Chinastark/bird_dataset huggingface dataset:
Database: movielens
Question: What is the proportion of action movies directors who are called 'box office success paradox'?
Evidence: 'box office success paradox' means average revenue exceeds their quality; The proportion can be computed by [(avg_revenue > d_quality) / ()] * 100%
SQL: SELECT CAST(SUM(IIF(T2.avg_revenue > T2.d_quality, 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN directors AS T2 ON T1.directorid = T2.directorid WHERE T1.genre = 'Action'
Database: movielens
Question: Please list the actor IDs whose movies have the newest published date.
Evidence: Year contains relative value, higher year value refers to newer date; Year = 4 refers to newest date
SQL: SELECT T1.actorid FROM movies2actors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.year = 4
Database: movielens
Question: Who are cast members in an English movie which has a running time equal to 2? Please list their IDs.
Evidence: isEnglish = 'T' means English movie
SQL: SELECT T2.actorid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.runningtime = 2 AND T1.isEnglish = 'T'
Database: movielens
Question: Which actor has acted in at least 2 French films? Please list their IDs.
Evidence: France is a country
SQL: SELECT T2.actorid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'France' GROUP BY T2.actorid HAVING COUNT(T1.movieid) > 2
Database: movielens
Question: How many American movies have cast number more than 1?
Evidence: USA is a country
SQL: SELECT COUNT(T2.actorid) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'USA' AND T2.cast_num > 1
Database: movielens
Question: Please list movie IDs which has the oldest publication date and the cast numbers are zero.
Evidence: Year contains relative value, higher year value refers to newer date; Year = 1 refer to oldest date
SQL: SELECT DISTINCT T1.movieid FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.year = 1 AND T2.cast_num = 0
Database: movielens
Question: How many actors have acted in both US or UK films?
Evidence: US and UK are 2 countries
SQL: SELECT COUNT(T1.actorid) FROM movies2actors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'USA' OR T2.country = 'UK'
Database: movielens
Question: How many directors with average revenue of 4 have made either action or adventure films?
SQL: SELECT COUNT(T1.directorid) FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.avg_revenue = 4 AND (T2.genre = 'Adventure' OR T2.genre = 'Action')
Database: movielens
Question: Please list director IDs who have the quality of at least 3 and have made at least 2 different genres of movies.
SQL: SELECT T1.directorid FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality >= 3 GROUP BY T1.directorid HAVING COUNT(T2.movieid) >= 2
Database: movielens
Question: How many American comedies are there?
Evidence: USA is a country
SQL: SELECT COUNT(T1.movieid) FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'USA' AND T2.genre = 'comedy'
Database: movielens
Question: How many latest released dramas and action movies?
SQL: SELECT COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.year = 4 AND T1.genre IN ('Action', 'drama')
Database: movielens
Question: What horror movies have a running time of at least 2? Please list movie IDs.
Evidence: Higher value of running time means running time is longer
SQL: SELECT T1.movieid FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.runningtime >= 2 AND T1.genre = 'Horror'
Database: movielens
Question: Please calculate negative critical reception of American movies
Evidence: 'negative critical reception' refers to percentage of movies with a rating of 1, which = [count(rating = 1) / count(all movies)] * 100% 
SQL: SELECT CAST(SUM(IIF(T1.rating = 1, 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'USA'
Database: movielens
Question: What is the disparate number of the comedy films that got the 1 rating?
SQL: SELECT COUNT(DISTINCT T1.movieid) FROM movies2directors AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T2.rating = 1 AND T1.genre = 'comedy'
Database: movielens
Question: What's different average revenue status for director who directed the movie that got the most 1 ratings?
SQL: SELECT DISTINCT T1.avg_revenue FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 5
Database: movielens
Question: How many French movies got the highest ranking?
Evidence: France is a country
SQL: SELECT COUNT(movieid) FROM movies WHERE country = 'France' AND movieid IN ( SELECT movieid FROM u2base WHERE rating = ( SELECT MAX(rating) FROM u2base ) )
Database: movielens
Question: List the movie that has been rated most by 25 years old users.
SQL: SELECT T2.movieid FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T1.age = 25 GROUP BY T2.movieid ORDER BY COUNT(T1.userid) DESC LIMIT 1
Database: movielens
Question: How many separate 35 year-old uesers have rated the movie from UK?
Evidence: UK is a country
SQL: SELECT COUNT(DISTINCT T2.userid) FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid INNER JOIN users AS T3 ON T2.userid = T3.userid WHERE T1.country = 'UK' AND T3.age = 35
Database: movielens
Question: List the user ids and ages who gave the rate 2 to the movie No. 2409051.
SQL: SELECT T1.userid, T1.age FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T2.movieid = '2409051' AND T2.rating = 2
Database: movielens
Question: Please give the ids of the oldest films that got the most ratings.
Evidence: Films and movies share the same meaning; oldest film refers to the movie with year = 1
SQL: SELECT DISTINCT T1.movieid FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T1.rating = 5 AND T2.year = 1
Database: movielens
Question: Which different movies from France got the least ratings?
Evidence: France is a country
SQL: SELECT DISTINCT T1.movieid FROM u2base AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid WHERE T2.country = 'France' AND T1.rating = 1
Database: movielens
Question: How many female actors have been played a role in any of French or USA movies?
Evidence: French and USA are two countries; Female actors mean that a_gender = 'F'
SQL: SELECT COUNT(T2.actorid) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.country IN ('France', 'USA')
Database: movielens
Question: How many different actors have played a role in the highest rating movie?
Evidence: highest rating of a movie is 5
SQL: SELECT COUNT(DISTINCT T2.actorid) FROM u2base AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid WHERE T1.rating = 5
Database: movielens
Question: Which Crime film got the lowest average rating?
SQL: SELECT T2.movieid FROM u2base AS T2 INNER JOIN movies2directors AS T3 ON T2.movieid = T3.movieid WHERE T3.genre = 'Crime' GROUP BY T2.movieid ORDER BY AVG(T2.rating) LIMIT 1
Database: movielens
Question: What's the ratio of gender in actors to actress in all the UK movies?
Evidence: UK is a country; Male actors mean that a_gender = 'M'; Female actors mean that a_gender = 'F'; ratio; ratio of gender in actors = count(a_gender = 'M') / a_gender = 'F'
SQL: SELECT CAST(SUM(IIF(T3.a_gender = 'M', 1, 0)) AS REAL) / SUM(IIF(T3.a_gender = 'F', 1, 0)) FROM movies AS T1 INNER JOIN movies2actors AS T2 ON T1.movieid = T2.movieid INNER JOIN actors AS T3 ON T2.actorid = T3.actorid WHERE T1.country = 'UK'
Database: movielens
Question: How many 35-year-old female users gave the movie 1711133 a rating of 3?
Evidence: Female users mean that u_gender = 'F'
SQL: SELECT COUNT(T1.userid) FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid WHERE T2.rating = 3 AND T2.movieid = '1711133' AND T1.age = 35 AND T1.u_gender = 'F'
Database: movielens
Question: How many users have rated 1 each for the UK's second newest movies with a running time of 2?
Evidence: second newest movies refers to year = 2 since year in this database is a relative value, less is the newer
SQL: SELECT COUNT(T2.userid) FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'UK' AND T1.runningtime = 2 AND T2.rating = 1 AND T1.year = 2
Database: movielens
Question: How many unique directors with an average earnings of 2 and a quality of 3 have not made comedy films? List them.
SQL: SELECT DISTINCT T1.directorid FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 3 AND T1.avg_revenue = 2 AND T2.genre != 'Comedy'
Database: movielens
Question: Calculate the percentage of female actors and quality 2 who have appeared twice at the casting of the film 1672580.
Evidence: Female actors mean that a_gender = 'F'; percentage can be computed by [cast_num = 2 AND a_quality = 2 in female) / (all female actors)] * 100%
SQL: SELECT CAST(SUM(IIF(T2.cast_num = 2 AND T1.a_quality = 2, 1, 0)) AS REAL) * 100 / COUNT(T1.actorid) FROM actors AS T1 INNER JOIN movies2actors AS T2 ON T1.actorid = T2.actorid WHERE T2.movieid = 1672580 AND T1.a_gender = 'F'
Database: movielens
Question: How many of the worst actors are men and how many of the worst actors are women? Indicate your answer in ratio form.
Evidence: The worst actors means a_quality = 0; Men and male share the same meaning; men actors refers to a_gender = 'M'
SQL: SELECT CAST(SUM(IIF(a_gender = 'M', 1, 0)) AS REAL) / SUM(IIF(a_gender = 'F', 1, 0)) FROM actors WHERE a_quality = 0
Database: movielens
Question: Which actor has appeared in the most films?
SQL: SELECT actorid FROM movies2actors GROUP BY actorid ORDER BY COUNT(movieid) DESC LIMIT 1
Database: movielens
Question: What is the most popular genre of film directed by directors?
Evidence: Most popular genre indicates that the genre has the most number of movies
SQL: SELECT genre FROM movies2directors GROUP BY genre ORDER BY COUNT(movieid) DESC LIMIT 1
Database: movielens
Question: What are the most common film genres made by the worst directors?
Evidence: d_quality = 5 refers to the best directors, d_quality = 0 refers to the worst directors
SQL: SELECT T2.genre FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid WHERE T1.d_quality = 0 GROUP BY T2.genre ORDER BY COUNT(T2.movieid) DESC LIMIT 1
Database: movielens
Question: What non-English American film/s has received the lowest user ratings? Mention the movie's I.D.
Evidence: USA is a country; non-English means isEnglish = 'F'
SQL: SELECT T2.movieid FROM movies AS T1 INNER JOIN u2base AS T2 ON T1.movieid = T2.movieid WHERE T1.isEnglish = 'F' AND T1.country = 'USA' ORDER BY T2.rating LIMIT 1
Database: movielens
Question: What is the total average movie directed by the directors who's quality and revenue is 4?
SQL: SELECT CAST(SUM(CASE WHEN T1.d_quality = 4 AND T1.avg_revenue = 4 THEN 1 ELSE 0 END) AS REAL) / COUNT(T2.movieid) FROM directors AS T1 INNER JOIN movies2directors AS T2 ON T1.directorid = T2.directorid
Database: movielens
Question: Which movies have received the greatest ratings from female users whose occupations fall within the category of 3?
Evidence: Female users mean that u_gender = 'F'
SQL: SELECT T2.movieid FROM users AS T1 INNER JOIN u2base AS T2 ON T1.userid = T2.userid INNER JOIN movies AS T3 ON T2.movieid = T3.movieid WHERE T1.u_gender = 'F' AND T1.occupation = 3 AND T2.rating = 5
Database: movielens
Question: How many female actresses appeared in the movie 2312852, what country was it in, and what was it's running time?
Evidence: female actresses mean that a_gender = 'F'
SQL: SELECT SUM(IIF(T1.a_gender = 'F', 1, 0)) , T3.country, T3.runningtime FROM actors AS T1 INNER JOIN movies2actors AS T2 ON T1.actorid = T2.actorid INNER JOIN movies AS T3 ON T2.movieid = T3.movieid WHERE T2.movieid = 2312852 GROUP BY T3.country, T3.runningtime
Database: movielens
Question: How many horror movies were made by the worst directors?
Evidence: d_quality = 5 refers to direct the best, d_quality = 0 refers to direct the worst
SQL: SELECT COUNT(T1.movieid) FROM movies2directors AS T1 INNER JOIN movies AS T2 ON T1.movieid = T2.movieid INNER JOIN directors AS T3 ON T1.directorid = T3.directorid WHERE T1.genre = 'horror' AND T3.d_quality = 0
Database: movielens
Question: What are the genres of all the English-language foreign films having a runtime of two hours or less? List each one.
Evidence: isEnglish = 'T' means films in English; Film and movie share the same meaning
SQL: SELECT T2.genre FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.runningtime <= 2 AND T1.isEnglish = 'T' AND T1.country = 'other'
Database: movielens
Question: Among the English comedy movies produced in the UK, how many movies with a running time of 3 was rated the highest by users between the age 45-50? Indicate the movie names.
Evidence: UK is a country
SQL: SELECT DISTINCT T1.movieid FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid INNER JOIN u2base AS T3 ON T1.movieid = T3.movieid INNER JOIN users AS T4 ON T3.userid = T4.userid WHERE T1.country = 'UK' AND T2.genre = 'Comedy' AND T1.runningtime = 3 AND T3.rating = 5 AND T4.age BETWEEN 45 AND 50 AND T1.isEnglish = 'T'
Database: movielens
Question: What is the percentage difference of English and non-English-language crime movies in other countries in year 3?
Evidence: non-English-language refers to isEnglish = 'F'; The percentage difference can be computed by [count(isEnglish = 'T' in movies) - count(isEnglish = 'F' in movies) / (all movies)] * 100%
SQL: SELECT CAST(SUM(IIF(T1.isEnglish = 'T', 1, 0)) - SUM(IIF(T1.isEnglish = 'F', 1, 0)) AS REAL) * 100 / COUNT(T1.movieid) FROM movies AS T1 INNER JOIN movies2directors AS T2 ON T1.movieid = T2.movieid WHERE T1.country = 'other' AND T1.year = 3
Database: movielens
Question: What is the total amount male and female actors who were casted in movie ID 1684910 and what is the proportion between the highest quality actors against the worst quality of actors? Indicate your answer in percentage. List the the director as well as the genre.
Evidence: Female actors mean that a_gender = 'F'; Male actors mean that a_gender = 'M'; a_quality = 5 refers to act the best, a_quality = 0 refers to act the worst
SQL: SELECT SUM(IIF(a_gender = 'M', 1, 0)) , SUM(IIF(a_gender = 'F', 1, 0)) , CAST(SUM(IIF(a_quality = 5, 1, 0)) AS REAL) * 100 / COUNT(*) , CAST(SUM(IIF(a_quality = 0, 1, 0)) AS REAL) * 100 / COUNT(*), ( SELECT directorid FROM movies2directors WHERE movieid = 1684910 ) , ( SELECT genre FROM movies2directors WHERE movieid = 1684910 ) FROM actors WHERE actorid IN ( SELECT actorid FROM movies2actors WHERE movieid = 1684910 )
Database: superstore
Question: Please list the names of all the products ordered in order CA-2011-112326 in superstores in the center.
Evidence: names of all the products refers to "Product Name"; order CA-2011-112326 refers to "Order ID" = 'CA-2011-112326'; in the center refers to Region = 'Central';
SQL: SELECT DISTINCT T2.`Product Name` FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Order ID` = 'CA-2011-112326'
Database: superstore
Question: Among all the orders made by Aimee Bixby, what was the longest shipment time?
Evidence: made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; longest shipment time refers to MAX(SUM(SUTRACT(julianday("Ship Date"), julianday("Order Date")), 1))
SQL: SELECT MAX(strftime('%J', `Ship Date`) - strftime('%J', `Order Date`)) AS longestTimeDays FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby'
Database: superstore
Question: Among all the orders made by Aimee Bixby, how many of them chose the slowest delivery speed?
Evidence: made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; the slowest delivery speed refers to "Ship Mode" = 'Standard Class';
SQL: SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T2.`Ship Mode` = 'Standard Class'
Database: superstore
Question: How many orders has Aimee Bixby made?
Evidence: Aimee Bixby made refers to "Customer Name" = 'Aimee Bixby';
SQL: SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby'
Database: superstore
Question: Please list the IDs of the orders made by Aimee Bixby with more than 3 kinds of products ordered.
Evidence: made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; with more than 3 kinds of products ordered refers to count("Product ID") > 3;
SQL: SELECT DISTINCT T2.`Order ID` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.`Customer Name` = 'Aimee Bixby' GROUP BY T2.`Product ID` HAVING COUNT(T2.`Product ID`) > 3
Database: superstore
Question: Among the orders made by Aimee Bixby, how many of them included at least one kind of product under the category "Furniture"?
Evidence: made by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby';
SQL: SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.Category = 'Furniture' AND T1.`Customer Name` = 'Aimee Bixby'
Database: superstore
Question: Please list the names of all the products ordered by Aimee Bixby in 2016.
Evidence: ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; ordered n 2016 refers to strftime('%Y', "Order Date") = '2016';
SQL: SELECT DISTINCT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND STRFTIME('%Y', T2.`Ship Date`) = '2016'
Database: superstore
Question: What is the total quantity of "Telescoping Adjustable Floor Lamp" ordered from central superstores?
Evidence: "Telescoping Adjustable Floor Lamp" is a "Product Name"; from central superstores refers to Region = 'Central';
SQL: SELECT SUM(T1.Quantity) FROM central_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Product Name` = 'Telescoping Adjustable Floor Lamp'
Database: superstore
Question: Please list the names of all the customers who had ordered the product "Telescoping Adjustable Floor Lamp".
Evidence: "Telescoping Adjustable Floor Lamp" is a product name; names of all the customers refers to "Customer Name"
SQL: SELECT DISTINCT T1.`Customer Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.`Product Name` = 'Telescoping Adjustable Floor Lamp'
Database: superstore
Question: Among the customers who have ordered the product "Telescoping Adjustable Floor Lamp", how many of them are consumers?
Evidence: "Telescoping Adjustable Floor Lamp" is a "Product Name"; consumers refers to Segment = 'Consumer';
SQL: SELECT COUNT(DISTINCT T1.`Customer Name`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T3.`Product Name` = 'Telescoping Adjustable Floor Lamp' AND T1.Segment = 'Consumer'
Database: superstore
Question: What was the quantity of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
Evidence: Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10');
SQL: SELECT SUM(T2.Quantity) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
Database: superstore
Question: For how many times has Aimee Bixby ordered the product Xerox 1952?
Evidence: Xerox 1952 is a "Product Name"; Aimee Bixby ordered refers to "Customer Name" = 'Aimee Bixby';
SQL: SELECT COUNT(DISTINCT T2.`Order ID`) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952'
Database: superstore
Question: What was the original price of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
Evidence: Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10'); original price refers to DIVIDE(Sales, SUTRACT(1, discount))
SQL: SELECT DISTINCT T2.Sales / (1 - T2.Discount) FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
Database: superstore
Question: What was the total cost of Xerox 1952 ordered by Aimee Bixby on 2014/9/10?
Evidence: Xerox 1952 is a "Product Name"; ordered by Aimee Bixby refers to "Customer Name" = 'Aimee Bixby'; on 2014/9/10 refers to "Order Date" = date('2014-09-10'); total cost refers to SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit)
SQL: SELECT DISTINCT (T2.Sales / (1 - T2.discount)) * T2.Quantity - Profit FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Aimee Bixby' AND T3.`Product Name` = 'Xerox 1952' AND T2.`Order Date` = '2014-09-10'
Database: superstore
Question: How many art products were ordered in 2013 in the east superstore?
Evidence: ordered in 2013 refers to strftime('%Y', "Order Date") = '2013'; art products refers to "Sub-Category" = 'Art'
SQL: SELECT COUNT(DISTINCT T1.`Product ID`) FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.`Sub-Category` = 'Art' AND T1.Region = 'East' AND STRFTIME('%Y', T1.`Order Date`) = '2013'
Database: superstore
Question: Who is the customer who purchased the largest total cost of products in a single order?
Evidence: largest total cost refers to MAX(SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit))
SQL: SELECT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` GROUP BY T1.`Order ID`, T2.`Customer Name` ORDER BY SUM((T1.Sales / (1 - T1.Discount)) * T1.Quantity - T1.Profit) DESC LIMIT 1
Database: superstore
Question: What is the name of the product that has the highest original price?
Evidence: has the highest original price refers to MAX(DIVIDE(Sales, SUTRACT(1, discount))); name of the product refers to "Product Name"
SQL: SELECT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` ORDER BY (T1.Sales / (1 - T1.Discount)) DESC LIMIT 1
Database: superstore
Question: What is the name of the product that was ordered recently by Darren Powers?
Evidence: Darren Powers is the "Customer Name"; name of the product refers to "Product Name"; recently refers to MAX("Order Date")
SQL: SELECT T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Darren Powers' ORDER BY T2.`Order Date` DESC LIMIT 1