1sf/bird-sql-train-with-schema huggingface dataset:
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Who is the customer from the West region that received the highest discount?
Evidence: received the highest discount refers to MAX(discount); customer refers to "Customer Name"
SQL: SELECT T2.`Customer Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'West' ORDER BY T1.Discount DESC LIMIT 1
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Provide the names of the products with a profit greater than 98% of the average profit of all products in the East region.
Evidence: names of the products refers to "Product Name";  profit greater than 98% of the average profit refers to Profit > MULTIPLY(AVG(Profit), 0.98)
SQL: SELECT DISTINCT T2.`Product Name` FROM east_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T2.Region = 'East' AND T1.Profit > ( SELECT AVG(Profit) * 0.98 FROM east_superstore )
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Name the customers from the Eastern region whose orders cost above 80000.
Evidence: cost above 80000 refers to SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit) > 80000
SQL: SELECT DISTINCT T2.`Customer Name` FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T1.Region = 'East' AND T1.Sales / (1 - T1.Discount) * T1.Quantity - T1.Profit > 80000
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: How many orders were made by Maxwell Schwartz in 2015?
Evidence: Maxwell Schwartz' is the "Customer Name"; in 2015 refers to strftime('%Y', "Order Date") = '2015';
SQL: SELECT COUNT(DISTINCT T1.`Order ID`) FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` WHERE T2.`Customer Name` = 'Maxwell Schwartz' AND STRFTIME('%Y', T1.`Order Date`) = '2015'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Who ordered the Bush Mission Pointe Library in the Central Region?
Evidence: Bush Mission Pointe Library' is the "Product Name";
SQL: SELECT DISTINCT T2.`Customer Name` FROM central_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Bush Mission Pointe Library' AND T3.Region = 'Central'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Calculate the total profit by Cisco SPA301 for all regions.
Evidence: Cisco SPA301' is the "Product Name"; all regions refers to central_superstore, south_superstore, west_superstore, east_superstore
SQL: SELECT SUM(T1.Profit) + SUM(T2.Profit) + SUM(T3.Profit) + SUM(T4.Profit) AS totalProfit FROM west_superstore AS T1 INNER JOIN east_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN central_superstore AS T3 ON T3.`Customer ID` = T2.`Customer ID` INNER JOIN south_superstore AS T4 ON T4.`Customer ID` = T3.`Customer ID` INNER JOIN product AS T5 ON T5.`Product ID` = T4.`Product ID` WHERE T5.`Product Name` = 'Cisco SPA301'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: List the products that were ordered by Anne McFarland from the Western store.
Evidence: Anne McFarland' is the "Customer Name"; Western store refers to west_superstore; products refers to "Product Name"
SQL: SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Anne McFarland'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: List the products ordered by customers in Coachella.
Evidence: in Coachella refers to City = 'Coachella'; products refers to "Product Name"
SQL: SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.City = 'Coachella'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Compare the numbers of orders between the Eastern and Western stores in 2015.
Evidence: in 2015 refers to strftime('%Y', "Order Date") = '2015'; Eastern store refers to east_superstore; Western store refers west_superstore;
SQL: SELECT east, west FROM ( SELECT COUNT(`Order ID`) AS east , ( SELECT COUNT(`Order ID`) FROM west_superstore WHERE `Order Date` LIKE '2015%' ) AS west FROM east_superstore WHERE `Order Date` LIKE '2015%' )
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: List the products ordered by Matt Abelman from the Western store in 2013.
Evidence: ordered by Matt Abelman refers to "Customer Name" = 'Matt Abelman'; in 2013 refers to "Order Date" like '2013%'
SQL: SELECT DISTINCT T3.`Product Name` FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Matt Abelman' AND STRFTIME('%Y', T1.`Order Date`) = '2013'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Calculate the total cost of the orders by Brad Thomas in 2016.
Evidence: Brad Thomas is the "Customer Name"; in 2016 refers to strftime('%Y', "Order Date") = '2016'; total cost refers to SUM(SUTRACT(MULTIPLY(DIVIDE(Sales, SUTRACT(1, discount)), Quantity), Profit))
SQL: SELECT SUM((T1.Sales / (1 - T1.Discount)) * T1.Quantity - T1.Profit) AS cost FROM east_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T1.`Product ID` = T3.`Product ID` AND T1.Region = T3.Region WHERE T1.Region = 'East' AND T2.`Customer Name` = 'Brad Thomas' AND strftime('%Y', T1.`Order Date`) = '2016'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Provide the names, cities, and countries of the customers who ordered the Plantronics single ear headset.
Evidence: Plantronics Single Ear Headset' is the "Product Name"; name refers to "Customer Name";
SQL: SELECT DISTINCT T2.`Customer Name`, T2.City, T2.Country FROM west_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.`Product Name` = 'Plantronics Single Ear Headset'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: Provide the shipping dates and products of the orders by Gene Hale.
Evidence: Gene Hale' refers to "Customer Name"; shipping date refers to "Ship Date"; products refers to "Product Name"
SQL: SELECT DISTINCT T2.`Ship Date`, T3.`Product Name` FROM people AS T1 INNER JOIN central_superstore AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T2.`Product ID` WHERE T1.`Customer Name` = 'Gene Hale'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: How many orders in the south superstore with the fastest delivery are items of furniture?
Evidence: fastest delivery refers to Ship Mode = 'First Class'; furniture refers to Category = 'Furniture'
SQL: SELECT COUNT(T1.`Order ID`) FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` WHERE T1.`Ship Mode` = 'First Class' AND T2.Category = 'Furniture'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: How many office supply orders were made by Cindy Stewart in the south superstore?
Evidence: office supply refers to Category = 'Office Supplies'
SQL: SELECT COUNT(*) FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T3.Category = 'Office Supplies' AND T2.`Customer Name` = 'Cindy Stewart'
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: What product category got the highest profit in the south superstore?
Evidence: highest profit refers to MAX(Profit)
SQL: SELECT T2.Category FROM south_superstore AS T1 INNER JOIN product AS T2 ON T1.`Product ID` = T2.`Product ID` ORDER BY T1.Profit DESC LIMIT 1
Database: superstore
Tables: people, product, central_superstore, east_superstore, south_superstore, west_superstore
Columns (table index, column name): -1, *, 0, Customer ID, 0, Customer Name, 0, Segment, 0, Country, 0, City, 0, State, 0, Postal Code, 0, Region, 1, Product ID, 1, Product Name, 1, Category, 1, Sub-Category, 1, Region, 2, Row ID, 2, Order ID, 2, Order Date, 2, Ship Date, 2, Ship Mode, 2, Customer ID, 2, Region, 2, Product ID, 2, Sales, 2, Quantity, 2, Discount, 2, Profit, 3, Row ID, 3, Order ID, 3, Order Date, 3, Ship Date, 3, Ship Mode, 3, Customer ID, 3, Region, 3, Product ID, 3, Sales, 3, Quantity, 3, Discount, 3, Profit, 4, Row ID, 4, Order ID, 4, Order Date, 4, Ship Date, 4, Ship Mode, 4, Customer ID, 4, Region, 4, Product ID, 4, Sales, 4, Quantity, 4, Discount, 4, Profit, 5, Row ID, 5, Order ID, 5, Order Date, 5, Ship Date, 5, Ship Mode, 5, Customer ID, 5, Region, 5, Product ID, 5, Sales, 5, Quantity, 5, Discount, 5, Profit
Question: List the name of all products that Cindy Stewart ordered in the east superstore.
Evidence: name of all products refers to Product Name; Cindy Stewart is the Customer Name;
SQL: SELECT T3.`Product Name` FROM south_superstore AS T1 INNER JOIN people AS T2 ON T1.`Customer ID` = T2.`Customer ID` INNER JOIN product AS T3 ON T3.`Product ID` = T1.`Product ID` WHERE T2.`Customer Name` = 'Cindy Stewart'