.9999 repeating = 1

To start this debate I will have an overview the go down the flow First there is on key argument that my opponent has dropped though out this round and that is power of infinity. This is going to be the killing blow to my opponent's arguments because it shows how infinity can have multiple values and can be applied in math. My opponent tries to argue that infinity increases at a different rate but this only proves my point if % were = 1 the %+1=2 and while both answers to these problems are infinity the they way that they are used in an equation the second on would be bigger this can be applied to the rhs lhs equation because when you multiply the .9999… repeating by 10 it still has % number of digits behind the decimal but it acts as %-1 digits so it would be one less than the normal .999… this way I said all I have to prove is that % has a value and can be applied in equations . The first point that my opponent makes is that it is illogical to have a 0 at the end of the repeating 9's but there is nothing illogical about this because using an example of the set of all real numbers we know that will end at infinity but the numbers in the between are the ones that continue to grow so the same can be applied to the 0 at the end while the 9's in between continue to grow and end in 0 Group my opponent's next 2 arguments and as I said above that these only prove my point because it shows how we can mortify the value that infinity has meaning that my opponent's arguments only support my point My opponent's opponent again tries to make have to prove that I have to prove that there is a final digit in the repeating 9's but this creates a huge contradictions because for one because it is not he rate that it is approaching infinity it the speed at which is growing, the second problem with this if infinity constantly increasing they it would be imposable to use in an equations Next my opponent tries to disprove the argument about the remainder with is example but this example is inadequate to describe to represent it would have to assume that 1 would increase to allow for the extra room to be created a better example would be that a hotel has 3 room and you have 10 people and you wanted to divide them equally up but o person would be left over and he goes to another hotel with another 10 people and they get 3 rooms and the same problem occurs even if you go to an infinite number of hotels there will always be that one left over and it will never go away. Also don't even listen to my opponent's argument because it is not specific to division and repeating decimals Next on the new equation that my opponent has presented, first I would like to point out that my opponent conceded the argument that 1/% is only approximately 0 this means that his final step when he subtracts 1 by 1/% it would only approximately equal to 1 making my opponent's equation mute and don't let him bring this up in his next speech because this is his final speech and being new arguments in is abusive because there is no time to debate them, the next problem with the equation that I had was how he went from 9/10 k to 1-1/10n there is no way that that 9 becomes a 1 thus creating a huge flaw in the equation Next I would like to point out my opponent's concession of the number line paradox that there are an infinite numbers between 1 and .999… this is proven by the power of infinity argument that shows how infinity has different values of infinity mean that there can be different number of 9's after the decimal. This point has be conceded don't let my opponent bring it up in his next speak because that is abusive and this is the reason that this debate round might as well be over because at the point that I have proven in a conceded point that 1 doesn't .999… then if it might in other situations it still doesn't equal it in this example proving that they don't equal Next on the law of functions my opponent argues that there can be multiple examples of 1 in a decimal form that can be at the point of 1 but the example of 1.00 doesn't prove me wrong because we simply by removing the 0's behind the decimal making be 1 now the difference with .999… is that we can remove the 9's and simplify it like this like this. The next thing he says is that I conceded that they could be in the same location if only for that 3 letter word called "but" that is right after that statement saying how them being in the same locations is imposable.