1sf/bird-sql-train-with-schema huggingface dataset:
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What is the total price of all the books ordered by Lucas Wyldbore?
Evidence: total price refers to Sum(price)
SQL: SELECT SUM(T1.price) FROM order_line AS T1 INNER JOIN cust_order AS T2 ON T2.order_id = T1.order_id INNER JOIN customer AS T3 ON T3.customer_id = T2.customer_id WHERE T3.first_name = 'Lucas' AND T3.last_name = 'Wyldbore'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How much money on average does Lucas Wyldbore spend on book orders?
Evidence: average spend on book orders = AVG (price)
SQL: SELECT SUM(T1.price) / COUNT(*) FROM order_line AS T1 INNER JOIN cust_order AS T2 ON T2.order_id = T1.order_id INNER JOIN customer AS T3 ON T3.customer_id = T2.customer_id WHERE T3.first_name = 'Lucas' AND T3.last_name = 'Wyldbore'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Among the books ordered by Lucas Wyldbore, what is the percentage of those books over $13?
Evidence: books over $13 refers to price > 13; percentage = Divide (Sum (order_id where price > 13), Count (order_id)) * 100
SQL: SELECT CAST(SUM(CASE WHEN T1.price > 13 THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM order_line AS T1 INNER JOIN cust_order AS T2 ON T2.order_id = T1.order_id INNER JOIN customer AS T3 ON T3.customer_id = T2.customer_id WHERE T3.first_name = 'Lucas' AND T3.last_name = 'Wyldbore'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which city does the address id 547 belong to?
SQL: SELECT city FROM address WHERE address_id = 547
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many orders has Cordy Dumbarton made?
SQL: SELECT COUNT(*) FROM customer AS T1 INNER JOIN cust_order AS T2 ON T1.customer_id = T2.customer_id WHERE T1.first_name = 'Cordy' AND T1.last_name = 'Dumbarton'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: List the title of the earliest published Japanese book.
Evidence: Japanese book refers to language_name = 'Japanese'; earliest published refers to Min(publication_date)
SQL: SELECT T1.title FROM book AS T1 INNER JOIN book_language AS T2 ON T1.language_id = T2.language_id WHERE T2.language_name = 'Japanese' ORDER BY T1.publication_date ASC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: For the publisher which published the most books, show its name.
Evidence: published the most books refers to Max(Count(book_id)); publisher refers to publisher_name
SQL: SELECT T2.publisher_name FROM book AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.publisher_id GROUP BY T2.publisher_name ORDER BY COUNT(T2.publisher_id) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many books were published by Kensington?
Evidence: "Kensington" is the publisher_name;
SQL: SELECT COUNT(T1.book_id) FROM book AS T1 INNER JOIN publisher AS T2 ON T1.publisher_id = T2.publisher_id WHERE T2.publisher_name = 'Kensington'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which language was book id 1405 written in?
Evidence: language written in refers to language_name;
SQL: SELECT T2.language_name FROM book AS T1 INNER JOIN book_language AS T2 ON T1.language_id = T2.language_id WHERE T1.book_id = 1405
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which customer has made the most orders? Show his/her full name.
Evidence: most order refers to Max(Count(order_id)); customer refers to first_name, last_name
SQL: SELECT T1.first_name, T1.last_name FROM customer AS T1 INNER JOIN cust_order AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.first_name, T1.last_name ORDER BY COUNT(*) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Name the book title of the bestseller.
Evidence: book title refers to title; best sellers refers to title where Max(count(order_id))
SQL: SELECT T1.title FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id GROUP BY T1.title ORDER BY COUNT(T1.title) DESC LIMIT 1
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many books did David Foster Wallace write?
Evidence: "David Foster Wallace" is the author_name;
SQL: SELECT COUNT(T1.title) FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id WHERE T3.author_name = 'David Foster Wallace'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: How many orders does the book "O Xará" have?
Evidence: "O Xará" is the title of the book
SQL: SELECT COUNT(*) FROM book AS T1 INNER JOIN order_line AS T2 ON T1.book_id = T2.book_id WHERE T1.title = 'O Xará'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which country does Malina Johnson live in?
Evidence: country refers to country_name
SQL: SELECT T4.country_name FROM customer AS T1 INNER JOIN customer_address AS T2 ON T1.customer_id = T2.customer_id INNER JOIN address AS T3 ON T3.address_id = T2.address_id INNER JOIN country AS T4 ON T4.country_id = T3.country_id WHERE T1.first_name = 'Malina' AND T1.last_name = 'Johnson' AND T2.status_id = 2
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Give the number of Ukrainian addresses in the database.
Evidence: Ukrainian address refers to country_name = 'Ukraine'
SQL: SELECT COUNT(*) FROM country AS T1 INNER JOIN address AS T2 ON T1.country_id = T2.country_id WHERE T1.country_name = 'Ukraine'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Which country does Žirovnica city belong to?
Evidence: "Žirovnica" is the city; country refers to country_name
SQL: SELECT T1.country_name FROM country AS T1 INNER JOIN address AS T2 ON T1.country_id = T2.country_id WHERE T2.city = 'Žirovnica'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: Calculate the percentage of the International shipping orders on 2022/11/10.
Evidence: International shipping order refers to method_name = 'International'; orders on 2022/11/10 refers to order_date LIKE '2022-11-10%'; percentage = Divide (Sum(order_id  where method_name = 'International'), Count(order_id)) * 100
SQL: SELECT CAST(SUM(CASE WHEN T1.method_name = 'International' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) FROM shipping_method AS T1 INNER JOIN cust_order AS T2 ON T1.method_id = T2.shipping_method_id WHERE T2.order_date LIKE '2022-11-10%'
Database: books
Tables: address_status, author, book_language, country, address, customer, customer_address, order_status, publisher, book, book_author, shipping_method, cust_order, order_history, order_line
Columns (table index, column name): -1, *, 0, status_id, 0, address_status, 1, author_id, 1, author_name, 2, language_id, 2, language_code, 2, language_name, 3, country_id, 3, country_name, 4, address_id, 4, street_number, 4, street_name, 4, city, 4, country_id, 5, customer_id, 5, first_name, 5, last_name, 5, email, 6, customer_id, 6, address_id, 6, status_id, 7, status_id, 7, status_value, 8, publisher_id, 8, publisher_name, 9, book_id, 9, title, 9, isbn13, 9, language_id, 9, num_pages, 9, publication_date, 9, publisher_id, 10, book_id, 10, author_id, 11, method_id, 11, method_name, 11, cost, 12, order_id, 12, order_date, 12, customer_id, 12, shipping_method_id, 12, dest_address_id, 13, history_id, 13, order_id, 13, status_id, 13, status_date, 14, line_id, 14, order_id, 14, book_id, 14, price
Question: What is the average number of pages of David Coward's books?
Evidence: number of pages refers to num_pages; average = Divide (Sum(num_pages), Count(book_id))
SQL: SELECT AVG(T1.num_pages) FROM book AS T1 INNER JOIN book_author AS T2 ON T1.book_id = T2.book_id INNER JOIN author AS T3 ON T3.author_id = T2.author_id WHERE T3.author_name = 'David Coward'