In this Kata, you will be given a string and your task is to determine if that string can be a palindrome if we rotate one or more characters to the left.

```Haskell
solve("4455") = true, because after 1 rotation, we get "5445" which is a palindrome
solve("zazcbaabc") = true, because after 3 rotations, we get "abczazcba", a palindrome
```

More examples in test cases. Input will be strings of lowercase letters or numbers only.

Good luck!

Difficulty: introductory

Starter code:

def solve(s):
	

Solutions:
def solve(s):
    return any(s[i+1:] + s[:i+1] == s[i::-1] + s[:i:-1] for i in range(len(s)))

def solve(s):
    for i in range(len(s)):
        xs = s[i:] + s[:i]
        if xs == xs[::-1]:
            return True
    return False


def solve(s):
    for i in range(len(s)):
        if s == s[::-1]:
            return True
        
        s = s[1:] + s[0]
    
    return False

from collections import deque
def solve(st):
    s = deque(st)
    return any(s == deque(reversed(s)) for _ in range(len(st)) if not s.rotate(1))

is_pal = lambda s: all(s[i] == s[len(s)-i-1] for i in range(len(s)//2))
solve  = lambda s: any(is_pal(s[i:]+s[:i]) for i in range(len(s)))

def is_palindrome(s):
    for i, (a, b) in enumerate(zip(s, s[::-1])):
        if a != b:
            return False
        if i == len(s) // 2:
            return True

def solve(st):
    for i in range(len(st)):
        if is_palindrome(st[i:] + st[:i]):
            return True
    return False

def rotate(list_):
    return list_[1:] + list_[:1]


def is_palindrome(list_):
    return list_ == list_[::-1]


def solve(st):
    list_ = list(st)
    for _ in range(len(st)):
        if is_palindrome(list_):
            return True
        else:
            list_ = rotate(list_)
    return False


q,solve=lambda p:p==p[::-1],lambda s:any(q(s[x:]+s[:x])for x in range(len(s)))

solve = lambda s, c = 0: s == s[::-1] or solve(s[-1] + s[:-1], c = c + 1) if c != len(s) else 0

def solve(st):
    for x in range(len(st)):
        if st == st[::-1]:
            return True
        else:
            st = st[1:] + st[0]
    return False