1840 United States presidential election in Rhode Island
Results

1840 United States presidential election in Rhode Island

Section Title: Results
Table Section Text: None

United States presidential election in Rhode Island, 1840

Party	Candidate	Running mate	Popular vote	Electoral vote

Count	%	Count	%

Whig	William Henry Harrison of Ohio	John Tyler of Virginia	5,278	61.22%	4	100.00%

Democratic	Martin Van Buren of New York	Richard M. Johnson of Kentucky	3,301	38.29%	0	0.00%

Liberty	James G. Birney of New York	Thomas Earle of Pennsylvania	42	0.49%	0	0.00%

Total	8,621	100.00%	4	100.00%

Sentence(s)

In 1840 United States presidential election in Rhode Island, Harrison received 61.22% of the popular vote.

final_sentence: In 1840 United States presidential election in Rhode Island, Harrison received 61.22% of the popular vote.