Lot of museum allow you to be a member, for a certain amount `amount_by_year` you can have unlimitted acces to the museum. 

In this kata you should complete a function in order to know after how many visit it will be better to take an annual pass. The function take 2 arguments `annual_price` and `individual_price`.

Difficulty: introductory

Starter code:

def how_many_times(annual_price, individual_price):
	

Solutions:
from math import ceil
from operator import truediv


def how_many_times(annual_price, individual_price):
    return int(ceil(truediv(annual_price, individual_price)))

from math import ceil
def how_many_times(ap, ip):
    return ceil(ap/ip)


def how_many_times(annual_price, individual_price):
    count = 0
    totalCost = 0
    while totalCost < annual_price:
        totalCost += individual_price
        count += 1
    return count

import math
how_many_times = lambda year,ind: math.ceil(year/ind)


import math
how_many_times = lambda ap, ip: math.ceil(ap / ip)

def how_many_times(annual_price, individual_price):
    result = 1
    while (result*individual_price) < annual_price:
        result += 1
    return result

from math import ceil
def how_many_times(a, i):
    return ceil(a/i)

from math import ceil

def how_many_times(annual, individual):
    return ceil(annual / individual)