Mash 2 arrays together so that the returning array has alternating elements of the 2 arrays . Both arrays will always be the same length.

eg. [1,2,3] + ['a','b','c'] =  [1, 'a', 2, 'b', 3, 'c']

Difficulty: introductory

Starter code:

def array_mash(a, b):
	

Solutions:
def array_mash(xs, ys):
    return [z for p in zip(xs, ys) for z in p]

def array_mash(a, b):
    lista=[]
    c=len(a)
    for i in range(len(a)):
        lista.append(a[i])
        lista.append(b[i])
    return lista

from itertools import chain

def array_mash(a, b):
    return list(chain(*zip(a,b)))

def array_mash(a, b):
    return [i for z in zip(a, b) for i in z]

array_mash = lambda a,b: list(sum(zip(a,b),()))

def array_mash(a, b):
    out_list = list()
    for i,j in zip(a,b):
        out_list.append(i)
        out_list.append(j)
    return out_list

def array_mash(a, b):
    return [x for xs in zip(a, b) for x in xs]

def array_mash(a, b):
    for v,y in zip (range(1,len(b)*2,2),b):
        a.insert(v, y) 
    return a

array_mash=lambda *a,c=__import__("itertools").chain:list(c(*zip(*a)))

def array_mash(a, b):
    r = [None] * (len(a) + len(b))
    r[::2] = a
    r[1::2] = b
    return r