You are given an array with several `"even"` words, one `"odd"` word, and some numbers mixed in.

Determine if any of the numbers in the array is the index of the `"odd"` word. If so, return `true`, otherwise `false`.

Source: codewars | Difficulty: EASY

Starter code: def odd_ball(arr):
	

Solutions:
def odd_ball(arr):
	return arr.index('odd') in arr


def odd_ball(xs):
	return xs.index('odd') in xs


def odd_ball(arr):
	g = arr.index('odd')
	if g in arr:
		return True
	else:
		return False


def odd_ball(arr):
	fl = arr.index('odd')
	for i in arr:
		if type(i) is int:
			if i == fl:
				return True
	return False


odd_ball = lambda a: a.index('odd') in a


def odd_ball(arr):
	index = arr.index('odd')
	number = [x for x in arr if x == index]
	if len(number) > 0:
		return True
	else:
		return False


def odd_ball(A):
	return A.index('odd') in A