Construct a function 'coordinates', that will return the distance between two points on a cartesian plane, given the x and y coordinates of each point.

There are two parameters in the function, ```p1``` and ```p2```. ```p1``` is a list ```[x1,y1]``` where ```x1``` and ```y1``` are the x and y coordinates of the first point. ```p2``` is a list ```[x2,y2]``` where ```x2``` and ```y2``` are the x and y coordinates of the second point. 

The distance between the two points should be rounded to the `precision` decimal if provided, otherwise to the nearest integer.

Source: codewars | Difficulty: EASY

Starter code: def coordinates(p1, p2, precision=0):
	

Solutions:
def coordinates(p1, p2, precision=0):
	return round(sum(((b - a) ** 2 for (a, b) in zip(p1, p2))) ** 0.5, precision)


import math

def coordinates(p1, p2, precision=0):
	return round(math.hypot(p1[0] - p2[0], p1[1] - p2[1]), precision)


def coordinates(a, b, p=0):
	return round(sum(((i - j) ** 2 for (i, j) in zip(a, b))) ** 0.5, p)


from math import hypot

def coordinates(p1, p2, r=0):
	(x1, y1) = p1
	(x2, y2) = p2
	return round(hypot(x2 - x1, y2 - y1), r)


import math

def coordinates(p1, p2, p=0):
	return round(math.hypot(abs(p1[0] - p2[0]), abs(p1[1] - p2[1])), p)


import math

def coordinates(p1, p2, d=0):
	formula = math.sqrt((p2[0] - p1[0]) ** 2 + (p2[1] - p1[1]) ** 2)
	distance = round(formula, d)
	return distance


coordinates = lambda p1, p2, p=0: round(((p1[0] - p2[0]) ** 2 + (p1[1] - p2[1]) ** 2) ** 0.5, p)


def coordinates(p1, p2, prec=0):
	return round(((p2[1] - p1[1]) ** 2 + (p2[0] - p1[0]) ** 2) ** 0.5, prec)


from math import sqrt

def coordinates(p1, p2, precision=0):
	(x1, y1) = p1
	(x2, y2) = p2
	distance = sqrt((x1 - x2) ** 2 + (y1 - y2) ** 2)
	return round(distance, precision)