CodeEff/ECCO huggingface dataset:
# Original solution
import sys

read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
sys.setrecursionlimit(10 ** 9)
INF = 1 << 60
MOD = 1000000007


def check(vec, init_pos, target_pos):
    dp = {init_pos}

    for nv in vec:
        dp_next = set()
        for v in dp:
            dp_next.add(v - nv)
            dp_next.add(v + nv)
        dp = dp_next

    return target_pos in dp


def main():
    S = readline().strip()
    x, y = list(map(int, readline().split()))

    L = [len(commands) for commands in S.split('T')]

    init_x = L[0]
    x_commands = L[2::2]
    y_commands = L[1::2]

    ok = check(x_commands, init_x, x) and check(y_commands, 0, y)

    if ok:
        print('Yes')
    else:
        print('No')

    return


if __name__ == '__main__':
    main()


# Optimized solution
import sys

read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
sys.setrecursionlimit(10 ** 9)
INF = 1 << 60
MOD = 1000000007


def check(vec, init_pos, target_pos):
    dp = {init_pos}

    for nv in vec:
        dp_next = set()
        for v in dp:
            dp_next.add(v - nv)
            dp_next.add(v + nv)
        dp = dp_next

    return target_pos in dp


def main():
    S = readline().strip()
    x, y = list(map(int, readline().split()))

    L = [len(commands) for commands in S.split('T')]

    init_x = L[0]
    x_commands = [c for c in L[2::2] if c != 0]
    y_commands = [c for c in L[1::2] if c != 0]

    ok = check(x_commands, init_x, x) and check(y_commands, 0, y)

    if ok:
        print('Yes')
    else:
        print('No')

    return


if __name__ == '__main__':
    main()
# Original solution
import sys

read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
sys.setrecursionlimit(10 ** 9)
INF = 1 << 60
MOD = 1000000007


def check(vec, init_pos, target_pos):
    dp = {init_pos}

    for nv in vec:
        dp_next = set()
        for v in dp:
            dp_next.add(v - nv)
            dp_next.add(v + nv)
        dp = dp_next

    return target_pos in dp


def main():
    S = readline().strip()
    x, y = list(map(int, readline().split()))

    L = [len(commands) for commands in S.split('T')]

    init_x = L[0]
    x_commands = [c for c in L[2::2] if c != 0]
    y_commands = [c for c in L[1::2] if c != 0]

    ok = check(x_commands, init_x, x) and check(y_commands, 0, y)

    if ok:
        print('Yes')
    else:
        print('No')

    return


if __name__ == '__main__':
    main()


# Optimized solution
import sys

read = sys.stdin.read
readline = sys.stdin.readline
readlines = sys.stdin.readlines
sys.setrecursionlimit(10 ** 9)
INF = 1 << 60
MOD = 1000000007


def check(vec, init_pos, target_pos):
    dp = {init_pos}

    for nv in vec:
        if nv == 0:
            continue
        dp_next = set()
        for v in dp:
            dp_next.add(v - nv)
            dp_next.add(v + nv)
        dp = dp_next

    return target_pos in dp


def main():
    S = readline().strip()
    x, y = list(map(int, readline().split()))

    L = [len(commands) for commands in S.split('T')]

    init_x = L[0]
    x_commands = L[2::2]
    y_commands = L[1::2]

    ok = check(x_commands, init_x, x) and check(y_commands, 0, y)

    if ok:
        print('Yes')
    else:
        print('No')

    return


if __name__ == '__main__':
    main()
# Original solution
#!/usr/bin/env python3

import sys, heapq
sys.setrecursionlimit(300000)

YES = "Yes"  # type: str
NO = "No"  # type: str

def solve(N: int, S: "List[str]"):
    tmp = []
    for i in range(N):
        cur = 0
        mn = 0
        for c in S[i]:
            if c == '(':
                cur += 1
            else:
                cur -= 1
                mn = min(mn, cur)
        tmp.append((mn, cur, cur - mn))

    tmp.sort(key=lambda x: (x[0], x[1]), reverse=True)
    #print(tmp)

    cur = 0
    idx = 0
    q = []
    count = 0
    while idx < N or len(q) > 0:
        while idx < N and cur + tmp[idx][0] >= 0:
            heapq.heappush(q, (-tmp[idx][2], -tmp[idx][1], -tmp[idx][0]))
            idx += 1
        if len(q) == 0:
            print(NO)
            return
        #print(count, q)
        diff, cnt, mn = heapq.heappop(q)
        diff, cnt, mn = -diff, -cnt, -mn
        #print(cnt, mn)
        if cur + mn < 0:
            print(NO)
            return
        cur += cnt
        count += 1

    #print(cur)
    if cur == 0:
        ret = YES
    else:
        ret = NO
    print(ret)
    return

def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    S = [next(tokens) for _ in range(N)]  # type: "List[str]"
    solve(N, S)

if __name__ == '__main__':
    main()


# Optimized solution
#!/usr/bin/env python3

import sys, heapq
sys.setrecursionlimit(300000)

YES = "Yes"  # type: str
NO = "No"  # type: str

def solve(N: int, S: "List[str]"):
    tmp = []
    for i in range(N):
        cur = 0
        mn = 0
        for c in S[i]:
            if c == '(':
                cur += 1
            else:
                cur -= 1
                mn = min(mn, cur)
        tmp.append((mn, cur))

    tmp.sort(key=lambda x: (x[1] < 0, (-x[0] if x[1] >= 0 else -(x[1] - x[0]))))
    #tmp.sort(key=lambda x: (x[1] < 0, -x[0], x[1]))
    #print(tmp)

    cur = 0
    for mn, cnt in tmp:
        #print(cur, mn, cnt)
        if abs(mn) > cur:
            print(NO)
            return
        cur += cnt

    if cur == 0:
        ret = YES
    else:
        ret = NO
    print(ret)
    return

def main():
    def iterate_tokens():
        for line in sys.stdin:
            for word in line.split():
                yield word
    tokens = iterate_tokens()
    N = int(next(tokens))  # type: int
    S = [next(tokens) for _ in range(N)]  # type: "List[str]"
    solve(N, S)

if __name__ == '__main__':
    main()
# Original solution
N = int(eval(input()))
D, E = [], []
t,l = 0, 0
res = 0
for _ in range(N):
    S = input().rstrip()
    x,y = 0,0
    for s in S:
        if s=="(": x+=1
        else: x=max(x-1,0)
    for s in reversed(S):
        if s==")": y+=1
        else: y=max(y-1,0)
    D.append((x,y))
D.sort(key=lambda x:x[1])
t = 0
for x,y in D:
    if x-y>=0:
        if t>=y: t+=x-y
        else: print("No"); exit()
D.sort(key=lambda x:x[0])
s = 0
for x,y in D:
    if y-x>=0:
        if s>=x: s+=y-x
        else: print("No"); exit()
if t!=s: print("No")
else: print("Yes")


# Optimized solution
import sys
input = sys.stdin.readline
N = int(eval(input()))
D, E = [], []
t,l = 0, 0
res = 0
for _ in range(N):
    S = input().rstrip()
    x,y = 0,0
    for s in S:
        if s=="(": x+=1
        else: x=max(x-1,0)
    for s in reversed(S):
        if s==")": y+=1
        else: y=max(y-1,0)
    D.append((x,y))
D.sort(key=lambda x:x[1])
t = 0
for x,y in D:
    if x-y>=0:
        if t>=y: t+=x-y
        else: print("No"); exit()
D.sort(key=lambda x:x[0])
s = 0
for x,y in D:
    if y-x>=0:
        if s>=x: s+=y-x
        else: print("No"); exit()
if t!=s: print("No")
else: print("Yes")
# Original solution
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
import math
import bisect
import random
from itertools import permutations, accumulate, combinations, product
import sys
import string
from bisect import bisect_left, bisect_right
from math import factorial, ceil, floor, cos, radians, pi, sin
from operator import mul
from functools import reduce
from operator import mul


sys.setrecursionlimit(2147483647)
INF = 10 ** 13
def LI(): return list(map(int, sys.stdin.buffer.readline().split()))
def I(): return int(sys.stdin.buffer.readline())
def LS(): return sys.stdin.buffer.readline().rstrip().decode('utf-8').split()
def S(): return sys.stdin.buffer.readline().rstrip().decode('utf-8')
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
def SRL(n): return [list(S()) for i in range(n)]
def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)]

n = I()
A = []
B = []
for _ in range(n):
    s = S()
    ret = 0
    ret2 = 0
    for i in s:
        if ret and i == ')':
            ret -= 1
        elif i == '(':
            ret += 1
        else:
            ret2 += 1
    if ret2 > ret:
        A += [(ret, ret2)]
    else:
        B += [(ret, ret2)]

A.sort()
B.sort(key=lambda x:x[1], reverse=True)
L = A + B
now = 0
for x, y in L:
    if x > now:
        print('No')
        exit()
    now = now - x + y

if now:
    print('No')
else:
    print('Yes')






# Optimized solution
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
import bisect
import random
from itertools import permutations, accumulate, combinations, product
import sys
import string
from bisect import bisect_left, bisect_right
from math import factorial, ceil, floor, acos, asin, atan, sqrt, tan, cos, pi
from operator import mul
from functools import reduce
from pprint import pprint


sys.setrecursionlimit(10 ** 7)
INF = 10 ** 20
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return sys.stdin.readline().strip()
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
def SRL(n): return [list(S()) for i in range(n)]
def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)]
mod = 10 ** 9 + 7


n = I()
plus = []
minus = []
for _ in range(n):
    s = S()
    ret = 0
    ret2 = 0
    for i in s:
        if ret and i == ')':
            ret -= 1
        elif i == '(':
            ret += 1
        else:
            ret2 += 1
    if ret2 > ret:
        plus += [(ret, ret2)]
    else:
        minus += [(ret, ret2)]


plus.sort()
minus.sort(key=lambda x:x[1], reverse=True)
L = plus + minus

now = 0
for x, y in L:
    if x > now:
        print("No")
        exit()
    now = now - x + y

if now:
    print("No")
else:
    print("Yes")
# Original solution
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
import bisect
import random
from itertools import permutations, accumulate, combinations, product
import sys
import string
from bisect import bisect_left, bisect_right
from math import factorial, ceil, floor, acos, asin, atan, sqrt, tan, cos, pi
from operator import mul
from functools import reduce
from pprint import pprint


sys.setrecursionlimit(10 ** 7)
INF = 10 ** 20
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return sys.stdin.readline().strip()
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
def SRL(n): return [list(S()) for i in range(n)]
def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)]
mod = 10 ** 9 + 7


n = I()
plus = []
minus = []
for _ in range(n):
    s = S()
    ret = 0
    ret2 = 0
    for i in s:
        if ret and i == ')':
            ret -= 1
        elif i == '(':
            ret += 1
        else:
            ret2 += 1
    if ret2 > ret:
        plus += [(ret, ret2)]
    else:
        minus += [(ret, ret2)]


plus.sort()
minus.sort(key=lambda x:x[1], reverse=True)
L = plus + minus

now = 0
for x, y in L:
    if x > now:
        print("No")
        exit()
    now = now - x + y

if now:
    print("No")
else:
    print("Yes")

# Optimized solution
from collections import defaultdict, deque, Counter
from heapq import heappush, heappop, heapify
import bisect
import random
from itertools import permutations, accumulate, combinations, product
import sys
import string
from bisect import bisect_left, bisect_right
from math import factorial, ceil, floor, acos, asin, atan, sqrt, tan, cos, pi
from operator import mul
from functools import reduce
from pprint import pprint


sys.setrecursionlimit(10 ** 7)
INF = 10 ** 20
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS(): return sys.stdin.readline().split()
def S(): return sys.stdin.readline().strip()
def IR(n): return [I() for i in range(n)]
def LIR(n): return [LI() for i in range(n)]
def SR(n): return [S() for i in range(n)]
def LSR(n): return [LS() for i in range(n)]
def SRL(n): return [list(S()) for i in range(n)]
def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)]
mod = 10 ** 9 + 7


n = I()
plus = []
minus = []
for _ in range(n):
    s = S()
    ret = 0
    ret2 = 0
    for i in s:
        if ret and i == ')':
            ret -= 1
        elif i == '(':
            ret += 1
        else:
            ret2 += 1
    if ret2 > ret:
        plus += [(ret, ret2)]
    else:
        minus += [(ret, ret2)]


plus.sort()
minus.sort(key=lambda x:x[1], reverse=True)
L = plus + minus

now = 0
for x, y in L:
    now -= x
    if now < 0:
        print("No")
        exit()
    now += y

if now:
    print("No")
else:
    print("Yes")
# Original solution
# -*- coding: utf-8 -*-

N = int(input().strip())
S_list = [input().strip() for _ in range(N)]
#-----

def count_brackets(brackets):
    cnt = 0
    min_cnt = float("inf")
    
    for i in range(len(brackets)):
        if brackets[i] == "(":
            cnt += 1
        else:  # brackets[i] == ")"
            cnt -= 1
            min_cnt = min(min_cnt, cnt)
    
    return cnt, min_cnt

#-----
tmp_cnt_plus  = []
tmp_cnt_minus = []

for S in S_list:
    cnt, min_cnt = count_brackets(S)
    
    if cnt >= 0:
        tmp_cnt_plus.append( (cnt, min_cnt) )
    else:  # cnt < 0
        tmp_cnt_minus.append( (cnt, min_cnt) )


tmp_cnt_plus.sort(key=lambda x: -x[1])
tmp_cnt_minus.sort(key=lambda x: -(x[0]-x[1]) )


sum_bracket = 0
flag = True

for cnt, min_cnt in (tmp_cnt_plus + tmp_cnt_minus):
    if (sum_bracket + min_cnt) < 0:
        flag = False
        break
    
    sum_bracket += cnt


if (sum_bracket == 0) and flag:
    print("Yes")
else:
    print("No")


# Optimized solution
# -*- coding: utf-8 -*-

N = int(input().strip())
S_list = [input().strip() for _ in range(N)]
#-----

def count_brackets(brackets):
    cnt = 0
    min_cnt = 0
    
    for i in range(len(brackets)):
        if brackets[i] == "(":
            cnt += 1
        else:  # brackets[i] == ")"
            cnt -= 1
            min_cnt = min(min_cnt, cnt)
    
    return cnt, min_cnt


tmp_cnt_plus  = []
tmp_cnt_minus = []

for S in S_list:
    cnt, min_cnt = count_brackets(S)
    
    if cnt == min_cnt == 0:
        continue
    
    if cnt >= 0:
        tmp_cnt_plus.append( (cnt, min_cnt) )
    else:  # cnt < 0
        tmp_cnt_minus.append( (cnt, min_cnt) )


tmp_cnt_plus.sort(key=lambda x: -x[1])
tmp_cnt_minus.sort(key=lambda x: -(x[0]-x[1]) )


sum_bracket = 0
flag = True

for cnt, min_cnt in (tmp_cnt_plus + tmp_cnt_minus):
    if (sum_bracket + min_cnt) < 0:
        flag = False
        break
    
    sum_bracket += cnt


if (sum_bracket == 0) and flag:
    print("Yes")
else:
    print("No")
# Original solution
import heapq
import sys
input = sys.stdin.readline
n = int(eval(input()))
sss = [input()[:-1] for _ in range(n)]

a = []
b = []
ss = 0
ii = 0
for i in sss:
    mi = 0
    ma = 0
    s = 0
    for j in i:
        if j == "(":
            s += 1
        else:
            s -= 1
        mi = min(mi, s)
        ma = max(ma, s)
    ss += s
    if s >= 0:
        a.append([-s, mi, ma, ii])
    else:
        b.append([s, mi - s, ma - s, ii])
    ii += 1


if ss != 0:
    print("No")
    exit()
a.sort(reverse=1, key=lambda x: x[1])
b.sort(reverse=1, key=lambda x: x[1])


def ok1(a):
    s = 0
    heap = []
    i = 0
    while True:
        while i < len(a) and a[i][1] + s >= 0:
            heapq.heappush(heap, a[i])
            i += 1
        if i < len(a) and not heap:
            print("No")
            exit()
        if not heap:
            break
        kkk = 0
        for j in sss[heapq.heappop(heap)[-1]]:
            kkk += 1
            if j == "(":
                s += 1
            else:
                s -= 1
            if s < 0:
                print("No")
                exit()


def ok(a):
    s = 0
    heap = []
    i = 0
    while True:
        while i < len(a) and a[i][1] + s >= 0:
            heapq.heappush(heap, a[i])
            i += 1
        if i < len(a) and not heap:
            print("No")
            exit()
        if not heap:
            break
        kkk = 0
        for j in reversed(sss[heapq.heappop(heap)[-1]]):
            kkk += 1
            if j == ")":
                s += 1
            else:
                s -= 1
            if s < 0:
                print("No")
                exit()


ok1(a)
ok(b)
print("Yes")


# Optimized solution
import heapq
import sys
input = sys.stdin.readline
n = int(eval(input()))
sss = [input()[:-1] for _ in range(n)]

a = []
b = []
ss = 0
ii = 0
for i in sss:
    mi = 0
    ma = 0
    s = 0
    for j in i:
        if j == "(":
            s += 1
        else:
            s -= 1
        mi = min(mi, s)
        ma = max(ma, s)
    ss += s
    if s >= 0:
        a.append([s, mi, ma, ii])
    else:
        mi = 0
        ma = 0
        s = 0
        for j in reversed(i):
            if j == ")":
                s += 1
            else:
                s -= 1
            mi = min(mi, s)
            ma = max(ma, s)
        b.append([s, mi, ma, ii])
    ii += 1


if ss != 0:
    print("No")
    exit()
a.sort(reverse=1, key=lambda x: x[1])
b.sort(reverse=1, key=lambda x: x[1])


def ok(a):
    s = 0
    for i, j, _, _ in a:
        if s + j < 0:
            print("No")
            exit()
        s += i

ok(a)
ok(b)
print("Yes")
# Original solution
n = int(input())
def gb(s):
	bal,m = 0,0
	for l in s: 
		bal += 1 if l == '(' else -1
		m = min(m, bal)
	return (bal,m)


rs = [gb(input()) for _ in range(n)]
rs.sort(key = lambda x: (0,-x[1], x[0]) if x[0]>=0 else (1,x[1] - x[0], -x[0]))

def f(rs):
	s = 0
	for aa,bb in rs:
		if s + bb < 0: return False
		s += aa
	return s == 0

print('Yes' if f(rs) else 'No')

# Optimized solution
n = int(input())
def gb(s):
	bal,m = 0,0
	for l in s: 
		bal += 1 if l == '(' else -1
		m = min(m, bal)
	return (bal,m)
-1 -1 -1 -3 -5 -11 -23 

-23 -11 -5 -3 -1 -1 -1

rs = [gb(input()) for _ in range(n)]
rs.sort(key = lambda x: (0, -x[1]) if x[0]>=0 else (1,x[1] - x[0], x[0]))

def f(rs):
	s = 0
	for aa,bb in rs:
		if s + bb < 0: return False
		s += aa
	return s == 0

print('Yes' if f(rs) else 'No')
# Original solution
from sys import exit
from itertools import accumulate,chain
n,*s=open(0).read().split()
t=list([2*x.count("(")-len(x) for x in s])
if sum(t)!=0:
    print("No")
    exit()
#pypyではinitialだめ
st=[[t_,min(accumulate(s_,lambda a,b: a+(1 if b=="(" else -1),initial=0))] for s_,t_ in zip(s,t)]

now=sum([x[0] for x in [x for x in st if x[1]>=0]])
v=list([x for x in st if x[1]<0 and x[0]>=0])
w=list([x for x in st if x[1]<0 and x[0]<0])
v.sort(reverse=True,key=lambda z:z[1])
w.sort(key=lambda z:z[0]-z[1],reverse=True)

for sub in chain(v,w):
    if now+sub[1]<0:
        print("No");exit()
    now+=sub[0]
print("Yes")


# Optimized solution
from sys import exit
from itertools import accumulate,chain
n,*s=open(0).read().split()
t=[2*(i.count("("))-len(i) for i in s]
if sum(t)!=0:
    print("No");exit()
#pypyではinitialだめ
st=[[t_,min(accumulate(s_,lambda a,b: a+(1 if b=="(" else -1),initial=0))] for s_,t_ in zip(s,t)]

now=0
v=list([x for x in st if x[0]>=0])
w=list([x for x in st if x[0]<0])
v.sort(reverse=True,key=lambda z:z[1])
w.sort(key=lambda z:z[0]-z[1],reverse=True)

for sub in chain(v,w):
    if now+sub[1]<0:
        print("No");exit()
    now+=sub[0]
print("Yes")
# Original solution
N,L=map(int,input().split());print(*(sorted([input() for _ in range(N)])),sep='')


# Optimized solution
n,l=map(int,input().split());print(*sorted([input() for _ in range(n)]),sep='')
# Original solution
# _*_ coding:utf-8 _*_
#  Atcoder_Beginners_Contest042-B
#  TODO https://atcoder.jp/contests/abc042/tasks/abc042_b
import time
from contextlib import contextmanager
# from time import sleep
@contextmanager
def timer(title):
	t0 = time.time()
	yield
	print(("{} - done in {:.0f}s".format(title,time.time()-t0) ))

def  makeString(givenStringCount):
	givenStringsList = []
	lineRange = list(range(0,givenStringCount,+1))
	for i in lineRange:
		givenStringsList.append(input().strip())
	givenStringsSortedList = sorted(givenStringsList,reverse=False)
	smallString = "".join(givenStringsSortedList)
	answer = smallString
	return answer


if __name__ == '__main__':
	N,_ = list(map(int,input().strip().split(' ')))
#	with timer("makeString"):
	solution=makeString(N)
	print(("{}".format(solution)))

# Optimized solution
# Problem: https://atcoder.jp/contests/abc042/tasks/abc042_b
# Python 1st Try

import sys
# from collections import defaultdict
# import heapq,copy
# from collections import deque


def II(): return int(sys.stdin.readline())


def MI(): return list(map(int, sys.stdin.readline().split()))


def LI(): return list(map(int, sys.stdin.readline().split()))


def LLI(rows_number): return [LI() for _ in range(rows_number)]


def solver(allNum, longLeng, eachString):
    result = ''
    eachString.sort()
    result = "".join(eachString)
    return result


if __name__ == "__main__":
    N, L = MI()
    SI = []
    for _ in range(0, N, +1):
        getStrList = sys.stdin.readline().split()
        SI.append(getStrList[0])
    print(("{}".format(solver(N, L, SI))))
# Original solution
N,L=map(int,input().split())
S=[]
for i in range (N):
	S.append(input())
K=sorted(S)

for i in range (N):
	print(K[i],end="")
print()


# Optimized solution
N,L=map(int,input().split())
S=[]
for i in range(N):
	S.append(input())
M=sorted(S)
for i in range(N):
	print(M[i],end="")
print()