You are given a set of n vectors on a plane. For each vector you are allowed to multiply any of its coordinates by -1. Thus, each vector vi = (xi, yi) can be transformed into one of the following four vectors:

  * vi1 = (xi, yi), 
  * vi2 = ( - xi, yi), 
  * vi3 = (xi, - yi), 
  * vi4 = ( - xi, - yi). 



You should find two vectors from the set and determine which of their coordinates should be multiplied by -1 so that the absolute value of the sum of the resulting vectors was minimally possible. More formally, you should choose two vectors vi, vj (1 ≤ i, j ≤ n, i ≠ j) and two numbers k1, k2 (1 ≤ k1, k2 ≤ 4), so that the value of the expression |vik1 + vjk2| were minimum.

Input

The first line contains a single integer n (2 ≤ n ≤ 105). Then n lines contain vectors as pairs of integers "xi yi" ( - 10000 ≤ xi, yi ≤ 10000), one pair per line.

Output

Print on the first line four space-separated numbers "i k1 j k2" — the answer to the problem. If there are several variants the absolute value of whose sums is minimum, you can print any of them. 

Examples

Input

5
-7 -3
9 0
-8 6
7 -8
4 -5


Output

3 2 4 2


Input

5
3 2
-4 7
-6 0
-8 4
5 1


Output

3 4 5 4

Note

A sum of two vectors v = (xv, yv) and u = (xu, yu) is vector s = v + u = (xv + xu, yv + yu).

An absolute value of vector v = (x, y) is number <image>. 

In the second sample there are several valid answers, such as:

(3 1 4 2), (3 1 4 4), (3 4 4 1), (3 4 4 3), (4 1 3 2), (4 1 3 4), (4 2 3 1).

Source: codeforces | Difficulty: HARD
Tags: Geometry

Sorting

Divide and conquer


Solutions: