Wind Corridor is a covered passageway where strong wind is always blowing. It is a long corridor of width W, and there are several pillars in it. Each pillar is a right prism and its face is a polygon (not necessarily convex).

In this problem, we consider two-dimensional space where the positive x-axis points the east and the positive y-axis points the north. The passageway spans from the south to the north, and its length is infinity. Specifically, it covers the area 0 ≤ x ≤ W. The outside of the passageway is filled with walls. Each pillar is expressed as a polygon, and all the pillars are located within the corridor without conflicting or touching each other.

Wind blows from the south side of the corridor to the north. For each second, w unit volume of air can be flowed at most if the minimum width of the path of the wind is w. Note that the path may fork and merge, but never overlaps with pillars and walls.

Your task in this problem is to write a program that calculates the maximum amount of air that can be flowed through the corridor per second.



Input

The input consists of multiple datasets. Each dataset has the following format:

The first line of the input contains two integers W and N. W is the width of the corridor, and N is the number of pillars. W and N satisfy the following condition: 1 ≤ W ≤ 104 and 0 ≤ N ≤ 200.

Then, N specifications of each pillar follow. Each specification starts with a line that contains a single integer M, which is the number of the vertices of a polygon (3 ≤ M ≤ 40). The following M lines describe the shape of the polygon. The i-th line (1 ≤ i ≤ M) contains two integers xi and yi that denote the coordinate of the i-th vertex (0 < xi < W, 0 < yi < 104).

The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.

Output

For each dataset, your program should print a line that contains the maximum amount of air flow per second, in unit volume. The output may contain arbitrary number of digits after the decimal point, but the absolute error must not exceed 10-6.

Example

Input

5 2
4
1 1
1 2
2 2
2 1
4
3 3
3 4
4 4
4 3
0 0


Output

3.41421356

Source: aizu | Difficulty: UNKNOWN_DIFFICULTY


Solutions:
def solve():
	from itertools import combinations
	from heapq import heappush, heappop

	def dot(c1, c2):
		return c1.real * c2.real + c1.imag * c2.imag

	def cross(c1, c2):
		return c1.real * c2.imag - c1.imag * c2.real

	def d_sp(sp1, sp2, p):
		a = sp2 - sp1
		b = p - sp1
		if dot(a, b) < 0:
			return abs(b)
		c = sp1 - sp2
		d = p - sp2
		if dot(c, d) < 0:
			return abs(d)
		return abs(cross(a, b) / a)

	def d_s(p1, p2, p3, p4):
		return min(d_sp(p1, p2, p3), d_sp(p1, p2, p4), d_sp(p3, p4, p1), d_sp(p3, p4, p2))
	from sys import stdin
	file_input = stdin
	while True:
		(W, N) = map(int, file_input.readline().split())
		if W == 0:
			break
		if N == 0:
			print(W)
			continue
		polygons = []
		adj = [[] for i in range(N + 1)]
		adj_s = adj[0]
		goal = N + 1
		for i in range(1, N + 1):
			M = int(file_input.readline())
			p = [i]
			s_d = W
			g_d = W
			for j in range(M):
				(x, y) = map(int, file_input.readline().split())
				p.append(x + y * 1j)
				s_d = min(s_d, x)
				g_d = min(g_d, W - x)
			adj_s.append((i, s_d))
			adj[i].append((goal, g_d))
			p.append(p[1])
			polygons.append(p)
		for (p1, p2) in combinations(polygons, 2):
			i = p1[0]
			j = p2[0]
			d = [d_s(v1, v2, v3, v4) for (v3, v4) in zip(p2[1:], p2[2:]) for (v1, v2) in zip(p1[1:], p1[2:])]
			d = min(d)
			adj[i].append((j, d))
			adj[j].append((i, d))
		PQ = [(0, 0)]
		isVisited = [False] * (N + 2)
		distance = [W] * (N + 2)
		distance[0] = 0
		while PQ:
			(u_cost, u) = heappop(PQ)
			if u == goal:
				print(u_cost)
				break
			if u_cost > distance[u]:
				continue
			isVisited[u] = True
			for (v, v_cost) in adj[u]:
				if isVisited[v]:
					continue
				t_cost = distance[u] + v_cost
				if t_cost < distance[v]:
					distance[v] = t_cost
					heappush(PQ, (t_cost, v))
solve()


from heapq import heappush, heappop
import sys
readline = sys.stdin.readline
write = sys.stdout.write

def cross2(p, q):
	return p[0] * q[1] - p[1] * q[0]

def dot2(p, q):
	return p[0] * q[0] + p[1] * q[1]

def dist2(p):
	return p[0] ** 2 + p[1] ** 2

def segment_line_dist(x, p0, p1):
	z0 = (p1[0] - p0[0], p1[1] - p0[1])
	z1 = (x[0] - p0[0], x[1] - p0[1])
	if 0 <= dot2(z0, z1) <= dist2(z0):
		return cross2(z0, z1) ** 2 / dist2(z0)
	z2 = (x[0] - p1[0], x[1] - p1[1])
	return min(dist2(z1), dist2(z2))

def solve():
	(W, N) = map(int, readline().split())
	if W == N == 0:
		return False
	PS = []
	for i in range(N):
		M = int(readline())
		P = [list(map(int, readline().split())) for i in range(M)]
		PS.append(P)
	G = [[] for i in range(N + 2)]
	for i in range(N):
		Pi = PS[i]
		ni = len(Pi)
		for j in range(i + 1, N):
			Pj = PS[j]
			r = 10 ** 18
			nj = len(Pj)
			for p1 in Pi:
				for k in range(nj):
					q1 = Pj[k - 1]
					q2 = Pj[k]
					r = min(r, segment_line_dist(p1, q1, q2))
			for q1 in Pj:
				for k in range(ni):
					p1 = Pi[k - 1]
					p2 = Pi[k]
					r = min(r, segment_line_dist(q1, p1, p2))
			d = r ** 0.5
			G[i].append((j, d))
			G[j].append((i, d))
		d = min((x for (x, y) in Pi))
		G[i].append((N, d))
		G[N].append((i, d))
		d = W - max((x for (x, y) in Pi))
		G[i].append((N + 1, d))
		G[N + 1].append((i, d))
	G[N].append((N + 1, W))
	G[N + 1].append((N, W))
	que = [(0, N)]
	dist = [10 ** 18] * (N + 2)
	dist[N] = 0
	while que:
		(cost, v) = heappop(que)
		if dist[v] < cost:
			continue
		for (w, d) in G[v]:
			if cost + d < dist[w]:
				dist[w] = cost + d
				heappush(que, (cost + d, w))
	write('%.16f\n' % dist[N + 1])
	return True
while solve():
	...