1860 United States presidential election in Iowa
Results

1860 United States presidential election in Iowa

Section Title: Results
Table Section Text: None

Party	Candidate	Votes	%

Republican	Abraham Lincoln	70,302	54.61%

Democratic	Stephen A. Douglas	55,639	43.22%

Constitutional Union	John Bell	1,763	1.37%

Southern Democratic	John C. Breckinridge	1,035	0.80%

Total votes	128,739	100%

Sentence(s)

Iowa was won by Abraham Lincoln (R), with 54.61% of the popular vote against Senator Stephen A. Douglas (D), with 43.22% of the popular vote.

final_sentence: Iowa was won by Abraham Lincoln (R), with 54.61% of the popular vote against Senator Stephen A. Douglas (D), with 43.22% of the popular vote.