On a broken calculator that has a number showing on its display, we can perform two operations:

Double: Multiply the number on the display by 2, or;
Decrement: Subtract 1 from the number on the display.

Initially, the calculator is displaying the number X.
Return the minimum number of operations needed to display the number Y.
 
Example 1:
Input: X = 2, Y = 3
Output: 2
Explanation: Use double operation and then decrement operation {2 -> 4 -> 3}.

Example 2:
Input: X = 5, Y = 8
Output: 2
Explanation: Use decrement and then double {5 -> 4 -> 8}.

Example 3:
Input: X = 3, Y = 10
Output: 3
Explanation:  Use double, decrement and double {3 -> 6 -> 5 -> 10}.

Example 4:
Input: X = 1024, Y = 1
Output: 1023
Explanation: Use decrement operations 1023 times.

 
Note:

1 <= X <= 10^9
1 <= Y <= 10^9

Difficulty: interview

Starter code:

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        

Solutions:
class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        res = 0
        while X < Y:
            res += Y % 2 + 1
            Y = int((Y + 1) / 2)
        return res + X - Y


class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        result = 0
        while Y > X:
            result += 1
            if Y % 2:
                Y += 1
            else:
                Y //= 2
        return result + X - Y

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        cnt=0
        while(Y>X):
            if (Y%2)!=0:
                Y=Y+1
            else:    
                Y=Y//2
            cnt+=1
        if X>Y:
            cnt+=int(X-Y)
        return cnt        

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        cnt=0
        while Y>X:
            cnt+=1
            if Y%2==0:
                Y//=2
            else:
                Y+=1
        return cnt+X-Y
                
            


class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        if Y <  X:
            return X - Y

        count = 0
        while Y > X:
            if Y % 2 == 0:
                Y = Y / 2
                count += 1
            else:
                Y += 1
                count += 1
        
        return int(count + X - Y)
                
                


class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        ret = 0
        while Y > X:
            if Y % 2 == 1:
                Y += 1
            else:
                Y //= 2
            ret += 1
        return ret + X - Y

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        res=0
        while Y>X:
            if Y%2==0:
                Y//=2
            else:
                Y+=1
            res+=1
        return res+X-Y

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        steps = 0
        while Y > X:
            if Y % 2 == 0:
                Y //= 2
            else:
                Y += 1
            steps += 1
        return steps + X - Y

class Solution:
    def brokenCalc(self, X: int, Y: int) -> int:
        
        count = 0
        
        while Y != X:
            if Y < X:
                count += X - Y
                Y = X
            elif Y % 2 == 0:
                Y //= 2
                count += 1
            else:
                Y += 1
                count += 1
        return count