The Noah's Ark story is a complete impossibility

I think the first point to discuss is how much volume Noah's Ark actually was. According to Genesis the ark was 300 X 50 X 30 cubits = 450000 cubits^3. This translates to 158.7 X 26.45 X 15.87 = 66616.15 m^3 as 1 cubit = 0,529 m as I said in my opening statement. So I am sure my opponent will agree with me on this. Next let us consider how many species of animals there are in the world, we have to consider all living animals as any animals that were not on the ark according to the story got destroyed. Lets assume that we only are taking land and air animals on to the Ark an also lets ignore fish at present. I don't want to ignore fish as salt water and fresh water fish are not going to survive in the mixture of fresh water that existed when the whole world was under water. However, I believe I can make the point regardless. So how many species of animals, if we just consider vertebrates and insects we get a total of 1,009,811. (1) But according to the story we need 2 of each kind of animal,so that brings the total to 2,019,622 animals total and then we have to add Noah's family, which brings us to 2,019,628. (2) By the way I am also ignoring the fact that for some animals we are meant to have seven pairs of clean animals, but I am not sure how we should define clean animals. However again, we don't need the extra numbers to show that this never happened. So how much space did these animals have?66616.15 m^3/2,019,628 = 0.03 m^3 or about 0.6 m by 0.6m by 0.6 m high. So I guess you are thinking that's not so bad,which is true if you are a piglet. However, at this point this is pure space and we have not calculated the amount of space occupied by timber to construct the ark, air to breathe and food needed. Again lets forget about all the excrement removal and water needed. Obviously these values are difficult to determine, but let me try. Let's assume we only need 5% of the space for timber, pitch and rope to construct the boat. That brings the space available to 63285.3m^3. Next lets consider how much air each animal needs to breathe, again this is a difficult number to determine. However a human needs about 0.005 m^3 per breath of air. (3) So lets assume that of all the animals and insects need only 5 % of a humans lung capacity then the total air needed is 0.005m^3 X 0.05 X 2,019,628 = 504.9 m^3. This brings the available space to 62780.4 m^3. Lastly lets consider the big problem of food. On average a human eats 1.6 kg of food per day. (4) So again lets assume all animals eat only 5% of what humans need and that its meat, as meat is dense and requires less space. (5) Then (1.6 kg X 0.05 X 2,019,628)/591.7 kg/m^3 = 273 m^3 of space per day. we also know the ark was afloat for 225 days (February 17th to October 1st plus a few more days which I wont count). So the space needed for food is 225 X 273 m^3 = 61425 m^3. Which brings the space available to the animals to 1359.4 m^3. This means that each animal had 1359.4 m^3/2,019,628 = 0.00067 m3 space to move around in, or 0.087 m by 0.087 m by 0.087 m high. Possible? I think not unless Noah was about one tenth as big as a rat. (6)I eagerly await my opponents reply. (1) . http://www.factmonster.com...(2) . http://www.biblegateway.com...(3) . http://humanphysiology.hubpages.com...(4) . http://wiki.answers.com...(5) . http://www.aqua-calc.com...(6) . http://www.rattycorner.com...