Riddle

I accept my opponent's sporting challenge.This is an interesting riddle - I think I have figured it out.-----The most important fact I gain from PRO's riddle is that each container is marked incorrectly.Therefore, the key to solving this riddle is the container incorrectly marked "mixed". Whatever coin you pull out of this container, since this container CANNOT be mixed, it is thus the container consisting of solely the type of coin you pulled out.Then the two remaining containers MUST have coins pulled that are contrary to their labels, because AT MOST 2 out of the 3 containers will contain one type of coin - the last container MUST contain ONLY the different coin. To demonstrate why this is so, if the coins pulled from these remaining two containers were to correspond to their label, then one of the containers would be correctly marked, which cannot occur per the rules of this riddle.(note: underlined text refers to example #3, bolded text refers to example #4)Since the two remaining containers will have coins pulled that are contrary to their labels, we can also deduce which container is mixed - it will be the container from which the coin pulled is the same as that of the incorrectly marked "mixed" container. Then, the last container will consist solely of the other type of coin.Example #1Containers A, B, C A is labeled 2005 B is labeled 1975 C is labeled Mixed. From A you pull a 1975 coin.From B you pull a 2005 coin.From C you pull a 2005 coin.Since C is incorrectly labeled mixed, and you pulled a 2005 coin out of it, it CANNOT be mixed, and is thus the 2005 container.Since B is incorrectly labeled 1975 and you pulled a 2005 coin out of it, it CANNOT be the 2005 container, since that is C. Therefore, it MUST be mixed.Since A is incorrectly labeled 2005 and you pulled a 1975 coin out of it, it CANNOT be the mixed container, since that is container B, and is thus the 1975 container. Example #2Containers A, B, CA is labeled 2005B is labeled 1975C is labeled Mixed. From A you pull a 1975 coin.From B you pull a 2005 coin.From C you pull a 1975 coin.Since C is incorrectly labeled mixed, and you pulled a 1975 coin out of it, it CANNOT be mixed, and is thus the 1975 container.Since A is incorrectly labeled 2005 and you pulled a 1975 coin out of it, it CANNOT be the 1975 container because that is container C, and is thus the mixed container. Since B is incorrectly labeled 1975 and you pulled a 2005 coin out of it, it CANNOT be the mixed container because that is container A. Therefore, it MUST be the 2005 container.Example #3 - WRONG scenario (the coins pulled from non-mixed containers correspond to their label)Containers A, B, CA is labeled 2005B is labeled 1975C is labeled Mixed.From A you pull a 2005 coin.From B you pull a 1975 coin. From C you pull a 1975 coin.Since C is incorrectly labeled mixed, and you pulled a 1975 coin out of it, it CANNOT be mixed, and is thus the 1975 container.Since B is incorrectly labeled 1975 and you pulled a 1975 coin out of it, it CANNOT be the 1975 container, since that is C. Therefore, it MUST be the mixed container.Since A is incorrectly labeled 2005 and you pulled a 2005 coin out of it, it CANNOT be the mixed container since that is container B, and is thus the 2005 container. However, this would mean that this container was originally labeled correctly, which is not possible given the rules of this riddle. This example demonstrates why the coins pulled from the remaining two containers must be different than their original labels.Example #4 - WRONG SCENARIO (all three coins pulled are the same)Containers A, B, CA is labeled 2005B is labeled 1975C is labeled Mixed.From A you pull a 1975 coin.From B you pull a 1975 coin. From C you pull a 1975 coin.Since C is incorrectly labeled mixed, and you pulled a 1975 coin out of it, it CANNOT be mixed, and is thus the 1975 container.Since B is incorrectly labeled 1975 and you pulled a 1975 coin out of it, it CANNOT be the 1975 container, since that is C. Therefore, it MUST be the mixed container.Since A is incorrectly labeled 2005 and you pulled a 1975 coin out of it, it CANNOT be the mixed container since that is container B, and is thus the 2005 container. However, the 2005 container CANNOT contain ANY 1975 coins. This example demonstrates why you can only pull AT MOST two of the same kind of coin from the three containers. -----Examples #1 and #2 are the only two possibilities, because the coins you pull from one of the containers MUST be different from the other two containers, and the coins pulled from the non-mixed containers MUST be different than their labels. Therefore, the only real variation is in the mixed container. I have demonstrated how to correctly label these three incorrectly labeled containers. I have also demonstrated how the coins pulled MUST correspond to a specific logic. Utilizing the logic I've explained and then demonstrated via examples, I have solved this riddle.Give me my seven points please. :) And thanks Azul145 for hosting this debate. :D