=====Problem Statement=====
In this challenge, the task is to debug the existing code to successfully execute all provided test files.
Consider that vowels in the alphabet are a, e, i, o, u and y.
Function score_words takes a list of lowercase words as an argument and returns a score as follows:
The score of a single word is 2 if the word contains an even number of vowels. Otherwise, the score of this word is 1. The score for the whole list of words is the sum of scores of all words in the list.
Debug the given function score_words such that it returns a correct score.
Your function will be tested on several cases by the locked template code.

=====Input Format=====
The input is read by the provided locked code template. In the first line, there is a single integer n denoting the number of words. In the second line, there are n space-separated lowercase words.

=====Constraints=====
1≤n≤20
Each word has at most 20 letters and all letters are English lowercase letters

=====Output Format=====
The output is produced by the provided and locked code template. It calls function score_words with the list of words read from the input as the argument and prints the returned score to the output.

Source: hackerrank | Difficulty: EASY

Starter code: def is_vowel(letter):
    return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
    score = 0
    for word in words:
        num_vowels = 0
        for letter in word:
            if is_vowel(letter):
                num_vowels += 1
        if num_vowels % 2 == 0:
            score += 2
        else:
            ++score
    return score


n = int(input())
words = input().split()
print(score_words(words))

Solutions:
def is_vowel(letter):
	return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
	score = 0
	for word in words:
		num_vowels = 0
		for letter in word:
			if is_vowel(letter):
				num_vowels += 1
		if num_vowels % 2 == 0:
			score += 2
		else:
			score += 1
	return score


def is_vowel(letter):
	return letter in ['a', 'e', 'i', 'o', 'u', 'y']

def score_words(words):
	score = 0
	for word in words:
		num_vowels = 0
		for letter in word:
			if is_vowel(letter):
				num_vowels += 1
		if num_vowels % 2 == 0:
			score += 2
		else:
			score += 1
	return score