Write a function called "filterEvenLengthWords".

Given an array of strings, "filterEvenLengthWords" returns an array containing only the elements of the given array whose length is an even number.

var output = filterEvenLengthWords(['word', 'words', 'word', 'words']);

console.log(output); // --> ['word', 'word']

Source: codewars | Difficulty: EASY
Tags: Fundamentals

Starter code: def filter_even_length_words(words):
	

Solutions:
def filter_even_length_words(words):
	return [word for word in words if len(word) % 2 == 0]


def filter_even_length_words(words):
	even_words_array = []
	for i in words:
		if len(i) % 2 == 0:
			even_words_array.append(i)
	return even_words_array


def filter_even_length_words(words):
	ret = []
	for w in words:
		if len(w) % 2 == 0:
			ret.append(w)
	return ret


def filter_even_length_words(words):
	return [w for w in words if len(w) % 2 == 0]


def filter_even_length_words(words):
	return [el for el in words if len(el) % 2 == 0]


filter_even_length_words = lambda w: [x for x in w if len(x) % 2 == 0]


def filter_even_length_words(words):
	arr = []
	for el in words:
		if len(el) % 2 == 0:
			arr.append(el)
	return arr