Coach Chef has selected all the players and now he has to separate them into 2 teams, $A$ and $B$.

Each player must be included in exactly one of the 2 teams and each player $x$, has a skill level $S_{x}$. It is not necessary for both teams to have equal number of players, but they have to be non-empty.

Since the number of players is way too high, Chef doesn't have an actual list of every player individually. Instead, he keeps a list of $N$ pairs $ {X_{i}, Y_{i} }$, which tells him that there are $Y_{i}$ players with skill level $X_{i}$.

Chef thinks that a division into 2 teams is Good, if the skill value of every player in A divides the skill value of every player in B. More formally, $S_{b} \bmod S_{a} = 0$, ∀ a ∈ A, b ∈ B.

Since he is busy, can you help him find total number of Good divisions? Since the answer can be very large, print it modulo $998244353$.

NOTE : 2 divisions are considered different if there exists any player $x$ belonging to different teams in the 2 divisions. (See example for more clarity). 

------  Input  ------ 

The first line of the input contains a single integer $T$ denoting the number of test cases. The description of
$T$ test cases follows.
The first line for each testcase has a single integer $N$, denoting the number of pairs in Chef's list. 
$N$ lines follow. Each contains 2 space separated integers $X_{i}$ and $Y_{i}$, denoting Chef has $Y_{i}$ players with skill level $X_{i}$.

------  Output  ------ 

Output one integer for every testcase. The number of total Good divisions, modulo $998244353$.

------ Constraints ------ 

$ $1 ≤ T, N ≤ 10^{5}$
$$ $1 ≤ X_{i} ≤ 10^{9}, X_{i} \neq X_{j}$ for $i \neq j$
$$ $1 ≤ Y_{i} ≤ 10^{5}$
$$ Sum of $N$ over all testcases does not exceed $10^{5}$

------ Example Input ------ 

5

1

10 1

3

1 1

3 1

6 1

3

1 1

3 2

6 1

10

1 30

2 40

3 30

6 50

12 100

18 500

216 400

24 999

432 9999

864 123

1

10 1000

------ Example Output ------ 

0

2

4

128248098

23226275

------ Explanation ------ 

Example Case 1: Only one player P1. No way to split into teams.

Example Case 2: 3 players total, P1, P2 & P3 with skill level 1, 3 & 6 respectively. Possible divisions:

$ A=[P1], B=[P2, P3]
$$ A=[P1, P2], B=[P3]Example Case 3: 4 players total, P1, P2, P3 & P4 with skill levels 1, 3, 3 & 6 respectively. Possible divisions :
 
$ A=[P1], B=[P2, P3, P4]
$$ A=[P1, P2], B=[P3, P4]
$$ A=[P1, P3], B=[P2, P4]
$$ A=[P1, P2, P3], B=[P4]

Source: codechef | Difficulty: VERY_HARD
Tags: Number theory

Combinatorics

Data structures

Mathematics


Solutions:
def gcd(a, b):
	if a == 0:
		return b
	return gcd(b % a, a)
for _ in range(int(input())):
	n = int(input())
	a = []
	mod = 998244353
	for i in range(n):
		(x, y) = map(int, input().split())
		a.append((x, y))
	a.sort()
	if n == 1:
		print((pow(2, a[0][1], mod) - 2) % mod)
		continue
	prefixlcm = []
	lcm = 1
	for i in range(n):
		lcm = lcm * a[i][0] // gcd(lcm, a[i][0])
		prefixlcm.append(lcm)
	suffixgcd = [0] * n
	g = 0
	for i in range(n - 1, -1, -1):
		g = gcd(g, a[i][0])
		suffixgcd[i] = g
	res = 0
	b = 0
	for i in range(n - 1):
		if prefixlcm[i] > 1000000000.0:
			b = 1
			break
		if suffixgcd[i] % prefixlcm[i] == 0:
			res = (res + pow(2, a[i][1], mod) - 2) % mod
		if i + 1 < n and suffixgcd[i + 1] % prefixlcm[i] == 0:
			res = (res + 1) % mod
	if not b and suffixgcd[n - 1] % prefixlcm[n - 1] == 0:
		res = (res + pow(2, a[n - 1][1], mod) - 2) % mod
	print(res)


m = 998244353

def p(y):
	ans = 1
	x = 2
	while y > 0:
		if y & 1 == 1:
			ans = x * ans % m
		y = y >> 1
		x = x * x % m
	return ans
for _ in range(int(input())):
	n = int(input())
	l = []
	for _ in range(n):
		(x, y) = map(int, input().split())
		l.append((x, y))
	l.sort()
	ans = 0
	for i in range(n):
		am = True
		j = i + 1
		while j < n:
			if l[j][0] % l[i][0] != 0:
				am = False
				break
			j += 1
		bm = True
		j = i - 1
		while j >= 0:
			if l[i][0] % l[j][0] != 0:
				bm = False
				break
			j -= 1
		if am and bm:
			ans = (ans + p(l[i][1]) - 1) % m
			if i == n - 1:
				ans = (ans - 1) % m
		if am and (not bm):
			ans = (ans + 1) % m
			if i == n - 1:
				ans = (ans - 1) % m
	print(ans)


import sys, math, itertools, random, bisect
from collections import defaultdict
INF = 10 ** 18

def get_ints():
	return map(int, sys.stdin.readline().strip().split())

def get_array():
	return list(map(int, sys.stdin.readline().strip().split()))

def input():
	return sys.stdin.readline().strip()
mod = 998244353
N = 10 ** 5 + 5
two = [0] * N
for i in range(1, N):
	two[i] = (two[i - 1] + 1) % mod * 2 % mod
	two[i] -= 1
	if two[i] == -1:
		two[i] = mod - 1
for _ in range(int(input())):
	n = int(input())
	a = []
	for i in range(n):
		(x, y) = get_ints()
		a.append([x, two[y]])
	if n == 1:
		print((a[0][1] - 1 + mod) % mod)
		continue
	a.sort(key=lambda x: x[0])
	(GCD, LCM) = ([-1] * n, [-1] * n)
	GCD[n - 1] = a[n - 1][0]
	for i in range(n - 2, -1, -1):
		GCD[i] = math.gcd(GCD[i + 1], a[i][0])
	ans = 0
	for i in range(n - 1):
		if i == 0:
			LCM[i] = a[i][0]
		else:
			LCM[i] = LCM[i - 1] * a[i][0] // math.gcd(LCM[i - 1], a[i][0])
		if LCM[i] > 10 ** 9:
			LCM[i] = -1
			break
		if GCD[i] % LCM[i] == 0:
			ans = (ans + a[i][1] - 1 + mod) % mod
		if GCD[i + 1] % LCM[i] == 0:
			ans = (ans + 1) % mod
	if LCM[n - 2] != -1:
		LCM[n - 1] = LCM[n - 2] * a[n - 1][0] // math.gcd(LCM[n - 2], a[n - 1][0])
		if GCD[n - 1] % LCM[n - 1] == 0:
			ans = (ans + a[n - 1][1] - 1 + mod) % mod
	print(ans)


from math import gcd

def lcm(x, y):
	if max(x, y) > 10 ** 9:
		return 10 ** 9 + 1
	ans = x * y // gcd(x, y)
	return ans if ans <= 10 ** 9 else 10 ** 9 + 1
mod = 998244353
for _ in range(int(input())):
	n = int(input())
	a = [tuple(map(int, input().split())) for _ in range(n)]
	a.sort(key=lambda xx: xx[0])
	pref = [1]
	suff = [0]
	for i in range(n):
		pref.append(lcm(pref[-1], a[i][0]))
	for i in range(n - 1, -1, -1):
		suff.append(gcd(suff[-1], a[i][0]))
	suff.reverse()
	(ans, prev) = (0, 0)
	for i in range(1, n + 1):
		if not suff[i - 1] % pref[i]:
			ans = (ans + pow(2, a[i - 1][1], mod) - prev - (i == 1) - (i == n)) % mod
			prev = 1
		else:
			prev = 0
	print(ans)