# Original solution
from collections import deque


class BipartiteGraph:
    """二部グラフの最大マッチングを求めるなどする"""
    def __init__(self, input_graph: list):
        """重み無し二部グラフinput_graphを入力する"""
        n = len(input_graph)
        self.INF = float("inf")
        self.max_bipartite_matching = -1
        
        # DFSでグラフを2色に彩色する
        visited = [-1] * n
        for i in range(n):
            if visited[i] >= 0:
                continue
            visited[i] = 0
            q = deque([i]) 
            while q:
                _from = q.pop()
                for to in input_graph[_from]:
                    if visited[to] >= 0:
                        continue
                    visited[to] = visited[_from] ^ 1
                    q.append(to)

        # 残余グラフを構築する
        self.s = n
        self.t = n + 1
        self.n = n + 2
        self.graph = [[] for i in range(self.n)]
        used = set([])
        for pos1 in range(n):
            if visited[pos1] == 0:
                self.add_edge(self.s, pos1)
            else:
                self.add_edge(pos1, self.t)
            for pos2 in input_graph[pos1]:
                if (min(pos1, pos2), max(pos1, pos2)) in used:
                    continue
                used.add((min(pos1, pos2), max(pos1, pos2)))
                if visited[pos1] == 0:
                    self.add_edge(pos1, pos2)
                else:
                    self.add_edge(pos2, pos1)
 
    def add_edge(self, _from: int, to: int):
        """残余グラフを構築
        1. _fromからtoへ向かう容量capacity = 1の辺をグラフに追加する
        2. toから_fromへ向かう容量0の辺をグラフに追加する
        """
        forward = [to, 1, None]
        forward[2] = backward = [_from, 0, forward]
        self.graph[_from].append(forward)
        self.graph[to].append(backward)
 
    def bfs(self, s: int, t: int):
        """capacityが正の辺のみを通ってsからtに移動可能かどうかBFSで探索
        level: sからの最短路の長さ
        """
        self.level = [-1] * self.n
        q = deque([s])
        self.level[s] = 0
        while q:
            _from = q.popleft()
            for to, capacity, _ in self.graph[_from]:
                if capacity > 0 and self.level[to] < 0:
                    self.level[to] = self.level[_from] + 1
                    q.append(to)
 
    def dfs(self, _from: int, t: int, f: int) -> int:
        """流量が増加するパスをDFSで探索
        BFSによって作られた最短路に従ってfを更新する
        """
        if _from == t:
            return f
        for edge in self.itr[_from]:
            to, capacity, reverse_edge = edge
            if capacity > 0 and self.level[_from] < self.level[to]:
                d = self.dfs(to, t, min(f, capacity))
                if d > 0:
                    edge[1] -= d
                    reverse_edge[1] += d
                    return d
        return 0
 
    def max_flow(self):
        """s-tパス上の最大流を求める = 最大マッチングを求める　= 最商店被覆を求める
        計算量: O(|E||V|^2)
        """
        if self.max_bipartite_matching >= 0:
            return self.max_bipartite_matching
        flow = 0
        while True:
            self.bfs(self.s, self.t)
            if self.level[self.t] < 0:
                break
            self.itr = list(map(iter, self.graph))
            f = self.dfs(self.s, self.t, self.INF)
            while f > 0:
                flow += f
                f = self.dfs(self.s, self.t, self.INF)
        self.max_bipartite_matching = flow
        return flow

    def maximum_matching(self):
        """最大マッチングを求める"""
        return self.max_flow()

    def minimum_point_covering(self):
        """最小点被覆を求める"""
        return self.max_flow()
      
    def maximum_independent_set(self):
        """最大安定集合を求める"""
        return (self.n - 2) - self.max_flow()

    def minimum_edge_covering(self):
        """最小辺被覆を求める"""
        return (self.n - 2) - self.max_flow()
      
      
n = int(eval(input()))
info = [list(map(int, input().split())) for i in range(n - 1)]

tree = [[] for i in range(n)]
for a, b in info:
    a -= 1
    b -= 1
    tree[a].append(b)
    tree[b].append(a)
    
bg = BipartiteGraph(tree)
if bg.maximum_matching() * 2 == n:
    print("Second")
else:
    print("First")

# Optimized solution
from collections import deque


n = int(eval(input()))
info = [list(map(int, input().split())) for i in range(n - 1)]

tree = [[] for i in range(n)]
for a, b in info:
    a -= 1
    b -= 1
    tree[a].append(b)
    tree[b].append(a)
    
root = 0
par = {root: -1}
q = deque([root])
topo = []
while q:
    v = q.popleft()
    topo.append(v)
    for nxt_v in tree[v]:
        if nxt_v in par:
            continue
        par[nxt_v] = v
        q.append(nxt_v)

used = [False] * n
for v in topo[::-1]:
    if used[v]:
        continue
    else:
        used[v] = True
        if par[v] == -1:
            print("First")
            exit()
        if used[par[v]]:
            print("First")
            exit()
        used[par[v]] = True
print("Second")