1sf/bird-sql-train-with-schema huggingface dataset:
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Give me the full name of the first customer, and tell me how long ago he or she wrote his or her first review since making his or her first purchase.
Evidence: full name = First, Last; how long ago = SUBTRACT(ReviewDate, FirstPurchaseDate);
SQL: SELECT T1.First, T1.Last , strftime('%J', ReviewDate) - strftime('%J', FirstPurchaseDate) AS TIMEAGO FROM customers AS T1 INNER JOIN rootbeerreview AS T2 ON T1.CustomerID = T2.CustomerID LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the credit card type used by Kenneth Walton?
Evidence: FALSE;
SQL: SELECT DISTINCT T2.CreditCardType FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.First = 'Kenneth' AND T1.Last = 'Walton'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the container type, brand name and star rating for root beer ID 10054?
Evidence: FALSE;
SQL: SELECT T4.ContainerType, T3.BrandName, T1.StarRating FROM rootbeerreview AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID INNER JOIN rootbeer AS T4 ON T2.RootBeerID = T4.RootBeerID WHERE T2.RootBeerID = 100054
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: List out the root beers bought by Tim Ocel and Dawn Childress.
Evidence: FALSE;
SQL: SELECT T2.RootBeerID FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T2.CustomerID = T1.CustomerID WHERE (T1.First = 'Tim' AND T1.Last = 'Ocel') OR (T1.First = 'Dawn' AND T1.Last = 'Childress')
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: List out the root beer ID for the brand Bulldog, Bundaberg, Dad's, Dog n Suds and Virgil's.
Evidence: Bulldog, Bundaberg, Dad's, Dog n Suds and Virgil's refers to BrandName IN('Bulldog', 'Bundaberg', 'Dad''s', 'Dog n Suds', 'Virgil''s');
SQL: SELECT T1.RootBeerID FROM rootbeer AS T1 INNER JOIN rootbeerbrand AS T2 ON T2.BrandID = T1.BrandID WHERE T2.BrandName IN ('Bulldog', 'Bundaberg', 'Dad''s', 'Dog n Suds', 'Virgil''s')
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: How many bottles of beer have been bought by Jim Breech?
Evidence: bottles refers to ContainerType = 'Bottle';
SQL: SELECT COUNT(T3.ContainerType) FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T2.CustomerID = T1.CustomerID INNER JOIN rootbeer AS T3 ON T3.RootBeerID = T2.RootBeerID WHERE T3.ContainerType = 'Bottle' AND T1.First = 'Jim' AND T1.Last = 'Breech'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: How many transactions have been made to purchase a root beer brand from California?
Evidence: California refers to State = 'CA';
SQL: SELECT COUNT(T3.RootBeerID) FROM rootbeerbrand AS T1 INNER JOIN rootbeer AS T2 ON T1.BrandID = T2.BrandID INNER JOIN `transaction` AS T3 ON T2.RootBeerID = T3.RootBeerID WHERE T1.State = 'CA'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the average review given by a subscriber?
Evidence: average review = AVG(StarRating); subscriber refers to SubscribedToEmailList = 'TRUE';
SQL: SELECT AVG(T2.StarRating) FROM customers AS T1 INNER JOIN rootbeerreview AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.SubscribedToEmailList = 'TRUE'
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the amount difference between the bottles of root beer sold from Louisiana and Missouri?
Evidence: difference = SUBTRACT(COUNT(ContainerType = 'Bottle' WHERE State = 'LA'), COUNT(ContainerType = 'Bottle' State = 'MO')); bottles refers to ContainerType = 'Bottle'; Louisiana refers to State = 'LA'; Missouri refers to State = 'MO';
SQL: SELECT ( SELECT COUNT(T1.BrandID) FROM rootbeer AS T1 INNER JOIN rootbeerbrand AS T2 ON T1.BrandID = T2.BrandID WHERE T2.State = 'LA' AND T1.ContainerType = 'Bottle' ) - ( SELECT COUNT(T3.BrandID) FROM rootbeer AS T3 INNER JOIN rootbeerbrand AS T4 ON T3.BrandID = T4.BrandID WHERE T4.State = 'MO' AND T3.ContainerType = 'Bottle' ) AS DIFFERENCE
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the transaction ratio being made at Sac State American River Courtyard and Sac State Union?
Evidence: transaction ratio = DIVIDE(SUM(TransactionID WHERE LocationName = 'Sac State American River Courtyard'), SUM(TransactionID WHERE LocationName = 'Sac State Union')); Sac State American River Courtyard refers to LocationName = 'Sac State American River Courtyard'; Sac State Union refers to LocationName = 'Sac State Union';
SQL: SELECT CAST(COUNT(CASE WHEN T2.LocationName = 'Sac State American River Courtyard' THEN T1.TransactionID ELSE NULL END) AS REAL) * 100 / COUNT(CASE WHEN T2.LocationName = 'Sac State Union' THEN T1.TransactionID ELSE NULL END) FROM `transaction` AS T1 INNER JOIN location AS T2 ON T1.LocationID = T2.LocationID
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: List out the name of the top 10 spenders and what credit card type are they using.
Evidence: top 10 spenders refers to MAX(PurchasePrice) LIMIT 10;
SQL: SELECT T1.First, T1.Last, T2.CreditCardType FROM customers AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID GROUP BY T1.CustomerID ORDER BY SUM(T2.PurchasePrice) DESC LIMIT 10
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: List out root beer brand that is not caffeinated and not containing cane sugar. What is the total amount sold for this products?
Evidence: root beer brand refers to BrandName; not caffeinated refers to Caffeinated = 'FALSE'; not containing cane sugar refers to CaneSugar = 'FALSE'; total amount sold = SUM(PurchasePrice);
SQL: SELECT T1.BrandName, SUM(T3.PurchasePrice) FROM rootbeerbrand AS T1 INNER JOIN rootbeer AS T2 ON T1.BrandID = T2.BrandID INNER JOIN `transaction` AS T3 ON T2.RootBeerID = T3.RootBeerID WHERE T1.CaneSugar = 'FALSE' AND T1.Caffeinated = 'FALSE' GROUP BY T1.BrandName
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Which of the root beer brand have the lowest purchase?
Evidence: root beer brand refers to BrandName; lowest purchase refers to MIN(COUNT(BrandID));
SQL: SELECT T2.BrandName FROM rootbeer AS T1 INNER JOIN rootbeerbrand AS T2 ON T1.BrandID = T2.BrandID GROUP BY T2.BrandID ORDER BY COUNT(T1.BrandID) LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the best seller root beer brand and what is the average star rating for this root beer?
Evidence: best seller root beer refers to MAX(COUNT(BrandID)); average star rating = AVG(StarRating);
SQL: SELECT T1.BrandID, AVG(T1.StarRating) FROM rootbeerreview AS T1 INNER JOIN `transaction` AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID GROUP BY T3.BrandID ORDER BY COUNT(T1.BrandID) DESC LIMIT 1
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: What is the percentage difference of River City sale compare to Frostie?
Evidence: percentage difference = (DIVIDE(MULTIPLY(SUBTRACT(SUM(PurchasePrice WHERE BrandName = 'River City'), SUM(PurchasePrice WHERE BrandName = 'Frostie')), 100), SUM(PurchasePrice WHERE BrandName = 'Frostie'))); River City refers to BrandName = 'River City'; Frostie refers to BrandName = 'Frostie';
SQL: SELECT CAST((SUM(CASE WHEN T3.BrandName = 'River City' THEN T2.PurchasePrice ELSE 0 END) - SUM(CASE WHEN T3.BrandName = 'Frostie' THEN T2.PurchasePrice ELSE 0 END)) AS REAL) * 100 / SUM(CASE WHEN T3.BrandName = 'Frostie' THEN T2.PurchasePrice ELSE 0 END) FROM rootbeer AS T1 INNER JOIN `transaction` AS T2 ON T1.RootBeerID = T2.RootBeerID INNER JOIN rootbeerbrand AS T3 ON T1.BrandID = T3.BrandID
Database: beer_factory
Tables: customers, geolocation, location, rootbeerbrand, rootbeer, rootbeerreview, transaction
Columns (table index, column name): -1, *, 0, CustomerID, 0, First, 0, Last, 0, StreetAddress, 0, City, 0, State, 0, ZipCode, 0, Email, 0, PhoneNumber, 0, FirstPurchaseDate, 0, SubscribedToEmailList, 0, Gender, 1, LocationID, 1, Latitude, 1, Longitude, 2, LocationID, 2, LocationName, 2, StreetAddress, 2, City, 2, State, 2, ZipCode, 3, BrandID, 3, BrandName, 3, FirstBrewedYear, 3, BreweryName, 3, City, 3, State, 3, Country, 3, Description, 3, CaneSugar, 3, CornSyrup, 3, Honey, 3, ArtificialSweetener, 3, Caffeinated, 3, Alcoholic, 3, AvailableInCans, 3, AvailableInBottles, 3, AvailableInKegs, 3, Website, 3, FacebookPage, 3, Twitter, 3, WholesaleCost, 3, CurrentRetailPrice, 4, RootBeerID, 4, BrandID, 4, ContainerType, 4, LocationID, 4, PurchaseDate, 5, CustomerID, 5, BrandID, 5, StarRating, 5, ReviewDate, 5, Review, 6, TransactionID, 6, CreditCardNumber, 6, CustomerID, 6, TransactionDate, 6, CreditCardType, 6, LocationID, 6, RootBeerID, 6, PurchasePrice
Question: Please name all of the cities in California.
Evidence: California refers to State = 'CA';
SQL: SELECT DISTINCT City FROM customers WHERE State = 'CA'