Gravity doesnt exist

I will rebut his argument, and state mine. FrameworkI do not really need arguments or anything in this debate because it is a truth debate, and I have to win the debate because gravity does exist. DefinitionsGravity: "Gravity is an always-attractive force that acts between particles of matter. "Rebuttal 1 for the arugment: "It is not proven and the bible doesn't mention it"The Bible, is a religious text, for followers of Jesus, and believers in Christianity. I believe that the Bible may or may not contain factual evidence. For example, Jesus died, and came back to life. It is true in Christianity, but not in nature. Also think about it. The Bible says that the world was created in 6 days. Was it? I don't think so. Rebuttal 2: "If gravity was created by 1600 by isaac then its false because god create world in year 0"This argument is wrong for many reasons. First of all, gravity was not created by issac. It was discovered by Newton. Also he says it is false because god create world in year 0. This is false also because there was something called BC. Argument 1: Newton says gravity exists"Supposedly, the above question occured to Newton when he saw an apple falling from a tree. John Conduitt, Newton's assistant at the royal mint and husband of Newton's niece, had this to say about the event when he wrote about Newton's life: In the year 1666 he retired again from Cambridge . .. to his mother in Lincolnshire & while he was musing in a garden it came into his thought that the power of gravity (which brought an apple from a tree to the ground) was not limited to a certain distance from earth, but that this power must extend much further than was usually thought. Why not as high as the Moon thought he to himself & that if so, that must influence her motion & perhaps retain her in her orbit, whereupon he fell a-calculating what would be the effect of that superposition. .. If it was the same force, then a connection would exist between the way objects fell and the motion of the Moon around Earth, that is, its distance and orbital period. The orbital period we know--it is the lunar month, corrected for the motion of the Earth around the Sun, which also affects the length of time between one "new moon" and the next. The distance was first estimated in ancient Greece--see hereand here. To calculate the force of gravity on the Moon, one must also know how much weaker it was at the Moon's distance. Newton showed that if gravity at a distance R was proportional to 1/R2 (varied like the "inverse square of the distance"), then indeed the acceleration g measured at the Earth's surface would correctly predict the orbital period T of the Moon. Newton went further and proposed that gravity was a "universal" force, and that the Sun's gravity was what held planets in their orbits. He was then able to show that Kepler's laws were a natural consequence of the "inverse squares law" and today all calculations of the orbits of planets and satellites follow in his footsteps. Nowadays students who derive Kepler's laws from the "inverse-square law" use differential calculus, a mathematical tool in whose creation Newton had a large share. Interestingly, however, the proof which Newton published did not use calculus, but relied on intricate properties of ellipses and other conic sections. Richard Feynman, Nobel-prize winning maverick physicist, rederived such a proof (as have some distinguished predecessors); see reference at the end of the section. Here we will retrace the calculation, which linked the gravity observed on Earth with the Moon's motion across the sky, two seemingly unrelated observations. If you want to check the calculation, a hand-held calculator is helpful. " So, Gravity Exists. Calculating the Moon's motion. We assume that the Moon's orbit is a circle, and that the Earth's pull is always directed toward's the Earth's center. Let RE be the average radius of the Earth (first estimated by Erathosthenes) RE= 6 371 km The distance R to the Moon is then about 60 RE. If a mass m on Earth is pulled by a force mg, and if Newton's "inverse square law" holds, then the pull on the same mass at the Moon's distance would be 602 = 3600 times weaker and would equal mg/3600 If m is the mass of the Moon, that is the force which keeps the Moon in its orbit. If the Moon's orbit is a circle, since R = 60 RE its length is 2 π R = 120 π RE Suppose the time required for one orbit is T seconds. The velocity v of the motion is then v = distance/time = 120 π RE/T (Please note: gravity is not what gives the Moon its velocity. Whatever velocity the Moon has was probably acquired when it was created. But gravity prevents the Moon from running away, and confines it to some orbit. ) The centripetal force holding the Moon in its orbit must therefore equal mv2/R = mv2/(60 RE) and if the Earth's gravity provides that force, then mg/3600 = mv2/(60 RE) dividing both sides by m and then multiplying by 60 simplifies things to g/60 = v2/RE = (120 π RE)2/(T2 RE) Canceling one factor of RE , multiplying both sides by 60 T2 and dividing them by g leaves T2 = (864 000 π2 RE)/g = 864 000 RE (π2/g) Providentially, in the units we use g ~ 9.81 is very close to π2 ~ 9.87, so that the term in parentheses is close to 1 and may be dropped. That leaves (the two parentheses are multiplied) T2 = (864 000) (6 371 000) With a hand held calculator, it is easy to find the square roots of the two terms. We get (to 4-figure accuracy) 864 000 = (929.5)2 6 371 000 = (2524)2 Then T ≅ (929.5) (2524) = 2 346 058 seconds To get T in days we divide by 86400, the number of seconds in a day, to get T = 27.153 days pretty close to the accepted value T = 27.3217 days"ConclusionI have proven scientfic evidence that gravity does exit.