You are given a string representing an attendance record for a student. The record only contains the following three characters:



'A' : Absent. 
'L' : Late.
 'P' : Present. 




A student could be rewarded if his attendance record doesn't contain more than one 'A' (absent) or more than two continuous 'L' (late).    

You need to return whether the student could be rewarded according to his attendance record.

Example 1:

Input: "PPALLP"
Output: True



Example 2:

Input: "PPALLL"
Output: False

Difficulty: introductory

Starter code:

class Solution:
    def checkRecord(self, s: str) -> bool:
        

Solutions:
class Solution:
     def checkRecord(self, s):
         count = 0
         for i in range(0,len(s)):
             if s[i] == "A":
                 count += 1
                 if count == 2:
                     return False
             elif i >= 2 and s[i] == "L" and s[max(i-1,0)] == "L" and s[max(i-2,0)] == "L":
                 return False
         return True


class Solution:
     def checkRecord(self, s):
         twoL = 0
         twoA = 0
         i = 0
         while i < len(s):
             if s[i] == 'A':
                 twoA += 1
                 if twoA > 1:
                     return False
                 twoL = 0
             elif s[i] == 'L':
                 twoL += 1
                 if twoL > 2:
                     return False
             else:
                 twoL = 0
             i += 1
         return True

class Solution:
     def checkRecord(self, s):
         if not s:
             return
         c=0
         if s=="AA":
             return False
         for i in range(len(s)-2):
             if s[i]=="L":
                 if s[i]==s[i+1] and s[i]==s[i+2]:
                     return False
             if s[i]=="A":
                 c+=1
                 if c==2:
                     return False
 
         return True

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         return s.count('A')<=1 and s.count('LLL')==0
 
 
         
 


class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         aCount=0
         clCount=0
         for r in s:
             if r=='A':
                 aCount+=1
                 if aCount >1:
                     return False
             if r=='L':
                 clCount+=1
                 if clCount>2:
                     return False
             else:
                 clCount=0
         return True

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         return(s.count("A") < 2 and "LLL" not in s)

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         from collections import Counter
         val=Counter(s)
         idx=[]
         for i in range(len(s)):
             if s[i]=="L":
                 idx.append(i)
         for j in range(len(idx)-2):
             if idx[j+2]-idx[j]==2:
                 return False
             
         if val["A"]>1:
             return False
         return True

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
     
         return s.count('A') <= 1 and s.count('LLL') == 0


class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         charA = charL = 0
         for c in s:
             if c == 'A':
                 charA += 1 
                 if charA > 1: return False
                 charL = 0
             elif c == 'L':
                 charL += 1
                 if charL > 2: return False
             else: 
                 charL = 0
             
         
         return True
         
             


class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         return s.count("A") < 2 and "LLL" not in s

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         return s.count('A')<2 and s.count('LLL')==0

class Solution:
     def checkRecord(self, s):
         """
         :type s: str
         :rtype: bool
         """
         mydir = {}
         for record in s:
             mydir[record] = mydir.get(record,0)+1
         return mydir.get('A',0) <= 1 and s.count('LLL') == 0