1sf/bird-sql-train-with-schema huggingface dataset:
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Which of the films released in 2006 was the most popular among Mubi users?
Evidence: released in 2006 refers to movie_release_year = 2006; most popular refers to Max(movie_popularity); film refers to movie;
SQL: SELECT movie_title FROM movies WHERE movie_release_year = 2006 ORDER BY movie_popularity DESC LIMIT 1
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: How many films did Åke Sandgren direct?
Evidence: Ake Sandgren is the director name;  film refers to movie
SQL: SELECT COUNT(movie_title) FROM movies WHERE director_name = 'Åke Sandgren'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Which of the films directed by Álex de la Iclesia is the most popular among Mubi users?
Evidence: Alex de la Iclesia is the director name; the most popular refers to Max(movie_popularity); films refers to movies;
SQL: SELECT movie_title FROM movies WHERE director_name = 'Åke Sandgren' ORDER BY movie_popularity DESC LIMIT 1
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: When was the movie Cops released?
Evidence: Cops' is movie_title; released refers to movie_release_year;
SQL: SELECT movie_release_year FROM movies WHERE movie_title = 'Cops'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please list the id of the director of the movie "It's Winter".
Evidence: It's Winter' is movie_title;
SQL: SELECT director_id FROM movies WHERE movie_title = 'It''s Winter'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please provide the ID of the user with the most followers on the list.
Evidence: most followers refers to Max(list_followers);
SQL: SELECT user_id FROM lists ORDER BY list_followers DESC LIMIT 1
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please provide the title of the list with the most comments on the list.
Evidence: the most comments refers to Max(list_comments);
SQL: SELECT list_title FROM lists GROUP BY list_title ORDER BY COUNT(list_comments) DESC LIMIT 1
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Which of the film released in 2008 scored the highest?
Evidence: film released in 2008 refers to movie_release_year = 2008; scored the highest refers to Max(rating_score); film refers to movie;
SQL: SELECT T2.movie_title FROM ratings AS T1 INNER JOIN movies AS T2 ON T1.movie_id = T2.movie_id WHERE T2.movie_release_year = 2008 ORDER BY T1.rating_score DESC LIMIT 1
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please list the names of the top three movies in the number of likes related to the critic made by the user rating the movie.
Evidence: likes related to the critic made by the user rating the movie refers to critic_likes; top refers to Max(critic_likes);
SQL: SELECT T2.movie_title FROM ratings AS T1 INNER JOIN movies AS T2 ON T1.movie_id = T2.movie_id ORDER BY T1.critic_likes DESC LIMIT 3
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: How many users have more than 100 followers in the list created by users in 2009?
Evidence: more than 100 followers refers to list_followers >100;  list created by the user in 2009 refers to list_creation_date_utc = '2009';
SQL: SELECT COUNT(T1.user_id) FROM lists_users AS T1 INNER JOIN lists AS T2 ON T1.list_id = T2.list_id WHERE T2.list_followers > 100 AND T1.list_creation_date_utc LIKE '2009%'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: How many users in Mubi give the movie "White Night Wedding for 5"?
Evidence: White Night Wedding' is movie_title; for 5 refers to rating_score = 5;
SQL: SELECT COUNT(T1.user_id) FROM ratings AS T1 INNER JOIN movies AS T2 ON T1.movie_id = T2.movie_id WHERE T1.rating_score = 5 AND T2.movie_title = 'White Night Wedding'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: What's the cover image of the user who created the movie list 'Georgia related films'?
Evidence: Play it cool' is list_title; cover image of user refers to user_cover_image_url;
SQL: SELECT T1.user_cover_image_url FROM lists_users AS T1 INNER JOIN lists AS T2 ON T1.list_id = T2.list_id WHERE T2.list_title LIKE 'Georgia related films'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: How many followers does the list created by the user whose user_avatar_image_url is https://assets.mubicdn.net/images/avatars/74983/images-w150.jpg?1523895214 have?
Evidence: followers refers to list_followers;
SQL: SELECT SUM(T2.list_followers) FROM lists_users AS T1 INNER JOIN lists AS T2 ON T1.list_id = T2.list_id WHERE T1.user_avatar_image_url = 'https://assets.mubicdn.net/images/avatars/74983/images-w150.jpg?1523895214'
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please list the names of the movies that user 94978 scored as 5.
Evidence: user 94978 refers to user_id = 94978; scored as 5 refers to rating_score = 5;
SQL: SELECT T2.movie_title FROM ratings AS T1 INNER JOIN movies AS T2 ON T1.movie_id = T2.movie_id WHERE T1.rating_score = 5 AND T1.user_id = 94978
Database: movie_platform
Tables: lists, movies, ratings_users, lists_users, ratings
Columns (table index, column name): -1, *, 0, user_id, 0, list_id, 0, list_title, 0, list_movie_number, 0, list_update_timestamp_utc, 0, list_creation_timestamp_utc, 0, list_followers, 0, list_url, 0, list_comments, 0, list_description, 0, list_cover_image_url, 0, list_first_image_url, 0, list_second_image_url, 0, list_third_image_url, 1, movie_id, 1, movie_title, 1, movie_release_year, 1, movie_url, 1, movie_title_language, 1, movie_popularity, 1, movie_image_url, 1, director_id, 1, director_name, 1, director_url, 2, user_id, 2, rating_date_utc, 2, user_trialist, 2, user_subscriber, 2, user_avatar_image_url, 2, user_cover_image_url, 2, user_eligible_for_trial, 2, user_has_payment_method, 3, user_id, 3, list_id, 3, list_update_date_utc, 3, list_creation_date_utc, 3, user_trialist, 3, user_subscriber, 3, user_avatar_image_url, 3, user_cover_image_url, 3, user_eligible_for_trial, 3, user_has_payment_method, 4, movie_id, 4, rating_id, 4, rating_url, 4, rating_score, 4, rating_timestamp_utc, 4, critic, 4, critic_likes, 4, critic_comments, 4, user_id, 4, user_trialist, 4, user_subscriber, 4, user_eligible_for_trial, 4, user_has_payment_method
Question: Please list the names of the films released in 2003 among the films scored by user 2941 .
Evidence: released in 2003 refers to movie_release_year = 2003; user 2941 refers to user_id = 2941; film refers to movie;
SQL: SELECT T2.movie_title FROM ratings AS T1 INNER JOIN movies AS T2 ON T1.movie_id = T2.movie_id WHERE T2.movie_release_year = 2003 AND T1.user_id = 2941