In English and programming, groups can be made using symbols such as `()` and `{}` that change meaning. However, these groups must be closed in the correct order to maintain correct syntax.

Your job in this kata will be to make a program that checks a string for correct grouping. For instance, the following groups are done correctly:

```
({})
[[]()]
[{()}]
```

The next are done incorrectly:
```
{(})
([]
[])
```

A correct string cannot close groups in the wrong order, open a group but fail to close it, or close a group before it is opened.

Your function will take an input string that may contain any of the symbols `()`, `{}` or `[]` to create groups.

It should return `True` if the string is empty or otherwise grouped correctly, or `False` if it is grouped incorrectly.

Source: codewars | Difficulty: EASY

Starter code: def group_check(s):
	

Solutions:
BRACES = {'(': ')', '[': ']', '{': '}'}

def group_check(s):
	stack = []
	for b in s:
		c = BRACES.get(b)
		if c:
			stack.append(c)
		elif not stack or stack.pop() != b:
			return False
	return not stack


def group_check(s):
	while '{}' in s or '()' in s or '[]' in s:
		s = s.replace('{}', '').replace('()', '').replace('[]', '')
	return not s


def group_check(s):
	while '()' in s or '{}' in s or '[]' in s:
		s = s.replace('()', '')
		s = s.replace('{}', '')
		s = s.replace('[]', '')
	return len(s) == 0


import re
BRACES = '\\(\\)|{}|\\[\\]'

def group_check(s):
	while re.search(BRACES, s):
		s = re.sub(BRACES, '', s)
	return s == ''


def group_check(s):
	l = 9223372036854775807
	while l > len(s):
		l = len(s)
		s = s.replace('()', '')
		s = s.replace('{}', '')
		s = s.replace('[]', '')
	return len(s) == 0


OPENING = '([{'
CLOSING = dict(['()', '[]', '{}'])

def group_check(s):
	stack = []
	for c in s:
		if c in OPENING:
			stack.append(CLOSING[c])
		elif len(stack) == 0 or c != stack.pop():
			return False
	return len(stack) == 0


parens = dict([')(', '][', '}{'])

def group_check(s):
	stack = []
	for c in s:
		if c in parens:
			if not (stack and parens[c] == stack.pop()):
				return False
		else:
			stack.append(c)
	return not stack


def group_check(s):
	open = ['(', '{', '[']
	closed = [')', '}', ']']
	f = lambda x: True if open[x] + closed[x] in s else False
	while f(0) or f(1) or f(2):
		for i in range(3):
			s = s.replace(open[i] + closed[i], '')
	if s == '':
		return True
	else:
		return False


import re

def group_check(brackets):
	while any((pair in brackets for pair in ('{}', '[]', '()'))):
		brackets = re.sub('{}|\\[]|\\(\\)', '', brackets)
	return not brackets


def group_check(s):
	for e in ['()', '{}', '[]', '{}', '()']:
		while e in s:
			s = s.replace(e, '')
	return not s