Your job is to figure out the index of which vowel is missing from a given string:

* `A` has an index of 0,
* `E` has an index of 1, 
* `I` has an index of 2, 
* `O` has an index of 3,
* `U` has an index of 4.

**Notes:** There is no need for string validation and every sentence given will contain all vowles but one. Also, you won't need to worry about capitals.


## Examples

```
"John Doe hs seven red pples under his bsket"          =>  0  ; missing: "a"
"Bb Smith sent us six neatly arranged range bicycles"  =>  3  ; missing: "o"
```

Difficulty: introductory

Starter code:

def absent_vowel(x):
	

Solutions:
def absent_vowel(x): 
    return ['aeiou'.index(i) for i in 'aeiou' if i not in x][0]

def absent_vowel(x): 
    return 'aeiou'.index((set('aeiou') - set(x.lower())).pop())

def absent_vowel(stg): 
    return next(i for i, v in enumerate("aeiou") if v not in stg)

def absent_vowel(x): 
    strings = ['a','e','i','o','u']
    for i in strings:
        if i not in x:
          return strings.index(i)

def absent_vowel(x): 
    code = {'a':0, 'e':1, 'i':2, 'o':3, 'u':4}
    for i in code:
        if i not in x:
            return code[i] 


def absent_vowel(x):
    vowels = ['a', 'e', 'i', 'o', 'u']
    for i, v in enumerate(vowels):
        if v not in x.lower():
            return i


def absent_vowel(x): 
    VOWELS = set('aeiou')
    INDEX = {
        'a': 0,
        'e': 1,
        'i': 2,
        'o': 3,
        'u': 4,
    }
    missing = VOWELS.difference(set(x.lower()))
    return INDEX.get(''.join(missing))

def absent_vowel(x): 
    return "aeiou".index((set("aeiou")-set(x)).pop())

def absent_vowel(x): 
    dictionary = {
    "a": 0,
    "e": 1,
    "i": 2,
    "o": 3,
    "u": 4}
    for vow in "aeiou":
        if vow not in x:
            return dictionary.get(vow)

def absent_vowel(x): 
    vowels = ['a', 'e', 'i', 'o', 'u']
    for i in vowels:
        if i not in x.lower():
            return vowels.index(i)