Reverse and invert all integer values in a given list. 

Python:

    reverse_invert([1,12,'a',3.4,87,99.9,-42,50,5.6]) = [-1,-21,-78,24,-5]
    
Ignore all other types than integer.

Difficulty: introductory

Starter code:

def reverse_invert(lst):
	

Solutions:
from math import copysign as sign

def reverse_invert(lst):
    return [-int(sign(int(str(abs(x))[::-1]),x)) for x in lst if isinstance(x,int)]  

def reverse_invert(lst):
    return [(-1,1)[x<0]*int(str(abs(x))[::-1]) for x in lst if isinstance(x,int)]

reverse_invert=lambda l: [(-1 if n>0 else 1)*int(str(abs(n))[::-1]) for n in l if type(n)==int]

def reverse_invert(lst):
    r = []
    for i in lst:
        if isinstance(i,int):
            if i < 0:
                i = int(str(i)[1:][::-1])
            else:
                i = -int(str(i)[::-1])
            r.append(i)
    return r

def reverse_invert(lst):
    return [(-1)**(n>0) * int(str(abs(n))[::-1]) for n in lst if type(n)==int]

def reverse_invert(lst):
    return [int(str(x).lstrip('-')[::-1]) * (1 if x < 0 else -1) for x in lst if isinstance(x, int)]

def reverse_invert(lst):
    return [(-1*int(str(i)[::-1])) if i>=0 else (int(str(i)[1:][::-1])) for i in lst if type(i)==int]

def reverse_invert(lst):
    step1 = [str(-1*int(str(n)))[::-1] for n in lst if type(n)==int]
    step2 = [int(x) if '-' not in x else -1*int(x.replace('-',''))for x in step1]
    return step2

def reverse_invert(lst):
    return [(-1)**(v>0)*int(str(abs(v))[::-1]) for v in lst if isinstance(v,int)]