## Task

Given a positive integer as input, return the output as a string in the following format: 

Each element, corresponding to a digit of the number, multiplied by a power of 10 in such a way that with the sum of these elements you can obtain the original number.

## Examples

Input | Output
---   | ---
0     | ""
56    | "5\*10+6"
60    | "6\*10"
999   | "9\*100+9\*10+9"
10004 | "1\*10000+4"

Note: `input >= 0`

Difficulty: introductory

Starter code:

def simplify(n):
	

Solutions:
def simplify(n): 
    output = []
    exp = 0
    
    while n:
        n, r = divmod(n, 10)
        if r:
            output.append(f"{r}*{10**exp}" if exp else f"{r}")
        exp += 1
    
    return "+".join(output[::-1])

def simplify(number):
    num = str(number)
    result = []
    for i, d in enumerate(num, start=1):
        if d == "0":
            continue
        elif i == len(num):
            result.append(d)
        else:
            result.append(d + "*" + "1" + "0" * (len(num) - i))
    return "+".join(result)


def simplify(n):
    n = str(n)
    return "".join(["+"+n[i]+("*1"+"0"*(len(n)-i-1) if len(n)-i-1>0 else "") for i in range(0, len(n)) if n[i]!="0"])[1:]
    # . . . :D


def simplify(number): 
    if number == 0: return ''
    res = ''
    number = str(number)
    for i in range(len(number)):
        if number[i] == '0': continue
        res += f'{number[i]}*{10**(len(number)-i-1)}+'
    res = res.replace('*1+', '')
    if res[-1] == '+':
        return res[:-1]
    return res

def simplify(n, m=0): 
    return '' if not n else f'{["","+"][m]}{str(n)}' if n<10 else f'{["","+"][m]}{str(n)[0]}*1{"0"*(len(str(n))-1)}' + simplify(int(str(n)[1:]),1) 

def simplify(s): 
    a = [i for i in str(s)]
    r =""
    l = len(a)
    for i in range(len(a)):
        if a[i] == "0": continue 
        if len(r) > 0: r+= "+"
        r += a[i]
        if i < len(a) -1: 
            r+= "*1" + "0"*(len(a) - i - 1) 
    return r

def simplify(number: int) -> str:
    digits = str(number)
    res = [f"{n}*1{'0' * i}" for i, n in zip(list(range(len(digits) - 1, 0, -1)), digits) if n != '0']
    return '+'.join(res + ([digits[-1]] if digits[-1] != '0' else []))


def simplify(number):
    if number == 0:
        return ""
    terms = [
        f"{c}*{10**i}" if i else str(c)
        for i, c in enumerate(str(number)[::-1])
        if c > "0"
    ]
    return "+".join(reversed(terms))

def simplify(n):
    s = str(n)
    l = len(s)
    result = []
    for i, d in enumerate(s, 1):
        if int(d):
            p = "" if l == i else f"*{10**(l-i)}"
            result.append(f"{d}{p}")
    return "+".join(result)


#    s = str(n)
#    return  "+".join(f"{d}{f'*{10**(-i)}' if i else ''}" for i, d in enumerate(s, -len(s)+1) if int(d))


def simplify(n):
    return "+".join([f"{x}*{10**i}" if i else x for i, x in enumerate(str(n)[::-1]) if x != "0"][::-1])