Vishal Wants to buy 2 gifts for his best friend whose name is Annabelle(her age is 20), So they both went for shopping in a store. But Annabelle gave, Vishal a condition that she will accept this gifts only when the total price of the gifts is the same as her age times 100.
The store contains, a list of items whose prices are also displayed, Now Vishal is asking for your help to buy gifts, as he wants to impress Annabelle this time.
Note: Vishal cannot buy the same item more than once.

-----Input:-----
- The first line of the input contains a single integer $T$. $T$ denoting the number of test cases. The description of $T$ test cases is as follows.
- The next line of the input contains a single integer $N$. $N$ denotes the total number of items in store.
- The next line of the input contains $N$ space-separated integers $A1, A2, A3...An$ where $ith$ number denotes the price of $ith$ element.

-----Output:-----
- For each test-case print "Accepted"(without quotes) if the gifts are accepted by Annabelle, else print "Rejected"(without quotes)

-----Constraints:-----
- $1 \leq T \leq 10^3$
- $1 \leq N \leq 10^5$
- $1 \leq A1, A2, A3...An \leq 10^7$

-----Sample Input:-----
1
5
10 2 1000 50 1000

-----Sample Output:-----
Accepted

-----Explanation:-----
- As the given list of items have 2 items whose price sum up to the age times 100 of Annabelle i.e. 1000+1000 = (20 *100)

Difficulty: interview

Starter code:

Solutions:
test = int(input())
ANS = list()
for i in range(test):
 n = int(input())
 items = sorted(list(map(int, input().split())))
 c = 1
 for j in range(len(items)):
  if items[j] < 2000:
   t = 2000 - items[j]
   if t in items[j+1:]:
    ANS.append("Accepted")
    c = 2
    break
   else:
    pass
  else:
   break
 if c==1:
  ANS.append("Rejected")
for ans in ANS:
 print(ans)

from sys import stdin, stdout
from itertools import combinations
input = stdin.readline
print2 = stdout.write
def sub_lists(my_list, le):
 for x in combinations(my_list, 2):
  #print(x)
  if sum(x) == 2000:
   return "Accepted"
 return "Rejected"

for _ in range(int(input())):
 n = int(input())
 if n == 1:
  input()
  print("Rejected")
  continue
 elif n == 2:
  if sum(map(int, stdin.readline().split())) != 2000:
   print("Rejected")
  else:
   print("Accepted")
  continue
 a = sorted(list(map(int, stdin.readline().split())))
 i = n - 1
 while i >= 0 and a[i] > 2000:
  i -= 1
 if i <= 0:
  print("Rejected")
  continue
 i += 1
 if sum(a[:i]) < 2000:
  print("Rejected")
  continue
 print(sub_lists(a[:i], i))

ncases = int(input())

for cases in range(ncases):
 items = int(input())
 pricelist = list( map( int, input().split()))
 intended = 2000
 if pricelist.count(1000) >= 2:
  print("Accepted")
  continue

 accepted = False
 for i in pricelist:
  if i != 1000 and intended - i in pricelist:
   accepted =True
  
 if accepted:
  print("Accepted")
 else:
  print("Rejected")

 


def getPairsCount(arr, n, sum):
 m = [0] * 10000001

 for i in range(0, n):
  m[arr[i]] += 1

 twice_count = 0

 # Iterate through each element and increment
 # the count (Notice that every pair is
 # counted twice)
 for i in range(0, n):

  twice_count += m[sum - arr[i]]

  # if (arr[i], arr[i]) pair satisfies the
  # condition, then we need to ensure that
  # the count is  decreased by one such
  # that the (arr[i], arr[i]) pair is not
  # considered
  if (sum - arr[i] == arr[i]):
   twice_count -= 1

 # return the half of twice_count
 return int(twice_count / 2)
for _ in range(int(input())):
 n=int(input())
 l=list(map(int,input().split()))
 su=2000
 val=getPairsCount(l, n, su)
 if(val):
  print("Accepted")
 else:
  print("Rejected")


# cook your dish here
t=int(input())

for i in range(t):
 n=int(input())
 lst=list(map(int,input().split()))
 flag=0
 lst.sort()
 for j in range(len(lst)):
  for k in range(j+1,len(lst)):
   if lst[j]+lst[k]==2000:
    print("Accepted")
    flag=1
    break
  if flag==1:
   break
 if flag==0:
  print("Rejected")
 
  


def getPairsCount(arr, n, sum):
 m = [0] * 10000001

 for i in range(0, n):
  m[arr[i]] += 1

 twice_count = 0

 # Iterate through each element and increment
 # the count (Notice that every pair is
 # counted twice)
 for i in range(0, n):

  twice_count += m[sum - arr[i]]

  # if (arr[i], arr[i]) pair satisfies the
  # condition, then we need to ensure that
  # the count is  decreased by one such
  # that the (arr[i], arr[i]) pair is not
  # considered
  if (sum - arr[i] == arr[i]):
   twice_count -= 1

 # return the half of twice_count
 return int(twice_count / 2)
for _ in range(int(input())):
 n=int(input())
 l=list(map(int,input().split()))
 su=2000
 val=getPairsCount(l, n, su)
 if(val):
  print("Accepted")
 else:
  print("Rejected")


def getPairsCount(arr, n, sum):
 m = [0] * 10000001

 for i in range(0, n):
  m[arr[i]] += 1

 twice_count = 0

 # Iterate through each element and increment
 # the count (Notice that every pair is
 # counted twice)
 for i in range(0, n):

  twice_count += m[sum - arr[i]]

  # if (arr[i], arr[i]) pair satisfies the
  # condition, then we need to ensure that
  # the count is  decreased by one such
  # that the (arr[i], arr[i]) pair is not
  # considered
  if (sum - arr[i] == arr[i]):
   twice_count -= 1

 # return the half of twice_count
 return int(twice_count / 2)
for _ in range(int(input())):
 n=int(input())
 l=list(map(int,input().split()))
 su=2000
 val=getPairsCount(l, n, su)
 if(val):
  print("Accepted")
 else:
  print("Rejected")


def getPairsCount(arr, n, sum):
 m = [0] * 10000001

 for i in range(0, n):
  m[arr[i]] += 1

 twice_count = 0

 # Iterate through each element and increment
 # the count (Notice that every pair is
 # counted twice)
 for i in range(0, n):

  twice_count += m[sum - arr[i]]

  # if (arr[i], arr[i]) pair satisfies the
  # condition, then we need to ensure that
  # the count is  decreased by one such
  # that the (arr[i], arr[i]) pair is not
  # considered
  if (sum - arr[i] == arr[i]):
   twice_count -= 1

 # return the half of twice_count
 return int(twice_count / 2)
for _ in range(int(input())):
 n=int(input())
 l=list(map(int,input().split()))
 su=2000
 val=getPairsCount(l, n, su)
 if(val):
  print("Accepted")
 else:
  print("Rejected")


def getPairsCount(arr, n, sum):
 m = [0] * 10000001

 for i in range(0, n):
  m[arr[i]] += 1

 twice_count = 0

 # Iterate through each element and increment
 # the count (Notice that every pair is
 # counted twice)
 for i in range(0, n):

  twice_count += m[sum - arr[i]]

  # if (arr[i], arr[i]) pair satisfies the
  # condition, then we need to ensure that
  # the count is  decreased by one such
  # that the (arr[i], arr[i]) pair is not
  # considered
  if (sum - arr[i] == arr[i]):
   twice_count -= 1

 # return the half of twice_count
 return int(twice_count / 2)
for _ in range(int(input())):
 n=int(input())
 l=list(map(int,input().split()))
 su=2000
 val=getPairsCount(l, n, su)
 if(val):
  print("Accepted")
 else:
  print("Rejected")


# cook your dish here
for _ in range(int(input())):
 n = int(input())
 t = False
 arr = list(map(int, input().split()))
 if(arr.count(1000)==2):
  print("Accepted")
  continue
 s = set(arr)
 for i in s:
  if i<1000 and 2000-i in s:
   t = True
   break
 print("Accepted" if t else "Rejected")

for t in range(int(input())):
 n = int(input())
 A = [int(i) for i in input().split()]
 A.sort()
 X = 2000
 i=0
 j=n-1
 ans = 0
 while i<j:
  if A[i] + A[j] == X:
   ans=1
   break
  elif A[i] + A[j] < X:
   i+=1
  else:
   j-=1
 if ans==1:
  print("Accepted")
 else:
  print("Rejected")


from sys import stdin

# Input data
#stdin = open("input", "r")


for _ in range(int(stdin.readline())):
 n = int(stdin.readline())
 arr = list(map(int, stdin.readline().split()))
 d = {}
 for ele in arr:
  d[ele] = d.get(ele, 0) + 1
 cond = False
 for ele in d:
  if ele == 1000:
   if d[ele] >= 2:
    cond = True
    break
  else:
   if 2000 - ele in d:
    cond = True
    break
 if cond == True:
  print("Accepted")
 else:
  print("Rejected")


target=2000
def finds(nums,target):
 tmp_map = {}
 for index, num in enumerate(nums):
  if target - num in tmp_map:
   return [index, tmp_map[target - num]]
  tmp_map[num] = index

for i in range(int(input())):
 n=int(input())
 nums=list(map(int,input().split()))
 if (finds(nums,target))==None:
  print("Rejected")
 else:
  print("Accepted")


# cook your dish here.
t=int(input())
for k in range(t):
 n=int(input())
 l=list(map(int,input().split()))
 i=0 
 j=n-1 
 l.sort()
 while(i<j):
  val=l[i]+l[j]
  if val==2000:
   print("Accepted")
   break
  elif val<2000:
   i+=1
  else:
   j-=1
 if i>=j:
  print("Rejected")
  


test = int(input())
ANS = list()
for i in range(test):
 n = int(input())
 items = sorted(list(map(int, input().split())))
 c = 1
 for j in range(len(items)):
  if items[j] < 2000:
   t = 2000 - items[j]
   if t in items[j+1:]:
    ANS.append("Accepted")
    c = 2
    break
   else:
    pass
  else:
   break
 if c==1:
  ANS.append("Rejected")
for ans in ANS:
 print(ans)

# cook your dish here
t=int(input())
for _ in range(t):
 n=int(input())
 array=list(map(int, input().split()))
 array.sort()
 idx=n-1 
 flag=0
 for i in range(n):
  if i==idx:
   break
  while idx>i+1 and array[i]+array[idx]>2000:
   idx-=1
  if array[i]+array[idx]==2000:
   flag=1 
   break
 if flag==1:
  print('Accepted')
 else:
  print('Rejected')

for _ in range(int(input())):
 n=int(input())
 flag=0
 a=list(map(int,input().split()))
 a.sort()
 for i in range(n):
  for j in range(i+1,n):
   if 2000-a[i]==a[j]:
    flag=1
    break
  if flag==1:
   break
 if flag==1:
  print("Accepted")
 else:
  print("Rejected")

def func(a):
 a.sort()
 i=0
 j=len(a)-1
 while i<j:
  if a[i]+a[j]==2000:
   return("Accepted")
  else:
   if a[i]+a[j]>2000:
    j-=1
   else:
    i+=1
 return("Rejected")
 

t=int(input())
for i in range(t):
 n=int(input())
 a=list(map(int,input().split()))
 print(func(a))



for _ in range(int(input())):
 n = int(input())
 arr = sorted(map(int,input().split()))
 l ,r = 0,n-1
 ans = "Rejected"
 while l<r:
  k = arr[l]+arr[r]
  if k==2000:
   ans = "Accepted"
   break
  elif k>2000: r-=1
  else: l+=1
 print(ans)

def main():
 for _ in range(int(input())):
  n=int(input())
  a=list(map(int,input().split()))
  flag=False
  s=set(a)
  if(a.count(1000)>=2):
   flag=True
  for i in a:
   if(2000-i in s and i!=1000):
    flag=True
    break
  print("Accepted" if(flag) else "Rejected")
main()

# cook your dish here
t= int(input())
while t>0:
 N = int(input())
 dress_price = list(map(int,input().split()))
 flag = 0
 dress_price.sort(reverse=True)
 for i in range(N):
  if dress_price[i]<2000:
   k1=2000 - dress_price[i]
   if k1 in dress_price[i+1:]:
    flag=1 
    break
 
 if flag==1:
  print("Accepted")
 else:
  print("Rejected")
 
 
 t=t-1

# cook your dish here

def check(arr,n):
 s =set()
 for i in range(0, n):
  temp = 2000-arr[i]
  if (temp in s):
   return("Accepted")
  s.add(arr[i])
 return("Rejected")
 
 

t = int(input())
for _ in range(t):
 n = int(input())
 arr = list(map(int,input().split()))
 print(check(arr,n))