1sf/bird-sql-train-with-schema huggingface dataset:
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Find the brand Id of the root beer which has the most number of customers who gave 1-star ratings.
Evidence: most number of customers who gave 1-star ratings refers to MAX(COUNT(StarRating = 1)); 1-star ratings refers to StarRating = 1;
SQL: SELECT BrandID FROM rootbeerreview WHERE StarRating = 1 GROUP BY BrandID ORDER BY COUNT(BrandID) DESC LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Among the transactions, what percentage is done by using a visa card?
Evidence: visa card refers to CreditCardType = 'Visa'; percentage = MULTIPLY(DIVIDE(SUM(CreditCardType = 'Visa'), COUNT(TransactionID)), 1.0);
SQL: SELECT CAST(COUNT(CASE WHEN CreditCardType = 'Visa' THEN TransactionID ELSE NULL END) AS REAL) * 100 / COUNT(TransactionID) FROM `transaction`
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: How many brands of root beers are available in cans and contain corn syrup and artificial sweeteners?
Evidence: available in cans refers to AvailableInCans = 'TRUE'; contain corn syrup refers to CornSyrup = 'TRUE'; contain artificial sweeteners refers to ArtificialSweetener = 'TRUE';
SQL: SELECT COUNT(BrandID) FROM rootbeerbrand WHERE CornSyrup = 'TRUE' AND ArtificialSweetener = 'TRUE' AND AvailableInCans = 'TRUE'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Calculate the percentage of sales done at Sac State American River Courtyard.
Evidence: percentage =   MULTIPLY(DIVIDE(SUM(LocationName = 'Sac State American River Courtyard'), COUNT(LocationID)), 1.0); Sac State American River Courtyard refers to LocationName = 'Sac State American River Courtyard';
SQL: SELECT CAST(COUNT(CASE WHEN T2.LocationName = 'Sac State American River Courtyard' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.TransactionID) FROM `transaction` AS T1 INNER JOIN location AS T2 ON T1.LocationID = T2.LocationID
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: On average how many caffeinated root beers are sold a day?
Evidence: average = DIVIDE(COUNT(RootBeerID WHERE Caffeinated = 'TRUE'), COUNT(PurchaseDate)); caffeinated refers to Caffeinated = 'TRUE';
SQL: SELECT CAST(COUNT(T2.RootBeerID) AS REAL) / COUNT(DISTINCT T2.PurchaseDate) FROM rootbeerbrand AS T1 INNER JOIN rootbeer AS T2 ON T1.BrandID = T2.BrandID INNER JOIN `transaction` AS T3 ON T2.RootBeerID = T3.RootBeerID WHERE T1.Caffeinated = 'TRUE'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Find the root beer with the most and least amount of profit per unit and list the container types in which these root beers are sold.
Evidence: most amount of profit per unit refers to MAX(SUBTRACT(CurrentRetailPrice, WholesaleCost)); least amount of profit per unit refers to MIN(SUBTRACT(CurrentRetailPrice, WholesaleCost));
SQL: SELECT * FROM ( SELECT T1.BrandName, T2.ContainerType FROM rootbeerbrand AS T1 INNER JOIN rootbeer AS T2 ON T1.BrandID = T2.BrandID ORDER BY T1.CurrentRetailPrice - T1.WholesaleCost DESC LIMIT 1 ) UNION ALL SELECT * FROM ( SELECT T3.BrandName, T4.ContainerType FROM rootbeerbrand AS T3 INNER JOIN rootbeer AS T4 ON T3.BrandID = T4.BrandID ORDER BY T3.CurrentRetailPrice - T3.WholesaleCost ASC LIMIT 1 )
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the average cost of root beers purchased for more than 2 dollars and sold in bottles?
Evidence: average cost = DIVIDE(SUM(PurchasePrice > 2), COUNT(RootBeerID) WHERE PurchasePrice > 2); more than 2 dollars refers to PurchasePrice > 2; in bottles refers to ContainerType = 'Bottle';
SQL: SELECT AVG(T2.PurchasePrice) FROM rootbeer AS T1 INNER JOIN `transaction` AS T2 ON T1.RootBeerID = T2.RootBeerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID WHERE T1.ContainerType = 'Bottle' AND T2.PurchasePrice > 2
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Among the root beers sold in bottles, how many are sold at the location 38.559615, -121.42243?
Evidence: in bottles refers to ContainerType = 'Bottle';  location 38.559615, -121.42243 refers to latitude = 38.559615 AND longitude = -121.42243;
SQL: SELECT COUNT(T4.BrandID) FROM `transaction` AS T1 INNER JOIN geolocation AS T2 ON T1.LocationID = T2.LocationID INNER JOIN location AS T3 ON T1.LocationID = T3.LocationID INNER JOIN rootbeer AS T4 ON T1.RootBeerID = T4.RootBeerID WHERE T2.Latitude = 38.559615 AND T2.Longitude = -121.42243 AND T4.ContainerType = 'Bottle'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Among the customers not subscribed to the mailing list, what percentage has given three or more stars in a review?
Evidence: not subscribed to the mailing list refers to SubscribedToEmailList = 'FALSE'; percentage = MULTIPLY(DIVIDE(SUM(CustomerID WHERE StarRating > 3), COUNT(CustomerID) WHERE SubscribedToEmailList = 'FALSE'), 1.0);
SQL: SELECT CAST(COUNT(CASE WHEN T2.StarRating > 3 THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T2.CustomerID) FROM customers AS T1 INNER JOIN rootbeerreview AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.SubscribedToEmailList = 'FALSE'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Which root beer got the most five stars in 2012? Give the brand name of this beer.
Evidence: most five stars refers to MAX(COUNT(StarRating = 5)); in 2012 refers to FirstBrewedYear = 2012;
SQL: SELECT T3.BrandName FROM rootbeer AS T1 INNER JOIN rootbeerreview AS T2 ON T1.BrandID = T2.BrandID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID WHERE T2.StarRating = 5 AND strftime('%Y', T2.ReviewDate) = '2012' GROUP BY T1.BrandID ORDER BY COUNT(T2.BrandID) DESC LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: In the female customers, how many bought root beer that contains artificial sweetener?
Evidence: female refers to Gender = 'F'; contains artificial sweetener refers to ArtificialSweetener = 'TRUE';
SQL: SELECT COUNT(T1.CustomerID) FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN rootbeer AS T3 ON T2.RootBeerID = T3.RootBeerID INNER JOIN rootbeerbrand AS T4 ON T3.BrandID = T4.BrandID WHERE T1.Gender = 'F' AND T4.ArtificialSweetener = 'TRUE'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Calculate the difference between the number of root beers sold that use cane sugar and corn syrup.
Evidence: difference = SUBTRACT(SUM(CaneSugar = 'TRUE'), SUM(CornSyrup = 'TRUE')); use cane sugar refers to CaneSugar = 'TRUE'; corn syrup refers to CornSyrup = 'TRUE';
SQL: SELECT COUNT(CASE WHEN T3.CaneSugar = 'TRUE' THEN T1.BrandID ELSE NULL END) - COUNT(CASE WHEN T3.CornSyrup = 'TRUE' THEN T1.BrandID ELSE NULL END) AS DIFFERENCE FROM rootbeer AS T1 INNER JOIN `transaction` AS T2 ON T1.RootBeerID = T2.RootBeerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Which brewery brewed the most sold root beer in 2015?
Evidence: brewery refers to BreweryName; most sold root beer refers to MAX(COUNT(BrandID)); in 2015 refers to TransactionDate > = '2015-01-01' AND TransactionDate < = '2015-12-31';
SQL: SELECT T3.BreweryName FROM rootbeer AS T1 INNER JOIN `transaction` AS T2 ON T1.RootBeerID = T2.RootBeerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID WHERE T2.TransactionDate LIKE '2015%' GROUP BY T3.BrandID ORDER BY COUNT(T1.BrandID) DESC LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Among the male customers in Sacramento, what percentage bought Dominion root beer in 2013?
Evidence: male customers refers to Gender = 'M'; Sacramento refers to City = 'Sacramento'; percentage = MULTIPLY(DIVIDE(SUM(BrandID WHERE BrandName = 'Dominion'), COUNT(BrandID) WHERE City = 'Sacramento'), 1.0); Dominion refers to BrandName = 'Dominion'; in 2013 refers to TransactionDate > = 2013-01-01 AND TransactionDate < 2014-01-01;
SQL: SELECT CAST(COUNT(CASE WHEN T4.BrandName = 'Dominion' THEN T1.CustomerID ELSE NULL END) AS REAL) * 100 / COUNT(T1.CustomerID) FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN rootbeer AS T3 ON T2.RootBeerID = T3.RootBeerID INNER JOIN rootbeerbrand AS T4 ON T3.BrandID = T4.BrandID WHERE T1.City = 'Sacramento' AND T1.Gender = 'M' AND T2.TransactionDate LIKE '2014%'