void operator()(OpKernelContext* ctx, const CPUDevice& d, int64 num_batches,
                  int64 samples_per_batch, int64 num_elements,
                  const BCast& bcast, typename TTypes<T>::ConstFlat counts,
                  typename TTypes<T>::ConstFlat probs,
                  const random::PhiloxRandom& gen,
                  typename TTypes<U>::Flat output) {
    auto worker_threads = *(ctx->device()->tensorflow_cpu_worker_threads());

    // The output layout is [B1, ... Bk, H1, ... Hm]. We have [B1, ... Bk] for
    // the sample shape and [H1, ... Hm] for the batch shape of the samples.
    // We have B1 * ... * Bk samples per batch member we need.
    auto DoWork = [num_batches, samples_per_batch, &bcast, &counts, &probs,
                   &gen, &output](int start_output, int limit_output) {
      // Vectorized intermediate calculations for uniform rejection sampling.
      // We always generate at most 4 samples.
      Eigen::array<T, 4> z;
      Eigen::array<T, 4> g;
      const bool should_bcast = bcast.IsBroadcastingRequired();
      const auto& counts_batch_indices = bcast.x_batch_indices();
      const auto& probs_batch_indices = bcast.y_batch_indices();
      auto output_flat = output.data();

      // We partition work across batches (count, prob) and then across samples
      // per batch member, to avoid extra work.
      for (int64 output_idx = start_output; output_idx < limit_output;
           // output_idx is incremented with the inner loops below.
      ) {
        int64 batch_idx = output_idx / samples_per_batch;
        U* const output_batch_offset = output_flat + batch_idx;
        // Generate batch counts from BCast, as it has the right indices to loop
        // over.
        T count, prob;
        if (should_bcast) {
          count = counts(counts_batch_indices[batch_idx]);
          prob = probs(probs_batch_indices[batch_idx]);
        } else {
          count = counts(batch_idx);
          prob = probs(batch_idx);
        }

        // Calculate normalized samples, then convert them.
        // Determine the method to use.
        double dcount = static_cast<double>(count);
        if (dcount <= 0.0 || prob <= T(0.0)) {
          for (int64 sample_idx = output_idx % samples_per_batch;
               sample_idx < samples_per_batch && output_idx < limit_output;
               ++sample_idx, ++output_idx) {
            output_batch_offset[sample_idx * num_batches] = static_cast<U>(0.0);
          }
        } else if (prob >= T(1.0)) {
          for (int64 sample_idx = output_idx % samples_per_batch;
               sample_idx < samples_per_batch && output_idx < limit_output;
               ++sample_idx, ++output_idx) {
            output_batch_offset[sample_idx * num_batches] =
                static_cast<U>(dcount);
          }
        } else if (prob <= T(0.5)) {
          double dp = static_cast<double>(prob);
          if (count * prob >= T(10)) {
            for (int64 sample_idx = output_idx % samples_per_batch;
                 sample_idx < samples_per_batch && output_idx < limit_output;
                 ++sample_idx, ++output_idx) {
              random::PhiloxRandom gen_copy = gen;
              gen_copy.Skip(256 * output_idx);
              output_batch_offset[sample_idx * num_batches] =
                  static_cast<U>(btrs(dcount, dp, &gen_copy));
            }
          } else {
            for (int64 sample_idx = output_idx % samples_per_batch;
                 sample_idx < samples_per_batch && output_idx < limit_output;
                 ++sample_idx, ++output_idx) {
              random::PhiloxRandom gen_copy = gen;
              // For binomial inversion, we have mean <= 10, variance <= 10.
              // This means on average we need at most 10 number of samples,
              // and for 10 standard deviations, we need 42 samples. We reserve
              // that much.
              gen_copy.Skip(42 * output_idx);
              output_batch_offset[sample_idx * num_batches] =
                  static_cast<U>(binomial_inversion(dcount, dp, &gen_copy));
            }
          }
        } else if (prob > T(0.5)) {
          T q = T(1) - prob;
          double dcount = static_cast<double>(count);
          double dq = static_cast<double>(q);
          if (count * q >= T(10)) {
            for (int64 sample_idx = output_idx % samples_per_batch;
                 sample_idx < samples_per_batch && output_idx < limit_output;
                 ++sample_idx, ++output_idx) {
              random::PhiloxRandom gen_copy = gen;
              gen_copy.Skip(256 * output_idx);
              output_batch_offset[sample_idx * num_batches] =
                  static_cast<U>(dcount - btrs(dcount, dq, &gen_copy));
            }
          } else {
            for (int64 sample_idx = output_idx % samples_per_batch;
                 sample_idx < samples_per_batch && output_idx < limit_output;
                 ++sample_idx, ++output_idx) {
              random::PhiloxRandom gen_copy = gen;
              // For binomial inversion, we have mean <= 10, variance <= 10.
              // This means on average we need at most 10 number of samples,
              // and for 10 standard deviations, we need 42 samples. We reserve
              // that much.
              gen_copy.Skip(42 * output_idx);
              output_batch_offset[sample_idx * num_batches] = static_cast<U>(
                  dcount - binomial_inversion(dcount, dq, &gen_copy));
            }
          }
        } else {  // prob is NaN
          // TODO(srvasude): What should happen if prob is NaN but the output
          // type is an integer (which doesn't have a sentinel for NaN)?  Fail
          // the whole batch sample?  Return a specialized sentinel like -1?
          for (int64 sample_idx = output_idx % samples_per_batch;
               sample_idx < samples_per_batch && output_idx < limit_output;
               ++sample_idx, ++output_idx) {
            output_batch_offset[sample_idx * num_batches] = static_cast<U>(NAN);
          }
        }
      }
    };

    // This will depend on count * p (or count * q).
    // For n * p < 10, on average, O(n * p) calls to uniform are
    // needed, with that
    // many multiplies. ~10 uniform calls on average with ~200 cost op calls.
    //
    // Very roughly, for rate >= 10, the four calls to log
    // occur for ~72 percent of samples.
    // 4 x 100 (64-bit cycles per log) * 0.72 = ~288
    // Additionally, there are ~10 other ops (+, *, /, ...) at 3-6 cycles each:
    // 40 * .72  = ~25.
    //
    // Finally, there are several other ops that are done every loop along with
    // 2 uniform generations along with 5 other ops at 3-6 cycles each.
    // ~15 / .89 = ~16
    //
    // In total this (rate >= 10) should be ~329 + 2 * Uniform::kElementCost.
    // We assume that half the tensor has rate < 10, so on average 6
    // uniform's
    // will be needed. We will upper bound the other op cost by the one for
    // rate > 10.
    static const int kElementCost = 329 + 6 * Uniform::kElementCost +
                                    6 * random::PhiloxRandom::kElementCost;
    Shard(worker_threads.num_threads, worker_threads.workers, num_elements,
          kElementCost, DoWork);
  }