## A square of squares
You like building blocks. You especially like building blocks that are squares. And what you even like more, is to arrange them into a square of square building blocks!

However, sometimes, you can't arrange them into a square. Instead, you end up with an ordinary rectangle! Those blasted things! If you just had a way to know, whether you're currently working in vain… Wait! That's it! You just have to check if your number of building blocks is a _perfect square_.

## Task

Given an integral number, determine if it's a [square number](https://en.wikipedia.org/wiki/Square_number):

> In mathematics, a __square number__ or __perfect square__ is an integer that is the square of an integer; in other words, it is the product of some integer with itself.

The tests will _always_ use some integral number, so don't worry about that in dynamic typed languages.

### Examples

```
-1  =>  false
 0  =>  true
 3  =>  false
 4  =>  true
25  =>  true
26  =>  false
```

Source: codewars | Difficulty: EASY
Tags: Fundamentals

Mathematics

Starter code: def is_square(n):
	

Solutions:
import math

def is_square(n):
	return n > -1 and math.sqrt(n) % 1 == 0


import math

def is_square(n):
	if n < 0:
		return False
	sqrt = math.sqrt(n)
	return sqrt.is_integer()


def is_square(n):
	return n >= 0 and n ** 0.5 % 1 == 0


import math

def is_square(n):
	try:
		return math.sqrt(n).is_integer()
	except ValueError:
		return False


def is_square(n):
	if n >= 0:
		if int(n ** 0.5) ** 2 == n:
			return True
	return False


import math

def is_square(n):
	return n >= 0 and int(math.sqrt(n)) ** 2 == n


from math import sqrt

def is_square(n):
	return n >= 0 and sqrt(n).is_integer()


from math import sqrt

def is_square(n):
	if n < 0:
		return False
	count = 0
	m = int(sqrt(n))
	if m * m == n:
		count = 1
	if count == 1:
		return True
	else:
		return False


import math

def is_square(n):
	if n < 0:
		return False
	r = math.sqrt(n)
	r = math.floor(r)
	return r * r == n


import math

def is_square(n):
	if n < 0:
		return False
	return int(math.sqrt(n)) - math.sqrt(n) == 0