# Presentation: 448056

## TTB Form 5154.1

- Preparing formulas for submission to the Nonbeverage Products Laboratory

- John Shifflett
- (240)264-1597

## Why should you be interested?

- Increasing workload impacts our ability to process submissions in a timely manner.
- Incomplete or incorrectly formatted submissions require more time and effort to process.
- _Number 2 intensifies the problem in  number 1_.

## What types of submissions do we see?

- Compounded Flavors
- Simple Extracts

- Roughly 80 to 90% of the formulas processed by the Nonbeverage Products Laboratory fall into two categories

## Slide 4

## Slide 5

## Slide 6

## Slide 7

## 0.83 gal or 7.0 % (v/v)

**0.83 gal or 7.0 % (v/v)**

## Taste Panel

**0.83 gal or 7.0 % (v/v)**

**Taste Panel**

## Slide 10

## Slide 11

## Slide 12

## Calculations:

- Convert weight to volume
- 	5.70 lbs ÷ 6.7943 lbs/gal = 0.84 gal

**Calculations:**

- Divide abs gal EtOH by the actual yield
- 	0.80 abs gal EtOH ÷ 11.90 gal = 0.067

- 0.067 × 100 = 6.70% (item 9)

- b) Calc absolute gallons of ethanol (abs gal EtOH)
- 	0.84 gal × 0.95 = 0.80 abs gal EtOH

## Item 10 – Calculated by dividing the total alcohol content by the theoretical yield.  Note that there are two sources of alcohol in the formula:

- Item 10 – Calculated by dividing the total alcohol content by the theoretical yield.  Note that there are two sources of alcohol in the formula:

## Item 10 – Calculated by dividing the total alcohol content by the theoretical yield.  Note that there are two sources of alcohol in the formula:

- Item 10 – Calculated by dividing the total alcohol content by the theoretical yield.  Note that there are two sources of alcohol in the formula:

- a) The abs gal EtOH from 190 proof alcohol was calculated for item 9  0.80 abs gal EtOH

- b) Calculate the abs gal EtOH from the Pineapple Essence 0.91 gal × 0.03 (mid-range) = 0.027 abs gal EtOH

- Divide the _sum of the__ abs gal EtOH_ by the theoretical yield  (0.80 + 0.027) abs gal EtOH ÷ 11.90 gal = **0.069 or 6.9%**
- The tolerance for item 10 can be found in the **Tolerance Table**.
- _Note: for simple mixtures, the theoretical yield ~ actual yield._

## Tolerance table for item 10 – TTB form 5154.1

| Alcohol percentage | Tolerances (Absolute %) |  |
| --- | --- | --- |
|  | Simple mixture | Filtration |
| (200o) > 95 | 93 – 100 | 91 – 100 |
| (190o) > 90 | 88 – 95 | 86 – 95 |
| >80 – 90 | ± 3.5 | ± 4.5 |
| >70 – 80 | ± 3.0 | ± 4.0 |
| >60 – 70 | ± 2.5 | ± 3.5 |
| >40 – 60 | ± 2.0 | ± 3.0 |
| >20 – 40 | ± 1.5 | ± 2.5 |
| 1 – 20 | ± 1.0 | ± 2.0 |

## Slide 17

## This product was found to be unfit for beverage purposes by organoleptic analysis.

- Following TTB guidelines, it was tasted by **six (6)** panelists, **four (4)** of whom agreed
- on the determination.

## Eligible alcohol in TTB #12

**Eligible alcohol in TTB #12**

**Limited Ingredient**

**Limited Ingredient**

## Slide 20

## Slide 21

## Slide 22

## Slide 23

## Calculations:

- Item 9 - two sources of eligible alcohol

## Calculations:

- Item 9 - two sources of eligible alcohol

- First source - 190 proof ethanol
- 		25.0 lbs ÷ 6.7943 lbs/gal = 3.68 gal
- 		3.68 gal × 0.95 = 3.50 gal abs EtOH
- Second source -Disapproved Raspberry Flavor
- 		0.51 gal × 0.050 = 0.026 gal abs EtOH

- Add up the gallons of absolute alcohol and divide by the actual yield
- 		(3.50 + 0.026) gal abs EtOH ÷ 11.2 gal = 0.315 or **31.5%**

## Calculations (cont’d):

- 	(3.50 + 0.026) gal abs EtOH = 3.526 gal abs EtOH

**Calculations (cont’d):**
- Item 10 calculation – use theoretical yield in this calculation

- divide this by the theoretical yield to get the ethanol content for item 10:
- 	3.526 gal abs EtOH ÷ 11.5 gal = 0.307 or **30.7%**

- The tolerance for item 10 can be found in the **Tolerance Table**.

## Tolerance table for item 10 – TTB form 5154.1

| Alcohol percentage | Tolerances (Absolute %) |  |
| --- | --- | --- |
|  | Simple mixture | Filtration |
| (200o) > 95 | 93 – 100 | 91 – 100 |
| (190o) > 90 | 88 – 95 | 86 – 95 |
| >80 – 90 | ± 3.5 | ± 4.5 |
| >70 – 80 | ± 3.0 | ± 4.0 |
| >60 – 70 | ± 2.5 | ± 3.5 |
| >40 – 60 | ± 2.0 | ± 3.0 |
| >20 – 40 | ± 1.5 | ± 2.5 |
| 1 – 20 | ± 1.0 | ± 2.0 |

## Filtered Products:

**Why do we use the final yield to calculate item 9?**
**Why do we use the theoretical yield to calculate item 10?**

- 	When filtration is the only other processing step, the ethanol content in the final product will be determined by the proportioning of **miscible** ingredients during mixing (even though there will be a loss of product to the filtration step).
- 	Since filtration is not a selective process for dissolved components we would not expect the ethanol level to change.

- 	It is not simply the ethanol in the final product that is calculated, it is the ethanol used in the manufacturing process.  This is especially important for products where some or all of the ethanol was lost due to processing.

## Slide 29

## Calculations:

- Item 9 calculation – Locate the eligible ethanol in the formula.  _Note that the Lemon Extract has a TTB approval for drawback.  _

## Calculations:

- Item 9 calculation – Locate the eligible ethanol in the formula.  _Note that the Lemon Extract has a TTB approval for drawback.  _

- Calculate the volume of absolute ethanol
- 55.0 lbs ÷ 6.7943 lbs/gal = 8.10 gal
- 8.10 gal × 0.95 = 7.70 gal abs EtOH

- next, divide by the final yield (actual yield)
- low end of yield range
- 7.70 gal abs EtOH ÷ 11.3 gal = 0.681 or **68.1%**

- high end of yield range
- 7.70 gal abs EtOH ÷ 12.0 gal = 0.642 or **64.2%**

- _This provides the range for the eligible alcohol in item 9._

## Calculations (cont’d):

**Calculations (cont’d):**
- Item 10 calculation
- Volume of the starting menstruum.  The starting menstruum is the ethanol and water along with other dissolved components (not the oil).

## Calculations (cont’d):

-              Ethanol = 55.0 lbs **÷** 6.794 lbs/gal = 8.10 gal
-                                          Lemon Extract = 0.14 gal
-              Glycerin = 23.0  lbs **÷** 9.79 lbs/gal = 2.35 gal
-               Water = 30.5  lbs ÷ 8.328 lbs/gal = 3.66 gal
-                -----------------------------------------------------------
-                                                        sum = 14.25 gal

**Calculations (cont’d):**
- Item 10 calculation
- Volume of the starting menstruum.  The starting menstruum is the ethanol and water along with other dissolved components (not the oil).

## Why use the starting menstruum to calculate Item 10?

- The oil does not add significant volume to the final product because it will not dissolve to an appreciable extent in the water: ethanol mixture.

- Once the oil is removed, the ethanol content will be determined by the _proportions of the soluble ingredients_ (in this case, the water, ethanol, glycerin, and lemon extract).

## Calculations (cont’d):

**Calculations (cont’d):**
- Item 10 calculation (cont’d)
- Item 10 = [gal abs EtOH ] ÷ [volume of starting menstruum]

## Calculations (cont’d):

**Calculations (cont’d):**
- Item 10 calculation (cont’d)
- Item 10 = [gal abs EtOH ] ÷ [volume of starting menstruum]

-      volume of abs EtOH = 190 proof EtOH +  EtOH from TTB # 8180
-                                8.10 gal × 0.95 = 7.70 gal abs EtOH
-                              0.14 gal × 0.671 = 0.09 gal abs EtOH
-                              --------------------------------------------------
-                                                 Sum = 7.79 gal abs EtOH

-            Divide this number by the volume of the starting menstruum
-              7.79 gal abs EtOH ÷ 14.25 gallons = 0.547 or **54.7%**

- Apply the tolerance used for filtered products to item 10.

## Tolerance table for item 10 – TTB form 5154.1

| Alcohol percentage | Tolerances (Absolute %) |  |
| --- | --- | --- |
|  | Simple mixture | Filtration |
| (200o) > 95 | 93 – 100 | 91 – 100 |
| (190o) > 90 | 88 – 95 | 86 – 95 |
| >80 – 90 | ± 3.5 | ± 4.5 |
| >70 – 80 | ± 3.0 | ± 4.0 |
| >60 – 70 | ± 2.5 | ± 3.5 |
| >40 – 60 | ± 2.0 | ± 3.0 |
| >20 – 40 | ± 1.5 | ± 2.5 |
| 1 – 20 | ± 1.0 | ± 2.0 |

## Slide 38