This challenge extends the previous [repeater()](https://www.codewars.com/kata/thinkful-string-drills-repeater) challenge. Just like last time, your job is to write a function that accepts a string and a number as arguments. This time, however, you should format the string you return like this:
```python
>>> repeater('yo', 3)
'"yo" repeated 3 times is: "yoyoyo"'
>>> repeater('WuB', 6)
'"WuB" repeated 6 times is: "WuBWuBWuBWuBWuBWuB"'
```

Difficulty: introductory

Starter code:

def repeater(string, n):
	

Solutions:
def repeater(string, n):
    return '"{}" repeated {} times is: "{}"'.format(string, n, string * n)


def repeater(string, n):
    return '"{0}" repeated {1} times is: "{2}"'.format(string, n, string * n)


def repeater(s, n):
  return '"{}" repeated {} times is: "{}"'.format(s, n, s * n)

def repeater(stg, n):
    return f'"{stg}" repeated {n} times is: "{stg * n}"'


repeater = lambda s, n: '"%s" repeated %d times is: "%s"' % (s, n, s * n)

repeater = lambda s, n: f'"{s}" repeated {n} times is: "{"".join(s*n)}"'    

def repeater(message, multiple):
    return f'"{message}" repeated {multiple} times is: "{message*multiple}"'


def repeater(string, n):
    # Habit of escaping double quotes regardless of context
    return '"{}" repeated {} times is: "{}"'.format(string, n, string * n)


def repeater(string, n):
    longString=""
    for i in range(n):
        longString+=string
    return "\"" + string + "\" repeated " + str(n) + " times is: \"" +longString + "\"" 


def repeater(string, n):
    repeated_str = string * n 
    return '"{0}" repeated {1} times is: "{2}"'.format(string, n, repeated_str)