Simple transposition is a basic and simple cryptography technique. We make 2 rows and put first a letter in the Row 1, the second in the Row 2, third in Row 1 and so on until the end. Then we put the text from Row 2 next to the Row 1 text and thats it.

Complete the function that receives a string and encrypt it with this simple transposition.

## Example
For example if the text to encrypt is: `"Simple text"`, the 2 rows will be:



Row 1
S
m
l
 
e
t


Row 2
i
p
e
t
x
 



So the result string will be: `"Sml etipetx"`

Source: codewars | Difficulty: EASY

Starter code: def simple_transposition(text):
	

Solutions:
def simple_transposition(text):
	return text[::2] + text[1::2]


def simple_transposition(text):
	text1 = text[0::2]
	text2 = text[1::2]
	return text1 + text2


def simple_transposition(text):
	rowOne = True
	one = ''
	two = ''
	for x in text:
		if rowOne:
			one += x
		else:
			two += x
		rowOne = not rowOne
	return str(one) + str(two)


def simple_transposition(text):
	row1 = []
	row2 = []
	count = 1
	for char in text:
		if count % 2 != 0:
			row1.append(char)
		else:
			row2.append(char)
		count += 1
	return ''.join(row1) + ''.join(row2)


def simple_transposition(text):
	even_idx = ''
	odd_idx = ''
	for (idx, char) in enumerate(text):
		if idx % 2 == 0:
			even_idx += char
		else:
			odd_idx += char
	new_text = even_idx + odd_idx
	return new_text


def simple_transposition(text):
	text = list(text)
	row1 = []
	row2 = []
	for x in range(len(text)):
		if x % 2 == 0:
			row1.append(text[x])
		else:
			row2.append(text[x])
	result = ''.join(row1) + ''.join(row2)
	return result


simple_transposition = lambda s: s[::2] + s[1::2]


def simple_transposition(text):
	r1 = ''
	r2 = ''
	for ch in range(len(text)):
		if ch % 2 == 0:
			r1 += text[ch]
		if ch % 2 == 1:
			r2 += text[ch]
	transpo = r1 + r2
	return transpo