Patent ID: 11920370
Assignee: CHINA INSTITUTE OF WATER RESOURCES AND HYDROPOWER RESEARCH
Field: Civil engineering (Other fields)
Classification: CPC E | IPC E

Claim 0:
1. An underground temporary danger avoiding system for defending against a short-duration and strong impact of a ground fluid, comprising: a danger avoiding chamber having a danger avoiding service radius of r; a danger avoiding entrance arranged at one side of the danger avoiding chamber and a rescue exit arranged at a position of the highest point of the danger avoiding chamber; waterproof doors resisting high water heads and unidirectionally opened outwards that are arranged at both the danger avoiding entrance and the rescue exit; an alarm apparatus arranged at the danger avoiding entrance; and a rotary stair leading to the rescue exit that is arranged in the danger avoiding chamber, and a life support system and a rescue device configured in the danger avoiding chamber;
wherein the danger avoiding service radius r is determined by an equation, comprising:, v
   =
   
    C
    ⁢
    
     
      R
      ⁢
      J
     
    
   
  
  ⁢
  
  
   C
   =
   
    
     1
     n
    
    ⁢
    
     R
     
      1
      6
     
    
   
  
  ⁢
  
  
   r
   =
   
    
     S
     v
    
    -
    
     t
     
      n
      ⁢
      o
      ⁢
      t
      ⁢
      i
      ⁢
      c
      ⁢
      e
     
    
   
  
 

wherein v is a flood propagation speed, C is Chezy coefficient, R is a hydraulic radius, J is a hydraulic gradient, n is watercourse roughness coefficient, is notification time, and S is a river length;
wherein the high water head, i.e., a land surface water depth hg, which the waterproof doors resist is calculated as:, Q
      down
     
     =
     
      
       Q
       
        u
        ⁢
        p
       
      
      *
      
       
        (
        
         1
         -
         α
        
        )
       
       
        S
        
         1
         ⁢
         0
         ⁢
         0
         ⁢
         0
        
       
      
     
    
   
  
  
   
    
     
      Q
      
       d
       ⁢
       o
       ⁢
       w
       ⁢
       n
      
     
     =
     
      A
      ⁢
      C
      ⁢
      
       
        R
        ⁢
        J
       
      
     
    
   
  
  
   
    
     R
     =
     
      
       
        
         (
         
          
           x
           2
          
          -
          
           x
           1
          
         
         )
        
        *
        
         h
         r
        
       
       -
       
        
         ∫
         
          x
          1
         
         
          x
          2
         
        
        
         
          f
          ⁡
          (
          x
          )
         
         ⁢
         d
         ⁢
         x
        
       
      
      
       
        ∫
        
         x
         1
        
        
         x
         2
        
       
       
        
         
          1
          +
          
           
            (
            
             
              f
              ′
             
             (
             x
             )
            
            )
           
           2
          
         
        
        ⁢
        d
        ⁢
        x
       
      
     
    
   
  
  
   
    
     A
     =
     
      
       
        (
        
         
          x
          2
         
         -
         
          x
          1
         
        
        )
       
       *
       
        h
        r
       
      
      -
      
       
        ∫
        
         x
         1
        
        
         x
         2
        
       
       
        f
        ⁢
        
         (
         x
         )
        
        ⁢
        d
        ⁢
        x
       
      
     
    
   
  
  
   
    
     
      h
      g
     
     =
     
      
       
        h
        r
       
       2
      
      *
      
       
        (
        
         1
         -
         β
        
        )
       
       
        r
        
         1
         ⁢
         0
         ⁢
         0
         ⁢
         0
        
       
      
     
    
   
  
 

wherein Qup is a flow rate of an upstream section, Qdown is a flow rate of a downstream section, S is a river length, α is flood peak attenuation coefficient, A is a section area, C is Chezy coefficient, R is a hydraulic radius, Jr is a hydraulic gradient, n is watercourse roughness coefficient, hr is a river water depth, hg is a land surface water depth, β is land surface flood water depth attenuation coefficient, x1 and x2 are starting point distances corresponding to two banks when the water depth is hr, f(x) is a polynomial function fitted by an irregular section, and the section f′(x) is the derivative of the fitting equation f(x);
wherein hg is solved as:, [
    
     
      
       
        (
        
         
          x
          2
         
         -
         
          x
          1
         
        
        )
       
       *
       2
       *
       
        h
        g
       
      
      
       
        (
        
         1
         -
         β
        
        )
       
       
        r
        
         1
         ⁢
         0
         ⁢
         0
         ⁢
         0
        
       
      
     
     -
     
      
       ∫
       
        x
        1
       
       
        x
        2
       
      
      
       
        f
        ⁡
        (
        x
        )
       
       ⁢
       d
       ⁢
       x
      
     
    
    ]
   
   *
   C
   ⁢
   
    
     
      
       
        
         
          (
          
           
            x
            2
           
           -
           
            x
            1
           
          
          )
         
         *
         2
         *
         
          h
          g
         
        
        
         
          (
          
           1
           -
           β
          
          )
         
         
          r
          
           1
           ⁢
           0
           ⁢
           0
           ⁢
           0
          
         
        
       
       ⁢
       
        
         ∫
         
          x
          1
         
         
          x
          2
         
        
        
         
          f
          ⁡
          (
          x
          )
         
         ⁢
         dx
        
       
      
      
       
        ∫
        
         x
         1
        
        
         x
         2
        
       
       
        
         
          1
          +
          
           
            (
            
             
              f
              ′
             
             (
             x
             )
            
            )
           
           2
          
         
        
        ⁢
        d
        ⁢
        x
       
      
     
     ⁢
     J
    
   
  
  =
  
   
    Q
    
     u
     ⁢
     p
    
   
   *
   
    
     (
     
      1
      -
      α
     
     )
    
    
     S
     
      1
      ⁢
      0
      ⁢
      0
      ⁢
      0
     
    
   
  
 

which is simplified into:

c12c3hg3−(c12c4+2c1c2c3)hg2+(2c1c2c4+c22c3)hg−(c22c4+c5)=0

wherein c1, c2, c3, c4, c5 are constants:, {
  
   
    
     
      
       
        c
        1
       
       =
       
        
         
          
           (
           
            
             x
             2
            
            -
            
             x
             1
            
           
           )
          
          *
          2
         
         
          
           (
           
            1
            -
            β
           
           )
          
          
           r
           
            1
            ⁢
            0
            ⁢
            0
            ⁢
            0
           
          
         
        
        ⁢
        C
       
      
     
    
    
     
      
       
        c
        2
       
       =
       
        
         ∫
         
          x
          1
         
         
          x
          2
         
        
        
         
          f
          ⁡
          (
          x
          )
         
         ⁢
         d
         ⁢
         x
         *
         C
        
       
      
     
    
    
     
      
       
        c
        3
       
       =
       
        
         
          (
          
           
            x
            2
           
           -
           
            x
            1
           
          
          )
         
         *
         2
         *
         J
        
        
         
          ∫
          
           x
           1
          
          
           x
           2
          
         
         
          
           
            1
            +
            
             
              (
              
               
                f
                ′
               
               (
               x
               )
              
              )
             
             2
            
           
          
          ⁢
          d
          ⁢
          x
          *
          
           
            (
            
             1
             -
             β
            
            )
           
           
            r
            
             1
             ⁢
             0
             ⁢
             0
             ⁢
             0
            
           
          
         
        
       
      
     
    
    
     
      
       
        c
        4
       
       =
       
        
         
          ∫
          
           x
           1
          
          
           x
           2
          
         
         
          
           f
           ⁡
           (
           x
           )
          
          ⁢
          d
          ⁢
          x
          *
          J
         
        
        
         
          ∫
          
           x
           1
          
          
           x
           2
          
         
         
          
           
            1
            +
            
             
              (
              
               
                f
                ′
               
               (
               x
               )
              
              )
             
             2
            
           
          
          ⁢
          d
          ⁢
          x
         
        
       
      
     
    
    
     
      
       
        c
        5
       
       =
       
        
         Q
         
          u
          ⁢
          p
         
        
        *
        
         
          (
          
           1
           -
           α
          
          )
         
         
          S
          
           1
           ⁢
           0
           ⁢
           0
           ⁢
           0
          
         
        
       
      
     
    
   
   .