Patent ID: 11893661
Assignee: SHANDONG UNIVERSITY
Field: nan (nan)
Classification: CPC nan | IPC A  G

Claim 11:
12. The system of claim 8, wherein the iterative algorithm comprises iterating on n as follows:, ϕ
      j
      
       n
       +
       
        1
        3
       
      
     
     =
     
      
       ϕ
       j
       n
      
      -
      
       
        δ
        1
       
       ⁢
       
        
         ∂
         L
        
        
         ∂
         
          ϕ
          j
         
        
       
       ⁢
       
        (
        
         
          ϕ
          n
         
         ,
         
          θ
          n
         
        
        )
       
       ⁢
       
        
         (
         
          
           ∑
           
            h
            =
            1
           
           J
          
          
           
            (
            
             
              
               
                ∂
                2
               
               L
              
              
               
                ∂
                
                 ϕ
                 j
                
               
               ⁢
               
                ∂
                
                 ϕ
                 h
                
               
              
             
             +
             
              
               
                ∂
                2
               
               L
              
              
               
                ∂
                
                 ϕ
                 j
                
               
               ⁢
               
                ∂
                
                 θ
                 h
                
               
              
             
            
            )
           
           ⁢
           
            (
            
             
              ϕ
              n
             
             ,
             
              θ
              n
             
            
            )
           
          
         
         )
        
        
         -
         1
        
       
      
     
    
   
  
  
   
    
     
      ϕ
      j
      
       n
       +
       
        2
        3
       
      
     
     =
     
      max
      ⁢
      
       {
       
        
         ϕ
         j
         
          n
          +
          
           1
           3
          
         
        
        ,
        0
       
       }
      
     
    
   
  
  
   
    
     
      θ
      j
      
       n
       +
       
        1
        3
       
      
     
     =
     
      
       θ
       j
       n
      
      -
      
       
        δ
        2
       
       ⁢
       
        
         ∂
         L
        
        
         ∂
         
          θ
          j
         
        
       
       ⁢
       
        (
        
         
          ϕ
          n
         
         ,
          
         
          θ
          n
         
        
        )
       
       ⁢
       
        
         (
         
          
           ∑
           
            h
            =
            1
           
           J
          
          
           
            (
            
             
              
               
                ∂
                2
               
               L
              
              
               
                ∂
                
                 θ
                 j
                
               
               ⁢
               
                ∂
                
                 ϕ
                 h
                
               
              
             
             +
             
              
               
                ∂
                2
               
               L
              
              
               
                ∂
                
                 θ
                 j
                
               
               ⁢
               
                ∂
                
                 θ
                 h
                
               
              
             
            
            )
           
           ⁢
           
            (
            
             
              ϕ
              n
             
             ,
             
              θ
              n
             
            
            )
           
          
         
         )
        
        
         -
         1
        
       
      
     
    
   
  
  
   
    
     
      θ
      j
      
       n
       +
       
        2
        3
       
      
     
     =
     
      max
      ⁢
      
       {
       
        
         θ
         j
         
          n
          +
          
           1
           3
          
         
        
        ,
        0
       
       }
      
     
    
   
  
  
   
    
     
      ϕ
      j
      
       n
       +
       1
      
     
     =
     
      
       W
       T
      
      ⁢
      
       T
       
        λ
        1
       
      
      ⁢
      
       (
       
        W
        ⁢
        
         ϕ
         j
         
          n
          +
          
           2
           3
          
         
        
       
       )
      
     
    
   
  
  
   
    
     
      
       θ
       j
       
        n
        +
        1
       
      
      =
      
       
        W
        T
       
       ⁢
       
        T
        
         λ
         2
        
       
       ⁢
       
        (
        
         W
         ⁢
         
          θ
          j
          
           n
           +
           
            2
            3
           
          
         
        
        )
       
      
     
     ,
    
   
  
 

wherein ϕ=ϕ(r) defines a photoelectric component and θ=θ(r) defines a
Compton scatter component of the attenuation coefficient μ(r, E) at each point r.