CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,c,s=0,r;
cin>>n;
c=n;
while(n>0){
r=n%10;
s=r+s*10;
n=n/10;}
cout <<s;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
    int n,a,b,c,d,m;
    cout<<"integer";cin>>n;
    n=1000*a+100*b+10*c+d;
    m=1000*d+100*c+10*b+a;
    cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;

int main()
{
int n;
cin>>n;
int p = 0;
while(n>0)
{
p*=10;
p+= (n%10);
n /= 10;




}
cout<<p;














return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
	int n,temp;
	cin >> n;
	temp = 0;
	while (n>0){
		temp *= 10;
		temp += n%10;
		n/=10;
	}
	cout << temp;
	return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,num,rem,m=0;
cin>>n;
num=n;
while(num>0){
rem=num%10;
num=num/10;
m=10*m+rem;
}
cout<<m;
return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

int main()
{
long long int n;
cin>>n;
long long int nn=n;
int c=-1;
long long int d=0;
while (n!=0)
{n=n/10;
c++;
}
while(nn!=0)
{d=d+(nn%10)*pow(10,c);
c--;
nn=nn/10;
}
cout<<d;;
return 0;

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
int n;
int  x1,x2,x3,x4;
cin>>n;
x1=(n%10);
x2=(n%100)/10;
x3=(n%1000)/100;
int y1=floor(x1),y2=floor(x2),y3=floor(x3),y4=floor(x4);
cout<<y1<<y2<<y3<<y4;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
	int n,m=0;
	cin>>n;
	while (n!=0){
		m=m*10+n%10;
		n=n/10;
	}
	cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m=0,t;
cin>>n;
while(n>0){
t=n%10;
m=m*10+t;
n=n/10;}
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int power (int d){
	int j=1;
	for (int i=0; i<d;i++)
	  j=j*10;
	
	return j;
}
int main ()
{
	int n,a,b,c;
	cin >> n;
	a=1;
	b=0;
	c=1;
	while (n/a>0)
	{
		a=a*10;
		b++;
	}

	while (c<=b)
	{  
		if (c==1&& (n%power(c))*10/power(c)==0)
		{ while ((n%power(c))*10/power(c)==0){
			c++; 
		}
		}
		cout<< (n%power(c))*10/power(c);
		c++;
	
	}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
 int n,m=0;
 cin >> n;
 while(n!=0)
 {
  m=m*10+n%10;
  n/=10;
 }
 cout << m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
	int digits=1,n;
	cin >> n;
	int n1;
	n1=n;
	while((n/10)!=0){
		digits++;
		n=n/10;
	}
	int ans=0;
	while(n1!=0){
		int q=0;
		q=n1%10;
		for(int i=0;i<digits-1;i++){q=q*10;}
		digits--;
		ans=ans+q;
		n1=n1/10;
	}
	cout << ans;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m,mn=0;
cin>>n;
while(n>0){
m=n%10;
n=n/10;
mn=mn*10+m;
}
cout<<mn;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>

using namespace std;

int main(){

int n;
cin >> n;
while(n%10==0){n=n/10;}
while(n>0){
cout<< n%10;
n=n/10;
}

}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include <cmath>
using namespace std;
int main(){
int n,m;
cin>>n;
m=n;
int i,d,j,s;
s=0;
for(j=0;m>0;j++){m=m/10;}
int l;
l=j;
for(i=0;i<l;n/=10,i++,j--)
{d=n%10;
s=s+d*pow(10,(j-1));}
cout<<s;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int number,remainder,reverse=0;
cin>>number;
while(number>0) {
 remainder=number % 10;
 reverse=reverse*10+remainder;
number=number/10;
}
cout<<"reverse="<<endl;
return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

int main(){
int n,m=0;
cin>>n;
while(n>0)
{
int a=(n%10);
m=m*10+a;
n=((n-a)/10);
}
cout<<m;
return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;

int main(){
	int n,rem = 0,m = 0;
	cin>>n;
	while(n%10!=n){
		rem =  n%10;
		m = m + rem;
		m = m*10;
		n = n/10;
	}
	m = m + n;
	cout<<m;
	
	return 0;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int m,a=0,b;
cin>>m;
while(m!=0){
b=m%10;
a=a*10+b;
m=m/10;
}
cout<<a;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n,m=0;
cin>>n;
while((n%10)==0){
n=n/10;
}
while(n>0){
m=m*10+n%10;
n=n/10;
}
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
int main()
{
int a, b, c, d; 
cin>>a>>b>>c>>d;
a=d;
b=c;
c=b;
d=a;	
cout<<a<<b<<c<<d;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
int n;
int m=0;
cin>>n;
if(n>0){
int i;
int k;
for(i=1;;i++){
k=n%10;
m=10*m+k;
n=n/10;
if(n==0){break;}
}
cout<<m;
}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
#include<cmath>
int main(){
int m,l,avg=0,q,k,j,i,p,n,o;
cin>>m;
n=((log(m))/(log(10)))+1;
p=1;
while(p<=m){
 j=(m/p)%10;
if(j!=0)cout<<j;
p*=10;} }

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
#include<cmath>

int main()
{
int n,a=1;
cin >> n;
int m =n;
while(m/10 !=0 )
{
m=m/10;
a++;
}
int j= a-1;
int d= n/(pow(10,j));
int k=0,i=0;
while(i<j)
{
int c =n/(pow(10,i));
int num = (c%10)*(pow(10,j-i)); 
k += num;
i++;
}
cout << k+d;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
long long int n, reverse=0,length,i=0,remainder;
cin>>n;

length=to_string(n).length();
while(i<length){
reverse=reverse*10;
remainder=n%10;
reverse=remainder+reverse;
n=n/10;
i+=1;
};
cout<<reverse;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main()
{
int n;
cin>>n;
while(n>0)
{
int m=n%10;
  n=n/10;
  if(m==0) continue;
  cout<<m;
}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
int x=0;
int ans=0,n,b,i=0;
cin>>n;
while(true){
i++;int q=pow(10,i);b=n%q;
		if(b==n)break;}

for(int j=1;j<i+1;j++){
int q=pow(10,j);
int digit;
int l=pow(10,j-1);
int x=n%l;
digit=(n%q)-x;
digit=digit/l;
int d=i-j;
int w=pow(10,d);
ans=ans+(digit*w);
}
cout<<ans;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>
main_program{
	int n,digit,reverse=0,temp;
	temp=n;
	cin>>n;
	while(n>0){
		digit=n%10;
		reverse=reverse*10+digit;
		n=n/10;
	}
	cout<<reverse;
	
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>

using namespace std;

int main()
{
int n;
cin >>n;
int m =0;
while (n != 0)
{
m = m*10 + (n%10);
n/=10;
}
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include <iostream>
using namespace std;
int main(){
int a,num_of_digits=0,i=1,n,j=0;
cin >>n;
while (n>=i){
i*=10;
num_of_digits++;
}
for (j=0;j<num_of_digits;j++)
{
a=n%10;
n/=10;
cout<<a;
}
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
using namespace std;
int main(){
int n; cin>>n;
int m=0;
int k;
k=n%10;
int j;
m=m+k;
n=n-k;
for(int i=10;n-(n%i)!=0;){
j=n/i;
k=j%10;
m=m*10+k;
j=j-k;
n=j;
}
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<simplecpp>

main_program{
int n,m=0,flag=1;
cin>>n;
if (n==n%10){
	 m=n;
	 flag=0;}
 while (flag){
	 m=m*10+n%10;
	 n=n-n%10;
	 n=n/10;
	 if (n==n%10){
		 m=m*10+n%10;
		 break;}
 }	
cout<<m;
}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: Write a C++ program that takes a positive integer n as input from the user and prints a number m whose digits are in reverse order as compared to n. If the number ends in one or more zeroes, then those zeroes should be ignored while printing the reverse.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
int main(){
	int n;
	cin>>n;
	int m=0;
	while(n>0){
	int remainder = n%10;
	n=n/10;
	m =m*10+remainder;
	}
cout<<m;}

Grading criterion: Placeholder for extra marks to be given for any reason
Rating A: Modularity, Extra Functions Defined, some corrective marks for failed testcases
Rating B: No reason for extra marks
Rating C: 0
Rating D: 0
Assigned grade: B