1sf/bird-sql-train-with-schema huggingface dataset:
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which language is the rarest among all the books?
Evidence: language written in refers to language_name; rarest refers to Min(Count(book_id))
SQL: SELECT T2.language_name FROM book AS T1 INNER JOIN book_language AS T2 ON T1.language_id = T2.language_id GROUP BY T2.language_name ORDER BY COUNT(T2.language_name) ASC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: List all the order dates for the customer named "Adrian Kunzelmann".
SQL: SELECT T3.order_date FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id INNER JOIN cust_order AS T3 ON T3.order_id = T2.order_id INNER JOIN customer AS T4 ON T4.customer_id = T3.customer_id WHERE T4.first_name = 'Adrian' AND T4.last_name = 'Kunzelmann'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many addresses are from the Philippines?
Evidence: "Philippines" is the country_name
SQL: SELECT COUNT(T2.country_id) FROM address AS T1 INNER JOIN country AS T2 ON T2.country_id = T1.country_id WHERE T2.country_name = 'Philippines'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Who is the author who wrote the most books?
Evidence: author refers to author_name; who wrote the most book refers to Max(Count(author_id))
SQL: SELECT T1.author_name FROM author AS T1 INNER JOIN book_author AS T2 ON T1.author_id = T2.author_id GROUP BY T1.author_name ORDER BY COUNT(T2.author_id) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What are the books published by "Harper Collins"?
Evidence: "Harper Collins" is the publisher_name; books refers to title
SQL: SELECT T1.title FROM book AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.publisher_id WHERE T2.publisher_name = 'Harper Collins'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many orders were returned in the year 2020?
Evidence: returned refers to status_value = 'Returned'; in the year 2020 refers to status_date LIKE '%2020%'
SQL: SELECT COUNT(*) FROM order_status AS T1 INNER JOIN order_history AS T2 ON T1.status_id = T2.status_id WHERE T1.status_value = 'Returned' AND STRFTIME('%Y', T2.status_date) = '2020'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What is the second-least common method of shipping?
Evidence: method of shipping refers to method_name; least method refers to Min(Count(method_id))
SQL: SELECT T2.method_name FROM cust_order AS T1 INNER JOIN shipping_method AS T2 ON T1.shipping_method_id = T2.method_id GROUP BY T2.method_name ORDER BY COUNT(T2.method_id) ASC LIMIT 1, 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many of the customer addresses are inactive?
Evidence: addresses are inactive refers to address_status = 'Inactive'
SQL: SELECT COUNT(*) FROM customer_address AS T1 INNER JOIN address_status AS T2 ON T1.status_id = T2.status_id WHERE T2.address_status = 'Inactive'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What is the book with the most orders?
Evidence: books refers to title; the most orders refers to Max(Count(order_id))
SQL: SELECT T2.title FROM order_line AS T1 INNER JOIN book AS T2 ON T1.book_id = T2.book_id GROUP BY T2.title ORDER BY COUNT(T1.book_id) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What is the address that received the most orders?
Evidence: address refers to street_name, city; received the most orders refers to Max(count(dest_address_id))
SQL: SELECT T2.street_name, T2.city FROM cust_order AS T1 INNER JOIN address AS T2 ON T1.dest_address_id = T2.address_id GROUP BY T2.street_number, T2.street_name, T2.city ORDER BY COUNT(T1.dest_address_id) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How much time does it take to update the status of order "2398"?
Evidence: "2398" is the order_id; time =   Subtract(strftime('%Y', status_date), strftime('%Y', order_date)) AS "year" , Subtract(strftime('%m', status_date), strftime('%m', order_date)) AS "month", Subtract (strftime('%d', status_date), strftime('%d', order_date)) AS "day"
SQL: SELECT strftime('%J', T2.status_date) - strftime('%J', T1.order_date) FROM cust_order AS T1 INNER JOIN order_history AS T2 ON T1.order_id = T2.order_id WHERE T1.order_id = 2398
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which customer has the most addresses?
Evidence: customer refers to first_name, last_name; the most address refers to Max(count(address_id))
SQL: SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN customer_address AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ORDER BY COUNT(T2.customer_id) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What percentage of the total prices of all orders are shipped internationally?
Evidence: shipped internationally refers to method_name = 'International'; percentage = Divide (Sum(price where method_name = 'International'), Sum(price)) * 100
SQL: SELECT CAST(SUM(CASE WHEN T3.method_name = 'International' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM cust_order AS T1 INNER JOIN order_line AS T2 ON T1.order_id = T2.order_id INNER JOIN shipping_method AS T3 ON T3.method_id = T1.shipping_method_id
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: List all the authors who wrote fewer pages than the average.
Evidence: author refers to author_name; who wrote fewer pages than the average refers to num_pages < AVG(num_pages)
SQL: SELECT T3.author_name FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id WHERE T1.num_pages < ( SELECT AVG(num_pages) FROM book )
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Other than zero, what is the lowest price paid by a customer for an order?
Evidence: other than 0 refers to price ! = 0; lowest price paid refers to Min(price)
SQL: SELECT MIN(price) FROM order_line WHERE price <> 0
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many customers have an address that is located in the city of Villeneuve-la-Garenne?
Evidence: "Villeneuve-la-Garenne" is the city
SQL: SELECT COUNT(address_id) FROM address WHERE city = 'Villeneuve-la-Garenne'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many authors are named Adam?
Evidence: authors named Adam refers to author_name LIKE 'Adam'
SQL: SELECT COUNT(*) FROM author WHERE author_name LIKE 'Adam%'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many customers use a Yahoo! Mail e-mail address?
Evidence: Yahoo! Mail e-mail address refers to email LIKE '%@yahoo.com'
SQL: SELECT COUNT(*) FROM customer WHERE email LIKE '%@yahoo.com'