Given a number n. Find the last two digits of 5 ^ n ( 5 to the power of n ).
Remember that overflow can occur.

-----Input:-----
- N  — the power in which you need to raise number 5.

-----Output:-----
Last two digits of 5^n.

-----Constraints-----
- $2 \leq N \leq 2.1018$

-----Sample Input:-----
2

-----Sample Output:-----
25

Source: codechef | Difficulty: UNKNOWN_DIFFICULTY


Solutions:
print(25)


import sys
import math
import bisect
from sys import stdin, stdout
from math import gcd, floor, sqrt, log
from collections import defaultdict as dd
from bisect import bisect_left as bl, bisect_right as br
sys.setrecursionlimit(100000000)
ii = lambda : int(input())
si = lambda : input()
jn = lambda x, l: x.join(map(str, l))
sl = lambda : list(map(str, input().strip()))
mi = lambda : list(map(int, input().split()))
mif = lambda : list(map(float, input().split()))
lii = lambda : list(map(int, input().split()))
ceil = lambda x: int(x) if x == int(x) else int(x) + 1
ceildiv = lambda x, d: x // d if x % d == 0 else x // d + 1
flush = lambda : stdout.flush()
stdstr = lambda : stdin.readline()
stdint = lambda : int(stdin.readline())
stdpr = lambda x: stdout.write(str(x))
mod = 1000000007
n = ii()
print(25)


x = int(input())
if x == 0:
	print(0)
elif x == 1:
	print(5)
else:
	print(25)


_ = input()
print(25)


N = float(eval(input()))
print(25)


n = float(input())
print(25)


def power(x, y, p):
	res = 1
	x = x % p
	while y > 0:
		if y & 1:
			res = res * x % p
		y = y >> 1
		x = x * x % p
	return res

def numberOfDigits(x):
	i = 0
	while x:
		x //= 10
		i += 1
	return i

def LastTwoDigit(n):
	temp = 1
	for i in range(1, 3):
		temp *= 10
	temp = power(5, n, temp)
	for i in range(2 - numberOfDigits(temp)):
		print(0, end='')
	if temp:
		print(temp)

def __starting_point():
	n = int(input())
	LastTwoDigit(n)
__starting_point()


def p(x, y, p):
	res = 1
	x = x % p
	while y > 0:
		if y & 1:
			res = res * x % p
		y = y >> 1
		x = x * x % p
	return res

def nod(x):
	i = 0
	while x:
		x //= 10
		i += 1
	return i

def ltd(n):
	temp = 1
	for i in range(1, 3):
		temp *= 10
		temp = p(5, n, temp)
	for i in range(2 - nod(temp)):
		print(0, end='')
	if temp:
		print(temp)

def __starting_point():
	n = int(input())
	ltd(n)
__starting_point()


n = int(input())
print(25)


b = int(input())
print(int(25))


n = eval(input())
print(25)


num = int(input())
print(25)


a = int(input())
print('25')