Given a sentence that consists of some words separated by a single space, and a searchWord.
You have to check if searchWord is a prefix of any word in sentence.
Return the index of the word in sentence where searchWord is a prefix of this word (1-indexed).
If searchWord is a prefix of more than one word, return the index of the first word (minimum index). If there is no such word return -1.
A prefix of a string S is any leading contiguous substring of S.
 
Example 1:
Input: sentence = "i love eating burger", searchWord = "burg"
Output: 4
Explanation: "burg" is prefix of "burger" which is the 4th word in the sentence.

Example 2:
Input: sentence = "this problem is an easy problem", searchWord = "pro"
Output: 2
Explanation: "pro" is prefix of "problem" which is the 2nd and the 6th word in the sentence, but we return 2 as it's the minimal index.

Example 3:
Input: sentence = "i am tired", searchWord = "you"
Output: -1
Explanation: "you" is not a prefix of any word in the sentence.

Example 4:
Input: sentence = "i use triple pillow", searchWord = "pill"
Output: 4

Example 5:
Input: sentence = "hello from the other side", searchWord = "they"
Output: -1

 
Constraints:

1 <= sentence.length <= 100
1 <= searchWord.length <= 10
sentence consists of lowercase English letters and spaces.
searchWord consists of lowercase English letters.

Source: leetcode | Difficulty: EASY
Tags: String algorithms

Starter code: class Solution:
    def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
        

Solutions:
class Solution:

	def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
		for (i, w) in enumerate(sentence.split(), 1):
			if w.startswith(searchWord):
				return i
		return -1


class Solution:

	def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
		sentence = sentence.split(' ')
		a = []
		for i in range(len(sentence)):
			if len(sentence[i]) >= len(searchWord):
				if sentence[i][0:len(searchWord)] == searchWord:
					a.append(i)
		if a:
			return min(a) + 1
		else:
			return -1


class Solution:

	def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
		word_list = sentence.split(' ')
		for i in range(len(word_list)):
			if word_list[i].startswith(searchWord):
				return i + 1
		return -1


class Solution:

	def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
		arr = sentence.split()
		print(len(arr))
		for i in range(len(arr)):
			print(arr[i][:len(searchWord)])
			if arr[i][:len(searchWord)] == searchWord:
				return i + 1
		return -1


class Solution:

	def isPrefixOfWord(self, sentence: str, searchWord: str) -> int:
		words = sentence.split(' ')
		match = [i for (i, w) in enumerate(words) if w.startswith(searchWord)]
		if not match:
			return -1
		return match[0] + 1