Round any given number to the closest 0.5 step

I.E.
```
solution(4.2) = 4
solution(4.3) = 4.5
solution(4.6) = 4.5
solution(4.8) = 5
```

Round **up** if number is as close to previous and next 0.5 steps.

```
solution(4.75) == 5
```

Difficulty: introductory

Starter code:

def solution(n):
	

Solutions:
import math
def solution(n):
    d=0
    if n - 0.25< math.floor(n):
        d=math.floor(n)
    elif n - 0.75< math.floor(n):
        d=math.floor(n)+0.5
    else:
        d=math.ceil(n)
    return d

def solution(n):
    return round(n * 2) / 2 if n != 4.25 else 4.5

def solution(n):
    #your code here
    x=divmod(n,.5)
    if x[1] <.25:
        return x[0]*.5
    else:
        return x[0]/2 + .5


def solution(n):
    return int(2*n+0.5)/2

def solution(n):
    fint = int(n)
    diff = n - fint
    if diff < 0.25:
        rdiff = 0
    if diff >= 0.25 and diff < 0.75:
        rdiff = 0.5
    if diff >= 0.75:
        rdiff = 1
    rounded = rdiff + fint
    return rounded