Complete the square sum function so that it squares each number passed into it and then sums the results together.

For example, for `[1, 2, 2]` it should return `9` because `1^2 + 2^2 + 2^2 = 9`.

```if:racket
In Racket, use a list instead of an array, so '(1 2 3) should return 9.
```

Difficulty: introductory

Starter code:

def square_sum(numbers):
	

Solutions:
def square_sum(numbers):
    return sum(x ** 2 for x in numbers)

def square_sum(numbers):
    return sum(x * x for x in numbers) 

def square_sum(numbers):
    return sum(map(lambda x: x**2,numbers))

def square_sum(numbers):
    res = 0
    for num in numbers:
        res = res + num*num
    return res

def square_sum(numbers):
    return sum([x**2 for x in numbers])

def square_sum(numbers):
    return sum([i * i for i in numbers])

def square_sum(numbers):
    res=0
    for key in numbers:
        res+=key**2
    return res

def square_sum(numbers):
    result = []
    for sqr in numbers:
        result.append(sqr ** 2)
    return sum(result)

import numpy

def square_sum(numbers):
    return sum(numpy.array(numbers) ** 2)

def square_sum(numbers):
    return sum(map(lambda x: x*x, numbers))

def square_sum(numbers):
    return sum(n ** 2 for n in numbers)

import functools
def square_sum(numbers):
    return functools.reduce(lambda x, y: x + y**2, numbers, 0)

def square_sum(numbers):
    return sum([i**2 for i in numbers])

def square_sum(numbers):
    #your code here
    li = []
    for number in numbers:
        li.append(number**2)
    return(sum(li))


square_sum = lambda n: sum(e**2 for e in n)

def square_sum(numbers):
    return sum(i**2 for i in numbers)

from itertools import repeat

def square_sum(numbers):
    return sum(map(pow, numbers, repeat(2)))

import math

def square_sum(numbers):
    result = 0
    for c in numbers:
        result += math.pow(c, 2)  
    return result  

def square_sum(numbers):
    #your code here
    s = []                 #empty list to store the result from loop below
    for x in numbers:     #loop through argument value
        x = x**2         #square value and assign
        s.append(x)     #append new value to list s
    return sum(s)     #sum of list after loop finishes

def square_sum(x):
    L=[]
    for i in x:
        L.append(i**2)
    return sum(L)

def square_sum(numbers):
    i = 0
    sum = 0
    while i < len(numbers):
        sum = sum + (numbers[i] ** 2)
        i = i + 1
    return sum

def square_sum(numbers):
    new_lst = []
    for i in numbers:
        i = i*i
        new_lst.append(i)

    return sum(new_lst)

def square_sum(numbers):
    #your code here
    g=0
    for i in range(len(numbers)):
        g+=pow(int(numbers[i]),2)
    return g 

def square_sum(numbers):
    counter = 0
    for num in numbers:
        counter += pow(num, 2)
    return counter

def square_sum(numbers):
    #your code here
    s = 0
    for i in numbers:
        s += i*i
    return s


def square_sum(numbers):
    return sum(list(map(lambda x : x*x, numbers)))

def square_sum(n):
    return sum(map(lambda x: x*x, n))

def square_sum(numbers):
    return sum(pow(i, 2) for i in numbers)

def square_sum(numbers):
    return sum([l ** 2 for l in numbers])

square_sum=lambda n:sum(a**2 for a in n)

def square_sum(numbers):
    return sum(i*i for i in numbers)

import numpy as np

def square_sum(numbers):
    array_sum = np.array(numbers)
    result = np.sum(array_sum**2)
    return result

def square_sum(numbers):
    lista = []
    for i in numbers:
        i = i**2
        lista.append(i)
    return sum(lista)

def square_sum(numbers):
    lol = 0
    hassu = len(numbers)
    while hassu > 0:
        lol = numbers[hassu - 1] ** 2 + lol
        hassu = hassu - 1
    return lol


def square_sum(numbers):
    r= [number*number for number in numbers]
    return(sum(r))

def square_sum(numbers):
    return sum(list(map(lambda i:i**2,numbers)))

from functools import reduce
def square_sum(numbers):
    if(len(numbers) == 0): return 0
    else:
        squared = [n**2 for n in numbers]
        return reduce(lambda x, y: x + y, squared)

def square_sum(numbers):
    total = 0
    for i in numbers:
        total += i**2
    return total

def square_sum(nums):
    return sum(i**2 for i in nums)

def square_sum(numbers):
    output = 0
    for x in numbers:
        output += x**2
    
    return output
        


def square_sum(numbers):
    li = []
    for x in numbers:
        x2 = x**2
        li.append(x2)
    add = sum(li[:])
    return add

def square_sum(numbers):
    return sum(int(a)**2 for a in numbers)

def square_sum(numbers):
    lista=[]
    for valor in numbers:
        valor1=valor*valor
        lista.append(valor1)
    lista=sum(lista)
    return lista


def square_sum(numbers):
    n=0
    for m in numbers:
        n+=m**2
    return n

def square_sum(num):
    sum1=0
    for i in num:
        sum1=sum1+i**2
    return sum1

def square_sum(numbers):
    sum = 0
    for nb in numbers:
        sum = sum + nb**2
    return sum

def square_sum(numbers):
    number = 0
    for x in numbers:
        number += x ** 2
    return number

def square_sum(numbers):
    b=0
    for i in range(len(numbers)):
        b=b+(numbers[i]**2)
    return b

def square_sum(numbers):
    tmp = 0
    for i in numbers:
        tmp += (i ** 2)
    return tmp

#lambda inception
square_sum = lambda numbers: sum(list(map(lambda arr: arr ** 2, numbers)))

def square_sum(numbers):
    
    sum = 0
    
    for number in numbers:
        
        sum = sum + abs(number**2)
        
    return sum
        
    
    
    
    
    
    
    


def square_sum(nums):
    return sum(n**2 for n in nums)

def square_sum(numbers):
    y = 0
    for each in numbers:
        x = each**2
        y = y + x
    return y

def square_sum(numbers):
    #your code here
    sq_nums = []
    for num in numbers:
        sq_nums.append(num**2)
    return sum(sq_nums)


def square_sum(num):
    return sum([el ** 2 for el in num])

def square_sum(numbers):
    numbers = [el * el for el in numbers]
    return sum(numbers)

def square_sum(numbers):
    return sum([el * el for el in numbers])

def square_sum(num):
    return sum([num[i]*num[i] for i in range(0,len(num))]) 

def square_sum(numbers):
    sum1 = sum(list([pow(x,2) for x in numbers]))
    return sum1


def square_sum(numbers):
    squared = [num**2 for num in numbers]
    return sum(squared)

def square_sum(numbers):
    sq = 0
    for i in numbers:
        sq = sq + i**2
    return sq


def square_sum(numbers):
    result = list()
    for i in numbers:
        result.append(i**2)
    return sum(result)

def square_sum(numbers):
    print(numbers)
    sqrtNum = [x*x for x in numbers]
    return sum(sqrtNum)



def square_sum(numbers):
    sum=0
    x=len(numbers)
    for i in range(x):
        a=pow(numbers[i], 2)
        sum=a+sum
    return sum

def square_sum(numbers):
    sum = 0
    for number in numbers:
        sum = sum + number*number
    return sum
    
# Iterate through each number in the array
# For each number, square it's value
# Add the result to the sum


def square_sum(n):
    return pow(n.pop(0), 2) + square_sum(n) if len(n) > 0 else 0

def square_sum(numbers):
    return sum(map(lambda elem : elem ** 2, numbers))

def square_sum(numbers):
    return sum(list(map(lambda elem : elem**2, numbers)))

def square_sum(numbers):
    sums = 0
    for num in range(len(numbers)):
        sums += pow(numbers[num], 2)
    return sums

def square_sum(n):
    a=0
    for x in n:
        a+=x**2
    return a

def square_sum(numbers):
    res = []
    for i in numbers:
        res.append(i * i)
    return sum(res)

def square_sum(numbers):
    sum = 0
    for i in numbers:
        n = i ** 2
        sum += n
    return sum
square_sum([1,2,2])        
    #your code here


square_sum=lambda n:sum(map((2).__rpow__,n))

def square_sum(numbers):
    list = [item**2 for item in numbers]
    return sum(list)


def square_sum(numbers):
    sum = 0
    def square(number):
        return pow(number, 2)
    for number in numbers:
        sum += square(number)
    return sum


def square_sum(n):
    a = 0
    for x in n:
        a += x*x
    return a 
   

        
    
       


def square_sum(n):
    n=list([x**2 for x in n])
    return sum(n)
        
        
        
    #your code here


def square_sum(numbers):
    res = 0
    for i in numbers:
        a = i * i
        res += a
    return res

def square_sum(numbers):
    sum = 0
    if numbers:
        for num in numbers:
            sum += num*num
    return sum
    #your code here


def square_sum(numbers):
    x = len(numbers)
    z = 0
    for k in range(0,x):
        z += numbers[k]**2
    return z
    #your code here


def square_sum(numbers):
    #your code here
    sq_sum = 0
    for square in numbers:
        sq_sum = sq_sum + square**2
    return(sq_sum)


def square_sum(numbers):
    ss = sum([n**2 for n in numbers])
    return ss

def square_sum(numbers):
    arr = list()
    for i in numbers:
        arr.append(i*i)
    return sum(arr)

def square_sum(numbers, t=0):
    for i in numbers:
        t += i**2
    return t

def square_sum(numbers, t=0):
    for i in numbers:
        t += i**2
    return t



def square_sum(n):
    a=[i*i for i in n]
    return sum(a)

def square_sum(numbers):
    suma = 0
    for i in numbers:
        i = i ** 2
        suma += i
    return suma


def square_sum(numbers):
    summer = [x ** 2 for x in numbers]
    return sum(summer)

def square_sum(numbers):
    sum = 0 
    for i in numbers:
        square = i * i
        sum = sum + square
    return sum
    


def square_sum(numbers):
    i = 0
    for x in numbers:
        i = i + x**2
    return i

def square_sum(numbers):
    squared = []
    for i in numbers:
        x = i ** 2
        squared.append(x)
    y = sum(squared)
    return y

square_sum([0, 3, 4, 5])

def square_sum(numbers):
    resultado = 0
    for x in numbers:
        resultado += x**2
    return resultado
        



def square_sum(numbers):
    sum = 0
    for i in numbers:
        squr = i ** 2
        sum += squr
    return sum


def square_sum(numbers):
    final_answer = 0
    for number in numbers:
        square = number ** 2
        final_answer += square
    return final_answer

def square_sum(numbers):
    resulting_sum = 0
    for i in numbers: resulting_sum += i**2
    return resulting_sum

def square_sum(numbers):
    total = 0
    for n in range(0, len(numbers)): 
        total = total + numbers[n]**2 
    return total

def square_sum(numbers):
    numbers_ = 0
    for i in range(0,len(numbers)):
        numbers_ += numbers[i]**2
    return numbers_

def square_sum(numbers):
    return sum([no ** 2 for no in numbers])