CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
#include<vector>

int checkADNB(int A[],int n){
    int i=1;
    for (;i<n;i++){
        if(A[i-1]>=A[i])
        break;
    }
    if (i>>1&&i<<n)
    return 2;
    else if(i==n)
    return 1;
    else if (i==1){
        int j =1;
        for (;j<n;j++){
        if(A[j-1]<=A[j])
        break;
    }
    if (j==n)
    return 3;
    if (j==0)
    return 4;
    }
}


int main()
{
    int n;
    cin>>n;
    int A[n];
    for(int i=0;i<n;i++){
        cin>>A[i];
    }
    for (int j=0;j<n;j++){
        cout<<A[n-j-1]<<" ";
    }
    cout<<endl;

    if (checkADNB(A,n)==1)
    cout<<"A";
    else if(checkADNB(A,n)==2)
    cout<<"N";
    else if (checkADNB(A,n)==3)
    cout<<"D";
    else if(checkADNB(A,n)==4)
    cout<<"B";

}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
#include <vector>
using namespace std;
int main() {
    int n; cin >> n;
    vector <int> v(n);
    bool flag[3]={true,true,true};
    char out[3]={'B','A','D'};
    cin >> v[0];
    for (int i=1;i<n;i++) {
        cin >> v[i];
        if (v[i]!=v[i-1])
            flag[0]=false;
        if (v[i]<v[i-1])
            flag[1]=false;
        if (v[i]>v[i-1])
            flag[2]=false;
    }
    for (int i=n-1;i>=0;cout << v[i--]<<" ");
    cout << "\n";
    for (int i=0;i<3;i++) {
        if (flag[i]) {
            cout << out[i];
            return 0;
        }
    }
    cout << 'N';
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
void checkcases( int n, int arr[]){
    bool A,B,D;
}
int main(){
    bool A,B,D;
    int n;
    cin>>n;
    int arr[n];
    for(int i=0;i<n-1;i++){
        if (arr[i]!=arr[i+1]){
            B=false;
        }
        if(arr[i]<arr[i+1]){
        D=false;
        }
        if(arr[i]>arr[i+1]){
            A=false;}
        }
        if(A){cout<<"A";}
        if(B){cout<<"B";}
        if(D){cout<"C   ";}}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: B
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n ;
    cin>>n;
    int nums[n];
    for(int i=0;i<n;i++){
        cin>>nums[i];
    }
    for(int i=n-1;i>=0;i--){
        cout<<nums[i]<<" ";
    }
    int a= 0;
    int b= 0;
    int c=0;

    for(int i=0;i<n-1;i++){if(nums[i]==nums[i+1]){
        a++;
    }}
     for(int i=0;i<n-1;i++){if(nums[i]>nums[i+1]||nums[i]==nums[i+1]){
        b++;
    }} for(int i=0;i<n-1;i++){if(nums[i]<nums[i+1]||nums[i]==nums[i+1]){
        c++;
    }}

    if(a++==n-1){cout<<endl<<"B";}
     else if(b++==n-1){cout<<endl<<"D";}
     else if(c++==n-1){cout<<endl<<"A";}
      else cout<<endl<<"N";
    }

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include<vector>
using namespace std;

int main() {
    int n;
    cin >> n;
    int nums[100];
    for(int i=0; i<n; i++) {
        cin >> nums[i];
    }
    int asc = 0, des=0, equal=0;
    for(int i=n-1; i>=0; i--) {
        cout << nums[i]<<" ";
        if(i>0) {
            if(nums[i-1]==nums[i]) {
                equal ++;
            }
            if(nums[i-1]<=nums[i]) {
                asc ++;
            }
            if(nums[i-1] >= nums[i]) {
                des ++;
            }
        }
    }
    cout << endl;
    if(equal == n-1) cout << "B";
    else if(asc == n-1) cout << "A";
    else if(des == n-1) cout << "D";
    else cout << "N";
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include <iostream>
using namespace std;
#include <vector>

int main() {
    int n;
    cin>>n;
    int nums[n];
    for (int i = 0; i<n; i++) {
        cin>>nums[i];
    }
    for (int i = n-1; i>=0; i--){
        cout<<nums[i]<<" ";
    }
    cout<<endl;
    bool asc= true, dsc = true;

    for (int i = 0; i<n-1; i++) {
        if (nums[i]<=nums[i+1]){
            continue;
        } else {
            asc = false;
            break;
    }
    }
    for (int i = 0; i<n-1; i++) {
        if (nums[i]>=nums[i+1]){
            continue;
        } else {
            dsc = false;
            break;
        }
    }

    if(asc && dsc) cout<<"B"<<endl;
    else if (asc== true && dsc == false) cout<<"A"<<endl;
    else if (asc== false && dsc == true) cout<<"D"<<endl;
    else cout<<"N"<<endl;



}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;
int main(){
    int n;
    cin>>n;
    int num[n]={};
    for(int i=0;i<n;i++){
        cin>>num[i];
    }
    for(int i=n-1;i>=0;i--){
        cout<<num[i]<<' ';
    }
    cout<<endl;
    int ch=0;
    for(int i=1;i<n;i++){
        if(num[i]==num[0]) continue;
        else{
            ch=1;
            break;
        }
    }
    int cha=0;
    for(int i=1;i<n;i++){
        if(num[i]>=num[i-1]) continue;
        else {
            cha=1;
            break;
        }
    }
    int chd=0;
    for(int i=1;i<n;i++){
        if(num[i]<num[i-1]) continue;
        else{
            chd=1;
            break;
        }
    }
    if(ch==0) cout<<'B'<<endl;
    else if(cha==0) cout<<'A'<<endl;
    else if(chd==0) cout<<'D'<<endl;
    else cout<<'N'<<endl;
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include<vector>
using namespace std;
int main(){
    vector<int> nums;
    int k;
    cin>>k;
    for(int i=k-1;i>0;k--)
    cout<<nums[i];
    cout<<""<<endl;
    bool cons=true;
    for(int i=0;i<k;k++){
        if(nums[i]!=nums[i+1]){
         cons=false;
         break;
        }
}   
bool as=true;
 for(int i=0;i<k;k++){
    if(nums[i]<nums[i+1]){
         as=false;
         break;
    }
 }
bool ds=true;
for(int i=0;i<k;k++){
        if(nums[i]>nums[i+1]){
         ds=false;
         break;
        }
}
bool nind=true;
if(as||ds||cons)
 nind=false;
 if(cons)
 cout<<"B";
 if(as)
 cout<<"A";
 if(ds)
 cout<<"D";

 if(nind)
 cout<<"N";
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
using namespace std;

int main(){
    int n;
    cin>>n;
    int nums[n];
    for( int i=0; i<n; i++){
        cin>> nums[i];
    }
    for( int i=i+1; i>=0; i--){
        cout<< nums[i]<<" ";

    }
    cout<<endl;

    for( int i=0; i<n-1; i++){

    if(nums[i]==nums[i+1])
    cout<<"B";
    else if (nums[i]>nums[i+1])
    cout<<"D";
    else if(nums[i]<nums[i+1])
    cout<<"A";
    }
    if(nums[n-3]>=nums[n-2] && nums[n-2]<=nums[n-1] && nums[n-3]!=nums[n-1])
    cout<<"N";

    else if(nums[n-3]<=nums[n-2] && nums[n-2]>=nums[n-1] && nums[n-3]!=nums[n-1])
    cout<<"N";
        
         
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: C
Problem: You are given a sequence of integers. Your task is to analyze the order of the elements in the sequence, print the sequence in reverse order, and determine the category of the sequence based on how the elements are arranged.



Categories

After reading the sequence, determine which of the following categories it belongs to:

A - Ascending Order  
   All elements are in strictly increasing order.

D - Descending Order  
   All elements are in strictly decreasing order.

B - Constant Order  
   All elements are equal.

N - None  
   The sequence does not belong to any of the above categories.



Your Task

1. Read an integer n representing the number of elements.
2. Read n integers into an array or vector.
3. Print the elements in reverse order.
4. Traverse the array to determine its category:
   - If every next element is greater than the previous, it is Ascending (A).
   - If every next element is smaller than the previous, it is Descending (D).
   - If all elements are equal, it is Constant (B).
   - Otherwise, it is None (N).
5. Print the corresponding category character after printing the reversed array.



Input Format

- An integer n.
- n integers representing the elements of the array.



Output Format

- First, print the array in reverse order with spaces.
- Then print a single character on a new line representing the category:
  A, D, B, or N.


Assumptions on Input

- 1 <= n <= 10^5
- Elements are integers.

Student submission:
#include<iostream>
#include <vector>
using std::cout; using std::cin; using std::endl;
std::vector<int> nums;
std::vector<int> help;
int main(){
    int n;
    cin>>n;
    int r;
    int t;
    int countA = 0;
    int countB = 0;
    int countD = 0;
    for(int i = 0; i < n;i++){
        cin>>r;
        nums.push_back(r);
    }
    for(int i = 0; i < n;i++){
        t = nums[n - 1 - i];
        help.push_back(t);
        cout<<t<<" "; 
    }
    cout<<endl;
    for(int i = 1; i < n; i++){
        if(help[i]>=help[i - 1]){
            countA++;
        }
    }
    for(int i = 1; i < n; i++){
        if(help[i]<=help[i - 1]){
            countD++;
        }
    }
    for(int i = 1; i < n; i++){
        if(help[i]==help[i - 1]){
            countB++;
        }
    }
    if(countB == n - 1){
        cout<<'B';
    }
    else if(countD==n - 1){
        cout<<'A';
    }
    else if(countA == n - 1){
        cout<<'D';
    }
    else{
        cout<<'N';
    }
}

Grading criterion: Traversing of the loop
Rating A: correctly traverses the loop n times
Rating B: Some issue.
Rating C: Major issue.
Rating D: 0
Assigned grade: A