Write function heron which calculates the area of a triangle with sides a, b, and c.

Heron's formula: sqrt (s \* (s - a) \* (s - b) \* (s - c)), where s = (a + b + c) / 2.
Output should have 2 digits precision.

Source: codewars | Difficulty: EASY
Tags: Fundamentals

Starter code: def heron(a,b,c):
	

Solutions:
import math

def heron(a, b, c):
	s = (a + b + c) / 2
	return round(math.sqrt(s * (s - a) * (s - b) * (s - c)), 2)


def heron(a, b, c):
	return round(1 / 4 * (4 * b * b * c * c - (b * b + c * c - a * a) ** 2) ** (1 / 2), 2)


heron = lambda *args: (lambda a, b, c, s: round((s * (s - a) * (s - b) * (s - c)) ** 0.5, 2))(*args, sum(args) / 2)


def heron(*sides):
	s = sum(sides) / 2
	(a, b, c) = sides
	return round((s * (s - a) * (s - b) * (s - c)) ** 0.5, 2)


def heron(*l):
	s = sum(l) / 2
	return round((s * (s - l[0]) * (s - l[1]) * (s - l[2])) ** 0.5, 2)


import math

def heron(*liste):
	sum = 0
	for i in liste:
		sum += i
	s = sum / 2
	return round(math.sqrt(s * (s - liste[0]) * (s - liste[1]) * (s - liste[2])), 2)


import math

def heron(a, b, c):
	d = (a + b + c) / 2
	return round(math.sqrt(d * (d - a) * (d - b) * (d - c)), 2)


import math

def heron(a, b, c):
	p = (a + b + c) / 2
	return round(math.sqrt(p * (p - a) * (p - b) * (p - c)), 2)