# Task

**_Given_** *an array of N integers, you have to find* **_how many times_** *you have to* **_add up the smallest numbers_** *in the array until* **_their Sum_**  *becomes greater or equal to* **_K_**.
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# Notes: 

* **_List size_**  is *at least 3*.

* **_All numbers_**  *will be*  **_positive_**.

* **_Numbers_**  could  *occur more than once* ,   **_(Duplications may exist)_**.

* Threshold  **_K_**  will *always be reachable*.
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# Input >> Output Examples

```
minimumSteps({1, 10, 12, 9, 2, 3}, 6)  ==>  return (2)
```
## **_Explanation_**:

* We  *add two smallest elements*  **_(1 + 2)_**,  *their sum is 3* .

* **_Then_**  we  **_add the next smallest number to it (3 + 3)_** , so  *the sum becomes 6* .

* **_Now_**  the result is greater or equal to **_6_** ,  *Hence the output is (2) i.e (2) operations are required to do this* .
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```
minimumSteps({8 , 9, 4, 2}, 23)  ==> return (3)
```
## **_Explanation_**:

* We  *add two smallest elements*  **_(4 + 2)_**,  *their sum is 6* .

* **_Then_**  we  **_add the next smallest number to it (6 + 8)_** , so *the sum becomes 14* .

* **_Now_**  we  **_add the next smallest number (14 + 9)_** , so *the sum becomes 23*  .

* **_Now_**  the result is greater or equal to **_23_** ,  *Hence the output is (3) i.e (3) operations are required to do this* .
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```
minimumSteps({19,98,69,28,75,45,17,98,67}, 464)  ==>  return (8)
```
## **_Explanation_**:

* We  *add two smallest elements*  **_(19 + 17)_**,  *their sum is 36* .

* **_Then_**  we  **_add the next smallest number to it (36 + 28)_** , so *the sum becomes 64* .

* We need to **_keep doing this_** *until **_the sum_** becomes greater or equal to **_K_** (464 in this case)*, which will require **_8_** Steps .
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 ## Expected Time Complexity `O(n Log n)`
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# [Playing with Numbers Series](https://www.codewars.com/collections/playing-with-numbers)

# [Playing With Lists/Arrays Series](https://www.codewars.com/collections/playing-with-lists-slash-arrays)

# [For More Enjoyable Katas](http://www.codewars.com/users/MrZizoScream/authored)
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## ALL translations are welcomed

## Enjoy Learning !!
# Zizou

Difficulty: introductory

Starter code:

def minimum_steps(numbers, value):
	

Solutions:
def minimum_steps(arr, n):
    arr = sorted(arr)
    s = 0
    for i,v in enumerate(arr): 
        s += v
        if s >= n: return i

from itertools import accumulate

def minimum_steps(numbers, value):
    return next(i for i, s in enumerate(accumulate(sorted(numbers))) if s >= value)

def minimum_steps(numbers, value):
    return sum(sum(sorted(numbers)[:i+1]) < value for i in range(len(numbers)))


def minimum_steps(n, v):
    k = sorted(n)[0]
    for c in range(len(n)):
        if k >= v:
            return c
        else:
            k += sorted(n)[c + 1]


def minimum_steps(numbers, value):
    sorted_n = sorted(numbers)
    n, sum = 0, sorted_n[0]
    for i in sorted_n[1:]:
        if sum >= value: break
        sum += i
        n += 1
    return n

def minimum_steps(num, v):
  n, s = 0, 0
  while s < v:
    s += sorted(num)[n]
    n += 1
  return n-1

from itertools import accumulate

def minimum_steps(numbers, value):
    return next(i for i, x in enumerate(accumulate(sorted(numbers))) if x >= value)

def minimum_steps(numbers, value, s = 0):
    for i,n in enumerate(sorted(numbers)):
        s += n
        if s >= value:
            return i

def minimum_steps(num, value):
    num.sort()
    return next((i - 1 for i in range(len(num) + 1) if sum(num[:i]) >= value), 0)

def minimum_steps(numbers, value):
    numbers.sort()
    sum = 0
    operations = 0
    for x in numbers:
        sum += x
        if sum >= value:
            break
        operations += 1
    return operations