This is an unusual problem in an unusual contest, here is the announcement: [http://codeforces.com/blog/entry/73543](//codeforces.com/blog/entry/73543)

You have the safe lock which consists of 5 decimal digits. If you rotate some digit, it increases by one, except 9 which becomes 0.

Initially, the lock contains number x. To unlock the safe you must do the following operations in order (and be careful, don't mix up if and else statements).

If sum of digits on positions 1 and 4 is greater than 10, rotate digit on position 1 by 3 times, else rotate digit on position 4 by 8 times.

If sum of digits on positions 3 and 2 is greater than 8, rotate digit on position 4 by 9 times, else rotate digit on position 5 by 8 times.

If digit on position 3 is odd, rotate digit on position 3 by 3 times, else rotate digit on position 3 by 4 times.

If digit on position 5 is greater than digit on position 2, rotate digit on position 4 by 1 times, else rotate digit on position 2 by 7 times.

If digit on position 1 is odd, rotate digit on position 1 by 3 times, else rotate digit on position 3 by 5 times.

If digit on position 4 is odd, rotate digit on position 4 by 7 times, else rotate digit on position 1 by 9 times.

If digit on position 4 is greater than digit on position 1, rotate digit on position 4 by 9 times, else rotate digit on position 4 by 2 times.

If digit on position 1 is greater than digit on position 3, rotate digit on position 2 by 1 times, else rotate digit on position 3 by 1 times.

If digit on position 5 is greater than digit on position 3, rotate digit on position 4 by 5 times, else rotate digit on position 5 by 8 times.

If sum of digits on positions 1 and 3 is greater than 8, rotate digit on position 4 by 5 times, else rotate digit on position 2 by 5 times.

If digit on position 1 is greater than digit on position 4, rotate digit on position 4 by 3 times, else rotate digit on position 2 by 3 times.

If sum of digits on positions 3 and 1 is greater than 9, rotate digit on position 2 by 9 times, else rotate digit on position 2 by 2 times.

If sum of digits on positions 4 and 3 is greater than 10, rotate digit on position 4 by 7 times, else rotate digit on position 5 by 7 times.

If digit on position 3 is greater than digit on position 2, rotate digit on position 3 by 2 times, else rotate digit on position 4 by 6 times.

If digit on position 1 is greater than digit on position 3, rotate digit on position 1 by 9 times, else rotate digit on position 2 by 9 times.

If digit on position 3 is odd, rotate digit on position 3 by 9 times, else rotate digit on position 1 by 5 times.

If sum of digits on positions 3 and 5 is greater than 9, rotate digit on position 3 by 4 times, else rotate digit on position 3 by 9 times.

If digit on position 3 is greater than digit on position 1, rotate digit on position 5 by 1 times, else rotate digit on position 5 by 7 times.

If digit on position 1 is greater than digit on position 3, rotate digit on position 2 by 9 times, else rotate digit on position 4 by 6 times.

If sum of digits on positions 2 and 3 is greater than 10, rotate digit on position 2 by 2 times, else rotate digit on position 3 by 6 times.

Input

Input contains single number x consisting of exactly 5 digits, leading zeroes are allowed.

Output

Output the number after applying all operations.

Examples

Input


00000


Output


61376


Input


12345


Output


07769

Source: codeforces | Difficulty: UNKNOWN_DIFFICULTY
Tags: Bit manipulation

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