Shubham recently learned the lexicographical order in strings.

Now, he has two strings s1  and  s2  of the equal size and Shubham wants to compare those two strings lexicographically.

Help Shubham with the strings comparison.

Note:

Letters are case insensitive. 


-----Input-----

First line contains a integer T denoting the number of test cases. Each test case contains two strings of equal size in two separate lines.

-----Output-----

For each test case,

If s1 < s2, print "first".

If s1 > s2, print "second".

If s1=s2, print "equal".


in separate lines.

-----Constraints-----

- 1 ≤ T ≤ 10^2
- 1 ≤ Length of the string ≤ 500

-----Example-----
Input:
2
abc
acb
AB
ba

Output:
first
first

Difficulty: interview

Starter code:

Solutions:
t=eval(input())
while t:
 t=t-1
 s1=input().lower()
 s2=input().lower()
 res="equal"
 for i in range(len(s1)):
  if(s1[i]!=s2[i]):
   
   res="first" if s1[i]<s2[i] else "second"
   break
 print(res)


import sys

for __ in range(eval(input())) :
 a , b = input().lower() , input().lower()
 if a>b :
  print("second")
 elif a < b :
  print("first")
 else :
  print("equal")


# cook your code here
def compare(a,b):
 return ord(a.lower())-ord(b.lower())
   
for test in range(eval(input())):
 A = input()
 B = input()
 
 length = len(A)
 diff = 0
 
 for i in range(length):
  diff = compare(A[i],B[i])
  if(diff==0):
   continue
  else:
   break
  
 if(diff<0):
  print("first")
 elif(diff>0):
  print("second")
 else:
  print("equal")

t = int(input())
for i in range (0, t):
 s1 = input().lower()
 s2 = input().lower()
 if(s1 < s2):
  print("first")
 elif(s1 > s2):
  print("second")
 else:
  print("equal")


for t in range(eval(input())) :
 s, t = input(), input()
 s = s.lower()
 t = t.lower()
 if s < t :
  print('first')
 elif s > t :
  print('second')
 else :
  print('equal') 

cases = int(input())
for i in range(0, cases):
 s1 = input()
 s2 = input()
 counter = 0
 s1 = s1.lower()
 s2 = s2.lower()
 for i in range(0, len(s1)):
  if s1[i] < s2[i]:
   print('first')
   break
  elif s1[i] > s2[i]:
   print('second')
   break
  else:
   counter += 1
 if counter == len(s1):
  print('equal')

t = eval(input())
while(t):
 s1 = input()
 s2 = input()
 s1 = s1.lower()
 s2 = s2.lower()
 if s1<s2:
  print("first")
 elif s1>s2:
  print("second")
 else:
  print("equal")
 t = t - 1

# cook your code here
t = eval(input())
while t:
 s1 = input().lower()
 s2 = input().lower()
 if s1 < s2:
  print("first")
 elif s1 > s2 :
  print("second")
 else :
  print("equal")
 t-=1

# cook your code here
n=int(input())
while n>0:
 s1=input()
 
 s2=input()
 if s1.lower()<s2.lower():
  print("first")
 elif s1.lower()>s2.lower():
  print("second")
 elif s1.lower()==s2.lower():
  print("equal")
 n-=1