*Debug*   function `getSumOfDigits` that takes positive integer to calculate sum of it's digits. Assume that argument is an integer.

### Example
```
123  => 6
223  => 7
1337 => 15
```

Source: codewars | Difficulty: EASY
Tags: Fundamentals

Starter code: def get_sum_of_digits(num):
	

Solutions:
def get_sum_of_digits(num):
	return sum(map(int, str(num)))


def get_sum_of_digits(num):
	sum = 0
	str_num = str(num)
	for x in str_num:
		sum += int(x)
	return sum


def get_sum_of_digits(n):
	return sum((int(d) for d in str(n)))


def get_sum_of_digits(n):
	return sum(map(int, str(int(n))))


def get_sum_of_digits(num):
	sum = int()
	digits = str(num)
	for x in digits:
		sum += int(x)
	return sum


def get_sum_of_digits(num):
	digits = []
	for i in str(num):
		digits.append(int(i))
	return sum(digits)


def get_sum_of_digits(num):
	return sum(list(map(int, [i for i in str(num)])))


import re

def get_sum_of_digits(num):
	sum = 0
	num = str(num)
	digits = re.findall('[0-9]{1}', num)
	for x in digits:
		x = int(x)
		sum = sum + x
	return sum


def get_sum_of_digits(num):
	my_list = []
	for i in str(num):
		my_list.append(int(i))
	return sum(my_list)


import functools

def get_sum_of_digits(num):
	return functools.reduce(lambda a, b: a + b, [int(x) for x in str(num)])