Write a function, that doubles every second integer in a list starting from the left.

Difficulty: introductory

Starter code:

def double_every_other(lst):
	

Solutions:
def double_every_other(l):
    return [x * 2 if i % 2 else x for i, x in enumerate(l)]

double_every_other = lambda l: [e * (1 + i % 2) for i, e in enumerate(l)]

def double_every_other(lst):
    return [x * (i % 2 + 1) for i, x in enumerate(lst)]

def double_every_other(lst):
    return [2*v if i&1 else v for i,v in enumerate(lst)]

def double_every_other(lst):
    for ind, item in enumerate(lst):
        if ind % 2 != 0:
            lst[ind] = item*2
    return lst

def double_every_other(lst):
    return [m * 2 if i%2 == 1 else m for i, m in enumerate(lst)]

def double_every_other(lst):
    return [a * 2 if i % 2 else a for i, a in enumerate(lst)]


def double_every_other(lst):
    return [x * 2 if i % 2 != 0 else x for i, x in enumerate(lst)]

def double_every_other(lst):
    return [num*2 if index % 2 != 0 else num for index,num in enumerate(lst)]

def double_every_other(lst):
    return [x * 2 if i % 2 == 1 else x for i, x in enumerate(lst)]