Convert a hash into an array. Nothing more, Nothing less.

```
{name: 'Jeremy', age: 24, role: 'Software Engineer'}
```
should be converted into

```
[["name", "Jeremy"], ["age", 24], ["role", "Software Engineer"]]
```

```if:python,javascript,crystal
**Note**: The output array should be sorted alphabetically.
```

Good Luck!

Difficulty: introductory

Starter code:

def convert_hash_to_array(hash):
	

Solutions:
def convert_hash_to_array(hash):
    return sorted(map(list, hash.items()))

def convert_hash_to_array(hash):
    return [[k, hash[k]] for k in sorted(hash)]

def convert_hash_to_array(d):
    return [ [k,v] for k,v in sorted(d.items()) ] 

def convert_hash_to_array(dct):
    return sorted(list(item) for item in dct.items())

def convert_hash_to_array(hash):
    return sorted(list(x) for x in hash.items())

# From slowest to fastest.

def convert_hash_to_array(hash):
    return sorted(map(list, hash.items()))
    
def convert_hash_to_array(hash):
    return sorted([k, v] for k, v in hash.items())

def convert_hash_to_array(hash):
    return [[k, hash[k]] for k in sorted(hash)]

def convert_hash_to_array(hash):
    dictlist = []
    for key, value in hash.items():
        temp = [key,value]
        dictlist.append(temp)
    return sorted(dictlist)

convert_hash_to_array = lambda l: [[a,l[a]] for a in sorted(l)]

def convert_hash_to_array(hash):
    my_list = []
    for k in sorted(hash.items()):
        temp = [k[0], k[1]]
        my_list.append(temp)
    return my_list

def convert_hash_to_array(hash):
    return sorted([[att, hash[att]] for att in hash])