UEFA Euro 1968 qualifying Group 7
Final table
Source: UEFA Rules for classification: Qualification tiebreakers

UEFA Euro 1968 qualifying Group 7

Section Title: Final table
Table Section Text: Source: UEFA Rules for classification: Qualification tiebreakers

Pos	Team[ vte ]	Pld	W	D	L	GF	GA	GD	Pts	Qualification	France	Belgium	Poland	Luxembourg

1	France	6	4	1	1	14	6	+8	9	Advance to play-offs	—	1–1	2–1	3–1

2	Belgium	6	3	1	2	14	9	+5	7	2–1	—	2–4	3–0

3	Poland	6	3	1	2	13	9	+4	7	1–4	3–1	—	4–0

4	Luxembourg	6	0	1	5	1	18	−17	1	0–3	0–5	0–0	—

Sentence(s)

Group 7 consisted of four teams: France, Belgium, Poland, and Luxembourg, where they all played against each other.

final_sentence: Group 7 consisted of four teams: France, Belgium, Poland, and Luxembourg, where they all played against each other.