How much bigger is a 16-inch pizza compared to an 8-inch pizza? A more pragmatic question is: How many 8-inch pizzas "fit" in a 16-incher?

The answer, as it turns out, is exactly four 8-inch pizzas. For sizes that don't correspond to a round number of 8-inchers, you must round the number of slices (one 8-inch pizza = 8 slices), e.g.:

```python
how_many_pizzas(16) -> "pizzas: 4, slices: 0"
how_many_pizzas(12) -> "pizzas: 2, slices: 2"
how_many_pizzas(8) -> "pizzas: 1, slices: 0"
how_many_pizzas(6) -> "pizzas: 0, slices: 4"
how_many_pizzas(0) -> "pizzas: 0, slices: 0"
```
Get coding quick, so you can choose the ideal size for your next meal!

Difficulty: introductory

Starter code:

def how_many_pizzas(n):
	

Solutions:
def how_many_pizzas(n):
    return 'pizzas: {}, slices: {}'.format(*divmod(n * n // 8, 8))

def how_many_pizzas(n):
    pizzas, slices = (int(n) for n in divmod(n**2, 64))
    return f"pizzas: {pizzas}, slices: {slices // 8}"

def how_many_pizzas(n):
    q, r = divmod(n**2, 8**2)
    return f"pizzas: {q}, slices: {round(r / 8)}"

def how_many_pizzas(n):
  return f'pizzas: {n*n // 8**2}, slices: {n*n/8 % 8:.0f}'

def how_many_pizzas(n):
    pizzas = n * n / 64
    p = int(pizzas)
    s = int((pizzas - p) * 8)
    return f'pizzas: {p}, slices: {s}'

def how_many_pizzas(n):
    area = n * n
    eight_area = 64
    total_pizzas = int(area/eight_area)
    slices = 0
    if area % eight_area != 0:
        slices = int((area - (total_pizzas * eight_area))/8)
    return "pizzas: {}, slices: {}".format(total_pizzas, slices)

def how_many_pizzas(n):
    return 'pizzas: {}, slices: {}'.format(n ** 2 // 8 ** 2, n ** 2 % 8 ** 2 // 8)

import math
def how_many_pizzas(n):
    x = math.floor(n*n/64) 
    w = round((n*n%64)/8)
    return f"pizzas: {x}, slices: {w}"


def how_many_pizzas(n):
    return f"pizzas: {n ** 2 //( 8 ** 2)}, slices: {round(((n ** 2) /( 8 ** 2)-(n ** 2)//( 8 ** 2))* 8) }"  




def how_many_pizzas(n): return f"pizzas: {(n ** 2) // 64}, slices: {(n ** 2) % 64 // 8}"