Tic-tac-toe is played by two players A and B on a 3 x 3 grid.
Here are the rules of Tic-Tac-Toe:

Players take turns placing characters into empty squares (" ").
The first player A always places "X" characters, while the second player B always places "O" characters.
"X" and "O" characters are always placed into empty squares, never on filled ones.
The game ends when there are 3 of the same (non-empty) character filling any row, column, or diagonal.
The game also ends if all squares are non-empty.
No more moves can be played if the game is over.

Given an array moves where each element is another array of size 2 corresponding to the row and column of the grid where they mark their respective character in the order in which A and B play.
Return the winner of the game if it exists (A or B), in case the game ends in a draw return "Draw", if there are still movements to play return "Pending".
You can assume that moves is valid (It follows the rules of Tic-Tac-Toe), the grid is initially empty and A will play first.
 
Example 1:
Input: moves = [[0,0],[2,0],[1,1],[2,1],[2,2]]
Output: "A"
Explanation: "A" wins, he always plays first.
"X  "    "X  "    "X  "    "X  "    "X  "
"   " -> "   " -> " X " -> " X " -> " X "
"   "    "O  "    "O  "    "OO "    "OOX"

Example 2:
Input: moves = [[0,0],[1,1],[0,1],[0,2],[1,0],[2,0]]
Output: "B"
Explanation: "B" wins.
"X  "    "X  "    "XX "    "XXO"    "XXO"    "XXO"
"   " -> " O " -> " O " -> " O " -> "XO " -> "XO " 
"   "    "   "    "   "    "   "    "   "    "O  "

Example 3:
Input: moves = [[0,0],[1,1],[2,0],[1,0],[1,2],[2,1],[0,1],[0,2],[2,2]]
Output: "Draw"
Explanation: The game ends in a draw since there are no moves to make.
"XXO"
"OOX"
"XOX"

Example 4:
Input: moves = [[0,0],[1,1]]
Output: "Pending"
Explanation: The game has not finished yet.
"X  "
" O "
"   "

 
Constraints:

1 <= moves.length <= 9
moves[i].length == 2
0 <= moves[i][j] <= 2
There are no repeated elements on moves.
moves follow the rules of tic tac toe.

Source: leetcode | Difficulty: EASY
Tags: Matrices

Data structures

Starter code: class Solution:
    def tictactoe(self, moves: List[List[int]]) -> str:
        

Solutions:
class Solution:

	def tictactoe(self, moves: List[List[int]]) -> str:
		(player_a, player_b) = (moves[0::2], moves[1::2])
		possible_wins = {0: [[0, 0], [1, 1], [2, 2]], 1: [[0, 0], [1, 0], [2, 0]], 2: [[0, 1], [1, 1], [2, 1]], 3: [[0, 2], [1, 2], [2, 2]], 4: [[0, 0], [0, 1], [0, 2]], 5: [[1, 0], [1, 1], [1, 2]], 6: [[2, 0], [2, 1], [2, 2]], 7: [[0, 2], [1, 1], [2, 0]]}
		for possible_win in list(possible_wins.values()):
			count_a = 0
			for move in player_a:
				if move in possible_win:
					count_a += 1
				if count_a == 3:
					return 'A'
			count_b = 0
			for move in player_b:
				if move in possible_win:
					count_b += 1
				if count_b == 3:
					return 'B'
		return 'Draw' if len(player_a) + len(player_b) == 9 else 'Pending'