# Original solution
import sys
sys.setrecursionlimit(10**7) #再帰関数の上限,10**5以上の場合python
import math
from copy import copy, deepcopy
from copy import deepcopy as dcp
from operator import itemgetter
from bisect import bisect_left, bisect, bisect_right#2分探索
#bisect_left(l,x), bisect(l,x)#aはソート済みである必要あり。aの中からx未満の要素数を返す。rightだと以下
from collections import deque, defaultdict
#deque(l), pop(), append(x), popleft(), appendleft(x)
#q.rotate(n)で → にn回ローテート
from collections import Counter#文字列を個数カウント辞書に、
#S=Counter(l),S.most_common(x),S.keys(),S.values(),S.items()
from itertools import accumulate,combinations,permutations,product#累積和
#list(accumulate(l))
from heapq import heapify,heappop,heappush
#heapify(q),heappush(q,a),heappop(q) #q=heapify(q)としないこと、返り値はNone
#import fractions#古いatcoderコンテストの場合GCDなどはここからimportする
from functools import reduce,lru_cache#pypyでもうごく
#@lru_cache(maxsize = None)#maxsizeは保存するデータ数の最大値、2**nが最も高効率
from decimal import Decimal

def input(): 
    x=sys.stdin.readline()
    return x[:-1] if x[-1]=="\n" else x
def printe(*x):print("## ",*x,file=sys.stderr)
def printl(li): _=print(*li, sep="\n") if li else None
def argsort(s, return_sorted=False): 
    inds=sorted(range(len(s)), key=lambda k: s[k])
    if return_sorted: return inds, [s[i] for i in inds]
    return inds
def alp2num(c,cap=False): return ord(c)-97 if not cap else ord(c)-65
def num2alp(i,cap=False): return chr(i+97) if not cap else chr(i+65)
def matmat(A,B):
    K,N,M=len(B),len(A),len(B[0])
    return [[sum([(A[i][k]*B[k][j]) for k in range(K)]) for j in range(M)] for i in range(N)]
def matvec(M,v):
    N,size=len(v),len(M)
    return [sum([M[i][j]*v[j] for j in range(N)]) for i in range(size)]
def T(M):
    n,m=len(M),len(M[0])
    return [[M[j][i] for j in range(n)] for i in range(m)]
def main():
    mod = 1000000007
    #w.sort(key=itemgetter(1),reverse=True)  #二個目の要素で降順並び替え

    N = int(input())
    s = input()
    #N, K = map(int, input().split())
    #A = tuple(map(int, input().split())) #1行ベクトル
    #L = tuple(int(input()) for i in range(N)) #改行ベクトル
    #S = tuple(tuple(map(int, input().split())) for i in range(N)) #改行行列
    
    @lru_cache(None)
    def r(n):
        if n==0:
            return 0
        bc=0
        for i in range(N):
            if n>>i&1:
                bc+=1
        return r(n%bc)+1

    mod=s.count("1")
    c1=0
    c2=0
    cur1=1%(mod+1)
    
    if mod>1:
        cur2=1%(mod-1)
        for i in range(N):
            if s[-1-i]=="1":
                c1+=cur1
                c1%=(mod+1)
                c2+=cur2
                c2%=(mod-1)

            cur1=cur1*2%(mod+1)
            cur2=cur2*2%(mod-1)
    else:

        for i in range(N):
            if s[-1-i]=="1":
                c1+=cur1
                c1%=(mod+1)
            cur1=cur1*2%(mod+1)



    for i in range(N):
        if s[i]=="1":
            f=-1
            cmod=mod-1
        else:
            f=1
            cmod=mod+1

        if cmod==0:
            print(0)
            continue
        
        if f==1:
            n=c1+pow(2,N-1-i,cmod)
            n%=cmod
        else:
            n=c2-pow(2,N-1-i,cmod)
            n%=cmod

        print(1+r(n))
    #printe(c1,c2)





if __name__ == "__main__":
    main()


# Optimized solution
import sys
sys.setrecursionlimit(10**7) #再帰関数の上限,10**5以上の場合python
import math
from copy import copy, deepcopy
from copy import deepcopy as dcp
from operator import itemgetter
from bisect import bisect_left, bisect, bisect_right#2分探索
#bisect_left(l,x), bisect(l,x)#aはソート済みである必要あり。aの中からx未満の要素数を返す。rightだと以下
from collections import deque, defaultdict
#deque(l), pop(), append(x), popleft(), appendleft(x)
#q.rotate(n)で → にn回ローテート
from collections import Counter#文字列を個数カウント辞書に、
#S=Counter(l),S.most_common(x),S.keys(),S.values(),S.items()
from itertools import accumulate,combinations,permutations,product#累積和
#list(accumulate(l))
from heapq import heapify,heappop,heappush
#heapify(q),heappush(q,a),heappop(q) #q=heapify(q)としないこと、返り値はNone
#import fractions#古いatcoderコンテストの場合GCDなどはここからimportする
from functools import reduce,lru_cache#pypyでもうごく
#@lru_cache(maxsize = None)#maxsizeは保存するデータ数の最大値、2**nが最も高効率
from decimal import Decimal

def input(): 
    x=sys.stdin.readline()
    return x[:-1] if x[-1]=="\n" else x
def printe(*x):print("## ",*x,file=sys.stderr)
def printl(li): _=print(*li, sep="\n") if li else None
def argsort(s, return_sorted=False): 
    inds=sorted(range(len(s)), key=lambda k: s[k])
    if return_sorted: return inds, [s[i] for i in inds]
    return inds
def alp2num(c,cap=False): return ord(c)-97 if not cap else ord(c)-65
def num2alp(i,cap=False): return chr(i+97) if not cap else chr(i+65)
def matmat(A,B):
    K,N,M=len(B),len(A),len(B[0])
    return [[sum([(A[i][k]*B[k][j]) for k in range(K)]) for j in range(M)] for i in range(N)]
def matvec(M,v):
    N,size=len(v),len(M)
    return [sum([M[i][j]*v[j] for j in range(N)]) for i in range(size)]
def T(M):
    n,m=len(M),len(M[0])
    return [[M[j][i] for j in range(n)] for i in range(m)]
def main():
    mod = 1000000007
    #w.sort(key=itemgetter(1),reverse=True)  #二個目の要素で降順並び替え

    N = int(input())
    s = input()
    #N, K = map(int, input().split())
    #A = tuple(map(int, input().split())) #1行ベクトル
    #L = tuple(int(input()) for i in range(N)) #改行ベクトル
    #S = tuple(tuple(map(int, input().split())) for i in range(N)) #改行行列
    
    @lru_cache(None)
    def r(n):
        if n==0:
            return 0
        bc=0
        for i in range(n.bit_length()):
            if n>>i&1:
                bc+=1
        return r(n%bc)+1

    mod=s.count("1")
    c1=0
    c2=0
    cur1=1%(mod+1)
    
    if mod>1:
        cur2=1%(mod-1)
        for i in range(N):
            if s[-1-i]=="1":
                c1+=cur1
                c1%=(mod+1)
                c2+=cur2
                c2%=(mod-1)

            cur1=cur1*2%(mod+1)
            cur2=cur2*2%(mod-1)
    else:
        for i in range(N):
            if s[-1-i]=="1":
                c1+=cur1
                c1%=(mod+1)
            cur1=cur1*2%(mod+1)



    for i in range(N):
        if s[i]=="1":
            f=-1
            cmod=mod-1
        else:
            f=1
            cmod=mod+1

        if cmod==0:
            print(0)
            continue
        
        if f==1:
            n=c1+pow(2,N-1-i,cmod)
            n%=cmod
        else:
            n=c2-pow(2,N-1-i,cmod)
            n%=cmod

        print(1+r(n))
    #printe(c1,c2)





if __name__ == "__main__":
    main()