CodeEff/ECCO huggingface dataset:
# Original solution
def dfs(i, j, s):
    if j > 3:
        return
    if j == 3 and sum(s) == x:
        res.append(1)

    for k in range(1, i):
        if sum(s) + k > x:
            break
        if k not in s:
            dfs(k, j + 1, s + [k])

ans = []
while True:
    res = []
    n, x = list(map(int, input().split()))
    if n == x == 0:
        break
    for i in range(3, n + 1):
        dfs(i, 1, [i])

    ans.append(sum(res))

print(("\n".join(map(str, ans))))


# Optimized solution
def calc(n, x):
    result = 0
    for i in range(3, n + 1):
        for j in range(2, i):
            if i + j < x < i + 2 * j:
                result += 1
    return str(result)

ans = []
while True:
    n, x = list(map(int, input().split()))
    if n == x == 0:
        break
    ans.append(calc(n, x))

print(("\n".join(ans)))
# Original solution
from itertools import product
from math import sqrt

def main():
    n = int(eval(input()))
    n_copy = n

    if n == 1:
        print((1))
        exit()

    if n % 2 == 0:
        ans = 2 * n - 1
        n *= 2
    else:
        ans = n - 1

    prime = [2, 3]
    for i in range(5, int(sqrt(n_copy)) + 1, 2):
        for p in prime:
            if p * p > i:
                prime.append(i)
                break

            if i % p == 0:
                break

    factors = []
    for p in prime:
        if p * p > n:
            if n > 1:
                factors.append(n)
            break

        if n % p == 0:
            cnt = 0
            while n % p == 0:
                cnt += 1
                n //= p
            factors.append(p ** cnt)

    for tf in product([True, False], repeat=len(factors)):
        a, b = 1, 1
        for i in range(len(factors)):
            if tf[i]:
                a *= factors[i]
            else:
                b *= factors[i]

        if a == 1 or b == 1:
            continue

        if a < b:
            a, b = b, a

        # Euclidean Algorithm
        # a*x - b*y = 1
        # quotient: 商
        l = []
        quo = []
        while a % b > 1:
            l.append(a)
            a = b
            quo.append(0)
            quo[-1], b = divmod(l[-1], b)
        x, y = 1, a//b
        flag = True
        while l:
            if flag:
                x += y * quo.pop()
                b = l.pop()
            else:
                y += x * quo.pop()
                a = l.pop()
            flag = not flag

        if ans > b * y:
            ans = b * y

    print(ans)

main()

# Optimized solution
from itertools import product

def main():
    n = int(eval(input()))
    n_copy = n

    if n == 1:
        print((1))
        exit()

    if n % 2 == 0:
        ans = 2 * n - 1
        n *= 2
    else:
        ans = n - 1

    factors = []
    for p in range(2, n):
        if p * p > n:
            if n > 1:
                factors.append(n)
            break

        if n % p == 0:
            cnt = 0
            while n % p == 0:
                cnt += 1
                n //= p
            factors.append(p ** cnt)

    for tf in product([True, False], repeat=len(factors)):
        a, b = 1, 1
        for i in range(len(factors)):
            if tf[i]:
                a *= factors[i]
            else:
                b *= factors[i]

        if a == 1 or b == 1:
            continue

        if a < b:
            a, b = b, a

        # Euclidean Algorithm
        # a*x - b*y = 1
        # quotient: 商
        l = []
        quo = []
        while a % b > 1:
            l.append(a)
            a = b
            quo.append(0)
            quo[-1], b = divmod(l[-1], b)
        x, y = 1, a//b
        flag = True
        while l:
            if flag:
                x += y * quo.pop()
                b = l.pop()
            else:
                y += x * quo.pop()
                a = l.pop()
            flag = not flag

        if ans > b * y:
            ans = b * y

    print(ans)

main()
# Original solution
import sys

sys.setrecursionlimit(10**7)
def I(): return int(sys.stdin.readline().rstrip())
def MI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))  #空白あり
def LI2(): return list(map(int,sys.stdin.readline().rstrip()))  #空白なし
def S(): return sys.stdin.readline().rstrip()
def LS(): return list(sys.stdin.readline().rstrip().split())  #空白あり
def LS2(): return list(sys.stdin.readline().rstrip())  #空白なし


def extgcd(a, b):
    if b:
        d, y, x = extgcd(b, a % b)
        y -= (a // b) * x
        return d, x, y
    return a, 1, 0


# V = [(X_i, Y_i), ...]: X_i (mod Y_i)
def remainder(V):
    x = 0; d = 1
    for X, Y in V:
        g, a, b = extgcd(d, Y)
        x, d = (Y*b*x + d*a*X) // g, d*(Y // g)
        x %= d
    return x, d


N = I()


def prime_factorization(n):
    ANS = {}
    for i in range(2,int(n**.5)+1):
        if n % i == 0:
            r = 0  # nがiで何回割り切れるか
            while n % i == 0:
                n //= i
                r += 1
            ANS[i] = r
    if n != 1:
        ANS[n] = 1
    return ANS


prime = prime_factorization(N)
if not 2 in list(prime.keys()):
    prime[2] = 1
else:
    prime[2] += 1

A = list(prime.keys())
B = list(prime.values())
l = len(A)


ans = 2*N
from itertools import product

for a in list(product([-1,0],repeat=l)):
    for i in range(l):
        if a[i] != 0:
            break
    else:
        continue

    V = [(a[i],A[i]**B[i]) for i in range(l)]
    x,d = remainder(V)
    ans = min(ans,x)

print(ans)


# Optimized solution
import sys
from itertools import product
def I(): return int(sys.stdin.readline().rstrip())


def ext_gcd(a, b):
    if b:
        d, y, x = ext_gcd(b, a % b)
        y -= (a // b) * x
        return d, x, y
    return a, 1, 0


# V = [(X_i, Y_i), ...]: X_i (mod Y_i)
def remainder(V):
    x = 0; d = 1
    for X, Y in V:
        g, a, b = ext_gcd(d, Y)
        x, d = (Y*b*x + d*a*X) // g, d*(Y // g)
        x %= d
    return x, d


def prime_factorization(n):
    res = {}
    for i in range(2,int(n**.5)+1):
        if n % i == 0:
            r = 0  # nがiで何回割り切れるか
            while n % i == 0:
                n //= i
                r += 1
            res[i] = r
    if n != 1:
        res[n] = 1
    return res


N = I()

prime_fac = prime_factorization(N)
if 2 in list(prime_fac.keys()):
    prime_fac[2] += 1
else:
    prime_fac[2] = 1

# prime_fac = 2*N の素因数分解
# 2*N|k*(k+1)
# 中国剰余定理を用いる

A = list(prime_fac.keys())
l = len(A)

ans = 2*N

for a in list(product([-1,0],repeat=l)):
    V = [(a[i],A[i]**prime_fac[A[i]]) for i in range(l)]
    x,d = remainder(V)
    if x != 0:
        ans = min(ans,x)

print(ans)
# Original solution
from itertools import product
def prime_factors(N): #素因数 1を含まないことに注意
    ret = []
    middle = int( N**(1/2))
    tmp = N
    for i in range(2, middle+1):
        if tmp%i == 0:
            t = 1
            while tmp%i == 0:
                tmp //= i
                t *= i
            ret.append(t)
    if tmp != 1:
        ret.append(tmp)
    return ret

def xgcd(a, b):
    x0, y0, x1, y1 = 1, 0, 0, 1
    while b != 0:
        q, a, b = a // b, b, a % b
        x0, x1 = x1, x0 - q * x1
        y0, y1 = y1, y0 - q * y1
    return a, x0, y0

def main():
    N = int( eval(input()))
    P = prime_factors(2*N)
    M = len(P)
    ans = 2*N-1
    for p in product( list(range(2)), repeat=M):
        x = 1
        for i, t in enumerate(p):
            if t == 1:
                x *= P[i]
        y = N*2//x
        if x == 1:
            if y-1 < ans:
                ans = y-1
            continue
        if y == 1:
            if x-1 < ans:
                ans = x-1
            continue
        _, a, b = xgcd(x,y)
        now = -a*x
        # print(x, y, a, b)
        if a < 0:
            pass
        else:
            now = -b*y
        if now < ans:
            ans = now
    print(ans)
        
        
if __name__ == '__main__':
    main()


# Optimized solution
from itertools import product
def prime_factors(N): #素因数 1を含まないことに注意
    ret = []
    middle = int( N**(1/2))
    tmp = N
    for i in range(2, middle+1):
        if tmp%i == 0:
            t = 1
            while tmp%i == 0:
                tmp //= i
                t *= i
            ret.append(t)
    if tmp != 1:
        ret.append(tmp)
    return ret

def xgcd(a, b):
    x0, y0, x1, y1 = 1, 0, 0, 1
    while b != 0:
        q, a, b = a // b, b, a % b
        x0, x1 = x1, x0 - q * x1
        y0, y1 = y1, y0 - q * y1
    return a, x0, y0

def main():
    N = int( eval(input()))
    # print("start")
    P = prime_factors(2*N)
    M = len(P)
    ans = 2*N-1
    # print(M)
    for p in product( list(range(2)), repeat=M):
        x = 1
        for i, t in enumerate(p):
            if t == 1:
                x *= P[i]
        y = N*2//x
        if x == 1:
            if y-1 < ans:
                ans = y-1
            continue
        if y == 1:
            if x-1 < ans:
                ans = x-1
            continue
        _, a, b = xgcd(x,y)
        now = -a*x
        # print(x, y, a, b)
        if a < 0:
            pass
        else:
            now = -b*y
        if now < ans:
            ans = now
    print(ans)
        
        
if __name__ == '__main__':
    main()
# Original solution
import copy
N = int(eval(input()))
K = [[1, N]]
for i in range(2, max(int(N**0.5)+1, 2)):
    if N % i == 0:
        K.append([i, N//i])

ans = 3*N
for i in range(len(K)):
    a, b = K[i]
    p = copy.copy(b)
    while(True):
        if b > ans:
            break
        if (2*b-1) % a == 0:
            ans = min(ans, 2*b-1)
        elif (2*b+1) % a == 0:
            ans = min(ans, 2*b)
        if b % 2 == 1:
            if ((b - 1) // 2) % a == 0:
                ans = min(ans, b - 1)
            elif ((b + 1) // 2) % a == 0:
                ans = min(ans, b)
        b += p

if N == 1:
    print((1))
elif N == 2:
    print((3))
else:
    print(ans)

# Optimized solution
import math
def extgcd(a, b):
    """
    ax + by = gcd(a,b) = d となる (x,y,d) を返す
    """
    if b == 0:
        return (1, 0, a)
    q, r = a // b, a % b
    x, y, d = extgcd(b, r)
    s, t = y, x - q * y
    return s, t, d

def inv_mod(a, N):
    """
    ax = 1 mod N となる x を返す
    """
    return extgcd(a, N)[0]

def CRT(a_1, a_2, m_1, m_2):
    """
    x = a_1 mod m_1, x = a_2 mod m_2 となる x を返す
    """
    y = (a_2 - a_1) * inv_mod(m_1, m_2) % m_2
    return a_1 + m_1 * y

N = int(eval(input()))
N *= 2
K = [[1, N]]
for i in range(2, max(int(N**0.5)+1, 2)):
    if N % i == 0:
        K.append([i, N//i])

ans = float("inf")
for i in range(len(K)):
    a, b = K[i]
    if math.gcd(a, b) == 1:
        P = CRT(0, -1, a, b)
        if P != 0:
            ans = min(P, ans)
        Q = CRT(0, -1, b, a)
        if Q != 0:
            ans = min(Q, ans)

print(ans)
# Original solution
import sys
from collections import deque
input = sys.stdin.readline
 
 
def inv_gcd(a, b):
    a = (a + b) % b
    if a == 0:
        return (b, 0)
    s, t = b, a
    m0, m1 = 0, 1
 
    while t:
        u = s // t
        s -= t * u
        m0 -= m1 * u
 
        tmp = s
        s = t
        t = tmp
        tmp = m0
        m0 = m1
        m1 = tmp
    
    if m0 < 0:
        m0 += b // s
    return (s, m0)
 
 
def crt(r, m):
    n = len(r)
    r0, m0 = 0, 1
 
    for i in range(n):
        r1, m1 = (r[i] + m[i]) % m[i], m[i]
 
        if m0 < m1:
            m0, m1 = m1, m0
            r0, r1 = r1, r0
        
        if m0 % m1 == 0:
            if r0 % m1 != r1:
                return (0, 0)
            continue
        
        g, im = inv_gcd(m0, m1)
 
        u1 = m1 // g
        if (r1 - r0) % g:
            return (0, 0)
        
        x = (r1 - r0) // g % u1 * im % u1
 
        r0 += x * m0
        m0 *= u1
        if (r0 < 0):
            r0 += m0
        
    return (r0, m0)
 
 
def make_divisors(n):
    divisors = []
    for i in range(1, int(n**0.5)+1):
        if n % i == 0:
            divisors.append(i)
            if i != n // i:
                divisors.append(n//i)
    divisors.sort()
    return divisors
 
 
def main():
    n = int(eval(input()))
    divisors = make_divisors(2 * n)
 
    ans = n-1 if n%2 else 2*n-1
    for x in divisors:
        y = n * 2 // x
        if y == 1:
            continue
        r = [0, y-1]
        m = [x, y]
        rem, mod = crt(r, m)
        if rem == mod == 0:
            continue
        ans = min(ans, rem)
 
    
    print((ans if n-1 else 1))
 
    
if __name__ == "__main__":
    main()

# Optimized solution
def inv_gcd(a, b):
    a = (a + b) % b
    if a == 0:
        return (b, 0)
    s, t = b, a
    m0, m1 = 0, 1
 
    while t:
        u = s // t
        s -= t * u
        m0 -= m1 * u
 
        tmp = s
        s = t
        t = tmp
        tmp = m0
        m0 = m1
        m1 = tmp
    
    if m0 < 0:
        m0 += b // s
    return (s, m0)
 
 
def crt(r, m):
    n = len(r)
    r0, m0 = 0, 1
 
    for i in range(n):
        r1, m1 = (r[i] + m[i]) % m[i], m[i]
 
        if m0 < m1:
            m0, m1 = m1, m0
            r0, r1 = r1, r0
        
        if m0 % m1 == 0:
            if r0 % m1 != r1:
                return (0, 0)
            continue
        
        g, im = inv_gcd(m0, m1)
 
        u1 = m1 // g
        if (r1 - r0) % g:
            return (0, 0)
        
        x = (r1 - r0) // g % u1 * im % u1
 
        r0 += x * m0
        m0 *= u1
        if (r0 < 0):
            r0 += m0
        
    return (r0, m0)


def divisors(n):
  divisors = []
  for i in range(1, int(n**0.5)+1):
    if n % i == 0:
      divisors.append(i)
      if i != n // i:
        divisors.append(n//i)
  divisors.sort()
  return divisors


# print(divisors(z))

z=int(eval(input()))


ans = z-1 if z%2 else 2*z-1
for i in divisors(2*z):
  y=2*z//i
  if y == 1:
    continue
  a=[0,-1]
  b=[i,y]
  rem, mod = crt(a, b)
  #print(rem)
  #print(mod)
  if rem == mod == 0:
      continue
  ans = min(ans, rem)

print((ans if z-1 else 1))
# Original solution
#素因数分解、計算量はO(√N)
from collections import defaultdict
def factorize(n):
  b = 2
  dic = defaultdict(lambda: 0)
  while b * b <= n:
    while n % b == 0:
      n //= b
      dic[b] += 1
    b = b + 1
  if n > 1:
    dic[n] += 1
  return dic
N = int(eval(input()))
fct = factorize(2*N)
lis = []
for k,v in list(fct.items()):
  lis.append(pow(k,v))
lis.sort(reverse=True)
ans = 10**18
from itertools import groupby, accumulate, product, permutations, combinations
for pro in product([1,0],repeat=len(lis)):
  prod1 = 1
  for i,p in enumerate(pro):
    if p==1:
      prod1 *= lis[i]
  prod2 = (N*2)//prod1
  if prod1<prod2:
    # prod1,prod2 = prod2,prod1
    continue
  for i in range(1,prod2+1):
    if prod1*i>ans:
      break
    if (prod1*i-1)%prod2==0:
      ans = min(ans, prod1*i-1)
      break
    if (prod1*i+1)%prod2==0:
      ans = min(ans, prod1*i)
      break
print(ans)



# Optimized solution
#素因数分解、計算量はO(√N)
from collections import defaultdict
def factorize(n):
  b = 2
  dic = defaultdict(lambda: 0)
  while b * b <= n:
    while n % b == 0:
      n //= b
      dic[b] += 1
    b = b + 1
  if n > 1:
    dic[n] += 1
  return dic
N = int(eval(input()))
fct = factorize(2*N)
lis = []
for k,v in list(fct.items()):
  lis.append(pow(k,v))
ans = 10**18
from itertools import groupby, accumulate, product, permutations, combinations
for pro in product([1,0],repeat=len(lis)):
  prod1 = 1
  for i,p in enumerate(pro):
    if p==1:
      prod1 *= lis[i]
  prod2 = (N*2)//prod1
  if prod1<prod2:
    # prod1,prod2 = prod2,prod1
    continue
  for i in range(1,prod2+1):
    if prod1*i>ans:
      break
    if (prod1*i-1)%prod2==0:
      ans = min(ans, prod1*i-1)
      break
    if (prod1*i+1)%prod2==0:
      ans = min(ans, prod1*i)
      break
print(ans)
# Original solution
#素因数分解、計算量はO(√N)
from collections import defaultdict
def factorize(n):
  b = 2
  dic = defaultdict(lambda: 0)
  while b * b <= n:
    while n % b == 0:
      n //= b
      dic[b] += 1
    b = b + 1
  if n > 1:
    dic[n] += 1
  return dic
N = int(eval(input()))
fct = factorize(2*N)
lis = []
for k,v in list(fct.items()):
  lis.append(pow(k,v))
ans = 10**18
from itertools import groupby, accumulate, product, permutations, combinations
for pro in product([0,1],repeat=len(lis)):
  prod1 = 1
  for i,p in enumerate(pro):
    if p==1:
      prod1 *= lis[i]
  prod2 = (N*2)//prod1
  if prod1<prod2:
    prod1,prod2 = prod2,prod1
    # continue
  for i in range(1,prod2+1):
    # if prod1*i>ans:
      # break
    if (prod1*i-1)%prod2==0:
      ans = min(ans, prod1*i-1)
      break
    if (prod1*i+1)%prod2==0:
      ans = min(ans, prod1*i)
      break
print(ans)



# Optimized solution
#素因数分解、計算量はO(√N)
from collections import defaultdict
def factorize(n):
  b = 2
  dic = defaultdict(lambda: 0)
  while b * b <= n:
    while n % b == 0:
      n //= b
      dic[b] += 1
    b = b + 1
  if n > 1:
    dic[n] += 1
  return dic

def extgcd(a, b):
  if b:
    d, y, x = extgcd(b, a%b)
    y -= (a//b)*x
    return d, x, y
  else:
    return a, 1, 0
N = int(eval(input()))
fct = factorize(2*N)
lis = []
for k,v in list(fct.items()):
  lis.append(pow(k,v))
ans = 10**18
from itertools import groupby, accumulate, product, permutations, combinations
for pro in product([0,1],repeat=len(lis)):
  prod1 = 1
  for i,p in enumerate(pro):
    if p==1:
      prod1 *= lis[i]
  prod2 = (N*2)//prod1
  if min(prod1,prod2)==1:
    ans = min(ans, max(prod1,prod2)-1)
  else:
    d,a1,a2 = extgcd(prod1,prod2)
    ans = min(ans, min(abs(a1*prod1),abs(a2*prod2)))
print(ans)
# Original solution
import math

N=int(eval(input()))

ANS=[0,1, 3, 2, 7, 4, 3, 6, 15, 8, 4, 10, 8, 12, 7, 5, 31, 16, 8, 18, 15, 6, 11, 22, 15, 24, 12, 26, 7, 28, 15, 30, 63, 11, 16, 14, 8, 36, 19, 12, 15, 40, 20, 42, 32, 9, 23, 46, 32, 48, 24, 17, 39, 52, 27, 10, 48, 18, 28, 58, 15, 60, 31, 27, 127, 25, 11, 66, 16, 23, 20, 70, 63, 72, 36, 24, 56, 21, 12, 78, 64, 80, 40, 82, 48, 34, 43, 29, 32, 88, 35, 13, 23, 30, 47, 19, 63, 96, 48, 44, 24]


if N<=100:
    print((ANS[N]))
    exit()


def ff(x):
    L=int(math.sqrt(x))

    FACT=dict()

    for i in range(2,L+2):
        while x%i==0:
            FACT[i]=FACT.get(i,0)+1
            x=x//i

    if x!=1:
        FACT[x]=FACT.get(x,0)+1

    return FACT

# 拡張ユークリッドの互除法.ax+by=gcd(a,b)となる(x,y)を一つ求め、(x,y)とgcd(x,y)を返す.
def Ext_Euc(a,b,axy=(1,0),bxy=(0,1)): # axy=a*1+b*0,bxy=a*0+b*1なので,a,bに対応する係数の初期値は(1,0),(0,1)
    # print(a,b,axy,bxy)
    q,r=divmod(a,b)

    if r==0:
        return bxy,b # a*bxy[0]+b*bxy[1]=b
   
    rxy=(axy[0]-bxy[0]*q,axy[1]-bxy[1]*q) # rに対応する係数を求める.
    return Ext_Euc(b,r,bxy,rxy)

FACT=ff(N*2)
LIST=[]
for f in FACT:
    LIST.append(f**FACT[f])
    
L=len(LIST)

LANS=1<<60

for i in range(1,(1<<L)-1):
    A=1
    B=1
    for j in range(L):
        if i & (1<<j)!=0:
            A*=LIST[j]
        else:
            B*=LIST[j]
    #print(A,B)
    #print(Ext_Euc(A,-B))
    x,_=Ext_Euc(A,-B)
    x,y=x[0],x[1]
    # ANS=x+B*k

    if x<0:
        x+=(1+abs(x)//B)*B
    #k=(B+x-1)//x
    #ANS=x+B*k
    #print(x,B,k,ANS)
    LANS=min(LANS,x*A)

print(LANS)
    


# Optimized solution
import math

N=int(eval(input()))

def ff(x):
    L=int(math.sqrt(x))

    FACT=dict()

    for i in range(2,L+2):
        while x%i==0:
            FACT[i]=FACT.get(i,0)+1
            x=x//i

    if x!=1:
        FACT[x]=FACT.get(x,0)+1

    return FACT

# 拡張ユークリッドの互除法.ax+by=gcd(a,b)となる(x,y)を一つ求め、(x,y)とgcd(x,y)を返す.
def Ext_Euc(a,b,axy=(1,0),bxy=(0,1)): # axy=a*1+b*0,bxy=a*0+b*1なので,a,bに対応する係数の初期値は(1,0),(0,1)
    # print(a,b,axy,bxy)
    q,r=divmod(a,b)

    if r==0:
        return bxy,b # a*bxy[0]+b*bxy[1]=b
   
    rxy=(axy[0]-bxy[0]*q,axy[1]-bxy[1]*q) # rに対応する係数を求める.
    return Ext_Euc(b,r,bxy,rxy)

FACT=ff(N*2)
LIST=[]
for f in FACT:
    LIST.append(f**FACT[f])
    
L=len(LIST)

LANS=2*N-1

for i in range(1<<L):
    A=1
    B=1
    for j in range(L):
        if i & (1<<j)!=0:
            A*=LIST[j]
        else:
            B*=LIST[j]
    if A==1 or B==1:
        continue

    x,_=Ext_Euc(A,-B)
    x,y=x[0],x[1]

    if x<0:
        x+=(1+abs(x)//B)*B

    LANS=min(LANS,x*A)

print(LANS)
# Original solution
from math import sqrt
from decimal import *
import decimal
N=int(eval(input()))
getcontext().prec=30
"""
l=[]
pf={}
m=N
for i in range(2,int(m**0.5)+1):
    while m%i==0:
        pf[i]=pf.get(i,0)+1
        m//=i
if m>1:pf[m]=1
print(pf)
keys=list(pf.keys())
values=list(pf.values())
for i in range(len(keys)):
    l.append([keys[i],values[i]])
print(l)
"""
a=1
while True:
    t=Decimal(1+8*a*N).sqrt()
    #print(t)
    #print(t.to_integral_value())
    n=t.to_integral_value()
    if (pow(n,Decimal(2),1+8*a*N)==0)and(int(t)%2==1):
        print(((int(t)-1)//2))
        break
    a=a+1


# Optimized solution
from math import sqrt
from collections import deque
def ggcd(a,b):
    if(b==0):
        return a
    return ggcd(b,a%b)
N=int(eval(input()))
def gcd_ext(a, b):
    x, y, lastx, lasty = 0, 1, 1, 0
    while b != 0:
        q = a // b
        a, b = b, a % b
        x, y, lastx, lasty = lastx - q * x, lasty - q * y, x, y
    return (lastx, lasty)
l=[]
pf={}
m=N*2
for i in range(2,int(m**0.5)+1):
    while m%i==0:
        pf[i]=pf.get(i,0)+1
        m//=i
if m>1:pf[m]=1
#print(pf)
keys=list(pf.keys())
values=list(pf.values())
for i in range(len(keys)):
    l.append([keys[i],values[i]])
#print(l)
d=deque()
d.append([])

for i in range(len(l)):
    x=list(range(values[i]+1))
    d2 = deque()
    #print(x)
    while len(d)>0:
        l=d.popleft()
        for j in x:
            l2=l[:]
            l2.append(j)
            d2.append(l2)
    d=d2
    #print(d)
ans=float("inf")
x=0
y=0
while len(d)>0:
    l=d.popleft()
    num=1
    res=1
    for i in range(len(l)):
        num=num*pow(keys[i],l[i])
        res=res*pow(keys[i],values[i]-l[i])
    #print(num,res)
    #x*num=k+1のときを考える
    if ggcd(num,res)==1:
        #x*num+y*res=1
        x,y=gcd_ext(num,res)
        if (x==0)or(y==0):
            x1=x+num*res
            y1=y+num+res
            ans=min(ans,x1*num-1)
            x2=x-num*res
            y2=x-num*res
            ans=min(ans,-x2*num)
        else:#どっちかは+でどっちかは-
            if x>y:
                ans=min(ans,x*num-1)
                x1=x-num*res
                ans=min(ans,-x1*num)
            else:
                x1=x+num*res
                ans=min(ans,x1*num-1)
                ans=min(ans,-x*num)
print(ans)
# Original solution
MOD = 10 ** 9 + 7


def main():
  N, K = list(map(int, input().strip().split()))
  dp = {}

  keys = []
  i = 1
  while i <= N:
    v = N // i
    j = N // v
    keys.append((v, j - i + 1))
    i += j - i + 1

  total = 0
  for nj, w in keys:
    total += w
    dp[nj] = total

  for i in range(2, K + 1):
    tmp = {}
    total = 0
    for nj, w in keys:
      j = N // nj
      v = dp[j] * w
      total += v
      total %= MOD
      tmp[nj] = total

    dp = tmp

  return dp[1]


if __name__ == '__main__':
  print((main()))

# Optimized solution
MOD = 10 ** 9 + 7


def main(N, K):
  W = []
  i = 1
  while i <= N:
    v = N // i
    j = N // v
    # keys.append((v, j - i + 1))
    W.append(j - i + 1)
    i += j - i + 1

  l = len(W)
  dp = [0] * l

  total = 0
  for i, w in enumerate(W):
    total += w
    dp[l - i - 1] = total

  for i in range(2, K + 1):
    tmp = [0] * l
    total = 0
    for j, w in enumerate(W):
      v = dp[j] * w
      total += v
      total %= MOD
      tmp[l - j - 1] = total

    dp = tmp

  return dp[0]


if __name__ == '__main__':
  N, K = list(map(int, input().strip().split()))
  # import time
  # t = time.time()
  print((main(N, K)))
  # print(time.time() - t)