Transpose means is to interchange rows and columns of a two-dimensional array matrix.

[A^(T)]ij=[A]ji

ie:
Formally, the i th row, j th column element of AT is the j th row, i th column element of A:



Example :

```
[[1,2,3],[4,5,6]].transpose() //should return [[1,4],[2,5],[3,6]]
```

Write a prototype transpose to array in JS or add a .transpose method in Ruby or create a transpose function in Python so that any matrix of order ixj 2-D array returns transposed Matrix of jxi .

Link:  To understand array prototype

Source: codewars | Difficulty: EASY
Tags: Matrices

Fundamentals

Data structures

Mathematics

Starter code: def transpose(arr):
	

Solutions:
import numpy as np

def transpose(A):
	if len(A) == 0:
		return []
	return np.array(A, dtype='O').T.tolist() if len(A[0]) > 0 else [[]]


def transpose(arr):
	if arr and (not any(map(bool, arr))):
		return [[]]
	return list(map(list, zip(*arr)))


def transpose(arr):
	tran_each = []
	tran_com = []
	if len(arr) > 0 and len(arr[0]) > 0:
		n_row = len(arr[0])
		n_col = len(arr)
		for j in range(n_row):
			for i in range(n_col):
				tran_each.append(arr[i][j])
			tran_com.append(tran_each)
			tran_each = []
		return tran_com
	elif len(arr) > 0:
		return [[]]
	else:
		return []


def transpose(arr):
	lst = []
	if len(arr) == 0:
		return arr
	for i in range(len(arr[0])):
		lst.append([arr[j][i] for j in range(len(arr))])
	return [[]] if not lst else lst


def transpose(arr):
	if len(arr) == 0:
		return []
	if len(arr[0]) == 0:
		return [[]]
	return [[arr[row][col] for row in range(len(arr))] for col in range(len(arr[0]))]


def transpose(arr):
	return [] if arr == [] else [[]] if arr[0] == [] else [[arr[i][j] for i in range(len(arr))] for j in range(len(arr[0]))]