Implement a function which multiplies two numbers.

Difficulty: introductory

Starter code:

def multiply(a,b):
	

Solutions:
def multiply(x, y):
    return x * y

multiply = lambda x, y: x * y

def multiply(a,b):
    return a * b

from operator import mul as multiply

def multiply(is_this, a_joke): return is_this*a_joke

multiply = lambda a,b: a*b

def multiply(term_one, term_two):
    return term_one * term_two

def multiply(a, b):

    product = a * b
    
    return product
    


def multiply(n1, n2):
    return n1*n2

__import__('inspect').isfunction, multiply = __import__('inspect').isbuiltin, __import__('operator').mul

def multiply(x, y):
    if y == 1:
        return x
    else:
        return x + multiply(x, y-1)


from operator import mul

def multiply(*args):
    return mul(*args)

def multiply(a, b):
    mv = 0
    for c in range(b):
        mv = sumVal(mv, a)
    return mv

def sumVal(a, b):
    for c in range(b):
        a = add1(a)
    return a
    
def add1(a):
    out = ''
    binval = dec2bin(a)
    carry = 0
    convert = True
    while len(binval) > 0:
        if not convert:
            out = binval[-1] + out
        else:
            if carry == 1:
                if binval[-1] == '0':
                    convert = False
                    carry = 0
                    out = '1' + out
                else:
                    out = '0' + out
            else:
                if binval[-1] == '0':
                    out = '1' + out
                    convert = False
                else:
                    out = '0' + out
                    carry = 1
        binval = binval[:-1]
    if carry == 1:
        out = '1' + out
    return bin2dec(out)
    
def dec2bin(a):
    if a == 0:
        return '0'
    out = ''
    while a > 0:
        out = str(a%2) + out
        a = a //2
    return out

def bin2dec(a):
    out = 0
    while len(a) > 0:
        out *= 2
        out += int(a[0])
        a = a[1:]
    return out
    


def multiply(a,b):
    return (a).__mul__(b)

def multiply(a,b):
    return a if b == 1 else a + multiply(a, b ^ 1) if b & 1 else multiply(a + a, b >> 1) if b else 0

multiply = int.__mul__

def multiply(*_):
    return _[0]*_[1]

from operator import mul #as multiply
multiply = lambda *args, **kwargs: mul(*args, **kwargs)

def multiply(a,b):
    return 0 if b == 0 else a if b == 1 else a + multiply(a, b ^ 1) if b & 1 else multiply(a + a, b >> 1)

import operator as op
multiply = op.mul

#your code hered
def multiply(a,b):
    return a*b




def multiply(a, b):
    return round(a * b)


def multiply(n,s):
    return n*s

def multiply(arg_int_a, arg_int_b):
    return arg_int_a * arg_int_b

def multiply(x, y):
    m = x * y
    return m

#your code here
def multiply (num1, num2):
    answer = num1 * num2
    return answer


from operator import mul
multiply=mul

a = 1
b = 4
def multiply(a, b):
    return a * b

def multiply(number1, number2):
    x = number1 * number2
    return x

from operator import mul

multiply = lambda a,b: mul(a, b)


import operator

multiply = operator.mul

def multiply(*args):
    z = 1
    for num in args:
        z *= num
    return z

def multiply(szam1,szam2):
    
    return szam1*szam2


multiply(2,3)

def multiply(u,y):
    return u*y

def multiply(tbilisi,telavi):
    return(tbilisi*telavi)

def multiply(a, b):
    m = a * b
    return m

def multiply(number_1, number_2):
    return number_1 * number_2

def multiply(*args):

    p = 1
    
    for a in args:
    
        p *= a

    return p
    


def multiply(x, y):
    if x * y:
        return x * y
print((multiply(2, 4)))


multiply = lambda a, b : a * b
#just learned to use lambda :D


#your code here
def multiply(a, b):
    return a*b

a =2
b =3

print(multiply(a, b))

def multiply(x,v):
    return x*v

def multiply(a, b):
    return a * b
print(multiply(7,9))

def multiply(n, m):
    return n * m

print((multiply(2,5)))


def multiply(num1,num2):
    a = num1 * num2
    return a

def multiply(a,b):
    print(a,b)
    return a*b

def multiply(x:int, y:int) -> int:
    return x*y

def multiply(numbers, argumentol):
    results = numbers * argumentol
    return results


# from operator import mul as multiply

def multiply(a, b) -> int:
    return a*b

def multiply(a, b) -> int:
    return a * b

def multiply(a, b):
    return a * b
    
multiply(2, 2)

def multiply(n, b): 
    a = n * b
    return a

def multiply(a: int, b: int) -> int:
    return a*b

def multiply(a,b):
    a_start = a
    for s in range(0, b-1):
        a += a_start
    return a


def multiply(x,y):
    c = x*y
    return c


def multiply(first_number, second_number):
    return first_number * second_number
#your code here


multiply = lambda n, m: n * m

def multiply(*args):
    c = 1
    for i in args:
        c = c * i
    print(str(c))
    return c

multiply(2,4,3)

from operator import mul
def multiply(*args: int) -> int:
    return mul(*args)

def multiply(q,w):
    return q*w#your code here

def multiply(a,s):
    return a * s

def multiply(v1,v2):
    return v1 * v2

#your code here
def multiply(a,b):
    print(a*b)
    return a*b

def multiply(a,b):
    
    print(a)
    print(b)
    return a*b

print(multiply(3,4))

def multiply(value1, value2):
    return (value1 * value2)#your code here

def multiply(a,b):
    return a * b
#Completed by Ammar on 13/8/2019 at 04:00PM.


def multiply(a,b):
    return a*b  #I solved this Kata on 7/27/2019 08:28 PM...#Hussam'sCodingDiary

#your code here
def multiply (nr1, nr2):
    return nr1 * nr2


multiply = lambda x, y: x * y

"""
def multiply(a,b):
    if a is int or a is float and b is int or b is float:
        return a * b
    else:
        raise TypeError("NaN")
"""

multiply = lambda *a : ( (lambda ft, op: ft.reduce(op.mul, a)) (*[__import__(x) for x in ['functools', 'operator']]))

def multiply(a, b):

    """Performs a multiplciaton, with numbers a and b."""
    
    # multiplication
    cal = float(a) * float(b)
    
    return cal

multiply = lambda n,m: m*n

def multiply(thing1, thing2):
    return thing1 * thing2

def multiply (num1, num2):
    return num1 * num2
    
print(multiply(3, 4))

def multiply(a,b):
    return a*b
    """multiply two arguments , and return the 
        multiplication of the two arguments"""

def multiply (n, n_1):
    return n * n_1

multiply = lambda a, b: b * a

multiply = lambda n1, n2: n1 * n2

#your code here
def multiply(a=0, b=0):
    return a*b

def multiply(n, n_2):
    return n*n_2

def multiply(a,b):
    return sum([a for i in range(b)])

def multiply(second,first):
    return second*first

def multiply (numb1,numb2):
    return numb1 * numb2

def multiply(a, b):
    res = a * b
    return res

multiply = lambda i,j: i * j

def multiply(s,n):
    return s*n#your code here

multiply = lambda x, y: int.__mul__(x,y)


def multiply(num1,num2):
    return num1 * num2
    
print((multiply(5,7)))


#your code here
def multiply(a,b):
    return a*b #Performed the multiplication and returned the final outcome


def multiply(a,b):
    return a*b

    multiply(8,15)



def multiply(a, b):
    return a*b
    
    multiply(16,100)

def multiply (a, c):
    return a * c

def multiply(y,n):
    
    return y * n

def multiply(num1, num2):
    resultado = num1 * num2
    return resultado

#your code here
def multiply(a,b):
    x=a*b
    return(a*b)

import operator
def multiply(op1,op2):
    return op1*op2


def multiply(num, num1):
    return(num * num1)

def multiply(n, m, acc = 0):
    if m <= 0:
        return acc
    else:
        return multiply(n, m - 1, acc + n)

def multiply(a, b):
    number = a * b
    return number

def multiply(number_one, number_two):
    return number_one * number_two