CodeGraderBench/CodeGraderBench huggingface dataset:
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include <iostream>
// i  wish i could vibes code TT
#include <vector>
#include <string>
using namespace std;
int recursion(int n,int k)
{
    int ret=0;
    if (n>=k&&k>=1)
        ret += recursion(n-1,k-1);
    if (n>=k+2&&k>=0)
        ret += recursion(n-2,k);
    if (n>=k+3&&k>=0)
        ret += recursion(n-3,k);
    if (n==0&&k==0)
        ret+=1;
    return ret;
}
int main()
{
    int M;
    cin >> M;
    int N;
    cin >> N;
    cout << recursion(M,N);
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std; 
int main(){
    int n;
    char A[100];
  cin<<n<<endl;
  cin<<A<<endl;


}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: C
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std;

int wayswith1(int n,int k){
    if(k==1&&n==1){
        return 1;
    }
    
}

int wayswith1(int n,int k){
    if(n<0 || k<0){
        return 0;
    }
    if(k==0){
        return wayswith1(n-2,k)+wayswith1(n-3,k);
    }
    if(n==0){
        return 0;
    }
    if(n==1 && k==1){
        return 1;
    }
    if(n<k){
        return 0;
    }
    return wayswith1(n-1,k-1)+wayswith1(n-2,k)+wayswith1(n-3,k);
    

}

int main(){
    int n,k;
    cin>>n>>k;
    cout<<wayswith1(n,k);

}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: C
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std;
int T(int n,int k){
    int sum=0;
    if(k==0){
        for(int i=0;i<n;i++){
            for(int j=0;j<n;j++){
                if(2*i+3*j==n){
                    sum++;
                }
            }
        } return sum;
    }
    if(k>n){return 0;}
    if(n==k){ return 1;}
    return T(n-1,k-1)+T(n-2,k)+T(n-3,k);
}
int main(){
    int n,k;
    cin>>n>>k;
    int ans=T(n,k);
    cout<<ans;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std;


   
    int block(int a, int b{
    if(a<<b){
        return 0;
    }
     if(a==0||b==0){
       cout<< 0;
    }
     if(b==1){
        cout<<a;
     }
     if(n>=k)
      cout<< block(n-1, k-1) + block(n-2, k) + block(n-3, k);

       
    
    }
 int main(){
    int n,k;
    cin>>n,k;
    block(n,k);
 }

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: B
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include <iostream>
using namespace std;

int ways(int n,int k){

if(n<=0){
return 0;
}
else if(n==3 && k==0){
return 1;
}

else if(n==2 && k==0){
return 1;
}

else if(n==1 && k==0){
return 0;
}

else if(k<0){
return 0;
}

else if(n==1 && k==1){
return 1;
}

else if(n<k){
    return 0;
}


return ways(n-1,k-1)+ways(n-2,k)+ways(n-3,k) ;

}

int main(){
int n , k ;
cin>>n>>k;


cout<<ways(n,k)<<endl ;





return 0;
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std;
int Typ(int i, int j){
if(i==1) return 1;
return Typ(i-1,j) + Typ(i-2,j);
i--;
}
int main(){
    int n;
    cout<<"Input n here"<<endl;
    cin>>n;
    int k;
    cout<<"Input k here"<<endl;
    cin>>k;
    cout<<Typ(n,k);
    
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
 using namespace std;
int main(){

    int n,k;
    cin>>n>>k;
    cout<<"3";
}

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: C
Problem: ​
Assume you are given blocks of size 1, 2 and 3. Write a C++ program to recursively count the number of ways in which a tower of size n can be built with these blocks, such that exactly k of the blocks are of size 1.

 

Example: If n = 4 and k = 2, then there are three possible ways in which the tower can be built. If L1, L2, L3 represent the lego blocks of sizes 1, 2, 3 respectively, then the tower of size 4 can be built using the following block arrangements:

 

L1, L1, L2

L1, L2, L1

L2, L1, L1

 

HINT: If T(n, k) represents the number of ways in which a tower of size n can be built with exactly k 1-sized blocks, then T(n, k) can be recursively written as:

 

T(n,k) = T(n-1, k-1) + T(n-2, k) + T(n-3, k)

where

T(n-1, k-1) represents the number of ways in which a size 1 block is used first, i.e., the number of ways to build a tower of size (n-1) containing exactly (k-1) blocks of size 1.
T(n-2, k) represents the number of ways in which a size 2 block is used first, i.e., the number of ways to build a tower of size (n-2) containing exactly k blocks of size 1.
T(n-3, k) represents the number of ways in which a size 3 block is used first, i.e., the number of ways to build a tower of size (n-3) containing exactly k blocks of size 1.
Use this recurrence formula to implement the recursive function. Think carefully about the base cases.

 

Note: 

You need to solve this question using recursion only. 
Solutions using any other approach will not be considered and any testcases that pass will be negated i.e. will be given a 0. 
 

Input Format

A line containing two positive integers n and k, separated by a space
 

Output Format

An integer representing the count of valid ways to build a tower.
 

Assumptions on Input

Assume that the value of n entered by the user will be between 1 and 15, both inclusive
Assume that the value of k entered by the user will be between 1 and 10, both inclusive
If it is not possible to construct a tower, return 0.

Student submission:
#include<iostream>
using namespace std;
   int noone(int p){
      int h=0;
      if (p==1){return (h);}
      else if (p==2){h+=1;return (h);}
      else if (p==3){h+=1;return (h);}
      else {h=noone(p-2)+noone(p-3);return (h);}
   }
   int numberofways(int a,int b){
    int x=0;
    if (a==1&b==1){x+=1;return (x);}
    else if (a==1&b==0){return (x);}
    else if (a==0&b==0){x+=1;return (x);}
    else if (a==0&b>=1){return (x);}
    else if (a==2&b==1){return (x);}
    else if (a==2&b==2){x+=1;return (x);}
    else if (a==2&b>2){return (x);}
    else if (a==1&b>1){return (x);}
    else if ((a>=2)&(b==0)){x=noone(a);return (x);}
    else{
    x=numberofways(a-1,b-1)+numberofways(a-2,b)+numberofways(a-3,b);
    return (x);}
   }
    

    int main(){
        int n,k;
        cin>>n>>k;
        cout << numberofways(n,k);
    }

Grading criterion: Calls the funcion from the main and prints the result
Rating A: Correctly calls the function from the main

Rating B: some issue
Rating C: major issue
Rating D: 0
Assigned grade: A