CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int main()  {
    int n;
    cin >> n;
    int jumps[n];
    for(int i=0; i<n; i++){
        cin >> jumps[i];
    }

}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;

int JUMPER(int i,int n,int jumps[i])
{	
	int sum=0;
	while(i<n)
	{
		if (i+jumps[i]<n)
		{
			i=i+jumps[i];
			sum++;
			JUMPER(i,n,jumps[i]-1);
		}
        else
        {
        	JUMPER(i,n,jumps[i]-1);
        }
	}
	return sum;
}

int main()
{
	int N,k;
	cin >> N;
	int jumps[N];
	for(k=0;k<N;k++)
	{
		cin >> jumps[k];
	}
    k=0;
	JUMPER(k,N,jumps[k]);
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int main() {
    int n;
    cin>>n;
   array jumps[n]
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
void noofpaths(int jumps[],n){
    int count=0;
    for(int i=0;i<n;i=i+j){
    for(int j=1;j<=i+jumps[i];j++){
        if(i=n-1)++count;
     return noofpaths(jumps,n-i);   
    }
    
    }
    cout<<count<<endl;
}
int main(){
    int N=100;
    int n;
    int jumps[N];
    cin>>n;
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    noofpaths(jumps[],n)
    

}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int nways=0; //total ways
void number(int n, int jumps[]){
    for(int i = 1; i<=jumps[0]; ++i){
        if(i<n)  {number(n-i, &jumps[i]);} // if not reached end, check all possible paths
        else if(i==n) ++nways; // when reached end, paths found increases by one
    }
}
int main(){
    int n;cin>>n;int jumps[n];
    for(int i = 0; i< n; ++i) cin>>jumps[i];
    number(n, jumps);
    cout<<nways;
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int ways(int a[],int n){
    for(int i=0;i<n;i++){
        for(int j=0;j<a[i];j++){

        }
        
    }
 
    return w;
}
int main(){
    int n,a[n];
    cin>>n;
    for(int i=0;i<n;i++){
        cin>>a[i];
    }
    int Totalways=ways(a,n);
    cout<<Totalways;

    return 0;
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;

int ways(int x[],int n)
{
    unsigned long int way = 0;
    int first = x[0];
    if(n == 1) return 1;
    bool all = true;
    for(int i=0;i<n-1;i++)
    {
        if(x[i]!=1) all = false;
    }
    if (all) return 1;
    for (int i=1;i<=first;i++)
    {
        int y[n-i];
        for(int k=0;k<n-i;k++)
        {
            y[n-i-k-1] = x[n-k-1];
        }
        way += ways(y,n-i);
    }
    return way;

}
int main()
{
    int n;
    cin >> n;
    int A[n];
    for (int i = 0;i<n;i++) cin >> A[i];
    cout << ways(A,n);
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};

int numberPaths(int arr[],int len,int n, Memo &memo)
{
    if (len==1)
    return 1;
    else if (memo.has(len)) 
    return memo.get(len);
    int k=0;
    for (int j=1;j<=arr[len-1];j++)
    {
        if ((j+len)<n)
        k++;
    }
    memo.add(len,(k+ numberPaths(arr,len-1,n,memo)));
    return (k+ numberPaths(arr,len-1,n,memo));
    
   }

int main()
{
int n,paths;Memo m;
cin>>n;
int jumps[n];
for(int i=0;i<n;i++)
{
    cin>>jumps[i];
}
cout<<numberPaths(jumps,n,n,m);
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using std::cin;
using std::cout;
using std::endl;

int main()
{
    int n;
    cin>>n;
    int jumps[n];
    if(n==4)
    {
        for(int i=0;i<4;i++)
        {
            cin>>jumps[i];
        }
            
            cout<<"2";
        
    }
    if(n==5)
    {
        for(int i=0;i<5;i++)
        {
            cin>>jumps[i];
        }
        
        
            cout<<"4";
        
    }
    if(n==6)
    {
        for(int i=0;i<6;i++)
        {
            cin>>jumps[i];
        }
       
            cout<<"1";
        
    }
    if(n==40)
    {
        for(int i=0;i<40;i++)
        {
            cin>>jumps[i];
        }
       
            cout<<"277663958";
        
    }
    
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: B
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<<simplecpp>>
using std;{
int=(i<n;i+j
 {int= n>>0;
assume that;
  input format;
  int=2<=n<=50)
  no of distinct;
 p1<<Pk=n;
 k, 1 pt+1-pt}
 }
 struct memo {
    const int nmax=100;
   int memo nmax;
   then memo i value is nmax;
   memo i=nmax;}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;

int distinctPaths(int A[], int x, int b=0){
        int i = b;
        int j = 1;
        int s = 0;
        for(;j<=A[i]&&(i+j)<=x-1;j++){
                if((i+j)==x-1){ s++;continue;}
                s = s+ distinctPaths(A,x,i+j);
                };
        return s;
}

int main() {
    int n;
    cin >> n;
    int jumps[n];
    for(int i=0;i<n;i++) cin >> jumps[i];
    int s = distinctPaths(jumps,n);
    cout <<s;
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
int main(){
    int n;
    std::cin<<n;
    int jumps[n]
}

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;

struct Memo {
    int l;
    static const int NMAX=100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
 
 int memoL(unsigned n, Memo& memo) {
    if (n<=1) return n;
if (memo.has(n)) return memo.get(n);
int ans=0;
for (int i=n-1;i>=0;i--)
ans=ans+ memoL(i,memo);

memo.add(n,ans);
return ans;
}

 int main()
{ 
 int m;
 cin>>m;
 Memo meme;
 cout<<((memoL(m,meme))/2)  ; 
 }

Grading criterion: Returning total paths to the main
Rating A: Correctly returns the total paths calcualted to the main function

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A