CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
int main(){
using namespace std;

int S;
cin>>S;
double xL=1, xR=5;
double epsilon=0.001;
bool flagL, flagR;
double xM;
bool flagM;
S=flagM;
flagL=xL*xL>0;
flagR=xR*xR>0;
if(flagL != flagR){
while(xR-xL>epsilon){
xM=(xL+xR)/2;
flagM=xM*xM>0;
if (flagM != flagL) xR=xM;
else if (flagM != flagR) xL=xM;
}
cout<<xL;
}
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;
void mysqrt(float x,float eps){
float a[1000000];
a[0]=x;
int n;
for(int i=0; ;i++){
         a[i+1]=(a[i]+(x/a[i]))/2;
if(a[i+1]-a[i]<eps &&a[i+1]-a[i]>-eps){n=i+1;break;}}
cout<<a[n];}
int main(){
float S,eps;
cin>>S>>eps;
mysqrt(S,eps);
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;
#include<cmath>

double root(int S,int x0){
double x,y;
double epsilon=0.01;
x=x0/1.00;
y=(x+S/x)/2.0;
while((y-x)>epsilon){
x=y;
y=(x+S/x)/2.0;}
return y;}
int main(){
int S,x0;
double y;
cin>>S;
x0=sqrt(S);
y=root(S,x0);
cout<<fixed;
cout.precision(5);
cout<<y;}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;


int main(){
    int a;
    cin>>a;

    int b = 2;
    double x = b;

    for(int i = 0;i<10 ;i++){
        x = (x + (a/x))/2;
        //cout<<x<<endl;
    }
    cout<<x;

    return 0; 
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;
#include<cmath>

double root(double S)
{
    double eps = (float)1.0/1000000;
    double x1 = 1;
    double x2 = (x1+(S/x1))/2;
    while(fabs(x2-x1)>eps)
    {
            x1 = x2;
            x2 = (x1+S/x1)/2;
    }
    return x2;
}

int main()
{
    cout<<fixed;
    cout.precision(5);
    double S; cin >> S;
    cout << root(S);
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<simplecpp>
main_program
int a,b;
{a==x0;
x1=(x0+S/x0)/2;
xn+1=(xn+S/xn)/2;
while loop a, 
return}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;
float findroot( float &p, float &eps)
{
  float temp, k=5.0, l=10.0;
  while( k-l>eps || l-k>eps)
  {
   temp=k;
   k=(l+(p/l))/2;
   l=temp;
  }
  return k;
}
int main()
{
 float S,epsi;
 cin>>S>>epsi;
 float b;
 b=findroot(S,epsi);
 cout<<b;
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<simplecpp>
using namespace std;
main_program{
float t;
float s;
float esp;
cin>>s>>esp;
t=sqrt(s);
float x=5;
do{
if(x==s || x<=(s+esp)){cout<<fixed;
cout.precision(5);
cout<<x;}
else if(x>(s+esp)){x=((x+s)/x)/2;}while(x>(s+esp)}


}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;
float  rootit(float s,float x,float epsilon){
float xo=x;
	do{x=xo;xo=(x+(s/x))/2;
		}while(fabs(x-xo)>epsilon);		
return xo;}
int main(){float s,x;
cin>>s>>x;
cout<<fixed;
cout.precision(5);
cout<<rootit(s,1,x);
return 0;}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include <iostream>
using namespace std;

double f(double S, double x)
{
return (x + (S/x))/2;
}

double sqrt_fun(double S, double epsilon)
{
	double val = 1;
	while (true)
	{
		if (val - f(S, val) < epsilon && val - f(S, val) > -1*epsilon)
		break;
		else
		val = f(S, val);
	}
	return val;
}

int main()
{
double S, epsilon;
cin >> S >> epsilon;
cout << sqrt_fun(S, epsilon);
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
# include <iostream>
using namespace std;
double square_root(double x,double epsilon){
int i=0;
while ((i*i)<x){
i++;}
double arr[1000000];
arr[0]=i;
arr[1]=(i+x/i)/2;
int j=0;
while ((arr[j]-arr[j+1])>epsilon){
arr[j+2]=(arr[j+1]+x/arr[j+1])/2;
j++;}
return arr[j];
}
int main(){
int S;
double epsilon;
cin >> S >> epsilon;
cout << square_root(S,epsilon);
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>

using namespace std;

double f(double s,double eps){
	double x0=1.39+18/s;
	double x1=(x0+s/x0)/2;
	while ((x1-x0)>eps){
		x0=x1;
		x1=(x0+s/x0)/2;	
	}
	return x1;
	   }

int main(){
	double S,eps,root;
	cin>>S>>eps;
	root=f(S,eps);
	
	cout<<fixed;
	cout.precision(5);
	cout<<root;
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: B
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
#include<cmath>
using namespace std;

double sq_root(double S, double epsilon){
    double x=2;
    while(fabs(x/2-S/(2*x))>epsilon){
        x = x/2+S/(2*x);
    }
    return x;
}

int main(){
    double S, epsilon;
    cin>>S>>epsilon;
    
    cout<<fixed;
    cout.precision(5);
    cout<<sq_root(S, epsilon);
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;

double f(double n,double S,double x0){
if (n<1){
return x0;
}
return ((f(n-1,S,x0)+S/f(n-1,S,x0))/2);
}

int main(){
double S,x0,epsilon;
cin>>S>>x0>>epsilon;

for(int i=0; (f(i+1,S,x0)-f(i,S,x0))>=epsilon; i++){
cout<<f(i+1,S,x0);
}
return 0;
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: A
Problem: An iterative method, called the Babylonian method, for finding square roots, was known to the ancient Babylonians (1500 BC) and Greeks (100 AD) long before Newton invented his general procedure. Here's how it works. Suppose you are given any positive number S. To find the square root of S, do the following: Make an initial guess. Guess any positive number x0.Improve the guess. Apply the formula x1 = (x0 + S / x0) / 2. The number x1 is a better approximation to sqrt(S).Iterate until convergence. Apply the formula xn+1 = (xn + S / xn) / 2 until the process converges. Convergence is achieved when the absolute difference between xn+1  and xn falls below some user specified epsilon.Your job is to write a C++ program containing a function that determines the approximate square root of the number S (taken as input) up to some desired precision epsilon. To get credit, you must write a function.

Input Format - S should be greater than 0. Epsilon should be small in value. 
Output Format - Print the value of the square root up to 5 decimal places.  

Constraints
S > 0, 
epsilon <= 0.01.

Student submission:
#include<iostream>
using namespace std;

double babylonianmethod(double x0, double S, double eps){
double x1= (x0+S/x0)/2.00;
if (abs(x1-x0)<eps){ return x1;}
else { x0=babylonianmethod(x1,S,eps); return x0;}
}

int main(){
double x0=10;
double S,eps;
cin>>S>>eps;
double o=babylonianmethod(x0,S,eps);
cout<<fixed;
cout.precision(5);
cout<<o;
}

Grading criterion: Use of function beyond what was instructed or any other nice quality.
Rating A: Some extra nice qualities
Rating B: Nothing Extra
Rating C: 0
Rating D: 0
Assigned grade: A