You have to create a function that converts integer given as string into ASCII uppercase letters.

All ASCII characters have their numerical order in table. 

For example,

```
from ASCII table, character of number 65 is "A".
```

Numbers will be next to each other, So you have to split given number to two digit long integers.

For example, 

```
'658776' to [65, 87, 76] and then turn it into 'AWL'.
```

Source: codewars | Difficulty: EASY
Tags: Fundamentals

Starter code: def convert(number):
	

Solutions:
def convert(number):
	return ''.join((chr(int(number[a:a + 2])) for a in range(0, len(number), 2)))


def convert(number):
	return ''.join((chr(int(number[i:i + 2])) for i in range(0, len(number), 2)))
	pass


def convert(number):
	return ''.join([chr(int(x)) for x in map(''.join, zip(*[iter(number)] * 2))])


def convert(number):
	return ''.join((chr(int(f'{e1}{e2}')) for (e1, e2) in zip(*[iter(number)] * 2)))


def convert(n):
	return ''.join([chr(int(i + k)) for (i, k) in zip(n[::2], n[1::2])])


convert = lambda s: ''.join((chr(int(s[i:i + 2])) for i in range(0, len(s), 2)))


import re

def convert(number):
	return ''.join((chr(int(code)) for code in re.findall('\\d\\d', number)))


def convert(n):
	return ''.join([chr(int(n[i:i + 2])) for i in range(0, len(n) - 1, 2)])


convert = lambda s: bytes((int(s[i:i + 2]) for i in range(0, len(s), 2))).decode()


def convert(line):
	return ''.join([chr(int(line[i:i + 2])) for i in range(0, len(line), 2)])