You are given a map of a server center, represented as a m * n integer matrix grid, where 1 means that on that cell there is a server and 0 means that it is no server. Two servers are said to communicate if they are on the same row or on the same column.

Return the number of servers that communicate with any other server.
 
Example 1:

Input: grid = [[1,0],[0,1]]
Output: 0
Explanation: No servers can communicate with others.
Example 2:

Input: grid = [[1,0],[1,1]]
Output: 3
Explanation: All three servers can communicate with at least one other server.

Example 3:

Input: grid = [[1,1,0,0],[0,0,1,0],[0,0,1,0],[0,0,0,1]]
Output: 4
Explanation: The two servers in the first row can communicate with each other. The two servers in the third column can communicate with each other. The server at right bottom corner can't communicate with any other server.

 
Constraints:

m == grid.length
n == grid[i].length
1 <= m <= 250
1 <= n <= 250
grid[i][j] == 0 or 1

Difficulty: interview

Starter code:

class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        

Solutions:
#[Runtime: 452 ms, faster than 97.27%] Hash
#O(MN)
#1. traverse all cells and mark server as (x, y)
#2. put each server (x, y) into serveral bucket named x1, x2, .., and y1, y2, ..
# e.g. each xbucket[x1] maintains the number of servers on line x1
#3. enumerate all server (x', y'), and see if there is at least 2 server on xbucket[x'] or ybucket[y'] 
class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        xbucket, ybucket, server = [0] * len(grid), [0] * len(grid[0]), []
        for x, row in enumerate(grid):
            for y, cell in enumerate(row):
                if cell:
                    server.append((x, y))
                    xbucket[x] += 1
                    ybucket[y] += 1
        return sum(xbucket[x] > 1 or ybucket[y] > 1 for x, y in server)

class Solution:
    def get_index_ones(self, row_list, current_columns, columns_to_check):
        counter = 0
        copy_list = list(current_columns)
        for i in copy_list:
            if row_list[i] == 1:
                if columns_to_check.get(i) == None:
                    columns_to_check[i] = 1
                else:
                    columns_to_check[i] = columns_to_check[i] + 1
                #current_columns.remove(i)
            
    def countServers(self, grid: List[List[int]]) -> int:
        row_dim = len(grid)
        column_dim = len(grid[0])
        result = 0
        map_single =[]
        current_columns = [i for i in range(column_dim)]
        columns_to_check ={}
        for x in range(row_dim):
            if 1 in grid[x]:
                difference = column_dim - len([i for i in grid[x] if i == 0])
                #more than 1
                if  difference > 1:
                    self.get_index_ones(grid[x], current_columns, columns_to_check)
                    result += difference
                else:
                    self.get_index_ones(grid[x], current_columns, columns_to_check)
                    map_single.append(grid[x])
        for row in map_single:
            for y, repeat in columns_to_check.items():
                if row[y] == 1 and repeat > 1:
                    result += 1
        return result

class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        d1 = defaultdict(int)
        d2 = defaultdict(int)
        
        for i in range(len(grid)):
            
            for j in range(len(grid[i])):
                
                if grid[i][j] == 1:
                    d1[i]+=1
                    d2[j]+=1
                    
        c = 0
        for i in range(len(grid)):
            for j in range(len(grid[i])):
                if grid[i][j] == 1 and (d1[i]>1 or d2[j]>1):
                    c+=1
                    
        return c
                
                    


class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        for i,row in enumerate(grid):
            if row.count(1)>1:
                for j,val in enumerate(row):
                    if val==1:
                        grid[i][j]=2
        for j,col in enumerate(zip(*grid)):
            if col.count(1)+col.count(2)>1:
                for i,val in enumerate(col):
                    if val==1:
                        grid[i][j]=2
        return sum(1 for row in grid for val in row if val==2)


class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        if not grid or not grid[0]:
            return 0
        
        resset = set()
        
        for ri, row in enumerate(grid):
            tmp = [(ri, ci) for ci, cell in enumerate(row) if cell]
            
            if len(tmp) >= 2:
                resset.update(tmp)
        
        for ci, col in enumerate(zip(*grid)):
            # col = (row[ci] for row in grid)
            tmp = [(ri, ci) for ri, cell in enumerate(col) if cell]

            if len(tmp) >= 2:
                resset.update(tmp)
        
        return len(resset)


class Solution:
    def get_index_ones(self, row_list, current_columns, columns_to_check):
        counter = 0
        for i in current_columns:
            if row_list[i] == 1:
                if columns_to_check.get(i) == None:
                    columns_to_check[i] = 1
                else:
                    columns_to_check[i] = columns_to_check[i] + 1
                #current_columns.remove(i)
            
    def countServers(self, grid: List[List[int]]) -> int:
        row_dim = len(grid)
        column_dim = len(grid[0])
        result = 0
        map_single =[]
        current_columns = [i for i in range(column_dim)]
        columns_to_check ={}
        for x in range(row_dim):
            if 1 in grid[x]:
                difference = column_dim - len([i for i in grid[x] if i == 0])
                #more than 1
                if  difference > 1:
                    self.get_index_ones(grid[x], current_columns, columns_to_check)
                    result += difference
                else:
                    self.get_index_ones(grid[x], current_columns, columns_to_check)
                    map_single.append(grid[x])
        for row in map_single:
            for y, repeat in columns_to_check.items():
                if row[y] == 1 and repeat > 1:
                    result += 1
        return result

from collections import deque,defaultdict
class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        row= defaultdict(lambda:[0 ,(0,0) ] )
        col= defaultdict(lambda:0)
        
        for r in range(len(grid)):
            for c in range(len(grid[r])):
                if grid[r][c] == 1:
                    row[ r  ][0] +=1
                    col[ c  ] +=1
                    row[ r  ][1] = (r,c)
                

        
        servers = 0
        

        for i in row:
            
            if row[i][0]>1:
                servers+= row[i][0]
                
            else:
                server= row[i][1][1]
                if col[server] > 1:
                    servers += 1
                    
        return servers
                
                


class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        row_count = [0 for i in range(len(grid))]
        col_count = [0 for i in range(len(grid[0]))]
        
        result = 0
        for round in range(1, 3):
            for row in range(len(grid)):
                for col in range(len(grid[row])):
                    cell = grid[row][col]
                    if cell == 1:
                        if round == 1:
                            row_count[row] += 1
                            col_count[col] += 1
                        elif row_count[row] > 1 or col_count[col] > 1:
                            result += 1
        return result

class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        m,n = len(grid), len(grid[0])
        
        rows = [0]*m
        cols = [0]*n        
        for r, row in enumerate(grid):
            for c, server in enumerate(row):
                if (server==1):
                    rows[r]+=1
                    cols[c]+=1
        
        ans = 0
        for r, row in enumerate(grid):
            for c, server in enumerate(row):
                if (server==1 and (rows[r]>1 or cols[c]>1)):
                    ans += 1
                    
        return ans


class Solution:
    def countServers(self, grid: List[List[int]]) -> int:
        rows = []
        cols = []
        servers = []
        conn = 0
        i = 0
        while i < len(grid):
            j = 0
            while j < len(grid[i]):
                if grid[i][j] == 1:
                    rows.append(i)
                    cols.append(j)
                    servers.append((i,j))
                j += 1
            i += 1
        for server in servers:
            if rows.count(server[0]) > 1 or cols.count(server[1]) > 1:
                conn += 1
        return conn