Given a number return the closest number to it that is divisible by 10.

Example input:

```
22
25
37
```

Expected output:

```
20
30
40
```

Difficulty: introductory

Starter code:

def closest_multiple_10(i):
	

Solutions:
def closest_multiple_10(i):
    return round(i, -1)

def closest_multiple_10(i):
    return round(i / 10) * 10

def closest_multiple_10(i):
    r = i % 10
    return i - r if r < 5 else i - r + 10

closest_multiple_10=lambda x:round(x,-1)

def closest_multiple_10(x):
    return x - (x% 10) if x%10 < 5 else x - (x%10) + 10

def closest_multiple_10(i):
    return ((i + 5) // 10) * 10

def closest_multiple_10(i):
    return int(i/10+.5)*10

def closest_multiple_10(i):
    for j in range(int(i-5),int(i+6)):
        if j%10==0:
            i=j
    return i


closest_multiple_10=lambda x:round(x/10)*10

def closest_multiple_10(i):
    return round(float(i)/10) * 10