout<<" ";
                        r=r+d1;
                        d1++;
                }
                cout<<endl;
                l--;
                k++;
                d1=k;
                r=f+k;
        }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include<simplecpp>
void print(int start){
        if (start < 10){
                cout << "0" << start;
        } else {
                cout << start;
        }
        return;
}
main_program{
        int n;
        int a = 1;
        int start = 1;
        int diff = 1;
        cin >> n;
        while(n){
                int x = start;
                print(x);
                int d = diff;
                cout << " ";
                repeat(n-1){
                        x = x + d;
                        print(x);
                        cout << " ";
                        d++;
                }
                diff++;
                a++;
                start = start + a;
                n--;
                cout << endl;
        }
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A
Problem: You are tasked with creating a special numbering pattern for a triangular grid of side length n.

The triangle is formed using rows such that:
- The first row has n elements.
- The second row has n - 1 elements.
- The third row has n - 2 elements.
- ...
- The last row has 1 element.

Your job is to fill this triangular grid with integers starting from 01, following a unique diagonal numbering pattern.

Numbering Rules

1. Start from the top-left element of the triangle with 01.
2. Fill the numbers diagonally downward while moving to the right.
3. Each diagonal starts from the top row and moves down toward the bottom-left of the triangle.
4. Filling must stay within the valid triangular bounds.

Hint

In each row, the difference between two consecutive entries increases by 1 with each step. The same rule applies to each column.

Input

An integer n, representing the side length of the triangle.

Output

Print n lines.
The i-th line contains n - i + 1 integers corresponding to the i-th row of the triangle.

Assumptions on Input

1 <= n <= 13

Note

- Do not print any extra messages such as:
  cout << "Enter a number"
  cout << "The computed answer is"
- Use cout only to print the computed final output.
- Do not print unnecessary spaces.
- Do not hard-code the solution.
- If any test case passes by simply printing with cout and without logic, marks will not be awarded.

Student submission:
#include <simplecpp>
main_program{
	int n;
	int x =0;
	int temp_x = 0;
    int c =1;
	cin >> n;
	for(int i = 1; i <=n;i++){
		x = temp_x+i;
		
		for(int j =c; j<=n; j++){
			if(x<10){
				cout<<"0"<<x<<" ";
			}
			else{cout<<x<<" ";}
			x = x+j;
		}
		temp_x = temp_x+i;
		cout <<endl;
        	c++;
	}
}

Grading criterion: Accepting input
Rating A: correctly accepts an integer as input
Rating B: Some issue. 

Rating C: Major issue. 

Rating D: 0
Assigned grade: A