When determining the age of a bull moose, the number of tines (sharp points), extending from the main antlers, can be used. An older bull moose tends to have more tines than a younger moose. However, just counting the number of tines can be misleading, as a moose can break off the tines, for example when fighting with other moose. Therefore, a point system is used when describing the antlers of a bull moose. 

The point system works like this: If the number of tines on the left side and the right side match, the moose is said to have the even sum of the number of points. So, “an even $6$-point moose”, would have three tines on each side. If the moose has a different number of tines on the left and right side, the moose is said to have twice the highest number of tines, but it is odd. So “an odd $10$-point moose” would have $5$ tines on one side, and $4$ or less tines on the other side.

Can you figure out how many points a moose has, given the number of tines on the left and right side?

-----Input-----
The input contains a single line with two integers $\ell $ and $r$, where $0 \le \ell \le 20$ is the number of tines on the left, and $0 \le r \le 20$ is the number of tines on the right.

-----Output-----
Output a single line describing the moose. For even pointed moose, output “Even $x$” where $x$ is the points of the moose. For odd pointed moose, output “Odd $x$” where $x$ is the points of the moose. If the moose has no tines, output “Not a moose”

-----Examples-----
Sample Input 1:
2 3
Sample Output 1:
Odd 6

Sample Input 2:
3 3
Sample Output 2:
Even 6

Difficulty: introductory

Starter code:

Solutions: