**This Kata is intended as a small challenge for my students**

All Star Code Challenge #18

Create a function called that accepts 2 string arguments and returns an integer of the count of occurrences the 2nd argument is found in the first one.

If no occurrences can be found, a count of 0 should be returned.

Notes:
* The first argument can be an empty string  
* The second string argument will always be of length 1

Source: codewars | Difficulty: EASY
Tags: String algorithms

Fundamentals

Starter code: def str_count(strng, letter):
	

Solutions:
def str_count(strng, letter):
	counter = 0
	for chr in strng:
		if chr == letter:
			counter += 1
	return counter


def str_count(strng, letter):
	return strng.count(letter)


def str_count(string, letter):
	return string.count(letter)


str_count = lambda strng, letter: strng.count(letter)


def str_count(strng, letter):
	count = 0
	for e in strng:
		if e == letter:
			count += 1
	return count


def str_count(_str: str, letter: str) -> int:
	return _str.count(letter)


def str_count(strng, letter):
	count = 0
	if letter in strng:
		for i in range(len(strng)):
			if strng[i] == letter:
				count += 1
		return count
	else:
		return 0


def str_count(st, l):
	return st.count(l)


import re

def str_count(strng, letter):
	return len(strng.split(letter)) - 1


def str_count(strng, letter):
	return sum([ch == letter for ch in strng])


def str_count(string, letter):
	return sum(map(lambda x: x == letter, string))


def str_count(strng, letter):
	from collections import Counter
	temp = Counter(strng)
	try:
		return temp[letter]
	except:
		return 0


def str_count(strng, letter):
	if strng in ['']:
		return 0
	else:
		return strng.count(letter)


def str_count(strng, letter):
	return strng.count(letter, 0, len(strng))


str_count = lambda x, y: x.count(y)


def str_count(strng, letter):
	count = 0
	for i in strng:
		if i == letter:
			count += 1
	return count


def str_count(string: str, letter: str) -> int:
	count_letter = 0
	for i in string:
		if i == letter:
			count_letter += 1
	return count_letter


def str_count(strng, letter):
	x = 0
	for i in range(len(strng)):
		if strng[i] == letter:
			x += 1
	return x


def str_count(strng, letter):
	c = 0
	for char in strng:
		if letter == char:
			c += 1
	return c


def str_count(strng, letter):
	strn = 0
	for i in strng:
		a = i.count(letter)
		strn += a
	return strn


def str_count(strng, letter):
	x = list(strng)
	y = 0
	for k in x:
		if k == letter:
			y += 1
		else:
			y += 0
	return y


def str_count(string, letter):
	counter = 0
	for n in string:
		if n == letter:
			counter += 1
		else:
			counter + 0
	return counter


def str_count(string, letter):
	res = 0
	for c in string.lower():
		res += 1 if c == letter else 0
	return res


def str_count(strng, letter):
	count = 0
	for letr in strng:
		if letter == letr:
			count += 1
		else:
			count += 0
	return count


def str_count(strng, letter):
	count = 0
	for alphabet in strng:
		if letter == alphabet:
			count += 1
	return count


def str_count(a, b):
	count = 0
	for i in a:
		if b == i:
			count += 1
	return count


def str_count(string, letter):
	count = 0
	for l in string:
		if letter == l:
			count += 1
	return count


from collections import Counter

def str_count(strng, letter):
	tot = Counter(strng)
	return tot[letter]


str_count = lambda s, l: len([i for i in range(len(s)) if s.startswith(l, i)])


def str_count(strng, letter):
	sm = 0
	for i in strng:
		if i == letter:
			sm += 1
	return sm


def str_count(string, letter):
	res = 0
	for i in string:
		if i == letter:
			res += 1
	return res


def str_count(strng, letter):
	Liste = list(strng)
	Counts = dict()
	for ch in Liste:
		if ch not in Counts:
			Counts[ch] = 1
		else:
			Counts[ch] = Counts[ch] + 1
	if letter in Counts:
		return Counts[letter]
	else:
		return 0
	return Counts[letter]


def str_count(strng, letter):
	soln = 0
	for char in strng:
		if char == letter:
			soln += 1
	return soln


def str_count(strng, letter):
	i = 0
	n = 0
	while i <= len(strng) - 1:
		for j in strng:
			if j == letter:
				n = n + 1
		i = i + 1
		return n


def str_count(strng, letter):
	counter = 0
	for char in strng:
		if letter == char:
			counter += 1
	return counter


def str_count(strng, letter):
	import re
	list = re.findall(letter, strng)
	return len(list)


def str_count(strng, letter):
	arr = []
	for j in letter:
		for i in strng:
			if j == i:
				arr.append(j)
	return len(arr)


def str_count(strng, letter):
	k = 0
	for i in strng:
		if letter == i:
			k += 1
	return k


def str_count(strng, letter):
	letter_count = {letter: 0}
	for char in strng:
		if char == letter:
			letter_count[char] += 1
	return letter_count[letter]


def str_count(strng, letter):
	strngL = list(strng)
	letterCount = 0
	for i in range(len(strngL)):
		if strngL[i] == letter:
			letterCount += 1
	return letterCount


def str_count(string, letter):
	amount = 0
	for l in string:
		if l == letter:
			amount += 1
	return amount


def str_count(strng, letter):
	ans = 0
	for c in strng:
		if c == letter:
			ans += 1
	return ans


def str_count(strng, letter):
	letter_count = 0
	for i in strng:
		if i == letter:
			letter_count += 1
	return letter_count


def str_count(str, letter):
	c = 0
	for l in str:
		if l == letter:
			c += 1
	return c


def str_count(strng, letter):
	return strng.count(letter) if len(strng) > 0 and letter in strng else 0


def str_count(st, letter):
	r = 0
	for i in st:
		if i == letter:
			r += 1
	return r


def str_count(strng: str, letter: str) -> int:
	return strng.count(letter)


def str_count(string, letter):
	return len([s for s in string if s == letter])


def str_count(string, letter):
	count = 0
	for c in string:
		if letter == c:
			count += 1
	return count


def str_count(string, letter):
	return string.count(letter) if len(string) > 0 else 0


def str_count(strng, letter):
	answer = 0
	x = 0
	length = len(strng)
	while x < length:
		if strng[x] == letter:
			answer = answer + 1
		x = x + 1
	return answer


def str_count(strng, letter):
	count = 0
	for check in strng:
		if check == letter:
			count += 1
	return count


def str_count(strng, letter):
	if strng.find(letter) == -1:
		return 0
	else:
		return strng.count(letter)


def str_count(string, letter):
	result = 0
	for i in string:
		if i == letter:
			result += 1
	return result


def str_count(strng, letter):
	val = 0
	for alpha in strng:
		if letter == alpha:
			val += 1
	print(val)
	return val


def str_count(string, letter):
	counter = 0
	for i in string:
		if i == letter:
			counter = counter + 1
	return counter


def str_count(strng, letter):
	if letter not in strng:
		return 0
	else:
		return 1 + str_count(strng.replace(letter, '', 1), letter)


def str_count(strng, letter):
	i = 0
	for c in strng:
		if c == letter:
			i += 1
	return i


def str_count(strng, letter):
	arr = list(strng)
	i = 0
	for item in arr:
		if item == letter:
			i += 1
	return i


def str_count(strng, letter):
	return len(['big ass' for x in strng if x == letter])


def str_count(s, r):
	return len([x for x in s if x == r])


import re

def str_count(strng, letter):
	x = re.findall(letter, strng)
	return len(x)


def str_count(strng, letter):
	instances = 0
	for char in strng:
		if char == letter:
			instances += 1
	return instances


def str_count(strng, letter):
	quantity_letter = 0
	for i in strng:
		if i == letter:
			quantity_letter = quantity_letter + 1
	return quantity_letter


def str_count(strng, letter):
	res = 0
	for simv in strng:
		if simv is letter:
			res = res + 1
	return res


def str_count(stroka, letter):
	spisok = list(stroka)
	razi = 0
	x = 0
	while x != len(spisok):
		if spisok[x] == letter:
			razi = razi + 1
			x = x + 1
		else:
			x = x + 1
	return razi


def str_count(string, letter):
	total = 0
	for i in string:
		if i == letter:
			total += 1
		else:
			pass
	return total


def str_count(strng, letter):
	a = 0
	for i in strng:
		if letter == i:
			a = a + 1
	return a


def str_count(strg, letter):
	return strg.count(letter)


def str_count(strng, letter):
	a = 0
	for l in strng:
		if l == letter:
			a += 1
	return a


def str_count(strng, letter):
	y = 0
	for n in strng:
		if n == letter:
			y += 1
	return y


def str_count(strng, letter):
	count_letter = 0
	for i in strng:
		if letter == i:
			count_letter += 1
	return count_letter


def str_count(strng, letter):
	return sum((True for x in strng if x == letter))


def str_count(strng, letter):
	count = 0
	x = 0
	while x < len(strng):
		if letter == strng[x]:
			count += 1
		x += 1
	return count


def str_count(string, letter):
	count = 0
	for i in range(len(string)):
		if letter in string[i]:
			count += 1
	return count


def str_count(strng, letter):
	count = 0
	for item in strng:
		if item in letter:
			count += 1
	return count