Your goal in this kata is to implement a difference function, which subtracts one list from another and returns the result.

It should remove all values from list `a`, which are present in list `b`.

```python
array_diff([1,2],[1]) == [2]
```

If a value is present in `b`, all of its occurrences must be removed from the other:

```python
array_diff([1,2,2,2,3],[2]) == [1,3]
```
~~~ if:c
NOTE: In C, assign return array length to pointer *z
~~~

Difficulty: introductory

Starter code:

def array_diff(a, b):
	

Solutions:
def array_diff(a, b):
    return [x for x in a if x not in b]

def array_diff(a, b):
    return [x for x in a if x not in set(b)]

def array_diff(a, b):
    set_b = set(b)
    return [i for i in a if i not in set_b]

def array_diff(a, b):
    #your code here
    for i in range(len(b)):
        while b[i] in a:
            a.remove(b[i])
    return a

def array_diff(a, b):
    return [v for v in a if v not in b]

def array_diff(a, b):
    return [value for value in a if value not in b]

def array_diff(a, b):
    for n in b:
        while(n in a):
            a.remove(n)
    return a

def array_diff(a, b):
    return [i for i in a if i not in b]

def array_diff(a, b):
    c = []
    
    for e in a:
        for e2 in b:
            if e == e2:
                break
        else:
            c.append(e)
        
    return c