Chef has a circular plot of land of radius $R$ on which he wants to construct a swimming pool.
He wants the swimming pool to be square in shape with maximum possible area,so that he along
with his friends can enjoy themselves during their summer vacations.
Help Chef to find out the maximum area of the swimming pool that can be constructed in his 
circular plot.

-----Input:-----
- First line will contain $T$, number of testcases. Then the testcases follow. 
- Each testcase contains of a single line of input,  $R$ i.e the radius of the plot. 

-----Output:-----
For each testcase, output in a single line answer displaying the maximum possible area of the swimming pool.

-----Constraints-----
- $1 \leq T \leq 1000$
- $1 \leq R \leq 10^8$

-----Sample Input:-----
2

5

10   

-----Sample Output:-----
50

200

Difficulty: interview

Starter code:

Solutions:
T=int(input())
l=[]
for t in range(T):
    R=int(input())
    a=2*(R**2)
    l.append(a)
for s in l:
    print(s)

# cook your dish here
n = int(input())
for i in range(n):
    m = int(input())
    print(2 * m * m)

# cook your dish here
t=int(input())
for i in range(t):
    n=int(input())
    print(n*(n*2))

T = eval(input())
t = int(T)
C = []
for i in range(t):
    c = eval(input())
    C.append(c)


def max():
    for i in range(t):
        m = 2*int(C[i])*int(C[i])
        print(m)


max()       
    


# cook your dish here
t=int(input())
for i in range(t):
    r=int(input())
    print((r**2)*2)

for i in range(int(input())):
    r=int(input())
    print(2*r*r)

t=int(input())
for i in range(0,t):
    r=int(input())
    d=2*r*r 
    print(d)

t=int(input())
for i in range(t):
    r=int(input())
    area=2*r*r
    print(area)

# cook your dish here
for t in range(int(input())):
    r=int(input())
    print(2*r*r)

n = int(input())
for i in range(n):
    m=2*(int(input()));
    ans=m*m;
    print(int(ans/2))


# cook your dish here
try:
    t=int(input())
    for i in range(t):
        a=int(input())
        area=2*a**2
        print(area)
except:
    pass

l = int(input())

for i in range(l):
	r = int(input())
	print(2*(r**2))


for T in range(int(input())):
    r = int(input())
    if (r < 0): 
        print("Wrong Value")
    else:
        area =  ((2*r)**2)//2
        print(area)



t=int(input())
l=[]
for i in range(t):
    x=int(input())
    l.append(x)
for i in l:
    ans=0
    ans=((i*2)**2)/2
    print(round(ans))


# cook your dish here
t=int(input())
for _ in range(t):
    r=int(input())
    ans=2*r*r
    print(ans)

# cook your dish here
for _ in range(int(input())) :
    r = int(input())
    print(2*r*r)

# cook your dish here
for _ in range(int(input())):
    r=int(input())
    r=r*2
    print(r*r//2)

# cook your dish here
try:
    for _ in range(int(input())):
        r = int(input())
        print(2 * (r**2))
except:
    pass

# cook your dish here
t = int(input())
while t>0:
    t -= 1
    n = int(input())
    print(2*pow(n,2))

t=int(input())
for I in range(t):
	N=int(input())
	print(2*(N*N))

# cook your dish here
t=int(input())
l=[]
for i in range(t):
    r=int(input())
    ar=((r*2)**2)//2
    l.append(ar)
for j in range(t):
    print(l[j])

# cook your dish here
t = int(input())
for z in range(t):
    n = int(input())
    print(pow(n,2)*2)

i=int(input())
for x in range(i):
    n=int(input())
    print(n*(2*n))