CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int countWays(int jumps[]){
    if()
}
int main(){
    int n;
    cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++){
        cin>>jumps[i];
    }
    int count=countWays(jumps)
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};
int way(int n,int i,int jumps[],Memo& memo){
    if(memo.has(n)){
        return memo.get(n);
    }
    int ans=0;
    if(n-i==1){
        return 1;
    }
    else if(i>n-2){
        return 0;
    }
    else{
        int j=i+1;
        int f= i+jumps[i];
        while(j<=f){
            ans+= way(n,j,jumps,memo);
            j+=1;
        }
        memo.add(n,ans);
    }
    return ans;
}
int main(){
    int n;
    cin>>n;
    int arr[n];
    Memo memo;
    for(int i=0;i<n;i++){
        cin>>arr[i];
    }
    cout<< way(n,0,arr,memo);
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   unsigned long long int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, unsigned long long int val) {
       memo[i] = val;
       filled[i] = true;
   }
};

unsigned long long int f(int n, Memo& memo, int arr[]){
    if (memo.has(n)) return memo.get(n);
    unsigned long long int ans =0;
    int k=min(8,n);
    for (int i=1;i<=k;i++){
        if (arr[n-i]>=i) {ans += f(n-i,memo,arr);}
    }
    memo.add(n,ans);
    return ans;
}

int main(){
    Memo memo;
    memo.add(0,1);
    memo.add(1,1);
    int n; cin >> n;
    int jumps[n];
    for (int i=0; i<n;i++) cin >> jumps[i];
    cout <<f(n,memo,jumps);
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;

int main () {
    int n;
    cin >> n;
    int jumps [n];
    for (int a=0; a<i; a++){
        cin>> jumps [a];
    }
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;

int ways(int n ; int arr[n]; int i=0)
{
    int j=0;
    int sum=0;
    while (sum<=n)
    {
        if (i+j<n)
        {
            sum=arr[i]+arr[i+j];
            j++;
        };
        if (sum==n)
        a=a+1;
    };
    return a + ways(int n ; int arr[n]; i++)
};
int main()
{
    int n;
    cin>>n;
    int a[n];
    for(int i=0;i<n;i++)
    cin>>a[i];
    int no_of_ways = ways(n ; a[n]; int i=0);
    cout<<no_of_ways;
    return 0;
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using std::cout; using std::cin; using std::endl;
int main() {
char c, vowels[] = {'a', 'e', 'i', 'o', 'u'}; // initialising explicitly
int N[5] = {}; // initialising all elements to 0
for(cin >> c; c >= 'a' && c <= 'z'; cin >> c)
for (int i=0; i<5; i++)
if(c == vowels[i]) {
N[i]++; break;
}
for (int i=0; i<5; i++)
cout << "#" << vowels[i] << " = " << N[i] << (i==4?"":", ");
cout << endl;
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
 void path(int jumps[],int i,int target,int& sum){
    if(i==target){
        ++sum;
        return ;
    }
    if(i>target){
        return ;
        
    }
    int possible=jumps[i];
    for(int j=1;j<=possible && i+j<=target+1;j++){

     path(jumps,i+j,target,sum);
    }
    
}
int main(){
    int n;
    cin>>n;
    int jumps[n],sum=0;
    for(int i=0;i<n;i++){
        cin>>jumps[n];
    }
    path(jumps,0,n-1,sum);
    cout<<sum<<endl;
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
 
  
    struct paths {
   static const int n;
   bool jumps[n] = {};
   bool has(unsigned i) { return filled[i]; }
   
};
int main(){
    cin>>n;
    for(int i=0;i<=n;++i){
        for(int j=0;i+j<=n;j++){
            
        }
    }
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int noj(const int jumps[], int i, int n)
{   int count;
    if(i==n)
    return 1;
    for(int j=1;j<=jumps[i-1];j++)
    {
    int &ur=count;
    if(i+j<=n)
    {
        ur+=noj(jumps, i+j, n);
    }
    

    }
    return count;
}
int main()
{
    int n; cin>>n;
    int jumps[n];
    for(int i=0;i<n;i++)
    cin>>jumps[i];
    cout<<noj(jumps,1,n);
}
struct Memo {
   static const int NMAX = 100;
   bool filled[NMAX] = {};
   int memo[NMAX];
   bool has(unsigned i) { return filled[i]; }
   int get(unsigned i) { return memo[i]; }
   void add(unsigned i, int val) {
       memo[i] = val;
       filled[i] = true;
   }
};

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int jumps[n];
    int i;
    for(i = 0;i<n;i++){
        cin>>jumps[i];
    }
    int distinctpaths = 0;
    for(i = 0;i<n;i++){
        for(int j = 1; j<=jumps[i];j++){

            if(i+j<=n){
                distinctpaths++;
            }
        }
    }   
           cout<<distinctpaths;  
       }

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;
int tdp (int i, int n, int jumps[]) {
    int j;
    int count=0;
    while (j>=1 && j<=jumps[i]) {
    tdp(i+j, n, jumps [n-j]);
    count ++;
    }
    return count;
}
int main() {
    int n;
    cin>>n;
    int jumps [n];
    for (int i=0; i<n; i++) {
        cin>>jumps [i];
    }
    cout<< tdp (0, n, jumps)<<endl;
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: C
Problem: You are given a game consisting of n positions arranged in a line from index 0 to n-1. From each position i, you are given a number jumps[i] which represents how far you are allowed to jump forward from that position.

Your task is to compute how many valid ways exist to reach the last position starting from position 0, following the rules below.

Rules

1. You start from position 0.
2. From position i, you may move to any position j such that:
   j > i and j - i <= jumps[i].
3. You may only move forward.
4. A path is considered valid if you can reach the last position (n-1) using the allowed jumps.

The program uses a recursive function to count all such valid paths.



Input Format

- An integer n representing the number of positions.
- n integers representing the array jumps, where jumps[i] indicates the maximum jump length from position i.



Output Format

- Print the total number of valid ways to reach the last position starting from index 0.



Constraints

- 1 <= n <= 1000  
- 0 <= jumps[i] <= n  



Explanation

The recursive function works backward and checks whether a position can reach the end based on the jump limits. If a position can reach the target, it contributes to the total count of paths.

Student submission:
#include <iostream>
using namespace std;
struct Memo {
    static const int NMAX = 100;
    bool filled[NMAX] = {};
    int memo[NMAX];
    bool has(unsigned i) { return filled[i]; }
    int get(unsigned i) { return memo[i]; }
    void add(unsigned i, int val) {
    memo[i] = val;
    filled[i] = true;
    }
};
unsigned int ways(int idx, int n, int jumps[], Memo & memo)
{
    
    if (memo.has(idx)) 
    {
    return memo.get(idx);
    }
    else
    {
        if(idx == n)
        {
            memo.add(idx,1);
            return 1;
        }   
        int way_s=0;
        for(int i =1; i<=jumps[idx]; i++)
        {
            if(idx + i<=n)
            {   
                way_s += ways(idx+i,n,jumps,memo);
            }
            else
            break;
        }
        memo.add(idx,way_s);
        return way_s;
    }
}
int main()
{
    int n;
    cin>>n;
    int jumps[n];
    for(int i =0; i<n ; i++)
    {
        cin>>jumps[i];
    }
    Memo memo;
    cout<< ways(0,n,jumps,memo);
}

Grading criterion: Output
Rating A: Correctly prints the output

Rating B: Some issue
Rating C: Major issue
Rating D: 0
Assigned grade: A