Poor Cade has got his number conversions mixed up again!

Fix his ```convert_num()``` function so it correctly converts a base-10 ```int```eger, 
to the selected of ```bin```ary or ```hex```adecimal.

```#The output should be a string at all times```

```python
convert_num(number, base):
    if 'base' = hex:
        return int(number, 16)
    if 'base' = bin:
        return int(number, 2)
    return (Incorrect base input)
```
Please note, invalid ```number``` or ```base``` inputs will be tested.
In the event of an invalid ```number/base``` you should return:
```python
"Invalid number input"
or
"Invalid base input"
```
For each respectively.

Good luck coding! :D

Source: codewars | Difficulty: EASY

Starter code: def convert_num(number, base):
	

Solutions:
def convert_num(number, base):
	try:
		if base == 'hex':
			return hex(number)
		if base == 'bin':
			return bin(number)
	except:
		return 'Invalid number input'
	return 'Invalid base input'


def convert_num(number, base):
	if not isinstance(number, int):
		return 'Invalid number input'
	if base == 'hex':
		return hex(number)
	elif base == 'bin':
		return bin(number)
	return 'Invalid base input'


def convert_num(number, base):
	try:
		return {'hex': hex, 'bin': bin}[base](number)
	except KeyError:
		return 'Invalid base input'
	except TypeError:
		return 'Invalid {} input'.format(('base', 'number')[isinstance(base, str)])


def convert_num(number, base):
	if base not in ('hex', 'bin'):
		return 'Invalid base input'
	try:
		return hex(number) if base == 'hex' else bin(number)
	except:
		return 'Invalid number input'


def convert_num(n, base):
	return 'Invalid number input' if not isinstance(n, int) else 'Invalid base input' if base not in ['bin', 'hex'] else bin(n) if base == 'bin' else hex(n)


def convert_num(number, base):
	try:
		return {'hex': hex(number), 'bin': bin(number)}[base]
	except:
		return 'Invalid {} input'.format(['base', 'number'][not str(number).isdigit()])