# Original solution
class UnionFind:
    """Union-Find: O(α(N))"""

    __slots__ = ["_data_size", "_first_idx", "_parents"]

    def __init__(self, data_size: int, is_zero_origin: bool = True) -> None:
        self._data_size = data_size
        self._first_idx = 0 if is_zero_origin else 1
        self._parents = [-1] * (data_size + self._first_idx)

    def _find(self, x: int) -> int:
        if self._parents[x] < 0:
            return x
        self._parents[x] = self._find(self._parents[x])
        return self._parents[x]

    def is_connected(self, x: int, y: int) -> bool:
        """Return whether two vertices x and y are connected or not."""
        return self._find(x) == self._find(y)

    def unite(self, x: int, y: int) -> None:
        """Unite two groups of vertices x and y."""
        x, y = self._find(x), self._find(y)
        if x == y:
            return
        if self._parents[x] > self._parents[y]:
            x, y = y, x
        self._parents[x] += self._parents[y]
        self._parents[y] = x


def unionfind():
    # https://judge.yosupo.jp/problem/unionfind
    # https://atcoder.jp/contests/practice2/tasks/practice2_a
    N, Q, *TUV = list(map(int, open(0).read().split()))
    tree = UnionFind(N)
    res = []
    for t, u, v in zip(*[iter(TUV)] * 3):
        if t:
            res.append(int(tree.is_connected(u, v)))
        else:
            tree.unite(u, v)
    print(("\n".join(map(str, res))))


if __name__ == "__main__":
    unionfind()


# Optimized solution
class UnionFind:
    __slots__ = ["N", "root", "rank"]

    def __init__(self, N):
        """
        N:要素数
        root:各要素の親要素の番号を格納するリスト.
             ただし, root[x] < 0 ならその頂点が根で-root[x]が木の要素数.
        rank:ランク
        """
        self.N = N
        self.root = [-1] * N

    def __repr__(self):
        return "\n".join("{}: {}".format(r, self.members(r)) for r in self.roots())

    def find(self, x):
        """頂点xの根を見つける"""
        while self.root[x] >= 0:
            x = self.root[x]
        return x

    def union(self, x, y):
        """x, yが属する木をunion"""
        # 根を比較する
        # すでに同じ木に属していた場合は何もしない.
        # 違う木に属していた場合はrankを見てくっつける方を決める.
        # rankが同じ時はrankを1増やす
        x = self.find(x)
        y = self.find(y)
        if x == y:
            return
        elif self.root[y] < self.root[x]:
            x, y = y, x
        self.root[x] += self.root[y]
        self.root[y] = x

    def same(self, x, y):
        """xとyが同じグループに属するかどうか"""
        return self.find(x) == self.find(y)

    def count(self, x):
        """頂点xが属する木のサイズを返す"""
        return -self.root[self.find(x)]

    def members(self, x):
        """xが属する木の要素を列挙"""
        _root = self.find(x)
        return [i for i in range(self.N) if self.find == _root]

    def roots(self):
        """森の根を列挙"""
        return [i for i, x in enumerate(self.root) if x < 0]

    def group_count(self):
        """連結成分の数"""
        return len(self.roots())

    def all_group_members(self):
        """{ルート要素: [そのグループに含まれる要素のリスト], ...}の辞書を返す"""
        return {r: self.members(r) for r in self.roots()}


def main():
    import sys
    input = sys.stdin.readline

    n, q = list(map(int, input().split()))
    uf = UnionFind(n)
    res = []
    for i in range(q):
        t, u, v = list(map(int, input().split()))
        if t:
            res.append(int(uf.same(u, v)))
        else:
            uf.union(u, v)
    print(("\n".join(map(str, res))))


if __name__ == "__main__":
    main()