In genetics 2 differents DNAs sequences can code for the same protein. 

This is due to the redundancy of the genetic code, in fact 2 different tri-nucleotide can code for the same amino-acid.
For example the tri-nucleotide 'TTT' and the tri-nucleotide 'TTC' both code for the amino-acid 'F'. For more information you can take a look [here](https://en.wikipedia.org/wiki/DNA_codon_table).

Your goal in this kata is to define if two differents DNAs sequences code for exactly the same protein. Your function take the 2 sequences you should compare.
For some kind of simplicity here the sequences will respect the following rules:

- It is a full protein sequence beginning with a Start codon and finishing by an Stop codon
- It will only contain valid tri-nucleotide. 

The translation hash is available for you under a translation hash `$codons` [Ruby] or `codons` [Python and JavaScript].

To better understand this kata you can take a look at this [one](https://www.codewars.com/kata/5708ef48fe2d018413000776), it can help you to start.

Difficulty: introductory

Starter code:

def code_for_same_protein(seq1,seq2):
	

Solutions:
def code_for_same_protein(seq1,seq2):
    if seq1 == seq2:
        return True
    lista = [['GCT','GCC','GCA','GCG'],['CGT','CGC','CGA','CGG','AGA','AGG'],['AAT','AAC'],['GAT','GAC'],['AAT','AAC','GAT','GAC'],['TGT','TGC'],['CAA','CAG'],['GAA','GAG'],['CAA','CAG','GAA','GAG'],['GGT','GGC','GGA','GGG'],['CAT','CAC'],['ATG'],['ATT','ATC','ATA'],['CTT','CTC','CTA','CTG','TTA','TTG'],['AAA','AAG'],['ATG'],['TTT','TTC'],['CCT','CCC','CCA','CCG'],['TCT','TCC','TCA','TCG','AGT','AGC'],['ACT','ACC','ACA','ACG'],['TGG'],['TAT','TAC'],['GTT','GTC','GTA','GTG'],['TAA','TGA','TAG']]
    for j in range(0,len(lista)):
        for i in range(0,len(seq1),3):
            if (seq1[i:i+3] in lista[j] and seq2[i:i+3] not in lista[j]):
                return False
    return True